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stringlengths 7
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math_qa__0anXn5ZMFAe2258n | When 242 is divided by a certain divisor the remainder obtained is 11. When 698 is divided by the same divisor the remainder obtained is 18. However, when the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 9. What is the value of the divisor? Answers:
A) 11
B) 17
C) 13
D) 20
E) none of these | <gadget id="calculator">11 + 18</gadget>
<output>29</output>
<gadget id="calculator">29 - 9</gadget>
<output>20</output>
<result>D</result> | D | 20 | When 242 is divided by a certain divisor the remainder obtained is 11. When 698 is divided by the same divisor the remainder obtained is 18. However, when the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 9. What is the value of the divisor? | {
"A": "11",
"B": "17",
"C": "13",
"D": "20",
"E": "none of these"
} | subtract(add(11, 18), 9) | add(n1,n3)|subtract(#0,n6)| | "let that divisor be x since remainder is 11 or 18 it means divisor is greater than 18 . now 242 - 11 = 231 = kx ( k is an integer and 234 is divisble by x ) similarly 698 - 18 = 680 = lx ( l is an integer and 689 is divisible by x ) adding both 698 and 242 = ( 231 + 680 ) + 11 + 18 = x ( k + l ) + 29 when we divide this number by x then remainder will be equal to remainder of ( 29 divided by x ) = 9 hence x = 29 - 9 = 20 hence d" | general |
math_qa__WLFMqJYqUpdSAxIL | Anil brought a scooter for a certain sum of money. He spent 10% of the cost on repairs and sold the scooter for a profit of Rs. 1100. How much did he spend on repairs if he made a profit of 20%? Choices:
A) 220 B) 420 C) 250 D) 700 E) 500 | <gadget id="calculator">20 / 10</gadget>
<output>2</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">1_100 * 5</gadget>
<output>5_500</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">5_500 / (11/10)</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 * 10</gadget>
<output>50_000</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">50_000 / 100</gadget>
<output>500</output>
<result>E</result> | E | 500 | Anil brought a scooter for a certain sum of money. He spent 10% of the cost on repairs and sold the scooter for a profit of Rs. 1100. How much did he spend on repairs if he made a profit of 20%? | {
"A": "220",
"B": "420",
"C": "250",
"D": "700",
"E": "500"
} | divide(multiply(divide(multiply(1100, divide(10, divide(20, 10))), add(const_1, divide(const_1, 10))), 10), multiply(10, 10)) | divide(n2,n0)|divide(const_1,n0)|multiply(n0,n0)|add(#1,const_1)|divide(n0,#0)|multiply(n1,#4)|divide(#5,#3)|multiply(n0,#6)|divide(#7,#2) | e c . p . be rs . x . then , 20 % of x = 1100 20 / 100 * x = 1100 = > x = 5500 c . p . = rs . 5500 , expenditure on repairs = 10 % actual price = rs . ( 100 * 5500 ) / 110 = rs . 5000 expenditures on repairs = ( 5500 - 5000 ) = rs . 500 . | gain |
math_qa__DA8mSTig5mPi1423 | If 7 persons can do 7 times of a particular work in 7 days, then, 9 persons can do 9 times of that work in
? Choose the most appropriate option: A) 3 days B) 8 days C) 9 days D) 11 days E) 7 days | <gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>
<gadget id="calculator">49 / (7/9)</gadget>
<output>63</output>
<gadget id="calculator">63 / 9</gadget>
<output>7</output>
<result>E</result> | E | 7 | If 7 persons can do 7 times of a particular work in 7 days, then, 9 persons can do 9 times of that work in
? | {
"A": "3 days",
"B": "8 days",
"C": "9 days",
"D": "11 days",
"E": "7 days"
} | divide(divide(multiply(7, 7), divide(7, 9)), 9) | divide(n0,n3)|multiply(n0,n0)|divide(#1,#0)|divide(#2,n3) | that is , 1 person can do one time of the work in 7 days . therefore , 9 persons can do 9 times work in the same 7 days itself . option ' e ' | physics |
math_qa__hAas8eQ1tVu3sWys | The cost per pound of green tea and coffee were the same in June. In July, the price of coffee shot up by 100% and that of green tea dropped by 90%. If in July, a mixture containing equal quantities of green tea and coffee costs $3.15 for 3lbs, how much did a pound of green tea cost in July? Pick one:
A) $ 4
B) $ 0.1
C) $ 1
D) $ 3
E) $ 1.65 | <gadget id="calculator">100 + 100</gadget>
<output>200</output>
<gadget id="calculator">200 / 100</gadget>
<output>2</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">2 * (3/2)</gadget>
<output>3</output>
<gadget id="calculator">100 - 90</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(3/2) * (1/10)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">3 + (3/20)</gadget>
<output>63/20 = around 3.15</output>
<gadget id="calculator">(63/20) / 3.15</gadget>
<output>1</output>
<gadget id="calculator">1 * (1/10)</gadget>
<output>1/10 = around 0.1</output>
<result>B</result> | B | 0.1 | The cost per pound of green tea and coffee were the same in June. In July, the price of coffee shot up by 100% and that of green tea dropped by 90%. If in July, a mixture containing equal quantities of green tea and coffee costs $3.15 for 3lbs, how much did a pound of green tea cost in July? | {
"A": "$ 4",
"B": "$ 0.1",
"C": "$ 1",
"D": "$ 3",
"E": "$ 1.65"
} | multiply(divide(add(multiply(divide(add(100, 100), 100), divide(3, const_2)), multiply(divide(3, const_2), divide(subtract(100, 90), 100))), 3.15), divide(subtract(100, 90), 100)) | add(n0,n0)|divide(n3,const_2)|subtract(n0,n1)|divide(#0,n0)|divide(#2,n0)|multiply(#3,#1)|multiply(#1,#4)|add(#5,#6)|divide(#7,n2)|multiply(#8,#4)| | "lets assume price of coffee in june = 100 x price of green tea in june = 100 x price of coffee in july = 200 x ( because of 100 % increase in price ) price of green tea in july = 10 x ( because of 90 % decrease in price ) price of 1.5 pound of coffee 1.5 pound of green tea in july will be = 300 x + 15 x = 315 x as per question 315 x = 3.15 $ x = 0.01 s so the price of green tea in july = 10 x = 10 x 0.01 = 0.1 $ / pound answer b" | general |
math_qa__Z9SHmslbWCvaTy0G | What is 0.01 percent of 12,356? Choose the correct answer:
A) 0.12356 B) 1.2356 C) 12.356 D) 0.012356 E) 0.0012356 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 * 100</gadget>
<output>1_200</output>
<gadget id="calculator">10 * 1_200</gadget>
<output>12_000</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">35 * 10</gadget>
<output>350</output>
<gadget id="calculator">12_000 + 350</gadget>
<output>12_350</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">12_350 + 6</gadget>
<output>12_356</output>
<gadget id="calculator">0.01 * 12_356</gadget>
<output>123.56</output>
<gadget id="calculator">123.56 / 100</gadget>
<output>1.2356</output>
<result>B</result> | B | 1.2356 | What is 0.01 percent of 12,356? | {
"A": "0.12356",
"B": "1.2356",
"C": "12.356",
"D": "0.012356",
"E": "0.0012356"
} | divide(multiply(0.01, add(add(multiply(multiply(add(const_3, const_2), const_2), multiply(multiply(const_3, const_4), const_100)), multiply(multiply(add(const_3, const_4), add(const_3, const_2)), multiply(add(const_3, const_2), const_2))), add(const_3, const_3))), const_100) | add(const_2,const_3)|add(const_3,const_4)|add(const_3,const_3)|multiply(const_3,const_4)|multiply(#0,const_2)|multiply(#3,const_100)|multiply(#1,#0)|multiply(#4,#5)|multiply(#6,#4)|add(#7,#8)|add(#9,#2)|multiply(n0,#10)|divide(#11,const_100)| | "soln : - 0.01 % of 12,356 = 0 . 011000.01100 x 12,356 = 1100 ∗ 1001100 ∗ 100 x 12,356 = 12,356100 ∗ 10012,356100 ∗ 100 = 1.2356 answer : b" | gain |
math_qa__BUYk5QrTpBzP6HPR | A case of 12 rolls of paper towels sells for $9. The cost of one roll sold individually is $1.What is the percent E of savings per roll for the 12-roll package over the cost of 12 rolls purchased individually?
Choose the correct choice from the following options:
A) 9 % B) 11 % C) 15 % D) 25 % E) 90 % | <gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 100</gadget>
<output>75</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<result>D</result> | D | 25 | A case of 12 rolls of paper towels sells for $9. The cost of one roll sold individually is $1.What is the percent E of savings per roll for the 12-roll package over the cost of 12 rolls purchased individually? | {
"A": "9 %",
"B": "11 %",
"C": "15 %",
"D": "25 %",
"E": "90 %"
} | subtract(const_100, multiply(divide(9, 12), const_100)) | divide(n1,n0)|multiply(#0,const_100)|subtract(const_100,#1)| | "cost of 12 paper towels individually = 1 * 12 = 12 cost of a set of 12 paper towels = 9 cost of one roll = 9 / 12 = 3 / 4 = 0.75 savings per roll = 1 - . 75 = 0.25 % of savings is e = . 25 / 1 * 100 = 25 % d is the answer ." | general |
math_qa__iWYWo2VOaSb9xkjY | For what values of k will the pair of equations 3(3x + 4y) = 36 and kx + 12y = 30 does not have a unique solution?
Options:
A) 12
B) 9
C) 3
D) 7.5
E) 2.5 | <gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<result>B</result> | B | 9 | For what values of k will the pair of equations 3(3x + 4y) = 36 and kx + 12y = 30 does not have a unique solution? | {
"A": "12",
"B": "9",
"C": "3",
"D": "7.5",
"E": "2.5"
} | divide(multiply(12, 3), const_4.0) | multiply(n1,n4)|divide(#0,n2)| | "we have 2 equations 1 . 3 ( 3 x + 4 y ) = 36 - - > 3 x + 4 y = 12 - - > 9 x + 12 y = 36 2 . kx + 12 y = 30 substract 1 - 2 , we get ( 9 - k ) x = 6 i . e . x = 6 / ( 9 - k ) then , by looking at options , we get some value of x except for b . when we put k = 9 , x becomes 6 / 0 and hence answer is b" | general |
math_qa__V5S9yNg7BEfEoK60 | There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total R of the book?
Select.
A) 3003 B) 3027 C) 3024 D) 3021 E) 3018 | <gadget id="calculator">3_000 + 3</gadget>
<output>3_003</output>
<result>A</result> | A | 3,003 | There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total R of the book? | {
"A": "3003",
"B": "3027",
"C": "3024",
"D": "3021",
"E": "3018"
} | add(3000, 3) | add(n0,n5)| | "first , you have to find the common ratio for all 3 books . you have : p : c : b 3 : 2 - - > multiply by 2 ( gives you row 3 ) 4 : 6 6 : 4 : 3 hence : p : c : b : t ( total ) r 6 : 4 : 3 : 13 - - - - > this means , the total number must be a multiple of 13 . answer a is correct since 299 is divisible by 13 , hence is 2990 and so is 3003 ( 2990 + 13 ) ." | other |
math_qa__QVX36pcvrjLUh9Es | On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 5 cups of tea. Last week Mo drank a total of 36 cups of tea and hot chocolate together. If during that week Mo drank 14 more tea cups than hot chocolate cups, then how many rainy days were there last week?
Choose the correct choice from the following: A) 5 B) 3 C) 4 D) 2 E) 6 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">36 + 14</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 / 5</gadget>
<output>5</output>
<gadget id="calculator">7 - 5</gadget>
<output>2</output>
<result>D</result> | D | 2 | On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 5 cups of tea. Last week Mo drank a total of 36 cups of tea and hot chocolate together. If during that week Mo drank 14 more tea cups than hot chocolate cups, then how many rainy days were there last week? | {
"A": "5",
"B": "3",
"C": "4",
"D": "2",
"E": "6"
} | subtract(add(const_4, const_3), divide(divide(add(36, 14), const_2), 5)) | add(const_3,const_4)|add(n1,n2)|divide(#1,const_2)|divide(#2,n0)|subtract(#0,#3)| | "t = the number of cups of tea c = the number of cups of hot chocolate t + c = 36 t - c = 14 - > t = 25 . c = 11 . mo drinks 5 cups of tea a day then number of days that are not rainy = 25 / 5 = 5 so number of rainy days = 7 - 5 = 2 d is the answer ." | general |
math_qa__ULf7tMpFI9hh36yc | A car traveled 75% of the way from town A to town B at an average speed of 60 miles per hour. The car travels at an average speed of S miles per hour for the remaining part of the trip. The average speed for the entire trip was 40 miles per hour. What is S ?
Answers:
A) 10 B) 20 C) 25 D) 30 E) 37.5 | <gadget id="calculator">40 + 60</gadget>
<output>100</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">100 / 40</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">75 / 60</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/2) - (5/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">25 / (5/4)</gadget>
<output>20</output>
<result>B</result> | B | 20 | A car traveled 75% of the way from town A to town B at an average speed of 60 miles per hour. The car travels at an average speed of S miles per hour for the remaining part of the trip. The average speed for the entire trip was 40 miles per hour. What is S ? | {
"A": "10",
"B": "20",
"C": "25",
"D": "30",
"E": "37.5"
} | divide(subtract(add(40, 60), 75), subtract(divide(add(40, 60), 40), divide(75, 60))) | add(n1,n2)|divide(n0,n1)|divide(#0,n2)|subtract(#0,n0)|subtract(#2,#1)|divide(#3,#4) | total distance = 100 miles ( easier to work with % ) 75 % of the distance = 75 miles 25 % of the distance = 25 miles 1 st part of the trip → 75 / 60 = 1.25 2 nd part of the trip → 25 / s = t total trip → ( 75 + 25 ) / 40 = 1.25 + t » 100 / 40 = 1.25 + t » 2.5 = 1.25 + t » t = 1.25 back to 2 nd part of the trip formula : 25 / s = 1.25 » s = 20 ans b | physics |
math_qa__wWprFSEGO4Gqhr9T | The price of a jacket is reduced by 35%. During a special sale the price of the jacket is reduced another 10%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount? Choose the correct choice from the following
A) 70.9 B) 75 C) 48 D) 65 E) 67.5 | <gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">65 * (1/10)</gadget>
<output>13/2 = around 6.5</output>
<gadget id="calculator">65 - (13/2)</gadget>
<output>117/2 = around 58.5</output>
<gadget id="calculator">100 - (117/2)</gadget>
<output>83/2 = around 41.5</output>
<gadget id="calculator">(83/2) / (117/2)</gadget>
<output>83/117 = around 0.709402</output>
<gadget id="calculator">100 * (83/117)</gadget>
<output>8_300/117 = around 70.940171</output>
<result>A</result> | A | 70.9 | The price of a jacket is reduced by 35%. During a special sale the price of the jacket is reduced another 10%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount? | {
"A": "70.9",
"B": "75",
"C": "48",
"D": "65",
"E": "67.5"
} | multiply(const_100, divide(subtract(const_100, subtract(subtract(const_100, 35), multiply(subtract(const_100, 35), divide(10, const_100)))), subtract(subtract(const_100, 35), multiply(subtract(const_100, 35), divide(10, const_100))))) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|subtract(#1,#2)|subtract(const_100,#3)|divide(#4,#3)|multiply(#5,const_100)| | "1 ) let the price of jacket initially be $ 100 . 2 ) then it is decreased by 35 % , therefore bringing down the price to $ 65 . 3 ) again it is further discounted by 10 % , therefore bringing down the price to $ 58.5 4 ) now 58.5 has to be added byx % in order to equal the original price . 58.5 + ( x % ) 58.5 = 100 . solving this eq for x , we get x = 70.9 ans is a ." | gain |
math_qa__1a9mxkcXrlRab8O6 | A retailer bought a shirt at wholesale and marked it up 80% to its initial price of $27. By how many more dollars does he need to increase the price to achieve a 100% markup?
