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stringlengths 7
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math_qa__rHB8qHb8hZCxDqI6 | For a certain art exhibit, a museum sold admission tickets to a group of 30 people every 5 minutes from 9:00 in the morning to 5:55 in the afternoon, inclusive. The price of a regular admission ticket was $8 and the price of a student ticket was $4. If on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day?
Choose the correct choice:
A) $ 20960 B) $ 21920 C) $ 22680 D) $ 28500 E) $ 29160 | <gadget id="calculator">12 + 5</gadget>
<output>17</output>
<gadget id="calculator">17 - 9</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">9 * 12</gadget>
<output>108</output>
<gadget id="calculator">108 * 30</gadget>
<output>3_240</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">3_240 / 4</gadget>
<output>810</output>
<gadget id="calculator">810 * 3</gadget>
<output>2_430</output>
<gadget id="calculator">2_430 * 8</gadget>
<output>19_440</output>
<gadget id="calculator">810 * 4</gadget>
<output>3_240</output>
<gadget id="calculator">19_440 + 3_240</gadget>
<output>22_680</output>
<result>C</result> | C | 22,680 | For a certain art exhibit, a museum sold admission tickets to a group of 30 people every 5 minutes from 9:00 in the morning to 5:55 in the afternoon, inclusive. The price of a regular admission ticket was $8 and the price of a student ticket was $4. If on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day? | {
"A": "$ 20960",
"B": "$ 21920",
"C": "$ 22680",
"D": "$ 28500",
"E": "$ 29160"
} | add(multiply(multiply(divide(multiply(multiply(add(subtract(add(const_12, 5), 9), const_1), const_12), 30), add(3, const_1)), 3), 8), multiply(divide(multiply(multiply(add(subtract(add(const_12, 5), 9), const_1), const_12), 30), add(3, const_1)), 4)) | add(const_12,n4)|add(n8,const_1)|subtract(#0,n2)|add(#2,const_1)|multiply(#3,const_12)|multiply(n0,#4)|divide(#5,#1)|multiply(n8,#6)|multiply(n7,#6)|multiply(n6,#7)|add(#9,#8)| | "from 9 : 00 in the morning to 5 : 55 in the afternoon , inclusive there are 9 * 12 = 108 five - minute intervals , thus total of 108 * 30 tickets were sold . say x student and 3 x regular tickets were sold , then x + 3 x = 108 * 30 - - > x = 27 * 30 and 3 x = 3 * ( 27 * 30 ) = 27 * 90 . therefore , the total revenue from ticket sales that day was 27 * 30 * 4 + 27 * 90 * 8 = $ 22,680 . answer : c ." | general |
math_qa__HKFduhSe7sdJI8JG | A train ride from Two P to Town Q costs $6.85 more than does a bus ride from Town P to Town Q. Together, the cost of one train ride and one bus ride is $9.85. What is the cost of a bus ride from Town P to Town Q?
Choose the correct choice from the following choices.
A) $ 1.50
B) $ 2.50
C) $ 4.10
D) $ 4.70
E) $ 8.20 | <gadget id="calculator">9.85 - 6.85</gadget>
<output>3</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<result>A</result> | A | 1.5 | A train ride from Two P to Town Q costs $6.85 more than does a bus ride from Town P to Town Q. Together, the cost of one train ride and one bus ride is $9.85. What is the cost of a bus ride from Town P to Town Q? | {
"A": "$ 1.50",
"B": "$ 2.50",
"C": "$ 4.10",
"D": "$ 4.70",
"E": "$ 8.20"
} | divide(subtract(9.85, 6.85), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "let x be the cost of a bus ride . x + ( x + 685 ) = 985 2 x = 300 x = $ 1.50 the answer is a ." | general |
math_qa__1ktA7QkIoYZV1zrb | Compound X contains elements A and B at an approximate ratio, by weight, of 2:10. Approximately how many grams of element B are there in 222 grams of compound X? Choose the correct choice from the following:
A) 54 B) 185 C) 250 D) 270 E) 322 | <gadget id="calculator">222 * 10</gadget>
<output>2_220</output>
<gadget id="calculator">2 + 10</gadget>
<output>12</output>
<gadget id="calculator">2_220 / 12</gadget>
<output>185</output>
<result>B</result> | B | 185 | Compound X contains elements A and B at an approximate ratio, by weight, of 2:10. Approximately how many grams of element B are there in 222 grams of compound X? | {
"A": "54",
"B": "185",
"C": "250",
"D": "270",
"E": "322"
} | divide(multiply(222, 10), add(2, 10)) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)| | "total number of fractions = 2 + 10 = 12 element b constitutes = 10 out of 12 parts of x so in 222 gms of x have 222 * 10 / 12 = 185 gms of b and 222 - 185 = 37 gms of a . cross check : - a / b = 37 / 185 = 2 / 10 ( as given ) ans b" | other |
math_qa__0nhzr2VqUAnk4haN | A train 100 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
Select the correct option
A) 6 sec B) 9 sec C) 12 sec D) 15 sec E) 18 sec | <gadget id="calculator">68 - 8</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">100 / (50/3)</gadget>
<output>6</output>
<result>A</result> | A | 6 | A train 100 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? | {
"A": "6 sec",
"B": "9 sec",
"C": "12 sec",
"D": "15 sec",
"E": "18 sec"
} | divide(100, multiply(subtract(68, 8), const_0_2778)) | subtract(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of the train relative to man = ( 68 - 8 ) kmph = ( 60 * 5 / 18 ) m / sec = ( 50 / 3 ) m / sec time taken by the train to cross the man = time taken by it to cover 100 m at 50 / 3 m / sec = 100 * 3 / 50 sec = 6 sec answer : a" | physics |
math_qa__wsevcwtVbMX6XA9B | Find k if 32 / k = 4. Choose one: A) 6 B) 7 C) 8 D) 4 E) 3 | <gadget id="calculator">32 / 4</gadget>
<output>8</output>
<result>C</result> | C | 8 | Find k if 32 / k = 4. | {
"A": "6",
"B": "7",
"C": "8",
"D": "4",
"E": "3"
} | divide(32, 4) | divide(n0,n1)| | "since 32 / k = 4 and 32 / 8 = 4 , then k = 8 correct answer c" | general |
math_qa__V1DBlmBdpP6sdqqD | Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/14 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21? Answers
A) 21
B) 35
C) 39
D) 42
E) 65 | <gadget id="calculator">7 * 14</gadget>
<output>98</output>
<gadget id="calculator">98 * 3</gadget>
<output>294</output>
<gadget id="calculator">294 / 7</gadget>
<output>42</output>
<result>D</result> | D | 42 | Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/14 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21? | {
"A": "21",
"B": "35",
"C": "39",
"D": "42",
"E": "65"
} | divide(multiply(multiply(7, 14), 3), 7) | multiply(n1,n4)|multiply(n0,#0)|divide(#1,n1)| | "the total number of the people in the room must be a multiple of both 7 and 14 ( in order 3 / 7 and 5 / 14 of the number to be an integer ) , thus the total number of the people must be a multiple of lcm of 7 and 14 , which is 98 . since , the total number of the people in the room is greater than 50 and less than 100 , then there are 98 people in the room . therefore there are 3 / 7 * 98 = 42 people in the room under the age of 21 . answer : d ." | general |
math_qa__UsMbiLAYzw2PpYF8 | In a group of ducks and cows, the total number of legs are 36 more than twice the number of heads. Find the total number of cows. Choose the correct answer: A) 12 B) 14 C) 16 D) 18 E) 20 | <gadget id="calculator">36 / 2</gadget>
<output>18</output>
<result>D</result> | D | 18 | In a group of ducks and cows, the total number of legs are 36 more than twice the number of heads. Find the total number of cows. | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "20"
} | divide(36, const_2) | divide(n0,const_2)| | "let the number of ducks be d and number of cows be c then , total number of legs = 2 d + 4 c = 2 ( d + 2 c ) total number of heads = c + d given that total number of legs are 36 more than twice the number of heads = > 2 ( d + 2 c ) = 36 + 2 ( c + d ) = > d + 2 c = 18 + c + d = > 2 c = 18 + c = > c = 18 i . e . , total number of cows = 18 answer is d ." | general |
math_qa__2YT4mXRaA0t2fwXt | The radius of a semi circle is 6.6 cm then its perimeter is? Select the correct option:
A) 32.7
B) 32.4
C) 22.4
D) 33.9
E) 32.1 | <gadget id="calculator">2 * pi * 6.6</gadget>
<output>13.2*pi = around 41.469023</output>
<gadget id="calculator">(13.2*pi) / 2</gadget>
<output>6.6*pi = around 20.734512</output>
<gadget id="calculator">6.6 * 2</gadget>
<output>13.2</output>
<gadget id="calculator">(6.6*pi) + 13.2</gadget>
<output>13.2 + 6.6*pi = around 33.934512</output>
<result>D</result> | D | 33.9 | The radius of a semi circle is 6.6 cm then its perimeter is? | {
"A": "32.7",
"B": "32.4",
"C": "22.4",
"D": "33.9",
"E": "32.1"
} | add(divide(circumface(6.6), const_2), multiply(6.6, const_2)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "36 / 7 r = 6.6 = 33.9 answer : d" | physics |
math_qa__XHpK14Y9k3EATBsZ | The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A.? Choose the correct choice from the following choices
A) 16 B) 12 C) 15 D) 20 E) 10 | <gadget id="calculator">12 * 1</gadget>
<output>12</output>
<result>B</result> | B | 12 | The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A.? | {
"A": "16",
"B": "12",
"C": "15",
"D": "20",
"E": "10"
} | multiply(12, const_1) | multiply(n0,const_1)| | "( a + b ) - ( b - c ) = 12 a - c = 12 answer is b" | general |
math_qa__lvcWkvjhityls8Ab | A polling company surveyed a certain country, and it found that 35% of that country’s registered voters had an unfavorable impression of both of that state’s major political parties and that 20% had a favorable impression only of Party W. If one registered voter has a favorable impression of both parties for every two registered voters who have a favorable impression only of Party B, then what percentage of the country’s registered voters have a favorable impression of both parties (assuming that respondents to the poll were given a choice between favorable and unfavorable impressions only)?
Select.
A) 15 B) 20 C) 30 D) 35 E) 45 | <gadget id="calculator">35 + 20</gadget>
<output>55</output>
<gadget id="calculator">100 - 55</gadget>
<output>45</output>
<gadget id="calculator">45 / 3</gadget>
<output>15</output>
<result>A</result> | A | 15 | A polling company surveyed a certain country, and it found that 35% of that country’s registered voters had an unfavorable impression of both of that state’s major political parties and that 20% had a favorable impression only of Party W. If one registered voter has a favorable impression of both parties for every two registered voters who have a favorable impression only of Party B, then what percentage of the country’s registered voters have a favorable impression of both parties (assuming that respondents to the poll were given a choice between favorable and unfavorable impressions only)? | {
"A": "15",
"B": "20",
"C": "30",
"D": "35",
"E": "45"
} | divide(subtract(const_100, add(35, 20)), const_3) | add(n0,n1)|subtract(const_100,#0)|divide(#1,const_3)| | "s = 100 not ( w and b ) = 35 only w = 20 ( w and b ) / b = 1 / 2 let ( w and b ) = x only b = 2 x so now , 20 + 35 + x + 2 x = 100 x = 15 a ans" | gain |
math_qa__CVmjypZZkg1iewvL | Pipe A fills a tank in 6 minutes. Pipe B can fill the same tank 2 times as fast as pipe A. If both the pipes are kept open when the tank is empty, how many minutes will it take to fill the tank?
Select: A) 0.5 B) 1.0 C) 1.5 D) 2.0 E) 2.5 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/6) + (1/3)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / (1/2)</gadget>
<output>2</output>
<result>D</result> | D | 2 | Pipe A fills a tank in 6 minutes. Pipe B can fill the same tank 2 times as fast as pipe A. If both the pipes are kept open when the tank is empty, how many minutes will it take to fill the tank? | {
"A": "0.5",
"B": "1.0",
"C": "1.5",
"D": "2.0",
"E": "2.5"
} | inverse(add(divide(const_1, 6), divide(2, 6))) | divide(const_1,n0)|divide(n1,n0)|add(#0,#1)|inverse(#2)| | "a ' s rate is 1 / 6 and b ' s rate is 1 / 3 . the combined rate is 1 / 6 + 1 / 3 = 1 / 2 the pipes will fill the tank in 2 minutes . the answer is d ." | physics |
math_qa__tlDH9pFOH5NB1960 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8600. If his salary for the month of May is Rs.6500, find his salary for the month of January? Choose the correct answer
A) s . 4100
B) s . 4270
C) s . 4500
D) s . 4550
E) s . 2500 | <gadget id="calculator">8_000 * 4</gadget>
<output>32_000</output>
<gadget id="calculator">8_600 * 4</gadget>
<output>34_400</output>
<gadget id="calculator">34_400 - 6_500</gadget>
<output>27_900</output>
<gadget id="calculator">32_000 - 27_900</gadget>
<output>4_100</output>
<result>A</result> | A | 4,100 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8600. If his salary for the month of May is Rs.6500, find his salary for the month of January? | {
"A": "s . 4100",
"B": "s . 4270",
"C": "s . 4500",
"D": "s . 4550",
"E": "s . 2500"
} | subtract(multiply(8000, const_4), subtract(multiply(8600, const_4), 6500)) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#1,n2)|subtract(#0,#2)| | "sum of the salaries of the person for the months of january , february , march and april = 4 * 8000 = 32000 - - - - ( 1 ) sum of the salaries of the person for the months of february , march , april and may = 4 * 8600 = 34400 - - - - ( 2 ) ( 2 ) - ( 1 ) i . e . may - jan = 2400 salary of may is rs . 6500 salary of january = rs . 4100 answer : a" | general |
math_qa__oO6SHMrXbpVYyiPr | What is the tens digit of 7^545?
