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math_qa__rfJT7qSPgjo1fybh | in a 4 person race , medals are awarded to the fastest 3 runners . the first - place runner receives a gold medal , the second - place runner receives a silver medal , and the third - place runner receives a bronze medal . in the event of a tie , the tied runners receive the same color medal . ( for example , if there is a two - way tie for first - place , the top two runners receive gold medals , the next - fastest runner receives a silver medal , and no bronze medal is awarded ) . assuming that exactly 3 medals are awarded , and that the 3 medal winners stand together with their medals to form a victory circle , how many z different victory circles are possible ? Choose the correct option:
A) 24 B) 52 C) 96 D) 144 E) 648 | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">36 + 12</gadget>
<output>48</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">24 / 6</gadget>
<output>4</output>
<gadget id="calculator">48 + 4</gadget>
<output>52</output>
<result>B</result> | B | 52 | in a 4 person race , medals are awarded to the fastest 3 runners . the first - place runner receives a gold medal , the second - place runner receives a silver medal , and the third - place runner receives a bronze medal . in the event of a tie , the tied runners receive the same color medal . ( for example , if there is a two - way tie for first - place , the top two runners receive gold medals , the next - fastest runner receives a silver medal , and no bronze medal is awarded ) . assuming that exactly 3 medals are awarded , and that the 3 medal winners stand together with their medals to form a victory circle , how many z different victory circles are possible ? | {
"A": "24",
"B": "52",
"C": "96",
"D": "144",
"E": "648"
} | add(add(add(factorial(4), divide(factorial(4), factorial(const_2))), divide(factorial(4), factorial(const_2))), divide(factorial(4), factorial(3))) | factorial(n0)|factorial(const_2)|factorial(n1)|divide(#0,#1)|divide(#0,#2)|add(#3,#0)|add(#5,#3)|add(#6,#4) | possible scenarios are : 1 . gold / silver / bronze / no medal ( no ties ) - 4 ! = 24 ; 2 . gold / gold / silver / no medal - 4 ! / 2 ! = 12 ; 3 . gold / silver / silver / no medal - 4 ! / 2 ! = 12 ; 4 . gold / gold / gold / no medal - 4 ! / 3 ! = 4 . total z : 24 + 12 + 12 + 4 = 52 answer : b . | general |
math_qa__Tuv2LRtH577G9K02 | an air - conditioning unit costs $ 470 . on december there was a discount for christmas of 16 % . 6 months later , the holiday season was over so the company raised the price of the air - conditioning by 12 % . how much will an air - conditioning unit cost in november ? Choose the correct choice from the following.
A) $ 442 B) $ 470 C) $ 472 D) $ 484 E) $ 491 | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) + 1</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">1 - (4/25)</gadget>
<output>21/25 = around 0.84</output>
<gadget id="calculator">(21/25) * 470</gadget>
<output>1_974/5 = around 394.8</output>
<gadget id="calculator">(28/25) * (1_974/5)</gadget>
<output>55_272/125 = around 442.176</output>
<result>A</result> | A | 442 | an air - conditioning unit costs $ 470 . on december there was a discount for christmas of 16 % . 6 months later , the holiday season was over so the company raised the price of the air - conditioning by 12 % . how much will an air - conditioning unit cost in november ? | {
"A": "$ 442",
"B": "$ 470",
"C": "$ 472",
"D": "$ 484",
"E": "$ 491"
} | multiply(add(divide(12, const_100), const_1), multiply(subtract(const_1, divide(16, const_100)), 470)) | divide(n3,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(n0,#3)|multiply(#2,#4) | if its previous november ( before discount ) then price is $ 470 . but if its november of next year then 16 % discount on $ 470 = 470 ( 1 - 16 / 100 ) = $ 394.8 again a corrected raised price of 12 % over $ 394.8 = 394.8 ( 1 + 12 / 100 ) = 442.176 ~ $ 4442 ans a | gain |
math_qa__v4uibZL5fhW1OKxH | In the Hillside summer camp there are 50 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen? Choose the most appropriate option: A) 50 B) 45 . C) 40 . D) 30 . E) 25 . | <gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">95 / 100</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) * 50</gadget>
<output>95/2 = around 47.5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 50</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(95/2) + (5/2)</gadget>
<output>50</output>
<result>A</result> | A | 50 | In the Hillside summer camp there are 50 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen? | {
"A": "50",
"B": "45 .",
"C": "40 .",
"D": "30 .",
"E": "25 ."
} | add(multiply(divide(subtract(const_100, 5), const_100), 50), multiply(divide(5, const_100), 50)) | divide(n2,const_100)|subtract(const_100,n2)|divide(#1,const_100)|multiply(n0,#0)|multiply(n0,#2)|add(#4,#3)| | "given there are 50 students , 90 % of 50 = 45 boys and remaining 5 girls . now here 90 % are boys and 10 % are girls . now question is asking about how many boys do we need to add , to make the girls percentage to 5 or 5 % . . if we add 50 to existing 45 then the count will be 95 and the girls number will be 5 as it . now boys are 95 % and girls are 5 % . ( out of 100 students = 95 boys + 5 girls ) . answer : option a is correct ." | general |
math_qa__xCE1qKnUjLwRX6hD | Maths, Physics and chemistry books are stored on a library shelf that can accommodate 25 books. Currently, 20% of the shelf spots remain empty. There are twice as many maths books as physics books and the number of physics books is 4 greater than that of chemistry books. Among all the books, 12 books are soft cover and the remaining are hard-cover. If there are a total of 7 hard-cover books among the maths and physics books. What is the probability E, that a book selected at random is either a hard cover book or a chemistry book? Select the correct option: A) 1 / 10 B) 3 / 20 C) 1 / 5 D) 1 / 4 E) 9 / 20 | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">2 + 6</gadget>
<output>8</output>
<gadget id="calculator">8 + 12</gadget>
<output>20</output>
<gadget id="calculator">2 / 20</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">8 / 20</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/10) + (2/5)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/10) * (2/5)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/2) - (1/25)</gadget>
<output>23/50 = around 0.46</output>
<result>E</result> | E | 0.45 | Maths, Physics and chemistry books are stored on a library shelf that can accommodate 25 books. Currently, 20% of the shelf spots remain empty. There are twice as many maths books as physics books and the number of physics books is 4 greater than that of chemistry books. Among all the books, 12 books are soft cover and the remaining are hard-cover. If there are a total of 7 hard-cover books among the maths and physics books. What is the probability E, that a book selected at random is either a hard cover book or a chemistry book? | {
"A": "1 / 10",
"B": "3 / 20",
"C": "1 / 5",
"D": "1 / 4",
"E": "9 / 20"
} | subtract(add(divide(const_2, add(add(const_2, add(const_2, 4)), 12)), divide(add(const_2, add(const_2, 4)), add(add(const_2, add(const_2, 4)), 12))), multiply(divide(const_2, add(add(const_2, add(const_2, 4)), 12)), divide(add(const_2, add(const_2, 4)), add(add(const_2, add(const_2, 4)), 12)))) | add(n2,const_2)|add(#0,const_2)|add(n3,#1)|divide(const_2,#2)|divide(#1,#2)|add(#3,#4)|multiply(#3,#4)|subtract(#5,#6)| | "first phase of this problem requires you to determine how many mathematics and chemistry books are even on the shelf . to do so , you have the equations : m + p + c = 20 ( since 4 / 5 of the 25 spots are full of books ) m = 2 p p = 4 + c from that , you can use substitution to get everything down to one variable . c = p - 4 m = 2 p p = p then ( p - 4 ) + 2 p + p = 20 , so 4 p = 24 and p = 6 . that means that there are 12 math , 6 physics , and 2 chemistry books on the shelf . with those numbers , you also know that there are 8 total hardcovers , 1 of which is chemistry . so if your goal is to get either a hardcover or a chemistry , there are 9 ways towin - either one of the 7 hardcovers that are n ' t chemistry or the two chemistry books . so out of the 20 total , e = 9 provide the desired outcome , making the answer e ." | general |
math_qa__9YSoRM3CnDK8O8yv | How many diagonals does a polygon with 17 sides have, if one of its vertices does not connect to any diagonal? Choose the correct option.
A) 102
B) 104
C) 110
D) 90
E) 84 | <gadget id="calculator">17 - 1</gadget>
<output>16</output>
<gadget id="calculator">16 - 3</gadget>
<output>13</output>
<gadget id="calculator">16 * 13</gadget>
<output>208</output>
<gadget id="calculator">208 / 2</gadget>
<output>104</output>
<result>B</result> | B | 104 | How many diagonals does a polygon with 17 sides have, if one of its vertices does not connect to any diagonal? | {
"A": "102",
"B": "104",
"C": "110",
"D": "90",
"E": "84"
} | divide(multiply(subtract(17, const_1), subtract(subtract(17, const_1), const_3)), const_2) | subtract(n0,const_1)|subtract(#0,const_3)|multiply(#0,#1)|divide(#2,const_2)| | "if i calculate it using the formulae , # diagonals = n ( n - 3 ) / 2 each vertex sends of n - 3 diagonals n = 17 - 1 then 16 * ( 16 - 3 ) / 2 = 104 correct option : b" | geometry |
math_qa__eVLwHzFRyXr0Ayfd | the sum of 3 consecutive multiples of 3 is 72 . what is the larget number ? Choose the correct option
A) 26 B) 27 C) 46 D) 57 E) none | <gadget id="calculator">72 / 3</gadget>
<output>24</output>
<gadget id="calculator">24 + 3</gadget>
<output>27</output>
<result>B</result> | B | 27 | the sum of 3 consecutive multiples of 3 is 72 . what is the larget number ? | {
"A": "26",
"B": "27",
"C": "46",
"D": "57",
"E": "none"
} | add(divide(72, 3), 3) | divide(n2,n0)|add(n0,#0) | sol . let the numbers be 3 x , 3 x + 3 and 3 x + 6 . then , 3 x + ( 3 x + 3 ) + ( 3 x + 6 ) = 72 ⇔ 9 x = 63 ⇔ x = 7 . ∴ largest number = 3 x + 6 = 27 . answer b | general |
math_qa__JIN8wXpKLh4i4VyC | A certain school implemented a reading program for its students, with the goal of getting each student to read 7 books per month year-round. If the school has c classes made up of s students in each class, how many books will the entire student body read in one year? Options:
A) 20 cs
B) cs / 2
C) 84 cs
D) ( 2 cs ) / 12
E) ( 24 c ) / s | <gadget id="calculator">7 * 12</gadget>
<output>84</output>
<result>C</result> | C | 84 | A certain school implemented a reading program for its students, with the goal of getting each student to read 7 books per month year-round. If the school has c classes made up of s students in each class, how many books will the entire student body read in one year? | {
"A": "20 cs",
"B": "cs / 2",
"C": "84 cs",
"D": "( 2 cs ) / 12",
"E": "( 24 c ) / s"
} | multiply(7, const_12) | multiply(n0,const_12) | ans : c solution : simple multiplication s students , c classes , 7 books / month = 84 books a year total number of books = 84 cs | general |
math_qa__yODVd318wu8r9w5u | A man, a woman and a boy can complete a job in 3,4 and 12 days respectively.
How many boys must assist 1 man and 1 woman to complete the job in ¼ of a day? Choose the correct option.
A) 1 day
B) 4 days
C) 19 days
D) 41 days
E) 52 days | <gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">48 - 7</gadget>
<output>41</output>
<result>D</result> | D | 41 | A man, a woman and a boy can complete a job in 3,4 and 12 days respectively.
How many boys must assist 1 man and 1 woman to complete the job in ¼ of a day? | {
"A": "1 day",
"B": "4 days",
"C": "19 days",
"D": "41 days",
"E": "52 days"
} | subtract(multiply(12, const_4), add(const_3, const_4)) | add(const_3,const_4)|multiply(n1,const_4)|subtract(#1,#0) | ( 1 man + 1 woman ) ' s 1 days work = 1 / 3 + 1 / 4 = 7 / 12 work done by 1 man and 1 women n 1 / 4 day = ( ( 7 / 12 ) * ( 1 / 4 ) ) = 7 / 48 remaining work = 1 - 7 / 48 = 41 / 48 work done by 1 boy in ¼ day = ( ( 1 / 12 ) * ( 1 / 4 ) ) = 1 / 48 therefore , number of boys required = ( ( 41 / 48 ) * 48 ) = 41 days answer d 41 days | physics |
math_qa__0K5Z9cB6w0agZ65A | If the radius of the sphere is 14 m. then its total surface area is Choose the correct choice from the following options
A) 2644 B) 2446 C) 2464 D) 6442 E) 6424 | <gadget id="calculator">4 * pi * (14 ** 2)</gadget>
<output>784*pi = around 2_463.00864</output>
<result>C</result> | C | 2,464 | If the radius of the sphere is 14 m. then its total surface area is | {
"A": "2644",
"B": "2446",
"C": "2464",
"D": "6442",
"E": "6424"
} | surface_sphere(14) | surface_sphere(n0) | sphere total surface area = 4 π r ( power 2 ) = 4 × 22 / 7 × 14 × 14 = 2464 answer is c . | geometry |
math_qa__DX12RB6uXIfzXDco | A dealer offers a cash discount of 10% and still makes a profit of 35% when he further allows 20 articles to be sold at the cost price of 15 articles to a particular sticky bargainer. How much percent above the cost price were his articles listed? Options:
A) 80 % B) 100 % C) 120 % D) 60 % E) 90 % | <gadget id="calculator">100 + 35</gadget>
<output>135</output>
<gadget id="calculator">135 / 100</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">5 / 20</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(27/20) / (3/4)</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/5) / (9/10)</gadget>
<output>2</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>B</result> | B | 100 | A dealer offers a cash discount of 10% and still makes a profit of 35% when he further allows 20 articles to be sold at the cost price of 15 articles to a particular sticky bargainer. How much percent above the cost price were his articles listed? | {
"A": "80 %",
"B": "100 %",
"C": "120 %",
"D": "60 %",
"E": "90 %"
} | multiply(subtract(divide(divide(divide(add(const_100, 35), const_100), subtract(const_1, divide(subtract(20, 15), 20))), divide(subtract(const_100, 10), const_100)), const_1), const_100) | add(n1,const_100)|subtract(n2,n3)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,n2)|divide(#2,const_100)|subtract(const_1,#4)|divide(#3,#6)|divide(#7,#5)|subtract(#8,const_1)|multiply(#9,const_100)| | "given cash discount - 10 % profit - 35 % items sold - 20 price sold at = list price of 15 assume list price = $ 20 total invoice = $ 300 - 10 % cash discount = $ 270 let cost price of 20 items be x so total cost = 20 * x given the shopkeeper had a profit of 20 % 20 * x * 135 / 100 = 270 or x = $ 10 which means his products were listed at $ 20 which is a 100 % markup over $ 10 answer b" | gain |
math_qa__vNIr3Z1GQHmPAWEK | Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $20 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $9 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discounts rates is 22 percent, what is the discount rate on Pony jeans?
Choose one
A) 9 % B) 10 % C) 11 % D) 12 % E) 18 % | <gadget id="calculator">22 / 100</gadget>
<output>11/50 = around 0.22</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">(11/50) * 40</gadget>
<output>44/5 = around 8.8</output>
<gadget id="calculator">9 - (44/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">45 - 40</gadget>
<output>5</output>
<gadget id="calculator">(1/5) / 5</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(11/50) - (1/25)</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) * 100</gadget>
<output>18</output>
<result>E</result> | E | 18 | Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $20 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $9 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discounts rates is 22 percent, what is the discount rate on Pony jeans? | {
"A": "9 %",
"B": "10 %",
"C": "11 %",
"D": "12 %",
"E": "18 %"
} | multiply(subtract(divide(22, const_100), divide(subtract(9, multiply(divide(22, const_100), multiply(20, 2))), subtract(multiply(15, 3), multiply(20, 2)))), const_100) | divide(n6,const_100)|multiply(n1,n5)|multiply(n0,n4)|multiply(#0,#1)|subtract(#2,#1)|subtract(n2,#3)|divide(#5,#4)|subtract(#0,#6)|multiply(#7,const_100)| | "x discount on pony jeans , ( 0.22 - x ) discount on fox jeans . set the equation : 3 * 15 ( 0.22 - x ) + 2 * 20 x = 9 - - > x = 0.18 = 18 % answer : e ." | gain |
math_qa__GDwc9nJvkqp8UTWf | If (5^7)(9^4)=3(15^x), what is the value of x? Choose the most appropriate option.
