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stringlengths 7
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math_qa__56WFNGYYJwHrWaco | A certain fraction has the same ratio to 1/36, as 4/7 does to 5/9. What is this certain fraction? Pick one:
A) 1 / 35 B) 1 / 42 C) 1 / 49 D) 1 / 56 E) 1 / 63 | <gadget id="calculator">1 / 36</gadget>
<output>1/36 = around 0.027778</output>
<result>A</result> | A | 0.028571 | A certain fraction has the same ratio to 1/36, as 4/7 does to 5/9. What is this certain fraction? | {
"A": "1 / 35",
"B": "1 / 42",
"C": "1 / 49",
"D": "1 / 56",
"E": "1 / 63"
} | divide(1, 36) | divide(n0,n1) | x / ( 1 / 36 ) = ( 4 / 7 ) / ( 5 / 9 ) x = 4 * 9 * 1 / 36 * 7 * 5 = 1 / 35 the answer is a . | other |
math_qa__3Z15vz1hjoWcQwFR | There are 780 male and female participants in a meeting. Half the female participants and one-quarterof the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female? Choose the correct choice from the following answers: A) 75 B) 100 C) 125 D) 130 E) 225 | <gadget id="calculator">780 / 3</gadget>
<output>260</output>
<gadget id="calculator">260 * 4</gadget>
<output>1_040</output>
<gadget id="calculator">1_040 - 780</gadget>
<output>260</output>
<gadget id="calculator">260 / 2</gadget>
<output>130</output>
<result>D</result> | D | 130 | There are 780 male and female participants in a meeting. Half the female participants and one-quarterof the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female? | {
"A": "75",
"B": "100",
"C": "125",
"D": "130",
"E": "225"
} | divide(subtract(multiply(divide(780, const_3), const_4), 780), const_2) | divide(n0,const_3)|multiply(#0,const_4)|subtract(#1,n0)|divide(#2,const_2)| | "female = x male = 780 - x x / 2 + 780 - x / 4 = 1 / 3 * ( 780 ) = 260 x = 260 x / 2 = 130 is supposed to be the answer m is missing something correct option d" | general |
math_qa__bPjJ7pzUegXWOQhM | What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
Choose the most appropriate option
A) 289 B) 500 C) 188 D) 666 E) 155 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + (1/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">4 * (7/2)</gadget>
<output>14</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">70 / (7/50)</gadget>
<output>500</output>
<result>B</result> | B | 500 | What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent? | {
"A": "289",
"B": "500",
"C": "188",
"D": "666",
"E": "155"
} | divide(70, divide(multiply(4, add(3, divide(1, 2))), const_100)) | divide(n3,n4)|add(n2,#0)|multiply(n1,#1)|divide(#2,const_100)|divide(n0,#3)| | "70 = ( p * 4 * 7 / 2 ) / 100 p = 500 answer : b" | gain |
math_qa__ZTMGr8FkPzJ04KK5 | A man is 34 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is?
Choose the correct answer
A) 16 B) 19 C) 15 D) 32 E) 40 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">34 - 2</gadget>
<output>32</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">32 / 1</gadget>
<output>32</output>
<result>D</result> | D | 32 | A man is 34 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is? | {
"A": "16",
"B": "19",
"C": "15",
"D": "32",
"E": "40"
} | divide(subtract(34, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1)) | multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)| | "let the son ' s present age be x years . then , man ' s present age = ( x + 24 ) years . ( x + 34 ) + 2 = 2 ( x + 2 ) x + 36 = 2 x + 4 = > x = 32 . answer : d" | general |
math_qa__MJw3qU1UH78xwBTO | A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 130 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? Options
A) 28 sec B) 16 sec C) 37 sec D) 18 sec E) 17 sec | <gadget id="calculator">240 + 130</gadget>
<output>370</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">5 / 18</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">370 / 10</gadget>
<output>37</output>
<result>C</result> | C | 37 | A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 130 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? | {
"A": "28 sec",
"B": "16 sec",
"C": "37 sec",
"D": "18 sec",
"E": "17 sec"
} | divide(add(240, 130), multiply(subtract(45, 9), divide(divide(const_10, const_2), divide(subtract(45, 9), const_2)))) | add(n1,n2)|divide(const_10,const_2)|subtract(n3,n0)|divide(#2,const_2)|divide(#1,#3)|multiply(#4,#2)|divide(#0,#5)| | "speed of train relative to jogger = 45 - 9 = 36 km / hr . = 36 * 5 / 18 = 10 m / sec . distance to be covered = 240 + 120 = 370 m . time taken = 370 / 10 = 37 sec . answer : c" | general |
math_qa__pMtgIWZv1UJiNPH2 | A train running at a speed of 36 km/h passes an electric pole in 14 seconds. In how many seconds will the whole train pass a 360-meter long platform? Choose the correct choice
A) 44 B) 46 C) 48 D) 50 E) 52 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">10 * 14</gadget>
<output>140</output>
<gadget id="calculator">140 + 360</gadget>
<output>500</output>
<gadget id="calculator">500 / 10</gadget>
<output>50</output>
<result>D</result> | D | 50 | A train running at a speed of 36 km/h passes an electric pole in 14 seconds. In how many seconds will the whole train pass a 360-meter long platform? | {
"A": "44",
"B": "46",
"C": "48",
"D": "50",
"E": "52"
} | divide(add(multiply(multiply(36, const_0_2778), 14), 360), multiply(36, const_0_2778)) | multiply(n0,const_0_2778)|multiply(n1,#0)|add(n2,#1)|divide(#2,#0)| | "let the length of the train be x meters . when a train crosses an electric pole , the distance covered is its own length x . speed = 36 km / h = 36000 m / 3600 s = 10 m / s x = 14 * 10 = 140 m . the time taken to pass the platform = ( 140 + 360 ) / 10 = 50 seconds the answer is d ." | physics |
math_qa__DFBy8iX5irDQSJng | If n is a positive integer and n^2 is divisible by 72, then the largest positive integer M that must divide n is?
Choose the correct option: A) 6 B) 12 C) 24 D) 36 E) 48 | <gadget id="calculator">72 / 2</gadget>
<output>36</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<result>B</result> | B | 12 | If n is a positive integer and n^2 is divisible by 72, then the largest positive integer M that must divide n is? | {
"A": "6",
"B": "12",
"C": "24",
"D": "36",
"E": "48"
} | multiply(sqrt(divide(72, 2)), 2) | divide(n1,n0)|sqrt(#0)|multiply(n0,#1)| | "q : if n is a positive integer and n ^ 2 is divisible by 72 , then the largest positive integer m that must divide n is : a 6 , b 12 , c 24 , d 36 , e 48 n ^ 2 is divisible by 72 , but it must also be greater than 72 . if n is an integer , then n ^ 2 must be a perfect square . the factorization of 72 is ( 8 ) ( 9 ) , so if it is multiplied by 2 , it will be ( 2 ) ( 8 ) ( 9 ) = ( 16 ) ( 9 ) = 144 , a perfect square . so n ^ 2 must be at least 144 or a multiple of 144 , which means that n must be 12 or a multiple of 12 . b" | general |
math_qa__leBaq1FI32QKMTYv | A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 27 m * 2 m * 0.75 m? Choose the correct choice from the following:
A) 29798 B) 27908 C) 78902 D) 25000 E) 27000 | <gadget id="calculator">27 * 100</gadget>
<output>2_700</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">2_700 * 200</gadget>
<output>540_000</output>
<gadget id="calculator">0.75 * 100</gadget>
<output>75</output>
<gadget id="calculator">540_000 * 75</gadget>
<output>40_500_000</output>
<gadget id="calculator">40_500_000 / 20</gadget>
<output>2_025_000</output>
<gadget id="calculator">2_025_000 / 10</gadget>
<output>202_500</output>
<gadget id="calculator">202_500 / 7.5</gadget>
<output>27_000</output>
<result>E</result> | E | 27,000 | A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 27 m * 2 m * 0.75 m? | {
"A": "29798",
"B": "27908",
"C": "78902",
"D": "25000",
"E": "27000"
} | divide(divide(divide(multiply(multiply(multiply(27, const_100), multiply(2, const_100)), multiply(0.75, const_100)), 20), 10), 7.5) | multiply(n3,const_100)|multiply(n4,const_100)|multiply(n5,const_100)|multiply(#0,#1)|multiply(#3,#2)|divide(#4,n0)|divide(#5,n1)|divide(#6,n2) | 27 * 2 * 0.75 = 20 / 100 * 10 / 100 * 7.5 / 100 * x 27 = 1 / 100 * x = > x = 27000 answer : e | physics |
math_qa__8VAEXn3ZeeKOkmKr | one-fourth of the workers in Palabras bookstore have read the latest book by J. Saramago, and 5/8 of the workers have read the latest book by H. Kureishi. The number of workers that have read neither book is one less than the number of the workers that have read the latest Saramago book and have not read the latest Kureishi book. If there are 72 workers in the Palabras bookstore, how many of them have read both books? Choose the correct option
A) 13 B) 12 C) 9 D) 8 E) 4 | <gadget id="calculator">72 / 4</gadget>
<output>18</output>
<gadget id="calculator">18 + 18</gadget>
<output>36</output>
<gadget id="calculator">72 / 8</gadget>
<output>9</output>
<gadget id="calculator">9 * 5</gadget>
<output>45</output>
<gadget id="calculator">36 + 45</gadget>
<output>81</output>
<gadget id="calculator">81 - 72</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>E</result> | E | 4 | one-fourth of the workers in Palabras bookstore have read the latest book by J. Saramago, and 5/8 of the workers have read the latest book by H. Kureishi. The number of workers that have read neither book is one less than the number of the workers that have read the latest Saramago book and have not read the latest Kureishi book. If there are 72 workers in the Palabras bookstore, how many of them have read both books? | {
"A": "13",
"B": "12",
"C": "9",
"D": "8",
"E": "4"
} | divide(subtract(subtract(add(add(divide(72, const_4), divide(72, const_4)), multiply(divide(72, 8), 5)), 72), const_1), const_2) | divide(n2,const_4)|divide(n2,n1)|add(#0,#0)|multiply(n0,#1)|add(#2,#3)|subtract(#4,n2)|subtract(#5,const_1)|divide(#6,const_2)| | "there are total 72 workers . one - fourth of the workers in palabras bookstore have read the latest book by j . saramago , so 18 have read saramago . 5 / 8 of the workers have read the latest book by h . kureishi . so ( 5 / 8 ) * 72 = 45 have read kureishi the number of workers that have read neither book is one less than the number of the workers that have read the latest saramago book and have not read the latest kureishi book if b workers have read both books , 18 - b have read saramago but not kureishi . so , ( 18 - b - 1 ) have read neither . total = n ( a ) + n ( b ) - both + neither 72 = 18 + 45 - b + ( 18 - b - 1 ) b = 4 answer ( e )" | general |
math_qa__pRAsZWZfs7gaWfQp | In traveling from a dormitory to a certain city, a student went 1/4 of the way by foot, 1/2 of the way by bus, and the remaining 10 kilometers by car. What is the distance, in kilometers, from the dormitory to the city? Answers: A) 10 B) 45 C) 30 D) 20 E) 40 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) + (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<result>E</result> | E | 40 | In traveling from a dormitory to a certain city, a student went 1/4 of the way by foot, 1/2 of the way by bus, and the remaining 10 kilometers by car. What is the distance, in kilometers, from the dormitory to the city? | {
"A": "10",
"B": "45",
"C": "30",
"D": "20",
"E": "40"
} | multiply(10, inverse(subtract(1, add(divide(1, 4), divide(1, 2))))) | divide(n0,n1)|divide(n2,n3)|add(#0,#1)|subtract(n0,#2)|inverse(#3)|multiply(n4,#4)| | "whole trip = distance by foot + distance by bus + distance by car x = 1 / 4 x + 1 / 2 x + 10 x - 1 / 4 x - 1 / 2 x = 10 x = 40 km option : e" | physics |
math_qa__O2eJO1JF4Dci0jSJ | In the faculty of Reverse-Engineering, 220 second year students study numeric methods, 423 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 80% of the total? Choose the correct choice from the following:
A) 515 . B) 545 . C) 618 . D) 644 . E) 636 . | <gadget id="calculator">220 + 423</gadget>
<output>643</output>
<result>E</result> | E | 636 | In the faculty of Reverse-Engineering, 220 second year students study numeric methods, 423 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 80% of the total? | {
"A": "515 .",
"B": "545 .",
"C": "618 .",
"D": "644 .",
"E": "636 ."
} | add(220, 423) | add(n0,n1) | answer is e : 636 solution : total number of students studying both are 423 + 220 - 134 = 509 ( subtracting the 134 since they were included in the both the other numbers already ) . so 80 % of total is 509 , so 100 % is approx . 636 . | general |
math_qa__iLgBrUJegfd0gode | What would be the minimum number of pumps required to fill a tank of 1000 m3 to 85% in one hour? The capacity of the pump is 150 m3/hour and operates at an efficiency of 75%. Choose the correct choice from the following options:
A) 6 B) 8 C) 10 D) 11 E) 12 | <gadget id="calculator">1_000 * 85</gadget>
<output>85_000</output>
<gadget id="calculator">85_000 / 100</gadget>
<output>850</output>
<gadget id="calculator">150 * 75</gadget>
<output>11_250</output>
<gadget id="calculator">11_250 / 100</gadget>
<output>225/2 = around 112.5</output>
<gadget id="calculator">850 / (225/2)</gadget>
<output>68/9 = around 7.555556</output>
<gadget id="calculator">(68/9) + 1</gadget>
<output>77/9 = around 8.555556</output>
<gadget id="calculator">floor(77/9)</gadget>
<output>8</output>
<result>B</result> | B | 8 | What would be the minimum number of pumps required to fill a tank of 1000 m3 to 85% in one hour? The capacity of the pump is 150 m3/hour and operates at an efficiency of 75%. | {
"A": "6",
"B": "8",
"C": "10",
"D": "11",
"E": "12"
} | floor(add(divide(divide(multiply(1000, 85), const_100), divide(multiply(150, 75), const_100)), const_1)) | multiply(n0,n2)|multiply(n3,n5)|divide(#0,const_100)|divide(#1,const_100)|divide(#2,#3)|add(#4,const_1)|floor(#5) | volume handled by pump in one hour = 150 x . 75 = 112.5 volume of the tank that needs to be filled = 1000 x . 85 = 850 number of pumps needed = 850 / 112.5 = 7.55 Γ’ β° Λ 8 answer : b | physics |
math_qa__aNKZhu5hSEQFxix0 | Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 60 percent was planted with grapes and 30 percent of the cleared land was planted with potato. If the remaining 360 acres of cleared land was planted with tomato, how many acres did the farmer own? Select
A) 3250 B) 3450 C) 4000 D) 3750 E) 3800 | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(1/10) * (9/10)</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">360 / (9/100)</gadget>
<output>4_000</output>
<result>C</result> | C | 4,000 | Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 60 percent was planted with grapes and 30 percent of the cleared land was planted with potato. If the remaining 360 acres of cleared land was planted with tomato, how many acres did the farmer own? | {
"A": "3250",
"B": "3450",
"C": "4000",
"D": "3750",
"E": "3800"
} | divide(360, multiply(divide(subtract(subtract(const_100, 60), 30), const_100), divide(90, const_100))) | divide(n0,const_100)|subtract(const_100,n1)|subtract(#1,n2)|divide(#2,const_100)|multiply(#3,#0)|divide(n3,#4)| | 60 % of 90 % = 54 % , 30 % 0 f 90 % = 27 % so the remaining 90 - 54 - 27 = 9 % = 360 acres or 10 % of 90 % = 9 % - - > 360 / 9 * 100 = 4000 acres answer ( c ) | gain |
math_qa__P62T6LTisvBAXwxJ | The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 8 months, find for how much time did Q invest the money?
