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stringlengths 7
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math_qa__H7zU9GxZzfT1CogH | A train is running at a speed of 40 km/hr and it crosses a post in 17.1 seconds. What is the length of the train? Choose the correct choice from the following options:
A) 190 metres
B) 160 metres
C) 200 metres
D) 120 metres
E) 250 metres | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">40 * (5/18)</gadget>
<output>100/9 = around 11.111111</output>
<gadget id="calculator">17.1 * (100/9)</gadget>
<output>190</output>
<result>A</result> | A | 190 | A train is running at a speed of 40 km/hr and it crosses a post in 17.1 seconds. What is the length of the train? | {
"A": "190 metres",
"B": "160 metres",
"C": "200 metres",
"D": "120 metres",
"E": "250 metres"
} | multiply(17.1, multiply(40, const_0_2778)) | multiply(n0,const_0_2778)|multiply(n1,#0)| | "speed of the train , v = 40 km / hr = 40000 / 3600 m / s = 400 / 36 m / s time taken to cross , t = 17.1 s distance covered , d = vt = ( 400 / 36 ) ã — 17.1 = 190 m distance covered is equal to the length of the train = 190 m correct answer is 190 metres a" | physics |
math_qa__pFc7qrfq3F7hu3Oe | Of the 160 people at a party, 70 were women, and 50 women tried the appetizer. If 50 people did not try the appetizer, what is the total number of men who tried the appetizer?
Choices
A) 40 B) 50 C) 60 D) 70 E) 80 | <gadget id="calculator">160 - 50</gadget>
<output>110</output>
<gadget id="calculator">110 - 50</gadget>
<output>60</output>
<result>C</result> | C | 60 | Of the 160 people at a party, 70 were women, and 50 women tried the appetizer. If 50 people did not try the appetizer, what is the total number of men who tried the appetizer? | {
"A": "40",
"B": "50",
"C": "60",
"D": "70",
"E": "80"
} | subtract(subtract(160, 50), 50) | subtract(n0,n3)|subtract(#0,n2)| | "total people at party = 160 women = 70 so men 160 - 70 = 90 no . of pple who tried appetizer = 160 - 50 ( given info ) = 110 no of women who tried appetizer = 50 so remaining ppl ( men ) who tried the appetizer = 110 - 50 = 60 correct option c" | general |
math_qa__alq13h5XxZZ8ndXJ | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 20 sec. What is the length of the platform?
Choose the correct choice from the following answers:
A) 389 m B) 350 m C) 285 m D) 299 m E) 219 m | <gadget id="calculator">300 / 20</gadget>
<output>15</output>
<gadget id="calculator">15 * 39</gadget>
<output>585</output>
<gadget id="calculator">585 - 300</gadget>
<output>285</output>
<result>C</result> | C | 285 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 20 sec. What is the length of the platform? | {
"A": "389 m",
"B": "350 m",
"C": "285 m",
"D": "299 m",
"E": "219 m"
} | subtract(multiply(speed(300, 20), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 20 = 15 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 15 = > x = 285 m . answer : c" | physics |
math_qa__EyihjGJEeMYDKcva | A box measuring 49 inches long by 42 inches wide by 14 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective? Pick one: A) 78 B) 82 C) 84 D) 86 E) 88 | <gadget id="calculator">49 * 42</gadget>
<output>2_058</output>
<gadget id="calculator">2_058 * 14</gadget>
<output>28_812</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">7 ** 3</gadget>
<output>343</output>
<gadget id="calculator">28_812 / 343</gadget>
<output>84</output>
<result>C</result> | C | 84 | A box measuring 49 inches long by 42 inches wide by 14 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective? | {
"A": "78",
"B": "82",
"C": "84",
"D": "86",
"E": "88"
} | divide(multiply(multiply(49, 42), 14), volume_cube(divide(14, const_2))) | divide(n2,const_2)|multiply(n0,n1)|multiply(n2,#1)|volume_cube(#0)|divide(#2,#3)| | "least number of cubes will be required when the cubes that could fit in are biggest . 7 is the biggest number that could divide all three , 49 , 42 and 14 . thus side of cube must be 7 , and total number of cubes = 49 / 7 * 42 / 7 * 14 / 7 = 84 ans c ." | geometry |
math_qa__WnewKY2rs6glWgYz | The height of cylinder is 14 Cm and its diameter is 10 Cm. The volume of the cylinder is: Pick:
A) 4400 B) 2200 C) 5500 D) 1100 E) 3300 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">pi * (5 ** 2) * 14</gadget>
<output>350*pi = around 1_099.557429</output>
<result>D</result> | D | 1,100 | The height of cylinder is 14 Cm and its diameter is 10 Cm. The volume of the cylinder is: | {
"A": "4400",
"B": "2200",
"C": "5500",
"D": "1100",
"E": "3300"
} | volume_cylinder(divide(10, const_2), 14) | divide(n1,const_2)|volume_cylinder(#0,n0) | h = 14 cm and r = 5 cm cylinder volume = π r ( power 2 ) h = ( 22 / 7 × 5 × 5 × 14 ) cm ( power 3 ) = 1100 cm ( power 3 ) answer is d . | geometry |
math_qa__b64C7dQmf9HSrV5l | If 20 liters of chemical X are added to 80 liters of a mixture that is 20% chemical X and 80% chemical Y, then what percentage of the resulting mixture is chemical X? Select the correct option:
A) 30 %
B) 33 %
C) 36 %
D) 39 %
E) 42 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 80</gadget>
<output>16</output>
<gadget id="calculator">20 + 16</gadget>
<output>36</output>
<result>C</result> | C | 36 | If 20 liters of chemical X are added to 80 liters of a mixture that is 20% chemical X and 80% chemical Y, then what percentage of the resulting mixture is chemical X? | {
"A": "30 %",
"B": "33 %",
"C": "36 %",
"D": "39 %",
"E": "42 %"
} | add(20, multiply(divide(20, const_100), 80)) | divide(n2,const_100)|multiply(n1,#0)|add(n0,#1)| | "the amount of chemical x in the solution is 20 + 0.2 ( 80 ) = 36 liters . 36 liters / 100 liters = 36 % the answer is c ." | general |
math_qa__CfT2TQxW3oy282Q9 | Working together, Jose and Jane can complete an assigned task in 20 days. However, if Jose worked alone and completed half the work and then Jane takes over and completes the second half, the task will be completed in 45 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose. Select the correct option.
A) 25 days
B) 30 days
C) 60 days
D) 65 days
E) 36 days | <gadget id="calculator">3 * 20</gadget>
<output>60</output>
<result>C</result> | C | 60 | Working together, Jose and Jane can complete an assigned task in 20 days. However, if Jose worked alone and completed half the work and then Jane takes over and completes the second half, the task will be completed in 45 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose. | {
"A": "25 days",
"B": "30 days",
"C": "60 days",
"D": "65 days",
"E": "36 days"
} | multiply(const_3, 20) | multiply(n0,const_3)| | "explanatory answer step 1 : assign variables and frame equations let jose take ' x ' days to complete the task if he worked alone . let jane take ' y ' days to complete the task if she worked alone . statement 1 of the question : they will complete the task in 20 days , if they worked together . in 1 day , jose will complete 1 / x of the task . in 1 day , jane will complete 1 / yof the task . together , in 1 day they will complete 1 / 20 of the task . therefore , 1 / x + 1 / y = 1 / 20 . . . . ( 1 ) statement 2 of the question : if jose worked alone and completed half the work and then jane takes over and completes the second half , the task will be completed in 45 days . jose will complete half the task in x / 2 days . jane will complete half the task in y / 2 days . ∴ x / 2 + y / 2 = 45 or , x + y = 90 or x = 90 - y . . . . ( 2 ) step 2 : solve the two equations and find x and y substitute the value of x as ( 90 - y ) in the first equation 1 / 90 − y + 1 / y = 1 / 20 or y 2 - 90 + 1800 = 0 . the quadratic equation factorizes as ( y - 60 ) ( y - 30 ) = 0 so , y = 60 or y = 30 . if y = 60 , then x = 90 - y = 90 - 60 = 30 and if y = 30 , then x = 90 - y = 90 - 30 = 60 . the question clearly states that jane is more efficient than jose . therefore , jane will take lesser time than jose . hence , jose will take 60 days to complete the task if he worked alone and jane will take 30 days to complete the same task . choice c" | physics |
math_qa__hWrhRyqHiHd1TYpm | The volume of a cube is 343 cc. Find its surface. Choose the most appropriate option: A) 864 B) 556 C) 294 D) 287 E) 267 | <gadget id="calculator">343 ** (1/3)</gadget>
<output>7</output>
<gadget id="calculator">6 * (7 ** 2)</gadget>
<output>294</output>
<result>C</result> | C | 294 | The volume of a cube is 343 cc. Find its surface. | {
"A": "864",
"B": "556",
"C": "294",
"D": "287",
"E": "267"
} | surface_cube(cube_edge_by_volume(343)) | cube_edge_by_volume(n0)|surface_cube(#0)| | "a 3 = 343 = > a = 7 6 a 2 = 6 * 7 * 7 = 294 answer : c" | geometry |
math_qa__UeR6cnvlBmhMGh0s | A Boeing 757 flies a direct route from Dallas, TX, to Phoenix, AZ and then returns to Dallas, TX. The flight is 900 miles one way. It took 2 hrs and 15 minutes for the flight to Phoenix and 2 hrs for the flight back to Dallas. What was the speed of the wind in mph? Choose the correct choice from the following answers:
A) 20 mph B) 25 mph C) 30 mph D) 35 mph E) 40 mph | <gadget id="calculator">900 / 2</gadget>
<output>450</output>
<gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">2 + (1/4)</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">900 / (9/4)</gadget>
<output>400</output>
<gadget id="calculator">450 - 400</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>B</result> | B | 25 | A Boeing 757 flies a direct route from Dallas, TX, to Phoenix, AZ and then returns to Dallas, TX. The flight is 900 miles one way. It took 2 hrs and 15 minutes for the flight to Phoenix and 2 hrs for the flight back to Dallas. What was the speed of the wind in mph? | {
"A": "20 mph",
"B": "25 mph",
"C": "30 mph",
"D": "35 mph",
"E": "40 mph"
} | divide(subtract(divide(900, 2), divide(900, add(2, divide(15, const_60)))), const_2) | divide(n1,n2)|divide(n3,const_60)|add(n2,#1)|divide(n1,#2)|subtract(#0,#3)|divide(#4,const_2) | explanation : change the times in the problem to minutes first . speed of airplane from dallas to phoenix : ( 900 / 135 ) x 60 = 400 mph speed of airplane from phoenix to dallas : ( 900 / 120 ) x 60 = 450 mph wind speed : 1 / 2 ( 450 - 400 ) = 50 / 2 = 25 mph answer : option b | physics |
math_qa__HqvKFjw8U6eOc2UV | Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 5 meters and a circumference of 4 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B? Select the correct option.
A) 10 %
B) 80 %
C) 100 %
D) 120 %
E) 125 % | <gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) ** 2</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">(4/25) * (5/8)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>
<result>A</result> | A | 10 | Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 5 meters and a circumference of 4 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B? | {
"A": "10 %",
"B": "80 %",
"C": "100 %",
"D": "120 %",
"E": "125 %"
} | multiply(multiply(power(divide(4, 10), const_2), divide(5, 8)), const_100) | divide(n0,n2)|divide(n1,n3)|power(#1,const_2)|multiply(#0,#2)|multiply(#3,const_100) | for a , r = 4 / 2 pi . its capacity = ( 2 pi ) ^ 2 * 5 = 20 pi for b , r = 10 / pi . its capacity = ( 5 pi ) ^ 2 * 8 = 200 pi a / b = 20 pi / 200 pi = 0.1 a | physics |
math_qa__2awuQdCA4aARKSs6 | he total marks obtained by a student in Physics, Chemistry and Mathematics is 180 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?
Pick: A) 55 B) 65 C) 75 D) 85 E) 90 | <gadget id="calculator">180 / 2</gadget>
<output>90</output>
<result>E</result> | E | 90 | he total marks obtained by a student in Physics, Chemistry and Mathematics is 180 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics? | {
"A": "55",
"B": "65",
"C": "75",
"D": "85",
"E": "90"
} | divide(180, const_2) | divide(n0,const_2) | let the marks obtained by the student in physics , chemistry and mathematics be p , c and m respectively . p + c + m = 180 + p c + m = 180 average mark obtained by the student in chemistry and mathematics = ( c + m ) / 2 = 180 / 2 = 90 . answer : e | general |
math_qa__5eD7i9OvBtPdZxX9 | Rahim bought 27 books for Rs.581 from one shop and 20 books for Rs.594 from another. What is the average price he paid per book ?
Select the correct option
A) 28 B) 18 C) 27 D) 25 E) 21 | <gadget id="calculator">581 + 594</gadget>
<output>1_175</output>
<gadget id="calculator">27 + 20</gadget>
<output>47</output>
<gadget id="calculator">1_175 / 47</gadget>
<output>25</output>
<result>D</result> | D | 25 | Rahim bought 27 books for Rs.581 from one shop and 20 books for Rs.594 from another. What is the average price he paid per book ? | {
"A": "28",
"B": "18",
"C": "27",
"D": "25",
"E": "21"
} | divide(add(581, 594), add(27, 20)) | add(n1,n3)|add(n0,n2)|divide(#0,#1)| | "average price per book = ( 581 + 594 ) / ( 27 + 20 ) = 1175 / 47 = rs . 25 answer : d" | general |
math_qa__WyeJ9iCKMrogOi4d | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.24000. A's share is? Options.
