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25
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stringlengths 45
1.01k
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stringlengths 75
4.11k
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stringclasses 5
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float64 -4,212
100B
| question_without_options
stringlengths 6
962
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dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
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stringlengths 1
2.74k
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stringclasses 6
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|---|---|---|---|---|---|---|---|---|---|---|
math_qa__MT3z5mE4bxK1AMMa | A man took a loan at rate of 12% per annum simple interest. After 3 years he had to pay 9000 interest. The principal amount borrowed by him was. Choose the correct choice from the following
A) rs 14000
B) rs 25000
C) rs 16000
D) rs 17000
E) none of these | <gadget id="calculator">9_000 * 100</gadget>
<output>900_000</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">900_000 / 36</gadget>
<output>25_000</output>
<result>B</result> | B | 25,000 | A man took a loan at rate of 12% per annum simple interest. After 3 years he had to pay 9000 interest. The principal amount borrowed by him was. | {
"A": "rs 14000",
"B": "rs 25000",
"C": "rs 16000",
"D": "rs 17000",
"E": "none of these"
} | divide(multiply(9000, const_100), multiply(12, 3)) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1) | explanation : s . i . = p Γ’ Λ β r Γ’ Λ β t / 100 = > p = s . i . Γ’ Λ β 100 / r Γ’ Λ β t = > p = 9000 Γ’ Λ β 100 / 12 Γ’ Λ β 3 = rs 25000 option b | gain |
math_qa__Dmnib7dhYm0JIpmr | Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 9 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?
Options:
A) 8 mph
B) 5.25 mph
C) 3.5 mph
D) 5 mph
E) 0.5 mph | <gadget id="calculator">1 + 9</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>D</result> | D | 5 | Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 9 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her? | {
"A": "8 mph",
"B": "5.25 mph",
"C": "3.5 mph",
"D": "5 mph",
"E": "0.5 mph"
} | divide(add(1, 9), const_2) | add(n0,n1)|divide(#0,const_2)| | "( 1 mph + 9 mph ) / 2 = 5 mph correct option is : d" | physics |
math_qa__xtIjRP6CyLCOfuLm | suppose you want to buy 3 loaves of bread that cost $ 2.25 each and a jar of peanut butter that costs $ 2 . a jar of jelly is $ 2.75 , but you don Γ’ β¬ β’ t need any jelly . you have $ 14 . how much money will you have left over ? Options
A) $ 1.50 B) $ 2.50 C) $ 5.25 D) $ 4.50 E) $ 5.50 | <gadget id="calculator">3 * 2.25</gadget>
<output>6.75</output>
<gadget id="calculator">14 - 6.75</gadget>
<output>7.25</output>
<gadget id="calculator">7.25 - 2</gadget>
<output>5.25</output>
<result>C</result> | C | 5.25 | suppose you want to buy 3 loaves of bread that cost $ 2.25 each and a jar of peanut butter that costs $ 2 . a jar of jelly is $ 2.75 , but you don Γ’ β¬ β’ t need any jelly . you have $ 14 . how much money will you have left over ? | {
"A": "$ 1.50",
"B": "$ 2.50",
"C": "$ 5.25",
"D": "$ 4.50",
"E": "$ 5.50"
} | subtract(subtract(14, multiply(3, 2.25)), 2) | multiply(n0,n1)|subtract(n4,#0)|subtract(#1,n2) | the jelly is extra information . 14.00 Γ’ β¬ β 3 x 2.25 Γ’ β¬ β 2.00 = 14.00 Γ’ β¬ β 6.75 Γ’ β¬ β 2.00 = 5.25 . you have $ 5.25 left . correct answer c | general |
math_qa__zWwvdtET9kDg5tdo | A man can row 3.6 km/hr in still water. It takes him twice as long to row upstream as to row downstream. What is the rate of the current ? Choose the correct answer.
A) 1.9 B) 1.7 C) 1.2 D) 1.5 E) 1.1 | <gadget id="calculator">3.6 * 2</gadget>
<output>7.2</output>
<gadget id="calculator">7.2 - 3.6</gadget>
<output>3.6</output>
<gadget id="calculator">3.6 / 3</gadget>
<output>1.2</output>
<result>C</result> | C | 1.2 | A man can row 3.6 km/hr in still water. It takes him twice as long to row upstream as to row downstream. What is the rate of the current ? | {
"A": "1.9",
"B": "1.7",
"C": "1.2",
"D": "1.5",
"E": "1.1"
} | divide(subtract(multiply(3.6, const_2), 3.6), const_3) | multiply(n0,const_2)|subtract(#0,n0)|divide(#1,const_3)| | "speed of boat in still water ( b ) = 3.6 km / hr . speed of boat with stream ( down stream ) , d = b + u speed of boat against stream ( up stream ) , u = b β u it is given upstream time is twice to that of down stream . β downstream speed is twice to that of upstream . so b + u = 2 ( b β u ) β u = b / 3 = 1.2 km / hr . answer : c" | general |
math_qa__lFwGdYVgLk7cT44J | Two cars are traveling in the same direction along the same route. The red car travels at a constant speed of 30 miles per hour, and the black car is traveling at a constant speed of 50 miles per hour. If the red car is 20 miles ahead of the black car, how many hours will it take the black car to overtake the red car? Select: A) 0.1 B) 0.6 C) 1 D) 1.2 E) 2 | <gadget id="calculator">50 - 30</gadget>
<output>20</output>
<gadget id="calculator">20 / 20</gadget>
<output>1</output>
<result>C</result> | C | 1 | Two cars are traveling in the same direction along the same route. The red car travels at a constant speed of 30 miles per hour, and the black car is traveling at a constant speed of 50 miles per hour. If the red car is 20 miles ahead of the black car, how many hours will it take the black car to overtake the red car? | {
"A": "0.1",
"B": "0.6",
"C": "1",
"D": "1.2",
"E": "2"
} | divide(20, subtract(50, 30)) | subtract(n1,n0)|divide(n2,#0)| | "option c 20 + 30 t = 50 t t = 1" | physics |
math_qa__P5aNkVaimR2cCy2I | The population of locusts in a certain swarm doubles every two hours. If 4 hours ago there were 1,000 locusts in the swarm, in approximately how many hours will the swarm population exceed 32,000 locusts? Choices
A) 2
B) 4
C) 6
D) 8
E) 9 | <gadget id="calculator">4 ** 4</gadget>
<output>256</output>
<gadget id="calculator">256 / 2</gadget>
<output>128</output>
<gadget id="calculator">log(128)</gadget>
<output>log(128) = around 4.85203</output>
<gadget id="calculator">log(128) * 2</gadget>
<output>2*log(128) = around 9.704061</output>
<gadget id="calculator">(2*log(128)) - 4</gadget>
<output>-4 + 2*log(128) = around 5.704061</output>
<result>C</result> | C | 6 | The population of locusts in a certain swarm doubles every two hours. If 4 hours ago there were 1,000 locusts in the swarm, in approximately how many hours will the swarm population exceed 32,000 locusts? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "9"
} | subtract(multiply(log(divide(power(4, 4), const_2)), const_2), 4) | power(n0,n0)|divide(#0,const_2)|log(#1)|multiply(#2,const_2)|subtract(#3,n0)| | "- 4 hours : 1,000 - 2 hours : 2,000 now : 4,000 + 2 hours : 8,000 + 4 hours : 16,000 + 6 hours : 32,000 answer : c" | general |
math_qa__eDbrYXx2knw9rxnf | Find the ratio in which rice at Rs. 7.10 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg Choices:
A) 2 : 0
B) 3 : 4
C) 2 : 1
D) 2 : 2
E) 2 : 8 | <gadget id="calculator">6.3 - 5.7</gadget>
<output>0.6</output>
<gadget id="calculator">7.1 - 6.3</gadget>
<output>0.8</output>
<gadget id="calculator">0.6 / 0.8</gadget>
<output>0.75</output>
<result>B</result> | B | 0.75 | Find the ratio in which rice at Rs. 7.10 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg | {
"A": "2 : 0",
"B": "3 : 4",
"C": "2 : 1",
"D": "2 : 2",
"E": "2 : 8"
} | divide(subtract(6.30, 5.70), subtract(7.10, 6.30)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "by the rule of alligation : cost of 1 kg rice of 1 st kind cost of 1 kg rice of 2 nd kind required ratio = 60 : 80 = 3 : 4 answer : b" | other |
math_qa__7sFa85phruwVwKQb | In an election, candidate A got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate.
Choose the most appropriate option.
A) 357000 B) 357003 C) 277677 D) 699377 E) 267877 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">560_000 * (17/20)</gadget>
<output>476_000</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">476_000 * (3/4)</gadget>
<output>357_000</output>
<result>A</result> | A | 357,000 | In an election, candidate A got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate. | {
"A": "357000",
"B": "357003",
"C": "277677",
"D": "699377",
"E": "267877"
} | multiply(multiply(560000, subtract(const_1, divide(15, const_100))), divide(75, const_100)) | divide(n0,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(n2,#2)|multiply(#0,#3)| | "total number of invalid votes = 15 % of 560000 = 15 / 100 Γ 560000 = 8400000 / 100 = 84000 total number of valid votes 560000 β 84000 = 476000 percentage of votes polled in favour of candidate a = 75 % therefore , the number of valid votes polled in favour of candidate a = 75 % of 476000 = 75 / 100 Γ 476000 = 35700000 / 100 = 357000 answer : a" | gain |
math_qa__egxHWXonbjSFZBC5 | You have been given a physical balance and 7 weights of 43, 45, 30, 33, 28, 37 and 55 kgs. Keeping weights on one pan and object on the other, what is the maximum you can weigh less than 145 kgs. Options.
A) 145
B) 143
C) 147
D) 141
E) 142 | <gadget id="calculator">45 + 30</gadget>
<output>75</output>
<gadget id="calculator">75 + 33</gadget>
<output>108</output>
<gadget id="calculator">108 + 37</gadget>
<output>145</output>
<result>B</result> | B | 143 | You have been given a physical balance and 7 weights of 43, 45, 30, 33, 28, 37 and 55 kgs. Keeping weights on one pan and object on the other, what is the maximum you can weigh less than 145 kgs. | {
"A": "145",
"B": "143",
"C": "147",
"D": "141",
"E": "142"
} | add(add(add(45, 30), 33), 37) | add(n2,n3)|add(n4,#0)|add(n6,#1) | 55 + 43 + 45 = 143 answer : b | general |
math_qa__QzpP5Xhzd3PxzRlc | United Telephone charges a base rate of $11.00 for service, plus an additional charge of $0.25 per minute. Atlantic Call charges a base rate of $12.00 for service, plus an additional charge of $0.20 per minute. For what number of minutes would the bills for each telephone company be the same?
Choose the correct choice from the following answers: A) 2 minutes B) 10 minutes C) 20 minutes D) 40 minutes E) 60 minutes | <gadget id="calculator">12 - 11</gadget>
<output>1</output>
<gadget id="calculator">0.25 - 0.2</gadget>
<output>0.05</output>
<gadget id="calculator">1 / 0.05</gadget>
<output>20</output>
<result>C</result> | C | 20 | United Telephone charges a base rate of $11.00 for service, plus an additional charge of $0.25 per minute. Atlantic Call charges a base rate of $12.00 for service, plus an additional charge of $0.20 per minute. For what number of minutes would the bills for each telephone company be the same? | {
"A": "2 minutes",
"B": "10 minutes",
"C": "20 minutes",
"D": "40 minutes",
"E": "60 minutes"
} | divide(subtract(12.00, 11.00), subtract(0.25, 0.20)) | subtract(n2,n0)|subtract(n1,n3)|divide(#0,#1)| | "lets take number of minutesx . given that , 11 + 0.25 x = 12 + 0.2 x - > 0.05 x = 2 - > x = 20 minutes ans c" | general |
math_qa__h0vkseaLhdD2HsxC | If the ratio of a to b is 8 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? Choose the most appropriate option:
A) 8 / 15 B) 1 / 3 C) 2 / 5 D) 4 / 5 E) 7 / 6 | <gadget id="calculator">8 * 1</gadget>
<output>8</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">8 / 15</gadget>
<output>8/15 = around 0.533333</output>
<result>A</result> | A | 0.533333 | If the ratio of a to b is 8 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? | {
"A": "8 / 15",
"B": "1 / 3",
"C": "2 / 5",
"D": "4 / 5",
"E": "7 / 6"
} | divide(multiply(8, 1), multiply(3, 5)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "a : b = 8 : 3 - - 1 b : c = 1 : 5 = > b : c = 3 : 15 - - 2 from 1 and 2 , we get a : c = 8 : 15 answer a" | other |
math_qa__9hPx29v7ATQ69WHu | the least number which when divided by 5 , 67 and 8 leaves a remainder 3 , but when divided by 9 leaves no remainder , is : Answers: A) 1677 B) 1683 C) 2523 D) 3363 E) none of these | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">30 * 7</gadget>
<output>210</output>
<gadget id="calculator">210 * 8</gadget>
<output>1_680</output>
<gadget id="calculator">1_680 + 3</gadget>
<output>1_683</output>
<result>B</result> | B | 1,683 | the least number which when divided by 5 , 67 and 8 leaves a remainder 3 , but when divided by 9 leaves no remainder , is : | {
"A": "1677",
"B": "1683",
"C": "2523",
"D": "3363",
"E": "none of these"
} | add(multiply(multiply(multiply(5, add(5, const_1)), add(5, const_2)), 8), 3) | add(n0,const_2)|add(n0,const_1)|multiply(n0,#1)|multiply(#0,#2)|multiply(n2,#3)|add(n3,#4) | solution l . c . m . of 5 , 6 , 7 , 8 = 840 . so , required number is of the form 840 k + 3 . least value of k for which ( 840 k + 3 ) is divisible by 9 is k = 2 . so , required number = ( 840 Γ 2 + 3 ) = 1683 . answer b | general |
math_qa__tNdyYsqPhmCX3hr2 | The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 16000, then find the annual income of A? Choose the correct choice.
