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stringlengths 7
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math_qa__kZtoi8nbbZzyMvmh | A train is 360 meter long is running at a speed of 36 km/hour. In what time will it pass a bridge of 140 meter length? Choose the correct choice:
A) 50 seconds B) 29 seconds C) 40 seconds D) 11 seconds E) 12 seconds | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">36 * 1_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 3_600</gadget>
<output>10</output>
<gadget id="calculator">500 / 10</gadget>
<output>50</output>
<result>A</result> | A | 50 | A train is 360 meter long is running at a speed of 36 km/hour. In what time will it pass a bridge of 140 meter length? | {
"A": "50 seconds",
"B": "29 seconds",
"C": "40 seconds",
"D": "11 seconds",
"E": "12 seconds"
} | divide(add(360, 140), divide(multiply(36, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 36 km / hr = 36 * ( 5 / 18 ) m / sec = 10 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 * ( 1 / 10 ) = 50 seconds answer : a" | physics |
math_qa__QTAOZteMvX6uNcEF | 15 times a positive integer is more than its square by 56, then the positive integer is
Select.
A) 13
B) 8
C) 11
D) 12
E) 14 | <gadget id="calculator">15 ** 2</gadget>
<output>225</output>
<gadget id="calculator">56 * 4</gadget>
<output>224</output>
<gadget id="calculator">225 - 224</gadget>
<output>1</output>
<gadget id="calculator">15 + 1</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>B</result> | B | 8 | 15 times a positive integer is more than its square by 56, then the positive integer is | {
"A": "13",
"B": "8",
"C": "11",
"D": "12",
"E": "14"
} | divide(add(15, subtract(power(15, const_2), multiply(56, const_4))), const_2) | multiply(n1,const_4)|power(n0,const_2)|subtract(#1,#0)|add(n0,#2)|divide(#3,const_2) | explanation : let the number be x . then , 15 x = x 2 + 56 = > x 2 - 15 x + 56 = 0 = > ( x - 7 ) ( x - 8 ) = 0 = > x = 7 or 8 answer : option b | general |
math_qa__Kn49jMMTraMFndtU | A number exceeds 20% of itself by 40. The number is Select the correct option.
A) 50 B) 60 C) 80 D) 320 E) none | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">40 / (4/5)</gadget>
<output>50</output>
<result>A</result> | A | 50 | A number exceeds 20% of itself by 40. The number is | {
"A": "50",
"B": "60",
"C": "80",
"D": "320",
"E": "none"
} | divide(40, subtract(const_1, divide(20, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1)| | "explanation : let the answer be ' a ' then a β 20 / 100 a = 40 β 5 a β a = 200 β a = 50 β a = 50 correct option : a" | gain |
math_qa__KsgtPfIZoC3zxCYE | A line that passes through (β1, β4) and (3, k) has a slope = k. What is the value of k?
Choose the correct answer: A) 3 / 4 B) 1 C) 4 / 3 D) 2 E) 7 / 2 | <gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<result>C</result> | C | 1.333333 | A line that passes through (β1, β4) and (3, k) has a slope = k. What is the value of k? | {
"A": "3 / 4",
"B": "1",
"C": "4 / 3",
"D": "2",
"E": "7 / 2"
} | divide(4, 3) | divide(n1,n2)| | "this is a considerably more difficult one , which will involve some algebra . let β s say that the β first β point is ( β 1 , β 4 ) and the β second , β ( 3 , k ) . the rise = k + 4 , which involves a variable . the run = 3 β ( β 1 ) = 4 . there the slope is ( k + 4 ) / 4 , and we can set this equal to k and solve for k . { { k + 4 } / 4 } = k k + 4 = 4 k 4 = 3 k k = 4 / 3 answer = c" | general |
math_qa__SbscXiQnixCBpOhm | In a class of 94 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course? Choices
A) 6 B) 15 C) 24 D) 33 E) 40 | <gadget id="calculator">41 + 22</gadget>
<output>63</output>
<gadget id="calculator">63 - 9</gadget>
<output>54</output>
<gadget id="calculator">94 - 54</gadget>
<output>40</output>
<result>E</result> | E | 40 | In a class of 94 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course? | {
"A": "6",
"B": "15",
"C": "24",
"D": "33",
"E": "40"
} | subtract(94, subtract(add(41, 22), 9)) | add(n1,n2)|subtract(#0,n3)|subtract(n0,#1)| | "formula for calculating two overlapping sets : a + b - both + not ( a or b ) = total so in our task we have equation : 41 ( french ) + 22 ( german ) - 9 ( both ) + not = 94 54 + not = 94 not = 94 - 54 = 40 so answer is e" | other |
math_qa__lGjXKVPKTHsFUuei | The faces of storage box are to be painted by 6 different colors. In how many ways can be this be done? Choose one
A) a . 720 B) b . 256 C) c . 1 D) d . 12 E) e . 36 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 4</gadget>
<output>120</output>
<gadget id="calculator">120 * 3</gadget>
<output>360</output>
<gadget id="calculator">360 * 2</gadget>
<output>720</output>
<gadget id="calculator">720 * 1</gadget>
<output>720</output>
<result>A</result> | A | 720 | The faces of storage box are to be painted by 6 different colors. In how many ways can be this be done? | {
"A": "a . 720",
"B": "b . 256",
"C": "c . 1",
"D": "d . 12",
"E": "e . 36"
} | multiply(multiply(multiply(multiply(multiply(6, subtract(6, const_1)), const_4), const_3), const_2), const_1) | subtract(n0,const_1)|multiply(n0,#0)|multiply(#1,const_4)|multiply(#2,const_3)|multiply(#3,const_2)|multiply(#4,const_1) | if i have to paint 6 sides with 6 different colour . . . first face can have 6 c 1 options , 2 nd would have 5 c 1 , and subsequent ones would have 4 c 1 , 3 c 1 , 2 c 1 and 1 options respectively . total options = 6 c 1 x 5 c 1 x 4 c 1 x 3 c 1 x 2 c 1 x 1 = 720 distinct ways correct answer - a | general |
math_qa__6TWhkgG6JTC5d6w5 | If A lends Rs.1000 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is? Choose the correct choice from the following choices
A) 112.5 B) 122.5 C) 132.5 D) 114.5 E) 45 | <gadget id="calculator">1_000 * 11.5</gadget>
<output>11_500</output>
<gadget id="calculator">11_500 * 3</gadget>
<output>34_500</output>
<gadget id="calculator">34_500 / 100</gadget>
<output>345</output>
<gadget id="calculator">1_000 * 10</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 * 3</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 / 100</gadget>
<output>300</output>
<gadget id="calculator">345 - 300</gadget>
<output>45</output>
<result>E</result> | E | 45 | If A lends Rs.1000 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is? | {
"A": "112.5",
"B": "122.5",
"C": "132.5",
"D": "114.5",
"E": "45"
} | subtract(divide(multiply(multiply(1000, 11.5), 3), const_100), divide(multiply(multiply(1000, 10), 3), const_100)) | multiply(n0,n2)|multiply(n0,n1)|multiply(#0,n3)|multiply(n3,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,#5)| | "( 1000 * 1.5 * 3 ) / 100 = > 45 answer : e" | gain |
math_qa__ENSfTAfgoPjvJwpf | In N is a positive integer less than 200, and 14N/60 is an integer, then N has how many different positive prime factors R?
Choose the correct answer:
A) 2
B) 3
C) 5
D) 6
E) 8 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">5 / 5</gadget>
<output>1</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<result>B</result> | B | 3 | In N is a positive integer less than 200, and 14N/60 is an integer, then N has how many different positive prime factors R? | {
"A": "2",
"B": "3",
"C": "5",
"D": "6",
"E": "8"
} | add(divide(add(const_1, const_4), divide(divide(divide(60, const_2), const_2), const_3)), const_2) | add(const_1,const_4)|divide(n2,const_2)|divide(#1,const_2)|divide(#2,const_3)|divide(#0,#3)|add(#4,const_2) | i like to put the numbers in prime factors so it is easier and faster to visualize . 14 * n / 60 if we write the factors of 14 - - > 2 , 7 , and the factors of 60 - - > 2 , 2 , 3 , 5 , we have ( 2 * 7 * n ) / ( 2 ^ 2 * 3 * 5 ) simplifying 7 * n / ( 2 * 3 * 5 ) the only way the equation above has an integer value is if n has at least the factors 2 , 3 and 5 , so we can simplify again and we have the number 7 . the number could be 2 * 3 * 5 , or 2 * 3 * 5 * 2 , or 2 * 3 * 5 * . . . . . however to be less than 200 we can not add any prime number . 2 * 3 * 5 = 120 if we added the next prime factor 7 , we would have r = 2 * 3 * 5 * 7 = 840 thus , answer b | general |
math_qa__9X78X8jdSeHf8jfu | A reduction of 50% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg?
Answers:
A) s . 42
B) s . 46
C) s . 40
D) s . 80
E) s . 34 | <gadget id="calculator">800 * 50</gadget>
<output>40_000</output>
<gadget id="calculator">40_000 / 100</gadget>
<output>400</output>
<gadget id="calculator">400 / 5</gadget>
<output>80</output>
<result>D</result> | D | 80 | A reduction of 50% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg? | {
"A": "s . 42",
"B": "s . 46",
"C": "s . 40",
"D": "s . 80",
"E": "s . 34"
} | divide(divide(multiply(800, 50), const_100), 5) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "800 * ( 50 / 100 ) = 400 - - - - 5 ? - - - - 1 = > rs . 80 answer : d" | gain |
math_qa__5k3OuEd3OkGVIkXP | A candidate who gets 30% of the marks fails by 50 marks. But another candidate who gets 45% marks gets 25 marks more than necessary for passing. Find the number of marks for passing? Answers:
A) 150 B) 200 C) 250 D) 275 E) 285 | <gadget id="calculator">50 + 25</gadget>
<output>75</output>
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(9/20) - (3/10)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">75 / (3/20)</gadget>
<output>500</output>
<gadget id="calculator">500 * (3/10)</gadget>
<output>150</output>
<gadget id="calculator">150 + 50</gadget>
<output>200</output>
<result>B</result> | B | 200 | A candidate who gets 30% of the marks fails by 50 marks. But another candidate who gets 45% marks gets 25 marks more than necessary for passing. Find the number of marks for passing? | {
"A": "150",
"B": "200",
"C": "250",
"D": "275",
"E": "285"
} | add(multiply(divide(add(50, 25), subtract(divide(45, const_100), divide(30, const_100))), divide(30, const_100)), 50) | add(n1,n3)|divide(n2,const_100)|divide(n0,const_100)|subtract(#1,#2)|divide(#0,#3)|multiply(#4,#2)|add(n1,#5) | 30 % - - - - - - - - - - - - 50 45 % - - - - - - - - - - - - 25 - - - - - - - - - - - - - - - - - - - - - - 15 % - - - - - - - - - - - - - 75 30 % - - - - - - - - - - - - - - ? 150 + 50 = 200 marks answer : b | gain |
math_qa__FUPKv1GDlz0jySb7 | The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 2 months, find for how much time did Q invest the money? Answers
A) 8
B) 10
C) 18
D) 4
E) 12 | <gadget id="calculator">7 / 5</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">10 / 7</gadget>
<output>10/7 = around 1.428571</output>
<gadget id="calculator">(7/5) * (10/7)</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<result>D</result> | D | 4 | The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 2 months, find for how much time did Q invest the money? | {
"A": "8",
"B": "10",
"C": "18",
"D": "4",
"E": "12"
} | multiply(multiply(divide(7, 5), divide(10, 7)), 2) | divide(n0,n1)|divide(n3,n2)|multiply(#0,#1)|multiply(n4,#2)| | "7 * 5 : 2 * x = 7 : 10 x = 4 answer : 4 answer is d" | gain |
math_qa__ESUslNAS7eJViDhB | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 35 kg. What is the weight of the new person?
Choose one.
A) 75
B) 65
C) 55
D) 95
E) 80 | <gadget id="calculator">8 * 2.5</gadget>
<output>20</output>
<gadget id="calculator">20 + 35</gadget>
<output>55</output>
<result>C</result> | C | 55 | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 35 kg. What is the weight of the new person? | {
"A": "75",
"B": "65",
"C": "55",
"D": "95",
"E": "80"
} | add(multiply(8, 2.5), 35) | multiply(n0,n1)|add(n2,#0)| | "total increase in weight = 8 Γ 2.5 = 20 if x is the weight of the new person , total increase in weight = x β 35 = > 20 = x - 35 = > x = 20 + 35 = 55 answer is c ." | general |
math_qa__b65UY8wr0HvzWz6B | In the manufacture of a certain product, 4 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale? Choose the correct choice from the following answers
A) 0.125 % B) 0.2 % C) 0.16 % D) 1.25 % E) 2.0 % | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">4 * (1/25)</gadget>
<output>4/25 = around 0.16</output>
<result>C</result> | C | 0.16 | In the manufacture of a certain product, 4 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale? | {
"A": "0.125 %",
"B": "0.2 %",
"C": "0.16 %",
"D": "1.25 %",
"E": "2.0 %"
} | multiply(4, divide(4, const_100)) | divide(n1,const_100)|multiply(n0,#0)| | "percent of defective produced = 4 % percent of the defective units that are shipped for sale = 4 % percent of units produced are defective units that are shipped for sale = ( 4 / 100 ) * ( 4 / 100 ) * 100 % = ( 16 / 10000 ) * 100 % = ( 16 / 100 ) % = . 16 % answer c" | gain |
math_qa__HQHomOPIY0R07GiG | How many seconds will a 770 m long train take to cross a man walking with a speed of 2.5 km/hr in the direction of the moving train if the speed of the train is 46.5 km/hr? Answers: A) 63 B) 88 C) 66 D) 44 E) 35 | <gadget id="calculator">46.5 - 2.5</gadget>
<output>44</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">44 * (5/18)</gadget>
<output>110/9 = around 12.222222</output>
<gadget id="calculator">770 / (110/9)</gadget>
<output>63</output>
<result>A</result> | A | 63 | How many seconds will a 770 m long train take to cross a man walking with a speed of 2.5 km/hr in the direction of the moving train if the speed of the train is 46.5 km/hr? | {
"A": "63",
"B": "88",
"C": "66",
"D": "44",
"E": "35"
} | divide(770, multiply(subtract(46.5, 2.5), const_0_2778)) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 46.5 - 2.5 = 44 km / hr . = 44 * 5 / 18 = 110 / 9 m / sec . time taken to pass the man = 770 * 9 / 110 = 63 sec . answer : a" | physics |
math_qa__HbCSzxisgeOSFNek | At a certain zoo, the ratio of sea lions to penguins is 4 to 11. If there are 84 more penguins than sea lions at the zoo, how many sea lions are there?
