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stringlengths 45
1.01k
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float64 -4,212
100B
| question_without_options
stringlengths 6
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stringlengths 7
6.48k
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stringlengths 8
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math_qa__329SEZPh4uEWgHwp | An inspector rejects 0.07% of the meters as defective. How many will he examine to reject 2? Pick:
A) 1500
B) 2000
C) 2857
D) 3000
E) 3100 | <gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 / 0.07</gadget>
<output>2_857.142857</output>
<result>C</result> | C | 2,857 | An inspector rejects 0.07% of the meters as defective. How many will he examine to reject 2? | {
"A": "1500",
"B": "2000",
"C": "2857",
"D": "3000",
"E": "3100"
} | divide(multiply(2, const_100), 0.07) | multiply(n1,const_100)|divide(#0,n0)| | "let the number of meters to be examined be x then , 0.07 % of x = 2 ( 7 / 100 ) * ( ( 1 / 100 ) * x = 2 x = 2857 answer is c" | gain |
math_qa__BwCDtW6QCkKilC08 | Teas worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs 154 per Kg , the price of the third variety per Kg will be?
Select: A) rs . 147.50 B) rs . 785.50 C) rs . 176.50 D) rs . 258.50 E) none of these | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">154 * 4</gadget>
<output>616</output>
<gadget id="calculator">126 + 135</gadget>
<output>261</output>
<gadget id="calculator">616 - 261</gadget>
<output>355</output>
<gadget id="calculator">355 / 2</gadget>
<output>355/2 = around 177.5</output>
<result>C</result> | C | 176.5 | Teas worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs 154 per Kg , the price of the third variety per Kg will be? | {
"A": "rs . 147.50",
"B": "rs . 785.50",
"C": "rs . 176.50",
"D": "rs . 258.50",
"E": "none of these"
} | divide(subtract(multiply(154, add(add(1, 1), 2)), add(126, 135)), 2) | add(n2,n2)|add(n0,n1)|add(n4,#0)|multiply(n5,#2)|subtract(#3,#1)|divide(#4,n4)| | "explanation : since first and second varieties are mixed in equal proportions . so , their average price = rs . ( 126 + 135 ) / 2 . = > rs . 130.50 . so , the mixture is formed by mixing two varieties , one at rs . 130.50 per kg and the other at say , rs . x per kg in the ratio 2 : 2 , i . e . , 1 : 1 . we have to find x . by the rule of alligation , we have : cost of 1 kg cost of 1 kg of 1 st kind of 2 nd kind ( rs . 130.50 ) ( rs . x ) \ / mean price ( rs . 154 ) / \ x â ˆ ’ 154 22.50 = > x â ˆ ’ ( 154 / 22.50 ) = 1 . = > x â ˆ ’ 154 = 22.50 . = > x = 176.50 rs . answer : c" | other |
math_qa__8gkJWZ2AvomCfosT | Mother,her daughter and her grand child weighs 110 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter? Answers: A) 46 B) 47 C) 48 D) 49 E) 50 | <gadget id="calculator">110 - 60</gadget>
<output>50</output>
<gadget id="calculator">50 / 5</gadget>
<output>10</output>
<gadget id="calculator">60 - 10</gadget>
<output>50</output>
<result>E</result> | E | 50 | Mother,her daughter and her grand child weighs 110 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter? | {
"A": "46",
"B": "47",
"C": "48",
"D": "49",
"E": "50"
} | subtract(60, divide(subtract(110, 60), 5)) | subtract(n0,n1)|divide(#0,n3)|subtract(n1,#1)| | "mother + daughter + child = 110 kg daughter + child = 60 kg mother = 110 - 60 = 50 kg child = 1 / 5 th of mother = ( 1 / 5 ) * 50 = 10 kg so now daughter = 110 - ( mother + child ) = 110 - ( 50 + 10 ) = 50 kg answer : e" | general |
math_qa__yZzbcEqoPotitomE | When a student Joe, weighing 42 kg, joins a group of students whose average weight is 30 kg, the average weight goes up by 1 kg. Subsequently, if two students, excluding Joe, leave the group the average weight comes back to 30 kg. What is the difference between the average weight of the two students who left and the weight of Joe? Options:
A) 5.5 kg B) 6 kg C) 30 kg D) 36.5 kg E) 71 kg | <gadget id="calculator">30 + 1</gadget>
<output>31</output>
<gadget id="calculator">42 - 31</gadget>
<output>11</output>
<gadget id="calculator">30 * 11</gadget>
<output>330</output>
<gadget id="calculator">330 + 42</gadget>
<output>372</output>
<gadget id="calculator">11 - 1</gadget>
<output>10</output>
<gadget id="calculator">10 * 30</gadget>
<output>300</output>
<gadget id="calculator">372 - 300</gadget>
<output>72</output>
<gadget id="calculator">72 / 2</gadget>
<output>36</output>
<gadget id="calculator">42 - 36</gadget>
<output>6</output>
<result>B</result> | B | 6 | When a student Joe, weighing 42 kg, joins a group of students whose average weight is 30 kg, the average weight goes up by 1 kg. Subsequently, if two students, excluding Joe, leave the group the average weight comes back to 30 kg. What is the difference between the average weight of the two students who left and the weight of Joe? | {
"A": "5.5 kg",
"B": "6 kg",
"C": "30 kg",
"D": "36.5 kg",
"E": "71 kg"
} | subtract(42, divide(subtract(add(multiply(30, subtract(42, add(30, 1))), 42), multiply(subtract(subtract(42, add(30, 1)), const_1), 30)), const_2)) | add(n1,n2)|subtract(n0,#0)|multiply(n1,#1)|subtract(#1,const_1)|add(n0,#2)|multiply(n1,#3)|subtract(#4,#5)|divide(#6,const_2)|subtract(n0,#7) | after two persons leave the group the average remains the same . that means the weight of the two persons = 42 + 30 = 72 so , the average the two persons = 36 that gives the answer 42 - 36 = 6 answer b | general |
math_qa__F6bZ2jrcLPvrlRnW | the sum of two numbers is 44 . 5 times one number is equal to 6 times the other . the smaller of the two numbers is Choose the correct choice from the following answers
A) 10 B) 12 C) 16 D) 22 E) 20 | <gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">44 / 11</gadget>
<output>4</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<result>E</result> | E | 20 | the sum of two numbers is 44 . 5 times one number is equal to 6 times the other . the smaller of the two numbers is | {
"A": "10",
"B": "12",
"C": "16",
"D": "22",
"E": "20"
} | multiply(divide(44, add(5, 6)), 5) | add(n1,n2)|divide(n0,#0)|multiply(n1,#1) | sol . let the numbers be x and ( 44 - x ) . then , 5 x = 6 ( 44 - x ) ⇔ 11 x = 264 ⇔ x = 24 . so , the numbers are 24 and 20 . answer e | general |
math_qa__AmMrF4gtcy4Dzsgm | Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 4 minutes more to walk to work than to ride his bike to work, then x equals? Pick:
A) 4 B) 6 C) 10 D) 15 E) 20 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>B</result> | B | 6 | Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 4 minutes more to walk to work than to ride his bike to work, then x equals? | {
"A": "4",
"B": "6",
"C": "10",
"D": "15",
"E": "20"
} | divide(multiply(4, const_3), const_2) | multiply(n2,const_3)|divide(#0,const_2)| | "please follow posting guidelines , link is in my signatures . as for your question , x / 60 = blocks / time / block = block ^ 2 / time . this is not what you want . you are given x blocks and 60 seconds per block . thus you need to put it as 60 * x to give you units of seconds as you are equating this to 240 ( which is time in seconds . ) . thus the correct equation is : 60 * x - 20 * x = 240 - - - - > 40 x = 240 - - > x = 6 option b" | physics |
math_qa__zjZa95jfnYCkgvKx | A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 5 days. B can do the work alone in?
Options:
A) 19 B) 12 C) 11 D) 30 E) 114 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<result>D</result> | D | 30 | A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 5 days. B can do the work alone in? | {
"A": "19",
"B": "12",
"C": "11",
"D": "30",
"E": "114"
} | multiply(add(add(const_1, const_2), const_3), 5) | add(const_1,const_2)|add(#0,const_3)|multiply(n0,#1) | suppose a , b and c take x , x / 2 and x / 3 respectively to finish the work . then , ( 1 / x + 2 / x + 3 / x ) = 1 / 5 6 / x = 1 / 5 = > x = 30 so , b takes 15 hours to finish the work . answer : d | physics |
math_qa__0u8PFa4IyHJyVBUw | The mass of 1 cubic meter of a substance is 200 kg under certain conditions. What is the volume in cubic centimeters of 1 gram of this substance under these conditions? (1 kg =1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters) Choices.
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">200 * 1_000</gadget>
<output>200_000</output>
<gadget id="calculator">1_000_000 / 200_000</gadget>
<output>5</output>
<result>E</result> | E | 5 | The mass of 1 cubic meter of a substance is 200 kg under certain conditions. What is the volume in cubic centimeters of 1 gram of this substance under these conditions? (1 kg =1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters) | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(multiply(const_1000, const_1000), multiply(200, const_1000)) | multiply(const_1000,const_1000)|multiply(n1,const_1000)|divide(#0,#1) | 200 kg - 1 cubic meter ; 200,000 g - 1 cubic meter ; 200,000 g - 1 , 000,000 cubic centimeters ; 1 g - 1 , 000,000 / 200,000 = 10 / 2 = 5 cubic centimeters . answer : e . | geometry |
math_qa__OrPlCS71g08SYdw4 | A rectangular field is to be fenced on three sides leaving a side of 8 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?
Choose one:
A) 244 ft B) 88 ft C) 122 ft D) 178 ft E) 66 ft | <gadget id="calculator">680 / 8</gadget>
<output>85</output>
<gadget id="calculator">85 * 2</gadget>
<output>170</output>
<gadget id="calculator">170 + 8</gadget>
<output>178</output>
<result>D</result> | D | 178 | A rectangular field is to be fenced on three sides leaving a side of 8 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required? | {
"A": "244 ft",
"B": "88 ft",
"C": "122 ft",
"D": "178 ft",
"E": "66 ft"
} | add(multiply(divide(680, 8), const_2), 8) | divide(n1,n0)|multiply(#0,const_2)|add(n0,#1)| | "given that length and area , so we can find the breadth . length x breadth = area 8 x breadth = 680 breadth = 85 feet area to be fenced = 2 b + l = 2 ( 85 ) + 8 = 178 feet answer : d ) 178 ft" | geometry |
math_qa__FVOqjoC7o7QXv68e | Ravi can do a piece of work in 50 days while Prakash can do it in 75 days. In how many days will they finish it together?
Choose the correct choice from the following options.
A) 30 days B) 35 days C) 25 days D) 27 days E) 29 days | <gadget id="calculator">1 / 50</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">1 / 75</gadget>
<output>1/75 = around 0.013333</output>
<gadget id="calculator">(1/50) + (1/75)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / (1/30)</gadget>
<output>30</output>
<result>A</result> | A | 30 | Ravi can do a piece of work in 50 days while Prakash can do it in 75 days. In how many days will they finish it together? | {
"A": "30 days",
"B": "35 days",
"C": "25 days",
"D": "27 days",
"E": "29 days"
} | divide(const_1, add(inverse(50), inverse(75))) | inverse(n0)|inverse(n1)|add(#0,#1)|divide(const_1,#2) | 1 / 50 + 1 / 75 = 5 / 150 30 / 1 = 30 days answer : a | physics |
math_qa__IZRRRih8cXnFqkcD | The marks obtained by Polly and Sandy are in the ratio 3:5 and those obtained by Sandy and Willy are in the ratio of 5:2. The marks obtained by Polly and Willy are in the ratio of...? Select the correct option.
A) 2 : 1 B) 3 : 2 C) 4 : 3 D) 5 : 4 E) 6 : 5 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">15 / 10</gadget>
<output>3/2 = around 1.5</output>
<result>B</result> | B | 1.5 | The marks obtained by Polly and Sandy are in the ratio 3:5 and those obtained by Sandy and Willy are in the ratio of 5:2. The marks obtained by Polly and Willy are in the ratio of...? | {
"A": "2 : 1",
"B": "3 : 2",
"C": "4 : 3",
"D": "5 : 4",
"E": "6 : 5"
} | divide(multiply(3, 5), multiply(5, 2)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "polly : sandy = 3 : 5 sandy : willy = 5 : 2 polly : sandy : willy = 3 : 5 : 2 polly : willy = 3 : 2 the answer is b ." | other |
math_qa__gjdZ0KHZKIwzCBXw | add 10% of 30 and 15% of 50.
