id
string | question
string | chain
string | result
string | result_float
float64 | question_without_options
string | options
dict | annotated_formula
string | linear_formula
string | rationale
string | category
string |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__GeSlyCQc7IGGFTOH | A grocery shop has a sale of Rs. 6535, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? Choose the correct choice from the following answers: A) 4857 B) 4184 C) 4012 D) 4891 E) 5291 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6_500 * 6</gadget>
<output>39_000</output>
<gadget id="calculator">6_535 + 6_927</gadget>
<output>13_462</output>
<gadget id="calculator">6_855 + 13_462</gadget>
<output>20_317</output>
<gadget id="calculator">20_317 + 7_230</gadget>
<output>27_547</output>
<gadget id="calculator">27_547 + 6_562</gadget>
<output>34_109</output>
<gadget id="calculator">39_000 - 34_109</gadget>
<output>4_891</output>
<result>D</result> | D | 4,891 | A grocery shop has a sale of Rs. 6535, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? | {
"A": "4857",
"B": "4184",
"C": "4012",
"D": "4891",
"E": "5291"
} | subtract(multiply(6500, add(5, const_1)), add(add(add(6855, add(6535, 6927)), 7230), 6562)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "let the sale in the sixth month = x then ( 6535 + 6927 + 6855 + 7230 + 6562 + x ) / 6 = 6500 = > 6535 + 6927 + 6855 + 7230 + 6562 + x = 6 × 6500 = > 34109 + x = 39000 = > x = 39000 − 34109 = 4891 answer : d" | general |
math_qa__gtNXQf0iYrN0f1nG | How many times will the digit 7 be written when listing the integers from 1 to 1000? Select the correct option.
A) 110 B) 111 C) 271 D) 300 E) 304 | <gadget id="calculator">1 * 10</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<result>D</result> | D | 300 | How many times will the digit 7 be written when listing the integers from 1 to 1000? | {
"A": "110",
"B": "111",
"C": "271",
"D": "300",
"E": "304"
} | multiply(multiply(multiply(1, const_10), const_10), const_3) | multiply(n1,const_10)|multiply(#0,const_10)|multiply(#1,const_3) | another approach : in the range 0 - 100 : 7 as units digit - 10 times ( 7 , 17 , 27 , . . . , 97 ) ; 7 as tens digit - 10 time ( 71 , 72 , 73 , . . . , 79 ) ; so in first one hundred numbers 7 is written 10 + 10 = 20 times . in 10 hundreds 7 as units or tens digit will be written 10 * 20 = 200 times . plus 100 times when 7 is written as hundreds digit ( 700 , 701 , 702 , . . . , 799 ) . total 200 + 100 = 300 . answer : d . | general |
math_qa__jdxX27IUxR6aElNP | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 8 inches by 15 inches and Jordan's rectangle is 4 inches long, how wide is Jordan's rectangle, in inches? Pick one.
A) 24 B) 26 C) 28 D) 30 E) 32 | <gadget id="calculator">8 * 15</gadget>
<output>120</output>
<gadget id="calculator">120 / 4</gadget>
<output>30</output>
<result>D</result> | D | 30 | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 8 inches by 15 inches and Jordan's rectangle is 4 inches long, how wide is Jordan's rectangle, in inches? | {
"A": "24",
"B": "26",
"C": "28",
"D": "30",
"E": "32"
} | divide(rectangle_area(8, 15), 4) | rectangle_area(n0,n1)|divide(#0,n2)| | "area of first rectangle is 8 * 15 = 120 hence area of second would be 4 x = 120 x x = 30 answer is d" | geometry |
math_qa__r9S2wacCyeH55cr0 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8450. If his salary for the month of May is Rs.6500, find his salary for the month of January? Choose the correct choice.
A) 2177 B) 2876 C) 4700 D) 2981 E) 2711 | <gadget id="calculator">8_000 * 4</gadget>
<output>32_000</output>
<gadget id="calculator">8_450 * 4</gadget>
<output>33_800</output>
<gadget id="calculator">33_800 - 6_500</gadget>
<output>27_300</output>
<gadget id="calculator">32_000 - 27_300</gadget>
<output>4_700</output>
<result>C</result> | C | 4,700 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8450. If his salary for the month of May is Rs.6500, find his salary for the month of January? | {
"A": "2177",
"B": "2876",
"C": "4700",
"D": "2981",
"E": "2711"
} | subtract(multiply(8000, const_4), subtract(multiply(8450, const_4), 6500)) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#1,n2)|subtract(#0,#2)| | "sum of the salaries of the person for the months of january , february , march and april = 4 * 8000 = 32000 - - - - ( 1 ) sum of the salaries of the person for the months of february , march , april and may = 4 * 8450 = 33800 - - - - ( 2 ) ( 2 ) - ( 1 ) i . e . may - jan = 1800 salary of may is rs . 6500 salary of january = rs . 4700 . answer : c" | general |
math_qa__q0n947KypihixK00 | A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 45 more than the correct answer. Find the number. Choose the correct choice from the following answers
A) 60
B) 80
C) 100
D) 120
E) 140 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">45 * (4/5)</gadget>
<output>36</output>
<gadget id="calculator">36 * (4/5)</gadget>
<output>144/5 = around 28.8</output>
<gadget id="calculator">(4/5) * (4/5)</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">1 - (16/25)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(144/5) / (9/25)</gadget>
<output>80</output>
<gadget id="calculator">80 / (4/5)</gadget>
<output>100</output>
<result>C</result> | C | 100 | A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 45 more than the correct answer. Find the number. | {
"A": "60",
"B": "80",
"C": "100",
"D": "120",
"E": "140"
} | divide(divide(multiply(multiply(45, divide(4, 5)), divide(4, 5)), subtract(const_1, multiply(divide(4, 5), divide(4, 5)))), divide(4, 5)) | divide(n0,n1)|multiply(n4,#0)|multiply(#0,#0)|multiply(#0,#1)|subtract(const_1,#2)|divide(#3,#4)|divide(#5,#0)| | "let the number be x . ( 5 / 4 ) * x = ( 4 / 5 ) * x + 45 25 x = 16 x + 900 9 x = 900 x = 100 the answer is c ." | general |
math_qa__tyxlGOoSvIWJkody | A quiz has one mcq question with a,b and c as options. and two questions with true/false answers. what is the probability of giving all 3 answers correct? Choices:
A) 1 / 12
B) 1 / 3
C) 1 / 4
D) 1 / 2
E) 1 / 6 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * (1/2)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/2) * (1/6)</gadget>
<output>1/12 = around 0.083333</output>
<result>A</result> | A | 0.083333 | A quiz has one mcq question with a,b and c as options. and two questions with true/false answers. what is the probability of giving all 3 answers correct? | {
"A": "1 / 12",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 2",
"E": "1 / 6"
} | multiply(divide(const_1, const_2), multiply(divide(const_1, const_3), divide(const_1, const_2))) | divide(const_1,const_2)|divide(const_1,const_3)|multiply(#1,#0)|multiply(#0,#2) | probability of getting mcq answer correct = 1 / 3 probability of getting one true / false answer correct = 1 / 2 probability of getting all 3 answers correct = 1 / 3 * 1 / 2 * 1 / 2 = 1 / 12 answer : a | probability |
math_qa__haYvam3dkndcIKNw | In the manufacture of a certain product, 9 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale?
Pick one:
A) 0.125 % B) 0.36 % C) 0.8 % D) 1.25 % E) 2.0 % | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">9 * (1/25)</gadget>
<output>9/25 = around 0.36</output>
<result>B</result> | B | 0.36 | In the manufacture of a certain product, 9 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale? | {
"A": "0.125 %",
"B": "0.36 %",
"C": "0.8 %",
"D": "1.25 %",
"E": "2.0 %"
} | multiply(9, divide(4, const_100)) | divide(n1,const_100)|multiply(n0,#0) | percent of defective produced = 9 % percent of the defective units that are shipped for sale = 4 % percent of units produced are defective units that are shipped for sale = ( 4 / 100 ) * ( 9 / 100 ) * 100 % = ( 36 / 10000 ) * 100 % = ( 36 / 100 ) % = . 36 % answer b | gain |
math_qa__ebJ4yDQJAyjHyLXg | 70 students are required to paint a picture. 52 use green color and some children use red, 38 students use both the colors. How many students use red color? Choose the correct answer
A) 53 B) 54 C) 55 D) 56 E) 57 | <gadget id="calculator">70 - 52</gadget>
<output>18</output>
<gadget id="calculator">18 + 38</gadget>
<output>56</output>
<result>D</result> | D | 56 | 70 students are required to paint a picture. 52 use green color and some children use red, 38 students use both the colors. How many students use red color? | {
"A": "53",
"B": "54",
"C": "55",
"D": "56",
"E": "57"
} | add(subtract(70, 52), 38) | subtract(n0,n1)|add(n2,#0) | 70 = red + green - both red = 70 - green + both = 70 - 52 + 38 = 56 answer : d | other |
math_qa__3uN8LsM6QqvobCPg | The cost price of a radio is Rs.1500 and it was sold for Rs.1245, find the loss %? Select: A) 17 % B) 16 % C) 19 % D) 78 % E) 28 % | <gadget id="calculator">1_500 - 1_245</gadget>
<output>255</output>
<gadget id="calculator">255 / 1_500</gadget>
<output>17/100 = around 0.17</output>
<gadget id="calculator">(17/100) * 100</gadget>
<output>17</output>
<result>A</result> | A | 17 | The cost price of a radio is Rs.1500 and it was sold for Rs.1245, find the loss %? | {
"A": "17 %",
"B": "16 %",
"C": "19 %",
"D": "78 %",
"E": "28 %"
} | multiply(divide(subtract(1500, 1245), 1500), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "1500 - - - - 255 100 - - - - ? = > 17 % answer : a" | gain |
math_qa__zYV4p6r3wgbZ268y | A person buys an article at $500. At what price should he sell the article so as to make a profit of 20%?
Choose the correct choice from the following: A) 560 B) 449 C) 600 D) 740 E) 460 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">500 * (1/5)</gadget>
<output>100</output>
<gadget id="calculator">500 + 100</gadget>
<output>600</output>
<result>C</result> | C | 600 | A person buys an article at $500. At what price should he sell the article so as to make a profit of 20%? | {
"A": "560",
"B": "449",
"C": "600",
"D": "740",
"E": "460"
} | add(500, multiply(500, divide(20, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | "c 600 cost price = $ 500 profit = 20 % of 500 = $ 100 selling price = cost price + profit = 500 + 100 = 600" | gain |
math_qa__P9ZUPp61gmYuofFZ | Ramu bought an old car for Rs. 36400. He spent Rs. 8000 on repairs and sold it for Rs. 68400. What is his profit percent? Choose the correct choice from the following answers: A) 16 % B) 17 % C) 18 % D) 54 % E) 13 % | <gadget id="calculator">36_400 + 8_000</gadget>
<output>44_400</output>
<gadget id="calculator">68_400 - 44_400</gadget>
<output>24_000</output>
<gadget id="calculator">24_000 / 44_400</gadget>
<output>20/37 = around 0.540541</output>
<gadget id="calculator">(20/37) * 100</gadget>
<output>2_000/37 = around 54.054054</output>
<result>D</result> | D | 54 | Ramu bought an old car for Rs. 36400. He spent Rs. 8000 on repairs and sold it for Rs. 68400. What is his profit percent? | {
"A": "16 %",
"B": "17 %",
"C": "18 %",
"D": "54 %",
"E": "13 %"
} | multiply(divide(subtract(68400, add(36400, 8000)), add(36400, 8000)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "total cp = rs . 36400 + rs . 8000 = rs . 44400 and sp = rs . 68400 profit ( % ) = ( 68400 - 44400 ) / 44400 * 100 = 54 % answer : d" | gain |
math_qa__oDZiscKQWS4mfYSH | A ladder 25m long reaches a window of building 20m above the ground. Then the distance of the foot of the ladder from the building is?
Choose the correct choice: A) 35 m B) 45 m C) 30 m D) 15 m E) 25 m | <gadget id="calculator">25 ** 2</gadget>
<output>625</output>
<gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">625 - 400</gadget>
<output>225</output>
<gadget id="calculator">225 ** (1/2)</gadget>
<output>15</output>
<result>D</result> | D | 15 | A ladder 25m long reaches a window of building 20m above the ground. Then the distance of the foot of the ladder from the building is? | {
"A": "35 m",
"B": "45 m",
"C": "30 m",
"D": "15 m",
"E": "25 m"
} | sqrt(subtract(power(25, const_2), power(20, const_2))) | power(n0,const_2)|power(n1,const_2)|subtract(#0,#1)|sqrt(#2) | let it forms a right angled triangle and follow c ^ 2 = a ^ 2 + b ^ 2 then 25 ^ 2 = 20 ^ 2 + b ^ 2 b ^ 2 = 625 - 400 b = 15 answer : d | physics |
math_qa__xzJGNwfYiUfpTAB7 | IF 2+7=57 ; 3+6=63 ; 5+9=206 Then 4+8=? Pick one: A) 125 B) 126 C) 127 D) 128 E) 129 | <gadget id="calculator">4 ** 3</gadget>
<output>64</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">64 + 64</gadget>
<output>128</output>
<result>D</result> | D | 128 | IF 2+7=57 ; 3+6=63 ; 5+9=206 Then 4+8=? | {
"A": "125",
"B": "126",
"C": "127",
"D": "128",
"E": "129"
} | add(power(4, const_3), power(8, const_2)) | power(n9,const_3)|power(n10,const_2)|add(#0,#1) | 2 ^ 3 + 7 ^ 2 = 57 3 ^ 3 + 6 ^ 2 = 63 5 ^ 3 + 9 ^ 2 = 206 and 4 ^ 3 + 8 ^ 2 = 128 answer : d | general |
math_qa__vrvZnOpTlYVkgdkI | A tank is filled to one quarter of its capacity with a mixture consisting of water and sodium chloride. The proportion of sodium chloride in the tank is 30% by volume and the capacity of the tank is 24 gallons. If the water evaporates from the tank at the rate of 0.4 gallons per hour, and the amount of sodium chloride stays the same, what will be the concentration of water in the mixture in 6 hours?