A) 2999
B) 8000
C) 6000
D) 2889
E) 6612 | <gadget id="calculator">1 * 12</gadget>
<output>12</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">24_000 / 36</gadget>
<output>2_000/3 = around 666.666667</output>
<gadget id="calculator">12 * (2_000/3)</gadget>
<output>8_000</output>
<result>B</result> | B | 8,000 | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.24000. A's share is? | {
"A": "2999",
"B": "8000",
"C": "6000",
"D": "2889",
"E": "6612"
} | multiply(multiply(const_1, const_12), divide(24000, add(add(multiply(const_1, const_12), multiply(subtract(const_12, 6), const_2)), multiply(subtract(const_12, 8), const_3)))) | multiply(const_1,const_12)|subtract(const_12,n0)|subtract(const_12,n1)|multiply(#1,const_2)|multiply(#2,const_3)|add(#0,#3)|add(#5,#4)|divide(n2,#6)|multiply(#7,#0)| | "x * 12 : 2 x * 6 : 3 x * 4 1 : 1 : 1 1 / 3 * 24000 = 8000 answer : b" | gain |
math_qa__Akv4pK7U0wXibDi7 | The ratio of flour to water to sugar in a recipe is 10:6:3. The ratio in a new recipe calls for a doubling of the ratio of flour to water from the original recipe and a halving of the ratio of flour to sugar. If the new recipe calls for 2 cups of water, how much sugar is required? Pick one
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">(1/3) * 12</gadget>
<output>4</output>
<result>B</result> | B | 4 | The ratio of flour to water to sugar in a recipe is 10:6:3. The ratio in a new recipe calls for a doubling of the ratio of flour to water from the original recipe and a halving of the ratio of flour to sugar. If the new recipe calls for 2 cups of water, how much sugar is required? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | multiply(divide(2, 6), multiply(const_4, 3)) | divide(n3,n1)|multiply(n2,const_4)|multiply(#0,#1)| | "the ratio of flour to water is 10 : 3 . the ratio of flour to sugar is 5 : 3 = 10 : 6 . the new ratio of flour to water to sugar is 10 : 3 : 6 if we need 2 cups of water , then we need 4 cups of sugar . the answer is b ." | other |
math_qa__9HNgwVWJ6aUuWvRD | The smallest number which when diminished by 4, is divisible by 12, 16, 18, 21 and 28 is Choose the correct answer:
A) 1008
B) 1012
C) 1022
D) 1032
E) 1043 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">9 * 16</gadget>
<output>144</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">144 * 7</gadget>
<output>1_008</output>
<gadget id="calculator">1_008 + 4</gadget>
<output>1_012</output>
<result>B</result> | B | 1,012 | The smallest number which when diminished by 4, is divisible by 12, 16, 18, 21 and 28 is | {
"A": "1008",
"B": "1012",
"C": "1022",
"D": "1032",
"E": "1043"
} | add(multiply(multiply(power(const_3, const_2.0), power(const_2.0, const_4)), add(const_3, const_4)), 4) | add(const_3,const_4)|power(const_3,const_2.0)|power(const_2.0,const_4)|multiply(#1,#2)|multiply(#0,#3)|add(#4,n0)| | "required number = ( l . c . m of 12 , 16 , 18 , 21,28 ) + 4 = 1008 + 4 = 1012 answer : b" | general |
math_qa__XIV0k700IZLOdaX0 | Two cars, Car1 and Car2 move towards each other from Q and Y respectively with respective speeds of 20 m/s and 15 m/s. After meeting each other Car1 reaches Y in 10 seconds. In how many seconds does Car 2 reach Q starting from Y? Choose the most appropriate option:
A) 15.5 sec
B) 8.4 sec
C) 33.6 sec
D) 31.11 sec
E) 16.8 sec | <gadget id="calculator">15 / 20</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">10 / (3/4)</gadget>
<output>40/3 = around 13.333333</output>
<gadget id="calculator">20 + 15</gadget>
<output>35</output>
<gadget id="calculator">(40/3) * 35</gadget>
<output>1_400/3 = around 466.666667</output>
<gadget id="calculator">(1_400/3) / 15</gadget>
<output>280/9 = around 31.111111</output>
<result>D</result> | D | 31.11 | Two cars, Car1 and Car2 move towards each other from Q and Y respectively with respective speeds of 20 m/s and 15 m/s. After meeting each other Car1 reaches Y in 10 seconds. In how many seconds does Car 2 reach Q starting from Y? | {
"A": "15.5 sec",
"B": "8.4 sec",
"C": "33.6 sec",
"D": "31.11 sec",
"E": "16.8 sec"
} | divide(multiply(divide(10, divide(15, 20)), add(20, 15)), 15) | add(n2,n3)|divide(n3,n2)|divide(n5,#1)|multiply(#0,#2)|divide(#3,n3) | q - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - | - - - - - - - - - - - - - - - - - - - - - - - - - - - - y car a ( 20 mps ) - - - - - - - - - - - - - - - - - - - - - - - - - > p < - - - - - - - - - - - - - - - car b ( 15 mps ) let 2 cars meet each other at point p in t seconds . car 1 covers distance = 20 t . car 2 covers distance = 15 t . so , total distance qy = 35 t . from p , car 1 reaches onto y in 10 secs . so it covers 15 t further . so , 15 t / 20 = 10 so t = 40 / 3 sec and total distance = ( 35 * 40 ) / 3 hence car 2 will cover total distance in ( 35 * 40 ) / ( 3 * 15 ) = 31.11 sec approx . answer d | physics |
math_qa__eHMxKBqMhutLZPWc | In a division sum, the remainder is 8 and the divisor is 3 times the quotient and is obtained by adding 3 to the thrice of the remainder. The dividend is: Options
A) 200 B) 251 C) 250 D) 262 E) 254 | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 + 3</gadget>
<output>27</output>
<gadget id="calculator">27 / 3</gadget>
<output>9</output>
<gadget id="calculator">27 * 9</gadget>
<output>243</output>
<gadget id="calculator">243 + 8</gadget>
<output>251</output>
<result>B</result> | B | 251 | In a division sum, the remainder is 8 and the divisor is 3 times the quotient and is obtained by adding 3 to the thrice of the remainder. The dividend is: | {
"A": "200",
"B": "251",
"C": "250",
"D": "262",
"E": "254"
} | add(multiply(add(multiply(8, const_3), 3), divide(add(multiply(8, const_3), 3), 3)), 8) | multiply(n0,const_3)|add(n2,#0)|divide(#1,n1)|multiply(#1,#2)|add(n0,#3)| | "diver = ( 8 * 3 ) + 3 = 27 3 * quotient = 27 quotient = 9 dividend = ( divisor * quotient ) + remainder dividend = ( 27 * 9 ) + 8 = 251 b" | general |
math_qa__Bxxy8922BnPSHSxH | The area of a sector of a circle of radius 5 cm formed by an arc of length 4.5 cm is? Choose the correct choice from the following.
A) 8.78 B) 11.25 C) 8.75 D) 8.98 E) 8.28 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">5 * 4.5</gadget>
<output>22.5</output>
<gadget id="calculator">(1/2) * 22.5</gadget>
<output>11.25</output>
<result>B</result> | B | 11.25 | The area of a sector of a circle of radius 5 cm formed by an arc of length 4.5 cm is? | {
"A": "8.78",
"B": "11.25",
"C": "8.75",
"D": "8.98",
"E": "8.28"
} | multiply(divide(const_1, const_2), multiply(5, 4.5)) | divide(const_1,const_2)|multiply(n0,n1)|multiply(#0,#1)| | "( 5 * 4.5 ) / 2 = 11.25 answer : b" | physics |
math_qa__DkTLUEcP0gISVdfU | If x = -5 and y = 8, what is the value of 2(x-y)^2 - xy ?
Choose the correct choice from the following choices
A) 358 B) 348 C) 368 D) 388 E) 378 | <gadget id="calculator">-5</gadget>
<output>-5</output>
<gadget id="calculator">(-5) - 8</gadget>
<output>-13</output>
<gadget id="calculator">(-13) ** 2</gadget>
<output>169</output>
<gadget id="calculator">169 * 2</gadget>
<output>338</output>
<gadget id="calculator">(-5) * 8</gadget>
<output>-40</output>
<gadget id="calculator">338 - (-40)</gadget>
<output>378</output>
<result>E</result> | E | 378 | If x = -5 and y = 8, what is the value of 2(x-y)^2 - xy ? | {
"A": "358",
"B": "348",
"C": "368",
"D": "388",
"E": "378"
} | subtract(multiply(power(subtract(negate(5), 8), const_2), 2), multiply(negate(5), 8)) | negate(n0)|multiply(n1,#0)|subtract(#0,n1)|power(#2,const_2)|multiply(n2,#3)|subtract(#4,#1) | x = - 5 and y = 8 x - y = - 5 - 8 = - 13 x * y = - 5 * 8 = - 40 now we apply it in the equation 2 ( x - y ) ^ 2 - xy = 2 ( - 13 ) ^ 2 - ( - 40 ) = = > 2 * 169 + 40 = 338 + 40 = 378 answer : e | general |
math_qa__t0m8oPZ0zGl2iPaN | Kim has 7 pairs of shoes; each pair is a different color. If Kim randomly selects 2 shoes without replacement from the 14 shoes, what is the probability that she will select 2 shoes of the same color?
Choose the correct choice from the following choices:
A) 1 / 13
B) 1 / 15
C) 11 / 9
D) 1 / 10
E) 1 / 25 | <gadget id="calculator">binomial(14, 2)</gadget>
<output>91</output>
<gadget id="calculator">7 / 91</gadget>
<output>1/13 = around 0.076923</output>
<result>A</result> | A | 0.076923 | Kim has 7 pairs of shoes; each pair is a different color. If Kim randomly selects 2 shoes without replacement from the 14 shoes, what is the probability that she will select 2 shoes of the same color? | {
"A": "1 / 13",
"B": "1 / 15",
"C": "11 / 9",
"D": "1 / 10",
"E": "1 / 25"
} | divide(7, choose(14, 2)) | choose(n2,n1)|divide(n0,#0)| | "can be tackled in this way as well : probability of selecting any 1 out of 14 shoes = 14 / 14 = 1 probability of selecting the next shoe ( out of 14 available ) having the same color = 1 / 14 ( as after selecting the 1 st one , there is only 1 another shoe left with the same color ) . thus the total probability = 1 * 1 / 13 = 1 / 13 . a is the correct answer ." | probability |
math_qa__C5p2edZeyEI7o8hN | Find the distance covered by a man walking for 36min at a speed of 10km/hr? Pick one:
A) 1 km
B) 3 km
C) 6 km
D) 5 km
E) 6 km | <gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 60</gadget>
<output>500/3 = around 166.666667</output>
<gadget id="calculator">36 * (500/3)</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 1_000</gadget>
<output>6</output>
<result>C</result> | C | 6 | Find the distance covered by a man walking for 36min at a speed of 10km/hr? | {
"A": "1 km",
"B": "3 km",
"C": "6 km",
"D": "5 km",
"E": "6 km"
} | divide(multiply(36, divide(multiply(10, const_1000), const_60)), const_1000) | multiply(n1,const_1000)|divide(#0,const_60)|multiply(n0,#1)|divide(#2,const_1000) | distance = 10 * 36 / 60 = 6 km answer is c | physics |
math_qa__4aJL4C8gl0XCxshU | in an xy - coordinate plane , a line is defined by y = kx + 1 . if ( 4 , b ) , ( a , 5 ) , and ( a , b + 1 ) are 3 points on the line , where a and b are unknown , then k = ? Choose the correct choice from the following:
A) 1 / 2 B) 1 C) 3 / 4 D) 2 E) 5 / 2 | <gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">1 * 3</gadget>
<output>3</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<result>C</result> | C | 0.75 | in an xy - coordinate plane , a line is defined by y = kx + 1 . if ( 4 , b ) , ( a , 5 ) , and ( a , b + 1 ) are 3 points on the line , where a and b are unknown , then k = ? | {
"A": "1 / 2",
"B": "1",
"C": "3 / 4",
"D": "2",
"E": "5 / 2"
} | divide(multiply(subtract(5, 4), const_3), 4) | subtract(n2,n1)|multiply(#0,const_3)|divide(#1,n1) | b = 4 k + 1 . . . ( 1 ) b + 1 = ak + 1 . . . ( 2 ) 5 = ak + 1 . . . ( 3 ) taking ( 2 ) and ( 3 ) 5 = b + 1 b = 4 taking ( 1 ) 4 = 4 k + 1 k = 3 / 4 answer : c | general |
math_qa__oqXtpnx4QSzzmnCT | David has $1,500 at the beginning of his trip, after spending money, he still has exactly $500 less than he spent on the trip. How much money does John still have? Choose the correct choice from the following answers:
A) $ 200 B) $ 400 C) $ 500 D) $ 800 E) $ 1,200 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 + 500</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 + 500</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 2</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 500</gadget>
<output>500</output>
<result>C</result> | C | 500 | David has $1,500 at the beginning of his trip, after spending money, he still has exactly $500 less than he spent on the trip. How much money does John still have? | {
"A": "$ 200",
"B": "$ 400",
"C": "$ 500",
"D": "$ 800",
"E": "$ 1,200"
} | subtract(divide(add(add(multiply(const_100, const_10), 500), 500), const_2), 500) | multiply(const_10,const_100)|add(n1,#0)|add(n1,#1)|divide(#2,const_2)|subtract(#3,n1)| | "suppose total money spent = x not spend ( money he still has ) = x - 500 x + x - 500 = 1500 x = 1000 money not spend = 1000 - 500 = 500 answer : c" | general |
math_qa__cKj5xDlketW1sBLK | A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 18 more than the correct answer. Find the number. Choose the correct choice from the following choices: A) 30 B) 35 C) 40 D) 45 E) 50 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">18 * (4/5)</gadget>
<output>72/5 = around 14.4</output>
<gadget id="calculator">(72/5) * (4/5)</gadget>
<output>288/25 = around 11.52</output>
<gadget id="calculator">(4/5) * (4/5)</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">1 - (16/25)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(288/25) / (9/25)</gadget>
<output>32</output>
<gadget id="calculator">32 / (4/5)</gadget>
<output>40</output>
<result>C</result> | C | 40 | A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 18 more than the correct answer. Find the number. | {
"A": "30",
"B": "35",
"C": "40",
"D": "45",
"E": "50"
} | divide(divide(multiply(multiply(18, divide(4, 5)), divide(4, 5)), subtract(const_1, multiply(divide(4, 5), divide(4, 5)))), divide(4, 5)) | divide(n0,n1)|multiply(n4,#0)|multiply(#0,#0)|multiply(#0,#1)|subtract(const_1,#2)|divide(#3,#4)|divide(#5,#0)| | "let the number be x . ( 5 / 4 ) * x = ( 4 / 5 ) * x + 18 25 x = 16 x + 360 9 x = 360 x = 40 the answer is c ." | general |
math_qa__OzqaCavVbBK4TU0T | In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 5 percent, but profits were 10 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
Choose the correct choice from the following.