Choose the correct choice from the following answers: A) 0 B) 1 C) 2 D) 3 E) 0 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">545 % 5</gadget>
<output>0</output>
<gadget id="calculator">7 ** 0</gadget>
<output>1</output>
<gadget id="calculator">1 % 100</gadget>
<output>1</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">floor(1/10)</gadget>
<output>0</output>
<result>E</result> | E | 0 | What is the tens digit of 7^545? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "0"
} | floor(divide(reminder(power(7, reminder(545, add(const_4, const_1))), const_100), const_10)) | add(const_1,const_4)|reminder(n1,#0)|power(n0,#1)|reminder(#2,const_100)|divide(#3,const_10)|floor(#4)| | "7 ^ 1 = 7 7 ^ 2 = 49 7 ^ 3 = 343 7 ^ 4 = 2401 7 ^ 5 = 16807 7 ^ 6 = 117649 we should see this as pattern recognition . we have a cycle of 4 . ( we can multiply the last 2 digits only as we care about ten ' s digit ) 0 , 4 , 4 , 0 . 546 = 4 * 136 + 1 the ten ' s digit will be 0 . answer e" | general |
math_qa__RfvZnn290IUutGDC | a certain elevator has a safe weight limit of 2000 pounds . what is the greatest possible number of people who can safely ride on the elevator at one time with the average ( arithmetic mean ) weight of half the riders being 200 pounds and the average weight of the others being 230 pounds ? Pick one: A) 7 B) 8 C) 9 D) 10 E) 11 | <gadget id="calculator">200 + 230</gadget>
<output>430</output>
<gadget id="calculator">2_000 / 430</gadget>
<output>200/43 = around 4.651163</output>
<gadget id="calculator">(200/43) * 2</gadget>
<output>400/43 = around 9.302326</output>
<result>C</result> | C | 9 | a certain elevator has a safe weight limit of 2000 pounds . what is the greatest possible number of people who can safely ride on the elevator at one time with the average ( arithmetic mean ) weight of half the riders being 200 pounds and the average weight of the others being 230 pounds ? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | multiply(divide(2000, add(200, 230)), const_2) | add(n1,n2)|divide(n0,#0)|multiply(#1,const_2) | lets assume there are 2 x people . half of them have average weight of 200 and other half has 230 . maximum weight is = 2000 so 200 * x + 230 * x = 2000 = > 430 x = 2000 = > x is approximately equal to 5 . so total people is 2 * 5 = 10 we are not taking 10 as answer because say 10 th person has minimum of 200 weight then 200 * 5 + 230 * 5 = 2150 ( which is more than 2000 ) answer c . | general |
math_qa__mSd2bWqJe9GKCuf2 | A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3360. They completed the work in 3 days with the help of C. How much is to be paid to C? Choose the most appropriate option: A) s . 380 B) s . 600 C) s . 420 D) s . 400 E) s . 480 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/6) + (1/8)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">(1/3) - (7/24)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">3 * (1/24)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 3_360</gadget>
<output>420</output>
<result>C</result> | C | 420 | A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3360. They completed the work in 3 days with the help of C. How much is to be paid to C? | {
"A": "s . 380",
"B": "s . 600",
"C": "s . 420",
"D": "s . 400",
"E": "s . 480"
} | multiply(multiply(3, subtract(divide(const_1, 3), add(divide(const_1, 6), divide(const_1, 8)))), 3360) | divide(const_1,n3)|divide(const_1,n0)|divide(const_1,n1)|add(#1,#2)|subtract(#0,#3)|multiply(n3,#4)|multiply(n2,#5) | explanation : amount of work a can do in 1 day = 1 / 6 amount of work b can do in 1 day = 1 / 8 amount of work a + b can do in 1 day = 1 / 6 + 1 / 8 = 7 / 24 amount of work a + b + c can do = 1 / 3 amount of work c can do in 1 day = 1 / 3 - 7 / 24 = 1 / 24 work a can do in 1 day : work b can do in 1 day : work c can do in 1 day = 1 / 6 : 1 / 8 : 1 / 24 = 4 : 3 : 1 amount to be paid to c = 3360 × ( 1 / 8 ) = 420 answer : option c | physics |
math_qa__ApvU5emDNh1a2gcj | 90 is increased by 50%. Find the final number.
Options.
A) 100 B) 110 C) 135 D) 140 E) 160 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">90 * (1/2)</gadget>
<output>45</output>
<gadget id="calculator">90 + 45</gadget>
<output>135</output>
<result>C</result> | C | 135 | 90 is increased by 50%. Find the final number. | {
"A": "100",
"B": "110",
"C": "135",
"D": "140",
"E": "160"
} | add(90, multiply(90, divide(50, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | "final number = initial number + 50 % ( original number ) = 90 + 50 % ( 90 ) = 90 + 45 = 135 . answer c" | gain |
math_qa__8UUDlP4v2DmHCbn6 | Rahim bought 55 books for Rs.1500 from one shop and 60 books for Rs.340 from another. What is the average price he paid per book ? Select the correct option:
A) s . 17 B) s . 18 C) s . 16 D) s . 11 E) s . 10 | <gadget id="calculator">1_500 + 340</gadget>
<output>1_840</output>
<gadget id="calculator">55 + 60</gadget>
<output>115</output>
<gadget id="calculator">1_840 / 115</gadget>
<output>16</output>
<result>C</result> | C | 16 | Rahim bought 55 books for Rs.1500 from one shop and 60 books for Rs.340 from another. What is the average price he paid per book ? | {
"A": "s . 17",
"B": "s . 18",
"C": "s . 16",
"D": "s . 11",
"E": "s . 10"
} | divide(add(1500, 340), add(55, 60)) | add(n1,n3)|add(n0,n2)|divide(#0,#1)| | "average price per book = ( 1500 + 340 ) / ( 55 + 60 ) = 1840 / 115 = rs . 16 answer : c" | general |
math_qa__dnbdbXGowyiU2PKl | The average of 10 numbers was calculated as 16. It is discovered later on that while calculating the average, one number, namely 46, was incorrectly read as 26. What is the correct average? Choose the correct choice from the following
A) 18 B) 19 C) 20 D) 21 E) 22 | <gadget id="calculator">10 * 16</gadget>
<output>160</output>
<gadget id="calculator">46 - 26</gadget>
<output>20</output>
<gadget id="calculator">160 + 20</gadget>
<output>180</output>
<gadget id="calculator">180 / 10</gadget>
<output>18</output>
<result>A</result> | A | 18 | The average of 10 numbers was calculated as 16. It is discovered later on that while calculating the average, one number, namely 46, was incorrectly read as 26. What is the correct average? | {
"A": "18",
"B": "19",
"C": "20",
"D": "21",
"E": "22"
} | divide(add(multiply(10, 16), subtract(46, 26)), 10) | multiply(n0,n1)|subtract(n2,n3)|add(#0,#1)|divide(#2,n0)| | "10 * 16 - 26 + 46 = 180 180 / 10 = 18 the answer is a ." | general |
math_qa__UJNFTiPWsGnRbQ52 | A can complete a project in 20 days and B can complete the same project in 30 days. If A and B start working on the project together and A quits 10 days before the project is completed, in how many days will the project be completed? Select: A) 18 days B) 27 days C) 26.67 days D) 16 days E) 12 days | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) * 10</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + (1/30)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(2/3) / (1/12)</gadget>
<output>8</output>
<gadget id="calculator">8 + 10</gadget>
<output>18</output>
<result>A</result> | A | 18 | A can complete a project in 20 days and B can complete the same project in 30 days. If A and B start working on the project together and A quits 10 days before the project is completed, in how many days will the project be completed? | {
"A": "18 days",
"B": "27 days",
"C": "26.67 days",
"D": "16 days",
"E": "12 days"
} | add(divide(subtract(const_1, multiply(divide(const_1, 30), 10)), add(divide(const_1, 20), divide(const_1, 30))), 10) | divide(const_1,n1)|divide(const_1,n0)|add(#1,#0)|multiply(n2,#0)|subtract(const_1,#3)|divide(#4,#2)|add(n2,#5)| | "answer a can complete a project in 20 days . so , a will complete 1 / 20 th of the project in a day . b can complete a project in 30 days . so , b will complete 1 / 30 th of the project in a day . let the total number of days taken to complete the project be x days . b worked for all x days . however , a worked for ( x - 10 ) days because a quits 10 days before the project is completed . in a day , a completes 1 / 20 th of the project . therefore , a would have completed x − 10 / 20 th of the project in ( x - 10 ) days . in a day , b completes 130130 th of the project . therefore , b would have completed x / 30 h of the project in x days . ∴ x − 10 / 20 + x / 30 = 1 or x = 18 . choice a" | physics |
math_qa__TFpqO32f7uwZTUX0 | 60 litres of diesel is required to travel 600 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 800 km using 1200 cc engine? Choose the correct choice from the following options:
A) 80 litres B) 90 litres C) 120 litres D) 170 litres E) none of these | <gadget id="calculator">800 * 600</gadget>
<output>480_000</output>
<gadget id="calculator">60 / 480_000</gadget>
<output>1/8_000 = around 0.000125</output>
<gadget id="calculator">800 * (1/8_000)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1_200 * (1/10)</gadget>
<output>120</output>
<result>C</result> | C | 120 | 60 litres of diesel is required to travel 600 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 800 km using 1200 cc engine? | {
"A": "80 litres",
"B": "90 litres",
"C": "120 litres",
"D": "170 litres",
"E": "none of these"
} | multiply(1200, multiply(800, divide(60, multiply(800, 600)))) | multiply(n1,n2)|divide(n0,#0)|multiply(n2,#1)|multiply(n4,#2) | explanatory answer to cover a distance of 800 kms using a 800 cc engine , the amount of diesel required = 800 / 600 * 60 = 80 litres . however , the vehicle uses a 1200 cc engine and the question states that the amount of diesel required varies directly as the engine capacity . i . e . , for instance , if the capacity of engine doubles , the diesel requirement will double too . therefore , with a 1200 cc engine , quantity of diesel required = 1200 / 800 * 80 = 120 litres . answer c | physics |
math_qa__1fDEsuUUqdoLttwJ | A bus trip of 450 miles would have taken 1 hour less if the average speed S for the trip had been greater by 5 miles per hour. What was the average speed S, in miles per hour, for the trip? Answers: A) 10 B) 40 C) 45 D) 50 E) 55 | <gadget id="calculator">450 * 5</gadget>
<output>2_250</output>
<gadget id="calculator">2_250 * 4</gadget>
<output>9_000</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">9_000 + 25</gadget>
<output>9_025</output>
<gadget id="calculator">9_025 ** (1/2)</gadget>
<output>95</output>
<gadget id="calculator">95 - 5</gadget>
<output>90</output>
<gadget id="calculator">90 / 2</gadget>
<output>45</output>
<result>C</result> | C | 45 | A bus trip of 450 miles would have taken 1 hour less if the average speed S for the trip had been greater by 5 miles per hour. What was the average speed S, in miles per hour, for the trip? | {
"A": "10",
"B": "40",
"C": "45",
"D": "50",
"E": "55"
} | divide(subtract(sqrt(add(multiply(multiply(450, 5), const_4), power(5, const_2))), 5), const_2) | multiply(n0,n2)|power(n2,const_2)|multiply(#0,const_4)|add(#2,#1)|sqrt(#3)|subtract(#4,n2)|divide(#5,const_2)| | "( s + 5 ) ( t - 1 ) = 450 s * t = 450 solving both the equations , we get : s = 45 or - 50 since speed should be positive , s = 45 hence , option c" | physics |
math_qa__N36HYZjVX1xv0qe9 | An equal number of desks and bookcases are to be placed along a library wall that is 15 meters long. Each desk is 2 meters long, and each bookshelf is 1.5 meters long. If the maximum possible number of desks and bookcases are to be placed along the wall, then the space along the wall that is left over will be how many meters W long? Select
A) 0.5
B) 1
C) 1.5
D) 2
E) 3 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">4 * 1.5</gadget>
<output>6</output>
<gadget id="calculator">8 + 6</gadget>
<output>14</output>
<gadget id="calculator">15 - 14</gadget>
<output>1</output>
<result>B</result> | B | 1 | An equal number of desks and bookcases are to be placed along a library wall that is 15 meters long. Each desk is 2 meters long, and each bookshelf is 1.5 meters long. If the maximum possible number of desks and bookcases are to be placed along the wall, then the space along the wall that is left over will be how many meters W long? | {
"A": "0.5",
"B": "1",
"C": "1.5",
"D": "2",
"E": "3"
} | subtract(15, add(multiply(const_4, 2), multiply(const_4, 1.5))) | multiply(n1,const_4)|multiply(n2,const_4)|add(#0,#1)|subtract(n0,#2) | let x be the number of desks and bookcases that are placed along the library wall . 2 x + 1.5 x < 15 3.5 x < 15 since x is a non negative integer , the largest number x can be is 4 . when x is 4 , the desks and bookcases take up 3.5 * 4 = 14 m , leaving 1 m of empty space . thus , i believe the answer is b ) 1 | general |
math_qa__YQCru7VlCK6RFNzd | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 110 mph. On the way home, I flew 72 mph. What was my average speed for the trip? Choose the correct choice from the following answers
A) 198 mph B) 91 mph C) 88 mph D) 100 mph E) 99 mph | <gadget id="calculator">110 + 72</gadget>
<output>182</output>
<gadget id="calculator">182 / 2</gadget>
<output>91</output>
<result>B</result> | B | 91 | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 110 mph. On the way home, I flew 72 mph. What was my average speed for the trip? | {
"A": "198 mph",
"B": "91 mph",
"C": "88 mph",
"D": "100 mph",
"E": "99 mph"
} | divide(add(110, 72), const_2) | add(n0,n1)|divide(#0,const_2)| | "( 110 mph + 72 mph ) / 2 = 91 mph correct answer is : b" | physics |
math_qa__ftTEOBZXbFpEQeNe | a starts business with rs . 35000 and after 5 months , b joins with a as his partner . after a year , the profit is divided in the ratio 2 : 3 . what is b ’ s contribution in the capital ? Choices:
A) 22378 B) 279889 C) 2788 D) 9000 E) 2882 | <gadget id="calculator">35_000 * 12</gadget>
<output>420_000</output>
<gadget id="calculator">420_000 * 3</gadget>
<output>1_260_000</output>
<gadget id="calculator">12 - 5</gadget>
<output>7</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">1_260_000 / 14</gadget>
<output>90_000</output>
<gadget id="calculator">90_000 / 10</gadget>
<output>9_000</output>
<result>D</result> | D | 9,000 | a starts business with rs . 35000 and after 5 months , b joins with a as his partner . after a year , the profit is divided in the ratio 2 : 3 . what is b ’ s contribution in the capital ? | {
"A": "22378",
"B": "279889",
"C": "2788",
"D": "9000",
"E": "2882"
} | divide(divide(multiply(multiply(35000, const_12), 3), multiply(subtract(const_12, 5), 2)), const_10) | multiply(n0,const_12)|subtract(const_12,n1)|multiply(n3,#0)|multiply(n2,#1)|divide(#2,#3)|divide(#4,const_10) | explanation : ratio in which profit is to be divided = 2 : 3 assume that b ' s contribution to the capital = b ⇒ 3500 × 12 : b × 7 = 2 : 3 ⇒ 3500 × 12 / 7 b = 2 / 3 ⇒ b = ( 3500 × 12 × 3 ) / ( 2 × 7 ) = 500 × 6 × 3 = 9000 answer : d | other |
math_qa__yAuucHjXI8uUUz31 | If 45-[28-{37-(15-*)}]= 55, then * is equal to: Choose the correct choice from the following choices.
A) - 29 B) - 19 C) 16 D) 29 E) 39 | <gadget id="calculator">28 - 37</gadget>
<output>-9</output>
<gadget id="calculator">(-9) + 15</gadget>
<output>6</output>
<gadget id="calculator">45 - 6</gadget>
<output>39</output>
<gadget id="calculator">55 - 39</gadget>
<output>16</output>
<result>C</result> | C | 16 | If 45-[28-{37-(15-*)}]= 55, then * is equal to: | {
"A": "- 29",
"B": "- 19",
"C": "16",
"D": "29",
"E": "39"
} | subtract(55, subtract(45, add(subtract(28, 37), 15))) | subtract(n1,n2)|add(n3,#0)|subtract(n0,#1)|subtract(n4,#2) | 45 - [ 28 - { 37 - ( 15 - * ) } ] = 55 = > 45 - [ 28 - { 37 - 15 + * } ] = 55 45 - [ 28 - 37 + 15 - * ] = 55 = > 45 [ 43 - 37 - * ] = 55 45 - [ 6 - * ] = 55 = > 45 - 6 + * = 55 39 + * = 55 = > * = 55 - 39 = 16 answer : c | general |
math_qa__wNk3aedzPw1CACLG | What is the remainder of Q= 3^19 when divided by 10? Choose the correct choice from the following answers: A) 0 B) 1 C) 5 D) 7 E) 9 | <gadget id="calculator">19 % 4</gadget>
<output>3</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">27 % 10</gadget>
<output>7</output>
<result>D</result> | D | 7 | What is the remainder of Q= 3^19 when divided by 10? | {
"A": "0",
"B": "1",
"C": "5",
"D": "7",
"E": "9"
} | reminder(power(3, reminder(19, const_4)), 10) | reminder(n1,const_4)|power(n0,#0)|reminder(#1,n2)| | "i looked for patterns : ^ 2 - units digit 9 ^ 3 - units digit 7 ^ 4 - units digit 1 ^ 5 - units digit 3 hence , we can see that when raised to a power which is multiple of 4 , the units digit is 1 , and when to an even power not multiple of 4 , the units digit is 9 and we can then see : ^ 16 - units digit 1 , or ^ 18 - units digit 9 and ^ 19 - units digit 7 therefore , q = when divided by 10 , the remainder must be 7 . d" | general |
math_qa__0bvBKOJeNaEZRRbB | Find the fraction which has the same ratio to 2/5 that 3/8 has to 1/5 Choices.
