Datasets:

id
stringlengths
25
25
question
stringlengths
45
1.01k
chain
stringlengths
75
4.11k
result
stringclasses
5 values
result_float
float64
-4,212
100B
question_without_options
stringlengths
6
962
options
dict
annotated_formula
stringlengths
7
6.48k
linear_formula
stringlengths
8
925
rationale
stringlengths
1
2.74k
category
stringclasses
6 values
math_qa__5asmlRIUpWxJUQvq
The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 200 resolutions. Select. A) 271.34 m B) 281.34 m C) 291.34 m D) 301.34 m E) 311.34 m
<gadget id="calculator">3 + 4</gadget> <output>7</output> <gadget id="calculator">7 * 3</gadget> <output>21</output> <gadget id="calculator">21 + 1</gadget> <output>22</output> <gadget id="calculator">22 / 7</gadget> <output>22/7 = around 3.142857</output> <gadget id="calculator">(22/7) * 22.4</gadget> <output>70.4</output> <gadget id="calculator">70.4 * 2</gadget> <output>140.8</output> <gadget id="calculator">140.8 * 200</gadget> <output>28_160</output> <gadget id="calculator">28_160 / 100</gadget> <output>1_408/5 = around 281.6</output> <result>B</result>
B
281.34
The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 200 resolutions.
{ "A": "271.34 m", "B": "281.34 m", "C": "291.34 m", "D": "301.34 m", "E": "311.34 m" }
divide(multiply(multiply(multiply(divide(add(multiply(add(const_3, const_4), const_3), const_1), add(const_3, const_4)), 22.4), const_2), 200), const_100)
add(const_3,const_4)|multiply(#0,const_3)|add(#1,const_1)|divide(#2,#0)|multiply(n0,#3)|multiply(#4,const_2)|multiply(n1,#5)|divide(#6,const_100)|
"in one resolution , the distance covered by the wheel is its own circumference . distance covered in 200 resolutions . = 200 * 2 * 22 / 7 * 22.4 = 28134 cm = 281.34 m answer : b"
physics
math_qa__x1IFkVfbquLV35CZ
If 8 workers can build 8 cars in 8 days, then how many days would it take 7 workers to build 7 cars? Choose the correct choice from the following. A) 4 B) 7 C) 8 D) 12 E) 14
<gadget id="calculator">8 * 8</gadget> <output>64</output> <gadget id="calculator">64 / 8</gadget> <output>8</output> <gadget id="calculator">7 / 7</gadget> <output>1</output> <gadget id="calculator">8 * 1</gadget> <output>8</output> <result>C</result>
C
8
If 8 workers can build 8 cars in 8 days, then how many days would it take 7 workers to build 7 cars?
{ "A": "4", "B": "7", "C": "8", "D": "12", "E": "14" }
multiply(divide(multiply(8, 8), 8), divide(7, 7))
divide(n3,n3)|multiply(n0,n0)|divide(#1,n0)|multiply(#2,#0)|
"8 workers can build 1 car per day on average . 1 worker can build 1 / 8 of a car per day . 7 workers can build 7 / 8 car per day . the time required to build 7 cars is 7 / ( 7 / 8 ) = 8 days the answer is c ."
physics
math_qa__LETYmpQhYFeqOycD
A girl was asked to multiply a certain number by 43. She multiplied it by 34 and got his answer less than the correct one by 1242. Find the number to be multiplied. Choose the correct choice from the following answers A) 130 B) 132 C) 134 D) 136 E) 138
<gadget id="calculator">43 - 34</gadget> <output>9</output> <gadget id="calculator">1_242 / 9</gadget> <output>138</output> <result>E</result>
E
138
A girl was asked to multiply a certain number by 43. She multiplied it by 34 and got his answer less than the correct one by 1242. Find the number to be multiplied.
{ "A": "130", "B": "132", "C": "134", "D": "136", "E": "138" }
divide(1242, subtract(43, 34))
subtract(n0,n1)|divide(n2,#0)|
"let the required number be x . then , 43 x – 34 x = 1242 or 9 x = 1242 or x = 138 . required number = 138 . answer : e"
general
math_qa__JyzO7j8JXjSvj4Bq
In an election, candidate A got 85% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favor of candidate. Choose one. A) 330000 B) 340000 C) 347000 D) 356000 E) 404600
<gadget id="calculator">15 / 100</gadget> <output>3/20 = around 0.15</output> <gadget id="calculator">1 - (3/20)</gadget> <output>17/20 = around 0.85</output> <gadget id="calculator">560_000 * (17/20)</gadget> <output>476_000</output> <gadget id="calculator">85 / 100</gadget> <output>17/20 = around 0.85</output> <gadget id="calculator">476_000 * (17/20)</gadget> <output>404_600</output> <result>E</result>
E
404,600
In an election, candidate A got 85% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favor of candidate.
{ "A": "330000", "B": "340000", "C": "347000", "D": "356000", "E": "404600" }
multiply(multiply(560000, subtract(const_1, divide(15, const_100))), divide(85, const_100))
divide(n0,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(n2,#2)|multiply(#0,#3)|
"total number of invalid votes = 15 % of 560000 = 15 / 100 × 560000 = 8400000 / 100 = 84000 total number of valid votes 560000 – 84000 = 476000 percentage of votes polled in favour of candidate a = 85 % therefore , the number of valid votes polled in favour of candidate a = 85 % of 476000 = 85 / 100 × 476000 = 40460000 / 100 = 404600 e )"
gain
math_qa__zPIrYXSUoBrlEiTV
Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years Choose the correct choice from the following options A) 306.09 B) 306.07 C) 306.04 D) 306.03 E) 306.01
<gadget id="calculator">4 / 100</gadget> <output>1/25 = around 0.04</output> <gadget id="calculator">1 + (1/25)</gadget> <output>26/25 = around 1.04</output> <gadget id="calculator">3 / 2</gadget> <output>3/2 = around 1.5</output> <gadget id="calculator">(26/25) ** (3/2)</gadget> <output>26*sqrt(26)/125 = around 1.060596</output> <gadget id="calculator">5_000 * (26*sqrt(26)/125)</gadget> <output>1040*sqrt(26) = around 5_302.980294</output> <gadget id="calculator">(1040*sqrt(26)) - 5_000</gadget> <output>-5000 + 1040*sqrt(26) = around 302.980294</output> <result>C</result>
C
306.04
Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years
{ "A": "306.09", "B": "306.07", "C": "306.04", "D": "306.03", "E": "306.01" }
subtract(multiply(5000, power(add(1, divide(4, const_100)), divide(const_3, 2))), 5000)
divide(n1,const_100)|divide(const_3,n4)|add(#0,n2)|power(#2,#1)|multiply(n0,#3)|subtract(#4,n0)|
"a = 5000 ( 51 / 50 ) 3 = 5306.04 5000 - - - - - - - - - - - 306.04 answer : c"
general
math_qa__ulrnDJZdi4rsF0Dc
A retailer purchases shirts from a wholesaler and then sells the shirts in her store at a retail price that is 80 percent greater than the wholesale price. If the retailer decreases the retail price by 20 percent this will have the same effect as increasing the wholesale price by what percent? Choose one: A) 26 B) 37.5 C) 42 D) 44 E) 50
<gadget id="calculator">80 / 100</gadget> <output>4/5 = around 0.8</output> <gadget id="calculator">1 + (4/5)</gadget> <output>9/5 = around 1.8</output> <gadget id="calculator">20 / 100</gadget> <output>1/5 = around 0.2</output> <gadget id="calculator">1 - (1/5)</gadget> <output>4/5 = around 0.8</output> <gadget id="calculator">(9/5) * (4/5)</gadget> <output>36/25 = around 1.44</output> <gadget id="calculator">(36/25) - 1</gadget> <output>11/25 = around 0.44</output> <gadget id="calculator">(11/25) * 100</gadget> <output>44</output> <result>D</result>
D
44
A retailer purchases shirts from a wholesaler and then sells the shirts in her store at a retail price that is 80 percent greater than the wholesale price. If the retailer decreases the retail price by 20 percent this will have the same effect as increasing the wholesale price by what percent?
{ "A": "26", "B": "37.5", "C": "42", "D": "44", "E": "50" }
multiply(subtract(multiply(add(const_1, divide(80, const_100)), subtract(const_1, divide(20, const_100))), const_1), const_100)
divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)|
"answer : d = 44 . assume rs . 100 to be the price at which the retailer buys from wholesaler . 80 % increase makes retail price = 180 . now 20 % decrease - > ( 1 - 20 / 100 ) * 180 = 144 . now compared to the wholesale price of 100 , 44 % increase is what will have the same effect as increasing the wholesale price ."
gain
math_qa__CPlTuXCxqg1h9ZS7
The slant height of a cone is 22 cm and radius of the base is 7cm, find the curved surface of the cone? Pick. A) 426 B) 284 C) 483 D) 256 E) 428
<gadget id="calculator">pi * 7</gadget> <output>7*pi = around 21.991149</output> <gadget id="calculator">(7*pi) * 22</gadget> <output>154*pi = around 483.805269</output> <result>C</result>
C
483
The slant height of a cone is 22 cm and radius of the base is 7cm, find the curved surface of the cone?
{ "A": "426", "B": "284", "C": "483", "D": "256", "E": "428" }
multiply(multiply(const_pi, 7), 22)
multiply(n1,const_pi)|multiply(n0,#0)|
"π * 22 * 7 = 483 answer : c"
geometry
math_qa__thpjuAvazoo7m6tq
One night 40 percent of the female officers on a police force were on duty. If 240 officers were on duty that night and half of these were female officers, how many female officers were on the police force? Choose the correct choice from the following answers: A) 90 B) 300 C) 270 D) 500 E) 1,000
<gadget id="calculator">240 / 2</gadget> <output>120</output> <gadget id="calculator">40 / 100</gadget> <output>2/5 = around 0.4</output> <gadget id="calculator">120 / (2/5)</gadget> <output>300</output> <result>B</result>
B
300
One night 40 percent of the female officers on a police force were on duty. If 240 officers were on duty that night and half of these were female officers, how many female officers were on the police force?
{ "A": "90", "B": "300", "C": "270", "D": "500", "E": "1,000" }
divide(divide(240, const_2), divide(40, const_100))
divide(n1,const_2)|divide(n0,const_100)|divide(#0,#1)|
"let total number of female officers in the police force = f total number of officers on duty on that night = 240 number of female officers on duty on that night = 240 / 2 = 120 ( 40 / 100 ) * f = 120 = > f = 300 answer b"
gain
math_qa__wIdJxyU7QzikEECG
There are 4 red shoes & 6 green shoes . If two of red shoes are drawn what is the probability of getting red shoes Select the correct option: A) 1 / 13 B) 1 / 14 C) 1 / 2 D) 2 / 15 E) 2 / 16
<gadget id="calculator">binomial(4, 2)</gadget> <output>6</output> <gadget id="calculator">4 + 6</gadget> <output>10</output> <gadget id="calculator">binomial(10, 2)</gadget> <output>45</output> <gadget id="calculator">6 / 45</gadget> <output>2/15 = around 0.133333</output> <result>D</result>
D
0.133333
There are 4 red shoes & 6 green shoes . If two of red shoes are drawn what is the probability of getting red shoes
{ "A": "1 / 13", "B": "1 / 14", "C": "1 / 2", "D": "2 / 15", "E": "2 / 16" }
divide(choose(4, const_2), choose(add(4, 6), const_2))
add(n0,n1)|choose(n0,const_2)|choose(#0,const_2)|divide(#1,#2)|
"taking 4 red shoe the probablity is 4 c 2 from 10 shoes probablity of taking 2 red shoe is 4 c 2 / 10 c 2 = 2 / 15 answer : d"
probability
math_qa__ZwXbOOpKOgretw6W
How much water should be added to 14 liters of a 20%-solution of alcohol to reduce the concentration of alcohol in the solution by 75% ? Choose the correct choice from the following: A) 25 liters B) 27 liters C) 26 liters D) 32 liters E) 35 liters
<gadget id="calculator">2 * 100</gadget> <output>200</output> <gadget id="calculator">75 / 100</gadget> <output>3/4 = around 0.75</output> <gadget id="calculator">(3/4) * 20</gadget> <output>15</output> <gadget id="calculator">20 - 15</gadget> <output>5</output> <gadget id="calculator">200 / 5</gadget> <output>40</output> <gadget id="calculator">40 - 14</gadget> <output>26</output> <result>C</result>
C
26
How much water should be added to 14 liters of a 20%-solution of alcohol to reduce the concentration of alcohol in the solution by 75% ?
{ "A": "25 liters", "B": "27 liters", "C": "26 liters", "D": "32 liters", "E": "35 liters" }
subtract(divide(multiply(const_2, const_100), subtract(20, multiply(divide(75, const_100), 20))), 14)
divide(n2,const_100)|multiply(const_100,const_2)|multiply(n1,#0)|subtract(n1,#2)|divide(#1,#3)|subtract(#4,n0)|
"let x ltr water to be added 2 ltr alcohol to be represented as ( 20 ( 1 - 3 / 4 ( new soln . = 14 + x ) ) ) 2 = 5 % * ( 14 + x ) - - - - - - - - > x = 26 ans c"
general
math_qa__bBJDpmQlTIq1UJDh
A group of hikers is planning a trip that will take them up a mountain using one route and back down using another route. They plan to travel down the mountain at a rate of one and a half times the rate they will use on the way up, but the time each route will take is the same. If they will go up the mountain at a rate of 8 miles per day and it will take them two days, how many miles long is the route down the mountain? Choose the correct choice from the following answers. A) 18 B) 20 C) 22 D) 24 E) 25
<gadget id="calculator">8 * 2</gadget> <output>16</output> <gadget id="calculator">3 / 2</gadget> <output>3/2 = around 1.5</output> <gadget id="calculator">16 * (3/2)</gadget> <output>24</output> <result>D</result>
D
24
A group of hikers is planning a trip that will take them up a mountain using one route and back down using another route. They plan to travel down the mountain at a rate of one and a half times the rate they will use on the way up, but the time each route will take is the same. If they will go up the mountain at a rate of 8 miles per day and it will take them two days, how many miles long is the route down the mountain?
{ "A": "18", "B": "20", "C": "22", "D": "24", "E": "25" }
multiply(multiply(8, const_2), divide(const_3, const_2))
divide(const_3,const_2)|multiply(n0,const_2)|multiply(#0,#1)
on the way down , the rate is 1.5 * 8 = 12 miles per day . the distance of the route down the mountain is 2 * 12 = 24 miles . the answer is d .
physics
math_qa__pTwqzBWsw0EHhHvZ
The banker's gain on a bill due due 1 year hence at 12% per annum is Rs.6.6. The true discount is Options: A) rs . 72 B) rs . 36 C) rs . 55 D) rs . 50 E) none
<gadget id="calculator">12 / 100</gadget> <output>3/25 = around 0.12</output> <gadget id="calculator">6.6 / (3/25)</gadget> <output>55</output> <result>C</result>
C
55
The banker's gain on a bill due due 1 year hence at 12% per annum is Rs.6.6. The true discount is
{ "A": "rs . 72", "B": "rs . 36", "C": "rs . 55", "D": "rs . 50", "E": "none" }
divide(6.6, divide(12, const_100))
divide(n1,const_100)|divide(n2,#0)
solution t . d = [ b . g x 100 / r x t ] = rs . ( 6.6 x 100 / 12 x 1 ) = rs . 55 . answer c
gain
math_qa__H6j2AcvkebniJNXV
The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 92. Find the number of students who wrote the exam. Select: A) 15 B) 25 C) 30 D) 45 E) 55
<gadget id="calculator">92 * 5</gadget> <output>460</output> <gadget id="calculator">5 * 20</gadget> <output>100</output> <gadget id="calculator">460 - 100</gadget> <output>360</output> <gadget id="calculator">92 - 80</gadget> <output>12</output> <gadget id="calculator">360 / 12</gadget> <output>30</output> <result>C</result>
C
30
The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 92. Find the number of students who wrote the exam.
