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math_qa__kbq5U8o3ouuLq8Vp | Running at the same constant rate, 8 identical machines can produce a total of 240 pens per minute. At this rate, how many pens could 5 such machines produce in 5 minutes? Pick one
A) 114 B) 108 C) 192 D) 750 E) 777 | <gadget id="calculator">240 / 8</gadget>
<output>30</output>
<gadget id="calculator">30 * 5</gadget>
<output>150</output>
<gadget id="calculator">150 * 5</gadget>
<output>750</output>
<result>D</result> | D | 750 | Running at the same constant rate, 8 identical machines can produce a total of 240 pens per minute. At this rate, how many pens could 5 such machines produce in 5 minutes? | {
"A": "114",
"B": "108",
"C": "192",
"D": "750",
"E": "777"
} | multiply(multiply(divide(240, 8), 5), 5) | divide(n1,n0)|multiply(n3,#0)|multiply(n2,#1)| | "let ' s take the approach that uses the answer choices to eliminate wasted time . 240 / 8 = 30 pens per minute per machine . 5 machines = 150 per minute . 5 minutes worth = 750 pens . looking at the answers it is clear . . . we can only choose ( d ) . the correct answer is d ." | gain |
math_qa__M9jzacf1GGvTXfK3 | Before 2 years, dog A’s age was 4 times of dog B’s age and after 4 years, dog A’s age will be 3 times of dog B’s age. What is the difference of dog A’s age and dog B’s now? Select:
A) 36 B) 42 C) 54 D) 60 E) 64 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">8 + 6</gadget>
<output>14</output>
<gadget id="calculator">4 * 14</gadget>
<output>56</output>
<gadget id="calculator">56 - 6</gadget>
<output>50</output>
<gadget id="calculator">50 - 14</gadget>
<output>36</output>
<result>A</result> | A | 36 | Before 2 years, dog A’s age was 4 times of dog B’s age and after 4 years, dog A’s age will be 3 times of dog B’s age. What is the difference of dog A’s age and dog B’s now? | {
"A": "36",
"B": "42",
"C": "54",
"D": "60",
"E": "64"
} | subtract(subtract(multiply(4, add(subtract(multiply(4, 3), 4), subtract(multiply(4, 2), 2))), subtract(multiply(4, 2), 2)), add(subtract(multiply(4, 3), 4), subtract(multiply(4, 2), 2))) | multiply(n1,n2)|multiply(n0,n1)|subtract(#0,n1)|subtract(#1,n0)|add(#2,#3)|multiply(n1,#4)|subtract(#5,#3)|subtract(#6,#4)| | a - 2 = 4 ( b - 2 ) - - > a - 4 b = - 6 . . . . . . . . . . . . . 1 a + 4 = 3 ( b + 4 ) - - > a - 3 b = 8 . . . . . . . . . . . . . 2 ( 2 ) - ( 1 ) - - > b = 14 - - > a = 3 ( 18 ) = 50 a - b = 50 - 14 = 36 answer : a | general |
math_qa__RH10gFV7XxGBEQ5e | How many integers between 500 and 1000 are there such that their unit digit is even? Answers
A) 250 B) 150 C) 500 D) 100 E) 200 | <gadget id="calculator">500 / 2</gadget>
<output>250</output>
<gadget id="calculator">250 + 1</gadget>
<output>251</output>
<result>A</result> | A | 250 | How many integers between 500 and 1000 are there such that their unit digit is even? | {
"A": "250",
"B": "150",
"C": "500",
"D": "100",
"E": "200"
} | add(divide(500, const_2), const_1) | divide(n0,const_2)|add(#0,const_1) | 500 numbers between - 500 and 1000 out of which half would be even , half odd . number of even unit digit number = 250 . correct option is a | general |
math_qa__SsYLL8o6pdMtgS1M | A man saves a certain portion of his income during a year and spends the remaining portion on his personal expenses. Next year his income increases by 50% but his savings increase by 100%. If his total expenditure in 2 years is double his expenditure in 1st year, What %age of his income in the first year did he save? Choose the correct choice from the following options.
A) 40 %
B) 45 %
C) 50 %
D) 60 %
E) 70 % | <gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">150 + 100</gadget>
<output>250</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">250 - 200</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | A man saves a certain portion of his income during a year and spends the remaining portion on his personal expenses. Next year his income increases by 50% but his savings increase by 100%. If his total expenditure in 2 years is double his expenditure in 1st year, What %age of his income in the first year did he save? | {
"A": "40 %",
"B": "45 %",
"C": "50 %",
"D": "60 %",
"E": "70 %"
} | multiply(divide(subtract(add(add(100, 50), 100), multiply(2, 100)), 100), 100) | add(n0,n1)|multiply(n1,n2)|add(n1,#0)|subtract(#2,#1)|divide(#3,n1)|multiply(#4,n1)| | "1 st year income = i 1 st year savings = s 1 st year expense = e 1 2 nd year income = 1.5 i 2 nd year savings = 2 s ( 100 % increase ) 2 nd year expense = e 2 e 1 + e 2 = 2 e 1 e 2 = e 1 that means expenses are same during both years . with increase of 50 % income the savings increased by 100 % . or s = . 5 i or s = 50 % of income c is the answer" | general |
math_qa__40qRC6dUCOSMCjtc | The cost price of 24 articles is the same as the selling price of x articles. If the profit is 20%, what is x? Choose the correct choice from the following options:
A) 14 B) 16 C) 18 D) 20 E) 22 | <gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">96 / 5</gadget>
<output>96/5 = around 19.2</output>
<result>D</result> | D | 20 | The cost price of 24 articles is the same as the selling price of x articles. If the profit is 20%, what is x? | {
"A": "14",
"B": "16",
"C": "18",
"D": "20",
"E": "22"
} | divide(multiply(24, const_4), add(const_4, const_1)) | add(const_1,const_4)|multiply(n0,const_4)|divide(#1,#0)| | "let the cost price = y the cost price of 24 articles = 24 y the selling price of x articles = 1.20 y * x 1.20 y * x = 24 y x = 24 / 1.2 = 20 the answer is d ." | gain |
math_qa__KvLsdXoTX7JQbUYA | On increasing the number of lines in a page by 110, they become 240. What is the % of increase in the no. of lines in the page? Options
A) 20 % B) 305 C) 50 % D) 55 % E) 84.6 % | <gadget id="calculator">240 - 110</gadget>
<output>130</output>
<gadget id="calculator">240 / 130</gadget>
<output>24/13 = around 1.846154</output>
<gadget id="calculator">(24/13) * 100</gadget>
<output>2_400/13 = around 184.615385</output>
<gadget id="calculator">(2_400/13) - 100</gadget>
<output>1_100/13 = around 84.615385</output>
<result>E</result> | E | 84.6 | On increasing the number of lines in a page by 110, they become 240. What is the % of increase in the no. of lines in the page? | {
"A": "20 %",
"B": "305",
"C": "50 %",
"D": "55 %",
"E": "84.6 %"
} | subtract(multiply(divide(240, subtract(240, 110)), const_100), const_100) | subtract(n1,n0)|divide(n1,#0)|multiply(#1,const_100)|subtract(#2,const_100)| | "explanation : number of pages increased = 110 now , the number of pages of book = 240 number of pages of the books before increase = 240 – 110 = 130 % increase in the number of pages in the book = 110 / 130 x 100 % = 84.6 % e" | general |
math_qa__ZRsEmsa13XrWa7uj | An empty fuel tank with a capacity of 200 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 18 gallons of ethanol, how many gallons of fuel A were added?
Choose one.
A) 160
B) 150
C) 100
D) 80
E) 350 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">200 * (4/25)</gadget>
<output>32</output>
<gadget id="calculator">32 - 18</gadget>
<output>14</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(4/25) - (3/25)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">14 / (1/25)</gadget>
<output>350</output>
<result>E</result> | E | 350 | An empty fuel tank with a capacity of 200 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 18 gallons of ethanol, how many gallons of fuel A were added? | {
"A": "160",
"B": "150",
"C": "100",
"D": "80",
"E": "350"
} | divide(subtract(multiply(200, divide(16, const_100)), 18), subtract(divide(16, const_100), divide(12, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n3)|divide(#4,#3)| | "say there are a gallons of fuel a in the tank , then there would be 200 - a gallons of fuel b . the amount of ethanol in a gallons of fuel a is 0.12 a ; the amount of ethanol in 200 - a gallons of fuel b is 0.16 ( 200 - a ) ; since the total amount of ethanol is 18 gallons then 0.12 a + 0.16 ( 200 - a ) = 18 - - > a = 350 . answer : e ." | gain |
math_qa__kkf6093eVLaM5YEN | What is the total number of D integers between 100 and 200 that are divisible by 3? Select the correct option:
A) 33 B) 32 C) 31 D) 30 E) 29 | <gadget id="calculator">200 / 3</gadget>
<output>200/3 = around 66.666667</output>
<gadget id="calculator">floor(200/3)</gadget>
<output>66</output>
<gadget id="calculator">66 * 3</gadget>
<output>198</output>
<gadget id="calculator">100 / 3</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">floor(100/3)</gadget>
<output>33</output>
<gadget id="calculator">3 * 33</gadget>
<output>99</output>
<gadget id="calculator">3 + 99</gadget>
<output>102</output>
<gadget id="calculator">198 - 102</gadget>
<output>96</output>
<gadget id="calculator">96 + 3</gadget>
<output>99</output>
<gadget id="calculator">99 / 3</gadget>
<output>33</output>
<result>A</result> | A | 33 | What is the total number of D integers between 100 and 200 that are divisible by 3? | {
"A": "33",
"B": "32",
"C": "31",
"D": "30",
"E": "29"
} | divide(add(subtract(multiply(floor(divide(200, 3)), 3), add(3, multiply(3, floor(divide(100, 3))))), 3), 3) | divide(n1,n2)|divide(n0,n2)|floor(#0)|floor(#1)|multiply(n2,#2)|multiply(n2,#3)|add(n2,#5)|subtract(#4,#6)|add(n2,#7)|divide(#8,n2) | yes there is a different way of arriving at that answer . . . . u can also use airthmetic progression to get the answer since the first term to be divisble by 3 is 102 . . take that as a . . the starting no and since 198 is the last digit to be divisible by 3 take that as n . . . since the difference is 3 take that as d no u have to find what term is 198 take that as nth term the formula for that is n = a + ( n - 1 ) * d 198 = 102 + ( n - 1 ) * 3 from this u get n = 33 | general |
math_qa__SUZaSBkQ2q52pLpP | 10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
Choose the correct choice from the following choices
A) 6 days B) 7 days C) 8 days D) 9 days E) none of these | <gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">5 / 70</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">10 * 14</gadget>
<output>140</output>
<gadget id="calculator">10 / 140</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">(1/14) + (1/14)</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">1 / (1/7)</gadget>
<output>7</output>
<result>B</result> | B | 7 | 10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work? | {
"A": "6 days",
"B": "7 days",
"C": "8 days",
"D": "9 days",
"E": "none of these"
} | inverse(add(divide(5, multiply(10, 7)), divide(10, multiply(10, 14)))) | multiply(n0,n1)|multiply(n0,n3)|divide(n4,#0)|divide(n0,#1)|add(#2,#3)|inverse(#4) | explanation : 1 woman ' s 1 day ' s work = 1 / 70 1 child ' s 1 day ' s work = 1 / 140 5 women and 10 children 1 day work = ( 570 + 10140 ) = 17 so 5 women and 10 children will finish the work in 7 days answer : b | physics |
math_qa__QFSEtiLr5TvO9gjJ | The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 20%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output? Choose the correct choice from the following answers:
A) 20 % B) 24 % C) 30 % D) 32 % E) 79 % | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(11/10) * (6/5)</gadget>
<output>33/25 = around 1.32</output>
<gadget id="calculator">(33/25) - 1</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">(8/25) / (33/25)</gadget>
<output>8/33 = around 0.242424</output>
<gadget id="calculator">(8/33) * 100</gadget>
<output>800/33 = around 24.242424</output>
<result>B</result> | B | 24 | The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 20%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output? | {
"A": "20 %",
"B": "24 %",
"C": "30 %",
"D": "32 %",
"E": "79 %"
} | multiply(divide(subtract(multiply(divide(add(const_100, 10), const_100), divide(add(const_100, 20), const_100)), const_1), multiply(divide(add(const_100, 10), const_100), divide(add(const_100, 20), const_100))), const_100) | add(n0,const_100)|add(n1,const_100)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|subtract(#4,const_1)|divide(#5,#4)|multiply(#6,const_100)| | "let the output of a factory is 100 first , increased by 10 % = 110 due to holiday rush , it increase by 20 % = 110 + 22 = 132 132 - ( x / 100 * 132 ) = 100 24.24 answer : b" | general |
math_qa__XPOLJQvxFP9xI1dy | Maria sold 10kg of apples in her first hour at the market, but only 2kg of apples in the second hour. On average, how many kg of apples did she sell in two hours at the market? Pick.
A) 6 kg B) 5 kg C) 12 kg D) 24 kg E) 20 kg | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<result>A</result> | A | 6 | Maria sold 10kg of apples in her first hour at the market, but only 2kg of apples in the second hour. On average, how many kg of apples did she sell in two hours at the market? | {
"A": "6 kg",
"B": "5 kg",
"C": "12 kg",
"D": "24 kg",
"E": "20 kg"
} | subtract(10, multiply(2, 2)) | multiply(n1,n1)|subtract(n0,#0) | ( 10 kg + 2 kg ) / 2 = 6 kg correct answer is : a | physics |
math_qa__8KX8H9JIIrdXEWYF | A club wants to mix 15 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used? Choices.
A) 20 B) 30 C) 40 D) 50 E) 60 | <gadget id="calculator">15 * 8</gadget>
<output>120</output>
<gadget id="calculator">6 * 15</gadget>
<output>90</output>
<gadget id="calculator">120 - 90</gadget>
<output>30</output>
<result>B</result> | B | 30 | A club wants to mix 15 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used? | {
"A": "20",
"B": "30",
"C": "40",
"D": "50",
"E": "60"
} | subtract(multiply(15, 8.00), multiply(6.00, 15)) | multiply(n0,n1)|multiply(n0,n3)|subtract(#0,#1)| | "let number of pounds of 5 $ candy to be used be w 6 = ( 15 * 8 + 5 * w ) / ( 15 + w ) = > 90 + 6 w = 120 + 5 w = > w = 30 answer b" | general |
math_qa__t1tlCLc1SV30wtzU | 300 + 5 × 8 = ? Choose the correct option.
