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math_qa__MT4wgzEnH83LK0kH | The price of a T.V. set worth Rs. 12000 is to be paid in 20 installments of Rs. 1200 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? Pick one:
A) 29997
B) 10800
C) 27098
D) 19000
E) 2799 | <gadget id="calculator">12_000 - 1_200</gadget>
<output>10_800</output>
<result>B</result> | B | 10,800 | The price of a T.V. set worth Rs. 12000 is to be paid in 20 installments of Rs. 1200 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? | {
"A": "29997",
"B": "10800",
"C": "27098",
"D": "19000",
"E": "2799"
} | subtract(12000, 1200) | subtract(n0,n2) | money paid in cash = rs . 1200 balance payment = ( 12000 - 1200 ) = rs . 10800 . answer : b | gain |
math_qa__ILIJVk0SxDw7LkAN | Two trains of length 140 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? Choose the correct option: A) 28 B) 266 C) 990 D) 20 E) 21 | <gadget id="calculator">140 + 280</gadget>
<output>420</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">420 / 20</gadget>
<output>21</output>
<result>E</result> | E | 21 | Two trains of length 140 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "28",
"B": "266",
"C": "990",
"D": "20",
"E": "21"
} | divide(add(140, 280), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 140 + 280 = 420 m . the time required = d / s = 420 / 20 = 21 sec . answer : e" | physics |
math_qa__U9NCdnYe2mPHUzwY | The tax on a commodity is diminished by 28% but its consumption is increased by 12%. Find the decrease percent in the revenue derived from it? Options.
A) 18 %
B) 19 %
C) 32 %
D) 12 %
E) 52 % | <gadget id="calculator">100 + 12</gadget>
<output>112</output>
<gadget id="calculator">100 - 28</gadget>
<output>72</output>
<gadget id="calculator">112 * 72</gadget>
<output>8_064</output>
<gadget id="calculator">8_064 / 100</gadget>
<output>2_016/25 = around 80.64</output>
<gadget id="calculator">100 - (2_016/25)</gadget>
<output>484/25 = around 19.36</output>
<result>B</result> | B | 19 | The tax on a commodity is diminished by 28% but its consumption is increased by 12%. Find the decrease percent in the revenue derived from it? | {
"A": "18 %",
"B": "19 %",
"C": "32 %",
"D": "12 %",
"E": "52 %"
} | subtract(const_100, divide(multiply(add(const_100, 12), subtract(const_100, 28)), const_100)) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|subtract(const_100,#3)| | "100 * 100 = 10000 72 * 112 = 8064 10000 - - - - - - - 1936 100 - - - - - - - ? = 19.36 % answer : b" | general |
math_qa__qcJpesN9aEYynwF1 | How many multiples of 4 are there between 20 and 196 ? Choose the correct choice from the following.
A) 45 B) 42 C) 52 D) 43 E) 51 | <gadget id="calculator">196 - 20</gadget>
<output>176</output>
<gadget id="calculator">176 / 4</gadget>
<output>44</output>
<gadget id="calculator">44 + 1</gadget>
<output>45</output>
<result>D</result> | D | 43 | How many multiples of 4 are there between 20 and 196 ? | {
"A": "45",
"B": "42",
"C": "52",
"D": "43",
"E": "51"
} | add(divide(subtract(196, 20), 4), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "it should be mentioned whether 20 and 196 are inclusive . if 20 and 196 are inclusive , then the answer is ( 196 - 20 ) / 4 + 1 = 45 . if 20 and 196 are not inclusive , then the answer is ( 192 - 24 ) / 4 + 1 = 43 . since oa is d , then we have not inclusive case ." | general |
math_qa__eh1irLspdx3Ng945 | A group of men decided to do a work in 6 days, but 4 of them became absent. If the rest of the group did the work in 12 days, Find the original number of men?
Select: A) 15 B) 6 C) 40 D) 10 E) 8 | <gadget id="calculator">4 * 12</gadget>
<output>48</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">48 / 6</gadget>
<output>8</output>
<result>E</result> | E | 8 | A group of men decided to do a work in 6 days, but 4 of them became absent. If the rest of the group did the work in 12 days, Find the original number of men? | {
"A": "15",
"B": "6",
"C": "40",
"D": "10",
"E": "8"
} | divide(multiply(4, 12), subtract(12, 6)) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "original number of men = 4 * 12 / ( 12 - 6 ) = 8 answer is e" | physics |
math_qa__f6aDr2BHmfUbNten | After 4 games, team B had an average of 61.5 points per game. If it got only 47 points in game 5, how many more points does it need to score to get its total above 500? Answers.
A) 85 B) 74 C) 67 D) 53 E) 207 | <gadget id="calculator">4 * 61.5</gadget>
<output>246</output>
<gadget id="calculator">246 + 47</gadget>
<output>293</output>
<gadget id="calculator">500 - 293</gadget>
<output>207</output>
<result>E</result> | E | 207 | After 4 games, team B had an average of 61.5 points per game. If it got only 47 points in game 5, how many more points does it need to score to get its total above 500? | {
"A": "85",
"B": "74",
"C": "67",
"D": "53",
"E": "207"
} | subtract(500, add(multiply(4, 61.5), 47)) | multiply(n0,n1)|add(n2,#0)|subtract(n4,#1)| | "( 4 * 61.5 ) + 47 + x > 500 246 + 47 + x > 500 293 + x > 500 = > x > 207 option e" | general |
math_qa__T9CINgRmpB8YaJhT | The jogging track in a sports complex is 726 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in? Choose the correct choice from the following answers.
A) 5.29 min B) 5.28 min C) 5.08 min D) 9.28 min E) 5.988 min | <gadget id="calculator">726 / 1_000</gadget>
<output>363/500 = around 0.726</output>
<gadget id="calculator">4.5 + 3.75</gadget>
<output>8.25</output>
<gadget id="calculator">(363/500) / 8.25</gadget>
<output>0.088</output>
<gadget id="calculator">0.088 * 60</gadget>
<output>5.28</output>
<result>B</result> | B | 5.28 | The jogging track in a sports complex is 726 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in? | {
"A": "5.29 min",
"B": "5.28 min",
"C": "5.08 min",
"D": "9.28 min",
"E": "5.988 min"
} | multiply(divide(divide(726, const_1000), add(4.5, 3.75)), const_60) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_60)| | "clearly , the two will meet when they are 726 m apart . to be ( 4.5 + 3.75 ) = 8.25 km apart , they take 1 hour . to be 726 m apart , they take ( 100 / 825 * 726 / 1000 ) hrs = ( 242 / 2750 * 60 ) min = 5.28 min . answer : b" | general |
math_qa__NqWuuaD4sHLM5PoQ | A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2415? Choose the correct choice from the following answers
A) s . 800
B) s . 810
C) s . 805
D) s . 900
E) s . 920 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2_415 * (1/3)</gadget>
<output>805</output>
<result>C</result> | C | 805 | A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2415? | {
"A": "s . 800",
"B": "s . 810",
"C": "s . 805",
"D": "s . 900",
"E": "s . 920"
} | multiply(2415, divide(1, 3)) | divide(n0,n1)|multiply(n6,#0) | 2415 * 1 / 3 = 805 option c | general |
math_qa__pnd0wlNdknOMI4No | A certain company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996?
Choose the correct option: A) 1 : 2 B) 4 : 5 C) 1 : 1 D) 3 : 2 E) 5 : 3 | <gadget id="calculator">100 + 7</gadget>
<output>107</output>
<gadget id="calculator">100 + 1</gadget>
<output>101</output>
<gadget id="calculator">107 - 101</gadget>
<output>6</output>
<gadget id="calculator">100 - 11</gadget>
<output>89</output>
<gadget id="calculator">101 - 89</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | A certain company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996? | {
"A": "1 : 2",
"B": "4 : 5",
"C": "1 : 1",
"D": "3 : 2",
"E": "5 : 3"
} | divide(subtract(add(const_100, 7), add(const_100, 1)), subtract(add(const_100, 1), subtract(const_100, 11))) | add(n3,const_100)|add(n6,const_100)|subtract(const_100,n1)|subtract(#0,#1)|subtract(#1,#2)|divide(#3,#4)| | a . . i have probably solved this question 3 - 4 times by now . . remember the answer . . 1 : 2 | other |
math_qa__T4eG9IzxftgY7JJ6 | 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 8 pumps work to empty the tank in 1 day? Options: A) 6 B) 10 C) 11 D) 12 E) 13 | <gadget id="calculator">3 * 8</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<result>A</result> | A | 6 | 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 8 pumps work to empty the tank in 1 day? | {
"A": "6",
"B": "10",
"C": "11",
"D": "12",
"E": "13"
} | divide(multiply(multiply(3, 8), 2), 8) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n3)| | "3 pumps take 16 hrs total ( 8 hrs a day ) if 1 pump will be working then , it will need 16 * 3 = 48 hrs 1 pump need 48 hrs if i contribute 8 pumps then 48 / 8 = 6 hrs . answer : a" | physics |
math_qa__wkCXbyqKDJrxN4bU | A student has to obtain 45% of the total marks to pass. He got 150 marks and failed by 30 marks. The maximum marks are? Choose one.
A) 300
B) 250
C) 280
D) 320
E) 400 | <gadget id="calculator">150 + 30</gadget>
<output>180</output>
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">180 / (9/20)</gadget>
<output>400</output>
<result>E</result> | E | 400 | A student has to obtain 45% of the total marks to pass. He got 150 marks and failed by 30 marks. The maximum marks are? | {
"A": "300",
"B": "250",
"C": "280",
"D": "320",
"E": "400"
} | divide(add(150, 30), divide(45, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "let the maximum marks be x then , 45 % of x = 150 + 30 45 x / 100 = 180 45 x = 180 * 100 = 18000 x = 400 answer is e" | general |
math_qa__rZeq799Arwix3J9x | A survey of employers found that during 1993 employment costs rose 3.5 percent, where employment costs consist of salary costs and fringe-benefit costs. If salary costs rose 3 percent and fringe-benefit costs rose 5.5 percent during 1993, then fringe-benefit costs represented what percent of employment costs at the beginning of 1993 ? Select the correct option:
A) 16.5 % B) 20 % C) 35 % D) 55 % E) 65 % | <gadget id="calculator">3.5 - 3</gadget>
<output>0.5</output>
<gadget id="calculator">5.5 - 3</gadget>
<output>2.5</output>
<gadget id="calculator">0.5 / 2.5</gadget>
<output>0.2</output>
<gadget id="calculator">0.2 * 100</gadget>
<output>20</output>
<result>B</result> | B | 20 | A survey of employers found that during 1993 employment costs rose 3.5 percent, where employment costs consist of salary costs and fringe-benefit costs. If salary costs rose 3 percent and fringe-benefit costs rose 5.5 percent during 1993, then fringe-benefit costs represented what percent of employment costs at the beginning of 1993 ? | {
"A": "16.5 %",
"B": "20 %",
"C": "35 %",
"D": "55 %",
"E": "65 %"
} | multiply(divide(subtract(3.5, 3), subtract(5.5, 3)), const_100) | subtract(n1,n2)|subtract(n3,n2)|divide(#0,#1)|multiply(#2,const_100)| | "in my view easiest method would be , eliminating the percentage sign let 3.5 be 35 5.5 be 55 and 3 be 30 then first eq : s + f = e 130 s + 155 f = 135 e 5 s = 20 f therefore , s = 4 f and then e = 5 f f / e = f / 5 f = 20 % therefore , answer is b" | gain |
math_qa__Sd0C7Qr3iNTh1VhZ | If f(x) = 2x^2 + y, and f(2) = 30, what is the value of f(10)? Choose the correct choice from the following options
A) 104 B) 60 C) 52 D) 50 E) 222 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">30 - 8</gadget>
<output>22</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">22 + 200</gadget>
<output>222</output>
<result>E</result> | E | 222 | If f(x) = 2x^2 + y, and f(2) = 30, what is the value of f(10)? | {
"A": "104",
"B": "60",
"C": "52",
"D": "50",
"E": "222"
} | add(subtract(30, multiply(power(2, 2), 2)), multiply(2, power(10, 2))) | power(n4,n0)|power(n0,n0)|multiply(n0,#0)|multiply(n0,#1)|subtract(n3,#3)|add(#2,#4) | f ( x ) = 2 x ^ 2 + y f ( 2 ) = 30 = > 2 * ( 2 ) ^ 2 + y = 30 = > 8 + y = 30 = > y = 22 f ( 10 ) = 2 * ( 10 ) ^ 2 + 22 = 222 answer e | general |
math_qa__PBrGM3RwgN2ubiR7 | If a certain coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 5 times, what is the probability that it will land heads up on the first 2 flips but not on the last 3 flips? Pick:
A) 1 / 2 B) 1 / 4 C) 1 / 8 D) 1 / 16 E) 1 / 32 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 5</gadget>
<output>1/32 = around 0.03125</output>
<result>E</result> | E | 0.03125 | If a certain coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 5 times, what is the probability that it will land heads up on the first 2 flips but not on the last 3 flips? | {
"A": "1 / 2",
"B": "1 / 4",
"C": "1 / 8",
"D": "1 / 16",
"E": "1 / 32"
} | power(divide(1, 2), 5) | divide(n0,n1)|power(#0,n2)| | "p ( hhttt ) = 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 = 1 / 32 the answer is e ." | probability |
math_qa__rhbXnTcnBtaLFtqo | By weight, liquid X makes up 0.5 percent of solution P and 1.5 percent of solution Q. If 200 grams of solution P are mixed with 800 grams of solution Q, then liquid X accounts for what percent of the weight of the resulting solution?
Select:
A) 1.3 %
B) 1.2 %
C) 1.1 %
D) 1.0 %
E) 0.9 % | <gadget id="calculator">1.5 * 800</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 100</gadget>
<output>12</output>
<gadget id="calculator">1 + 12</gadget>
<output>13</output>
<gadget id="calculator">13 / 1_000</gadget>
<output>13/1_000 = around 0.013</output>
<gadget id="calculator">(13/1_000) * 100</gadget>
<output>13/10 = around 1.3</output>
<result>A</result> | A | 1.3 | By weight, liquid X makes up 0.5 percent of solution P and 1.5 percent of solution Q. If 200 grams of solution P are mixed with 800 grams of solution Q, then liquid X accounts for what percent of the weight of the resulting solution? | {
"A": "1.3 %",
"B": "1.2 %",
"C": "1.1 %",
"D": "1.0 %",
"E": "0.9 %"
} | multiply(divide(add(const_1, divide(multiply(1.5, 800), const_100)), const_1000), const_100) | multiply(n1,n3)|divide(#0,const_100)|add(#1,const_1)|divide(#2,const_1000)|multiply(#3,const_100) | the number of grams of liquid x is 0.5 ( 200 ) / 100 + 1.5 ( 800 ) / 100 = 1 + 12 = 13 grams . 13 / 1000 = 1.3 % the answer is a . | gain |
math_qa__4QIthFid06jDeJWz | There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total Q of the book? Choose one.
