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stringlengths 7
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math_qa__5G21iXJlUjRi91Ct | If 10 litres of an oil of Rs.50 per litres be mixed with 5 litres of another oil of Rs.67 per litre then what is the rate of mixed oil per litre?
Choose the correct option
A) rs . 49.17 B) rs . 51.03 C) rs . 54.17 D) rs . 55.66 E) none of the above | <gadget id="calculator">10 * 50</gadget>
<output>500</output>
<gadget id="calculator">5 * 67</gadget>
<output>335</output>
<gadget id="calculator">500 + 335</gadget>
<output>835</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">835 / 15</gadget>
<output>167/3 = around 55.666667</output>
<result>D</result> | D | 55.66 | If 10 litres of an oil of Rs.50 per litres be mixed with 5 litres of another oil of Rs.67 per litre then what is the rate of mixed oil per litre? | {
"A": "rs . 49.17",
"B": "rs . 51.03",
"C": "rs . 54.17",
"D": "rs . 55.66",
"E": "none of the above"
} | divide(add(multiply(10, 50), multiply(5, 67)), add(10, 5)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | "50 * 10 = 500 67 * 5 = 335 835 / 15 = 55.66 answer : d" | gain |
math_qa__8rh66aF7X4CCklil | The sum of first 45 natural numbers is:
Choose the most appropriate option: A) 1035 B) 1040 C) 1042 D) 1045 E) 1050 | <gadget id="calculator">45 + 1</gadget>
<output>46</output>
<gadget id="calculator">45 * 46</gadget>
<output>2_070</output>
<gadget id="calculator">2_070 / 2</gadget>
<output>1_035</output>
<result>A</result> | A | 1,035 | The sum of first 45 natural numbers is: | {
"A": "1035",
"B": "1040",
"C": "1042",
"D": "1045",
"E": "1050"
} | divide(multiply(45, add(45, const_1)), const_2) | add(n0,const_1)|multiply(n0,#0)|divide(#1,const_2)| | "let sn = ( 1 + 2 + 3 + . . . + 45 ) . this is an a . p . in which a = 1 , d = 1 , n = 45 . sn = n [ 2 a + ( n - 1 ) d ] = 45 x [ 2 x 1 + ( 45 - 1 ) x 1 ] = 45 x 46 = ( 45 x 23 ) 2 2 2 = 45 x ( 20 + 3 ) = 45 x 20 + 45 x 3 = 900 + 135 = 1035 . shorcut method : sn = n ( n + 1 ) = 45 ( 45 + 1 ) = 1035 . 2 2 a" | general |
math_qa__IC0prca1mFuPW4w1 | If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 226 m, what is its area? Select:
A) 2510 B) 2535 C) 3060 D) 2515 E) 2520 | <gadget id="calculator">2 * 23</gadget>
<output>46</output>
<gadget id="calculator">226 - 46</gadget>
<output>180</output>
<gadget id="calculator">180 / 4</gadget>
<output>45</output>
<gadget id="calculator">45 + 23</gadget>
<output>68</output>
<gadget id="calculator">68 * 45</gadget>
<output>3_060</output>
<result>C</result> | C | 3,060 | If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 226 m, what is its area? | {
"A": "2510",
"B": "2535",
"C": "3060",
"D": "2515",
"E": "2520"
} | rectangle_area(add(divide(subtract(226, multiply(const_2, 23)), const_4), 23), divide(subtract(226, multiply(const_2, 23)), const_4)) | multiply(n0,const_2)|subtract(n1,#0)|divide(#1,const_4)|add(n0,#2)|rectangle_area(#3,#2)| | "length = breadth + 23 . therefore , 4 × breadth + 2 × 23 = 226 m ⇒ breadth = 45 m length = 45 + 23 = 68 m area = 68 × 45 = 3060 m 2 answer is c ." | geometry |
math_qa__tQZNCNTFhEAQamsU | the total price of a basic computer and printer are $ 2500 . if the same printer had been purchased with an enhanced computer whose price was $ 500 more than the price of the basic computer , then the price of the printer would have been 1 / 6 of that total . what was the price of the basic computer ? Choose the correct choice from the following options.
A) 1500 B) 1600 C) 1750 D) 1900 E) 2000 | <gadget id="calculator">2_500 + 500</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 6</gadget>
<output>500</output>
<gadget id="calculator">2_500 - 500</gadget>
<output>2_000</output>
<result>E</result> | E | 2,000 | the total price of a basic computer and printer are $ 2500 . if the same printer had been purchased with an enhanced computer whose price was $ 500 more than the price of the basic computer , then the price of the printer would have been 1 / 6 of that total . what was the price of the basic computer ? | {
"A": "1500",
"B": "1600",
"C": "1750",
"D": "1900",
"E": "2000"
} | subtract(2500, divide(add(2500, 500), 6)) | add(n0,n1)|divide(#0,n3)|subtract(n0,#1) | let the price of basic computer be c and the price of the printer be p : c + p = $ 2,500 . the price of the enhanced computer will be c + 500 and total price for that computer and the printer will be 2,500 + 500 = $ 3,000 . now , we are told that the price of the printer is 1 / 6 of that new total price : p = 1 / 6 * $ 3,000 = $ 500 . plug this value in the first equation : c + 500 = $ 2,500 - - > c = $ 2000 answer : e . | general |
math_qa__EBzWMsZZPYX1dccg | Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companyís workforce consists of 25 percent managers, what percent of the workforce originated from Company A? Pick one: A) 10 % B) 20 % C) 25 % D) 50 % E) 75 % | <gadget id="calculator">60 / 30</gadget>
<output>2</output>
<gadget id="calculator">2 * 25</gadget>
<output>50</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<gadget id="calculator">5 + 90</gadget>
<output>95</output>
<gadget id="calculator">95 - 60</gadget>
<output>35</output>
<gadget id="calculator">35 - 10</gadget>
<output>25</output>
<result>C</result> | C | 25 | Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. The two companies merge, every employee stays with the resulting company, and no new employees are added. If the resulting companyís workforce consists of 25 percent managers, what percent of the workforce originated from Company A? | {
"A": "10 %",
"B": "20 %",
"C": "25 %",
"D": "50 %",
"E": "75 %"
} | subtract(subtract(add(divide(multiply(divide(60, 30), 25), 10), 90), 60), 10) | divide(n4,n2)|multiply(n5,#0)|divide(#1,n0)|add(n1,#2)|subtract(#3,n4)|subtract(#4,n0) | let say company a has x employes and b has y employees . now they merge and total no of employees = x + y employees . per the question company a ' s workforce consists of 10 percent managers and 90 percent software engineers . company b ' s workforce consists of 30 percent managers , 10 percent software engineers , and 60 percent support staff . we translate it into equation as follows : . 1 x + . 3 y = . 25 ( x + y ) = > x + 3 y = 2.5 ( x + y ) = > . 5 y = 1.5 x = > y = 3 x . now we know total employee = x + y . we need to find % age of x in total ( x + y ) ie x / ( x + y ) x 100 % = > x / ( 3 x + x ) [ substitute y = 3 x ] = > x / 4 x x 100 % = > . 25 x 100 % = > 25 % . answer : c | general |
math_qa__dsycWWVVmGf0Q6WC | If X is invested in a bank at a rate of simple interest of y% p.a. for two years, then the interest earned is 300. if X is invested at y% p.a., for two years when the interest is compounded annually, the interest is 307.50. What is the value of X? Choose the correct choice from the following answers
A) 8000
B) 6000
C) 5000
D) 4000
E) 3000 | <gadget id="calculator">300 / 2</gadget>
<output>150</output>
<gadget id="calculator">150 ** 2</gadget>
<output>22_500</output>
<gadget id="calculator">307.5 - 300</gadget>
<output>7.5</output>
<gadget id="calculator">22_500 / 7.5</gadget>
<output>3_000</output>
<result>E</result> | E | 3,000 | If X is invested in a bank at a rate of simple interest of y% p.a. for two years, then the interest earned is 300. if X is invested at y% p.a., for two years when the interest is compounded annually, the interest is 307.50. What is the value of X? | {
"A": "8000",
"B": "6000",
"C": "5000",
"D": "4000",
"E": "3000"
} | divide(power(divide(300, const_2), const_2), subtract(307.50, 300)) | divide(n0,const_2)|subtract(n1,n0)|power(#0,const_2)|divide(#2,#1)| | "simple way to solve this question is to use options . from si , we know that x * y = 15,000 . now , put the value of x = 3000 , we will have y = 5 % to calculate ci , now , we know 1 st year amount = 3000 + 5 % of 3000 = 3150 . 2 nd year , amount = 3150 + 5 % of 3150 = 3307.50 . we can see after 2 years interest = 3307.50 - 3000 = 307.50 . hence , it satisfies the question . hence e is the correct answer" | gain |
math_qa__3ELKIcE7MbFgVihC | A dress on sale in a shop is marked at $D. During the discount sale its price is reduced by 25%. Staff are allowed a further 20% reduction on the discounted price. If a staff member buys the dress what will she have to pay in terms of D ? Choose the correct choice:
A) 0.6 d B) 0.7 d C) 0.5 d D) 0.8 d E) 0.9 d | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/4) * (1/5)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/4) - (3/20)</gadget>
<output>3/5 = around 0.6</output>
<result>A</result> | A | 0.6 | A dress on sale in a shop is marked at $D. During the discount sale its price is reduced by 25%. Staff are allowed a further 20% reduction on the discounted price. If a staff member buys the dress what will she have to pay in terms of D ? | {
"A": "0.6 d",
"B": "0.7 d",
"C": "0.5 d",
"D": "0.8 d",
"E": "0.9 d"
} | subtract(divide(subtract(const_100, 25), const_100), multiply(divide(subtract(const_100, 25), const_100), divide(20, const_100))) | divide(n1,const_100)|subtract(const_100,n0)|divide(#1,const_100)|multiply(#2,#0)|subtract(#2,#3)| | "effective discount = a + b + ab / 100 = - 25 - 20 + ( - 25 ) ( - 20 ) / 100 = - 40 sale price = d * ( 1 - 40 / 100 ) sale price = . 6 * d answer ( a )" | gain |
math_qa__WyuDEsQ5wK46BDOn | What is the normal price of an article sold at $108 after two successive discounts of 10% and 20%? Select the correct option.
A) $ 130 B) $ 140 C) $ 150 D) $ 160 E) $ 170 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(9/10) * (4/5)</gadget>
<output>18/25 = around 0.72</output>
<gadget id="calculator">108 / (18/25)</gadget>
<output>150</output>
<result>C</result> | C | 150 | What is the normal price of an article sold at $108 after two successive discounts of 10% and 20%? | {
"A": "$ 130",
"B": "$ 140",
"C": "$ 150",
"D": "$ 160",
"E": "$ 170"
} | divide(108, multiply(divide(subtract(const_100, 10), const_100), divide(subtract(const_100, 20), const_100))) | subtract(const_100,n1)|subtract(const_100,n2)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|divide(n0,#4)| | "0.8 * 0.9 * cost price = $ 108 cost price = $ 150 the answer is c ." | gain |
math_qa__g2U9JHAK292y1y4m | Kim has 8 pairs of shoes; each pair is a different color. If Kim randomly selects 2 shoes without replacement from the 16 shoes, what is the probability that she will select 2 shoes of the same color? Pick one: A) 2 / 5 B) 1 / 5 C) 1 / 9 D) 1 / 10 E) 1 / 15 | <gadget id="calculator">binomial(16, 2)</gadget>
<output>120</output>
<gadget id="calculator">8 / 120</gadget>
<output>1/15 = around 0.066667</output>
<result>E</result> | E | 0.066667 | Kim has 8 pairs of shoes; each pair is a different color. If Kim randomly selects 2 shoes without replacement from the 16 shoes, what is the probability that she will select 2 shoes of the same color? | {
"A": "2 / 5",
"B": "1 / 5",
"C": "1 / 9",
"D": "1 / 10",
"E": "1 / 15"
} | divide(8, choose(16, 2)) | choose(n2,n1)|divide(n0,#0)| | "total pairs = 16 c 2 = 120 ; same color pairs = 8 c 1 * 1 c 1 = 8 ; prob = 1 / 15 ans e" | probability |
math_qa__9ZXQ1XgJz2MiMibV | There are 14 teams in a certain league and each team plays each of the other teams exactly once. What is the total number of games played? Pick: A) 91 B) 98 C) 105 D) 112 E) 119 | <gadget id="calculator">14 - 1</gadget>
<output>13</output>
<gadget id="calculator">14 * 13</gadget>
<output>182</output>
<gadget id="calculator">182 / 2</gadget>
<output>91</output>
<result>A</result> | A | 91 | There are 14 teams in a certain league and each team plays each of the other teams exactly once. What is the total number of games played? | {
"A": "91",
"B": "98",
"C": "105",
"D": "112",
"E": "119"
} | divide(multiply(14, subtract(14, const_1)), const_2) | subtract(n0,const_1)|multiply(n0,#0)|divide(#1,const_2)| | "14 c 2 = 91 the answer is a ." | general |
math_qa__vkfvVOLejFS5SIBe | A technology company made a $5 million profit on its first $15 million in sales and a $12 million profit on its next $30 million in sales. By what percent did the ratio of profit to sales increase from the first $15 million in sales to the next $30 million in sales? Choose the correct choice from the following options.
