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stringlengths 7
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math_qa__v01yQ7i3W99aZDAu | Jim’s Taxi Service charges an initial fee of $2.35 at the beginning of a trip and an additional charge of $0.35 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles? Choose the correct choice from the following answers.
A) $ 3.15 B) $ 4.45 C) $ 4.80 D) $ 5.50 E) $ 5.40 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3.6 / (2/5)</gadget>
<output>9</output>
<gadget id="calculator">9 * 0.35</gadget>
<output>3.15</output>
<gadget id="calculator">3.15 + 2.35</gadget>
<output>5.5</output>
<result>D</result> | D | 5.5 | Jim’s Taxi Service charges an initial fee of $2.35 at the beginning of a trip and an additional charge of $0.35 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles? | {
"A": "$ 3.15",
"B": "$ 4.45",
"C": "$ 4.80",
"D": "$ 5.50",
"E": "$ 5.40"
} | add(multiply(divide(3.6, divide(2, 5)), 0.35), 2.35) | divide(n2,n3)|divide(n4,#0)|multiply(n1,#1)|add(n0,#2)| | "let the fixed charge of jim â € ™ s taxi service = 2.35 $ and charge per 2 / 5 mile ( . 4 mile ) = . 35 $ total charge for a trip of 3.6 miles = 2.35 + ( 3.6 / . 4 ) * . 35 = 2.35 + 9 * . 35 = 5.5 $ answer d" | general |
math_qa__oJO09CcguvCpI6OC | A special municipal payroll tax charges not tax on a payroll less than $200,000 and only 0.2% on a company’s payroll above $200,000. If Belfried Industries paid $400 in this special municipal payroll tax, then they must have had a payroll of
Choose the correct choice from the following choices:
A) $ 180,000 B) $ 400,000 C) $ 220,000 D) $ 402,000 E) $ 2 , 200,000 | <gadget id="calculator">400 * 100</gadget>
<output>40_000</output>
<gadget id="calculator">40_000 * 10</gadget>
<output>400_000</output>
<result>B</result> | B | 400,000 | A special municipal payroll tax charges not tax on a payroll less than $200,000 and only 0.2% on a company’s payroll above $200,000. If Belfried Industries paid $400 in this special municipal payroll tax, then they must have had a payroll of | {
"A": "$ 180,000",
"B": "$ 400,000",
"C": "$ 220,000",
"D": "$ 402,000",
"E": "$ 2 , 200,000"
} | multiply(multiply(400, const_100), const_10) | multiply(n3,const_100)|multiply(#0,const_10)| | "answer : b , ( with different approach ) : the 400 paid is 0.2 % of the additional amount above 200,000 . let it be x now 0.2 % of x = 400 therefore x = 200,000 total = 200,000 + x = 400,000" | general |
math_qa__7hutqQQuoUtsAQkv | The speed of a boat in still water in 20 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 24 minutes is: Choose the most appropriate option: A) 9.6 B) 10.2 C) 9.2 D) 10.4 E) 9.0 | <gadget id="calculator">20 + 3</gadget>
<output>23</output>
<gadget id="calculator">24 / 60</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">23 * (2/5)</gadget>
<output>46/5 = around 9.2</output>
<result>C</result> | C | 9.2 | The speed of a boat in still water in 20 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 24 minutes is: | {
"A": "9.6",
"B": "10.2",
"C": "9.2",
"D": "10.4",
"E": "9.0"
} | multiply(add(20, 3), divide(24, const_60)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "speed downstream = ( 20 + 3 ) = 23 kmph time = 24 minutes = 24 / 60 hour = 2 / 5 hour distance travelled = time × speed = 2 / 5 × 23 = 9.20 km answer is c ." | physics |
math_qa__zP8T2jphVrfdXNmP | What is remainder of the division (1225*1227*1229)/12? Choose one.
A) 1 B) 0 C) 3 D) 2 E) 4 | <gadget id="calculator">1_225 * 1_227</gadget>
<output>1_503_075</output>
<gadget id="calculator">1_503_075 * 1_229</gadget>
<output>1_847_279_175</output>
<gadget id="calculator">1_847_279_175 - 3</gadget>
<output>1_847_279_172</output>
<gadget id="calculator">1_847_279_175 - 1_847_279_172</gadget>
<output>3</output>
<result>C</result> | C | 3 | What is remainder of the division (1225*1227*1229)/12? | {
"A": "1",
"B": "0",
"C": "3",
"D": "2",
"E": "4"
} | subtract(multiply(multiply(1225, 1227), 1229), subtract(multiply(multiply(1225, 1227), 1229), const_3)) | multiply(n0,n1)|multiply(n2,#0)|subtract(#1,const_3)|subtract(#1,#2)| | "remainder will be number / 100 here as the divisor is two digit number = 12 . hence checking for the last two digits = 5 * 7 * 9 = 15 thus remainder = 3 . answer : c" | general |
math_qa__RjwW8KZQWVhJVdoO | What number should replace the question mark? 2, 16, 4, 14, 6, 12, ---? Choose the correct option.
A) 8 B) 10 C) 12 D) 14 E) 16 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<result>A</result> | A | 8 | What number should replace the question mark? 2, 16, 4, 14, 6, 12, ---? | {
"A": "8",
"B": "10",
"C": "12",
"D": "14",
"E": "16"
} | add(add(add(2, 2), 2), const_2) | add(n0,n0)|add(n0,#0)|add(#1,const_2) | answer : a 2 , 16 , 4 , 14 , 6 , 12 , 8 ? there are two alternate sequences : + 2 and - 2 . | general |
math_qa__StNBWnUv4OWoGEPz | A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 62 now, the son age 5 years back was Choose the correct option.
A) 14 B) 17 C) 11 D) 19 E) 26 | <gadget id="calculator">62 / 2</gadget>
<output>31</output>
<gadget id="calculator">31 - 5</gadget>
<output>26</output>
<result>E</result> | E | 26 | A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 62 now, the son age 5 years back was | {
"A": "14",
"B": "17",
"C": "11",
"D": "19",
"E": "26"
} | subtract(divide(62, const_2), 5) | divide(n0,const_2)|subtract(#0,n1)| | "let the son ' s present age be x years . then , ( 62 - x ) = x x = 31 . son ' s age 5 years back = ( 31 - 5 ) = 26 years answer : e" | general |
math_qa__8zy3fIYkQA1Zt736 | Calculate the average of all the numbers between 7 and 49 which are divisible by 6. Choose the correct choice from the following choices
A) 20 B) 18 C) 19 D) 15 E) 30 | <gadget id="calculator">7 / 6</gadget>
<output>7/6 = around 1.166667</output>
<gadget id="calculator">floor(7/6)</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">49 / 6</gadget>
<output>49/6 = around 8.166667</output>
<gadget id="calculator">floor(49/6)</gadget>
<output>8</output>
<gadget id="calculator">2 + 8</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<result>E</result> | E | 30 | Calculate the average of all the numbers between 7 and 49 which are divisible by 6. | {
"A": "20",
"B": "18",
"C": "19",
"D": "15",
"E": "30"
} | multiply(divide(add(add(floor(divide(7, 6)), const_1), floor(divide(49, 6))), const_2), 6) | divide(n0,n2)|divide(n1,n2)|floor(#0)|floor(#1)|add(#2,const_1)|add(#4,#3)|divide(#5,const_2)|multiply(n2,#6)| | "explanation : numbers divisible by 6 are 12 , 18,24 , 30,36 , 42,48 , average = ( 12 + 18 + 24 + 30 + 36 + 42 + 48 , ) / 7 = 210 / 7 = 30 answer : e" | general |
math_qa__jx6zyEzQfzmcNVfI | A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $35 more than that received by B, find the total amount shared by A, B and C.
Pick:
A) $ 1360
B) $ 1250
C) $ 1260
D) $ 1270
E) $ 1280 | <gadget id="calculator">3 * 35</gadget>
<output>105</output>
<gadget id="calculator">105 * 2</gadget>
<output>210</output>
<gadget id="calculator">2 * 35</gadget>
<output>70</output>
<gadget id="calculator">210 + 70</gadget>
<output>280</output>
<gadget id="calculator">280 + 35</gadget>
<output>315</output>
<gadget id="calculator">280 + 315</gadget>
<output>595</output>
<gadget id="calculator">315 * 3</gadget>
<output>945</output>
<gadget id="calculator">945 - 280</gadget>
<output>665</output>
<gadget id="calculator">595 + 665</gadget>
<output>1_260</output>
<result>C</result> | C | 1,260 | A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $35 more than that received by B, find the total amount shared by A, B and C. | {
"A": "$ 1360",
"B": "$ 1250",
"C": "$ 1260",
"D": "$ 1270",
"E": "$ 1280"
} | add(add(add(multiply(multiply(const_3, 35), const_2), multiply(const_2, 35)), add(add(multiply(multiply(const_3, 35), const_2), multiply(const_2, 35)), 35)), subtract(multiply(add(add(multiply(multiply(const_3, 35), const_2), multiply(const_2, 35)), 35), const_3), add(multiply(multiply(const_3, 35), const_2), multiply(const_2, 35)))) | multiply(n0,const_3)|multiply(n0,const_2)|multiply(#0,const_2)|add(#2,#1)|add(n0,#3)|add(#3,#4)|multiply(#4,const_3)|subtract(#6,#3)|add(#5,#7)| | "a = 1 / 3 ( b + c ) = > c = 3 a - b - - - ( 1 ) b = 2 / 7 ( a + c ) = > c = 3.5 b - a - - ( b ) a - b = $ 35 a = 35 + b ( 1 ) = = = > c = 105 + 3 b - b = 2 b + 105 = = > 2 b - c = - 105 - - - ( 3 ) ( 2 ) = = = > c = 3.5 b - b - 35 = 2.5 b - 35 = = > 2.5 b - c = 35 - - - ( 4 ) from ( 4 ) and ( 3 ) 0.5 b = 140 b = $ 280 a = $ 315 c = 945 - 280 = $ 665 total amount = 315 + 280 + 665 = $ 1260 answer : c" | general |
math_qa__3EoegJhaVGvdY5ng | The number which exceeds 16% of it by 21 is : Choose the most appropriate option:
A) 25 B) 52 C) 58 D) 60 E) 62 | <gadget id="calculator">21 * 100</gadget>
<output>2_100</output>
<gadget id="calculator">100 - 16</gadget>
<output>84</output>
<gadget id="calculator">2_100 / 84</gadget>
<output>25</output>
<result>A</result> | A | 25 | The number which exceeds 16% of it by 21 is : | {
"A": "25",
"B": "52",
"C": "58",
"D": "60",
"E": "62"
} | divide(multiply(21, const_100), subtract(const_100, 16)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "solution solution let the number be x . x - 16 % of x = 21 x - 16 / 100 x = 21 x - 4 / 25 x = 21 21 / 25 x = 21 x = ( 21 x 25 / 21 ) = 25 answer a" | gain |
math_qa__6PMigfBKbUHddXDk | Excluding stoppages, the speed of a bus is 60 kmph and including stoppages, it is 50 kmph. For how many minutes does the bus stop per hour? Choices.
A) 10 min B) 15 min C) 12 min D) 8 min E) 16 min | <gadget id="calculator">60 - 50</gadget>
<output>10</output>
<gadget id="calculator">10 / 60</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">60 * (1/6)</gadget>
<output>10</output>
<result>A</result> | A | 10 | Excluding stoppages, the speed of a bus is 60 kmph and including stoppages, it is 50 kmph. For how many minutes does the bus stop per hour? | {
"A": "10 min",
"B": "15 min",
"C": "12 min",
"D": "8 min",
"E": "16 min"
} | multiply(const_60, divide(subtract(60, 50), 60)) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)| | "due to stoppages , it covers 10 km less . time taken to cover 10 km = ( 10 / 60 x 60 ) min = 10 min answer : a" | physics |
math_qa__tesG7IvQJlSh84QM | If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4960 , R will receive Choose the correct choice from the following choices:
A) 600
B) 700
C) 800
D) 960
E) none of these | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 6</gadget>
<output>31</output>
<gadget id="calculator">6 / 31</gadget>
<output>6/31 = around 0.193548</output>
<gadget id="calculator">4_960 * (6/31)</gadget>
<output>960</output>
<result>D</result> | D | 960 | If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4960 , R will receive | {
"A": "600",
"B": "700",
"C": "800",
"D": "960",
"E": "none of these"
} | multiply(4960, divide(6, add(add(add(10, add(4, const_1)), 10), 6))) | add(n0,const_1)|add(n2,#0)|add(n2,#1)|add(n1,#2)|divide(n1,#3)|multiply(n3,#4)| | "explanation : let p ' s capital = p , q ' s capital = q and r ' s capital = r then 4 p = 6 q = 10 r = > 2 p = 3 q = 5 r = > q = 2 p / 3 r = 2 p / 5 p : q : r = p : 2 p / 3 : 2 p / 5 = 15 : 10 : 6 r ' s share = 4960 * ( 6 / 31 ) = 160 * 6 = 960 . answer : option d" | general |
math_qa__hNt9P1uos2JYgYOT | An isosceles triangle those sides are 13cm,13cm,10cm long inscribed in a circle.find the radius of the circle Choose the correct choice from the following options: A) 8 cm B) 9 cm C) 10 cm D) 11 cm E) 7 cm | <gadget id="calculator">13 ** 2</gadget>
<output>169</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">169 - 25</gadget>
<output>144</output>
<gadget id="calculator">144 + 25</gadget>
<output>169</output>
<gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">169 / 24</gadget>
<output>169/24 = around 7.041667</output>
<gadget id="calculator">(169/24) + 1</gadget>
<output>193/24 = around 8.041667</output>
<result>A</result> | A | 8 | An isosceles triangle those sides are 13cm,13cm,10cm long inscribed in a circle.find the radius of the circle | {
"A": "8 cm",
"B": "9 cm",
"C": "10 cm",
"D": "11 cm",
"E": "7 cm"
} | add(divide(add(subtract(power(13, const_2), power(divide(10, const_2), const_2)), power(divide(10, const_2), const_2)), multiply(sqrt(subtract(power(13, const_2), power(divide(10, const_2), const_2))), const_2)), const_1) | divide(n2,const_2)|power(n0,const_2)|power(#0,const_2)|subtract(#1,#2)|add(#2,#3)|sqrt(#3)|multiply(#5,const_2)|divide(#4,#6)|add(#7,const_1) | a , b , c are sides of triangle , ad is the median , ad ^ 2 = ab ^ 2 - bd ^ 2 then ad = 12 , the centriod median divides into 2 : 1 ratio so 12 will be divide into 2 : 1 ratio so 8 is radius . so ans is 8 cm answer : a | geometry |
math_qa__uqt3665mVYcYdFXg | N is an 80-digit positive integer (in the decimal scale). All digits except the 44th digit (from the left) are 2. If N is divisible by 13, find the 26th digit? Select: A) 5 B) 6 C) 1 D) 2 E) 3 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 1</gadget>
<output>6</output>
<result>B</result> | B | 6 | N is an 80-digit positive integer (in the decimal scale). All digits except the 44th digit (from the left) are 2. If N is divisible by 13, find the 26th digit? | {
"A": "5",
"B": "6",
"C": "1",
"D": "2",
"E": "3"
} | divide(divide(const_12, const_2), const_1) | divide(const_12,const_2)|divide(#0,const_1) | detailed solution to begin with , the question should read ` ` find the 44 th digit ' ' . any number of the form abcabc is a multiple of 1001 . 1001 is 7 * 11 * 13 . so , any number of the form abcabc is a multiple of 13 . so , a number comprising 42 2 ' s would be a multiple of 13 , so would a number comprising 36 2 ' s . so , in effect , we are left with a two digit number 2 a , where a is the 44 th digit . 26 is a multiple of 13 , so the 44 th digit should be 6 . correct answer b | general |
math_qa__eoadg2NEumkSpHkJ | 60 boys can complete a work in 40 days.how many men need to complete twice the work in 20 days Choose the correct choice from the following answers.