Choose the correct choice from the following choices
A) 9.5 B) 10.5 C) 11.5 D) 12 E) 15 | <gadget id="calculator">10 * 30</gadget>
<output>300</output>
<gadget id="calculator">300 / 100</gadget>
<output>3</output>
<gadget id="calculator">15 * 50</gadget>
<output>750</output>
<gadget id="calculator">750 / 100</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">3 + (15/2)</gadget>
<output>21/2 = around 10.5</output>
<result>B</result> | B | 10.5 | add 10% of 30 and 15% of 50. | {
"A": "9.5",
"B": "10.5",
"C": "11.5",
"D": "12",
"E": "15"
} | add(divide(multiply(10, 30), const_100), divide(multiply(15, 50), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)| | "10 % of 30 + 15 % of 50 30 * 10 / 100 + 50 * 15 / 100 3 + 7.5 = 10.5 answer b" | gain |
math_qa__iR1TjKjIuqsVae92 | Smita Was Making A Cube With Dimensions 5*5*5 Using 1*1*1 Cubes. What Is The Number Of Cubes Needed To Make A Hollow Cube Looking Of The Same Shape? Answers:
A) 98
B) 104
C) 100
D) 61
E) 51 | <gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">125 - 27</gadget>
<output>98</output>
<result>A</result> | A | 98 | Smita Was Making A Cube With Dimensions 5*5*5 Using 1*1*1 Cubes. What Is The Number Of Cubes Needed To Make A Hollow Cube Looking Of The Same Shape? | {
"A": "98",
"B": "104",
"C": "100",
"D": "61",
"E": "51"
} | subtract(volume_cube(5), volume_cube(const_3)) | volume_cube(n0)|volume_cube(const_3)|subtract(#0,#1) | cube use to make perfect 5 * 5 * 5 = 125 no need of cube to make hollow = ( 5 - 2 ) * ( 5 - 2 ) * ( 5 - 2 ) = 27 so total cube need to make hollow cube is = 125 - 27 = 98 answer : a | geometry |
math_qa__Ei4zzGlIUTPrxJqD | The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 40, what is the possible maximum range of the temperatures? Choose the correct choice from the following
A) 20 B) 25 C) 40 D) 50 E) 75 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">50 * 5</gadget>
<output>250</output>
<gadget id="calculator">40 * 4</gadget>
<output>160</output>
<gadget id="calculator">250 - 160</gadget>
<output>90</output>
<gadget id="calculator">90 - 40</gadget>
<output>50</output>
<result>D</result> | D | 50 | The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 40, what is the possible maximum range of the temperatures? | {
"A": "20",
"B": "25",
"C": "40",
"D": "50",
"E": "75"
} | subtract(subtract(multiply(50, add(const_2, const_3)), multiply(40, const_4)), 40) | add(const_2,const_3)|multiply(n1,const_4)|multiply(n0,#0)|subtract(#2,#1)|subtract(#3,n1)| | "there are 5 days so the sum of temperature can be 50 * 5 = 250 lowest is 40 . to find the maximum range we can say the temperature was the lowest for 4 of the 5 days so 4 * 40 = 160 . on the fifth day it is 250 - 160 = 90 range is therefore 90 - 40 = 50 answer d" | general |
math_qa__No74gJVHckYTTKZM | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 36, what is the total amount? Select the correct option: A) 166 B) 140 C) 178 D) 177 E) 169 | <gadget id="calculator">100 / 45</gadget>
<output>20/9 = around 2.222222</output>
<gadget id="calculator">(20/9) * 36</gadget>
<output>80</output>
<gadget id="calculator">30 / 45</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 36</gadget>
<output>24</output>
<gadget id="calculator">80 + 24</gadget>
<output>104</output>
<gadget id="calculator">104 + 36</gadget>
<output>140</output>
<result>B</result> | B | 140 | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 36, what is the total amount? | {
"A": "166",
"B": "140",
"C": "178",
"D": "177",
"E": "169"
} | add(add(multiply(divide(const_100, 45), 36), multiply(divide(30, 45), 36)), 36) | divide(const_100,n0)|divide(n1,n0)|multiply(n2,#0)|multiply(n2,#1)|add(#2,#3)|add(n2,#4)| | "x : y : z = 100 : 45 : 30 20 : 9 : 6 9 - - - 36 35 - - - ? = > 140 answer : b" | general |
math_qa__ZlV8jLuJ9iYgA2aX | A retailer sold 2 houses at each $10000. On 1st house he got 30% profit and on 2nd house he loss 10% then find his net profit or loss? Choose the most appropriate option
A) 15 %
B) 17 %
C) 21 %
D) 19 %
E) 25 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 2</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) - (1/10)</gadget>
<output>17/10 = around 1.7</output>
<gadget id="calculator">(17/10) * 10</gadget>
<output>17</output>
<result>B</result> | B | 17 | A retailer sold 2 houses at each $10000. On 1st house he got 30% profit and on 2nd house he loss 10% then find his net profit or loss? | {
"A": "15 %",
"B": "17 %",
"C": "21 %",
"D": "19 %",
"E": "25 %"
} | multiply(subtract(multiply(subtract(const_1, divide(10, const_100)), const_2), divide(10, const_100)), 10) | divide(n5,const_100)|subtract(const_1,#0)|multiply(#1,const_2)|subtract(#2,#0)|multiply(n5,#3) | a = 30 % b = - 10 % profit % = 30 - 10 + ( - 300 / 100 ) = 17 % answer is b | gain |
math_qa__0rw2WrIzIZdiiGfy | today joelle opened an interest - bearing savings account and deposited $ 6000 . if the annual interest rate is 5 percent compounded interest , and she neither deposits nor withdraws money for exactly 2 years , how much money will she have in the account ? Choices:
A) $ 6715 B) $ 5615 C) $ 6415 D) $ 6615 E) $ 6315 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">6_000 * (441/400)</gadget>
<output>6_615</output>
<result>D</result> | D | 6,615 | today joelle opened an interest - bearing savings account and deposited $ 6000 . if the annual interest rate is 5 percent compounded interest , and she neither deposits nor withdraws money for exactly 2 years , how much money will she have in the account ? | {
"A": "$ 6715",
"B": "$ 5615",
"C": "$ 6415",
"D": "$ 6615",
"E": "$ 6315"
} | multiply(6000, power(add(const_1, divide(5, const_100)), const_2)) | divide(n1,const_100)|add(#0,const_1)|power(#1,const_2)|multiply(n0,#2) | interest for 1 st year = 6000 * 5 / 100 = 300 interest for 2 nd year = 6300 * 5 / 100 = 315 total = 6000 + 300 + 315 = 6615 answer : d | gain |
math_qa__6HNu2PTzGoGtzxa2 | A boat can travel with a speed of 24 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 196 km downstream Choose the correct answer
A) 3 hours B) 4 hours C) 5 hours D) 6 hours E) 7 hours | <gadget id="calculator">24 + 4</gadget>
<output>28</output>
<gadget id="calculator">196 / 28</gadget>
<output>7</output>
<result>E</result> | E | 7 | A boat can travel with a speed of 24 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 196 km downstream | {
"A": "3 hours",
"B": "4 hours",
"C": "5 hours",
"D": "6 hours",
"E": "7 hours"
} | divide(196, add(24, 4)) | add(n0,n1)|divide(n2,#0)| | "explanation : speed of the boat in still water = 24 km / hr speed of the stream = 4 km / hr speed downstream = ( 22 + 5 ) = 28 km / hr distance travelled downstream = 196 km time taken = distance / speed = 196 / 28 = 7 hours answer : option e" | physics |
math_qa__WxRek0Ka2aXm395n | 600 men have provisions for 20 days. If 200 more men join them, for how many days will the provisions last now? Choose the most appropriate option:
A) 15 B) 11 C) 10 D) 8 E) 7 | <gadget id="calculator">20 * 600</gadget>
<output>12_000</output>
<gadget id="calculator">600 + 200</gadget>
<output>800</output>
<gadget id="calculator">12_000 / 800</gadget>
<output>15</output>
<result>A</result> | A | 15 | 600 men have provisions for 20 days. If 200 more men join them, for how many days will the provisions last now? | {
"A": "15",
"B": "11",
"C": "10",
"D": "8",
"E": "7"
} | divide(multiply(20, 600), add(600, 200)) | add(n0,n2)|multiply(n0,n1)|divide(#1,#0)| | "600 * 20 = 800 * x x = 15 . answer : a" | physics |
math_qa__DkvJ9p2YQ6mtMbDn | The HCF of two numbers is 52 and the other two factors of their LCM are 11 and 12. What is the largest number.
Choose the correct choice.
A) 624 B) 450 C) 480 D) 504 E) 555 | <gadget id="calculator">52 * 12</gadget>
<output>624</output>
<result>A</result> | A | 624 | The HCF of two numbers is 52 and the other two factors of their LCM are 11 and 12. What is the largest number. | {
"A": "624",
"B": "450",
"C": "480",
"D": "504",
"E": "555"
} | multiply(52, 12) | multiply(n0,n2)| | "explanation : hcf of the two numbers = 52 hcf will be always a factor of lcm 52 is factor of lcm other two factors are 11 & 12 then the numbers are ( 52 * 11 ) and ( 52 x 12 ) = 572 and 624 answer : option a" | other |
math_qa__fEtL0inEesMbn1Jv | A whale goes on a feeding frenzy that lasts for 9 hours. For the first hour he catches and eats x kilos of plankton. In every hour after the first, it consumes 3 kilos of plankton more than it consumed in the previous hour. If by the end of the frenzy the whale will have consumed a whopping accumulated total 270 kilos of plankton, how many kilos did he consume on the sixth hour? Choices:
A) 33 B) 47 C) 50 D) 53 E) 62 | <gadget id="calculator">270 / 9</gadget>
<output>30</output>
<gadget id="calculator">30 + 3</gadget>
<output>33</output>
<result>A</result> | A | 33 | A whale goes on a feeding frenzy that lasts for 9 hours. For the first hour he catches and eats x kilos of plankton. In every hour after the first, it consumes 3 kilos of plankton more than it consumed in the previous hour. If by the end of the frenzy the whale will have consumed a whopping accumulated total 270 kilos of plankton, how many kilos did he consume on the sixth hour? | {
"A": "33",
"B": "47",
"C": "50",
"D": "53",
"E": "62"
} | add(divide(270, 9), 3) | divide(n2,n0)|add(n1,#0)| | "if you list the amount eaten each hour , you ' ll get an equally spaced list , increasing by 3 each hour . in any equally spaced list , the median equals the mean . here , the mean is 270 / 9 = 30 , so the median is also 30 , and that is the amount eaten in the 5 th hour . we need to add 3 to find the total eaten in the next hour , so the answer is 33 . option a" | general |
math_qa__0aEcNtsHWF7CROoa | In a garment industry, 12 men working 8 hours per day complete a piece of work in 10 days. To complete the same work in 8 days, working 5 hours a day, the number of men required is:
Choose the correct option.
A) 24 B) 5 C) 6 D) 8 E) 9 | <gadget id="calculator">12 * 8</gadget>
<output>96</output>
<gadget id="calculator">96 * 10</gadget>
<output>960</output>
<gadget id="calculator">960 / 5</gadget>
<output>192</output>
<gadget id="calculator">192 / 8</gadget>
<output>24</output>
<result>A</result> | A | 24 | In a garment industry, 12 men working 8 hours per day complete a piece of work in 10 days. To complete the same work in 8 days, working 5 hours a day, the number of men required is: | {
"A": "24",
"B": "5",
"C": "6",
"D": "8",
"E": "9"
} | divide(divide(multiply(multiply(12, 8), 10), 5), 8) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n4)|divide(#2,n1)| | "explanation : let the required number of men be x . less days , more men ( indirect proportion ) more working hrs per day , less men ( indirect proportion ) days 8 : 10 working hrs 5 : 8 : : 12 : x = > 8 x 5 x x = 10 x 8 x 12 = > x = 10 x 8 x 12 / ( 8 x 5 ) = > x = 24 answer : a" | physics |
math_qa__Muy2E62j60jNIib8 | If the radii of umbra and penumbra cast by an object on a wall are of the ratio 2:6, what is the area of the penumbra ring around the umbra of the latter’s radius is 40 cms? Choose the correct choice from the following answers.
A) 40288.57 cm ^ 2 B) 40388.57 cm ^ 2 C) 40488.57 cm ^ 2 D) 40588.57 cm ^ 2 E) 40688.57 cm ^ 2 | <gadget id="calculator">6 * 40</gadget>
<output>240</output>
<gadget id="calculator">240 * 240</gadget>
<output>57_600</output>
<gadget id="calculator">pi * 57_600</gadget>
<output>57600*pi = around 180_955.736847</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">80 * 80</gadget>
<output>6_400</output>
<gadget id="calculator">pi * 6_400</gadget>
<output>6400*pi = around 20_106.192983</output>
<gadget id="calculator">(57600*pi) - (6400*pi)</gadget>
<output>51200*pi = around 160_849.543864</output>
<gadget id="calculator">(51200*pi) / 2</gadget>
<output>25600*pi = around 80_424.771932</output>
<gadget id="calculator">(25600*pi) / 2</gadget>
<output>12800*pi = around 40_212.385966</output>
<result>A</result> | A | 40,288.57 | If the radii of umbra and penumbra cast by an object on a wall are of the ratio 2:6, what is the area of the penumbra ring around the umbra of the latter’s radius is 40 cms? | {
"A": "40288.57 cm ^ 2",
"B": "40388.57 cm ^ 2",
"C": "40488.57 cm ^ 2",
"D": "40588.57 cm ^ 2",
"E": "40688.57 cm ^ 2"
} | divide(divide(subtract(multiply(const_pi, multiply(multiply(6, 40), multiply(6, 40))), multiply(const_pi, multiply(multiply(40, const_2), multiply(40, const_2)))), 2), 2) | multiply(n1,n2)|multiply(n2,const_2)|multiply(#0,#0)|multiply(#1,#1)|multiply(#2,const_pi)|multiply(#3,const_pi)|subtract(#4,#5)|divide(#6,n0)|divide(#7,n0) | et the radius of umbra and penumbra are 2 k and 6 k . then as given radius of umbra = 40 cm so 2 k = 40 k = 20 radius of penumbra = 20 * 6 = 120 area of penumbra ring around the umbra = area of penumbra - area of umbra 22 / 7 * [ ( 120 ) ^ 2 - ( 40 ) ^ 2 ] = 40288.57 cm ^ 2 answer : a | other |
math_qa__r7sDuiAzuzJ4gG35 | If in a box of dimensions 6 m * 5 m * 4 m smaller boxes of dimensions 60 cm * 50 cm * 40 cm are kept in it, then what will be the maximum number of the small boxes that can be kept in it?
Choose the most appropriate option.
A) 1098 B) 1000 C) 1628 D) 1098 E) 1094 | <gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 4</gadget>
<output>120</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/5) * (1/2)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/10) * (2/5)</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">120 / (3/25)</gadget>
<output>1_000</output>
<result>B</result> | B | 1,000 | If in a box of dimensions 6 m * 5 m * 4 m smaller boxes of dimensions 60 cm * 50 cm * 40 cm are kept in it, then what will be the maximum number of the small boxes that can be kept in it? | {
"A": "1098",
"B": "1000",
"C": "1628",
"D": "1098",
"E": "1094"
} | divide(multiply(multiply(6, 5), 4), multiply(multiply(divide(60, const_100), divide(50, const_100)), divide(40, const_100))) | divide(n5,const_100)|divide(n3,const_100)|divide(n4,const_100)|multiply(n0,n1)|multiply(n2,#3)|multiply(#1,#2)|multiply(#0,#5)|divide(#4,#6) | 6 * 5 * 4 = 60 / 100 * 50 / 100 * 40 / 100 * x 1 = 1 / 10 * 1 / 10 * 1 / 10 * x = > x = 1000 answer : b | physics |
math_qa__j69jI5c0On4A2xtK | The ratio 15:25 expressed as percent equals to Choose the correct option: A) 70 % B) 60 % C) 30 % D) 75 % E) none of above | <gadget id="calculator">15 / 25</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>B</result> | B | 60 | The ratio 15:25 expressed as percent equals to | {
"A": "70 %",
"B": "60 %",
"C": "30 %",
"D": "75 %",
"E": "none of above"
} | multiply(divide(15, 25), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "explanation : actually it means 15 is what percent of 25 , which can be calculated as , ( 15 / 25 ) * 100 = 15 * 4 = 60 answer : option b" | general |
math_qa__p1UWRvAsiT7WId2K | The ratio between the number of sheep and the number of horses at the Stewar farm is 2 to 7. If each of horse is fed 230 ounces of horse food per day and the farm needs a total 12880 ounces of horse food per day. what is number sheep in the form?? Choose the correct answer.
