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math_qa__DnwMdAIoJvQNsZQM | A towel, when bleached, lost 30% of its length and 40% of its breadth. What is the percentage decrease in area? Choose the correct choice from the following answers: A) 24 % B) 30 % C) 44 % D) 58 % E) 64 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">70 * 60</gadget>
<output>4_200</output>
<gadget id="calculator">10_000 - 4_200</gadget>
<output>5_800</output>
<gadget id="calculator">5_800 / 100</gadget>
<output>58</output>
<result>D</result> | D | 58 | A towel, when bleached, lost 30% of its length and 40% of its breadth. What is the percentage decrease in area? | {
"A": "24 %",
"B": "30 %",
"C": "44 %",
"D": "58 %",
"E": "64 %"
} | divide(subtract(multiply(const_100, const_100), multiply(subtract(const_100, 30), subtract(const_100, 40))), const_100) | multiply(const_100,const_100)|subtract(const_100,n0)|subtract(const_100,n1)|multiply(#1,#2)|subtract(#0,#3)|divide(#4,const_100)| | "percentage change in area = ( − 30 − 40 + ( 30 × 40 ) / 100 ) % = − 58 % i . e . , area is decreased by 58 % answer : d" | gain |
math_qa__s2TMK3gg9tdUrhwK | In order to obtain an income of Rs. 3800 from 70% stock at Rs. 280, one must make an investment of Choose the correct choice from the following answers
A) rs . 16000 B) rs . 15000 C) rs . 15250 D) rs . 15200 E) rs . 15300 | <gadget id="calculator">280 / 70</gadget>
<output>4</output>
<gadget id="calculator">4 * 3_800</gadget>
<output>15_200</output>
<result>D</result> | D | 15,200 | In order to obtain an income of Rs. 3800 from 70% stock at Rs. 280, one must make an investment of | {
"A": "rs . 16000",
"B": "rs . 15000",
"C": "rs . 15250",
"D": "rs . 15200",
"E": "rs . 15300"
} | multiply(divide(280, 70), 3800) | divide(n2,n1)|multiply(n0,#0)| | "explanation : market value = rs . 280 required income = rs . 3800 . here face value is not given . take face value as rs . 100 if it is not given in the question to obtain rs . 70 ( ie , 70 % of the face value 100 ) , investment = rs . 280 to obtain rs . 3800 , investment = 280 / 70 ã — 3800 = rs . 15200 answer : option d" | gain |
math_qa__ZSTmviuv2kvtZsqH | A train 300 m long can cross an electric pole in 15 sec and then find the speed of the train? Choices
A) 65 kmph B) 70 kmph C) 72 kmph D) 75 kmph E) 78 kmph | <gadget id="calculator">300 / 1_000</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">15 / 3_600</gadget>
<output>1/240 = around 0.004167</output>
<gadget id="calculator">(3/10) / (1/240)</gadget>
<output>72</output>
<result>C</result> | C | 72 | A train 300 m long can cross an electric pole in 15 sec and then find the speed of the train? | {
"A": "65 kmph",
"B": "70 kmph",
"C": "72 kmph",
"D": "75 kmph",
"E": "78 kmph"
} | divide(divide(300, const_1000), divide(15, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 300 / 15 s = 20 m / sec speed = 20 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 72 kmph answer : c" | physics |
math_qa__QJwf6AzX0TKOTryq | A pipe can empty 2/3rd of a cistern in 12mins. In 5 mins, what part of the cistern will be empty? Choose the correct choice:
A) 2 / 3 B) 5 / 18 C) 4 / 9 D) 3 / 8 E) 4 / 7 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 5</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(10/3) / 12</gadget>
<output>5/18 = around 0.277778</output>
<result>B</result> | B | 0.277778 | A pipe can empty 2/3rd of a cistern in 12mins. In 5 mins, what part of the cistern will be empty? | {
"A": "2 / 3",
"B": "5 / 18",
"C": "4 / 9",
"D": "3 / 8",
"E": "4 / 7"
} | divide(multiply(divide(2, 3), 5), 12) | divide(n0,n1)|multiply(n3,#0)|divide(#1,n2) | 2 / 3 - - - - 12 ? - - - - - 5 = = > 5 / 18 b | physics |
math_qa__JvwnTxaPuC4d2L7x | Find the surface area of a10cm x 4cm x 3cm brick Choose the correct option:
A) 84
B) 124
C) 164
D) 180
E) 120 | <gadget id="calculator">2 * (3 * 4 + 4 * 10 + 3 * 10)</gadget>
<output>164</output>
<result>C</result> | C | 164 | Find the surface area of a10cm x 4cm x 3cm brick | {
"A": "84",
"B": "124",
"C": "164",
"D": "180",
"E": "120"
} | surface_rectangular_prism(3, 4, 10) | surface_rectangular_prism(n0,n1,n2)| | "explanation : surface area = [ 2 ( 10 x 4 + 4 x 3 + 10 x 3 ) ] cm 2 = 164 cm 2 answer : c" | geometry |
math_qa__QMKhjMVm1VOtUjGF | If john makes a contribution to a charity fund at school, the average contribution size will increase by 50% reaching $75 per person. If there were 6 other contributions made before john's, what is the size of his donation? Options.
A) $ 225 B) $ 150 C) $ 200 D) $ 250 E) $ 450 | <gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 * 75</gadget>
<output>525</output>
<gadget id="calculator">7 * 50</gadget>
<output>350</output>
<gadget id="calculator">525 - 350</gadget>
<output>175</output>
<gadget id="calculator">175 + 50</gadget>
<output>225</output>
<result>A</result> | A | 225 | If john makes a contribution to a charity fund at school, the average contribution size will increase by 50% reaching $75 per person. If there were 6 other contributions made before john's, what is the size of his donation? | {
"A": "$ 225",
"B": "$ 150",
"C": "$ 200",
"D": "$ 250",
"E": "$ 450"
} | add(subtract(multiply(add(6, const_1), 75), multiply(add(6, const_1), 50)), 50) | add(n2,const_1)|multiply(n1,#0)|multiply(n0,#0)|subtract(#1,#2)|add(n0,#3)| | "cavg = average contribution before john cavg * 1.5 = 75 , therefore the average cont is $ 50 before john . if he needs to increase the average contribution by $ 25 , he must put in $ 25 for each of the 6 people . so $ 150 . but , he also has to put in the average for himself ( the seventh person ) , so add $ 75 . so $ 225 is your answer . answer a" | general |
math_qa__ji2rZJMqtPN1bf2V | A box measuring 35 inches long by 20 inches wide by 10 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective?
Choose the correct choice from the following answers:
A) 17
B) 18
C) 54
D) 56
E) 864 | <gadget id="calculator">35 * 20</gadget>
<output>700</output>
<gadget id="calculator">700 * 10</gadget>
<output>7_000</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<gadget id="calculator">7_000 / 125</gadget>
<output>56</output>
<result>D</result> | D | 56 | A box measuring 35 inches long by 20 inches wide by 10 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective? | {
"A": "17",
"B": "18",
"C": "54",
"D": "56",
"E": "864"
} | divide(multiply(multiply(35, 20), 10), volume_cube(divide(10, const_2))) | divide(n2,const_2)|multiply(n0,n1)|multiply(n2,#1)|volume_cube(#0)|divide(#2,#3)| | "least number of cubes will be required when the cubes that could fit in are biggest . 5 is the biggest number that could divide all three , 35 , 20 and 10 . thus side of cube must be 5 , and total number of cubes = 35 / 5 * 20 / 5 * 10 / 5 = 56 ans d it is ." | geometry |
math_qa__0CPtAyoOwPesCrn9 | If P represents the product of the first 14 positive integers, then P is not a
multiple of: Choose the correct choice from the following choices.
A) 99 B) 84 C) 51 D) 65 E) 57 | <gadget id="calculator">14 + 3</gadget>
<output>17</output>
<gadget id="calculator">17 * 3</gadget>
<output>51</output>
<result>C</result> | C | 51 | If P represents the product of the first 14 positive integers, then P is not a
multiple of: | {
"A": "99",
"B": "84",
"C": "51",
"D": "65",
"E": "57"
} | multiply(add(14, const_3), const_3) | add(n0,const_3)|multiply(#0,const_3) | a ) 99 = 9 * 11 b ) 84 = 4 * 7 * 3 c ) 51 = 17 * 3 d ) 65 = 5 * 13 e ) 57 = 19 * 3 since 17 is not there in first 15 positive numbers it is the only possibility c | general |
math_qa__0EHs91hw8ocFlREB | The average weight of 10 girls increases by 5 kg when a new girl comes in place of one of them weighing 50 kg. What might be the weight of the new girl? Choose the correct choice from the following answers
A) 90 kg B) 100 kg C) 95 kg D) 85 kg E) 92 kg | <gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">50 + 50</gadget>
<output>100</output>
<result>B</result> | B | 100 | The average weight of 10 girls increases by 5 kg when a new girl comes in place of one of them weighing 50 kg. What might be the weight of the new girl? | {
"A": "90 kg",
"B": "100 kg",
"C": "95 kg",
"D": "85 kg",
"E": "92 kg"
} | add(multiply(10, 5), 50) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = 10 x 5 kg = 50 kg . weight of new person = 50 + 50 kg = 100 kg answer : b" | general |
math_qa__IsLKT4S883V46KOc | On dividing 144 by a number, the quotient is 13 and the remainder is 1. Find the divisor. Choose the correct choice from the following answers
A) 11 B) 14 C) 16 D) 18 E) 22 | <gadget id="calculator">144 / 13</gadget>
<output>144/13 = around 11.076923</output>
<gadget id="calculator">floor(144/13)</gadget>
<output>11</output>
<result>A</result> | A | 11 | On dividing 144 by a number, the quotient is 13 and the remainder is 1. Find the divisor. | {
"A": "11",
"B": "14",
"C": "16",
"D": "18",
"E": "22"
} | floor(divide(144, 13)) | divide(n0,n1)|floor(#0)| | "d = ( d - r ) / q = ( 144 - 1 ) / 13 = 143 / 13 = 11 a )" | general |
math_qa__3WAmNQbjAGqCzufF | A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1100. How many workers were part of the latter production run? Answers.
A) 26 B) 10 C) 11 D) 15 E) 23.5 | <gadget id="calculator">20 + 5</gadget>
<output>25</output>
<result>A</result> | A | 26 | A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1100. How many workers were part of the latter production run? | {
"A": "26",
"B": "10",
"C": "11",
"D": "15",
"E": "23.5"
} | add(20, 5) | add(n0,n1) | the daily average production is given by 5 n + 20 - given in the first k days , 500 units are produced = ( 5 n + 20 ) k = 500 k = 500 / 5 n + 20 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 5 workers were added = 5 ( n + 5 ) + 20 = 5 n + 45 cumulative is 1100 . . thus for the current period = 1100 - 500 = 600 ( 5 n + 45 ) k = 600 k = 600 / 5 n + 45 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 equate 1 and 2 500 / 5 n + 20 = 600 / 5 n + 45 500 ( 5 n + 45 ) = 600 ( 5 n + 20 ) 2500 n + 22500 = 3000 n + 12000 - 500 n = - 10500 n = 21 thus n + 5 = 26 hence a | general |
math_qa__MtGN82getv61oi4c | Find the area of a parallelogram with base 24 cm and height 16 cm? Pick one.
A) 298 cm 2 B) 384 cm 2 C) 279 cm 2 D) 297 cm 2 E) 278 cm 2 | <gadget id="calculator">24 * 16</gadget>
<output>384</output>
<result>B</result> | B | 384 | Find the area of a parallelogram with base 24 cm and height 16 cm? | {
"A": "298 cm 2",
"B": "384 cm 2",
"C": "279 cm 2",
"D": "297 cm 2",
"E": "278 cm 2"
} | multiply(24, 16) | multiply(n0,n1)| | "area of a parallelogram = base * height = 24 * 16 = 384 cm 2 answer : b" | geometry |
math_qa__VIpZfpKeZC4CXnNF | The principal that amounts to Rs. 4893 in 3 years at 6 1/4 % per annum C.I. compounded annually, is? Choose the correct choice from the following answers: A) s . 3096 B) s . 4076 C) s . 4085 D) s . 4096 E) s . 5096 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">6 + (1/4)</gadget>
<output>25/4 = around 6.25</output>
<gadget id="calculator">(25/4) / 100</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">1 + (1/16)</gadget>
<output>17/16 = around 1.0625</output>
<gadget id="calculator">(17/16) ** 3</gadget>
<output>4_913/4_096 = around 1.199463</output>
<gadget id="calculator">4_893 / (4_913/4_096)</gadget>
<output>20_041_728/4_913 = around 4_079.32587</output>
<result>C</result> | C | 4,085 | The principal that amounts to Rs. 4893 in 3 years at 6 1/4 % per annum C.I. compounded annually, is? | {
"A": "s . 3096",
"B": "s . 4076",
"C": "s . 4085",
"D": "s . 4096",
"E": "s . 5096"
} | divide(4893, power(add(const_1, divide(add(6, divide(1, 4)), const_100)), 3)) | divide(n3,n4)|add(n2,#0)|divide(#1,const_100)|add(#2,const_1)|power(#3,n1)|divide(n0,#4) | principal = [ 4913 / ( 1 + 25 / ( 4 * 100 ) ) 3 ] = 4893 * 16 / 17 * 16 / 17 * 16 / 17 = rs . 4085 . answer : c | gain |
math_qa__nQjtwnJXksOTqtV7 | An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 25 times the difference between the two numbers. How many coins did the old man have?