Choose the correct answer
A) 30 % B) 35 % C) 40 % D) 45 % E) 50 % | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">6 * 70</gadget>
<output>420</output>
<gadget id="calculator">420 / 100</gadget>
<output>21/5 = around 4.2</output>
<gadget id="calculator">0.4 * 6</gadget>
<output>2.4</output>
<gadget id="calculator">(21/5) - 2.4</gadget>
<output>1.8</output>
<gadget id="calculator">6 - 2.4</gadget>
<output>3.6</output>
<gadget id="calculator">1.8 / 3.6</gadget>
<output>0.5</output>
<gadget id="calculator">0.5 * 100</gadget>
<output>50</output>
<result>E</result> | E | 50 | A tank is filled to one quarter of its capacity with a mixture consisting of water and sodium chloride. The proportion of sodium chloride in the tank is 30% by volume and the capacity of the tank is 24 gallons. If the water evaporates from the tank at the rate of 0.4 gallons per hour, and the amount of sodium chloride stays the same, what will be the concentration of water in the mixture in 6 hours? | {
"A": "30 %",
"B": "35 %",
"C": "40 %",
"D": "45 %",
"E": "50 %"
} | multiply(divide(subtract(divide(multiply(6, subtract(const_100, 30)), const_100), multiply(0.4, 6)), subtract(6, multiply(0.4, 6))), const_100) | multiply(n2,n3)|subtract(const_100,n0)|multiply(n3,#1)|subtract(n3,#0)|divide(#2,const_100)|subtract(#4,#0)|divide(#5,#3)|multiply(#6,const_100)| | "the number of gallons in the tank is ( 1 / 4 ) 24 = 6 gallons the amount of sodium chloride is 0.3 ( 6 ) = 1.8 gallons at the start , the amount of water is 0.7 ( 6 ) = 4.2 gallons after 6 hours , the amount of water is 4.2 - 0.4 ( 6 ) = 1.8 gallons the concentration of water is 1.8 / ( 1.8 + 1.8 ) = 1.8 / 3.6 = 50 % the answer is e ." | gain |
math_qa__Yz88A7gSxKypAmBz | By selling 20 pencils for a rupee a man loses 35%. How many for a rupee should he sell in order to gain 30%? Pick: A) 8 B) 9 C) 6 D) 14 E) 10 | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">1 / 65</gadget>
<output>1/65 = around 0.015385</output>
<gadget id="calculator">130 * (1/65)</gadget>
<output>2</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 20</gadget>
<output>10</output>
<result>E</result> | E | 10 | By selling 20 pencils for a rupee a man loses 35%. How many for a rupee should he sell in order to gain 30%? | {
"A": "8",
"B": "9",
"C": "6",
"D": "14",
"E": "10"
} | multiply(divide(const_1, multiply(add(const_100, 30), divide(const_1, subtract(const_100, 35)))), 20) | add(n2,const_100)|subtract(const_100,n1)|divide(const_1,#1)|multiply(#0,#2)|divide(const_1,#3)|multiply(n0,#4)| | 65 % - - - 20 130 % - - - ? 65 / 130 * 20 = 10 answer : e | gain |
math_qa__U3aMtWAvVWQsMtPv | In order to obtain an income of Rs. 500 from 30% stock at Rs. 90, one must make an investment of
Choose the correct option:
A) rs . 1550 B) rs . 1430 C) rs . 1450 D) rs . 1400 E) rs . 1500 | <gadget id="calculator">90 / 30</gadget>
<output>3</output>
<gadget id="calculator">3 * 500</gadget>
<output>1_500</output>
<result>E</result> | E | 1,500 | In order to obtain an income of Rs. 500 from 30% stock at Rs. 90, one must make an investment of | {
"A": "rs . 1550",
"B": "rs . 1430",
"C": "rs . 1450",
"D": "rs . 1400",
"E": "rs . 1500"
} | multiply(divide(90, 30), 500) | divide(n2,n1)|multiply(n0,#0)| | "explanation : market value = rs . 90 required income = rs . 500 . here face value is not given . take face value as rs . 100 if it is not given in the question to obtain rs . 30 ( ie , 30 % of the face value 100 ) , investment = rs . 90 to obtain rs . 15000 , investment = 90 / 30 ã — 500 = rs . 1500 answer : option e" | gain |
math_qa__ys6X79fWu9NetIuF | If n is a positive integer and n^2 is divisible by 72, then the largest positive integer Q that must divide n is?
Options
A) 6
B) 12
C) 24
D) 36
E) 48 | <gadget id="calculator">72 / 2</gadget>
<output>36</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<result>B</result> | B | 12 | If n is a positive integer and n^2 is divisible by 72, then the largest positive integer Q that must divide n is? | {
"A": "6",
"B": "12",
"C": "24",
"D": "36",
"E": "48"
} | multiply(sqrt(divide(72, 2)), 2) | divide(n1,n0)|sqrt(#0)|multiply(n0,#1)| | "q : if n is a positive integer and n ^ 2 is divisible by 72 , then the largest positive integer q that must divide n is : a 6 , b 12 , c 24 , d 36 , e 48 n ^ 2 is divisible by 72 , but it must also be greater than 72 . if n is an integer , then n ^ 2 must be a perfect square . the factorization of 72 is ( 8 ) ( 9 ) , so if it is multiplied by 2 , it will be ( 2 ) ( 8 ) ( 9 ) = ( 16 ) ( 9 ) = 144 , a perfect square . so n ^ 2 must be at least 144 or a multiple of 144 , which means that n must be 12 or a multiple of 12 . b" | general |
math_qa__Y6W5Skbst7Mr2w2V | The value of (2.502+0.064)^2 - (2.502-0.064)^2/2.502*0.064
Options
A) . 25 B) . 235 C) 4 D) 3 E) 2 | <gadget id="calculator">2.502 + 0.064</gadget>
<output>2.566</output>
<gadget id="calculator">2.566 ** 2</gadget>
<output>6.584356</output>
<gadget id="calculator">2.502 - 0.064</gadget>
<output>2.438</output>
<gadget id="calculator">2.438 ** 2</gadget>
<output>5.943844</output>
<gadget id="calculator">6.584356 - 5.943844</gadget>
<output>0.640512</output>
<gadget id="calculator">2.502 * 0.064</gadget>
<output>0.160128</output>
<gadget id="calculator">0.640512 / 0.160128</gadget>
<output>4</output>
<result>C</result> | C | 4 | The value of (2.502+0.064)^2 - (2.502-0.064)^2/2.502*0.064 | {
"A": ". 25",
"B": ". 235",
"C": "4",
"D": "3",
"E": "2"
} | divide(subtract(power(add(2.502, 0.064), const_2), power(subtract(2.502, 0.064), const_2)), multiply(2.502, 0.064)) | add(n0,n1)|multiply(n0,n1)|subtract(n0,n1)|power(#0,const_2)|power(#2,const_2)|subtract(#3,#4)|divide(#5,#1)| | "( 2.502 + 0.064 ) 2 - ( 2.502 - 0.064 ) 2 / 2.502 * 0.064 = ( a + b ) 2 - ( a - b ) / ab = 4 ab / ab = 4 answer : c" | general |
math_qa__eoxfOchPMGe9DI1p | A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.320. How much does C have? Select:
A) 50 B) 78 C) 267 D) 20 E) 27 | <gadget id="calculator">200 + 320</gadget>
<output>520</output>
<gadget id="calculator">520 - 500</gadget>
<output>20</output>
<result>D</result> | D | 20 | A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.320. How much does C have? | {
"A": "50",
"B": "78",
"C": "267",
"D": "20",
"E": "27"
} | subtract(add(200, 320), 500) | add(n1,n2)|subtract(#0,n0) | a + b + c = 500 a + c = 200 b + c = 320 - - - - - - - - - - - - - - a + b + 2 c = 520 a + b + c = 500 - - - - - - - - - - - - - - - - c = 20 answer : d | general |
math_qa__ADL1I2nCGhUYHAaa | Car A runs at the speed of 70km/hr & reaches its destination in 10hr. Car B runs at the speed of 35 km/h & reaches its destination in 10h. What is the respective ratio of distances covered by Car A & Car B?
Choose the correct choice from the following choices.
A) 11 : 5
B) 11 : 8
C) 13 : 7
D) 15 : 7
E) 2 : 1 | <gadget id="calculator">70 * 10</gadget>
<output>700</output>
<gadget id="calculator">35 * 10</gadget>
<output>350</output>
<gadget id="calculator">700 / 350</gadget>
<output>2</output>
<result>E</result> | E | 2 | Car A runs at the speed of 70km/hr & reaches its destination in 10hr. Car B runs at the speed of 35 km/h & reaches its destination in 10h. What is the respective ratio of distances covered by Car A & Car B? | {
"A": "11 : 5",
"B": "11 : 8",
"C": "13 : 7",
"D": "15 : 7",
"E": "2 : 1"
} | divide(multiply(70, 10), multiply(35, 10)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "sol . distance travelled by car a = 70 × 10 = 700 km distance travelled by car b = 35 × 10 = 350 km ratio = 700 / 350 = 2 : 1 answer : e" | physics |
math_qa__4DbtYE1fjNXQMMhY | Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 50 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped? Pick
A) 105
B) 120
C) 140
D) 147
E) 98 | <gadget id="calculator">72 / 60</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 35</gadget>
<output>42</output>
<gadget id="calculator">50 - 35</gadget>
<output>15</output>
<gadget id="calculator">42 / 15</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">35 * (14/5)</gadget>
<output>98</output>
<result>E</result> | E | 98 | Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 50 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped? | {
"A": "105",
"B": "120",
"C": "140",
"D": "147",
"E": "98"
} | multiply(35, divide(multiply(divide(72, const_60), 35), subtract(50, 35))) | divide(n1,const_60)|subtract(n2,n0)|multiply(n0,#0)|divide(#2,#1)|multiply(n0,#3)| | "car y began travelling after 72 minutes or 1.2 hours . let t be the time for which car y travelled before it stopped . both cars stop when they have travelled the same distance . so , 35 ( t + 1.2 ) = 50 t t = 2.8 distance travelled by car x from the time car y began traveling until both cars stopped is 35 x 2.8 = 98 miles answer : - e" | physics |
math_qa__s7bIz7S1o3ESQ2Pt | A and B together can do a work in 4 days. If A alone can do it in 14 days. In how many days can B alone do it? Select
A) 10 B) 6 C) 77 D) 55 E) 21 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 14</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">(1/4) - (1/14)</gadget>
<output>5/28 = around 0.178571</output>
<gadget id="calculator">1 / (5/28)</gadget>
<output>28/5 = around 5.6</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(28/5) + (2/5)</gadget>
<output>6</output>
<result>B</result> | B | 6 | A and B together can do a work in 4 days. If A alone can do it in 14 days. In how many days can B alone do it? | {
"A": "10",
"B": "6",
"C": "77",
"D": "55",
"E": "21"
} | add(inverse(subtract(divide(const_1, 4), divide(const_1, 14))), divide(const_2, add(const_2, const_3))) | add(const_2,const_3)|divide(const_1,n0)|divide(const_1,n1)|divide(const_2,#0)|subtract(#1,#2)|inverse(#4)|add(#3,#5) | 1 / 4 – 1 / 12 = 1 / 6 = > 6 answer : b | physics |
math_qa__59FMlfaEavSq3uLd | Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/6 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent?
Select
A) 2 / 3 B) 29 / 60 C) 17 / 30 D) 19 / 30 E) 11 / 15 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/3) * (1/2)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) + (1/6)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<result>A</result> | A | 0.666667 | Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/6 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent? | {
"A": "2 / 3",
"B": "29 / 60",
"C": "17 / 30",
"D": "19 / 30",
"E": "11 / 15"
} | subtract(1, add(multiply(inverse(3), inverse(const_2)), inverse(6))) | inverse(n3)|inverse(n1)|inverse(const_2)|multiply(#1,#2)|add(#0,#3)|subtract(n0,#4)| | "let s assume the platinum card spending limit = x gold card spending limit will be = x / 2 balance on gold card is = x / 2 * 1 / 3 = x / 6 platinum card unspent limit is = x - 1 / 6 x = 5 / 6 x so if gold card balance is transferred then the rest unspent will be 5 / 6 x - x / 6 = 2 / 3 x so the ans is a" | general |
math_qa__ICWMQBu3nbVvWJJk | City A and City B are 140 miles apart. Train C departs City A, heading towards City B, at 4:00 and travels at 40 miles per hour. Train D departs City B, heading towards City A, at 5:30 and travels at 20 miles per hour. The trains travel on parallel tracks. At what time do the two trains meet? Choose the most appropriate option
A) 5 : 00 B) 7 : 30 C) 6 : 00 D) 6 : 30 E) 7 : 00 | <gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 / 30</gadget>
<output>7/30 = around 0.233333</output>
<result>B</result> | B | 0.233333 | City A and City B are 140 miles apart. Train C departs City A, heading towards City B, at 4:00 and travels at 40 miles per hour. Train D departs City B, heading towards City A, at 5:30 and travels at 20 miles per hour. The trains travel on parallel tracks. At what time do the two trains meet? | {
"A": "5 : 00",
"B": "7 : 30",
"C": "6 : 00",
"D": "6 : 30",
"E": "7 : 00"
} | divide(add(5, const_2), 30) | add(n4,const_2)|divide(#0,n5) | train c has traveled 20 mi in the half hour before train d has started its journey . 140 - 20 = 120 40 + 20 = 60 mph 120 mi / 60 mph = 2 hrs 5 : 30 pm + 2 hrs = 7 : 30 pm answer : b . 7 : 30 | physics |
math_qa__wDqEkhf4ITjVAxUp | The perimeter of a triangle is 32 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?
Choose the correct choice from the following answers: A) 87 cm 2 B) 28 cm 2 C) 98 cm 2 D) 26 cm 2 E) 40 cm 2 | <gadget id="calculator">(2.5 * 32) / 2</gadget>
<output>40</output>
<result>E</result> | E | 40 | The perimeter of a triangle is 32 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle? | {
"A": "87 cm 2",
"B": "28 cm 2",
"C": "98 cm 2",
"D": "26 cm 2",
"E": "40 cm 2"
} | triangle_area(2.5, 32) | triangle_area(n0,n1)| | "area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 2.5 * 32 / 2 = 40 cm 2 answer : e" | geometry |
math_qa__YY7D79nJvqLk1iin | You cook a pot of beef stew for you and your roommate. Normally it lasts 7 days between the two of you. If 3 guests are now staying with you and your roommate, how many days will the beef stew now last if everyone eats it? Choose the correct choice.
