id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__wY57av8DMMzNva7Q | An army’s recruitment process included N rounds of selection tasks. For the first A rounds, the rejection percentage was 60 percent per round. For the next B rounds, the rejection percentage was 50 percent per round and for the remaining rounds, the selection percentage was 70 percent per round. If there were 100000 people who applied for the army and 245 were finally selected, what was the value of N? Select: A) 4 B) 5 C) 6 D) 8 E) 9 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">2 + 5</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<result>E</result> | E | 9 | An army’s recruitment process included N rounds of selection tasks. For the first A rounds, the rejection percentage was 60 percent per round. For the next B rounds, the rejection percentage was 50 percent per round and for the remaining rounds, the selection percentage was 70 percent per round. If there were 100000 people who applied for the army and 245 were finally selected, what was the value of N? | {
"A": "4",
"B": "5",
"C": "6",
"D": "8",
"E": "9"
} | add(add(const_2, add(const_1, const_4)), const_2) | add(const_1,const_4)|add(#0,const_2)|add(#1,const_2) | fastly i reduce 60 % till it gets closer to our required 2000 candidates step ( 1 ) 40000 accepted . step ( 2 ) another 40 % of 40000 = 16000 accepted . here it is quiet observable that if we further deduct candidate by 60 % it would change our probablity of easy going 2000 candidate . so i would get to second stage of recruitment where 50 % is accepted step ( 3 ) 50 % of 16000 = 8000 step ( 4 ) 50 % of 8000 = 4000 step ( 5 ) 50 % of 4000 = 2000 step ( 6 ) 50 % of 2000 = 1000 step ( 7 ) 50 % of 1000 = 500 step ( 8 ) 70 % of 500 = 350 step ( 9 ) 70 % of 350 = 245 ( our target ) total 9 steps required . ans e | general |
math_qa__OSEiQRV2f8Zer1OZ | When the price of an article was reduced by 30% its sale increased by 80%. What was the net effect on the sale? Choose the correct choice from the following choices
A) 26 % increase B) 44 % decrease C) 60 % increase D) 66 % increase E) 66 % decrease | <gadget id="calculator">80 + 100</gadget>
<output>180</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">180 * 70</gadget>
<output>12_600</output>
<gadget id="calculator">12_600 / 100</gadget>
<output>126</output>
<gadget id="calculator">126 - 100</gadget>
<output>26</output>
<result>A</result> | A | 26 | When the price of an article was reduced by 30% its sale increased by 80%. What was the net effect on the sale? | {
"A": "26 % increase",
"B": "44 % decrease",
"C": "60 % increase",
"D": "66 % increase",
"E": "66 % decrease"
} | subtract(divide(multiply(add(80, const_100), subtract(const_100, 30)), const_100), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|subtract(#3,const_100)| | "if n items are sold for $ p each , revenue is $ np . if we reduce the price by 30 % , the new price is 0.7 p . if we increase the number sold by 80 % , the new number sold is 1.8 n . so the new revenue is ( 0.7 p ) ( 1.8 n ) = 1.26 np , which is 1.26 times the old revenue , so is 26 % greater . answer : a" | gain |
math_qa__49rxHt3MoQpoWaN0 | If the simple interest on a certain sum of money for 4 years is one–fifth of the sum, then the rate of interest per annum is
Choose the correct option.
A) 4 % B) 7 % C) 6 % D) 5 % E) 3 % | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<result>D</result> | D | 5 | If the simple interest on a certain sum of money for 4 years is one–fifth of the sum, then the rate of interest per annum is | {
"A": "4 %",
"B": "7 %",
"C": "6 %",
"D": "5 %",
"E": "3 %"
} | divide(divide(const_100, add(const_1, const_4)), 4) | add(const_1,const_4)|divide(const_100,#0)|divide(#1,n0)| | "explanation : let the principal ( p ) be x then , simple interest ( si ) = x / 5 time ( t ) = 4 years rate of interest per annum ( r ) = ( 100 × si ) / pt = ( 100 × ( x / 5 ) / ( x × 4 ) = 20 / 4 = 5 % answer : option d" | gain |
math_qa__T3Bm3w8dEhiaVFjX | the average of 11 results is 60 . if the average of first 6 results is 58 and that of the last 6 is 63 , find the sixth result ?
Choose the correct choice
A) 50 B) 52 C) 65 D) 42 E) 66 | <gadget id="calculator">6 * 58</gadget>
<output>348</output>
<gadget id="calculator">6 * 63</gadget>
<output>378</output>
<gadget id="calculator">348 + 378</gadget>
<output>726</output>
<gadget id="calculator">11 * 60</gadget>
<output>660</output>
<gadget id="calculator">726 - 660</gadget>
<output>66</output>
<result>E</result> | E | 66 | the average of 11 results is 60 . if the average of first 6 results is 58 and that of the last 6 is 63 , find the sixth result ? | {
"A": "50",
"B": "52",
"C": "65",
"D": "42",
"E": "66"
} | subtract(add(multiply(6, 58), multiply(6, 63)), multiply(11, 60)) | multiply(n2,n3)|multiply(n2,n5)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2) | sixth result = 58 * 6 + 63 * 6 - 60 * 11 = 66 answer is e | general |
math_qa__Sg7DtuK1ZPvj4k3l | If a student loses 5 kilograms, he will weigh twice as much as his sister. Together they now weigh 116 kilograms. What is the student's present weight in kilograms? Pick one
A) 76 B) 77 C) 78 D) 79 E) 80 | <gadget id="calculator">116 - 5</gadget>
<output>111</output>
<gadget id="calculator">111 / 3</gadget>
<output>37</output>
<gadget id="calculator">116 - 37</gadget>
<output>79</output>
<result>D</result> | D | 79 | If a student loses 5 kilograms, he will weigh twice as much as his sister. Together they now weigh 116 kilograms. What is the student's present weight in kilograms? | {
"A": "76",
"B": "77",
"C": "78",
"D": "79",
"E": "80"
} | subtract(116, divide(subtract(116, 5), const_3)) | subtract(n1,n0)|divide(#0,const_3)|subtract(n1,#1)| | "let x be the weight of the sister . then the student ' s weight is 2 x + 5 . x + ( 2 x + 5 ) = 116 3 x = 111 x = 37 kg then the student ' s weight is 79 kg . the answer is d ." | other |
math_qa__CJWMJ4Z6QryH7tDP | Tom drives from town Q to town B, driving at a constant speed of 60 miles per hour. From town B Tom immediately continues to town C. The distance between Q and B is twice the distance between B and C. If the average speed of the whole journey was 36 mph, then what is Tom's speed driving from B to C in miles per hour? Select the correct option:
A) 12 B) 20 C) 24 D) 30 E) 36 | <gadget id="calculator">60 * 36</gadget>
<output>2_160</output>
<gadget id="calculator">36 * 3</gadget>
<output>108</output>
<gadget id="calculator">2_160 / 108</gadget>
<output>20</output>
<result>B</result> | B | 20 | Tom drives from town Q to town B, driving at a constant speed of 60 miles per hour. From town B Tom immediately continues to town C. The distance between Q and B is twice the distance between B and C. If the average speed of the whole journey was 36 mph, then what is Tom's speed driving from B to C in miles per hour? | {
"A": "12",
"B": "20",
"C": "24",
"D": "30",
"E": "36"
} | divide(multiply(60, 36), multiply(36, const_3)) | multiply(n0,n1)|multiply(n1,const_3)|divide(#0,#1) | let ' s assume that it takes 4 hours to go from point q to b . then the distance between them becomes 240 which makes distance between b and c 120 . ( 240 + 120 ) / ( 4 + x ) gives us the average speed which is 36 . you find x = 6 . so the question simplifies itself to 120 / 6 = 20 hence the answer is b . | physics |
math_qa__2RuP8vLkDmGvrL1J | A watch was sold at a loss of 10%. If it was sold for Rs.540 more, there would have been a gain of 8%. What is the cost price? Pick one.
A) 1000
B) 2998
C) 3000
D) 2788
E) 2991 | <gadget id="calculator">540 * 100</gadget>
<output>54_000</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">108 - 90</gadget>
<output>18</output>
<gadget id="calculator">54_000 / 18</gadget>
<output>3_000</output>
<result>C</result> | C | 3,000 | A watch was sold at a loss of 10%. If it was sold for Rs.540 more, there would have been a gain of 8%. What is the cost price? | {
"A": "1000",
"B": "2998",
"C": "3000",
"D": "2788",
"E": "2991"
} | divide(multiply(540, const_100), subtract(add(const_100, 8), subtract(const_100, 10))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "90 % 108 % - - - - - - - - 18 % - - - - 540 100 % - - - - ? = > rs . 3000 answer : c" | gain |
math_qa__dQ5ufRh1Jz1PzLOq | A jar contains 3 black, 3 white and 1 green balls. If you pick two balls at the same time, what's the probability that one ball is black and one is white? Choices.
A) 2 / 7
B) 5 / 7
C) 4 / 7
D) 3 / 7
E) 1 / 2 | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">6 / 7</gadget>
<output>6/7 = around 0.857143</output>
<gadget id="calculator">(1/2) * (6/7)</gadget>
<output>3/7 = around 0.428571</output>
<result>D</result> | D | 0.428571 | A jar contains 3 black, 3 white and 1 green balls. If you pick two balls at the same time, what's the probability that one ball is black and one is white? | {
"A": "2 / 7",
"B": "5 / 7",
"C": "4 / 7",
"D": "3 / 7",
"E": "1 / 2"
} | multiply(divide(3, subtract(add(add(3, 3), 1), 1)), divide(add(3, 3), add(add(3, 3), 1))) | add(n0,n0)|add(n2,#0)|divide(#0,#1)|subtract(#1,n2)|divide(n0,#3)|multiply(#4,#2) | p ( 1 st black , 2 nd white ) = 3 / 7 * 3 / 6 = 9 / 42 ; p ( 1 st white , 2 nd black ) = 3 / 7 * 3 / 6 = 9 / 42 . p = 9 / 42 + 9 / 42 = 18 / 42 = 3 / 7 . answer : d . | probability |
math_qa__E0vIfCNIkWXqd4fL | Of the two square fields, the area of the one is 1 hectare, while anothe one is broader by 1%. There differences in area is: Select the correct option
A) 201 m ( power ) 2
B) 220 m ( power ) 2
C) 211 m ( power ) 2
D) 219 m ( power ) 2
E) 205 m ( power ) 2 | <gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 ** (1/2)</gadget>
<output>100</output>
<gadget id="calculator">1 + 100</gadget>
<output>101</output>
<gadget id="calculator">101 ** 2</gadget>
<output>10_201</output>
<gadget id="calculator">10_201 - 10_000</gadget>
<output>201</output>
<result>A</result> | A | 201 | Of the two square fields, the area of the one is 1 hectare, while anothe one is broader by 1%. There differences in area is: | {
"A": "201 m ( power ) 2",
"B": "220 m ( power ) 2",
"C": "211 m ( power ) 2",
"D": "219 m ( power ) 2",
"E": "205 m ( power ) 2"
} | subtract(square_area(add(1, sqrt(multiply(const_10, const_1000)))), multiply(const_10, const_1000)) | multiply(const_10,const_1000)|sqrt(#0)|add(n0,#1)|square_area(#2)|subtract(#3,#0) | area of one square field = 10000 m ( power ) 2 10000 × 1 = 10000 side of this field = √ 10000 m = 100 m side of another square = 101 m difference of areas = [ 101 ( power ) 2 - 100 ( power ) 2 ] m ( power ) 2 [ 101 + 100 ] [ 101 - 100 ] m ( power ) 2 ( 201 ) ( 1 ) m 2 = 201 m ( power ) 2 answer is a . | geometry |
math_qa__5youd1Lvrv7QUao4 | If there are 4 peanuts in a box and Mary puts 8 more peanuts inside, how many peanuts are in the box? Options:
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">4 + 8</gadget>
<output>12</output>
<result>E</result> | E | 12 | If there are 4 peanuts in a box and Mary puts 8 more peanuts inside, how many peanuts are in the box? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | add(4, 8) | add(n0,n1)| | "8 + 4 = 12 correct answer is e ) 12" | general |
math_qa__n9nHImyoBF0lzpb0 | Rs. 6000 is lent out in two parts. One part is lent at 5% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest? Choose the correct choice.
A) 5 : 1 B) 5 : 5 C) 5 : 8 D) 5 : 4 E) 5 : 2 | <gadget id="calculator">450 * 100</gadget>
<output>45_000</output>
<gadget id="calculator">6_000 * 5</gadget>
<output>30_000</output>
<gadget id="calculator">45_000 - 30_000</gadget>
<output>15_000</output>
<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<gadget id="calculator">15_000 / 5</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 3_000</gadget>
<output>1</output>
<result>B</result> | B | 1 | Rs. 6000 is lent out in two parts. One part is lent at 5% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest? | {
"A": "5 : 1",
"B": "5 : 5",
"C": "5 : 8",
"D": "5 : 4",
"E": "5 : 2"
} | divide(divide(subtract(multiply(450, const_100), multiply(6000, 5)), subtract(10, 5)), divide(subtract(multiply(450, const_100), multiply(6000, 5)), subtract(10, 5))) | multiply(n3,const_100)|multiply(n0,n1)|subtract(n2,n1)|subtract(#0,#1)|divide(#3,#2)|divide(#4,#4) | let the amount lent at 5 % be rs . x amount lent at 10 % is rs . ( 6000 - x ) total interest for one year on the two sums lent = 5 / 100 x + 10 / 100 ( 6000 - x ) = 600 - 1 x / 20 = > 600 - 1 / 20 x = 450 = > x = 3000 amount lent at 10 % = 3000 required ratio = 3000 : 3000 = 5 : 5 answer : b | gain |
math_qa__pBcynNmfXqj4v9mX | If Rs.1440/- are divided among A,B and C so that A receives 1/3rd as much as B and B receives 1/4th as much as C. The amount B received is?