A) 18
B) 16
C) 32
D) 56
E) 58 | <gadget id="calculator">12_880 / 230</gadget>
<output>56</output>
<gadget id="calculator">56 / 7</gadget>
<output>8</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<result>B</result> | B | 16 | The ratio between the number of sheep and the number of horses at the Stewar farm is 2 to 7. If each of horse is fed 230 ounces of horse food per day and the farm needs a total 12880 ounces of horse food per day. what is number sheep in the form?? | {
"A": "18",
"B": "16",
"C": "32",
"D": "56",
"E": "58"
} | multiply(divide(divide(12880, 230), 7), 2) | divide(n3,n2)|divide(#0,n1)|multiply(n0,#1)| | "et no of sheep and horses are 2 k and 7 k no of horses = 12880 / 230 = 56 now 7 k = 56 and k = 8 no of sheep = ( 2 * 8 ) = 16 answer : b" | other |
math_qa__as2JPUPDGBTtHqYf | The ratio of the arithmetic mean of two numbers to one of the numbers is 4:6. What is the ratio of the smaller number to the larger number? Choose one
A) 1 : 5 B) 1 : 4 C) 1 : 3 D) 1 : 2 E) 2 : 3 | <gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(2/3) - (1/2)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 2</gadget>
<output>1/3 = around 0.333333</output>
<result>C</result> | C | 0.333333 | The ratio of the arithmetic mean of two numbers to one of the numbers is 4:6. What is the ratio of the smaller number to the larger number? | {
"A": "1 : 5",
"B": "1 : 4",
"C": "1 : 3",
"D": "1 : 2",
"E": "2 : 3"
} | multiply(subtract(divide(4, 6), divide(const_1, const_2)), const_2) | divide(n0,n1)|divide(const_1,const_2)|subtract(#0,#1)|multiply(#2,const_2) | for two numbers , the arithmetic mean is the middle of the two numbers . the ratio of the mean to the larger number is 4 : 6 , thus the smaller number must have a ratio of 2 . the ratio of the smaller number to the larger number is 2 : 6 = 1 : 3 . the answer is c . | other |
math_qa__wceiZ6QvPeKuTrsx | The speed of a boat in still water in 22 km/hr and the rate of current is 4 km/hr. The distance travelled downstream in 24 minutes is: Choose the correct answer.
A) 10.6 B) 10.2 C) 10.8 D) 10.4 E) 10.0 | <gadget id="calculator">22 + 4</gadget>
<output>26</output>
<gadget id="calculator">24 / 60</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">26 * (2/5)</gadget>
<output>52/5 = around 10.4</output>
<result>D</result> | D | 10.4 | The speed of a boat in still water in 22 km/hr and the rate of current is 4 km/hr. The distance travelled downstream in 24 minutes is: | {
"A": "10.6",
"B": "10.2",
"C": "10.8",
"D": "10.4",
"E": "10.0"
} | multiply(add(22, 4), divide(24, const_60)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "speed downstream = ( 22 + 4 ) = 26 kmph time = 24 minutes = 24 / 60 hour = 2 / 5 hour distance travelled = time × speed = 2 / 5 × 26 = 10.4 km answer is d ." | physics |
math_qa__nzRxLpclu154Sied | A certain bacteria colony doubles in size every day for 16 days, at which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit? Choose the most appropriate option:
A) 6.33 B) 7.5 C) 10 D) 15 E) 19 | <gadget id="calculator">16 / 16</gadget>
<output>1</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<result>D</result> | D | 15 | A certain bacteria colony doubles in size every day for 16 days, at which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit? | {
"A": "6.33",
"B": "7.5",
"C": "10",
"D": "15",
"E": "19"
} | subtract(16, divide(16, 16)) | divide(n0,n0)|subtract(n0,#0) | if there is one bacteria colony , then it will reach the limit of its habitat in 16 days . if there are two bacteria colonies , then in order to reach the limit of habitat they would need to double one time less than in case with one colony . thus colonies need to double 15 times . answer : d . similar questions to practice : hope it helps . | physics |
math_qa__28Bneb2Td7etsSC6 | Find the area of the quadrilateral of one of its diagonals is 15 cm and its off sets 6 cm and 4 cm? Choose the correct answer.
A) 50 cm 2 B) 60 cm 2 C) 75 cm 2 D) 90 cm 2 E) 150 cm 2 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">(1/2) * 10</gadget>
<output>5</output>
<gadget id="calculator">5 * 15</gadget>
<output>75</output>
<result>C</result> | C | 75 | Find the area of the quadrilateral of one of its diagonals is 15 cm and its off sets 6 cm and 4 cm? | {
"A": "50 cm 2",
"B": "60 cm 2",
"C": "75 cm 2",
"D": "90 cm 2",
"E": "150 cm 2"
} | multiply(multiply(divide(const_1, const_2), add(4, 6)), 15) | add(n1,n2)|divide(const_1,const_2)|multiply(#0,#1)|multiply(n0,#2)| | "1 / 2 * 15 ( 6 + 4 ) = 75 cm 2 answer : c" | geometry |
math_qa__zSEFYUqaUAVJJ04z | The average of 10 numbers is 23. If each number is increased by 1, what will the new average be? Select: A) 36 B) 24 C) 72 D) 29 E) 22 | <gadget id="calculator">23 * 1</gadget>
<output>23</output>
<result>B</result> | B | 24 | The average of 10 numbers is 23. If each number is increased by 1, what will the new average be? | {
"A": "36",
"B": "24",
"C": "72",
"D": "29",
"E": "22"
} | multiply(23, 1) | multiply(n1,n2)| | "sum of the 10 numbers = 230 if each number is increased by 1 , the total increase = 1 * 10 = 10 the new sum = 230 + 10 = 240 the new average = 240 / 10 = 24 . answer : b" | general |
math_qa__EAxbwY3smUxhSLKc | Sakshi can do a piece of work in 15 days.Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work : Choose the correct choice from the following:
A) 15
B) 16
C) 18
D) 12
E) 10 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">15 / (5/4)</gadget>
<output>12</output>
<result>D</result> | D | 12 | Sakshi can do a piece of work in 15 days.Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work : | {
"A": "15",
"B": "16",
"C": "18",
"D": "12",
"E": "10"
} | divide(15, add(const_1, divide(25, const_100))) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)| | "solution ratio of times taken by sakshi and tanya = 125 : 100 = 5 : 4 . suppose tanya taken x days to do the work . 5 : 4 : : 15 : x ⇒ x = ( 15 x 4 / 5 ) ⇒ x = 12 days . hence , tanya takes 16 days is complete the work . answer d" | physics |
math_qa__sbHaTkJUBS6nJOFl | An electric pump can fill a tank in 5 hours. Because of a leak in the tank, it took 10hours to fill the tank. If the tank is full, how much time will the leak take to empty it? Choose one: A) 10 hours B) 12 hours C) 8 hours D) 5 hours E) 15 hours | <gadget id="calculator">10 / 1</gadget>
<output>10</output>
<result>A</result> | A | 10 | An electric pump can fill a tank in 5 hours. Because of a leak in the tank, it took 10hours to fill the tank. If the tank is full, how much time will the leak take to empty it? | {
"A": "10 hours",
"B": "12 hours",
"C": "8 hours",
"D": "5 hours",
"E": "15 hours"
} | divide(10, const_1) | divide(n1,const_1)| | "work done by the leak in 1 hour = 1 / 5 - 1 / 10 = 1 / 10 the leak will empty the tank in 10 hours answer is a" | physics |
math_qa__B6oq1vJ7czHquzpy | A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long? Choose the correct choice from the following choices
A) 48
B) 99
C) 266
D) 28
E) 17 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<result>A</result> | A | 48 | A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long? | {
"A": "48",
"B": "99",
"C": "266",
"D": "28",
"E": "17"
} | multiply(6, multiply(const_2, const_4)) | multiply(const_2,const_4)|multiply(n0,#0)| | "explanation : if you double the sides of a cube , the ratio of the surface areas of the old and new cubes will be 1 : 4 . the ratio of the volumes of the old and new cubes will be 1 : 8 . weight is proportional to volume . so , if the first weighs 6 pounds , the second weighs 6 x 8 pounds = 48 . answer : a ) 48" | geometry |
math_qa__ojyk94K3d4MiNs1F | Working together at their respective constant rates, Machine A and Machine B can produce 1,600 units in 8 hours. Working alone, Machine B would complete that same output in 50% more time. If Machine A were to work on its own for an 8-hour shift, what percent of the 1,600 unit total would it produce? Choose the correct choice from the following answers:
A) 25
B) 33
C) 50
D) 67
E) 75 | <gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 / 8</gadget>
<output>200</output>
<gadget id="calculator">8 * 50</gadget>
<output>400</output>
<gadget id="calculator">400 / 100</gadget>
<output>4</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">1_600 / 12</gadget>
<output>400/3 = around 133.333333</output>
<gadget id="calculator">200 - (400/3)</gadget>
<output>200/3 = around 66.666667</output>
<gadget id="calculator">(200/3) * 8</gadget>
<output>1_600/3 = around 533.333333</output>
<gadget id="calculator">(1_600/3) / 1_600</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>B</result> | B | 33 | Working together at their respective constant rates, Machine A and Machine B can produce 1,600 units in 8 hours. Working alone, Machine B would complete that same output in 50% more time. If Machine A were to work on its own for an 8-hour shift, what percent of the 1,600 unit total would it produce? | {
"A": "25",
"B": "33",
"C": "50",
"D": "67",
"E": "75"
} | multiply(divide(multiply(subtract(divide(multiply(multiply(const_4, const_4), const_100), 8), divide(multiply(multiply(const_4, const_4), const_100), add(8, divide(multiply(8, 50), const_100)))), 8), multiply(multiply(const_4, const_4), const_100)), const_100) | multiply(const_4,const_4)|multiply(n1,n2)|divide(#1,const_100)|multiply(#0,const_100)|add(n1,#2)|divide(#3,n1)|divide(#3,#4)|subtract(#5,#6)|multiply(n1,#7)|divide(#8,#3)|multiply(#9,const_100) | 1 / a + 1 / b = 1 / t 1 / a + 1 / 12 = 1 / 8 ( 50 % more of 8 is 12 ) 1 / a = 1 / 24 machine a can produce 1600 units in 24 hrs , so it can produce 1600 * 8 / 24 = 533.33 units is 8 hrs . 533.33 is 33.33 % of 1600 . b is the answer | gain |
math_qa__CFOXxLsOT7VhlYND | A sum of money is sufficient to pay X's wages for 36 days and Y's wages for 45 days. The same money is sufficient to pay the wages of both for?
Select:
A) 16 B) 17 C) 18 D) 19 E) 20 | <gadget id="calculator">1 / 36</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">(1/36) + (1/45)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / (1/20)</gadget>
<output>20</output>
<result>E</result> | E | 20 | A sum of money is sufficient to pay X's wages for 36 days and Y's wages for 45 days. The same money is sufficient to pay the wages of both for? | {
"A": "16",
"B": "17",
"C": "18",
"D": "19",
"E": "20"
} | inverse(add(divide(const_1, 36), divide(const_1, 45))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2) | let the total money be $ x x ' s 1 day work = $ x / 36 y ' s 1 day work = $ x / 45 x + y 1 day work = $ x / 20 money is sufficient to pay the wages of both for 20 days answer is e | general |
math_qa__sLmkEiJWk0q9CfAz | Length of a rectangular plot is 16 mtr more than its breadth. If the cost of fencing the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr? Choose one:
A) 58 m B) 60 m C) 80 m D) 82 m E) 84 m | <gadget id="calculator">5_300 / 26.5</gadget>
<output>200</output>
<gadget id="calculator">2 * 16</gadget>
<output>32</output>
<gadget id="calculator">200 + 32</gadget>
<output>232</output>
<gadget id="calculator">232 / 4</gadget>
<output>58</output>
<result>A</result> | A | 58 | Length of a rectangular plot is 16 mtr more than its breadth. If the cost of fencing the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr? | {
"A": "58 m",
"B": "60 m",
"C": "80 m",
"D": "82 m",
"E": "84 m"
} | divide(add(divide(5300, 26.50), multiply(const_2, 16)), const_4) | divide(n2,n1)|multiply(n0,const_2)|add(#0,#1)|divide(#2,const_4)| | "let breadth = x metres . then , length = ( x + 16 ) metres . perimeter = 5300 m = 200 m . 26.50 2 [ ( x + 16 ) + x ] = 200 2 x + 16 = 100 2 x = 84 x = 42 . hence , length = x + 16 = 58 m a" | physics |
math_qa__CiHWPr5UQiRXJznk | At what price must an article costing Rs.75 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price? Choose the correct choice from the following: A) 62.5 B) 62.0 C) 62.6 D) 62.1 E) 98.68 | <gadget id="calculator">75 * 25</gadget>
<output>1_875</output>
<gadget id="calculator">1_875 / 100</gadget>
<output>75/4 = around 18.75</output>
<gadget id="calculator">75 + (75/4)</gadget>
<output>375/4 = around 93.75</output>
<gadget id="calculator">(375/4) * 100</gadget>
<output>9_375</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">9_375 / 95</gadget>
<output>1_875/19 = around 98.684211</output>
<result>E</result> | E | 98.68 | At what price must an article costing Rs.75 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price? | {
"A": "62.5",
"B": "62.0",
"C": "62.6",
"D": "62.1",
"E": "98.68"
} | divide(multiply(add(75, divide(multiply(75, 25), const_100)), const_100), subtract(const_100, 5)) | multiply(n0,n2)|subtract(const_100,n1)|divide(#0,const_100)|add(n0,#2)|multiply(#3,const_100)|divide(#4,#1)| | "cp = 75 sp = 75 * ( 125 / 100 ) = 93.75 mp * ( 95 / 100 ) = 93.75 mp = 98.68 answer : e" | gain |
math_qa__bmA7nkhqR4LAMGW7 | Two stations A and B are 155 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? Options.
A) 9 B) 10 C) 11 D) 12 E) 8 | <gadget id="calculator">155 - 20</gadget>
<output>135</output>
<gadget id="calculator">25 + 20</gadget>
<output>45</output>
<gadget id="calculator">135 / 45</gadget>
<output>3</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<result>C</result> | C | 11 | Two stations A and B are 155 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "8"
} | add(8, divide(subtract(155, 20), add(25, 20))) | add(n2,n4)|subtract(n0,n2)|divide(#1,#0)|add(n3,#2)| | "suppose they meet x hours after 7 a . m . distance covered by a in x hours = 20 x km . distance covered by b in ( x - 1 ) hours = 25 ( x - 1 ) km . therefore 20 x + 25 ( x - 1 ) = 155 45 x = 180 x = 4 . so , they meet at 11 a . m . answer : option c" | physics |
math_qa__0aYeXfs5S7zoebnH | Each week, Harry is paid x dollars per hour for the first 12 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ?