A) 80 %
B) 105 %
C) 120 %
D) 124.2 %
E) 95 % | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 - (1/20)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">10 * (19/20)</gadget>
<output>19/2 = around 9.5</output>
<gadget id="calculator">(19/2) / 10</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) * 100</gadget>
<output>95</output>
<result>E</result> | E | 95 | In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 5 percent, but profits were 10 percent of revenues. The profits in 2009 were what percent of the profits in 2008? | {
"A": "80 %",
"B": "105 %",
"C": "120 %",
"D": "124.2 %",
"E": "95 %"
} | multiply(divide(multiply(10, subtract(const_1, divide(5, const_100))), 10), const_100) | divide(n3,const_100)|subtract(const_1,#0)|multiply(n4,#1)|divide(#2,n1)|multiply(#3,const_100)| | "the profit 0 f 2009 interms of 2008 = 0.95 * 10 / 10 * 100 = 95 % e" | gain |
math_qa__UAWvYTSIHa3TP9zm | A house wife saved $3.50 in buying an item on sale. If she spent $32.50 for the item, approximately how much percent she saved in the transaction? Answers
A) 8 % B) 9 % C) 10 % D) 11 % E) 12 % | <gadget id="calculator">32.5 + 3.5</gadget>
<output>36</output>
<gadget id="calculator">3.5 / 36</gadget>
<output>0.097222</output>
<gadget id="calculator">0.097222 * 100</gadget>
<output>9.7222</output>
<result>C</result> | C | 10 | A house wife saved $3.50 in buying an item on sale. If she spent $32.50 for the item, approximately how much percent she saved in the transaction? | {
"A": "8 %",
"B": "9 %",
"C": "10 %",
"D": "11 %",
"E": "12 %"
} | multiply(divide(3.50, add(32.50, 3.50)), const_100) | add(n0,n1)|divide(n0,#0)|multiply(#1,const_100)| | "actual price = 32.50 + 3.50 = $ 36 saving = 3.50 / 36 * 100 = 10 % approximately answer is c" | general |
math_qa__gZ6NHpty1xEE1Wh7 | A garrison of 1000 men has provisions for 60 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement?
Choose the correct choice from the following answers
A) 1000
B) 2250
C) 60
D) 45
E) 1250 | <gadget id="calculator">1_000 * 60</gadget>
<output>60_000</output>
<gadget id="calculator">1_000 * 15</gadget>
<output>15_000</output>
<gadget id="calculator">60_000 - 15_000</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 20</gadget>
<output>2_250</output>
<gadget id="calculator">2_250 - 1_000</gadget>
<output>1_250</output>
<result>E</result> | E | 1,250 | A garrison of 1000 men has provisions for 60 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement? | {
"A": "1000",
"B": "2250",
"C": "60",
"D": "45",
"E": "1250"
} | subtract(divide(subtract(multiply(1000, 60), multiply(1000, 15)), 20), 1000) | multiply(n0,n1)|multiply(n0,n2)|subtract(#0,#1)|divide(#2,n3)|subtract(#3,n0)| | "1000 - - - - 60 1000 - - - - 45 x - - - - - 20 x * 20 = 1000 * 45 x = 2250 1000 - - - - - - - 1250 answer : e" | physics |
math_qa__WYDfAAEK03QtkvZY | If a - b = 3 and a^2 + b^2 = 35, find the value of ab. Choose the most appropriate option:
A) 12
B) 13
C) 10
D) 18
E) 13 | <gadget id="calculator">35 ** (1/2)</gadget>
<output>sqrt(35) = around 5.91608</output>
<gadget id="calculator">(sqrt(35)) - 3</gadget>
<output>-3 + sqrt(35) = around 2.91608</output>
<gadget id="calculator">(-3 + sqrt(35)) / 2</gadget>
<output>-3/2 + sqrt(35)/2 = around 1.45804</output>
<gadget id="calculator">3 + (-3/2 + sqrt(35)/2)</gadget>
<output>3/2 + sqrt(35)/2 = around 4.45804</output>
<gadget id="calculator">(3/2 + sqrt(35)/2) * (-3/2 + sqrt(35)/2)</gadget>
<output>(-3/2 + sqrt(35)/2)*(3/2 + sqrt(35)/2) = around 6.5</output>
<gadget id="calculator">((-3/2 + sqrt(35)/2)*(3/2 + sqrt(35)/2)) * 2</gadget>
<output>2*(-3/2 + sqrt(35)/2)*(3/2 + sqrt(35)/2) = around 13</output>
<result>B</result> | B | 13 | If a - b = 3 and a^2 + b^2 = 35, find the value of ab. | {
"A": "12",
"B": "13",
"C": "10",
"D": "18",
"E": "13"
} | multiply(multiply(add(3, divide(subtract(sqrt(35), 3), 2)), divide(subtract(sqrt(35), 3), 2)), 2) | sqrt(n3)|subtract(#0,n0)|divide(#1,n1)|add(n0,#2)|multiply(#3,#2)|multiply(n1,#4)| | "2 ab = ( a ^ 2 + b ^ 2 ) - ( a - b ) ^ 2 = 35 - 9 = 26 ab = 13 . answer is b ." | general |
math_qa__WFqIUGT9HiW2V4gv | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 320 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?
Choose one
A) 600
B) 640
C) 500
D) 520
E) 720 | <gadget id="calculator">320 * 2</gadget>
<output>640</output>
<result>B</result> | B | 640 | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 320 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school? | {
"A": "600",
"B": "640",
"C": "500",
"D": "520",
"E": "720"
} | multiply(320, const_2) | multiply(n0,const_2)| | "let the number of children in the school be x . since each child gets 2 bananas , total number of bananas = 2 x . 2 x / ( x - 320 ) = 2 + 2 ( extra ) = > 2 x - 640 = x = > x = 640 . answer : b" | general |
math_qa__qowpSYhijhwQBwkw | 45 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day? Choose one.
A) 17 B) 97 C) 18 D) 55 E) 72 | <gadget id="calculator">45 * 8</gadget>
<output>360</output>
<gadget id="calculator">360 / 30</gadget>
<output>12</output>
<gadget id="calculator">12 * 50</gadget>
<output>600</output>
<gadget id="calculator">600 / 6</gadget>
<output>100</output>
<gadget id="calculator">100 - 45</gadget>
<output>55</output>
<result>D</result> | D | 55 | 45 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day? | {
"A": "17",
"B": "97",
"C": "18",
"D": "55",
"E": "72"
} | subtract(divide(multiply(divide(multiply(45, 8), 30), 50), 6), 45) | multiply(n0,n1)|divide(#0,n2)|multiply(n3,#1)|divide(#2,n4)|subtract(#3,n0)| | "( 45 * 8 ) / 30 = ( x * 6 ) / 50 = > x = 100 100 – 45 = 55 answer : d" | physics |
math_qa__zOAVTfR2lm4qk4qc | Simplify 586645 * 9999 Choose one.
A) 5865863355 B) 5665863355 C) 4865863355 D) 4665863355 E) none of these | <gadget id="calculator">586_645 * 9_999</gadget>
<output>5_865_863_355</output>
<result>A</result> | A | 5,865,863,355 | Simplify 586645 * 9999 | {
"A": "5865863355",
"B": "5665863355",
"C": "4865863355",
"D": "4665863355",
"E": "none of these"
} | multiply(586645, 9999) | multiply(n0,n1) | explanation : although it is a simple question , but the trick is to save time in solving this . rather than multiplying it we can do as follows : 586645 * ( 10000 - 1 ) = 5866450000 - 586645 = 5865863355 option a | general |
math_qa__2PKiucAMDwQoIi1X | The true discount on a bill due 9 months hence at 16% per annum is Rs. 189. The amount of the bill is : Choose the correct option.
A) rs . 1386 B) rs . 1764 C) rs . 1575 D) rs . 2268 E) none of these | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 16</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">189 / (3/25)</gadget>
<output>1_575</output>
<gadget id="calculator">1_575 + 189</gadget>
<output>1_764</output>
<result>B</result> | B | 1,764 | The true discount on a bill due 9 months hence at 16% per annum is Rs. 189. The amount of the bill is : | {
"A": "rs . 1386",
"B": "rs . 1764",
"C": "rs . 1575",
"D": "rs . 2268",
"E": "none of these"
} | add(divide(189, divide(multiply(divide(9, multiply(const_4, const_3)), 16), const_100)), 189) | multiply(const_3,const_4)|divide(n0,#0)|multiply(n1,#1)|divide(#2,const_100)|divide(n2,#3)|add(n2,#4)| | "solution 32.5 let p . w . be rs . x . then , s . i . on rs . x at 16 % for 9 months = rs . 189 . ∴ x 16 x 9 / 12 x 1 / 100 = 189 or x = 1575 . ∴ p . w . = rs . 1575 . ∴ sum due = p . w . + t . d . = rs . ( 1575 + 189 ) = rs . 1764 . answer b" | gain |
math_qa__bfJHEZGJ37EsnYku | If the price of petrol increases by 30, by how much must a user cut down his consumption so that his expenditure on petrol remains constant? Choose the correct choice from the following choices
A) 25 % B) 23 % C) 16.67 % D) 33.33 % E) none of these | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">100 / 130</gadget>
<output>10/13 = around 0.769231</output>
<gadget id="calculator">1 - (10/13)</gadget>
<output>3/13 = around 0.230769</output>
<gadget id="calculator">(3/13) * 100</gadget>
<output>300/13 = around 23.076923</output>
<result>B</result> | B | 23 | If the price of petrol increases by 30, by how much must a user cut down his consumption so that his expenditure on petrol remains constant? | {
"A": "25 %",
"B": "23 %",
"C": "16.67 %",
"D": "33.33 %",
"E": "none of these"
} | multiply(subtract(const_1, divide(const_100, add(const_100, 30))), const_100) | add(n0,const_100)|divide(const_100,#0)|subtract(const_1,#1)|multiply(#2,const_100)| | "explanation : let us assume before increase the petrol will be rs . 100 . after increase it will be rs ( 100 + 30 ) i . e 130 . now , his consumption should be reduced to : - = ( 130 − 100 ) / 130 ∗ 100 . hence , the consumption should be reduced to 23 % . answer : b" | general |
math_qa__v3FYT2Jn9YcWwAHK | Pipe A that can fill a tank in two hour and pipe B that can fill the tank in an hour are opened simultaneously when the tank is empty. Pipe B is shut 30 minutes before the tank overflows. When will the tank overflow? Choose the correct choice from the following choices
A) 36 mins B) 35 mins C) 40 mins D) 32 mins E) 30 mins | <gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/60) / 2</gadget>
<output>1/120 = around 0.008333</output>
<gadget id="calculator">30 * (1/120)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/60) + (1/120)</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(3/4) / (1/40)</gadget>
<output>30</output>
<result>E</result> | E | 30 | Pipe A that can fill a tank in two hour and pipe B that can fill the tank in an hour are opened simultaneously when the tank is empty. Pipe B is shut 30 minutes before the tank overflows. When will the tank overflow? | {
"A": "36 mins",
"B": "35 mins",
"C": "40 mins",
"D": "32 mins",
"E": "30 mins"
} | divide(subtract(const_1, multiply(30, divide(divide(const_1, const_60), const_2))), add(divide(const_1, const_60), divide(divide(const_1, const_60), const_2))) | divide(const_1,const_60)|divide(#0,const_2)|add(#0,#1)|multiply(n0,#1)|subtract(const_1,#3)|divide(#4,#2) | the last 30 minutes only pipe a was open . since it needs 2 hour to fill the tank , then in 30 minutes it fills 1 / 4 th of the tank , thus 3 / 4 of the tank is filled with both pipes open . the combined rate of two pipes is 1 + 2 = 3 tanks / hour , therefore to fill 3 / 4 th of the tank they need ( time ) = ( work ) / ( rate ) = ( 3 / 4 ) / 3 = 1 / 4 hours = 15 minutes . total time = 15 + 15 = 30 minutes . answer : e | physics |
math_qa__gNeQLEEiLxOacdV1 | Two family reunions are happening at the Taj hotel, the Oates reunion and the Hall reunion. All 150 guests at the hotel attend at least one of the reunions. If 70 people attend the Oates reunion and 52 people attend the Hall reunion, how many people attend both reunions? Pick
A) 2
B) 5
C) 10
D) 16
E) 28 | <gadget id="calculator">52 + 70</gadget>
<output>122</output>
<gadget id="calculator">150 - 122</gadget>
<output>28</output>
<result>E</result> | E | 28 | Two family reunions are happening at the Taj hotel, the Oates reunion and the Hall reunion. All 150 guests at the hotel attend at least one of the reunions. If 70 people attend the Oates reunion and 52 people attend the Hall reunion, how many people attend both reunions? | {
"A": "2",
"B": "5",
"C": "10",
"D": "16",
"E": "28"
} | subtract(150, add(52, 70)) | add(n1,n2)|subtract(n0,#0) | no of people in oates reunion = 70 no of people in hall reunion = 52 attending both = x all guests attend at least one . therefore , 150 = 70 + 52 - ( both ) both = 28 answer e | other |
math_qa__xzRD5O3m7r2wyoxu | You buy a piece of land with an area of √1024, how long is one side of the land plot? Answers
A) 28 B) 29 C) 30 D) 31 E) 32 | <gadget id="calculator">1_024 ** (1/2)</gadget>
<output>32</output>
<result>E</result> | E | 32 | You buy a piece of land with an area of √1024, how long is one side of the land plot? | {
"A": "28",
"B": "29",
"C": "30",
"D": "31",
"E": "32"
} | sqrt(1024) | sqrt(n0)| | "try filling the numbers into the answer y x y = find the closest to 1024 . answer e" | geometry |
math_qa__wzUtSptLIXJ6xUlL | The least common multiple of positive integer e and 3-digit integer n is 690. If n is not divisible by 3 and e is not divisible by 2, what is the value of n? Choose the correct choice from the following choices: A) 115 B) 230 C) 460 D) 575 E) 690 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">690 / 30</gadget>
<output>23</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">23 * 10</gadget>
<output>230</output>
<result>B</result> | B | 230 | The least common multiple of positive integer e and 3-digit integer n is 690. If n is not divisible by 3 and e is not divisible by 2, what is the value of n? | {
"A": "115",
"B": "230",
"C": "460",
"D": "575",
"E": "690"
} | multiply(divide(690, multiply(3, const_10)), multiply(2, add(const_2, const_3))) | add(const_2,const_3)|multiply(n0,const_10)|divide(n1,#1)|multiply(n3,#0)|multiply(#2,#3) | the lcm of n and e is 690 = 2 * 3 * 5 * 23 . e is not divisible by 2 , thus 2 goes to n n is not divisible by 3 , thus 3 goes to e . from above : n must be divisible by 2 and not divisible by 3 : n = 2 * . . . in order n to be a 3 - digit number it must take all other primes too : n = 2 * 5 * 23 = 230 . answer : b . | general |
math_qa__bB8nF1rlpQGVP7tS | Half a number plus 5 is 15.What is the number? Choose the correct choice:
A) 8 B) 20 C) 10 D) 11 E) 12 | <gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<result>B</result> | B | 20 | Half a number plus 5 is 15.What is the number? | {
"A": "8",
"B": "20",
"C": "10",
"D": "11",
"E": "12"
} | multiply(subtract(15, 5), const_2) | subtract(n1,n0)|multiply(#0,const_2)| | "let x be the number . always replace ` ` is ' ' with an equal sign ( 1 / 2 ) x + 5 = 15 ( 1 / 2 ) x = 15 - 5 ( 1 / 2 ) x = 10 x = 20 correct answer is b" | general |
math_qa__XAFieYSaXTCfiuRE | A car takes 6 hours to cover a distance of 630 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Choose the correct choice from the following options
A) 48 kmph B) 50 kmph C) 52 kmph D) 56 kmph E) 70 kmph | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">630 / 9</gadget>
<output>70</output>
<result>E</result> | E | 70 | A car takes 6 hours to cover a distance of 630 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "48 kmph",
"B": "50 kmph",
"C": "52 kmph",
"D": "56 kmph",
"E": "70 kmph"
} | divide(630, divide(multiply(6, 3), 2)) | multiply(n0,n2)|divide(#0,n3)|divide(n1,#1)| | "time = 6 distence = 630 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 630 / 9 = 70 kmph e" | physics |
math_qa__xltXBOnAK9e9zoQ4 | The cost price of an book is 64% of the marked price. Calculate the gain percent after allowing a discount of 13%? Choose the correct choice:
A) 31.5 % B) 35.9 % C) 37.5 % D) 39.5 % E) 30.5 % | <gadget id="calculator">100 / 64</gadget>
<output>25/16 = around 1.5625</output>
<gadget id="calculator">100 - 13</gadget>
<output>87</output>
<gadget id="calculator">87 / 100</gadget>
<output>87/100 = around 0.87</output>
<gadget id="calculator">(25/16) * (87/100)</gadget>
<output>87/64 = around 1.359375</output>
<gadget id="calculator">(87/64) - 1</gadget>
<output>23/64 = around 0.359375</output>
<gadget id="calculator">(23/64) * 100</gadget>
<output>575/16 = around 35.9375</output>
<result>B</result> | B | 35.9 | The cost price of an book is 64% of the marked price. Calculate the gain percent after allowing a discount of 13%? | {
"A": "31.5 %",
"B": "35.9 %",
"C": "37.5 %",
"D": "39.5 %",
"E": "30.5 %"
} | multiply(subtract(multiply(divide(const_100, 64), divide(subtract(const_100, 13), const_100)), const_1), const_100) | divide(const_100,n0)|subtract(const_100,n1)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,const_1)|multiply(#4,const_100)| | "let marked price = $ 100 . then , c . p . = $ 64 , s . p . = $ 87 gain % = 23 / 64 * 100 = 35.9 % . b" | gain |
math_qa__DCSAQ93Yosb6odaf | A candidate got 25% of the votes polled and he lost to his rival by 4000 votes. How many votes were cast?