A) 7
B) 9
C) 11
D) 13
E) 15 | <gadget id="calculator">5 ** 7</gadget>
<output>78_125</output>
<gadget id="calculator">9 ** 4</gadget>
<output>6_561</output>
<gadget id="calculator">78_125 * 6_561</gadget>
<output>512_578_125</output>
<gadget id="calculator">512_578_125 / 3</gadget>
<output>170_859_375</output>
<gadget id="calculator">log(170_859_375)</gadget>
<output>log(170859375) = around 18.956351</output>
<gadget id="calculator">log(15)</gadget>
<output>log(15) = around 2.70805</output>
<gadget id="calculator">log(170859375) / log(15)</gadget>
<output>log(170859375)/log(15) = around 7</output>
<result>A</result> | A | 7 | If (5^7)(9^4)=3(15^x), what is the value of x? | {
"A": "7",
"B": "9",
"C": "11",
"D": "13",
"E": "15"
} | divide(log(divide(multiply(power(5, 7), power(9, 4)), 3)), log(15)) | log(n5)|power(n0,n1)|power(n2,n3)|multiply(#1,#2)|divide(#3,n4)|log(#4)|divide(#5,#0)| | "( 5 ^ 7 ) ( 9 ^ 4 ) = 3 ( 15 ^ x ) = > 5 ^ 7 * 3 ^ 8 = 3 * 3 ^ x * 5 ^ x = > 5 ^ 7 * 3 ^ 8 = 3 ^ ( x + 1 ) * 5 ^ x value of x = 7 answer a" | general |
math_qa__OMhOTrHU4SacSrAo | Henrikh lives x blocks from his office. It takes him 1 minute per block to walk to
work and 20 seconds per block to ride his bicycle to work. If it takes him exactly
8 minutes more to walk to work than to ride his bicycle, then x equals Choose the correct choice from the following choices:
A) 4 B) 7 C) 12 D) 15 E) 20 | <gadget id="calculator">8 * 60</gadget>
<output>480</output>
<gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">60 - 20</gadget>
<output>40</output>
<gadget id="calculator">480 / 40</gadget>
<output>12</output>
<result>C</result> | C | 12 | Henrikh lives x blocks from his office. It takes him 1 minute per block to walk to
work and 20 seconds per block to ride his bicycle to work. If it takes him exactly
8 minutes more to walk to work than to ride his bicycle, then x equals | {
"A": "4",
"B": "7",
"C": "12",
"D": "15",
"E": "20"
} | divide(multiply(8, const_60), subtract(multiply(1, const_60), 20)) | multiply(n2,const_60)|multiply(n0,const_60)|subtract(#1,n1)|divide(#0,#2) | the best way would be . . . per km , he takes 40 secs extra if he walks so he will take 8 mins or 8 * 60 secs in 8 * 60 / 40 = 12 km answer : c | physics |
math_qa__ln1AuVXvcLRyqjCm | George is 8 years more than Christopher and Ford is 2 years younger than Christopher. The sum of their ages is 60. Find the ages of Christopher. Choices:
A) 18 B) 19 C) 20 D) 21 E) 22 | <gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">60 - 6</gadget>
<output>54</output>
<gadget id="calculator">54 / 3</gadget>
<output>18</output>
<result>A</result> | A | 18 | George is 8 years more than Christopher and Ford is 2 years younger than Christopher. The sum of their ages is 60. Find the ages of Christopher. | {
"A": "18",
"B": "19",
"C": "20",
"D": "21",
"E": "22"
} | divide(subtract(60, subtract(8, 2)), const_3) | subtract(n0,n1)|subtract(n2,#0)|divide(#1,const_3) | christopher age = x george age , y = x + 8 - - - - - - - - - - > ( 1 ) ford age , z = x - 2 - - - - - - - - - - - - > ( 2 ) sum of their ages , x + y + z = 60 - - - - > ( 3 ) substitute z and y values in equation ( 3 ) therefore , x + ( x + 8 ) + ( x - 2 ) = 60 = > 3 x + 8 - 2 = 60 = > 3 x = 60 - 6 = > 3 x = 54 = > x = 54 / 3 x = 18 answer : a | general |
math_qa__7kU94EOAX5nhQsbC | John and Ingrid pay 30% and 40% tax annually, respectively. If John makes $56000 and Ingrid makes $74000, what is their combined tax rate?
Select the correct option: A) 32 % B) 34.4 % C) 35 % D) 35.6 % E) 36.4 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 56_000</gadget>
<output>16_800</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 74_000</gadget>
<output>29_600</output>
<gadget id="calculator">16_800 + 29_600</gadget>
<output>46_400</output>
<gadget id="calculator">74_000 + 56_000</gadget>
<output>130_000</output>
<gadget id="calculator">46_400 / 130_000</gadget>
<output>116/325 = around 0.356923</output>
<gadget id="calculator">(116/325) * 100</gadget>
<output>464/13 = around 35.692308</output>
<result>D</result> | D | 35.6 | John and Ingrid pay 30% and 40% tax annually, respectively. If John makes $56000 and Ingrid makes $74000, what is their combined tax rate? | {
"A": "32 %",
"B": "34.4 %",
"C": "35 %",
"D": "35.6 %",
"E": "36.4 %"
} | multiply(divide(add(multiply(divide(30, const_100), 56000), multiply(divide(40, const_100), 74000)), add(74000, 56000)), const_100) | add(n2,n3)|divide(n0,const_100)|divide(n1,const_100)|multiply(n2,#1)|multiply(n3,#2)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100)| | "( 1 ) when 30 and 40 has equal weight or weight = 1 / 2 , the answer would be 35 . ( 2 ) when 40 has larger weight than 30 , the answer would be in between 35 and 40 . unfortunately , we have 2 answer choices d and e that fit that condition so we need to narrow down our range . ( 3 ) get 74000 / 128000 = 74 / 128 = 37 / 65 is a little above 1 / 2 . thus , our answer is just a little above 35 . answer : d" | gain |
math_qa__e7VToxj3AF61fo4P | 10^(65) ÷ 10^(64) = ?
Choose the most appropriate option
A) 1
B) 10
C) 100
D) 1000
E) 10000 | <gadget id="calculator">65 - 64</gadget>
<output>1</output>
<gadget id="calculator">10 ** 1</gadget>
<output>10</output>
<result>B</result> | B | 10 | 10^(65) ÷ 10^(64) = ? | {
"A": "1",
"B": "10",
"C": "100",
"D": "1000",
"E": "10000"
} | power(10, subtract(65, 64)) | subtract(n1,n3)|power(n0,#0)| | "10 ^ ( 65 ) ã · 10 ^ ( 64 ) = 10 ^ ( 65 - 64 ) = 10 ^ 1 = 10 answer : b" | general |
math_qa__mKrOkfXIDAMzYCMz | The average of the marks of 11 students in a class is 36. If the marks of each student are doubled, find the new average?
Choices:
A) 69 B) 70 C) 71 D) 72 E) 75 | <gadget id="calculator">36 * 2</gadget>
<output>72</output>
<result>D</result> | D | 72 | The average of the marks of 11 students in a class is 36. If the marks of each student are doubled, find the new average? | {
"A": "69",
"B": "70",
"C": "71",
"D": "72",
"E": "75"
} | multiply(36, const_2) | multiply(n1,const_2) | sum of the marks for the 11 students = 11 * 36 = 396 . the marks of each student are doubled , the sum also will be doubled . the new sum = 396 * 2 = 792 . so , the new average = 792 / 11 = 72 . answer : d | general |
math_qa__m8BAJygO4oPgpWI0 | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is: Choose the correct choice from the following choices: A) 2 : 5 B) 2 : 3 C) 2 : 4 D) 2 : 1 E) 2 : 9 | <gadget id="calculator">15.8 - 15.4</gadget>
<output>0.4</output>
<gadget id="calculator">16.4 - 15.8</gadget>
<output>0.6</output>
<gadget id="calculator">0.4 / 0.6</gadget>
<output>0.666667</output>
<result>B</result> | B | 0.666667 | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is: | {
"A": "2 : 5",
"B": "2 : 3",
"C": "2 : 4",
"D": "2 : 1",
"E": "2 : 9"
} | divide(subtract(15.8, 15.4), subtract(16.4, 15.8)) | subtract(n0,n2)|subtract(n1,n0)|divide(#0,#1)| | "let the ratio be k : 1 . then , k * 16.4 + 1 * 15.4 = ( k + 1 ) * 15.8 = ( 16.4 - 15.8 ) k = ( 15.8 - 15.4 ) = k = 0.4 / 0.6 = 2 / 3 required ratio = 2 / 3 : 1 = 2 : 3 . answer : b" | general |
math_qa__iUTdlkrUdoJJlpDS | In a restaurant, the profit is 140% of the cost. If the cost increases by 12% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Select:
A) 30 %
B) 53 %
C) 90 %
D) 100 %
E) none of these | <gadget id="calculator">140 / 100</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">100 * (7/5)</gadget>
<output>140</output>
<gadget id="calculator">140 + 100</gadget>
<output>240</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 + (3/25)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">100 * (28/25)</gadget>
<output>112</output>
<gadget id="calculator">240 - 112</gadget>
<output>128</output>
<gadget id="calculator">128 / 240</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">100 * (8/15)</gadget>
<output>160/3 = around 53.333333</output>
<result>B</result> | B | 53 | In a restaurant, the profit is 140% of the cost. If the cost increases by 12% but the selling price remains constant, approximately what percentage of the selling price is the profit? | {
"A": "30 %",
"B": "53 %",
"C": "90 %",
"D": "100 %",
"E": "none of these"
} | multiply(const_100, divide(subtract(add(multiply(const_100, divide(140, const_100)), const_100), multiply(const_100, add(const_1, divide(12, const_100)))), add(multiply(const_100, divide(140, const_100)), const_100))) | divide(n0,const_100)|divide(n1,const_100)|add(#1,const_1)|multiply(#0,const_100)|add(#3,const_100)|multiply(#2,const_100)|subtract(#4,#5)|divide(#6,#4)|multiply(#7,const_100)| | "explanation : let c . p . = rs . 100 . then , profit = rs . 140 , s . p . = rs . 240 . new c . p . = 112 % of rs . 100 = rs . 112 new s . p . = rs . 240 . profit = rs . ( 240 - 112 ) = rs . 128 . required percentage = ( 128 / 240 * 100 ) % = 53 % appox answer : b" | gain |
math_qa__8T6Tryr30ske9S8f | A hemispherical bowl is made of 0.5 cm thick steel. Inner radius of the bowl is 4 cm. The volume of steel used in making the bowl is
Choose the most appropriate option.
A) 55.83 cm 3
B) 56.83 cm 3
C) 113.67 cm 3
D) 58.83 cm 3
E) none of these | <gadget id="calculator">4 + 0.5</gadget>
<output>4.5</output>
<gadget id="calculator">4/3 * pi * (4.5 ** 3)</gadget>
<output>121.5*pi = around 381.703507</output>
<gadget id="calculator">4/3 * pi * (4 ** 3)</gadget>
<output>256*pi/3 = around 268.082573</output>
<gadget id="calculator">(121.5*pi) - (256*pi/3)</gadget>
<output>36.1666666666667*pi = around 113.620934</output>
<gadget id="calculator">(36.1666666666667*pi) / 2</gadget>
<output>18.0833333333333*pi = around 56.810467</output>
<result>B</result> | B | 56.83 | A hemispherical bowl is made of 0.5 cm thick steel. Inner radius of the bowl is 4 cm. The volume of steel used in making the bowl is | {
"A": "55.83 cm 3",
"B": "56.83 cm 3",
"C": "113.67 cm 3",
"D": "58.83 cm 3",
"E": "none of these"
} | divide(subtract(volume_sphere(add(4, 0.5)), volume_sphere(4)), const_2) | add(n0,n1)|volume_sphere(n1)|volume_sphere(#0)|subtract(#2,#1)|divide(#3,const_2) | inner r = 4 outer r = 4.5 formula = 2 / 3 * 22 / 7 ( r ^ 2 - r ^ 2 ) ( 2 / 3 ) * ( 22 / 7 ) * ( 4.5 * 4.5 * 4.5 - 4 * 4 * 4 ) = 56.83 answer : b | physics |
math_qa__S26MqDJOYY7tj3DL | A large box contains 18 small boxes and each small box contains 28 chocolate bars. How many chocolate bars are in the large box? Select the correct option:
A) 220
B) 490
C) 380
D) 450
E) 504 | <gadget id="calculator">18 * 28</gadget>
<output>504</output>
<result>E</result> | E | 504 | A large box contains 18 small boxes and each small box contains 28 chocolate bars. How many chocolate bars are in the large box? | {
"A": "220",
"B": "490",
"C": "380",
"D": "450",
"E": "504"
} | multiply(18, 28) | multiply(n0,n1)| | "the only thing you have to do is a simple multiply we have : 18 * 28 = 504 correct answer is : e ) 504" | general |
math_qa__XyJmkdiuuANjqI7I | If one root of the equation 2x^2 + 3x – k = 0 is 5, what is the value of k? Choose the correct choice
A) 65
B) 79
C) 68
D) 87
E) 90 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">2 * 25</gadget>
<output>50</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">50 + 15</gadget>
<output>65</output>
<result>A</result> | A | 65 | If one root of the equation 2x^2 + 3x – k = 0 is 5, what is the value of k? | {
"A": "65",
"B": "79",
"C": "68",
"D": "87",
"E": "90"
} | add(multiply(2, power(5, 2)), multiply(3, 5)) | multiply(n2,n4)|power(n4,n0)|multiply(n0,#1)|add(#2,#0)| | "we just enter this root into the equation in order to recieve an equation to find the answer ! 2 * 5 ^ 2 + 3 * 5 - k = 0 k = 50 + 15 = 65 the answer is a" | general |
math_qa__6dn8Q3LP45sSkwNC | from the salary of rahul , 20 % is deducted as house rent , 10 % of the rest he spends on children ’ s education and 10 % of the balance , he spends on clothes . after this expenditure he is left with rs 1377 . his salary is ? Select: A) rs 2125 B) rs 2040 C) rs 2100 D) rs 2200 E) rs 2,300 | <gadget id="calculator">1_377 * 100</gadget>
<output>137_700</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">10 * 80</gadget>
<output>800</output>
<gadget id="calculator">800 / 100</gadget>
<output>8</output>
<gadget id="calculator">80 - 8</gadget>
<output>72</output>
<gadget id="calculator">72 * 10</gadget>
<output>720</output>
<gadget id="calculator">720 / 100</gadget>
<output>36/5 = around 7.2</output>
<gadget id="calculator">72 - (36/5)</gadget>
<output>324/5 = around 64.8</output>
<gadget id="calculator">137_700 / (324/5)</gadget>
<output>2_125</output>
<result>A</result> | A | 2,125 | from the salary of rahul , 20 % is deducted as house rent , 10 % of the rest he spends on children ’ s education and 10 % of the balance , he spends on clothes . after this expenditure he is left with rs 1377 . his salary is ? | {
"A": "rs 2125",
"B": "rs 2040",
"C": "rs 2100",
"D": "rs 2200",
"E": "rs 2,300"
} | divide(multiply(1377, const_100), subtract(subtract(subtract(const_100, 20), divide(multiply(10, subtract(const_100, 20)), const_100)), divide(multiply(subtract(subtract(const_100, 20), divide(multiply(10, subtract(const_100, 20)), const_100)), 10), const_100))) | multiply(n3,const_100)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,const_100)|subtract(#1,#3)|multiply(n1,#4)|divide(#5,const_100)|subtract(#4,#6)|divide(#0,#7) | suppose that his salary = rs 100 house rent = rs 20 , balance = rs 80 expenditure on education = rs ( 10 x 80 ) / 100 = rs 8 balance = rs 72 expenditure on clothes rs ( 10 x 72 ) / 100 = rs 7.2 balance now = rs 64.8 if balance is rs 64.8 , salary = rs 100 if balance is rs 1,377 , salary = rs ( 100 x 1377 ) / 64.8 rs 2,125 answer : a | gain |
math_qa__y2AsFNAcYQfPwHyj | The closest approximation of Q=(69.28 × 0.004)/0.03 is Choose the correct choice from the following choices: A) 0.092 B) 0.92 C) 9.2 D) 92 E) 920 | <gadget id="calculator">0.004 / 0.03</gadget>
<output>0.133333</output>
<gadget id="calculator">0.133333 * 69.28</gadget>
<output>9.23731</output>
<result>C</result> | C | 9.2 | The closest approximation of Q=(69.28 × 0.004)/0.03 is | {
"A": "0.092",
"B": "0.92",
"C": "9.2",
"D": "92",
"E": "920"
} | multiply(divide(0.004, 0.03), 69.28) | divide(n1,n2)|multiply(n0,#0)| | "q = ( 69.28 × 0.004 ) / 0.03 1 . 0.004 = 4 × 10 ^ ( - 3 ) 2 . 0.03 = 3 × 10 ^ ( - 2 ) 3 . ( a × b ) / c = a × ( b / c ) 4 . 0.004 / 0.03 = 4 × 10 ^ ( - 3 ) / ( 3 × 10 ^ ( - 2 ) ) = 4 × 10 ^ ( - 3 - ( - 2 ) ) / 3 = 4 × 10 ^ ( - 1 ) / 3 = ( 4 / 3 ) × 10 ^ ( - 1 ) = 1.333 × 10 ^ ( - 1 ) therefore , ( 69.28 × 0.004 ) / 0.03 = 69.28 × ( 0.004 / 0.03 ) = 69.28 × 1.33 × 10 ^ ( - 1 ) = 69.28 × 1.33 / 10 = 6.928 * 1.33 now , 7 × 2 = 14 7 × 1 = 7 or better : 6.9 × 1 = 6.9 6.9 × 2 = 13.8 hence , 6.9 < 6.928 × 1.33 < 13.8 9.2 is the only answer that satisfies this condition . c" | general |
math_qa__LLczZEpEXyFtltq7 | In an office, totally there are 800 employees and 25% of the total employees are males. 40% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years? Choose the correct choice from the following options.
