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stringlengths 7
6.48k
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math_qa__PCIsgybYzXwtwXyQ | In the xy-plane, the point (2, 1) is the center of a circle. The point (-2, 1) lies inside the circle and the point (2, -5) lies outside the circle. If the radius r of the circle is an integer, then r =
Choose the most appropriate option.
A) 6 B) 5 C) 4 D) 3 E) 2 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<result>B</result> | B | 5 | In the xy-plane, the point (2, 1) is the center of a circle. The point (-2, 1) lies inside the circle and the point (2, -5) lies outside the circle. If the radius r of the circle is an integer, then r = | {
"A": "6",
"B": "5",
"C": "4",
"D": "3",
"E": "2"
} | add(add(2, 2), 1) | add(n0,n0)|add(n1,#0) | an easy way to solve this question will be just to mark the points on the coordinate plane . you ' ll see that the distance between the center ( 2 , 1 ) and the point inside the circle ( - 2 , 1 ) is 4 units ( both points are on y = 1 line so the distance will simply be 2 - ( - 2 ) = 4 ) so the radius must be more than 4 units . the distance between the center ( 2,1 ) and the point outside the circle ( 2 , - 5 ) is 6 units ( both points are on x = 2 line so the distance will simply be 1 - ( - 5 ) = 6 ) so the radius must be less than 6 units , which implies 4 < r < 6 , thus as r is an integer then r = 5 . answer : b . | general |
math_qa__HAg9VfTHaLVG6Wr5 | If k is the greatest positive integer such that 4^k is a divisor of 16! then k = Pick:
A) 3
B) 4
C) 5
D) 6
E) 7 | <gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<result>C</result> | C | 5 | If k is the greatest positive integer such that 4^k is a divisor of 16! then k = | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | add(const_1, divide(16, 4)) | divide(n1,n0)|add(#0,const_1)| | "16 / 4 = 4 16 / 16 = 1 4 + 1 = 5 k = 5 answer : c" | general |
math_qa__b7F7wVJWhZKohG0E | Johnny makes $8.25 per hour at his work. If he works 2 hours, how much money will he earn?
Answers: A) $ 30.50 B) $ 16.50 C) $ 28.50 D) $ 12 E) $ 9.60 | <gadget id="calculator">8.25 * 2</gadget>
<output>16.5</output>
<result>B</result> | B | 16.5 | Johnny makes $8.25 per hour at his work. If he works 2 hours, how much money will he earn? | {
"A": "$ 30.50",
"B": "$ 16.50",
"C": "$ 28.50",
"D": "$ 12",
"E": "$ 9.60"
} | multiply(8.25, 2) | multiply(n0,n1) | 8.25 * 2 = 16.50 . answer is b . | physics |
math_qa__xSz9E88QdZJd2Jcc | The difference between the value of a number increased by 12.5% and the value of the original number decreased by 25% is 30. What is the original number T? Pick one.
A) 60 B) 80 C) 40 D) 120 E) 160 | <gadget id="calculator">12.5 / 100</gadget>
<output>0.125</output>
<gadget id="calculator">1 + 0.125</gadget>
<output>1.125</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1.125 - (3/4)</gadget>
<output>0.375</output>
<gadget id="calculator">30 / 0.375</gadget>
<output>80</output>
<result>B</result> | B | 80 | The difference between the value of a number increased by 12.5% and the value of the original number decreased by 25% is 30. What is the original number T? | {
"A": "60",
"B": "80",
"C": "40",
"D": "120",
"E": "160"
} | divide(30, subtract(add(const_1, divide(12.5, const_100)), subtract(const_1, divide(25, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|subtract(#2,#3)|divide(n2,#4)| | "( 1 + 1 / 8 ) x - ( 1 - 1 / 4 ) x = 30 ( 9 / 8 ) x - ( 3 / 4 ) x = 30 x = 80 = t answer : b" | general |
math_qa__W8dzOGjJ9LjBLiP0 | Evaluate: |4 - 8(3 - 12)| - |5 - 11| = ?
Choices.
A) 40
B) 50
C) 60
D) 70
E) 80 | <gadget id="calculator">3 - 12</gadget>
<output>-9</output>
<gadget id="calculator">8 * (-9)</gadget>
<output>-72</output>
<gadget id="calculator">4 - (-72)</gadget>
<output>76</output>
<gadget id="calculator">5 - 11</gadget>
<output>-6</output>
<gadget id="calculator">-(-6)</gadget>
<output>6</output>
<gadget id="calculator">76 - 6</gadget>
<output>70</output>
<result>D</result> | D | 70 | Evaluate: |4 - 8(3 - 12)| - |5 - 11| = ? | {
"A": "40",
"B": "50",
"C": "60",
"D": "70",
"E": "80"
} | subtract(subtract(4, multiply(8, subtract(3, 12))), negate(subtract(5, 11))) | subtract(n2,n3)|subtract(n4,n5)|multiply(n1,#0)|negate(#1)|subtract(n0,#2)|subtract(#4,#3)| | "according to order of operations , inner brackets first . hence | 4 - 8 ( 3 - 12 ) | - | 5 - 11 | = | 4 - 8 * ( - 9 ) | - | 5 - 11 | according to order of operations , multiplication within absolute value signs ( which may be considered as brackets when it comes to order of operations ) next . hence = | 4 + 72 | - | 5 - 11 | = | 76 | - | - 6 | = 76 - 6 = 70 correct answer d ) 70" | general |
math_qa__v5LgbOEWNHmjZ4pO | In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes? Choose the correct choice from the following options:
A) 430 B) 438 C) 436 D) 434 E) 422 | <gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">172 / (2/5)</gadget>
<output>430</output>
<result>A</result> | A | 430 | In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes? | {
"A": "430",
"B": "438",
"C": "436",
"D": "434",
"E": "422"
} | divide(172, divide(subtract(70, subtract(const_100, 70)), const_100)) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)| | "let the total number of valid votes be x . 70 % of x = 70 / 100 * x = 7 x / 10 number of votes secured by the other candidate = x - 7 x / 100 = 3 x / 10 given , 7 x / 10 - 3 x / 10 = 172 = > 4 x / 10 = 172 = > 4 x = 1720 = > x = 430 . answer : a" | gain |
math_qa__3fVEFxpkmTwFtMhw | 12 buckets of water fill a tank when the capacity of each bucket is 55 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 5 litres? Select:
A) 142
B) 130
C) 132
D) 123
E) 120 | <gadget id="calculator">55 * 12</gadget>
<output>660</output>
<gadget id="calculator">660 / 5</gadget>
<output>132</output>
<result>C</result> | C | 132 | 12 buckets of water fill a tank when the capacity of each bucket is 55 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 5 litres? | {
"A": "142",
"B": "130",
"C": "132",
"D": "123",
"E": "120"
} | divide(multiply(55, 12), 5) | multiply(n0,n1)|divide(#0,n2)| | "capacity of the tank = ( 12 ã — 55 ) litre number of buckets required of capacity of each bucket is 17 litre = 12 ã — 55 / 5 = 12 ã — 11 = 132 answer is c" | physics |
math_qa__nJV8M7KM5KqsoS4y | A watch was sold at a loss of 46%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? Choose the correct choice from the following options: A) 280 B) 288 C) 279 D) 277 E) 290 | <gadget id="calculator">140 * 100</gadget>
<output>14_000</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 - 46</gadget>
<output>54</output>
<gadget id="calculator">104 - 54</gadget>
<output>50</output>
<gadget id="calculator">14_000 / 50</gadget>
<output>280</output>
<result>A</result> | A | 280 | A watch was sold at a loss of 46%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? | {
"A": "280",
"B": "288",
"C": "279",
"D": "277",
"E": "290"
} | divide(multiply(140, const_100), subtract(add(const_100, 4), subtract(const_100, 46))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "54 % 104 % - - - - - - - - 50 % - - - - 140 100 % - - - - ? = > rs . 280 answer : a" | gain |
math_qa__7yBzLceSswctxC7M | (168% of 1265) ÷ 6 = ? Choose the correct choice from the following answers:
A) 354 B) 175 C) 225 D) 375 E) 524 | <gadget id="calculator">168 / 100</gadget>
<output>42/25 = around 1.68</output>
<gadget id="calculator">(42/25) * 1_265</gadget>
<output>10_626/5 = around 2_125.2</output>
<gadget id="calculator">(10_626/5) / 6</gadget>
<output>1_771/5 = around 354.2</output>
<result>A</result> | A | 354 | (168% of 1265) ÷ 6 = ? | {
"A": "354",
"B": "175",
"C": "225",
"D": "375",
"E": "524"
} | divide(multiply(divide(168, const_100), 1265), 6) | divide(n0,const_100)|multiply(n1,#0)|divide(#1,n2)| | "explanation : ? = ( 168 x 1265 / 100 ) ÷ 6 = 212520 / 600 = 354 answer : option a" | general |
math_qa__5BWKIpfVm46r1Cyx | There are 15 teams in the hockey league, and each team faces all the other teams 10 times each. How many games are played in the season? Choices: A) 650 B) 750 C) 850 D) 950 E) 1050 | <gadget id="calculator">15 - 1</gadget>
<output>14</output>
<gadget id="calculator">15 * 14</gadget>
<output>210</output>
<gadget id="calculator">210 * 10</gadget>
<output>2_100</output>
<gadget id="calculator">2_100 / 2</gadget>
<output>1_050</output>
<result>E</result> | E | 1,050 | There are 15 teams in the hockey league, and each team faces all the other teams 10 times each. How many games are played in the season? | {
"A": "650",
"B": "750",
"C": "850",
"D": "950",
"E": "1050"
} | divide(multiply(multiply(15, subtract(15, const_1)), 10), const_2) | subtract(n0,const_1)|multiply(n0,#0)|multiply(n1,#1)|divide(#2,const_2)| | "the number of ways to choose two teams is 15 c 2 = 15 * 14 / 2 = 105 the total number of games in the season is 10 * 105 = 1050 . the answer is e ." | general |
math_qa__GPUknUkRmFL5VWZY | If 3 : 12 :: x : 16, then find the value of x Choose the most appropriate option:
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">36 + 12</gadget>
<output>48</output>
<gadget id="calculator">48 / 16</gadget>
<output>3</output>
<result>B</result> | B | 3 | If 3 : 12 :: x : 16, then find the value of x | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(add(multiply(12, 3), 12), 16) | multiply(n0,n1)|add(n1,#0)|divide(#1,n2) | explanation : treat 3 : 12 as 3 / 12 and x : 16 as x / 16 , treat : : as = so we get 3 / 12 = x / 16 = > 12 x = 48 = > x = 4 option b | general |
math_qa__lFirfWsI9JOVXqZf | John can complete a given task in 20 days. Jane will take only 12 days to complete the same task. John and Jane set out to complete the task by beginning to work together. However, Jane was indisposed 4 days before the work got over. In how many days did the work get over from the time John and Jane started to work on it together? Select the correct option:
A) 6
B) 10
C) 8
D) 7.5
E) 3.5 | <gadget id="calculator">20 * 12</gadget>
<output>240</output>
<gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">240 - 48</gadget>
<output>192</output>
<gadget id="calculator">12 + 20</gadget>
<output>32</output>
<gadget id="calculator">192 / 32</gadget>
<output>6</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<result>B</result> | B | 10 | John can complete a given task in 20 days. Jane will take only 12 days to complete the same task. John and Jane set out to complete the task by beginning to work together. However, Jane was indisposed 4 days before the work got over. In how many days did the work get over from the time John and Jane started to work on it together? | {
"A": "6",
"B": "10",
"C": "8",
"D": "7.5",
"E": "3.5"
} | add(4, divide(subtract(multiply(20, 12), multiply(12, 4)), add(12, 20))) | add(n0,n1)|multiply(n0,n1)|multiply(n1,n2)|subtract(#1,#2)|divide(#3,#0)|add(n2,#4)| | "john 6 * 20 = 120 jane 10 * 12 = 120 in 4 days working alone john did : 4 days * rate = 4 * 6 = 24 , so working together they did 120 - 24 = 96 - - > rate ( a + b ) * t = 96 - > 16 * t = 96 , t = 6 . hence the answer is b ( john worked 4 days + 6 days they worked together = 10 days )" | physics |
math_qa__FHI4KcSTMk2Ri70K | In Cliff’s impressive rock collection, there are half as many igneous rocks as sedimentary rocks. Of the igneous rocks, 1/3 are shiny and the rest are matte, while 1/5 of the sedimentary rocks are shiny. If there are 30 shiny igneous rocks, how many total rocks does Cliff have? Choose the correct option
A) 30 B) 45 C) 270 D) 90 E) 135 | <gadget id="calculator">1 * 3</gadget>
<output>3</output>
<gadget id="calculator">3 * 30</gadget>
<output>90</output>
<gadget id="calculator">90 / 1</gadget>
<output>90</output>
<gadget id="calculator">90 * 3</gadget>
<output>270</output>
<gadget id="calculator">270 / 1</gadget>
<output>270</output>
<result>C</result> | C | 270 | In Cliff’s impressive rock collection, there are half as many igneous rocks as sedimentary rocks. Of the igneous rocks, 1/3 are shiny and the rest are matte, while 1/5 of the sedimentary rocks are shiny. If there are 30 shiny igneous rocks, how many total rocks does Cliff have? | {
"A": "30",
"B": "45",
"C": "270",
"D": "90",
"E": "135"
} | divide(multiply(divide(multiply(multiply(1, 3), 30), 1), 3), 1) | multiply(n0,n1)|multiply(n4,#0)|divide(#1,n0)|multiply(n1,#2)|divide(#3,n0)| | "we can start with the known quantity and then go on to find the others . shiny igneous ricks are 30 . these are ( 1 / 3 ) of total igneous rocks . ( 1 / 3 ) * total igneous rocks = 30 total igneous rocks = 30 * ( 3 ) = 90 total sedimentary rocks = 2 * total igneous rocks = 2 * 90 = 180 total number of rocks = 90 + 180 = 270 answer ( c )" | general |
math_qa__Mq7equkw0CGvQFNz | At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 5/6 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? Select the correct option:
A) 4 / 7 B) 5 / 9 C) 6 / 11 D) 7 / 12 E) 8 / 13 | <gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">24 + 15</gadget>
<output>39</output>
<gadget id="calculator">24 / 39</gadget>
<output>8/13 = around 0.615385</output>
<result>E</result> | E | 0.615385 | At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 5/6 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? | {
"A": "4 / 7",
"B": "5 / 9",
"C": "6 / 11",
"D": "7 / 12",
"E": "8 / 13"
} | divide(multiply(6, 4), add(multiply(6, 4), multiply(3, 5))) | multiply(n1,n3)|multiply(n0,n2)|add(#0,#1)|divide(#0,#2)| | "let x be the number of workers on the day crew . let y be the number of boxes loaded by each member of the day crew . then the number of boxes loaded by the day crew is xy . the number of boxes loaded by the night crew is ( 5 x / 6 ) ( 3 y / 4 ) = 5 xy / 8 the total number of boxes is xy + 5 xy / 8 = 13 xy / 8 the fraction loaded by the day crew is xy / ( 13 xy / 8 ) = 8 / 13 the answer is e ." | physics |
math_qa__8LisYQig4AsL1kZt | A man has some hens and cows. If the number of heads be 50 and the number of feet equals 140, then the number of hens will be:
Choose the most appropriate option
A) 22
B) 23
C) 24
D) 30
E) 28 | <gadget id="calculator">50 * 4</gadget>
<output>200</output>
<gadget id="calculator">200 - 140</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>D</result> | D | 30 | A man has some hens and cows. If the number of heads be 50 and the number of feet equals 140, then the number of hens will be: | {
"A": "22",
"B": "23",
"C": "24",
"D": "30",
"E": "28"
} | divide(subtract(multiply(50, const_4), 140), const_2) | multiply(n0,const_4)|subtract(#0,n1)|divide(#1,const_2)| | "let hens be x and cows be y now , feet : x * 2 + y * 4 = 140 heads : x * 1 + y * 1 = 50 implies , 2 x + 4 y = 140 and x + y = 50 solving these two equations , we get x = 30 and y = 20 therefore , hens are 26 . answer : d" | general |
math_qa__xe0bsxL1A4hvBWWQ | The average speed of a car decreased by 3 miles per hour every successive 8-minutes interval. If the car traveled 4.4 miles in the fifth 8-minute interval, what was the average speed of the car, in miles per hour, in the first 8 minute interval? Choose the correct choice from the following:
A) 45 B) 48 C) 51 D) 54 E) 57 | <gadget id="calculator">8 / 60</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">4.4 / (2/15)</gadget>
<output>33</output>
<gadget id="calculator">33 + 3</gadget>
<output>36</output>
<gadget id="calculator">36 + 3</gadget>
<output>39</output>
<gadget id="calculator">39 + 3</gadget>
<output>42</output>
<gadget id="calculator">42 + 3</gadget>
<output>45</output>
<result>A</result> | A | 45 | The average speed of a car decreased by 3 miles per hour every successive 8-minutes interval. If the car traveled 4.4 miles in the fifth 8-minute interval, what was the average speed of the car, in miles per hour, in the first 8 minute interval? | {
"A": "45",
"B": "48",
"C": "51",
"D": "54",
"E": "57"
} | add(add(add(add(divide(4.4, divide(8, const_60)), 3), 3), 3), 3) | divide(n1,const_60)|divide(n2,#0)|add(n0,#1)|add(n0,#2)|add(n0,#3)|add(n0,#4)| | "( 4.4 miles / 8 minutes ) * 60 minutes / hour = 33 mph let x be the original speed . x - 4 ( 3 ) = 33 x = 45 mph the answer is a ." | physics |
math_qa__NyL7hmsDZcbsO7cx | A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 9%. What was its profit on the items sold in February? Answers.