Choose the correct choice from the following options: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 + (4/5)</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">27 / (9/5)</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">30 - 27</gadget>
<output>3</output>
<result>C</result> | C | 3 | A retailer bought a shirt at wholesale and marked it up 80% to its initial price of $27. By how many more dollars does he need to increase the price to achieve a 100% markup? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(multiply(divide(27, add(const_1, divide(80, 100))), const_2), 27) | divide(n0,n2)|add(#0,const_1)|divide(n1,#1)|multiply(#2,const_2)|subtract(#3,n1)| | "let x be the wholesale price . then 1.8 x = 27 and x = 27 / 1.8 = 15 . to achieve a 100 % markup , the price needs to be $ 30 . the retailer needs to increase the price by $ 3 more . the answer is c ." | general |
math_qa__Q65jsGqCdYwwdMGN | A train is running with a speed of 60 kmph and its length is 110 metres. Calculate the time by which it will pass a man running opposite with speed of 6 kmph Choose one: A) 2 second B) 4 second C) 6 second D) 8 second E) 10 second | <gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">66 * (5/18)</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">110 / (55/3)</gadget>
<output>6</output>
<result>C</result> | C | 6 | A train is running with a speed of 60 kmph and its length is 110 metres. Calculate the time by which it will pass a man running opposite with speed of 6 kmph | {
"A": "2 second",
"B": "4 second",
"C": "6 second",
"D": "8 second",
"E": "10 second"
} | divide(110, multiply(add(60, 6), const_0_2778)) | add(n0,n2)|multiply(#0,const_0_2778)|divide(n1,#1) | explanation : from the given question , we will first calculate the speed of train relative to man , = > ( 60 + 6 ) = 66 km / hr ( we added 6 because man is running opposite ) convert it in metre / second = 66 ã — 5 / 18 = 55 / 3 m / sec time it will take to pass man = 110 ã — 3 / 55 = 6 seconds answer is c | physics |
math_qa__3VOZFWchSoDWt6Ah | the total of the ages of amar , akbar and anthony is 66 years . what was the total of their ages 4 years ago ? Select: A) 71 B) 44 C) 54 D) 16 E) 18 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">66 - 12</gadget>
<output>54</output>
<result>C</result> | C | 54 | the total of the ages of amar , akbar and anthony is 66 years . what was the total of their ages 4 years ago ? | {
"A": "71",
"B": "44",
"C": "54",
"D": "16",
"E": "18"
} | subtract(66, multiply(4, const_3)) | multiply(n1,const_3)|subtract(n0,#0) | explanation : required sum = ( 66 - 3 x 4 ) years = ( 66 - 12 ) years = 54 years . answer : c | general |
math_qa__kDj1mMPYLWmoLzLy | Kim finds a 3-meter tree branch and marks it off in thirds and fifths. She then breaks the branch along all the markings and removes one piece of every distinct length. What fraction of the original branch remains?
Select.
A) 2 / 5
B) 3 / 5
C) 8 / 15
D) 1 / 2
E) 7 / 5 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">3 / 15</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2 / 15</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(1/5) + (2/15)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/3) + (1/15)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<result>B</result> | B | 0.6 | Kim finds a 3-meter tree branch and marks it off in thirds and fifths. She then breaks the branch along all the markings and removes one piece of every distinct length. What fraction of the original branch remains? | {
"A": "2 / 5",
"B": "3 / 5",
"C": "8 / 15",
"D": "1 / 2",
"E": "7 / 5"
} | subtract(const_1, add(add(divide(const_3, multiply(add(const_2, const_3), 3)), divide(const_2, multiply(add(const_2, const_3), 3))), divide(const_1, multiply(add(const_2, const_3), 3)))) | add(const_2,const_3)|multiply(n0,#0)|divide(const_3,#1)|divide(const_2,#1)|divide(const_1,#1)|add(#2,#3)|add(#5,#4)|subtract(const_1,#6) | 3 pieces of 1 / 5 length and two piece each of 1 / 15 and 2 / 15 lengths . removing one piece each from pieces of each kind of lengths the all that will remain will be 2 pieces of 1 / 5 i . e 2 / 5 , 1 piece of 1 / 15 , and 1 piece of 2 / 15 which gives us 2 / 5 + 1 / 15 + 2 / 15 - - - - - > 3 / 5 answer is b | physics |
math_qa__xtOr0GCLwiz4Dg64 | A certain country is divided into 8 provinces. Each province consists entirely of Progressives and Traditionalists. If each province contains the same number of Traditionalists and the number of Traditionalists in any given province is 1/12 the total number of Progressives in the entire country, what fraction of the country is Traditionalist? Select
A) 1 / 5 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 3 / 5 | <gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) + 1</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(2/3) / (5/3)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<result>E</result> | E | 0.6 | A certain country is divided into 8 provinces. Each province consists entirely of Progressives and Traditionalists. If each province contains the same number of Traditionalists and the number of Traditionalists in any given province is 1/12 the total number of Progressives in the entire country, what fraction of the country is Traditionalist? | {
"A": "1 / 5",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "3 / 5"
} | subtract(1, divide(divide(8, 12), add(divide(8, 12), 1))) | divide(n0,n2)|add(n1,#0)|divide(#0,#1)|subtract(n1,#2)| | "let p be the number of progressives in the country as a whole . in each province , the number of traditionalists is p / 12 the total number of traditionalists is 8 p / 12 = 2 p / 3 . the total population is p + 2 p / 3 = 5 p / 3 p / ( 5 p / 3 ) = 3 / 5 the answer is e ." | general |
math_qa__x4De6yW5D99P3TPp | n and m are each 3 - digit integers . each of the numbers 1 , 2 , 3 , 45 and 6 is a digit of either n or m . what is the smallest possible positive difference between n and m ? Choose one.
A) 59 B) 49 C) 58 D) 113 E) 131 | <gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">60 - 10</gadget>
<output>50</output>
<result>B</result> | B | 49 | n and m are each 3 - digit integers . each of the numbers 1 , 2 , 3 , 45 and 6 is a digit of either n or m . what is the smallest possible positive difference between n and m ? | {
"A": "59",
"B": "49",
"C": "58",
"D": "113",
"E": "131"
} | subtract(multiply(const_10, 6), const_10) | multiply(n5,const_10)|subtract(#0,const_10) | you have 6 digits : 12 , 3 , 4 , 5 , 6 each digit needs to be used to make two 3 digit numbers . this means that we will use each of the digits only once and in only one of the numbers . the numbers need to be as close to each other as possible . the numbers can not be equal so the greater number needs to be as small as possible and the smaller number needs to be as large as possible to be close to each other . the first digit ( hundreds digit ) of both numbers should be consecutive integers now let ' s think about the next digit ( the tens digit ) . to minimize the difference between the numbers , the tens digit of the greater number should be as small as possible and the tens digit of the smaller number should be as large as possible . so let ' s not use 1 and 6 in the hundreds places and reserve them for the tens places now what are the options ? try and make a pair with ( 2 * * and 3 * * ) . make the 2 * * number as large as possible and make the 3 * * number as small as possible . 265 and 314 ( difference is 49 ) or try and make a pair with ( 4 * * and 5 * * ) . make the 4 * * number as large as possible and make the 5 * * number as small as possible . we get 463 and 512 ( difference is 49 ) b | general |
math_qa__ZPTXZtGDySVgDL43 | 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.90 only. Men’s wages are? Answers
A) rs . 6 B) rs . 6.5 C) rs . 8 D) rs . 5 E) rs . 2 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">90 / 15</gadget>
<output>6</output>
<result>A</result> | A | 6 | 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.90 only. Men’s wages are? | {
"A": "rs . 6",
"B": "rs . 6.5",
"C": "rs . 8",
"D": "rs . 5",
"E": "rs . 2"
} | divide(90, multiply(const_3, 5)) | multiply(n0,const_3)|divide(n2,#0)| | "answer : option a 5 m = xw = 8 b 5 m + xw + 8 b - - - - - 90 rs . 5 m + 5 m + 5 m - - - - - 90 rs . 15 m - - - - - - 90 rs . = > 1 m = 6 rs ." | general |
math_qa__nTAcYZBxv1ZR1qe0 | Stacy has a 33 page history paper due in 3 days. How many pages per day would she have to write to finish on time? Choose the correct choice from the following choices.
A) 9 B) 8 C) 11 D) 8.5 E) 6 | <gadget id="calculator">33 / 3</gadget>
<output>11</output>
<result>C</result> | C | 11 | Stacy has a 33 page history paper due in 3 days. How many pages per day would she have to write to finish on time? | {
"A": "9",
"B": "8",
"C": "11",
"D": "8.5",
"E": "6"
} | divide(33, 3) | divide(n0,n1)| | "33 / 3 = 11 answer : c" | physics |
math_qa__sVQEVqEcn8lgvLFl | The smallest value of n, for which 2n+1 is not a prime number, is Choose the correct choice from the following.
A) 3 B) 4 C) 5 D) none E) 6 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<result>B</result> | B | 4 | The smallest value of n, for which 2n+1 is not a prime number, is | {
"A": "3",
"B": "4",
"C": "5",
"D": "none",
"E": "6"
} | add(2, 2) | add(n0,n0)| | "solution ( 2 × 1 + 1 ) = 3 . ( 2 × 2 + 1 ) = 5 . ( 2 × 3 + 1 ) = 7 . ( 2 × 4 + 1 ) = 9 . which is not prime , n = 4 . answer b" | general |
math_qa__zDlDO1IY0dJJUEiT | A train running at the speed of 50 km/hr crosses a pole in 18 seconds. Find the length of the train. Options: A) 150 B) 188 C) 250 D) 288 E) 300 | <gadget id="calculator">50 * 1_000</gadget>
<output>50_000</output>
<gadget id="calculator">50_000 / 3_600</gadget>
<output>125/9 = around 13.888889</output>
<gadget id="calculator">(125/9) * 18</gadget>
<output>250</output>
<result>C</result> | C | 250 | A train running at the speed of 50 km/hr crosses a pole in 18 seconds. Find the length of the train. | {
"A": "150",
"B": "188",
"C": "250",
"D": "288",
"E": "300"
} | multiply(divide(multiply(50, const_1000), const_3600), 18) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 50 * ( 5 / 18 ) m / sec = 125 / 9 m / sec length of train ( distance ) = speed * time ( 125 / 9 ) * 18 = 250 meter answer : c" | physics |
math_qa__yneB3rEGdCdkNd15 | What sum of money put at C.I amounts in 2 years to Rs.7000 and in 3 years to Rs.9261?
Choose one: A) 4000 B) 8877 C) 2877 D) 2678 E) 1011 | <gadget id="calculator">9_261 / 7_000</gadget>
<output>1_323/1_000 = around 1.323</output>
<gadget id="calculator">(1_323/1_000) - 1</gadget>
<output>323/1_000 = around 0.323</output>
<gadget id="calculator">(323/1_000) + 1</gadget>
<output>1_323/1_000 = around 1.323</output>
<gadget id="calculator">(1_323/1_000) ** 2</gadget>
<output>1_750_329/1_000_000 = around 1.750329</output>
<gadget id="calculator">7_000 / (1_750_329/1_000_000)</gadget>
<output>1_000_000_000/250_047 = around 3_999.248141</output>
<result>A</result> | A | 4,000 | What sum of money put at C.I amounts in 2 years to Rs.7000 and in 3 years to Rs.9261? | {
"A": "4000",
"B": "8877",
"C": "2877",
"D": "2678",
"E": "1011"
} | divide(7000, power(add(subtract(divide(9261, 7000), const_1), const_1), 2)) | divide(n3,n1)|subtract(#0,const_1)|add(#1,const_1)|power(#2,n0)|divide(n1,#3)| | "7000 - - - - 2261 100 - - - - ? = > 32.3 % x * 1323 / 100 * 1323 / 100 = 7000 x * 1.75 = 7000 x = 7000 / 1.75 = > 3999.25 answer : a" | general |
math_qa__hQlT2ez1izaDMHJY | Two employees M and N are paid a total of $583 per week by their employer. If M is paid 120 percent of the salary paid to N, how much is N paid per week? Options:
A) $ 245 B) $ 255 C) $ 265 D) $ 275 E) $ 285 | <gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) + 1</gadget>
<output>11/5 = around 2.2</output>
<gadget id="calculator">583 / (11/5)</gadget>
<output>265</output>
<result>C</result> | C | 265 | Two employees M and N are paid a total of $583 per week by their employer. If M is paid 120 percent of the salary paid to N, how much is N paid per week? | {
"A": "$ 245",
"B": "$ 255",
"C": "$ 265",
"D": "$ 275",
"E": "$ 285"
} | divide(583, add(divide(120, const_100), const_1)) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)| | "1.2 n + n = 583 2.2 n = 583 n = 265 the answer is c ." | general |
math_qa__ZLjyqtBzi24KmmLa | if remainder is 1 , quotient is 54 and dividend is 217 then what is divisor ? Pick
A) 2 B) 4 C) 6 D) 14 E) 16 | <gadget id="calculator">217 - 1</gadget>
<output>216</output>
<gadget id="calculator">216 / 54</gadget>
<output>4</output>
<result>B</result> | B | 4 | if remainder is 1 , quotient is 54 and dividend is 217 then what is divisor ? | {
"A": "2",
"B": "4",
"C": "6",
"D": "14",
"E": "16"
} | divide(subtract(217, 1), 54) | subtract(n2,n0)|divide(#0,n1)| | "we know dividend = divisor * quotient + remainder = = = > 217 = divisor * 54 + 1 = = = = = > 216 / 54 = divisor = = = > divisor = 4 ans - b" | general |
math_qa__Oysr3ugrMjgOni5g | Find the least number that must be subtracted from 1387 so that the remaining number is divisible by 15.