{ "A": "15", "B": "25", "C": "30", "D": "45", "E": "55" }
divide(subtract(multiply(92, 5), multiply(5, 20)), subtract(92, 80))
multiply(n1,n3)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)|
"let the number of students who wrote the exam be x . total marks of students = 80 x . total marks of ( x - 5 ) students = 92 ( x - 5 ) 80 x - ( 5 * 20 ) = 92 ( x - 5 ) 360 = 12 x = > x = 30 answer : c"
general
math_qa__nSlyG7ZXBR7rPaE6
A bowl was filled with 10 ounces of water, and 0.08 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period? Choose the most appropriate option. A) 0.004 % B) 0.04 % C) 40 % D) 4 % E) 40 %
<gadget id="calculator">50 * 0.08</gadget> <output>4</output> <gadget id="calculator">4 / 10</gadget> <output>2/5 = around 0.4</output> <gadget id="calculator">(2/5) * 100</gadget> <output>40</output> <result>C</result>
C
40
A bowl was filled with 10 ounces of water, and 0.08 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?
{ "A": "0.004 %", "B": "0.04 %", "C": "40 %", "D": "4 %", "E": "40 %" }
multiply(divide(multiply(50, 0.08), 10), const_100)
multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)|
"total amount of water evaporated each day during a 50 - day period = . 08 * 50 = . 08 * 100 / 2 = 8 / 2 = 4 percent of the original amount of water evaporated during this period = ( 4 / 10 ) * 100 % = 40 % answer c"
gain
math_qa__Nm2WRZMQJTowKJbo
Machine A and machine B are each used to manufacture 440 sprockets. It takes machine A 10 hours longer to produce 440 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces? Choose the correct choice from the following answers: A) 5 B) 6 C) 4 D) 3 E) 2
<gadget id="calculator">10 * 440</gadget> <output>4_400</output> <gadget id="calculator">100 + 10</gadget> <output>110</output> <gadget id="calculator">110 / 100</gadget> <output>11/10 = around 1.1</output> <gadget id="calculator">4_400 * (11/10)</gadget> <output>4_840</output> <gadget id="calculator">440 * (11/10)</gadget> <output>484</output> <gadget id="calculator">484 - 440</gadget> <output>44</output> <gadget id="calculator">4_840 / 44</gadget> <output>110</output> <gadget id="calculator">440 / 110</gadget> <output>4</output> <result>C</result>
C
4
Machine A and machine B are each used to manufacture 440 sprockets. It takes machine A 10 hours longer to produce 440 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces?
{ "A": "5", "B": "6", "C": "4", "D": "3", "E": "2" }
divide(440, divide(multiply(multiply(10, 440), divide(add(const_100, 10), const_100)), subtract(multiply(440, divide(add(const_100, 10), const_100)), 440)))
add(n1,const_100)|multiply(n0,n1)|divide(#0,const_100)|multiply(#2,#1)|multiply(n0,#2)|subtract(#4,n0)|divide(#3,#5)|divide(n0,#6)|
"machine b : takes x hours to produce 440 sprockets machine a : takes ( x + 10 ) hours to produce 440 sprockets machine b : in 1 hour , b makes 440 / x sprockets machine a : in 1 hour , a makes 440 / ( x + 10 ) sprockets equating : 1.1 ( 440 / ( x + 10 ) ) = 440 / x 484 / ( x + 10 ) = 440 / x 484 x = 440 x + 4400 44 x = 4400 x = 100 a makes 440 / ( 110 ) = 4 sprockets per hour answer : c"
gain
math_qa__nKfyGb62plVGR5oL
The length of a rectangular plot is 10mtr more than its width. The cost of fencing the plot along its perimeter at the rate of Rs. 6.5mtr is Rs.1170. The perimeter of the plot is? Select. A) 126 B) 156 C) 180 D) 321 E) 260
<gadget id="calculator">1_170 / 6.5</gadget> <output>180</output> <gadget id="calculator">180 / 2</gadget> <output>90</output> <gadget id="calculator">90 - 10</gadget> <output>80</output> <gadget id="calculator">80 / 2</gadget> <output>40</output> <gadget id="calculator">40 + 10</gadget> <output>50</output> <gadget id="calculator">40 + 50</gadget> <output>90</output> <gadget id="calculator">90 * 2</gadget> <output>180</output> <result>C</result>
C
180
The length of a rectangular plot is 10mtr more than its width. The cost of fencing the plot along its perimeter at the rate of Rs. 6.5mtr is Rs.1170. The perimeter of the plot is?
{ "A": "126", "B": "156", "C": "180", "D": "321", "E": "260" }
multiply(add(divide(subtract(divide(divide(1170, 6.5), const_2), 10), const_2), add(divide(subtract(divide(divide(1170, 6.5), const_2), 10), const_2), 10)), const_2)
divide(n2,n1)|divide(#0,const_2)|subtract(#1,n0)|divide(#2,const_2)|add(#3,n0)|add(#4,#3)|multiply(#5,const_2)|
"sol . let width = x , length = ( 10 + x ) perimeter = 2 ( x + ( 10 + x ) ) = 2 ( 2 x = 10 ) & 2 ( 2 x + 10 ) * 6.5 = 1170 x = 40 required perimeter = 2 ( 40 + 50 ) = 180 c"
geometry
math_qa__1serTN4f6njEEkZe
kim bought a total of $ 2.65 worth of postage stamps in 4 denominations . if she bought an equal number of 2 - cent and 20 - cent stamps and twice as many 10 - cent stamps as 5 - cent stamps , what is the least number of 1 - cent stamps she could have bought ? Choose the correct answer: A) 5 B) 10 C) 55 D) 80 E) 95
<gadget id="calculator">2.65 * 100</gadget> <output>265</output> <gadget id="calculator">20 + 2</gadget> <output>22</output> <gadget id="calculator">265 % 22</gadget> <output>1</output> <gadget id="calculator">1 + 1</gadget> <output>2</output> <gadget id="calculator">2 + 1</gadget> <output>3</output> <gadget id="calculator">3 + 1</gadget> <output>4</output> <gadget id="calculator">4 + 1</gadget> <output>5</output> <gadget id="calculator">5 + 1</gadget> <output>6</output> <gadget id="calculator">6 + 1</gadget> <output>7</output> <gadget id="calculator">7 + 1</gadget> <output>8</output> <gadget id="calculator">8 + 1</gadget> <output>9</output> <gadget id="calculator">9 + 1</gadget> <output>10</output> <gadget id="calculator">10 + 1</gadget> <output>11</output> <gadget id="calculator">11 + 1</gadget> <output>12</output> <gadget id="calculator">12 + 1</gadget> <output>13</output> <gadget id="calculator">13 + 1</gadget> <output>14</output> <gadget id="calculator">14 + 1</gadget> <output>15</output> <gadget id="calculator">15 + 1</gadget> <output>16</output> <gadget id="calculator">16 + 1</gadget> <output>17</output> <gadget id="calculator">17 + 1</gadget> <output>18</output> <gadget id="calculator">18 + 1</gadget> <output>19</output> <gadget id="calculator">19 + 1</gadget> <output>20</output> <gadget id="calculator">20 + 1</gadget> <output>21</output> <gadget id="calculator">21 + 1</gadget> <output>22</output> <gadget id="calculator">22 + 1</gadget> <output>23</output> <gadget id="calculator">23 + 1</gadget> <output>24</output> <gadget id="calculator">24 + 1</gadget> <output>25</output> <gadget id="calculator">25 + 1</gadget> <output>26</output> <gadget id="calculator">26 + 1</gadget> <output>27</output> <gadget id="calculator">27 + 1</gadget> <output>28</output> <gadget id="calculator">28 + 1</gadget> <output>29</output> <gadget id="calculator">29 + 1</gadget> <output>30</output> <gadget id="calculator">30 + 1</gadget> <output>31</output> <gadget id="calculator">31 + 1</gadget> <output>32</output> <gadget id="calculator">32 + 1</gadget> <output>33</output> <gadget id="calculator">33 + 1</gadget> <output>34</output> <gadget id="calculator">34 + 1</gadget> <output>35</output> <gadget id="calculator">35 + 1</gadget> <output>36</output> <gadget id="calculator">36 + 1</gadget> <output>37</output> <gadget id="calculator">37 + 1</gadget> <output>38</output> <gadget id="calculator">38 + 1</gadget> <output>39</output> <gadget id="calculator">39 + 1</gadget> <output>40</output> <gadget id="calculator">40 + 1</gadget> <output>41</output> <gadget id="calculator">41 + 1</gadget> <output>42</output> <gadget id="calculator">42 + 1</gadget> <output>43</output> <gadget id="calculator">43 + 1</gadget> <output>44</output> <gadget id="calculator">44 + 1</gadget> <output>45</output> <gadget id="calculator">45 + 1</gadget> <output>46</output> <gadget id="calculator">46 + 1</gadget> <output>47</output> <gadget id="calculator">47 + 1</gadget> <output>48</output> <gadget id="calculator">48 + 1</gadget> <output>49</output> <gadget id="calculator">49 + 1</gadget> <output>50</output> <gadget id="calculator">50 + 1</gadget> <output>51</output> <gadget id="calculator">51 + 1</gadget> <output>52</output> <gadget id="calculator">52 + 1</gadget> <output>53</output> <result>C</result>
C
55
kim bought a total of $ 2.65 worth of postage stamps in 4 denominations . if she bought an equal number of 2 - cent and 20 - cent stamps and twice as many 10 - cent stamps as 5 - cent stamps , what is the least number of 1 - cent stamps she could have bought ?
{ "A": "5", "B": "10", "C": "55", "D": "80", "E": "95" }
add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(reminder(multiply(2.65, const_100), add(20, 2)), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1), const_1)
add(n2,n3)|multiply(n0,const_100)|reminder(#1,#0)|add(#2,const_1)|add(#3,const_1)|add(#4,const_1)|add(#5,const_1)|add(#6,const_1)|add(#7,const_1)|add(#8,const_1)|add(#9,const_1)|add(#10,const_1)|add(#11,const_1)|add(#12,const_1)|add(#13,const_1)|add(#14,const_1)|add(#15,const_1)|add(#16,const_1)|add(#17,const_1)|add(#18,const_1)|add(#19,const_1)|add(#20,const_1)|add(#21,const_1)|add(#22,const_1)|add(#23,const_1)|add(#24,const_1)|add(#25,const_1)|add(#26,const_1)|add(#27,const_1)|add(#28,const_1)|add(#29,const_1)|add(#30,const_1)|add(#31,const_1)|add(#32,const_1)|add(#33,const_1)|add(#34,const_1)|add(#35,const_1)|add(#36,const_1)|add(#37,const_1)|add(#38,const_1)|add(#39,const_1)|add(#40,const_1)|add(#41,const_1)|add(#42,const_1)|add(#43,const_1)|add(#44,const_1)|add(#45,const_1)|add(#46,const_1)|add(#47,const_1)|add(#48,const_1)|add(#49,const_1)|add(#50,const_1)|add(#51,const_1)|add(#52,const_1)|add(#53,const_1)
let : # of 2 and 20 cents stamps = n # of 10 cent stamps = 2 n # of 1 cent stamps = m therefore : 2 n + 20 n + 10 ( 2 n ) + m = 265 cents 42 n + m = 265 forleastnumber of 1 cents stamps , maximize 50 n . hence , 42 * 5 + m = 265 m = 55 i . e . 55 stamps 1 cents each answer : c
general
math_qa__XBwOQRQj9iQqvDGH
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train. Choose the correct choice A) 150 B) 388 C) 266 D) 299 E) 261
<gadget id="calculator">60 * 1_000</gadget> <output>60_000</output> <gadget id="calculator">60_000 / 3_600</gadget> <output>50/3 = around 16.666667</output> <gadget id="calculator">(50/3) * 9</gadget> <output>150</output> <result>A</result>
A
150
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.
{ "A": "150", "B": "388", "C": "266", "D": "299", "E": "261" }
multiply(divide(multiply(60, const_1000), const_3600), 9)
multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)|
"speed = 60 * ( 5 / 18 ) m / sec = 50 / 3 m / sec length of train ( distance ) = speed * time ( 50 / 3 ) * 9 = 150 meter . answer : a"
physics
math_qa__884rNPxmWUzDs7zU
The average weight of 8 students decreases by 5 kg when one of them weighing 86 kg is replaced by a new student. The weight of the student is Select: A) 46 kg B) 48 kg C) 70 kg D) 72 kg E) none of these
<gadget id="calculator">8 * 5</gadget> <output>40</output> <gadget id="calculator">86 - 40</gadget> <output>46</output> <result>A</result>
A
46
The average weight of 8 students decreases by 5 kg when one of them weighing 86 kg is replaced by a new student. The weight of the student is
{ "A": "46 kg", "B": "48 kg", "C": "70 kg", "D": "72 kg", "E": "none of these" }
subtract(86, multiply(8, 5))
multiply(n0,n1)|subtract(n2,#0)|
"explanation : let the weight of student be x kg . given , difference in average weight = 5 kg = > ( 86 - x ) / 8 = 5 = > x = 46 answer : a"
general
math_qa__VRNm72NHWGFmp4LA
A football team lost 5 yards and then gained 8. What is the team's progress? Options. A) 2 B) 3 C) 5 D) 6 E) 8
<gadget id="calculator">8 - 5</gadget> <output>3</output> <result>B</result>
B
3
A football team lost 5 yards and then gained 8. What is the team's progress?
{ "A": "2", "B": "3", "C": "5", "D": "6", "E": "8" }
subtract(8, 5)
subtract(n1,n0)|
"for lost , use negative . for gain , use positive . progress = - 5 + 8 = 3 yards b"
gain
math_qa__I1mbgwMMKwMHCaPP
80% of the population of a village is 23040. The total population of the village is ? Choose the correct answer. A) 28800 B) 24000 C) 24936 D) 25640 E) none
<gadget id="calculator">100 / 80</gadget> <output>5/4 = around 1.25</output> <gadget id="calculator">(5/4) * 23_040</gadget> <output>28_800</output> <result>A</result>
A
28,800
80% of the population of a village is 23040. The total population of the village is ?
{ "A": "28800", "B": "24000", "C": "24936", "D": "25640", "E": "none" }
multiply(divide(const_100, 80), 23040)
divide(const_100,n0)|multiply(n1,#0)|
"answer ∵ 80 % of p = 23040 ∴ p = ( 23040 x 100 ) / 80 = 28800 correct option : a"
general
math_qa__xyBKMcnZsW7HYzaM
A, B and C completed a piece of work, A worked for 6 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1702? Choose the correct choice from the following answers A) s . 109 B) s . 115 C) s . 100 D) s . 103 E) s . 102
<gadget id="calculator">6 * 3</gadget> <output>18</output> <gadget id="calculator">9 * 4</gadget> <output>36</output> <gadget id="calculator">18 + 36</gadget> <output>54</output> <gadget id="calculator">4 * 5</gadget> <output>20</output> <gadget id="calculator">54 + 20</gadget> <output>74</output> <gadget id="calculator">1_702 / 74</gadget> <output>23</output> <gadget id="calculator">5 * 23</gadget> <output>115</output> <result>B</result>
B
115
A, B and C completed a piece of work, A worked for 6 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1702?
{ "A": "s . 109", "B": "s . 115", "C": "s . 100", "D": "s . 103", "E": "s . 102" }
multiply(5, divide(1702, add(add(multiply(6, 3), multiply(9, 4)), multiply(4, 5))))
multiply(n0,n3)|multiply(n1,n2)|multiply(n2,n5)|add(#0,#1)|add(#3,#2)|divide(n6,#4)|multiply(n5,#5)|
"3 x 4 x 5 x 6 9 4 18 x + 36 x + 20 x = 1702 74 x = 1702 = > x = 23 5 x = 115 rs . answer : b"
physics
math_qa__lCtVKk1f2ApS6QKC
A hiker walking at a constant rate of 4 kilometers per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 18 kilometers per hour. The cyclist stops and waits for the hiker 5 minutes after passing her while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up? Pick one: A) 7.5 B) 12.5 C) 17.5 D) 22.5 E) 27.5
<gadget id="calculator">5 / 60</gadget> <output>1/12 = around 0.083333</output> <gadget id="calculator">18 * (1/12)</gadget> <output>3/2 = around 1.5</output> <gadget id="calculator">4 * (1/12)</gadget> <output>1/3 = around 0.333333</output> <gadget id="calculator">(3/2) - (1/3)</gadget> <output>7/6 = around 1.166667</output> <gadget id="calculator">(7/6) / 4</gadget> <output>7/24 = around 0.291667</output> <gadget id="calculator">(7/24) * 60</gadget> <output>35/2 = around 17.5</output> <result>C</result>
C
17.5
A hiker walking at a constant rate of 4 kilometers per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 18 kilometers per hour. The cyclist stops and waits for the hiker 5 minutes after passing her while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up?