A) 27.5 % B) 30 % C) 35 % D) 36.5 % E) 40 % | <gadget id="calculator">100 - 9</gadget>
<output>91</output>
<gadget id="calculator">91 / 100</gadget>
<output>91/100 = around 0.91</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">120 * (5/4)</gadget>
<output>150</output>
<gadget id="calculator">(91/100) * 150</gadget>
<output>273/2 = around 136.5</output>
<gadget id="calculator">(273/2) - 100</gadget>
<output>73/2 = around 36.5</output>
<result>D</result> | D | 36.5 | A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 9%. What was its profit on the items sold in February? | {
"A": "27.5 %",
"B": "30 %",
"C": "35 %",
"D": "36.5 %",
"E": "40 %"
} | subtract(multiply(divide(subtract(const_100, 9), const_100), multiply(add(const_100, 20), divide(add(const_100, 25), const_100))), const_100) | add(n0,const_100)|add(n1,const_100)|subtract(const_100,n2)|divide(#2,const_100)|divide(#1,const_100)|multiply(#0,#4)|multiply(#3,#5)|subtract(#6,const_100)| | "assume the total price = 100 x price after 20 % markup = 120 x price after 25 % further markup = 1.25 * 120 x = 150 x price after the discount = 0.91 * 150 x = 136.5 x hence total profit = 36.5 % option d" | gain |
math_qa__gwhnpv1KkWkUzshq | If p/q = 6/7 , then 2p+q= ? Choose the most appropriate option: A) 12 B) 14 C) 13 D) 15 E) 19 | <gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 7</gadget>
<output>19</output>
<result>E</result> | E | 19 | If p/q = 6/7 , then 2p+q= ? | {
"A": "12",
"B": "14",
"C": "13",
"D": "15",
"E": "19"
} | add(multiply(6, 2), 7) | multiply(n0,n2)|add(n1,#0)| | "let p = 6 , q = 7 then 2 * 6 + 7 = 19 so 2 p + q = 19 . answer : e" | general |
math_qa__HUoP76R7rRzmYvF0 | it is currently 7 : 05 pm . what time was it in the morning exactly 51132 minutes ago ? Choose the most appropriate option.
A) 6 : 53 B) 6 : 55 C) 6 : 59 D) 7 : 03 E) 7 : 09 | <gadget id="calculator">7 * 60</gadget>
<output>420</output>
<gadget id="calculator">5 + 420</gadget>
<output>425</output>
<gadget id="calculator">51_132 % 60</gadget>
<output>12</output>
<gadget id="calculator">425 - 12</gadget>
<output>413</output>
<gadget id="calculator">413 / 3_600</gadget>
<output>413/3_600 = around 0.114722</output>
<result>A</result> | A | 0.113208 | it is currently 7 : 05 pm . what time was it in the morning exactly 51132 minutes ago ? | {
"A": "6 : 53",
"B": "6 : 55",
"C": "6 : 59",
"D": "7 : 03",
"E": "7 : 09"
} | divide(subtract(add(5, multiply(7, const_60)), reminder(51132, const_60)), const_3600) | multiply(n0,const_60)|reminder(n2,const_60)|add(n1,#0)|subtract(#2,#1)|divide(#3,const_3600) | convert 51,132 minutes to hours by dividing by 60 : 51,132 / 60 = 852 r 12 . that is 852 hours , 12 minutes . convert 852 hours to days by dividing by 24 : 852 / 24 = 35 r 12 . that is 35 days , 12 hours . thus 852 hours before 7 : 05 pm is 12 hours before 7 : 05 pm which is 7 : 05 am . 12 minutes before that is 6 : 53 am . a | physics |
math_qa__Fp5bSQ3jtwhmrOX8 | Mary and Mike enter into a partnership by investing $800 and $200 respectively. At the end of one year, they divided their profits such that a third of the profit is divided equally for the efforts they have put into the business and the remaining amount of profit is divided in the ratio of the investments they made in the business. If Mary received $1200 more than Mike did, what was the profit made by their business in that year? Select:
A) $ 3000 B) $ 3500 C) $ 4000 D) $ 4200 E) $ 4500 | <gadget id="calculator">800 / 1_000</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">200 / 1_000</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(4/5) - (1/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(3/5) * (2/3)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1_200 / (2/5)</gadget>
<output>3_000</output>
<result>A</result> | A | 3,000 | Mary and Mike enter into a partnership by investing $800 and $200 respectively. At the end of one year, they divided their profits such that a third of the profit is divided equally for the efforts they have put into the business and the remaining amount of profit is divided in the ratio of the investments they made in the business. If Mary received $1200 more than Mike did, what was the profit made by their business in that year? | {
"A": "$ 3000",
"B": "$ 3500",
"C": "$ 4000",
"D": "$ 4200",
"E": "$ 4500"
} | divide(1200, multiply(subtract(divide(800, const_1000), divide(200, const_1000)), subtract(const_1, divide(const_1, const_3)))) | divide(n0,const_1000)|divide(n1,const_1000)|divide(const_1,const_3)|subtract(#0,#1)|subtract(const_1,#2)|multiply(#3,#4)|divide(n2,#5)| | "explanatory answer let the profit made during the year be $ 3 x therefore , $ x would have been shared equally and the remaining $ 2 x would have been shared in the ratio 8 : 2 . i . e . , 80 % of 2 x would go to mary and 20 % of 2 x would go to mike . hence , mary would get ( 80 - 20 ) % of 2 x more than mike or 60 % of 2 x = $ 1200 i . e . , ( 60 / 100 ) * 2 x = 1200 or 2 x = 2000 . hence , the profit made by the company during the year $ 3 x = $ 3000 . answer : a" | general |
math_qa__Vvc0LkkMIvwcJR1W | The ratio of the length and the width of a rectangle is 4 : 3 and the area of the rectangle is 4332 sq cm. What is the ratio of the width and the area of the rectangle?
Choose the most appropriate option: A) 1 : 72 B) 1 : 76 C) 1 : 80 D) 1 : 84 E) 1 : 88 | <gadget id="calculator">3 * 4_332</gadget>
<output>12_996</output>
<gadget id="calculator">12_996 ** (1/2)</gadget>
<output>114</output>
<gadget id="calculator">114 / 2</gadget>
<output>57</output>
<gadget id="calculator">57 / 4_332</gadget>
<output>1/76 = around 0.013158</output>
<result>B</result> | B | 0.013158 | The ratio of the length and the width of a rectangle is 4 : 3 and the area of the rectangle is 4332 sq cm. What is the ratio of the width and the area of the rectangle? | {
"A": "1 : 72",
"B": "1 : 76",
"C": "1 : 80",
"D": "1 : 84",
"E": "1 : 88"
} | divide(divide(sqrt(multiply(3, 4332)), const_2), 4332) | multiply(n2,n1)|sqrt(#0)|divide(#1,const_2)|divide(#2,n2)| | "let the length and the width be 4 x and 3 x respectively . area = ( 4 x ) ( 3 x ) = 4332 12 x ^ 2 = 4332 x ^ 2 = 361 x = 19 the ratio of the width and the area is 3 x : 12 x ^ 2 = 1 : 4 x = 1 : 76 the answer is b ." | geometry |
math_qa__ruJr2gf2mtUtBMI6 | An owner of a pizza stand sold small slices of pizza for Rs. 150 each and large slices for Rs. 250 each. One night he sold 5000 slices, for a total of Rs. 10.50 lakh. How many small slices were sold? Choose the correct choice from the following options
A) 3000 B) 2000 C) 4000 D) 2500 E) 3500 | <gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">5_000 - 3_000</gadget>
<output>2_000</output>
<result>B</result> | B | 2,000 | An owner of a pizza stand sold small slices of pizza for Rs. 150 each and large slices for Rs. 250 each. One night he sold 5000 slices, for a total of Rs. 10.50 lakh. How many small slices were sold? | {
"A": "3000",
"B": "2000",
"C": "4000",
"D": "2500",
"E": "3500"
} | subtract(5000, multiply(const_3, const_1000)) | multiply(const_1000,const_3)|subtract(n2,#0) | explanatory answer this question is a word problem in linear equations . the problem is solved by framing two linear equations from the information given in the question and solving them . let ' s ' be the number of small slices and ' b ' the number of large slices sold on that night . therefore , s + b = 5000 . . . eqn ( 1 ) each small slice was sold for rs . 150 . therefore , ' s ' small slices would have fetched rs . 150 s . each large slice was sold for rs . 250 . therefore , ' b ' large slices would have fetched rs . 250 b . total value of sale = 150 s + 250 b = 10 , 50000 ( note the left hand side is in rupees and hence we have to convert right hand also to rupees from lakhs of rupees ) or 150 s + 250 b = 10 , 50000 . . . eqn ( 2 ) multiplying equation ( 1 ) by 150 , we get 150 s + 150 b = 7 , 50000 . . . eqn ( 3 ) subtracting eqn ( 3 ) from eqn ( 2 ) , we get 100 b = 300000 or b = 3000 we know that s + b = 5000 so , s = 5000 - b = 5000 - 3000 = 2000 . 2000 small slices were sold . answer b | general |
math_qa__ryMGEpPQcbuKOy79 | A boat can travel with a speed of 22 km/hr in still water. If the speed of the stream is 5 km/hr, find the time taken by the boat to go 189 km downstream Choose the correct choice from the following choices
A) 5 hours
B) 4 hours
C) 3 hours
D) 2 hours
E) 7 hours | <gadget id="calculator">22 + 5</gadget>
<output>27</output>
<gadget id="calculator">189 / 27</gadget>
<output>7</output>
<result>E</result> | E | 7 | A boat can travel with a speed of 22 km/hr in still water. If the speed of the stream is 5 km/hr, find the time taken by the boat to go 189 km downstream | {
"A": "5 hours",
"B": "4 hours",
"C": "3 hours",
"D": "2 hours",
"E": "7 hours"
} | divide(189, add(22, 5)) | add(n0,n1)|divide(n2,#0)| | "explanation : speed of the boat in still water = 22 km / hr speed of the stream = 5 km / hr speed downstream = ( 22 + 5 ) = 27 km / hr distance travelled downstream = 189 km time taken = distance / speed = 189 / 27 = 7 hours . answer : option e" | physics |
math_qa__EmLMWa7Zf4VrnnZT | Light glows for every 21 seconds . How many max. times did it glow between 1:57:58 and 3:20:47 am.
Choose the correct option:
A) 380 times
B) 236 times
C) 382 times
D) 392 times
E) 482 times | <gadget id="calculator">2 + 47</gadget>
<output>49</output>
<gadget id="calculator">2 + 60</gadget>
<output>62</output>
<gadget id="calculator">20 + 62</gadget>
<output>82</output>
<gadget id="calculator">82 * 60</gadget>
<output>4_920</output>
<gadget id="calculator">49 + 4_920</gadget>
<output>4_969</output>
<gadget id="calculator">4_969 / 21</gadget>
<output>4_969/21 = around 236.619048</output>
<result>B</result> | B | 236 | Light glows for every 21 seconds . How many max. times did it glow between 1:57:58 and 3:20:47 am. | {
"A": "380 times",
"B": "236 times",
"C": "382 times",
"D": "392 times",
"E": "482 times"
} | divide(add(add(const_2, 47), multiply(add(20, add(const_2, const_60)), const_60)), 21) | add(n6,const_2)|add(const_2,const_60)|add(n5,#1)|multiply(#2,const_60)|add(#0,#3)|divide(#4,n0)| | "time difference is 1 hr , 22 min , 49 sec = 4969 sec . so , light glows floor ( 4969 / 21 ) = 236 times . answer : b" | general |
math_qa__qKQkSBwpoECNnG3E | A man buys a cycle for Rs. 1400 and sells it at a loss of 12%. What is the selling price of the cycle?
Choose the correct choice from the following answers.