A) 160
B) 170
C) 180
D) 190
E) 240 | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">60 * 80</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 20</gadget>
<output>240</output>
<result>E</result> | E | 240 | 60 boys can complete a work in 40 days.how many men need to complete twice the work in 20 days | {
"A": "160",
"B": "170",
"C": "180",
"D": "190",
"E": "240"
} | divide(multiply(60, multiply(40, const_2)), 20) | multiply(n1,const_2)|multiply(n0,#0)|divide(#1,n2)| | "one man can complete the work in 40 * 60 = 2400 days = one time work to complete the work twice it will be completed in let m be the no . of worker assign for this therefore the eqn becomes m * 20 = 2 * 2400 m = 240 workers answer : e" | physics |
math_qa__dYOVuKahi0cP7jCL | An outlet pipe empties a tank which is full in 8 hours. If the inlet pipe is kept open, which lets water in at the rate of 8 litres/min then outlet pipe would take 4 hours longer. Find the capacity of the tank. Choose the correct answer: A) 8600 litres B) 200 litres C) 12800 litres D) 11520 litres E) 13200 litres | <gadget id="calculator">8 * 60</gadget>
<output>480</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">480 * 12</gadget>
<output>5_760</output>
<gadget id="calculator">5_760 / 4</gadget>
<output>1_440</output>
<gadget id="calculator">1_440 * 8</gadget>
<output>11_520</output>
<result>D</result> | D | 11,520 | An outlet pipe empties a tank which is full in 8 hours. If the inlet pipe is kept open, which lets water in at the rate of 8 litres/min then outlet pipe would take 4 hours longer. Find the capacity of the tank. | {
"A": "8600 litres",
"B": "200 litres",
"C": "12800 litres",
"D": "11520 litres",
"E": "13200 litres"
} | multiply(divide(multiply(multiply(8, const_60), add(8, 4)), 4), 8) | add(n0,n2)|multiply(n1,const_60)|multiply(#0,#1)|divide(#2,n2)|multiply(n0,#3)| | "let the rate of outlet pipe be x liters / hour ; rate of inlet pipe is 8 litres / min , or 8 * 60 = 480 liters / hour ; net outflow rate when both pipes operate would be x - 480 liters / hour . capacity of the tank = x * 8 hours = ( x - 480 ) * ( 8 + 4 ) hours 8 x = ( x - 480 ) * 12 - - > x = 1440 - - > capacity = 8 x = 11520 liters . answer : d ." | physics |
math_qa__TOln1nzrdPmQbqV3 | How should we mix two rice packets to get one 1kg packet priced at Rs 8 when the prices of 1 kg packets of the two types are Rs 7.1 and Rs 9.2. Options.
A) 4 : 3 B) 4 : 7 C) 4 : 9 D) 4 : 2 E) 4 : 1 | <gadget id="calculator">9.2 - 8</gadget>
<output>1.2</output>
<gadget id="calculator">8 - 7.1</gadget>
<output>0.9</output>
<gadget id="calculator">1.2 / 0.9</gadget>
<output>1.333333</output>
<result>A</result> | A | 1.333333 | How should we mix two rice packets to get one 1kg packet priced at Rs 8 when the prices of 1 kg packets of the two types are Rs 7.1 and Rs 9.2. | {
"A": "4 : 3",
"B": "4 : 7",
"C": "4 : 9",
"D": "4 : 2",
"E": "4 : 1"
} | divide(subtract(9.2, 8), subtract(8, 7.1)) | subtract(n4,n1)|subtract(n1,n3)|divide(#0,#1) | explanation : no explanation is available for this question ! answer : a | general |
math_qa__sjoBW5avnxKRoHjX | Car A runs at the speed of 35 km/hr & reaches its destination in 9hr. Car B runs at the speed of 43 km/h & reaches its destination in 10h. What is the respective ratio of distances covered by Car A & Car B? Choose the correct choice from the following choices:
A) 65 : 69
B) 56 : 45
C) 89 : 71
D) 68 : 23
E) 63 : 86 | <gadget id="calculator">35 * 9</gadget>
<output>315</output>
<gadget id="calculator">43 * 10</gadget>
<output>430</output>
<gadget id="calculator">315 / 430</gadget>
<output>63/86 = around 0.732558</output>
<result>E</result> | E | 0.732558 | Car A runs at the speed of 35 km/hr & reaches its destination in 9hr. Car B runs at the speed of 43 km/h & reaches its destination in 10h. What is the respective ratio of distances covered by Car A & Car B? | {
"A": "65 : 69",
"B": "56 : 45",
"C": "89 : 71",
"D": "68 : 23",
"E": "63 : 86"
} | divide(multiply(35, 9), multiply(43, 10)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "sol . distance travelled by car a = 35 × 9 = 315 km distance travelled by car b = 43 × 10 = 430 km ratio = 315 / 430 = 63 : 86 e" | physics |
math_qa__8Eq4pMNa7lHQaaQI | The average weight of 3 packets A, B and C is 84 kg. Another packet D added into the group and the average now becomes 80 kg. If another packet E, whose weight is 3 kg more than that of D, replaces A then the average weight of B, C, D and E becomes 79 kg. The weight of A is: Choose the correct choice from the following: A) 70 kg B) 72 kg C) 75 kg D) 80 kg E) none of these | <gadget id="calculator">3 * 84</gadget>
<output>252</output>
<gadget id="calculator">4 * 79</gadget>
<output>316</output>
<gadget id="calculator">4 * 80</gadget>
<output>320</output>
<gadget id="calculator">320 - 252</gadget>
<output>68</output>
<gadget id="calculator">68 + 3</gadget>
<output>71</output>
<gadget id="calculator">68 + 71</gadget>
<output>139</output>
<gadget id="calculator">316 - 139</gadget>
<output>177</output>
<gadget id="calculator">252 - 177</gadget>
<output>75</output>
<result>C</result> | C | 75 | The average weight of 3 packets A, B and C is 84 kg. Another packet D added into the group and the average now becomes 80 kg. If another packet E, whose weight is 3 kg more than that of D, replaces A then the average weight of B, C, D and E becomes 79 kg. The weight of A is: | {
"A": "70 kg",
"B": "72 kg",
"C": "75 kg",
"D": "80 kg",
"E": "none of these"
} | subtract(multiply(3, 84), subtract(multiply(const_4, 79), add(subtract(multiply(const_4, 80), multiply(3, 84)), add(subtract(multiply(const_4, 80), multiply(3, 84)), 3)))) | multiply(n0,n1)|multiply(n4,const_4)|multiply(n2,const_4)|subtract(#2,#0)|add(n0,#3)|add(#4,#3)|subtract(#1,#5)|subtract(#0,#6) | explanation : a + b + c = ( 84 x 3 ) = 252 kg , a + b + c + d = ( 80 x 4 ) = 320 kg . d = ( 320 - 252 ) = 68 , e = ( 68 + 3 ) = 7 l . b + c + d + e = ( 79 x 4 ) = 316 . ( a + b + c + d ) - ( b + c + d + e ) = ( 320 - 316 ) kg = 4 kg . a - e = 4 = a = ( 4 + e ) = 75 kg answer : c | general |
math_qa__hkznAX41h4iIb0Ly | The consumption of diesel per hour of a bus varies directly as square of its speed. When the bus is travelling at 60 kmph its consumption is 1 litre per hour. if each litre costs $30 and other expenses per hous is $ 20, then what would be the minimum expenditure required to cover a distance of 600 Km? Options.
A) 500 B) 450 C) 600 D) 650 E) 750 | <gadget id="calculator">600 / 60</gadget>
<output>10</output>
<gadget id="calculator">10 * 30</gadget>
<output>300</output>
<gadget id="calculator">10 * 20</gadget>
<output>200</output>
<gadget id="calculator">300 + 200</gadget>
<output>500</output>
<result>A</result> | A | 500 | The consumption of diesel per hour of a bus varies directly as square of its speed. When the bus is travelling at 60 kmph its consumption is 1 litre per hour. if each litre costs $30 and other expenses per hous is $ 20, then what would be the minimum expenditure required to cover a distance of 600 Km? | {
"A": "500",
"B": "450",
"C": "600",
"D": "650",
"E": "750"
} | add(multiply(divide(600, 60), 30), multiply(divide(600, 60), 20)) | divide(n4,n0)|multiply(n2,#0)|multiply(n3,#0)|add(#1,#2) | 60 kmph consumption is 1 lt / hr so 600 km will take 10 hrs and the consumption is 10 lt for entire distance . 1 lt costs $ 30 so 10 lt costs $ 300 extra expenses for 1 hr - $ 20 10 hrs - $ 200 total expense - $ 300 + $ 200 = $ 500 answer : a | physics |
math_qa__RJVGXZytHqnqrDrU | On the first day of her vacation, Louisa traveled 100 miles. On the second day, traveling at the same average speed, she traveled 175 miles. If the 100-mile trip took 3 hours less than the 175-mile trip, what was the average speed, in miles per hour? Choose the most appropriate option
A) 27 B) 28 C) 25 D) 30 E) 35 | <gadget id="calculator">175 - 100</gadget>
<output>75</output>
<gadget id="calculator">75 / 3</gadget>
<output>25</output>
<result>C</result> | C | 25 | On the first day of her vacation, Louisa traveled 100 miles. On the second day, traveling at the same average speed, she traveled 175 miles. If the 100-mile trip took 3 hours less than the 175-mile trip, what was the average speed, in miles per hour? | {
"A": "27",
"B": "28",
"C": "25",
"D": "30",
"E": "35"
} | divide(subtract(175, 100), 3) | subtract(n1,n0)|divide(#0,n3)| | "( time ) * ( rate ) = ( distance ) - - > ( rate ) = ( distance ) / ( time ) - - > given : ( rate ) = 100 / t = 175 / ( t + 3 ) - - > 4 / t = 7 / ( t + 3 ) - - > 4 t + 12 = 7 t - - - - > 3 t = 12 . t = 4 - - - - > ( rate ) = 100 / 4 = 25 answer : c" | physics |
math_qa__gSQbNZWqmhiDYW8T | In a office work is distribute between p persons. If 1/5 members are absent then work increased for each person is? Options
A) 13.28 % B) 14.28 % C) 15.28 % D) 16.28 % E) 25 % | <gadget id="calculator">100 * 5</gadget>
<output>500</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">500 / 4</gadget>
<output>125</output>
<gadget id="calculator">125 - 100</gadget>
<output>25</output>
<result>E</result> | E | 25 | In a office work is distribute between p persons. If 1/5 members are absent then work increased for each person is? | {
"A": "13.28 %",
"B": "14.28 %",
"C": "15.28 %",
"D": "16.28 %",
"E": "25 %"
} | subtract(divide(multiply(const_100, 5), subtract(5, 1)), const_100) | multiply(n1,const_100)|subtract(n1,n0)|divide(#0,#1)|subtract(#2,const_100)| | "let total % of work is 100 % total person = p 1 / 5 person are absent of total person . so absent person is 1 / 5 p ie p / 5 . left person is , p - p / 5 = 4 p / 5 . p person do the work 100 % 1 person do the work 100 * p % 4 p / 5 person do the work ( 100 * p * 5 ) / 4 p % = 125 % work increased for each person is = ( 125 - 100 ) % = 25 % answer : e" | general |
math_qa__nyvrIhj48rIsGEt1 | A book is bought for $60 and sold for $75. What is the profit in percentage? Answers
A) 12 B) 15 C) 20 D) 25 E) 30 | <gadget id="calculator">75 - 60</gadget>
<output>15</output>
<gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>D</result> | D | 25 | A book is bought for $60 and sold for $75. What is the profit in percentage? | {
"A": "12",
"B": "15",
"C": "20",
"D": "25",
"E": "30"
} | multiply(divide(subtract(75, 60), 60), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "75 / 60 = 1.25 the answer is d ." | gain |
math_qa__sAdjdPBhDHpnsqvv | The value of a machine depreciates at 23% per annum. If its present value is $1,50,000, at what price should it be sold after two years such that a profit of $24,000 is made? Choose the correct choice from the following answers.
A) $ 252935 B) $ 432935 C) $ 122935 D) $ 112935 E) $ 152935 | <gadget id="calculator">23 / 100</gadget>
<output>23/100 = around 0.23</output>
<gadget id="calculator">1 - (23/100)</gadget>
<output>77/100 = around 0.77</output>
<gadget id="calculator">(77/100) * (77/100)</gadget>
<output>5_929/10_000 = around 0.5929</output>
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">10_000 * 10</gadget>
<output>100_000</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">500 * 100</gadget>
<output>50_000</output>
<gadget id="calculator">100_000 + 50_000</gadget>
<output>150_000</output>
<gadget id="calculator">(5_929/10_000) * 150_000</gadget>
<output>88_935</output>
<gadget id="calculator">23 + 2</gadget>
<output>25</output>
<gadget id="calculator">25 * 100</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 * 10</gadget>
<output>25_000</output>
<gadget id="calculator">88_935 + 25_000</gadget>
<output>113_935</output>
<result>D</result> | D | 112,935 | The value of a machine depreciates at 23% per annum. If its present value is $1,50,000, at what price should it be sold after two years such that a profit of $24,000 is made? | {
"A": "$ 252935",
"B": "$ 432935",
"C": "$ 122935",
"D": "$ 112935",
"E": "$ 152935"
} | add(multiply(multiply(subtract(1, divide(23, const_100)), subtract(1, divide(23, const_100))), add(multiply(multiply(const_100, const_100), sqrt(const_100)), multiply(multiply(divide(sqrt(const_100), const_2), const_100), const_100))), multiply(multiply(add(23, const_2), const_100), sqrt(const_100))) | add(n0,const_2)|divide(n0,const_100)|multiply(const_100,const_100)|sqrt(const_100)|divide(#3,const_2)|multiply(#2,#3)|multiply(#0,const_100)|subtract(n1,#1)|multiply(#4,const_100)|multiply(#7,#7)|multiply(#6,#3)|multiply(#8,const_100)|add(#5,#11)|multiply(#12,#9)|add(#13,#10)| | "the value of the machine after two years = 0.77 * 0.77 * 1 , 50,000 = $ 88,935 sp such that a profit of $ 24,000 is made = 88,935 + 24,000 = $ 1 , 12,935 d" | gain |
math_qa__VB3ASdu9vGJmhDSm | A train travels 240 km in 3 hours and 450 km in 5 hours.find the average speed of train.
