id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__vKpRwtWNdmJFVrTv | Divide Rs. 1301 between A and B, so that the amount of A after 7 years is equal to the amount of B after 9 years, the interest being compounded at 4% per annum. Answers
A) 625
B) 367
C) 288
D) 209
E) 198 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 9</gadget>
<output>5_429_503_678_976/3_814_697_265_625 = around 1.423312</output>
<gadget id="calculator">(26/25) ** 7</gadget>
<output>8_031_810_176/6_103_515_625 = around 1.315932</output>
<gadget id="calculator">(5_429_503_678_976/3_814_697_265_625) / (8_031_810_176/6_103_515_625)</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">1 + (676/625)</gadget>
<output>1_301/625 = around 2.0816</output>
<gadget id="calculator">1_301 / (1_301/625)</gadget>
<output>625</output>
<result>A</result> | A | 625 | Divide Rs. 1301 between A and B, so that the amount of A after 7 years is equal to the amount of B after 9 years, the interest being compounded at 4% per annum. | {
"A": "625",
"B": "367",
"C": "288",
"D": "209",
"E": "198"
} | divide(1301, add(const_1, divide(power(add(const_1, divide(4, const_100)), 9), power(add(const_1, divide(4, const_100)), 7)))) | divide(n3,const_100)|add(#0,const_1)|power(#1,n2)|power(#1,n1)|divide(#2,#3)|add(#4,const_1)|divide(n0,#5) | explanation : let the two parts be rs . x and rs . ( 1301 - x ) . 625 x = 676 ( 1301 - x ) 1301 x = 676 x 1301 x = 676 . so , the parts are rs . 676 and rs . ( 1301 - 676 ) i . e rs . 676 and rs . 625 answer : a ) rs . 625 | gain |
math_qa__kaMVBcjRk5AfudPV | Heinz produces tomato puree by boiling tomato juice. The tomato puree has only 20% water while the tomato juice has 90% water. How many liters of tomato puree will be obtained from 40 litres of tomato juice? Choose the most appropriate option.
A) 2.8 liters . B) 2.5 liters . C) 5 liters . D) 2.6 liters . E) 2.1 liters . | <gadget id="calculator">100 - 90</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 40</gadget>
<output>4</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">4 / (4/5)</gadget>
<output>5</output>
<result>C</result> | C | 5 | Heinz produces tomato puree by boiling tomato juice. The tomato puree has only 20% water while the tomato juice has 90% water. How many liters of tomato puree will be obtained from 40 litres of tomato juice? | {
"A": "2.8 liters .",
"B": "2.5 liters .",
"C": "5 liters .",
"D": "2.6 liters .",
"E": "2.1 liters ."
} | divide(multiply(divide(subtract(const_100, 90), const_100), 40), divide(subtract(const_100, 20), const_100)) | subtract(const_100,n1)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,const_100)|multiply(n2,#2)|divide(#4,#3)| | "answer : explanation : in each of the solutions , there is a pure tomato component and some water . so while boiling , water evaporates but tomato not . so we equate tomato part in the both equations . â ‡ ’ â ‡ ’ 10 % ( 40 ) = 80 % ( x ) â ‡ ’ â ‡ ’ x = 5 liters . answer : c" | gain |
math_qa__C6I6TqZ5ejI0IuqU | David works at a resort from the beginning of March to the end of September. During the month of August this past year, he made 4 times the average (arithmetic mean) of his monthly totals in tips for the other months. His total tips for August were what fraction of his total tips for all of the months he worked? Answers: A) 3 / 5 B) 2 / 5 C) 4 / 5 D) 1 / 5 E) 6 / 5 | <gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<result>B</result> | B | 0.4 | David works at a resort from the beginning of March to the end of September. During the month of August this past year, he made 4 times the average (arithmetic mean) of his monthly totals in tips for the other months. His total tips for August were what fraction of his total tips for all of the months he worked? | {
"A": "3 / 5",
"B": "2 / 5",
"C": "4 / 5",
"D": "1 / 5",
"E": "6 / 5"
} | divide(4, add(subtract(const_10, 4), 4)) | subtract(const_10,n0)|add(n0,#0)|divide(n0,#1) | first notice the number of months for which he worked - march to sept i . e . 7 months avg of monthly totals in tips for months other than august = x tips in august = 4 x total tips for all months = 6 * x + 4 x = 10 x tips for august / total tips for all months = 4 x / 10 x = 2 / 5 answer : b | general |
math_qa__kQnCeuztDOBbTJbN | A train 330 metres long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in : Choose the correct option: A) 30 sec B) 32 sec C) 36 sec D) 38 sec E) 44 sec | <gadget id="calculator">330 / 1_000</gadget>
<output>33/100 = around 0.33</output>
<gadget id="calculator">25 + 2</gadget>
<output>27</output>
<gadget id="calculator">(33/100) / 27</gadget>
<output>11/900 = around 0.012222</output>
<gadget id="calculator">3_600 * (11/900)</gadget>
<output>44</output>
<result>E</result> | E | 44 | A train 330 metres long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in : | {
"A": "30 sec",
"B": "32 sec",
"C": "36 sec",
"D": "38 sec",
"E": "44 sec"
} | multiply(const_3600, divide(divide(330, const_1000), add(25, 2))) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_3600)| | "relative speed = ( 25 + 2 ) km / hr = 27 km / hr = ( 27 × 5 / 18 ) m / sec = 15 / 2 m / sec . time taken by the train to pass the man = ( 330 × 2 / 15 ) sec = 44 sec answer : e" | physics |
math_qa__nBvk8twakhmE4vDx | Walking at 4/5 of her normal speed, a worker is 15 minutes later than usual in reaching her office. The usual time (in minutes) taken by her to cover the distance between her home and her office is Choose the correct option.
A) 45 B) 50 C) 55 D) 60 E) 65 | <gadget id="calculator">4 * 15</gadget>
<output>60</output>
<result>D</result> | D | 60 | Walking at 4/5 of her normal speed, a worker is 15 minutes later than usual in reaching her office. The usual time (in minutes) taken by her to cover the distance between her home and her office is | {
"A": "45",
"B": "50",
"C": "55",
"D": "60",
"E": "65"
} | multiply(4, 15) | multiply(n0,n2)| | "let v be her normal speed and let t be her normal time . d = ( 4 / 5 ) v * ( t + 15 ) since the distance is the same we can equate this to a regular day which is d = v * t v * t = ( 4 / 5 ) v * ( t + 15 ) t / 5 = 12 t = 60 the answer is d ." | physics |
math_qa__6HRoiegWGihqXzrh | A cylinder of height h is 8/9 of water. When all of the water is poured into an empty cylinder whose radius is 25 percent larger than that of the original cylinder, the new cylinder is 3/5 full. The height of the new cylinder is what percent of h? Options: A) 25 % B) 50 % C) 68 % D) 80 % E) 100 % | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">8 / 9</gadget>
<output>8/9 = around 0.888889</output>
<gadget id="calculator">(3/5) / (8/9)</gadget>
<output>27/40 = around 0.675</output>
<gadget id="calculator">(27/40) * 100</gadget>
<output>135/2 = around 67.5</output>
<result>C</result> | C | 68 | A cylinder of height h is 8/9 of water. When all of the water is poured into an empty cylinder whose radius is 25 percent larger than that of the original cylinder, the new cylinder is 3/5 full. The height of the new cylinder is what percent of h? | {
"A": "25 %",
"B": "50 %",
"C": "68 %",
"D": "80 %",
"E": "100 %"
} | multiply(divide(divide(3, 5), divide(8, 9)), const_100) | divide(n3,n4)|divide(n0,n1)|divide(#0,#1)|multiply(#2,const_100) | basically we can disregard the radius is 25 % information , as we are only asked about the height of the original and the new cylinder . this is becausethe new cylinder is 3 / 5 fullmeans the same as that it ' s height is 3 / 5 . original cylinder 8 / 9 new cylinder 3 / 5 so 3 / 5 / 8 / 9 = 3 / 5 * 9 / 8 = 12 / 15 = 4 / 5 = 0.680 or 68 % . answer c | gain |
math_qa__94HbJIEPQ2PI1YGu | A can do a job in 15days and B in 30days. If they work on it together for 4 days, then the fraction of the work that is left is?
Choose the correct choice from the following answers: A) 2 / 15 B) 3 / 5 C) 3 / 11 D) 1 / 12 E) 6 / 13 | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/15) + (1/30)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">4 * (1/10)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<result>B</result> | B | 0.6 | A can do a job in 15days and B in 30days. If they work on it together for 4 days, then the fraction of the work that is left is? | {
"A": "2 / 15",
"B": "3 / 5",
"C": "3 / 11",
"D": "1 / 12",
"E": "6 / 13"
} | subtract(const_1, multiply(4, add(divide(const_1, 15), divide(const_1, 30)))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)| | "a ' s 1 day work = 1 / 15 b ' s 1 day work = 1 / 30 a + b 1 day work = 1 / 15 + 1 / 30 = 3 / 30 = 1 / 10 a + b 4 days work = 1 / 10 * 4 = 2 / 5 remaining work = 1 - 2 / 5 = 3 / 5 answer is b" | physics |
math_qa__rQiRwx8r1oifht8R | The population of a city increases by 9% per year but due to migration it decrease by 1% per years. What will be the percentage increase in population in 3 years?
Choices
A) 9 % B) 9.27 % C) 25.97 % D) 12 % E) none of these | <gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">108 * 8</gadget>
<output>864</output>
<gadget id="calculator">864 / 100</gadget>
<output>216/25 = around 8.64</output>
<gadget id="calculator">(216/25) + 8</gadget>
<output>416/25 = around 16.64</output>
<gadget id="calculator">100 + (416/25)</gadget>
<output>2_916/25 = around 116.64</output>
<gadget id="calculator">(2_916/25) * 8</gadget>
<output>23_328/25 = around 933.12</output>
<gadget id="calculator">(23_328/25) / 100</gadget>
<output>5_832/625 = around 9.3312</output>
<gadget id="calculator">(5_832/625) + (416/25)</gadget>
<output>16_232/625 = around 25.9712</output>
<result>C</result> | C | 25.97 | The population of a city increases by 9% per year but due to migration it decrease by 1% per years. What will be the percentage increase in population in 3 years? | {
"A": "9 %",
"B": "9.27 %",
"C": "25.97 %",
"D": "12 %",
"E": "none of these"
} | add(divide(multiply(add(const_100, add(divide(multiply(add(const_100, subtract(9, 1)), subtract(9, 1)), const_100), subtract(9, 1))), subtract(9, 1)), const_100), add(divide(multiply(add(const_100, subtract(9, 1)), subtract(9, 1)), const_100), subtract(9, 1))) | subtract(n0,n1)|add(#0,const_100)|multiply(#1,#0)|divide(#2,const_100)|add(#3,#0)|add(#4,const_100)|multiply(#5,#0)|divide(#6,const_100)|add(#4,#7)| | "actual increase in population = 8 % let , earlier population = 100 then the population after 3 years = 100 ( 1 + 8 / 100 ) ^ 3 = 125.97 ∴ required percentage = 25.97 % answer : c" | general |
math_qa__1LlMwH9cZ60uII0J | A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.5 m and its walls are 5 cm thick. The thickness of the bottom is: Answers.
A) 90 cm B) 5 dm C) 1 m D) 1.1 cm E) none of these | <gadget id="calculator">3.3 * 2.6</gadget>
<output>8.58</output>
<gadget id="calculator">8.58 * 1.5</gadget>
<output>12.87</output>
<gadget id="calculator">8_000 / 1_000</gadget>
<output>8</output>
<gadget id="calculator">12.87 - 8</gadget>
<output>4.87</output>
<result>B</result> | B | 5 | A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.5 m and its walls are 5 cm thick. The thickness of the bottom is: | {
"A": "90 cm",
"B": "5 dm",
"C": "1 m",
"D": "1.1 cm",
"E": "none of these"
} | subtract(multiply(multiply(3.3, 2.6), 1.5), divide(8000, const_1000)) | divide(n0,const_1000)|multiply(n1,n2)|multiply(n3,#1)|subtract(#2,#0)| | "explanation : let the thickness of the bottom be x cm . then , [ ( 330 - 10 ) × ( 260 - 10 ) × ( 150 - x ) ] = 8000 × 1000 = > 320 × 250 × ( 150 - x ) = 8000 × 1000 = > ( 150 - x ) = 8000 × 1000 / 320 = 100 = > x = 50 cm = 5 dm . answer : b" | physics |
math_qa__ZfZh08BW96EKzqO0 | if 18888 – n is divisible by 11 , and 0 < n < 11 , what is n ? Options:
A) 1
B) 3
C) 5
D) 7
E) 9 | <gadget id="calculator">gcd(18_888, 11)</gadget>
<output>1</output>
<result>A</result> | A | 1 | if 18888 – n is divisible by 11 , and 0 < n < 11 , what is n ? | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | gcd(18888, 11) | gcd(n0,n1) | 18,888 / 11 = 1717 with a remainder of 1 . we need to subtract the remainder to get a multiple of 11 . the answer is a . | general |
math_qa__GI5A29zMMW4XtNqT | After decreasing 56% in the price of an article costs Rs.4400. Find the actual cost of an article? Choose the correct choice from the following options:
A) 12000
B) 15000
C) 1200
D) 1000
E) 10000 | <gadget id="calculator">56 / 100</gadget>
<output>14/25 = around 0.56</output>
<gadget id="calculator">1 - (14/25)</gadget>
<output>11/25 = around 0.44</output>
<gadget id="calculator">4_400 / (11/25)</gadget>
<output>10_000</output>
<result>E</result> | E | 10,000 | After decreasing 56% in the price of an article costs Rs.4400. Find the actual cost of an article? | {
"A": "12000",
"B": "15000",
"C": "1200",
"D": "1000",
"E": "10000"
} | divide(4400, subtract(const_1, divide(56, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1)| | "cp * ( 44 / 100 ) = 4400 cp = 100 * 100 = > cp = 10000 answer : e" | gain |
math_qa__y57jzqwtibvZ9HEh | For each of her sales, a saleswoman receives a commission equal to 20 percent of the first $500 of the total amount of the sale, plus 45 percent of the total amount in excess of $500. If the total amount of one of her sales was $800, the saleswoman’s commission was approximately what percent of the total amount of the sale? Answers.