A) 2.8 B) 1 C) 3.5 D) 14 E) 1.6 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">1 / 14</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">(1/14) * 5</gadget>
<output>5/14 = around 0.357143</output>
<gadget id="calculator">1 / (5/14)</gadget>
<output>14/5 = around 2.8</output>
<result>A</result> | A | 2.8 | You cook a pot of beef stew for you and your roommate. Normally it lasts 7 days between the two of you. If 3 guests are now staying with you and your roommate, how many days will the beef stew now last if everyone eats it? | {
"A": "2.8",
"B": "1",
"C": "3.5",
"D": "14",
"E": "1.6"
} | divide(const_1, multiply(divide(const_1, multiply(7, const_2)), add(const_2, 3))) | add(n1,const_2)|multiply(n0,const_2)|divide(const_1,#1)|multiply(#0,#2)|divide(const_1,#3) | first set up a ratio with all the relevant values and also the unknown variable : 2 * 7 = 5 * x now solve by multiplying 2 by 7 and then dividing that product by 5 : 2 * 7 = 14 14 / 5 = x x = 2.8 the value of x represents the amount of days a bot of beef stew will last for 5 total people . answer : a | physics |
math_qa__SULMXHHovqBApewO | A person can swim in still water at 12 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 10km? Choose one:
A) 1 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">12 - 2</gadget>
<output>10</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<result>A</result> | A | 1 | A person can swim in still water at 12 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 10km? | {
"A": "1",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(10, subtract(12, 2)) | subtract(n0,n1)|divide(n2,#0)| | "m = 12 s = 2 us = 12 - 2 = 10 d = 10 t = 10 / 10 = 1 answer : a" | physics |
math_qa__M7A5xcdROEEd8Ofv | A train running at the speed of 54 km/hr crosses a pole in 9 seconds. What is the length of the train? Select the correct option.
A) 135
B) 278
C) 255
D) 150
E) 287 | <gadget id="calculator">54 * 1_000</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 / 3_600</gadget>
<output>15</output>
<gadget id="calculator">15 * 9</gadget>
<output>135</output>
<result>A</result> | A | 135 | A train running at the speed of 54 km/hr crosses a pole in 9 seconds. What is the length of the train? | {
"A": "135",
"B": "278",
"C": "255",
"D": "150",
"E": "287"
} | multiply(divide(multiply(54, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = ( 54 * 5 / 18 ) m / sec = ( 15 ) m / sec length of the train = ( speed x time ) = ( 15 * 9 ) m = 135 m . answer : a" | physics |
math_qa__tDXMNhwJVjNJfbMy | The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 44 kg, then the weight of B is: Select:
A) 31 kg B) 32 kg C) 33 kg D) 34 kg E) none of these | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">44 * 2</gadget>
<output>88</output>
<gadget id="calculator">80 + 88</gadget>
<output>168</output>
<gadget id="calculator">45 * 3</gadget>
<output>135</output>
<gadget id="calculator">168 - 135</gadget>
<output>33</output>
<result>C</result> | C | 33 | The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 44 kg, then the weight of B is: | {
"A": "31 kg",
"B": "32 kg",
"C": "33 kg",
"D": "34 kg",
"E": "none of these"
} | subtract(add(multiply(40, const_2), multiply(44, const_2)), multiply(45, const_3)) | multiply(n1,const_2)|multiply(n2,const_2)|multiply(n0,const_3)|add(#0,#1)|subtract(#3,#2)| | "explanation : let a , b , c represent their respective weights . then , we have : a + b + c = ( 45 x 3 ) = 135 … . ( i ) a + b = ( 40 x 2 ) = 80 … . ( ii ) b + c = ( 44 x 2 ) = 88 … . ( iii ) adding ( ii ) and ( iii ) , we get : a + 2 b + c = 168 … . ( iv ) subtracting ( i ) from ( iv ) , we get : b = 33 . b ’ s weight = 33 kg . answer : c" | general |
math_qa__cq0TTbk1Hix2YjW8 | The duplicate ratio of 3:4 is?
Choose one
A) 1 : 2 B) 1 : 4 C) 1 : 8 D) 9 : 16 E) 1 : 13 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">9 / 16</gadget>
<output>9/16 = around 0.5625</output>
<result>D</result> | D | 0.5625 | The duplicate ratio of 3:4 is? | {
"A": "1 : 2",
"B": "1 : 4",
"C": "1 : 8",
"D": "9 : 16",
"E": "1 : 13"
} | divide(power(3, const_2), power(4, const_2)) | power(n0,const_2)|power(n1,const_2)|divide(#0,#1)| | "3 ^ 2 : 4 ^ 2 = 9 : 16 answer : d" | other |
math_qa__62GpfzP0J9ey6j2A | In the first 15 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 35 overs to reach the target of 275 runs? Choices:
A) 5.55
B) 6.25
C) 6.75
D) 7.02
E) 6.48 | <gadget id="calculator">15 * 3.2</gadget>
<output>48</output>
<gadget id="calculator">275 - 48</gadget>
<output>227</output>
<gadget id="calculator">227 / 35</gadget>
<output>227/35 = around 6.485714</output>
<result>E</result> | E | 6.48 | In the first 15 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 35 overs to reach the target of 275 runs? | {
"A": "5.55",
"B": "6.25",
"C": "6.75",
"D": "7.02",
"E": "6.48"
} | divide(subtract(275, multiply(15, 3.2)), 35) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)| | required run rate = 275 - ( 3.2 x 15 ) / 35 = 227 / 35 = 6.48 option e | gain |
math_qa__9f0IJpdoeIlFpCV7 | a car salesman earns a base salary of $ 1000 per month plus a commission of $ 200 for each car he sells . if the car salesman earned $ 1800 in january , how many cars does he need to sell in february in order to double his january earnings ? Choose the correct choice from the following
A) 13 B) 14 C) 15 D) 16 E) 17 | <gadget id="calculator">1_800 * 2</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 - 1_000</gadget>
<output>2_600</output>
<gadget id="calculator">2_600 / 200</gadget>
<output>13</output>
<result>A</result> | A | 13 | a car salesman earns a base salary of $ 1000 per month plus a commission of $ 200 for each car he sells . if the car salesman earned $ 1800 in january , how many cars does he need to sell in february in order to double his january earnings ? | {
"A": "13",
"B": "14",
"C": "15",
"D": "16",
"E": "17"
} | divide(subtract(multiply(1800, const_2), 1000), 200) | multiply(n2,const_2)|subtract(#0,n0)|divide(#1,n1) | 1000 + 200 x = 3600 x = 13 cars . the answer is a . | general |
math_qa__UxIH6DSjPWjJcDsD | The area of a sector of a circle of radius 4 cm formed by an arc of length 3.5 cm is? Choose the correct choice from the following answers
A) 7 B) 7.67 C) 8.75 D) 8.98 E) 8.28 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 * 3.5</gadget>
<output>14</output>
<gadget id="calculator">(1/2) * 14</gadget>
<output>7</output>
<result>A</result> | A | 7 | The area of a sector of a circle of radius 4 cm formed by an arc of length 3.5 cm is? | {
"A": "7",
"B": "7.67",
"C": "8.75",
"D": "8.98",
"E": "8.28"
} | multiply(divide(const_1, const_2), multiply(4, 3.5)) | divide(const_1,const_2)|multiply(n0,n1)|multiply(#0,#1)| | "( 4 * 3.5 ) / 2 = 7 answer : a" | physics |
math_qa__LW6pmbaF3R41s3AX | Working alone, A can complete a certain kind of job in 12 hours. A and D, working together at their respective rates, can complete one of these jobs in 4 hours. In how many hours can D, working alone, complete one of these jobs? Choose the correct option.
A) 1 B) 3 C) 4 D) 6 E) 9 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/4) - (1/12)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>D</result> | D | 6 | Working alone, A can complete a certain kind of job in 12 hours. A and D, working together at their respective rates, can complete one of these jobs in 4 hours. In how many hours can D, working alone, complete one of these jobs? | {
"A": "1",
"B": "3",
"C": "4",
"D": "6",
"E": "9"
} | inverse(subtract(inverse(4), inverse(12))) | inverse(n1)|inverse(n0)|subtract(#0,#1)|inverse(#2)| | "let total time taken by s to complete the job = s total time taken by a to complete the job = 12 work done by a in an hour 1 / a = 1 / 12 working together a and d can complete the job in 4 hours 1 / a + 1 / d = 1 / 4 = > 1 / d = 1 / 4 - 1 / 12 = 1 / 4 - 1 / 12 = 1 / 6 = > d = 6 hours answer d" | physics |
math_qa__aRVLJNCRUc3dc9hO | The perimeter of a triangle is 35 cm and the inradius of the triangle is 4.5 cm. What is the area of the triangle? Choose the correct choice from the following:
A) 22
B) 75
C) 78
D) 54
E) 23 | <gadget id="calculator">(4.5 * 35) / 2</gadget>
<output>78.75</output>
<result>C</result> | C | 78 | The perimeter of a triangle is 35 cm and the inradius of the triangle is 4.5 cm. What is the area of the triangle? | {
"A": "22",
"B": "75",
"C": "78",
"D": "54",
"E": "23"
} | triangle_area(4.5, 35) | triangle_area(n0,n1)| | "area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 4.5 * 35 / 2 = 78.75 cm 2 answer : c" | geometry |
math_qa__ZzKGsuSyiLXzYu03 | A’s speed is 22/19 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat? Choose the correct choice from the following choices:
A) 1 / 22 B) 1 / 19 C) 3 / 19 D) 2 / 19 E) 3 / 22 | <gadget id="calculator">22 - 19</gadget>
<output>3</output>
<gadget id="calculator">3 / 22</gadget>
<output>3/22 = around 0.136364</output>
<result>E</result> | E | 0.136364 | A’s speed is 22/19 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat? | {
"A": "1 / 22",
"B": "1 / 19",
"C": "3 / 19",
"D": "2 / 19",
"E": "3 / 22"
} | divide(subtract(22, 19), 22) | subtract(n0,n1)|divide(#0,n0)| | "we have the ratio of a ’ s speed and b ’ s speed . this means , we know how much distance a covers compared with b in the same time . this is what the beginning of the race will look like : ( start ) a _________ b ______________________________ if a covers 22 meters , b covers 19 meters in that time . so if the race is 22 meters long , when a reaches the finish line , b would be 3 meters behind him . if we want the race to end in a dead heat , we want b to be at the finish line too at the same time . this means b should get a head start of 3 meters so that he doesn ’ t need to cover that . in that case , the time required by a ( to cover 22 meters ) would be the same as the time required by b ( to cover 19 meters ) to reach the finish line . so b should get a head start of 3 / 22 th of the race . answer ( e )" | general |
math_qa__dI5w3itCNgC1V32I | The average weight of 8 girls increases by 3 kg when a new girl comes in place of one of them weighing 70 kg. What might be the weight of the new girl? Pick.
A) 94 kg B) 95 kg C) 96 kg D) 97 kg E) 98 kg | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 + 70</gadget>
<output>94</output>
<result>A</result> | A | 94 | The average weight of 8 girls increases by 3 kg when a new girl comes in place of one of them weighing 70 kg. What might be the weight of the new girl? | {
"A": "94 kg",
"B": "95 kg",
"C": "96 kg",
"D": "97 kg",
"E": "98 kg"
} | add(multiply(8, 3), 70) | multiply(n0,n1)|add(n2,#0) | total weight increased = 8 x 3 kg = 24 kg . weight of new person = 70 + 24 kg = 94 kg answer : a | general |
math_qa__NCXl8eWoI3Nc20vc | If T = 5/9 * (K - 32), and if T = 35, then what is the value of K? Choices:
A) 92 B) 95 C) 98 D) 101 E) 104 | <gadget id="calculator">35 * 9</gadget>
<output>315</output>
<gadget id="calculator">315 / 5</gadget>
<output>63</output>
<gadget id="calculator">63 + 32</gadget>
<output>95</output>
<result>B</result> | B | 95 | If T = 5/9 * (K - 32), and if T = 35, then what is the value of K? | {
"A": "92",
"B": "95",
"C": "98",
"D": "101",
"E": "104"
} | add(divide(multiply(35, 9), 5), 32) | multiply(n1,n3)|divide(#0,n0)|add(n2,#1)| | "k - 32 = 9 t / 5 k = 9 t / 5 + 32 k = 9 ( 35 ) / 5 + 32 = 95 the answer is b ." | general |
math_qa__cuKRhQJJ6xnqUIib | The effective annual rate of interest corresponding to a nominal rate of 8% per annum payable half-yearly is? Select.
A) 6.06 % B) 8.16 % C) 6.08 % D) 6.09 % E) 6.19 % | <gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">8 + (4/25)</gadget>
<output>204/25 = around 8.16</output>
<result>B</result> | B | 8.16 | The effective annual rate of interest corresponding to a nominal rate of 8% per annum payable half-yearly is? | {
"A": "6.06 %",
"B": "8.16 %",
"C": "6.08 %",
"D": "6.09 %",
"E": "6.19 %"
} | add(add(divide(8, const_2), divide(8, const_2)), divide(multiply(divide(8, const_2), divide(8, const_2)), const_100)) | divide(n0,const_2)|add(#0,#0)|multiply(#0,#0)|divide(#2,const_100)|add(#1,#3) | amount of rs . 100 for 1 year when compounded half - yearly = [ 100 * ( 1 + 4 / 100 ) 2 ] = rs . 108.16 effective rate = ( 108.16 - 100 ) = 8.16 % answer : b | gain |
math_qa__VDFE6LnEpMpidjXH | A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 50, how many horses are there ? Select the correct option: A) 10 B) 12 C) 14 D) 16 E) 18 | <gadget id="calculator">2 / 2</gadget>
<output>1</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">50 / 5</gadget>
<output>10</output>
<result>A</result> | A | 10 | A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 50, how many horses are there ? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(50, add(const_4, divide(const_2, const_2))) | divide(const_2,const_2)|add(#0,const_4)|divide(n0,#1)| | "legs 10 * 4 = 40 now half on their horses so remaining on the walk so 5 men 5 men has 10 legs so , 10 + 40 = 50 legs walking answer : a" | general |
math_qa__B5G6cyVaBPjKOwH9 | If a car went the first third of the distance at 80 kmh, the second third at 24 kmh, and the last third at 60 kmh, what was the average speed of the car for the entire trip?
Choose the correct choice.