Options:
A) 80 kmph B) 60 kmph C) 86 kmph D) 90 kmph E) none of these | <gadget id="calculator">240 + 450</gadget>
<output>690</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">690 / 8</gadget>
<output>345/4 = around 86.25</output>
<result>C</result> | C | 86 | A train travels 240 km in 3 hours and 450 km in 5 hours.find the average speed of train. | {
"A": "80 kmph",
"B": "60 kmph",
"C": "86 kmph",
"D": "90 kmph",
"E": "none of these"
} | divide(add(240, 450), add(3, 5)) | add(n0,n2)|add(n1,n3)|divide(#0,#1)| | "as we know that speed = distance / time for average speed = total distance / total time taken thus , total distance = 240 + 450 = 690 km thus , total speed = 8 hrs or , average speed = 690 / 8 or , 86 kmph . answer : c" | physics |
math_qa__HClcH0ta4QrPZYtm | A gambler bought $3,000 worth of chips at a casino in denominations of $20 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $20 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back? Choose the correct choice from the following options:
A) $ 2,040 B) $ 2,120 C) $ 1,960 D) $ 1,920 E) $ 1,400 | <gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">16 + 2</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">9 * 20</gadget>
<output>180</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">7 * 100</gadget>
<output>700</output>
<gadget id="calculator">180 + 700</gadget>
<output>880</output>
<gadget id="calculator">3_000 - 880</gadget>
<output>2_120</output>
<result>B</result> | B | 2,120 | A gambler bought $3,000 worth of chips at a casino in denominations of $20 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $20 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back? | {
"A": "$ 2,040",
"B": "$ 2,120",
"C": "$ 1,960",
"D": "$ 1,920",
"E": "$ 1,400"
} | subtract(multiply(const_3, const_1000), add(multiply(divide(add(16, 2), 2), 20), multiply(subtract(divide(add(16, 2), 2), 2), 100))) | add(n3,n5)|multiply(const_1000,const_3)|divide(#0,n5)|multiply(n1,#2)|subtract(#2,n5)|multiply(n2,#4)|add(#3,#5)|subtract(#1,#6) | in order to maximize the amount of money that the gambler kept , we should maximize # of $ 20 chips lost and minimize # of $ 100 chips lost , which means that # of $ 20 chips lost must be 2 more than # of $ 100 chips lost . so , if # of $ 20 chips lost is x then # of $ 100 chips lost should be x - 2 . now , given that total # of chips lost is 16 : x + x - 2 = 16 - - > x = 9 : 9 $ 20 chips were lost and 9 - 2 = 7 $ 100 chips were lost . total worth of chips lost is 9 * 20 + 7 * 100 = $ 880 , so the gambler kept $ 3,000 - $ 880 = $ 2,120 . answer : b . | general |
math_qa__GbMq4SaDdu3sYm5C | A train running at the speed of 60 km/hr crosses a pole in 12 seconds. Find the length of the train? Answers.
A) 150 meter B) 200 meter C) 156 meter D) 168 meter E) 154 meter | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 12</gadget>
<output>200</output>
<result>B</result> | B | 200 | A train running at the speed of 60 km/hr crosses a pole in 12 seconds. Find the length of the train? | {
"A": "150 meter",
"B": "200 meter",
"C": "156 meter",
"D": "168 meter",
"E": "154 meter"
} | multiply(divide(multiply(60, const_1000), const_3600), 12) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 * ( 5 / 18 ) m / sec = 50 / 3 m / sec length of train ( distance ) = speed * time ( 50 / 3 ) * 12 = 200 meter answer : b" | physics |
math_qa__P0MbNHcoGXwK5dlS | Two trains of equal lengths take 12 sec and 24 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
Choose the correct choice from the following choices: A) 18 sec B) 12 sec C) 17 sec D) 21 sec E) 16 sec | <gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">120 / 24</gadget>
<output>5</output>
<gadget id="calculator">120 / 12</gadget>
<output>10</output>
<gadget id="calculator">5 + 10</gadget>
<output>15</output>
<gadget id="calculator">240 / 15</gadget>
<output>16</output>
<result>E</result> | E | 16 | Two trains of equal lengths take 12 sec and 24 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? | {
"A": "18 sec",
"B": "12 sec",
"C": "17 sec",
"D": "21 sec",
"E": "16 sec"
} | divide(multiply(120, const_2), add(speed(120, 24), speed(120, 12))) | multiply(n2,const_2)|speed(n2,n1)|speed(n2,n0)|add(#1,#2)|divide(#0,#3)| | "speed of the first train = 120 / 12 = 10 m / sec . speed of the second train = 120 / 24 = 5 m / sec . relative speed = 10 + 5 = 15 m / sec . required time = ( 120 + 120 ) / 15 = 16 sec . answer : e" | physics |
math_qa__MuvEmwYaZkjC2PiX | set a contains 4 different positive odd integers and 6 different positive even integers . set b contains two different positive odd integers and 3 different positive even integers . if one integer from set a and one integer from set b are chosen at random , what is the probability that the product of the chosen integers is even ? Choose the correct choice from the following options.
A) 3 / 5 B) 4 / 5 C) 17 / 25 D) 21 / 25 E) 43 / 50 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * (2/5)</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">1 - (4/25)</gadget>
<output>21/25 = around 0.84</output>
<result>D</result> | D | 0.84 | set a contains 4 different positive odd integers and 6 different positive even integers . set b contains two different positive odd integers and 3 different positive even integers . if one integer from set a and one integer from set b are chosen at random , what is the probability that the product of the chosen integers is even ? | {
"A": "3 / 5",
"B": "4 / 5",
"C": "17 / 25",
"D": "21 / 25",
"E": "43 / 50"
} | subtract(const_1, multiply(divide(const_2, add(const_2, const_3)), divide(4, add(4, 6)))) | add(const_2,const_3)|add(n0,n1)|divide(const_2,#0)|divide(n0,#1)|multiply(#2,#3)|subtract(const_1,#4) | there can be an odd product only if both integers are odd . p ( odd product ) = 4 / 10 * 2 / 5 = 4 / 25 p ( even product ) = 1 - 4 / 25 = 21 / 25 the answer is d . | probability |
math_qa__xZB8HpYYPSpzRhfO | A and B can do a piece of work in 16 days, B and C in 24 days, C and A in 12 days. How long will C take to do it? Choose the correct choice from the following answers.
A) 16 days B) 55 days C) 24 days D) 32 days E) 22 days | <gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 / 12</gadget>
<output>4</output>
<gadget id="calculator">48 / 16</gadget>
<output>3</output>
<gadget id="calculator">48 / 24</gadget>
<output>2</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(9/2) - 3</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">48 / (3/2)</gadget>
<output>32</output>
<result>D</result> | D | 32 | A and B can do a piece of work in 16 days, B and C in 24 days, C and A in 12 days. How long will C take to do it? | {
"A": "16 days",
"B": "55 days",
"C": "24 days",
"D": "32 days",
"E": "22 days"
} | divide(multiply(16, const_3), subtract(divide(add(divide(multiply(16, const_3), 12), add(divide(multiply(16, const_3), 16), divide(multiply(16, const_3), 24))), const_2), divide(multiply(16, const_3), 16))) | multiply(n0,const_3)|divide(#0,n0)|divide(#0,n1)|divide(#0,n2)|add(#1,#2)|add(#4,#3)|divide(#5,const_2)|subtract(#6,#1)|divide(#0,#7)| | "2 c = 1 / 24 + 1 / 12 – 1 / 16 = 1 / 16 c = 1 / 32 = > 32 days answer : d" | physics |
math_qa__qp3p0C42mfgPALi2 | A searchlight on top of the watch-tower makes 3 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 5 seconds? Choose the correct answer:
A) 1 / 4
B) 1 / 3
C) 1 / 2
D) 2 / 3
E) 3 / 4 | <gadget id="calculator">60 * 1</gadget>
<output>60</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<gadget id="calculator">5 / 20</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<result>E</result> | E | 0.75 | A searchlight on top of the watch-tower makes 3 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 5 seconds? | {
"A": "1 / 4",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "3 / 4"
} | subtract(const_1, divide(5, divide(multiply(const_60, const_1), 3))) | multiply(const_1,const_60)|divide(#0,n0)|divide(n1,#1)|subtract(const_1,#2)| | "3 revolutions per minute = 1 revolution every 20 seconds so no matter what anybody appearing at the tower can not stay in the dark for more than 20 seconds . this will be our total number of possibilities i . e the denominator . p ( man in dark for at least 5 seconds ) = 1 - p ( man in dark for max of 5 seconds ) = 1 - 5 / 20 = 1 - 1 / 4 = 3 / 4 or the other way would be : p ( man in dark for at least 5 seconds ) is like saying he can be in dark for 5 , 6,7 . . . all the way to 20 seconds because that is the max . in this approach it would be 15 / 20 seconds = 3 / 4 ." | physics |
math_qa__2a4nHCjCnNGV0fGU | In the first 10 overs of a cricket game, the run rate was only 4.8. What should be the run rate in the remaining 40 overs to reach the target of 282 runs? Choose the correct answer:
A) 4.25 B) 5.85 C) 6.25 D) 7 E) 7.5 | <gadget id="calculator">10 * 4.8</gadget>
<output>48</output>
<gadget id="calculator">282 - 48</gadget>
<output>234</output>
<gadget id="calculator">234 / 40</gadget>
<output>117/20 = around 5.85</output>
<result>B</result> | B | 5.85 | In the first 10 overs of a cricket game, the run rate was only 4.8. What should be the run rate in the remaining 40 overs to reach the target of 282 runs? | {
"A": "4.25",
"B": "5.85",
"C": "6.25",
"D": "7",
"E": "7.5"
} | divide(subtract(282, multiply(10, 4.8)), 40) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)| | "required run rate = 282 - ( 4.8 x 10 ) = 234 234 / 40 = 5.85 b )" | gain |
math_qa__f5YFHpt2rNgwSAs0 | In the Land of Oz only one or two-letter words are used. The local language has 66 different letters. The parliament decided to forbid the use of the seventh letter. How many words have the people of Oz lost because of the prohibition? Options:
A) 65 B) 66 C) 67 D) 131 E) 132 | <gadget id="calculator">1 + 66</gadget>
<output>67</output>
<gadget id="calculator">67 + 66</gadget>
<output>133</output>
<result>D</result> | D | 131 | In the Land of Oz only one or two-letter words are used. The local language has 66 different letters. The parliament decided to forbid the use of the seventh letter. How many words have the people of Oz lost because of the prohibition? | {
"A": "65",
"B": "66",
"C": "67",
"D": "131",
"E": "132"
} | add(add(const_1, 66), 66) | add(n0,const_1)|add(n0,#0)| | "the seventh letter ( let it be @ ) can be used with other 65 in two type of arrangents one when seventh letter is in 1 st slot @ _ ( 65 ways ) another , when seventh letter is in 2 nd slot _ @ ( 65 ways ) seventh letter ( @ ) itself lost words = 1 + 65 + 65 = 131 answer : d" | general |
math_qa__Ty9epyBJEwZTp08y | The sum of the first 100 numbers, 1 to 100 is always divisible by
Choose one:
A) 2
B) 2 and 4
C) 2 , 4 and 8
D) 2 , 4 and 9
E) none of these | <gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">100 + 1</gadget>
<output>101</output>
<gadget id="calculator">50 * 101</gadget>
<output>5_050</output>
<gadget id="calculator">5_050 / 2</gadget>
<output>2_525</output>
<gadget id="calculator">5_050 / 2_525</gadget>
<output>2</output>
<result>A</result> | A | 2 | The sum of the first 100 numbers, 1 to 100 is always divisible by | {
"A": "2",
"B": "2 and 4",
"C": "2 , 4 and 8",
"D": "2 , 4 and 9",
"E": "none of these"
} | divide(multiply(divide(100, const_2), add(100, 1)), divide(multiply(divide(100, const_2), add(100, 1)), const_2)) | add(n0,n1)|divide(n0,const_2)|multiply(#0,#1)|divide(#2,const_2)|divide(#2,#3) | explanation : the sum of the first 100 natural numbers = ( 100 x 101 ) / 2 = ( 50 x 101 ) as 101 is an odd number and 50 is divisible by 2 , so the sum is always divisible by 2 . answer : option a | general |
math_qa__zuSE7ium7H2stElL | A horse is tethered to one corner of a rectangular grassy field 45 m by 25 m with a rope 22 m long. Over how much area of the field can it graze?
Answers
A) 354 cm 2 B) 380 m 2 C) 350 m 2 D) 407 m 2 E) none of these | <gadget id="calculator">22 ** 2</gadget>
<output>484</output>
<gadget id="calculator">484 * pi</gadget>
<output>484*pi = around 1_520.530844</output>
<gadget id="calculator">(484*pi) / 4</gadget>
<output>121*pi = around 380.132711</output>
<result>B</result> | B | 380 | A horse is tethered to one corner of a rectangular grassy field 45 m by 25 m with a rope 22 m long. Over how much area of the field can it graze? | {
"A": "354 cm 2",
"B": "380 m 2",
"C": "350 m 2",
"D": "407 m 2",
"E": "none of these"
} | divide(multiply(power(22, const_2), const_pi), const_4) | power(n2,const_2)|multiply(#0,const_pi)|divide(#1,const_4)| | "area of the shaded portion = 1 ⁄ 4 × π × ( 22 ) 2 = 380 m 2 answer b" | geometry |
math_qa__uGIGeFSElm86wdid | P and Q started a business investing Rs. 85,000 and Rs. 35,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively? Options:
A) 17 : 6 B) 17 : 0 C) 17 : 7 D) 17 : 2 E) 17 : 3 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">8 * 10</gadget>
<output>80</output>
<gadget id="calculator">80 + 5</gadget>
<output>85</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 + 5</gadget>
<output>35</output>
<gadget id="calculator">85 / 35</gadget>
<output>17/7 = around 2.428571</output>
<result>C</result> | C | 2.428571 | P and Q started a business investing Rs. 85,000 and Rs. 35,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively? | {
"A": "17 : 6",
"B": "17 : 0",
"C": "17 : 7",
"D": "17 : 2",
"E": "17 : 3"
} | divide(add(multiply(add(add(const_2, const_3), const_3), multiply(add(const_2, const_3), 2)), add(const_2, const_3)), add(multiply(const_3, multiply(add(const_2, const_3), 2)), add(const_2, const_3))) | add(const_2,const_3)|add(#0,const_3)|multiply(n2,#0)|multiply(#1,#2)|multiply(#2,const_3)|add(#0,#3)|add(#0,#4)|divide(#5,#6) | p : q = 85000 : 35000 = 17 : 7 . answer : c | gain |
math_qa__3iOgnRYY4yyShXqm | Express a speed of 42 kmph in meters per second?