Pick: A) 32 B) 36 C) 37 D) 38 E) 39 | <gadget id="calculator">40 + 2</gadget>
<output>42</output>
<gadget id="calculator">42 - 12</gadget>
<output>30</output>
<gadget id="calculator">30 / 1.5</gadget>
<output>20</output>
<gadget id="calculator">20 + 12</gadget>
<output>32</output>
<result>A</result> | A | 32 | Each week, Harry is paid x dollars per hour for the first 12 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ? | {
"A": "32",
"B": "36",
"C": "37",
"D": "38",
"E": "39"
} | add(divide(subtract(add(40, 2), 12), 1.5), 12) | add(n2,n3)|subtract(#0,n0)|divide(#1,n1)|add(n0,#2)| | "42 x = 12 x + 1.5 x ( h - 12 ) = = > 42 = 12 + 1.5 ( h - 12 ) = = > h - 12 = 30 / 1.5 = 20 = = > h = 32 answer is a" | general |
math_qa__0hpTKDSVsOZ3bYCB | If the volume of two cubes are in the ratio 64:1, the ratio of their edges is: Choose the correct choice from the following:
A) 3 : 1 B) 3 : 2 C) 3 : 5 D) 4 : 1 E) none of these | <gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>
<result>D</result> | D | 4 | If the volume of two cubes are in the ratio 64:1, the ratio of their edges is: | {
"A": "3 : 1",
"B": "3 : 2",
"C": "3 : 5",
"D": "4 : 1",
"E": "none of these"
} | cube_edge_by_volume(64) | cube_edge_by_volume(n0)| | "explanation : let the edges be a and b of two cubes , then a 3 / b 3 = 64 / 1 = > ( a / b ) 3 = ( 4 / 1 ) 3 a / b = 4 / 1 = > a : b = 4 : 1 option d" | geometry |
math_qa__UCDsKOz5qsPy4dqd | A van takes 6 hours to cover a distance of 180 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
Choose one: A) 50 kmph B) 60 kmph C) 70 kmph D) 80 kmph E) 20 kmph | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 6</gadget>
<output>9</output>
<gadget id="calculator">180 / 9</gadget>
<output>20</output>
<result>E</result> | E | 20 | A van takes 6 hours to cover a distance of 180 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "50 kmph",
"B": "60 kmph",
"C": "70 kmph",
"D": "80 kmph",
"E": "20 kmph"
} | divide(180, multiply(divide(3, 2), 6)) | divide(n2,n3)|multiply(n0,#0)|divide(n1,#1)| | "time = 6 distence = 180 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 180 / 9 = 20 kmph e" | physics |
math_qa__ineu5WjEq1qox2j7 | A can do a work in 40days, B in 60days. A alone start the work after 10days he left work. In how many days B can finish the work? Options
A) 20 days B) 15 days C) 30 days D) 45 days E) 50 days | <gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">10 * (1/40)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(3/4) / (1/60)</gadget>
<output>45</output>
<result>D</result> | D | 45 | A can do a work in 40days, B in 60days. A alone start the work after 10days he left work. In how many days B can finish the work? | {
"A": "20 days",
"B": "15 days",
"C": "30 days",
"D": "45 days",
"E": "50 days"
} | divide(subtract(const_1, multiply(10, divide(const_1, 40))), divide(const_1, 60)) | divide(const_1,n0)|divide(const_1,n1)|multiply(n2,#0)|subtract(const_1,#2)|divide(#3,#1) | 10 days work of a = 10 / 40 = 1 / 4 remaining work = 1 - 1 / 4 = 3 / 4 b can finish 3 / 4 work = 60 * 3 / 4 = 45 days answer is d | physics |
math_qa__tEhkZLo8G0hfuoyc | A certain university will select 1 of 4 candidates eligible to fill a position in the mathematics department and 2 of 7 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions? Pick one: A) 81 B) 82 C) 84 D) 86 E) 88 | <gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 * 4</gadget>
<output>84</output>
<result>C</result> | C | 84 | A certain university will select 1 of 4 candidates eligible to fill a position in the mathematics department and 2 of 7 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions? | {
"A": "81",
"B": "82",
"C": "84",
"D": "86",
"E": "88"
} | multiply(multiply(7, 3), 4) | multiply(n3,n5)|multiply(n1,#0) | 1 c 4 * 2 c 7 = 4 * 21 = 84 the answer is ( c ) | other |
math_qa__ewM1hEYSe3HDWTwQ | 12 men can complete a piece of work in 4 days, while 15 women can complete the same work in 4 days. 6 men start working on the job and after working for 2 days, all of them stopped working. How many women should be put on the job to complete the remaining work, if it is to be completed in 3 days.
Choose the most appropriate option
A) 15 B) 18 C) 22 D) 25 E) 26 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / 15</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">1 / (1/60)</gadget>
<output>60</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">(1/4) / 12</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">12 * (1/48)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">60 * (3/4)</gadget>
<output>45</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">45 * (1/3)</gadget>
<output>15</output>
<result>A</result> | A | 15 | 12 men can complete a piece of work in 4 days, while 15 women can complete the same work in 4 days. 6 men start working on the job and after working for 2 days, all of them stopped working. How many women should be put on the job to complete the remaining work, if it is to be completed in 3 days. | {
"A": "15",
"B": "18",
"C": "22",
"D": "25",
"E": "26"
} | multiply(multiply(divide(const_1, divide(divide(const_1, 4), 15)), subtract(const_1, multiply(multiply(6, 2), divide(divide(const_1, 4), 12)))), divide(const_1, 3)) | divide(const_1,n6)|divide(const_1,n1)|multiply(n4,n5)|divide(#1,n2)|divide(#1,n0)|divide(const_1,#3)|multiply(#4,#2)|subtract(const_1,#6)|multiply(#5,#7)|multiply(#0,#8) | one man ’ s one day ’ s work = 1 / 48 one woman ’ s one day ’ s work = 1 / 60 6 men ’ s 2 day ’ s work = ( ( 6 / 48 ) x 2 ) = 1 / 4 remaining work = 3 / 4 now , 1 / 60 work s done in 1 day by 1 woman . thus , 3 / 4 work will be done in 3 days by ( 60 x ( 3 / 4 ) x ( 1 / 3 ) ) = 15 women . answer : a | physics |
math_qa__8c4B5xaj9cDM4qSF | Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 20 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast? Select the correct option: A) 10 % B) 12 % C) 15 % D) 27 % E) 37 % | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/2) - (1/5)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(3/10) / (4/5)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(3/8) * 100</gadget>
<output>75/2 = around 37.5</output>
<result>E</result> | E | 37 | Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 20 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast? | {
"A": "10 %",
"B": "12 %",
"C": "15 %",
"D": "27 %",
"E": "37 %"
} | multiply(divide(subtract(divide(50, const_100), divide(20, const_100)), subtract(const_1, divide(20, const_100))), const_100) | divide(n2,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(const_1,#1)|divide(#2,#3)|multiply(#4,const_100)| | "lets assume that candidate got 20 % votes and total votes is 100 . candidate won = 20 remaining = 80 to get 50 % , candidate requires 30 votes from 100 which is 30 % and 30 votes from 80 . 30 / 80 = 37.5 % which is approx 37 % . hence the answer is e" | general |
math_qa__4kE5oBHaPS9OBIne | In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quanity of water to be further added is: Choose the correct option
A) 20 B) 30 C) 40 D) 50 E) 60 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<gadget id="calculator">60 - 20</gadget>
<output>40</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">80 - 20</gadget>
<output>60</output>
<result>E</result> | E | 60 | In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quanity of water to be further added is: | {
"A": "20",
"B": "30",
"C": "40",
"D": "50",
"E": "60"
} | subtract(multiply(subtract(60, divide(60, add(2, 1))), 2), divide(60, add(2, 1))) | add(n1,n2)|divide(n0,#0)|subtract(n0,#1)|multiply(n1,#2)|subtract(#3,#1) | quantity of milk = ( 60 x 2 / 3 ) litres = 40 litres . quantity of water in it = ( 60 - 40 ) litres = 20 litres . new ratio = 1 : 2 let quantity of water to be added further be x litres . then , milk : water = ( 40 / ( 20 + x ) ) now , ( 40 / ( 20 + x ) ) = 1 / 2 = 20 + x = 80 = x = 60 . therefore , quantity of water to be added = 60 litres . answer is e . | general |
math_qa__ltpTCFAD9POZOXQL | a tap can fill a tank in 16 hours . after half the tank is filled , 3 more similar taps are opened . what is the total time taken to fill the tank completely ? Choose the correct choice from the following options.
A) 2 hrs
B) 1 hrs
C) 10 hrs
D) 5 hrs
E) 4 hrs | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">16 - 6</gadget>
<output>10</output>
<result>C</result> | C | 10 | a tap can fill a tank in 16 hours . after half the tank is filled , 3 more similar taps are opened . what is the total time taken to fill the tank completely ? | {
"A": "2 hrs",
"B": "1 hrs",
"C": "10 hrs",
"D": "5 hrs",
"E": "4 hrs"
} | subtract(16, add(3, 3)) | add(n1,n1)|subtract(n0,#0) | explanation : a tap can fill a tank in 16 hours . therefore the tap can fill half the tank in 8 hours . one tap take time to fill half of the tank = 8 hrs 4 taps take time to fill half of the tank = 8 / 4 hrs = 2 hrs total time taken to fill the tank = 8 hr + 2 hr = 10 hrs answer : c | physics |
math_qa__7zh50lbm7Y9l1cJm | The sale price sarees listed for Rs.600 after successive discount is 20% and 5% is? Choose the most appropriate option
A) 227 B) 358 C) 456 D) 787 E) 191 | <gadget id="calculator">600 * 20</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 / 100</gadget>
<output>120</output>
<gadget id="calculator">600 - 120</gadget>
<output>480</output>
<gadget id="calculator">480 * 5</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 / 100</gadget>
<output>24</output>
<gadget id="calculator">480 - 24</gadget>
<output>456</output>
<result>C</result> | C | 456 | The sale price sarees listed for Rs.600 after successive discount is 20% and 5% is? | {
"A": "227",
"B": "358",
"C": "456",
"D": "787",
"E": "191"
} | subtract(subtract(600, divide(multiply(600, 20), const_100)), divide(multiply(subtract(600, divide(multiply(600, 20), const_100)), 5), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "600 * ( 80 / 100 ) * ( 95 / 100 ) = 456 answer : c" | gain |
math_qa__Vdk9Z9Dd0FoUtZn2 | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.700, what is the reduced price for kg? Choose the correct choice.
A) 35 B) 60 C) 70 D) 80 E) 20 | <gadget id="calculator">700 * 25</gadget>
<output>17_500</output>
<gadget id="calculator">17_500 / 100</gadget>
<output>175</output>
<gadget id="calculator">175 / 5</gadget>
<output>35</output>
<result>A</result> | A | 35 | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.700, what is the reduced price for kg? | {
"A": "35",
"B": "60",
"C": "70",
"D": "80",
"E": "20"
} | divide(divide(multiply(700, 25), const_100), 5) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "a 700 * ( 25 / 100 ) = 175 - - - - 5 ? - - - - 1 = > rs . 35" | gain |
math_qa__PPzyOVQzTukmkvBW | Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.? Choose the correct choice from the following answers:
A) 8 B) 12 C) 11 D) 16 E) 18 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) - (1/15)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">2 / (1/30)</gadget>
<output>60</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<result>B</result> | B | 12 | Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.? | {
"A": "8",
"B": "12",
"C": "11",
"D": "16",
"E": "18"
} | divide(divide(2, subtract(divide(1, 10), divide(1, 15))), add(const_4, 1)) | add(n4,const_4)|divide(n4,n1)|divide(n4,n3)|subtract(#1,#2)|divide(n0,#3)|divide(#4,#0)| | "explanation : let the distance travelled by x km . then , = > ( x / 10 ) - ( x / 15 ) = 2 = > 3 x - 2 x = 60 = > x = 60 = > time taken to travel 60 km at 10 km / hr = 60 / 10 = 6 hours . = > so , robert started 6 hours before 2 p . m . i . e . , at 8 a . m . therefore , speed required = ( 60 / 5 ) km / hr = 12 km / hr answer : b" | physics |
math_qa__TKUx6gT2uI0BysIp | The average of 10 consecutive integers is 16. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average? Pick
A) 10.5
B) 11
C) 11.5
D) 12
E) 12.5 | <gadget id="calculator">10 * 16</gadget>
<output>160</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 9</gadget>
<output>45</output>
<gadget id="calculator">160 - 45</gadget>
<output>115</output>
<gadget id="calculator">115 / 10</gadget>
<output>23/2 = around 11.5</output>
<result>C</result> | C | 11.5 | The average of 10 consecutive integers is 16. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average? | {
"A": "10.5",
"B": "11",
"C": "11.5",
"D": "12",
"E": "12.5"
} | divide(subtract(multiply(10, 16), multiply(add(const_4, const_1), 9)), 10) | add(const_1,const_4)|multiply(n0,n1)|multiply(n2,#0)|subtract(#1,#2)|divide(#3,n0) | the total subtracted is ( 9 + 8 + . . . + 1 ) = ( 9 * 10 ) / 2 = 45 on average , each number will be reduced by 45 / 10 = 4.5 therefore , the overall average will be reduced by 4.5 the answer is c . | general |
math_qa__Ob5wXWnDU4f8lwh2 | After 2 games, team B had an average of 61.5 points per game. If it got only 47 points in game 3, how many more points does it need to score to get its total above 500? Choose one.