A) 120 B) 160 C) 132 D) 130 E) none of these | <gadget id="calculator">800 * 25</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 100</gadget>
<output>200</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">200 * (3/5)</gadget>
<output>120</output>
<result>A</result> | A | 120 | In an office, totally there are 800 employees and 25% of the total employees are males. 40% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years? | {
"A": "120",
"B": "160",
"C": "132",
"D": "130",
"E": "none of these"
} | multiply(divide(multiply(800, 25), const_100), divide(subtract(const_100, 40), const_100)) | multiply(n0,n1)|subtract(const_100,n2)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)| | "number of male employees = 800 * 25 / 100 = 200 required number of male employees who are less than 50 years old = 200 * ( 100 - 40 ) % = 200 * 60 / 100 = 120 . answer : a" | general |
math_qa__u9F3BlRYiDkIs0yc | If a certain number X is divided by 82, the reminder is 5. what is the reminder when X+13 is divided by 41? Select the correct option
A) 3
B) 18
C) 6
D) 16
E) 5 | <gadget id="calculator">5 + 13</gadget>
<output>18</output>
<result>B</result> | B | 18 | If a certain number X is divided by 82, the reminder is 5. what is the reminder when X+13 is divided by 41? | {
"A": "3",
"B": "18",
"C": "6",
"D": "16",
"E": "5"
} | add(5, 13) | add(n1,n2)| | "x can be written as 82 k + 5 or x = 5 , 87,169 , etc . x + 13 = 82 k + 5 + 13 = 82 k + 18 or x + 13 = 18,100 , 182 etc . when divided by 41 , we will get the remainder 18 . b" | general |
math_qa__UMuxNBjf8iswPmyl | Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.341 in 2 years?
Choose the correct option: A) 221 B) 309 C) 400 D) 288 E) 171 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">341 / (441/400)</gadget>
<output>136_400/441 = around 309.297052</output>
<result>B</result> | B | 309 | Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.341 in 2 years? | {
"A": "221",
"B": "309",
"C": "400",
"D": "288",
"E": "171"
} | divide(341, power(add(const_1, divide(5, const_100)), 2)) | divide(n0,const_100)|add(#0,const_1)|power(#1,n2)|divide(n1,#2)| | "explanation : 341 = p ( 21 / 20 ) 2 p = 309.29 answer : b" | general |
math_qa__pTfvQVdOHgAiCGZi | A sum fetched total simple interest of 4016.25 at the rate of 10 p.c.p.a. in 5 years. What is the sum?
Choose the correct choice from the following choices:
A) 8925
B) 8032.5
C) 4462.5
D) 8900
E) none of these | <gadget id="calculator">100 * 4_016.25</gadget>
<output>401_625</output>
<gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">401_625 / 50</gadget>
<output>16_065/2 = around 8_032.5</output>
<result>B</result> | B | 8,032.5 | A sum fetched total simple interest of 4016.25 at the rate of 10 p.c.p.a. in 5 years. What is the sum? | {
"A": "8925",
"B": "8032.5",
"C": "4462.5",
"D": "8900",
"E": "none of these"
} | divide(multiply(const_100, 4016.25), multiply(10, 5)) | multiply(n0,const_100)|multiply(n1,n2)|divide(#0,#1) | let the sums be p . now , 50 % of p = 4016.25 or , p = 8032.5 answer b | gain |
math_qa__gPdKC4NcePTGwgj1 | In a factory, an average of 50 TV's are produced per day for the fist 25days of the months. A few workers fell ill for the next 5days reducing the daily avg for the month to 45 sets/day . The average production per day for day last 5days is ? Options: A) 20 B) 36 C) 48 D) 50 E) 59 | <gadget id="calculator">25 + 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 45</gadget>
<output>1_350</output>
<gadget id="calculator">25 * 50</gadget>
<output>1_250</output>
<gadget id="calculator">1_350 - 1_250</gadget>
<output>100</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<result>A</result> | A | 20 | In a factory, an average of 50 TV's are produced per day for the fist 25days of the months. A few workers fell ill for the next 5days reducing the daily avg for the month to 45 sets/day . The average production per day for day last 5days is ? | {
"A": "20",
"B": "36",
"C": "48",
"D": "50",
"E": "59"
} | divide(subtract(multiply(add(25, 5), 45), multiply(25, 50)), 5) | add(n1,n2)|multiply(n0,n1)|multiply(n3,#0)|subtract(#2,#1)|divide(#3,n2)| | "production during these 5 days = total production in a month - production in first 25 days . = 30 x 45 - 25 x 50 = 100 ∴ average for last 5 days = 100 / 5 = 20 a" | general |
math_qa__JuFIGId1vCuHWaUR | (1.2)(power 3) - (0.9)(power 3)/ (1.2)(power 2) + 1.08+ (0.9)(power 2) is: Select the correct option:
A) 0.68 B) 0.6 C) 0.8 D) 0.3 E) none of them | <gadget id="calculator">1.2 ** 3</gadget>
<output>1.728</output>
<gadget id="calculator">0.9 ** 3</gadget>
<output>0.729</output>
<gadget id="calculator">1.728 - 0.729</gadget>
<output>0.999</output>
<gadget id="calculator">1.2 ** 2</gadget>
<output>1.44</output>
<gadget id="calculator">1.44 + 1.08</gadget>
<output>2.52</output>
<gadget id="calculator">0.9 ** 2</gadget>
<output>0.81</output>
<gadget id="calculator">2.52 + 0.81</gadget>
<output>3.33</output>
<gadget id="calculator">0.999 / 3.33</gadget>
<output>0.3</output>
<result>D</result> | D | 0.3 | (1.2)(power 3) - (0.9)(power 3)/ (1.2)(power 2) + 1.08+ (0.9)(power 2) is: | {
"A": "0.68",
"B": "0.6",
"C": "0.8",
"D": "0.3",
"E": "none of them"
} | divide(subtract(power(1.2, 3), power(0.9, 3)), add(add(power(1.2, 2), 1.08), power(0.9, 2))) | power(n0,n1)|power(n2,n1)|power(n0,n5)|power(n2,n5)|add(n6,#2)|subtract(#0,#1)|add(#4,#3)|divide(#5,#6)| | "given expression = ( 1.2 ) ( power 3 ) - ( 0.9 ) ( power 3 ) / ( 1.2 ) ( power 2 ) + ( 1.2 x 0.9 ) + ( 0.9 ) ( power 2 ) = a ( power 3 ) - b ( power 3 ) / a ( power 2 ) + ab + b ( power 2 ) = ( a - b ) = ( 1.2 - 0.9 ) = 0.3 answer is d" | general |
math_qa__ETf0oslirXg8YHSg | A volume of 10996 l water is in a container of sphere. How many hemisphere of volume 4l each will be required to transfer all the water into the small hemispheres? Pick.
A) 2812 B) 8231 C) 2734 D) 4222 E) 2749 | <gadget id="calculator">10_996 / 4</gadget>
<output>2_749</output>
<result>E</result> | E | 2,749 | A volume of 10996 l water is in a container of sphere. How many hemisphere of volume 4l each will be required to transfer all the water into the small hemispheres? | {
"A": "2812",
"B": "8231",
"C": "2734",
"D": "4222",
"E": "2749"
} | divide(10996, 4) | divide(n0,n1)| | "a volume of 4 l can be kept in 1 hemisphere therefore , a volume of 10996 l can be kept in ( 10996 / 4 ) hemispheres ans . 2749 answer : e" | geometry |
math_qa__LARCyAWlbL24DeO5 | Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $200, what were her original savings? Pick one.
A) $ 500 B) $ 600 C) $ 700 D) $ 800 E) $ 900 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">200 / (1/4)</gadget>
<output>800</output>
<result>D</result> | D | 800 | Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $200, what were her original savings? | {
"A": "$ 500",
"B": "$ 600",
"C": "$ 700",
"D": "$ 800",
"E": "$ 900"
} | divide(200, subtract(const_1, divide(3, 4))) | divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1)| | "if linda spent 3 / 4 of her savings on furnitute , the rest 4 / 4 - 3 / 4 = 1 / 4 on a tv but the tv cost her $ 200 . so 1 / 4 of her savings is $ 200 . so her original savings are 4 times $ 200 = $ 800 correct answer d" | general |
math_qa__fxt1JADzhyOCHKTe | A lent Rs. 4000 to B for 2 years and Rs. 2000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is : Choose the correct choice from the following options: A) 14 % B) 15 % C) 12 % D) 13.75 % E) 14.56 % | <gadget id="calculator">4_000 * 2</gadget>
<output>8_000</output>
<gadget id="calculator">2_000 * 4</gadget>
<output>8_000</output>
<gadget id="calculator">8_000 + 8_000</gadget>
<output>16_000</output>
<gadget id="calculator">2_200 / 16_000</gadget>
<output>11/80 = around 0.1375</output>
<gadget id="calculator">(11/80) * 100</gadget>
<output>55/4 = around 13.75</output>
<result>D</result> | D | 13.75 | A lent Rs. 4000 to B for 2 years and Rs. 2000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is : | {
"A": "14 %",
"B": "15 %",
"C": "12 %",
"D": "13.75 %",
"E": "14.56 %"
} | multiply(divide(2200, add(multiply(4000, 2), multiply(2000, 4))), const_100) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)|divide(n4,#2)|multiply(#3,const_100) | explanation : let the rate of interest per annum be r % simple interest for rs . 4000 for 2 years at r % + simple interest for rs . 2000 for 4 years at r % = 2200 ( 4000 × r × 2 ) / 100 + ( 2000 × r × 4 ) / 100 = 2200 80 r + 80 r = 2200 160 r = 2200 16 r = 220 4 r = 55 r = 55 / 4 = 13.75 % answer : option d | gain |
math_qa__TGUyxSiQAYYBonbN | A man can row his boat with the stream at 6 km/h and against the stream in 2 km/h. The man's rate is? Choices
A) 1 kmph B) 2 kmph C) 5 kmph D) 7 kmph E) 8 kmph | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>B</result> | B | 2 | A man can row his boat with the stream at 6 km/h and against the stream in 2 km/h. The man's rate is? | {
"A": "1 kmph",
"B": "2 kmph",
"C": "5 kmph",
"D": "7 kmph",
"E": "8 kmph"
} | divide(subtract(6, 2), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "ds = 6 us = 2 s = ? s = ( 6 - 2 ) / 2 = 2 kmph answer : b" | gain |
math_qa__sr73qMxp1ahce8pr | If the L.C.M of two numbers is 600 and their product is 18000, find the H.C.F of the numbers. Choose the most appropriate option.
A) 50
B) 30
C) 125
D) 25
E) none of these | <gadget id="calculator">18_000 / 600</gadget>
<output>30</output>
<result>B</result> | B | 30 | If the L.C.M of two numbers is 600 and their product is 18000, find the H.C.F of the numbers. | {
"A": "50",
"B": "30",
"C": "125",
"D": "25",
"E": "none of these"
} | divide(18000, 600) | divide(n1,n0)| | "h . c . f = ( product of the numbers ) / ( their l . c . m ) = 18000 / 600 = 30 . answer : b" | physics |
math_qa__atHct3KFdjznSS7K | Working at a constant rate, P can finish a job in 3 hours. Q, also working at a constant rate, can finish the same job in 18 hours. If they work together for 2 hours, how many more minutes will it take P to finish the job, working alone at his constant rate? Options.