A) s . 1090 B) s . 1160 C) s . 1232 D) s . 1202 E) s . 1204 | <gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">88 * 1_400</gadget>
<output>123_200</output>
<gadget id="calculator">123_200 / 100</gadget>
<output>1_232</output>
<result>C</result> | C | 1,232 | A man buys a cycle for Rs. 1400 and sells it at a loss of 12%. What is the selling price of the cycle? | {
"A": "s . 1090",
"B": "s . 1160",
"C": "s . 1232",
"D": "s . 1202",
"E": "s . 1204"
} | divide(multiply(subtract(const_100, 12), 1400), const_100) | subtract(const_100,n1)|multiply(n0,#0)|divide(#1,const_100)| | "since , c . p = 1400 loss % = ( c . p - s . p ) / c . p * 100 12 = ( 1400 - s . p ) / 1400 * 100 so , after solving answer = 1232 . answer : c" | gain |
math_qa__a7rkHBRUYs0BI4WQ | If there are 26 laborers in a crew, and on a certain day, 10 were present. Calculate the percentage that showed up for work? (round to the nearest tenth). Choose the most appropriate option.
A) 39.5 % B) 38.5 % C) 36.5 % D) 37.5 % E) 30.5 % | <gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 26</gadget>
<output>500/13 = around 38.461538</output>
<result>B</result> | B | 38.5 | If there are 26 laborers in a crew, and on a certain day, 10 were present. Calculate the percentage that showed up for work? (round to the nearest tenth). | {
"A": "39.5 %",
"B": "38.5 %",
"C": "36.5 %",
"D": "37.5 %",
"E": "30.5 %"
} | divide(multiply(10, const_100), 26) | multiply(n1,const_100)|divide(#0,n0)| | "10 / 26 * 100 = 38.46 38.5 % correct answer b" | physics |
math_qa__TUKpFGMxiB6UcrhS | The profit obtained by selling an article for Rs. 66 is the same as the loss obtained by selling it for Rs. 52. What is the cost price of the article? Pick.
A) rs . 40
B) rs . 50
C) rs . 49
D) rs . 59
E) none of these | <gadget id="calculator">66 + 52</gadget>
<output>118</output>
<gadget id="calculator">118 / 2</gadget>
<output>59</output>
<result>D</result> | D | 59 | The profit obtained by selling an article for Rs. 66 is the same as the loss obtained by selling it for Rs. 52. What is the cost price of the article? | {
"A": "rs . 40",
"B": "rs . 50",
"C": "rs . 49",
"D": "rs . 59",
"E": "none of these"
} | divide(add(66, 52), const_2) | add(n0,n1)|divide(#0,const_2)| | "s . p 1 - c . p = c . p – s . p 2 66 - c . p = c . p - 52 2 c . p = 66 + 52 ; c . p = 118 / 2 = 59 answer : d" | gain |
math_qa__hl6AjGLZyybwTNoh | A bag contains 5 red, 4 blue and 3 green balls. If 2 ballsare picked at random, what is the probability that both are red? Choose the correct choice from the following options
A) 1 / 13
B) 2 / 23
C) 5 / 33
D) 4 / 27
E) 3 / 23 | <gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">9 + 3</gadget>
<output>12</output>
<gadget id="calculator">binomial(12, 2)</gadget>
<output>66</output>
<gadget id="calculator">10 / 66</gadget>
<output>5/33 = around 0.151515</output>
<result>C</result> | C | 0.151515 | A bag contains 5 red, 4 blue and 3 green balls. If 2 ballsare picked at random, what is the probability that both are red? | {
"A": "1 / 13",
"B": "2 / 23",
"C": "5 / 33",
"D": "4 / 27",
"E": "3 / 23"
} | divide(choose(5, 2), choose(add(add(5, 4), 3), 2)) | add(n0,n1)|choose(n0,n3)|add(n2,#0)|choose(#2,n3)|divide(#1,#3)| | "p ( both are red ) , = 5 c 212 c 2 = 5 c 212 c 2 = 10 / 66 = 5 / 33 c" | other |
math_qa__gLitpfmjwFJcbrwb | In an election between two candidates, the first candidate got 70% of the votes and the second candidate got 240 votes. What was the total number of votes? Choose one:
A) 800 B) 900 C) 1000 D) 1100 E) 1200 | <gadget id="calculator">240 * 100</gadget>
<output>24_000</output>
<gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">24_000 / 30</gadget>
<output>800</output>
<result>A</result> | A | 800 | In an election between two candidates, the first candidate got 70% of the votes and the second candidate got 240 votes. What was the total number of votes? | {
"A": "800",
"B": "900",
"C": "1000",
"D": "1100",
"E": "1200"
} | divide(multiply(240, const_100), subtract(const_100, 70)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "let v be the total number of votes . 0.3 v = 240 v = 800 the answer is a ." | gain |
math_qa__HGwXOLRyuTQS5lJQ | Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 38 percent ryegrass, what percent of the weight of this mixture is X ? Answers.
A) 10 % B) 33.33 % C) 40 % D) 86.66 % E) 66.66 % | <gadget id="calculator">38 - 25</gadget>
<output>13</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(2/5) - (1/4)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">13 / (3/20)</gadget>
<output>260/3 = around 86.666667</output>
<result>D</result> | D | 86.66 | Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 38 percent ryegrass, what percent of the weight of this mixture is X ? | {
"A": "10 %",
"B": "33.33 %",
"C": "40 %",
"D": "86.66 %",
"E": "66.66 %"
} | divide(subtract(38, 25), subtract(divide(40, const_100), divide(25, const_100))) | divide(n0,const_100)|divide(n2,const_100)|subtract(n4,n2)|subtract(#0,#1)|divide(#2,#3) | - - - - - - - - - - - - - - - - > ryegrass x - - - - - - - - - - - - - - > 40 % y - - - - - - - - - - - - - - > 25 % m ( mixture ) - - - - > 38 % 0.4 x + ( m - x ) 0.25 = 0.38 m 0.15 x = 0.13 m x = 0.8666 m x = 86.66 % of m d | gain |
math_qa__bFGiEw33ASGx4tlq | A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 5 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
Choose the most appropriate option:
A) rs . 1178.55 B) rs . 1978.25 C) rs . 1332.5 D) rs . 1678 E) rs . 1675.55 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 * 2_665</gadget>
<output>39_975</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 + 15</gadget>
<output>30</output>
<gadget id="calculator">39_975 / 30</gadget>
<output>2_665/2 = around 1_332.5</output>
<gadget id="calculator">2_665 - (2_665/2)</gadget>
<output>2_665/2 = around 1_332.5</output>
<result>C</result> | C | 1,332.5 | A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 5 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum? | {
"A": "rs . 1178.55",
"B": "rs . 1978.25",
"C": "rs . 1332.5",
"D": "rs . 1678",
"E": "rs . 1675.55"
} | subtract(2665, divide(multiply(multiply(3, 5), 2665), add(multiply(3, 5), multiply(5, 3)))) | multiply(n2,n4)|multiply(n1,n2)|add(#0,#1)|multiply(n0,#0)|divide(#3,#2)|subtract(n0,#4)| | "( x * 5 * 3 ) / 100 = ( ( 2665 - x ) * 3 * 5 ) / 100 15 x / 100 = 39975 / 100 - 15 x / 100 30 x = 39975 = > x = 1332.5 second sum = 2665 – 1025 = 1332.5 answer : c" | gain |
math_qa__sSPYsppXRA9zMSm8 | Nitin ranks 15th in a class of 47 students. What is rank from the last ? Answers:
A) 33 B) 38 C) 32 D) 28 E) 19 | <gadget id="calculator">47 - 15</gadget>
<output>32</output>
<result>A</result> | A | 33 | Nitin ranks 15th in a class of 47 students. What is rank from the last ? | {
"A": "33",
"B": "38",
"C": "32",
"D": "28",
"E": "19"
} | subtract(47, 15) | subtract(n1,n0)| | "explanation : number students behind the nitin in rank = ( 47 - 15 ) = 32 nitin is 33 rd from the last answer : a ) 33" | other |
math_qa__MzbF6U6pFkcP0kx9 | Cole drove from home to work at an average speed of 70 kmh. He then returned home at an average speed of 105 kmh. If the round trip took a total of 2 hours, how many minutes did it take Cole to drive to work? Pick one:
A) 66 B) 70 C) 72 D) 75 E) 78 | <gadget id="calculator">105 * 2</gadget>
<output>210</output>
<gadget id="calculator">70 + 105</gadget>
<output>175</output>
<gadget id="calculator">210 / 175</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 60</gadget>
<output>72</output>
<result>C</result> | C | 72 | Cole drove from home to work at an average speed of 70 kmh. He then returned home at an average speed of 105 kmh. If the round trip took a total of 2 hours, how many minutes did it take Cole to drive to work? | {
"A": "66",
"B": "70",
"C": "72",
"D": "75",
"E": "78"
} | multiply(divide(multiply(105, 2), add(70, 105)), const_60) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)|multiply(#2,const_60)| | "let the distance one way be x time from home to work = x / 70 time from work to home = x / 105 total time = 2 hrs ( x / 70 ) + ( x / 105 ) = 2 solving for x , we get x = 84 time from home to work in minutes = ( 84 ) * 60 / 70 = 72 minutes ans = c" | physics |
math_qa__0CuuScUAlfEFJ3KK | Canister C is 1/2 full of water and canister D, which has twice the capacity of canister C, is 1/3 full of water. If the water in canister D is poured in canister C until canister C is completely full of water, canister D will still contain what fraction of its capacity of water? Choose the correct choice from the following: A) 0 B) 1 / 36 C) 1 / 12 D) 1 / 6 E) 1 / 4 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * (1/2)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) - (1/4)</gadget>
<output>1/12 = around 0.083333</output>
<result>C</result> | C | 0.083333 | Canister C is 1/2 full of water and canister D, which has twice the capacity of canister C, is 1/3 full of water. If the water in canister D is poured in canister C until canister C is completely full of water, canister D will still contain what fraction of its capacity of water? | {
"A": "0",
"B": "1 / 36",
"C": "1 / 12",
"D": "1 / 6",
"E": "1 / 4"
} | subtract(divide(1, 3), multiply(divide(1, 2), divide(1, 2))) | divide(n0,n3)|divide(n0,n1)|multiply(#1,#1)|subtract(#0,#2) | say canister c has a capacity of 6 liters . it ' s half full , thus there can be poured 3 liters of water . canister b is 12 liters and there are 4 liters of water . we can pour 3 liters from d to c and 1 liter will still be left in d , which is 1 / 12 of its total capacity . answer : c . | general |
math_qa__vk7aRqMQZZRqmfyv | Jose is uploading a file to the internet for a college project. The file weighs 160 megabytes. If Jose's internet speed for uploading tops 8 megabytes per minute, how long will it take until the upload is completed? Choices.
A) 1 hour B) 45 minutes C) 20 minutes D) 5 minutes E) 1 hour and 10 minutes | <gadget id="calculator">160 / 8</gadget>
<output>20</output>
<result>C</result> | C | 20 | Jose is uploading a file to the internet for a college project. The file weighs 160 megabytes. If Jose's internet speed for uploading tops 8 megabytes per minute, how long will it take until the upload is completed? | {
"A": "1 hour",
"B": "45 minutes",
"C": "20 minutes",
"D": "5 minutes",
"E": "1 hour and 10 minutes"
} | divide(160, 8) | divide(n0,n1) | answer is ( c ) . jose calculates that if the files weighs 160 megabytes , and his internet uploads at 8 megabytes per minute , it would take 20 minutes to upload as 160 divided by 8 megabytes per minute equals 20 . | physics |
math_qa__FsEINIV2Dh8Ve6aj | The average monthly salary of 20 employees in an organisation is Rs. 1600. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?
Choose the correct answer.
A) 3700
B) 3890
C) 88798
D) 2789
E) 2891 | <gadget id="calculator">1_600 + 100</gadget>
<output>1_700</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">1_700 * 21</gadget>
<output>35_700</output>
<gadget id="calculator">1_600 * 20</gadget>
<output>32_000</output>
<gadget id="calculator">35_700 - 32_000</gadget>
<output>3_700</output>
<result>A</result> | A | 3,700 | The average monthly salary of 20 employees in an organisation is Rs. 1600. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ? | {
"A": "3700",
"B": "3890",
"C": "88798",
"D": "2789",
"E": "2891"
} | subtract(multiply(add(1600, 100), add(20, const_1)), multiply(1600, 20)) | add(n1,n2)|add(n0,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "explanation : manager ' s monthly salary rs . ( 1700 * 21 - 1600 * 20 ) = rs . 3700 . answer : a ) 3700" | general |
math_qa__r1VxKE5eHhdK3StM | A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $19000 left with him. find salary.. Answers
A) $ 10900 B) $ 19000 C) $ 190000 D) $ 1900 E) none | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/5) + (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/10) + (3/5)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 - (9/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">19_000 / (1/10)</gadget>
<output>190_000</output>
<result>C</result> | C | 190,000 | A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $19000 left with him. find salary.. | {
"A": "$ 10900",
"B": "$ 19000",
"C": "$ 190000",
"D": "$ 1900",
"E": "none"
} | divide(19000, subtract(1, add(add(divide(1, 5), divide(1, 10)), divide(3, 5)))) | divide(n0,n1)|divide(n0,n3)|divide(n4,n1)|add(#0,#1)|add(#3,#2)|subtract(n0,#4)|divide(n6,#5)| | "[ 1 / ( x 1 / y 1 + x 2 / y 2 + x 3 / y 3 ) ] * total amount = balance amount [ 1 - ( 1 / 5 + 1 / 10 + 3 / 5 ) } * total salary = $ 19000 , = [ 1 - 9 / 10 ] * total salary = $ 19000 , total salary = $ 19000 * 10 = $ 190000 , correct answer ( c )" | general |
math_qa__HpjxvXGF66lbnKy5 | In an examination, there were 2,000 candidates, out of which 900 candidates were girls and rest were Boys. If 30% of the boys and 32% of the girls passed, then the total percentage of failed candidates is? Select the correct option
A) 35.67 %
B) 64.75 %
C) 68.57 %
D) 69.10 %
E) none of these | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">2 * 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">2_000 - 900</gadget>
<output>1_100</output>
<gadget id="calculator">(3/10) * 1_100</gadget>
<output>330</output>
<gadget id="calculator">2_000 - 330</gadget>
<output>1_670</output>
<gadget id="calculator">32 / 100</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">(8/25) * 900</gadget>
<output>288</output>
<gadget id="calculator">1_670 - 288</gadget>
<output>1_382</output>
<gadget id="calculator">1_382 / 2_000</gadget>
<output>691/1_000 = around 0.691</output>
<gadget id="calculator">(691/1_000) * 100</gadget>
<output>691/10 = around 69.1</output>
<result>D</result> | D | 69.1 | In an examination, there were 2,000 candidates, out of which 900 candidates were girls and rest were Boys. If 30% of the boys and 32% of the girls passed, then the total percentage of failed candidates is? | {
"A": "35.67 %",
"B": "64.75 %",
"C": "68.57 %",
"D": "69.10 %",
"E": "none of these"
} | multiply(divide(subtract(subtract(multiply(const_2, multiply(const_100, const_10)), multiply(divide(30, const_100), subtract(multiply(const_2, multiply(const_100, const_10)), 900))), multiply(divide(32, const_100), 900)), multiply(const_2, multiply(const_100, const_10))), const_100) | divide(n2,const_100)|divide(n3,const_100)|multiply(const_10,const_100)|multiply(#2,const_2)|multiply(n1,#1)|subtract(#3,n1)|multiply(#0,#5)|subtract(#3,#6)|subtract(#7,#4)|divide(#8,#3)|multiply(#9,const_100)| | "girls = 900 , boys = 1100 passed = ( 30 % of 1100 ) + ( 32 % of 900 ) = 330 + 288 = 618 failed = 2000 - 618 = 1382 failed % = [ ( 1382 / 2000 ) x 100 ] % = 69.1 % . answer : d" | general |
math_qa__lh06O5Mdx4z86jiR | If 2x + y = 7 and x + 2y = 10, then (x + y)/3 = Answers.