Choose the correct choice from the following
A) 24 B) 26 C) 30 D) 25 E) 40 | <gadget id="calculator">floor(25)</gadget>
<output>25</output>
<result>D</result> | D | 25 | An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 25 times the difference between the two numbers. How many coins did the old man have? | {
"A": "24",
"B": "26",
"C": "30",
"D": "25",
"E": "40"
} | floor(25) | floor(n0)| | "let the number of coins one son got be x and the number of coins another got be y . total = x + y . x ^ 2 - y ^ 2 = 25 ( x - y ) - - > x + y = 25 . answer : d ." | general |
math_qa__1uwPpXNC9qNNUQAr | Two trains are moving in opposite directions @100kmph and 120kmph. Their length are 500m and 700m. The time taken by the slower train to cross faster train in second is? Pick one
A) 15 sec
B) 18.3 sec
C) 19.6 sec
D) 20.4 sec
E) 22.5 sec | <gadget id="calculator">500 + 700</gadget>
<output>1_200</output>
<gadget id="calculator">100 + 120</gadget>
<output>220</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">220 * (5/18)</gadget>
<output>550/9 = around 61.111111</output>
<gadget id="calculator">1_200 / (550/9)</gadget>
<output>216/11 = around 19.636364</output>
<result>C</result> | C | 19.6 | Two trains are moving in opposite directions @100kmph and 120kmph. Their length are 500m and 700m. The time taken by the slower train to cross faster train in second is? | {
"A": "15 sec",
"B": "18.3 sec",
"C": "19.6 sec",
"D": "20.4 sec",
"E": "22.5 sec"
} | divide(add(500, 700), multiply(add(100, 120), const_0_2778)) | add(n2,n3)|add(n0,n1)|multiply(#1,const_0_2778)|divide(#0,#2) | relative speed = 100 + 120 = 220 * 5 / 18 = 550 / 9 m / s distance covered = 500 + 700 = 1200 m required time = 1200 * 9 / 550 = 19.6 sec answer is c | physics |
math_qa__4bcVJBYXqYEFRR9C | How many seconds will a 250 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? Answers
A) 12 B) 30 C) 40 D) 15 E) 60 | <gadget id="calculator">63 - 3</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">250 / (50/3)</gadget>
<output>15</output>
<result>D</result> | D | 15 | How many seconds will a 250 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? | {
"A": "12",
"B": "30",
"C": "40",
"D": "15",
"E": "60"
} | divide(250, multiply(subtract(63, 3), const_0_2778)) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 63 - 3 = 60 km / hr . = 60 * 5 / 18 = 50 / 3 m / sec . time taken to pass the man = 250 * 3 / 50 = 15 sec . answer : option d" | physics |
math_qa__X9vWd0hNOfgpdwCM | The last two-digits in the multiplication 122 × 123 × 125 × 127 × 129 will be Pick one:
A) 20
B) 50
C) 30
D) 40
E) 10 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<result>B</result> | B | 50 | The last two-digits in the multiplication 122 × 123 × 125 × 127 × 129 will be | {
"A": "20",
"B": "50",
"C": "30",
"D": "40",
"E": "10"
} | multiply(add(const_4, const_1), const_10) | add(const_1,const_4)|multiply(#0,const_10) | solution the answer will be 50 since , ( 125 × 122 ) will give 50 as the last two digits . answer b | general |
math_qa__wkXcBY0B7fNcnCW9 | Riya and Priya set on a journey. Riya moves eastward at a speed of 20kmph and Priya moves westward at a speed of 30 kmph.How far will be priya from Riya after 30 minutes
Options:
A) 25 kms B) 10 kms C) 50 kms D) 30 kms E) 40 kms | <gadget id="calculator">20 + 30</gadget>
<output>50</output>
<gadget id="calculator">50 / 60</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(5/6) * 30</gadget>
<output>25</output>
<result>A</result> | A | 25 | Riya and Priya set on a journey. Riya moves eastward at a speed of 20kmph and Priya moves westward at a speed of 30 kmph.How far will be priya from Riya after 30 minutes | {
"A": "25 kms",
"B": "10 kms",
"C": "50 kms",
"D": "30 kms",
"E": "40 kms"
} | multiply(speed(add(20, 30), const_60), 30) | add(n0,n1)|speed(#0,const_60)|multiply(n2,#1)| | "total eastward distance = 20 kmph * 1 / 2 hr = 10 km total westward distance = 30 kmph * 1 / 2 hr = 15 km total distn betn them = 10 + 15 = 25 km ans 25 km answer : a" | physics |
math_qa__IJ0hlazumk4EpXsP | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 10 sec. What is the length of the platform? Choose the correct choice from the following choices.
A) 187 m B) 350 m C) 267 m D) 287 m E) 870 m | <gadget id="calculator">300 / 10</gadget>
<output>30</output>
<gadget id="calculator">30 * 39</gadget>
<output>1_170</output>
<gadget id="calculator">1_170 - 300</gadget>
<output>870</output>
<result>E</result> | E | 870 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 10 sec. What is the length of the platform? | {
"A": "187 m",
"B": "350 m",
"C": "267 m",
"D": "287 m",
"E": "870 m"
} | subtract(multiply(speed(300, 10), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 10 = 30 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 30 = > x = 870 m . answer : e" | physics |
math_qa__3kO1XefFjt8OngPz | Running at the same constant rate, 15 identical machines can produce a total of 45 bags per minute. At this rate, how many bags could 150 such machines produce in 8 minutes?
Choose the most appropriate option: A) 9,00 B) 1,800 C) 2,700 D) 3,600 E) 4,800 | <gadget id="calculator">45 / 15</gadget>
<output>3</output>
<gadget id="calculator">3 * 8</gadget>
<output>24</output>
<gadget id="calculator">24 * 150</gadget>
<output>3_600</output>
<result>D</result> | D | 3,600 | Running at the same constant rate, 15 identical machines can produce a total of 45 bags per minute. At this rate, how many bags could 150 such machines produce in 8 minutes? | {
"A": "9,00",
"B": "1,800",
"C": "2,700",
"D": "3,600",
"E": "4,800"
} | multiply(multiply(divide(45, 15), 8), 150) | divide(n1,n0)|multiply(n3,#0)|multiply(n2,#1)| | "let ' s take the approach that uses the answer choices to eliminate wasted time . 45 / 15 = 3 bags per minute per machine . 150 machines = 450 per minute . 8 minutes worth = 3600 bags . looking at the answers it is clear . . . we can only choose ( d ) . the correct answer is d ." | gain |
math_qa__tfpaskMa8HePxJSL | A train 700 m long can cross an electric pole in 40 sec and then find the speed of the train? Pick: A) 987 B) 271 C) 72 D) 27 E) 63 | <gadget id="calculator">700 / 1_000</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">40 / 3_600</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">(7/10) / (1/90)</gadget>
<output>63</output>
<result>E</result> | E | 63 | A train 700 m long can cross an electric pole in 40 sec and then find the speed of the train? | {
"A": "987",
"B": "271",
"C": "72",
"D": "27",
"E": "63"
} | divide(divide(700, const_1000), divide(40, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 700 / 40 s = 17.5 m / sec speed = 17.5 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 63 kmph answer : e" | physics |
math_qa__P7hIpzFJBfoBHuVG | A certain music store stocks 800 cellos and 600 violas. Of these instruments, there are 100 cello-viola pairs, such that a cello and a viola were both made with wood from the same tree (each tree can make at most one viola and one cello, so there are no pairs other than these 90). If one viola and one cello are chosen at random, what is the probability that the two instruments are made with wood from the same tree? Pick one.
A) 3 / 16,000 B) 1 / 4,800 C) 3 / 1,600 D) 1 / 90 E) 2 / 45 | <gadget id="calculator">100 / 800</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 600</gadget>
<output>1/600 = around 0.001667</output>
<gadget id="calculator">(1/8) * (1/600)</gadget>
<output>1/4_800 = around 0.000208</output>
<result>B</result> | B | 0.000208 | A certain music store stocks 800 cellos and 600 violas. Of these instruments, there are 100 cello-viola pairs, such that a cello and a viola were both made with wood from the same tree (each tree can make at most one viola and one cello, so there are no pairs other than these 90). If one viola and one cello are chosen at random, what is the probability that the two instruments are made with wood from the same tree? | {
"A": "3 / 16,000",
"B": "1 / 4,800",
"C": "3 / 1,600",
"D": "1 / 90",
"E": "2 / 45"
} | multiply(divide(100, 800), divide(const_1, 600)) | divide(n2,n0)|divide(const_1,n1)|multiply(#0,#1) | solution provided by stanford 2012 is correct : 100 / 800 choosing one of the cellos which has a pair viola , 1 / 600 choosing the viola which is the pair of chosen cello - - > p = 100 / 800 * 1 / 600 = 1 / 4,800 . answer : b . | other |
math_qa__GqHNd723uRkUSacH | total 85 matches are conducted in Knockout match type. How many players will be participated in that tournament?
Choose the correct choice from the following
A) 85
B) 81
C) 53
D) 82
E) 84 | <gadget id="calculator">85 + 1</gadget>
<output>86</output>
<result>E</result> | E | 84 | total 85 matches are conducted in Knockout match type. How many players will be participated in that tournament? | {
"A": "85",
"B": "81",
"C": "53",
"D": "82",
"E": "84"
} | add(85, const_1) | add(n0,const_1) | 84 players answer : e | general |
math_qa__7QRVmyvHc9p3rxEn | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 8% p.a. in 5 years. What is the sum? Choose the correct choice from the following.
A) rs . 10060.625 B) rs . 10040.62 C) rs . 12040.62 D) rs . 20040.625 E) rs . 10030.625 | <gadget id="calculator">4_016.25 * 100</gadget>
<output>401_625</output>
<gadget id="calculator">401_625 / 8</gadget>
<output>401_625/8 = around 50_203.125</output>
<gadget id="calculator">(401_625/8) / 5</gadget>
<output>80_325/8 = around 10_040.625</output>
<result>B</result> | B | 10,040.62 | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 8% p.a. in 5 years. What is the sum? | {
"A": "rs . 10060.625",
"B": "rs . 10040.62",
"C": "rs . 12040.62",
"D": "rs . 20040.625",
"E": "rs . 10030.625"
} | divide(divide(multiply(4016.25, const_100), 8), 5) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "principal = ( 100 * 4016.25 ) / ( 8 * 5 ) = rs . 10040.625 . answer : b" | gain |
math_qa__s6r7xr8uhL4M6mIM | A woman complete a journey in 25 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
Choose the correct choice from the following answers.
A) 334 km . B) 216 km . C) 314 km . D) 224 km . E) 560 km . | <gadget id="calculator">25 * 24</gadget>
<output>600</output>
<gadget id="calculator">24 + 21</gadget>
<output>45</output>
<gadget id="calculator">600 / 45</gadget>
<output>40/3 = around 13.333333</output>
<gadget id="calculator">(40/3) * 21</gadget>
<output>280</output>
<gadget id="calculator">280 * 2</gadget>
<output>560</output>
<result>E</result> | E | 560 | A woman complete a journey in 25 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km. | {
"A": "334 km .",
"B": "216 km .",
"C": "314 km .",
"D": "224 km .",
"E": "560 km ."
} | multiply(multiply(divide(multiply(25, 24), add(24, 21)), 21), const_2) | add(n1,n2)|multiply(n0,n2)|divide(#1,#0)|multiply(n1,#2)|multiply(#3,const_2) | 0.5 x / 21 + 0.5 x / 24 = 25 - - > x / 21 + x / 24 = 50 - - > x = 560 km . e | physics |
math_qa__ixs1LWIDUDDcQB4n | Set J consists of 10 consecutive even numbers. If the smallest term in the set is -4, what is the range of the positive integers in set J? Pick one:
A) 8 B) 12 C) 14 D) 16 E) 18 | <gadget id="calculator">-2</gadget>
<output>-2</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">(-2) + 18</gadget>
<output>16</output>
<gadget id="calculator">16 - 4</gadget>
<output>12</output>
<result>B</result> | B | 12 | Set J consists of 10 consecutive even numbers. If the smallest term in the set is -4, what is the range of the positive integers in set J? | {
"A": "8",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | subtract(add(negate(const_2.0), multiply(subtract(10, const_1), const_2.0)), 4) | negate(const_2.0)|subtract(n0,const_1)|multiply(const_2.0,#1)|add(#2,#0)|subtract(#3,n1)| | "since there are only 10 integers , another approach is the just list all 10 . we get : - 4 , - 2 , 0,2 , 4 , 6 , 8 , 10 , 12 , 14 range of positive integers = 14 - 2 = 12 answer : b" | general |
math_qa__nOLAtdVWcIb1olek | A man two flats for $675958 each. On one he gains 12% while on the other he loses 12%. How much does he gain or lose in the whole transaction?
Choose one.
A) 1.44 % B) 2.56 % C) 3.12 % D) 4.65 % E) 5.12 % | <gadget id="calculator">100 + 12</gadget>
<output>112</output>
<gadget id="calculator">100 / 112</gadget>
<output>25/28 = around 0.892857</output>
<gadget id="calculator">(25/28) * 675_958</gadget>
<output>8_449_475/14 = around 603_533.928571</output>
<gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">100 / 88</gadget>
<output>25/22 = around 1.136364</output>
<gadget id="calculator">(25/22) * 675_958</gadget>
<output>8_449_475/11 = around 768_134.090909</output>
<gadget id="calculator">(8_449_475/14) + (8_449_475/11)</gadget>
<output>211_236_875/154 = around 1_371_668.019481</output>
<gadget id="calculator">675_958 + 675_958</gadget>
<output>1_351_916</output>
<gadget id="calculator">(211_236_875/154) - 1_351_916</gadget>
<output>3_041_811/154 = around 19_752.019481</output>
<gadget id="calculator">(3_041_811/154) / (211_236_875/154)</gadget>
<output>9/625 = around 0.0144</output>
<gadget id="calculator">(9/625) * 100</gadget>
<output>36/25 = around 1.44</output>
<result>A</result> | A | 1.44 | A man two flats for $675958 each. On one he gains 12% while on the other he loses 12%. How much does he gain or lose in the whole transaction? | {
"A": "1.44 %",
"B": "2.56 %",
"C": "3.12 %",
"D": "4.65 %",
"E": "5.12 %"
} | multiply(divide(subtract(add(multiply(divide(const_100, add(const_100, 12)), 675958), multiply(divide(const_100, subtract(const_100, 12)), 675958)), add(675958, 675958)), add(multiply(divide(const_100, add(const_100, 12)), 675958), multiply(divide(const_100, subtract(const_100, 12)), 675958))), const_100) | add(n1,const_100)|add(n0,n0)|subtract(const_100,n1)|divide(const_100,#0)|divide(const_100,#2)|multiply(n0,#3)|multiply(n0,#4)|add(#5,#6)|subtract(#7,#1)|divide(#8,#7)|multiply(#9,const_100)| | "in such a case there is always a loss loss % = ( 12 / 10 ) ^ 2 = 36 / 25 = 1.44 % answer is a" | gain |
math_qa__Gp2i3n0HtlQPpPWA | In a certain company, a third of the workers do not have a retirement plan. 10% of the workers who do not have a retirement plan are women, and 40% of the workers who do have a retirement plan are men. If 120 of the workers of that company are men, how many of the workers are women?