A) 22 % B) 24 % C) 25 % D) 29 % E) 28 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 500</gadget>
<output>100</output>
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">800 - 500</gadget>
<output>300</output>
<gadget id="calculator">(9/20) * 300</gadget>
<output>135</output>
<gadget id="calculator">100 + 135</gadget>
<output>235</output>
<gadget id="calculator">235 / 800</gadget>
<output>47/160 = around 0.29375</output>
<gadget id="calculator">(47/160) * 100</gadget>
<output>235/8 = around 29.375</output>
<result>D</result> | D | 29 | For each of her sales, a saleswoman receives a commission equal to 20 percent of the first $500 of the total amount of the sale, plus 45 percent of the total amount in excess of $500. If the total amount of one of her sales was $800, the saleswoman’s commission was approximately what percent of the total amount of the sale? | {
"A": "22 %",
"B": "24 %",
"C": "25 %",
"D": "29 %",
"E": "28 %"
} | multiply(divide(add(multiply(divide(20, const_100), 500), multiply(divide(45, const_100), subtract(800, 500))), 800), const_100) | divide(n0,const_100)|divide(n2,const_100)|subtract(n4,n1)|multiply(n1,#0)|multiply(#1,#2)|add(#3,#4)|divide(#5,n4)|multiply(#6,const_100) | total sales = 800 comission = ( 20 / 100 ) * 500 + ( 45 / 100 ) * 300 = 100 + 135 = 235 % comission = ( 235 / 800 ) * 100 = 29.4 ~ 29 % answer is d | general |
math_qa__z1PNsYCRshRd5WWI | A shop owner sells 50mtr of cloth and gains SP of 10 mtrs. Find the gain %? Choose the correct option.
A) 25 %
B) 40 %
C) 50 %
D) 60 %
E) 70 % | <gadget id="calculator">50 - 10</gadget>
<output>40</output>
<gadget id="calculator">10 / 40</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>A</result> | A | 25 | A shop owner sells 50mtr of cloth and gains SP of 10 mtrs. Find the gain %? | {
"A": "25 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "70 %"
} | multiply(divide(10, subtract(50, 10)), const_100) | subtract(n0,n1)|divide(n1,#0)|multiply(#1,const_100) | here , selling price of 10 m cloth is obtained as profit . profit of 10 m cloth = ( s . p . of 50 m cloth ) – ( c . p . of 50 m cloth ) selling price of 40 m cloth = selling price of 50 m of cloth let cost of each metre be rs . 100 . therefore , cost price of 40 m cloth = rs . 4000 and s . p . of 40 m cloth = rs . rs . 5000 profit % = 10 / 40 × 100 = 25 % profit of 25 % was made by the merchant . a | gain |
math_qa__iteZayMKfMtVzPMc | Find compound interest on Rs. 7500 at 4% per annum for 2 years, compounded annually.
Choose the correct choice from the following answers
A) rs . 512 B) rs . 552 C) rs . 612 D) rs . 622 E) none | <gadget id="calculator">7_500 * 4</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 / 100</gadget>
<output>300</output>
<gadget id="calculator">7_500 + 300</gadget>
<output>7_800</output>
<gadget id="calculator">7_800 * 4</gadget>
<output>31_200</output>
<gadget id="calculator">31_200 / 100</gadget>
<output>312</output>
<gadget id="calculator">7_800 + 312</gadget>
<output>8_112</output>
<gadget id="calculator">8_112 - 7_500</gadget>
<output>612</output>
<result>C</result> | C | 612 | Find compound interest on Rs. 7500 at 4% per annum for 2 years, compounded annually. | {
"A": "rs . 512",
"B": "rs . 552",
"C": "rs . 612",
"D": "rs . 622",
"E": "none"
} | subtract(add(add(7500, divide(multiply(7500, 4), const_100)), divide(multiply(add(7500, divide(multiply(7500, 4), const_100)), 4), const_100)), 7500) | multiply(n0,n1)|divide(#0,const_100)|add(n0,#1)|multiply(n1,#2)|divide(#3,const_100)|add(#2,#4)|subtract(#5,n0)| | "solution amount = rs [ 7500 x ( 1 + 4 / 100 ) ² ] = rs . ( 7500 x 26 / 25 x 26 / 25 ) = rs . 8112 . c . i = rs ( 8112 - 7500 ) = rs . 612 . answer c" | gain |
math_qa__6YgSwoAbne5YheXG | a number is 4 less than 6 times the other number . if the sum of both the number is 38 , what are the numbers ? Choose the correct option:
A) 632
B) 731
C) 533
D) 434
E) none of the above | <gadget id="calculator">38 - 6</gadget>
<output>32</output>
<gadget id="calculator">38 - 32</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 + 32</gadget>
<output>632</output>
<result>A</result> | A | 632 | a number is 4 less than 6 times the other number . if the sum of both the number is 38 , what are the numbers ? | {
"A": "632",
"B": "731",
"C": "533",
"D": "434",
"E": "none of the above"
} | add(multiply(subtract(38, subtract(38, 6)), const_100), subtract(38, 6)) | subtract(n2,n1)|subtract(n2,#0)|multiply(#1,const_100)|add(#2,#0) | that numbers are x , 6 x - 4 so sum = x + 6 x - 4 = 38 7 x = 42 = = > x = 6 another no is 32 answer is 6 , 32 answer : a | general |
math_qa__SmvOwPx4jdUeqEtX | Two trains of length 250 m and 120 m are 50 m apart. They start moving towards each other on parallel tracks, at speeds 64 kmph and 42 kmph. After how much time will the trains meet? Choose the correct choice from the following choices
A) 15 / 10 B) 17 / 10 C) 16 / 10 D) 18 / 10 E) 16 / 10 | <gadget id="calculator">64 + 42</gadget>
<output>106</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">106 * (5/18)</gadget>
<output>265/9 = around 29.444444</output>
<gadget id="calculator">50 / (265/9)</gadget>
<output>90/53 = around 1.698113</output>
<result>B</result> | B | 1.7 | Two trains of length 250 m and 120 m are 50 m apart. They start moving towards each other on parallel tracks, at speeds 64 kmph and 42 kmph. After how much time will the trains meet? | {
"A": "15 / 10",
"B": "17 / 10",
"C": "16 / 10",
"D": "18 / 10",
"E": "16 / 10"
} | divide(50, multiply(add(64, 42), const_0_2778)) | add(n3,n4)|multiply(#0,const_0_2778)|divide(n2,#1)| | "they are moving in opposite directions , relative speed is equal to the sum of their speeds . relative speed = ( 64 + 42 ) * 5 / 18 = 7 * 5 = 29.4 mps . the time required = d / s = 50 / 29.4 = 17 / 10 sec . answer : b" | physics |
math_qa__sfVm9x8yADKi9TPn | The area of sector of a circle whose radius is 12 metro and whose angle at the center is 38° is? Answers.
A) 30 m 2 B) 40 m 2 C) 47.7 m 2 D) 50 m 2 E) 55 m 2 | <gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">144 * (22/7)</gadget>
<output>3_168/7 = around 452.571429</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">38 / 360</gadget>
<output>19/180 = around 0.105556</output>
<gadget id="calculator">(3_168/7) * (19/180)</gadget>
<output>1_672/35 = around 47.771429</output>
<result>C</result> | C | 47.7 | The area of sector of a circle whose radius is 12 metro and whose angle at the center is 38° is? | {
"A": "30 m 2",
"B": "40 m 2",
"C": "47.7 m 2",
"D": "50 m 2",
"E": "55 m 2"
} | multiply(multiply(power(12, const_2), divide(add(multiply(const_2, const_10), const_2), add(const_4, const_3))), divide(38, divide(const_3600, const_10))) | add(const_3,const_4)|divide(const_3600,const_10)|multiply(const_10,const_2)|power(n0,const_2)|add(#2,const_2)|divide(n1,#1)|divide(#4,#0)|multiply(#6,#3)|multiply(#5,#7)| | "38 / 360 * 22 / 7 * 12 * 12 = 47.7 m 2 answer : c" | geometry |
math_qa__AmBDUoT22KLOUoGO | If the L.C.M of two numbers is 750 and their product is 18750, find the H.C.F of the numbers. Choices
A) 50 B) 30 C) 125 D) 25 E) none of these | <gadget id="calculator">18_750 / 750</gadget>
<output>25</output>
<result>D</result> | D | 25 | If the L.C.M of two numbers is 750 and their product is 18750, find the H.C.F of the numbers. | {
"A": "50",
"B": "30",
"C": "125",
"D": "25",
"E": "none of these"
} | divide(18750, 750) | divide(n1,n0)| | "h . c . f = ( product of the numbers ) / ( their l . c . m ) = 18750 / 750 = 25 . answer : d" | physics |
math_qa__y9vXZ2lY3bXWzmv3 | The marks obtained by Polly and Sandy are in the ratio 3:5 and those obtained by Sandy and Willy are in the ratio of 3:2. The marks obtained by Polly and Willy are in the ratio of...? Choose one
A) 3 : 4 B) 5 : 6 C) 7 : 8 D) 9 : 10 E) 11 : 12 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>
<result>D</result> | D | 0.9 | The marks obtained by Polly and Sandy are in the ratio 3:5 and those obtained by Sandy and Willy are in the ratio of 3:2. The marks obtained by Polly and Willy are in the ratio of...? | {
"A": "3 : 4",
"B": "5 : 6",
"C": "7 : 8",
"D": "9 : 10",
"E": "11 : 12"
} | divide(multiply(3, 3), multiply(5, 2)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "polly : sandy = 3 : 5 = 9 : 15 sandy : willy = 3 : 2 = 15 : 10 polly : sandy : willy = 9 : 15 : 10 polly : willy = 9 : 10 the answer is d ." | other |
math_qa__2iXKkrQSYR1dIIqs | if the largest 3 digit number is subtracted from the smallest 5 digit number , then the remainder is
Choose the correct choice from the following answers:
A) 1 B) 9000 C) 9001 D) 90001 E) none | <gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">500 + 500</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 10</gadget>
<output>10_000</output>
<gadget id="calculator">1_000 - 1</gadget>
<output>999</output>
<gadget id="calculator">10_000 - 999</gadget>
<output>9_001</output>
<result>C</result> | C | 9,001 | if the largest 3 digit number is subtracted from the smallest 5 digit number , then the remainder is | {
"A": "1",
"B": "9000",
"C": "9001",
"D": "90001",
"E": "none"
} | subtract(multiply(add(multiply(5, const_100), multiply(5, const_100)), const_10), subtract(add(multiply(5, const_100), multiply(5, const_100)), const_1)) | multiply(n1,const_100)|add(#0,#0)|multiply(#1,const_10)|subtract(#1,const_1)|subtract(#2,#3) | solution required remainder = ( 10000 - 999 ) = 9001 answer c | general |
math_qa__VqmNdKEStx0ntE3I | x and y started a business investing rs . 50000 and rs 40000 respectively . in what ratio the profit earned after 2 years be divided between x and y respectively ? Pick
A) 3 : 2 B) 9 : 2 C) 5 : 4 D) 1 : 4 E) 18 : 4 | <gadget id="calculator">50_000 / 40_000</gadget>
<output>5/4 = around 1.25</output>
<result>C</result> | C | 1.25 | x and y started a business investing rs . 50000 and rs 40000 respectively . in what ratio the profit earned after 2 years be divided between x and y respectively ? | {
"A": "3 : 2",
"B": "9 : 2",
"C": "5 : 4",
"D": "1 : 4",
"E": "18 : 4"
} | divide(50000, 40000) | divide(n0,n1) | x : y = 50000 : 40000 = 5 : 4 answer : c | gain |
math_qa__AWXe38nSkrKYc7jf | If $ 5,000 is invested in an account that earns 12% interest compounded semi-annually, then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8% simple yearly interest? Pick one
A) $ 4 B) $ 8 C) $ 12 D) $ 16 E) $ 432 | <gadget id="calculator">12 * 1</gadget>
<output>12</output>
<result>C</result> | C | 12 | If $ 5,000 is invested in an account that earns 12% interest compounded semi-annually, then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8% simple yearly interest? | {
"A": "$ 4",
"B": "$ 8",
"C": "$ 12",
"D": "$ 16",
"E": "$ 432"
} | multiply(12, const_1) | multiply(n1,const_1)| | "solution amount ( ci ) = p + ( 1 + r / n ) ^ nt = 5000 + ( 1 + 0.12 / 2 ) ^ 2 = 5412 amount ( si ) = p + ptr / 100 = 5000 + ( 5000 * 1 * 12 / 100 ) = 5400 difference = 5412 - 5400 = 12 $ c" | gain |
math_qa__xT1i4TraoFu4MNAg | What is the sum of 80 consecutive integers from -39 inclusive, in a increasing order? Choose the correct choice from the following options.