Choose the most appropriate option:
A) 10 mps B) 18 mps C) 19 mps D) 17 mps E) 12 mps | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 42</gadget>
<output>35/3 = around 11.666667</output>
<result>E</result> | E | 12 | Express a speed of 42 kmph in meters per second? | {
"A": "10 mps",
"B": "18 mps",
"C": "19 mps",
"D": "17 mps",
"E": "12 mps"
} | multiply(const_0_2778, 42) | multiply(n0,const_0_2778)| | "42 * 5 / 18 = 12 mps answer : e" | physics |
math_qa__j080p9Y3XsD9wsjH | Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 459? Choose the correct choice from the following options: A) 18 % B) 21 % C) 20 % D) 26.1 % E) none of these | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 / 100</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">540 * (23/20)</gadget>
<output>621</output>
<gadget id="calculator">621 - 459</gadget>
<output>162</output>
<gadget id="calculator">162 * 100</gadget>
<output>16_200</output>
<gadget id="calculator">16_200 / 621</gadget>
<output>600/23 = around 26.086957</output>
<result>D</result> | D | 26.1 | Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 459? | {
"A": "18 %",
"B": "21 %",
"C": "20 %",
"D": "26.1 %",
"E": "none of these"
} | divide(multiply(subtract(multiply(540, divide(add(const_100, 15), const_100)), 459), const_100), multiply(540, divide(add(const_100, 15), const_100))) | add(n0,const_100)|divide(#0,const_100)|multiply(n1,#1)|subtract(#2,n2)|multiply(#3,const_100)|divide(#4,#2)| | "cp = rs . 540 , mp = 540 + 15 % of 540 = rs . 621 sp = rs . 459 , discount = 621 - 459 = 162 discount % = 162 / 621 * 100 = 26.1 % answer : d" | gain |
math_qa__TPo4ddKWwDhCjGu7 | Income and expenditure of a person are in the ratio 7 : 6. If the income of the person is Rs. 21000, then find his savings? Pick one:
A) rs . 3600
B) rs . 3603
C) rs . 3639
D) rs . 3000
E) rs . 3602 | <gadget id="calculator">6 / 7</gadget>
<output>6/7 = around 0.857143</output>
<gadget id="calculator">(6/7) * 21_000</gadget>
<output>18_000</output>
<gadget id="calculator">21_000 - 18_000</gadget>
<output>3_000</output>
<result>D</result> | D | 3,000 | Income and expenditure of a person are in the ratio 7 : 6. If the income of the person is Rs. 21000, then find his savings? | {
"A": "rs . 3600",
"B": "rs . 3603",
"C": "rs . 3639",
"D": "rs . 3000",
"E": "rs . 3602"
} | subtract(21000, multiply(divide(6, 7), 21000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | "let the income and the expenditure of the person be rs . 7 x and rs . 6 x respectively . income , 7 x = 21000 = > x = 3000 savings = income - expenditure = 7 x - 6 x = x so , savings = rs . 3000 answer : d" | other |
math_qa__Yb6eGdnBb5ihbxJA | A man spends 1/3rd of his salary on food. he spends 1/4th on rent and 1/5th on cloths. If he is left with 1760, then who much salary does he earn Options.
A) 8223 B) 8123 C) 8323 D) 8423 E) 8523 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) + (1/4)</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(7/12) + (1/5)</gadget>
<output>47/60 = around 0.783333</output>
<gadget id="calculator">1 - (47/60)</gadget>
<output>13/60 = around 0.216667</output>
<gadget id="calculator">1_760 / (13/60)</gadget>
<output>105_600/13 = around 8_123.076923</output>
<result>B</result> | B | 8,123 | A man spends 1/3rd of his salary on food. he spends 1/4th on rent and 1/5th on cloths. If he is left with 1760, then who much salary does he earn | {
"A": "8223",
"B": "8123",
"C": "8323",
"D": "8423",
"E": "8523"
} | divide(1760, subtract(const_1, add(add(divide(1, 3), divide(1, 4)), divide(1, 5)))) | divide(n0,n1)|divide(n0,n3)|divide(n0,n5)|add(#0,#1)|add(#3,#2)|subtract(const_1,#4)|divide(n6,#5) | let total salary be x a / q = > x = ( x / 3 ) + ( x / 4 ) + ( x / 5 ) + 1760 = > x - 47 x / 60 = 1760 = > 13 x / 60 = 1760 = > x = 1760 * 60 / 13 = > x = 8123 ( approax ) answer : b | general |
math_qa__GQ6AMMiNhhq2ug0h | What is the largest 4 digit number exactly divisible by 48? Select the correct option
A) 4676
B) 4678
C) 9984
D) 9504
E) 9936 | <gadget id="calculator">10 ** 4</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 48</gadget>
<output>625/3 = around 208.333333</output>
<gadget id="calculator">floor(625/3)</gadget>
<output>208</output>
<gadget id="calculator">208 * 48</gadget>
<output>9_984</output>
<result>C</result> | C | 9,984 | What is the largest 4 digit number exactly divisible by 48? | {
"A": "4676",
"B": "4678",
"C": "9984",
"D": "9504",
"E": "9936"
} | multiply(floor(divide(power(const_10, 4), 48)), 48) | power(const_10,n0)|divide(#0,n1)|floor(#1)|multiply(n1,#2) | largest 4 digit number = 9999 9999 ÷ 48 = 208 , remainder = 15 hence largest 4 digit number exactly divisible by 48 = 9999 - 15 = 9984 answer : c | general |
math_qa__y334PM7QMEcsA7W2 | The ratio of length of two refill is 9:8.2nd refill got damaged when only half length of 2nd refill get used.The ratio of total no. of pages written by both refill. Options
A) 8 : 3 B) 6 : 5 C) 9 : 8 D) 9 : 4 E) 5 : 4 | <gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">9 / 4</gadget>
<output>9/4 = around 2.25</output>
<result>D</result> | D | 2.25 | The ratio of length of two refill is 9:8.2nd refill got damaged when only half length of 2nd refill get used.The ratio of total no. of pages written by both refill. | {
"A": "8 : 3",
"B": "6 : 5",
"C": "9 : 8",
"D": "9 : 4",
"E": "5 : 4"
} | divide(9, divide(subtract(9, const_1), const_2)) | subtract(n0,const_1)|divide(#0,const_2)|divide(n0,#1) | the no . of page written is directly proportional to length of refill . so , initial no . of page to be write = 9 x , 8 x . now , 2 nd refill only can write 4 x page so new ratio of page written = 9 x / 4 x = 9 : 4 . answer d | other |
math_qa__HtkFhxJcvpMQFQAp | A train running at the speed of 45 km/hr crosses a pole in 16 seconds. Find the length of the train.
Choices.
A) 200 B) 188 C) 204 D) 288 E) 500 | <gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 16</gadget>
<output>200</output>
<result>A</result> | A | 200 | A train running at the speed of 45 km/hr crosses a pole in 16 seconds. Find the length of the train. | {
"A": "200",
"B": "188",
"C": "204",
"D": "288",
"E": "500"
} | multiply(divide(multiply(45, const_1000), const_3600), 16) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 45 * ( 5 / 18 ) m / sec = 25 / 2 m / sec length of train ( distance ) = speed * time ( 25 / 2 ) * 16 = 200 meter answer : a" | physics |
math_qa__tMMOOpCJ8LSU5mxs | he number of times a bucket of capacity 4 liters to be used to fill up a tank is less than number of ties another bucket of capacity 3 liters used for the same purpose by 4. What is the capacity of the tank?
Choose the most appropriate option: A) 360 liters B) 256 C) 48 D) 525 E) 425 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">4 * 12</gadget>
<output>48</output>
<result>C</result> | C | 48 | he number of times a bucket of capacity 4 liters to be used to fill up a tank is less than number of ties another bucket of capacity 3 liters used for the same purpose by 4. What is the capacity of the tank? | {
"A": "360 liters",
"B": "256",
"C": "48",
"D": "525",
"E": "425"
} | multiply(4, multiply(3, 4)) | multiply(n0,n1)|multiply(n0,#0) | 4 x = 3 ( x + 4 ) , where x may be number of times 4 l bucket is used . 4 x = 3 ( x + 4 ) - - > 1 . x = 12 , substitute x to lhs or rhs of 1 , which gets you the capacity , and it is 48 . answer : c | general |
math_qa__F0JL2EtRZBmDabim | A and B start a business, with A investing the total capital of Rs.5000, on the condition that B pays A interest @ 10% per annum on his half of the capital. A is a working partner and receives Rs.500 per month from the total profit and any profit remaining is equally shared by both of them. At the end of the year, it was found that the income of A is twice that of B. Find the total profit for the year?
Answers: A) 2500 B) 3500 C) 5000 D) 6000 E) 8000 | <gadget id="calculator">5_000 / 2</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 10</gadget>
<output>250</output>
<gadget id="calculator">250 * 3</gadget>
<output>750</output>
<gadget id="calculator">750 * 4</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 + 500</gadget>
<output>3_500</output>
<result>B</result> | B | 3,500 | A and B start a business, with A investing the total capital of Rs.5000, on the condition that B pays A interest @ 10% per annum on his half of the capital. A is a working partner and receives Rs.500 per month from the total profit and any profit remaining is equally shared by both of them. At the end of the year, it was found that the income of A is twice that of B. Find the total profit for the year? | {
"A": "2500",
"B": "3500",
"C": "5000",
"D": "6000",
"E": "8000"
} | add(multiply(multiply(divide(divide(5000, const_2), 10), const_3), const_4), 500) | divide(n0,const_2)|divide(#0,n1)|multiply(#1,const_3)|multiply(#2,const_4)|add(n2,#3) | interest received by a from b = 10 % of half of rs . 5000 = 10 % * 2500 = 250 . amount received by a per annum for being a working partner = 500 * 12 = rs . 1000 . let ' p ' be the part of the remaining profit that a receives as his share . total income of a = ( 250 + 1000 + p ) total income of b = only his share from the remaining profit = ' p ' , as a and b share the remaining profit equally . income of a = twice the income of b ( 250 + 1000 + p ) = 2 ( p ) p = 1250 total profit = 2 p + 1000 = 2 * 1250 + 1000 = 3500 answer : b | gain |
math_qa__usdBdZC9LcxgM26D | Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability W that Jane will be on the same committee as Albert? Choose the correct option:
A) 12 %
B) 20 %
C) 33 %
D) 40 %
E) 50 % | <gadget id="calculator">binomial(4, 1)</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">binomial(6, 3)</gadget>
<output>20</output>
<gadget id="calculator">8 / 20</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 4</gadget>
<output>100</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>D</result> | D | 40 | Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability W that Jane will be on the same committee as Albert? | {
"A": "12 %",
"B": "20 %",
"C": "33 %",
"D": "40 %",
"E": "50 %"
} | multiply(divide(multiply(choose(const_4, const_1), const_2), choose(6, 3)), multiply(multiply(const_5, const_5), const_4)) | choose(const_4,const_1)|choose(n0,n1)|multiply(const_5,const_5)|multiply(#0,const_2)|multiply(#2,const_4)|divide(#3,#1)|multiply(#5,#4)| | "total number of ways to choose 3 member committee - 6 c 3 = ( 6 ! / 3 ! 3 ! ) = 20 no . of ways albert n jane are in same committee : - ( 4 c 1 * 2 ) = 8 probability w = ( 8 / 20 ) * 100 = 40 % . + 1 for me . . : d" | probability |
math_qa__0ueNngzMOfj3vvjO | How many plants will be there in a circular bed whose outer edge measure 35 cms, allowing 4 cm2 for each plant ? Choose the correct choice from the following answers.
A) 18
B) 750
C) 24
D) 19
E) none of these | <gadget id="calculator">2 * pi</gadget>
<output>2*pi = around 6.283185</output>
<gadget id="calculator">35 / (2*pi)</gadget>
<output>35/(2*pi) = around 5.570423</output>
<gadget id="calculator">pi * ((35/(2*pi)) ** 2)</gadget>
<output>1225/(4*pi) = around 97.482403</output>
<gadget id="calculator">(1225/(4*pi)) / 4</gadget>
<output>1225/(16*pi) = around 24.370601</output>
<result>C</result> | C | 24 | How many plants will be there in a circular bed whose outer edge measure 35 cms, allowing 4 cm2 for each plant ? | {
"A": "18",
"B": "750",
"C": "24",
"D": "19",
"E": "none of these"
} | divide(circle_area(divide(35, multiply(2, const_pi))), 4) | multiply(n2,const_pi)|divide(n0,#0)|circle_area(#1)|divide(#2,n1)| | "circumference of circular bed = 35 cm area of circular bed = ( 35 ) 2 â „ 4 ï € space for each plant = 4 cm 2 â ˆ ´ required number of plants = ( 35 ) 2 â „ 4 ï € ã · 4 = 24.36 = 24 ( approx ) answer c" | physics |
math_qa__cm805bcyJn5o4AAS | The weights of one liter vegetable ghee packet of two brands ‘A’ and ‘B’ are 900 gm and 700 gm respectively. If they are mixed in the ratio of 3 : 2 by volumes to form a mixture of 4 liters, what is the weight (in kg) of the mixture? Choose one.
A) 3.84 B) 1.75 C) 3.28 D) 2.72 E) none of these | <gadget id="calculator">3 * 900</gadget>
<output>2_700</output>
<gadget id="calculator">2 * 700</gadget>
<output>1_400</output>
<gadget id="calculator">2_700 + 1_400</gadget>
<output>4_100</output>
<gadget id="calculator">4 * 4_100</gadget>
<output>16_400</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">16_400 / 5</gadget>
<output>3_280</output>
<gadget id="calculator">3_280 / 1_000</gadget>
<output>82/25 = around 3.28</output>
<result>C</result> | C | 3.28 | The weights of one liter vegetable ghee packet of two brands ‘A’ and ‘B’ are 900 gm and 700 gm respectively. If they are mixed in the ratio of 3 : 2 by volumes to form a mixture of 4 liters, what is the weight (in kg) of the mixture? | {
"A": "3.84",
"B": "1.75",
"C": "3.28",
"D": "2.72",
"E": "none of these"
} | divide(divide(multiply(4, add(multiply(3, 900), multiply(2, 700))), add(3, 2)), const_1000) | add(n2,n3)|multiply(n0,n2)|multiply(n1,n3)|add(#1,#2)|multiply(n4,#3)|divide(#4,#0)|divide(#5,const_1000)| | "here ' s how i did it . my notes from reading the problem were : 1 l a = 900 gm 1 l b = 700 gm we are mixing five parts ( 3 parts a plus 2 parts b , 5 parts total ) to get 4 l , so 5 x = 4 - - - > x = 4 / 5 . each part is 4 / 5 of a liter . so if we have 3 parts a , we have 900 * 3 * ( 4 / 5 ) = 2160 if we have 2 parts b , we have 700 * 2 * ( 4 / 5 ) = 1120 2160 + 1120 = 3280 solving for units gives us 3.28 so the answer is c" | other |
math_qa__w0JdsHW4UKQXzUic | find the last 3 digit of 443^443. Choose the correct answer.
A) 306 B) 307 C) 308 D) 309 E) 310 | <gadget id="calculator">443 % 4</gadget>
<output>3</output>
<gadget id="calculator">443 ** 3</gadget>
<output>86_938_307</output>
<gadget id="calculator">86_938_307 % 1_000</gadget>
<output>307</output>
<result>B</result> | B | 307 | find the last 3 digit of 443^443. | {
"A": "306",
"B": "307",
"C": "308",
"D": "309",
"E": "310"
} | reminder(power(443, reminder(443, const_4)), const_1000) | reminder(n1,const_4)|power(n1,#0)|reminder(#1,const_1000) | power is 443 = > 443 / 4 rem = 3 so , 443 ^ 3 = 86938307 last 3 digit = 307 answer : b | general |
math_qa__JvVltAA0T7ndoaO0 | The average of 11numbers is 60. Out of 11numbers the average of first 6no. is 78, and last 6numbers is 75 then find 6th number? Choose one:
A) 258
B) 65
C) 58
D) 62
E) 48 | <gadget id="calculator">6 * 78</gadget>
<output>468</output>
<gadget id="calculator">6 * 75</gadget>
<output>450</output>
<gadget id="calculator">468 + 450</gadget>
<output>918</output>
<gadget id="calculator">11 * 60</gadget>
<output>660</output>
<gadget id="calculator">918 - 660</gadget>
<output>258</output>
<result>A</result> | A | 258 | The average of 11numbers is 60. Out of 11numbers the average of first 6no. is 78, and last 6numbers is 75 then find 6th number? | {
"A": "258",
"B": "65",
"C": "58",
"D": "62",
"E": "48"
} | subtract(add(multiply(6, 78), multiply(6, 75)), multiply(11, 60)) | multiply(n3,n4)|multiply(n3,n6)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2)| | "6 th number = sum of 1 st 6 no . s + sum of last 6 no . s - sum of 11 no . s answer = 6 * 78 + 6 * 75 - 11 * 60 = 258 answer is a" | general |
math_qa__dFlS4WWRZ6I9KBGb | A train running at the speed of 120 km/hr crosses a pole in 9 seconds. Find the length of the train.