Choose the correct choice from the following options: A) 80 B) 95 C) 105 D) 120 E) 91 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/3) * (1/10)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/3) - (1/30)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/3) * (2/5)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">(3/10) + (4/15)</gadget>
<output>17/30 = around 0.566667</output>
<gadget id="calculator">120 / (17/30)</gadget>
<output>3_600/17 = around 211.764706</output>
<gadget id="calculator">(2/3) - (4/15)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/30) + (2/5)</gadget>
<output>13/30 = around 0.433333</output>
<gadget id="calculator">(3_600/17) * (13/30)</gadget>
<output>1_560/17 = around 91.764706</output>
<result>E</result> | E | 91 | In a certain company, a third of the workers do not have a retirement plan. 10% of the workers who do not have a retirement plan are women, and 40% of the workers who do have a retirement plan are men. If 120 of the workers of that company are men, how many of the workers are women? | {
"A": "80",
"B": "95",
"C": "105",
"D": "120",
"E": "91"
} | multiply(divide(120, add(subtract(divide(const_1, const_3), multiply(divide(const_1, const_3), divide(10, const_100))), multiply(subtract(const_1, divide(const_1, const_3)), divide(40, const_100)))), add(multiply(divide(const_1, const_3), divide(10, const_100)), subtract(subtract(const_1, divide(const_1, const_3)), multiply(subtract(const_1, divide(const_1, const_3)), divide(40, const_100))))) | divide(const_1,const_3)|divide(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|subtract(const_1,#0)|multiply(#2,#4)|subtract(#0,#3)|add(#5,#6)|subtract(#4,#5)|add(#3,#8)|divide(n2,#7)|multiply(#9,#10) | 20 % of the workerswithoutretirement plan are women , this means 80 % of the workerswithoutretirement plan are men right ? makes 100 % = no retirement plan . then 40 % of those wo have a retirement plan are men , which means 60 % of those who have a retirement plan are women . these percentages are always refering to the subgroupsretirement plan = yesandno retirement plan . make the total workers equal x and work from there and it should be fine > x / 3 have no retirement plan at all . i struggled with the question a lot , it was hard for me although usually i have no problems with sets questions like this . i believe it must be a 700 + question . yes , you are right . i read the question incorrectly ! i glazed overnotfor some reason . if 20 % of the workers who do not have a retirement plan are women , 80 % who do not have retirement plan are men . also 40 % who do have retirement plan are men . since 1 / 3 do not have retirement plan and 2 / 3 do have , it becomes a simple weighted average question . cavg = ( 90 * 1 + 40 * 2 ) / 3 = 170 / 3 % are men total = 120 * 300 / 170 = 211 no . of women = 211 - 120 = 91 e | gain |
math_qa__aI5fs2ka9JO0mi1N | The distance from City A to City B is 120 miles. While driving from City A to City B, Cara drives at a constant speed of 30 miles per hour. Dan leaves City A 60 minutes after Cara. What is the minimum constant speed in miles per hour that Dan must exceed in order to arrive in City B before Cara? Choose one
A) 42 B) 44 C) 46 D) 48 E) 40 | <gadget id="calculator">120 / 30</gadget>
<output>4</output>
<gadget id="calculator">60 / 60</gadget>
<output>1</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">120 / 3</gadget>
<output>40</output>
<result>E</result> | E | 40 | The distance from City A to City B is 120 miles. While driving from City A to City B, Cara drives at a constant speed of 30 miles per hour. Dan leaves City A 60 minutes after Cara. What is the minimum constant speed in miles per hour that Dan must exceed in order to arrive in City B before Cara? | {
"A": "42",
"B": "44",
"C": "46",
"D": "48",
"E": "40"
} | divide(120, subtract(divide(120, 30), divide(60, const_60))) | divide(n0,n1)|divide(n2,const_60)|subtract(#0,#1)|divide(n0,#2) | the time it takes cara to drive to city b is 120 / 30 = 4 hours . dan needs to take less than 3 hours for the trip . dan needs to exceed a constant speed of 120 / 3 = 40 miles per hour . the answer is e . | physics |
math_qa__5LeG6HjoEBaZl8hu | Jack and Christina are standing 150 feet apart on a level surface. Their dog, Lindy, is standing next to Christina. At the same time, they all begin moving toward each other. Jack walks in a straight line toward Christina at a constant speed of 7 feet per second and Christina walks in a straight line toward Jack at a constant speed of 8 feet per second. Lindy runs at a constant speed of 10 feet per second from Christina to Jack, back to Christina, back to Jack, and so forth. What is the total distance, in feet, that Lindy has traveled when the three meet at one place? Pick:
A) 40 B) 60 C) 80 D) 100 E) 120 | <gadget id="calculator">7 + 8</gadget>
<output>15</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<result>D</result> | D | 100 | Jack and Christina are standing 150 feet apart on a level surface. Their dog, Lindy, is standing next to Christina. At the same time, they all begin moving toward each other. Jack walks in a straight line toward Christina at a constant speed of 7 feet per second and Christina walks in a straight line toward Jack at a constant speed of 8 feet per second. Lindy runs at a constant speed of 10 feet per second from Christina to Jack, back to Christina, back to Jack, and so forth. What is the total distance, in feet, that Lindy has traveled when the three meet at one place? | {
"A": "40",
"B": "60",
"C": "80",
"D": "100",
"E": "120"
} | multiply(divide(150, add(7, 8)), 10) | add(n1,n2)|divide(n0,#0)|multiply(n3,#1)| | "the relative speed of jack and christina is 7 + 8 = 15 feet per second . the distance between them is 210 feet , hence they will meet in ( time ) = ( distance ) / ( relative speed ) = 150 / 15 = 10 seconds . for all this time lindy was running back and forth , so it covered ( distance ) = ( speed ) * ( time ) = 10 * 10 = 100 feet . answer : d ." | physics |
math_qa__MONJx28aESchrqjF | A man by motorcycle goes from Delhi to Bharatpur , a distance of 192 km, at an average speed of 32 kmph. Another man starts from Delhi by car 2.5 h after the motorcyclist starts and reaches Bharatpur half an hour late. What is the ratio of person on the motorcycle to the person going by car ?
Choose the correct choice from the following choices:
A) 1 : 2
B) 2 : 3
C) 10 : 27
D) 5 : 4
E) 4 : 5 | <gadget id="calculator">192 / 32</gadget>
<output>6</output>
<gadget id="calculator">6 - 2.5</gadget>
<output>3.5</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3.5 + (1/2)</gadget>
<output>4</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<result>B</result> | B | 0.666667 | A man by motorcycle goes from Delhi to Bharatpur , a distance of 192 km, at an average speed of 32 kmph. Another man starts from Delhi by car 2.5 h after the motorcyclist starts and reaches Bharatpur half an hour late. What is the ratio of person on the motorcycle to the person going by car ? | {
"A": "1 : 2",
"B": "2 : 3",
"C": "10 : 27",
"D": "5 : 4",
"E": "4 : 5"
} | divide(add(subtract(divide(192, 32), 2.5), divide(const_1, const_2)), divide(192, 32)) | divide(const_1,const_2)|divide(n0,n1)|subtract(#1,n2)|add(#0,#2)|divide(#3,#1) | a man by motorcycle goes from delhi to bharatpur the time take by the motorcyclist = 192 / 32 = 6 hours another man start from delhi be car after 2.5 hour the man starts = 6 - 2.5 = 3.5 and the man on can reaches half and hour late which is = 3.5 + . 5 = 4 thus , the ratio between motorcycle to car is 4 : 6 or , 2 : 3 . answer : b | physics |
math_qa__VwuVowEoghz7Ueiw | If p/q =4/5, then the value of 18/7 + {(2q - p) / (2q + p)} is ? Pick: A) 3 / 7 B) 34 C) 1 D) 2 E) 3 | <gadget id="calculator">18 / 7</gadget>
<output>18/7 = around 2.571429</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">2 - (4/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">2 + (4/5)</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">(6/5) / (14/5)</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(18/7) + (3/7)</gadget>
<output>3</output>
<result>E</result> | E | 3 | If p/q =4/5, then the value of 18/7 + {(2q - p) / (2q + p)} is ? | {
"A": "3 / 7",
"B": "34",
"C": "1",
"D": "2",
"E": "3"
} | add(divide(18, 7), divide(subtract(2, divide(4, 5)), add(2, divide(4, 5)))) | divide(n2,n3)|divide(n0,n1)|add(n4,#1)|subtract(n4,#1)|divide(#3,#2)|add(#0,#4)| | "answer given exp . = 18 / 7 + { ( 2 q - p ) / ( 2 q + p ) } dividing numerator as well as denominator by q , exp = 18 / 7 + { 2 - p / q ) / ( 2 + p / q ) } = 18 / 7 + { ( 2 - 4 / 5 ) / ( 2 + 4 / 5 ) } = 18 / 7 + 6 / 14 = 18 / 7 + 3 / 7 = 21 / 7 = 3 correct option : e" | general |
math_qa__32PnDcDRKFKpkbqb | A scuba diver descends at a rate of 30 feet per minute. a diver dive from a ship to search for a lost ship at the depth of 2400feet below the sea level..how long will he take to reach the ship?
Choose the correct option.
A) 70 minutes B) 72 minutes C) 80 minutes D) 76 minutes E) 77 minutes | <gadget id="calculator">2_400 / 30</gadget>
<output>80</output>
<result>C</result> | C | 80 | A scuba diver descends at a rate of 30 feet per minute. a diver dive from a ship to search for a lost ship at the depth of 2400feet below the sea level..how long will he take to reach the ship? | {
"A": "70 minutes",
"B": "72 minutes",
"C": "80 minutes",
"D": "76 minutes",
"E": "77 minutes"
} | divide(2400, 30) | divide(n1,n0)| | "time taken to reach = 2400 / 30 = 80 minutes answer : c" | gain |
math_qa__cXy9bljqR5BKCsTi | How many prime numbers are between 26/3 and 85/6? Options:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">floor(2)</gadget>
<output>2</output>
<result>B</result> | B | 2 | How many prime numbers are between 26/3 and 85/6? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | floor(const_2) | floor(const_2)| | "26 / 3 = 8 . xxx 85 / 6 = 14 . xxx so we need to find prime numbers between 8 ( exclusive ) - 13 ( inclusive ) there are 2 prime numbers 1113 hence answer will be ( b ) 2 b" | general |
math_qa__CJkxiN9rkl45YuVL | Average of 10 matches is 32, How many runs one should should score to increase his average by 5 runs. Choose the correct choice from the following options.
A) 70
B) 76
C) 78
D) 80
E) 87 | <gadget id="calculator">32 + 5</gadget>
<output>37</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">37 * 11</gadget>
<output>407</output>
<gadget id="calculator">10 * 32</gadget>
<output>320</output>
<gadget id="calculator">407 - 320</gadget>
<output>87</output>
<result>E</result> | E | 87 | Average of 10 matches is 32, How many runs one should should score to increase his average by 5 runs. | {
"A": "70",
"B": "76",
"C": "78",
"D": "80",
"E": "87"
} | subtract(multiply(add(32, 5), add(10, const_1)), multiply(10, 32)) | add(n1,n2)|add(n0,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "explanation : average after 11 innings should be 37 so , required score = ( 11 * 37 ) - ( 10 * 32 ) = 407 - 320 = 87 answer : option e" | general |
math_qa__Q3y3yX6gVPiolLVT | If there are 4 peanuts in a box and Mary puts 2 more peanuts inside, how many peanuts are in the box? Answers: A) 8 B) 9 C) 6 D) 11 E) 12 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<result>C</result> | C | 6 | If there are 4 peanuts in a box and Mary puts 2 more peanuts inside, how many peanuts are in the box? | {
"A": "8",
"B": "9",
"C": "6",
"D": "11",
"E": "12"
} | add(4, 2) | add(n0,n1)| | "2 + 4 = 6 correct answer is c ) 6" | general |
math_qa__DJ0oQjA5UXxvDiU1 | Speed of a boat in standing water is 16 kmph and the speed of the stream is 2 kmph. A man rows to a place at a distance of 6840 km and comes back to the starting point. The total time taken by him is: Choose the correct choice
A) 914.2 hours B) 900 hours C) 915 hours D) 868.6 hours E) 915 hours | <gadget id="calculator">16 + 2</gadget>
<output>18</output>
<gadget id="calculator">6_840 / 18</gadget>
<output>380</output>
<gadget id="calculator">16 - 2</gadget>
<output>14</output>
<gadget id="calculator">6_840 / 14</gadget>
<output>3_420/7 = around 488.571429</output>
<gadget id="calculator">380 + (3_420/7)</gadget>
<output>6_080/7 = around 868.571429</output>
<result>D</result> | D | 868.6 | Speed of a boat in standing water is 16 kmph and the speed of the stream is 2 kmph. A man rows to a place at a distance of 6840 km and comes back to the starting point. The total time taken by him is: | {
"A": "914.2 hours",
"B": "900 hours",
"C": "915 hours",
"D": "868.6 hours",
"E": "915 hours"
} | add(divide(6840, add(16, 2)), divide(6840, subtract(16, 2))) | add(n0,n1)|subtract(n0,n1)|divide(n2,#0)|divide(n2,#1)|add(#2,#3)| | "explanation : speed downstream = ( 16 + 2 ) = 18 kmph speed upstream = ( 16 - 2 ) = 14 kmph total time taken = 6840 / 18 + 6840 / 14 = 380 + 488.6 = 868.6 hours answer : option d" | physics |
math_qa__wwinc98nJW4BYGTU | In August,a cricket team that played 120 matches won 22% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average? Choose the correct choice:
A) 40 B) 52 C) 68 D) 75 E) 98 | <gadget id="calculator">52 / 100</gadget>
<output>13/25 = around 0.52</output>
<gadget id="calculator">(13/25) * 120</gadget>
<output>312/5 = around 62.4</output>
<gadget id="calculator">22 / 100</gadget>
<output>11/50 = around 0.22</output>
<gadget id="calculator">(11/50) * 120</gadget>
<output>132/5 = around 26.4</output>
<gadget id="calculator">(312/5) - (132/5)</gadget>
<output>36</output>
<gadget id="calculator">1 - (13/25)</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">36 / (12/25)</gadget>
<output>75</output>
<result>D</result> | D | 75 | In August,a cricket team that played 120 matches won 22% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average? | {
"A": "40",
"B": "52",
"C": "68",
"D": "75",
"E": "98"
} | divide(subtract(multiply(divide(52, const_100), 120), multiply(divide(22, const_100), 120)), subtract(const_1, divide(52, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|multiply(n0,#1)|subtract(const_1,#0)|subtract(#2,#3)|divide(#5,#4)| | "let the no of matches played more = x so , ( 120 + x ) * 52 / 100 = 26.4 + x by solving we get x = 75 answer : d" | general |
math_qa__Qg8uZPRGKQuiqWaV | Jane started baby-sitting when she was 16 years old. Whenever she baby-sat for a child, that child was no more than half her age at the time. Jane is currently 32 years old, and she stopped baby-sitting 10 years ago. What is the current age of the oldest person for whom Jane could have baby-sat? Answers:
A) 20 B) 21 C) 22 D) 23 E) 24 | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">32 - 16</gadget>
<output>16</output>
<gadget id="calculator">8 + 16</gadget>
<output>24</output>
<result>E</result> | E | 24 | Jane started baby-sitting when she was 16 years old. Whenever she baby-sat for a child, that child was no more than half her age at the time. Jane is currently 32 years old, and she stopped baby-sitting 10 years ago. What is the current age of the oldest person for whom Jane could have baby-sat? | {
"A": "20",
"B": "21",
"C": "22",
"D": "23",
"E": "24"
} | add(divide(16, const_2), subtract(32, 16)) | divide(n0,const_2)|subtract(n1,n0)|add(#0,#1)| | "check two extreme cases : jane = 16 , child = 8 , years ago = 32 - 16 = 16 - - > child ' s age now = 8 + 16 = 24 ; jane = 22 , child = 11 , years ago = 32 - 22 = 10 - - > child ' s age now = 11 + 10 = 21 . answer : e ." | general |
math_qa__F3uAqshWy4swo00K | A cylindrical container of radius 6 cm and height 15 cm is filled with ice-cream. The whole icecream has to be distributed to 10 children in equal cones with hemispherical tops. If the height of the conical portion is four times the radius of its base, find the radius of the ice-cream cone. Choose the correct option.
