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math_qa__ZSZY2n4u7sYiUDOJ | haresh went to buy fruits.she bought 1 apple , 3 bananas , 5 oranges and paid 21 rupees.another person bought 7 apple ,5 bananas , 3 oranges and paid 51 rupees.if i want to buy 1 apple, 1 banana , 1 orange then how much i have to pay? Answers
A) 8
B) 9
C) 10
D) 11
E) 7 | <gadget id="calculator">21 + 51</gadget>
<output>72</output>
<gadget id="calculator">1 + 7</gadget>
<output>8</output>
<gadget id="calculator">72 / 8</gadget>
<output>9</output>
<result>B</result> | B | 9 | haresh went to buy fruits.she bought 1 apple , 3 bananas , 5 oranges and paid 21 rupees.another person bought 7 apple ,5 bananas , 3 oranges and paid 51 rupees.if i want to buy 1 apple, 1 banana , 1 orange then how much i have to pay? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "7"
} | divide(add(21, 51), add(1, 7)) | add(n3,n7)|add(n0,n4)|divide(#0,#1) | there can be multiple possible rates of apple , banana and orange to satisfy given conditions , but cost of 1 apple , 1 banana , 1 orange will be rs 9 . 1 x + 3 y + 5 z = 21 . . . . . . . . ( 1 ) 7 x + 5 y + 3 z = 51 . . . . . . . . ( 2 ) adding ( 1 ) and ( 2 ) , we get 8 x + 8 y + 8 z = 72 8 * ( x + y + z ) = 72 x + y + z = 9 answer : b | general |
math_qa__rxlgNuLkYp0d2wnq | Mahesh can do a piece of work in 60days. He works at it for 20days and then Rajesh finished it in 30days. How long will Y take to complete the work?
Select the correct option:
A) 45 B) 25 C) 37 D) 41 E) 30 | <gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">20 * (1/60)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) / 30</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">1 / (1/45)</gadget>
<output>45</output>
<result>A</result> | A | 45 | Mahesh can do a piece of work in 60days. He works at it for 20days and then Rajesh finished it in 30days. How long will Y take to complete the work? | {
"A": "45",
"B": "25",
"C": "37",
"D": "41",
"E": "30"
} | divide(const_1, divide(subtract(const_1, multiply(20, divide(const_1, 60))), 30)) | divide(const_1,n0)|multiply(n1,#0)|subtract(const_1,#1)|divide(#2,n2)|divide(const_1,#3)| | "work done by mahesh in 60 days = 20 * 1 / 60 = 1 / 3 remaining work = 1 - 1 / 3 = 2 / 3 2 / 3 work is done by rajesh in 30 days whole work will be done by rajesh is 30 * 3 / 2 = 45 days answer is a" | physics |
math_qa__pTBgpfhVkxDYKwq4 | A land owner needs to fence his semicircular land leaving an opening of length of 3m for access. The radius of the semicircular plot is 7m. How long would be the fence in meters? Answers.
A) 22 B) 33 C) 36 D) 44 E) 51 | <gadget id="calculator">2 + 10</gadget>
<output>12</output>
<gadget id="calculator">12 + 10</gadget>
<output>22</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">7 * (22/7)</gadget>
<output>22</output>
<gadget id="calculator">2 * 7</gadget>
<output>14</output>
<gadget id="calculator">22 + 14</gadget>
<output>36</output>
<gadget id="calculator">36 - 3</gadget>
<output>33</output>
<result>B</result> | B | 33 | A land owner needs to fence his semicircular land leaving an opening of length of 3m for access. The radius of the semicircular plot is 7m. How long would be the fence in meters? | {
"A": "22",
"B": "33",
"C": "36",
"D": "44",
"E": "51"
} | subtract(add(multiply(7, divide(add(add(const_2, const_10), const_10), 7)), multiply(const_2, 7)), 3) | add(const_10,const_2)|multiply(n1,const_2)|add(#0,const_10)|divide(#2,n1)|multiply(n1,#3)|add(#4,#1)|subtract(#5,n0) | perimeter of the semicircle = Γ― β¬ xd / 2 + d = Γ― β¬ x 7 + 14 = 22 + 14 = 36 m length of the fence = 36 - 3 = 33 m answer : b | physics |
math_qa__DbOuF8SE5XF2HSLm | Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has travelled 60 km more than the other one. The distance between the two stations is?
Choose the correct choice from the following choices.
A) 222 km B) 333 km C) 555 km D) 444 km E) 666 km | <gadget id="calculator">21 - 16</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">12 * 16</gadget>
<output>192</output>
<gadget id="calculator">12 * 21</gadget>
<output>252</output>
<gadget id="calculator">192 + 252</gadget>
<output>444</output>
<result>D</result> | D | 444 | Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has travelled 60 km more than the other one. The distance between the two stations is? | {
"A": "222 km",
"B": "333 km",
"C": "555 km",
"D": "444 km",
"E": "666 km"
} | add(multiply(divide(60, subtract(21, 16)), 16), multiply(divide(60, subtract(21, 16)), 21)) | subtract(n1,n0)|divide(n2,#0)|multiply(n0,#1)|multiply(n1,#1)|add(#2,#3) | d 444 km 1 h - - - - - 5 ? - - - - - - 60 12 h rs = 16 + 21 = 37 t = 12 d = 37 * 12 = 444 | physics |
math_qa__YR43T8u1rj2HpB14 | If a = 105 and a^3 = 21 Γ 25 Γ 45 Γ q, what is the value of q?
Choices:
A) 35 B) 42 C) 45 D) 49 E) 54 | <gadget id="calculator">105 ** 3</gadget>
<output>1_157_625</output>
<gadget id="calculator">21 * 25</gadget>
<output>525</output>
<gadget id="calculator">525 * 45</gadget>
<output>23_625</output>
<gadget id="calculator">1_157_625 / 23_625</gadget>
<output>49</output>
<result>D</result> | D | 49 | If a = 105 and a^3 = 21 Γ 25 Γ 45 Γ q, what is the value of q? | {
"A": "35",
"B": "42",
"C": "45",
"D": "49",
"E": "54"
} | divide(power(105, 3), multiply(multiply(21, 25), 45)) | multiply(n2,n3)|power(n0,n1)|multiply(n4,#0)|divide(#1,#2)| | "a = 105 = 3 * 5 * 7 a ^ 3 = 21 Γ 25 Γ 45 Γ q = > a ^ 3 = ( 7 * 3 ) x ( 5 * 5 ) x ( 3 ^ 2 * 5 ) x q = > a ^ 3 = 3 ^ 3 * 5 ^ 3 * 7 x q = > ( 3 * 5 * 7 ) ^ 3 = 3 ^ 3 * 5 ^ 3 * 7 x q q = 7 ^ 2 = 49 answer d" | general |
math_qa__qT7QM2atQK37Qs44 | The average (arithmetic mean) of 4 different integers is 72. If the largest integer is 90, what is the least possible value of the smallest integer?
Select the correct option: A) 1 B) 19 C) 21 D) 30 E) 33 | <gadget id="calculator">72 * 4</gadget>
<output>288</output>
<gadget id="calculator">288 - 90</gadget>
<output>198</output>
<gadget id="calculator">90 - 1</gadget>
<output>89</output>
<gadget id="calculator">198 - 89</gadget>
<output>109</output>
<gadget id="calculator">90 - 2</gadget>
<output>88</output>
<gadget id="calculator">109 - 88</gadget>
<output>21</output>
<result>C</result> | C | 21 | The average (arithmetic mean) of 4 different integers is 72. If the largest integer is 90, what is the least possible value of the smallest integer? | {
"A": "1",
"B": "19",
"C": "21",
"D": "30",
"E": "33"
} | subtract(subtract(subtract(multiply(72, 4), 90), subtract(90, const_1)), subtract(90, const_2)) | multiply(n0,n1)|subtract(n2,const_1)|subtract(n2,const_2)|subtract(#0,n2)|subtract(#3,#1)|subtract(#4,#2) | total of integers = 72 * 4 = 288 lowest of the least possible integer is when the middle 2 intergers are at the maximum or equal to the highest possible integer . but all integers are distinct . so if the largest integer is 90 , then the middle 2 will be 88 and 89 lowest of least possible integer = 288 - ( 90 + 89 + 88 ) = 288 - 267 = 21 answer : c | general |
math_qa__ii73ooLMq0Xpjt3E | Stacy has a 66 page history paper due in 6 days. How many pages per day would she have to write to finish on time? Pick.
A) 9
B) 8
C) 11
D) 8.5
E) 6 | <gadget id="calculator">66 / 6</gadget>
<output>11</output>
<result>C</result> | C | 11 | Stacy has a 66 page history paper due in 6 days. How many pages per day would she have to write to finish on time? | {
"A": "9",
"B": "8",
"C": "11",
"D": "8.5",
"E": "6"
} | divide(66, 6) | divide(n0,n1) | 66 / 6 = 11 answer : c | physics |
math_qa__m8mYoP0SamxwbI3a | Jane makes toy bears. When she works with an assistant, she makes 80 percent more bears per week and works 10 percent fewer hours each week. Having an assistant increases Janeβs output of toy bears per hour by what percent W? Choose the correct choice from the following choices: A) 20 % B) 80 % C) 100 % D) 180 % E) 200 % | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>C</result> | C | 100 | Jane makes toy bears. When she works with an assistant, she makes 80 percent more bears per week and works 10 percent fewer hours each week. Having an assistant increases Janeβs output of toy bears per hour by what percent W? | {
"A": "20 %",
"B": "80 %",
"C": "100 %",
"D": "180 %",
"E": "200 %"
} | multiply(divide(const_10, subtract(subtract(const_100, 80), 10)), const_100) | subtract(const_100,n0)|subtract(#0,n1)|divide(const_10,#1)|multiply(#2,const_100) | c . let ' s assume just jane 40 bears per 40 / hrs a week , so that is 1 bear / hr . with an assistant she makes 72 bears per 36 hours a week or 2 bears / hr ( [ 40 bears * 1.8 ] / [ 40 hrs * . 90 ] ) . w = [ ( 2 - 1 ) / 1 ] * 100 % = 100 % | physics |
math_qa__fKf5R8cQb3N6o4pY | Diana took out a charge account at the General Store and agreed to pay 7% simple annual interest. If she charges $75 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? Choose the correct choice from the following
A) $ 79.25 B) $ 79.50 C) $ 79.75 D) $ 80.00 E) $ 80.25 | <gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">(7/100) * 75</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">75 + (21/4)</gadget>
<output>321/4 = around 80.25</output>
<result>E</result> | E | 80.25 | Diana took out a charge account at the General Store and agreed to pay 7% simple annual interest. If she charges $75 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? | {
"A": "$ 79.25",
"B": "$ 79.50",
"C": "$ 79.75",
"D": "$ 80.00",
"E": "$ 80.25"
} | add(75, multiply(divide(7, const_100), 75)) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1) | 1.07 * $ 75 = $ 80.25 the answer is e . | general |
math_qa__l5XE9tN44yxWYifq | A man completes of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
Pick
A) 6 B) 12 C) 7 D) 15 E) 5 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">1 - (5/8)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">10 * (3/8)</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">(15/4) / (5/8)</gadget>
<output>6</output>
<result>A</result> | A | 6 | A man completes of a job in 10 days. At this rate, how many more days will it takes him to finish the job? | {
"A": "6",
"B": "12",
"C": "7",
"D": "15",
"E": "5"
} | divide(multiply(10, subtract(const_1, divide(add(const_2, const_3), multiply(const_2, const_4)))), divide(add(const_2, const_3), multiply(const_2, const_4))) | add(const_2,const_3)|multiply(const_2,const_4)|divide(#0,#1)|subtract(const_1,#2)|multiply(n0,#3)|divide(#4,#2) | work done = 5 / 8 balance work = ( 1 - 5 / 8 ) = 3 / 8 let the required number of days be x . then , ( 5 / 8 ) : ( 3 / 8 ) = : : 10 : x ( 5 / 8 ) * x = ( 3 / 8 ) * 10 x = ( 3 / 8 ) * 10 * ( 8 / 5 ) x = 6 . answer is a . | gain |
math_qa__PTrMrQoc1l2U8c1m | In a sample of 800 high school students in which all students are either freshmen, sophomores, juniors, or seniors, 22 percent are juniors and 74 percent are not sophomores. If there are 160 seniors, how many more freshmen than sophomores are there among the sample of students?
Pick: A) 42 B) 48 C) 56 D) 208 E) 256 | <gadget id="calculator">160 / 800</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 - 22</gadget>
<output>58</output>
<gadget id="calculator">100 - 74</gadget>
<output>26</output>
<gadget id="calculator">58 - 26</gadget>
<output>32</output>
<gadget id="calculator">32 * 800</gadget>
<output>25_600</output>
<gadget id="calculator">25_600 / 100</gadget>
<output>256</output>
<gadget id="calculator">26 * 800</gadget>
<output>20_800</output>
<gadget id="calculator">20_800 / 100</gadget>
<output>208</output>
<gadget id="calculator">256 - 208</gadget>
<output>48</output>
<result>B</result> | B | 48 | In a sample of 800 high school students in which all students are either freshmen, sophomores, juniors, or seniors, 22 percent are juniors and 74 percent are not sophomores. If there are 160 seniors, how many more freshmen than sophomores are there among the sample of students? | {
"A": "42",
"B": "48",
"C": "56",
"D": "208",
"E": "256"
} | subtract(divide(multiply(subtract(subtract(subtract(const_100, multiply(divide(160, 800), const_100)), 22), subtract(const_100, 74)), 800), const_100), divide(multiply(subtract(const_100, 74), 800), const_100)) | divide(n3,n0)|subtract(const_100,n2)|multiply(#0,const_100)|multiply(n0,#1)|divide(#3,const_100)|subtract(const_100,#2)|subtract(#5,n1)|subtract(#6,#1)|multiply(n0,#7)|divide(#8,const_100)|subtract(#9,#4)| | "sophomores = 26 % juniors = 22 % seniors = 160 / 800 = 20 % total : 68 % 1 - 68 % = 32 % ( freshmen ) 0,32 * 800 - 0,26 * 800 = 256 - 208 = 48 . answer choice b" | gain |
math_qa__uGE18sibElxW0liE | A student needs 60% of the marks on a test to pass the test. If the student gets 80 marks and fails the test by 100 marks, find the maximum marks set for the test.