Select the correct option:
A) 24
B) 36
C) 48
D) 72
E) 132 | <gadget id="calculator">11 - 4</gadget>
<output>7</output>
<gadget id="calculator">7 / 4</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">84 / (7/4)</gadget>
<output>48</output>
<result>C</result> | C | 48 | At a certain zoo, the ratio of sea lions to penguins is 4 to 11. If there are 84 more penguins than sea lions at the zoo, how many sea lions are there? | {
"A": "24",
"B": "36",
"C": "48",
"D": "72",
"E": "132"
} | divide(84, divide(subtract(11, 4), 4)) | subtract(n1,n0)|divide(#0,n0)|divide(n2,#1) | the ratio as mentioned = 4 / 11 also sea lion + 84 = penguins or , 4 x + 84 = 11 x x = 84 / 7 = 12 number of sea lions = 12 * 4 = 48 answer : c | other |
math_qa__TRZPeFP5aKKWk4At | Two trains of equal length, running with the speeds of 60 and 40 kmph, take 36 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions? Choose the correct answer.
A) 10 sec B) 16 sec C) 19 sec D) 7.2 sec E) 13 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">(5/18) * 20</gadget>
<output>50/9 = around 5.555556</output>
<gadget id="calculator">(50/9) * 36</gadget>
<output>200</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">(5/18) * 100</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">1 / (250/9)</gadget>
<output>9/250 = around 0.036</output>
<gadget id="calculator">200 * (9/250)</gadget>
<output>36/5 = around 7.2</output>
<result>D</result> | D | 7.2 | Two trains of equal length, running with the speeds of 60 and 40 kmph, take 36 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions? | {
"A": "10 sec",
"B": "16 sec",
"C": "19 sec",
"D": "7.2 sec",
"E": "13 sec"
} | multiply(multiply(multiply(const_0_2778, subtract(60, 40)), 36), inverse(multiply(const_0_2778, add(60, 40)))) | add(n0,n1)|subtract(n0,n1)|multiply(#0,const_0_2778)|multiply(#1,const_0_2778)|inverse(#2)|multiply(n2,#3)|multiply(#4,#5) | rs = 60 - 40 = 20 * 5 / 18 = 100 / 18 t = 36 d = 36 * 100 / 18 = 200 rs = 60 + 40 = 100 * 5 / 18 t = 200 * 18 / 500 = 7.2 sec answer : d | physics |
math_qa__hrWNmvqltOekxqwr | If X+Y = 2X+Z, X-2Y = 4Z and X+Y+Z = 21, what is the value of Y/Z? Choose the correct choice from the following options
A) - 4.5 . B) - 2 . C) - 1.7 . D) 3 . E) 6 . | <gadget id="calculator">21 / 2</gadget>
<output>21/2 = around 10.5</output>
<gadget id="calculator">21 / 10</gadget>
<output>21/10 = around 2.1</output>
<gadget id="calculator">-(21/10)</gadget>
<output>-21/10 = around -2.1</output>
<gadget id="calculator">(21/2) / (-21/10)</gadget>
<output>-5</output>
<gadget id="calculator">-(-5)</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>E</result> | E | 6 | If X+Y = 2X+Z, X-2Y = 4Z and X+Y+Z = 21, what is the value of Y/Z? | {
"A": "- 4.5 .",
"B": "- 2 .",
"C": "- 1.7 .",
"D": "3 .",
"E": "6 ."
} | add(negate(divide(divide(21, 2), negate(divide(21, const_10)))), const_1) | divide(n3,n0)|divide(n3,const_10)|negate(#1)|divide(#0,#2)|negate(#3)|add(#4,const_1) | x + y = 2 x + 2 z y = x + 2 z - - - - - - - - - - 1 x - 2 y = 4 z x - 4 z = 2 y - - - - - - - - - 2 subtracting equation 1 from equation 2 - 6 z = y y / z = - 6 e is the answer | general |
math_qa__zYXNGO5oARSomwwO | The bankers discount of a certain sum of money is Rs. 36 and the true discount on the same sum for the same time is Rs. 30. The sum due is: Select.
A) 140 B) 150 C) 160 D) 170 E) 180 | <gadget id="calculator">30 * 36</gadget>
<output>1_080</output>
<gadget id="calculator">36 - 30</gadget>
<output>6</output>
<gadget id="calculator">1_080 / 6</gadget>
<output>180</output>
<result>E</result> | E | 180 | The bankers discount of a certain sum of money is Rs. 36 and the true discount on the same sum for the same time is Rs. 30. The sum due is: | {
"A": "140",
"B": "150",
"C": "160",
"D": "170",
"E": "180"
} | divide(multiply(30, 36), subtract(36, 30)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "sum = ( b . d * t . d ) / ( b . d - t . d ) ( 36 * 30 ) / 36 - 30 ; 180 answer : e" | gain |
math_qa__hdNFfD34VaX1b4Nv | 12 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? Pick one:
A) 190 B) 132 C) 210 D) 220 E) 225 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">12 * 11</gadget>
<output>132</output>
<result>B</result> | B | 132 | 12 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? | {
"A": "190",
"B": "132",
"C": "210",
"D": "220",
"E": "225"
} | multiply(12, subtract(12, const_1)) | subtract(n0,const_1)|multiply(n0,#0)| | "though 2 * ( 12 c 2 ) is the correct approcah to do this , but for people like me who find perm , comb n prob a nightmare , an easy approach can be used . the first guy has to play 2 matches with the rest of 11 , so he ' ll play 22 matches . similarly , second guy has to play with the rest of 10 as his 2 games with the first guy are already played . so he plays 20 matches . this continues like this and the total matches are 22 + 20 + 18 . . . + 2 22 + 20 + . . . + 2 = 2 ( 11 + 10 + . . . + 1 ) = 2 ( ( 11 * 12 ) / 2 ) = 11 * 12 = 132 . answer : b" | general |
math_qa__kUc8rKYgYJgbqX6j | One hour after Adrienne started walking the 60 miles from X to Y, Harold started walking from X to Y as well. Adrienne walks 3 miles per hour and Harold walks 1 mile per hour faster than Adrienne. How far from X will Harold be when he catches up to Adrienne? Pick one.
A) 8 miles B) 12 miles C) 10 miles D) 11 miles E) 14 miles | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<result>B</result> | B | 12 | One hour after Adrienne started walking the 60 miles from X to Y, Harold started walking from X to Y as well. Adrienne walks 3 miles per hour and Harold walks 1 mile per hour faster than Adrienne. How far from X will Harold be when he catches up to Adrienne? | {
"A": "8 miles",
"B": "12 miles",
"C": "10 miles",
"D": "11 miles",
"E": "14 miles"
} | multiply(3, add(3, 1)) | add(n1,n2)|multiply(n1,#0) | first , determine how far adrienne has walked in the one hour . she has walked three miles which means she is three miles ahead of harold when he sets off . harold walks at four miles / hour which means that every hour , harold will get one mile closer to adrienne . if he gets one mile closer every hour , it will take him three hours to catch up to her which means he travels 3 hours * 4 miles / hour = 12 miles and she travels 4 hours * 3 miles / hour = 12 miles . he will be 12 miles from x when he catches up to her . a slightly different way to solve . . . we do n ' t know how long they will walk before they catch up to one another but we do know that a walks for one hour more than j . j = t and a = t + 1 . we are looking for the distance at which they meet up which means the distance will be the same . d = r * t so , r * t ( harold ) = r * t ( adrienne ) r * ( t ) = r * ( t + 1 ) 4 t = 3 t + 3 t = 3 d = r * t d = 4 * 3 d = 12 b ) 12 miles | physics |
math_qa__v5WKCcR62r9h523l | In a division, a student took 48 as divisor instead of 36. his answer was 24 . The correct answer is- Options.
A) 42 B) 32 C) 48 D) 28 E) 38 | <gadget id="calculator">48 * 24</gadget>
<output>1_152</output>
<gadget id="calculator">1_152 / 36</gadget>
<output>32</output>
<result>B</result> | B | 32 | In a division, a student took 48 as divisor instead of 36. his answer was 24 . The correct answer is- | {
"A": "42",
"B": "32",
"C": "48",
"D": "28",
"E": "38"
} | divide(multiply(48, 24), 36) | multiply(n0,n2)|divide(#0,n1)| | "x / 48 = 24 . x = 24 * 48 . so correct answer would be , ( 24 * 48 ) / 36 = 32 . answer : b" | general |
math_qa__NcO76tu7irde3eFL | A man can row upstream at 20 kmph and downstream at 60 kmph, and then find the speed of the man in still water? Choose the correct choice from the following choices
A) 32 kmph
B) 34 kmph
C) 30 kmph
D) 45 kmph
E) 40 kmph | <gadget id="calculator">20 + 60</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>E</result> | E | 40 | A man can row upstream at 20 kmph and downstream at 60 kmph, and then find the speed of the man in still water? | {
"A": "32 kmph",
"B": "34 kmph",
"C": "30 kmph",
"D": "45 kmph",
"E": "40 kmph"
} | divide(add(20, 60), const_2) | add(n0,n1)|divide(#0,const_2)| | "us = 20 ds = 60 m = ( 20 + 60 ) / 2 = 40 answer : e" | physics |
math_qa__Uig0bYkXhq0AGill | Two family reunions are happening at the same hotel, the Dates reunion and the Hall reunion. All 50 guests at the hotel attend at least one of the reunions. If 50 people attend the Dates reunion and 60 people attend the Hall reunion, how many people attend both reunions? Select the correct option:
A) 2
B) 5
C) 10
D) 16
E) 60 | <gadget id="calculator">50 + 60</gadget>
<output>110</output>
<gadget id="calculator">110 - 50</gadget>
<output>60</output>
<result>E</result> | E | 60 | Two family reunions are happening at the same hotel, the Dates reunion and the Hall reunion. All 50 guests at the hotel attend at least one of the reunions. If 50 people attend the Dates reunion and 60 people attend the Hall reunion, how many people attend both reunions? | {
"A": "2",
"B": "5",
"C": "10",
"D": "16",
"E": "60"
} | subtract(add(50, 60), 50) | add(n0,n2)|subtract(#0,n0) | no of people in dates reunion = 50 no of people in hall reunion = 60 attending both = x all guests attend at least one . therefore , 50 = 50 + 60 - ( both ) both = 60 answer e | other |
math_qa__8k6NfGkvDjSBUKR2 | A person travels equal distances with speeds of 6km/hr, 12km/hr,18km/hr. and takes a total time of 11minutes. Find the total distance ?