{ "A": "7.5", "B": "12.5", "C": "17.5", "D": "22.5", "E": "27.5" }
multiply(divide(subtract(multiply(18, divide(5, const_60)), multiply(4, divide(5, const_60))), 4), const_60)
divide(n2,const_60)|multiply(n1,#0)|multiply(n0,#0)|subtract(#1,#2)|divide(#3,n0)|multiply(#4,const_60)
in 5 minutes , the cyclist travels a distance of ( 5 / 60 ) * 18 = 1.5 km . the time it takes the hiker to complete this distance is 1.5 / 4 hours = 22.5 minutes the cyclist needs to wait 22.5 - 5 = 17.5 minutes the answer is c .
physics
math_qa__TaM5GGHmgkTf8wuF
An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 26 metre of cloth ? Choose the correct choice from the following answers A) 175 seconds B) 195 seconds C) 155 seconds D) 115 seconds E) 203 seconds
<gadget id="calculator">26 / 0.128</gadget> <output>203.125</output> <result>E</result>
E
203
An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 26 metre of cloth ?
{ "A": "175 seconds", "B": "195 seconds", "C": "155 seconds", "D": "115 seconds", "E": "203 seconds" }
divide(26, 0.128)
divide(n1,n0)|
"explanation : let the time required by x seconds . then , more cloth means more time ( direct proportion ) so , 0.128 : 1 : : 26 : x = > x = { \ color { blue } \ frac { 26 \ times 1 } { 0.128 } } = > x = 203.13 so time will be approx 203 seconds answer : e"
physics
math_qa__aPtb35yabAbs8FXA
In a class of 38 students 26 play football and play 20 long tennis, if 17 play above, many play neither? Choices: A) 6 B) 8 C) 9 D) 12 E) 14
<gadget id="calculator">26 + 20</gadget> <output>46</output> <gadget id="calculator">46 - 17</gadget> <output>29</output> <gadget id="calculator">38 - 29</gadget> <output>9</output> <result>C</result>
C
9
In a class of 38 students 26 play football and play 20 long tennis, if 17 play above, many play neither?
{ "A": "6", "B": "8", "C": "9", "D": "12", "E": "14" }
subtract(38, subtract(add(26, 20), 17))
add(n1,n2)|subtract(#0,n3)|subtract(n0,#1)|
"26 + 20 - 17 = 29 38 - 29 = 9 play neither answer is c"
other
math_qa__JkUEDSfc4qeFNZFc
If the diameter of circle R is 80% of the diameter of circle S, the area of circle R is what percent of the area of circle S? Select: A) 74 % B) 64 % C) 84 % D) 94 % E) 34 %
<gadget id="calculator">pi * (80 ** 2)</gadget> <output>6400*pi = around 20_106.192983</output> <gadget id="calculator">(6400*pi) * 100</gadget> <output>640000*pi = around 2_010_619.298297</output> <gadget id="calculator">pi * (100 ** 2)</gadget> <output>10000*pi = around 31_415.926536</output> <gadget id="calculator">(640000*pi) / (10000*pi)</gadget> <output>64</output> <result>B</result>
B
64
If the diameter of circle R is 80% of the diameter of circle S, the area of circle R is what percent of the area of circle S?
{ "A": "74 %", "B": "64 %", "C": "84 %", "D": "94 %", "E": "34 %" }
divide(multiply(circle_area(80), const_100), circle_area(const_100))
circle_area(n0)|circle_area(const_100)|multiply(#0,const_100)|divide(#2,#1)|
"let diameter of circle r , dr = 80 and diameter of circle s , ds = 100 radius of circle r , rr = 40 radius of circle s , rs = 50 area of circle r / area of circle s = ( pi * rr ^ 2 ) / ( pi * rs ^ 2 ) = ( 40 / 50 ) ^ 2 = ( 8 / 10 ) ^ 2 = 64 % answer : b"
geometry
math_qa__z3XW0IaVktrrxrvx
Find the perimeter and area of a square of side 9 cm. Pick. A) 36 B) 49 C) 64 D) 81 E) 100
<gadget id="calculator">9 ** 2</gadget> <output>81</output> <result>D</result>
D
81
Find the perimeter and area of a square of side 9 cm.
{ "A": "36", "B": "49", "C": "64", "D": "81", "E": "100" }
square_area(9)
square_area(n0)|
"we know that the perimeter of square = 4 ã — side side = 9 cm therefore , perimeter = 4 ã — 9 cm = 36 cm now , area of the square = ( side ã — side ) sq . units = 9 ã — 9 cm â ² = 81 cm â ² answer : d"
geometry
math_qa__j7aOyiYCZsnZSIt0
The ratio of the volumes of two cubes is 9261: 12167. What is the ratio of their total surface areas? Choose the correct choice: A) 1 : 12 B) 85 : 31 C) 51 : 45 D) 58 : 67 E) 53 : 58
<gadget id="calculator">9_261 / 12_167</gadget> <output>9_261/12_167 = around 0.761157</output> <gadget id="calculator">1 / 3</gadget> <output>1/3 = around 0.333333</output> <gadget id="calculator">(9_261/12_167) ** (1/3)</gadget> <output>21/23 = around 0.913043</output> <result>E</result>
E
0.913793
The ratio of the volumes of two cubes is 9261: 12167. What is the ratio of their total surface areas?
{ "A": "1 : 12", "B": "85 : 31", "C": "51 : 45", "D": "58 : 67", "E": "53 : 58" }
power(divide(9261, 12167), divide(const_1, const_3))
divide(n0,n1)|divide(const_1,const_3)|power(#0,#1)|
"ratio of the sides = ³ √ 9261 : ³ √ 12167 = 21 : 23 ratio of surface areas = 212 : 232 = 53 : 58 answer : e"
geometry
math_qa__O6hl2n3PF3MyVDFg
Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 300 milliliters of solution X to create a solution that is 18 percent alcohol by volume? Choose the correct choice from the following choices A) 100 B) 150 C) 200 D) 250 E) 300
<gadget id="calculator">18 - 10</gadget> <output>8</output> <gadget id="calculator">30 - 18</gadget> <output>12</output> <gadget id="calculator">8 / 12</gadget> <output>2/3 = around 0.666667</output> <gadget id="calculator">(2/3) * 300</gadget> <output>200</output> <result>C</result>
C
200
Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 300 milliliters of solution X to create a solution that is 18 percent alcohol by volume?
{ "A": "100", "B": "150", "C": "200", "D": "250", "E": "300" }
multiply(divide(subtract(18, 10), subtract(30, 18)), 300)
subtract(n3,n0)|subtract(n1,n3)|divide(#0,#1)|multiply(n2,#2)|
"18 % is 8 % - points higher than 10 % but 12 % - points lower than 30 % . thus there should be 3 parts of solution x for 2 parts of solution y . we should add 200 ml of solution y . the answer is c ."
general
math_qa__F1TDO0nrO9Dg40w3
If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 100% of j ? Choose the correct choice from the following options: A) 0.35 B) 3.5 C) 35 D) 350 E) 700
<gadget id="calculator">125 * 150</gadget> <output>18_750</output> <gadget id="calculator">18_750 * 175</gadget> <output>3_281_250</output> <gadget id="calculator">25 * 50</gadget> <output>1_250</output> <gadget id="calculator">1_250 * 75</gadget> <output>93_750</output> <gadget id="calculator">3_281_250 / 93_750</gadget> <output>35</output> <gadget id="calculator">35 * 20</gadget> <output>700</output> <gadget id="calculator">700 / 100</gadget> <output>7</output> <gadget id="calculator">7 * 100</gadget> <output>700</output> <result>E</result>
E
700
If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 100% of j ?
{ "A": "0.35", "B": "3.5", "C": "35", "D": "350", "E": "700" }
multiply(divide(multiply(divide(multiply(multiply(125, 150), 175), multiply(multiply(25, 50), 75)), 20), 100), const_100)
multiply(n0,n2)|multiply(n1,n3)|multiply(n4,#0)|multiply(n5,#1)|divide(#2,#3)|multiply(n6,#4)|divide(#5,n7)|multiply(#6,const_100)|
"imo answer should be 350 . . . consider j = 10 , then k = 50 , l = 150 and m = 350 . . . . 20 % of 350 , comes out to be 70 . . . . 100 % of 10 is 10 . . . . ( 70 * 100 ) / 10 = 700 . . . . ans : e"
gain
math_qa__RWeGDb3TZPXbrb9K
If P is a prime number greater than 5, what is the remainder when P^2 is divided by 6. Choose the correct choice from the following options. A) 4 B) can not be determined C) 2 D) 6 E) 1
<gadget id="calculator">5 + 2</gadget> <output>7</output> <gadget id="calculator">7 ** 2</gadget> <output>49</output> <gadget id="calculator">49 % 6</gadget> <output>1</output> <result>E</result>
E
1
If P is a prime number greater than 5, what is the remainder when P^2 is divided by 6.
{ "A": "4", "B": "can not be determined", "C": "2", "D": "6", "E": "1" }
reminder(power(add(5, 2), const_2), 6)
add(n0,n1)|power(#0,const_2)|reminder(#1,n2)
take square of any prime number remainder will be 1 ans e
general
math_qa__mOAPE1cSz3pZC8Tr
The price of a T.V. set worth Rs. 8000 is to be paid in 20 installments of Rs. 750 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? Choose the correct choice from the following answers: A) 7250 B) 7200 C) 7820 D) 6000 E) 2799
<gadget id="calculator">8_000 - 750</gadget> <output>7_250</output> <result>A</result>
A
7,250
The price of a T.V. set worth Rs. 8000 is to be paid in 20 installments of Rs. 750 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be?
{ "A": "7250", "B": "7200", "C": "7820", "D": "6000", "E": "2799" }
subtract(8000, 750)
subtract(n0,n2)|
"money paid in cash = rs . 750 balance payment = ( 8000 - 1000 ) = rs . 7250 answer : a"
gain
math_qa__QY6RW6cJXi0ATmy5
Some students are standing in a circle in which 6th and the 16th student are standing opposite to each other. find how many students were present there. Select A) 10 B) 15 C) 20 D) 25 E) 30
<gadget id="calculator">16 - 6</gadget> <output>10</output> <gadget id="calculator">10 * 2</gadget> <output>20</output> <result>C</result>
C
20
Some students are standing in a circle in which 6th and the 16th student are standing opposite to each other. find how many students were present there.
{ "A": "10", "B": "15", "C": "20", "D": "25", "E": "30" }
multiply(subtract(16, 6), const_2)
subtract(n1,n0)|multiply(#0,const_2)
( n / 2 ) - x = 6 n - x = 16 solving these two = > n = number of students = 20 answer : c
geometry
math_qa__P7PxXni9MrthxYcf
If the annual increase in the population of a town is 10% and the present number of people is 13000, what will the population be in 2 years? Choose the correct choice from the following options. A) 15730 B) 15240 C) 12456 D) 11452 E) 10002
<gadget id="calculator">10 + 100</gadget> <output>110</output> <gadget id="calculator">110 / 100</gadget> <output>11/10 = around 1.1</output> <gadget id="calculator">(11/10) * 13_000</gadget> <output>14_300</output> <gadget id="calculator">14_300 * (11/10)</gadget> <output>15_730</output> <result>A</result>
A
15,730
If the annual increase in the population of a town is 10% and the present number of people is 13000, what will the population be in 2 years?
{ "A": "15730", "B": "15240", "C": "12456", "D": "11452", "E": "10002" }
multiply(multiply(divide(add(10, const_100), const_100), 13000), divide(add(10, const_100), const_100))
add(n0,const_100)|divide(#0,const_100)|multiply(n1,#1)|multiply(#1,#2)
the required population is = 13000 ( 1 + 10 / 100 ) ^ 2 = 13000 * 11 / 10 * 11 / 10 = 15730 answer is a
gain
math_qa__f4eIoVil2orguqpm
lagaan is levied on the 60 percent of the cultivated land . the revenue department collected total rs . 3 , 44000 through the lagaan from the village of mutter . mutter , a very rich farmer , paid only rs . 480 as lagaan . the percentage of total land of mutter over the total taxable land of the village is : Pick one. A) 0.23255 B) 0.14544 C) 0.25632 D) 0.35466 E) 0.63435
<gadget id="calculator">60 / 100</gadget> <output>3/5 = around 0.6</output> <gadget id="calculator">480 / (3/5)</gadget> <output>800</output> <gadget id="calculator">44_000 + 44_000</gadget> <output>88_000</output> <gadget id="calculator">88_000 + 44_000</gadget> <output>132_000</output> <gadget id="calculator">132_000 + 88_000</gadget> <output>220_000</output> <gadget id="calculator">220_000 + 88_000</gadget> <output>308_000</output> <gadget id="calculator">308_000 + 44_000</gadget> <output>352_000</output> <gadget id="calculator">352_000 - 3_600</gadget> <output>348_400</output> <gadget id="calculator">348_400 - 3_600</gadget> <output>344_800</output> <gadget id="calculator">344_800 - 800</gadget> <output>344_000</output> <gadget id="calculator">800 / 344_000</gadget> <output>1/430 = around 0.002326</output> <gadget id="calculator">(1/430) * 100</gadget> <output>10/43 = around 0.232558</output> <result>A</result>
A
0.23255
lagaan is levied on the 60 percent of the cultivated land . the revenue department collected total rs . 3 , 44000 through the lagaan from the village of mutter . mutter , a very rich farmer , paid only rs . 480 as lagaan . the percentage of total land of mutter over the total taxable land of the village is :
{ "A": "0.23255", "B": "0.14544", "C": "0.25632", "D": "0.35466", "E": "0.63435" }
multiply(divide(divide(480, divide(60, const_100)), subtract(subtract(subtract(add(add(add(add(add(44000, 44000), 44000), add(44000, 44000)), add(44000, 44000)), 44000), const_3600), const_3600), divide(480, divide(60, const_100)))), const_100)
add(n2,n2)|divide(n0,const_100)|add(n2,#0)|divide(n3,#1)|add(#2,#0)|add(#4,#0)|add(n2,#5)|subtract(#6,const_3600)|subtract(#7,const_3600)|subtract(#8,#3)|divide(#3,#9)|multiply(#10,const_100)
total land of sukhiya = \ inline \ frac { 480 x } { 0.6 } = 800 x \ therefore cultivated land of village = 344000 x \ therefore required percentage = \ inline \ frac { 800 x } { 344000 } \ times 100 = 0.23255 a
general
math_qa__gp94ogjZTYDLyMm3
How many positive integer solutions does the equation 5x+10y = 100 have? Pick one. A) 2 B) 33 C) 38 D) 35 E) 14
<gadget id="calculator">10 / 5</gadget> <output>2</output> <result>A</result>
A
2
How many positive integer solutions does the equation 5x+10y = 100 have?
{ "A": "2", "B": "33", "C": "38", "D": "35", "E": "14" }
divide(10, 5)
divide(n1,n0)
formula : ( constant ) / ( lcm of two nos ) = 100 / ( 5 * 10 ) = 2 answer : a
general
math_qa__E68Uh7fel6FB9q3r
The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 3025 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units? Choose the correct choice from the following choices: A) 140 B) 150 C) 160 D) 170 E) 220
<gadget id="calculator">3_025 ** (1/2)</gadget> <output>55</output> <gadget id="calculator">10 / 2</gadget> <output>5</output> <gadget id="calculator">55 / 5</gadget> <output>11</output> <gadget id="calculator">2 * 11</gadget> <output>22</output> <gadget id="calculator">10 * 22</gadget> <output>220</output> <result>E</result>
E
220
The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 3025 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
{ "A": "140", "B": "150", "C": "160", "D": "170", "E": "220" }
multiply(10, multiply(const_2, divide(sqrt(3025), divide(10, const_2))))
divide(n1,const_2)|sqrt(n0)|divide(#1,#0)|multiply(#2,const_2)|multiply(n1,#3)|
"given that the area of the square = 3025 sq . units = > side of square = √ 3025 = 55 units the radius of the circle = side of the square = 55 units length of the rectangle = 2 / 5 * 55 = 22 units given that breadth = 10 units area of the rectangle = lb = 22 * 10 = 220 sq . units answer : option e"
geometry
math_qa__x5ZKdMUzMuRw4LOK
What is the difference between the CI on Rs. 5000 for 1 years at 4% per annum CI yearly and half yearly? Pick A) rs . 2.04 B) rs . 2.12 C) rs . 2.23 D) rs . 3 E) rs . 3.04
<gadget id="calculator">4 / 2</gadget> <output>2</output> <gadget id="calculator">2 / 100</gadget> <output>1/50 = around 0.02</output> <gadget id="calculator">1 + (1/50)</gadget> <output>51/50 = around 1.02</output> <gadget id="calculator">(51/50) ** 2</gadget> <output>2_601/2_500 = around 1.0404</output> <gadget id="calculator">5_000 * (2_601/2_500)</gadget> <output>5_202</output> <gadget id="calculator">5_202 - 5_000</gadget> <output>202</output> <gadget id="calculator">5_000 * 4</gadget> <output>20_000</output> <gadget id="calculator">20_000 / 100</gadget> <output>200</output> <gadget id="calculator">202 - 200</gadget> <output>2</output> <result>A</result>
A
2.04
What is the difference between the CI on Rs. 5000 for 1 years at 4% per annum CI yearly and half yearly?