A) 1 B) 4 / 3 C) 17 / 9 D) 18 / 5 E) 4 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">14 - 10</gadget>
<output>4</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">2 * (4/3)</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">7 - (8/3)</gadget>
<output>13/3 = around 4.333333</output>
<gadget id="calculator">(4/3) + (13/3)</gadget>
<output>17/3 = around 5.666667</output>
<gadget id="calculator">(17/3) / 3</gadget>
<output>17/9 = around 1.888889</output>
<result>C</result> | C | 1.888889 | If 2x + y = 7 and x + 2y = 10, then (x + y)/3 = | {
"A": "1",
"B": "4 / 3",
"C": "17 / 9",
"D": "18 / 5",
"E": "4"
} | divide(add(divide(subtract(multiply(7, 2), 10), subtract(multiply(2, 2), const_1)), subtract(7, multiply(2, divide(subtract(multiply(7, 2), 10), subtract(multiply(2, 2), const_1))))), 3) | multiply(n0,n1)|multiply(n0,n0)|subtract(#0,n3)|subtract(#1,const_1)|divide(#2,#3)|multiply(n0,#4)|subtract(n1,#5)|add(#4,#6)|divide(#7,n4)| | "we have two equations : 2 x + y = 7 x + 2 y = 10 notice that something nice happens when we add them . we get : 3 x + 3 y = 17 divide both sides by 3 to get : x + y = 17 / 3 so , ( x + y ) / 3 = 17 / 9 answer : c" | general |
math_qa__3nOLNJr1MLiodfD4 | Two friends decide to get together; so they start riding bikes towards each other. They plan to meet halfway. Each is riding at 6 MPH. They live 36 miles apart. One of them has a pet carrier pigeon and it starts flying the instant the friends start traveling. The pigeon flies back and forth at 40 MPH between the 2 friends until the friends meet. How many miles does the pigeon travel? Choose the correct choice from the following answers
A) 54 B) 110 C) 120 D) 16 E) 180 | <gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">18 / 6</gadget>
<output>3</output>
<gadget id="calculator">40 * 3</gadget>
<output>120</output>
<result>C</result> | C | 120 | Two friends decide to get together; so they start riding bikes towards each other. They plan to meet halfway. Each is riding at 6 MPH. They live 36 miles apart. One of them has a pet carrier pigeon and it starts flying the instant the friends start traveling. The pigeon flies back and forth at 40 MPH between the 2 friends until the friends meet. How many miles does the pigeon travel? | {
"A": "54",
"B": "110",
"C": "120",
"D": "16",
"E": "180"
} | multiply(40, divide(divide(36, 2), 6)) | divide(n1,n3)|divide(#0,n0)|multiply(n2,#1)| | "c 120 it takes 3 hours for the friends to meet ; so the pigeon flies for 3 hours at 40 mph = 120 miles" | physics |
math_qa__ZnOF9cQWejy9BR7L | Puzzle !!! 🙂
if
111 = 09
444 = 12
777 = 15
then
888 = ??? Choose the correct choice from the following options:
A) 13
B) 17
C) 18
D) 11
E) 15 | <gadget id="calculator">15 * 1</gadget>
<output>15</output>
<result>E</result> | E | 15 | Puzzle !!! 🙂
if
111 = 09
444 = 12
777 = 15
then
888 = ??? | {
"A": "13",
"B": "17",
"C": "18",
"D": "11",
"E": "15"
} | multiply(15, const_1) | multiply(n5,const_1) | e 15 one + one + one ( 3 + 3 + 3 ) = 09 four + four + four ( 4 + 4 + 4 ) = 12 seven + seven + seven ( 5 + 5 + 5 ) = 15 therefore eight + eight + eight ( 5 + 5 + 5 ) = 15 | other |
math_qa__lE5hD7uJfHgdc2hs | town m town n town o town p town q town r ; town a town b town c town d town e town f in the table above , what is the least number of table entries that are needed to show the mileage between each town and each of the other 5 towns ?
Choose the correct choice from the following answers
A) 11 B) 12 C) 13 D) 14 E) 15 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>E</result> | E | 15 | town m town n town o town p town q town r ; town a town b town c town d town e town f in the table above , what is the least number of table entries that are needed to show the mileage between each town and each of the other 5 towns ? | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | divide(multiply(multiply(const_2, const_3), 5), const_2) | multiply(const_2,const_3)|multiply(n0,#0)|divide(#1,const_2) | easy way to go about this problem is we have 6 * 6 = 36 enteries in table the least number of enteries would be ( 36 - 6 ) / 2 since 6 enteries represent the distances between same points . alternatively this can be solved as combination problem . correct answer e | physics |
math_qa__vLAgDc8P3yPOsmaN | What is the greatest of 3 consecutive integers whose sum is 33 ? Choose one: A) 10 B) 11 C) 12 D) 13 E) 14 | <gadget id="calculator">33 - 3</gadget>
<output>30</output>
<gadget id="calculator">30 / 3</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<result>C</result> | C | 12 | What is the greatest of 3 consecutive integers whose sum is 33 ? | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | add(divide(subtract(33, 3), 3), const_2) | subtract(n1,n0)|divide(#0,n0)|add(#1,const_2)| | "33 / 3 = 11 the three numbers are 10 , 11 , and 12 . the answer is c ." | physics |
math_qa__cPsyG614iQqvcu7w | A diagonal of a polygon is an segment between two non-adjacent vertices of the polygon. How many diagonals does a regular 45-sided polygon have? Pick
A) 875 B) 945 C) 1425 D) 2025 E) 2500 | <gadget id="calculator">45 - 3</gadget>
<output>42</output>
<gadget id="calculator">42 * 45</gadget>
<output>1_890</output>
<gadget id="calculator">1_890 / 2</gadget>
<output>945</output>
<result>B</result> | B | 945 | A diagonal of a polygon is an segment between two non-adjacent vertices of the polygon. How many diagonals does a regular 45-sided polygon have? | {
"A": "875",
"B": "945",
"C": "1425",
"D": "2025",
"E": "2500"
} | divide(multiply(subtract(45, const_3), 45), const_2) | subtract(n0,const_3)|multiply(n0,#0)|divide(#1,const_2)| | "there ' s a direct formula for this . number of diagonals in a regular polygon = [ n * ( n - 3 ) ] / 2 , n = number of sides of the regular polygon . here , n = 45 . plugging it in , we get 945 diagonals ! answer ( b ) ." | geometry |
math_qa__Ze9Baambv1akkPbz | A, B and C started a shop by investing Rs. 5,000, Rs. 15,000 and Rs. 30,000 respectively. At the end of the year, the profits were distributed among them. If C’s share of profit be Rs. 3000, then the total profit was : Choose the correct choice from the following answers
A) 30,000 B) 5,000 C) 80,000 D) 120,000 E) none | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">50 * 100</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 * 3</gadget>
<output>15_000</output>
<gadget id="calculator">5_000 + 15_000</gadget>
<output>20_000</output>
<gadget id="calculator">15_000 * 2</gadget>
<output>30_000</output>
<gadget id="calculator">20_000 + 30_000</gadget>
<output>50_000</output>
<gadget id="calculator">3_000 / 30_000</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">50_000 * (1/10)</gadget>
<output>5_000</output>
<result>B</result> | B | 5,000 | A, B and C started a shop by investing Rs. 5,000, Rs. 15,000 and Rs. 30,000 respectively. At the end of the year, the profits were distributed among them. If C’s share of profit be Rs. 3000, then the total profit was : | {
"A": "30,000",
"B": "5,000",
"C": "80,000",
"D": "120,000",
"E": "none"
} | multiply(add(add(multiply(multiply(add(const_2, const_3), multiply(add(const_2, const_3), const_2)), const_100), multiply(multiply(multiply(add(const_2, const_3), multiply(add(const_2, const_3), const_2)), const_100), const_3)), multiply(multiply(multiply(multiply(add(const_2, const_3), multiply(add(const_2, const_3), const_2)), const_100), const_3), const_2)), divide(3000, multiply(multiply(multiply(multiply(add(const_2, const_3), multiply(add(const_2, const_3), const_2)), const_100), const_3), const_2))) | add(const_2,const_3)|multiply(#0,const_2)|multiply(#0,#1)|multiply(#2,const_100)|multiply(#3,const_3)|add(#3,#4)|multiply(#4,const_2)|add(#5,#6)|divide(n3,#6)|multiply(#7,#8) | sol . a : b : c = 5000 : 15000 : 30000 = 1 : 3 : 6 . so , c â € ™ s share : total profit = 6 : 10 let the total profit be rs . x . then , 6 / 10 = 3000 / x or x = 3000 * 10 / 6 = 5000 . answer b | gain |
math_qa__5nKKxo7btTVgwT7Z | Christine selects an item at a 25% off ticket price sale. The item is ticket priced at $25. How much should Christine expect to pay at the register?
Choose one:
A) 22.5
B) 20.0
C) 18.75
D) 12.5
E) 10.0 | <gadget id="calculator">25 * 25</gadget>
<output>625</output>
<gadget id="calculator">625 / 100</gadget>
<output>25/4 = around 6.25</output>
<gadget id="calculator">25 - (25/4)</gadget>
<output>75/4 = around 18.75</output>
<result>C</result> | C | 18.75 | Christine selects an item at a 25% off ticket price sale. The item is ticket priced at $25. How much should Christine expect to pay at the register? | {
"A": "22.5",
"B": "20.0",
"C": "18.75",
"D": "12.5",
"E": "10.0"
} | subtract(25, divide(multiply(25, 25), const_100)) | multiply(n0,n0)|divide(#0,const_100)|subtract(n0,#1) | r . p . = $ 25.00 sale % = 25 s . p . = r . p . * ( 1 - ( sale % / 100 ) ) = 25 * ( 1 - ( 25 / 100 ) ) = 18.75 answer : c | general |
math_qa__vsWGZABrucUYc8mG | Two employees X and Y are paid a total of Rs. 500 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Choose the correct choice from the following choices
A) s . 227 B) s . 287 C) s . 297 D) s . 300 E) s . 380 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">500 * 10</gadget>
<output>5_000</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">5_000 / 22</gadget>
<output>2_500/11 = around 227.272727</output>
<result>A</result> | A | 227 | Two employees X and Y are paid a total of Rs. 500 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? | {
"A": "s . 227",
"B": "s . 287",
"C": "s . 297",
"D": "s . 300",
"E": "s . 380"
} | divide(multiply(500, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4)| | "let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 500 but x = 120 % of y = 120 y / 100 = 12 y / 10 ∴ 12 y / 10 + y = 500 ⇒ y [ 12 / 10 + 1 ] = 500 ⇒ 22 y / 10 = 500 ⇒ 22 y = 5000 ⇒ y = 5000 / 22 = rs . 227.77 a )" | general |
math_qa__DMBPW3b27WrVdXlh | If the perimeter of square region E and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3 then the ratio of the area of R to the area of E
Answers
A) 25 : 16
B) 24 : 25
C) 5 : 6
D) 4 : 5
E) 4 : 9 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">10 / 4</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) ** 2</gadget>
<output>25/4 = around 6.25</output>
<gadget id="calculator">6 / (25/4)</gadget>
<output>24/25 = around 0.96</output>
<result>B</result> | B | 0.96 | If the perimeter of square region E and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3 then the ratio of the area of R to the area of E | {
"A": "25 : 16",
"B": "24 : 25",
"C": "5 : 6",
"D": "4 : 5",
"E": "4 : 9"
} | divide(rectangle_area(2, 3), square_area(divide(const_10, const_4))) | divide(const_10,const_4)|rectangle_area(n0,n1)|square_area(#0)|divide(#1,#2) | we know perimeter of a square ( pe ) = 4 * side perimeter of a rectangle ( pr ) = 2 ( length + breath ) let us assume 40 to be the perimeter of the square ( since we know each side of a square is equal and the perimeter is divisible by 4 , also take in to account the length and breadth of the rectangle is in the ration 2 k : 3 k = 5 k ; we can assume such a number ) therefore , pe = pr = 40 area of the square = 100 sq . units we know 2 ( length + breadth ) = 40 i . e . length + breadth = 20 ( or 5 k = 20 given that l : b ( or b : l ) = 2 : 3 ) therefore length = 8 , breath = 12 area of the rectangle = 8 * 12 = 96 sq . units question asked = area of the rectangle : area of the square = 96 : 100 = = > 24 : 25 = b | geometry |
math_qa__ua76J10SJU0lwdg6 | P can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 30 days to complete the same work. then Q alone can do it in Choose the correct option.