A) 3003
B) 3027
C) 3024
D) 3021
E) 3018 | <gadget id="calculator">3_000 + 3</gadget>
<output>3_003</output>
<result>A</result> | A | 3,003 | There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total Q of the book? | {
"A": "3003",
"B": "3027",
"C": "3024",
"D": "3021",
"E": "3018"
} | add(3000, 3) | add(n0,n5) | first , you have to find the common ratio for all 3 books . you have : p : c : b 3 : 2 - - > multiply by 2 ( gives you row 3 ) 4 : 6 6 : 4 : 3 hence : p : c : b : t ( total ) = q 6 : 4 : 3 : 13 - - - - > this means , the total number must be a multiple of 13 . answer a is correct since 299 is divisible by 13 , hence is 2990 and so is 3003 ( 2990 + 13 ) . | other |
math_qa__NcxVlKeNpcB9diMl | When tossed, a certain coin has equal probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land twice on heads and once on tails? Choose one.
A) 1 / 16
B) 1 / 3
C) 1 / 6
D) 1 / 2
E) 1 / 8 | <gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<result>E</result> | E | 0.125 | When tossed, a certain coin has equal probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land twice on heads and once on tails? | {
"A": "1 / 16",
"B": "1 / 3",
"C": "1 / 6",
"D": "1 / 2",
"E": "1 / 8"
} | divide(const_1, power(const_2, 3)) | power(const_2,n0)|divide(const_1,#0)| | "must be once on twice and once on tails 1 / 2 * 1 / 2 * 1 / 2 = 1 / 8 answer : e" | general |
math_qa__ceBLMAzywqunnpE7 | [(5/2 ÷ 1/2 × 5/2)]/[(5/2 × 1/2 ÷ 5/2)] = ? Choose the most appropriate option: A) 25 B) 20 C) 18 D) 16 E) 14 | <gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(5/2) / (1/2)</gadget>
<output>5</output>
<gadget id="calculator">5 * (5/2)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(5/2) * (1/2)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) / (5/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(25/2) / (1/2)</gadget>
<output>25</output>
<result>A</result> | A | 25 | [(5/2 ÷ 1/2 × 5/2)]/[(5/2 × 1/2 ÷ 5/2)] = ? | {
"A": "25",
"B": "20",
"C": "18",
"D": "16",
"E": "14"
} | divide(multiply(divide(divide(5, 2), divide(1, 2)), divide(5, 2)), divide(multiply(divide(5, 2), divide(1, 2)), divide(5, 2))) | divide(n0,n1)|divide(n2,n1)|divide(#0,#1)|multiply(#0,#1)|divide(#3,#0)|multiply(#2,#0)|divide(#5,#4) | explanation : [ ( 5 / 2 ÷ 1 / 2 × 5 / 2 ) ] / [ ( 5 / 2 × 1 / 2 ÷ 5 / 2 ) ] = [ 5 / 2 × 2 / 1 × 5 / 2 ] / [ 5 / 2 × 1 / 2 × 2 / 5 ] = 25 / 2 / 1 / 2 = 25 / 2 x 2 / 1 = 25 answer : option a | general |
math_qa__FRZqfcj4Z3WDlnoG | The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of $700 per sq. metre. Select.
A) $ 12537.50 B) $ 13537.50 C) $ 14437.50 D) $ 16437.50 E) $ 18537.50 | <gadget id="calculator">5.5 * 3.75</gadget>
<output>20.625</output>
<gadget id="calculator">700 * 20.625</gadget>
<output>14_437.5</output>
<result>C</result> | C | 14,437.5 | The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of $700 per sq. metre. | {
"A": "$ 12537.50",
"B": "$ 13537.50",
"C": "$ 14437.50",
"D": "$ 16437.50",
"E": "$ 18537.50"
} | multiply(700, multiply(5.5, 3.75)) | multiply(n0,n1)|multiply(n2,#0)| | "c area = 5.5 × 3.75 sq . metre . cost for 1 sq . metre . = $ 700 hence , total cost = 5.5 × 3.75 × 700 = $ 14437.50" | physics |
math_qa__ezujXY5zhsC65itY | Find the value of (85 + 32/113) × 113 Pick.
A) 9263 B) 9244 C) 9636 D) 9623 E) 9637 | <gadget id="calculator">32 / 113</gadget>
<output>32/113 = around 0.283186</output>
<gadget id="calculator">(32/113) + 85</gadget>
<output>9_637/113 = around 85.283186</output>
<gadget id="calculator">(9_637/113) * 113</gadget>
<output>9_637</output>
<result>E</result> | E | 9,637 | Find the value of (85 + 32/113) × 113 | {
"A": "9263",
"B": "9244",
"C": "9636",
"D": "9623",
"E": "9637"
} | multiply(add(divide(32, 113), 85), 113) | divide(n1,n2)|add(n0,#0)|multiply(#1,n2)| | "= ( 85 + 32 / 113 ) × 113 = ( 9605 + 32 ) / 113 × 113 = 9637 / 113 × 113 = 9637 answer is e ." | general |
math_qa__TeS1oufqAcnLekGT | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 20000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is: Select the correct option:
A) 23
B) 49
C) 22
D) 20
E) 21 | <gadget id="calculator">20_000 - 8_000</gadget>
<output>12_000</output>
<gadget id="calculator">7 * 12_000</gadget>
<output>84_000</output>
<gadget id="calculator">8_000 - 6_000</gadget>
<output>2_000</output>
<gadget id="calculator">84_000 / 2_000</gadget>
<output>42</output>
<gadget id="calculator">7 + 42</gadget>
<output>49</output>
<result>B</result> | B | 49 | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 20000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is: | {
"A": "23",
"B": "49",
"C": "22",
"D": "20",
"E": "21"
} | add(7, divide(multiply(7, subtract(20000, 8000)), subtract(8000, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3)| | "let the total number of workers be x . then , 8000 x = ( 20000 * 7 ) + 6000 ( x - 7 ) = 2000 x = 98000 = x = 49 . answer : b" | general |
math_qa__VWCWfG5kTwejUoBl | The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 12 and 13. The larger of the two numbers is: Choices: A) 299 B) 278 C) 322 D) 231 E) 121 | <gadget id="calculator">23 * 13</gadget>
<output>299</output>
<result>A</result> | A | 299 | The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 12 and 13. The larger of the two numbers is: | {
"A": "299",
"B": "278",
"C": "322",
"D": "231",
"E": "121"
} | multiply(23, 13) | multiply(n0,n2)| | "clearly , the numbers are ( 23 * 12 ) and ( 23 * 13 ) . larger number = ( 23 * 13 ) = 299 . answer : a" | other |
math_qa__2kYCvQ4Xn1QxdUet | Two sides of a triangle have lengths x and t and meet at a right angle. If the perimeter of the triangle is 4x, what is the ratio of x to t ?
Pick:
A) 2 : 3
B) 3 : 4
C) 4 : 3
D) 3 : 2
E) 2 : 1 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<result>B</result> | B | 0.75 | Two sides of a triangle have lengths x and t and meet at a right angle. If the perimeter of the triangle is 4x, what is the ratio of x to t ? | {
"A": "2 : 3",
"B": "3 : 4",
"C": "4 : 3",
"D": "3 : 2",
"E": "2 : 1"
} | divide(const_3, 4) | divide(const_3,n0) | ahhhh . . . . my bad . thank you , you ' re correct . 8 x = 6 t - - > x / t = 3 / 4 . actually b is the right answer . | geometry |
math_qa__lYe6JSgcx6mJd6nb | In 70 liters of a mixture of milk and water ,the quantity of water is 10%. how much water should be added so that new mixture may 25% water. Pick:
A) 14 B) 15 C) 16 D) 17 E) 18 | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">25 - 10</gadget>
<output>15</output>
<gadget id="calculator">75 / 15</gadget>
<output>5</output>
<gadget id="calculator">70 / 5</gadget>
<output>14</output>
<result>A</result> | A | 14 | In 70 liters of a mixture of milk and water ,the quantity of water is 10%. how much water should be added so that new mixture may 25% water. | {
"A": "14",
"B": "15",
"C": "16",
"D": "17",
"E": "18"
} | divide(70, divide(subtract(const_100, 25), subtract(25, 10))) | subtract(const_100,n2)|subtract(n2,n1)|divide(#0,#1)|divide(n0,#2) | there are 10 % of water in 70 l - - > there are 7 l of waters ; after x liters of water is added amount of water becomes ( 7 + x ) liters , which on the other hand is 1 / 4 th ( 25 % ) of new ( 70 + x ) liters of mixture : 7 + x = 1 / 4 * ( 70 + x ) - - > 28 + 4 x = 70 + x - - > x = 14 answer : a | general |
math_qa__knOiKyEQ9DUa6USH | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 25 hours respectively. The ratio of their speeds is? Pick one: A) 4 : 5 B) 5 : 3 C) 4 : 4 D) 4 : 8 E) 4 : 1 | <gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<result>B</result> | B | 1.666667 | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 25 hours respectively. The ratio of their speeds is? | {
"A": "4 : 5",
"B": "5 : 3",
"C": "4 : 4",
"D": "4 : 8",
"E": "4 : 1"
} | divide(sqrt(25), sqrt(9)) | sqrt(n1)|sqrt(n0)|divide(#0,#1)| | "let us name the trains a and b . then , ( a ' s speed ) : ( b ' s speed ) = √ b : √ a = √ 25 : √ 9 = 5 : 3 answer : b" | physics |
math_qa__XHptR77gnlCImx92 | X does a work in 10 days. Y does the same work in 15 days. In how many days they together will do the same work? Pick one
A) 10 B) 15 C) 3 D) 6 E) 12 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) + (1/15)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>D</result> | D | 6 | X does a work in 10 days. Y does the same work in 15 days. In how many days they together will do the same work? | {
"A": "10",
"B": "15",
"C": "3",
"D": "6",
"E": "12"
} | inverse(add(divide(const_1, 10), divide(const_1, 15))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2)| | "x ' s 1 day ' s work = 1 / 10 y ' s 1 day ' s work = 1 / 15 ( x + y ) ' s 1 day ' s work = ( 1 / 10 + 1 / 15 ) = 1 / 6 both together will finish the work in 6 days . correct option is d" | physics |
math_qa__H1vUnkSDnn8LJ4R9 | A rectangular lawn of length 200m by 120m has two roads running along its center, one along the length and the other along the width. If the width of the roads is 5m what is the area Y covered by the two roads? Pick one
A) 400 B) 1550 C) 1575 D) 1600 E) 1625 | <gadget id="calculator">200 * 5</gadget>
<output>1_000</output>
<gadget id="calculator">120 * 5</gadget>
<output>600</output>
<gadget id="calculator">1_000 + 600</gadget>
<output>1_600</output>
<result>C</result> | C | 1,575 | A rectangular lawn of length 200m by 120m has two roads running along its center, one along the length and the other along the width. If the width of the roads is 5m what is the area Y covered by the two roads? | {
"A": "400",
"B": "1550",
"C": "1575",
"D": "1600",
"E": "1625"
} | add(rectangle_area(200, 5), rectangle_area(120, 5)) | rectangle_area(n0,n2)|rectangle_area(n1,n2)|add(#0,#1)| | "area covered by road along the length = 5 * 200 = 1000 square meter area covered by road along the width = 5 * 120 = 600 square meter common area in both roads ( where the roads intersect ) = square with side 5 meter = 5 * 5 = 25 total area of the roads y = 1000 + 600 - 25 = 1575 answer : option c" | geometry |
math_qa__BtGftFLjlQrxLvVC | Which expression has the greatest value?
Choose the correct choice from the following answers.
A) 1977452 / 1977455 B) 1982466 / 1982469 C) 1982487 / 1982490 D) 1982456 / 1982459 E) 1982465 / 1982468 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">3_600 - 9</gadget>
<output>3_591</output>
<gadget id="calculator">3_600 - 4</gadget>
<output>3_596</output>
<gadget id="calculator">3_591 / 3_596</gadget>
<output>3_591/3_596 = around 0.99861</output>
<result>C</result> | C | 0.999998 | Which expression has the greatest value? | {
"A": "1977452 / 1977455",
"B": "1982466 / 1982469",
"C": "1982487 / 1982490",
"D": "1982456 / 1982459",
"E": "1982465 / 1982468"
} | divide(subtract(const_3600, multiply(const_3, const_3)), subtract(const_3600, const_4)) | multiply(const_3,const_3)|subtract(const_3600,const_4)|subtract(const_3600,#0)|divide(#2,#1)| | "the difference between each numerator / denominator pair is three . the largest expression ( which in this case will also be the closest to one ) is the expression where ' 3 ' is the smallest fraction of the numerator ( or the denominator ) . the largest numerator is 1982487 , or c , and this will give an expression with a value closest to one . we can also demonstrate that this approach works with some simple logic . taking numerator / denominator pairs that differ by three . . . 1 / 4 = 0.25 2 / 5 = 0.4 3 / 6 = 0.5 . . . 27 / 30 = 0.9 . . . 1982487 / 1982490 = 0.999998486 . . . answer : c" | general |
math_qa__ISazDX5tiqxbCU6X | What is the greatest prime factor of 4^17 - 2^29? Pick:
A) 2
B) 3
C) 5
D) 7
E) 31 | <gadget id="calculator">2 + 29</gadget>
<output>31</output>
<result>E</result> | E | 31 | What is the greatest prime factor of 4^17 - 2^29? | {
"A": "2",
"B": "3",
"C": "5",
"D": "7",
"E": "31"
} | add(2, 29) | add(n2,n3) | i ' m happy to help with this . we know 4 = 2 ^ 2 , so 4 ^ 17 = ( 2 ^ 2 ) ^ 17 = 2 ^ ( 2 * 17 ) = 2 ^ 34 that takes advantage of a law of exponents that says ( a ^ n ) ^ m = a ^ ( n * m ) so , 4 ^ 17 - 2 ^ 29 = 2 ^ 34 - 2 ^ 29 = 2 ^ ( 29 + 5 ) - 2 ^ 29 = ( 2 ^ 29 ) * ( 2 * 6 ) - 2 ^ 29 = ( 2 ^ 6 - 1 ) * ( 2 ^ 29 ) = ( 32 - 1 ) * ( 2 ^ 29 ) = 31 * ( 2 ^ 29 ) the prime factors of 31 are 31 , so the largest prime factor is 31 , answer choice d . here ' s a blog you may find helpful . http : / / magoosh . com / gmat / 2012 / gmat - math - factors / does all that make sense ? please let me know if you have any further questions . mike wow . i am floored by how great of an explanation you provided . posts like that make me really think that doing thousands of practice problems with good explanations beats out reading books on math every day of the week . e | general |
math_qa__ogr3K6qp177a3XPy | Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 4 to 1, what is the ratio of US to British stamps?