Options:
A) 250 B) 300 C) 350 D) 400 E) 450 | <gadget id="calculator">80 + 100</gadget>
<output>180</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">180 / (3/5)</gadget>
<output>300</output>
<result>B</result> | B | 300 | A student needs 60% of the marks on a test to pass the test. If the student gets 80 marks and fails the test by 100 marks, find the maximum marks set for the test. | {
"A": "250",
"B": "300",
"C": "350",
"D": "400",
"E": "450"
} | divide(add(80, 100), divide(60, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "60 % = 180 marks 1 % = 3 marks 100 % = 300 marks the answer is b ." | gain |
math_qa__3YupvCdm87VcD4Bg | A football player scores 2 goals in his fifth match thus increasing his average goals score by 0.1. The total number of goals in his 5 matches would be
Choose one:
A) 4 B) 6 C) 8 D) 10 E) 12 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 0.1</gadget>
<output>2</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<result>C</result> | C | 8 | A football player scores 2 goals in his fifth match thus increasing his average goals score by 0.1. The total number of goals in his 5 matches would be | {
"A": "4",
"B": "6",
"C": "8",
"D": "10",
"E": "12"
} | add(subtract(multiply(const_4, 2), multiply(multiply(const_4, 5), 0.1)), 2) | multiply(n0,const_4)|multiply(n2,const_4)|multiply(n1,#1)|subtract(#0,#2)|add(n0,#3)| | "while this question can be solved with a rather straight - forward algebra approach ( as the other posters have noted ) , it can also be solved by testing the answers . one of those numbers must be the total number of goals . . . from a tactical standpoint , it ' s best to test either answer b or answer d , so if the answer is not correct , then you would have a gauge for whether you should gohigherorlowerwith your next test . here , i ' ll start with answer c = 8 goals if . . . . total goals = 8 goals 5 th game = 2 goals 1 st 4 games = 6 goals avg . for 1 st 4 games = 6 / 4 = 1.5 goal / game avg . for all 5 games = 8 / 5 = 1.6 goals / game this is an exact match for what we ' re told in the prompt , so answer c must be the answer ." | general |
math_qa__K9r7SxkhyojQycqM | If the weight of 12 meters long rod is 14 kg. What is the weight of 6 meters long rod ? Answers:
A) 8 kg . B) 10.8 kg . C) 7 kg . D) 18.0 kg E) none | <gadget id="calculator">6 * 14</gadget>
<output>84</output>
<gadget id="calculator">84 / 12</gadget>
<output>7</output>
<result>C</result> | C | 7 | If the weight of 12 meters long rod is 14 kg. What is the weight of 6 meters long rod ? | {
"A": "8 kg .",
"B": "10.8 kg .",
"C": "7 kg .",
"D": "18.0 kg",
"E": "none"
} | divide(multiply(6, 14), 12) | multiply(n1,n2)|divide(#0,n0)| | "answer β΅ weight of 12 m long rod = 14 kg β΄ weight of 1 m long rod = 14 / 12 kg β΄ weight of 6 m long rod = 14 x 6 / 12 = 7 kg option : c" | physics |
math_qa__XgfkaTfsSpqKtlJJ | After giving a discount of rs.45 the shopkeeper still gets a profit of 20%,if the cost price is rs.180.find the markup %? Choose the correct choice from the following
A) 0.4 B) 0.55 C) 0.45 D) 0.48 E) 0.58 | <gadget id="calculator">100 / 20</gadget>
<output>5</output>
<gadget id="calculator">180 / 5</gadget>
<output>36</output>
<gadget id="calculator">180 + 36</gadget>
<output>216</output>
<gadget id="calculator">216 + 45</gadget>
<output>261</output>
<gadget id="calculator">261 - 180</gadget>
<output>81</output>
<gadget id="calculator">81 / 180</gadget>
<output>9/20 = around 0.45</output>
<result>C</result> | C | 0.45 | After giving a discount of rs.45 the shopkeeper still gets a profit of 20%,if the cost price is rs.180.find the markup %? | {
"A": "0.4",
"B": "0.55",
"C": "0.45",
"D": "0.48",
"E": "0.58"
} | divide(subtract(add(add(180, divide(180, divide(const_100, 20))), 45), 180), 180) | divide(const_100,n1)|divide(n2,#0)|add(n2,#1)|add(n0,#2)|subtract(#3,n2)|divide(#4,n2) | cost price = 180 s . p = 180 * 120 / 100 = 216 disc = 45 so . . . mark price = 216 + 45 = 261 . . . . . . mark up % = 261 - 180 / 180 = 81 / 180 = . 45 or 45 % answer : c | gain |
math_qa__umVOZ2UCLKWTL9Mu | A train travelling 80kmph to pass through a tunnel of 70km at 5:12am. the train leaves the tunnel at 5:18am. find the length of train?
Choose the correct choice.
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">18 - 12</gadget>
<output>6</output>
<gadget id="calculator">6 / 60</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 80</gadget>
<output>8</output>
<gadget id="calculator">70 / 10</gadget>
<output>7</output>
<gadget id="calculator">8 - 7</gadget>
<output>1</output>
<result>A</result> | A | 1 | A train travelling 80kmph to pass through a tunnel of 70km at 5:12am. the train leaves the tunnel at 5:18am. find the length of train? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(multiply(divide(subtract(18, 12), const_60), 80), divide(70, const_10)) | divide(n1,const_10)|subtract(n5,n3)|divide(#1,const_60)|multiply(n0,#2)|subtract(#3,#0) | distance = speed * time let x is length of train 5 : 18 - 5 : 12 = 6 minutes = 6 / 60 hr = 1 / 10 hr now d = ( x + 7 ) = 80 kmph * 1 / 10 x = 1 km answer : a | physics |
math_qa__OmNbznFiwPrvhf7E | If x is equal to the sum of the integers from 30 to 50, inclusive, and y is the number of even integers from 30 to 50, inclusive, what is the value of x + y ?
Choose the correct choice from the following: A) 810 B) 811 C) 830 D) 850 E) 851 | <gadget id="calculator">30 + 50</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<gadget id="calculator">50 - 30</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">40 * 21</gadget>
<output>840</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">840 + 11</gadget>
<output>851</output>
<result>E</result> | E | 851 | If x is equal to the sum of the integers from 30 to 50, inclusive, and y is the number of even integers from 30 to 50, inclusive, what is the value of x + y ? | {
"A": "810",
"B": "811",
"C": "830",
"D": "850",
"E": "851"
} | add(multiply(divide(add(30, 50), const_2), add(subtract(50, 30), const_1)), add(divide(subtract(50, 30), const_2), const_1)) | add(n0,n1)|subtract(n1,n0)|add(#1,const_1)|divide(#1,const_2)|divide(#0,const_2)|add(#3,const_1)|multiply(#2,#4)|add(#5,#6)| | since the integers from 30 - 50 are consecutive we can use the ` ` median x # of terms formula ' ' to determine x . there are 21 terms and the median is 40 . this gives a total of 21 x 40 = 840 . there are 11 even integers from 30 - 50 = y . therefore , x + y = 851 . answer : e | general |
math_qa__SVB7ysr45a7uFbrA | Of the 100 people in a room, 2/5 are women. If 1/4 of the people are married, what is the maximum number of women in the room who could be unmarried? Choices: A) 32 B) 34 C) 36 D) 38 E) 40 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">100 * (2/5)</gadget>
<output>40</output>
<result>E</result> | E | 40 | Of the 100 people in a room, 2/5 are women. If 1/4 of the people are married, what is the maximum number of women in the room who could be unmarried? | {
"A": "32",
"B": "34",
"C": "36",
"D": "38",
"E": "40"
} | multiply(100, divide(2, 5)) | divide(n1,n2)|multiply(n0,#0) | women = 2 / 5 * 100 = 40 married = 1 / 4 * 100 = 25 unmarried = 75 max ( un - married women ) = 40 answer e | general |
math_qa__xBBwTSj4y6e4PRR1 | The length of the bridge, which a train 160 meters long and travelling at 45 km/hr can cross in 30 seconds, is: Choose the correct choice from the following answers
A) 230 B) 244 C) 245 D) 215 E) 236 | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 160</gadget>
<output>215</output>
<result>D</result> | D | 215 | The length of the bridge, which a train 160 meters long and travelling at 45 km/hr can cross in 30 seconds, is: | {
"A": "230",
"B": "244",
"C": "245",
"D": "215",
"E": "236"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 160) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "speed = ( 45 * 5 / 18 ) m / sec = ( 25 / 2 ) m / sec . time = 30 sec . let the length of bridge be x meters . then , ( 160 + x ) / 30 = 25 / 2 = = > 2 ( 160 + x ) = 750 = = > x = 215 m . answer : option d" | physics |
math_qa__4rfFhEdrjCMYDrHD | If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/5 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? Select
A) 5 / 2 B) 10 / 3 C) 15 / 4 D) 25 / 3 E) 25 / 6 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(2/5) * (1/5)</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/5) + (2/25)</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">(12/25) / 2</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">1 / (6/25)</gadget>
<output>25/6 = around 4.166667</output>
<result>E</result> | E | 4.166667 | If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/5 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? | {
"A": "5 / 2",
"B": "10 / 3",
"C": "15 / 4",
"D": "25 / 3",
"E": "25 / 6"
} | divide(1, divide(add(divide(2, 5), multiply(divide(2, 5), divide(1, 5))), const_2)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)|add(#0,#2)|divide(#3,const_2)|divide(n2,#4)| | "n = 2 d / 5 j = n / 5 = 2 d / 25 the average of november and january is ( n + j ) / 2 = 12 d / 25 / 2 = 6 d / 25 d is 25 / 6 times the average of november and january . the answer is e ." | general |
math_qa__3r8SnVYHJwHiWmWF | A rainstorm increased the amount of water stored in State J reservoirs from 130 billion gallons to 160 billion gallons. If the storm increased the amount of water in the reservoirs to 60 percent of total capacity, approximately how many billion gallons of water were the reservoirs short of total capacity prior to the storm?
Options:
A) 92
B) 85
C) 136.67
D) 140.67
E) 150 | <gadget id="calculator">160 * 100</gadget>
<output>16_000</output>
<gadget id="calculator">16_000 / 60</gadget>
<output>800/3 = around 266.666667</output>
<gadget id="calculator">(800/3) / 2</gadget>
<output>400/3 = around 133.333333</output>
<result>C</result> | C | 136.67 | A rainstorm increased the amount of water stored in State J reservoirs from 130 billion gallons to 160 billion gallons. If the storm increased the amount of water in the reservoirs to 60 percent of total capacity, approximately how many billion gallons of water were the reservoirs short of total capacity prior to the storm? | {
"A": "92",
"B": "85",
"C": "136.67",
"D": "140.67",
"E": "150"
} | divide(divide(multiply(160, const_100), 60), const_2) | multiply(n1,const_100)|divide(#0,n2)|divide(#1,const_2)| | "let total capacity be x we know 160 = 0.60 x x = 160 / 0.60 = 266.67 prior to storm , we had 130 bn gallons 266.67 - 130 = 136.67 answer : c" | general |
math_qa__60n5zSiRFy80k0nJ | If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively? Select
A) rs . 300
B) rs . 360
C) rs . 389
D) rs . 368
E) rs . 323 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(2/3) * (1/4)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) + (1/4)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) + 1</gadget>
<output>17/12 = around 1.416667</output>
<gadget id="calculator">510 / (17/12)</gadget>
<output>360</output>
<result>B</result> | B | 360 | If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively? | {
"A": "rs . 300",
"B": "rs . 360",
"C": "rs . 389",
"D": "rs . 368",
"E": "rs . 323"
} | divide(510, add(add(multiply(divide(2, 3), divide(1, 4)), divide(1, 4)), 1)) | divide(n3,n4)|divide(n1,n2)|multiply(#1,#0)|add(#0,#2)|add(#3,n3)|divide(n0,#4)| | "( a = 2 / 3 b and b = 1 / 4 c ) = a / b = 2 / 3 and b / c = 1 / 4 a : b = 2 : 3 and b : c = 1 : 4 = 3 : 12 a : b : c = 2 : 3 : 12 a ; s share = 510 * 2 / 17 = rs . 60 b ' s share = 510 * 3 / 17 = rs . 90 c ' s share = 510 * 12 / 17 = rs . 360 . answer : b" | general |
math_qa__jlZRjJZMIfZPtJ0U | If p#q denotes the least common multiple of p and q, then P=((12#16)#(18#24)) = ? Choose the most appropriate option
A) 216 B) 180 C) 144 D) 108 E) 72 | <gadget id="calculator">18 * 24</gadget>
<output>432</output>
<gadget id="calculator">12 * 16</gadget>
<output>192</output>
<gadget id="calculator">432 - 192</gadget>
<output>240</output>
<gadget id="calculator">240 / 2</gadget>
<output>120</output>
<gadget id="calculator">120 + 24</gadget>
<output>144</output>
<result>C</result> | C | 144 | If p#q denotes the least common multiple of p and q, then P=((12#16)#(18#24)) = ? | {
"A": "216",
"B": "180",
"C": "144",
"D": "108",
"E": "72"
} | add(divide(subtract(multiply(18, 24), multiply(12, 16)), const_2), 24) | multiply(n2,n3)|multiply(n0,n1)|subtract(#0,#1)|divide(#2,const_2)|add(n3,#3)| | "there are several ways to find the least common multiple of two numbers . in this case , the most efficient method is to use the greatest common factor : ( a * b ) / ( gcf ab ) = lcm ab the greatest common factor of 12 and 16 is 4 . so , 12 # 16 = 12 * 16 / 4 = 48 . the greatest common factor of 18 and 24 is 6 . so , 18 # 24 = 18 * 24 / 6 = 72 finally , the greatest common factor of 48 and 72 is 24 . so , p = ( ( 12 # 16 ) # ( 18 # 24 ) ) = 48 # 72 = ( 48 * 72 ) / 24 = 2 * 72 = 144 the correct answer is c ." | general |
math_qa__sPR5veG8gY5p4GfZ | Solution A is made up of alcohol and water mixed in the ratio of 21:4 by volume; Solution B is made up of alcohol and water mixed in the ratio of 2:3 by volume. If Solution A and Solution B are mixed in the ratio of 5:6 by volume, what percent of the resultant mixture is alcohol? Choices
A) 32.5 %
B) 40 %
C) 60 %
D) 65 %
E) can not be determined | <gadget id="calculator">21 + 4</gadget>
<output>25</output>
<gadget id="calculator">21 / 25</gadget>
<output>21/25 = around 0.84</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">5 / 11</gadget>
<output>5/11 = around 0.454545</output>
<gadget id="calculator">(21/25) * (5/11)</gadget>
<output>21/55 = around 0.381818</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">6 / 11</gadget>
<output>6/11 = around 0.545455</output>
<gadget id="calculator">(2/5) * (6/11)</gadget>
<output>12/55 = around 0.218182</output>
<gadget id="calculator">(21/55) + (12/55)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>C</result> | C | 60 | Solution A is made up of alcohol and water mixed in the ratio of 21:4 by volume; Solution B is made up of alcohol and water mixed in the ratio of 2:3 by volume. If Solution A and Solution B are mixed in the ratio of 5:6 by volume, what percent of the resultant mixture is alcohol? | {
"A": "32.5 %",
"B": "40 %",
"C": "60 %",
"D": "65 %",
"E": "can not be determined"
} | multiply(add(multiply(divide(21, add(21, 4)), divide(5, add(5, 6))), multiply(divide(2, add(2, 3)), divide(6, add(5, 6)))), const_100) | add(n0,n1)|add(n4,n5)|add(n2,n3)|divide(n0,#0)|divide(n4,#1)|divide(n2,#2)|divide(n5,#1)|multiply(#3,#4)|multiply(#5,#6)|add(#7,#8)|multiply(#9,const_100) | let mixture after mixing a and b is 110 ml ( number assumed for calculation because of 5 : 6 ) now solution a is 50 ml and solu b is 60 ml further in a 100 ml a contains 84 ml alch so 50 ml contain 42 ml in mix b 100 ml solution contain 40 ml alc , 60 ml of b , it will be 24 ml alcohol . so 42 + 24 = 66 in 110 ml solution which is 60 % answer : c | other |
math_qa__OqVlDe2ykTV1I5Vh | Keats Library purchases a number of new books, all in the category of biography, and the library does not acquire any other books. With the addition of the new biographies, the biography collection of the library amounts to 55% of the total number of books in the library. If prior to the purchase, only 20% of the books in Keats Library were biographies, by what percent has the number of biographies in the library increased?