A) 36 kmh
B) 40 kmh
C) 42 kmh
D) 44 kmh
E) 50 kmh | <gadget id="calculator">1 / 80</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/80) + (1/24)</gadget>
<output>13/240 = around 0.054167</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(13/240) + (1/60)</gadget>
<output>17/240 = around 0.070833</output>
<gadget id="calculator">3 / (17/240)</gadget>
<output>720/17 = around 42.352941</output>
<result>C</result> | C | 42 | If a car went the first third of the distance at 80 kmh, the second third at 24 kmh, and the last third at 60 kmh, what was the average speed of the car for the entire trip? | {
"A": "36 kmh",
"B": "40 kmh",
"C": "42 kmh",
"D": "44 kmh",
"E": "50 kmh"
} | divide(const_3, add(add(divide(const_1, 80), divide(const_1, 24)), divide(const_1, 60))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#3,#2)|divide(const_3,#4)| | "assume d / 3 = 240 ( this number is convenient because it is divisible by 80 , 24 and 60 ) so : 240 = 80 * t 1 = 3 hrs 240 = 24 * t 2 = 10 hrs 240 = 60 * t 3 = 4 hrs t = t 1 + t 2 + t 3 = 17 hrs d = rt ( 240 * 3 ) = r * 17 r = 42.35 answer : c" | physics |
math_qa__bRmbu0ZLj0hdJ1jG | in 1990 the budgets for projects q and v were $ 540000 and $ 780000 , respectively . in each of the next 10 years , the budget for q was increased by $ 30000 and the budget for v was decreased by $ 10000 . in which year was the budget for q equal to the budget for v ? Select the correct option
A) 1992 B) 1993 C) 1994 D) 1995 E) 1996 | <gadget id="calculator">1_990 + 4</gadget>
<output>1_994</output>
<result>E</result> | E | 1,996 | in 1990 the budgets for projects q and v were $ 540000 and $ 780000 , respectively . in each of the next 10 years , the budget for q was increased by $ 30000 and the budget for v was decreased by $ 10000 . in which year was the budget for q equal to the budget for v ? | {
"A": "1992",
"B": "1993",
"C": "1994",
"D": "1995",
"E": "1996"
} | add(1990, const_4) | add(n0,const_4) | let the no of years it takes is x . 540 + 30 x = 780 - 10 x - - > 40 x = 240 and x = 6 . thus , it happens in 1996 . e . | general |
math_qa__CQOaqLSNIUrwTI5f | A shopkeeper sells 500 metres of cloth for Rs. 15000 at a loss of Rs.10 per metre. Find his cost price for one metre of cloth?
Choose the correct choice from the following.
A) s . 40 B) s . 12 C) s . 96 D) s . 50 E) s . 13 | <gadget id="calculator">15_000 / 500</gadget>
<output>30</output>
<gadget id="calculator">30 + 10</gadget>
<output>40</output>
<result>A</result> | A | 40 | A shopkeeper sells 500 metres of cloth for Rs. 15000 at a loss of Rs.10 per metre. Find his cost price for one metre of cloth? | {
"A": "s . 40",
"B": "s . 12",
"C": "s . 96",
"D": "s . 50",
"E": "s . 13"
} | add(divide(15000, 500), 10) | divide(n1,n0)|add(n2,#0)| | "sp per metre = 15000 / 500 = rs . 30 loss per metre = rs . 10 cp per metre = 30 + 10 = rs . 40 answer : a" | gain |
math_qa__mGKiibER1TAJx7oi | A larger cube has 216 cubic inch as a volume and in the cube there are 216 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 216 smaller cubes and the surface area of the larger cube, in square inch?
Pick one:
A) 54 B) 64 C) 81 D) 1080 E) 120 | <gadget id="calculator">1 ** (1/3)</gadget>
<output>1</output>
<gadget id="calculator">6 * (1 ** 2)</gadget>
<output>6</output>
<gadget id="calculator">6 * 216</gadget>
<output>1_296</output>
<gadget id="calculator">216 ** (1/3)</gadget>
<output>6</output>
<gadget id="calculator">6 * (6 ** 2)</gadget>
<output>216</output>
<gadget id="calculator">1_296 - 216</gadget>
<output>1_080</output>
<result>D</result> | D | 1,080 | A larger cube has 216 cubic inch as a volume and in the cube there are 216 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 216 smaller cubes and the surface area of the larger cube, in square inch? | {
"A": "54",
"B": "64",
"C": "81",
"D": "1080",
"E": "120"
} | subtract(multiply(surface_cube(cube_edge_by_volume(1)), 216), surface_cube(cube_edge_by_volume(216))) | cube_edge_by_volume(n2)|cube_edge_by_volume(n0)|surface_cube(#0)|surface_cube(#1)|multiply(n0,#2)|subtract(#4,#3)| | "volume of larger cube = 216 = 6 ^ 3 side of larger cube = 6 volume of smaller cube = 1 - - > side of smaller cube = 1 surface area of larger cube = 6 * 6 ^ 2 = 216 surface area of 27 smaller cubes = 216 * 6 * 1 = 1296 difference = 1296 - 216 = 1080 answer : d" | geometry |
math_qa__NvQZDJ1sy7pLFi8S | In a colony the municipality decided to number the houses and the shops. They want to number the shops with the numbers containing 3 between 1-100. The houses are 10-20 floored and at the back of the houses 8 feet is left for fire exit. How many shops can be numbered?
Choose the correct choice from the following:
A) 19 B) 20 C) 21 D) 22 E) 23 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 - 10</gadget>
<output>20</output>
<gadget id="calculator">20 - 1</gadget>
<output>19</output>
<result>A</result> | A | 19 | In a colony the municipality decided to number the houses and the shops. They want to number the shops with the numbers containing 3 between 1-100. The houses are 10-20 floored and at the back of the houses 8 feet is left for fire exit. How many shops can be numbered? | {
"A": "19",
"B": "20",
"C": "21",
"D": "22",
"E": "23"
} | subtract(subtract(multiply(3, 10), 10), 1) | multiply(n0,n3)|subtract(#0,n3)|subtract(#1,n1) | 3 numbers containing 3 - - - > 3 , 1323 , . . . = 10 numbers - - - - > 30 , 3132 . . . = 10 numbers total = 20 - 1 = 19 answer : a | general |
math_qa__PkmPUXQoy1oVSFRI | A sporting goods store sold 64 Frisbees in one week, some for $3 and the rest for $4 each. If receipts from Frisbee sales for the week totaled $196 what is the fewest number of $4 Frisbees that could have been sold? Options
A) 24 B) 12 C) 8 D) 2 E) 4 | <gadget id="calculator">64 * 3</gadget>
<output>192</output>
<gadget id="calculator">196 - 192</gadget>
<output>4</output>
<result>E</result> | E | 4 | A sporting goods store sold 64 Frisbees in one week, some for $3 and the rest for $4 each. If receipts from Frisbee sales for the week totaled $196 what is the fewest number of $4 Frisbees that could have been sold? | {
"A": "24",
"B": "12",
"C": "8",
"D": "2",
"E": "4"
} | subtract(196, multiply(64, 3)) | multiply(n0,n1)|subtract(n3,#0)| | "in this question however , because we are told that exactly 64 frisbees have been sold and revenue was exactly $ 204 , there is only one possible solution for the number of $ 3 and $ 4 frisbees sold . to solve , we have 2 equations and 2 unknowns let x = number of $ 3 frisbees sold let y = number of $ 4 frisbees sold x + y = 64 3 x + 4 y = 196 x = 64 - y 3 ( 64 - y ) + 4 y = 196 192 - 3 y + 4 y = 196 y = 4 answer : e" | general |
math_qa__HvlI9xr910iHUuVC | the average ( arithmetic man ) of 3 integers a , b , and c is exactly half the median . if a < b < c and a = 0 , what is the value of c / b ? Choose the correct choice from the following choices
A) 2 B) 3 / 2 C) 4 D) 5 E) can not be determined from the information given . | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 3</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<result>B</result> | B | 1.5 | the average ( arithmetic man ) of 3 integers a , b , and c is exactly half the median . if a < b < c and a = 0 , what is the value of c / b ? | {
"A": "2",
"B": "3 / 2",
"C": "4",
"D": "5",
"E": "can not be determined from the information given ."
} | multiply(subtract(multiply(divide(const_1, const_2), 3), const_1), 3) | divide(const_1,const_2)|multiply(n0,#0)|subtract(#1,const_1)|multiply(n0,#2) | the average of three integers a , b , and c is exactly twice the median - - > ( a + b + c ) / 3 = 1 b / 2 - - > since a = 0 , then ( 0 + b + c ) / 3 = 1 b / 2 - - > c = 3 b / 2 - - > c / b = 3 / 2 . answer : b . | general |
math_qa__fURJebvXJ2qiAEBS | Dan’s car gets 32 miles per gallon. If gas costs $4/gallon, then how many miles can Dan’s car go on $46 of gas?
Answers:
A) 124 B) 256 C) 368 D) 424 E) 512 | <gadget id="calculator">46 * 32</gadget>
<output>1_472</output>
<gadget id="calculator">1_472 / 4</gadget>
<output>368</output>
<result>C</result> | C | 368 | Dan’s car gets 32 miles per gallon. If gas costs $4/gallon, then how many miles can Dan’s car go on $46 of gas? | {
"A": "124",
"B": "256",
"C": "368",
"D": "424",
"E": "512"
} | divide(multiply(46, 32), 4) | multiply(n0,n2)|divide(#0,n1)| | "46 / 4 = 11.5 gallons 11.5 * 32 = 368 miles the answer is c ." | physics |
math_qa__ejJGKlcTaAK1xPdj | An object thrown directly upward is at a height of h feet after t seconds, where h = -12 (t-3)^2 + 120. At what height, in feet, is the object 2 seconds after it reaches its maximum height?
Choose the correct choice from the following
A) 48
B) 54
C) 60
D) 66
E) 72 | <gadget id="calculator">-12</gadget>
<output>-12</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">(-12) * 4</gadget>
<output>-48</output>
<gadget id="calculator">(-48) + 120</gadget>
<output>72</output>
<result>E</result> | E | 72 | An object thrown directly upward is at a height of h feet after t seconds, where h = -12 (t-3)^2 + 120. At what height, in feet, is the object 2 seconds after it reaches its maximum height? | {
"A": "48",
"B": "54",
"C": "60",
"D": "66",
"E": "72"
} | add(multiply(negate(12), power(subtract(add(3, 2), 3), 2)), 120) | add(n1,n2)|negate(n0)|subtract(#0,n1)|power(#2,n2)|multiply(#1,#3)|add(n3,#4)| | "we see that h will be a maximum h = 120 when t - 3 = 0 , that is when t = 3 . at t = 5 , h = - 12 * ( 5 - 3 ) ^ 2 + 120 = - 12 ( 4 ) + 120 = 72 the answer is e ." | general |
math_qa__Orl9NQOGej29jasF | If |x - 5| = 23 what is the sum of all the values of x. Pick one: A) 46 B) 10 C) 56 D) - 46 E) 28 | <gadget id="calculator">23 + 5</gadget>
<output>28</output>
<gadget id="calculator">23 - 5</gadget>
<output>18</output>
<gadget id="calculator">28 - 18</gadget>
<output>10</output>
<result>B</result> | B | 10 | If |x - 5| = 23 what is the sum of all the values of x. | {
"A": "46",
"B": "10",
"C": "56",
"D": "- 46",
"E": "28"
} | subtract(add(23, 5), subtract(23, 5)) | add(n0,n1)|subtract(n1,n0)|subtract(#0,#1)| | "there will be two cases x - 5 = 23 and x - 5 = - 23 solve for x = > x = 23 + 5 = > x = 28 or x = - 23 + 5 = > x = - 18 the sum of both values will be 28 + - 18 = 10 answer is b" | general |
math_qa__sOlnI47WsWvDPjNm | Find √? /11= 4 ? Choose the correct option.
A) 76 B) 1936 C) 1304 D) 1296 E) none | <gadget id="calculator">4 * 11</gadget>
<output>44</output>
<gadget id="calculator">44 ** 2</gadget>
<output>1_936</output>
<result>B</result> | B | 1,936 | Find √? /11= 4 ? | {
"A": "76",
"B": "1936",
"C": "1304",
"D": "1296",
"E": "none"
} | power(multiply(4, 11), const_2) | multiply(n0,n1)|power(#0,const_2) | answer let √ n / 11 = 4 then √ n = 11 x 4 = 44 ∴ n = 44 x 44 = 1936 . correct option : b | general |
math_qa__fT4bUJtJ3OX2uIOA | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price W per glass on the second day? Choose the correct choice from the following options: A) $ 015 B) $ 0.20 C) $ 0.30 D) $ 0.40 E) $ 0.45 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 0.6</gadget>
<output>1.2</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">1.2 / 3</gadget>
<output>0.4</output>
<result>D</result> | D | 0.4 | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price W per glass on the second day? | {
"A": "$ 015",
"B": "$ 0.20",
"C": "$ 0.30",
"D": "$ 0.40",
"E": "$ 0.45"
} | divide(multiply(add(const_1, const_1), 0.60), add(const_1, const_2)) | add(const_1,const_1)|add(const_1,const_2)|multiply(n0,#0)|divide(#2,#1)| | "on the first day 1 unit of orange juice and 1 unit of water was used to make 2 units of orangeade ; on the second day 1 unit of orange juice and 2 units of water was used to make 3 units of orangeade ; so , the ratio of the amount of orangeade made on the first day to the amount of orangeade made on the second day is 2 to 3 . naturally the ratio of the # of glasses of orangeade made on the first day to the # of glasses of orangeade made on the second day is 2 to 3 . we are told thatthe revenue from selling the orangeade was the same for both daysso the revenue from 2 glasses on the first day equals to the revenue from 3 glasses on the second day . say the price of the glass of the orangeade on the second day was $ x then 2 * 0.6 = 3 * x - - > x = $ 0.4 . answer : d ." | general |
math_qa__8Zcf6B0rnzpGZTxk | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 130 mph. On the way home, I flew 88 mph. What was my average speed for the trip? Pick.