Pick one:
A) 7500 B) 2028 C) 2775 D) 5496 E) 8000 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) - (1/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4_000 / (1/2)</gadget>
<output>8_000</output>
<result>E</result> | E | 8,000 | A candidate got 25% of the votes polled and he lost to his rival by 4000 votes. How many votes were cast? | {
"A": "7500",
"B": "2028",
"C": "2775",
"D": "5496",
"E": "8000"
} | divide(4000, subtract(subtract(const_1, divide(25, const_100)), divide(25, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n1,#2)| | "25 % - - - - - - - - - - - l 75 % - - - - - - - - - - - w - - - - - - - - - - - - - - - - - - 50 % - - - - - - - - - - 4000 100 % - - - - - - - - - ? = > 8000 answer : e" | gain |
math_qa__wP9JBsWPnIaBJtgG | 39! is divided by 41. Then what is the remainder for this?
Choose the correct option: A) 1 B) 3 C) 5 D) 6 E) 7 | <gadget id="calculator">factorial(39)</gadget>
<output>20_397_882_081_197_443_358_640_281_739_902_897_356_800_000_000</output>
<gadget id="calculator">20_397_882_081_197_443_358_640_281_739_902_897_356_800_000_000 % 41</gadget>
<output>1</output>
<result>A</result> | A | 1 | 39! is divided by 41. Then what is the remainder for this? | {
"A": "1",
"B": "3",
"C": "5",
"D": "6",
"E": "7"
} | reminder(factorial(39), 41) | factorial(n0)|reminder(#0,n1) | substituting p = 41 in the wilson ' s theorem , we get 40 ! + 141 = 0 40 × 39 ! + 141 = 0 − 1 × 39 ! 41 = − 1 cancelling - 1 on both sides , 39 ! 41 = 1 a | other |
math_qa__UTmfErWvpwmCJoHM | The ratio 5:20 expressed as percent equals to Choose the correct choice from the following:
A) 50 % B) 125 % C) 25 % D) none of above E) 30 % | <gadget id="calculator">5 / 20</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | The ratio 5:20 expressed as percent equals to | {
"A": "50 %",
"B": "125 %",
"C": "25 %",
"D": "none of above",
"E": "30 %"
} | multiply(divide(5, 20), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "explanation : actually it means 5 is what percent of 20 , which can be calculated as , ( 5 / 20 ) * 100 = 5 * 5 = 25 option c" | general |
math_qa__irMISvuXvc87YR7V | A sum of money becomes 7/6 of itself in 2 years at a certain rate of simple interest. The rate per annum is? Choose the correct choice from the following answers.
A) 50 / 9
B) 50 / 7
C) 50 / 6
D) 50 / 8
E) 50 / 3 | <gadget id="calculator">7 / 6</gadget>
<output>7/6 = around 1.166667</output>
<gadget id="calculator">(7/6) - 1</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) / 2</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 100</gadget>
<output>25/3 = around 8.333333</output>
<result>C</result> | C | 8.333333 | A sum of money becomes 7/6 of itself in 2 years at a certain rate of simple interest. The rate per annum is? | {
"A": "50 / 9",
"B": "50 / 7",
"C": "50 / 6",
"D": "50 / 8",
"E": "50 / 3"
} | multiply(divide(subtract(divide(7, 6), const_1), 2), const_100) | divide(n0,n1)|subtract(#0,const_1)|divide(#1,n2)|multiply(#2,const_100)| | "let sum = x . then , amount = 7 x / 6 s . i . = 7 x / 6 - x = x / 6 ; time = 2 years . rate = ( 100 * x ) / ( x * 6 * 2 ) = 50 / 6 % . answer : c" | gain |
math_qa__dAMDiMETwNYZ1XTW | A train travels 325 km in 3.5 hours and 470 km in 4 hours. Find the average speed of train ? Options:
A) 116 kmph
B) 106 kmph
C) 186 kmph
D) 126 kmph
E) 176 kmph | <gadget id="calculator">325 + 470</gadget>
<output>795</output>
<gadget id="calculator">3.5 + 4</gadget>
<output>7.5</output>
<gadget id="calculator">795 / 7.5</gadget>
<output>106</output>
<result>B</result> | B | 106 | A train travels 325 km in 3.5 hours and 470 km in 4 hours. Find the average speed of train ? | {
"A": "116 kmph",
"B": "106 kmph",
"C": "186 kmph",
"D": "126 kmph",
"E": "176 kmph"
} | divide(add(325, 470), add(3.5, 4)) | add(n0,n2)|add(n1,n3)|divide(#0,#1) | explanation : as we know that speed = distance / time for average speed = total distance / total time taken thus , total distance = 325 + 470 = 795 km thus , total speed = 7.5 hrs average speed = 795 / 7.5 = > 106 kmph . answer : b | physics |
math_qa__Wh8mxhIL3eYYsfza | Speed of a boat in standing water is 16 kmph and the speed of the stream is 2 kmph. A man rows to a place at a distance of 7560 km and comes back to the starting point. The total time taken by him is: Choose the correct choice.
A) 914.2 hours
B) 900 hours
C) 915 hours
D) 905 hours
E) 960 hours | <gadget id="calculator">16 + 2</gadget>
<output>18</output>
<gadget id="calculator">7_560 / 18</gadget>
<output>420</output>
<gadget id="calculator">16 - 2</gadget>
<output>14</output>
<gadget id="calculator">7_560 / 14</gadget>
<output>540</output>
<gadget id="calculator">420 + 540</gadget>
<output>960</output>
<result>E</result> | E | 960 | Speed of a boat in standing water is 16 kmph and the speed of the stream is 2 kmph. A man rows to a place at a distance of 7560 km and comes back to the starting point. The total time taken by him is: | {
"A": "914.2 hours",
"B": "900 hours",
"C": "915 hours",
"D": "905 hours",
"E": "960 hours"
} | add(divide(7560, add(16, 2)), divide(7560, subtract(16, 2))) | add(n0,n1)|subtract(n0,n1)|divide(n2,#0)|divide(n2,#1)|add(#2,#3)| | "explanation : speed downstream = ( 16 + 2 ) = 18 kmph speed upstream = ( 16 - 2 ) = 14 kmph total time taken = 7560 / 18 + 7560 / 14 = 420 + 540 = 960 hours answer : option e" | physics |
math_qa__1mhVe81CQ5ihkDUU | Jennifer had $150 to spend on herself. She spent 1/5 of the money on a sandwich, 1/6 for a ticket to a museum, and 1/2 of it on a book. How much money does Jennifer have left over? Select:
A) $ 4 B) $ 14 C) $ 5 D) $ 15 E) $ 20 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">150 * (1/5)</gadget>
<output>30</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">150 * (1/6)</gadget>
<output>25</output>
<gadget id="calculator">30 + 25</gadget>
<output>55</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">150 * (1/2)</gadget>
<output>75</output>
<gadget id="calculator">55 + 75</gadget>
<output>130</output>
<gadget id="calculator">150 - 130</gadget>
<output>20</output>
<result>E</result> | E | 20 | Jennifer had $150 to spend on herself. She spent 1/5 of the money on a sandwich, 1/6 for a ticket to a museum, and 1/2 of it on a book. How much money does Jennifer have left over? | {
"A": "$ 4",
"B": "$ 14",
"C": "$ 5",
"D": "$ 15",
"E": "$ 20"
} | subtract(150, add(add(multiply(150, divide(1, 5)), multiply(150, divide(1, 6))), multiply(150, divide(1, 2)))) | divide(n1,n2)|divide(n1,n4)|divide(n1,n6)|multiply(n0,#0)|multiply(n0,#1)|multiply(n0,#2)|add(#3,#4)|add(#6,#5)|subtract(n0,#7)| | "1 / 5 x $ 150 = $ 30 for sandwich 1 / 6 x $ 150 = $ 25 for museum 1 / 2 x $ 150 = $ 75 for book $ 30 + $ 25 + $ 75 = $ 130 spent $ 150 - $ 130 = $ 20 left over correct answer e" | general |
math_qa__cTQWh2Q3jVrt4c3J | Excluding the stoppages, the speed of a bus is 32 km/hr and including the stoppages the speed of the bus is 16 km/hr. For how many minutes does the bus stop per hour? Pick one
A) 15 min B) 10 min C) 12 min D) 30 min E) 18 min | <gadget id="calculator">16 / 32</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 60</gadget>
<output>30</output>
<gadget id="calculator">60 - 30</gadget>
<output>30</output>
<result>D</result> | D | 30 | Excluding the stoppages, the speed of a bus is 32 km/hr and including the stoppages the speed of the bus is 16 km/hr. For how many minutes does the bus stop per hour? | {
"A": "15 min",
"B": "10 min",
"C": "12 min",
"D": "30 min",
"E": "18 min"
} | subtract(const_60, multiply(divide(16, 32), const_60)) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "speed of the bus without stoppage = 32 km / hr speed of the bus with stoppage = 16 km / hr difference in speed = 16 km / hr so , the time taken in the stoppages = time taken to cover 16 km = ( 16 / 32 ) hr = 1 / 2 hr = 30 min answer : d" | physics |
math_qa__bwanVzlhkZi2MksP | The length of a rectangular plot is 10mtr more than its width. The cost of fencing the plot along its perimeter at the rate of Rs. 6.5mtr is Rs.2210. The perimeter of the plot is? Choose one
A) 126 B) 156 C) 340 D) 321 E) 260 | <gadget id="calculator">2_210 / 6.5</gadget>
<output>340</output>
<gadget id="calculator">340 / 2</gadget>
<output>170</output>
<gadget id="calculator">170 - 10</gadget>
<output>160</output>
<gadget id="calculator">160 / 2</gadget>
<output>80</output>
<gadget id="calculator">80 + 10</gadget>
<output>90</output>
<gadget id="calculator">80 + 90</gadget>
<output>170</output>
<gadget id="calculator">170 * 2</gadget>
<output>340</output>
<result>C</result> | C | 340 | The length of a rectangular plot is 10mtr more than its width. The cost of fencing the plot along its perimeter at the rate of Rs. 6.5mtr is Rs.2210. The perimeter of the plot is? | {
"A": "126",
"B": "156",
"C": "340",
"D": "321",
"E": "260"
} | multiply(add(divide(subtract(divide(divide(2210, 6.5), const_2), 10), const_2), add(divide(subtract(divide(divide(2210, 6.5), const_2), 10), const_2), 10)), const_2) | divide(n2,n1)|divide(#0,const_2)|subtract(#1,n0)|divide(#2,const_2)|add(#3,n0)|add(#4,#3)|multiply(#5,const_2)| | "sol . let width = x , length = ( 10 + x ) perimeter = 2 ( x + ( 10 + x ) ) = 2 ( 2 x = 10 ) & 2 ( 2 x + 10 ) * 6.5 = 2210 x = 80 required perimeter = 2 ( 80 + 90 ) = 340 c" | geometry |
math_qa__kM06w7tYmWHJwR2v | At what rate percent on simple interest will Rs.1750 amount to Rs.2000 in 4 years? Choose the correct choice from the following answers:
A) 4 %
B) 3.57 %
C) 2 6 / 7 %
D) 5 %
E) 6 % | <gadget id="calculator">2_000 - 1_750</gadget>
<output>250</output>
<gadget id="calculator">250 / 1_750</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/7) / 4</gadget>
<output>1/28 = around 0.035714</output>
<gadget id="calculator">(1/28) * 100</gadget>
<output>25/7 = around 3.571429</output>
<result>B</result> | B | 3.57 | At what rate percent on simple interest will Rs.1750 amount to Rs.2000 in 4 years? | {
"A": "4 %",
"B": "3.57 %",
"C": "2 6 / 7 %",
"D": "5 %",
"E": "6 %"
} | multiply(divide(divide(subtract(2000, 1750), 1750), 4), const_100) | subtract(n1,n0)|divide(#0,n0)|divide(#1,n2)|multiply(#2,const_100)| | "explanation : 250 = ( 1750 x 4 xr ) / 100 r = 3.57 % answer : option b" | gain |
math_qa__dDpLN9uGML3R9kFo | Having scored 95 runs in the 19th inning, a cricketer increases his average score by 4. What will be his average score after 19 innings? Answers
A) 28
B) 27
C) 23
D) 22
E) 24 | <gadget id="calculator">19 * 4</gadget>
<output>76</output>
<gadget id="calculator">95 - 76</gadget>
<output>19</output>
<gadget id="calculator">19 + 4</gadget>
<output>23</output>
<result>C</result> | C | 23 | Having scored 95 runs in the 19th inning, a cricketer increases his average score by 4. What will be his average score after 19 innings? | {
"A": "28",
"B": "27",
"C": "23",
"D": "22",
"E": "24"
} | add(subtract(95, multiply(19, 4)), 4) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "explanation : let the average score of the first 18 innings be n 18 n + 95 = 19 ( n + 4 ) = > n = 19 so , average score after 19 th innings = x + 4 = 23 . answer : c" | general |
math_qa__i3BcXfI0u6ITZmD5 | If a rectangular billboard has an area of 104 square feet and a perimeter of 42 feet, what is the length of each of the shorter sides?