A) - 29
B) 39
C) - 30
D) 40
E) 60 | <gadget id="calculator">39 + 1</gadget>
<output>40</output>
<result>D</result> | D | 40 | What is the sum of 80 consecutive integers from -39 inclusive, in a increasing order? | {
"A": "- 29",
"B": "39",
"C": "- 30",
"D": "40",
"E": "60"
} | add(39, const_1) | add(n1,const_1)| | "from - 39 to - 1 - - > 39 nos . zero - - > 1 number from + 1 to + 39 - - > 39 nos . when we add up nos . from - 39 to + 39 sum will be zero . total 79 nos will be added . 80 th number will be 40 . sum of these 80 nos . = 40 . d is the answer ." | general |
math_qa__r4J4Njd57WjoRGpZ | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 70% profit? Options.
A) 277
B) 1088
C) 277
D) 266
E) 121 | <gadget id="calculator">832 - 448</gadget>
<output>384</output>
<gadget id="calculator">384 / 2</gadget>
<output>192</output>
<gadget id="calculator">832 - 192</gadget>
<output>640</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">1 + (7/10)</gadget>
<output>17/10 = around 1.7</output>
<gadget id="calculator">640 * (17/10)</gadget>
<output>1_088</output>
<result>B</result> | B | 1,088 | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 70% profit? | {
"A": "277",
"B": "1088",
"C": "277",
"D": "266",
"E": "121"
} | multiply(subtract(832, divide(subtract(832, 448), const_2)), add(const_1, divide(70, const_100))) | divide(n2,const_100)|subtract(n0,n1)|add(#0,const_1)|divide(#1,const_2)|subtract(n0,#3)|multiply(#2,#4)| | "let c . p . = rs . x . then , 832 - x = x - 448 2 x = 1280 = > x = 640 required s . p . = 170 % of rs . 640 = 170 / 100 * 640 = rs . 1088 . answer : b" | gain |
math_qa__IlRslgzOtQdCXkEK | A man has some hens and cows. If the number of heads be 46 and the number of feet equals 136, then the number of hens will be
Choose the correct option.
A) 22
B) 24
C) 26
D) 20
E) 28 | <gadget id="calculator">46 * 4</gadget>
<output>184</output>
<gadget id="calculator">184 - 136</gadget>
<output>48</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<result>B</result> | B | 24 | A man has some hens and cows. If the number of heads be 46 and the number of feet equals 136, then the number of hens will be | {
"A": "22",
"B": "24",
"C": "26",
"D": "20",
"E": "28"
} | divide(subtract(multiply(46, const_4), 136), const_2) | multiply(n0,const_4)|subtract(#0,n1)|divide(#1,const_2)| | "explanation : let number of hens = h and number of cows = c number of heads = 46 = > h + c = 46 - - - ( equation 1 ) number of feet = 136 = > 2 h + 4 c = 136 = > h + 2 c = 68 - - - ( equation 2 ) ( equation 2 ) - ( equation 1 ) gives 2 c - c = 68 - 46 = > c = 22 substituting the value of c in equation 1 , we get h + 22 = 46 = > h = 46 - 22 = 24 i . e . , number of hens = 24 answer : b" | general |
math_qa__tJaTBgaPma1uRYdh | Find the smallest number which when divided by 13 and 17 leaves respective remainders of 3 and 7. Choose the correct answer
A) 187
B) 211
C) 207
D) 219
E) 227 | <gadget id="calculator">13 * 17</gadget>
<output>221</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">221 - 11</gadget>
<output>210</output>
<result>B</result> | B | 211 | Find the smallest number which when divided by 13 and 17 leaves respective remainders of 3 and 7. | {
"A": "187",
"B": "211",
"C": "207",
"D": "219",
"E": "227"
} | subtract(multiply(13, 17), add(const_10, const_1)) | add(const_1,const_10)|multiply(n0,n1)|subtract(#1,#0)| | "let ' n ' is the smallest number which divided by 13 and 17 leaves respective remainders of 3 and 7 . required number = ( lcm of 13 and 17 ) - ( common difference of divisors and remainders ) = ( 221 ) - ( 10 ) = 211 . answer : b" | general |
math_qa__zctY2zgOZMFnFmjP | Find the constant k so that : -x2 - (k + 11)x - 8 = -(x - 2)(x - 4) Answers:
A) 11
B) 12
C) 17
D) 14
E) 15 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">11 + 6</gadget>
<output>17</output>
<result>C</result> | C | 17 | Find the constant k so that : -x2 - (k + 11)x - 8 = -(x - 2)(x - 4) | {
"A": "11",
"B": "12",
"C": "17",
"D": "14",
"E": "15"
} | add(11, add(4, 2)) | add(n0,n4)|add(n1,#0)| | "- x 2 - ( k + 11 ) x - 8 = - ( x - 2 ) ( x - 4 ) : given - x 2 - ( k + 11 ) x - 8 = - x 2 + 6 x - 8 - ( k + 11 ) = 6 : two polynomials are equal if their corresponding coefficients are equal . k = - 17 : solve the above for k correct answer c" | general |
math_qa__tmq4I5NlJ5kh01L8 | What is the maximum number of pieces of birthday cake of size 10” by 10” that can be cut from a cake 20” by 20”?
Choose the correct choice from the following options:
A) 4 B) 10 C) 16 D) 20 E) 25 | <gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">400 / 100</gadget>
<output>4</output>
<result>A</result> | A | 4 | What is the maximum number of pieces of birthday cake of size 10” by 10” that can be cut from a cake 20” by 20”? | {
"A": "4",
"B": "10",
"C": "16",
"D": "20",
"E": "25"
} | divide(multiply(20, 20), multiply(10, 10)) | multiply(n2,n2)|multiply(n0,n0)|divide(#0,#1)| | "the prompt is essentially asking for the maximum number of 10 x 10 squares that can be cut from a larger 20 by 20 square . since each ' row ' and each ' column ' of the larger square can be sub - divided into 2 ' pieces ' each , we have ( 2 ) ( 2 ) = 4 total smaller squares ( at maximum ) . a" | physics |
math_qa__yYIG329Xk9zqInUr | If the sides of a triangle are 65 cm, 60 cm and 25 cm, what is its area? Answers
A) 120 cm 2 B) 750 cm 2 C) 216 cm 2 D) 197 cm 2 E) 275 cm 2 | <gadget id="calculator">60 * 25</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 2</gadget>
<output>750</output>
<result>B</result> | B | 750 | If the sides of a triangle are 65 cm, 60 cm and 25 cm, what is its area? | {
"A": "120 cm 2",
"B": "750 cm 2",
"C": "216 cm 2",
"D": "197 cm 2",
"E": "275 cm 2"
} | divide(multiply(60, 25), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 65 cm , 60 cm and 25 cm is right angled , where the hypotenuse is 65 cm . area of the triangle = 1 / 2 * 60 * 25 = 750 cm 2 answer : b" | geometry |
math_qa__7GtgPCi22ZPW8pO4 | At a restaurant, glasses are stored in two different-sized boxes. One box contains 12 glasses, and the other contains 16 glasses. If the average number of glasses per box is 15, and there are 16 more of the larger boxes, what is the total number of glasses R at the restaurant? (Assume that all boxes are filled to capacity.) Pick:
A) 96 B) 240 C) r = 256 D) r = 384 E) r = 480 | <gadget id="calculator">16 * 2</gadget>
<output>32</output>
<gadget id="calculator">32 * 15</gadget>
<output>480</output>
<result>E</result> | E | 480 | At a restaurant, glasses are stored in two different-sized boxes. One box contains 12 glasses, and the other contains 16 glasses. If the average number of glasses per box is 15, and there are 16 more of the larger boxes, what is the total number of glasses R at the restaurant? (Assume that all boxes are filled to capacity.) | {
"A": "96",
"B": "240",
"C": "r = 256",
"D": "r = 384",
"E": "r = 480"
} | multiply(multiply(16, const_2), 15) | multiply(n1,const_2)|multiply(n2,#0) | most test takers would recognize thesystemof equations in this prompt and just do algebra to get to the solution ( and that ' s fine ) . the wording of the prompt and the ' spread ' of the answer choices actually provide an interesting ' brute force ' shortcut that you can take advantage of to eliminate the 4 wrong answers . . . . we ' re told that there are 2 types of boxes : those that hold 12 glasses and those that hold 16 glasses . since the average number of boxes is 15 , we know that there must be at least some of each . we ' re also told that that there are 16 more of the larger boxes . this means , at the minimum , we have . . . 1 small box and 17 large boxes = 1 ( 12 ) + 17 ( 16 ) = 12 + 272 = 284 glasses at the minimum since the question asks for the total number of glasses , we can now eliminate answers a , b and c . . . . the difference in the number of boxes must be 16 though , so we could have . . . . 2 small boxes and 18 large boxes 3 small boxes and 19 large boxes etc . with every additional small box + large box that we add , we add 12 + 16 = 28 more glasses . thus , we can justadd 28 suntil we hit the correct answer . . . . 284 + 28 = 312 312 + 28 = 340 340 + 28 = 368 368 + 28 = 396 at this point , we ' ve ' gone past ' answer d , so the correct answer must be answer e . . . . . but here ' s the proof . . . . 396 + 28 = 424 424 + 28 = 452 452 + 28 = 480 final answer : e | general |
math_qa__uWe3OtR7Od3bnT95 | On increasing the number of lines in a page by 60, they become 240. What is the % of increase in the no. of lines in the page? Options:
A) 33.3 % B) 305 C) 50 % D) 55 % E) 60 % | <gadget id="calculator">240 - 60</gadget>
<output>180</output>
<gadget id="calculator">240 / 180</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) * 100</gadget>
<output>400/3 = around 133.333333</output>
<gadget id="calculator">(400/3) - 100</gadget>
<output>100/3 = around 33.333333</output>
<result>A</result> | A | 33.3 | On increasing the number of lines in a page by 60, they become 240. What is the % of increase in the no. of lines in the page? | {
"A": "33.3 %",
"B": "305",
"C": "50 %",
"D": "55 %",
"E": "60 %"
} | subtract(multiply(divide(240, subtract(240, 60)), const_100), const_100) | subtract(n1,n0)|divide(n1,#0)|multiply(#1,const_100)|subtract(#2,const_100)| | "explanation : number of pages increased = 60 now , the number of pages of book = 240 number of pages of the books before increase = 240 – 60 = 180 % increase in the number of pages in the book = 60 / 180 x 100 % = 33.3 % a" | general |
math_qa__KV8J7gACsYybSfzc | A goods train runs at the speed of 72 km/hr and crosses a 220 m long platform in 26 sec. What is the length of the goods train? Choose the correct choice from the following:
A) 382 B) 782 C) 300 D) 270 E) 881 | <gadget id="calculator">72 / 3_600</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 1_000</gadget>
<output>20</output>
<gadget id="calculator">20 * 26</gadget>
<output>520</output>
<gadget id="calculator">520 - 220</gadget>
<output>300</output>
<result>C</result> | C | 300 | A goods train runs at the speed of 72 km/hr and crosses a 220 m long platform in 26 sec. What is the length of the goods train? | {
"A": "382",
"B": "782",
"C": "300",
"D": "270",
"E": "881"
} | subtract(multiply(multiply(divide(72, const_3600), const_1000), 26), 220) | divide(n0,const_3600)|multiply(#0,const_1000)|multiply(n2,#1)|subtract(#2,n1)| | "speed = 72 * 5 / 18 = 20 m / sec . time = 26 sec . let the length of the train be x meters . then , ( x + 220 ) / 26 = 20 x = 300 m . answer : c" | physics |
math_qa__tdNu5OHRSquKxBtP | A and B are two partially filled buckets of water. If 5 liters are transferred from A to B, then A would contain one-third of the amount of water in B. Alternatively, if 3 liters are transferred from B to A, B would contain one-half of the amount of water in A. Bucket A contains how many liters of water? Choose the correct choice from the following
A) 11 B) 13 C) 17 D) 49 / 5 E) 23 | <gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">10 * (5/2)</gadget>
<output>25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 + (1/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">25 / (5/2)</gadget>
<output>10</output>
<result>D</result> | D | 9.8 | A and B are two partially filled buckets of water. If 5 liters are transferred from A to B, then A would contain one-third of the amount of water in B. Alternatively, if 3 liters are transferred from B to A, B would contain one-half of the amount of water in A. Bucket A contains how many liters of water? | {
"A": "11",
"B": "13",
"C": "17",
"D": "49 / 5",
"E": "23"