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">pi * (6 ** 2) * 15</gadget>
<output>540*pi = around 1_696.460033</output>
<gadget id="calculator">(540*pi) / 10</gadget>
<output>54*pi = around 169.646003</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * pi</gadget>
<output>pi/3 = around 1.047198</output>
<gadget id="calculator">(pi/3) * 4</gadget>
<output>4*pi/3 = around 4.18879</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * pi</gadget>
<output>2*pi/3 = around 2.094395</output>
<gadget id="calculator">(4*pi/3) + (2*pi/3)</gadget>
<output>2*pi = around 6.283185</output>
<gadget id="calculator">(54*pi) / (2*pi)</gadget>
<output>27</output>
<gadget id="calculator">27 / 3</gadget>
<output>9</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<result>C</result> | C | 3 | A cylindrical container of radius 6 cm and height 15 cm is filled with ice-cream. The whole icecream has to be distributed to 10 children in equal cones with hemispherical tops. If the height of the conical portion is four times the radius of its base, find the radius of the ice-cream cone. | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | sqrt(divide(divide(divide(volume_cylinder(6, 15), const_10), add(multiply(multiply(divide(const_1, const_3), const_pi), const_4), multiply(divide(const_2, const_3), const_pi))), const_3)) | divide(const_1,const_3)|divide(const_2,const_3)|volume_cylinder(n0,n1)|divide(#2,const_10)|multiply(#0,const_pi)|multiply(#1,const_pi)|multiply(#4,const_4)|add(#6,#5)|divide(#3,#7)|divide(#8,const_3)|sqrt(#9) | volume of given ice cream = ( pie ) * 6 ² * 15 = 540 ( pie ) dividing to 10 children volume given to a child = 54 ( pie ) let r be radius and h be the height of the cone , then ( pie ) r ² h / 3 + 2 ( pie ) r ³ / 3 = 54 ( pie ) also given h = 4 r 4 r ³ / 3 + 2 r ³ / 3 = 54 2 r ³ = 54 r ³ = 27 r = 3 answer : c | geometry |
math_qa__jQ5C9CY2syphDg2j | If
1 = 3
2 = 6
3 = 9
4 = 12
5 = 15
Then 9 = ?
Hint: Its a logic Riddle not a mathematical riddle Choose the correct answer.
A) 1
B) 2
C) 3
D) 4
E) 5 | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 9</gadget>
<output>54</output>
<gadget id="calculator">54 / 15</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(18/5) - (1/3)</gadget>
<output>49/15 = around 3.266667</output>
<gadget id="calculator">(49/15) - (1/3)</gadget>
<output>44/15 = around 2.933333</output>
<result>C</result> | C | 3 | If
1 = 3
2 = 6
3 = 9
4 = 12
5 = 15
Then 9 = ?
Hint: Its a logic Riddle not a mathematical riddle | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(subtract(divide(multiply(add(3, 3), 9), 15), const_0_33), const_0_33) | add(n1,n1)|multiply(n5,#0)|divide(#1,n9)|subtract(#2,const_0_33)|subtract(#3,const_0_33) | c 3 as stated 3 = 9 = > 9 = 3 answer is c | other |
math_qa__htkTnMTqXrK26Qrr | there are 3 boats b 1 , b 2 and b 3 working together they carry 60 people in each trip . one day an early morning b 1 carried 50 people in few trips alone . when it stopped carrying the passengers b 2 and b 3 started carrying the people together . it took a total of 10 trips to carry 300 people by b 1 , b 2 and b 3 . it is known that each day on an average 300 people cross the river using only one of the 3 boats b 1 , b 2 and b 3 . how many trips it would take to b 1 , to carry 150 passengers alone ? Choose the correct choice from the following answers:
A) 15 B) 30 C) 25 D) 10 E) 15 | <gadget id="calculator">300 / 2</gadget>
<output>150</output>
<gadget id="calculator">150 / 10</gadget>
<output>15</output>
<result>A</result> | A | 15 | there are 3 boats b 1 , b 2 and b 3 working together they carry 60 people in each trip . one day an early morning b 1 carried 50 people in few trips alone . when it stopped carrying the passengers b 2 and b 3 started carrying the people together . it took a total of 10 trips to carry 300 people by b 1 , b 2 and b 3 . it is known that each day on an average 300 people cross the river using only one of the 3 boats b 1 , b 2 and b 3 . how many trips it would take to b 1 , to carry 150 passengers alone ? | {
"A": "15",
"B": "30",
"C": "25",
"D": "10",
"E": "15"
} | divide(divide(300, 2), 10) | divide(n10,n2)|divide(#0,n9) | explanation : combined efficiency of all the three boats = 60 passenger / trip now , consider option ( a ) 15 trips and 150 passengers means efficiency of b 1 = 10 p / t which means in carrying 50 passengers b 1 must has taken 5 trips . so the rest trips equal to 5 ( 10 - 5 = 5 ) in which b 2 and b 3 together carried remaining 250 ( 300 - 50 = 250 ) passengers . therefore the efficiency of b 2 and b 3 = 250 / 5 = 50 p / t since , the combined efficiency of b 1 , b 2 and b 3 is 60 . which is same as given in the first statement hence option ( a ) is correct answer : a | general |
math_qa__scez06AVRKut0eBv | The average age of 12 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is Choose the correct choice from the following answers.
A) 22
B) 30
C) 34
D) 38
E) 27 | <gadget id="calculator">21 + 23</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<gadget id="calculator">1 * 12</gadget>
<output>12</output>
<gadget id="calculator">22 + 12</gadget>
<output>34</output>
<result>C</result> | C | 34 | The average age of 12 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is | {
"A": "22",
"B": "30",
"C": "34",
"D": "38",
"E": "27"
} | add(divide(add(21, 23), const_2), multiply(const_1, 12)) | add(n1,n2)|multiply(n0,const_1)|divide(#0,const_2)|add(#2,#1)| | "total age increased = ( 12 * 2 ) years = 24 years . sum of ages of two new men = ( 21 + 23 + 24 ) years = 68 years average age of two new men = ( 68 / 2 ) years = 34 years . answer : c" | general |
math_qa__TtWZ4MEWQMjDY3kQ | A boat can travel with a speed of 24 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 112 km downstream Choose the correct choice from the following answers:
A) 3 hours
B) 4 hours
C) 5 hours
D) 6 hours
E) 7 hours | <gadget id="calculator">24 + 4</gadget>
<output>28</output>
<gadget id="calculator">112 / 28</gadget>
<output>4</output>
<result>B</result> | B | 4 | A boat can travel with a speed of 24 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 112 km downstream | {
"A": "3 hours",
"B": "4 hours",
"C": "5 hours",
"D": "6 hours",
"E": "7 hours"
} | divide(112, add(24, 4)) | add(n0,n1)|divide(n2,#0)| | "explanation : speed of the boat in still water = 24 km / hr speed of the stream = 4 km / hr speed downstream = ( 22 + 5 ) = 28 km / hr distance travelled downstream = 112 km time taken = distance / speed = 112 / 28 = 4 hours answer : option b" | physics |
math_qa__txeZc2r7EH7EMndu | Find the L.C.M. of 72, 108 and 2100. Pick one.
A) 37800 B) 37600 C) 37200 D) 37500 E) none of them | <gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">8 * 25</gadget>
<output>200</output>
<gadget id="calculator">27 * 200</gadget>
<output>5_400</output>
<gadget id="calculator">2_100 / 2</gadget>
<output>1_050</output>
<gadget id="calculator">1_050 / 2</gadget>
<output>525</output>
<gadget id="calculator">525 / 3</gadget>
<output>175</output>
<gadget id="calculator">175 / 5</gadget>
<output>35</output>
<gadget id="calculator">35 / 5</gadget>
<output>7</output>
<gadget id="calculator">5_400 * 7</gadget>
<output>37_800</output>
<result>A</result> | A | 37,800 | Find the L.C.M. of 72, 108 and 2100. | {
"A": "37800",
"B": "37600",
"C": "37200",
"D": "37500",
"E": "none of them"
} | multiply(multiply(power(const_3, const_3), multiply(power(const_2, const_3), power(add(const_4, const_1), const_2))), divide(divide(divide(divide(divide(2100, const_2), const_2), const_3), add(const_4, const_1)), add(const_4, const_1))) | add(const_1,const_4)|divide(n2,const_2)|power(const_2,const_3)|power(const_3,const_3)|divide(#1,const_2)|power(#0,const_2)|divide(#4,const_3)|multiply(#2,#5)|divide(#6,#0)|multiply(#7,#3)|divide(#8,#0)|multiply(#10,#9) | 72 = 2 ^ 3 x 3 ^ 2 , 108 = 3 ^ 3 x 2 ^ 2 , 2100 = 2 ^ 2 x 5 ^ 2 x 3 x 7 . l . c . m . = 2 ^ 3 x 3 ^ 3 x 5 ^ 2 x 7 = 37800 . answer is a . | physics |
math_qa__VawNCmlcy1FlDoQ3 | The average of 10 numbers is calculated as 16. It is discovered later on that while calculating the average, the number 55 was incorrectly read as 25, and this incorrect number was used in the calculation. What is the correct average?
Choose the correct choice from the following answers.
A) 17 B) 19 C) 25 D) 31 E) 46 | <gadget id="calculator">16 * 10</gadget>
<output>160</output>
<gadget id="calculator">160 - 25</gadget>
<output>135</output>
<gadget id="calculator">135 + 55</gadget>
<output>190</output>
<gadget id="calculator">190 / 10</gadget>
<output>19</output>
<result>B</result> | B | 19 | The average of 10 numbers is calculated as 16. It is discovered later on that while calculating the average, the number 55 was incorrectly read as 25, and this incorrect number was used in the calculation. What is the correct average? | {
"A": "17",
"B": "19",
"C": "25",
"D": "31",
"E": "46"
} | divide(add(subtract(multiply(16, 10), 25), 55), 10) | multiply(n0,n1)|subtract(#0,n3)|add(n2,#1)|divide(#2,n0)| | "the total sum of the numbers should be increased by 30 . then the average will increase by 30 / 10 = 3 . the correct average is 19 . the answer is b ." | general |
math_qa__wvxLNkG57f5er5gs | How many inches are in 2000 millimeters? (round your answer to the nearest hundredth of of an inch).
Answers
A) 48.74 inches B) 58.74 inches C) 78.74 inches D) 28.74 inches E) 88.74 inches | <gadget id="calculator">2_000 / 10</gadget>
<output>200</output>
<gadget id="calculator">100 / 254</gadget>
<output>50/127 = around 0.393701</output>
<gadget id="calculator">200 * (50/127)</gadget>
<output>10_000/127 = around 78.740157</output>
<result>C</result> | C | 78.74 | How many inches are in 2000 millimeters? (round your answer to the nearest hundredth of of an inch). | {
"A": "48.74 inches",
"B": "58.74 inches",
"C": "78.74 inches",
"D": "28.74 inches",
"E": "88.74 inches"
} | multiply(divide(2000, const_10), const_0_3937) | divide(n0,const_10)|multiply(#0,const_0_3937) | one inch is the same as 25.4 mm . let x inches be the same as 1000 mm x = 1 inch * 2000 mm / 25.4 mm = 78.74 inches correct answer c | physics |
math_qa__JWjWT2kWQ0JGPV4w | The average of 6 no.'s is 6.40. The average of 2 of them is 6.2, while the average of the other 2 is 6.1. What is the average of the remaining 2 no's?
Choose the correct answer:
A) 2.3 B) 2.6 C) 6.9 D) 4.5 E) 4.6 | <gadget id="calculator">6 * 6.4</gadget>
<output>38.4</output>
<gadget id="calculator">2 * 6.2</gadget>
<output>12.4</output>
<gadget id="calculator">2 * 6.1</gadget>
<output>12.2</output>
<gadget id="calculator">12.4 + 12.2</gadget>
<output>24.6</output>
<gadget id="calculator">38.4 - 24.6</gadget>
<output>13.8</output>
<gadget id="calculator">13.8 / 2</gadget>
<output>6.9</output>
<result>C</result> | C | 6.9 | The average of 6 no.'s is 6.40. The average of 2 of them is 6.2, while the average of the other 2 is 6.1. What is the average of the remaining 2 no's? | {
"A": "2.3",
"B": "2.6",
"C": "6.9",
"D": "4.5",
"E": "4.6"
} | divide(subtract(multiply(6, 6.40), add(multiply(2, 6.2), multiply(2, 6.1))), 2) | multiply(n0,n1)|multiply(n2,n3)|multiply(n2,n5)|add(#1,#2)|subtract(#0,#3)|divide(#4,n2)| | "sum of the remaining two numbers = ( 6.4 * 6 ) - [ ( 6.2 * 2 ) + ( 6.1 * 2 ) ] = 38.40 - ( 12.4 + 12.2 ) = 38.40 - 24.6 = 13.80 required average = ( 13.8 / 2 ) = 6.9 answer : c" | general |
math_qa__P6L41ZLHFvlnsOfl | The current in a river is 6 mph. A boat can travel 20 mph in still water. How far up the river can the boat travel if the round trip is to take 10 hours? Choose the correct choice from the following
A) 69 miles B) 88 miles C) 96 miles D) 91 miles E) 112 miles | <gadget id="calculator">20 - 6</gadget>
<output>14</output>
<gadget id="calculator">20 + 6</gadget>
<output>26</output>
<gadget id="calculator">14 * 26</gadget>
<output>364</output>
<gadget id="calculator">364 * 10</gadget>
<output>3_640</output>
<gadget id="calculator">26 + 14</gadget>
<output>40</output>
<gadget id="calculator">3_640 / 40</gadget>
<output>91</output>
<result>D</result> | D | 91 | The current in a river is 6 mph. A boat can travel 20 mph in still water. How far up the river can the boat travel if the round trip is to take 10 hours? | {
"A": "69 miles",
"B": "88 miles",
"C": "96 miles",
"D": "91 miles",
"E": "112 miles"
} | divide(multiply(multiply(subtract(20, 6), add(20, 6)), 10), add(add(20, 6), subtract(20, 6))) | add(n0,n1)|subtract(n1,n0)|add(#0,#1)|multiply(#0,#1)|multiply(n2,#3)|divide(#4,#2)| | "upstream speed = 20 - 6 = 14 mph downstream speed = 20 + 6 = 26 mph d / 14 + d / 26 = 10 hours solving for d we get d = 91 answer : d" | physics |
math_qa__ZLR128hoo0NYuKQ0 | a school has 6 maths 5 physics and 5 chemistry teachers each teacher can teach 4 subjects max what is he minimum number of teachers required Answers.