Choose the correct choice from the following answers.
A) 11 B) 10 C) 18 D) 16 E) 12 | <gadget id="calculator">7 / 5</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">10 / 7</gadget>
<output>10/7 = around 1.428571</output>
<gadget id="calculator">(7/5) * (10/7)</gadget>
<output>2</output>
<gadget id="calculator">2 * 8</gadget>
<output>16</output>
<result>D</result> | D | 16 | The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 8 months, find for how much time did Q invest the money? | {
"A": "11",
"B": "10",
"C": "18",
"D": "16",
"E": "12"
} | multiply(multiply(divide(7, 5), divide(10, 7)), 8) | divide(n0,n1)|divide(n3,n2)|multiply(#0,#1)|multiply(n4,#2)| | "7 * 5 : 8 * x = 7 : 10 x = 16 answer : d" | gain |
math_qa__Snlhbo2dioz3zC02 | A monkey ascends a greased pole 12 metres high. He ascends 2 metres in first minute and slips down 1 metre in the alternate minute. In which minute, he reaches the top ?
Select
A) 21 st B) 22 nd C) 23 rd D) 24 th E) none of these | <gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">24 - 1</gadget>
<output>23</output>
<result>B</result> | B | 22 | A monkey ascends a greased pole 12 metres high. He ascends 2 metres in first minute and slips down 1 metre in the alternate minute. In which minute, he reaches the top ? | {
"A": "21 st",
"B": "22 nd",
"C": "23 rd",
"D": "24 th",
"E": "none of these"
} | subtract(multiply(2, 12), 1) | multiply(n0,n1)|subtract(#0,n2) | in 2 minutes , he ascends = 1 metre β΄ 10 metres , he ascends in 20 minutes . β΄ he reaches the top in 21 st minute . answer b | physics |
math_qa__nLZSwRQQWMpS60MF | sakshi invests a part of rs . 12000 in 12 % stock at rs . 120 and the remainder in 15 % stock at rs . 125 . if his total dividend per annum is rs . 1360 , how much does he invest in 12 % stock at rs . 120 ? Pick one:
A) rs . 4000 B) rs . 4500 C) rs . 5500 D) rs . 6000 E) rs . 6500 | <gadget id="calculator">15 / 125</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) * 12_000</gadget>
<output>1_440</output>
<gadget id="calculator">1_360 - 1_440</gadget>
<output>-80</output>
<gadget id="calculator">12 / 120</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) - (3/25)</gadget>
<output>-1/50 = around -0.02</output>
<gadget id="calculator">(-80) / (-1/50)</gadget>
<output>4_000</output>
<result>A</result> | A | 4,000 | sakshi invests a part of rs . 12000 in 12 % stock at rs . 120 and the remainder in 15 % stock at rs . 125 . if his total dividend per annum is rs . 1360 , how much does he invest in 12 % stock at rs . 120 ? | {
"A": "rs . 4000",
"B": "rs . 4500",
"C": "rs . 5500",
"D": "rs . 6000",
"E": "rs . 6500"
} | divide(subtract(1360, multiply(divide(15, 125), 12000)), subtract(divide(12, 120), divide(15, 125))) | divide(n3,n4)|divide(n1,n2)|multiply(n0,#0)|subtract(#1,#0)|subtract(n5,#2)|divide(#4,#3) | let investment in 12 % stock be rs . x . then , investment in 15 % stock = rs . ( 12000 - x ) . 12 / 120 * x + 15 / 125 * ( 12000 - x ) = 1360 x / 10 + 3 / 25 ( 12000 - x ) = 1360 5 x + 72000 - 6 x = 1360 x 50 x = 4000 . answer = a | general |
math_qa__wEiphrWbXJbvloN3 | Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/5, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem? Choices: A) 11 / 8 B) 3 / 80 C) 9 / 64 D) 5 / 64 E) 3 / 64 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/5) * (1/2)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">1 - (5/8)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(1/10) * (3/8)</gadget>
<output>3/80 = around 0.0375</output>
<result>B</result> | B | 0.0375 | Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/5, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem? | {
"A": "11 / 8",
"B": "3 / 80",
"C": "9 / 64",
"D": "5 / 64",
"E": "3 / 64"
} | multiply(multiply(divide(1, 5), divide(1, 2)), subtract(1, divide(5, 8))) | divide(n0,n1)|divide(n2,n3)|divide(n4,n5)|multiply(#0,#1)|subtract(n0,#2)|multiply(#3,#4)| | "p ( xavier will solve ) = 1 / 5 p ( yvonne will solve ) = 1 / 2 p ( zelda will not solve ) = 1 - 5 / 8 = 3 / 8 . now , we need to multiply all this ps to find an answer : p = ( 1 / 5 ) * ( 1 / 2 ) * ( 3 / 8 ) = 3 / 80 . ans . b ." | general |
math_qa__riiDM4BTVNveCtfx | In a college, the ratio of the number of boys to girls is 8 : 5. If there are 400 girls, the total number of students in the college is Options: A) 1040 B) 920 C) 980 D) 720 E) 820 | <gadget id="calculator">400 / 5</gadget>
<output>80</output>
<gadget id="calculator">80 * 8</gadget>
<output>640</output>
<gadget id="calculator">400 + 640</gadget>
<output>1_040</output>
<result>A</result> | A | 1,040 | In a college, the ratio of the number of boys to girls is 8 : 5. If there are 400 girls, the total number of students in the college is | {
"A": "1040",
"B": "920",
"C": "980",
"D": "720",
"E": "820"
} | add(400, multiply(divide(400, 5), 8)) | divide(n2,n1)|multiply(n0,#0)|add(n2,#1)| | "explanation : let the boy are 8 x and girls are 5 x = > 5 x = 400 = > x = 80 total students = 8 x + 5 x = 13 x = 13 ( 80 ) = 1040 option a" | other |
math_qa__zGTVgpUX110imeWL | The tax on a commodity is diminished by 18% and its consumption increased by 15%. The effect on revenue is? Choose the correct option
A) 2 % B) 8.7 % C) 5.7 % D) 6.7 % E) 1 % | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">1 - (9/50)</gadget>
<output>41/50 = around 0.82</output>
<gadget id="calculator">(23/20) * (41/50)</gadget>
<output>943/1_000 = around 0.943</output>
<gadget id="calculator">(943/1_000) * 100</gadget>
<output>943/10 = around 94.3</output>
<gadget id="calculator">100 - (943/10)</gadget>
<output>57/10 = around 5.7</output>
<result>C</result> | C | 5.7 | The tax on a commodity is diminished by 18% and its consumption increased by 15%. The effect on revenue is? | {
"A": "2 %",
"B": "8.7 %",
"C": "5.7 %",
"D": "6.7 %",
"E": "1 %"
} | subtract(const_100, multiply(multiply(add(const_1, divide(15, const_100)), subtract(const_1, divide(18, const_100))), const_100)) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)|subtract(const_100,#5)| | "100 * 100 = 10000 82 * 115 = 9430 - - - - - - - - - - - 10000 - - - - - - - - - - - 570 100 - - - - - - - - - - - ? = > 5.7 % decrease answer : c" | general |
math_qa__97dOVWgXi6iUKEzE | If Jamie's income is Rs 20000, calculate his savings given that his income and expenditure are in the ratio 7:5.?
Pick:
A) rs 7500
B) rs 4000
C) rs 2000
D) rs 8000
E) rs 7000 | <gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) * 20_000</gadget>
<output>25_000/3 = around 8_333.333333</output>
<result>D</result> | D | 8,000 | If Jamie's income is Rs 20000, calculate his savings given that his income and expenditure are in the ratio 7:5.? | {
"A": "rs 7500",
"B": "rs 4000",
"C": "rs 2000",
"D": "rs 8000",
"E": "rs 7000"
} | multiply(divide(5, add(7, 5)), 20000) | add(n1,n2)|divide(n2,#0)|multiply(n0,#1) | let the income and the expenditure of the person be rs . 7 x and rs . 7 x respectively . income , 7 x = 28000 = > x = 4000 savings = income - expenditure = 7 x - 5 x = 2 x so , savings = rs . 8000 answer : d | other |
math_qa__1JGsiG2Ib5sSJafS | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 1% p.a. in 5 years. What is the sum?
Choose the correct choice from the following options.
A) 82762 B) 12877 C) 82882 D) 80925 E) 80325 | <gadget id="calculator">4_016.25 * 100</gadget>
<output>401_625</output>
<gadget id="calculator">401_625 / 1</gadget>
<output>401_625</output>
<gadget id="calculator">401_625 / 5</gadget>
<output>80_325</output>
<result>E</result> | E | 80,325 | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 1% p.a. in 5 years. What is the sum? | {
"A": "82762",
"B": "12877",
"C": "82882",
"D": "80925",
"E": "80325"
} | divide(divide(multiply(4016.25, const_100), 1), 5) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "principal = ( 100 * 4016.25 ) / ( 1 * 5 ) = rs . 80325 . answer : e" | gain |
math_qa__mzNWIgUbLoDPMGwY | On thrusday mabel handled 90 transactions. anthony handled 10 % more transaction than mabel, cal handled 2/3rds of the transactions that anthony handled and jade handled 16 more transaction than cal. how much transaction did jade handled? Choose the correct choice from the following choices:
A) 92
B) 80
C) 72
D) 82
E) 28 | <gadget id="calculator">90 / 10</gadget>
<output>9</output>
<gadget id="calculator">90 + 9</gadget>
<output>99</output>
<gadget id="calculator">99 * 2</gadget>
<output>198</output>
<gadget id="calculator">198 / 3</gadget>
<output>66</output>
<gadget id="calculator">66 + 16</gadget>
<output>82</output>
<result>D</result> | D | 82 | On thrusday mabel handled 90 transactions. anthony handled 10 % more transaction than mabel, cal handled 2/3rds of the transactions that anthony handled and jade handled 16 more transaction than cal. how much transaction did jade handled? | {
"A": "92",
"B": "80",
"C": "72",
"D": "82",
"E": "28"
} | add(divide(multiply(add(90, divide(90, 10)), 2), 3), 16) | divide(n0,n1)|add(n0,#0)|multiply(n2,#1)|divide(#2,n3)|add(n4,#3) | mabel handled 90 transaction , anthony 10 % more transaction the mabel . anthony = 90 + 90 * 10 % , = 90 + 90 * 0.10 , = 90 + 9 , = 99 , cal handled 2 / 3 rds than anthony handled , cal = 2 / 3 * 99 = 66 , jade handled 16 more than cal . jade = 66 + 16 = 82 , jade handled = 82 tranasactions . correct answer : ( d ) | general |
math_qa__dUsAswYmsoGdqXad | A cement mixture is composed of 3 elements. By weight, 1/3 of the mixture is sand, 1/4 of the mixture is water, and the remaining 10 pounds of the mixture is gravel. What is the weight of the entire mixture in pounds?
Choices.
A) 24 B) 26 C) 28 D) 30 E) 36 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) + (1/4)</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">1 - (7/12)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">10 / (5/12)</gadget>
<output>24</output>
<result>A</result> | A | 24 | A cement mixture is composed of 3 elements. By weight, 1/3 of the mixture is sand, 1/4 of the mixture is water, and the remaining 10 pounds of the mixture is gravel. What is the weight of the entire mixture in pounds? | {
"A": "24",
"B": "26",
"C": "28",
"D": "30",
"E": "36"
} | divide(10, subtract(1, add(divide(1, 3), divide(1, 4)))) | divide(n1,n2)|divide(n3,n4)|add(#0,#1)|subtract(n1,#2)|divide(n5,#3)| | "let the total weight be x . sand content = ( 1 / 3 ) x water content = ( 1 / 4 ) x gravel = x - ( 1 / 3 ) x - ( 1 / 4 ) x = ( 5 / 12 ) x = 10 x = 24 then answer will be a = 24" | general |
math_qa__JRDo6UoGPChwyOyi | 0.01 is what percent of 0.1? Choose the correct choice:
A) 1 % B) 10 % C) 100 % D) 50 % E) 25 % | <gadget id="calculator">0.01 / 0.1</gadget>
<output>0.1</output>
<gadget id="calculator">0.1 * 100</gadget>
<output>10</output>
<result>B</result> | B | 10 | 0.01 is what percent of 0.1? | {
"A": "1 %",
"B": "10 %",
"C": "100 %",
"D": "50 %",
"E": "25 %"
} | multiply(divide(0.01, 0.1), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "required percentage = 0.01 * 100 / 0.1 = 100 / 10 = 10 % answer is b" | gain |
math_qa__BCmH0ibvEgseSkSZ | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 26 sec. What is the length of the platform? Answers
A) 389 m
B) 150 m
C) 289 m
D) 299 m
E) 219 m | <gadget id="calculator">300 / 26</gadget>
<output>150/13 = around 11.538462</output>
<gadget id="calculator">(150/13) * 39</gadget>
<output>450</output>
<gadget id="calculator">450 - 300</gadget>
<output>150</output>
<result>B</result> | B | 150 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 26 sec. What is the length of the platform? | {
"A": "389 m",
"B": "150 m",
"C": "289 m",
"D": "299 m",
"E": "219 m"
} | subtract(multiply(speed(300, 26), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 26 = 150 / 13 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 150 / 13 = > x = 150 m . answer : b" | physics |
math_qa__RqEXSDjD7wBNqCrM | 9 persons went to a hotel for taking their meals . 8 of them spent rs 12 each on their meals and the ninth spent rs . 8 more than the average expenditure of all the 9 . what was the total money spent by them ? Choose the correct choice from the following
A) 117 B) 180 C) 150 D) 200 E) 250 | <gadget id="calculator">8 * 12</gadget>
<output>96</output>
<gadget id="calculator">96 + 8</gadget>
<output>104</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">104 / 8</gadget>
<output>13</output>
<gadget id="calculator">9 * 13</gadget>
<output>117</output>
<result>A</result> | A | 117 | 9 persons went to a hotel for taking their meals . 8 of them spent rs 12 each on their meals and the ninth spent rs . 8 more than the average expenditure of all the 9 . what was the total money spent by them ? | {
"A": "117",
"B": "180",
"C": "150",
"D": "200",
"E": "250"
} | multiply(9, divide(add(multiply(8, 12), 8), subtract(9, const_1))) | multiply(n1,n2)|subtract(n0,const_1)|add(n1,#0)|divide(#2,#1)|multiply(n0,#3) | exp . let the total expenditure be x , then the average = x / 9 , 8 * 12 + [ x / 9 + 8 ] = x or [ x - x / 9 ] = 104 . 8 x / 9 = 104 , x = 104 * 9 / 8 = 117 . answer : a | general |
math_qa__3xToiZxKFB8mX9gU | The average (arithmetic mean) of 4 positive integers is 40. If the average of 2 of these integers is 45, what is the greatest possible value that one of the other 2 integers can have? Pick
A) 55 B) 69 C) 100 D) 109 E) 115 | <gadget id="calculator">40 * 4</gadget>
<output>160</output>
<gadget id="calculator">45 * 2</gadget>
<output>90</output>
<gadget id="calculator">160 - 90</gadget>
<output>70</output>
<result>B</result> | B | 69 | The average (arithmetic mean) of 4 positive integers is 40. If the average of 2 of these integers is 45, what is the greatest possible value that one of the other 2 integers can have? | {
"A": "55",
"B": "69",
"C": "100",
"D": "109",
"E": "115"
} | subtract(multiply(40, 4), multiply(45, 2)) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1) | a + b + c + d = 160 a + b = 90 c + d = 70 greatest possible = 69 ( just less than 1 ) answer = b | general |
math_qa__26YWfSY8dtESeAQE | A train running at the speed of 48 km/hr crosses a pole in 9 seconds. Find the length of the train? Pick:
A) 120 meter B) 299 meter C) 666 meter D) 155 meter E) 144 meter | <gadget id="calculator">48 * 1_000</gadget>
<output>48_000</output>
<gadget id="calculator">48_000 / 3_600</gadget>
<output>40/3 = around 13.333333</output>
<gadget id="calculator">(40/3) * 9</gadget>
<output>120</output>
<result>A</result> | A | 120 | A train running at the speed of 48 km/hr crosses a pole in 9 seconds. Find the length of the train? | {
"A": "120 meter",
"B": "299 meter",
"C": "666 meter",
"D": "155 meter",
"E": "144 meter"
} | multiply(divide(multiply(48, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 48 * ( 5 / 18 ) m / sec = 40 / 3 m / sec length of train ( distance ) = speed * time ( 40 / 3 ) * 9 = 120 meter answer : a" | physics |
math_qa__LJ1L1uz9UwIoowNE | A cricket player whose bowling average was 20.5 runs per wicket, takes 5 wicket for 52 runs in a match. Due to this his average decreases by 0.5. What will be the number of wickets taken by him till the last match?