Options
A) 100 meter B) 150 meter C) 200 meter D) 250 meter E) 300 meter | <gadget id="calculator">120 * 1_000</gadget>
<output>120_000</output>
<gadget id="calculator">120_000 / 3_600</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(100/3) * 9</gadget>
<output>300</output>
<result>E</result> | E | 300 | A train running at the speed of 120 km/hr crosses a pole in 9 seconds. Find the length of the train. | {
"A": "100 meter",
"B": "150 meter",
"C": "200 meter",
"D": "250 meter",
"E": "300 meter"
} | multiply(divide(multiply(120, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 120 * ( 5 / 18 ) m / sec = 200 / 6 m / sec length of train ( distance ) = speed * time ( 200 / 6 ) * 9 = 300 meter answer : e" | physics |
math_qa__jlg11cG1JXOsQdEL | Marts income is 60 percent more than Tims income and Tims income is 50 percent less than Juans income. What percentage of Juans income is Marts income Choices
A) 124 % B) 120 % C) 96 % D) 80 % E) 64 % | <gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">100 / 50</gadget>
<output>2</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">160 / 200</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<result>D</result> | D | 80 | Marts income is 60 percent more than Tims income and Tims income is 50 percent less than Juans income. What percentage of Juans income is Marts income | {
"A": "124 %",
"B": "120 %",
"C": "96 %",
"D": "80 %",
"E": "64 %"
} | multiply(divide(add(const_100, 60), multiply(divide(const_100, subtract(const_100, 50)), const_100)), const_100) | add(n0,const_100)|subtract(const_100,n1)|divide(const_100,#1)|multiply(#2,const_100)|divide(#0,#3)|multiply(#4,const_100)| | "m = ( 160 / 100 ) t t = ( 50 / 100 ) j = > m = ( 80 / 100 ) j answer d ." | general |
math_qa__sSu6UkyQUPB83dhP | 155 liters of a mixture of milk and water contains in the ratio 3:2. How much water should now be added so that the ratio of milk and water becomes 3:4? Answers:
A) 12 liters B) 62 liters C) 41 liters D) 50 liters E) 34 liters | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">155 / 5</gadget>
<output>31</output>
<gadget id="calculator">31 * 2</gadget>
<output>62</output>
<result>B</result> | B | 62 | 155 liters of a mixture of milk and water contains in the ratio 3:2. How much water should now be added so that the ratio of milk and water becomes 3:4? | {
"A": "12 liters",
"B": "62 liters",
"C": "41 liters",
"D": "50 liters",
"E": "34 liters"
} | multiply(divide(155, add(3, 2)), 2) | add(n1,n2)|divide(n0,#0)|multiply(n2,#1) | milk = 3 / 5 * 155 = 93 liters water = 62 liters 93 : ( 62 + p ) = 3 : 4 186 + 3 p = 372 = > p = 62 62 liters of water are to be added for the ratio become 3 : 4 . answer : b | general |
math_qa__xKkXEAKTLcp6aIGN | The center of a circle lies on the origin of the coordinate plane. If a point (x, y) is randomly selected inside of the circle, what is the probability that y > 0 and y > x? Choose the correct choice from the following options.
A) 1 / 8 B) 1 / 6 C) 3 / 8 D) 1 / 2 E) 3 / 4 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<result>C</result> | C | 0.375 | The center of a circle lies on the origin of the coordinate plane. If a point (x, y) is randomly selected inside of the circle, what is the probability that y > 0 and y > x? | {
"A": "1 / 8",
"B": "1 / 6",
"C": "3 / 8",
"D": "1 / 2",
"E": "3 / 4"
} | divide(const_3, multiply(const_2, const_4)) | multiply(const_2,const_4)|divide(const_3,#0) | the line y = x divides the circle into two equal areas . all the points above the line y = x satisfy the condition that y > x . all the points above the x - axis satisfy the condition that y > 0 . the intersection of these two areas is 3 / 8 of the circle . the answer is c . | physics |
math_qa__NogrRsYf0CGav3VG | If 821562 is to be divisible by 5, what is the least whole number that should be added to it? Select the correct option: A) 6 B) 4 C) 5 D) 2 E) 3 | <gadget id="calculator">floor(5)</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>A</result> | A | 6 | If 821562 is to be divisible by 5, what is the least whole number that should be added to it? | {
"A": "6",
"B": "4",
"C": "5",
"D": "2",
"E": "3"
} | add(floor(5), const_1) | floor(n1)|add(#0,const_1) | a number is divisible by 8 if the number formed by the last three digits is divisible by 8 . here , 821562 = 562 , the next multiple of 9 is 568 . 6 must be added to 821562 to make it divisible by 8 a | general |
math_qa__OClYTSlOhJwrBBva | In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 16 percent of revenues. The profits in 2009 were what percent of the profits in 2008? Choose one.
A) 80 % B) 105 % C) 120 % D) 124.2 % E) 128 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">16 * (4/5)</gadget>
<output>64/5 = around 12.8</output>
<gadget id="calculator">(64/5) / 10</gadget>
<output>32/25 = around 1.28</output>
<gadget id="calculator">(32/25) * 100</gadget>
<output>128</output>
<result>E</result> | E | 128 | In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 16 percent of revenues. The profits in 2009 were what percent of the profits in 2008? | {
"A": "80 %",
"B": "105 %",
"C": "120 %",
"D": "124.2 %",
"E": "128 %"
} | multiply(divide(multiply(16, subtract(const_1, divide(20, const_100))), 10), const_100) | divide(n3,const_100)|subtract(const_1,#0)|multiply(n4,#1)|divide(#2,n1)|multiply(#3,const_100)| | "x = profits r = revenue x / r = 0,1 x = 10 r = 100 2009 : r = 80 x / 80 = 0,16 = 16 / 100 x = 80 * 16 / 100 x = 12.8 12.8 / 10 = 1,28 = 128 % , answer e" | gain |
math_qa__AVxsk6edeDnxvszp | What is the unit digit of 3^58? Pick
A) 0 B) 5 C) 7 D) 1 E) 9 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">9 % 10</gadget>
<output>9</output>
<result>E</result> | E | 9 | What is the unit digit of 3^58? | {
"A": "0",
"B": "5",
"C": "7",
"D": "1",
"E": "9"
} | reminder(power(3, const_2), const_10) | power(n0,const_2)|reminder(#0,const_10)| | "unit digit in 3 ^ 58 = unit digit in [ ( 3 ^ 4 ) ^ 14 ] * 3 ^ 2 = 1 * 9 = 9 answer is e" | general |
math_qa__uubnSfF3sK1Srrqn | If the average (arithmetic mean) of a and b is 35 and the average of b and c is 80, what is the value of c − a? Choose the correct choice: A) 25 B) 50 C) 90 D) 140 E) it can not be determined from the information given . | <gadget id="calculator">80 * 2</gadget>
<output>160</output>
<gadget id="calculator">35 * 2</gadget>
<output>70</output>
<gadget id="calculator">160 - 70</gadget>
<output>90</output>
<result>C</result> | C | 90 | If the average (arithmetic mean) of a and b is 35 and the average of b and c is 80, what is the value of c − a? | {
"A": "25",
"B": "50",
"C": "90",
"D": "140",
"E": "it can not be determined from the information given ."
} | subtract(multiply(80, const_2), multiply(35, const_2)) | multiply(n1,const_2)|multiply(n0,const_2)|subtract(#0,#1)| | "- ( a + b = 70 ) b + c = 160 c - a = 90 c . 90" | general |
math_qa__p6RXuI2jfFcewqvS | A group of men decided to do a work in 17 days, but 8 of them became absent. If the rest of the group did the work in 21days, Find the original number of men?
Choose the most appropriate option.
A) 15 B) 20 C) 42 D) 25 E) 18 | <gadget id="calculator">8 * 21</gadget>
<output>168</output>
<gadget id="calculator">21 - 17</gadget>
<output>4</output>
<gadget id="calculator">168 / 4</gadget>
<output>42</output>
<result>C</result> | C | 42 | A group of men decided to do a work in 17 days, but 8 of them became absent. If the rest of the group did the work in 21days, Find the original number of men? | {
"A": "15",
"B": "20",
"C": "42",
"D": "25",
"E": "18"
} | divide(multiply(8, 21), subtract(21, 17)) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "original number of men = 8 * 21 / ( 21 - 17 ) = 42 answer is c" | physics |
math_qa__VTFbZUmo1OcuBMn6 | Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 10% profit? Choose the correct choice from the following options:
A) 13.86 B) 16.33 C) 16.35 D) 16.3 E) 16.32 | <gadget id="calculator">30 * 11.5</gadget>
<output>345</output>
<gadget id="calculator">20 * 14.25</gadget>
<output>285</output>
<gadget id="calculator">345 + 285</gadget>
<output>630</output>
<gadget id="calculator">630 / 100</gadget>
<output>63/10 = around 6.3</output>
<gadget id="calculator">(63/10) * 10</gadget>
<output>63</output>
<gadget id="calculator">630 + 63</gadget>
<output>693</output>
<gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">693 / 50</gadget>
<output>693/50 = around 13.86</output>
<result>A</result> | A | 13.86 | Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 10% profit? | {
"A": "13.86",
"B": "16.33",
"C": "16.35",
"D": "16.3",
"E": "16.32"
} | divide(add(add(multiply(30, 11.50), multiply(20, 14.25)), multiply(divide(add(multiply(30, 11.50), multiply(20, 14.25)), const_100), 10)), add(30, 20)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,const_100)|multiply(n4,#4)|add(#3,#5)|divide(#6,#0)| | "c . p . of 50 kg wheat = ( 30 * 11.50 + 20 * 14.25 ) = rs . 630 . s . p . of 50 kg wheat = 110 % of rs . 630 = 110 / 100 * 630 = rs . 693 s . p . per kg = 693 / 50 = rs . 13.86 answer : a" | gain |
math_qa__jciTdAnSa7pp2sZu | In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/6 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented?
Choose the most appropriate option
A) 50 B) 70 C) 10 D) 105 E) 140 | <gadget id="calculator">490 / 7</gadget>
<output>70</output>
<gadget id="calculator">4 * 70</gadget>
<output>280</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">280 / 7</gadget>
<output>40</output>
<gadget id="calculator">6 * 40</gadget>
<output>240</output>
<gadget id="calculator">280 - 240</gadget>
<output>40</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">40 / (1/6)</gadget>
<output>240</output>
<gadget id="calculator">490 - 240</gadget>
<output>250</output>
<gadget id="calculator">250 - 240</gadget>
<output>10</output>
<result>C</result> | C | 10 | In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/6 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented? | {
"A": "50",
"B": "70",
"C": "10",
"D": "105",
"E": "140"
} | subtract(subtract(490, divide(subtract(multiply(4, divide(490, 7)), multiply(6, divide(multiply(4, divide(490, 7)), add(6, 1)))), divide(1, 6))), multiply(6, divide(multiply(4, divide(490, 7)), add(6, 1)))) | add(n3,n4)|divide(n0,n2)|divide(n3,n4)|multiply(n1,#1)|divide(#3,#0)|multiply(n4,#4)|subtract(#3,#5)|divide(#6,#2)|subtract(n0,#7)|subtract(#8,#5) | rented = 4 / 7 * 490 = 280 . rented two - bedroom = 6 / 7 * 280 = 240 ; rented one - bedroom = 1 / 7 * 280 = 40 ( or 280 - 240 = 40 ) . rented one - bedroom units are 1 / 5 of all one - bedroom : 1 / 6 * { all one bedroom } = 40 - - > { all one - bedroom } = 240 . { all two - bedroom } = 490 - 240 = 250 . two - bedroom not rented = 250 - 240 = 10 . answer : c . | general |
math_qa__wQhtsmW7cNlwYToQ | A certain bus driver is paid a regular rate of $16 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $976 in total compensation, how many total hours did he work that week? Choose the correct option: A) 51 B) 52 C) 59 D) 55 E) 56 | <gadget id="calculator">16 * 40</gadget>
<output>640</output>
<gadget id="calculator">976 - 640</gadget>
<output>336</output>
<gadget id="calculator">100 + 75</gadget>
<output>175</output>
<gadget id="calculator">16 * 175</gadget>
<output>2_800</output>
<gadget id="calculator">2_800 / 100</gadget>
<output>28</output>
<gadget id="calculator">336 / 28</gadget>
<output>12</output>
<gadget id="calculator">40 + 12</gadget>
<output>52</output>
<result>B</result> | B | 52 | A certain bus driver is paid a regular rate of $16 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $976 in total compensation, how many total hours did he work that week? | {
"A": "51",
"B": "52",
"C": "59",
"D": "55",
"E": "56"
} | add(40, divide(subtract(976, multiply(16, 40)), divide(multiply(16, add(const_100, 75)), const_100))) | add(n3,const_100)|multiply(n0,n1)|multiply(n0,#0)|subtract(n4,#1)|divide(#2,const_100)|divide(#3,#4)|add(n1,#5)| | "for 40 hrs = 40 * 16 = 640 excess = 976 - 640 = 336 for extra hours = . 75 ( 16 ) = 12 + 16 = 28 number of extra hrs = 336 / 28 = 12 total hrs = 40 + 12 = 52 answer b" | general |
math_qa__3FVNETxn2wN5RMvM | A works twice as fast as B.If B can complete a work in 18 days independently,the number of days in which A and B can together finish the work is: Choose the correct choice from the following options:
A) 4 days B) 6 days C) 8 days D) 10 days E) 12 days | <gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">2 * (1/18)</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/18) + (1/9)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>B</result> | B | 6 | A works twice as fast as B.If B can complete a work in 18 days independently,the number of days in which A and B can together finish the work is: | {
"A": "4 days",
"B": "6 days",
"C": "8 days",
"D": "10 days",
"E": "12 days"
} | inverse(add(divide(const_1, 18), multiply(const_2, divide(const_1, 18)))) | divide(const_1,n0)|multiply(#0,const_2)|add(#0,#1)|inverse(#2)| | "explanation : ratio of rates of working of a and b = 2 : 1 . so , ratio of times taken = 1 : 2 a ' s 1 day ' s work = 1 / 9 b ' s 1 day ' s work = 1 / 18 ( a + b ) ' s 1 day ' s work = ( 1 / 9 + 1 / 18 ) = 3 / 18 = 1 / 6 so , a and b together can finish the work in 6 days answer is b" | physics |
math_qa__2eW7pGJDLbSIDZOj | he average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ? Options.