A) 820 B) 340 C) 420 D) 209 E) none of these | <gadget id="calculator">5 * 8</gadget>
<output>40</output>
<gadget id="calculator">40 + 300</gadget>
<output>340</output>
<result>B</result> | B | 340 | 300 + 5 × 8 = ? | {
"A": "820",
"B": "340",
"C": "420",
"D": "209",
"E": "none of these"
} | add(multiply(5, 8), 300) | multiply(n1,n2)|add(n0,#0) | 300 + 5 × 8 = ? or , ? = 300 + 40 = 340 answer b | general |
math_qa__CRwY3LnXicPHYLVb | A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km. Pick
A) 18 kmph B) 17 kmph C) 24 kmph D) 19 kmph E) 12 kmph | <gadget id="calculator">40 * 3</gadget>
<output>120</output>
<gadget id="calculator">40 / 40</gadget>
<output>1</output>
<gadget id="calculator">2 * 40</gadget>
<output>80</output>
<gadget id="calculator">80 / 20</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">120 / 5</gadget>
<output>24</output>
<result>C</result> | C | 24 | A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km. | {
"A": "18 kmph",
"B": "17 kmph",
"C": "24 kmph",
"D": "19 kmph",
"E": "12 kmph"
} | divide(multiply(40, 3), add(divide(40, 40), divide(multiply(2, 40), 20))) | divide(n0,n0)|multiply(n0,n3)|multiply(n0,n1)|divide(#2,n2)|add(#0,#3)|divide(#1,#4)| | "total time taken = x / 40 + 2 x / 20 hours = 5 x / 40 = x / 8 hours average speed = 3 x / ( x / 8 ) = 24 kmph answer : c" | general |
math_qa__JSz1Pse8juCreT88 | The avg weight of A,B & C is 70 kg. If D joins the group, the avg weight of the group becomes 70 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 68 kg. What is the weight of A? Pick:
A) 81 B) 65 C) 75 D) 89 E) 90 | <gadget id="calculator">70 * 4</gadget>
<output>280</output>
<gadget id="calculator">68 * 4</gadget>
<output>272</output>
<gadget id="calculator">70 * 3</gadget>
<output>210</output>
<gadget id="calculator">280 - 210</gadget>
<output>70</output>
<gadget id="calculator">3 + 70</gadget>
<output>73</output>
<gadget id="calculator">272 - 73</gadget>
<output>199</output>
<gadget id="calculator">280 - 199</gadget>
<output>81</output>
<result>A</result> | A | 81 | The avg weight of A,B & C is 70 kg. If D joins the group, the avg weight of the group becomes 70 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 68 kg. What is the weight of A? | {
"A": "81",
"B": "65",
"C": "75",
"D": "89",
"E": "90"
} | subtract(multiply(70, const_4), subtract(multiply(68, const_4), add(3, subtract(multiply(70, const_4), multiply(70, 3))))) | multiply(n1,const_4)|multiply(n3,const_4)|multiply(n0,n2)|subtract(#0,#2)|add(n2,#3)|subtract(#1,#4)|subtract(#0,#5)| | "a + b + c = 3 * 70 = 210 a + b + c + d = 4 * 70 = 280 - - - - ( i ) so , d = 70 & e = 70 + 3 = 73 b + c + d + e = 68 * 4 = 272 - - - ( ii ) from eq . ( i ) & ( ii ) a - e = 280 – 272 = 8 a = e + 8 = 73 + 8 = 81 answer : a" | general |
math_qa__KOdT8JFLkoNvGjQ2 | John paid a sum of money for purchasing 30 pens, which he recovered in full when he sold 20 of them. What was his percentage of profit or loss per pen? Pick one: A) 50 % B) 60 % C) 40 % D) 30 % E) 45 % | <gadget id="calculator">30 - 20</gadget>
<output>10</output>
<gadget id="calculator">10 / 20</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>A</result> | A | 50 | John paid a sum of money for purchasing 30 pens, which he recovered in full when he sold 20 of them. What was his percentage of profit or loss per pen? | {
"A": "50 %",
"B": "60 %",
"C": "40 %",
"D": "30 %",
"E": "45 %"
} | multiply(divide(subtract(30, 20), 20), const_100) | subtract(n0,n1)|divide(#0,n1)|multiply(#1,const_100)| | "a 50 % if the sum he paid whilst purchasing 30 pens = a , then the cost price of each pen = a / 30 . since the amount he got whilst selling 20 pens is also = a then the selling price of each pen = a / 20 . since selling price > cost price , he made a profit . profit per pen = selling price - cost price = a / 20 - a / 30 = a / 60 . profit percentage per pen = profit per pen / cost per pen x 100 = ( a / 60 ) / ( a / 30 ) x 100 = 50 %" | gain |
math_qa__7X5YxfNI3tHdVVmo | 1/0.025 is equal to Choose the correct choice from the following options:
A) 25.5 B) 2.5 C) 40 D) . 25 E) none of these | <gadget id="calculator">1 / 0.025</gadget>
<output>40</output>
<result>C</result> | C | 40 | 1/0.025 is equal to | {
"A": "25.5",
"B": "2.5",
"C": "40",
"D": ". 25",
"E": "none of these"
} | divide(1, 0.025) | divide(n0,n1)| | "explanation : 1 / 0.025 = ( 1 * 1000 ) / 25 = 1000 / 25 = 40 option c" | general |
math_qa__XCDeCEE58avrduvf | Find the circumference and area of radius 4 cm.
Choose the correct choice from the following choices
A) 24 cm ² B) 44 cm ² C) 50 cm ² D) 84 cm ² E) 94 cm ² | <gadget id="calculator">pi * (4 ** 2)</gadget>
<output>16*pi = around 50.265482</output>
<result>C</result> | C | 50 | Find the circumference and area of radius 4 cm. | {
"A": "24 cm ²",
"B": "44 cm ²",
"C": "50 cm ²",
"D": "84 cm ²",
"E": "94 cm ²"
} | circle_area(4) | circle_area(n0)| | "area of circle = π r ² = 22 / 7 × 4 × 4 cm ² = 50 cm ² answer : c" | geometry |
math_qa__bVqAo1nehPvkPTbT | Evaluate: |4 - 8(3 - 12)| - |5 - 11| = Choose the correct choice
A) 49
B) 55
C) 69
D) 70
E) 82 | <gadget id="calculator">3 - 12</gadget>
<output>-9</output>
<gadget id="calculator">8 * (-9)</gadget>
<output>-72</output>
<gadget id="calculator">4 - (-72)</gadget>
<output>76</output>
<gadget id="calculator">5 - 11</gadget>
<output>-6</output>
<gadget id="calculator">-(-6)</gadget>
<output>6</output>
<gadget id="calculator">76 - 6</gadget>
<output>70</output>
<result>D</result> | D | 70 | Evaluate: |4 - 8(3 - 12)| - |5 - 11| = | {
"A": "49",
"B": "55",
"C": "69",
"D": "70",
"E": "82"
} | subtract(subtract(4, multiply(8, subtract(3, 12))), negate(subtract(5, 11))) | subtract(n2,n3)|subtract(n4,n5)|multiply(n1,#0)|negate(#1)|subtract(n0,#2)|subtract(#4,#3)| | "according to order of operations , inner brackets first . hence | 4 - 8 ( 3 - 12 ) | - | 5 - 11 | = | 4 - 8 * ( - 9 ) | - | 5 - 11 | according to order of operations , multiplication within absolute value signs ( which may be considered as brackets when it comes to order of operations ) next . hence = | 4 + 72 | - | 5 - 11 | = | 76 | - | - 6 | = 76 - 6 = 70 correct answer d ) 70" | general |
math_qa__U7m1yyh0Cfp1IE4Y | How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction? Choose the correct choice from the following
A) 50 sec B) 26 sec C) 80 sec D) 82 sec E) 81 sec | <gadget id="calculator">200 + 300</gadget>
<output>500</output>
<gadget id="calculator">72 - 36</gadget>
<output>36</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">500 / 10</gadget>
<output>50</output>
<result>A</result> | A | 50 | How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction? | {
"A": "50 sec",
"B": "26 sec",
"C": "80 sec",
"D": "82 sec",
"E": "81 sec"
} | divide(add(200, 300), multiply(subtract(72, 36), const_0_2778)) | add(n0,n2)|subtract(n1,n3)|multiply(#1,const_0_2778)|divide(#0,#2) | the distance to be covered = sum of their lengths = 200 + 300 = 500 m . relative speed = 72 - 36 = 36 kmph = 36 * 5 / 18 = 10 mps . time required = d / s = 500 / 10 = 50 sec . answer : a | physics |
math_qa__eBetdHqALfnBXwEb | A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.3146 in 3 years. Find the rate percent? Select.
A) 11 B) 30 C) 28 D) 24 E) 82 | <gadget id="calculator">3_146 - 2_420</gadget>
<output>726</output>
<gadget id="calculator">726 / 2_420</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 100</gadget>
<output>30</output>
<result>B</result> | B | 30 | A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.3146 in 3 years. Find the rate percent? | {
"A": "11",
"B": "30",
"C": "28",
"D": "24",
"E": "82"
} | multiply(divide(subtract(3146, 2420), 2420), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : 2420 - - - 726 100 - - - ? = > 30 % answer : option b" | gain |
math_qa__0PvUkdTB4xgUTMEu | The rate of spin of a certain gyroscope doubled every 10 seconds from the moment a particular stopwatch started. If after a minute and a half the gyroscope reached a speed of 800 meters per second, what was the speed, in meters per second, when the stopwatch was started? Select the correct option: A) 25 / 3 B) 25 / 4 C) 25 / 8 D) 25 / 16 E) 25 / 32 | <gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 + 60</gadget>
<output>90</output>
<gadget id="calculator">90 / 10</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">2 ** 8</gadget>
<output>256</output>
<gadget id="calculator">800 / 256</gadget>
<output>25/8 = around 3.125</output>
<gadget id="calculator">(25/8) / 2</gadget>
<output>25/16 = around 1.5625</output>
<result>D</result> | D | 1.5625 | The rate of spin of a certain gyroscope doubled every 10 seconds from the moment a particular stopwatch started. If after a minute and a half the gyroscope reached a speed of 800 meters per second, what was the speed, in meters per second, when the stopwatch was started? | {
"A": "25 / 3",
"B": "25 / 4",
"C": "25 / 8",
"D": "25 / 16",
"E": "25 / 32"
} | divide(divide(800, power(const_2, subtract(divide(add(divide(const_60, const_2), const_60), 10), const_1))), const_2) | divide(const_60,const_2)|add(#0,const_60)|divide(#1,n0)|subtract(#2,const_1)|power(const_2,#3)|divide(n1,#4)|divide(#5,const_2) | let x be the original speed when the stopwatch was started . in 90 seconds , the speed doubled 9 times . 2 ^ 9 * x = 800 x = ( 2 ^ 5 * 25 ) / 2 ^ 9 = 25 / 16 the answer is d . | physics |
math_qa__IHMNYxTHB9ohHb5u | If i equals the sum of the even integers from 2 to 224, inclusive, and k equals the sum of the even integers from 8 to 80, inclusive, what is the value of i - k?
Pick one
A) 11028 B) 14172 C) 14284 D) 14015 E) 14397 | <gadget id="calculator">80 + 2</gadget>
<output>82</output>
<gadget id="calculator">82 + 224</gadget>
<output>306</output>
<gadget id="calculator">224 - 82</gadget>
<output>142</output>
<gadget id="calculator">142 / 2</gadget>
<output>71</output>
<gadget id="calculator">306 * 71</gadget>
<output>21_726</output>
<gadget id="calculator">21_726 + 306</gadget>
<output>22_032</output>
<gadget id="calculator">22_032 / 2</gadget>
<output>11_016</output>
<gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 8</gadget>
<output>12</output>
<gadget id="calculator">11_016 + 12</gadget>
<output>11_028</output>
<result>A</result> | A | 11,028 | If i equals the sum of the even integers from 2 to 224, inclusive, and k equals the sum of the even integers from 8 to 80, inclusive, what is the value of i - k? | {
"A": "11028",
"B": "14172",
"C": "14284",
"D": "14015",
"E": "14397"
} | add(divide(add(multiply(add(add(80, 2), 224), divide(subtract(224, add(80, 2)), const_2)), add(add(80, 2), 224)), const_2), add(add(2, 2), 8)) | add(n0,n0)|add(n0,n3)|add(n2,#0)|add(n1,#1)|subtract(n1,#1)|divide(#4,const_2)|multiply(#3,#5)|add(#3,#6)|divide(#7,const_2)|add(#2,#8) | use following formulae for such problems : sum of evenly spaced integers = ( # of integers ) * ( mean of integers ) # of integers = [ ( last - first ) / 2 ] + 1 mean of integers = ( last + first ) / 2 in above problem : # of integers = [ ( 224 - 2 ) / 2 ] + 1 = 112 and [ ( 80 - 8 ) / 2 ] + 1 = 37 mean of integers = ( 224 + 2 ) / 2 = 113 and ( 80 + 8 ) / 2 = 44 sum of integers = ( 112 * 113 ) = 12656 and ( 37 * 44 ) = 1628 thus their difference ( i - k ) = 12656 - 1628 = 11028 answer : a | general |
math_qa__hIRW6mGzd4dVsiFj | If 25% of x is 15 less than 12% of 1500, then x is? Pick:
A) 660
B) 738
C) 837
D) 840
E) 83 | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1_500 * (3/25)</gadget>
<output>180</output>
<gadget id="calculator">180 - 15</gadget>
<output>165</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">165 / (1/4)</gadget>
<output>660</output>
<result>A</result> | A | 660 | If 25% of x is 15 less than 12% of 1500, then x is? | {
"A": "660",
"B": "738",
"C": "837",
"D": "840",
"E": "83"
} | divide(subtract(multiply(1500, divide(12, const_100)), 15), divide(25, const_100)) | divide(n2,const_100)|divide(n0,const_100)|multiply(n3,#0)|subtract(#2,n1)|divide(#3,#1)| | "25 % of x = x / 4 ; 12 % of 1500 = 12 / 100 * 1500 = 180 given that , x / 4 = 180 - 15 = > x / 4 = 165 = > x = 660 . answer : a" | general |
math_qa__NTXlPOdzXrmt2lPW | Evaluate: 11 + sqrt(- 4 + 6×4÷3)=....