Select the correct option:
A) 250 B) 270 C) 310 D) 330 E) 350 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/12) + (1/4)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) + 1</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">1_440 / (4/3)</gadget>
<output>1_080</output>
<gadget id="calculator">1_080 / 4</gadget>
<output>270</output>
<result>B</result> | B | 270 | If Rs.1440/- are divided among A,B and C so that A receives 1/3rd as much as B and B receives 1/4th as much as C. The amount B received is? | {
"A": "250",
"B": "270",
"C": "310",
"D": "330",
"E": "350"
} | divide(divide(1440, add(add(divide(1, multiply(3, 4)), divide(1, 4)), 1)), 4) | divide(n1,n4)|multiply(n2,n4)|divide(n1,#1)|add(#2,#0)|add(n1,#3)|divide(n0,#4)|divide(#5,n4) | a : b : c = 1 : 3 : 12 total parts = 16 b ' s share is = 3 parts 16 - - - - - > 1440 1 - - - - - > 90 3 - - - - - > 270 ( b ' s share is 270 ) b ) | general |
math_qa__az7CT2BeBpX8VT0G | 375 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
Select the correct option:
A) 10 B) 12 C) 14 D) 16 E) 15 | <gadget id="calculator">26 - 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<gadget id="calculator">375 / 25</gadget>
<output>15</output>
<result>E</result> | E | 15 | 375 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "15"
} | divide(375, add(subtract(26, 2), const_1)) | subtract(n1,n2)|add(#0,const_1)|divide(n0,#1)| | "26 trees have 25 gaps between them , required distance ( 375 / 25 ) = 15 e" | physics |
math_qa__WHuXKkbIaa8haYjR | When toys are grouped into 12 and 18, always 3 toys remain ungrouped. What is the minimum number of toys to be added so that when they are grouped into 7, no toys will remain ungrouped ? Choose one
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">lcm(12, 18)</gadget>
<output>36</output>
<gadget id="calculator">36 + 3</gadget>
<output>39</output>
<gadget id="calculator">42 - 39</gadget>
<output>3</output>
<result>D</result> | D | 3 | When toys are grouped into 12 and 18, always 3 toys remain ungrouped. What is the minimum number of toys to be added so that when they are grouped into 7, no toys will remain ungrouped ? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | subtract(multiply(7, add(const_2, const_4)), add(lcm(12, 18), 3)) | add(const_2,const_4)|lcm(n0,n1)|add(n2,#1)|multiply(n3,#0)|subtract(#3,#2) | t = 12 a + 3 = 18 b + 3 2 a = 3 b - - > min ( a , b ) = ( 3,2 ) so minimum number of toys - - > 12 * 3 + 3 = 39 when toys are grouped into 7 , 4 will remain ungrouped so in order to make another group of 7 toys - - > 7 - 4 = 3 toys at least to be added . answer : d | general |
math_qa__LLKMmO9TP1YOtOuW | In a particular state, 62% of the counties received some rain on Monday, and 54% of the counties received some rain on Tuesday. No rain fell either day in 28% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday?
Select:
A) 25 %
B) 44 %
C) 56 %
D) 62 %
E) 70 % | <gadget id="calculator">62 + 54</gadget>
<output>116</output>
<gadget id="calculator">100 - 28</gadget>
<output>72</output>
<gadget id="calculator">116 - 72</gadget>
<output>44</output>
<result>B</result> | B | 44 | In a particular state, 62% of the counties received some rain on Monday, and 54% of the counties received some rain on Tuesday. No rain fell either day in 28% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday? | {
"A": "25 %",
"B": "44 %",
"C": "56 %",
"D": "62 %",
"E": "70 %"
} | subtract(add(62, 54), subtract(const_100, 28)) | add(n0,n1)|subtract(const_100,n2)|subtract(#0,#1)| | "62 + 54 + 28 = 144 % the number is 44 % above 100 % because 44 % of the counties were counted twice . the answer is b ." | gain |
math_qa__9AtJ7BYt7lfYSIlk | The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 41 degrees. Find the temperature on Friday? Choose the correct choice.
A) 65 degrees B) 73 degrees C) 37 degrees D) 34 degrees E) 33 degrees | <gadget id="calculator">48 * 4</gadget>
<output>192</output>
<gadget id="calculator">46 * 4</gadget>
<output>184</output>
<gadget id="calculator">192 - 184</gadget>
<output>8</output>
<gadget id="calculator">41 - 8</gadget>
<output>33</output>
<result>E</result> | E | 33 | The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 41 degrees. Find the temperature on Friday? | {
"A": "65 degrees",
"B": "73 degrees",
"C": "37 degrees",
"D": "34 degrees",
"E": "33 degrees"
} | subtract(41, subtract(multiply(48, const_4), multiply(46, const_4))) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#0,#1)|subtract(n2,#2)| | "m + tu + w + th = 4 * 48 = 192 tu + w + th + f = 4 * 46 = 184 m = 41 tu + w + th = 192 - 41 = 151 f = 184 – 151 = 33 answer : e" | general |
math_qa__TMFhLNgeqGmVKp2r | A courtyard is 18 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is? Options: A) 22877 B) 27778 C) 20000 D) 27999 E) 14400 | <gadget id="calculator">18 * 100</gadget>
<output>1_800</output>
<gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<gadget id="calculator">1_800 * 1_600</gadget>
<output>2_880_000</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">2_880_000 / 200</gadget>
<output>14_400</output>
<result>E</result> | E | 14,400 | A courtyard is 18 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is? | {
"A": "22877",
"B": "27778",
"C": "20000",
"D": "27999",
"E": "14400"
} | divide(multiply(multiply(18, const_100), multiply(16, const_100)), multiply(20, 10)) | multiply(n0,const_100)|multiply(n1,const_100)|multiply(n2,n3)|multiply(#0,#1)|divide(#3,#2)| | "number of bricks = courtyard area / 1 brick area = ( 1800 × 1600 / 20 × 10 ) = 14400 answer : e" | physics |
math_qa__iHTmyC3pYfWS00Cm | A CAN FINISH A WORK IN 21 DAYS AND B CAN DO THE SAME WORK IN15 DAYS. B WORKED FOR 10 DAYS AND LEFT THE JOB. IN HOW MANY DAYS, A ALONE CAN FINISH THE REMAINING WORK? Pick one
A) 6
B) 5
C) 5.5
D) 7
E) 8 | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) * 10</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 21</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<result>D</result> | D | 7 | A CAN FINISH A WORK IN 21 DAYS AND B CAN DO THE SAME WORK IN15 DAYS. B WORKED FOR 10 DAYS AND LEFT THE JOB. IN HOW MANY DAYS, A ALONE CAN FINISH THE REMAINING WORK? | {
"A": "6",
"B": "5",
"C": "5.5",
"D": "7",
"E": "8"
} | divide(multiply(multiply(divide(const_1, 15), 10), 21), const_2) | divide(const_1,n1)|multiply(n2,#0)|multiply(n0,#1)|divide(#2,const_2)| | "b ' s 10 day ' s work = ( 1 x 10 ) = 2 . 15 3 remaining work = ( 1 - 2 ) = 1 . 3 3 now , 1 work is done by a in 1 day . 21 therefore 1 work is done by a in ( 21 x 1 ) = 7 days . d" | physics |
math_qa__fWJLLaPCXo4Lf43V | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of man is : Answers.
A) 12 kg B) 60 kg C) 72 kg D) 96 kg E) none of these | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">6 * (1/100)</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 1_000</gadget>
<output>60</output>
<result>B</result> | B | 60 | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of man is : | {
"A": "12 kg",
"B": "60 kg",
"C": "72 kg",
"D": "96 kg",
"E": "none of these"
} | multiply(multiply(multiply(3, 2), divide(1, const_100)), const_1000) | divide(n2,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(#2,const_1000)| | "solution volume of water displaced = ( 3 × 2 × 0.01 ) m 3 = 0.06 m 3 . ∴ mass of man = volume of water displaced × density of water = ( 0.06 × 100 ) kg = 60 kg . answer b" | physics |
math_qa__NRDxkyRsQxtfMce3 | What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 16%? Choose the correct choice from the following.
A) 26 % B) 28 % C) 27 % D) 40 % E) 70 % | <gadget id="calculator">100 - 16</gadget>
<output>84</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">84 / (2/3)</gadget>
<output>126</output>
<gadget id="calculator">126 - 100</gadget>
<output>26</output>
<result>A</result> | A | 26 | What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 16%? | {
"A": "26 %",
"B": "28 %",
"C": "27 %",
"D": "40 %",
"E": "70 %"
} | subtract(divide(subtract(const_100, 16), divide(2, 3)), const_100) | divide(n0,n1)|subtract(const_100,n2)|divide(#1,#0)|subtract(#2,const_100)| | "sp 2 = 2 / 3 sp 1 cp = 100 sp 2 = 84 2 / 3 sp 1 = 84 sp 1 = 126 100 - - - 26 = > 26 % answer : a" | gain |
math_qa__VTPl63urZ1P8paTF | UBA Capital recently bought Brand new vehicles for office use. UBA capital only went for Toyota and Honda and bought less of Toyota than Honda at the ratio of 4:6. If 40% of the Toyota bought and 60% of the Honda bought were SUV’s. How many SUV’s did UBA capital buy in the aforementioned purchase? Choose the most appropriate option.
A) 66 % B) 64 % C) 68 % D) 52 % E) 72 % | <gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">24 + 24</gadget>
<output>48</output>
<gadget id="calculator">100 - 48</gadget>
<output>52</output>
<result>D</result> | D | 52 | UBA Capital recently bought Brand new vehicles for office use. UBA capital only went for Toyota and Honda and bought less of Toyota than Honda at the ratio of 4:6. If 40% of the Toyota bought and 60% of the Honda bought were SUV’s. How many SUV’s did UBA capital buy in the aforementioned purchase? | {
"A": "66 %",
"B": "64 %",
"C": "68 %",
"D": "52 %",
"E": "72 %"
} | subtract(const_100, add(multiply(4, 6), multiply(6, 4))) | multiply(n0,n1)|add(#0,#0)|subtract(const_100,#1)| | "let total no of vehicles bought be 100 , toyota 40 and honda 60 , so total number of suv ' s bought for toyota and honda respectively 40 * 40 / 100 = 16 and 60 * 60 / 100 = 36 so total 52 suv ' s were bought out of 100 vehicles bought . . so required % is 52 % answer : d" | other |
math_qa__1FTVpM1orVYRAZ3T | If 15% of 40 is greater than 25% of a number by 2, then the number is?
Choose the correct choice from the following answers.
A) 12 B) 8 C) 15 D) 20 E) 16 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 40</gadget>
<output>6</output>
<gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">4 / (1/4)</gadget>
<output>16</output>
<result>E</result> | E | 16 | If 15% of 40 is greater than 25% of a number by 2, then the number is? | {
"A": "12",
"B": "8",
"C": "15",
"D": "20",
"E": "16"
} | divide(subtract(multiply(divide(15, const_100), 40), 2), divide(25, const_100)) | divide(n0,const_100)|divide(n2,const_100)|multiply(n1,#0)|subtract(#2,n3)|divide(#3,#1)| | "let the number be x 50 % of 40 - 25 % of x = 2 25 / 100 x = ( 15 / 100 * 40 ) - 2 x / 4 = 4 x = 16 answer is e" | gain |
math_qa__lWEbPAfLeaUJDoOm | month average price per dozen april $ 1.2 may $ 1.20 june $ 3.00 the table above shows the average ( arithmetic mean ) price per dozen of the large grade a eggs sold in a certain store during 3 successive months . if 2 / 3 as many dozen were sold in april as in may , and twice as many were sold in june as in april , what was the average price per dozen of the eggs sold over the 3 - month period ? Choose the correct answer
A) 1.8 B) 2.2 C) 2 D) 1.9 E) 2.4 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">3 * (2/3)</gadget>
<output>2</output>
<result>C</result> | C | 2 | month average price per dozen april $ 1.2 may $ 1.20 june $ 3.00 the table above shows the average ( arithmetic mean ) price per dozen of the large grade a eggs sold in a certain store during 3 successive months . if 2 / 3 as many dozen were sold in april as in may , and twice as many were sold in june as in april , what was the average price per dozen of the eggs sold over the 3 - month period ? | {
"A": "1.8",
"B": "2.2",
"C": "2",
"D": "1.9",
"E": "2.4"
} | multiply(3, divide(2, 3)) | divide(n4,n2)|multiply(n2,#0) | say x dozen eggs were sold in may . then 2 x / 3 dozen eggs were sold in april and 2 * 2 x / 3 = 4 x / 3 dozen eggs were sold in may . total x + 2 x / 3 + 4 x / 3 = 3 x dozen eggs were sold in three months . total sales : 2 x / 3 * 1.2 + x * 1.2 + 4 x / 3 * 3.00 = $ 6.00 x . the average price per dozen 6.00 x / 3 x = $ 2.00 c | general |
math_qa__jGbBpVhHhMyxX6Kc | Walking 7/6 of his usual rate, a boy reaches his school 7 min early. Find his usual time to reach the school? Select the correct option:
A) 22
B) 28
C) 99
D) 49
E) 66 | <gadget id="calculator">7 * 7</gadget>
<output>49</output>
<result>D</result> | D | 49 | Walking 7/6 of his usual rate, a boy reaches his school 7 min early. Find his usual time to reach the school? | {
"A": "22",
"B": "28",
"C": "99",
"D": "49",
"E": "66"
} | multiply(7, 7) | multiply(n0,n2)| | "speed ratio = 1 : 7 / 6 = 6 : 7 time ratio = 7 : 6 1 - - - - - - - - 7 7 - - - - - - - - - ? 49 m answer : d" | gain |
math_qa__mceGlp9qCyG8jtxZ | A company received $2 million in royalties on the first $10 million in sales and then $8 million in royalties on the next $100 million in sales. By what percent did the ratio of royalties to sales decrease from the first $10 million in sales to the next $100 million in sales? Choose the correct choice from the following answers:
A) 30 % B) 40 % C) 50 % D) 60 % E) 70 % | <gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(1/5) - (2/25)</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) / (1/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>D</result> | D | 60 | A company received $2 million in royalties on the first $10 million in sales and then $8 million in royalties on the next $100 million in sales. By what percent did the ratio of royalties to sales decrease from the first $10 million in sales to the next $100 million in sales? | {
"A": "30 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "70 %"
} | multiply(divide(subtract(divide(2, const_10), divide(8, 100)), divide(2, const_10)), 100) | divide(n0,const_10)|divide(n2,n3)|subtract(#0,#1)|divide(#2,#0)|multiply(n3,#3) | first find out ( ratio of royalties to sales ) : 2 : 10 first 0.2 8 : 100 second 0.08 decrease = 0.2 - 0.08 = 0.12 percent = ( 0.12 / 0.20 ) = 60 % . answer : d | general |
math_qa__jTA3gxTBdlgPrbz2 | The cost price of a radio is Rs.1500 and it was sold for Rs.1200, find the loss %? Pick
A) 18 B) 16 C) 26 D) 17 E) 20 | <gadget id="calculator">1_500 - 1_200</gadget>
<output>300</output>
<gadget id="calculator">300 / 1_500</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>E</result> | E | 20 | The cost price of a radio is Rs.1500 and it was sold for Rs.1200, find the loss %? | {
"A": "18",
"B": "16",
"C": "26",
"D": "17",
"E": "20"
} | multiply(divide(subtract(1500, 1200), 1500), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : 1500 - - - - 300 100 - - - - ? = > 20 % answer : e" | gain |
math_qa__CyM4tzF5B5kbirhg | Zinc and copper are melted together in the ratio 9 : 11. What is the weight of melted mixture, if 35.1 kg of zinc has been consumed in it? Choose one.