Choose the most appropriate option.
A) 5 : 1 B) 10 : 5 C) 15 : 2 D) 20 : 2 E) 25 : 2 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>D</result> | D | 10 | Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 4 to 1, what is the ratio of US to British stamps? | {
"A": "5 : 1",
"B": "10 : 5",
"C": "15 : 2",
"D": "20 : 2",
"E": "25 : 2"
} | divide(multiply(5, 4), multiply(1, 2)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "u / i = 5 / 2 i / b = 4 / 1 since i is multiple of both 2 ( as per first ratio ) and 5 ( as per second ratio ) so let ' s assume that i = 10 i . e . multiplying teh first ratio by 5 and second ration by 2 in each numerator and denominator then , u : i : b = 20 : 8 : 2 i . e . u : b = 20 : 2 answer : option d" | other |
math_qa__ouYPovhZPhAh9XOD | A student,after his teacher's question, chose a number, multiplied it by 2, then subtracted 138 from the result and got 102. What was the number he chose? Choose the correct choice from the following
A) 344 B) 251 C) 411 D) 212 E) 120 | <gadget id="calculator">138 + 102</gadget>
<output>240</output>
<gadget id="calculator">240 / 2</gadget>
<output>120</output>
<result>E</result> | E | 120 | A student,after his teacher's question, chose a number, multiplied it by 2, then subtracted 138 from the result and got 102. What was the number he chose? | {
"A": "344",
"B": "251",
"C": "411",
"D": "212",
"E": "120"
} | divide(add(138, 102), 2) | add(n1,n2)|divide(#0,n0) | let x be the number he chose , then 2 ⋅ x − 138 = 102 2 x = 240 x = 120 correct answer is e ) 120 | general |
math_qa__4JzbXJUmggyCp7kQ | What is the sum of the greatest common factor and the lowest common multiple of 36 and 16? Choose the most appropriate option.
A) 148 B) 210 C) 314 D) 320 E) 344 | <gadget id="calculator">36 * 16</gadget>
<output>576</output>
<gadget id="calculator">576 / 4</gadget>
<output>144</output>
<result>A</result> | A | 148 | What is the sum of the greatest common factor and the lowest common multiple of 36 and 16? | {
"A": "148",
"B": "210",
"C": "314",
"D": "320",
"E": "344"
} | divide(multiply(36, 16), const_4) | multiply(n0,n1)|divide(#0,const_4) | prime factorization of 36 = 2 x 2 x 3 x 3 prime factorization of 16 = 2 x 2 x 2 x 2 gcf = 4 lcm = 144 sum = 148 . answer a . | general |
math_qa__ldFpJZ2uszyMlR3O | Lisa and Robert have taken the same number of photos on their school trip. Lisa has taken 3 times as many photos as Claire and Robert has taken 28 more photos than Claire. How many photos has Claire taken?
Choose the correct option:
A) 6 B) 8 C) 10 D) 12 E) 14 | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">28 / 2</gadget>
<output>14</output>
<result>E</result> | E | 14 | Lisa and Robert have taken the same number of photos on their school trip. Lisa has taken 3 times as many photos as Claire and Robert has taken 28 more photos than Claire. How many photos has Claire taken? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "14"
} | divide(28, subtract(3, const_1)) | subtract(n0,const_1)|divide(n1,#0)| | "l = r l = 3 c r = c + 28 3 c = c + 28 c = 14 the answer is e ." | general |
math_qa__ujwh0F51XPh8ZkUu | A fruit seller sells mangoes at the rate of Rs.5 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5%
Pick one.
A) rs 6.56 B) rs 9.56 C) rs 10.56 D) rs 11.56 E) none of these | <gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">5 * 105</gadget>
<output>525</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">525 / 80</gadget>
<output>105/16 = around 6.5625</output>
<result>A</result> | A | 6.56 | A fruit seller sells mangoes at the rate of Rs.5 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5% | {
"A": "rs 6.56",
"B": "rs 9.56",
"C": "rs 10.56",
"D": "rs 11.56",
"E": "none of these"
} | divide(multiply(5, add(const_100, 5)), subtract(const_100, 20)) | add(n2,const_100)|subtract(const_100,n1)|multiply(n0,#0)|divide(#2,#1)| | "explanation : 80 : 5 = 105 : x x = ( 5 × 105 / 80 ) = rs 6.56 option a" | gain |
math_qa__LbMp8dDSSyREfuSJ | When a certain number X is divided by 66, the remainder is 14. What is the remainder when X is divided by 11?
Choose the correct choice from the following options: A) 2 B) 3 C) 7 D) 9 E) 10 | <gadget id="calculator">14 % 11</gadget>
<output>3</output>
<result>B</result> | B | 3 | When a certain number X is divided by 66, the remainder is 14. What is the remainder when X is divided by 11? | {
"A": "2",
"B": "3",
"C": "7",
"D": "9",
"E": "10"
} | reminder(14, 11) | reminder(n1,n2)| | "let possible value of x is 80 least possible value of x / 11 is 80 / 11 = > 7 quotient with remainder 3 thus answer is ( b ) 3" | general |
math_qa__33EpyLLwRlCeKzx8 | There are 7 red shoes & 3 green shoes . If two of red shoes are drawn what is the probability of getting red shoes Select:
A) 1 / 13
B) 1 / 14
C) 1 / 15
D) 7 / 15
E) 7 / 16 | <gadget id="calculator">binomial(7, 2)</gadget>
<output>21</output>
<gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">binomial(10, 2)</gadget>
<output>45</output>
<gadget id="calculator">21 / 45</gadget>
<output>7/15 = around 0.466667</output>
<result>D</result> | D | 0.466667 | There are 7 red shoes & 3 green shoes . If two of red shoes are drawn what is the probability of getting red shoes | {
"A": "1 / 13",
"B": "1 / 14",
"C": "1 / 15",
"D": "7 / 15",
"E": "7 / 16"
} | divide(choose(7, const_2), choose(add(7, 3), const_2)) | add(n0,n1)|choose(n0,const_2)|choose(#0,const_2)|divide(#1,#2)| | "taking 2 red shoe the probablity is 7 c 2 from 10 shoes probablity of taking 2 red shoe is 7 c 2 / 10 c 2 = 7 / 15 answer : d" | probability |
math_qa__jJCCGIAnLHdamd6K | A can do a piece of work in 8 days. B can do it in 16 days. With the assistance of C they completed the work in 4 days. Find in how many days can C alone do it? Pick one:
A) 87 days B) 20 days C) 26 days D) 19 days E) 16 days | <gadget id="calculator">8 * 16</gadget>
<output>128</output>
<gadget id="calculator">128 / 8</gadget>
<output>16</output>
<gadget id="calculator">128 / 16</gadget>
<output>8</output>
<gadget id="calculator">16 + 8</gadget>
<output>24</output>
<gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">128 - 96</gadget>
<output>32</output>
<gadget id="calculator">32 / 4</gadget>
<output>8</output>
<result>E</result> | E | 16 | A can do a piece of work in 8 days. B can do it in 16 days. With the assistance of C they completed the work in 4 days. Find in how many days can C alone do it? | {
"A": "87 days",
"B": "20 days",
"C": "26 days",
"D": "19 days",
"E": "16 days"
} | divide(multiply(8, 16), divide(subtract(multiply(8, 16), multiply(add(divide(multiply(8, 16), 8), divide(multiply(8, 16), 16)), 4)), 4)) | multiply(n0,n1)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)|multiply(n2,#3)|subtract(#0,#4)|divide(#5,n2)|divide(#0,#6)| | "c = 1 / 4 - 1 / 8 - 1 / 16 = 1 / 16 = > 16 days answer : e" | physics |
math_qa__qsBf5HMbiNdEpRpl | Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 70 ps per meter is? Choose the correct answer
A) 287 B) 369 C) 175 D) 279 E) 361 | <gadget id="calculator">3_750 * 2</gadget>
<output>7_500</output>
<gadget id="calculator">7_500 / 3</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 ** (1/2)</gadget>
<output>50</output>
<gadget id="calculator">3_750 / 50</gadget>
<output>75</output>
<gadget id="calculator">2 * (50 + 75)</gadget>
<output>250</output>
<gadget id="calculator">70 * 250</gadget>
<output>17_500</output>
<gadget id="calculator">17_500 / 100</gadget>
<output>175</output>
<result>C</result> | C | 175 | Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 70 ps per meter is? | {
"A": "287",
"B": "369",
"C": "175",
"D": "279",
"E": "361"
} | divide(multiply(70, rectangle_perimeter(sqrt(divide(multiply(3750, 2), 3)), divide(3750, sqrt(divide(multiply(3750, 2), 3))))), const_100) | multiply(n1,n2)|divide(#0,n0)|sqrt(#1)|divide(n2,#2)|rectangle_perimeter(#3,#2)|multiply(n3,#4)|divide(#5,const_100)| | "3 x * 2 x = 3750 = > x = 25 2 ( 75 + 50 ) = 250 m 250 * 0.70 = rs . 175 answer : c" | physics |
math_qa__shTqrNhYc1YCLLer | A 40-liter solution of alcohol and water is 5 percent alcohol. If 5.5 liters of alcohol and 4.5 liters of water are added to this solution, what percent of the solution produced is alcohol? Pick one.
A) 9 %
B) 11 %
C) 13 %
D) 15 %
E) 17 % | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">40 * (1/20)</gadget>
<output>2</output>
<gadget id="calculator">2 + 5.5</gadget>
<output>7.5</output>
<gadget id="calculator">5.5 + 4.5</gadget>
<output>10</output>
<gadget id="calculator">40 + 10</gadget>
<output>50</output>
<gadget id="calculator">7.5 / 50</gadget>
<output>0.15</output>
<gadget id="calculator">0.15 * 100</gadget>
<output>15</output>
<result>D</result> | D | 15 | A 40-liter solution of alcohol and water is 5 percent alcohol. If 5.5 liters of alcohol and 4.5 liters of water are added to this solution, what percent of the solution produced is alcohol? | {
"A": "9 %",
"B": "11 %",
"C": "13 %",
"D": "15 %",
"E": "17 %"
} | multiply(divide(add(multiply(40, divide(5, const_100)), 5.5), add(40, add(5.5, 4.5))), const_100) | add(n2,n3)|divide(n1,const_100)|add(n0,#0)|multiply(n0,#1)|add(n2,#3)|divide(#4,#2)|multiply(#5,const_100)| | "the percent of alcohol in the solution is ( 0.05 ( 40 ) + 5.5 ) / 50 = 7.5 / 50 = 15 % the answer is d ." | general |
math_qa__A4huaBDx97xgrkX8 | in the first round of the elections , the only two candidates got exactly the same number of votes . during the second round , 16000 votes switched from the first candidate to the second one . the total number of votes remained the same in both rounds , and no other votes switched sides . if , in the second round , the winning candidate got 5 times as many votes as the other candidate , how many people have voted in each round ?
Select:
A) 15,000 B) 25,000 C) 40,000 D) 48,000 E) 60,000 | <gadget id="calculator">5 * 16_000</gadget>
<output>80_000</output>
<gadget id="calculator">80_000 + 16_000</gadget>
<output>96_000</output>
<gadget id="calculator">96_000 / 4</gadget>
<output>24_000</output>
<gadget id="calculator">24_000 * 2</gadget>
<output>48_000</output>
<result>D</result> | D | 48,000 | in the first round of the elections , the only two candidates got exactly the same number of votes . during the second round , 16000 votes switched from the first candidate to the second one . the total number of votes remained the same in both rounds , and no other votes switched sides . if , in the second round , the winning candidate got 5 times as many votes as the other candidate , how many people have voted in each round ? | {
"A": "15,000",
"B": "25,000",
"C": "40,000",
"D": "48,000",
"E": "60,000"
} | multiply(divide(add(multiply(5, 16000), 16000), const_4), const_2) | multiply(n0,n1)|add(n0,#0)|divide(#1,const_4)|multiply(#2,const_2) | let a be the first candidate and b be the second one . given x + 16000 = 5 ( x - 16000 ) = > x = 24000 2 x = 48000 imo option d . | general |
math_qa__JKXL8zpKaMpxwD9P | In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 80 questions and secures 120 marks, How many questions does he answer correctly? Answers: A) 20 B) 10 C) 30 D) 50 E) 40 | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">200 / 5</gadget>
<output>40</output>
<result>E</result> | E | 40 | In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 80 questions and secures 120 marks, How many questions does he answer correctly? | {
"A": "20",
"B": "10",
"C": "30",
"D": "50",
"E": "40"
} | divide(add(120, 80), add(4, 1)) | add(n2,n3)|add(n0,n1)|divide(#0,#1)| | "let the number of correct answers be x then , number of wrong answers = ( 80 - x ) 4 x – ( 80 - x ) = 120 = > 4 x – 80 + x = 120 = > 5 x = 200 = > x = 200 / 5 = 40 i . e . , he does 40 questions correctly answer is e ." | physics |
math_qa__ygYwAiRy4GV4FkVq | After striking the floor, a rubber ball rebounds to 4/5th of the height from which it has fallen. Find the total distance that it travels before coming to rest if it has been gently dropped from a height of 120 metres. Choose the correct answer
A) 540 m B) 960 m C) 1080 m D) 1020 m E) 1120 m | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">120 * 9</gadget>
<output>1_080</output>
<result>C</result> | C | 1,080 | After striking the floor, a rubber ball rebounds to 4/5th of the height from which it has fallen. Find the total distance that it travels before coming to rest if it has been gently dropped from a height of 120 metres. | {
"A": "540 m",
"B": "960 m",
"C": "1080 m",
"D": "1020 m",
"E": "1120 m"
} | multiply(120, add(4, 5)) | add(n0,n1)|multiply(n2,#0) | solution : the first drop is 120 metres . after this the ball will rise by 96 metres and fall by 96 metres . this process will continue in the form of infinite gp with common ratio 0.8 and first term 96 . the required answer is given by the formula : a / ( 1 - r ) now , [ { 120 / ( 1 / 5 ) } + { 96 / ( 1 / 5 ) } ] = 1080 m . answer c | physics |
math_qa__nZJqPiwDzfd5Kbis | A sum was put a simple interest at a certain rate for 5 years. Had it been put at 2% higher rate, it would have fetched Rs. 250 more. The sum is: Choose the correct option:
A) s . 2000
B) s . 2500
C) s . 3000
D) s . 3500
E) s . 4000 | <gadget id="calculator">250 / 5</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 * 100</gadget>
<output>2_500</output>
<result>B</result> | B | 2,500 | A sum was put a simple interest at a certain rate for 5 years. Had it been put at 2% higher rate, it would have fetched Rs. 250 more. The sum is: | {
"A": "s . 2000",
"B": "s . 2500",
"C": "s . 3000",
"D": "s . 3500",
"E": "s . 4000"
} | multiply(divide(divide(250, 5), 2), const_100) | divide(n2,n0)|divide(#0,n1)|multiply(#1,const_100)| | "explanation : let the sub be rs . x and the initial rate be r % . then x ã — ( r + 2 ) ã — 5 / 100 â ˆ ’ x ã — r ã — 5 / 100 = 250 â ‡ ’ x ã — 2 ã — 5 / 100 = 250 â ‡ ’ x ã — 5 / 100 = 125 â ‡ ’ 5 x = 12500 â ‡ ’ x = 2500 answer : option b" | gain |
math_qa__ZXynd8sK53oURMPU | What is the largest 4 digit number exactly divisible by 35?