Choose the correct choice from the following options.
A) 3 B) 33 C) 43 D) 23 E) 13 | <gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">24 / 3</gadget>
<output>8</output>
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">4 ** (1/2)</gadget>
<output>2</output>
<gadget id="calculator">11 + 2</gadget>
<output>13</output>
<result>E</result> | E | 13 | Evaluate: 11 + sqrt(- 4 + 6×4÷3)=.... | {
"A": "3",
"B": "33",
"C": "43",
"D": "23",
"E": "13"
} | add(11, sqrt(subtract(divide(multiply(6, 4), 3), 4))) | multiply(n1,n2)|divide(#0,n4)|subtract(#1,n1)|sqrt(#2)|add(n0,#3) | according to order of operations , inner brackets first where 6 × 4 ÷ 3 is first calculated since it has a multiplication and a division . 6 × 4 ÷ 3 = 24 ÷ 3 = 8 hence 11 + sqrt ( - 4 + 6 × 4 ÷ 3 ) = 11 + sqrt ( - 4 + 8 ) = 11 + sqrt ( 4 ) = 11 + 2 = 13 correct answer is e ) 13 | general |
math_qa__UpAPQNHIDa3muPZK | If 3 women can color 180 m long cloth in 2 days, then 5 women can color 300 m long cloth in? Choose the correct choice from the following choices.
A) 2 days B) 3 days C) 5 days D) 1 day E) 4 days | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">180 / 6</gadget>
<output>30</output>
<gadget id="calculator">5 * 30</gadget>
<output>150</output>
<gadget id="calculator">300 / 150</gadget>
<output>2</output>
<result>A</result> | A | 2 | If 3 women can color 180 m long cloth in 2 days, then 5 women can color 300 m long cloth in? | {
"A": "2 days",
"B": "3 days",
"C": "5 days",
"D": "1 day",
"E": "4 days"
} | divide(300, multiply(5, divide(180, multiply(3, 2)))) | multiply(n0,n2)|divide(n1,#0)|multiply(n3,#1)|divide(n4,#2)| | "the length of cloth painted by one woman in one day = 180 / 3 × 2 = 30 m no . of days required to paint 300 m cloth by 5 women = 300 / 5 × 30 = 2 days answer : a" | physics |
math_qa__gfCisorhakpZR9s0 | If $ 5,000 is invested in an account that earns 6% interest compounded semi-annually, then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8% simple yearly interest? Choices
A) $ 6
B) $ 8
C) $ 12
D) $ 16
E) $ 432 | <gadget id="calculator">6 * 1</gadget>
<output>6</output>
<result>A</result> | A | 6 | If $ 5,000 is invested in an account that earns 6% interest compounded semi-annually, then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8% simple yearly interest? | {
"A": "$ 6",
"B": "$ 8",
"C": "$ 12",
"D": "$ 16",
"E": "$ 432"
} | multiply(6, const_1) | multiply(n1,const_1)| | "ans a solution amount ( ci ) = p + ( 1 + r / n ) ^ nt = 5000 + ( 1 + 0.06 / 2 ) ^ 2 = 5406 amount ( si ) = p + ptr / 100 = 5000 + ( 5000 * 1 * 8 / 100 ) = 5400 difference = 5406 - 5400 = 6 $ a" | gain |
math_qa__uuQU6sFXPCLZuUVM | A train with 1200m crosses a tree in 120sec, how much time will I take to pass a platform 700m long?
Pick one:
A) 150 sec
B) 130 sec
C) 190 sec
D) 200 sec
E) 100 sec | <gadget id="calculator">1_200 + 700</gadget>
<output>1_900</output>
<gadget id="calculator">1_200 / 120</gadget>
<output>10</output>
<gadget id="calculator">1_900 / 10</gadget>
<output>190</output>
<result>C</result> | C | 190 | A train with 1200m crosses a tree in 120sec, how much time will I take to pass a platform 700m long? | {
"A": "150 sec",
"B": "130 sec",
"C": "190 sec",
"D": "200 sec",
"E": "100 sec"
} | divide(add(1200, 700), divide(1200, 120)) | add(n0,n2)|divide(n0,n1)|divide(#0,#1) | s = 1200 / 120 s - 10 m / sec total length = 1900 m t = d / s t = 1900 / 10 t = 190 sec answer c | physics |
math_qa__tUU0fKimmmTd5hgP | The area of a circle is added to its diameter, and the circumference is then subtracted from this total, the result is 10. What is the radius of the circle? Pick
A) 2 * pi B) pi C) 2 D) 4 * pi E) 4 | <gadget id="calculator">1 - pi</gadget>
<output>1 - pi = around -2.141593</output>
<gadget id="calculator">(1 - pi) * 2</gadget>
<output>2 - 2*pi = around -4.283185</output>
<gadget id="calculator">(2 - 2*pi) / pi</gadget>
<output>(2 - 2*pi)/pi = around -1.36338</output>
<gadget id="calculator">((2 - 2*pi)/pi) ** 2</gadget>
<output>(2 - 2*pi)**2/pi**2 = around 1.858806</output>
<gadget id="calculator">10 / pi</gadget>
<output>10/pi = around 3.183099</output>
<gadget id="calculator">-(10/pi)</gadget>
<output>-10/pi = around -3.183099</output>
<gadget id="calculator">4 * (-10/pi)</gadget>
<output>-40/pi = around -12.732395</output>
<gadget id="calculator">((2 - 2*pi)**2/pi**2) - (-40/pi)</gadget>
<output>(2 - 2*pi)**2/pi**2 + 40/pi = around 14.591201</output>
<gadget id="calculator">((2 - 2*pi)**2/pi**2 + 40/pi) ** (1/2)</gadget>
<output>sqrt((2 - 2*pi)**2/pi**2 + 40/pi) = around 3.819843</output>
<result>E</result> | E | 4 | The area of a circle is added to its diameter, and the circumference is then subtracted from this total, the result is 10. What is the radius of the circle? | {
"A": "2 * pi",
"B": "pi",
"C": "2",
"D": "4 * pi",
"E": "4"
} | sqrt(subtract(power(divide(multiply(subtract(const_1, const_pi), const_2), const_pi), const_2), multiply(const_4, negate(divide(10, const_pi))))) | divide(n0,const_pi)|subtract(const_1,const_pi)|multiply(#1,const_2)|negate(#0)|divide(#2,const_pi)|multiply(#3,const_4)|power(#4,const_2)|subtract(#6,#5)|sqrt(#7) | the equation is ; diameter + area - circumference = d + a - c = d + pi * r ^ 2 - 2 * pi * r = 2 r + pi * r ( r - 2 ) . by plugging in the answers we can test the answers quickly ; then , 4 is the only possible answer . answer : e | geometry |
math_qa__bSakWhhyGc5g1AmF | A circular well with a diameter of 2 metres , is dug to a depth of 8 metres. What is the volume of the earth dug out? Choose the most appropriate option
A) 32 m 3
B) 25.1 m 3
C) 40 m 3
D) 44 m 3
E) none | <gadget id="calculator">2 / 2</gadget>
<output>1</output>
<gadget id="calculator">pi * (1 ** 2) * 8</gadget>
<output>8*pi = around 25.132741</output>
<result>B</result> | B | 25.1 | A circular well with a diameter of 2 metres , is dug to a depth of 8 metres. What is the volume of the earth dug out? | {
"A": "32 m 3",
"B": "25.1 m 3",
"C": "40 m 3",
"D": "44 m 3",
"E": "none"
} | volume_cylinder(divide(2, 2), 8) | divide(n0,n0)|volume_cylinder(#0,n1)| | "solution volume = π r 2 h ‹ = › ( 22 / 7 × 1 × 1 × 8 ) m 3 ‹ = › 25.1 m 3 . answer b" | geometry |
math_qa__zS4UEesbTVBx7ngi | A man can row upstream at 5 kmph and downstream at 25kmph, and then find the speed of the man in still water? Choices
A) 15 B) 77 C) 30 D) 88 E) 34 | <gadget id="calculator">5 + 25</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>A</result> | A | 15 | A man can row upstream at 5 kmph and downstream at 25kmph, and then find the speed of the man in still water? | {
"A": "15",
"B": "77",
"C": "30",
"D": "88",
"E": "34"
} | divide(add(5, 25), const_2) | add(n0,n1)|divide(#0,const_2)| | "us = 5 ds = 25 m = ( 5 + 25 ) / 2 = 15 answer : a" | physics |
math_qa__q6crdOuImih51p0s | Sum of 49 odd numbers is?
Choose the correct choice from the following answers.
A) 2398
B) 2399
C) 2400
D) 2401
E) 2402 | <gadget id="calculator">49 * 2</gadget>
<output>98</output>
<gadget id="calculator">49 / 2</gadget>
<output>49/2 = around 24.5</output>
<gadget id="calculator">98 * (49/2)</gadget>
<output>2_401</output>
<result>D</result> | D | 2,401 | Sum of 49 odd numbers is? | {
"A": "2398",
"B": "2399",
"C": "2400",
"D": "2401",
"E": "2402"
} | multiply(multiply(49, const_2), divide(49, const_2)) | divide(n0,const_2)|multiply(n0,const_2)|multiply(#0,#1) | sum of 1 st n odd no . s = 1 + 3 + 5 + 7 + . . . = n ^ 2 so , sum of 1 st 49 odd numbers = 49 ^ 2 = 2401 answer : d | general |
math_qa__XAXuxZ8nq2ZKDkZg | The product of x and y is a constant. If the value of x is increased by 20%, by what percentage must the value of y be decreased? Choose the correct choice from the following answers.
A) 16.66 % B) 33.33 % C) 44.44 % D) 55.55 % E) 19.92 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 / 120</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">1 - (5/6)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 100</gadget>
<output>50/3 = around 16.666667</output>
<result>A</result> | A | 16.66 | The product of x and y is a constant. If the value of x is increased by 20%, by what percentage must the value of y be decreased? | {
"A": "16.66 %",
"B": "33.33 %",
"C": "44.44 %",
"D": "55.55 %",
"E": "19.92 %"
} | multiply(subtract(const_1, divide(const_100, add(const_100, 20))), const_100) | add(n0,const_100)|divide(const_100,#0)|subtract(const_1,#1)|multiply(#2,const_100)| | "x * y = constt . let x = y = 100 in beginning i . e . x * y = 100 * 100 = 10000 x ( 100 ) - - - becomes - - - > 1.2 x ( 120 ) i . e . 120 * new ' y ' = 10000 i . e . new ' y ' = 10000 / 120 = 83.33 i . e . y decreases from 100 to 83.33 i . e . decrease of 16.66 % answer : option a" | general |
math_qa__tc88kY6EWPMCmeQ2 | If 12 men or 20 women can do a piece of work in 27 days, then in how many days can 9 men and 12 women together do the work?
Choose the correct option
A) 10 days B) 30 days C) 20 days D) 80 days E) 40 days | <gadget id="calculator">12 * 27</gadget>
<output>324</output>
<gadget id="calculator">9 / 324</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">20 * 27</gadget>
<output>540</output>
<gadget id="calculator">12 / 540</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">(1/36) + (1/45)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / (1/20)</gadget>
<output>20</output>
<result>C</result> | C | 20 | If 12 men or 20 women can do a piece of work in 27 days, then in how many days can 9 men and 12 women together do the work? | {
"A": "10 days",
"B": "30 days",
"C": "20 days",
"D": "80 days",
"E": "40 days"
} | inverse(add(divide(9, multiply(12, 27)), divide(12, multiply(20, 27)))) | multiply(n0,n2)|multiply(n1,n2)|divide(n3,#0)|divide(n4,#1)|add(#2,#3)|inverse(#4)| | "c 20 days given that 12 m = 20 w = > 3 m = 5 w 9 men + 12 women = 15 women + 12 women = 27 women 20 women can do the work in 27 days . so , 27 women can do it in ( 20 * 27 ) / 27 = 20 days ." | physics |
math_qa__OtVHiHQyDFP4hrJb | How many trucks are there if each truck carrying 70 packages and total of 490 packages?
Choose the correct choice
A) 7 B) 6 C) 9 D) 11 E) none of the above | <gadget id="calculator">490 / 70</gadget>
<output>7</output>
<result>A</result> | A | 7 | How many trucks are there if each truck carrying 70 packages and total of 490 packages? | {
"A": "7",
"B": "6",
"C": "9",
"D": "11",
"E": "none of the above"
} | divide(490, 70) | divide(n1,n0) | sol . total packages 490 each truck carries 70 packages = 490 / 70 = 7 answer : a | general |
math_qa__u2nRr9afEgnsRjyW | The average of 6 observations is 14. A new observation is included and the new average is decreased by 1. The seventh observation is? Choose the correct option.
