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math_qa__UtID2NBH2Mv4ExwO | When a student Joe, weighing 43 kg, joins a group of students whose average weight is 30 kg, the average weight goes up by 1 kg. Subsequently, if two students, excluding Joe, leave the group the average weight comes back to 30 kg. What is the difference between the average weight of the two students who left and the weight of Joe? Choices: A) 5.5 kg B) 11 kg C) 30 kg D) 6.5 kg E) 71 kg | <gadget id="calculator">30 + 1</gadget>
<output>31</output>
<gadget id="calculator">43 - 31</gadget>
<output>12</output>
<gadget id="calculator">30 * 12</gadget>
<output>360</output>
<gadget id="calculator">360 + 43</gadget>
<output>403</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 30</gadget>
<output>330</output>
<gadget id="calculator">403 - 330</gadget>
<output>73</output>
<gadget id="calculator">73 / 2</gadget>
<output>73/2 = around 36.5</output>
<gadget id="calculator">43 - (73/2)</gadget>
<output>13/2 = around 6.5</output>
<result>D</result> | D | 6.5 | When a student Joe, weighing 43 kg, joins a group of students whose average weight is 30 kg, the average weight goes up by 1 kg. Subsequently, if two students, excluding Joe, leave the group the average weight comes back to 30 kg. What is the difference between the average weight of the two students who left and the weight of Joe? | {
"A": "5.5 kg",
"B": "11 kg",
"C": "30 kg",
"D": "6.5 kg",
"E": "71 kg"
} | subtract(43, divide(subtract(add(multiply(30, subtract(43, add(30, 1))), 43), multiply(subtract(subtract(43, add(30, 1)), 1), 30)), const_2)) | add(n1,n2)|subtract(n0,#0)|multiply(n1,#1)|subtract(#1,n2)|add(n0,#2)|multiply(n1,#3)|subtract(#4,#5)|divide(#6,const_2)|subtract(n0,#7)| | "after two persons leave the group the average remains the same . that means the weight of the two persons = 43 + 30 = 73 so , the average the two persons = 36.5 that gives the answer 43 - 36.5 = 6.5 answer d" | general |
math_qa__RNiUUL2gVIFUpAIa | The speed of a train is 90 kmph. What is the distance covered by it in 30 minutes? Select:
A) 15 B) 66 C) 77 D) 52 E) 45 | <gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 90</gadget>
<output>45</output>
<result>E</result> | E | 45 | The speed of a train is 90 kmph. What is the distance covered by it in 30 minutes? | {
"A": "15",
"B": "66",
"C": "77",
"D": "52",
"E": "45"
} | multiply(divide(30, const_60), 90) | divide(n1,const_60)|multiply(n0,#0)| | "90 * 30 / 60 = 45 kmph answer : e" | physics |
math_qa__qv1YYiUa9K78mCZo | In a kilometer race, A beats B by 60 meters or 15 seconds. What time does A take to complete the race? Choose the correct choice from the following answers.
A) 221 B) 235 C) 245 D) 289 E) 260 | <gadget id="calculator">1 * 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">60 / 15</gadget>
<output>4</output>
<gadget id="calculator">1_000 / 4</gadget>
<output>250</output>
<gadget id="calculator">250 - 15</gadget>
<output>235</output>
<result>B</result> | B | 235 | In a kilometer race, A beats B by 60 meters or 15 seconds. What time does A take to complete the race? | {
"A": "221",
"B": "235",
"C": "245",
"D": "289",
"E": "260"
} | subtract(divide(multiply(const_1, const_1000), divide(60, 15)), 15) | divide(n0,n1)|multiply(const_1,const_1000)|divide(#1,#0)|subtract(#2,n1)| | "time taken by b run 1000 meters = ( 1000 * 15 ) / 60 = 250 sec . time taken by a = 250 - 15 = 235 sec . answer : b" | physics |
math_qa__xXtR25H043Irxusx | In a certain diving competition, 5 judges score each dive on a scale from 1 to 10. The point value of the dive is obtained by dropping the highest score and the lowest score and multiplying the sum of the remaining scores by the degree of difficulty. If a dive with a degree of difficulty of 3.2 received scores of 7.5, 8.3, 9.0, 6.0, and 8.6, what was the point value of the dive? Pick one: A) 78.08 B) 73.6 C) 75.2 D) 76.8 E) 81.6 | <gadget id="calculator">7.5 + 8.3</gadget>
<output>15.8</output>
<gadget id="calculator">15.8 + 8.6</gadget>
<output>24.4</output>
<gadget id="calculator">24.4 * 3.2</gadget>
<output>78.08</output>
<result>A</result> | A | 78.08 | In a certain diving competition, 5 judges score each dive on a scale from 1 to 10. The point value of the dive is obtained by dropping the highest score and the lowest score and multiplying the sum of the remaining scores by the degree of difficulty. If a dive with a degree of difficulty of 3.2 received scores of 7.5, 8.3, 9.0, 6.0, and 8.6, what was the point value of the dive? | {
"A": "78.08",
"B": "73.6",
"C": "75.2",
"D": "76.8",
"E": "81.6"
} | multiply(add(add(7.5, 8.3), 8.6), 3.2) | add(n4,n5)|add(n8,#0)|multiply(n3,#1)| | "degree of difficulty of dive = 3.2 scores are 6.0 , 7.5 , 8.0 , 8.5 and 9.0 we can drop 6.0 and 9.0 sum of the remaining scores = ( 7.5 + 8.3 + 8.6 ) = 24 point of value of the dive = 24.4 * 3.2 = 78.08 answer a" | general |
math_qa__FDgHCtt5laFB3Sfp | Train starts from amritsar to Bombay at 9am. It reaches destination after 3days at 9:30am. Every day a train starts. How many trains does it come across on the way ? Pick:
A) 5 th B) 4 th C) 6 th D) 7 th E) 8 th | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<result>B</result> | B | 4 | Train starts from amritsar to Bombay at 9am. It reaches destination after 3days at 9:30am. Every day a train starts. How many trains does it come across on the way ? | {
"A": "5 th",
"B": "4 th",
"C": "6 th",
"D": "7 th",
"E": "8 th"
} | add(3, const_1) | add(n1,const_1) | because one train taking 3 days so 1 train first day another at second day and 3 rd one at third day but as given train reaches at 9.30 am insted of 9 . oo am so d same day train already left that train will be 4 th train . answer : b | physics |
math_qa__Zo9AbE2xxYpIavqq | At what rate percent per annum will the simple interest on a sum of money be 1/5 of the amount in 10 years? Choose the correct answer:
A) 2 %
B) 7 %
C) 9 %
D) 3 %
E) 1 % | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<gadget id="calculator">20 / 10</gadget>
<output>2</output>
<result>A</result> | A | 2 | At what rate percent per annum will the simple interest on a sum of money be 1/5 of the amount in 10 years? | {
"A": "2 %",
"B": "7 %",
"C": "9 %",
"D": "3 %",
"E": "1 %"
} | divide(multiply(divide(1, 5), const_100), 10) | divide(n0,n1)|multiply(#0,const_100)|divide(#1,n2)| | "let sum = x . then , s . i . = x / 5 , time = 10 years . rate = ( 100 * x ) / ( x * 5 * 10 ) = 2 % answer : a" | gain |
math_qa__JSc4JoWLO9BsCBFK | In a neighborhood having 90 households, 11 did not have either a car or a bike. If 22 households had a both a car and a bike and 44 had a car, how many had bike only? Pick:
A) 30
B) 35
C) 20
D) 18
E) 10 | <gadget id="calculator">90 - 11</gadget>
<output>79</output>
<gadget id="calculator">79 + 22</gadget>
<output>101</output>
<gadget id="calculator">101 - 44</gadget>
<output>57</output>
<gadget id="calculator">57 - 22</gadget>
<output>35</output>
<result>B</result> | B | 35 | In a neighborhood having 90 households, 11 did not have either a car or a bike. If 22 households had a both a car and a bike and 44 had a car, how many had bike only? | {
"A": "30",
"B": "35",
"C": "20",
"D": "18",
"E": "10"
} | subtract(subtract(add(subtract(90, 11), 22), 44), 22) | subtract(n0,n1)|add(n2,#0)|subtract(#1,n3)|subtract(#2,n2) | { total } = { car } + { bike } - { both } + { neither } - - > 90 = 44 + { bike } - 22 + 11 - - > { bike } = 57 - - > # those who have bike only is { bike } - { both } = 57 - 22 = 35 . answer : b . | other |
math_qa__C82AjxNqp3U6o7kX | The 3 digits of a number add up to 11. The number is divisible by 5. The leftmost digit is double the middle digit. What is the product of the 3 digits? Choose one:
A) 38 B) 40 C) 78 D) 88 E) 125 | <gadget id="calculator">11 - 5</gadget>
<output>6</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 5</gadget>
<output>40</output>
<result>B</result> | B | 40 | The 3 digits of a number add up to 11. The number is divisible by 5. The leftmost digit is double the middle digit. What is the product of the 3 digits? | {
"A": "38",
"B": "40",
"C": "78",
"D": "88",
"E": "125"
} | multiply(multiply(multiply(divide(subtract(11, 5), 3), const_2), divide(subtract(11, 5), 3)), 5) | subtract(n1,n2)|divide(#0,n0)|multiply(#1,const_2)|multiply(#1,#2)|multiply(n2,#3) | xyz is a 3 digit integer divisible by 5 . so z can take only 0 or 5 . we are also given that x = 2 y this means x + y ( 2 y + y ) must be a multiple of 3 xy 5 or xy 0 case 1 x + y + 0 = 11 x + y = 11 this ca n ' t be the case because 11 is not a multiple of 3 case 2 x + y + 5 = 11 x + y = 6 solving we get , x = 4 y = 2 so the 3 digit number is 425 thus the product of the digits will be = 4 x 2 x 5 = 40 answer b | general |
math_qa__2bji8leU4tWHOqgw | If a randomly selected positive single digit multiple of 3 is multiplied by a randomly selected prime number less than 20, what is the probability T that this product will be a multiple of 45? Choose the correct choice from the following options:
A) 1 / 32 B) 1 / 28 C) 1 / 24 D) 1 / 16 E) 1 / 14 | <gadget id="calculator">20 + 4</gadget>
<output>24</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<result>C</result> | C | 0.041667 | If a randomly selected positive single digit multiple of 3 is multiplied by a randomly selected prime number less than 20, what is the probability T that this product will be a multiple of 45? | {
"A": "1 / 32",
"B": "1 / 28",
"C": "1 / 24",
"D": "1 / 16",
"E": "1 / 14"
} | divide(const_1, add(20, const_4)) | add(n1,const_4)|divide(const_1,#0)| | "there are 3 single digit multiple of 3 , that is , 3 , 6,9 . there are 8 prime nos less than 20 - 2,3 , 5,7 , 11,13 , 17,19 total outcome - 8 * 3 = 24 favourable outcome = 1 ( 9 * 5 ) hence required probability t = 1 / 24 . answer c ." | general |
math_qa__mNa0fuQam2gD7Y0h | UBA Capital recently bought Brand new vehicles for office use. UBA capital only went for Toyota and Honda and bought more of Toyota than Honda at the ratio of 8:2. If 80% of the Toyota bought and 20% of the Honda bought were SUV’s. How many SUV’s did UBA capital buy in the aforementioned purchase? Choose the correct choice from the following answers.
A) 66 % B) 64 % C) 68 % D) 69 % E) 72 % | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">2 * 8</gadget>
<output>16</output>
<gadget id="calculator">16 + 16</gadget>
<output>32</output>
<gadget id="calculator">100 - 32</gadget>
<output>68</output>
<result>C</result> | C | 68 | UBA Capital recently bought Brand new vehicles for office use. UBA capital only went for Toyota and Honda and bought more of Toyota than Honda at the ratio of 8:2. If 80% of the Toyota bought and 20% of the Honda bought were SUV’s. How many SUV’s did UBA capital buy in the aforementioned purchase? | {
"A": "66 %",
"B": "64 %",
"C": "68 %",
"D": "69 %",
"E": "72 %"
} | subtract(const_100, add(multiply(8, 2), multiply(2, 8))) | multiply(n0,n1)|add(#0,#0)|subtract(const_100,#1)| | "let total no of vehicles bought be 100 , toyota 80 and honda 20 , so total number of suv ' s bought for toyota and honda respectively 80 * 80 / 100 = 64 and 20 * 20 / 100 = 4 so total 68 suv ' s were bought out of 100 vehicles bought . . so required % is 68 % answer : c" | other |
math_qa__4dYC3ewo1z7IDMcI | 10^(655) ÷ 10^(650) = ? Pick one: A) 100 B) 10 C) 10000 D) 100000 E) 1000000 | <gadget id="calculator">655 - 650</gadget>
<output>5</output>
<gadget id="calculator">10 ** 5</gadget>
<output>100_000</output>
<result>D</result> | D | 100,000 | 10^(655) ÷ 10^(650) = ? | {
"A": "100",
"B": "10",
"C": "10000",
"D": "100000",
"E": "1000000"
} | power(10, subtract(655, 650)) | subtract(n1,n3)|power(n0,#0)| | "10 ^ ( 655 ) ã · 10 ^ ( 651 ) = 10 ^ ( 655 - 651 ) = 10 ^ 5 = 100000 answer : d" | general |
math_qa__180P2J0eknlKp9RE | A corporation that had $115.19 billion in profits for the year paid out $250.10 million in employee benefits. Approximately what percent of the profits were the employee benefits? (Note: 1 billion = 10^9) Choose the correct choice from the following answers.
