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100B
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stringlengths 7
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math_qa__NxzlwJAut3Cb3SDU | On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent R of thatbeforeJuly 1 last year? Choose the correct choice from the following answers
A) 90 %
B) 99 %
C) 100 %
D) 101 %
E) 110 % | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<result>B</result> | B | 99 | On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent R of thatbeforeJuly 1 last year? | {
"A": "90 %",
"B": "99 %",
"C": "100 %",
"D": "101 %",
"E": "110 %"
} | multiply(10, 10) | multiply(n1,n1) | the total number of employees = n the average salary = x total salary to all emplyoees = xn after the total number of employees = n - 0.1 n = 0.9 n the average salary = x + 10 % of x = 1.1 x total salary to all emplyoees = 0.9 n ( 1.1 x ) total salary after as a % of total salary before r = [ 0.9 n ( 1.1 x ) ] / xn = 0.99 or 99 % . b | general |
math_qa__APIXCDdjIMph2mFm | 3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 140kg then find the average weight of all the 7 rounds? Choose the correct choice from the following answers.
A) 98.5 kgs
B) 80 kgs
C) 76.5 kgs
D) 67.5 kgs
E) 58.2 kgs | <gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 140</gadget>
<output>560</output>
<gadget id="calculator">560 / 7</gadget>
<output>80</output>
<result>B</result> | B | 80 | 3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 140kg then find the average weight of all the 7 rounds? | {
"A": "98.5 kgs",
"B": "80 kgs",
"C": "76.5 kgs",
"D": "67.5 kgs",
"E": "58.2 kgs"
} | divide(multiply(add(const_1, 3), 140), 7) | add(const_1,n0)|multiply(n2,#0)|divide(#1,n1)| | "average weight = [ ( a + b + c + ( a + b ) + ( b + c ) + ( c + a ) + ( a + b + c ) ] / 7 = 4 ( a + b + c ) / 7 = 4 x 140 / 7 = 80 kgs answer : b" | general |
math_qa__PgrZuC0rdylhlP1z | What is the greatest of 3 consecutive integers whose sum is 21 ? Pick one: A) 6 B) 7 C) 8 D) 9 E) 5 | <gadget id="calculator">21 - 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<result>C</result> | C | 8 | What is the greatest of 3 consecutive integers whose sum is 21 ? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "5"
} | add(divide(subtract(21, 3), 3), const_2) | subtract(n1,n0)|divide(#0,n0)|add(#1,const_2)| | "the sum of three consecutive integers can be written as n + ( n + 1 ) + ( n + 2 ) = 3 n + 3 if the sum is 24 , we need to solve the equation 3 n + 3 = 21 ; = > 3 n = 18 ; = > n = 6 the greatest of the three numbers is therefore 6 + 2 = 8 answer : c" | physics |
math_qa__HpBtvFfeBE5wkROa | Speed of a boat in standing water is 8 kmph and the speed of the stream is 2 kmph. A man rows to place at a distance of 210 km and comes back to the starting point. The total time taken by him is: Options.
A) 48 hours
B) 51 hours
C) 36 hours
D) 56 hours
E) none | <gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">210 / 10</gadget>
<output>21</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">210 / 6</gadget>
<output>35</output>
<gadget id="calculator">21 + 35</gadget>
<output>56</output>
<result>D</result> | D | 56 | Speed of a boat in standing water is 8 kmph and the speed of the stream is 2 kmph. A man rows to place at a distance of 210 km and comes back to the starting point. The total time taken by him is: | {
"A": "48 hours",
"B": "51 hours",
"C": "36 hours",
"D": "56 hours",
"E": "none"
} | add(divide(210, add(8, 2)), divide(210, subtract(8, 2))) | add(n0,n1)|subtract(n0,n1)|divide(n2,#0)|divide(n2,#1)|add(#2,#3)| | "sol . speed upstream = 6 kmph ; speed downstream = 10 kmph . ∴ total time taken = [ 210 / 6 + 210 / 10 ] hours = 56 hours . answer d" | physics |
math_qa__qdtrbb5YfsdOaolY | Find the annual income derived by investing $ 6800 in 20% stock at 136. Choose the correct choice from the following options: A) 550 B) 1000 C) 2500 D) 300 E) 4000 | <gadget id="calculator">6_800 * 20</gadget>
<output>136_000</output>
<gadget id="calculator">136_000 / 136</gadget>
<output>1_000</output>
<result>B</result> | B | 1,000 | Find the annual income derived by investing $ 6800 in 20% stock at 136. | {
"A": "550",
"B": "1000",
"C": "2500",
"D": "300",
"E": "4000"
} | divide(multiply(6800, 20), 136) | multiply(n0,n1)|divide(#0,n2)| | "by investing $ 136 , income obtained = $ 20 . by investing $ 6800 , income obtained = $ [ ( 20 / 136 ) * 6800 ] = $ 1000 . answer b ." | gain |
math_qa__rZWmUbPDwlIpJKfN | A man can row his boat with the stream at 16 km/h and against the stream in 6 km/h. The man's rate is?
Pick.
A) 5 kmph B) 6 kmph C) 7 kmph D) 4 kmph E) 9 kmph | <gadget id="calculator">16 - 6</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>A</result> | A | 5 | A man can row his boat with the stream at 16 km/h and against the stream in 6 km/h. The man's rate is? | {
"A": "5 kmph",
"B": "6 kmph",
"C": "7 kmph",
"D": "4 kmph",
"E": "9 kmph"
} | divide(subtract(16, 6), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "explanation : ds = 16 us = 6 s = ? s = ( 16 - 6 ) / 2 = 5 kmph answer : a" | gain |
math_qa__Zak4ZjQvYACGluaO | If the compound interest on a certain sum of money for 4 years at 10% per annum be Rs. 993, what would be the simple interest? Choose the most appropriate option.
A) rs . 880 B) rs . 890 C) rs . 1200 D) rs . 900 E) none | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">300 * 10</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 * 10</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 * 4</gadget>
<output>120_000</output>
<gadget id="calculator">120_000 / 100</gadget>
<output>1_200</output>
<result>C</result> | C | 1,200 | If the compound interest on a certain sum of money for 4 years at 10% per annum be Rs. 993, what would be the simple interest? | {
"A": "rs . 880",
"B": "rs . 890",
"C": "rs . 1200",
"D": "rs . 900",
"E": "none"
} | divide(multiply(multiply(multiply(multiply(const_3.0, const_100), 10), 10), 4), const_100) | multiply(const_3.0,const_100)|multiply(n1,#0)|multiply(n1,#1)|multiply(n0,#2)|divide(#3,const_100)| | "let p = principal a - amount we have a = p ( 1 + r / 100 ) 3 and ci = a - p atq 993 = p ( 1 + r / 100 ) 3 - p ? p = 3000 / - now si @ 10 % on 3000 / - for 4 yrs = ( 3000 x 10 x 4 ) / 100 = 1200 / - answer : c ." | gain |
math_qa__Po9TMTzjR9b8LTuX | Jar A has 16% more marbles than Jar B . What percent of marbles from Jar A need to be moved into Jar B so that both jars have equal marbles? Choose the correct option:
A) 5 %
B) 7 %
C) 9 %
D) 11 %
E) 13 % | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">16 + 100</gadget>
<output>116</output>
<gadget id="calculator">8 / 116</gadget>
<output>2/29 = around 0.068966</output>
<gadget id="calculator">(2/29) * 100</gadget>
<output>200/29 = around 6.896552</output>
<result>B</result> | B | 7 | Jar A has 16% more marbles than Jar B . What percent of marbles from Jar A need to be moved into Jar B so that both jars have equal marbles? | {
"A": "5 %",
"B": "7 %",
"C": "9 %",
"D": "11 %",
"E": "13 %"
} | multiply(divide(divide(16, const_2), add(16, const_100)), const_100) | add(n0,const_100)|divide(n0,const_2)|divide(#1,#0)|multiply(#2,const_100) | an easy way to solve this question is by number plugging . assume there are 100 marbles in jar b then in jar a there will be 116 marbles . now , for both jars to have equal marbles we should move 8 marbles from a to b , which is 8 / 116 = ~ 7 % of a . answer : b . | gain |
math_qa__Kx8HsRvtWlm2wvdO | A merchant marks goods up by 75% and then offers a discount on the marked price. The profit that the merchant makes after offering the discount is 5%. What % discount did the merchant offer?
Choose the correct choice from the following: A) 20 % B) 25 % C) 35 % D) 40 % E) 45 % | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 + (3/4)</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">(7/4) - 1</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(3/4) - (1/20)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) / (7/4)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>D</result> | D | 40 | A merchant marks goods up by 75% and then offers a discount on the marked price. The profit that the merchant makes after offering the discount is 5%. What % discount did the merchant offer? | {
"A": "20 %",
"B": "25 %",
"C": "35 %",
"D": "40 %",
"E": "45 %"
} | multiply(divide(subtract(subtract(add(const_1, divide(75, const_100)), const_1), divide(5, const_100)), add(const_1, divide(75, const_100))), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(#2,const_1)|subtract(#3,#1)|divide(#4,#2)|multiply(#5,const_100)| | "let p be the original price of the goods and let x be the rate after the markup . ( 1.75 p ) * x = 1.05 p x = 1.05 / 1.75 = 0.6 which is a discount of 40 % . the answer is d ." | gain |
math_qa__j0Sf5BgCmDBRCUue | Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.17 per cubic meter? Choose the correct choice from the following answers:
A) 2998
B) 2799
C) 2890
D) 1683
E) 2780 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">pi * ((3/2) ** 2) * 14</gadget>
<output>63*pi/2 = around 98.960169</output>
<gadget id="calculator">(63*pi/2) * 17</gadget>
<output>1071*pi/2 = around 1_682.322866</output>
<result>D</result> | D | 1,683 | Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.17 per cubic meter? | {
"A": "2998",
"B": "2799",
"C": "2890",
"D": "1683",
"E": "2780"
} | multiply(volume_cylinder(divide(3, const_2), 14), 17) | divide(n1,const_2)|volume_cylinder(#0,n0)|multiply(n2,#1)| | "22 / 7 * 14 * 3 / 2 * 3 / 2 = 99 m 2 99 * 17 = 1683 answer : d" | physics |
math_qa__VBQ9KPqHiejsJwZE | If (27/4)x - 18 = 3x+27
what is the value of x? Select the correct option
A) 12 B) - 12 C) 1 / 12 D) - 1 / 12 E) 3 | <gadget id="calculator">27 + 18</gadget>
<output>45</output>
<gadget id="calculator">27 / 4</gadget>
<output>27/4 = around 6.75</output>
<gadget id="calculator">(27/4) - 3</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">45 / (15/4)</gadget>
<output>12</output>
<result>A</result> | A | 12 | If (27/4)x - 18 = 3x+27
what is the value of x? | {
"A": "12",
"B": "- 12",
"C": "1 / 12",
"D": "- 1 / 12",
"E": "3"
} | divide(add(27, 18), subtract(divide(27, 4), 3)) | add(n0,n2)|divide(n0,n1)|subtract(#1,n3)|divide(#0,#2) | ( 27 / 4 ) x - 18 = 3 x + 27 = > 27 x - 72 = 12 x + 108 = > 15 x = 180 = > x = 12 answer : a | general |
math_qa__pqC2R1QWnHIcAlEV | If the average marks of 3classes of 55, 60 and 45 students respectively is 50, 55, 60, then find the average marksof all the students is Choose the correct choice from the following choices
A) 53 B) 53.5 C) 54.68 D) 55.6 E) 67.2 | <gadget id="calculator">55 * 50</gadget>
<output>2_750</output>
<gadget id="calculator">60 * 55</gadget>
<output>3_300</output>
<gadget id="calculator">2_750 + 3_300</gadget>
<output>6_050</output>
<gadget id="calculator">45 * 60</gadget>
<output>2_700</output>
<gadget id="calculator">6_050 + 2_700</gadget>
<output>8_750</output>
<gadget id="calculator">55 + 50</gadget>
<output>105</output>
<gadget id="calculator">60 + 105</gadget>
<output>165</output>
<gadget id="calculator">8_750 / 165</gadget>
<output>1_750/33 = around 53.030303</output>
<result>C</result> | C | 54.68 | If the average marks of 3classes of 55, 60 and 45 students respectively is 50, 55, 60, then find the average marksof all the students is | {
"A": "53",
"B": "53.5",
"C": "54.68",
"D": "55.6",
"E": "67.2"
} | divide(add(add(multiply(55, 50), multiply(60, 55)), multiply(45, 60)), add(60, add(55, 50))) | add(n1,n4)|multiply(n1,n4)|multiply(n1,n2)|multiply(n2,n3)|add(#1,#2)|add(n2,#0)|add(#4,#3)|divide(#6,#5) | required average = 55 x 50 + 60 x 55 + 45 x 60 55 + 60 + 45 = 2750 + 3300 + 2700 160 = 8750 160 = 54.68 c | general |
math_qa__d3Bw2LTDibULe5gN | The batting average of a particular batsman is 63 runs in 46 innings. If the difference in his highest and lowest score is 150 runs and his average excluding these two innings is 58 runs, find his highest score.
Choose the most appropriate option
A) 179 B) 208 C) 210 D) 223 E) 248 | <gadget id="calculator">63 * 46</gadget>
<output>2_898</output>
<gadget id="calculator">46 - 2</gadget>
<output>44</output>
<gadget id="calculator">58 * 44</gadget>
<output>2_552</output>
<gadget id="calculator">2_898 - 2_552</gadget>
<output>346</output>
<gadget id="calculator">150 + 346</gadget>
<output>496</output>
<gadget id="calculator">496 / 2</gadget>
<output>248</output>
<result>E</result> | E | 248 | The batting average of a particular batsman is 63 runs in 46 innings. If the difference in his highest and lowest score is 150 runs and his average excluding these two innings is 58 runs, find his highest score. | {
"A": "179",
"B": "208",
"C": "210",
"D": "223",
"E": "248"
} | divide(add(150, subtract(multiply(63, 46), multiply(58, subtract(46, const_2)))), const_2) | multiply(n0,n1)|subtract(n1,const_2)|multiply(n3,#1)|subtract(#0,#2)|add(n2,#3)|divide(#4,const_2) | explanation : total runs scored by the batsman = 63 * 46 = 2898 runs now excluding the two innings the runs scored = 58 * 44 = 2552 runs hence the runs scored in the two innings = 2898 – 2552 = 346 runs . let the highest score be x , hence the lowest score = x – 150 x + ( x - 150 ) = 346 2 x = 496 x = 248 runs answer e | general |
math_qa__mEFwWtEvQE13bg2S | A lady builds 10cm length, 13cm width, and 5cm height box using 5cubic cm cubes. What is the minimum number of cubes required to build the box?