A) 1 B) 3 C) 5 D) 6 E) 7 | <gadget id="calculator">14 - 1</gadget>
<output>13</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">13 * 7</gadget>
<output>91</output>
<gadget id="calculator">14 * 6</gadget>
<output>84</output>
<gadget id="calculator">91 - 84</gadget>
<output>7</output>
<result>E</result> | E | 7 | The average of 6 observations is 14. A new observation is included and the new average is decreased by 1. The seventh observation is? | {
"A": "1",
"B": "3",
"C": "5",
"D": "6",
"E": "7"
} | subtract(multiply(subtract(14, 1), add(6, 1)), multiply(14, 6)) | add(n0,n2)|multiply(n0,n1)|subtract(n1,n2)|multiply(#0,#2)|subtract(#3,#1)| | "let seventh observation = x . then , according to the question we have = > ( 84 + x ) / 7 = 13 = > x = 7 . hence , the seventh observation is 7 . answer : e" | general |
math_qa__Qr0YlelnAMLud8Wd | Find the value of (50+ 20/90) × 90 Choose the correct choice from the following answers: A) 2520 B) 3520 C) 4520 D) 1520 E) 1750 | <gadget id="calculator">20 / 90</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(2/9) + 50</gadget>
<output>452/9 = around 50.222222</output>
<gadget id="calculator">(452/9) * 90</gadget>
<output>4_520</output>
<result>C</result> | C | 4,520 | Find the value of (50+ 20/90) × 90 | {
"A": "2520",
"B": "3520",
"C": "4520",
"D": "1520",
"E": "1750"
} | multiply(add(divide(20, 90), 50), 90) | divide(n1,n2)|add(n0,#0)|multiply(#1,n2)| | "( 4500 + 20 ) / 90 * 90 = 4520 answer : c" | general |
math_qa__sF3FIxmjjvOo98a5 | From January 1, 2015, to January 1, 2017, the number of people enrolled in health maintenance organizations increased by 5 percent. The enrollment on January 1, 2017, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 2015 ? Choices:
A) 38
B) 39
C) 40
D) 41
E) 43 | <gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">100 / 105</gadget>
<output>20/21 = around 0.952381</output>
<gadget id="calculator">(20/21) * 45</gadget>
<output>300/7 = around 42.857143</output>
<result>E</result> | E | 43 | From January 1, 2015, to January 1, 2017, the number of people enrolled in health maintenance organizations increased by 5 percent. The enrollment on January 1, 2017, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 2015 ? | {
"A": "38",
"B": "39",
"C": "40",
"D": "41",
"E": "43"
} | multiply(divide(const_100, add(const_100, 5)), 45) | add(n4,const_100)|divide(const_100,#0)|multiply(n7,#1)| | "soln : - 5 x = 45 - - > 21 / 20 * x = 45 - - > x = 45 * 20 / 21 = 300 / 7 = ~ 43 . answer : e ." | gain |
math_qa__5xDRhRs8iVRGtWyT | The number which exceeds 16% of it by 42 is :
Choose the correct choice from the following options: A) 50 B) 52 C) 58 D) 60 E) 62 | <gadget id="calculator">42 * 100</gadget>
<output>4_200</output>
<gadget id="calculator">100 - 16</gadget>
<output>84</output>
<gadget id="calculator">4_200 / 84</gadget>
<output>50</output>
<result>A</result> | A | 50 | The number which exceeds 16% of it by 42 is : | {
"A": "50",
"B": "52",
"C": "58",
"D": "60",
"E": "62"
} | divide(multiply(42, const_100), subtract(const_100, 16)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "solution solution let the number be x . x - 16 % of x = 42 x - 16 / 100 x = 42 x - 4 / 25 x = 42 21 / 25 x = 42 x = ( 42 x 25 / 21 ) = 50 answer a" | gain |
math_qa__xpZiqdMDD10M0unB | In assembling a Bluetooth device, a factory uses one of two kinds of modules. One module costs $10 and the other one, that is cheaper, costs $2.5. The factory holds a $62.50 worth stock of 22 modules. How many of the modules in the stock are of the cheaper kind? Choose the correct choice from the following answers
A) 31 B) 35 C) 21 D) 40 E) 45 | <gadget id="calculator">62.5 - 10</gadget>
<output>52.5</output>
<gadget id="calculator">52.5 / 2.5</gadget>
<output>21</output>
<result>C</result> | C | 21 | In assembling a Bluetooth device, a factory uses one of two kinds of modules. One module costs $10 and the other one, that is cheaper, costs $2.5. The factory holds a $62.50 worth stock of 22 modules. How many of the modules in the stock are of the cheaper kind? | {
"A": "31",
"B": "35",
"C": "21",
"D": "40",
"E": "45"
} | divide(subtract(62.50, 10), 2.5) | subtract(n2,n0)|divide(#0,n1)| | "so the number of $ 2.50 modules must be 21 so that the leftover 1 modules are of $ 10 which will give a total value $ 62.50 . 21 * 2.50 + 1 * 10 = 52.50 + 10 = 62.50 answer : c" | other |
math_qa__byRUAIS18bUxzrrY | Mary goes into labor at her local grocery store and is rushed to a hospital in an ambulance traveling 60mph. Her husband Don drives after the ambulance at an average speed of 30mph. Mary reaches the hospital fifteen minutes later. How long does it take Don to get there from the store? Options.
A) 25 minutes B) 30 minutes C) 10 minutes D) 15 minutes E) 7 minutes | <gadget id="calculator">3 + 12</gadget>
<output>15</output>
<gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">30 * (1/4)</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">60 - 30</gadget>
<output>30</output>
<gadget id="calculator">(15/2) / 30</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 60</gadget>
<output>15</output>
<gadget id="calculator">15 + 15</gadget>
<output>30</output>
<result>B</result> | B | 30 | Mary goes into labor at her local grocery store and is rushed to a hospital in an ambulance traveling 60mph. Her husband Don drives after the ambulance at an average speed of 30mph. Mary reaches the hospital fifteen minutes later. How long does it take Don to get there from the store? | {
"A": "25 minutes",
"B": "30 minutes",
"C": "10 minutes",
"D": "15 minutes",
"E": "7 minutes"
} | add(add(const_3, const_12), multiply(divide(multiply(30, divide(add(const_3, const_12), const_60)), subtract(60, 30)), const_60)) | add(const_12,const_3)|subtract(n0,n1)|divide(#0,const_60)|multiply(n1,#2)|divide(#3,#1)|multiply(#4,const_60)|add(#0,#5) | distance covered by the ambulance in 15 minutes = 15 miles 60 mph is one mile per minute , therefore 30 mph will be 1 / 2 a mile per minute . so , he reaches the hospital half an hour after leaving the store . correct answer : b | physics |
math_qa__8cgSgKC1jiqwAv5G | What is the ratio between perimeters of two squares one having 7 times the diagonal then the other? Choose the correct choice from the following answers.
A) 3 : 7 B) 3 : 5 C) 3 : 8 D) 7 : 1 E) 3 : 5 | <gadget id="calculator">7 / 7</gadget>
<output>1</output>
<gadget id="calculator">7 / 1</gadget>
<output>7</output>
<result>D</result> | D | 7 | What is the ratio between perimeters of two squares one having 7 times the diagonal then the other? | {
"A": "3 : 7",
"B": "3 : 5",
"C": "3 : 8",
"D": "7 : 1",
"E": "3 : 5"
} | divide(7, divide(7, 7)) | divide(n0,n0)|divide(n0,#0)| | "d = 7 d d = d a √ 2 = 7 d a √ 2 = d a = 7 d / √ 2 a = d / √ 2 = > 7 : 1 answer : d" | geometry |
math_qa__S7w1HLXJgPOVa4B3 | Square A has an area of 65 square centimeters. Square B has a perimeter of 16 centimeters. If square B is placed within square A and a random point is chosen within square A, what is the probability the point is not within square B? Choose the correct choice from the following options:
A) 0.25
B) 0.5
C) 0.75
D) 0.1
E) 0.3 | <gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">65 - 16</gadget>
<output>49</output>
<gadget id="calculator">49 / 65</gadget>
<output>49/65 = around 0.753846</output>
<result>C</result> | C | 0.75 | Square A has an area of 65 square centimeters. Square B has a perimeter of 16 centimeters. If square B is placed within square A and a random point is chosen within square A, what is the probability the point is not within square B? | {
"A": "0.25",
"B": "0.5",
"C": "0.75",
"D": "0.1",
"E": "0.3"
} | divide(subtract(65, power(divide(16, const_4), const_2)), 65) | divide(n1,const_4)|power(#0,const_2)|subtract(n0,#1)|divide(#2,n0)| | "i guess it ' s mean that square b is placed within square aentirely . since , the perimeter of b is 16 , then its side is 16 / 4 = 4 and the area is 4 ^ 2 = 16 ; empty space between the squares is 65 - 16 = 48 square centimeters , so if a random point is in this area then it wo n ' t be within square b : p = favorable / total = 48 / 64 = 0.75 . answer : c" | geometry |
math_qa__X5n6HiLwkaV9ukzG | In an election, candidate A got 80% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favor of candidate. Choose the correct choice from the following answers.
A) 330000 B) 340000 C) 380800 D) 356000 E) 357000 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">560_000 * (17/20)</gadget>
<output>476_000</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">476_000 * (4/5)</gadget>
<output>380_800</output>
<result>C</result> | C | 380,800 | In an election, candidate A got 80% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favor of candidate. | {
"A": "330000",
"B": "340000",
"C": "380800",
"D": "356000",
"E": "357000"
} | multiply(multiply(560000, subtract(const_1, divide(15, const_100))), divide(80, const_100)) | divide(n0,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(n2,#2)|multiply(#0,#3)| | "total number of invalid votes = 15 % of 560000 = 15 / 100 × 560000 = 8400000 / 100 = 84000 total number of valid votes 560000 – 84000 = 476000 percentage of votes polled in favour of candidate a = 80 % therefore , the number of valid votes polled in favour of candidate a = 80 % of 476000 = 80 / 100 × 476000 = 38080000 / 100 = 380800 c )" | gain |
math_qa__fSIUWlj6Zhv9elh0 | A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 560 sq. feet, how many feet of fencing will be required?
Select the correct option.
A) 34 B) 40 C) 68 D) 76 E) 92 | <gadget id="calculator">560 / 20</gadget>
<output>28</output>
<gadget id="calculator">28 * 2</gadget>
<output>56</output>
<gadget id="calculator">56 + 20</gadget>
<output>76</output>
<result>D</result> | D | 76 | A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 560 sq. feet, how many feet of fencing will be required? | {
"A": "34",
"B": "40",
"C": "68",
"D": "76",
"E": "92"
} | add(multiply(divide(560, 20), const_2), 20) | divide(n1,n0)|multiply(#0,const_2)|add(n0,#1)| | "given that length and area , so we can find the breadth . length x breadth = area 20 x breadth = 560 breadth = 28 feet area to be fenced = 2 b + l = 2 ( 28 ) + 20 = 76 feet answer : d" | geometry |
math_qa__j32f9ZiqEl5rOYQV | if a man earns Rs20 on first day and spends Rs15 on second day ,and earns Rs20 on third day and spends Rs 15 on fourth day and goes on on which day he will be having Rs 60.
Choose the correct choice:
A) 40 rs
B) 45 rs
C) 50 rs
D) 55 rs
E) 60 rs | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">(5/2) * 16</gadget>
<output>40</output>
<gadget id="calculator">40 + 20</gadget>
<output>60</output>
<result>E</result> | E | 60 | if a man earns Rs20 on first day and spends Rs15 on second day ,and earns Rs20 on third day and spends Rs 15 on fourth day and goes on on which day he will be having Rs 60. | {
"A": "40 rs",
"B": "45 rs",
"C": "50 rs",
"D": "55 rs",
"E": "60 rs"
} | add(multiply(divide(add(const_3, const_2), const_2), multiply(const_4, const_4)), 20) | add(const_2,const_3)|multiply(const_4,const_4)|divide(#0,const_2)|multiply(#2,#1)|add(n0,#3) | earns rs 20 on first day and spends rs 15 on second day means , end of day 2 , he have 5 rs . therefore , in 16 days he have 40 rs 2 * 8 = 16 days 5 rs * 8 = 40 rs and on the 17 th day again he earn rs . 20 , 40 + 20 = 60 rs . answer : e | physics |
math_qa__xYIihZavyxPG70E1 | 4 mat-weaves can weaves 4 mats in 4 days.At the same rate,how many mats would be woven by 8 mat-weaves in 8 days ? Options:
A) 4
B) 8
C) 12
D) 16
E) 17 | <gadget id="calculator">4 * 8</gadget>
<output>32</output>
<gadget id="calculator">32 * 8</gadget>
<output>256</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">256 / 16</gadget>
<output>16</output>
<result>D</result> | D | 16 | 4 mat-weaves can weaves 4 mats in 4 days.At the same rate,how many mats would be woven by 8 mat-weaves in 8 days ? | {
"A": "4",
"B": "8",
"C": "12",
"D": "16",
"E": "17"
} | divide(multiply(multiply(4, 8), 8), multiply(4, 4)) | multiply(n0,n3)|multiply(n0,n0)|multiply(n3,#0)|divide(#2,#1) | solution let the required number of mats be x . more weaves , more mats ( direct proportion ) more days , more mats ( direct proportion ) ∴ 4 × 4 × x = 8 × 8 × 4 ⇔ x = ( 8 x 8 x 4 ) / ( 4 x 4 ) = 16 . answer d | gain |
math_qa__O4eOZH79F2NyfpZt | Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train catches and completely passes the slower train in 18 seconds. What is the length of each train (in meters)? Choices: A) 20 B) 25 C) 35 D) 50 E) 65 | <gadget id="calculator">46 - 36</gadget>
<output>10</output>
<gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 3_600</gadget>
<output>25/9 = around 2.777778</output>
<gadget id="calculator">(25/9) * 18</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>B</result> | B | 25 | Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train catches and completely passes the slower train in 18 seconds. What is the length of each train (in meters)? | {
"A": "20",
"B": "25",
"C": "35",
"D": "50",
"E": "65"
} | divide(multiply(divide(multiply(subtract(46, 36), const_1000), const_3600), 18), const_2) | subtract(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n2,#2)|divide(#3,const_2)| | "the relative speed = 46 - 36 = 10 km / hr = 10 * 5 / 18 = 25 / 9 m / s in 18 seconds , the relative difference in distance traveled is 18 * 25 / 9 = 50 meters this distance is twice the length of each train . the length of each train is 50 / 2 = 25 meters the answer is b ." | physics |
math_qa__b1ekjVAWjlRfaa1Y | A train is 360 meter long is running at a speed of 90 km/hour. In what time will it pass a bridge of 140 meter length? Choose the correct choice from the following: A) 27 seconds B) 29 seconds C) 40 seconds D) 11 seconds E) 20 seconds | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">90 * 1_000</gadget>
<output>90_000</output>
<gadget id="calculator">90_000 / 3_600</gadget>
<output>25</output>
<gadget id="calculator">500 / 25</gadget>
<output>20</output>
<result>E</result> | E | 20 | A train is 360 meter long is running at a speed of 90 km/hour. In what time will it pass a bridge of 140 meter length? | {
"A": "27 seconds",
"B": "29 seconds",
"C": "40 seconds",
"D": "11 seconds",
"E": "20 seconds"
} | divide(add(360, 140), divide(multiply(90, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 90 km / hr = 90 * ( 5 / 18 ) m / sec = 25 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 * ( 1 / 25 ) = 20 seconds answer : e" | physics |
math_qa__3QTVmFdBrpnCT7JO | If Sharon's weekly salary increased by 16 percent, she would earn $348 per week. If instead, her weekly salary were to increase by 20 percent, how much would she earn per week?