Pick:
A) 270 % B) 310 % C) 350 % D) 390 % E) 430 % | <gadget id="calculator">55 * 100</gadget>
<output>5_500</output>
<gadget id="calculator">20 * 100</gadget>
<output>2_000</output>
<gadget id="calculator">5_500 - 2_000</gadget>
<output>3_500</output>
<gadget id="calculator">100 - 55</gadget>
<output>45</output>
<gadget id="calculator">3_500 / 45</gadget>
<output>700/9 = around 77.777778</output>
<gadget id="calculator">(700/9) / 20</gadget>
<output>35/9 = around 3.888889</output>
<gadget id="calculator">(35/9) * 100</gadget>
<output>3_500/9 = around 388.888889</output>
<result>D</result> | D | 390 | Keats Library purchases a number of new books, all in the category of biography, and the library does not acquire any other books. With the addition of the new biographies, the biography collection of the library amounts to 55% of the total number of books in the library. If prior to the purchase, only 20% of the books in Keats Library were biographies, by what percent has the number of biographies in the library increased? | {
"A": "270 %",
"B": "310 %",
"C": "350 %",
"D": "390 %",
"E": "430 %"
} | multiply(divide(divide(subtract(multiply(55, const_100), multiply(20, const_100)), subtract(const_100, 55)), 20), const_100) | multiply(n0,const_100)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#1)|divide(#3,#2)|divide(#4,n1)|multiply(#5,const_100)| | "let x be the number of new biographies added to the library . let b be the original number of biographies , so the original number of books was 5 b . 0.55 ( 5 b + x ) = b + x 1.75 b = 0.45 x x = 3.9 b the answer is d ." | general |
math_qa__swMhlsqO7SeyMrIw | After decreasing 24% in the price of an article costs Rs.836. Find the actual cost of an article? Choose the most appropriate option:
A) 1667 B) 6789 C) 1200 D) 1100 E) 1421 | <gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">1 - (6/25)</gadget>
<output>19/25 = around 0.76</output>
<gadget id="calculator">836 / (19/25)</gadget>
<output>1_100</output>
<result>D</result> | D | 1,100 | After decreasing 24% in the price of an article costs Rs.836. Find the actual cost of an article? | {
"A": "1667",
"B": "6789",
"C": "1200",
"D": "1100",
"E": "1421"
} | divide(836, subtract(const_1, divide(24, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1) | cp * ( 76 / 100 ) = 836 cp = 11 * 100 = > cp = 1100 answer : d | gain |
math_qa__EA9E0n49z0omdFjj | Two isosceles Triangles have equal vertical angles and their areas are in the ratio 16:36. Find the ratio of their corresponding heights . Choices.
A) 4 / 6 B) 5 / 4 C) 3 / 2 D) 5 / 7 E) 2 / 3 | <gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<result>A</result> | A | 0.666667 | Two isosceles Triangles have equal vertical angles and their areas are in the ratio 16:36. Find the ratio of their corresponding heights . | {
"A": "4 / 6",
"B": "5 / 4",
"C": "3 / 2",
"D": "5 / 7",
"E": "2 / 3"
} | divide(sqrt(16), sqrt(36)) | sqrt(n0)|sqrt(n1)|divide(#0,#1)| | "we are basically given that the triangles are similar . in two similar triangles , the ratio of their areas is the square of the ratio of their sides and also , the square of the ratio of their corresponding heights . therefore , area / area = height ^ 2 / height ^ 2 = 16 / 36 - - > height / height = 4 / 6 . answer : a ." | geometry |
math_qa__dx0d6yEM0eIpnj8W | In a weight-lifting competition, the total weight of Joe's two lifts was 1500 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift? Choose the correct choice from the following answers.
A) 225
B) 275
C) 325
D) 350
E) 600 | <gadget id="calculator">1_500 + 300</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 3</gadget>
<output>600</output>
<result>E</result> | E | 600 | In a weight-lifting competition, the total weight of Joe's two lifts was 1500 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift? | {
"A": "225",
"B": "275",
"C": "325",
"D": "350",
"E": "600"
} | divide(add(1500, 300), const_3) | add(n0,n1)|divide(#0,const_3)| | "this problem is a general word translation . we first define variables and then set up equations . we can define the following variables : f = the weight of the first lift s = the weight of the second lift we are given that the total weight of joe ' s two lifts was 1500 pounds . we sum the two variables to obtain : f + s = 1500 we are also given that twice the weight of his first lift was 300 pounds more than the weight of his second lift . we express this as : 2 f = 300 + s 2 f β 300 = s we can now plug in ( 2 f β 300 ) for s into the first equation , so we have : f + 2 f β 300 = 1500 3 f = 1,800 f = 600 answer is e ." | general |
math_qa__UGedGuGY6zX8y1bK | The cash realised on selling a 14% stock is Rs.109.25, brokerage being 1/4% is Select the correct option
A) 123 B) 109 C) 100 D) 156 E) 240 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">109.25 - (1/4)</gadget>
<output>109</output>
<result>B</result> | B | 109 | The cash realised on selling a 14% stock is Rs.109.25, brokerage being 1/4% is | {
"A": "123",
"B": "109",
"C": "100",
"D": "156",
"E": "240"
} | subtract(109.25, divide(1, 4)) | divide(n2,n3)|subtract(n1,#0)| | "explanation : cash realised = rs . ( 109.25 - 0.25 ) = rs . 109 . answer : b" | general |
math_qa__DNePgkLcaDj24fa4 | If 47.5% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class? Choose the correct choice from the following options.
A) 110
B) 330
C) 550
D) 462
E) 880 | <gadget id="calculator">880 / 100</gadget>
<output>44/5 = around 8.8</output>
<gadget id="calculator">100 - 47.5</gadget>
<output>52.5</output>
<gadget id="calculator">(44/5) * 52.5</gadget>
<output>462</output>
<result>D</result> | D | 462 | If 47.5% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class? | {
"A": "110",
"B": "330",
"C": "550",
"D": "462",
"E": "880"
} | multiply(divide(880, const_100), subtract(const_100, 47.5)) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)| | "students enrolled in biology are 47.5 % and therefore not enrolled are 52.5 % . so of 880 is 880 * . 525 = 462 answer is d 462" | other |
math_qa__jsx70eXML24yvwiv | Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30Β° and 45Β° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Choose the most appropriate option
A) 173 m B) 200 m C) 273 m D) 300 m E) 373 m | <gadget id="calculator">3 ** (1/2)</gadget>
<output>sqrt(3) = around 1.732051</output>
<gadget id="calculator">(sqrt(3)) + 1</gadget>
<output>1 + sqrt(3) = around 2.732051</output>
<gadget id="calculator">(1 + sqrt(3)) * 100</gadget>
<output>100 + 100*sqrt(3) = around 273.205081</output>
<result>C</result> | C | 273 | Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30Β° and 45Β° respectively. If the lighthouse is 100 m high, the distance between the two ships is: | {
"A": "173 m",
"B": "200 m",
"C": "273 m",
"D": "300 m",
"E": "373 m"
} | multiply(add(sqrt(const_3), const_1), 100) | sqrt(const_3)|add(#0,const_1)|multiply(n2,#1) | let ab be the lighthouse and c and d be the positions of the ships . then , ab = 100 m , acb = 30 Β° and adb = 45 Β° . ab = tan 30 Β° = 1 ac = ab x 3 = 1003 m . ac 3 ab = tan 45 Β° = 1 ad = ab = 100 m . ad cd = ( ac + ad ) = ( 1003 + 100 ) m = 100 ( 3 + 1 ) = ( 100 x 2.73 ) m = 273 m . answer = c | physics |
math_qa__9b7zvgKBd6aE9cOk | A tank can supply water to a village for 80 days. If a leak at the bottom of the tank drains out 10 liters per day, the supply lasts for 60 days only. For how many days will the supply last if the leak drains out 20 liters per day? Choose the correct choice from the following choices:
A) 42 B) 45 C) 48 D) 50 E) 55 | <gadget id="calculator">10 * 60</gadget>
<output>600</output>
<gadget id="calculator">80 - 60</gadget>
<output>20</output>
<gadget id="calculator">600 / 20</gadget>
<output>30</output>
<gadget id="calculator">30 * 80</gadget>
<output>2_400</output>
<gadget id="calculator">20 + 30</gadget>
<output>50</output>
<gadget id="calculator">2_400 / 50</gadget>
<output>48</output>
<result>C</result> | C | 48 | A tank can supply water to a village for 80 days. If a leak at the bottom of the tank drains out 10 liters per day, the supply lasts for 60 days only. For how many days will the supply last if the leak drains out 20 liters per day? | {
"A": "42",
"B": "45",
"C": "48",
"D": "50",
"E": "55"
} | divide(multiply(divide(multiply(10, 60), subtract(80, 60)), 80), add(20, divide(multiply(10, 60), subtract(80, 60)))) | multiply(n1,n2)|subtract(n0,n2)|divide(#0,#1)|add(n3,#2)|multiply(n0,#2)|divide(#4,#3)| | "losing 10 liters per day results in a loss of 600 liters in 60 days . so , those 600 liters were for 20 days , making daily consumption of the village 30 liters per day . thus the capacity of the tank is 30 * 80 = 2400 liters . losing 20 liters plus 30 liters gives 50 liters per day . at this rate the supply will last 2400 / 50 = 48 days . the answer is c ." | physics |
math_qa__8qKlRMQMV9otI64F | a' and 'b' are positive integers such that their LCM is 20 and their HCF is 1. What is the difference between the maximum and minimum possible values of 'a - b'? Options.
A) 28 B) 29 C) 34 D) 38 E) 36 | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">40 - 2</gadget>
<output>38</output>
<result>D</result> | D | 38 | a' and 'b' are positive integers such that their LCM is 20 and their HCF is 1. What is the difference between the maximum and minimum possible values of 'a - b'? | {
"A": "28",
"B": "29",
"C": "34",
"D": "38",
"E": "36"
} | subtract(add(20, 20), add(1, 1)) | add(n0,n0)|add(n1,n1)|subtract(#0,#1) | possible values of a and b can be 54 ; 45 and 120 ; 201 maximum possible value for a - b is 20 - 1 = 19 minimum possible value for a - b is 1 - 20 = - 19 19 - ( - 19 ) = 38 ans is d | general |
math_qa__itq4BTIw1PTFA6Jb | The size of a television screen is given as the length of the screen's diagonal. If the screens were flat, then the area of a square 18-inch screen would be how many square inches greater than the area of a square 16-inch screen? Choose the correct choice from the following answers:
A) 2 B) 4 C) 34 D) 38 E) 40 | <gadget id="calculator">18 ** 2</gadget>
<output>324</output>
<gadget id="calculator">16 ** 2</gadget>
<output>256</output>
<gadget id="calculator">324 - 256</gadget>
<output>68</output>
<gadget id="calculator">68 / 2</gadget>
<output>34</output>
<result>C</result> | C | 34 | The size of a television screen is given as the length of the screen's diagonal. If the screens were flat, then the area of a square 18-inch screen would be how many square inches greater than the area of a square 16-inch screen? | {
"A": "2",
"B": "4",
"C": "34",
"D": "38",
"E": "40"
} | divide(subtract(power(18, const_2), power(16, const_2)), const_2) | power(n0,const_2)|power(n1,const_2)|subtract(#0,#1)|divide(#2,const_2) | pythogoras will help here ! let the sides be x and diagonal be d then d ^ 2 = 2 x ^ 2 and area = x ^ 2 now plug in the given diagonal values to find x values and then subtract the areas ans will be 18 ^ 2 / 2 - 16 ^ 2 / 2 = 68 / 2 = 34 ans c . | geometry |
math_qa__TSvGIMD9q0Cax44t | Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1456? Select:
A) 1000 B) 2217 C) 2889 D) 2777 E) 1300 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 5</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) + 1</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">1_456 / (28/25)</gadget>
<output>1_300</output>
<result>E</result> | E | 1,300 | Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1456? | {
"A": "1000",
"B": "2217",
"C": "2889",
"D": "2777",
"E": "1300"
} | divide(1456, add(divide(multiply(divide(add(multiply(2, 5), 2), 5), 5), const_100), const_1)) | multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)| | "1456 = p [ 1 + ( 5 * 12 / 5 ) / 100 ] p = 1300 answer : e" | general |
math_qa__7vhiATZCzTYCxV6z | What is the 4 digit no. in which the 1st digit is 1/3 of the second, the 3rd is the sum of the 1st and 2nd, and the last is 3 times the second?
Choose the most appropriate option:
A) 1123 B) 1234 C) 1349 D) 1455 E) 1567 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">1_000 + 300</gadget>
<output>1_300</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">1_300 + 49</gadget>
<output>1_349</output>
<result>C</result> | C | 1,349 | What is the 4 digit no. in which the 1st digit is 1/3 of the second, the 3rd is the sum of the 1st and 2nd, and the last is 3 times the second? | {
"A": "1123",
"B": "1234",
"C": "1349",
"D": "1455",
"E": "1567"
} | add(add(multiply(const_100, const_10), multiply(const_3, const_100)), multiply(add(4, 3), add(4, 3))) | add(n0,n3)|multiply(const_10,const_100)|multiply(const_100,const_3)|add(#1,#2)|multiply(#0,#0)|add(#3,#4) | first digit is 1 / 3 second digit = > the numbers can be 1 & 3 , 2 & 6 , 3 & 9 . first + second = third = > we can eliminate 3 & 9 since 3 + 9 = 12 . last is 3 times the second = > we can eliminate option 2 & 6 since 3 * 6 = 18 . hence the number is 1349 c | general |
math_qa__c6tDzb43pyG9HhGv | What number is 76 more than one-fourth of itself?