A) 78 kg B) 60 kg C) 64 kg D) 70 kg E) none | <gadget id="calculator">11 / 9</gadget>
<output>11/9 = around 1.222222</output>
<gadget id="calculator">(11/9) * 35.1</gadget>
<output>42.9</output>
<gadget id="calculator">42.9 + 35.1</gadget>
<output>78</output>
<result>A</result> | A | 78 | Zinc and copper are melted together in the ratio 9 : 11. What is the weight of melted mixture, if 35.1 kg of zinc has been consumed in it? | {
"A": "78 kg",
"B": "60 kg",
"C": "64 kg",
"D": "70 kg",
"E": "none"
} | add(multiply(divide(11, 9), 35.1), 35.1) | divide(n1,n0)|multiply(n2,#0)|add(n2,#1)| | "sol . for 9 kg zinc , mixture melted = ( 9 + 11 ) kg . for 35.1 kg zinc , mixture , melted = [ 20 / 9 x 35.1 ] kg = 78 kg . answer a" | general |
math_qa__xciNKeczdSD93KwL | P and Q started a business investing Rs. 54,000 and Rs. 36,000 respectively. Out of a total profit of Rs. 18,000, Q's share is : Choices.
A) 5980
B) 5990
C) 6000
D) 6010
E) 6020 | <gadget id="calculator">18_000 + 3</gadget>
<output>18_003</output>
<gadget id="calculator">18_003 + 3</gadget>
<output>18_006</output>
<gadget id="calculator">18_003 * 18_000</gadget>
<output>324_054_000</output>
<gadget id="calculator">18_006 * 324_054_000</gadget>
<output>5_834_916_324_000</output>
<gadget id="calculator">5_834_916_324_000 + 18_003</gadget>
<output>5_834_916_342_003</output>
<gadget id="calculator">3 * 324_054_000</gadget>
<output>972_162_000</output>
<gadget id="calculator">972_162_000 + 18_003</gadget>
<output>972_180_003</output>
<gadget id="calculator">5_834_916_342_003 / 972_180_003</gadget>
<output>324_108_001/54_001 = around 6_001.888872</output>
<result>C</result> | C | 6,000 | P and Q started a business investing Rs. 54,000 and Rs. 36,000 respectively. Out of a total profit of Rs. 18,000, Q's share is : | {
"A": "5980",
"B": "5990",
"C": "6000",
"D": "6010",
"E": "6020"
} | divide(add(multiply(add(add(18,000, const_3), const_3), multiply(add(18,000, const_3), 18,000)), add(18,000, const_3)), add(multiply(const_3, multiply(add(18,000, const_3), 18,000)), add(18,000, const_3))) | add(n2,const_3)|add(#0,const_3)|multiply(n2,#0)|multiply(#1,#2)|multiply(#2,const_3)|add(#0,#3)|add(#0,#4)|divide(#5,#6)| | "ratio of their shares = 54000 : 27000 = 6 : 3 . q ’ s share = rs . 18000 * 3 / 9 = rs . 6000 answer : c" | gain |
math_qa__6PoOtLfdYcTQ9ywO | Two numbers are respectively 71% and 80% more than a third number. The percentage that is first of the second is? Choose the correct choice from the following options:
A) 4 % B) 5 % C) 6 % D) 7 % E) 8 % | <gadget id="calculator">71 + 100</gadget>
<output>171</output>
<gadget id="calculator">80 + 100</gadget>
<output>180</output>
<gadget id="calculator">171 / 180</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) * 100</gadget>
<output>95</output>
<gadget id="calculator">100 - 95</gadget>
<output>5</output>
<result>B</result> | B | 5 | Two numbers are respectively 71% and 80% more than a third number. The percentage that is first of the second is? | {
"A": "4 %",
"B": "5 %",
"C": "6 %",
"D": "7 %",
"E": "8 %"
} | subtract(const_100, multiply(divide(add(71, const_100), add(80, const_100)), const_100)) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)|multiply(#2,const_100)|subtract(const_100,#3)| | "i ii iii 171 180 100 180 - - - - - - - - - - 171 100 - - - - - - - - - - - ? = > 5 % answer : b" | gain |
math_qa__iKZ80J7YelD5NDYg | A machine, working at a constant rate, manufactures 20 candles in 40 minutes. How many candles does it make in 1 hr 20 min? Choose the correct choice from the following choices: A) 25 B) 30 C) 40 D) 45 E) 50 | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">60 + 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 40</gadget>
<output>2</output>
<gadget id="calculator">2 * 20</gadget>
<output>40</output>
<result>C</result> | C | 40 | A machine, working at a constant rate, manufactures 20 candles in 40 minutes. How many candles does it make in 1 hr 20 min? | {
"A": "25",
"B": "30",
"C": "40",
"D": "45",
"E": "50"
} | multiply(divide(add(multiply(1, const_60), 20), 40), 20) | multiply(n2,const_60)|add(n3,#0)|divide(#1,n1)|multiply(n0,#2)| | "change 1 hr 20 min to 80 min . for this , we need to set up a simple proportion of staplers per time 20 / 40 = s / 80 the absolutely worst thing you could do at this point in the problem is to cross - multiply . that would be a supremely unstrategic move . instead , cancel before you multiply . for what we can and can ’ t cancel in a proportion , seethis post . we can cancel the factor of 10 in the 20 and 40 . 2 / 4 = s / 80 1 / 2 = s / 80 ; 1 / 2 * 2 = s / 80 * 2 1 / 1 = s / 40 now that the fraction is entirely simplified , we can cross - multiply . s = 1 * 40 = 40 the machine would be 40 candles in 1 hr 20 min . answer : c ." | physics |
math_qa__ZfyYMrFXWQGpRVp9 | A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 8km?
Choose the correct choice from the following answers:
A) 4 B) 7 C) 8 D) 9 E) 6 | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>A</result> | A | 4 | A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 8km? | {
"A": "4",
"B": "7",
"C": "8",
"D": "9",
"E": "6"
} | divide(8, subtract(4, 2)) | subtract(n0,n1)|divide(n2,#0)| | "m = 4 s = 2 us = 4 - 2 = 2 d = 8 t = 8 / 2 = 4 answer : a" | physics |
math_qa__48yVQb9D3lpT9acH | If a and b are both odd prime numbers and a < b, then how many different positive integer factors does 2ab have? Choose one
A) 3 B) 4 C) 6 D) 8 E) 12 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<result>D</result> | D | 8 | If a and b are both odd prime numbers and a < b, then how many different positive integer factors does 2ab have? | {
"A": "3",
"B": "4",
"C": "6",
"D": "8",
"E": "12"
} | multiply(2, const_4) | multiply(n0,const_4) | a and b are both odd prime numbers - it means either a or b is not 2 and since prime numbers have only two factors - 1 and the number itself a and b each will have ( 1 + 1 ) = 2 factors hence 2 ab will have ( 1 + 1 ) ( 1 + 1 ) ( 1 + 1 ) = 8 factors d is the answer | other |
math_qa__fkfrtU0bUoPo4OLm | Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.130. How much was lent at 5%? Choose one:
A) 2000
B) 2777
C) 2688
D) 1000
E) 2871 | <gadget id="calculator">6 * 2_500</gadget>
<output>15_000</output>
<gadget id="calculator">15_000 / 100</gadget>
<output>150</output>
<gadget id="calculator">130 - 150</gadget>
<output>-20</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(1/20) - (3/50)</gadget>
<output>-1/100 = around -0.01</output>
<gadget id="calculator">(-20) / (-1/100)</gadget>
<output>2_000</output>
<result>A</result> | A | 2,000 | Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.130. How much was lent at 5%? | {
"A": "2000",
"B": "2777",
"C": "2688",
"D": "1000",
"E": "2871"
} | divide(subtract(130, divide(multiply(6, 2500), const_100)), subtract(divide(5, const_100), divide(6, const_100))) | divide(n1,const_100)|divide(n2,const_100)|multiply(n0,n2)|divide(#2,const_100)|subtract(#0,#1)|subtract(n3,#3)|divide(#5,#4)| | "( x * 5 * 1 ) / 100 + [ ( 2500 - x ) * 6 * 1 ] / 100 = 130 x = 2000 answer : a" | gain |
math_qa__kjTYzkiEROhkstOI | Find the lowest common multiple of 15, 25 and 35. Pick one
A) 360 B) 420 C) 510 D) 525 E) 280 | <gadget id="calculator">lcm(15, 25)</gadget>
<output>75</output>
<gadget id="calculator">lcm(75, 35)</gadget>
<output>525</output>
<result>D</result> | D | 525 | Find the lowest common multiple of 15, 25 and 35. | {
"A": "360",
"B": "420",
"C": "510",
"D": "525",
"E": "280"
} | lcm(lcm(15, 25), 35) | lcm(n0,n1)|lcm(n2,#0)| | "lcm = 3 * 5 * 5 * 7 = 525 . answer is d" | general |
math_qa__dc372efVXkGfWj2f | A person travels equal distances with speeds of 5km/hr, 10km/hr, 15km/hr. and takes a total time of 11minutes. Find the total distance ?
Choices.
A) 1 km B) 1500 mts C) 1600 mts D) 2 km E) 1250 mts | <gadget id="calculator">11 / 60</gadget>
<output>11/60 = around 0.183333</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/5) + (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(3/10) + (1/15)</gadget>
<output>11/30 = around 0.366667</output>
<gadget id="calculator">(11/60) / (11/30)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 3</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 1_000</gadget>
<output>1_500</output>
<result>B</result> | B | 1,500 | A person travels equal distances with speeds of 5km/hr, 10km/hr, 15km/hr. and takes a total time of 11minutes. Find the total distance ? | {
"A": "1 km",
"B": "1500 mts",
"C": "1600 mts",
"D": "2 km",
"E": "1250 mts"
} | multiply(multiply(divide(divide(11, const_60), add(add(divide(const_1, 5), divide(const_1, 10)), divide(const_1, 15))), const_3), const_1000) | divide(n3,const_60)|divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#1,#2)|add(#4,#3)|divide(#0,#5)|multiply(#6,const_3)|multiply(#7,const_1000)| | "let the each distance be x km total distance = 3 x then total time , ( x / 5 ) + ( x / 10 ) + ( x / 15 ) = 11 / 60 x = 0.5 total distance = 3 * 0.5 = 1.5 km = 1500 meters correct option is b" | physics |
math_qa__alJpepero1YJS9sr | A charitable woman gave one penny more than half pennies in her purse to a farmer .Afterwards she came across a beggar whom she gave 2 pennies more than half of what she had in her purse. In the end she gave 3 pennies more than half of what she had in her purse and left with a penny with her to a boy. Find what she had in the beginning?
Choose the correct option
A) 41
B) 42
C) 43
D) 44
E) 45 | <gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">21 * 2</gadget>
<output>42</output>
<result>B</result> | B | 42 | A charitable woman gave one penny more than half pennies in her purse to a farmer .Afterwards she came across a beggar whom she gave 2 pennies more than half of what she had in her purse. In the end she gave 3 pennies more than half of what she had in her purse and left with a penny with her to a boy. Find what she had in the beginning? | {
"A": "41",
"B": "42",
"C": "43",
"D": "44",
"E": "45"
} | multiply(add(multiply(add(multiply(add(const_1, 3), 2), 2), 2), const_1), 2) | add(n1,const_1)|multiply(n0,#0)|add(n0,#1)|multiply(n0,#2)|add(#3,const_1)|multiply(n0,#4) | she gave 1 penny more than the half in the purse i . e ( x / 2 + 1 ) now she is left with : : ( x - ( x / 2 + 1 ) ) = ( x - 2 ) / 2 now to the beggar : : she gave 2 pennies more than the half in the purse i . e ( x - 2 ) / 4 + 2 and she is left with : : ( ( x - 2 ) / 2 ) - ( ( x - 2 ) / 4 + 2 ) = ( x - 10 ) / 4 now at last sh gave 3 pennies more then the half she was left with i . e ( ( x - 10 ) / 8 + 3 ) = a so she is left with ( x - 10 ) / 4 - a = ( x - 34 ) / 8 now acc . to quest ( x - 34 ) / 8 = 1 hence x = 42 answer : b | general |
math_qa__XbhqWwQXHjXNVZfa | If x, y, and z are positive integers, and 2x = 5y = 6z, then the least possible value of x + y + z is Choose one:
A) 15 B) 26 C) 37 D) 42 E) 60 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">15 + 6</gadget>
<output>21</output>
<gadget id="calculator">30 / 6</gadget>
<output>5</output>
<gadget id="calculator">21 + 5</gadget>
<output>26</output>
<result>B</result> | B | 26 | If x, y, and z are positive integers, and 2x = 5y = 6z, then the least possible value of x + y + z is | {
"A": "15",
"B": "26",
"C": "37",
"D": "42",
"E": "60"
} | add(add(divide(divide(multiply(multiply(2, 5), 6), const_2), 2), divide(divide(multiply(multiply(2, 5), 6), const_2), 5)), divide(divide(multiply(multiply(2, 5), 6), const_2), 6)) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_2)|divide(#2,n0)|divide(#2,n1)|divide(#2,n2)|add(#3,#4)|add(#6,#5)| | "take lcm of 2,5 and 6 = 30 now 2 x = 30 = > x = 15 5 y = 30 = > y = 6 6 z = 30 = > z = 5 15 + 6 + 5 = 26 . option b ." | general |
math_qa__zrxQMYQB0NqplyWP | one - third of rahul ' s savings in national savings certificate is equal to one - half of his savings in public provident fund . if he has rs . 1 , 80000 as total savings , how much has he saved in public provident fund ?