} | divide(multiply(add(add(5, const_3), const_2), divide(5, const_2)), add(const_2, divide(const_1, const_2))) | add(n0,const_3)|divide(n0,const_2)|divide(const_1,const_2)|add(#0,const_2)|add(#2,const_2)|multiply(#3,#1)|divide(#5,#4)| | "let a contains a , b contains b liters so , ( a - 5 ) / ( b + 5 ) = 1 / 3 . . . . . . . ( 1 ) again , ( b - 3 ) / ( a + 3 ) = 1 / 2 . . . . . . . . . . ( 2 ) from ( 1 ) ( 2 ) we find a = 49 / 5 ans : ( d )" | general |
math_qa__pa25qNhXO2slWZ0h | Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 10% and 35% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of Answers
A) 18 % B) 20 % C) 21 % D) 35 % E) can not be determined | <gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">20 + 15</gadget>
<output>35</output>
<result>D</result> | D | 35 | Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 10% and 35% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of | {
"A": "18 %",
"B": "20 %",
"C": "21 %",
"D": "35 %",
"E": "can not be determined"
} | add(divide(multiply(10, 4), 2), add(10, 5)) | add(n4,n8)|multiply(n4,n6)|divide(#1,n1)|add(#0,#2) | answer : d . | general |
math_qa__IWgPfsv0zeFSdIPf | Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 18 boys and 42 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad? Choose the correct option:
A) 2
B) 4
C) 6
D) 8
E) 10 | <gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">18 - 6</gadget>
<output>12</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<result>C</result> | C | 6 | Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 18 boys and 42 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | subtract(subtract(18, subtract(10, 4)), 6) | subtract(n2,n7)|subtract(n4,#0)|subtract(#1,n6)| | "venn diagrams are useful for multiple values of a single variable e . g . state of mind - happy / sad / neither . when you have two or more variables such as here where you have gender - boy / girl too , it becomes unwieldy . in this case , either use the table or logic . table method is shown above ; here is how you will use logic : there are 6 happy boys . there are 4 sad girls but total 10 sad children . so rest 6 sad children must be sad boys . we have 6 happy boys and 6 sad boys . total we have 18 boys . so 18 - 6 - 6 = 6 boys must be neither happy nor sad . answer ( c )" | other |
math_qa__MgNCEjDd2tjWO2pJ | The sum of all the integers k such that −26 < k < 24 is Choose the correct choice from the following choices: A) 0 B) − 2 C) − 25 D) − 49 E) − 51 | <gadget id="calculator">-26</gadget>
<output>-26</output>
<gadget id="calculator">(-26) + 1</gadget>
<output>-25</output>
<gadget id="calculator">(-25) + 1</gadget>
<output>-24</output>
<gadget id="calculator">(-25) + (-24)</gadget>
<output>-49</output>
<result>D</result> | D | -49 | The sum of all the integers k such that −26 < k < 24 is | {
"A": "0",
"B": "− 2",
"C": "− 25",
"D": "− 49",
"E": "− 51"
} | add(add(negate(26), const_1), add(add(negate(26), const_1), const_1)) | negate(n0)|add(#0,const_1)|add(#1,const_1)|add(#1,#2)| | "since k defines a range between − 26 < k < 24 we can set 0 as the reference point for the negative values and positive values . the negative values will range from - 25 to 0 whereas the positive values will range from 0 - 23 . we can conclude that for all but - 25 and - 24 the number pairs will add to 0 . so we have left - 25 - 24 = - 49 . answer d ." | general |
math_qa__LpO0JspmEYojw1ZU | Evaluate 75 / .05 Choose the correct choice:
A) 1400 B) 1500 C) 1505 D) none of these E) 1506 | <gadget id="calculator">5 / 75</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">100 / (1/15)</gadget>
<output>1_500</output>
<result>B</result> | B | 1,500 | Evaluate 75 / .05 | {
"A": "1400",
"B": "1500",
"C": "1505",
"D": "none of these",
"E": "1506"
} | divide(const_100.0, divide(05, 75)) | divide(n1,const_100)|divide(n0,#0)| | "explanation : 75 / . 05 = 7500 / 5 = 1500 option b" | general |
math_qa__HSuFWKifyCpB4k3B | The length of a rectangle is three times of its width. If the length of the diagonal is 8√10 then find the perimeter of the rectangle. Select the correct option
A) 77 cm B) 88 cm C) 64 cm D) 11 cm E) 18 cm | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">64 ** (1/2)</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">8 + 24</gadget>
<output>32</output>
<gadget id="calculator">32 * 2</gadget>
<output>64</output>
<result>C</result> | C | 64 | The length of a rectangle is three times of its width. If the length of the diagonal is 8√10 then find the perimeter of the rectangle. | {
"A": "77 cm",
"B": "88 cm",
"C": "64 cm",
"D": "11 cm",
"E": "18 cm"
} | multiply(add(sqrt(power(8, const_2)), multiply(sqrt(power(8, const_2)), const_3)), const_2) | power(n0,const_2)|sqrt(#0)|multiply(#1,const_3)|add(#2,#1)|multiply(#3,const_2) | let breadth = x cm , then , length = 3 x cm x 2 + ( 3 x ) 2 = ( 810 − − √ ) 2 = > 10 x 2 = 640 = > x = 8 x 2 + ( 3 x ) 2 = ( 810 ) 2 = > 10 x 2 = 640 = > x = 8 so , length = 24 cm and breadth = 8 cm perimeter = 2 ( l + b ) = 2 ( 24 + 8 ) = 64 cm answer : c | geometry |
math_qa__2iCARxbGIIaR7YnC | Car A runs at the speed of 60 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B?
Choose one.
A) 3 : 7 B) 4 : 9 C) 12 : 7 D) 5 : 7 E) 6 : 11 | <gadget id="calculator">60 * 8</gadget>
<output>480</output>
<gadget id="calculator">70 * 4</gadget>
<output>280</output>
<gadget id="calculator">480 / 280</gadget>
<output>12/7 = around 1.714286</output>
<result>C</result> | C | 1.714286 | Car A runs at the speed of 60 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B? | {
"A": "3 : 7",
"B": "4 : 9",
"C": "12 : 7",
"D": "5 : 7",
"E": "6 : 11"
} | divide(multiply(60, 8), multiply(70, 4)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1) | car a travels 60 × 8 = 480 km car b travels 70 × 4 = 280 km the ratio is 480 : 280 = 48 : 28 = 12 : 7 the answer is c . | physics |
math_qa__JKxgB2gxPqz0Zrl5 | A house wife saved $4 in buying an item on sale. If she spent $29 for the item, approximately how much percent she saved in the transaction? Choose the most appropriate option.
A) 8 % B) 9 % C) 10 % D) 11 % E) 12 % | <gadget id="calculator">29 + 4</gadget>
<output>33</output>
<gadget id="calculator">4 / 33</gadget>
<output>4/33 = around 0.121212</output>
<gadget id="calculator">(4/33) * 100</gadget>
<output>400/33 = around 12.121212</output>
<result>E</result> | E | 12 | A house wife saved $4 in buying an item on sale. If she spent $29 for the item, approximately how much percent she saved in the transaction? | {
"A": "8 %",
"B": "9 %",
"C": "10 %",
"D": "11 %",
"E": "12 %"
} | multiply(divide(4, add(29, 4)), const_100) | add(n0,n1)|divide(n0,#0)|multiply(#1,const_100)| | "actual price = 29 + 4 = $ 33 saving = 4 / 33 * 100 = 12 % approximately answer is e" | general |
math_qa__CDuYmVAGkcgaF9ux | Tough and Tricky questions: Exponents.
If 2^(3x+2)*3^(2y-3) = 32^x*9^y, then x + y = Choose the correct choice from the following.
A) - 3 B) - 1 C) 0 D) - 5 E) - 2 | <gadget id="calculator">2 - 3</gadget>
<output>-1</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 3</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(-1) * (9/2)</gadget>
<output>-9/2 = around -4.5</output>
<gadget id="calculator">(-9/2) + (3/2)</gadget>
<output>-3</output>
<gadget id="calculator">(-3) + 1</gadget>
<output>-2</output>
<result>E</result> | E | -2 | Tough and Tricky questions: Exponents.
If 2^(3x+2)*3^(2y-3) = 32^x*9^y, then x + y = | {
"A": "- 3",
"B": "- 1",
"C": "0",
"D": "- 5",
"E": "- 2"
} | add(add(multiply(subtract(const_2, 3), multiply(divide(const_3, 2), const_3)), divide(const_3, 2)), const_1) | divide(const_3,n0)|subtract(const_2,n1)|multiply(#0,const_3)|multiply(#2,#1)|add(#0,#3)|add(#4,const_1) | here is my solution . 2 ^ ( 3 x + 2 ) * 3 ^ ( y - 3 ) = 32 ^ x * 9 ^ y here rhs 32 ^ x * 9 ^ y = 2 ^ ( 5 x ) * 3 ^ ( 2 y ) equating powers on both sides - - > 3 x + 2 = 5 x , thus x = 1 and y - 3 = 2 y giving y = - 3 so , x + y = - 2 option : e | general |
math_qa__GkIfklR7mlqDEzdW | Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on $4000 for 2 years at 10% per annum. The sum placed on simple interest is:
Options:
A) $ 1750 B) $ 2250 C) $ 1250 D) $ 1500 E) $ 2000 | <gadget id="calculator">4_000 * 10</gadget>
<output>40_000</output>
<gadget id="calculator">40_000 / 100</gadget>
<output>400</output>
<gadget id="calculator">4_000 + 400</gadget>
<output>4_400</output>
<gadget id="calculator">4_400 * 10</gadget>
<output>44_000</output>
<gadget id="calculator">44_000 / 100</gadget>
<output>440</output>
<gadget id="calculator">400 + 440</gadget>
<output>840</output>
<gadget id="calculator">840 / 2</gadget>
<output>420</output>
<gadget id="calculator">420 / 3</gadget>
<output>140</output>
<gadget id="calculator">140 * 100</gadget>
<output>14_000</output>
<gadget id="calculator">14_000 / 8</gadget>
<output>1_750</output>
<result>A</result> | A | 1,750 | Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on $4000 for 2 years at 10% per annum. The sum placed on simple interest is: | {
"A": "$ 1750",
"B": "$ 2250",
"C": "$ 1250",
"D": "$ 1500",
"E": "$ 2000"
} | divide(multiply(divide(divide(add(divide(multiply(4000, 10), const_100), divide(multiply(add(4000, divide(multiply(4000, 10), const_100)), 10), const_100)), 2), 3), const_100), 8) | multiply(n2,n4)|divide(#0,const_100)|add(n2,#1)|multiply(n4,#2)|divide(#3,const_100)|add(#1,#4)|divide(#5,n3)|divide(#6,n0)|multiply(#7,const_100)|divide(#8,n1)| | "compound interest = ( 4000 x ( 1 + 10 / 100 ) ^ 2 - 4000 ) = 4000 x 11 / 10 x 11 / 10 - 4000 = 840 therefore the sum is 420 x 100 / ( 3 x 8 ) = 1750 . answer a ) $ 1750" | gain |
math_qa__TPbRErUXRY7oigsD | In one hour, a boat goes 11 km along the stream and 3 km against the stream. the sped of the boat in still water (in km/hr) is : Choose the correct choice from the following answers:
A) 3 B) 5 C) 7 D) 9 E) 10 | <gadget id="calculator">11 + 3</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<result>C</result> | C | 7 | In one hour, a boat goes 11 km along the stream and 3 km against the stream. the sped of the boat in still water (in km/hr) is : | {
"A": "3",
"B": "5",
"C": "7",
"D": "9",
"E": "10"
} | divide(add(11, 3), const_2) | add(n0,n1)|divide(#0,const_2)| | "solution speed in still water = 1 / 2 ( 11 + 3 ) km / hr = 7 kmph . answer c" | gain |
math_qa__6lyMN7SuNUGjcYTN | If a+b=−6, and a=10/b, what is the value of a^2+b^2? Select the correct option.
A) 22 B) 24 C) 16 D) 18 E) 20 | <gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">36 - 20</gadget>
<output>16</output>
<result>C</result> | C | 16 | If a+b=−6, and a=10/b, what is the value of a^2+b^2? | {
"A": "22",
"B": "24",
"C": "16",
"D": "18",
"E": "20"
} | subtract(power(6, const_2), multiply(const_2, 10)) | multiply(n1,const_2)|power(n0,const_2)|subtract(#1,#0) | a ^ 2 + b ^ 2 should make you think of these formulas : ( a + b ) ( a + b ) = a ^ 2 + b ^ 2 + 2 ab we already know ( a + b ) = - 6 and a * b = 10 ( a + b ) ( a + b ) = ( - 6 ) ( - 6 ) = a ^ 2 + b ^ 2 + 2 * ( 10 ) a ^ 2 + b ^ 2 = 36 - 20 = 16 answer : c | general |
math_qa__XspuuSv2ToLsg751 | How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 175 m length?
Select the correct option.
A) 12.9 sec B) 12.1 sec C) 17.9 sec D) 16.8 sec E) 14.25 sec | <gadget id="calculator">110 + 175</gadget>
<output>285</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">285 / 20</gadget>
<output>57/4 = around 14.25</output>
<result>E</result> | E | 14.25 | How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 175 m length? | {
"A": "12.9 sec",
"B": "12.1 sec",
"C": "17.9 sec",
"D": "16.8 sec",
"E": "14.25 sec"
} | divide(add(110, 175), multiply(72, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 72 * 5 / 18 = 20 m / sec total distance covered = 110 + 175 = 285 m . required time = 285 / 20 = 14.25 sec . answer : e" | physics |
math_qa__pT2Tuwl88fDloWCD | Find the length of the wire required to go 15 times round a square field containing 69696 m2.