A) 50 % B) 20 % C) 5 % D) 2 % E) 0.22 % | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">10 ** 6</gadget>
<output>1_000_000</output>
<gadget id="calculator">250.1 * 1_000_000</gadget>
<output>250_100_000</output>
<gadget id="calculator">10 ** 9</gadget>
<output>1_000_000_000</output>
<gadget id="calculator">115.19 * 1_000_000_000</gadget>
<output>115_190_000_000</output>
<gadget id="calculator">250_100_000 / 115_190_000_000</gadget>
<output>2_501/1_151_900 = around 0.002171</output>
<gadget id="calculator">(2_501/1_151_900) * 100</gadget>
<output>2_501/11_519 = around 0.21712</output>
<result>E</result> | E | 0.22 | A corporation that had $115.19 billion in profits for the year paid out $250.10 million in employee benefits. Approximately what percent of the profits were the employee benefits? (Note: 1 billion = 10^9) | {
"A": "50 %",
"B": "20 %",
"C": "5 %",
"D": "2 %",
"E": "0.22 %"
} | multiply(divide(multiply(250.10, power(10, add(const_3, const_3))), multiply(115.19, power(10, 9))), const_100) | add(const_3,const_3)|power(n3,n4)|multiply(n0,#1)|power(n3,#0)|multiply(n1,#3)|divide(#4,#2)|multiply(#5,const_100)| | "required answer = [ employee benefit / profit ] * 100 = [ ( 250.10 million ) / ( 115.19 billion ) ] * 100 = [ ( 250.10 * 10 ^ 6 ) / ( 115.19 * 10 ^ 9 ) ] * 100 = ( 2.2 / 1000 ) * 100 = 0.22 % so answer is ( e )" | general |
math_qa__VW6mFo2RGBeHJrT2 | The average (arithmetic mean) of 16 students first quiz scores in a difficult English class is 62.5. When one student dropped the class, the average of the remaining scores increased to 62.0. What is the quiz score of the student who dropped the class? Select:
A) 10 B) 25 C) 40 D) 55 E) 70 | <gadget id="calculator">16 * 62.5</gadget>
<output>1_000</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<gadget id="calculator">15 * 62</gadget>
<output>930</output>
<gadget id="calculator">1_000 - 930</gadget>
<output>70</output>
<result>E</result> | E | 70 | The average (arithmetic mean) of 16 students first quiz scores in a difficult English class is 62.5. When one student dropped the class, the average of the remaining scores increased to 62.0. What is the quiz score of the student who dropped the class? | {
"A": "10",
"B": "25",
"C": "40",
"D": "55",
"E": "70"
} | subtract(multiply(16, 62.5), multiply(subtract(16, const_1), 62.0)) | multiply(n0,n1)|subtract(n0,const_1)|multiply(n2,#1)|subtract(#0,#2)| | "total score of 16 students is 16 * 62.50 = 1000 total score of 15 students is 15 * 62 = 930 so , the score of the person who left is 70 ( 1000 - 930 ) answer will be ( e )" | general |
math_qa__ADSeet4hxOsWVvsk | The triplicate ratio of 2:3 is? Choose the correct choice from the following answers: A) 1 : 64 B) 1 : 62 C) 1 : 34 D) 8 : 27 E) 5 : 64 | <gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">8 / 27</gadget>
<output>8/27 = around 0.296296</output>
<result>D</result> | D | 0.296296 | The triplicate ratio of 2:3 is? | {
"A": "1 : 64",
"B": "1 : 62",
"C": "1 : 34",
"D": "8 : 27",
"E": "5 : 64"
} | divide(power(2, const_3), power(3, const_3)) | power(n0,const_3)|power(n1,const_3)|divide(#0,#1) | 2 ^ 3 : 3 ^ 3 = 8 : 27 answer : d | other |
math_qa__jyo2cod18w2vrkVJ | If 15 lions can kill 15 deers in 15 minutes how long will it take 100 lions to kill 100 deers? Choose the most appropriate option
A) 1 minutes B) 15 minute C) 100 minutes D) 10000 minutes E) 1000 minutes | <gadget id="calculator">15 / 15</gadget>
<output>1</output>
<gadget id="calculator">1 * 15</gadget>
<output>15</output>
<result>B</result> | B | 15 | If 15 lions can kill 15 deers in 15 minutes how long will it take 100 lions to kill 100 deers? | {
"A": "1 minutes",
"B": "15 minute",
"C": "100 minutes",
"D": "10000 minutes",
"E": "1000 minutes"
} | multiply(divide(15, 15), 15) | divide(n0,n0)|multiply(n0,#0) | we can try the logic of time and work , our work is to kill the deers so 15 ( lions ) * 15 ( min ) / 15 ( deers ) = 100 ( lions ) * x ( min ) / 100 ( deers ) hence answer is x = 15 answer : b | physics |
math_qa__6AP8z0BcTWE06G4r | What is the least number that should be added to 1076, so the sum of the number is divisible by 23? Select: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">1_076 / 23</gadget>
<output>1_076/23 = around 46.782609</output>
<gadget id="calculator">floor(1_076/23)</gadget>
<output>46</output>
<gadget id="calculator">1 + 46</gadget>
<output>47</output>
<gadget id="calculator">47 - (1_076/23)</gadget>
<output>5/23 = around 0.217391</output>
<gadget id="calculator">(5/23) * 23</gadget>
<output>5</output>
<result>E</result> | E | 5 | What is the least number that should be added to 1076, so the sum of the number is divisible by 23? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | multiply(subtract(add(const_1, floor(divide(1076, 23))), divide(1076, 23)), 23) | divide(n0,n1)|floor(#0)|add(#1,const_1)|subtract(#2,#0)|multiply(n1,#3) | ( 1076 / 23 ) gives a remainder 18 so we need to add 5 . the answer is e . | general |
math_qa__A2SXa8PbxfjzeeZU | The sum of two numbers is 40 and their product is 375. What will be the sum of their reciprocals?
Choose one:
A) 1 / 40 B) 8 / 75 C) 75 / 4 D) 75 / 8 E) 75 / 6 | <gadget id="calculator">40 / 375</gadget>
<output>8/75 = around 0.106667</output>
<result>B</result> | B | 0.106667 | The sum of two numbers is 40 and their product is 375. What will be the sum of their reciprocals? | {
"A": "1 / 40",
"B": "8 / 75",
"C": "75 / 4",
"D": "75 / 8",
"E": "75 / 6"
} | divide(40, 375) | divide(n0,n1) | ( 1 / a ) + ( 1 / b ) = ( a + b ) / ab = 40 / 375 = 8 / 75 answer : b | general |
math_qa__yWloiEgOkn6oNOQ7 | In a throw of a coin find the probability of getting a tail? Options: A) 1 / 2 B) 1 / 3 C) 1 / 4 D) 2 / 5 E) 2 / 7 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | In a throw of a coin find the probability of getting a tail? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "2 / 5",
"E": "2 / 7"
} | divide(const_1, const_2) | divide(const_1,const_2)| | "s = { h , t } e = { t } p ( e ) = 1 / 2 answer is a" | probability |
math_qa__IHRTsV8pMS1hjx0S | Pavan travelled for 15 hours. He covered the first half of the distance at 30 kmph and remaining half of the distance at 25 kmph. Find the distance travelled by Pavan. Choose the correct choice from the following choices:
A) 408 km B) 409 km C) 410 km D) 412 km E) 419 km | <gadget id="calculator">2 * 30</gadget>
<output>60</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">1 / 50</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/60) + (1/50)</gadget>
<output>11/300 = around 0.036667</output>
<gadget id="calculator">1 / (11/300)</gadget>
<output>300/11 = around 27.272727</output>
<gadget id="calculator">(300/11) * 15</gadget>
<output>4_500/11 = around 409.090909</output>
<result>B</result> | B | 409 | Pavan travelled for 15 hours. He covered the first half of the distance at 30 kmph and remaining half of the distance at 25 kmph. Find the distance travelled by Pavan. | {
"A": "408 km",
"B": "409 km",
"C": "410 km",
"D": "412 km",
"E": "419 km"
} | multiply(inverse(add(inverse(multiply(const_2, 30)), inverse(multiply(25, const_2)))), 15) | multiply(n1,const_2)|multiply(n2,const_2)|inverse(#0)|inverse(#1)|add(#2,#3)|inverse(#4)|multiply(n0,#5) | let the distance travelled be x km . total time = ( x / 2 ) / 30 + ( x / 2 ) / 25 = 15 = > x / 60 + x / 50 = 15 = > ( 5 x + 6 x ) / 300 = 15 = > x = 409 km answer : b | physics |
math_qa__vssHEHHGxvTlbgzd | How many quarters are equal to 5 dollars? Choose the correct choice from the following answers:
A) 1 B) 8 C) 12 D) 20 E) 7 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<result>D</result> | D | 20 | How many quarters are equal to 5 dollars? | {
"A": "1",
"B": "8",
"C": "12",
"D": "20",
"E": "7"
} | multiply(5, const_4) | multiply(n0,const_4)| | "5 * 4 = 20 quarters answer : d" | general |
math_qa__Y6uacqO7om3WGy9r | During a particular baseball game, the probability of a team's pitcher throwing a strike on each throw is 2/5. What is the least number of times that the pitcher should pitch the ball that will increase the probability of getting a strike at least once to more than 50%. Pick: A) 3 B) 2 C) 1 D) 4 E) 5 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/2) * (2/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 10</gadget>
<output>2</output>
<result>B</result> | B | 2 | During a particular baseball game, the probability of a team's pitcher throwing a strike on each throw is 2/5. What is the least number of times that the pitcher should pitch the ball that will increase the probability of getting a strike at least once to more than 50%. | {
"A": "3",
"B": "2",
"C": "1",
"D": "4",
"E": "5"
} | multiply(multiply(divide(50, const_100), divide(2, 5)), const_10) | divide(n2,const_100)|divide(n0,n1)|multiply(#0,#1)|multiply(#2,const_10) | rule of subtraction : p ( a ) = 1 - p ( a ' ) rule of multiplication : p ( a ∩ b ) = p ( a ) p ( b ) the probability that the pitcher throws a strike at least once in 2 guesses is 1 - ( 3 / 5 ) ^ 2 = 1 - 9 / 25 = 16 / 25 > 50 % . answer : b | general |
math_qa__dCvOe322Tp6qh1HU | y = x^2 + bx +64 cuts the x axis at (h, 0) and (k, 0). If h and k are integers, what is the least value of b? Choose the correct choice from the following answers: A) - 65 B) - 64 C) - 32 D) 32 E) 64 | <gadget id="calculator">-64</gadget>
<output>-64</output>
<gadget id="calculator">(-64) - 1</gadget>
<output>-65</output>
<result>B</result> | B | -64 | y = x^2 + bx +64 cuts the x axis at (h, 0) and (k, 0). If h and k are integers, what is the least value of b? | {
"A": "- 65",
"B": "- 64",
"C": "- 32",
"D": "32",
"E": "64"
} | subtract(negate(64), const_1) | negate(n1)|subtract(#0,const_1)| | "as the curve cuts the x - axis at ( h , 0 ) and ( k , 0 ) . therefore h , k are the roots of the quadratic equation . for the quadratic equation is in the form ofax ^ 2 + bx + c = 0 , the product of the roots = c / a = 64 / 1 = 256 and the sum of the roots = - b / a = - b 64 can be expressed as product of two numbers in the following ways : 1 * 64 2 * 32 4 * 16 the sum of the roots is maximum when the roots are 1 and 64 and the maximum sum is 1 + 64 = 65 . the least value possible for b is therefore - 65 . b" | general |
math_qa__eRnu1YjRV1ig1j9f | A merchant marks his goods up by 20% and then offers a discount of 5% on the marked price. What % profit does the merchant make after the discount?
Choices:
A) 8 % B) 6 % C) 21 % D) 14 % E) 17 % | <gadget id="calculator">20 + 100</gadget>
<output>120</output>
<gadget id="calculator">120 * 5</gadget>
<output>600</output>
<gadget id="calculator">600 / 100</gadget>
<output>6</output>
<gadget id="calculator">120 - 6</gadget>
<output>114</output>
<gadget id="calculator">114 - 100</gadget>
<output>14</output>
<result>D</result> | D | 14 | A merchant marks his goods up by 20% and then offers a discount of 5% on the marked price. What % profit does the merchant make after the discount? | {
"A": "8 %",
"B": "6 %",
"C": "21 %",
"D": "14 %",
"E": "17 %"
} | subtract(subtract(add(20, const_100), divide(multiply(add(20, const_100), 5), const_100)), const_100) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(#3,const_100)| | "let the price be 100 . the price becomes 120 after a 20 % markup . now a discount of 5 % on 120 . profit = 114 - 100 14 % answer d" | gain |
math_qa__obtKAvTKRqTbg8TU | A fruit seller sells mangoes at the rate of Rs.16 per kg and thereby loses 12%. At what price per kg, he should have sold them to make a profit of 20%?
Choose the correct choice from the following options:
A) rs . 21.81 B) rs . 12 C) rs . 12.25 D) rs . 12.31 E) none | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">16 * 120</gadget>
<output>1_920</output>
<gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">1_920 / 88</gadget>
<output>240/11 = around 21.818182</output>
<result>A</result> | A | 21.81 | A fruit seller sells mangoes at the rate of Rs.16 per kg and thereby loses 12%. At what price per kg, he should have sold them to make a profit of 20%? | {
"A": "rs . 21.81",
"B": "rs . 12",
"C": "rs . 12.25",
"D": "rs . 12.31",
"E": "none"
} | divide(multiply(16, add(const_100, 20)), subtract(const_100, 12)) | add(n2,const_100)|subtract(const_100,n1)|multiply(n0,#0)|divide(#2,#1)| | "solution 88 : 16 = 120 : x x = ( 16 ã — 120 / 88 ) = rs . 21.81 hence , s . p per kg = rs . 21.81 answer a" | gain |
math_qa__46hhYNYKGndLY8MG | A batsman scored 120 runs which included 5 boundaries and 5 sixes. What percent of his total score did he make by running between the wickets? Choices.