Answers
A) 81000 B) 85000 C) 75000 D) 72000 E) 77000 | <gadget id="calculator">10 ** 4</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 * 10</gadget>
<output>100_000</output>
<gadget id="calculator">100_000 + 80_000</gadget>
<output>180_000</output>
<gadget id="calculator">180_000 / 2</gadget>
<output>90_000</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">90_000 * 6</gadget>
<output>540_000</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">540_000 / 5</gadget>
<output>108_000</output>
<gadget id="calculator">180_000 - 108_000</gadget>
<output>72_000</output>
<result>D</result> | D | 72,000 | one - third of rahul ' s savings in national savings certificate is equal to one - half of his savings in public provident fund . if he has rs . 1 , 80000 as total savings , how much has he saved in public provident fund ? | {
"A": "81000",
"B": "85000",
"C": "75000",
"D": "72000",
"E": "77000"
} | subtract(add(multiply(power(const_10, const_4), const_10), 80000), divide(multiply(divide(add(multiply(power(const_10, const_4), const_10), 80000), const_2), multiply(const_2, const_3)), add(const_2, const_3))) | add(const_2,const_3)|multiply(const_2,const_3)|power(const_10,const_4)|multiply(#2,const_10)|add(n1,#3)|divide(#4,const_2)|multiply(#5,#1)|divide(#6,#0)|subtract(#4,#7) | let savings in national savings certificate = x and savings in public provident fund = ( 180000 - x ) 1 / 3 x = 1 / 2 ( 180000 − x ) ⇒ 2 x = 3 ( 180000 − x ) ⇒ 2 x = 540000 − 3 x ⇒ 5 x = 540000 ⇒ x = 540000 / 5 = 108000 savings in public provident fund = ( 180000 - 108000 ) = 72000 answer is d . | general |
math_qa__kPaIFtkY1UNYmDe4 | The weight of every type A widget is the same, the weight of every type B widget is the same, and the weight of every type C widget is the same. If the weight of 7 type A widgets is equal to the weight of 2 type B widgets, and the weight of 3 type B widgets is equal to the weight of 7 type C widgets. What is the ratio of the total weight of 1 type A widget and 1 type B widget, to the total weight of 1 type B widget and 1 type C widget? Pick one:
A) 1 : 2 B) 3 : 4 C) 5 : 6 D) 7 : 8 E) 9 : 10 | <gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">1 + (7/2)</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(7/2) + (3/2)</gadget>
<output>5</output>
<gadget id="calculator">(9/2) / 5</gadget>
<output>9/10 = around 0.9</output>
<result>E</result> | E | 0.9 | The weight of every type A widget is the same, the weight of every type B widget is the same, and the weight of every type C widget is the same. If the weight of 7 type A widgets is equal to the weight of 2 type B widgets, and the weight of 3 type B widgets is equal to the weight of 7 type C widgets. What is the ratio of the total weight of 1 type A widget and 1 type B widget, to the total weight of 1 type B widget and 1 type C widget? | {
"A": "1 : 2",
"B": "3 : 4",
"C": "5 : 6",
"D": "7 : 8",
"E": "9 : 10"
} | divide(add(1, divide(7, 2)), add(divide(7, 2), divide(3, 2))) | divide(n0,n1)|divide(n2,n1)|add(n4,#0)|add(#0,#1)|divide(#2,#3) | 3 b = 7 c and so b = 7 c / 3 7 a = 2 b and so a = 2 b / 7 = 2 c / 3 a + b = 2 c / 3 + 7 c / 3 = 9 c / 3 b + c = 7 c / 3 + c = 10 c / 3 the ratio of a + b : b + c = 9 : 10 the answer is e . | general |
math_qa__tbQwP9Drqqr7f8Ch | Two trains 140m and 160m long run at the speed of 60kmph and 48kmph in opposite directions in parallel tracks. The time which they take to cross each other is?
Choices
A) 5.6 sec
B) 8.9 sec
C) 10 sec
D) 12.6 sec
E) 15 sec | <gadget id="calculator">140 + 160</gadget>
<output>300</output>
<gadget id="calculator">60 + 48</gadget>
<output>108</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">108 * (5/18)</gadget>
<output>30</output>
<gadget id="calculator">300 / 30</gadget>
<output>10</output>
<result>C</result> | C | 10 | Two trains 140m and 160m long run at the speed of 60kmph and 48kmph in opposite directions in parallel tracks. The time which they take to cross each other is? | {
"A": "5.6 sec",
"B": "8.9 sec",
"C": "10 sec",
"D": "12.6 sec",
"E": "15 sec"
} | divide(add(140, 160), multiply(add(60, 48), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 48 = 108 kmph * 5 / 18 = 30 m / s distance covered in crossing each other = 140 + 160 = 300 m required time = 300 * 1 / 30 = 10 sec answer is c" | physics |
math_qa__nNiuXWs3ZenwTiDt | There are 408 boys and 192 girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed.
Pick.
A) 25 B) 32 C) 35 D) 30 E) 45 | <gadget id="calculator">408 + 192</gadget>
<output>600</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">600 / 24</gadget>
<output>25</output>
<result>A</result> | A | 25 | There are 408 boys and 192 girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed. | {
"A": "25",
"B": "32",
"C": "35",
"D": "30",
"E": "45"
} | divide(add(408, 192), multiply(multiply(multiply(const_2, const_2), const_2), const_3)) | add(n0,n1)|multiply(const_2,const_2)|multiply(#1,const_2)|multiply(#2,const_3)|divide(#0,#3)| | "explanation : hcf ( 408 , 192 ) = 24 the number of boys or girls that can be placed in a section = 24 . thus the total number of sections is given by 408 / 24 + 192 / 24 = 17 + 8 = 25 answer : a" | general |
math_qa__QsKxfaSUCsR90JYf | Joe needs to paint all the airplane hangars at the airport, so he buys 360 gallons of paint to do the job. During the first week, he uses 1/4 of all the paint. During the second week, he uses 1/7 of the remaining paint. How many gallons of paint has Joe used?
Pick.
A) 18 B) 128 C) 175 D) 216 E) 250 | <gadget id="calculator">360 / 4</gadget>
<output>90</output>
<gadget id="calculator">90 * 1</gadget>
<output>90</output>
<gadget id="calculator">360 - 90</gadget>
<output>270</output>
<gadget id="calculator">270 / 7</gadget>
<output>270/7 = around 38.571429</output>
<gadget id="calculator">90 + (270/7)</gadget>
<output>900/7 = around 128.571429</output>
<result>B</result> | B | 128 | Joe needs to paint all the airplane hangars at the airport, so he buys 360 gallons of paint to do the job. During the first week, he uses 1/4 of all the paint. During the second week, he uses 1/7 of the remaining paint. How many gallons of paint has Joe used? | {
"A": "18",
"B": "128",
"C": "175",
"D": "216",
"E": "250"
} | add(multiply(divide(360, 4), 1), divide(subtract(360, multiply(divide(360, 4), 1)), 7)) | divide(n0,n2)|multiply(n1,#0)|subtract(n0,#1)|divide(#2,n4)|add(#3,#1)| | "total paint initially = 360 gallons paint used in the first week = ( 1 / 4 ) * 360 = 90 gallons . remaning paint = 270 gallons paint used in the second week = ( 1 / 7 ) * 270 = 38 gallons total paint used = 128 gallons . option b" | physics |
math_qa__F29CwOLPwUDiFcpA | The sale price sarees listed for Rs.540 after successive discount is 5% and 2% is? Choose the correct choice from the following answers.
A) 288
B) 500
C) 502
D) 540
E) 262 | <gadget id="calculator">540 * 5</gadget>
<output>2_700</output>
<gadget id="calculator">2_700 / 100</gadget>
<output>27</output>
<gadget id="calculator">540 - 27</gadget>
<output>513</output>
<gadget id="calculator">513 * 2</gadget>
<output>1_026</output>
<gadget id="calculator">1_026 / 100</gadget>
<output>513/50 = around 10.26</output>
<gadget id="calculator">513 - (513/50)</gadget>
<output>25_137/50 = around 502.74</output>
<result>C</result> | C | 502 | The sale price sarees listed for Rs.540 after successive discount is 5% and 2% is? | {
"A": "288",
"B": "500",
"C": "502",
"D": "540",
"E": "262"
} | subtract(subtract(540, divide(multiply(540, 5), const_100)), divide(multiply(subtract(540, divide(multiply(540, 5), const_100)), 2), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "540 * ( 95 / 100 ) * ( 98 / 100 ) = 502 answer : c" | gain |
math_qa__No7M8NOp5RJ1R53C | A bag contains 3red, 2blue and 3green balls. If 2 ballsare picked at random, what is the probability that both are red? Choose one.
A) 2 / 21 B) 3 / 41 C) 3 / 28 D) 3 / 31 E) 5 / 32 | <gadget id="calculator">binomial(3, 2)</gadget>
<output>3</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">binomial(8, 2)</gadget>
<output>28</output>
<gadget id="calculator">3 / 28</gadget>
<output>3/28 = around 0.107143</output>
<result>C</result> | C | 0.107143 | A bag contains 3red, 2blue and 3green balls. If 2 ballsare picked at random, what is the probability that both are red? | {
"A": "2 / 21",
"B": "3 / 41",
"C": "3 / 28",
"D": "3 / 31",
"E": "5 / 32"
} | divide(choose(3, 2), choose(add(add(3, 2), 3), 2)) | add(n0,n1)|choose(n0,n3)|add(n2,#0)|choose(#2,n3)|divide(#1,#3)| | "p ( both are red ) , = 3 c 2 / 8 c 2 = 6 c 213 c 2 = 3 / 28 c" | other |
math_qa__WM1iduWyKd9fAjqs | Company P had 15 percent more employees in December than it had in January. If Company P had 480 employees in December, how many employees did it have in January?
Select the correct option.
A) 391 B) 417 C) 410 D) 423 E) 445 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">480 / (23/20)</gadget>
<output>9_600/23 = around 417.391304</output>
<result>B</result> | B | 417 | Company P had 15 percent more employees in December than it had in January. If Company P had 480 employees in December, how many employees did it have in January? | {
"A": "391",
"B": "417",
"C": "410",
"D": "423",
"E": "445"
} | divide(480, add(const_1, divide(15, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "d = number of employees in december j = number of employees in january j x 1.15 = d j x 1.15 = 480 j = 480 / 1.15 j = 48,000 / 115 = 417 thus b is the correct answer ." | gain |
math_qa__jfC2LJqfMYjOcLHG | At Deluxe paint store, Fuchsia paint is made by mixing 5 parts of red paint with 3 parts of blue paint. Mauve paint is made by mixing 3 parts of red paint with 5 parts blue paint. How many liters of blue paint must be added to 40 liters of Fuchsia to change it to Mauve paint? Choices:
A) 9
B) 12
C) 15
D) 16
E) 26.6 | <gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">40 * (5/8)</gadget>
<output>25</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">25 / (3/8)</gadget>
<output>200/3 = around 66.666667</output>
<gadget id="calculator">(200/3) * (5/8)</gadget>
<output>125/3 = around 41.666667</output>
<gadget id="calculator">40 - 25</gadget>
<output>15</output>
<gadget id="calculator">(125/3) - 15</gadget>
<output>80/3 = around 26.666667</output>
<result>E</result> | E | 26.6 | At Deluxe paint store, Fuchsia paint is made by mixing 5 parts of red paint with 3 parts of blue paint. Mauve paint is made by mixing 3 parts of red paint with 5 parts blue paint. How many liters of blue paint must be added to 40 liters of Fuchsia to change it to Mauve paint? | {
"A": "9",
"B": "12",
"C": "15",
"D": "16",
"E": "26.6"
} | subtract(multiply(divide(multiply(40, divide(5, add(5, 3))), divide(3, add(5, 3))), divide(5, add(5, 3))), subtract(40, multiply(40, divide(5, add(5, 3))))) | add(n0,n1)|divide(n0,#0)|divide(n2,#0)|divide(n3,#0)|multiply(n4,#1)|divide(#4,#2)|subtract(n4,#4)|multiply(#5,#3)|subtract(#7,#6)| | "in 40 liters , red = 5 / 8 * 40 = 25 and blue = 15 so , 25 / ( 15 + x ) = 3 / 5 or , x = 26.6 ( answer e )" | general |
math_qa__XavmKbYtvz3GCjNT | According to the directions on the can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12 ounces cans of the concentrate are required to prepare 320 6 ounces servings of orange juice? Choose the correct choice from the following options:
A) 25 B) 34 C) 50 D) 40 E) 100 | <gadget id="calculator">320 * 6</gadget>
<output>1_920</output>
<gadget id="calculator">1_920 / 12</gadget>
<output>160</output>
<gadget id="calculator">160 / 4</gadget>
<output>40</output>
<result>D</result> | D | 40 | According to the directions on the can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12 ounces cans of the concentrate are required to prepare 320 6 ounces servings of orange juice? | {
"A": "25",
"B": "34",
"C": "50",
"D": "40",
"E": "100"
} | divide(divide(multiply(320, 6), 12), const_4) | multiply(n3,n4)|divide(#0,n2)|divide(#1,const_4) | its d . total juice rquired = 320 * 6 = 1920 ounce 12 ounce concentate makes = 12 * 4 = 48 ounce juice total cans required = 1920 / 48 = 40 . answer d | general |
math_qa__JsgUMtxRjWeljemQ | the largest natural number which exactly divides the product of any 4 consecutive natural numbers is Options.
A) 6 B) 12 C) 24 D) 120 E) none | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<result>C</result> | C | 24 | the largest natural number which exactly divides the product of any 4 consecutive natural numbers is | {
"A": "6",
"B": "12",
"C": "24",
"D": "120",
"E": "none"
} | factorial(4) | factorial(n0) | sol . required number = 1 × 2 × 3 × 4 = 24 . answer c | general |
math_qa__kbv2vH28wRqvu0oD | 16 boys or 24 girls can construct the wall in 6 days. the number of days that 16 boys and 12 girls Will take to construct? Choose the correct choice from the following
A) 7 days B) 4 days C) 6 days D) 8 days E) 9 days | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) / 24</gadget>
<output>1/144 = around 0.006944</output>
<gadget id="calculator">12 * (1/144)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/6) / 16</gadget>
<output>1/96 = around 0.010417</output>
<gadget id="calculator">16 * (1/96)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/12) + (1/6)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<result>B</result> | B | 4 | 16 boys or 24 girls can construct the wall in 6 days. the number of days that 16 boys and 12 girls Will take to construct? | {
"A": "7 days",
"B": "4 days",
"C": "6 days",
"D": "8 days",
"E": "9 days"
} | divide(const_1, add(multiply(12, divide(divide(const_1, 6), 24)), multiply(16, divide(divide(const_1, 6), 16)))) | divide(const_1,n2)|divide(#0,n1)|divide(#0,n0)|multiply(n4,#1)|multiply(n3,#2)|add(#3,#4)|divide(const_1,#5)| | "explanation : 16 boys = 24 girls , 1 boy = 24 / 16 girls 1 boy = 6 / 4 girls 16 boys + 12 girls = 16 ã — 6 / 4 + 12 = 24 + 12 = 36 girls 4 days to complete the work answer : option b" | physics |
math_qa__mis5f5KKzYKYNfWU | 9873 + x = 13800, then x is ? Choose the correct choice from the following: A) 3327 B) 3237 C) 3927 D) 2337 E) none of these | <gadget id="calculator">13_800 - 9_873</gadget>
<output>3_927</output>
<result>C</result> | C | 3,927 | 9873 + x = 13800, then x is ? | {
"A": "3327",
"B": "3237",
"C": "3927",
"D": "2337",
"E": "none of these"
} | subtract(13800, 9873) | subtract(n1,n0)| | "answer x = 13800 - 9873 = 3927 option : c" | general |
math_qa__R0RNT6gpvZQGT4qT | In a sports club with 40 members, 20 play badminton and 18 play tennis and 5 do not play either. How many members play both badminton and tennis? Choose the correct choice from the following options.