Choose one:
A) 107 B) 108 C) 130 D) 150 E) 145 | <gadget id="calculator">10 * 13</gadget>
<output>130</output>
<gadget id="calculator">130 * 5</gadget>
<output>650</output>
<gadget id="calculator">650 / 5</gadget>
<output>130</output>
<result>C</result> | C | 130 | A lady builds 10cm length, 13cm width, and 5cm height box using 5cubic cm cubes. What is the minimum number of cubes required to build the box? | {
"A": "107",
"B": "108",
"C": "130",
"D": "150",
"E": "145"
} | divide(multiply(multiply(10, 13), 5), 5) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n3)| | "number of cubes required = volume of box / volume of cube = 10 * 13 * 5 / 5 = 130 cubes answer : c" | geometry |
math_qa__hqmx9m9NGcnbmMSV | A train 275 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? Choose the correct choice: A) 8 B) 6 C) 5 D) 15 E) 1 | <gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">66 * (5/18)</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">275 / (55/3)</gadget>
<output>15</output>
<result>D</result> | D | 15 | A train 275 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? | {
"A": "8",
"B": "6",
"C": "5",
"D": "15",
"E": "1"
} | divide(275, multiply(add(60, 6), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 60 + 6 = 66 km / hr . = 66 * 5 / 18 = 55 / 3 m / sec . time taken to pass the men = 275 * 3 / 55 = 15 sec . answer : d" | physics |
math_qa__67kcnfqboAdQscvS | When 2 + 3 = 65, 3 + 4 = 125, 4 + 5 = 205, then 5 + 6 = ? Choose one.
A) 285 B) 305 C) 315 D) 350 E) 245 | <gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">30 * 10</gadget>
<output>300</output>
<gadget id="calculator">300 + 2</gadget>
<output>302</output>
<result>B</result> | B | 305 | When 2 + 3 = 65, 3 + 4 = 125, 4 + 5 = 205, then 5 + 6 = ? | {
"A": "285",
"B": "305",
"C": "315",
"D": "350",
"E": "245"
} | add(multiply(multiply(5, 6), const_10), 2) | multiply(n7,n10)|multiply(#0,const_10)|add(n0,#1)| | "2 + 3 = > 2 ã — 3 = 6 = > 6 ã — 10 + 5 = 65 3 + 4 = > 3 ã — 4 = 12 = > 12 ã — 10 + 5 = 125 4 + 5 = > 4 ã — 5 = 20 = > 20 ã — 10 + 5 = 205 then 5 + 6 = > 5 ã — 6 = 30 = > 30 ã — 10 + 5 = 305 answer : b" | general |
math_qa__B0UeTkTnyMyO2w2t | What will be the difference between simple and compound interest at 12% per annum on a sum of Rs. 1000 after 4 years? Options
A) 94.19 B) 94.12 C) 93.5 D) 64.1 E) 64.11 | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) + 1</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">(28/25) ** 4</gadget>
<output>614_656/390_625 = around 1.573519</output>
<gadget id="calculator">1_000 * (614_656/390_625)</gadget>
<output>4_917_248/3_125 = around 1_573.51936</output>
<gadget id="calculator">(4_917_248/3_125) - 1_000</gadget>
<output>1_792_248/3_125 = around 573.51936</output>
<gadget id="calculator">1_000 * (3/25)</gadget>
<output>120</output>
<gadget id="calculator">120 * 4</gadget>
<output>480</output>
<gadget id="calculator">(1_792_248/3_125) - 480</gadget>
<output>292_248/3_125 = around 93.51936</output>
<result>C</result> | C | 93.5 | What will be the difference between simple and compound interest at 12% per annum on a sum of Rs. 1000 after 4 years? | {
"A": "94.19",
"B": "94.12",
"C": "93.5",
"D": "64.1",
"E": "64.11"
} | subtract(subtract(multiply(1000, power(add(divide(12, const_100), const_1), 4)), 1000), multiply(multiply(1000, divide(12, const_100)), 4)) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|multiply(n2,#2)|power(#1,n2)|multiply(n1,#4)|subtract(#5,n1)|subtract(#6,#3)| | "s . i . = ( 1000 * 12 * 4 ) / 100 = rs . 480 c . i . = [ 1000 * ( 1 + 12 / 100 ) 4 - 1000 ] = rs . 573.5 difference = ( 573.5 - 480 ) = rs . 93.5 answer : c" | gain |
math_qa__26xTxysaS0UjBusP | Q' = 3Q - 3, what is the value of (7')' ? Pick.
A) 6
B) 106
C) 206
D) 306
E) 406 | <gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">21 - 3</gadget>
<output>18</output>
<gadget id="calculator">18 * 3</gadget>
<output>54</output>
<gadget id="calculator">54 - 3</gadget>
<output>51</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">51 * 6</gadget>
<output>306</output>
<result>D</result> | D | 306 | Q' = 3Q - 3, what is the value of (7')' ? | {
"A": "6",
"B": "106",
"C": "206",
"D": "306",
"E": "406"
} | multiply(subtract(multiply(subtract(multiply(3, 7), 3), 3), 3), subtract(7, const_1)) | multiply(n0,n2)|subtract(n2,const_1)|subtract(#0,n0)|multiply(n0,#2)|subtract(#3,n0)|multiply(#4,#1)| | "( 7 ' ) ' = ( 3 * 7 - 3 ) ' = 18 ' = 18 * 18 - 18 = 306 answer d" | general |
math_qa__JkvlOJGzfhqvYNj9 | Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.50 a kg to produce a mixture worth Rs. 6.30 a kg
Pick:
A) 2 : 0 B) 2 : 3 C) 2 : 1 D) 8 : 9 E) 2 : 8 | <gadget id="calculator">6.3 - 5.5</gadget>
<output>0.8</output>
<gadget id="calculator">7.2 - 6.3</gadget>
<output>0.9</output>
<gadget id="calculator">0.8 / 0.9</gadget>
<output>0.888889</output>
<result>D</result> | D | 0.888889 | Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.50 a kg to produce a mixture worth Rs. 6.30 a kg | {
"A": "2 : 0",
"B": "2 : 3",
"C": "2 : 1",
"D": "8 : 9",
"E": "2 : 8"
} | divide(subtract(6.30, 5.50), subtract(7.20, 6.30)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "by the rule of alligation : cost of 1 kg rice of 1 st kind cost of 1 kg rice of 2 nd kind required ratio = 80 : 90 = 8 : 9 answer : d" | other |
math_qa__Hdgn8KMADAIJ8KkD | A grocer has a sale of Rs. 5400, Rs. 9000, Rs. 6300, Rs. 7200 and Rs.4500 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5600? Select the correct option: A) s . 1200 B) s . 5400 C) s . 5400 D) s . 4999 E) s . 5000 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 5_600</gadget>
<output>33_600</output>
<gadget id="calculator">5_400 + 9_000</gadget>
<output>14_400</output>
<gadget id="calculator">14_400 + 6_300</gadget>
<output>20_700</output>
<gadget id="calculator">20_700 + 7_200</gadget>
<output>27_900</output>
<gadget id="calculator">27_900 + 4_500</gadget>
<output>32_400</output>
<gadget id="calculator">33_600 - 32_400</gadget>
<output>1_200</output>
<result>A</result> | A | 1,200 | A grocer has a sale of Rs. 5400, Rs. 9000, Rs. 6300, Rs. 7200 and Rs.4500 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5600? | {
"A": "s . 1200",
"B": "s . 5400",
"C": "s . 5400",
"D": "s . 4999",
"E": "s . 5000"
} | subtract(multiply(add(5, const_1), 5600), add(add(add(add(5400, 9000), 6300), 7200), 4500)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "total sale for 5 months = rs . ( 5400 + 9000 + 6300 + 7200 + 4500 ) = rs . 32400 . required sale = rs . [ ( 5600 x 6 ) - 32400 ] = rs . ( 33600 - 32400 ) = rs . 1200 . option a" | general |
math_qa__HuYxm7IFImIumxgi | marginal cost is the cost of increasing the quantity produced ( or purchased ) by one unit . if the fixed cost for n products is $ 12000 and the marginal cost is $ 200 , and the total cost is $ 16000 , what is the value of n ? Choose the correct choice
A) 20 B) 50 C) 60 D) 80 E) 100 | <gadget id="calculator">16_000 - 12_000</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 / 200</gadget>
<output>20</output>
<result>A</result> | A | 20 | marginal cost is the cost of increasing the quantity produced ( or purchased ) by one unit . if the fixed cost for n products is $ 12000 and the marginal cost is $ 200 , and the total cost is $ 16000 , what is the value of n ? | {
"A": "20",
"B": "50",
"C": "60",
"D": "80",
"E": "100"
} | divide(subtract(16000, 12000), 200) | subtract(n2,n0)|divide(#0,n1) | total cost for n products = fixed cost for n products + n * marginal cost - - > $ 16,000 = $ 12,000 + n * $ 200 - - > n = 20 . answer : a . | general |
math_qa__BfR1HzVlPSOQx1IF | $392 is divided among A, B, and C so that A receives half as much as B, and B receives half as much as C. How much money is C's share? Choose the correct choice from the following.
A) $ 212
B) $ 216
C) $ 220
D) $ 224
E) $ 228 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) + 1</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">392 / (7/2)</gadget>
<output>112</output>
<gadget id="calculator">112 * 2</gadget>
<output>224</output>
<result>D</result> | D | 224 | $392 is divided among A, B, and C so that A receives half as much as B, and B receives half as much as C. How much money is C's share? | {
"A": "$ 212",
"B": "$ 216",
"C": "$ 220",
"D": "$ 224",
"E": "$ 228"
} | multiply(divide(392, add(add(divide(const_1, const_2), const_1), const_2)), const_2) | divide(const_1,const_2)|add(#0,const_1)|add(#1,const_2)|divide(n0,#2)|multiply(#3,const_2)| | "let the shares for a , b , and c be x , 2 x , and 4 x respectively . 7 x = 392 x = 56 4 x = 224 the answer is d ." | general |
math_qa__GzN0voSjLe3y5pgM | the cyclist walking at a constant rate of 15 miles per hour is passed by a car traveling in the same direction along the same path at 60 miles per hour. the car stops to wait for the cyclist for 6 minutes after passing her, while the cyclist continues to go at her constant rate, how many minutes must the car wait until the cyclist catches up? Choose the correct choice from the following options:
A) 9 B) 10 C) 12 D) 15 E) 18 | <gadget id="calculator">60 - 15</gadget>
<output>45</output>
<gadget id="calculator">6 / 60</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">45 * (1/10)</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(9/2) / 15</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 60</gadget>
<output>18</output>
<result>E</result> | E | 18 | the cyclist walking at a constant rate of 15 miles per hour is passed by a car traveling in the same direction along the same path at 60 miles per hour. the car stops to wait for the cyclist for 6 minutes after passing her, while the cyclist continues to go at her constant rate, how many minutes must the car wait until the cyclist catches up? | {
"A": "9",
"B": "10",
"C": "12",
"D": "15",
"E": "18"
} | multiply(divide(multiply(subtract(60, 15), divide(6, const_60)), 15), const_60) | divide(n2,const_60)|subtract(n1,n0)|multiply(#0,#1)|divide(#2,n0)|multiply(#3,const_60) | for the 6 minutes the car continues to overtake the cyclist , she is going at 45 miles per hour faster than the cyclist . once the car stops , the cyclist is going at 15 miles per hour while the car is at rest so the amount of time the cyclist will take to cover the distance between them is going to be in the ratio of the relative speeds . 45 / 15 * 6 or 18 minutes answer is ( e ) | physics |
math_qa__uBN1cdJBzXdYhQuH | The value for D=(0.889 × 55)/9.97 to the nearest tenth is Select the correct option.