Select the correct option: A) 64 B) 72 C) 101 D) 111 E) 128 | <gadget id="calculator">20.5 - 0.5</gadget>
<output>20</output>
<gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">100 - 52</gadget>
<output>48</output>
<gadget id="calculator">48 / 0.5</gadget>
<output>96</output>
<result>C</result> | C | 101 | A cricket player whose bowling average was 20.5 runs per wicket, takes 5 wicket for 52 runs in a match. Due to this his average decreases by 0.5. What will be the number of wickets taken by him till the last match? | {
"A": "64",
"B": "72",
"C": "101",
"D": "111",
"E": "128"
} | divide(subtract(multiply(subtract(20.5, 0.5), 5), 52), 0.5) | subtract(n0,n3)|multiply(n1,#0)|subtract(#1,n2)|divide(#2,n3)| | "average = total runs / total wickets total runs after last match = 20.5 w + 52 total wickets after last match = w + 5 ( 20.5 w + 52 ) / ( w + 5 ) = 20.5 - 0.5 = 20 w = 96 so total wickets aftr last match = w + 5 = 101 answer : c" | general |
math_qa__RrSjSRPnOfdKZMyC | If a trader sold two cars each at Rs. 325475 and gains 11% on the first and loses 11% on the second, then his profit or loss percent on the whole is? Options.
A) 1.21 % B) 1.74 % C) 1.84 % D) 1.47 % E) 1.24 % | <gadget id="calculator">11 * 11</gadget>
<output>121</output>
<gadget id="calculator">121 / 100</gadget>
<output>121/100 = around 1.21</output>
<result>A</result> | A | 1.21 | If a trader sold two cars each at Rs. 325475 and gains 11% on the first and loses 11% on the second, then his profit or loss percent on the whole is? | {
"A": "1.21 %",
"B": "1.74 %",
"C": "1.84 %",
"D": "1.47 %",
"E": "1.24 %"
} | divide(multiply(11, 11), const_100) | multiply(n1,n1)|divide(#0,const_100)| | "sp of each car is rs . 325475 , he gains 11 % on first car and losses 11 % on second car . in this case , there will be loss and percentage of loss is given by = [ ( profit % ) ( loss % ) ] / 100 = ( 11 ) ( 11 ) / 100 % = 1.21 % answer : a" | gain |
math_qa__mouGDUJUSjhP0MRH | 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm, there are 15 buffaloes, 8 oxen, and 24 cows. The fodder for these cattle is available for 36 days. If 40 more cows and 15 more buffaloes are brought in, how many days will the fodder last? Choose the correct choice from the following answers: A) 15 days B) 18 days C) 21 days D) 24 days E) 27 days | <gadget id="calculator">24 / 4</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">15 + 18</gadget>
<output>33</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">33 + 12</gadget>
<output>45</output>
<gadget id="calculator">36 * 45</gadget>
<output>1_620</output>
<gadget id="calculator">15 + 15</gadget>
<output>30</output>
<gadget id="calculator">24 + 40</gadget>
<output>64</output>
<gadget id="calculator">64 / 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">30 + 48</gadget>
<output>78</output>
<gadget id="calculator">78 + 12</gadget>
<output>90</output>
<gadget id="calculator">1_620 / 90</gadget>
<output>18</output>
<result>B</result> | B | 18 | 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm, there are 15 buffaloes, 8 oxen, and 24 cows. The fodder for these cattle is available for 36 days. If 40 more cows and 15 more buffaloes are brought in, how many days will the fodder last? | {
"A": "15 days",
"B": "18 days",
"C": "21 days",
"D": "24 days",
"E": "27 days"
} | divide(multiply(36, add(add(15, multiply(divide(24, 4), 3)), multiply(divide(8, 2), 3))), add(add(add(15, 15), multiply(divide(add(24, 40), 4), 3)), multiply(divide(8, 2), 3))) | add(n3,n8)|add(n5,n7)|divide(n5,n1)|divide(n4,n2)|divide(#1,n1)|multiply(n0,#2)|multiply(n0,#3)|add(n3,#5)|multiply(n0,#4)|add(#7,#6)|add(#0,#8)|add(#10,#6)|multiply(n6,#9)|divide(#12,#11)| | "2 oxen = 3 buffaloes = 4 cows also : 15 buffaloes + 8 oxen + 24 cows = 10 oxen + 8 oxen + 12 oxen = 30 oxen there is enough fodder for 1 oxen for 30 * 36 days . 40 cows + 15 buffaloes = 20 oxen + 10 oxen = 30 oxen the new total is equal to 60 oxen instead of 30 oxen . 30 * 36 / 60 oxen = 18 days the answer is b ." | general |
math_qa__csWtA2l7dsImjYIt | For any non-zero a and b that satisfy |ab| = ab and |a| = a
|b - 4| + |ab - b| = ? Select the correct option
A) ab - 4 B) 2 b - ab - 4 C) ab + 4 D) ab - 2 b + 4 E) 4 - ab | <gadget id="calculator">1 - 1</gadget>
<output>0</output>
<gadget id="calculator">0 - 4</gadget>
<output>-4</output>
<result>A</result> | A | -4 | For any non-zero a and b that satisfy |ab| = ab and |a| = a
|b - 4| + |ab - b| = ? | {
"A": "ab - 4",
"B": "2 b - ab - 4",
"C": "ab + 4",
"D": "ab - 2 b + 4",
"E": "4 - ab"
} | subtract(subtract(const_1, const_1), 4) | subtract(const_1,const_1)|subtract(#0,n0) | | ab | = ab and | a | = - a = > b is also negative . so | b - 4 | + | ab - b | = ( b - 4 ) + ab - b ( as ab is positive and - b is positive , so expression is totally positive ) = b - 4 + ab - b = ab - 4 answer - a | general |
math_qa__jumnjg1YLSRyvI11 | P software has coding line 5% more than N, N software has coding line 1/3 more than M. M software has 90 lines of coding. find P lines. Select
A) 106 B) 107 C) 126 D) 109 E) 110 | <gadget id="calculator">90 / 3</gadget>
<output>30</output>
<gadget id="calculator">90 + 30</gadget>
<output>120</output>
<result>C</result> | C | 126 | P software has coding line 5% more than N, N software has coding line 1/3 more than M. M software has 90 lines of coding. find P lines. | {
"A": "106",
"B": "107",
"C": "126",
"D": "109",
"E": "110"
} | add(90, divide(90, 3)) | divide(n3,n2)|add(n3,#0) | m s / w has 90 line of code n s / w has = 90 + 90 * 1 / 3 = 120 line of code p s / w 5 % more n ' code 120 + 6 = 126 answer : c | general |
math_qa__oXO8r8LjTdCT4hfB | The length of a rectangle is 4 times its width. If the width of the rectangle is 5 inches, what is the rectangle's area, in square inches?
Choose the correct choice from the following: A) 30 square inches B) 75 square inches C) 100 square inches D) 89 square inches E) 92 square inches | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">5 * 20</gadget>
<output>100</output>
<result>C</result> | C | 100 | The length of a rectangle is 4 times its width. If the width of the rectangle is 5 inches, what is the rectangle's area, in square inches? | {
"A": "30 square inches",
"B": "75 square inches",
"C": "100 square inches",
"D": "89 square inches",
"E": "92 square inches"
} | rectangle_area(5, multiply(4, 5)) | multiply(n0,n1)|rectangle_area(n1,#0)| | "if the width is 5 in and the length is 4 times the width , then the length is 4 * 5 = 20 in the area is given by 5 * 20 = 100 square inches correct answer c" | geometry |
math_qa__OelhNGulu7HOSAym | A and B go around a circular track of length 1800 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point? Choose the correct choice from the following options
A) 120 sec B) 165 sec C) 186 sec D) 167 sec E) 360 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">1_800 / 5</gadget>
<output>360</output>
<result>E</result> | E | 360 | A and B go around a circular track of length 1800 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point? | {
"A": "120 sec",
"B": "165 sec",
"C": "186 sec",
"D": "167 sec",
"E": "360 sec"
} | divide(1800, subtract(multiply(54, const_0_2778), multiply(36, const_0_2778))) | multiply(n2,const_0_2778)|multiply(n1,const_0_2778)|subtract(#0,#1)|divide(n0,#2) | time taken to meet for the first time at the starting point = lcm { length of the track / speed of a , length of the track / speed of b } = lcm { 1800 / ( 36 * 5 / 18 ) , 1800 / ( 54 * 5 / 18 ) } = lcm ( 180 , 120 ) = 360 sec . answer : e | physics |
math_qa__HpvPZC21x5zd3JWb | If f(x) = 3x^4 - 4x^3 - 3x^2 + 6x , then f(-1) =
Choose the correct choice from the following choices
A) - 2
B) - 1
C) 0
D) 1
E) 2 | <gadget id="calculator">-1</gadget>
<output>-1</output>
<gadget id="calculator">(-1) ** 4</gadget>
<output>1</output>
<gadget id="calculator">3 * 1</gadget>
<output>3</output>
<gadget id="calculator">(-1) ** 3</gadget>
<output>-1</output>
<gadget id="calculator">4 * (-1)</gadget>
<output>-4</output>
<gadget id="calculator">3 - (-4)</gadget>
<output>7</output>
<gadget id="calculator">(-1) ** 2</gadget>
<output>1</output>
<gadget id="calculator">7 - 3</gadget>
<output>4</output>
<gadget id="calculator">6 * (-1)</gadget>
<output>-6</output>
<gadget id="calculator">4 + (-6)</gadget>
<output>-2</output>
<result>A</result> | A | -2 | If f(x) = 3x^4 - 4x^3 - 3x^2 + 6x , then f(-1) = | {
"A": "- 2",
"B": "- 1",
"C": "0",
"D": "1",
"E": "2"
} | add(subtract(subtract(multiply(3, power(negate(1), 4)), multiply(4, power(negate(1), 3))), multiply(3, power(negate(1), 2))), multiply(6, negate(1))) | negate(n7)|multiply(n6,#0)|power(#0,n1)|power(#0,n0)|power(#0,n5)|multiply(n0,#2)|multiply(n1,#3)|multiply(n0,#4)|subtract(#5,#6)|subtract(#8,#7)|add(#1,#9) | f ( - 1 ) = 3 ( - 1 ) ^ 4 - 4 ( - 1 ) ^ 3 - 3 ( - 1 ) ^ 2 + 6 ( - 1 ) = 3 + 4 - 3 - 6 = - 2 the answer is a . | general |
math_qa__rXYkktSaC7yOJ6I7 | The greatest common divisor of (b-2)!,(b+1)!, and (b+4)! is 5040. what is the value of b? Choices
A) 8
B) 10
C) 12
D) 9
E) 6 | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<result>D</result> | D | 9 | The greatest common divisor of (b-2)!,(b+1)!, and (b+4)! is 5040. what is the value of b? | {
"A": "8",
"B": "10",
"C": "12",
"D": "9",
"E": "6"
} | add(add(4, 4), 1) | add(n2,n2)|add(n1,#0) | gcd of ( b - 2 ) ! , ( b + 1 ) ! , and ( b + 4 ) ! is 5040 . find x . best way to find n is substitute each of the answer and find out the correct one . only option d gave the correct answer . option d : 9 and find gcd or 7 ! , 10 ! and 13 ! . 7 ! itself is 5040 and 7 ! which is contained in the other two factorials . this satisfies the condition , hence answer is 9 . answer is d . | general |
math_qa__AnNPjynJW43uIH6I | The length of a side of a hexagon is 10 inches. What is the perimeter? Pick one.
A) 10 B) 20 C) 30 D) 40 E) 60 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<result>E</result> | E | 60 | The length of a side of a hexagon is 10 inches. What is the perimeter? | {
"A": "10",
"B": "20",
"C": "30",
"D": "40",
"E": "60"
} | multiply(10, multiply(const_3, const_2)) | multiply(const_2,const_3)|multiply(n0,#0)| | "hexagon . it means 6 equal sides . p = 6 ( 10 ) = 60 inches answer e" | physics |
math_qa__Bh9n9wMIYzE1jVqo | In February Wilsonβs earnings were 40 percent of his familyβs total income. In March Wilson earned 25 percent less than in February. If the rest of his familyβs income was the same in both months, then, in March, Wilsonβs earnings were approximately what percent S of his familyβs total income?
Choose the correct choice from the following choices
A) 15 % B) 17 % C) 24 % D) 30 % E) 33 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * (2/5)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(2/5) - (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(3/10) / (9/10)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33 | In February Wilsonβs earnings were 40 percent of his familyβs total income. In March Wilson earned 25 percent less than in February. If the rest of his familyβs income was the same in both months, then, in March, Wilsonβs earnings were approximately what percent S of his familyβs total income? | {
"A": "15 %",
"B": "17 %",
"C": "24 %",
"D": "30 %",
"E": "33 %"
} | multiply(divide(subtract(divide(40, const_100), multiply(divide(25, const_100), divide(40, const_100))), subtract(const_1, multiply(divide(25, const_100), divide(40, const_100)))), const_100) | divide(n0,const_100)|divide(n1,const_100)|multiply(#1,#0)|subtract(#0,#2)|subtract(const_1,#2)|divide(#3,#4)|multiply(#5,const_100)| | "lets suppose the total family income in feb = 100 x wilson ' s earning in feb = 40 % of 100 x = 40 x earnings of remaining family in feb = 100 x - 40 x = 60 x wilson ' s earning in march = 75 % of wilson ' s feb earnings = 75 % of 40 x = 30 x earnings of remaining family in march = earnings of remaining family in feb = 60 x thus wilson ' s earning as % of total family income in march s = 30 x / ( 30 + 60 ) x = 30 x / 90 x = 33.33 % thus answer is e" | general |
math_qa__qTIYfTaKpiXAiCpI | If a: b = 1:4, b:c = 13:9, c:d = 5:13, find a:d? Choose the correct choice from the following choices: A) 5 / 46 B) 7 / 36 C) 1 / 36 D) 5 / 36 E) 5 / 37 | <gadget id="calculator">1 * 13</gadget>
<output>13</output>
<gadget id="calculator">13 * 5</gadget>
<output>65</output>
<gadget id="calculator">4 * 9</gadget>
<output>36</output>
<gadget id="calculator">36 * 13</gadget>
<output>468</output>
<gadget id="calculator">65 / 468</gadget>
<output>5/36 = around 0.138889</output>
<result>D</result> | D | 0.138889 | If a: b = 1:4, b:c = 13:9, c:d = 5:13, find a:d? | {
"A": "5 / 46",
"B": "7 / 36",
"C": "1 / 36",
"D": "5 / 36",
"E": "5 / 37"
} | divide(multiply(multiply(1, 13), 5), multiply(multiply(4, 9), 13)) | multiply(n0,n2)|multiply(n1,n3)|multiply(n4,#0)|multiply(n2,#1)|divide(#2,#3) | a / d = ( 1 / 4 ) * ( 13 / 9 ) * ( 5 / 13 ) = > 5 / 36 answer : d | general |
math_qa__u5Dp2V6Bu3jXoHgV | In a rectangular coordinate system, what is the area of a rectangle whose vertices have the coordinates (-5, 1), (1, 1), (1, -4) and (-5, -4)?