Choose the correct option
A) 4 B) 7 C) 8 D) 13 E) 26 | <gadget id="calculator">42 / 2</gadget>
<output>21</output>
<gadget id="calculator">21 ** 2</gadget>
<output>441</output>
<gadget id="calculator">4 * 104</gadget>
<output>416</output>
<gadget id="calculator">441 - 416</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">21 - 5</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>C</result> | C | 8 | If a rectangular billboard has an area of 104 square feet and a perimeter of 42 feet, what is the length of each of the shorter sides? | {
"A": "4",
"B": "7",
"C": "8",
"D": "13",
"E": "26"
} | divide(subtract(divide(42, const_2), sqrt(subtract(power(divide(42, const_2), const_2), multiply(const_4, 104)))), const_2) | divide(n1,const_2)|multiply(n0,const_4)|power(#0,const_2)|subtract(#2,#1)|sqrt(#3)|subtract(#0,#4)|divide(#5,const_2) | assume the sides to be x and y . perimeter = 2 x + 2 y = 42 hence x + y = 21 - ( i ) area = xy = 104 - ( ii ) since these are the sides of a billboard , we are dealing with positive numbers only and the options tell us that they are integers . 104 can be written as a product of two numbers as 104 * 1 or 52 * 2 or 26 * 4 or 13 * 8 of these , only 13 * 8 satisfies the equation ( i ) hence the lengths are 13 and 8 length of shorter side = 8 answer : c | geometry |
math_qa__MAfuKi5kAs13fTZK | In a village of 2,700 people, 900 people are over 70 years old and 1200 people are female. It is known that 40 percent of the females are younger than 70 years old. If no one in the village is 70 years old, what is the probability that a person chosen at random is either a male or younger than 70 years old? Choose the most appropriate option
A) 3 / 5 B) 7 / 10 C) 11 / 15 D) 23 / 30 E) 31 / 45 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">25 / (1/4)</gadget>
<output>100</output>
<gadget id="calculator">26 * 100</gadget>
<output>2_600</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1_200 * (3/5)</gadget>
<output>720</output>
<gadget id="calculator">2_600 - 720</gadget>
<output>1_880</output>
<gadget id="calculator">1_880 / 2_600</gadget>
<output>47/65 = around 0.723077</output>
<result>C</result> | C | 0.733333 | In a village of 2,700 people, 900 people are over 70 years old and 1200 people are female. It is known that 40 percent of the females are younger than 70 years old. If no one in the village is 70 years old, what is the probability that a person chosen at random is either a male or younger than 70 years old? | {
"A": "3 / 5",
"B": "7 / 10",
"C": "11 / 15",
"D": "23 / 30",
"E": "31 / 45"
} | divide(subtract(multiply(const_26, divide(multiply(const_5, const_5), const_0_25)), multiply(1200, subtract(const_1, divide(40, divide(multiply(const_5, const_5), const_0_25))))), multiply(const_26, divide(multiply(const_5, const_5), const_0_25))) | multiply(const_5,const_5)|divide(#0,const_0_25)|divide(n4,#1)|multiply(#1,const_26)|subtract(const_1,#2)|multiply(n3,#4)|subtract(#3,#5)|divide(#6,#3)| | "the number of people younger than 70 years old is 2700 - 900 = 1800 the number of females older than 70 years old is 0.6 * 1200 = 720 the number of males older than 70 years old is 900 - 720 = 180 the number of people who are either male or younger than 70 is 1800 + 180 = 1980 . p ( a person is younger than 70 or male ) = 1980 / 2700 = 11 / 15 the answer is c ." | gain |
math_qa__PYxvVIpjcFn35FyU | The marks obtained by Vijay and Amith are in the ratio 4:4 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of? Select:
A) 3 : 2 B) 6 : 1 C) 6 : 5 D) 6 : 2 E) 6 : 3 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">12 / 8</gadget>
<output>3/2 = around 1.5</output>
<result>A</result> | A | 1.5 | The marks obtained by Vijay and Amith are in the ratio 4:4 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of? | {
"A": "3 : 2",
"B": "6 : 1",
"C": "6 : 5",
"D": "6 : 2",
"E": "6 : 3"
} | divide(multiply(4, 3), multiply(4, 2)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "4 : 4 3 : 2 - - - - - - - 12 : 12 : 8 12 : 8 3 : 2 answer : a" | other |
math_qa__rJ8kjHpOsjG7t9gN | 5x + y = 19 , and x + 3y = 1. Find the value of 3x + 2y
Options: A) 20 B) 18 C) 11 D) 10 E) 5 | <gadget id="calculator">19 + 1</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>D</result> | D | 10 | 5x + y = 19 , and x + 3y = 1. Find the value of 3x + 2y | {
"A": "20",
"B": "18",
"C": "11",
"D": "10",
"E": "5"
} | divide(add(19, 1), const_2) | add(n1,n3)|divide(#0,const_2) | add these two equations 6 x + 4 y = 20 divide by 2 ( to get 3 x + 2 y ) answer will be d . 10 | general |
math_qa__iBTq6PzutPXQezrX | If 0.75 : x :: 5 : 8, then x is equal to:
Pick.
A) 1.12 B) 1.2 C) 1.25 D) 1.3 E) none | <gadget id="calculator">0.75 * 8</gadget>
<output>6</output>
<gadget id="calculator">6 / 5</gadget>
<output>6/5 = around 1.2</output>
<result>B</result> | B | 1.2 | If 0.75 : x :: 5 : 8, then x is equal to: | {
"A": "1.12",
"B": "1.2",
"C": "1.25",
"D": "1.3",
"E": "none"
} | divide(multiply(0.75, 8), 5) | multiply(n0,n2)|divide(#0,n1)| | "( x * 5 ) = ( 0.75 * 8 ) x = 6 / 5 x = 1.20 answer = b" | general |
math_qa__I7vr9yszKYCU5gV3 | The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is: Choose the correct choice from the following:
A) 6.09 % B) 6.08 % C) 6.1 % D) 6.07 % E) 6.05 % | <gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">6 + (9/100)</gadget>
<output>609/100 = around 6.09</output>
<result>A</result> | A | 6.09 | The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is: | {
"A": "6.09 %",
"B": "6.08 %",
"C": "6.1 %",
"D": "6.07 %",
"E": "6.05 %"
} | add(add(divide(6, const_2), divide(6, const_2)), divide(multiply(divide(6, const_2), divide(6, const_2)), const_100)) | divide(n0,const_2)|add(#0,#0)|multiply(#0,#0)|divide(#2,const_100)|add(#1,#3)| | "amount of rs . 100 for 1 year when compounded half - yearly = 100 x ( 1 + 3 / 100 ) ^ 2 = 106.09 therefore effective rate = ( 106.09 - 100 ) % = 6.09 % answer a ) 6.09 %" | gain |
math_qa__m34sXF9YgZO4A2Fj | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.1200, what is the reduced price for kg? Select
A) s . 40
B) s . 46
C) s . 49
D) s . 41
E) s . 60 | <gadget id="calculator">1_200 * 25</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 / 100</gadget>
<output>300</output>
<gadget id="calculator">300 / 5</gadget>
<output>60</output>
<result>E</result> | E | 60 | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.1200, what is the reduced price for kg? | {
"A": "s . 40",
"B": "s . 46",
"C": "s . 49",
"D": "s . 41",
"E": "s . 60"
} | divide(divide(multiply(1200, 25), const_100), 5) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "1200 * ( 25 / 100 ) = 300 - - - - 5 ? - - - - 1 = > rs . 60 answer : e" | gain |
math_qa__uuNfhlms8vL3faDg | if 50% of (x-y) = 20% of (x+y) then what percent of x is y? Pick one
A) 2.5 % B) 10 % C) 5 % D) 15 % E) 43 % | <gadget id="calculator">50 - 20</gadget>
<output>30</output>
<gadget id="calculator">50 + 20</gadget>
<output>70</output>
<gadget id="calculator">30 / 70</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 100</gadget>
<output>300/7 = around 42.857143</output>
<result>E</result> | E | 43 | if 50% of (x-y) = 20% of (x+y) then what percent of x is y? | {
"A": "2.5 %",
"B": "10 %",
"C": "5 %",
"D": "15 %",
"E": "43 %"
} | multiply(divide(subtract(50, 20), add(50, 20)), const_100) | add(n0,n1)|subtract(n0,n1)|divide(#1,#0)|multiply(#2,const_100)| | "50 % of ( x - y ) = 20 % of ( x + y ) ( 50 / 100 ) ( x - y ) = ( 20 / 100 ) ( x + y ) 5 ( x - y ) = 2 ( x + y ) 3 x = 7 y x = 7 / 3 y therefore required percentage = ( ( y / x ) x 100 ) % = ( ( y / ( 7 / 3 ) y ) x 100 ) = 43 % answer is e ." | general |
math_qa__bluIKmHhwDjWBqw6 | Ashwin rented a power tool from a rental shop. The rent for the tool was $25 for the first hour and $10 for each additional hour. If Ashwin paid a total of $125, excluding sales tax, to rent the tool, for how many hours did she rent it?
Select the correct option
A) 11 B) 12 C) 15 D) 18 E) 16 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<result>A</result> | A | 11 | Ashwin rented a power tool from a rental shop. The rent for the tool was $25 for the first hour and $10 for each additional hour. If Ashwin paid a total of $125, excluding sales tax, to rent the tool, for how many hours did she rent it? | {
"A": "11",
"B": "12",
"C": "15",
"D": "18",
"E": "16"
} | add(10, const_1) | add(n1,const_1) | 25 + 10 n = 125 n = 10 total time = n + 1 hrs = 10 + 1 hrs = 11 hrs answer : a | general |
math_qa__dYzYLVUOdzWCfqaM | B as a percentage of A is equal to A as a percentage of (A+B). Find B as a percentage of A. Select the correct option.
A) 62 % B) 73 % C) 41 % D) 71 % E) none of these | <gadget id="calculator">-1</gadget>
<output>-1</output>
<gadget id="calculator">-4</gadget>
<output>-4</output>
<gadget id="calculator">(-1) * (-4)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 ** (1/2)</gadget>
<output>sqrt(5) = around 2.236068</output>
<gadget id="calculator">(-1) + (sqrt(5))</gadget>
<output>-1 + sqrt(5) = around 1.236068</output>
<gadget id="calculator">(-1 + sqrt(5)) / 2</gadget>
<output>-1/2 + sqrt(5)/2 = around 0.618034</output>
<gadget id="calculator">(-1/2 + sqrt(5)/2) * 100</gadget>
<output>-50 + 50*sqrt(5) = around 61.803399</output>
<result>A</result> | A | 62 | B as a percentage of A is equal to A as a percentage of (A+B). Find B as a percentage of A. | {
"A": "62 %",
"B": "73 %",
"C": "41 %",
"D": "71 %",
"E": "none of these"
} | multiply(divide(add(negate(const_1), sqrt(add(multiply(negate(const_1), negate(const_4)), const_1))), const_2), const_100) | negate(const_1)|negate(const_4)|multiply(#0,#1)|add(#2,const_1)|sqrt(#3)|add(#0,#4)|divide(#5,const_2)|multiply(#6,const_100) | explanation : according to the question : - = > b / a = a / ( a + b ) . as b is a percent of a , let us assume b = ax . then , equation ( 1 ) can be re - written as = > x = 11 + x . = > x ( 1 + x ) = 1 . = > x 2 + x + 1 = 0 . = > x = − 1 ± 5 / √ 2 thus , x = − 1 + 5 / √ 2 = > 0.62 . = > 62 % . answer : a | general |
math_qa__YCDYQvfCD3XDd6qw | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 390 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school? Select the correct option:
A) 237 B) 780 C) 197 D) 287 E) 720 | <gadget id="calculator">390 * 2</gadget>
<output>780</output>
<result>B</result> | B | 780 | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 390 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school? | {
"A": "237",
"B": "780",
"C": "197",
"D": "287",
"E": "720"
} | multiply(390, const_2) | multiply(n0,const_2)| | "explanation : let the number of children in the school be x . since each child gets 2 bananas , total number of bananas = 2 x . 2 x / ( x - 390 ) = 2 + 2 ( extra ) = > 2 x - 780 = x = > x = 780 . answer : b" | general |
math_qa__j85AXBf4fFC5XEBo | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 40 men in 3 days? Answers:
A) 65 mtr . B) 52 mtr C) 70 mtr . D) 112 mtr . E) 17 mtr . | <gadget id="calculator">40 * 3</gadget>
<output>120</output>
<gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">120 / 120</gadget>
<output>1</output>
<gadget id="calculator">112 * 1</gadget>
<output>112</output>
<result>D</result> | D | 112 | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 40 men in 3 days? | {
"A": "65 mtr .",
"B": "52 mtr",
"C": "70 mtr .",
"D": "112 mtr .",
"E": "17 mtr ."
} | multiply(112, divide(multiply(40, 3), multiply(20, 6))) | multiply(n3,n4)|multiply(n0,n2)|divide(#0,#1)|multiply(n1,#2)| | "20 men is 6 days can build 112 metres 25 men in 3 days can build = 112 * ( 40 / 20 ) x ( 3 / 6 ) = 112 meters answer : d ." | physics |
math_qa__43keicDYrsRT3g50 | A train running at the speed of 180 km/hr crosses a pole in 8 seconds. Find the length of the train. Options
A) 150
B) 88
C) 480
D) 288
E) 400 | <gadget id="calculator">180 * 1_000</gadget>
<output>180_000</output>
<gadget id="calculator">180_000 / 3_600</gadget>
<output>50</output>
<gadget id="calculator">50 * 8</gadget>
<output>400</output>
<result>E</result> | E | 400 | A train running at the speed of 180 km/hr crosses a pole in 8 seconds. Find the length of the train. | {
"A": "150",
"B": "88",
"C": "480",
"D": "288",
"E": "400"
} | multiply(divide(multiply(180, const_1000), const_3600), 8) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 180 * ( 5 / 18 ) m / sec = 50 m / sec length of train ( distance ) = speed * time 50 * 8 = 400 meter answer : e" | physics |
math_qa__Ol3fDSNIvgbxQ8yJ | In Goshawk-Eurasian nature reserve 30 percent of the birds are Hawks, and 40 percent of the non-Hawks are Paddyfield-Warblers. If there are 25 percent as many Kingfishers as Paddyfield-Warblers in the reserve, then what percent of the birds b in the nature reserve are not Hawks, Paddyfield-Warblers, or Kingfishers? Choose the correct option.