A) 45 B) 58.33 % C) 600 / 11 D) 55 E) 35 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 + 25</gadget>
<output>50</output>
<gadget id="calculator">120 - 50</gadget>
<output>70</output>
<gadget id="calculator">70 / 120</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">(7/12) * 100</gadget>
<output>175/3 = around 58.333333</output>
<result>B</result> | B | 58.33 | A batsman scored 120 runs which included 5 boundaries and 5 sixes. What percent of his total score did he make by running between the wickets? | {
"A": "45",
"B": "58.33 %",
"C": "600 / 11",
"D": "55",
"E": "35"
} | multiply(divide(subtract(120, add(multiply(5, 5), multiply(5, 5))), 120), const_100) | multiply(n1,n2)|multiply(n1,n2)|add(#0,#1)|subtract(n0,#2)|divide(#3,n0)|multiply(#4,const_100)| | "explanation : number of runs made by running , = > 120 − ( 5 × 4 + 5 × 6 ) . = > 120 − ( 50 ) . = > 70 . hence , the required percentage is : - = > 70 / 120 * 100 = > 58.33 % answer : b" | general |
math_qa__10k0tz5FSFkt4eSM | Right now, the ratio between the ages of Sandy and Molly is 4:3. After 6 years, Sandy’s age will be 30 years. What is Molly's age right now? Select
A) 12 B) 14 C) 16 D) 18 E) 20 | <gadget id="calculator">30 - 6</gadget>
<output>24</output>
<gadget id="calculator">24 / 4</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<result>D</result> | D | 18 | Right now, the ratio between the ages of Sandy and Molly is 4:3. After 6 years, Sandy’s age will be 30 years. What is Molly's age right now? | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "20"
} | multiply(divide(subtract(30, 6), 4), 3) | subtract(n3,n2)|divide(#0,n0)|multiply(n1,#1)| | "now , sandy is 30 - 6 = 24 molly ' s age is ( 3 / 4 ) * 24 = 18 the answer is d ." | other |
math_qa__x5eDXPo7n0RKxmv7 | A goods train runs at a speed of 72 kmph and crosses a 290 m long platform in 26 seconds.What is the length of the goods train? Choose one
A) 230 m
B) 240 m
C) 260 m
D) 270 m
E) 250 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">20 * 26</gadget>
<output>520</output>
<gadget id="calculator">520 - 290</gadget>
<output>230</output>
<result>A</result> | A | 230 | A goods train runs at a speed of 72 kmph and crosses a 290 m long platform in 26 seconds.What is the length of the goods train? | {
"A": "230 m",
"B": "240 m",
"C": "260 m",
"D": "270 m",
"E": "250 m"
} | subtract(multiply(multiply(72, const_0_2778), 26), 290) | multiply(n0,const_0_2778)|multiply(n2,#0)|subtract(#1,n1)| | "s = 290 + x / t 72 * 5 / 18 = 290 + x / 26 x = 230 answer : a" | physics |
math_qa__fXNKGnHgG51ua9Mv | two years ago , ram put $ 1000 into a savings account . at the end of the first year , his account had accrued $ 100 in interest bringing his total balance to $ 1100 . the next year , his account balance increased by 20 % . at the end of the two years , by what percent has sam ' s account balance increased from his initial deposit of $ 1000 ? Choose the correct choice from the following options:
A) 40 % B) 25 % C) 35 % D) 30 % E) 32 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">1_100 * (6/5)</gadget>
<output>1_320</output>
<gadget id="calculator">1_320 - 1_000</gadget>
<output>320</output>
<gadget id="calculator">320 / 1_000</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">(8/25) * 100</gadget>
<output>32</output>
<result>E</result> | E | 32 | two years ago , ram put $ 1000 into a savings account . at the end of the first year , his account had accrued $ 100 in interest bringing his total balance to $ 1100 . the next year , his account balance increased by 20 % . at the end of the two years , by what percent has sam ' s account balance increased from his initial deposit of $ 1000 ? | {
"A": "40 %",
"B": "25 %",
"C": "35 %",
"D": "30 %",
"E": "32 %"
} | multiply(divide(subtract(multiply(1100, add(const_1, divide(20, const_100))), 1000), 1000), const_100) | divide(n3,const_100)|add(#0,const_1)|multiply(n2,#1)|subtract(#2,n0)|divide(#3,n0)|multiply(#4,const_100) | investment 1000 dollars 1 st year total gained = 100 total amount end of first year = 1100 second year account increased by 20 % = 1100 * 0.2 = 220 therefore total amount by second year end = 1320 so total percentage increase in money = ( 1320 - 1000 ) * 100 / 1000 = 32 % correct answer e = 32 % | gain |
math_qa__HGFXsdI8Cwwqqsgw | In a certain egg-processing plant, every egg must be inspected, and is either accepted for processing or rejected. For every 96 eggs accepted for processing, 4 eggs are rejected. If, on a particular day, 12 additional eggs were accepted, but the overall number of eggs inspected remained the same, the ratio of those accepted to those rejected would be 99 to 1. How many R eggs does the plant process per day?
Pick one: A) 100 B) 300 C) 400 D) 3,000 E) 4,000 | <gadget id="calculator">99 - 96</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<result>C</result> | C | 400 | In a certain egg-processing plant, every egg must be inspected, and is either accepted for processing or rejected. For every 96 eggs accepted for processing, 4 eggs are rejected. If, on a particular day, 12 additional eggs were accepted, but the overall number of eggs inspected remained the same, the ratio of those accepted to those rejected would be 99 to 1. How many R eggs does the plant process per day? | {
"A": "100",
"B": "300",
"C": "400",
"D": "3,000",
"E": "4,000"
} | multiply(divide(12, subtract(99, 96)), const_100) | subtract(n3,n0)|divide(n2,#0)|multiply(#1,const_100)| | "straight pluggin in for me . as usual , i started with c and got the answer . lets ' back calculate and see what we get let us consider eggs processed each day to be 400 so initial ratio of eggs processed and rejected is 96 : 4 or 24 : 1 so out of 400 eggs , there will be 384 eggs processed and 16 rejected . now if the no . of eggs inspected remain and 12 more eggs get accepted that means there r = 384 + 12 = 396 eggs accepted and 4 rejected . . . and the ratio will be 99 : 1 bingo . . . this is what the questions says . . . . its always a good idea to start with c ." | general |
math_qa__3Qi0BFtYYm32Y7nP | An empty fuel tank with a capacity of 200 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added? Answers: A) 160 B) 150 C) 100 D) 80 E) 50 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">200 * (4/25)</gadget>
<output>32</output>
<gadget id="calculator">32 - 30</gadget>
<output>2</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(4/25) - (3/25)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">2 / (1/25)</gadget>
<output>50</output>
<result>E</result> | E | 50 | An empty fuel tank with a capacity of 200 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added? | {
"A": "160",
"B": "150",
"C": "100",
"D": "80",
"E": "50"
} | divide(subtract(multiply(200, divide(16, const_100)), 30), subtract(divide(16, const_100), divide(12, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n3)|divide(#4,#3)| | "say there are a gallons of fuel a in the tank , then there would be 200 - a gallons of fuel b . the amount of ethanol in a gallons of fuel a is 0.12 a ; the amount of ethanol in 200 - a gallons of fuel b is 0.16 ( 200 - a ) ; since the total amount of ethanol is 30 gallons then 0.12 a + 0.16 ( 200 - a ) = 30 - - > a = 50 . answer : e ." | gain |
math_qa__8J7lDnAv5kG22ga7 | What quantity of water should taken out to concentrate 24 liters of 40% acidic liquid to 60% acidic liquid? Answers
A) 5 liters B) 10 liters C) 15 liters D) 8 liters E) 6 liters | <gadget id="calculator">24 * 40</gadget>
<output>960</output>
<gadget id="calculator">960 / 60</gadget>
<output>16</output>
<gadget id="calculator">24 - 16</gadget>
<output>8</output>
<result>D</result> | D | 8 | What quantity of water should taken out to concentrate 24 liters of 40% acidic liquid to 60% acidic liquid? | {
"A": "5 liters",
"B": "10 liters",
"C": "15 liters",
"D": "8 liters",
"E": "6 liters"
} | subtract(24, divide(multiply(24, 40), 60)) | multiply(n0,n1)|divide(#0,n2)|subtract(n0,#1)| | "required answer is = 24 ( 60 - 40 ) / 60 = 8 liters answer is d" | gain |
math_qa__DkwNr9iUvrfrLWqn | If 2x + y = 7 and x + 2y = 5, then 2xy/3 =? Choices: A) 1 B) 2 C) 17 / 5 D) 18 / 5 E) 4 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">14 - 5</gadget>
<output>9</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">9 / 3</gadget>
<output>3</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">7 - 6</gadget>
<output>1</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>B</result> | B | 2 | If 2x + y = 7 and x + 2y = 5, then 2xy/3 =? | {
"A": "1",
"B": "2",
"C": "17 / 5",
"D": "18 / 5",
"E": "4"
} | divide(add(divide(subtract(multiply(7, 2), 5), subtract(multiply(2, 2), const_1)), subtract(7, multiply(2, divide(subtract(multiply(7, 2), 5), subtract(multiply(2, 2), const_1))))), 2) | multiply(n0,n1)|multiply(n0,n0)|subtract(#0,n3)|subtract(#1,const_1)|divide(#2,#3)|multiply(n0,#4)|subtract(n1,#5)|add(#4,#6)|divide(#7,n4)| | "2 * ( x + 2 y = 5 ) equals 2 x + 4 y = 10 2 x + 4 y = 10 - 2 x + y = 7 = 3 y = 3 therefore y = 1 plug and solve . . . 2 x + 1 = 7 2 x = 6 x = 3 ( 2 * 3 * 1 ) / 3 = 6 / 3 = 2 b" | general |
math_qa__dp2g9ZGglg3guhwh | In a colony of 50 residents, the ratio of the number of men and women is 3:2. Among the women, the ratio of the educated to the uneducated is 1:3. If the ratio of the number of education to uneducated persons is 4:6, then find the ratio of the number of educated and uneducated men in the colony? Choose the correct choice from the following answers
A) 1 : 1
B) 3 : 2
C) 1 : 3
D) 2 : 5
E) 5 : 7 | <gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">50 / 5</gadget>
<output>10</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">20 - 5</gadget>
<output>15</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">30 - 15</gadget>
<output>15</output>
<gadget id="calculator">15 / 15</gadget>
<output>1</output>
<result>A</result> | A | 1 | In a colony of 50 residents, the ratio of the number of men and women is 3:2. Among the women, the ratio of the educated to the uneducated is 1:3. If the ratio of the number of education to uneducated persons is 4:6, then find the ratio of the number of educated and uneducated men in the colony? | {
"A": "1 : 1",
"B": "3 : 2",
"C": "1 : 3",
"D": "2 : 5",
"E": "5 : 7"
} | divide(subtract(multiply(divide(50, add(4, 6)), 4), divide(multiply(divide(50, add(3, 2)), 2), add(1, 3))), subtract(multiply(divide(50, add(4, 6)), 6), multiply(divide(multiply(divide(50, add(3, 2)), 2), add(1, 3)), 3))) | add(n5,n6)|add(n1,n2)|add(n1,n3)|divide(n0,#0)|divide(n0,#1)|multiply(n5,#3)|multiply(n2,#4)|multiply(n6,#3)|divide(#6,#2)|multiply(n1,#8)|subtract(#5,#8)|subtract(#7,#9)|divide(#10,#11)| | "number of men in the colony = 3 / 5 ( 50 ) = 30 number of women in the colony = 2 / 5 ( 50 ) = 20 number of educated women in the colony = 1 / 4 ( 20 ) = 5 number of uneducated women in the colony = 3 / 4 ( 20 ) = 15 number of educated persons in the colony = 4 / 10 ( 50 ) = 20 as 5 females are educated , remaining 15 educated persons must be men . number of uneducated men in the colony = 30 - 15 = 15 number of educated men and uneducated men are in the ratio 15 : 15 = > 1 : 1 answer : a" | other |
math_qa__SfLHLDHgzaMENzel | A train running at the speed of 72 km/hr crosses a pole in 8 seconds. Find the length of the train. Select the correct option:
A) 150 meter
B) 145 meter
C) 160 meter
D) 135 meter
E) none of these | <gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">20 * 8</gadget>
<output>160</output>
<result>C</result> | C | 160 | A train running at the speed of 72 km/hr crosses a pole in 8 seconds. Find the length of the train. | {
"A": "150 meter",
"B": "145 meter",
"C": "160 meter",
"D": "135 meter",
"E": "none of these"
} | multiply(divide(multiply(72, const_1000), const_3600), 8) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "explanation : speed = 72 * ( 5 / 18 ) m / sec = 20 m / sec length of train ( distance ) = speed * time = 20 * 8 = 160 meter option c" | physics |
math_qa__iHguOlSsfHhOyo4k | A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container? Choose the most appropriate option:
A) 26.34 litres B) 27.36 litres C) 28 litres D) 29.16 litres E) 30 litres | <gadget id="calculator">4 / 40</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) ** 3</gadget>
<output>729/1_000 = around 0.729</output>
<gadget id="calculator">(729/1_000) * 40</gadget>
<output>729/25 = around 29.16</output>
<result>D</result> | D | 29.16 | A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container? | {
"A": "26.34 litres",
"B": "27.36 litres",
"C": "28 litres",
"D": "29.16 litres",
"E": "30 litres"
} | multiply(power(subtract(const_1, divide(4, 40)), const_3), 40) | divide(n1,n0)|subtract(const_1,#0)|power(#1,const_3)|multiply(n0,#2)| | "amount of milk left after 3 operations = [ 40 ( 1 - 4 / 40 ) ^ 3 ] litres = 40 x 9 / 10 x 9 / 10 x 9 / 10 = 29.16 litres answer : d" | general |
math_qa__tugVd2huBcgLCbMF | Last year a certain bond price with a face value of 5000 yielded 5% of its face value in interest. If that interest was approx 6.5 of the bond's selling price approx what was the bond's selling price? Choices:
A) 4063 B) 3846 C) 5351 D) 6000 E) 6154 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">5_000 * (1/20)</gadget>
<output>250</output>
<gadget id="calculator">6.5 / 100</gadget>
<output>0.065</output>
<gadget id="calculator">250 / 0.065</gadget>
<output>3_846.153846</output>
<result>B</result> | B | 3,846 | Last year a certain bond price with a face value of 5000 yielded 5% of its face value in interest. If that interest was approx 6.5 of the bond's selling price approx what was the bond's selling price? | {
"A": "4063",
"B": "3846",
"C": "5351",
"D": "6000",
"E": "6154"
} | divide(multiply(5000, divide(5, const_100)), divide(6.5, const_100)) | divide(n1,const_100)|divide(n2,const_100)|multiply(n0,#0)|divide(#2,#1)| | "interest = 0.05 * 5000 = 0.065 * selling price - - > selling price = 0.05 * 5000 / 0.065 - - > selling price = ~ 3,846 answer : b ." | gain |
math_qa__9sps79jURjmyX3pF | A man can row his boat with the stream at 8 km/h and against the stream in 4 km/h. The man's rate is? Pick one
A) 1 kmph B) 2 kmph C) 8 kmph D) 7 kmph E) 5 kmph | <gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>B</result> | B | 2 | A man can row his boat with the stream at 8 km/h and against the stream in 4 km/h. The man's rate is? | {
"A": "1 kmph",
"B": "2 kmph",
"C": "8 kmph",
"D": "7 kmph",
"E": "5 kmph"
} | divide(subtract(8, 4), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "ds = 8 us = 4 s = ? s = ( 8 - 4 ) / 2 = 2 kmph answer : b" | gain |
math_qa__lwqk5xXBJHqxM3d9 | A, B and C have Rs.350 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
Select:
A) 200
B) 190
C) 180
D) 170
E) 160 | <gadget id="calculator">200 + 350</gadget>
<output>550</output>
<gadget id="calculator">550 - 350</gadget>
<output>200</output>
<result>A</result> | A | 200 | A, B and C have Rs.350 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have? | {
"A": "200",
"B": "190",
"C": "180",
"D": "170",
"E": "160"
} | subtract(add(200, 350), 350) | add(n1,n2)|subtract(#0,n0)| | "a + b + c = 350 a + c = 200 b + c = 350 - - - - - - - - - - - - - - a + b + 2 c = 550 a + b + c = 350 - - - - - - - - - - - - - - - - c = 200 answer : a" | general |
math_qa__HyiWcy4cDzooJsnl | The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in metres) is: Select: A) 400 B) 525 C) 750 D) 850 E) none | <gadget id="calculator">90 * 1_000</gadget>
<output>90_000</output>
<gadget id="calculator">60 / 1</gadget>
<output>60</output>
<gadget id="calculator">90_000 / 60</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 2</gadget>
<output>750</output>
<result>C</result> | C | 750 | The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in metres) is: | {
"A": "400",
"B": "525",
"C": "750",
"D": "850",
"E": "none"
} | divide(divide(multiply(90, const_1000), divide(const_60, const_1)), const_2) | divide(const_60,const_1)|multiply(n0,const_1000)|divide(#1,#0)|divide(#2,const_2)| | "sol . speed = [ 90 * 5 / 18 ] m / sec = 25 m / sec ; time = 1 min . = 60 sec . let the length of the train and that of the platform be x metres . then , 2 x / 60 = 25 ⇔ x = 25 * 60 / 2 = 750 answer c" | physics |
math_qa__RzHihH3ItzR1KUQ2 | Linda spent 2/4 of her savings on furniture and the rest on a TV. If the TV cost her $300, what were her original savings? Choose the correct choice from the following options: A) $ 900 B) $ 300 C) $ 600 D) $ 700 E) $ 800 | <gadget id="calculator">2 / 4</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">300 / (1/2)</gadget>
<output>600</output>
<result>C</result> | C | 600 | Linda spent 2/4 of her savings on furniture and the rest on a TV. If the TV cost her $300, what were her original savings? | {
"A": "$ 900",
"B": "$ 300",
"C": "$ 600",
"D": "$ 700",
"E": "$ 800"
} | divide(300, subtract(const_1, divide(2, 4))) | divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1)| | "if linda spent 3 / 4 of her savings on furnitute , the rest 4 / 4 - 2 / 4 = 1 / 2 on a tv but the tv cost her $ 300 . so 1 / 2 of her savings is $ 300 . so her original savings are 2 times $ 300 = $ 600 correct answer c" | general |
math_qa__YeHeSyIIuY4Tsbh6 | What is the speed of the stream if a canoe rows upstream at 3km/hr and downstream at 12km/hr
Choose the correct choice from the following answers.