Answers
A) 101 B) 225 C) 304 D) 324 E) 336 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">76 / (3/4)</gadget>
<output>304/3 = around 101.333333</output>
<result>A</result> | A | 101 | What number is 76 more than one-fourth of itself? | {
"A": "101",
"B": "225",
"C": "304",
"D": "324",
"E": "336"
} | divide(76, subtract(const_1, divide(const_1, const_4))) | divide(const_1,const_4)|subtract(const_1,#0)|divide(n0,#1)| | "1 / 4 x + 76 = x that means 76 = 3 / 4 x x = ( 76 * 4 ) / 3 = 304 / 3 = 101 a is the answer" | general |
math_qa__ewz08zV1I5sm9FXt | Someone on a skateboard is traveling 15 miles per hour. How many feet does she travel in 30 seconds? (1 mile = 5280 feet) Choose the correct choice from the following answers
A) 600 ft
B) 660 ft
C) 670 ft
D) 680 ft
E) 700 ft | <gadget id="calculator">15 * 5_280</gadget>
<output>79_200</output>
<gadget id="calculator">79_200 / 3_600</gadget>
<output>22</output>
<gadget id="calculator">30 * 22</gadget>
<output>660</output>
<result>B</result> | B | 660 | Someone on a skateboard is traveling 15 miles per hour. How many feet does she travel in 30 seconds? (1 mile = 5280 feet) | {
"A": "600 ft",
"B": "660 ft",
"C": "670 ft",
"D": "680 ft",
"E": "700 ft"
} | multiply(30, divide(multiply(15, 5280), const_3600)) | multiply(n0,n3)|divide(#0,const_3600)|multiply(n1,#1)| | "per second = > 15 * 5280 ft / 60 * 60 = 22 ft 30 seconds = > 22 * 30 = 660 ft answer : b" | physics |
math_qa__iDLDy7ycSnSAGwh6 | A company produces 72000 bottles of water everyday. If a case can hold 10 bottles of water .How many cases are required by the company to hold its one day production Pick
A) 2000 B) 4500 C) 5000 D) 7200 E) 9000 | <gadget id="calculator">72_000 / 10</gadget>
<output>7_200</output>
<result>D</result> | D | 7,200 | A company produces 72000 bottles of water everyday. If a case can hold 10 bottles of water .How many cases are required by the company to hold its one day production | {
"A": "2000",
"B": "4500",
"C": "5000",
"D": "7200",
"E": "9000"
} | divide(72000, 10) | divide(n0,n1)| | "number of bottles that can be held in a case = 10 number of cases required to hold 72000 bottles = 72000 / 10 = 7200 cases . so the answer is d = 7200" | physics |
math_qa__FaNf5yf5DNBXu8za | A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 3.5 km long? Pick one:
A) 4 B) 3 C) 5 D) 7 E) 9 | <gadget id="calculator">24 + 1</gadget>
<output>25</output>
<gadget id="calculator">25 * 60</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 1_000</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 3.5</gadget>
<output>5</output>
<result>C</result> | C | 5 | A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 3.5 km long? | {
"A": "4",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | add(divide(multiply(add(24, const_1), 60), const_1000), 3.5) | add(n0,const_1)|multiply(n1,#0)|divide(#1,const_1000)|add(n4,#2)| | "d = 25 * 60 + 3500 = 5000 m t = 5000 / 60 * 18 / 5 = 300 sec = 5 mins answer : c" | physics |
math_qa__WZchpRUmbstqQ3Ql | The tax on a commodity is diminished by 20% and its consumption increased by 15%. The effect on revenue is?
Pick: A) 9 % decrease B) 8 % decrease C) 6 % decrease D) 1 % decrease E) 2 % decrease | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(23/20) * (4/5)</gadget>
<output>23/25 = around 0.92</output>
<gadget id="calculator">(23/25) * 100</gadget>
<output>92</output>
<gadget id="calculator">100 - 92</gadget>
<output>8</output>
<result>B</result> | B | 8 | The tax on a commodity is diminished by 20% and its consumption increased by 15%. The effect on revenue is? | {
"A": "9 % decrease",
"B": "8 % decrease",
"C": "6 % decrease",
"D": "1 % decrease",
"E": "2 % decrease"
} | subtract(const_100, multiply(multiply(add(const_1, divide(15, const_100)), subtract(const_1, divide(20, const_100))), const_100)) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)|subtract(const_100,#5)| | "100 * 100 = 10000 80 * 115 = 9200 - - - - - - - - - - - 10000 - - - - - - - - - - - 800 100 - - - - - - - - - - - ? = > 8 % decrease answer : b" | general |
math_qa__tfO5sgHge8rtdiuN | The length of a rectangular floor is more than its breadth by 200%. If Rs.484 is required to paint the floor at the rate of Rs.3/sq m, what would be the length of the floor? Choose the correct choice from the following choices: A) 12 B) 18 C) 20 D) 22 E) 24 | <gadget id="calculator">484 / 3</gadget>
<output>484/3 = around 161.333333</output>
<gadget id="calculator">(484/3) / 3</gadget>
<output>484/9 = around 53.777778</output>
<gadget id="calculator">(484/9) ** (1/2)</gadget>
<output>22/3 = around 7.333333</output>
<gadget id="calculator">(22/3) * 3</gadget>
<output>22</output>
<result>D</result> | D | 22 | The length of a rectangular floor is more than its breadth by 200%. If Rs.484 is required to paint the floor at the rate of Rs.3/sq m, what would be the length of the floor? | {
"A": "12",
"B": "18",
"C": "20",
"D": "22",
"E": "24"
} | multiply(sqrt(divide(divide(484, 3), const_3)), const_3) | divide(n1,n2)|divide(#0,const_3)|sqrt(#1)|multiply(#2,const_3)| | "let the length and the breadth of the floor be l m and b m respectively . l = b + 200 % of b = l + 2 b = 3 b area of the floor = 484 / 3 = 161.33 sq m l b = 161.33 i . e . , l * l / 3 = 161.33 l ^ 2 = 484 = > l = 22 . d" | gain |
math_qa__iRntj7FMaxmwS2XB | A train running at the speed of 50 km/hr crosses a pole in 9 seconds. Find the length of the train?
Choose the correct choice from the following answers: A) 125 B) 272 C) 278 D) 277 E) 112 | <gadget id="calculator">50 * 1_000</gadget>
<output>50_000</output>
<gadget id="calculator">50_000 / 3_600</gadget>
<output>125/9 = around 13.888889</output>
<gadget id="calculator">(125/9) * 9</gadget>
<output>125</output>
<result>A</result> | A | 125 | A train running at the speed of 50 km/hr crosses a pole in 9 seconds. Find the length of the train? | {
"A": "125",
"B": "272",
"C": "278",
"D": "277",
"E": "112"
} | multiply(divide(multiply(50, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 50 * ( 5 / 18 ) m / sec = 125 / 9 m / sec length of train ( distance ) = speed * time ( 125 / 9 ) * 9 = 125 meter answer : a" | physics |
math_qa__NuslhaEzXo5Jkqpl | After decreasing 20% in the price of an article costs Rs.620. Find the actual cost of an article? Pick:
A) 775 B) 620 C) 750 D) 800 E) 720 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">620 / (4/5)</gadget>
<output>775</output>
<result>A</result> | A | 775 | After decreasing 20% in the price of an article costs Rs.620. Find the actual cost of an article? | {
"A": "775",
"B": "620",
"C": "750",
"D": "800",
"E": "720"
} | divide(620, subtract(const_1, divide(20, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1)| | "cp * ( 80 / 100 ) = 620 cp = 7.75 * 100 = > cp = 775 answer : a" | gain |
math_qa__0dWU0ox0Up8JuiuW | 90% of the population of a village is 23040. The total population of the village is ? Choose the correct choice from the following answers:
A) 32256 B) 24000 C) 24936 D) 25600 E) none | <gadget id="calculator">100 / 90</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">(10/9) * 23_040</gadget>
<output>25_600</output>
<result>D</result> | D | 25,600 | 90% of the population of a village is 23040. The total population of the village is ? | {
"A": "32256",
"B": "24000",
"C": "24936",
"D": "25600",
"E": "none"
} | multiply(divide(const_100, 90), 23040) | divide(const_100,n0)|multiply(n1,#0)| | "answer β΅ 90 % of p = 23040 β΄ p = ( 23040 x 100 ) / 90 = 25600 correct option : d" | general |
math_qa__32jsdl8TczblmwzL | A group of men decided to do a work in 15days, but 8 of them became absent. If the rest of the group did the work in 18days, Find the original number of men? Answers.
A) 15 B) 48 C) 54 D) 33 E) 45 | <gadget id="calculator">8 * 18</gadget>
<output>144</output>
<gadget id="calculator">18 - 15</gadget>
<output>3</output>
<gadget id="calculator">144 / 3</gadget>
<output>48</output>
<result>B</result> | B | 48 | A group of men decided to do a work in 15days, but 8 of them became absent. If the rest of the group did the work in 18days, Find the original number of men? | {
"A": "15",
"B": "48",
"C": "54",
"D": "33",
"E": "45"
} | divide(multiply(8, 18), subtract(18, 15)) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "original number of men = 8 * 18 / ( 18 - 15 ) = 48 answer is b" | physics |
math_qa__cllmBBjOS2qkb4ow | A and B can do a piece of work in 2 days, B and C in 3 days, C and A in 4 days. How long will C take to do it? Choose the correct choice
A) 14 days B) 20 days C) 22 days D) 24 days E) 26 days | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 / 4</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">(3/2) + 5</gadget>
<output>13/2 = around 6.5</output>
<gadget id="calculator">(13/2) / 2</gadget>
<output>13/4 = around 3.25</output>
<gadget id="calculator">(13/4) - 3</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">6 / (1/4)</gadget>
<output>24</output>
<result>D</result> | D | 24 | A and B can do a piece of work in 2 days, B and C in 3 days, C and A in 4 days. How long will C take to do it? | {
"A": "14 days",
"B": "20 days",
"C": "22 days",
"D": "24 days",
"E": "26 days"
} | divide(multiply(2, const_3), subtract(divide(add(divide(multiply(2, const_3), 4), add(divide(multiply(2, const_3), 2), divide(multiply(2, const_3), 3))), const_2), divide(multiply(2, const_3), 2))) | multiply(n0,const_3)|divide(#0,n0)|divide(#0,n1)|divide(#0,n2)|add(#1,#2)|add(#4,#3)|divide(#5,const_2)|subtract(#6,#1)|divide(#0,#7)| | "2 c = 1 / 3 + 1 / 4 β 1 / 2 = 1 / 12 c = 1 / 24 = > 24 days answer : d" | physics |
math_qa__NSLiDyczuv6abkUS | A tourist does not have to pay tax on the first $600 of goods he purchases in Country B, but does have to pay a 12 percent tax on the portion of the total value that is in excess of $600. What tax must be paid by a tourist if he buys goods with a total value of $1720? Select
A) $ 54.00 B) $ 64.80 C) $ 90.00 D) $ 100.80 E) $ 134.40 | <gadget id="calculator">1_720 - 600</gadget>
<output>1_120</output>
<gadget id="calculator">1_120 * 12</gadget>
<output>13_440</output>
<gadget id="calculator">13_440 / 100</gadget>
<output>672/5 = around 134.4</output>
<result>E</result> | E | 134.4 | A tourist does not have to pay tax on the first $600 of goods he purchases in Country B, but does have to pay a 12 percent tax on the portion of the total value that is in excess of $600. What tax must be paid by a tourist if he buys goods with a total value of $1720? | {
"A": "$ 54.00",
"B": "$ 64.80",
"C": "$ 90.00",
"D": "$ 100.80",
"E": "$ 134.40"
} | divide(multiply(subtract(1720, 600), 12), const_100) | subtract(n3,n0)|multiply(n1,#0)|divide(#1,const_100)| | "correct answer : e the tourist must pay tax on $ 1720 - $ 600 = $ 1120 . thus , the amount of tax he has to pay is 0.12 ( $ 1120 ) = $ 134.40 . the correct answer is e ." | general |
math_qa__6uRsHjlK6KmbXlv7 | when magnified 1000 times by an electron microscope , the image of a certain circular piece of tissue has a diameter of 0.3 centimeter . the actual diameter of the tissue , in centimeters , is
Choose the correct choice: A) 0.005 B) 0.002 C) 0.001 D) 0.0003 E) 0.0002 | <gadget id="calculator">0.3 / 1_000</gadget>
<output>0.0003</output>
<result>D</result> | D | 0.0003 | when magnified 1000 times by an electron microscope , the image of a certain circular piece of tissue has a diameter of 0.3 centimeter . the actual diameter of the tissue , in centimeters , is | {
"A": "0.005",
"B": "0.002",
"C": "0.001",
"D": "0.0003",
"E": "0.0002"
} | divide(0.3, 1000) | divide(n1,n0) | it is very easy if x is the diameter , then the magnified length is 1000 x . ince 1000 x = 0.3 then x = 0.3 / 1000 = 0.0003 . the answer is d | geometry |
math_qa__tsMlsgceHkNYVNET | A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 9 kilometer long bridge, at the same speed? Choose the most appropriate option: A) 4 min B) 2 min C) 10 min D) 9 min E) 3 min | <gadget id="calculator">9 * 1_000</gadget>
<output>9_000</output>
<gadget id="calculator">600 / 40</gadget>
<output>15</output>
<gadget id="calculator">9_000 / 15</gadget>
<output>600</output>
<gadget id="calculator">600 / 60</gadget>
<output>10</output>
<result>C</result> | C | 10 | A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 9 kilometer long bridge, at the same speed? | {
"A": "4 min",
"B": "2 min",
"C": "10 min",
"D": "9 min",
"E": "3 min"
} | divide(divide(multiply(9, const_1000), speed(600, 40)), const_60) | multiply(n2,const_1000)|speed(n0,n1)|divide(#0,#1)|divide(#2,const_60)| | "s = 600 / 40 = 15 mps s = 9000 / 15 = 600 sec = 10 min . answer : c" | physics |
math_qa__WL7srnwUcoUIiy8X | A car travels at a speed of 65 miles per hour. How far will it travel in 9 hours? Choose one:
A) 125 miles B) 225 miles C) 585 miles D) 425 miles E) 525 miles | <gadget id="calculator">65 * 9</gadget>
<output>585</output>
<result>C</result> | C | 585 | A car travels at a speed of 65 miles per hour. How far will it travel in 9 hours? | {
"A": "125 miles",
"B": "225 miles",
"C": "585 miles",
"D": "425 miles",
"E": "525 miles"
} | multiply(65, 9) | multiply(n0,n1)| | "during each hour , the car travels 65 miles . for 9 hours it will travel 65 + 65 + 65 + 65 + 65 + 65 + 65 + 65 + 65 = 9 Γ 65 = 585 miles correct answer is c ) 585 miles" | physics |
math_qa__iugaInYEEahjE83w | How many of the integers between 45 and 105 are even ? Choose the correct choice from the following answers.