A) 10 %
B) 20 %
C) 30 %
D) 40 %
E) 50 % | <gadget id="calculator">12 / 30</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">5 / 15</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(2/5) - (1/3)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) / (1/3)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>B</result> | B | 20 | A technology company made a $5 million profit on its first $15 million in sales and a $12 million profit on its next $30 million in sales. By what percent did the ratio of profit to sales increase from the first $15 million in sales to the next $30 million in sales? | {
"A": "10 %",
"B": "20 %",
"C": "30 %",
"D": "40 %",
"E": "50 %"
} | multiply(divide(subtract(divide(12, 30), divide(5, 15)), divide(5, 15)), const_100) | divide(n2,n3)|divide(n0,n1)|subtract(#0,#1)|divide(#2,#1)|multiply(#3,const_100) | solution : this is a percent increase problem . we will use the formula : percent change = ( new – old ) / old x 100 to calculate the final answer . we first set up the ratios of profits to sales . the first ratio will be for the first 15 million in sales , and the second ratio will be for the next 30 million in sales . because all of the sales are in millions , we do not have to express all the trailing zeros in our ratios . first 15 million profit / sales = 5 / 15 = 1 / 3 next 30 million profit / sales = 12 / 30 = 2 / 5 we can simplify each ratio by multiplying each by the lcm of the two denominators , which is 15 . keep in mind that we are able to do this only because our answer choices are expressed in percents . first 15 million royalties / sales = ( 1 / 3 ) x 15 = 5 next 30 million royalties / sales = ( 2 / 5 ) x 15 = 6 we can plug 5 and 6 into our percent change formula : ( new – old ) / old x 100 [ ( 6 – 5 ) / 5 ] x 100 1 / 5 x 100 , so a 20 % increase . answer b . | other |
math_qa__tRaHawfZUXu49ySe | A number is doubled and 9 is added. If the resultant is trebled, it becomes 63. What is that number? Choose the correct choice from the following answers
A) 3.5 B) 6 C) 8 D) 7 E) 4 | <gadget id="calculator">3 * 9</gadget>
<output>27</output>
<gadget id="calculator">63 - 27</gadget>
<output>36</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">36 / 6</gadget>
<output>6</output>
<result>B</result> | B | 6 | A number is doubled and 9 is added. If the resultant is trebled, it becomes 63. What is that number? | {
"A": "3.5",
"B": "6",
"C": "8",
"D": "7",
"E": "4"
} | divide(subtract(63, multiply(const_3, 9)), multiply(const_3, const_2)) | multiply(n0,const_3)|multiply(const_2,const_3)|subtract(n1,#0)|divide(#2,#1)| | "let the number be x . then , 3 ( 2 x + 9 ) = 63 2 x = 12 = > x = 6 answer : b" | general |
math_qa__gwwYo1FCIjbhinh8 | A cab driver 5days income was $300, $150, $750, $400 , $500. Then his average income is? Options: A) $ 500 B) $ 650 C) $ 420 D) $ 375 E) $ 625 | <gadget id="calculator">300 + 150</gadget>
<output>450</output>
<gadget id="calculator">450 + 750</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 + 400</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 + 500</gadget>
<output>2_100</output>
<gadget id="calculator">2_100 / 5</gadget>
<output>420</output>
<result>C</result> | C | 420 | A cab driver 5days income was $300, $150, $750, $400 , $500. Then his average income is? | {
"A": "$ 500",
"B": "$ 650",
"C": "$ 420",
"D": "$ 375",
"E": "$ 625"
} | divide(add(add(add(add(300, 150), 750), 400), 500), 5) | add(n1,n2)|add(n3,#0)|add(n4,#1)|add(n5,#2)|divide(#3,n0)| | "avg = sum of observations / number of observations avg income = ( 300 + 150 + 750 + 400 + 500 ) / 5 = 420 answer is c" | general |
math_qa__5tpkXfSI7cKobhOb | if 12401 is divided by any no. then quotient is 76 and remainder is 13.what is divisor? Choose the correct choice from the following answers
A) 154 B) 124 C) 153 D) 163 E) 183 | <gadget id="calculator">12_401 - 13</gadget>
<output>12_388</output>
<gadget id="calculator">12_388 / 76</gadget>
<output>163</output>
<result>D</result> | D | 163 | if 12401 is divided by any no. then quotient is 76 and remainder is 13.what is divisor? | {
"A": "154",
"B": "124",
"C": "153",
"D": "163",
"E": "183"
} | divide(subtract(12401, 13), 76) | subtract(n0,n2)|divide(#0,n1) | divisor = ( dividend - remainder ) / quotient = ( 12401 - 13 ) / 76 = 12388 / 76 = 163 divisor = 163 answer d | general |
math_qa__pNuMfgl8K1jly4uG | In a games hour 4 different types of players came to the ground? cricket 12, hokey 17, football 11, softball 10. How many players are present in the ground? Choose the correct choice from the following answers:
A) 70
B) 50
C) 62
D) 49
E) 50 | <gadget id="calculator">12 + 17</gadget>
<output>29</output>
<gadget id="calculator">11 + 10</gadget>
<output>21</output>
<gadget id="calculator">29 + 21</gadget>
<output>50</output>
<result>B</result> | B | 50 | In a games hour 4 different types of players came to the ground? cricket 12, hokey 17, football 11, softball 10. How many players are present in the ground? | {
"A": "70",
"B": "50",
"C": "62",
"D": "49",
"E": "50"
} | add(add(12, 17), add(11, 10)) | add(n1,n2)|add(n3,n4)|add(#0,#1)| | "total number of players = 12 + 17 + 11 + 10 = 50 answer is b" | physics |
math_qa__5xdVKWGlTq2X6o8k | A trader sells 40 metres of cloth for Rs.8200 at a profit of Rs.55 per metre of cloth. How much profit will the trder earn on 40 metres of cloth? Choose the correct choice from the following:
A) rs . 950 B) rs . 1500 C) rs . 1000 D) rs . 2200 E) none of these | <gadget id="calculator">55 * 40</gadget>
<output>2_200</output>
<result>D</result> | D | 2,200 | A trader sells 40 metres of cloth for Rs.8200 at a profit of Rs.55 per metre of cloth. How much profit will the trder earn on 40 metres of cloth? | {
"A": "rs . 950",
"B": "rs . 1500",
"C": "rs . 1000",
"D": "rs . 2200",
"E": "none of these"
} | multiply(55, 40) | multiply(n0,n2) | explanation : sp of 1 metre cloth = 8200 / 40 = rs . 205 . cp of 1 metre cloth = rs . 205 – 55 = rs . 150 cp on 40 metres = 150 x 40 = rs . 6000 profit earned on 40 metres cloth = rs . 8200 – rs . 6000 = rs . 2200 . answer : option d | gain |
math_qa__FWdAP19DxEU9PJuD | In a neighborhood having 90 households, 11 did not have either a car or a bike. If 20 households had a both a car and a bike and 44 had a car, how many had bike only? Pick one
A) 30 B) 35 C) 20 D) 18 E) 10 | <gadget id="calculator">90 - 11</gadget>
<output>79</output>
<gadget id="calculator">79 + 20</gadget>
<output>99</output>
<gadget id="calculator">99 - 44</gadget>
<output>55</output>
<gadget id="calculator">55 - 20</gadget>
<output>35</output>
<result>B</result> | B | 35 | In a neighborhood having 90 households, 11 did not have either a car or a bike. If 20 households had a both a car and a bike and 44 had a car, how many had bike only? | {
"A": "30",
"B": "35",
"C": "20",
"D": "18",
"E": "10"
} | subtract(subtract(add(subtract(90, 11), 20), 44), 20) | subtract(n0,n1)|add(n2,#0)|subtract(#1,n3)|subtract(#2,n2)| | "{ total } = { car } + { bike } - { both } + { neither } - - > 90 = 44 + { bike } - 20 + 11 - - > { bike } = 55 - - > # those who have bike only is { bike } - { both } = 55 - 20 = 35 . answer : b ." | other |
math_qa__8zg0LoAVormEnsZ5 | 75 persons Major in physics, 83 major in chemistry, 10 not at major in these subjects u want to find number of students majoring in both subjects Choose the correct option
A) 65 B) 66 C) 67 D) 68 E) 69 | <gadget id="calculator">75 + 83</gadget>
<output>158</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">158 - 90</gadget>
<output>68</output>
<result>D</result> | D | 68 | 75 persons Major in physics, 83 major in chemistry, 10 not at major in these subjects u want to find number of students majoring in both subjects | {
"A": "65",
"B": "66",
"C": "67",
"D": "68",
"E": "69"
} | subtract(add(75, 83), subtract(const_100, 10)) | add(n0,n1)|subtract(const_100,n2)|subtract(#0,#1) | consider the number of total students = n ( t ) = 100 number of persons major in physics = n ( p ) = 75 number of persons major in chemistry = n ( c ) = 83 according to the question ; 10 not at major in these subjects = n ( p ' ∩ c ' ) = 10 n ( p ' ∩ c ' ) = n ( p u c ) ' = 10 n ( p u c ) ' = n ( t ) - n ( p u c ) 10 = 100 - n ( p u c ) n ( p u c ) = 90 n ( p u c ) = n ( p ) + n ( c ) - n ( p ∩ c ) 90 = 75 + 83 - n ( p ∩ c ) n ( p ∩ c ) = 158 - 90 n ( p ∩ c ) = 68 number of students majoring in both subjects will be 68 answer : d | other |
math_qa__uj0YcSOM6zrSgfFd | Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 320 square feet. How many feet offence does Frank use? Choose the correct choice from the following answers: A) 14 B) 47 C) 54 D) 56 E) 240 | <gadget id="calculator">320 / 40</gadget>
<output>8</output>
<gadget id="calculator">8 + 8</gadget>
<output>16</output>
<gadget id="calculator">16 + 40</gadget>
<output>56</output>
<result>D</result> | D | 56 | Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 320 square feet. How many feet offence does Frank use? | {
"A": "14",
"B": "47",
"C": "54",
"D": "56",
"E": "240"
} | add(add(divide(320, 40), divide(320, 40)), 40) | divide(n1,n0)|add(#0,#0)|add(n0,#1)| | "area = length x breadth 320 = 40 x breadth so , breadth = 8 units fencing required is - breadth + breadth + length 8 + 8 + 40 = > 56 feet answer must be ( d ) 56" | geometry |
math_qa__yuIoPmhcxgrF2kv5 | Lagaan is levied on the 60 percent of the cultivated land. The revenue department collected total Rs. 3,54,000 through the lagaan from the village of Mutter. Mutter, a very rich farmer , paid only Rs.480 as lagaan. The percentage of total land of Mutter over the total taxable land of the village is: Choose the correct choice from the following choices
A) 0.22598
B) 0.14544
C) 0.25632
D) 0.35466
E) 0.63435 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">480 / (3/5)</gadget>
<output>800</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">300 * 1_000</gadget>
<output>300_000</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 + 4</gadget>
<output>44</output>
<gadget id="calculator">44 * 1_000</gadget>
<output>44_000</output>
<gadget id="calculator">300_000 + 44_000</gadget>
<output>344_000</output>
<gadget id="calculator">800 / 344_000</gadget>
<output>1/430 = around 0.002326</output>
<gadget id="calculator">(1/430) * 100</gadget>
<output>10/43 = around 0.232558</output>
<result>A</result> | A | 0.22598 | Lagaan is levied on the 60 percent of the cultivated land. The revenue department collected total Rs. 3,54,000 through the lagaan from the village of Mutter. Mutter, a very rich farmer , paid only Rs.480 as lagaan. The percentage of total land of Mutter over the total taxable land of the village is: | {
"A": "0.22598",
"B": "0.14544",
"C": "0.25632",
"D": "0.35466",
"E": "0.63435"
} | multiply(divide(divide(480, divide(60, const_100)), add(multiply(multiply(3, const_100), const_1000), multiply(add(multiply(const_4, const_10), const_4), const_1000))), const_100) | divide(n0,const_100)|multiply(n1,const_100)|multiply(const_10,const_4)|add(#2,const_4)|divide(n3,#0)|multiply(#1,const_1000)|multiply(#3,const_1000)|add(#5,#6)|divide(#4,#7)|multiply(#8,const_100)| | "total land of sukhiya = \ inline \ frac { 480 x } { 0.6 } = 800 x \ therefore cultivated land of village = 354000 x \ therefore required percentage = \ inline \ frac { 800 x } { 354000 } \ times 100 = 0.22598 a" | general |
math_qa__Lum22GLB9rb1LE9F | If 15 students in a class average 70% on an exam and 10 students average 90% on the same exam, what is the average in percent for all 25 students?
Choose one
A) 78 % B) 79 % C) 80 % D) 81 % E) 82 % | <gadget id="calculator">15 * 70</gadget>
<output>1_050</output>
<gadget id="calculator">10 * 90</gadget>
<output>900</output>
<gadget id="calculator">1_050 + 900</gadget>
<output>1_950</output>
<gadget id="calculator">1_950 / 25</gadget>
<output>78</output>
<result>A</result> | A | 78 | If 15 students in a class average 70% on an exam and 10 students average 90% on the same exam, what is the average in percent for all 25 students? | {
"A": "78 %",
"B": "79 %",
"C": "80 %",
"D": "81 %",
"E": "82 %"
} | divide(add(multiply(15, 70), multiply(10, 90)), 25) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)|divide(#2,n4) | ( 15 * 70 + 10 * 90 ) / 25 = 78 % the answer is a . | general |
math_qa__TE7VtVnEFujDxbeb | The average (arithmetic mean) of all scores on a certain algebra test was 90. If the average of the 8 male students’ grades was 87, and the average of the female students’ grades was 92, how many female students took the test? Pick one:
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">90 * 8</gadget>
<output>720</output>
<gadget id="calculator">87 * 8</gadget>
<output>696</output>
<gadget id="calculator">720 - 696</gadget>
<output>24</output>
<gadget id="calculator">92 - 90</gadget>
<output>2</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<result>E</result> | E | 12 | The average (arithmetic mean) of all scores on a certain algebra test was 90. If the average of the 8 male students’ grades was 87, and the average of the female students’ grades was 92, how many female students took the test? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | divide(subtract(multiply(90, 8), multiply(87, 8)), subtract(92, 90)) | multiply(n0,n1)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)| | "total marks of male = m total marks of female = f number of males = 8 number of females = f given : ( m + f ) / ( 8 + f ) = 90 - - - - - - - - - - - - - 1 also given , m / 8 = 87 thus m = 696 - - - - - - - - - 2 also , f / f = 92 thus f = 92 f - - - - - - - - - 3 put 2 and 3 in 1 : we get ( 696 + 92 f ) / ( 8 + f ) = 90 solving this we get f = 12 answer : e" | general |
math_qa__0Pzm0Gu6rpCCWD25 | Ajith and Rana walk around a circular course 115 km in circumference, starting together from the same point. If they walk at speed of 4 and 5 kmph respectively, in the same direction, when will they meet ? Choose the correct choice from the following options:
A) after 20 hours
B) after 115 hours
C) after 115 minutes
D) after 20 minutes
E) after 30 minutes | <gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">115 * 1</gadget>
<output>115</output>
<result>B</result> | B | 115 | Ajith and Rana walk around a circular course 115 km in circumference, starting together from the same point. If they walk at speed of 4 and 5 kmph respectively, in the same direction, when will they meet ? | {
"A": "after 20 hours",
"B": "after 115 hours",
"C": "after 115 minutes",
"D": "after 20 minutes",
"E": "after 30 minutes"
} | multiply(115, subtract(5, 4)) | subtract(n2,n1)|multiply(n0,#0) | rana is the faster person . he gains 1 km in 1 hour . so rana will gain one complete round over ajith in 115 hours . i . e . they will meet after 115 hours . answer : b | physics |
math_qa__hSAaedLWF6Kuq757 | A car is purchased on hire-purchase. The cash price is $26 000 and the terms are a deposit of 10% of the price, then the balance to be paid off over 60 equal monthly installments. Interest is charged at 12% p.a. What is the monthly installment? Pick:
A) $ 603 B) $ 624 C) $ 625 D) $ 626 E) $ 627 | <gadget id="calculator">26 * 1_000</gadget>
<output>26_000</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">26_000 * (9/10)</gadget>
<output>23_400</output>
<gadget id="calculator">23_400 / 60</gadget>
<output>390</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) / 12</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/100) * 23_400</gadget>
<output>234</output>
<gadget id="calculator">390 + 234</gadget>
<output>624</output>
<result>B</result> | B | 624 | A car is purchased on hire-purchase. The cash price is $26 000 and the terms are a deposit of 10% of the price, then the balance to be paid off over 60 equal monthly installments. Interest is charged at 12% p.a. What is the monthly installment? | {
"A": "$ 603",
"B": "$ 624",
"C": "$ 625",
"D": "$ 626",
"E": "$ 627"
} | add(divide(multiply(multiply(26, const_1000), subtract(const_1, divide(10, const_100))), 60), multiply(divide(divide(12, const_100), 12), multiply(multiply(26, const_1000), subtract(const_1, divide(10, const_100))))) | divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_1000)|divide(#1,n4)|subtract(const_1,#0)|multiply(#2,#4)|divide(#5,n3)|multiply(#3,#5)|add(#6,#7)| | "explanation : cash price = $ 26 000 deposit = 10 % ã — $ 26 000 = $ 2600 loan amount = $ 26000 â ˆ ’ $ 2600 number of payments = 60 = $ 23400 i = p * r * t / 100 i = 14040 total amount = 23400 + 14040 = $ 37440 regular payment = total amount / number of payments = 624 answer : b" | gain |
math_qa__L2eyuJAQmm3z9HEg | A certain industrial loom weaves 0.129 meters of cloth every second. Approximately how many seconds will it take for the loom to weave 15 meters of cloth? Answers:
A) 114 B) 115 C) 116 D) 117 E) 118 | <gadget id="calculator">15 / 0.129</gadget>
<output>116.27907</output>
<result>C</result> | C | 116 | A certain industrial loom weaves 0.129 meters of cloth every second. Approximately how many seconds will it take for the loom to weave 15 meters of cloth? | {
"A": "114",
"B": "115",
"C": "116",
"D": "117",
"E": "118"
} | divide(15, 0.129) | divide(n1,n0)| | "let the required number of seconds be x more cloth , more time , ( direct proportion ) hence we can write as ( cloth ) 0.129 : 15 : : 1 : x = > 0.129 * x = 15 = > x = 15 / 0.129 = > x = 116 answer : c" | physics |
math_qa__8BqUkzqLZH8qtQmd | A number is selected at random from the first 30 natural numbers. What is the probability that the number is a multiple of either 2 or 19?