A) 0.5 B) 4.63 C) 4.9 D) 7.7 E) 49.1 | <gadget id="calculator">0.889 * 55</gadget>
<output>48.895</output>
<gadget id="calculator">48.895 / 9.97</gadget>
<output>4.904213</output>
<gadget id="calculator">4.904213 * 10</gadget>
<output>49.04213</output>
<gadget id="calculator">floor(49.04213)</gadget>
<output>49</output>
<gadget id="calculator">49 / 10</gadget>
<output>49/10 = around 4.9</output>
<result>C</result> | C | 4.9 | The value for D=(0.889 × 55)/9.97 to the nearest tenth is | {
"A": "0.5",
"B": "4.63",
"C": "4.9",
"D": "7.7",
"E": "49.1"
} | divide(floor(multiply(divide(multiply(0.889, 55), 9.97), const_10)), const_10) | multiply(n0,n1)|divide(#0,n2)|multiply(#1,const_10)|floor(#2)|divide(#3,const_10) | if we read the q , we can easily home on to the answer , , the numerator is clearly between 40 and 50 . . denomiator is close to 10 . . so d = ( 0.889 × 55 ) / 9.97 is between 4 and 5 . . it may tempt us to solve it since ther are two values between 4 and 5 . . but the catch is innearest tenth 4.63 can be called nearest to hundreth and no tenth , so can be eliminated . . 4.9 is our answer . . . c | general |
math_qa__H1wuJi4bqr5K0xsJ | Find the least number which when divided by 37 and 7 leaves a remainder of 2 in each case. Answers
A) 259 B) 261 C) 263 D) 265 E) 267 | <gadget id="calculator">lcm(37, 7)</gadget>
<output>259</output>
<gadget id="calculator">2 + 259</gadget>
<output>261</output>
<result>B</result> | B | 261 | Find the least number which when divided by 37 and 7 leaves a remainder of 2 in each case. | {
"A": "259",
"B": "261",
"C": "263",
"D": "265",
"E": "267"
} | add(2, lcm(37, 7)) | lcm(n0,n1)|add(n2,#0) | the least number which when divided by different divisors leaving the same remainder in each case = lcm ( different divisors ) + remainder left in each case . hence the required least number = lcm ( 37 , 7 ) + 2 = 261 . answer : b | general |
math_qa__fJfM8obwwM3AW7F0 | A cubical tank is filled with water to a level of 1 foot. If the water in the tank occupies 16 cubic feet, to what fraction of its capacity is the tank filled with water? Choose the most appropriate option
A) 1 / 2 B) 1 / 3 C) 1 / 4 D) 1 / 5 E) 1 / 6 | <gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">4 ** 3</gadget>
<output>64</output>
<gadget id="calculator">16 / 64</gadget>
<output>1/4 = around 0.25</output>
<result>C</result> | C | 0.25 | A cubical tank is filled with water to a level of 1 foot. If the water in the tank occupies 16 cubic feet, to what fraction of its capacity is the tank filled with water? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 5",
"E": "1 / 6"
} | divide(16, volume_cube(sqrt(16))) | sqrt(n1)|volume_cube(#0)|divide(n1,#1) | the volume of water in the tank is h * l * b = 16 cubic feet . since h = 1 , then l * b = 16 and l = b = 4 . since the tank is cubical , the capacity of the tank is 4 * 4 * 4 = 64 . the ratio of the water in the tank to the capacity is 16 / 64 = 1 / 4 the answer is c . | physics |
math_qa__YyhxPIRsiX5AeYjR | A furniture store owner decided to drop the price of her recliners by 20% to spur business. By the end of the week she had sold 60% more recliners. What is the percentage increase of the gross?
Choose the correct choice.
A) 10 % B) 15 % C) 20 % D) 28 % E) 50 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 + (3/5)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(4/5) * (8/5)</gadget>
<output>32/25 = around 1.28</output>
<gadget id="calculator">(32/25) * 100</gadget>
<output>128</output>
<gadget id="calculator">128 - 100</gadget>
<output>28</output>
<result>D</result> | D | 28 | A furniture store owner decided to drop the price of her recliners by 20% to spur business. By the end of the week she had sold 60% more recliners. What is the percentage increase of the gross? | {
"A": "10 %",
"B": "15 %",
"C": "20 %",
"D": "28 %",
"E": "50 %"
} | subtract(multiply(multiply(subtract(const_1, divide(20, const_100)), add(const_1, divide(60, const_100))), const_100), const_100) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)|subtract(#5,const_100)| | "say a recliner is actually worth $ 100 if she sells 100 recliners then she earns $ 10000 after the discount of 20 % , she will earn $ 80 per recliner and she sells 60 % more ie . , 160 recliners hence her sales tields 160 * 80 = $ 12800 increase in sales = 12800 - 10000 = $ 2800 so % increase = 2800 * 100 / 10000 = 28 % d is the answer" | general |
math_qa__sMvQzJL4qgU0sEHX | 10 play kabadi, 25 play kho kho only, 5 play both gmaes. Then how many in total? Choose the correct choice: A) 30 B) 35 C) 38 D) 40 E) 45 | <gadget id="calculator">25 + 5</gadget>
<output>30</output>
<gadget id="calculator">10 + 30</gadget>
<output>40</output>
<gadget id="calculator">40 - 5</gadget>
<output>35</output>
<result>B</result> | B | 35 | 10 play kabadi, 25 play kho kho only, 5 play both gmaes. Then how many in total? | {
"A": "30",
"B": "35",
"C": "38",
"D": "40",
"E": "45"
} | subtract(add(10, add(25, 5)), 5) | add(n1,n2)|add(n0,#0)|subtract(#1,n2)| | "10 play kabadi = > n ( a ) = 10 , 5 play both gmaes . = > n ( anb ) = 5 25 play kho kho only , = > n ( b ) = n ( b only ) + n ( anb ) = 25 + 5 = 30 total = > n ( aub ) = n ( a ) + n ( b ) - n ( anb ) = 10 + 30 - 5 = 35 answer : b" | general |
math_qa__6JXirf7JZPgf3ysl | On dividing a number by 5, we get 5 as quotient and 0 as remainder. On dividing the same number by 11, what will be the remainder? Choose the correct choice from the following:
A) 5 B) 2 C) 7 D) 9 E) 3 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 % 11</gadget>
<output>3</output>
<result>E</result> | E | 3 | On dividing a number by 5, we get 5 as quotient and 0 as remainder. On dividing the same number by 11, what will be the remainder? | {
"A": "5",
"B": "2",
"C": "7",
"D": "9",
"E": "3"
} | reminder(multiply(5, 5), 11) | multiply(n0,n1)|reminder(#0,n3)| | "number = 5 * 5 + 0 = 25 11 ) 25 ( 2 22 - - - - - - - - 3 required number = 0 . answer : e" | general |
math_qa__MU5h5DGaoWFliKNA | If the area of a square with sides of length 8 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters?
Choose the correct choice from the following answers:
A) 4 B) 8 C) 12 D) 16 E) 18 | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">64 / 4</gadget>
<output>16</output>
<result>D</result> | D | 16 | If the area of a square with sides of length 8 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters? | {
"A": "4",
"B": "8",
"C": "12",
"D": "16",
"E": "18"
} | divide(power(8, const_2), 4) | power(n0,const_2)|divide(#0,n1)| | "let length of rectangle = l 8 ^ 2 = l * 4 = > l = 64 / 4 = 16 answer d" | geometry |
math_qa__dQ882VQSj2B4EkcU | In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of thesportformulation contains 5 ounces of corn syrup, how many ounces of water does it contain? Choices
A) 15 B) 30 C) 45 D) 75 E) 90 | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 3</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) / 2</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/4) / (1/60)</gadget>
<output>15</output>
<gadget id="calculator">15 * 5</gadget>
<output>75</output>
<result>D</result> | D | 75 | In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of thesportformulation contains 5 ounces of corn syrup, how many ounces of water does it contain? | {
"A": "15",
"B": "30",
"C": "45",
"D": "75",
"E": "90"
} | multiply(divide(multiply(divide(1, 12), const_3), divide(divide(1, 30), const_2)), 5) | divide(n0,n1)|divide(n0,n2)|divide(#1,const_2)|multiply(#0,const_3)|divide(#3,#2)|multiply(n3,#4) | standard : fl : corn s : water = 1 : 12 : 30 sport : fl : corn s : water = 3 : 12 : 180 this simplifies to 1 : 4 : 60 if the large bottle has a capacity of x ounces , then 4 x / 65 = 5 . so , x = 325 / 4 ounces . water = ( 60 / 65 ) * ( 325 / 4 ) = 60 * 3 / 4 = 75 ounces . ans d | other |
math_qa__Hs0XE40hurDMiSYM | Two brothers took the GMAT exam, the higher score is U and the lower one is V. If the difference between the two scores is equal to their average, what is the value of V/U ? Choose the correct option
A) 3 B) 2 C) 1 / 2 D) 1 / 3 E) there is n ' t enough data to answer the question . | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<result>D</result> | D | 0.333333 | Two brothers took the GMAT exam, the higher score is U and the lower one is V. If the difference between the two scores is equal to their average, what is the value of V/U ? | {
"A": "3",
"B": "2",
"C": "1 / 2",
"D": "1 / 3",
"E": "there is n ' t enough data to answer the question ."
} | divide(const_1, const_3) | divide(const_1,const_3) | answer is d : 1 / 3 u - v = ( u + v ) / 2 solving for v / u = 1 / 3 d | general |
math_qa__lV4iCqC52d6gT7kf | Two trains 131 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? Choose the most appropriate option
A) 7.16 B) 7.16 C) 7.12 D) 7.35 E) 7.11 | <gadget id="calculator">131 + 165</gadget>
<output>296</output>
<gadget id="calculator">80 + 65</gadget>
<output>145</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">145 * (5/18)</gadget>
<output>725/18 = around 40.277778</output>
<gadget id="calculator">296 / (725/18)</gadget>
<output>5_328/725 = around 7.348966</output>
<result>D</result> | D | 7.35 | Two trains 131 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? | {
"A": "7.16",
"B": "7.16",
"C": "7.12",
"D": "7.35",
"E": "7.11"
} | divide(add(131, 165), multiply(add(80, 65), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "t = ( 131 + 165 ) / ( 80 + 65 ) * 18 / 5 t = 7.35 answer : d" | physics |
math_qa__eq6mGPG9KETvJ56b | In the rectangular coordinate system, if the line x = 6y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p? Choices.
A) 1 / 2 B) 1 / 3 C) 1 / 4 D) 1 / 5 E) 1 / 6 | <gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<result>B</result> | B | 0.333333 | In the rectangular coordinate system, if the line x = 6y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 5",
"E": "1 / 6"
} | divide(2, 6) | divide(n2,n0)| | "x = 6 y + 5 , and thus y = x / 6 - 5 / 6 the slope is 1 / 6 . the slope of a line through points ( m , n ) and ( m + 2 , n + p ) is ( n + p - n ) / ( m + 2 - m ) = p / 2 p / 2 = 1 / 6 and thus p = 1 / 3 the answer is b ." | general |
math_qa__GTYJdabcobIpVxYK | A man can row his boat with the stream at 16 km/h and against the stream in 8 km/h. The man's rate is? Pick one.
A) 4 kmph
B) 2 kmph
C) 7 kmph
D) 8 kmph
E) 3 kmph | <gadget id="calculator">16 - 8</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>A</result> | A | 4 | A man can row his boat with the stream at 16 km/h and against the stream in 8 km/h. The man's rate is? | {
"A": "4 kmph",
"B": "2 kmph",
"C": "7 kmph",
"D": "8 kmph",
"E": "3 kmph"
} | divide(subtract(16, 8), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "ds = 16 us = 8 s = ? s = ( 16 - 8 ) / 2 = 4 kmph answer : a" | gain |
math_qa__U8xF57kmSFpOIf7M | 2.09 can be expressed in terms of percentage as Answers.
A) 2.09 %
B) 20.9 %
C) 209 %
D) 0.209 %
E) none of these | <gadget id="calculator">2.09 * 100</gadget>
<output>209</output>
<result>C</result> | C | 209 | 2.09 can be expressed in terms of percentage as | {
"A": "2.09 %",
"B": "20.9 %",
"C": "209 %",
"D": "0.209 %",
"E": "none of these"
} | multiply(2.09, const_100) | multiply(n0,const_100)| | "explanation : while calculation in terms of percentage we need to multiply by 100 , so 2.09 * 100 = 209 answer : option c" | general |
math_qa__cX8aiLaMqIeuFMnt | johnny bought 6 peanut butter cans at an average price ( arithmetic mean ) of 36.5 ¢ . if johnny returned two cans to the retailer , and the average price of the remaining cans was 30 ¢ , then what is the average price , in cents , of the two returned peanut butter cans ? Answers
A) 5.5 B) 11 C) 47.5 D) 66 E) 49.5 | <gadget id="calculator">6 * 36.5</gadget>
<output>219</output>
<gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 30</gadget>
<output>120</output>
<gadget id="calculator">219 - 120</gadget>
<output>99</output>
<gadget id="calculator">99 / 2</gadget>
<output>99/2 = around 49.5</output>
<result>E</result> | E | 49.5 | johnny bought 6 peanut butter cans at an average price ( arithmetic mean ) of 36.5 ¢ . if johnny returned two cans to the retailer , and the average price of the remaining cans was 30 ¢ , then what is the average price , in cents , of the two returned peanut butter cans ? | {
"A": "5.5",
"B": "11",
"C": "47.5",
"D": "66",
"E": "49.5"
} | divide(subtract(multiply(6, 36.5), multiply(subtract(6, const_2), 30)), const_2) | multiply(n0,n1)|subtract(n0,const_2)|multiply(n2,#1)|subtract(#0,#2)|divide(#3,const_2) | total price of six cans = 6 * 36.5 = 219 total price of 4 cans = 4 * 30 = 120 total rice of two cans = 219 - 120 = 99 average price of two cans = 99 / 2 = 49.5 c another way to do it is this : assume that the four leftover cans were of 30 c each . the avg was 36.5 c initially because the two cans were 36.5 c each and were providing another 6.5 c of cost to other 4 cans . so cost of the two cans = 2 * 36.5 + 4 * 6.5 = 99 avg cost of the two cans = 99 / 2 = 49.5 c answer ( e ) | general |
math_qa__9NoqxejEOxFpvrhU | A clockwise rotation around point Z (that is, a rotation
in the direction of the arrow) transforms the shaded
quadrilateral to the unshaded quadrilateral. The angle
of rotation is approximately Pick one:
A) 180 o B) 270 o C) 360 o D) 45 o E) 135 o | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">360 / 4</gadget>
<output>90</output>
<gadget id="calculator">360 - 90</gadget>
<output>270</output>
<result>B</result> | B | 270 | A clockwise rotation around point Z (that is, a rotation
in the direction of the arrow) transforms the shaded
quadrilateral to the unshaded quadrilateral. The angle
of rotation is approximately | {
"A": "180 o",
"B": "270 o",
"C": "360 o",
"D": "45 o",
"E": "135 o"
} | subtract(divide(const_3600, const_10), divide(divide(const_3600, const_10), const_4)) | divide(const_3600,const_10)|divide(#0,const_4)|subtract(#0,#1) | the measure of \ pzq formed by the bottom edge of the shaded quadrilateral , zq , and this same edge after the rotation , zp , is approximately 90 . the transformation of the shaded quadrilateral to the unshaded quadrilateral is a clockwise rotation around point z through an an - gle equal to the measure of re ex angle pzq . the measure of \ pzq added to the measure of re ex \ pzq is equal to the measure of one complete rotation , or 360 . therefore , the measure of re ex angle pzq is approximately 360 o - 90 o or 270 o . thus the clockwise rotation around point z is through an angle of approximately 270 o correct answer b | geometry |
math_qa__wQkHIketBLGSEsUF | The length of the bridge, which a train 120 metres long and travelling at 45 km/hr can cross in 30 seconds, is? Pick:
A) 10 m
B) 255 m
C) 245 m
D) 19 m
E) 27 m | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 120</gadget>
<output>255</output>
<result>B</result> | B | 255 | The length of the bridge, which a train 120 metres long and travelling at 45 km/hr can cross in 30 seconds, is? | {
"A": "10 m",
"B": "255 m",
"C": "245 m",
"D": "19 m",
"E": "27 m"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 120) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "speed = [ 45 x 5 / 18 ] m / sec = [ 25 / 2 ] m / sec time = 30 sec let the length of bridge be x metres . then , ( 120 + x ) / 30 = 25 / 2 = > 2 ( 120 + x ) = 750 = > x = 255 m . answer : b" | physics |
math_qa__yEvtiI3Qhr3rDLU1 | An uneducated retailer marks all his goods at 40% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales?