{ "A": "rs . 2.04", "B": "rs . 2.12", "C": "rs . 2.23", "D": "rs . 3", "E": "rs . 3.04" }
subtract(subtract(multiply(5000, power(add(1, divide(divide(4, const_2), const_100)), const_2)), 5000), divide(multiply(5000, 4), const_100))
divide(n2,const_2)|multiply(n0,n2)|divide(#0,const_100)|divide(#1,const_100)|add(n1,#2)|power(#4,const_2)|multiply(n0,#5)|subtract(#6,n0)|subtract(#7,#3)
c . i . when interest compounded yearly = rs . 5000 x 1 + 4 x 1 + x 4 100 100 = rs . 5000 x 26 x 51 25 50 = rs . 5304 . c . i . when interest is compounded half - yearly = rs . 5000 x 1 + 2 3 100 = rs . 5000 x 51 x 51 x 51 50 50 50 = rs . 5306.04 difference = rs . ( 5306.04 - 5304 ) = rs . 2.04 a
gain
math_qa__SyFum7F8pZXf7zZH
140 is what percent of 40? Pick one A) 5 % B) 20 % C) 50 % D) 350 % E) 500 %
<gadget id="calculator">140 / 40</gadget> <output>7/2 = around 3.5</output> <gadget id="calculator">(7/2) * 100</gadget> <output>350</output> <result>D</result>
D
350
140 is what percent of 40?
{ "A": "5 %", "B": "20 %", "C": "50 %", "D": "350 %", "E": "500 %" }
multiply(divide(140, 40), const_100)
divide(n0,n1)|multiply(#0,const_100)|
"40 * x = 140 - - > x = 3.5 - - > 3.5 expressed as percent is 350 % . answer : d ."
gain
math_qa__cKNLxxpLLKA4atOI
Tickets to a certain concert sell for $20 each. The first 10 people to show up at the ticket booth received a 40% discount, and the next 20 received a 15% discount. If 56 people bought tickets to the concert, what was the total revenue from ticket sales? Choose the correct choice A) $ 600 B) $ 740 C) $ 850 D) $ 980 E) $ 1,140
<gadget id="calculator">56 - 20</gadget> <output>36</output> <gadget id="calculator">36 - 10</gadget> <output>26</output> <gadget id="calculator">40 / 100</gadget> <output>2/5 = around 0.4</output> <gadget id="calculator">1 - (2/5)</gadget> <output>3/5 = around 0.6</output> <gadget id="calculator">(3/5) * 10</gadget> <output>6</output> <gadget id="calculator">26 + 6</gadget> <output>32</output> <gadget id="calculator">15 / 100</gadget> <output>3/20 = around 0.15</output> <gadget id="calculator">1 - (3/20)</gadget> <output>17/20 = around 0.85</output> <gadget id="calculator">(17/20) * 20</gadget> <output>17</output> <gadget id="calculator">32 + 17</gadget> <output>49</output> <gadget id="calculator">49 * 20</gadget> <output>980</output> <result>D</result>
D
980
Tickets to a certain concert sell for $20 each. The first 10 people to show up at the ticket booth received a 40% discount, and the next 20 received a 15% discount. If 56 people bought tickets to the concert, what was the total revenue from ticket sales?
{ "A": "$ 600", "B": "$ 740", "C": "$ 850", "D": "$ 980", "E": "$ 1,140" }
multiply(add(add(subtract(subtract(56, 20), 10), multiply(subtract(const_1, divide(40, const_100)), 10)), multiply(subtract(const_1, divide(15, const_100)), 20)), 20)
divide(n2,const_100)|divide(n4,const_100)|subtract(n5,n0)|subtract(const_1,#0)|subtract(#2,n1)|subtract(const_1,#1)|multiply(n1,#3)|multiply(n0,#5)|add(#6,#4)|add(#8,#7)|multiply(n0,#9)|
"price of 1 ticket = 20 $ revenue generated from sales of first 10 tickets = 10 * ( 60 / 100 * 20 ) = 10 * 12 = 120 revenue generated from sales of next 20 tickets = 20 * ( 85 / 100 * 20 ) = 20 * 17 = 340 revenue generated from sales of last 26 tickets = 20 * 26 = 520 revenue generated from sales of 56 tickets = 120 + 340 + 520 = 980 $ answer d"
gain
math_qa__iqy5r9ARQ0tKSp3l
In the annual Cultural Programme of indra prastha there was this Math Quiz going on.yudhisthir faced this last question that will bring the champion's trophy. What will be thesolution for the given problem?The function f is defined is defined asf(2x+3)= (x-3)(x+4)What is f(29)? Options: A) 200 B) 230 C) 140 D) 170 E) none of these
<gadget id="calculator">29 - 3</gadget> <output>26</output> <gadget id="calculator">26 / 2</gadget> <output>13</output> <gadget id="calculator">13 - 3</gadget> <output>10</output> <gadget id="calculator">13 + 4</gadget> <output>17</output> <gadget id="calculator">10 * 17</gadget> <output>170</output> <result>D</result>
D
170
In the annual Cultural Programme of indra prastha there was this Math Quiz going on.yudhisthir faced this last question that will bring the champion's trophy. What will be thesolution for the given problem?The function f is defined is defined asf(2x+3)= (x-3)(x+4)What is f(29)?
{ "A": "200", "B": "230", "C": "140", "D": "170", "E": "none of these" }
multiply(subtract(divide(subtract(29, 3), 2), 3), add(divide(subtract(29, 3), 2), 4))
subtract(n4,n1)|divide(#0,n0)|add(n3,#1)|subtract(#1,n1)|multiply(#2,#3)
explanation : f ( 2 x + 3 ) = ( x - 3 ) ( x + 4 ) put x = 13 f ( 2 * 13 + 3 ) = ( 13 - 3 ) * ( 13 + 4 ) = 10 * 17 f ( 29 ) = 170 answer : d
general
math_qa__jpD2SAPXhEHLbdTA
A driver goes on a trip of 70 kilometers, the first 35 kilometers at 48 kilometers per hour and the remaining distance at 24 kilometers per hour. What is the average speed of the entire trip in kilometers per hour? Choose the most appropriate option: A) 30 B) 32 C) 35 D) 36 E) 40
<gadget id="calculator">35 / 48</gadget> <output>35/48 = around 0.729167</output> <gadget id="calculator">70 - 35</gadget> <output>35</output> <gadget id="calculator">35 / 24</gadget> <output>35/24 = around 1.458333</output> <gadget id="calculator">(35/48) + (35/24)</gadget> <output>35/16 = around 2.1875</output> <gadget id="calculator">70 / (35/16)</gadget> <output>32</output> <result>B</result>
B
32
A driver goes on a trip of 70 kilometers, the first 35 kilometers at 48 kilometers per hour and the remaining distance at 24 kilometers per hour. What is the average speed of the entire trip in kilometers per hour?
{ "A": "30", "B": "32", "C": "35", "D": "36", "E": "40" }
divide(70, add(divide(35, 48), divide(subtract(70, 35), 24)))
divide(n1,n2)|subtract(n0,n1)|divide(#1,n3)|add(#0,#2)|divide(n0,#3)|
"the time for the first part of the trip was 35 / 48 hours . the time for the second part of the trip was 35 / 24 hours . the total time fro the trip was 35 / 48 + 35 / 24 = 105 / 48 = 35 / 16 hours . the average speed for the trip was 70 / ( 35 / 16 ) = 32 kph the answer is b ."
physics
math_qa__U7AXhj1HmiRPngBW
One day a car rental agency rented 2/3 of its cars, including 3/5 of its cars with CD players. If 3/4 of its cars have CD players, what percent of the cars that were not rented had CD players? Answers A) 10 % B) 35 % C) 45 % D) 66.7 % E) 90 %
<gadget id="calculator">3 * 5</gadget> <output>15</output> <gadget id="calculator">15 * 4</gadget> <output>60</output> <gadget id="calculator">3 * 60</gadget> <output>180</output> <gadget id="calculator">180 / 4</gadget> <output>45</output> <gadget id="calculator">45 * 3</gadget> <output>135</output> <gadget id="calculator">135 / 5</gadget> <output>27</output> <gadget id="calculator">45 - 27</gadget> <output>18</output> <gadget id="calculator">2 * 60</gadget> <output>120</output> <gadget id="calculator">120 / 3</gadget> <output>40</output> <gadget id="calculator">60 - 40</gadget> <output>20</output> <gadget id="calculator">18 / 20</gadget> <output>9/10 = around 0.9</output> <gadget id="calculator">(9/10) * 100</gadget> <output>90</output> <result>E</result>
E
90
One day a car rental agency rented 2/3 of its cars, including 3/5 of its cars with CD players. If 3/4 of its cars have CD players, what percent of the cars that were not rented had CD players?
{ "A": "10 %", "B": "35 %", "C": "45 %", "D": "66.7 %", "E": "90 %" }
multiply(divide(subtract(divide(multiply(3, multiply(multiply(3, 5), 4)), 4), divide(multiply(divide(multiply(3, multiply(multiply(3, 5), 4)), 4), 3), 5)), subtract(multiply(multiply(3, 5), 4), divide(multiply(const_2, multiply(multiply(3, 5), 4)), 3))), const_100)
multiply(n1,n2)|multiply(n3,#0)|multiply(n1,#1)|multiply(#1,const_2)|divide(#2,n3)|divide(#3,n1)|multiply(n1,#4)|subtract(#1,#5)|divide(#6,n2)|subtract(#4,#8)|divide(#9,#7)|multiply(#10,const_100)|
let us try to solve this by getting some number for total cars . let there be 3,4 and 5 = 60 cars . . . ( we have taken denominators of 2 / 3,3 / 4 and 3 / 5 least common number ) . 2 / 3 ( 60 ) = 40 cars . . . total rented cars , then 1 / 3 ( 60 ) = 20 cars were not rented . 3 / 4 ( 60 ) = 45 cars with cd players . . . total cdp cars now 3 / 5 ( 3 / 4 ) = 3 / 5 ( 45 ) = 27 cdp cars and these are cars that we rented . non rented cdp = total cdp - rented cdp = 45 - 27 = 18 . 18 / 20 = 90 % . answer : e
general
math_qa__VJJc0MHD3D4ZLtKQ
If 183 is divisible by 11, find the value of the smallest natural no. N? Options: A) 5 B) 7 C) 9 D) 10 E) 12
<gadget id="calculator">2 * 4</gadget> <output>8</output> <gadget id="calculator">8 - 3</gadget> <output>5</output> <gadget id="calculator">5 - 1</gadget> <output>4</output> <gadget id="calculator">11 - 4</gadget> <output>7</output> <result>B</result>
B
7
If 183 is divisible by 11, find the value of the smallest natural no. N?
{ "A": "5", "B": "7", "C": "9", "D": "10", "E": "12" }
subtract(11, subtract(subtract(multiply(const_2, const_4), const_3), const_1))
multiply(const_2,const_4)|subtract(#0,const_3)|subtract(#1,const_1)|subtract(n1,#2)
in aptitude tests , we get questions on divisibility by 11 . a number is divisible by 11 , when the difference between the sum of digits at even places and at odd places is 0 or multiple of 11 the given number is n 183 . ( sum of digits at even places ) – ( sum of digits at odd places ) = 0 ( 8 + n ) - ( 3 + 1 ) = 0 ( 8 + n ) - 4 = 0 here the value of n must be 7 b
general
math_qa__BEXM4edCFKkFxfPT
A can do a piece of work in 40 days; B can do the same in 40 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in? Choose the correct choice from the following choices: A) 20 days B) 65 days C) 86 days D) 45 days E) 17 days
<gadget id="calculator">10 + 10</gadget> <output>20</output> <gadget id="calculator">20 / 40</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">1 - (1/2)</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">10 / (1/2)</gadget> <output>20</output> <result>A</result>
A
20
A can do a piece of work in 40 days; B can do the same in 40 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in?
{ "A": "20 days", "B": "65 days", "C": "86 days", "D": "45 days", "E": "17 days" }
divide(10, subtract(const_1, divide(add(10, 10), 40)))
add(n2,n2)|divide(#0,n0)|subtract(const_1,#1)|divide(n2,#2)|
"10 / 40 + 10 / 40 + 10 / x = 1 x = 20 days answer : a"
physics
math_qa__VCrOmgWSZEwxh9oh
In a 280 meters race A beats B by 56 m or 7 seconds. A's time over the course is: Choose the correct choice from the following options A) 22 seconds B) 12 seconds C) 10 seconds D) 18 seconds E) 28 seconds
<gadget id="calculator">7 / 56</gadget> <output>1/8 = around 0.125</output> <gadget id="calculator">(1/8) * 280</gadget> <output>35</output> <gadget id="calculator">35 - 7</gadget> <output>28</output> <result>E</result>
E
28
In a 280 meters race A beats B by 56 m or 7 seconds. A's time over the course is:
{ "A": "22 seconds", "B": "12 seconds", "C": "10 seconds", "D": "18 seconds", "E": "28 seconds" }
subtract(multiply(divide(7, 56), 280), 7)
divide(n2,n1)|multiply(n0,#0)|subtract(#1,n2)|
"b runs 56 m in 7 sec . = > b runs 280 m in 7 / 56 * 280 = 35 seconds since a beats b by 7 seconds , a runs 280 m in ( 35 - 7 ) = 28 seconds hence , a ' s time over the course = 28 seconds answer : e"
physics
math_qa__gDGQ2BW8kqB3rRlu
In Smithtown, the ratio of right-handed people to left-handed people is 3 to 1 and the ratio of men to women is 3 to 2. If the number of right-handed men is maximized, then what Z percent of all the people in Smithtown are left-handed women? Choose the correct choice from the following A) 50 % B) 40 % C) 25 % D) 20 % E) 10 %
<gadget id="calculator">3 + 1</gadget> <output>4</output> <gadget id="calculator">3 + 2</gadget> <output>5</output> <gadget id="calculator">4 / 5</gadget> <output>4/5 = around 0.8</output> <gadget id="calculator">2 * (4/5)</gadget> <output>8/5 = around 1.6</output> <gadget id="calculator">3 * (4/5)</gadget> <output>12/5 = around 2.4</output> <gadget id="calculator">3 - (12/5)</gadget> <output>3/5 = around 0.6</output> <gadget id="calculator">(8/5) - (3/5)</gadget> <output>1</output> <gadget id="calculator">1 / 4</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">(1/4) * 100</gadget> <output>25</output> <result>C</result>
C
25
In Smithtown, the ratio of right-handed people to left-handed people is 3 to 1 and the ratio of men to women is 3 to 2. If the number of right-handed men is maximized, then what Z percent of all the people in Smithtown are left-handed women?
{ "A": "50 %", "B": "40 %", "C": "25 %", "D": "20 %", "E": "10 %" }
multiply(divide(subtract(multiply(2, divide(add(3, 1), add(3, 2))), subtract(3, multiply(3, divide(add(3, 1), add(3, 2))))), add(3, 1)), const_100)
add(n0,n1)|add(n0,n3)|divide(#0,#1)|multiply(n3,#2)|multiply(n0,#2)|subtract(n0,#4)|subtract(#3,#5)|divide(#6,#0)|multiply(#7,const_100)|
"looking at the ratio we can take total number of people = 20 . . ans 5 / 20 or 25 % c"
general
math_qa__729yykLI8cqxWlqy
In a kilometer race, A beats B by 80 meters or 10 seconds. What time does A take to complete the race? Choose the correct choice from the following A) 167 sec B) 190 sec C) 176 sec D) 115 sec E) 123 sec
<gadget id="calculator">1 * 1_000</gadget> <output>1_000</output> <gadget id="calculator">80 / 10</gadget> <output>8</output> <gadget id="calculator">1_000 / 8</gadget> <output>125</output> <gadget id="calculator">125 - 10</gadget> <output>115</output> <result>D</result>
D
115
In a kilometer race, A beats B by 80 meters or 10 seconds. What time does A take to complete the race?