A) 75 kg
B) 55 kg
C) 45 kg
D) 85 kg
E) 25 kg | <gadget id="calculator">2.5 * 8</gadget>
<output>20</output>
<gadget id="calculator">20 + 65</gadget>
<output>85</output>
<result>D</result> | D | 85 | he average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ? | {
"A": "75 kg",
"B": "55 kg",
"C": "45 kg",
"D": "85 kg",
"E": "25 kg"
} | add(multiply(2.5, 8), 65) | multiply(n0,n1)|add(n2,#0) | explanation : total weight increased = ( 8 x 2.5 ) kg = 20 kg . weight of new person = ( 65 + 20 ) kg = 85 kg . answer : d | general |
math_qa__fLa94QGVPRP1X1yB | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 8800. What is the share of B ? Answers:
A) 1100 B) 800 C) 1400 D) 1200 E) 1600 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 3</gadget>
<output>2</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<gadget id="calculator">2 / 11</gadget>
<output>2/11 = around 0.181818</output>
<gadget id="calculator">8_800 * (2/11)</gadget>
<output>1_600</output>
<result>E</result> | E | 1,600 | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 8800. What is the share of B ? | {
"A": "1100",
"B": "800",
"C": "1400",
"D": "1200",
"E": "1600"
} | multiply(8800, divide(const_2, add(add(multiply(const_2, 3), multiply(divide(const_2, 3), 3)), 3))) | divide(const_2,n0)|multiply(const_2,n0)|multiply(#0,n0)|add(#1,#2)|add(#3,n0)|divide(const_2,#4)|multiply(n1,#5)| | "let c ' s capital = rs . x . then , b ' s capital = rs . ( 2 / 3 ) x a ’ s capital = rs . ( 3 x ( 2 / 3 ) . x ) = rs . 2 x . ratio of their capitals = 2 x : ( 2 / 3 ) x : x = 6 : 2 : 3 . hence , b ' s share = rs . ( 8800 x ( 2 / 11 ) ) = rs . 1600 . answer is e" | gain |
math_qa__OXbrinz737aGwmVv | How many numbers are divisible by 4 between 1 and 100?
Pick
A) 25 B) 24 C) 23 D) 22 E) 20 | <gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">100 / 4</gadget>
<output>25</output>
<result>B</result> | B | 24 | How many numbers are divisible by 4 between 1 and 100? | {
"A": "25",
"B": "24",
"C": "23",
"D": "22",
"E": "20"
} | divide(100, multiply(4, 1)) | multiply(n0,n1)|divide(n2,#0)| | "numbers divisible by 4 till 100 = ( 100 / 4 ) = 25 but we should not consider 100 as we are asked to find the numbers between 1 and 100 which are divisible by 4 . so answer is 24 numbers . answer is option b" | general |
math_qa__AGQq5sWK7CeKPake | Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet? Choose the most appropriate option:
A) 20 / 8 sec B) 20 / 4 sec C) 20 / 7 sec D) 22 / 7 sec E) 60 / 7 sec | <gadget id="calculator">54 + 72</gadget>
<output>126</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">126 * (5/18)</gadget>
<output>35</output>
<gadget id="calculator">100 / 35</gadget>
<output>20/7 = around 2.857143</output>
<result>C</result> | C | 2.857143 | Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet? | {
"A": "20 / 8 sec",
"B": "20 / 4 sec",
"C": "20 / 7 sec",
"D": "22 / 7 sec",
"E": "60 / 7 sec"
} | divide(100, multiply(add(54, 72), const_0_2778)) | add(n3,n4)|multiply(#0,const_0_2778)|divide(n2,#1)| | "they are moving in opposite directions , relative speed is equal to the sum of their speeds . relative speed = ( 54 + 72 ) * 5 / 18 = 7 * 5 = 35 mps . the time required = d / s = 100 / 35 = 20 / 7 sec . answer : c" | physics |
math_qa__PfoCBbNr8bSxVHaR | an oil cylinder was 3 / 4 th full . when 4 bottles of oil is poured into it , it is 4 / 5 th full . how many bottles of oil can the full cylinder hold ? Choose one
A) 90 B) 75 C) 70 D) 80 E) 85 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(4/5) - (3/4)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) / 4</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">1 / (1/80)</gadget>
<output>80</output>
<result>D</result> | D | 80 | an oil cylinder was 3 / 4 th full . when 4 bottles of oil is poured into it , it is 4 / 5 th full . how many bottles of oil can the full cylinder hold ? | {
"A": "90",
"B": "75",
"C": "70",
"D": "80",
"E": "85"
} | divide(const_1, divide(subtract(divide(4, 5), divide(3, 4)), 4)) | divide(n1,n4)|divide(n0,n1)|subtract(#0,#1)|divide(#2,n1)|divide(const_1,#3) | ( 4 / 5 - 3 / 4 ) cylinder is filled by 4 bottles 0.8 - 0.75 = 0.05 cylinder is filled by 4 bottles 1 cylinder is filled by 4 / 0.05 = 80 bottles answer : d | geometry |
math_qa__vf6cCrBt3AN082km | If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2013) = ?
Select.
A) 2014 B) 2088 C) 270 D) 1881 E) 1781 | <gadget id="calculator">1 + 2_013</gadget>
<output>2_014</output>
<result>A</result> | A | 2,014 | If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2013) = ? | {
"A": "2014",
"B": "2088",
"C": "270",
"D": "1881",
"E": "1781"
} | add(1, 2013) | add(n3,n4)| | "f ( f ( 0 ) ) + f ( 0 ) = 2 ( 0 ) + 3 ⇒ ⇒ f ( 1 ) = 3 - 1 = 2 , f ( 1 ) = 2 f ( f ( 1 ) ) + f ( 1 ) = 2 ( 1 ) + 3 ⇒ ⇒ f ( 2 ) = 5 - 2 = 3 , f ( 2 ) = 3 f ( f ( 2 ) ) + f ( 2 ) = 2 ( 2 ) + 3 ⇒ ⇒ f ( 3 ) = 7 - 3 = 4 , f ( 3 ) = 4 . . . . . . . . . . . . . . f ( 2013 ) = 2014 ans : a" | general |
math_qa__xA1pHTRXxmlXoGOH | Of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 30 grades are D's. What is the number of students in the course? Choose the correct choice from the following answers
A) 80 B) 110 C) 160 D) 600 E) 400 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/5) + (1/4)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(9/20) + (1/2)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">1 - (19/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">30 / (1/20)</gadget>
<output>600</output>
<result>D</result> | D | 600 | Of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 30 grades are D's. What is the number of students in the course? | {
"A": "80",
"B": "110",
"C": "160",
"D": "600",
"E": "400"
} | divide(30, subtract(1, add(add(divide(1, 5), divide(1, 4)), divide(1, 2)))) | divide(n0,n1)|divide(n0,n3)|divide(n0,n5)|add(#0,#1)|add(#3,#2)|subtract(n0,#4)|divide(n6,#5)| | "we start by creating a variable for the total number of students in the math course . we can say : t = total number of students in the math course next , we can use variable t in an equation that we translate from the given information . we are given that , of the final grades received by the students in a certain math course , 1 / 5 are a ' s , 1 / 4 are b ' s , 1 / 2 are c ' s , and the remaining 30 grades are d ' s . since this represents all the grades in the class , it represents all the students in the class . thus we know : # a ’ s + # b ’ s + # c ’ s + # d ’ s = total number of students in the class 1 / 5 ( t ) + ¼ ( t ) + ½ ( t ) + 30 = t we can multiply the entire equation by 20 to cancel out the denominators of the fractions and we have : 4 t + 5 t + 10 t + 600 = 20 t 19 t + 600 = 20 t 600 = t there are a total of 600 students in the math class . answer is d ." | general |
math_qa__NK9Xd3vVrKSz7NBU | A man can row 3 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man? Options
A) 2.9 B) 2.8 C) 2.4 D) 2.8 E) 2.2 | <gadget id="calculator">3 + 1.2</gadget>
<output>4.2</output>
<gadget id="calculator">3 - 1.2</gadget>
<output>1.8</output>
<gadget id="calculator">4.2 * 1.8</gadget>
<output>7.56</output>
<gadget id="calculator">4.2 + 1.8</gadget>
<output>6</output>
<gadget id="calculator">7.56 / 6</gadget>
<output>1.26</output>
<gadget id="calculator">1.26 * 2</gadget>
<output>2.52</output>
<result>C</result> | C | 2.4 | A man can row 3 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man? | {
"A": "2.9",
"B": "2.8",
"C": "2.4",
"D": "2.8",
"E": "2.2"
} | multiply(divide(multiply(add(3, 1.2), subtract(3, 1.2)), add(add(3, 1.2), subtract(3, 1.2))), const_2) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|multiply(#0,#1)|divide(#3,#2)|multiply(#4,const_2)| | "m = 3 s = 1.2 ds = 3.6 us = 1.8 x / 3.6 + x / 1.8 = 1 x = 1.2 d = 1.2 * 2 = 2.4 answer : c" | physics |
math_qa__buxsYUFxbHikdfpr | Lloyd normally works 7.5 hours per day and earns $4.50 per hour. For each hour he works in excess of 7.5 hours on a given day, he is paid 2.5 times his regular rate. If Lloyd works 10.5 hours on a given day, how much does he earn for that day? Choose the correct choice: A) $ 33.75 B) $ 47.25 C) $ 51.75 D) $ 54.00 E) $ 67.50 | <gadget id="calculator">7.5 * 4.5</gadget>
<output>33.75</output>
<gadget id="calculator">10.5 - 7.5</gadget>
<output>3</output>
<gadget id="calculator">3 * 2.5</gadget>
<output>7.5</output>
<gadget id="calculator">33.75 + 33.75</gadget>
<output>67.5</output>
<result>E</result> | E | 67.5 | Lloyd normally works 7.5 hours per day and earns $4.50 per hour. For each hour he works in excess of 7.5 hours on a given day, he is paid 2.5 times his regular rate. If Lloyd works 10.5 hours on a given day, how much does he earn for that day? | {
"A": "$ 33.75",
"B": "$ 47.25",
"C": "$ 51.75",
"D": "$ 54.00",
"E": "$ 67.50"
} | add(multiply(7.5, 4.50), multiply(multiply(subtract(10.5, 7.5), 2.5), 4.50)) | multiply(n0,n1)|subtract(n4,n0)|multiply(n3,#1)|multiply(n1,#2)|add(#0,#3)| | "daily working hour * regular rate + overtime * increased rate 7.5 * 4.5 + 3 * 4.5 * 2.5 = 67.5 answer e" | physics |
math_qa__j7zydTC4WSPwvjLE | If a large pizza has a radius that is 40% larger that that of a medium pizza, what is the percent increase in area between a medium and a large pizza? Choose the most appropriate option
A) 40 % B) 80 % C) 96 % D) 112 % E) 124 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) ** 2</gadget>
<output>49/25 = around 1.96</output>
<gadget id="calculator">(49/25) - 1</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">(24/25) * 100</gadget>
<output>96</output>
<result>C</result> | C | 96 | If a large pizza has a radius that is 40% larger that that of a medium pizza, what is the percent increase in area between a medium and a large pizza? | {
"A": "40 %",
"B": "80 %",
"C": "96 %",
"D": "112 %",
"E": "124 %"
} | multiply(subtract(power(add(const_1, divide(40, const_100)), const_2), const_1), const_100) | divide(n0,const_100)|add(#0,const_1)|power(#1,const_2)|subtract(#2,const_1)|multiply(#3,const_100) | let the radius of medium pizza be r . then the radius of large pizza is 1.4 r . the area of the medium pizza is pi * r ^ 2 the area of the large pizza is pi * ( 1.4 * r ) ^ 2 = 1.96 * pi * r ^ 2 , an increase of 96 % . the answer is c . | gain |
math_qa__vwYp5MLnQsJnGxXM | If Tim had lunch at $60.50 and he gave 20% tip, how much did he spend?
Choose the correct choice from the following answers:
A) $ 30.60 B) $ 72.60 C) $ 70.60 D) $ 40.60 E) $ 50.60 | <gadget id="calculator">60.5 * 20</gadget>
<output>1_210</output>
<gadget id="calculator">1_210 / 100</gadget>
<output>121/10 = around 12.1</output>
<gadget id="calculator">60.5 + (121/10)</gadget>
<output>72.6</output>
<result>B</result> | B | 72.6 | If Tim had lunch at $60.50 and he gave 20% tip, how much did he spend? | {
"A": "$ 30.60",
"B": "$ 72.60",
"C": "$ 70.60",
"D": "$ 40.60",
"E": "$ 50.60"
} | add(60.50, divide(multiply(60.50, 20), const_100)) | multiply(n0,n1)|divide(#0,const_100)|add(n0,#1)| | "the tip is 20 % of what he paid for lunch . hence tip = 20 % of 60.50 = ( 20 / 100 ) * 60.50 = $ 12.1 total spent 60.50 + 12.1 = $ 72.6 correct answer b" | gain |
math_qa__UtuYYbGaf4hAhn7D | The salary of A, B, C, D, E is Rs. 8000, Rs. 5000, Rs. 14000, Rs. 7000, Rs. 9000 per month respectively, then the average salary of A, B, C, D, and E per month is Choose the correct choice from the following answers: A) rs . 7000 B) rs . 8000 C) rs . 8600 D) rs . 9000 E) none | <gadget id="calculator">8_000 + 5_000</gadget>
<output>13_000</output>
<gadget id="calculator">13_000 + 14_000</gadget>
<output>27_000</output>
<gadget id="calculator">27_000 + 7_000</gadget>
<output>34_000</output>
<gadget id="calculator">34_000 + 9_000</gadget>
<output>43_000</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">43_000 / 5</gadget>
<output>8_600</output>
<result>C</result> | C | 8,600 | The salary of A, B, C, D, E is Rs. 8000, Rs. 5000, Rs. 14000, Rs. 7000, Rs. 9000 per month respectively, then the average salary of A, B, C, D, and E per month is | {
"A": "rs . 7000",
"B": "rs . 8000",
"C": "rs . 8600",
"D": "rs . 9000",
"E": "none"
} | divide(add(add(add(add(8000, 5000), 14000), 7000), 9000), add(const_4, const_1)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1) | answer average salary = 8000 + 5000 + 14000 + 7000 + 9000 / 5 = rs . 8600 correct option : c | general |
math_qa__nIQeq27dOoNpvOoU | A can do a piece of work in 20 days and B can do it in 30 days and C can do it 10 days. They started the work together and A leaves after 2 days and C leaves after 4 days from the beginning. How long will work lost?
Pick.