A) 21
B) 30
C) 11
D) 10
E) 9 | <gadget id="calculator">105 - 45</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>B</result> | B | 30 | How many of the integers between 45 and 105 are even ? | {
"A": "21",
"B": "30",
"C": "11",
"D": "10",
"E": "9"
} | divide(subtract(105, 45), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "number start between 45 to 105 is 60 numbers half of them is even . . which is 30 answer : b" | general |
math_qa__JNrMxZIEhwhxnSUQ | Yearly subscription to professional magazines cost a company $940.00. To Make a 50% cut in the magazine budget, how much less must be spent? Choose the most appropriate option.
A) 654 B) 655 C) 656 D) 657 E) 470 | <gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 940</gadget>
<output>470</output>
<result>E</result> | E | 470 | Yearly subscription to professional magazines cost a company $940.00. To Make a 50% cut in the magazine budget, how much less must be spent? | {
"A": "654",
"B": "655",
"C": "656",
"D": "657",
"E": "470"
} | multiply(divide(subtract(const_100, 50), const_100), 940.00) | subtract(const_100,n1)|divide(#0,const_100)|multiply(n0,#1)| | "total cost 940 940 * 50 / 100 = 470 so the cut in amount is 470 the less amount to be spend is 940 - 470 = 470 answer : e" | general |
math_qa__7xYTn21bzBoQg3RZ | Price of a book increases 15% successively (2times) what is the new price of the book more compared to that of the old price:
Choose the correct choice from the following answers.
A) 32.25 % B) 23.34 % C) 36 % D) 39 % E) 29 % | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 / 100</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(23/20) * (23/20)</gadget>
<output>529/400 = around 1.3225</output>
<gadget id="calculator">(529/400) - 1</gadget>
<output>129/400 = around 0.3225</output>
<gadget id="calculator">(129/400) * 100</gadget>
<output>129/4 = around 32.25</output>
<result>A</result> | A | 32.25 | Price of a book increases 15% successively (2times) what is the new price of the book more compared to that of the old price: | {
"A": "32.25 %",
"B": "23.34 %",
"C": "36 %",
"D": "39 %",
"E": "29 %"
} | multiply(subtract(multiply(divide(add(const_100, 15), const_100), divide(add(const_100, 15), const_100)), const_1), const_100) | add(n0,const_100)|divide(#0,const_100)|multiply(#1,#1)|subtract(#2,const_1)|multiply(#3,const_100) | new price is 1.15 * 1.15 * old price = 1.3225 * old price increase in price = 0.3225 * old price % increase = 100 * 0.3225 * old price / old price = 32.25 % answer : a | general |
math_qa__sYzhzHGX3eENbkzB | Andrew purchased 6kg of grapes at the rate of 74 per kg and 9 kg of mangoes at the rate of 59 per kg. How much amount did he pay to the shopkeeper?
Select:
A) 1000 B) 975 C) 980 D) 1020 E) 1080 | <gadget id="calculator">6 * 74</gadget>
<output>444</output>
<gadget id="calculator">9 * 59</gadget>
<output>531</output>
<gadget id="calculator">444 + 531</gadget>
<output>975</output>
<result>B</result> | B | 975 | Andrew purchased 6kg of grapes at the rate of 74 per kg and 9 kg of mangoes at the rate of 59 per kg. How much amount did he pay to the shopkeeper? | {
"A": "1000",
"B": "975",
"C": "980",
"D": "1020",
"E": "1080"
} | add(multiply(6, 74), multiply(9, 59)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1) | cost of 6 kg grapes = 74 Γ 6 = 444 . cost of 9 kg of mangoes = 59 Γ 9 = 531 . total cost he has to pay = 444 + 531 = 975 b | gain |
math_qa__vMkDymHRzB66GkIb | The ratio of the incomes of Uma and Bala is 4:3 and the ratio of their expenditure is 3:2. If at the end of the year, each saves $5000 then the income of Uma is? Choose one
A) $ 24000
B) $ 23000
C) $ 22000
D) $ 21000
E) $ 20000 | <gadget id="calculator">4 * 5_000</gadget>
<output>20_000</output>
<result>E</result> | E | 20,000 | The ratio of the incomes of Uma and Bala is 4:3 and the ratio of their expenditure is 3:2. If at the end of the year, each saves $5000 then the income of Uma is? | {
"A": "$ 24000",
"B": "$ 23000",
"C": "$ 22000",
"D": "$ 21000",
"E": "$ 20000"
} | multiply(4, 5000) | multiply(n0,n4)| | "let the income of uma and bala be $ 4 x and $ 3 x let their expenditures be $ 3 y and $ 2 y 4 x - 3 y = 5000 - - - - - - - 1 ) 3 x - 2 y = 5000 - - - - - - - 2 ) from 1 ) and 2 ) x = 5000 uma ' s income = 4 x = 4 * 5000 = $ 20000 answer is e" | other |
math_qa__UB1d5zBBm47gebS6 | 3/4 of 1/2 of 2/5 of 5040 = ? Pick one:
A) 392
B) 229
C) 756
D) 493
E) 540 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/4) * (1/2)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/8) * (2/5)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 5_040</gadget>
<output>756</output>
<result>C</result> | C | 756 | 3/4 of 1/2 of 2/5 of 5040 = ? | {
"A": "392",
"B": "229",
"C": "756",
"D": "493",
"E": "540"
} | multiply(multiply(multiply(divide(3, 4), divide(1, 2)), divide(2, 5)), 5040) | divide(n3,n5)|divide(n0,n1)|divide(n2,n3)|multiply(#1,#2)|multiply(#0,#3)|multiply(n6,#4) | c 756 ? = 5040 * ( 2 / 5 ) * ( 1 / 2 ) * ( 3 / 4 ) = 756 | general |
math_qa__NYkMCRef7YSvmf3n | There are 17 stations between Hyderabad and Bangalore. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station? Choose the correct choice from the following answers
A) 156 B) 167 C) 157 D) 342 E) 380 | <gadget id="calculator">17 + 1</gadget>
<output>18</output>
<gadget id="calculator">18 + 1</gadget>
<output>19</output>
<gadget id="calculator">18 * 19</gadget>
<output>342</output>
<result>D</result> | D | 342 | There are 17 stations between Hyderabad and Bangalore. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station? | {
"A": "156",
"B": "167",
"C": "157",
"D": "342",
"E": "380"
} | multiply(add(17, const_1), add(add(17, const_1), const_1)) | add(n0,const_1)|add(#0,const_1)|multiply(#0,#1)| | "the total number of stations = 19 from 19 stations we have to choose any two stations and the direction of travel ( i . e . , hyderabad to bangalore is different from bangalore to hyderabad ) in 19 p β ways . Β² β° p β = 19 * 18 = 342 . answer : d" | physics |
math_qa__6vveAxWuktcI0tA3 | There are 18 stations between Ernakulam and Chennai. How many second class tickets have to be printed, so that a passenger can travel from one station to any other station?
Choose the correct choice from the following
A) 800 B) 380 C) 360 D) 478 E) 566 | <gadget id="calculator">18 + 2</gadget>
<output>20</output>
<gadget id="calculator">20 - 1</gadget>
<output>19</output>
<gadget id="calculator">20 * 19</gadget>
<output>380</output>
<result>B</result> | B | 380 | There are 18 stations between Ernakulam and Chennai. How many second class tickets have to be printed, so that a passenger can travel from one station to any other station? | {
"A": "800",
"B": "380",
"C": "360",
"D": "478",
"E": "566"
} | multiply(add(18, const_2), subtract(add(18, const_2), const_1)) | add(n0,const_2)|subtract(#0,const_1)|multiply(#0,#1)| | "the total number of stations = 20 from 20 stations we have to choose any two stations and the direction of travel ( ernakulam to chennai is different from chennai to ernakulam ) in 20 p 2 ways . 20 p 2 = 20 * 19 = 380 answer : b" | physics |
math_qa__iKjFyaFpeJGqlJca | The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly copied. The first is 16 greater than the actual number and the second number added is 13 instead of 31. Find the correct average. Select:
A) 40.2 B) 40.4 C) 40.6 D) 40.8 E) none of the above | <gadget id="calculator">40.2 * 10</gadget>
<output>402</output>
<gadget id="calculator">13 + 16</gadget>
<output>29</output>
<gadget id="calculator">402 + 29</gadget>
<output>431</output>
<gadget id="calculator">431 - 31</gadget>
<output>400</output>
<gadget id="calculator">400 / 10</gadget>
<output>40</output>
<result>B</result> | B | 40.4 | The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly copied. The first is 16 greater than the actual number and the second number added is 13 instead of 31. Find the correct average. | {
"A": "40.2",
"B": "40.4",
"C": "40.6",
"D": "40.8",
"E": "none of the above"
} | divide(subtract(add(multiply(40.2, 10), add(13, 16)), 31), 10) | add(n2,n3)|multiply(n0,n1)|add(#0,#1)|subtract(#2,n4)|divide(#3,n0)| | "sum of 10 numbers = 402 corrected sum of 10 numbers = 402 β 13 + 31 β 16 = 404 hence , new average = 404 β 10 = 40.4 answer b" | general |
math_qa__Z8Fz6U988CcgOVjM | The sale price sarees listed for Rs.175 after successive discount is 20% and 5% is?
Choose the correct choice from the following answers: A) 187 B) 133 C) 142 D) 178 E) 175 | <gadget id="calculator">175 * 20</gadget>
<output>3_500</output>
<gadget id="calculator">3_500 / 100</gadget>
<output>35</output>
<gadget id="calculator">175 - 35</gadget>
<output>140</output>
<gadget id="calculator">140 * 5</gadget>
<output>700</output>
<gadget id="calculator">700 / 100</gadget>
<output>7</output>
<gadget id="calculator">140 - 7</gadget>
<output>133</output>
<result>B</result> | B | 133 | The sale price sarees listed for Rs.175 after successive discount is 20% and 5% is? | {
"A": "187",
"B": "133",
"C": "142",
"D": "178",
"E": "175"
} | subtract(subtract(175, divide(multiply(175, 20), const_100)), divide(multiply(subtract(175, divide(multiply(175, 20), const_100)), 5), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "175 * ( 80 / 100 ) * ( 95 / 100 ) = 133 answer : b" | gain |
math_qa__4FI5DzuVKwpgLHoy | The average salary of all the workers in a workshop is Rs. 9500. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is? Choose the correct option:
A) 23 B) 21 C) 52 D) 56 E) 12 | <gadget id="calculator">12_000 - 9_500</gadget>
<output>2_500</output>
<gadget id="calculator">7 * 2_500</gadget>
<output>17_500</output>
<gadget id="calculator">9_500 - 6_000</gadget>
<output>3_500</output>
<gadget id="calculator">17_500 / 3_500</gadget>
<output>5</output>
<gadget id="calculator">7 + 5</gadget>
<output>12</output>
<result>E</result> | E | 12 | The average salary of all the workers in a workshop is Rs. 9500. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is? | {
"A": "23",
"B": "21",
"C": "52",
"D": "56",
"E": "12"
} | add(7, divide(multiply(7, subtract(12000, 9500)), subtract(9500, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3) | let the total number of workers be x . then , 9500 x = ( 12000 * 7 ) + 6000 ( x - 7 ) = > 3500 x = 42000 = x = 12 . answer : e | general |
math_qa__IZnWh926ILvslYmt | A sum of money lent at compound interest for 2 years at 20% per annum would fetch Rs.482 more, if the interest was payable half yearly than if it was payable annually . The sum is Select.
A) 200000 B) 20000 C) 200029 D) 288778 E) 277789 | <gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 4</gadget>
<output>14_641/10_000 = around 1.4641</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) ** 2</gadget>
<output>36/25 = around 1.44</output>
<gadget id="calculator">(14_641/10_000) - (36/25)</gadget>
<output>241/10_000 = around 0.0241</output>
<gadget id="calculator">482 / (241/10_000)</gadget>
<output>20_000</output>
<result>B</result> | B | 20,000 | A sum of money lent at compound interest for 2 years at 20% per annum would fetch Rs.482 more, if the interest was payable half yearly than if it was payable annually . The sum is | {
"A": "200000",
"B": "20000",
"C": "200029",
"D": "288778",
"E": "277789"
} | divide(482, subtract(power(add(divide(divide(20, const_2), const_100), const_1), const_4), power(add(divide(20, const_100), const_1), const_2))) | divide(n1,const_2)|divide(n1,const_100)|add(#1,const_1)|divide(#0,const_100)|add(#3,const_1)|power(#2,const_2)|power(#4,const_4)|subtract(#6,#5)|divide(n2,#7) | explanation : let sum = rs . x c . i . when compounded half yearly = c . i . when compounded annually = = > x = 20000 answer : b ) 20000 | gain |
math_qa__yDQdiNCm6ybJlsD0 | A monkey start climbing up a tree 20ft tall.Each hour it hops 3 ft and slips back 2ft.How much time would it take the monkey to reach the top. Choices:
A) 15 hrs
B) 18 hrs
C) 19 hrs
D) 17 hrs
E) 16 hrs | <gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">20 / 1</gadget>
<output>20</output>
<gadget id="calculator">20 - 2</gadget>
<output>18</output>
<result>B</result> | B | 18 | A monkey start climbing up a tree 20ft tall.Each hour it hops 3 ft and slips back 2ft.How much time would it take the monkey to reach the top. | {
"A": "15 hrs",
"B": "18 hrs",
"C": "19 hrs",
"D": "17 hrs",
"E": "16 hrs"
} | subtract(divide(20, subtract(3, 2)), 2) | subtract(n1,n2)|divide(n0,#0)|subtract(#1,n2) | if monkey hops 3 ft and slips back 2 ft in a hour , it means the monkey hops ( 3 ft - 2 ft ) = 1 ft / hr . similarly in 17 hrs it wil be 17 ft . bt since the height of the tree is 20 ft , so if the monkey hops up the tree in the next hr i . e 18 th hr then it reaches at the top of the tree . hence it takes 18 hrs for monkey to reach at the top answer : b | physics |
math_qa__ujgHd6IzjwtVZ3ae | 1/0.06 is equal to Choose the correct choice from the following.