A) rs . 537600 B) rs . 180000 C) rs . 201600 D) rs . 504000 E) none of these | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 + (3/25)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">16_000 * (28/25)</gadget>
<output>17_920</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">17_920 * (5/2)</gadget>
<output>44_800</output>
<gadget id="calculator">44_800 * 12</gadget>
<output>537_600</output>
<result>A</result> | A | 537,600 | The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 16000, then find the annual income of A? | {
"A": "rs . 537600",
"B": "rs . 180000",
"C": "rs . 201600",
"D": "rs . 504000",
"E": "none of these"
} | multiply(multiply(multiply(16000, add(const_1, divide(12, const_100))), divide(5, 2)), 12) | divide(n0,n1)|divide(n2,const_100)|add(#1,const_1)|multiply(n3,#2)|multiply(#0,#3)|multiply(n2,#4) | b ' s monthly income = 16000 * 112 / 100 = rs . 17920 b ' s monthly income = 2 parts - - - - > rs . 17920 a ' s monthly income = 5 parts = 5 / 2 * 17920 = rs . 44800 a ' s annual income = rs . 44800 * 12 = rs . 537600 answer : a | other |
math_qa__d207ZS1YjIL988fo | Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point? Pick:
A) 65 B) 38 C) 20 D) 28 E) 21 | <gadget id="calculator">150 - 35</gadget>
<output>115</output>
<gadget id="calculator">25 + 25</gadget>
<output>50</output>
<gadget id="calculator">115 - 50</gadget>
<output>65</output>
<result>A</result> | A | 65 | Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point? | {
"A": "65",
"B": "38",
"C": "20",
"D": "28",
"E": "21"
} | subtract(subtract(150, 35), add(25, 25)) | add(n1,n1)|subtract(n0,n4)|subtract(#1,#0)| | answer : a ) 65 km | physics |
math_qa__ClmY0C6LxNJ1du0K | A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 380 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra? Choose the correct choice from the following:
A) 90 B) 110 C) 120 D) 130 E) 240 | <gadget id="calculator">12 * 380</gadget>
<output>4_560</output>
<gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">3_000 + 300</gadget>
<output>3_300</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">3_300 + 20</gadget>
<output>3_320</output>
<gadget id="calculator">4_560 - 3_320</gadget>
<output>1_240</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">1_240 / 4</gadget>
<output>310</output>
<gadget id="calculator">380 - 310</gadget>
<output>70</output>
<gadget id="calculator">310 - 70</gadget>
<output>240</output>
<result>E</result> | E | 240 | A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 380 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra? | {
"A": "90",
"B": "110",
"C": "120",
"D": "130",
"E": "240"
} | subtract(divide(subtract(multiply(12, 380), add(add(multiply(const_3, const_1000), multiply(const_3, const_100)), multiply(const_2, const_10))), subtract(12, 8)), subtract(380, divide(subtract(multiply(12, 380), add(add(multiply(const_3, const_1000), multiply(const_3, const_100)), multiply(const_2, const_10))), subtract(12, 8)))) | multiply(n0,n2)|multiply(const_1000,const_3)|multiply(const_100,const_3)|multiply(const_10,const_2)|subtract(n0,n1)|add(#1,#2)|add(#5,#3)|subtract(#0,#6)|divide(#7,#4)|subtract(n2,#8)|subtract(#8,#9)| | "orchestra seats - a balcony seats - b a + b = 380 and 12 a + 8 b = 3320 solving equations simultaneously ( multiply equation 1 with 8 and subtract from second equation ) 4 a = 3320 - 8 * 380 = 3320 - 3040 = 280 i . e . a = 70 and b = 380 - 70 = 310 more seats in balcony than orchestra = b - a = 310 - 70 = 240 answer : option e" | general |
math_qa__E24ARRJoz9lVuJkV | In an electric circuit, two resistors with resistances x and y are connected in parallel. If R is the combined resistance of these two resistors, then the reciprocal of R is equal to the sum of the reciprocals of x and y. What is R if x is 5 Ohms and y is 6 Ohms?
Options
A) 7 / 30
B) 11 / 30
C) 11 / 15
D) 30 / 11
E) 15 / 11 | <gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">30 / 11</gadget>
<output>30/11 = around 2.727273</output>
<result>D</result> | D | 2.727273 | In an electric circuit, two resistors with resistances x and y are connected in parallel. If R is the combined resistance of these two resistors, then the reciprocal of R is equal to the sum of the reciprocals of x and y. What is R if x is 5 Ohms and y is 6 Ohms? | {
"A": "7 / 30",
"B": "11 / 30",
"C": "11 / 15",
"D": "30 / 11",
"E": "15 / 11"
} | divide(multiply(6, 5), add(5, 6)) | add(n0,n1)|multiply(n0,n1)|divide(#1,#0) | 1 / r = 1 / x + 1 / y 1 / r = 1 / 5 + 1 / 6 = 11 / 30 r = 30 / 11 the answer is d . | general |
math_qa__Cgy51mzi2EUCip6M | In a practice paper at 2iim.com, questions were given from 5 topics. Out of the appearing students, 10% passed in all topics while 10% did not pass in any. Of the remaining, 20% passed in one topic only and 25% in two topics only. If 24% of the total students passed 4 topics only and 500 students passed in 3 topics only, find the total number of students who appeared in the examination?
Pick one: A) 2500 B) 2000 C) 1600 D) 4545 E) 6565 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 - 10</gadget>
<output>80</output>
<gadget id="calculator">20 + 25</gadget>
<output>45</output>
<gadget id="calculator">80 * 45</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 / 100</gadget>
<output>36</output>
<gadget id="calculator">36 + 24</gadget>
<output>60</output>
<gadget id="calculator">60 + 10</gadget>
<output>70</output>
<gadget id="calculator">70 + 10</gadget>
<output>80</output>
<gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">500 / (1/5)</gadget>
<output>2_500</output>
<result>A</result> | A | 2,500 | In a practice paper at 2iim.com, questions were given from 5 topics. Out of the appearing students, 10% passed in all topics while 10% did not pass in any. Of the remaining, 20% passed in one topic only and 25% in two topics only. If 24% of the total students passed 4 topics only and 500 students passed in 3 topics only, find the total number of students who appeared in the examination? | {
"A": "2500",
"B": "2000",
"C": "1600",
"D": "4545",
"E": "6565"
} | divide(500, divide(subtract(const_100, add(add(add(divide(multiply(subtract(subtract(const_100, 10), 10), add(20, 25)), const_100), 24), 10), 10)), const_100)) | add(n4,n5)|subtract(const_100,n2)|subtract(#1,n2)|multiply(#0,#2)|divide(#3,const_100)|add(n6,#4)|add(n2,#5)|add(n2,#6)|subtract(const_100,#7)|divide(#8,const_100)|divide(n8,#9) | detailed solution let the number of appearing students be 100 . pass only in 0 topic β 10 1 β 16 ( 20 % of 80 ) 2 β 20 ( 25 % of 80 ) 3 β 20 % ( 100 β ( 16 + 20 + 24 + 20 ) ) 4 β 24 % 5 β 20 % therefore , 20 % of x = 500 = ) x = 2500 correct answer : a | general |
math_qa__3YevYt5ffDjm6zJQ | A person buys an article at Rs.650. At what price should he sell the article so as to make a profit of 10%? Choose the correct option
A) 600 B) 715 C) 269 D) 261 E) 281 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">650 * (1/10)</gadget>
<output>65</output>
<gadget id="calculator">650 + 65</gadget>
<output>715</output>
<result>B</result> | B | 715 | A person buys an article at Rs.650. At what price should he sell the article so as to make a profit of 10%? | {
"A": "600",
"B": "715",
"C": "269",
"D": "261",
"E": "281"
} | add(650, multiply(650, divide(10, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | "cost price = rs . 650 profit = 10 % of 650 = rs . 65 selling price = cost price + profit = 650 + 65 = rs . 715 answer : b" | gain |
math_qa__MbbDHwH5hMDPk1Qg | A mixture contains milk and water in the ratio 3:2. On adding 10 litters of water, the ratio of milk to water becomes 2:3. Total quantity of milk & water before adding water to it? Choose the correct choice from the following choices.
A) 10 B) 30 C) 50 D) 20 E) 30 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">10 * (2/3)</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * (2/3)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">(3/5) - (4/15)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(20/3) / (1/3)</gadget>
<output>20</output>
<result>D</result> | D | 20 | A mixture contains milk and water in the ratio 3:2. On adding 10 litters of water, the ratio of milk to water becomes 2:3. Total quantity of milk & water before adding water to it? | {
"A": "10",
"B": "30",
"C": "50",
"D": "20",
"E": "30"
} | divide(multiply(10, divide(2, 3)), subtract(divide(3, add(3, 2)), multiply(divide(2, add(3, 2)), divide(2, 3)))) | add(n0,n1)|divide(n1,n0)|divide(n0,#0)|divide(n1,#0)|multiply(n2,#1)|multiply(#3,#1)|subtract(#2,#5)|divide(#4,#6)| | "explanation : milk : water = 3 : 2 after adding 10 liters of water milk : water = 2 : 3 olny water patrs increase when mixture of water milk : wate = 3 : 2 = 2 * ( 3 : 2 ) = 6 : 4 after adding 10 liters of water milk : water = 2 : 3 = 3 * ( 2 : 3 ) = 6 : 9 milk parts always same short cut method : milk : water = 6 : 4 after adding 10 liters of water milk : water = 6 : 9 milk is same but water increse 10 liters then the water ratio is increse 5 parts 5 part - - - - - > 10 liters the quantity of milk in the original mixture is = 6 : 4 = 6 + 4 = 10 10 parts - - - - - > 20 liters ( answer is = 20 ) short cut method - 2 : for only milk problems milk : water 6 : 4 6 : 9 milk ratio same but water ratio 5 parts incress per 10 liters 5 part of ratio - - - - - - - > 10 liters 10 part of ratio - - - - - - > 20 liters answer : option d" | general |
math_qa__CoKNQ6dzYtxK8rQD | A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required? Choose the correct choice from the following choices: A) 35 B) 37 C) 42 D) 30 E) 38 | <gadget id="calculator">gcd(80, 144)</gadget>
<output>16</output>
<gadget id="calculator">gcd(16, 368)</gadget>
<output>16</output>
<gadget id="calculator">368 / 16</gadget>
<output>23</output>
<gadget id="calculator">80 / 16</gadget>
<output>5</output>
<gadget id="calculator">144 / 16</gadget>
<output>9</output>
<gadget id="calculator">5 + 9</gadget>
<output>14</output>
<gadget id="calculator">23 + 14</gadget>
<output>37</output>
<result>B</result> | B | 37 | A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required? | {
"A": "35",
"B": "37",
"C": "42",
"D": "30",
"E": "38"
} | add(divide(368, gcd(gcd(80, 144), 368)), add(divide(80, gcd(gcd(80, 144), 368)), divide(144, gcd(gcd(80, 144), 368)))) | gcd(n0,n1)|gcd(n2,#0)|divide(n0,#1)|divide(n1,#1)|divide(n2,#1)|add(#2,#3)|add(#5,#4)| | "the number of liters in each can = hcf of 80 , 144 and 368 = 16 liters . number of cans of maaza = 80 / 16 = 5 number of cans of pepsi = 144 / 16 = 9 number of cans of sprite = 368 / 16 = 23 the total number of cans required = 5 + 9 + 23 = 37 cans . answer : b" | general |
math_qa__YuH6phbwuStFeaPj | (112% of 2348) Γ· 4.98 = ? Choices.
A) 505 B) 515 C) 525 D) 538 E) 567 | <gadget id="calculator">112 / 100</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">(28/25) * 2_348</gadget>
<output>65_744/25 = around 2_629.76</output>
<gadget id="calculator">(65_744/25) / 4.98</gadget>
<output>528.064257</output>
<result>C</result> | C | 525 | (112% of 2348) Γ· 4.98 = ? | {
"A": "505",
"B": "515",
"C": "525",
"D": "538",
"E": "567"
} | divide(multiply(divide(112, const_100), 2348), 4.98) | divide(n0,const_100)|multiply(n1,#0)|divide(#1,n2)| | "explanation : ? = ( 112 x 2348 / 100 ) Γ· 5 = 2630 / 5 = 526 = 525 answer : option c" | general |
math_qa__8nsPYGpFaRJtXAtM | A man can row upstream at 60 kmph and downstream at 90 kmph, and then find the speed of the man in still water?
Choose the correct choice from the following options.
A) 75 kmph B) 65 kmph C) 30 kmph D) 73 kmph E) 65 kmph | <gadget id="calculator">60 + 90</gadget>
<output>150</output>
<gadget id="calculator">150 / 2</gadget>
<output>75</output>
<result>A</result> | A | 75 | A man can row upstream at 60 kmph and downstream at 90 kmph, and then find the speed of the man in still water? | {
"A": "75 kmph",
"B": "65 kmph",
"C": "30 kmph",
"D": "73 kmph",
"E": "65 kmph"
} | divide(add(60, 90), const_2) | add(n0,n1)|divide(#0,const_2) | us = 60 ds = 90 m = ( 60 + 90 ) / 2 = 75 answer : a | physics |
math_qa__LlDn89QHy9SeSTLO | A train running at the speed of 52 km/hr crosses a pole in 9 sec. What is the length of the train?
Answers:
A) 130 m
B) 786 m
C) 566 m
D) 546 m
E) 440 m | <gadget id="calculator">52 * 1_000</gadget>
<output>52_000</output>
<gadget id="calculator">52_000 / 3_600</gadget>
<output>130/9 = around 14.444444</output>
<gadget id="calculator">(130/9) * 9</gadget>
<output>130</output>
<result>A</result> | A | 130 | A train running at the speed of 52 km/hr crosses a pole in 9 sec. What is the length of the train? | {
"A": "130 m",
"B": "786 m",
"C": "566 m",
"D": "546 m",
"E": "440 m"
} | multiply(divide(multiply(52, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 52 * 5 / 18 = 130 / 9 m / sec length of the train = speed * time = 130 / 9 * 9 = 130 m answer : a" | physics |
math_qa__kvQIBTsottKCKzV9 | Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.441 in 2 years? Choose the most appropriate option.
A) 387 B) 400 C) 776 D) 268 E) 181 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">441 / (441/400)</gadget>
<output>400</output>
<result>B</result> | B | 400 | Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.441 in 2 years? | {
"A": "387",
"B": "400",
"C": "776",
"D": "268",
"E": "181"
} | divide(441, power(add(const_1, divide(5, const_100)), 2)) | divide(n0,const_100)|add(#0,const_1)|power(#1,n2)|divide(n1,#2)| | "441 = p ( 21 / 20 ) 2 p = 400 answer : b" | general |
math_qa__v0AMSlp4GnD0cjkr | Jaime earned enough money by selling seashells at 30 cents each to buy several used paperback books at 55 cents each. If he spent all of the money he earned selling seashells to buy the books, what is the least number of seashells he could have sold ?