A) 13 B) 16 C) 25 D) 14 E) 15 | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/30) + (1/10)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">2 * (2/15)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + (1/30)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/10) + (1/12)</gadget>
<output>11/60 = around 0.183333</output>
<gadget id="calculator">(11/60) * 2</gadget>
<output>11/30 = around 0.366667</output>
<gadget id="calculator">(4/15) + (11/30)</gadget>
<output>19/30 = around 0.633333</output>
<gadget id="calculator">1 - (19/30)</gadget>
<output>11/30 = around 0.366667</output>
<gadget id="calculator">(11/30) / (1/30)</gadget>
<output>11</output>
<gadget id="calculator">11 + 4</gadget>
<output>15</output>
<result>E</result> | E | 15 | A can do a piece of work in 20 days and B can do it in 30 days and C can do it 10 days. They started the work together and A leaves after 2 days and C leaves after 4 days from the beginning. How long will work lost? | {
"A": "13",
"B": "16",
"C": "25",
"D": "14",
"E": "15"
} | add(divide(subtract(const_1, add(multiply(subtract(4, 2), add(inverse(30), inverse(10))), multiply(add(inverse(10), add(inverse(20), inverse(30))), 2))), inverse(30)), 4) | inverse(n1)|inverse(n2)|inverse(n0)|subtract(n4,n3)|add(#0,#1)|add(#2,#0)|add(#5,#1)|multiply(#4,#3)|multiply(n3,#6)|add(#7,#8)|subtract(const_1,#9)|divide(#10,#0)|add(n4,#11) | 2 / 20 + x / 30 + 4 / 10 = 1 x = 300 / 20 = 15 answer : e | physics |
math_qa__iAxa7dCMy1GwzOjr | In February Wilson’s earnings were 40 percent of his family’s total income. In March Wilson earned 25 percent less than in February. If the rest of his family’s income was the same in both months, then, in March, Wilson’s earnings were approximately what percent of his family’s total income? Choose the correct choice from the following options:
A) 15 % B) 17 % C) 24 % D) 30 % E) 33 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * (2/5)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(2/5) - (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(3/10) / (9/10)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33 | In February Wilson’s earnings were 40 percent of his family’s total income. In March Wilson earned 25 percent less than in February. If the rest of his family’s income was the same in both months, then, in March, Wilson’s earnings were approximately what percent of his family’s total income? | {
"A": "15 %",
"B": "17 %",
"C": "24 %",
"D": "30 %",
"E": "33 %"
} | multiply(divide(subtract(divide(40, const_100), multiply(divide(25, const_100), divide(40, const_100))), subtract(const_1, multiply(divide(25, const_100), divide(40, const_100)))), const_100) | divide(n0,const_100)|divide(n1,const_100)|multiply(#1,#0)|subtract(#0,#2)|subtract(const_1,#2)|divide(#3,#4)|multiply(#5,const_100)| | "lets suppose the total family income in feb = 100 x wilson ' s earning in feb = 40 % of 100 x = 40 x earnings of remaining family in feb = 100 x - 40 x = 60 x wilson ' s earning in march = 75 % of wilson ' s feb earnings = 75 % of 40 x = 30 x earnings of remaining family in march = earnings of remaining family in feb = 60 x thus wilson ' s earning as % of total family income in march = 30 x / ( 30 + 60 ) x = 30 x / 90 x = 33.33 % thus answer is e" | general |
math_qa__g06ySVrtbf1jHKLA | If 0.75 : x :: 7 : 8, then x is equal to: Choose the correct option: A) 1.12 B) 1.2 C) 0.95 D) 0.85 E) 0.9 | <gadget id="calculator">0.75 * 8</gadget>
<output>6</output>
<gadget id="calculator">6 / 7</gadget>
<output>6/7 = around 0.857143</output>
<result>D</result> | D | 0.85 | If 0.75 : x :: 7 : 8, then x is equal to: | {
"A": "1.12",
"B": "1.2",
"C": "0.95",
"D": "0.85",
"E": "0.9"
} | divide(multiply(0.75, 8), 7) | multiply(n0,n2)|divide(#0,n1)| | "( x * 7 ) = ( 0.75 * 8 ) x = 6 / 7 x = 0.85 answer = d" | general |
math_qa__I367GPBXDBKnzkQa | Tom drives from town R to town B, driving at a constant speed of 60 miles per hour. From town B Tom immediately continues to town C. The distance between R and B is twice the distance between B and C. If the average speed of the whole journey was 36 mph, then what is Tom's speed driving from B to C in miles per hour?
Choose the correct answer:
A) 12
B) 20
C) 24
D) 30
E) 36 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 / 36</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 / 60</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/12) - (1/30)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / (1/20)</gadget>
<output>20</output>
<result>B</result> | B | 20 | Tom drives from town R to town B, driving at a constant speed of 60 miles per hour. From town B Tom immediately continues to town C. The distance between R and B is twice the distance between B and C. If the average speed of the whole journey was 36 mph, then what is Tom's speed driving from B to C in miles per hour? | {
"A": "12",
"B": "20",
"C": "24",
"D": "30",
"E": "36"
} | divide(const_1, subtract(divide(add(const_1, const_2), 36), divide(const_2, 60))) | add(const_1,const_2)|divide(const_2,n0)|divide(#0,n1)|subtract(#2,#1)|divide(const_1,#3) | let ' s assume that it takes 4 hours to go from point r to b . then the distance between them becomes 240 which makes distance between b and c 120 . ( 240 + 120 ) / ( 4 + x ) gives us the average speed which is 36 . you find x = 6 . so the question simplifies itself to 120 / 6 = 20 hence the answer is b . | physics |
math_qa__Qzp0meQlHSsPXQVa | Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/3, what percent of the total number of the remaining employees would then be clerical?
Choices
A) 25 % B) 22.2 % C) 20 % D) 12.5 % E) 11.1 % | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(1/3) * (2/3)</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(2/9) + (2/3)</gadget>
<output>8/9 = around 0.888889</output>
<gadget id="calculator">(2/9) / (8/9)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>A</result> | A | 25 | Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/3, what percent of the total number of the remaining employees would then be clerical? | {
"A": "25 %",
"B": "22.2 %",
"C": "20 %",
"D": "12.5 %",
"E": "11.1 %"
} | multiply(divide(multiply(divide(1, 3), subtract(1, divide(1, 3))), add(multiply(divide(1, 3), subtract(1, divide(1, 3))), subtract(1, divide(1, 3)))), const_100) | divide(n1,n2)|divide(n3,n4)|subtract(n3,#1)|subtract(n3,#0)|multiply(#0,#2)|add(#4,#3)|divide(#4,#5)|multiply(#6,const_100)| | "let ' s see , the way i did it was 1 / 3 are clerical out of 3600 so 1200 are clerical 1200 reduced by 1 / 3 is 1200 * 1 / 3 so it reduced 400 people , so there is 800 clerical people left but since 400 people left , it also reduced from the total of 3600 so there are 3200 people total since 800 clerical left / 3200 people total you get ( a ) 25 %" | general |
math_qa__OfjHLObwxvgR13F4 | Two trains are moving in opposite directions with speed of 210 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. the slower train cross the faster train in --- seconds Select the correct option: A) 56 B) 48 C) 47 D) 26 E) 24 | <gadget id="calculator">1.1 + 0.9</gadget>
<output>2</output>
<gadget id="calculator">210 + 90</gadget>
<output>300</output>
<gadget id="calculator">2 / 300</gadget>
<output>1/150 = around 0.006667</output>
<gadget id="calculator">(1/150) * 3_600</gadget>
<output>24</output>
<result>E</result> | E | 24 | Two trains are moving in opposite directions with speed of 210 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. the slower train cross the faster train in --- seconds | {
"A": "56",
"B": "48",
"C": "47",
"D": "26",
"E": "24"
} | multiply(divide(add(1.1, 0.9), add(210, 90)), const_3600) | add(n2,n3)|add(n0,n1)|divide(#0,#1)|multiply(#2,const_3600) | explanation : relative speed = 210 + 90 = 300 km / hr ( since both trains are moving in opposite directions ) total distance = 1.1 + . 9 = 2 km time = 2 / 300 hr = 1 / 150 hr = 3600 / 150 seconds = 24 seconds answer : option e | physics |
math_qa__SNpHVooNKaZL4sTH | Pat, kate and mark charged a total of 216 hours to a certain project . If pat charged twice as much time to the project as kate and 1/3 as much times as mark, how many more hours did mark charge to the project than kate. Choose the correct answer:
A) 18
B) 36
C) 120
D) 90
E) 108 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">3 + 6</gadget>
<output>9</output>
<gadget id="calculator">216 / 9</gadget>
<output>24</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">24 * 5</gadget>
<output>120</output>
<result>C</result> | C | 120 | Pat, kate and mark charged a total of 216 hours to a certain project . If pat charged twice as much time to the project as kate and 1/3 as much times as mark, how many more hours did mark charge to the project than kate. | {
"A": "18",
"B": "36",
"C": "120",
"D": "90",
"E": "108"
} | multiply(divide(216, add(add(1, const_2), multiply(const_2, 3))), subtract(multiply(const_2, 3), 1)) | add(n1,const_2)|multiply(n2,const_2)|add(#0,#1)|subtract(#1,n1)|divide(n0,#2)|multiply(#4,#3)| | "let kate charge for x hours , then pat charged for 2 x and mat - for 6 x . so , 2 x + 6 x + x = 216 - total hours charged for , x = 24 . mat charged 6 x - x or 5 x for more hours than kate , or for 120 hours . c is correct" | general |
math_qa__FZRa032OE9uEvdPb | Find the principle on a certain sum of money at 5% per annum for 5 years if the amount being Rs.1120?
Select:
A) 896 B) 1067 C) 1977 D) 1056 E) 1097 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">1_120 / (5/4)</gadget>
<output>896</output>
<result>A</result> | A | 896 | Find the principle on a certain sum of money at 5% per annum for 5 years if the amount being Rs.1120? | {
"A": "896",
"B": "1067",
"C": "1977",
"D": "1056",
"E": "1097"
} | divide(1120, add(const_1, divide(multiply(5, 5), const_100))) | multiply(n0,n1)|divide(#0,const_100)|add(#1,const_1)|divide(n2,#2)| | "1120 = p [ 1 + ( 5 * 5 ) / 100 ] p = 896 answer : a" | gain |
math_qa__MqaadGq26LuLIZMP | 10 percent of the women in a college class are science majors , and the non - science majors make up 60 % of the class . what percentage of the men are science majors if 40 % of the class are men ? Options:
A) 45 %
B) 55 %
C) 65 %
D) 75 %
E) 85 % | <gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(4/5) + (1/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(17/20) * 100</gadget>
<output>85</output>
<result>E</result> | E | 85 | 10 percent of the women in a college class are science majors , and the non - science majors make up 60 % of the class . what percentage of the men are science majors if 40 % of the class are men ? | {
"A": "45 %",
"B": "55 %",
"C": "65 %",
"D": "75 %",
"E": "85 %"
} | multiply(add(divide(subtract(add(60, 40), multiply(10, const_2)), const_100), divide(divide(10, const_2), const_100)), const_100) | add(n1,n2)|divide(n0,const_2)|multiply(n0,const_2)|divide(#1,const_100)|subtract(#0,#2)|divide(#4,const_100)|add(#5,#3)|multiply(#6,const_100) | science majors make up 0.4 of the class . 60 % of the class are women and 0.1 * 0.6 = 0.06 of the class are female science majors . then 0.34 of the class are male science majors . 0.4 x = 0.34 x = 0.85 = 85 % the answer is e . | gain |
math_qa__W49XlB2DmWVrEgRK | A 40-liter solution of alcohol and water is 5 percent alcohol. If 6.5 liters of alcohol and 3.5 liters of water are added to this solution, what percent of the solution produced is alcohol? Choose one.
A) 13 % B) 14 % C) 15 % D) 16 % E) 17 % | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">40 * (1/20)</gadget>
<output>2</output>
<gadget id="calculator">2 + 6.5</gadget>
<output>8.5</output>
<gadget id="calculator">6.5 + 3.5</gadget>
<output>10</output>
<gadget id="calculator">40 + 10</gadget>
<output>50</output>
<gadget id="calculator">8.5 / 50</gadget>
<output>0.17</output>
<gadget id="calculator">0.17 * 100</gadget>
<output>17</output>
<result>E</result> | E | 17 | A 40-liter solution of alcohol and water is 5 percent alcohol. If 6.5 liters of alcohol and 3.5 liters of water are added to this solution, what percent of the solution produced is alcohol? | {
"A": "13 %",
"B": "14 %",
"C": "15 %",
"D": "16 %",
"E": "17 %"
} | multiply(divide(add(multiply(40, divide(5, const_100)), 6.5), add(40, add(6.5, 3.5))), const_100) | add(n2,n3)|divide(n1,const_100)|add(n0,#0)|multiply(n0,#1)|add(n2,#3)|divide(#4,#2)|multiply(#5,const_100)| | "the percent of alcohol in the solution is ( 0.05 ( 40 ) + 6.5 ) / 50 = 8.5 / 50 = 17 % the answer is e ." | general |
math_qa__D68yl7yClJclpzOP | Rs. 730 were divided among Punith, Michael, Suresh in such a way that if Punith gets Rs. 3, then Michael gets Rs. 4 and if Michael gets Rs. 3.50 then Suresh gets Rs. 3. The share of Michael exceeds that of Suresh by Pick: A) rs 30 B) rs 40 C) rs 70 D) rs 210 E) rs 310 | <gadget id="calculator">4 * 3.5</gadget>
<output>14</output>
<gadget id="calculator">3 * 3.5</gadget>
<output>10.5</output>
<gadget id="calculator">10.5 + 14</gadget>
<output>24.5</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">24.5 + 12</gadget>
<output>36.5</output>
<gadget id="calculator">730 / 36.5</gadget>
<output>20</output>
<gadget id="calculator">14 * 20</gadget>
<output>280</output>
<gadget id="calculator">12 * 20</gadget>
<output>240</output>
<gadget id="calculator">280 - 240</gadget>
<output>40</output>
<result>B</result> | B | 40 | Rs. 730 were divided among Punith, Michael, Suresh in such a way that if Punith gets Rs. 3, then Michael gets Rs. 4 and if Michael gets Rs. 3.50 then Suresh gets Rs. 3. The share of Michael exceeds that of Suresh by | {
"A": "rs 30",
"B": "rs 40",
"C": "rs 70",
"D": "rs 210",
"E": "rs 310"
} | subtract(multiply(multiply(4, 3.5), divide(730, add(add(multiply(3, 3.5), multiply(4, 3.5)), multiply(4, 3)))), multiply(multiply(4, 3), divide(730, add(add(multiply(3, 3.5), multiply(4, 3.5)), multiply(4, 3))))) | multiply(n1,n3)|multiply(n2,n3)|multiply(n1,n2)|add(#0,#1)|add(#3,#2)|divide(n0,#4)|multiply(#5,#1)|multiply(#5,#2)|subtract(#6,#7) | explanation : let a = punith , b = michael , c = suresh . a : b = 3 : 4 and b : c = 7 / 2 : 3 = ( 8 / 7 ) * ( 7 / 2 ) * ( 8 / 7 ) * 3 = 4 : ( 24 / 7 ) a : b : c = 3 : 4 : 24 / 7 = 21 : 28 : 24 . bs share = rs . [ 730 * ( 28 / 73 ) ] = rs . 280 . cs share = rs . [ 730 * ( 24 / 73 ) ] = rs . 240 . difference of their shares = 40 answer : b | general |
math_qa__W9aSvQDFjTpTYoVq | A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $222 for it, the cost price of the Cricket Bat for A is: Answers
A) 150 B) 148 C) 130 D) 160 E) 210 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(6/5) * (5/4)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">222 / (3/2)</gadget>
<output>148</output>
<result>B</result> | B | 148 | A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $222 for it, the cost price of the Cricket Bat for A is: | {
"A": "150",
"B": "148",
"C": "130",
"D": "160",
"E": "210"
} | divide(222, multiply(add(const_1, divide(20, const_100)), add(const_1, divide(25, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|divide(n2,#4)| | "125 % of 120 % of a = 222 125 / 100 * 120 / 100 * a = 222 a = 222 * 2 / 3 = 148 . answer b" | gain |
math_qa__S1kDJJKF8kvUx6I0 | There are 190 items that are members of set U. Of these items, 49 are members of set B, 59 are not members of either of set A or set B, and 23 are members of both sets A and B. How many of the members of set U are members of set A ? Choose the correct option:
A) 72
B) 85
C) 94
D) 105
E) 108 | <gadget id="calculator">190 - 59</gadget>
<output>131</output>
<gadget id="calculator">131 + 23</gadget>
<output>154</output>
<gadget id="calculator">154 - 49</gadget>
<output>105</output>
<result>D</result> | D | 105 | There are 190 items that are members of set U. Of these items, 49 are members of set B, 59 are not members of either of set A or set B, and 23 are members of both sets A and B. How many of the members of set U are members of set A ? | {
"A": "72",
"B": "85",
"C": "94",
"D": "105",
"E": "108"
} | subtract(add(subtract(190, 59), 23), 49) | subtract(n0,n2)|add(n3,#0)|subtract(#1,n1)| | "you had the answer almost right . the x = 82 refers to only set a . however what ' s being asked is how many members are part of set a . this will include : 1 . only set a 2 . set a and set b so the answer is set a = 82 + set ab = 82 + 23 = 105 d" | other |
math_qa__v6rRW1rKwJBAPKPp | In a 240 meters race A beats B by 56 m or 7 seconds. A's time over the course is: Choose the correct choice from the following choices.