A) 2 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">11 + 5</gadget>
<output>16</output>
<gadget id="calculator">16 / 4</gadget>
<output>4</output>
<result>B</result> | B | 4 | a school has 6 maths 5 physics and 5 chemistry teachers each teacher can teach 4 subjects max what is he minimum number of teachers required | {
"A": "2",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(add(add(6, 5), 5), 4) | add(n0,n1)|add(n2,#0)|divide(#1,n3)| | "total subjects = 6 + 5 + 5 = 16 max subjects by 1 teacher = 4 so , min of teachers required = 16 / 4 = 4 answer : b" | general |
math_qa__C59QvMtHREpEjFvd | If a monkey can climb 6 meter & slip down 3 meter in alternate minutes, than how much time can be taken by the monkey to climb up to a height of 60 meter.
Choose the correct option
A) 36 min
B) 37 min
C) 38 min
D) 39 min
E) 32 min | <gadget id="calculator">60 - 6</gadget>
<output>54</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">54 / (3/2)</gadget>
<output>36</output>
<gadget id="calculator">36 + 1</gadget>
<output>37</output>
<result>B</result> | B | 37 | If a monkey can climb 6 meter & slip down 3 meter in alternate minutes, than how much time can be taken by the monkey to climb up to a height of 60 meter. | {
"A": "36 min",
"B": "37 min",
"C": "38 min",
"D": "39 min",
"E": "32 min"
} | add(divide(subtract(60, 6), divide(3, const_2)), const_1) | divide(n1,const_2)|subtract(n2,n0)|divide(#1,#0)|add(#2,const_1) | in 1 st min it climb 6 m and in 2 nd min it slips 3 m , so it final displacement is 3 m in 2 min . now for 51 m it has taken 34 min . in 35 min it goes to 57 m . in 36 min come down to 54 m . in 37 min it goes to 60 answer : b | physics |
math_qa__83uSa34NLFkyWeim | On a map, 1.5 inches represent 24 miles. How many miles approximately is the distance if you measured 46 centimeters assuming that 1-inch is 2.54 centimeters? Choose the most appropriate option
A) 174.2 B) 212 C) 288.1 D) 290 E) 282.4 | <gadget id="calculator">46 / 2.54</gadget>
<output>18.110236</output>
<gadget id="calculator">24 / 1.5</gadget>
<output>16</output>
<gadget id="calculator">18.110236 * 16</gadget>
<output>289.763776</output>
<result>D</result> | D | 290 | On a map, 1.5 inches represent 24 miles. How many miles approximately is the distance if you measured 46 centimeters assuming that 1-inch is 2.54 centimeters? | {
"A": "174.2",
"B": "212",
"C": "288.1",
"D": "290",
"E": "282.4"
} | multiply(divide(46, 2.54), divide(24, 1.5)) | divide(n2,n4)|divide(n1,n0)|multiply(#0,#1)| | "1.5 inch = 2.54 * 1.5 cm . so , 2.54 * 1.5 represents 24 miles . so for 46 cm . : 46 / ( 2.54 * 1.5 ) = x / 24 - - - > x = 24 * 46 / ( 3.81 ) = 290 answer will be d ." | physics |
math_qa__2VLivbADPRArW9Xt | The cash realised on selling a 14% stock is Rs.104.25, brokerage being 1/4% is? Select the correct option:
A) 104 B) 106 C) 102 D) 192 E) 122 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">104.25 - (1/4)</gadget>
<output>104</output>
<result>A</result> | A | 104 | The cash realised on selling a 14% stock is Rs.104.25, brokerage being 1/4% is? | {
"A": "104",
"B": "106",
"C": "102",
"D": "192",
"E": "122"
} | subtract(104.25, divide(1, 4)) | divide(n2,n3)|subtract(n1,#0)| | "cash realised = rs . ( 104.25 - 0.25 ) = rs . 104 . answer : a" | general |
math_qa__0gMO4k0OioPTw19T | How many numbers up to 200 are divisible by 2 and 3 both? Choose the correct choice from the following answers.
A) 22 B) 33 C) 77 D) 28 E) 22 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">200 / 6</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">floor(100/3)</gadget>
<output>33</output>
<result>B</result> | B | 33 | How many numbers up to 200 are divisible by 2 and 3 both? | {
"A": "22",
"B": "33",
"C": "77",
"D": "28",
"E": "22"
} | floor(divide(200, multiply(2, 3))) | multiply(n1,n2)|divide(n0,#0)|floor(#1) | explanation : 200 / 6 = 33 2 / 6 = > 33 numbers answer : b | other |
math_qa__c20AefnVZV0MhA4w | A dog has 15 bones, then he finds 8 more bones. Now how many bones does he have. Pick
A) 7 B) 27 C) 23 D) 19 E) 21 | <gadget id="calculator">15 + 8</gadget>
<output>23</output>
<result>C</result> | C | 23 | A dog has 15 bones, then he finds 8 more bones. Now how many bones does he have. | {
"A": "7",
"B": "27",
"C": "23",
"D": "19",
"E": "21"
} | add(15, 8) | add(n0,n1) | 15 + 8 = 23 . answer is c . | general |
math_qa__RQGMUIEl3fCDlJHd | Last year Manfred received 26 paychecks. Each of his first 6 paychecks was $750; each of his remaining paychecks was $20 more than each of his first 6 paychecks. To the nearest dollar, what was the average (arithmetic mean) amount of his pay checks for the year? Choose the correct choice:
A) $ 752 B) $ 755 C) $ 765 D) $ 773 E) $ 775 | <gadget id="calculator">750 + 20</gadget>
<output>770</output>
<gadget id="calculator">770 * 20</gadget>
<output>15_400</output>
<gadget id="calculator">6 * 750</gadget>
<output>4_500</output>
<gadget id="calculator">15_400 + 4_500</gadget>
<output>19_900</output>
<gadget id="calculator">19_900 / 26</gadget>
<output>9_950/13 = around 765.384615</output>
<result>C</result> | C | 765 | Last year Manfred received 26 paychecks. Each of his first 6 paychecks was $750; each of his remaining paychecks was $20 more than each of his first 6 paychecks. To the nearest dollar, what was the average (arithmetic mean) amount of his pay checks for the year? | {
"A": "$ 752",
"B": "$ 755",
"C": "$ 765",
"D": "$ 773",
"E": "$ 775"
} | divide(add(multiply(add(750, 20), 20), multiply(6, 750)), 26) | add(n2,n3)|multiply(n1,n2)|multiply(n3,#0)|add(#2,#1)|divide(#3,n0) | = ( 750 * 6 + 770 * 20 ) / 26 = 765 answer is c . posted from my mobile device | general |
math_qa__q5ExpWiOPZdT0l2B | What is the rate percent when the simple interest on Rs.800 amount to Rs.200 in 4 Years? Answers.
A) 5 % B) 7 % C) 6.25 % D) 2 % E) 4 % | <gadget id="calculator">100 * 200</gadget>
<output>20_000</output>
<gadget id="calculator">800 * 4</gadget>
<output>3_200</output>
<gadget id="calculator">20_000 / 3_200</gadget>
<output>25/4 = around 6.25</output>
<result>C</result> | C | 6.25 | What is the rate percent when the simple interest on Rs.800 amount to Rs.200 in 4 Years? | {
"A": "5 %",
"B": "7 %",
"C": "6.25 %",
"D": "2 %",
"E": "4 %"
} | divide(multiply(const_100, 200), multiply(800, 4)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)| | "200 = ( 800 * 4 * r ) / 100 r = 6.25 % answer : c" | gain |
math_qa__Ma9cBI7IfmeV0A2U | The sides of a cube are in the ratio 1:2 the ratio of their volume is? Pick one:
A) 1 : 6
B) 1 : 4
C) 1 : 0
D) 1 : 2
E) 1 : 1 | <gadget id="calculator">1 ** 3</gadget>
<output>1</output>
<gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">2 * (1/8)</gadget>
<output>1/4 = around 0.25</output>
<result>B</result> | B | 0.25 | The sides of a cube are in the ratio 1:2 the ratio of their volume is? | {
"A": "1 : 6",
"B": "1 : 4",
"C": "1 : 0",
"D": "1 : 2",
"E": "1 : 1"
} | multiply(const_2, divide(volume_cube(const_1), volume_cube(2))) | volume_cube(const_1)|volume_cube(n1)|divide(#0,#1)|multiply(#2,const_2) | 1 : 4 answer : b | geometry |
math_qa__C51p7rptzjB69lui | A train running at the speed of 6 km/hr crosses a pole in 2 seconds. Find the length of the train? Answers: A) 150 B) 872 C) 3.33 D) 3.21 E) 30.1 | <gadget id="calculator">6 * 1_000</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 3_600</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 2</gadget>
<output>10/3 = around 3.333333</output>
<result>C</result> | C | 3.33 | A train running at the speed of 6 km/hr crosses a pole in 2 seconds. Find the length of the train? | {
"A": "150",
"B": "872",
"C": "3.33",
"D": "3.21",
"E": "30.1"
} | multiply(divide(multiply(6, const_1000), const_3600), 2) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 6 * ( 5 / 18 ) m / sec = 5 / 3 m / sec length of train ( distance ) = speed * time 5 / 3 ) * 2 = 3.33 meter answer : c" | physics |
math_qa__BQDnR15LHy3g4Jpg | The denominator of a fraction is 5 greater than the numerator. If the numerator and the denominator are increased by 1, the resulting fraction is equal to 7â„12. What is the value of the original fraction? Choose the correct option:
A) 6 / 11
B) 8 / 13
C) 11 / 16
D) 12 / 17
E) 14 / 19 | <gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">42 - 12</gadget>
<output>30</output>
<gadget id="calculator">12 - 7</gadget>
<output>5</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">6 / 11</gadget>
<output>6/11 = around 0.545455</output>
<result>A</result> | A | 0.545455 | The denominator of a fraction is 5 greater than the numerator. If the numerator and the denominator are increased by 1, the resulting fraction is equal to 7â„12. What is the value of the original fraction? | {
"A": "6 / 11",
"B": "8 / 13",
"C": "11 / 16",
"D": "12 / 17",
"E": "14 / 19"
} | divide(divide(subtract(multiply(7, add(1, 5)), 12), subtract(12, 7)), add(divide(subtract(multiply(7, add(1, 5)), 12), subtract(12, 7)), 5)) | add(n0,n1)|subtract(n3,n2)|multiply(n2,#0)|subtract(#2,n3)|divide(#3,#1)|add(n0,#4)|divide(#4,#5) | let the numerator be x . then the denominator is x + 5 . x + 1 / x + 6 = 7 / 12 . 12 x + 12 = 7 x + 42 . 5 x = 30 . x = 6 . the original fraction is 6 / 11 . the answer is a . | general |
math_qa__H3dkWoXzx806qldI | If the sum of two positive integers is 22 and the difference of their squares is 44, what is the product of the two integers? Choose the correct choice from the following answers
A) 108 B) 119 C) 120 D) 135 E) 143 | <gadget id="calculator">44 / 22</gadget>
<output>2</output>
<gadget id="calculator">22 - 2</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">10 * 12</gadget>
<output>120</output>
<result>C</result> | C | 120 | If the sum of two positive integers is 22 and the difference of their squares is 44, what is the product of the two integers? | {
"A": "108",
"B": "119",
"C": "120",
"D": "135",
"E": "143"
} | multiply(divide(subtract(22, divide(44, 22)), divide(44, 22)), add(divide(subtract(22, divide(44, 22)), divide(44, 22)), divide(44, 22))) | divide(n1,n0)|subtract(n0,#0)|divide(#1,#0)|add(#2,#0)|multiply(#3,#2)| | "let the 2 positive numbers x and y x + y = 22 - - 1 x ^ 2 - y ^ 2 = 44 = > ( x + y ) ( x - y ) = 44 - - 2 using equation 1 in 2 , we get = > x - y = 2 - - 3 solving equation 1 and 3 , we get x = 12 y = 10 product = 12 * 10 = 120 answer c" | general |
math_qa__3Me40y3lQsBHSzLt | Suppose you work for a manufacturing plant that pays you $12.50 an hour plus $0.16 for each widget you make. How many widgets must you produce in a 40 hour week to earn $660 (before payroll deductions)? Select:
A) 800
B) 900
C) 1000
D) 1100
E) 1200 | <gadget id="calculator">12.5 * 40</gadget>
<output>500</output>
<gadget id="calculator">660 - 500</gadget>
<output>160</output>
<gadget id="calculator">160 / 0.16</gadget>
<output>1_000</output>
<result>C</result> | C | 1,000 | Suppose you work for a manufacturing plant that pays you $12.50 an hour plus $0.16 for each widget you make. How many widgets must you produce in a 40 hour week to earn $660 (before payroll deductions)? | {
"A": "800",
"B": "900",
"C": "1000",
"D": "1100",
"E": "1200"
} | divide(subtract(660, multiply(12.50, 40)), 0.16) | multiply(n0,n2)|subtract(n3,#0)|divide(#1,n1)| | "total pay = 40 * $ 12.50 + $ 0.16 * x = 660 x = 160 / 0.16 = 1000 the answer is c ." | physics |
math_qa__yZM3Wl6J0iv7LXEo | In a stream running at 3 Kmph, a motor boat goes 10 Km upstream and back again to the starting point in 57 minutes. Find the speed of motor boat in still water? Choose the correct choice from the following: A) 18 kmph B) 22 kmph C) 16 kmph D) 20 kmph E) none of these | <gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">57 / 60</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">20 / (19/20)</gadget>
<output>400/19 = around 21.052632</output>
<result>B</result> | B | 22 | In a stream running at 3 Kmph, a motor boat goes 10 Km upstream and back again to the starting point in 57 minutes. Find the speed of motor boat in still water? | {
"A": "18 kmph",
"B": "22 kmph",
"C": "16 kmph",
"D": "20 kmph",
"E": "none of these"
} | divide(add(10, 10), divide(57, const_60)) | add(n1,n1)|divide(n2,const_60)|divide(#0,#1)| | "explanation : let the speed of motor boat instill water be x kmph then , speed in downstream = ( x + 3 ) km and . speed in upstream = ( x - 3 ) kmph time taken to row 10 km & back = ( 10 / x + 3,10 / x - 3 ) 10 / x + 3 + 10 / x - 3 = 57 / 60 11 x 2 - 240 x - 44 = 0 ( x - 22 ) ( 11 x + 2 ) = 0 x = 22 or x = - 2 / 11 then x = 22 kmph answer : option b" | physics |
math_qa__t1DGi5J3o1wbOewf | People were sitting in a circle.7th one is direct opposite to 18th one..Then how many were there in that group?