Pick one:
A) 1 km B) 1500 mts C) 1800 mts D) 2 km E) 1250 mts | <gadget id="calculator">11 / 60</gadget>
<output>11/60 = around 0.183333</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/6) + (1/12)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/4) + (1/18)</gadget>
<output>11/36 = around 0.305556</output>
<gadget id="calculator">(11/60) / (11/36)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 3</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) * 1_000</gadget>
<output>1_800</output>
<result>C</result> | C | 1,800 | A person travels equal distances with speeds of 6km/hr, 12km/hr,18km/hr. and takes a total time of 11minutes. Find the total distance ? | {
"A": "1 km",
"B": "1500 mts",
"C": "1800 mts",
"D": "2 km",
"E": "1250 mts"
} | multiply(multiply(divide(divide(11, const_60), add(add(divide(const_1, 6), divide(const_1, 12)), divide(const_1, 18))), const_3), const_1000) | divide(n3,const_60)|divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#1,#2)|add(#4,#3)|divide(#0,#5)|multiply(#6,const_3)|multiply(#7,const_1000)| | "let the each distance be x km total distance = 3 x then total time , ( x / 6 ) + ( x / 12 ) + ( x / 18 ) = 11 / 60 x = 0.6 total distance = 3 * 0.6 = 1.8 km = 1800 meters correct option is c" | physics |
math_qa__GIoLYSDBv6O834sP | Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 5x boxes? Choices:
A) 3 minutes B) 4 minutes C) 5 minutes D) 6 minutes E) 10 minutes | <gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">50 / 5</gadget>
<output>10</output>
<result>E</result> | E | 10 | Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 5x boxes? | {
"A": "3 minutes",
"B": "4 minutes",
"C": "5 minutes",
"D": "6 minutes",
"E": "10 minutes"
} | divide(multiply(5, 10), add(speed(10, 10), speed(multiply(2, 10), 5))) | multiply(n0,n3)|multiply(n0,n1)|speed(n0,n0)|speed(#1,n2)|add(#2,#3)|divide(#0,#4)| | "rate = work / time given rate of machine a = x / 10 min machine b produces 2 x boxes in 5 min hence , machine b produces 4 x boxes in 10 min . rate of machine b = 4 x / 10 we need tofind the combined time that machines a and b , working simultaneouslytakeat their respective constant rates let ' s first find the combined rate of machine a and b rate of machine a = x / 10 min + rate of machine b = 4 x / 10 = 5 x / 10 now combine time = combine work needs to be done / combine rate = 5 x / 5 x * 10 = 10 min ans : e" | physics |
math_qa__Co2iTVZeSGzg0JUt | The volume of a cube is 1331 cc. Find its surface. Choose the correct choice from the following options
A) 864
B) 726
C) 255
D) 287
E) 267 | <gadget id="calculator">1_331 ** (1/3)</gadget>
<output>11</output>
<gadget id="calculator">6 * (11 ** 2)</gadget>
<output>726</output>
<result>B</result> | B | 726 | The volume of a cube is 1331 cc. Find its surface. | {
"A": "864",
"B": "726",
"C": "255",
"D": "287",
"E": "267"
} | surface_cube(cube_edge_by_volume(1331)) | cube_edge_by_volume(n0)|surface_cube(#0)| | "a 3 = 1331 = > a = 11 6 a 2 = 6 * 11 * 11 = 726 answer : b" | geometry |
math_qa__idQECg8Jnq180erA | Two trains 180 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? Choose the correct choice from the following answers: A) 10.7 B) 10.9 C) 10.24 D) 12.24 E) 18.8 | <gadget id="calculator">180 + 160</gadget>
<output>340</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">340 / (250/9)</gadget>
<output>306/25 = around 12.24</output>
<result>D</result> | D | 12.24 | Two trains 180 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "10.7",
"B": "10.9",
"C": "10.24",
"D": "12.24",
"E": "18.8"
} | divide(add(180, 160), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 180 + 160 = 340 m . required time = 340 * 9 / 250 = 12.24 sec . answer : d" | physics |
math_qa__uZ8MKYDXL68eD3wK | A train passes a man standing on a platform in 8 seconds and also crosses the platform which is 267 metres long in 20 seconds. The length of the train (in metres) is: Select the correct option:
A) 178 B) 176 C) 175 D) 96 E) none of these | <gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">267 / 12</gadget>
<output>89/4 = around 22.25</output>
<gadget id="calculator">(89/4) * 8</gadget>
<output>178</output>
<result>A</result> | A | 178 | A train passes a man standing on a platform in 8 seconds and also crosses the platform which is 267 metres long in 20 seconds. The length of the train (in metres) is: | {
"A": "178",
"B": "176",
"C": "175",
"D": "96",
"E": "none of these"
} | multiply(divide(267, subtract(20, 8)), 8) | subtract(n2,n0)|divide(n1,#0)|multiply(n0,#1) | explanation : let the length of train be l m . acc . to question ( 267 + l ) / 20 = l / 8 2136 + 8 l = 20 l l = 2136 / 12 = 178 m answer a | physics |
math_qa__jzl4w2uqc89wpmOe | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 160 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?
Choose the correct choice from the following
A) 600 B) 320 C) 500 D) 520 E) 720 | <gadget id="calculator">160 * 2</gadget>
<output>320</output>
<result>B</result> | B | 320 | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 160 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school? | {
"A": "600",
"B": "320",
"C": "500",
"D": "520",
"E": "720"
} | multiply(160, const_2) | multiply(n0,const_2)| | "let the number of children in the school be x . since each child gets 2 bananas , total number of bananas = 2 x . 2 x / ( x - 160 ) = 2 + 2 ( extra ) = > 2 x - 320 = x = > x = 320 . answer : b" | general |
math_qa__FWWufwufE9nBUJQB | A certain store sold pens for $0.35 each and pencils for $0.25 each. If a customer purchased both pens and pencils from the store for a total of $3.00, what total number of pens and pencils did the customer purchase?
Choose the correct choice from the following choices.
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">0.35 + 0.25</gadget>
<output>0.6</output>
<gadget id="calculator">3 / 0.6</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<result>C</result> | C | 10 | A certain store sold pens for $0.35 each and pencils for $0.25 each. If a customer purchased both pens and pencils from the store for a total of $3.00, what total number of pens and pencils did the customer purchase? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | multiply(divide(3, add(0.35, 0.25)), const_2) | add(n0,n1)|divide(n2,#0)|multiply(#1,const_2) | answer : algebraically , the question looks like this : 3.0 = 0.35 x + 0.25 y there are six possible numbers of pens that fit that requirement : 1 pen : $ 0.35 2 pens : $ 0.70 3 pens : $ 1.05 4 pens : $ 1.40 5 pens : $ 1.75 balance 1.25 5 pencils cost $ 1.25 that ' s 5 pens and 5 pencils choice ( c ) is correct . | other |
math_qa__LuAG2T5EGRBKNzso | 4 weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 6 weavers in 6 days? Choose the correct option:
A) 6 B) 9 C) 12 D) 15 E) 18 | <gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">4 / 16</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">6 * (1/4)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">6 * (3/2)</gadget>
<output>9</output>
<result>B</result> | B | 9 | 4 weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 6 weavers in 6 days? | {
"A": "6",
"B": "9",
"C": "12",
"D": "15",
"E": "18"
} | multiply(6, multiply(6, divide(4, multiply(4, 4)))) | multiply(n0,n0)|divide(n0,#0)|multiply(n3,#1)|multiply(n3,#2) | 1 weaver can weave 1 mat in 4 days . 6 weavers can weave 6 mats in 4 days . 6 weavers can weave 9 mats in 6 days . the answer is b . | gain |
math_qa__l80mg7PIDMZs73FA | A number whose fifth part increased by 6 is equal to its fourth part diminished by 6 is ? Choose the correct choice from the following choices:
A) 160
B) 180
C) 200
D) 240
E) none | <gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/4) - (1/5)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">12 / (1/20)</gadget>
<output>240</output>
<result>D</result> | D | 240 | A number whose fifth part increased by 6 is equal to its fourth part diminished by 6 is ? | {
"A": "160",
"B": "180",
"C": "200",
"D": "240",
"E": "none"
} | divide(add(6, 6), subtract(divide(const_1, const_4), divide(const_1, add(const_1, const_4)))) | add(n0,n1)|add(const_1,const_4)|divide(const_1,const_4)|divide(const_1,#1)|subtract(#2,#3)|divide(#0,#4)| | "answer let the number be n . then , ( n / 5 ) + 6 = ( n / 4 ) - 6 Γ’ β‘ β ( n / 4 ) - ( n / 5 ) = 12 Γ’ β‘ β ( 5 n - 4 n ) / 20 = 12 Γ’ Λ Β΄ n = 240 option : d" | general |
math_qa__JdA2LODjVoif10CI | How many seconds will a train 120 meters long take to cross a bridge 200 meters long if the speed of the train is 36 kmph?
Choose the correct choice from the following: A) 22 sec B) 32 sec C) 25 sec D) 24 sec E) 31 sec | <gadget id="calculator">200 + 120</gadget>
<output>320</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">320 / 10</gadget>
<output>32</output>
<result>B</result> | B | 32 | How many seconds will a train 120 meters long take to cross a bridge 200 meters long if the speed of the train is 36 kmph? | {
"A": "22 sec",
"B": "32 sec",
"C": "25 sec",
"D": "24 sec",
"E": "31 sec"
} | divide(add(200, 120), multiply(36, const_0_2778)) | add(n0,n1)|multiply(n2,const_0_2778)|divide(#0,#1)| | "explanation : d = 120 + 200 = 320 s = 36 * 5 / 18 = 10 mps t = 250 / 10 = 32 sec answer : option b" | physics |
math_qa__135lEl3QYpCESq2M | Robert ate 7 chocolates, Nickel ate 3 chocolates. How many more chocolates did Robert ate than nickel? Choices
A) 4
B) 7
C) 9
D) 5
E) 2 | <gadget id="calculator">7 - 3</gadget>
<output>4</output>
<result>A</result> | A | 4 | Robert ate 7 chocolates, Nickel ate 3 chocolates. How many more chocolates did Robert ate than nickel? | {
"A": "4",
"B": "7",
"C": "9",
"D": "5",
"E": "2"
} | subtract(7, 3) | subtract(n0,n1)| | 7 - 3 = 4 . answer is a | general |
math_qa__NiVAu5x8shRQ7ORI | A car traveling at a certain constant speed takes 20 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 36 kilometers per hour. At what speed, in kilometers per hour, is the car traveling? Choose the correct answer:
A) 24
B) 26
C) 28
D) 30
E) 32 | <gadget id="calculator">1 / 36</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">3_600 * (1/36)</gadget>
<output>100</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 3_600</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / (1/30)</gadget>
<output>30</output>
<result>D</result> | D | 30 | A car traveling at a certain constant speed takes 20 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 36 kilometers per hour. At what speed, in kilometers per hour, is the car traveling? | {
"A": "24",
"B": "26",
"C": "28",
"D": "30",
"E": "32"
} | divide(1, divide(add(multiply(const_3600, divide(1, 36)), 20), const_3600)) | divide(n1,n3)|multiply(#0,const_3600)|add(n0,#1)|divide(#2,const_3600)|divide(n1,#3)| | "36 * t = 1 km = > t = 1 / 36 km / h v * ( t + 20 / 3600 ) = 1 v ( 1 / 36 + 20 / 3600 ) = 1 v ( 120 / 3600 ) = 1 v = 30 km / h the answer is d ." | physics |
math_qa__65FdCFiuRGi5WySt | The product of x and y is a constant. If the value of x is increased by 50%, by what percentage must the value of y be decreased? Select:
A) 50 %
B) 40 %
C) 33 1 β 3 %
D) 25 %
E) 12 1 β 2 % | <gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">100 / 150</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>C</result> | C | 33 | The product of x and y is a constant. If the value of x is increased by 50%, by what percentage must the value of y be decreased? | {
"A": "50 %",
"B": "40 %",
"C": "33 1 β 3 %",
"D": "25 %",
"E": "12 1 β 2 %"
} | multiply(subtract(const_1, divide(const_100, add(const_100, 50))), const_100) | add(n0,const_100)|divide(const_100,#0)|subtract(const_1,#1)|multiply(#2,const_100)| | "product of x and y = xy if the value of x is increased by 50 % , value of y needs to be = xy / ( 1.5 x ) = 2 / 3 y decrease in value of y = y - 2 / 3 y = 1 / 3 y % decrease in value of y = ( 1 / 3 y ) / y * 100 % = 33 1 β 3 % answer c" | general |
math_qa__Kd9gw0c8okB53COu | Working at a constant rate, P can finish a job in 3 hours. Q, also working at a constant rate, can finish the same job in 15 hours. If they work together for 2 hours, how many more minutes will it take P to finish the job, working alone at his constant rate? Choose the correct choice from the following answers: A) 30 B) 36 C) 40 D) 45 E) 48 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/3) + (1/15)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 2</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / (1/3)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 60</gadget>
<output>36</output>
<result>B</result> | B | 36 | Working at a constant rate, P can finish a job in 3 hours. Q, also working at a constant rate, can finish the same job in 15 hours. If they work together for 2 hours, how many more minutes will it take P to finish the job, working alone at his constant rate? | {
"A": "30",
"B": "36",
"C": "40",
"D": "45",
"E": "48"
} | multiply(divide(subtract(const_1, multiply(add(inverse(3), inverse(15)), const_2)), inverse(3)), const_60) | inverse(n0)|inverse(n1)|add(#0,#1)|multiply(#2,const_2)|subtract(const_1,#3)|divide(#4,#0)|multiply(#5,const_60) | each hour they complete 1 / 3 + 1 / 15 = 2 / 5 of the job . in 2 hours , they complete 2 ( 2 / 5 ) = 4 / 5 of the job . the time for p to finish is ( 1 / 5 ) / ( 1 / 3 ) = ( 3 / 5 ) hour = 36 minutes the answer is b . | physics |
math_qa__IAKlfg6ILGfYtR4f | What is the sum of the digits of integer k, if k = (10^30- 54)
Choose the correct option.
A) 251 B) 261 C) 262 D) 269 E) 278 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">30 - 2</gadget>
<output>28</output>
<gadget id="calculator">9 * 28</gadget>
<output>252</output>
<gadget id="calculator">252 + 10</gadget>
<output>262</output>
<result>C</result> | C | 262 | What is the sum of the digits of integer k, if k = (10^30- 54) | {
"A": "251",
"B": "261",
"C": "262",
"D": "269",
"E": "278"
} | add(multiply(subtract(10, const_1), subtract(30, const_2)), 10) | subtract(n0,const_1)|subtract(n1,const_2)|multiply(#0,#1)|add(#2,n0)| | "there are 31 digits in 10 ^ 30 when we subtract 54 from it , there will be 30 digits left . 10 ^ 30 can be written as 9999999 . . . . ( 30 times ) + 1 so , 10 ^ 30 - 54 = 9999999 . . . . ( 30 times ) + 1 - 54 = 9999999 . . . . ( 30 times ) - 53 consider the last 2 digits , 99 - 53 = 46 the last 2 digits will be 46 . and our number would be 99999 . . . . . . 99946 with 2 less 9 s after subtraction . number of 9 s left are 28 and the last two digits are 46 the sum of the digits will be ( 28 * 9 ) + 4 + 6 = 262 answer : - c" | general |
math_qa__8eDv3v85AxVIFRq6 | A football team lost 5 yards and then gained 7. What is the team's progress? Choose the most appropriate option.