Choices
A) 4676 B) 4678 C) 9975 D) 9504 E) 9936 | <gadget id="calculator">10 ** 4</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 35</gadget>
<output>2_000/7 = around 285.714286</output>
<gadget id="calculator">floor(2_000/7)</gadget>
<output>285</output>
<gadget id="calculator">285 * 35</gadget>
<output>9_975</output>
<result>C</result> | C | 9,975 | What is the largest 4 digit number exactly divisible by 35? | {
"A": "4676",
"B": "4678",
"C": "9975",
"D": "9504",
"E": "9936"
} | multiply(floor(divide(power(const_10, 4), 35)), 35) | power(const_10,n0)|divide(#0,n1)|floor(#1)|multiply(n1,#2)| | "largest 4 digit number = 9999 9999 ÷ 35 = 285 , remainder = 24 hence largest 4 digit number exactly divisible by 88 = 9999 - 24 = 9975 answer : c" | general |
math_qa__SgWCYgcjxqhKKFFM | A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 105 km downstream.
Select:
A) 4 hours
B) 5 hours
C) 6 hours
D) 7 hours
E) 8 hours | <gadget id="calculator">16 + 5</gadget>
<output>21</output>
<gadget id="calculator">105 / 21</gadget>
<output>5</output>
<result>B</result> | B | 5 | A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 105 km downstream. | {
"A": "4 hours",
"B": "5 hours",
"C": "6 hours",
"D": "7 hours",
"E": "8 hours"
} | divide(105, add(16, 5)) | add(n0,n1)|divide(n2,#0)| | "explanation : it is very important to check , if the boat speed given is in still water or with water or against water . because if we neglect it we will not reach on right answer . i just mentioned here because mostly mistakes in this chapter are of this kind only . lets see the question now . speed downstream = ( 16 + 5 ) = 21 kmph time = distance / speed = 105 / 21 = 5 hours option b" | physics |
math_qa__yVUReKqrIlAMjLNU | The Sum of the average (arithmetic mean) of the even integers from 0 to 100 inclusive and the average (arithmetic mean) of the even integers from 0 to 50 inclusive? Choices.
A) 15 B) 125 C) 25 D) 75 E) 50 | <gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">50 + 25</gadget>
<output>75</output>
<result>D</result> | D | 75 | The Sum of the average (arithmetic mean) of the even integers from 0 to 100 inclusive and the average (arithmetic mean) of the even integers from 0 to 50 inclusive? | {
"A": "15",
"B": "125",
"C": "25",
"D": "75",
"E": "50"
} | add(divide(100, const_2), divide(50, const_2)) | divide(n1,const_2)|divide(n3,const_2)|add(#0,#1) | so , according to a mean of a set of even numbers from 0 to 100 = ( 0 + 100 ) / 2 = 50 and mean of a set of even numbers from 0 to 50 = ( 0 + 50 ) / 2 = 25 sum = 50 + 25 = 75 answer : d . | general |
math_qa__6XD6BsTC7KrEMlvD | Mr. loyd wants to fence his Square shaped land of 150Sqft each side.If a pole is laid every 30ft how many poles do he need? Choose the correct answer:
A) 20
B) 30
C) 40
D) 50
E) 60 | <gadget id="calculator">150 * 4</gadget>
<output>600</output>
<gadget id="calculator">600 / 10</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>B</result> | B | 30 | Mr. loyd wants to fence his Square shaped land of 150Sqft each side.If a pole is laid every 30ft how many poles do he need? | {
"A": "20",
"B": "30",
"C": "40",
"D": "50",
"E": "60"
} | divide(divide(multiply(150, const_4), const_10), const_2) | multiply(n0,const_4)|divide(#0,const_10)|divide(#1,const_2) | if each side is 120 feet . . then total perimeter is 150 * 4 = 600 poles every 20 feet hence no of poles = 600 / 20 = 30 answer : b | geometry |
math_qa__KZ70gJRy4bWON9VB | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 12-inch boxes. If the university pays $0.50 for every box, and if the university needs 1.92 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? Choose the correct choice from the following choices: A) $ 150 B) $ 200 C) $ 320 D) $ 650 E) $ 810 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">1.92 * 1_000_000</gadget>
<output>1_920_000</output>
<gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">400 * 12</gadget>
<output>4_800</output>
<gadget id="calculator">1_920_000 / 4_800</gadget>
<output>400</output>
<gadget id="calculator">400 * 0.5</gadget>
<output>200</output>
<result>B</result> | B | 200 | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 12-inch boxes. If the university pays $0.50 for every box, and if the university needs 1.92 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? | {
"A": "$ 150",
"B": "$ 200",
"C": "$ 320",
"D": "$ 650",
"E": "$ 810"
} | multiply(divide(multiply(1.92, multiply(const_1000, const_1000)), multiply(multiply(20, 20), 12)), 0.50) | multiply(const_1000,const_1000)|multiply(n0,n0)|multiply(n4,#0)|multiply(n2,#1)|divide(#2,#3)|multiply(n3,#4)| | "the volume of each box is 20 * 20 * 12 = 4800 cubic inches . number of boxes = 1 , 920,000 / 4800 = 400 boxes total cost = 400 × $ 0.5 = $ 200 the answer is b ." | general |
math_qa__IaLzAnDgsXMSjs5e | Find the simple interest on Rs. 68,800 at 16 2/3% per annum for 9 months. Choose the correct choice from the following answers
A) s . 8600 B) s . 8000 C) s . 7500 D) s . 7000 E) s . 6500 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 * 100</gadget>
<output>60_000</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 100</gadget>
<output>900</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">900 * 10</gadget>
<output>9_000</output>
<gadget id="calculator">60_000 + 9_000</gadget>
<output>69_000</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 + 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 3</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">69_000 * (50/3)</gadget>
<output>1_150_000</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1_150_000 * (3/4)</gadget>
<output>862_500</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">862_500 * (1/100)</gadget>
<output>8_625</output>
<result>A</result> | A | 8,600 | Find the simple interest on Rs. 68,800 at 16 2/3% per annum for 9 months. | {
"A": "s . 8600",
"B": "s . 8000",
"C": "s . 7500",
"D": "s . 7000",
"E": "s . 6500"
} | multiply(multiply(multiply(add(multiply(multiply(multiply(2, 3), const_100), const_100), multiply(multiply(multiply(3, 3), const_100), multiply(add(3, 2), 2))), divide(add(multiply(16, 3), 2), 3)), divide(multiply(3, 3), multiply(2, multiply(2, 3)))), divide(const_1, const_100)) | add(n2,n3)|divide(const_1,const_100)|multiply(n3,n3)|multiply(n2,n3)|multiply(n1,n3)|add(n2,#4)|multiply(n2,#3)|multiply(#3,const_100)|multiply(#2,const_100)|multiply(#0,n2)|divide(#2,#6)|divide(#5,n3)|multiply(#7,const_100)|multiply(#8,#9)|add(#12,#13)|multiply(#14,#11)|multiply(#10,#15)|multiply(#1,#16)| | "p = rs . 68800 , r = 50 / 3 % p . a and t = 9 / 12 years = 3 / 4 years . s . i . = ( p * r * t ) / 100 = rs . ( 68,800 * ( 50 / 3 ) * ( 3 / 4 ) * ( 1 / 100 ) ) = rs . 8600 answer is a ." | gain |
math_qa__wEJKXUqhDUlQq30n | In the list 1, 2, 3, 4, 5, 5, 5, 5, 7, 11, 21, what fraction of the data is less than the mode? Answers
A) 2 / 9
B) 1 / 3
C) 2 / 5
D) 4 / 11
E) 7 / 9 | <gadget id="calculator">4 / 11</gadget>
<output>4/11 = around 0.363636</output>
<result>D</result> | D | 0.363636 | In the list 1, 2, 3, 4, 5, 5, 5, 5, 7, 11, 21, what fraction of the data is less than the mode? | {
"A": "2 / 9",
"B": "1 / 3",
"C": "2 / 5",
"D": "4 / 11",
"E": "7 / 9"
} | divide(const_4.0, 11) | divide(n3,n9)| | "mode : the mode of any set is the term which has the highest frequency ( occurrence ) highest frequent term in the set is 5 ( with frequency 4 ) hence mode = 5 four terms ( 1 , 2 , 3 , 4 ) out of a total of 11 terms are less than mode of the set . fraction of set that are less than mode of set = 4 / 11 answer : option d" | general |
math_qa__xdYCh5UbPaVhckWf | A soft drink company had 6000 small and 14000 big bottles in storage. If 20% of small 23% of big bottles have been sold, then the total bottles remaining in storage is Options.
A) 15360
B) 15720
C) 15060
D) 14930
E) 16075 | <gadget id="calculator">6_000 + 14_000</gadget>
<output>20_000</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">6_000 * (1/5)</gadget>
<output>1_200</output>
<gadget id="calculator">23 / 100</gadget>
<output>23/100 = around 0.23</output>
<gadget id="calculator">(23/100) * 14_000</gadget>
<output>3_220</output>
<gadget id="calculator">1_200 + 3_220</gadget>
<output>4_420</output>
<gadget id="calculator">20_000 - 4_420</gadget>
<output>15_580</output>
<result>B</result> | B | 15,720 | A soft drink company had 6000 small and 14000 big bottles in storage. If 20% of small 23% of big bottles have been sold, then the total bottles remaining in storage is | {
"A": "15360",
"B": "15720",
"C": "15060",
"D": "14930",
"E": "16075"
} | subtract(add(6000, 14000), add(multiply(6000, divide(20, const_100)), multiply(divide(23, const_100), 14000))) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|subtract(#0,#5)| | "6000 + 14000 - ( 0.2 * 6000 + 0.22 * 14000 ) = 15720 . answer : b ." | general |
math_qa__7ftAYDLoUtGSd45h | Express a speed of 72 kmph in meters per second? Choose the correct choice
A) 10 mps B) 76 mps C) 20 mps D) 97 mps E) 16 mps | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 72</gadget>
<output>20</output>
<result>C</result> | C | 20 | Express a speed of 72 kmph in meters per second? | {
"A": "10 mps",
"B": "76 mps",
"C": "20 mps",
"D": "97 mps",
"E": "16 mps"
} | multiply(const_0_2778, 72) | multiply(n0,const_0_2778)| | "72 * 5 / 18 = 20 mps answer : c" | physics |
math_qa__D0KrFamPP8hdj1T6 | There are 10 teams in a soccer league and each team plays each of the other teams once. How many games will be played in total? Choose the correct choice from the following options:
A) 33 B) 36 C) 39 D) 42 E) 45 | <gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">40_320 * 2</gadget>
<output>80_640</output>
<gadget id="calculator">3_628_800 / 80_640</gadget>
<output>45</output>
<result>E</result> | E | 45 | There are 10 teams in a soccer league and each team plays each of the other teams once. How many games will be played in total? | {
"A": "33",
"B": "36",
"C": "39",
"D": "42",
"E": "45"
} | divide(factorial(10), multiply(factorial(subtract(10, const_2)), factorial(const_2))) | factorial(n0)|factorial(const_2)|subtract(n0,const_2)|factorial(#2)|multiply(#3,#1)|divide(#0,#4)| | "10 c 2 = 45 the answer is e ." | general |
math_qa__AUHkKEqP33bJEeuk | if two of the 4 expressions x + y , x + 5 y , x - y , 5 x + y are chosen at random , what is the probability that their product will be of the form of x ^ 2 - ( by ) ^ 2 , where b is an integer ? Select:
A) 1 / 2
B) 1 / 3
C) 1 / 4
D) 1 / 5
E) 1 / 6 | <gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<result>E</result> | E | 0.166667 | if two of the 4 expressions x + y , x + 5 y , x - y , 5 x + y are chosen at random , what is the probability that their product will be of the form of x ^ 2 - ( by ) ^ 2 , where b is an integer ? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 5",
"E": "1 / 6"
} | divide(subtract(5, 4), add(4, 2)) | add(n0,n3)|subtract(n1,n0)|divide(#1,#0) | there are total 4 c 2 = 64 c 2 = 6 ways to choose 2 equations out of 4 at random . we want the product of 2 equations in format x 2 − ( by ) 2 x 2 − ( by ) 2 , where b is a constant coefficient of term y 2 y 2 . also note equation does not contain any xyxy term . there are only 2 equations , ( x + y ) & ( x - y ) which gives the product x 2 − y 2 x 2 − y 2 . product of all other equations will contain term xyxy so answer = 1 / 6 ans : e | general |
math_qa__TKDHBqEzLAHLpGXF | How many seconds will a 100 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Choose the correct option: A) 11 sec B) 6 sec C) 77 sec D) 14 sec E) 12 | <gadget id="calculator">63 - 3</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">100 / (50/3)</gadget>
<output>6</output>
<result>B</result> | B | 6 | How many seconds will a 100 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? | {
"A": "11 sec",
"B": "6 sec",
"C": "77 sec",
"D": "14 sec",
"E": "12"
} | divide(100, multiply(subtract(63, 3), const_0_2778)) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 63 - 3 = 60 km / hr . = 60 * 5 / 18 = 50 / 3 m / sec . time taken to pass the man = 100 * 3 / 50 = 6 sec . answer : b" | physics |
math_qa__AohqkUqXCufBQDeL | In a colony of 70 residents, the ratio of the number of men and women is 4 : 3. Among the women, the ratio of the educated to the uneducated is 1 : 4. If the ratio of the number of educated to uneducated persons is 8 : 27, then find the ratio of the number of educated to uneducated men in the colony?