A) 805 B) 740 C) 670 D) 530 E) 330 | <gadget id="calculator">2 * 61.5</gadget>
<output>123</output>
<gadget id="calculator">123 + 47</gadget>
<output>170</output>
<gadget id="calculator">500 - 170</gadget>
<output>330</output>
<result>E</result> | E | 330 | After 2 games, team B had an average of 61.5 points per game. If it got only 47 points in game 3, how many more points does it need to score to get its total above 500? | {
"A": "805",
"B": "740",
"C": "670",
"D": "530",
"E": "330"
} | subtract(500, add(multiply(2, 61.5), 47)) | multiply(n0,n1)|add(n2,#0)|subtract(n4,#1) | ( 2 * 61.5 ) + 47 + x > 500 123 + 47 + x > 500 170 + x > 500 = > x > 330 option e | general |
math_qa__7eDvlsgWYzGwfRZK | Calculate the number of bricks, each measuring 25 cm * 15 cm * 8 cm required to construct a wall of dimensions 10 m * 4 m * 5 m when 10% of its volume is occupied by mortar? Choose the correct answer
A) 3388
B) 27678
C) 6000
D) 2977
E) 27681 | <gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">1_000 * 400</gadget>
<output>400_000</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">400_000 * 500</gadget>
<output>200_000_000</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">200_000_000 * (9/10)</gadget>
<output>180_000_000</output>
<gadget id="calculator">25 * 15</gadget>
<output>375</output>
<gadget id="calculator">375 * 8</gadget>
<output>3_000</output>
<gadget id="calculator">180_000_000 / 3_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 10</gadget>
<output>6_000</output>
<result>C</result> | C | 6,000 | Calculate the number of bricks, each measuring 25 cm * 15 cm * 8 cm required to construct a wall of dimensions 10 m * 4 m * 5 m when 10% of its volume is occupied by mortar? | {
"A": "3388",
"B": "27678",
"C": "6000",
"D": "2977",
"E": "27681"
} | divide(divide(multiply(multiply(multiply(multiply(10, const_100), multiply(4, const_100)), multiply(5, const_100)), divide(subtract(10, const_1), 10)), multiply(multiply(25, 15), 8)), 10) | multiply(n3,const_100)|multiply(n4,const_100)|multiply(n5,const_100)|multiply(n0,n1)|subtract(n3,const_1)|divide(#4,n3)|multiply(#0,#1)|multiply(n2,#3)|multiply(#6,#2)|multiply(#5,#8)|divide(#9,#7)|divide(#10,n3) | 10 * 4 / 100 * 5 * 90 / 100 = 25 / 100 * 15 / 100 * 8 / 100 * x 10 * 20 * 90 = 15 * 2 * x = > x = 6000 answer : c | physics |
math_qa__2LAc1x1ykFG2VSSg | A class has a ratio of 3:6:7 of children with red hair, blonde hair and black hair respectively. If the class has 9 kids with red hair, how many kids are in the class? Choices:
A) 99 B) 48 C) 16 D) 22 E) 60 | <gadget id="calculator">7 + 6</gadget>
<output>13</output>
<gadget id="calculator">13 + 3</gadget>
<output>16</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<result>B</result> | B | 48 | A class has a ratio of 3:6:7 of children with red hair, blonde hair and black hair respectively. If the class has 9 kids with red hair, how many kids are in the class? | {
"A": "99",
"B": "48",
"C": "16",
"D": "22",
"E": "60"
} | multiply(add(add(7, 6), 3), 3) | add(n1,n2)|add(n0,#0)|multiply(n0,#1) | since there are 9 children with red hair , and the class exists in a 3 : 6 : 7 ratio , there are 3 times more children than the unit ratio . therefore 9 red - haired children 3 * ( 6 ) blonde - haired children 3 * ( 7 ) black - haired children 9 + 18 + 21 = 48 alternatively , a part - to - whole ratio can be set up . since the whole is 3 + 6 + 7 = 16 , 9 / 3 = x / 16 3 * 16 = 48 answer : b ) | other |
math_qa__Ynz1Bu4RCbQvK3GJ | A certain club has 10 members, including Parry. One of the 10 members is chosen at random to be the president, one of the remaining 9 members is to be chosen at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that parry will be either the member chose to be secretary or the member chose to be treasurer? Choose the correct option:
A) 1 / 720 B) 1 / 80 C) 1 / 10 D) 1 / 9 E) 1 / 5 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + (1/10)</gadget>
<output>1/5 = around 0.2</output>
<result>E</result> | E | 0.2 | A certain club has 10 members, including Parry. One of the 10 members is chosen at random to be the president, one of the remaining 9 members is to be chosen at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that parry will be either the member chose to be secretary or the member chose to be treasurer? | {
"A": "1 / 720",
"B": "1 / 80",
"C": "1 / 10",
"D": "1 / 9",
"E": "1 / 5"
} | add(divide(const_1, 10), divide(const_1, 10)) | divide(const_1,n0)|add(#0,#0) | in order to become a secretary the person can not be chosen as a president . this can be done in 9 / 10 ways . then to become a secretary this person ' s probability is 1 / 9 probability to become a secretary = ( 9 / 10 * 1 / 9 ) = 1 / 10 similar concept for treasurer . probability of not president = 9 / 10 , probability of not secretary = 8 / 9 , probability of treasurer 1 / 8 probability to become a treasurer = ( 9 / 10 * 8 / 9 * 1 / 8 ) = 1 / 10 since , the problem is saying parry secretary or treasurer it is addition : 1 / 10 + 1 / 10 = 1 / 5 = e | probability |
math_qa__ngpx32hiCKBaUFIJ | A millionaire bought a job lot of hats 1/4 of which were brown. The millionaire sold 2/3 of the hats including 4/5 of the brown hats. What fraction of the unsold hats were brown. Choices:
A) 1 / 60 B) 1 / 15 C) 3 / 20 D) 3 / 5 E) 3 / 4 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/5) * (1/4)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/20) / (1/3)</gadget>
<output>3/20 = around 0.15</output>
<result>C</result> | C | 0.15 | A millionaire bought a job lot of hats 1/4 of which were brown. The millionaire sold 2/3 of the hats including 4/5 of the brown hats. What fraction of the unsold hats were brown. | {
"A": "1 / 60",
"B": "1 / 15",
"C": "3 / 20",
"D": "3 / 5",
"E": "3 / 4"
} | divide(multiply(subtract(const_1, divide(4, 5)), divide(1, 4)), subtract(const_1, divide(2, 3))) | divide(n0,n1)|divide(n1,n5)|divide(n2,n3)|subtract(const_1,#1)|subtract(const_1,#2)|multiply(#0,#3)|divide(#5,#4) | if initially he had x hats . x / 4 were brown . sold x * 2 / 3 hats . left with x / 3 hats . sold ( x / 4 ) * ( ( 4 / 5 ) = x / 5 brown hats and left with x / 4 - x / 5 = x / 20 brown hats . fraction of brown hats in total remaining hats = ( x / 20 ) / ( x / 3 ) = 3 / 20 hats answer : c | general |
math_qa__RUWGRk6d1Pt6hKC2 | {(481 + 426)2 - 4 x 481 x 426} = ? Choose the correct choice from the following choices:
A) 3025 B) 4200 C) 3060 D) 3210 E) none of these | <gadget id="calculator">481 + 426</gadget>
<output>907</output>
<gadget id="calculator">907 ** 2</gadget>
<output>822_649</output>
<gadget id="calculator">4 * 481</gadget>
<output>1_924</output>
<gadget id="calculator">1_924 * 426</gadget>
<output>819_624</output>
<gadget id="calculator">822_649 - 819_624</gadget>
<output>3_025</output>
<result>A</result> | A | 3,025 | {(481 + 426)2 - 4 x 481 x 426} = ? | {
"A": "3025",
"B": "4200",
"C": "3060",
"D": "3210",
"E": "none of these"
} | subtract(power(add(481, 426), 2), multiply(multiply(4, 481), 426)) | add(n0,n1)|multiply(n0,n3)|multiply(n1,#1)|power(#0,n2)|subtract(#3,#2)| | "explanation : here , the given statement is like ( a + b ) 2 - 4 ab where a = 481 and b = 426 ( a + b ) 2 - 4 ab = ( a 2 + 2 ab + b 2 ) - 4 ab = a 2 - 2 ab + b 2 = ( a - b ) 2 hence { ( 481 + 426 ) 2 - 4 x 481 x 426 } = ( 481 - 426 ) 2 = 552 = 3025 . answer : option a" | general |
math_qa__eLJZNkyDJUnJKAVZ | Sum of the squares of 3 no.'s is 138 and the sum of their products taken two at a time is 131. Find the sum? Select the correct option:
A) 20 B) 24 C) 26 D) 28 E) 30 | <gadget id="calculator">131 * 2</gadget>
<output>262</output>
<gadget id="calculator">262 + 138</gadget>
<output>400</output>
<gadget id="calculator">400 ** (1/2)</gadget>
<output>20</output>
<result>A</result> | A | 20 | Sum of the squares of 3 no.'s is 138 and the sum of their products taken two at a time is 131. Find the sum? | {
"A": "20",
"B": "24",
"C": "26",
"D": "28",
"E": "30"
} | sqrt(add(multiply(131, const_2), 138)) | multiply(n2,const_2)|add(n1,#0)|sqrt(#1) | ( a + b + c ) 2 = a 2 + b 2 + c 2 + 2 ( ab + bc + ca ) = 138 + 2 * 131 a + b + c = √ 400 = 20 a | general |
math_qa__7kTjMIsftWc2CFic | A 6000 liter tank, half-full of water is being filled from a pipe with a flow rate of 1 kiloliter every 2 minutes. At the same time, the tank is losing water from two drains at a rate of 1 kiloliter every 4 minutes and every 6 minutes. How many minutes does it take to fill the tank completely?
Select the correct option.
A) 8
B) 12
C) 18
D) 24
E) 36 | <gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">6_000 / 2</gadget>
<output>3_000</output>
<gadget id="calculator">12 * 3_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 1_000</gadget>
<output>36</output>
<result>E</result> | E | 36 | A 6000 liter tank, half-full of water is being filled from a pipe with a flow rate of 1 kiloliter every 2 minutes. At the same time, the tank is losing water from two drains at a rate of 1 kiloliter every 4 minutes and every 6 minutes. How many minutes does it take to fill the tank completely? | {
"A": "8",
"B": "12",
"C": "18",
"D": "24",
"E": "36"
} | divide(multiply(add(add(6, 4), 2), divide(6000, 2)), const_1000) | add(n4,n5)|divide(n0,n2)|add(n2,#0)|multiply(#2,#1)|divide(#3,const_1000)| | "in : we have : 1,000 / 2 min = 500 litres per minute out : we have : 1,000 / 4 + 1,000 / 6 then do : in - out to figure out the net inflow per minute ( you get 83.3 ) . then divide the total number of litres you need ( 3,000 by that net inflow to get the minutes ) - 36 min . answer e ." | physics |
math_qa__mEk59gL1u3jdq5LZ | If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 6 is subtracted and divided by 8? Choices
A) 4
B) 6
C) 8
D) 5
E) 3 | <gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">49 + 5</gadget>
<output>54</output>
<gadget id="calculator">54 - 6</gadget>
<output>48</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<result>B</result> | B | 6 | If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 6 is subtracted and divided by 8? | {
"A": "4",
"B": "6",
"C": "8",
"D": "5",
"E": "3"
} | divide(subtract(add(multiply(7, 7), 5), 6), 8) | multiply(n1,n1)|add(n0,#0)|subtract(#1,n3)|divide(#2,n4) | explanation : let the number be x . then , ( x - 5 ) / 7 = 7 = > x - 5 = 49 x = 54 . : ( x - 6 ) / 8 = ( 54 - 6 ) / 8 = 6 answer : option b | general |
math_qa__HOsYHx60fqly4QyU | (x + 5) is a factor in x^2 - mx - 40. What is the value of m? Choose the correct choice:
A) 1
B) 2
C) 4
D) 3
E) 5 | <gadget id="calculator">40 / 5</gadget>
<output>8</output>
<gadget id="calculator">8 - 5</gadget>
<output>3</output>
<result>D</result> | D | 3 | (x + 5) is a factor in x^2 - mx - 40. What is the value of m? | {
"A": "1",
"B": "2",
"C": "4",
"D": "3",
"E": "5"
} | subtract(divide(40, 5), 5) | divide(n2,n0)|subtract(#0,n0)| | "i solved the second degree equation and found it like this : x ^ 2 - mx - 40 = 0 ( x - 8 ) ( x + 5 ) = 0 x = 8 or x = - 5 substituting both values for x in the equation we find : x ^ 2 - mx - 40 = > ( - 5 ) ^ 2 - m ( - 5 ) = 40 = > 25 + 5 m = 40 = > 5 m = 40 - 25 = 15 = > m = 3 and with 8 , using a similar process we end up with : ( 8 ) ^ 2 - m ( 8 ) = 40 - 8 m = 40 - 64 = - 24 m = 3 ao , ans d" | general |
math_qa__0vCV0zPXXBtgukz0 | A sum is divided among B, C and D in such a way that for each rupee B gets, C gets 150 paisa and D gets 50 paisa. If the share of C is RS. 40, what is the total amount?
Choose the most appropriate option
A) 70 B) 75 C) 80 D) 85 E) 90 | <gadget id="calculator">50 / 50</gadget>
<output>1</output>
<gadget id="calculator">100 / 50</gadget>
<output>2</output>
<gadget id="calculator">150 / 50</gadget>
<output>3</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">2 * 40</gadget>
<output>80</output>
<result>C</result> | C | 80 | A sum is divided among B, C and D in such a way that for each rupee B gets, C gets 150 paisa and D gets 50 paisa. If the share of C is RS. 40, what is the total amount? | {
"A": "70",
"B": "75",
"C": "80",
"D": "85",
"E": "90"
} | multiply(divide(add(divide(50, 50), add(divide(const_100, 50), divide(150, 50))), divide(150, 50)), 40) | divide(const_100,n1)|divide(n0,n1)|divide(n1,n1)|add(#0,#1)|add(#3,#2)|divide(#4,#1)|multiply(n2,#5) | b : c : d = 100 : 150 : 100 20 : 30 : 10 30 - - - 40 60 - - - ? = > 80 answer : c | general |
math_qa__Jkj0uQCrS5dqbeKQ | Find the average marks of all the students in 2 separate classes, if the average marks of students in the first class of 58 students is 67 and that of another class of 52 students is 82. Choose the correct answer: A) 74.1 B) 56.3 C) 67.8 D) 79.7 E) 19.4 | <gadget id="calculator">58 * 67</gadget>
<output>3_886</output>
<gadget id="calculator">52 * 82</gadget>
<output>4_264</output>
<gadget id="calculator">3_886 + 4_264</gadget>
<output>8_150</output>
<gadget id="calculator">58 + 52</gadget>
<output>110</output>
<gadget id="calculator">8_150 / 110</gadget>
<output>815/11 = around 74.090909</output>
<result>A</result> | A | 74.1 | Find the average marks of all the students in 2 separate classes, if the average marks of students in the first class of 58 students is 67 and that of another class of 52 students is 82. | {
"A": "74.1",
"B": "56.3",
"C": "67.8",
"D": "79.7",
"E": "19.4"
} | divide(add(multiply(58, 67), multiply(52, 82)), add(58, 52)) | add(n1,n3)|multiply(n1,n2)|multiply(n3,n4)|add(#1,#2)|divide(#3,#0)| | "sum of the marks for the class of 58 students = 58 * 67 = 3886 sum of the marks for the class of 52 students = 52 * 82 = 4264 sum of the marks for the class of 110 students = 3886 + 4262 = 8150 average marks of all the students = 4200 / 80 = 74.1 answer : a" | general |
math_qa__pOOMJLTb2V7VI6aP | Four horses are tethered at four corners of a square plot of side 63 metres so that they just cannot reach one another. The area left ungrazed is: Choices: A) 675.5 m 2 B) 780.6 m 2 C) 785.8 m 2 D) 850.5 m 2 E) 950.5 m 2 | <gadget id="calculator">63 * 63</gadget>
<output>3_969</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">4 * (1/4)</gadget>
<output>1</output>
<gadget id="calculator">1 * pi</gadget>
<output>pi = around 3.141593</output>
<gadget id="calculator">63 / 2</gadget>
<output>63/2 = around 31.5</output>
<gadget id="calculator">pi * (63/2)</gadget>
<output>63*pi/2 = around 98.960169</output>
<gadget id="calculator">(63*pi/2) * (63/2)</gadget>
<output>3969*pi/4 = around 3_117.245311</output>
<gadget id="calculator">3_969 - (3969*pi/4)</gadget>
<output>3969 - 3969*pi/4 = around 851.754689</output>
<result>D</result> | D | 850.5 | Four horses are tethered at four corners of a square plot of side 63 metres so that they just cannot reach one another. The area left ungrazed is: | {
"A": "675.5 m 2",
"B": "780.6 m 2",
"C": "785.8 m 2",
"D": "850.5 m 2",
"E": "950.5 m 2"
} | subtract(multiply(63, 63), multiply(multiply(multiply(multiply(const_4, const_0_25), const_pi), divide(63, const_2)), divide(63, const_2))) | divide(n0,const_2)|multiply(n0,n0)|multiply(const_0_25,const_4)|multiply(#2,const_pi)|multiply(#0,#3)|multiply(#0,#4)|subtract(#1,#5) | required area = ( 63 * 63 – 4 * 1 / 4 * 22 / 7 * 63 / 2 * 63 / 2 ) = 850.5 m 2 answer : d | geometry |
math_qa__6gVAuQDj7CFSo2P5 | mixture contains alcohol and water in the ratio 4 : 3. If 7 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture. Answers.