Select.
A) 21 B) 22 C) 23 D) 24 E) 20 | <gadget id="calculator">18 - 7</gadget>
<output>11</output>
<gadget id="calculator">2 * 11</gadget>
<output>22</output>
<result>B</result> | B | 22 | People were sitting in a circle.7th one is direct opposite to 18th one..Then how many were there in that group? | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "20"
} | multiply(const_2, subtract(18, 7)) | subtract(n1,n0)|multiply(#0,const_2) | 7 th one is exactly opposite represents half of circle . with 7 and 18 total members are 12 for remaing half = 12 * 2 - 2 ( 7 th and 18 th ( already taken ) ) = 22 answer : b | geometry |
math_qa__tN0eaVyKhtnpOfWj | A certain cube floating in a bucket of water has between 80 and 90 percent of its volume below the surface of the water. If between 6 and 13 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately Choose the correct choice from the following options:
A) 4 B) 5 C) 7 D) 8 E) 9 | <gadget id="calculator">13 * 100</gadget>
<output>1_300</output>
<gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">1_300 / 20</gadget>
<output>65</output>
<gadget id="calculator">65 ** (1/3)</gadget>
<output>65**(1/3) = around 4.020726</output>
<result>A</result> | A | 4 | A certain cube floating in a bucket of water has between 80 and 90 percent of its volume below the surface of the water. If between 6 and 13 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately | {
"A": "4",
"B": "5",
"C": "7",
"D": "8",
"E": "9"
} | cube_edge_by_volume(divide(multiply(13, const_100), subtract(const_100, 80))) | multiply(n3,const_100)|subtract(const_100,n0)|divide(#0,#1)|cube_edge_by_volume(#2)| | "if sides are 7 , vol = 7 ^ 3 = 343 80 % = 274.4 , 90 % = 308.7 so vol above water , between 68.6 and 34.3 - - > too big if side are 4 , vol = 64 80 % = 51.2 , 90 % = 57.6 vol above water between 12.8 and 6.4 so 4 should be the answer . check option c , if sides are 5 , vol = 125 80 % = 100 , . 90 % = 112.5 vol above water between 12.5 - 25 ( sides are 4 cubic centimeters ) a" | geometry |
math_qa__rRNRgMrdtu6EtXG3 | A waitress's income consists of her salary and tips.During one week ,her tips were 11/4 of her salary.What fraction of her income for the week came from tips? Options
A) 1 / 9 B) 1 / 6 C) 1 / 3 D) 4 / 9 E) 11 / 15 | <gadget id="calculator">11 + 4</gadget>
<output>15</output>
<gadget id="calculator">11 / 15</gadget>
<output>11/15 = around 0.733333</output>
<result>E</result> | E | 0.733333 | A waitress's income consists of her salary and tips.During one week ,her tips were 11/4 of her salary.What fraction of her income for the week came from tips? | {
"A": "1 / 9",
"B": "1 / 6",
"C": "1 / 3",
"D": "4 / 9",
"E": "11 / 15"
} | divide(11, add(11, 4)) | add(n0,n1)|divide(n0,#0)| | "her tips were 11 / 4 of her salary . let ' s say her salary = $ 4 this mean her tips = ( 11 / 4 ) ( $ 4 ) = $ 11 so , her total income = $ 4 + $ 11 = $ 15 what fraction of her income for the week came from tips $ 11 / $ 15 = 11 / 15 = e" | general |
math_qa__BAGvoMWhCjzK2fjk | On a certain farm the ratio of horses to cows is 5:1. If the farm were to sell 15 horses and buy 15 cows, the ratio of horses to cows would then be 17:7. After the transaction, how many more horses than cows would the farm own? Select the correct option.
A) 30 B) 40 C) 50 D) 60 E) 70 | <gadget id="calculator">15 * 17</gadget>
<output>255</output>
<gadget id="calculator">15 * 7</gadget>
<output>105</output>
<gadget id="calculator">255 + 105</gadget>
<output>360</output>
<gadget id="calculator">5 * 7</gadget>
<output>35</output>
<gadget id="calculator">35 - 17</gadget>
<output>18</output>
<gadget id="calculator">360 / 18</gadget>
<output>20</output>
<gadget id="calculator">5 * 20</gadget>
<output>100</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">20 + 15</gadget>
<output>35</output>
<gadget id="calculator">85 - 35</gadget>
<output>50</output>
<result>C</result> | C | 50 | On a certain farm the ratio of horses to cows is 5:1. If the farm were to sell 15 horses and buy 15 cows, the ratio of horses to cows would then be 17:7. After the transaction, how many more horses than cows would the farm own? | {
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "70"
} | subtract(subtract(multiply(5, divide(add(multiply(15, 17), multiply(15, 7)), subtract(multiply(5, 7), 17))), 15), add(divide(add(multiply(15, 17), multiply(15, 7)), subtract(multiply(5, 7), 17)), 15)) | multiply(n2,n4)|multiply(n2,n5)|multiply(n0,n5)|add(#0,#1)|subtract(#2,n4)|divide(#3,#4)|add(n2,#5)|multiply(n0,#5)|subtract(#7,n2)|subtract(#8,#6) | originally , there were 5 k horses and k cows . 7 ( 5 k - 15 ) = 17 ( k + 15 ) 35 k - 17 k = 255 + 105 18 k = 360 k = 20 the difference between horses and cows is ( 5 k - 15 ) - ( k + 15 ) = 4 k - 30 = 50 the answer is c . | other |
math_qa__QlQu2rP50maMK8mj | In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 50 questions and secures 130 marks, the no of questions he attempts correctly is : Choose the correct answer
A) 36 B) 38 C) 90 D) 88 E) 37 | <gadget id="calculator">130 + 50</gadget>
<output>180</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">180 / 5</gadget>
<output>36</output>
<result>A</result> | A | 36 | In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 50 questions and secures 130 marks, the no of questions he attempts correctly is : | {
"A": "36",
"B": "38",
"C": "90",
"D": "88",
"E": "37"
} | divide(add(130, 50), add(4, 1)) | add(n2,n3)|add(n0,n1)|divide(#0,#1)| | "let the number of correct answers be x . number of incorrect answers = ( 60 – x ) . 4 x – ( 50 – x ) = 130 = > 5 x = 180 = > x = 36 answer : a" | physics |
math_qa__36QG3hL36ZQ3zTuG | The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 684. What is the banker's discount? Choose the correct choice from the following options:
A) 1240 B) 1120 C) 1190 D) 1634 E) none of these | <gadget id="calculator">684 * 100</gadget>
<output>68_400</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<gadget id="calculator">68_400 / 72</gadget>
<output>950</output>
<gadget id="calculator">684 + 950</gadget>
<output>1_634</output>
<result>D</result> | D | 1,634 | The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 684. What is the banker's discount? | {
"A": "1240",
"B": "1120",
"C": "1190",
"D": "1634",
"E": "none of these"
} | add(684, divide(multiply(684, const_100), multiply(12, 6))) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2)| | "explanation : td = ( bg × 100 ) / tr = ( 684 × 100 ) / ( 6 × 12 ) = rs . 950 bg = bd – td = > 684 = bd - 950 = > bd = 684 + 950 = 1634 answer : option d" | gain |
math_qa__EWD6z0bNUyMpZ6xv | The price of commodity X increases by 45 cents every year, while the price of commodity Y increases by 20 cents every year. In 2001, the price of commodity X was $5.20 and the price of commodity Y was $7.30. In which year will the price of commodity X be 90 cents more than the price of commodity Y? Pick
A) 2010 B) 2011 C) 2012 D) 2013 E) 2014 | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">7.3 - 5.2</gadget>
<output>2.1</output>
<gadget id="calculator">(9/10) + 2.1</gadget>
<output>3</output>
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(9/20) - 2.1</gadget>
<output>-1.65</output>
<gadget id="calculator">3 / (-1.65)</gadget>
<output>-1.818182</output>
<gadget id="calculator">2_001 + (-1.818182)</gadget>
<output>1_999.181818</output>
<result>D</result> | D | 2,013 | The price of commodity X increases by 45 cents every year, while the price of commodity Y increases by 20 cents every year. In 2001, the price of commodity X was $5.20 and the price of commodity Y was $7.30. In which year will the price of commodity X be 90 cents more than the price of commodity Y? | {
"A": "2010",
"B": "2011",
"C": "2012",
"D": "2013",
"E": "2014"
} | add(2001, divide(add(divide(90, const_100), subtract(7.30, 5.20)), subtract(divide(45, const_100), subtract(7.30, 5.20)))) | divide(n5,const_100)|divide(n0,const_100)|subtract(n4,n3)|add(#0,#2)|subtract(#1,#2)|divide(#3,#4)|add(n2,#5)| | "the price of commodity x increases 25 cents each year relative to commodity y . the price difference is $ 2.10 and commodity x needs to be 90 cents more than commodity y . $ 3.00 / 25 cents = 12 years the answer is 2001 + 12 years = 2013 . the answer is d ." | general |
math_qa__jZoRHxSsqspc37sE | A shopkeeper cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 20% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 10% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage. Choose the correct choice from the following options:
A) 20 % B) 32 % C) 23.365 % D) 22.109 % E) 2 % | <gadget id="calculator">20 + 100</gadget>
<output>120</output>
<gadget id="calculator">10 + 100</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">120 * (11/10)</gadget>
<output>132</output>
<gadget id="calculator">132 - 100</gadget>
<output>32</output>
<result>B</result> | B | 32 | A shopkeeper cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 20% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 10% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage. | {
"A": "20 %",
"B": "32 %",
"C": "23.365 %",
"D": "22.109 %",
"E": "2 %"
} | subtract(multiply(add(20, const_100), divide(add(10, const_100), const_100)), const_100) | add(n0,const_100)|add(n1,const_100)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,const_100) | anyways , one can infer that he ' steals ' 20 % from suppliers and then charges 10 % extra to customers so basically 1.2 * 1.1 = 1.32 given that 1 is start point , we get 32 % more hence answer is b | gain |
math_qa__muBWkQuLqk4olLeW | of 3 numbers , the third is 4 times the second and the second is two times the first . if their average is 165 , the smallest of the 3 numbers is : Answers.
A) 18
B) 19
C) 45
D) 21
E) 22 | <gadget id="calculator">165 * 3</gadget>
<output>495</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<gadget id="calculator">495 / 11</gadget>
<output>45</output>
<result>C</result> | C | 45 | of 3 numbers , the third is 4 times the second and the second is two times the first . if their average is 165 , the smallest of the 3 numbers is : | {
"A": "18",
"B": "19",
"C": "45",
"D": "21",
"E": "22"
} | divide(multiply(165, 3), add(multiply(4, const_2), 3)) | multiply(n0,n2)|multiply(n1,const_2)|add(n0,#1)|divide(#0,#2) | explanation : let first number be x . so , 2 nd no . = 2 x & 3 rd no . = 8 x . so , x + 2 x + 8 x = 165 × 3 = 495 11 x = 495 / 11 x = 495 / 11 hence , smallest number x = 45 answer : c | general |
math_qa__H9MTqvaoluWG0Eop | Two mixers and one T.V. cost Rs. 7000, while two T.V.s and a mixer cost Rs, 9800. The value of one T.V. is: Choose the correct choice:
A) rs . 4000 B) rs . 4500 C) rs . 4300 D) rs . 4200 E) none of these | <gadget id="calculator">9_800 * 2</gadget>
<output>19_600</output>
<gadget id="calculator">7_000 - 19_600</gadget>
<output>-12_600</output>
<gadget id="calculator">(-12_600) / 3</gadget>
<output>-4_200</output>
<gadget id="calculator">-(-4_200)</gadget>
<output>4_200</output>
<result>D</result> | D | 4,200 | Two mixers and one T.V. cost Rs. 7000, while two T.V.s and a mixer cost Rs, 9800. The value of one T.V. is: | {
"A": "rs . 4000",
"B": "rs . 4500",
"C": "rs . 4300",
"D": "rs . 4200",
"E": "none of these"
} | negate(divide(subtract(7000, multiply(9800, const_2)), const_3)) | multiply(n1,const_2)|subtract(n0,#0)|divide(#1,const_3)|negate(#2) | explanation : let c . p . of a mixer be rs . x and that of a t . v . be rs . y . then , 2 x + y = 7000 and 2 y + x = 9800 . multiplying 2 nd equatien by 2 and subtracting first from it , we get 3 y = 19600 - 7000 = 12600 or y = 4200 c . p . of a t . v . = rs . 4200 answer : d | general |
math_qa__Bbco7rZJmZxI8pvm | In a certain diving competition, 5 judges score each dive on a scale from 1 to 10. The point value of the dive is obtained by dropping the highest score and the lowest score and multiplying the sum of the remaining scores by the degree of difficulty. If a dive with a degree of difficulty of 3.2 received scores of 7.5, 7.8, 9.0, 6.0, and 8.5, what was the point value of the dive? Choose the correct choice: A) 68.8 B) 73.6 C) 75.2 D) 76.16 E) 81.6 | <gadget id="calculator">7.5 + 7.8</gadget>
<output>15.3</output>
<gadget id="calculator">15.3 + 8.5</gadget>
<output>23.8</output>
<gadget id="calculator">23.8 * 3.2</gadget>
<output>76.16</output>
<result>D</result> | D | 76.16 | In a certain diving competition, 5 judges score each dive on a scale from 1 to 10. The point value of the dive is obtained by dropping the highest score and the lowest score and multiplying the sum of the remaining scores by the degree of difficulty. If a dive with a degree of difficulty of 3.2 received scores of 7.5, 7.8, 9.0, 6.0, and 8.5, what was the point value of the dive? | {
"A": "68.8",
"B": "73.6",
"C": "75.2",
"D": "76.16",
"E": "81.6"
} | multiply(add(add(7.5, 7.8), 8.5), 3.2) | add(n4,n5)|add(n8,#0)|multiply(n3,#1) | degree of difficulty of dive = 3.2 scores are 6.0 , 7.5 , 8.0 , 8.5 and 9.0 we can drop 6.0 and 9.0 sum of the remaining scores = ( 7.5 + 7.8 + 8.5 ) = 23.8 point of value of the dive = 23.8 * 3.2 = 76.16 answer d | general |
math_qa__EHobvCUdlhSucWNk | The workforce of Company X is 60% female. The company hired 28 additional male workers, and as a result, the percent of female workers dropped to 55%.How many employees did the company have after hiring the additional male workers? Pick.