A) 25 % B) 35 % C) 45 % D) 70 % E) 80 % | <gadget id="calculator">25 + 25</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">10 + 25</gadget>
<output>35</output>
<result>B</result> | B | 35 | In Goshawk-Eurasian nature reserve 30 percent of the birds are Hawks, and 40 percent of the non-Hawks are Paddyfield-Warblers. If there are 25 percent as many Kingfishers as Paddyfield-Warblers in the reserve, then what percent of the birds b in the nature reserve are not Hawks, Paddyfield-Warblers, or Kingfishers? | {
"A": "25 %",
"B": "35 %",
"C": "45 %",
"D": "70 %",
"E": "80 %"
} | add(const_10, divide(add(25, 25), const_2)) | add(n2,n2)|divide(#0,const_2)|add(#1,const_10)| | "1 . we are given the following percentages : 30 ( 70 ) , 40 ( 60 ) , 25 ( 75 ) . there are two threads from here . first starts at 30 % and finishes there . second one starts at 70 , then 40 , and then 25 . we need a value that is divisible by 7 , 2 , and 5 at least once . lets pick a number now , say 700 . so say if non hawks are 700 ( this is 70 % of the total , so total = 1000 ) , then paddy warbs are 2 / 5 x 700 = 1400 / 5 = 280 . kingfishers , therefore , are 280 / 4 = 70 . lets add them up . 300 hawks + 280 peddy warbs + 70 kingsifhers = 650 . so all others are 1000 - 650 = 350 or 35 % of total birds . the main job here to to identify the smart number to start the question with . this can be time consuming , but once identified , this question can be solved fairly quickly . 2 . another method : if x is total - - > non hawks = 0.7 x - - > warbs = 0.4 ( 0.7 x ) - - > kfs = 0.25 ( 0.4 ( 0.7 x ) ) . our job is to find out b : ( 0.3 x + 0.28 x + 0.07 x ) / x . or 0.65 x / x = 0.65 . we need to find 1 - 0.65 = 0.35 or 35 % . b" | general |
math_qa__BMscodcswK6bQkhc | The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person? Answers: A) 22 B) 18 C) 12 D) 88 E) 66 | <gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">42 - 30</gadget>
<output>12</output>
<result>C</result> | C | 12 | The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person? | {
"A": "22",
"B": "18",
"C": "12",
"D": "88",
"E": "66"
} | subtract(42, multiply(10, 3)) | multiply(n0,n1)|subtract(n2,#0)| | "initial average age of the 10 persons be p . age of the new person q . sum of the ages of the initial 10 persons = 10 p new average = ( p - 3 ) 10 ( p - 3 ) = 10 p - 42 + q = > q = 12 answer : c" | general |
math_qa__sgdec5ahKc2BC6kk | What is the sum of the squares of the first 20 natural numbers (1 to 20)? Choose the most appropriate option:
A) 2870 B) 2000 C) 5650 D) 6650 E) 7650 | <gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">20 * 21</gadget>
<output>420</output>
<gadget id="calculator">2 * 20</gadget>
<output>40</output>
<gadget id="calculator">40 + 1</gadget>
<output>41</output>
<gadget id="calculator">420 * 41</gadget>
<output>17_220</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">17_220 / 6</gadget>
<output>2_870</output>
<result>A</result> | A | 2,870 | What is the sum of the squares of the first 20 natural numbers (1 to 20)? | {
"A": "2870",
"B": "2000",
"C": "5650",
"D": "6650",
"E": "7650"
} | divide(multiply(multiply(20, add(20, 1)), add(multiply(const_2, 20), 1)), multiply(const_2, const_3)) | add(n0,n1)|multiply(n0,const_2)|multiply(const_2,const_3)|add(n1,#1)|multiply(n0,#0)|multiply(#3,#4)|divide(#5,#2) | n ( n + 1 ) ( 2 n + 1 ) / 6 20 ( 21 ) ( 21 ) / 6 = 2870 answer : a | geometry |
math_qa__7h93uLxGWAz9YJ9p | The Guests at a football banquet consumed a total of 319 pounds of food. if no individual guest consumed more than 2 pounds of food, What is the minimum number of guests that could have attended the banquet? Choose the correct choice from the following options
A) 160 B) 161 C) 162 D) 163 E) 164 | <gadget id="calculator">319 / 2</gadget>
<output>319/2 = around 159.5</output>
<gadget id="calculator">floor(319/2)</gadget>
<output>159</output>
<gadget id="calculator">159 + 1</gadget>
<output>160</output>
<result>A</result> | A | 160 | The Guests at a football banquet consumed a total of 319 pounds of food. if no individual guest consumed more than 2 pounds of food, What is the minimum number of guests that could have attended the banquet? | {
"A": "160",
"B": "161",
"C": "162",
"D": "163",
"E": "164"
} | add(floor(divide(319, 2)), const_1) | divide(n0,n1)|floor(#0)|add(#1,const_1)| | "to minimize one quantity maximize other . 159 * 2 ( max possible amount of food a guest could consume ) = 318 pounds , so there must be more than 159 guests , next integer is 160 . answer : a ." | general |
math_qa__RoZ2C5vrWZw2eHPh | 8 persons can build a wall 140m long in 42 days. In how many days can 30 persons complete a similar wall 100 m long? Choose the correct choice from the following choices: A) 12 B) 10 C) 8 D) 6 E) 5 | <gadget id="calculator">8 * 42</gadget>
<output>336</output>
<gadget id="calculator">140 / 336</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">30 * (5/12)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">100 / (25/2)</gadget>
<output>8</output>
<result>C</result> | C | 8 | 8 persons can build a wall 140m long in 42 days. In how many days can 30 persons complete a similar wall 100 m long? | {
"A": "12",
"B": "10",
"C": "8",
"D": "6",
"E": "5"
} | divide(100, multiply(30, divide(140, multiply(8, 42)))) | multiply(n0,n2)|divide(n1,#0)|multiply(n3,#1)|divide(n4,#2) | explanation : more persons , less days ( indirect proportion ) more length of the wall , more days ( direct proportion ) ⇒ 8 × 100 × 42 = 30 × 140 × x ⇒ x = ( 8 × 100 × 42 ) / ( 30 × 140 ) = ( 8 × 100 × 14 ) / ( 10 × 140 ) = ( 8 × 100 ) / ( 10 × 10 ) = 8 . answer : option c | physics |
math_qa__5IWg1U4JYbn404lE | What is the prime factors’ number of 48? Answers: A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<result>D</result> | D | 5 | What is the prime factors’ number of 48? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | add(add(add(const_1, add(const_1, const_1)), const_1), const_1) | add(const_1,const_1)|add(#0,const_1)|add(#1,const_1)|add(#2,const_1) | prime factors ’ number , as i assume , for a number x = a ^ n * b ^ m * c ^ o * d ^ p . . . is = n + m + o + p . . . so , 24 = 2 ^ 4 * 3 ^ 1 prime factors ’ number will be 4 + 1 = 5 . hence , answer is d . | other |
math_qa__jvm1fD4CrmqzPWuA | The compound interest on a sum of money for 2 years is rs.832 and the simple interest on the same sum for the same period is rs.800 .the difference between the compound interest and simple interest for 3 years
Choices: A) 98.5 B) 08.56 C) 98.56 D) 98.86 E) 98.46 | <gadget id="calculator">800 / 2</gadget>
<output>400</output>
<gadget id="calculator">832 - 400</gadget>
<output>432</output>
<gadget id="calculator">432 - 400</gadget>
<output>32</output>
<gadget id="calculator">32 * 100</gadget>
<output>3_200</output>
<gadget id="calculator">3_200 / 400</gadget>
<output>8</output>
<gadget id="calculator">832 * 8</gadget>
<output>6_656</output>
<gadget id="calculator">6_656 / 100</gadget>
<output>1_664/25 = around 66.56</output>
<gadget id="calculator">(1_664/25) + 32</gadget>
<output>2_464/25 = around 98.56</output>
<result>C</result> | C | 98.56 | The compound interest on a sum of money for 2 years is rs.832 and the simple interest on the same sum for the same period is rs.800 .the difference between the compound interest and simple interest for 3 years | {
"A": "98.5",
"B": "08.56",
"C": "98.56",
"D": "98.86",
"E": "98.46"
} | add(divide(multiply(832, divide(multiply(subtract(subtract(832, divide(800, 2)), divide(800, 2)), const_100), divide(800, 2))), const_100), subtract(subtract(832, divide(800, 2)), divide(800, 2))) | divide(n2,n0)|subtract(n1,#0)|subtract(#1,#0)|multiply(#2,const_100)|divide(#3,#0)|multiply(n1,#4)|divide(#5,const_100)|add(#6,#2) | explanation : difference in c . i and s . i in 2 years = rs . 32 s . i for 1 year = rs . 400 s . i for rs . 400 for one year = rs . 32 rate = [ 100 * 32 ) / ( 400 * 1 ) % = 8 % difference between in c . i and s . i for 3 rd year = s . i on rs . 832 = rs . ( 832 * 8 * 1 ) / 100 = rs . 66.56 answer : c ) rs . 98.56 | general |
math_qa__ruPdEUuAAxJbhinN | Each child has 2 pencils and 13 Skittles. If there are 11 children, how many pencils are there in total? Choose the correct choice from the following options: A) 16 B) 12 C) 18 D) 22 E) 08 | <gadget id="calculator">2 * 11</gadget>
<output>22</output>
<result>D</result> | D | 22 | Each child has 2 pencils and 13 Skittles. If there are 11 children, how many pencils are there in total? | {
"A": "16",
"B": "12",
"C": "18",
"D": "22",
"E": "08"
} | multiply(2, 11) | multiply(n0,n2)| | 2 * 11 = 22 . answer is d . | general |
math_qa__omzJRD3kXccUSEYI | . A car covers a distance of 390 km in 4 hours. Find its speed? Choices
A) 104
B) 55
C) 66
D) 98
E) 100 | <gadget id="calculator">390 / 4</gadget>
<output>195/2 = around 97.5</output>
<result>D</result> | D | 98 | . A car covers a distance of 390 km in 4 hours. Find its speed? | {
"A": "104",
"B": "55",
"C": "66",
"D": "98",
"E": "100"
} | divide(390, 4) | divide(n0,n1) | 390 / 4 = 98 kmph answer : d | physics |
math_qa__iQXuKmMnDxoiCV2J | Find the sum of all 3 digit natural numbers, which are divisible by 8 Answers:
A) 61376 B) 54411 C) 612314 D) 64170 E) 64171 | <gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 8</gadget>
<output>992</output>
<gadget id="calculator">104 + 992</gadget>
<output>1_096</output>
<gadget id="calculator">992 - 104</gadget>
<output>888</output>
<gadget id="calculator">888 / 8</gadget>
<output>111</output>
<gadget id="calculator">111 + 1</gadget>
<output>112</output>
<gadget id="calculator">112 / 2</gadget>
<output>56</output>
<gadget id="calculator">1_096 * 56</gadget>
<output>61_376</output>
<result>A</result> | A | 61,376 | Find the sum of all 3 digit natural numbers, which are divisible by 8 | {
"A": "61376",
"B": "54411",
"C": "612314",
"D": "64170",
"E": "64171"
} | multiply(add(add(const_100, const_4), subtract(multiply(const_100, const_10), 8)), divide(add(divide(subtract(subtract(multiply(const_100, const_10), 8), add(const_100, const_4)), 8), const_1), const_2)) | add(const_100,const_4)|multiply(const_10,const_100)|subtract(#1,n1)|add(#0,#2)|subtract(#2,#0)|divide(#4,n1)|add(#5,const_1)|divide(#6,const_2)|multiply(#3,#7)| | "the three digit natural numbers divisible by 8 are 104 , 112 , 120 , … . 992 . let sndenote their sum . that is , sn = 104 112 120 128 , 992 g + + + + + . now , the sequence 104 , 112 , 120 , g , 992 forms an a . p . a = 104 , d = 8 , l = 992 n = l - a / d n = 112 s 112 = n / 2 ( a + l ) = 61376 answer a 61376" | general |
math_qa__UUP20F15dUHTXVVo | John left home and drove at the rate of 45 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 55 mph to reach his destination. How many miles did John drive? Choose the correct choice from the following answers
A) 235 miles . B) 245 miles . C) 255 miles . D) 265 miles . E) 275 miles . | <gadget id="calculator">45 * 2</gadget>
<output>90</output>
<gadget id="calculator">3 * 55</gadget>
<output>165</output>
<gadget id="calculator">90 + 165</gadget>
<output>255</output>
<result>C</result> | C | 255 | John left home and drove at the rate of 45 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 55 mph to reach his destination. How many miles did John drive? | {
"A": "235 miles .",
"B": "245 miles .",
"C": "255 miles .",
"D": "265 miles .",
"E": "275 miles ."