A) 23 seconds
B) 12 seconds
C) 10 seconds
D) 18 seconds
E) 28 seconds | <gadget id="calculator">7 / 56</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 240</gadget>
<output>30</output>
<gadget id="calculator">30 - 7</gadget>
<output>23</output>
<result>A</result> | A | 23 | In a 240 meters race A beats B by 56 m or 7 seconds. A's time over the course is: | {
"A": "23 seconds",
"B": "12 seconds",
"C": "10 seconds",
"D": "18 seconds",
"E": "28 seconds"
} | subtract(multiply(divide(7, 56), 240), 7) | divide(n2,n1)|multiply(n0,#0)|subtract(#1,n2)| | "b runs 56 m in 7 sec . = > b runs 240 m in 7 / 56 * 240 = 30 seconds since a beats b by 7 seconds , a runs 240 m in ( 30 - 7 ) = 23 seconds hence , a ' s time over the course = 23 seconds answer : a" | physics |
math_qa__jc744QAXj0n4RpbJ | The perimeter of a semi circle is 198 cm then the radius is? Choose the correct choice from the following options
A) 22 B) 28 C) 98 D) 38.5 E) 13 | <gadget id="calculator">2 + pi</gadget>
<output>2 + pi = around 5.141593</output>
<gadget id="calculator">198 / (2 + pi)</gadget>
<output>198/(2 + pi) = around 38.509468</output>
<result>D</result> | D | 38.5 | The perimeter of a semi circle is 198 cm then the radius is? | {
"A": "22",
"B": "28",
"C": "98",
"D": "38.5",
"E": "13"
} | divide(198, add(const_2, const_pi)) | add(const_2,const_pi)|divide(n0,#0)| | "36 / 7 r = 198 = > r = 38.5 answer : d" | physics |
math_qa__Zj9voOiscfL1aOCJ | For any number Z, Z* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.35 – 6.35*? Choose the most appropriate option:
A) 0.35 B) 0.5 C) 6.25 D) 0.25 E) 6.0 | <gadget id="calculator">floor(6.35)</gadget>
<output>6</output>
<gadget id="calculator">6.35 - 6</gadget>
<output>0.35</output>
<result>A</result> | A | 0.35 | For any number Z, Z* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.35 – 6.35*? | {
"A": "0.35",
"B": "0.5",
"C": "6.25",
"D": "0.25",
"E": "6.0"
} | subtract(6.35, floor(6.35)) | floor(n0)|subtract(n0,#0)| | "since z * is defined as the greatest positive even integer less than or equal to z , then 6.35 * = 6 ( the greatest positive even integer less than or equal to 6.35 is 6 ) . hence , 6.35 – 6.35 * = 6.35 - 6 = 0.35 answer : a ." | general |
math_qa__HtaTaGjzo79ti0pN | Joe drives 360 miles at 60 miles per hour, and then he drives the next 120 miles at 40 miles per hour. What is his average speed for the entire trip in miles per hour? Pick one: A) 42 B) 53 C) 50 D) 54 E) 56 | <gadget id="calculator">360 + 120</gadget>
<output>480</output>
<gadget id="calculator">360 / 60</gadget>
<output>6</output>
<gadget id="calculator">120 / 40</gadget>
<output>3</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">480 / 9</gadget>
<output>160/3 = around 53.333333</output>
<result>B</result> | B | 53 | Joe drives 360 miles at 60 miles per hour, and then he drives the next 120 miles at 40 miles per hour. What is his average speed for the entire trip in miles per hour? | {
"A": "42",
"B": "53",
"C": "50",
"D": "54",
"E": "56"
} | divide(add(360, 120), add(divide(360, 60), divide(120, 40))) | add(n0,n2)|divide(n0,n1)|divide(n2,n3)|add(#1,#2)|divide(#0,#3) | t 1 = 360 / 60 = 6 hours t 2 = 120 / 40 = 3 hours t = t 1 + t 2 = 9 hours avg speed = total distance / t = 480 / 9 = 53 mph = b | physics |
math_qa__ulvSKTftjK2FIgUd | 12. What is the dividend. divisor 17, the quotient is 9 and the remainder is 8.
Select:
A) 161 B) 152 C) 154 D) 158 E) 144 | <gadget id="calculator">17 * 9</gadget>
<output>153</output>
<gadget id="calculator">153 + 8</gadget>
<output>161</output>
<result>A</result> | A | 161 | 12. What is the dividend. divisor 17, the quotient is 9 and the remainder is 8. | {
"A": "161",
"B": "152",
"C": "154",
"D": "158",
"E": "144"
} | add(multiply(17, 9), 8) | multiply(n1,n2)|add(n3,#0)| | "d = d * q + r d = 17 * 9 + 8 d = 153 + 8 d = 161 answer a" | general |
math_qa__pP3MJPsqZzzmEJth | Car A runs at the speed of 55 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B? Choose the most appropriate option: A) 3 : 7 B) 4 : 9 C) 11 : 7 D) 5 : 7 E) 6 : 11 | <gadget id="calculator">55 * 8</gadget>
<output>440</output>
<gadget id="calculator">70 * 4</gadget>
<output>280</output>
<gadget id="calculator">440 / 280</gadget>
<output>11/7 = around 1.571429</output>
<result>C</result> | C | 1.571429 | Car A runs at the speed of 55 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B? | {
"A": "3 : 7",
"B": "4 : 9",
"C": "11 : 7",
"D": "5 : 7",
"E": "6 : 11"
} | divide(multiply(55, 8), multiply(70, 4)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "car a travels 55 × 8 = 440 km car b travels 70 × 4 = 280 km the ratio is 440 : 280 = 44 : 28 = 11 : 7 the answer is c ." | physics |
math_qa__u81xd5A7jIw3qBrT | A train running at the speed of 70 km/hr crosses a pole in 36 seconds. What is the length of the train? Options
A) 700 B) 770 C) 707 D) 710 E) 720 | <gadget id="calculator">70 * 1_000</gadget>
<output>70_000</output>
<gadget id="calculator">70_000 / 3_600</gadget>
<output>175/9 = around 19.444444</output>
<gadget id="calculator">(175/9) * 36</gadget>
<output>700</output>
<result>A</result> | A | 700 | A train running at the speed of 70 km/hr crosses a pole in 36 seconds. What is the length of the train? | {
"A": "700",
"B": "770",
"C": "707",
"D": "710",
"E": "720"
} | multiply(divide(multiply(70, const_1000), const_3600), 36) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = ( 70 * 5 / 18 ) m / sec = ( 175 / 9 ) m / sec length of the train = ( speed x time ) = ( 175 / 9 * 36 ) m = 700 m . answer : a" | physics |
math_qa__23O0V6jN9qyQhAeA | A jeep takes 3 hours to cover a distance of 440 Km. how much should the speed in Kmph be maintained to cover the same direction in 1/2th of the previous time? Choose the correct option.
A) 48 kmph B) 252 kmph C) 293 kmph D) 263 kmph E) 265 kmph | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 3</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">440 / (3/2)</gadget>
<output>880/3 = around 293.333333</output>
<result>C</result> | C | 293 | A jeep takes 3 hours to cover a distance of 440 Km. how much should the speed in Kmph be maintained to cover the same direction in 1/2th of the previous time? | {
"A": "48 kmph",
"B": "252 kmph",
"C": "293 kmph",
"D": "263 kmph",
"E": "265 kmph"
} | divide(440, multiply(divide(1, 2), 3)) | divide(n2,n3)|multiply(n0,#0)|divide(n1,#1)| | "time = 3 distance = 340 1 / 2 of 3 hours = 6 * 1 / 2 = 1.5 hours required speed = 440 / 1.5 = 293 kmph c )" | physics |
math_qa__7p3A1fU1WwgcHJ3k | The ratio between the length and the breadth of a rectangular park is 1 : 4. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 min, then the area of the park (in sq. m) is? Choose the correct choice from the following answers.
A) 124545 m B) 134561 m C) 156787 m D) 15450 m E) 102400 m | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">12 / 60</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 8</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(8/5) * 1_000</gadget>
<output>1_600</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">1_600 / 5</gadget>
<output>320</output>
<gadget id="calculator">320 / 2</gadget>
<output>160</output>
<gadget id="calculator">160 * 4</gadget>
<output>640</output>
<gadget id="calculator">160 * 640</gadget>
<output>102_400</output>
<result>E</result> | E | 102,400 | The ratio between the length and the breadth of a rectangular park is 1 : 4. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 min, then the area of the park (in sq. m) is? | {
"A": "124545 m",
"B": "134561 m",
"C": "156787 m",
"D": "15450 m",
"E": "102400 m"
} | rectangle_area(divide(divide(multiply(multiply(divide(12, multiply(const_10, multiply(const_3, const_2))), 8), const_1000), add(1, 4)), const_2), multiply(divide(divide(multiply(multiply(divide(12, multiply(const_10, multiply(const_3, const_2))), 8), const_1000), add(1, 4)), const_2), 4)) | add(n0,n1)|multiply(const_2,const_3)|multiply(#1,const_10)|divide(n2,#2)|multiply(n3,#3)|multiply(#4,const_1000)|divide(#5,#0)|divide(#6,const_2)|multiply(n1,#7)|rectangle_area(#7,#8) | perimeter = distance covered in 8 min . = 12000 x 8 m = 1600 m . 60 let length = 1 x metres and breadth = 4 x metres . then , 2 ( 1 x + 4 x ) = 1600 or x = 160 . length = 160 m and breadth = 640 m . area = ( 160 x 640 ) m 2 = 102400 m e | physics |
math_qa__O7iLOkCE8OnS4gXw | The difference between the ages of two persons is 20 years. Fifteen years ago, the elder one was twice as old as the younger one. The present age of the younger person is? Choices: A) 30 B) 35 C) 25 D) 28 E) 32 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">20 - 5</gadget>
<output>15</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">5 + 30</gadget>
<output>35</output>
<result>B</result> | B | 35 | The difference between the ages of two persons is 20 years. Fifteen years ago, the elder one was twice as old as the younger one. The present age of the younger person is? | {
"A": "30",
"B": "35",
"C": "25",
"D": "28",
"E": "32"
} | add(subtract(20, subtract(20, add(const_3, const_2))), multiply(subtract(20, add(const_3, const_2)), const_2)) | add(const_2,const_3)|subtract(n0,#0)|multiply(#1,const_2)|subtract(n0,#1)|add(#2,#3) | let their ages be x years and ( x + 20 ) years then , ( x + 20 ) - 15 = 2 ( x - 15 ) x + 5 = 2 x - 30 x = 35 answer is b | general |
math_qa__2qumG89qvP9cek3O | If 70 percent of 600 is 40 percent of x, then x=? Choices.
A) 105 B) 168 C) 342 D) 660 E) 1050 | <gadget id="calculator">70 * 600</gadget>
<output>42_000</output>
<gadget id="calculator">42_000 / 40</gadget>
<output>1_050</output>
<result>E</result> | E | 1,050 | If 70 percent of 600 is 40 percent of x, then x=? | {
"A": "105",
"B": "168",
"C": "342",
"D": "660",
"E": "1050"
} | divide(multiply(70, 600), 40) | multiply(n0,n1)|divide(#0,n2)| | "given : 0.7 * 600 = 0.4 x - - > 420 = 4 / 10 * x - - > x = 1,050 . answer : e ." | general |
math_qa__O68DiQtb98yLRv2O | Find the sum of divisors of 544 which are perfect squares Choices.
A) 21
B) 22
C) 23
D) 24
E) 25 | <gadget id="calculator">544 / 2</gadget>
<output>272</output>
<gadget id="calculator">272 / 2</gadget>
<output>136</output>
<gadget id="calculator">136 / 2</gadget>
<output>68</output>
<gadget id="calculator">68 / 2</gadget>
<output>34</output>
<gadget id="calculator">34 / 2</gadget>
<output>17</output>
<gadget id="calculator">544 / 17</gadget>
<output>32</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">16 + 5</gadget>
<output>21</output>
<result>A</result> | A | 21 | Find the sum of divisors of 544 which are perfect squares | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | add(divide(divide(544, divide(divide(divide(divide(divide(544, const_2), const_2), const_2), const_2), const_2)), const_2), add(const_1, sqrt(divide(divide(544, divide(divide(divide(divide(divide(544, const_2), const_2), const_2), const_2), const_2)), const_2)))) | divide(n0,const_2)|divide(#0,const_2)|divide(#1,const_2)|divide(#2,const_2)|divide(#3,const_2)|divide(n0,#4)|divide(#5,const_2)|sqrt(#6)|add(#7,const_1)|add(#8,#6) | perfect squares divisiors are 1 , 2 ^ 2 & 2 ^ 4 only sum of divisors of 544 which are perfect squares = 1 + 2 ^ 2 + 2 ^ 4 = 21 answer : a | geometry |
math_qa__TxFX3RuJWfhxLY7J | Find compound interest on $ 6000 at 15% per annum for 2 years 4 months, compounded annually. Choices:
A) 2331.75
B) 2209.75
C) 2108.75
D) 2107.75
E) 2100.75 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">6_000 * (3/20)</gadget>
<output>900</output>
<gadget id="calculator">6_000 + 900</gadget>
<output>6_900</output>
<gadget id="calculator">6_900 * (3/20)</gadget>
<output>1_035</output>
<gadget id="calculator">900 + 1_035</gadget>
<output>1_935</output>
<gadget id="calculator">6_900 + 1_035</gadget>
<output>7_935</output>
<gadget id="calculator">(3/20) / 3</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">7_935 * (1/20)</gadget>
<output>1_587/4 = around 396.75</output>
<gadget id="calculator">1_935 + (1_587/4)</gadget>
<output>9_327/4 = around 2_331.75</output>
<result>A</result> | A | 2,331.75 | Find compound interest on $ 6000 at 15% per annum for 2 years 4 months, compounded annually. | {
"A": "2331.75",
"B": "2209.75",
"C": "2108.75",
"D": "2107.75",
"E": "2100.75"
} | add(add(multiply(6000, divide(15, const_100)), multiply(add(6000, multiply(6000, divide(15, const_100))), divide(15, const_100))), multiply(add(add(6000, multiply(6000, divide(15, const_100))), multiply(add(6000, multiply(6000, divide(15, const_100))), divide(15, const_100))), divide(divide(15, const_100), const_3))) | divide(n1,const_100)|divide(#0,const_3)|multiply(n0,#0)|add(n0,#2)|multiply(#3,#0)|add(#2,#4)|add(#3,#4)|multiply(#6,#1)|add(#5,#7)| | "time = 2 years 4 months = 2 ( 4 / 12 ) years = 2 ( 1 / 3 ) years . amount = $ [ 6000 x ( 1 + ( 15 / 100 ) ) 2 x ( 1 + ( ( 1 / 3 ) * 15 ) / 100 ) ] = $ [ 6000 * ( 23 / 20 ) * ( 23 / 20 ) * ( 21 / 20 ) ] = $ 8331.75 . : . c . i . = rs . ( 8331.75 - 6000 ) = $ 2331.75 answer a ." | gain |
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