A) 10 B) 22 C) 25 D) 27 E) 30 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/10) + (1/30)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/15) / 2</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) - (1/30)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / (1/30)</gadget>
<output>30</output>
<result>E</result> | E | 30 | P can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 30 days to complete the same work. then Q alone can do it in | {
"A": "10",
"B": "22",
"C": "25",
"D": "27",
"E": "30"
} | divide(const_1, subtract(divide(add(divide(const_1, 10), divide(const_1, 30)), const_2), divide(const_1, 30))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(#2,const_2)|subtract(#3,#1)|divide(const_1,#4) | work done by p and q in 1 day = 1 / 10 work done by r in 1 day = 1 / 30 work done by p , q and r in 1 day = 1 / 10 + 1 / 30 = 4 / 30 but work done by p in 1 day = work done by q and r in 1 day . hence the above equation can be written as work done by p in 1 day ã — 2 = 4 / 30 = > work done by p in 1 day = 4 / 60 = > work done by q and r in 1 day = 4 / 60 hence work done by q in 1 day = 4 / 60 â € “ 1 / 30 = 2 / 60 = 1 / 30 so q alone can do the work in 30 days answer is e . | physics |
math_qa__mUcCqXOc7FJbfwPh | Calculate the average of all the numbers between 11 and 27 which are divisible by 2. Choose the correct choice from the following choices:
A) 11 B) 10 C) 18 D) 19 E) 21 | <gadget id="calculator">11 / 2</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">floor(11/2)</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">27 / 2</gadget>
<output>27/2 = around 13.5</output>
<gadget id="calculator">floor(27/2)</gadget>
<output>13</output>
<gadget id="calculator">6 + 13</gadget>
<output>19</output>
<gadget id="calculator">19 / 2</gadget>
<output>19/2 = around 9.5</output>
<gadget id="calculator">(19/2) * 2</gadget>
<output>19</output>
<result>D</result> | D | 19 | Calculate the average of all the numbers between 11 and 27 which are divisible by 2. | {
"A": "11",
"B": "10",
"C": "18",
"D": "19",
"E": "21"
} | multiply(divide(add(add(floor(divide(11, 2)), const_1), floor(divide(27, 2))), const_2), 2) | divide(n0,n2)|divide(n1,n2)|floor(#0)|floor(#1)|add(#2,const_1)|add(#4,#3)|divide(#5,const_2)|multiply(n2,#6)| | "explanation : numbers divisible by 2 are 12,14 , 16,18 , 20,22 , 24,26 , average = ( 12 + 14 + 16 + 18 + 20 + 22 + 24 + 26 , ) / 8 = 152 / 8 = 19 answer : d" | general |
math_qa__Aq8x0Ahn7bRPxkRM | We had $3500 left after spending 30% of the money that we took for shopping. How much money did we start with? Choose one
A) $ 4600 B) $ 4800 C) $ 5000 D) $ 5200 E) $ 5400 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">3_500 / (7/10)</gadget>
<output>5_000</output>
<result>C</result> | C | 5,000 | We had $3500 left after spending 30% of the money that we took for shopping. How much money did we start with? | {
"A": "$ 4600",
"B": "$ 4800",
"C": "$ 5000",
"D": "$ 5200",
"E": "$ 5400"
} | divide(3500, subtract(const_1, divide(30, const_100))) | divide(n1,const_100)|subtract(const_1,#0)|divide(n0,#1)| | "let x be the amount of money we started with . 0.7 x = 3500 x = 5000 the answer is c ." | gain |
math_qa__YQwtBdUv0oUTvhxl | On a certain farm the ratio of horses to cows is 3:1. If the farm were to sell 15 horses and buy 15 cows, the ratio of horses to cows would then be 5:3. After the transaction, how many more horses than cows would the farm own?
Choices:
A) 20 B) 30 C) 40 D) 50 E) 60 | <gadget id="calculator">15 * 5</gadget>
<output>75</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">75 + 45</gadget>
<output>120</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 - 5</gadget>
<output>4</output>
<gadget id="calculator">120 / 4</gadget>
<output>30</output>
<gadget id="calculator">3 * 30</gadget>
<output>90</output>
<gadget id="calculator">90 - 15</gadget>
<output>75</output>
<gadget id="calculator">30 + 15</gadget>
<output>45</output>
<gadget id="calculator">75 - 45</gadget>
<output>30</output>
<result>B</result> | B | 30 | On a certain farm the ratio of horses to cows is 3:1. If the farm were to sell 15 horses and buy 15 cows, the ratio of horses to cows would then be 5:3. After the transaction, how many more horses than cows would the farm own? | {
"A": "20",
"B": "30",
"C": "40",
"D": "50",
"E": "60"
} | subtract(subtract(multiply(3, divide(add(multiply(15, 5), multiply(15, 3)), subtract(multiply(3, 3), 5))), 15), add(divide(add(multiply(15, 5), multiply(15, 3)), subtract(multiply(3, 3), 5)), 15)) | multiply(n2,n4)|multiply(n2,n5)|multiply(n0,n5)|add(#0,#1)|subtract(#2,n4)|divide(#3,#4)|add(n2,#5)|multiply(n0,#5)|subtract(#7,n2)|subtract(#8,#6)| | "originally , there were 3 k horses and k cows . 3 ( 3 k - 15 ) = 5 ( k + 15 ) 9 k - 5 k = 75 + 45 4 k = 120 k = 30 the difference between horses and cows is ( 3 k - 15 ) - ( k + 15 ) = 2 k - 30 = 30 the answer is b ." | other |
math_qa__BLpJNHCKE9FI0bQa | A gardener wants to plant trees in his garden in such a way that the number of trees in each row should be the same. If there are 7 rows or 6 rows or 4 rows, then no tree will be left. Find the least number of trees required
Choose the correct choice from the following choices: A) 22 B) 84 C) 28 D) 76 E) 21 | <gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">24 * 7</gadget>
<output>168</output>
<gadget id="calculator">168 / 2</gadget>
<output>84</output>
<result>B</result> | B | 84 | A gardener wants to plant trees in his garden in such a way that the number of trees in each row should be the same. If there are 7 rows or 6 rows or 4 rows, then no tree will be left. Find the least number of trees required | {
"A": "22",
"B": "84",
"C": "28",
"D": "76",
"E": "21"
} | divide(multiply(multiply(4, 6), 7), const_2) | multiply(n1,n2)|multiply(n0,#0)|divide(#1,const_2)| | "explanation : the least number of trees that are required = lcm ( 7 , 6,4 ) = 84 . answer : b" | general |
math_qa__yPGxqtjtOoZHY6Uc | If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {22} + {20}? Choose the correct option.
A) 23
B) 20
C) 11
D) 5
E) 2 | <gadget id="calculator">22 + 20</gadget>
<output>42</output>
<gadget id="calculator">42 / 2</gadget>
<output>21</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">21 + 2</gadget>
<output>23</output>
<result>A</result> | A | 23 | If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {22} + {20}? | {
"A": "23",
"B": "20",
"C": "11",
"D": "5",
"E": "2"
} | add(divide(add(22, 20), const_2), multiply(1, const_2)) | add(n1,n2)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "soln : { 22 } + { 20 } = 22 * { 20 } + { 20 } = 23 * { 20 } answer : a" | general |
math_qa__k35yaPYsNYFBgtST | What is the maximum number T of 27 cubic centimetre cubes that can fit in a rectangular box measuring 8 centimetre x 9 centimetre x 12 centimetre ? Select the correct option: A) 36 B) 32 C) 24 D) 21 E) 15 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">27 ** (1/3)</gadget>
<output>3</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">9 / 3</gadget>
<output>3</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<result>C</result> | C | 24 | What is the maximum number T of 27 cubic centimetre cubes that can fit in a rectangular box measuring 8 centimetre x 9 centimetre x 12 centimetre ? | {
"A": "36",
"B": "32",
"C": "24",
"D": "21",
"E": "15"
} | multiply(multiply(divide(multiply(const_3, const_2), cube_edge_by_volume(27)), divide(9, cube_edge_by_volume(27))), divide(12, cube_edge_by_volume(27))) | cube_edge_by_volume(n0)|multiply(const_2,const_3)|divide(n3,#0)|divide(#1,#0)|divide(n2,#0)|multiply(#3,#4)|multiply(#2,#5) | 27 cubic centimetre cubes gives side = 3 cm so if : l * w * h is 9 * 12 * 8 , then max . cube we can have are 3 * 4 * 2 = 24 l * w * h is 9 * 8 * 12 , then max . cube we can have are 3 * 2 * 4 = 24 l * w * h is 12 * 8 * 9 , then max . cube we can have are 4 * 2 * 3 = 24 l * w * h is 12 * 9 * 8 , then max . cube we can have are 4 * 3 * 2 = 24 l * w * h is 8 * 12 * 9 , then max . cube we can have are 2 * 4 * 3 = 24 l * w * h is 8 * 9 * 12 , then max . cube we can have are 2 * 3 * 4 = 24 in all cases we get t = 24 cubes . ans . c | geometry |
math_qa__SJlF8XsJe4WSzpQR | If X gets 25% more than Y and Y gets 20% more than Z, the share of Z out of Rs. 1480 will be: Answers
A) rs . 300 B) rs . 200 C) rs . 240 D) rs . 400 E) none of these | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(5/4) * (6/5)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + (6/5)</gadget>
<output>27/10 = around 2.7</output>
<gadget id="calculator">(27/10) + 1</gadget>
<output>37/10 = around 3.7</output>
<gadget id="calculator">1_480 / (37/10)</gadget>
<output>400</output>
<result>D</result> | D | 400 | If X gets 25% more than Y and Y gets 20% more than Z, the share of Z out of Rs. 1480 will be: | {
"A": "rs . 300",
"B": "rs . 200",
"C": "rs . 240",
"D": "rs . 400",
"E": "none of these"
} | divide(1480, add(add(multiply(add(const_1, divide(25, const_100)), add(const_1, divide(20, const_100))), add(const_1, divide(20, const_100))), const_1)) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#3,#2)|add(#2,#4)|add(#5,const_1)|divide(n2,#6)| | "z share = z , y = 1.2 z x = 1.25 ã — 1.2 z , x + y + z = 1480 ( 1.25 ã — 1.2 + 1.2 + 1 ) z = 1480 3.7 z = 1480 , z = 400 answer : . d" | general |
math_qa__vuFFhRzEC9TDQl51 | If the ratio of apples to bananas is 5 to 2 and the ratio of bananas to cucumbers is 1 to 3, what is the ratio of apples to cucumbers? Select: A) 2 : 3 B) 5 : 3 C) 5 : 6 D) 1 : 4 E) 3 : 4 | <gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) / 3</gadget>
<output>5/6 = around 0.833333</output>
<result>C</result> | C | 0.833333 | If the ratio of apples to bananas is 5 to 2 and the ratio of bananas to cucumbers is 1 to 3, what is the ratio of apples to cucumbers? | {
"A": "2 : 3",
"B": "5 : 3",
"C": "5 : 6",
"D": "1 : 4",
"E": "3 : 4"
} | divide(divide(5, 2), 3) | divide(n0,n1)|divide(#0,n3)| | "the ratio of bananas to cucumbers is 1 to 3 which equals 2 to 6 . the ratio of apples to bananas to cucumbers is 5 to 2 to 6 . the ratio of apples to cucumbers is 5 to 6 . the answer is c ." | other |
math_qa__YkkpWkGyPgUZGAYn | The edge of a cube is 4a cm. Find its surface? Pick
A) 24 a 8 B) 24 a 4 C) 96 a 2 D) 24 a 2 E) 24 a 7 | <gadget id="calculator">6 * (4 ** 2)</gadget>
<output>96</output>
<result>C</result> | C | 96 | The edge of a cube is 4a cm. Find its surface? | {
"A": "24 a 8",
"B": "24 a 4",
"C": "96 a 2",
"D": "24 a 2",
"E": "24 a 7"
} | surface_cube(4) | surface_cube(n0)| | "6 a 2 = 6 * 4 a * 4 a = 96 a 2 answer : c" | geometry |
math_qa__Wx0KqeNtbMbAnqbP | The ratio of the present age of two brothers is 1:2 and 5 years back, the ratio was 1:3. What will be the ratio of their ages after 5 years? Choose the correct option
A) 3 : 9 B) 3 : 0 C) 3 : 5 D) 3 : 2 E) 3 : 1 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">5 + 10</gadget>
<output>15</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">5 + 20</gadget>
<output>25</output>
<gadget id="calculator">15 / 25</gadget>
<output>3/5 = around 0.6</output>
<result>C</result> | C | 0.6 | The ratio of the present age of two brothers is 1:2 and 5 years back, the ratio was 1:3. What will be the ratio of their ages after 5 years? | {
"A": "3 : 9",
"B": "3 : 0",
"C": "3 : 5",
"D": "3 : 2",
"E": "3 : 1"
} | divide(add(5, subtract(multiply(5, 3), 5)), add(5, multiply(2, subtract(multiply(5, 3), 5)))) | multiply(n2,n4)|subtract(#0,n2)|add(n2,#1)|multiply(n1,#1)|add(n2,#3)|divide(#2,#4) | let the present ages of the two brothers be x and 2 x years respectively . then , ( x - 5 ) / ( 2 x - 5 ) = 1 / 3 3 ( x - 5 ) = ( 2 x - 5 ) = > x = 10 required ratio = ( x + 5 ) : ( 2 x + 5 ) = 15 : 25 = 3 : 5 answer : c | other |
math_qa__14JBebI5tQOwPuhf | Find the least number must be subtracted from 724946 so that remaining no.is divisible by 10? Choose the correct choice from the following
A) 0
B) 2
C) 4
D) 6
E) 8 | <gadget id="calculator">724_946 / 10</gadget>
<output>362_473/5 = around 72_494.6</output>
<gadget id="calculator">floor(362_473/5)</gadget>
<output>72_494</output>
<gadget id="calculator">72_494 * 10</gadget>
<output>724_940</output>
<gadget id="calculator">724_946 - 724_940</gadget>
<output>6</output>
<result>D</result> | D | 6 | Find the least number must be subtracted from 724946 so that remaining no.is divisible by 10? | {
"A": "0",
"B": "2",
"C": "4",
"D": "6",
"E": "8"
} | subtract(724946, multiply(floor(divide(724946, 10)), 10)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)| | "on dividing 724946 by 10 we get the remainder 6 , so 6 should be subtracted d" | general |
math_qa__sQ2dKiurWfGlvtF8 | If x is 20 percent more than y and y is 30 percent less than z, then x is what percent of z? Select: A) 500 % B) 250 % C) 500 / 3 % D) 84 % E) 60 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">(6/5) * 70</gadget>
<output>84</output>
<result>D</result> | D | 84 | If x is 20 percent more than y and y is 30 percent less than z, then x is what percent of z? | {
"A": "500 %",
"B": "250 %",
"C": "500 / 3 %",
"D": "84 %",
"E": "60 %"
} | multiply(add(const_1, divide(20, const_100)), subtract(const_100, 30)) | divide(n0,const_100)|subtract(const_100,n1)|add(#0,const_1)|multiply(#2,#1)| | "z = 100 ; y = 70 so x = 84 x as % of z = 84 / 100 * 100 = > 84 % answer will be ( d )" | general |
math_qa__eXML697FMhF8fhxv | A truck covers a distance of 240 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 0 km more than that travelled by the truck ? Choose the correct choice from the following: A) 6 hours B) 5 hours C) 7 hours D) 8 hours E) none | <gadget id="calculator">240 + 0</gadget>
<output>240</output>
<gadget id="calculator">240 / 8</gadget>
<output>30</output>
<gadget id="calculator">30 + 18</gadget>
<output>48</output>
<gadget id="calculator">240 / 48</gadget>
<output>5</output>
<result>B</result> | B | 5 | A truck covers a distance of 240 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 0 km more than that travelled by the truck ? | {
"A": "6 hours",
"B": "5 hours",
"C": "7 hours",
"D": "8 hours",
"E": "none"
} | divide(add(240, 0), add(divide(240, 8), 18)) | add(n0,n3)|divide(n0,n1)|add(n2,#1)|divide(#0,#2)| | "explanation : speed of the truck = distance / time = 240 / 8 = 30 kmph now , speed of car = ( speed of truck + 18 ) kmph = ( 30 + 18 ) = 48 kmph distance travelled by car = 240 + 0 = 240 km time taken by car = distance / speed = 240 / 48 = 5 hours . answer – b" | physics |
math_qa__sggttpiOSV7Zp63n | A mixture of 180 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture? Options
A) 4 liters B) 8 liters C) 10 liters D) 12 liters E) 12.5 liters | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 180</gadget>
<output>45</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 180</gadget>
<output>36</output>
<gadget id="calculator">45 - 36</gadget>
<output>9</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">9 / (3/4)</gadget>
<output>12</output>
<result>D</result> | D | 12 | A mixture of 180 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture? | {
"A": "4 liters",
"B": "8 liters",
"C": "10 liters",
"D": "12 liters",
"E": "12.5 liters"
} | divide(subtract(multiply(divide(25, const_100), 180), multiply(divide(20, const_100), 180)), subtract(const_1, divide(25, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|multiply(n0,#1)|subtract(const_1,#0)|subtract(#2,#3)|divide(#5,#4)| | "number of liters of water in 180 liters of the mixture = 20 % of 120 = 20 / 100 * 180 = 36 liters . p liters of water added to the mixture to make water 25 % of the new mixture . total amount of water becomes ( 36 + p ) and total volume of mixture is ( 180 + p ) . ( 36 + p ) = 25 / 100 * ( 180 + p ) 96 + 4 p = 180 + p p = 12 liters . answer : d" | general |
math_qa__kZ9lthH0QgqWmMmP | The sum of all the integers k such that –23 < k < 24 is Choose the most appropriate option.