A) 32 B) 36 C) 40 D) 44 E) 48 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/3) + (1/18)</gadget>
<output>7/18 = around 0.388889</output>
<gadget id="calculator">(7/18) * 2</gadget>
<output>7/9 = around 0.777778</output>
<gadget id="calculator">1 - (7/9)</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(2/9) / (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 60</gadget>
<output>40</output>
<result>C</result> | C | 40 | Working at a constant rate, P can finish a job in 3 hours. Q, also working at a constant rate, can finish the same job in 18 hours. If they work together for 2 hours, how many more minutes will it take P to finish the job, working alone at his constant rate? | {
"A": "32",
"B": "36",
"C": "40",
"D": "44",
"E": "48"
} | multiply(divide(subtract(const_1, multiply(add(inverse(3), inverse(18)), 2)), inverse(3)), const_60) | inverse(n0)|inverse(n1)|add(#0,#1)|multiply(#2,n2)|subtract(const_1,#3)|divide(#4,#0)|multiply(#5,const_60)| | "each hour they complete 1 / 3 + 1 / 18 = 7 / 18 of the job . in 2 hours , they complete 2 ( 7 / 18 ) = 7 / 9 of the job . the time for p to finish is ( 2 / 9 ) / ( 1 / 3 ) = ( 2 / 3 ) hour = 40 minutes the answer is c ." | physics |
math_qa__IdvqjPlk7TZGqmqU | At a restaurant, glasses are stored in two different-sized boxes. One box contains 12 glasses, and the other contains 16 glasses. If the average number of glasses per box is 15, and there are 16 more of the larger boxes, what is the total number of glasses Q at the restaurant? (Assume that all boxes are filled to capacity.) Pick:
A) 96 B) 240 C) q = 256 D) q = 384 E) q = 480 | <gadget id="calculator">16 * 2</gadget>
<output>32</output>
<gadget id="calculator">32 * 15</gadget>
<output>480</output>
<result>E</result> | E | 480 | At a restaurant, glasses are stored in two different-sized boxes. One box contains 12 glasses, and the other contains 16 glasses. If the average number of glasses per box is 15, and there are 16 more of the larger boxes, what is the total number of glasses Q at the restaurant? (Assume that all boxes are filled to capacity.) | {
"A": "96",
"B": "240",
"C": "q = 256",
"D": "q = 384",
"E": "q = 480"
} | multiply(multiply(16, const_2), 15) | multiply(n1,const_2)|multiply(n2,#0)| | "most test takers would recognize the system of equations in this prompt and just do algebra to get to the solution ( and that ' s fine ) . the wording of the prompt and the ' spread ' of the answer choices actually provide an interesting ' brute force ' shortcut that you can take advantage of to eliminate the 4 wrong answers . . . . we ' re told that there are 2 types of boxes : those that hold 12 glasses and those that hold 16 glasses . since the average number of boxes is 15 , we know that there must be at least some of each . we ' re also told that that there are 16 more of the larger boxes . this means , at the minimum , we have . . . 1 small box and 17 large boxes = 1 ( 12 ) + 17 ( 16 ) = 12 + 272 = 284 glasses at the minimum since the question asks for the total number of glasses , we can now eliminate answers a , b and c . . . . the difference in the number of boxes must be 16 though , so we could have . . . . 2 small boxes and 18 large boxes 3 small boxes and 19 large boxes etc . with every additional small box + large box that we add , we add 12 + 16 = 28 more glasses . thus , we can justadd 28 suntil we hit the correct answer . . . . 284 + 28 = 312 312 + 28 = 340 340 + 28 = 368 368 + 28 = 396 at this point , we ' ve ' gone past ' answer d , so the correct answer must be answer e . . . . . but here ' s the proof . . . . 396 + 28 = 424 424 + 28 = 452 452 + 28 = 480 final answer : e" | general |
math_qa__yUWXGtTOWKj62kJt | Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 10 meters and a circumference of 7 meters, and the interior of tank B has a height of 7 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B? Choose one:
A) 70 %
B) 80 %
C) 100 %
D) 120 %
E) 125 % | <gadget id="calculator">7 / 10</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) ** 2</gadget>
<output>49/100 = around 0.49</output>
<gadget id="calculator">10 / 7</gadget>
<output>10/7 = around 1.428571</output>
<gadget id="calculator">(49/100) * (10/7)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 100</gadget>
<output>70</output>
<result>A</result> | A | 70 | Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 10 meters and a circumference of 7 meters, and the interior of tank B has a height of 7 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B? | {
"A": "70 %",
"B": "80 %",
"C": "100 %",
"D": "120 %",
"E": "125 %"
} | multiply(multiply(power(divide(7, 10), const_2), divide(10, 7)), const_100) | divide(n0,n2)|divide(n1,n3)|power(#1,const_2)|multiply(#0,#2)|multiply(#3,const_100)| | "the radius of tank a is 7 / ( 2 * pi ) . the capacity of tank a is 10 * pi * 49 / ( 4 * pi ^ 2 ) = 245 / ( 2 * pi ) the radius of tank b is 10 / ( 2 * pi ) . the capacity of tank b is 7 * pi * 100 / ( 4 * pi ^ 2 ) = 350 / ( 2 * pi ) tank a / tank b = 245 / 350 = 7 / 10 = 70 % the answer is a ." | physics |
math_qa__EDk2sqcMvE98P25X | Car A runs at the speed of 50 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B? Choose the correct choice: A) 3 : 7 B) 4 : 9 C) 10 : 7 D) 5 : 7 E) 6 : 11 | <gadget id="calculator">50 * 8</gadget>
<output>400</output>
<gadget id="calculator">70 * 4</gadget>
<output>280</output>
<gadget id="calculator">400 / 280</gadget>
<output>10/7 = around 1.428571</output>
<result>C</result> | C | 1.428571 | Car A runs at the speed of 50 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B? | {
"A": "3 : 7",
"B": "4 : 9",
"C": "10 : 7",
"D": "5 : 7",
"E": "6 : 11"
} | divide(multiply(50, 8), multiply(70, 4)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "car a travels 50 × 8 = 400 km car b travels 70 × 4 = 280 km the ratio is 400 : 280 = 40 : 28 = 10 : 7 the answer is c ." | physics |
math_qa__NHn46EKCdTLwsQJH | A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12700 after a year? Pick one: A) 3630 B) 9232 C) 8828 D) 2387 E) 3810 | <gadget id="calculator">6_300 + 4_200</gadget>
<output>10_500</output>
<gadget id="calculator">10_500 + 10_500</gadget>
<output>21_000</output>
<gadget id="calculator">6_300 / 21_000</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 12_700</gadget>
<output>3_810</output>
<result>E</result> | E | 3,810 | A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12700 after a year? | {
"A": "3630",
"B": "9232",
"C": "8828",
"D": "2387",
"E": "3810"
} | multiply(divide(6300, add(add(6300, 4200), 10500)), 12700) | add(n0,n1)|add(n2,#0)|divide(n0,#1)|multiply(n3,#2)| | "6300 : 4200 : 10500 3 : 2 : 5 3 / 10 * 12700 = 3810 answer : e" | gain |
math_qa__ZTfMzVUaVU9nUOMv | John's Bank's saving amount is decreased 12% due to loan payment and current balance is Rs.44000. Find the actual balance before deduction? Choose the correct option.
A) 8000 B) 50000 C) 9000 D) 9500 E) 10000 | <gadget id="calculator">44_000 * 12</gadget>
<output>528_000</output>
<gadget id="calculator">528_000 / 100</gadget>
<output>5_280</output>
<gadget id="calculator">5_280 + 44_000</gadget>
<output>49_280</output>
<result>B</result> | B | 50,000 | John's Bank's saving amount is decreased 12% due to loan payment and current balance is Rs.44000. Find the actual balance before deduction? | {
"A": "8000",
"B": "50000",
"C": "9000",
"D": "9500",
"E": "10000"
} | add(divide(multiply(44000, 12), const_100), 44000) | multiply(n0,n1)|divide(#0,const_100)|add(n1,#1) | 12 % decreased 88 % balance = 44000 100 % = 44000 / 88 * 100 = 50000 answer : b | gain |
math_qa__PABW257f5CtQLnZX | A 280 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? Pick:
A) 230 B) 288 C) 267 D) 256 E) 220 | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">(500/9) * 9</gadget>
<output>500</output>
<gadget id="calculator">500 - 280</gadget>
<output>220</output>
<result>E</result> | E | 220 | A 280 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? | {
"A": "230",
"B": "288",
"C": "267",
"D": "256",
"E": "220"
} | subtract(multiply(multiply(add(120, 80), const_0_2778), 9), 280) | add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)| | "relative speed = 120 + 80 = 200 km / hr . = 200 * 5 / 18 = 500 / 9 m / sec . let the length of the other train be x m . then , ( x + 280 ) / 9 = 500 / 9 = > x = 220 . answer : e" | physics |
math_qa__9G3NZGDeAs8MhQIr | An escalator moves towards the top level at the rate of 12 ft.sec and its length is 150 feet. If a person walks on the moving escalator at the rate of 3 feet per second towards the top level, how much time does he take to cover the entire length. Choose the correct choice from the following answers:
A) 10 sec
B) 20 sec
C) 15 sec
D) 16 sec
E) 14 sec | <gadget id="calculator">12 + 3</gadget>
<output>15</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<result>A</result> | A | 10 | An escalator moves towards the top level at the rate of 12 ft.sec and its length is 150 feet. If a person walks on the moving escalator at the rate of 3 feet per second towards the top level, how much time does he take to cover the entire length. | {
"A": "10 sec",
"B": "20 sec",
"C": "15 sec",
"D": "16 sec",
"E": "14 sec"
} | divide(150, add(12, 3)) | add(n0,n2)|divide(n1,#0)| | "explanation : time taken to cover the entire length = tot . dist / resultant speed = 150 / ( 12 + 3 ) = 10 sec answer : a" | gain |
math_qa__ZWNHgnsLuv7jIfbE | The area of rectangular field of length 90 meters and breadth 80 meters is equal to the area of a square plot. What will be the length of the diagonal of the square plot? Choose the correct choice from the following: A) 100 m B) 120 m C) 95 m D) 80 m E) 150 m | <gadget id="calculator">90 * 80</gadget>
<output>7_200</output>
<gadget id="calculator">7_200 ** (1/2)</gadget>
<output>60*sqrt(2) = around 84.852814</output>
<gadget id="calculator">((60*sqrt(2)) ** 2 + (60*sqrt(2)) ** 2) ** (1/2)</gadget>
<output>120</output>
<result>B</result> | B | 120 | The area of rectangular field of length 90 meters and breadth 80 meters is equal to the area of a square plot. What will be the length of the diagonal of the square plot? | {
"A": "100 m",
"B": "120 m",
"C": "95 m",
"D": "80 m",
"E": "150 m"
} | diagonal(square_edge_by_area(rectangle_area(90, 80)), square_edge_by_area(rectangle_area(90, 80))) | rectangle_area(n0,n1)|square_edge_by_area(#0)|diagonal(#1,#1) | given that the length of the rectangular field l = 90 m and breadth = b = 80 m . then its area lb = 90 x 80 sq . m we know that the area of square = ( 1 / 2 ) x ( diagonal ) 2 from the given question , we have area of square plot = area of rectangular field that is , 90 x 80 = 1 / 2 x diagonal 2 diagonal ^ 2 = 2 x 7200 = 14400 = ( 120 ) 2 diagonal = 120 m . hence b | geometry |
math_qa__8Rvah7bVvexhGisE | In a 100 m sprint race Kelly was given a 3 m head start by Abel. If Abel lost the race to Kelly by a distance of 0.50 m, how many meters more would Abel need to overtake Kelly? Choose the correct choice from the following options:
A) 20.5 B) 18.4 C) 17.5 D) 19.9 E) 21.5 | <gadget id="calculator">100 - 0.5</gadget>
<output>99.5</output>
<gadget id="calculator">100 - 3</gadget>
<output>97</output>
<gadget id="calculator">99.5 - 97</gadget>
<output>2.5</output>
<gadget id="calculator">99.5 / 2.5</gadget>
<output>39.8</output>
<gadget id="calculator">39.8 * 0.5</gadget>
<output>19.9</output>
<result>D</result> | D | 19.9 | In a 100 m sprint race Kelly was given a 3 m head start by Abel. If Abel lost the race to Kelly by a distance of 0.50 m, how many meters more would Abel need to overtake Kelly? | {
"A": "20.5",
"B": "18.4",
"C": "17.5",
"D": "19.9",
"E": "21.5"
} | multiply(divide(subtract(100, 0.5), subtract(subtract(100, 0.5), subtract(100, 3))), 0.5) | subtract(n0,n2)|subtract(n0,n1)|subtract(#0,#1)|divide(#0,#2)|multiply(n2,#3) | distance abel ran before completion of race - - - 100 m - 0.50 m = 99.5 m distance gained on kelly over 99.5 m - - - 3 m - 0.50 m = 2.50 m then abel gains 99.5 m / 2.50 m = 1 m on kelly every 39.8 meters . therefore 39.8 divided by half a meter ( i . e the 0.50 m abel was defeated with ) answer : d . 19.9 m | physics |
math_qa__qGJoreaVpKC8fXJd | The volume of a wall, 5 times as high as it is broad and 8 times as long as it is high, is 12.8 cu. meters. Find the breadth of the wall. Choose the correct choice from the following answers: A) 40 B) 29 C) 28 D) 27 E) 12 | <gadget id="calculator">5 * 8</gadget>
<output>40</output>
<gadget id="calculator">40 * 5</gadget>
<output>200</output>
<gadget id="calculator">12.8 / 200</gadget>
<output>0.064</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">0.064 / (2/5)</gadget>
<output>0.16</output>
<gadget id="calculator">0.16 / (2/5)</gadget>
<output>0.4</output>
<gadget id="calculator">0.4 * 100</gadget>
<output>40</output>
<result>A</result> | A | 40 | The volume of a wall, 5 times as high as it is broad and 8 times as long as it is high, is 12.8 cu. meters. Find the breadth of the wall. | {
"A": "40",
"B": "29",
"C": "28",
"D": "27",
"E": "12"
} | multiply(divide(divide(divide(12.8, multiply(multiply(5, 8), 5)), divide(const_4, const_10)), divide(const_4, const_10)), const_100) | divide(const_4,const_10)|multiply(n0,n1)|multiply(n0,#1)|divide(n2,#2)|divide(#3,#0)|divide(#4,#0)|multiply(#5,const_100) | explanation : let the breadth of the wall be x metres . then , height = 5 x metres and length = 40 x metres . x * 5 x * 40 x = 12.8 = > \ inline \ fn _ jvn x ^ 3 = \ frac { 12.8 } { 200 } = \ frac { 128 } { 2000 } = \ frac { 64 } { 1000 } = > \ inline \ fn _ jvn x = \ frac { 4 } { 10 } m = > \ inline \ fn _ jvn x = \ frac { 4 } { 10 } \ times 100 = 40 cm answer : a ) 40 cm | physics |
math_qa__N0XLERUN2iDQdGWZ | A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68% of the distribution lies one standard deviation h of the mean, what percent of the distribution is less than m+h?
Choose the correct choice.
A) 16 % B) 32 % C) 48 % D) 84 % E) 92 % | <gadget id="calculator">100 - 68</gadget>
<output>32</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<gadget id="calculator">100 - 16</gadget>
<output>84</output>
<result>D</result> | D | 84 | A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68% of the distribution lies one standard deviation h of the mean, what percent of the distribution is less than m+h? | {
"A": "16 %",
"B": "32 %",
"C": "48 %",
"D": "84 %",
"E": "92 %"
} | subtract(const_100, divide(subtract(const_100, 68), const_2)) | subtract(const_100,n0)|divide(#0,const_2)|subtract(const_100,#1)| | "16 % ________________________________________________ m + h 34 % ________________________________________________ m 34 % ________________________________________________ m - h 16 % since 68 % lies one standard deviation from mean m , = > 50 % of 68 % lies on either side as it is symmetric about m . thus 16 % lie below m - h and 16 % lie above m + h now below m + h = 16 + 34 + 34 = 84 % hence d" | general |
math_qa__yV1KizvBVhsrDN8W | What is the 4 digit number whose second digit is thrice the first digit and 3rd digit is sum of 1st and 2nd and last digit is thrice the second digit. Choose the correct answer.