Select:
A) 1 B) 5 C) 7 D) 9 E) 13 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">100 - 8</gadget>
<output>92</output>
<gadget id="calculator">92 * 15</gadget>
<output>1_380</output>
<gadget id="calculator">1_387 - 1_380</gadget>
<output>7</output>
<result>C</result> | C | 7 | Find the least number that must be subtracted from 1387 so that the remaining number is divisible by 15. | {
"A": "1",
"B": "5",
"C": "7",
"D": "9",
"E": "13"
} | subtract(1387, multiply(subtract(const_100, multiply(const_2, const_4)), 15)) | multiply(const_2,const_4)|subtract(const_100,#0)|multiply(n1,#1)|subtract(n0,#2) | on dividing 1387 by 15 we get the remainder 7 , so 7 should be subtracted . the answer is c . | general |
math_qa__WO9OJh3N9kvo462I | The output of a factory was increased by 5% to keep up with rising demand. To handle the holiday rush, this new output was increased by 20%. By approximately what percent would the output now have to be decreased in order to restore the original output? Select the correct option.
A) 20 %
B) 24 %
C) 30 %
D) 32 %
E) 79 % | <gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">105 * (1/5)</gadget>
<output>21</output>
<gadget id="calculator">105 + 21</gadget>
<output>126</output>
<gadget id="calculator">126 - 100</gadget>
<output>26</output>
<gadget id="calculator">26 * 100</gadget>
<output>2_600</output>
<gadget id="calculator">2_600 / 126</gadget>
<output>1_300/63 = around 20.634921</output>
<result>A</result> | A | 20 | The output of a factory was increased by 5% to keep up with rising demand. To handle the holiday rush, this new output was increased by 20%. By approximately what percent would the output now have to be decreased in order to restore the original output? | {
"A": "20 %",
"B": "24 %",
"C": "30 %",
"D": "32 %",
"E": "79 %"
} | divide(multiply(subtract(add(add(const_100, 5), multiply(add(const_100, 5), divide(20, const_100))), const_100), const_100), add(add(const_100, 5), multiply(add(const_100, 5), divide(20, const_100)))) | add(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|add(#0,#2)|subtract(#3,const_100)|multiply(#4,const_100)|divide(#5,#3)| | "the original output increases by 5 % and then 20 % . total % change = a + b + ab / 100 total % change = 5 + 20 + 5 * 20 / 100 = 26 % now , you want to change it to 0 , so , 0 = 26 + x + 26 x / 100 x = - 26 ( 100 ) / 126 = 20 % approximately answer is a" | general |
math_qa__msl5jomqzgK9gbyM | If A and B get profits of Rs.60,000 and Rs.6,000 respectively at the end of year then ratio of their investments are Pick one.
A) 4 : 1 B) 10 : 1 C) 3 : 2 D) 2 : 3 E) 2 : 5 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 * 100</gadget>
<output>60_000</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">60_000 / 10</gadget>
<output>6_000</output>
<gadget id="calculator">60_000 / 6_000</gadget>
<output>10</output>
<result>B</result> | B | 10 | If A and B get profits of Rs.60,000 and Rs.6,000 respectively at the end of year then ratio of their investments are | {
"A": "4 : 1",
"B": "10 : 1",
"C": "3 : 2",
"D": "2 : 3",
"E": "2 : 5"
} | divide(multiply(multiply(multiply(const_3, const_2), const_100), const_100), divide(multiply(multiply(multiply(const_3, const_2), const_100), const_100), multiply(add(const_2, const_3), const_2))) | add(const_2,const_3)|multiply(const_2,const_3)|multiply(#1,const_100)|multiply(#0,const_2)|multiply(#2,const_100)|divide(#4,#3)|divide(#4,#5) | ratio = 60000 / 6000 = 10 : 1 answer : b | gain |
math_qa__xDHlCfFCFOMI5zDy | What is the 99th digit after the decimal point in the decimal expansion of 2/9 + 3/11? Choose the correct option
A) 1 B) 2 C) 4 D) 7 E) 9 | <gadget id="calculator">99 / 9</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">99 / 11</gadget>
<output>9</output>
<gadget id="calculator">9 * 3</gadget>
<output>27</output>
<gadget id="calculator">22 + 27</gadget>
<output>49</output>
<gadget id="calculator">49 / 99</gadget>
<output>49/99 = around 0.494949</output>
<gadget id="calculator">(49/99) * 10</gadget>
<output>490/99 = around 4.949495</output>
<gadget id="calculator">floor(490/99)</gadget>
<output>4</output>
<result>C</result> | C | 4 | What is the 99th digit after the decimal point in the decimal expansion of 2/9 + 3/11? | {
"A": "1",
"B": "2",
"C": "4",
"D": "7",
"E": "9"
} | floor(multiply(divide(add(multiply(divide(99, 9), 2), multiply(divide(99, 11), 3)), 99), const_10)) | divide(n0,n2)|divide(n0,n4)|multiply(n1,#0)|multiply(n3,#1)|add(#2,#3)|divide(#4,n0)|multiply(#5,const_10)|floor(#6) | 2 / 9 = 0.22222 . . . . = = > 99 th digit is 2 3 / 11 = 0.27272727 . . . . = = > every odd digit is 2 . so , 99 th digit will be 2 . 2 + 2 = 4 answer : c | general |
math_qa__HqgHEguDzfCOyawH | The ratio of ages of Aman, Bren, and Charlie are in the ratio 5:8:7 respectively. If 8 years ago, the sum of their ages was 76, what will be the age of Bren 10 years from now? Options.
A) 17 B) 25 C) 27 D) 35 E) 50 | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 + 76</gadget>
<output>100</output>
<gadget id="calculator">5 + 8</gadget>
<output>13</output>
<gadget id="calculator">13 + 7</gadget>
<output>20</output>
<gadget id="calculator">100 / 20</gadget>
<output>5</output>
<gadget id="calculator">5 * 8</gadget>
<output>40</output>
<gadget id="calculator">40 + 10</gadget>
<output>50</output>
<result>E</result> | E | 50 | The ratio of ages of Aman, Bren, and Charlie are in the ratio 5:8:7 respectively. If 8 years ago, the sum of their ages was 76, what will be the age of Bren 10 years from now? | {
"A": "17",
"B": "25",
"C": "27",
"D": "35",
"E": "50"
} | add(multiply(divide(add(multiply(8, const_3), 76), add(add(5, 8), 7)), 8), 10) | add(n0,n1)|multiply(n1,const_3)|add(n4,#1)|add(n2,#0)|divide(#2,#3)|multiply(n1,#4)|add(n5,#5) | let the present ages of aman , bren , and charlie be 5 x , 8 x and 7 x respectively . 5 x - 8 + 8 x - 8 + 7 x - 8 = 76 x = 5 present age of bren = 8 * 5 = 40 bren ' s age 10 years hence = 40 + 10 = 50 answer = e | general |
math_qa__9dd8RJAp0aZg0XJc | A trainer is standing in one corner of a square ground of side 25m. His voice can be heard upto 140m. Find the area of the ground in which his voice can be heard? Choose the correct choice from the following options:
A) 12300
B) 14500
C) 15400
D) 16700
E) 18200 | <gadget id="calculator">pi * (140 ** 2)</gadget>
<output>19600*pi = around 61_575.21601</output>
<gadget id="calculator">(19600*pi) / 4</gadget>
<output>4900*pi = around 15_393.804003</output>
<result>C</result> | C | 15,400 | A trainer is standing in one corner of a square ground of side 25m. His voice can be heard upto 140m. Find the area of the ground in which his voice can be heard? | {
"A": "12300",
"B": "14500",
"C": "15400",
"D": "16700",
"E": "18200"
} | divide(circle_area(140), const_4) | circle_area(n1)|divide(#0,const_4) | area covered by goat = pi * r ^ 2 / 4 ( here we divide by 4 because the trainer is standing in a corner of the ground and only in 1 / 4 part , the voice can be heard ) where r = 14 m = length reaching the voice so area = ( 22 / 7 ) * 140 * 140 / 4 = 15400 sq m answer : c | geometry |
math_qa__31MWK0Wfr4PlACsq | machine m , n , o working simultaneously machine m can produce x units in 3 / 4 of the time it takes machine n to produce the same amount of units . machine n can produce x units in 2 / 7 the time it takes machine o to produce that amount of units . if all 3 machines are working simultaneously , what fraction of the total output is produced by machine n ? Choose the correct option
A) 1 / 2 B) 7 / 13 C) 4 / 13 D) 8 / 29 E) 6 / 33 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">14 - 1</gadget>
<output>13</output>
<gadget id="calculator">7 / 13</gadget>
<output>7/13 = around 0.538462</output>
<result>B</result> | B | 0.538462 | machine m , n , o working simultaneously machine m can produce x units in 3 / 4 of the time it takes machine n to produce the same amount of units . machine n can produce x units in 2 / 7 the time it takes machine o to produce that amount of units . if all 3 machines are working simultaneously , what fraction of the total output is produced by machine n ? | {
"A": "1 / 2",
"B": "7 / 13",
"C": "4 / 13",
"D": "8 / 29",
"E": "6 / 33"
} | divide(7, subtract(multiply(7, 2), const_1)) | multiply(n2,n3)|subtract(#0,const_1)|divide(n3,#1) | now ultimately the speed of every machine is given with respect to mach o . so lets assume the speed of o , say 12 hrs to make x units ( assuming 6 because we can see we will need to divide by 3 and 4 mach o makes x units in 12 hrs so , mach n = 2 / 7 of o = 2 / 7 * 12 = 24 / 7 hrs to make x units and mach m = 3 / 4 of n = 3 / 4 * 24 / 7 = 1 / 6 hrs to make x units no they are running simultaneously . lets see how much each mach makes in 1 hr mach o = x / 12 units mach n = 7 / 24 units mach m = x / 6 units in 1 hr , together they make - x / 12 + 7 / 24 + x / 6 = 13 / 24 so what ratio of this has mach n made ? ( 7 / 24 ) / ( 13 / 24 ) = 7 / 13 ans : b = 7 / 13 | general |
math_qa__JkYy474Uajj7NUHo | A and B can do a work in 2 days, B and C in 6 days and C and A in 8 days. In how many days will the work be completed, if all three of them work together? Choose the correct choice from the following answers.
A) 12 / 28 B) 48 / 19 C) 16 / 48 D) 18 / 48 E) 12 / 64 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/2) + (1/6)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(2/3) + (1/8)</gadget>
<output>19/24 = around 0.791667</output>
<gadget id="calculator">(19/24) / 2</gadget>
<output>19/48 = around 0.395833</output>
<gadget id="calculator">1 / (19/48)</gadget>
<output>48/19 = around 2.526316</output>
<result>B</result> | B | 2.526316 | A and B can do a work in 2 days, B and C in 6 days and C and A in 8 days. In how many days will the work be completed, if all three of them work together? | {
"A": "12 / 28",
"B": "48 / 19",
"C": "16 / 48",
"D": "18 / 48",
"E": "12 / 64"
} | divide(const_1, divide(add(add(inverse(2), inverse(6)), inverse(8)), 2)) | inverse(n0)|inverse(n1)|inverse(n2)|add(#0,#1)|add(#3,#2)|divide(#4,n0)|divide(const_1,#5)| | "one day work of a and b = 1 / 2 one day work of b and c = 1 / 6 one day work of c and a = 1 / 8 2 ( a + b + c ) = 1 / 2 + 1 / 6 + 1 / 8 2 ( a + b + c ) = 19 / 24 ( a + b + c ) = 19 / 48 number of days required = 48 / 19 days . answer : b" | physics |
math_qa__4sg2hRdGIKV0OtTW | A man is 18 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is
Pick one:
A) 21 years B) 22 years C) 23 years D) 12 years E) 16 years | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">18 - 2</gadget>
<output>16</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">16 / 1</gadget>
<output>16</output>
<result>E</result> | E | 16 | A man is 18 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is | {
"A": "21 years",
"B": "22 years",
"C": "23 years",
"D": "12 years",
"E": "16 years"
} | divide(subtract(18, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1)) | multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)| | "explanation : let ' s son age is x , then father age is x + 18 . = > 2 ( x + 2 ) = ( x + 18 + 2 ) = > 2 x + 4 = x + 20 = > x = 16 years option e" | general |
math_qa__uOXb288OYSjRa4xk | (0.0088)(4.5) / (0.05)(0.1)(0.008)= Choose the correct answer:
A) 950 B) 940 C) 980 D) 960 E) 990 | <gadget id="calculator">0.0088 * 4.5</gadget>
<output>0.0396</output>
<gadget id="calculator">0.05 * 0.1</gadget>
<output>0.005</output>
<gadget id="calculator">0.005 * 0.008</gadget>
<output>0.00004</output>
<gadget id="calculator">0.0396 / 0.00004</gadget>
<output>990</output>
<result>E</result> | E | 990 | (0.0088)(4.5) / (0.05)(0.1)(0.008)= | {
"A": "950",
"B": "940",
"C": "980",
"D": "960",
"E": "990"
} | divide(multiply(0.0088, 4.5), multiply(multiply(0.05, 0.1), 0.008)) | multiply(n0,n1)|multiply(n2,n3)|multiply(n4,#1)|divide(#0,#2)| | "( 0.0088 ) ( 4.5 ) / ( 0.05 ) ( 0.1 ) ( 0.008 ) = 0.0088 * 450 / 5 * ( 0.1 ) ( 0.008 ) = 0.088 * 90 / 1 * 0.008 = 88 * 90 / 8 = 11 * 90 = 990 answer : e" | general |
math_qa__uehPh2SWZ3UBwdH6 | A watch was sold at a loss of 10%. If it was sold for Rs.210 more, there would have been a gain of 4%. What is the cost price? Choices: A) s . 1000 B) s . 1009 C) s . 1007 D) s . 1006 E) s . 1500 | <gadget id="calculator">210 * 100</gadget>
<output>21_000</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">104 - 90</gadget>
<output>14</output>
<gadget id="calculator">21_000 / 14</gadget>
<output>1_500</output>
<result>E</result> | E | 1,500 | A watch was sold at a loss of 10%. If it was sold for Rs.210 more, there would have been a gain of 4%. What is the cost price? | {
"A": "s . 1000",
"B": "s . 1009",
"C": "s . 1007",
"D": "s . 1006",
"E": "s . 1500"
} | divide(multiply(210, const_100), subtract(add(const_100, const_4), subtract(const_100, 10))) | add(const_100,const_4)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3) | explanation : 90 % 104 % - - - - - - - - 14 % - - - - 210 100 % - - - - ? = > rs . 1500 answer : e | gain |
math_qa__gR8Cz4UboMcYId4d | Two trains 250 m and 500 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Choose the correct choice from the following choices: A) 10.6 B) 10.9 C) 10.4 D) 27 E) 10.1 | <gadget id="calculator">250 + 500</gadget>
<output>750</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">750 / (250/9)</gadget>
<output>27</output>
<result>D</result> | D | 27 | Two trains 250 m and 500 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "10.6",
"B": "10.9",
"C": "10.4",
"D": "27",
"E": "10.1"
} | divide(add(250, 500), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 250 + 500 = 750 m . required time = 750 * 9 / 250 = 27 sec answer : d" | physics |
math_qa__JU8ctEvZcJ2y7LQb | In a rectangular coordinate system, what is the area of a rectangle whose vertices have the coordinates (-3, 1), (1, 1), (1, -2) and (-3, -2)?