A) 0 B) - 43 C) - 25 D) - 49 E) - 51 | <gadget id="calculator">-23</gadget>
<output>-23</output>
<gadget id="calculator">(-23) + 1</gadget>
<output>-22</output>
<gadget id="calculator">(-22) + 1</gadget>
<output>-21</output>
<gadget id="calculator">(-22) + (-21)</gadget>
<output>-43</output>
<result>B</result> | B | -43 | The sum of all the integers k such that –23 < k < 24 is | {
"A": "0",
"B": "- 43",
"C": "- 25",
"D": "- 49",
"E": "- 51"
} | add(add(negate(23), const_1), add(add(negate(23), const_1), const_1)) | negate(n0)|add(#0,const_1)|add(#1,const_1)|add(#1,#2)| | "- 22 - - - - - - - - - - - - - - - - - - 0 - - - - - - - - - - - - - - - - - 23 values upto + 23 cancels outwe are left with only - 22 - 21 sum of which is - 43 . hence option d . b" | general |
math_qa__RgNJBXOkAmvR1vYY | What is the sum between the place values of three 7's in the numeral 87953.0727 Choose the correct choice from the following options: A) 21 B) 7000.0707 C) 7777 D) 7014 E) 7000.0077 | <gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">7 * 1_000</gadget>
<output>7_000</output>
<gadget id="calculator">70 + 7_000</gadget>
<output>7_070</output>
<result>B</result> | B | 7,000.0707 | What is the sum between the place values of three 7's in the numeral 87953.0727 | {
"A": "21",
"B": "7000.0707",
"C": "7777",
"D": "7014",
"E": "7000.0077"
} | add(multiply(7, const_10), multiply(7, const_1000)) | multiply(n0,const_10)|multiply(n0,const_1000)|add(#0,#1)| | "required sum = 7000 + 0.0700 + 0.0007 = 7000.0707 answer is b" | general |
math_qa__UEnZEmTxcnncUej4 | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 6 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is?
Choose the most appropriate option:
A) 23 B) 21 C) 18 D) 56 E) 12 | <gadget id="calculator">12_000 - 8_000</gadget>
<output>4_000</output>
<gadget id="calculator">6 * 4_000</gadget>
<output>24_000</output>
<gadget id="calculator">8_000 - 6_000</gadget>
<output>2_000</output>
<gadget id="calculator">24_000 / 2_000</gadget>
<output>12</output>
<gadget id="calculator">6 + 12</gadget>
<output>18</output>
<result>C</result> | C | 18 | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 6 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is? | {
"A": "23",
"B": "21",
"C": "18",
"D": "56",
"E": "12"
} | add(6, divide(multiply(6, subtract(12000, 8000)), subtract(8000, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3)| | "let the total number of workers be x . then , 8000 x = ( 12000 * 6 ) + 6000 ( x - 6 ) = > 2000 x = 36000 = x = 18 . answer : c" | general |
math_qa__W2ldBNxxoZorLbK3 | Two good train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km / hr and 30 km /hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answers
A) 12 sec B) 24 sec C) 48 sec D) 60 sec E) none | <gadget id="calculator">45 + 30</gadget>
<output>75</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">75 * (5/18)</gadget>
<output>125/6 = around 20.833333</output>
<gadget id="calculator">1 / (125/6)</gadget>
<output>6/125 = around 0.048</output>
<gadget id="calculator">500 * (6/125)</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<result>C</result> | C | 48 | Two good train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km / hr and 30 km /hr respectively. Find the time taken by the slower train to pass the driver of the faster one. | {
"A": "12 sec",
"B": "24 sec",
"C": "48 sec",
"D": "60 sec",
"E": "none"
} | multiply(multiply(500, inverse(multiply(add(45, 30), const_0_2778))), const_2) | add(n1,n2)|multiply(#0,const_0_2778)|inverse(#1)|multiply(n0,#2)|multiply(#3,const_2) | sol . relative speed = ( 45 + 30 ) km / hr = ( 75 x 5 / 18 ) m / sec = ( 125 / 6 ) m / sec . distance covered = ( 500 + 500 ) m = 1000 m . required time = ( 1000 x 6 / 125 ) sec = 48 sec . answer c | physics |
math_qa__iDhCLLOVmCvMF3Tx | In a tree, 2/5 of the birds are robins while the rest are bluejays. If 1/3 of the robins are female and 2/3 of the bluejays are female, what fraction of the birds in the tree are male? Pick
A) 3 / 5 B) 4 / 15 C) 7 / 15 D) 8 / 15 E) 17 / 30 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/5) * (2/3)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(3/5) * (1/3)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(4/15) + (1/5)</gadget>
<output>7/15 = around 0.466667</output>
<result>C</result> | C | 0.466667 | In a tree, 2/5 of the birds are robins while the rest are bluejays. If 1/3 of the robins are female and 2/3 of the bluejays are female, what fraction of the birds in the tree are male? | {
"A": "3 / 5",
"B": "4 / 15",
"C": "7 / 15",
"D": "8 / 15",
"E": "17 / 30"
} | add(multiply(divide(2, 5), divide(2, 3)), multiply(divide(const_3, 5), divide(1, 3))) | divide(n0,n1)|divide(n0,n3)|divide(const_3,n1)|divide(n2,n3)|multiply(#0,#1)|multiply(#2,#3)|add(#4,#5) | the fraction of birds that are male robins is ( 2 / 3 ) ( 2 / 5 ) = 4 / 15 . the fraction of birds that are male bluejays is ( 1 / 3 ) ( 3 / 5 ) = 1 / 5 . the total fraction of male birds is 4 / 15 + 1 / 5 = 7 / 15 . the answer is c . | general |
math_qa__6opP4IUYeoOAWe8p | What distance will be covered by a bus moving at 90 kmph in 20 seconds? Choices:
A) 500
B) 600
C) 289
D) 276
E) 207 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">90 * (5/18)</gadget>
<output>25</output>
<gadget id="calculator">25 * 20</gadget>
<output>500</output>
<result>A</result> | A | 500 | What distance will be covered by a bus moving at 90 kmph in 20 seconds? | {
"A": "500",
"B": "600",
"C": "289",
"D": "276",
"E": "207"
} | multiply(multiply(90, const_0_2778), 20) | multiply(n0,const_0_2778)|multiply(n1,#0)| | "90 kmph = 90 * 5 / 18 = 25 mps d = speed * time = 25 * 20 = 500 m . answer : a" | physics |
math_qa__wBfh7ffUSky9Sxtm | In traveling from a dormitory to a certain city, a student went 1/2 of the way by foot, 1/4 of the way by bus, and the remaining 6 kilometers by car. What is the distance, in kilometers, from the dormitory to the city?
Pick:
A) 35 B) 24 C) 14 D) 24 E) 12 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/2) + (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<result>D</result> | D | 24 | In traveling from a dormitory to a certain city, a student went 1/2 of the way by foot, 1/4 of the way by bus, and the remaining 6 kilometers by car. What is the distance, in kilometers, from the dormitory to the city? | {
"A": "35",
"B": "24",
"C": "14",
"D": "24",
"E": "12"
} | multiply(6, inverse(subtract(1, add(divide(1, 2), divide(1, 4))))) | divide(n0,n1)|divide(n2,n3)|add(#0,#1)|subtract(n0,#2)|inverse(#3)|multiply(n4,#4)| | "whole trip = distance by foot + distance by bus + distance by car x = 1 / 2 x + 1 / 4 x + 6 x - 1 / 2 x - 1 / 4 x = 6 x = 24 km option : d" | physics |
math_qa__36r3gRMMe59qJNoM | The speed of a car is 80 km in the first hour and 60 km in the second hour. What is the average speed of the car? Pick: A) 76 kmph B) 70 kmph C) 87 kmph D) 56 kmph E) 86 kmph | <gadget id="calculator">80 + 60</gadget>
<output>140</output>
<gadget id="calculator">140 / 2</gadget>
<output>70</output>
<result>B</result> | B | 70 | The speed of a car is 80 km in the first hour and 60 km in the second hour. What is the average speed of the car? | {
"A": "76 kmph",
"B": "70 kmph",
"C": "87 kmph",
"D": "56 kmph",
"E": "86 kmph"
} | divide(add(80, 60), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 80 + 60 ) / 2 = 70 kmph answer : b" | physics |
math_qa__9L16ly4KdiKGMtwv | The ratio, by volume, of bleach(B) to detergent(D) to water in a certain solution is 2 : 40 : 100. The solution will be altered so that the ratio of bleach to detergent is tripled while the ratio of detergent to water is halved. If the altered solution will contain 300 liters of water, how many liters of detergent will it contain? Answers:
A) 60
B) 50
C) 40
D) 80
E) 70 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) / 2</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">300 * (1/5)</gadget>
<output>60</output>
<result>A</result> | A | 60 | The ratio, by volume, of bleach(B) to detergent(D) to water in a certain solution is 2 : 40 : 100. The solution will be altered so that the ratio of bleach to detergent is tripled while the ratio of detergent to water is halved. If the altered solution will contain 300 liters of water, how many liters of detergent will it contain? | {
"A": "60",
"B": "50",
"C": "40",
"D": "80",
"E": "70"
} | multiply(300, divide(divide(40, 100), const_2)) | divide(n1,n2)|divide(#0,const_2)|multiply(n3,#1) | b : d : w = 2 : 40 : 100 bnew / dnew = ( 1 / 3 ) * ( 2 / 40 ) = ( 1 / 60 ) dnew / wnew = ( 1 / 2 ) * ( 40 / 100 ) = ( 1 / 5 ) wnew = 300 dnew = wnew / 5 = 300 / 5 = 60 so , answer will be a | other |
math_qa__n50m5mwC1eNMSrin | In a garden, 26 trees are planted at equal distances along a yard 400 metres long, one tree being at each end of the yard. What is the distance between two consecutive trees? Choose the correct choice from the following answers:
A) 10 B) 8 C) 12 D) 14 E) 16 | <gadget id="calculator">26 - 1</gadget>
<output>25</output>
<gadget id="calculator">400 / 25</gadget>
<output>16</output>
<result>E</result> | E | 16 | In a garden, 26 trees are planted at equal distances along a yard 400 metres long, one tree being at each end of the yard. What is the distance between two consecutive trees? | {
"A": "10",
"B": "8",
"C": "12",
"D": "14",
"E": "16"
} | divide(400, subtract(26, const_1)) | subtract(n0,const_1)|divide(n1,#0) | 26 trees have 25 gaps between them . length of each gap = 400 / 25 = 16 i . e . , distance between two consecutive trees = 16 answer is e . | physics |
math_qa__Le67ctsh6KYa9MuA | 36 men can complete a piece of work in 18 days. In how many days will 108 men complete the same work ? Choose the most appropriate option:
A) 24
B) 77
C) 6
D) 29
E) 21 | <gadget id="calculator">18 * 36</gadget>
<output>648</output>
<gadget id="calculator">648 / 108</gadget>
<output>6</output>
<result>C</result> | C | 6 | 36 men can complete a piece of work in 18 days. In how many days will 108 men complete the same work ? | {
"A": "24",
"B": "77",
"C": "6",
"D": "29",
"E": "21"
} | divide(multiply(18, 36), 108) | multiply(n0,n1)|divide(#0,n2)| | "explanation : less men , means more days { indirect proportion } let the number of days be x then , 108 : 36 : : 18 : x x = 6 answer : c ) 6 days" | physics |
math_qa__wG26QYN82jZBh5Fv | The length and breadth of a rectangle is increased by 11% and 22% respectively. What is the increase in the area?
Choose the correct answer:
A) 35.22 B) 33.52 C) 35.42 D) 36.22 E) 38.42 | <gadget id="calculator">11 + 100</gadget>
<output>111</output>
<gadget id="calculator">22 + 100</gadget>
<output>122</output>
<gadget id="calculator">111 * 122</gadget>
<output>13_542</output>
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">13_542 - 10_000</gadget>
<output>3_542</output>
<gadget id="calculator">3_542 * 100</gadget>
<output>354_200</output>
<gadget id="calculator">354_200 / 10_000</gadget>
<output>1_771/50 = around 35.42</output>
<result>C</result> | C | 35.42 | The length and breadth of a rectangle is increased by 11% and 22% respectively. What is the increase in the area? | {
"A": "35.22",
"B": "33.52",
"C": "35.42",
"D": "36.22",
"E": "38.42"
} | divide(multiply(subtract(rectangle_area(add(11, const_100), add(22, const_100)), rectangle_area(const_100, const_100)), const_100), rectangle_area(const_100, const_100)) | add(n0,const_100)|add(n1,const_100)|rectangle_area(const_100,const_100)|rectangle_area(#0,#1)|subtract(#3,#2)|multiply(#4,const_100)|divide(#5,#2)| | "100 * 100 = 10000 111 * 122 = 13542 - - - - - - - - - - - - 3542 10000 - - - - - - - 3542 100 - - - - - - - - - - 35.42 answer c" | geometry |
math_qa__ljTfysnRPXm0JYlG | The simple interest on a sum of money will be Rs.700 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? Choose the correct choice from the following choices
A) 2261 B) 2888 C) 1400 D) 2699 E) 2771 | <gadget id="calculator">700 / 10</gadget>
<output>70</output>
<gadget id="calculator">70 * 5</gadget>
<output>350</output>
<gadget id="calculator">350 * 3</gadget>
<output>1_050</output>
<gadget id="calculator">1_050 + 350</gadget>
<output>1_400</output>
<result>C</result> | C | 1,400 | The simple interest on a sum of money will be Rs.700 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? | {
"A": "2261",
"B": "2888",
"C": "1400",
"D": "2699",
"E": "2771"
} | add(multiply(multiply(divide(700, 10), 5), const_3), multiply(divide(700, 10), 5)) | divide(n0,n1)|multiply(n2,#0)|multiply(#1,const_3)|add(#2,#1)| | "p - - - 10 - - - - 700 p - - - 5 - - - - - 350 3 p - - - 5 - - - - - 1050 - - - - - - = > 1400 answer : c" | general |
math_qa__fvyHw1wdN2ZQOp8V | Barbata invests $2000 in the National Bank at 5%. How much additional money must she invest at 8% so that the total annual income will be equal to 6% of her entire investment?