Choose the correct answer
A) 1 : 7 B) 2 : 3 C) 1 : 8 D) 2 : 3 E) 1 : 3 | <gadget id="calculator">8 + 27</gadget>
<output>35</output>
<gadget id="calculator">70 / 35</gadget>
<output>2</output>
<gadget id="calculator">2 * 8</gadget>
<output>16</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">70 / 7</gadget>
<output>10</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">16 - 6</gadget>
<output>10</output>
<gadget id="calculator">2 * 27</gadget>
<output>54</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">54 - 24</gadget>
<output>30</output>
<gadget id="calculator">10 / 30</gadget>
<output>1/3 = around 0.333333</output>
<result>E</result> | E | 0.333333 | In a colony of 70 residents, the ratio of the number of men and women is 4 : 3. Among the women, the ratio of the educated to the uneducated is 1 : 4. If the ratio of the number of educated to uneducated persons is 8 : 27, then find the ratio of the number of educated to uneducated men in the colony? | {
"A": "1 : 7",
"B": "2 : 3",
"C": "1 : 8",
"D": "2 : 3",
"E": "1 : 3"
} | divide(subtract(multiply(divide(70, add(8, 27)), 8), divide(multiply(divide(70, add(4, 3)), 3), add(1, 4))), subtract(multiply(divide(70, add(8, 27)), 27), multiply(divide(multiply(divide(70, add(4, 3)), 3), add(1, 4)), 4))) | add(n5,n6)|add(n1,n2)|add(n1,n3)|divide(n0,#0)|divide(n0,#1)|multiply(n5,#3)|multiply(n2,#4)|multiply(n6,#3)|divide(#6,#2)|multiply(n1,#8)|subtract(#5,#8)|subtract(#7,#9)|divide(#10,#11) | number of men in the colony = 4 / 7 * 70 = 40 . number of women in the colony = 3 / 7 * 70 = 40 . number educated women in the colony = 1 / 5 * 30 = 6 . number of uneducated women in the colony = 4 / 5 * 50 = 24 . number of educated persons in the colony = 8 / 35 * 70 = 16 . as 6 females are educated , remaining 10 educated persons must be men . number of uneducated men in the colony = 40 - 10 = 30 . number of educated men and uneducated men are in the ratio 10 : 30 i . e . , 1 : 3 . answer : e | other |
math_qa__NJgCoKvTmSotH8ST | A cube of edge 5 cm is cut into cubes of each edge 1 cm. The ratio of the total surface area of one of the small cubes to that of the large cube is equal to Choose the correct answer
A) 1 : 5 B) 1 : 25 C) 1 : 125 D) 1 : 625 E) none | <gadget id="calculator">6 * (1 ** 2)</gadget>
<output>6</output>
<gadget id="calculator">6 * (5 ** 2)</gadget>
<output>150</output>
<gadget id="calculator">6 / 150</gadget>
<output>1/25 = around 0.04</output>
<result>B</result> | B | 0.04 | A cube of edge 5 cm is cut into cubes of each edge 1 cm. The ratio of the total surface area of one of the small cubes to that of the large cube is equal to | {
"A": "1 : 5",
"B": "1 : 25",
"C": "1 : 125",
"D": "1 : 625",
"E": "none"
} | divide(surface_cube(1), surface_cube(5)) | surface_cube(n1)|surface_cube(n0)|divide(#0,#1) | solution required ratio = ( 6 x 1 x 1 / 6 x 5 x 5 ) ‹ = › 1 / 25 ‹ = › 1 : 125 . answer b | geometry |
math_qa__JdY4jNJx5wikHFBw | Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 7 as quotient and the 15 as remainder Pick one
A) 1235 B) 1346 C) 1590 D) 1635 E) 1489 | <gadget id="calculator">1_365 - 15</gadget>
<output>1_350</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">1_350 / 6</gadget>
<output>225</output>
<gadget id="calculator">225 * 7</gadget>
<output>1_575</output>
<result>C</result> | C | 1,590 | Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 7 as quotient and the 15 as remainder | {
"A": "1235",
"B": "1346",
"C": "1590",
"D": "1635",
"E": "1489"
} | multiply(divide(subtract(1365, 15), subtract(7, const_1)), 7) | subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)| | "let the smaller number be x . then larger number = ( x + 1365 ) . x + 1365 = 7 x + 15 6 x = 1350 x = 225 large number = 225 + 1365 = 1590 c" | general |
math_qa__sjfArfKQiP1yE0Z5 | Alex age after 13years will be 10 times his age 10years back. What is the present age of Alex?
Options:
A) 15 B) 13 C) 20 D) 21 E) 26 | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">100 + 13</gadget>
<output>113</output>
<gadget id="calculator">12 - 3</gadget>
<output>9</output>
<gadget id="calculator">113 / 9</gadget>
<output>113/9 = around 12.555556</output>
<result>B</result> | B | 13 | Alex age after 13years will be 10 times his age 10years back. What is the present age of Alex? | {
"A": "15",
"B": "13",
"C": "20",
"D": "21",
"E": "26"
} | divide(add(multiply(const_10, const_10), 13), subtract(const_12, const_3)) | multiply(const_10,const_10)|subtract(const_12,const_3)|add(n0,#0)|divide(#2,#1) | let alex ' s present age be x alex ' s age after 17 years = x + 17 alex ' s age 10 years back = x - 10 x + 17 = 10 ( x - 10 ) x = 13 rajeev ' s present age = 13 years answer is b | general |
math_qa__0o6hRzjybAEPQvpE | When a person aged 39 is added to a group of n people, the average age increases by 2. When a person aged 15 is added instead, the average age decreases by 1. What is the value of Q? Choose the correct choice from the following options
A) 7
B) 8
C) 9
D) 10
E) 11 | <gadget id="calculator">39 - 15</gadget>
<output>24</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">24 / 3</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<result>A</result> | A | 7 | When a person aged 39 is added to a group of n people, the average age increases by 2. When a person aged 15 is added instead, the average age decreases by 1. What is the value of Q? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | subtract(divide(subtract(39, 15), add(2, 1)), 1) | add(n1,n3)|subtract(n0,n2)|divide(#1,#0)|subtract(#2,n3)| | "a simple and elegant solution . as addition of 39 , shifts mean by 2 , and addition of 15 , shifts mean by 1 to the other side , we have the mean lying between 3915 , and in a ratio of 2 : 1 39 - 15 = 24 24 divide by 3 is 8 . meaning mean of the n terms is 15 + 8 = 39 - 16 = 23 now , from first statement , when a person aged 39 is added to a group of n people , the average age increases by 2 . q * 23 + 39 = 25 * ( q + 1 ) q = 7 ans . ( a )" | general |
math_qa__Tl2E1nZ6HUIaQiYT | How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 60 m long and 16 1/2 m board? Choose the correct answer.
A) 99 B) 18 C) 16 D) 198 E) 15 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">16 + (1/2)</gadget>
<output>33/2 = around 16.5</output>
<gadget id="calculator">60 * (33/2)</gadget>
<output>990</output>
<gadget id="calculator">2 + (1/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 2</gadget>
<output>5</output>
<gadget id="calculator">990 / 5</gadget>
<output>198</output>
<result>D</result> | D | 198 | How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 60 m long and 16 1/2 m board? | {
"A": "99",
"B": "18",
"C": "16",
"D": "198",
"E": "15"
} | divide(multiply(60, add(16, divide(1, 2))), multiply(add(2, divide(1, 2)), 2)) | divide(n1,n0)|add(n5,#0)|add(n0,#0)|multiply(n4,#1)|multiply(n0,#2)|divide(#3,#4)| | "60 * 33 / 2 = 5 / 2 * 2 * x = > x = 198 answer : d" | general |
math_qa__a6u3TGNQg7oGLbkA | 10% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3213, how much was it in the beginning?
Options
A) 3800 B) 4200 C) 4400 D) 4500 E) 4600 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(9/10) * (17/20)</gadget>
<output>153/200 = around 0.765</output>
<gadget id="calculator">3_213 / (153/200)</gadget>
<output>4_200</output>
<gadget id="calculator">floor(4_200)</gadget>
<output>4_200</output>
<result>B</result> | B | 4,200 | 10% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3213, how much was it in the beginning? | {
"A": "3800",
"B": "4200",
"C": "4400",
"D": "4500",
"E": "4600"
} | floor(divide(3213, multiply(divide(subtract(const_100, 10), const_100), divide(subtract(const_100, 15), const_100)))) | subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|divide(n2,#4)|floor(#5)| | "x * ( 90 / 100 ) * ( 85 / 100 ) = 3213 x = 4200 answer : b" | general |
math_qa__Eg24VM63giR09Q6S | A jogger running at 9 km/hr along side a railway track is 180 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Pick one: A) 89 B) 20 C) 36 D) 88 E) 30 | <gadget id="calculator">180 + 120</gadget>
<output>300</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">5 / 18</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">300 / 10</gadget>
<output>30</output>
<result>E</result> | E | 30 | A jogger running at 9 km/hr along side a railway track is 180 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? | {
"A": "89",
"B": "20",
"C": "36",
"D": "88",
"E": "30"
} | divide(add(180, 120), multiply(subtract(45, 9), divide(divide(const_10, const_2), divide(subtract(45, 9), const_2)))) | add(n1,n2)|divide(const_10,const_2)|subtract(n3,n0)|divide(#2,const_2)|divide(#1,#3)|multiply(#4,#2)|divide(#0,#5)| | "speed of train relative to jogger = 45 - 9 = 36 km / hr . = 36 * 5 / 18 = 10 m / sec . distance to be covered = 180 + 120 = 300 m . time taken = 300 / 10 = 30 sec . answer : option e" | general |
math_qa__lRLWRWOlGOI8XIq4 | 4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 6 mat-weavers in 6 days? Pick one: A) 25 B) 9 C) 39 D) 61 E) 16 | <gadget id="calculator">6 / 4</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">4 * (3/2)</gadget>
<output>6</output>
<gadget id="calculator">6 * (3/2)</gadget>
<output>9</output>
<result>B</result> | B | 9 | 4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 6 mat-weavers in 6 days? | {
"A": "25",
"B": "9",
"C": "39",
"D": "61",
"E": "16"
} | multiply(multiply(4, divide(6, 4)), divide(6, 4)) | divide(n3,n0)|multiply(n0,#0)|multiply(#0,#1)| | "let the required number of bottles be x . more weavers , more mats ( direct proportion ) more days , more mats ( direct proportion ) wavers 4 : 6 : : 4 : x days 4 : 6 4 * 4 * x = 6 * 6 * 4 x = ( 6 * 6 * 4 ) / ( 4 x 4 ) x = 9 . answer is b ." | gain |
math_qa__f0gJdSs5j9tWXOAC | Nitin ranks 12th in a class of 56 students. What is rank from the last ? Choose the correct choice from the following choices.