Select the correct option
A) 17 / 30 B) 2 / 5 C) 7 / 15 D) 8 / 15 E) 11 / 30 | <gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">floor(15)</gadget>
<output>15</output>
<gadget id="calculator">30 / 19</gadget>
<output>30/19 = around 1.578947</output>
<gadget id="calculator">15 + (30/19)</gadget>
<output>315/19 = around 16.578947</output>
<gadget id="calculator">(315/19) / 30</gadget>
<output>21/38 = around 0.552632</output>
<result>D</result> | D | 0.533333 | A number is selected at random from the first 30 natural numbers. What is the probability that the number is a multiple of either 2 or 19? | {
"A": "17 / 30",
"B": "2 / 5",
"C": "7 / 15",
"D": "8 / 15",
"E": "11 / 30"
} | divide(add(floor(divide(30, 2)), divide(30, 19)), 30) | divide(n0,n2)|divide(n0,n1)|floor(#1)|add(#0,#2)|divide(#3,n0)| | "number of multiples of 2 from 1 through 30 = 30 / 2 = 15 number of multiples of 19 from 1 through 30 = 30 / 19 = 1 number of multiples of 2 and 19 both from 1 through 30 = number of multiples of 19 * 2 ( = 38 ) = 0 total favourable cases = 15 + 1 - 0 = 16 probability = 16 / 30 = 8 / 15 answer : option d" | probability |
math_qa__tROMbSLehp98DhDo | The cash difference between the selling prices of an article at a profit of 6% and 8% is Rs 3. The ratio of two selling prices is Choose the correct choice: A) 51 : 52 B) 52 : 53 C) 53 : 54 D) 54 : 55 E) none of these | <gadget id="calculator">100 + 6</gadget>
<output>106</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">106 / 108</gadget>
<output>53/54 = around 0.981481</output>
<result>C</result> | C | 0.981481 | The cash difference between the selling prices of an article at a profit of 6% and 8% is Rs 3. The ratio of two selling prices is | {
"A": "51 : 52",
"B": "52 : 53",
"C": "53 : 54",
"D": "54 : 55",
"E": "none of these"
} | divide(add(const_100, 6), add(const_100, 8)) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)| | "explanation : let the cost price of article is rs . x required ratio = ( 106 % of x ) / ( 108 % of x ) = 106 / 108 = 53 / 54 = 53 : 54 . answer : c" | gain |
math_qa__8B5B1GrkfuzBboyK | Working simultaneously and independently at an identical constant rate, 30 machines of a certain type can produce a total of x units of product P in 3 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 5x units of product P in 10 days? Choose the correct option
A) 41 B) 44 C) 45 D) 47 E) 50 | <gadget id="calculator">30 * 5</gadget>
<output>150</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">150 * (3/10)</gadget>
<output>45</output>
<result>C</result> | C | 45 | Working simultaneously and independently at an identical constant rate, 30 machines of a certain type can produce a total of x units of product P in 3 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 5x units of product P in 10 days? | {
"A": "41",
"B": "44",
"C": "45",
"D": "47",
"E": "50"
} | multiply(multiply(30, 5), divide(3, 10)) | divide(n1,n3)|multiply(n0,n2)|multiply(#0,#1)| | "the rate of 30 machines is rate = job / time = x / 3 units per day - - > the rate of 1 machine 1 / 30 * ( x / 3 ) = x / 90 units per day ; now , again as { time } * { combined rate } = { job done } then 10 * ( m * x / 90 ) = 5 x - - > m = 45 . answer : c ." | general |
math_qa__fWoSOTLTMZxPjHae | 30 men shake hands with each other. Maximum no of handshakes without cyclic handshakes. Select: A) 190 B) 200 C) 210 D) 220 E) 435 | <gadget id="calculator">30 - 1</gadget>
<output>29</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">29 * 15</gadget>
<output>435</output>
<result>E</result> | E | 435 | 30 men shake hands with each other. Maximum no of handshakes without cyclic handshakes. | {
"A": "190",
"B": "200",
"C": "210",
"D": "220",
"E": "435"
} | multiply(subtract(30, const_1), divide(30, const_2)) | divide(n0,const_2)|subtract(n0,const_1)|multiply(#0,#1)| | "or , if there are n persons then no . of shakehands = nc 2 = 30 c 2 = 435 answer : e" | general |
math_qa__Jv5mq7kbu2RyHVI7 | A car traveled 448 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 6 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city? Pick one
A) 14
B) 18
C) 21
D) 22
E) 27 | <gadget id="calculator">448 - 336</gadget>
<output>112</output>
<gadget id="calculator">112 / 6</gadget>
<output>56/3 = around 18.666667</output>
<gadget id="calculator">336 / (56/3)</gadget>
<output>18</output>
<result>B</result> | B | 18 | A car traveled 448 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 6 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city? | {
"A": "14",
"B": "18",
"C": "21",
"D": "22",
"E": "27"
} | divide(336, divide(subtract(448, 336), 6)) | subtract(n0,n1)|divide(#0,n2)|divide(n1,#1)| | "let the speed in highway be h mpg and in city be c mpg . h = c + 6 h miles are covered in 1 gallon 462 miles will be covered in 462 / h . similarly c miles are covered in 1 gallon 336 miles will be covered in 336 / c . both should be same ( as car ' s fuel capacity does not change with speed ) = > 336 / c = 448 / h = > 336 / c = 448 / ( c + 6 ) = > 336 c + 336 * 6 = 448 c = > c = 336 * 6 / 112 = 18 answer b ." | physics |
math_qa__Q6SCyt7dcIiCdQJG | At what rate percent on simple interest will Rs.750 amount to Rs.950 in 5 years? Answers.
A) 3.33 % B) 5.93 % C) 4.33 % D) 5.33 % E) 6.33 % | <gadget id="calculator">950 - 750</gadget>
<output>200</output>
<gadget id="calculator">200 / 750</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">(4/15) / 5</gadget>
<output>4/75 = around 0.053333</output>
<gadget id="calculator">(4/75) * 100</gadget>
<output>16/3 = around 5.333333</output>
<result>D</result> | D | 5.33 | At what rate percent on simple interest will Rs.750 amount to Rs.950 in 5 years? | {
"A": "3.33 %",
"B": "5.93 %",
"C": "4.33 %",
"D": "5.33 %",
"E": "6.33 %"
} | multiply(divide(divide(subtract(950, 750), 750), 5), const_100) | subtract(n1,n0)|divide(#0,n0)|divide(#1,n2)|multiply(#2,const_100)| | "200 = ( 750 * 5 * r ) / 100 r = 5.33 % answer : d" | gain |
math_qa__63XXHIKjhH8UF7dy | From the sale of sleeping bags, a retailer made a gross profit of 15% of the wholesale cost. If each sleeping bag was sold for $28, what was the wholesale cost per bag?
Choose the correct choice:
A) 3.0 B) 3.36 C) 24.34 D) 25.0 E) 31.36 | <gadget id="calculator">28 * 100</gadget>
<output>2_800</output>
<gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">2_800 / 115</gadget>
<output>560/23 = around 24.347826</output>
<result>C</result> | C | 24.34 | From the sale of sleeping bags, a retailer made a gross profit of 15% of the wholesale cost. If each sleeping bag was sold for $28, what was the wholesale cost per bag? | {
"A": "3.0",
"B": "3.36",
"C": "24.34",
"D": "25.0",
"E": "31.36"
} | divide(multiply(28, const_100), add(const_100, 15)) | add(n0,const_100)|multiply(n1,const_100)|divide(#1,#0)| | "cost price * 1.15 = selling price - - > cost price * 1.15 = $ 28 - - > cost price = $ 24.34 . answer : c ." | gain |
math_qa__VzZOWq5mcuhP63nT | Sara bought both German chocolate and Swiss chocolate for some cakes she was baking. The Swiss chocolate cost $3.5 per pound, and German chocolate cost $2.5 per pound. if the total the she spent on chocolate was $70 and both types of chocolate were purchased in whole number of pounds, how many total pounds of chocolate she purchased? Select.
A) 7
B) 8
C) 10
D) 24
E) 15 | <gadget id="calculator">3.5 + 2.5</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">70 / 3</gadget>
<output>70/3 = around 23.333333</output>
<result>D</result> | D | 24 | Sara bought both German chocolate and Swiss chocolate for some cakes she was baking. The Swiss chocolate cost $3.5 per pound, and German chocolate cost $2.5 per pound. if the total the she spent on chocolate was $70 and both types of chocolate were purchased in whole number of pounds, how many total pounds of chocolate she purchased? | {
"A": "7",
"B": "8",
"C": "10",
"D": "24",
"E": "15"
} | divide(70, divide(add(3.5, 2.5), const_2)) | add(n0,n1)|divide(#0,const_2)|divide(n2,#1) | if there were all the expensive ones , 3.5 . . . . there would be 70 / 3.5 or 20 of them but since 2.5 $ ones are also there , answer has to be > 20 . . . . if all were 2.5 $ ones , there will be 70 / 2.5 or 28 . . so only 24 is left ans d . . | other |
math_qa__TOXfJTduRPKNxjmz | Two men start from opposite banks of a river . They meet 340 meters away from one of the banks on forward journey. After that they meet at 170 meters from the other bank of the river on their backward journey. What will be the width of the river (in meters)? Choose the correct choice from the following options: A) 750 B) 850 C) 900 D) 980 E) 950 | <gadget id="calculator">340 + 170</gadget>
<output>510</output>
<gadget id="calculator">510 + 170</gadget>
<output>680</output>
<gadget id="calculator">680 + 170</gadget>
<output>850</output>
<result>B</result> | B | 850 | Two men start from opposite banks of a river . They meet 340 meters away from one of the banks on forward journey. After that they meet at 170 meters from the other bank of the river on their backward journey. What will be the width of the river (in meters)? | {
"A": "750",
"B": "850",
"C": "900",
"D": "980",
"E": "950"
} | add(add(add(340, 170), 170), 170) | add(n0,n1)|add(n1,#0)|add(n1,#1) | let p , q are two persons then their speeds be a , b - > m / hr x - - - - 340 - - - - - - - - - - - - - - - - - - - - - - | - - - ( d - 340 ) - - - - - - - - - y in forward journey time taken by p = 340 / a ; time taken by q = d - 340 / b ; in forward journey , time taken by p = time taken by q so 340 / a = d - 340 / b a / b = 340 / d - 340 - - - - - - - - - - - - ( 1 ) after that they continue their journeyand reach other banks now in backward journey , x - - - - - - - - - - - - - - - ( d - 170 ) - - - - - - - - - - - - - - - - - - - - - - - - - - | - - - - - 170 - - - - - - y distance travelled by p from meet 1 to meet 2 = ( d - 340 ) + 170 distance travelled by p from meet 1 to meet 2 = 340 + ( d - 170 ) now time taken by p = time taken by q ( d - 340 ) + 170 / a = 340 + ( d - 170 ) / b ( d - 340 ) + 170 / 340 + ( d - 170 ) = a / b - - - - - - - - - ( 2 ) from 1 & 2 340 / ( d - 340 ) = ( d - 340 ) + 170 / 340 + ( d - 170 ) 340 / ( d - 340 ) = d - 170 / d + 170 340 d + 57800 = d ^ 2 - 340 d - 170 d + 57800 340 d = d ^ 2 - 510 d d ^ 2 - 850 d = 0 d ( d - 850 ) = 0 d = 0 ord = 850 so width of the river is 850 answer : b | physics |
math_qa__lNIzwn53onYj1phq | If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 34 is subtracted and divided by 10? Answers:
A) 4
B) 7
C) 8
D) 2
E) 3 | <gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">49 + 5</gadget>
<output>54</output>
<gadget id="calculator">54 - 34</gadget>
<output>20</output>
<gadget id="calculator">20 / 10</gadget>
<output>2</output>
<result>D</result> | D | 2 | If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 34 is subtracted and divided by 10? | {
"A": "4",
"B": "7",
"C": "8",
"D": "2",
"E": "3"
} | divide(subtract(add(multiply(7, 7), 5), 34), 10) | multiply(n1,n1)|add(n0,#0)|subtract(#1,n3)|divide(#2,n4)| | "explanation : let the number be x . then , ( x - 5 ) / 7 = 7 = > x - 5 = 49 x = 54 . : ( x - 34 ) / 10 = ( 54 - 34 ) / 10 = 2 answer : option d" | general |
math_qa__inQFtjBrO0PbA6qP | The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs. ) is? Choose the correct choice:
A) 625 B) 827 C) 657 D) 726 E) 634 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) ** 2</gadget>
<output>1/625 = around 0.0016</output>
<gadget id="calculator">(1/625) * 1</gadget>
<output>1/625 = around 0.0016</output>
<gadget id="calculator">1 / (1/625)</gadget>
<output>625</output>
<result>A</result> | A | 625 | The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs. ) is? | {
"A": "625",
"B": "827",
"C": "657",
"D": "726",
"E": "634"
} | inverse(multiply(power(divide(4, const_100), 2), 1)) | divide(n1,const_100)|power(#0,n0)|multiply(n2,#1)|inverse(#2)| | "let the sum be rs . x . then , [ x ( 1 + 4 / 100 ) 2 - x ] = ( 676 / 625 x - x ) = 51 / 625 x s . i . = ( x * 4 * 2 ) / 100 = 2 x / 25 51 x / 625 - 2 x / 25 = 1 or x = 625 . answer : a" | gain |
math_qa__lac1kb9vNwk2C6JM | How many pieces of 0.85 metres can be cut from a rod 42.5 metres long? Choose the correct choice from the following choices.