A) 10 B) 99 C) 5 D) 22 E) 29 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">7 * 4</gadget>
<output>28</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">28 - 12</gadget>
<output>16</output>
<gadget id="calculator">20 / 16</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 4</gadget>
<output>5</output>
<result>C</result> | C | 5 | mixture contains alcohol and water in the ratio 4 : 3. If 7 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture. | {
"A": "10",
"B": "99",
"C": "5",
"D": "22",
"E": "29"
} | multiply(divide(multiply(4, 5), subtract(multiply(7, 4), multiply(3, 4))), 4) | multiply(n0,n4)|multiply(n0,n2)|multiply(n0,n1)|subtract(#1,#2)|divide(#0,#3)|multiply(n0,#4)| | "let the quantity of alcohol and water be 4 x litres and 3 x litres respectively 28 x = 4 ( 3 x + 5 ) 16 x = 20 x = 1.25 quantity of alcohol = ( 4 x 1.25 ) litres = 5 litres . answer : c" | general |
math_qa__fJFQbI44I8bJg2hm | Find the value of 1/(3+1/(3+1/(3-1/3)))? Choose the most appropriate option
A) 13 / 89 B) 15 / 87 C) 27 / 89 D) 27 / 87 E) 89 / 27 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">3 - (1/3)</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">1 / (8/3)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">3 + (3/8)</gadget>
<output>27/8 = around 3.375</output>
<gadget id="calculator">1 / (27/8)</gadget>
<output>8/27 = around 0.296296</output>
<gadget id="calculator">3 + (8/27)</gadget>
<output>89/27 = around 3.296296</output>
<gadget id="calculator">1 / (89/27)</gadget>
<output>27/89 = around 0.303371</output>
<result>C</result> | C | 0.303371 | Find the value of 1/(3+1/(3+1/(3-1/3)))? | {
"A": "13 / 89",
"B": "15 / 87",
"C": "27 / 89",
"D": "27 / 87",
"E": "89 / 27"
} | divide(1, add(3, divide(1, add(3, divide(1, subtract(3, divide(1, 3))))))) | divide(n0,n1)|subtract(n1,#0)|divide(n0,#1)|add(n1,#2)|divide(n0,#3)|add(n1,#4)|divide(n0,#5)| | "1 / [ 3 + ( 1 / ( 3 + 1 / ( 3 - 1 / 3 ) ) ) ] = > 1 / [ 3 + 1 / ( 3 + 1 / ( 8 / 3 ) ) ] = > 1 / [ 3 + 1 / ( 3 + 3 / 8 ) ] = > 1 / [ 3 + 8 / 27 ] = > 1 / ( 89 / 27 ) = > 27 / 89 c )" | general |
math_qa__W1GYSBYYZpTV4FuO | 18 men can complete a piece of work in 20 days. In how many days can 15 men complete that piece of work? Pick one.
A) 23 B) 27 C) 20 D) 24 E) 11 | <gadget id="calculator">20 * 18</gadget>
<output>360</output>
<gadget id="calculator">360 / 15</gadget>
<output>24</output>
<result>D</result> | D | 24 | 18 men can complete a piece of work in 20 days. In how many days can 15 men complete that piece of work? | {
"A": "23",
"B": "27",
"C": "20",
"D": "24",
"E": "11"
} | divide(multiply(20, 18), 15) | multiply(n0,n1)|divide(#0,n2)| | "18 * 20 = 15 * x = > x = 24 days answer : d" | physics |
math_qa__6FzBix1k7pwdecDB | The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 9000, brokerage being 1/4%, is: Choose the correct choice
A) 113.2 B) 114 C) 114.75 D) 124 E) 124.75 | <gadget id="calculator">9_000 / 756</gadget>
<output>250/21 = around 11.904762</output>
<gadget id="calculator">(250/21) * 10.5</gadget>
<output>125</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">125 - (1/4)</gadget>
<output>499/4 = around 124.75</output>
<result>E</result> | E | 124.75 | The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 9000, brokerage being 1/4%, is: | {
"A": "113.2",
"B": "114",
"C": "114.75",
"D": "124",
"E": "124.75"
} | subtract(multiply(divide(9000, 756), 10.5), divide(1, 4)) | divide(n2,n1)|divide(n3,n4)|multiply(n0,#0)|subtract(#2,#1)| | "face value = rs . 9000 . dividend = 10.5 % . annual income = rs . 756 . brokerage per rs . 100 = rs . 0.25 . dividend is always paid on the face value of a share . face value * dividend / ( market value + brokerage per rs . 100 ) = annual income . = 9000 * 10.5 / 756 = market value of rs . 100 stock + brokerage per rs . 100 . = market value of rs . 100 stock + brokerage per rs . 100 = rs . 125 . = market value of rs . 100 stock = rs . 125 - re . 0.25 . = market value of rs . 100 stock = rs . 124.75 . answer : e" | gain |
math_qa__WL61G92tQJT2UXyA | A dog takes 2 leaps for every 3 leaps of a hare. If one leap of the dog is equal to 5 leaps of the hare, the ratio of the speed of the dog to that of the hare is : Pick one.
A) 9 : 3
B) 3 : 10
C) 2 : 3
D) 6 : 3
E) 10 : 3 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 / 3</gadget>
<output>10/3 = around 3.333333</output>
<result>E</result> | E | 3.333333 | A dog takes 2 leaps for every 3 leaps of a hare. If one leap of the dog is equal to 5 leaps of the hare, the ratio of the speed of the dog to that of the hare is : | {
"A": "9 : 3",
"B": "3 : 10",
"C": "2 : 3",
"D": "6 : 3",
"E": "10 : 3"
} | divide(multiply(2, 5), 3) | multiply(n0,n2)|divide(#0,n1)| | "explanation : dog : hare = ( 2 * 5 ) leaps of hare : 3 leaps of hare = 10 : 3 answer : e" | other |
math_qa__9cwBYVczRB6yfTw8 | If a 10 percent deposit that has been paid toward the purchase of a certain product is $55, how much more remains to be paid? Choose one:
A) $ 455 B) $ 495 C) $ 525 D) $ 550 E) $ 585 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">55 * 10</gadget>
<output>550</output>
<gadget id="calculator">550 - 55</gadget>
<output>495</output>
<result>B</result> | B | 495 | If a 10 percent deposit that has been paid toward the purchase of a certain product is $55, how much more remains to be paid? | {
"A": "$ 455",
"B": "$ 495",
"C": "$ 525",
"D": "$ 550",
"E": "$ 585"
} | subtract(multiply(55, divide(const_100, 10)), 55) | divide(const_100,n0)|multiply(n1,#0)|subtract(#1,n1)| | "90 % remains to be paid so the remaining amount is 9 * 55 = $ 495 . the answer is b ." | general |
math_qa__UkgD9Javbzuy1KVD | If two times of the daughter’s age in years is included to the mother’s age, the total is 70 and if two times of the mother’s age is included to the daughter’s age, the total is 95. So the Mother’s age is,
Select: A) 30 B) 40 C) 50 D) 60 E) 39 | <gadget id="calculator">95 * 2</gadget>
<output>190</output>
<gadget id="calculator">190 - 70</gadget>
<output>120</output>
<gadget id="calculator">120 / 3</gadget>
<output>40</output>
<result>B</result> | B | 40 | If two times of the daughter’s age in years is included to the mother’s age, the total is 70 and if two times of the mother’s age is included to the daughter’s age, the total is 95. So the Mother’s age is, | {
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "39"
} | divide(subtract(multiply(95, const_2), 70), const_3) | multiply(n1,const_2)|subtract(#0,n0)|divide(#1,const_3) | b 40 let daughter ’ s age = a and mother ’ s age = b given : 2 a + b = 70 and , a + 2 b = 95 solving b , we will get b = 40 . | general |
math_qa__13IC4RjwMh2eDWrT | an auto assembly plant performs 6 functions with each frame that arrives : add axles , add wheels to the axles , install the windshield to the frame , install the instrument panel , install the steering wheel , and install the interior seating . once those 6 tasks are performed , each car goes to a separate building for finishing touches . if these tasks can be arranged along a linear assembly line in any order , except that the axles must be installed before the wheels can be added , how many r ways can the assembly line be arranged ? Choose the correct choice from the following choices
A) 120 B) 240 C) 360 D) 480 E) 720 | <gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">720 / 2</gadget>
<output>360</output>
<result>C</result> | C | 360 | an auto assembly plant performs 6 functions with each frame that arrives : add axles , add wheels to the axles , install the windshield to the frame , install the instrument panel , install the steering wheel , and install the interior seating . once those 6 tasks are performed , each car goes to a separate building for finishing touches . if these tasks can be arranged along a linear assembly line in any order , except that the axles must be installed before the wheels can be added , how many r ways can the assembly line be arranged ? | {
"A": "120",
"B": "240",
"C": "360",
"D": "480",
"E": "720"
} | divide(factorial(6), const_2) | factorial(n0)|divide(#0,const_2) | c ) 360 short way : there are 6 c ! ways to do the six tasks . half will have wheels before axles and half will have axles before wheels . so we want r = 6 c ! / 2 - > 720 / 2 = 360 | general |
math_qa__eb84gD8JVYLe3QF7 | The difference between the compound interest and simple interest on a certain sum at 10% per annum for 2years is $631. Find the sum? Answers.
A) $ 52000
B) $ 61000
C) $ 71540
D) $ 63100
E) $ 56210 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 * 631</gadget>
<output>6_310_000</output>
<gadget id="calculator">6_310_000 / 100</gadget>
<output>63_100</output>
<result>D</result> | D | 63,100 | The difference between the compound interest and simple interest on a certain sum at 10% per annum for 2years is $631. Find the sum? | {
"A": "$ 52000",
"B": "$ 61000",
"C": "$ 71540",
"D": "$ 63100",
"E": "$ 56210"
} | divide(multiply(multiply(const_100, const_100), 631), const_100) | multiply(const_100,const_100)|multiply(n2,#0)|divide(#1,const_100) | let the sum be $ x c . i . = x ( 1 + 10 / 100 ) ^ 2 - x = 21 x / 100 s . i . = ( x * 10 * 2 ) / 100 = x / 5 c . i . - s . i . = ( 21 x / 100 ) - ( x / 5 ) = x / 100 x / 100 = 631 x = 63100 answer is d | gain |
math_qa__zvcvDjGYnic70b4l | What is the smallest number which when diminished by 16, is divisible 4, 6, 8 and 10?
Options.
A) 136 B) 192 C) 198 D) 122 E) 142 | <gadget id="calculator">lcm(4, 6)</gadget>
<output>12</output>
<gadget id="calculator">lcm(8, 10)</gadget>
<output>40</output>
<gadget id="calculator">lcm(12, 40)</gadget>
<output>120</output>
<gadget id="calculator">120 + 16</gadget>
<output>136</output>
<result>A</result> | A | 136 | What is the smallest number which when diminished by 16, is divisible 4, 6, 8 and 10? | {
"A": "136",
"B": "192",
"C": "198",
"D": "122",
"E": "142"
} | add(lcm(lcm(4, 6), lcm(8, 10)), 16) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2) | required number = ( lcm of 4 , 6,8 , and 10 ) + 16 = 120 + 16 = 136 option a | general |
math_qa__mZkjDnHmVSYakmyE | In a room with 10 people, 6 people have exactly 1 friend in the room and 5 people have exactly 2 friends in the room (Assuming that friendship is a mutual relationship, i.e. if Jane is Paul's friend, Paul is Jane's friend). If two individuals are selected from the room at random, what is the probability that those two individuals are NOT friends? Choose the correct choice:
A) 5 / 21 B) 3 / 7 C) 4 / 5 D) 5 / 7 E) 16 / 21 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>
<result>C</result> | C | 0.8 | In a room with 10 people, 6 people have exactly 1 friend in the room and 5 people have exactly 2 friends in the room (Assuming that friendship is a mutual relationship, i.e. if Jane is Paul's friend, Paul is Jane's friend). If two individuals are selected from the room at random, what is the probability that those two individuals are NOT friends? | {
"A": "5 / 21",
"B": "3 / 7",
"C": "4 / 5",
"D": "5 / 7",
"E": "16 / 21"
} | divide(subtract(subtract(subtract(10, 1), 1), 1), subtract(10, 1)) | subtract(n0,n2)|subtract(#0,n2)|subtract(#1,n2)|divide(#2,#0) | ( 6 / 10 ) ( 7 / 9 ) + ( 5 / 10 ) ( 6 / 9 ) if you choose one of the 6 with one other friend , then you have a 7 / 9 chance of not picking their friend 2 nd . if you choose one of the 5 with 2 friends , you have a 6 / 9 chance of not picking one of their friends second . add them up . 42 / 90 + 30 / 90 72 / 90 = 4 / 5 c . 4 / 5 | general |
math_qa__HtAE79NHwei6FrrS | There are 4 people of different heights standing in order of increasing height. The difference is 2 inches between the first person and the second person, and also between the second person and the third person. The difference between the third person and the fourth person is 6 inches and the average height is 79. How tall is the fourth person? Options
A) 85 B) 87 C) 89 D) 91 E) 93 | <gadget id="calculator">79 * 4</gadget>
<output>316</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">6 + 10</gadget>
<output>16</output>
<gadget id="calculator">316 - 16</gadget>
<output>300</output>
<gadget id="calculator">300 / 4</gadget>
<output>75</output>
<gadget id="calculator">75 + 10</gadget>
<output>85</output>
<result>A</result> | A | 85 | There are 4 people of different heights standing in order of increasing height. The difference is 2 inches between the first person and the second person, and also between the second person and the third person. The difference between the third person and the fourth person is 6 inches and the average height is 79. How tall is the fourth person? | {
"A": "85",
"B": "87",
"C": "89",
"D": "91",
"E": "93"
} | add(divide(subtract(multiply(79, 4), add(6, add(4, 6))), 4), add(4, 6)) | add(n0,n2)|multiply(n0,n3)|add(n2,#0)|subtract(#1,#2)|divide(#3,n0)|add(#0,#4)| | "let x be the height of the first person . then the heights are x , x + 2 , x + 4 , and x + 10 . 4 x + 16 = 4 ( 79 ) = 316 x = 75 and the fourth person has a height of 75 + 10 = 85 inches the answer is a ." | general |
math_qa__DjHD9lSd21lkKEDR | The profit earned by selling an article for 812 is equal to the loss incurred when the same article is sold for 448. What should be the sale price of the article for making 50 per cent profit?