A) 1 / 15 B) 3 / 4 C) 5 / 8 D) 9 / 6 E) 8 / 7 | <gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/8) / (1/5)</gadget>
<output>15/8 = around 1.875</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(15/8) * (2/5)</gadget>
<output>3/4 = around 0.75</output>
<result>B</result> | B | 0.75 | Find the fraction which has the same ratio to 2/5 that 3/8 has to 1/5 | {
"A": "1 / 15",
"B": "3 / 4",
"C": "5 / 8",
"D": "9 / 6",
"E": "8 / 7"
} | multiply(divide(divide(3, 8), divide(1, 5)), divide(2, 5)) | divide(n2,n3)|divide(n4,n5)|divide(n0,n1)|divide(#0,#1)|multiply(#3,#2)| | "p : 2 / 5 = 3 / 8 : 1 / 5 as the product of the means is equal to the product of the extremes . p * 1 / 5 = 2 / 5 * 3 / 8 p * 1 / 5 = 6 / 40 p = 3 / 4 = > p = 3 / 4 answer : b" | other |
math_qa__l6DIuio6MO60KlOU | In a class of 27 students in an examination in maths 5 students scored 95 marks each, 3 get zero each and the average of the rest was 45. What is the average of the whole class? Choose the correct option
A) 47
B) 45.6
C) 44
D) 48
E) 49.3 | <gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">27 - 8</gadget>
<output>19</output>
<gadget id="calculator">45 * 19</gadget>
<output>855</output>
<gadget id="calculator">95 * 5</gadget>
<output>475</output>
<gadget id="calculator">855 + 475</gadget>
<output>1_330</output>
<gadget id="calculator">1_330 / 27</gadget>
<output>1_330/27 = around 49.259259</output>
<result>E</result> | E | 49.3 | In a class of 27 students in an examination in maths 5 students scored 95 marks each, 3 get zero each and the average of the rest was 45. What is the average of the whole class? | {
"A": "47",
"B": "45.6",
"C": "44",
"D": "48",
"E": "49.3"
} | divide(add(multiply(45, subtract(27, add(3, 5))), multiply(95, 5)), 27) | add(n1,n3)|multiply(n1,n2)|subtract(n0,#0)|multiply(n4,#2)|add(#3,#1)|divide(#4,n0) | explanation : total marks obtained by a class of 25 students = 5 * 95 + 3 * 0 + 19 * 45 = 1330 average marks of whole class = 1330 / 27 = 49.3 answer : option e | general |
math_qa__md0g1vvghA8vz4SZ | A trader marked the selling price of an article at 12% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of : Choose the correct option: A) 10 % B) 10.5 % C) 11 % D) 12.5 % E) 9.8 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">100 + 12</gadget>
<output>112</output>
<gadget id="calculator">11 / 112</gadget>
<output>11/112 = around 0.098214</output>
<gadget id="calculator">100 * (11/112)</gadget>
<output>275/28 = around 9.821429</output>
<result>E</result> | E | 9.8 | A trader marked the selling price of an article at 12% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of : | {
"A": "10 %",
"B": "10.5 %",
"C": "11 %",
"D": "12.5 %",
"E": "9.8"
} | multiply(const_100, divide(add(multiply(add(const_2, const_3), const_2), 1), add(const_100, 12))) | add(const_2,const_3)|add(n0,const_100)|multiply(#0,const_2)|add(#2,n1)|divide(#3,#1)|multiply(#4,const_100)| | "sol . let c . p . = rs . 100 . then , marked price = rs . 110 , s . p . = rs . 99 . ∴ discount % = [ 11 / 112 * 100 ] % = 9.8 % answer e" | gain |
math_qa__GeCiufENXuIZGqUo | In a river flowing at 2 km/hr, a boat travels 64 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time. Choose the correct option: A) 10 hours B) 12 hours C) 14 hours D) 24 hours E) none of these | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">64 / 4</gadget>
<output>16</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">64 / 8</gadget>
<output>8</output>
<gadget id="calculator">16 + 8</gadget>
<output>24</output>
<result>D</result> | D | 24 | In a river flowing at 2 km/hr, a boat travels 64 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time. | {
"A": "10 hours",
"B": "12 hours",
"C": "14 hours",
"D": "24 hours",
"E": "none of these"
} | add(divide(64, subtract(6, 2)), divide(64, add(6, 2))) | add(n0,n2)|subtract(n2,n0)|divide(n1,#1)|divide(n1,#0)|add(#2,#3)| | "explanation : speed of the boat = 6 km / hr speed downstream = ( 6 + 2 ) = 8 km / hr speed upstream = ( 6 - 2 ) = 4 km / hr distance travelled downstream = distance travelled upstream = 64 km total time taken = time taken downstream + time taken upstream = ( 64 / 8 ) + ( 64 / 4 ) = = 24 hr . answer : option d" | general |
math_qa__cFrt1pxF6GuULF5D | If (m-8) is a factor of m^2-pm-24, then p= Choose the correct choice from the following answers.
A) 3 B) 5 C) 6 D) 11 E) 16 | <gadget id="calculator">24 / 8</gadget>
<output>3</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<result>B</result> | B | 5 | If (m-8) is a factor of m^2-pm-24, then p= | {
"A": "3",
"B": "5",
"C": "6",
"D": "11",
"E": "16"
} | subtract(8, divide(24, 8)) | divide(n2,n0)|subtract(n0,#0)| | "( m - 8 ) ( m - a ) = m ^ 2 - pm - 24 a = - 3 p = 8 + a = 5 = b" | general |
math_qa__nl0yLCBW4bVhgBGg | You and your friend spent a total of $15 for lunch. Your friend spent $1 more than you. How much did your friend spend on their lunch? Select the correct option
A) $ 9
B) $ 8
C) $ 4
D) $ 6
E) $ 5 | <gadget id="calculator">15 - 1</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<result>B</result> | B | 8 | You and your friend spent a total of $15 for lunch. Your friend spent $1 more than you. How much did your friend spend on their lunch? | {
"A": "$ 9",
"B": "$ 8",
"C": "$ 4",
"D": "$ 6",
"E": "$ 5"
} | add(divide(subtract(15, 1), const_2), 1) | subtract(n0,n1)|divide(#0,const_2)|add(n1,#1)| | "my lunch = l , my friends lunch = l + 1 ( l ) + ( l + 1 ) = 15 l + l + 1 - 1 = 15 - 1 2 l = 14 l = 7 my friends lunch l + 1 = 7 + 1 = $ 8 , the answer is b" | general |
math_qa__W8RDnRIuq6wGanTb | Maxwell leaves his home and walks toward Brad's house. One hour later, Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 54 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the total time it takes Maxwell before he meets up with Brad? Choose the correct choice from the following answers: A) 3 B) 4 C) 5 D) 6 E) 8 | <gadget id="calculator">54 + 6</gadget>
<output>60</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<result>D</result> | D | 6 | Maxwell leaves his home and walks toward Brad's house. One hour later, Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 54 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the total time it takes Maxwell before he meets up with Brad? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "8"
} | divide(add(54, 6), add(4, 6)) | add(n0,n2)|add(n1,n2)|divide(#0,#1)| | "total distance = 54 kms maxwell speed = 4 kms / hr maxwell travelled for 1 hour before brad started , therefore maxwell traveled for 4 kms in 1 hour . time taken = total distance / relative speed total distance after brad started = 50 kms relative speed ( opposite side ) ( as they are moving towards each other speed would be added ) = 6 + 4 = 10 kms / hr time taken to meet brad after brad started = 50 / 10 = 5 hrs distance traveled by maxwell = maxwell ' s speed * time taken = 4 * 5 = 20 + 4 = 24 kms . . . therefore total time taken by maxwell to meet brad = distance travelled by maxwell / maxwell ' s speed = 24 / 4 = 6 hrs . . . answer d alternatively . . . total time taken by maxwell to meet brad = maxwell started 1 hour earlier to brad + total time taken to meet brad after brad started = 1 + 5 = 6 hrs . . . answer d" | physics |
math_qa__CeAylgJ4xb4soivA | What are the total number of divisors of 600(including 1 and 600)? Pick.
A) 4
B) 24
C) 40
D) 16
E) 20 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<gadget id="calculator">600 / 25</gadget>
<output>24</output>
<result>B</result> | B | 24 | What are the total number of divisors of 600(including 1 and 600)? | {
"A": "4",
"B": "24",
"C": "40",
"D": "16",
"E": "20"
} | divide(600, multiply(const_0_25, const_100)) | multiply(const_0_25,const_100)|divide(n0,#0) | write the prime factorization . 600 = ( 2 ^ 3 ) ( 3 ^ 1 ) ( 5 ^ 2 ) the number of divisors ( including 1 and the number itself ) is the product of one plus the exponents . ( 3 + 1 ) ( 1 + 1 ) ( 2 + 1 ) = 24 answer : b | general |
math_qa__A45A0mA7zK1HJ9qp | The overall ages of Kumar, Hathim and Rahul is 93 years. 1 decade ago, the ratio of their ages was 2 : 3 : 4. What is the current age of Rahul? Choose the correct answer.
A) 38 B) 37 C) 34 D) 35 E) 33 | <gadget id="calculator">93 / 3</gadget>
<output>31</output>
<gadget id="calculator">31 / 2</gadget>
<output>31/2 = around 15.5</output>
<gadget id="calculator">31 + (31/2)</gadget>
<output>93/2 = around 46.5</output>
<gadget id="calculator">(93/2) - 10</gadget>
<output>73/2 = around 36.5</output>
<result>A</result> | A | 38 | The overall ages of Kumar, Hathim and Rahul is 93 years. 1 decade ago, the ratio of their ages was 2 : 3 : 4. What is the current age of Rahul? | {
"A": "38",
"B": "37",
"C": "34",
"D": "35",
"E": "33"
} | subtract(add(divide(93, 3), divide(divide(93, 3), 2)), const_10) | divide(n0,n3)|divide(#0,n2)|add(#0,#1)|subtract(#2,const_10) | a 38 if the ages of kumar , hathim and rahul 1 decade ago be 2 a , 3 a and 4 a years correspondingly then , ( 2 a + 10 ) + ( 3 a + 10 ) + ( 4 a + 10 ) = 93 9 a = 93 - 30 9 a = 63 a = 7 rahul ’ s current age = ( 4 a + 10 ) = 38 years . | other |
math_qa__iH7TfVq5h5X8v1qL | Set #1 = {A, B}
Set #2 = {K, L, M, N, O, P}
There are these two sets of letters, and you are going to pick exactly one letter from each set. What is the probability of picking at least one vowel? Pick one:
A) 1 / 6 B) 1 / 3 C) 7 / 12 D) 2 / 3 E) 5 / 6 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(1/2) * (5/6)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">1 - (5/12)</gadget>
<output>7/12 = around 0.583333</output>
<result>C</result> | C | 0.583333 | Set #1 = {A, B}
Set #2 = {K, L, M, N, O, P}
There are these two sets of letters, and you are going to pick exactly one letter from each set. What is the probability of picking at least one vowel? | {
"A": "1 / 6",
"B": "1 / 3",
"C": "7 / 12",
"D": "2 / 3",
"E": "5 / 6"
} | subtract(1, multiply(divide(const_1, const_2), divide(add(const_4, const_1), add(add(const_4, const_1), const_1)))) | add(const_1,const_4)|divide(const_1,const_2)|add(#0,const_1)|divide(#0,#2)|multiply(#1,#3)|subtract(n0,#4) | so not a vowel in set - 1 : 1 / 2 and not a vowel in ser - 2 : 5 / 6 now , 1 / 2 ∗ 5 / 6 = 5 / 12 this is for not a vowel . then for at least one vowel will be = 1 − 5 / 12 = 7 / 12 answer will be c . | general |
math_qa__4TPLa5QhJ3WKNv4Q | In a rectangular coordinate system, what is the area of a rectangle whose vertices have the coordinates (-7, 1), (1, 1), (1, -6) and (-7, -6)? Choose the correct choice from the following choices: A) 112 B) 64 C) 42 D) 24 E) 56 | <gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">1 + 6</gadget>
<output>7</output>
<gadget id="calculator">8 * 7</gadget>
<output>56</output>
<result>E</result> | E | 56 | In a rectangular coordinate system, what is the area of a rectangle whose vertices have the coordinates (-7, 1), (1, 1), (1, -6) and (-7, -6)? | {
"A": "112",
"B": "64",
"C": "42",
"D": "24",
"E": "56"
} | multiply(add(7, 1), add(1, 6)) | add(n0,n1)|add(n1,n5)|multiply(#0,#1)| | "length of side 1 = 7 + 1 = 8 length of side 2 = 6 + 1 = 7 area of rectangle = 7 * 8 = 56 e is the answer" | geometry |
math_qa__XQ7l7modKZk8BTTs | In digging a pond 20 m * 12 m * 5 m the volumes of the soil extracted will be? Choose the correct choice from the following:
A) 3387
B) 1000
C) 1200
D) 2787
E) 1121 | <gadget id="calculator">20 * 12</gadget>
<output>240</output>
<gadget id="calculator">240 * 5</gadget>
<output>1_200</output>
<result>C</result> | C | 1,200 | In digging a pond 20 m * 12 m * 5 m the volumes of the soil extracted will be? | {
"A": "3387",
"B": "1000",
"C": "1200",
"D": "2787",
"E": "1121"
} | multiply(multiply(20, 12), 5) | multiply(n0,n1)|multiply(n2,#0)| | "20 * 12 * 5 = 1200 answer : c" | general |
math_qa__x9TKZ1KTzGWs9RI4 | Define A = The sum of digits of the number 7^100 and B = The sum of the digits of A. What is the sum of the digits of B? Select the correct option: A) 7 B) 16 C) 10 D) 11 E) can not be determined | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">1 + 6</gadget>
<output>7</output>
<result>A</result> | A | 7 | Define A = The sum of digits of the number 7^100 and B = The sum of the digits of A. What is the sum of the digits of B? | {
"A": "7",
"B": "16",
"C": "10",
"D": "11",
"E": "can not be determined"
} | add(const_1, add(const_2, const_4)) | add(const_2,const_4)|add(#0,const_1) | following approach will take you only couple of sec . \ ( 7 ^ { 100 } = ( 7 ^ { 50 } ) ^ 2 \ ) the sum of digits ( digital root ) of a perfect square can only be 1 , 4 , 7 or 9 . for example \ ( 7 ^ 2 = 49 \ ) = > dr = 4 + 9 = 13 = > 1 + 3 = 4 and etc . checking available options . answer a . | general |
math_qa__5BFbK435nNRh1yiV | How many zeros does 1000! end with? Choices:
A) 20 o
B) 24 o
C) 249
D) 30 o
E) 325 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">1_000 / 5</gadget>
<output>200</output>
<gadget id="calculator">1_000 - 5</gadget>
<output>995</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">995 / 25</gadget>
<output>199/5 = around 39.8</output>
<gadget id="calculator">200 + (199/5)</gadget>
<output>1_199/5 = around 239.8</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<gadget id="calculator">995 / 125</gadget>
<output>199/25 = around 7.96</output>
<gadget id="calculator">(1_199/5) + (199/25)</gadget>
<output>6_194/25 = around 247.76</output>
<result>C</result> | C | 249 | How many zeros does 1000! end with? | {
"A": "20 o",
"B": "24 o",
"C": "249",
"D": "30 o",
"E": "325"
} | add(add(divide(1000, add(const_4, const_1)), divide(subtract(1000, add(const_4, const_1)), power(add(const_4, const_1), const_2))), divide(subtract(1000, add(const_4, const_1)), power(add(const_4, const_1), const_3))) | add(const_1,const_4)|divide(n0,#0)|power(#0,const_2)|power(#0,const_3)|subtract(n0,#0)|divide(#4,#2)|divide(#4,#3)|add(#1,#5)|add(#7,#6)| | "according to above 1000 ! has 1000 / 5 + 1000 / 25 + 1000 / 125 + 1000 / 625 = 200 + 40 + 8 + 1 = 249 trailing zeros . answer : c" | other |
math_qa__CpcCog2KalydsPg9 | Train E and F, 455 miles apart, are traveling toward each other at constant rates and in the same time zone. If train E left at 4 pm traveling at a speed of 60 miles per hour, and train F left at 5:45 pm and traveling at 45 miles per hour, then at what time would they pass each other?