A) 30 B) 40 C) 50 D) 60 E) 70 | <gadget id="calculator">42.5 / 0.85</gadget>
<output>50</output>
<result>C</result> | C | 50 | How many pieces of 0.85 metres can be cut from a rod 42.5 metres long? | {
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "70"
} | divide(42.5, 0.85) | divide(n1,n0)| | "number of pieces = 42.5 / 0.85 = 42.50 / 0.85 = 4250 / 85 = 50 . answer : c" | physics |
math_qa__NzY1j1dkMsH54ZdX | Cole drove from home to work at an average speed of 75 kmh. He then returned home at an average speed of 105 kmh. If the round trip took a total of 1 hours, how many minutes did it take Cole to drive to work? Choose the correct choice from the following answers.
A) 35 B) 50 C) 62 D) 75 E) 78 | <gadget id="calculator">105 * 1</gadget>
<output>105</output>
<gadget id="calculator">75 + 105</gadget>
<output>180</output>
<gadget id="calculator">105 / 180</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">(7/12) * 60</gadget>
<output>35</output>
<result>A</result> | A | 35 | Cole drove from home to work at an average speed of 75 kmh. He then returned home at an average speed of 105 kmh. If the round trip took a total of 1 hours, how many minutes did it take Cole to drive to work? | {
"A": "35",
"B": "50",
"C": "62",
"D": "75",
"E": "78"
} | multiply(divide(multiply(105, 1), add(75, 105)), const_60) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)|multiply(#2,const_60)| | "first round distance travelled ( say ) = d speed = 75 k / h time taken , t 2 = d / 75 hr second round distance traveled = d ( same distance ) speed = 105 k / h time taken , t 2 = d / 105 hr total time taken = 1 hrs therefore , 1 = d / 75 + d / 105 lcm of 75 and 105 = 525 1 = d / 75 + d / 105 = > 1 = 7 d / 525 + 5 d / 525 = > d = 525 / 12 km therefore , t 1 = d / 75 = > t 1 = 525 / ( 12 x 75 ) = > t 1 = ( 7 x 60 ) / 12 - - in minutes = > t 1 = 35 minutes . a" | physics |
math_qa__XaNkVt81ShakNKkl | Sum of the squares of 3 no.'s is 179 and the sum of their products taken two at a time is 131. Find the sum? Choices: A) 20 B) 21 C) 26 D) 28 E) 30 | <gadget id="calculator">131 * 2</gadget>
<output>262</output>
<gadget id="calculator">262 + 179</gadget>
<output>441</output>
<gadget id="calculator">441 ** (1/2)</gadget>
<output>21</output>
<result>B</result> | B | 21 | Sum of the squares of 3 no.'s is 179 and the sum of their products taken two at a time is 131. Find the sum? | {
"A": "20",
"B": "21",
"C": "26",
"D": "28",
"E": "30"
} | sqrt(add(multiply(131, const_2), 179)) | multiply(n2,const_2)|add(n1,#0)|sqrt(#1)| | "( a + b + c ) 2 = a 2 + b 2 + c 2 + 2 ( ab + bc + ca ) = 179 + 2 * 131 a + b + c = √ 441 = 21 b" | general |
math_qa__nBcv3ZvMlXCVxQGq | If 20% of 30 is greater than 25% of a number by 2, the number is:
Pick:
A) 16
B) 24
C) 20
D) 32
E) none of these | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 30</gadget>
<output>6</output>
<gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">4 / (1/4)</gadget>
<output>16</output>
<result>A</result> | A | 16 | If 20% of 30 is greater than 25% of a number by 2, the number is: | {
"A": "16",
"B": "24",
"C": "20",
"D": "32",
"E": "none of these"
} | divide(subtract(multiply(divide(20, const_100), 30), 2), divide(25, const_100)) | divide(n0,const_100)|divide(n2,const_100)|multiply(n1,#0)|subtract(#2,n3)|divide(#3,#1) | explanation : = > 20 / 100 * 30 - 25 / 100 * x = 2 = > x / 4 = 4 so x = 16 answer : a | gain |
math_qa__nhls2Ah8gObiuHvS | Suzie’s Discount Footwear sells all pairs of shoes for one price and all pairs of boots for another price. On Monday the store sold 22 pairs of shoes and 16 pairs of boots for $460. On Tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $560. How much more do pairs of boots cost than pairs of shoes at Suzie’s Discount Footwear? Choose the correct choice from the following answers.
A) 15 B) 18 C) 21 D) 23 E) 25 | <gadget id="calculator">460 * 2</gadget>
<output>920</output>
<gadget id="calculator">920 - 560</gadget>
<output>360</output>
<gadget id="calculator">22 * 2</gadget>
<output>44</output>
<gadget id="calculator">44 - 8</gadget>
<output>36</output>
<gadget id="calculator">360 / 36</gadget>
<output>10</output>
<gadget id="calculator">22 * 10</gadget>
<output>220</output>
<gadget id="calculator">460 - 220</gadget>
<output>240</output>
<gadget id="calculator">240 / 16</gadget>
<output>15</output>
<result>A</result> | A | 15 | Suzie’s Discount Footwear sells all pairs of shoes for one price and all pairs of boots for another price. On Monday the store sold 22 pairs of shoes and 16 pairs of boots for $460. On Tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $560. How much more do pairs of boots cost than pairs of shoes at Suzie’s Discount Footwear? | {
"A": "15",
"B": "18",
"C": "21",
"D": "23",
"E": "25"
} | divide(subtract(460, multiply(22, divide(subtract(multiply(460, const_2), 560), subtract(multiply(22, const_2), 8)))), 16) | multiply(n2,const_2)|multiply(n0,const_2)|subtract(#0,n5)|subtract(#1,n3)|divide(#2,#3)|multiply(n0,#4)|subtract(n2,#5)|divide(#6,n1) | let x be pair of shoes and y be pair of boots . 22 x + 16 y = 460 . . . eq 1 8 x + 32 y = 560 . . . . eq 2 . now multiply eq 1 by 2 and sub eq 2 . 44 x = 920 8 x = 560 . 36 x = 360 = > x = 10 . sub x in eq 2 . . . . we get 80 + 32 y = 560 . . . then we get 32 y = 480 then y = 25 differenece between x and y is 15 answer : a | general |
math_qa__TGZdOntqx80mHDNw | If (A+B) = 4, (B+C) = 9 and (C+D) = 3, what is the value of (A+D)?
Choose the correct choice: A) 16 . B) 8 . C) 7 D) 2 . E) - 2 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 - 9</gadget>
<output>-2</output>
<result>E</result> | E | -2 | If (A+B) = 4, (B+C) = 9 and (C+D) = 3, what is the value of (A+D)? | {
"A": "16 .",
"B": "8 .",
"C": "7",
"D": "2 .",
"E": "- 2"
} | subtract(add(4, 3), 9) | add(n0,n2)|subtract(#0,n1)| | "given a + b = 4 = > a = 4 - b - - > eq 1 b + c = 9 c + d = 3 = > d = 3 - c - - > eq 2 then eqs 1 + 2 = > a + d = 4 - b + 3 - c = > 7 - ( b + c ) = > 7 - 9 = - 2 . option e . . ." | general |
math_qa__JS6hTqYZB6PfzDs2 | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B? Pick
A) 11 years B) 10 years C) 18 years D) 189 years E) 28 years | <gadget id="calculator">27 - 2</gadget>
<output>25</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">50 / 5</gadget>
<output>10</output>
<result>B</result> | B | 10 | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B? | {
"A": "11 years",
"B": "10 years",
"C": "18 years",
"D": "189 years",
"E": "28 years"
} | divide(multiply(subtract(27, const_2), const_2), add(const_4, const_1)) | add(const_1,const_4)|subtract(n0,const_2)|multiply(#1,const_2)|divide(#2,#0)| | "let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 27 5 x = 25 = > x = 5 hence , b ' s age = 2 x = 10 years . answer : b" | general |
math_qa__f6SDBEPyemH0K55t | There are 225 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers. Answers:
A) 300
B) 400
C) 562.5
D) 600
E) none of these | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">225 / (2/5)</gadget>
<output>1_125/2 = around 562.5</output>
<result>C</result> | C | 562.5 | There are 225 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers. | {
"A": "300",
"B": "400",
"C": "562.5",
"D": "600",
"E": "none of these"
} | divide(225, divide(2, 5)) | divide(n1,n2)|divide(n0,#0)| | as per question stem 2 / 5 m ( portion of men employees who are managers ) + 225 ( portion of female employees who are managers ) = 2 / 5 t ( portion of total number of employees who are managers ) , thus we get that 2 / 5 m + 225 = 2 / 5 t , or 2 / 5 ( t - m ) = 225 , from here we get that t - m = 562.5 , that would be total number of female employees and the answer ( c ) | general |
math_qa__r8KfNUnJUBAE1GA4 | the cost of manufacturing a popular model car is made up of 3 items : cost of raw material , labour and overheads - in a year the cost of 3 items were in the ration of 4 : 3 : 2 . next year the cost of the raw material rose by 10 % , labour cost increased by 8 % but overhead reduced by 5 % . then % increase int the price of the car ? Choose the correct choice from the following choices.
A) 7.67 %
B) 6 %
C) 0.54 %
D) 9.54 %
E) 8.54 % | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">(4/9) * 110</gadget>
<output>440/9 = around 48.888889</output>
<gadget id="calculator">3 / 9</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">(1/3) * 108</gadget>
<output>36</output>
<gadget id="calculator">(440/9) + 36</gadget>
<output>764/9 = around 84.888889</output>
<gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">(2/9) * 95</gadget>
<output>190/9 = around 21.111111</output>
<gadget id="calculator">(764/9) + (190/9)</gadget>
<output>106</output>
<gadget id="calculator">106 - 100</gadget>
<output>6</output>
<result>B</result> | B | 6 | the cost of manufacturing a popular model car is made up of 3 items : cost of raw material , labour and overheads - in a year the cost of 3 items were in the ration of 4 : 3 : 2 . next year the cost of the raw material rose by 10 % , labour cost increased by 8 % but overhead reduced by 5 % . then % increase int the price of the car ? | {
"A": "7.67 %",
"B": "6 %",
"C": "0.54 %",
"D": "9.54 %",
"E": "8.54 %"
} | subtract(add(add(multiply(divide(4, add(add(4, 3), 2)), add(const_100, 10)), multiply(divide(3, add(add(4, 3), 2)), add(const_100, 8))), multiply(divide(2, add(add(4, 3), 2)), subtract(const_100, 5))), const_100) | add(n5,const_100)|add(n0,n2)|add(n6,const_100)|subtract(const_100,n7)|add(n4,#1)|divide(n2,#4)|divide(n0,#4)|divide(n4,#4)|multiply(#0,#5)|multiply(#2,#6)|multiply(#7,#3)|add(#8,#9)|add(#11,#10)|subtract(#12,const_100) | before increase total cost = 4 + 3 + 2 = 9 , after increasing the cost = 9.54 so increase of . 54 over 9 , equal to 6 % answer : b | general |
math_qa__UoSIFTcqeWx2VJSS | Two trains A and B starting from two points and travelling in opposite directions, reach their destinations 9 hours and 4 hours respectively after meeting each other. If the train A travels at 90kmph, find the rate at which the train B runs. Choose the correct choice:
A) 40 B) 60 C) 135 D) 80 E) 100 | <gadget id="calculator">9 / 4</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">(9/4) ** (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">90 * (3/2)</gadget>
<output>135</output>
<result>C</result> | C | 135 | Two trains A and B starting from two points and travelling in opposite directions, reach their destinations 9 hours and 4 hours respectively after meeting each other. If the train A travels at 90kmph, find the rate at which the train B runs. | {
"A": "40",
"B": "60",
"C": "135",
"D": "80",
"E": "100"
} | multiply(90, sqrt(divide(9, 4))) | divide(n0,n1)|sqrt(#0)|multiply(n2,#1)| | "if two objects a and b start simultaneously from opposite points and , after meeting , reach their destinations in ‘ a ’ and ‘ b ’ hours respectively ( i . e . a takes ‘ a hrs ’ to travel from the meeting point to his destination and b takes ‘ b hrs ’ to travel from the meeting point to his destination ) , then the ratio of their speeds is given by : sa / sb = √ ( b / a ) i . e . ratio of speeds is given by the square root of the inverse ratio of time taken . sa / sb = √ ( 4 / 9 ) = 2 / 3 this gives us that the ratio of the speed of a : speed of b as 2 : 3 . since speed of a is 80 kmph , speed of b must be 80 * ( 3 / 2 ) = 135 kmph c" | physics |
math_qa__RO5lXatocquJeXSH | A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution? Select the correct option: A) 73.9 B) 72.9 C) 73.0 D) 73.5 E) 92.2 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">90 - 9</gadget>
<output>81</output>
<gadget id="calculator">81 / 90</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 9</gadget>
<output>81/10 = around 8.1</output>
<gadget id="calculator">81 - (81/10)</gadget>
<output>729/10 = around 72.9</output>
<result>B</result> | B | 72.9 | A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution? | {
"A": "73.9",
"B": "72.9",
"C": "73.0",
"D": "73.5",
"E": "92.2"
} | subtract(subtract(90, multiply(const_3, const_3)), multiply(divide(subtract(90, multiply(const_3, const_3)), 90), multiply(const_3, const_3))) | multiply(const_3,const_3)|subtract(n0,#0)|divide(#1,n0)|multiply(#2,#0)|subtract(#1,#3)| | "let the initial quantity of milk in vessel be t litres . let us say y litres of the mixture is taken out and replaced by water for n times , alternatively . quantity of milk finally in the vessel is then given by [ ( t - y ) / t ] n * t for the given problem , t = 90 , y = 9 and n = 2 . hence , quantity of milk finally in the vessel = [ ( 90 - 9 ) / 90 ] 2 ( 90 ) = 72.9 litres . answer : option b" | physics |
math_qa__dkiZ00B43jDix4b3 | 377 ÷ 13 ÷ 29 × 1/4 ÷ 2 = ? Choose the correct choice from the following options
A) 1 / 6 B) 1 / 8 C) 1 / 10 D) 1 / 12 E) 1 / 15 | <gadget id="calculator">377 / 13</gadget>
<output>29</output>
<gadget id="calculator">29 / 29</gadget>
<output>1</output>
<gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / 2</gadget>
<output>1/8 = around 0.125</output>
<result>B</result> | B | 0.125 | 377 ÷ 13 ÷ 29 × 1/4 ÷ 2 = ? | {
"A": "1 / 6",
"B": "1 / 8",
"C": "1 / 10",
"D": "1 / 12",
"E": "1 / 15"
} | divide(divide(multiply(divide(divide(377, 13), 29), 1), 4), 2) | divide(n0,n1)|divide(#0,n2)|multiply(n3,#1)|divide(#2,n4)|divide(#3,n5) | explanation : 377 ÷ 13 ÷ 29 × 1 / 4 ÷ 2 = ? = > ? = ( 337 / ( 13 × 29 × 4 × 2 ) ) = 1 / 8 answer : option b | general |
math_qa__rK9a5DoXkaE3PWN7 | If 11.25 m of a uniform steel rod weighs 42.75 kg. what will be the weight of 6 m of the same rod?
Choose the correct choice from the following choices.