{ "A": "167 sec", "B": "190 sec", "C": "176 sec", "D": "115 sec", "E": "123 sec" }
subtract(divide(multiply(const_1, const_1000), divide(80, 10)), 10)
divide(n0,n1)|multiply(const_1,const_1000)|divide(#1,#0)|subtract(#2,n1)|
"time taken by b run 1000 meters = ( 1000 * 10 ) / 80 = 125 sec . time taken by a = 125 - 10 = 115 sec . answer : d"
physics
math_qa__5xuHMoDXEt6oXoAk
How much space, in cubic units, is left vacant when maximum number of 4x4x4 cubes are fitted in a rectangular box measuring 10x12x16 ? Choose the correct choice from the following choices A) 0 B) 36 C) 180 D) 216 E) 384
<gadget id="calculator">4 * 2</gadget> <output>8</output> <gadget id="calculator">10 - 8</gadget> <output>2</output> <gadget id="calculator">12 * 16</gadget> <output>192</output> <gadget id="calculator">2 * 192</gadget> <output>384</output> <result>E</result>
E
384
How much space, in cubic units, is left vacant when maximum number of 4x4x4 cubes are fitted in a rectangular box measuring 10x12x16 ?
{ "A": "0", "B": "36", "C": "180", "D": "216", "E": "384" }
multiply(subtract(10, multiply(4, const_2)), multiply(12, 16))
multiply(n4,n5)|multiply(n0,const_2)|subtract(n3,#1)|multiply(#0,#2)
no of cubes that can be accommodated in box = ( 10 * 12 * 16 ) / ( 4 * 4 * 4 ) 12 * 16 in numerator can be perfectly divided by 4 * 4 in denominator . side with length 10 ca n ' t be perfectly divided by 4 and hence is the limiting factor . closet multiple of 4 less that 10 is 8 . so vacant area in cube = = 12 * 16 * ( 10 - 8 ) = 12 * 16 * 2 = 384 answer : e
geometry
math_qa__lhXkY8iPwhnlnMkU
It is currently 8:34 PM. At what time in the morning was it exactly 39,668 minutes ago? Pick one. A) 7 : 22 B) 7 : 24 C) 7 : 26 D) 7 : 28 E) 7 : 30
<gadget id="calculator">34 - 3</gadget> <output>31</output> <gadget id="calculator">8 / 31</gadget> <output>8/31 = around 0.258065</output> <result>C</result>
C
0.269231
It is currently 8:34 PM. At what time in the morning was it exactly 39,668 minutes ago?
{ "A": "7 : 22", "B": "7 : 24", "C": "7 : 26", "D": "7 : 28", "E": "7 : 30" }
divide(8, subtract(34, const_3))
subtract(n1,const_3)|divide(n0,#0)|
divide 39,668 by 60 to convert to minutes : 39,668 / 60 = 661 r 8 . that is 661 hours , 8 minutes . all of the answer choices are during the same hour before : 34 , so we can assume the 661 hours takes the time back into the 7 am hour to 7 : 34 am . going back 8 more minutes yields the time 7 : 26 am . c
physics
math_qa__vATVARa2Hi8uTjlh
A palindrome is a number that reads the same forward and backward. For example. 2442 and 111 are palindromes. If 5-digit palindromes are formed using one or more of the digits, 1, 2, 3, how many such palindromes are possible? Choose the most appropriate option: A) 12 B) 15 C) 18 D) 24 E) 27
<gadget id="calculator">3 * 3</gadget> <output>9</output> <gadget id="calculator">9 * 3</gadget> <output>27</output> <result>E</result>
E
27
A palindrome is a number that reads the same forward and backward. For example. 2442 and 111 are palindromes. If 5-digit palindromes are formed using one or more of the digits, 1, 2, 3, how many such palindromes are possible?
{ "A": "12", "B": "15", "C": "18", "D": "24", "E": "27" }
multiply(multiply(const_3, 3), 3)
multiply(n5,const_3)|multiply(n5,#0)
xyzyx x can be 1 , 2 , or 3 , thus 3 options . y can be 1 , 2 , or 3 , thus 3 options . z can be 1 , 2 , or 3 , thus 3 options . total 3 ^ 3 = 27 . answer : e .
general
math_qa__TO59tpWuDoJvRjwR
If 20% of (x-y) = 14% of (x+y), then what percent of x is y? Choose one. A) 50.5 % B) 44.4 % C) 22.2 % D) 17.6 % E) 25 %
<gadget id="calculator">20 - 14</gadget> <output>6</output> <gadget id="calculator">20 + 14</gadget> <output>34</output> <gadget id="calculator">6 / 34</gadget> <output>3/17 = around 0.176471</output> <gadget id="calculator">(3/17) * 100</gadget> <output>300/17 = around 17.647059</output> <result>D</result>
D
17.6
If 20% of (x-y) = 14% of (x+y), then what percent of x is y?
{ "A": "50.5 %", "B": "44.4 %", "C": "22.2 %", "D": "17.6 %", "E": "25 %" }
multiply(divide(subtract(20, 14), add(20, 14)), const_100)
add(n0,n1)|subtract(n0,n1)|divide(#1,#0)|multiply(#2,const_100)|
"20 % of ( x - y ) = 14 % of ( x + y ) 20 / 100 ( x - y ) = 14 / 100 ( x + y ) 6 x = 34 y required percentage = y / x * 100 = 6 y / 34 y * 100 = 17.64 % answer is d"
general
math_qa__B5UcCgBl559f0BUJ
If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively: Options. A) rs . 260 B) rs . 360 C) rs . 350 D) rs . 364 E) rs . 362
<gadget id="calculator">2 / 3</gadget> <output>2/3 = around 0.666667</output> <gadget id="calculator">1 / 4</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">(2/3) * (1/4)</gadget> <output>1/6 = around 0.166667</output> <gadget id="calculator">(1/6) + (1/4)</gadget> <output>5/12 = around 0.416667</output> <gadget id="calculator">(5/12) + 1</gadget> <output>17/12 = around 1.416667</output> <gadget id="calculator">510 / (17/12)</gadget> <output>360</output> <result>B</result>
B
360
If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively:
{ "A": "rs . 260", "B": "rs . 360", "C": "rs . 350", "D": "rs . 364", "E": "rs . 362" }
divide(510, add(add(multiply(divide(2, 3), divide(1, 4)), divide(1, 4)), 1))
divide(n3,n4)|divide(n1,n2)|multiply(#1,#0)|add(#0,#2)|add(#3,n3)|divide(n0,#4)|
"( a = 2 / 3 b and b = 1 / 4 c ) = a / b = 2 / 3 and b / c = 1 / 4 a : b = 2 : 3 and b : c = 1 : 4 = 3 : 12 a : b : c = 2 : 3 : 12 a ; s share = 510 * 2 / 17 = rs . 60 b ' s share = 510 * 3 / 17 = rs . 90 c ' s share = 510 * 12 / 17 = rs . 360 . answer : b"
general
math_qa__LpKcd7QOoFdiXMnj
What is the dividend. divisor 15, the quotient is 9 and the remainder is 5? Choose the correct choice from the following: A) 140 B) 134 C) 148 D) 158 E) 160
<gadget id="calculator">15 * 9</gadget> <output>135</output> <gadget id="calculator">135 + 5</gadget> <output>140</output> <result>A</result>
A
140
What is the dividend. divisor 15, the quotient is 9 and the remainder is 5?
{ "A": "140", "B": "134", "C": "148", "D": "158", "E": "160" }
add(multiply(15, 9), 5)
multiply(n0,n1)|add(n2,#0)|
"d = d * q + r d = 15 * 9 + 5 d = 135 + 5 d = 140 answer a"
general
math_qa__D8i9tENKvdEUX6ow
An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases. Choose the correct choice: A) 4 : 3 B) 8 : 7 C) 4 : 1 D) 6 : 5 E) none of these
<gadget id="calculator">3 * 2</gadget> <output>6</output> <gadget id="calculator">6 * 4</gadget> <output>24</output> <gadget id="calculator">7 * 3</gadget> <output>21</output> <gadget id="calculator">24 / 21</gadget> <output>8/7 = around 1.142857</output> <result>B</result>
B
1.142857
An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases.
{ "A": "4 : 3", "B": "8 : 7", "C": "4 : 1", "D": "6 : 5", "E": "none of these" }
divide(multiply(multiply(3, 2), const_4), multiply(7, 3))
multiply(n0,n1)|multiply(n0,n2)|multiply(#0,const_4)|divide(#2,#1)|
"explanation : let the length and breadth of the carpet in the first case be 3 x units and 2 x units respectively . let the dimensions of the carpet in the second case be 7 y , 3 y units respectively . from the data , . 2 ( 3 x + 2 x ) = 2 ( 7 y + 3 y ) = > 5 x = 10 y = > x = 2 y required ratio of the areas of the carpet in both the cases = 3 x * 2 x : 7 y : 3 y = 6 x 2 : 21 y 2 = 6 * ( 2 y ) 2 : 21 y 2 = 6 * 4 y 2 : 21 y 2 = 8 : 7 answer is b"
other
math_qa__MVJM451KmyDlPxWS
Stacy and Heather are 10 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?. Choose the correct option: A) 6.0 mile B) 3.0 mile C) 4.0 mile D) 3.45 mile E) 12 mile
<gadget id="calculator">1 + 5</gadget> <output>6</output> <gadget id="calculator">6 / 60</gadget> <output>1/10 = around 0.1</output> <gadget id="calculator">24 * (1/10)</gadget> <output>12/5 = around 2.4</output> <gadget id="calculator">10 - (12/5)</gadget> <output>38/5 = around 7.6</output> <gadget id="calculator">5 + 6</gadget> <output>11</output> <gadget id="calculator">(38/5) / 11</gadget> <output>38/55 = around 0.690909</output> <gadget id="calculator">(38/55) * 5</gadget> <output>38/11 = around 3.454545</output> <result>D</result>
D
3.45
Stacy and Heather are 10 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?.
{ "A": "6.0 mile", "B": "3.0 mile", "C": "4.0 mile", "D": "3.45 mile", "E": "12 mile" }
multiply(divide(subtract(10, multiply(24, divide(add(1, 5), const_60))), add(5, add(1, 5))), 5)
add(n1,n2)|add(n2,#0)|divide(#0,const_60)|multiply(n3,#2)|subtract(n0,#3)|divide(#4,#1)|multiply(n2,#5)|
"ss - stacy ' s speed = 6 m / hr sh - heather ' s speed = 5 m / hr in 24 minutes stacy will cover = ( 24 / 60 ) * 6 = 2.4 miles now since both are walking in opposite directions , add their speeds - 6 + 5 = 11 m / hr and distance to cover is 10 - 2.4 = 7.6 time taken = distance / speed = 7.6 / 11 = 0.69 hrs heather will cover = 5 * 0.69 = 3.45 miles . answer d"
physics
math_qa__blhj0DS7LcFnCnap
A man can row upstream at 26 kmph and downstream at 40 kmph, and then find the speed of the man in still water? Choose the most appropriate option: A) 22 B) 37 C) 30 D) 33 E) 18
<gadget id="calculator">26 + 40</gadget> <output>66</output> <gadget id="calculator">66 / 2</gadget> <output>33</output> <result>D</result>
D
33
A man can row upstream at 26 kmph and downstream at 40 kmph, and then find the speed of the man in still water?
{ "A": "22", "B": "37", "C": "30", "D": "33", "E": "18" }
divide(add(26, 40), const_2)
add(n0,n1)|divide(#0,const_2)|
"us = 26 ds = 40 m = ( 40 + 26 ) / 2 = 33 answer : d"
physics
math_qa__zdCFLFjzPxDRMnTj
If n is an integer from 1 to 96 (inclusive), what is the probability for n*(n+1)*(n+2) being divisible by 8? Select the correct option. A) 25 % B) 50 % C) 62.5 % D) 72.5 % E) 75 %
<gadget id="calculator">96 + 2</gadget> <output>98</output> <gadget id="calculator">1 + 1</gadget> <output>2</output> <gadget id="calculator">98 + 2</gadget> <output>100</output> <gadget id="calculator">100 * 2</gadget> <output>200</output> <gadget id="calculator">200 / 8</gadget> <output>25</output> <result>A</result>
A
25
If n is an integer from 1 to 96 (inclusive), what is the probability for n*(n+1)*(n+2) being divisible by 8?
{ "A": "25 %", "B": "50 %", "C": "62.5 %", "D": "72.5 %", "E": "75 %" }
divide(multiply(add(add(96, 2), add(1, 1)), add(1, 1)), 8)
add(n1,n3)|add(n0,n0)|add(#0,#1)|multiply(#2,#1)|divide(#3,n4)
( a ) 25 % , to be divisible by 8 the number needs to have 3 2 s in it . only a multiple of 4 can provide that . number of numbers divisible by 4 = 96 / 4 = 24 . so p ( 8 ) = 24 / 96 = 25 % .
general
math_qa__ikfuMe5KHIypIHu8
By selling an article for $90, a person gains $15. What is the gain %? Choose the correct choice from the following answers. A) 25 % B) 30 % C) 50 % D) 20 % E) 10 %
<gadget id="calculator">15 * 100</gadget> <output>1_500</output> <gadget id="calculator">90 - 15</gadget> <output>75</output> <gadget id="calculator">1_500 / 75</gadget> <output>20</output> <result>D</result>
D
20
By selling an article for $90, a person gains $15. What is the gain %?
{ "A": "25 %", "B": "30 %", "C": "50 %", "D": "20 %", "E": "10 %" }
divide(multiply(15, const_100), subtract(90, 15))
multiply(n1,const_100)|subtract(n0,n1)|divide(#0,#1)|
"s . p . = $ 90 gain = $ 15 c . p . = 90 - 15 = 75 gain % = 15 / 75 * 100 = 20 % answer is d"
gain
math_qa__7g9cmnlq1JXjbUQ9
On multiplying a number B by 153, the result obtained was 102325. However, it is found that both the 2's are wrong. Find the correct result. Choose the correct option: A) 104345 B) 107375 C) 108385 D) 109395 E) 105355
<gadget id="calculator">153 * 2</gadget> <output>306</output> <gadget id="calculator">306 * 10</gadget> <output>3_060</output> <gadget id="calculator">102_325 + 3_060</gadget> <output>105_385</output> <result>D</result>
D
109,395
On multiplying a number B by 153, the result obtained was 102325. However, it is found that both the 2's are wrong. Find the correct result.
{ "A": "104345", "B": "107375", "C": "108385", "D": "109395", "E": "105355" }
add(102325, multiply(multiply(153, 2), const_10))
multiply(n0,n2)|multiply(#0,const_10)|add(n1,#1)
the only thing you actually know about the correct number b is that it is divisible by 153 and has 5 as a factor . you should immediately try to find the factors of 153 and look for them in the options . 153 = 9 * 17 divisibility by 9 is easy to check . only ( d ) satisfies .
other
math_qa__Ic5Fb1mYj6lPEq4A
if a computer program generates 3 - digit odd numbers using the numbers 9 , 7 , 0 , 8 , and 1 , and the digits can be repeated , what is the probability that the number formed from the program is a multiple of 3 ? Choose one: A) 1 / 3 B) 1 / 4 C) 1 / 5 D) 1 / 6 E) 1 / 7
<gadget id="calculator">9 + 10</gadget> <output>19</output> <gadget id="calculator">2 * 3</gadget> <output>6</output> <gadget id="calculator">6 * 10</gadget> <output>60</output> <gadget id="calculator">19 / 60</gadget> <output>19/60 = around 0.316667</output> <result>A</result>
A
0.333333
if a computer program generates 3 - digit odd numbers using the numbers 9 , 7 , 0 , 8 , and 1 , and the digits can be repeated , what is the probability that the number formed from the program is a multiple of 3 ?