A) 198 mph
B) 110 mph
C) 88 mph
D) 100 mph
E) 109 mph | <gadget id="calculator">130 + 88</gadget>
<output>218</output>
<gadget id="calculator">218 / 2</gadget>
<output>109</output>
<result>E</result> | E | 109 | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 130 mph. On the way home, I flew 88 mph. What was my average speed for the trip? | {
"A": "198 mph",
"B": "110 mph",
"C": "88 mph",
"D": "100 mph",
"E": "109 mph"
} | divide(add(130, 88), const_2) | add(n0,n1)|divide(#0,const_2)| | "( 130 mph + 88 mph ) / 2 = 109 mph correct answer is : e" | physics |
math_qa__scYwBn9mItiS0n3a | A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 10%. What was its profit on the items sold in February? Choose one:
A) 27.5 % B) 30 % C) 35 % D) 37.5 % E) 40 % | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">120 * (5/4)</gadget>
<output>150</output>
<gadget id="calculator">(9/10) * 150</gadget>
<output>135</output>
<gadget id="calculator">135 - 100</gadget>
<output>35</output>
<result>C</result> | C | 35 | A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 10%. What was its profit on the items sold in February? | {
"A": "27.5 %",
"B": "30 %",
"C": "35 %",
"D": "37.5 %",
"E": "40 %"
} | subtract(multiply(divide(subtract(const_100, 10), const_100), multiply(add(const_100, 20), divide(add(const_100, 25), const_100))), const_100) | add(n0,const_100)|add(n1,const_100)|subtract(const_100,n2)|divide(#2,const_100)|divide(#1,const_100)|multiply(#0,#4)|multiply(#3,#5)|subtract(#6,const_100)| | "assume the total price = 100 x price after 20 % markup = 120 x price after 25 % further markup = 1.25 * 120 x = 150 x price after the discount = 0.9 * 150 x = 135 x hence total profit = 35 % option c" | gain |
math_qa__CWMDDE70zOHQXL5a | A man has some hens and cows. If the number of heads be 44 and the number of feet equals 128, then the number of hens will be Choose the most appropriate option.
A) 22
B) 24
C) 26
D) 20
E) 28 | <gadget id="calculator">44 * 4</gadget>
<output>176</output>
<gadget id="calculator">176 - 128</gadget>
<output>48</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<result>B</result> | B | 24 | A man has some hens and cows. If the number of heads be 44 and the number of feet equals 128, then the number of hens will be | {
"A": "22",
"B": "24",
"C": "26",
"D": "20",
"E": "28"
} | divide(subtract(multiply(44, const_4), 128), const_2) | multiply(n0,const_4)|subtract(#0,n1)|divide(#1,const_2)| | "explanation : let number of hens = h and number of cows = c number of heads = 44 = > h + c = 44 - - - ( equation 1 ) number of feet = 128 = > 2 h + 4 c = 128 = > h + 2 c = 64 - - - ( equation 2 ) ( equation 2 ) - ( equation 1 ) gives 2 c - c = 64 - 44 = > c = 20 substituting the value of c in equation 1 , we get h + 22 = 44 = > h = 44 - 20 = 24 i . e . , number of hens = 24 answer : b" | general |
math_qa__OAc7zAwo4GV8Yy5m | In a 200 meters race A beats B by 35 m or 7 seconds.A’s time over the course is : Choose the correct choice from the following answers.
A) 40 sec B) 47 sec C) 33 sec D) 35 sec E) none of these | <gadget id="calculator">7 / 35</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 200</gadget>
<output>40</output>
<gadget id="calculator">40 - 7</gadget>
<output>33</output>
<result>C</result> | C | 33 | In a 200 meters race A beats B by 35 m or 7 seconds.A’s time over the course is : | {
"A": "40 sec",
"B": "47 sec",
"C": "33 sec",
"D": "35 sec",
"E": "none of these"
} | subtract(multiply(divide(7, 35), 200), 7) | divide(n2,n1)|multiply(n0,#0)|subtract(#1,n2)| | "solution b runs 35 m in 7 sec . ∴ b covers 200 m in ( 7 / 35 x 200 ) = 40 sec b ’ s time over the course = 40 sec . ∴ a ’ s time over the course = ( 40 - 7 ) sec = 33 sec answer c" | physics |
math_qa__wS9q4SRPj7WY5P3B | -84*29+365=? Choose the correct choice from the following answers
A) 2436
B) 2801
C) - 2801
D) - 2071
E) none of these | <gadget id="calculator">-84</gadget>
<output>-84</output>
<gadget id="calculator">(-84) * 29</gadget>
<output>-2_436</output>
<gadget id="calculator">(-2_436) + 365</gadget>
<output>-2_071</output>
<result>D</result> | D | -2,071 | -84*29+365=? | {
"A": "2436",
"B": "2801",
"C": "- 2801",
"D": "- 2071",
"E": "none of these"
} | add(multiply(negate(84), 29), 365) | negate(n0)|multiply(n1,#0)|add(n2,#1)| | "= > - 84 * ( 30 - 1 ) + 365 ; = > - ( 84 * 30 ) + 84 + 365 ; = > - 2520 + 449 = - 2071 . correct option : d" | general |
math_qa__pnHLarNFdHpp9A7P | Approximately how many cubic feet of water are needed to fill a circular swimming pool that is 80 feet across and 10 feet deep? Choose the correct choice from the following choices: A) 10000 B) 50000 C) 80000 D) 85000 E) 90000 | <gadget id="calculator">80 / 2</gadget>
<output>40</output>
<gadget id="calculator">pi * (40 ** 2) * 10</gadget>
<output>16000*pi = around 50_265.482457</output>
<result>B</result> | B | 50,000 | Approximately how many cubic feet of water are needed to fill a circular swimming pool that is 80 feet across and 10 feet deep? | {
"A": "10000",
"B": "50000",
"C": "80000",
"D": "85000",
"E": "90000"
} | volume_cylinder(divide(80, const_2), 10) | divide(n0,const_2)|volume_cylinder(#0,n1)| | "answer should be b . v = \ pir ^ 2 h = \ pi * 40 ^ 2 * 10 = approximately 50000" | geometry |
math_qa__N6lkkos73qQrrJww | If shares of two persons in profits are Rs.300 and Rs.500 then ratio of their capitals is Pick one.
A) 3 : 4 B) 3 : 5 C) 4 : 3 D) 1 : 3 E) 1 : 5 | <gadget id="calculator">300 / 500</gadget>
<output>3/5 = around 0.6</output>
<result>B</result> | B | 0.6 | If shares of two persons in profits are Rs.300 and Rs.500 then ratio of their capitals is | {
"A": "3 : 4",
"B": "3 : 5",
"C": "4 : 3",
"D": "1 : 3",
"E": "1 : 5"
} | divide(300, 500) | divide(n0,n1)| | "total profit = 1000 ratio = 300 / 500 = 3 : 5 answer : b" | other |
math_qa__vXMOHqFXSQTHy8uJ | There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability R that the both positions will be taken by members of just one party? Choose the correct choice from the following options
A) 1 / 25 B) 12 / 49 C) 1 / 4 D) 24 / 49 E) 1 / 2 | <gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 1</gadget>
<output>24</output>
<gadget id="calculator">50 - 1</gadget>
<output>49</output>
<gadget id="calculator">24 / 49</gadget>
<output>24/49 = around 0.489796</output>
<gadget id="calculator">25 / 50</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(24/49) * (1/2)</gadget>
<output>12/49 = around 0.244898</output>
<gadget id="calculator">(12/49) * 2</gadget>
<output>24/49 = around 0.489796</output>
<result>D</result> | D | 0.489796 | There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability R that the both positions will be taken by members of just one party? | {
"A": "1 / 25",
"B": "12 / 49",
"C": "1 / 4",
"D": "24 / 49",
"E": "1 / 2"
} | multiply(multiply(divide(subtract(divide(50, 2), const_1), subtract(50, const_1)), divide(divide(50, 2), 50)), 2) | divide(n1,n0)|subtract(n1,const_1)|divide(#0,n1)|subtract(#0,const_1)|divide(#3,#1)|multiply(#4,#2)|multiply(n0,#5)| | "r probability of one party having both spots : ( 1 / 2 ) * ( 24 / 49 ) = 12 / 49 ( 1 / 2 ) or ( 25 / 50 ) because it does not matter which party or which person gets the first spot . ( 24 / 49 ) because after one person from a particular party is chosen , there are 24 members of the same party left out of 49 total candidates . since this result can happen for both parties , ( 12 / 49 ) + ( 12 / 49 ) = ( 24 / 49 ) answer : d" | other |
math_qa__CB8LSTEm7Wr7FRap | A train 270 m long, running with a speed of 108 km / hr will pass a tree in Select.
A) 12 sec B) 9 sec C) 16 sec D) 20 sec E) none | <gadget id="calculator">108 * 1_000</gadget>
<output>108_000</output>
<gadget id="calculator">270 / 108_000</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">(1/400) * 3_600</gadget>
<output>9</output>
<result>B</result> | B | 9 | A train 270 m long, running with a speed of 108 km / hr will pass a tree in | {
"A": "12 sec",
"B": "9 sec",
"C": "16 sec",
"D": "20 sec",
"E": "none"
} | multiply(divide(270, multiply(108, const_1000)), const_3600) | multiply(n1,const_1000)|divide(n0,#0)|multiply(#1,const_3600)| | "sol . speed = ( 108 x 5 / 18 ) m / sec . = 30 m / sec . time taken = ( 270 x 1 / 30 ) sec = 9 sec answer b" | physics |
math_qa__BeMhZB3TxrmYTpAu | A container holding 12 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 12 ounces of a solution that is 1 part alcohol to 3 parts water. What is the ratio of alcohol to water in the resulting solution? Choose the correct choice:
A) 2 : 5
B) 3 : 7
C) 3 : 5
D) 4 : 7
E) 7 : 17 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">12 * (1/3)</gadget>
<output>4</output>
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">12 * (1/4)</gadget>
<output>3</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">24 - 7</gadget>
<output>17</output>
<gadget id="calculator">7 / 17</gadget>
<output>7/17 = around 0.411765</output>
<result>E</result> | E | 0.411765 | A container holding 12 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 12 ounces of a solution that is 1 part alcohol to 3 parts water. What is the ratio of alcohol to water in the resulting solution? | {
"A": "2 : 5",
"B": "3 : 7",
"C": "3 : 5",
"D": "4 : 7",
"E": "7 : 17"
} | divide(add(multiply(12, divide(1, add(1, 2))), multiply(12, divide(1, add(1, 3)))), subtract(add(12, 12), add(multiply(12, divide(1, add(1, 2))), multiply(12, divide(1, add(1, 3)))))) | add(n1,n2)|add(n1,n5)|add(n0,n3)|divide(n1,#0)|divide(n1,#1)|multiply(n0,#3)|multiply(n3,#4)|add(#5,#6)|subtract(#2,#7)|divide(#7,#8)| | "container 1 has 12 ounces in the ratio 1 : 2 or , x + 2 x = 12 gives x ( alcohol ) = 4 and remaining water = 8 container 2 has 12 ounces in the ratio 1 : 3 or , x + 3 x = 12 gives x ( alcohol ) = 3 and remaining water = 9 mixing both we have alcohol = 4 + 3 and water = 8 + 9 ratio thus alcohol / water = 7 / 17 answer e" | other |
math_qa__0MQuMLqroCipZcKH | A and B invests Rs.3000 and Rs.4500 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit? Pick: A) 6 : 8 B) 9 : 8 C) 7 : 9 D) 9 : 5 E) 1 : 1 | <gadget id="calculator">3_000 * 6</gadget>
<output>18_000</output>
<gadget id="calculator">3_000 * 2</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 * 6</gadget>
<output>36_000</output>
<gadget id="calculator">18_000 + 36_000</gadget>
<output>54_000</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">4_500 * 12</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 / 54_000</gadget>
<output>1</output>
<result>E</result> | E | 1 | A and B invests Rs.3000 and Rs.4500 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit? | {
"A": "6 : 8",
"B": "9 : 8",
"C": "7 : 9",
"D": "9 : 5",
"E": "1 : 1"
} | divide(add(multiply(3000, 6), multiply(multiply(3000, const_2), 6)), multiply(4500, add(6, 6))) | add(n2,n2)|multiply(n0,n2)|multiply(n0,const_2)|multiply(n2,#2)|multiply(n1,#0)|add(#1,#3)|divide(#5,#4)| | "( 3 * 6 + 6 * 6 ) : ( 4.5 * 12 ) 54 : 54 = > 1 : 1 answer : e" | gain |
math_qa__0IMPrwJWyM0cIlrW | On a test average (arithmetic mean) test score for 4 students is 85. What must be 5th student's score that average score for 5 students to be 86?
Options.
A) 70
B) 80
C) 90
D) 100
E) 110 | <gadget id="calculator">86 * 5</gadget>
<output>430</output>
<gadget id="calculator">4 * 85</gadget>
<output>340</output>
<gadget id="calculator">430 - 340</gadget>
<output>90</output>
<result>C</result> | C | 90 | On a test average (arithmetic mean) test score for 4 students is 85. What must be 5th student's score that average score for 5 students to be 86? | {
"A": "70",
"B": "80",
"C": "90",
"D": "100",
"E": "110"
} | subtract(multiply(86, 5), multiply(4, 85)) | multiply(n2,n4)|multiply(n0,n1)|subtract(#0,#1) | ( 4 * 85 + x ) / 5 = 86 x = ( 5 * 86 ) - ( 4 * 85 ) x = 430 - 340 total score required 430 - 340 = 90 correct answer is c | general |
math_qa__GvVzj5wfKRfPmqNZ | A 200 meter long train running at the speed of 120 kmph crosses another train running in the opposite direction at the speed of 80 kmph in 9 seconds.What is the lenght of other train.
Select: A) 210 m B) 300 m C) 230 m D) 240 m E) 250 m | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">9 * (500/9)</gadget>
<output>500</output>
<gadget id="calculator">500 - 200</gadget>
<output>300</output>
<result>B</result> | B | 300 | A 200 meter long train running at the speed of 120 kmph crosses another train running in the opposite direction at the speed of 80 kmph in 9 seconds.What is the lenght of other train. | {
"A": "210 m",
"B": "300 m",
"C": "230 m",
"D": "240 m",
"E": "250 m"
} | subtract(multiply(9, multiply(add(120, 80), const_0_2778)), 200) | add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)| | "relative speeds = ( 120 + 80 ) km / hr = 200 km / hr = ( 200 * 5 / 18 ) m / s = ( 500 / 9 ) m / s let length of train be xm x + 200 / 9 = 500 / 9 x = 300 ans is 300 m answer : b" | physics |
math_qa__gP8Y8Fqvpf1qaaXd | Sharmila works 10 hours per day on Monday, Wednesday and Friday, and 8 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $460 per week. How much does she earn in dollars per hour?