A) 33 B) 38 C) 45 D) 28 E) 19 | <gadget id="calculator">56 - 12</gadget>
<output>44</output>
<result>C</result> | C | 45 | Nitin ranks 12th in a class of 56 students. What is rank from the last ? | {
"A": "33",
"B": "38",
"C": "45",
"D": "28",
"E": "19"
} | subtract(56, 12) | subtract(n1,n0)| | "explanation : number students behind the nitin in rank = ( 56 - 12 ) = 44 nitin is 45 th from the last answer : c ) 45" | other |
math_qa__QX0OlkA6OQjlPUIV | Find the cost of fencing around a circular field of diameter 40 m at the rate of Rs.3 a meter? Choose the correct choice from the following choices:
A) 400 B) 370.4 C) 376.98 D) 340.9 E) 350.03 | <gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">2 * pi * 20</gadget>
<output>40*pi = around 125.663706</output>
<gadget id="calculator">(40*pi) * 3</gadget>
<output>120*pi = around 376.991118</output>
<result>C</result> | C | 376.98 | Find the cost of fencing around a circular field of diameter 40 m at the rate of Rs.3 a meter? | {
"A": "400",
"B": "370.4",
"C": "376.98",
"D": "340.9",
"E": "350.03"
} | multiply(circumface(divide(40, const_2)), 3) | divide(n0,const_2)|circumface(#0)|multiply(n1,#1)| | "2 * 22 / 7 * 20 = 125.66 125.66 * 3 = rs . 376.98 answer : c" | physics |
math_qa__u7IvzfMAqPUZmbQs | Tickets to a certain concert sell for $20 each. The first 10 people to show up at the ticket booth received a 40% discount, and the next 20 received a 15% discount. If 50 people bought tickets to the concert, what was the total revenue from ticket sales? Choose the correct choice from the following options: A) $ 600 B) $ 740 C) $ 860 D) $ 980 E) $ 1,140 | <gadget id="calculator">50 - 20</gadget>
<output>30</output>
<gadget id="calculator">30 - 10</gadget>
<output>20</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 10</gadget>
<output>6</output>
<gadget id="calculator">20 + 6</gadget>
<output>26</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(17/20) * 20</gadget>
<output>17</output>
<gadget id="calculator">26 + 17</gadget>
<output>43</output>
<gadget id="calculator">43 * 20</gadget>
<output>860</output>
<result>C</result> | C | 860 | Tickets to a certain concert sell for $20 each. The first 10 people to show up at the ticket booth received a 40% discount, and the next 20 received a 15% discount. If 50 people bought tickets to the concert, what was the total revenue from ticket sales? | {
"A": "$ 600",
"B": "$ 740",
"C": "$ 860",
"D": "$ 980",
"E": "$ 1,140"
} | multiply(add(add(subtract(subtract(50, 20), 10), multiply(subtract(const_1, divide(40, const_100)), 10)), multiply(subtract(const_1, divide(15, const_100)), 20)), 20) | divide(n2,const_100)|divide(n4,const_100)|subtract(n5,n0)|subtract(const_1,#0)|subtract(#2,n1)|subtract(const_1,#1)|multiply(n1,#3)|multiply(n0,#5)|add(#6,#4)|add(#8,#7)|multiply(n0,#9)| | "price of 1 ticket = 20 $ revenue generated from sales of first 10 tickets = 10 * ( 60 / 100 * 20 ) = 10 * 12 = 120 revenue generated from sales of next 20 tickets = 20 * ( 85 / 100 * 20 ) = 20 * 17 = 340 revenue generated from sales of last 20 tickets = 20 * 20 = 400 revenue generated from sales of 50 tickets = 120 + 340 + 400 = 860 $ answer c" | gain |
math_qa__jCsaGVX1p98vDCwB | x+(1/x) = 1.5 find x^2 + (1/x^2) Options:
A) 2.25 B) 3.25 C) 4.25 D) 5.25 E) 0.25 | <gadget id="calculator">1.5 ** 2</gadget>
<output>2.25</output>
<gadget id="calculator">2.25 - 2</gadget>
<output>0.25</output>
<result>E</result> | E | 0.25 | x+(1/x) = 1.5 find x^2 + (1/x^2) | {
"A": "2.25",
"B": "3.25",
"C": "4.25",
"D": "5.25",
"E": "0.25"
} | subtract(power(1.5, 2), 2) | power(n1,n2)|subtract(#0,n2)| | "squaring on both sides ( x + 1 / x ) ^ 2 = 1.5 ^ 2 x ^ 2 + 1 / x ^ 2 = 2.25 - 2 x ^ 2 + 1 / x ^ 2 = 0.25 answer : e" | general |
math_qa__L6jCzBrziVsbt8P3 | P can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 60 days to complete the same work. then Q alone can do it in Pick one: A) 20 B) 24 C) 25 D) 27 E) 30 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/10) + (1/60)</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">(7/60) / 2</gadget>
<output>7/120 = around 0.058333</output>
<gadget id="calculator">(7/120) - (1/60)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<result>B</result> | B | 24 | P can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 60 days to complete the same work. then Q alone can do it in | {
"A": "20",
"B": "24",
"C": "25",
"D": "27",
"E": "30"
} | divide(const_1, subtract(divide(add(divide(const_1, 10), divide(const_1, 60)), const_2), divide(const_1, 60))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(#2,const_2)|subtract(#3,#1)|divide(const_1,#4)| | "work done by p and q in 1 day = 1 / 10 work done by r in 1 day = 1 / 60 work done by p , q and r in 1 day = 1 / 10 + 1 / 60 = 7 / 60 but work done by p in 1 day = work done by q and r in 1 day . hence the above equation can be written as work done by p in 1 day ã — 2 = 7 / 60 = > work done by p in 1 day = 7 / 120 = > work done by q and r in 1 day = 7 / 120 hence work done by q in 1 day = 7 / 120 â € “ 1 / 60 = 1 / 24 so q alone can do the work in 24 days answer is b ." | physics |
math_qa__HpcOoefJ6KT9lnyp | The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A? Select the correct option.
A) 10
B) 11
C) 12
D) 13
E) 15 | <gadget id="calculator">12 * 1</gadget>
<output>12</output>
<result>C</result> | C | 12 | The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A? | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "15"
} | multiply(12, const_1) | multiply(n0,const_1)| | "given that , a + b = 12 + b + c ⇒ a - c = 12 therefore , c is younger than a by 12 years answer is c ." | general |
math_qa__ehfQKtFfqJBT14ia | There are 1000 students in a school and among them 25 % of them attends chess class. 50% of the students who are in the chess class are also enrolled for swimming. No other students are interested in swimming so how many will attend the swimming class if all enrolled attends? Choose the correct choice from the following: A) 1 B) 10 C) 125 D) 50 E) 20 | <gadget id="calculator">25 * 1_000</gadget>
<output>25_000</output>
<gadget id="calculator">25_000 / 100</gadget>
<output>250</output>
<gadget id="calculator">250 * 50</gadget>
<output>12_500</output>
<gadget id="calculator">12_500 / 100</gadget>
<output>125</output>
<result>C</result> | C | 125 | There are 1000 students in a school and among them 25 % of them attends chess class. 50% of the students who are in the chess class are also enrolled for swimming. No other students are interested in swimming so how many will attend the swimming class if all enrolled attends? | {
"A": "1",
"B": "10",
"C": "125",
"D": "50",
"E": "20"
} | divide(multiply(divide(multiply(25, 1000), const_100), 50), const_100) | multiply(n0,n1)|divide(#0,const_100)|multiply(n2,#1)|divide(#2,const_100)| | "25 % of 1000 gives 250 . so 250 attends chess and 50 % of 250 gives 125 so 125 enrolled for swimming answer : c" | gain |
math_qa__7czdsxW80WjuNBMp | The temperature of a certain cup of coffee 10 minutes after it was poured was 120 degrees Fahrenheit. If the temperature F of the coffee t minutes after it was poured can be determined by the formula F=120(2^-at) + 60, where F is in degrees Fahrenheit and a is a constant. Then the temperature of the coffee 60 minutes after it was poured was how many degrees Fahrenheit? Choose the correct choice from the following choices:
A) 125 B) 95 C) 80 D) 61.8 E) 50 | <gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">1 - 2</gadget>
<output>-1</output>
<gadget id="calculator">6 * (-1)</gadget>
<output>-6</output>
<gadget id="calculator">2 ** (-6)</gadget>
<output>1/64 = around 0.015625</output>
<gadget id="calculator">(1/64) * 120</gadget>
<output>15/8 = around 1.875</output>
<gadget id="calculator">(15/8) + 60</gadget>
<output>495/8 = around 61.875</output>
<result>D</result> | D | 61.8 | The temperature of a certain cup of coffee 10 minutes after it was poured was 120 degrees Fahrenheit. If the temperature F of the coffee t minutes after it was poured can be determined by the formula F=120(2^-at) + 60, where F is in degrees Fahrenheit and a is a constant. Then the temperature of the coffee 60 minutes after it was poured was how many degrees Fahrenheit? | {
"A": "125",
"B": "95",
"C": "80",
"D": "61.8",
"E": "50"
} | add(multiply(power(2, multiply(divide(60, 10), subtract(const_1, const_2))), 120), 60) | divide(n4,n0)|subtract(const_1,const_2)|multiply(#0,#1)|power(n3,#2)|multiply(n1,#3)|add(n4,#4) | answer : b the temperature of coffee 10 minutes after it was poured ( 120 f ) will help in solving the constant “ a ” . 120 = 120 ( 2 ^ 10 a ) + 60 2 ^ - 1 = 2 ^ 10 a a = - 1 / 10 the temperature of coffee 60 minutes after it was poured is : f = 120 ( 2 ^ - 60 / 10 ) + 60 f = 120 * 1 / 64 + 60 f = 15 / 8 + 60 f = 495 / 8 = 61.8 d | general |
math_qa__2W1n127cwNs5tULa | The edges of three iron cubes are 6cm; 8cm; 10cm respectively. A new cube was made by melting them. Find the edge of the new cube?
Choose the correct choice from the following choices
A) 17 B) 19 C) 16 D) 12 E) 14 | <gadget id="calculator">100 + 3</gadget>
<output>103</output>
<gadget id="calculator">8 * 10</gadget>
<output>80</output>
<gadget id="calculator">80 + 3</gadget>
<output>83</output>
<gadget id="calculator">103 + 83</gadget>
<output>186</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">60 + 3</gadget>
<output>63</output>
<gadget id="calculator">186 + 63</gadget>
<output>249</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">1 + 20</gadget>
<output>21</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">21 - (1/4)</gadget>
<output>83/4 = around 20.75</output>
<gadget id="calculator">249 / (83/4)</gadget>
<output>12</output>
<result>D</result> | D | 12 | The edges of three iron cubes are 6cm; 8cm; 10cm respectively. A new cube was made by melting them. Find the edge of the new cube? | {
"A": "17",
"B": "19",
"C": "16",
"D": "12",
"E": "14"
} | divide(add(add(add(const_100, const_3), add(multiply(8, const_10), const_3)), add(multiply(10, 6), const_3)), subtract(add(const_1, multiply(const_2, 10)), const_0_25)) | add(const_100,const_3)|multiply(n1,const_10)|multiply(n0,n2)|multiply(n2,const_2)|add(#1,const_3)|add(#2,const_3)|add(#3,const_1)|add(#0,#4)|subtract(#6,const_0_25)|add(#7,#5)|divide(#9,#8) | 63 + 83 + 103 = a 3 = > a = 12 answer : d | physics |
math_qa__7L6Vz2kFb0HTtCrz | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? Choose the most appropriate option
A) 76 B) 76.5 C) 85 D) 80 E) none of these | <gadget id="calculator">8 * 2.5</gadget>
<output>20</output>
<gadget id="calculator">20 + 65</gadget>
<output>85</output>
<result>C</result> | C | 85 | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? | {
"A": "76",
"B": "76.5",
"C": "85",
"D": "80",
"E": "none of these"
} | add(multiply(8, 2.5), 65) | multiply(n0,n1)|add(n2,#0)| | "explanation : total weight increased = ( 8 x 2.5 ) kg = 20 kg . weight of new person = ( 65 + 20 ) kg = 85 kg . answer : c" | general |
math_qa__kOGdrLa0L0RqmRK3 | Someone on a skateboard is traveling 5 miles per hour. How many feet does she travel in 45 seconds? (1 mile = 5280 feet) Answers.
A) 380 ft B) 400 ft C) 410.05 ft D) 329.85 ft E) 420.85 ft | <gadget id="calculator">5 * 5_280</gadget>
<output>26_400</output>
<gadget id="calculator">26_400 / 3_600</gadget>
<output>22/3 = around 7.333333</output>
<gadget id="calculator">45 * (22/3)</gadget>
<output>330</output>
<result>D</result> | D | 329.85 | Someone on a skateboard is traveling 5 miles per hour. How many feet does she travel in 45 seconds? (1 mile = 5280 feet) | {
"A": "380 ft",
"B": "400 ft",
"C": "410.05 ft",
"D": "329.85 ft",
"E": "420.85 ft"
} | multiply(45, divide(multiply(5, 5280), const_3600)) | multiply(n0,n3)|divide(#0,const_3600)|multiply(n1,#1)| | "per second = > 5 * 5280 ft / 60 * 60 = 7.33 ft 45 seconds = > 7.33 * 45 = 329.85 ft answer : d" | physics |
math_qa__70fbujiFQyoprt9y | A bucket contains 2 mixtures A and B in the ratio 7:5. If 9 liters of the mixture is replaced by 9 liters of liquid B, then the ratio of the two liquids becomes 7:9. How much of the liquid A was there in the bucket? Choose the correct choice from the following answers
A) 15 liters
B) 21 liters
C) 12 liters
D) 18 liters
E) 25 liters | <gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">7 / 12</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">(7/12) * 9</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">9 * (21/4)</gadget>
<output>189/4 = around 47.25</output>
<gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) * 9</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">9 - (15/4)</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">7 * (21/4)</gadget>
<output>147/4 = around 36.75</output>
<gadget id="calculator">(189/4) + (147/4)</gadget>
<output>84</output>
<gadget id="calculator">9 * 7</gadget>
<output>63</output>
<gadget id="calculator">5 * 7</gadget>
<output>35</output>
<gadget id="calculator">63 - 35</gadget>
<output>28</output>
<gadget id="calculator">84 / 28</gadget>
<output>3</output>
<gadget id="calculator">3 * 7</gadget>
<output>21</output>
<result>B</result> | B | 21 | A bucket contains 2 mixtures A and B in the ratio 7:5. If 9 liters of the mixture is replaced by 9 liters of liquid B, then the ratio of the two liquids becomes 7:9. How much of the liquid A was there in the bucket? | {
"A": "15 liters",
"B": "21 liters",
"C": "12 liters",
"D": "18 liters",
"E": "25 liters"
} | multiply(divide(add(multiply(9, multiply(divide(7, add(7, 5)), 9)), multiply(7, subtract(9, multiply(divide(5, add(7, 5)), 9)))), subtract(multiply(9, 7), multiply(5, 7))), 7) | add(n1,n2)|multiply(n1,n3)|multiply(n1,n2)|divide(n1,#0)|divide(n2,#0)|subtract(#1,#2)|multiply(n3,#3)|multiply(n3,#4)|multiply(n3,#6)|subtract(n3,#7)|multiply(n1,#9)|add(#8,#10)|divide(#11,#5)|multiply(n1,#12) | 1 st ratio = 7 : 5 2 nd ratio = 7 : 9 difference of cross products ratio = 7 * 9 - 7 * 5 = 28 common factor of the 1 st ratio = ( quantity replaced / sum of terms in 1 st ratio ) + ( quantity replaced * term a in 2 nd ratio / difference ) = ( 9 / 7 + 5 ) + ( 9 * 7 / 28 ) = 3 quantity of a = 7 * 3 = 21 liters answer is b | general |
math_qa__QH7JzEZgvqoG4Tvg | The cost to park a car in a certain parking garage is $12.00 for up to 2 hours of parking and $1.75 for each hour in excess of 2 hours. What is the average (arithmetic mean) cost per hour to park a car in the parking garage for 9 hours?