A) 3 B) 5 C) 6 D) 7 E) 3 | <gadget id="calculator">20 + 18</gadget>
<output>38</output>
<gadget id="calculator">38 + 5</gadget>
<output>43</output>
<gadget id="calculator">43 - 40</gadget>
<output>3</output>
<result>E</result> | E | 3 | In a sports club with 40 members, 20 play badminton and 18 play tennis and 5 do not play either. How many members play both badminton and tennis? | {
"A": "3",
"B": "5",
"C": "6",
"D": "7",
"E": "3"
} | subtract(add(add(20, 18), 5), 40) | add(n1,n2)|add(n3,#0)|subtract(#1,n0)| | "20 + 18 = 38 but where as total number is 40 - 5 = 35 therefore answer is 38 - 35 = 3 hence answer is e" | other |
math_qa__knXeresiQZ9iOGfX | An article is bought for Rs.600 and sold for Rs.300, find the loss percent?
Pick one:
A) 12 % B) 16 % C) 19 % D) 50 % E) 60 % | <gadget id="calculator">300 * 100</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 / 600</gadget>
<output>50</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<result>D</result> | D | 50 | An article is bought for Rs.600 and sold for Rs.300, find the loss percent? | {
"A": "12 %",
"B": "16 %",
"C": "19 %",
"D": "50 %",
"E": "60 %"
} | subtract(const_100, divide(multiply(300, const_100), 600)) | multiply(n1,const_100)|divide(#0,n0)|subtract(const_100,#1)| | "600 - - - - 300 100 - - - - ? = > 50 % answer : d" | gain |
math_qa__G8g9Bc7Mgwv8pkYP | A 300 m long train crosses a platform in 33 sec while it crosses a signal pole in 18 sec. What is the length of the platform? Choose the correct answer.
A) 286 m B) 250 m C) 277 m D) 278 m E) 267 m | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 33</gadget>
<output>550</output>
<gadget id="calculator">550 - 300</gadget>
<output>250</output>
<result>B</result> | B | 250 | A 300 m long train crosses a platform in 33 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | {
"A": "286 m",
"B": "250 m",
"C": "277 m",
"D": "278 m",
"E": "267 m"
} | subtract(multiply(speed(300, 18), 33), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 18 = 50 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 33 = 50 / 3 = > x = 250 m . answer : b" | physics |
math_qa__0Af7KoIahnQryurz | Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 14 minutes more to walk to work than to ride his bike to work, then x equals? Answers.
A) 4 B) 7 C) 10 D) 15 E) 21 | <gadget id="calculator">14 * 3</gadget>
<output>42</output>
<gadget id="calculator">42 / 2</gadget>
<output>21</output>
<result>E</result> | E | 21 | Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 14 minutes more to walk to work than to ride his bike to work, then x equals? | {
"A": "4",
"B": "7",
"C": "10",
"D": "15",
"E": "21"
} | divide(multiply(14, const_3), const_2) | multiply(n2,const_3)|divide(#0,const_2) | please follow posting guidelines , link is in my signatures . as for your question , x / 60 = blocks / time / block = block ^ 2 / time . this is not what you want . you are given x blocks and 60 seconds per block . thus you need to put it as 60 * x to give you units of seconds as you are equating this to 840 ( which is time in seconds . ) . thus the correct equation is : 60 * x - 20 * x = 840 - - - - > 40 x = 840 - > x = 21 . option e | physics |
math_qa__HLVoC3oNBGgqluAV | What sum of money will produce Rs.60 as simple interest in 4 years at 3 1/2 percent? Choose the correct choice from the following options.
A) 337 B) 429 C) 266 D) 288 E) 211 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + (1/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">4 * (7/2)</gadget>
<output>14</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">60 / (7/50)</gadget>
<output>3_000/7 = around 428.571429</output>
<result>B</result> | B | 429 | What sum of money will produce Rs.60 as simple interest in 4 years at 3 1/2 percent? | {
"A": "337",
"B": "429",
"C": "266",
"D": "288",
"E": "211"
} | divide(60, divide(multiply(4, add(3, divide(1, 2))), const_100)) | divide(n3,n4)|add(n2,#0)|multiply(n1,#1)|divide(#2,const_100)|divide(n0,#3)| | "60 = ( p * 4 * 7 / 2 ) / 100 p = 429 answer : b" | gain |
math_qa__mDRogwAQYXBGfKiu | An woman sitting in a train which is travelling at 25 kmph observes that a goods train travelling in a opposite direction, takes 3 seconds to pass him. If the goods train is 140 m long, find its speed. Choices.
A) 141 B) 142 C) 143 D) 144 E) 145 | <gadget id="calculator">140 / 3</gadget>
<output>140/3 = around 46.666667</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(140/3) / (5/18)</gadget>
<output>168</output>
<gadget id="calculator">168 - 25</gadget>
<output>143</output>
<result>C</result> | C | 143 | An woman sitting in a train which is travelling at 25 kmph observes that a goods train travelling in a opposite direction, takes 3 seconds to pass him. If the goods train is 140 m long, find its speed. | {
"A": "141",
"B": "142",
"C": "143",
"D": "144",
"E": "145"
} | subtract(speed(speed(140, 3), const_0_2778), 25) | speed(n2,n1)|speed(#0,const_0_2778)|subtract(#1,n0)| | "relative speed = ( 140 / 3 ) m / s = ( 140 / 3 ) * ( 18 / 5 ) = 168 kmph speed of goods train = 168 - 25 = 143 kmph answer is c" | physics |
math_qa__GJ7L3xJfNBy586RQ | On a trip, a cyclist averaged 12 miles per hour for the first 18 miles and 10 miles per hour for the remaining 18 miles. If the cyclist returned immediately via the same route and took a total of 7.3 hours for the round trip, what was the average speed (in miles per hour) for the return trip? Choose the correct choice from the following answers:
A) 8.4 B) 8.6 C) 8.8 D) 9 E) 9.2 | <gadget id="calculator">18 + 18</gadget>
<output>36</output>
<gadget id="calculator">18 / 12</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">18 / 10</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(3/2) + (9/5)</gadget>
<output>33/10 = around 3.3</output>
<gadget id="calculator">7.3 - (33/10)</gadget>
<output>4</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<result>D</result> | D | 9 | On a trip, a cyclist averaged 12 miles per hour for the first 18 miles and 10 miles per hour for the remaining 18 miles. If the cyclist returned immediately via the same route and took a total of 7.3 hours for the round trip, what was the average speed (in miles per hour) for the return trip? | {
"A": "8.4",
"B": "8.6",
"C": "8.8",
"D": "9",
"E": "9.2"
} | divide(add(18, 18), subtract(7.3, add(divide(18, 12), divide(18, 10)))) | add(n1,n3)|divide(n1,n0)|divide(n3,n2)|add(#1,#2)|subtract(n4,#3)|divide(#0,#4)| | "the time to go 36 miles was 18 / 12 + 18 / 10 = 1.5 + 1.8 = 3.3 hours . the average speed for the return trip was 36 miles / 4 hours = 9 mph . the answer is d ." | physics |
math_qa__B8U77mvjLHImzGJ6 | There is a rectangular prism made of 1 in cubes that has been covered in tin foil. There are exactly 128 cubes that are not touching any tin foil on any of their sides. If the width of the figure created by these 128 cubes is twice the length and twice the height, what is the measure q in inches of the width of the foil covered prism?
Choose the correct answer:
A) 4
B) 6
C) 8
D) 9
E) 10 | <gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">128 / 2</gadget>
<output>64</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<result>E</result> | E | 10 | There is a rectangular prism made of 1 in cubes that has been covered in tin foil. There are exactly 128 cubes that are not touching any tin foil on any of their sides. If the width of the figure created by these 128 cubes is twice the length and twice the height, what is the measure q in inches of the width of the foil covered prism? | {
"A": "4",
"B": "6",
"C": "8",
"D": "9",
"E": "10"
} | add(multiply(power(divide(128, multiply(1, multiply(1, const_2))), inverse(const_3)), multiply(1, const_2)), multiply(1, const_2)) | inverse(const_3)|multiply(n0,const_2)|multiply(n0,#1)|divide(n1,#2)|power(#3,#0)|multiply(#1,#4)|add(#5,#1)| | "if the width is w , then length and height would be w / 2 . so , w * w / 2 * w / 2 = 128 = > w ^ 3 = ( 2 ^ 3 ) * 64 = ( 2 ^ 3 ) * ( 4 ^ 3 ) = > w = 2 * 4 = 8 in . along the width of the cuboid , 8 cubes do n ' t touch the tin foil . so the actual width will be non - touching cubes + touching cubes = 8 + 2 = q = 10 ans e ." | geometry |
math_qa__SIwhNnqqx3z08xdy | In covering a distance of 30 km, Arun takes 2 hours more than Anil. If Arun doubles his speed, then he would take 1 hour less than Anil. What is Arun's speed? Select the correct option
A) 2 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">30 / 6</gadget>
<output>5</output>
<result>B</result> | B | 5 | In covering a distance of 30 km, Arun takes 2 hours more than Anil. If Arun doubles his speed, then he would take 1 hour less than Anil. What is Arun's speed? | {
"A": "2",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | divide(30, multiply(add(1, const_2), const_2)) | add(n2,const_2)|multiply(#0,const_2)|divide(n0,#1)| | "let the speed of arun = x kmph and the speed of anil = y kmph distance = 30 km we know that distancespeed = timehence 30 x − 30 y = 2 . . . . . . . . . . . ( equation 1 ) 30 y − 302 x = 1 . . . . . . . . . . . ( equation 2 ) equation 1 + equation 2 ⇒ 30 x − 302 x = 3 ⇒ 302 x = 3 ⇒ 15 x = 3 ⇒ 5 x = 1 ⇒ x = 5 hence arun ' s speed = 5 kmph answer : b" | physics |
math_qa__FinQey4oe3LZLMWi | The Racing magic takes 150 seconds to circle the racing track once. The Charging bull makes 40 rounds of the track in an hour. If they left the starting point together, how many minutes will it take for them to meet at the starting point for the second time? Choose one:
A) 3 B) 6 C) 9 D) 12 E) 15 | <gadget id="calculator">150 / 40</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">150 * (15/4)</gadget>
<output>1_125/2 = around 562.5</output>
<gadget id="calculator">(1_125/2) * 2</gadget>
<output>1_125</output>
<gadget id="calculator">1_125 / 150</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 2</gadget>
<output>15</output>
<result>E</result> | E | 15 | The Racing magic takes 150 seconds to circle the racing track once. The Charging bull makes 40 rounds of the track in an hour. If they left the starting point together, how many minutes will it take for them to meet at the starting point for the second time? | {
"A": "3",
"B": "6",
"C": "9",
"D": "12",
"E": "15"
} | multiply(divide(multiply(multiply(150, divide(150, 40)), const_2), 150), const_2) | divide(n0,n1)|multiply(#0,n0)|multiply(#1,const_2)|divide(#2,n0)|multiply(#3,const_2)| | "time taken by racing magic to make one circle = 150 seconds time taken bycharging bullto make one circle = 60 mins / 40 = 1.5 mins = 90 seconds lcm of 90 and 150 seconds = 450 seconds time taken for them to meet at the starting point for the second time = 2 * 450 = 900 seconds = 15 mins answer e" | physics |
math_qa__l57X4HdUD0G7VM49 | A grocer is storing soap boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton?
Choose the correct choice from the following answers: A) 210 B) 252 C) 280 D) 300 E) 420 | <gadget id="calculator">25 * 42</gadget>
<output>1_050</output>
<gadget id="calculator">1_050 * 60</gadget>
<output>63_000</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">42 * 5</gadget>
<output>210</output>
<gadget id="calculator">63_000 / 210</gadget>
<output>300</output>
<result>D</result> | D | 300 | A grocer is storing soap boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton? | {
"A": "210",
"B": "252",
"C": "280",
"D": "300",
"E": "420"
} | divide(multiply(multiply(25, 42), 60), multiply(multiply(7, 6), 5)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|multiply(n5,#1)|divide(#2,#3) | maximum number of soap boxes that can be placed in each carton = volume of each carton / volume of each box = ( 25 * 42 * 60 ) / ( 7 * 6 * 5 ) = 300 answer : d | general |
math_qa__icB8o35VByAwgrI8 | How many multiples of 10 are there between 100 and 10000 (both are inclusive)?
Choose the correct option:
A) 456 B) 789 C) 991 D) 1020 E) 1100 | <gadget id="calculator">10_000 - 100</gadget>
<output>9_900</output>
<gadget id="calculator">9_900 / 10</gadget>
<output>990</output>
<gadget id="calculator">990 + 1</gadget>
<output>991</output>
<result>C</result> | C | 991 | How many multiples of 10 are there between 100 and 10000 (both are inclusive)? | {
"A": "456",
"B": "789",
"C": "991",
"D": "1020",
"E": "1100"
} | add(divide(subtract(10000, 100), 10), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "the answer is ( 10000 - 100 ) / 10 + 1 = 991 answer is c" | other |
math_qa__nIjzvvlAB0WKgzZc | There are 20 poles with a constant distance between each pole. A car takes 25 second to reach the 12th pole. How much will it take to reach the last pole.