Options: A) 8 B) 9 C) 9.5 D) 10 E) 11 | <gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">30 + 16</gadget>
<output>46</output>
<gadget id="calculator">460 / 46</gadget>
<output>10</output>
<result>D</result> | D | 10 | Sharmila works 10 hours per day on Monday, Wednesday and Friday, and 8 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $460 per week. How much does she earn in dollars per hour? | {
"A": "8",
"B": "9",
"C": "9.5",
"D": "10",
"E": "11"
} | divide(460, add(multiply(10, const_3), multiply(8, const_2))) | multiply(n0,const_3)|multiply(n1,const_2)|add(#0,#1)|divide(n2,#2) | so , she works 30 hours in 3 days so , she works 16 hours in 2 days so in a week she works 46 hours ( 30 + 16 ) and earns $ 460 so , hourly wage is 460 / 46 = > 10 hence answer will be ( d ) 10 | physics |
math_qa__5rObhpYHpuMNuZlf | (0.86)(power 3) - (0.1)(power 3)/ (0.86)(power 2) + 0.086 + (0.1)(power 2) is: Select.
A) 0.86 B) 0.68 C) 0.96 D) 0.69 E) 0.76 | <gadget id="calculator">0.86 ** 3</gadget>
<output>0.636056</output>
<gadget id="calculator">0.1 ** 3</gadget>
<output>0.001</output>
<gadget id="calculator">0.636056 - 0.001</gadget>
<output>0.635056</output>
<gadget id="calculator">0.86 ** 2</gadget>
<output>0.7396</output>
<gadget id="calculator">0.7396 + 0.086</gadget>
<output>0.8256</output>
<gadget id="calculator">0.1 ** 2</gadget>
<output>0.01</output>
<gadget id="calculator">0.8256 + 0.01</gadget>
<output>0.8356</output>
<gadget id="calculator">0.635056 / 0.8356</gadget>
<output>0.76</output>
<result>E</result> | E | 0.76 | (0.86)(power 3) - (0.1)(power 3)/ (0.86)(power 2) + 0.086 + (0.1)(power 2) is: | {
"A": "0.86",
"B": "0.68",
"C": "0.96",
"D": "0.69",
"E": "0.76"
} | divide(subtract(power(0.86, 3), power(0.1, 3)), add(add(power(0.86, 2), 0.086), power(0.1, 2))) | power(n0,n1)|power(n2,n1)|power(n0,n5)|power(n2,n5)|add(n6,#2)|subtract(#0,#1)|add(#4,#3)|divide(#5,#6) | given expression = ( 0.86 ) ( power 3 ) - ( 0.1 ) ( power 3 ) / ( 0.86 ) ( power 2 ) + ( 0.86 x 0.1 ) + ( 0.1 ) ( power 2 ) = a ( power 3 ) - b ( power 3 ) / a ( power 2 ) + ab + b ( power 2 ) = ( a - b ) = ( 0.86 - 0.1 ) = 0.76 answer is e | general |
math_qa__zGRpX54dNd9cnFN1 | Find the ratio in which wheat of inferior quality (Rs.14/kg) be mixed with wheat of superior quality (Rs.28/kg) so that the shopkeeper gains Rs.2 by selling the resulting mixture at Rs.20/kg. Choose the correct choice from the following: A) 5 : 2 B) 5 : 9 C) 5 : 3 D) 5 : 1 E) 5 : 8 | <gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<result>A</result> | A | 2.5 | Find the ratio in which wheat of inferior quality (Rs.14/kg) be mixed with wheat of superior quality (Rs.28/kg) so that the shopkeeper gains Rs.2 by selling the resulting mixture at Rs.20/kg. | {
"A": "5 : 2",
"B": "5 : 9",
"C": "5 : 3",
"D": "5 : 1",
"E": "5 : 8"
} | divide(divide(divide(20, 2), const_2), 2) | divide(n3,n2)|divide(#0,const_2)|divide(#1,n2) | explanation : let the resulting mixture be 1 kg , and x kg be the amount of wheat of inferior quality . therefore , ( 1 - x ) kg is the amount of wheat of superior quality . as the shopkeeper gains rs . 2 , the cost of the mixture is rs . 18 14 * x + 28 * ( 1 - x ) = 18 14 x - 28 x + 28 = 18 14 x = 10 x = 5 / 7 ( 1 – x ) = 2 / 7 x : ( 1 - x ) = 5 / 7 : 2 / 7 = 5 : 2 answer : a | general |
math_qa__fxlxx2LQa7RGH2Ks | ----------------YES---------NO----UNSURE Subject M----500--------200-----100 Subject R----400--------100-----300 A total of 800 students were asked whether they found two subjects, M and R, interesting. Each answer was either yes or no or unsure, and the numbers of students who gave these answers are listed in the table above. If 150 students answered yes only for subject M, how many of the students did not answer yes for either subject? Choose the correct choice from the following options: A) 100 B) 250 C) 300 D) 400 E) 500 | <gadget id="calculator">500 - 150</gadget>
<output>350</output>
<gadget id="calculator">150 + 350</gadget>
<output>500</output>
<gadget id="calculator">400 - 350</gadget>
<output>50</output>
<gadget id="calculator">500 + 50</gadget>
<output>550</output>
<gadget id="calculator">800 - 550</gadget>
<output>250</output>
<result>B</result> | B | 250 | ----------------YES---------NO----UNSURE Subject M----500--------200-----100 Subject R----400--------100-----300 A total of 800 students were asked whether they found two subjects, M and R, interesting. Each answer was either yes or no or unsure, and the numbers of students who gave these answers are listed in the table above. If 150 students answered yes only for subject M, how many of the students did not answer yes for either subject? | {
"A": "100",
"B": "250",
"C": "300",
"D": "400",
"E": "500"
} | subtract(800, add(add(150, subtract(500, 150)), subtract(400, subtract(500, 150)))) | subtract(n0,n7)|add(n7,#0)|subtract(n3,#0)|add(#1,#2)|subtract(n6,#3)| | "since 150 students answered yes only for subject m , then the remaining 350 students who answered yes for subject m , also answered yes for subject r . so , 350 students answered yes for both subjects . if 350 students answered yes for both subjects , then 400 - 350 = 50 students answered yes only for subject r . so , we have that : 200 students answered yes only for subject m ; 50 students answered yes only for subject r ; 300 students answered yes for both subjects ; therefore 800 - ( 200 + 50 + 300 ) = 250 students did not answer yes for either subject . answer : b ." | general |
math_qa__F4YRgXidNJ5d2Z92 | In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 50% of all the employees are men .What % of all the employee went to the picnic? Pick: A) 30 % B) 34 % C) 35 % D) 36 % E) 37 % | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/2) * (1/5)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/2) * (2/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/10) + (1/5)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 100</gadget>
<output>30</output>
<result>A</result> | A | 30 | In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 50% of all the employees are men .What % of all the employee went to the picnic? | {
"A": "30 %",
"B": "34 %",
"C": "35 %",
"D": "36 %",
"E": "37 %"
} | multiply(add(multiply(divide(50, const_100), divide(20, const_100)), multiply(divide(subtract(const_100, 50), const_100), divide(40, const_100))), const_100) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(const_100,n2)|divide(#3,const_100)|multiply(#0,#1)|multiply(#4,#2)|add(#5,#6)|multiply(#7,const_100)| | "total men in company 50 % means total women in company 50 % ( assume total people in company 100 % ) no of men employees attended picnic = 50 x ( 20 / 100 ) = 10 no of women employees attend picnic = 50 x ( 40 / 100 ) = 20 total percentage of employees attend the picnic = 10 + 20 = 30 % answer : a" | gain |
math_qa__hoklheAVj8Mlw0W2 | A trader sells 80 meters of cloth for Rs. 10000 at the profit of Rs. 7 per metre of cloth. What is the cost price of one metre of cloth? Choose the correct choice from the following answers.
A) 118
B) 88
C) 90
D) 42
E) 22 | <gadget id="calculator">10_000 / 80</gadget>
<output>125</output>
<gadget id="calculator">125 - 7</gadget>
<output>118</output>
<result>A</result> | A | 118 | A trader sells 80 meters of cloth for Rs. 10000 at the profit of Rs. 7 per metre of cloth. What is the cost price of one metre of cloth? | {
"A": "118",
"B": "88",
"C": "90",
"D": "42",
"E": "22"
} | subtract(divide(10000, 80), 7) | divide(n1,n0)|subtract(#0,n2)| | "sp of 1 m of cloth = 8925 / 85 = rs . 125 cp of 1 m of cloth = sp of 1 m of cloth - profit on 1 m of cloth = rs . 125 - rs . 7 = rs . 118 answer : a" | physics |
math_qa__YrKvMqHD4XIYKzSj | If x and y are the two digits of the number 653xy. Such that this number is divisible by 80, then x+y is equal to Pick one: A) 3 B) 2 C) 4 D) 1 E) 0 | <gadget id="calculator">653 * 100</gadget>
<output>65_300</output>
<gadget id="calculator">65_300 % 80</gadget>
<output>20</output>
<gadget id="calculator">20 / 10</gadget>
<output>2</output>
<result>B</result> | B | 2 | If x and y are the two digits of the number 653xy. Such that this number is divisible by 80, then x+y is equal to | {
"A": "3",
"B": "2",
"C": "4",
"D": "1",
"E": "0"
} | divide(reminder(multiply(653, const_100), 80), const_10) | multiply(n0,const_100)|reminder(#0,n1)|divide(#1,const_10) | since 653 xy is divisible by 5 as well as 2 . so y = 0 now 653 x 0 must be divisible by 8 so 3 x 0 must be 8 this happens when x = 2 hence , x + y = 2 + 0 = 2 answer b 2 | general |
math_qa__tu2XjDoJ0W2mJnK7 | The price of lunch for 15 people was $208.00, including a 15 percent gratuity for service. What was the average price per person, EXCLUDING the gratuity? Choose the correct choice from the following answers: A) $ 11.73 B) $ 12.60 C) $ 13.80 D) $ 14.00 E) $ 15.87 | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">208 / 115</gadget>
<output>208/115 = around 1.808696</output>
<gadget id="calculator">(208/115) * 100</gadget>
<output>4_160/23 = around 180.869565</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(4_160/23) * (1/15)</gadget>
<output>832/69 = around 12.057971</output>
<result>B</result> | B | 12.6 | The price of lunch for 15 people was $208.00, including a 15 percent gratuity for service. What was the average price per person, EXCLUDING the gratuity? | {
"A": "$ 11.73",
"B": "$ 12.60",
"C": "$ 13.80",
"D": "$ 14.00",
"E": "$ 15.87"
} | multiply(multiply(divide(208.00, add(const_100, 15)), const_100), divide(const_1, 15)) | add(n0,const_100)|divide(const_1,n0)|divide(n1,#0)|multiply(#2,const_100)|multiply(#1,#3)| | "take the initial price before the gratuity is 100 the gratuity is calculated on the final price , so as we assumed the final bill before adding gratuity is 100 so gratuity is 15 % of 100 is 15 so the total price of meals is 115 so the given amount i . e 208 is for 115 then we have to calculate for 100 for 115 208 for 100 x so by cross multiplication we get 115 x = 100 * 208 = > x = 100 * 208 / 110 by simplifying we get x as 189 which is the price of lunch before gratuity so the gratuity is 19 so as the question ask the average price person excluding gratuity is 189 / 15 = 12.6 so our answer is b )" | general |
math_qa__9on84eCcVSYulC88 | If the area of a circle decreases by 36%, then the radius of a circle decreases by Choose the correct option.
A) 20 % B) 18 % C) 36 % D) 64 % E) none of these | <gadget id="calculator">100 - 36</gadget>
<output>64</output>
<gadget id="calculator">64 / 100</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">(16/25) ** (1/2)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>A</result> | A | 20 | If the area of a circle decreases by 36%, then the radius of a circle decreases by | {
"A": "20 %",
"B": "18 %",
"C": "36 %",
"D": "64 %",
"E": "none of these"
} | multiply(subtract(const_1, sqrt(divide(subtract(const_100, 36), const_100))), const_100) | subtract(const_100,n0)|divide(#0,const_100)|sqrt(#1)|subtract(const_1,#2)|multiply(#3,const_100)| | "if area of a circle decreased by x % then the radius of a circle decreases by ( 100 − 10 √ 100 − x ) % = ( 100 − 10 √ 100 − 36 ) % = ( 100 − 10 √ 64 ) % = 100 - 80 = 20 % answer a" | geometry |
math_qa__nVyDsVTrYDJJ1ca0 | If n is a positive integer and n^2 is divisible by 450, then what is the largest positive integer that must divide n? Pick: A) 10 B) 20 C) 30 D) 40 E) 50 | <gadget id="calculator">450 / 2</gadget>
<output>225</output>
<gadget id="calculator">225 ** (1/2)</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<result>C</result> | C | 30 | If n is a positive integer and n^2 is divisible by 450, then what is the largest positive integer that must divide n? | {
"A": "10",
"B": "20",
"C": "30",
"D": "40",
"E": "50"
} | multiply(sqrt(divide(450, 2)), 2) | divide(n1,n0)|sqrt(#0)|multiply(n0,#1)| | "450 = 2 * 3 ^ 2 * 5 ^ 2 if 450 divides n ^ 2 , then n must be divisible by 2 * 3 * 5 = 30 the answer is c ." | general |
math_qa__7NwgQfCrixC2icfI | If the given two numbers are respectively 7% and 14% of a third number, then what percentage is the first of the second ? Answers.