{ "A": "1 / 3", "B": "1 / 4", "C": "1 / 5", "D": "1 / 6", "E": "1 / 7" }
divide(add(9, const_10), multiply(multiply(const_2, const_3), const_10))
add(n1,const_10)|multiply(const_2,const_3)|multiply(#1,const_10)|divide(#0,#2)
a
general
math_qa__2TH2FYXyllmDET5G
The length of a side of a hexagon is 5 inches. What is the perimeter? Choose the correct choice from the following A) 116 B) 25 C) 30 D) 24 E) 15
<gadget id="calculator">3 * 2</gadget> <output>6</output> <gadget id="calculator">5 * 6</gadget> <output>30</output> <result>C</result>
C
30
The length of a side of a hexagon is 5 inches. What is the perimeter?
{ "A": "116", "B": "25", "C": "30", "D": "24", "E": "15" }
multiply(5, multiply(const_3, const_2))
multiply(const_2,const_3)|multiply(n0,#0)|
"hexagon . it means 6 equal sides . p = 5 + 5 + 5 + 5 + 5 + 5 = 10 + 10 + 10 = 30 inches answer c"
physics
math_qa__5gMY5SyVUa9Iz1pc
One fourth of a solution that was 12% salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent salt by weight? Choose the correct choice from the following options A) 28 % B) 34 % C) 22 % D) 18 % E) 8.5 %
<gadget id="calculator">16 / 100</gadget> <output>4/25 = around 0.16</output> <gadget id="calculator">(4/25) * 4</gadget> <output>16/25 = around 0.64</output> <gadget id="calculator">12 / 100</gadget> <output>3/25 = around 0.12</output> <gadget id="calculator">(3/25) * 4</gadget> <output>12/25 = around 0.48</output> <gadget id="calculator">(12/25) - (3/25)</gadget> <output>9/25 = around 0.36</output> <gadget id="calculator">(16/25) - (9/25)</gadget> <output>7/25 = around 0.28</output> <gadget id="calculator">(7/25) * 100</gadget> <output>28</output> <result>A</result>
A
28
One fourth of a solution that was 12% salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent salt by weight?
{ "A": "28 %", "B": "34 %", "C": "22 %", "D": "18 %", "E": "8.5 %" }
multiply(subtract(multiply(divide(16, const_100), const_4), subtract(multiply(divide(12, const_100), const_4), divide(12, const_100))), const_100)
divide(n1,const_100)|divide(n0,const_100)|multiply(#0,const_4)|multiply(#1,const_4)|subtract(#3,#1)|subtract(#2,#4)|multiply(#5,const_100)
consider total solution to be 100 liters and in this case you ' ll have : 75 * 0.12 + 25 * x = 100 * 0.16 - - > x = 0.28 . answer : a .
gain
math_qa__psQ2pxD2a3S6X4HO
A house wife saved $4 in buying an item on sale. If she spent $28 for the item, approximately how much percent she saved in the transaction? Pick A) 8 % B) 13 % C) 10 % D) 11 % E) 12 %
<gadget id="calculator">28 + 4</gadget> <output>32</output> <gadget id="calculator">4 / 32</gadget> <output>1/8 = around 0.125</output> <gadget id="calculator">(1/8) * 100</gadget> <output>25/2 = around 12.5</output> <result>B</result>
B
13
A house wife saved $4 in buying an item on sale. If she spent $28 for the item, approximately how much percent she saved in the transaction?
{ "A": "8 %", "B": "13 %", "C": "10 %", "D": "11 %", "E": "12 %" }
multiply(divide(4, add(28, 4)), const_100)
add(n0,n1)|divide(n0,#0)|multiply(#1,const_100)|
"actual price = 28 + 4 = $ 32 saving = 4 / 32 * 100 = 13 % approximately answer is b"
general
math_qa__JbbENVxH8G5SQfvY
two friends deepak and rajeev have agreed to meet at a definite spot on a particular day between 9pm and 10pm. the first person to come waits for some time and leaves.If the other one does not turn up by that time.If Deepak comes first,he waits for 45minutes and if Rajeev comes first,he waits for 15minutes.What is the probability of meeting between Deepak and rajeev if their arrival times are independent of eachother and each person arrives during the indicated period at random? Choose the correct choice from the following answers: A) 3 / 4 B) 11 / 16 C) 7 / 8 D) 3 / 16 E) 5 / 16
<gadget id="calculator">45 / 60</gadget> <output>3/4 = around 0.75</output> <gadget id="calculator">15 / 60</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">(3/4) * (1/4)</gadget> <output>3/16 = around 0.1875</output> <result>D</result>
D
0.1875
two friends deepak and rajeev have agreed to meet at a definite spot on a particular day between 9pm and 10pm. the first person to come waits for some time and leaves.If the other one does not turn up by that time.If Deepak comes first,he waits for 45minutes and if Rajeev comes first,he waits for 15minutes.What is the probability of meeting between Deepak and rajeev if their arrival times are independent of eachother and each person arrives during the indicated period at random?
{ "A": "3 / 4", "B": "11 / 16", "C": "7 / 8", "D": "3 / 16", "E": "5 / 16" }
multiply(divide(45, const_60), divide(15, const_60))
divide(n2,const_60)|divide(n3,const_60)|multiply(#0,#1)
deepak : 45 / 60 = 3 / 4 rajeev : 15 / 60 = 1 / 4 as these are independent events total probability = ( 3 / 4 ) * ( 1 / 4 ) = 3 / 16 answer : d
physics
math_qa__F46hAUwGur2pu0z3
Claire has a total of 90 pets consisting of gerbils and hamsters only. One-quarter of the gerbils are male, and one-third of the hamsters are male. If there are 25 males altogether, how many gerbils does Claire have? Options. A) 39 B) 50 C) 66 D) 57 E) 60
<gadget id="calculator">90 - 25</gadget> <output>65</output> <gadget id="calculator">65 + 1</gadget> <output>66</output> <result>C</result>
C
66
Claire has a total of 90 pets consisting of gerbils and hamsters only. One-quarter of the gerbils are male, and one-third of the hamsters are male. If there are 25 males altogether, how many gerbils does Claire have?
{ "A": "39", "B": "50", "C": "66", "D": "57", "E": "60" }
add(subtract(90, 25), const_1)
subtract(n0,n1)|add(#0,const_1)
g + h = 90 . . . 1 ; g / 4 + h / 3 = 25 . . . . 2 or 3 g + 4 h = 25 * 12 = 300 g = 90 - h or 3 ( 90 - h ) + 4 h = 300 h = 300 - 270 = 30 then g = 96 - 30 = 66 c
general
math_qa__zaELUYqgCneeAuc9
A shopkeeper labeled the price of his articles so as to earn a profit of 30% on the cost price. He then sold the articles by offering a discount of 10% on the labeled price. What is the actual percent profit earned in the deal? Choose the correct answer A) 18 % B) 20 % C) 17 % D) 18 % E) none of these
<gadget id="calculator">100 + 30</gadget> <output>130</output> <gadget id="calculator">10 / 100</gadget> <output>1/10 = around 0.1</output> <gadget id="calculator">130 * (1/10)</gadget> <output>13</output> <gadget id="calculator">130 - 13</gadget> <output>117</output> <gadget id="calculator">117 - 100</gadget> <output>17</output> <result>C</result>
C
17
A shopkeeper labeled the price of his articles so as to earn a profit of 30% on the cost price. He then sold the articles by offering a discount of 10% on the labeled price. What is the actual percent profit earned in the deal?
{ "A": "18 %", "B": "20 %", "C": "17 %", "D": "18 %", "E": "none of these" }
subtract(subtract(add(const_100, 30), multiply(add(const_100, 30), divide(10, const_100))), const_100)
add(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|subtract(#0,#2)|subtract(#3,const_100)
explanation : let the cp of the article = rs . 100 . then labeled price = rs . 130 . sp = rs . 130 - 10 % of 130 = rs . 130 - 13 = rs . 117 . gain = rs . 117 – rs . 100 = rs . 17 therefore , gain / profit percent = 17 % . answer : option c
gain
math_qa__MzCIPTQpVaqFytIX
what is rate of interest if principal.amount be 400,simple interest 100 and time 2year. Select. A) 10 B) 12.5 C) 25 D) 12 E) 14.5
<gadget id="calculator">400 * 2</gadget> <output>800</output> <gadget id="calculator">100 / 800</gadget> <output>1/8 = around 0.125</output> <gadget id="calculator">(1/8) * 100</gadget> <output>25/2 = around 12.5</output> <result>B</result>
B
12.5
what is rate of interest if principal.amount be 400,simple interest 100 and time 2year.
{ "A": "10", "B": "12.5", "C": "25", "D": "12", "E": "14.5" }
multiply(divide(100, multiply(400, 2)), const_100)
multiply(n0,n2)|divide(n1,#0)|multiply(#1,const_100)|
"s . i = ( p * r * t ) / 100 100 = 800 r / 100 r = 100 / 8 = 12.5 % answer b"
gain
math_qa__F0iOwrzHeEbi8ssW
The ratio of the volumes of two cubes is 6859 : 1331. What is the ratio of their total surface areas? Options: A) 1 : 21 B) 12 : 7 C) 1 : 15 D) 21 : 17 E) 13 : 13
<gadget id="calculator">6_859 / 1_331</gadget> <output>6_859/1_331 = around 5.153268</output> <gadget id="calculator">1 / 3</gadget> <output>1/3 = around 0.333333</output> <gadget id="calculator">(6_859/1_331) ** (1/3)</gadget> <output>19/11 = around 1.727273</output> <result>B</result>
B
1.714286
The ratio of the volumes of two cubes is 6859 : 1331. What is the ratio of their total surface areas?
{ "A": "1 : 21", "B": "12 : 7", "C": "1 : 15", "D": "21 : 17", "E": "13 : 13" }
power(divide(6859, 1331), divide(const_1, const_3))
divide(n0,n1)|divide(const_1,const_3)|power(#0,#1)|
"ratio of the sides = ³ √ 6859 : ³ √ 1331 = 19 : 11 ratio of surface areas = 192 : 112 = 12 : 7 answer : b"
geometry
math_qa__Dd1HFw4gxPvNQ1rT
If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 14% per annum then the gain of B in a period of 3 years is? Choose the correct choice: A) 400 B) 410 C) 460 D) 420 E) 430
<gadget id="calculator">3_500 * 14</gadget> <output>49_000</output> <gadget id="calculator">49_000 * 3</gadget> <output>147_000</output> <gadget id="calculator">147_000 / 100</gadget> <output>1_470</output> <gadget id="calculator">3_500 * 10</gadget> <output>35_000</output> <gadget id="calculator">35_000 * 3</gadget> <output>105_000</output> <gadget id="calculator">105_000 / 100</gadget> <output>1_050</output> <gadget id="calculator">1_470 - 1_050</gadget> <output>420</output> <result>D</result>
D
420
If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 14% per annum then the gain of B in a period of 3 years is?
{ "A": "400", "B": "410", "C": "460", "D": "420", "E": "430" }
subtract(divide(multiply(multiply(3500, 14), 3), const_100), divide(multiply(multiply(3500, 10), 3), const_100))
multiply(n0,n2)|multiply(n0,n1)|multiply(#0,n3)|multiply(n3,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,#5)|
"( 3500 * 4 * 3 ) / 100 = > 420 answer : d"
gain
math_qa__twascKqtG6InL2Sv
A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 6 days. B can do the work alone in? Choose the correct answer: A) 19 B) 36 C) 11 D) 19 E) 114
<gadget id="calculator">1 + 2</gadget> <output>3</output> <gadget id="calculator">3 + 3</gadget> <output>6</output> <gadget id="calculator">6 * 6</gadget> <output>36</output> <result>B</result>
B
36
A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 6 days. B can do the work alone in?
{ "A": "19", "B": "36", "C": "11", "D": "19", "E": "114" }
multiply(add(add(const_1, const_2), const_3), 6)
add(const_1,const_2)|add(#0,const_3)|multiply(n0,#1)|
"suppose a , b and c take x , x / 2 and x / 3 respectively to finish the work . then , ( 1 / x + 2 / x + 3 / x ) = 1 / 6 6 / x = 1 / 6 = > x = 36 so , b takes 18 hours to finish the work . answer : b"
physics
math_qa__TMhJHljDIodiFL9N
A train running at a speed of 36 km/h passes an electric pole in 14 seconds. In how many seconds will the whole train pass a 350-meter long platform? Select the correct option: A) 43 B) 45 C) 47 D) 49 E) 51
<gadget id="calculator">10 / 36</gadget> <output>5/18 = around 0.277778</output> <gadget id="calculator">36 * (5/18)</gadget> <output>10</output> <gadget id="calculator">10 * 14</gadget> <output>140</output> <gadget id="calculator">140 + 350</gadget> <output>490</output> <gadget id="calculator">490 / 10</gadget> <output>49</output> <result>D</result>
D
49
A train running at a speed of 36 km/h passes an electric pole in 14 seconds. In how many seconds will the whole train pass a 350-meter long platform?
{ "A": "43", "B": "45", "C": "47", "D": "49", "E": "51" }
divide(add(multiply(multiply(36, const_0_2778), 14), 350), multiply(36, const_0_2778))
multiply(n0,const_0_2778)|multiply(n1,#0)|add(n2,#1)|divide(#2,#0)|
"let the length of the train be x meters . when a train crosses an electric pole , the distance covered is its own length x . speed = 36 km / h = 36000 m / 3600 s = 10 m / s x = 14 * 10 = 140 m . the time taken to pass the platform = ( 140 + 350 ) / 10 = 49 seconds the answer is d ."
physics
math_qa__Pcffta0ae5U1Js4S
Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 110 mangoes. Pick: A) 367 B) 380 C) 400 D) 406 E) 412
<gadget id="calculator">1 / 10</gadget> <output>1/10 = around 0.1</output> <gadget id="calculator">1 - (1/10)</gadget> <output>9/10 = around 0.9</output> <gadget id="calculator">360 / (9/10)</gadget> <output>400</output> <gadget id="calculator">400 - 360</gadget> <output>40</output> <gadget id="calculator">40 / 12</gadget> <output>10/3 = around 3.333333</output> <gadget id="calculator">(10/3) * 110</gadget> <output>1_100/3 = around 366.666667</output> <result>A</result>
A
367
Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 110 mangoes.
{ "A": "367", "B": "380", "C": "400", "D": "406", "E": "412" }
multiply(divide(subtract(divide(360, subtract(const_1, divide(const_1, 10))), 360), 12), 110)
divide(const_1,n1)|subtract(const_1,#0)|divide(n0,#1)|subtract(#2,n0)|divide(#3,n2)|multiply(n3,#4)|
"mr . john used to purchase certain number of mangoes for $ 360 since the price of mangoes is reduced by 10 % he got 12 more mangoes today . find the original price of 120 mangoes . method 1 : let price per mango = x . let number of mangoes be n . then , nx = 360 . now price = 0.9 x ; number of mangoes = n + 12 . total amount = 0.9 x * ( n + 12 ) = 360 . nx = 0.9 nx + 10.8 x = > 0.1 nx = 10.8 x = > n = 108 = > x = 360 / 108 = 3.33 original price of 110 mangoes = 110 * 3.33 = 367 . answer a"
gain
math_qa__Bf1BQo6YEgZLyRfN
there are two numbers . if 20 % of the first number is added to the second number , then the second number increases to its 5 - fourth . what is the ratio of the first number to the second number ? Choose the correct choice from the following answers A) 2 : 9 B) 3 : 8 C) 8 : 5 D) 5 : 4 E) 7 : 3
<gadget id="calculator">20 / 5</gadget> <output>4</output> <gadget id="calculator">5 / 4</gadget> <output>5/4 = around 1.25</output> <result>D</result>
D
1.25
there are two numbers . if 20 % of the first number is added to the second number , then the second number increases to its 5 - fourth . what is the ratio of the first number to the second number ?