Select the correct option:
A) 12
B) 24
C) 20
D) 30
E) 36 | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<result>A</result> | A | 12 | In a rectangular coordinate system, what is the area of a rectangle whose vertices have the coordinates (-3, 1), (1, 1), (1, -2) and (-3, -2)? | {
"A": "12",
"B": "24",
"C": "20",
"D": "30",
"E": "36"
} | multiply(add(3, 1), add(1, 2)) | add(n0,n1)|add(n1,n5)|multiply(#0,#1)| | "length of side 1 = 3 + 1 = 4 length of side 2 = 2 + 1 = 3 area of rectangle = 4 * 3 = 12 a is the answer" | geometry |
math_qa__kpDaF3VoPrgUFAy3 | A can finish a piece of work in 4 days. B can do it in 8 days. They work together for two days and then A goes away. In how many days will B finish the work?
Pick one
A) 4
B) 5
C) 6
D) 2
E) 8 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/2) + (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / (1/8)</gadget>
<output>2</output>
<result>D</result> | D | 2 | A can finish a piece of work in 4 days. B can do it in 8 days. They work together for two days and then A goes away. In how many days will B finish the work? | {
"A": "4",
"B": "5",
"C": "6",
"D": "2",
"E": "8"
} | divide(subtract(const_1, add(multiply(divide(const_1, 4), const_2), multiply(divide(const_1, 8), const_2))), divide(const_1, 8)) | divide(const_1,n0)|divide(const_1,n1)|multiply(#0,const_2)|multiply(#1,const_2)|add(#2,#3)|subtract(const_1,#4)|divide(#5,#1)| | "2 / 4 + ( 2 + x ) / 8 = 1 = > x = 2 days answer : d" | physics |
math_qa__0pOQn0OhSZif9YYw | A batsman in his 12th innings makes a score of 65 and thereby increases his average by 3 runs. What is his average after the 12th innings if he had never been ‘not out’? Choose the most appropriate option.
A) 32 B) 43 C) 44 D) 45 E) 46 | <gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">65 - 36</gadget>
<output>29</output>
<gadget id="calculator">29 + 3</gadget>
<output>32</output>
<result>A</result> | A | 32 | A batsman in his 12th innings makes a score of 65 and thereby increases his average by 3 runs. What is his average after the 12th innings if he had never been ‘not out’? | {
"A": "32",
"B": "43",
"C": "44",
"D": "45",
"E": "46"
} | add(subtract(65, multiply(12, 3)), 3) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1)| | "let ‘ x ’ be the average score after 12 th innings ⇒ 12 x = 11 × ( x – 3 ) + 65 ∴ x = 32 answer a" | general |
math_qa__ceay9cewi7RzjvHj | A train is 360 meter long is running at a speed of 72 km/hour. In what time will it pass a bridge of 140 meter length?
Select the correct option: A) 65 seconds B) 46 seconds C) 25 seconds D) 97 seconds E) 26 seconds | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">500 / 20</gadget>
<output>25</output>
<result>C</result> | C | 25 | A train is 360 meter long is running at a speed of 72 km/hour. In what time will it pass a bridge of 140 meter length? | {
"A": "65 seconds",
"B": "46 seconds",
"C": "25 seconds",
"D": "97 seconds",
"E": "26 seconds"
} | divide(add(360, 140), divide(multiply(72, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 72 km / hr = 72 * ( 5 / 18 ) m / sec = 20 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 * ( 1 / 20 ) = 25 seconds answer : c" | physics |
math_qa__gA2uoLKOkJXZ1URD | A bullet train 220 m long is running with a speed of 59 kmph. In what time will it pass a man who is running at 7 kmph in the direction opposite to that in which the bullet train is going? Choose the correct choice from the following answers.
A) 23 sec B) 15 sec C) 12 sec D) 11 sec E) 16 sec | <gadget id="calculator">59 + 7</gadget>
<output>66</output>
<gadget id="calculator">66 * 1_000</gadget>
<output>66_000</output>
<gadget id="calculator">66_000 / 3_600</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">220 / (55/3)</gadget>
<output>12</output>
<result>C</result> | C | 12 | A bullet train 220 m long is running with a speed of 59 kmph. In what time will it pass a man who is running at 7 kmph in the direction opposite to that in which the bullet train is going? | {
"A": "23 sec",
"B": "15 sec",
"C": "12 sec",
"D": "11 sec",
"E": "16 sec"
} | divide(220, divide(multiply(add(59, 7), const_1000), const_3600)) | add(n1,n2)|multiply(#0,const_1000)|divide(#1,const_3600)|divide(n0,#2)| | "c 12 sec speed of the bullet train relative to man = ( 59 + 7 ) kmph = 66 * 5 / 18 m / sec = 55 / 3 m / sec . time taken by the bullet train to cross the man = time taken by it to cover 220 m at ( 55 / 3 ) m / sec = ( 220 * 3 / 55 ) sec = 12 sec" | physics |
math_qa__XolWkAeySq0lvjjB | At the wholesale store you can buy an 8-pack of hot dogs for $1.55, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $208?
Choose the correct choice from the following options: A) 1,108 B) 2,100 C) 2,108 D) 2,160 E) 2,256 | <gadget id="calculator">208 / 22.95</gadget>
<output>9.063181</output>
<gadget id="calculator">9.063181 * 250</gadget>
<output>2_265.79525</output>
<result>D</result> | D | 2,160 | At the wholesale store you can buy an 8-pack of hot dogs for $1.55, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $208? | {
"A": "1,108",
"B": "2,100",
"C": "2,108",
"D": "2,160",
"E": "2,256"
} | multiply(divide(208, 22.95), 250) | divide(n6,n5)|multiply(n4,#0)| | "i think it should be d . i can buy 8 250 - pack for rs 22.95 * 8 = $ 183.60 now , i can buy 8 20 - pack for 3.05 * 8 = $ 24.40 now , i am left with only $ 1.15 . i can not but anything with this . hence total hotdogs = 250 * 8 + 20 * 5 = 2160" | general |
math_qa__tpLKCyceKJw1VVLF | The spherical ball of lead 3 cm in diameter is melted and recast into 3 spherical balls. The diameters of two of these are 1 ½ cm and 2 cm respectively. The diameter of third ball is? Choose the correct answer: A) 2.66 cm B) 2.5 cm C) 3 cm D) 3.5 cm E) 4 cm | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) ** 3</gadget>
<output>27/8 = around 3.375</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) / 2</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) ** 3</gadget>
<output>27/64 = around 0.421875</output>
<gadget id="calculator">(27/8) - (27/64)</gadget>
<output>189/64 = around 2.953125</output>
<gadget id="calculator">(189/64) - 1</gadget>
<output>125/64 = around 1.953125</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(125/64) ** (1/3)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 2</gadget>
<output>5/2 = around 2.5</output>
<result>B</result> | B | 2.5 | The spherical ball of lead 3 cm in diameter is melted and recast into 3 spherical balls. The diameters of two of these are 1 ½ cm and 2 cm respectively. The diameter of third ball is? | {
"A": "2.66 cm",
"B": "2.5 cm",
"C": "3 cm",
"D": "3.5 cm",
"E": "4 cm"
} | multiply(power(subtract(subtract(power(divide(3, 2), const_3), power(divide(add(1, divide(1, 2)), 2), const_3)), 1), inverse(3)), const_2) | divide(n0,n3)|divide(n2,n3)|inverse(n0)|add(n2,#1)|power(#0,const_3)|divide(#3,n3)|power(#5,const_3)|subtract(#4,#6)|subtract(#7,n2)|power(#8,#2)|multiply(#9,const_2) | 4 / 3 π * 3 * 3 * 3 = 4 / 3 π [ ( 3 / 2 ) 3 + 23 + r 3 ] r = 1.25 d = 2.5 answer : b | physics |
math_qa__bEYjRB31oQicW6Nl | Find the number which when multiplied by 15 is increased by 196
Choose the correct choice
A) 10 B) 12 C) 14 D) 16 E) 17 | <gadget id="calculator">15 - 1</gadget>
<output>14</output>
<gadget id="calculator">196 / 14</gadget>
<output>14</output>
<result>C</result> | C | 14 | Find the number which when multiplied by 15 is increased by 196 | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "17"
} | divide(196, subtract(15, const_1)) | subtract(n0,const_1)|divide(n1,#0)| | "explanation : let the number be x . then , 15 x = x + 196 = › 14 x = 196 = › x = 14 . answer : option c" | general |
math_qa__FkU9tVS13n3HTH8A | If the speed of a man is 51 km per hour, then what is the distance traveled by him in 30 seconds ? Choose the correct choice from the following answers:
A) 275 m B) 360 m C) 375 m D) 425 m E) 440 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">51 * (5/18)</gadget>
<output>85/6 = around 14.166667</output>
<gadget id="calculator">(85/6) * 30</gadget>
<output>425</output>
<result>D</result> | D | 425 | If the speed of a man is 51 km per hour, then what is the distance traveled by him in 30 seconds ? | {
"A": "275 m",
"B": "360 m",
"C": "375 m",
"D": "425 m",
"E": "440 m"
} | multiply(multiply(51, const_0_2778), 30) | multiply(n0,const_0_2778)|multiply(n1,#0)| | "the distance traveled in 30 sec = 51 * ( 5 / 18 ) * 30 = 425 m answer : d" | physics |
math_qa__pepJXIk3oW3F9BP0 | The ratio between the sale price and the cost price of an article is 6:4. What is the ratio between the profit and the cost price of that article? Answers
A) 23 B) 1 : 2 C) 2 : 5 D) 3 : 5 E) 25 | <gadget id="calculator">6 - 4</gadget>
<output>2</output>
<gadget id="calculator">2 / 4</gadget>
<output>1/2 = around 0.5</output>
<result>B</result> | B | 0.5 | The ratio between the sale price and the cost price of an article is 6:4. What is the ratio between the profit and the cost price of that article? | {
"A": "23",
"B": "1 : 2",
"C": "2 : 5",
"D": "3 : 5",
"E": "25"
} | divide(subtract(6, 4), 4) | subtract(n0,n1)|divide(#0,n1)| | "c . p . = rs . 4 x and s . p . = rs . 6 x . then , gain = rs . 2 x required ratio = 2 x : 4 x = 1 : 2 b" | other |
math_qa__qGYGqVUujTeImY75 | A person want to give his money of $5400 to his 3 children A,B,C in the ratio 2:3:4. What is the B's share? Choose the correct choice from the following answers
A) $ 2000 B) $ 1800 C) $ 2500 D) $ 1500 E) $ 1600 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">3 / 9</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 5_400</gadget>
<output>1_800</output>
<result>B</result> | B | 1,800 | A person want to give his money of $5400 to his 3 children A,B,C in the ratio 2:3:4. What is the B's share? | {
"A": "$ 2000",
"B": "$ 1800",
"C": "$ 2500",
"D": "$ 1500",
"E": "$ 1600"
} | multiply(divide(3, add(add(2, 3), 4)), 5400) | add(n1,n2)|add(n4,#0)|divide(n1,#1)|multiply(n0,#2)| | "b ' s share = 5400 * 3 / 9 = $ 1800 answer is b" | other |
math_qa__eEWU7GLk8M1iwad5 | The perimeter of one face of a cube is 32 cm. Its volume will be: Choose the correct choice from the following options.
A) 125 cm 3 B) 400 cm 3 C) 512 cm 3 D) 625 cm 3 E) none of these | <gadget id="calculator">32 / 4</gadget>
<output>8</output>
<gadget id="calculator">8 ** 3</gadget>
<output>512</output>
<result>C</result> | C | 512 | The perimeter of one face of a cube is 32 cm. Its volume will be: | {
"A": "125 cm 3",
"B": "400 cm 3",
"C": "512 cm 3",
"D": "625 cm 3",
"E": "none of these"
} | volume_cube(square_edge_by_perimeter(32)) | square_edge_by_perimeter(n0)|volume_cube(#0)| | "explanation : edge of cude = 32 / 4 = 8 cm volume = a * a * a = 8 * 8 * 8 = 512 cm cube option c" | geometry |
math_qa__E2KFqgwB2LXnTqyb | Income and expenditure of a person are in the ratio 10 : 7. If the income of the person is Rs. 10000, then find his savings? Choose the correct choice: A) 3005 B) 3098 C) 3300 D) 3010 E) 3000 | <gadget id="calculator">7 / 10</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 10_000</gadget>
<output>7_000</output>
<gadget id="calculator">10_000 - 7_000</gadget>
<output>3_000</output>
<result>E</result> | E | 3,000 | Income and expenditure of a person are in the ratio 10 : 7. If the income of the person is Rs. 10000, then find his savings? | {
"A": "3005",
"B": "3098",
"C": "3300",
"D": "3010",
"E": "3000"
} | subtract(10000, multiply(divide(7, 10), 10000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | "let the income and the expenditure of the person be rs . 10 x and rs . 7 x respectively . income , 10 x = 10000 = > x = 1000 savings = income - expenditure = 10 x - 7 x = 3 x = 3 ( 1000 ) so , savings = rs . 3000 . answer : e" | other |
math_qa__Bj7nEqRUWyVpeNzA | Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 100 milliliters of solution X to create a solution that is 25 percent alcohol by volume? Choose the correct choice: A) 250 / 3 B) 500 / 3 C) 300 D) 480 E) 600 | <gadget id="calculator">25 - 10</gadget>
<output>15</output>
<gadget id="calculator">30 - 25</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<result>C</result> | C | 300 | Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 100 milliliters of solution X to create a solution that is 25 percent alcohol by volume? | {
"A": "250 / 3",
"B": "500 / 3",
"C": "300",
"D": "480",
"E": "600"
} | multiply(divide(subtract(25, 10), subtract(30, 25)), 100) | subtract(n3,n0)|subtract(n1,n3)|divide(#0,#1)|multiply(n2,#2)| | "we know that x is 10 % , y is 30 % and w . avg = 25 % . what does this mean with respect to w . avg technique ? w . avg is 1 portion away from y and 3 portion away from x so for every 1 portion of x we will have to add 3 portions of y . if x = 100 then y = 300 answer : c" | general |
math_qa__OZVPzRIgpmZZULk7 | one millisecond is 0.001 of a second . the costs for a single run of a computer program are $ 1.07 for operating - system overhead , $ 0.023 per millisecond of computer time , and $ 5.35 for the mounting of a data tape . what is the total of these 3 costs for 1 run of a program that requires 1.5 seconds of computer time ?