} | add(multiply(45, 2), multiply(3, 55)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "the total distance d traveled by john is given by d = 45 * 2 + 3 * 55 = 255 miles . answer c" | physics |
math_qa__rHxg0p7fwKJ09oj2 | A contractor is engaged for 30days on the condition thathe receives Rs.25 for each day he works &is fined Rs.7.50 for each day is absent. He gets Rs.555 in all. For how many days was he absent? Choose the correct option:
A) 8
B) 10
C) 15
D) 6
E) 19 | <gadget id="calculator">7.5 * 30</gadget>
<output>225</output>
<gadget id="calculator">225 + 555</gadget>
<output>780</output>
<gadget id="calculator">7.5 + 25</gadget>
<output>32.5</output>
<gadget id="calculator">780 / 32.5</gadget>
<output>24</output>
<gadget id="calculator">30 - 24</gadget>
<output>6</output>
<result>D</result> | D | 6 | A contractor is engaged for 30days on the condition thathe receives Rs.25 for each day he works &is fined Rs.7.50 for each day is absent. He gets Rs.555 in all. For how many days was he absent? | {
"A": "8",
"B": "10",
"C": "15",
"D": "6",
"E": "19"
} | subtract(30, divide(add(multiply(7.50, 30), 555), add(7.50, 25))) | add(n1,n2)|multiply(n0,n2)|add(n3,#1)|divide(#2,#0)|subtract(n0,#3)| | "30 * 25 = 750 455 - - - - - - - - - - - 195 25 + 7.50 = 32.5 195 / 32.5 = 6 d" | physics |
math_qa__97Z1f8lJYoDY5HFA | A does 4/5th of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
Choose the most appropriate option
A) 23 days B) 37 days C) 37 ½ days D) 40 days E) 41 days | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 20</gadget>
<output>25</output>
<gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/15) - (1/25)</gadget>
<output>2/75 = around 0.026667</output>
<gadget id="calculator">1 / (2/75)</gadget>
<output>75/2 = around 37.5</output>
<result>C</result> | C | 37 | A does 4/5th of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work? | {
"A": "23 days",
"B": "37 days",
"C": "37 ½ days",
"D": "40 days",
"E": "41 days"
} | inverse(subtract(inverse(multiply(3, 5)), inverse(multiply(divide(5, 4), 20)))) | divide(n1,n0)|multiply(n1,n3)|inverse(#1)|multiply(n2,#0)|inverse(#3)|subtract(#2,#4)|inverse(#5) | explanation : a can finish the whole work in 20 × 5 / 4 days = 25 days a and b together finish the whole work in 5 × 3 days = 15 days therefore , b can finish the whole work in 25 b / 25 + b = 15 25 b = 15 ( 25 + b ) = 375 + 15 b 10 b = 375 and b = 375 / 10 = 37 ½ days . answer : option c | physics |
math_qa__NwDIt7iEHtY3Y1go | A and B can do a work in 12 days and 36 days respectively. If they work on alternate days beginning with B, in how many days will the work be completed? Choose the correct answer: A) 11 B) 17 C) 10 D) 17 E) 18 | <gadget id="calculator">1 / 36</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/36) + (1/12)</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">1 / (1/9)</gadget>
<output>9</output>
<gadget id="calculator">9 + 12</gadget>
<output>21</output>
<gadget id="calculator">21 - 3</gadget>
<output>18</output>
<result>E</result> | E | 18 | A and B can do a work in 12 days and 36 days respectively. If they work on alternate days beginning with B, in how many days will the work be completed? | {
"A": "11",
"B": "17",
"C": "10",
"D": "17",
"E": "18"
} | subtract(add(inverse(add(inverse(36), inverse(12))), 12), const_3) | inverse(n1)|inverse(n0)|add(#0,#1)|inverse(#2)|add(n0,#3)|subtract(#4,const_3) | the work done in the first two days = 1 / 12 + 1 / 36 = 1 / 9 so , 9 such two days are required to finish the work . i . e . , 18 days are required to finish the work . answer : e | physics |
math_qa__mrgExhTtwqTyZDtg | A train ,140 meters long travels at a speed of 45 km/hr crosses a bridge in 30 seconds. The length of the bridge is Options:
A) 270 m B) 245 m C) 235 m D) 220 m E) 240 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">45 * (5/18)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 140</gadget>
<output>235</output>
<result>C</result> | C | 235 | A train ,140 meters long travels at a speed of 45 km/hr crosses a bridge in 30 seconds. The length of the bridge is | {
"A": "270 m",
"B": "245 m",
"C": "235 m",
"D": "220 m",
"E": "240 m"
} | subtract(multiply(multiply(45, const_0_2778), 30), 140) | multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0)| | "explanation : assume the length of the bridge = x meter total distance covered = 140 + x meter total time taken = 30 s speed = total distance covered / total time taken = ( 140 + x ) / 30 m / s = > 45 ã — ( 10 / 36 ) = ( 140 + x ) / 30 = > 45 ã — 10 ã — 30 / 36 = 140 + x = > 45 ã — 10 ã — 10 / 12 = 140 + x = > 15 ã — 10 ã — 10 / 4 = 140 + x = > 15 ã — 25 = 140 + x = 375 = > x = 375 - 140 = 235 answer : option c" | physics |
math_qa__ObZLBQPGXw98Y7T2 | An error 2% in excess is made while measuring the sideofa square. The % of error in the calculated area of the square is? Choose the correct option:
A) 4.00 % B) 4.04 % C) 4.26 % D) 4.56 % E) 4.67 % | <gadget id="calculator">100 + 2</gadget>
<output>102</output>
<gadget id="calculator">102 ** 2</gadget>
<output>10_404</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">10_404 - 10_000</gadget>
<output>404</output>
<gadget id="calculator">404 * 100</gadget>
<output>40_400</output>
<gadget id="calculator">40_400 / 10_000</gadget>
<output>101/25 = around 4.04</output>
<result>B</result> | B | 4.04 | An error 2% in excess is made while measuring the sideofa square. The % of error in the calculated area of the square is? | {
"A": "4.00 %",
"B": "4.04 %",
"C": "4.26 %",
"D": "4.56 %",
"E": "4.67 %"
} | divide(multiply(subtract(square_area(add(const_100, 2)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)| | "100 cm is read as 102 cm . a 1 = ( 100 x 100 ) cm 2 and a 2 ( 102 x 102 ) cm 2 . ( a 2 - a 1 ) = [ ( 102 ) 2 - ( 100 ) 2 ] = ( 102 + 100 ) x ( 102 - 100 ) = 404 cm 2 . percentage error = 404 x 100 % = 4.04 % 100 x 100 b" | geometry |
math_qa__25WYCZGfFhGsiI1Z | A can do a piece of work in 30 days; B can do the same in 30 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in? Choose the correct choice from the following options:
A) 30 days B) 65 days C) 86 days D) 45 days E) 17 days | <gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">20 / 30</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">10 / (1/3)</gadget>
<output>30</output>
<result>A</result> | A | 30 | A can do a piece of work in 30 days; B can do the same in 30 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in? | {
"A": "30 days",
"B": "65 days",
"C": "86 days",
"D": "45 days",
"E": "17 days"
} | divide(10, subtract(const_1, divide(add(10, 10), 30))) | add(n2,n2)|divide(#0,n0)|subtract(const_1,#1)|divide(n2,#2) | 10 / 30 + 10 / 30 + 10 / x = 1 x = 30 days answer : a | physics |
math_qa__JcBQ1sw0J7fvvDAr | The distance between towns A and B is 300 km. One train departs from town A and another train departs from town B, both leaving at the same moment of time and heading towards each other. We know that one of them is 10 km/hr faster than the other. Find the speeds of both trains if 2 hours after their departure the distance between them is 40 km.
Choose the correct choice:
A) 22 B) 27 C) 236 D) 90 E) 81 | <gadget id="calculator">300 - 40</gadget>
<output>260</output>
<gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">260 / 4</gadget>
<output>65</output>
<gadget id="calculator">65 - 10</gadget>
<output>55</output>
<gadget id="calculator">55 - 10</gadget>
<output>45</output>
<gadget id="calculator">45 + 45</gadget>
<output>90</output>
<result>D</result> | D | 90 | The distance between towns A and B is 300 km. One train departs from town A and another train departs from town B, both leaving at the same moment of time and heading towards each other. We know that one of them is 10 km/hr faster than the other. Find the speeds of both trains if 2 hours after their departure the distance between them is 40 km. | {
"A": "22",
"B": "27",
"C": "236",
"D": "90",
"E": "81"
} | add(subtract(subtract(divide(subtract(300, 40), add(2, 2)), 10), 10), subtract(subtract(divide(subtract(300, 40), add(2, 2)), 10), 10)) | add(n2,n2)|subtract(n0,n3)|divide(#1,#0)|subtract(#2,n1)|subtract(#3,n1)|add(#4,#4) | let the speed of the slower train be xx km / hr . then the speed of the faster train is ( x + 10 ) ( x + 10 ) km / hr . in 2 hours they cover 2 x 2 x km and 2 ( x + 10 ) 2 ( x + 10 ) km , respectively . therefore if they did n ' t meet yet , the whole distance from a to b is 2 x + 2 ( x + 10 ) + 40 = 4 x + 602 x + 2 ( x + 10 ) + 40 = 4 x + 60 km . however , if they already met and continued to move , the distance would be 2 x + 2 ( x + 10 ) − 40 = 4 x − 202 x + 2 ( x + 10 ) − 40 = 4 x − 20 km . so we get the following equations : 4 x + 60 = 3004 x + 60 = 300 4 x = 2404 x = 240 x = 60 x = 60 or 4 x − 20 = 3004 x − 20 = 300 4 x = 3204 x = 320 x = 80 x = 80 hence the speed of the slower train is 60 km / hr or 80 km / hr and the speed of the faster train is 70 km / hr or 90 km / hr . answer : d | physics |
math_qa__tVsEDkU4s8KOdGGX | a textile manufacturing firm employees 70 looms . it makes fabrics for a branded company . the aggregate sales value of the output of the 70 looms is rs 00000 and the monthly manufacturing expenses is rs 1 , 50000 . assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms . monthly establishment charges are rs 75000 . if one loom breaks down and remains idle for one month , the decrease in profit is : Pick one:
A) 13000
B) 7000
C) 10000
D) 5000
E) none of these | <gadget id="calculator">75_000 - 50_000</gadget>
<output>25_000</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">25_000 / 5</gadget>
<output>5_000</output>
<result>D</result> | D | 5,000 | a textile manufacturing firm employees 70 looms . it makes fabrics for a branded company . the aggregate sales value of the output of the 70 looms is rs 00000 and the monthly manufacturing expenses is rs 1 , 50000 . assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms . monthly establishment charges are rs 75000 . if one loom breaks down and remains idle for one month , the decrease in profit is : | {
"A": "13000",
"B": "7000",
"C": "10000",
"D": "5000",
"E": "none of these"
} | divide(subtract(75000, 50000), add(const_2, const_3)) | add(const_2,const_3)|subtract(n5,n4)|divide(#1,#0) | explanation : profit = 5 , 00,000 â ˆ ’ ( 1 , 50,000 + 75,000 ) = rs . 2 , 75,000 . since , such loom contributes equally to sales and manufacturing expenses . but the monthly charges are fixed at rs 75,000 . if one loan breaks down sales and expenses will decrease . new profit : - = > 500000 ã — ( 69 / 70 ) â ˆ ’ 150000 ã — ( 69 / 70 ) â ˆ ’ 75000 . = > rs 2 , 70,000 . decrease in profit = > 2 , 75,000 â ˆ ’ 2 , 70,000 = > rs . 5,000 . answer : d | general |
math_qa__nuApy9n9tgl0kql7 | A fruit seller sells mangoes at the rate of Rs.14 per kg and thereby loses 15%. At what price per kg, he should have sold them to make a profit of 15%?
Choose the correct choice:
A) rs . 11.81 B) rs . 12 C) rs . 18.94 D) rs . 12.31 E) none | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">14 * 115</gadget>
<output>1_610</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">1_610 / 85</gadget>
<output>322/17 = around 18.941176</output>
<result>C</result> | C | 18.94 | A fruit seller sells mangoes at the rate of Rs.14 per kg and thereby loses 15%. At what price per kg, he should have sold them to make a profit of 15%? | {
"A": "rs . 11.81",
"B": "rs . 12",
"C": "rs . 18.94",
"D": "rs . 12.31",
"E": "none"
} | divide(multiply(14, add(const_100, 15)), subtract(const_100, 15)) | add(n2,const_100)|subtract(const_100,n1)|multiply(n0,#0)|divide(#2,#1)| | "solution 85 : 14 = 115 : x x = ( 14 ã — 115 / 85 ) = rs . 18.94 hence , s . p per kg = rs . 18.94 answer c" | gain |
math_qa__A2EDyaUhr1MJEYVm | for a 3 - digit number xyz , where x , y , and z are the digits of the number , f ( xyz ) = 5 ^ x 2 ^ y 3 ^ z . if f ( abc ) = 3 * f ( def ) , what is the value of abc - def ? Choose the most appropriate option
A) 1 B) 2 C) 3 D) 9 E) 27 | <gadget id="calculator">3 - 2</gadget>
<output>1</output>
<result>A</result> | A | 1 | for a 3 - digit number xyz , where x , y , and z are the digits of the number , f ( xyz ) = 5 ^ x 2 ^ y 3 ^ z . if f ( abc ) = 3 * f ( def ) , what is the value of abc - def ? | {
"A": "1",
"B": "2",
"C": "3",
"D": "9",
"E": "27"
} | subtract(3, 2) | subtract(n0,n2) | since f ( abc ) = 3 * f ( def ) , i would assume that f = c - 1 from the function above . the answer should be ( a ) | general |
math_qa__2rBes8HHyQ12DrGR | How long does a train 165 meters long running at the rate of 54 kmph take to cross a bridge 660 meters in length Pick one.
A) 33 B) 44 C) 55 D) 77 E) 22 | <gadget id="calculator">165 + 660</gadget>
<output>825</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">825 / 15</gadget>
<output>55</output>
<result>C</result> | C | 55 | How long does a train 165 meters long running at the rate of 54 kmph take to cross a bridge 660 meters in length | {
"A": "33",
"B": "44",
"C": "55",
"D": "77",
"E": "22"
} | divide(add(165, 660), multiply(54, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "t = ( 660 + 165 ) / 54 * 18 / 5 t = 55 answer : c" | physics |
math_qa__0TYZPJGKbGsnEXDS | A truck covers a distance of 392 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 70 km more than that travelled by the truck ? Pick
A) 6 hours B) 5 hours C) 7 hours D) 8 hours E) none | <gadget id="calculator">392 + 70</gadget>
<output>462</output>
<gadget id="calculator">392 / 8</gadget>
<output>49</output>
<gadget id="calculator">49 + 18</gadget>
<output>67</output>
<gadget id="calculator">462 / 67</gadget>
<output>462/67 = around 6.895522</output>
<result>C</result> | C | 7 | A truck covers a distance of 392 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 70 km more than that travelled by the truck ? | {
"A": "6 hours",
"B": "5 hours",
"C": "7 hours",
"D": "8 hours",
"E": "none"
} | divide(add(392, 70), add(divide(392, 8), 18)) | add(n0,n3)|divide(n0,n1)|add(n2,#1)|divide(#0,#2)| | "explanation : speed of the truck = distance / time = 392 / 8 = 49 kmph now , speed of car = ( speed of truck + 18 ) kmph = ( 48 + 18 ) = 66 kmph distance travelled by car = 392 + 70 = 462 km time taken by car = distance / speed = 462 / 66 = 7 hours . answer – c" | physics |
math_qa__xYdRhL5mzin9xnLI | The area of a triangle is with base 4m and height 8m?