A) 25.5 B) 16.7 C) 25 D) . 25 E) none of these | <gadget id="calculator">1 / 0.06</gadget>
<output>16.666667</output>
<result>B</result> | B | 16.7 | 1/0.06 is equal to | {
"A": "25.5",
"B": "16.7",
"C": "25",
"D": ". 25",
"E": "none of these"
} | divide(1, 0.06) | divide(n0,n1)| | "explanation : 1 / 0.06 = ( 1 * 100 ) / 6 = 100 / 6 = 16.7 option b" | general |
math_qa__D30MSwVBJ3BdKwSu | Rs 3600 is divided into two parts such that one part is put out at 3% and the other at 5%. If the annual interest earned from both the investments be Rs 144, find the first part. Pick
A) s 4000 B) s 2800 C) s 1800 D) s 3500 E) s 3100 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">3_600 * (1/20)</gadget>
<output>180</output>
<gadget id="calculator">180 - 144</gadget>
<output>36</output>
<gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">(1/20) - (3/100)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">36 / (1/50)</gadget>
<output>1_800</output>
<result>C</result> | C | 1,800 | Rs 3600 is divided into two parts such that one part is put out at 3% and the other at 5%. If the annual interest earned from both the investments be Rs 144, find the first part. | {
"A": "s 4000",
"B": "s 2800",
"C": "s 1800",
"D": "s 3500",
"E": "s 3100"
} | divide(subtract(multiply(3600, divide(5, const_100)), 144), subtract(divide(5, const_100), divide(3, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n3)|divide(#4,#3)| | "explanation : average rate = ( 144 / 3600 ) * 100 = 4 ratio = 1 : 1 so , first part = ( 1 / 2 ) * 3600 = rs 1800 . answer : c" | gain |
math_qa__k7giHWdRmJY4HuH8 | Without stoppages, a train travels certain distance with an average speed of 200 km/h, and with stoppages, it covers the same distance with an average speed of 160 km/h. How many minutes per hour the train stops ? Select the correct option
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">160 / 200</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 60</gadget>
<output>48</output>
<gadget id="calculator">60 - 48</gadget>
<output>12</output>
<result>E</result> | E | 12 | Without stoppages, a train travels certain distance with an average speed of 200 km/h, and with stoppages, it covers the same distance with an average speed of 160 km/h. How many minutes per hour the train stops ? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | subtract(const_60, multiply(divide(160, 200), const_60)) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "due to stoppages , it covers 40 km less . time taken to cover 40 km = 40 Γ’ Β β 200 h = 1 Γ’ Β β 5 h = 1 Γ’ Β β 5 Γ£ β 60 min = 12 min answer e" | physics |
math_qa__P6SNXNCib2tMFHT9 | In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 56 liters and they are all empty, how much money total will it cost to fuel all cars? Choices.
A) 320.8 $ B) 387.8 $ C) 420.8 $ D) 457.8 $ E) 480.8 $ | <gadget id="calculator">0.65 * 56</gadget>
<output>36.4</output>
<gadget id="calculator">36.4 * 12</gadget>
<output>436.8</output>
<result>D</result> | D | 457.8 | In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 56 liters and they are all empty, how much money total will it cost to fuel all cars? | {
"A": "320.8 $",
"B": "387.8 $",
"C": "420.8 $",
"D": "457.8 $",
"E": "480.8 $"
} | multiply(multiply(0.65, 56), 12) | multiply(n1,n3)|multiply(n2,#0)| | "total cost = ( 1.75 * 12 ) + ( 0.65 * 12 * 56 ) = 457.8 hence answer will be ( d )" | general |
math_qa__x0MbSk0vxpQLMXDN | A sum fetched a total simple interest of Rs. 2700 at the rate of 6 p.c.p.a. in 3 years. What is the sum? Choose the correct answer
A) 25000 B) 20000 C) 18000 D) 14000 E) 15000 | <gadget id="calculator">2_700 * 100</gadget>
<output>270_000</output>
<gadget id="calculator">270_000 / 6</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 3</gadget>
<output>15_000</output>
<result>E</result> | E | 15,000 | A sum fetched a total simple interest of Rs. 2700 at the rate of 6 p.c.p.a. in 3 years. What is the sum? | {
"A": "25000",
"B": "20000",
"C": "18000",
"D": "14000",
"E": "15000"
} | divide(divide(multiply(2700, const_100), 6), 3) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "sol . principal = rs . [ 100 * 2700 / 6 * 3 ] = rs . [ 270000 / 18 ] = rs . 15000 . answer e" | gain |
math_qa__lsY1yw7QPBhdZ7BY | If 20 men can build a water fountain 56 metres long in 21 days, what length of a similar water fountain can be built by 35 men in 3 days? Select the correct option:
A) 10 m B) 14 m C) 17 m D) 19 m E) 20 m | <gadget id="calculator">20 * 21</gadget>
<output>420</output>
<gadget id="calculator">56 / 420</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">35 * 3</gadget>
<output>105</output>
<gadget id="calculator">(2/15) * 105</gadget>
<output>14</output>
<result>B</result> | B | 14 | If 20 men can build a water fountain 56 metres long in 21 days, what length of a similar water fountain can be built by 35 men in 3 days? | {
"A": "10 m",
"B": "14 m",
"C": "17 m",
"D": "19 m",
"E": "20 m"
} | multiply(divide(56, multiply(20, 21)), multiply(35, 3)) | multiply(n0,n2)|multiply(n3,n4)|divide(n1,#0)|multiply(#2,#1)| | "explanation : let the required length be x metres more men , more length built ( direct proportion ) less days , less length built ( direct proportion ) men 20 : 35 days 21 : 3 : : 56 : x therefore ( 20 x 21 x x ) = ( 35 x 3 x 56 ) x = ( 35 x 3 x 56 ) / 420 = 14 hence , the required length is 14 m . answer : b" | physics |
math_qa__8fOW2Hdwx9L6AqIP | A circular garden is surrounded by a fence of negligible width along the boundary. If the length of the fence is 1/5 of th area of the garden. What is the radius of the circular garden? Choose the correct choice from the following options.
A) 1
B) 2
C) 10
D) 8
E) 16 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<result>C</result> | C | 10 | A circular garden is surrounded by a fence of negligible width along the boundary. If the length of the fence is 1/5 of th area of the garden. What is the radius of the circular garden? | {
"A": "1",
"B": "2",
"C": "10",
"D": "8",
"E": "16"
} | multiply(const_2, sqrt(power(5, const_2))) | power(n1,const_2)|sqrt(#0)|multiply(#1,const_2)| | "as per the question - - width is negligible now , let l be the length of the fence = 2 pir l = 1 / 5 ( pir ^ 2 ) pir ^ 2 = 10 pir r = 10 answer : c" | geometry |
math_qa__QqFA0zQKJM8IPD2J | The average of 1st 3 of 4 numbers is 6 and of the last 3 are 3. If the sum of the first and the last number is 13. What is the last numbers? Choose the correct choice from the following answers:
A) 4 B) 2 C) 6 D) 7 E) 8 | <gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">13 - 6</gadget>
<output>7</output>
<gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">18 - 10</gadget>
<output>8</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<result>B</result> | B | 2 | The average of 1st 3 of 4 numbers is 6 and of the last 3 are 3. If the sum of the first and the last number is 13. What is the last numbers? | {
"A": "4",
"B": "2",
"C": "6",
"D": "7",
"E": "8"
} | subtract(subtract(multiply(3, 6), add(subtract(13, 6), 3)), 6) | multiply(n1,n3)|subtract(n6,n3)|add(n1,#1)|subtract(#0,#2)|subtract(#3,n3) | a + b + c = 18 b + c + d = 9 a + d = 13 a β d = 9 a + d = 13 2 d = 4 d = 2 answer : b | general |
math_qa__s1uYOHOX8IWCrbYa | a classroom has equal number of boys and girls . 8 girls left to play kho - kho , leaving twice as many boys as girls in the classroom . what was the total number of girls and boys present initially ? Choices
A) 16 B) 24 C) 32 D) 48 E) 54 | <gadget id="calculator">2 * 8</gadget>
<output>16</output>
<gadget id="calculator">16 * 2</gadget>
<output>32</output>
<result>C</result> | C | 32 | a classroom has equal number of boys and girls . 8 girls left to play kho - kho , leaving twice as many boys as girls in the classroom . what was the total number of girls and boys present initially ? | {
"A": "16",
"B": "24",
"C": "32",
"D": "48",
"E": "54"
} | multiply(multiply(const_2, 8), const_2) | multiply(n0,const_2)|multiply(#0,const_2) | after 8 girls left remaining 8 girls now boys 16 are twice as many as remaining girls . initially boys = 16 and girls = 16 . answer : c | general |
math_qa__L3UGb353gPtDrrhq | The speed of a boat in still water is 50kmph and the speed of the current is 20kmph. Find the speed and upstream?
Select the correct option.
A) 30 kmph B) 40 kmph C) 78 kmph D) 15 kmph E) 23 kmph | <gadget id="calculator">50 - 20</gadget>
<output>30</output>
<result>A</result> | A | 30 | The speed of a boat in still water is 50kmph and the speed of the current is 20kmph. Find the speed and upstream? | {
"A": "30 kmph",
"B": "40 kmph",
"C": "78 kmph",
"D": "15 kmph",
"E": "23 kmph"
} | subtract(50, 20) | subtract(n0,n1) | speed downstream = 50 + 20 = 70 kmph speed upstream = 50 - 20 = 30 kmph answer : a | physics |
math_qa__gtQF6fUHwbleqLdx | If 5x = 6y and xy β 0, what is the ratio of 1/5*x to 1/8*y ? Choose the correct choice from the following answers
A) 48 / 25 B) 36 / 25 C) 6 / 5 D) 5 / 6 E) 25 / 36 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/3) / (1/5)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">6 / 5</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(5/3) * (6/5)</gadget>
<output>2</output>
<result>A</result> | A | 1.92 | If 5x = 6y and xy β 0, what is the ratio of 1/5*x to 1/8*y ? | {
"A": "48 / 25",
"B": "36 / 25",
"C": "6 / 5",
"D": "5 / 6",
"E": "25 / 36"
} | multiply(divide(divide(1, const_3.0), divide(1, 5)), divide(6, 5)) | divide(n3,const_3.0)|divide(n3,n0)|divide(n1,n0)|divide(#0,#1)|multiply(#3,#2)| | "5 x = 6 y = > x / y = 6 / 5 1 / 5 * x to 1 / 8 * y = x / y * 8 / 5 = ( 6 / 5 ) * ( 8 / 5 ) = 48 / 25 ans : a" | general |
math_qa__2N6L7m97AeH7tKyk | When a number is divided by 6 &then multiply by 12 the answer is 10 what is the no.? Pick
A) 4.5 B) 5 C) 5.6 D) 5.7 E) 6.5 | <gadget id="calculator">10 / 12</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(5/6) * 6</gadget>
<output>5</output>
<result>B</result> | B | 5 | When a number is divided by 6 &then multiply by 12 the answer is 10 what is the no.? | {
"A": "4.5",
"B": "5",
"C": "5.6",
"D": "5.7",
"E": "6.5"
} | multiply(divide(10, 12), 6) | divide(n2,n1)|multiply(n0,#0)| | "if $ x $ is the number , x / 6 * 12 = 10 = > 2 x = 10 = > x = 5 b" | general |
math_qa__i8Dbawid2ASNnAmy | A and B start from house at 10am. They travel on the MG road at 20kmph and 40 kmph. there is a Junction T on their path. A turns left at T junction at 12:00 noon, B reaches T earlier, and turns right. Both of them continue to travel till 2pm. What is the distance between A and B at 2 pm Select.
A) 160 km B) 170 km C) 180 km D) 190 km E) 150 km | <gadget id="calculator">12 - 10</gadget>
<output>2</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">40 * 3</gadget>
<output>120</output>
<gadget id="calculator">40 + 120</gadget>
<output>160</output>
<result>A</result> | A | 160 | A and B start from house at 10am. They travel on the MG road at 20kmph and 40 kmph. there is a Junction T on their path. A turns left at T junction at 12:00 noon, B reaches T earlier, and turns right. Both of them continue to travel till 2pm. What is the distance between A and B at 2 pm | {
"A": "160 km",
"B": "170 km",
"C": "180 km",
"D": "190 km",
"E": "150 km"
} | add(multiply(20, subtract(12, 10)), multiply(40, const_3)) | multiply(n2,const_3)|subtract(n3,n0)|multiply(n1,#1)|add(#2,#0) | at 12 a will travel = 20 * 2 = 40 km b will travel this 40 km in 40 / 40 = 1 hr i . e . by 11 am . after t junction for a - distance travelled = 2 * 20 = 40 km for b distance travelled = 40 * 3 = 120 so distance between a & b is = 120 + 40 = 160 km answer : a | physics |
math_qa__UlCIjB4sTLxzrs6I | The circulation for magazine P in 1971 was 4 times the average (arithmetic mean) yearly circulation for magazine P for the years 1972-1980. What is the ratio of the circulation in 1971 to the total circulation during 1971-1980 for magazine P ? Choose the correct choice from the following
A) 4 / 7 B) 5 / 7 C) 3 / 7 D) 2 / 7 E) 1 / 7 | <gadget id="calculator">1_980 - 1_972</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">9 + 4</gadget>
<output>13</output>
<gadget id="calculator">13 + 1</gadget>
<output>14</output>
<gadget id="calculator">4 / 14</gadget>
<output>2/7 = around 0.285714</output>
<result>D</result> | D | 0.285714 | The circulation for magazine P in 1971 was 4 times the average (arithmetic mean) yearly circulation for magazine P for the years 1972-1980. What is the ratio of the circulation in 1971 to the total circulation during 1971-1980 for magazine P ? | {
"A": "4 / 7",
"B": "5 / 7",
"C": "3 / 7",
"D": "2 / 7",
"E": "1 / 7"
} | divide(4, add(add(add(subtract(1980, 1972), const_1), 4), const_1)) | subtract(n3,n2)|add(#0,const_1)|add(n1,#1)|add(#2,const_1)|divide(n1,#3) | there are 9 years from 1972 - 1980 , inclusive . let ' s say the average circulation every year between 1972 - 1980 inclusive is x . so the total circulation is 9 x from 1972 - 1980 , inclusive . in 1971 , the circulation is 4 x . so total circulation for 1971 - 1980 is 4 x + 9 x = 13 x . ratio of circulation in 1971 to total circulation during 1971 - 1980 is 4 x to 14 x or 4 / 14 = 2 / 7 answer : d | general |
math_qa__0NyJb2qKiugCHcHp | The regular price per can of a certain brand of soda is $0.30. If the regular price per can is discounted 15 percent when the soda is purchased in 24-can cases, what is the price of 72 cans of this brand of soda purchased in 24-can cases? Choose the correct choice from the following: A) $ 16.32 B) $ 18.36 C) $ 21.60 D) $ 24.48 E) $ 28.80 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">0.3 * 72</gadget>
<output>21.6</output>
<gadget id="calculator">(17/20) * 21.6</gadget>
<output>18.36</output>
<result>B</result> | B | 18.36 | The regular price per can of a certain brand of soda is $0.30. If the regular price per can is discounted 15 percent when the soda is purchased in 24-can cases, what is the price of 72 cans of this brand of soda purchased in 24-can cases? | {
"A": "$ 16.32",
"B": "$ 18.36",
"C": "$ 21.60",
"D": "$ 24.48",
"E": "$ 28.80"
} | multiply(divide(subtract(const_100, 15), const_100), multiply(0.30, 72)) | multiply(n0,n3)|subtract(const_100,n1)|divide(#1,const_100)|multiply(#2,#0)| | "the discounted price of one can of soda is ( 0.85 ) ( $ 0.30 ) , or $ 0.255 . therefore , the price of 72 cans of soda at the discounted price would be ( 72 ) ( $ 0.255 ) = 18.36 answer : b ." | gain |
math_qa__1qXdb0CFAq4TVlc1 | A bag contains 12 red marbles. If someone were to remove 2 marbles from the bag, one at a time, and replace the first marble after it was removed, the probability that neither marble would be red is 9/16. How many marbles are in the bag? Pick one:
A) 48
B) 24
C) 60
D) 72
E) 84 | <gadget id="calculator">9 / 16</gadget>
<output>9/16 = around 0.5625</output>
<gadget id="calculator">(9/16) ** (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">12 / (1/4)</gadget>
<output>48</output>
<result>A</result> | A | 48 | A bag contains 12 red marbles. If someone were to remove 2 marbles from the bag, one at a time, and replace the first marble after it was removed, the probability that neither marble would be red is 9/16. How many marbles are in the bag? | {
"A": "48",
"B": "24",
"C": "60",
"D": "72",
"E": "84"
} | divide(12, subtract(const_1, sqrt(divide(9, 16)))) | divide(n2,n3)|sqrt(#0)|subtract(const_1,#1)|divide(n0,#2)| | "ok let me see if i can explain what went on in the previous post lets say i have x marbles in the bag in total - - > out of them 12 are red so the probability of pulling a non - red marble is ( x - 12 ) / x now the marble is placed back in the bag and we have x marbles again , of which again 12 are red . so the probability of pulling a non - red marble out is ( x - 12 ) / x probability theorm states that if the probability of event a occuring is m and the probability of event b occuring is n then the probability of both a and b occuring is m * n so therefore the probability of 2 non - red marbles getting pulled out is [ ( x - 12 ) / x ] * [ ( x - 12 ) / x ] this is given as 9 / 16 - - > ( x - 12 ) ^ 2 = 16 / 25 x ^ 2 a square rooting u have x - 12 / x = 3 / 4 or 4 x - 48 = 3 x or x = 48" | other |
math_qa__4To4Ao0uD2ELVKUg | The average marks of a class of 26 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students? Choose the most appropriate option.