Choices:
A) $ 7.15 B) $ 8.87 C) $ 28.96 D) $ 35.57 E) $ 40.92 | <gadget id="calculator">1.07 + 5.35</gadget>
<output>6.42</output>
<gadget id="calculator">1.5 / 0.001</gadget>
<output>1_500</output>
<gadget id="calculator">0.023 * 1_500</gadget>
<output>34.5</output>
<gadget id="calculator">6.42 + 34.5</gadget>
<output>40.92</output>
<result>E</result> | E | 40.92 | one millisecond is 0.001 of a second . the costs for a single run of a computer program are $ 1.07 for operating - system overhead , $ 0.023 per millisecond of computer time , and $ 5.35 for the mounting of a data tape . what is the total of these 3 costs for 1 run of a program that requires 1.5 seconds of computer time ? | {
"A": "$ 7.15",
"B": "$ 8.87",
"C": "$ 28.96",
"D": "$ 35.57",
"E": "$ 40.92"
} | add(add(1.07, 5.35), multiply(0.023, divide(1.5, 0.001))) | add(n1,n3)|divide(n6,n0)|multiply(n2,#1)|add(#0,#2) | operating system overhead for 1 run = 1.07 $ mounting of data tape = 5.35 $ cost per 1 millisecond of computer time = . 023 $ total cost of 1 run of a program that requires 1.5 seconds of computer time = 1.07 + ( . 023 * 1500 ) + 5.35 = 1.07 + 34.5 + 5.35 = 40.92 $ answer e | general |
math_qa__Emq5kPR6fsy7RCQD | If 20 typists can type 46 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour? Choose the correct option: A) 63 B) 72 C) 144 D) 216 E) 207 | <gadget id="calculator">46 * 3</gadget>
<output>138</output>
<gadget id="calculator">138 / 20</gadget>
<output>69/10 = around 6.9</output>
<gadget id="calculator">(69/10) * 30</gadget>
<output>207</output>
<result>E</result> | E | 207 | If 20 typists can type 46 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour? | {
"A": "63",
"B": "72",
"C": "144",
"D": "216",
"E": "207"
} | multiply(divide(multiply(46, const_3), 20), 30) | multiply(n1,const_3)|divide(#0,n0)|multiply(n3,#1)| | "20 typists can type 46 letters , so 30 typists can type = 46 * 30 / 20 46 * 30 / 20 letters can be typed in 20 mins . in 60 mins typist can type = 46 * 30 * 60 / 20 * 20 = 207 e is the answer" | physics |
math_qa__ncDpgeMcW1c0pDsL | If 4x+y=34, 2x-y=20, for integers of x and y, y^2=? Answers: A) 2 B) 4 C) 0 D) 10 E) 3 | <gadget id="calculator">34 + 20</gadget>
<output>54</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">54 / 6</gadget>
<output>9</output>
<gadget id="calculator">2 * 9</gadget>
<output>18</output>
<gadget id="calculator">18 - 20</gadget>
<output>-2</output>
<gadget id="calculator">(-2) ** 2</gadget>
<output>4</output>
<result>B</result> | B | 4 | If 4x+y=34, 2x-y=20, for integers of x and y, y^2=? | {
"A": "2",
"B": "4",
"C": "0",
"D": "10",
"E": "3"
} | power(subtract(multiply(2, divide(add(34, 20), add(4, 2))), 20), 2) | add(n1,n3)|add(n0,n2)|divide(#0,#1)|multiply(n2,#2)|subtract(#3,n3)|power(#4,n2) | 4 x + y = 34 2 x - y = 20 6 x = 54 x = 9 y = - 2 y ^ 2 = 4 answer is b | general |
math_qa__av4iuFRX1j1LqJ8F | what is the sum of mean and median of 17 , 45 , 59 , 113 , 76 , 95 , 59 , 35 , 1236 ? Select the correct option: A) 50.2 B) 45.8 C) 54.7 D) 61.8 E) 10.5 | <gadget id="calculator">113 - 59</gadget>
<output>54</output>
<result>C</result> | C | 54.7 | what is the sum of mean and median of 17 , 45 , 59 , 113 , 76 , 95 , 59 , 35 , 1236 ? | {
"A": "50.2",
"B": "45.8",
"C": "54.7",
"D": "61.8",
"E": "10.5"
} | subtract(113, 59) | subtract(n3,n2) | mean = ( 17 + 45 + 59 + 113 + 76 + 95 + 59 + 35 + 12 + 36 ) / 10 = 547 / 10 = 54.7 answer is c | general |
math_qa__ToHwtyUy6YbbF701 | If 0 is the remainder when m is divided by 4, what is the remainder when 6m is divided by 4? Options:
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">4 % 2</gadget>
<output>0</output>
<result>A</result> | A | 0 | If 0 is the remainder when m is divided by 4, what is the remainder when 6m is divided by 4? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | reminder(4, const_2.0) | reminder(n1,const_2.0)| | "for any m that is divisible by 4 , any multiple of m ( such as 6 m ) will also be divisible by 4 . m = 4 * a 6 m = 6 * 4 * a the answer is , therefore , ( a ) ." | physics |
math_qa__DiJ6cZcVRgBSzu4Q | If a/b = 5/2, b/c = 1/2, c/d = 1, d/e = 3/2 and e/f = 4/3, then what is the value of abc/def ? Pick one
A) 15 / 8 B) 14 / 3 C) 41 / 7 D) 3 / 18 E) 18 / 4 | <gadget id="calculator">5 * 1</gadget>
<output>5</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">1 * 3</gadget>
<output>3</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(5/4) * (3/4)</gadget>
<output>15/16 = around 0.9375</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">12 / 6</gadget>
<output>2</output>
<gadget id="calculator">(15/16) * 2</gadget>
<output>15/8 = around 1.875</output>
<result>A</result> | A | 1.875 | If a/b = 5/2, b/c = 1/2, c/d = 1, d/e = 3/2 and e/f = 4/3, then what is the value of abc/def ? | {
"A": "15 / 8",
"B": "14 / 3",
"C": "41 / 7",
"D": "3 / 18",
"E": "18 / 4"
} | multiply(multiply(divide(multiply(multiply(5, 1), 1), multiply(multiply(2, 2), 1)), divide(multiply(multiply(1, 1), 3), multiply(multiply(2, 1), 2))), divide(multiply(multiply(1, 3), 4), multiply(multiply(1, 2), 3))) | multiply(n2,n5)|multiply(n1,n2)|multiply(n0,n2)|multiply(n1,n1)|multiply(n2,n2)|multiply(n7,#0)|multiply(n5,#1)|multiply(n2,#2)|multiply(n2,#3)|multiply(n5,#4)|multiply(n1,#1)|divide(#5,#6)|divide(#7,#8)|divide(#9,#10)|multiply(#12,#13)|multiply(#11,#14) | say a = 2 . then : a / b = 5 / 2 - - > b = 2 / 5 ; b / c = 1 / 2 - - > c = 4 / 5 ; c / d = 1 - - > d = 4 / 5 ; d / e = 3 / 2 - - > e = 8 / 15 ; e / f = 4 / 3 - - > f = 2 / 5 . abc / def = ( 1 * 2 / 5 * 4 / 5 ) / ( 4 / 5 * 8 / 15 * 2 / 5 ) = 15 / 8 . answer : a . | general |
math_qa__yz06V8MKLhJEYY0A | A computer manufacturer produces a certain electronic component at a cost of $75 per component. Shipping costs for delivering the components are $2 per unit. Further, the manufacturer has costs of $16,500 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 150 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues? Options:
A) $ 28 B) $ 187 C) $ 110 D) $ 138 E) $ 192 | <gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 1_000</gadget>
<output>16_000</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">16_000 + 200</gadget>
<output>16_200</output>
<gadget id="calculator">75 + 2</gadget>
<output>77</output>
<gadget id="calculator">77 * 150</gadget>
<output>11_550</output>
<gadget id="calculator">16_200 + 11_550</gadget>
<output>27_750</output>
<gadget id="calculator">27_750 / 150</gadget>
<output>185</output>
<result>B</result> | B | 187 | A computer manufacturer produces a certain electronic component at a cost of $75 per component. Shipping costs for delivering the components are $2 per unit. Further, the manufacturer has costs of $16,500 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 150 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues? | {
"A": "$ 28",
"B": "$ 187",
"C": "$ 110",
"D": "$ 138",
"E": "$ 192"
} | divide(add(add(multiply(multiply(const_4, const_4), const_1000), multiply(2, const_100)), multiply(add(75, 2), 150)), 150) | add(n0,n1)|multiply(const_4,const_4)|multiply(n1,const_100)|multiply(#1,const_1000)|multiply(n3,#0)|add(#3,#2)|add(#5,#4)|divide(#6,n3)| | "this question can be solved easily using a equation model . 150 * p = 16500 ( fixed cost ) + 150 * 75 + 150 * 2 . = 16500 + 11250 + 300 p = $ 187 b" | general |
math_qa__9vUrOVGs4vRCSLKi | If paint costs $3.20 per quart, and a quart covers 10 square feet, how much will it cost to paint the outside of a cube 10 feet on each edge? Choose one.
A) $ 1.60 B) $ 16.00 C) $ 96.00 D) $ 108.00 E) $ 192.00 | <gadget id="calculator">3.2 / 10</gadget>
<output>0.32</output>
<gadget id="calculator">6 * (10 ** 2)</gadget>
<output>600</output>
<gadget id="calculator">0.32 * 600</gadget>
<output>192</output>
<result>E</result> | E | 192 | If paint costs $3.20 per quart, and a quart covers 10 square feet, how much will it cost to paint the outside of a cube 10 feet on each edge? | {
"A": "$ 1.60",
"B": "$ 16.00",
"C": "$ 96.00",
"D": "$ 108.00",
"E": "$ 192.00"
} | multiply(divide(3.20, 10), surface_cube(10)) | divide(n0,n1)|surface_cube(n2)|multiply(#0,#1)| | "total surface area = 6 a ^ 2 = 6 * 10 * 10 = 600 each quart covers 20 sqr ft thus total number of quarts = 600 / 10 = 60 cost will be 60 * 3.2 = $ 192 ans : e" | geometry |
math_qa__6eg48aGXxW0UikMY | Walking 7/6 of his usual rate, a boy reaches his school 3 min early. Find his usual time to reach the school? Choose the correct choice from the following options: A) 21 B) 28 C) 99 D) 77 E) 66 | <gadget id="calculator">3 * 7</gadget>
<output>21</output>
<result>A</result> | A | 21 | Walking 7/6 of his usual rate, a boy reaches his school 3 min early. Find his usual time to reach the school? | {
"A": "21",
"B": "28",
"C": "99",
"D": "77",
"E": "66"
} | multiply(3, 7) | multiply(n0,n2)| | "speed ratio = 1 : 7 / 6 = 6 : 7 time ratio = 7 : 6 1 - - - - - - - - 7 3 - - - - - - - - - ? = 21 m answer : a" | gain |
math_qa__1LNztBaf2bD87jib | In a rectangular coordinate system, what is the area of a triangle whose vertices have the coordinates (-1, 0), (7, 4), and (7, -4)?
Select the correct option
A) 29 B) 30 C) 31 D) 32 E) 33 | <gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">(8 * 4) / 2</gadget>
<output>16</output>
<gadget id="calculator">16 * 2</gadget>
<output>32</output>
<result>D</result> | D | 32 | In a rectangular coordinate system, what is the area of a triangle whose vertices have the coordinates (-1, 0), (7, 4), and (7, -4)? | {
"A": "29",
"B": "30",
"C": "31",
"D": "32",
"E": "33"
} | multiply(triangle_area(add(7, 1), 4), const_2) | add(n0,n2)|triangle_area(n3,#0)|multiply(#1,const_2) | the triangle is symmetric about the x - axis . the part above the x - axis forms a triangle with a base of 8 and a height of 4 . the area of this part is ( 1 / 2 ) ( 8 ) ( 4 ) . we can double this to find the area of the whole triangle . the total area is ( 2 ) ( 1 / 2 ) ( 8 ) ( 4 ) = 32 . the answer is d . | geometry |
math_qa__uigadJG9vFxElB9V | In a school of 850 boys, 40% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities? Choose the correct answer.
A) 125
B) 627
C) 187
D) 721
E) 159 | <gadget id="calculator">40 + 28</gadget>
<output>68</output>
<gadget id="calculator">68 + 10</gadget>
<output>78</output>
<gadget id="calculator">100 - 78</gadget>
<output>22</output>
<gadget id="calculator">850 * 22</gadget>
<output>18_700</output>
<gadget id="calculator">18_700 / 100</gadget>
<output>187</output>
<result>C</result> | C | 187 | In a school of 850 boys, 40% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities? | {
"A": "125",
"B": "627",
"C": "187",
"D": "721",
"E": "159"
} | divide(multiply(850, subtract(const_100, add(add(40, 28), 10))), const_100) | add(n1,n2)|add(n3,#0)|subtract(const_100,#1)|multiply(n0,#2)|divide(#3,const_100)| | "40 + 28 + 10 = 78 % 100 – 78 = 22 % 850 * 22 / 100 = 187 answer : c" | gain |
math_qa__RoKEr3QiSwHf4t3x | The price of a certain painting increased by 20% during the first year and decreased by 15% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price? Pick one.
A) 102 % B) 105 % C) 120 % D) 135 % E) 140 % | <gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">15 * 20</gadget>
<output>300</output>
<gadget id="calculator">300 / 100</gadget>
<output>3</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">2 + 100</gadget>
<output>102</output>
<result>A</result> | A | 102 | The price of a certain painting increased by 20% during the first year and decreased by 15% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price? | {
"A": "102 %",
"B": "105 %",
"C": "120 %",
"D": "135 %",
"E": "140 %"
} | add(subtract(subtract(20, 15), divide(multiply(15, 20), const_100)), const_100) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,const_100)|subtract(#1,#2)|add(#3,const_100)| | "assume that price is 100 price at the end of yr 1 : 100 + 20 = 120 price at the end of year 2 = 120 - 120 * 0.15 = 120 * 0.85 = 102 hence required answer = ( 102 / 100 ) * 100 % = 102 % answer is a ." | general |
math_qa__CSk4cNm2NL30YGMA | There are 7 books on a shelf, of which 2 are paperbacks and 5 are hardbacks. How many possible selections of 4 books from this shelf include at least one paperback? Select.