A) 22.8 kg B) 25.6 kg C) 28 kg D) 26.5 kg E) none of these | <gadget id="calculator">6 * 42.75</gadget>
<output>256.5</output>
<gadget id="calculator">256.5 / 11.25</gadget>
<output>22.8</output>
<result>A</result> | A | 22.8 | If 11.25 m of a uniform steel rod weighs 42.75 kg. what will be the weight of 6 m of the same rod? | {
"A": "22.8 kg",
"B": "25.6 kg",
"C": "28 kg",
"D": "26.5 kg",
"E": "none of these"
} | divide(multiply(6, 42.75), 11.25) | multiply(n1,n2)|divide(#0,n0)| | "explanation : let the required weight be x kg . then , less length , less weight ( direct proportion ) = > 11.25 : 6 : : 42.75 : x = > 11.25 x x = 6 x 42.75 = > x = ( 6 x 42.75 ) / 11.25 = > x = 22.8 answer : a" | physics |
math_qa__42qYbJqivirTGUo8 | David obtained 70, 60, 78, 60 and 65 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ? Select the correct option.
A) 75 B) 27.6 C) 66.6 D) 16.5 E) 11 | <gadget id="calculator">70 + 60</gadget>
<output>130</output>
<gadget id="calculator">130 + 78</gadget>
<output>208</output>
<gadget id="calculator">208 + 60</gadget>
<output>268</output>
<gadget id="calculator">268 + 65</gadget>
<output>333</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">333 / 5</gadget>
<output>333/5 = around 66.6</output>
<result>C</result> | C | 66.6 | David obtained 70, 60, 78, 60 and 65 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ? | {
"A": "75",
"B": "27.6",
"C": "66.6",
"D": "16.5",
"E": "11"
} | divide(add(add(add(add(70, 60), 78), 60), 65), add(const_2, const_3)) | add(n0,n1)|add(const_2,const_3)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "explanation : average = ( 70 + 60 + 78 + 60 + 65 ) / 5 = 333 / 5 = 66.6 . answer : c" | general |
math_qa__AoUd5Is4Q0ILa3k9 | A car drives 60 miles on local roads at 30 mph, and 65 miles on the highway at 65 mph, what is the average speed of the entire trip?
Choose the correct answer
A) 36 mph B) 40 mph C) 44 mph D) 42 mph E) 58 mph | <gadget id="calculator">60 + 65</gadget>
<output>125</output>
<gadget id="calculator">60 / 30</gadget>
<output>2</output>
<gadget id="calculator">65 / 65</gadget>
<output>1</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">125 / 3</gadget>
<output>125/3 = around 41.666667</output>
<result>D</result> | D | 42 | A car drives 60 miles on local roads at 30 mph, and 65 miles on the highway at 65 mph, what is the average speed of the entire trip? | {
"A": "36 mph",
"B": "40 mph",
"C": "44 mph",
"D": "42 mph",
"E": "58 mph"
} | divide(add(60, 65), add(divide(60, 30), divide(65, 65))) | add(n0,n2)|divide(n0,n1)|divide(n2,n3)|add(#1,#2)|divide(#0,#3)| | "so the answer is plainly d . . . . we have a general relation for speed , time and distance : v ( velocity ) * t ( time ) = d ( distance ) for first part we have d = 60 miles , and v = 30 mph so we can obtain time : 30 * t = 60 or t = 60 / 30 = 2 hours the needed time to cover 60 miles in the same way we should divide 65 by 65 to find the needed time to cover 65 miles , so t = 1 hours so the total time for covering total distance would be 2 + 1 = 3 hours and total distance is 60 + 65 = 125 miles final stage : average speed is total distance divide to total time : 125 / 3 = 41.6 miles per hour that rounds up to 42 . . . ." | physics |
math_qa__8iomzTLX9O7mOxQI | The length of the bridge, which a train 120 metres long and travelling at 45 km/hr can cross in 30 seconds, is: Choose the correct choice from the following options
A) 230 B) 240 C) 245 D) 255 E) 260 | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 120</gadget>
<output>255</output>
<result>D</result> | D | 255 | The length of the bridge, which a train 120 metres long and travelling at 45 km/hr can cross in 30 seconds, is: | {
"A": "230",
"B": "240",
"C": "245",
"D": "255",
"E": "260"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 120) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "speed = [ 45 x 5 / 18 ] m / sec = [ 25 / 2 ] m / sec time = 30 sec let the length of bridge be x metres . then , ( 120 + x ) / 30 = 25 / 2 = > 2 ( 120 + x ) = 750 = > x = 255 m . answer : option d" | physics |
math_qa__TxHJvCTlaHXHk1MK | The floor of a rectangular room is 15 m long and 12 m wide. The room is surrounded by a verandah of width 2 m on all its sides. The area of the verandah is : Select the correct option:
A) 124 m 2 B) 120 m 2 C) 108 m 2 D) 58 m 2 E) none of these | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 15</gadget>
<output>19</output>
<gadget id="calculator">12 + 4</gadget>
<output>16</output>
<gadget id="calculator">19 * 16</gadget>
<output>304</output>
<gadget id="calculator">15 * 12</gadget>
<output>180</output>
<gadget id="calculator">304 - 180</gadget>
<output>124</output>
<result>A</result> | A | 124 | The floor of a rectangular room is 15 m long and 12 m wide. The room is surrounded by a verandah of width 2 m on all its sides. The area of the verandah is : | {
"A": "124 m 2",
"B": "120 m 2",
"C": "108 m 2",
"D": "58 m 2",
"E": "none of these"
} | subtract(rectangle_area(add(multiply(2, const_2), 15), add(12, multiply(2, const_2))), rectangle_area(15, 12)) | multiply(n2,const_2)|rectangle_area(n0,n1)|add(n0,#0)|add(n1,#0)|rectangle_area(#2,#3)|subtract(#4,#1) | area of the outer rectangle = 19 × 16 = 304 m 2 area of the inner rectangle = 15 × 12 = 180 m 2 required area = ( 304 – 180 ) = 124 m 2 answer a | geometry |
math_qa__XIZOuBOcZrbZiInK | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 6600. What is the share of B ?
Choose the correct choice from the following:
A) 1100
B) 800
C) 1400
D) 1200
E) none of them | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 3</gadget>
<output>2</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<gadget id="calculator">2 / 11</gadget>
<output>2/11 = around 0.181818</output>
<gadget id="calculator">6_600 * (2/11)</gadget>
<output>1_200</output>
<result>D</result> | D | 1,200 | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 6600. What is the share of B ? | {
"A": "1100",
"B": "800",
"C": "1400",
"D": "1200",
"E": "none of them"
} | multiply(6600, divide(const_2, add(add(multiply(const_2, 3), multiply(divide(const_2, 3), 3)), 3))) | divide(const_2,n0)|multiply(const_2,n0)|multiply(#0,n0)|add(#1,#2)|add(#3,n0)|divide(const_2,#4)|multiply(n1,#5)| | "let c ' s capital = rs . x . then , b ' s capital = rs . ( 2 / 3 ) x a ’ s capital = rs . ( 3 x ( 2 / 3 ) . x ) = rs . 2 x . ratio of their capitals = 2 x : ( 2 / 3 ) x : x = 6 : 2 : 3 . hence , b ' s share = rs . ( 6600 x ( 2 / 11 ) ) = rs . 1200 . answer is d ." | gain |
math_qa__MB3I1iAJrMucUHTE | A reduction of 40% in the price of apples would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?
Options: A) 1 B) 3 C) 6 D) 7 E) 10 | <gadget id="calculator">40 * 40</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 / 100</gadget>
<output>16</output>
<gadget id="calculator">16 / 64</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 12</gadget>
<output>3</output>
<result>B</result> | B | 3 | A reduction of 40% in the price of apples would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen? | {
"A": "1",
"B": "3",
"C": "6",
"D": "7",
"E": "10"
} | multiply(divide(divide(multiply(40, 40), const_100), 64), const_12) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)|multiply(#2,const_12)| | "b 40 * ( 40 / 100 ) = 16 - - - 64 ? - - - 12 = > rs . 3" | gain |
math_qa__E0XtJSu9MaPwwkCr | A, B, C, D and E are 5 consecutive points on a straight line. If BC = 3CD, DE = 7, AB = 5 and AC = 11, what is the length of AE? Choose the correct choice from the following answers
A) 18
B) 19
C) 20
D) 21
E) 22 | <gadget id="calculator">11 - 5</gadget>
<output>6</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">11 + 2</gadget>
<output>13</output>
<gadget id="calculator">13 + 7</gadget>
<output>20</output>
<result>C</result> | C | 20 | A, B, C, D and E are 5 consecutive points on a straight line. If BC = 3CD, DE = 7, AB = 5 and AC = 11, what is the length of AE? | {
"A": "18",
"B": "19",
"C": "20",
"D": "21",
"E": "22"
} | add(add(11, divide(subtract(11, 5), 3)), 7) | subtract(n4,n0)|divide(#0,n1)|add(n4,#1)|add(n2,#2) | ac = 11 and ab = 5 , so bc = 6 . bc = 3 cd so cd = 2 . the length of ae is ab + bc + cd + de = 5 + 6 + 2 + 7 = 20 the answer is c . | physics |
math_qa__nKPtquw3IiTjJFOs | If a: b :: 3 : 7, then what is (5a+6b): (a-4b)? Choose the correct choice from the following:
A) 57 : 11 B) - 57 : 11 C) 11 : 10 D) - 57 : 25 E) - 1 : 10 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">15 + 42</gadget>
<output>57</output>
<gadget id="calculator">4 * 7</gadget>
<output>28</output>
<gadget id="calculator">3 - 28</gadget>
<output>-25</output>
<gadget id="calculator">57 / (-25)</gadget>
<output>-57/25 = around -2.28</output>
<result>D</result> | D | -2.28 | If a: b :: 3 : 7, then what is (5a+6b): (a-4b)? | {
"A": "57 : 11",
"B": "- 57 : 11",
"C": "11 : 10",
"D": "- 57 : 25",
"E": "- 1 : 10"
} | divide(add(multiply(5, 3), multiply(7, 6)), subtract(3, multiply(4, 7))) | multiply(n0,n2)|multiply(n1,n3)|multiply(n1,n4)|add(#0,#1)|subtract(n0,#2)|divide(#3,#4)| | "a / b = 3 / 7 dividing numerator & denominator of ' ( 5 a + 6 b ) / ( a - 2 b ) ' by b , [ 5 ( a / b ) + 6 ] / [ ( a / b ) - 4 ] = [ 5 * ( 3 / 7 ) + 6 ] / [ ( 3 / 7 ) - 4 ] = - 57 / 25 answer : d" | general |
math_qa__7ajMhw6sqX5KxAs1 | of 3 numbers , the third is 4 times the second and the second is two times the first . if their average is 165 , the second number of the 3 numbers is :
Choices
A) 18 B) 100 C) 90 D) 45 E) 120 | <gadget id="calculator">3 * 165</gadget>
<output>495</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<gadget id="calculator">11 / 2</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">495 / (11/2)</gadget>
<output>90</output>
<result>C</result> | C | 90 | of 3 numbers , the third is 4 times the second and the second is two times the first . if their average is 165 , the second number of the 3 numbers is : | {
"A": "18",
"B": "100",
"C": "90",
"D": "45",
"E": "120"
} | divide(multiply(const_3, 165), divide(add(multiply(const_4, const_2), 3), const_2)) | multiply(n2,const_3)|multiply(const_2,const_4)|add(n0,#1)|divide(#2,const_2)|divide(#0,#3) | explanation : let first number be x . so , 2 nd no . = 2 x & 3 rd no . = 8 x . so , x + 2 x + 8 x = 165 × 3 = 495 11 x = 495 / 11 x = 495 / 11 hence , first number is x = 45 so , second number is = 2 x 45 = 90 answer : c | general |
math_qa__rAmreffHedaryBSu | The side of a rhombus is 20 m and length of one of its diagonals is 16 m. The area of the rhombus is?
Choose the correct choice from the following choices: A) 223.28 B) 293.28 C) 293.78 D) 291.28 E) 193.28 | <gadget id="calculator">2 * 20</gadget>
<output>40</output>
<gadget id="calculator">40 ** 2</gadget>
<output>1_600</output>
<gadget id="calculator">16 ** 2</gadget>
<output>256</output>
<gadget id="calculator">1_600 - 256</gadget>
<output>1_344</output>
<gadget id="calculator">1_344 ** (1/2)</gadget>
<output>8*sqrt(21) = around 36.660606</output>
<gadget id="calculator">16 * (8*sqrt(21))</gadget>
<output>128*sqrt(21) = around 586.569689</output>
<gadget id="calculator">(128*sqrt(21)) / 2</gadget>
<output>64*sqrt(21) = around 293.284844</output>
<result>B</result> | B | 293.28 | The side of a rhombus is 20 m and length of one of its diagonals is 16 m. The area of the rhombus is? | {
"A": "223.28",
"B": "293.28",
"C": "293.78",
"D": "291.28",
"E": "193.28"
} | divide(multiply(16, sqrt(subtract(power(multiply(const_2, 20), const_2), power(16, const_2)))), const_2) | multiply(n0,const_2)|power(n1,const_2)|power(#0,const_2)|subtract(#2,#1)|sqrt(#3)|multiply(n1,#4)|divide(#5,const_2)| | "area of the rhombus = 1 / 2 * p * √ 4 ( a ) 2 - ( p ) 2 a = 20 ; p = 16 a = 1 / 2 * 16 * √ 4 ( 20 ) 2 - ( 16 ) 2 = 1 / 2 * 16 * √ 1600 - 256 = 1 / 2 * 16 * √ 1344 a = 293.28 answer : b" | geometry |
math_qa__1pPG1HqSWQc3apS6 | In a certain company, a third of the workers do not have a retirement plan. 20% of the workers who do not have a retirement plan are women, and 50% of the workers who do have a retirement plan are men. If 120 of the workers of that company are men, how many of the workers are women?