A) 1 kmph B) 4 kmph C) 3 kmph D) 2 kmph E) 4.5 kmph | <gadget id="calculator">12 - 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<result>E</result> | E | 4.5 | What is the speed of the stream if a canoe rows upstream at 3km/hr and downstream at 12km/hr | {
"A": "1 kmph",
"B": "4 kmph",
"C": "3 kmph",
"D": "2 kmph",
"E": "4.5 kmph"
} | divide(subtract(12, 3), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "sol . speed of stream = 1 / 2 ( 12 - 3 ) kmph = 4.5 kmph . answer e" | physics |
math_qa__DziEKHIkT5xkHxX5 | The ratio of the number of females to males at a party was 1:2 but when 3 females and 3 males left, the ratio became 1:3. How many people were at the party originally? Answers:
A) 14 B) 16 C) 18 D) 20 E) 22 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 - 6</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 12</gadget>
<output>18</output>
<result>C</result> | C | 18 | The ratio of the number of females to males at a party was 1:2 but when 3 females and 3 males left, the ratio became 1:3. How many people were at the party originally? | {
"A": "14",
"B": "16",
"C": "18",
"D": "20",
"E": "22"
} | add(divide(subtract(multiply(multiply(3, 2), 3), multiply(3, 2)), 2), subtract(multiply(multiply(3, 2), 3), multiply(3, 2))) | multiply(n1,n2)|multiply(n5,#0)|subtract(#1,#0)|divide(#2,n1)|add(#3,#2)| | "the total number of people are x females + 2 x males . 3 * ( x - 3 ) = 2 x - 3 x = 6 there were 3 x = 18 people at the party originally . the answer is c ." | other |
math_qa__rJhjIBCCgVTysfRh | One fourth of one third of two fifth of a number is 30. What will be40% of that number Answers.
A) 360 B) 150 C) 180 D) 200 E) 220 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/4) * (1/3)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/12) * (2/5)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">30 / (1/30)</gadget>
<output>900</output>
<gadget id="calculator">900 * 40</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 100</gadget>
<output>360</output>
<result>A</result> | A | 360 | One fourth of one third of two fifth of a number is 30. What will be40% of that number | {
"A": "360",
"B": "150",
"C": "180",
"D": "200",
"E": "220"
} | divide(multiply(divide(30, multiply(multiply(divide(const_1, const_4), divide(const_1, const_3)), divide(const_2, add(const_2, const_3)))), 40), const_100) | add(const_2,const_3)|divide(const_1,const_4)|divide(const_1,const_3)|divide(const_2,#0)|multiply(#1,#2)|multiply(#3,#4)|divide(n0,#5)|multiply(n1,#6)|divide(#7,const_100)| | "explanation : ( 1 / 4 ) * ( 1 / 3 ) * ( 2 / 5 ) * x = 30 then x = 30 * 30 = 900 40 % of 900 = 360 answer : option a" | gain |
math_qa__NFUug2ryMBiQmDJX | 5 percent of 255 = Choices
A) 5 B) 12.5 C) 14.5 D) 12.75 E) 25 | <gadget id="calculator">5 * 255</gadget>
<output>1_275</output>
<gadget id="calculator">1_275 / 100</gadget>
<output>51/4 = around 12.75</output>
<result>D</result> | D | 12.75 | 5 percent of 255 = | {
"A": "5",
"B": "12.5",
"C": "14.5",
"D": "12.75",
"E": "25"
} | divide(multiply(5, 255), const_100) | multiply(n0,n1)|divide(#0,const_100) | 255 / 100 = 2.55 1 % = 2.55 5 % = 2.55 * 5 = 12.75 answer : d | gain |
math_qa__omUi1ePYvl2Md0Bv | A certain number of men can do a work in 20days. If there were 4 men less it could be finished in 5days more. How many men are there? Choose the correct choice from the following options
A) 10 B) 20 C) 25 D) 30 E) 35 | <gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 4</gadget>
<output>100</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<result>B</result> | B | 20 | A certain number of men can do a work in 20days. If there were 4 men less it could be finished in 5days more. How many men are there? | {
"A": "10",
"B": "20",
"C": "25",
"D": "30",
"E": "35"
} | divide(multiply(add(20, 5), 4), 5) | add(n0,n2)|multiply(n1,#0)|divide(#1,n2) | the original number of men = 4 ( 20 + 5 ) / 5 = 20 men answer is b | physics |
math_qa__HBnoezjEOM91Urgf | A train running at the speed of 36 km/hr crosses a pole in 9 seconds. Find the length of the train? Choose the correct choice from the following answers: A) 150 meter B) 299 meter C) 666 meter D) 90 meter E) 144 meter | <gadget id="calculator">36 * 1_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 3_600</gadget>
<output>10</output>
<gadget id="calculator">10 * 9</gadget>
<output>90</output>
<result>D</result> | D | 90 | A train running at the speed of 36 km/hr crosses a pole in 9 seconds. Find the length of the train? | {
"A": "150 meter",
"B": "299 meter",
"C": "666 meter",
"D": "90 meter",
"E": "144 meter"
} | multiply(divide(multiply(36, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 36 * ( 5 / 18 ) m / sec = 10 m / sec length of train ( distance ) = speed * time ( 10 ) * 9 = 90 meter answer : d" | physics |
math_qa__i202TQ5tWlSAxWGb | Point (m,n) is on the circle represented by m^2+n^2=10, and m, n are integers. How many such points are possible? Options: A) 0 B) 2 C) 4 D) 6 E) 8 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<result>E</result> | E | 8 | Point (m,n) is on the circle represented by m^2+n^2=10, and m, n are integers. How many such points are possible? | {
"A": "0",
"B": "2",
"C": "4",
"D": "6",
"E": "8"
} | multiply(power(2, 2), 2) | power(n0,n0)|multiply(n0,#0) | m ^ 2 + n ^ 2 = 10 and m , n are integers means that 10 is the sum of two perfect squares . 10 is the sum of only one pair of perfect squares 1 and 9 . so , there can be 8 such points , 4 in each quadrant : ( 1 , 3 ) ; ( 1 , - 3 ) ; ( - 1 , 3 ) ; ( - 1 , - 3 ) ; ( 3 , 1 ) ; ( 3 , - 1 ) ; ( - 3 , 1 ) ; ( - 3 , - 1 ) . answer : e . | general |
math_qa__Ce4loafnAUqwjGSa | Find the area of the quadrilateral of one of its diagonals is 26 cm and its off sets 9 cm and 6 cm?
Choose the correct choice: A) 188 cm 2 B) 150 cm 2 C) 168 cm 2 D) 195 cm 2 E) 987 cm 2 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">6 + 9</gadget>
<output>15</output>
<gadget id="calculator">(1/2) * 15</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 26</gadget>
<output>195</output>
<result>D</result> | D | 195 | Find the area of the quadrilateral of one of its diagonals is 26 cm and its off sets 9 cm and 6 cm? | {
"A": "188 cm 2",
"B": "150 cm 2",
"C": "168 cm 2",
"D": "195 cm 2",
"E": "987 cm 2"
} | multiply(multiply(divide(const_1, const_2), add(6, 9)), 26) | add(n1,n2)|divide(const_1,const_2)|multiply(#0,#1)|multiply(n0,#2)| | "1 / 2 * 26 ( 9 + 6 ) = 195 cm 2 answer : d" | geometry |
math_qa__qu67Looxaf83ZEV0 | A soft drink company had 5000 small and 12000 big bottles in storage. If 15% of small 18% of big bottles have been sold, then the total bottles remaining in storage is Options:
A) 14090 B) 16010 C) 15060 D) 14930 E) 16075 | <gadget id="calculator">5_000 + 12_000</gadget>
<output>17_000</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">5_000 * (3/20)</gadget>
<output>750</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) * 12_000</gadget>
<output>2_160</output>
<gadget id="calculator">750 + 2_160</gadget>
<output>2_910</output>
<gadget id="calculator">17_000 - 2_910</gadget>
<output>14_090</output>
<result>A</result> | A | 14,090 | A soft drink company had 5000 small and 12000 big bottles in storage. If 15% of small 18% of big bottles have been sold, then the total bottles remaining in storage is | {
"A": "14090",
"B": "16010",
"C": "15060",
"D": "14930",
"E": "16075"
} | subtract(add(5000, 12000), add(multiply(5000, divide(15, const_100)), multiply(divide(18, const_100), 12000))) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|subtract(#0,#5) | 5000 + 12000 - ( 0.15 * 5000 + 0.18 * 12000 ) = 14090 . answer : a . | general |
math_qa__OjDQyM97HEXsxSfJ | 4 - fifths of 3 - eighths of a number is 24 . what is 250 per cent of that number ? Choose the correct choice from the following answers
A) 100 B) 160 C) 120 D) 200 E) none of these | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(4/5) * (3/8)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">24 / (3/10)</gadget>
<output>80</output>
<gadget id="calculator">250 / 100</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">80 * (5/2)</gadget>
<output>200</output>
<result>D</result> | D | 200 | 4 - fifths of 3 - eighths of a number is 24 . what is 250 per cent of that number ? | {
"A": "100",
"B": "160",
"C": "120",
"D": "200",
"E": "none of these"
} | multiply(divide(24, multiply(divide(4, add(const_1, const_4)), divide(3, add(const_4, const_4)))), divide(250, const_100)) | add(const_1,const_4)|add(const_4,const_4)|divide(n3,const_100)|divide(n0,#0)|divide(n1,#1)|multiply(#3,#4)|divide(n2,#5)|multiply(#6,#2) | let the number = x . 4 ⁄ 5 × 3 ⁄ 8 x = 24 or x = 24 × 2 × 5 / 3 = 80 ∴ 250 per cent of the number = 250 ⁄ 100 × 80 = 200 answer d | general |
math_qa__HfUgKonGerVnMypv | Find the mean proportional between 7921 & 9409? Select the correct option:
A) 8163
B) 8633
C) 8663
D) 8636
E) none of these | <gadget id="calculator">7_921 + 9_409</gadget>
<output>17_330</output>
<gadget id="calculator">17_330 / 2</gadget>
<output>8_665</output>
<result>B</result> | B | 8,633 | Find the mean proportional between 7921 & 9409? | {
"A": "8163",
"B": "8633",
"C": "8663",
"D": "8636",
"E": "none of these"
} | divide(add(7921, 9409), const_2) | add(n0,n1)|divide(#0,const_2)| | "explanation : formula = √ a × b a = 7921 and b = 9409 √ 7921 × 9409 = 89 × 97 = 8633 answer : option b" | general |
math_qa__PD3DB8oKiO5yrZo6 | there are 3 vessels of equal capacity . vessel a contains milk and water in the ratio 7 : 3 ; vessel b contains milk and water in the ratio 2 : 1 and vessel c contains milk and water in the ratio 3 : 2 . if the mixture in all the 3 vessels is mixed up . what will be the ratio of milk and water ? Choose the correct choice from the following answers.