A) 2 B) 4 C) 5 D) 6 E) 8 | <gadget id="calculator">7 - 5</gadget>
<output>2</output>
<result>A</result> | A | 2 | A football team lost 5 yards and then gained 7. What is the team's progress? | {
"A": "2",
"B": "4",
"C": "5",
"D": "6",
"E": "8"
} | subtract(7, 5) | subtract(n1,n0) | for lost , use negative . for gain , use positive . progress = - 5 + 7 = 2 yards a | gain |
math_qa__xnJfux8b3b58dOvQ | A batsman makes a score of 90 runs in the 11th inning and thus increases his average by 5. Find his average after 11th inning. Choose the correct choice from the following choices.
A) 40 B) 50 C) 62 D) 45 E) 56 | <gadget id="calculator">11 * 5</gadget>
<output>55</output>
<gadget id="calculator">90 - 55</gadget>
<output>35</output>
<gadget id="calculator">35 + 5</gadget>
<output>40</output>
<result>A</result> | A | 40 | A batsman makes a score of 90 runs in the 11th inning and thus increases his average by 5. Find his average after 11th inning. | {
"A": "40",
"B": "50",
"C": "62",
"D": "45",
"E": "56"
} | add(subtract(90, multiply(11, 5)), 5) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "let the average after 11 th inning = x then , average after 10 th inning = x - 5 10 ( x - 5 ) + 90 = 11 x x = 90 - 50 = 40 answer is a" | general |
math_qa__cNJvdhbMpbycxsRN | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 72, then how old is B? Pick
A) 28 years B) 19 years C) 29 years D) 10 years E) 12 years | <gadget id="calculator">72 - 2</gadget>
<output>70</output>
<gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">140 / 5</gadget>
<output>28</output>
<result>A</result> | A | 28 | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 72, then how old is B? | {
"A": "28 years",
"B": "19 years",
"C": "29 years",
"D": "10 years",
"E": "12 years"
} | divide(multiply(subtract(72, const_2), const_2), add(const_4, const_1)) | add(const_1,const_4)|subtract(n0,const_2)|multiply(#1,const_2)|divide(#2,#0)| | "let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 72 5 x = 70 = > x = 14 hence , b ' s age = 2 x = 28 years . answer : a" | general |
math_qa__QDJYXcM5KAntTYXV | Dick and Jane each saved $1,000 in 1989. In 1990 Dick saved 15 percent more than in 1989, and together he and Jane saved a total of $2,000. Approximately what percent less did Jane save in 1990 than in 1989? Choose the correct choice:
A) 3 % B) 5 % C) 10 % D) 15 % E) 18 % | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) + 1</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">2 - (23/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">1 - (17/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>D</result> | D | 15 | Dick and Jane each saved $1,000 in 1989. In 1990 Dick saved 15 percent more than in 1989, and together he and Jane saved a total of $2,000. Approximately what percent less did Jane save in 1990 than in 1989? | {
"A": "3 %",
"B": "5 %",
"C": "10 %",
"D": "15 %",
"E": "18 %"
} | multiply(subtract(const_1, subtract(const_2, add(divide(15, const_100), const_1))), const_100) | divide(n3,const_100)|add(#0,const_1)|subtract(const_2,#1)|subtract(const_1,#2)|multiply(#3,const_100) | 1990 dick saved = $ 1150 jane saved = $ 850 ( jane saved $ 150 less than she did the prior year ) jane saved approximately $ 150 / 1000 $ ( 15 % ) less in 1990 answer : d | general |
math_qa__oov8iy5GWfM7s726 | Worker A takes 10 hours to do a job. Worker B takes 15 hours to do the same job. How long it take both A & B, working together but independently, to do the same job? Choose the correct choice from the following answers
A) 40 days
B) 40 / 9 days
C) 39 / 9 days
D) 6 days
E) 60 / 9 days | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) + (1/15)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>D</result> | D | 6 | Worker A takes 10 hours to do a job. Worker B takes 15 hours to do the same job. How long it take both A & B, working together but independently, to do the same job? | {
"A": "40 days",
"B": "40 / 9 days",
"C": "39 / 9 days",
"D": "6 days",
"E": "60 / 9 days"
} | divide(const_1, add(divide(const_1, 10), divide(const_1, 15))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)| | "a ' s one hour work = 1 / 10 . b ' s one hour work = 1 / 15 . ( a + b ) ' s one hour work = 1 / 10 + 1 / 15 = 5 / 30 = 1 / 6 . both a & b can finish the work in 6 days d" | physics |
math_qa__bNdPjm4j8Ted7vnL | a,b,c,d,e sitting in a row what is the probability that a & b sitting adjacent. Pick one
A) 1 / 5 B) 2 / 5 C) 3 / 5 D) 4 / 5 E) 6 / 5 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">factorial(3) / factorial(3 - 3)</gadget>
<output>6</output>
<gadget id="calculator">8 * 6</gadget>
<output>48</output>
<gadget id="calculator">factorial(5) / factorial(5 - 5)</gadget>
<output>120</output>
<gadget id="calculator">48 / 120</gadget>
<output>2/5 = around 0.4</output>
<result>B</result> | B | 0.4 | a,b,c,d,e sitting in a row what is the probability that a & b sitting adjacent. | {
"A": "1 / 5",
"B": "2 / 5",
"C": "3 / 5",
"D": "4 / 5",
"E": "6 / 5"
} | divide(multiply(multiply(const_4, const_2), permutation(const_3, const_3)), permutation(const_5, const_5)) | multiply(const_2,const_4)|permutation(const_3,const_3)|permutation(const_5,const_5)|multiply(#0,#1)|divide(#3,#2) | total number of arrangement is = 5 ! = 120 favorable event i . e a and b can be arranged in 2 ! and the remaining can be arranged in 4 ! since ab can be in any of the four positions . so 4 ! * 2 ! / 5 ! = 2 / 5 answer : b | probability |
math_qa__fnQ5LQs2SWsd5EyO | How many seconds will a 620 metre long train take to cross a man running with a speed of 8 km/hr in the direction of the moving train if the speed of the train is 80 km/hr?
Choose the correct choice from the following answers.
A) 25 B) 30 C) 31 D) 45 E) 60 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">80 - 8</gadget>
<output>72</output>
<gadget id="calculator">(5/18) * 72</gadget>
<output>20</output>
<gadget id="calculator">620 / 20</gadget>
<output>31</output>
<result>C</result> | C | 31 | How many seconds will a 620 metre long train take to cross a man running with a speed of 8 km/hr in the direction of the moving train if the speed of the train is 80 km/hr? | {
"A": "25",
"B": "30",
"C": "31",
"D": "45",
"E": "60"
} | divide(620, multiply(const_0_2778, subtract(80, 8))) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "explanation : speed of train relatively to man = ( 80 - 8 ) km / hr = 72 km / hr = ( 72 x 5 / 18 ) m / sec = 20 m / sec time taken to pass the man = ( 620 / 20 ) sec = 31 sec . answer : c" | physics |
math_qa__kmMfMNafe1Y73v1P | In an election a candidate who gets 60% of the votes is elected by a majority of 1040 votes. What is the total number of votes polled? Choose the most appropriate option:
A) 4500 B) 5200 C) 6900 D) 7520 E) 6000 | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1_040 / (1/5)</gadget>
<output>5_200</output>
<result>B</result> | B | 5,200 | In an election a candidate who gets 60% of the votes is elected by a majority of 1040 votes. What is the total number of votes polled? | {
"A": "4500",
"B": "5200",
"C": "6900",
"D": "7520",
"E": "6000"
} | divide(1040, divide(subtract(60, subtract(const_100, 60)), const_100)) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)| | "let the total number of votes polled be x then , votes polled by other candidate = ( 100 - 60 ) % of x = 40 % of x 60 % of x - 40 % of x = 1040 20 x / 100 = 1040 x = 1040 * 100 / 20 = 5200 answer is b" | gain |
math_qa__5RoKyx4U4oo16SXq | A person is traveling at 40 km/hr and reached his destiny in 6 hr then find the distance? Answers:
A) 260 km B) 240 km C) 280 km D) 340 km E) 350 km | <gadget id="calculator">40 * 6</gadget>
<output>240</output>
<result>B</result> | B | 240 | A person is traveling at 40 km/hr and reached his destiny in 6 hr then find the distance? | {
"A": "260 km",
"B": "240 km",
"C": "280 km",
"D": "340 km",
"E": "350 km"
} | multiply(40, 6) | multiply(n0,n1)| | "t = 6 hrs d = t * s = 40 * 6 = 240 km answer is b" | physics |
math_qa__Mnb42BzOp1a47XcR | A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.07. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total for a book on the fifth day it is overdue?
Choose the correct choice from the following choices:
A) $ 0.60 B) $ 0.70 C) $ 0.86 D) $ 0.90 E) $ 1.00 | <gadget id="calculator">0.07 * 2</gadget>
<output>0.14</output>
<gadget id="calculator">0.14 * 2</gadget>
<output>0.28</output>
<gadget id="calculator">0.28 * 2</gadget>
<output>0.56</output>
<gadget id="calculator">0.56 + 0.3</gadget>
<output>0.86</output>
<result>C</result> | C | 0.86 | A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.07. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total for a book on the fifth day it is overdue? | {
"A": "$ 0.60",
"B": "$ 0.70",
"C": "$ 0.86",
"D": "$ 0.90",
"E": "$ 1.00"
} | add(multiply(multiply(multiply(0.07, const_2), const_2), const_2), 0.30) | multiply(n0,const_2)|multiply(#0,const_2)|multiply(#1,const_2)|add(n1,#2)| | "1 st day fine - 0.07 2 nd day fine - 0.07 * 2 = 0.14 ( as doubling gives lower value ) 3 rd day fine - 0.14 * 2 = 0.28 ( as doubling gives lower value ) 4 rd day fine - 0.28 * 2 = 0.56 ( as doubling gives lower value ) 5 th day fine - 0.56 + 0.3 = 0.86 ( as doubling gives higher value we add 0.3 this time ) answer : c ." | general |
math_qa__JA0aB2V5gigQMwZh | By selling 100 pens, a trader gains the cost of 40 pens. Find his gain percentage? Choose the correct choice from the following choices:
A) 40 % B) 50 % C) 60 % D) 70 % E) 30 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>A</result> | A | 40 | By selling 100 pens, a trader gains the cost of 40 pens. Find his gain percentage? | {
"A": "40 %",
"B": "50 %",
"C": "60 %",
"D": "70 %",
"E": "30 %"
} | multiply(divide(40, 100), const_100) | divide(n1,n0)|multiply(#0,const_100)| | "let the cp of each pen be rs . 1 . cp of 100 pens = rs . 100 profit = cost of 40 pens = rs . 40 profit % = 40 / 100 * 100 = 40 % answer : a" | gain |
math_qa__YbP7GiG8WbzArT4h | A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is? Choose the correct choice from the following options:
A) 1978 B) 2707 C) 7728 D) 4200 E) 7291 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">9_600 * (9/10)</gadget>
<output>8_640</output>
<gadget id="calculator">15_000 + 25_000</gadget>
<output>40_000</output>
<gadget id="calculator">25_000 / 40_000</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">8_640 * (5/8)</gadget>
<output>5_400</output>
<gadget id="calculator">9_600 - 5_400</gadget>
<output>4_200</output>
<result>D</result> | D | 4,200 | A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is? | {
"A": "1978",
"B": "2707",
"C": "7728",
"D": "4200",
"E": "7291"
} | subtract(9600, multiply(multiply(9600, subtract(const_1, divide(10, const_100))), divide(25000, add(15000, 25000)))) | add(n0,n1)|divide(n2,const_100)|divide(n1,#0)|subtract(const_1,#1)|multiply(n3,#3)|multiply(#2,#4)|subtract(n3,#5)| | "15 : 25 = > 3 : 5 9600 * 10 / 100 = 960 9600 - 960 = 8640 8640 * 3 / 8 = 3240 + 960 = 4200 answer : d" | gain |
math_qa__ZhRXhJbQNU628gWV | How many numbers from 19 to 79 are exactly divisible by 11? Choices: A) 5 B) 6 C) 9 D) 11 E) 12 | <gadget id="calculator">79 / 11</gadget>
<output>79/11 = around 7.181818</output>
<gadget id="calculator">floor(79/11)</gadget>
<output>7</output>
<gadget id="calculator">7 * 11</gadget>
<output>77</output>
<gadget id="calculator">19 / 11</gadget>
<output>19/11 = around 1.727273</output>
<gadget id="calculator">floor(19/11)</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 11</gadget>
<output>22</output>
<gadget id="calculator">77 - 22</gadget>
<output>55</output>
<gadget id="calculator">55 / 11</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>B</result> | B | 6 | How many numbers from 19 to 79 are exactly divisible by 11? | {
"A": "5",
"B": "6",
"C": "9",
"D": "11",
"E": "12"
} | add(divide(subtract(multiply(floor(divide(79, 11)), 11), multiply(add(floor(divide(19, 11)), const_1), 11)), 11), const_1) | divide(n1,n2)|divide(n0,n2)|floor(#0)|floor(#1)|add(#3,const_1)|multiply(n2,#2)|multiply(n2,#4)|subtract(#5,#6)|divide(#7,n2)|add(#8,const_1)| | "19 / 11 = 1 and 79 / 11 = 7 = = > 7 - 1 = 6 numbers answer : b" | general |
math_qa__5a7cqRiLur8MOmWH | Exactly 20% of the reporters for a certain wire service cover local politics in Country X. If 20% of the reporters who cover politics for the wire service do not cover local politics in Country X, what percent of the reporters for the wire service do not cover politics? Choose the correct choice from the following:
A) 20 %
B) 42 %
C) 44 %
D) 75 %
E) 84 % | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">20 / 80</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 100</gadget>
<output>75</output>
<result>D</result> | D | 75 | Exactly 20% of the reporters for a certain wire service cover local politics in Country X. If 20% of the reporters who cover politics for the wire service do not cover local politics in Country X, what percent of the reporters for the wire service do not cover politics? | {
"A": "20 %",
"B": "42 %",
"C": "44 %",
"D": "75 %",
"E": "84 %"
} | multiply(subtract(const_1, divide(20, subtract(const_100, 20))), const_100) | subtract(const_100,n1)|divide(n0,#0)|subtract(const_1,#1)|multiply(#2,const_100)| | "you are correct . people who cover local politics are a subset of people who cover politics . 20 % of reporters who cover politics do not cover local politics so 80 % do cover local politics . reporters covering local politics = 80 % of reporters covering politics = 20 % ofall reporters reporters covering politics / all reporters = 20 / 80 = 1 / 4 reporters not covering politics / all reporters = 3 / 4 = 75 % = d" | gain |
math_qa__99YJgdYtoNkE7ZD7 | We had $840 left after spending 30% of the money that we took for shopping. How much money did we start with? Choose the correct choice from the following answers
A) $ 1000 B) $ 1050 C) $ 1100 D) $ 1150 E) $ 1200 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">840 / (7/10)</gadget>
<output>1_200</output>
<result>E</result> | E | 1,200 | We had $840 left after spending 30% of the money that we took for shopping. How much money did we start with? | {
"A": "$ 1000",
"B": "$ 1050",
"C": "$ 1100",
"D": "$ 1150",
"E": "$ 1200"
} | divide(840, subtract(const_1, divide(30, const_100))) | divide(n1,const_100)|subtract(const_1,#0)|divide(n0,#1) | let x be the amount of money we started with . 0.7 x = 840 x = 1200 the answer is e . | gain |
math_qa__D4TNeTWzJvA23T5d | If the sum and difference of two numbers are 10 and 8 respectively, then the difference of their square is:
Choose the correct choice from the following answers: A) 12 B) 28 C) 160 D) 180 E) 80 | <gadget id="calculator">10 + 8</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">9 ** 2</gadget>
<output>81</output>
<gadget id="calculator">10 - 9</gadget>
<output>1</output>
<gadget id="calculator">1 ** 2</gadget>
<output>1</output>
<gadget id="calculator">81 - 1</gadget>
<output>80</output>
<result>E</result> | E | 80 | If the sum and difference of two numbers are 10 and 8 respectively, then the difference of their square is: | {
"A": "12",
"B": "28",
"C": "160",
"D": "180",
"E": "80"
} | subtract(power(divide(add(10, 8), const_2), const_2), power(subtract(10, divide(add(10, 8), const_2)), const_2)) | add(n0,n1)|divide(#0,const_2)|power(#1,const_2)|subtract(n0,#1)|power(#3,const_2)|subtract(#2,#4)| | "let the numbers be x and y . then , x + y = 10 and x - y = 8 x 2 - y 2 = ( x + y ) ( x - y ) = 10 * 8 = 80 . answer : e" | general |
math_qa__6B6FToIilTJeMLSs | How many times will the digit 5 be written when listing the integers from 1 to 1000? Choose one.