A) 160
B) 220
C) 336
D) 360
E) 420 | <gadget id="calculator">55 / 100</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">(11/20) * 28</gadget>
<output>77/5 = around 15.4</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) - (11/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(77/5) / (1/20)</gadget>
<output>308</output>
<gadget id="calculator">308 + 28</gadget>
<output>336</output>
<result>C</result> | C | 336 | The workforce of Company X is 60% female. The company hired 28 additional male workers, and as a result, the percent of female workers dropped to 55%.How many employees did the company have after hiring the additional male workers? | {
"A": "160",
"B": "220",
"C": "336",
"D": "360",
"E": "420"
} | add(divide(multiply(divide(55, const_100), 28), subtract(divide(60, const_100), divide(55, const_100))), 28) | divide(n2,const_100)|divide(n0,const_100)|multiply(n1,#0)|subtract(#1,#0)|divide(#2,#3)|add(n1,#4)| | "let ' s xx be total quantity of employees 0.6 x = females before adding men 0.55 ( x + 28 ) = females after adding men as quantity of women does n ' t change we can make an equation : 0.6 x = 0.55 ( x + 28 ) 0.05 x = 15.4 x = 308 - this is quantity of employees before adding 28 men so after adding it will be 336 answer is c" | gain |
math_qa__kcwtkadjurOo70my | 14 men can complete a piece of work in 22 days. In how many days can 18 men complete that piece of work? Choose the correct choice from the following answers:
A) 23 days B) 26 days C) 17 days D) 29 days E) 20 days | <gadget id="calculator">22 * 14</gadget>
<output>308</output>
<gadget id="calculator">308 / 18</gadget>
<output>154/9 = around 17.111111</output>
<result>C</result> | C | 17 | 14 men can complete a piece of work in 22 days. In how many days can 18 men complete that piece of work? | {
"A": "23 days",
"B": "26 days",
"C": "17 days",
"D": "29 days",
"E": "20 days"
} | divide(multiply(22, 14), 18) | multiply(n0,n1)|divide(#0,n2)| | "c 17 days 14 * 22 = 18 * x = > x = 17 days" | physics |
math_qa__AN2urgp1VAGwnYz7 | What amount does an investor receive if the investor invests $7000 at 10% p.a. compound interest for two years, compounding done annually? Choose the correct answer:
A) $ 8080 B) $ 8130 C) $ 8260 D) $ 8320 E) $ 8470 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 2</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">7_000 * (121/100)</gadget>
<output>8_470</output>
<result>E</result> | E | 8,470 | What amount does an investor receive if the investor invests $7000 at 10% p.a. compound interest for two years, compounding done annually? | {
"A": "$ 8080",
"B": "$ 8130",
"C": "$ 8260",
"D": "$ 8320",
"E": "$ 8470"
} | multiply(7000, power(add(const_1, divide(10, const_100)), const_2)) | divide(n1,const_100)|add(#0,const_1)|power(#1,const_2)|multiply(n0,#2)| | "a = ( 1 + r / 100 ) ^ n * p ( 1.1 ) ^ 2 * 7000 = 1.21 * 7000 = 8470 the answer is e ." | gain |
math_qa__Ii5oxe7LJGfaKSG1 | 15 times a number gives 150. The number is Choose the correct choice from the following answers
A) 11 B) 15 C) 13 D) 14 E) can not be determined | <gadget id="calculator">150 / 15</gadget>
<output>10</output>
<gadget id="calculator">150 / 10</gadget>
<output>15</output>
<result>B</result> | B | 15 | 15 times a number gives 150. The number is | {
"A": "11",
"B": "15",
"C": "13",
"D": "14",
"E": "can not be determined"
} | divide(150, divide(150, 15)) | divide(n1,n0)|divide(n1,#0) | explanation : let the number be ' n ' 15 × n = 150 ⇒ n = 10 correct option : b | general |
math_qa__wm1dZzAoVPsbwbE0 | What is the total surface area in square meters of a rectangular solid whose length is 10 meters, width is 9 meters, and depth is 6 meters?
Choose the correct choice from the following answers:
A) 400 m 2
B) 404 m 2
C) 408 m 2
D) 401 m 2
E) 412 m 2 | <gadget id="calculator">2 * (9 * 10 + 10 * 6 + 9 * 6)</gadget>
<output>408</output>
<result>C</result> | C | 408 | What is the total surface area in square meters of a rectangular solid whose length is 10 meters, width is 9 meters, and depth is 6 meters? | {
"A": "400 m 2",
"B": "404 m 2",
"C": "408 m 2",
"D": "401 m 2",
"E": "412 m 2"
} | surface_rectangular_prism(9, 10, 6) | surface_rectangular_prism(n0,n1,n2)| | "surface area of a cuboid = 2 ( lb + bh + lh ) = 2 ( 10 * 9 + 9 * 6 + 10 * 6 ) = 2 ( 90 + 54 + 60 ) = 2 * 204 = 408 m 2 answer : c" | geometry |
math_qa__rNfAlMm2RuMjRktS | 39 persons can repair a road in 12 days, working 10 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work? Select.
A) 10 B) 13 C) 14 D) 15 E) 26 | <gadget id="calculator">39 * 12</gadget>
<output>468</output>
<gadget id="calculator">468 * 10</gadget>
<output>4_680</output>
<gadget id="calculator">30 * 6</gadget>
<output>180</output>
<gadget id="calculator">4_680 / 180</gadget>
<output>26</output>
<result>E</result> | E | 26 | 39 persons can repair a road in 12 days, working 10 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work? | {
"A": "10",
"B": "13",
"C": "14",
"D": "15",
"E": "26"
} | divide(multiply(multiply(39, 12), 10), multiply(30, 6)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|divide(#2,#1)| | "let the required number of days be x . less persons , more days ( indirect proportion ) more working hours per day , less days ( indirect proportion ) persons 30 : 39 : : 12 : x working hours / day 6 : 10 30 x 6 x x = 39 x 10 x 12 x = ( 39 x 10 x 12 ) / ( 30 x 6 ) x = 26 . answer : e" | physics |
math_qa__Qm7mvb9FIGmBpERw | What is the rate percent when the simple interest on Rs.4000 amount to Rs.320 in 2 Years?
Answers: A) 4 % B) 4.1 % C) 4.2 % D) 4.3 % E) 4.5 % | <gadget id="calculator">100 * 320</gadget>
<output>32_000</output>
<gadget id="calculator">4_000 * 2</gadget>
<output>8_000</output>
<gadget id="calculator">32_000 / 8_000</gadget>
<output>4</output>
<result>A</result> | A | 4 | What is the rate percent when the simple interest on Rs.4000 amount to Rs.320 in 2 Years? | {
"A": "4 %",
"B": "4.1 %",
"C": "4.2 %",
"D": "4.3 %",
"E": "4.5 %"
} | divide(multiply(const_100, 320), multiply(4000, 2)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)| | "interest for 1 year = 320 / 2 = 160 interest on rs 4000 p / a = 160 interest rate = 160 / 4000 * 100 = 4 % answer : a" | gain |
math_qa__rZ11VffWGsJTRVv0 | man can row upstream at 30 kmph and downstream at 40 kmph, and then find the speed of the man in still water? Choose the correct choice from the following answers
A) 30 B) 35 C) 40 D) 70 E) 45 | <gadget id="calculator">30 + 40</gadget>
<output>70</output>
<gadget id="calculator">70 / 2</gadget>
<output>35</output>
<result>B</result> | B | 35 | man can row upstream at 30 kmph and downstream at 40 kmph, and then find the speed of the man in still water? | {
"A": "30",
"B": "35",
"C": "40",
"D": "70",
"E": "45"
} | divide(add(30, 40), const_2) | add(n0,n1)|divide(#0,const_2)| | "us = 30 ds = 40 m = ( 30 + 40 ) / 2 = 35 answer : b" | physics |
math_qa__V0C8WcIKjLYM1ysJ | For a certain exam,a score of 58 was 2 standard deviations below mean and a score of 98 was 3 standard deviations above mean.What was the mean score Q for the exam? Choose the correct choice from the following answers: A) 74 B) 76 C) 78 D) 80 E) 82 | <gadget id="calculator">58 * 3</gadget>
<output>174</output>
<gadget id="calculator">98 * 2</gadget>
<output>196</output>
<gadget id="calculator">174 + 196</gadget>
<output>370</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">370 / 5</gadget>
<output>74</output>
<result>A</result> | A | 74 | For a certain exam,a score of 58 was 2 standard deviations below mean and a score of 98 was 3 standard deviations above mean.What was the mean score Q for the exam? | {
"A": "74",
"B": "76",
"C": "78",
"D": "80",
"E": "82"
} | divide(add(multiply(58, 3), multiply(98, 2)), add(2, 3)) | add(n1,n3)|multiply(n0,n3)|multiply(n1,n2)|add(#1,#2)|divide(#3,#0) | a score of 58 was 2 standard deviations below the mean - - > 58 = mean - 2 d a score of 98 was 3 standard deviations above the mean - - > 98 = mean + 3 d solving above for mean q = 74 . answer : a . | general |
math_qa__ZR01HN8qynmRwx3P | The standard deviation of a normal distribution of data is 2, and 3 standard deviations below the mean is greater than 47. What is a possible value for the mean of the distribution? Select: A) 46 B) 54 C) 48 D) 49 E) 50 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">47 + 6</gadget>
<output>53</output>
<gadget id="calculator">53 + 1</gadget>
<output>54</output>
<result>B</result> | B | 54 | The standard deviation of a normal distribution of data is 2, and 3 standard deviations below the mean is greater than 47. What is a possible value for the mean of the distribution? | {
"A": "46",
"B": "54",
"C": "48",
"D": "49",
"E": "50"
} | add(add(47, multiply(3, 2)), const_1) | multiply(n0,n1)|add(n2,#0)|add(#1,const_1) | the standard deviation ( { sd } ) = 2 ; 3 standard deviations below the mean is greater than 47 : { mean } - 3 * { sd } > 47 ; { mean } - 6 > 47 ; { mean } > 53 . answer : b . | general |
math_qa__yJJrFhWfSXsUa0Ys | A cycle is bought for Rs.900 and sold for Rs.1120, find the gain percent? Pick one.
A) 11 B) 24 C) 99 D) 77 E) 18 | <gadget id="calculator">1_120 - 900</gadget>
<output>220</output>
<gadget id="calculator">220 / 900</gadget>
<output>11/45 = around 0.244444</output>
<gadget id="calculator">(11/45) * 100</gadget>
<output>220/9 = around 24.444444</output>
<result>B</result> | B | 24 | A cycle is bought for Rs.900 and sold for Rs.1120, find the gain percent? | {
"A": "11",
"B": "24",
"C": "99",
"D": "77",
"E": "18"
} | multiply(divide(subtract(1120, 900), 900), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "900 - - - - 220 100 - - - - ? = > 24 % answer : b" | gain |
math_qa__WnJgPKOQmGFjV5af | The ratio between the sale price and the cost price of an article is 4:3. What is the ratio between the profit and the cost price of that article? Choose the correct choice
A) 2 : 9 B) 2 : 5 C) 3 : 6 D) 2 : 0 E) 1 : 3 | <gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<result>E</result> | E | 0.333333 | The ratio between the sale price and the cost price of an article is 4:3. What is the ratio between the profit and the cost price of that article? | {
"A": "2 : 9",
"B": "2 : 5",
"C": "3 : 6",
"D": "2 : 0",
"E": "1 : 3"
} | divide(subtract(4, 3), 3) | subtract(n0,n1)|divide(#0,n1)| | "let c . p . = rs . 3 x and s . p . = rs . 4 x . then , gain = rs . x required ratio = x : 3 x = 1 : 3 answer : e" | other |
math_qa__me8WmHaSfbMf342c | Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 27 seconds. What is the length of each train (in meters)? Choose the correct choice from the following answers
A) 50.5 B) 88.5 C) 37.5 D) 55.5 E) 23.5 | <gadget id="calculator">46 - 36</gadget>
<output>10</output>
<gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 3_600</gadget>
<output>25/9 = around 2.777778</output>
<gadget id="calculator">(25/9) * 27</gadget>
<output>75</output>
<gadget id="calculator">75 / 2</gadget>
<output>75/2 = around 37.5</output>
<result>C</result> | C | 37.5 | Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 27 seconds. What is the length of each train (in meters)? | {
"A": "50.5",
"B": "88.5",
"C": "37.5",
"D": "55.5",
"E": "23.5"
} | divide(multiply(divide(multiply(subtract(46, 36), const_1000), const_3600), 27), const_2) | subtract(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n2,#2)|divide(#3,const_2)| | "the relative speed = 46 - 36 = 10 km / hr = 10 * 5 / 18 = 25 / 9 m / s in 27 seconds , the relative difference in distance traveled is 27 * 25 / 9 = 75 meters this distance is twice the length of each train . the length of each train is 75 / 2 = 37.5 meters the answer is c ." | physics |
math_qa__bDrrnR0Ezm6ghm4h | The average of 35 numbers is 25. If each number is multiplied by 5, find the new average?
Choices:
A) 125
B) 189
C) 297
D) 267
E) 298 | <gadget id="calculator">25 * 5</gadget>
<output>125</output>
<result>A</result> | A | 125 | The average of 35 numbers is 25. If each number is multiplied by 5, find the new average? | {
"A": "125",
"B": "189",
"C": "297",
"D": "267",
"E": "298"
} | multiply(25, 5) | multiply(n1,n2)| | "sum of the 35 numbers = 35 * 25 = 875 if each number is multiplied by 5 , the sum also gets multiplied by 5 and the average also gets multiplied by 5 . thus , the new average = 25 * 5 = 125 . answer : a" | general |
math_qa__vZgsC3tb2n6NNNl7 | The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 50 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam.