A) 20 % B) 25 % C) 18 % D) 50 % E) none of these | <gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/100) / (7/50)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>D</result> | D | 50 | If the given two numbers are respectively 7% and 14% of a third number, then what percentage is the first of the second ? | {
"A": "20 %",
"B": "25 %",
"C": "18 %",
"D": "50 %",
"E": "none of these"
} | multiply(divide(divide(7, const_100), divide(14, const_100)), const_100) | divide(n0,const_100)|divide(n1,const_100)|divide(#0,#1)|multiply(#2,const_100)| | "here , l = 7 and m = 14 therefore , first number = l / m x 100 % of second number = 7 / 14 x 100 % of second number = 50 % of second number answer : d" | gain |
math_qa__YGT9nkiKBNbotvpd | A trailer carries 3, 4 and 6 crates on a trip. Each crate weighs no less than 120 kg. What is the maximum weight of the crates on a single trip? Choose the correct choice
A) 1250 B) 625 C) 600 D) 7500 E) 720 | <gadget id="calculator">6 * 120</gadget>
<output>720</output>
<result>E</result> | E | 720 | A trailer carries 3, 4 and 6 crates on a trip. Each crate weighs no less than 120 kg. What is the maximum weight of the crates on a single trip? | {
"A": "1250",
"B": "625",
"C": "600",
"D": "7500",
"E": "720"
} | multiply(6, 120) | multiply(n2,n3)| | "max no . of crates = 6 . max weight = 120 kg max . weight carried = 6 * 120 = 720 kg = e" | general |
math_qa__S49rsGEEIVKyJ4dI | The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 21 years. The ratio of their ages after 8 years will be Choose the correct choice from the following choices:
A) 2 : 3 B) 20 : 17 C) 5 : 4 D) 3 : 5 E) 6 : 11 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">21 / 7</gadget>
<output>3</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 8</gadget>
<output>17</output>
<gadget id="calculator">20 / 17</gadget>
<output>20/17 = around 1.176471</output>
<result>B</result> | B | 1.176471 | The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 21 years. The ratio of their ages after 8 years will be | {
"A": "2 : 3",
"B": "20 : 17",
"C": "5 : 4",
"D": "3 : 5",
"E": "6 : 11"
} | divide(add(multiply(4, divide(21, add(4, 3))), 8), add(multiply(3, divide(21, add(4, 3))), 8)) | add(n0,n1)|divide(n2,#0)|multiply(n0,#1)|multiply(n1,#1)|add(n3,#2)|add(n3,#3)|divide(#4,#5)| | "let mini ’ s age = 4 x and minakshi ’ s age = 3 x then 4 x + 3 x = 21 x = 3 mini ’ s age = 12 years and minakshi ’ s age = 9 years ratio of their ages after 8 years = ( 12 + 8 ) : ( 9 + 8 ) = 20 : 17 answer : b" | general |
math_qa__eog1TAncN7QPimMQ | A train with a length of 100 meters, is traveling at a speed of 72 km/hr. The train enters a tunnel 1.7 km long. How many minutes does it take the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? Choose the correct choice from the following
A) 0.9 B) 1.2 C) 1.5 D) 1.8 E) 2.1 | <gadget id="calculator">100 / 1_000</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1.7 + (1/10)</gadget>
<output>1.8</output>
<gadget id="calculator">1.8 / 72</gadget>
<output>0.025</output>
<gadget id="calculator">0.025 * 60</gadget>
<output>1.5</output>
<result>C</result> | C | 1.5 | A train with a length of 100 meters, is traveling at a speed of 72 km/hr. The train enters a tunnel 1.7 km long. How many minutes does it take the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? | {
"A": "0.9",
"B": "1.2",
"C": "1.5",
"D": "1.8",
"E": "2.1"
} | multiply(divide(add(1.7, divide(100, const_1000)), 72), const_60) | divide(n0,const_1000)|add(n2,#0)|divide(#1,n1)|multiply(#2,const_60)| | "72 km / hr = 1.2 km / min the total distance is 1.8 km . 1.8 / 1.2 = 1.5 minutes the answer is c ." | physics |
math_qa__HsFvCUzPzJgLEB14 | The contents of two vessels containing copper and tin in the ratio 1:2 and 2:5 are mixed in the ratio 1:4. The resulting mixture will have copper and tin in the ratio? Pick one
A) 15 : 32
B) 21 : 28
C) 31 : 74
D) 33 : 37
E) 41 : 92 | <gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">4 + 10</gadget>
<output>14</output>
<gadget id="calculator">6 / 14</gadget>
<output>3/7 = around 0.428571</output>
<result>C</result> | C | 0.418919 | The contents of two vessels containing copper and tin in the ratio 1:2 and 2:5 are mixed in the ratio 1:4. The resulting mixture will have copper and tin in the ratio? | {
"A": "15 : 32",
"B": "21 : 28",
"C": "31 : 74",
"D": "33 : 37",
"E": "41 : 92"
} | divide(add(multiply(1, 2), multiply(2, 2)), add(multiply(2, 2), multiply(5, 2))) | multiply(n0,n1)|multiply(n2,n2)|multiply(n1,n1)|multiply(n2,n3)|add(#0,#1)|add(#2,#3)|divide(#4,#5)| | "the ratio of copper and tin the new vessel = ( 1 / 3 * 1 / 5 + 2 / 7 * 4 / 5 ) : ( 2 / 3 * 1 / 5 + 5 / 7 * 4 / 5 ) = 31 / 105 : 74 / 105 = 31 : 74 answer is c" | other |
math_qa__Z1HceiSFujJ7oCrQ | A can do a piece of work in 4 days. B can do it in 8 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it? Select.
A) 22 days
B) 8 days
C) 67 days
D) 1 days
E) 18 days | <gadget id="calculator">4 * 8</gadget>
<output>32</output>
<gadget id="calculator">32 / 4</gadget>
<output>8</output>
<gadget id="calculator">32 / 8</gadget>
<output>4</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">32 - 24</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>B</result> | B | 8 | A can do a piece of work in 4 days. B can do it in 8 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it? | {
"A": "22 days",
"B": "8 days",
"C": "67 days",
"D": "1 days",
"E": "18 days"
} | divide(multiply(4, 8), divide(subtract(multiply(4, 8), multiply(add(divide(multiply(4, 8), 4), divide(multiply(4, 8), 8)), 2)), 2)) | multiply(n0,n1)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)|multiply(n2,#3)|subtract(#0,#4)|divide(#5,n2)|divide(#0,#6)| | "c = 1 / 2 - 1 / 4 - 1 / 8 = 1 / 8 = > 8 days answer : b" | physics |
math_qa__ReGTwUVBQ7vj8yUj | If X and Y are sets of integers, X # Y denotes the set of integers that belong to set X or set Y, but not both. If X consists of 8 integers, Y consists of 18 integers, and 6 of the integers are in both X and Y, then X # Y consists of how many integers? Answers: A) 6 B) 14 C) 22 D) 30 E) 174 | <gadget id="calculator">18 - 6</gadget>
<output>12</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<result>B</result> | B | 14 | If X and Y are sets of integers, X # Y denotes the set of integers that belong to set X or set Y, but not both. If X consists of 8 integers, Y consists of 18 integers, and 6 of the integers are in both X and Y, then X # Y consists of how many integers? | {
"A": "6",
"B": "14",
"C": "22",
"D": "30",
"E": "174"
} | add(subtract(18, 6), subtract(8, 6)) | subtract(n1,n2)|subtract(n0,n2)|add(#0,#1)| | "the number of integers that belong to set x only is 8 - 6 = 2 ; the number of integers that belong to set y only is 18 - 6 = 12 ; the number of integers that belong to set x or set y , but not both is 2 + 12 = 14 . answer : b ." | other |
math_qa__75quPiyiqBTcjjiu | A train with a length of 100 meters, is traveling at a speed of 72 km/hr. The train enters a tunnel 3.5 km long. How many minutes does it take the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? Choose the correct choice from the following answers.
A) 3 B) 4.2 C) 3.4 D) 5.5 E) 5.7 | <gadget id="calculator">100 / 1_000</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">3.5 + (1/10)</gadget>
<output>3.6</output>
<gadget id="calculator">3.6 / 72</gadget>
<output>0.05</output>
<gadget id="calculator">0.05 * 60</gadget>
<output>3</output>
<result>A</result> | A | 3 | A train with a length of 100 meters, is traveling at a speed of 72 km/hr. The train enters a tunnel 3.5 km long. How many minutes does it take the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? | {
"A": "3",
"B": "4.2",
"C": "3.4",
"D": "5.5",
"E": "5.7"
} | multiply(divide(add(3.5, divide(100, const_1000)), 72), const_60) | divide(n0,const_1000)|add(n2,#0)|divide(#1,n1)|multiply(#2,const_60)| | "72 km / hr = 1.2 km / min the total distance is 3.6 km . 3.6 / 1.2 = 3 minutes the answer is a ." | physics |
math_qa__l5LMrY8uiXXgABhm | If 0.5% of A =80 paise, then the value of A is ? Choose the correct choice from the following choices:
A) rs . 170 B) rs . 160 C) rs . 1.70 D) rs . 4.25 E) none | <gadget id="calculator">80 / 0.5</gadget>
<output>160</output>
<result>B</result> | B | 160 | If 0.5% of A =80 paise, then the value of A is ? | {
"A": "rs . 170",
"B": "rs . 160",
"C": "rs . 1.70",
"D": "rs . 4.25",
"E": "none"
} | divide(80, 0.5) | divide(n1,n0)| | "answer ∵ 0.5 / 100 of a = 80 / 100 ∴ a = rs . ( 80 / 0.5 ) = rs . 160 correct option : b" | gain |
math_qa__dLeRXrSyHaKezdqa | Find compound interest on $ 8000 at 15% per annum for 2 years 4 months, compounded annually.
Answers:
A) 3109 B) 3209 C) 3108 D) 3107 E) 3100 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">8_000 * (3/20)</gadget>
<output>1_200</output>
<gadget id="calculator">8_000 + 1_200</gadget>
<output>9_200</output>
<gadget id="calculator">9_200 * (3/20)</gadget>
<output>1_380</output>
<gadget id="calculator">1_200 + 1_380</gadget>
<output>2_580</output>
<gadget id="calculator">9_200 + 1_380</gadget>
<output>10_580</output>
<gadget id="calculator">(3/20) / 3</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">10_580 * (1/20)</gadget>
<output>529</output>
<gadget id="calculator">2_580 + 529</gadget>
<output>3_109</output>
<result>A</result> | A | 3,109 | Find compound interest on $ 8000 at 15% per annum for 2 years 4 months, compounded annually. | {
"A": "3109",
"B": "3209",
"C": "3108",
"D": "3107",
"E": "3100"
} | add(add(multiply(8000, divide(15, const_100)), multiply(add(8000, multiply(8000, divide(15, const_100))), divide(15, const_100))), multiply(add(add(8000, multiply(8000, divide(15, const_100))), multiply(add(8000, multiply(8000, divide(15, const_100))), divide(15, const_100))), divide(divide(15, const_100), const_3))) | divide(n1,const_100)|divide(#0,const_3)|multiply(n0,#0)|add(n0,#2)|multiply(#3,#0)|add(#2,#4)|add(#3,#4)|multiply(#6,#1)|add(#5,#7) | time = 2 years 4 months = 2 ( 4 / 12 ) years = 2 ( 1 / 3 ) years . amount = $ [ 8000 x ( 1 + ( 15 / 100 ) ) 2 x ( 1 + ( ( 1 / 3 ) * 15 ) / 100 ) ] = $ [ 8000 * ( 23 / 20 ) * ( 23 / 20 ) * ( 21 / 20 ) ] = $ 11109 . . : . c . i . = rs . ( 11109 - 8000 ) = $ 3109 . answer a . | gain |
math_qa__AU8kgTCVm75ucB8x | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 45kg. What is the weight of the new person? Select: A) 75 kg B) 65 kg C) 85 kg D) 80 kg E) 60 kg | <gadget id="calculator">8 * 2.5</gadget>
<output>20</output>
<gadget id="calculator">20 + 45</gadget>
<output>65</output>
<result>B</result> | B | 65 | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 45kg. What is the weight of the new person? | {
"A": "75 kg",
"B": "65 kg",
"C": "85 kg",
"D": "80 kg",
"E": "60 kg"
} | add(multiply(8, 2.5), 45) | multiply(n0,n1)|add(n2,#0)| | "explanation : total increase in weight = 8 ã — 2.5 = 20 if x is the weight of the new person , total increase in weight = x â ˆ ’ 45 = > 20 = x - 45 = > x = 20 + 45 = 65 answer : option b" | general |
math_qa__0Kdiymgst95JJBGT | In what time will a train 100 m long cross an electric pole, it its speed be 54 km/hr?
Choose the correct choice from the following
A) 2.5 B) 2.9 C) 6.67 D) 2.8 E) 2.1 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">100 / 15</gadget>
<output>20/3 = around 6.666667</output>
<result>C</result> | C | 6.67 | In what time will a train 100 m long cross an electric pole, it its speed be 54 km/hr? | {
"A": "2.5",
"B": "2.9",
"C": "6.67",
"D": "2.8",
"E": "2.1"
} | divide(100, multiply(54, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 54 * 5 / 18 = 15 m / sec time taken = 100 / 15 = 6.67 sec . answer : c" | physics |
math_qa__Kcldj6MtUOz5DJhT | Find the area of a triangle whose sides are 41 cm, 28 cm, 15 cm. Also, find the length of the altitude corresponding to the largest side of the triangle.
Select.
A) 4.1 cm B) 5.1 cm C) 6.1 cm D) 7.1 cm E) 8.1 cm | <gadget id="calculator">(((41 + 28 + 15) / 2) * ((41 + 28 + 15) / 2 - 41) * ((41 + 28 + 15) / 2 - 28) * ((41 + 28 + 15) / 2 - 15)) ** (1/2)</gadget>
<output>126</output>
<gadget id="calculator">126 * 2</gadget>
<output>252</output>
<gadget id="calculator">252 / 41</gadget>
<output>252/41 = around 6.146341</output>
<result>C</result> | C | 6.1 | Find the area of a triangle whose sides are 41 cm, 28 cm, 15 cm. Also, find the length of the altitude corresponding to the largest side of the triangle. | {
"A": "4.1 cm",
"B": "5.1 cm",
"C": "6.1 cm",
"D": "7.1 cm",
"E": "8.1 cm"
} | divide(multiply(triangle_area_three_edges(41, 28, 15), const_2), 41) | triangle_area_three_edges(n0,n1,n2)|multiply(#0,const_2)|divide(#1,n0) | semi - perimeter of the triangle = ( a + b + c ) / 2 = ( 41 + 28 + 15 ) / 2 = 84 / 2 = 42 cm therefore , area of the triangle = √ ( s ( s - a ) ( s - b ) ( s - c ) ) = √ ( 42 ( 42 - 41 ) ( 42 - 28 ) ( 42 - 15 ) ) cm ² = √ ( 42 × 1 × 27 × 14 ) cm ² = √ ( 3 × 3 × 3 × 3 × 2 × 2 × 7 × 7 ) cm ² = 3 × 3 × 2 × 7 cm ² = 126 cm ² now , area of triangle = 1 / 2 × b × h therefore , h = 2 a / b = ( 2 × 126 ) / 41 = 252 / 41 = 6.1 cm answer : option c | geometry |
math_qa__BkRplv0H5j7Eye4R | If John covers a certain distance in 1 hr. 24 min. by covering two third of the distance at 4 kmph and the rest at 5 kmph, then find the total distance Choose the correct answer:
A) 4 km
B) 6 km
C) 6.8 km
D) 7.2 km
E) none of these | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">24 / 60</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(2/3) * (7/5)</gadget>
<output>14/15 = around 0.933333</output>
<gadget id="calculator">4 * (14/15)</gadget>
<output>56/15 = around 3.733333</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * (7/5)</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">(7/15) * 5</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">(56/15) + (7/3)</gadget>
<output>91/15 = around 6.066667</output>
<result>B</result> | B | 6 | If John covers a certain distance in 1 hr. 24 min. by covering two third of the distance at 4 kmph and the rest at 5 kmph, then find the total distance | {
"A": "4 km",
"B": "6 km",
"C": "6.8 km",
"D": "7.2 km",
"E": "none of these"
} | add(multiply(4, multiply(divide(const_2, const_3), add(1, divide(24, const_60)))), multiply(multiply(subtract(const_1, divide(const_2, const_3)), add(1, divide(24, const_60))), 5)) | divide(n1,const_60)|divide(const_2,const_3)|add(n0,#0)|subtract(const_1,#1)|multiply(#2,#1)|multiply(#2,#3)|multiply(n2,#4)|multiply(n3,#5)|add(#6,#7) | explanation : let the total distance be y km . then , ( 2 / 3 ) y / 4 + ( 1 / 3 ) y / 5 = 7 / 5 y / 6 + y / 15 = 7 / 5 7 y = 42 y = 6 km answer b | physics |
math_qa__kJyDIiY6F4QVFpNe | In how many ways 4 boys and 3 girls can be seated in a row so that they are alternative? Choose the correct choice from the following choices:
A) 120
B) 144
C) 160
D) 210
E) 180 | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">24 * 6</gadget>
<output>144</output>
<result>B</result> | B | 144 | In how many ways 4 boys and 3 girls can be seated in a row so that they are alternative? | {
"A": "120",
"B": "144",
"C": "160",
"D": "210",
"E": "180"
} | multiply(factorial(4), factorial(3)) | factorial(n0)|factorial(n1)|multiply(#0,#1)| | "4 boys can be seated in 4 ! three girls can be seated in 3 ! required number = 4 ! 3 ! = 144 answer is b" | probability |
math_qa__6chEeWmGsr2YSC75 | If (10^4 * 3.456789)^10 is written as a single term, how many digits would be to the right of the decimal place?