Choose the correct choice from the following answers: A) 9.03 pm B) 9.05 pm C) 9.07 pm D) 9.08 pm E) 9.10 pm | <gadget id="calculator">455 / 60</gadget>
<output>91/12 = around 7.583333</output>
<gadget id="calculator">455 / 45</gadget>
<output>91/9 = around 10.111111</output>
<gadget id="calculator">(91/12) + (91/9)</gadget>
<output>637/36 = around 17.694444</output>
<gadget id="calculator">(637/36) / 2</gadget>
<output>637/72 = around 8.847222</output>
<result>B</result> | B | 9.05 | Train E and F, 455 miles apart, are traveling toward each other at constant rates and in the same time zone. If train E left at 4 pm traveling at a speed of 60 miles per hour, and train F left at 5:45 pm and traveling at 45 miles per hour, then at what time would they pass each other? | {
"A": "9.03 pm",
"B": "9.05 pm",
"C": "9.07 pm",
"D": "9.08 pm",
"E": "9.10 pm"
} | divide(add(divide(455, 60), divide(455, 45)), const_2) | divide(n0,n2)|divide(n0,n4)|add(#0,#1)|divide(#2,const_2) | first , since e has a headstart then in that 1 hr 45 min or 1.75 hrs he travels 105 miles then remaining distance to be traveled will be 455 - 105 = 350 miles now , using relative rates ( 105 ) ( t ) = 350 this gives 10 / 3 hours now 5.45 pm + 10 / 3 hours gives us 9.05 pm hence answer is b | physics |
math_qa__lid35AHaZzK3pnjP | When 2/9 of the votes on a certain resolution have been counted, 3/4 of those counted are in favor of the resolution. What fraction w of the remaining votes must be against the resolution so that the total count will result in a vote of 2 to 1 against the resolution? Select the correct option.
A) 11 / 14
B) 13 / 18
C) 4 / 7
D) 3 / 7
E) 3 / 14 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(2/9) * (3/4)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(2/9) - (1/6)</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(2/3) - (1/18)</gadget>
<output>11/18 = around 0.611111</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>
<gadget id="calculator">(11/18) / (7/9)</gadget>
<output>11/14 = around 0.785714</output>
<result>A</result> | A | 0.785714 | When 2/9 of the votes on a certain resolution have been counted, 3/4 of those counted are in favor of the resolution. What fraction w of the remaining votes must be against the resolution so that the total count will result in a vote of 2 to 1 against the resolution? | {
"A": "11 / 14",
"B": "13 / 18",
"C": "4 / 7",
"D": "3 / 7",
"E": "3 / 14"
} | divide(subtract(divide(2, add(1, 2)), subtract(divide(2, 9), multiply(divide(2, 9), divide(3, 4)))), divide(subtract(9, 2), 9)) | add(n0,n5)|divide(n0,n1)|divide(n2,n3)|subtract(n1,n0)|divide(n0,#0)|divide(#3,n1)|multiply(#1,#2)|subtract(#1,#6)|subtract(#4,#7)|divide(#8,#5)| | "if we use variable for total votes there will be too many fractions to manipulate with , so pick some smart # : let set total # of votes is 18 . 2 / 9 of the votes on a certain resolution have been counted - - > 4 counted and 18 - 4 = 14 votes left to be counted ; 3 / 4 of those counted are in favor of the resolution - - > 3 in favor and 1 against ; ratio of those who voted against to those who voted for to be 2 to 1 there should be total of 18 * 2 / 3 = 12 people who voted against , so in the remaining 14 votes there should be 12 - 1 = 11 people who voted against . thus w = 11 / 14 of the remaining votes must be against . answer : a ." | general |
math_qa__tNqIZoE61ujghcAk | The total age of A and B is 17 years more than the total age of B and C. C is how many years younger than A ? Options
A) 12 B) 27 C) 21 D) 17 E) 11 | <gadget id="calculator">17 * 1</gadget>
<output>17</output>
<result>D</result> | D | 17 | The total age of A and B is 17 years more than the total age of B and C. C is how many years younger than A ? | {
"A": "12",
"B": "27",
"C": "21",
"D": "17",
"E": "11"
} | multiply(17, const_1) | multiply(n0,const_1)| | "( a + b ) - ( b + c ) = 17 a - c = 17 . c is younger than a by 17 years . answer : d" | general |
math_qa__dUh4CcNgW5JTeuPf | If a=(10^10)-47, what is the sum of all the digit of a? Options: A) 40 B) 45 C) 50 D) 55 E) 80 | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">160 / 2</gadget>
<output>80</output>
<result>E</result> | E | 80 | If a=(10^10)-47, what is the sum of all the digit of a? | {
"A": "40",
"B": "45",
"C": "50",
"D": "55",
"E": "80"
} | divide(add(multiply(10, 10), const_60), const_2) | multiply(n0,n0)|add(#0,const_60)|divide(#1,const_2) | start small and check for any pattern : 10 ^ 2 - 47 = 53 - > number of digits = power of 10 ; number of 9 s = ( power of 10 ) - 2 ; 53 is the last 2 digits 10 ^ 3 - 47 = 953 - > number of digits = power of 10 ; number of 9 s = ( power of 10 ) - 2 ; 53 is the last 2 digits . . . extrapolate 10 ^ 10 - 47 - > number of digits = 10 ; number of 9 s = 8 ; 53 will be the last 2 digits sum , a = 9 * 8 + 5 + 3 = 80 . answer ( e ) . | general |
math_qa__2hQXH33yNMzrEcE4 | Two sets of 7 consecutive positive integers have exactly one integer in common. The sum of the integers in the set with greater numbers is how much greater than the sum of the integers in the other set? Choose the correct choice from the following answers
A) 24 B) 17 C) 28 D) 42 E) it can not be determined from the information given . | <gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">4 * 7</gadget>
<output>28</output>
<gadget id="calculator">70 - 28</gadget>
<output>42</output>
<result>D</result> | D | 42 | Two sets of 7 consecutive positive integers have exactly one integer in common. The sum of the integers in the set with greater numbers is how much greater than the sum of the integers in the other set? | {
"A": "24",
"B": "17",
"C": "28",
"D": "42",
"E": "it can not be determined from the information given ."
} | subtract(multiply(7, const_10), multiply(const_4, 7)) | multiply(n0,const_10)|multiply(n0,const_4)|subtract(#0,#1) | a = ( 1 , 2,3 , 4,5 , 6,7 ) , sum of this = 28 b = ( 7 , 8,9 , 10,11 , 12,13 ) , sum of this = 70 the differenct between 70 - 28 = 42 hence , 42 is the answer i . e . d | general |
math_qa__xyEv2AlSNY57K1ZH | A lady grows Cauliflower in her garden that is in the shape of a square. Each Cauliflower takes 1 square foot of area in her garden. This year, she has increased her output by 223 Cauliflower when compared to last year. The shape of the area used for growing the Cauliflower has remained a square in both these years. How many Cauliflowers did she produce this year? Choose one:
A) 12541
B) 12542
C) 12544
D) 12545
E) can not be determined | <gadget id="calculator">223 - 1</gadget>
<output>222</output>
<gadget id="calculator">222 / 2</gadget>
<output>111</output>
<gadget id="calculator">111 ** 2</gadget>
<output>12_321</output>
<gadget id="calculator">12_321 + 223</gadget>
<output>12_544</output>
<result>C</result> | C | 12,544 | A lady grows Cauliflower in her garden that is in the shape of a square. Each Cauliflower takes 1 square foot of area in her garden. This year, she has increased her output by 223 Cauliflower when compared to last year. The shape of the area used for growing the Cauliflower has remained a square in both these years. How many Cauliflowers did she produce this year? | {
"A": "12541",
"B": "12542",
"C": "12544",
"D": "12545",
"E": "can not be determined"
} | add(power(divide(subtract(223, 1), const_2), const_2), 223) | subtract(n1,n0)|divide(#0,const_2)|power(#1,const_2)|add(n1,#2) | explanatory answer the shape of the area used for growing cauliflower has remained a square in both the years . let the side of the square area used for growing cauliflower this year be x ft . therefore , the area of the ground used for cultivation this year = x 2 sq . ft . let the side of the square area used for growing cauliflower last year be y ft . therefore , the area of the ground used for cultivation last year = y 2 sq . ft . as the number of cauliflower grown has increased by 223 , the area would have increased by 223 sq ft because each cauliflower takes 1 sq ft space . hence , x 2 - y 2 = 223 ( x + y ) ( x - y ) = 223 . 223 is a prime number and hence it will have only two factors . i . e . , 223 and 1 . therefore , 223 can be expressed as product of 2 numbers in only way = 223 * 1 i . e . , ( x + y ) ( x - y ) = 223 * 1 so , ( x + y ) should be 223 and ( x - y ) should be 1 . solving the two equations we get x = 112 and y = 111 . therefore , number of cauliflower produced this year = x 2 = 1122 = 12544 . alternative approach : use answer choices the area in both the years are squares of two numbers . that rules out choice a , b and d . as 12541,12542 and 12545 are not the square of any number . check choice c : if this year ' s produce is 12544 , last year ' s produce would have been 12544 - 223 = 12321 12321 is the square of 111 . so , 12544 is the answer . choice c . | geometry |
math_qa__uJmSqMUgR9dp5keb | 12. What is the dividend. divisor 17, the quotient is 9 and the remainder is 9. Pick: A) 150 B) 162 C) 154 D) 158 E) 144 | <gadget id="calculator">17 * 9</gadget>
<output>153</output>
<gadget id="calculator">153 + 9</gadget>
<output>162</output>
<result>B</result> | B | 162 | 12. What is the dividend. divisor 17, the quotient is 9 and the remainder is 9. | {
"A": "150",
"B": "162",
"C": "154",
"D": "158",
"E": "144"
} | add(multiply(17, 9), 9) | multiply(n1,n2)|add(n3,#0)| | "d = d * q + r d = 17 * 9 + 9 d = 153 + 9 d = 162 answer b" | general |
math_qa__wpZkoc4mQm7QhdhD | A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr. find the time taken by the boat to go 68 km downstream?
Choices.
A) 2 hours B) 3 hours C) 4 hours D) 5 hours E) none | <gadget id="calculator">13 + 4</gadget>
<output>17</output>
<gadget id="calculator">68 / 17</gadget>
<output>4</output>
<result>C</result> | C | 4 | A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr. find the time taken by the boat to go 68 km downstream? | {
"A": "2 hours",
"B": "3 hours",
"C": "4 hours",
"D": "5 hours",
"E": "none"
} | divide(68, add(13, 4)) | add(n0,n1)|divide(n2,#0)| | "solution speed downstream = ( 13 + 4 ) km / hr = 17 km / hr . time taken to travel 68 km downstream = ( 68 / 17 ) hrs = 4 hrs . answer c" | physics |
math_qa__1BxcBC8xR4asbpkb | Find the cost of fencing around a circular field of diameter 42 m at the rate of Rs.3 a meter?
Choices:
A) 138 B) 390 C) 393 D) 279 E) 222 | <gadget id="calculator">42 / 2</gadget>
<output>21</output>
<gadget id="calculator">2 * pi * 21</gadget>
<output>42*pi = around 131.946891</output>
<gadget id="calculator">(42*pi) * 3</gadget>
<output>126*pi = around 395.840674</output>
<result>C</result> | C | 393 | Find the cost of fencing around a circular field of diameter 42 m at the rate of Rs.3 a meter? | {
"A": "138",
"B": "390",
"C": "393",
"D": "279",
"E": "222"
} | multiply(circumface(divide(42, const_2)), 3) | divide(n0,const_2)|circumface(#0)|multiply(n1,#1)| | "2 * 22 / 7 * 21 = 131 131 * 3 = rs . 393 answer : c" | physics |
math_qa__Jkke2rS1z5CgCObo | The average salary of all the workers in a workshop is Rs. 6750. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is? Choices
A) 23 B) 21 C) 52 D) 56 E) 12 | <gadget id="calculator">12_000 - 6_750</gadget>
<output>5_250</output>
<gadget id="calculator">7 * 5_250</gadget>
<output>36_750</output>
<gadget id="calculator">6_750 - 6_000</gadget>
<output>750</output>
<gadget id="calculator">36_750 / 750</gadget>
<output>49</output>
<gadget id="calculator">7 + 49</gadget>
<output>56</output>
<result>D</result> | D | 56 | The average salary of all the workers in a workshop is Rs. 6750. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is? | {
"A": "23",
"B": "21",
"C": "52",
"D": "56",
"E": "12"
} | add(7, divide(multiply(7, subtract(12000, 6750)), subtract(6750, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3)| | "let the total number of workers be x . then , 6750 x = ( 12000 * 7 ) + 6000 ( x - 7 ) = > 750 x = 42000 = x = 56 . answer : d" | general |
math_qa__cXGtQQKNKLtSDLKv | On dividinng 109 by a number, the quotient is 9 and the remainder is 1. Find the divisor.
Select: A) 12 B) 14 C) 15 D) 16 E) 17 | <gadget id="calculator">109 / 9</gadget>
<output>109/9 = around 12.111111</output>
<gadget id="calculator">floor(109/9)</gadget>
<output>12</output>
<result>A</result> | A | 12 | On dividinng 109 by a number, the quotient is 9 and the remainder is 1. Find the divisor. | {
"A": "12",
"B": "14",
"C": "15",
"D": "16",
"E": "17"
} | floor(divide(109, 9)) | divide(n0,n1)|floor(#0) | d = ( d - r ) / q = ( 109 - 1 ) / 9 = 108 / 9 = 18 a | general |
math_qa__RbWey9SLtGK1y8It | What is the compound interest paid on a sum of Rs.700 for the period of 2 years at 10% per annum. Choose the correct choice.