Choose the correct choice from the following choices:
A) 80 B) 95 C) 105 D) 120 E) 210 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/3) * (1/5)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/3) - (1/15)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(2/3) * (1/2)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(4/15) + (1/3)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">120 / (3/5)</gadget>
<output>200</output>
<gadget id="calculator">(2/3) - (1/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/15) + (1/3)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">200 * (2/5)</gadget>
<output>80</output>
<result>A</result> | A | 80 | In a certain company, a third of the workers do not have a retirement plan. 20% of the workers who do not have a retirement plan are women, and 50% of the workers who do have a retirement plan are men. If 120 of the workers of that company are men, how many of the workers are women? | {
"A": "80",
"B": "95",
"C": "105",
"D": "120",
"E": "210"
} | multiply(divide(120, add(subtract(divide(const_1, const_3), multiply(divide(const_1, const_3), divide(20, const_100))), multiply(subtract(const_1, divide(const_1, const_3)), divide(50, const_100)))), add(multiply(divide(const_1, const_3), divide(20, const_100)), subtract(subtract(const_1, divide(const_1, const_3)), multiply(subtract(const_1, divide(const_1, const_3)), divide(50, const_100))))) | divide(const_1,const_3)|divide(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|subtract(const_1,#0)|multiply(#2,#4)|subtract(#0,#3)|add(#5,#6)|subtract(#4,#5)|add(#3,#8)|divide(n2,#7)|multiply(#9,#10)| | "20 % of the workerswithoutretirement plan are women , this means 80 % of the workerswithoutretirement plan are men right ? makes 100 % = no retirement plan . then 40 % of those wo have a retirement plan are men , which means 60 % of those who have a retirement plan are women . these percentages are always refering to the subgroupsretirement plan = yesandno retirement plan . make the total workers equal x and work from there and it should be fine > x / 3 have no retirement plan at all . i struggled with the question a lot , it was hard for me although usually i have no problems with sets questions like this . i believe it must be a 700 + question . yes , you are right . i read the question incorrectly ! i glazed overnotfor some reason . if 20 % of the workers who do not have a retirement plan are women , 80 % who do not have retirement plan are men . also 40 % who do have retirement plan are men . since 1 / 3 do not have retirement plan and 2 / 3 do have , it becomes a simple weighted average question . cavg = ( 80 * 1 + 50 * 2 ) / 3 = 60 % are men total = 120 * 100 / 60 = 200 no . of women = 200 - 120 = 80 a" | gain |
math_qa__q9UThaiWJ4AuvoW6 | How many seconds will a train 70 meters long take to cross a bridge 80 meters long if the speed of the train is 36 kmph? Options:
A) 22 sec B) 27 sec C) 25 sec D) 15 sec E) 11 sec | <gadget id="calculator">80 + 70</gadget>
<output>150</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">150 / 10</gadget>
<output>15</output>
<result>D</result> | D | 15 | How many seconds will a train 70 meters long take to cross a bridge 80 meters long if the speed of the train is 36 kmph? | {
"A": "22 sec",
"B": "27 sec",
"C": "25 sec",
"D": "15 sec",
"E": "11 sec"
} | divide(add(80, 70), multiply(36, const_0_2778)) | add(n0,n1)|multiply(n2,const_0_2778)|divide(#0,#1)| | "explanation : d = 70 + 80 = 150 s = 36 * 5 / 18 = 10 mps t = 150 / 10 = 15 sec answer : option d" | physics |
math_qa__r4iN7JQDouCLBI48 | How many unique positive odd integers less than 80 are equal to the product of a positive multiple of 5 and an odd number? Choose the correct option.
A) 4 B) 8 C) 11 D) 12 E) 15 | <gadget id="calculator">80 / 5</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>B</result> | B | 8 | How many unique positive odd integers less than 80 are equal to the product of a positive multiple of 5 and an odd number? | {
"A": "4",
"B": "8",
"C": "11",
"D": "12",
"E": "15"
} | divide(divide(80, 5), const_2) | divide(n0,n1)|divide(#0,const_2)| | "the question basically asks how many positive odd integers less than 80 are odd multiples of 5 so we have 5,15 , 25,35 , 45,55 , 65,75 = 8 b" | general |
math_qa__psiB5WFHodkkGqwB | There were two candidates in an election. Winner candidate received 70% of votes and won the election by 280 votes. Find the number of votes casted to the winning candidate?
Choose the correct choice:
A) 228 B) 744 C) 490 D) 199 E) 231 | <gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">280 / (2/5)</gadget>
<output>700</output>
<gadget id="calculator">700 * 70</gadget>
<output>49_000</output>
<gadget id="calculator">49_000 / 100</gadget>
<output>490</output>
<result>C</result> | C | 490 | There were two candidates in an election. Winner candidate received 70% of votes and won the election by 280 votes. Find the number of votes casted to the winning candidate? | {
"A": "228",
"B": "744",
"C": "490",
"D": "199",
"E": "231"
} | divide(multiply(divide(280, divide(subtract(70, subtract(const_100, 70)), const_100)), 70), const_100) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)| | "w = 70 % l = 30 % 70 % - 30 % = 40 % 40 % - - - - - - - - 280 70 % - - - - - - - - ? = > 280 / 40 * 70 = 490 answer : c" | gain |
math_qa__nHTuwVEkLGArfCF2 | A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days? Choices
A) 11 days
B) 13 days
C) 20 3 / 17 days
D) 21 days
E) none of these | <gadget id="calculator">1 / 23</gadget>
<output>1/23 = around 0.043478</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) + 1</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">(13/10) * 23</gadget>
<output>299/10 = around 29.9</output>
<gadget id="calculator">1 / (299/10)</gadget>
<output>10/299 = around 0.033445</output>
<gadget id="calculator">(1/23) + (10/299)</gadget>
<output>1/13 = around 0.076923</output>
<gadget id="calculator">1 / (1/13)</gadget>
<output>13</output>
<result>B</result> | B | 13 | A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days? | {
"A": "11 days",
"B": "13 days",
"C": "20 3 / 17 days",
"D": "21 days",
"E": "none of these"
} | inverse(add(divide(const_1, 23), divide(const_1, multiply(add(divide(30, const_100), const_1), 23)))) | divide(const_1,n1)|divide(n0,const_100)|add(#1,const_1)|multiply(n1,#2)|divide(const_1,#3)|add(#0,#4)|inverse(#5)| | "explanation : ratio of times taken by a and b = 100 : 130 = 10 : 13 suppose b takes x days to do the work . x = ( 23 * 13 ) / 10 = 299 / 10 a ' s 1 day work = 1 / 23 ; b ' s 1 day work = 10 / 299 ( a + b ) ' s 1 day work = ( 1 / 23 + 10 / 299 ) = 1 / 13 a and b together can complete the job in 13 days . answer is b" | physics |
math_qa__x6uyJ62gU8XrQn4B | Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.3850. What is the difference between Rohan’s and Sudhir’s share in the profit? Options:
A) s . 345 B) s . 350 C) s . 352 D) s . 362 E) s . 368 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">12_000 * (3/4)</gadget>
<output>9_000</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">9_000 * (2/3)</gadget>
<output>6_000</output>
<gadget id="calculator">9_000 - 6_000</gadget>
<output>3_000</output>
<gadget id="calculator">18_000 + 9_000</gadget>
<output>27_000</output>
<gadget id="calculator">27_000 + 6_000</gadget>
<output>33_000</output>
<gadget id="calculator">3_850 / 33_000</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">3_000 * (7/60)</gadget>
<output>350</output>
<result>B</result> | B | 350 | Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.3850. What is the difference between Rohan’s and Sudhir’s share in the profit? | {
"A": "s . 345",
"B": "s . 350",
"C": "s . 352",
"D": "s . 362",
"E": "s . 368"
} | multiply(subtract(multiply(12000, divide(subtract(multiply(const_3, const_4), 3), multiply(const_3, const_4))), multiply(9000, divide(subtract(multiply(const_3, const_4), 4), multiply(const_3, const_4)))), divide(3850, add(add(18000, multiply(12000, divide(subtract(multiply(const_3, const_4), 3), multiply(const_3, const_4)))), multiply(9000, divide(subtract(multiply(const_3, const_4), 4), multiply(const_3, const_4)))))) | multiply(const_3,const_4)|subtract(#0,n1)|subtract(#0,n2)|divide(#1,#0)|divide(#2,#0)|multiply(n3,#3)|multiply(n4,#4)|add(n0,#5)|subtract(#5,#6)|add(#7,#6)|divide(n5,#9)|multiply(#10,#8) | suresh : rohan : sudhir ratio of their investments = 18000 × 12 : 12000 × 9 : 9000 × 8 = 6 : 3 : 2 the difference between rohan ’ s and sudhir ’ s share = 1 share : . i . e . = rs . 3850 × 1 / 11 = rs . 350 . b | gain |
math_qa__1e7onsSk9HXxn7Zc | In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 75 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ?
Answers:
A) 50 %
B) 53 %
C) 54 %
D) 55 %
E) 57 % | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">60 * (3/4)</gadget>
<output>45</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">40 * (1/5)</gadget>
<output>8</output>
<gadget id="calculator">45 + 8</gadget>
<output>53</output>
<result>B</result> | B | 53 | In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 75 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ? | {
"A": "50 %",
"B": "53 %",
"C": "54 %",
"D": "55 %",
"E": "57 %"
} | add(multiply(60, divide(75, const_100)), multiply(subtract(const_100, 60), divide(20, const_100))) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_100,n0)|multiply(n0,#0)|multiply(#1,#2)|add(#3,#4)| | "registered voters = 100 d = 60 r = 40 75 % of d ( 60 ) = 45 20 % of r ( 40 ) = 8 total voter % of registered voters = 53 / 100 53 % answer : b" | gain |
math_qa__KawBd9sSHmUlnHOr | A jogger running at 9 km/hr along side a railway track is 200 m ahead of the engine of a 210 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? Select the correct option: A) 89 B) 20 C) 36 D) 41 E) 34 | <gadget id="calculator">200 + 210</gadget>
<output>410</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">5 / 18</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">410 / 10</gadget>
<output>41</output>
<result>D</result> | D | 41 | A jogger running at 9 km/hr along side a railway track is 200 m ahead of the engine of a 210 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? | {
"A": "89",
"B": "20",
"C": "36",
"D": "41",
"E": "34"
} | divide(add(200, 210), multiply(subtract(45, 9), divide(divide(const_10, const_2), divide(subtract(45, 9), const_2)))) | add(n1,n2)|divide(const_10,const_2)|subtract(n3,n0)|divide(#2,const_2)|divide(#1,#3)|multiply(#4,#2)|divide(#0,#5)| | "speed of train relative to jogger = 45 - 9 = 36 km / hr . = 36 * 5 / 18 = 10 m / sec . distance to be covered = 200 + 210 = 410 m . time taken = 410 / 10 = 41 sec . answer : option d" | general |
math_qa__b1mxEiHzxaC0pDke | A box contain the number of balls which is as much greater than 20 is less than 30. The number of balls is? Choose the correct answer:
A) 40 B) 25 C) 30 D) 50 E) 35 | <gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>B</result> | B | 25 | A box contain the number of balls which is as much greater than 20 is less than 30. The number of balls is? | {
"A": "40",
"B": "25",
"C": "30",
"D": "50",
"E": "35"
} | divide(add(30, 20), const_2) | add(n0,n1)|divide(#0,const_2)| | "answer let the number be x . then , x - 20 = 30 - x â ‡ ’ 2 x = 30 + 20 = 50 â ‡ ’ 2 x = 50 â ˆ ´ x = 25 correct option : b" | general |
math_qa__TIevgH9MtiTd7iur | The ratio of number of boys and girls in a school is 1:2. If there are 90 students in the school, find the number of girls in the school? Pick one
A) 45 B) 50 C) 60 D) 75 E) 90 | <gadget id="calculator">90 / 3</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<result>C</result> | C | 60 | The ratio of number of boys and girls in a school is 1:2. If there are 90 students in the school, find the number of girls in the school? | {
"A": "45",
"B": "50",
"C": "60",
"D": "75",
"E": "90"
} | multiply(divide(90, const_3), 2) | divide(n2,const_3)|multiply(n1,#0) | let the number of boys and girls be x and 2 x total students = 100 number of girls in the school = 2 * 90 / 3 = 60 answer is c | other |
math_qa__xbHMU2VWUFcJi6f1 | A group of 3 investors and 3 clients recently frequented the Chinese Luyang Restaurant. The total bill for the meal, including 20% gratuity, came to $720. On average, how much did the meal of each individual cost before gratuity? Choose one.