Select the correct option
A) $ 374 B) $ 382 C) $ 385 D) $ 360 E) $ 399 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">1 + (4/25)</gadget>
<output>29/25 = around 1.16</output>
<gadget id="calculator">348 / (29/25)</gadget>
<output>300</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 300</gadget>
<output>60</output>
<gadget id="calculator">300 + 60</gadget>
<output>360</output>
<result>D</result> | D | 360 | If Sharon's weekly salary increased by 16 percent, she would earn $348 per week. If instead, her weekly salary were to increase by 20 percent, how much would she earn per week? | {
"A": "$ 374",
"B": "$ 382",
"C": "$ 385",
"D": "$ 360",
"E": "$ 399"
} | add(divide(348, add(const_1, divide(16, const_100))), multiply(divide(20, const_100), divide(348, add(const_1, divide(16, const_100))))) | divide(n0,const_100)|divide(n2,const_100)|add(#0,const_1)|divide(n1,#2)|multiply(#1,#3)|add(#3,#4)| | "( 348 / 116 ) 120 = 360 in this case long division does not take much time . ( 348 / 116 ) = 3 3 * 120 = 360 ( 300 + 60 ) answer d" | general |
math_qa__emA35p8GfouVO8Ri | If the ratio of a to b is 11 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? Choose the correct choice from the following.
A) 4 / 15 B) 11 / 15 C) 2 / 5 D) 4 / 5 E) 7 / 6 | <gadget id="calculator">11 * 1</gadget>
<output>11</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">11 / 15</gadget>
<output>11/15 = around 0.733333</output>
<result>B</result> | B | 0.733333 | If the ratio of a to b is 11 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? | {
"A": "4 / 15",
"B": "11 / 15",
"C": "2 / 5",
"D": "4 / 5",
"E": "7 / 6"
} | divide(multiply(11, 1), multiply(3, 5)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "a : b = 11 : 3 - - 1 b : c = 1 : 5 = > b : c = 3 : 15 - - 2 from 1 and 2 , we get a : c = 11 : 15 answer b" | other |
math_qa__pvCiU75gurDUYNtt | What should be the least number to be added to the 2496 number to make it divisible by 5? Choose the correct option: A) 12 B) 17 C) 18 D) 4 E) 26 | <gadget id="calculator">2_496 % 5</gadget>
<output>1</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<result>D</result> | D | 4 | What should be the least number to be added to the 2496 number to make it divisible by 5? | {
"A": "12",
"B": "17",
"C": "18",
"D": "4",
"E": "26"
} | subtract(5, reminder(2496, 5)) | reminder(n0,n1)|subtract(n1,#0)| | "answer : 4 option : d" | general |
math_qa__7ni7vgs75bZNX27K | 1⁄5 of a number is equal to 5⁄8 of the second number. If 35 is added to the first number then it becomes 4 times of second number. What is the value of the second number? Options.
A) 125
B) 70
C) 40
D) 25
E) none of these | <gadget id="calculator">35 * 8</gadget>
<output>280</output>
<gadget id="calculator">8 * 4</gadget>
<output>32</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">32 - 25</gadget>
<output>7</output>
<gadget id="calculator">280 / 7</gadget>
<output>40</output>
<result>C</result> | C | 40 | 1⁄5 of a number is equal to 5⁄8 of the second number. If 35 is added to the first number then it becomes 4 times of second number. What is the value of the second number? | {
"A": "125",
"B": "70",
"C": "40",
"D": "25",
"E": "none of these"
} | divide(multiply(35, 8), subtract(multiply(8, 4), multiply(5, 5))) | multiply(n3,n4)|multiply(n3,n5)|multiply(n1,n1)|subtract(#1,#2)|divide(#0,#3) | let x be the first number and y be the second number . 1 ⁄ 5 x = 5 ⁄ 8 y \ x ⁄ y = 25 ⁄ 8 . . . . . . ( i ) x + 35 = 4 y or , 25 ⁄ 8 y + 35 = 4 y \ y = 40 answee c | general |
math_qa__BzrItxB9eB0vUGlV | In what time will a train 130 m long cross an electric pole, it its speed be 144 km/hr?
Answers:
A) 2.5 sec
B) 3.25 sec
C) 5 sec
D) 12.5 sec
E) 6 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">130 / 40</gadget>
<output>13/4 = around 3.25</output>
<result>B</result> | B | 3.25 | In what time will a train 130 m long cross an electric pole, it its speed be 144 km/hr? | {
"A": "2.5 sec",
"B": "3.25 sec",
"C": "5 sec",
"D": "12.5 sec",
"E": "6 sec"
} | divide(130, multiply(144, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 144 * 5 / 18 = 40 m / sec time taken = 130 / 40 = 3.25 sec . answer : b" | physics |
math_qa__Ye8gN8QBPhXlp5k0 | Donald duck can can swim his pool downstream(with the pool current helping time) in exact 40 seconds and upstream(against the pool current) in a pool in exact 60 seconds. The length of pool is 2 kilometers.
How long Donald duck can cover distance of one side at a still pool (with no current). Answers
A) 40 minutes
B) 45 minutes
C) 38 minutes
D) 48 minutes
E) 30 minutes | <gadget id="calculator">2 * 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 40</gadget>
<output>50</output>
<gadget id="calculator">2_000 / 60</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">50 + (100/3)</gadget>
<output>250/3 = around 83.333333</output>
<gadget id="calculator">(250/3) / 2</gadget>
<output>125/3 = around 41.666667</output>
<gadget id="calculator">2_000 / (125/3)</gadget>
<output>48</output>
<result>D</result> | D | 48 | Donald duck can can swim his pool downstream(with the pool current helping time) in exact 40 seconds and upstream(against the pool current) in a pool in exact 60 seconds. The length of pool is 2 kilometers.
How long Donald duck can cover distance of one side at a still pool (with no current). | {
"A": "40 minutes",
"B": "45 minutes",
"C": "38 minutes",
"D": "48 minutes",
"E": "30 minutes"
} | divide(multiply(2, const_1000), divide(add(divide(multiply(2, const_1000), 40), divide(multiply(2, const_1000), 60)), 2)) | multiply(n2,const_1000)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)|divide(#3,n2)|divide(#0,#4) | d 48 minutes . donald duck ' s speed = x km / seconds pool current speed = y km / seconds 2 / ( x + y ) = 40 2 / ( x - y ) = 60 solving the simultaneous equations gives x = 1 / 24 therefore , to cover 2 km will take 2 / x = 48 seconds | physics |
math_qa__WLGGOxnhwOVnnNMm | An plane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 5/3 hours, it must travel at a speed of ? Pick one
A) 100
B) 720
C) 1100
D) 940
E) 860 | <gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">5 / (5/3)</gadget>
<output>3</output>
<gadget id="calculator">240 * 3</gadget>
<output>720</output>
<result>B</result> | B | 720 | An plane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 5/3 hours, it must travel at a speed of ? | {
"A": "100",
"B": "720",
"C": "1100",
"D": "940",
"E": "860"
} | multiply(240, divide(5, divide(5, 3))) | divide(n1,n3)|divide(n1,#0)|multiply(n0,#1) | we know distance = speed * time = 240 * 5 = 1200 km now to cover 1200 km in 5 / 3 hrs , speed = distance / time = 1200 / ( 5 / 3 ) = 720 kmph ans - b | physics |
math_qa__QhonTrCqb7e9E8Lo | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 4. If the sum of their ages is 132, what is the difference between the ages of Patrick and Monica? Choose the most appropriate option
A) 27 B) 48 C) 45 D) 72 E) 33 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">9 + 15</gadget>
<output>24</output>
<gadget id="calculator">24 + 20</gadget>
<output>44</output>
<gadget id="calculator">132 / 44</gadget>
<output>3</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">9 * 3</gadget>
<output>27</output>
<gadget id="calculator">60 - 27</gadget>
<output>33</output>
<result>E</result> | E | 33 | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 4. If the sum of their ages is 132, what is the difference between the ages of Patrick and Monica? | {
"A": "27",
"B": "48",
"C": "45",
"D": "72",
"E": "33"
} | subtract(multiply(multiply(4, 5), divide(132, add(add(multiply(3, const_3), multiply(const_3, 5)), multiply(4, 5)))), multiply(multiply(3, const_3), divide(132, add(add(multiply(3, const_3), multiply(const_3, 5)), multiply(4, 5))))) | multiply(n0,const_3)|multiply(n1,const_3)|multiply(n1,n3)|add(#0,#1)|add(#3,#2)|divide(n4,#4)|multiply(#5,#2)|multiply(#5,#0)|subtract(#6,#7) | ages of p and mi = 3 x : 5 x ages of mi and mo = 3 x : 4 x rationalizing their ages . ratio of their ages will be 9 x : 15 x : 20 x sum = 44 x = 132 x = 3 difference if ages of pa and mo = 20 x - 9 x = 11 x = 11 * 3 = 33 answer e | general |
math_qa__vluAQaykCuL90ub0 | Two vessels contains equal number of mixtures milk and water in the ratio 5:2 and 6:1. Both the mixtures are now mixed thoroughly. Find the ratio of milk to water in the new mixture so obtained? Choose the correct choice from the following choices:
A) 1 : 3
B) 9 : 13
C) 5 : 11
D) 11 : 3
E) 15 : 4 | <gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 / 7</gadget>
<output>1</output>
<gadget id="calculator">5 * 1</gadget>
<output>5</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">11 / 3</gadget>
<output>11/3 = around 3.666667</output>
<result>D</result> | D | 3.666667 | Two vessels contains equal number of mixtures milk and water in the ratio 5:2 and 6:1. Both the mixtures are now mixed thoroughly. Find the ratio of milk to water in the new mixture so obtained? | {
"A": "1 : 3",
"B": "9 : 13",
"C": "5 : 11",
"D": "11 : 3",
"E": "15 : 4"
} | divide(add(multiply(5, divide(add(6, 1), add(5, 2))), 6), add(multiply(2, divide(add(6, 1), add(5, 2))), 1)) | add(n2,n3)|add(n0,n1)|divide(#0,#1)|multiply(n0,#2)|multiply(n1,#2)|add(n2,#3)|add(n3,#4)|divide(#5,#6)| | "the ratio of milk and water in the new vessel is = ( 5 / 7 + 6 / 7 ) : ( 2 / 7 + 1 / 7 ) = 11 / 7 : 3 / 7 = 11 : 3 answer is d" | other |
math_qa__o4YCJ1rYB90iioYI | Ashok secured average of 80 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject? Pick one: A) 38 B) 27 C) 99 D) 110 E) 80 | <gadget id="calculator">80 * 6</gadget>
<output>480</output>
<gadget id="calculator">74 * 5</gadget>
<output>370</output>
<gadget id="calculator">480 - 370</gadget>
<output>110</output>
<result>D</result> | D | 110 | Ashok secured average of 80 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject? | {
"A": "38",
"B": "27",
"C": "99",
"D": "110",
"E": "80"
} | subtract(multiply(80, 6), multiply(74, 5)) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)| | "explanation : number of subjects = 6 average of marks in 6 subjects = 80 therefore total marks in 6 subjects = 80 * 6 = 480 now , no . of subjects = 5 total marks in 5 subjects = 74 * 5 = 370 therefore marks in 6 th subject = 480 – 370 = 110 answer : d" | general |
math_qa__hwXl6lddZpw3ha85 | Out of 410 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ? Choose the correct answer
A) 120
B) 150
C) 100
D) 140
E) 220 | <gadget id="calculator">175 + 325</gadget>
<output>500</output>
<gadget id="calculator">410 - 50</gadget>
<output>360</output>
<gadget id="calculator">500 - 360</gadget>
<output>140</output>
<result>D</result> | D | 140 | Out of 410 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ? | {
"A": "120",
"B": "150",
"C": "100",
"D": "140",
"E": "220"
} | subtract(add(175, 325), subtract(410, 50)) | add(n1,n2)|subtract(n0,n3)|subtract(#0,#1) | n ( a ) = 325 , n ( b ) = 175 , n ( aub ) = 410 - 50 = 360 . required number = n ( anb ) = n ( a ) + n ( b ) - n ( aub ) = 325 + 175 - 360 = 140 . answer is d | other |
math_qa__JOGkLlha6HZP8O11 | A number consists of 3 digit whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is: Choose the correct choice from the following.
A) 145 B) 253 C) 370 D) 352 E) 300 | <gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 4</gadget>
<output>3</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">200 + 50</gadget>
<output>250</output>
<gadget id="calculator">250 + 3</gadget>
<output>253</output>
<result>B</result> | B | 253 | A number consists of 3 digit whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is: | {
"A": "145",
"B": "253",
"C": "370",
"D": "352",
"E": "300"
} | add(add(multiply(subtract(divide(add(10, const_2), const_4), const_1), const_100), multiply(add(divide(add(10, const_2), const_4), subtract(divide(add(10, const_2), const_4), const_1)), const_10)), divide(add(10, const_2), const_4)) | add(n1,const_2)|divide(#0,const_4)|subtract(#1,const_1)|add(#1,#2)|multiply(#2,const_100)|multiply(#3,const_10)|add(#4,#5)|add(#6,#1) | explanation : let the middle digit be x . then , 2 x = 10 or x = 5 . so , the number is either 253 or 352 . since the number increases on reversing the digits , so the hundred ' s digit is smaller than the unit ' s digit . hence , required number = 253 . answer is b | general |
math_qa__FcLfGKQmCG64nhue | What amount does an investor receive if the investor invests $5000 at 10% p.a. compound interest for two years, compounding done annually? Select the correct option.
A) $ 5850 B) $ 5950 C) $ 6050 D) $ 6150 E) $ 6250 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 2</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">5_000 * (121/100)</gadget>
<output>6_050</output>
<result>C</result> | C | 6,050 | What amount does an investor receive if the investor invests $5000 at 10% p.a. compound interest for two years, compounding done annually? | {
"A": "$ 5850",
"B": "$ 5950",
"C": "$ 6050",
"D": "$ 6150",
"E": "$ 6250"
} | multiply(5000, power(add(const_1, divide(10, const_100)), const_2)) | divide(n1,const_100)|add(#0,const_1)|power(#1,const_2)|multiply(n0,#2)| | "a = ( 1 + r / 100 ) ^ n * p ( 1.1 ) ^ 2 * 5000 = 1.21 * 5000 = 6050 the answer is c ." | gain |
math_qa__RWO9HEBuTO8XLGce | Of the 3,600 employees of Company X, 1/4 are clerical. If the clerical staff were to be reduced by 1/4, what percent of the total number of the remaining employees would then be clerical?