A) 59 : 31 B) 3 : 2 C) 118 : 126 D) 193 : 122 E) 201 : 132 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">7 * 15</gadget>
<output>105</output>
<gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">2 * 50</gadget>
<output>100</output>
<gadget id="calculator">105 + 100</gadget>
<output>205</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">3 * 30</gadget>
<output>90</output>
<gadget id="calculator">205 + 90</gadget>
<output>295</output>
<gadget id="calculator">3 * 15</gadget>
<output>45</output>
<gadget id="calculator">1 * 50</gadget>
<output>50</output>
<gadget id="calculator">45 + 50</gadget>
<output>95</output>
<gadget id="calculator">2 * 30</gadget>
<output>60</output>
<gadget id="calculator">95 + 60</gadget>
<output>155</output>
<gadget id="calculator">295 / 155</gadget>
<output>59/31 = around 1.903226</output>
<result>A</result> | A | 1.903226 | there are 3 vessels of equal capacity . vessel a contains milk and water in the ratio 7 : 3 ; vessel b contains milk and water in the ratio 2 : 1 and vessel c contains milk and water in the ratio 3 : 2 . if the mixture in all the 3 vessels is mixed up . what will be the ratio of milk and water ? | {
"A": "59 : 31",
"B": "3 : 2",
"C": "118 : 126",
"D": "193 : 122",
"E": "201 : 132"
} | divide(add(add(multiply(7, multiply(add(2, 1), add(3, 2))), multiply(2, multiply(add(7, 3), add(3, 2)))), multiply(3, multiply(add(7, 3), add(2, 1)))), add(add(multiply(3, multiply(add(2, 1), add(3, 2))), multiply(1, multiply(add(7, 3), add(3, 2)))), multiply(2, multiply(add(7, 3), add(2, 1))))) | add(n3,n4)|add(n0,n3)|add(n0,n1)|multiply(#0,#1)|multiply(#2,#1)|multiply(#2,#0)|multiply(n1,#3)|multiply(n3,#4)|multiply(n0,#5)|multiply(n0,#3)|multiply(n4,#4)|multiply(n3,#5)|add(#6,#7)|add(#9,#10)|add(#12,#8)|add(#13,#11)|divide(#14,#15) | 7 : 3 = > 7 x + 3 x = 10 x 2 : 1 = > 2 y + 1 y = 3 y 3 : 2 = > 3 z + 2 z = 5 z 10 x = 3 y = 5 z take lcm of 10 , 3,5 = 30 or simply ; x = 3 y = 10 z = 6 so , ratio of milk : water = ( 7 x + 2 y + 3 z ) / ( 3 x + y + 2 z ) = 59 / 31 ans : a | general |
math_qa__rUBOHCrTTs9DgEqF | A train moves with a speed of 108 kmph. Its speed in metres per second is Choose the correct answer:
A) 10.8 B) 18 C) 25 D) 30 E) none | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">108 * (5/18)</gadget>
<output>30</output>
<result>D</result> | D | 30 | A train moves with a speed of 108 kmph. Its speed in metres per second is | {
"A": "10.8",
"B": "18",
"C": "25",
"D": "30",
"E": "none"
} | multiply(108, const_0_2778) | multiply(n0,const_0_2778)| | "sol . 108 kmph = [ 108 x 5 / 18 ] m / sec = 30 m / sec . answer d" | physics |
math_qa__YLnUH0OWmieQPQwi | Martin bought 5 packet milk at an average price (arithmetic mean) of 20¢. If Martin returned two packet to the retailer, and the average price of the remaining millk packet was 12¢, then what is the average price, in cents, of the two returned milk packets? Choose the most appropriate option.
A) 30
B) 31
C) 32
D) 33
E) 34 | <gadget id="calculator">5 * 20</gadget>
<output>100</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">100 - 36</gadget>
<output>64</output>
<gadget id="calculator">64 / 2</gadget>
<output>32</output>
<result>C</result> | C | 32 | Martin bought 5 packet milk at an average price (arithmetic mean) of 20¢. If Martin returned two packet to the retailer, and the average price of the remaining millk packet was 12¢, then what is the average price, in cents, of the two returned milk packets? | {
"A": "30",
"B": "31",
"C": "32",
"D": "33",
"E": "34"
} | divide(subtract(multiply(5, 20), multiply(12, subtract(5, const_2))), const_2) | multiply(n0,n1)|subtract(n0,const_2)|multiply(n2,#1)|subtract(#0,#2)|divide(#3,const_2) | total price of 5 packet milk = 5 * 20 = 100 total price of 3 packet milk = 3 * 12 = 36 total price of 2 packet returned milk = 100 - 36 = 64 average price of 2 packet milk = 64 / 2 = 32 correct option answer : c | general |
math_qa__JMEK2X46jDw0l8Lr | 20 beavers, working together in a constant pace, can build a dam in 18 hours. How many hours will it take 12 beavers that work at the same pace, to build the same dam?
Choices.
A) 22 . B) 24 . C) 30 . D) 36 E) 38 . | <gadget id="calculator">18 * 20</gadget>
<output>360</output>
<gadget id="calculator">360 / 12</gadget>
<output>30</output>
<result>C</result> | C | 30 | 20 beavers, working together in a constant pace, can build a dam in 18 hours. How many hours will it take 12 beavers that work at the same pace, to build the same dam? | {
"A": "22 .",
"B": "24 .",
"C": "30 .",
"D": "36",
"E": "38 ."
} | divide(multiply(18, 20), 12) | multiply(n0,n1)|divide(#0,n2) | total work = 20 * 18 = 360 beaver hours 12 beaver * x = 360 beaver hours x = 360 / 12 = 30 answer : c | physics |
math_qa__DYYKYD1V111WbLVO | A, B, C, D and E are ve
consecutive odd numbers The sum of A and C is 146. What is
the value of E?
Choose the correct choice from the following
A) 75 B) 81 C) 71 D) 79 E) none of these | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">146 - 4</gadget>
<output>142</output>
<gadget id="calculator">142 / 2</gadget>
<output>71</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">71 + 8</gadget>
<output>79</output>
<result>D</result> | D | 79 | A, B, C, D and E are ve
consecutive odd numbers The sum of A and C is 146. What is
the value of E? | {
"A": "75",
"B": "81",
"C": "71",
"D": "79",
"E": "none of these"
} | add(divide(subtract(146, multiply(const_2, const_2)), const_2), multiply(const_4, const_2)) | multiply(const_2,const_2)|multiply(const_2,const_4)|subtract(n0,#0)|divide(#2,const_2)|add(#3,#1) | a + c = 146 ⇒ a + a + 4 = 146 ⇒ a = 146 - 4 / 2 = 71 ∴ e = a + 8 = 71 + 8 = 79 answer d | physics |
math_qa__ZYqXZR5kzhcmy8wa | The radius of a cylindrical vessel is 7cm and height is 3cm. Find the whole surface of the cylinder?
Choose the correct choice: A) 520 sq cm B) 840 sq cm C) 440 sq cm D) 120 sq cm E) 5 sq cm | <gadget id="calculator">2 * pi * 7 * (7 + 3)</gadget>
<output>140*pi = around 439.822972</output>
<result>C</result> | C | 440 | The radius of a cylindrical vessel is 7cm and height is 3cm. Find the whole surface of the cylinder? | {
"A": "520 sq cm",
"B": "840 sq cm",
"C": "440 sq cm",
"D": "120 sq cm",
"E": "5 sq cm"
} | surface_cylinder(7, 3) | surface_cylinder(n0,n1) | explanation : r = 7 h = 3 2 π r ( h + r ) = 2 * 22 / 7 * 7 ( 10 ) = 440 sq cm answer : c | geometry |
math_qa__2Z20Uen5bdQBMTcu | A jar contains 20 red, 20 blue, 6 yellow and 4 pink balls. If two balls are to be selected at random and without replacement, approximately what is the probability both of them to be the same colour? Pick:
A) 1 / 25 B) 1 / 15 C) 1 / 3 D) 1 / 2 E) 1 | <gadget id="calculator">20 - 1</gadget>
<output>19</output>
<gadget id="calculator">20 * 19</gadget>
<output>380</output>
<gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">40 + 6</gadget>
<output>46</output>
<gadget id="calculator">46 + 4</gadget>
<output>50</output>
<gadget id="calculator">50 - 1</gadget>
<output>49</output>
<gadget id="calculator">50 * 49</gadget>
<output>2_450</output>
<gadget id="calculator">380 / 2_450</gadget>
<output>38/245 = around 0.155102</output>
<gadget id="calculator">(38/245) + (38/245)</gadget>
<output>76/245 = around 0.310204</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 / 2_450</gadget>
<output>3/245 = around 0.012245</output>
<gadget id="calculator">(76/245) + (3/245)</gadget>
<output>79/245 = around 0.322449</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 / 2_450</gadget>
<output>6/1_225 = around 0.004898</output>
<gadget id="calculator">(79/245) + (6/1_225)</gadget>
<output>401/1_225 = around 0.327347</output>
<result>C</result> | C | 0.333333 | A jar contains 20 red, 20 blue, 6 yellow and 4 pink balls. If two balls are to be selected at random and without replacement, approximately what is the probability both of them to be the same colour? | {
"A": "1 / 25",
"B": "1 / 15",
"C": "1 / 3",
"D": "1 / 2",
"E": "1"
} | add(add(add(divide(multiply(20, subtract(20, const_1)), multiply(add(add(add(20, 20), 6), 4), subtract(add(add(add(20, 20), 6), 4), const_1))), divide(multiply(20, subtract(20, const_1)), multiply(add(add(add(20, 20), 6), 4), subtract(add(add(add(20, 20), 6), 4), const_1)))), divide(multiply(6, add(4, const_1)), multiply(add(add(add(20, 20), 6), 4), subtract(add(add(add(20, 20), 6), 4), const_1)))), divide(multiply(4, const_3), multiply(add(add(add(20, 20), 6), 4), subtract(add(add(add(20, 20), 6), 4), const_1)))) | add(n0,n0)|add(n3,const_1)|multiply(n3,const_3)|subtract(n0,const_1)|add(n2,#0)|multiply(n0,#3)|multiply(n2,#1)|add(n3,#4)|subtract(#7,const_1)|multiply(#7,#8)|divide(#5,#9)|divide(#6,#9)|divide(#2,#9)|add(#10,#10)|add(#13,#11)|add(#14,#12) | ok so jar contains 20 red 20 blue 6 yellow and 4 pink . . adding the number of balls we get 50 total . . now its a counting + probability exercise . . 2 stages exist : pick first ball then second ball . . denominator for first ball = 50 since there are 50 balls denominator for second ball = 49 since only 49 would remain for each type ball i constructed probability of getting 2 of same . . i used a counting method . . first ball 20 chances blue and 2 nd ball 19 chances blue and so on and so forth blue = ( 20 * 19 ) / ( 50 * 49 ) rounded to 400 / 2500 red = ( 20 * 19 ) / ( 50 * 49 ) rounded to 400 / 2500 yellow = ( 6 * 5 ) / ( 50 * 49 ) rounded to 30 / 2500 pink = ( 4 * 3 ) / ( 49 * 50 ) rounded to 12 / 2500 then i summed these individual probabilities to get 842 / 2500 this is ~ 1 / 3 as 800 * 3 = 2400 ans : c | other |
math_qa__YZsNOFAq3j2iPPmK | Diana is painting statues. She has 7/8 of a gallon of paint remaining. Each statue requires 1/8 gallon of paint. How many statues can she paint? Pick one: A) 7 B) 20 C) 28 D) 14 E) 19 | <gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(7/8) / (1/8)</gadget>
<output>7</output>
<result>A</result> | A | 7 | Diana is painting statues. She has 7/8 of a gallon of paint remaining. Each statue requires 1/8 gallon of paint. How many statues can she paint? | {
"A": "7",
"B": "20",
"C": "28",
"D": "14",
"E": "19"
} | divide(divide(7, 8), divide(1, 8)) | divide(n0,n1)|divide(n2,n3)|divide(#0,#1)| | "number of statues = all the paint ÷ amount used per statue = 7 / 8 ÷ 1 / 8 = 7 / 8 * 8 / 1 = 7 / 1 = 7 answer is a ." | general |
math_qa__6F6QdIesGihcadpn | Jonathan can type a 10 page document in 40 minutes, Susan can type it in 30 minutes, and Jack can type it in 24 minutes. Working together, how much time will it take them to type the same document?
Choose the correct answer:
A) 5 minutes B) 10 minutes C) 15 minutes D) 18 minutes E) 20 minutes | <gadget id="calculator">10 / 24</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">10 / 40</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">10 / 30</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/4) + (1/3)</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">(5/12) + (7/12)</gadget>
<output>1</output>
<gadget id="calculator">10 / 1</gadget>
<output>10</output>
<result>B</result> | B | 10 | Jonathan can type a 10 page document in 40 minutes, Susan can type it in 30 minutes, and Jack can type it in 24 minutes. Working together, how much time will it take them to type the same document? | {
"A": "5 minutes",
"B": "10 minutes",
"C": "15 minutes",
"D": "18 minutes",
"E": "20 minutes"
} | divide(10, add(divide(10, 24), add(divide(10, 40), divide(10, 30)))) | divide(n0,n1)|divide(n0,n2)|divide(n0,n3)|add(#0,#1)|add(#3,#2)|divide(n0,#4)| | "you may set up common equation like this : job / a + job / b + job / c = job / x memorize this universal formula , you will need it definitely for gmat . and find x from this equation in this specific case , the equation will look like this : 10 / 40 + 10 / 30 + 10 / 24 = 10 / x if you solve this equation , you get the same answer b ( 10 )" | physics |
math_qa__hiMaArrMiM0tzN7x | A train 220 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? Choose the most appropriate option.
A) 12
B) 6
C) 7
D) 8
E) 9 | <gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">66 * (5/18)</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">220 / (55/3)</gadget>
<output>12</output>
<result>A</result> | A | 12 | A train 220 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? | {
"A": "12",
"B": "6",
"C": "7",
"D": "8",
"E": "9"
} | divide(220, multiply(add(60, 6), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 60 + 6 = 66 km / hr . = 66 * 5 / 18 = 55 / 3 m / sec . time taken to pass the men = 220 * 3 / 55 = 12 sec . answer : option a" | physics |
math_qa__AFG1aregVbPERnX3 | A cyclist rides a bicycle 8 km at an average speed of 11 km/hr and again travels 11 km at an average speed of 8 km/hr. What is the average speed for the entire trip? Choose the correct choice
A) 8.58 B) 8.76 C) 9.04 D) 9.12 E) 9.25 | <gadget id="calculator">8 + 11</gadget>
<output>19</output>
<gadget id="calculator">8 / 11</gadget>
<output>8/11 = around 0.727273</output>
<gadget id="calculator">11 / 8</gadget>
<output>11/8 = around 1.375</output>
<gadget id="calculator">(8/11) + (11/8)</gadget>
<output>185/88 = around 2.102273</output>
<gadget id="calculator">19 / (185/88)</gadget>
<output>1_672/185 = around 9.037838</output>
<result>C</result> | C | 9.04 | A cyclist rides a bicycle 8 km at an average speed of 11 km/hr and again travels 11 km at an average speed of 8 km/hr. What is the average speed for the entire trip? | {
"A": "8.58",
"B": "8.76",
"C": "9.04",
"D": "9.12",
"E": "9.25"
} | divide(add(8, 11), add(divide(8, 11), divide(11, 8))) | add(n0,n1)|divide(n0,n1)|divide(n1,n0)|add(#1,#2)|divide(#0,#3)| | "distance = 19 km time = 8 / 11 + 11 / 8 = ( 64 + 121 ) / 88 = 185 / 88 hours average speed = ( 19 * 88 ) / 185 = 9.04 km / h the answer is c ." | general |
math_qa__qDIhEfRswx1wAFCm | How many numbers from 13 to 76 are exactly divisible by 10?