Choose the correct choice from the following choices:
A) 43.1543 B) 43.1818 C) 43.45128 D) 43.41288 E) 43.41222 | <gadget id="calculator">25 / 12</gadget>
<output>25/12 = around 2.083333</output>
<gadget id="calculator">(25/12) * 20</gadget>
<output>125/3 = around 41.666667</output>
<result>B</result> | B | 43.1818 | There are 20 poles with a constant distance between each pole. A car takes 25 second to reach the 12th pole. How much will it take to reach the last pole. | {
"A": "43.1543",
"B": "43.1818",
"C": "43.45128",
"D": "43.41288",
"E": "43.41222"
} | multiply(divide(25, 12), 20) | divide(n1,n2)|multiply(n0,#0)| | "assuming the car starts at the first pole . to reach the 12 th pole , the car need to travel 11 poles ( the first pole does n ' t count , as the car is already there ) . 11 poles 25 seconds 1 pole ( 25 / 11 ) seconds to reach the last ( 20 th ) pole , the car needs to travel 19 poles . 19 pole 19 x ( 25 / 11 ) seconds = 43.1818 seconds answer : b" | physics |
math_qa__1Jve8rxflMECS48n | Two employees X and Y are paid a total of Rs. 572 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Choices
A) s . 250 B) s . 280 C) s . 290 D) s . 260 E) s . 300 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">572 * 10</gadget>
<output>5_720</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">5_720 / 22</gadget>
<output>260</output>
<result>D</result> | D | 260 | Two employees X and Y are paid a total of Rs. 572 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? | {
"A": "s . 250",
"B": "s . 280",
"C": "s . 290",
"D": "s . 260",
"E": "s . 300"
} | divide(multiply(572, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4)| | "let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 572 but x = 120 % of y = 120 y / 100 = 12 y / 10 ∴ 12 y / 10 + y = 572 ⇒ y [ 12 / 10 + 1 ] = 572 ⇒ 22 y / 10 = 572 ⇒ 22 y = 5720 ⇒ y = 5720 / 22 = 520 / 2 = rs . 260 d" | general |
math_qa__PPOajYxZcrQgF4g9 | Along a yard 434 metres long, 32 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees Choose the most appropriate option: A) 14 B) 16 C) 10 D) 11 E) 12 | <gadget id="calculator">32 - 1</gadget>
<output>31</output>
<gadget id="calculator">434 / 31</gadget>
<output>14</output>
<result>A</result> | A | 14 | Along a yard 434 metres long, 32 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees | {
"A": "14",
"B": "16",
"C": "10",
"D": "11",
"E": "12"
} | divide(434, subtract(32, const_1)) | subtract(n1,const_1)|divide(n0,#0)| | "explanation : 32 trees have 31 gaps between them , required distance ( 434 / 31 ) = 14 option a" | physics |
math_qa__x4VbqNB2Jh0YMSTp | A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 300. Find the total worth of the stock? Choose the correct choice from the following choices:
A) 20029 B) 20000 C) 20289 D) 20027 E) 15000 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(1/20) * (4/5)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/10) * (1/5)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/25) - (1/50)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">300 / (1/50)</gadget>
<output>15_000</output>
<result>E</result> | E | 15,000 | A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 300. Find the total worth of the stock? | {
"A": "20029",
"B": "20000",
"C": "20289",
"D": "20027",
"E": "15000"
} | divide(300, subtract(multiply(divide(5, const_100), divide(subtract(const_100, 20), const_100)), multiply(divide(10, const_100), divide(20, const_100)))) | divide(n2,const_100)|divide(n1,const_100)|divide(n0,const_100)|subtract(const_100,n0)|divide(#3,const_100)|multiply(#1,#2)|multiply(#0,#4)|subtract(#6,#5)|divide(n3,#7)| | "let the total worth of the stock be rs . x . the sp of 20 % of the stock = 1 / 5 * x * 1.1 = 11 x / 50 the sp of 80 % of the stock = 4 / 5 * x * 0.95 = 19 x / 25 = 38 x / 50 total sp = 11 x / 50 + 38 x / 50 = 49 x / 50 overall loss = x - 49 x / 50 = x / 50 x / 50 = 300 = > x = 15000 answer : e" | gain |
math_qa__qfKJWx4hiieQMrUB | The product of a and b is equal to 11 more than twice the sum of a and b. If b = 7, what is the value of b - a?
Pick one: A) 2 B) 5 C) 7 D) 24 E) 35 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">14 + 11</gadget>
<output>25</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">25 / 5</gadget>
<output>5</output>
<gadget id="calculator">7 - 5</gadget>
<output>2</output>
<result>A</result> | A | 2 | The product of a and b is equal to 11 more than twice the sum of a and b. If b = 7, what is the value of b - a? | {
"A": "2",
"B": "5",
"C": "7",
"D": "24",
"E": "35"
} | subtract(7, divide(add(multiply(7, const_2), 11), subtract(7, const_2))) | multiply(n1,const_2)|subtract(n1,const_2)|add(n0,#0)|divide(#2,#1)|subtract(n1,#3)| | "given : ab = 2 ( a + b ) + 11 and b = 7 hence 7 a = 2 a + 14 + 11 5 a = 25 , a = 5 ( a potential trap . do not get excited here . we need to find b - a , not a ) b - a = 7 - 5 = 2 correct option : a" | general |
math_qa__ewhXqkdcNQjFU8Ax | Thirty percent of the members of a swim club have passed the lifesaving test. Among the members who havenotpassed the test, 5 have taken the preparatory course and 30 have not taken the course. How many members are there in the swim club? Answers
A) 60 B) 80 C) 50 D) 120 E) 140 | <gadget id="calculator">5 + 30</gadget>
<output>35</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">35 / (7/10)</gadget>
<output>50</output>
<result>C</result> | C | 50 | Thirty percent of the members of a swim club have passed the lifesaving test. Among the members who havenotpassed the test, 5 have taken the preparatory course and 30 have not taken the course. How many members are there in the swim club? | {
"A": "60",
"B": "80",
"C": "50",
"D": "120",
"E": "140"
} | divide(add(5, 30), divide(subtract(const_100, 30), const_100)) | add(n0,n1)|subtract(const_100,n1)|divide(#1,const_100)|divide(#0,#2)| | "30 % of the members have passed the test , thus 70 % have not passed the test . we also know that 30 + 5 = 42 members have not passed the test , thus 0.7 * total = 35 - - > total = 50 . answer : c ." | gain |
math_qa__uVoesGeG3IR3qaUr | 9 men are equal to as many women as are equal to 7 boys. All of them earn Rs.216 only. Men’s wages are? Options.
A) 6
B) 5
C) 2
D) 8
E) 2 | <gadget id="calculator">3 * 9</gadget>
<output>27</output>
<gadget id="calculator">216 / 27</gadget>
<output>8</output>
<result>D</result> | D | 8 | 9 men are equal to as many women as are equal to 7 boys. All of them earn Rs.216 only. Men’s wages are? | {
"A": "6",
"B": "5",
"C": "2",
"D": "8",
"E": "2"
} | divide(216, multiply(const_3, 9)) | multiply(n0,const_3)|divide(n2,#0)| | "9 m = xw = 7 b 9 m + xw + 7 b - - - - - 216 rs . 9 m + 9 m + 9 m - - - - - 216 rs . 27 m - - - - - - 216 rs . = > 1 m = 8 rs . answer : d" | general |
math_qa__x4ZLsE1stR6m6JBr | Jim is able to sell a hand-carved statue for $670 which was a 35% profit over his cost. How much did the statue originally cost him? Choose the most appropriate option:
A) $ 496.30 B) $ 512.40 C) $ 555.40 D) $ 574.90 E) $ 588.20 | <gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) + 1</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">670 / (27/20)</gadget>
<output>13_400/27 = around 496.296296</output>
<result>A</result> | A | 496.3 | Jim is able to sell a hand-carved statue for $670 which was a 35% profit over his cost. How much did the statue originally cost him? | {
"A": "$ 496.30",
"B": "$ 512.40",
"C": "$ 555.40",
"D": "$ 574.90",
"E": "$ 588.20"
} | divide(670, add(divide(35, const_100), const_1)) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)| | "670 is the final price that is the selling price . now suppose , x is the cost price . therefore 670 = 1.35 * x now while doing x = 670 / 1.35 calculation . i saw that the answer choices begin with 5 . so i did 135 * 5 = 675 . as 670 is less than 675 . therefore the quotient will be less than 5 . which is only in the answer a ." | gain |
math_qa__2Q0Jax7uj51duReA | A baseball team played 10 games and won 5. What is the ratio of the number of games played to the number of losses?
Choices
A) 5 : 1 B) 1 : 1 C) 20 : 4 D) 10 : 3 E) 2 : 1 | <gadget id="calculator">10 / 5</gadget>
<output>2</output>
<result>E</result> | E | 2 | A baseball team played 10 games and won 5. What is the ratio of the number of games played to the number of losses? | {
"A": "5 : 1",
"B": "1 : 1",
"C": "20 : 4",
"D": "10 : 3",
"E": "2 : 1"
} | divide(10, 5) | divide(n0,n1) | the number of games played is 10 . the number of games won is 5 , so 10 - 5 = 5 = number of game losses . answer = ! 0 : 5 = 2 : 1 answer is e | other |
math_qa__MeGrbJAuha9FKMCc | 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm, there are 15 buffaloes, 8 oxen, and 24 cows. The fodder for these cattle is available for 48 days. If 40 more cows and 15 more buffaloes are brought in, how many days will the fodder last? Options
A) 20 B) 24 C) 28 D) 32 E) 36 | <gadget id="calculator">24 / 4</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">15 + 18</gadget>
<output>33</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">33 + 12</gadget>
<output>45</output>
<gadget id="calculator">48 * 45</gadget>
<output>2_160</output>
<gadget id="calculator">15 + 15</gadget>
<output>30</output>
<gadget id="calculator">24 + 40</gadget>
<output>64</output>
<gadget id="calculator">64 / 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">30 + 48</gadget>
<output>78</output>
<gadget id="calculator">78 + 12</gadget>
<output>90</output>
<gadget id="calculator">2_160 / 90</gadget>
<output>24</output>
<result>B</result> | B | 24 | 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm, there are 15 buffaloes, 8 oxen, and 24 cows. The fodder for these cattle is available for 48 days. If 40 more cows and 15 more buffaloes are brought in, how many days will the fodder last? | {
"A": "20",
"B": "24",
"C": "28",
"D": "32",
"E": "36"
} | divide(multiply(48, add(add(15, multiply(divide(24, 4), 3)), multiply(divide(8, 2), 3))), add(add(add(15, 15), multiply(divide(add(24, 40), 4), 3)), multiply(divide(8, 2), 3))) | add(n3,n8)|add(n5,n7)|divide(n5,n1)|divide(n4,n2)|divide(#1,n1)|multiply(n0,#2)|multiply(n0,#3)|add(n3,#5)|multiply(n0,#4)|add(#7,#6)|add(#0,#8)|add(#10,#6)|multiply(n6,#9)|divide(#12,#11)| | "2 oxen = 3 buffaloes = 4 cows also : 15 buffaloes + 8 oxen + 24 cows = 10 oxen + 8 oxen + 12 oxen = 30 oxen there is enough fodder for 1 oxen for 30 * 48 days . 40 cows + 15 buffaloes = 20 oxen + 10 oxen = 30 oxen the new total is equal to 60 oxen instead of 30 oxen . 30 * 48 / 60 oxen = 24 days the answer is b ." | general |
math_qa__8pqj1leoUupCQBF2 | The purchase price of an article is $48. In order to include 10% of cost for overhead and to provide $12 of net profit, the markup should be Choices: A) 15 % B) 25 % C) 35 % D) 40 % E) 45 % | <gadget id="calculator">12 / 48</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<gadget id="calculator">25 + 10</gadget>
<output>35</output>
<result>C</result> | C | 35 | The purchase price of an article is $48. In order to include 10% of cost for overhead and to provide $12 of net profit, the markup should be | {
"A": "15 %",
"B": "25 %",
"C": "35 %",
"D": "40 %",
"E": "45 %"
} | add(multiply(divide(12, 48), const_100), 10) | divide(n2,n0)|multiply(#0,const_100)|add(n1,#1)| | "cost price of article = 48 $ % of overhead cost = 10 net profit = 12 $ we need to calculate % markup net profit as % of cost price = ( 12 / 48 ) * 100 = 25 % total markup should be = 25 + 10 = 35 % answer c" | gain |
math_qa__zuYmlcaFzs24cjXT | In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/8. For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life? Select.
A) 134
B) 146
C) 152
D) 162
E) 170 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 - (1/8)</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">200 * (7/8)</gadget>
<output>175</output>
<gadget id="calculator">175 * (7/8)</gadget>
<output>1_225/8 = around 153.125</output>
<gadget id="calculator">(1_225/8) * (7/8)</gadget>
<output>8_575/64 = around 133.984375</output>
<result>A</result> | A | 134 | In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/8. For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life? | {
"A": "134",
"B": "146",
"C": "152",
"D": "162",
"E": "170"
} | multiply(multiply(multiply(200, subtract(1, divide(1, 8))), subtract(1, divide(1, 8))), subtract(1, divide(1, 8))) | divide(n1,n2)|subtract(n1,#0)|multiply(n3,#1)|multiply(#2,#1)|multiply(#3,#1)| | "the probability of survival for each of the first 3 months of life is 1 - 1 / 8 = 7 / 8 , so of 200 newborn 200 * 7 / 8 * 7 / 8 * 7 / 8 = ~ 134 is expected to survive . answer : a ." | probability |
math_qa__bC4P7UMwMLxDXK0R | Increasing the original price of a certain item by 15 percent and then increasing the new price by 25 percent is equivalent to increasing the original price by what percent?
Choices.
A) 31.25
B) 37.5
C) 50.0
D) 52.5
E) 43.75 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) + 1</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(5/4) * (23/20)</gadget>
<output>23/16 = around 1.4375</output>
<gadget id="calculator">(23/16) - 1</gadget>
<output>7/16 = around 0.4375</output>
<gadget id="calculator">(7/16) * 100</gadget>
<output>175/4 = around 43.75</output>
<result>E</result> | E | 43.75 | Increasing the original price of a certain item by 15 percent and then increasing the new price by 25 percent is equivalent to increasing the original price by what percent? | {
"A": "31.25",
"B": "37.5",
"C": "50.0",
"D": "52.5",
"E": "43.75"
} | multiply(subtract(multiply(add(divide(25, const_100), const_1), add(divide(15, const_100), const_1)), const_1), const_100) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "we ' re told that the original price of an item is increased by 15 % and then that price is increased by 25 % . . . . if . . . . starting value = $ 100 + 15 % = 100 + . 15 ( 100 ) = 115 + 25 % = 115 + . 25 ( 115 ) = 115 + 28.75 = 143.75 the question asks how the final price relates to the original price . this is essentially about percentage change , which means we should use the percentage change formula : percentage change = ( new - old ) / old = difference / original doing either calculation will yield the same result : 43.75 / 100 = 43.75 % final answer : e" | gain |
math_qa__gGUoJTIFLwCn4YoT | Find the least number must be subtracted from 378461 so that remaining no.is divisible by 13? Choose the most appropriate option.