A) 52.2 B) 59.5 C) 52.8 D) 52.5 E) 53.1 | <gadget id="calculator">26 * 40</gadget>
<output>1_040</output>
<gadget id="calculator">50 * 60</gadget>
<output>3_000</output>
<gadget id="calculator">1_040 + 3_000</gadget>
<output>4_040</output>
<gadget id="calculator">26 + 50</gadget>
<output>76</output>
<gadget id="calculator">4_040 / 76</gadget>
<output>1_010/19 = around 53.157895</output>
<result>E</result> | E | 53.1 | The average marks of a class of 26 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students? | {
"A": "52.2",
"B": "59.5",
"C": "52.8",
"D": "52.5",
"E": "53.1"
} | divide(add(multiply(26, 40), multiply(50, 60)), add(26, 50)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0) | sum of the marks for the class of 26 students = 26 * 40 = 1040 sum of the marks for the class of 50 students = 50 * 60 = 3000 sum of the marks for the class of 76 students = 1040 + 3000 = 4040 average marks of all the students = 4040 / 76 = 53.15 answer : e | general |
math_qa__VIZR9OVLeROre26a | Pipe A can fill a tank in 8 hours. Due to a leak at the bottom, it takes 12 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank? Pick one.
A) 5 B) 24 C) 78 D) 90 E) 54 | <gadget id="calculator">12 * 8</gadget>
<output>96</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">96 / 4</gadget>
<output>24</output>
<result>B</result> | B | 24 | Pipe A can fill a tank in 8 hours. Due to a leak at the bottom, it takes 12 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank? | {
"A": "5",
"B": "24",
"C": "78",
"D": "90",
"E": "54"
} | divide(multiply(12, 8), subtract(12, 8)) | multiply(n0,n1)|subtract(n1,n0)|divide(#0,#1)| | "let the leak can empty the full tank in x hours 1 / 8 - 1 / x = 1 / 12 = > 1 / x = 1 / 8 - 1 / 12 = ( 3 - 2 ) / 24 = 1 / 24 = > x = 24 . answer : b" | physics |
math_qa__CtjCrLsvRUUzI8P9 | An escalator is descending at constant speed. A walks down and takes 50 steps to reach the bottom. B runs down and takes 90 steps in the same time as A takes 10 steps. How many steps are visible when the escalator is not operating? Options:
A) 80
B) 90
C) 100
D) 110
E) 120 | <gadget id="calculator">90 - 50</gadget>
<output>40</output>
<gadget id="calculator">40 / 40</gadget>
<output>1</output>
<gadget id="calculator">50 * 1</gadget>
<output>50</output>
<gadget id="calculator">50 + 50</gadget>
<output>100</output>
<result>C</result> | C | 100 | An escalator is descending at constant speed. A walks down and takes 50 steps to reach the bottom. B runs down and takes 90 steps in the same time as A takes 10 steps. How many steps are visible when the escalator is not operating? | {
"A": "80",
"B": "90",
"C": "100",
"D": "110",
"E": "120"
} | add(50, multiply(50, divide(subtract(90, 50), subtract(90, 50)))) | subtract(n1,n0)|divide(#0,#0)|multiply(n0,#1)|add(n0,#2) | lets suppose that a walks down 1 step / min and escalator moves n steps / min it is given that a takes 50 steps to reach the bottom in the same time escalator would have covered 50 n steps so total steps on escalator is 50 + 50 n . again it is given that b takes 90 steps to reach the bottom and time taken by him for this is equal to time taken by a to cover 10 steps i . e 10 minutes . so in this 10 min escalator would have covered 10 n steps . so total steps on escalatro is 90 + 10 n again equating 50 + 50 n = 90 + 10 n we get n = 1 hence total no . of steps on escalator is 100 . answer : c | physics |
math_qa__Xu2t7ptu8eCbqvy8 | How many Kg of sugar must be added to 30 Kg of 2% solution of sugar and water to increase it to a 10% solution? Answers.
A) 2.6 kg B) 4 kg C) 3.4 kg D) 1.8 kg E) none of these | <gadget id="calculator">30 * 10</gadget>
<output>300</output>
<gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 30</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<gadget id="calculator">300 - 60</gadget>
<output>240</output>
<gadget id="calculator">30 * 3</gadget>
<output>90</output>
<gadget id="calculator">240 / 90</gadget>
<output>8/3 = around 2.666667</output>
<result>A</result> | A | 2.6 | How many Kg of sugar must be added to 30 Kg of 2% solution of sugar and water to increase it to a 10% solution? | {
"A": "2.6 kg",
"B": "4 kg",
"C": "3.4 kg",
"D": "1.8 kg",
"E": "none of these"
} | divide(subtract(multiply(30, 10), multiply(multiply(divide(2, const_100), 30), const_100)), multiply(30, const_3)) | divide(n1,const_100)|multiply(n0,n2)|multiply(n0,const_3)|multiply(n0,#0)|multiply(#3,const_100)|subtract(#1,#4)|divide(#5,#2) | explanation : solution : amount of sugar in 30 kg solution = ( 2 / 100 * 30 ) kg = 0.6 kg . let x kg of sugar be added . then , ( 0.6 + x ) / ( 30 + x ) = 10 / 100 60 + 100 x = 300 + 10 x x = 240 / 90 = 8 / 3 = 2.6 answer : a | general |
math_qa__MNGj8mq3tFBjM73K | Each of the integers from 1 to 18 is written on the a seperate index card and placed in a box. If the cards are drawn from the box at random without replecement, how many cards must be drawn to ENSURE that the product of all the integers drawn is even
Answers:
A) 19 B) 12 C) 11 D) 10 E) 3 | <gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<result>D</result> | D | 10 | Each of the integers from 1 to 18 is written on the a seperate index card and placed in a box. If the cards are drawn from the box at random without replecement, how many cards must be drawn to ENSURE that the product of all the integers drawn is even | {
"A": "19",
"B": "12",
"C": "11",
"D": "10",
"E": "3"
} | add(divide(18, const_2), 1) | divide(n1,const_2)|add(n0,#0) | out of the 18 integers : 9 are odd and 9 are even . if we need to make sure that the product of all the integers withdrawn is even then we need to make sure that we have at least one even number . in the worst case : 1 . we will end up picking odd numbers one by one , so we will pick all 9 odd numbers first 2 . 10 th number will be the first even number so we need to withdraw at least 10 numbers to make sure that we get one even number and the product of all the integers picked is even . so , answer will be 10 . ( d ) | general |
math_qa__rSpQ1F0j7a4ojp9w | Suppose f(x) is an odd function for which f(x + 2) = f(x) for all x, and
f(x) = x2 for x 2 (0, 1). Compute f(-3/2) + f(1).
Select: A) - 1 B) - 1 / 2 C) - 1 / 4 D) 1 / 4 E) 1 / 2 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<result>D</result> | D | 0.25 | Suppose f(x) is an odd function for which f(x + 2) = f(x) for all x, and
f(x) = x2 for x 2 (0, 1). Compute f(-3/2) + f(1). | {
"A": "- 1",
"B": "- 1 / 2",
"C": "- 1 / 4",
"D": "1 / 4",
"E": "1 / 2"
} | divide(1, add(2, 2)) | add(n0,n0)|divide(n4,#0) | because f is periodic , we know that f ( - 3 / 2 ) = f ( 1 / 2 ) = ( 1 / 2 ) 2 = 1 = 4 . because f is odd , we know that f ( 1 ) = - f ( / 1 ) , but because f is periodic , f ( 1 ) = f ( - 1 ) . therefore , f ( 1 ) = 0 and the answer is 1 = 4 . correct answer d | general |
math_qa__OKNmqPttP4RfOVSs | A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 1980 in all from both of them as interest. The rate of interest per annum is? Choose the correct choice from the following:
A) 16 %
B) 12 %
C) 9 %
D) 10 %
E) 45 % | <gadget id="calculator">5_000 * 2</gadget>
<output>10_000</output>
<gadget id="calculator">3_000 * 4</gadget>
<output>12_000</output>
<gadget id="calculator">10_000 + 12_000</gadget>
<output>22_000</output>
<gadget id="calculator">1_980 / 22_000</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">(9/100) * 100</gadget>
<output>9</output>
<result>C</result> | C | 9 | A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 1980 in all from both of them as interest. The rate of interest per annum is? | {
"A": "16 %",
"B": "12 %",
"C": "9 %",
"D": "10 %",
"E": "45 %"
} | multiply(divide(1980, add(multiply(5000, 2), multiply(3000, 4))), const_100) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)|divide(n4,#2)|multiply(#3,const_100)| | "let the rate be r % p . a . then , ( 5000 * r * 2 ) / 100 + ( 3000 * r * 4 ) / 100 = 1980 100 r + 120 r = 1980 r = 9 % answer : c" | gain |
math_qa__dawy5XKqXHdajGP4 | In what time will a railway train 60 m long moving at the rate of 72 kmph pass a telegraph post on its way? Select:
A) 8 sec B) 3 sec C) 2 sec D) 6 sec E) 9 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">60 / 20</gadget>
<output>3</output>
<result>B</result> | B | 3 | In what time will a railway train 60 m long moving at the rate of 72 kmph pass a telegraph post on its way? | {
"A": "8 sec",
"B": "3 sec",
"C": "2 sec",
"D": "6 sec",
"E": "9 sec"
} | divide(60, multiply(72, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 60 / 72 * 18 / 5 = 3 sec answer : b" | physics |
math_qa__0iky89w6vo3TcACL | X starts a business with Rs.45000. Y joins in the business after 3 months with Rs.36000. What will be the ratio in which they should share the profit at the end of the year? Select the correct option:
A) 20 : 9
B) 2 : 1
C) 3 : 2
D) 2 : 3
E) 5 : 3 | <gadget id="calculator">45_000 * 12</gadget>
<output>540_000</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">36_000 * 7</gadget>
<output>252_000</output>
<gadget id="calculator">540_000 / 252_000</gadget>
<output>15/7 = around 2.142857</output>
<result>A</result> | A | 2.222222 | X starts a business with Rs.45000. Y joins in the business after 3 months with Rs.36000. What will be the ratio in which they should share the profit at the end of the year? | {
"A": "20 : 9",
"B": "2 : 1",
"C": "3 : 2",
"D": "2 : 3",
"E": "5 : 3"
} | divide(multiply(45000, const_12), multiply(36000, add(const_4, const_3))) | add(const_3,const_4)|multiply(n0,const_12)|multiply(n2,#0)|divide(#1,#2)| | "ratio in which they should share the profit = ratio of the investments multiplied by the time period = 45000 Γ 12 : 36000 Γ 9 = 45 Γ 12 : 36 Γ 9 = 15 Γ 12 : 9 Γ 9 = 20 : 9 answer is a ." | other |
math_qa__KAxAvstyClF87fKH | A car travels first 160 km at 75 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour? Choose the correct choice from the following answers: A) 71.11 B) 71.12 C) 71.1 D) 71.17 E) 77.42 | <gadget id="calculator">160 / 75</gadget>
<output>32/15 = around 2.133333</output>
<gadget id="calculator">160 / 80</gadget>
<output>2</output>
<gadget id="calculator">(32/15) + 2</gadget>
<output>62/15 = around 4.133333</output>
<gadget id="calculator">1 / (62/15)</gadget>
<output>15/62 = around 0.241935</output>
<gadget id="calculator">320 * (15/62)</gadget>
<output>2_400/31 = around 77.419355</output>
<result>E</result> | E | 77.42 | A car travels first 160 km at 75 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour? | {
"A": "71.11",
"B": "71.12",
"C": "71.1",
"D": "71.17",
"E": "77.42"
} | multiply(320, divide(const_1, add(divide(160, 75), divide(160, 80)))) | divide(n0,n1)|divide(n0,n3)|add(#0,#1)|divide(const_1,#2)|multiply(n4,#3) | car travels first 160 km at 75 km / hr time taken to travel first 160 km = distancespeed = 160 / 75 car travels next 160 km at 80 km / hr time taken to travel next 160 km = distancespeed = 160 / 80 total distance traveled = 160 + 160 = 2 Γ 160 total time taken = 160 / 75 + 160 / 80 average speed = total distance traveled / total time taken = 320 / ( 160 / 75 + 160 / 80 ) = 77.42 km / hr answer : e | general |
math_qa__4rFMbPLw09q5VLtK | The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 18. Find the sum : Options: A) 4500 B) 7500 C) 5000 D) 7200 E) none of these | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">2 * (1/20)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(441/400) - (11/10)</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">18 / (1/400)</gadget>
<output>7_200</output>
<result>D</result> | D | 7,200 | The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 18. Find the sum : | {
"A": "4500",
"B": "7500",
"C": "5000",
"D": "7200",
"E": "none of these"
} | divide(18, subtract(power(add(const_1, divide(5, const_100)), 2), add(const_1, multiply(2, divide(5, const_100))))) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|add(#2,const_1)|power(#1,n1)|subtract(#4,#3)|divide(n2,#5)| | "sol . ( d ) let the sum be 100 . therefore , si = 100 Γ 5 Γ 2100 = 10100 Γ 5 Γ 2100 = 10 and ci = 100 ( 1 + 5100 ) 2 β 100100 ( 1 + 5100 ) 2 β 100 β΄ = 100 Γ 21 Γ 2120 Γ 20 β 100 = 414 = 100 Γ 21 Γ 2120 Γ 20 β 100 = 414 difference of ci and si = 41 β 4 - 10 = 1 β 4 if the difference is 1 β 4 , the sum = 100 = > if the difference is 18 , the sum = 400 Γ 18 = 7200 answer d" | gain |
math_qa__LffBVZSu2eOhxWpV | A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter W of liquid A was contained by the can initially?