{ "A": "2 : 9", "B": "3 : 8", "C": "8 : 5", "D": "5 : 4", "E": "7 : 3" }
divide(5, divide(20, 5))
divide(n0,n1)|divide(n1,#0)
let the two numbers be x and y . ( 2 / 10 ) * x + y = ( 5 / 4 ) * y ( 2 / 10 ) * x = ( 1 / 4 ) * y x / y = 10 / 8 = 5 / 4 the answer is d .
general
math_qa__UiPUy2Y2BlLblFsZ
A train is 560 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length? Pick: A) 56 seconds B) 18 seconds C) 40 seconds D) 19 seconds E) 45 seconds
<gadget id="calculator">560 + 140</gadget> <output>700</output> <gadget id="calculator">45 * 1_000</gadget> <output>45_000</output> <gadget id="calculator">45_000 / 3_600</gadget> <output>25/2 = around 12.5</output> <gadget id="calculator">700 / (25/2)</gadget> <output>56</output> <result>A</result>
A
56
A train is 560 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
{ "A": "56 seconds", "B": "18 seconds", "C": "40 seconds", "D": "19 seconds", "E": "45 seconds" }
divide(add(560, 140), divide(multiply(45, const_1000), const_3600))
add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)|
"speed = 45 km / hr = 45 * ( 5 / 18 ) m / sec = 25 / 2 m / sec total distance = 560 + 140 = 700 meter time = distance / speed = 700 * ( 2 / 25 ) = 56 seconds answer : a"
physics
math_qa__nCoO0IAcJ67tEfo9
The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1600 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units? Choose the most appropriate option. A) 140 B) 99 C) 88 D) 160 E) 12
<gadget id="calculator">1_600 ** (1/2)</gadget> <output>40</output> <gadget id="calculator">10 / 2</gadget> <output>5</output> <gadget id="calculator">40 / 5</gadget> <output>8</output> <gadget id="calculator">2 * 8</gadget> <output>16</output> <gadget id="calculator">10 * 16</gadget> <output>160</output> <result>D</result>
D
160
The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1600 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
{ "A": "140", "B": "99", "C": "88", "D": "160", "E": "12" }
multiply(10, multiply(const_2, divide(sqrt(1600), divide(10, const_2))))
divide(n1,const_2)|sqrt(n0)|divide(#1,#0)|multiply(#2,const_2)|multiply(n1,#3)|
"given that the area of the square = 1600 sq . units = > side of square = √ 1600 = 40 units the radius of the circle = side of the square = 40 units length of the rectangle = 2 / 5 * 40 = 16 units given that breadth = 10 units area of the rectangle = lb = 16 * 10 = 160 sq . units answer : d"
geometry
math_qa__TUlXOMZHJoyiFLv4
A man can row his boat with the stream at 10 km/h and against the stream in 6 km/h. The man's rate is? Select A) 2 kmph B) 7 kmph C) 98 kmph D) 6 kmph E) 4 kmph
<gadget id="calculator">10 - 6</gadget> <output>4</output> <gadget id="calculator">4 / 2</gadget> <output>2</output> <result>A</result>
A
2
A man can row his boat with the stream at 10 km/h and against the stream in 6 km/h. The man's rate is?
{ "A": "2 kmph", "B": "7 kmph", "C": "98 kmph", "D": "6 kmph", "E": "4 kmph" }
divide(subtract(10, 6), const_2)
subtract(n0,n1)|divide(#0,const_2)|
"ds = 10 us = 6 s = ? s = ( 10 - 6 ) / 2 = 2 kmph answer : a"
gain
math_qa__5jD7NTL3tsHV4cp2
If the product of 12 integers is negative, at most how many of the integers can be negative? Choose the correct choice from the following answers: A) 2 B) 3 C) 4 D) 5 E) 11
<gadget id="calculator">12 - 1</gadget> <output>11</output> <result>E</result>
E
11
If the product of 12 integers is negative, at most how many of the integers can be negative?
{ "A": "2", "B": "3", "C": "4", "D": "5", "E": "11" }
subtract(12, const_1)
subtract(n0,const_1)|
"the product of 12 integers is negative thus an odd number of integers need to be negative to have a negative product we are asked at most how many are required . so , the highest odd integer before 6 , i . e . 11 correct option : e"
general
math_qa__hO63901yMniMCrVQ
A number is said to be prime saturated if the product of all the different positive prime factors of d is less than the square root of d. What is the greatest two digit prime saturated integer ? Pick one A) 99 B) 98 C) 97 D) 96 E) 95
<gadget id="calculator">2 * 3</gadget> <output>6</output> <gadget id="calculator">100 - 10</gadget> <output>90</output> <gadget id="calculator">6 + 90</gadget> <output>96</output> <result>D</result>
D
96
A number is said to be prime saturated if the product of all the different positive prime factors of d is less than the square root of d. What is the greatest two digit prime saturated integer ?
{ "A": "99", "B": "98", "C": "97", "D": "96", "E": "95" }
add(multiply(const_2, const_3), subtract(const_100, const_10))
multiply(const_2,const_3)|subtract(const_100,const_10)|add(#0,#1)|
"clearly d a number is said to be prime saturated if the product of all the different positive prime factors of d is less than the square root of d . 96 has more number of smaller prime factor thats the clue ! ! = d"
other
math_qa__ANTJVhDIa0ZycvrH
The distance from Steve's house to work is 28 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work? Choose the correct choice. A) 5 . B) 10 . C) 14 . D) 15 . E) 20 .
<gadget id="calculator">28 / 2</gadget> <output>14</output> <gadget id="calculator">28 + 14</gadget> <output>42</output> <gadget id="calculator">42 / 6</gadget> <output>7</output> <gadget id="calculator">7 * 2</gadget> <output>14</output> <result>C</result>
C
14
The distance from Steve's house to work is 28 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work?
{ "A": "5 .", "B": "10 .", "C": "14 .", "D": "15 .", "E": "20 ." }
multiply(divide(add(28, divide(28, const_2)), 6), const_2)
divide(n0,const_2)|add(n0,#0)|divide(#1,n1)|multiply(#2,const_2)|
"time is in the ratio 2 : 1 : : to : fro office therefore , 2 x + 1 x = 6 hrs time take to come back - 2 hrs , distance travelled - 28 km = > speed = 14 kmph c"
physics
math_qa__cb7pcWQcJGVhXBbO
There are 20 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played? Select: A) 10 B) 30 C) 190 D) 60 E) 90
<gadget id="calculator">20 - 1</gadget> <output>19</output> <gadget id="calculator">20 * 19</gadget> <output>380</output> <gadget id="calculator">380 / 2</gadget> <output>190</output> <result>C</result>
C
190
There are 20 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?
{ "A": "10", "B": "30", "C": "190", "D": "60", "E": "90" }
divide(multiply(20, subtract(20, const_1)), const_2)
subtract(n0,const_1)|multiply(n0,#0)|divide(#1,const_2)|
"20 players are there . two players play one game with one another . so 20 c 2 = 20 * 19 / 2 = 190 so option c is correct"
general
math_qa__28dSMgApqRiILvLN
The sum of four consecutive even numbers is 36. Find the sum of the squares of these numbers? Choose the correct option A) 296 B) 252 C) 344 D) 388 E) none of these
<gadget id="calculator">36 - 10</gadget> <output>26</output> <gadget id="calculator">26 - 2</gadget> <output>24</output> <gadget id="calculator">24 / 4</gadget> <output>6</output> <gadget id="calculator">6 + 2</gadget> <output>8</output> <gadget id="calculator">8 + 2</gadget> <output>10</output> <gadget id="calculator">10 ** 2</gadget> <output>100</output> <gadget id="calculator">10 + 2</gadget> <output>12</output> <gadget id="calculator">12 ** 2</gadget> <output>144</output> <gadget id="calculator">100 + 144</gadget> <output>244</output> <gadget id="calculator">6 ** 2</gadget> <output>36</output> <gadget id="calculator">8 ** 2</gadget> <output>64</output> <gadget id="calculator">36 + 64</gadget> <output>100</output> <gadget id="calculator">244 + 100</gadget> <output>344</output> <result>C</result>
C
344
The sum of four consecutive even numbers is 36. Find the sum of the squares of these numbers?
{ "A": "296", "B": "252", "C": "344", "D": "388", "E": "none of these" }
add(add(power(add(add(divide(subtract(subtract(36, const_10), const_2), const_4), const_2), const_2), const_2), power(add(add(add(divide(subtract(subtract(36, const_10), const_2), const_4), const_2), const_2), const_2), const_2)), add(power(divide(subtract(subtract(36, const_10), const_2), const_4), const_2), power(add(divide(subtract(subtract(36, const_10), const_2), const_4), const_2), const_2)))
subtract(n0,const_10)|subtract(#0,const_2)|divide(#1,const_4)|add(#2,const_2)|power(#2,const_2)|add(#3,const_2)|power(#3,const_2)|add(#5,const_2)|add(#4,#6)|power(#5,const_2)|power(#7,const_2)|add(#9,#10)|add(#11,#8)
let the four numbers be x , x + 2 , x + 4 and x + 6 . = > x + x + 2 + x + 4 + x + 6 = 36 = > 4 x + 12 = 36 = > x = 6 the numbers are 6 , 8 , 10 and 12 . sum of their squares = 62 + 82 + 102 + 122 = 36 + 64 + 100 + 144 = 344 . answer : c
physics
math_qa__sIDVko6FEBE8aRkq
P is 40% more efficient than Q. P can complete a work in 24 days. If P and Q work together, how many days will it take to complete the same work? Pick one: A) 8 B) 9 C) 11 D) 14 E) 15
<gadget id="calculator">40 / 100</gadget> <output>2/5 = around 0.4</output> <gadget id="calculator">(2/5) + 1</gadget> <output>7/5 = around 1.4</output> <gadget id="calculator">(7/5) * 24</gadget> <output>168/5 = around 33.6</output> <gadget id="calculator">(7/5) + 1</gadget> <output>12/5 = around 2.4</output> <gadget id="calculator">(168/5) / (12/5)</gadget> <output>14</output> <result>D</result>
D
14
P is 40% more efficient than Q. P can complete a work in 24 days. If P and Q work together, how many days will it take to complete the same work?
{ "A": "8", "B": "9", "C": "11", "D": "14", "E": "15" }
divide(multiply(add(divide(40, const_100), const_1), 24), add(add(divide(40, const_100), const_1), const_1))
divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(n1,#1)|divide(#3,#2)|
"the work done by p in 1 day = 1 / 24 let work done by q in 1 day = q q × ( 140 / 100 ) = 1 / 24 q = 100 / ( 24 × 140 ) = 10 / ( 24 × 14 ) the work done by p and q in 1 day = 1 / 24 + 10 / ( 24 × 14 ) = 24 / ( 24 × 14 ) = 1 / 14 p and q together can do the work in 14 days . the answer is d ."
physics
math_qa__eDQnEeNMeR3f22Ue
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is: Select: A) 50 km B) 56 km C) 70 km D) 80 km E) 46 km
<gadget id="calculator">14 - 10</gadget> <output>4</output> <gadget id="calculator">20 / 4</gadget> <output>5</output> <gadget id="calculator">10 * 5</gadget> <output>50</output> <result>A</result>
A
50
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
{ "A": "50 km", "B": "56 km", "C": "70 km", "D": "80 km", "E": "46 km" }
multiply(10, divide(20, subtract(14, 10)))
subtract(n0,n1)|divide(n2,#0)|multiply(n1,#1)|
"let the actual distance travelled be x km . then , x / 10 = ( x + 20 ) / 14 14 x = 10 x + 200 4 x = 200 x = 50 km . answer : a"
general
math_qa__QrAVqT0RJHXXFe5l
The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/98 of the area of the field. What is the length of the field? Pick: A) 73 B) 32 C) 34 D) 43 E) 112
<gadget id="calculator">8 ** 2</gadget> <output>64</output> <gadget id="calculator">64 * 98</gadget> <output>6_272</output> <gadget id="calculator">1 / 2</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">6_272 / (1/2)</gadget> <output>12_544</output> <gadget id="calculator">12_544 ** (1/2)</gadget> <output>112</output> <result>E</result>
E
112
The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/98 of the area of the field. What is the length of the field?
{ "A": "73", "B": "32", "C": "34", "D": "43", "E": "112" }
sqrt(divide(multiply(square_area(8), 98), inverse(const_2)))
inverse(const_2)|square_area(n0)|multiply(n2,#1)|divide(#2,#0)|sqrt(#3)|
"explanation : a / 98 = 8 * 8 = > a = 8 * 8 * 98 x * 2 x = 8 * 8 * 98 x = 56 = > 2 x = 112 answer : option e"
geometry
math_qa__FH49A4OUCHqbxqDE
There are 50 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played? Choose the correct answer. A) 1000 B) 3000 C) 1225 D) 6000 E) 9000
<gadget id="calculator">50 - 1</gadget> <output>49</output> <gadget id="calculator">50 * 49</gadget> <output>2_450</output> <gadget id="calculator">2_450 / 2</gadget> <output>1_225</output> <result>C</result>
C
1,225
There are 50 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?
{ "A": "1000", "B": "3000", "C": "1225", "D": "6000", "E": "9000" }
divide(multiply(50, subtract(50, const_1)), const_2)
subtract(n0,const_1)|multiply(n0,#0)|divide(#1,const_2)|
"50 players are there . two players play one game with one another . so 50 c 2 = 50 * 49 / 2 = 1225 so option c is correct"
general
math_qa__dip4yIqvom6Wz7vy
An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 1/4 %, then the amount invested at 11% was? Options: A) 12500 B) 37500 C) 29977 D) 26777 E) 19871
<gadget id="calculator">1 / 4</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">9 + (1/4)</gadget> <output>37/4 = around 9.25</output> <gadget id="calculator">(37/4) / 100</gadget> <output>37/400 = around 0.0925</output> <gadget id="calculator">100_000 * (37/400)</gadget> <output>9_250</output> <gadget id="calculator">9 / 100</gadget> <output>9/100 = around 0.09</output> <gadget id="calculator">100_000 * (9/100)</gadget> <output>9_000</output> <gadget id="calculator">9_250 - 9_000</gadget> <output>250</output> <gadget id="calculator">11 / 100</gadget> <output>11/100 = around 0.11</output> <gadget id="calculator">(11/100) - (9/100)</gadget> <output>1/50 = around 0.02</output> <gadget id="calculator">250 / (1/50)</gadget> <output>12_500</output> <result>A</result>
A
12,500
An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 1/4 %, then the amount invested at 11% was?
{ "A": "12500", "B": "37500", "C": "29977", "D": "26777", "E": "19871" }
divide(subtract(multiply(100000, divide(add(9, divide(1, 4)), const_100)), multiply(100000, divide(9, const_100))), subtract(divide(11, const_100), divide(9, const_100)))
divide(n4,n5)|divide(n1,const_100)|divide(n2,const_100)|add(n1,#0)|multiply(n0,#1)|subtract(#2,#1)|divide(#3,const_100)|multiply(n0,#6)|subtract(#7,#4)|divide(#8,#5)|
"let the sum invested at 9 % be rs . x and that invested at 11 % be rs . ( 100000 - x ) . then , ( x * 9 * 1 ) / 100 + [ ( 100000 - x ) * 11 * 1 ] / 100 = ( 100000 * 37 / 4 * 1 / 100 ) ( 9 x + 1100000 - 11 x ) = 37000 / 4 = 925000 x = 87500 sum invested at 9 % = rs . 87500 sum invested at 11 % = rs . ( 100000 - 87500 ) = rs . 12500 . answer : a"
gain
math_qa__fM6DadJedFkrVqYa
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed Y of the train. Choose the correct answer. A) 45 B) 33 C) 48 D) 55 E) 61
<gadget id="calculator">24 * 4</gadget> <output>96</output> <gadget id="calculator">96 / 3</gadget> <output>32</output> <gadget id="calculator">32 - 24</gadget> <output>8</output> <gadget id="calculator">35 - 25</gadget> <output>10</output> <gadget id="calculator">10 + 50</gadget> <output>60</output> <gadget id="calculator">60 / 10</gadget> <output>6</output> <gadget id="calculator">8 * 6</gadget> <output>48</output> <result>C</result>
C
48
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed Y of the train.