A) 4
B) 5
C) 7
D) 6
E) 8 | <gadget id="calculator">378_461 / 13</gadget>
<output>378_461/13 = around 29_112.384615</output>
<gadget id="calculator">floor(378_461/13)</gadget>
<output>29_112</output>
<gadget id="calculator">29_112 * 13</gadget>
<output>378_456</output>
<gadget id="calculator">378_461 - 378_456</gadget>
<output>5</output>
<result>B</result> | B | 5 | Find the least number must be subtracted from 378461 so that remaining no.is divisible by 13? | {
"A": "4",
"B": "5",
"C": "7",
"D": "6",
"E": "8"
} | subtract(378461, multiply(floor(divide(378461, 13)), 13)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)| | "on dividing 378461 by 13 we get the remainder 5 , so 5 should be subtracted b" | general |
math_qa__UEDSXXxYhneVwkce | The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 40% profit? Choose the correct choice from the following options.
A) $ 480 B) $ 450 C) $ 896 D) $ 870 E) $ 660 | <gadget id="calculator">832 + 448</gadget>
<output>1_280</output>
<gadget id="calculator">1_280 / 2</gadget>
<output>640</output>
<gadget id="calculator">640 * 40</gadget>
<output>25_600</output>
<gadget id="calculator">25_600 / 100</gadget>
<output>256</output>
<gadget id="calculator">256 + 640</gadget>
<output>896</output>
<result>C</result> | C | 896 | The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 40% profit? | {
"A": "$ 480",
"B": "$ 450",
"C": "$ 896",
"D": "$ 870",
"E": "$ 660"
} | add(divide(multiply(divide(add(832, 448), const_2), 40), const_100), divide(add(832, 448), const_2)) | add(n0,n1)|divide(#0,const_2)|multiply(n2,#1)|divide(#2,const_100)|add(#3,#1) | let c . p . = $ x . then , 832 - x = x - 448 2 x = 1280 = > x = 640 required s . p . = 140 % of $ 640 = $ 896 . c | gain |
math_qa__93m0PMR7c8slKDoi | A certain pair of used shoes can be repaired for $11.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $28.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes?
Choose the correct choice from the following
A) 20.8 B) 21.46 C) 21.74 D) 22.3 E) 21.4 | <gadget id="calculator">11.5 * 2</gadget>
<output>23</output>
<gadget id="calculator">28 - 23</gadget>
<output>5</output>
<gadget id="calculator">5 / 23</gadget>
<output>5/23 = around 0.217391</output>
<gadget id="calculator">100 * (5/23)</gadget>
<output>500/23 = around 21.73913</output>
<result>C</result> | C | 21.74 | A certain pair of used shoes can be repaired for $11.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $28.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes? | {
"A": "20.8",
"B": "21.46",
"C": "21.74",
"D": "22.3",
"E": "21.4"
} | multiply(const_100, divide(subtract(28.00, multiply(11.50, 2)), multiply(11.50, 2))) | multiply(n0,n3)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "1 ) cost of repairing = 11.5 ( for one year ) , therefore for 2 years it would be $ 23 . 2 ) cost of new pair which will last for 2 years is $ 28 . percentage change formula = ( final value - initial value ) / ( initial value ) * 100 . in this case the final value would be the price of new shoeinitial value would be the cost of repairing the old shoe . i . e ( 28 - 23 ) / ( 23 ) * 100 = 21.74 % . ans is c" | general |
math_qa__H8896BjAGhLynppo | Renu can do a piece of work in 6 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone?
Choose the correct choice from the following choices: A) 10 B) 12 C) 14 D) 15 E) 17 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/4) - (1/6)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>B</result> | B | 12 | Renu can do a piece of work in 6 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone? | {
"A": "10",
"B": "12",
"C": "14",
"D": "15",
"E": "17"
} | inverse(subtract(divide(const_1, 4), divide(const_1, 6))) | divide(const_1,n1)|divide(const_1,n0)|subtract(#0,#1)|inverse(#2)| | "renu ’ s one day ’ s work = 1 / 6 suma ’ s one day ’ s work = 1 / 4 - 1 / 6 = 1 / 12 suma can do it alone in 12 days . answer : b" | physics |
math_qa__JmuEsDX4UYOgmiPC | Working at their respective constant rates, machine A makes 100 copies in 8 minutes and machine B makes 150 copies in 10 minutes. If these machines work simultaneously at their respective rates for 30 minutes, what is the total number of copies that they will produce? Choose the correct choice from the following answers: A) 250 B) 425 C) 675 D) 825 E) 750 | <gadget id="calculator">100 / 8</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">150 / 10</gadget>
<output>15</output>
<gadget id="calculator">(25/2) + 15</gadget>
<output>55/2 = around 27.5</output>
<gadget id="calculator">(55/2) * 30</gadget>
<output>825</output>
<result>D</result> | D | 825 | Working at their respective constant rates, machine A makes 100 copies in 8 minutes and machine B makes 150 copies in 10 minutes. If these machines work simultaneously at their respective rates for 30 minutes, what is the total number of copies that they will produce? | {
"A": "250",
"B": "425",
"C": "675",
"D": "825",
"E": "750"
} | multiply(add(divide(100, 8), divide(150, 10)), 30) | divide(n0,n1)|divide(n2,n3)|add(#0,#1)|multiply(n4,#2)| | "machine a can produce 100 * 30 / 8 = 375 copies and , machine b can produce 150 * 30 / 10 = 825 copies total producing 700 copies . d is the answer" | physics |
math_qa__Nq12i9ksu49Sn1xW | Q-1) Of the 84 parents who attended a meeting at a
school, 25 volunteered to supervise children during
the school picnic and 11 volunteered both to supervise
children during the picnic and to bring refreshments to
the picnic. If the number of parents who volunteered
to bring refreshments was 1.5 times the number of
parents who neither volunteered to supervise children
during the picnic nor volunteered to bring
refreshments, how many of the parents volunteered to
bring refreshments?
Choose the most appropriate option.
A) 25 B) 36 C) 38 D) 45 E) 42 | <gadget id="calculator">84 - 25</gadget>
<output>59</output>
<gadget id="calculator">59 * 1.5</gadget>
<output>88.5</output>
<gadget id="calculator">88.5 - 11</gadget>
<output>77.5</output>
<gadget id="calculator">1.5 + 1</gadget>
<output>2.5</output>
<gadget id="calculator">77.5 / 2.5</gadget>
<output>31</output>
<gadget id="calculator">31 + 11</gadget>
<output>42</output>
<result>E</result> | E | 42 | Q-1) Of the 84 parents who attended a meeting at a
school, 25 volunteered to supervise children during
the school picnic and 11 volunteered both to supervise
children during the picnic and to bring refreshments to
the picnic. If the number of parents who volunteered
to bring refreshments was 1.5 times the number of
parents who neither volunteered to supervise children
during the picnic nor volunteered to bring
refreshments, how many of the parents volunteered to
bring refreshments? | {
"A": "25",
"B": "36",
"C": "38",
"D": "45",
"E": "42"
} | add(divide(subtract(multiply(subtract(84, 25), 1.5), 11), add(1.5, const_1)), 11) | add(n4,const_1)|subtract(n1,n2)|multiply(n4,#1)|subtract(#2,n3)|divide(#3,#0)|add(n3,#4) | i used the following formula : total = group 1 + group 2 + neither - both using the information from the question stem , we have : 84 total people 25 who supervise ( group 1 ) x who neither supervise nor bring refreshments 1.5 x people who bring refreshments ( group 2 ) 11 who supervise and bring refreshments ( both ) therefore . . . 84 = 25 + 1.5 x + x - 11 solving , we get x = 28 since we want the value of those who bring refreshments and supervise : 1.5 ( 28 ) = 42 answer is e | other |
math_qa__gqeWZfs2pquWSWBQ | in 15 year ’ s time the combined age of my 4 brothers will be 107 . what will it be in 6 year ’ s time ?
Choose the correct option
A) 65 B) 87 C) 71 D) 60 E) 66 | <gadget id="calculator">15 - 6</gadget>
<output>9</output>
<gadget id="calculator">4 * 9</gadget>
<output>36</output>
<gadget id="calculator">107 - 36</gadget>
<output>71</output>
<result>C</result> | C | 71 | in 15 year ’ s time the combined age of my 4 brothers will be 107 . what will it be in 6 year ’ s time ? | {
"A": "65",
"B": "87",
"C": "71",
"D": "60",
"E": "66"
} | subtract(107, multiply(4, subtract(15, 6))) | subtract(n0,n3)|multiply(n1,#0)|subtract(n2,#1) | c 71 combined age in 15 years = 107 . 4 × 15 = 60 , therefore combined age now is 107 – 60 = 47 . in 6 years time , therefore , combined age will be 47 + 24 ( 4 × 6 ) = 71 . | probability |
math_qa__BfMBFvXbZjddnAjw | If Sharon's weekly salary increased by 10 percent, she would earn $330 per week. If instead, her weekly salary were to increase by 8 percent, how much would she earn per week?
Choose the most appropriate option:
A) rs . 424
B) rs . 524
C) rs . 324
D) rs . 350
E) rs . 354 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">330 / (11/10)</gadget>
<output>300</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/25) * 300</gadget>
<output>24</output>
<gadget id="calculator">300 + 24</gadget>
<output>324</output>
<result>C</result> | C | 324 | If Sharon's weekly salary increased by 10 percent, she would earn $330 per week. If instead, her weekly salary were to increase by 8 percent, how much would she earn per week? | {
"A": "rs . 424",
"B": "rs . 524",
"C": "rs . 324",
"D": "rs . 350",
"E": "rs . 354"
} | add(divide(330, add(const_1, divide(10, const_100))), multiply(divide(8, const_100), divide(330, add(const_1, divide(10, const_100))))) | divide(n0,const_100)|divide(n2,const_100)|add(#0,const_1)|divide(n1,#2)|multiply(#1,#3)|add(#3,#4)| | "soln : - ( 330 / 110 ) 108 = 324 in this case long division does not take much time . ( 330 / 110 ) 108 = 324 answer : c" | general |
math_qa__VSFQq2OJRC2ChH9U | A bicycle wheel has a diameter of 0.61m. How many complete revolutions does it make in 1km? Options:
A) 246
B) 522
C) 1408
D) 710
E) 223 | <gadget id="calculator">1_000 * 1</gadget>
<output>1_000</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">3 + (7/50)</gadget>
<output>157/50 = around 3.14</output>
<gadget id="calculator">(157/50) * 0.61</gadget>
<output>1.9154</output>
<gadget id="calculator">1_000 / 1.9154</gadget>
<output>522.08416</output>
<result>B</result> | B | 522 | A bicycle wheel has a diameter of 0.61m. How many complete revolutions does it make in 1km? | {
"A": "246",
"B": "522",
"C": "1408",
"D": "710",
"E": "223"
} | divide(multiply(const_1000, 1), multiply(add(const_3, divide(add(multiply(const_3, const_4), const_2), power(add(multiply(const_4, const_2), const_2), const_2))), 0.61)) | multiply(n1,const_1000)|multiply(const_3,const_4)|multiply(const_2,const_4)|add(#1,const_2)|add(#2,const_2)|power(#4,const_2)|divide(#3,#5)|add(#6,const_3)|multiply(n0,#7)|divide(#0,#8)| | "1 revolution = 3.14 * diameter . number of revolutions in 1 km = 1000 m / ( 3.14 * 0.61 m ) = 522.1 . hence 522 complete revolutions . answer b" | physics |
math_qa__NoGQOVrgmZP85xaw | nitin borrowed some money at the rate of 6 % p . a . for the first 3 years , 9 % p . a . for the next 5 years and 13 % p . a . for the period beyond 8 years . if the total interest paid by him at the end of 11 years is rs . 8160 , how much money did he borrow ? Choose the most appropriate option
A) 8000 B) 2787 C) 27766 D) 9976 E) 21671 | <gadget id="calculator">8_160 * 100</gadget>
<output>816_000</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">9 * 5</gadget>
<output>45</output>
<gadget id="calculator">18 + 45</gadget>
<output>63</output>
<gadget id="calculator">13 * 3</gadget>
<output>39</output>
<gadget id="calculator">63 + 39</gadget>
<output>102</output>
<gadget id="calculator">816_000 / 102</gadget>
<output>8_000</output>
<result>A</result> | A | 8,000 | nitin borrowed some money at the rate of 6 % p . a . for the first 3 years , 9 % p . a . for the next 5 years and 13 % p . a . for the period beyond 8 years . if the total interest paid by him at the end of 11 years is rs . 8160 , how much money did he borrow ? | {
"A": "8000",
"B": "2787",
"C": "27766",
"D": "9976",
"E": "21671"
} | divide(multiply(8160, const_100), add(add(multiply(6, 3), multiply(9, 5)), multiply(13, 3))) | multiply(n7,const_100)|multiply(n0,n1)|multiply(n2,n3)|multiply(n1,n4)|add(#1,#2)|add(#4,#3)|divide(#0,#5) | let the sum be rs . x . then , [ ( x * 6 * 3 ) / 100 ] + [ ( x * 9 * 5 ) / 100 ] + [ ( x * 13 * 3 ) / 100 ] = 8160 18 x + 45 x + 39 x = ( 8160 * 100 ) 102 x = 816000 = > x = 8000 . answer : a | gain |
math_qa__ncYwiiAuqnV4hhcX | The ratio between the sale price and the cost price of an article is 6:2. What is the ratio between the profit and the cost price of that article? Options.
A) 23 B) 1 : 2 C) 2 : 5 D) 3 : 5 E) 2 : 1 | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>E</result> | E | 2 | The ratio between the sale price and the cost price of an article is 6:2. What is the ratio between the profit and the cost price of that article? | {
"A": "23",
"B": "1 : 2",
"C": "2 : 5",
"D": "3 : 5",
"E": "2 : 1"
} | divide(subtract(6, 2), 2) | subtract(n0,n1)|divide(#0,n1)| | "c . p . = rs . 2 x and s . p . = rs . 6 x . then , gain = rs . 4 x required ratio = 4 x : 2 x = 2 : 1 e" | other |
math_qa__EtTGsXN04F4tTcJg | A certain bus driver is paid a regular rate of $16 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $1200 in total compensation, how many total hours did he work that week?
Choices
A) 60 B) 40 C) 44 D) 48 E) 52 | <gadget id="calculator">16 * 40</gadget>
<output>640</output>
<gadget id="calculator">1_200 - 640</gadget>
<output>560</output>
<gadget id="calculator">100 + 75</gadget>
<output>175</output>
<gadget id="calculator">16 * 175</gadget>
<output>2_800</output>
<gadget id="calculator">2_800 / 100</gadget>
<output>28</output>
<gadget id="calculator">560 / 28</gadget>
<output>20</output>
<gadget id="calculator">40 + 20</gadget>
<output>60</output>
<result>A</result> | A | 60 | A certain bus driver is paid a regular rate of $16 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $1200 in total compensation, how many total hours did he work that week? | {
"A": "60",
"B": "40",
"C": "44",
"D": "48",
"E": "52"
} | add(40, divide(subtract(1200, multiply(16, 40)), divide(multiply(16, add(const_100, 75)), const_100))) | add(n3,const_100)|multiply(n0,n1)|multiply(n0,#0)|subtract(n4,#1)|divide(#2,const_100)|divide(#3,#4)|add(n1,#5)| | "for 40 hrs = 40 * 16 = 640 excess = 1200 - 640 = 560 for extra hours = . 75 ( 16 ) = 12 + 16 = 28 number of extra hrs = 560 / 28 = 20 total hrs = 40 + 20 = 60 answer a 60" | general |
math_qa__cZmTnMCuwLnsOPkN | If 5^29 * 4^15 = 2 * 10^n, what is the value of n? Choose the correct choice from the following options.