A) 130
B) 620
C) 147
D) 120
E) none of these | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 2</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">700 * (121/100)</gadget>
<output>847</output>
<gadget id="calculator">847 - 700</gadget>
<output>147</output>
<result>C</result> | C | 147 | What is the compound interest paid on a sum of Rs.700 for the period of 2 years at 10% per annum. | {
"A": "130",
"B": "620",
"C": "147",
"D": "120",
"E": "none of these"
} | subtract(multiply(700, power(add(const_1, divide(10, const_100)), 2)), 700) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|multiply(n0,#2)|subtract(#3,n0)| | "solution = interest % for 1 st year = 10 interest % for 2 nd year = 10 + 10 % of 10 = 10 + 10 * 10 / 100 = 11 total % of interest = 10 + 11 = 21 total interest = 21 % 700 = 700 * ( 21 / 100 ) = 147 answer c" | gain |
math_qa__jvOYgXZGX3J1KBuR | Fresh grapes contain 65% by weight while dried grapes contain 10% water by weight. What is the weight of dry grapes available from 400 kg of fresh grapes?
Choose the correct answer
A) 105.00 kg B) 115.60 kg C) 125.00 kg D) 130.50 kg E) 155.55 kg | <gadget id="calculator">100 - 65</gadget>
<output>35</output>
<gadget id="calculator">35 * 400</gadget>
<output>14_000</output>
<gadget id="calculator">14_000 / 100</gadget>
<output>140</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">140 / 90</gadget>
<output>14/9 = around 1.555556</output>
<gadget id="calculator">(14/9) * 100</gadget>
<output>1_400/9 = around 155.555556</output>
<result>E</result> | E | 155.55 | Fresh grapes contain 65% by weight while dried grapes contain 10% water by weight. What is the weight of dry grapes available from 400 kg of fresh grapes? | {
"A": "105.00 kg",
"B": "115.60 kg",
"C": "125.00 kg",
"D": "130.50 kg",
"E": "155.55 kg"
} | multiply(divide(divide(multiply(subtract(const_100, 65), 400), const_100), subtract(const_100, 10)), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|multiply(n2,#0)|divide(#2,const_100)|divide(#3,#1)|multiply(#4,const_100)| | "from the question we know : 400 kg * 65 % = 260 kg of water in the fresh grapes 400 kg - 260 kg of water = 140 kg of non - water mass we are looking for the weight of the dry grapes ( x ) . since the question tells us that 10 % of the weight of the dry graps is water and we know that 140 kg is non - water mass we can set up the following equation : x = 1 / 10 ( x ) + 140 kg 9 / 10 ( x ) = 140 kg x = 155.55 kg answer - e" | gain |
math_qa__HCQfTsvn0Z39QryZ | In a fuel station the service costs $2.20 per vehicle and every liter of fuel costs $0.70. Assuming that you fill up 4 mini-vans and 2 trucks, what will be the total cost, if a mini-van's tank is 65 liters and a truck's tank is 120% bigger and they are all empty? Choose the correct choice from the following options:
A) $ 382.10 B) $ 395.40 C) $ 404.30 D) $ 416.80 E) $ 426.50 | <gadget id="calculator">120 * 65</gadget>
<output>7_800</output>
<gadget id="calculator">7_800 / 100</gadget>
<output>78</output>
<gadget id="calculator">78 + 65</gadget>
<output>143</output>
<gadget id="calculator">143 * 2</gadget>
<output>286</output>
<gadget id="calculator">286 * 0.7</gadget>
<output>200.2</output>
<gadget id="calculator">4 * 65</gadget>
<output>260</output>
<gadget id="calculator">260 * 0.7</gadget>
<output>182</output>
<gadget id="calculator">200.2 + 182</gadget>
<output>382.2</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">2.2 * 6</gadget>
<output>13.2</output>
<gadget id="calculator">382.2 + 13.2</gadget>
<output>395.4</output>
<result>B</result> | B | 395.4 | In a fuel station the service costs $2.20 per vehicle and every liter of fuel costs $0.70. Assuming that you fill up 4 mini-vans and 2 trucks, what will be the total cost, if a mini-van's tank is 65 liters and a truck's tank is 120% bigger and they are all empty? | {
"A": "$ 382.10",
"B": "$ 395.40",
"C": "$ 404.30",
"D": "$ 416.80",
"E": "$ 426.50"
} | add(add(multiply(multiply(add(divide(multiply(120, 65), const_100), 65), 2), 0.70), multiply(multiply(4, 65), 0.70)), multiply(2.20, add(4, 2))) | add(n2,n3)|multiply(n4,n5)|multiply(n2,n4)|divide(#1,const_100)|multiply(n1,#2)|multiply(n0,#0)|add(n4,#3)|multiply(n3,#6)|multiply(n1,#7)|add(#8,#4)|add(#9,#5)| | "the service cost of 4 vans and 2 trucks is 6 * 2.20 $ 13.20 the fuel in 4 vans is 4 * 65 = 260 liters the fuel in 2 trucks is 2 * 65 * 2.2 = 286 liters the total fuel ( vans + trucks ) = 546 liters the total fuel cost is 546 * 0.7 = $ 382.20 the total cost is $ 382.20 + $ 13.20 = $ 395.40 the answer is b ." | general |
math_qa__lJGVJi50Lpv30vDW | A group of n students can be divided into equal groups of 4 with 1 student left over or equal groups of 7 with 4 students left over. What is the sum of the two smallest possible values of n? Select the correct option:
A) 66
B) 70
C) 74
D) 78
E) 82 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">14 + 4</gadget>
<output>18</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">7 * 8</gadget>
<output>56</output>
<gadget id="calculator">56 + 4</gadget>
<output>60</output>
<gadget id="calculator">18 + 60</gadget>
<output>78</output>
<result>D</result> | D | 78 | A group of n students can be divided into equal groups of 4 with 1 student left over or equal groups of 7 with 4 students left over. What is the sum of the two smallest possible values of n? | {
"A": "66",
"B": "70",
"C": "74",
"D": "78",
"E": "82"
} | add(add(multiply(7, const_2), 4), add(multiply(7, multiply(const_2, 4)), 4)) | multiply(n2,const_2)|multiply(const_2,n3)|add(n3,#0)|multiply(n2,#1)|add(n3,#3)|add(#2,#4)| | "n = 4 k + 1 = 7 j + 4 let ' s start at 1 = 4 ( 0 ) + 1 and keep adding 4 until we find a number in the form 7 j + 4 . 1 , 5 , 9 , 13 , 17 , 21 , 25 = 7 ( 3 ) + 4 the next such number is 25 + 4 * 7 = 53 . 25 + 53 = 78 the answer is d ." | general |
math_qa__oqJNAOcuzB7L1UbH | If an integer n is to be chosen at random from the integers 1 to 84, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8? Choose the correct choice from the following choices: A) 9 / 14 B) 3 / 8 C) 1 / 2 D) 5 / 8 E) 3 / 4 | <gadget id="calculator">84 / 2</gadget>
<output>42</output>
<gadget id="calculator">84 / 8</gadget>
<output>21/2 = around 10.5</output>
<gadget id="calculator">42 + (21/2)</gadget>
<output>105/2 = around 52.5</output>
<gadget id="calculator">(105/2) / 84</gadget>
<output>5/8 = around 0.625</output>
<result>A</result> | A | 0.642857 | If an integer n is to be chosen at random from the integers 1 to 84, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8? | {
"A": "9 / 14",
"B": "3 / 8",
"C": "1 / 2",
"D": "5 / 8",
"E": "3 / 4"
} | divide(add(divide(84, 2), divide(84, 8)), 84) | divide(n1,n3)|divide(n1,n4)|add(#0,#1)|divide(#2,n1)| | "n ( n + 1 ) ( n + 2 ) will be divisible by 8 when n is a multiple of 2 or when ( n + 1 ) is a multiple of 8 . thus when n is even , this whole expression will be divisible by 8 . from 1 to 84 , there are 42 even integers . now when ( n + 1 ) is multiple by 8 , we have 12 such values for ( n + 1 ) probability that n ( n + 1 ) ( n + 2 ) will be divisible by 8 = ( 42 + 12 ) / 84 = 54 / 84 = 9 / 14 ans is a" | general |
math_qa__EPjOHY9sKtjqhcqX | an auto assembly plant performs 6 functions with each frame that arrives : add axles , add wheels to the axles , install the windshield to the frame , install the instrument panel , install the steering wheel , and install the interior seating . once those 6 tasks are performed , each car goes to a separate building for finishing touches . if these tasks can be arranged along a linear assembly line in any order , except that the axles must be installed before the wheels can be added , how many y ways can the assembly line be arranged ? Choices.
A) 120 B) 240 C) 360 D) 480 E) 720 | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">24 * 10</gadget>
<output>240</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">240 + 120</gadget>
<output>360</output>
<result>C</result> | C | 360 | an auto assembly plant performs 6 functions with each frame that arrives : add axles , add wheels to the axles , install the windshield to the frame , install the instrument panel , install the steering wheel , and install the interior seating . once those 6 tasks are performed , each car goes to a separate building for finishing touches . if these tasks can be arranged along a linear assembly line in any order , except that the axles must be installed before the wheels can be added , how many y ways can the assembly line be arranged ? | {
"A": "120",
"B": "240",
"C": "360",
"D": "480",
"E": "720"
} | add(multiply(factorial(const_4), add(add(add(const_4, const_3), const_2), const_1)), factorial(subtract(6, const_1))) | add(const_3,const_4)|factorial(const_4)|subtract(n0,const_1)|add(#0,const_2)|factorial(#2)|add(#3,const_1)|multiply(#5,#1)|add(#4,#6) | c ) 360 short way : there are 6 c ! ways to do the six tasks . half will have wheels before axles and half will have axles before wheels . so we want y = 6 c ! / 2 - > 720 / 2 = 360 | general |
math_qa__QAC9whow8Stgei5L | If the cost price of 50 articles is equal to the selling price of 15 articles, then the gain or loss percent is? Choose the correct option:
A) 16
B) 127
C) 12
D) 18
E) 233 | <gadget id="calculator">100 * 15</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 50</gadget>
<output>30</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 30</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">100 * (7/3)</gadget>
<output>700/3 = around 233.333333</output>
<result>E</result> | E | 233 | If the cost price of 50 articles is equal to the selling price of 15 articles, then the gain or loss percent is? | {
"A": "16",
"B": "127",
"C": "12",
"D": "18",
"E": "233"
} | multiply(const_100, divide(subtract(const_100, divide(multiply(const_100, 15), 50)), divide(multiply(const_100, 15), 50))) | multiply(n1,const_100)|divide(#0,n0)|subtract(const_100,#1)|divide(#2,#1)|multiply(#3,const_100)| | "percentage of profit = 35 / 15 * 100 = 233 % answer : e" | gain |
math_qa__bm10ChnnVGbhGqtP | If the function Q is defined by the formula Q = 5e/(4x(z^2)), by what factor will Q be multiplied if e is quadrupled, x is doubled, and z is tripled?
Choose the correct choice from the following choices: A) 1 / 9 B) 2 / 9 C) 4 / 9 D) 3 / 9 E) 2 / 27 | <gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>
<result>B</result> | B | 0.222222 | If the function Q is defined by the formula Q = 5e/(4x(z^2)), by what factor will Q be multiplied if e is quadrupled, x is doubled, and z is tripled? | {
"A": "1 / 9",
"B": "2 / 9",
"C": "4 / 9",
"D": "3 / 9",
"E": "2 / 27"
} | divide(2, add(5, 4)) | add(n0,n1)|divide(n2,#0) | we just need to find the factor thats all , e - > quadrupled - > 4 e x - > doubled - > 2 x z - > tripled - > 3 z hence , z ^ 2 = 9 z ^ 2 e is in numerator , and x * z in denominator . hence , additional factor being introduced = 4 / 2 * 9 = 4 / 18 = 2 / 9 = b | general |
math_qa__lmwTEZj82CHZOOdw | A man rows his boat 95 km downstream and 60 km upstream, taking 2 hours each time. Find the speed of the stream? Choose the correct choice from the following choices
A) 76 kmph B) 6 kmph C) 9 kmph D) 8 kmph E) 4 kmph | <gadget id="calculator">95 / 2</gadget>
<output>95/2 = around 47.5</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">(95/2) - 30</gadget>
<output>35/2 = around 17.5</output>
<gadget id="calculator">(35/2) / 2</gadget>
<output>35/4 = around 8.75</output>
<result>C</result> | C | 9 | A man rows his boat 95 km downstream and 60 km upstream, taking 2 hours each time. Find the speed of the stream? | {
"A": "76 kmph",
"B": "6 kmph",
"C": "9 kmph",
"D": "8 kmph",
"E": "4 kmph"
} | divide(subtract(divide(95, 2), divide(60, 2)), const_2) | divide(n0,n2)|divide(n1,n2)|subtract(#0,#1)|divide(#2,const_2)| | "speed downstream = d / t = 95 / ( 2 ) = 48 kmph speed upstream = d / t = 60 / ( 2 ) = 30 kmph the speed of the stream = ( 48 - 30 ) / 2 = 9 kmph answer : c" | physics |
math_qa__IatX7Lls5iiHl0ya | A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 6% of bananas were rotten. Find the percentage of fruits in good condition?
Answers: A) 92.5 % B) 88.6 % C) 85.2 % D) 96.8 % E) 78.9 % | <gadget id="calculator">600 + 400</gadget>
<output>1_000</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">600 * (3/20)</gadget>
<output>90</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">400 * (3/50)</gadget>
<output>24</output>
<gadget id="calculator">90 + 24</gadget>
<output>114</output>
<gadget id="calculator">1_000 - 114</gadget>
<output>886</output>
<gadget id="calculator">886 / 1_000</gadget>
<output>443/500 = around 0.886</output>
<gadget id="calculator">(443/500) * 100</gadget>
<output>443/5 = around 88.6</output>
<result>B</result> | B | 88.6 | A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 6% of bananas were rotten. Find the percentage of fruits in good condition? | {
"A": "92.5 %",
"B": "88.6 %",
"C": "85.2 %",
"D": "96.8 %",
"E": "78.9 %"
} | multiply(divide(subtract(add(600, 400), add(multiply(600, divide(15, const_100)), multiply(400, divide(6, const_100)))), add(600, 400)), const_100) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|subtract(#0,#5)|divide(#6,#0)|multiply(#7,const_100)| | "total number of fruits shopkeeper bought = 600 + 400 = 1000 number of rotten oranges = 15 % of 600 = 15 / 100 × 600 = 9000 / 100 = 90 number of rotten bananas = 6 % of 400 = 24 therefore , total number of rotten fruits = 90 + 24 = 114 therefore number of fruits in good condition = 1000 - 114 = 886 therefore percentage of fruits in good condition = ( 886 / 1000 × 100 ) % = ( 88600 / 1000 ) % = 88.6 % answer : b" | gain |
math_qa__2pueU2K2CErMpokS | If a farmer sells 20 of his chickens, his stock of feed will last for 3 more days than planned, but if he buys 15 more chickens, he will run out of feed 4 days earlier than planned. If no chickens are sold or bought, the farmer will be exactly on schedule. How many chickens does the farmer have? Pick one
A) 40 B) 60 C) 80 D) 90 E) 100 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">5 * 12</gadget>
<output>60</output>
<result>B</result> | B | 60 | If a farmer sells 20 of his chickens, his stock of feed will last for 3 more days than planned, but if he buys 15 more chickens, he will run out of feed 4 days earlier than planned. If no chickens are sold or bought, the farmer will be exactly on schedule. How many chickens does the farmer have? | {
"A": "40",
"B": "60",
"C": "80",
"D": "90",
"E": "100"
} | multiply(add(const_2, const_3), multiply(4, 3)) | add(const_2,const_3)|multiply(n1,n3)|multiply(#0,#1) | let x = total feed required for the planned period n = number of chicken t = total time of the planned feed x = nt 1 ) x = ( n - 15 ) * ( t + 4 ) 2 ) x = ( n + 20 ) * ( t - 3 ) equating 1 & 2 ( n - 15 ) * ( t + 4 ) = ( n + 20 ) * ( t - 3 ) 7 n = 35 t n = 5 t x = n * n / 5 substituting this value in 1 n * n / 5 = ( n - 15 ) * ( n / 5 + 4 ) 5 n = 300 n = 60 b | general |
math_qa__TmOlwoSyzwSNfT4L | Which number can we add to 987654 to get a number exactly divisible by 456? Pick
A) 18 B) 24 C) 30 D) 36 E) 42 | <gadget id="calculator">987_654 % 456</gadget>
<output>414</output>
<gadget id="calculator">456 - 414</gadget>
<output>42</output>
<result>E</result> | E | 42 | Which number can we add to 987654 to get a number exactly divisible by 456? | {
"A": "18",
"B": "24",
"C": "30",
"D": "36",
"E": "42"
} | subtract(456, reminder(987654, 456)) | reminder(n0,n1)|subtract(n1,#0)| | "987654 / 456 = 2165 with a remainder of 414 . we need to add 456 - 414 = 42 the answer is e ." | general |
math_qa__IMYN4J8RsOLc8eFW | if 25 % of a number is subtracted from a second number , the second number reduces to its 4 - sixth . what is the ratio of the first number to the second number ?