{ "A": "45", "B": "33", "C": "48", "D": "55", "E": "61" }
multiply(subtract(divide(multiply(24, 4), 3), 24), divide(add(subtract(35, 25), 50), subtract(35, 25)))
multiply(n2,n4)|subtract(n3,n5)|add(n0,#1)|divide(#0,n1)|divide(#2,#1)|subtract(#3,n4)|multiply(#4,#5)|
"let y be the balance distance to be covered and x be the former speed . a train after traveling for 50 km meets with an accident and then proceeds at 3 / 4 of its former speed and arrives at its destination 35 minutes late so , y / ( 3 x / 4 ) - y / x = 35 / 60 4 y / 3 x - y / x = 7 / 12 y / x ( 4 / 3 - 1 ) = 7 / 12 y / x * 1 / 3 = 7 / 12 y / x = 7 / 4 4 y - 7 x = 0 . . . . . . . . 1 had the accident occurred 24 km farther , it would have reached the destination only 25 minutes late so , ( y - 24 ) / ( 3 x / 4 ) - ( y - 24 ) / x = 25 / 60 4 ( y - 24 ) / 3 x - ( y - 24 ) / x = 5 / 12 ( y - 24 ) / x ( 4 / 3 - 1 ) = 5 / 12 ( y - 24 ) / x * 1 / 3 = 5 / 12 ( y - 24 ) * 12 = 3 x * 5 ( y - 24 ) * 4 = 5 x 4 y - 5 x = 96 . . . . . . . 2 eq 2 - eq 1 2 x = 96 x = 48 = y ans = c"
physics
math_qa__u9w6uyHvvNCJsLL4
A and B can do a piece of work in 10 days, B and C in 5 days, C and A in 15 days. How long will C take to do it? Choose the correct option: A) 77 days B) 55 days C) 12 days D) 33 days E) 11 days
<gadget id="calculator">10 * 3</gadget> <output>30</output> <gadget id="calculator">30 / 15</gadget> <output>2</output> <gadget id="calculator">30 / 10</gadget> <output>3</output> <gadget id="calculator">30 / 5</gadget> <output>6</output> <gadget id="calculator">3 + 6</gadget> <output>9</output> <gadget id="calculator">2 + 9</gadget> <output>11</output> <gadget id="calculator">11 / 2</gadget> <output>11/2 = around 5.5</output> <gadget id="calculator">(11/2) - 3</gadget> <output>5/2 = around 2.5</output> <gadget id="calculator">30 / (5/2)</gadget> <output>12</output> <result>C</result>
C
12
A and B can do a piece of work in 10 days, B and C in 5 days, C and A in 15 days. How long will C take to do it?
{ "A": "77 days", "B": "55 days", "C": "12 days", "D": "33 days", "E": "11 days" }
divide(multiply(10, const_3), subtract(divide(add(divide(multiply(10, const_3), 15), add(divide(multiply(10, const_3), 10), divide(multiply(10, const_3), 5))), const_2), divide(multiply(10, const_3), 10)))
multiply(n0,const_3)|divide(#0,n0)|divide(#0,n1)|divide(#0,n2)|add(#1,#2)|add(#4,#3)|divide(#5,const_2)|subtract(#6,#1)|divide(#0,#7)
2 c = 1 / 5 + 1 / 15 – 1 / 10 = 1 / 6 c = 1 / 12 = > 12 days answer : c
physics
math_qa__eD1F5JD7044yzPSZ
A rectangular courtyard 3.78 meters long 5.25 meters wide is to be paved exactly with square tiles, all of the same size. what is the largest size of the tile which could be used for the purpose? Choose the most appropriate option A) 14 cms B) 21 cms C) 42 cms D) none of these E) 56 cms
<gadget id="calculator">3.78 * 100</gadget> <output>378</output> <gadget id="calculator">378 / 2</gadget> <output>189</output> <gadget id="calculator">189 / 3</gadget> <output>63</output> <gadget id="calculator">63 / 3</gadget> <output>21</output> <gadget id="calculator">21 / 3</gadget> <output>7</output> <gadget id="calculator">21 / 7</gadget> <output>3</output> <gadget id="calculator">3 * 7</gadget> <output>21</output> <result>B</result>
B
21
A rectangular courtyard 3.78 meters long 5.25 meters wide is to be paved exactly with square tiles, all of the same size. what is the largest size of the tile which could be used for the purpose?
{ "A": "14 cms", "B": "21 cms", "C": "42 cms", "D": "none of these", "E": "56 cms" }
multiply(divide(divide(divide(divide(multiply(3.78, const_100), const_2), const_3), const_3), divide(divide(divide(divide(multiply(3.78, const_100), const_2), const_3), const_3), const_3)), divide(divide(divide(divide(multiply(3.78, const_100), const_2), const_3), const_3), const_3))
multiply(n0,const_100)|divide(#0,const_2)|divide(#1,const_3)|divide(#2,const_3)|divide(#3,const_3)|divide(#3,#4)|multiply(#5,#4)
explanation : 3.78 meters = 378 cm = 2 × 3 × 3 × 3 × 7 5.25 meters = 525 cm = 5 × 5 × 3 × 7 hence common factors are 3 and 7 hence lcm = 3 × 7 = 21 hence largest size of square tiles that can be paved exactly with square tiles is 21 cm . answer : b
geometry
math_qa__WD09DNs5Wy1qHHsL
If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number E of integers that can be negative? Choose the correct answer: A) 2 B) 3 C) 4 D) 5 E) 6
<gadget id="calculator">10 / 2</gadget> <output>5</output> <gadget id="calculator">5 + 0</gadget> <output>5</output> <result>D</result>
D
5
If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number E of integers that can be negative?
{ "A": "2", "B": "3", "C": "4", "D": "5", "E": "6" }
add(divide(const_10, const_2), 0)
divide(const_10,const_2)|add(n0,#0)|
"minimuum should be 1 maximum should be 4 : 1 out of a or b to make the multiplication negative 3 out of c , d , e or f to make the multiplication negative . negative + negative < 0 answer : c maximum will be 5 . . you dont require both the multiplicatin to be negative for entire equation to be negative . . . any one a or b can be negative to make ab negative and it can still be more ( away from 0 ) than the multiplication of 4 other - ve numbers . . . actually by writing minimum required as 1 out of 6 , you are actually meaning 5 out of 6 also possible as you will see e = 5 or 1 will give you same equation . . ans d"
general
math_qa__IPIz9hXe3MHZv7FB
On a certain road, 10% of the motorists exceed the posted speed limit and receive speeding tickets, but 40% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit? Choices A) 10.5 % B) 12.5 % C) 16.7 % D) 25 % E) 30 %
<gadget id="calculator">100 - 40</gadget> <output>60</output> <gadget id="calculator">10 / 60</gadget> <output>1/6 = around 0.166667</output> <gadget id="calculator">(1/6) * 100</gadget> <output>50/3 = around 16.666667</output> <result>C</result>
C
16.7
On a certain road, 10% of the motorists exceed the posted speed limit and receive speeding tickets, but 40% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit?
{ "A": "10.5 %", "B": "12.5 %", "C": "16.7 %", "D": "25 %", "E": "30 %" }
multiply(divide(10, subtract(const_100, 40)), const_100)
subtract(const_100,n1)|divide(n0,#0)|multiply(#1,const_100)|
"suppose there are x motorists . 10 % of them exceeded the speed limit and received the ticket , i . e . x / 10 . again , suppose total no . of motorists who exceeded the speed limit are y . 40 % of y exceeded the speed limit but did n ' t received the ticket , i . e . 2 y / 5 . it means 3 y / 5 received the ticket . hence , 3 y / 5 = x / 10 or y / x = 1 / 6 or y / x * 100 = 1 / 6 * 100 = 16.7 % c"
gain
math_qa__UPxFuShXFSt04Fvl
There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 54% Choose the most appropriate option. A) 18.75 B) 19.75 C) 20.75 D) 33 E) 22.75
<gadget id="calculator">100 / 54</gadget> <output>50/27 = around 1.851852</output> <gadget id="calculator">60 * 84</gadget> <output>5_040</output> <gadget id="calculator">5_040 / 100</gadget> <output>252/5 = around 50.4</output> <gadget id="calculator">(50/27) * (252/5)</gadget> <output>280/3 = around 93.333333</output> <gadget id="calculator">(280/3) - 60</gadget> <output>100/3 = around 33.333333</output> <result>D</result>
D
33
There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 54%
{ "A": "18.75", "B": "19.75", "C": "20.75", "D": "33", "E": "22.75" }
subtract(multiply(divide(const_100, 54), divide(multiply(60, 84), const_100)), 60)
divide(const_100,n2)|multiply(n0,n1)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,n0)
60 * 84 / 100 = 50.40 lit milk that is 9.60 lit water let x lit water will be added then ( 60 + x ) * 54 / 100 = 50.40 so x = 33.33 answer : d
gain
math_qa__6xnyagv20cLBHLEm
A certain bus driver is paid a regular rate of $14 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $998 in total compensation, how many total hours did he work that week? Choose the correct choice from the following answers: A) 54 B) 51 C) 58 D) 55 E) 52
<gadget id="calculator">14 * 40</gadget> <output>560</output> <gadget id="calculator">998 - 560</gadget> <output>438</output> <gadget id="calculator">100 + 75</gadget> <output>175</output> <gadget id="calculator">14 * 175</gadget> <output>2_450</output> <gadget id="calculator">2_450 / 100</gadget> <output>49/2 = around 24.5</output> <gadget id="calculator">438 / (49/2)</gadget> <output>876/49 = around 17.877551</output> <gadget id="calculator">40 + (876/49)</gadget> <output>2_836/49 = around 57.877551</output> <result>C</result>
C
58
A certain bus driver is paid a regular rate of $14 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $998 in total compensation, how many total hours did he work that week?
{ "A": "54", "B": "51", "C": "58", "D": "55", "E": "52" }
add(40, divide(subtract(998, multiply(14, 40)), divide(multiply(14, add(const_100, 75)), const_100)))
add(n3,const_100)|multiply(n0,n1)|multiply(n0,#0)|subtract(n4,#1)|divide(#2,const_100)|divide(#3,#4)|add(n1,#5)|
"for 40 hrs = 40 * 14 = 560 excess = 998 - 560 = 438 for extra hours = . 75 ( 14 ) = 10.5 + 14 = 24.5 number of extra hrs = 438 / 24.5 = 17.8 = 18 approx . total hrs = 40 + 18 = 58 answer c"
general
math_qa__D0PKoUG4Kf4AAKVs
A certain debt will be paid in 40 installments from January 1 to December 31 of a certain year. Each of the first 20 payments is to be $410; each of the remaining payments is to be $65 more than each of the first 20 payments. What is the average (arithmetic mean) payment that will be made on the debt for the year? Answers: A) 442.5 B) 450 C) 465 D) 468 E) 475
<gadget id="calculator">20 * 410</gadget> <output>8_200</output> <gadget id="calculator">410 + 65</gadget> <output>475</output> <gadget id="calculator">40 - 20</gadget> <output>20</output> <gadget id="calculator">475 * 20</gadget> <output>9_500</output> <gadget id="calculator">8_200 + 9_500</gadget> <output>17_700</output> <gadget id="calculator">17_700 / 40</gadget> <output>885/2 = around 442.5</output> <result>A</result>
A
442.5
A certain debt will be paid in 40 installments from January 1 to December 31 of a certain year. Each of the first 20 payments is to be $410; each of the remaining payments is to be $65 more than each of the first 20 payments. What is the average (arithmetic mean) payment that will be made on the debt for the year?
{ "A": "442.5", "B": "450", "C": "465", "D": "468", "E": "475" }
divide(add(multiply(20, 410), multiply(add(410, 65), subtract(40, 20))), 40)
add(n4,n5)|multiply(n3,n4)|subtract(n0,n3)|multiply(#0,#2)|add(#1,#3)|divide(#4,n0)|
"total number of installments = 40 payment per installment for the first 20 installments = 410 payment per installment for the remaining 20 installments = 410 + 65 = 475 average = ( 20 * 410 + 20 * 475 ) / 40 = 442.50 answer a"
general
math_qa__nbSxojheUjXYNDNS
20 men do a work in 20days. How many men are needed to finish the work in 4days? Options: A) 50 B) 20 C) 30 D) 100 E) 15
<gadget id="calculator">20 * 20</gadget> <output>400</output> <gadget id="calculator">400 / 4</gadget> <output>100</output> <result>D</result>
D
100
20 men do a work in 20days. How many men are needed to finish the work in 4days?
{ "A": "50", "B": "20", "C": "30", "D": "100", "E": "15" }
divide(multiply(20, 20), 4)
multiply(n0,n1)|divide(#0,n2)|
"men required to finish the work in 4 days = 20 * 20 / 4 = 100 answer is d"
physics
math_qa__a5I7qqLuICXT9lxG
The cost of 20 articles is equal to selling price of 10. Find the gain or loss percent? Choose the correct choice from the following. A) 50 % B) 100 % C) 25 % D) 15 % E) 60 %
<gadget id="calculator">10 / 10</gadget> <output>1</output> <gadget id="calculator">1 * 100</gadget> <output>100</output> <result>B</result>
B
100
The cost of 20 articles is equal to selling price of 10. Find the gain or loss percent?
{ "A": "50 %", "B": "100 %", "C": "25 %", "D": "15 %", "E": "60 %" }
multiply(divide(10, 10), const_100)
divide(n1,n1)|multiply(#0,const_100)
c . p . of each article be $ 1 c . p . of 10 articles = 10 gain % = 10 / 10 * 100 = 100 % answer is b
gain
math_qa__rI0pjH8pJ77Y7L0w
a man owns 2/3 of market reserch beauro buzness,and sells 3/4 of his shares for 6500rs,what is the value of buzness? Options A) 150000 B) 16000 C) 15000 D) 190000 E) 13000
<gadget id="calculator">2 / 3</gadget> <output>2/3 = around 0.666667</output> <gadget id="calculator">3 / 4</gadget> <output>3/4 = around 0.75</output> <gadget id="calculator">(2/3) * (3/4)</gadget> <output>1/2 = around 0.5</output> <gadget id="calculator">6_500 / (1/2)</gadget> <output>13_000</output> <result>E</result>
E
13,000
a man owns 2/3 of market reserch beauro buzness,and sells 3/4 of his shares for 6500rs,what is the value of buzness?
{ "A": "150000", "B": "16000", "C": "15000", "D": "190000", "E": "13000" }
divide(6500, multiply(divide(2, 3), divide(3, 4)))
divide(n0,n1)|divide(n1,n3)|multiply(#0,#1)|divide(n4,#2)|
"if value of business = x total sell ( 2 x / 3 ) ( 3 / 4 ) = 6500 - > x = 13000 answer : e"
general
math_qa__4aDHN9jCVsV5uG4m
Find the 25% of Rs. 200. Choose the correct choice from the following options: A) rs . 50 B) rs . 70 C) rs . 100 D) rs . 80 E) rs . 60
<gadget id="calculator">25 / 100</gadget> <output>1/4 = around 0.25</output> <gadget id="calculator">200 * (1/4)</gadget> <output>50</output> <result>A</result>
A
50
Find the 25% of Rs. 200.
{ "A": "rs . 50", "B": "rs . 70", "C": "rs . 100", "D": "rs . 80", "E": "rs . 60" }
multiply(200, divide(25, const_100))
divide(n0,const_100)|multiply(n1,#0)
explanation : 25 % of 200 = > 25 / 100 * 200 = rs . 50 answer : a
gain
math_qa__lj52Apk1zFtAoUfq
A bowl of fruit contains 14 apples and 25 oranges. How many oranges must be removed so that 70% of the pieces of fruit in the bowl will be apples? Choose the correct choice. A) 3 B) 6 C) 14 D) 17 E) 19
<gadget id="calculator">14 + 25</gadget> <output>39</output> <gadget id="calculator">70 / 100</gadget> <output>7/10 = around 0.7</output> <gadget id="calculator">39 * (7/10)</gadget> <output>273/10 = around 27.3</output> <gadget id="calculator">(273/10) - 14</gadget> <output>133/10 = around 13.3</output> <gadget id="calculator">(133/10) / (7/10)</gadget> <output>19</output> <result>E</result>
E
19
A bowl of fruit contains 14 apples and 25 oranges. How many oranges must be removed so that 70% of the pieces of fruit in the bowl will be apples?
{ "A": "3", "B": "6", "C": "14", "D": "17", "E": "19" }
divide(subtract(multiply(add(14, 25), divide(70, const_100)), 14), divide(70, const_100))
add(n0,n1)|divide(n2,const_100)|multiply(#0,#1)|subtract(#2,n0)|divide(#3,#1)|
"number of apples = 14 number of oranges = 25 let number of oranges that must be removed so that 70 % of pieces of fruit in bowl will be apples = x total number of fruits after x oranges are removed = 14 + ( 25 - x ) = 39 - x 14 / ( 39 - x ) = 7 / 10 = > 20 = 39 - x = > x = 19 answer e"
gain