A) 300 B) 380 C) 180 D) 415 E) 264 | <gadget id="calculator">1 * 10</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<result>A</result> | A | 300 | How many times will the digit 5 be written when listing the integers from 1 to 1000? | {
"A": "300",
"B": "380",
"C": "180",
"D": "415",
"E": "264"
} | multiply(multiply(multiply(1, const_10), const_10), const_3) | multiply(n1,const_10)|multiply(#0,const_10)|multiply(#1,const_3)| | "many approaches are possible . for example : consider numbers from 0 to 999 written as follows : 1 . 000 2 . 001 3 . 002 4 . 003 . . . . . . . . . 1000 . 999 we have 1000 numbers . we used 3 digits per number , hence used total of 3 * 1000 = 3000 digits . now , why should any digit have preferences over another ? we used each of 10 digits equal # of times , thus we used each digit ( including 5 ) 3000 / 10 = 300 times . answer : a ." | general |
math_qa__JSz1dau6r5dOFRMs | The distance from Steve's house to work is 30 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work? Choose one: A) 5 . B) 10 . C) 14 . D) 15 E) 20 . | <gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">30 + 15</gadget>
<output>45</output>
<gadget id="calculator">45 / 6</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 2</gadget>
<output>15</output>
<result>D</result> | D | 15 | The distance from Steve's house to work is 30 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work? | {
"A": "5 .",
"B": "10 .",
"C": "14 .",
"D": "15",
"E": "20 ."
} | multiply(divide(add(30, divide(30, const_2)), 6), const_2) | divide(n0,const_2)|add(n0,#0)|divide(#1,n1)|multiply(#2,const_2)| | "time is in the ratio 2 : 1 : : to : fro office therefore , 2 x + 1 x = 6 hrs time take to come back - 2 hrs , distance travelled - 30 km = > speed = 15 kmph answer : d" | physics |
math_qa__IxpKbUAQAQ43MyBH | How many times in a day the hands of a clock are straight? Choices:
A) 21 B) 27 C) 24 D) 22 E) 25 | <gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">2 * 24</gadget>
<output>48</output>
<gadget id="calculator">48 - 4</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<result>D</result> | D | 22 | How many times in a day the hands of a clock are straight? | {
"A": "21",
"B": "27",
"C": "24",
"D": "22",
"E": "25"
} | divide(subtract(multiply(const_2, multiply(const_2, const_12)), const_4), const_2) | multiply(const_12,const_2)|multiply(#0,const_2)|subtract(#1,const_4)|divide(#2,const_2)| | "in 12 hours , the hands coincide or are in oppesite direction 22 times . in 24 hours , they are at right angles 22 times . answer is d ." | physics |
math_qa__XwrBguJaTfw9Y0iR | On a ranch, a rancher can place a loop of rope, called a lasso, once in every 2 throws around a cowβs neck. What is the probability that the rancher will be able to place a lasso around a cowβs neck at least once in 3 attempts?
Answers
A) 3 / 4 B) 5 / 8 C) 7 / 8 D) 9 / 16 E) 15 / 16 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 3</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 - (1/8)</gadget>
<output>7/8 = around 0.875</output>
<result>C</result> | C | 0.875 | On a ranch, a rancher can place a loop of rope, called a lasso, once in every 2 throws around a cowβs neck. What is the probability that the rancher will be able to place a lasso around a cowβs neck at least once in 3 attempts? | {
"A": "3 / 4",
"B": "5 / 8",
"C": "7 / 8",
"D": "9 / 16",
"E": "15 / 16"
} | subtract(const_1, power(divide(const_1, 2), 3)) | divide(const_1,n0)|power(#0,n1)|subtract(const_1,#1)| | "p ( missing all 3 ) = ( 1 / 2 ) ^ 3 = 1 / 8 p ( success on at least one attempt ) = 1 - 1 / 8 = 7 / 8 the answer is c ." | probability |
math_qa__BFctNdSjhh5qPyiM | Twelve machines, each working at the same constant rate, together can complete a certain job in 12 days. How many additional machines, each working at the same constant rate, will be needed to complete the Job in 8 days? Choose the correct option:
A) 2 B) 3 C) 4 D) 6 E) 8 | <gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / (2/3)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">12 * (3/2)</gadget>
<output>18</output>
<gadget id="calculator">18 - 12</gadget>
<output>6</output>
<result>D</result> | D | 6 | Twelve machines, each working at the same constant rate, together can complete a certain job in 12 days. How many additional machines, each working at the same constant rate, will be needed to complete the Job in 8 days? | {
"A": "2",
"B": "3",
"C": "4",
"D": "6",
"E": "8"
} | subtract(multiply(12, inverse(divide(8, 12))), 12) | divide(n1,n0)|inverse(#0)|multiply(n0,#1)|subtract(#2,n0) | another solution which is faster is since each machine works at a constant rate . the time needs to bought down from 12 to 8 . so the new time is 2 / 3 of the original time . thus to achieve this we need the rate to be 3 / 2 of original . so 3 / 2 * 12 = 18 so we need 18 - 12 = 6 more machines . answer : d | physics |
math_qa__hbBeRO8Q2xHjs7Ar | A cab driver 5 days income was $200, $150, $750, $400 , $500. Then his average income is? Choose the correct choice from the following answers:
A) $ 420 B) $ 410 C) $ 400 D) $ 390 E) $ 380 | <gadget id="calculator">200 + 150</gadget>
<output>350</output>
<gadget id="calculator">350 + 750</gadget>
<output>1_100</output>
<gadget id="calculator">1_100 + 400</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 + 500</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 5</gadget>
<output>400</output>
<result>C</result> | C | 400 | A cab driver 5 days income was $200, $150, $750, $400 , $500. Then his average income is? | {
"A": "$ 420",
"B": "$ 410",
"C": "$ 400",
"D": "$ 390",
"E": "$ 380"
} | divide(add(add(add(add(200, 150), 750), 400), 500), 5) | add(n1,n2)|add(n3,#0)|add(n4,#1)|add(n5,#2)|divide(#3,n0)| | "avg = sum of observations / number of observations avg income = ( 200 + 150 + 750 + 400 + 500 ) / 5 = 400 answer is c" | general |
math_qa__ARZ7tI1AUxS4DRJ2 | X is able to do a piece of work in 14 days and Y can do the same work in 20 days. If they can work together for 5 days, what is the fraction of work completed? Choose the correct option: A) 15 / 28 B) 17 / 28 C) 13 / 28 D) 19 / 28 E) 11 / 28 | <gadget id="calculator">14 * 20</gadget>
<output>280</output>
<gadget id="calculator">14 + 20</gadget>
<output>34</output>
<gadget id="calculator">280 / 34</gadget>
<output>140/17 = around 8.235294</output>
<gadget id="calculator">5 / (140/17)</gadget>
<output>17/28 = around 0.607143</output>
<result>B</result> | B | 0.607143 | X is able to do a piece of work in 14 days and Y can do the same work in 20 days. If they can work together for 5 days, what is the fraction of work completed? | {
"A": "15 / 28",
"B": "17 / 28",
"C": "13 / 28",
"D": "19 / 28",
"E": "11 / 28"
} | divide(5, divide(multiply(14, 20), add(14, 20))) | add(n0,n1)|multiply(n0,n1)|divide(#1,#0)|divide(n2,#2) | explanation : amount of work x can do in 1 day = 1 / 14 amount of work y can do in 1 day = 1 / 20 amount of work x and y can do in 1 day = 1 / 14 + 1 / 20 = 17 / 140 amount of work x and y can together do in 5 days = 5 Γ ( 17 / 140 ) = 17 / 28 answer : option b | physics |
math_qa__tWgdxlstXjDVODVL | A football field is 9600 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 5600 square yards? Choose the correct option
A) 450
B) 600
C) 700
D) 2400
E) 3200 | <gadget id="calculator">1_200 / 9_600</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">5_600 * (1/8)</gadget>
<output>700</output>
<result>C</result> | C | 700 | A football field is 9600 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 5600 square yards? | {
"A": "450",
"B": "600",
"C": "700",
"D": "2400",
"E": "3200"
} | multiply(5600, divide(1200, 9600)) | divide(n1,n0)|multiply(n2,#0) | answer c ) 9600 yards need 1200 lbs 1 yard will need 1200 / 9600 = 1 / 8 lbs 3600 yards will need 1 / 8 * 5600 yards = 700 lbs | geometry |
math_qa__T4GQgbdvjtHaemyL | If a man buys 1 liter of milk for 12 rs. and mixes it with 20% water and sells it for 15 rs then what is the %age of gain... Answers.
A) 30 B) 40 C) 50 D) 60 E) 70 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 15</gadget>
<output>18</output>
<gadget id="calculator">18 - 12</gadget>
<output>6</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | If a man buys 1 liter of milk for 12 rs. and mixes it with 20% water and sells it for 15 rs then what is the %age of gain... | {
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "70"
} | multiply(divide(subtract(multiply(add(1, divide(20, const_100)), 15), 12), 12), const_100) | divide(n2,const_100)|add(n0,#0)|multiply(n3,#1)|subtract(#2,n1)|divide(#3,n1)|multiply(#4,const_100) | quantity after adding 20 % water = 1.2 liter sp of 1.2 lit . @ 15 rs . / liter = 15 * 1.2 = 18 rs cp = 12 rs / lit . % profit = 100 * ( 18 - 12 ) / 12 = 50 answer : c | gain |
math_qa__IZwUad3hzW62PNcV | A tightrope approximately 320 m long is suspended between two poles. During a performance, a break occurs in the line. Assume that the line has an equal chance of breaking anywhere along its length. What is the probability that the break happened in the first 50 meters of the rope?
Choose the correct choice from the following answers.