Choose the correct option.
A) 12.50 % B) 13.50 % C) 5 % D) 14.50 % E) none | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(7/5) * (1/4)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/5) - (7/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) - 1</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 100</gadget>
<output>5</output>
<result>C</result> | C | 5 | An uneducated retailer marks all his goods at 40% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales? | {
"A": "12.50 %",
"B": "13.50 %",
"C": "5 %",
"D": "14.50 %",
"E": "none"
} | multiply(subtract(subtract(add(const_1, divide(40, const_100)), multiply(add(const_1, divide(40, const_100)), divide(25, const_100))), const_1), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|multiply(#2,#1)|subtract(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100) | sol . let c . p . = rs . 100 . then , marked price = rs . 140 . s . p . = 75 % of rs . 140 = rs . 105 . ∴ gain % = 5 % . answer c | gain |
math_qa__lWhcj228rqafldhY | The area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm is? Select:
A) 0.35 cm 2 B) 17.5 cm 2 C) 8.75 cm 2 D) 55 cm 2 E) 50 cm 2 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">5 * 3.5</gadget>
<output>17.5</output>
<gadget id="calculator">(1/2) * 17.5</gadget>
<output>8.75</output>
<result>C</result> | C | 8.75 | The area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm is? | {
"A": "0.35 cm 2",
"B": "17.5 cm 2",
"C": "8.75 cm 2",
"D": "55 cm 2",
"E": "50 cm 2"
} | multiply(divide(const_1, const_2), multiply(5, 3.5)) | divide(const_1,const_2)|multiply(n0,n1)|multiply(#0,#1) | explanation : ( 5 * 3.5 ) / 2 = 8.75 answer is c | physics |
math_qa__xttXsrj8euKm6Ri8 | There are 16 bees in the hive , then 5 more fly. How many bees are there in all?
Select.
A) 20 B) 33 C) 12 D) 17 E) 25 | <gadget id="calculator">16 + 5</gadget>
<output>21</output>
<result>A</result> | A | 20 | There are 16 bees in the hive , then 5 more fly. How many bees are there in all? | {
"A": "20",
"B": "33",
"C": "12",
"D": "17",
"E": "25"
} | add(16, 5) | add(n0,n1)| | 16 + 5 = 20 . answer is a . | general |
math_qa__Xb9kBhLTEIIE7xE5 | For what value of x, is |x – 3| + |x + 1| + |x| = 11?
Select
A) 0 B) 3 C) - 3 D) 4 E) - 2 | <gadget id="calculator">-3</gadget>
<output>-3</output>
<result>C</result> | C | -3 | For what value of x, is |x – 3| + |x + 1| + |x| = 11? | {
"A": "0",
"B": "3",
"C": "- 3",
"D": "4",
"E": "- 2"
} | negate(3) | negate(n0) | for what value of x , is | x – 3 | + | x + 1 | + | x | = 11 ? it ' s easiest just to plug in answer choices : ( c ) : - 3 | x – 3 | + | x + 1 | + | x | = 11 ? | - 3 - 3 | + | - 3 + 1 | + | - 3 | = 11 ? | 6 | + | 2 | + | 3 | = 11 ( c ) | general |
math_qa__npmbPRcJhJQCLFCv | What should be the least number to be added to the 1202 number to make it divisible by 4? Options
A) 12
B) 17
C) 18
D) 77
E) 2 | <gadget id="calculator">1_202 % 4</gadget>
<output>2</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<result>E</result> | E | 2 | What should be the least number to be added to the 1202 number to make it divisible by 4? | {
"A": "12",
"B": "17",
"C": "18",
"D": "77",
"E": "2"
} | subtract(4, reminder(1202, 4)) | reminder(n0,n1)|subtract(n1,#0) | answer : 2 option : e | general |
math_qa__UzjMuKqLqMmX1DaX | A sum of money deposited at C.I. amounts to Rs.3250 in 2 years and to Rs.3830 in 3 years. Find the rate percent? Options:
A) 30 % B) 10 % C) 20 % D) 17 % E) 50 % | <gadget id="calculator">3_830 - 3_250</gadget>
<output>580</output>
<gadget id="calculator">580 / 3_250</gadget>
<output>58/325 = around 0.178462</output>
<gadget id="calculator">(58/325) * 100</gadget>
<output>232/13 = around 17.846154</output>
<result>D</result> | D | 17 | A sum of money deposited at C.I. amounts to Rs.3250 in 2 years and to Rs.3830 in 3 years. Find the rate percent? | {
"A": "30 %",
"B": "10 %",
"C": "20 %",
"D": "17 %",
"E": "50 %"
} | multiply(divide(subtract(3830, 3250), 3250), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "3250 - - - 580 100 - - - ? = > 17 % answer : d" | gain |
math_qa__P9ewm50casSFVRi0 | A certain car uses 12 gallons of gasoline in traveling 180 miles. In order for the car to travel the same distance using 10 gallons of gasoline, by how many miles per gallon must the car’s gas mileage be increased? Select:
A) 2 B) 3 C) 6 D) 8 E) 10 | <gadget id="calculator">180 / 10</gadget>
<output>18</output>
<gadget id="calculator">180 / 12</gadget>
<output>15</output>
<gadget id="calculator">18 - 15</gadget>
<output>3</output>
<result>B</result> | B | 3 | A certain car uses 12 gallons of gasoline in traveling 180 miles. In order for the car to travel the same distance using 10 gallons of gasoline, by how many miles per gallon must the car’s gas mileage be increased? | {
"A": "2",
"B": "3",
"C": "6",
"D": "8",
"E": "10"
} | subtract(divide(180, 10), divide(180, 12)) | divide(n1,n2)|divide(n1,n0)|subtract(#0,#1)| | "180 / 10 = 18 . the difference is 18 - 15 = 3 . answer b" | physics |
math_qa__us3LrvH6jzb6mWmL | A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son? Options: A) 23 years B) 22 years C) 21 years D) 20 years E) 30 years | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">24 - 2</gadget>
<output>22</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">22 / 1</gadget>
<output>22</output>
<result>B</result> | B | 22 | A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son? | {
"A": "23 years",
"B": "22 years",
"C": "21 years",
"D": "20 years",
"E": "30 years"
} | divide(subtract(24, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1)) | multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)| | "let present age of the son = x years then present age the man = ( x + 24 ) years given that in 2 years man ' s age will be twice the age of his son x = 22 answer b" | general |
math_qa__DpuhMPdnPrc3ctWS | In the Hillside summer camp there are 60 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen? Pick one.
A) 50 .
B) 45 .
C) 40 .
D) 60 .
E) 25 . | <gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">95 / 100</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) * 60</gadget>
<output>57</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 60</gadget>
<output>3</output>
<gadget id="calculator">57 + 3</gadget>
<output>60</output>
<result>D</result> | D | 60 | In the Hillside summer camp there are 60 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen? | {
"A": "50 .",
"B": "45 .",
"C": "40 .",
"D": "60 .",
"E": "25 ."
} | add(multiply(divide(subtract(const_100, 5), const_100), 60), multiply(divide(5, const_100), 60)) | divide(n2,const_100)|subtract(const_100,n2)|divide(#1,const_100)|multiply(n0,#0)|multiply(n0,#2)|add(#4,#3)| | "given there are 60 students , 90 % of 60 = 54 boys and remaining 6 girls . now here 90 % are boys and 10 % are girls . now question is asking about how many boys do we need to add , to make the girls percentage to 5 or 5 % . . if we add 60 to existing 54 then the count will be 114 and the girls number will be 6 as it . now boys are 95 % and girls are 5 % . ( out of 120 students = 114 boys + 6 girls ) . imo option d is correct ." | general |
math_qa__LZ5Xq2PH7XcSz0Cu | 49 pumps can empty a reservoir in 13/2 days, Working 8 hours a day. If 196 pumps are used for 5 hours each day, then the same work will be completed in: Answers: A) 2 days B) 5 / 2 days C) 13 / 5 days D) 3 days E) none of these | <gadget id="calculator">49 / 196</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">8 / 5</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(1/4) * (8/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">13 / 2</gadget>
<output>13/2 = around 6.5</output>
<gadget id="calculator">(2/5) * (13/2)</gadget>
<output>13/5 = around 2.6</output>
<result>C</result> | C | 2.6 | 49 pumps can empty a reservoir in 13/2 days, Working 8 hours a day. If 196 pumps are used for 5 hours each day, then the same work will be completed in: | {
"A": "2 days",
"B": "5 / 2 days",
"C": "13 / 5 days",
"D": "3 days",
"E": "none of these"
} | multiply(multiply(divide(49, 196), divide(8, 5)), divide(13, 2)) | divide(n1,n2)|divide(n0,n4)|divide(n3,n5)|multiply(#1,#2)|multiply(#0,#3) | explanation : let the required number of days be x . then , more pumps , less days ( indirect proportion ) less working hrs / day , more days ( indirect proportion ) pumps 196 : 49 working hrs / day 5 : 8 : : 13 / 2 : x 96 x 5 x x = 49 x 8 x 13 / 2 x = 49 x 8 x 13 / 2 x 1 / ( 196 x 5 ) x = 13 / 5 answer c | physics |
math_qa__Me8KYkQR6IKJrn2T | Some of the 50% solution of acid was removed and this was replaced with an equal amount of 30% solution of acid. As a result, a 40% solution of acid was obtained. What fraction of the original solution was replaced?
Pick one:
A) 1 / 2 B) 1 / 3 C) 2 / 3 D) 1 / 4 E) 2 / 5 | <gadget id="calculator">50 + 30</gadget>
<output>80</output>
<gadget id="calculator">40 / 80</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | Some of the 50% solution of acid was removed and this was replaced with an equal amount of 30% solution of acid. As a result, a 40% solution of acid was obtained. What fraction of the original solution was replaced? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "2 / 3",
"D": "1 / 4",
"E": "2 / 5"
} | divide(40, add(50, 30)) | add(n0,n1)|divide(n2,#0)| | "let x be the fraction of the original solution that was replaced . 0.5 * ( 1 - x ) + 0.3 ( x ) = 0.4 0.2 x = 0.1 x = 1 / 2 the answer is a ." | gain |
math_qa__7ozjWSWo42w1B1W6 | In a certain brick wall, each row of bricks above the bottom row contains one less brick than the row just below it. If there are 5 rows in all and a total of 200 bricks in the wall, how many bricks does the bottom row contain ?
Choose the correct choice from the following answers:
A) 42 B) 35 C) 40 D) 33 E) 38 | <gadget id="calculator">200 - 1</gadget>
<output>199</output>
<gadget id="calculator">199 - 2</gadget>
<output>197</output>
<gadget id="calculator">197 - 3</gadget>
<output>194</output>
<gadget id="calculator">194 - 4</gadget>
<output>190</output>
<gadget id="calculator">190 / 5</gadget>
<output>38</output>
<result>E</result> | E | 38 | In a certain brick wall, each row of bricks above the bottom row contains one less brick than the row just below it. If there are 5 rows in all and a total of 200 bricks in the wall, how many bricks does the bottom row contain ? | {
"A": "42",
"B": "35",
"C": "40",
"D": "33",
"E": "38"
} | divide(subtract(subtract(subtract(subtract(200, const_1), const_2), const_3), const_4), 5) | subtract(n1,const_1)|subtract(#0,const_2)|subtract(#1,const_3)|subtract(#2,const_4)|divide(#3,n0)| | "the bottom row has x bricks x + x - 1 + x - 2 + x - 3 + x - 4 = 200 5 x - 10 = 200 5 x = 190 x = 38 answer : e" | general |
math_qa__KNnzu7gkWzzAyDir | A certain business school has 500 students, and the law school at the same university has 800 students. Among these students, there are 30 sibling pairs consisting of 1 business student and 1 law student. If 1 student is selected at random from both schools, what is the probability that a sibling pair is selected?