A) $ 160 B) $ 96 C) $ 90 D) $ 80 E) $ 100 | <gadget id="calculator">20 + 100</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">720 / (6/5)</gadget>
<output>600</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">600 / 6</gadget>
<output>100</output>
<result>E</result> | E | 100 | A group of 3 investors and 3 clients recently frequented the Chinese Luyang Restaurant. The total bill for the meal, including 20% gratuity, came to $720. On average, how much did the meal of each individual cost before gratuity? | {
"A": "$ 160",
"B": "$ 96",
"C": "$ 90",
"D": "$ 80",
"E": "$ 100"
} | divide(divide(720, divide(add(20, const_100), const_100)), add(3, 3)) | add(n2,const_100)|add(n0,n0)|divide(#0,const_100)|divide(n3,#2)|divide(#3,#1) | 3 investors and 3 clients - so total 6 people the bill $ 720 includes 20 % gratuity . . . so the actual cost of dinner was $ 600 now , the cost per person will be $ 600 / 6 which is $ 100 option e | general |
math_qa__PKyrPJLY9MSWS57z | A man can row a distance of 5 km in 60 min with the help of the tide. The direction of the tide reverses with the same speed. Now he travels a further 30 km in 10 hours. How much time he would have saved if the direction of tide has not changed? Select the correct option: A) 2 B) 8 C) 4 D) 6 E) 5 | <gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">10 - 6</gadget>
<output>4</output>
<result>C</result> | C | 4 | A man can row a distance of 5 km in 60 min with the help of the tide. The direction of the tide reverses with the same speed. Now he travels a further 30 km in 10 hours. How much time he would have saved if the direction of tide has not changed? | {
"A": "2",
"B": "8",
"C": "4",
"D": "6",
"E": "5"
} | subtract(10, divide(30, 5)) | divide(n2,n0)|subtract(n3,#0)| | "explanation : he covered 5 km in 1 hour , so he might cover 30 km in 6 hours . but he took 10 hours . he would have saved 10 â € “ 6 = 4 hours . answer : c" | physics |
math_qa__9HVgpqAdTaWhz1JI | The average score of 35 students in a class is 37. If every student is given 3 grace marks, the new average of the class is:
Choose one
A) 33 B) 21 C) 38 D) 40 E) 92 | <gadget id="calculator">3 * 35</gadget>
<output>105</output>
<gadget id="calculator">105 / 35</gadget>
<output>3</output>
<gadget id="calculator">37 + 3</gadget>
<output>40</output>
<result>D</result> | D | 40 | The average score of 35 students in a class is 37. If every student is given 3 grace marks, the new average of the class is: | {
"A": "33",
"B": "21",
"C": "38",
"D": "40",
"E": "92"
} | add(37, divide(multiply(3, 35), 35)) | multiply(n0,n2)|divide(#0,n0)|add(n1,#1) | explanation : average score = 37 grace mark 3 is given to 35 student then its average will be 3 . hence new average = 37 + 3 = 40 answer : d | general |
math_qa__r4gvFf4k8DuJmwHY | Chris mixed 3 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 2 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture? Choose the most appropriate option
A) 1 / 7 B) 1 / 5 C) 1 / 4 D) 1 / 3 E) 3 / 11 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<gadget id="calculator">3 / 11</gadget>
<output>3/11 = around 0.272727</output>
<result>E</result> | E | 0.272727 | Chris mixed 3 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 2 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture? | {
"A": "1 / 7",
"B": "1 / 5",
"C": "1 / 4",
"D": "1 / 3",
"E": "3 / 11"
} | divide(3, add(multiply(4, 2), 3)) | multiply(n1,n2)|add(n0,#0)|divide(n0,#1) | 1 lbs of raisin = $ 1 3 lbs of raisin = $ 3 1 lbs of nuts = $ 2 4 lbs of nuts = $ 8 total value of mixture = 8 + 3 = 11 fraction of the value of raisin = 3 / 11 ans : e | general |
math_qa__wUgQYg20OdiIFrYJ | There are 17 students in a certain class. On the day the test was given, Taqeesha was absent. The other 16 students took the test, and their average was 77. The next day, Taqeesha took the test, and with her grade included, the new average is 78. What is Taqeesha’s grade on the test? Choose the correct choice from the following answers: A) 78 B) 80 C) 87 D) 91 E) 94 | <gadget id="calculator">78 + 16</gadget>
<output>94</output>
<result>E</result> | E | 94 | There are 17 students in a certain class. On the day the test was given, Taqeesha was absent. The other 16 students took the test, and their average was 77. The next day, Taqeesha took the test, and with her grade included, the new average is 78. What is Taqeesha’s grade on the test? | {
"A": "78",
"B": "80",
"C": "87",
"D": "91",
"E": "94"
} | add(78, 16) | add(n1,n3) | explanations 1 ) the average of the first 16 students is 77 . this means , the sum of these 16 scores is sum = ( average ) * ( number of scores ) = 77 * 16 = 1232 once taqeesha takes her test , the average of all 17 scores is 78 . this means , the sum of these 17 scores is : sum = ( average ) * ( number of scores ) = 78 * 17 = 1326 once we had the sum of the 16 scores , all we had to do was add taqeesha ’ s score to that total to get the sum of all 17 . therefore , the difference in these two sums is taqeesha ’ s score . 1326 – 1232 = 94 . answer : e . | general |
math_qa__v6HTtqIM4wc81ABo | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 15 percent. The enrollment on January 1, 1993, was 60 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ? Choose the correct choice from the following choices
A) 38 B) 39 C) 40 D) 41 E) 52 | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">100 / 115</gadget>
<output>20/23 = around 0.869565</output>
<gadget id="calculator">(20/23) * 60</gadget>
<output>1_200/23 = around 52.173913</output>
<result>E</result> | E | 52 | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 15 percent. The enrollment on January 1, 1993, was 60 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ? | {
"A": "38",
"B": "39",
"C": "40",
"D": "41",
"E": "52"
} | multiply(divide(const_100, add(const_100, 15)), 60) | add(n4,const_100)|divide(const_100,#0)|multiply(n7,#1)| | "1.15 x = 60 - - > 23 / 20 * x = 60 - - > x = 60 * 20 / 23 = 1200 / 23 = ~ 52 . answer : e ." | gain |
math_qa__46PIcAkZr37Z3ZOV | A reduction of 30% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg? Select the correct option: A) 46 B) 47 C) 48 D) 49 E) 50 | <gadget id="calculator">800 * 30</gadget>
<output>24_000</output>
<gadget id="calculator">24_000 / 100</gadget>
<output>240</output>
<gadget id="calculator">240 / 5</gadget>
<output>48</output>
<result>C</result> | C | 48 | A reduction of 30% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg? | {
"A": "46",
"B": "47",
"C": "48",
"D": "49",
"E": "50"
} | divide(divide(multiply(800, 30), const_100), 5) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "800 * ( 30 / 100 ) = 240 - - - - 5 ? - - - - 1 = > rs . 48 answer : c" | gain |
math_qa__VcA1Ikxl1M4F81tN | a , b , c and d are 4 consecutive numbers . if the sum of a and dis 109 , what is the product of b and c ? Choose the correct choice from the following answers:
A) 2652
B) 2578
C) 2970
D) 3354
E) 4234 | <gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">109 - 3</gadget>
<output>106</output>
<gadget id="calculator">106 / 2</gadget>
<output>53</output>
<gadget id="calculator">53 + 1</gadget>
<output>54</output>
<gadget id="calculator">54 + 1</gadget>
<output>55</output>
<gadget id="calculator">54 * 55</gadget>
<output>2_970</output>
<result>C</result> | C | 2,970 | a , b , c and d are 4 consecutive numbers . if the sum of a and dis 109 , what is the product of b and c ? | {
"A": "2652",
"B": "2578",
"C": "2970",
"D": "3354",
"E": "4234"
} | multiply(add(divide(subtract(109, subtract(4, const_1)), const_2), const_1), add(add(divide(subtract(109, subtract(4, const_1)), const_2), const_1), const_1)) | subtract(n0,const_1)|subtract(n1,#0)|divide(#1,const_2)|add(#2,const_1)|add(#3,const_1)|multiply(#3,#4) | c 2970 here d = a + 3 a + a + 3 = 109 2 a = 106 a = 53 so , numbers are 53 , 54 , 55 and 56 ∴ b × c = 54 × 55 = 2970 | general |
math_qa__VGHsDgxFYE5lRhiH | Jane makes toy bears. When she works with an assistant, she makes 80 percent more bears per week and works 10 percent fewer hours each week. Having an assistant increases Jane’s output of toy bears per hour by what percent Q? Pick one.
A) 20 % B) 80 % C) 100 % D) 180 % E) 200 % | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>C</result> | C | 100 | Jane makes toy bears. When she works with an assistant, she makes 80 percent more bears per week and works 10 percent fewer hours each week. Having an assistant increases Jane’s output of toy bears per hour by what percent Q? | {
"A": "20 %",
"B": "80 %",
"C": "100 %",
"D": "180 %",
"E": "200 %"
} | multiply(divide(10, subtract(subtract(const_100, 80), 10)), const_100) | subtract(const_100,n0)|subtract(#0,n1)|divide(n1,#1)|multiply(#2,const_100)| | "c . let ' s assume just jane 40 bears per 40 / hrs a week , so that is 1 bear / hr . with an assistant she makes 72 bears per 36 hours a week or 2 bears / hr ( [ 40 bears * 1.8 ] / [ 40 hrs * . 90 ] ) . q = [ ( 2 - 1 ) / 1 ] * 100 % = 100 %" | physics |
math_qa__XFlFAE9xdnrJCj5F | Of all the students in a certain dormitory, 1/2 are first-year students and the rest are second-year students. If 4/5 of the first-year students have not declared a major and if the fraction of second-year students who have declared a major is 4 times the fraction of first-year students who have declared a major, what fraction of all the students in the dormitory are second-year students who have not declared a major?
Choose the correct choice.
A) 1 / 15 B) 4 / 5 C) 4 / 15 D) 1 / 5 E) 2 / 5 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<result>D</result> | D | 0.2 | Of all the students in a certain dormitory, 1/2 are first-year students and the rest are second-year students. If 4/5 of the first-year students have not declared a major and if the fraction of second-year students who have declared a major is 4 times the fraction of first-year students who have declared a major, what fraction of all the students in the dormitory are second-year students who have not declared a major? | {
"A": "1 / 15",
"B": "4 / 5",
"C": "4 / 15",
"D": "1 / 5",
"E": "2 / 5"
} | subtract(const_1, divide(4, 5)) | divide(n2,n3)|subtract(const_1,#0) | tot students = x 1 st year student = x / 2 - - - - > non majaor = 4 / 5 ( x / 2 ) - - - - - > maj = 1 / 5 ( x / 2 ) 2 nd year student = x / 2 - - - - > maj = 4 ( 1 / 5 ( x / 2 ) ) = 2 / 5 ( x ) - - - > non major = x / 2 - 2 / 5 ( x ) = 1 / 5 ( x ) hence 1 / 5 d | general |
math_qa__EAeB0dMn6BY0rHAm | If the personal income tax rate is lowered from 42% to 28%, what is the differential savings for a tax payer having an annual income before tax to the tune of $34500?
Pick one:
A) $ 3500
B) $ 5000
C) $ 4830
D) $ 7000
E) $ 10000 | <gadget id="calculator">34_500 / 100</gadget>
<output>345</output>
<gadget id="calculator">42 - 28</gadget>
<output>14</output>
<gadget id="calculator">345 * 14</gadget>
<output>4_830</output>
<result>C</result> | C | 4,830 | If the personal income tax rate is lowered from 42% to 28%, what is the differential savings for a tax payer having an annual income before tax to the tune of $34500? | {
"A": "$ 3500",
"B": "$ 5000",
"C": "$ 4830",
"D": "$ 7000",
"E": "$ 10000"
} | multiply(divide(34500, const_100), subtract(42, 28)) | divide(n2,const_100)|subtract(n0,n1)|multiply(#0,#1)| | "saving = ( 42 - 28 ) % of 34500 = 4830 . answer : c" | gain |
math_qa__E4q6wDuOZKwIJIKF | The positive integers a and b leave remainders of 2 and 3, respectively, when divided by 6. a > b.
What is the remainder when a – b is divided by 6?
Choose the correct option
A) 4 B) 3 C) 5 D) 2 E) 1 | <gadget id="calculator">2 % 6</gadget>
<output>2</output>
<gadget id="calculator">3 % 6</gadget>
<output>3</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<result>C</result> | C | 5 | The positive integers a and b leave remainders of 2 and 3, respectively, when divided by 6. a > b.
What is the remainder when a – b is divided by 6? | {
"A": "4",
"B": "3",
"C": "5",
"D": "2",
"E": "1"
} | add(reminder(2, 6), reminder(3, 6)) | reminder(n0,n2)|reminder(n1,n2)|add(#0,#1) | let ' s test out some values of m and n that satisfy the given information . a leaves are remainder of 2 when divided by 6 so , a could equal 8 b leaves are remainder of 3 when divided by 6 so , b could equal 3 what is the remainder when a – b is divided by 6 ? so , a - b = 8 - 3 = 5 , and when we divide 5 by 6 , we get 0 with remainder 5 answer : c | general |
math_qa__PLUzwWzTcNx61TtP | John left home and drove at the rate of 35 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 55 mph to reach his destination. How many miles did John drive? Select the correct option
A) 235 miles . B) 245 miles . C) 255 miles . D) 265 miles . E) 275 miles . | <gadget id="calculator">35 * 2</gadget>
<output>70</output>
<gadget id="calculator">3 * 55</gadget>
<output>165</output>
<gadget id="calculator">70 + 165</gadget>
<output>235</output>
<result>A</result> | A | 235 | John left home and drove at the rate of 35 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 55 mph to reach his destination. How many miles did John drive? | {
"A": "235 miles .",
"B": "245 miles .",
"C": "255 miles .",
"D": "265 miles .",
"E": "275 miles ."
} | add(multiply(35, 2), multiply(3, 55)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "the total distance d traveled by john is given by d = 35 * 2 + 3 * 55 = 235 miles . answer a" | physics |
math_qa__4XTQW5fjT4ROQIAp | A team won 40 percent of its first 30 games in a particular season, and 80 percent of its remaining games. If the team won a total of 70 percent of its games that season, what was the total number of games that the team played?
Choose the correct option: A) 60 B) 90 C) 120 D) 150 E) 180 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">30 * (2/5)</gadget>
<output>12</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(4/5) - (7/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">12 / (1/10)</gadget>
<output>120</output>
<result>C</result> | C | 120 | A team won 40 percent of its first 30 games in a particular season, and 80 percent of its remaining games. If the team won a total of 70 percent of its games that season, what was the total number of games that the team played? | {
"A": "60",
"B": "90",
"C": "120",
"D": "150",
"E": "180"
} | divide(multiply(30, divide(40, const_100)), subtract(divide(80, const_100), divide(70, const_100))) | divide(n0,const_100)|divide(n2,const_100)|divide(n3,const_100)|multiply(n1,#0)|subtract(#1,#2)|divide(#3,#4)| | "70 % is 30 % - points above 40 % and 10 % - points below 80 % . thus the ratio of ` ` the first 30 games ' ' to ` ` remaining games ' ' is 1 : 3 . so the team played a total of 30 + 90 = 120 games . the answer is c ." | gain |
math_qa__vdWrPE7ep6GY2vde | Mangoes, Oranges and Apples in a fruit shop are in the ratio of 10: 2 : 3. If there are 120 Mangoes, the number of Apples in the shop is:. Choose the correct choice from the following answers.
A) 36
B) 42
C) 72
D) 400
E) 56 | <gadget id="calculator">120 / 10</gadget>
<output>12</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<result>A</result> | A | 36 | Mangoes, Oranges and Apples in a fruit shop are in the ratio of 10: 2 : 3. If there are 120 Mangoes, the number of Apples in the shop is:. | {
"A": "36",
"B": "42",
"C": "72",
"D": "400",
"E": "56"
} | multiply(divide(120, 10), 3) | divide(n3,n0)|multiply(n2,#0) | explanation : let mangoes = 10 x , oranges = 2 x & apples = 3 x . now , 10 x = 120 hence x = 12 . number of apples = 3 x = 36 . answer : a | other |
math_qa__uI4jOg20pSm1V4jy | The average (arithmetic mean) of 20, 40, and 60 is 9 more than the average of 10, 70, and what number? Choose one
A) 15 B) 25 C) 35 D) 13 E) 55 | <gadget id="calculator">20 + 40</gadget>
<output>60</output>
<gadget id="calculator">60 + 60</gadget>
<output>120</output>
<gadget id="calculator">9 * 3</gadget>
<output>27</output>
<gadget id="calculator">27 + 10</gadget>
<output>37</output>
<gadget id="calculator">37 + 70</gadget>
<output>107</output>
<gadget id="calculator">120 - 107</gadget>
<output>13</output>
<result>D</result> | D | 13 | The average (arithmetic mean) of 20, 40, and 60 is 9 more than the average of 10, 70, and what number? | {
"A": "15",
"B": "25",
"C": "35",
"D": "13",
"E": "55"
} | subtract(add(add(20, 40), 60), add(add(multiply(9, const_3), 10), 70)) | add(n0,n1)|multiply(n3,const_3)|add(n2,#0)|add(n4,#1)|add(n5,#3)|subtract(#2,#4)| | "a 1 = 120 / 3 = 40 a 2 = a 1 - 9 = 31 sum of second list = 31 * 3 = 93 therefore the number = 93 - 80 = 13 answer : d" | general |
math_qa__OtDzqT3l845nNF2o | Two cars start at the same time from opposite ends of a highway that is 105 miles long. One car is riding at 15 mph and the second car is riding at 20 mph. How long after they begin will they meet? Choose the correct option:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">15 + 20</gadget>
<output>35</output>
<gadget id="calculator">105 / 35</gadget>
<output>3</output>
<result>C</result> | C | 3 | Two cars start at the same time from opposite ends of a highway that is 105 miles long. One car is riding at 15 mph and the second car is riding at 20 mph. How long after they begin will they meet? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(105, add(15, 20)) | add(n1,n2)|divide(n0,#0)| | "as cars are moving in opposite directions their speeds will be added . so their relative speeds : 20 + 15 = 35 mph total distance to be covered = 105 miles . time taken would be : 105 miles / 35 mph = 3 hours c is the answer ." | physics |
math_qa__JzGR33amwt6yeZsI | Find the annual income derived by investing $ 6800 in 10% stock at 136. Choose the correct choice from the following answers: A) 550 B) 500 C) 250 D) 300 E) 400 | <gadget id="calculator">6_800 * 10</gadget>
<output>68_000</output>
<gadget id="calculator">68_000 / 136</gadget>
<output>500</output>
<result>B</result> | B | 500 | Find the annual income derived by investing $ 6800 in 10% stock at 136. | {
"A": "550",
"B": "500",
"C": "250",
"D": "300",
"E": "400"
} | divide(multiply(6800, 10), 136) | multiply(n0,n1)|divide(#0,n2)| | "by investing $ 136 , income obtained = $ 10 . by investing $ 6800 , income obtained = $ [ ( 10 / 136 ) * 6800 ] = $ 500 . answer b ." | gain |
math_qa__nbcTiiWENvImSYot | There are 60 people and 3 clubs M, S, and Z in a company. 16 people joined M, 18 people joined S and 11 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not
join any club? Choose the correct choice from the following answers:
A) 22
B) 23
C) 24
D) 25
E) 26 | <gadget id="calculator">60 - 16</gadget>
<output>44</output>
<gadget id="calculator">44 - 18</gadget>
<output>26</output>
<result>E</result> | E | 26 | There are 60 people and 3 clubs M, S, and Z in a company. 16 people joined M, 18 people joined S and 11 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not
join any club? | {
"A": "22",
"B": "23",
"C": "24",
"D": "25",
"E": "26"
} | subtract(subtract(60, 16), 18) | subtract(n0,n2)|subtract(#0,n3) | answer e . key is ' atmost ' here . so 16 people joined m . 18 people joined s and 11 people joined z . to get maximum people who did not join any club , 11 people who joined z are among 18 people who joined s . so 18 + 16 = 34 60 - 34 = 26 | physics |
math_qa__QR5nhPSfJn2cDyyT | 3*14 + 3*15 + 3*18 + 11 = ? Choose one
A) 125 B) 126 C) 130 D) 148 E) 152 | <gadget id="calculator">3 * 14</gadget>
<output>42</output>
<gadget id="calculator">3 * 15</gadget>
<output>45</output>
<gadget id="calculator">42 + 45</gadget>
<output>87</output>
<gadget id="calculator">3 * 18</gadget>
<output>54</output>
<gadget id="calculator">87 + 54</gadget>
<output>141</output>
<gadget id="calculator">141 + 11</gadget>
<output>152</output>
<result>E</result> | E | 152 | 3*14 + 3*15 + 3*18 + 11 = ? | {
"A": "125",
"B": "126",
"C": "130",
"D": "148",
"E": "152"
} | add(add(add(multiply(3, 14), multiply(3, 15)), multiply(3, 18)), 11) | multiply(n0,n1)|multiply(n0,n3)|multiply(n0,n5)|add(#0,#1)|add(#3,#2)|add(n6,#4)| | "3 * 14 + 3 * 15 + 3 * 18 + 11 = 42 + 45 + 54 + 11 = 152 the answer is e ." | general |
math_qa__ZfX32eYmrpIAqTbe | 550−(104÷20.8)=?