A) 2674 B) 1349 C) 3343 D) 3678 E) 3679 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1 * 3</gadget>
<output>3</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">1_000 + 300</gadget>
<output>1_300</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">1_300 + 40</gadget>
<output>1_340</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">1_340 + 9</gadget>
<output>1_349</output>
<result>B</result> | B | 1,349 | What is the 4 digit number whose second digit is thrice the first digit and 3rd digit is sum of 1st and 2nd and last digit is thrice the second digit. | {
"A": "2674",
"B": "1349",
"C": "3343",
"D": "3678",
"E": "3679"
} | add(add(add(multiply(const_100, const_10), multiply(multiply(1, const_3), const_100)), multiply(add(multiply(1, const_3), 1), const_10)), multiply(const_3, multiply(1, const_3))) | multiply(const_10,const_100)|multiply(n2,const_3)|add(n2,#1)|multiply(#1,const_100)|multiply(#1,const_3)|add(#0,#3)|multiply(#2,const_10)|add(#5,#6)|add(#7,#4) | let four digits is a , b , c & d . . . so by given b is 3 a c is 4 a d is 9 a so ans is 1349 answer : b | general |
math_qa__uVevsKbVWZnvmKvJ | Rs.525 among A, B and C such that B may get 2/3 of A and C together get. Find the share of C? Choose the correct option:
A) 127 B) 150 C) 177 D) 167 E) 122 | <gadget id="calculator">525 / 3</gadget>
<output>175</output>
<gadget id="calculator">175 - 100</gadget>
<output>75</output>
<gadget id="calculator">75 * 2</gadget>
<output>150</output>
<result>B</result> | B | 150 | Rs.525 among A, B and C such that B may get 2/3 of A and C together get. Find the share of C? | {
"A": "127",
"B": "150",
"C": "177",
"D": "167",
"E": "122"
} | multiply(subtract(divide(525, 3), const_100), 2) | divide(n0,n2)|subtract(#0,const_100)|multiply(n1,#1) | a + b + c = 590 5 a = 6 b = 8 c = x a : b : c = 1 / 5 : 1 / 6 : 1 / 8 = 24 : 20 : 15 15 / 59 * 590 = rs . 150 answer : b | general |
math_qa__R8GCVM1f8CfD7Uyg | the difference in compound interest earned on a deposit ( compounded annually ) in year 1 and year 2 is $ 40 . had the interest rate been 3 times its present value , the difference c would have been how much ? Answers:
A) 40 / 3 B) 40 C) 120 D) 360 E) 420 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 40</gadget>
<output>360</output>
<result>D</result> | D | 360 | the difference in compound interest earned on a deposit ( compounded annually ) in year 1 and year 2 is $ 40 . had the interest rate been 3 times its present value , the difference c would have been how much ? | {
"A": "40 / 3",
"B": "40",
"C": "120",
"D": "360",
"E": "420"
} | multiply(multiply(3, 3), 40) | multiply(n3,n3)|multiply(n2,#0) | case 1 : deposit = $ x ; rate of increase = r . interest yearned in 1 year = xr . deposit in 1 year = x + xr . interest yearned in 2 year = ( x + xr ) r . the difference c = ( x + xr ) r - xr = xr ^ 2 = 40 . case 2 : deposit = $ x ; rate of increase = 3 r . interest yearned in 1 year = x ( 3 r ) . deposit in 1 year = x + 3 xr . interest yearned in 2 year = ( x + 3 xr ) 3 r . the difference = ( x + 3 xr ) 3 r - 3 xr = 9 xr ^ 2 . since from case 1 we know that xr ^ 2 = 40 , then 9 xr ^ 2 = 9 * 40 = 360 . answer : d . | general |
math_qa__E8VKZUYzTr2VPgq5 | The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers? Pick
A) 9 , 10
B) 10 , 11
C) 11 , 12
D) 12 , 13
E) none of these | <gadget id="calculator">91 - 1</gadget>
<output>90</output>
<gadget id="calculator">90 * 4</gadget>
<output>360</output>
<gadget id="calculator">360 + 1</gadget>
<output>361</output>
<gadget id="calculator">361 ** (1/2)</gadget>
<output>19</output>
<gadget id="calculator">19 - 1</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<result>A</result> | A | 9 | The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers? | {
"A": "9 , 10",
"B": "10 , 11",
"C": "11 , 12",
"D": "12 , 13",
"E": "none of these"
} | divide(subtract(sqrt(add(multiply(subtract(91, const_1), const_4), const_1)), const_1), const_2) | subtract(n0,const_1)|multiply(#0,const_4)|add(#1,const_1)|sqrt(#2)|subtract(#3,const_1)|divide(#4,const_2) | let the two consecutive positive integers be x and x + 1 x 2 + ( x + 1 ) 2 - x ( x + 1 ) = 91 x 2 + x - 90 = 0 ( x + 10 ) ( x - 9 ) = 0 = > x = - 10 or 9 . as x is positive x = 9 hence the two consecutive positive integers are 9 and 10 . answer : a | general |
math_qa__1XJzFeGLtfEO2F7D | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 48 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake? Select
A) 36 B) 2 ^ 4 * 3 C) 24 D) 38 E) 47 | <gadget id="calculator">48 - 1</gadget>
<output>47</output>
<result>E</result> | E | 47 | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 48 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake? | {
"A": "36",
"B": "2 ^ 4 * 3",
"C": "24",
"D": "38",
"E": "47"
} | subtract(48, const_1) | subtract(n0,const_1) | working backward from the day it ' s covered : day 48 : fully covered day 47 : half covered so 47 days answer : e | physics |
math_qa__4HBEn1deaLOULjF0 | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 35 men in 3 days? Choose the correct choice from the following.
A) 16 mtr . B) 52 mtr C) 70 mtr . D) 78 mtr . E) 98 mtr . | <gadget id="calculator">35 * 3</gadget>
<output>105</output>
<gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">105 / 120</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">112 * (7/8)</gadget>
<output>98</output>
<result>E</result> | E | 98 | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 35 men in 3 days? | {
"A": "16 mtr .",
"B": "52 mtr",
"C": "70 mtr .",
"D": "78 mtr .",
"E": "98 mtr ."
} | multiply(112, divide(multiply(35, 3), multiply(20, 6))) | multiply(n3,n4)|multiply(n0,n2)|divide(#0,#1)|multiply(n1,#2)| | "20 men is 6 days can build 112 metres 35 men in 3 days can build = 112 * ( 35 / 20 ) x ( 3 / 6 ) = 98 meters answer : e ." | physics |
math_qa__e2AHHcy8Qlds6KmN | Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is? Select the correct option
A) 4 days B) 6 days C) 10 days D) 16 days E) 22 days | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">20 / (5/4)</gadget>
<output>16</output>
<result>D</result> | D | 16 | Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is? | {
"A": "4 days",
"B": "6 days",
"C": "10 days",
"D": "16 days",
"E": "22 days"
} | divide(20, add(const_1, divide(25, const_100))) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1) | ratio of times taken by sakshi and tanya = 125 : 100 = 5 : 4 . suppose tanya takes x days to do the work . 5 : 4 : : 20 : x x = 4 x 20 / 5 x = 16 days . hence , tanya takes 16 days to complete the work . answer : d | physics |
math_qa__XIc2BR2mNrBIKibv | If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/6, then what is the value of abc/def ? Select:
A) 27 / 4 B) 27 / 8 C) 3 / 4 D) 3 / 8 E) 1 / 4 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">2 * 18</gadget>
<output>36</output>
<gadget id="calculator">9 / 36</gadget>
<output>1/4 = around 0.25</output>
<result>E</result> | E | 0.25 | If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/6, then what is the value of abc/def ? | {
"A": "27 / 4",
"B": "27 / 8",
"C": "3 / 4",
"D": "3 / 8",
"E": "1 / 4"
} | divide(multiply(3, 3), multiply(2, multiply(3, 6))) | multiply(n1,n1)|multiply(n1,n7)|multiply(n2,#1)|divide(#0,#2)| | "say a = 2 . then : a / b = 1 / 3 - - > b = 6 ; b / c = 2 - - > c = 3 ; c / d = 1 / 2 - - > d = 6 ; d / e = 3 - - > e = 2 ; e / f = 1 / 6 - - > f = 12 . abc / def = ( 2 * 6 * 3 ) / ( 6 * 2 * 12 ) = 1 / 4 . answer : e ." | general |
math_qa__M13VXoSbz1aHE3h3 | A and B invests Rs.4000 and Rs.4000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit? Choose the correct answer
A) 3 : 5 B) 3 : 8 C) 3 : 2 D) 9 : 9 E) 3 : 1 | <gadget id="calculator">4_000 * 6</gadget>
<output>24_000</output>
<gadget id="calculator">4_000 * 2</gadget>
<output>8_000</output>
<gadget id="calculator">8_000 * 6</gadget>
<output>48_000</output>
<gadget id="calculator">24_000 + 48_000</gadget>
<output>72_000</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">4_000 * 12</gadget>
<output>48_000</output>
<gadget id="calculator">72_000 / 48_000</gadget>
<output>3/2 = around 1.5</output>
<result>C</result> | C | 1.5 | A and B invests Rs.4000 and Rs.4000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit? | {
"A": "3 : 5",
"B": "3 : 8",
"C": "3 : 2",
"D": "9 : 9",
"E": "3 : 1"
} | divide(add(multiply(4000, 6), multiply(multiply(4000, const_2), 6)), multiply(4000, add(6, 6))) | add(n2,n2)|multiply(n0,n2)|multiply(n0,const_2)|multiply(n2,#2)|multiply(n1,#0)|add(#1,#3)|divide(#5,#4)| | "( 4 * 6 + 8 * 6 ) : ( 4 * 12 ) 72 : 48 = > 3 : 2 answer : c" | gain |
math_qa__q94c6VazmwR4yLGO | In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 200 more than the correct answer. Find the number. Answers
A) 384
B) 76
C) 26
D) 28
E) 11 | <gadget id="calculator">200 * 16</gadget>
<output>3_200</output>
<gadget id="calculator">3_200 * 6</gadget>
<output>19_200</output>
<gadget id="calculator">5 * 16</gadget>
<output>80</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">80 - 30</gadget>
<output>50</output>
<gadget id="calculator">19_200 / 50</gadget>
<output>384</output>
<result>A</result> | A | 384 | In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 200 more than the correct answer. Find the number. | {
"A": "384",
"B": "76",
"C": "26",
"D": "28",
"E": "11"
} | divide(multiply(multiply(200, 16), 6), subtract(multiply(5, 16), multiply(5, 6))) | multiply(n1,n4)|multiply(n0,n1)|multiply(n0,n3)|multiply(n3,#0)|subtract(#1,#2)|divide(#3,#4)| | "explanation : let the number be x . 5 * x / 6 = 5 * x / 16 + 200 25 * x / 48 = 200 x = 384 answer : a" | general |
math_qa__wWIldmgaUUJRJLFc | How many seconds does Sandy take to cover a distance of 500 meters, if Sandy runs at a speed of 18 km/hr? Choose the most appropriate option:
A) 80 B) 100 C) 120 D) 140 E) 160 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">18 * (5/18)</gadget>
<output>5</output>
<gadget id="calculator">500 / 5</gadget>
<output>100</output>
<result>B</result> | B | 100 | How many seconds does Sandy take to cover a distance of 500 meters, if Sandy runs at a speed of 18 km/hr? | {
"A": "80",
"B": "100",
"C": "120",
"D": "140",
"E": "160"
} | divide(500, multiply(18, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "18 km / hr = 18000 m / 3600 s = 5 m / s time = 500 / 5 = 100 seconds the answer is b ." | physics |
math_qa__I7yj6KoYH3SxP736 | A frog can climb up a well at 3 ft per min but due to slipperiness of the well, frog slips down 2 ft before it starts climbing the next minute. If the depth of the well is 57 ft, how much time will the frog take to reach the top? Choose the correct choice from the following:
A) 29 B) 27 C) 55 D) 17 E) 10 | <gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">57 / 1</gadget>
<output>57</output>
<result>C</result> | C | 55 | A frog can climb up a well at 3 ft per min but due to slipperiness of the well, frog slips down 2 ft before it starts climbing the next minute. If the depth of the well is 57 ft, how much time will the frog take to reach the top? | {
"A": "29",
"B": "27",
"C": "55",
"D": "17",
"E": "10"
} | divide(57, subtract(3, 2)) | subtract(n0,n1)|divide(n2,#0) | explanation : as per given , in 1 min , frog climbs up 3 ft and slips down by 2 ft . so the frog climbs only 1 ft in 1 min so after 54 mins , it would have climbed 54 ft . at the end of 55 mins it climbs up 3 ft to make it 57 ft and come out of the well . once it had reached the destination , it will not slip . so the frog will take only 55 minutes to climb up the well . answer : c | general |
math_qa__YEUpNNGv8juEywLU | If 50% of x is 20 less than 5% of 500, then x is? Choose the correct choice from the following answers.
A) 50
B) 100
C) 75
D) 25
E) 10 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">500 * (1/20)</gadget>
<output>25</output>
<gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">5 / (1/2)</gadget>
<output>10</output>
<result>E</result> | E | 10 | If 50% of x is 20 less than 5% of 500, then x is? | {
"A": "50",
"B": "100",
"C": "75",
"D": "25",
"E": "10"
} | divide(subtract(multiply(500, divide(5, const_100)), 20), divide(50, const_100)) | divide(n2,const_100)|divide(n0,const_100)|multiply(n3,#0)|subtract(#2,n1)|divide(#3,#1) | 50 % of x = x / 2 ; 5 % of 500 = 5 / 100 * 500 = 25 given that , x / 2 = 25 - 20 = > x / 2 = 5 = > x = 10 . answer : e | general |
math_qa__sovLZXuCeiV9eHAA | A rectangular room 14 m long, 12 m broad is surrounded by a varandah, 3 m wide. Find the area of the varandah? Choose the correct choice from the following answers: A) 170 B) 180 C) 190 D) 210 E) 150 | <gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">2 * (3/10)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">14 + (3/5)</gadget>
<output>73/5 = around 14.6</output>
<gadget id="calculator">12 + (3/5)</gadget>
<output>63/5 = around 12.6</output>
<gadget id="calculator">(73/5) * (63/5)</gadget>
<output>4_599/25 = around 183.96</output>
<result>B</result> | B | 180 | A rectangular room 14 m long, 12 m broad is surrounded by a varandah, 3 m wide. Find the area of the varandah? | {
"A": "170",
"B": "180",
"C": "190",
"D": "210",
"E": "150"
} | multiply(add(14, multiply(const_2, divide(3, const_10))), add(12, multiply(const_2, divide(3, const_10)))) | divide(n2,const_10)|multiply(#0,const_2)|add(n0,#1)|add(n1,#1)|multiply(#2,#3) | area of varandah = ( l + b + 2 p ) 2 p = ( 14 + 12 + 6 ) 6 = 180 m ( power ) 2 answer is b . | geometry |
math_qa__XmvhfxTs946qEaYe | Calculate the largest 4 digit number which is exactly divisible by 98? Options.
A) 9800 B) 9898 C) 9702 D) 9604 E) 9996 | <gadget id="calculator">100 + 2</gadget>
<output>102</output>
<gadget id="calculator">102 * 98</gadget>
<output>9_996</output>
<result>E</result> | E | 9,996 | Calculate the largest 4 digit number which is exactly divisible by 98? | {
"A": "9800",
"B": "9898",
"C": "9702",
"D": "9604",
"E": "9996"
} | multiply(add(const_100, const_2), 98) | add(const_100,const_2)|multiply(n1,#0) | largest 4 digit number is 9999 after doing 9999 ÷ 98 we get remainder 3 hence largest 4 digit number exactly divisible by 98 = 9999 - 3 = 9996 e | general |
math_qa__muCo6xR96b39ghlz | 20 6 years ago , a father was 3 times as old as his son . now the father is only twice as old as his son . then the sum of the present ages of the son and the father is : Choose the correct choice from the following answers: A) 120 B) 156 C) 108 D) 105 E) 86 | <gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">120 + 36</gadget>
<output>156</output>
<result>B</result> | B | 156 | 20 6 years ago , a father was 3 times as old as his son . now the father is only twice as old as his son . then the sum of the present ages of the son and the father is : | {
"A": "120",
"B": "156",
"C": "108",
"D": "105",
"E": "86"
} | add(multiply(20, 6), multiply(multiply(6, 3), const_2)) | multiply(n0,n1)|multiply(n1,n2)|multiply(#1,const_2)|add(#0,#2) | let the present ages of the father and son be 2 x and x years respectively . then , ( 2 x - 26 ) = 3 ( x - 26 ) x = 52 . required sum = ( 2 x + x ) = 3 x = 156 years . answer is b | general |
math_qa__8Ds324hEHmamhKiD | The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum? Choose the correct answer:
A) rs . 17029 B) rs . 17028 C) rs . 17000 D) rs . 17008 E) rs . 17067 | <gadget id="calculator">100 * 10_200</gadget>
<output>1_020_000</output>
<gadget id="calculator">11_730 - 10_200</gadget>
<output>1_530</output>
<gadget id="calculator">1_530 * 100</gadget>
<output>153_000</output>
<gadget id="calculator">10_200 / 2</gadget>
<output>5_100</output>
<gadget id="calculator">153_000 / 5_100</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">1_020_000 / 60</gadget>
<output>17_000</output>
<result>C</result> | C | 17,000 | The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum? | {
"A": "rs . 17029",
"B": "rs . 17028",
"C": "rs . 17000",
"D": "rs . 17008",
"E": "rs . 17067"
} | divide(multiply(const_100, 10200), multiply(divide(multiply(subtract(11730, 10200), const_100), divide(10200, const_2)), const_2)) | divide(n1,const_2)|multiply(n1,const_100)|subtract(n0,n1)|multiply(#2,const_100)|divide(#3,#0)|multiply(#4,const_2)|divide(#1,#5)| | "the simple interest for the first year is 10200 / 2 is rs . 5100 and compound interest for first year also is rs . 5100 . the compound interest for second year on rs . 5100 for one year so rate of the interest = ( 100 * 1530 ) / ( 5100 * 1 ) = 30 % p . a . so p = ( 100 * 10200 ) / ( 30 * 2 ) = rs . 17000 answer : c" | gain |
math_qa__VhqQb4Qcag69X2Hr | x varies inversely as square of y. Given that y=3 for x=1. The value of x for y = 6 will be equal to: Choose one
A) 3 B) 6 C) 1 / 4 D) 1 / 3 E) 9 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">1 * 9</gadget>
<output>9</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">9 / 36</gadget>
<output>1/4 = around 0.25</output>
<result>C</result> | C | 0.25 | x varies inversely as square of y. Given that y=3 for x=1. The value of x for y = 6 will be equal to: | {
"A": "3",
"B": "6",
"C": "1 / 4",
"D": "1 / 3",
"E": "9"
} | divide(multiply(1, power(3, const_2)), power(6, const_2)) | power(n0,const_2)|power(n2,const_2)|multiply(n1,#0)|divide(#2,#1)| | "explanation : solution : given x = k / y ^ 2 , where k is constant . now , y = 3 and x = 1 gives k = 9 . . ' . x = 9 / y ^ 2 = > x = 9 / 6 ^ 2 = 1 / 4 answer : c" | general |
math_qa__HAs9GUSEjcJOFrrD | Each child has 3 crayons and 12 apples. If there are 6 children, how many crayons are there in total? Choose the correct option
A) 22
B) 65
C) 18
D) 36
E) 10 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<result>C</result> | C | 18 | Each child has 3 crayons and 12 apples. If there are 6 children, how many crayons are there in total? | {
"A": "22",
"B": "65",
"C": "18",
"D": "36",
"E": "10"
} | multiply(6, 3) | multiply(n0,n2)| | 3 * 6 = 18 . answer is c . | general |
math_qa__1oUhLxk1dKjoZjw0 | A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man? Choose the correct answer.