Choose the correct answer: A) 5 : 3 B) 4 : 3 C) 6 : 3 D) 3 : 4 E) 5 : 4 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) / (1/4)</gadget>
<output>4/3 = around 1.333333</output>
<result>B</result> | B | 1.333333 | if 25 % of a number is subtracted from a second number , the second number reduces to its 4 - sixth . what is the ratio of the first number to the second number ? | {
"A": "5 : 3",
"B": "4 : 3",
"C": "6 : 3",
"D": "3 : 4",
"E": "5 : 4"
} | divide(subtract(const_1, divide(4, multiply(const_3, const_2))), divide(25, const_100)) | divide(n0,const_100)|multiply(const_2,const_3)|divide(n1,#1)|subtract(const_1,#2)|divide(#3,#0) | explanation : let the numbers be p & q q - p / 4 = 4 q / 6 = > q - 4 q / 6 = p / 4 = > 2 q / 6 = p / 4 = > p / q = 4 / 3 answer b | general |
math_qa__Tdmr1vv5NMdT67iD | The weight of a glass of jar is 10% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?
Pick:
A) 1 / 5 B) 1 / 3 C) 2 / 5 D) 1 / 2 E) 5 / 9 | <gadget id="calculator">60 - 10</gadget>
<output>50</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">50 / 90</gadget>
<output>5/9 = around 0.555556</output>
<result>E</result> | E | 0.555556 | The weight of a glass of jar is 10% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar? | {
"A": "1 / 5",
"B": "1 / 3",
"C": "2 / 5",
"D": "1 / 2",
"E": "5 / 9"
} | divide(subtract(60, 10), subtract(const_100, 10)) | subtract(n1,n0)|subtract(const_100,n0)|divide(#0,#1)| | "let weight of jar filled with beans = 100 g weight of jar = 10 g weight of coffee beans = 90 g weight of jar and remaining beans = 60 g weight of remaining beans = 50 g fraction remaining = 50 / 90 = 5 / 9 answer is e ." | gain |
math_qa__8P2uWl5T7EjKvY8g | The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of Rs.800 per sq. metre.
Choose the correct option:
A) 16200 B) 16350 C) 16500 D) 16750 E) 16250 | <gadget id="calculator">5.5 * 3.75</gadget>
<output>20.625</output>
<gadget id="calculator">800 * 20.625</gadget>
<output>16_500</output>
<result>C</result> | C | 16,500 | The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of Rs.800 per sq. metre. | {
"A": "16200",
"B": "16350",
"C": "16500",
"D": "16750",
"E": "16250"
} | multiply(800, multiply(5.5, 3.75)) | multiply(n0,n1)|multiply(n2,#0)| | "area = 5.5 × 3.75 sq . metre . cost for 1 sq . metre . = rs . 800 hence , total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = rs . 16500 answer is c ." | physics |
math_qa__UJkZcwwje5AFy2Jm | The sum of the even numbers between 1 and n is 105*106, where n is an odd number, then n=?
Pick one:
A) 187 B) 193 C) 199 D) 205 E) 211 | <gadget id="calculator">105 * 2</gadget>
<output>210</output>
<gadget id="calculator">210 + 1</gadget>
<output>211</output>
<result>E</result> | E | 211 | The sum of the even numbers between 1 and n is 105*106, where n is an odd number, then n=? | {
"A": "187",
"B": "193",
"C": "199",
"D": "205",
"E": "211"
} | add(multiply(105, const_2), const_1) | multiply(n1,const_2)|add(#0,const_1) | let n - 1 = 2 a . 2 + 4 + . . . + 2 a = 2 * ( 1 + 2 + . . . + a ) = 2 * ( a ) ( a + 1 ) / 2 = ( a ) ( a + 1 ) = 105 * 106 then a = 105 and n = 211 . the answer is e . | general |
math_qa__wBOndgSquSdobEUp | o mow a grass field a team of mowers planned to cover 15 hectares a day. After 4 working days they increased the daily productivity by 33×13%33×13%, and finished the work 1 day earlier than it was planned.
A) What is the area of the grass field?
B) How many days did it take to mow the whole field?
C) How many days were scheduled initially for this job? Options:
A) 387
B) 39
C) 37
D) 20
E) 28 | <gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">15 + 5</gadget>
<output>20</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">15 * 4</gadget>
<output>60</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">40 / 5</gadget>
<output>8</output>
<gadget id="calculator">15 * 8</gadget>
<output>120</output>
<gadget id="calculator">120 % 100</gadget>
<output>20</output>
<result>D</result> | D | 20 | o mow a grass field a team of mowers planned to cover 15 hectares a day. After 4 working days they increased the daily productivity by 33×13%33×13%, and finished the work 1 day earlier than it was planned.
A) What is the area of the grass field?
B) How many days did it take to mow the whole field?
C) How many days were scheduled initially for this job? | {
"A": "387",
"B": "39",
"C": "37",
"D": "20",
"E": "28"
} | reminder(multiply(15, divide(subtract(multiply(add(15, divide(15, const_3)), add(4, 1)), multiply(15, 4)), subtract(add(15, divide(15, const_3)), 15))), const_100) | add(n1,n6)|divide(n0,const_3)|multiply(n0,n1)|add(n0,#1)|multiply(#3,#0)|subtract(#3,n0)|subtract(#4,#2)|divide(#6,#5)|multiply(n0,#7)|reminder(#8,const_100) | hint : see problem 20 and solve by yourself . answer : a ) 120 hectares ; b ) 7 days ; c ) 8 days . answer : d | general |
math_qa__pywFuBvBwBs74rSK | If (20)² is subtracted from the square of a number, the answer so obtained is 4321. What is the number? Choose the correct answer
A) 68 B) 69 C) 70 D) 71 E) 72 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">4_321 + 400</gadget>
<output>4_721</output>
<gadget id="calculator">4_721 ** (1/2)</gadget>
<output>sqrt(4721) = around 68.709534</output>
<result>B</result> | B | 69 | If (20)² is subtracted from the square of a number, the answer so obtained is 4321. What is the number? | {
"A": "68",
"B": "69",
"C": "70",
"D": "71",
"E": "72"
} | sqrt(add(4321, power(multiply(const_2, const_10), const_2))) | multiply(const_10,const_2)|power(#0,const_2)|add(n1,#1)|sqrt(#2) | x ^ 2 = 4321 + 400 = 4721 4761 = 69 * 69 x = 69 answer : b | geometry |
math_qa__2Evgwob8r0eXhEFP | Excluding stoppages, the speed of a bus is 60 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? Select the correct option: A) 10 min B) 12 min C) 18 min D) 20 min E) 15 min | <gadget id="calculator">60 - 45</gadget>
<output>15</output>
<gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">60 * (1/4)</gadget>
<output>15</output>
<result>E</result> | E | 15 | Excluding stoppages, the speed of a bus is 60 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? | {
"A": "10 min",
"B": "12 min",
"C": "18 min",
"D": "20 min",
"E": "15 min"
} | multiply(const_60, divide(subtract(60, 45), 60)) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)| | "due to stoppages , it covers 15 km less . time taken to cover 15 km = ( 15 / 60 x 60 ) min = 15 min answer : e" | physics |
math_qa__axgEsWC16CmaGutQ | The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is: Choose the correct answer
A) 4050 B) 3500 C) 4000 D) 4500 E) 5000 | <gadget id="calculator">5_050 + 5_200</gadget>
<output>10_250</output>
<gadget id="calculator">10_250 - 6_250</gadget>
<output>4_000</output>
<result>C</result> | C | 4,000 | The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is: | {
"A": "4050",
"B": "3500",
"C": "4000",
"D": "4500",
"E": "5000"
} | subtract(add(5050, 5200), 6250) | add(n0,n2)|subtract(#0,n1) | let p , q and r represent their respective monthly incomes . then , we have : p + q = ( 5050 x 2 ) = 10100 . . . . ( i ) q + r = ( 6250 x 2 ) = 12500 . . . . ( ii ) p + r = ( 5200 x 2 ) = 10400 . . . . ( iii ) adding ( i ) , ( ii ) and ( iii ) , we get : 2 ( p + q + r ) = 33000 or p + q + r = 16500 . . . . ( iv ) subtracting ( ii ) from ( iv ) , we get p = 4000 . p ' s monthly income = rs . 4000 . answer : c | general |
math_qa__qC8bCOPlK493gBTT | If (1/2)^23 (1/81)^k = 1/18^23, then k =
Choose the correct choice from the following choices:
A) 8 B) 12 C) 16 D) 24 E) 46 / 4 | <gadget id="calculator">23 * 2</gadget>
<output>46</output>
<gadget id="calculator">46 / 4</gadget>
<output>23/2 = around 11.5</output>
<result>E</result> | E | 11.5 | If (1/2)^23 (1/81)^k = 1/18^23, then k = | {
"A": "8",
"B": "12",
"C": "16",
"D": "24",
"E": "46 / 4"
} | divide(multiply(23, 2), const_4) | multiply(n1,n2)|divide(#0,const_4)| | "i ' m going to focus on denominator only . . ( 2 ^ 23 ) . ( ( 3 ^ 4 ) ^ k = 18 ^ 23 ( 2 ^ 23 ) . ( ( 3 ^ 4 k ) = ( 2 . 3 ^ 2 ) ^ 23 ( 2 ^ 23 ) . ( ( 3 ^ 4 k ) = ( 2 ^ 23 ) . ( 3 ^ 2 ) ^ 23 hence 4 k = 46 k = 46 / 4 answer e i hope it ' s quite clear" | general |
math_qa__fKPkhNvPGH1WDYPG | The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $90 per day. What was his wage on the 8th day?
Pick:
A) $ 83 B) $ 90 C) $ 92 D) $ 97 E) $ 111 | <gadget id="calculator">90 * 15</gadget>
<output>1_350</output>
<gadget id="calculator">87 * 7</gadget>
<output>609</output>
<gadget id="calculator">90 * 7</gadget>
<output>630</output>
<gadget id="calculator">609 + 630</gadget>
<output>1_239</output>
<gadget id="calculator">1_350 - 1_239</gadget>
<output>111</output>
<result>E</result> | E | 111 | The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $90 per day. What was his wage on the 8th day? | {
"A": "$ 83",
"B": "$ 90",
"C": "$ 92",
"D": "$ 97",
"E": "$ 111"
} | subtract(multiply(90, 15), add(multiply(87, 7), multiply(90, 7))) | multiply(n0,n1)|multiply(n2,n3)|multiply(n2,n5)|add(#1,#2)|subtract(#0,#3)| | "average daily wage of a worker for 15 consecutive working days = 90 $ during the first 7 days , the daily average daily wage = 87 $ during the last 7 days , the daily average daily wage = 90 $ wage on 8 th day = 90 * 15 - ( 87 * 7 + 90 * 7 ) = 1350 - ( 609 + 630 ) = 1350 - 1239 = 111 answer e" | physics |
math_qa__tb1OyD92dqTd9Eqm | A certain company expects quarterly earnings of $0.80 per share of stock, half of which will be distributed as dividends to shareholders while the rest will be used for research and development. If earnings are greater than expected , shareholders will receive an additional $0.04 per share for each additional $0.10 of per share earnings. If quarterly earnings are $1.10 per share, what will be the dividend paid to a person who owns 400 shares of the company's stock?
Select the correct option.
A) $ 208
B) $ 96
C) $ 104
D) $ 120
E) $ 240 | <gadget id="calculator">0.8 / 2</gadget>
<output>0.4</output>
<gadget id="calculator">1.1 - 0.8</gadget>
<output>0.3</output>
<gadget id="calculator">0.3 * 10</gadget>
<output>3</output>
<gadget id="calculator">3 * 0.04</gadget>
<output>0.12</output>
<gadget id="calculator">0.4 + 0.12</gadget>
<output>0.52</output>
<gadget id="calculator">0.52 * 400</gadget>
<output>208</output>
<result>A</result> | A | 208 | A certain company expects quarterly earnings of $0.80 per share of stock, half of which will be distributed as dividends to shareholders while the rest will be used for research and development. If earnings are greater than expected , shareholders will receive an additional $0.04 per share for each additional $0.10 of per share earnings. If quarterly earnings are $1.10 per share, what will be the dividend paid to a person who owns 400 shares of the company's stock? | {
"A": "$ 208",
"B": "$ 96",
"C": "$ 104",
"D": "$ 120",
"E": "$ 240"
} | multiply(add(divide(0.80, const_2), multiply(multiply(subtract(1.10, 0.80), const_10), 0.04)), 400) | divide(n0,const_2)|subtract(n3,n0)|multiply(#1,const_10)|multiply(n1,#2)|add(#0,#3)|multiply(n4,#4)| | "eps actual > eps expected . each gets and additional . 12 per share . thus . 52 * 400 - - > $ 208 answer is a" | general |
math_qa__GvlyK5u5MJ1hPRWK | The content of several smaller cylinders ( 3 meter diameter and 6 meter height) were to be emptied into a larger cylinder(20 meter diameter and 10 meter height), how many smaller cylinders will fill up the larger cylinder? Choose the correct choice from the following
A) 20 B) 10 C) 50 D) 74 E) 73 | <gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">pi * (10 ** 2) * 10</gadget>
<output>1000*pi = around 3_141.592654</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">pi * ((3/2) ** 2) * 6</gadget>
<output>27*pi/2 = around 42.411501</output>
<gadget id="calculator">(1000*pi) / (27*pi/2)</gadget>
<output>2_000/27 = around 74.074074</output>
<result>D</result> | D | 74 | The content of several smaller cylinders ( 3 meter diameter and 6 meter height) were to be emptied into a larger cylinder(20 meter diameter and 10 meter height), how many smaller cylinders will fill up the larger cylinder? | {
"A": "20",
"B": "10",
"C": "50",
"D": "74",
"E": "73"
} | divide(volume_cylinder(divide(20, const_2), 10), volume_cylinder(divide(3, const_2), 6)) | divide(n2,const_2)|divide(n0,const_2)|volume_cylinder(#0,n3)|volume_cylinder(#1,n1)|divide(#2,#3) | calculate the volume of the larger cylinder and divide it by the volume of the smaller cylinder . volume of cylinder = π r 2 h larger cylinder volume = 3141.59 smaller cylinder volume = 42.41 therefore the number of cylinders b that can be filled to capacity = 3141.59 / 42.41 = 74.1 answer is d 74 smaller cylinders can be filled to capacity . | geometry |
math_qa__75wHdPKuWJWn1oBu | If n is a positive integer and the product of all integers from 1 to n, inclusive, is a multiple of 840, what is the least possible value of n?