Choose the correct choice from the following answers:
A) 5 B) 22 C) 17 D) 25 E) 30 | <gadget id="calculator">lcm(30, 55)</gadget>
<output>330</output>
<gadget id="calculator">330 / 30</gadget>
<output>11</output>
<gadget id="calculator">11 + 10</gadget>
<output>21</output>
<result>B</result> | B | 22 | Jaime earned enough money by selling seashells at 30 cents each to buy several used paperback books at 55 cents each. If he spent all of the money he earned selling seashells to buy the books, what is the least number of seashells he could have sold ? | {
"A": "5",
"B": "22",
"C": "17",
"D": "25",
"E": "30"
} | add(divide(lcm(30, 55), 30), const_10) | lcm(n0,n1)|divide(#0,n0)|add(#1,const_10)| | "let ' s test answer b : 22 seashells . . . with 22 seashells , jamie would have 22 ( 30 ) = 660 cents . this would allow him to buy 12 books for 660 cents total , with no money left over . this is an exact match for what we were told , so this must be the answer . final answer : [ reveal ] spoiler : b" | general |
math_qa__fY2NBbmOUUuxpGVq | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 180 kilometers?
Choose the correct choice from the following:
A) 3.5 gallons
B) 2.7 gallons
C) 5.7 gallons
D) 4.5 gallons
E) 7.5 gallons | <gadget id="calculator">180 / 40</gadget>
<output>9/2 = around 4.5</output>
<result>D</result> | D | 4.5 | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 180 kilometers? | {
"A": "3.5 gallons",
"B": "2.7 gallons",
"C": "5.7 gallons",
"D": "4.5 gallons",
"E": "7.5 gallons"
} | divide(180, 40) | divide(n1,n0)| | "each 40 kilometers , 1 gallon is needed . we need to know how many 40 kilometers are there in 180 kilometers ? 180 Γ· 40 = 4.5 Γ 1 gallon = 4.5 gallons correct answer is d ) 4.5 gallons" | physics |
math_qa__FUeOesqBYCTNRsHW | A car covers a distance of 624 km in 3 1/5 hours. Find its speed? Choices: A) 104 kmph B) 195 kmph C) 109 kmph D) 174 kmph E) 101 kmph | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">3 + (1/5)</gadget>
<output>16/5 = around 3.2</output>
<gadget id="calculator">624 / (16/5)</gadget>
<output>195</output>
<result>B</result> | B | 195 | A car covers a distance of 624 km in 3 1/5 hours. Find its speed? | {
"A": "104 kmph",
"B": "195 kmph",
"C": "109 kmph",
"D": "174 kmph",
"E": "101 kmph"
} | divide(624, add(3, divide(1, 5))) | divide(n2,n3)|add(n1,#0)|divide(n0,#1)| | "624 / 3 1 / 5 = 195 kmph answer : b" | physics |
math_qa__rWIVjeAoBPYCzbMC | If an integer n is to be selected at random from 1 to 100, inclusive, what is probability n(n+1) will be divisible by 5?
Pick one:
A) 1 / 5 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 2 / 5 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<result>E</result> | E | 0.4 | If an integer n is to be selected at random from 1 to 100, inclusive, what is probability n(n+1) will be divisible by 5? | {
"A": "1 / 5",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "2 / 5"
} | divide(const_2, 5) | divide(const_2,n3)| | "for n ( n + 1 ) to be a multiple of 5 , either n or n + 1 has to be a multiple of 5 . thus n must be of the form 5 k or 5 k - 1 . the probability is 2 / 5 . the answer is e ." | general |
math_qa__HnjUXtXqczXLB9eX | Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into a hat. If 4 of the slips are the drawn, without replacement, what is the probability that all 4 have a odd number written on it? Choose the correct choice from the following answers:
A) 1 / 12 B) 1 / 10 C) 1 / 8 D) 1 / 42 E) 5 / 9 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">5 / 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">(1/2) * (4/9)</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(2/9) * (3/8)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(1/12) * (2/7)</gadget>
<output>1/42 = around 0.02381</output>
<result>D</result> | D | 0.02381 | Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into a hat. If 4 of the slips are the drawn, without replacement, what is the probability that all 4 have a odd number written on it? | {
"A": "1 / 12",
"B": "1 / 10",
"C": "1 / 8",
"D": "1 / 42",
"E": "5 / 9"
} | multiply(multiply(multiply(divide(add(4, const_1), add(9, const_1)), divide(subtract(add(4, const_1), const_1), subtract(add(9, const_1), const_1))), divide(subtract(subtract(add(4, const_1), const_1), const_1), subtract(subtract(add(9, const_1), const_1), const_1))), divide(subtract(subtract(subtract(add(4, const_1), const_1), const_1), const_1), subtract(subtract(subtract(add(9, const_1), const_1), const_1), const_1))) | add(const_1,n2)|add(n1,const_1)|divide(#0,#1)|subtract(#0,const_1)|subtract(#1,const_1)|divide(#3,#4)|subtract(#3,const_1)|subtract(#4,const_1)|divide(#6,#7)|multiply(#2,#5)|subtract(#6,const_1)|subtract(#7,const_1)|divide(#10,#11)|multiply(#8,#9)|multiply(#12,#13)| | "key is that there is no replacement , so each successive choice will become more skewed towards picking a neg ( i . e . the pool of positives decreases , while the pool of negatives stay the same ) p ( + on 1 st pick ) = 5 / 10 p ( + on 2 nd pick ) = 4 / 9 p ( + on 3 rd pick ) = 3 / 8 p ( + on 4 rd pick ) = 2 / 7 5 / 10 * 4 / 9 * 3 / 8 * 2 / 7 = 1 / 42 d" | gain |
math_qa__5Ca7QZepdwraN6Zq | A superhero flies at an incredible rate of 1000 kilometers per minute. What is her speed in miles per hour? [1km = 0.6 miles] Select: A) 6000 B) 36000 C) 60000 D) 600 E) 3600 | <gadget id="calculator">1_000 * 60</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 * 0.6</gadget>
<output>36_000</output>
<result>B</result> | B | 36,000 | A superhero flies at an incredible rate of 1000 kilometers per minute. What is her speed in miles per hour? [1km = 0.6 miles] | {
"A": "6000",
"B": "36000",
"C": "60000",
"D": "600",
"E": "3600"
} | multiply(multiply(1000, const_60), 0.6) | multiply(n0,const_60)|multiply(n2,#0) | to calculate the equivalent of miles in a kilometer 0.6 kilometers = 1 mile 1000 kilometers = ( 0.6 ) * 1000 = 600 miles speed in miles per minute = 600 = 600 1 hour = 60 minutes speed in miles per hour = 600 * 60 = 36,000 correct answer - b | physics |
math_qa__hg62oHIsuaDf4pZy | 5100β(102Γ·20.4)=?
Options: A) 5200 B) 5150 C) 5250 D) 6150 E) 5095 | <gadget id="calculator">102 / 20.4</gadget>
<output>5</output>
<gadget id="calculator">5_100 - 5</gadget>
<output>5_095</output>
<result>E</result> | E | 5,095 | 5100β(102Γ·20.4)=? | {
"A": "5200",
"B": "5150",
"C": "5250",
"D": "6150",
"E": "5095"
} | subtract(5100, divide(102, 20.4)) | divide(n1,n2)|subtract(n0,#0) | explanation : = 5100 β ( 102 / 204 Γ 10 ) = 5100 β 5 = 5095 option e | general |
math_qa__M5vkkxIaj4cCytQs | What least number should be subtracted from 13603 such that the remainder is divisible by 87 ? Choose the correct option.
A) 27
B) 29
C) 28
D) 30
E) 31 | <gadget id="calculator">13_603 % 87</gadget>
<output>31</output>
<result>E</result> | E | 31 | What least number should be subtracted from 13603 such that the remainder is divisible by 87 ? | {
"A": "27",
"B": "29",
"C": "28",
"D": "30",
"E": "31"
} | reminder(13603, 87) | reminder(n0,n1)| | "13603 Γ· 87 = 156 , remainder = 31 hence 31 is the least number which can be subtracted from 13603 such that the remainder is divisible by 87 answer is e" | general |
math_qa__PPdUZhmkYqFqTe34 | In a sports club with 30 members, 17 play badminton and 21 play tennis and 2 do not play either. How many members play both badminton and tennis?
Choose the correct choice from the following answers
A) 7 B) 8 C) 9 D) 10 E) 11 | <gadget id="calculator">17 + 21</gadget>
<output>38</output>
<gadget id="calculator">38 + 2</gadget>
<output>40</output>
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
<result>D</result> | D | 10 | In a sports club with 30 members, 17 play badminton and 21 play tennis and 2 do not play either. How many members play both badminton and tennis? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | subtract(add(add(17, 21), 2), 30) | add(n1,n2)|add(n3,#0)|subtract(#1,n0)| | "let x play both badminton and tennis so 17 - x play only badminton and 19 - x play only tennis . 2 play none and there are total 30 students . hence , ( 17 - x ) + ( 21 - x ) + x + 2 = 30 40 - 2 x + x = 30 40 - x = 30 x = 10 so 10 members play both badminton and tennis . d" | other |
math_qa__kRuYzjmSucerguma | In 40 litres of a mixture, the ratio of milk to water is 7:1. In order to make the ratio of milk to water as 3:1, the quantity of water that should be added to the mixture will be?
Choose the correct option:
A) rs . 1000
B) rs . 1200
C) rs . 1400
D) rs . 1600
E) rs . 2500 | <gadget id="calculator">3 / 1</gadget>
<output>3</output>
<gadget id="calculator">7 / 1</gadget>
<output>7</output>
<gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">21 * 40</gadget>
<output>840</output>
<gadget id="calculator">840 * 2</gadget>
<output>1_680</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">1_680 - 80</gadget>
<output>1_600</output>
<result>D</result> | D | 1,600 | In 40 litres of a mixture, the ratio of milk to water is 7:1. In order to make the ratio of milk to water as 3:1, the quantity of water that should be added to the mixture will be? | {
"A": "rs . 1000",
"B": "rs . 1200",
"C": "rs . 1400",
"D": "rs . 1600",
"E": "rs . 2500"
} | subtract(multiply(multiply(multiply(divide(3, 1), divide(7, 1)), 40), const_2), multiply(40, const_2)) | divide(n3,n2)|divide(n1,n2)|multiply(n0,const_2)|multiply(#0,#1)|multiply(n0,#3)|multiply(#4,const_2)|subtract(#5,#2) | explanation : total simple interest received , i = rs . 1600 principal , p = 7000 period , n = 5 years rate of interest , r = ? simple interest , i = p n r 100 i = pnr 100 β 1600 = 7000 Γ 5 Γ r 100 β r = 1600 Γ 100 7000 Γ 5 = 160 35 = 32 7 % β 1600 = 7000 Γ 5 Γ r 100 β r = 1600 Γ 1007000 Γ 5 = 16035 = 327 % by rule of alligation , rate of interest % from part 1 rate of interest % from part 2 6 4 net rate of interest % 32 7 327 32 7 β 4 = 4 7 327 β 4 = 47 6 β 32 7 = 10 7 6 β 327 = 107 = > part 1 : part 2 = 4 7 : 10 7 = 4 : 10 = 2 : 5 = 47 : 107 = 4 : 10 = 2 : 5 given that total amount is rs . 7000 . therefore , the amount lent at 6 % per annum ( part 1 amount ) = 7000 Γ 2 7 = rs . 2000 d ) | general |
math_qa__LTv2DHTmB0jnMSHT | 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? Answers:
A) 388 B) 266 C) 350 D) 112 E) 134 | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 39</gadget>
<output>650</output>
<gadget id="calculator">650 - 300</gadget>
<output>350</output>
<result>C</result> | C | 350 | 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? | {
"A": "388",
"B": "266",
"C": "350",
"D": "112",
"E": "134"
} | subtract(multiply(speed(300, 18), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0) | speed = [ 300 / 18 ] m / sec = 50 / 3 m / sec . let the length of the platform be x meters . then , x + 300 / 39 = 50 / 3 3 ( x + 300 ) = 1950 Γ¨ x = 350 m . answer : c | physics |
math_qa__l3CFcA5O1iBWXhgi | Two cars started from the same point, at 5 am, traveling in opposite directions at 40 and 50 mph respectively. At what time will they be 450 miles apart? Pick one:
A) 8 am
B) 10 am
C) 11 am
D) 12 am
E) 14 am | <gadget id="calculator">40 + 50</gadget>
<output>90</output>
<gadget id="calculator">450 / 90</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<result>B</result> | B | 10 | Two cars started from the same point, at 5 am, traveling in opposite directions at 40 and 50 mph respectively. At what time will they be 450 miles apart? | {
"A": "8 am",
"B": "10 am",
"C": "11 am",
"D": "12 am",
"E": "14 am"
} | add(divide(450, add(40, 50)), 5) | add(n1,n2)|divide(n3,#0)|add(n0,#1) | after t hours the distances d 1 and d 2 , in miles per hour , traveled by the two cars are given by d 1 = 40 t and d 2 = 50 t after t hours the distance d separating the two cars is given by d = d 1 + d 2 = 40 t + 50 t = 90 t distance d will be equal to 450 miles when d = 90 t = 450 miles t = 5 hours . 5 am + 5 hours = 10 am answer : b | physics |
math_qa__wnp2mWFDepK8QkrL | If 8 men or 12 women can do a piece of work in 20 days, in how many days can the same work be done by 6 men and 11 women? Options.
A) 10 days B) 11 days C) 12 days D) 15 days E) 17 days | <gadget id="calculator">8 * 20</gadget>
<output>160</output>
<gadget id="calculator">6 / 160</gadget>
<output>3/80 = around 0.0375</output>
<gadget id="calculator">12 * 20</gadget>
<output>240</output>
<gadget id="calculator">11 / 240</gadget>
<output>11/240 = around 0.045833</output>
<gadget id="calculator">(3/80) + (11/240)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>C</result> | C | 12 | If 8 men or 12 women can do a piece of work in 20 days, in how many days can the same work be done by 6 men and 11 women? | {
"A": "10 days",
"B": "11 days",
"C": "12 days",
"D": "15 days",
"E": "17 days"
} | inverse(add(divide(6, multiply(8, 20)), divide(11, multiply(12, 20)))) | multiply(n0,n2)|multiply(n1,n2)|divide(n3,#0)|divide(n4,#1)|add(#2,#3)|inverse(#4)| | "8 men = 12 women ( i . e 2 men = 3 women ) 12 women 1 day work = 1 / 20 soln : 6 men ( 9 women ) + 11 women = 20 women = ? 1 women 1 day work = 12 * 20 = 1 / 240 so , 20 women work = 20 / 240 = 1 / 12 ans : 12 days answer : c" | physics |
math_qa__cwUuTbclCyz6xRSm | 3 men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will they take to complete the remaining work?