Choose the most appropriate option
A) 3 / 40000 B) 3 / 20000 C) 3 / 4000 D) 9 / 400 E) 6 / 130 | <gadget id="calculator">1 / 500</gadget>
<output>1/500 = around 0.002</output>
<gadget id="calculator">1 / 800</gadget>
<output>1/800 = around 0.00125</output>
<gadget id="calculator">(1/500) * (1/800)</gadget>
<output>1/400_000 = around 0.000002</output>
<gadget id="calculator">(1/400_000) * 30</gadget>
<output>3/40_000 = around 0.000075</output>
<result>A</result> | A | 0.000075 | A certain business school has 500 students, and the law school at the same university has 800 students. Among these students, there are 30 sibling pairs consisting of 1 business student and 1 law student. If 1 student is selected at random from both schools, what is the probability that a sibling pair is selected? | {
"A": "3 / 40000",
"B": "3 / 20000",
"C": "3 / 4000",
"D": "9 / 400",
"E": "6 / 130"
} | multiply(multiply(divide(1, 500), divide(1, 800)), 30) | divide(n3,n0)|divide(n3,n1)|multiply(#0,#1)|multiply(n2,#2) | probability of selecting 1 student from harvard ' s business school - - - 1 / 500 probability of selecting 1 student from harvard ' s law school - - - - - - - - - 1 / 800 probability that these two students are siblings - - - - ( 1 / 500 * 1 / 800 ) since there are 30 siblings , hence ( 1 / 500 * 1 / 800 ) * 30 . 3 / 40000 answer : a | other |
math_qa__vReIQuJUsgKxAZeT | A number increased by 40% gives 700. The number is
Choose the correct choice:
A) 250 B) 500 C) 450 D) 500 E) 520 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">700 / (7/5)</gadget>
<output>500</output>
<result>B</result> | B | 500 | A number increased by 40% gives 700. The number is | {
"A": "250",
"B": "500",
"C": "450",
"D": "500",
"E": "520"
} | divide(700, add(const_1, divide(40, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "formula = total = 100 % , increse = ` ` + ' ' decrease = ` ` - ' ' a number means = 100 % that same number increased by 40 % = 140 % 140 % - - - - - - - > 700 ( 140 × 5 = 700 ) 100 % - - - - - - - > 700 ( 100 × 5 = 500 ) b )" | gain |
math_qa__EHDR6Ace1XYvUKVd | When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 41, what is the remainder when k is divided by 7?
Pick one.
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">12 + 5</gadget>
<output>17</output>
<gadget id="calculator">17 % 7</gadget>
<output>3</output>
<result>A</result> | A | 3 | When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 41, what is the remainder when k is divided by 7? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | reminder(add(const_12, 5), 7) | add(n0,const_12)|reminder(#0,n5)| | "cant think of a straight approach but here is how i solved it : k is divided by 5 and remainder is 2 . this means k = 5 n + 2 ( n is an integer ) so the possible values of k = { 2 , 7 , 12 , 17 , 22 , 27 , 32 , 37 } ( less than 41 ) secondly , if k is divided by 6 , the remainder is 5 = > k = 6 m + 5 so the possible value set for k = { 5 , 11 , 17 , 23 , 29,35 } ( less than 41 ) 17 is the only common number in both the sets . hence k = 17 answer : a" | general |
math_qa__MSHWXcrwwdp5b9qR | The profits of QRS company rose 40% from March to April, then dropped 20% from April to May, then rose 50% from May to June. What was the percent increase for the whole quarter, from March to June? Choose the correct choice from the following options:
A) 15 %
B) 32 %
C) 40 %
D) 68 %
E) 80 % | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(7/5) * (4/5)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">(3/2) * (28/25)</gadget>
<output>42/25 = around 1.68</output>
<gadget id="calculator">(42/25) - 1</gadget>
<output>17/25 = around 0.68</output>
<gadget id="calculator">100 * (17/25)</gadget>
<output>68</output>
<result>D</result> | D | 68 | The profits of QRS company rose 40% from March to April, then dropped 20% from April to May, then rose 50% from May to June. What was the percent increase for the whole quarter, from March to June? | {
"A": "15 %",
"B": "32 %",
"C": "40 %",
"D": "68 %",
"E": "80 %"
} | multiply(const_100, subtract(multiply(add(const_1, divide(50, const_100)), multiply(add(const_1, divide(40, const_100)), subtract(const_1, divide(20, const_100)))), const_1)) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|subtract(const_1,#2)|multiply(#4,#5)|multiply(#3,#6)|subtract(#7,const_1)|multiply(#8,const_100)| | "assume 100 in march , then 140 in april as 40 % increase , then 112 in may as 20 % decrease from april , and then 168 in june which is 150 % of 112 . so overall increase is from 100 to 168 is 68 % answer d" | gain |
math_qa__Q0W2wfCJ0lB96pmv | Find the value of 4 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)] Choose the correct choice from the following answers: A) 800 B) 3200 C) 900 D) 1600 E) none | <gadget id="calculator">3.6 * 0.48</gadget>
<output>1.728</output>
<gadget id="calculator">1.728 * 2.5</gadget>
<output>4.32</output>
<gadget id="calculator">0.12 * 0.09</gadget>
<output>0.0108</output>
<gadget id="calculator">0.0108 * 0.5</gadget>
<output>0.0054</output>
<gadget id="calculator">4.32 / 0.0054</gadget>
<output>800</output>
<gadget id="calculator">800 * 4</gadget>
<output>3_200</output>
<result>B</result> | B | 3,200 | Find the value of 4 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)] | {
"A": "800",
"B": "3200",
"C": "900",
"D": "1600",
"E": "none"
} | multiply(divide(multiply(multiply(3.6, 0.48), 2.50), multiply(multiply(0.12, 0.09), 0.5)), 4) | multiply(n1,n2)|multiply(n4,n5)|multiply(n3,#0)|multiply(n6,#1)|divide(#2,#3)|multiply(n0,#4)| | "answer 4 x [ ( 3.6 x 0.48 x 2.50 ) / ( 0.12 x 0.09 x 0.5 ) ] = 4 x [ ( 36 x 48 x 250 ) / ( 12 x 9 x 5 ) ] = 4 x 4 x 4 x 50 = 3200 correct option : b" | general |
math_qa__BlfZxOiUpR6zWaOl | An army’s recruitment process included N rounds of selection tasks. For the first A rounds, the rejection percentage was 60 percent per round. For the next B rounds, the rejection percentage was 50 percent per round and for the remaining rounds, the selection percentage was 70 percent per round. If there were 100000 people who applied for the army and 175 were finally selected, what was the value of N? Choose the correct choice.
A) 4 B) 9 C) 6 D) 8 E) 10 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">2 + 5</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<result>B</result> | B | 9 | An army’s recruitment process included N rounds of selection tasks. For the first A rounds, the rejection percentage was 60 percent per round. For the next B rounds, the rejection percentage was 50 percent per round and for the remaining rounds, the selection percentage was 70 percent per round. If there were 100000 people who applied for the army and 175 were finally selected, what was the value of N? | {
"A": "4",
"B": "9",
"C": "6",
"D": "8",
"E": "10"
} | add(add(const_2, add(const_1, const_4)), const_2) | add(const_1,const_4)|add(#0,const_2)|add(#1,const_2)| | "fastly i reduce 60 % till it gets closer to our required 2000 candidates step ( 1 ) 40000 accepted . step ( 2 ) another 40 % of 40000 = 16000 accepted . here it is quiet observable that if we further deduct candidate by 60 % it would change our probablity of easy going 2000 candidate . so i would get to second stage of recruitment where 50 % is accepted step ( 3 ) 50 % of 16000 = 8000 step ( 4 ) 50 % of 8000 = 4000 step ( 5 ) 50 % of 4000 = 2000 step ( 6 ) 50 % of 2000 = 1000 step ( 7 ) 50 % of 1000 = 500 step ( 8 ) 50 % of 500 = 250 step ( 9 ) 70 % of 350 = 175 ( our target ) total 9 steps required . ans b" | general |
math_qa__FdsGWY2g3hmXOj3B | From the sale of sleeping bags, a retailer made a gross profit of 12% of the wholesale cost. If each sleeping bag was sold for $28, what was the wholesale cost per bag? Choose the correct choice from the following:
A) 3.0 B) 3.36 C) 24.64 D) 25.0 E) 31.36 | <gadget id="calculator">28 * 100</gadget>
<output>2_800</output>
<gadget id="calculator">100 + 12</gadget>
<output>112</output>
<gadget id="calculator">2_800 / 112</gadget>
<output>25</output>
<result>D</result> | D | 25 | From the sale of sleeping bags, a retailer made a gross profit of 12% of the wholesale cost. If each sleeping bag was sold for $28, what was the wholesale cost per bag? | {
"A": "3.0",
"B": "3.36",
"C": "24.64",
"D": "25.0",
"E": "31.36"
} | divide(multiply(28, const_100), add(const_100, 12)) | add(n0,const_100)|multiply(n1,const_100)|divide(#1,#0) | cost price * 1.12 = selling price - - > cost price * 1.12 = $ 28 - - > cost price = $ 25 . answer : d . actually even without any math only c and d make any sense , but since 24.64 * 1.12 wo n ' t be an integer ( $ 28 ) then only answer choice d remains . | gain |
math_qa__8kVhvJwnXwkp8Xhe | There is enough provisions for 700 men in an army camp for 25 days. If there were 300 men less, how long will the provision last? Choose the correct choice from the following choices:
A) 30 days
B) 40 days
C) 50 days
D) 59 days
E) 65 days | <gadget id="calculator">700 * 25</gadget>
<output>17_500</output>
<gadget id="calculator">17_500 / 300</gadget>
<output>175/3 = around 58.333333</output>
<result>D</result> | D | 59 | There is enough provisions for 700 men in an army camp for 25 days. If there were 300 men less, how long will the provision last? | {
"A": "30 days",
"B": "40 days",
"C": "50 days",
"D": "59 days",
"E": "65 days"
} | divide(multiply(700, 25), 300) | multiply(n0,n1)|divide(#0,n2)| | "exp : we have , m 1 d 1 = m 2 d 2 700 * 25 = 300 * d 2 d 2 = 700 * 25 / 300 = 59 days . answer : d" | physics |
math_qa__Vt6ZZOQvs7x19JL3 | 3 distinct single - digit numbers . a , b , c are in gp . if abs ( x ) for real x is the absolute value of x ( x if x is + ve or 0 and - x if x is - ve ) , then the number of different possible values of abs ( a + b + c ) is Choose the correct answer
A) 5
B) 6
C) 3
D) 4
E) 7 | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<result>D</result> | D | 4 | 3 distinct single - digit numbers . a , b , c are in gp . if abs ( x ) for real x is the absolute value of x ( x if x is + ve or 0 and - x if x is - ve ) , then the number of different possible values of abs ( a + b + c ) is | {
"A": "5",
"B": "6",
"C": "3",
"D": "4",
"E": "7"
} | add(3, const_1) | add(n0,const_1) | a , b , c may be ( 1 , 2,4 ) & ( 4 , 2,1 ) ( 1 , 3,9 ) & ( 9 , 3,1 ) ( 2 , 4,8 ) & ( 8 , 4,2 ) ( 4 , 6,9 ) & ( 9 , 6,4 ) find abs ( a + b + c ) for these 8 gps 7,13 , 15,19 so , we get 4 different values answer : d | general |
math_qa__dLPQvlfETCk1XlRf | A courtyard is 18 meter long and 12 meter board is to be paved with bricks of dimensions 12 cm by 6 cm. The total number of bricks required is : Choose the correct option.
A) 16000
B) 18000
C) 20000
D) 30000
E) none of these | <gadget id="calculator">18 * 100</gadget>
<output>1_800</output>
<gadget id="calculator">12 * 100</gadget>
<output>1_200</output>
<gadget id="calculator">1_800 * 1_200</gadget>
<output>2_160_000</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<gadget id="calculator">2_160_000 / 72</gadget>
<output>30_000</output>
<result>D</result> | D | 30,000 | A courtyard is 18 meter long and 12 meter board is to be paved with bricks of dimensions 12 cm by 6 cm. The total number of bricks required is : | {
"A": "16000",
"B": "18000",
"C": "20000",
"D": "30000",
"E": "none of these"
} | divide(multiply(multiply(18, const_100), multiply(12, const_100)), multiply(12, 6)) | multiply(n0,const_100)|multiply(n1,const_100)|multiply(n2,n3)|multiply(#0,#1)|divide(#3,#2)| | "explanation : number of bricks = courtyard area / 1 brick area = ( 1800 ã — 1200 / 12 ã — 6 ) = 30000 option d" | physics |
math_qa__8Fv7is27v3tIImJ1 | a batch of cookies was divided among 3 tins : 2 / 3 of all the cookies were placed in either the blue tin or the green tin , and the rest were placed in the red tin . if 1 / 4 of all the cookies were placed in the blue tin , what fraction w of the cookies that were placed in the other tins were placed in the green tin ? Pick one
A) 15 / 2
B) 9 / 4
C) 5 / 9
D) 7 / 5
E) 9 / 7 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(2/3) - (1/4)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(5/12) + (1/3)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(5/12) / (3/4)</gadget>
<output>5/9 = around 0.555556</output>
<result>C</result> | C | 0.555556 | a batch of cookies was divided among 3 tins : 2 / 3 of all the cookies were placed in either the blue tin or the green tin , and the rest were placed in the red tin . if 1 / 4 of all the cookies were placed in the blue tin , what fraction w of the cookies that were placed in the other tins were placed in the green tin ? | {
"A": "15 / 2",
"B": "9 / 4",
"C": "5 / 9",
"D": "7 / 5",
"E": "9 / 7"
} | divide(subtract(divide(2, 3), divide(1, 4)), add(subtract(divide(2, 3), divide(1, 4)), divide(1, 3))) | divide(n1,n0)|divide(n3,n4)|divide(n3,n0)|subtract(#0,#1)|add(#2,#3)|divide(#3,#4) | blue tin or red tin : 2 / 3 ( n ) red tin : ( 1 / 3 ) n blue tin : ( 1 / 4 ) n what the last statment meant , is it wants this fraction : ( # of cookies in green tin ) / ( # of cookies in red and green tin ) # of cookies in green tin = 2 n / 3 - n / 4 = 8 n - 3 n / 12 = 5 n / 12 # of cookies in red and green tin = n / 3 + 5 n / 12 = 9 n / 12 fraction w = 5 n / 12 * 12 / 9 n = 5 / 9 ( c ) | general |
math_qa__YT5zEflwCudkhwzx | Two trains of equal lengths take 12 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? Choose the correct option.