Pick:
A) 15840 B) 15848 C) 15828 D) 27892 E) 22892 | <gadget id="calculator">69_696 ** (1/2)</gadget>
<output>264</output>
<gadget id="calculator">4 * 264</gadget>
<output>1_056</output>
<gadget id="calculator">1_056 * 15</gadget>
<output>15_840</output>
<result>A</result> | A | 15,840 | Find the length of the wire required to go 15 times round a square field containing 69696 m2. | {
"A": "15840",
"B": "15848",
"C": "15828",
"D": "27892",
"E": "22892"
} | multiply(square_perimeter(square_edge_by_area(69696)), 15) | square_edge_by_area(n1)|square_perimeter(#0)|multiply(n0,#1)| | "a 2 = 69696 = > a = 264 4 a = 1056 1056 * 15 = 15840 answer : a" | physics |
math_qa__7GkClIXUdDgRRBQE | A large box contains 15 small boxes and each small box contains 20 chocolate bars. How many chocolate bars are in the large box? Choose the correct option: A) 220 B) 490 C) 380 D) 300 E) 690 | <gadget id="calculator">15 * 20</gadget>
<output>300</output>
<result>D</result> | D | 300 | A large box contains 15 small boxes and each small box contains 20 chocolate bars. How many chocolate bars are in the large box? | {
"A": "220",
"B": "490",
"C": "380",
"D": "300",
"E": "690"
} | multiply(15, 20) | multiply(n0,n1)| | "the only thing you have to do is a simple multiply we have : 15 * 20 = 300 correct answer is : d ) 300" | general |
math_qa__2G4OjJq5gTzMg9cD | The length of the bridge, which a train 170 metres long and travelling at 45 km/hr can cross in 30 seconds, is? Options:
A) 245
B) 777
C) 282
D) 266
E) 205 | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 170</gadget>
<output>205</output>
<result>E</result> | E | 205 | The length of the bridge, which a train 170 metres long and travelling at 45 km/hr can cross in 30 seconds, is? | {
"A": "245",
"B": "777",
"C": "282",
"D": "266",
"E": "205"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 170) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "speed = [ 45 x 5 / 18 ] m / sec = [ 25 / 2 ] m / sec time = 30 sec let the length of bridge be x metres . then , ( 170 + x ) / 30 = 25 / 2 = > 2 ( 170 + x ) = 750 = > x = 205 m . answer : e" | physics |
math_qa__IJJzBhg1QDnPi24P | A retail appliance store priced a video recorder at 20 percent above the wholesale cost of $200. If a store employee applied the 5 percent employee discount to the retail price to buy the recorder, how much did the employee pay for the recorder? Choose the correct choice.
A) $ 198 B) $ 228 C) $ 220 D) $ 230 E) $ 240 | <gadget id="calculator">200 / 100</gadget>
<output>2</output>
<gadget id="calculator">2 * 20</gadget>
<output>40</output>
<gadget id="calculator">200 + 40</gadget>
<output>240</output>
<gadget id="calculator">240 / 100</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 5</gadget>
<output>12</output>
<gadget id="calculator">240 - 12</gadget>
<output>228</output>
<result>B</result> | B | 228 | A retail appliance store priced a video recorder at 20 percent above the wholesale cost of $200. If a store employee applied the 5 percent employee discount to the retail price to buy the recorder, how much did the employee pay for the recorder? | {
"A": "$ 198",
"B": "$ 228",
"C": "$ 220",
"D": "$ 230",
"E": "$ 240"
} | subtract(add(200, multiply(divide(200, const_100), 20)), multiply(divide(add(200, multiply(divide(200, const_100), 20)), const_100), 5)) | divide(n1,const_100)|multiply(n0,#0)|add(n1,#1)|divide(#2,const_100)|multiply(n2,#3)|subtract(#2,#4)| | "wholesale cost of video recorder = 200 $ video recorder was priced at 20 percent above 200 = 240 $ % discount given by store employee = 5 emlpoyee paid = . 95 * 240 = 228 $ answer b" | gain |
math_qa__pDsQkR8Pr7Cv5818 | If a#b = ab – b + b^2, then 3#6 =
Answers: A) 2 B) 8 C) 15 D) 21 E) 48 | <gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">18 - 6</gadget>
<output>12</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">12 + 36</gadget>
<output>48</output>
<result>E</result> | E | 48 | If a#b = ab – b + b^2, then 3#6 = | {
"A": "2",
"B": "8",
"C": "15",
"D": "21",
"E": "48"
} | add(subtract(multiply(3, 6), 6), power(6, 2)) | multiply(n1,n2)|power(n2,n0)|subtract(#0,n2)|add(#1,#2)| | "solution - simply substitute 3 and 6 in equation in the place of a and b respectively . 3 # 6 = 3 * 6 - 6 + 6 ^ 2 = 18 - 6 + 36 = 48 . ans e" | general |
math_qa__aC2ioXiTnT7rIcQZ | A man engaged a servant on a condition that he'll pay Rs 90 and also give him a bag at the end of the yr. He served for 9 months and was given a turban and Rs 65. So the price of turban is Pick one
A) rs 10 B) rs 9 C) rs 0 D) rs 55 E) rs 8 | <gadget id="calculator">90 / 12</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 10</gadget>
<output>75</output>
<gadget id="calculator">75 - 65</gadget>
<output>10</output>
<result>A</result> | A | 10 | A man engaged a servant on a condition that he'll pay Rs 90 and also give him a bag at the end of the yr. He served for 9 months and was given a turban and Rs 65. So the price of turban is | {
"A": "rs 10",
"B": "rs 9",
"C": "rs 0",
"D": "rs 55",
"E": "rs 8"
} | subtract(multiply(divide(90, const_12), const_10), 65) | divide(n0,const_12)|multiply(#0,const_10)|subtract(#1,n2) | let the value of turban = rs x for 1 year = 90 + x for 9 months ( i , e 3 / 4 year ) = 65 + x i , e 1 : ( 90 + x ) : : 3 / 4 : ( 65 + x ) i , e ( 90 + x ) / ( 65 + x ) = 1 / ( 3 / 4 ) 270 + 3 x = 260 + 4 x thus x = 10 answer : a | general |
math_qa__0zUfobpa5PmuupfN | If W is the set of all the integers between 29 and 99, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers?
Choose the correct choice: A) 26 B) 32 C) 33 D) 34 E) 47 | <gadget id="calculator">99 - 29</gadget>
<output>70</output>
<gadget id="calculator">70 / 3</gadget>
<output>70/3 = around 23.333333</output>
<gadget id="calculator">floor(70/3)</gadget>
<output>23</output>
<gadget id="calculator">70 / 2</gadget>
<output>35</output>
<gadget id="calculator">23 + 35</gadget>
<output>58</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">70 / 6</gadget>
<output>35/3 = around 11.666667</output>
<gadget id="calculator">floor(35/3)</gadget>
<output>11</output>
<gadget id="calculator">58 - 11</gadget>
<output>47</output>
<result>E</result> | E | 47 | If W is the set of all the integers between 29 and 99, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers? | {
"A": "26",
"B": "32",
"C": "33",
"D": "34",
"E": "47"
} | subtract(add(floor(divide(subtract(99, 29), 3)), divide(subtract(99, 29), 2)), floor(divide(subtract(99, 29), multiply(2, 3)))) | multiply(n3,n2)|subtract(n1,n0)|divide(#1,n3)|divide(#1,n2)|divide(#1,#0)|floor(#3)|floor(#4)|add(#2,#5)|subtract(#7,#6)| | "multiples of 2 from 29 to 99 = multiples of 2 from 1 to 99 - multiples of 2 from 1 to 28 = [ 99 / 2 ] - [ 28 / 2 ] = 49 - 14 = 35 multiples of 3 from 29 to 99 = multiples of 3 from 1 to 99 - multiples of 3 from 1 to 28 = [ 99 / 3 ] - [ 28 / 3 ] = 33 - 9 = 24 multiples of 2 and 3 bothi . e . 6 from 29 to 99 = multiples of 6 from 1 to 99 - multiples of 6 from 1 to 28 = [ 99 / 6 ] - [ 28 / 6 ] = 16 - 4 = 12 these 8 numbers have been counted twice in both the above calculation while calculating multiples of 2 and 3 i . e . total numbers in w = 35 + 24 - 12 = 47 answer option e" | other |
math_qa__vL05BMbASeR9o2hF | For a certain exam,a score of 86 was 7 standard deviations below mean and a score of 90 was 3 standard deviations above mean.What was the mean score for the exam? Choose the correct answer: A) 86.25 B) 84 C) 85 D) 88.8 E) 80 | <gadget id="calculator">86 * 3</gadget>
<output>258</output>
<gadget id="calculator">90 * 7</gadget>
<output>630</output>
<gadget id="calculator">258 + 630</gadget>
<output>888</output>
<gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">888 / 10</gadget>
<output>444/5 = around 88.8</output>
<result>D</result> | D | 88.8 | For a certain exam,a score of 86 was 7 standard deviations below mean and a score of 90 was 3 standard deviations above mean.What was the mean score for the exam? | {
"A": "86.25",
"B": "84",
"C": "85",
"D": "88.8",
"E": "80"
} | divide(add(multiply(86, 3), multiply(90, 7)), add(7, 3)) | add(n1,n3)|multiply(n0,n3)|multiply(n1,n2)|add(#1,#2)|divide(#3,#0)| | "mean - 7 sd = 86 mean + 3 sd = 90 by solving above equations we get , sd ( absolute value ) = 0.4 mean = 88.8 ans . d" | general |
math_qa__uZVHRZTVN9S82GQ2 | In a division, a student took 72 as divisor instead of 36. his answer was 24 . The correct answer is- Choices.
A) 42 B) 32 C) 48 D) 28 E) 38 | <gadget id="calculator">72 * 24</gadget>
<output>1_728</output>
<gadget id="calculator">1_728 / 36</gadget>
<output>48</output>
<result>C</result> | C | 48 | In a division, a student took 72 as divisor instead of 36. his answer was 24 . The correct answer is- | {
"A": "42",
"B": "32",
"C": "48",
"D": "28",
"E": "38"
} | divide(multiply(72, 24), 36) | multiply(n0,n2)|divide(#0,n1)| | "x / 72 = 24 . x = 24 * 72 . so correct answer would be , ( 24 * 72 ) / 36 = 48 . answer : c" | general |
math_qa__7J0E4xpRje7QrI9f | a scientist used a unique two - color code to identify each of the test subjects involved in a certain study . if the scientist found that choosing from among 5 colors produced enough color codes to identify all but 6 of the test subjects , how many test subjects were in the study ? ( assume that the order of the colors in the codes does not matter . ) Pick one.
A) 14
B) 15
C) 16
D) 17
E) 18 | <gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">120 / 12</gadget>
<output>10</output>
<gadget id="calculator">10 + 6</gadget>
<output>16</output>
<result>C</result> | C | 16 | a scientist used a unique two - color code to identify each of the test subjects involved in a certain study . if the scientist found that choosing from among 5 colors produced enough color codes to identify all but 6 of the test subjects , how many test subjects were in the study ? ( assume that the order of the colors in the codes does not matter . ) | {
"A": "14",
"B": "15",
"C": "16",
"D": "17",
"E": "18"
} | add(divide(factorial(5), multiply(factorial(subtract(5, const_2)), factorial(const_2))), 6) | factorial(n0)|factorial(const_2)|subtract(n0,const_2)|factorial(#2)|multiply(#3,#1)|divide(#0,#4)|add(n1,#5) | 5 c 2 = 10 the number of test subjects is 10 + 6 = 16 the answer is c . | general |
math_qa__1KwQWPCamM89e4kZ | Enrollment in City College in 1980 was 85/3 percent of enrollment in 1990. What was the percent increase in the college’s enrollment from 1980 to 1990? Choose the correct choice from the following options
A) 100 % B) 16 2 / 3 % C) 200 % D) 253 % E) 183 1 / 3 % | <gadget id="calculator">85 / 3</gadget>
<output>85/3 = around 28.333333</output>
<gadget id="calculator">100 - (85/3)</gadget>
<output>215/3 = around 71.666667</output>
<gadget id="calculator">(215/3) / (85/3)</gadget>
<output>43/17 = around 2.529412</output>
<gadget id="calculator">(43/17) * 100</gadget>
<output>4_300/17 = around 252.941176</output>
<result>D</result> | D | 253 | Enrollment in City College in 1980 was 85/3 percent of enrollment in 1990. What was the percent increase in the college’s enrollment from 1980 to 1990? | {
"A": "100 %",
"B": "16 2 / 3 %",
"C": "200 %",
"D": "253 %",
"E": "183 1 / 3 %"
} | multiply(divide(subtract(const_100, divide(85, 3)), divide(85, 3)), const_100) | divide(n1,n2)|subtract(const_100,#0)|divide(#1,#0)|multiply(#2,const_100) | assume 100 enrollments present in 1990 85 / 3 % of 1990 = enrollments on 1980 enrollments on 1980 = 28.33 % change = ( enrollment in 1990 - enrollment in 1980 ) * 100 / ( enrollment in 1980 ) = ( 100 - 28.33 ) * 100 / 28.333 = 7166.67 / 28.333 = 253 % ans - d | general |
math_qa__aYZgKQirEiqjeuQB | There were two candidates in an election. Winner candidate received 54% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate? Choose the correct choice from the following answers:
A) 776
B) 1944
C) 2199
D) 2157
E) 2125 | <gadget id="calculator">100 - 54</gadget>
<output>46</output>
<gadget id="calculator">54 - 46</gadget>
<output>8</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">288 / (2/25)</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 * 54</gadget>
<output>194_400</output>
<gadget id="calculator">194_400 / 100</gadget>
<output>1_944</output>
<result>B</result> | B | 1,944 | There were two candidates in an election. Winner candidate received 54% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate? | {
"A": "776",
"B": "1944",
"C": "2199",
"D": "2157",
"E": "2125"
} | divide(multiply(divide(288, divide(subtract(54, subtract(const_100, 54)), const_100)), 54), const_100) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)| | "w = 54 % l = 46 % 54 % - 46 % = 8 % 8 % - - - - - - - - 288 54 % - - - - - - - - ? = > 1944 answer : b" | gain |
math_qa__fJtrANkyKX5KneKn | A person bought 115 glass bowls at a rate of Rs. 18 per bowl. He sold 104 of them at Rs. 20 and the remaining broke. What is the percentage gain for A? Choose the correct choice from the following choices: A) 40 B) 300 / 11 C) 243 / 7 D) 279 / 11 E) 100 / 207 | <gadget id="calculator">104 * 20</gadget>
<output>2_080</output>
<gadget id="calculator">115 * 18</gadget>
<output>2_070</output>
<gadget id="calculator">2_080 - 2_070</gadget>
<output>10</output>
<gadget id="calculator">10 / 2_070</gadget>
<output>1/207 = around 0.004831</output>
<gadget id="calculator">(1/207) * 100</gadget>
<output>100/207 = around 0.483092</output>
<result>E</result> | E | 0.483092 | A person bought 115 glass bowls at a rate of Rs. 18 per bowl. He sold 104 of them at Rs. 20 and the remaining broke. What is the percentage gain for A? | {
"A": "40",
"B": "300 / 11",
"C": "243 / 7",
"D": "279 / 11",
"E": "100 / 207"
} | multiply(divide(subtract(multiply(104, 20), multiply(115, 18)), multiply(115, 18)), const_100) | multiply(n2,n3)|multiply(n0,n1)|subtract(#0,#1)|divide(#2,#1)|multiply(#3,const_100)| | "cp = 115 * 18 = 2070 and sp = 104 * 20 = 2080 gain % = 100 * ( 2080 - 2070 ) / 2070 = 100 / 207 answer : e" | gain |
math_qa__Kbv4ZCIYAcR0WXTO | Lisa and Robert have taken the same number of photos on their school trip. Lisa has taken 3 times as many photos as Claire and Robert has taken 10 more photos than Claire. How many photos has Claire taken? Answers.