Choose one.
A) 20
B) 30
C) 40
D) 55
E) 48 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<result>B</result> | B | 30 | In a rectangular coordinate system, what is the area of a rectangle whose vertices have the coordinates (-5, 1), (1, 1), (1, -4) and (-5, -4)? | {
"A": "20",
"B": "30",
"C": "40",
"D": "55",
"E": "48"
} | multiply(add(5, 1), add(1, 4)) | add(n0,n1)|add(n1,n5)|multiply(#0,#1) | length of side 1 = 5 + 1 = 6 length of side 2 = 4 + 1 = 5 area of rectangle = 6 * 5 = 30 b is the answer | geometry |
math_qa__VrYAUvYiAZthCyTQ | Population of a city in 20004 was 1000000. If in 2005 there isan increment of 15% , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 30%, then find the population of city atthe end of the year 2007 Options
A) 976374 B) 971750 C) 980241 D) 2356677 E) 1083875 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">1 - (7/20)</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(23/20) * (13/20)</gadget>
<output>299/400 = around 0.7475</output>
<gadget id="calculator">1 + (7/20)</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">(299/400) * (27/20)</gadget>
<output>8_073/8_000 = around 1.009125</output>
<gadget id="calculator">1_000_000 * (8_073/8_000)</gadget>
<output>1_009_125</output>
<result>B</result> | B | 971,750 | Population of a city in 20004 was 1000000. If in 2005 there isan increment of 15% , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 30%, then find the population of city atthe end of the year 2007 | {
"A": "976374",
"B": "971750",
"C": "980241",
"D": "2356677",
"E": "1083875"
} | multiply(1000000, multiply(multiply(add(const_1, divide(15, const_100)), subtract(const_1, divide(35, const_100))), add(const_1, divide(35, const_100)))) | divide(n5,const_100)|divide(n3,const_100)|add(#0,const_1)|add(#1,const_1)|subtract(const_1,#0)|multiply(#3,#4)|multiply(#2,#5)|multiply(n1,#6)| | "required population = p ( 1 + r 1 / 100 ) ( 1 - r 2 / 100 ) ( 1 + r 3 / 100 ) = p ( 1 + 15 / 100 ) ( 1 - 35 / 100 ) ( 1 + 30 / 100 ) = 971750 b" | gain |
math_qa__YegsjOhWL1UOaFVl | Alex takes a loan of $9,000 to buy a used truck at the rate of 9 % simple Interest.Calculate the annual interest to be paid for the loan amount. Choose the correct answer:
A) 680
B) 810
C) 800
D) 730
E) 750 | <gadget id="calculator">9 * 100</gadget>
<output>900</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">900 * 10</gadget>
<output>9_000</output>
<gadget id="calculator">9_000 * 9</gadget>
<output>81_000</output>
<gadget id="calculator">81_000 / 100</gadget>
<output>810</output>
<result>B</result> | B | 810 | Alex takes a loan of $9,000 to buy a used truck at the rate of 9 % simple Interest.Calculate the annual interest to be paid for the loan amount. | {
"A": "680",
"B": "810",
"C": "800",
"D": "730",
"E": "750"
} | divide(multiply(multiply(multiply(9, const_100), sqrt(const_100)), 9), const_100) | multiply(n1,const_100)|sqrt(const_100)|multiply(#0,#1)|multiply(n1,#2)|divide(#3,const_100) | from the details given in the problem principle = p = $ 9,000 and r = 9 % or 0.09 expressed as a decimal . as the annual interest is to be calculated , the time period t = 1 . plugging these values in the simple interest formula , i = p x t x r = 9,000 x 1 x 0.09 = 810.00 annual interest to be paid = $ 810 answer : b | gain |
math_qa__2so3k7wtrs66Qeme | Last month, John rejected 0.7% of the products that he inspected and Jane rejected 0.8 percent of the products that she inspected. If total of 0.75 percent of the products produced last month were rejected, what fraction of the products did Jane inspect? Choose the correct option.
A) 1 / 6
B) 1 / 2
C) 5 / 8
D) 5 / 6
E) 15 / 16 | <gadget id="calculator">0.75 - 0.7</gadget>
<output>0.05</output>
<gadget id="calculator">0.8 - 0.7</gadget>
<output>0.1</output>
<gadget id="calculator">0.05 / 0.1</gadget>
<output>0.5</output>
<result>B</result> | B | 0.5 | Last month, John rejected 0.7% of the products that he inspected and Jane rejected 0.8 percent of the products that she inspected. If total of 0.75 percent of the products produced last month were rejected, what fraction of the products did Jane inspect? | {
"A": "1 / 6",
"B": "1 / 2",
"C": "5 / 8",
"D": "5 / 6",
"E": "15 / 16"
} | divide(subtract(0.75, 0.7), subtract(0.8, 0.7)) | subtract(n2,n0)|subtract(n1,n0)|divide(#0,#1)| | "x - fraction of products jane inspected ( 1 - x ) - fraction of products john inspected 0.8 ( x ) + 0.7 ( 1 - x ) = 0.75 0.1 x = 0.75 - 0.7 x = 0.05 / 0.1 x = 1 / 2 therefore the answer is b : 1 / 2 ." | gain |
math_qa__BLDWnxLFGyp5zQXb | What is the smallest integer z for which 27^z> 3^24? Choose the most appropriate option
A) 7 B) 8 C) 9 D) 10 E) 12 | <gadget id="calculator">24 / 3</gadget>
<output>8</output>
<gadget id="calculator">floor(8)</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<result>C</result> | C | 9 | What is the smallest integer z for which 27^z> 3^24? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "12"
} | add(floor(divide(24, const_3)), const_1) | divide(n2,const_3)|floor(#0)|add(#1,const_1)| | "27 ^ z > 3 ^ 24 converting into the same bases : 27 ^ z > 27 ^ 8 therefore for the equation to hold true , z > 8 or z = 9 option c" | general |
math_qa__2RPJuYJaKHweYKEH | The sum of two numbers is 21 and the sum of their squares is 527. Find the product of the numbers.
Choices.
A) 48
B) 41
C) 46
D) 43
E) 96 | <gadget id="calculator">21 ** 2</gadget>
<output>441</output>
<gadget id="calculator">527 - 441</gadget>
<output>86</output>
<gadget id="calculator">86 / 2</gadget>
<output>43</output>
<result>D</result> | D | 43 | The sum of two numbers is 21 and the sum of their squares is 527. Find the product of the numbers. | {
"A": "48",
"B": "41",
"C": "46",
"D": "43",
"E": "96"
} | divide(subtract(527, power(21, const_2)), const_2) | power(n0,const_2)|subtract(n1,#0)|divide(#1,const_2) | let a and b be the two numbers ( a + b ) ^ 2 = a ^ 2 + 2 ab + b ^ 2 given ( a + b ) = 21 a ^ 2 + b ^ 2 = 527 so , 21 ^ 2 = 527 + 2 ab 2 ab = 527 - 441 2 ab = 86 ab = 43 ans d | general |
math_qa__vJJL2skwnU9unZft | Thabo owns exactly 280 books, and each book is either paperback fiction, paperback nonfiction, or hardcover nonfiction. If he owns 20 more paperback nonfiction books than hardcover nonfiction books, and twice as many paperback fiction books as paperback nonfiction books, how many hardcover books nonfiction books does Thabo own? Choose the correct choice from the following answers: A) 10 B) 20 C) 30 D) 40 E) 55 | <gadget id="calculator">280 + 20</gadget>
<output>300</output>
<gadget id="calculator">300 / 4</gadget>
<output>75</output>
<gadget id="calculator">75 - 20</gadget>
<output>55</output>
<result>E</result> | E | 55 | Thabo owns exactly 280 books, and each book is either paperback fiction, paperback nonfiction, or hardcover nonfiction. If he owns 20 more paperback nonfiction books than hardcover nonfiction books, and twice as many paperback fiction books as paperback nonfiction books, how many hardcover books nonfiction books does Thabo own? | {
"A": "10",
"B": "20",
"C": "30",
"D": "40",
"E": "55"
} | subtract(divide(add(280, 20), const_4), 20) | add(n0,n1)|divide(#0,const_4)|subtract(#1,n1)| | "i think we can use double - matrix method and solve using only one variable . our goal is to find the number of hardcover nonfiction books . let that number be x . we are given that all 140 books are either paperback fiction , paperback nonfiction , or hardcover nonfiction . this implies that number of hardcover fiction books is 0 . double - matrix : p = paperback ; h = hardcover ; f = fiction ; nf = nonfiction p h total f 2 x + 40 0 nf x + 20 x total 3 x + 60 x 280 3 x + 60 + x = 280 x = 55 answer ( e . )" | general |
math_qa__zyxxyU7X9H14VRl2 | in the number 100 ab , a and b represent the tens and units digits , respectively . if 110 ab is divisible by 55 , what is the greatest possible value of b Γ a ?
Choose the most appropriate option:
A) 0
B) 5
C) 10
D) 15
E) 25 | <gadget id="calculator">110 / 10</gadget>
<output>11</output>
<gadget id="calculator">55 / 11</gadget>
<output>5</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<result>D</result> | D | 15 | in the number 100 ab , a and b represent the tens and units digits , respectively . if 110 ab is divisible by 55 , what is the greatest possible value of b Γ a ? | {
"A": "0",
"B": "5",
"C": "10",
"D": "15",
"E": "25"
} | multiply(divide(55, divide(110, const_10)), subtract(divide(55, divide(110, const_10)), const_2)) | divide(n1,const_10)|divide(n2,#0)|subtract(#1,const_2)|multiply(#1,#2) | you should notice that 55 * 2 = 110 so 11,000 is divisible by 55 : 55 * 200 = 11,000 ( or you can notice that 11,000 is obviously divisible by both 5 and 11 so by 55 ) - - > b * a = 0 * 0 = 0 . next number divisible by 55 is 11,000 + 55 = 11,055 : b * a = 5 * 5 = 15 ( next number wo n ' t have 110 as the first 3 digits so we have only two options 0 and 25 ) . answer : e . ! please post ps questions in the ps subforum : gmat - problem - solving - ps - 140 / please post ds questions in the ds subforum : gmat - data - sufficiency - ds - 141 / no posting of ps / ds questions is allowed in the mainmath forum . d | general |
math_qa__eswbExx8Yqqgas5x | A train 350 m long, running with a speed of 63 km/hr will pass a tree in?
Choose the most appropriate option.
A) 22 sec B) 16 sec C) 17 sec D) 88 sec E) 20 sec | <gadget id="calculator">63 * 1_000</gadget>
<output>63_000</output>
<gadget id="calculator">350 / 63_000</gadget>
<output>1/180 = around 0.005556</output>
<gadget id="calculator">(1/180) * 3_600</gadget>
<output>20</output>
<result>E</result> | E | 20 | A train 350 m long, running with a speed of 63 km/hr will pass a tree in? | {
"A": "22 sec",
"B": "16 sec",
"C": "17 sec",
"D": "88 sec",
"E": "20 sec"
} | multiply(divide(350, multiply(63, const_1000)), const_3600) | multiply(n1,const_1000)|divide(n0,#0)|multiply(#1,const_3600)| | "speed = 63 * 5 / 18 = 35 / 2 m / sec time taken = 350 * 2 / 35 = 20 sec answer : e" | physics |
math_qa__AxuyGImnUKVwzGhz | A car travelling with 5/7 km of its actual speed covers 42km in 1hr 40 min 48 sec find the actual speed of the car? Select
A) 78 kmph
B) 85 kmph
C) 35 kmph
D) 24 kmph
E) 74 kmph | <gadget id="calculator">40 * 60</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 + 48</gadget>
<output>2_448</output>
<gadget id="calculator">2_448 / 3_600</gadget>
<output>17/25 = around 0.68</output>
<gadget id="calculator">1 + (17/25)</gadget>
<output>42/25 = around 1.68</output>
<gadget id="calculator">42 / (42/25)</gadget>
<output>25</output>
<gadget id="calculator">25 * 7</gadget>
<output>175</output>
<gadget id="calculator">175 / 5</gadget>
<output>35</output>
<result>C</result> | C | 35 | A car travelling with 5/7 km of its actual speed covers 42km in 1hr 40 min 48 sec find the actual speed of the car? | {
"A": "78 kmph",
"B": "85 kmph",
"C": "35 kmph",
"D": "24 kmph",
"E": "74 kmph"
} | divide(multiply(divide(42, add(1, divide(add(multiply(40, const_60), 48), const_3600))), 7), 5) | multiply(n4,const_60)|add(n5,#0)|divide(#1,const_3600)|add(n3,#2)|divide(n2,#3)|multiply(n1,#4)|divide(#5,n0) | time taken = 1 hr 40 min 48 sec = 126 / 75 hrs let the actual speed be x kmph then 5 / 7 x * 126 / 75 = 42 x = ( 42 * 7 * 75 ) / 5 * 126 = 35 kmph answer ( c ) | physics |
math_qa__H8lavjHvNG4B5L01 | Compare the rates of two trains, one travelling at 90 km/hr and other is at 50m/s?