Choose one:
A) 11 B) 10 C) 787 D) 16 E) 12 | <gadget id="calculator">(4 * 8) / 2</gadget>
<output>16</output>
<result>D</result> | D | 16 | The area of a triangle is with base 4m and height 8m? | {
"A": "11",
"B": "10",
"C": "787",
"D": "16",
"E": "12"
} | triangle_area(4, 8) | triangle_area(n0,n1)| | "1 / 2 * 4 * 8 = 16 m 2 answer : d" | geometry |
math_qa__7ioYDXlkd1RRcV2N | A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 70 as remainder. Find the no. is? Pick.
A) 145646 B) 236578 C) 645353 D) 456546 E) 220070 | <gadget id="calculator">555 + 445</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 2</gadget>
<output>2_000</output>
<gadget id="calculator">555 - 445</gadget>
<output>110</output>
<gadget id="calculator">2_000 * 110</gadget>
<output>220_000</output>
<gadget id="calculator">220_000 + 70</gadget>
<output>220_070</output>
<result>E</result> | E | 220,070 | A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 70 as remainder. Find the no. is? | {
"A": "145646",
"B": "236578",
"C": "645353",
"D": "456546",
"E": "220070"
} | add(multiply(multiply(add(555, 445), 2), subtract(555, 445)), 70) | add(n0,n1)|subtract(n0,n1)|multiply(n2,#0)|multiply(#2,#1)|add(n3,#3)| | "( 555 + 445 ) * 2 * 110 + 70 = 220000 + 70 = 220070 e" | general |
math_qa__FbxCysSCr7V5mONj | If a 10 percent deposit that has been paid toward the purchase of a certain product is $140, how much more remains to be paid? Pick:
A) $ 880
B) $ 990
C) $ 1,000
D) $ 1,100
E) $ 1,260 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">140 * 10</gadget>
<output>1_400</output>
<gadget id="calculator">1_400 - 140</gadget>
<output>1_260</output>
<result>E</result> | E | 1,260 | If a 10 percent deposit that has been paid toward the purchase of a certain product is $140, how much more remains to be paid? | {
"A": "$ 880",
"B": "$ 990",
"C": "$ 1,000",
"D": "$ 1,100",
"E": "$ 1,260"
} | subtract(multiply(140, divide(const_100, 10)), 140) | divide(const_100,n0)|multiply(n1,#0)|subtract(#1,n1)| | "10 / 100 p = 140 > > p = 140 * 100 / 10 = 1400 1400 - 140 = 1260 answer : e" | general |
math_qa__dqxIyB8fwnLK3ME7 | A professional janitor can clean a certain high school in (4+4) hours, working at a constant rate. A student sentenced to detention can clean that same high school in 20 hours, also working at a constant rate. If the student is paid $7 total per hour and the janitor is paid $21 per hour, how much more would it cost the school to pay the janitor to do the job himself than it would to pay the student and the janitor to do the job together? Choose the correct choice.
A) - $ 56 B) - $ 6 C) $ 0 D) $ 6 E) $ 8 | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 * 21</gadget>
<output>168</output>
<gadget id="calculator">7 + 21</gadget>
<output>28</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/8) + (1/20)</gadget>
<output>7/40 = around 0.175</output>
<gadget id="calculator">1 / (7/40)</gadget>
<output>40/7 = around 5.714286</output>
<gadget id="calculator">28 * (40/7)</gadget>
<output>160</output>
<gadget id="calculator">168 - 160</gadget>
<output>8</output>
<result>E</result> | E | 8 | A professional janitor can clean a certain high school in (4+4) hours, working at a constant rate. A student sentenced to detention can clean that same high school in 20 hours, also working at a constant rate. If the student is paid $7 total per hour and the janitor is paid $21 per hour, how much more would it cost the school to pay the janitor to do the job himself than it would to pay the student and the janitor to do the job together? | {
"A": "- $ 56",
"B": "- $ 6",
"C": "$ 0",
"D": "$ 6",
"E": "$ 8"
} | subtract(multiply(add(4, 4), 21), multiply(add(7, 21), divide(const_1, add(divide(const_1, add(4, 4)), divide(const_1, 20))))) | add(n0,n0)|add(n3,n4)|divide(const_1,n2)|divide(const_1,#0)|multiply(n4,#0)|add(#3,#2)|divide(const_1,#5)|multiply(#1,#6)|subtract(#4,#7) | a professional janitor can clean a certain high school in ( 4 + 4 ) or 8 hours so ( applying rule # 1 ) , the janitor can clean 1 / 8 of the school in one hour a student sentenced to detention can clean that same high school in 20 hours so ( applying rule # 1 ) , the student can clean 1 / 20 of the school in one hour so , combined , the student and janitor can clean ( 1 / 8 + 1 / 20 ) of the school in one hour 1 / 8 + 1 / 20 = 5 / 40 + 2 / 40 = 7 / 40 so , in one hour they can clean 7 / 40 of the school . applying rule # 2 , it will takethem 40 / 7 hoursto clean the entire school . the janitor earns $ 21 / hour and the student earns $ 7 / hour , so their combined rate is $ 28 / hour . theircombined wages = ( pay rate ) ( time ) = ( $ 28 / hour ) ( 40 / 7 hours ) = $ 160 working alone , the janitor takes 8 hours and earns $ 21 / hour so , working alone , the janitor ' s earnings = ( pay rate ) ( time ) = ( $ 21 / hour ) ( 8 hours ) = $ 168 $ 168 - $ 160 = $ 8 , so the answer is e | general |
math_qa__a1KRStvUxHrrW93F | 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 2 men and 3 women will do that task. Choose one
A) 1 / 2 B) 1 / 10 C) 1 / 18 D) 1 / 16 E) 1 / 11 | <gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">7 / 14</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 2 men and 3 women will do that task. | {
"A": "1 / 2",
"B": "1 / 10",
"C": "1 / 18",
"D": "1 / 16",
"E": "1 / 11"
} | divide(add(multiply(divide(subtract(8, 2), subtract(6, 3)), 2), 3), add(multiply(6, divide(subtract(8, 2), subtract(6, 3))), 2)) | subtract(n1,n3)|subtract(n2,n0)|divide(#0,#1)|multiply(n4,#2)|multiply(n2,#2)|add(n5,#3)|add(n3,#4)|divide(#5,#6)| | "3 m + 8 w = 6 m + 2 w 3 m = 6 w 1 m = 2 w therefore 3 m + 8 w = 14 w 2 m + 3 w = 7 w answer is 7 / 14 = 1 / 2 answer : a" | physics |
math_qa__ISsiqQERyEEInP1U | A light has a rating of 60 watts, it is replaced with a new light that has 12% higher wattage. How many watts does the new light have?
Select:
A) 105
B) 67
C) 80
D) 60
E) 100 | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 + (3/25)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">60 * (28/25)</gadget>
<output>336/5 = around 67.2</output>
<result>B</result> | B | 67 | A light has a rating of 60 watts, it is replaced with a new light that has 12% higher wattage. How many watts does the new light have? | {
"A": "105",
"B": "67",
"C": "80",
"D": "60",
"E": "100"
} | multiply(60, add(const_1, divide(12, const_100))) | divide(n1,const_100)|add(#0,const_1)|multiply(n0,#1)| | "final number = initial number + 12 % ( original number ) = 60 + 12 % ( 60 ) = 60 + 7 = 67 answer b" | gain |
math_qa__exuE0duNLn7fFcLH | A sum of money becomes 7/6 of itself in 6 years at a certain rate of simple interest. The rate per annum is? Choices: A) 50 / 9 B) 50 / 13 C) 50 / 17 D) 25 / 9 E) 5 5 / 1 | <gadget id="calculator">7 / 6</gadget>
<output>7/6 = around 1.166667</output>
<gadget id="calculator">(7/6) - 1</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) / 6</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">(1/36) * 100</gadget>
<output>25/9 = around 2.777778</output>
<result>D</result> | D | 2.777778 | A sum of money becomes 7/6 of itself in 6 years at a certain rate of simple interest. The rate per annum is? | {
"A": "50 / 9",
"B": "50 / 13",
"C": "50 / 17",
"D": "25 / 9",
"E": "5 5 / 1"
} | multiply(divide(subtract(divide(7, 6), const_1), 6), const_100) | divide(n0,n1)|subtract(#0,const_1)|divide(#1,n2)|multiply(#2,const_100)| | "let sum = x . then , amount = 7 x / 6 s . i . = 7 x / 6 - x = x / 6 ; time = 6 years . rate = ( 100 * x ) / ( x * 6 * 6 ) = 25 / 9 % . answer : d" | gain |
math_qa__exNe1Igef4BSGfNb | Find the missing figures: 0.3% of ? = 0.15 Choose the correct choice from the following answers: A) 50 B) 45 C) 150 D) 450 E) 500 | <gadget id="calculator">0.3 / 100</gadget>
<output>0.003</output>
<gadget id="calculator">0.15 / 0.003</gadget>
<output>50</output>
<result>A</result> | A | 50 | Find the missing figures: 0.3% of ? = 0.15 | {
"A": "50",
"B": "45",
"C": "150",
"D": "450",
"E": "500"
} | divide(0.15, divide(0.3, const_100)) | divide(n0,const_100)|divide(n1,#0) | let 0.3 % of x = 0.15 . then , 0.30 * x / 100 = 0.15 x = [ ( 0.15 * 100 ) / 0.3 ] = 50 . answer is a . | gain |
math_qa__hn6QwPBvTNoKQTbE | The mean daily profit made by a shopkeeper in a month of 30 days was Rs. 350. If the mean profit for the first fifteen days was Rs. 265, then the mean profit for the last 15 days would be Choose the correct choice from the following choices
A) rs . 435 B) rs . 350 C) rs . 275 D) rs . 425 E) none of these | <gadget id="calculator">30 * 350</gadget>
<output>10_500</output>
<gadget id="calculator">15 * 265</gadget>
<output>3_975</output>
<gadget id="calculator">10_500 - 3_975</gadget>
<output>6_525</output>
<gadget id="calculator">6_525 / 15</gadget>
<output>435</output>
<result>A</result> | A | 435 | The mean daily profit made by a shopkeeper in a month of 30 days was Rs. 350. If the mean profit for the first fifteen days was Rs. 265, then the mean profit for the last 15 days would be | {
"A": "rs . 435",
"B": "rs . 350",
"C": "rs . 275",
"D": "rs . 425",
"E": "none of these"
} | divide(subtract(multiply(30, 350), multiply(15, 265)), 15) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)|divide(#2,n3) | average would be : 350 = ( 265 + x ) / 2 on solving , x = 435 . answer : a | gain |
math_qa__KTHd2pIPJlBUCOpU | The ratio of the number of females to males at a party was 1:2 but when 5 females and 5 males left, the ratio became 1:3. How many people were at the party originally? Choose the most appropriate option: A) 26 B) 28 C) 30 D) 32 E) 34 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">30 - 10</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 20</gadget>
<output>30</output>
<result>C</result> | C | 30 | The ratio of the number of females to males at a party was 1:2 but when 5 females and 5 males left, the ratio became 1:3. How many people were at the party originally? | {
"A": "26",
"B": "28",
"C": "30",
"D": "32",
"E": "34"
} | add(divide(subtract(multiply(multiply(5, 2), 3), multiply(5, 2)), 2), subtract(multiply(multiply(5, 2), 3), multiply(5, 2))) | multiply(n1,n2)|multiply(n5,#0)|subtract(#1,#0)|divide(#2,n1)|add(#3,#2)| | "the total number of people are x females + 2 x males . 3 * ( x - 5 ) = 2 x - 5 x = 10 there were 3 x = 30 people at the party originally . the answer is c ." | other |
math_qa__NDKY6mg5D6EO2dGA | The least number which when increased by 8 each divisible by each one of 24, 32, 36 and 54 is : Select.
A) 427 B) 859 C) 869 D) 856 E) none of these | <gadget id="calculator">lcm(24, 32)</gadget>
<output>96</output>
<gadget id="calculator">lcm(96, 36)</gadget>
<output>288</output>
<gadget id="calculator">lcm(288, 54)</gadget>
<output>864</output>
<gadget id="calculator">864 - 8</gadget>
<output>856</output>
<result>D</result> | D | 856 | The least number which when increased by 8 each divisible by each one of 24, 32, 36 and 54 is : | {
"A": "427",
"B": "859",
"C": "869",
"D": "856",
"E": "none of these"
} | subtract(lcm(lcm(lcm(24, 32), 36), 54), 8) | lcm(n1,n2)|lcm(n3,#0)|lcm(n4,#1)|subtract(#2,n0)| | "solution required number = ( l . c . m . of 24 , 32 , 36 , 54 ) - 8 = 864 - 8 = 856 . answer d" | general |
math_qa__Vvd6GciC6NXMvZAQ | Find the length of the wire required to go 10 times round a square field containing 53824 m2.
Choose the correct choice from the following choices:
A) 15840 B) 9280 C) 2667 D) 8766 E) 66711 | <gadget id="calculator">53_824 ** (1/2)</gadget>
<output>232</output>
<gadget id="calculator">4 * 232</gadget>
<output>928</output>
<gadget id="calculator">928 * 10</gadget>
<output>9_280</output>
<result>B</result> | B | 9,280 | Find the length of the wire required to go 10 times round a square field containing 53824 m2. | {
"A": "15840",
"B": "9280",
"C": "2667",
"D": "8766",
"E": "66711"
} | multiply(square_perimeter(square_edge_by_area(53824)), 10) | square_edge_by_area(n1)|square_perimeter(#0)|multiply(n0,#1) | a 2 = 53824 = > a = 232 4 a = 928 928 * 10 = 9280 answer : b | physics |
math_qa__teZToDLUIRYDaPs1 | The number of the members of a club is more than 20 and less than 50. When 4 people sit at a table, other people exactly divided to 6-people groups (6 people sit at a table) or 7-people groups (7 people sit at a table). If the members are divided to 8-people groups, how many people will be left?
Choose the correct option.
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">lcm(6, 7)</gadget>
<output>42</output>
<gadget id="calculator">42 + 4</gadget>
<output>46</output>
<gadget id="calculator">46 % 8</gadget>
<output>6</output>
<result>D</result> | D | 6 | The number of the members of a club is more than 20 and less than 50. When 4 people sit at a table, other people exactly divided to 6-people groups (6 people sit at a table) or 7-people groups (7 people sit at a table). If the members are divided to 8-people groups, how many people will be left? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | reminder(add(lcm(6, 7), 4), 8) | lcm(n3,n5)|add(n2,#0)|reminder(#1,n7)| | "the number of members is 7 k + 4 = 6 j + 4 the only number in this range which satisfies this is 46 . 46 / 8 = 5 ( 8 ) + 6 the answer is d ." | general |
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