A) 5 B) 8 C) 11 D) 12 E) 14 | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>A</result> | A | 5 | Lisa and Robert have taken the same number of photos on their school trip. Lisa has taken 3 times as many photos as Claire and Robert has taken 10 more photos than Claire. How many photos has Claire taken? | {
"A": "5",
"B": "8",
"C": "11",
"D": "12",
"E": "14"
} | divide(10, subtract(3, const_1)) | subtract(n0,const_1)|divide(n1,#0)| | "l = r l = 3 c r = c + 10 3 c = c + 10 c = 5 the answer is a ." | general |
math_qa__CbNveeLA5nga7JTt | How many even multiples of 45 are there between 449 and 901?
Pick
A) 5 B) 6 C) 9 D) 10 E) 11 | <gadget id="calculator">901 - 449</gadget>
<output>452</output>
<gadget id="calculator">45 * 2</gadget>
<output>90</output>
<gadget id="calculator">452 / 90</gadget>
<output>226/45 = around 5.022222</output>
<gadget id="calculator">(226/45) + 1</gadget>
<output>271/45 = around 6.022222</output>
<result>B</result> | B | 6 | How many even multiples of 45 are there between 449 and 901? | {
"A": "5",
"B": "6",
"C": "9",
"D": "10",
"E": "11"
} | add(divide(subtract(901, 449), multiply(45, const_2)), const_1) | multiply(n0,const_2)|subtract(n2,n1)|divide(#1,#0)|add(#2,const_1) | 450 = 10 * 45 900 = 20 * 45 the even multiples are 45 multiplied by 10 , 12 , 14 , 16 , 18 , and 20 for a total of 6 . the answer is b . | general |
math_qa__FLaqneQDR7h878WS | 19 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? Choose the correct choice from the following: A) 286 B) 342 C) 422 D) 540 E) 618 | <gadget id="calculator">19 - 1</gadget>
<output>18</output>
<gadget id="calculator">19 * 18</gadget>
<output>342</output>
<result>B</result> | B | 342 | 19 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? | {
"A": "286",
"B": "342",
"C": "422",
"D": "540",
"E": "618"
} | multiply(19, subtract(19, const_1)) | subtract(n0,const_1)|multiply(n0,#0)| | "2 * 19 c 2 = 2 * 171 = 342 the answer is b ." | general |
math_qa__qf6uGmkmcz0jC8KE | Rs.585 is divided amongst A, B, C so that 4 times A's share, 6 times B's share and 3 times C's share are all equal. Find C's share? Pick.
A) 260
B) 150
C) 817
D) 716
E) 616 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/4) + (1/2)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) + 1</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">585 / (9/4)</gadget>
<output>260</output>
<result>A</result> | A | 260 | Rs.585 is divided amongst A, B, C so that 4 times A's share, 6 times B's share and 3 times C's share are all equal. Find C's share? | {
"A": "260",
"B": "150",
"C": "817",
"D": "716",
"E": "616"
} | divide(585, add(add(divide(3, 4), divide(3, 6)), const_1)) | divide(n3,n1)|divide(n3,n2)|add(#0,#1)|add(#2,const_1)|divide(n0,#3)| | a + b + c = 585 4 a = 6 b = 3 c = x a : b : c = 1 / 4 : 1 / 6 : 1 / 3 = 3 : 2 : 4 4 / 9 * 585 = rs . 260 answer : a | general |
math_qa__1ecnFby746tO5dJm | In 10 years, A will be twice as old as B was 10 years ago. If A is now 8 years older than B the present age of B is Choose the most appropriate option
A) 37 B) 38 C) 39 D) 40 E) 41 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">30 + 8</gadget>
<output>38</output>
<result>B</result> | B | 38 | In 10 years, A will be twice as old as B was 10 years ago. If A is now 8 years older than B the present age of B is | {
"A": "37",
"B": "38",
"C": "39",
"D": "40",
"E": "41"
} | add(add(multiply(const_2, 10), 10), 8) | multiply(n0,const_2)|add(n0,#0)|add(n2,#1)| | "let present age of a be a and b be b a + 10 = 2 * ( b - 10 ) = > 2 b - a = 30 . . . . . . ( i ) a = b + 8 = > 2 b - b - 8 = 30 b = 38 so the present age of b is 38 years answer : b" | general |
math_qa__5ZB8dM6kXktFnrgN | A man can row his boat with the stream at 14 km/h and against the stream in 4 km/h. The man's rate is? Answers:
A) 1 kmph
B) 3 kmph
C) 8 kmph
D) 7 kmph
E) 5 kmph | <gadget id="calculator">14 - 4</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>E</result> | E | 5 | A man can row his boat with the stream at 14 km/h and against the stream in 4 km/h. The man's rate is? | {
"A": "1 kmph",
"B": "3 kmph",
"C": "8 kmph",
"D": "7 kmph",
"E": "5 kmph"
} | divide(subtract(14, 4), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "ds = 14 us = 4 s = ? s = ( 14 - 4 ) / 2 = 5 kmph answer : e" | gain |
math_qa__nRlshwbaenSarpPA | Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent T of the original cost? Choose the correct choice from the following options: A) t = 200 B) t = 600 C) t = 800 D) t = 1600 E) t = 50 | <gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<result>D</result> | D | 1,600 | Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent T of the original cost? | {
"A": "t = 200",
"B": "t = 600",
"C": "t = 800",
"D": "t = 1600",
"E": "t = 50"
} | multiply(power(const_2, 4), const_100) | power(const_2,n0)|multiply(#0,const_100)| | "original cost c 1 = t 1 * b 1 ^ 4 new cost c 2 = t 2 * b 2 ^ 4 . . . . only b is doubled so t 2 = t 1 and b 2 = 2 b 1 c 2 = t 2 * ( 2 b 1 ) ^ 4 = 16 ( t 1 * b 1 ^ 4 ) = 16 c 1 16 times c 1 = > 1600 % of c 1 ans d = 1600" | general |
math_qa__fKb3q1IJVQJSpXJZ | In a certain egg-processing plant, every egg must be inspected, and is either accepted for processing or rejected. For every 96 eggs accepted for processing, 4 eggs are rejected. If, on a particular day, 12 additional eggs were accepted, but the overall number of eggs inspected remained the same, the ratio of those accepted to those rejected would be 99 to 1. How many Q eggs does the plant process per day? Choose one: A) 100 B) 300 C) 400 D) 3000 E) 4000 | <gadget id="calculator">99 - 96</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<result>C</result> | C | 400 | In a certain egg-processing plant, every egg must be inspected, and is either accepted for processing or rejected. For every 96 eggs accepted for processing, 4 eggs are rejected. If, on a particular day, 12 additional eggs were accepted, but the overall number of eggs inspected remained the same, the ratio of those accepted to those rejected would be 99 to 1. How many Q eggs does the plant process per day? | {
"A": "100",
"B": "300",
"C": "400",
"D": "3000",
"E": "4000"
} | multiply(divide(12, subtract(99, 96)), const_100) | subtract(n3,n0)|divide(n2,#0)|multiply(#1,const_100) | straight pluggin in for me . as usual , i started with c and got the answer . lets ' back calculate and see what we get let us consider eggs processed each day to be 400 so initial ratio of eggs processed and rejected is 96 : 4 or 24 : 1 so out of 400 eggs , there will be 384 eggs processed and 16 rejected . now if the no . of eggs inspected remain and 12 more eggs get accepted that means there q = 384 + 12 = 396 eggs accepted and 4 rejected . . . and the ratio will be 99 : 1 bingo . . . this is what the questions says . . . . its always a good idea to start with c . | general |
math_qa__aSkKqQaslfezG7xX | A certain country had a total annual expenditure of $1.2 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure? Choose the correct choice from the following options.
A) $ 500 B) $ 1,000 C) $ 2,000 D) $ 3,000 E) $ 5,000 | <gadget id="calculator">10 ** 11</gadget>
<output>100_000_000_000</output>
<gadget id="calculator">1.2 * 100_000_000_000</gadget>
<output>120_000_000_000</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">10 ** 6</gadget>
<output>1_000_000</output>
<gadget id="calculator">240 * 1_000_000</gadget>
<output>240_000_000</output>
<gadget id="calculator">120_000_000_000 / 240_000_000</gadget>
<output>500</output>
<result>A</result> | A | 500 | A certain country had a total annual expenditure of $1.2 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure? | {
"A": "$ 500",
"B": "$ 1,000",
"C": "$ 2,000",
"D": "$ 3,000",
"E": "$ 5,000"
} | divide(multiply(1.2, power(10, 11)), multiply(240, power(10, add(const_4, const_2)))) | add(const_2,const_4)|power(n1,n2)|multiply(n0,#1)|power(n1,#0)|multiply(n3,#3)|divide(#2,#4)| | "total expenditure / population = per capita expenditure hence , ( 1,2 x 10 ^ 11 ) / 240 000 000 = ( 12 x 10 ^ 10 ) / ( 2,4 x 10 ^ 8 ) = 5 x 10 ^ ( 10 - 8 ) = 5 x 10 ^ 2 = 500 . answer is a ." | general |
math_qa__qHIVaECkC1zvdDAd | If x is the product of the positive integers from 1 to 8, inclusive, and if i, k, m, and p are positive integers such that x=2^i∗3^k∗5^m∗7^p, then i + k + m + p = Choose the correct option
A) 4 B) 7 C) 8 D) 11 E) 12 | <gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">5 / 5</gadget>
<output>1</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">3 / 3</gadget>
<output>1</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<result>D</result> | D | 11 | If x is the product of the positive integers from 1 to 8, inclusive, and if i, k, m, and p are positive integers such that x=2^i∗3^k∗5^m∗7^p, then i + k + m + p = | {
"A": "4",
"B": "7",
"C": "8",
"D": "11",
"E": "12"
} | add(add(add(7, 2), divide(5, 5)), divide(3, 3)) | add(n2,n5)|divide(n4,n4)|divide(n3,n3)|add(#0,#1)|add(#3,#2)| | "here the idea is to go expressing each factor from one to eight , decomposed into its primes : 1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 = 1 * 2 * 3 * ( 2 * 2 ) * 5 + ( 2 * 3 ) * 7 * ( 2 * 2 * 2 ) = 2 ^ 7 * 3 ^ 2 * 5 ^ 1 * 7 ^ 1 then i = 7 k = 2 m = 1 p = 1 i + k + m + p = 11 correct answer d" | general |
math_qa__RXDolEZqVesrXfuZ | Each side of a rectangular field diminished by 40%. By how much per cent is the area of the field diminished? Choose one.