A) 22 B) 13 C) 77 D) 99 E) 21 | <gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">120 / 15</gadget>
<output>8</output>
<gadget id="calculator">120 / 12</gadget>
<output>10</output>
<gadget id="calculator">8 + 10</gadget>
<output>18</output>
<gadget id="calculator">240 / 18</gadget>
<output>40/3 = around 13.333333</output>
<result>B</result> | B | 13 | Two trains of equal lengths take 12 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? | {
"A": "22",
"B": "13",
"C": "77",
"D": "99",
"E": "21"
} | divide(multiply(120, const_2), add(speed(120, 15), speed(120, 12))) | multiply(n2,const_2)|speed(n2,n1)|speed(n2,n0)|add(#1,#2)|divide(#0,#3)| | "speed of the first train = 120 / 12 = 10 m / sec . speed of the second train = 120 / 15 = 8 m / sec . relative speed = 10 + 8 = 18 m / sec . required time = ( 120 + 120 ) / 18 = 13 sec . answer : b" | physics |
math_qa__Pzpy7AHbFMxcyBqt | 40% of major airline companies equip their planes with wireless internet access. 70% of major airlines offer passengers free on-board snacks. What is the greatest possible percentage of major airline companies that offer both wireless internet and free on-board snacks? Select the correct option:
A) 30 %
B) 40 %
C) 50 %
D) 60 %
E) 70 % | <gadget id="calculator">40 * 1</gadget>
<output>40</output>
<result>B</result> | B | 40 | 40% of major airline companies equip their planes with wireless internet access. 70% of major airlines offer passengers free on-board snacks. What is the greatest possible percentage of major airline companies that offer both wireless internet and free on-board snacks? | {
"A": "30 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "70 %"
} | multiply(40, const_1) | multiply(n0,const_1)| | "to maximize the percentage of companies offering both , let ' s assume that all 40 % of companies which offer wireless internet also offer snacks . the answer is b ." | general |
math_qa__Mb3jfCx4tt9Zli2t | A boat moves down stream at the rate of 1 km in 6 minutes and
upstream at the rate of 1 km in 10 minutes. The speed of current is
Select
A) 2 kmph
B) 3 kmph
C) 4 kmph
D) 5 kmph
E) 6 kmph | <gadget id="calculator">6 / 60</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / (1/10)</gadget>
<output>10</output>
<gadget id="calculator">10 / 60</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<gadget id="calculator">10 - 6</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>A</result> | A | 2 | A boat moves down stream at the rate of 1 km in 6 minutes and
upstream at the rate of 1 km in 10 minutes. The speed of current is | {
"A": "2 kmph",
"B": "3 kmph",
"C": "4 kmph",
"D": "5 kmph",
"E": "6 kmph"
} | divide(subtract(divide(1, divide(6, const_60)), divide(1, divide(10, const_60))), const_2) | divide(n1,const_60)|divide(n3,const_60)|divide(n0,#0)|divide(n0,#1)|subtract(#2,#3)|divide(#4,const_2) | if speed ( in kmph ) of the boat = b and current = c , then in downstream time taken ( in hrs . ) = 1 / ( b + c ) = 6 / 60 = 1 / 10 or b + c = 10 - - - ( i ) & in upstream time taken ( in hrs . ) = 1 / ( b - c ) = 10 / 60 = 1 / 6 or b - c = 6 - - - ( ii ) from ( i ) & ( ii ) , b = 8 , c = 2 answer : a | physics |
math_qa__HNpSl85hut8r0skG | The population of a city increases by 8% per year but due to migration it decrease by 1% per years. What will be the percentage increase in population in 3 years?
Choose one.
A) 9 % B) 9.27 % C) 22.50 % D) 12 % E) none of these | <gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">100 + 7</gadget>
<output>107</output>
<gadget id="calculator">107 * 7</gadget>
<output>749</output>
<gadget id="calculator">749 / 100</gadget>
<output>749/100 = around 7.49</output>
<gadget id="calculator">(749/100) + 7</gadget>
<output>1_449/100 = around 14.49</output>
<gadget id="calculator">100 + (1_449/100)</gadget>
<output>11_449/100 = around 114.49</output>
<gadget id="calculator">(11_449/100) * 7</gadget>
<output>80_143/100 = around 801.43</output>
<gadget id="calculator">(80_143/100) / 100</gadget>
<output>80_143/10_000 = around 8.0143</output>
<gadget id="calculator">(80_143/10_000) + (1_449/100)</gadget>
<output>225_043/10_000 = around 22.5043</output>
<result>C</result> | C | 22.5 | The population of a city increases by 8% per year but due to migration it decrease by 1% per years. What will be the percentage increase in population in 3 years? | {
"A": "9 %",
"B": "9.27 %",
"C": "22.50 %",
"D": "12 %",
"E": "none of these"
} | add(divide(multiply(add(const_100, add(divide(multiply(add(const_100, subtract(8, 1)), subtract(8, 1)), const_100), subtract(8, 1))), subtract(8, 1)), const_100), add(divide(multiply(add(const_100, subtract(8, 1)), subtract(8, 1)), const_100), subtract(8, 1))) | subtract(n0,n1)|add(#0,const_100)|multiply(#1,#0)|divide(#2,const_100)|add(#3,#0)|add(#4,const_100)|multiply(#5,#0)|divide(#6,const_100)|add(#4,#7)| | "actual increase in population = 7 % let , earlier population = 100 then the population after 3 years = 100 ( 1 + 7 / 100 ) ^ 3 = 122.5043 ∴ required percentage = 22.50 % answer : c" | general |
math_qa__rGcIwPCU1x4mhWwi | Pipe A can fill a tank in 3 hours. Due to a leak at the bottom, it takes 9 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank? Choices:
A) 4.5 B) 17 C) 18 D) 19 E) 12 | <gadget id="calculator">9 * 3</gadget>
<output>27</output>
<gadget id="calculator">9 - 3</gadget>
<output>6</output>
<gadget id="calculator">27 / 6</gadget>
<output>9/2 = around 4.5</output>
<result>A</result> | A | 4.5 | Pipe A can fill a tank in 3 hours. Due to a leak at the bottom, it takes 9 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank? | {
"A": "4.5",
"B": "17",
"C": "18",
"D": "19",
"E": "12"
} | divide(multiply(9, 3), subtract(9, 3)) | multiply(n0,n1)|subtract(n1,n0)|divide(#0,#1)| | "let the leak can empty the full tank in x hours 1 / 3 - 1 / x = 1 / 9 = > 1 / x = 1 / 3 - 1 / 9 = ( 3 - 1 ) / 9 = 2 / 9 = > x = 9 / 2 = 4.5 . answer : a" | physics |
math_qa__SkHoc7qi4UvaQbdt | The radius of a semi circle is 4.8 cm then its perimeter is? Choices:
A) 32.51 B) 32.4 C) 32.1 D) 32.92 E) 24.69 | <gadget id="calculator">2 * pi * 4.8</gadget>
<output>9.6*pi = around 30.159289</output>
<gadget id="calculator">(9.6*pi) / 2</gadget>
<output>4.8*pi = around 15.079645</output>
<gadget id="calculator">4.8 * 2</gadget>
<output>9.6</output>
<gadget id="calculator">(4.8*pi) + 9.6</gadget>
<output>9.6 + 4.8*pi = around 24.679645</output>
<result>E</result> | E | 24.69 | The radius of a semi circle is 4.8 cm then its perimeter is? | {
"A": "32.51",
"B": "32.4",
"C": "32.1",
"D": "32.92",
"E": "24.69"
} | add(divide(circumface(4.8), const_2), multiply(4.8, const_2)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "36 / 7 r = 4.8 = 24.69 answer : e" | physics |
math_qa__fMcv14d1aF3VVpFw | A man can row a distance of 5 km in 60 min with the help of the tide. The direction of the tide reverses with the same speed. Now he travels a further 40 km in 10 hours. How much time he would have saved if the direction of tide has not changed?
Choose the correct choice from the following options.
A) 2 B) 8 C) 1 D) 6 E) 5 | <gadget id="calculator">40 / 5</gadget>
<output>8</output>
<gadget id="calculator">10 - 8</gadget>
<output>2</output>
<result>A</result> | A | 2 | A man can row a distance of 5 km in 60 min with the help of the tide. The direction of the tide reverses with the same speed. Now he travels a further 40 km in 10 hours. How much time he would have saved if the direction of tide has not changed? | {
"A": "2",
"B": "8",
"C": "1",
"D": "6",
"E": "5"
} | subtract(10, divide(40, 5)) | divide(n2,n0)|subtract(n3,#0) | explanation : he covered 5 km in 1 hour , so he might cover 40 km in 8 hours . but he took 10 hours . he would have saved 10 â € “ 8 = 2 hours . answer : a | physics |
math_qa__9kNh7F4DAAeVUFp3 | How many 3-digit numerals end with a digit that represents a prime number? Choose the most appropriate option:
A) 16
B) 80
C) 160
D) 180
E) 400 | <gadget id="calculator">100 * 3</gadget>
<output>300</output>
<gadget id="calculator">300 + 100</gadget>
<output>400</output>
<result>E</result> | E | 400 | How many 3-digit numerals end with a digit that represents a prime number? | {
"A": "16",
"B": "80",
"C": "160",
"D": "180",
"E": "400"
} | add(multiply(const_100, 3), const_100) | multiply(n0,const_100)|add(#0,const_100)| | "prime digits 2 , 3,5 and 7 . three digit numbers _ _ _ 1 st place can be filled in 4 ways 2 nd place can be filled in 10 ways 3 rd place can be filled in 10 ways total = 4 * 10 * 10 = 400 ans : e" | general |
math_qa__ZrfUNaH2jH6AuHwQ | machine a and machine b process the same work at different rates . machine c processes work as fast as machines a and b combined . machine d processes work 3 times as fast as machine c ; machine d ’ s work rate is also exactly 4 times machine b ’ s rate . assume all 4 machines work at fixed unchanging rates . if machine a works alone on a job , it takes 6 hours and 20 minutes . if all 4 machines work together on the same job simultaneously , how many minutes will it take all of them to complete it ? Choose the correct choice from the following choices.
A) 15
B) 17
C) 19
D) 21
E) 24 | <gadget id="calculator">6 * 60</gadget>
<output>360</output>
<gadget id="calculator">360 + 20</gadget>
<output>380</output>
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">8 + 12</gadget>
<output>20</output>
<gadget id="calculator">380 / 20</gadget>
<output>19</output>
<result>C</result> | C | 19 | machine a and machine b process the same work at different rates . machine c processes work as fast as machines a and b combined . machine d processes work 3 times as fast as machine c ; machine d ’ s work rate is also exactly 4 times machine b ’ s rate . assume all 4 machines work at fixed unchanging rates . if machine a works alone on a job , it takes 6 hours and 20 minutes . if all 4 machines work together on the same job simultaneously , how many minutes will it take all of them to complete it ? | {
"A": "15",
"B": "17",
"C": "19",
"D": "21",
"E": "24"
} | divide(add(multiply(6, const_60), 20), add(add(add(const_1, 3), add(3, const_1)), multiply(add(3, const_1), 3))) | add(n0,const_1)|multiply(n3,const_60)|add(n4,#1)|add(#0,#0)|multiply(n0,#0)|add(#3,#4)|divide(#2,#5) | c = a + b d = 3 c = 3 ( a + b ) = 4 b then b = 3 a and c = 4 a the combined rate of the four machines is a + 3 a + 4 a + 12 a = 20 a machine a can complete the work in 380 minutes , so its rate is 1 / 380 of the work per minute . the combined rate is 20 / 380 = 1 / 19 so the work will be completed in 19 minutes . the answer is c . | physics |
math_qa__tCFzWNNhCkgxTsN3 | In a fuel station the service costs $1.50 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 55 liters and they are all empty, how much money total will it cost to fuel all cars? Select the correct option
A) 320 $ B) 380 $ C) 410 $ D) 430 $ E) 447 $ | <gadget id="calculator">0.65 * 55</gadget>
<output>35.75</output>
<gadget id="calculator">35.75 * 12</gadget>
<output>429</output>
<result>E</result> | E | 447 | In a fuel station the service costs $1.50 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 55 liters and they are all empty, how much money total will it cost to fuel all cars? | {
"A": "320 $",
"B": "380 $",
"C": "410 $",
"D": "430 $",
"E": "447 $"
} | multiply(multiply(0.65, 55), 12) | multiply(n1,n3)|multiply(n2,#0)| | 12 * 1.50 + 0.65 * 12 * 55 = 447 hence - e | general |
math_qa__Htz6TuqXfCBR5bZu | Cole drove from home to work at an average speed of 60 kmh. He then returned home at an average speed of 90 kmh. If the round trip took a total of 2 hours, how many minutes did it take Cole to drive to work? Choose the correct option.