A) 30 B) 45 C) 50 D) 55 E) 60 | <gadget id="calculator">binomial(7, 4)</gadget>
<output>35</output>
<gadget id="calculator">binomial(5, 4)</gadget>
<output>5</output>
<gadget id="calculator">35 - 5</gadget>
<output>30</output>
<result>A</result> | A | 30 | There are 7 books on a shelf, of which 2 are paperbacks and 5 are hardbacks. How many possible selections of 4 books from this shelf include at least one paperback? | {
"A": "30",
"B": "45",
"C": "50",
"D": "55",
"E": "60"
} | subtract(choose(7, 4), choose(5, 4)) | choose(n0,n3)|choose(n2,n3)|subtract(#0,#1)| | "approach 1 at - least 1 paper back = total - no paper back 7 c 4 - 5 c 4 = 30 approach 2 at - least 1 paper back = 1 paper back , 3 hard back or 2 paper back 2 hard back = 2 c 1 * 5 c 3 + 2 c 2 * 5 c 2 = 30 answer is a" | probability |
math_qa__9LvATGnGd9BUvLjP | A man sold 18 toys for Rs. 25200, gaining thereby the cost price of 3 toy find the cost price of a toy Choose the correct choice from the following options:
A) s . 600
B) s . 800
C) s . 500
D) s . 900
E) s . 1200 | <gadget id="calculator">18 + 3</gadget>
<output>21</output>
<gadget id="calculator">25_200 / 21</gadget>
<output>1_200</output>
<result>E</result> | E | 1,200 | A man sold 18 toys for Rs. 25200, gaining thereby the cost price of 3 toy find the cost price of a toy | {
"A": "s . 600",
"B": "s . 800",
"C": "s . 500",
"D": "s . 900",
"E": "s . 1200"
} | divide(25200, add(18, 3)) | add(n0,n2)|divide(n1,#0) | let the cost of one toy = x . then , cost of 18 toys = 18 x . gain = 3 x . sp of 18 toys = rs . 25200 . gain = sp â € “ cp 3 x = 25200 â € “ 18 x 21 x = 25200 x = rs . 1200 . answer : option e | gain |
math_qa__06zQHSow81iNyxnC | Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 3% more. She would get how much? Answers:
A) 9920
B) 96288
C) 26667
D) 1662
E) 2882 | <gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">9_200 - 8_000</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 3</gadget>
<output>400</output>
<gadget id="calculator">400 / 8_000</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(3/100) + (1/20)</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/25) * 8_000</gadget>
<output>640</output>
<gadget id="calculator">640 * 3</gadget>
<output>1_920</output>
<gadget id="calculator">1_920 + 8_000</gadget>
<output>9_920</output>
<result>A</result> | A | 9,920 | Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 3% more. She would get how much? | {
"A": "9920",
"B": "96288",
"C": "26667",
"D": "1662",
"E": "2882"
} | add(multiply(multiply(add(divide(3, const_100), divide(divide(subtract(9200, 8000), 3), 8000)), 8000), 3), 8000) | divide(n3,const_100)|subtract(n1,n0)|divide(#1,n2)|divide(#2,n0)|add(#0,#3)|multiply(n0,#4)|multiply(n2,#5)|add(n0,#6)| | "( 8000 * 3 * 3 ) / 100 = 720 9200 - - - - - - - - 9920 answer : a" | gain |
math_qa__AtI9Bc89KqEjWIGb | In a graduating class of 232 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number I and the smallest possible number of students that could have taken both geometry and biology? Choose one: A) 144 B) 119 C) 113 D) 88 E) 31 | <gadget id="calculator">144 + 119</gadget>
<output>263</output>
<gadget id="calculator">263 - 232</gadget>
<output>31</output>
<gadget id="calculator">119 - 31</gadget>
<output>88</output>
<result>D</result> | D | 88 | In a graduating class of 232 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number I and the smallest possible number of students that could have taken both geometry and biology? | {
"A": "144",
"B": "119",
"C": "113",
"D": "88",
"E": "31"
} | subtract(119, subtract(add(144, 119), 232)) | add(n1,n2)|subtract(#0,n0)|subtract(n2,#1) | official solution : first of all , notice that since 144 took geometry and 119 took biology , then the number of students who took both geometry and biology can not be greater than 119 . { total } = { geometry } + { biology } - { both } + { neither } ; 232 = 144 + 119 - { both } + { neither } ; { both } = 31 + { neither } . { both } is minimized when { neither } is 0 . in this case { both } = 31 . the greatest possible number i of students that could have taken both geometry and biology , is 119 . thus , the answer is 119 - 31 = 88 . answer : d . | other |
math_qa__LjcWxVplfbrdinsk | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 60 units raises the average to 55 units per day, what is the value of n ? Choose the correct choice from the following: A) 30 B) 18 C) 10 D) 9 E) 1 | <gadget id="calculator">60 - 50</gadget>
<output>10</output>
<gadget id="calculator">55 - 50</gadget>
<output>5</output>
<gadget id="calculator">10 / 5</gadget>
<output>2</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<result>E</result> | E | 1 | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 60 units raises the average to 55 units per day, what is the value of n ? | {
"A": "30",
"B": "18",
"C": "10",
"D": "9",
"E": "1"
} | subtract(divide(subtract(60, 50), subtract(55, 50)), const_1) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,#1)|subtract(#2,const_1)| | "( average production for n days ) * n = ( total production for n days ) - - > 50 n = ( total production for n days ) ; ( total production for n days ) + 60 = ( average production for n + 1 days ) * ( n + 1 ) - - > 50 n + 60 = 55 * ( n + 1 ) - - > n = 1 . answer : e ." | general |
math_qa__GsWcH83y9PtvLaGw | Think of a number, divide it by 4 and add 9 to it. The result is 15. What is the number thought of? Select
A) 24 B) 77 C) 297 D) 267 E) 29 | <gadget id="calculator">15 - 9</gadget>
<output>6</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<result>A</result> | A | 24 | Think of a number, divide it by 4 and add 9 to it. The result is 15. What is the number thought of? | {
"A": "24",
"B": "77",
"C": "297",
"D": "267",
"E": "29"
} | multiply(subtract(15, 9), 4) | subtract(n2,n1)|multiply(n0,#0)| | answer : a | general |
math_qa__Czy2gWdmyFmJQyZB | In a new housing development, trees are to be planted along the sidewalk of a certain street. Each tree takes up one square foot of sidewalk space, and there are to be 10 feet between each tree. How many trees can be planted if the road is 166 feet long? Choose the correct answer
A) 8 B) 9 C) 10 D) 11 E) 16 | <gadget id="calculator">166 - 1</gadget>
<output>165</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">165 / 11</gadget>
<output>15</output>
<gadget id="calculator">15 + 1</gadget>
<output>16</output>
<result>E</result> | E | 16 | In a new housing development, trees are to be planted along the sidewalk of a certain street. Each tree takes up one square foot of sidewalk space, and there are to be 10 feet between each tree. How many trees can be planted if the road is 166 feet long? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "16"
} | add(divide(subtract(166, const_1), add(10, const_1)), const_1) | add(n0,const_1)|subtract(n1,const_1)|divide(#1,#0)|add(#2,const_1)| | "let t be the number of trees . then the length required for trees on the sidewalk will be 1 * t = t to maximize the number of trees , the number of 10 feet spaces between trees should be 1 less than total number of trees . for example , if there are 3 trees , then there should be 2 spaces between them . so the number of 10 feet spaces will be t - 1 . then , the length of sidewalk required for 10 feet spaces will be 10 * ( t - 1 ) it is given that total lenght of sidewalk is 166 feet . or 10 ( t - 1 ) + t = 166 or 10 t - 10 + t = 166 or t = 16 answer : - e" | geometry |
math_qa__Nx6yDXH6ojKxscA8 | A cube is painted red on all faces. It is then cut into 27 equal smaller cubes. How many L cubes are painted on only 2 faces?
Choices
A) 12 B) 8 C) 6 D) 10 E) 16 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">27 ** (1/3)</gadget>
<output>3</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<result>A</result> | A | 12 | A cube is painted red on all faces. It is then cut into 27 equal smaller cubes. How many L cubes are painted on only 2 faces? | {
"A": "12",
"B": "8",
"C": "6",
"D": "10",
"E": "16"
} | multiply(const_4, power(27, divide(const_1, const_3))) | divide(const_1,const_3)|power(n0,#0)|multiply(#1,const_4)| | "1 ) draw a simple cube 2 ) draw 9 squares on each face of the cube ( so that it looks like a rubik ' s cube ) - this is what the cube will look like when it ' s cut into 27 equal smaller cubes . 3 ) remember that the outside of the cube is the part that ' s painted . . . . the mini - cubes with 2 painted sides are all on the edge of the cube , in themiddleof the edge . there are 4 in front , 4 in back and 4 more on thestripthat runs around the left / top / right / bottom of the cube . l = 4 + 4 + 4 = 12 . answer a" | geometry |
math_qa__DipfaS2X3uh5wpmy | Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the game remainder in each case. Then sum of the digits in N is : Choose the most appropriate option.
A) 4 B) 5 C) 6 D) 8 E) 9 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 + 2</gadget>
<output>4</output>
<result>A</result> | A | 4 | Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the game remainder in each case. Then sum of the digits in N is : | {
"A": "4",
"B": "5",
"C": "6",
"D": "8",
"E": "9"
} | add(add(const_1, const_1), const_2) | add(const_1,const_1)|add(#0,const_2) | solution n = h . c . f . of ( 4665 - 1305 ) , ( 6905 - 4665 ) and ( 6905 - 1305 ) = h . c . f . of 3360 , 2240 and 5600 = 1120 . sum of digits in n = ( 1 + 1 + 2 + 0 ) = 4 . answer a | general |
math_qa__eLTbL50kGEdj0YTT | A train running at a speed of 36 km/h passes an electric pole in 15 seconds. In how many seconds will the whole train pass a 380-meter long platform?
Choose the correct choice.
A) 47 B) 49 C) 51 D) 53 E) 55 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">10 * 15</gadget>
<output>150</output>
<gadget id="calculator">150 + 380</gadget>
<output>530</output>
<gadget id="calculator">530 / 10</gadget>
<output>53</output>
<result>D</result> | D | 53 | A train running at a speed of 36 km/h passes an electric pole in 15 seconds. In how many seconds will the whole train pass a 380-meter long platform? | {
"A": "47",
"B": "49",
"C": "51",
"D": "53",
"E": "55"
} | divide(add(multiply(multiply(36, const_0_2778), 15), 380), multiply(36, const_0_2778)) | multiply(n0,const_0_2778)|multiply(n1,#0)|add(n2,#1)|divide(#2,#0)| | "let the length of the train be x meters . when a train crosses an electric pole , the distance covered is its own length x . speed = 36 km / h = 36000 m / 3600 s = 10 m / s x = 15 * 10 = 150 m . the time taken to pass the platform = ( 150 + 380 ) / 10 = 53 seconds the answer is d ." | physics |
math_qa__bn6nyfuBuUC62AJN | A train running at the speed of 60 km/hr crosses a pole in 21 sec. What is the length of the train? Choose the correct option.
A) 350 m B) 490 m C) 115 m D) 210 m E) 150 m | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 21</gadget>
<output>350</output>
<result>A</result> | A | 350 | A train running at the speed of 60 km/hr crosses a pole in 21 sec. What is the length of the train? | {
"A": "350 m",
"B": "490 m",
"C": "115 m",
"D": "210 m",
"E": "150 m"
} | multiply(divide(multiply(60, const_1000), const_3600), 21) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 * 5 / 18 = 50 / 3 m / sec length of the train = speed * time = 50 / 3 * 21 = 350 m answer : a" | physics |
math_qa__S8U6xHBpmJavqQ0x | The sum of the first 70 positive even integers is 4,970. What is the sum of the first 70 odd integers? Pick:
A) 4500 B) 4600 C) 4300 D) 4900 E) 5000 | <gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">70 / 2</gadget>
<output>35</output>
<gadget id="calculator">140 * 35</gadget>
<output>4_900</output>
<result>D</result> | D | 4,900 | The sum of the first 70 positive even integers is 4,970. What is the sum of the first 70 odd integers? | {
"A": "4500",
"B": "4600",
"C": "4300",
"D": "4900",
"E": "5000"
} | multiply(multiply(70, const_2), divide(70, const_2)) | divide(n0,const_2)|multiply(n0,const_2)|multiply(#0,#1) | sum of first n even numbers = n ( n + 1 ) = 4970 sum of first n odd numbers = n ^ 2 = 70 * 70 = 4900 ( here n = 70 ) answer : d | general |
math_qa__fyitCCJXZs9unjZF | a family consists of two grandparents , two parents , and 3 grandchildren . the average age of the grandparents is 64 years , the average age of the parents is 39 years , and the average age of the grandchildren is 6 years . what is the average age ( in years ) of the family ? Pick:
A) 31
B) 32
C) 33
D) 34
E) 35 | <gadget id="calculator">64 * 2</gadget>
<output>128</output>
<gadget id="calculator">39 * 2</gadget>
<output>78</output>
<gadget id="calculator">128 + 78</gadget>
<output>206</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">206 + 18</gadget>
<output>224</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">224 / 7</gadget>
<output>32</output>
<result>B</result> | B | 32 | a family consists of two grandparents , two parents , and 3 grandchildren . the average age of the grandparents is 64 years , the average age of the parents is 39 years , and the average age of the grandchildren is 6 years . what is the average age ( in years ) of the family ? | {
"A": "31",
"B": "32",
"C": "33",
"D": "34",
"E": "35"
} | divide(add(add(multiply(64, const_2), multiply(39, const_2)), multiply(6, 3)), add(3, const_4)) | add(n0,const_4)|multiply(n1,const_2)|multiply(n2,const_2)|multiply(n0,n3)|add(#1,#2)|add(#4,#3)|divide(#5,#0) | total age of the grandparents = 64 ã — 2 = 128 total age of the parents = 39 ã — 2 = 78 total age of the grandchildren = 6 ã — 3 = 18 average age of the family = ( 128 + 78 + 18 ) / 7 = 224 / 7 = 32 years the answer is b . | general |
math_qa__WTHszedQjAAGzsaN | If 0.5% of A =70 paise, then the value of A is ? Choose one
A) rs . 170 B) rs . 140 C) rs . 1.70 D) rs . 4.25 E) none | <gadget id="calculator">70 / 0.5</gadget>
<output>140</output>
<result>B</result> | B | 140 | If 0.5% of A =70 paise, then the value of A is ? | {
"A": "rs . 170",
"B": "rs . 140",
"C": "rs . 1.70",
"D": "rs . 4.25",
"E": "none"
} | divide(70, 0.5) | divide(n1,n0)| | "answer ∵ 0.5 / 100 of a = 70 / 100 ∴ a = rs . ( 70 / 0.5 ) = rs . 140 correct option : b" | gain |
math_qa__QkJxlcIlBJcc8uk6 | Darcy lives 1.5 miles from work. She can walk to work at a constant rate of 3 miles per hour, or she can ride the train to work at a constant rate of 20 miles per hour. If she rides the train, there is an additional x minutes spent walking to the nearest train station, waiting for the train, and walking from the final train station to her work. If it takes Darcy a total of 15 more minutes to commute to work by walking than it takes her to commute to work by riding the train, what is the value of x?
Choices.