A) 32 B) 64 C) 25 D) 16 E) none | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">60 * 60</gadget>
<output>3_600</output>
<gadget id="calculator">10_000 - 3_600</gadget>
<output>6_400</output>
<gadget id="calculator">6_400 / 10_000</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">(16/25) * 100</gadget>
<output>64</output>
<result>B</result> | B | 64 | Each side of a rectangular field diminished by 40%. By how much per cent is the area of the field diminished? | {
"A": "32",
"B": "64",
"C": "25",
"D": "16",
"E": "none"
} | multiply(divide(subtract(multiply(const_100, const_100), multiply(subtract(const_100, 40), subtract(const_100, 40))), multiply(const_100, const_100)), const_100) | multiply(const_100,const_100)|subtract(const_100,n0)|multiply(#1,#1)|subtract(#0,#2)|divide(#3,#0)|multiply(#4,const_100) | solution : let the original length of the rectangle be 20 unit and breadth be 10 unit . then original area = length * breadth = 20 * 10 = 200 square unit . 40 % decrease in each side , then length = ( 20 - 40 % of 20 ) = 12 unit . breadth = ( 10 - 40 % of 10 ) = 6 unit . now , area = 12 * 6 = 72 square unit . decrease in area = 200 - 72 = 128 square unit . % decrease in area = ( 128 / 200 ) * 100 = 64 % mind calculation method : let the original area be 100 square unit . 100 = = = 40 % ↓ ( decrease in length ) = = = > 60 = = = 40 % ↓ = = = ( decrease in breadth ) = = = > 36 . diminished in area = 100 - 36 = 64 % answer : option b | geometry |
math_qa__BF8YCNjMhoBhPB23 | The average of 10 numbers is calculated as 14. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is? Pick:
A) 16 B) 15 C) 19 D) 22 E) 24 | <gadget id="calculator">36 - 26</gadget>
<output>10</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">14 + 1</gadget>
<output>15</output>
<result>B</result> | B | 15 | The average of 10 numbers is calculated as 14. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is? | {
"A": "16",
"B": "15",
"C": "19",
"D": "22",
"E": "24"
} | add(14, divide(subtract(36, 26), 10)) | subtract(n2,n3)|divide(#0,n0)|add(n1,#1)| | "explanation : 10 * 14 + 36 – 26 = 150 = > 150 / 10 = 15 b )" | general |
math_qa__CyAGoMqJNjT5OTdk | There are two groups of students in the sixth grade. There are 20 students in group A, and 80 students in group B. If, on a particular day, 20% of the students in group A forget their homework, and 15% of the students in group B forget their homework, then what percentage of the sixth graders forgot their homework? Choose the correct choice from the following options
A) 13 % B) 14 % C) 15 % D) 16 % E) 17 % | <gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">400 / 100</gadget>
<output>4</output>
<gadget id="calculator">80 * 15</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 100</gadget>
<output>12</output>
<gadget id="calculator">4 + 12</gadget>
<output>16</output>
<gadget id="calculator">20 + 80</gadget>
<output>100</output>
<gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * 100</gadget>
<output>16</output>
<result>D</result> | D | 16 | There are two groups of students in the sixth grade. There are 20 students in group A, and 80 students in group B. If, on a particular day, 20% of the students in group A forget their homework, and 15% of the students in group B forget their homework, then what percentage of the sixth graders forgot their homework? | {
"A": "13 %",
"B": "14 %",
"C": "15 %",
"D": "16 %",
"E": "17 %"
} | multiply(divide(add(divide(multiply(20, 20), const_100), divide(multiply(80, 15), const_100)), add(20, 80)), const_100) | add(n0,n1)|multiply(n0,n2)|multiply(n1,n3)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100)| | "number of students in group a = 20 students who forget homework in group a = 20 % of 20 = 4 students number of students in group b = 80 students who forget homework in group b = 15 % of 80 = 12 students total number of students = 20 + 80 = 100 students who forgot homework = 4 + 12 = 16 students percentage of students who forget homework = 16 / 100 * 100 = 16 % answer : d" | gain |
math_qa__begANVYYa055LV0q | The average of 6 quantities is 8. The average of 4 of them is 5. What is the avg. of the remaining 2 numbers? Choose the correct answer
A) 11 B) 12 C) 13 D) 14 E) 15 | <gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">48 - 20</gadget>
<output>28</output>
<gadget id="calculator">28 / 2</gadget>
<output>14</output>
<result>D</result> | D | 14 | The average of 6 quantities is 8. The average of 4 of them is 5. What is the avg. of the remaining 2 numbers? | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | divide(subtract(multiply(6, 8), multiply(4, 5)), 2) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)|divide(#2,n4)| | "sum of 8 quantities = total no of quantities x average of them = 6 x 8 = 48 sum of 4 quantities = 4 x 5 = 20 sum of 4 quantities + sum of 2 quantities = sum of 6 quantities 20 + sum of 2 quantities = 48 sum of 2 quantities = 28 average of 2 quantities = sum of 2 quantities / 2 = 28 / 2 = 14 answer : d" | general |
math_qa__ROjv4Z6DAanrjIDt | Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.4048. What is the difference between Rohan’s and Sudhir’s share in the profit?
Choose the correct choice from the following options.
A) s . 345 B) s . 350 C) s . 352 D) s . 362 E) s . 368 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">12_000 * (3/4)</gadget>
<output>9_000</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">9_000 * (2/3)</gadget>
<output>6_000</output>
<gadget id="calculator">9_000 - 6_000</gadget>
<output>3_000</output>
<gadget id="calculator">18_000 + 9_000</gadget>
<output>27_000</output>
<gadget id="calculator">27_000 + 6_000</gadget>
<output>33_000</output>
<gadget id="calculator">4_048 / 33_000</gadget>
<output>46/375 = around 0.122667</output>
<gadget id="calculator">3_000 * (46/375)</gadget>
<output>368</output>
<result>E</result> | E | 368 | Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.4048. What is the difference between Rohan’s and Sudhir’s share in the profit? | {
"A": "s . 345",
"B": "s . 350",
"C": "s . 352",
"D": "s . 362",
"E": "s . 368"
} | multiply(subtract(multiply(12000, divide(subtract(multiply(3, 4), 3), multiply(3, 4))), multiply(9000, divide(subtract(multiply(3, 4), 4), multiply(3, 4)))), divide(4048, add(add(18000, multiply(12000, divide(subtract(multiply(3, 4), 3), multiply(3, 4)))), multiply(9000, divide(subtract(multiply(3, 4), 4), multiply(3, 4)))))) | multiply(n1,n2)|subtract(#0,n1)|subtract(#0,n2)|divide(#1,#0)|divide(#2,#0)|multiply(n3,#3)|multiply(n4,#4)|add(n0,#5)|subtract(#5,#6)|add(#7,#6)|divide(n5,#9)|multiply(#10,#8)| | "suresh : rohan : sudhir ratio of their investments = 18000 × 12 : 12000 × 9 : 9000 × 8 = 6 : 3 : 2 the difference between rohan ’ s and sudhir ’ s share = 1 share : . i . e . = rs . 4048 × 1 / 11 = rs . 368 . e" | gain |
math_qa__52LO5RjV7cSKUDMV | A man has Rs.10350 in the form of Rs.50 notes and Rs.500 notes. The total number of notes are 90.Find the number of notes of Rs.50 denomination. Select the correct option.
A) 15 B) 21 C) 17 D) 57 E) 77 | <gadget id="calculator">500 * 90</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 - 10_350</gadget>
<output>34_650</output>
<gadget id="calculator">500 - 50</gadget>
<output>450</output>
<gadget id="calculator">34_650 / 450</gadget>
<output>77</output>
<result>E</result> | E | 77 | A man has Rs.10350 in the form of Rs.50 notes and Rs.500 notes. The total number of notes are 90.Find the number of notes of Rs.50 denomination. | {
"A": "15",
"B": "21",
"C": "17",
"D": "57",
"E": "77"
} | divide(subtract(multiply(500, 90), 10350), subtract(500, 50)) | multiply(n2,n3)|subtract(n2,n1)|subtract(#0,n0)|divide(#2,#1) | total money = rs . 10350 . let 50 rupees note was x . then 500 rupees note = 90 - x now , 50 * x + 500 * ( 90 - x ) = 10350 50 x + 45000 - 500 x = 10350 - 450 x = - 34650 x = 77 . no . of 50 rupees note = 77 . answer : option e | general |
math_qa__5ENJrTa4sv5js8F2 | The average age of an adult class is 40years. 12new students with an avg age of 32years join the class. Thereforedecreasing the average by 4year. Find what was theoriginal strength of class?
Select: A) 10 B) 12 C) 16 D) 20 E) 22 | <gadget id="calculator">40 - 4</gadget>
<output>36</output>
<gadget id="calculator">12 * 36</gadget>
<output>432</output>
<gadget id="calculator">12 * 32</gadget>
<output>384</output>
<gadget id="calculator">432 - 384</gadget>
<output>48</output>
<gadget id="calculator">48 / 4</gadget>
<output>12</output>
<result>B</result> | B | 12 | The average age of an adult class is 40years. 12new students with an avg age of 32years join the class. Thereforedecreasing the average by 4year. Find what was theoriginal strength of class? | {
"A": "10",
"B": "12",
"C": "16",
"D": "20",
"E": "22"
} | divide(subtract(multiply(12, subtract(40, 4)), multiply(12, 32)), 4) | multiply(n1,n2)|subtract(n0,n3)|multiply(n1,#1)|subtract(#2,#0)|divide(#3,n3)| | "let original strength = y then , 40 y + 12 x 32 = ( y + 12 ) x 36 ⇒ 40 y + 384 = 36 y + 432 ⇒ 4 y = 48 ∴ y = 12 b" | general |
math_qa__OcXL2KXtQnXB0A6F | The distance from the x-axis to point P is half the distance from the y-axis to point P. If the coordinates of P are (x,-5), how many units is P from the y-axis? Choose the correct choice from the following.
A) 2.5 B) 5 C) 7.5 D) 10 E) 12 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<result>D</result> | D | 10 | The distance from the x-axis to point P is half the distance from the y-axis to point P. If the coordinates of P are (x,-5), how many units is P from the y-axis? | {
"A": "2.5",
"B": "5",
"C": "7.5",
"D": "10",
"E": "12"
} | multiply(5, const_2) | multiply(n0,const_2)| | "the x - axis is 5 units from the point p . thus the y - axis is 10 units from the point p . the answer is d ." | general |
math_qa__1toj3gG3wCcDv6Ti | We bought a total of 90 books at the store. Math books cost $4 and history books cost $5. The total price was $397. How many math books did we buy? Choose the correct choice from the following
A) 47
B) 53
C) 56
D) 61
E) 64 | <gadget id="calculator">90 * 4</gadget>
<output>360</output>
<gadget id="calculator">397 - 360</gadget>
<output>37</output>
<gadget id="calculator">90 - 37</gadget>
<output>53</output>
<result>B</result> | B | 53 | We bought a total of 90 books at the store. Math books cost $4 and history books cost $5. The total price was $397. How many math books did we buy? | {
"A": "47",
"B": "53",
"C": "56",
"D": "61",
"E": "64"
} | subtract(90, subtract(397, multiply(90, 4))) | multiply(n0,n1)|subtract(n3,#0)|subtract(n0,#1)| | "let m be the number of math books and let h be the number of history books . m + h = 90 . h = 90 - m . 4 m + 5 h = 397 . 4 m + 5 ( 90 - m ) = 397 . - m + 450 = 397 . m = 450 - 397 = 53 . the answer is b ." | general |
math_qa__c1thXNomZhtAt9s4 | Two employees A and B are paid a total of Rs. 580 per week by their employer. If A is paid 150 percent of the sum paid to B, how much is B paid per week? Choose the correct answer:
A) s . 130
B) s . 140
C) s . 150
D) s . 232
E) s . 280 | <gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">580 / (5/2)</gadget>
<output>232</output>
<result>D</result> | D | 232 | Two employees A and B are paid a total of Rs. 580 per week by their employer. If A is paid 150 percent of the sum paid to B, how much is B paid per week? | {
"A": "s . 130",
"B": "s . 140",
"C": "s . 150",
"D": "s . 232",
"E": "s . 280"
} | divide(580, add(divide(150, const_100), const_1)) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)| | "let the amount paid to a per week = x and the amount paid to b per week = y then x + y = 580 but x = 150 % of y = 150 y / 100 = 15 y / 10 ∴ 15 y / 10 + y = 580 ⇒ y [ 15 / 10 + 1 ] = 580 ⇒ 25 y / 10 = 580 ⇒ 25 y = 5800 ⇒ y = 5800 / 25 = rs . 232 d )" | general |
math_qa__zYLFMAdzuRi8WowH | At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 7 pencils and 11 charts have been brought to the meeting, how many people are present? Select:
A) 6
B) 7
C) 8
D) 9
E) 10 | <gadget id="calculator">11 + 7</gadget>
<output>18</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">18 / 3</gadget>
<output>6</output>
<result>A</result> | A | 6 | At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 7 pencils and 11 charts have been brought to the meeting, how many people are present? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | divide(add(11, 7), add(2, 1)) | add(n4,n5)|add(n0,n1)|divide(#0,#1)| | "say there are ' a ' associate professors . so we have 2 a pencils and a charts . say there are ' b ' assistant professors . so we have b pencils and 2 b charts . total pencils are 10 so 2 a + b = 7 total charts are 11 so a + 2 b = 11 add both : 3 a + 3 b = 18 so a + b = 6 total number of people = 6 a" | general |
math_qa__hbf6Uag1PmEEjlpN | The difference between the value of a number increased by 12.5% and the value of the original number decreased by 25% is 30. What is the original number R?
Choose the correct option: A) 60 B) 80 C) 40 D) 120 E) 160 | <gadget id="calculator">12.5 / 100</gadget>
<output>0.125</output>
<gadget id="calculator">1 + 0.125</gadget>
<output>1.125</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1.125 - (3/4)</gadget>
<output>0.375</output>
<gadget id="calculator">30 / 0.375</gadget>
<output>80</output>
<result>B</result> | B | 80 | The difference between the value of a number increased by 12.5% and the value of the original number decreased by 25% is 30. What is the original number R? | {
"A": "60",
"B": "80",
"C": "40",
"D": "120",
"E": "160"
} | divide(30, subtract(add(const_1, divide(12.5, const_100)), subtract(const_1, divide(25, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|subtract(#2,#3)|divide(n2,#4)| | "( 1 + 1 / 8 ) x - ( 1 - 1 / 4 ) x = 30 ( 9 / 8 ) x - ( 3 / 4 ) x = 30 x = 80 = r answer : b" | general |
math_qa__JeWlxYEXyJerphpA | The average height of 35 boys in a class was calculated as 182cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).? Choose the correct choice from the following options.