A) 5.79 B) 5.77 C) 5.76 D) 5.72 E) 5.71 | <gadget id="calculator">6 + 1.2</gadget>
<output>7.2</output>
<gadget id="calculator">6 - 1.2</gadget>
<output>4.8</output>
<gadget id="calculator">7.2 * 4.8</gadget>
<output>34.56</output>
<gadget id="calculator">7.2 + 4.8</gadget>
<output>12</output>
<gadget id="calculator">34.56 / 12</gadget>
<output>2.88</output>
<gadget id="calculator">2.88 * 2</gadget>
<output>5.76</output>
<result>C</result> | C | 5.76 | A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man? | {
"A": "5.79",
"B": "5.77",
"C": "5.76",
"D": "5.72",
"E": "5.71"
} | multiply(divide(multiply(add(6, 1.2), subtract(6, 1.2)), add(add(6, 1.2), subtract(6, 1.2))), const_2) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|multiply(#0,#1)|divide(#3,#2)|multiply(#4,const_2)| | "m = 6 s = 1.2 ds = 7.2 us = 4.8 x / 7.2 + x / 4.8 = 1 x = 2.88 d = 2.88 * 2 = 5.76 . answer : c" | physics |
math_qa__fXSShItqwgbOKJMD | show timer statistics to apply for the position of photographer at a local magazine , veronica needs to include 3 or 4 of her pictures in an envelope accompanying her application . if she has pre - selected 5 photos representative of her work , how many choices does she have to provide the photos for the magazine ? Pick one
A) 5
B) 10
C) 12
D) 15
E) 50 | <gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">120 / 12</gadget>
<output>10</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(1)</gadget>
<output>1</output>
<gadget id="calculator">24 * 1</gadget>
<output>24</output>
<gadget id="calculator">120 / 24</gadget>
<output>5</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<result>D</result> | D | 15 | show timer statistics to apply for the position of photographer at a local magazine , veronica needs to include 3 or 4 of her pictures in an envelope accompanying her application . if she has pre - selected 5 photos representative of her work , how many choices does she have to provide the photos for the magazine ? | {
"A": "5",
"B": "10",
"C": "12",
"D": "15",
"E": "50"
} | add(divide(factorial(5), multiply(factorial(3), factorial(subtract(5, 3)))), divide(factorial(5), multiply(factorial(4), factorial(const_1)))) | factorial(n2)|factorial(n0)|factorial(n1)|factorial(const_1)|subtract(n2,n0)|factorial(#4)|multiply(#2,#3)|divide(#0,#6)|multiply(#1,#5)|divide(#0,#8)|add(#9,#7) | veronica can choose 3 photos in 5 c 3 = 10 ways she can choose 4 photos in 5 c 4 = 5 ways total number of ways = 10 + 5 = 15 answer : d | physics |
math_qa__PKkBLtMP63Ouenbo | A consignment of 20 picture tubes contains 5 defectives. Two tubes are selected one after the other at random. The probability that both are defective assuming that the first tube is not replaced before drawing
the second, would be: Choose the correct choice from the following
A) 1 / 16 B) 1 / 19 C) 1 / 4 D) 1 / 3 E) none of these | <gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">binomial(20, 2)</gadget>
<output>190</output>
<gadget id="calculator">10 / 190</gadget>
<output>1/19 = around 0.052632</output>
<result>B</result> | B | 0.052632 | A consignment of 20 picture tubes contains 5 defectives. Two tubes are selected one after the other at random. The probability that both are defective assuming that the first tube is not replaced before drawing
the second, would be: | {
"A": "1 / 16",
"B": "1 / 19",
"C": "1 / 4",
"D": "1 / 3",
"E": "none of these"
} | divide(choose(const_5, const_2), choose(20, const_2)) | choose(const_5,const_2)|choose(n0,const_2)|divide(#0,#1) | probability of drawing a defective tube in first draw is 5 / 20 probability of drawing a defective tube in second draw ( without replacing first tube ) is 4 / 19 . therefore probability of getting both defective is = ( 5 / 20 ) * ( 4 / 19 ) = 1 / 19 answer : b | other |
math_qa__ZIf4HOb49LIY5Y3r | A sum of $500 amounts to 600 in 2 years at simple interest. If the interest rate is increased by 10% it would amount to how much ? Choices:
A) $ 500 B) $ 700 C) $ 800 D) $ 600 E) $ 300 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">500 * (1/5)</gadget>
<output>100</output>
<gadget id="calculator">600 + 100</gadget>
<output>700</output>
<result>B</result> | B | 700 | A sum of $500 amounts to 600 in 2 years at simple interest. If the interest rate is increased by 10% it would amount to how much ? | {
"A": "$ 500",
"B": "$ 700",
"C": "$ 800",
"D": "$ 600",
"E": "$ 300"
} | add(600, multiply(500, divide(multiply(2, 10), const_100))) | multiply(n2,n3)|divide(#0,const_100)|multiply(n0,#1)|add(n1,#2) | s . i = 600 - 500 = 100 p = $ 500 t = 2 years r = 100 * 100 / 500 * 2 = 10 % new rate = 10 + 10 = 20 % new s . i . = 500 * 20 * 2 / 100 = $ 200 new amount = 500 + 200 = $ 700 answer is b | gain |
math_qa__EZa12lEZwi65utpj | Find out the square of a number which when doubled exceeds its one fifth by 9 ? Choose the correct choice from the following answers:
A) 16
B) 25
C) 19
D) 26
E) 17 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2 - (1/5)</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">9 / (9/5)</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<result>B</result> | B | 25 | Find out the square of a number which when doubled exceeds its one fifth by 9 ? | {
"A": "16",
"B": "25",
"C": "19",
"D": "26",
"E": "17"
} | power(divide(9, subtract(const_2, divide(const_1, add(const_4, const_1)))), const_2) | add(const_1,const_4)|divide(const_1,#0)|subtract(const_2,#1)|divide(n0,#2)|power(#3,const_2) | a let the number be p , then the square will be p ^ 2 according to question : 2 p = ( p / 5 ) + 9 = > 10 p = p + 45 = > p = 5 p ^ 2 = 5 ^ 2 = 25 . answer : b | general |
math_qa__U0bZ65RvT8nHJRgc | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 18, what is the total amount? Choose the correct choice from the following.
A) 115 B) 116 C) 117 D) 78 E) 119 | <gadget id="calculator">100 / 45</gadget>
<output>20/9 = around 2.222222</output>
<gadget id="calculator">(20/9) * 18</gadget>
<output>40</output>
<gadget id="calculator">50 / 45</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">(10/9) * 18</gadget>
<output>20</output>
<gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">60 + 18</gadget>
<output>78</output>
<result>D</result> | D | 78 | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 18, what is the total amount? | {
"A": "115",
"B": "116",
"C": "117",
"D": "78",
"E": "119"
} | add(add(multiply(divide(const_100, 45), 18), multiply(divide(50, 45), 18)), 18) | divide(const_100,n0)|divide(n1,n0)|multiply(n2,#0)|multiply(n2,#1)|add(#2,#3)|add(n2,#4)| | "x : y : z = 100 : 45 : 50 20 : 9 : 10 9 - - - 18 39 - - - ? = > 78 answer : d" | general |
math_qa__fUBF5ez9r6u35RXF | If 15 Horses eat 15 bags of gram in 15 days, in how many days will one horse eat one bag of Grain? Choose the correct choice from the following answers: A) 15 days B) 1 / 15 days C) 1 day D) 30 days E) 225 days | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / (1/15)</gadget>
<output>15</output>
<result>A</result> | A | 15 | If 15 Horses eat 15 bags of gram in 15 days, in how many days will one horse eat one bag of Grain? | {
"A": "15 days",
"B": "1 / 15 days",
"C": "1 day",
"D": "30 days",
"E": "225 days"
} | inverse(inverse(15)) | inverse(n0)|inverse(#0) | horse * days = bags 15 * 15 = 15 and 1 * days = 1 ( 15 * 15 ) / ( 1 * days ) = 15 / 1 days = 15 answer : a | physics |
math_qa__uR4yHwkhCa6Xbulu | In a certain game, each player scores either 2 points or 5 points. If n players score 2 points and m players score 5 points, and the total number of points scored is 50, what is the least possible positive T difference between n and m?
Choose the correct choice from the following
A) 1 B) 3 C) 5 D) 7 E) 9 | <gadget id="calculator">5 - 2</gadget>
<output>3</output>
<result>B</result> | B | 3 | In a certain game, each player scores either 2 points or 5 points. If n players score 2 points and m players score 5 points, and the total number of points scored is 50, what is the least possible positive T difference between n and m? | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | subtract(5, 2) | subtract(n1,n0)| | "we have equation 2 n + 5 m = 50 we have factor 2 in first number and we have factor 5 in second number . lcm ( 2 , 5 ) = 10 so we can try some numbers and we should start from 5 because it will be less list than for 2 2 * 5 = 10 and n should be equal 20 4 * 5 = 20 and n should be equal 15 6 * 5 = 30 and n should be equal 10 8 * 5 = 40 and n should be equal 5 10 * 5 = 50 and n should be equal 0 third variant give us the mininal difference n - m = 10 - 6 = 4 and there is some mistake in my way of thinking because we do n ' t have such answer ) if we change the task and will seek for difference between m and n than minimal result t will be 8 - 5 = 3 and answer b" | general |
math_qa__XWaof3gdyhVaF7DB | If the average of 201, 202, 204, 205, 206, 209, 209, 210, 212 and x is 207, what is the value of x?
Choose the correct choice:
A) 207 B) 209 C) 211 D) 212 E) 213 | <gadget id="calculator">207 * 10</gadget>
<output>2_070</output>
<gadget id="calculator">201 + 202</gadget>
<output>403</output>
<gadget id="calculator">403 + 204</gadget>
<output>607</output>
<gadget id="calculator">607 + 205</gadget>
<output>812</output>
<gadget id="calculator">812 + 206</gadget>
<output>1_018</output>
<gadget id="calculator">1_018 + 209</gadget>
<output>1_227</output>
<gadget id="calculator">1_227 + 209</gadget>
<output>1_436</output>
<gadget id="calculator">1_436 + 210</gadget>
<output>1_646</output>
<gadget id="calculator">1_646 + 212</gadget>
<output>1_858</output>
<gadget id="calculator">2_070 - 1_858</gadget>
<output>212</output>
<result>D</result> | D | 212 | If the average of 201, 202, 204, 205, 206, 209, 209, 210, 212 and x is 207, what is the value of x? | {
"A": "207",
"B": "209",
"C": "211",
"D": "212",
"E": "213"
} | subtract(multiply(207, const_10), add(add(add(add(add(add(add(add(201, 202), 204), 205), 206), 209), 209), 210), 212)) | add(n0,n1)|multiply(n9,const_10)|add(n2,#0)|add(n3,#2)|add(n4,#3)|add(n5,#4)|add(n5,#5)|add(n7,#6)|add(n8,#7)|subtract(#1,#8) | sum of the deviations of the numbers in the set from the mean is always zero 201 , 202 , 204 , 205 , 206 , 209 , 209 , 210 , 212 mean is 207 so the list is - 6 - 5 - 3 - 2 - 1 + 2 + 2 + 3 + 5 . . . this shud total to zero but this is - 5 , hence we need a number that is 5 more than the mean to get a + 5 and make it zero hence the answer is 207 + 5 = 212 d | general |
math_qa__ssihJ2rdYPtwnXDG | In a group of cows and chickens, the number of legs was 20 more than twice the number of heads. The number of cows was: Options:
A) 5
B) 7
C) 10
D) 12
E) 14 | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>C</result> | C | 10 | In a group of cows and chickens, the number of legs was 20 more than twice the number of heads. The number of cows was: | {
"A": "5",
"B": "7",
"C": "10",
"D": "12",
"E": "14"
} | divide(20, subtract(const_4, const_2)) | subtract(const_4,const_2)|divide(n0,#0)| | "let the number of cows be x and their legs be 4 x . let the number of chicken be y and their legs be 2 x . total number of legs = 4 x + 2 y . total number of heads = x + y . the number of legs was 20 more than twice the number of heads . therefore , 2 × ( x + y ) + 20 = 4 x + 2 y . or , 2 x + 2 y + 20 = 4 x + 2 y . or , 2 x + 20 = 4 x [ subtracting 2 y from both sides ] . or , 20 = 4 x – 2 x [ subtracting 2 x from both sides ] . or , 20 = 2 x . or , x = 10 [ dividing by 2 on both sides ] . therefore , the number of cows = 10 . correct answer : c ) 10" | general |
math_qa__YuLuu4SopcRnB7mY | the average marks in mathematics scored by the pupils of a school at the public examination were 39 . if 4 of these pupils who actually scored 25 , 12 , 15 and 19 marks at the examination had not been sent up , the average marks for the school would have been 44 . find the number of pupils sent up for examination from the school ? Choose the correct choice:
A) 20 B) 21 C) 22 D) 23 E) 24 | <gadget id="calculator">44 * 4</gadget>
<output>176</output>
<gadget id="calculator">25 + 12</gadget>
<output>37</output>
<gadget id="calculator">37 + 15</gadget>
<output>52</output>
<gadget id="calculator">52 + 19</gadget>
<output>71</output>
<gadget id="calculator">176 - 71</gadget>
<output>105</output>
<gadget id="calculator">44 - 39</gadget>
<output>5</output>
<gadget id="calculator">105 / 5</gadget>
<output>21</output>
<result>B</result> | B | 21 | the average marks in mathematics scored by the pupils of a school at the public examination were 39 . if 4 of these pupils who actually scored 25 , 12 , 15 and 19 marks at the examination had not been sent up , the average marks for the school would have been 44 . find the number of pupils sent up for examination from the school ? | {
"A": "20",
"B": "21",
"C": "22",
"D": "23",
"E": "24"
} | divide(subtract(multiply(44, 4), add(add(add(25, 12), 15), 19)), subtract(44, 39)) | add(n2,n3)|multiply(n1,n6)|subtract(n6,n0)|add(n4,#0)|add(n5,#3)|subtract(#1,#4)|divide(#5,#2) | 39 x = 25 + 12 + 15 + 19 + ( x – 4 ) 44 39 x = 71 + 44 x - 176 5 x = 105 x = 21 answer : b | general |
math_qa__RXBRskQ1Nrv5Sxjh | Amanda sees a sale for 30% off all items, she sees a dress on sale that originally cost $50. How much will it cost Amanda to buy the dress after the sale amount of 30% has been take off? Pick one:
A) $ 40
B) $ 35
C) $ 50
D) $ 65
E) $ 15 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 50</gadget>
<output>15</output>
<gadget id="calculator">50 - 15</gadget>
<output>35</output>
<result>B</result> | B | 35 | Amanda sees a sale for 30% off all items, she sees a dress on sale that originally cost $50. How much will it cost Amanda to buy the dress after the sale amount of 30% has been take off? | {
"A": "$ 40",
"B": "$ 35",
"C": "$ 50",
"D": "$ 65",
"E": "$ 15"
} | subtract(50, multiply(divide(30, const_100), 50)) | divide(n0,const_100)|multiply(n1,#0)|subtract(n1,#1) | final number = original number - 30 % ( original number ) = 50 - 30 % ( 50 ) = 50 - 15 = $ 35 . answer b | gain |
math_qa__52cVSMlxUqCDDEEr | A cricket bat is sold for $900, making a profit of $150. The profit percentage would be
Choose the correct choice from the following options.