Select: A) 2 : 1 B) 1 : 2 C) 1 : 3 D) 3 : 1 E) 2 : 3 | <gadget id="calculator">50 / 1_000</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 3_600</gadget>
<output>180</output>
<gadget id="calculator">90 / 180</gadget>
<output>1/2 = around 0.5</output>
<result>B</result> | B | 0.5 | Compare the rates of two trains, one travelling at 90 km/hr and other is at 50m/s? | {
"A": "2 : 1",
"B": "1 : 2",
"C": "1 : 3",
"D": "3 : 1",
"E": "2 : 3"
} | divide(90, multiply(divide(50, const_1000), const_3600)) | divide(n1,const_1000)|multiply(#0,const_3600)|divide(n0,#1) | speed of the 1 st train = 90 km / hr speed of the 2 nd train = 50 m / s = 50 * 18 / 5 = 180 km / hr ratio of the speeds of the train = 90 : 180 = 1 : 2 answer is b | gain |
math_qa__Zxw7eerSq9X781At | The average weight of A, B and C is 30 kg. If the average weight of A and B be 25 kg and that of B and C be 28 kg, then the weight of B is: Select:
A) 14 kg B) 15 kg C) 18 kg D) 19 kg E) 16 kg | <gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">28 * 2</gadget>
<output>56</output>
<gadget id="calculator">50 + 56</gadget>
<output>106</output>
<gadget id="calculator">30 * 3</gadget>
<output>90</output>
<gadget id="calculator">106 - 90</gadget>
<output>16</output>
<result>E</result> | E | 16 | The average weight of A, B and C is 30 kg. If the average weight of A and B be 25 kg and that of B and C be 28 kg, then the weight of B is: | {
"A": "14 kg",
"B": "15 kg",
"C": "18 kg",
"D": "19 kg",
"E": "16 kg"
} | subtract(add(multiply(25, const_2), multiply(28, const_2)), multiply(30, const_3)) | multiply(n1,const_2)|multiply(n2,const_2)|multiply(n0,const_3)|add(#0,#1)|subtract(#3,#2) | explanation let a , b , c represent their respective weights . then , we have : a + b + c = ( 30 x 3 ) = 90 Γ’ β¬ Β¦ . ( i ) a + b = ( 25 x 2 ) = 50 Γ’ β¬ Β¦ . ( ii ) b + c = ( 28 x 2 ) = 56 Γ’ β¬ Β¦ . ( iii ) adding ( ii ) and ( iii ) , we get : a + 2 b + c = 106 Γ’ β¬ Β¦ . ( iv ) subtracting ( i ) from ( iv ) , we get : b = 16 . b Γ’ β¬ β’ s weight = 16 kg . answer e | general |
math_qa__y8lppGL89GnUOflb | the cost of a one - family home was $ 120000 in 1980 . in 1988 , the price had increased to $ 192000 . what was the percent increase in the cost of the home ? Select the correct option
A) 60 % B) 50 % C) 55 % D) 40 % E) 33.3 % | <gadget id="calculator">192_000 / 120_000</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(8/5) - 1</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>A</result> | A | 60 | the cost of a one - family home was $ 120000 in 1980 . in 1988 , the price had increased to $ 192000 . what was the percent increase in the cost of the home ? | {
"A": "60 %",
"B": "50 %",
"C": "55 %",
"D": "40 %",
"E": "33.3 %"
} | multiply(subtract(divide(192000, 120000), const_1), const_100) | divide(n3,n0)|subtract(#0,const_1)|multiply(#1,const_100) | increase = 192000 - 120000 = 72000 % increase = 72000 * 100 / 120000 = 60 % answer : option a | general |
math_qa__e2ZuPhQjdZlPBXMI | One fourth of one third of two fifth of a number is 20. What will be40% of that number Choose the correct choice from the following
A) 140 B) 150 C) 180 D) 240 E) 220 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/4) * (1/3)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/12) * (2/5)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">20 / (1/30)</gadget>
<output>600</output>
<gadget id="calculator">600 * 40</gadget>
<output>24_000</output>
<gadget id="calculator">24_000 / 100</gadget>
<output>240</output>
<result>D</result> | D | 240 | One fourth of one third of two fifth of a number is 20. What will be40% of that number | {
"A": "140",
"B": "150",
"C": "180",
"D": "240",
"E": "220"
} | divide(multiply(divide(20, multiply(multiply(divide(const_1, const_4), divide(const_1, const_3)), divide(const_2, add(const_2, const_3)))), 40), const_100) | add(const_2,const_3)|divide(const_1,const_4)|divide(const_1,const_3)|divide(const_2,#0)|multiply(#1,#2)|multiply(#3,#4)|divide(n0,#5)|multiply(n1,#6)|divide(#7,const_100) | explanation : ( 1 / 4 ) * ( 1 / 3 ) * ( 2 / 5 ) * x = 20 then x = 20 * 30 = 600 40 % of 600 = 240 answer : option d | gain |
math_qa__VChVHWkrcwKcwCj5 | A card board of 34 * 14 has to be attached to a wooden box and a total of 35 pins are to be used on the each side of the cardbox. Find the total number of pins used .
Pick.
A) 135
B) 136
C) 137
D) 138
E) 139 | <gadget id="calculator">35 * 4</gadget>
<output>140</output>
<result>B</result> | B | 136 | A card board of 34 * 14 has to be attached to a wooden box and a total of 35 pins are to be used on the each side of the cardbox. Find the total number of pins used . | {
"A": "135",
"B": "136",
"C": "137",
"D": "138",
"E": "139"
} | multiply(35, const_4) | multiply(n2,const_4) | ( 35 * 4 ) - 4 = 136 answer : b | general |
math_qa__osmZ8fBxc6Z2eSc2 | A 200 meter long train crosses a platform in 50 seconds while it crosses a signal pole in 42 seconds. What is the length of the platform? Pick one: A) 39.9 B) 37.88 C) 35 D) 38.88 E) 38.09 | <gadget id="calculator">200 / 42</gadget>
<output>100/21 = around 4.761905</output>
<gadget id="calculator">(100/21) * 50</gadget>
<output>5_000/21 = around 238.095238</output>
<gadget id="calculator">(5_000/21) - 200</gadget>
<output>800/21 = around 38.095238</output>
<result>E</result> | E | 38.09 | A 200 meter long train crosses a platform in 50 seconds while it crosses a signal pole in 42 seconds. What is the length of the platform? | {
"A": "39.9",
"B": "37.88",
"C": "35",
"D": "38.88",
"E": "38.09"
} | subtract(multiply(divide(200, 42), 50), 200) | divide(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = [ 200 / 42 ] m / sec = 100 / 21 m / sec . let the length of the platform be x meters . then , x + 200 / 50 = 100 / 21 21 ( x + 200 ) = 5000 Γ¨ x = 38.09 m . answer : e" | physics |
math_qa__1x42PRJG2D7az9AS | How much water should be added to 11 liters of a 20%-solution of alcohol to reduce the concentration of alcohol in the solution by 75% ? Choose the correct choice from the following:
A) 25 liters B) 29 liters C) 30 liters D) 32 liters E) 35 liters | <gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 20</gadget>
<output>15</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">200 / 5</gadget>
<output>40</output>
<gadget id="calculator">40 - 11</gadget>
<output>29</output>
<result>B</result> | B | 29 | How much water should be added to 11 liters of a 20%-solution of alcohol to reduce the concentration of alcohol in the solution by 75% ? | {
"A": "25 liters",
"B": "29 liters",
"C": "30 liters",
"D": "32 liters",
"E": "35 liters"
} | subtract(divide(multiply(const_2, const_100), subtract(20, multiply(divide(75, const_100), 20))), 11) | divide(n2,const_100)|multiply(const_100,const_2)|multiply(n1,#0)|subtract(n1,#2)|divide(#1,#3)|subtract(#4,n0)| | "let x ltr water to be added 2 ltr alcohol to be represented as ( 20 ( 1 - 3 / 4 ( new soln . = 11 + x ) ) ) 2 = 5 % * ( 11 + x ) - - - - - - - - > x = 29 ans b" | general |
math_qa__ZEwJN4gNaL1d1v77 | A van takes 5 hours to cover a distance of 600 km. What speed in kph should the van maintain to cover the same distance in 3/2 of the previous time? Answers
A) 80 B) 84 C) 88 D) 92 E) 96 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 5</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">600 / (15/2)</gadget>
<output>80</output>
<result>A</result> | A | 80 | A van takes 5 hours to cover a distance of 600 km. What speed in kph should the van maintain to cover the same distance in 3/2 of the previous time? | {
"A": "80",
"B": "84",
"C": "88",
"D": "92",
"E": "96"
} | divide(600, multiply(divide(3, 2), 5)) | divide(n2,n3)|multiply(n0,#0)|divide(n1,#1)| | "( 3 / 2 ) * 5 = 7.5 hours 600 / 7.5 = 80 kph the answer is a ." | physics |
math_qa__lstGGK1zv6Obh8sw | A and B undertake to do a piece of work for $500. A alone can do it in 5days while B alone can do it in 10days. With the help of C, they finish it in 2days. Find the share of C? Choose the most appropriate option
A) $ 200 B) $ 150 C) $ 300 D) $ 25 E) $ 100 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">20 * (1/5)</gadget>
<output>4</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/5) + (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(1/2) - (3/10)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">20 * (1/10)</gadget>
<output>2</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 500</gadget>
<output>200</output>
<result>A</result> | A | 200 | A and B undertake to do a piece of work for $500. A alone can do it in 5days while B alone can do it in 10days. With the help of C, they finish it in 2days. Find the share of C? | {
"A": "$ 200",
"B": "$ 150",
"C": "$ 300",
"D": "$ 25",
"E": "$ 100"
} | multiply(divide(multiply(multiply(2, 10), inverse(5)), add(add(multiply(multiply(2, 10), subtract(inverse(2), add(inverse(5), inverse(10)))), multiply(multiply(2, 10), inverse(5))), multiply(multiply(2, 10), inverse(10)))), 500) | inverse(n1)|inverse(n3)|inverse(n2)|multiply(n2,n3)|add(#0,#2)|multiply(#0,#3)|multiply(#2,#3)|subtract(#1,#4)|multiply(#3,#7)|add(#8,#5)|add(#9,#6)|divide(#5,#10)|multiply(n0,#11)| | "c ' s 1 day work = ( 1 / 2 ) - ( 1 / 5 + 1 / 10 ) = 1 / 5 a : b : c = 1 / 5 : 1 / 10 : 1 / 5 = 2 : 1 : 2 b ' s share = 500 * 2 / 5 = $ 200 answer is a" | physics |
math_qa__5diym08Ho8yldpqn | Angelina walked 100 meters from her home to the grocery at a constant speed. She then walked 180 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym? Choose the correct option
A) 2
B) 3
C) 0.5
D) 6
E) 12 | <gadget id="calculator">180 / 2</gadget>
<output>90</output>
<gadget id="calculator">100 - 90</gadget>
<output>10</output>
<gadget id="calculator">10 / 40</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 2</gadget>
<output>1/2 = around 0.5</output>
<result>C</result> | C | 0.5 | Angelina walked 100 meters from her home to the grocery at a constant speed. She then walked 180 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym? | {
"A": "2",
"B": "3",
"C": "0.5",
"D": "6",
"E": "12"
} | multiply(divide(subtract(100, divide(180, const_2)), 40), const_2) | divide(n1,const_2)|subtract(n0,#0)|divide(#1,n2)|multiply(#2,const_2)| | "let the speed be x . . . so time taken from home to grocery = 100 / x . . the speed to gym = 2 x . . so time taken = 180 / 2 x = 90 / x . . its given 100 / x - 90 / x = 40 . . 10 / x = 40 . . x = 0.25 m / secs . . so grocery to gym = 2 * 0.25 = 0.5 m / s . . . answer : c" | physics |
math_qa__uwbUlv2llk5n9F6a | If 45% of z is 39% of y and y is 75% of x, what percent of x is z? Choose the correct choice from the following choices.
A) 200
B) 160
C) 100
D) 65
E) 50 | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">39 / 100</gadget>
<output>39/100 = around 0.39</output>
<gadget id="calculator">(9/20) / (39/100)</gadget>
<output>15/13 = around 1.153846</output>
<gadget id="calculator">(3/4) / (15/13)</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(13/20) * 100</gadget>
<output>65</output>
<result>D</result> | D | 65 | If 45% of z is 39% of y and y is 75% of x, what percent of x is z? | {
"A": "200",
"B": "160",
"C": "100",
"D": "65",
"E": "50"
} | multiply(divide(divide(75, const_100), divide(divide(45, const_100), divide(39, const_100))), const_100) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|divide(#1,#2)|divide(#0,#3)|multiply(#4,const_100)| | "( 45 / 100 ) z = ( 39 / 100 ) y and y = ( 75 / 100 ) x i . e . y = ( 3 / 4 ) x i . e . ( 45 / 100 ) z = ( 39 / 100 ) * ( 3 / 4 ) x i . e . z = ( 39 * 3 ) x / ( 45 * 4 ) i . e . z = ( 0.65 ) x = ( 65 / 100 ) x i . e . z is 65 % of x answer : option d" | gain |
math_qa__dmaDl0eNEoS0ubox | 10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs.130000, find the cost of a camel?
Choose the correct choice from the following options:
A) s . 9800
B) s . 3800
C) s . 9800
D) s . 5200
E) s . 6880 | <gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">96 * 4</gadget>
<output>384</output>
<gadget id="calculator">384 * 130_000</gadget>
<output>49_920_000</output>
<gadget id="calculator">10 * 16</gadget>
<output>160</output>
<gadget id="calculator">160 * 6</gadget>
<output>960</output>
<gadget id="calculator">960 * 10</gadget>
<output>9_600</output>
<gadget id="calculator">49_920_000 / 9_600</gadget>
<output>5_200</output>
<result>D</result> | D | 5,200 | 10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs.130000, find the cost of a camel? | {
"A": "s . 9800",
"B": "s . 3800",
"C": "s . 9800",
"D": "s . 5200",
"E": "s . 6880"
} | divide(multiply(multiply(multiply(24, 4), 4), 130000), multiply(multiply(multiply(10, 16), 6), 10)) | multiply(n1,n3)|multiply(n0,n2)|multiply(n3,#0)|multiply(n4,#1)|multiply(n7,#2)|multiply(n0,#3)|divide(#4,#5)| | "cost of the camel = p 10 camels = 24 horses 16 horses = 4 oxen 6 oxen = 4 elephants 10 elephants = rs . 130000 p = rs . [ ( 24 * 4 * 4 * 130000 ) / ( 10 * 16 * 6 * 10 ) ] p = rs . ( 49920000 / 9600 ) = > p = rs . 5200 answer : d" | general |
math_qa__tqclApll6tWkraGQ | A worker makes a toy in every 3h. If he works for 150h, then how many toys will he make ? Choose the most appropriate option:
A) 40 B) 54 C) 45 D) 50 E) none | <gadget id="calculator">150 / 3</gadget>
<output>50</output>
<result>D</result> | D | 50 | A worker makes a toy in every 3h. If he works for 150h, then how many toys will he make ? | {
"A": "40",
"B": "54",
"C": "45",
"D": "50",
"E": "none"
} | divide(150, 3) | divide(n1,n0) | no . of toys = 150 / 3 = 50 answer : d | physics |
math_qa__iOwIBnXPcZypHAsY | In one hour, a boat goes 11 km along the stream and 5 km against the stream. The speed of the boat in still water in ( km/hr) is Choose the correct choice from the following answers:
A) 3
B) 5
C) 8
D) 9
E) 7 | <gadget id="calculator">11 + 5</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>C</result> | C | 8 | In one hour, a boat goes 11 km along the stream and 5 km against the stream. The speed of the boat in still water in ( km/hr) is | {
"A": "3",
"B": "5",
"C": "8",
"D": "9",
"E": "7"
} | divide(add(11, 5), const_2) | add(n0,n1)|divide(#0,const_2)| | "solution speed in still water = 1 / 2 ( 11 + 5 ) km / hr = 8 km / hr . answer c" | physics |
math_qa__wMUICqATTmslHhrc | 45 workers work 8 hours to dig a hole 30 meters deep. How many extra workers should be hired to dig another hole 40 meters deep by working for 6 hours?
Select.