Choose the correct choice from the following answers.
A) 960
B) 1060
C) 1,200
D) 945
E) none of these | <gadget id="calculator">812 + 448</gadget>
<output>1_260</output>
<gadget id="calculator">1_260 / 2</gadget>
<output>630</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">630 * (3/2)</gadget>
<output>945</output>
<result>D</result> | D | 945 | The profit earned by selling an article for 812 is equal to the loss incurred when the same article is sold for 448. What should be the sale price of the article for making 50 per cent profit? | {
"A": "960",
"B": "1060",
"C": "1,200",
"D": "945",
"E": "none of these"
} | multiply(divide(add(812, 448), const_2), add(const_1, divide(50, const_100))) | add(n0,n1)|divide(n2,const_100)|add(#1,const_1)|divide(#0,const_2)|multiply(#2,#3)| | "let the profit or loss be x and 812 – x = 448 + x or , x = 364 ⁄ 2 = 182 \ cost price of the article = 812 – x = 448 + x = 630 \ sp of the article = 630 × 150 ⁄ 100 = 945 answer d" | gain |
math_qa__FKhQhF8mBYUIGm8h | If w is 40 percent less than e, e is 40 percent less than y, and z is 46 percent less than y, then z is greater than w by what percent of w? Choices:
A) 4 % B) 18 % C) 36 % D) 40 % E) 50 % | <gadget id="calculator">46 / 100</gadget>
<output>23/50 = around 0.46</output>
<gadget id="calculator">1 - (23/50)</gadget>
<output>27/50 = around 0.54</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * (3/5)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(27/50) / (9/25)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>E</result> | E | 50 | If w is 40 percent less than e, e is 40 percent less than y, and z is 46 percent less than y, then z is greater than w by what percent of w? | {
"A": "4 %",
"B": "18 %",
"C": "36 %",
"D": "40 %",
"E": "50 %"
} | multiply(subtract(divide(subtract(const_1, divide(46, const_100)), multiply(subtract(const_1, divide(40, const_100)), subtract(const_1, divide(40, const_100)))), const_1), const_100) | divide(n2,const_100)|divide(n0,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|multiply(#3,#3)|divide(#2,#4)|subtract(#5,const_1)|multiply(#6,const_100) | given w = 0.6 e , e = 0.6 y , z = 0.54 y , substituting , w = 2 / 3 z - - - - > z = 1.5 w and thus z is 50 % greater than w . e is the correct answer . | gain |
math_qa__taTuvwd3BEUjtdyx | What is the angle between the minute hand and the hour hand when the time is 1540 hours? Pick:
A) 150
B) 160
C) 140
D) 130
E) none | <gadget id="calculator">1_540 / 4</gadget>
<output>385</output>
<gadget id="calculator">385 / 3</gadget>
<output>385/3 = around 128.333333</output>
<result>D</result> | D | 130 | What is the angle between the minute hand and the hour hand when the time is 1540 hours? | {
"A": "150",
"B": "160",
"C": "140",
"D": "130",
"E": "none"
} | divide(divide(1540, const_4), const_3) | divide(n0,const_4)|divide(#0,const_3) | solution : the total angle made by the minute hand during an hour is 360 o . if it takes 360 o for an hour , it will take ( 40 / 60 ) * 360 = 240 o . the angle between the hour hand the minute hand will therefore , be somewhere between 240 - 90 = 150 o , as the hour hand is between 3 and 4 . the angle made by the hour hand when it moves from say 3 to 4 will be 30 o . that is the hour hand makes 30 o during the course of an hour . the hour hand will therefore , move ( 40 / 60 ) * 30 = 20 o . therefore , the net angle between the hour hand and the minute hand will be 150 - 20 = 130 o . answer d | physics |
math_qa__dGydvC4znTxlWJr9 | 3 people each took 5 tests . if the ranges of their scores in the 5 practice tests were 15 , 25 and 30 , what is the minimum possible range in scores of the 3 test - takers ? Choices
A) 25 B) 30 C) 35 D) 15 E) 10 | <gadget id="calculator">30 - 5</gadget>
<output>25</output>
<result>A</result> | A | 25 | 3 people each took 5 tests . if the ranges of their scores in the 5 practice tests were 15 , 25 and 30 , what is the minimum possible range in scores of the 3 test - takers ? | {
"A": "25",
"B": "30",
"C": "35",
"D": "15",
"E": "10"
} | subtract(30, 5) | subtract(n5,n1) | i simply looked at the 3 different possible scores for each individual test : 15 , 30,25 we have to find the minimum range : 30 - 15 = 15 30 - 25 = 5 25 - 15 = 10 the find the minimum range , you have to make the set of the 5 scores as small as possible . which means that 4 of the 5 scores of each individual person is zero . 5 * 5 = 25 . answer : a | general |
math_qa__e8dpW4YB8hf0koAB | A goods train runs at the speed of 72 kmph and crosses a 270 m long platform in 26 seconds. What is the length of the goods train?
Choose the correct choice from the following: A) 230 m B) 250 m C) 643 m D) 832 m E) 270 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 72</gadget>
<output>20</output>
<gadget id="calculator">270 / 20</gadget>
<output>27/2 = around 13.5</output>
<gadget id="calculator">26 - (27/2)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 20</gadget>
<output>250</output>
<result>B</result> | B | 250 | A goods train runs at the speed of 72 kmph and crosses a 270 m long platform in 26 seconds. What is the length of the goods train? | {
"A": "230 m",
"B": "250 m",
"C": "643 m",
"D": "832 m",
"E": "270 m"
} | multiply(subtract(26, divide(270, multiply(const_0_2778, 72))), multiply(const_0_2778, 72)) | multiply(n0,const_0_2778)|divide(n1,#0)|subtract(n2,#1)|multiply(#0,#2)| | "speed = ( 72 x 5 / 18 ) m / sec = 20 m / sec . time = 26 sec . let the length of the train be x metres . then , x + 270 / 26 = 20 x + 270 = 520 x = 250 . answer : b" | physics |
math_qa__0EYsEjCcOQt124Zp | rebecca ' s annual income is $ 15000 and jimmy ' s annual income is $ 18000 . by how much must rebecca ' s annual income increase so that it constitutes 50 % of rebecca and jimmy ' s combined income ? Choose the correct choice from the following.
A) 7000 B) 6000 C) 5000 D) 4000 E) 3000 | <gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">18_000 / (1/2)</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 - 18_000</gadget>
<output>18_000</output>
<gadget id="calculator">18_000 - 15_000</gadget>
<output>3_000</output>
<result>E</result> | E | 3,000 | rebecca ' s annual income is $ 15000 and jimmy ' s annual income is $ 18000 . by how much must rebecca ' s annual income increase so that it constitutes 50 % of rebecca and jimmy ' s combined income ? | {
"A": "7000",
"B": "6000",
"C": "5000",
"D": "4000",
"E": "3000"
} | subtract(subtract(divide(18000, divide(subtract(const_100, 50), const_100)), 18000), 15000) | subtract(const_100,n2)|divide(#0,const_100)|divide(n1,#1)|subtract(#2,n1)|subtract(#3,n0) | total rebecca = x + 15000 ; total = x + 15000 + 18000 x + 15000 / x + 33000 = 50 / 100 therefore x = 3000 e | general |
math_qa__fyUqI9GU5KmYhSzk | A cubic object 3'' x 3'' x 3'' is painted blue on all the outside surfaces, including the top and bottom. If the cube is cut into 27 cubes of 1'' x 1'' x 1'' , how many 1" cubes do have any painted surfaces? Select
A) 15
B) 22
C) 26
D) 33
E) 44 | <gadget id="calculator">27 - 1</gadget>
<output>26</output>
<result>C</result> | C | 26 | A cubic object 3'' x 3'' x 3'' is painted blue on all the outside surfaces, including the top and bottom. If the cube is cut into 27 cubes of 1'' x 1'' x 1'' , how many 1" cubes do have any painted surfaces? | {
"A": "15",
"B": "22",
"C": "26",
"D": "33",
"E": "44"
} | subtract(27, const_1) | subtract(n3,const_1) | c 26 only the box in the very centre of the stack will not suffer the strokes of the paint brush , whereas all the other 26 boxes will have at least one side painted . | geometry |
math_qa__WtqBf9jtKkjDi8ze | Rectangle A has sides a and b, and rectangle B has sides c and d. If a/c=b/d=3/5, what is the ratio of rectangle A’s area to rectangle B’s area? Select the correct option:
A) 5 / 3 B) 9 / 5 C) 9 / 25 D) 3 / 5 E) 25 / 9 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">9 / 25</gadget>
<output>9/25 = around 0.36</output>
<result>C</result> | C | 0.36 | Rectangle A has sides a and b, and rectangle B has sides c and d. If a/c=b/d=3/5, what is the ratio of rectangle A’s area to rectangle B’s area? | {
"A": "5 / 3",
"B": "9 / 5",
"C": "9 / 25",
"D": "3 / 5",
"E": "25 / 9"
} | divide(power(3, const_2), power(5, const_2)) | power(n0,const_2)|power(n1,const_2)|divide(#0,#1) | the area of rectangle a is ab . c = 5 a / 3 and d = 5 b / 3 . the area of rectangle b is cd = 25 ab / 9 . the ratio of rectangle a ' s area to rectangle b ' s area is ab / ( 25 ab / 9 ) = 9 / 25 . the answer is c . | geometry |
math_qa__VlioxPR8m3OwV6F7 | J is faster than P. J and P each walk 24 km. Sum of the speeds of J and P is 7 kmph. Sum of time taken by them is 14 hours. Then J speed is equal to
Choose the correct choice from the following options:
A) 22
B) 14
C) 6
D) 8
E) 16 | <gadget id="calculator">24 / 4</gadget>
<output>6</output>
<gadget id="calculator">24 / 3</gadget>
<output>8</output>
<gadget id="calculator">6 + 8</gadget>
<output>14</output>
<result>B</result> | B | 14 | J is faster than P. J and P each walk 24 km. Sum of the speeds of J and P is 7 kmph. Sum of time taken by them is 14 hours. Then J speed is equal to | {
"A": "22",
"B": "14",
"C": "6",
"D": "8",
"E": "16"
} | add(divide(24, const_4), divide(24, const_3)) | divide(n0,const_4)|divide(n0,const_3)|add(#0,#1) | given j > p j + p = 7 , only options are ( 6 , 1 ) , ( 5 , 2 ) , ( 4 , 3 ) from the given options , if j = 4 the p = 3 . times taken by them = 244 + 243 = 14 answer : b | physics |
math_qa__cAkT6Hm1Q9iYt4Zq | A river 5m deep and 35 m wide is flowing at the rate of 2 kmph, calculate the amount of water that runs into the sea per minute?
Pick one: A) 5832.75 B) 5839.75 C) 5837.75 D) 5222.75 E) 5835.75 | <gadget id="calculator">5 * 35</gadget>
<output>175</output>
<gadget id="calculator">2 * 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">175 * 2_000</gadget>
<output>350_000</output>
<gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">350_000 / 60</gadget>
<output>17_500/3 = around 5_833.333333</output>
<result>A</result> | A | 5,832.75 | A river 5m deep and 35 m wide is flowing at the rate of 2 kmph, calculate the amount of water that runs into the sea per minute? | {
"A": "5832.75",
"B": "5839.75",
"C": "5837.75",
"D": "5222.75",
"E": "5835.75"
} | divide(multiply(multiply(5, 35), multiply(2, const_1000)), multiply(const_1, const_60)) | multiply(n0,n1)|multiply(n2,const_1000)|multiply(const_1,const_60)|multiply(#0,#1)|divide(#3,#2)| | "rate of water flow - 2 kmph - - 2000 / 60 - - 33.33 m / min depth of river - - 5 m width of river - - 35 m vol of water per min - - 33.33 * 5 * 35 - - - 5832.75 answer a" | physics |
math_qa__Wxv385kMFWBc9FQ7 | The area of a square field is 4802 m(power)2 the length of its diagonal is: Choose the correct choice from the following answers
A) 98 m
B) 102 m
C) 95 m
D) 105 m
E) 96 m | <gadget id="calculator">4_802 ** (1/2)</gadget>
<output>49*sqrt(2) = around 69.296465</output>
<gadget id="calculator">2 ** (1/2)</gadget>
<output>sqrt(2) = around 1.414214</output>
<gadget id="calculator">(49*sqrt(2)) * (sqrt(2))</gadget>
<output>98</output>
<result>A</result> | A | 98 | The area of a square field is 4802 m(power)2 the length of its diagonal is: | {
"A": "98 m",
"B": "102 m",
"C": "95 m",
"D": "105 m",
"E": "96 m"
} | multiply(sqrt(4802), sqrt(2)) | sqrt(n0)|sqrt(n1)|multiply(#0,#1) | let the diagonal be d metres , then 1 / 2 d ( power ) 2 = 4802 d 2 = 9604 d = √ 9604 d = 98 m answer is a . | geometry |
math_qa__IYgWNJUxLBxcVlG6 | The probability that a computer company will get a computer hardware contract is 3/4 and the probability that it will not get a software contract is 3/5. If the probability of getting at least one contract is 5/6, what is the probability that it will get both the contracts? Choose the correct choice from the following options
A) 7 / 30
B) 11 / 40
C) 17 / 50
D) 19 / 60
E) 33 / 80 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/4) + (2/5)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(23/20) - (5/6)</gadget>
<output>19/60 = around 0.316667</output>
<result>D</result> | D | 0.316667 | The probability that a computer company will get a computer hardware contract is 3/4 and the probability that it will not get a software contract is 3/5. If the probability of getting at least one contract is 5/6, what is the probability that it will get both the contracts? | {
"A": "7 / 30",
"B": "11 / 40",
"C": "17 / 50",
"D": "19 / 60",
"E": "33 / 80"
} | subtract(add(divide(3, 4), subtract(const_1, divide(3, 5))), divide(5, 6)) | divide(n0,n1)|divide(n0,n3)|divide(n3,n5)|subtract(const_1,#1)|add(#0,#3)|subtract(#4,#2) | let , a ≡ event of getting hardware contract b ≡ event of getting software contract ab ≡ event of getting both hardware and software contract . p ( a ) = 3 / 4 , p ( ~ b ) = 5 / 9 = > p ( b ) = 1 - ( 3 / 5 ) = 2 / 5 . a and b are not mutually exclusive events but independent events . so , p ( at least one of a and b ) = p ( a ) + p ( b ) - p ( ab ) . = > 5 / 6 = ( 3 / 4 ) + ( 2 / 5 ) - p ( ab ) . = > p ( ab ) = 19 / 60 . hence , the required probability is 19 / 60 . the answer is d . | other |
math_qa__FizC8bshzW2d7jOL | To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ? Select
A) 62.5 B) 65 C) 61 D) 64 E) 60 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">25 * 5</gadget>
<output>125</output>
<gadget id="calculator">125 / 2</gadget>
<output>125/2 = around 62.5</output>
<result>A</result> | A | 62.5 | To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ? | {
"A": "62.5",
"B": "65",
"C": "61",
"D": "64",
"E": "60"
} | divide(multiply(25, add(const_4, const_1)), const_2) | add(const_1,const_4)|multiply(n0,#0)|divide(#1,const_2)| | "let the capacity of 1 bucket = x . then , the capacity of tank = 25 x . new capacity of bucket = 2 / 5 x therefore , required number of buckets = ( 25 x ) / ( 2 x / 5 ) = ( 25 x ) x 5 / 2 x = 125 / 2 = 62.5 answer is a ." | physics |
math_qa__2tbGJdBxnftcoZiO | the walker walking at a constant rate of 4 miles per hour is passed by a cyclist traveling in the same direction along the same path at 20 miles per hour. the cyclist stops to wait for the hiker 5 minutes after passing her, while the walker continues to walk at her constant rate, how many minutes must the cyclist wait until the walker catches up?