Choose the correct option:
A) 2 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">(2/3) * 18</gadget>
<output>12</output>
<gadget id="calculator">12 / 6</gadget>
<output>2</output>
<result>A</result> | A | 2 | 3 men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will they take to complete the remaining work? | {
"A": "2",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(multiply(subtract(const_1, divide(const_2, 6)), multiply(3, 6)), 6) | divide(const_2,n1)|multiply(n0,n1)|subtract(const_1,#0)|multiply(#1,#2)|divide(#3,n1) | explanation : 3 man 1 day work = 1616 3 man 2 days work = 2626 remaining work = ( 1 β 2626 ) = 2 / 3 parts . 6 man together perform the work in 1 day is = 1616 + 1616 = 2626 parts 2626 parts completed in 1 day 2323 parts will b completed in 2 days answer : a | physics |
math_qa__Y74Abgo99ODmCHZD | 36 people {a1, a2β¦ a36} meet and shake hands in a circular fashion. In other words, there are totally 36 handshakes involving the pairs, {a1, a2}, {a2, a3}, β¦, {a35, a36}, {a36, a1}. Then size of the smallest set of people such that the rest have shaken hands with at least one person in the set is Pick one.
A) 76 B) 55 C) 44 D) 12 E) 91 | <gadget id="calculator">36 / 3</gadget>
<output>12</output>
<result>D</result> | D | 12 | 36 people {a1, a2β¦ a36} meet and shake hands in a circular fashion. In other words, there are totally 36 handshakes involving the pairs, {a1, a2}, {a2, a3}, β¦, {a35, a36}, {a36, a1}. Then size of the smallest set of people such that the rest have shaken hands with at least one person in the set is | {
"A": "76",
"B": "55",
"C": "44",
"D": "12",
"E": "91"
} | divide(36, const_3) | divide(n0,const_3) | ans : { a 1 , a 2 } , { a 2 , a 3 } , { a 3 , a 4 } , { a 4 , a 5 } , { a 5 , a 6 } , { a 6 , a 7 } β¦ , { a 35 , a 36 } , { a 36 , a 1 } from the above arrangement , if we separate a 3 , a 6 , a 9 , . . . . . a 36 . total 12 persons the reamining persons must have shaked hand with atleast one person . so answer is 12 . answer : d | geometry |
math_qa__Agkh9vOH76iUo1xJ | Rates for having a manuscript typed at a certain typing service are $6 per page for the first time a page is typed and $4 per page each time a page is revised. If a certain manuscript has 100 pages, of which 35 were revised only once, 15 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed? Answers: A) $ 860 B) $ 850 C) $ 840 D) $ 830 E) $ 820 | <gadget id="calculator">100 * 6</gadget>
<output>600</output>
<gadget id="calculator">35 * 4</gadget>
<output>140</output>
<gadget id="calculator">600 + 140</gadget>
<output>740</output>
<gadget id="calculator">15 * 4</gadget>
<output>60</output>
<gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">740 + 120</gadget>
<output>860</output>
<result>A</result> | A | 860 | Rates for having a manuscript typed at a certain typing service are $6 per page for the first time a page is typed and $4 per page each time a page is revised. If a certain manuscript has 100 pages, of which 35 were revised only once, 15 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed? | {
"A": "$ 860",
"B": "$ 850",
"C": "$ 840",
"D": "$ 830",
"E": "$ 820"
} | add(add(multiply(100, 6), multiply(35, 4)), multiply(multiply(15, 4), const_2)) | multiply(n0,n2)|multiply(n1,n3)|multiply(n1,n4)|add(#0,#1)|multiply(#2,const_2)|add(#3,#4)| | "50 pages typed 1 x 35 pages typed 2 x ( original + one revision ) 15 pages typed 3 x ( original + two revisions ) 50 ( 6 ) + 35 ( 6 + 4 ) + 15 ( 6 + 4 + 4 ) = 300 + 350 + 210 = 860 answer - a" | general |
math_qa__omvPbtBNBC3J7lIe | The perimeter of a semi circle is 216 cm then the radius is? Choose one
A) 26 B) 48 C) 98 D) 37 E) 42 | <gadget id="calculator">2 + pi</gadget>
<output>2 + pi = around 5.141593</output>
<gadget id="calculator">216 / (2 + pi)</gadget>
<output>216/(2 + pi) = around 42.010329</output>
<result>E</result> | E | 42 | The perimeter of a semi circle is 216 cm then the radius is? | {
"A": "26",
"B": "48",
"C": "98",
"D": "37",
"E": "42"
} | divide(216, add(const_2, const_pi)) | add(const_2,const_pi)|divide(n0,#0)| | "36 / 7 r = 216 = > r = 42 answer : e" | physics |
math_qa__rPUSRtlm3rJ60LRj | A train 360 metre long runs with a speed of 45 km/hr. What time will it take to pass a platform of 140 metre long? Select the correct option
A) 30 B) 35 C) 40 D) 45 E) 50 | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">500 / 1_000</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) / 45</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">(1/90) * 3_600</gadget>
<output>40</output>
<result>C</result> | C | 40 | A train 360 metre long runs with a speed of 45 km/hr. What time will it take to pass a platform of 140 metre long? | {
"A": "30",
"B": "35",
"C": "40",
"D": "45",
"E": "50"
} | multiply(divide(divide(add(360, 140), const_1000), 45), const_3600) | add(n0,n2)|divide(#0,const_1000)|divide(#1,n1)|multiply(#2,const_3600) | speed = 45 km / hr = 45 Γ 5 / 18 = 25 / 2 m / s distance travelled = ( speed x time ) time = ( distance travelled / speed ) distance travelled = length of the train + length of the platform = 360 + 140 = 500 m = 500 / 25 / 2 = 40 sec answer : c | physics |
math_qa__cywGQ6DixZwhszZA | The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 18 times the probability that both events A and B occur. What is the probability that event A occurs?
Choose the correct choice from the following options:
A) 12 / 112
B) 6 / 81
C) 11 / 61
D) 12 / 33
E) 3 / 19 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">36 + 2</gadget>
<output>38</output>
<gadget id="calculator">3 / 38</gadget>
<output>3/38 = around 0.078947</output>
<gadget id="calculator">(3/38) * 2</gadget>
<output>3/19 = around 0.157895</output>
<result>E</result> | E | 0.157895 | The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 18 times the probability that both events A and B occur. What is the probability that event A occurs? | {
"A": "12 / 112",
"B": "6 / 81",
"C": "11 / 61",
"D": "12 / 33",
"E": "3 / 19"
} | multiply(divide(add(const_2, const_1), add(multiply(18, const_2), const_2)), const_2) | add(const_1,const_2)|multiply(n1,const_2)|add(#1,const_2)|divide(#0,#2)|multiply(#3,const_2)| | "let us say probability of a occuring is a . let us say probability of b occuring is b . a = 2 b probability ( either a or b or both ) = 8 times probability ( a and b ) a * ( 1 - b ) + b * ( 1 - a ) + ab = 18 * ab substituting a = 2 b in the second equation : 2 b * ( 1 - b ) + b * ( 1 - 2 b ) + 2 b * b = 18 * 2 b * b 3 b - 2 b ^ 2 = 36 b ^ 2 3 b = 38 b ^ 2 b = 3 / 38 so , a = 2 b = 6 / 38 = 3 / 19 the correct answer is e ." | general |
math_qa__Vq4Ngq8QunygNa4n | A student got twice as many sums wrong as he got right. If he attempted 24 sums in all, how many did he solve correctly ?
Choose the correct answer:
A) 12 B) 16 C) 8 D) 24 E) 26 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">24 / 3</gadget>
<output>8</output>
<result>C</result> | C | 8 | A student got twice as many sums wrong as he got right. If he attempted 24 sums in all, how many did he solve correctly ? | {
"A": "12",
"B": "16",
"C": "8",
"D": "24",
"E": "26"
} | divide(24, add(const_1, const_2)) | add(const_1,const_2)|divide(n0,#0) | explanation : suppose the boy got x sums right and 2 x sums wrong . then , x + 2 x = 24 3 x = 24 x = 8 . answer : c | general |
math_qa__3zSGL9qx3qO24IdN | A 300 m long train crosses a platform in 42 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Select:
A) 287
B) 350
C) 828
D) 277
E) 400 | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 42</gadget>
<output>700</output>
<gadget id="calculator">700 - 300</gadget>
<output>400</output>
<result>E</result> | E | 400 | A 300 m long train crosses a platform in 42 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | {
"A": "287",
"B": "350",
"C": "828",
"D": "277",
"E": "400"
} | subtract(multiply(speed(300, 18), 42), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 18 = 50 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 42 = 50 / 3 3 x + 900 = 2200 = > x = 400 m . answer : e" | physics |
math_qa__a4nZi9mjAMYbZXWv | A fashion designer sold a pair of jeans to a retail store for 40 percent more than it cost to manufacture the pair of jeans. A customer bought the pair of jeans for 10 percent more than the retailer paid for them. The price the customer paid was what percent greater than the cost of manufacturing the jeans?
Select the correct option.
A) 54 % B) 70 % C) 75 % D) 85 % E) 95 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">100 * (7/5)</gadget>
<output>140</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">140 * (11/10)</gadget>
<output>154</output>
<gadget id="calculator">154 / 100</gadget>
<output>77/50 = around 1.54</output>
<gadget id="calculator">(77/50) - 1</gadget>
<output>27/50 = around 0.54</output>
<gadget id="calculator">(27/50) * 100</gadget>
<output>54</output>
<result>A</result> | A | 54 | A fashion designer sold a pair of jeans to a retail store for 40 percent more than it cost to manufacture the pair of jeans. A customer bought the pair of jeans for 10 percent more than the retailer paid for them. The price the customer paid was what percent greater than the cost of manufacturing the jeans? | {
"A": "54 %",
"B": "70 %",
"C": "75 %",
"D": "85 %",
"E": "95 %"
} | multiply(subtract(divide(multiply(multiply(const_100, add(const_1, divide(40, const_100))), add(const_1, divide(10, const_100))), const_100), const_1), const_100) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#3,const_100)|multiply(#2,#4)|divide(#5,const_100)|subtract(#6,const_1)|multiply(#7,const_100)| | "find the product of the two increases : ( 1.4 ) * ( 1.1 ) , which is 1.54 and a 54 % increase . a" | gain |
math_qa__RkqkN6xh70tOwLkG | The time it took car P to travel 900 miles was 2 hours less than the time it took car R to travel the same distance. If car Pβs average speed was 10 miles per hour greater than that of car R, what was car Rβs average speed, in miles per hour?
Pick one
A) 40
B) 54
C) 62
D) 70
E) 80 | <gadget id="calculator">-10</gadget>
<output>-10</output>
<gadget id="calculator">(-10) ** 2</gadget>
<output>100</output>
<gadget id="calculator">900 * 10</gadget>
<output>9_000</output>
<gadget id="calculator">9_000 / 2</gadget>
<output>4_500</output>
<gadget id="calculator">-4_500</gadget>
<output>-4_500</output>
<gadget id="calculator">4 * (-4_500)</gadget>
<output>-18_000</output>
<gadget id="calculator">100 - (-18_000)</gadget>
<output>18_100</output>
<gadget id="calculator">18_100 ** (1/2)</gadget>
<output>10*sqrt(181) = around 134.53624</output>
<gadget id="calculator">(-10) + (10*sqrt(181))</gadget>
<output>-10 + 10*sqrt(181) = around 124.53624</output>
<gadget id="calculator">(-10 + 10*sqrt(181)) / 2</gadget>
<output>-5 + 5*sqrt(181) = around 62.26812</output>
<result>C</result> | C | 62 | The time it took car P to travel 900 miles was 2 hours less than the time it took car R to travel the same distance. If car Pβs average speed was 10 miles per hour greater than that of car R, what was car Rβs average speed, in miles per hour? | {
"A": "40",
"B": "54",
"C": "62",
"D": "70",
"E": "80"
} | divide(add(negate(10), sqrt(subtract(power(negate(10), 2), multiply(const_4, negate(divide(multiply(900, 10), 2)))))), 2) | multiply(n0,n2)|negate(n2)|divide(#0,n1)|power(#1,n1)|negate(#2)|multiply(#4,const_4)|subtract(#3,#5)|sqrt(#6)|add(#1,#7)|divide(#8,n1)| | "let speed of car r be = x then speed of car p = x + 10 a / q , ( 900 / x ) - ( 900 / ( x + 10 ) ) = 2 solving for x = 62 miles \ hr . c" | physics |
math_qa__CyBJmUaygJ4xnXUW | How many seconds will a 400 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? Choose one.
A) 20 B) 30 C) 40 D) 24 E) 60 | <gadget id="calculator">63 - 3</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">400 / (50/3)</gadget>
<output>24</output>
<result>D</result> | D | 24 | How many seconds will a 400 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? | {
"A": "20",
"B": "30",
"C": "40",
"D": "24",
"E": "60"
} | divide(400, multiply(subtract(63, 3), const_0_2778)) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 63 - 3 = 60 km / hr . = 60 * 5 / 18 = 50 / 3 m / sec . time taken to pass the man = 400 * 3 / 50 = 24 sec . answer : option d" | physics |
math_qa__fXey4AFwOxk4GbgH | A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.150 more. What was the Sum? Choose the correct answer.
A) s . 120
B) s . 130
C) s . 140
D) s . 150
E) s . 300 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">150 / (1/2)</gadget>
<output>300</output>
<result>E</result> | E | 300 | A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.150 more. What was the Sum? | {
"A": "s . 120",
"B": "s . 130",
"C": "s . 140",
"D": "s . 150",
"E": "s . 300"
} | divide(150, multiply(divide(5, const_100), 10)) | divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1) | at 5 % more rate , the increase in s . i for 10 years = rs . 150 ( given ) so , at 5 % more rate , the increase in si for 1 year = 150 / 10 = rs . 15 / - i . e . rs . 15 is 5 % of the invested sum so , 1 % of the invested sum = 15 / 5 therefore , the invested sum = 15 Γ 100 / 5 = rs . 300 answer : e | gain |
math_qa__hkyVm1gHHEZbu7Du | 12 men can complete a piece of work in 4 days, while 15 women can complete the same work in 4 days. 6 men start working on the job and after working for 2 days, all of them stopped working. How many women should be put on the job to complete the remaining work, if it so to be completed in 3 days? Choose the correct option:
A) 15 women B) 85 women C) 75 women D) 65 women E) 35 women | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / 15</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">1 / (1/60)</gadget>
<output>60</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">(1/4) / 12</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">12 * (1/48)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">60 * (3/4)</gadget>
<output>45</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">45 * (1/3)</gadget>
<output>15</output>
<result>A</result> | A | 15 | 12 men can complete a piece of work in 4 days, while 15 women can complete the same work in 4 days. 6 men start working on the job and after working for 2 days, all of them stopped working. How many women should be put on the job to complete the remaining work, if it so to be completed in 3 days? | {
"A": "15 women",
"B": "85 women",
"C": "75 women",
"D": "65 women",
"E": "35 women"
} | multiply(multiply(divide(const_1, divide(divide(const_1, 4), 15)), subtract(const_1, multiply(multiply(6, 2), divide(divide(const_1, 4), 12)))), divide(const_1, 3)) | divide(const_1,n6)|divide(const_1,n1)|multiply(n4,n5)|divide(#1,n2)|divide(#1,n0)|divide(const_1,#3)|multiply(#4,#2)|subtract(const_1,#6)|multiply(#5,#7)|multiply(#0,#8)| | "1 man ' s 1 day work = 1 / 48 ; 1 woman ' s 1 day work = 1 / 60 . 6 men ' s 2 day ' s work = 6 / 48 * 2 = 1 / 4 . remaining work = ( 1 - 1 / 4 ) = 3 / 4 now , 1 / 60 work is done in 1 day by 1 woman . so , 3 / 4 work will be done in 3 days by ( 60 * 3 / 4 * 1 / 3 ) = 15 women . answer : a" | physics |
math_qa__hkpgFu1LMAPxPj8A | In a stream running at 2 Kmph, a motor boat goes 10 Km upstream and back again to the starting point in 55 minutes. Find the speed of motor boat in still water?