A) 75 B) 80 C) 50 D) 35 E) 40 | <gadget id="calculator">8 / 6</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">45 * (4/3)</gadget>
<output>60</output>
<gadget id="calculator">40 / 30</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">60 * (4/3)</gadget>
<output>80</output>
<gadget id="calculator">80 - 45</gadget>
<output>35</output>
<result>D</result> | D | 35 | 45 workers work 8 hours to dig a hole 30 meters deep. How many extra workers should be hired to dig another hole 40 meters deep by working for 6 hours? | {
"A": "75",
"B": "80",
"C": "50",
"D": "35",
"E": "40"
} | subtract(multiply(multiply(45, divide(8, 6)), divide(40, 30)), 45) | divide(n3,n2)|divide(n1,n4)|multiply(n0,#1)|multiply(#0,#2)|subtract(#3,n0) | 45 workers * 8 hours / 30 meters = x * 6 / 40 x = 80 total workers 80 - 45 = 35 the answer is d . | physics |
math_qa__jcsZJMpHlPxGrYXI | If an amount of Rs 42,900 is distributed equally
amongst 22 persons, how much amount would each
person get? Choose one
A) rs 1950 B) rs 2000 C) rs 745 D) rs 765 E) none | <gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 + 3</gadget>
<output>43</output>
<gadget id="calculator">43 * 1_000</gadget>
<output>43_000</output>
<gadget id="calculator">43_000 - 100</gadget>
<output>42_900</output>
<gadget id="calculator">42_900 / 22</gadget>
<output>1_950</output>
<result>A</result> | A | 1,950 | If an amount of Rs 42,900 is distributed equally
amongst 22 persons, how much amount would each
person get? | {
"A": "rs 1950",
"B": "rs 2000",
"C": "rs 745",
"D": "rs 765",
"E": "none"
} | divide(subtract(multiply(add(multiply(const_4, const_10), const_3), const_1000), const_100), 22) | multiply(const_10,const_4)|add(#0,const_3)|multiply(#1,const_1000)|subtract(#2,const_100)|divide(#3,n1) | required amount = 42900 / 22 = rs 1950 answer a | general |
math_qa__8iEhDLA4RPvHYjel | What is the perimeter, in meters, of a rectangular garden 8 meters wide that has the same area as a rectangular playground 16 meters long and 12 meters wide? Choose the correct choice from the following choices
A) 48
B) 56
C) 64
D) 76
E) 192 | <gadget id="calculator">16 * 12</gadget>
<output>192</output>
<gadget id="calculator">192 / 8</gadget>
<output>24</output>
<gadget id="calculator">2 * (24 + 8)</gadget>
<output>64</output>
<result>C</result> | C | 64 | What is the perimeter, in meters, of a rectangular garden 8 meters wide that has the same area as a rectangular playground 16 meters long and 12 meters wide? | {
"A": "48",
"B": "56",
"C": "64",
"D": "76",
"E": "192"
} | rectangle_perimeter(divide(rectangle_area(16, 12), 8), 8) | rectangle_area(n1,n2)|divide(#0,n0)|rectangle_perimeter(n0,#1)| | "say length of garden is l meters . then ( l * 8 ) = 16 * 12 [ given area is same . area = l * b ] therefore l works out to 24 meters . perimeter of garden = 2 * ( 24 + 8 ) = 64 meter . answer is c" | geometry |
math_qa__vvIukI0pQbVundGG | Let the sides of a rectangular prism are consecutive multiples of 5. Which among the following could be the base area
Answers:
A) 360 B) 450 C) 560 D) 670 E) 780 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">30 * 15</gadget>
<output>450</output>
<result>B</result> | B | 450 | Let the sides of a rectangular prism are consecutive multiples of 5. Which among the following could be the base area | {
"A": "360",
"B": "450",
"C": "560",
"D": "670",
"E": "780"
} | multiply(multiply(multiply(5, const_3), const_2), multiply(5, const_3)) | multiply(n0,const_3)|multiply(#0,const_2)|multiply(#1,#0) | length = 5 * a breadth = 5 * ( a + 1 ) or 5 * ( a + 2 ) base area - > multiple of 25 450 = 25 * 18 answer : b | geometry |
math_qa__XahwkgvdCGrl6rno | A bag contains 3 blue and 5 white marbles. One by one, marbles are drawn out randomly until only two are left in the bag. What is the probability X that out of the two, one is white and one is blue? Choices.
A) 15 / 56 B) 41 / 56 C) 13 / 28 D) 15 / 28 E) 5 / 14 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">8 * 7</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<gadget id="calculator">15 / 28</gadget>
<output>15/28 = around 0.535714</output>
<result>D</result> | D | 0.535714 | A bag contains 3 blue and 5 white marbles. One by one, marbles are drawn out randomly until only two are left in the bag. What is the probability X that out of the two, one is white and one is blue? | {
"A": "15 / 56",
"B": "41 / 56",
"C": "13 / 28",
"D": "15 / 28",
"E": "5 / 14"
} | divide(multiply(3, 5), divide(multiply(add(3, 5), add(5, const_2)), const_2)) | add(n0,n1)|add(n1,const_2)|multiply(n0,n1)|multiply(#0,#1)|divide(#3,const_2)|divide(#2,#4)| | "the required probability x = probability of choosing 6 balls out of the total 8 in such a way that we remove 4 out of 5 white and 2 out of 3 blue balls . ways to select 6 out of total 8 = 8 c 6 ways to select 4 out of 5 white balls = 5 c 4 ways to select 2 out of 3 blue balls = 3 c 2 thus the required probability = ( 5 c 4 * 3 c 2 ) / 8 c 6 = 15 / 28 . d is thus the correct answer ." | probability |
math_qa__KvIDXcx1QdQ0SlFv | One hour after Yolanda started walking from X to Y, a distance of 17 miles, Bob started walking along the same road from Y to X. If Yolanda's walking rate was 3 miles per hour and BobΡ's was 4 miles per hour, how many miles had Bob walked when they met? Pick.
A) 24 B) 23 C) 22 D) 21 E) 8 | <gadget id="calculator">17 - 3</gadget>
<output>14</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">14 / 7</gadget>
<output>2</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<result>E</result> | E | 8 | One hour after Yolanda started walking from X to Y, a distance of 17 miles, Bob started walking along the same road from Y to X. If Yolanda's walking rate was 3 miles per hour and BobΡ's was 4 miles per hour, how many miles had Bob walked when they met? | {
"A": "24",
"B": "23",
"C": "22",
"D": "21",
"E": "8"
} | multiply(divide(subtract(17, 3), add(3, 4)), 4) | add(n1,n2)|subtract(n0,n1)|divide(#1,#0)|multiply(n2,#2) | when b started walking y already has covered 3 miles out of 17 , hence the distance at that time between them was 17 - 3 = 14 miles . combined rate of b and y was 3 + 4 = 7 miles per hour , hence they would meet each other in 14 / 7 = 2 hours . in 6 hours b walked 2 * 4 = 8 miles . answer : e . | physics |
math_qa__aibkOzTt2DOEL24d | A dozen eggs and 10 pounds of oranges are currently at the same price. If the price of a dozen eggs rises by 9 percent and the price of oranges rises by 6 %. How much more will it cost to buy a dozen eggs and 10 pounds of oranges . Select the correct option: A) 5 % B) 10 % C) 15 % D) 20 % E) 25 % | <gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">(9/100) * 10</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">10 + (9/10)</gadget>
<output>109/10 = around 10.9</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 10</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">10 + (3/5)</gadget>
<output>53/5 = around 10.6</output>
<gadget id="calculator">(109/10) + (53/5)</gadget>
<output>43/2 = around 21.5</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">(43/2) - 20</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 100</gadget>
<output>150</output>
<gadget id="calculator">150 / 20</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 2</gadget>
<output>15</output>
<result>C</result> | C | 15 | A dozen eggs and 10 pounds of oranges are currently at the same price. If the price of a dozen eggs rises by 9 percent and the price of oranges rises by 6 %. How much more will it cost to buy a dozen eggs and 10 pounds of oranges . | {
"A": "5 %",
"B": "10 %",
"C": "15 %",
"D": "20 %",
"E": "25 %"
} | multiply(divide(multiply(subtract(add(add(10, multiply(divide(9, const_100), 10)), add(10, multiply(divide(6, const_100), 10))), add(10, 10)), const_100), add(10, 10)), const_2) | add(n3,n3)|divide(n1,const_100)|divide(n2,const_100)|multiply(#1,n3)|multiply(n3,#2)|add(n3,#3)|add(n3,#4)|add(#5,#6)|subtract(#7,#0)|multiply(#8,const_100)|divide(#9,#0)|multiply(#10,const_2)| | "say currently both a dozen eggs and 10 pounds of oranges cost $ 100 ( they are at the same price ) . so , to buy a dozen eggs and 10 pounds of oranges we need $ 100 . after the increase , the price of a dozen eggs will be $ 109 and the price of 10 pounds of oranges will be $ 106 . so after the increase , to buy a dozen eggs and 10 pounds of oranges we ' ll need $ 215 . increase = 15 % . answer : c ." | general |
math_qa__BitSyyFABLsgLTVt | At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 40% on the cost price?
Select:
A) 62.5 B) 69.5 C) 67.5 D) 62.5 E) 70 | <gadget id="calculator">47.5 * 40</gadget>
<output>1_900</output>
<gadget id="calculator">1_900 / 100</gadget>
<output>19</output>
<gadget id="calculator">47.5 + 19</gadget>
<output>66.5</output>
<gadget id="calculator">66.5 * 100</gadget>
<output>6_650</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">6_650 / 95</gadget>
<output>70</output>
<result>E</result> | E | 70 | At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 40% on the cost price? | {
"A": "62.5",
"B": "69.5",
"C": "67.5",
"D": "62.5",
"E": "70"
} | divide(multiply(add(47.50, divide(multiply(47.50, 40), const_100)), const_100), subtract(const_100, 5)) | multiply(n0,n2)|subtract(const_100,n1)|divide(#0,const_100)|add(n0,#2)|multiply(#3,const_100)|divide(#4,#1)| | "cp = 47.50 sp = 47.50 * ( 140 / 100 ) = 66.5 mp * ( 95 / 100 ) = 66.5 mp = 70 answer : e" | gain |
math_qa__4JN85ejlDJRn5D8z | Two friends decide to get together; so they start riding bikes towards each other. They plan to meet halfway. Each is riding at 6 MPH. They live 36 miles apart. One of them has a pet carrier pigeon and it starts flying the instant the friends start traveling. The pigeon flies back and forth at 19 MPH between the 2 friends until the friends meet. How many miles does the pigeon travel? Choose one:
A) 54 B) 57 C) 60 D) 36 E) 96 | <gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">18 / 6</gadget>
<output>3</output>
<gadget id="calculator">19 * 3</gadget>
<output>57</output>
<result>B</result> | B | 57 | Two friends decide to get together; so they start riding bikes towards each other. They plan to meet halfway. Each is riding at 6 MPH. They live 36 miles apart. One of them has a pet carrier pigeon and it starts flying the instant the friends start traveling. The pigeon flies back and forth at 19 MPH between the 2 friends until the friends meet. How many miles does the pigeon travel? | {
"A": "54",
"B": "57",
"C": "60",
"D": "36",
"E": "96"
} | multiply(19, divide(divide(36, 2), 6)) | divide(n1,n3)|divide(#0,n0)|multiply(n2,#1)| | "b 57 it takes 3 hours for the friends to meet ; so the pigeon flies for 3 hours at 19 mph = 57 miles" | physics |
math_qa__heEfD7FN4HgjkFQh | In a river flowing at 2 km/hr, a boat travels 48 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time.
Choose the correct answer: A) 10 hours B) 12 hours C) 14 hours D) 18 hours E) none of these | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">48 / 4</gadget>
<output>12</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<gadget id="calculator">12 + 6</gadget>
<output>18</output>
<result>D</result> | D | 18 | In a river flowing at 2 km/hr, a boat travels 48 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time. | {
"A": "10 hours",
"B": "12 hours",
"C": "14 hours",
"D": "18 hours",
"E": "none of these"
} | add(divide(48, subtract(6, 2)), divide(48, add(6, 2))) | add(n0,n2)|subtract(n2,n0)|divide(n1,#1)|divide(n1,#0)|add(#2,#3)| | "explanation : speed of the boat = 6 km / hr speed downstream = ( 6 + 2 ) = 8 km / hr speed upstream = ( 6 - 2 ) = 4 km / hr distance traveled downstream = distance traveled upstream = 48 km total time taken = time taken downstream + time taken upstream = ( 48 / 8 ) + ( 48 / 4 ) = 18 hr . answer : option d" | general |
math_qa__DrxcLHZBORwLgG7r | In Smithtown, the ratio of right-handed people to left-handed people is 3 to 1 and the ratio of men to women is 3 to 2. If the number of right-handed men is maximized, then what X percent of all the people in Smithtown are left-handed women? Choose the most appropriate option
A) 50 % B) 40 % C) 25 % D) 20 % E) 10 % | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">2 * (4/5)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">3 * (4/5)</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">3 - (12/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(8/5) - (3/5)</gadget>
<output>1</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | In Smithtown, the ratio of right-handed people to left-handed people is 3 to 1 and the ratio of men to women is 3 to 2. If the number of right-handed men is maximized, then what X percent of all the people in Smithtown are left-handed women? | {
"A": "50 %",
"B": "40 %",
"C": "25 %",
"D": "20 %",
"E": "10 %"
} | multiply(divide(subtract(multiply(2, divide(add(3, 1), add(3, 2))), subtract(3, multiply(3, divide(add(3, 1), add(3, 2))))), add(3, 1)), const_100) | add(n0,n1)|add(n0,n3)|divide(#0,#1)|multiply(n3,#2)|multiply(n0,#2)|subtract(n0,#4)|subtract(#3,#5)|divide(#6,#0)|multiply(#7,const_100)| | "looking at the ratio we can take total number of people = 20 . . ans 5 / 20 or 25 % c" | general |
math_qa__ZOuPFtSWk2ZfjnDw | The number of degrees that the hour hand of a clock moves through between noon and 2.30 in the afternoon of the same day is? Choose the correct answer:
A) 38
B) 27
C) 75
D) 28
E) 21 | <gadget id="calculator">floor(2.3)</gadget>
<output>2</output>
<gadget id="calculator">2.3 - 2</gadget>
<output>0.3</output>
<gadget id="calculator">0.3 / 60</gadget>
<output>0.005</output>
<gadget id="calculator">0.005 * 100</gadget>
<output>0.5</output>
<gadget id="calculator">2 + 0.5</gadget>
<output>2.5</output>
<gadget id="calculator">2.5 * 3</gadget>
<output>7.5</output>
<gadget id="calculator">7.5 * 10</gadget>
<output>75</output>
<result>C</result> | C | 75 | The number of degrees that the hour hand of a clock moves through between noon and 2.30 in the afternoon of the same day is? | {
"A": "38",
"B": "27",
"C": "75",
"D": "28",
"E": "21"
} | multiply(multiply(add(floor(2.3), multiply(divide(subtract(2.3, floor(2.3)), const_60), const_100)), const_3), const_10) | floor(n0)|subtract(n0,#0)|divide(#1,const_60)|multiply(#2,const_100)|add(#0,#3)|multiply(#4,const_3)|multiply(#5,const_10) | explanation : the hour hand moves from pointing to 12 to pointing to half way between 2 and 3 . the angle covered between each hour marking on the clock is 360 / 12 = 30 . since the hand has covered 2.5 of these divisions the angle moved through is 75 . answer : c | physics |
math_qa__KYpkAjIiSwfyb6ye | A rectangular tiled patio is composed of 30 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 30 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout? Select.