A) 66 B) 70 C) 72 D) 75 E) 78 | <gadget id="calculator">90 * 2</gadget>
<output>180</output>
<gadget id="calculator">60 + 90</gadget>
<output>150</output>
<gadget id="calculator">180 / 150</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 60</gadget>
<output>72</output>
<result>C</result> | C | 72 | Cole drove from home to work at an average speed of 60 kmh. He then returned home at an average speed of 90 kmh. If the round trip took a total of 2 hours, how many minutes did it take Cole to drive to work? | {
"A": "66",
"B": "70",
"C": "72",
"D": "75",
"E": "78"
} | multiply(divide(multiply(90, 2), add(60, 90)), const_60) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)|multiply(#2,const_60)| | "let the distance one way be x time from home to work = x / 60 time from work to home = x / 90 total time = 2 hrs ( x / 60 ) + ( x / 90 ) = 2 solving for x , we get x = 72 time from home to work in minutes = ( 72 ) * 60 / 60 = 72 minutes ans = c" | physics |
math_qa__sr8XEBoEOLhASLju | From a group of 5 boys and 5 girls, 6 children are to be randomly selected. What is the probability that 3 boys and 3 girls will be selected? Choose the correct choice
A) 4 / 15 B) 6 / 17 C) 8 / 19 D) 10 / 21 E) 12 / 23 | <gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">binomial(10, 6)</gadget>
<output>210</output>
<gadget id="calculator">100 / 210</gadget>
<output>10/21 = around 0.47619</output>
<result>D</result> | D | 0.47619 | From a group of 5 boys and 5 girls, 6 children are to be randomly selected. What is the probability that 3 boys and 3 girls will be selected? | {
"A": "4 / 15",
"B": "6 / 17",
"C": "8 / 19",
"D": "10 / 21",
"E": "12 / 23"
} | divide(multiply(choose(5, const_2), choose(5, const_2)), choose(add(5, 5), 6)) | add(n0,n0)|choose(n0,const_2)|choose(n0,const_2)|choose(#0,n2)|multiply(#1,#2)|divide(#4,#3)| | "the total number of ways to choose 6 children from 10 is 10 c 6 = 210 the number of ways to choose 3 boys and 3 girls is 5 c 3 * 5 c 3 = 10 * 10 = 100 p ( 3 boys and 3 girls ) = 100 / 210 = 10 / 21 the answer is d ." | probability |
math_qa__TxEjDWAjbBuzTX6K | What is the area of square field whose side of length 14 m? Choose the correct choice from the following:
A) 225
B) 196
C) 266
D) 288
E) 261 | <gadget id="calculator">14 ** 2</gadget>
<output>196</output>
<result>B</result> | B | 196 | What is the area of square field whose side of length 14 m? | {
"A": "225",
"B": "196",
"C": "266",
"D": "288",
"E": "261"
} | square_area(14) | square_area(n0)| | "14 * 14 = 196 sq m answer : b" | geometry |
math_qa__hBfOZnCbKGcKYKpR | #p is defined as 2p-20 for any number p. What is p, if #(#(#p))=6? Choose the correct option
A) – 108
B) – 44
C) 10
D) 16
E) 18.25 | <gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">20 + 120</gadget>
<output>140</output>
<gadget id="calculator">140 + 6</gadget>
<output>146</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">146 / 8</gadget>
<output>73/4 = around 18.25</output>
<result>E</result> | E | 18.25 | #p is defined as 2p-20 for any number p. What is p, if #(#(#p))=6? | {
"A": "– 108",
"B": "– 44",
"C": "10",
"D": "16",
"E": "18.25"
} | divide(add(add(20, multiply(20, 6)), 6), multiply(2, const_4)) | multiply(n1,n2)|multiply(n0,const_4)|add(n1,#0)|add(n2,#2)|divide(#3,#1) | # p = 2 p - 20 - - - > # ( # p ) = 2 ( 2 p - 20 ) - 20 = 4 p - 60 and thus # ( 4 p - 60 ) = 2 ( 4 p - 60 ) - 20 = 8 p - 140 = 6 - - - > 8 p = 146 - - - > p = 18.25 , e is the correct answer . | general |
math_qa__v4hwgGXRVTxa5pjU | A watch was sold at a loss of 9%. If it was sold for Rs.220 more, there would have been a gain of 4%. What is the cost price? Select the correct option:
A) 1000 B) 2876 C) 1977 D) 2778 E) 1692 | <gadget id="calculator">220 * 100</gadget>
<output>22_000</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 - 9</gadget>
<output>91</output>
<gadget id="calculator">104 - 91</gadget>
<output>13</output>
<gadget id="calculator">22_000 / 13</gadget>
<output>22_000/13 = around 1_692.307692</output>
<result>E</result> | E | 1,692 | A watch was sold at a loss of 9%. If it was sold for Rs.220 more, there would have been a gain of 4%. What is the cost price? | {
"A": "1000",
"B": "2876",
"C": "1977",
"D": "2778",
"E": "1692"
} | divide(multiply(220, const_100), subtract(add(const_100, 4), subtract(const_100, 9))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "91 % 104 % - - - - - - - - 13 % - - - - 220 100 % - - - - ? = > rs . 1692 answer : e" | gain |
math_qa__KZEjEgjcOTXzes7K | Two persons A and B can complete a piece of work in 30 days and 60 days respectively. If they work together, what part of the work will be completed in 10 days? Choose the correct choice from the following options:
A) 1 / 8
B) 1 / 3
C) 1 / 6
D) 1 / 2
E) 5 / 3 | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/30) + (1/60)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">10 * (1/20)</gadget>
<output>1/2 = around 0.5</output>
<result>D</result> | D | 0.5 | Two persons A and B can complete a piece of work in 30 days and 60 days respectively. If they work together, what part of the work will be completed in 10 days? | {
"A": "1 / 8",
"B": "1 / 3",
"C": "1 / 6",
"D": "1 / 2",
"E": "5 / 3"
} | multiply(10, add(divide(const_1, 30), divide(const_1, 60))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2) | a ' s one day ' s work = 1 / 30 b ' s one day ' s work = 1 / 60 ( a + b ) ' s one day ' s work = 1 / 30 + 1 / 60 = 1 / 20 the part of the work completed in 10 days = 10 ( 1 / 20 ) = 1 / 2 . answer : d | physics |
math_qa__akBEQ5EeVqwYKCSI | By travelling at 30 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time?
Choose one
A) 19 kmph B) 15 kmph C) 12 kmph D) 20 kmph E) 23 kmph | <gadget id="calculator">30 * 3</gadget>
<output>90</output>
<gadget id="calculator">90 * 2</gadget>
<output>180</output>
<gadget id="calculator">180 / 3</gadget>
<output>60</output>
<gadget id="calculator">90 - 60</gadget>
<output>30</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>B</result> | B | 15 | By travelling at 30 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time? | {
"A": "19 kmph",
"B": "15 kmph",
"C": "12 kmph",
"D": "20 kmph",
"E": "23 kmph"
} | divide(subtract(multiply(30, const_3), divide(multiply(multiply(30, const_3), const_2), const_3)), subtract(const_3, const_1)) | multiply(n0,const_3)|subtract(const_3,const_1)|multiply(#0,const_2)|divide(#2,const_3)|subtract(#0,#3)|divide(#4,#1)| | "let the time taken to reach the destination be 3 x hours . total distance = 30 * 3 x = 90 x km he covered 2 / 3 * 90 x = 60 x km in 1 / 3 * 3 x = x hours so , the remaining 30 x km , he has to cover in 2 x hours . required speed = 30 x / 2 x = 15 kmph . answer : b" | physics |
math_qa__Ea9k8rtp0cRFYb3l | 33 1/3% OF 270? Choose the correct choice from the following.
A) 80 B) 90 C) 110 D) 120 E) 130 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">33 + (1/3)</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(100/3) * 270</gadget>
<output>9_000</output>
<gadget id="calculator">9_000 / 100</gadget>
<output>90</output>
<result>B</result> | B | 90 | 33 1/3% OF 270? | {
"A": "80",
"B": "90",
"C": "110",
"D": "120",
"E": "130"
} | divide(multiply(add(33, divide(1, 3)), 270), const_100) | divide(n1,n2)|add(n0,#0)|multiply(n3,#1)|divide(#2,const_100)| | "33 1 / 3 % = 1 / 3 1 / 3 × 270 = 90 b )" | gain |
math_qa__1PysmH2JUQKvji9Y | In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1300 employees, then the no. of female employees who are computer literate ? Choose the correct choice from the following choices:
A) 546
B) 674
C) 672
D) 960
E) none | <gadget id="calculator">62 / 100</gadget>
<output>31/50 = around 0.62</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(2/5) * (1/2)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(31/50) - (1/5)</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">(21/50) * 1_300</gadget>
<output>546</output>
<result>A</result> | A | 546 | In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1300 employees, then the no. of female employees who are computer literate ? | {
"A": "546",
"B": "674",
"C": "672",
"D": "960",
"E": "none"
} | multiply(subtract(divide(62, const_100), multiply(subtract(const_1, divide(60, const_100)), divide(50, const_100))), 1300) | divide(n2,const_100)|divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#2)|multiply(#1,#3)|subtract(#0,#4)|multiply(n3,#5)| | "solution : total employees , = 1300 female employees , 60 % of 1300 . = ( 60 * 1300 ) / 100 = 780 . then male employees , = 520 50 % of male are computer literate , = 260 male computer literate . 62 % of total employees are computer literate , = ( 62 * 1300 ) / 100 = 806 computer literate . thus , female computer literate = 806 - 260 = 546 . answer : option a" | gain |
math_qa__RoKEs7J1ToiettnH | Susan drove an average speed of 15 miles per hour for the first 40 miles of a tripthen at a average speed of 60 miles/hr for the remaining 20 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip
Choose the correct choice from the following answers
A) 35 B) 20 C) 45 D) 50 E) 55 | <gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">40 / 15</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(8/3) + (1/3)</gadget>
<output>3</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<result>B</result> | B | 20 | Susan drove an average speed of 15 miles per hour for the first 40 miles of a tripthen at a average speed of 60 miles/hr for the remaining 20 miles of the trip if she made no stops during the trip what was susan's avg speed in miles/hr for the entire trip | {
"A": "35",
"B": "20",
"C": "45",
"D": "50",
"E": "55"
} | divide(add(40, 20), add(divide(40, 15), divide(20, 60))) | add(n1,n3)|divide(n1,n0)|divide(n3,n2)|add(#1,#2)|divide(#0,#3) | avg . speed = total distance / total time total distance = 60 miles total time = 40 / 15 + 20 / 60 = 3 avg . speed = 20 . answer - b | physics |
math_qa__noQ18mSa50EqyqHy | The perimeter of a semi circle is 113 cm then the radius is? Choose the correct choice from the following options
A) 17 B) 28 C) 19 D) 11 E) 22 | <gadget id="calculator">2 + pi</gadget>
<output>2 + pi = around 5.141593</output>
<gadget id="calculator">113 / (2 + pi)</gadget>
<output>113/(2 + pi) = around 21.977626</output>
<result>E</result> | E | 22 | The perimeter of a semi circle is 113 cm then the radius is? | {
"A": "17",
"B": "28",
"C": "19",
"D": "11",
"E": "22"
} | divide(113, add(const_2, const_pi)) | add(const_2,const_pi)|divide(n0,#0)| | "36 / 7 r = 113 = > r = 22 answer : e" | physics |
math_qa__e3ijAlrhXCvBwHca | A boat having a length 4 m and breadth 3 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is: Options.
A) 12 kg B) 120 kg C) 72 kg D) 96 kg E) none of these | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">12 * (1/100)</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) * 1_000</gadget>
<output>120</output>
<result>B</result> | B | 120 | A boat having a length 4 m and breadth 3 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is: | {
"A": "12 kg",
"B": "120 kg",
"C": "72 kg",
"D": "96 kg",
"E": "none of these"
} | multiply(multiply(multiply(4, 3), divide(1, const_100)), const_1000) | divide(n2,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(#2,const_1000)| | "explanation : volume of water displaced = ( 4 x 3 x 0.01 ) m 3 = 0.12 m 3 . ∴ mass of man = volume of water displaced x density of water = ( 0.12 x 1000 ) kg = 120 kg . answer : b" | physics |
math_qa__FMamcfro4McsQLKh | A train 450 m long running at 108 kmph crosses a platform in 25 sec. What is the length of the platform? Choose the correct option:
A) 271 B) 266 C) 350 D) 277 E) 300 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">108 * (5/18)</gadget>
<output>30</output>
<gadget id="calculator">25 * 30</gadget>
<output>750</output>
<gadget id="calculator">750 - 450</gadget>
<output>300</output>
<result>E</result> | E | 300 | A train 450 m long running at 108 kmph crosses a platform in 25 sec. What is the length of the platform? | {
"A": "271",
"B": "266",
"C": "350",
"D": "277",
"E": "300"
} | subtract(multiply(25, multiply(108, const_0_2778)), 450) | multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0)| | "length of the platform = 108 * 5 / 18 * 25 = 750 – 450 = 300 answer : e" | physics |
math_qa__xBk12g7VWW7uhAqm | When the price of sugar was increased by 32%, a family reduced its consumption in such a way that the expenditure on sugar was only 10% more than before. If 30 kg were consumed per month before, find the new monthly consumption. Choose the correct option
A) 20 kg B) 25 kg C) 30 kg D) 35 kg E) none of these | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">100 + 32</gadget>
<output>132</output>
<gadget id="calculator">110 / 132</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(5/6) * 30</gadget>
<output>25</output>
<result>B</result> | B | 25 | When the price of sugar was increased by 32%, a family reduced its consumption in such a way that the expenditure on sugar was only 10% more than before. If 30 kg were consumed per month before, find the new monthly consumption. | {
"A": "20 kg",
"B": "25 kg",
"C": "30 kg",
"D": "35 kg",
"E": "none of these"
} | multiply(divide(add(const_100, 10), add(const_100, 32)), 30) | add(n1,const_100)|add(n0,const_100)|divide(#0,#1)|multiply(n2,#2) | since , expenditure = price × consumption ∴ 110 % of 30 = 132 ⁄ 100 × new consumption ⇒ 110 ⁄ 100 × 30 = 132 ⁄ 100 × new consumption ⇒ new consumption = 25 kg answer b | general |
math_qa__NSQl6L2ZRQYsMeFE | Find the 25th term of an arithmetic progression whose first term is 5 and the common difference is 7. Choose the correct choice from the following
A) 145 B) 38 C) 173 D) 156 E) 189 | <gadget id="calculator">25 - 1</gadget>
<output>24</output>
<gadget id="calculator">24 * 7</gadget>
<output>168</output>
<gadget id="calculator">168 + 5</gadget>
<output>173</output>
<result>C</result> | C | 173 | Find the 25th term of an arithmetic progression whose first term is 5 and the common difference is 7. | {
"A": "145",
"B": "38",
"C": "173",
"D": "156",
"E": "189"
} | add(multiply(subtract(25, const_1), 7), 5) | subtract(n0,const_1)|multiply(n2,#0)|add(n1,#1) | n th term of a . p = a + ( n - 1 ) * d = 5 + ( 25 - 1 ) * 7 , = 5 + 168 = 173 . answer : c | general |
math_qa__6nUJrlIYUh0J87IA | In a graduating class, 40 percent of the students are male. In this class, 50 percent of the male students and 30 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old? Choices.