Answers
A) 12 B) 16 C) 20 D) 32 E) 48 | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<result>C</result> | C | 20 | If (10^4 * 3.456789)^10 is written as a single term, how many digits would be to the right of the decimal place? | {
"A": "12",
"B": "16",
"C": "20",
"D": "32",
"E": "48"
} | multiply(10, const_2) | multiply(n3,const_2)| | "3.456789 ^ 10 has 6 * 10 = 60 decimal places . 10 ^ 40 moves the decimal place to the right 40 places . ( 10 ^ 4 * 3.456789 ) ^ 10 has 60 - 40 = 20 digits after the decimal point . the answer is c ." | general |
math_qa__Ua97dd43znOqAeZJ | A certain drink of type A is prepared by mixing 4 parts milk with 3 parts fruit juice. Another drink of type B is prepared by mixing 4 parts of fruit juice and 3 parts of milk. How many liters of fruit juice must be added to 63 liters of drink A to convert it to drink B?
Choose the correct choice from the following answers: A) 7 B) 14 C) 21 D) 28 E) 35 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">(4/7) * 63</gadget>
<output>36</output>
<gadget id="calculator">36 * 4</gadget>
<output>144</output>
<gadget id="calculator">144 / 3</gadget>
<output>48</output>
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 63</gadget>
<output>27</output>
<gadget id="calculator">48 - 27</gadget>
<output>21</output>
<result>C</result> | C | 21 | A certain drink of type A is prepared by mixing 4 parts milk with 3 parts fruit juice. Another drink of type B is prepared by mixing 4 parts of fruit juice and 3 parts of milk. How many liters of fruit juice must be added to 63 liters of drink A to convert it to drink B? | {
"A": "7",
"B": "14",
"C": "21",
"D": "28",
"E": "35"
} | subtract(divide(multiply(multiply(divide(4, add(4, 3)), 63), 4), 3), multiply(divide(3, add(4, 3)), 63)) | add(n0,n1)|divide(n0,#0)|divide(n1,#0)|multiply(n4,#1)|multiply(n4,#2)|multiply(n0,#3)|divide(#5,n1)|subtract(#6,#4)| | "in 63 liters of drink a , there are 36 liters of milk and 27 liters of juice . with 36 liters of milk , we need a total of 48 liters of juice to make drink b . we need to add 21 liters of juice . the answer is c ." | general |
math_qa__110fope1s4QZ9Rv1 | James went on a diet 12 months ago when he weighed 222 pounds. If he now weighs 198 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 190 pounds?
Choose the correct choice from the following answers
A) 3 B) 3.5 C) 4 D) 4.5 E) 5 | <gadget id="calculator">222 - 198</gadget>
<output>24</output>
<gadget id="calculator">198 - 190</gadget>
<output>8</output>
<gadget id="calculator">24 / 8</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<result>C</result> | C | 4 | James went on a diet 12 months ago when he weighed 222 pounds. If he now weighs 198 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 190 pounds? | {
"A": "3",
"B": "3.5",
"C": "4",
"D": "4.5",
"E": "5"
} | divide(12, divide(subtract(222, 198), subtract(198, 190))) | subtract(n1,n2)|subtract(n2,n3)|divide(#0,#1)|divide(n0,#2) | 222 - 198 = 24 pounds lost in 12 months 24 / 12 = 2 , so joe is losing weight at a rate of 2 pounds per month . . . . in approximately how many months will he weigh 190 pounds ? a simple approach is to just list the weights . now : 198 lbs in 1 month : 196 lbs in 2 months : 194 lbs in 3 months : 192 lbs in 4 months : 190 lbs answer : c | general |
math_qa__gHzGpcdMLq6Ffjyv | A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 800 m long? Choose the correct choice from the following options:
A) 266 sec B) 200 sec C) 776 sec D) 166 sec E) 997 sec | <gadget id="calculator">1_200 + 800</gadget>
<output>2_000</output>
<gadget id="calculator">1_200 / 120</gadget>
<output>10</output>
<gadget id="calculator">2_000 / 10</gadget>
<output>200</output>
<result>B</result> | B | 200 | A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 800 m long? | {
"A": "266 sec",
"B": "200 sec",
"C": "776 sec",
"D": "166 sec",
"E": "997 sec"
} | divide(add(1200, 800), divide(1200, 120)) | add(n0,n2)|divide(n0,n1)|divide(#0,#1)| | "l = s * t s = 1200 / 120 s = 10 m / sec . total length ( d ) = 2000 m t = d / s t = 2000 / 10 t = 200 sec answer : b" | physics |
math_qa__t19ROAsOsV1cwBWi | At what rate percent of simple interest will a sum of money double itself in 11 years? Choose the correct choice from the following answers
A) 9.09 % B) 4.54 % C) 8 . 2 % D) 4.94 % E) 5.54 % | <gadget id="calculator">100 / 11</gadget>
<output>100/11 = around 9.090909</output>
<result>A</result> | A | 9.09 | At what rate percent of simple interest will a sum of money double itself in 11 years? | {
"A": "9.09 %",
"B": "4.54 %",
"C": "8 . 2 %",
"D": "4.94 %",
"E": "5.54 %"
} | divide(const_100, 11) | divide(const_100,n0)| | "let sum = x . then , s . i . = x . rate = ( 100 * s . i . ) / ( p * t ) = ( 100 * x ) / ( x * 11 ) = 100 / 11 = 9.09 % answer : a" | gain |
math_qa__r9qQyowqOL6dgrm2 | A monkey start climbing up a tree 22 ft tall.Each hour it hops 3 ft and slips back 2 ft. How much time would it take the monkey to reach the top. Options:
A) 15 hrs B) 18 hrs C) 20 hrs D) 17 hrs E) 16 hrs | <gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">22 / 1</gadget>
<output>22</output>
<gadget id="calculator">22 - 2</gadget>
<output>20</output>
<result>C</result> | C | 20 | A monkey start climbing up a tree 22 ft tall.Each hour it hops 3 ft and slips back 2 ft. How much time would it take the monkey to reach the top. | {
"A": "15 hrs",
"B": "18 hrs",
"C": "20 hrs",
"D": "17 hrs",
"E": "16 hrs"
} | subtract(divide(22, subtract(3, 2)), 2) | subtract(n1,n2)|divide(n0,#0)|subtract(#1,n2)| | "if monkey hops 3 ft and slips back 2 ft in a hour , it means the monkey hops ( 3 ft - 2 ft ) = 1 ft / hr . similarly in 19 hrs it wil be 19 ft . bt since the height of the tree is 22 ft , so if the monkey hops up the tree in the next hr i . e 20 th hr then it reaches at the top of the tree . hence it takes 20 hrs for monkey to reach at the top answer : c" | physics |
math_qa__hAOnLCSfArHiY3E0 | The first doughnut is priced at $1 and then if you purchase additional doughnuts as dozens then the price is $6/dozen. What is the total number of doughnuts purchased if you paid $26?
Choose the most appropriate option:
A) 50 B) 52 C) 54 D) 56 E) 58 | <gadget id="calculator">26 / 6</gadget>
<output>13/3 = around 4.333333</output>
<gadget id="calculator">(13/3) * 12</gadget>
<output>52</output>
<result>A</result> | A | 50 | The first doughnut is priced at $1 and then if you purchase additional doughnuts as dozens then the price is $6/dozen. What is the total number of doughnuts purchased if you paid $26? | {
"A": "50",
"B": "52",
"C": "54",
"D": "56",
"E": "58"
} | multiply(divide(26, 6), const_12) | divide(n2,n1)|multiply(#0,const_12)| | "$ 26 = 4 * $ 6 + $ 2 the number of doughnuts is 4 * 12 + 2 = 50 the answer is a ." | general |
math_qa__uCBo54HlDswieJWV | When you draw 2 dices together, find the probability of getting a total of 6? Choose the most appropriate option:
A) 3 / 13
B) 2 / 31
C) 5 / 36
D) 7 / 41
E) 7 / 43 | <gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">2 / 36</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">3 / 36</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/18) + (1/12)</gadget>
<output>5/36 = around 0.138889</output>
<result>C</result> | C | 0.138889 | When you draw 2 dices together, find the probability of getting a total of 6? | {
"A": "3 / 13",
"B": "2 / 31",
"C": "5 / 36",
"D": "7 / 41",
"E": "7 / 43"
} | add(divide(2, power(6, 2)), divide(const_3, power(6, 2))) | power(n1,n0)|divide(n0,#0)|divide(const_3,#0)|add(#1,#2) | s = { ( 1,1 ) , ( 1,2 ) , ( 1,3 ) , ( 1,4 ) , ( 1,5 ) , ( 1,6 ) , ( 4,1 ) , ( 4,2 ) , ( 4,3 ) , ( 4,4 ) , ( 4,5 ) , ( 4,6 ) , ( 2,1 ) , ( 2,2 ) , ( 2,3 ) , ( 2,4 ) , ( 2,5 ) , ( 2,6 ) , ( 5,1 ) , ( 5,2 ) , ( 5,3 ) , ( 5,4 ) , ( 5,5 ) , ( 5,6 ) , ( 3,1 ) , ( 3,2 ) , ( 3,3 ) , ( 3,4 ) , ( 3,5 ) , ( 3,6 ) , ( 6,1 ) , ( 6,2 ) , ( 6,3 ) , ( 6,4 ) , ( 6,5 ) , ( 6,6 ) } n ( s ) = 36 set of total of 6 , a = { ( 1,5 ) , ( 5,1 ) , ( 2,4 ) , ( 4,2 ) , ( 3,3 ) } ; n ( a ) = 5 p ( total of 6 ) = n ( a ) n ( s ) n ( a ) n ( s ) = 5 / 36 c | probability |
math_qa__0uUTuitdbH8YtdSZ | Elvin's monthly telephone bill is the sum of the charge for the calls he made during the month and a fixed monthly charge for Internet service. Elvin's total telephone bill for January was $50 and Elvin's total telephone bill for February was 76$. If Elvin's charge for the calls he made in February was twice the charge for the calls he made in January, what is Elvin's fixed monthly charge for Internet service? Pick one
A) $ 5 B) $ 10 C) $ 14 D) $ 24 E) $ 28 | <gadget id="calculator">50 * 2</gadget>
<output>100</output>
<gadget id="calculator">100 - 76</gadget>
<output>24</output>
<result>D</result> | D | 24 | Elvin's monthly telephone bill is the sum of the charge for the calls he made during the month and a fixed monthly charge for Internet service. Elvin's total telephone bill for January was $50 and Elvin's total telephone bill for February was 76$. If Elvin's charge for the calls he made in February was twice the charge for the calls he made in January, what is Elvin's fixed monthly charge for Internet service? | {
"A": "$ 5",
"B": "$ 10",
"C": "$ 14",
"D": "$ 24",
"E": "$ 28"
} | subtract(multiply(50, const_2), 76) | multiply(n0,const_2)|subtract(#0,n1)| | "bill = fixed charge + charge of calls made in jan , bill = fixed charge ( let , y ) + charge of calls made in jan ( let , x ) = $ 50 in feb , bill = fixed charge ( let , y ) + charge of calls made in feb ( then , 2 x ) = $ 76 i . e . x + y = 50 and 2 x + y = 76 take the difference if two equations i . e . ( 2 x + y ) - ( x + y ) = 76 - 50 i . e . x = 26 i . e . fixed monthly charge , y = 26 answer : d" | general |
math_qa__X1RavGuNoiE11qBV | A salesman’s terms were changed from a flat commission of 5% on all his sales to a fixed salary of Rs.1300 plus 2.5% commission on all sales exceeding Rs. 4,000. If his remuneration as per new scheme was Rs. 600 more than that by the previous schema, his sales were worth? Choose the correct option:
A) 12028 B) 12000 C) 12019 D) 12197 E) 18000 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">600 / (1/20)</gadget>
<output>12_000</output>
<result>C</result> | C | 12,019 | A salesman’s terms were changed from a flat commission of 5% on all his sales to a fixed salary of Rs.1300 plus 2.5% commission on all sales exceeding Rs. 4,000. If his remuneration as per new scheme was Rs. 600 more than that by the previous schema, his sales were worth? | {
"A": "12028",
"B": "12000",
"C": "12019",
"D": "12197",
"E": "18000"
} | divide(600, divide(5, const_100)) | divide(n0,const_100)|divide(n4,#0) | [ 1300 + ( x - 4000 ) * ( 2.5 / 100 ) ] - x * ( 5 / 100 ) = 600 x = 18000 answer : c | general |
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