Choose the correct option:
A) $ 1.09 B) $ 2.69 C) $ 2.25 D) $ 2.37 E) $ 2.50 | <gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">1.75 * 7</gadget>
<output>12.25</output>
<gadget id="calculator">12 + 12.25</gadget>
<output>24.25</output>
<gadget id="calculator">24.25 / 9</gadget>
<output>2.694444</output>
<result>B</result> | B | 2.69 | The cost to park a car in a certain parking garage is $12.00 for up to 2 hours of parking and $1.75 for each hour in excess of 2 hours. What is the average (arithmetic mean) cost per hour to park a car in the parking garage for 9 hours? | {
"A": "$ 1.09",
"B": "$ 2.69",
"C": "$ 2.25",
"D": "$ 2.37",
"E": "$ 2.50"
} | divide(add(12.00, multiply(1.75, subtract(9, 2))), 9) | subtract(n4,n1)|multiply(n2,#0)|add(n0,#1)|divide(#2,n4)| | "total cost of parking for 9 hours = 12 $ for the first 2 hours and then 1.75 for ( 9 - 2 ) hours = 12 + 7 * 1.75 = 24.25 thus the average parking price = 24.25 / 9 = 2.69 $ b is the correct answer ." | general |
math_qa__wWUoDJ37mNoxwmmA | In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability T this college graduate has a graduate degree?
Choose the most appropriate option:
A) 1 / 11 B) 1 / 12 C) 1 / 13 D) 3 / 19 E) 3 / 43 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(1/8) / (2/3)</gadget>
<output>3/16 = around 0.1875</output>
<gadget id="calculator">(3/16) + 1</gadget>
<output>19/16 = around 1.1875</output>
<gadget id="calculator">(3/16) / (19/16)</gadget>
<output>3/19 = around 0.157895</output>
<result>D</result> | D | 0.157895 | In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability T this college graduate has a graduate degree? | {
"A": "1 / 11",
"B": "1 / 12",
"C": "1 / 13",
"D": "3 / 19",
"E": "3 / 43"
} | divide(divide(divide(1, 8), divide(2, 3)), add(divide(divide(1, 8), divide(2, 3)), 1)) | divide(n0,n1)|divide(n2,n3)|divide(#0,#1)|add(#2,n0)|divide(#2,#3)| | "in believe the answer is d . please see below for explanation . 0 ) we are told the following ratios cgd - college graduate with degree ncg - non college graduate cgn - college graduate no degree cgd ncg cgn 1 8 3 2 in order to make cgd and cgn comparable we need to find the least common multiple of 8 and 3 and that is 24 multiplying the first ratio by 3 and the second ratio by 8 we get cgd ncg cgn 3 24 16 if one picks a random college graduate at this large company , what is the probability this college graduate has a graduate degree ? nr of cgd = 3 nr of cg = 3 + 16 = 19 probability t of cgd / ( cg ) - > 3 / 19 answer d" | other |
math_qa__pKG0YygwmSIWfctc | Walking with 4/5 of my usual speed, I arrive at the bus stop 6 minutes later than normal. How many minutes does it take to walk to the bus stop at my usual speed? Choices
A) 20 min B) 22 min C) 15 min D) 18 min E) 24 min | <gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) - 1</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">6 / (1/4)</gadget>
<output>24</output>
<result>E</result> | E | 24 | Walking with 4/5 of my usual speed, I arrive at the bus stop 6 minutes later than normal. How many minutes does it take to walk to the bus stop at my usual speed? | {
"A": "20 min",
"B": "22 min",
"C": "15 min",
"D": "18 min",
"E": "24 min"
} | divide(6, subtract(divide(5, 4), const_1)) | divide(n1,n0)|subtract(#0,const_1)|divide(n2,#1)| | "let t = usual time = distance / usual speed t + 6 = distance / ( 4 * usual speed / 5 ) = ( 5 * distance ) / ( 4 * usual speed ) = 5 t / 4 t = 24 the answer is e ." | physics |
math_qa__I8XzEFw7eP5nSowz | With both valves open, the pool will be filled with water in 48 minutes. The first valve alone would fill the pool in 2 hours. If the second valve emits 50 cubic meters of water more than the first every minute, then what is the capacity T of the pool? Choose the correct choice from the following options
A) 9000 cubic meters
B) 10500 cubic meters
C) 11750 cubic meters
D) 12000 cubic meters
E) 12500 cubic meters | <gadget id="calculator">48 / 60</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">(4/5) * 5</gadget>
<output>4</output>
<gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">50 * 240</gadget>
<output>12_000</output>
<result>D</result> | D | 12,000 | With both valves open, the pool will be filled with water in 48 minutes. The first valve alone would fill the pool in 2 hours. If the second valve emits 50 cubic meters of water more than the first every minute, then what is the capacity T of the pool? | {
"A": "9000 cubic meters",
"B": "10500 cubic meters",
"C": "11750 cubic meters",
"D": "12000 cubic meters",
"E": "12500 cubic meters"
} | multiply(50, multiply(const_60, multiply(divide(48, const_60), add(const_4, const_1)))) | add(const_1,const_4)|divide(n0,const_60)|multiply(#0,#1)|multiply(#2,const_60)|multiply(n2,#3)| | "d . 12000 cubic meters . if both hte valves fill the pool in 48 minutes and valve 1 only fills in 120 minutes then valve 2 alone will fill the pool in ( 48 * 120 ) / ( 120 - 48 ) = 80 minutes . now , if valve 1 admits x cubic meter of water per minute then the capacity of pool will be 120 x and also 80 ( x + 50 ) . or , 120 x = 80 ( x + 50 ) . or x = 100 . hence , the capacity of pool = 120 x = 12000 cubic meters ." | physics |
math_qa__iQgH4HqIMQs7ffqm | A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.160. Find the unknown rate of two blankets? Choose the correct option:
A) 420 B) 550 C) 490 D) 450 E) 457 | <gadget id="calculator">10 * 160</gadget>
<output>1_600</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">300 + 750</gadget>
<output>1_050</output>
<gadget id="calculator">1_600 - 1_050</gadget>
<output>550</output>
<result>B</result> | B | 550 | A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.160. Find the unknown rate of two blankets? | {
"A": "420",
"B": "550",
"C": "490",
"D": "450",
"E": "457"
} | subtract(multiply(const_10, 160), add(multiply(3, 100), multiply(5, 150))) | multiply(n4,const_10)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|subtract(#0,#3)| | "10 * 160 = 1600 3 * 100 + 5 * 150 = 1050 1600 – 1050 = 550 answer : b" | general |
math_qa__MBWxkYeQBJ5GcDqk | A 300 meter long train crosses a platform in 30 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? Choose the correct choice
A) 227 B) 266 C) 230 D) 288 E) 200 | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 30</gadget>
<output>500</output>
<gadget id="calculator">500 - 300</gadget>
<output>200</output>
<result>E</result> | E | 200 | A 300 meter long train crosses a platform in 30 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? | {
"A": "227",
"B": "266",
"C": "230",
"D": "288",
"E": "200"
} | subtract(multiply(divide(300, 18), 30), 300) | divide(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = [ 300 / 18 ] m / sec = 50 / 3 m / sec . let the length of the platform be x meters . then , x + 300 / 30 = 50 / 3 3 ( x + 300 ) = 1500 è x = 200 m . answer : e" | physics |
math_qa__AFh0t9CtxRt3ULh7 | Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. If the faster train passes the slower train in 36 seconds,what is the length of each train? Choose the most appropriate option:
A) 25 B) 30 C) 50 D) 75 E) 40 | <gadget id="calculator">46 - 36</gadget>
<output>10</output>
<gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 3_600</gadget>
<output>25/9 = around 2.777778</output>
<gadget id="calculator">(25/9) * 36</gadget>
<output>100</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<result>C</result> | C | 50 | Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. If the faster train passes the slower train in 36 seconds,what is the length of each train? | {
"A": "25",
"B": "30",
"C": "50",
"D": "75",
"E": "40"
} | divide(multiply(divide(multiply(subtract(46, 36), const_1000), const_3600), 36), const_2) | subtract(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n2,#2)|divide(#3,const_2)| | "assume the length of each train = x total distance covered for overtaking the slower train = x + x = 2 x relative speed = 46 - 36 = 10 km / hr = ( 10 × 10 ) / 36 = 100 / 36 m / s time = 36 seconds 2 x / ( 100 / 36 ) = 36 = > ( 2 x × 36 ) / 100 = 36 = > x = 50 meter answer is c ." | general |
math_qa__26RxIOROcyyDBtzh | In what time will a train 120 m long cross an electric pole, it its speed be 160 km/hr?
Choose the correct choice from the following choices.
A) 2.5 sec B) 2.9 sec C) 2.7 sec D) 8.7 sec E) 8.5 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">160 * (5/18)</gadget>
<output>400/9 = around 44.444444</output>
<gadget id="calculator">120 / (400/9)</gadget>
<output>27/10 = around 2.7</output>
<result>C</result> | C | 2.7 | In what time will a train 120 m long cross an electric pole, it its speed be 160 km/hr? | {
"A": "2.5 sec",
"B": "2.9 sec",
"C": "2.7 sec",
"D": "8.7 sec",
"E": "8.5 sec"
} | divide(120, multiply(160, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 160 * 5 / 18 = 44 m / sec time taken = 120 / 44 = 2.7 sec . answer : c" | physics |
math_qa__rUL7pKzYI5OWRdLD | A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
Choose the correct choice from the following options:
A) 320 m B) 350 m C) 650 m D) none of these E) can not be determined | <gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">300 / 6</gadget>
<output>50</output>
<gadget id="calculator">50 * 39</gadget>
<output>1_950</output>
<gadget id="calculator">3 * 300</gadget>
<output>900</output>
<gadget id="calculator">1_950 - 900</gadget>
<output>1_050</output>
<gadget id="calculator">1_050 / 3</gadget>
<output>350</output>
<result>B</result> | B | 350 | A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? | {
"A": "320 m",
"B": "350 m",
"C": "650 m",
"D": "none of these",
"E": "can not be determined"
} | divide(subtract(multiply(divide(300, divide(18, const_3)), 39), multiply(const_3, 300)), const_3) | divide(n2,const_3)|multiply(n0,const_3)|divide(n0,#0)|multiply(n1,#2)|subtract(#3,#1)|divide(#4,const_3)| | "solution speed = ( 300 / 18 ) m / sec = ( 50 / 3 ) m / sec . length of the platform be x metres . then = x + 300 / 39 = 50 / 3 m / sec = 3 ( x + 300 ) = 1950 . = 350 m answer b" | physics |
math_qa__vRePBcxG5toq3ZTT | Marketing executives for a certain chewing gum company projected a 30 percent increase in revenue this year over that of last year, but revenue this year actually decreased by 25%. What percent of the projected revenue was the actual revenue ? Choose the correct choice from the following choices
A) 53 %
B) 57.7 %
C) 62.5 %
D) 64 %
E) 75 % | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">30 + 100</gadget>
<output>130</output>
<gadget id="calculator">75 / 130</gadget>
<output>15/26 = around 0.576923</output>
<gadget id="calculator">(15/26) * 100</gadget>
<output>750/13 = around 57.692308</output>
<result>B</result> | B | 57.7 | Marketing executives for a certain chewing gum company projected a 30 percent increase in revenue this year over that of last year, but revenue this year actually decreased by 25%. What percent of the projected revenue was the actual revenue ? | {
"A": "53 %",
"B": "57.7 %",
"C": "62.5 %",
"D": "64 %",
"E": "75 %"
} | multiply(divide(subtract(const_100, 25), add(30, const_100)), const_100) | add(n0,const_100)|subtract(const_100,n1)|divide(#1,#0)|multiply(#2,const_100)| | "last year revenue = 100 ( assume ) ; this year revenue = 75 ; projected revenue = 130 . actual / projected * 100 = 75 / 130 * 100 = 57.7 % . answer : b ." | general |
math_qa__7I4VY9LCSqiglu3J | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 190 m long? Choose the correct choice from the following options
A) 38 sec B) 35 sec C) 44 sec D) 40 sec E) 50 sec | <gadget id="calculator">190 / 1_000</gadget>
<output>19/100 = around 0.19</output>
<gadget id="calculator">360 / 1_000</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(19/100) + (9/25)</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">(11/20) / 45</gadget>
<output>11/900 = around 0.012222</output>
<gadget id="calculator">(11/900) * 3_600</gadget>
<output>44</output>
<result>C</result> | C | 44 | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 190 m long? | {
"A": "38 sec",
"B": "35 sec",
"C": "44 sec",
"D": "40 sec",
"E": "50 sec"
} | multiply(divide(add(divide(190, const_1000), divide(360, const_1000)), 45), const_3600) | divide(n2,const_1000)|divide(n0,const_1000)|add(#0,#1)|divide(#2,n1)|multiply(#3,const_3600)| | "explanation : speed = 45 km / hr = 45 × ( 10 / 36 ) m / s = 150 / 12 = 50 / 4 = 25 / 2 m / s total distance = length of the train + length of the platform = 360 + 190 = 550 meter time taken to cross the platform = 550 / ( 25 / 2 ) = 550 × 2 / 25 = 44 seconds answer : option c" | physics |
math_qa__JGtb4wgSQNOikUp9 | Find large number from below question The difference of two numbers is 2500. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
Choose the correct choice from the following choices:
A) 3345
B) 1250
C) 1540
D) 2997
E) 1635 | <gadget id="calculator">2_500 - 15</gadget>
<output>2_485</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">2_485 / 5</gadget>
<output>497</output>
<gadget id="calculator">497 * 6</gadget>
<output>2_982</output>
<result>D</result> | D | 2,997 | Find large number from below question The difference of two numbers is 2500. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder | {
"A": "3345",
"B": "1250",
"C": "1540",
"D": "2997",
"E": "1635"
} | multiply(divide(subtract(2500, 15), subtract(6, const_1)), 6) | subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)| | "let the smaller number be x . then larger number = ( x + 1365 ) . x + 2500 = 6 x + 15 5 x = 2485 x = 497 large number = 497 + 1365 = 2997 d" | general |
math_qa__XIj8nwqw7peIB0c6 | Which number should replace both the asterisks in (* /18) x (*/72) = 1 ? Choices: A) 24 B) 30 C) 36 D) 42 E) 48 | <gadget id="calculator">72 * 18</gadget>
<output>1_296</output>
<gadget id="calculator">1_296 ** (1/2)</gadget>
<output>36</output>
<result>C</result> | C | 36 | Which number should replace both the asterisks in (* /18) x (*/72) = 1 ? | {
"A": "24",
"B": "30",
"C": "36",
"D": "42",
"E": "48"
} | sqrt(multiply(72, 18)) | multiply(n0,n1)|sqrt(#0)| | "let ( y / 18 ) x ( y / 72 ) = 1 y ^ 2 = 18 x 72 = 18 x 18 x 4 y = ( 18 x 2 ) = 36 the answer is c ." | general |
math_qa__52cVo7PcJdpiJvvn | In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 200 m. Then, A wins by: Choose the correct choice from the following answers
A) 60 m B) 100 m C) 43 m D) 20 m E) 23 m | <gadget id="calculator">500 - 200</gadget>
<output>300</output>
<gadget id="calculator">300 * 4</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 3</gadget>
<output>400</output>
<gadget id="calculator">500 - 400</gadget>
<output>100</output>
<result>B</result> | B | 100 | In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 200 m. Then, A wins by: | {
"A": "60 m",
"B": "100 m",
"C": "43 m",
"D": "20 m",
"E": "23 m"
} | subtract(500, divide(multiply(subtract(500, 200), 4), 3)) | subtract(n0,n3)|multiply(n2,#0)|divide(#1,n1)|subtract(n0,#2)| | "to reach the winning post a will have to cover a distance of ( 500 - 200 ) m , i . e . , 300 m . while a covers 3 m , b covers 4 m . while a covers 300 m , b covers 4 x 300 / 3 m = 400 m . thus , when a reaches the winning post , b covers 400 m and therefore remains 100 m behind . a wins by 100 m . answer : b" | physics |
math_qa__NMFt3N0gtXzISxOX | A and B are two multiples of 14, and Q is the set of consecutive integers between A and B, inclusive. If Q contains 9 multiples of 14, how many multiples of 7 are there in Q? Choose the correct choice from the following:
A) 20
B) 19
C) 18
D) 17
E) 16 | <gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">18 - 1</gadget>
<output>17</output>
<result>D</result> | D | 17 | A and B are two multiples of 14, and Q is the set of consecutive integers between A and B, inclusive. If Q contains 9 multiples of 14, how many multiples of 7 are there in Q? | {
"A": "20",
"B": "19",
"C": "18",
"D": "17",
"E": "16"
} | subtract(multiply(9, const_2), const_1) | multiply(n1,const_2)|subtract(#0,const_1)| | "lets q ' s first number be 14 as per question , q contains 9 multiples of 14 , so let q ' s last number be 126 . ( 14 ∗ 9 ) we have , a n = a + ( n − 1 ) d then 126 = 14 + ( n - 1 ) 7 solving for n , we get n = 17 answer : d" | physics |
math_qa__CkhXn4GCNkgBkcIT | Express a speed of 66 kmph in meters per second? Options
A) 10.33 mps B) 17 mps C) 97 mps D) 17.33 mps E) 18.33 mps | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 66</gadget>
<output>55/3 = around 18.333333</output>
<result>E</result> | E | 18.33 | Express a speed of 66 kmph in meters per second? | {
"A": "10.33 mps",
"B": "17 mps",
"C": "97 mps",
"D": "17.33 mps",
"E": "18.33 mps"
} | multiply(const_0_2778, 66) | multiply(n0,const_0_2778)| | "66 * 5 / 18 = 18.33 mps answer : e" | physics |
math_qa__xd2BUpDaWLYgRmcT | A man buys a cycle for Rs. 1600 and sells it at a loss of 15%. What is the selling price of the cycle? Choose the correct choice from the following: A) s . 1090 B) s . 1360 C) s . 1190 D) s . 1202 E) s . 1256 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 * 1_600</gadget>
<output>136_000</output>
<gadget id="calculator">136_000 / 100</gadget>
<output>1_360</output>
<result>B</result> | B | 1,360 | A man buys a cycle for Rs. 1600 and sells it at a loss of 15%. What is the selling price of the cycle? | {
"A": "s . 1090",
"B": "s . 1360",
"C": "s . 1190",
"D": "s . 1202",
"E": "s . 1256"
} | divide(multiply(subtract(const_100, 15), 1600), const_100) | subtract(const_100,n1)|multiply(n0,#0)|divide(#1,const_100)| | "s . p . = 85 % of rs . 1600 = rs . 85 / 100 x 1600 = rs . 1360 answer : b" | gain |
math_qa__OFSeSOcHl7hdm1gI | The parameter of a square is equal to the perimeter of a rectangle of length 8 cm and breadth 6 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square.