A) 27 / 32
B) 1 / 2
C) 5 / 32
D) 5 / 27
E) . 2 / 3 | <gadget id="calculator">50 / 320</gadget>
<output>5/32 = around 0.15625</output>
<result>C</result> | C | 0.15625 | A tightrope approximately 320 m long is suspended between two poles. During a performance, a break occurs in the line. Assume that the line has an equal chance of breaking anywhere along its length. What is the probability that the break happened in the first 50 meters of the rope? | {
"A": "27 / 32",
"B": "1 / 2",
"C": "5 / 32",
"D": "5 / 27",
"E": ". 2 / 3"
} | divide(50, 320) | divide(n1,n0) | simly 50 / 320 = 5 / 32 answer will be ( c ) | general |
math_qa__OSG4TAPcRTFgnFkp | On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 18 more transactions than Cal. How much transactions did Jade handled? Choose the correct choice from the following
A) 80 B) 81 C) 82 D) 83 E) 84 | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">10 + 100</gadget>
<output>110</output>
<gadget id="calculator">(9/10) * 110</gadget>
<output>99</output>
<gadget id="calculator">99 * 2</gadget>
<output>198</output>
<gadget id="calculator">198 / 3</gadget>
<output>66</output>
<gadget id="calculator">66 + 18</gadget>
<output>84</output>
<result>E</result> | E | 84 | On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 18 more transactions than Cal. How much transactions did Jade handled? | {
"A": "80",
"B": "81",
"C": "82",
"D": "83",
"E": "84"
} | add(divide(multiply(multiply(divide(90, const_100), add(10, const_100)), 2), 3), 18) | add(n1,const_100)|divide(n0,const_100)|multiply(#0,#1)|multiply(n2,#2)|divide(#3,n3)|add(n4,#4)| | "solution : mabel handled 90 transactions anthony handled 10 % more transactions than mabel anthony = 90 + 90 Γ 10 % = 90 + 90 Γ 0.10 = 90 + 9 = 99 cal handled 2 / 3 rds of the transactions than anthony handled cal = 2 / 3 Γ 99 = 66 jade handled 18 more transactions than cal . jade = 66 + 18 = 84 jade handled = 84 transactions . answer : e" | general |
math_qa__A3kQ1Rb5XMwcwS3t | While working alone at their constant rates, computer X can process 240 files in 4 hours, and computer Y can process 240 files in 6 hours. If all files processed by these computers are the same size, how many hours would it take the two computers, working at the same time at their respective constant rates, to process a total of 240 files? Choose the correct choice from the following options.
A) 2
B) 2.2
C) 2.4
D) 2.6
E) 2.8 | <gadget id="calculator">240 / 4</gadget>
<output>60</output>
<gadget id="calculator">240 / 6</gadget>
<output>40</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">240 / 100</gadget>
<output>12/5 = around 2.4</output>
<result>C</result> | C | 2.4 | While working alone at their constant rates, computer X can process 240 files in 4 hours, and computer Y can process 240 files in 6 hours. If all files processed by these computers are the same size, how many hours would it take the two computers, working at the same time at their respective constant rates, to process a total of 240 files? | {
"A": "2",
"B": "2.2",
"C": "2.4",
"D": "2.6",
"E": "2.8"
} | divide(240, add(divide(240, 4), divide(240, 6))) | divide(n0,n1)|divide(n0,n3)|add(#0,#1)|divide(n0,#2) | both computers together process files at a rate of 240 / 4 + 240 / 6 = 60 + 40 = 100 files per hour . the time required to process 240 files is 240 / 100 = 2.4 hours the answer is c . | physics |
math_qa__X11eH6JQJotckHQ0 | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 140, then how much amount should C pay as his share of rent? Choose the most appropriate option
A) 35 B) 45 C) 25 D) 36 E) 55 | <gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">70 + 60</gadget>
<output>130</output>
<gadget id="calculator">130 + 45</gadget>
<output>175</output>
<gadget id="calculator">45 / 175</gadget>
<output>9/35 = around 0.257143</output>
<gadget id="calculator">140 * (9/35)</gadget>
<output>36</output>
<result>D</result> | D | 36 | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 140, then how much amount should C pay as his share of rent? | {
"A": "35",
"B": "45",
"C": "25",
"D": "36",
"E": "55"
} | multiply(140, divide(multiply(15, 3), add(add(multiply(10, 7), multiply(12, 5)), multiply(15, 3)))) | multiply(n4,n5)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|add(#3,#0)|divide(#0,#4)|multiply(n6,#5)| | "a : b : c = 10 Γ 7 : 12 Γ 5 : 15 Γ 3 = 2 Γ 7 : 12 Γ 1 : 3 Γ 3 = 14 : 12 : 9 amount that c should pay = 140 Γ 9 / 35 = 4 Γ 9 = 36 answer is d" | general |
math_qa__mETWqCwNhMMWOBAv | What is the rate percent when the simple interest on Rs.1000 amount to Rs.400 in 4 Years?
Choose the correct answer:
A) 5 % B) 6 % C) 2 % D) 95 % E) 10 % | <gadget id="calculator">100 * 400</gadget>
<output>40_000</output>
<gadget id="calculator">1_000 * 4</gadget>
<output>4_000</output>
<gadget id="calculator">40_000 / 4_000</gadget>
<output>10</output>
<result>E</result> | E | 10 | What is the rate percent when the simple interest on Rs.1000 amount to Rs.400 in 4 Years? | {
"A": "5 %",
"B": "6 %",
"C": "2 %",
"D": "95 %",
"E": "10 %"
} | divide(multiply(const_100, 400), multiply(1000, 4)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)| | "interest for 4 yrs = 400 interest for 1 yr = 100 interest rate = 100 / 1000 x 100 = 10 % answer : e" | gain |
math_qa__CgM3XJGKixWVzywQ | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 7 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled? Choose the correct choice from the following
A) 9.5 B) 9.4 C) 9.3 D) 9.2 E) 9.1 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/4) - (1/7)</gadget>
<output>3/28 = around 0.107143</output>
<gadget id="calculator">1 / (3/28)</gadget>
<output>28/3 = around 9.333333</output>
<result>C</result> | C | 9.3 | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 7 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled? | {
"A": "9.5",
"B": "9.4",
"C": "9.3",
"D": "9.2",
"E": "9.1"
} | divide(const_1, subtract(divide(const_1, 4), divide(const_1, 7))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)| | "net part filled in 1 hour = ( 1 / 4 - 1 / 7 ) = 3 / 28 the cistern will be filled in 28 / 3 hrs i . e . , 9.3 hrs . answer : c" | physics |
math_qa__m7T317nMvJh6CzxH | By how much is 12% of 24.2 more than 10% of 14.2 ? Choose the most appropriate option:
A) 0.1484 B) 14.84 C) 1.484 D) 2.762 E) none | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">24.2 * (3/25)</gadget>
<output>2.904</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 14.2</gadget>
<output>1.42</output>
<gadget id="calculator">2.904 - 1.42</gadget>
<output>1.484</output>
<result>C</result> | C | 1.484 | By how much is 12% of 24.2 more than 10% of 14.2 ? | {
"A": "0.1484",
"B": "14.84",
"C": "1.484",
"D": "2.762",
"E": "none"
} | subtract(multiply(24.2, divide(12, const_100)), multiply(divide(10, const_100), 14.2)) | divide(n0,const_100)|divide(n2,const_100)|multiply(n1,#0)|multiply(n3,#1)|subtract(#2,#3)| | "answer required difference = ( 12 x 24.2 ) / 100 - ( 10 x 14.2 ) / 100 = 2.904 - 1.42 = 1.484 . correct option : c" | general |
math_qa__6BKotV6kH8bSgTF1 | The jogging track in a sports complex is 627 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in?
Answers.
A) 4.56 min
B) 5.28 min
C) 5.08 min
D) 9.28 min
E) 5.988 min | <gadget id="calculator">627 / 1_000</gadget>
<output>627/1_000 = around 0.627</output>
<gadget id="calculator">4.5 + 3.75</gadget>
<output>8.25</output>
<gadget id="calculator">(627/1_000) / 8.25</gadget>
<output>0.076</output>
<gadget id="calculator">0.076 * 60</gadget>
<output>4.56</output>
<result>A</result> | A | 4.56 | The jogging track in a sports complex is 627 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in? | {
"A": "4.56 min",
"B": "5.28 min",
"C": "5.08 min",
"D": "9.28 min",
"E": "5.988 min"
} | multiply(divide(divide(627, const_1000), add(4.5, 3.75)), const_60) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_60)| | "clearly , the two will meet when they are 627 m apart . to be ( 4.5 + 3.75 ) = 8.25 km apart , they take 1 hour . to be 627 m apart , they take ( 100 / 825 * 627 / 1000 ) hrs = ( 627 / 8250 * 60 ) min = 4.56 min . answer : a" | general |
math_qa__7x2OyMy7wP9NEWjz | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 36, what is the total amount? Choose the correct choice from the following answers: A) 115 B) 116 C) 117 D) 118 E) 156 | <gadget id="calculator">100 / 45</gadget>
<output>20/9 = around 2.222222</output>
<gadget id="calculator">(20/9) * 36</gadget>
<output>80</output>
<gadget id="calculator">50 / 45</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">(10/9) * 36</gadget>
<output>40</output>
<gadget id="calculator">80 + 40</gadget>
<output>120</output>
<gadget id="calculator">120 + 36</gadget>
<output>156</output>
<result>E</result> | E | 156 | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 36, what is the total amount? | {
"A": "115",
"B": "116",
"C": "117",
"D": "118",
"E": "156"
} | add(add(multiply(divide(const_100, 45), 36), multiply(divide(50, 45), 36)), 36) | divide(const_100,n0)|divide(n1,n0)|multiply(n2,#0)|multiply(n2,#1)|add(#2,#3)|add(n2,#4)| | "x : y : z = 100 : 45 : 50 20 : 9 : 10 9 - - - 36 39 - - - ? = > 156 answer : e" | general |
math_qa__wQ6FE1oHuxfmGaFv | A certain company retirement plan has arule of 70provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1989 on her 32nd birthday first be eligible to retire under this provision? Pick:
A) 2008 B) 2004 C) 2005 D) 2006 E) 2007 | <gadget id="calculator">70 - 32</gadget>
<output>38</output>
<gadget id="calculator">38 / 2</gadget>
<output>19</output>
<gadget id="calculator">1_989 + 19</gadget>
<output>2_008</output>
<result>A</result> | A | 2,008 | A certain company retirement plan has arule of 70provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1989 on her 32nd birthday first be eligible to retire under this provision? | {
"A": "2008",
"B": "2004",
"C": "2005",
"D": "2006",
"E": "2007"
} | add(1989, divide(subtract(70, 32), const_2)) | subtract(n0,n3)|divide(#0,const_2)|add(n2,#1)| | "she must gain at least 70 points , now she has 32 and every year gives her two more points : one for age and one for additional year of employment , so 32 + 2 * ( # of years ) = 70 - - > ( # of years ) = 19 - - > 1989 + 19 = 2008 . answer : a ." | general |
math_qa__RcdbryrVOHfOBkbd | Carina has 115 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have? Options
A) 5 B) 7 C) 6 D) 4 E) 3 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">115 - 10</gadget>
<output>105</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">105 / 15</gadget>
<output>7</output>
<result>B</result> | B | 7 | Carina has 115 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have? | {
"A": "5",
"B": "7",
"C": "6",
"D": "4",
"E": "3"
} | divide(subtract(115, multiply(5, 2)), add(10, 5)) | add(n1,n2)|multiply(n1,n3)|subtract(n0,#1)|divide(#2,#0)| | "lets say 5 and 10 ounce packages be x and y respectively . given that , 5 x + 10 y = 115 and x = y + 2 . what is the value of y . substituting the x in first equation , 5 y + 10 + 10 y = 85 - > y = 105 / 15 . = 7 b" | general |
math_qa__VUzBnypzlsv13TZg | A trader bought a car at 40% discount on its original price. He sold it at a 80% increase on the price he bought it. What percent of profit did he make on the original price?
Choose the correct answer.
A) 8 % B) 62 % C) 2 % D) 9 % E) 22 % | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">100 + 80</gadget>
<output>180</output>
<gadget id="calculator">60 * 180</gadget>
<output>10_800</output>
<gadget id="calculator">10_800 / 100</gadget>
<output>108</output>
<gadget id="calculator">108 / 100</gadget>
<output>27/25 = around 1.08</output>
<gadget id="calculator">(27/25) - 1</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/25) * 100</gadget>
<output>8</output>
<result>A</result> | A | 8 | A trader bought a car at 40% discount on its original price. He sold it at a 80% increase on the price he bought it. What percent of profit did he make on the original price? | {
"A": "8 %",
"B": "62 %",
"C": "2 %",
"D": "9 %",
"E": "22 %"
} | multiply(subtract(divide(divide(multiply(subtract(const_100, 40), add(const_100, 80)), const_100), const_100), const_1), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,const_1)|multiply(#5,const_100)| | "original price = 100 cp = 60 s = 60 * ( 180 / 100 ) = 112 100 - 108 = 8 % answer : a" | gain |
math_qa__IFTa1FJzRrvRlRbe | What is the sum of 100 consecutive integers from -49 inclusive, in a increasing order? Choose the correct choice from the following choices:
A) - 29 B) 50 C) - 30 D) 30 E) 60 | <gadget id="calculator">49 + 1</gadget>
<output>50</output>
<result>B</result> | B | 50 | What is the sum of 100 consecutive integers from -49 inclusive, in a increasing order? | {
"A": "- 29",
"B": "50",
"C": "- 30",
"D": "30",
"E": "60"
} | add(49, const_1) | add(n1,const_1)| | "from - 49 to - 1 - - > 49 nos . zero - - > 1 number from + 1 to + 49 - - > 49 nos . when we add up nos . from - 49 to + 49 sum will be zero . total 99 nos will be added . 100 th number will be 50 . sum of these 100 nos . = 50 . b is the answer ." | general |
math_qa__hmnDv5NpBHwfdC7Q | a reduction of 40 % in the price of bananas would enable a man to obtain 64 more for rs . 40.00001 , what is reduced price per dozen ? Select:
A) 6
B) 5
C) 4
D) 3
E) 2 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">40 * (2/5)</gadget>
<output>16</output>
<gadget id="calculator">16 / 64</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">12 * (1/4)</gadget>
<output>3</output>
<result>D</result> | D | 3 | a reduction of 40 % in the price of bananas would enable a man to obtain 64 more for rs . 40.00001 , what is reduced price per dozen ? | {
"A": "6",
"B": "5",
"C": "4",
"D": "3",
"E": "2"
} | multiply(const_12, divide(multiply(40, divide(40, const_100)), 64)) | divide(n0,const_100)|multiply(n0,#0)|divide(#1,n1)|multiply(#2,const_12) | 40 * ( 40 / 100 ) = 16 - - - 64 ? - - - 12 = > rs . 3 answer : d | gain |
math_qa__DivXDksjvK2t2AOe | An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 24 metre of cloth ?