Pick one:
A) 5 B) 6 C) 7 D) 8 E) 9 | <gadget id="calculator">840 / 2</gadget>
<output>420</output>
<gadget id="calculator">420 / 3</gadget>
<output>140</output>
<gadget id="calculator">140 / 4</gadget>
<output>35</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">35 / 5</gadget>
<output>7</output>
<result>C</result> | C | 7 | If n is a positive integer and the product of all integers from 1 to n, inclusive, is a multiple of 840, what is the least possible value of n? | {
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "9"
} | divide(divide(divide(divide(840, const_2), const_3), const_4), divide(const_10, const_2)) | divide(n1,const_2)|divide(const_10,const_2)|divide(#0,const_3)|divide(#2,const_4)|divide(#3,#1) | 840 = 2 * 2 * 2 * 3 * 5 * 7 , so n must be at least 7 . the answer is c . | general |
math_qa__hFNkneK44VpabhnW | A semicircle has a radius of 9. What is the approximate perimeter of the semicircle? Choose the most appropriate option.
A) 16 B) 25 C) 33 D) 46 E) 58 | <gadget id="calculator">2 * pi * 9</gadget>
<output>18*pi = around 56.548668</output>
<gadget id="calculator">(18*pi) / 2</gadget>
<output>9*pi = around 28.274334</output>
<gadget id="calculator">2 * 9</gadget>
<output>18</output>
<gadget id="calculator">(9*pi) + 18</gadget>
<output>18 + 9*pi = around 46.274334</output>
<result>D</result> | D | 46 | A semicircle has a radius of 9. What is the approximate perimeter of the semicircle? | {
"A": "16",
"B": "25",
"C": "33",
"D": "46",
"E": "58"
} | add(divide(circumface(9), const_2), multiply(const_2, 9)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "the perimeter of a circle is 2 * pi * r . the perimeter of a semicircle is 2 * pi * r / 2 + 2 r = pi * r + 2 r the perimeter is pi * 9 + 2 * 9 which is about 46 . the answer is d ." | geometry |
math_qa__PVpUQQIMOnRoT86R | Calculate 469158 x 9999 = ?
Answers
A) 4586970843
B) 4686970743
C) 4691100843
D) 4586870843
E) 4691110842 | <gadget id="calculator">469_158 * 9_999</gadget>
<output>4_691_110_842</output>
<result>E</result> | E | 4,691,110,842 | Calculate 469158 x 9999 = ? | {
"A": "4586970843",
"B": "4686970743",
"C": "4691100843",
"D": "4586870843",
"E": "4691110842"
} | multiply(469158, 9999) | multiply(n0,n1)| | "answer 469158 x 9999 = 469157 x ( 10000 - 1 ) = 4691580000 - 469158 = 4691110842 . option : e" | general |
math_qa__d3uQ1UUZPElwbCLz | 33 1/3% OF 210?
Pick: A) 70 B) 90 C) 110 D) 120 E) 130 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">33 + (1/3)</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(100/3) * 210</gadget>
<output>7_000</output>
<gadget id="calculator">7_000 / 100</gadget>
<output>70</output>
<result>A</result> | A | 70 | 33 1/3% OF 210? | {
"A": "70",
"B": "90",
"C": "110",
"D": "120",
"E": "130"
} | divide(multiply(add(33, divide(1, 3)), 210), const_100) | divide(n1,n2)|add(n0,#0)|multiply(n3,#1)|divide(#2,const_100)| | "33 1 / 3 % = 1 / 3 1 / 3 × 210 = 70 a )" | gain |
math_qa__jVAgi2At5bIEjqkU | On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 40 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets? Choose the correct choice: A) 33.3 % B) 40 % C) 50 % D) 60 % E) 66.6 % | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">20 / (3/5)</gadget>
<output>100/3 = around 33.333333</output>
<result>A</result> | A | 33.3 | On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 40 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets? | {
"A": "33.3 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "66.6 %"
} | divide(20, divide(subtract(const_100, 40), const_100)) | subtract(const_100,n1)|divide(#0,const_100)|divide(n0,#1)| | "0.20 p = rt + c 0.4 ( rt ) = no c = > 0.60 ( rt ) had c 0.20 p = 0.60 ( rt ) rt / p = 1 / 3 = 33 % answer - a" | gain |
math_qa__asjatuxCv2bfldVg | A man has some hens and cows. If the number of heads be 48 and the number of feet equals 136, then the number of hens will be: Choose the correct choice from the following answers
A) 22 B) 23 C) 24 D) 26 E) 28 | <gadget id="calculator">48 * 4</gadget>
<output>192</output>
<gadget id="calculator">192 - 136</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<result>E</result> | E | 28 | A man has some hens and cows. If the number of heads be 48 and the number of feet equals 136, then the number of hens will be: | {
"A": "22",
"B": "23",
"C": "24",
"D": "26",
"E": "28"
} | divide(subtract(multiply(48, const_4), 136), const_2) | multiply(n0,const_4)|subtract(#0,n1)|divide(#1,const_2)| | "let hens be x and cows be y now , feet : x * 2 + y * 4 = 136 heads : x * 1 + y * 1 = 48 implies , 2 x + 4 y = 136 and x + y = 48 solving these two equations , we get x = 28 and y = 20 therefore , hens are 28 . answer : e" | general |
math_qa__vTuv3zUNYGomtAnH | Hillary and Eddy are climbing to the summit of Mt. Everest from a base camp 5,100 ft from the summit. When they depart for the summit at 06:00, Hillary climbs at a rate of 800 ft/hr with Eddy lagging behind at a slower rate of 500 ft/hr. If Hillary stops 1100 ft short of the summit and then descends at a rate of 1,000 ft/hr, at what time do Hillary and Eddy pass each other on her return trip?
Pick
A) 14.0
B) 9.0
C) 10.0
D) 11.0
E) 12.0 | <gadget id="calculator">500 / 100</gadget>
<output>5</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">800 / 1_100</gadget>
<output>8/11 = around 0.727273</output>
<gadget id="calculator">4 / (8/11)</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">500 / 1_100</gadget>
<output>5/11 = around 0.454545</output>
<gadget id="calculator">(8/11) - (5/11)</gadget>
<output>3/11 = around 0.272727</output>
<gadget id="calculator">(11/2) * (3/11)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(5/11) + 1</gadget>
<output>16/11 = around 1.454545</output>
<gadget id="calculator">(3/2) / (16/11)</gadget>
<output>33/32 = around 1.03125</output>
<gadget id="calculator">(33/32) + (11/2)</gadget>
<output>209/32 = around 6.53125</output>
<gadget id="calculator">6 + (209/32)</gadget>
<output>401/32 = around 12.53125</output>
<result>E</result> | E | 12 | Hillary and Eddy are climbing to the summit of Mt. Everest from a base camp 5,100 ft from the summit. When they depart for the summit at 06:00, Hillary climbs at a rate of 800 ft/hr with Eddy lagging behind at a slower rate of 500 ft/hr. If Hillary stops 1100 ft short of the summit and then descends at a rate of 1,000 ft/hr, at what time do Hillary and Eddy pass each other on her return trip? | {
"A": "14.0",
"B": "9.0",
"C": "10.0",
"D": "11.0",
"E": "12.0"
} | add(06, add(divide(multiply(divide(subtract(divide(500, const_100), const_1), divide(800, 1100)), subtract(divide(800, 1100), divide(500, 1100))), add(divide(500, 1100), const_1)), divide(subtract(divide(500, const_100), const_1), divide(800, 1100)))) | divide(n4,const_100)|divide(n3,n5)|divide(n4,n5)|add(#2,const_1)|subtract(#0,const_1)|subtract(#1,#2)|divide(#4,#1)|multiply(#6,#5)|divide(#7,#3)|add(#8,#6)|add(n1,#9)| | "solution : h stopped 800 ft before reaching the final point , time taken to reach 4000 ft = 4000 / 800 = 5 hrs . this means she reached there at 11 : 00 . speed difference between them is 800 - 500 = 300 ft / hr so by the time h stops they have 1500 ft of distance so now here we use relative speed formula they both are travelling toward each other with speed of 1000 and 500 total 1500 ft / hr and distance between them is 1500 ft so time taken to meet = 1 hr from 11 : 00 means 12 : 00 is the answer . e" | general |
math_qa__HRRyXZcWbxFqWBzW | An error 6% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is Choose the correct answer.
A) 12.04 % B) 14.14 % C) 12.36 % D) 12.26 % E) 15.5 % | <gadget id="calculator">100 + 6</gadget>
<output>106</output>
<gadget id="calculator">106 ** 2</gadget>
<output>11_236</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">11_236 - 10_000</gadget>
<output>1_236</output>
<gadget id="calculator">1_236 * 100</gadget>
<output>123_600</output>
<gadget id="calculator">123_600 / 10_000</gadget>
<output>309/25 = around 12.36</output>
<result>D</result> | D | 12.26 | An error 6% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is | {
"A": "12.04 %",
"B": "14.14 %",
"C": "12.36 %",
"D": "12.26 %",
"E": "15.5 %"
} | divide(multiply(subtract(square_area(add(const_100, 6)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)| | "100 cm is read as 102 cm . a 1 = ( 100 x 100 ) cm 2 and a 2 ( 106 x 106 ) cm 2 . ( a 2 - a 1 ) = [ ( 106 ) 2 - ( 100 ) 2 ] = ( 106 + 100 ) x ( 106 - 100 ) = 1236 cm 2 . percentage error = 12.36 % d" | gain |
math_qa__z2Javlh8j5WPQj2s | In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is: Pick
A) 86 B) 88 C) 92 D) 94 E) 96 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 + 2</gadget>
<output>20</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">20 * 4</gadget>
<output>80</output>
<gadget id="calculator">80 + 6</gadget>
<output>86</output>
<result>A</result> | A | 86 | In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is: | {
"A": "86",
"B": "88",
"C": "92",
"D": "94",
"E": "96"
} | add(multiply(add(multiply(6, const_3), 2), divide(add(multiply(6, const_3), 2), 5)), 6) | multiply(n0,const_3)|add(n2,#0)|divide(#1,n1)|multiply(#1,#2)|add(n0,#3)| | "divisor = ( 6 * 3 ) + 2 = 20 5 * quotient = 20 quotient = 4 . dividend = ( divisor * quotient ) + remainder dividend = ( 20 * 4 ) + 6 = 86 . a" | general |
math_qa__jiqsXoaxbeQ5N2VG | A man is 22 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is Choose the correct choice from the following choices.
A) 21 years
B) 22 years
C) 20 years
D) 24 years
E) 26 years | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">22 - 2</gadget>
<output>20</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">20 / 1</gadget>
<output>20</output>
<result>C</result> | C | 20 | A man is 22 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is | {
"A": "21 years",
"B": "22 years",
"C": "20 years",
"D": "24 years",
"E": "26 years"
} | divide(subtract(22, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1)) | multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)| | "explanation : let ' s son age is x , then father age is x + 22 . = > 2 ( x + 2 ) = ( x + 22 + 2 ) = > 2 x + 4 = x + 24 = > x = 20 years option c" | general |
math_qa__dg9EDHsP7eaLZcPE | A train 55 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going? Choices:
A) 7 sec B) 5 sec C) 4 sec D) 6 sec E) 3 sec | <gadget id="calculator">55 / 1_000</gadget>
<output>11/200 = around 0.055</output>
<gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">(11/200) / 66</gadget>
<output>1/1_200 = around 0.000833</output>
<gadget id="calculator">3_600 * (1/1_200)</gadget>
<output>3</output>
<result>E</result> | E | 3 | A train 55 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going? | {
"A": "7 sec",
"B": "5 sec",
"C": "4 sec",
"D": "6 sec",
"E": "3 sec"
} | multiply(const_3600, divide(divide(55, const_1000), add(60, 6))) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_3600)| | "speed of train relative to man = ( 60 + 6 ) km / hr = 66 km / hr [ 66 * 5 / 18 ] m / sec = [ 55 / 3 ] m / sec . time taken to pass the man = [ 55 * 3 / 55 ] sec = 3 sec answer : e" | physics |
math_qa__8XvUA4YbmJgOvN6X | How long will a boy take to run round a square field of side 60 meters, if he runs at the rate of 12km/hr? Choices:
A) 52 sec B) 45 sec C) 72 sec D) 25 sec E) 39 sec | <gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">1_000 / 3_600</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">12 * (5/18)</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">240 / (10/3)</gadget>
<output>72</output>
<result>C</result> | C | 72 | How long will a boy take to run round a square field of side 60 meters, if he runs at the rate of 12km/hr? | {
"A": "52 sec",
"B": "45 sec",
"C": "72 sec",
"D": "25 sec",
"E": "39 sec"
} | divide(multiply(60, const_4), multiply(12, divide(const_1000, const_3600))) | divide(const_1000,const_3600)|multiply(n0,const_4)|multiply(n1,#0)|divide(#1,#2)| | "speed = 12 km / hr = 12 * 5 / 18 = 10 / 3 m / sec distance = 60 * 4 = 240 m time taken = 240 * 3 / 10 = 72 sec answer is c" | gain |
math_qa__ie0yTnHmzhRg6oyT | In a market, a dozen eggs cost as much as a pound of rice, and a half-liter of kerosene costs as much as 6 eggs. If the cost of each pound of rice is $0.24, then how many cents does a liter of kerosene cost? [One dollar has 100 cents.] Choose the correct option:
A) 0.20 B) 0.24 C) 20 D) 24 E) 55 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">6 / (1/2)</gadget>
<output>12</output>
<gadget id="calculator">12 / 12</gadget>
<output>1</output>
<gadget id="calculator">0.24 * 100</gadget>
<output>24</output>
<gadget id="calculator">1 * 24</gadget>
<output>24</output>
<result>D</result> | D | 24 | In a market, a dozen eggs cost as much as a pound of rice, and a half-liter of kerosene costs as much as 6 eggs. If the cost of each pound of rice is $0.24, then how many cents does a liter of kerosene cost? [One dollar has 100 cents.] | {
"A": "0.20",
"B": "0.24",
"C": "20",
"D": "24",
"E": "55"
} | multiply(divide(divide(6, divide(const_1, const_2)), const_12), multiply(0.24, 100)) | divide(const_1,const_2)|multiply(n1,n2)|divide(n0,#0)|divide(#2,const_12)|multiply(#3,#1)| | "a dozen eggs cost as much as a pound of rice - - > 12 eggs = 1 pound of rice = 24 cents ; a half - liter of kerosene costs as much as 6 eggs - - > 6 eggs = 1 / 2 liters of kerosene . how many cents does a liter of kerosene cost - - > 1 liter of kerosene = 12 eggs = 12 / 12 * 24 = 24 cents . answer : d ." | general |
math_qa__RDsgHFtyJif0XbwD | Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 1 : 2?
A. 48 kmph
Pick:
A) 33
B) 360 / 7
C) 28
D) 27 / 8
E) 16 | <gadget id="calculator">40 + 60</gadget>
<output>100</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<result>B</result> | B | 51.428571 | Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 1 : 2?