Pick:
A) 23.56 B) 23.59 C) 23.55 D) 23.53 E) 11.0 | <gadget id="calculator">2 * (8 + 6)</gadget>
<output>28</output>
<gadget id="calculator">28 / 4</gadget>
<output>7</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">2 * pi * (7/2)</gadget>
<output>7*pi = around 21.991149</output>
<gadget id="calculator">(7*pi) / 2</gadget>
<output>7*pi/2 = around 10.995574</output>
<result>E</result> | E | 11 | The parameter of a square is equal to the perimeter of a rectangle of length 8 cm and breadth 6 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. | {
"A": "23.56",
"B": "23.59",
"C": "23.55",
"D": "23.53",
"E": "11.0"
} | divide(circumface(divide(square_edge_by_perimeter(rectangle_perimeter(8, 6)), const_2)), const_2) | rectangle_perimeter(n0,n1)|square_edge_by_perimeter(#0)|divide(#1,const_2)|circumface(#2)|divide(#3,const_2)| | "let the side of the square be a cm . parameter of the rectangle = 2 ( 8 + 6 ) = 28 cm parameter of the square = 28 cm i . e . 4 a = 28 a = 7 diameter of the semicircle = 7 cm circimference of the semicircle = 1 / 2 ( â ˆ ) 7 = 1 / 2 ( 22 / 7 ) ( 7 ) = 11 cm answer : e" | geometry |
math_qa__3i99mRPy3jHsIlXJ | A tempo is insured to an extent of 5/7 of its original value. If the premium on it at the rate of 3% amounts to $300, The original value of the tempo is? Answers
A) 12500
B) 13280
C) 17520
D) 14000
E) 12560 | <gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">(5/7) * 3</gadget>
<output>15/7 = around 2.142857</output>
<gadget id="calculator">(15/7) / 100</gadget>
<output>3/140 = around 0.021429</output>
<gadget id="calculator">300 / (3/140)</gadget>
<output>14_000</output>
<result>D</result> | D | 14,000 | A tempo is insured to an extent of 5/7 of its original value. If the premium on it at the rate of 3% amounts to $300, The original value of the tempo is? | {
"A": "12500",
"B": "13280",
"C": "17520",
"D": "14000",
"E": "12560"
} | divide(300, divide(multiply(divide(5, 7), 3), const_100)) | divide(n0,n1)|multiply(n2,#0)|divide(#1,const_100)|divide(n3,#2)| | "let the original value of the tempo is $ x 3 % of 5 / 7 of x = 300 ( 3 / 100 ) * ( 5 / 7 ) x = 300 x = $ 14000 answer is d" | gain |
math_qa__Me1Lrq121zIwZlDx | Last year Department Store X had a sales total for December that was 3 times the average (arithmetic mean) of the monthly sales totals for January through November. The sales total for December was what fraction of the sales total for the year?
Select the correct option.
A) 1 / 4 B) 4 / 15 C) 3 / 14 D) 4 / 11 E) 4 / 5 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 + 3</gadget>
<output>14</output>
<gadget id="calculator">3 / 14</gadget>
<output>3/14 = around 0.214286</output>
<result>C</result> | C | 0.214286 | Last year Department Store X had a sales total for December that was 3 times the average (arithmetic mean) of the monthly sales totals for January through November. The sales total for December was what fraction of the sales total for the year? | {
"A": "1 / 4",
"B": "4 / 15",
"C": "3 / 14",
"D": "4 / 11",
"E": "4 / 5"
} | divide(3, add(subtract(const_12, const_1), 3)) | subtract(const_12,const_1)|add(n0,#0)|divide(n0,#1) | let avg for 11 mos . = 10 therefore , dec = 30 year total = 11 * 10 + 30 = 140 answer = 30 / 140 = 3 / 14 = c | general |
math_qa__CvF7BQnFLL4LvyP7 | If a-b= 3 and a^2+b^2=29, find the value of ab Answers: A) 10 B) 12 C) 15 D) 18 E) 19 | <gadget id="calculator">29 ** (1/2)</gadget>
<output>sqrt(29) = around 5.385165</output>
<gadget id="calculator">(sqrt(29)) - 3</gadget>
<output>-3 + sqrt(29) = around 2.385165</output>
<gadget id="calculator">(-3 + sqrt(29)) / 2</gadget>
<output>-3/2 + sqrt(29)/2 = around 1.192582</output>
<gadget id="calculator">3 + (-3/2 + sqrt(29)/2)</gadget>
<output>3/2 + sqrt(29)/2 = around 4.192582</output>
<gadget id="calculator">(3/2 + sqrt(29)/2) * (-3/2 + sqrt(29)/2)</gadget>
<output>(-3/2 + sqrt(29)/2)*(3/2 + sqrt(29)/2) = around 5</output>
<gadget id="calculator">((-3/2 + sqrt(29)/2)*(3/2 + sqrt(29)/2)) * 2</gadget>
<output>2*(-3/2 + sqrt(29)/2)*(3/2 + sqrt(29)/2) = around 10</output>
<result>A</result> | A | 10 | If a-b= 3 and a^2+b^2=29, find the value of ab | {
"A": "10",
"B": "12",
"C": "15",
"D": "18",
"E": "19"
} | multiply(multiply(add(3, divide(subtract(sqrt(29), 3), 2)), divide(subtract(sqrt(29), 3), 2)), 2) | sqrt(n3)|subtract(#0,n0)|divide(#1,n1)|add(n0,#2)|multiply(#3,#2)|multiply(n1,#4)| | "2 ab = ( a ^ 2 + b ^ 2 ) - ( a - b ) ^ 2 = 29 - 9 = 20 = > ab = 10 . answer : a" | general |
math_qa__uHlU6NtfJvzGNyqT | The ratio of the cost price and selling price is 4:5. The profit percent is? Choose the correct answer: A) 20 % B) 25 % C) 30 % D) 50 % E) 15 % | <gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) - 1</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>B</result> | B | 25 | The ratio of the cost price and selling price is 4:5. The profit percent is? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "50 %",
"E": "15 %"
} | multiply(subtract(divide(5, 4), const_1), const_100) | divide(n1,n0)|subtract(#0,const_1)|multiply(#1,const_100)| | "let the c . p . = $ 4 x then s . p . = $ 5 x then , gain = 5 x - 4 x = $ x gain % = x / 4 x * 100 = 25 % answer is b" | gain |
math_qa__3SwtmK6IC1iMzSzT | Farm Tax is levied on the 50% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. willam. Mr. willam paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is :
Answers:
A) 15 % B) 25 % C) 0.125 % D) 0.2083 % E) none | <gadget id="calculator">480 / 3_840</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 100</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 100</gadget>
<output>1_250</output>
<gadget id="calculator">1_250 / 50</gadget>
<output>25</output>
<result>B</result> | B | 25 | Farm Tax is levied on the 50% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. willam. Mr. willam paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is : | {
"A": "15 %",
"B": "25 %",
"C": "0.125 %",
"D": "0.2083 %",
"E": "none"
} | divide(multiply(multiply(divide(480, 3840), const_100), const_100), 50) | divide(n2,n1)|multiply(#0,const_100)|multiply(#1,const_100)|divide(#2,n0) | only trick n this question is to ignore 50 % information as farm tax is levied uniformly in the village and that includes mr william ' s land . what percentage of tax mr william paid ? this will be equal to the percentage of total cultivated land he holds over the total cultivated land in the village . that leads to ( 480 / 3840 ) x 100 = 12.5 % in percentage terms . but the question asks ratio between his total land to total cultivated land . hence the answer is 12.5 % x ( 100 / 50 ) = 25 % and the answer is not there in the options . the correct answer is ( b ) . | general |
math_qa__ZJ8N6oB2CSnDi1RT | How many even 4-digit numbers can be formed, so that the numbers are divisible by 4 and no two digits are repeated? Choose the correct option:
A) 336
B) 784
C) 1120
D) 1804
E) 1936 | <gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">100 / 4</gadget>
<output>25</output>
<gadget id="calculator">25 - 3</gadget>
<output>22</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">22 - 6</gadget>
<output>16</output>
<gadget id="calculator">49 * 16</gadget>
<output>784</output>
<gadget id="calculator">8 * 7</gadget>
<output>56</output>
<gadget id="calculator">56 * 6</gadget>
<output>336</output>
<gadget id="calculator">784 + 336</gadget>
<output>1_120</output>
<result>C</result> | C | 1,120 | How many even 4-digit numbers can be formed, so that the numbers are divisible by 4 and no two digits are repeated? | {
"A": "336",
"B": "784",
"C": "1120",
"D": "1804",
"E": "1936"
} | add(multiply(multiply(subtract(subtract(const_10, const_2), const_1), subtract(subtract(const_10, const_2), const_1)), subtract(subtract(divide(const_100, 4), const_3), multiply(const_2, const_3))), multiply(multiply(subtract(const_10, const_2), subtract(subtract(const_10, const_2), const_1)), multiply(const_2, const_3))) | divide(const_100,n0)|multiply(const_2,const_3)|subtract(const_10,const_2)|subtract(#2,const_1)|subtract(#0,const_3)|multiply(#3,#3)|multiply(#2,#3)|subtract(#4,#1)|multiply(#5,#7)|multiply(#6,#1)|add(#8,#9) | number is divisible by 4 if the last two digits form a number divisible by 4 . therefore last two digits can be : 00 ; 04 ; 08 ; 12 16 ; . . . 96 . basically multiples of 4 in the range 0 - 96 , inclusive . multiples of 4 in a range 0 - 96 , inclusive are last multiple in the range − first multiple in the range 4 + 1 = 25 last multiple in the range − first multiple in the range 4 + 1 = 25 but 3 numbers out of these 25 are not formed with distinct digits : 00 , 44 , and 88 . hence the numbers we are looking for can have only 22 endings . if there is 0 in the ending ( 04 , 08 , 20 , 40 , 60 , 80 - total 6 such numbers ) , then the first and second digit can take 8 and 7 choices each = 56 choices total . as there are 6 numbers with 0 in ending , hence total 6 * 56 = 336 . if there is no 0 in the ending ( total 22 - 6 with zero = 16 such numbers ) , then the first digit can take 7 choices ( 10 - 2 digits in the ending and zero , so total 3 digits = 7 , as 4 - digit number can not start with zero ) and the second digit can take 7 choices too ( 10 digits - 3 digits we ' ve already used ) = 7 * 7 = 49 choices total . as there are 16 numbers without zero in ending , hence total 16 * 49 = 784 . total : 336 + 784 = 1120 answer : c . | general |
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