A) 5 B) 6 C) 10 D) 13 E) 28 | <gadget id="calculator">-4</gadget>
<output>-4</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">4 * 60</gadget>
<output>240</output>
<gadget id="calculator">16 + 240</gadget>
<output>256</output>
<gadget id="calculator">256 ** (1/2)</gadget>
<output>16</output>
<gadget id="calculator">(-4) + 16</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">30 / 6</gadget>
<output>5</output>
<result>A</result> | A | 5 | A rectangular tiled patio is composed of 30 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 30 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout? | {
"A": "5",
"B": "6",
"C": "10",
"D": "13",
"E": "28"
} | divide(30, divide(add(negate(4), sqrt(add(power(4, 2), multiply(4, multiply(30, 2))))), 2)) | multiply(n0,n1)|negate(n2)|power(n2,n1)|multiply(n2,#0)|add(#3,#2)|sqrt(#4)|add(#1,#5)|divide(#6,n1)|divide(n0,#7)| | "suppose there are c columns and there are r rows original situation so , number of tiles = c * r = 30 also . reach column has r tiles and each row has c tiles new situation number of tiles in each column is r - 2 and number of tiles in each row is c + 4 so , number of rows = r - 2 and number of columns is c + 4 so , number of tiles = ( r - 2 ) * ( c + 4 ) = 30 comparing both of them we get c * r = ( r - 2 ) * ( c + 4 ) = > 4 r - 2 c = 8 c = 2 r - 4 putting it in c * r = 30 ( 2 r - 4 ) * r = 30 2 r ^ 2 - 4 r - 30 = 0 r can not be negative so r = 5 and c = 6 so , answer will be a" | geometry |
math_qa__LkIxEZmDuXvyEGx5 | A row of ants comprised of 102 ants. A man walked upon it and all except 42 were crushed beneath his foot.
How many ants are left alive? Pick: A) 41 B) 42 C) 43 D) 44 E) 45 | <gadget id="calculator">42 * 1</gadget>
<output>42</output>
<result>B</result> | B | 42 | A row of ants comprised of 102 ants. A man walked upon it and all except 42 were crushed beneath his foot.
How many ants are left alive? | {
"A": "41",
"B": "42",
"C": "43",
"D": "44",
"E": "45"
} | multiply(42, const_1) | multiply(n1,const_1) | solution : all except 42 were crushed means that all the ants except 42 were crushed beneath the man ' s foot . hence , 42 ants are alive now answer b | general |
math_qa__t2BPGss7TusW1LtV | At a certain food stand, the price of each apple is 40Β’ and the price of each orange is 60Β’. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is 54Β’. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 45Β’? Pick one
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">60 * 10</gadget>
<output>600</output>
<gadget id="calculator">54 * 10</gadget>
<output>540</output>
<gadget id="calculator">600 - 540</gadget>
<output>60</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">60 / 20</gadget>
<output>3</output>
<gadget id="calculator">3 * 40</gadget>
<output>120</output>
<gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">7 * 60</gadget>
<output>420</output>
<gadget id="calculator">120 + 420</gadget>
<output>540</output>
<gadget id="calculator">45 * 10</gadget>
<output>450</output>
<gadget id="calculator">540 - 450</gadget>
<output>90</output>
<gadget id="calculator">60 - 45</gadget>
<output>15</output>
<gadget id="calculator">90 / 15</gadget>
<output>6</output>
<result>E</result> | E | 6 | At a certain food stand, the price of each apple is 40Β’ and the price of each orange is 60Β’. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is 54Β’. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 45Β’? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(subtract(add(multiply(divide(subtract(multiply(60, 10), multiply(54, 10)), subtract(60, 40)), 40), multiply(subtract(10, divide(subtract(multiply(60, 10), multiply(54, 10)), subtract(60, 40))), 60)), multiply(45, 10)), subtract(60, 45)) | multiply(n1,n2)|multiply(n2,n4)|multiply(n2,n5)|subtract(n1,n0)|subtract(n1,n5)|subtract(#0,#1)|divide(#5,#3)|multiply(n0,#6)|subtract(n2,#6)|multiply(n1,#8)|add(#7,#9)|subtract(#10,#2)|divide(#11,#4)| | "if the average price is 54 , then mary has 7 oranges and 3 apples ( a ratio of 7 : 3 ) . for the average price to be 45 , the ratio should be 1 : 3 . mary must put back 6 oranges . the answer is e ." | general |
math_qa__nzNKMM8NV3AD6Ipj | The dimensions of a rectangular solid are 6 inches, 5 inches, and 8 inches. If a cube, a side of which is equal to one of the dimensions of the rectangular solid, is placed entirely within thespherejust large enough to hold the cube, what the ratio of the volume of the cube to the volume within thespherethat is not occupied by the cube? Pick one:
A) 10 : 17 B) 2 : 5 C) 5 : 16 D) 10 : 19 E) 32 : 25 | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">16 + 2</gadget>
<output>18</output>
<gadget id="calculator">18 + 1</gadget>
<output>19</output>
<gadget id="calculator">10 / 19</gadget>
<output>10/19 = around 0.526316</output>
<result>D</result> | D | 0.526316 | The dimensions of a rectangular solid are 6 inches, 5 inches, and 8 inches. If a cube, a side of which is equal to one of the dimensions of the rectangular solid, is placed entirely within thespherejust large enough to hold the cube, what the ratio of the volume of the cube to the volume within thespherethat is not occupied by the cube? | {
"A": "10 : 17",
"B": "2 : 5",
"C": "5 : 16",
"D": "10 : 19",
"E": "32 : 25"
} | divide(const_10, add(add(multiply(8, const_2), const_2), const_1)) | multiply(n2,const_2)|add(#0,const_2)|add(#1,const_1)|divide(const_10,#2) | answer : d . | geometry |
math_qa__0TnTXHAPB6wPpazm | A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 50 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time? Choices.
A) 75 men
B) 80 men
C) 70 men
D) 60 men
E) 50 men | <gadget id="calculator">120 - 50</gadget>
<output>70</output>
<result>C</result> | C | 70 | A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 50 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time? | {
"A": "75 men",
"B": "80 men",
"C": "70 men",
"D": "60 men",
"E": "50 men"
} | subtract(120, 50) | subtract(n3,n2)| | "in 120 days , only 240 m of the tunnel is constructed by 50 men . the remaining 120 days , 480 m of the tunnel can be constructed by 120 men . additional number of men required = 120 - 50 = 70 men . answer : c" | physics |
math_qa__u3WNGa1KIVQ7vy5s | For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What is the value of <2>*<4>? Choose the correct choice from the following answers
A) 60 B) 116 C) 210 D) 263 E) 360 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">8 + 7</gadget>
<output>15</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">15 + 6</gadget>
<output>21</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">21 + 5</gadget>
<output>26</output>
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">26 + 4</gadget>
<output>30</output>
<gadget id="calculator">8 - 5</gadget>
<output>3</output>
<gadget id="calculator">30 + 3</gadget>
<output>33</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<gadget id="calculator">33 + 2</gadget>
<output>35</output>
<gadget id="calculator">8 - 7</gadget>
<output>1</output>
<gadget id="calculator">35 + 1</gadget>
<output>36</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">36 * 10</gadget>
<output>360</output>
<result>E</result> | E | 360 | For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What is the value of <2>*<4>? | {
"A": "60",
"B": "116",
"C": "210",
"D": "263",
"E": "360"
} | multiply(add(add(add(add(add(add(add(multiply(const_4, 2), subtract(multiply(const_4, 2), const_1)), subtract(multiply(const_4, 2), const_2)), subtract(multiply(const_4, 2), const_3)), subtract(multiply(const_4, 2), const_4)), subtract(multiply(const_4, 2), subtract(multiply(const_4, 2), const_3))), subtract(multiply(const_4, 2), subtract(multiply(const_4, 2), const_2))), subtract(multiply(const_4, 2), subtract(multiply(const_4, 2), const_1))), add(add(add(multiply(2, const_2), subtract(multiply(2, const_2), const_1)), subtract(multiply(2, const_2), const_2)), subtract(multiply(2, const_2), const_3))) | multiply(n1,const_4)|multiply(n1,const_2)|subtract(#0,const_1)|subtract(#0,const_2)|subtract(#0,const_3)|subtract(#0,const_4)|subtract(#1,const_1)|subtract(#1,const_2)|subtract(#1,const_3)|add(#0,#2)|add(#1,#6)|subtract(#0,#4)|subtract(#0,#3)|subtract(#0,#2)|add(#9,#3)|add(#10,#7)|add(#14,#4)|add(#15,#8)|add(#16,#5)|add(#18,#11)|add(#19,#12)|add(#20,#13)|multiply(#21,#17) | since < x > = 2 x + ( 2 x - 1 ) + ( 2 x - 2 ) + . . . . . . 2 + 1 = 1 + 2 + . . + ( 2 x - 2 ) + ( 2 x - 1 ) + 2 x then < x > is basically the sum of all integers from 1 to 2 x , inclusive . hence < 2 > is the sum of all integers from 1 to 2 * 2 = 4 and < 4 > is the sum of all integers from 1 to 2 * 4 = 8 - > < 4 > = 36 and < 2 > = 10 - - > < 3 > * < 2 > = 21 * 10 = 360 answer : e | general |
math_qa__iGrOuHuKVPsgI2xF | Pradeep has to obtain 35% of the total marks to pass. He got 150 marks and failed by 25 marks. The maximum marks are Options
A) 300
B) 600
C) 800
D) 500
E) 900 | <gadget id="calculator">150 + 25</gadget>
<output>175</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">175 / (7/20)</gadget>
<output>500</output>
<result>D</result> | D | 500 | Pradeep has to obtain 35% of the total marks to pass. He got 150 marks and failed by 25 marks. The maximum marks are | {
"A": "300",
"B": "600",
"C": "800",
"D": "500",
"E": "900"
} | divide(add(150, 25), divide(35, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "explanation : let their maximum marks be x . then , 35 % of x = 150 + 25 = > 35 / 100 x = 175 x = ( 17500 / 35 ) x = 500 . answer : d" | general |
math_qa__ZL0VDiEGbJqOZc9z | If the length of a rectangle is increased by 20% and the breadth is reduced by 20%, what will be the effect on its area?
Select the correct option
A) 4 % increase B) 6 % increase C) 5 % decrease D) 4 % decrease E) none of these | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(6/5) * (4/5)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">1 - (24/25)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) * 100</gadget>
<output>4</output>
<result>D</result> | D | 4 | If the length of a rectangle is increased by 20% and the breadth is reduced by 20%, what will be the effect on its area? | {
"A": "4 % increase",
"B": "6 % increase",
"C": "5 % decrease",
"D": "4 % decrease",
"E": "none of these"
} | multiply(subtract(const_1, multiply(add(const_1, divide(20, const_100)), subtract(const_1, divide(20, const_100)))), const_100) | divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#0)|multiply(#1,#2)|subtract(const_1,#3)|multiply(#4,const_100) | percentage change = x - y - xy β 100 = 20 β 20 β 20 Γ 20 / 100 = β 4 % = 4 % decrease answer d | geometry |
math_qa__ILVTuaBOtNNXvip1 | A and B can do a piece of work in 2 days and 6 days respectively. Both work for 1 days and then A goes away. Find how long will B take to complete the remaining work? Choose the correct choice from the following choices
A) 1 days B) 2 days C) 3 days D) 4 days E) 5 days | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/6) + (1/2)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) / (1/6)</gadget>
<output>2</output>
<result>B</result> | B | 2 | A and B can do a piece of work in 2 days and 6 days respectively. Both work for 1 days and then A goes away. Find how long will B take to complete the remaining work? | {
"A": "1 days",
"B": "2 days",
"C": "3 days",
"D": "4 days",
"E": "5 days"
} | divide(subtract(const_1, add(divide(1, 6), divide(1, 2))), divide(1, 6)) | divide(n2,n1)|divide(n2,n0)|add(#0,#1)|subtract(const_1,#2)|divide(#3,#0) | 1 / 2 + ( 1 + x ) / 6 = 1 x = 2 days answer : b | physics |
math_qa__5jmPwGIYj8AtktBj | Karen places a bet with Tom that she will beat Tom in a car race by 4 miles even if Karen starts 4 minutes late. Assuming that Karen drives at an average speed of 60 mph and Tom drives at an average speed of 45 mph, how many H miles will Tom drive before Karen wins the bet? Choose the correct choice from the following: A) 15 B) 18 C) 21 D) 24 E) 27 | <gadget id="calculator">45 / 60</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 4</gadget>
<output>3</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">60 / 60</gadget>
<output>1</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">7 / (1/4)</gadget>
<output>28</output>
<gadget id="calculator">28 - 4</gadget>
<output>24</output>
<result>D</result> | D | 24 | Karen places a bet with Tom that she will beat Tom in a car race by 4 miles even if Karen starts 4 minutes late. Assuming that Karen drives at an average speed of 60 mph and Tom drives at an average speed of 45 mph, how many H miles will Tom drive before Karen wins the bet? | {
"A": "15",
"B": "18",
"C": "21",
"D": "24",
"E": "27"
} | subtract(divide(add(multiply(divide(45, 60), 4), 4), subtract(divide(60, 60), divide(45, 60))), 4) | divide(n3,n2)|divide(n2,n2)|multiply(n0,#0)|subtract(#1,#0)|add(n0,#2)|divide(#4,#3)|subtract(#5,n0)| | "let k and t be the speeds of karen and tom respectively . t be the time that karen will travel - - - - > t + 4 / 60 will be the total time tom will travel by the time the distance between karen and tom is 4 miles . thus , per the question , k ( t ) - t ( t + 4 / 60 ) = 4 - - - > t = 7 / 15 hours thus the distance traveled by tom when karen is 4 miles ahead of him h : t * ( t + 4 / 60 ) = 45 ( 7 / 15 + 4 / 60 ) = 24 miles . d is the correct answer ." | physics |
math_qa__v6UXLcvLh43BVyWA | Rs.1210 were divided among 3 person P, Q, R so that P:Q=5:4 and Q: R=9:10. Then R gets the amount. Choose the correct choice from the following.
A) rs . 300
B) rs . 400
C) rs . 480
D) rs . 490
E) rs . 500 | <gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">10 / 9</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">(5/4) + (10/9)</gadget>
<output>85/36 = around 2.361111</output>
<gadget id="calculator">(85/36) + 1</gadget>
<output>121/36 = around 3.361111</output>
<gadget id="calculator">1_210 / (121/36)</gadget>
<output>360</output>
<gadget id="calculator">360 * (10/9)</gadget>
<output>400</output>
<result>B</result> | B | 400 | Rs.1210 were divided among 3 person P, Q, R so that P:Q=5:4 and Q: R=9:10. Then R gets the amount. | {
"A": "rs . 300",
"B": "rs . 400",
"C": "rs . 480",
"D": "rs . 490",
"E": "rs . 500"
} | multiply(divide(1210, add(add(divide(5, 4), divide(10, 9)), const_1)), divide(10, 9)) | divide(n2,n3)|divide(n5,n4)|add(#0,#1)|add(#2,const_1)|divide(n0,#3)|multiply(#4,#1)| | "p : q = 5 : 4 , q : r = 9 : 10 = ( 9 x 4 / 9 ) : ( 10 x 4 / 9 ) = 4 : 40 / 9 . so , p : q : r = 5 : 4 : 40 / 9 = 45 : 36 : 40 sum of ratio terms is = ( 45 + 36 + 40 ) = 121 . r share of amount is rs ( 1210 x 40 / 121 ) = rs . 400 . b" | general |
math_qa__4oUOY4wIAsOM91My | In what ratio should a variety of Rice costing Rs. 7 per kg be mixed with another variety of Rice costing Rs. 14.50 per kg to obtain a mixture costing Rs. 9.75 per kg?