Choose the correct choice from the following answers
A) 5
B) 6
C) 9
D) 11
E) 12 | <gadget id="calculator">76 / 10</gadget>
<output>38/5 = around 7.6</output>
<gadget id="calculator">floor(38/5)</gadget>
<output>7</output>
<gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">13 / 10</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">floor(13/10)</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">70 - 20</gadget>
<output>50</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>B</result> | B | 6 | How many numbers from 13 to 76 are exactly divisible by 10? | {
"A": "5",
"B": "6",
"C": "9",
"D": "11",
"E": "12"
} | add(divide(subtract(multiply(floor(divide(76, 10)), 10), multiply(add(floor(divide(13, 10)), const_1), 10)), 10), const_1) | divide(n1,n2)|divide(n0,n2)|floor(#0)|floor(#1)|add(#3,const_1)|multiply(n2,#2)|multiply(n2,#4)|subtract(#5,#6)|divide(#7,n2)|add(#8,const_1)| | "option ' b ' 13 / 10 = 1 and 76 / 10 = 7 = = > 7 - 1 = 6 numbers" | general |
math_qa__Y0oKhqydNJ8dAA6Z | Among all sales staff at Listco Corporation, college graduates and those without college degrees are equally represented . Each sales staff member is either a level-1 or level-2 employee. Level-1 college graduates account for 15% of Listco's sales staff. Listco employs 60 level-1 employees, 30 of whom are college graduates. How many sales staff members without college degrees are level-2 employees ? Choose one
A) 46 B) 42 C) 56 D) 70 E) 58 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">30 / (3/20)</gadget>
<output>200</output>
<gadget id="calculator">200 - 60</gadget>
<output>140</output>
<gadget id="calculator">140 / 2</gadget>
<output>70</output>
<result>D</result> | D | 70 | Among all sales staff at Listco Corporation, college graduates and those without college degrees are equally represented . Each sales staff member is either a level-1 or level-2 employee. Level-1 college graduates account for 15% of Listco's sales staff. Listco employs 60 level-1 employees, 30 of whom are college graduates. How many sales staff members without college degrees are level-2 employees ? | {
"A": "46",
"B": "42",
"C": "56",
"D": "70",
"E": "58"
} | divide(subtract(divide(30, divide(15, const_100)), 60), 2) | divide(n3,const_100)|divide(n6,#0)|subtract(#1,n4)|divide(#2,n1) | i ' m going in on this one . so let ' s say that we have the following so we know that l 1 = 60 and that c and l 1 = 0.15 x , we should set up a double set matrix btw but anyways , i ' m just explaining the point with this problem . now we are told that 0.15 x = 30 , therefore the grand total is 200 . now we know that l 2 is 200 - 60 = 140 . we also learn that c and no c are equally represented thus 100 each . therefore no c and no l 2 will be 100 - 30 = 70 . thus d is the correct answer choice | general |
math_qa__go7tLGjGLxpoIYRp | 90% of the population of a village is 8100. The total population of the village is? Choose one:
A) 9000
B) 24000
C) 26682
D) 29973
E) 12312 | <gadget id="calculator">100 / 90</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">(10/9) * 8_100</gadget>
<output>9_000</output>
<result>A</result> | A | 9,000 | 90% of the population of a village is 8100. The total population of the village is? | {
"A": "9000",
"B": "24000",
"C": "26682",
"D": "29973",
"E": "12312"
} | multiply(divide(const_100, 90), 8100) | divide(const_100,n0)|multiply(n1,#0)| | "x * ( 90 / 100 ) = 8100 x = 90 * 100 x = 9000 answer : a" | general |
math_qa__1V9VDPbN6zpqtNuI | A tank is filled by 3 pipes A,B,C in 4 hours. Pipe C is twice as fast as B and B is twice as fast as A. How much will pipe A alone take to fill the tank ? Choose one:
A) 25 hr
B) 35 hr
C) 40 hr
D) 20 hr
E) 28 hr | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 * 4</gadget>
<output>28</output>
<result>E</result> | E | 28 | A tank is filled by 3 pipes A,B,C in 4 hours. Pipe C is twice as fast as B and B is twice as fast as A. How much will pipe A alone take to fill the tank ? | {
"A": "25 hr",
"B": "35 hr",
"C": "40 hr",
"D": "20 hr",
"E": "28 hr"
} | multiply(add(add(multiply(const_2, const_2), const_2), const_1), 4) | multiply(const_2,const_2)|add(#0,const_2)|add(#1,const_1)|multiply(n1,#2)| | "suppose pipe a alone take x hours to fill the tank then pipe b and c will take x / 2 and x / 4 hours respectively to fill the tank . 1 / x + 2 / x + 4 / x = 1 / 4 7 / x = 1 / 4 x = 28 hours answer is e" | physics |
math_qa__Vjl37WSLR3EowI9O | A rectangular garden is to be twice as long as it is wide. If 240 yards of fencing, including the gate, will completely enclose the garden, what will be the length of the garden, in yards? Pick one
A) 40 B) 50 C) 60 D) 80 E) 100 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">240 / 6</gadget>
<output>40</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<result>D</result> | D | 80 | A rectangular garden is to be twice as long as it is wide. If 240 yards of fencing, including the gate, will completely enclose the garden, what will be the length of the garden, in yards? | {
"A": "40",
"B": "50",
"C": "60",
"D": "80",
"E": "100"
} | multiply(divide(240, multiply(add(const_2, const_1), const_2)), const_2) | add(const_1,const_2)|multiply(#0,const_2)|divide(n0,#1)|multiply(#2,const_2)| | "alternate approach backsolving ( using answer options to reach the correct answer ) can work wonders here if one is fast in calculations . given perimeter is 240 so , 2 ( l + b ) = 240 or , l + b = 120 now use the answer options ( given length ; breath will be half the length ) ( a ) 40 l = 40 ; b = 20 l + b = 60 ( b ) 50 l = 50 ; b = 25 l + b = 75 ( c ) 60 l = 60 ; b = 30 l + b = 90 ( d ) 80 l = 80 ; b = 40 l + b = 120 ( e ) 100 l = 100 ; b = 50 l + b = 150 thus you see no , need of any calculations , u can reach the correct option only by checking options ; correct answer will be ( d )" | geometry |
math_qa__g7KxvHDlvlqJo8Hw | At what rate percent on simple interest will Rs.415 amount to Rs.514 in 4 years ? Pick:
A) 4.58 % B) 5.96 % C) 6.52 % D) 4.98 % E) none of these | <gadget id="calculator">514 - 415</gadget>
<output>99</output>
<gadget id="calculator">99 / 415</gadget>
<output>99/415 = around 0.238554</output>
<gadget id="calculator">(99/415) / 4</gadget>
<output>99/1_660 = around 0.059639</output>
<gadget id="calculator">(99/1_660) * 100</gadget>
<output>495/83 = around 5.963855</output>
<result>B</result> | B | 5.96 | At what rate percent on simple interest will Rs.415 amount to Rs.514 in 4 years ? | {
"A": "4.58 %",
"B": "5.96 %",
"C": "6.52 %",
"D": "4.98 %",
"E": "none of these"
} | multiply(divide(divide(subtract(514, 415), 415), 4), const_100) | subtract(n1,n0)|divide(#0,n0)|divide(#1,n2)|multiply(#2,const_100)| | "explanation : difference in amount = 514 - 415 = 99 99 = ( 415 x 4 x r ) / 100 r = 5.96 % answer is b" | gain |
math_qa__pQRjEr9lGz2Flcf9 | The diagonals of a rhombus are 14 cm and 18 cm. Find its area? Select the correct option:
A) 176 B) 190 C) 150 D) 126 E) 292 | <gadget id="calculator">(14 * 18) / 2</gadget>
<output>126</output>
<result>D</result> | D | 126 | The diagonals of a rhombus are 14 cm and 18 cm. Find its area? | {
"A": "176",
"B": "190",
"C": "150",
"D": "126",
"E": "292"
} | rhombus_area(14, 18) | rhombus_area(n0,n1)| | "1 / 2 * 14 * 18 = 126 answer : d" | geometry |
math_qa__A37mrD4IN5HJodjZ | 75 is what percent of 125? Choose the correct choice from the following answers:
A) 60 % B) 40 % C) 45 % D) 50 % E) 55 % | <gadget id="calculator">75 / 125</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>A</result> | A | 60 | 75 is what percent of 125? | {
"A": "60 %",
"B": "40 %",
"C": "45 %",
"D": "50 %",
"E": "55 %"
} | multiply(divide(75, 125), const_100) | divide(n0,n1)|multiply(#0,const_100)| | 75 / 125 × 100 = 50 % answer : a | gain |
math_qa__woghVHuYO6WHQBgd | How much more would Rs.50000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly? Choose one:
A) 482
B) 1205
C) 992
D) 837
E) 923 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 4</gadget>
<output>14_641/10_000 = around 1.4641</output>
<gadget id="calculator">(14_641/10_000) * 50_000</gadget>
<output>73_205</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) ** 2</gadget>
<output>36/25 = around 1.44</output>
<gadget id="calculator">(36/25) * 50_000</gadget>
<output>72_000</output>
<gadget id="calculator">73_205 - 72_000</gadget>
<output>1_205</output>
<result>B</result> | B | 1,205 | How much more would Rs.50000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly? | {
"A": "482",
"B": "1205",
"C": "992",
"D": "837",
"E": "923"
} | subtract(multiply(power(add(const_1, divide(divide(20, const_100), const_2)), const_4), 50000), multiply(power(add(divide(20, const_100), const_1), const_2), 50000)) | divide(n1,const_100)|add(#0,const_1)|divide(#0,const_2)|add(#2,const_1)|power(#1,const_2)|multiply(n0,#4)|power(#3,const_4)|multiply(n0,#6)|subtract(#7,#5)| | "50000 ( 11 / 10 ) 4 - 50000 ( 6 / 5 ) 2 = 1205 answer : b" | gain |
math_qa__kfMuAIDF5WF6cstg | A certain psychologist charges $40 more for the first hour of therapy than for each additional hour. If the total charge to a patient who receives 5 hours of therapy is $375, what is the total charge to a patient who receives only 2 hours of therapy ?
Choose the correct choice from the following options:
A) $ 120 B) $ 135 C) $ 150 D) $ 174 E) $ 192 | <gadget id="calculator">375 - 40</gadget>
<output>335</output>
<gadget id="calculator">335 / 5</gadget>
<output>67</output>
<gadget id="calculator">67 * 2</gadget>
<output>134</output>
<gadget id="calculator">134 + 40</gadget>
<output>174</output>
<result>D</result> | D | 174 | A certain psychologist charges $40 more for the first hour of therapy than for each additional hour. If the total charge to a patient who receives 5 hours of therapy is $375, what is the total charge to a patient who receives only 2 hours of therapy ? | {
"A": "$ 120",
"B": "$ 135",
"C": "$ 150",
"D": "$ 174",
"E": "$ 192"
} | add(multiply(divide(subtract(375, 40), 5), 2), 40) | subtract(n2,n0)|divide(#0,n1)|multiply(n3,#1)|add(n0,#2) | let the charge for first hour = x + 40 then charge for each additional hour = x x + 40 + 4 x = 375 = > 5 x = 335 = > x = 67 total charge for patient for 3 hours of therapy = x + 40 + x = 2 x + 40 = 174 $ answer d | general |
math_qa__y6KhzGQbLbwVvPKW | If the product 4864*9 P 2 is divisible by 12, the value of p? Choose the correct choice from the following choices
A) 1
B) 5
C) 6
D) 7
E) 9 | <gadget id="calculator">4_864 * 9</gadget>
<output>43_776</output>
<gadget id="calculator">43_776 * 2</gadget>
<output>87_552</output>
<gadget id="calculator">87_552 / 12</gadget>
<output>7_296</output>
<gadget id="calculator">7_296 / 7_296</gadget>
<output>1</output>
<result>A</result> | A | 1 | If the product 4864*9 P 2 is divisible by 12, the value of p? | {
"A": "1",
"B": "5",
"C": "6",
"D": "7",
"E": "9"
} | divide(divide(multiply(multiply(4864, 9), 2), 12), divide(multiply(multiply(4864, 9), 2), 12)) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n3)|divide(#2,#2) | explanation : clearly 4864 is divisible by 4 so 9 p 2 must be divisible by 3 . so ( 9 + p + 2 ) must be divisible by 3 . so p = 1 . answer : a ) 1 | general |
math_qa__Wb6Jzl8NTvVTUnp8 | How many multiples of 4 are there between 20 and 112, inclusive?