Choose the correct choice from the following answers:
A) 11 B) 15 C) 22 D) 18 E) 25 | <gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">55 / 60</gadget>
<output>11/12 = around 0.916667</output>
<gadget id="calculator">20 / (11/12)</gadget>
<output>240/11 = around 21.818182</output>
<result>C</result> | C | 22 | In a stream running at 2 Kmph, a motor boat goes 10 Km upstream and back again to the starting point in 55 minutes. Find the speed of motor boat in still water? | {
"A": "11",
"B": "15",
"C": "22",
"D": "18",
"E": "25"
} | divide(add(10, 10), divide(55, const_60)) | add(n1,n1)|divide(n2,const_60)|divide(#0,#1)| | "let the speed of motor boat instill water be x kmph then , speed in downstream = ( x + 2 ) km and . speed in upstream = ( x - 2 ) kmph time taken to row 10 km & back = ( 10 / x + 2,10 / x - 2 ) 10 / x + 2 + 10 / x - 2 = 55 / 60 11 x 2 - 240 x - 44 = 0 ( x - 22 ) ( 11 x + 2 ) = 0 x = 22 or x = - 2 / 11 then x = 22 kmph answer is c ." | physics |
math_qa__YO2rAfKVMr3oUPh2 | A train 100 m long can cross an electric pole in 20 sec and then find the speed of the train?
Answers:
A) 19 kmph
B) 18 kmph
C) 72 kmph
D) 17 kmph
E) 91 kmph | <gadget id="calculator">100 / 1_000</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">20 / 3_600</gadget>
<output>1/180 = around 0.005556</output>
<gadget id="calculator">(1/10) / (1/180)</gadget>
<output>18</output>
<result>B</result> | B | 18 | A train 100 m long can cross an electric pole in 20 sec and then find the speed of the train? | {
"A": "19 kmph",
"B": "18 kmph",
"C": "72 kmph",
"D": "17 kmph",
"E": "91 kmph"
} | divide(divide(100, const_1000), divide(20, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 100 / 20 s = 5 m / sec speed = 5 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 18 kmph answer : b" | physics |
math_qa__rJQoukM1QOYnMA5k | There are 2 sections A and B in a class, consisting of 30and 20 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, Find the average of the whole class?
Select the correct option
A) 35 kg
B) 37 kg
C) 42 kg
D) 38 kg
E) 29.78 kg | <gadget id="calculator">30 * 40</gadget>
<output>1_200</output>
<gadget id="calculator">20 * 35</gadget>
<output>700</output>
<gadget id="calculator">1_200 + 700</gadget>
<output>1_900</output>
<gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">1_900 / 50</gadget>
<output>38</output>
<result>D</result> | D | 38 | There are 2 sections A and B in a class, consisting of 30and 20 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, Find the average of the whole class? | {
"A": "35 kg",
"B": "37 kg",
"C": "42 kg",
"D": "38 kg",
"E": "29.78 kg"
} | divide(add(multiply(30, 40), multiply(20, 35)), add(30, 20)) | add(n1,n2)|multiply(n1,n3)|multiply(n2,n4)|add(#1,#2)|divide(#3,#0)| | "total weight of 36 + 44 students = 30 * 40 + 20 * 35 = 1900 average weight of the class is = 1900 / 50 = 38 kg answer is d" | general |
math_qa__iwzmbuDu0cwaQyML | A person can swim in still water at 6 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 14km? Pick one.
A) 3.5
B) 4.5
C) 5
D) 9
E) 6 | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">14 / 4</gadget>
<output>7/2 = around 3.5</output>
<result>A</result> | A | 3.5 | A person can swim in still water at 6 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 14km? | {
"A": "3.5",
"B": "4.5",
"C": "5",
"D": "9",
"E": "6"
} | divide(14, subtract(6, 2)) | subtract(n0,n1)|divide(n2,#0)| | "m = 6 s = 2 us = 6 - 2 = 4 d = 42 t = 14 / 4 = 3.5 answer : a" | physics |
math_qa__ODM7GE8UKVvIZqo9 | When tossed, a certain coin has an equal probability of landing on either side. If the coin is tossed 5 times, what is the probability that it will land on the same side each time? Choose the correct option:
A) 1 / 6
B) 1 / 8
C) 1 / 12
D) 1 / 16
E) 1 / 32 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 5</gadget>
<output>1/32 = around 0.03125</output>
<gadget id="calculator">(1/32) + (1/32)</gadget>
<output>1/16 = around 0.0625</output>
<result>D</result> | D | 0.0625 | When tossed, a certain coin has an equal probability of landing on either side. If the coin is tossed 5 times, what is the probability that it will land on the same side each time? | {
"A": "1 / 6",
"B": "1 / 8",
"C": "1 / 12",
"D": "1 / 16",
"E": "1 / 32"
} | add(power(divide(const_1, const_2), 5), power(divide(const_1, const_2), 5)) | divide(const_1,const_2)|power(#0,n0)|add(#1,#1)| | "on the first toss , the coin will land on one side or the other . on the second toss , the probability of landing on the same side is 1 / 2 . on the third toss , the probability of landing on the same side is 1 / 2 . on the fourth toss , the probability of landing on the same side is 1 / 2 . on the fifth toss , the probability of landing on the same side is 1 / 2 . p ( same side all five times ) = 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 = 1 / 16 . the answer is d ." | probability |
math_qa__n9UIomnq5OZWnvhb | The closest approximation of D(69.28 Γ 0.004)/0.03 is Choose the correct option.
A) 0.092
B) 0.92
C) 9.2
D) 92
E) 920 | <gadget id="calculator">0.004 / 0.03</gadget>
<output>0.133333</output>
<gadget id="calculator">0.133333 * 69.28</gadget>
<output>9.23731</output>
<result>C</result> | C | 9.2 | The closest approximation of D(69.28 Γ 0.004)/0.03 is | {
"A": "0.092",
"B": "0.92",
"C": "9.2",
"D": "92",
"E": "920"
} | multiply(divide(0.004, 0.03), 69.28) | divide(n1,n2)|multiply(n0,#0)| | "d ( 69.28 Γ 0.004 ) / 0.03 1 . 0.004 = 4 Γ 10 ^ ( - 3 ) 2 . 0.03 = 3 Γ 10 ^ ( - 2 ) 3 . ( a Γ b ) / c = a Γ ( b / c ) 4 . 0.004 / 0.03 = 4 Γ 10 ^ ( - 3 ) / ( 3 Γ 10 ^ ( - 2 ) ) = 4 Γ 10 ^ ( - 3 - ( - 2 ) ) / 3 = 4 Γ 10 ^ ( - 1 ) / 3 = ( 4 / 3 ) Γ 10 ^ ( - 1 ) = 1.333 Γ 10 ^ ( - 1 ) therefore , ( 69.28 Γ 0.004 ) / 0.03 = 69.28 Γ ( 0.004 / 0.03 ) = 69.28 Γ 1.33 Γ 10 ^ ( - 1 ) = 69.28 Γ 1.33 / 10 = 6.928 * 1.33 now , 7 Γ 2 = 14 7 Γ 1 = 7 or better : 6.9 Γ 1 = 6.9 6.9 Γ 2 = 13.8 hence , 6.9 < 6.928 Γ 1.33 < 13.8 9.2 is the only answer that satisfies this condition . c" | general |
math_qa__Cp4hqxf4u2lIKnJ3 | In a 1000 m race, A beats B by 200 meters or 25 seconds. Find the speed of B? Answers.
A) 5 m / s B) 8 m / s C) 9 m / s D) 4 m / s E) 2 m / s | <gadget id="calculator">200 / 25</gadget>
<output>8</output>
<result>B</result> | B | 8 | In a 1000 m race, A beats B by 200 meters or 25 seconds. Find the speed of B? | {
"A": "5 m / s",
"B": "8 m / s",
"C": "9 m / s",
"D": "4 m / s",
"E": "2 m / s"
} | divide(200, 25) | divide(n1,n2) | b 8 m / s since a beats b by 200 m or 25 seconds , i t implies that b covers 200 m in 25 seconds . hence speed of b = 200 / 25 = 8 m / s . | physics |
math_qa__7QVrQLr0HnWwA0FP | Robert's salary was decreased by 50% and subsequently increased by 50%. how much percentage does he lose? Pick: A) 10 % B) 20 % C) 25 % D) 30 % E) 50 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">50 * 150</gadget>
<output>7_500</output>
<gadget id="calculator">10_000 - 7_500</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 10_000</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | Robert's salary was decreased by 50% and subsequently increased by 50%. how much percentage does he lose? | {
"A": "10 %",
"B": "20 %",
"C": "25 %",
"D": "30 %",
"E": "50 %"
} | multiply(divide(subtract(multiply(const_100, const_100), multiply(subtract(const_100, 50), add(const_100, 50))), multiply(const_100, const_100)), const_100) | add(n0,const_100)|multiply(const_100,const_100)|subtract(const_100,n0)|multiply(#0,#2)|subtract(#1,#3)|divide(#4,#1)|multiply(#5,const_100)| | "let original salary be $ 100 new final salary = 150 % of ( 50 % of $ 100 ) = ( 150 / 100 ) * ( 50 / 100 ) * 100 = $ 75 decrease = 25 % correct option is c" | general |
math_qa__vM0xTBwxZ9226DdD | The average age of 10 members of a committee is the same as it was 4 years ago, because an old member has been replaced by a young member.
Find how much younger is the new member ? Choose one: A) 35 B) 15 C) 40 D) 52 E) 14 | <gadget id="calculator">10 * 4</gadget>
<output>40</output>
<result>C</result> | C | 40 | The average age of 10 members of a committee is the same as it was 4 years ago, because an old member has been replaced by a young member.
Find how much younger is the new member ? | {
"A": "35",
"B": "15",
"C": "40",
"D": "52",
"E": "14"
} | multiply(10, 4) | multiply(n0,n1) | c let the sum of nine member ( total ) = x and the age of old one = z so its average 4 yrs before = ( x + z ) / 10 . after 4 yrs let z be replaced by y . so now avg = ( x + 4 * 10 + y ) / 10 now ( x + z ) / 10 = ( x + 40 + y ) / 10 so after solving it found z = y + 40 . so old person is 40 yrs older than young one . | general |
math_qa__0bwRf7GdCrmzsI5G | Tea worth Rs.126 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs.157 per kg, the price of the third variety per kg will be Choose the correct choice from the following choices
A) rs . 179.50 B) rs . 1700 C) rs . 175.50 D) rs . 180 E) none | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">157 * 4</gadget>
<output>628</output>
<gadget id="calculator">126 + 126</gadget>
<output>252</output>
<gadget id="calculator">628 - 252</gadget>
<output>376</output>
<gadget id="calculator">376 / 2</gadget>
<output>188</output>
<result>A</result> | A | 179.5 | Tea worth Rs.126 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs.157 per kg, the price of the third variety per kg will be | {
"A": "rs . 179.50",
"B": "rs . 1700",
"C": "rs . 175.50",
"D": "rs . 180",
"E": "none"
} | divide(subtract(multiply(157, add(add(1, 1), 2)), add(126, 126)), 2) | add(n1,n1)|add(n0,n0)|add(n3,#0)|multiply(n4,#2)|subtract(#3,#1)|divide(#4,n3) | solution since first second varieties are mixed in equal proportions , so their average price = rs . ( 126 + 135 / 2 ) = rs . 130.50 so , the mixture is formed by mixing two varieties , one at rs . 130.50 per kg and the other at say , rs . x per kg in the ratio 2 : 2 , i . e . , 1 : 1 . we have to find x . x - 157 / 22.50 = 1 = Γ’ β¬ ΒΊ x - 157 = 22.50 = Γ’ β¬ ΒΊ x = 179.50 . hence , price of the third variety = rs . 179.50 per kg . answer a | other |
math_qa__JW0JKkuXRcNYyL6d | If 75 percent of 600 is 50 percent of x, then x=? Choose the correct choice from the following choices: A) 800 B) 900 C) 1000 D) 1100 E) 1200 | <gadget id="calculator">75 * 600</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 50</gadget>
<output>900</output>
<result>B</result> | B | 900 | If 75 percent of 600 is 50 percent of x, then x=? | {
"A": "800",
"B": "900",
"C": "1000",
"D": "1100",
"E": "1200"
} | divide(multiply(75, 600), 50) | multiply(n0,n1)|divide(#0,n2)| | "0.75 * 600 = 0.5 * x x = 7.5 / 5 * 600 = 900" | general |
math_qa__gzDLjw5OglRxcndU | There were 35 students in a hostel. Due to the admission of 7 new students, the expenses of mess were increased by 42 per day while the average expenditure per head diminished by 1. What was the original expenditure of the mess? Choose the correct choice
A) 400 B) 400 C) 445 D) 465 E) none of the above | <gadget id="calculator">42 + 42</gadget>
<output>84</output>
<gadget id="calculator">42 - 35</gadget>
<output>7</output>
<gadget id="calculator">84 / 7</gadget>
<output>12</output>
<gadget id="calculator">12 * 35</gadget>
<output>420</output>
<gadget id="calculator">42 - 12</gadget>
<output>30</output>
<gadget id="calculator">30 - 12</gadget>
<output>18</output>
<gadget id="calculator">18 + 2</gadget>
<output>20</output>
<gadget id="calculator">420 - 20</gadget>
<output>400</output>
<result>B</result> | B | 400 | There were 35 students in a hostel. Due to the admission of 7 new students, the expenses of mess were increased by 42 per day while the average expenditure per head diminished by 1. What was the original expenditure of the mess? | {
"A": "400",
"B": "400",
"C": "445",
"D": "465",
"E": "none of the above"
} | subtract(multiply(divide(add(42, 42), subtract(42, 35)), 35), add(subtract(subtract(42, divide(add(42, 42), subtract(42, 35))), divide(add(42, 42), subtract(42, 35))), const_2)) | add(n2,n2)|subtract(n2,n0)|divide(#0,#1)|multiply(n0,#2)|subtract(n2,#2)|subtract(#4,#2)|add(#5,const_2)|subtract(#3,#6) | let the original average expenditure be ` x . then , 42 ( x β 1 ) β 35 x = 42 β 7 x = 84 β x = 12 . β΄ original expenditure = ( 35 Γ 12 ) = 420 . answer b | general |
math_qa__X0iiZzJMBuNFiSFO | A person can row at 10 kmph and still water. He takes 5 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 2 kmph? Pick:
A) 32 km B) 25 km C) 28 km D) 24 km E) 20 km | <gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">8 * 12</gadget>
<output>96</output>
<gadget id="calculator">96 * 5</gadget>
<output>480</output>
<gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">480 / 20</gadget>
<output>24</output>
<result>D</result> | D | 24 | A person can row at 10 kmph and still water. He takes 5 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 2 kmph? | {
"A": "32 km",
"B": "25 km",
"C": "28 km",
"D": "24 km",
"E": "20 km"
} | divide(multiply(multiply(subtract(10, 2), add(10, const_2)), 5), add(add(10, const_2), subtract(10, 2))) | add(n0,const_2)|subtract(n0,n2)|add(#0,#1)|multiply(#0,#1)|multiply(n1,#3)|divide(#4,#2) | let the distance between a and b be x km . total time = x / ( 10 + 2 ) + x / ( 10 - 2 ) = 5 = > x / 12 + x / 8 = 5 = > ( 2 x + 3 x ) / 24 = 5 = > x = 24 km . answer : d | physics |
math_qa__Bltv2g9UoseIjrBA | A tour group of 25 people paid a total of $945 for entrance to a museum. If this price included a 5% sales tax, and all the tickets cost the same amount, what was the face value of each ticket price without the sales tax?