Choose the correct answer
A) 19 : 10 B) 19 : 11 C) 11 : 19 D) 12 : 18 E) 11 : 20 | <gadget id="calculator">14.5 - 9.75</gadget>
<output>4.75</output>
<gadget id="calculator">14.5 - 7</gadget>
<output>7.5</output>
<gadget id="calculator">4.75 / 7.5</gadget>
<output>0.633333</output>
<gadget id="calculator">1 - 0.633333</gadget>
<output>0.366667</output>
<gadget id="calculator">0.633333 / 0.366667</gadget>
<output>1.72727</output>
<result>B</result> | B | 1.727273 | In what ratio should a variety of Rice costing Rs. 7 per kg be mixed with another variety of Rice costing Rs. 14.50 per kg to obtain a mixture costing Rs. 9.75 per kg? | {
"A": "19 : 10",
"B": "19 : 11",
"C": "11 : 19",
"D": "12 : 18",
"E": "11 : 20"
} | divide(divide(subtract(14.50, 9.75), subtract(14.50, 7)), subtract(const_1, divide(subtract(14.50, 9.75), subtract(14.50, 7)))) | subtract(n1,n2)|subtract(n1,n0)|divide(#0,#1)|subtract(const_1,#2)|divide(#2,#3)| | "let us say the ratio of the quantities of cheaper and dearer varieties = x : y by the rule of allegation , x / y = ( 14.50 - 9.75 ) / ( 9.75 - 7 ) = 31 / 15 answer : b" | other |
math_qa__2uSVYxFItwxcNaQy | If 10 is added to thrice a number and this sum is multiplied by 5, the result is the same as if the number is multiplied by 5 and 13 is added to the product. What is the number?
Choose one:
A) - 3.5 B) - 3.7 C) - 5 D) - 9 E) 11 | <gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">50 - 13</gadget>
<output>37</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">5 - 15</gadget>
<output>-10</output>
<gadget id="calculator">37 / (-10)</gadget>
<output>-37/10 = around -3.7</output>
<result>B</result> | B | -3.7 | If 10 is added to thrice a number and this sum is multiplied by 5, the result is the same as if the number is multiplied by 5 and 13 is added to the product. What is the number? | {
"A": "- 3.5",
"B": "- 3.7",
"C": "- 5",
"D": "- 9",
"E": "11"
} | divide(subtract(multiply(10, 5), 13), subtract(5, multiply(const_3, 5))) | multiply(n0,n1)|multiply(n1,const_3)|subtract(#0,n3)|subtract(n2,#1)|divide(#2,#3)| | "let the number be x ; 5 ( 10 + 3 x ) = 5 x + 13 ; x = - 3.7 answer : b" | general |
math_qa__xVuV3onVIvVkcFBc | If a2 + b2 + c2 = 390 and ab + bc + ca = 5, then a + b + c is
Choose the correct choice from the following answers: A) 19 B) 20 C) 25 D) 30 E) 64 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">390 + 10</gadget>
<output>400</output>
<gadget id="calculator">400 ** (1/2)</gadget>
<output>20</output>
<result>B</result> | B | 20 | If a2 + b2 + c2 = 390 and ab + bc + ca = 5, then a + b + c is | {
"A": "19",
"B": "20",
"C": "25",
"D": "30",
"E": "64"
} | sqrt(add(390, multiply(5, const_2))) | multiply(n4,const_2)|add(n3,#0)|sqrt(#1) | by formula , ( a + b + c ) ^ 2 = a ^ 2 + b ^ 2 + c ^ 2 + 2 ( ab + bc + ca ) , since , a ^ 2 + b ^ 2 + c ^ 2 = 390 and ab + bc + ca = 5 , ( a + b + c ) ^ 2 = 390 + 2 ( 5 ) = 400 = 20 ^ 2 therefore : a + b + c = 20 answer : b | general |
math_qa__5MBC9V9CtwN9uE5y | In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1500 employees, then the no. of female employees who are computer literate ? Choices:
A) 630
B) 674
C) 672
D) 960
E) none | <gadget id="calculator">62 / 100</gadget>
<output>31/50 = around 0.62</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(2/5) * (1/2)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(31/50) - (1/5)</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">(21/50) * 1_500</gadget>
<output>630</output>
<result>A</result> | A | 630 | In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1500 employees, then the no. of female employees who are computer literate ? | {
"A": "630",
"B": "674",
"C": "672",
"D": "960",
"E": "none"
} | multiply(subtract(divide(62, const_100), multiply(subtract(const_1, divide(60, const_100)), divide(50, const_100))), 1500) | divide(n2,const_100)|divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#2)|multiply(#1,#3)|subtract(#0,#4)|multiply(n3,#5)| | "solution : total employees , = 1500 female employees , 60 % of 1500 . = ( 60 * 1500 ) / 100 = 900 . then male employees , = 600 50 % of male are computer literate , = 300 male computer literate . 62 % of total employees are computer literate , = ( 62 * 1500 ) / 100 = 930 computer literate . thus , female computer literate = 930 - 300 = 630 answer : option a" | gain |
math_qa__dYO4qFkOxN0XTO6K | A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be Choose the correct choice from the following:
A) 22 B) 24 C) 26 D) 20 E) 18 | <gadget id="calculator">48 * 4</gadget>
<output>192</output>
<gadget id="calculator">192 - 140</gadget>
<output>52</output>
<gadget id="calculator">52 / 2</gadget>
<output>26</output>
<result>C</result> | C | 26 | A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be | {
"A": "22",
"B": "24",
"C": "26",
"D": "20",
"E": "18"
} | divide(subtract(multiply(48, const_4), 140), const_2) | multiply(n0,const_4)|subtract(#0,n1)|divide(#1,const_2) | let number of hens = h number of cows = c number of heads = 48 β h + c = 48 β― ( 1 ) number of feet = 140 β 2 h + 4 c = 140 β h + 2 c = 70 β― ( 2 ) ( 2 ) β ( 1 ) gives 2 c β c = 70 β 48 β c = 22 substituting the value of c in ( 1 ) , we get h + 22 = 48 β h = 48 β 22 = 26 h + 22 = 48 β h = 48 β 22 = 26 i . e . , number of hens = 26 answer : c | general |
math_qa__ScnHYjoMAG4RkUVw | The cash realised on selling a 14% stock is Rs.120.50, brokerage being 1/4% is Choose one: A) 120.25 B) 120.35 C) 106.5 D) 156 E) 240 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">120.5 - (1/4)</gadget>
<output>120.25</output>
<result>A</result> | A | 120.25 | The cash realised on selling a 14% stock is Rs.120.50, brokerage being 1/4% is | {
"A": "120.25",
"B": "120.35",
"C": "106.5",
"D": "156",
"E": "240"
} | subtract(120.50, divide(1, 4)) | divide(n2,n3)|subtract(n1,#0)| | "explanation : cash realised = rs . ( 120.50 - 0.25 ) = rs . 120.25 . answer : a" | general |
math_qa__iMLqdD3xueEwudW1 | An equilateral triangle T2 is formed by joining the mid points of the sides of another equilateral triangle T1. A third equilateral triangle T3 is formed by joining the mid-points of T2 and this process is continued indefinitely. If each side of T1 is 50 cm, find the sum of the perimeters of all the triangles. Choices.
A) 180 cm B) 220 cm C) 240 cm D) 270 cm E) 300 cm | <gadget id="calculator">50 + 50 + 50</gadget>
<output>150</output>
<gadget id="calculator">150 + 150</gadget>
<output>300</output>
<result>E</result> | E | 300 | An equilateral triangle T2 is formed by joining the mid points of the sides of another equilateral triangle T1. A third equilateral triangle T3 is formed by joining the mid-points of T2 and this process is continued indefinitely. If each side of T1 is 50 cm, find the sum of the perimeters of all the triangles. | {
"A": "180 cm",
"B": "220 cm",
"C": "240 cm",
"D": "270 cm",
"E": "300 cm"
} | add(triangle_perimeter(50, 50, 50), triangle_perimeter(50, 50, 50)) | triangle_perimeter(n5,n5,n5)|add(#0,#0)| | "we have 50 for first triangle , when we join mid - points of first triangle we get the second equilateral triangle then the length of second one is 25 and continues . so we have 50,25 , 12.5 , . . . we have ratio = 1 / 2 , and it is gp type . sum of infinite triangle is a / 1 - r = 50 / 1 - ( 1 / 2 ) = 100 equilateral triangle perimeter is 3 a = 3 * 100 = 300 . so option e ." | geometry |
math_qa__LE7H2lokvYIsdrdO | Three walls have wallpaper covering a combined area of 300 square meters. By overlapping the wallpaper to cover a wall with an area of 180 square meters, the area that is covered by exactly two layers of wallpaper is 40 square meters. What is the area that is covered with three layers of wallpaper? Choose the correct choice from the following answers.
A) 5 square meters
B) 36 square meters
C) 40 square meters
D) 83.3 square meters
E) 120 square meters | <gadget id="calculator">300 - 180</gadget>
<output>120</output>
<gadget id="calculator">120 - 40</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>C</result> | C | 40 | Three walls have wallpaper covering a combined area of 300 square meters. By overlapping the wallpaper to cover a wall with an area of 180 square meters, the area that is covered by exactly two layers of wallpaper is 40 square meters. What is the area that is covered with three layers of wallpaper? | {
"A": "5 square meters",
"B": "36 square meters",
"C": "40 square meters",
"D": "83.3 square meters",
"E": "120 square meters"
} | divide(subtract(subtract(300, 180), 40), const_2) | subtract(n0,n1)|subtract(#0,n2)|divide(#1,const_2)| | "300 - 180 = 120 sq m of the wallpaper overlaps ( in either two layers or three layers ) if 36 sq m has two layers , 120 - 40 = 80 sq m of the wallpaper overlaps in three layers . 80 sq m makes two extra layers hence the area over which it makes two extra layers is 40 sq m . answer ( c ) ." | geometry |
math_qa__p6ymIbG9eXbs3PA8 | A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 4x km. Choose the correct choice from the following answers.
A) 16 B) 18 C) 32 D) 19 E) 12 | <gadget id="calculator">40 * 4</gadget>
<output>160</output>
<gadget id="calculator">40 / 40</gadget>
<output>1</output>
<gadget id="calculator">2 * 40</gadget>
<output>80</output>
<gadget id="calculator">80 / 20</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">160 / 5</gadget>
<output>32</output>
<result>C</result> | C | 32 | A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 4x km. | {
"A": "16",
"B": "18",
"C": "32",
"D": "19",
"E": "12"
} | divide(multiply(40, 4), add(divide(40, 40), divide(multiply(2, 40), 20))) | divide(n0,n0)|multiply(n0,n3)|multiply(n0,n1)|divide(#2,n2)|add(#0,#3)|divide(#1,#4)| | "total time taken = x / 40 + 2 x / 20 hours = 5 x / 40 = x / 8 hours average speed = 4 x / ( x / 8 ) = 32 kmph answer : c" | general |
math_qa__baf9CbBEajNLdGOF | Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.240 in 2 years? Choose the correct answer:
A) 217 B) 287 C) 400 D) 288 E) 171 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">240 / (441/400)</gadget>
<output>32_000/147 = around 217.687075</output>
<result>A</result> | A | 217 | Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.240 in 2 years? | {
"A": "217",
"B": "287",
"C": "400",
"D": "288",
"E": "171"
} | divide(240, power(add(const_1, divide(5, const_100)), 2)) | divide(n0,const_100)|add(#0,const_1)|power(#1,n2)|divide(n1,#2)| | "explanation : 240 = p ( 21 / 20 ) 2 p = 217 answer : a" | general |
math_qa__fePiv0ndA4YcvxQo | A bag contains 7 green balls and 7 white balls. If two balls are drawn simultaneously, what is the probability that both balls are the same colour? Choose the correct choice from the following: A) 4 / 13 B) 6 / 13 C) 8 / 21 D) 11 / 21 E) 17 / 42 | <gadget id="calculator">7 + 7</gadget>
<output>14</output>
<gadget id="calculator">7 / 14</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">14 - 1</gadget>
<output>13</output>
<gadget id="calculator">6 / 13</gadget>
<output>6/13 = around 0.461538</output>
<gadget id="calculator">(1/2) * (6/13)</gadget>
<output>3/13 = around 0.230769</output>
<gadget id="calculator">(6/13) * (1/2)</gadget>
<output>3/13 = around 0.230769</output>
<gadget id="calculator">(3/13) + (3/13)</gadget>
<output>6/13 = around 0.461538</output>
<result>B</result> | B | 0.461538 | A bag contains 7 green balls and 7 white balls. If two balls are drawn simultaneously, what is the probability that both balls are the same colour? | {
"A": "4 / 13",
"B": "6 / 13",
"C": "8 / 21",
"D": "11 / 21",
"E": "17 / 42"
} | add(multiply(divide(7, add(7, 7)), divide(subtract(7, const_1), subtract(add(7, 7), const_1))), multiply(divide(subtract(7, const_1), subtract(add(7, 7), const_1)), divide(7, add(7, 7)))) | add(n0,n1)|subtract(n1,const_1)|subtract(n0,const_1)|divide(n1,#0)|divide(n0,#0)|subtract(#0,const_1)|divide(#1,#5)|divide(#2,#5)|multiply(#3,#6)|multiply(#7,#4)|add(#8,#9)| | "the total number of ways to draw two balls is 14 c 2 = 91 the number of ways to draw two green balls is 7 c 2 = 21 the number of ways to draw two white balls is 7 c 2 = 21 p ( two balls of the same colour ) = 42 / 91 = 6 / 13 the answer is b ." | other |
math_qa__R7kCfTyIWPJjYaBz | A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next day he sells 50 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw? Select the correct option.
A) 17 B) 23 C) 77 D) 26 E) 30 | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">40 * (3/20)</gadget>
<output>6</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">40 - 6</gadget>
<output>34</output>
<gadget id="calculator">(1/2) * 34</gadget>
<output>17</output>
<gadget id="calculator">6 + 17</gadget>
<output>23</output>
<result>B</result> | B | 23 | A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next day he sells 50 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw? | {
"A": "17",
"B": "23",
"C": "77",
"D": "26",
"E": "30"
} | add(multiply(subtract(const_100, 60), divide(15, const_100)), multiply(divide(50, const_100), subtract(subtract(const_100, 60), multiply(subtract(const_100, 60), divide(15, const_100))))) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_100,n0)|multiply(#0,#2)|subtract(#2,#3)|multiply(#1,#4)|add(#3,#5) | explanation : let , the number of apples be 100 . on the first day he sells 60 % apples i . e . , 60 apples . remaining apples = 40 . he throws 15 % of the remaining i . e . , 15 % of 40 = 6 . now he has 40 β 6 = 34 apples the next day he throws 50 % of the remaining 34 apples i . e . , 17 . therefore , in total he throws 6 + 17 = 23 apples . answer : b | gain |
math_qa__krBTa9Xi5addtpRl | Average of money that group of 4 friends pay for rent each month is $800.After one persons rent is increased by 20% the new mean is $880.What was original rent of friend whose rent is increased? Select the correct option.
A) 800 B) 900 C) 1600 D) 1100 E) 1200 | <gadget id="calculator">880 - 800</gadget>
<output>80</output>
<gadget id="calculator">80 * 4</gadget>
<output>320</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">320 / (1/5)</gadget>
<output>1_600</output>
<result>C</result> | C | 1,600 | Average of money that group of 4 friends pay for rent each month is $800.After one persons rent is increased by 20% the new mean is $880.What was original rent of friend whose rent is increased? | {
"A": "800",
"B": "900",
"C": "1600",
"D": "1100",
"E": "1200"
} | divide(multiply(subtract(880, 800), 4), divide(20, const_100)) | divide(n2,const_100)|subtract(n3,n1)|multiply(n0,#1)|divide(#2,#0) | 0.2 x = 4 ( 880 - 800 ) 0.2 x = 320 x = 1600 answer c | general |
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