Select the correct option:
A) 21
B) 22
C) 23
D) 24
E) 25 | <gadget id="calculator">112 - 20</gadget>
<output>92</output>
<gadget id="calculator">92 / 4</gadget>
<output>23</output>
<gadget id="calculator">23 + 1</gadget>
<output>24</output>
<result>D</result> | D | 24 | How many multiples of 4 are there between 20 and 112, inclusive? | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | add(divide(subtract(112, 20), 4), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "the multiples of 4 are from 4 * 5 up to 4 * 28 . 28 - 5 + 1 = 24 . the answer is d ." | general |
math_qa__h4X3w5tnM802aflY | A fellow borrowed a certain sum of money at 5% per annum at simple interest and in 5 years the interest amounted to Rs.750 less than the sum lent. What was the sum lent? Answers:
A) 1000
B) 1220
C) 1250
D) 1060
E) 1110 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">750 / (3/4)</gadget>
<output>1_000</output>
<result>A</result> | A | 1,000 | A fellow borrowed a certain sum of money at 5% per annum at simple interest and in 5 years the interest amounted to Rs.750 less than the sum lent. What was the sum lent? | {
"A": "1000",
"B": "1220",
"C": "1250",
"D": "1060",
"E": "1110"
} | divide(750, subtract(const_1, divide(multiply(5, 5), const_100))) | multiply(n0,n0)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2) | p - 750 = ( p * 5 * 5 ) / 100 p = 1000 answer : a | gain |
math_qa__N2cX5YaoLWZeXBtH | For any number Z, Z* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.32 – 6.32*? Choices:
A) 1.5
B) 0.5
C) 0.32
D) 0.25
E) 6.32 | <gadget id="calculator">floor(6.32)</gadget>
<output>6</output>
<gadget id="calculator">6.32 - 6</gadget>
<output>0.32</output>
<result>C</result> | C | 0.32 | For any number Z, Z* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.32 – 6.32*? | {
"A": "1.5",
"B": "0.5",
"C": "0.32",
"D": "0.25",
"E": "6.32"
} | subtract(6.32, floor(6.32)) | floor(n0)|subtract(n0,#0) | since z * is defined as the greatest positive even integer less than or equal to z , then 6.32 * = 6 ( the greatest positive even integer less than or equal to 6.32 is 6 ) . hence , 6.32 – 6.32 * = 6.32 - 6 = 0.32 answer : c . | general |
math_qa__1mK6nWvKXhfekYUN | A solution contains 8 parts of water for every 7 parts of Lemonade syrup. How many parts of the solution should be removed and replaced with water so that the solution will now contain 20% lemonade syrup? Choose the correct choice from the following answers:
A) 1.5
B) 1.75
C) 2.14
D) 2.34
E) 2.64 | <gadget id="calculator">8 + 7</gadget>
<output>15</output>
<gadget id="calculator">7 / 15</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(7/15) - (2/5)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) / (7/15)</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/7) * 15</gadget>
<output>15/7 = around 2.142857</output>
<result>C</result> | C | 2.14 | A solution contains 8 parts of water for every 7 parts of Lemonade syrup. How many parts of the solution should be removed and replaced with water so that the solution will now contain 20% lemonade syrup? | {
"A": "1.5",
"B": "1.75",
"C": "2.14",
"D": "2.34",
"E": "2.64"
} | multiply(divide(subtract(divide(7, add(8, 7)), divide(const_2, add(const_2, const_3))), divide(7, add(8, 7))), add(8, 7)) | add(n0,n1)|add(const_2,const_3)|divide(n1,#0)|divide(const_2,#1)|subtract(#2,#3)|divide(#4,#2)|multiply(#0,#5) | let the total solution is 150 l with 80 l water 70 l syrup . to make 20 % syrup solution , the result solution must have 120 l syrup and 30 l syrup . therefore we are taking 40 l of syrup from initial solution and replacing with water . using urinary method : 70 l syrup in 150 l solution 40 l syrup in 85.7 l solution we started by multiplying 10 now to get to the result we need to divide by 40 = > amount of solution to be replaced with water = ( 85.7 / 40 ) = 2.14 . correct option : c | gain |
math_qa__F8cv88T6Crs865Kh | The total age of A and B is 18 years more than the total age of B and C. C is how many years younger than A ? Select: A) 12 B) 27 C) 21 D) 18 E) 11 | <gadget id="calculator">18 * 1</gadget>
<output>18</output>
<result>D</result> | D | 18 | The total age of A and B is 18 years more than the total age of B and C. C is how many years younger than A ? | {
"A": "12",
"B": "27",
"C": "21",
"D": "18",
"E": "11"
} | multiply(18, const_1) | multiply(n0,const_1) | ( a + b ) - ( b + c ) = 18 a - c = 18 . c is younger than a by 18 years . answer : d | general |
math_qa__Nf5PEzjWz88KpEXl | If x is divided by 7, the remainder is 5. What is the remainder if 4x is divided by 7? Answers.
A) 1
B) 2
C) 4
D) 6
E) 8 | <gadget id="calculator">4 * 7</gadget>
<output>28</output>
<gadget id="calculator">28 + 10</gadget>
<output>38</output>
<gadget id="calculator">38 + 10</gadget>
<output>48</output>
<gadget id="calculator">48 / 4</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>D</result> | D | 6 | If x is divided by 7, the remainder is 5. What is the remainder if 4x is divided by 7? | {
"A": "1",
"B": "2",
"C": "4",
"D": "6",
"E": "8"
} | divide(divide(add(add(multiply(4, 7), const_10), const_10), 4), const_2) | multiply(n0,n2)|add(#0,const_10)|add(#1,const_10)|divide(#2,n2)|divide(#3,const_2) | x = 7 q + 5 4 x = 7 * 4 q + 20 4 x = 7 * 4 q + 7 * 2 + 6 4 x = 7 ( 4 q + 2 ) + 6 4 x = 7 k + 6 ( k = 4 q + 2 ) answer d | general |
math_qa__NhFtpeX2coZr9u7w | The speed of a boat in still water is 21 km/hr and the rate of current is 8 km/hr. The distance travelled downstream in 13 minutes is Select the correct option:
A) 1.6 km
B) 2 km
C) 6.3 km
D) 4 km
E) none of these | <gadget id="calculator">13 / 60</gadget>
<output>13/60 = around 0.216667</output>
<gadget id="calculator">21 + 8</gadget>
<output>29</output>
<gadget id="calculator">(13/60) * 29</gadget>
<output>377/60 = around 6.283333</output>
<result>C</result> | C | 6.3 | The speed of a boat in still water is 21 km/hr and the rate of current is 8 km/hr. The distance travelled downstream in 13 minutes is | {
"A": "1.6 km",
"B": "2 km",
"C": "6.3 km",
"D": "4 km",
"E": "none of these"
} | multiply(divide(13, const_60), add(21, 8)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "explanation : speed downstreams = ( 21 + 8 ) kmph = 18 kmph . distance travelled = ( 29 x 13 / 60 ) km = 6.3 km option c" | physics |
math_qa__ltcoZ1pczQKswlVV | 3 candidates in an election and received 3000, 5000 and 20000 votes respectively. What % of the total votes did the winningcandidate got in that election? Select.
A) 45.12 %
B) 50 %
C) 57 %
D) 71.42 %
E) 65 % | <gadget id="calculator">3_000 + 5_000</gadget>
<output>8_000</output>
<gadget id="calculator">8_000 + 20_000</gadget>
<output>28_000</output>
<gadget id="calculator">20_000 / 28_000</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">(5/7) * 100</gadget>
<output>500/7 = around 71.428571</output>
<result>D</result> | D | 71.42 | 3 candidates in an election and received 3000, 5000 and 20000 votes respectively. What % of the total votes did the winningcandidate got in that election? | {
"A": "45.12 %",
"B": "50 %",
"C": "57 %",
"D": "71.42 %",
"E": "65 %"
} | multiply(divide(20000, add(add(3000, 5000), 20000)), const_100) | add(n1,n2)|add(n3,#0)|divide(n3,#1)|multiply(#2,const_100)| | "total number of votes polled = ( 3000 + 5000 + 20000 ) = 28000 so , required percentage = 11628 / 20400 * 100 = 71.42 % d" | gain |
math_qa__ivRcLnExMM4BMatc | A clock shows the time as 9 a.m. If the minute hand gains 5 minutes every hour, how many minutes will the clock gain by 4 p.m.? Choose the correct choice:
A) 30 min B) 35 min C) 45 min D) 50 min E) 55 min | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<result>B</result> | B | 35 | A clock shows the time as 9 a.m. If the minute hand gains 5 minutes every hour, how many minutes will the clock gain by 4 p.m.? | {
"A": "30 min",
"B": "35 min",
"C": "45 min",
"D": "50 min",
"E": "55 min"
} | multiply(add(const_3, const_4), 5) | add(const_3,const_4)|multiply(n1,#0) | there are 7 hours in between 9 a . m . to 4 p . m . 7 * 5 = 35 minutes . answer : b | physics |
math_qa__NaPEKzmRasmHi8jn | The average weight of 4 person's increases by 3 kg when a new person comes in place of one of them weighing 70 kg. What might be the weight of the new person?
Select.
A) 75 kg B) 82 kg C) 86 kg D) data inadequate E) none of these | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 + 70</gadget>
<output>82</output>
<result>B</result> | B | 82 | The average weight of 4 person's increases by 3 kg when a new person comes in place of one of them weighing 70 kg. What might be the weight of the new person? | {
"A": "75 kg",
"B": "82 kg",
"C": "86 kg",
"D": "data inadequate",
"E": "none of these"
} | add(multiply(4, 3), 70) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 4 x 3 ) kg = 12 kg . weight of new person = ( 70 + 12 ) kg = 82 kg . answer : option b" | general |
math_qa__raS1WRk6K2Dit4Re | The no. of girls in a class are 7times the no. of boys, which value cannever be the of total students? Choose the correct choice from the following: A) 20 B) 35 C) 30 D) 40 E) 42 | <gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">8 * 4</gadget>
<output>32</output>
<gadget id="calculator">32 - 2</gadget>
<output>30</output>
<result>C</result> | C | 30 | The no. of girls in a class are 7times the no. of boys, which value cannever be the of total students? | {
"A": "20",
"B": "35",
"C": "30",
"D": "40",
"E": "42"
} | subtract(multiply(add(7, const_1), const_4), const_2) | add(n0,const_1)|multiply(#0,const_4)|subtract(#1,const_2) | let the boys are x , then girls are 7 x , total = x + 7 x = 8 x so it should be multiple of 8 , 30 is not a multiple of 8 . c | general |
math_qa__85Q2VQkT2u5SGGk8 | A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 650 sq. feet, how many feet of fencing will be required? Choose the correct answer.
A) 34
B) 40
C) 85
D) 88
E) none | <gadget id="calculator">650 / 20</gadget>
<output>65/2 = around 32.5</output>
<gadget id="calculator">(65/2) * 2</gadget>
<output>65</output>
<gadget id="calculator">65 + 20</gadget>
<output>85</output>
<result>C</result> | C | 85 | A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 650 sq. feet, how many feet of fencing will be required? | {
"A": "34",
"B": "40",
"C": "85",
"D": "88",
"E": "none"
} | add(multiply(divide(650, 20), const_2), 20) | divide(n1,n0)|multiply(#0,const_2)|add(n0,#1)| | "explanation we have : l = 20 ft and lb = 650 sq . ft . so , b = 32.5 ft . length of fencing = ( l + 2 b ) = ( 20 + 65 ) ft = 85 ft . answer c" | geometry |
math_qa__tqj0uBOfqLcbIBsT | John want to buy a $100 Trouser at the store, but he think it’s too expensive. Finally, it goes on sale for $50. What is the percent decrease? Choose the correct option:
A) 20 % B) 30 % C) 50 % D) 70 % E) 80 % | <gadget id="calculator">100 - 50</gadget>
<output>50</output>
<result>C</result> | C | 50 | John want to buy a $100 Trouser at the store, but he think it’s too expensive. Finally, it goes on sale for $50. What is the percent decrease? | {
"A": "20 %",
"B": "30 %",
"C": "50 %",
"D": "70 %",
"E": "80 %"
} | subtract(100, 50) | subtract(n0,n1)| | "the is always the difference between our starting and ending points . in this case , it ’ s 100 – 50 = 50 . the “ original ” is our starting point ; in this case , it ’ s 100 . ( 50 / 100 ) * 100 = ( 0.5 ) * 100 = 50 % . c" | general |
math_qa__mUCG5GXXHadQ15Dk | 10% of a number is more than 20% of 650 by 190. Find the number?
Choose the correct choice from the following answers.
A) 288 B) 3200 C) 800 D) 267 E) 121 | <gadget id="calculator">650 * 20</gadget>
<output>13_000</output>
<gadget id="calculator">13_000 / 100</gadget>
<output>130</output>
<gadget id="calculator">130 + 190</gadget>
<output>320</output>
<gadget id="calculator">320 * 100</gadget>
<output>32_000</output>
<gadget id="calculator">32_000 / 10</gadget>
<output>3_200</output>
<result>B</result> | B | 3,200 | 10% of a number is more than 20% of 650 by 190. Find the number? | {
"A": "288",
"B": "3200",
"C": "800",
"D": "267",
"E": "121"
} | divide(multiply(add(divide(multiply(650, 20), const_100), 190), const_100), 10) | multiply(n1,n2)|divide(#0,const_100)|add(n3,#1)|multiply(#2,const_100)|divide(#3,n0)| | "( 10 / 100 ) * x â € “ ( 20 / 100 ) * 650 = 190 1 / 10 x = 320 x = 3200 answer : b" | gain |
math_qa__eaimnXFkJvgTShRR | The ratio of spinsters to cats is 2 to 9. If there are 63 more cats than spinsters, how many spinsters are there? Choices.