Pick one:
A) 20 B) 27 C) 25 D) 99 E) 21 | <gadget id="calculator">90 * 5</gadget>
<output>450</output>
<gadget id="calculator">5 * 50</gadget>
<output>250</output>
<gadget id="calculator">450 - 250</gadget>
<output>200</output>
<gadget id="calculator">90 - 80</gadget>
<output>10</output>
<gadget id="calculator">200 / 10</gadget>
<output>20</output>
<result>A</result> | A | 20 | The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 50 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam. | {
"A": "20",
"B": "27",
"C": "25",
"D": "99",
"E": "21"
} | divide(subtract(multiply(90, 5), multiply(5, 50)), subtract(90, 80)) | multiply(n1,n3)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)| | "let the number of students who wrote the exam be x . total marks of students = 80 x . total marks of ( x - 5 ) students = 90 ( x - 5 ) 80 x - ( 5 * 50 ) = 90 ( x - 5 ) 200 = 10 x = > x = 20 . answer : a" | general |
math_qa__OFcMAkJi3E1WGWoY | P, Q and R have Rs.4000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R? Answers:
A) rs . 3000 B) rs . 1600 C) rs . 2400 D) rs . 4000 E) none of these | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 + (2/3)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">4_000 / (5/3)</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 * (2/3)</gadget>
<output>1_600</output>
<result>B</result> | B | 1,600 | P, Q and R have Rs.4000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R? | {
"A": "rs . 3000",
"B": "rs . 1600",
"C": "rs . 2400",
"D": "rs . 4000",
"E": "none of these"
} | multiply(divide(4000, add(const_1, divide(const_2, const_3))), divide(const_2, const_3)) | divide(const_2,const_3)|add(#0,const_1)|divide(n0,#1)|multiply(#2,#0)| | "let the amount with r be rs . r r = 2 / 3 ( total amount with p and q ) r = 2 / 3 ( 4000 - r ) = > 3 r = 8000 - 2 r = > 5 r = 8000 = > r = 1600 . answer : b" | general |
math_qa__2seL7QNLyeQFcwdD | Two friends A, B decided to share a lot of apples. Each of them had half of the total plus half an apple in order. After each of them took their share 4 time, no apples were left.How many apples were there? Pick one.
A) 250 B) 255 C) 254 D) 253 E) 251 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">2 ** 8</gadget>
<output>256</output>
<gadget id="calculator">256 - 1</gadget>
<output>255</output>
<result>E</result> | E | 251 | Two friends A, B decided to share a lot of apples. Each of them had half of the total plus half an apple in order. After each of them took their share 4 time, no apples were left.How many apples were there? | {
"A": "250",
"B": "255",
"C": "254",
"D": "253",
"E": "251"
} | subtract(power(const_2, multiply(4, const_2)), const_1) | multiply(n0,const_2)|power(const_2,#0)|subtract(#1,const_1) | whenever the rate of reduction is ' half of the total and half of it ' , the answer is always ( 2 ^ n ) - 1 , where ' n ' is the number of times the process is repeated . here , the process is repeated 8 times . so answer is ( 2 ^ 8 ) - 1 = 255 answer : e | general |
math_qa__6RaqY7VyWypo6zyM | Find the simple interest on $10000 at 9% per annum for 12 months? Select.
A) $ 410 B) $ 500 C) $ 650 D) $ 710 E) $ 900 | <gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">10_000 * (9/100)</gadget>
<output>900</output>
<result>E</result> | E | 900 | Find the simple interest on $10000 at 9% per annum for 12 months? | {
"A": "$ 410",
"B": "$ 500",
"C": "$ 650",
"D": "$ 710",
"E": "$ 900"
} | multiply(10000, divide(9, const_100)) | divide(n1,const_100)|multiply(n0,#0) | p = $ 10000 r = 9 % t = 12 / 12 years = 1 year s . i . = p * r * t / 100 = 10000 * 9 * 1 / 100 = $ 900 answer is e | gain |
math_qa__fUGnZQbVURO0WTkz | How many multiples of 4 are there between 64 and 256 ? Choose the correct choice from the following options.
A) 47
B) 49
C) 42
D) 41
E) 40 | <gadget id="calculator">256 - 64</gadget>
<output>192</output>
<gadget id="calculator">192 / 4</gadget>
<output>48</output>
<gadget id="calculator">48 + 1</gadget>
<output>49</output>
<result>A</result> | A | 47 | How many multiples of 4 are there between 64 and 256 ? | {
"A": "47",
"B": "49",
"C": "42",
"D": "41",
"E": "40"
} | add(divide(subtract(256, 64), 4), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "it should be mentioned whether 64 and 256 are inclusive . if 64 and 256 are inclusive , then the answer is ( 256 - 64 ) / 4 + 1 = 49 . if 64 and 256 are not inclusive , then the answer is ( 252 - 68 ) / 4 + 1 = 47 . since oa is a , then we have not inclusive case ." | general |
math_qa__Wxtjle2IfLlWTcw3 | At the end of the month, a certain ocean desalination plant’s reservoir contained 14 million gallons of water. This amount is twice the normal level. If this amount represents 70% of the reservoir’s total capacity, how many million gallons short of total capacity is the normal level? Select:
A) 2 B) 5 C) 10 D) 12 E) 15 | <gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">7 / (7/10)</gadget>
<output>10</output>
<result>C</result> | C | 10 | At the end of the month, a certain ocean desalination plant’s reservoir contained 14 million gallons of water. This amount is twice the normal level. If this amount represents 70% of the reservoir’s total capacity, how many million gallons short of total capacity is the normal level? | {
"A": "2",
"B": "5",
"C": "10",
"D": "12",
"E": "15"
} | divide(divide(14, const_2), divide(70, const_100)) | divide(n0,const_2)|divide(n1,const_100)|divide(#0,#1) | the q talks of total capacity , normal level , present level , shortage etc . . so it is all about not going wrong in these terms 14 mg = 70 % of total . . total = 14 / . 7 = 20 mg . . normal level = 1 / 2 of 20 = 10 mg . . shortage of normal level = 20 - 10 = 10 mg . . c | general |
math_qa__OXMVoYeN3H7opw5W | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 14% microphotonics; 24% home electronics; 10% food additives; 29% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? Choose one
A) 8 ° B) 10 ° C) 18 ° D) 54 ° E) 52 ° | <gadget id="calculator">14 + 24</gadget>
<output>38</output>
<gadget id="calculator">38 + 10</gadget>
<output>48</output>
<gadget id="calculator">48 + 29</gadget>
<output>77</output>
<gadget id="calculator">77 + 8</gadget>
<output>85</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">15 * 360</gadget>
<output>5_400</output>
<gadget id="calculator">5_400 / 100</gadget>
<output>54</output>
<result>D</result> | D | 54 | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 14% microphotonics; 24% home electronics; 10% food additives; 29% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? | {
"A": "8 °",
"B": "10 °",
"C": "18 °",
"D": "54 °",
"E": "52 °"
} | divide(multiply(subtract(const_100, add(add(add(add(14, 24), 10), 29), 8)), divide(const_3600, const_10)), const_100) | add(n0,n1)|divide(const_3600,const_10)|add(n2,#0)|add(n3,#2)|add(n4,#3)|subtract(const_100,#4)|multiply(#1,#5)|divide(#6,const_100)| | "14 % microphotonics ; 24 % home electronics ; 10 % food additives ; 29 % genetically modified microorganisms ; 8 % industrial lubricants ; 100 - ( 14 + 24 + 10 + 29 + 8 ) = 15 % basic astrophysics . 15 % of 360 ° is 54 ° . answer : d ." | gain |
math_qa__3cW2nFFvnOopExXv | F and E are midpoints of AB and AD respectively. If the side of square ABCD is 8, what is the area of triangle CEF? Choose one
A) 8 √ 2 B) 9 √ 3 C) 18 D) 16 √ 2 E) 24 | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">(4 * 8) / 2</gadget>
<output>16</output>
<gadget id="calculator">64 - 16</gadget>
<output>48</output>
<gadget id="calculator">48 - 16</gadget>
<output>32</output>
<gadget id="calculator">(4 * 4) / 2</gadget>
<output>8</output>
<gadget id="calculator">32 - 8</gadget>
<output>24</output>
<result>E</result> | E | 24 | F and E are midpoints of AB and AD respectively. If the side of square ABCD is 8, what is the area of triangle CEF? | {
"A": "8 √ 2",
"B": "9 √ 3",
"C": "18",
"D": "16 √ 2",
"E": "24"
} | subtract(subtract(subtract(square_area(8), triangle_area(divide(8, const_2), 8)), triangle_area(divide(8, const_2), 8)), triangle_area(divide(8, const_2), divide(8, const_2))) | divide(n0,const_2)|square_area(n0)|triangle_area(n0,#0)|triangle_area(#0,#0)|subtract(#1,#2)|subtract(#4,#2)|subtract(#5,#3) | area of shaded figure = area of square - ( area of triangle aef + area of triangle fbc + area of triangle edc ) = 8 * 8 - ( 1 / 2 * 4 * 4 + 1 / 2 * 4 * 8 + 1 / 2 * 4 * 8 ) = 24 . answer e . | geometry |
math_qa__GwuFaogHCOlJQrhe | Two trains of length 120 meter and 150 meter crosses a stationary man in 10 and 15 seconds respectively. In what time they will cross each other when they are moving in same direction. Pick
A) 120 sec B) 125 sec C) 135 sec D) 140 sec E) none of these | <gadget id="calculator">150 + 120</gadget>
<output>270</output>
<gadget id="calculator">120 / 10</gadget>
<output>12</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<gadget id="calculator">12 - 10</gadget>
<output>2</output>
<gadget id="calculator">270 / 2</gadget>
<output>135</output>
<result>C</result> | C | 135 | Two trains of length 120 meter and 150 meter crosses a stationary man in 10 and 15 seconds respectively. In what time they will cross each other when they are moving in same direction. | {
"A": "120 sec",
"B": "125 sec",
"C": "135 sec",
"D": "140 sec",
"E": "none of these"
} | divide(add(150, 120), subtract(divide(120, 10), divide(150, 15))) | add(n0,n1)|divide(n0,n2)|divide(n1,n3)|subtract(#1,#2)|divide(#0,#3) | explanation : 120 = a * 10 , a = 12 m / sec ( speed of first train ) 150 = b * 15 , b = 10 m / sec ( speed of second train ) 270 = ( 2 ) * t , t = 135 seconds answer – c | physics |
math_qa__2uhPguJJvaVQLotc | A, B two inlet pipes takes 15,18 minutes to fill the tank and C an oulet pipe takes 45 minutes to empty the tank respectively. In what time the tank be filled if all of them are operated together? Choose the correct choice from the following answers:
A) 11 minutes B) 10 minutes C) 12 minutes D) 13 minutes E) 14 minutes | <gadget id="calculator">45 / 3</gadget>
<output>15</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">3 + 15</gadget>
<output>18</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/15) + (1/18)</gadget>
<output>11/90 = around 0.122222</output>
<gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">(11/90) - (1/45)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / (1/10)</gadget>
<output>10</output>
<result>B</result> | B | 10 | A, B two inlet pipes takes 15,18 minutes to fill the tank and C an oulet pipe takes 45 minutes to empty the tank respectively. In what time the tank be filled if all of them are operated together? | {
"A": "11 minutes",
"B": "10 minutes",
"C": "12 minutes",
"D": "13 minutes",
"E": "14 minutes"
} | divide(const_1, subtract(add(divide(const_1, divide(45, const_3)), divide(const_1, add(const_3, divide(45, const_3)))), divide(const_1, 45))) | divide(n1,const_3)|divide(const_1,n1)|add(#0,const_3)|divide(const_1,#0)|divide(const_1,#2)|add(#3,#4)|subtract(#5,#1)|divide(const_1,#6) | lcm = 90 no of days = [ 90 / ( 90 / 15 + 90 / 18 - 90 / 45 ) = [ 90 / ( 6 + 5 - 2 ) ] = [ 90 / 9 ] = 10 minutes answer : b | physics |
math_qa__Cvc468efalIOsk8K | A car traveled from San Diego to San Francisco at an average speed of 63 miles per hour. If the journey back took twice as long, what was the average speed of the trip?
Choices: A) 24 . B) 32 . C) 36 . D) 42 . E) 44 . | <gadget id="calculator">1 / 63</gadget>
<output>1/63 = around 0.015873</output>
<gadget id="calculator">(1/63) / 2</gadget>
<output>1/126 = around 0.007937</output>
<gadget id="calculator">(1/63) + (1/126)</gadget>
<output>1/42 = around 0.02381</output>
<gadget id="calculator">1 / (1/42)</gadget>
<output>42</output>
<result>D</result> | D | 42 | A car traveled from San Diego to San Francisco at an average speed of 63 miles per hour. If the journey back took twice as long, what was the average speed of the trip? | {
"A": "24 .",
"B": "32 .",
"C": "36 .",
"D": "42 .",
"E": "44 ."
} | inverse(add(inverse(63), divide(inverse(63), const_2))) | inverse(n0)|divide(#0,const_2)|add(#1,#0)|inverse(#2)| | "let the time taken be = x one way distance = 63 x total distance traveled = 2 * 63 x = 126 x total time taken = x + 2 x = 3 x average speed = 126 x / 3 x = 42 answer : d" | physics |
math_qa__iMZBiO4bXxTi4ZMk | At the opening of a trading day at a certain stock exchange, the price per share of stock K was $6. If the price per share of stock K was $8 at the closing of the day, what was the percent increase in the price per share of stock K for that day? Select
A) 1.4 % B) 5.9 % C) 11.1 % D) 12.5 % E) 33.33 % | <gadget id="calculator">8 / 6</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) - 1</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33.33 | At the opening of a trading day at a certain stock exchange, the price per share of stock K was $6. If the price per share of stock K was $8 at the closing of the day, what was the percent increase in the price per share of stock K for that day? | {
"A": "1.4 %",
"B": "5.9 %",
"C": "11.1 %",
"D": "12.5 %",
"E": "33.33 %"
} | multiply(subtract(divide(8, 6), const_1), const_100) | divide(n1,n0)|subtract(#0,const_1)|multiply(#1,const_100)| | "opening = 6 closing = 8 rise in price = 2 so , percent increase = 2 / 6 * 100 = 33.33 % answer : e" | general |
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