A) 11
B) 21
C) 22
D) 29
E) 32 | <gadget id="calculator">2 * 15</gadget>
<output>30</output>
<gadget id="calculator">30 - 1</gadget>
<output>29</output>
<result>D</result> | D | 29 | If 5^29 * 4^15 = 2 * 10^n, what is the value of n? | {
"A": "11",
"B": "21",
"C": "22",
"D": "29",
"E": "32"
} | subtract(multiply(const_2, 15), const_1) | multiply(n3,const_2)|subtract(#0,const_1) | my attempt : 5 ^ ( 29 ) * 4 ^ ( 15 ) = 2 * 10 ^ p 5 ^ ( 29 ) * 2 ^ ( 30 ) = 2 * ( 2 * 5 ) ^ p 5 ^ ( 29 ) * 2 ^ ( 30 ) = 2 * 2 ^ ( p ) * 5 ^ ( p ) 5 ^ ( 29 ) * 2 ^ ( 30 ) = 2 ^ ( p + 1 ) * 5 ^ ( p ) = > ( p + 1 ) = 30 = > p = 29 answer : 29 ( d ) | general |
math_qa__orwtmelYjVFeDbyZ | A man is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of the train and its speed. Choose the correct answer
A) 10 m / sec B) 15 m / sec C) 18 m / sec D) 19 m / sec E) 25 m / sec | <gadget id="calculator">180 / 20</gadget>
<output>9</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/8) - (1/20)</gadget>
<output>3/40 = around 0.075</output>
<gadget id="calculator">9 / (3/40)</gadget>
<output>120</output>
<gadget id="calculator">120 / 8</gadget>
<output>15</output>
<result>B</result> | B | 15 | A man is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of the train and its speed. | {
"A": "10 m / sec",
"B": "15 m / sec",
"C": "18 m / sec",
"D": "19 m / sec",
"E": "25 m / sec"
} | speed(divide(divide(180, 20), subtract(inverse(8), inverse(20))), 8) | divide(n0,n1)|inverse(n2)|inverse(n1)|subtract(#1,#2)|divide(#0,#3)|speed(#4,n2) | if length of train is l and speed of train is s , then l / s = 8 ( l + 180 ) / s = 20 ( l + 180 ) / l = 20 / 8 = 5 / 2 2 l + 360 = 5 * l 3 * l = 360 l = 120 mtrs s = l / 8 = 120 / 8 = 15 m / sec answer : b | physics |
math_qa__J4yYIG21YRC3Szu1 | If 2^k = 4, then 2^(2K+2) =
Choose the most appropriate option:
A) 29 B) 45 C) 81 D) 64 E) 18 | <gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">16 * 4</gadget>
<output>64</output>
<result>D</result> | D | 64 | If 2^k = 4, then 2^(2K+2) = | {
"A": "29",
"B": "45",
"C": "81",
"D": "64",
"E": "18"
} | multiply(power(4, 2), power(2, 2)) | power(n1,n3)|power(n0,n4)|multiply(#0,#1)| | "2 ^ k = 4 2 ^ 2 k = 4 ^ 2 2 ^ 2 k = 16 2 ^ ( 2 k + 2 ) = 2 ^ 2 k * 2 ^ 2 = 16 * 4 = 64 answer : d" | general |
math_qa__a6kRbWwjsYqR7TPF | A spirit and water solution is sold in a market. The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has. A solution of 1 liter of spirit and 1 liter of water costs 60 cents. How many cents does a solution of 1 liter of spirit and 2 liters of water cost? Select the correct option: A) 13 B) 33 C) 50 D) 51 E) 60 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">60 * (1/3)</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<result>E</result> | E | 60 | A spirit and water solution is sold in a market. The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has. A solution of 1 liter of spirit and 1 liter of water costs 60 cents. How many cents does a solution of 1 liter of spirit and 2 liters of water cost? | {
"A": "13",
"B": "33",
"C": "50",
"D": "51",
"E": "60"
} | multiply(multiply(60, divide(1, add(1, 2))), add(1, 2)) | add(n0,n4)|divide(n0,#0)|multiply(n2,#1)|multiply(#0,#2)| | "yes , ensure that you understand the relation thoroughly ! cost per liter = k * fraction of spirit 60 cents is the cost of 2 liters of solution ( 1 part water , 1 part spirit ) . so cost per liter is 30 cents . fraction of spirit is 1 / 2 . 30 = k * ( 1 / 2 ) k = 60 cost per liter = 60 * ( 1 / 3 ) ( 1 part spirit , 2 parts water ) cost for 3 liters = 60 * ( 1 / 3 ) * 3 = 50 cents e . 60 cents" | geometry |
math_qa__wroBoRkzlE44Pvtb | The average marks of a class of 28 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students? Choices.
A) 52.2 B) 59.5 C) 52.8 D) 52.5 E) 52.1 | <gadget id="calculator">28 * 40</gadget>
<output>1_120</output>
<gadget id="calculator">50 * 60</gadget>
<output>3_000</output>
<gadget id="calculator">1_120 + 3_000</gadget>
<output>4_120</output>
<gadget id="calculator">28 + 50</gadget>
<output>78</output>
<gadget id="calculator">4_120 / 78</gadget>
<output>2_060/39 = around 52.820513</output>
<result>C</result> | C | 52.8 | The average marks of a class of 28 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students? | {
"A": "52.2",
"B": "59.5",
"C": "52.8",
"D": "52.5",
"E": "52.1"
} | divide(add(multiply(28, 40), multiply(50, 60)), add(28, 50)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | "sum of the marks for the class of 28 students = 28 * 40 = 1120 sum of the marks for the class of 50 students = 50 * 60 = 3000 sum of the marks for the class of 78 students = 1120 + 3000 = 4120 average marks of all the students = 4120 / 78 = 52.8 answer : c" | general |
math_qa__9ETPPURpBcuxv3gZ | Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed? Select:
A) 256 B) 512 C) 432 D) 352 E) 640 | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 8</gadget>
<output>64</output>
<gadget id="calculator">64 * 8</gadget>
<output>512</output>
<result>B</result> | B | 512 | Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed? | {
"A": "256",
"B": "512",
"C": "432",
"D": "352",
"E": "640"
} | multiply(multiply(divide(16, const_2), divide(16, const_2)), divide(16, const_2)) | divide(n0,const_2)|multiply(#0,#0)|multiply(#0,#1) | let total number of children be x . then , x * ( 1 / 8 ) x = ( x / 2 ) x 16 x = 64 . number of notebooks = ( 1 / 8 ) x ^ 2 = ( 1 / 8 ) x 64 x 64 = 512 . answer is b . | general |
math_qa__uIhyuU4NoHCOHwPs | Tim and Élan are 120 miles away from one another. They are starting to move towards each other simultaneously, Tim at a speed of 10 Mph and Élan at a speed of 5 Mph. If every hour they double their speeds, what is the distance that Tim will pass until he meets Élan? Answers:
A) 30 miles .
B) 35 miles .
C) 45 miles .
D) 60 miles .
E) 80 miles . | <gadget id="calculator">5 + 10</gadget>
<output>15</output>
<gadget id="calculator">10 / 15</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 120</gadget>
<output>80</output>
<result>E</result> | E | 80 | Tim and Élan are 120 miles away from one another. They are starting to move towards each other simultaneously, Tim at a speed of 10 Mph and Élan at a speed of 5 Mph. If every hour they double their speeds, what is the distance that Tim will pass until he meets Élan? | {
"A": "30 miles .",
"B": "35 miles .",
"C": "45 miles .",
"D": "60 miles .",
"E": "80 miles ."
} | multiply(divide(10, add(5, 10)), 120) | add(n1,n2)|divide(n1,#0)|multiply(n0,#1)| | "tim and elan will meet at the same time while their ratio of speed is 2 : 1 respectively . so their individual distance traveled ratio will be same . plugging in the answer choice only answer choice e meet the 2 : 1 ( tim : elan = 80 : 40 ) ratio of maintaining total distance traveled 120 miles so correct answer e" | physics |
math_qa__qWiaiqjAqa5drgO7 | The diagonals of a rhombus are 14 cm and 20 cm. Find its area?
Options.
A) 176 B) 190 C) 140 D) 278 E) 292 | <gadget id="calculator">(14 * 20) / 2</gadget>
<output>140</output>
<result>C</result> | C | 140 | The diagonals of a rhombus are 14 cm and 20 cm. Find its area? | {
"A": "176",
"B": "190",
"C": "140",
"D": "278",
"E": "292"
} | rhombus_area(14, 20) | rhombus_area(n0,n1)| | "1 / 2 * 14 * 20 = 140 answer : c" | geometry |
math_qa__9WcdlW8JsikHxm6p | Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively Choose the correct choice.
A) 125 B) 127 C) 129 D) 131 E) 150 | <gadget id="calculator">1_661 - 10</gadget>
<output>1_651</output>
<gadget id="calculator">2_045 - 13</gadget>
<output>2_032</output>
<gadget id="calculator">gcd(1_651, 2_032)</gadget>
<output>127</output>
<result>B</result> | B | 127 | Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively | {
"A": "125",
"B": "127",
"C": "129",
"D": "131",
"E": "150"
} | gcd(subtract(1661, 10), subtract(2045, 13)) | subtract(n0,n2)|subtract(n1,n3)|gcd(#0,#1) | explanation : in this type of question , its obvious we need to calculate the hcf , trick is hcf of ( 1661 - 10 ) and ( 2045 - 13 ) = hcf ( 1651 , 2032 ) = 127 option b | general |
math_qa__3I2bhlXITnNS4aq3 | The price of a T.V. set worth Rs. 40000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? Pick one: A) 22678 B) 26699 C) 26788 D) 19000 E) 39000 | <gadget id="calculator">40_000 - 1_000</gadget>
<output>39_000</output>
<result>E</result> | E | 39,000 | The price of a T.V. set worth Rs. 40000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? | {
"A": "22678",
"B": "26699",
"C": "26788",
"D": "19000",
"E": "39000"
} | subtract(40000, 1000) | subtract(n0,n2)| | "money paid in cash = rs . 1000 balance payment = ( 40000 - 1000 ) = rs . 39000 answer : e" | gain |
math_qa__7PaVf91hpuz9Co4f | 3 candidates in an election and received 2136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election?
Choose the correct answer
A) 45 % B) 49 % C) 54 % D) 59 % E) 61 % | <gadget id="calculator">2_136 + 7_636</gadget>
<output>9_772</output>
<gadget id="calculator">9_772 + 11_628</gadget>
<output>21_400</output>
<gadget id="calculator">11_628 / 21_400</gadget>
<output>2_907/5_350 = around 0.543364</output>
<gadget id="calculator">(2_907/5_350) * 100</gadget>
<output>5_814/107 = around 54.336449</output>
<result>C</result> | C | 54 | 3 candidates in an election and received 2136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election? | {
"A": "45 %",
"B": "49 %",
"C": "54 %",
"D": "59 %",
"E": "61 %"
} | multiply(divide(11628, add(add(2136, 7636), 11628)), const_100) | add(n1,n2)|add(n3,#0)|divide(n3,#1)|multiply(#2,const_100)| | "total number of votes polled = ( 2136 + 7636 + 11628 ) = 21260 so , required percentage = 11628 / 21260 * 100 = 54 % c" | gain |
math_qa__3IxtLFIiEGwWXFBc | Find the number of terms in an arithmetic progression with the first term 2 and the last term being 62, given that common difference is 2.
Choose the correct choice from the following options: A) 31 B) 40 C) 22 D) 27 E) 25 | <gadget id="calculator">62 - 2</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 + 1</gadget>
<output>31</output>
<result>A</result> | A | 31 | Find the number of terms in an arithmetic progression with the first term 2 and the last term being 62, given that common difference is 2. | {
"A": "31",
"B": "40",
"C": "22",
"D": "27",
"E": "25"
} | add(divide(subtract(62, 2), 2), const_1) | subtract(n1,n0)|divide(#0,n0)|add(#1,const_1) | the n th term = a + ( n - 1 ) * d 62 = 2 + ( n - 1 ) * 2 , 62 – 2 = ( n - 1 ) * 2 , n = 60 / 2 + 1 = 31 . answer : a | general |
math_qa__vbjcUxlM5CnUXQof | a, b, c, d, and e are positive consecutive integers and a < b < c < d < e.
If the sum of a + b is one less than e, and the product of ab is one more than d, then what is the value of c?
Choose the correct answer:
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">-2</gadget>
<output>-2</output>
<gadget id="calculator">-(-2)</gadget>
<output>2</output>
<gadget id="calculator">(-2) ** 2</gadget>
<output>4</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">-8</gadget>
<output>-8</output>
<gadget id="calculator">(-8) * 4</gadget>
<output>-32</output>
<gadget id="calculator">4 - (-32)</gadget>
<output>36</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">2 + 6</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>B</result> | B | 4 | a, b, c, d, and e are positive consecutive integers and a < b < c < d < e.
If the sum of a + b is one less than e, and the product of ab is one more than d, then what is the value of c? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(add(negate(negate(const_2)), sqrt(subtract(power(negate(const_2), const_2), multiply(negate(multiply(const_2, const_4)), power(negate(const_2), const_2))))), negate(negate(const_2))) | multiply(const_2,const_4)|negate(const_2)|negate(#1)|negate(#0)|power(#1,const_2)|multiply(#3,#4)|subtract(#4,#5)|sqrt(#6)|add(#2,#7)|divide(#8,#2) | since the integers are consecutive , we can write each as the previous integer + 1 . for example , b = a + 1 , and c = b + 1 . we can also reverse this : a + 1 = b , and b + 1 = c . since ab = d + 1 , we can also write this ab = e . since a + b = e - 1 , then a + b = ab - 1 . find the pair of consecutive integers whose sum is one less than its product . these numbers are 2 and 3 ( sum : 5 ; product : 6 ) . now that we know how the series starts , we can find the value of c . if the first two numbers are 2 and 3 , the third number is 4 ( option b ) . | general |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.