Answers.
A) 25 %
B) 22.2 %
C) 20 %
D) 12.5 %
E) 11.1 % | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/4) * (3/4)</gadget>
<output>3/16 = around 0.1875</output>
<gadget id="calculator">(3/16) + (3/4)</gadget>
<output>15/16 = around 0.9375</output>
<gadget id="calculator">(3/16) / (15/16)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>C</result> | C | 20 | Of the 3,600 employees of Company X, 1/4 are clerical. If the clerical staff were to be reduced by 1/4, what percent of the total number of the remaining employees would then be clerical? | {
"A": "25 %",
"B": "22.2 %",
"C": "20 %",
"D": "12.5 %",
"E": "11.1 %"
} | multiply(divide(multiply(divide(1, 4), subtract(1, divide(1, 4))), add(multiply(divide(1, 4), subtract(1, divide(1, 4))), subtract(1, divide(1, 4)))), const_100) | divide(n1,n2)|divide(n3,n4)|subtract(n3,#1)|subtract(n3,#0)|multiply(#0,#2)|add(#4,#3)|divide(#4,#5)|multiply(#6,const_100)| | "let ' s see , the way i did it was 1 / 4 are clerical out of 3600 so 900 are clerical 900 reduced by 1 / 4 is 900 * 1 / 4 so it reduced 225 people , so there is 675 clerical people left but since 225 people left , it also reduced from the total of 3600 so there are 3375 people total since 675 clerical left / 3375 people total you get ( c ) 20 %" | general |
math_qa__9kQAzKdCJRVaw5l1 | There are 12 teams in a certain league and each team plays each of the other teams exactly once. What is the total number of games played? Choose the correct choice from the following
A) 55 B) 66 C) 77 D) 88 E) 99 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">12 * 11</gadget>
<output>132</output>
<gadget id="calculator">132 / 2</gadget>
<output>66</output>
<result>B</result> | B | 66 | There are 12 teams in a certain league and each team plays each of the other teams exactly once. What is the total number of games played? | {
"A": "55",
"B": "66",
"C": "77",
"D": "88",
"E": "99"
} | divide(multiply(12, subtract(12, const_1)), const_2) | subtract(n0,const_1)|multiply(n0,#0)|divide(#1,const_2)| | "12 c 2 = 66 the answer is b ." | general |
math_qa__qlFs2oNztWNufqg7 | Tough and Tricky questions: Statistics.
Set X consists of prime numbers {3, 11, 7, A, 17, 19}. If integer Y represents the product of all elements in set X and if 11Y is an even number, what is the range of set X?
Select.
A) 14
B) 16
C) 17
D) 20
E) 26 | <gadget id="calculator">19 - 2</gadget>
<output>17</output>
<result>C</result> | C | 17 | Tough and Tricky questions: Statistics.
Set X consists of prime numbers {3, 11, 7, A, 17, 19}. If integer Y represents the product of all elements in set X and if 11Y is an even number, what is the range of set X? | {
"A": "14",
"B": "16",
"C": "17",
"D": "20",
"E": "26"
} | subtract(19, const_2) | subtract(n4,const_2) | since 11 y = even therefore y has to beevensince 11 is a odd integer ( even * odd = even ) similarly , y is the product of all integers in set x but all integers in set x are odd except the unknown a and since x contains only prime numbers , a has to equal to 2 . . . ( 2 is the only even prime number and the product of all prime numbers in set x has to be even , even * odd = even ) since you know value of a you can calculate the range = largest integer in the set minus smallest integer in the set = 19 - 2 = 17 answer is c | general |
math_qa__muQYHA7Fo1XJ3Lgf | What profit percent is made by selling an article at a certain price, if by selling at 4/5rd of that price, there would be a loss of 20%? Choose the correct choice from the following choices:
A) 0 % B) 29 % C) 70 % D) 27 % E) 28 % | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">80 / (4/5)</gadget>
<output>100</output>
<gadget id="calculator">100 - 100</gadget>
<output>0</output>
<result>A</result> | A | 0 | What profit percent is made by selling an article at a certain price, if by selling at 4/5rd of that price, there would be a loss of 20%? | {
"A": "0 %",
"B": "29 %",
"C": "70 %",
"D": "27 %",
"E": "28 %"
} | subtract(divide(subtract(const_100, 20), divide(4, 5)), const_100) | divide(n0,n1)|subtract(const_100,n2)|divide(#1,#0)|subtract(#2,const_100)| | "sp 2 = 4 / 5 sp 1 cp = 100 sp 2 = 80 4 / 5 sp 1 = 80 sp 1 = 100 100 - - - 100 = > 0 % answer : a" | gain |
math_qa__6X6VERBLEewuUutO | On a sum of money, the simple interest for 2 years is Rs. 320, while the compound interest is Rs. 340, the rate of interest being the same in both the cases. The rate of interest is Choose the correct choice from the following choices.
A) 15 %
B) 14.25 %
C) 12.5 %
D) 10.5 %
E) 11.5 % | <gadget id="calculator">320 / 2</gadget>
<output>160</output>
<gadget id="calculator">340 - 160</gadget>
<output>180</output>
<gadget id="calculator">180 - 160</gadget>
<output>20</output>
<gadget id="calculator">100 * 20</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 160</gadget>
<output>25/2 = around 12.5</output>
<result>C</result> | C | 12.5 | On a sum of money, the simple interest for 2 years is Rs. 320, while the compound interest is Rs. 340, the rate of interest being the same in both the cases. The rate of interest is | {
"A": "15 %",
"B": "14.25 %",
"C": "12.5 %",
"D": "10.5 %",
"E": "11.5 %"
} | divide(multiply(const_100, subtract(subtract(340, divide(320, 2)), divide(320, 2))), divide(320, 2)) | divide(n1,n0)|subtract(n2,#0)|subtract(#1,#0)|multiply(#2,const_100)|divide(#3,#0) | explanation : - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - solution 1 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - simple interest for 2 years is rs . 320 = > simple interest for first year = 320 / 2 = 160 = > similarly , simple interest for second year is also 160 compound interest for first year = 160 compound interest for second year = 340 - 160 = 180 we can see that compound interest for second year is more than simple interest for second year by 180 - 160 = 20 i . e . , rs . 20 is the simple interest on rs . 160 for 1 year r = 100 × si / pt = ( 100 × 20 ) / ( 160 × 1 ) = 12.5 % - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - solution 2 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - the difference between compound interest and simple interest on rs . p for 2 years at r % per annum = ( r × si ) / ( 2 × 100 ) difference between the compound interest and simple interest = 340 - 320 = 20 ( r × si ) / ( 2 × 100 ) = 20 ( r × 320 ) / ( 2 × 100 ) = 20 r = 20 × 100 × 2320 = 12.5 % answer : option c | gain |
math_qa__5tKqCURIF89W13EG | Of the families in City X in 1992, 30 percent owned a personal computer. The number of families in City X owning a computer in 1999 was 50 percent greater than it was in 1992, and the total number of families in City X was 5 percent greater in 1999 than it was in 1994. what percent of the families in City X owned a personal computer in 1999? Choose one
A) 43 % B) 42.85 % C) 45.25 % D) 46.23 % E) 41.66 % | <gadget id="calculator">50 + 100</gadget>
<output>150</output>
<gadget id="calculator">150 * 30</gadget>
<output>4_500</output>
<gadget id="calculator">4_500 / 100</gadget>
<output>45</output>
<gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">45 / 105</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">100 * (3/7)</gadget>
<output>300/7 = around 42.857143</output>
<result>B</result> | B | 42.85 | Of the families in City X in 1992, 30 percent owned a personal computer. The number of families in City X owning a computer in 1999 was 50 percent greater than it was in 1992, and the total number of families in City X was 5 percent greater in 1999 than it was in 1994. what percent of the families in City X owned a personal computer in 1999? | {
"A": "43 %",
"B": "42.85 %",
"C": "45.25 %",
"D": "46.23 %",
"E": "41.66 %"
} | multiply(const_100, divide(divide(multiply(add(50, const_100), 30), const_100), add(const_100, 5))) | add(n3,const_100)|add(n5,const_100)|multiply(n1,#0)|divide(#2,const_100)|divide(#3,#1)|multiply(#4,const_100)| | "say a 100 families existed in 1992 then the number of families owning a computer in 1992 - 30 number of families owning computer in 1999 = 30 * 150 / 100 = 45 number of families in 1999 = 105 the percentage = 45 / 105 * 100 = 42.85 % . answer : b" | general |
math_qa__tVKj0xzFbiJ9vMhq | Of the votes cast on a certain proposal, 70 more were in favor of the proposal than were against it. If the number of votes against the proposal was 40 percent of the total vote, what was the total number of votes cast? (Each vote cast was either in favor of the proposal or against it.) Choices: A) 350 B) 375 C) 400 D) 425 E) 450 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) - (2/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">70 / (1/5)</gadget>
<output>350</output>
<result>A</result> | A | 350 | Of the votes cast on a certain proposal, 70 more were in favor of the proposal than were against it. If the number of votes against the proposal was 40 percent of the total vote, what was the total number of votes cast? (Each vote cast was either in favor of the proposal or against it.) | {
"A": "350",
"B": "375",
"C": "400",
"D": "425",
"E": "450"
} | divide(70, subtract(subtract(const_1, divide(40, const_100)), divide(40, const_100))) | divide(n1,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n0,#2)| | "let x be the total number of votes cast . 0.6 x = 0.4 x + 70 0.2 x = 70 x = 350 the answer is a ." | gain |
math_qa__dyosqQxBUwPHb3S0 | A man can do a piece of work in 4 days, but with the help of his son he can do it in 3 days. In what time can the son do it alone ? Select the correct option:
A) 12 days
B) 6 days
C) 5 days
D) 4 days
E) none of these | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">12 / 1</gadget>
<output>12</output>
<result>A</result> | A | 12 | A man can do a piece of work in 4 days, but with the help of his son he can do it in 3 days. In what time can the son do it alone ? | {
"A": "12 days",
"B": "6 days",
"C": "5 days",
"D": "4 days",
"E": "none of these"
} | divide(multiply(4, 3), subtract(4, 3)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "explanation : in this type of question , where we have one person work and together work done . then we can easily get the other person work just by subtracting them . as son ' s one day work = ( 1 / 3 − 1 / 4 ) = ( 4 − 3 ) / 12 = 1 / 12 so son will do whole work in 12 days answer : a" | physics |
math_qa__xzIYC3NOOA6u7PEF | Beginning in Town A, Biker Bob rides his bike 10 miles west, 5 miles north, 5 miles east, and then 15 miles north, to Town B. How far apart are Town A and Town B? (Ignore the curvature of the earth.) Choose the correct choice from the following answers
A) 22 miles B) 20.62 miles C) 25 miles D) 26 miles E) 28 miles | <gadget id="calculator">5 + 15</gadget>
<output>20</output>
<gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">400 + 25</gadget>
<output>425</output>
<gadget id="calculator">425 ** (1/2)</gadget>
<output>5*sqrt(17) = around 20.615528</output>
<result>B</result> | B | 20.62 | Beginning in Town A, Biker Bob rides his bike 10 miles west, 5 miles north, 5 miles east, and then 15 miles north, to Town B. How far apart are Town A and Town B? (Ignore the curvature of the earth.) | {
"A": "22 miles",
"B": "20.62 miles",
"C": "25 miles",
"D": "26 miles",
"E": "28 miles"
} | sqrt(add(power(add(5, 15), const_2), power(5, const_2))) | add(n1,n3)|power(n2,const_2)|power(#0,const_2)|add(#2,#1)|sqrt(#3)| | "using pythagoras we have one side i , e total distance traveled in north direction = 15 + 5 = 20 m other being the base ie distance traveled west - distance traveled eat = 10 - 5 = 5 m now this third side or the distance between town a and town b = 20 ^ 2 + 5 ^ 2 = sq root 425 = 20.62 mile answer : b" | physics |
math_qa__TUdez28GuLCckUuE | A, B and C have Rs.400 between them, A and C together have Rs.300 and B and C Rs.150. How much does C have? Choose the correct choice from the following options:
A) 40 B) 50 C) 60 D) 70 E) 100 | <gadget id="calculator">300 + 150</gadget>
<output>450</output>
<gadget id="calculator">450 - 400</gadget>
<output>50</output>
<result>B</result> | B | 50 | A, B and C have Rs.400 between them, A and C together have Rs.300 and B and C Rs.150. How much does C have? | {
"A": "40",
"B": "50",
"C": "60",
"D": "70",
"E": "100"
} | subtract(add(300, 150), 400) | add(n1,n2)|subtract(#0,n0)| | "a + b + c = 400 a + c = 300 b + c = 150 - - - - - - - - - - - - - - a + b + 2 c = 450 a + b + c = 400 - - - - - - - - - - - - - - - - c = 50 answer : b" | general |
math_qa__AdUN0HNBvlZ89Lo7 | City X has a population 8 times as great as the population of City Y, which has a population twice as great as the population of City Z. What is the ratio of the population of City X to the population of City Z? Choose the correct choice from the following answers:
A) 1 : 8
B) 1 : 4
C) 2 : 1
D) 4 : 1
E) 16 : 1 | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<result>E</result> | E | 16 | City X has a population 8 times as great as the population of City Y, which has a population twice as great as the population of City Z. What is the ratio of the population of City X to the population of City Z? | {
"A": "1 : 8",
"B": "1 : 4",
"C": "2 : 1",
"D": "4 : 1",
"E": "16 : 1"
} | multiply(8, const_2) | multiply(n0,const_2)| | "x = 8 y , y = 2 * z x : y , y : z 8 : 1 , 2 : 1 16 : 2 , 2 : 1 so , x : z = 16 : 1 ( e )" | general |
math_qa__AJrysIurxqcYU5JY | In digging a pond 20 m * 10 m * 8 m the volumes of the soil extracted will be?