Choices.
A) 1200 B) 3000 C) 1000 D) 3600 E) 2400 | <gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 2_000</gadget>
<output>120</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">2_000 * (1/20)</gadget>
<output>100</output>
<gadget id="calculator">120 - 100</gadget>
<output>20</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/25) - (3/50)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">20 / (1/50)</gadget>
<output>1_000</output>
<result>C</result> | C | 1,000 | Barbata invests $2000 in the National Bank at 5%. How much additional money must she invest at 8% so that the total annual income will be equal to 6% of her entire investment? | {
"A": "1200",
"B": "3000",
"C": "1000",
"D": "3600",
"E": "2400"
} | divide(subtract(multiply(divide(6, const_100), 2000), multiply(2000, divide(5, const_100))), subtract(divide(8, const_100), divide(6, const_100))) | divide(n3,const_100)|divide(n1,const_100)|divide(n2,const_100)|multiply(n0,#0)|multiply(n0,#1)|subtract(#2,#0)|subtract(#3,#4)|divide(#6,#5)| | "let the additional invested amount for 8 % interest be x ; equation will be ; 2000 + 0.05 * 2000 + x + 0.08 x = 2000 + x + 0.06 ( 2000 + x ) 0.05 * 2000 + 0.08 x = 0.06 x + 0.06 * 2000 0.02 x = 2000 ( 0.06 - 0.05 ) x = 2000 * 0.01 / 0.02 = 1000 ans : ` ` c ' '" | general |
math_qa__HrnBoFfVlrE4skyE | Two trains start simultaneously from opposite ends of a 150-km route and travel toward each other on parallel tracks. Train X, traveling at a constant rate, completes the 150-km trip in 4 hours. Train Y, travelling at a constant rate, completes the 150-km trip in 3.5 hours. How many kilometers had Train X traveled when it met Train Y? Choose the correct choice from the following options.
A) 68
B) 70
C) 72
D) 74
E) 76 | <gadget id="calculator">150 / 4</gadget>
<output>75/2 = around 37.5</output>
<gadget id="calculator">150 / 3.5</gadget>
<output>42.857143</output>
<gadget id="calculator">(75/2) + 42.857143</gadget>
<output>80.357143</output>
<gadget id="calculator">150 / 80.357143</gadget>
<output>1.866667</output>
<gadget id="calculator">(75/2) * 1.866667</gadget>
<output>70.000012</output>
<result>B</result> | B | 70 | Two trains start simultaneously from opposite ends of a 150-km route and travel toward each other on parallel tracks. Train X, traveling at a constant rate, completes the 150-km trip in 4 hours. Train Y, travelling at a constant rate, completes the 150-km trip in 3.5 hours. How many kilometers had Train X traveled when it met Train Y? | {
"A": "68",
"B": "70",
"C": "72",
"D": "74",
"E": "76"
} | multiply(divide(150, 4), divide(150, add(divide(150, 4), divide(150, 3.5)))) | divide(n0,n2)|divide(n0,n4)|add(#0,#1)|divide(n0,#2)|multiply(#0,#3) | if the two trains cover a total distance d , then train x travels ( 7 / 15 ) * d while train y travels ( 8 / 15 ) * d . if the trains travel 150 km to the meeting point , then train x travels ( 7 / 15 ) * 150 = 70 km . the answer is b . | physics |
math_qa__FhP6kijdYAqg7jNr | ((1^(m+1))/(5^(m+1)))((1^18)/(4^18)) = 1/(2(10)^35)
What is m?
Choose the correct choice from the following options
A) 17 B) 18 C) 34 D) 35 E) 36 | <gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">36 - 1</gadget>
<output>35</output>
<gadget id="calculator">35 - 1</gadget>
<output>34</output>
<result>C</result> | C | 34 | ((1^(m+1))/(5^(m+1)))((1^18)/(4^18)) = 1/(2(10)^35)
What is m? | {
"A": "17",
"B": "18",
"C": "34",
"D": "35",
"E": "36"
} | subtract(subtract(multiply(18, 2), const_1), 1) | multiply(n5,n9)|subtract(#0,const_1)|subtract(#1,n0) | ( ( 1 ^ ( m + 1 ) ) / ( 5 ^ ( m + 1 ) ) ) ( ( 1 ^ 18 ) / ( 4 ^ 18 ) ) = 1 / ( 2 ( 10 ) ^ 35 ) ( ( 1 / 5 ) ^ ( m + 1 ) ) * ( ( 1 / 2 ) ^ 36 ) = 1 / ( 2 * ( 2 * 5 ) ^ 35 ) ) 2 ^ 36 will cancel out , since 1 can be written as 1 ^ 35 , so ( 1 / 5 ) ^ ( m + 1 ) = ( 1 / 5 ) ^ 35 ( ( 1 / 5 ) ^ ( m + 1 ) ) * ( ( 1 / 2 ) ^ 36 ) = 1 / [ ( 2 ^ 36 ) * ( 5 ^ 35 ) ] so , m = 34 answer c | general |
math_qa__DD0cC2sOZ6rwObGz | A student chose a number, multiplied it by 2, then subtracted 138 from the result and got 106. What was the number he chose? Answers:
A) 123 B) 267 C) 277 D) 122 E) 120 | <gadget id="calculator">106 + 138</gadget>
<output>244</output>
<gadget id="calculator">244 / 2</gadget>
<output>122</output>
<result>D</result> | D | 122 | A student chose a number, multiplied it by 2, then subtracted 138 from the result and got 106. What was the number he chose? | {
"A": "123",
"B": "267",
"C": "277",
"D": "122",
"E": "120"
} | divide(add(106, 138), 2) | add(n1,n2)|divide(#0,n0)| | "let xx be the number he chose , then 2 â ‹ … x â ˆ ’ 138 = 106 x = 122 answer : d" | general |
math_qa__DX5nGu1tbmiBmWEG | If the cost price is 98% of sp then what is the profit %
Options:
A) 4.07 %
B) 4 %
C) 2.7 %
D) 2.04 %
E) 2.08 % | <gadget id="calculator">100 - 98</gadget>
<output>2</output>
<gadget id="calculator">2 / 98</gadget>
<output>1/49 = around 0.020408</output>
<gadget id="calculator">(1/49) * 100</gadget>
<output>100/49 = around 2.040816</output>
<result>D</result> | D | 2.04 | If the cost price is 98% of sp then what is the profit % | {
"A": "4.07 %",
"B": "4 %",
"C": "2.7 %",
"D": "2.04 %",
"E": "2.08 %"
} | multiply(divide(subtract(const_100, 98), 98), const_100) | subtract(const_100,n0)|divide(#0,n0)|multiply(#1,const_100)| | "sol . sp = rs 100 : then cp = rs 98 : profit = rs 2 . profit = { ( 2 / 98 ) * 100 } % = 2.04 % answer is d ." | gain |
math_qa__xdaAhkG19uYmttzq | The banker’s discount of a certain sum of money is Rs. 78 and the true discount on the same sum for the same time is Rs. 66. The sum due is Choose the correct choice from the following options: A) 429 B) 280 C) 360 D) 450 E) none | <gadget id="calculator">78 * 66</gadget>
<output>5_148</output>
<gadget id="calculator">78 - 66</gadget>
<output>12</output>
<gadget id="calculator">5_148 / 12</gadget>
<output>429</output>
<result>A</result> | A | 429 | The banker’s discount of a certain sum of money is Rs. 78 and the true discount on the same sum for the same time is Rs. 66. The sum due is | {
"A": "429",
"B": "280",
"C": "360",
"D": "450",
"E": "none"
} | divide(multiply(78, 66), subtract(78, 66)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1) | sol . sum = b . d . * t . d . / b . d . - t . d . = rs . [ 78 * 66 / 78 - 66 ] = rs . [ 78 * 66 / 12 ] = rs . 429 answer a | gain |
math_qa__PjAGOzBe8wh8WHDN | A charitable association sold an average of 66 raffle tickets per member. Among the female members, the average was 70 raffle tickets. The male to female ratio of the association is 1:2. What was the average number Q of tickets sold by the male members of the association Select.
A) 50 B) 56 C) 58 D) 62 E) 66 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">66 * 3</gadget>
<output>198</output>
<gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">198 - 140</gadget>
<output>58</output>
<result>C</result> | C | 58 | A charitable association sold an average of 66 raffle tickets per member. Among the female members, the average was 70 raffle tickets. The male to female ratio of the association is 1:2. What was the average number Q of tickets sold by the male members of the association | {
"A": "50",
"B": "56",
"C": "58",
"D": "62",
"E": "66"
} | subtract(multiply(66, add(1, 2)), multiply(70, 2)) | add(n2,n3)|multiply(n1,n3)|multiply(n0,#0)|subtract(#2,#1)| | "given that , total average q sold is 66 , male / female = 1 / 2 and female average is 70 . average of male members isx . ( 70 * f + x * m ) / ( m + f ) = 66 - > solving this equation after substituting 2 m = f , x = 58 . ans c ." | general |
math_qa__NwYM6lhBAzzUBl0j | Subtract the absolute value from the local value of 4 in 564823
Choose the correct option:
A) 196 B) 1996 C) 2996 D) 3996 E) 6000 | <gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">400 * 10</gadget>
<output>4_000</output>
<result>D</result> | D | 3,996 | Subtract the absolute value from the local value of 4 in 564823 | {
"A": "196",
"B": "1996",
"C": "2996",
"D": "3996",
"E": "6000"
} | multiply(multiply(4, const_100), const_10) | multiply(n0,const_100)|multiply(#0,const_10) | explanation : place value = local value face value = absolute value the place value of 4 in 564823 is 4 x 1000 = 4000 the face value of 4 in 564823 is nothing but 4 . = > 4000 - 4 = 3996 answer : option d | general |
math_qa__PkN5j1XRcBEHJSP0 | Machine A and machine G are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine G. Machine G produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces? Choose the correct choice from the following answers.
A) 6 B) 6.6 C) 60 D) 100 E) 110 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) * 660</gadget>
<output>726</output>
<gadget id="calculator">726 * 10</gadget>
<output>7_260</output>
<gadget id="calculator">726 - 660</gadget>
<output>66</output>
<gadget id="calculator">7_260 / 66</gadget>
<output>110</output>
<gadget id="calculator">660 / 110</gadget>
<output>6</output>
<result>A</result> | A | 6 | Machine A and machine G are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine G. Machine G produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces? | {
"A": "6",
"B": "6.6",
"C": "60",
"D": "100",
"E": "110"
} | divide(660, divide(multiply(multiply(add(divide(10, const_100), const_1), 660), 10), subtract(multiply(add(divide(10, const_100), const_1), 660), 660))) | divide(n1,const_100)|add(#0,const_1)|multiply(n0,#1)|multiply(n1,#2)|subtract(#2,n0)|divide(#3,#4)|divide(n0,#5) | [ reveal ] spoiler : timeg : 660 / x timea : [ 660 / x + 10 ] 660 / x = [ 660 / x + 10 ] * 110 / 100 660 / x = 66 * 11 / x + 10 660 x + 10 = 66 * 11 * x 660 x + 6600 = 66 * 11 * x x = 100 plug in back to timea 660 / 100 + 10 = > 660 / 110 = 6 | gain |
math_qa__oBDXxtrFrLzx8CVq | Machine X and machine B are each used to manufacture 660 sprockets. It takes machine X 10 hours longer to produce 660 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine X. How many sprockets per hour does machine X produces? Select:
A) 6
B) 6.6
C) 60
D) 100
E) 110 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) * 100</gadget>
<output>110</output>
<gadget id="calculator">660 / 110</gadget>
<output>6</output>
<result>A</result> | A | 6 | Machine X and machine B are each used to manufacture 660 sprockets. It takes machine X 10 hours longer to produce 660 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine X. How many sprockets per hour does machine X produces? | {
"A": "6",
"B": "6.6",
"C": "60",
"D": "100",
"E": "110"
} | divide(660, multiply(add(const_1, divide(10, const_100)), const_100)) | divide(n1,const_100)|add(#0,const_1)|multiply(#1,const_100)|divide(n0,#2) | i think the correct answer is a . machine x produces at a speed of x sp / hour and b at a speed of b sp / hour . so , 660 / x = ( 660 / b ) + 10 and x = 1,1 x - - - > 1,1 * 660 = 660 + 11 x - - - > a = 6 , so answer a is correct | general |
math_qa__AoUSd0WSH7ccwKYg | A can do a piece of work in 2 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it? Choose the most appropriate option
A) 12
B) 9
C) 8
D) 6
E) 3 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) - (1/2)</gadget>
<output>0</output>
<gadget id="calculator">(1/3) - 0</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / (1/3)</gadget>
<output>3</output>
<result>E</result> | E | 3 | A can do a piece of work in 2 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it? | {
"A": "12",
"B": "9",
"C": "8",
"D": "6",
"E": "3"
} | divide(const_1, subtract(divide(const_1, 3), subtract(divide(const_1, 2), divide(const_1, 2)))) | divide(const_1,n1)|divide(const_1,n2)|divide(const_1,n0)|subtract(#1,#2)|subtract(#0,#3)|divide(const_1,#4)| | "a ' s 1 hour ' s work = 1 / 2 ; ( b + c ) ' s 1 hour ' s work = 1 / 3 ; ( a + c ) ' s 1 hour ' s work = 1 / 2 . ( a + b + c ) ' s 1 hour ' s work = ( 1 / 2 + 1 / 3 ) = 5 / 6 . b ' s 1 hour ' s work = ( 5 / 6 - 1 / 2 ) = 1 / 3 . therefore a alone will take 3 hours to do the work . e" | physics |
math_qa__VuGl707zsJRWViMc | The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person Choices
A) 11 B) 66 C) 28 D) 30 E) 99 | <gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">16 - 6</gadget>
<output>10</output>
<gadget id="calculator">18 + 10</gadget>
<output>28</output>
<gadget id="calculator">28 / 2</gadget>
<output>14</output>
<gadget id="calculator">14 + 16</gadget>
<output>30</output>
<result>D</result> | D | 30 | The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person | {
"A": "11",
"B": "66",
"C": "28",
"D": "30",
"E": "99"
} | add(divide(add(multiply(3, 6), subtract(16, 6)), const_2), 16) | multiply(n1,n2)|subtract(n0,n1)|add(#0,#1)|divide(#2,const_2)|add(n0,#3)| | "let ' s take the present age of the elder person = x and the present age of the younger person = x – 16 ( x – 6 ) = 3 ( x - 16 - 6 ) = > x – 6 = 3 x – 66 = > 2 x = 60 = > x = 60 / 2 = 30 answer : d" | general |
math_qa__1t180BeKBLvEC9y6 | In one alloy there is 12% chromium while in another alloy it is 8%. 10 kg of the first alloy was melted together with 30 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy. Choose the correct answer.