A. 48 kmph | {
"A": "33",
"B": "360 / 7",
"C": "28",
"D": "27 / 8",
"E": "16"
} | divide(add(40, 60), 2) | add(n0,n1)|divide(#0,n3) | let the distances between city a to b and b to c be x km and 2 x km respectively . total time taken to cover from a to c = ( x ) / 40 + ( 2 x ) / 60 = ( 3 x + 4 x ) / 120 = 7 x / 120 average speed = ( x + 2 x ) / ( 7 x / 120 ) = 360 / 7 kmph . answer : b | physics |
math_qa__tDQT3ka5ryJzLrAa | A’s speed is 30/17 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat? Choose the correct choice from the following answers:
A) 1 / 17 B) 13 / 30 C) 17 / 30 D) 11 / 30 E) 11 / 13 | <gadget id="calculator">30 - 17</gadget>
<output>13</output>
<gadget id="calculator">13 / 30</gadget>
<output>13/30 = around 0.433333</output>
<result>B</result> | B | 0.433333 | A’s speed is 30/17 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat? | {
"A": "1 / 17",
"B": "13 / 30",
"C": "17 / 30",
"D": "11 / 30",
"E": "11 / 13"
} | divide(subtract(30, 17), 30) | subtract(n0,n1)|divide(#0,n0)| | "we have the ratio of a ’ s speed and b ’ s speed . this means , we know how much distance a covers compared with b in the same time . this is what the beginning of the race will look like : ( start ) a _________ b ______________________________ if a covers 30 meters , b covers 17 meters in that time . so if the race is 30 meters long , when a reaches the finish line , b would be 13 meters behind him . if we want the race to end in a dead heat , we want b to be at the finish line too at the same time . this means b should get a head start of 13 meters so that he doesn ’ t need to cover that . in that case , the time required by a ( to cover 30 meters ) would be the same as the time required by b ( to cover 17 meters ) to reach the finish line . so b should get a head start of 13 / 30 th of the race . answer ( b )" | general |
math_qa__3hfoikeJTf7DS9Sw | A cycle is bought for Rs.670 and sold for Rs.780, find the gain percent?
Select.
A) 70 % B) 20 % C) 16 % D) 19 % E) 80 % | <gadget id="calculator">780 - 670</gadget>
<output>110</output>
<gadget id="calculator">110 / 670</gadget>
<output>11/67 = around 0.164179</output>
<gadget id="calculator">(11/67) * 100</gadget>
<output>1_100/67 = around 16.41791</output>
<result>C</result> | C | 16 | A cycle is bought for Rs.670 and sold for Rs.780, find the gain percent? | {
"A": "70 %",
"B": "20 %",
"C": "16 %",
"D": "19 %",
"E": "80 %"
} | multiply(divide(subtract(780, 670), 670), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : 670 - - - - 110 100 - - - - ? = > 16 % answer : c" | gain |
math_qa__edWsbIWLXmMuMWeU | The cost of 10 kg of mangos is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is $22. Find the total cost of 4 kg of mangos, 3 kg of rice and 5 kg of flour? Choose the correct choice from the following choices:
A) 347.6
B) 987.6
C) 941.6
D) 637.6
E) 667.6 | <gadget id="calculator">24 / 10</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">22 * 6</gadget>
<output>132</output>
<gadget id="calculator">132 / 2</gadget>
<output>66</output>
<gadget id="calculator">(12/5) * 66</gadget>
<output>792/5 = around 158.4</output>
<gadget id="calculator">4 * (792/5)</gadget>
<output>3_168/5 = around 633.6</output>
<gadget id="calculator">3 * 66</gadget>
<output>198</output>
<gadget id="calculator">(3_168/5) + 198</gadget>
<output>4_158/5 = around 831.6</output>
<gadget id="calculator">5 * 22</gadget>
<output>110</output>
<gadget id="calculator">(4_158/5) + 110</gadget>
<output>4_708/5 = around 941.6</output>
<result>C</result> | C | 941.6 | The cost of 10 kg of mangos is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is $22. Find the total cost of 4 kg of mangos, 3 kg of rice and 5 kg of flour? | {
"A": "347.6",
"B": "987.6",
"C": "941.6",
"D": "637.6",
"E": "667.6"
} | add(add(multiply(4, multiply(divide(24, 10), divide(multiply(22, 6), 2))), multiply(3, divide(multiply(22, 6), 2))), multiply(5, 22)) | divide(n1,n0)|multiply(n2,n4)|multiply(n4,n7)|divide(#1,n3)|multiply(#0,#3)|multiply(n6,#3)|multiply(n5,#4)|add(#6,#5)|add(#7,#2)| | "let the costs of each kg of mangos and each kg of rice be $ a and $ r respectively . 10 a = 24 r and 6 * 22 = 2 r a = 12 / 5 r and r = 66 a = 158.4 required total cost = 4 * 158.4 + 3 * 66 + 5 * 22 = 633.6 + 198 + 110 = $ 941.60 c" | general |
math_qa__Y2i8L2Zz8jbCRnqx | A shopkeeper sold an article offering a discount of 5% and earned a profit of 20.65%. What would have been the percentage of profit earned if no discount was offered?
Choose the correct answer:
A) 60 %
B) 27 %
C) 30 %
D) 56 %
E) 73 % | <gadget id="calculator">100 + 20.65</gadget>
<output>120.65</output>
<gadget id="calculator">120.65 * 100</gadget>
<output>12_065</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">12_065 / 95</gadget>
<output>127</output>
<gadget id="calculator">127 - 100</gadget>
<output>27</output>
<result>B</result> | B | 27 | A shopkeeper sold an article offering a discount of 5% and earned a profit of 20.65%. What would have been the percentage of profit earned if no discount was offered? | {
"A": "60 %",
"B": "27 %",
"C": "30 %",
"D": "56 %",
"E": "73 %"
} | subtract(divide(multiply(add(const_100, 20.65), const_100), subtract(const_100, 5)), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,const_100)|divide(#2,#1)|subtract(#3,const_100)| | "let c . p . be rs . 100 . then , s . p . = rs . 120.65 let marked price be rs . x . then , 95 / 100 x = 120.65 x = 12065 / 95 = rs . 127 now , s . p . = rs . 127 , c . p . = rs . 100 profit % = 27 % . answer : b" | gain |
math_qa__CGQRmg34tzVaGyZh | Workers at a campaign office have 2000 fliers to send out. If they send out 1/10 of them in the morning and 1/4 of the remaining ones out during the afternoon, how many are left for the next day? Answers.
A) 300
B) 1350
C) 1100
D) 1200
E) 1900 | <gadget id="calculator">2_000 / 10</gadget>
<output>200</output>
<gadget id="calculator">2_000 - 200</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 4</gadget>
<output>450</output>
<gadget id="calculator">1_800 - 450</gadget>
<output>1_350</output>
<result>B</result> | B | 1,350 | Workers at a campaign office have 2000 fliers to send out. If they send out 1/10 of them in the morning and 1/4 of the remaining ones out during the afternoon, how many are left for the next day? | {
"A": "300",
"B": "1350",
"C": "1100",
"D": "1200",
"E": "1900"
} | subtract(subtract(2000, divide(2000, 10)), divide(subtract(2000, divide(2000, 10)), 4)) | divide(n0,n2)|subtract(n0,#0)|divide(#1,n4)|subtract(#1,#2)| | "( 1 / 10 ) * 2000 = 200 remaining = 2000 - 200 = 1800 ( 1 / 4 ) of remaining = ( 1 / 4 ) * 1800 = 450 remaining now = 1800 - 450 = 1350 answer : option b" | physics |
math_qa__fFJP8POoV2cG4iFS | When x is even, [x] = x/2 + 1, when x is odd [x] = 2x + 1 then [5]*[4] = ? Choose the correct answer.
A) [ 33 ] B) [ 44 ] C) [ 45 ] D) [ 88 ] E) [ 90 ] | <gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) + 1</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">(7/2) * 9</gadget>
<output>63/2 = around 31.5</output>
<result>A</result> | A | 33 | When x is even, [x] = x/2 + 1, when x is odd [x] = 2x + 1 then [5]*[4] = ? | {
"A": "[ 33 ]",
"B": "[ 44 ]",
"C": "[ 45 ]",
"D": "[ 88 ]",
"E": "[ 90 ]"
} | multiply(add(divide(5, 2), 1), add(multiply(2, 4), 1)) | divide(n4,n0)|multiply(n0,n5)|add(#0,n1)|add(#1,n1)|multiply(#2,#3)| | "[ 5 ] * [ 4 ] = ( 2 * 5 + 1 ) ( 4 / 2 + 1 ) = [ 33 ] . ans - a" | general |
math_qa__OJ7QX9rxs5ny2Ckb | 765 chairs are to be arranged in a column in such a way that the number of chairs in each column should be equal to the columns. How many chairs will be excluded to make this arrangement possible? Options.
A) 6 B) 36 C) 19 D) 27 E) none of these | <gadget id="calculator">765 - 12</gadget>
<output>753</output>
<gadget id="calculator">753 - 12</gadget>
<output>741</output>
<gadget id="calculator">741 - 12</gadget>
<output>729</output>
<gadget id="calculator">765 - 729</gadget>
<output>36</output>
<result>B</result> | B | 36 | 765 chairs are to be arranged in a column in such a way that the number of chairs in each column should be equal to the columns. How many chairs will be excluded to make this arrangement possible? | {
"A": "6",
"B": "36",
"C": "19",
"D": "27",
"E": "none of these"
} | subtract(765, subtract(subtract(subtract(765, const_12), const_12), const_12)) | subtract(n0,const_12)|subtract(#0,const_12)|subtract(#1,const_12)|subtract(n0,#2) | 27 ( 2 ) < 765 < 28 ( 2 ) ∴ required no . of chairs to be excluded = 765 – 729 = 36 answer b | general |
math_qa__QGT97CaUL3csQe9q | A mobile battery in 1 hour charges to 20 percent.How much time (in minute) will it require more to charge to 40 percent. Choose the correct choice from the following.
A) 120 B) 150 C) 175 D) 160 E) 130 | <gadget id="calculator">40 / 20</gadget>
<output>2</output>
<gadget id="calculator">2 * 60</gadget>
<output>120</output>
<result>A</result> | A | 120 | A mobile battery in 1 hour charges to 20 percent.How much time (in minute) will it require more to charge to 40 percent. | {
"A": "120",
"B": "150",
"C": "175",
"D": "160",
"E": "130"
} | multiply(divide(40, 20), const_60) | divide(n2,n1)|multiply(#0,const_60)| | 1 hr = 20 percent . thus 15 min = 5 percent . now to charge 40 percent 120 min . answer : a | physics |
math_qa__7XkP5ECtZ1FmaLiT | If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11% per annum then the gain of B in a period of 3 years is? Choose the correct choice from the following
A) 110
B) 106
C) 105
D) 107
E) 109 | <gadget id="calculator">3_500 * 11</gadget>
<output>38_500</output>
<gadget id="calculator">38_500 * 3</gadget>
<output>115_500</output>
<gadget id="calculator">115_500 / 100</gadget>
<output>1_155</output>
<gadget id="calculator">3_500 * 10</gadget>
<output>35_000</output>
<gadget id="calculator">35_000 * 3</gadget>
<output>105_000</output>
<gadget id="calculator">105_000 / 100</gadget>
<output>1_050</output>
<gadget id="calculator">1_155 - 1_050</gadget>
<output>105</output>
<result>C</result> | C | 105 | If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11% per annum then the gain of B in a period of 3 years is? | {
"A": "110",
"B": "106",
"C": "105",
"D": "107",
"E": "109"
} | subtract(divide(multiply(multiply(3500, 11), 3), const_100), divide(multiply(multiply(3500, 10), 3), const_100)) | multiply(n0,n2)|multiply(n0,n1)|multiply(#0,n3)|multiply(n3,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,#5)| | "( 3500 * 1 * 3 ) / 100 = > 105 answer : c" | gain |
math_qa__nLZRNyjvptw29p32 | X and Y began business with Rs.10000 and Rs.8000 after 6 months, X advances Rs.2000 and Y advances Rs.2000 more.
At the end of the year, their profits amounted to Rs.2000 find the share of X and Y respectively.
Choose the correct option: A) 10001000 B) 9001100 C) 1200800 D) 8001200 E) 1100 , 900 | <gadget id="calculator">10_000 * 6</gadget>
<output>60_000</output>
<gadget id="calculator">10_000 + 2_000</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 * 6</gadget>
<output>72_000</output>
<gadget id="calculator">60_000 + 72_000</gadget>
<output>132_000</output>
<gadget id="calculator">8_000 * 6</gadget>
<output>48_000</output>
<gadget id="calculator">2_000 + 2_000</gadget>
<output>4_000</output>
<gadget id="calculator">8_000 + 4_000</gadget>
<output>12_000</output>
<gadget id="calculator">48_000 + 72_000</gadget>
<output>120_000</output>
<gadget id="calculator">gcd(132_000, 120_000)</gadget>
<output>12_000</output>
<gadget id="calculator">132_000 / 12_000</gadget>
<output>11</output>
<gadget id="calculator">120_000 / 12_000</gadget>
<output>10</output>
<gadget id="calculator">11 + 10</gadget>
<output>21</output>
<gadget id="calculator">11 / 21</gadget>
<output>11/21 = around 0.52381</output>
<gadget id="calculator">(11/21) * 2_000</gadget>
<output>22_000/21 = around 1_047.619048</output>
<result>E</result> | E | 1,100 | X and Y began business with Rs.10000 and Rs.8000 after 6 months, X advances Rs.2000 and Y advances Rs.2000 more.
At the end of the year, their profits amounted to Rs.2000 find the share of X and Y respectively. | {
"A": "10001000",
"B": "9001100",
"C": "1200800",
"D": "8001200",
"E": "1100 , 900"
} | multiply(divide(divide(add(multiply(10000, 6), multiply(add(10000, 2000), 6)), gcd(add(multiply(10000, 6), multiply(add(10000, 2000), 6)), add(multiply(8000, 6), multiply(add(8000, add(2000, 2000)), 6)))), add(divide(add(multiply(10000, 6), multiply(add(10000, 2000), 6)), gcd(add(multiply(10000, 6), multiply(add(10000, 2000), 6)), add(multiply(8000, 6), multiply(add(8000, add(2000, 2000)), 6)))), divide(add(multiply(8000, 6), multiply(add(8000, add(2000, 2000)), 6)), gcd(add(multiply(10000, 6), multiply(add(10000, 2000), 6)), add(multiply(8000, 6), multiply(add(8000, add(2000, 2000)), 6)))))), 2000) | add(n0,n3)|add(n3,n3)|multiply(n0,n2)|multiply(n1,n2)|add(n1,#1)|multiply(n2,#0)|add(#2,#5)|multiply(n2,#4)|add(#3,#7)|gcd(#6,#8)|divide(#6,#9)|divide(#8,#9)|add(#10,#11)|divide(#10,#12)|multiply(n3,#13) | ( 10 * 6 + 12 * 6 ) : ( 8 * 6 + 10 * 6 ) 11 : 9 x share = 11 / 20 * 2000 = 1100 . y share = 9 / 20 * 2000 = 900 . x and y share respectively is 1100 , 900 . answer : e | general |
math_qa__wHnHm4UzYDthy8FG | In a group of ducks and cows, the total number of legs are 30 more than twice the no. of heads. Find the total no.of buffaloes. Choose the correct choice from the following answers.
A) 11 B) 12 C) 14 D) 15 E) 18 | <gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>D</result> | D | 15 | In a group of ducks and cows, the total number of legs are 30 more than twice the no. of heads. Find the total no.of buffaloes. | {
"A": "11",
"B": "12",
"C": "14",
"D": "15",
"E": "18"
} | divide(30, const_2) | divide(n0,const_2)| | "let the number of buffaloes be x and the number of ducks be y = > 4 x + 2 y = 2 ( x + y ) + 30 = > 2 x = 30 = > x = 15 d" | general |
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