Choices
Select.
A) $ 22
B) $ 23.94
C) $ 36
D) $ 25.20
E) $ 30 | <gadget id="calculator">945 / 25</gadget>
<output>189/5 = around 37.8</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">(189/5) * 95</gadget>
<output>3_591</output>
<gadget id="calculator">3_591 / 100</gadget>
<output>3_591/100 = around 35.91</output>
<result>C</result> | C | 36 | A tour group of 25 people paid a total of $945 for entrance to a museum. If this price included a 5% sales tax, and all the tickets cost the same amount, what was the face value of each ticket price without the sales tax?
Choices | {
"A": "$ 22",
"B": "$ 23.94",
"C": "$ 36",
"D": "$ 25.20",
"E": "$ 30"
} | divide(multiply(divide(945, 25), subtract(const_100, 5)), const_100) | divide(n1,n0)|subtract(const_100,n2)|multiply(#0,#1)|divide(#2,const_100) | soln : - 945 / 25 = x + 0.05 x 945 / 25 = 1.05 x x = 36 answer : c | general |
math_qa__x9oQoRtt08vwr96X | Carrie likes to buy t-shirts at the local clothing store. They cost $8.55 each. One day, she bought 9 t-shirts. How much money did she spend? Select
A) $ 150
B) $ 248.75
C) $ 200
D) $ 171.6
E) $ 73.1025 | <gadget id="calculator">9 * 8.55</gadget>
<output>76.95</output>
<gadget id="calculator">floor(76.95)</gadget>
<output>76</output>
<result>E</result> | E | 73.1025 | Carrie likes to buy t-shirts at the local clothing store. They cost $8.55 each. One day, she bought 9 t-shirts. How much money did she spend? | {
"A": "$ 150",
"B": "$ 248.75",
"C": "$ 200",
"D": "$ 171.6",
"E": "$ 73.1025"
} | floor(multiply(9, 8.55)) | multiply(n0,n1)|floor(#0) | $ 8.55 * 9 = $ 73.1025 . answer is e . | general |
math_qa__af6QyshwXtvUJyhB | What is the average of the first 10 multiples of 11?
Choose the correct choice from the following options:
A) 55.5
B) 61.5
C) 53.5
D) 78.5
E) 60.5 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">10 * 11</gadget>
<output>110</output>
<gadget id="calculator">110 / 2</gadget>
<output>55</output>
<gadget id="calculator">55 / 10</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">(11/2) * 11</gadget>
<output>121/2 = around 60.5</output>
<result>E</result> | E | 60.5 | What is the average of the first 10 multiples of 11? | {
"A": "55.5",
"B": "61.5",
"C": "53.5",
"D": "78.5",
"E": "60.5"
} | multiply(divide(divide(multiply(10, add(10, const_1)), const_2), 10), 11) | add(n0,const_1)|multiply(n0,#0)|divide(#1,const_2)|divide(#2,n0)|multiply(n1,#3)| | "( 11 + 22 + . . . + 110 ) / 10 = 11 ( 1 + 2 + . . . + 10 ) / 10 = 11 ( 10 ) ( 11 ) / ( 10 * 2 ) = 121 / 2 = 60.5 option e" | general |
math_qa__lBJKou7wao7LLrlA | The diagonals of a rhombus are 25 cm and 30 cm. Find its area? Answers.
A) 250 B) 300 C) 375 D) 550 E) 750 | <gadget id="calculator">(25 * 30) / 2</gadget>
<output>375</output>
<result>C</result> | C | 375 | The diagonals of a rhombus are 25 cm and 30 cm. Find its area? | {
"A": "250",
"B": "300",
"C": "375",
"D": "550",
"E": "750"
} | rhombus_area(25, 30) | rhombus_area(n0,n1)| | "area = 0.5 x 25 x 30 = 375 cm Γ’ Β² answer : c" | geometry |
math_qa__UdXoIPdKLI9Xm1Jm | At golds gym class can be divided into 8 teams with an equal number of players on each team or into 12 teams with an equal number of players on each team. What is the lowest possible number of students in the class? Choose the correct choice from the following choices:
A) 20 B) 24 C) 36 D) 48 E) 96 | <gadget id="calculator">lcm(8, 12)</gadget>
<output>24</output>
<result>B</result> | B | 24 | At golds gym class can be divided into 8 teams with an equal number of players on each team or into 12 teams with an equal number of players on each team. What is the lowest possible number of students in the class? | {
"A": "20",
"B": "24",
"C": "36",
"D": "48",
"E": "96"
} | lcm(8, 12) | lcm(n0,n1) | we are given that golds gym class can be divided into 8 teams or 12 teams , with an equal number of players on each team . translating this into two mathematical expressions we can say , where g is the total number of students in the gym class , that : g / 8 = integer and g / 12 = integer this means that g is a multiple of both 8 and 12 . we are asked to determine the lowest number of students in the class , or the lowest value for variable β g β . because we know that g is a multiple of 8 and of 12 , we need to find the least common multiple of 8 and 12 . although there are technical ways for determining the least common multiple , the easiest method is to analyze the multiples of 8 and 12 until we find one in common . starting with 8 , we have : 8 , 16 , 24 , 32 for 12 , we have : 12 , 24 for the multiples of 12 , we stopped at 24 , because we see that 24 is also a multiple of 8 . thus , 24 is the least common multiple of 8 and 12 , and therefore we know that the lowest possible number of students in the gym class is 24 . answer b . | general |
math_qa__xFAo6Poku0nGkLoN | how many internal diagonals does a hexagon ( 6 sided polygon ) have ? Choose the correct choice from the following answers:
A) 5
B) 6
C) 8
D) 9
E) 10 | <gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<result>D</result> | D | 9 | how many internal diagonals does a hexagon ( 6 sided polygon ) have ? | {
"A": "5",
"B": "6",
"C": "8",
"D": "9",
"E": "10"
} | divide(multiply(6, subtract(6, const_3)), const_2) | subtract(n0,const_3)|multiply(n0,#0)|divide(#1,const_2) | number of diagonals in any polygon can be found using this formula : n ( n - 3 ) / 2 here n = 6 no . of diagonals = 6 ( 6 - 3 ) / 2 = 9 ans d | geometry |
math_qa__wBQfzwtF55GbSxax | A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.14.70 less, he would have gained 30%. Find the cost of the article. Choose the correct choice from the following.
A) 30 B) 40 C) 50 D) 60 E) 70 | <gadget id="calculator">14.7 * 100</gadget>
<output>1_470</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">30 + 100</gadget>
<output>130</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">130 * 80</gadget>
<output>10_400</output>
<gadget id="calculator">10_400 / 100</gadget>
<output>104</output>
<gadget id="calculator">125 - 104</gadget>
<output>21</output>
<gadget id="calculator">1_470 / 21</gadget>
<output>70</output>
<result>E</result> | E | 70 | A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.14.70 less, he would have gained 30%. Find the cost of the article. | {
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "70"
} | divide(multiply(14.70, const_100), subtract(add(25, const_100), divide(multiply(add(30, const_100), subtract(const_100, 20)), const_100))) | add(n0,const_100)|add(n3,const_100)|multiply(n2,const_100)|subtract(const_100,n1)|multiply(#1,#3)|divide(#4,const_100)|subtract(#0,#5)|divide(#2,#6)| | "let c . p = 100 gain = 25 % s . p = 125 supposed c . p = 80 gain = 30 % s . p = ( 130 * 80 ) / 100 = 104 diff = ( 125 - 104 ) = 21 diff 21 when c . p = 100 then diff 14.70 when c . p = ( 100 * 14.70 ) / 21 = 70 answer : e" | gain |
math_qa__YCSWerYkGUTJvmak | Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1568? Choose the correct choice from the following answers: A) 1000 B) 2777 C) 2889 D) 1400 E) 2771 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 5</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) + 1</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">1_568 / (28/25)</gadget>
<output>1_400</output>
<result>D</result> | D | 1,400 | Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1568? | {
"A": "1000",
"B": "2777",
"C": "2889",
"D": "1400",
"E": "2771"
} | divide(1568, add(divide(multiply(divide(add(multiply(2, 5), 2), 5), 5), const_100), const_1)) | multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)| | "1568 = p [ 1 + ( 5 * 12 / 5 ) / 100 ] p = 1400 . answer : d" | general |
math_qa__62pz05nQUREyoFvJ | How many seconds will a 700 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Choose one: A) 23 sec B) 30 sec C) 27 sec D) 36 sec E) 42 sec | <gadget id="calculator">63 - 3</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">700 / (50/3)</gadget>
<output>42</output>
<result>E</result> | E | 42 | How many seconds will a 700 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? | {
"A": "23 sec",
"B": "30 sec",
"C": "27 sec",
"D": "36 sec",
"E": "42 sec"
} | divide(700, multiply(subtract(63, 3), const_0_2778)) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 63 - 3 = 60 km / hr . = 60 * 5 / 18 = 50 / 3 m / sec . time taken to pass the man = 700 * 3 / 50 = 42 sec . answer : e" | physics |
math_qa__YYmSemLYtCWvx0Hs | If 3 men or 4 women can reap a field in 10 days how long will 5 men and 6 women take to reap it? Choose the correct choice from the following:
A) 19 / 60 B) 9 / 60 C) 2 / 3 D) 5 / 18 E) 6 / 24 | <gadget id="calculator">10 / 3</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">5 * (10/3)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">10 / 4</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">6 * (5/2)</gadget>
<output>15</output>
<gadget id="calculator">(50/3) + 15</gadget>
<output>95/3 = around 31.666667</output>
<gadget id="calculator">10 / (95/3)</gadget>
<output>6/19 = around 0.315789</output>
<result>A</result> | A | 0.316667 | If 3 men or 4 women can reap a field in 10 days how long will 5 men and 6 women take to reap it? | {
"A": "19 / 60",
"B": "9 / 60",
"C": "2 / 3",
"D": "5 / 18",
"E": "6 / 24"
} | divide(10, add(multiply(5, divide(10, 3)), multiply(6, divide(10, 4)))) | divide(n2,n0)|divide(n2,n1)|multiply(n3,#0)|multiply(n4,#1)|add(#2,#3)|divide(n2,#4) | explanation : 3 men reap 1 / 10 field in 1 day 1 man reap 1 / ( 3 x 10 ) 4 women reap 1 / 10 field in 1 day 1 woman reap 1 / ( 10 x 4 ) 5 men and 6 women reap ( 5 / ( 3 x 10 ) + 6 / ( 4 x 10 ) ) = 19 / 60 in 1 day 5 men and 6 women will reap the field in 19 / 60 days answer : option a | physics |
math_qa__V5aRNK08Mclhfce5 | Qames can eat 25 marshmallows is 20 minutes. Dylan can eat 25 in one hour. In how much time will the two eat 150 marshmallows?
Choose the correct choice from the following options:
A) 40 minutes . B) 1 hour and 30 minutes . C) 1 hour . D) 1 hour and 40 minutes . E) 2 hours and 15 minutes . | <gadget id="calculator">25 / 60</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">25 / 20</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/12) + (5/4)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">150 / (5/3)</gadget>
<output>90</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">90 / (3/2)</gadget>
<output>60</output>
<gadget id="calculator">60 / 60</gadget>
<output>1</output>
<result>C</result> | C | 1 | Qames can eat 25 marshmallows is 20 minutes. Dylan can eat 25 in one hour. In how much time will the two eat 150 marshmallows? | {
"A": "40 minutes .",
"B": "1 hour and 30 minutes .",
"C": "1 hour .",
"D": "1 hour and 40 minutes .",
"E": "2 hours and 15 minutes ."
} | divide(const_60, divide(divide(150, add(divide(25, const_60), divide(25, 20))), divide(const_3, const_2))) | divide(n0,const_60)|divide(n0,n1)|divide(const_3,const_2)|add(#0,#1)|divide(n3,#3)|divide(#4,#2)|divide(const_60,#5) | rate = output / time qames rate = 25 / 20 = 5 / 4 dylan rate = 25 / 60 = 5 / 12 combined rate = 5 / 4 + 5 / 12 = 20 / 12 combinedrate * combinedtime = combinedoutput 20 / 12 * t = 150 t = 90 mins = > 1 hr 30 min | physics |
math_qa__Ysvpyq28hs1bTCiM | Ajay and Balu together can do a piece of work in 12 days. Balu and Charan together can do the same work in 16 days. After Ajay has been working at it for 5 days and Balu for 7 days, Charan finishes it in 13 days. In how many days will Charan alone be able to do the work? Options.