A) 10.5
B) 15
C) 25.5
D) 30
E) 60 | <gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 - 15</gadget>
<output>15</output>
<gadget id="calculator">20 / 1.5</gadget>
<output>13.333333</output>
<gadget id="calculator">60 / 13.333333</gadget>
<output>4.5</output>
<gadget id="calculator">15 - 4.5</gadget>
<output>10.5</output>
<result>A</result> | A | 10.5 | Darcy lives 1.5 miles from work. She can walk to work at a constant rate of 3 miles per hour, or she can ride the train to work at a constant rate of 20 miles per hour. If she rides the train, there is an additional x minutes spent walking to the nearest train station, waiting for the train, and walking from the final train station to her work. If it takes Darcy a total of 15 more minutes to commute to work by walking than it takes her to commute to work by riding the train, what is the value of x? | {
"A": "10.5",
"B": "15",
"C": "25.5",
"D": "30",
"E": "60"
} | subtract(subtract(divide(const_60, const_2), 15), divide(const_60, divide(20, 1.5))) | divide(const_60,const_2)|divide(n2,n0)|divide(const_60,#1)|subtract(#0,n3)|subtract(#3,#2) | the time it takes darcy to walk to work is ( 1.5 / 3 ) * 60 = 30 minutes the time it takes darcy to take the train is ( 1.5 / 20 ) * 60 + x = 4.5 + x minutes it takes 15 minutes longer to walk , so 30 = 4.5 + x + 15 x = 10.5 minutes answer : a | physics |
math_qa__IOHDx4SAWopXYZwI | The sale price of a trolley bag including the sale tax is Rs. 280. The rate of sale tax is 12% . If the shopkeeper has made a profit of 25%, the cost price of the trolley bag is:
Options:
A) rs 200 B) rs 220 C) rs 260 D) rs 280 E) none of these | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">280 * (3/25)</gadget>
<output>168/5 = around 33.6</output>
<gadget id="calculator">280 - (168/5)</gadget>
<output>1_232/5 = around 246.4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(1_232/5) / (5/4)</gadget>
<output>4_928/25 = around 197.12</output>
<result>A</result> | A | 200 | The sale price of a trolley bag including the sale tax is Rs. 280. The rate of sale tax is 12% . If the shopkeeper has made a profit of 25%, the cost price of the trolley bag is: | {
"A": "rs 200",
"B": "rs 220",
"C": "rs 260",
"D": "rs 280",
"E": "none of these"
} | divide(subtract(280, multiply(280, divide(12, const_100))), add(divide(25, const_100), const_1)) | divide(n1,const_100)|divide(n2,const_100)|add(#1,const_1)|multiply(n0,#0)|subtract(n0,#3)|divide(#4,#2)| | "explanation : 112 % of s . p . = 280 s . p . = rs . ( 280 x 100 / 112 ) = rs . 250 . c . p . = rs ( 100 / 125 x 250 ) = rs 200 answer : a" | gain |
math_qa__dbZVdp0Zc3KXA42J | In what time will a train 120 meters long completely pass an electric pole, if it travels at a speed of 60kmph. Choose the correct choice from the following choices:
A) 6.18 B) 5.18 C) 4.18 D) 4.18 E) 7.18 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">120 / (50/3)</gadget>
<output>36/5 = around 7.2</output>
<result>E</result> | E | 7.18 | In what time will a train 120 meters long completely pass an electric pole, if it travels at a speed of 60kmph. | {
"A": "6.18",
"B": "5.18",
"C": "4.18",
"D": "4.18",
"E": "7.18"
} | divide(120, multiply(60, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "sol . speed = [ 60 x 5 / 18 ] m / sec = 16.7 m / sec . time taken = ( 120 / 16.7 ) sec = 7.18 sec . answer e" | physics |
math_qa__usG68gnylXtFe5Lo | A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price e of the machine? Choose the correct choice.
A) 81
B) 100
C) 120
D) 135
E) 160 | <gadget id="calculator">90 * 20</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">90 + 18</gadget>
<output>108</output>
<gadget id="calculator">108 * 100</gadget>
<output>10_800</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">10_800 / 90</gadget>
<output>120</output>
<result>C</result> | C | 120 | A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price e of the machine? | {
"A": "81",
"B": "100",
"C": "120",
"D": "135",
"E": "160"
} | divide(multiply(add(90, divide(multiply(90, 20), const_100)), const_100), multiply(multiply(const_3, const_3), 10)) | multiply(n0,n2)|multiply(const_3,const_3)|divide(#0,const_100)|multiply(n1,#1)|add(n0,#2)|multiply(#4,const_100)|divide(#5,#3)| | "since the wholesale price was $ 90 and the profit was 20 % of the wholesale price ( [ . 2 ] [ 90 ] = $ 18 ) , the retail price would have to be above $ 108 , but not that much greater than that . let ' s start by testing answer c : $ 120 . . . . if . . . . . retail price e = $ 120 10 % discount off = $ 120 - ( . 1 ) ( 120 ) = 120 - 12 = 108 20 % profit on wholesale price = 90 + ( . 2 ) ( 90 ) = 90 + 18 = 108 these two numbers match , so this must be the answer ! final answer : [ reveal ] spoiler : c" | gain |
math_qa__QCf7BiMDgPfXWbxx | How many numbers from 49 to 79 are exactly divisible by 11? Choose the correct choice from the following options: A) 5 B) 7 C) 9 D) 3 E) 12 | <gadget id="calculator">79 / 11</gadget>
<output>79/11 = around 7.181818</output>
<gadget id="calculator">floor(79/11)</gadget>
<output>7</output>
<gadget id="calculator">7 * 11</gadget>
<output>77</output>
<gadget id="calculator">49 / 11</gadget>
<output>49/11 = around 4.454545</output>
<gadget id="calculator">floor(49/11)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 11</gadget>
<output>55</output>
<gadget id="calculator">77 - 55</gadget>
<output>22</output>
<gadget id="calculator">22 / 11</gadget>
<output>2</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<result>D</result> | D | 3 | How many numbers from 49 to 79 are exactly divisible by 11? | {
"A": "5",
"B": "7",
"C": "9",
"D": "3",
"E": "12"
} | add(divide(subtract(multiply(floor(divide(79, 11)), 11), multiply(add(floor(divide(49, 11)), const_1), 11)), 11), const_1) | divide(n1,n2)|divide(n0,n2)|floor(#0)|floor(#1)|add(#3,const_1)|multiply(n2,#2)|multiply(n2,#4)|subtract(#5,#6)|divide(#7,n2)|add(#8,const_1)| | "49 / 11 = 4 and 79 / 11 = 7 = = > 7 - 4 = 3 numbers answer : d" | general |
math_qa__CckUC8uneqG7BorR | The jogging track in a sports complex is 640 m in circumference. Lata and Geeta start from the same point and walk in opposite directions at 4.2 km/hr and 3.8 km/hr respectively. They will meet for the first time in? Choose the correct choice from the following.
A) 2.9 min
B) 3.9 min
C) 4.2 min
D) 4.8 min
E) 5.6 min | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">640 * 60</gadget>
<output>38_400</output>
<gadget id="calculator">4.2 * 1_000</gadget>
<output>4_200</output>
<gadget id="calculator">3.8 * 1_000</gadget>
<output>3_800</output>
<gadget id="calculator">4_200 + 3_800</gadget>
<output>8_000</output>
<gadget id="calculator">38_400 / 8_000</gadget>
<output>24/5 = around 4.8</output>
<result>D</result> | D | 4.8 | The jogging track in a sports complex is 640 m in circumference. Lata and Geeta start from the same point and walk in opposite directions at 4.2 km/hr and 3.8 km/hr respectively. They will meet for the first time in? | {
"A": "2.9 min",
"B": "3.9 min",
"C": "4.2 min",
"D": "4.8 min",
"E": "5.6 min"
} | divide(multiply(640, multiply(const_1, const_60)), add(multiply(4.2, const_1000), multiply(3.8, const_1000))) | multiply(const_1,const_60)|multiply(n1,const_1000)|multiply(n2,const_1000)|add(#1,#2)|multiply(n0,#0)|divide(#4,#3) | clearly , the two will meet when they are 640 m apart . to be ( 4.2 + 3.8 ) = 8.0 km apart , they take 1 hour . that is 60 min . to be 640 m apart , they take ( 640 / 8000 * 60 ) min = 4.8 min . answer : d | general |
math_qa__0MZe64BIPo3VC9pS | Village X has a population of 68000, which is decreasing at the rate of 1200 per year. Village Y has a population of 42000, which is increasing at the rate of 800 per year .in how many years will the population of the two villages be equal? Select
A) 15 B) 19 C) 11 D) 18 E) 13 | <gadget id="calculator">68_000 - 42_000</gadget>
<output>26_000</output>
<gadget id="calculator">800 + 1_200</gadget>
<output>2_000</output>
<gadget id="calculator">26_000 / 2_000</gadget>
<output>13</output>
<result>E</result> | E | 13 | Village X has a population of 68000, which is decreasing at the rate of 1200 per year. Village Y has a population of 42000, which is increasing at the rate of 800 per year .in how many years will the population of the two villages be equal? | {
"A": "15",
"B": "19",
"C": "11",
"D": "18",
"E": "13"
} | divide(subtract(68000, 42000), add(800, 1200)) | add(n1,n3)|subtract(n0,n2)|divide(#1,#0) | let the population of two villages be equal after p years then , 68000 - 1200 p = 42000 + 800 p 2000 p = 26000 p = 13 answer is e . | general |
math_qa__k1kLUeJoZB4dHXe7 | If a man lost 4% by selling oranges at the rate of 16 a rupee at how many a rupee must he sell them to gain 28%? Choose one: A) 12 B) 13 C) 14 D) 15 E) 10 | <gadget id="calculator">100 - 4</gadget>
<output>96</output>
<gadget id="calculator">96 * 16</gadget>
<output>1_536</output>
<gadget id="calculator">100 + 28</gadget>
<output>128</output>
<gadget id="calculator">1_536 / 128</gadget>
<output>12</output>
<result>A</result> | A | 12 | If a man lost 4% by selling oranges at the rate of 16 a rupee at how many a rupee must he sell them to gain 28%? | {
"A": "12",
"B": "13",
"C": "14",
"D": "15",
"E": "10"
} | divide(multiply(subtract(const_100, 4), 16), add(const_100, 28)) | add(n2,const_100)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,#0)| | "96 % - - - - 16 128 % - - - - ? 96 / 128 * 16 = 12 answer : a" | gain |
math_qa__d0FHcJlSlTaleOTc | A man purchased 15 pens, 12 books, 10 pencils and 5 erasers. The cost of each pen is Rs.36, each book is Rs.45, each pencil is Rs.8, and the cost of each eraser is Rs.40 less than the combined costs of pen and pencil. Find the total amount spent?
Select
A) 2388 B) 2337 C) 1192 D) 2827 E) 1180 | <gadget id="calculator">15 * 36</gadget>
<output>540</output>
<gadget id="calculator">12 * 45</gadget>
<output>540</output>
<gadget id="calculator">540 + 540</gadget>
<output>1_080</output>
<gadget id="calculator">10 * 8</gadget>
<output>80</output>
<gadget id="calculator">1_080 + 80</gadget>
<output>1_160</output>
<result>E</result> | E | 1,180 | A man purchased 15 pens, 12 books, 10 pencils and 5 erasers. The cost of each pen is Rs.36, each book is Rs.45, each pencil is Rs.8, and the cost of each eraser is Rs.40 less than the combined costs of pen and pencil. Find the total amount spent? | {
"A": "2388",
"B": "2337",
"C": "1192",
"D": "2827",
"E": "1180"
} | add(add(multiply(15, 36), multiply(12, 45)), multiply(10, 8)) | multiply(n0,n4)|multiply(n1,n5)|multiply(n2,n6)|add(#0,#1)|add(#3,#2) | explanation : cost of each eraser = ( 36 + 8 - 40 ) = rs . 4 required amount = 15 * 36 + 12 * 45 + 10 * 8 + 5 * 4 540 + 540 + 80 + 20 = rs . 1180 answer : e | general |
math_qa__hzILucnhGEL12Aux | John was 22 years old when he married Betty. They just celebrated their fifth wedding anniversary, and Betty's age is now 7/9 of John's. How old is Betty?
Choose the correct answer:
A) 24 B) 26 C) 28 D) 21 E) 32 | <gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>
<gadget id="calculator">22 + 4</gadget>
<output>26</output>
<gadget id="calculator">(7/9) * 26</gadget>
<output>182/9 = around 20.222222</output>
<result>D</result> | D | 21 | John was 22 years old when he married Betty. They just celebrated their fifth wedding anniversary, and Betty's age is now 7/9 of John's. How old is Betty? | {
"A": "24",
"B": "26",
"C": "28",
"D": "21",
"E": "32"
} | multiply(divide(7, 9), add(22, const_4)) | add(n0,const_4)|divide(n1,n2)|multiply(#0,#1) | assume betty ' s age on marriage = x years . john ' s age on marriage = 22 john ' s age after 5 years = 27 years . betty ' s age after 5 years = x + 5 given : x + 5 = 7 / 9 ( 27 ) = 21 therefore betty ' s current age = 21 option d | general |
math_qa__KwSXxTAwxvUYZK6Z | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 60% profit? Choices: A) 1024 B) 960 C) 277 D) 266 E) 121 | <gadget id="calculator">832 - 448</gadget>
<output>384</output>
<gadget id="calculator">384 / 2</gadget>
<output>192</output>
<gadget id="calculator">832 - 192</gadget>
<output>640</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 + (3/5)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">640 * (8/5)</gadget>
<output>1_024</output>
<result>A</result> | A | 1,024 | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 60% profit? | {
"A": "1024",
"B": "960",
"C": "277",
"D": "266",
"E": "121"
} | multiply(subtract(832, divide(subtract(832, 448), const_2)), add(const_1, divide(60, const_100))) | divide(n2,const_100)|subtract(n0,n1)|add(#0,const_1)|divide(#1,const_2)|subtract(n0,#3)|multiply(#2,#4) | let c . p . = rs . x . then , 832 - x = x - 448 2 x = 1280 = > x = 640 required s . p . = 160 % of rs . 640 = 160 / 100 * 640 = rs . 1024 . answer : a | gain |
math_qa__4Pzmq9Fk0LRGYsKy | Workers at a campaign office have 1000 fliers to send out. If they send out 1/5 of them in the morning and 1/4 of the remaining ones out during the afternoon, how many are left for the next day? Choose one
A) 300 B) 800 C) 1100 D) 600 E) 1900 | <gadget id="calculator">1_000 / 5</gadget>
<output>200</output>
<gadget id="calculator">1_000 - 200</gadget>
<output>800</output>
<gadget id="calculator">800 / 4</gadget>
<output>200</output>
<gadget id="calculator">800 - 200</gadget>
<output>600</output>
<result>D</result> | D | 600 | Workers at a campaign office have 1000 fliers to send out. If they send out 1/5 of them in the morning and 1/4 of the remaining ones out during the afternoon, how many are left for the next day? | {
"A": "300",
"B": "800",
"C": "1100",
"D": "600",
"E": "1900"
} | subtract(subtract(1000, divide(1000, 5)), divide(subtract(1000, divide(1000, 5)), 4)) | divide(n0,n2)|subtract(n0,#0)|divide(#1,n4)|subtract(#1,#2)| | "( 1 / 5 ) * 1000 = 200 remaining = 1000 - 200 = 800 ( 1 / 4 ) of remaining = ( 1 / 4 ) * 800 = 200 remaining now = 800 - 200 = 600 answer : option d" | physics |
math_qa__68znoTVPAQ9LpmaJ | A cycle is bought for Rs.1000 and sold for Rs.1080, find the gain percent? Options:
A) 11 B) 20 C) 12 D) 40 E) 8 | <gadget id="calculator">1_080 - 1_000</gadget>
<output>80</output>
<gadget id="calculator">80 / 1_000</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/25) * 100</gadget>
<output>8</output>
<result>E</result> | E | 8 | A cycle is bought for Rs.1000 and sold for Rs.1080, find the gain percent? | {
"A": "11",
"B": "20",
"C": "12",
"D": "40",
"E": "8"
} | multiply(divide(subtract(1080, 1000), 1000), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "1000 - - - - 80 100 - - - - ? = > 8 % answer : e" | gain |
math_qa__yCD8HTRxizlkWusE | If x^2+(1/x^2)=2, x^4+(1/x^4)=? Choose the correct choice from the following answers
A) 10
B) 2
C) 12
D) 14
E) 15 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<result>B</result> | B | 2 | If x^2+(1/x^2)=2, x^4+(1/x^4)=? | {
"A": "10",
"B": "2",
"C": "12",
"D": "14",
"E": "15"
} | subtract(power(2, 2), 2) | power(n0,n0)|subtract(#0,n0) | - > x ^ 4 + ( 1 / x ^ 4 ) = ( x ^ 2 ) ^ 2 + ( 1 / x ^ 2 ) ^ 2 = ( x ^ 2 + 1 / x ^ 2 ) ^ 2 - 2 x ^ 2 ( 1 / x ^ 2 ) = 2 ^ 2 - 2 = 2 . thus , the answer is b . | general |
math_qa__gbap5W9nUvPY5vhS | In the x-y plane, point (x, y) is a lattice point if both x and y are integers. A square has a center at (0, 0) and side = 4. Some points, such as the center (0, 0), are inside the square, but a point such as (0, 2) is on the square but not in the square. How many lattice points are in the square?