A) 9.4 % B) 9.6 % C) 9 % D) 9.8 % E) 10 % | <gadget id="calculator">12 * 10</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">8 * 30</gadget>
<output>240</output>
<gadget id="calculator">240 / 100</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(6/5) + (12/5)</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">10 + 30</gadget>
<output>40</output>
<gadget id="calculator">(18/5) / 40</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">(9/100) * 100</gadget>
<output>9</output>
<result>C</result> | C | 9 | In one alloy there is 12% chromium while in another alloy it is 8%. 10 kg of the first alloy was melted together with 30 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy. | {
"A": "9.4 %",
"B": "9.6 %",
"C": "9 %",
"D": "9.8 %",
"E": "10 %"
} | multiply(divide(add(divide(multiply(12, 10), const_100), divide(multiply(8, 30), const_100)), add(10, 30)), const_100) | add(n2,n3)|multiply(n0,n2)|multiply(n1,n3)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100)| | "the amount of chromium in the new 10 + 30 = 40 kg alloy is 0.12 * 10 + 0.08 * 30 = 3.6 kg , so the percentage is 3.6 / 40 * 100 = 9 % . answer : c" | gain |
math_qa__9Zb2VPlO0lXY1DE2 | an automotive test consisted of driving a car the same distance 3 separate times , first at an average rate of 4 miles per hour , then 5 miles per hour , then 6 miles per hour . if the test took 37 hours to complete , how many miles was the car driven during the entire test ? Select the correct option: A) 100 B) 120 C) 180 D) 200 E) 240 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/4) + (1/5)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(1/6) + (9/20)</gadget>
<output>37/60 = around 0.616667</output>
<gadget id="calculator">37 / (37/60)</gadget>
<output>60</output>
<gadget id="calculator">60 * 3</gadget>
<output>180</output>
<result>C</result> | C | 180 | an automotive test consisted of driving a car the same distance 3 separate times , first at an average rate of 4 miles per hour , then 5 miles per hour , then 6 miles per hour . if the test took 37 hours to complete , how many miles was the car driven during the entire test ? | {
"A": "100",
"B": "120",
"C": "180",
"D": "200",
"E": "240"
} | multiply(divide(37, add(divide(const_1, 6), add(divide(const_1, 4), divide(const_1, 5)))), const_3) | divide(const_1,n1)|divide(const_1,n2)|divide(const_1,n3)|add(#0,#1)|add(#3,#2)|divide(n4,#4)|multiply(#5,const_3) | x is the segment to be traveled x / 4 + x / 5 + x / 6 = 37 or 74 x / 120 = 37 x = 60 miles . total distance = 3 * 60 = 180 miles c | physics |
math_qa__8adNM2gvsv7MvTD2 | A can do a work in 12 days. B can do the same work in 24 days. If both A & B are working together in how many days they will finish the work? Choose the correct choice from the following choices.
A) 3 B) 5 C) 8 D) 2 E) 6 | <gadget id="calculator">12 * 24</gadget>
<output>288</output>
<gadget id="calculator">12 + 24</gadget>
<output>36</output>
<gadget id="calculator">288 / 36</gadget>
<output>8</output>
<result>C</result> | C | 8 | A can do a work in 12 days. B can do the same work in 24 days. If both A & B are working together in how many days they will finish the work? | {
"A": "3",
"B": "5",
"C": "8",
"D": "2",
"E": "6"
} | divide(multiply(12, 24), add(12, 24)) | add(n0,n1)|multiply(n0,n1)|divide(#1,#0)| | "a rate = 1 / 12 b rate = 1 / 24 ( a + b ) rate = ( 1 / 12 ) + ( 1 / 24 ) = 1 / 8 a & b finish the work in 8 days correct option is c" | physics |
math_qa__sueGCwp4cidqaCOl | The average of 5 quantities is 10. The average of 3 of them is 4. What is the average of remaining 2 numbers? Choose the correct choice from the following choices.
A) 19 B) 14 C) 8 D) 9.5 E) none of these | <gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">50 - 12</gadget>
<output>38</output>
<gadget id="calculator">38 / 2</gadget>
<output>19</output>
<result>A</result> | A | 19 | The average of 5 quantities is 10. The average of 3 of them is 4. What is the average of remaining 2 numbers? | {
"A": "19",
"B": "14",
"C": "8",
"D": "9.5",
"E": "none of these"
} | divide(subtract(multiply(5, 10), multiply(3, 4)), 2) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)|divide(#2,n4) | answer : a ( 5 x 10 - 3 x 4 ) / 2 = 19 | general |
math_qa__zQKGpOkAj1a2q1co | A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 70 paise per sq m is Select the correct option:
A) rs . 258.80
B) rs . 358.80
C) rs . 458.80
D) rs . 520.80
E) none of these | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">25 * 12</gadget>
<output>300</output>
<gadget id="calculator">25 * 6</gadget>
<output>150</output>
<gadget id="calculator">2 * 150</gadget>
<output>300</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<gadget id="calculator">72 * 2</gadget>
<output>144</output>
<gadget id="calculator">300 + 144</gadget>
<output>444</output>
<gadget id="calculator">300 + 444</gadget>
<output>744</output>
<gadget id="calculator">(7/10) * 744</gadget>
<output>2_604/5 = around 520.8</output>
<result>D</result> | D | 520.8 | A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 70 paise per sq m is | {
"A": "rs . 258.80",
"B": "rs . 358.80",
"C": "rs . 458.80",
"D": "rs . 520.80",
"E": "none of these"
} | multiply(divide(70, const_100), add(multiply(25, 12), add(multiply(const_2, multiply(25, 6)), multiply(multiply(12, 6), const_2)))) | divide(n3,const_100)|multiply(n0,n2)|multiply(n1,n2)|multiply(n0,n1)|multiply(#1,const_2)|multiply(#2,const_2)|add(#4,#5)|add(#6,#3)|multiply(#7,#0)| | "explanation : area to be plastered = [ 2 ( l + b ) ã — h ] + ( l ã — b ) = [ 2 ( 25 + 12 ) ã — 6 ] + ( 25 ã — 12 ) = 744 sq m cost of plastering = 744 ã — ( 70 / 100 ) = rs . 520.80 answer : d" | physics |
math_qa__iJftt51vt7WSuvFV | If the sum of two numbers is 22 and the sum of their squares is 460, then the product of the numbers is Choose the correct choice from the following options:
A) 40 B) 44 C) 12 D) 88 E) 48 | <gadget id="calculator">22 ** 2</gadget>
<output>484</output>
<gadget id="calculator">484 - 460</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<result>C</result> | C | 12 | If the sum of two numbers is 22 and the sum of their squares is 460, then the product of the numbers is | {
"A": "40",
"B": "44",
"C": "12",
"D": "88",
"E": "48"
} | divide(subtract(power(22, const_2), 460), const_2) | power(n0,const_2)|subtract(#0,n1)|divide(#1,const_2)| | "according to the given conditions x + y = 22 and x ^ 2 + y ^ 2 = 460 now ( x + y ) ^ 2 = x ^ 2 + y ^ 2 + 2 xy so 22 ^ 2 = 460 + 2 xy so xy = 24 / 2 = 12 answer : c" | general |
math_qa__DYZ1kRPJNtkjWU6a | What is the value of n if the sum of the consecutive odd integers from 1 to n equals 169? Choices.
A) 47
B) 25
C) 37
D) 33
E) 29 | <gadget id="calculator">169 ** (1/2)</gadget>
<output>13</output>
<gadget id="calculator">13 * 2</gadget>
<output>26</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">26 - 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<result>B</result> | B | 25 | What is the value of n if the sum of the consecutive odd integers from 1 to n equals 169? | {
"A": "47",
"B": "25",
"C": "37",
"D": "33",
"E": "29"
} | add(subtract(multiply(sqrt(169), const_2), multiply(const_2, 1)), 1) | multiply(n0,const_2)|sqrt(n1)|multiply(#1,const_2)|subtract(#2,#0)|add(n0,#3) | # of terms = ( n - 1 / 2 ) + 1 { ( last term - first term ) / 2 + 1 | sum = ( 1 + n ) / 2 * # of terms = ( n + 1 ) ^ 2 / 4 = 169 n + 1 = 13 * 2 n + 1 = 26 n = 25 . answer : b | general |
math_qa__aUJG664fBv9fxtY9 | The total number of plums that grew during each year on a certain plum tree was equal to the number of plums that grew during the previous year, less the age of the tree in years (rounded to the nearest lower integer.) During its 3rd year, this plum tree grew 50 plums. How many plums did it grow during its 6th year? Pick
A) 41
B) 38
C) 35
D) 29
E) 28 | <gadget id="calculator">50 - 4</gadget>
<output>46</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">46 - 5</gadget>
<output>41</output>
<gadget id="calculator">41 - 6</gadget>
<output>35</output>
<result>C</result> | C | 35 | The total number of plums that grew during each year on a certain plum tree was equal to the number of plums that grew during the previous year, less the age of the tree in years (rounded to the nearest lower integer.) During its 3rd year, this plum tree grew 50 plums. How many plums did it grow during its 6th year? | {
"A": "41",
"B": "38",
"C": "35",
"D": "29",
"E": "28"
} | subtract(subtract(subtract(50, const_4), add(const_4, const_1)), 6) | add(const_1,const_4)|subtract(n1,const_4)|subtract(#1,#0)|subtract(#2,n2) | the answer shud be 38 . ( 50 - 3 - 4 - 5 = 38 ) yes , if you go the 50 - 3 way , then it will be 38 . if instead you go the 50 - 4 way ( which they have suggested ) , the answer will be 35 . as i said , there is ambiguity here . answer is c | general |
math_qa__oZaH1bKDDSxhhiS0 | A can finish a work in 8 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day?
Pick
A) 3 / 5 B) 3 / 6 C) 3 / 7 D) 3 / 8 E) none of these | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/8) + (1/4)</gadget>
<output>3/8 = around 0.375</output>
<result>D</result> | D | 0.375 | A can finish a work in 8 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day? | {
"A": "3 / 5",
"B": "3 / 6",
"C": "3 / 7",
"D": "3 / 8",
"E": "none of these"
} | add(divide(const_1, 8), multiply(divide(const_1, 8), const_2)) | divide(const_1,n0)|multiply(#0,const_2)|add(#0,#1)| | "explanation : please note in this question , we need to answer part of work for a day rather than complete work . it was worth mentioning here because many do mistake at this point in hurry to solve the question so lets solve now , a ' s 1 day work = 1 / 8 b ' s 1 day work = 1 / 4 [ because b take half the time than a ] ( a + b ) ' s one day work = ( 1 / 8 + 1 / 4 ) = 3 / 8 so in one day 3 / 8 work will be done answer : d" | physics |
math_qa__INKwDgIcZzidIAw3 | Donovan and Michael are racing around a circular 500-meter track. If Donovan runs each lap in 45 seconds and Michael runs each lap in 40 seconds, how many laps will Michael have to complete in order to pass Donovan, assuming they start at the same time? Options
A) 9 B) 10 C) 11 D) 12 E) 13 | <gadget id="calculator">500 / 40</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">500 / 45</gadget>
<output>100/9 = around 11.111111</output>
<gadget id="calculator">(25/2) - (100/9)</gadget>
<output>25/18 = around 1.388889</output>
<gadget id="calculator">500 / (25/18)</gadget>
<output>360</output>
<gadget id="calculator">360 / 40</gadget>
<output>9</output>
<result>A</result> | A | 9 | Donovan and Michael are racing around a circular 500-meter track. If Donovan runs each lap in 45 seconds and Michael runs each lap in 40 seconds, how many laps will Michael have to complete in order to pass Donovan, assuming they start at the same time? | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "13"
} | divide(divide(500, subtract(divide(500, 40), divide(500, 45))), 40) | divide(n0,n2)|divide(n0,n1)|subtract(#0,#1)|divide(n0,#2)|divide(#3,n2)| | "one way of approaching this question is by relative speed method 1 . speed / rate of donovan = distance / time = > 500 / 45 = > 100 / 9 2 . speed / rate of michael = distance / time = > 500 / 40 = > 50 / 4 relative speed between them = 50 / 4 - 100 / 9 = > 25 / 36 ( we subtract the rates if moving in the same direction and add the rates if moving in the opposite direction ) in order to pass donovan - distance to be covered = 500 , relative rate = 50 / 36 total time taken by micheal to surpass donovan = distance / rate = > 500 * 36 / 50 = > 3600 / 10 = > 360 no . of laps taken by michael = total time / michael ' s rate = > 360 / 40 = > 9 hence correct answer is 9 laps . a" | physics |
math_qa__MJs89SP0EHjPBLZr | If m = ||n – 3| – 2|, for how many values of n is m = 6? Select.
A) 1
B) 3
C) 4
D) 5
E) 2 | <gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<result>E</result> | E | 2 | If m = ||n – 3| – 2|, for how many values of n is m = 6? | {
"A": "1",
"B": "3",
"C": "4",
"D": "5",
"E": "2"
} | subtract(add(6, 2), 6) | add(n1,n2)|subtract(#0,n2)| | "m = | | n – 3 | – 2 | can be 4 only and only when n - 3 = + / - 8 . so there are 2 values of n answer : e" | physics |
math_qa__vzVuZwD4r2QbptIs | In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of:
Choose the correct choice from the following
A) 3488
B) 6240
C) 2776
D) 2889
E) 7721 | <gadget id="calculator">96 / 10</gadget>
<output>48/5 = around 9.6</output>
<gadget id="calculator">(48/5) * 650</gadget>
<output>6_240</output>
<result>B</result> | B | 6,240 | In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of: | {
"A": "3488",
"B": "6240",
"C": "2776",
"D": "2889",
"E": "7721"
} | multiply(divide(96, 10), 650) | divide(n2,n1)|multiply(n0,#0)| | "explanation : to obtain rs . 10 , investment = rs . 96 . to obtain rs . 650 , investment = = rs . 6240 answer : b ) 6240" | gain |
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