A) 16 days B) 24 days C) 36 days D) 48 days E) 58 days | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">5 * (1/12)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">1 - (5/12)</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">7 - 5</gadget>
<output>2</output>
<gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">2 * (1/16)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(7/12) - (1/8)</gadget>
<output>11/24 = around 0.458333</output>
<gadget id="calculator">1 / (11/24)</gadget>
<output>24/11 = around 2.181818</output>
<gadget id="calculator">13 - 2</gadget>
<output>11</output>
<gadget id="calculator">(24/11) * 11</gadget>
<output>24</output>
<result>B</result> | B | 24 | Ajay and Balu together can do a piece of work in 12 days. Balu and Charan together can do the same work in 16 days. After Ajay has been working at it for 5 days and Balu for 7 days, Charan finishes it in 13 days. In how many days will Charan alone be able to do the work? | {
"A": "16 days",
"B": "24 days",
"C": "36 days",
"D": "48 days",
"E": "58 days"
} | multiply(inverse(subtract(subtract(const_1, multiply(5, inverse(12))), multiply(subtract(7, 5), inverse(16)))), subtract(13, const_2)) | inverse(n0)|inverse(n1)|subtract(n3,n2)|subtract(n4,const_2)|multiply(n2,#0)|multiply(#1,#2)|subtract(const_1,#4)|subtract(#6,#5)|inverse(#7)|multiply(#8,#3) | let the total work be 48 units . ajay and balu β s one day work = 48 / 12 = 4 units . balu and charan β s one day work = 48 / 16 = 3 units . ajay β s one day work = 4 - balu β s one day work . balu β s one day work = 3 - charan β s one day work . therefore , ajay β s one day work = 1 + charan β s one day work . also given , 5 x ajay β s one day work + 7 x balu β s one day work + 13 x charan β s one day work = 48 equating all the equations formed , we get charan β s one day work is 2 units . hence , charan can finish the whole work in 48 / 2 = 24 days . answer : b | physics |
math_qa__lr6F2whbmHtvRv6H | City A to city B, John drove for 1 hour at 40 mph and for 3 hours at 60 mph. What was the average speed for the whole trip? Choose the correct answer: A) 57 B) 57.5 C) 58.2 D) 59 E) 55 | <gadget id="calculator">1 * 40</gadget>
<output>40</output>
<gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">40 + 180</gadget>
<output>220</output>
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">220 / 4</gadget>
<output>55</output>
<result>E</result> | E | 55 | City A to city B, John drove for 1 hour at 40 mph and for 3 hours at 60 mph. What was the average speed for the whole trip? | {
"A": "57",
"B": "57.5",
"C": "58.2",
"D": "59",
"E": "55"
} | divide(add(multiply(1, 40), multiply(3, 60)), add(1, 3)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0) | the total distance is 1 Γ 40 + 3 Γ 60 = 220 and the total time is 4 hours . hence , average speed = ( total distance / total time ) = 220 / 4 = 55 answer : e | physics |
math_qa__2Lur6Ui4pzFJHh60 | If each digit in the set A = {1, 2, 3, 4, 5, 6} is used exactly once, in how many ways can the digits be arranged?
Answers: A) 720 B) 830 C) 940 D) 1050 E) 1160 | <gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<result>A</result> | A | 720 | If each digit in the set A = {1, 2, 3, 4, 5, 6} is used exactly once, in how many ways can the digits be arranged? | {
"A": "720",
"B": "830",
"C": "940",
"D": "1050",
"E": "1160"
} | factorial(6) | factorial(n5) | 6 ! = 720 the answer is a . | general |
math_qa__xFyDHLjnN2ZelkTz | Aβs speed is 20/19 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat? Choose one:
A) 1 / 19
B) 3 / 19
C) 1 / 10
D) 1 / 20
E) 3 / 10 | <gadget id="calculator">20 - 19</gadget>
<output>1</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<result>D</result> | D | 0.05 | Aβs speed is 20/19 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat? | {
"A": "1 / 19",
"B": "3 / 19",
"C": "1 / 10",
"D": "1 / 20",
"E": "3 / 10"
} | divide(subtract(20, 19), 20) | subtract(n0,n1)|divide(#0,n0)| | "let d be the full distance . let x be the fraction of the distance that b runs . let v be the speed at which b runs . the time should be the same for both runners . time = d / ( 20 v / 19 ) = xd / v ( 19 / 20 ) * d / v = x * d / v x = 19 / 20 b should have a head start of 1 / 20 of the full distance . the answer is d ." | general |
math_qa__7MyqfJU65jwa6Pts | Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $504 per week. How much does she earn in dollars per hour?
Select
A) 2
B) 8
C) 9
D) 14
E) 24 | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">504 / 36</gadget>
<output>14</output>
<result>D</result> | D | 14 | Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $504 per week. How much does she earn in dollars per hour? | {
"A": "2",
"B": "8",
"C": "9",
"D": "14",
"E": "24"
} | divide(504, add(multiply(8, const_3), multiply(6, const_2))) | multiply(n0,const_3)|multiply(n1,const_2)|add(#0,#1)|divide(n2,#2) | explanation : total hours worked = 8 x 3 + 6 x 2 = 36 total earned = 504 . hourly wage = 504 / 36 = 14 answer : d | physics |
math_qa__T3EfoSxbukyTTCfM | If
1 = 6 ,
2 = 12 ,
3 = 18,
4 = 24,
5 = 30,
Then 6 = ?
Choose the correct choice from the following choices
A) 5
B) 3
C) 1
D) 7
E) 9 | <gadget id="calculator">2 - 1</gadget>
<output>1</output>
<result>C</result> | C | 1 | If
1 = 6 ,
2 = 12 ,
3 = 18,
4 = 24,
5 = 30,
Then 6 = ? | {
"A": "5",
"B": "3",
"C": "1",
"D": "7",
"E": "9"
} | subtract(2, 1) | subtract(n2,n0) | solution : 1 as stated 1 = 6 = > 6 = 1 answer c | general |
math_qa__Ic6H4sxGloCY8E46 | 3 partners a , b , c start a business . twice a β s capital is equal to thrice b β s capital and b β s capital is 4 times c β s capital . out of a total profit of rs . 16500 at the end of the year , b β share is : Choose the correct choice from the following answers:
A) 2000 B) 4000 C) 5000 D) 6000 E) none | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(5/2) + (1/4)</gadget>
<output>11/4 = around 2.75</output>
<gadget id="calculator">16_500 / (11/4)</gadget>
<output>6_000</output>
<result>D</result> | D | 6,000 | 3 partners a , b , c start a business . twice a β s capital is equal to thrice b β s capital and b β s capital is 4 times c β s capital . out of a total profit of rs . 16500 at the end of the year , b β share is : | {
"A": "2000",
"B": "4000",
"C": "5000",
"D": "6000",
"E": "none"
} | divide(16500, add(add(divide(const_3, const_2), const_1), divide(const_1, 4))) | divide(const_3,const_2)|divide(const_1,n1)|add(#0,const_1)|add(#2,#1)|divide(n2,#3) | sol . let c = x . then , b = 4 x and 2 a = 3 * 4 x = 12 x or a = 6 x . β΄ a : b : c = 6 x : 4 x : x = 6 : 4 : 1 . so , b β s capital = rs . [ 16500 * 4 / 11 ] = rs . 6000 . answer d | general |
math_qa__cjY4kpsEcA5iq0yU | A certain college's enrollment at the beginning of 1992 was 20 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 25 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ?
Choose the correct answer: A) 47.5 % B) 44 % C) 50 % D) 35 % E) 38 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">120 * (5/4)</gadget>
<output>150</output>
<gadget id="calculator">150 - 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | A certain college's enrollment at the beginning of 1992 was 20 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 25 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ? | {
"A": "47.5 %",
"B": "44 %",
"C": "50 %",
"D": "35 %",
"E": "38 %"
} | subtract(multiply(add(const_100, 20), divide(add(const_100, 25), const_100)), const_100) | add(n1,const_100)|add(n4,const_100)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,const_100) | suppose enrollment in 1991 was 100 then enrollment in 1992 will be 120 and enrollment in 1993 will be 120 * 1.25 = 150 increase in 1993 from 1991 = 150 - 100 = 50 answer : c | gain |
math_qa__EWKbEujJoyF2lR8s | By selling 10 pencils for a rupee a man loses 15%. How many for a rupee should he sell in order to gain 15%? Choices: A) 8.39 B) 6.39 C) 7.39 D) 9.39 E) 2.39 | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">1 / 85</gadget>
<output>1/85 = around 0.011765</output>
<gadget id="calculator">115 * (1/85)</gadget>
<output>23/17 = around 1.352941</output>
<gadget id="calculator">1 / (23/17)</gadget>
<output>17/23 = around 0.73913</output>
<gadget id="calculator">(17/23) * 10</gadget>
<output>170/23 = around 7.391304</output>
<result>C</result> | C | 7.39 | By selling 10 pencils for a rupee a man loses 15%. How many for a rupee should he sell in order to gain 15%? | {
"A": "8.39",
"B": "6.39",
"C": "7.39",
"D": "9.39",
"E": "2.39"
} | multiply(divide(const_1, multiply(add(const_100, 15), divide(const_1, subtract(const_100, 15)))), 10) | add(n2,const_100)|subtract(const_100,n1)|divide(const_1,#1)|multiply(#0,#2)|divide(const_1,#3)|multiply(n0,#4)| | 85 % - - - 10 115 % - - - ? 85 / 115 * 10 = 7.39 answer : c | gain |
math_qa__3m9ujtw9i88a2XC0 | A trader bought a car at 20% discount on its original price. He sold it at a 100% increase on the price he bought it. What percent of profit did he make on the original price? Choose the correct choice from the following answers.
A) 18 % B) 13 % C) 60 % D) 40 % E) 15 % | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">100 + 100</gadget>
<output>200</output>
<gadget id="calculator">80 * 200</gadget>
<output>16_000</output>
<gadget id="calculator">16_000 / 100</gadget>
<output>160</output>
<gadget id="calculator">160 / 100</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(8/5) - 1</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>C</result> | C | 60 | A trader bought a car at 20% discount on its original price. He sold it at a 100% increase on the price he bought it. What percent of profit did he make on the original price? | {
"A": "18 %",
"B": "13 %",
"C": "60 %",
"D": "40 %",
"E": "15 %"
} | multiply(subtract(divide(divide(multiply(subtract(const_100, 20), add(const_100, 100)), const_100), const_100), const_1), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,const_1)|multiply(#5,const_100)| | "original price = 100 cp = 80 s = 80 * ( 200 / 100 ) = 160 100 - 160 = 60 % answer : c" | gain |
math_qa__VkEKSI2tDNwEF2He | If a motorist had driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 70 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 2 hours longer and at an average rate of 10 miles per hour faster on that day? Choose the correct option
A) 100 B) 120 C) 140 D) 150 miles E) 160 | <gadget id="calculator">70 - 5</gadget>
<output>65</output>
<gadget id="calculator">65 * 2</gadget>
<output>130</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">130 + 20</gadget>
<output>150</output>
<result>D</result> | D | 150 | If a motorist had driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 70 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 2 hours longer and at an average rate of 10 miles per hour faster on that day? | {
"A": "100",
"B": "120",
"C": "140",
"D": "150 miles",
"E": "160"
} | add(multiply(subtract(70, 5), 2), multiply(2, 10)) | multiply(n3,n4)|subtract(n2,n1)|multiply(n3,#1)|add(#2,#0) | let v and t be initial parameter vt = d from the stem ( t + 1 ) ( v + 5 ) = 70 + d = > v + 5 t = 65 - - - - - - - 1 ) we need the additional distance traveled second time at v + 10 and t + 2 ( t + 2 ) ( v + 10 ) = vt + 2 v + 10 t + 20 but vt = d hence d + 2 ( v + 5 t ) + 20 but v + 5 t = 65 hence the additional distance traveled is 2 ( v + 5 t ) + 20 = 2 * 65 + 20 = 130 + 20 = 150 d | physics |
math_qa__WE46ELDbUHOnKCJe | A glass was filled with 40 ounces of water, and 0.01 ounce of the water evaporated each day during a 20-day period. What percent of the original amount of water evaporated during this period? Choose the correct choice from the following answers:
A) 0.005 %
B) 0.02 %
C) 0.5 %
D) 5 %
E) 20 % | <gadget id="calculator">0.01 * 20</gadget>
<output>0.2</output>
<gadget id="calculator">0.2 / 40</gadget>
<output>0.005</output>
<gadget id="calculator">0.005 * 100</gadget>
<output>0.5</output>
<result>C</result> | C | 0.5 | A glass was filled with 40 ounces of water, and 0.01 ounce of the water evaporated each day during a 20-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.005 %",
"B": "0.02 %",
"C": "0.5 %",
"D": "5 %",
"E": "20 %"
} | multiply(divide(multiply(0.01, 20), 40), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "we are given that 0.01 ounces of water evaporated each day . furthermore , we know that this process happened over a 20 - day period . to calculate the total amount of water that evaporated during this time frame we need to multiply 0.01 by 20 . this gives us : 0.01 x 20 = 0.2 ounces finally , we are asked for β what percent β of the original amount of water evaporated during this period . to determine this percentage , we have to make sure we translate the expression correctly . we can translate it to : ( amount evaporated / original amount ) x 100 % ( 0.2 / 40 ) x 100 % = 0.5 % answer c" | gain |
math_qa__CWBHR7yzDGwprMtU | Mike and his friend are going on a road trip and hoping to miss traffic. If they are driving at a rate of 6 miles per minute, what is their speed in kilometers per hour? [1km = 0.6 miles]
Choose the most appropriate option.