A) 24 % B) 20 % C) 30 % D) 36 % E) 40 % | <gadget id="calculator">900 - 150</gadget>
<output>750</output>
<gadget id="calculator">150 / 750</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>B</result> | B | 20 | A cricket bat is sold for $900, making a profit of $150. The profit percentage would be | {
"A": "24 %",
"B": "20 %",
"C": "30 %",
"D": "36 %",
"E": "40 %"
} | multiply(divide(150, subtract(900, 150)), const_100) | subtract(n0,n1)|divide(n1,#0)|multiply(#1,const_100) | 150 / ( 900 - 150 ) = 150 / 750 = 0.2 = 20 % . answer : b | gain |
math_qa__crdGzZvJLeJ03lSz | Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/4, what percent of the total number of the remaining employees would then be clerical? Answers:
A) 25 % B) 28.1 % C) 20 % D) 12.5 % E) 11.1 % | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/3) * (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(1/4) + (2/3)</gadget>
<output>11/12 = around 0.916667</output>
<gadget id="calculator">(1/4) / (11/12)</gadget>
<output>3/11 = around 0.272727</output>
<gadget id="calculator">(3/11) * 100</gadget>
<output>300/11 = around 27.272727</output>
<result>B</result> | B | 28.1 | Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/4, what percent of the total number of the remaining employees would then be clerical? | {
"A": "25 %",
"B": "28.1 %",
"C": "20 %",
"D": "12.5 %",
"E": "11.1 %"
} | multiply(divide(multiply(divide(1, 3), subtract(1, divide(1, 4))), add(multiply(divide(1, 3), subtract(1, divide(1, 4))), subtract(1, divide(1, 3)))), const_100) | divide(n1,n2)|divide(n3,n4)|subtract(n3,#1)|subtract(n3,#0)|multiply(#0,#2)|add(#4,#3)|divide(#4,#5)|multiply(#6,const_100)| | "welcome , just post the question and the choices let ' s see , the way i did it was 1 / 3 are clerical out of 3600 so 1200 are clerical 1200 reduced by 1 / 4 is 1200 * 1 / 4 so it reduced 300 people , so there is 900 clerical people left but since 300 people left , it also reduced from the total of 3600 so there are 3300 people total since 900 clerical left / 3200 people total answer : b" | general |
math_qa__flEeWafTmEoMx1iC | Raja spends 60% of his monthly income on household items, 10% of his monthly income on buying cloths, 10% of his monthly income on medicines and saves the remaining amount which is Rs. 5000. Find his monthly income.
Choose one.
A) rs . 40000
B) rs . 36000
C) rs . 50000
D) rs . 25000
E) none of these | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(3/5) + (1/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) + (1/10)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">5_000 / (1/5)</gadget>
<output>25_000</output>
<result>D</result> | D | 25,000 | Raja spends 60% of his monthly income on household items, 10% of his monthly income on buying cloths, 10% of his monthly income on medicines and saves the remaining amount which is Rs. 5000. Find his monthly income. | {
"A": "rs . 40000",
"B": "rs . 36000",
"C": "rs . 50000",
"D": "rs . 25000",
"E": "none of these"
} | divide(5000, subtract(const_1, add(add(divide(60, const_100), divide(10, const_100)), divide(10, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|divide(n2,const_100)|add(#0,#1)|add(#3,#2)|subtract(const_1,#4)|divide(n3,#5)| | "savings 20 % - 5000 expenditure 80 % - 20000 total - 25000 answer : d" | gain |
math_qa__lzGhjid8R9DaLNPl | A certain company has records stored with a record storage firm in 15-inch by 12-inch by 10-inch boxes. The boxes occupy 1.08 million cubic inches of space. If the company pays $0.8 per box per month for the record storage, what is the total amount that the company pays each month for record storage? Select:
A) a . 480 B) b . 300 C) c . 600 D) d . 410 E) e . 240 | <gadget id="calculator">15 * 12</gadget>
<output>180</output>
<gadget id="calculator">180 * 10</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) / 100</gadget>
<output>9/5_000 = around 0.0018</output>
<gadget id="calculator">1.08 / (9/5_000)</gadget>
<output>600</output>
<gadget id="calculator">0.8 * 600</gadget>
<output>480</output>
<result>A</result> | A | 480 | A certain company has records stored with a record storage firm in 15-inch by 12-inch by 10-inch boxes. The boxes occupy 1.08 million cubic inches of space. If the company pays $0.8 per box per month for the record storage, what is the total amount that the company pays each month for record storage? | {
"A": "a . 480",
"B": "b . 300",
"C": "c . 600",
"D": "d . 410",
"E": "e . 240"
} | multiply(0.8, divide(1.08, divide(divide(divide(multiply(multiply(15, 12), 10), const_100), const_100), const_100))) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_100)|divide(#2,const_100)|divide(#3,const_100)|divide(n3,#4)|multiply(n4,#5)| | "volume per box : 15 x 12 x 10 = 1,800 total volume : 1 , 080,000 number of boxes : total volume / volume per box = 1 , 080,000 / 1,800 = 600 price per month : number of boxes * price per box = 600 * 0.8 = 480 answer : a" | general |
math_qa__il36MWmA1mmPqLKe | Two trains of equal length are running on parallel lines in the same directions at 46km/hr. and 36km/hr. The faster trains pass the slower train in 108 seconds. The length of each train is: Choose the correct choice from the following answers
A) 82 m
B) 50 m
C) 72 m
D) 150 m
E) none of these | <gadget id="calculator">46 - 36</gadget>
<output>10</output>
<gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 3_600</gadget>
<output>25/9 = around 2.777778</output>
<gadget id="calculator">(25/9) * 108</gadget>
<output>300</output>
<gadget id="calculator">300 / 2</gadget>
<output>150</output>
<result>D</result> | D | 150 | Two trains of equal length are running on parallel lines in the same directions at 46km/hr. and 36km/hr. The faster trains pass the slower train in 108 seconds. The length of each train is: | {
"A": "82 m",
"B": "50 m",
"C": "72 m",
"D": "150 m",
"E": "none of these"
} | divide(multiply(divide(multiply(subtract(46, 36), const_1000), const_3600), 108), const_2) | subtract(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n2,#2)|divide(#3,const_2)| | "explanation : the relative speed of train is 46 - 36 = 10 km / hr = ( 10 x 5 ) / 18 = 25 / 9 m / s 10 × 518 = 259 m / s in 108 secs the total distance traveled is 108 x 25 / 9 = 300 m . therefore the length of each train is = 300 / 2 = 150 m . answer d" | general |
math_qa__4jNCkWgJ4qAqmplQ | A team won 40 percent of its first 30 games in a particular season, and 80 percent of its remaining games. If the team won a total of 50 percent of its games that season, what was the total number of games that the team played? Options.
A) 40
B) 50
C) 60
D) 70
E) 80 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">30 * (2/5)</gadget>
<output>12</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(4/5) - (1/2)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">12 / (3/10)</gadget>
<output>40</output>
<result>A</result> | A | 40 | A team won 40 percent of its first 30 games in a particular season, and 80 percent of its remaining games. If the team won a total of 50 percent of its games that season, what was the total number of games that the team played? | {
"A": "40",
"B": "50",
"C": "60",
"D": "70",
"E": "80"
} | divide(multiply(30, divide(40, const_100)), subtract(divide(80, const_100), divide(50, const_100))) | divide(n0,const_100)|divide(n2,const_100)|divide(n3,const_100)|multiply(n1,#0)|subtract(#1,#2)|divide(#3,#4) | 50 % is 10 % - points above 40 % and 30 % - points below 80 % . thus the ratio of ` ` the first 30 games ' ' to ` ` remaining games ' ' is 3 : 1 . so the team played a total of 30 + 10 = 40 games . the answer is a . | gain |
math_qa__FYpxGzxndFO6VFPu | The parameter of a square is equal to the perimeter of a rectangle of length 22 cm and breadth 16 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places) Choose the correct choice from the following:
A) 77.14 cm B) 47.14 cm C) 84.92 cm D) 29.85 cm E) 23.57 cm | <gadget id="calculator">2 * (22 + 16)</gadget>
<output>76</output>
<gadget id="calculator">76 / 4</gadget>
<output>19</output>
<gadget id="calculator">19 / 2</gadget>
<output>19/2 = around 9.5</output>
<gadget id="calculator">2 * pi * (19/2)</gadget>
<output>19*pi = around 59.69026</output>
<gadget id="calculator">(19*pi) / 2</gadget>
<output>19*pi/2 = around 29.84513</output>
<result>D</result> | D | 29.85 | The parameter of a square is equal to the perimeter of a rectangle of length 22 cm and breadth 16 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places) | {
"A": "77.14 cm",
"B": "47.14 cm",
"C": "84.92 cm",
"D": "29.85 cm",
"E": "23.57 cm"
} | divide(circumface(divide(square_edge_by_perimeter(rectangle_perimeter(22, 16)), const_2)), const_2) | rectangle_perimeter(n0,n1)|square_edge_by_perimeter(#0)|divide(#1,const_2)|circumface(#2)|divide(#3,const_2)| | "let the side of the square be a cm . parameter of the rectangle = 2 ( 22 + 16 ) = 76 cm parameter of the square = 76 cm i . e . 4 a = 76 a = 19 diameter of the semicircle = 19 cm circimference of the semicircle = 1 / 2 ( ∏ ) ( 19 ) = 1 / 2 ( 22 / 7 ) ( 19 ) = 418 / 14 = 29.85 cm to two decimal places answer : d" | geometry |
math_qa__9FFKOK8bqNTiTYAa | The ratio of the arithmetic mean of two numbers to one of the numbers is 5:9. What is the ratio of the smaller number to the larger number? Choose the correct choice from the following answers:
A) 1 : 5
B) 1 : 6
C) 1 : 7
D) 1 : 8
E) 1 : 9 | <gadget id="calculator">5 / 9</gadget>
<output>5/9 = around 0.555556</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(5/9) - (1/2)</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/18) * 2</gadget>
<output>1/9 = around 0.111111</output>
<result>E</result> | E | 0.111111 | The ratio of the arithmetic mean of two numbers to one of the numbers is 5:9. What is the ratio of the smaller number to the larger number? | {
"A": "1 : 5",
"B": "1 : 6",
"C": "1 : 7",
"D": "1 : 8",
"E": "1 : 9"
} | multiply(subtract(divide(5, 9), divide(const_1, const_2)), const_2) | divide(n0,n1)|divide(const_1,const_2)|subtract(#0,#1)|multiply(#2,const_2)| | "for two numbers , the arithmetic mean is the middle of the two numbers . the ratio of the mean to the larger number is 5 : 9 , thus the smaller number must have a ratio of 1 . the ratio of the smaller number to the larger number is 1 : 9 . the answer is e ." | other |
math_qa__ZMxQ5fUYdZKvryHt | A, B and C invests Rs.4000, Rs.2000 and Rs.6000 in a business. After one year A removed his money; B and C continued the business for two more year. If the net profit after 3 years be Rs.3300, then A's share in the profit is?