A) 10
B) 12
C) 14
D) 16
E) 18 | <gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">63 / 7</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<result>E</result> | E | 18 | The ratio of spinsters to cats is 2 to 9. If there are 63 more cats than spinsters, how many spinsters are there? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | multiply(divide(63, subtract(9, 2)), 2) | subtract(n1,n0)|divide(n2,#0)|multiply(n0,#1)| | "let 2 x be the number of spinsters . then 9 x is the number of cats . 9 x - 2 x = 63 x = 9 and the number of spinsters is 2 ( 9 ) = 18 . the answer is e ." | other |
math_qa__Gm5N4dsGtEJLtA1Y | A survey of employers found that during 1993 employment costs rose 3.5 percent, where employment costs consist of salary costs and fringe-benefit costs. If salary costs rose 3 percent and fringe-benefit costs rose 8.5 percent during 1993, then fringe-benefit costs represented what percent of employment costs at the beginning of 1993 ? Options: A) 16.5 % B) 9 % C) 35 % D) 55 % E) 65 % | <gadget id="calculator">3.5 - 3</gadget>
<output>0.5</output>
<gadget id="calculator">8.5 - 3</gadget>
<output>5.5</output>
<gadget id="calculator">0.5 / 5.5</gadget>
<output>0.090909</output>
<gadget id="calculator">0.090909 * 100</gadget>
<output>9.0909</output>
<result>B</result> | B | 9 | A survey of employers found that during 1993 employment costs rose 3.5 percent, where employment costs consist of salary costs and fringe-benefit costs. If salary costs rose 3 percent and fringe-benefit costs rose 8.5 percent during 1993, then fringe-benefit costs represented what percent of employment costs at the beginning of 1993 ? | {
"A": "16.5 %",
"B": "9 %",
"C": "35 %",
"D": "55 %",
"E": "65 %"
} | multiply(divide(subtract(3.5, 3), subtract(8.5, 3)), const_100) | subtract(n1,n2)|subtract(n3,n2)|divide(#0,#1)|multiply(#2,const_100)| | "the amount by which employment costs rose is equal to 0.035 ( salary costs + fringe benefit costs ) ; on the other hand the amount by which employment costs rose is equal to 0.03 * salary costs + 0.085 * fringe benefit costs ; so , 35 ( s + f ) = 30 s + 85 f - - > s = 10 f - - > f / s = 1 / 10 - - > f / ( s + f ) = 1 / ( 1 + 10 ) = 1 / 11 = 0.09 . answer : b ." | gain |
math_qa__dlqK4Jy1ldXFtxfY | The time it took car P to travel 600 miles was 2 hours less than the time it took car R to travel the same distance. If car P’s average speed was 10 miles per hour greater than that of car R, what was car R’s average speed, in miles per hour? Choose the correct choice:
A) 40 B) 50 C) 60 D) 70 E) 80 | <gadget id="calculator">-10</gadget>
<output>-10</output>
<gadget id="calculator">(-10) ** 2</gadget>
<output>100</output>
<gadget id="calculator">600 * 10</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 2</gadget>
<output>3_000</output>
<gadget id="calculator">-3_000</gadget>
<output>-3_000</output>
<gadget id="calculator">4 * (-3_000)</gadget>
<output>-12_000</output>
<gadget id="calculator">100 - (-12_000)</gadget>
<output>12_100</output>
<gadget id="calculator">12_100 ** (1/2)</gadget>
<output>110</output>
<gadget id="calculator">(-10) + 110</gadget>
<output>100</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<result>B</result> | B | 50 | The time it took car P to travel 600 miles was 2 hours less than the time it took car R to travel the same distance. If car P’s average speed was 10 miles per hour greater than that of car R, what was car R’s average speed, in miles per hour? | {
"A": "40",
"B": "50",
"C": "60",
"D": "70",
"E": "80"
} | divide(add(negate(10), sqrt(subtract(power(negate(10), 2), multiply(const_4, negate(divide(multiply(600, 10), 2)))))), 2) | multiply(n0,n2)|negate(n2)|divide(#0,n1)|power(#1,n1)|negate(#2)|multiply(#4,const_4)|subtract(#3,#5)|sqrt(#6)|add(#1,#7)|divide(#8,n1)| | "let speed of car r be = x then speed of car p = x + 10 a / q , ( 600 / x ) - ( 600 / ( x + 10 ) ) = 2 solving for x = 50 miles \ hr answer : b" | physics |
math_qa__pWx5ZNupAOKUMGtk | The H.C.F. of two numbers is 60 and the other two factors of their L.C.M. are 11 and 15. The larger of the two numbers is: Pick:
A) 276 B) 300 C) 500 D) 700 E) 900 | <gadget id="calculator">60 * 15</gadget>
<output>900</output>
<result>E</result> | E | 900 | The H.C.F. of two numbers is 60 and the other two factors of their L.C.M. are 11 and 15. The larger of the two numbers is: | {
"A": "276",
"B": "300",
"C": "500",
"D": "700",
"E": "900"
} | multiply(60, 15) | multiply(n0,n2)| | "the numbers are ( 60 x 11 ) and ( 60 x 15 ) . larger number = ( 60 x 15 ) = 900 . answer : e" | other |
math_qa__Y0PlIJMS164qcLsL | The number of even factors of 21600 is Options
A) 32 B) 42 C) 60 D) 25 E) 52 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">24 * 3</gadget>
<output>72</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">72 - 12</gadget>
<output>60</output>
<result>C</result> | C | 60 | The number of even factors of 21600 is | {
"A": "32",
"B": "42",
"C": "60",
"D": "25",
"E": "52"
} | subtract(multiply(multiply(add(add(const_2, const_3), const_1), add(const_3, const_1)), add(const_2, const_1)), multiply(add(const_3, const_1), add(const_2, const_1))) | add(const_1,const_2)|add(const_2,const_3)|add(const_1,const_3)|add(#1,const_1)|multiply(#2,#0)|multiply(#3,#2)|multiply(#0,#5)|subtract(#6,#4) | make a prime factorization of the number : 21,600 = 25 ∗ 33 ∗ 52 according to the above the number of factors is ( 5 + 1 ) ( 3 + 1 ) ( 2 + 1 ) = 72 now , get rid of powers of 2 as they give even factors - - > you ' ll have 33 ∗ 52 which has ( 3 + 1 ) ( 2 + 1 ) = 12 factors . all the remaining factors will be odd , therefore 21,600 has 72 - 12 = 60 even factors . answer : c . | other |
math_qa__fhZO6sM1apiEOe39 | At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 10 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank? Choose the correct choice from the following choices: A) 3 / 25 B) 5 / 6 C) 7 / 12 D) 2 / 3 E) 25 / 36 | <gadget id="calculator">50 * 5</gadget>
<output>250</output>
<gadget id="calculator">250 / 30</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">(25/3) / 10</gadget>
<output>5/6 = around 0.833333</output>
<result>B</result> | B | 0.833333 | At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 10 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank? | {
"A": "3 / 25",
"B": "5 / 6",
"C": "7 / 12",
"D": "2 / 3",
"E": "25 / 36"
} | divide(divide(multiply(50, 5), 30), 10) | multiply(n0,n4)|divide(#0,n2)|divide(#1,n3)| | "gas used = ( 5 hours ) * ( 50 miles / hour ) * ( 1 gallon / 30 miles ) = 8 + 1 / 3 gallons portion used = ( 8 + 1 / 3 ) / 10 = 5 / 6 ans b" | physics |
math_qa__POC4gb8jZ5PyINRI | What least number should be subtracted from 2590 so that the remainder when divided by 9, 11, and 13 will leave in each case the same remainder 6 ? Choose the correct answer:
A) 2 B) 3 C) 6 D) 10 E) 11 | <gadget id="calculator">9 * 11</gadget>
<output>99</output>
<gadget id="calculator">99 * 13</gadget>
<output>1_287</output>
<gadget id="calculator">1_287 * 2</gadget>
<output>2_574</output>
<gadget id="calculator">2_574 + 6</gadget>
<output>2_580</output>
<gadget id="calculator">2_590 - 2_580</gadget>
<output>10</output>
<result>D</result> | D | 10 | What least number should be subtracted from 2590 so that the remainder when divided by 9, 11, and 13 will leave in each case the same remainder 6 ? | {
"A": "2",
"B": "3",
"C": "6",
"D": "10",
"E": "11"
} | subtract(2590, add(multiply(multiply(multiply(9, 11), 13), const_2), 6)) | multiply(n1,n2)|multiply(n3,#0)|multiply(#1,const_2)|add(n4,#2)|subtract(n0,#3)| | "the lcm of 9 , 11 , and 13 is 1,287 . the next multiple is 2 * 1,287 = 2,574 . 2,574 + { remainder } = 2,574 + 6 = 2,580 , which is 10 less than 2,590 . answer : d ." | general |
math_qa__Uh4MvRrwfpUNKIAx | The second angle of a triangle is double the first(110). The third angle is 40 less than
the first(15). Find the first angle. Select the correct option:
A) 35 B) 45 C) 55 D) 65 E) 75 | <gadget id="calculator">40 + 15</gadget>
<output>55</output>
<result>C</result> | C | 55 | The second angle of a triangle is double the first(110). The third angle is 40 less than
the first(15). Find the first angle. | {
"A": "35",
"B": "45",
"C": "55",
"D": "65",
"E": "75"
} | add(40, 15) | add(n1,n2) | first x with nothing given about the firstwemake that x second 2 x the second is double the first , third x − 40 the third is 40 less than the first f + s + t = 180 all three angles add to 180 ( x ) + ( 2 x ) + ( x − 40 ) = 180 replace f , s , and t with the labeled values . x + 2 x + x − 40 = 180 here the parenthesis are not needed . 4 x − 40 = 180 combine like terms , x + 2 x + x + 40 + 40 add 40 to both sides 4 x = 220 the variable ismultiplied by 4 4 4 divide both sides by 4 x = 55 our solution for x first 55 replace xwith 55 in the original list of angles second 2 ( 55 ) = 110 our angles are 55 , 110 , and 15 third ( 55 ) − 40 = 15 correct answer c | geometry |
math_qa__Y72qAog3P8jD69Ca | For each of her sales, a saleswoman receives a commission equal to 20 percent of the first $500 of the total amount of the sale, plus 25 percent of the total amount in excess of $500. If the total amount of one of her sales was $800, the saleswoman’s commission was approximately what percent of the total amount of the sale? Choose the correct choice:
A) 22 %
B) 24 %
C) 25 %
D) 27 %
E) 28 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 500</gadget>
<output>100</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">800 - 500</gadget>
<output>300</output>
<gadget id="calculator">(1/4) * 300</gadget>
<output>75</output>
<gadget id="calculator">100 + 75</gadget>
<output>175</output>
<gadget id="calculator">175 / 800</gadget>
<output>7/32 = around 0.21875</output>
<gadget id="calculator">(7/32) * 100</gadget>
<output>175/8 = around 21.875</output>
<result>A</result> | A | 22 | For each of her sales, a saleswoman receives a commission equal to 20 percent of the first $500 of the total amount of the sale, plus 25 percent of the total amount in excess of $500. If the total amount of one of her sales was $800, the saleswoman’s commission was approximately what percent of the total amount of the sale? | {
"A": "22 %",
"B": "24 %",
"C": "25 %",
"D": "27 %",
"E": "28 %"
} | multiply(divide(add(multiply(divide(20, const_100), 500), multiply(divide(25, const_100), subtract(800, 500))), 800), const_100) | divide(n0,const_100)|divide(n2,const_100)|subtract(n4,n1)|multiply(n1,#0)|multiply(#1,#2)|add(#3,#4)|divide(#5,n4)|multiply(#6,const_100)| | "total sales = 800 comission = ( 20 / 100 ) * 500 + ( 25 / 100 ) * 300 = 100 + 75 = 175 % comission = ( 175 / 800 ) * 100 = 21.8 ~ 22 % answer is a" | general |
math_qa__Lywjy5ppEGWXTTRX | Mike took a bus from home to market, that travels at 30 kmph. While walking back at 6 kmph,
halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 20 kmph. Find the average speed.
Choose the correct choice
A) 21.2 kmph B) 12.1 kmph C) 23.4 kmph D) 20.4 kmph E) none of these | <gadget id="calculator">6 + 20</gadget>
<output>26</output>
<gadget id="calculator">26 / 2</gadget>
<output>13</output>
<gadget id="calculator">13 + 30</gadget>
<output>43</output>
<gadget id="calculator">43 / 2</gadget>
<output>43/2 = around 21.5</output>
<result>A</result> | A | 21.2 | Mike took a bus from home to market, that travels at 30 kmph. While walking back at 6 kmph,
halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 20 kmph. Find the average speed. | {
"A": "21.2 kmph",
"B": "12.1 kmph",
"C": "23.4 kmph",
"D": "20.4 kmph",
"E": "none of these"
} | divide(add(divide(add(6, 20), const_2), 30), const_2) | add(n1,n2)|divide(#0,const_2)|add(n0,#1)|divide(#2,const_2) | let the distance be 2 x ( one way ) time taken by bus = 2 x / 30 , by walking = x / 6 , by cycling = x / 20 hours : . average speed = total distance / total time = 6 x / x / 15 + x / 6 + x / 20 = 6 * 60 / 4 + 10 + 3 = 21.2 answer : a | physics |
math_qa__pzgVOZaK0Q7W4c81 | In the youth summer village there are 100 people, 50 of them are not working,25 of them have families and 75 of them like to sing in the shower. What is the largest possible number of people in the village, which are working, that don't have families and that are singing in the shower? Pick
A) 100 B) 75 C) 25 D) 50 E) 125 | <gadget id="calculator">50 + 25</gadget>
<output>75</output>
<gadget id="calculator">75 + 75</gadget>
<output>150</output>
<gadget id="calculator">150 - 100</gadget>
<output>50</output>
<result>D</result> | D | 50 | In the youth summer village there are 100 people, 50 of them are not working,25 of them have families and 75 of them like to sing in the shower. What is the largest possible number of people in the village, which are working, that don't have families and that are singing in the shower? | {
"A": "100",
"B": "75",
"C": "25",
"D": "50",
"E": "125"
} | subtract(add(add(50, 25), 75), 100) | add(n1,n2)|add(n3,#0)|subtract(#1,n0)| | "total = 100 not working = 50 having family = 25 like to sing in shower = 75 working = 100 - 50 = 50 not having family = 100 - 25 = 75 like to sing in shower = 75 largest possible number is the lowest possible among the above thus 50 d" | general |
math_qa__ydq1gojgiGE4ZsCU | A train 130 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going? Choose the correct option
A) 4 B) 7 C) 5 D) 9 E) 8 | <gadget id="calculator">130 / 1_000</gadget>
<output>13/100 = around 0.13</output>
<gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">(13/100) / 66</gadget>
<output>13/6_600 = around 0.00197</output>
<gadget id="calculator">3_600 * (13/6_600)</gadget>
<output>78/11 = around 7.090909</output>
<result>B</result> | B | 7 | A train 130 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going? | {
"A": "4",
"B": "7",
"C": "5",
"D": "9",
"E": "8"
} | multiply(const_3600, divide(divide(130, const_1000), add(60, 6))) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_3600)| | "speed of train relative to man = ( 60 + 6 ) km / hr = 66 km / hr [ 66 * 5 / 18 ] m / sec = [ 55 / 3 ] m / sec . time taken to pass the man = [ 130 * 3 / 55 ] sec = 7 sec answer : b" | physics |
math_qa__lNVS6rYH4EnVtjGq | A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent J of the distribution is less than m +d ? Select the correct option: A) 16 % B) 32 % C) 48 % D) 84 % E) 92 % | <gadget id="calculator">100 - 68</gadget>
<output>32</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<gadget id="calculator">100 - 16</gadget>
<output>84</output>
<result>D</result> | D | 84 | A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent J of the distribution is less than m +d ? | {
"A": "16 %",
"B": "32 %",
"C": "48 %",
"D": "84 %",
"E": "92 %"
} | subtract(const_100, divide(subtract(const_100, 68), const_2)) | subtract(const_100,n0)|divide(#0,const_2)|subtract(const_100,#1)| | "d the prompt says that 68 % of the population lies between m - d and m + d . thus , 32 % of the population is less than m - d or greater than m + d . since the population is symmetric , half of this 32 % is less than m - d and half is greater than m + d . thus , j = ( 68 + 16 ) % or ( 100 - 16 ) % of the population is less than m + d . d" | general |
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