Select: A) 10 B) 9 C) 8 D) 5 E) 12 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<result>B</result> | B | 9 | In the x-y plane, point (x, y) is a lattice point if both x and y are integers. A square has a center at (0, 0) and side = 4. Some points, such as the center (0, 0), are inside the square, but a point such as (0, 2) is on the square but not in the square. How many lattice points are in the square? | {
"A": "10",
"B": "9",
"C": "8",
"D": "5",
"E": "12"
} | add(multiply(4, 2), const_1) | multiply(n2,n6)|add(#0,const_1) | the lattice points that are in the square , that lie on the x and y axes , are ( 0 , 0 ) , ( 0 , 1 ) , ( 1 , 0 ) , ( 0 , - 1 ) , and ( - 1 , 0 ) . the lattice points in the square and not on the x and y axes are ( 1 , 1 ) , ( - 1 , 1 ) , ( 1 , - 1 ) , and ( - 1 , - 1 ) . there are a total of 9 lattice points in the square . answer : b | general |
math_qa__U8GCK0qI1eC3D6Tm | A boy is travelling from his home to school at 5km/hr and reached 5min late. Next day he travelled at 10km/hr and reached 10min early. Distance between home and school?
Choose the most appropriate option:
A) 2.5 km B) 3 km C) 4 km D) 5.6 km E) 6.5 km | <gadget id="calculator">5 / 60</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">10 / 60</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/12) + (1/6)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/4) / (1/10)</gadget>
<output>5/2 = around 2.5</output>
<result>A</result> | A | 2.5 | A boy is travelling from his home to school at 5km/hr and reached 5min late. Next day he travelled at 10km/hr and reached 10min early. Distance between home and school? | {
"A": "2.5 km",
"B": "3 km",
"C": "4 km",
"D": "5.6 km",
"E": "6.5 km"
} | divide(add(divide(5, const_60), divide(10, const_60)), divide(const_1, 10)) | divide(n1,const_60)|divide(n3,const_60)|divide(const_1,n2)|add(#0,#1)|divide(#3,#2)| | "let the distance be x t 1 = x / 5 hr t 2 = x / 10 hr difference in time = 5 + 10 = 15 = 1 / 4 hr x / 5 - x / 10 = 1 / 4 x / 10 = 1 / 4 x = 2.5 km answer is a" | physics |
math_qa__UU48OqtaDVBgAfny | A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 168 km downstream. Choose one
A) 4 hours
B) 5 hours
C) 6 hours
D) 7 hours
E) 8 hours | <gadget id="calculator">16 + 5</gadget>
<output>21</output>
<gadget id="calculator">168 / 21</gadget>
<output>8</output>
<result>E</result> | E | 8 | A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 168 km downstream. | {
"A": "4 hours",
"B": "5 hours",
"C": "6 hours",
"D": "7 hours",
"E": "8 hours"
} | divide(168, add(16, 5)) | add(n0,n1)|divide(n2,#0)| | "explanation : it is very important to check , if the boat speed given is in still water or with water or against water . because if we neglect it we will not reach on right answer . i just mentioned here because mostly mistakes in this chapter are of this kind only . lets see the question now . speed downstream = ( 16 + 5 ) = 21 kmph time = distance / speed = 168 / 21 = 8 hours option e" | physics |
math_qa__xqNzG0vSf9HuHjb6 | A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
Choose the correct choice from the following answers
A) 1898 B) 1098 C) 1000 D) 2008 E) 1082 | <gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">100 ** 3</gadget>
<output>1_000_000</output>
<gadget id="calculator">10 ** 3</gadget>
<output>1_000</output>
<gadget id="calculator">1_000_000 / 1_000</gadget>
<output>1_000</output>
<result>C</result> | C | 1,000 | A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained? | {
"A": "1898",
"B": "1098",
"C": "1000",
"D": "2008",
"E": "1082"
} | divide(power(power(10, const_2), const_3), power(10, const_3)) | power(n0,const_2)|power(n0,const_3)|power(#0,const_3)|divide(#2,#1) | along one edge , the number of small cubes that can be cut = 100 / 10 = 10 along each edge 10 cubes can be cut . ( along length , breadth and height ) . total number of small cubes that can be cut = 10 * 10 * 10 = 1000 answer : c | physics |
math_qa__MxhSW2WCtF0PApg6 | At what price must an Book costing $47.50 be marked in order that after deducting 10% from the list price. It may be sold at a profit of 25% on the cost price? Pick one.
A) 72.5
B) 55.5
C) 62.5
D) 82.5
E) 65.9 | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">47.5 * 125</gadget>
<output>5_937.5</output>
<gadget id="calculator">5_937.5 / 100</gadget>
<output>59.375</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">59.375 / 90</gadget>
<output>0.659722</output>
<gadget id="calculator">0.659722 * 100</gadget>
<output>65.9722</output>
<result>E</result> | E | 65.9 | At what price must an Book costing $47.50 be marked in order that after deducting 10% from the list price. It may be sold at a profit of 25% on the cost price? | {
"A": "72.5",
"B": "55.5",
"C": "62.5",
"D": "82.5",
"E": "65.9"
} | multiply(divide(divide(multiply(47.50, add(const_100, 25)), const_100), subtract(const_100, 10)), const_100) | add(n2,const_100)|subtract(const_100,n1)|multiply(n0,#0)|divide(#2,const_100)|divide(#3,#1)|multiply(#4,const_100)| | "e $ 62.50 cp = 47.50 sp = 47.50 * ( 125 / 100 ) = 59.375 mp * ( 90 / 100 ) = 59.375 mp = 65.9 e" | gain |
math_qa__ALf5bgul5Q3a6882 | If the sides of a triangle are 78 cm, 72 cm and 30 cm, what is its area? Choose the correct option
A) 120 cm 2 B) 765 cm 2 C) 1080 cm 2 D) 197 cm 2 E) 275 cm 2 | <gadget id="calculator">72 * 30</gadget>
<output>2_160</output>
<gadget id="calculator">2_160 / 2</gadget>
<output>1_080</output>
<result>C</result> | C | 1,080 | If the sides of a triangle are 78 cm, 72 cm and 30 cm, what is its area? | {
"A": "120 cm 2",
"B": "765 cm 2",
"C": "1080 cm 2",
"D": "197 cm 2",
"E": "275 cm 2"
} | divide(multiply(72, 30), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 78 cm , 72 cm and 30 cm is right angled , where the hypotenuse is 78 cm . area of the triangle = 1 / 2 * 72 * 30 = 1080 cm 2 answer : c" | geometry |
math_qa__cT3bXvx1khK6blJ7 | An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/5 %, then the amount invested at 11% was?
Choose the correct choice from the following answers:
A) 23777
B) 30000
C) 29977
D) 26777
E) 19871 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">9 + (3/5)</gadget>
<output>48/5 = around 9.6</output>
<gadget id="calculator">(48/5) / 100</gadget>
<output>12/125 = around 0.096</output>
<gadget id="calculator">100_000 * (12/125)</gadget>
<output>9_600</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">100_000 * (9/100)</gadget>
<output>9_000</output>
<gadget id="calculator">9_600 - 9_000</gadget>
<output>600</output>
<gadget id="calculator">11 / 100</gadget>
<output>11/100 = around 0.11</output>
<gadget id="calculator">(11/100) - (9/100)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">600 / (1/50)</gadget>
<output>30_000</output>
<result>B</result> | B | 30,000 | An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/5 %, then the amount invested at 11% was? | {
"A": "23777",
"B": "30000",
"C": "29977",
"D": "26777",
"E": "19871"
} | divide(subtract(multiply(100000, divide(add(9, divide(3, 5)), const_100)), multiply(100000, divide(9, const_100))), subtract(divide(11, const_100), divide(9, const_100))) | divide(n4,n5)|divide(n1,const_100)|divide(n2,const_100)|add(n1,#0)|multiply(n0,#1)|subtract(#2,#1)|divide(#3,const_100)|multiply(n0,#6)|subtract(#7,#4)|divide(#8,#5)| | "let the sum invested at 9 % be rs . x and that invested at 11 % be rs . ( 100000 - x ) . then , ( x * 9 * 1 ) / 100 + [ ( 100000 - x ) * 11 * 1 ] / 100 = ( 100000 * 48 / 5 * 1 / 100 ) ( 9 x + 1100000 - 11 x ) = 960000 x = 70000 sum invested at 9 % = rs . 70000 sum invested at 11 % = rs . ( 100000 - 70000 ) = rs . 30000 . answer : b" | gain |
math_qa__LsXBLR0CRzOZo86J | A shopkeeper loses 15%,if an article is sold for Rs. 170. What should be the selling price of the article to gain 20%? Choose one
A) s . 247
B) s . 248
C) s . 240
D) s . 229
E) s . 212 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">170 / (17/20)</gadget>
<output>200</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">200 * (1/5)</gadget>
<output>40</output>
<gadget id="calculator">200 + 40</gadget>
<output>240</output>
<result>C</result> | C | 240 | A shopkeeper loses 15%,if an article is sold for Rs. 170. What should be the selling price of the article to gain 20%? | {
"A": "s . 247",
"B": "s . 248",
"C": "s . 240",
"D": "s . 229",
"E": "s . 212"
} | add(divide(170, subtract(const_1, divide(15, const_100))), multiply(divide(170, subtract(const_1, divide(15, const_100))), divide(20, const_100))) | divide(n0,const_100)|divide(n2,const_100)|subtract(const_1,#0)|divide(n1,#2)|multiply(#3,#1)|add(#3,#4)| | "given that sp = rs . 170 and loss = 15 % cp = [ 100 ( sp ) ] / ( 100 - l % ) = ( 100 * 170 ) / 85 = 20 * 6 = rs . 200 . to get 20 % profit , new sp = [ ( 100 + p % ) cp ] / 100 = ( 200 * 120 ) / 100 = rs . 240 answer : c" | gain |
math_qa__vROfbmtSDAsBlG2W | Mary's income is 50 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income? Choices: A) 124 % B) 120 % C) 96 % D) 90 % E) 64 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/5) * (3/2)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 100</gadget>
<output>90</output>
<result>D</result> | D | 90 | Mary's income is 50 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income? | {
"A": "124 %",
"B": "120 %",
"C": "96 %",
"D": "90 %",
"E": "64 %"
} | multiply(multiply(subtract(const_1, divide(40, const_100)), add(const_1, divide(50, const_100))), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)| | "juan ' s income = 100 ( assume ) ; tim ' s income = 60 ( 40 percent less than juan ' s income ) ; mary ' s income = 90 ( 50 percent more than tim ' s income ) . thus , mary ' s income ( 90 ) is 90 % of juan ' s income ( 100 ) . answer : d ." | general |
math_qa__u5XgYLkHg52lZViL | Peter invests a sum of money and gets back an amount of $ 800 in 3 years . David invests an equal amount of money and gets an amount of $854 in 4 years. If both amounts were invested at the same rate (simple interest ) What was the sum of money invested ? Select the correct option:
A) 653 B) 664 C) 698 D) 744 E) 700 | <gadget id="calculator">854 - 800</gadget>
<output>54</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">(1/25) - (3/100)</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">54 / (1/100)</gadget>
<output>5_400</output>
<gadget id="calculator">5_400 * (3/100)</gadget>
<output>162</output>
<gadget id="calculator">800 - 162</gadget>
<output>638</output>
<result>A</result> | A | 653 | Peter invests a sum of money and gets back an amount of $ 800 in 3 years . David invests an equal amount of money and gets an amount of $854 in 4 years. If both amounts were invested at the same rate (simple interest ) What was the sum of money invested ? | {
"A": "653",
"B": "664",
"C": "698",
"D": "744",
"E": "700"
} | subtract(800, multiply(divide(subtract(854, 800), subtract(divide(4, const_100), divide(3, const_100))), divide(3, const_100))) | divide(n3,const_100)|divide(n1,const_100)|subtract(n2,n0)|subtract(#0,#1)|divide(#2,#3)|multiply(#4,#1)|subtract(n0,#5)| | "since both peter and david invested the same amount of money at the same rate , they would earn same interest per year . david invested for one year more than peter and hence he got interest amount for one more year . interest earned per year = amount received by david - amount received by peter = 854 - 800 = 54 interest earned for 3 years = 54 * 3 = 162 amount invested = 815 - 162 = 653 answer : a" | gain |
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