Choices
A) 16 B) 18 C) 20 D) 22 E) 24 | <gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 5</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">4 / 60</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) * 5</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(5/3) - (1/3)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) / (1/15)</gadget>
<output>20</output>
<result>C</result> | C | 20 | the walker walking at a constant rate of 4 miles per hour is passed by a cyclist traveling in the same direction along the same path at 20 miles per hour. the cyclist stops to wait for the hiker 5 minutes after passing her, while the walker continues to walk at her constant rate, how many minutes must the cyclist wait until the walker catches up? | {
"A": "16",
"B": "18",
"C": "20",
"D": "22",
"E": "24"
} | divide(subtract(multiply(divide(20, const_60), 5), multiply(divide(4, const_60), 5)), divide(4, const_60)) | divide(n1,const_60)|divide(n0,const_60)|multiply(n2,#0)|multiply(n2,#1)|subtract(#2,#3)|divide(#4,#1) | after passing the hiker the cyclist travels for 5 minutes at a rate of 20 miles / hour . in those 5 mins the cyclist travels a distance of 5 / 3 miles . in those 5 mins the hiker travels a distance of 1 / 3 miles . so the hiker still has to cover 4 / 3 miles to meet the waiting cyclist . the hiker will need 1 / 3 hours or 20 mins to cover the remaining 4 / 3 miles . so the answer is c . | physics |
math_qa__FGND9olJ6qDZN9YK | The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 13000, then find the annual income of A? Select the correct option.
A) rs . 420000
B) rs . 180000
C) rs . 436800
D) rs . 504000
E) none of these | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 + (3/25)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">13_000 * (28/25)</gadget>
<output>14_560</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">14_560 * (5/2)</gadget>
<output>36_400</output>
<gadget id="calculator">36_400 * 12</gadget>
<output>436_800</output>
<result>C</result> | C | 436,800 | The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 13000, then find the annual income of A? | {
"A": "rs . 420000",
"B": "rs . 180000",
"C": "rs . 436800",
"D": "rs . 504000",
"E": "none of these"
} | multiply(multiply(multiply(13000, add(const_1, divide(12, const_100))), divide(5, 2)), 12) | divide(n0,n1)|divide(n2,const_100)|add(#1,const_1)|multiply(n3,#2)|multiply(#0,#3)|multiply(n2,#4)| | "b ' s monthly income = 13000 * 112 / 100 = rs . 14560 b ' s monthly income = 2 parts - - - - > rs . 14560 a ' s monthly income = 5 parts = 5 / 2 * 14560 = rs . 36400 a ' s annual income = rs . 36400 * 12 = rs . 436800 answer : c" | other |
math_qa__KDvVDW7cnvDXMZSj | 3*13+3*14+3*17+11 = ? Choose the correct choice from the following answers.
A) 125 B) 126 C) 130 D) 143 E) 151 | <gadget id="calculator">3 * 13</gadget>
<output>39</output>
<gadget id="calculator">3 * 14</gadget>
<output>42</output>
<gadget id="calculator">39 + 42</gadget>
<output>81</output>
<gadget id="calculator">3 * 17</gadget>
<output>51</output>
<gadget id="calculator">81 + 51</gadget>
<output>132</output>
<gadget id="calculator">132 + 11</gadget>
<output>143</output>
<result>D</result> | D | 143 | 3*13+3*14+3*17+11 = ? | {
"A": "125",
"B": "126",
"C": "130",
"D": "143",
"E": "151"
} | add(add(add(multiply(3, 13), multiply(3, 14)), multiply(3, 17)), 11) | multiply(n0,n1)|multiply(n0,n3)|multiply(n0,n5)|add(#0,#1)|add(#3,#2)|add(n6,#4)| | "3 * 13 + 3 * 14 + 3 * 17 + 11 = 39 + 42 + 51 + 11 = 143 the answer is d ." | general |
math_qa__Qzp6mPCf70ZqDEjA | In Mrs. Susna's class, 1/4 of her students are getting an A, 1/2 are getting a B, 1/8 are getting a C, 1/12 are getting a D, and 1/24 are getting a F. What fraction of Mrs. Susna's class getting a passing grade of C or higher. Choose the correct option:
A) 5 / 6
B) 3 / 4
C) 7 / 8
D) 1 / 8
E) 1 / 2 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) + (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(3/4) + (1/8)</gadget>
<output>7/8 = around 0.875</output>
<result>C</result> | C | 0.875 | In Mrs. Susna's class, 1/4 of her students are getting an A, 1/2 are getting a B, 1/8 are getting a C, 1/12 are getting a D, and 1/24 are getting a F. What fraction of Mrs. Susna's class getting a passing grade of C or higher. | {
"A": "5 / 6",
"B": "3 / 4",
"C": "7 / 8",
"D": "1 / 8",
"E": "1 / 2"
} | add(add(divide(1, 4), divide(1, 2)), divide(1, 8)) | divide(n0,n1)|divide(n0,n3)|divide(n0,n5)|add(#0,#1)|add(#3,#2) | if mrs . susna ' s class has 24 students , the number of students receiving as , bs , or cs , are 6 , 12 , and 3 respectively . that means 21 / 24 of her students are receiving passing grades or 7 / 8 . ( answer : c ) | general |
math_qa__21zY9MWgHyF1rYtE | The area of the house of a hall is 20 m2 that of a longer wall 10 m2 and of the shorter wall 8 m2, find the edge of the new cube? Answers:
A) 45 m 3 B) 40 m 3 C) 60 m 3 D) 600 m 3 E) 300 m 3 | <gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">2 * 200</gadget>
<output>400</output>
<gadget id="calculator">400 / 10</gadget>
<output>40</output>
<result>B</result> | B | 40 | The area of the house of a hall is 20 m2 that of a longer wall 10 m2 and of the shorter wall 8 m2, find the edge of the new cube? | {
"A": "45 m 3",
"B": "40 m 3",
"C": "60 m 3",
"D": "600 m 3",
"E": "300 m 3"
} | divide(multiply(2, multiply(20, 10)), 10) | multiply(n0,n2)|multiply(n1,#0)|divide(#1,n2) | lb = 20 ; lh = 10 ; fh = 8 ( lbh ) 2 = 20 * 10 * 8 = > lbh = 40 m 3 answer : b | geometry |
math_qa__GMTJxb60DRHHUrDS | john has taken 4 ( 4 ) tests that have an average of 82 . in order to bring his course grade up to a ‘ b ’ , he will need to have a final average of 86 . what will he need to average on his final two tests to achieve this grade ? Choose one.
A) 87 B) 90 C) 92 D) 94 E) 97 | <gadget id="calculator">86 * 2</gadget>
<output>172</output>
<gadget id="calculator">172 - 82</gadget>
<output>90</output>
<result>D</result> | D | 94 | john has taken 4 ( 4 ) tests that have an average of 82 . in order to bring his course grade up to a ‘ b ’ , he will need to have a final average of 86 . what will he need to average on his final two tests to achieve this grade ? | {
"A": "87",
"B": "90",
"C": "92",
"D": "94",
"E": "97"
} | subtract(multiply(86, const_2), 82) | multiply(n3,const_2)|subtract(#0,n2) | traditional method : total scored till now 82 * 4 = 328 total score to avg 86 in 6 tests = 86 * 6 = 516 total to be scored on 2 tests = 516 - 328 = 188 avg on 2 tests = 188 / 2 = 94 answer : d | general |
math_qa__7qxs62U7O7YYjVBE | Find the surface area of a 8 cm x 4 cm x 2 cm brick. Choose the correct choice from the following options
A) 136 cu cm
B) 112 cu cm
C) 164 cu cm
D) 180 cu cm
E) none | <gadget id="calculator">2 * (2 * 4 + 4 * 8 + 2 * 8)</gadget>
<output>112</output>
<result>B</result> | B | 112 | Find the surface area of a 8 cm x 4 cm x 2 cm brick. | {
"A": "136 cu cm",
"B": "112 cu cm",
"C": "164 cu cm",
"D": "180 cu cm",
"E": "none"
} | surface_rectangular_prism(2, 4, 8) | surface_rectangular_prism(n0,n1,n2)| | "sol . surface area = [ 2 ( 8 x 4 + 4 x 2 + 8 x 2 ) ] = ( 2 x 56 ) = 112 cu cm answer b" | geometry |
math_qa__kkUykPUMBUez7RX0 | A car started running at a speed of 38 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey.
Choose the correct choice.
A) 47 km B) 76 km C) 25 km D) 15 km E) 30 km | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">38 + 20</gadget>
<output>58</output>
<gadget id="calculator">58 + 38</gadget>
<output>96</output>
<gadget id="calculator">96 / 2</gadget>
<output>48</output>
<result>A</result> | A | 47 | A car started running at a speed of 38 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey. | {
"A": "47 km",
"B": "76 km",
"C": "25 km",
"D": "15 km",
"E": "30 km"
} | divide(add(add(38, multiply(2, 10)), 38), 2) | multiply(n1,n2)|add(n0,#0)|add(n0,#1)|divide(#2,n1) | a 47 km the total distance covered by the car in the first 10 hours = 38 + 40 + 42 + 44 + 46 + 48 + 50 + 52 + 54 + 56 = sum of 10 terms in ap whose first term is 30 and last term is 56 = 10 / 2 [ 38 + 56 ] = 470 km . | physics |
math_qa__h3QRltAmaXkOsWRL | 3 containers a , b and c are having mixtures of milk and water in the ratio of 1 : 5 and 3 : 5 and 5 : 7 respectively . if the capacities of the containers are in the ratio of all the 3 containers are in the ratio 5 : 4 : 5 , find the ratio of milk to water , if the mixtures of all the 3 containers are mixed together . Pick one: A) 53 : 115 B) 55 : 115 C) 115 : 55 D) 5 : 115 E) 115 : 53 | <gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 5</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(3/8) * 4</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(5/6) + (3/2)</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">5 + 7</gadget>
<output>12</output>
<gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) * 5</gadget>
<output>25/12 = around 2.083333</output>
<gadget id="calculator">(7/3) + (25/12)</gadget>
<output>53/12 = around 4.416667</output>
<gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">9 + 5</gadget>
<output>14</output>
<gadget id="calculator">14 - (53/12)</gadget>
<output>115/12 = around 9.583333</output>
<gadget id="calculator">(53/12) / (115/12)</gadget>
<output>53/115 = around 0.46087</output>
<result>A</result> | A | 0.46087 | 3 containers a , b and c are having mixtures of milk and water in the ratio of 1 : 5 and 3 : 5 and 5 : 7 respectively . if the capacities of the containers are in the ratio of all the 3 containers are in the ratio 5 : 4 : 5 , find the ratio of milk to water , if the mixtures of all the 3 containers are mixed together . | {
"A": "53 : 115",
"B": "55 : 115",
"C": "115 : 55",
"D": "5 : 115",
"E": "115 : 53"
} | divide(add(add(multiply(divide(1, add(1, 5)), 5), multiply(divide(3, add(3, 5)), 4)), multiply(divide(5, add(5, 7)), 5)), subtract(add(add(5, 4), 5), add(add(multiply(divide(1, add(1, 5)), 5), multiply(divide(3, add(3, 5)), 4)), multiply(divide(5, add(5, 7)), 5)))) | add(n1,n2)|add(n0,n2)|add(n2,n6)|add(n2,n9)|add(n2,#3)|divide(n1,#0)|divide(n0,#1)|divide(n2,#2)|multiply(n2,#5)|multiply(n9,#6)|multiply(n2,#7)|add(#8,#9)|add(#11,#10)|subtract(#4,#12)|divide(#12,#13) | assume that there are 500400 and 500 liters respectively in the 3 containers . then , we have , 83.33 , 150 and 208.33 liters of milk in each of the three containers . thus , the total milk is 441.66 liters . hence , the amount of water in the mixture is 1400 - 441.66 = 958.33 liters . hence , the ratio of milk to water is 441.66 : 958.33 = > 53 : 115 ( using division by . 3333 ) the calculation thought process should be ( 441 * 2 + 2 ) : ( 958 * 3 + 1 ) = 1325 : 2875 dividing by 25 = > 53 : 115 . answer a 53 : 115 | other |
math_qa__d18DZ4801L8TSWzZ | The length of a rectangle is reduced by 22%. By what % would the width have to be increased to maintainthe original area? Choose the correct choice from the following.
A) 15 % B) 20 % C) 28 % D) 35 % E) 40 % | <gadget id="calculator">100 - 22</gadget>
<output>78</output>
<gadget id="calculator">78 / 100</gadget>
<output>39/50 = around 0.78</output>
<gadget id="calculator">1 - (39/50)</gadget>
<output>11/50 = around 0.22</output>
<gadget id="calculator">(11/50) / (39/50)</gadget>
<output>11/39 = around 0.282051</output>
<gadget id="calculator">(11/39) * 100</gadget>
<output>1_100/39 = around 28.205128</output>
<result>C</result> | C | 28 | The length of a rectangle is reduced by 22%. By what % would the width have to be increased to maintainthe original area? | {
"A": "15 %",
"B": "20 %",
"C": "28 %",
"D": "35 %",
"E": "40 %"
} | multiply(divide(subtract(const_1, divide(subtract(const_100, 22), const_100)), divide(subtract(const_100, 22), const_100)), const_100) | subtract(const_100,n0)|divide(#0,const_100)|subtract(const_1,#1)|divide(#2,#1)|multiply(#3,const_100)| | "sol . required change = ( 22 * 100 ) / ( 100 - 22 ) = 28 % c" | geometry |
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