Choose the correct choice.
A) 10 B) 20 C) 21 D) 25 E) 27 | <gadget id="calculator">7 + 9</gadget>
<output>16</output>
<gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) * 9</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">9 - (15/4)</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">16 * (21/4)</gadget>
<output>84</output>
<gadget id="calculator">9 * 7</gadget>
<output>63</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">63 - 35</gadget>
<output>28</output>
<gadget id="calculator">84 / 28</gadget>
<output>3</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<result>C</result> | C | 21 | A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter W of liquid A was contained by the can initially? | {
"A": "10",
"B": "20",
"C": "21",
"D": "25",
"E": "27"
} | multiply(7, divide(multiply(add(7, 9), subtract(9, multiply(divide(5, add(7, 5)), 9))), subtract(multiply(9, 7), multiply(7, 5)))) | add(n0,n2)|add(n0,n1)|multiply(n0,n2)|multiply(n0,n1)|divide(n1,#1)|subtract(#2,#3)|multiply(n2,#4)|subtract(n2,#6)|multiply(#0,#7)|divide(#8,#5)|multiply(n0,#9)| | "as a : b : : 7 : 5 - - - > only option c is a multiple of 7 and hence it is a good place to start . also a : b : : 7 : 5 means that , a = ( 712 ) * total and b = ( 5 / 12 ) * total if a = 21 , b = 15 - - - > remove 9 litres - - - > you remove ( 7 / 12 ) * 9 of a - - - > a remaining = 21 - ( 7 / 12 ) * 9 = 63 / 4 similarly , for b , you remove ( 5 / 12 ) * 9 - - - > b remaining = 15 - ( 5 / 12 ) * 9 = 45 / 4 and then add 9 more litres of b - - - > 9 + 45 / 4 = 81 / 4 thus a / b ( final ratio ) = ( 45 / 4 ) / ( 81 / 4 ) = 7 : 9 , the same as the final ratio mentioned in the question . hence c is the correct answer . a / b = 7 / 9 = ( 7 x - ( 7 / 12 ) * 9 ) / ( 5 x - ( 5 / 12 ) * 9 + 9 ) , where 7 x and 5 x are initial quantities of a and b respectively . thus , 7 / 9 = ( 7 x - ( 7 / 12 ) * 9 ) / ( 5 x - ( 5 / 12 ) * 9 + 9 ) - - - > giving you x = 3 . thus a ( original ) w = 7 * 3 = 21 . c" | other |
math_qa__Qz1Qq4VPDFpC5xVu | A bus covered a distance of 250 km, partly at an average speed of 40 kmph and partly at 60 kmph. If the total time taken is 6 hours, then the distance covered at 40 kmph is Select the correct option
A) 220 km B) 120 km C) 100 km D) 140 km E) none of these | <gadget id="calculator">60 * 6</gadget>
<output>360</output>
<gadget id="calculator">360 - 250</gadget>
<output>110</output>
<gadget id="calculator">40 - 60</gadget>
<output>-20</output>
<gadget id="calculator">-(-20)</gadget>
<output>20</output>
<gadget id="calculator">110 / 20</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">(11/2) * 40</gadget>
<output>220</output>
<result>A</result> | A | 220 | A bus covered a distance of 250 km, partly at an average speed of 40 kmph and partly at 60 kmph. If the total time taken is 6 hours, then the distance covered at 40 kmph is | {
"A": "220 km",
"B": "120 km",
"C": "100 km",
"D": "140 km",
"E": "none of these"
} | multiply(divide(subtract(multiply(60, 6), 250), negate(subtract(40, 60))), 40) | multiply(n2,n3)|subtract(n1,n2)|negate(#1)|subtract(#0,n0)|divide(#3,#2)|multiply(n1,#4)| | "let the partial distance covered at 40 kmph be x let the another partial distance covered at 60 kmph be ( 250 - x ) thus , x / 40 - ( 250 - x ) / 60 = 6 or , x / 40 + ( 250 - x ) / 60 = 6 or , ( 3 x + 500 - 2 x ) / / 120 = 6 or 500 + x = 720 x = 220 answer : a" | physics |
math_qa__PDLj3vZeBkTH3f4a | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 180 m long?
Choose the correct choice from the following answers.
A) 38 sec B) 35 sec C) 43.2 sec D) 40 sec E) none of these | <gadget id="calculator">180 / 1_000</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">360 / 1_000</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(9/50) + (9/25)</gadget>
<output>27/50 = around 0.54</output>
<gadget id="calculator">(27/50) / 45</gadget>
<output>3/250 = around 0.012</output>
<gadget id="calculator">(3/250) * 3_600</gadget>
<output>216/5 = around 43.2</output>
<result>C</result> | C | 43.2 | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 180 m long? | {
"A": "38 sec",
"B": "35 sec",
"C": "43.2 sec",
"D": "40 sec",
"E": "none of these"
} | multiply(divide(add(divide(180, const_1000), divide(360, const_1000)), 45), const_3600) | divide(n2,const_1000)|divide(n0,const_1000)|add(#0,#1)|divide(#2,n1)|multiply(#3,const_3600)| | "speed = 45 km / hr = 45 Γ£ β ( 5 / 18 ) m / s = 150 / 12 = 50 / 4 = 25 / 2 m / s total distance = length of the train + length of the platform = 360 + 180 = 540 meter time taken to cross the platform = 540 / ( 25 / 2 ) = 540 Γ£ β 2 / 25 = 43.2 seconds answer : c" | physics |
math_qa__Zm6ed8sOfvve8smN | If the length of the longest chord of a certain circle is 22, what is the radius of that certain circle?
Choose the most appropriate option:
A) 11
B) 5
C) 10
D) 15
E) 20 | <gadget id="calculator">22 / 2</gadget>
<output>11</output>
<result>A</result> | A | 11 | If the length of the longest chord of a certain circle is 22, what is the radius of that certain circle? | {
"A": "11",
"B": "5",
"C": "10",
"D": "15",
"E": "20"
} | divide(22, const_2) | divide(n0,const_2)| | "longest chord of a circle is the diameter of the circle diameter = 2 * radius if diameter of the circle is given as 22 = 2 * 11 so radius of the circle = 11 correct answer - a" | geometry |
math_qa__hl2iVCKployCWOpO | If y is 70% greater than x, than x is what % less than y? Pick one.
A) 18.7 B) 25.5 C) 33.3 D) 41.2 E) 54.4 | <gadget id="calculator">70 + 100</gadget>
<output>170</output>
<gadget id="calculator">70 / 170</gadget>
<output>7/17 = around 0.411765</output>
<gadget id="calculator">(7/17) * 100</gadget>
<output>700/17 = around 41.176471</output>
<result>D</result> | D | 41.2 | If y is 70% greater than x, than x is what % less than y? | {
"A": "18.7",
"B": "25.5",
"C": "33.3",
"D": "41.2",
"E": "54.4"
} | multiply(divide(70, add(70, const_100)), const_100) | add(n0,const_100)|divide(n0,#0)|multiply(#1,const_100) | y = 1.7 x x = y / 1.7 = 10 y / 17 x is 7 / 17 less which is about 41.2 % less than y . the answer is d . | general |
math_qa__CqZUhMTgdYt3xGY6 | In a room filled with 7 people, 3 people have exactly 1 sibling in the room and 4 people have exactly 2 siblings in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings? Pick one.
A) 5 / 21
B) 3 / 7
C) 4 / 7
D) 5 / 7
E) 13 / 21 | <gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(3/7) * (5/6)</gadget>
<output>5/14 = around 0.357143</output>
<gadget id="calculator">7 - 3</gadget>
<output>4</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(3/7) * (2/3)</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(5/14) + (2/7)</gadget>
<output>9/14 = around 0.642857</output>
<result>E</result> | E | 0.619048 | In a room filled with 7 people, 3 people have exactly 1 sibling in the room and 4 people have exactly 2 siblings in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings? | {
"A": "5 / 21",
"B": "3 / 7",
"C": "4 / 7",
"D": "5 / 7",
"E": "13 / 21"
} | add(multiply(divide(3, 7), divide(subtract(7, 2), subtract(7, const_1))), multiply(divide(3, 7), divide(subtract(7, 3), subtract(7, const_1)))) | divide(n1,n0)|subtract(n0,n4)|subtract(n0,const_1)|subtract(n0,n1)|divide(#1,#2)|divide(#3,#2)|multiply(#0,#4)|multiply(#0,#5)|add(#6,#7) | there are suppose a b c d e f g members in the room 4 people who have exactly one sibling . . . . a b c d . . . . ( a is bs β sssibl β g β ssand β ssviceversa ) β ss ( c β ssis β ssds β sssibl β g β ssand β ssviceversa ) β ss ( c β ssis β ssdssibl β gandviceversa ) ( cisds sibling and viceversa ) ( c is ds sibling and viceversa ) . . . now remaning efg are 4 people who have exactly 2 siblings . . . . ( e has f and g as his / her sibling and so on . . ) there are now 3 different set of siblings ( a and b ) ( c and d ) ; ( efg ) now first selecting 2 people out of 7 is 7 c 2 = 21 first sibling pair - - - - ( a and b ) - - selecting 2 people - - 2 c 2 = 1 second sibling pair ( c and d ) - - selecting 2 people - - 2 c 2 = 1 third sibling pair ( e f g ) - - selecting 2 out of 4 - - 4 c 2 = 6 total = 1 + 1 + 6 = 8 but , a / c to formula p ( success ) - 1 - p ( fail ) here , p ( failure ) is selecting 2 people who are siblings = 8 / 21 ( 21 is 7 c 2 ) = 1 - 8 / 21 = 13 / 21 ans e | general |
math_qa__rbrNktLnAdvGLCu4 | Mohit sold an article for $27000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article? Choose one
A) 16000 B) 22500 C) 15000 D) 18000 E) 17000 | <gadget id="calculator">27_000 * 10</gadget>
<output>270_000</output>
<gadget id="calculator">270_000 / 100</gadget>
<output>2_700</output>
<gadget id="calculator">27_000 - 2_700</gadget>
<output>24_300</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">24_300 / 108</gadget>
<output>225</output>
<gadget id="calculator">225 * 100</gadget>
<output>22_500</output>
<result>B</result> | B | 22,500 | Mohit sold an article for $27000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article? | {
"A": "16000",
"B": "22500",
"C": "15000",
"D": "18000",
"E": "17000"
} | multiply(divide(subtract(27000, divide(multiply(27000, 10), const_100)), add(const_100, 8)), const_100) | add(n2,const_100)|multiply(n0,n1)|divide(#1,const_100)|subtract(n0,#2)|divide(#3,#0)|multiply(#4,const_100)| | "let the cp be $ x . had he offered 10 % discount , profit = 8 % profit = 8 / 100 x and hence his sp = x + 8 / 100 x = $ 1.08 x = 27000 - 10 / 100 ( 27000 ) = 27000 - 2700 = $ 22500 = > 1.08 x = 22500 = > x = 22500 b" | gain |
math_qa__uoJWedxVEZg9f9Mq | If a farmer wants to plough a farm field on time, he must plough 260 hectares a day. For technical reasons he ploughed only 85 hectares a day, hence he had to plough 2 more days than he planned and he still has 40 hectares left. What is the area of the farm field and how many days the farmer planned to work initially? Choose the correct option:
A) 312 B) 490 C) 720 D) 435 E) 679 | <gadget id="calculator">2 * 85</gadget>
<output>170</output>
<gadget id="calculator">40 + 170</gadget>
<output>210</output>
<gadget id="calculator">260 - 85</gadget>
<output>175</output>
<gadget id="calculator">210 / 175</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 260</gadget>
<output>312</output>
<result>A</result> | A | 312 | If a farmer wants to plough a farm field on time, he must plough 260 hectares a day. For technical reasons he ploughed only 85 hectares a day, hence he had to plough 2 more days than he planned and he still has 40 hectares left. What is the area of the farm field and how many days the farmer planned to work initially? | {
"A": "312",
"B": "490",
"C": "720",
"D": "435",
"E": "679"
} | multiply(divide(add(40, multiply(2, 85)), subtract(260, 85)), 260) | multiply(n1,n2)|subtract(n0,n1)|add(n3,#0)|divide(#2,#1)|multiply(n0,#3)| | "let x be the number of days in the initial plan . therefore , the whole field is 260 Γ’ βΉ β¦ x hectares . the farmer had to work for x + 2 days , and he ploughed 85 ( x + 2 ) hectares , leaving 40 hectares unploughed . then we have the equation : 260 x = 85 ( x + 2 ) + 40 175 x = 210 x = 1.2 so the farmer planned to have the work done in 6 days , and the area of the farm field is 260 ( 1.2 ) = 312 hectares correct answer a" | physics |
math_qa__hpNV9OIgxZ2OOyqp | On my sister's 15th birthday, she was 159 cm in height, having grown 6% since the year before. How tall was she the previous year? Choose the correct choice from the following options: A) 150 cm B) 160 cm C) 170 cm D) 140 cm E) 150 cm | <gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">1 + (3/50)</gadget>
<output>53/50 = around 1.06</output>
<gadget id="calculator">159 / (53/50)</gadget>
<output>150</output>
<result>A</result> | A | 150 | On my sister's 15th birthday, she was 159 cm in height, having grown 6% since the year before. How tall was she the previous year? | {
"A": "150 cm",
"B": "160 cm",
"C": "170 cm",
"D": "140 cm",
"E": "150 cm"
} | divide(159, add(const_1, divide(6, const_100))) | divide(n2,const_100)|add(#0,const_1)|divide(n1,#1) | explanation : given that height on 15 th birthday = 159 cm and growth = 6 % let the previous year height = x then height on 15 th birthday = x Γ ( 100 + 6 ) / 100 = x Γ 106 / 100 β 159 = x Γ 106 / 100 β x = 159 Γ 100 / 106 = 1.5 Γ 100 = 150 cm answer : option a | physics |
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