Select:
A) 175 seconds B) 195 seconds C) 155 seconds D) 188 seconds E) 115 seconds | <gadget id="calculator">24 / 0.128</gadget>
<output>187.5</output>
<result>D</result> | D | 188 | An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 24 metre of cloth ? | {
"A": "175 seconds",
"B": "195 seconds",
"C": "155 seconds",
"D": "188 seconds",
"E": "115 seconds"
} | divide(24, 0.128) | divide(n1,n0)| | "explanation : let the time required by x seconds . then , more cloth means more time ( direct proportion ) so , 0.128 : 1 : : 24 : x = > x = { \ color { blue } \ frac { 24 \ times 1 } { 0.128 } } = > x = 187.5 so time will be approx 188 seconds answer : d" | physics |
math_qa__yQRwzC4jBoP0EryJ | The perimeter of one face of a cube is 20 cm. Its volume will be: Pick.
A) 125 cm 3 B) 400 cm 3 C) 250 cm 3 D) 625 cm 3 E) none of these | <gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<result>A</result> | A | 125 | The perimeter of one face of a cube is 20 cm. Its volume will be: | {
"A": "125 cm 3",
"B": "400 cm 3",
"C": "250 cm 3",
"D": "625 cm 3",
"E": "none of these"
} | volume_cube(square_edge_by_perimeter(20)) | square_edge_by_perimeter(n0)|volume_cube(#0)| | "explanation : edge of cude = 20 / 4 = 5 cm volume = a * a * a = 5 * 5 * 5 = 125 cm cube option a" | geometry |
math_qa__UPMyGBMRWE4Uq20R | If the average (arithmetic mean) of (2a+16) and (3a-8) is 84, what is the value of a? Options
A) 25 B) 30 C) 28 D) 32 E) 42 | <gadget id="calculator">84 * 2</gadget>
<output>168</output>
<gadget id="calculator">16 - 8</gadget>
<output>8</output>
<gadget id="calculator">168 - 8</gadget>
<output>160</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">160 / 5</gadget>
<output>32</output>
<result>D</result> | D | 32 | If the average (arithmetic mean) of (2a+16) and (3a-8) is 84, what is the value of a? | {
"A": "25",
"B": "30",
"C": "28",
"D": "32",
"E": "42"
} | divide(subtract(multiply(84, 2), subtract(16, 8)), add(2, 3)) | add(n0,n2)|multiply(n0,n4)|subtract(n1,n3)|subtract(#1,#2)|divide(#3,#0)| | "( ( 2 a + 16 ) + ( 3 a - 8 ) ) / 2 = ( 5 a + 8 ) / 2 = 84 a = 32 the answer is d ." | general |
math_qa__y4ne6usB30nrKARR | A square mirror has exactly half the area of the rectangular wall on which it is hung. If each side of the mirror is 18 inches and the width of the wall is 32 inches, what is the length of the wall, in inches? Choices:
A) 15.25
B) 18.25
C) 19.25
D) 20.25
E) 21.25 | <gadget id="calculator">18 ** 2</gadget>
<output>324</output>
<gadget id="calculator">2 * 324</gadget>
<output>648</output>
<gadget id="calculator">648 / 32</gadget>
<output>81/4 = around 20.25</output>
<result>D</result> | D | 20.25 | A square mirror has exactly half the area of the rectangular wall on which it is hung. If each side of the mirror is 18 inches and the width of the wall is 32 inches, what is the length of the wall, in inches? | {
"A": "15.25",
"B": "18.25",
"C": "19.25",
"D": "20.25",
"E": "21.25"
} | divide(multiply(const_2, square_area(18)), 32) | square_area(n0)|multiply(#0,const_2)|divide(#1,n1)| | "since the mirror is 42 inches in all sides , it must be a square . area of a square is a = a ^ 2 ; 18 ^ 2 = 324 . area of rectangle is double of that 2 * 324 = 648 . now a = lw and we need find w so a / l = w ; 648 / 32 = 20.25 answer ! answer is d" | geometry |
math_qa__zSSm2tKLYZuIt21r | How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27kg of sugar costing Rs.7 per kg so that there may be gain of 10% by selling the mixture at Rs.9.24 per kg? Options: A) 60 kg B) 63 kg C) 50 kg D) 77 kg E) none of these | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">9.24 / (11/10)</gadget>
<output>8.4</output>
<gadget id="calculator">27 * 8.4</gadget>
<output>226.8</output>
<gadget id="calculator">27 * 7</gadget>
<output>189</output>
<gadget id="calculator">226.8 - 189</gadget>
<output>37.8</output>
<gadget id="calculator">9 - 8.4</gadget>
<output>0.6</output>
<gadget id="calculator">37.8 / 0.6</gadget>
<output>63</output>
<result>B</result> | B | 63 | How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27kg of sugar costing Rs.7 per kg so that there may be gain of 10% by selling the mixture at Rs.9.24 per kg? | {
"A": "60 kg",
"B": "63 kg",
"C": "50 kg",
"D": "77 kg",
"E": "none of these"
} | divide(subtract(multiply(27, divide(9.24, add(divide(10, const_100), const_1))), multiply(27, 7)), subtract(9, divide(9.24, add(divide(10, const_100), const_1)))) | divide(n3,const_100)|multiply(n1,n2)|add(#0,const_1)|divide(n4,#2)|multiply(n1,#3)|subtract(n0,#3)|subtract(#4,#1)|divide(#6,#5)| | "explanation : let the rate of second quality be rs x per kg . step 1 : s . p of 1 kg of mixture = rs . 9.24 gain = 10 % c . p of 1 kg of mixture = [ 100 / ( 100 + 10 ) Γ 9.24 ] . = > rs . 8.40 . thus , the mean price = rs . 8.40 . step 2 : c . p of 1 kg of sugar of 1 st kind = 900 p c . p of 1 kg of sugar of 2 nd kind = 700 p mean price = 840 p by the rule of alligation , we have : c . p . of 1 kg of c . p . of 1 kg of sugar of 1 st sugar of 2 nd kind ( 900 p ) kind ( 700 p ) \ / mean price ( 840 p ) / \ 840 - 700 : 900 - 840 ( 140 ) ( 60 ) = > required ratio = 140 : 60 = 7 : 3 . step 3 : let , x kg of sugar of 1 st kind be mixed with 27 kg of 2 nd kind , then = > 7 : 3 = x : 27 . = > 7 / 3 = x / 27 . = > x = ( 7 / 3 ) x 27 . = > x = 63 . answer : b" | gain |
math_qa__n5qXz4kZIbkaAoRM | At a loading dock, each worker on the night crew loaded 1/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? Choose the most appropriate option
A) 1 / 2 B) 2 / 5 C) 3 / 5 D) 4 / 5 E) 5 / 6 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">1 * 4</gadget>
<output>4</output>
<gadget id="calculator">20 + 4</gadget>
<output>24</output>
<gadget id="calculator">20 / 24</gadget>
<output>5/6 = around 0.833333</output>
<result>E</result> | E | 0.833333 | At a loading dock, each worker on the night crew loaded 1/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? | {
"A": "1 / 2",
"B": "2 / 5",
"C": "3 / 5",
"D": "4 / 5",
"E": "5 / 6"
} | divide(multiply(5, 4), add(multiply(5, 4), multiply(1, 4))) | multiply(n1,n3)|multiply(n0,n2)|add(#0,#1)|divide(#0,#2)| | "method : x = no . of boxes loaded by day crew . boxes by night crew = 1 / 4 * 4 / 5 x = 1 / 5 x % loaded by day crew = x / ( x + 1 / 5 x ) = 5 / 6 answer e" | physics |
math_qa__D7RtzLSMScorrk67 | A jeep takes 7 hours to cover a distance of 420 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
Select the correct option.
A) 48 kmph B) 52 kmph C) 40 kmph D) 63 kmph E) 65 kmph | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 7</gadget>
<output>21/2 = around 10.5</output>
<gadget id="calculator">420 / (21/2)</gadget>
<output>40</output>
<result>C</result> | C | 40 | A jeep takes 7 hours to cover a distance of 420 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "48 kmph",
"B": "52 kmph",
"C": "40 kmph",
"D": "63 kmph",
"E": "65 kmph"
} | divide(420, multiply(divide(3, 2), 7)) | divide(n2,n3)|multiply(n0,#0)|divide(n1,#1)| | "time = 7 distance = 420 3 / 2 of 7 hours = 7 * 3 / 2 = 10.5 hours required speed = 420 / 10.5 = 40 kmph c )" | physics |
math_qa__1cUN6ucHYLCwDSkm | What will be the cost of building a fence around a square plot with area equal to 144 sq ft, if the price per foot of building the fence is Rs. 58? Choose one.
A) 2784 B) 2287 C) 2977 D) 2668 E) 1298 | <gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<gadget id="calculator">4 * 12</gadget>
<output>48</output>
<gadget id="calculator">48 * 58</gadget>
<output>2_784</output>
<result>A</result> | A | 2,784 | What will be the cost of building a fence around a square plot with area equal to 144 sq ft, if the price per foot of building the fence is Rs. 58? | {
"A": "2784",
"B": "2287",
"C": "2977",
"D": "2668",
"E": "1298"
} | multiply(square_perimeter(sqrt(144)), 58) | sqrt(n0)|square_perimeter(#0)|multiply(n1,#1)| | "let the side of the square plot be a ft . a 2 = 144 = > a = 12 length of the fence = perimeter of the plot = 4 a = 48 ft . cost of building the fence = 48 * 58 = rs . 2784 . answer : a" | geometry |
math_qa__ZNkaPAHYa6qbrgeb | If an object travels 400 feet in 4 seconds, what is the object's approximate speed in miles per hour? (Note: 1 mile = 5280 feet) Select the correct option
A) 68 B) 54 C) 87 D) 96 E) 15 | <gadget id="calculator">400 / 5_280</gadget>
<output>5/66 = around 0.075758</output>
<gadget id="calculator">1 / 3_600</gadget>
<output>1/3_600 = around 0.000278</output>
<gadget id="calculator">4 * (1/3_600)</gadget>
<output>1/900 = around 0.001111</output>
<gadget id="calculator">(5/66) / (1/900)</gadget>
<output>750/11 = around 68.181818</output>
<result>A</result> | A | 68 | If an object travels 400 feet in 4 seconds, what is the object's approximate speed in miles per hour? (Note: 1 mile = 5280 feet) | {
"A": "68",
"B": "54",
"C": "87",
"D": "96",
"E": "15"
} | divide(divide(400, 5280), multiply(4, divide(1, const_3600))) | divide(n0,n3)|divide(n2,const_3600)|multiply(n1,#1)|divide(#0,#2)| | "1 mile = 5280 feet = > 1 feet = 1 / 5280 miles if the object travels 400 feet in 4 sec then it travels 400 / 4 * 60 * 60 feet in 1 hour ( 1 hr = 60 min * 60 sec ) = 3600 * 100 feet in 1 hour = 360000 feet in 1 hr = 360000 / 5280 miles in 1 hour = 36000 / 528 miles / hr ~ 68 miles / hr answer - a" | physics |
math_qa__i2G55PTbWP6HBTDl | If the sum and difference of two numbers are 10 and 19 respectively, then the difference of their square is:
Choose the correct option
A) 12 B) 28 C) 160 D) 180 E) 190 | <gadget id="calculator">10 + 19</gadget>
<output>29</output>
<gadget id="calculator">29 / 2</gadget>
<output>29/2 = around 14.5</output>
<gadget id="calculator">(29/2) ** 2</gadget>
<output>841/4 = around 210.25</output>
<gadget id="calculator">10 - (29/2)</gadget>
<output>-9/2 = around -4.5</output>
<gadget id="calculator">(-9/2) ** 2</gadget>
<output>81/4 = around 20.25</output>
<gadget id="calculator">(841/4) - (81/4)</gadget>
<output>190</output>
<result>E</result> | E | 190 | If the sum and difference of two numbers are 10 and 19 respectively, then the difference of their square is: | {
"A": "12",
"B": "28",
"C": "160",
"D": "180",
"E": "190"
} | subtract(power(divide(add(10, 19), const_2), const_2), power(subtract(10, divide(add(10, 19), const_2)), const_2)) | add(n0,n1)|divide(#0,const_2)|power(#1,const_2)|subtract(n0,#1)|power(#3,const_2)|subtract(#2,#4) | let the numbers be x and y . then , x + y = 10 and x - y = 19 x 2 - y 2 = ( x + y ) ( x - y ) = 10 * 19 = 190 . answer : e | general |
math_qa__bdwkRj41efsFYj0K | If 14 percent of the students at a certain school went to a camping trip and took more than $100, and 75 percent of the students who went to the camping trip did not take more than $100, what percentage of the students at the school went to the camping trip?