A) 0.56
B) 0.62
C) 0.68
D) 0.74
E) 0.8 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(2/5) * (1/2)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/10) * (3/5)</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(1/5) + (9/50)</gadget>
<output>19/50 = around 0.38</output>
<gadget id="calculator">1 - (19/50)</gadget>
<output>31/50 = around 0.62</output>
<result>B</result> | B | 0.62 | In a graduating class, 40 percent of the students are male. In this class, 50 percent of the male students and 30 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old? | {
"A": "0.56",
"B": "0.62",
"C": "0.68",
"D": "0.74",
"E": "0.8"
} | subtract(const_1, add(multiply(divide(40, const_100), divide(50, const_100)), multiply(divide(30, const_100), subtract(const_1, divide(40, const_100))))) | divide(n0,const_100)|divide(n1,const_100)|divide(n2,const_100)|multiply(#0,#1)|subtract(const_1,#0)|multiply(#2,#4)|add(#3,#5)|subtract(const_1,#6) | let x be the total number of students . the number students who are younger than 25 is 0.5 * 0.4 x + 0.7 * 0.6 x = 0.62 x the answer is b . | general |
math_qa__8NwH58HScgL6YCFQ | The function g(a) is defined for integers a such that if a is even, g(a) = a/2 and if a is odd, g(a) = a + 5. Given that g(g(g(g(g(a))))) = 19, how many possible values for a would satisfy this equation?
Pick one.
A) 1
B) 5
C) 7
D) 8
E) 11 | <gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<result>D</result> | D | 8 | The function g(a) is defined for integers a such that if a is even, g(a) = a/2 and if a is odd, g(a) = a + 5. Given that g(g(g(g(g(a))))) = 19, how many possible values for a would satisfy this equation? | {
"A": "1",
"B": "5",
"C": "7",
"D": "8",
"E": "11"
} | add(add(5, 2), const_1) | add(n0,n1)|add(#0,const_1) | let me define terms : in g ( a ) = r a is argument , r is result , g ( ) is function , in g ( g ( g ( g ( g ( a ) ) ) ) ) , g 1 is inner most , g 5 is outermost for identification . from definition of function g , we can deduce that : if result is even then two possibilities for argument = 1 even 1 odd if result is odd then one possibility for argument = 1 even since final result = 19 = odd possibilities : g 1 : 1 even g 2 : 1 * ( even , odd ) = 1 even 1 odd g 3 : 1 * ( even , odd ) + 1 even = 2 even 1 odd g 4 : 2 * ( even , odd ) + 1 even = 3 even 2 odd g 5 : 3 * ( even , odd ) + 2 even = 5 even 3 odd = total 8 ans d it is ! | general |
math_qa__Lf1iDcoZInhJsuxA | There are 16 bees in the hive , then 9 more fly. How many bees are there in all?
Choose the correct choice from the following answers.
A) 7 B) 33 C) 12 D) 17 E) 25 | <gadget id="calculator">16 + 9</gadget>
<output>25</output>
<result>E</result> | E | 25 | There are 16 bees in the hive , then 9 more fly. How many bees are there in all? | {
"A": "7",
"B": "33",
"C": "12",
"D": "17",
"E": "25"
} | add(16, 9) | add(n0,n1) | 16 + 9 = 25 . answer is e . | general |
math_qa__u2QyTrH4UzH9ktrh | Seller selling an apple for Rs.20, a Seller loses 1/6th of what it costs him. The CP of the apple is? Choose the correct choice from the following choices: A) 10 B) 12 C) 21 D) 18 E) 20 | <gadget id="calculator">20 + 1</gadget>
<output>21</output>
<result>C</result> | C | 21 | Seller selling an apple for Rs.20, a Seller loses 1/6th of what it costs him. The CP of the apple is? | {
"A": "10",
"B": "12",
"C": "21",
"D": "18",
"E": "20"
} | add(20, 1) | add(n0,n1)| | "sp = 20 loss = cp 21 loss = cp − sp = cp − 20 ⇒ cp 21 = cp − 20 ⇒ 20 cp 21 = 20 ⇒ cp 21 = 1 ⇒ cp = 21 c" | general |
math_qa__onu94uXFNgPnIYBD | Nina has exactly enough money to purchase 6 widgets. If the cost of each widget were reduced by $1.15, then Nina would have exactly enough money to purchase 8 widgets. How much money does Nina have? Choose the correct choice from the following answers: A) $ 22 B) $ 27.6 C) $ 30 D) $ 36 E) $ 40 | <gadget id="calculator">1.15 * 8</gadget>
<output>9.2</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<gadget id="calculator">9.2 / 2</gadget>
<output>4.6</output>
<gadget id="calculator">4.6 * 6</gadget>
<output>27.6</output>
<result>B</result> | B | 27.6 | Nina has exactly enough money to purchase 6 widgets. If the cost of each widget were reduced by $1.15, then Nina would have exactly enough money to purchase 8 widgets. How much money does Nina have? | {
"A": "$ 22",
"B": "$ 27.6",
"C": "$ 30",
"D": "$ 36",
"E": "$ 40"
} | multiply(divide(multiply(1.15, 8), subtract(8, 6)), 6) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)|multiply(n0,#2)| | "b its is . let price = x ( x - 1.15 ) 8 = 6 x x = 4.6 hence total money = 6 * 4.6 = 27.6" | general |
math_qa__G7Oi9n6K76o8QTVq | A broker invested her own money in the stock market. During the first year, she increased her stock market wealth by 60 percent. In the second year, largely as a result of a slump in the stock market, she suffered a 30 percent decrease in the value of her stock investments. What was the net increase or decrease on her overall stock investment wealth by the end of the second year?
Choose the correct option.
A) − 5 % B) 5 % C) 12 % D) 20 % E) 80 % | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 + (3/5)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(8/5) * (7/10)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">(28/25) - 1</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) * 100</gadget>
<output>12</output>
<result>C</result> | C | 12 | A broker invested her own money in the stock market. During the first year, she increased her stock market wealth by 60 percent. In the second year, largely as a result of a slump in the stock market, she suffered a 30 percent decrease in the value of her stock investments. What was the net increase or decrease on her overall stock investment wealth by the end of the second year? | {
"A": "− 5 %",
"B": "5 %",
"C": "12 %",
"D": "20 %",
"E": "80 %"
} | multiply(subtract(multiply(add(const_1, divide(60, const_100)), subtract(const_1, divide(30, const_100))), const_1), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100) | the actual answer is obtained by multiplying 160 % by 70 % and subtracting 100 % from this total . that is : 160 % × 70 % = 112 % ; 112 % − 100 % = 12 % . answer : c | gain |
math_qa__3bYORCCiuzXJnx5G | A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 1200 m long? Pick.
A) 200 sec B) 240 sec C) 167 sec D) 197 sec E) 179 sec | <gadget id="calculator">1_200 + 1_200</gadget>
<output>2_400</output>
<gadget id="calculator">1_200 / 120</gadget>
<output>10</output>
<gadget id="calculator">2_400 / 10</gadget>
<output>240</output>
<result>B</result> | B | 240 | A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 1200 m long? | {
"A": "200 sec",
"B": "240 sec",
"C": "167 sec",
"D": "197 sec",
"E": "179 sec"
} | divide(add(1200, 1200), divide(1200, 120)) | add(n0,n2)|divide(n0,n1)|divide(#0,#1)| | "l = s * t s = 1200 / 120 s = 10 m / sec . total length ( d ) = 2400 m t = d / s t = 2400 / 10 t = 240 sec answer : b" | physics |
math_qa__T5a4VSYqOFktGXiF | A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform. Select the correct option.
A) 310 meter B) 335 meter C) 345 meter D) 350 meter E) none of these | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 39</gadget>
<output>650</output>
<gadget id="calculator">650 - 300</gadget>
<output>350</output>
<result>D</result> | D | 350 | A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform. | {
"A": "310 meter",
"B": "335 meter",
"C": "345 meter",
"D": "350 meter",
"E": "none of these"
} | subtract(multiply(divide(300, 18), 39), 300) | divide(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "explanation : speed = distance / time = 300 / 18 = 50 / 3 m / sec let the length of the platform be x meters then distance = speed ∗ time x + 300 = 50 / 3 ∗ 39 = > 3 ( x + 300 ) = 1950 = > x = 350 meters option d" | physics |
math_qa__hsbzqN3bt8ICXgZL | A and B go around a circular track of length 100 m on a cycle at speeds of 18 kmph and 36 kmph. After how much time will they meet for the first time at the starting point? Pick
A) 120 sec B) 198 sec C) 178 sec D) 665 sec E) 20 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">18 * (5/18)</gadget>
<output>5</output>
<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<result>E</result> | E | 20 | A and B go around a circular track of length 100 m on a cycle at speeds of 18 kmph and 36 kmph. After how much time will they meet for the first time at the starting point? | {
"A": "120 sec",
"B": "198 sec",
"C": "178 sec",
"D": "665 sec",
"E": "20 sec"
} | divide(100, subtract(multiply(36, const_0_2778), multiply(18, const_0_2778))) | multiply(n2,const_0_2778)|multiply(n1,const_0_2778)|subtract(#0,#1)|divide(n0,#2)| | "time taken to meet for the first time at the starting point = lcm { length of the track / speed of a , length of the track / speed of b } = lcm { 100 / ( 18 * 5 / 18 ) , 100 / ( 36 * 5 / 18 ) } = lcm ( 20 , 10 ) = 20 sec . answer : e" | physics |
math_qa__wVIUb6LvqUlO9F5R | zoey won the lottery and got $ 7 , 348340 . she wants to split it among herself and 5 friends evenly . how much money must she add if she wants to split it evenly ? Choose the correct choice from the following choices
A) $ 3 B) $ 2 C) $ 9 D) $ 1 E) $ 4 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">7 * 1_000_000</gadget>
<output>7_000_000</output>
<gadget id="calculator">7_000_000 + 348_340</gadget>
<output>7_348_340</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">7_348_340 % 6</gadget>
<output>2</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<result>D</result> | D | 1 | zoey won the lottery and got $ 7 , 348340 . she wants to split it among herself and 5 friends evenly . how much money must she add if she wants to split it evenly ? | {
"A": "$ 3",
"B": "$ 2",
"C": "$ 9",
"D": "$ 1",
"E": "$ 4"
} | subtract(reminder(add(multiply(7, multiply(const_1000, const_1000)), 348340), add(5, const_1)), const_1) | add(n2,const_1)|multiply(const_1000,const_1000)|multiply(n0,#1)|add(n1,#2)|reminder(#3,#0)|subtract(#4,const_1) | zoey and her 5 friends is 6 people in all . $ 7 , 348340 must be divisible by 6 if she wants to split it evenly . the money is divisible by 6 if it ' s divisible by 2 and 3 . 7 + 3 + 4 + 8 + 3 + 4 + 0 = 29 . 2 and 3 cant go into 29 . adding 1 dollar makes it 30 . 2 and 3 can go into 30 so 6 can also . the answer is d . | general |
math_qa__iH6rbBjRNwBpYBAp | In a certain code language, 'book' is coded as 'pencil', 'pencil' is coded as 'mirror', 'mirror' is coded as 'board'. Then what is useful to write on a paper?
Pick one
A) 2 B) 6278 C) 277 D) 281 E) 22 | <gadget id="calculator">2 * 1</gadget>
<output>2</output>
<result>A</result> | A | 2 | In a certain code language, 'book' is coded as 'pencil', 'pencil' is coded as 'mirror', 'mirror' is coded as 'board'. Then what is useful to write on a paper? | {
"A": "2",
"B": "6278",
"C": "277",
"D": "281",
"E": "22"
} | multiply(const_2, const_1) | multiply(const_1,const_2) | we use pencil to write on a paper but here pencil is coded as mirror . so , the answer is mirror . answer : a | general |
math_qa__btfRrd9iL8R9salC | A box contains 4 red balls and 4 black balls. One by one, every ball is selected at random without replacement. What is the probability that the fourth ball selected is black? Select:
A) 1 / 4 B) 1 / 2 C) 1 / 2 D) 5 / 8 E) 2 | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 4</gadget>
<output>2</output>
<result>E</result> | E | 2 | A box contains 4 red balls and 4 black balls. One by one, every ball is selected at random without replacement. What is the probability that the fourth ball selected is black? | {
"A": "1 / 4",
"B": "1 / 2",
"C": "1 / 2",
"D": "5 / 8",
"E": "2"
} | divide(add(4, 4), 4) | add(n0,n1)|divide(#0,n1)| | "my complicated version of your simple approach let the 4 black balls be bbbband 4 red balls be rrrr they can be arranged in 8 slots _ _ _ _ _ _ _ _ in ( 8 ! ) / ( 4 ! x 4 ! ) if the fourth slot is black ball then the arrangement will be to fill _ _ _ b _ _ _ _ we have 7 slots and 3 black ( bbb ) and 4 red ( rrrr ) they can be arranged in ( 7 ! ) / ( 4 ! x 3 ! ) hence required probability = [ ( 8 ! ) / ( 4 ! x 4 ! ) ] / [ ( 7 ! ) / ( 4 ! x 3 ! ) ] = 2 e" | probability |
math_qa__CxvOPjvsakqlbLNn | If 50% of (x-y) = 30% of (x+y), then what percent of x is y? Pick one: A) 20 % B) 30 % C) 25 % D) 15 % E) 50 % | <gadget id="calculator">50 - 30</gadget>
<output>20</output>
<gadget id="calculator">50 + 30</gadget>
<output>80</output>
<gadget id="calculator">20 / 80</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | If 50% of (x-y) = 30% of (x+y), then what percent of x is y? | {
"A": "20 %",
"B": "30 %",
"C": "25 %",
"D": "15 %",
"E": "50 %"
} | multiply(divide(subtract(50, 30), add(50, 30)), const_100) | add(n0,n1)|subtract(n0,n1)|divide(#1,#0)|multiply(#2,const_100)| | "50 % of ( x - y ) = 30 % of ( x + y ) 50 / 100 ( x - y ) = 30 / 100 ( x + y ) x = 4 y required percentage = y / x * 100 = y / 4 y * 100 = 25 % answer is c" | general |
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