Choose the correct choice from the following answers:
A) 6000
B) 4000
C) 2000
D) 600
E) 300 | <gadget id="calculator">2_000 * 3</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 * 3</gadget>
<output>18_000</output>
<gadget id="calculator">6_000 + 18_000</gadget>
<output>24_000</output>
<gadget id="calculator">4_000 + 24_000</gadget>
<output>28_000</output>
<gadget id="calculator">4_000 / 28_000</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/7) * 4_000</gadget>
<output>4_000/7 = around 571.428571</output>
<result>D</result> | D | 600 | A, B and C invests Rs.4000, Rs.2000 and Rs.6000 in a business. After one year A removed his money; B and C continued the business for two more year. If the net profit after 3 years be Rs.3300, then A's share in the profit is? | {
"A": "6000",
"B": "4000",
"C": "2000",
"D": "600",
"E": "300"
} | multiply(divide(4000, add(4000, add(multiply(2000, 3), multiply(6000, 3)))), 4000) | multiply(n1,n3)|multiply(n2,n3)|add(#0,#1)|add(n0,#2)|divide(n0,#3)|multiply(n0,#4) | 4 * 12 : 2 * 36 : 4 * 36 2 : 3 : 6 2 / 11 * 3300 = 600 answer : d | gain |
math_qa__jdwM8WhRkB6VddbZ | The avg weight of A,B & C is 80 kg. If D joins the group, the avg weight of the group becomes 82 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 81 kg. What is the weight of A? Choose the correct choice: A) 56 B) 65 C) 75 D) 89 E) 95 | <gadget id="calculator">82 * 4</gadget>
<output>328</output>
<gadget id="calculator">81 * 4</gadget>
<output>324</output>
<gadget id="calculator">80 * 3</gadget>
<output>240</output>
<gadget id="calculator">328 - 240</gadget>
<output>88</output>
<gadget id="calculator">3 + 88</gadget>
<output>91</output>
<gadget id="calculator">324 - 91</gadget>
<output>233</output>
<gadget id="calculator">328 - 233</gadget>
<output>95</output>
<result>E</result> | E | 95 | The avg weight of A,B & C is 80 kg. If D joins the group, the avg weight of the group becomes 82 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 81 kg. What is the weight of A? | {
"A": "56",
"B": "65",
"C": "75",
"D": "89",
"E": "95"
} | subtract(multiply(82, const_4), subtract(multiply(81, const_4), add(3, subtract(multiply(82, const_4), multiply(80, const_3))))) | multiply(n1,const_4)|multiply(n3,const_4)|multiply(n0,const_3)|subtract(#0,#2)|add(n2,#3)|subtract(#1,#4)|subtract(#0,#5) | a + b + c = 3 * 80 = 240 a + b + c + d = 4 * 82 = 328 - - - - ( i ) so , d = 88 & e = 88 + 3 = 91 b + c + d + e = 81 * 4 = 324 - - - ( ii ) from eq . ( i ) & ( ii ) a - e = 328 – 324 = 4 a = e + 4 = 91 + 4 = 95 answer : e | general |
math_qa__rWQdVl8UPIG5TeNG | The base of a triangle is 15 cm and height is 12 cm. The height of another triangle of double the area having the base 20 cm is : Choose one:
A) 22 cm
B) 20 cm
C) 18 cm
D) 10 cm
E) none of these | <gadget id="calculator">(15 * 12) / 2</gadget>
<output>90</output>
<gadget id="calculator">2 * 90</gadget>
<output>180</output>
<gadget id="calculator">180 * 2</gadget>
<output>360</output>
<gadget id="calculator">360 / 20</gadget>
<output>18</output>
<result>C</result> | C | 18 | The base of a triangle is 15 cm and height is 12 cm. The height of another triangle of double the area having the base 20 cm is : | {
"A": "22 cm",
"B": "20 cm",
"C": "18 cm",
"D": "10 cm",
"E": "none of these"
} | divide(multiply(multiply(const_2, triangle_area(15, 12)), const_2), 20) | triangle_area(n0,n1)|multiply(#0,const_2)|multiply(#1,const_2)|divide(#2,n2) | explanation : area of triangle , a 1 = 1 / 2 ∗ base ∗ height = 1 / 2 ∗ 15 ∗ 12 = 90 cm 2 area of second triangle = 2 ∗ a 1 = 180 cm 2 1 / 2 ∗ 20 ∗ height = 180 = > height = 18 cm option c | geometry |
math_qa__gmy5Bh9g6RUWLWpw | Rectangular tile each of size 20cm by 30cm must be laid horizontally on a rectangular floor of size 100cm by 150cm,such that the tiles do not overlap and they are placed with edges jutting against each other on all edges. A tile can be placed in any orientation so long as its edges are parallel to the edges of floor. No tile should overshoot any edge of the floor. The maximum number of tiles that can be accommodated on the floor is:
Choices
A) 40 B) 15 C) 25 D) 32 E) 45 | <gadget id="calculator">100 * 150</gadget>
<output>15_000</output>
<gadget id="calculator">20 * 30</gadget>
<output>600</output>
<gadget id="calculator">15_000 / 600</gadget>
<output>25</output>
<result>C</result> | C | 25 | Rectangular tile each of size 20cm by 30cm must be laid horizontally on a rectangular floor of size 100cm by 150cm,such that the tiles do not overlap and they are placed with edges jutting against each other on all edges. A tile can be placed in any orientation so long as its edges are parallel to the edges of floor. No tile should overshoot any edge of the floor. The maximum number of tiles that can be accommodated on the floor is: | {
"A": "40",
"B": "15",
"C": "25",
"D": "32",
"E": "45"
} | divide(multiply(100, 150), multiply(20, 30)) | multiply(n2,n3)|multiply(n0,n1)|divide(#0,#1)| | "area of tile = 20 * 30 = 600 area of floor = 100 * 150 = 15000 no of tiles = 15000 / 600 = 25 so , the no of tile = 25 answer : c" | geometry |
math_qa__f91Hbm7k4futPxAL | If x is 30 percent more than y and y is 40 percent less than z, then x is what percent of z? Choose one:
A) 78 %
B) 250 %
C) 500 / 3 %
D) 125 %
E) 60 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">(13/10) * 60</gadget>
<output>78</output>
<result>A</result> | A | 78 | If x is 30 percent more than y and y is 40 percent less than z, then x is what percent of z? | {
"A": "78 %",
"B": "250 %",
"C": "500 / 3 %",
"D": "125 %",
"E": "60 %"
} | multiply(add(const_1, divide(30, const_100)), subtract(const_100, 40)) | divide(n0,const_100)|subtract(const_100,n1)|add(#0,const_1)|multiply(#2,#1)| | "z = 100 ; y = 60 so x = 78 x as % of z = 78 / 100 * 100 = > 78 % answer will be ( a )" | general |
math_qa__k5Yhz1dk5Ew7M4qX | A train running at the speed of 60 km/hr crosses a pole in 12 seconds. Find the length of the train. Choose one
A) 150 B) 278 C) 179 D) 200 E) 191 | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 12</gadget>
<output>200</output>
<result>D</result> | D | 200 | A train running at the speed of 60 km/hr crosses a pole in 12 seconds. Find the length of the train. | {
"A": "150",
"B": "278",
"C": "179",
"D": "200",
"E": "191"
} | multiply(divide(multiply(60, const_1000), const_3600), 12) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | ": speed = 60 * ( 5 / 18 ) m / sec = 50 / 3 m / sec length of train ( distance ) = speed * time ( 50 / 3 ) * 12 = 200 meter answer : d" | physics |
math_qa__cnzA7FqSB0CCp4u3 | If y > 0, (7y)/20 + (3y)/10 is what percent of y? Choose the correct choice:
A) 40 %
B) 50 %
C) 65 %
D) 70 %
E) 80 % | <gadget id="calculator">7 / 20</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(7/20) + (3/10)</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">100 * (13/20)</gadget>
<output>65</output>
<result>C</result> | C | 65 | If y > 0, (7y)/20 + (3y)/10 is what percent of y? | {
"A": "40 %",
"B": "50 %",
"C": "65 %",
"D": "70 %",
"E": "80 %"
} | multiply(const_100, add(divide(7, 20), divide(3, 10))) | divide(n1,n2)|divide(n3,n4)|add(#0,#1)|multiply(#2,const_100)| | "can be reduced to 7 y / 20 + 6 y / 20 = 13 y / 20 = 65 % answer c" | general |
math_qa__AjZy1tEGqCn0HlJL | The value of a machine depreciates at 21% per annum. If its present value is $1,50,000, at what price should it be sold after two years such that a profit of $24,000 is made?
Choose the correct choice from the following options: A) $ 257615 B) $ 437615 C) $ 127615 D) $ 117615 E) $ 157615 | <gadget id="calculator">21 / 100</gadget>
<output>21/100 = around 0.21</output>
<gadget id="calculator">1 - (21/100)</gadget>
<output>79/100 = around 0.79</output>
<gadget id="calculator">(79/100) * (79/100)</gadget>
<output>6_241/10_000 = around 0.6241</output>
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">10_000 * 10</gadget>
<output>100_000</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">500 * 100</gadget>
<output>50_000</output>
<gadget id="calculator">100_000 + 50_000</gadget>
<output>150_000</output>
<gadget id="calculator">(6_241/10_000) * 150_000</gadget>
<output>93_615</output>
<gadget id="calculator">21 + 2</gadget>
<output>23</output>
<gadget id="calculator">23 * 100</gadget>
<output>2_300</output>
<gadget id="calculator">2_300 * 10</gadget>
<output>23_000</output>
<gadget id="calculator">93_615 + 23_000</gadget>
<output>116_615</output>
<result>D</result> | D | 117,615 | The value of a machine depreciates at 21% per annum. If its present value is $1,50,000, at what price should it be sold after two years such that a profit of $24,000 is made? | {
"A": "$ 257615",
"B": "$ 437615",
"C": "$ 127615",
"D": "$ 117615",
"E": "$ 157615"
} | add(multiply(multiply(subtract(1, divide(21, const_100)), subtract(1, divide(21, const_100))), add(multiply(multiply(const_100, const_100), sqrt(const_100)), multiply(multiply(divide(sqrt(const_100), const_2), const_100), const_100))), multiply(multiply(add(21, const_2), const_100), sqrt(const_100))) | add(n0,const_2)|divide(n0,const_100)|multiply(const_100,const_100)|sqrt(const_100)|divide(#3,const_2)|multiply(#2,#3)|multiply(#0,const_100)|subtract(n1,#1)|multiply(#4,const_100)|multiply(#7,#7)|multiply(#6,#3)|multiply(#8,const_100)|add(#5,#11)|multiply(#12,#9)|add(#13,#10)| | "the value of the machine after two years = 0.79 * 0.79 * 1 , 50,000 = $ 96,000 sp such that a profit of $ 24,000 is made = 93,615 + 24,000 = $ 1 , 17,615 d" | gain |
math_qa__GR0jrqnFENb3sG76 | What is the CP of Rs 100 stock at 9 discount, with 1/5% brokerage?
Choose the correct choice from the following
A) 96.9 B) 96.3 C) 91.2 D) 96.7 E) 96.21 | <gadget id="calculator">100 - 9</gadget>
<output>91</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">91 + (1/5)</gadget>
<output>456/5 = around 91.2</output>
<result>C</result> | C | 91.2 | What is the CP of Rs 100 stock at 9 discount, with 1/5% brokerage? | {
"A": "96.9",
"B": "96.3",
"C": "91.2",
"D": "96.7",
"E": "96.21"
} | add(subtract(100, 9), divide(1, 5)) | divide(n2,n3)|subtract(n0,n1)|add(#0,#1)| | "explanation : use the formula , cp = 100 â € “ discount + brokerage % cp = 100 - 9 + 1 / 5 91.2 thus the cp is rs 91.2 . answer : c" | gain |
math_qa__YtpGfVRDa9TSabI9 | The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 8000 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation? Options
A) 500 B) 1,600 / 3 C) 1,000 D) 1,500 E) 2,000 | <gadget id="calculator">8_000 / 2</gadget>
<output>4_000</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4_000 * (1/2)</gadget>
<output>2_000</output>
<result>E</result> | E | 2,000 | The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 8000 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation? | {
"A": "500",
"B": "1,600 / 3",
"C": "1,000",
"D": "1,500",
"E": "2,000"
} | multiply(divide(8000, const_2), divide(const_1, const_2)) | divide(n8,const_2)|divide(const_1,const_2)|multiply(#0,#1) | x 13 : ( t , d , s ) y 14 : ( t , 3 d , s + 8000 mi / hour ) z 15 : ( t + 2 seconds , s , 5 d ) d = ? distance = speed * time x 13 : d = s * t x 14 : 3 d = ( s + 8000 ) * t = = = > 3 d = ts + 8000 t z 15 : 5 d = s * ( t + 2 t ) = = = > 5 d = st + 2 st = = = > 5 d - 2 st = st 3 d = 5 d - 2 st + 8000 t - 2 d = - 2 st + 8000 t 2 d = 2 st - 8000 t d = st - 4000 t x 13 : d = s * t st - 4000 t = s * t s - 4000 = s - 2000 = s i got to this point and could n ' t go any further . this seems like a problem where i can set up individual d = r * t formulas and solve but it appears that ' s not the case . for future reference how would i know not to waste my time setting up this problem in the aforementioned way ? thanks ! ! ! the distance of z 15 is equal to five times the distance of x 13 ( we established that x 13 is the baseline and thus , it ' s measurements are d , s , t ) s ( t + 2 ) = 5 ( s * t ) what clues would i have to know to set up the equation in this fashion ? is it because i am better off setting two identical distances together ? st + 2 s = 5 st t + 2 = 5 t 2 = 4 t t = 1 / 2 we are looking for distance ( d = s * t ) so we need to solve for speed now that we have time . speed y 14 - speed x 13 speed = d / t 3 d / t - d / t = 8000 ( remember , t is the same because both asteroids were observed for the same amount of time ) 2 d = 8000 2 = 4000 d = s * t d = 4000 * ( 1 / 2 ) d = 2000 answer : e | physics |
math_qa__ak4jTRwW1aHSyD0Q | the average of 15 numbers is 75 . average of the first 8 of them is 68 and that of the last 8.00001 is 77 . find the 8.000001 th number ?
Choose the correct choice from the following answers
A) 51 B) 87 C) 35 D) 75 E) 68 | <gadget id="calculator">8.000001 * 77</gadget>
<output>616.000077</output>
<gadget id="calculator">15 * 75</gadget>
<output>1_125</output>
<gadget id="calculator">68 * 8</gadget>
<output>544</output>
<gadget id="calculator">1_125 - 544</gadget>
<output>581</output>
<gadget id="calculator">616.000077 - 581</gadget>
<output>35.000077</output>
<result>C</result> | C | 35 | the average of 15 numbers is 75 . average of the first 8 of them is 68 and that of the last 8.00001 is 77 . find the 8.000001 th number ? | {
"A": "51",
"B": "87",
"C": "35",
"D": "75",
"E": "68"
} | subtract(multiply(8.000001, 77), subtract(multiply(15, 75), multiply(68, 8))) | multiply(n5,n6)|multiply(n0,n1)|multiply(n2,n3)|subtract(#1,#2)|subtract(#0,#3) | sum of all the 15 numbers = 15 * 75 = 1,125 sum of the first 8 of them = 8 * 68 = 544 sum of the last 8 of them = 8 * 77 = 616 so , the 8 th number = 544 + 616 - 1,125 = 35 . answer : c | general |
math_qa__0MlSz64YmEd8J5l4 | Mr Yadav spends 60% of his monthly salary on consumable items and 50% of the remaining on clothes and transport. He saves the remaining amount. If his savings at the end of the year were 48456, how much amount per month would he have spent on clothes and transport? Choose the correct choice from the following choices:
A) 4038 B) 8076 C) 9691.2 D) 4845.6 E) none of these | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 * 50</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 100</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">48_456 / (1/5)</gadget>
<output>242_280</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">242_280 / 12</gadget>
<output>20_190</output>
<gadget id="calculator">20_190 * (1/5)</gadget>
<output>4_038</output>
<result>A</result> | A | 4,038 | Mr Yadav spends 60% of his monthly salary on consumable items and 50% of the remaining on clothes and transport. He saves the remaining amount. If his savings at the end of the year were 48456, how much amount per month would he have spent on clothes and transport? | {
"A": "4038",
"B": "8076",
"C": "9691.2",
"D": "4845.6",
"E": "none of these"
} | multiply(divide(divide(48456, divide(divide(multiply(subtract(const_100, 60), 50), const_100), const_100)), multiply(const_3, const_4)), divide(divide(multiply(subtract(const_100, 60), 50), const_100), const_100)) | multiply(const_3,const_4)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,const_100)|divide(#3,const_100)|divide(n2,#4)|divide(#5,#0)|multiply(#6,#4) | ∵ amount , he have spent in 1 month on clothes transport = amount spent on saving per month ∵ amount , spent on clothes and transport = 48456 ⁄ 12 = 4038 answer a | general |
math_qa__angbCM4U6h6s8Snc | The length of a rectangular field is 7/5 its width. If the perimeter of the field is 336 meters, what is the width of the field? Select the correct option:
A) 50
B) 60
C) 70
D) 80
E) 90 | <gadget id="calculator">7 / 5</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) + (7/5)</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">(14/5) + 2</gadget>
<output>24/5 = around 4.8</output>
<gadget id="calculator">336 / (24/5)</gadget>
<output>70</output>
<result>C</result> | C | 70 | The length of a rectangular field is 7/5 its width. If the perimeter of the field is 336 meters, what is the width of the field? | {
"A": "50",
"B": "60",
"C": "70",
"D": "80",
"E": "90"
} | divide(336, add(add(divide(7, 5), divide(7, 5)), const_2)) | divide(n0,n1)|add(#0,#0)|add(#1,const_2)|divide(n2,#2)| | "let l be the length and w be the width . l = ( 7 / 5 ) w perimeter : 2 l + 2 w = 336 , 2 ( 7 / 5 ) w + 2 w = 336 solve the above equation to find : w = 70 m and l = 98 m . correct answer c ) 70" | geometry |
math_qa__RFbe9zpyvozqMDEb | Difference of two numbers is 1650. If 7.5% of the number is 12.5% of the other number , find the number ? Choose the correct choice from the following options:
A) 2660 , 1000 B) 3660 , 2000 C) 3000 , 4160 D) 2490 , 4150 E) 2475 , 4125 | <gadget id="calculator">7.5 / 12.5</gadget>
<output>0.6</output>
<gadget id="calculator">1 - 0.6</gadget>
<output>0.4</output>
<gadget id="calculator">1_650 / 0.4</gadget>
<output>4_125</output>
<gadget id="calculator">0.6 * 4_125</gadget>
<output>2_475</output>
<result>E</result> | E | 2,475 | Difference of two numbers is 1650. If 7.5% of the number is 12.5% of the other number , find the number ? | {
"A": "2660 , 1000",
"B": "3660 , 2000",
"C": "3000 , 4160",
"D": "2490 , 4150",
"E": "2475 , 4125"
} | multiply(divide(7.5, 12.5), divide(1650, subtract(const_1, divide(7.5, 12.5)))) | divide(n1,n2)|subtract(const_1,#0)|divide(n0,#1)|multiply(#0,#2)| | "let the numbers be x and y . then , 7.5 % of x = 12.5 % of y x = 125 * y / 75 = 5 * y / 3 . now , x - y = 1650 5 * y / 3 – y = 1650 2 * y / 3 = 1650 y = [ ( 1650 * 3 ) / 2 ] = 2475 . one number = 2475 , second number = 5 * y / 3 = 4125 . answer e ." | gain |
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