Choose the correct option: A) 3387 B) 1600 C) 2866 D) 2787 E) 1121 | <gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">200 * 8</gadget>
<output>1_600</output>
<result>B</result> | B | 1,600 | In digging a pond 20 m * 10 m * 8 m the volumes of the soil extracted will be? | {
"A": "3387",
"B": "1600",
"C": "2866",
"D": "2787",
"E": "1121"
} | multiply(multiply(20, 10), 8) | multiply(n0,n1)|multiply(n2,#0)| | "20 * 10 * 8 = 1600 answer : b" | general |
math_qa__faLCCPP6hBgOOD0W | A man took loan from a bank at the rate of 12% p.a. S.I. After 10 years he had to pay Rs. 1500 interest only for the period. The principal amount borrowed by him was? Select the correct option:
A) 1502 B) 1900 C) 1250 D) 1750 E) 2000 | <gadget id="calculator">1_500 * 100</gadget>
<output>150_000</output>
<gadget id="calculator">150_000 / 10</gadget>
<output>15_000</output>
<gadget id="calculator">15_000 / 12</gadget>
<output>1_250</output>
<result>C</result> | C | 1,250 | A man took loan from a bank at the rate of 12% p.a. S.I. After 10 years he had to pay Rs. 1500 interest only for the period. The principal amount borrowed by him was? | {
"A": "1502",
"B": "1900",
"C": "1250",
"D": "1750",
"E": "2000"
} | divide(divide(multiply(1500, const_100), 10), 12) | multiply(n2,const_100)|divide(#0,n1)|divide(#1,n0)| | "principal = ( 100 * 1500 ) / ( 12 * 10 ) = rs . 1250 answer : c" | gain |
math_qa__hy72MuWmWX0ShjZ6 | in a bus left side are 15 seats available,3 few seats in right side because in rear exit door .Each seat hold 3 people.In addition ,there is a seat back can sit 8 people all together .how many people can sit in a bus? Choose the most appropriate option: A) 52 B) 49 C) 95 D) 88 E) 89 | <gadget id="calculator">15 - 3</gadget>
<output>12</output>
<gadget id="calculator">15 + 12</gadget>
<output>27</output>
<gadget id="calculator">27 * 3</gadget>
<output>81</output>
<gadget id="calculator">81 + 8</gadget>
<output>89</output>
<result>E</result> | E | 89 | in a bus left side are 15 seats available,3 few seats in right side because in rear exit door .Each seat hold 3 people.In addition ,there is a seat back can sit 8 people all together .how many people can sit in a bus? | {
"A": "52",
"B": "49",
"C": "95",
"D": "88",
"E": "89"
} | add(multiply(add(15, subtract(15, 3)), 3), 8) | subtract(n0,n1)|add(n0,#0)|multiply(n1,#1)|add(n3,#2)| | "right side = 15 seat left side = 15 - 3 ( 3 few seat in right side ) = 12 seat total = 15 + 12 = 27 people can seat in 27 seat = 27 * 3 = 81 people can seat in last seat = 8 total people can seat = 81 + 8 = 89 answer : e" | general |
math_qa__dIvBjEqYy8fVXZPd | a computer wholesaler sells 10 different computers and each is priced differently . if the wholesaler chooses 3 computers for display at a trade show , what is the probability ( all things being equal ) that the two most expensive computers will be among the 3 chosen for display ? Answers: A) 15 / 56 B) 3 / 28 C) 1 / 28 D) 1 / 15 E) 1 / 168 | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/5) * (1/9)</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">3 * (1/45)</gadget>
<output>1/15 = around 0.066667</output>
<result>D</result> | D | 0.066667 | a computer wholesaler sells 10 different computers and each is priced differently . if the wholesaler chooses 3 computers for display at a trade show , what is the probability ( all things being equal ) that the two most expensive computers will be among the 3 chosen for display ? | {
"A": "15 / 56",
"B": "3 / 28",
"C": "1 / 28",
"D": "1 / 15",
"E": "1 / 168"
} | multiply(3, multiply(divide(subtract(3, const_1), 10), divide(const_1, subtract(10, const_1)))) | subtract(n1,const_1)|subtract(n0,const_1)|divide(#0,n0)|divide(const_1,#1)|multiply(#2,#3)|multiply(n1,#4) | since , two of the choices are prefixed , we are free to choose 1 from the rest of the 8 avilable . so 8 c 1 is the numerator . total no of ways we can choose 3 from 10 is 10 c 3 , which is the denominator . so , the probability : 8 c 1 / 10 c 3 = 1 / 15 ans is d . | general |
math_qa__k3iSq2MaRoRAp1Ic | how many internal diagonals does a octagon (eight sided polygon) have?
Choose one:
A) 90 B) 85 C) 70 D) 35 E) 20 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<result>E</result> | E | 20 | how many internal diagonals does a octagon (eight sided polygon) have? | {
"A": "90",
"B": "85",
"C": "70",
"D": "35",
"E": "20"
} | multiply(subtract(multiply(const_2, const_4), const_3), divide(multiply(const_2, const_4), const_2)) | multiply(const_2,const_4)|divide(#0,const_2)|subtract(#0,const_3)|multiply(#1,#2) | number of diagonals in any polygon can be found using this formula : n ( n - 3 ) / 2 here n = 8 no . of diagonals = 8 ( 8 - 3 ) / 2 = 20 ans e | geometry |
math_qa__zLLMnjdD1Ytt54vD | On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 17 more transactions than Cal. How much transactions did Jade handled? Answers.
A) 80 B) 81 C) 82 D) 83 E) 84 | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">10 + 100</gadget>
<output>110</output>
<gadget id="calculator">(9/10) * 110</gadget>
<output>99</output>
<gadget id="calculator">99 * 2</gadget>
<output>198</output>
<gadget id="calculator">198 / 3</gadget>
<output>66</output>
<gadget id="calculator">66 + 17</gadget>
<output>83</output>
<result>D</result> | D | 83 | On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 17 more transactions than Cal. How much transactions did Jade handled? | {
"A": "80",
"B": "81",
"C": "82",
"D": "83",
"E": "84"
} | add(divide(multiply(multiply(divide(90, const_100), add(10, const_100)), 2), 3), 17) | add(n1,const_100)|divide(n0,const_100)|multiply(#0,#1)|multiply(n2,#2)|divide(#3,n3)|add(n4,#4)| | "solution : mabel handled 90 transactions anthony handled 10 % more transactions than mabel anthony = 90 + 90 × 10 % = 90 + 90 × 0.10 = 90 + 9 = 99 cal handled 2 / 3 rds of the transactions than anthony handled cal = 2 / 3 × 99 = 66 jade handled 16 more transactions than cal . jade = 66 + 17 = 83 jade handled = 83 transactions . answer : d" | general |
math_qa__iXTVR2X1Yv7zbor9 | Among 600 students, 56% study sociology, 44% study mathematics and 40% study biology. If 30% of students study both mathematics and sociology, what is the largest possible number of students who study biology but do not study either mathematics or sociology? Select the correct option
A) 30 B) 90 C) 120 D) 172 E) 180 | <gadget id="calculator">600 / 100</gadget>
<output>6</output>
<gadget id="calculator">6 * 56</gadget>
<output>336</output>
<gadget id="calculator">6 * 44</gadget>
<output>264</output>
<gadget id="calculator">336 + 264</gadget>
<output>600</output>
<gadget id="calculator">6 * 30</gadget>
<output>180</output>
<gadget id="calculator">600 - 180</gadget>
<output>420</output>
<gadget id="calculator">600 - 420</gadget>
<output>180</output>
<result>E</result> | E | 180 | Among 600 students, 56% study sociology, 44% study mathematics and 40% study biology. If 30% of students study both mathematics and sociology, what is the largest possible number of students who study biology but do not study either mathematics or sociology? | {
"A": "30",
"B": "90",
"C": "120",
"D": "172",
"E": "180"
} | subtract(600, subtract(add(multiply(divide(600, const_100), 56), multiply(divide(600, const_100), 44)), multiply(divide(600, const_100), 30))) | divide(n0,const_100)|multiply(n1,#0)|multiply(n2,#0)|multiply(n4,#0)|add(#1,#2)|subtract(#4,#3)|subtract(n0,#5)| | "i would just like to add a bit of explanation after the step where you calculate that the number of students studying both m and s = 180 using your analysis : we see that the total number of students who study either maths or sociology = 264 + 336 - 180 = 420 so , in the image we know that the number of students in the zone with the black boundary = 420 let ' s assume the number of students who studyonlybiology to beb ( this is the number that we have to maximize ) and , let ' s assume the number of students who study none of the three subjects , that is the number of students in the white space = w since the total number of students = 600 , we can write : 420 + b + w = 600 or , b + w = 600 - 420 = 180 that is , b = 180 - w so , the maximum value ofbwill happen forw = 0 this is how we get , the maximum value ofb = 180 e" | other |
math_qa__GN4hP8UKfUFiJyQh | 15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 3 hrs. each would it take for 21 women if 3 women do as much work as 2 men? Choose the most appropriate option: A) 60 B) 20 C) 19 D) 29 E) 39 | <gadget id="calculator">15 * 21</gadget>
<output>315</output>
<gadget id="calculator">315 * 8</gadget>
<output>2_520</output>
<gadget id="calculator">21 * 3</gadget>
<output>63</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">63 * (2/3)</gadget>
<output>42</output>
<gadget id="calculator">2_520 / 42</gadget>
<output>60</output>
<result>A</result> | A | 60 | 15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 3 hrs. each would it take for 21 women if 3 women do as much work as 2 men? | {
"A": "60",
"B": "20",
"C": "19",
"D": "29",
"E": "39"
} | divide(multiply(multiply(15, 21), 8), multiply(multiply(21, 3), divide(2, 3))) | divide(n6,n5)|multiply(n0,n1)|multiply(n1,n3)|multiply(n2,#1)|multiply(#0,#2)|divide(#3,#4)| | "let 1 man does 1 unit / hr of work 15 m in 21 days of 8 hrs will do ( 15 * 21 * 8 ) units 3 w = 2 m 1 w = ( 2 / 3 ) units / hr 21 w with 3 hrs a day will take ( 15 * 21 * 8 ) / ( 21 * 3 * ( 2 / 3 ) ) days = > 60 days answer : a" | physics |
math_qa__l628WQHT8q3zGdeQ | If a tire rotates at 400 revolutions per minute when the car is traveling 72km/h, what is the circumference of the tire? Options.
A) 7 meters B) 9 meters C) 8 meters D) 5 meters E) 3 meters | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">60 * 400</gadget>
<output>24_000</output>
<gadget id="calculator">72 / 24_000</gadget>
<output>3/1_000 = around 0.003</output>
<gadget id="calculator">(3/1_000) * 1_000</gadget>
<output>3</output>
<result>E</result> | E | 3 | If a tire rotates at 400 revolutions per minute when the car is traveling 72km/h, what is the circumference of the tire? | {
"A": "7 meters",
"B": "9 meters",
"C": "8 meters",
"D": "5 meters",
"E": "3 meters"
} | multiply(divide(72, multiply(multiply(multiply(const_2, const_3), const_10), 400)), const_1000) | multiply(const_2,const_3)|multiply(#0,const_10)|multiply(n0,#1)|divide(n1,#2)|multiply(#3,const_1000)| | "400 rev / minute = 400 * 60 rev / 60 minutes = 24,000 rev / hour 24,000 * c = 72,000 m : c is the circumference c = 3 meters correct answer e" | physics |
math_qa__p5jLPjn44JtvbLS3 | The sum of number of boys and girls in a school is 900. If the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is? Choose the most appropriate option.
A) 50 B) 40 C) 60 D) 90 E) 70 | <gadget id="calculator">900 / 100</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">900 / 10</gadget>
<output>90</output>
<result>D</result> | D | 90 | The sum of number of boys and girls in a school is 900. If the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is? | {
"A": "50",
"B": "40",
"C": "60",
"D": "90",
"E": "70"
} | divide(900, add(divide(900, const_100), const_1)) | divide(n0,const_100)|add(#0,const_1)|divide(n0,#1) | we have x + x % of 900 = 900 x + x / 100 * 900 = 900 10 * x = 900 x = 90 answer is d | general |
math_qa__Fif8sW9o2Gcp56HS | One half of a two digit number exceeds its one fourth by 3. What is the sum of the digits of the number? Pick one:
A) 3 B) 9 C) 11 D) 12 E) 15 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 % 10</gadget>
<output>2</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<result>A</result> | A | 3 | One half of a two digit number exceeds its one fourth by 3. What is the sum of the digits of the number? | {
"A": "3",
"B": "9",
"C": "11",
"D": "12",
"E": "15"
} | add(reminder(multiply(3, const_4), const_10), const_1) | multiply(n0,const_4)|reminder(#0,const_10)|add(#1,const_1) | explanation : x / 2 – x / 4 = 3 = > x = 12 1 + 2 = 3 a | general |
math_qa__56rn93JRkyKyNR2a | A student chose a number, multiplied it by 2, then subtracted 200 from the result and got 110. What was the number he chose?
Select the correct option
A) 168 B) 100 C) 155 D) 160 E) 200 | <gadget id="calculator">110 + 200</gadget>
<output>310</output>
<gadget id="calculator">310 / 2</gadget>
<output>155</output>
<result>C</result> | C | 155 | A student chose a number, multiplied it by 2, then subtracted 200 from the result and got 110. What was the number he chose? | {
"A": "168",
"B": "100",
"C": "155",
"D": "160",
"E": "200"
} | divide(add(110, 200), 2) | add(n1,n2)|divide(#0,n0)| | "solution : let x be the number he chose , then 2 * x * 200 = 110 2 x = 310 x = 155 correct answer c" | general |
math_qa__FhiW9n6Kn4F3PGnO | The average expenditure of a labourer for 6 months was 90 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income i
Pick.
A) 70 B) 72 C) 75 D) 78 E) 81 | <gadget id="calculator">90 * 6</gadget>
<output>540</output>
<gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">540 + 240</gadget>
<output>780</output>
<gadget id="calculator">780 + 30</gadget>
<output>810</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">810 / 10</gadget>
<output>81</output>
<result>E</result> | E | 81 | The average expenditure of a labourer for 6 months was 90 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income i | {
"A": "70",
"B": "72",
"C": "75",
"D": "78",
"E": "81"
} | divide(add(add(multiply(90, 6), multiply(60, 4)), 30), add(6, 4)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|add(n4,#3)|divide(#4,#0) | income of 6 months = ( 6 × 90 ) – debt = 540 – debt income of the man for next 4 months = 4 × 60 + debt + 30 = 270 + debt ∴ income of 10 months = 810 average monthly income = 810 ÷ 10 = 81 answer e | general |
math_qa__Paq5IbLQgJCt7JTz | The length of rectangle is thrice its breadth and its perimeter is 48 m, find the area of the rectangle?