Choose the correct option
A) 95 B) 90 C) 85 D) 80 E) 56 | <gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">14 / (1/4)</gadget>
<output>56</output>
<result>E</result> | E | 56 | If 14 percent of the students at a certain school went to a camping trip and took more than $100, and 75 percent of the students who went to the camping trip did not take more than $100, what percentage of the students at the school went to the camping trip? | {
"A": "95",
"B": "90",
"C": "85",
"D": "80",
"E": "56"
} | divide(14, divide(subtract(const_100, 75), const_100)) | subtract(const_100,n2)|divide(#0,const_100)|divide(n0,#1) | let x be the number of students in the school . 0.14 x students went to the trip and took more than 100 $ . they compose ( 100 - 75 ) = 25 % of all students who went to the trip . therefore the toal of 0.14 x / 0.25 = 0.56 x students went to the camping which is 56 % . the answer is e | general |
math_qa__G1Y9v434GFKLjTjA | Cole drove from home to work at an average speed of 80 kmh. He then returned home at an average speed of 120 kmh. If the round trip took a total of 3 hours, how many minutes did it take Cole to drive to work?
Pick one
A) 66 B) 70 C) 72 D) 85 E) 108 | <gadget id="calculator">120 * 3</gadget>
<output>360</output>
<gadget id="calculator">80 + 120</gadget>
<output>200</output>
<gadget id="calculator">360 / 200</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) * 60</gadget>
<output>108</output>
<result>E</result> | E | 108 | Cole drove from home to work at an average speed of 80 kmh. He then returned home at an average speed of 120 kmh. If the round trip took a total of 3 hours, how many minutes did it take Cole to drive to work? | {
"A": "66",
"B": "70",
"C": "72",
"D": "85",
"E": "108"
} | multiply(divide(multiply(120, 3), add(80, 120)), const_60) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)|multiply(#2,const_60)| | "first round distance travelled ( say ) = d speed = 80 k / h time taken , t 2 = d / 80 hr second round distance traveled = d ( same distance ) speed = 120 k / h time taken , t 2 = d / 120 hr total time taken = 3 hrs therefore , 3 = d / 80 + d / 120 lcm of 80 and 120 = 240 3 = d / 80 + d / 120 = > 3 = 3 d / 240 + 2 d / 240 = > d = 240 * 2 / 5 km therefore , t 1 = d / 80 = > t 1 = ( 240 * 3 ) / ( 5 x 80 ) = > t 1 = ( 9 x 60 ) / 5 - - in minutes = > t 1 = 108 minutes . e" | physics |
math_qa__tJpPqKOJrtEVFPru | The reciprocal of the hcf and lcm of two are 1/16 and 1/312 .if one of the number is 24 then other no. is Choose the correct option.
A) 126 B) 136 C) 146 D) 208 E) 266 | <gadget id="calculator">16 * 312</gadget>
<output>4_992</output>
<gadget id="calculator">4_992 / 24</gadget>
<output>208</output>
<result>D</result> | D | 208 | The reciprocal of the hcf and lcm of two are 1/16 and 1/312 .if one of the number is 24 then other no. is | {
"A": "126",
"B": "136",
"C": "146",
"D": "208",
"E": "266"
} | divide(multiply(16, 312), 24) | multiply(n1,n3)|divide(#0,n4)| | "reciprocal of the hcf and lcm of two are 1 / 16 and 1 / 312 so , hcf = 16 , lcm = 312 lcm * hcf = product of two numbers = a * b = > b = lcm * hcf / a so , other = 16 * 312 / 24 = 208 answer : d" | physics |
math_qa__bFuo5NPH1H90bf0b | 360 metres long yard, 31 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
Choose the correct choice from the following options
A) 10
B) 12
C) 14
D) 16
E) 17 | <gadget id="calculator">31 - 2</gadget>
<output>29</output>
<gadget id="calculator">29 + 1</gadget>
<output>30</output>
<gadget id="calculator">360 / 30</gadget>
<output>12</output>
<result>B</result> | B | 12 | 360 metres long yard, 31 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "17"
} | divide(360, add(subtract(31, 2), const_1)) | subtract(n1,n2)|add(#0,const_1)|divide(n0,#1)| | "31 trees have 30 gaps between them , required distance ( 360 / 30 ) = 12 b" | physics |
math_qa__Ofce17rjurAMId5d | A train running at the speed of 80 km/hr crosses a pole in 9 sec. What is the length of the train? Choose the correct choice from the following choices
A) 227 m B) 150 m C) 187 m D) 167 m E) 200 m | <gadget id="calculator">80 * 1_000</gadget>
<output>80_000</output>
<gadget id="calculator">80_000 / 3_600</gadget>
<output>200/9 = around 22.222222</output>
<gadget id="calculator">(200/9) * 9</gadget>
<output>200</output>
<result>E</result> | E | 200 | A train running at the speed of 80 km/hr crosses a pole in 9 sec. What is the length of the train? | {
"A": "227 m",
"B": "150 m",
"C": "187 m",
"D": "167 m",
"E": "200 m"
} | multiply(divide(multiply(80, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 80 * 5 / 18 = 200 / 9 m / sec length of the train = speed * time = 200 / 9 * 9 = 200 m answer : e" | physics |
math_qa__E0ubpzzhW5IfhhEs | A train 180 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? Choose the correct choice from the following answers:
A) 7 B) 10 C) 8 D) 2 E) 4 | <gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">66 * (5/18)</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">180 / (55/3)</gadget>
<output>108/11 = around 9.818182</output>
<result>B</result> | B | 10 | A train 180 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? | {
"A": "7",
"B": "10",
"C": "8",
"D": "2",
"E": "4"
} | divide(180, multiply(add(60, 6), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 60 + 6 = 66 km / hr . = 66 * 5 / 18 = 55 / 3 m / sec . time taken to pass the men = 180 * 3 / 55 = 10 sec . answer b" | physics |
math_qa__WmGw1YA7J01oXg9C | What is the difference between 38% of 80 nd 12% of 160. Choose the correct choice from the following answers.
A) 11.3 B) 12.4 C) 12.7 D) 11.2 E) 10.3 | <gadget id="calculator">38 * 80</gadget>
<output>3_040</output>
<gadget id="calculator">3_040 / 100</gadget>
<output>152/5 = around 30.4</output>
<gadget id="calculator">12 * 160</gadget>
<output>1_920</output>
<gadget id="calculator">1_920 / 100</gadget>
<output>96/5 = around 19.2</output>
<gadget id="calculator">(152/5) - (96/5)</gadget>
<output>56/5 = around 11.2</output>
<result>D</result> | D | 11.2 | What is the difference between 38% of 80 nd 12% of 160. | {
"A": "11.3",
"B": "12.4",
"C": "12.7",
"D": "11.2",
"E": "10.3"
} | subtract(divide(multiply(38, 80), const_100), divide(multiply(12, 160), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|subtract(#2,#3)| | "( 38 / 100 ) * 80 Γ’ β¬ β ( 12 / 100 ) * 160 30.4 - 19.2 = 11.2 answer : d" | gain |
math_qa__HCborbXjpOn3mheu | Paul completes a piece of work in 80 days, Rose completes the same work in 120 days. If both of them work together, then the number of days required to complete the work is? Answers:
A) 42 B) 44 C) 46 D) 48 E) 50 | <gadget id="calculator">1 / 80</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">1 / 120</gadget>
<output>1/120 = around 0.008333</output>
<gadget id="calculator">(1/80) + (1/120)</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">1 / (1/48)</gadget>
<output>48</output>
<result>D</result> | D | 48 | Paul completes a piece of work in 80 days, Rose completes the same work in 120 days. If both of them work together, then the number of days required to complete the work is? | {
"A": "42",
"B": "44",
"C": "46",
"D": "48",
"E": "50"
} | inverse(add(divide(const_1, 80), divide(const_1, 120))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2) | if a can complete a work in x days and b can complete the same work in y days , then , both of them together can complete the work in x y / x + y days . that is , the required no . of days = 80 Γ 120 / 200 = 48 days answer is d | physics |
math_qa__jARgGc4kXWpiA6JG | The manufacturing cost of a shoe is Rs.210 and the transportation lost is Rs.500 for 100 shoes. What will be the selling price if it is sold at 20% gains
Pick one:
A) s 222 B) s 216 C) s 258 D) s 210 E) s 217 | <gadget id="calculator">500 / 100</gadget>
<output>5</output>
<gadget id="calculator">210 + 5</gadget>
<output>215</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 215</gadget>
<output>43</output>
<gadget id="calculator">215 + 43</gadget>
<output>258</output>
<result>C</result> | C | 258 | The manufacturing cost of a shoe is Rs.210 and the transportation lost is Rs.500 for 100 shoes. What will be the selling price if it is sold at 20% gains | {
"A": "s 222",
"B": "s 216",
"C": "s 258",
"D": "s 210",
"E": "s 217"
} | add(add(210, divide(500, 100)), multiply(divide(20, 100), add(210, divide(500, 100)))) | divide(n1,n2)|divide(n3,n2)|add(n0,#0)|multiply(#2,#1)|add(#2,#3)| | "explanation : total cost of a watch = 210 + ( 500 / 100 ) = 215 . gain = 20 % = > sp = 1.2 cp = 1.2 x 215 = 258 answer : c" | gain |
math_qa__oBoL1hpddkqLb5jV | A vessel of capacity 2 litre has 40% of alcohol and another vessel of capacity 6 litre had 60% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture? Choose one: A) 31 % . B) 44 % . C) 49 % . D) 29 % . E) 51 % . | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 2</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 6</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">(4/5) + (18/5)</gadget>
<output>22/5 = around 4.4</output>
<gadget id="calculator">(22/5) / 10</gadget>
<output>11/25 = around 0.44</output>
<gadget id="calculator">(11/25) * 100</gadget>
<output>44</output>
<result>B</result> | B | 44 | A vessel of capacity 2 litre has 40% of alcohol and another vessel of capacity 6 litre had 60% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture? | {
"A": "31 % .",
"B": "44 % .",
"C": "49 % .",
"D": "29 % .",
"E": "51 % ."
} | multiply(divide(add(multiply(divide(40, const_100), 2), multiply(divide(60, const_100), 6)), 10), const_100) | divide(n1,const_100)|divide(n3,const_100)|multiply(n0,#0)|multiply(n2,#1)|add(#2,#3)|divide(#4,n5)|multiply(#5,const_100)| | "40 % of 2 litres = 0.8 litres 60 % of 6 litres = 3.6 litres therefore , total quantity of alcohol is 4.4 litres . this mixture is in a 10 litre vessel . hence , the concentration of alcohol in this 10 litre vessel is 44 % b" | general |
math_qa__3fDV46wHXLCYVdYS | 65% of x = 20% of 422.50. Find the value of x? Choose the correct choice from the following answers.
A) 100 B) 130 C) 150 D) 180 E) 199 | <gadget id="calculator">422.5 / 100</gadget>
<output>4.225</output>
<gadget id="calculator">4.225 * 20</gadget>
<output>84.5</output>
<gadget id="calculator">84.5 * 100</gadget>
<output>8_450</output>
<gadget id="calculator">8_450 / 65</gadget>
<output>130</output>
<result>B</result> | B | 130 | 65% of x = 20% of 422.50. Find the value of x? | {
"A": "100",
"B": "130",
"C": "150",
"D": "180",
"E": "199"
} | divide(multiply(multiply(divide(422.50, const_100), 20), const_100), 65) | divide(n2,const_100)|multiply(n1,#0)|multiply(#1,const_100)|divide(#2,n0)| | "65 % of x = 20 % of 422.50 then , 65 / 100 * x = 20 / 100 * 4225 / 10 x = 845 / 10 * 100 / 65 = 130 answer is b" | general |
math_qa__NKKfaXrGHWPvqs9P | On increasing the number of lines in a page by 80, they become 240. What is the % of increase in the no. of lines in the page? Choose the correct choice from the following: A) 20 % B) 305 C) 50 % D) 55 % E) 60 % | <gadget id="calculator">240 - 80</gadget>
<output>160</output>
<gadget id="calculator">240 / 160</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 100</gadget>
<output>150</output>
<gadget id="calculator">150 - 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | On increasing the number of lines in a page by 80, they become 240. What is the % of increase in the no. of lines in the page? | {
"A": "20 %",
"B": "305",
"C": "50 %",
"D": "55 %",
"E": "60 %"
} | subtract(multiply(divide(240, subtract(240, 80)), const_100), const_100) | subtract(n1,n0)|divide(n1,#0)|multiply(#1,const_100)|subtract(#2,const_100) | explanation : number of pages increased = 80 now , the number of pages of book = 240 number of pages of the books before increase = 240 β 80 = 160 % increase in the number of pages in the book = 80 160 x 100 % = 50 % c | general |
math_qa__lomqw6NmzKmU8y6H | A batsman scored 120 runs whichincluded 3 boundaries and 8sixes. What % of his total score did he make by running between the wickets
Choose the correct choice from the following answers
A) 40 %
B) 50 %
C) 55 %
D) 65 %
E) 70 % | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">12 + 48</gadget>
<output>60</output>
<gadget id="calculator">60 / 120</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>B</result> | B | 50 | A batsman scored 120 runs whichincluded 3 boundaries and 8sixes. What % of his total score did he make by running between the wickets | {
"A": "40 %",
"B": "50 %",
"C": "55 %",
"D": "65 %",
"E": "70 %"
} | multiply(divide(add(multiply(3, const_4), multiply(add(3, const_3), 8)), 120), const_100) | add(n1,const_3)|multiply(n1,const_4)|multiply(n2,#0)|add(#1,#2)|divide(#3,n0)|multiply(#4,const_100) | number of runs made by running = 110 - ( 3 x 4 + 8 x 6 ) = 120 - ( 60 ) = 60 now , we need to calculate 60 is what percent of 120 . = > 60 / 120 * 100 = 50 % b | general |
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