Choose the correct choice from the following.
A) 545 B) 525 C) 535 D) 625 E) 105 | <gadget id="calculator">104 / 20.8</gadget>
<output>5</output>
<gadget id="calculator">550 - 5</gadget>
<output>545</output>
<result>A</result> | A | 545 | 550−(104÷20.8)=? | {
"A": "545",
"B": "525",
"C": "535",
"D": "625",
"E": "105"
} | subtract(550, divide(104, 20.8)) | divide(n1,n2)|subtract(n0,#0)| | "explanation : = 550 − ( 104 / 208 x 10 ) = 550 − 5 = 545 option a" | general |
math_qa__zXqq4geBk3BzCYTx | A worker's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 4 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month? Choose the most appropriate option: A) 1 / 3 B) 1 / 4 C) 1 / 5 D) 1 / 6 E) 1 / 7 | <gadget id="calculator">12 / 4</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<result>B</result> | B | 0.25 | A worker's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 4 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month? | {
"A": "1 / 3",
"B": "1 / 4",
"C": "1 / 5",
"D": "1 / 6",
"E": "1 / 7"
} | inverse(add(divide(const_12, 4), const_1)) | divide(const_12,n0)|add(#0,const_1)|inverse(#1)| | "let x be the fraction of her take - home pay that the worker saved . let p be the monthly pay . 12 xp = 4 ( 1 - x ) p 12 xp = 4 p - 4 xp 16 xp = 4 p x = 1 / 4 the answer is b ." | general |
math_qa__nAZTPNk5CWgnNi8M | One pump drains one-half of a pond in 4 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone? Choose the correct option.
A) 1 hour B) 1.1 hour C) 3 hours D) 5 hours E) 6 hours | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 - (1/8)</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">1 / (7/8)</gadget>
<output>8/7 = around 1.142857</output>
<result>B</result> | B | 1.1 | One pump drains one-half of a pond in 4 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone? | {
"A": "1 hour",
"B": "1.1 hour",
"C": "3 hours",
"D": "5 hours",
"E": "6 hours"
} | divide(const_1, subtract(const_1, divide(const_1, multiply(4, const_2)))) | multiply(n0,const_2)|divide(const_1,#0)|subtract(const_1,#1)|divide(const_1,#2)| | "first pump drains 1 / 2 of the tank in 4 hours so 8 hours it will take to drain the full tank . let , 2 nd pump drains the full tank in a hours so both together can drain ( 1 / 8 + 1 / a ) part in 1 hour son in 1 / 2 hour they drain 1 / 2 * ( 1 / 8 + 1 / a ) part of the tank given that in 1 / 2 hour they drain 1 / 2 of the tank hence we can say 1 / 2 * ( 1 / 8 + 1 / a ) = 1 / 2 solving u get a = 8 / 7 = 1.1 hence answer is b" | physics |
math_qa__uzKJ1aWRignHMrWc | If 0.60: x : : 6 : 4, then x is equal to Choices
A) 0.1 B) 0.4 C) 0.82 D) 0.8 E) none | <gadget id="calculator">0.6 * 4</gadget>
<output>2.4</output>
<gadget id="calculator">2.4 / 6</gadget>
<output>0.4</output>
<result>B</result> | B | 0.4 | If 0.60: x : : 6 : 4, then x is equal to | {
"A": "0.1",
"B": "0.4",
"C": "0.82",
"D": "0.8",
"E": "none"
} | divide(multiply(0.60, 4), 6) | multiply(n0,n2)|divide(#0,n1)| | "sol . ( x × 6 ) = ( 0.60 × 4 ) ⇒ x = 2.4 / 6 = 0.40 . answer b" | general |
math_qa__2LCk56YCLeIlXipg | In a small snack shop, the average (arithmetic mean) revenue was $400 per day over a 10-day period. During this period, if the average daily revenue was $360 for the first 6 days, what was the average daily revenue for the last 4 days? Pick one.
A) $ 420
B) $ 440
C) $ 450
D) $ 460
E) $ 480 | <gadget id="calculator">400 * 10</gadget>
<output>4_000</output>
<gadget id="calculator">360 * 6</gadget>
<output>2_160</output>
<gadget id="calculator">4_000 - 2_160</gadget>
<output>1_840</output>
<gadget id="calculator">1_840 / 4</gadget>
<output>460</output>
<result>D</result> | D | 460 | In a small snack shop, the average (arithmetic mean) revenue was $400 per day over a 10-day period. During this period, if the average daily revenue was $360 for the first 6 days, what was the average daily revenue for the last 4 days? | {
"A": "$ 420",
"B": "$ 440",
"C": "$ 450",
"D": "$ 460",
"E": "$ 480"
} | divide(subtract(multiply(400, 10), multiply(360, 6)), 4) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)|divide(#2,n4) | the average revenue was $ 400 per day over a 10 - day period - - > total revenue over 10 - day period is 10 * $ 400 = $ 4000 ; the average daily revenue was $ 360 for the first 6 days - - > total revenue for the first 6 days is 6 * $ 360 = 2160 ; total revenue for the last 4 days is $ 4000 - 2160 = $ 1840 ; average daily revenue for the last 4 days is $ 1840 / 4 = $ 460 . answer : d . | general |
math_qa__ZICBlV7z98dA2UR0 | Water boils at 212°F or 100°C and ice melts at 32°F or 0°C . If the temperature of a pot of water is 50°C, what is the temperature of the pot of water in °F? Pick
A) 101 ° f B) 108 ° f C) 116 ° f D) 122 ° f E) 127 ° f | <gadget id="calculator">212 - 32</gadget>
<output>180</output>
<gadget id="calculator">180 / 100</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) * 50</gadget>
<output>90</output>
<gadget id="calculator">90 + 32</gadget>
<output>122</output>
<result>D</result> | D | 122 | Water boils at 212°F or 100°C and ice melts at 32°F or 0°C . If the temperature of a pot of water is 50°C, what is the temperature of the pot of water in °F? | {
"A": "101 ° f",
"B": "108 ° f",
"C": "116 ° f",
"D": "122 ° f",
"E": "127 ° f"
} | add(multiply(divide(subtract(212, 32), 100), 50), 32) | subtract(n0,n2)|divide(#0,n1)|multiply(n4,#1)|add(n2,#2) | let f and c denote the temperature in fahrenheit and celsius respectively . ( f - 32 ) / ( 212 - 32 ) = ( c - 0 ) / ( 100 - 0 ) f = 9 c / 5 + 32 f = 9 ( 50 ) / 5 + 32 = 122 ° f the answer is d . | physics |
math_qa__v3qDtO9YxQTIiPFQ | louie takes out a 3 - month loan of $ 1000 . the lender charges him 10 % interest per month compunded monthly . the terms of the loan state that louie must repay the loan in 3 equal monthly payments . to the nearest dollar , how much does louie have to pay each month ? Choose the correct answer.
A) 333 B) 383 C) 402 D) 433 E) 483 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">1_000 * (11/10)</gadget>
<output>1_100</output>
<gadget id="calculator">1_100 * (11/10)</gadget>
<output>1_210</output>
<gadget id="calculator">1_210 * (11/10)</gadget>
<output>1_331</output>
<gadget id="calculator">1 + (11/10)</gadget>
<output>21/10 = around 2.1</output>
<gadget id="calculator">(21/10) * (11/10)</gadget>
<output>231/100 = around 2.31</output>
<gadget id="calculator">1 + (231/100)</gadget>
<output>331/100 = around 3.31</output>
<gadget id="calculator">1_331 / (331/100)</gadget>
<output>133_100/331 = around 402.114804</output>
<result>C</result> | C | 402 | louie takes out a 3 - month loan of $ 1000 . the lender charges him 10 % interest per month compunded monthly . the terms of the loan state that louie must repay the loan in 3 equal monthly payments . to the nearest dollar , how much does louie have to pay each month ? | {
"A": "333",
"B": "383",
"C": "402",
"D": "433",
"E": "483"
} | divide(multiply(multiply(multiply(1000, add(const_1, divide(10, const_100))), add(const_1, divide(10, const_100))), add(const_1, divide(10, const_100))), add(const_1, multiply(add(const_1, add(const_1, divide(10, const_100))), add(const_1, divide(10, const_100))))) | divide(n2,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(n1,#1)|multiply(#1,#3)|multiply(#2,#1)|add(#5,const_1)|multiply(#1,#4)|divide(#7,#6) | let the monthly payment be xx . after the 1 st month there will be 1000 ∗ 1.1 − x dollars left to repay ; after the 2 nd month there will be ( 1000 ∗ 1.1 − x ) ∗ 1.1 − x = 1210 − 2.1 x dollars left to repay ; after the 3 rd month there should be 0 dollars left to repay : ( 1210 − 2.1 x ) ∗ 1.1 − x = 0 - - > 1331 = 3.31 x - - > x ≈ 402 x ≈ 402 answer : c . | general |
math_qa__R9Tk0pzGFYFQ8841 | Kim has 9 pairs of shoes; each pair is a different color. If Kim randomly selects 2 shoes without replacement from the 18 shoes, what is the probability that she will select 2 shoes of the same color?
Options
A) 2 / 5 B) 11 / 5 C) 1 / 9 D) 1 / 17 E) 1 / 5 | <gadget id="calculator">binomial(18, 2)</gadget>
<output>153</output>
<gadget id="calculator">9 / 153</gadget>
<output>1/17 = around 0.058824</output>
<result>D</result> | D | 0.058824 | Kim has 9 pairs of shoes; each pair is a different color. If Kim randomly selects 2 shoes without replacement from the 18 shoes, what is the probability that she will select 2 shoes of the same color? | {
"A": "2 / 5",
"B": "11 / 5",
"C": "1 / 9",
"D": "1 / 17",
"E": "1 / 5"
} | divide(9, choose(18, 2)) | choose(n2,n1)|divide(n0,#0)| | "can be tackled in this way as well : probability of selecting any 1 out of 10 shoes = 18 / 18 = 1 probability of selecting the next shoe ( out of 18 available ) having the same color = 1 / 18 ( as after selecting the 1 st one , there is only 1 another shoe left with the same color ) . thus the total probability = 1 * 1 / 17 = 1 / 17 . d is the correct answer ." | probability |
math_qa__PiE5ifbJfFguilGC | Rahim bought 4 pillows with the average cost of $5. If Rahim also buys the fifth pillow with the price of $ 10, what is the average (arithmetic mean) price of those 5 pillows? Choose the correct choice from the following options:
A) $ 6 B) $ 5 C) $ 5.5 D) $ 6.5 E) $ 7 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<result>A</result> | A | 6 | Rahim bought 4 pillows with the average cost of $5. If Rahim also buys the fifth pillow with the price of $ 10, what is the average (arithmetic mean) price of those 5 pillows? | {
"A": "$ 6",
"B": "$ 5",
"C": "$ 5.5",
"D": "$ 6.5",
"E": "$ 7"
} | divide(add(multiply(4, 5), 10), 5) | multiply(n0,n1)|add(n2,#0)|divide(#1,n1) | 4 pillowss - > total cost = 4 * avg cost = 4 * 5 = 20 fifth pillow cost = 10 total cost for 5 pillows = 20 + 10 = 30 am = 30 / 5 = 6 hence a | general |
math_qa__aRmJwpLdFaOOhGHo | There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total E of the book? Choose the most appropriate option.
A) 3003 B) 3027 C) 3024 D) 3021 E) 3018 | <gadget id="calculator">3_000 + 3</gadget>
<output>3_003</output>
<result>A</result> | A | 3,003 | There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total E of the book? | {
"A": "3003",
"B": "3027",
"C": "3024",
"D": "3021",
"E": "3018"
} | add(3000, 3) | add(n0,n5)| | "first , you have to find the common ratio for all 3 books . you have : p : c : b 3 : 2 - - > multiply by 2 ( gives you row 3 ) 4 : 6 6 : 4 : 3 hence : p : c : b : t ( total ) 6 : 4 : 3 : 13 - - - - > this means , the total number e must be a multiple of 13 . answer a is correct since 299 is divisible by 13 , hence is 2990 and so is 3003 ( 2990 + 13 ) ." | other |
math_qa__GfAZvxSla0xUUiAD | -84x19+100=?
Select: A) 2436 B) 2801 C) - 1496 D) - 2071 E) none of them | <gadget id="calculator">1 - 2</gadget>
<output>-1</output>
<gadget id="calculator">84 * 19</gadget>
<output>1_596</output>
<gadget id="calculator">1_596 - 100</gadget>
<output>1_496</output>
<gadget id="calculator">(-1) * 1_496</gadget>
<output>-1_496</output>
<result>C</result> | C | -1,496 | -84x19+100=? | {
"A": "2436",
"B": "2801",
"C": "- 1496",
"D": "- 2071",
"E": "none of them"
} | multiply(subtract(const_1, const_2), subtract(multiply(84, 19), 100)) | multiply(n0,n1)|subtract(const_1,const_2)|subtract(#0,n2)|multiply(#1,#2)| | "given exp . = - 84 x ( 20 - 1 ) + 100 = - ( 84 x 20 ) + 84 + 100 = - 1680 + 184 = - 1496 answer is c" | general |
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