Answers.
A) 432
B) 108
C) 252
D) 992
E) 212 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 * 6</gadget>
<output>108</output>
<result>B</result> | B | 108 | The length of rectangle is thrice its breadth and its perimeter is 48 m, find the area of the rectangle? | {
"A": "432",
"B": "108",
"C": "252",
"D": "992",
"E": "212"
} | multiply(multiply(divide(48, add(multiply(const_3, const_2), multiply(const_1, const_2))), const_3), divide(48, add(multiply(const_3, const_2), multiply(const_1, const_2)))) | multiply(const_2,const_3)|multiply(const_1,const_2)|add(#0,#1)|divide(n0,#2)|multiply(#3,const_3)|multiply(#3,#4)| | "2 ( 3 x + x ) = 48 l = 18 b = 6 lb = 18 * 6 = 108 answer : b" | geometry |
math_qa__tQUIbfMNzifi1sHS | Find the value of (√1.1)/(√0.81) + (√1.44)/(√0.49) is Choose one.
A) 195 / 63 B) 2.879 C) 155 / 63 D) 125 / 63 E) 185 / 63 | <gadget id="calculator">1.1 ** (1/2)</gadget>
<output>1.048809</output>
<gadget id="calculator">0.81 ** (1/2)</gadget>
<output>0.9</output>
<gadget id="calculator">1.048809 / 0.9</gadget>
<output>1.165343</output>
<gadget id="calculator">1.44 ** (1/2)</gadget>
<output>1.2</output>
<gadget id="calculator">0.49 ** (1/2)</gadget>
<output>0.7</output>
<gadget id="calculator">1.2 / 0.7</gadget>
<output>1.714286</output>
<gadget id="calculator">1.165343 + 1.714286</gadget>
<output>2.879629</output>
<result>B</result> | B | 2.879 | Find the value of (√1.1)/(√0.81) + (√1.44)/(√0.49) is | {
"A": "195 / 63",
"B": "2.879",
"C": "155 / 63",
"D": "125 / 63",
"E": "185 / 63"
} | add(divide(sqrt(1.1), sqrt(0.81)), divide(sqrt(1.44), sqrt(0.49))) | sqrt(n0)|sqrt(n1)|sqrt(n2)|sqrt(n3)|divide(#0,#1)|divide(#2,#3)|add(#4,#5)| | "( √ 1.1 ) / ( √ 0.81 ) + ( √ 1.44 ) / ( √ 0.49 ) = > 2.879 answer is b" | general |
math_qa__4oUXIkNJAXLQQ1ga | If x^2 + y^2 = 15 and xy = 3, then (x − y)^2 = Pick one:
A) 8 B) 9 C) 14 D) 17 E) 20 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<result>B</result> | B | 9 | If x^2 + y^2 = 15 and xy = 3, then (x − y)^2 = | {
"A": "8",
"B": "9",
"C": "14",
"D": "17",
"E": "20"
} | power(3, 2) | power(n3,n0) | but you can not take xy + 3 to mean xy = - 3 . . only if xy + 3 = 0 , it will mean xy = - 3 . . rest your solution is perfect and you will get your correct answer as 15 - 2 * 3 = 9 . . answer b | general |
math_qa__Q9ey9D0tsjksRi4K | The perimeter of a triangle is 48 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle? Choose the correct answer: A) 76 B) 88 C) 60 D) 55 E) 35 | <gadget id="calculator">(2.5 * 48) / 2</gadget>
<output>60</output>
<result>C</result> | C | 60 | The perimeter of a triangle is 48 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle? | {
"A": "76",
"B": "88",
"C": "60",
"D": "55",
"E": "35"
} | triangle_area(2.5, 48) | triangle_area(n0,n1)| | "area of a triangle = r * s where r is the in radius and s is the semi perimeter of the triangle . area of triangle = 2.5 * 48 / 2 = 60 cm 2 answer : c" | geometry |
math_qa__FjaCblEWh1Ek0pxE | If H = {1, 7, 18, 20, 29, 33}, how much less is the mean of the numbers in H than the median of the numbers in H? Choose the correct answer
A) 1.0 B) 1.5 C) 2.0 D) 2.5 E) 3.0 | <gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">8 + 20</gadget>
<output>28</output>
<gadget id="calculator">29 - 28</gadget>
<output>1</output>
<result>A</result> | A | 1 | If H = {1, 7, 18, 20, 29, 33}, how much less is the mean of the numbers in H than the median of the numbers in H? | {
"A": "1.0",
"B": "1.5",
"C": "2.0",
"D": "2.5",
"E": "3.0"
} | subtract(29, add(add(7, 1), 20)) | add(n0,n1)|add(n3,#0)|subtract(n4,#1) | this is a good question to understand the difference between mean and median . mean : average of all the numbers . ( sum of all the elements divided by the number of elements ) median : arrange the elements of the set in increasing order . if the number of terms is odd , the middle term is the median . if the number of terms is even , the average of middle two terms is the median coming to this question , mean = ( 1 + 7 + 18 + 20 + 29 + 33 ) / 6 = 18 median = ( 18 + 20 ) / 2 = 19 difference = 1 option a | general |
math_qa__AEKBuGueBqr4gLxe | What will be the cost of house to paint which area equal to 484 sq ft, if the price per foot of building is Rs. 20
Choose the correct option
A) 1800 B) 1760 C) 1400 D) 2600 E) 3600 | <gadget id="calculator">484 ** (1/2)</gadget>
<output>22</output>
<gadget id="calculator">22 * 4</gadget>
<output>88</output>
<gadget id="calculator">88 * 20</gadget>
<output>1_760</output>
<result>B</result> | B | 1,760 | What will be the cost of house to paint which area equal to 484 sq ft, if the price per foot of building is Rs. 20 | {
"A": "1800",
"B": "1760",
"C": "1400",
"D": "2600",
"E": "3600"
} | multiply(multiply(sqrt(484), const_4), 20) | sqrt(n0)|multiply(#0,const_4)|multiply(n1,#1) | let the side of the square plot be a ft . a 2 = 484 = > a = 22 length of the fence = perimeter of the plot = 4 a = 88 ft . cost of building the fence = 88 * 20 = rs . 1760 . answer : b | geometry |
math_qa__cTtnTyxFiHAX2pqM | x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to?
Choose the correct choice from the following choices
A) 1 / 6 B) 1 / 3 C) 1 / 0 D) 1 / 9 E) 1 / 5 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">1 * 4</gadget>
<output>4</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">4 / 36</gadget>
<output>1/9 = around 0.111111</output>
<result>D</result> | D | 0.111111 | x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to? | {
"A": "1 / 6",
"B": "1 / 3",
"C": "1 / 0",
"D": "1 / 9",
"E": "1 / 5"
} | divide(multiply(1, power(2, const_2)), power(6, const_2)) | power(n0,const_2)|power(n2,const_2)|multiply(n1,#0)|divide(#2,#1)| | "given x = k / y 2 , where k is a constant . now , y = 2 and x = 1 gives k = 4 . x = 4 / y 2 = > x = 4 / 62 , when y = 6 = > x = 4 / 36 = 1 / 9 . answer : d" | general |
math_qa__TnZ05KdrVJpk0ozN | Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability R that Jane will be on the same committee as Albert? Choose the most appropriate option
A) 12 % B) 20 % C) 33 % D) 40 % E) 50 % | <gadget id="calculator">binomial(4, 1)</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">binomial(6, 3)</gadget>
<output>20</output>
<gadget id="calculator">8 / 20</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 4</gadget>
<output>100</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>D</result> | D | 40 | Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability R that Jane will be on the same committee as Albert? | {
"A": "12 %",
"B": "20 %",
"C": "33 %",
"D": "40 %",
"E": "50 %"
} | multiply(divide(multiply(choose(const_4, const_1), const_2), choose(6, 3)), multiply(multiply(const_5, const_5), const_4)) | choose(const_4,const_1)|choose(n0,n1)|multiply(const_5,const_5)|multiply(#0,const_2)|multiply(#2,const_4)|divide(#3,#1)|multiply(#5,#4)| | "total number of ways to choose 3 member committee - 6 c 3 = ( 6 ! / 3 ! 3 ! ) = 20 no . of ways albert n jane are in same committee : - ( 4 c 1 * 2 ) = 8 probability r = ( 8 / 20 ) * 100 = 40 % . + 1 for me . . : d" | probability |
math_qa__gg4CgunzYnpl2pff | There are, in a certain league, 50 teams, and each team face another team for a total of 4 times. How many games are played in the season?
Pick one
A) 6660 B) 3600 C) 2400 D) 4900 E) 5400 | <gadget id="calculator">50 - 1</gadget>
<output>49</output>
<gadget id="calculator">49 * 4</gadget>
<output>196</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">196 * 25</gadget>
<output>4_900</output>
<result>D</result> | D | 4,900 | There are, in a certain league, 50 teams, and each team face another team for a total of 4 times. How many games are played in the season? | {
"A": "6660",
"B": "3600",
"C": "2400",
"D": "4900",
"E": "5400"
} | multiply(multiply(subtract(50, const_1), const_4), divide(50, const_2)) | divide(n0,const_2)|subtract(n0,const_1)|multiply(#1,const_4)|multiply(#0,#2) | by using the formula , t [ n ( n - 1 ) / 2 ] , where t = no . of games between two teams and n = total no . of teams , we get : 4900 option d . | general |
math_qa__JEQkPzwo0S1ZfBUU | A cycle is bought for Rs.1000 and sold for Rs.2000, find the gain percent? Choose one: A) 11 B) 20 C) 100 D) 77 E) 12 | <gadget id="calculator">2_000 - 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 1_000</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>C</result> | C | 100 | A cycle is bought for Rs.1000 and sold for Rs.2000, find the gain percent? | {
"A": "11",
"B": "20",
"C": "100",
"D": "77",
"E": "12"
} | multiply(divide(subtract(2000, 1000), 1000), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "1000 - - - - 1000 100 - - - - ? = > 100 % answer : c" | gain |
math_qa__dhCBPmHocUGpX3DS | A 360 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 520 m in ?
Choose the most appropriate option
A) 57.6 sec
B) 20.2 sec
C) 31.8 sec
D) 50.4 sec
E) none of the above | <gadget id="calculator">360 + 520</gadget>
<output>880</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">55 * (5/18)</gadget>
<output>275/18 = around 15.277778</output>
<gadget id="calculator">880 / (275/18)</gadget>
<output>288/5 = around 57.6</output>
<result>A</result> | A | 57.6 | A 360 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 520 m in ? | {
"A": "57.6 sec",
"B": "20.2 sec",
"C": "31.8 sec",
"D": "50.4 sec",
"E": "none of the above"
} | divide(add(360, 520), multiply(55, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 55 km / hr ( to convert km / hr in to m / s ) = 55 x 5 / 18 m / s distance = 360 m + 520 m ( if questions is about train crossing a post you need to consider only the length of train , ) = 880 m time = distance / speed = 880 x 18 / ( 5 x 55 ) = 57.6 sec ans is : a" | physics |
math_qa__ijRJRxDwaJVCAomV | 5 x 1.6 - 2 x 1.4/1.3 = ? Choose the correct answer: A) 3 B) 0 C) 5 D) 4 E) 2 | <gadget id="calculator">5 * 1.6</gadget>
<output>8</output>
<gadget id="calculator">2 * 1.4</gadget>
<output>2.8</output>
<gadget id="calculator">8 - 2.8</gadget>
<output>5.2</output>
<gadget id="calculator">5.2 / 1.3</gadget>
<output>4</output>
<result>D</result> | D | 4 | 5 x 1.6 - 2 x 1.4/1.3 = ? | {
"A": "3",
"B": "0",
"C": "5",
"D": "4",
"E": "2"
} | divide(subtract(multiply(5, 1.6), multiply(2, 1.4)), 1.3) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)|divide(#2,n4)| | "given expression = ( 8 - 2.8 ) / 1.3 = 5.2 / 1.3 = 52 / 1.3 = 4 . answer is d ." | general |
math_qa__S90wzvcVWA36Lv9T | The speed of a car is 98 km in the first hour and 70 km in the second hour. What is the average speed of the car?
Choose the correct choice from the following answers
A) 76 kmph
B) 75 kmph
C) 87 kmph
D) 56 kmph
E) 84 kmph | <gadget id="calculator">98 + 70</gadget>
<output>168</output>
<gadget id="calculator">168 / 2</gadget>
<output>84</output>
<result>E</result> | E | 84 | The speed of a car is 98 km in the first hour and 70 km in the second hour. What is the average speed of the car? | {
"A": "76 kmph",
"B": "75 kmph",
"C": "87 kmph",
"D": "56 kmph",
"E": "84 kmph"
} | divide(add(98, 70), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 98 + 70 ) / 2 = 84 kmph answer : e" | physics |
math_qa__WmICJddiSFgWkqFh | 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 10 days, working 12 hours a day, the number of men required? Choices:
A) 10 days B) 9 days C) 6 days D) 8 days E) 7 days | <gadget id="calculator">12 * 10</gadget>
<output>120</output>
<gadget id="calculator">120 * 8</gadget>
<output>960</output>
<gadget id="calculator">10 * 12</gadget>
<output>120</output>
<gadget id="calculator">960 / 120</gadget>
<output>8</output>
<result>D</result> | D | 8 | 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 10 days, working 12 hours a day, the number of men required? | {
"A": "10 days",
"B": "9 days",
"C": "6 days",
"D": "8 days",
"E": "7 days"
} | divide(multiply(multiply(12, 10), 8), multiply(10, 12)) | multiply(n0,n2)|multiply(n3,n4)|multiply(n1,#0)|divide(#2,#1)| | "that is , 1 work done = 12 × 8 × 10 then , 12 8 × 10 = ? × 12 × 10 ? ( i . e . no . of men required ) = 12 × 8 × 10 / 12 × 10 = 8 days d )" | physics |
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