A) 60
B) 30
C) 300
D) 600
E) none of the above | <gadget id="calculator">6 * 60</gadget>
<output>360</output>
<gadget id="calculator">360 / 0.6</gadget>
<output>600</output>
<result>D</result> | D | 600 | Mike and his friend are going on a road trip and hoping to miss traffic. If they are driving at a rate of 6 miles per minute, what is their speed in kilometers per hour? [1km = 0.6 miles] | {
"A": "60",
"B": "30",
"C": "300",
"D": "600",
"E": "none of the above"
} | divide(multiply(6, const_60), 0.6) | multiply(n0,const_60)|divide(#0,n2) | to calculate the equivalent of kilometres in a mile 6 miles = 6 * ( 0.6 ) ^ - 1 = 10 kilometres in 1 hour there are 60 minutes speed in kmph = 10 * 60 = 600 correct answer - d | physics |
math_qa__58192O71NypYJC67 | The average weight of 10 students decreases by 6 kg when one of them weighing 120 kg is replaced by a new student. The weight of the student is Pick
A) 62 kg B) 60 kg C) 70 kg D) 72 kg E) none of these | <gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">120 - 60</gadget>
<output>60</output>
<result>B</result> | B | 60 | The average weight of 10 students decreases by 6 kg when one of them weighing 120 kg is replaced by a new student. The weight of the student is | {
"A": "62 kg",
"B": "60 kg",
"C": "70 kg",
"D": "72 kg",
"E": "none of these"
} | subtract(120, multiply(10, 6)) | multiply(n0,n1)|subtract(n2,#0)| | "explanation : let the weight of student be x kg . given , difference in average weight = 6 kg = > ( 120 - x ) / 10 = 6 = > x = 60 answer : b" | general |
math_qa__oWMRSNapzFwSLN3z | The length of a rectangular landscape is 4times its breadth. There is a playground in it whose area is 1200 square mtr & which is 1/3rd of the total landscape. What is the length of the landscape? Choose the correct choice from the following choices.
A) 90 B) 100 C) 120 D) 130 E) 140 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 * 10</gadget>
<output>120</output>
<result>C</result> | C | 120 | The length of a rectangular landscape is 4times its breadth. There is a playground in it whose area is 1200 square mtr & which is 1/3rd of the total landscape. What is the length of the landscape? | {
"A": "90",
"B": "100",
"C": "120",
"D": "130",
"E": "140"
} | multiply(multiply(4, 3), const_10) | multiply(n0,n3)|multiply(#0,const_10) | sol . x * 4 x = 3 * 1200 x = 30 length = 4 * 30 = 120 c | geometry |
math_qa__VSjqOE6HHvU2E8vy | Each week, Harry is paid x dollars per hour for the first 30 hours and 2x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ? Select.
A) 35 B) 36 C) 37 D) 38 E) 39 | <gadget id="calculator">40 + 2</gadget>
<output>42</output>
<gadget id="calculator">42 - 30</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 30</gadget>
<output>36</output>
<result>B</result> | B | 36 | Each week, Harry is paid x dollars per hour for the first 30 hours and 2x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ? | {
"A": "35",
"B": "36",
"C": "37",
"D": "38",
"E": "39"
} | add(divide(subtract(add(40, 2), 30), 2), 30) | add(n2,n3)|subtract(#0,n0)|divide(#1,n1)|add(n0,#2)| | "james worked for 41 hours hence he earned 40 * x + 1 * 2 x = 42 x dollars ; we know that harry also earned the same 42 x dollars , out of which he earned 30 x dollars for thefirst 30 hoursplus 12 x additional dollars . since for each additional hour he gets 2 x dollars then he worked for 12 x / 2 x = 6 additional hours , so harry worked for total of 30 + 6 = 36 hours . answer : b ." | general |
math_qa__0NoxVEI01zl5sNRu | the sum of 3 numbers is 98 . the ratio of the first to the second is 2 / 3 , and the ratio of the second to the third is 5 / 8 . the second number is :
Choose the correct choice from the following choices
A) 20 B) 30 C) 60 D) 70 E) 10 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">98 * 15</gadget>
<output>1_470</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">25 + 24</gadget>
<output>49</output>
<gadget id="calculator">1_470 / 49</gadget>
<output>30</output>
<result>B</result> | B | 30 | the sum of 3 numbers is 98 . the ratio of the first to the second is 2 / 3 , and the ratio of the second to the third is 5 / 8 . the second number is : | {
"A": "20",
"B": "30",
"C": "60",
"D": "70",
"E": "10"
} | divide(multiply(98, multiply(3, 5)), add(add(multiply(3, 5), multiply(2, 5)), multiply(8, 3))) | multiply(n0,n4)|multiply(n2,n4)|multiply(n0,n5)|add(#0,#1)|multiply(n1,#0)|add(#3,#2)|divide(#4,#5) | b 30 let the three numbers be x , y and z . sum of the numbers is 98 . x + y + z = 98 β¦ β¦ β¦ β¦ β¦ β¦ ( i ) the ratio of the first to the second is 2 / 3 . x / y = 2 / 3 . x = 2 / 3 Γ y . x = 2 y / 3 . the ratio of the second to the third is 5 / 8 . y / z = 5 / 8 . z / y = 8 / 5 . z = 8 / 5 Γ y . z = 8 y / 5 . put the value of x = 2 y / 3 and z = 8 y / 5 in ( i ) . 2 y / 3 + y + 8 y / 5 = 98 49 y / 15 = 98 . 49 y = 98 Γ 15 . 49 y = 1470 . y = 1470 / 49 . y = 30 . therefore , the second number is 30 . | general |
math_qa__nZLDLpainPpFdvWh | A trader sold an article on a certain price with 20% profit. If he sold double of previous selling price then find its profit % Choose one
A) 140 % B) 120 % C) 100 % D) 90 % E) 80 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">2 * 120</gadget>
<output>240</output>
<gadget id="calculator">240 - 100</gadget>
<output>140</output>
<result>A</result> | A | 140 | A trader sold an article on a certain price with 20% profit. If he sold double of previous selling price then find its profit % | {
"A": "140 %",
"B": "120 %",
"C": "100 %",
"D": "90 %",
"E": "80 %"
} | subtract(multiply(const_2, add(const_100, 20)), const_100) | add(n0,const_100)|multiply(#0,const_2)|subtract(#1,const_100) | let cost price = 100 % selling price = 120 % new s . p . = 240 % p % = 240 - 100 = 140 % answer is a | gain |
math_qa__PC1dpMApSYNzlWow | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 57 kmph, find the speed of the stream?
Choose the most appropriate option.
A) 15 B) 17 C) 19 D) 18 E) 16 | <gadget id="calculator">57 * 2</gadget>
<output>114</output>
<gadget id="calculator">114 / 3</gadget>
<output>38</output>
<gadget id="calculator">57 - 38</gadget>
<output>19</output>
<result>C</result> | C | 19 | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 57 kmph, find the speed of the stream? | {
"A": "15",
"B": "17",
"C": "19",
"D": "18",
"E": "16"
} | subtract(57, divide(multiply(57, const_2), const_3)) | multiply(n0,const_2)|divide(#0,const_3)|subtract(n0,#1)| | "the ratio of the times taken is 2 : 1 . the ratio of the speed of the boat in still water to the speed of the stream = ( 2 + 1 ) / ( 2 - 1 ) = 3 / 1 = 3 : 1 speed of the stream = 57 / 3 = 19 kmph . answer : c" | physics |
math_qa__kYvPuLRMVhD77En8 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 650 grams per kg, what is his percent? Select
A) 15 % B) 25 % C) 65 % D) 53.8 % E) 35 % | <gadget id="calculator">100 / 650</gadget>
<output>2/13 = around 0.153846</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">(2/13) * 1_000</gadget>
<output>2_000/13 = around 153.846154</output>
<gadget id="calculator">(2_000/13) - 100</gadget>
<output>700/13 = around 53.846154</output>
<result>D</result> | D | 53.8 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 650 grams per kg, what is his percent? | {
"A": "15 %",
"B": "25 %",
"C": "65 %",
"D": "53.8 %",
"E": "35 %"
} | subtract(multiply(divide(const_100, 650), multiply(const_100, multiply(add(const_3, const_2), const_2))), const_100) | add(const_2,const_3)|divide(const_100,n0)|multiply(#0,const_2)|multiply(#2,const_100)|multiply(#1,#3)|subtract(#4,const_100)| | "explanation : 650 - - - 350 100 - - - ? = > 53.8 % answer : d" | gain |
math_qa__IbFyh0xAClAu2uiP | What is the remainder when (55)(57) is divided by 7?
Choices:
A) 1 B) 2 C) 3 D) 5 E) 6 | <gadget id="calculator">57 * 55</gadget>
<output>3_135</output>
<gadget id="calculator">3_135 % 7</gadget>
<output>6</output>
<result>E</result> | E | 6 | What is the remainder when (55)(57) is divided by 7? | {
"A": "1",
"B": "2",
"C": "3",
"D": "5",
"E": "6"
} | reminder(multiply(57, 55), 7) | multiply(n0,n1)|reminder(#0,n2)| | "( 55 ) ( 57 ) = ( 56 - 1 ) ( 56 + 1 ) = 56 ^ 2 - 1 which is 1 less than a multiple of 7 . then the remainder will be 6 . the answer is e ." | general |
math_qa__orN9uZFDmPum5h4X | The ratio, by volume, of bleach to detergent to water in a certain solution is 2 : 40 : 100. The solution will be altered so that the ratio of bleach to detergent is tripled while the ratio of detergent to water is halved. If the altered solution will contain 200 liters of water, how many liters of detergent will it contain? Choose the correct choice from the following options: A) 60 B) 55 C) 50 D) 45 E) 40 | <gadget id="calculator">200 / 100</gadget>
<output>2</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">2 * 20</gadget>
<output>40</output>
<result>E</result> | E | 40 | The ratio, by volume, of bleach to detergent to water in a certain solution is 2 : 40 : 100. The solution will be altered so that the ratio of bleach to detergent is tripled while the ratio of detergent to water is halved. If the altered solution will contain 200 liters of water, how many liters of detergent will it contain? | {
"A": "60",
"B": "55",
"C": "50",
"D": "45",
"E": "40"
} | multiply(divide(200, 100), divide(40, const_2)) | divide(n3,n2)|divide(n1,const_2)|multiply(#0,#1)| | "b : d : w = 2 : 40 : 100 bnew / dnew = ( 1 / 3 ) * ( 2 / 40 ) = ( 1 / 60 ) dnew / wnew = ( 1 / 2 ) * ( 40 / 100 ) = ( 1 / 5 ) wnew = 200 dnew = wnew / 5 = 200 / 5 = 40 so , answer will be e" | other |
math_qa__YFuOoRbh7hV0QAHb | A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is Choose the correct choice:
A) rs . 258 B) rs . 358 C) rs . 458 D) rs . 558 E) none of these | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">25 * 12</gadget>
<output>300</output>
<gadget id="calculator">25 * 6</gadget>
<output>150</output>
<gadget id="calculator">2 * 150</gadget>
<output>300</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<gadget id="calculator">72 * 2</gadget>
<output>144</output>
<gadget id="calculator">300 + 144</gadget>
<output>444</output>
<gadget id="calculator">300 + 444</gadget>
<output>744</output>
<gadget id="calculator">(3/4) * 744</gadget>
<output>558</output>
<result>D</result> | D | 558 | A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is | {
"A": "rs . 258",
"B": "rs . 358",
"C": "rs . 458",
"D": "rs . 558",
"E": "none of these"
} | multiply(divide(75, const_100), add(multiply(25, 12), add(multiply(const_2, multiply(25, 6)), multiply(multiply(12, 6), const_2)))) | divide(n3,const_100)|multiply(n0,n2)|multiply(n1,n2)|multiply(n0,n1)|multiply(#1,const_2)|multiply(#2,const_2)|add(#4,#5)|add(#6,#3)|multiply(#7,#0)| | "explanation : area to be plastered = [ 2 ( l + b ) Γ h ] + ( l Γ b ) = [ 2 ( 25 + 12 ) Γ 6 ] + ( 25 Γ 12 ) = 744 sq m cost of plastering = 744 Γ ( 75 / 100 ) = rs . 558 answer : d" | physics |
math_qa__5zhhkygnUUoTYTOK | It takes printer A 4 more minutes more than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. How long will it take Printer A to print 140 pages? Choose the correct choice from the following answers:
A) 12 B) 18 C) 20 D) 42 E) 30 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">140 * 12</gadget>
<output>1_680</output>
<gadget id="calculator">1_680 / 40</gadget>
<output>42</output>
<result>D</result> | D | 42 | It takes printer A 4 more minutes more than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. How long will it take Printer A to print 140 pages? | {
"A": "12",
"B": "18",
"C": "20",
"D": "42",
"E": "30"
} | divide(multiply(140, add(multiply(4, const_2), 4)), 40) | multiply(n0,const_2)|add(n0,#0)|multiply(n4,#1)|divide(#2,n1)| | "if it takes 4 more minutes for a to print 40 pages than it takes b , it takes 5 more minutes for a to print 50 pages than it takes b . thus if b is the number of minutes than b takes to print 50 pages , we can write : 1 / b + 1 / ( b + 5 ) = 1 / 6 ( since in 1 minute , they print 1 / 6 th of the 50 page job ) 6 ( 2 b + 5 ) = b ( b + 5 ) b ^ 2 - 7 b - 30 = 0 ( b - 10 ) ( b + 3 ) = 0 b = 10 thus it takes a 15 minutes to print 50 pages and 15 * 140 / 50 = 42 minutes to print 140 pages ( answer d )" | physics |
math_qa__anCtKcq2sxHtztI9 | There is a total of 100 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/4 and the probability that it will be green is 1/5. What is the probability that the marble will be either red or blue? Select the correct option.
A) 2 / 3 B) 3 / 5 C) 7 / 10 D) 9 / 20 E) 11 / 20 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/4) + (1/5)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">1 - (9/20)</gadget>
<output>11/20 = around 0.55</output>
<result>E</result> | E | 0.55 | There is a total of 100 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/4 and the probability that it will be green is 1/5. What is the probability that the marble will be either red or blue? | {
"A": "2 / 3",
"B": "3 / 5",
"C": "7 / 10",
"D": "9 / 20",
"E": "11 / 20"
} | subtract(1, add(divide(1, 4), divide(1, 5))) | divide(n1,n2)|divide(n3,n4)|add(#0,#1)|subtract(n1,#2)| | "p ( red or blue ) = 1 - p ( white ) - p ( green ) = 20 / 20 - 5 / 20 - 4 / 20 = 11 / 20 the answer is e ." | general |
math_qa__2UfT1arY1rtB8peY | You and your friend spent a total of $11 for lunch. Your friend spent $3 more than you. How much did your friend spend on their lunch? Pick one.
A) $ 9 B) $ 3 C) $ 7 D) $ 6 E) $ 5 | <gadget id="calculator">11 - 3</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<result>C</result> | C | 7 | You and your friend spent a total of $11 for lunch. Your friend spent $3 more than you. How much did your friend spend on their lunch? | {
"A": "$ 9",
"B": "$ 3",
"C": "$ 7",
"D": "$ 6",
"E": "$ 5"
} | add(divide(subtract(11, 3), const_2), 3) | subtract(n0,n1)|divide(#0,const_2)|add(n1,#1)| | "my lunch = l , my friends lunch = l + 1 ( l ) + ( l + 3 ) = 11 l + l + 3 - 3 = 11 - 3 2 l = 8 l = 4 my friends lunch l + 3 = 4 + 3 = $ 7 , the answer is c" | general |
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