A) 180.27 cm B) 180.29 cm C) 978.29 cm D) 178.89 cm E) 176.29 cm | <gadget id="calculator">35 * 182</gadget>
<output>6_370</output>
<gadget id="calculator">6_370 - 166</gadget>
<output>6_204</output>
<gadget id="calculator">6_204 + 106</gadget>
<output>6_310</output>
<gadget id="calculator">6_310 / 35</gadget>
<output>1_262/7 = around 180.285714</output>
<gadget id="calculator">floor(1_262/7)</gadget>
<output>180</output>
<result>B</result> | B | 180.29 | The average height of 35 boys in a class was calculated as 182cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).? | {
"A": "180.27 cm",
"B": "180.29 cm",
"C": "978.29 cm",
"D": "178.89 cm",
"E": "176.29 cm"
} | floor(divide(add(subtract(multiply(35, 182), 166), 106), 35)) | multiply(n0,n1)|subtract(#0,n2)|add(n3,#1)|divide(#2,n0)|floor(#3)| | "calculated average height of 35 boys = 182 cm . wrong total height of 35 boys = 182 * 35 cm . this was as a result of an actual height of 106 cm being wrongly written as 166 cm . correct total height of 35 boys = 182 cm - ( 166 cm - 106 cm ) / 35 = 182 cm - 60 / 35 cm = 182 cm - 1.71 cm = 180.29 cm . answer : b" | general |
math_qa__qD9viKnIqFv61dFh | The salaries of A and B together amount to $3000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary? Choose the correct option: A) $ 1000 B) $ 1250 C) $ 2500 D) $ 2250 E) $ 1200 | <gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">100 - 95</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">3_000 / 4</gadget>
<output>750</output>
<gadget id="calculator">3_000 - 750</gadget>
<output>2_250</output>
<result>D</result> | D | 2,250 | The salaries of A and B together amount to $3000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary? | {
"A": "$ 1000",
"B": "$ 1250",
"C": "$ 2500",
"D": "$ 2250",
"E": "$ 1200"
} | subtract(3000, divide(3000, add(divide(subtract(const_100, 85), subtract(const_100, 95)), const_1))) | subtract(const_100,n2)|subtract(const_100,n1)|divide(#0,#1)|add(#2,const_1)|divide(n0,#3)|subtract(n0,#4)| | "let a ' s salary is x b ' s salary = 3000 - x ( 100 - 95 ) % of x = ( 100 - 85 ) % of ( 3000 - x ) x = $ 2250 answer is d" | gain |
math_qa__lU1yIkKS3a0VKJ9Z | If a number is subtracted from its square we get 272. Find the number?
Choose the correct choice from the following options.
A) 7 B) 21 C) 19 D) 15 E) 17 | <gadget id="calculator">4 * 272</gadget>
<output>1_088</output>
<gadget id="calculator">1 + 1_088</gadget>
<output>1_089</output>
<gadget id="calculator">1_089 ** (1/2)</gadget>
<output>33</output>
<gadget id="calculator">1 + 33</gadget>
<output>34</output>
<gadget id="calculator">34 / 2</gadget>
<output>17</output>
<result>E</result> | E | 17 | If a number is subtracted from its square we get 272. Find the number? | {
"A": "7",
"B": "21",
"C": "19",
"D": "15",
"E": "17"
} | divide(add(const_1, sqrt(add(const_1, multiply(const_4, 272)))), const_2) | multiply(n0,const_4)|add(#0,const_1)|sqrt(#1)|add(#2,const_1)|divide(#3,const_2) | x ^ 2 â € “ x = 272 = > x = 17 answer e | geometry |
math_qa__YrVGkACKdqzSXer1 | if solomon distributes his toys in the ratio of 1 / 4 : 1 / 6 : 1 / 10 : 1 / 9 between his 4 friends a , b , c and d , then find the total number of toys solomon should have ? Choose the correct answer
A) 111.7 B) 118.7 C) 113.7 D) 218.7 E) 418.7 | <gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">100 + 18</gadget>
<output>118</output>
<result>B</result> | B | 118.7 | if solomon distributes his toys in the ratio of 1 / 4 : 1 / 6 : 1 / 10 : 1 / 9 between his 4 friends a , b , c and d , then find the total number of toys solomon should have ? | {
"A": "111.7",
"B": "118.7",
"C": "113.7",
"D": "218.7",
"E": "418.7"
} | add(add(multiply(10, 6), multiply(10, 4)), multiply(6, const_3)) | multiply(n3,n5)|multiply(n1,n5)|multiply(n3,const_3)|add(#0,#1)|add(#3,#2) | here , a : b : c : d = 1 / 4 : 1 / 6 : 1 / 10 : 1 / 9 1 ) l . c . m of 4 : 6 : 10 : 9 is 180 2 ) find the number of pens each friend received - - - - - - - - - ( to find no . of pens each friend has , multiply the ratio with the l . c . m . calculated ) a = ( 1 / 4 ) x 180 = 45 b = ( 1 / 6 ) x 180 = 30 c = ( 1 / 10 ) x 180 = 18 d = ( 1 / 7 ) x 180 = 25.7 3 ) total number of toys = ( 45 x + 30 x + 18 x + 25.7 x ) = 118.7 x minimum number of pens ( x ) = 1 therefore , total number of pens = 118.7 pens . correct option : b | general |
math_qa__o7p6Liww8E0D78jO | The area of a circular field is 13.86 hectares. Find the cost of fencing it at the rate of Rs. 4.40 per metre.
Choose the correct answer:
A) 2399 B) 3888 C) 2999 D) 5808 E) 2888 | <gadget id="calculator">13.86 / pi</gadget>
<output>13.86/pi = around 4.411775</output>
<gadget id="calculator">(13.86/pi) ** (1/2)</gadget>
<output>3.72290209379726/sqrt(pi) = around 2.100423</output>
<gadget id="calculator">(3.72290209379726/sqrt(pi)) * 100</gadget>
<output>372.290209379726/sqrt(pi) = around 210.042258</output>
<gadget id="calculator">2 * pi * (372.290209379726/sqrt(pi))</gadget>
<output>744.580418759452*sqrt(pi) = around 1_319.734431</output>
<gadget id="calculator">(744.580418759452*sqrt(pi)) * 4.4</gadget>
<output>3276.15384254159*sqrt(pi) = around 5_806.831494</output>
<result>D</result> | D | 5,808 | The area of a circular field is 13.86 hectares. Find the cost of fencing it at the rate of Rs. 4.40 per metre. | {
"A": "2399",
"B": "3888",
"C": "2999",
"D": "5808",
"E": "2888"
} | multiply(circumface(multiply(sqrt(divide(13.86, const_pi)), const_100)), 4.40) | divide(n0,const_pi)|sqrt(#0)|multiply(#1,const_100)|circumface(#2)|multiply(#3,n1)| | "explanation : area = ( 13.86 x 10000 ) sq . m = 138600 sq . m circumference = cost of fencing = rs . ( 1320 x 4.40 ) = rs . 5808 . answer : d ) 5808" | geometry |
math_qa__hICxX8dOkj4KoHwi | A 13% stock yields 8%.The market value of the stock is : Choose the correct choice from the following
A) rs . 72 B) rs . 92 C) rs . 162.50 D) rs . 116.50 E) none of these | <gadget id="calculator">100 / 8</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 13</gadget>
<output>325/2 = around 162.5</output>
<result>C</result> | C | 162.5 | A 13% stock yields 8%.The market value of the stock is : | {
"A": "rs . 72",
"B": "rs . 92",
"C": "rs . 162.50",
"D": "rs . 116.50",
"E": "none of these"
} | multiply(divide(const_100, 8), 13) | divide(const_100,n1)|multiply(n0,#0)| | "solution to obtain rs . 8 , investment = rs . 100 . to obtain rs . 13 , investment = rs . ( 100 / 8 x 13 ) = rs . 162.50 ∴ market value of rs . 100 stock = rs . 162.50 answer c" | gain |
math_qa__8vYhwwZA6zlS8xnu | From a container, 6 liters milk was drawn out and was replaced by water. Again 6 liters of mixture was drawn out and was replaced by the water. Thus the quantity of milk and water in the container after these two operations is 9:16. The quantity of mixture is: Choices:
A) 15 B) 26 C) 22 D) 27 E) 11 | <gadget id="calculator">9 + 16</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>A</result> | A | 15 | From a container, 6 liters milk was drawn out and was replaced by water. Again 6 liters of mixture was drawn out and was replaced by the water. Thus the quantity of milk and water in the container after these two operations is 9:16. The quantity of mixture is: | {
"A": "15",
"B": "26",
"C": "22",
"D": "27",
"E": "11"
} | divide(multiply(6, sqrt(add(9, 16))), const_2) | add(n2,n3)|sqrt(#0)|multiply(n0,#1)|divide(#2,const_2) | explanation : let quantity of mixture be x liters . suppose a container contains x units of liquid from which y units are taken out and replaced by water . after operations , the quantity of pure liquid = units , where n = no of operations . so , quantity of milk = given that , milk : water = 9 : 16 milk : ( milk + water ) = 9 : ( 9 + 16 ) milk : mixture = 9 : 25 answer : a ) 15 | other |
math_qa__reDylpqPdFqmKpcx | The speed of a subway train is represented by the equation z=s^2+2s for all situations where 0≤s≤7, where z is the rate of speed in kilometers per hour and s is the time in seconds from the moment the train starts moving. In kilometers per hour, how much faster is the subway train moving after 7 seconds than it was moving after 2 seconds? Select the correct option:
A) 4 B) 55 C) 15 D) 48 E) 63 | <gadget id="calculator">7 ** 2</gadget>
<output>49</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">49 + 14</gadget>
<output>63</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">63 - 8</gadget>
<output>55</output>
<result>B</result> | B | 55 | The speed of a subway train is represented by the equation z=s^2+2s for all situations where 0≤s≤7, where z is the rate of speed in kilometers per hour and s is the time in seconds from the moment the train starts moving. In kilometers per hour, how much faster is the subway train moving after 7 seconds than it was moving after 2 seconds? | {
"A": "4",
"B": "55",
"C": "15",
"D": "48",
"E": "63"
} | subtract(add(power(7, 2), multiply(7, 2)), add(power(2, 2), multiply(2, 2))) | multiply(n0,n4)|multiply(n0,n5)|power(n4,n0)|power(n5,n0)|add(#0,#2)|add(#1,#3)|subtract(#4,#5)| | "given : z = s ^ 2 + 2 s for 0 ≤ s ≤ 7 z ( 2 ) = 2 ^ 2 + 2 * 2 = 8 z ( 7 ) = 7 ^ 2 + 2 * 7 = 63 therefore z ( 7 ) - z ( 3 ) = 63 - 8 = 55 km / hr option b" | physics |
math_qa__6eD0VkohQJyYYo9A | The diagonals of a rhombus are 11 cm and 16 cm. Find its area? Answers: A) 277 B) 266 C) 150 D) 88 E) 212 | <gadget id="calculator">(11 * 16) / 2</gadget>
<output>88</output>
<result>D</result> | D | 88 | The diagonals of a rhombus are 11 cm and 16 cm. Find its area? | {
"A": "277",
"B": "266",
"C": "150",
"D": "88",
"E": "212"
} | rhombus_area(11, 16) | rhombus_area(n0,n1)| | "1 / 2 * 11 * 16 = 88 answer : d" | geometry |
math_qa__DGV0bDDsmSj1Axwe | In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.6 times as old as Robert? Choose the correct choice from the following options
A) 1960 B) 1965 C) 1970 D) 1975 E) 1990 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">1.6 + 7</gadget>
<output>8.6</output>
<gadget id="calculator">1_950 + 8.6</gadget>
<output>1_958.6</output>
<result>E</result> | E | 1,990 | In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.6 times as old as Robert? | {
"A": "1960",
"B": "1965",
"C": "1970",
"D": "1975",
"E": "1990"
} | add(1950, add(1.6, add(4, 3))) | add(n3,n1)|add(n4,#0)|add(n0,#1)| | "in 1950 : ri = 4 ro - - - - - - - - - - - - - - eq 1 in 1955 : ri + 5 = 3 ( ro + 5 ) - - - - - - - - - eq 2 thus in 1950 , solving eq 1 and eq 2 1950 ro = 10 , ri = 40 1990 ro = 50 , ri = 80 = 1.6 times thus ans : e" | general |
math_qa__CJvxUu4rB6zlBoN0 | A room is 8 meters 16 centimeters in length and 4 meters 32 centimeters in Width. Find the least number of square tiles of equal size required to cover the entire floor of the room. Options: A) 107 B) 153 C) 178 D) 198 E) 165 | <gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">800 + 16</gadget>
<output>816</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">400 + 32</gadget>
<output>432</output>
<gadget id="calculator">816 * 432</gadget>
<output>352_512</output>
<gadget id="calculator">gcd(816, 432)</gadget>
<output>48</output>
<gadget id="calculator">48 * 48</gadget>
<output>2_304</output>
<gadget id="calculator">352_512 / 2_304</gadget>
<output>153</output>
<result>B</result> | B | 153 | A room is 8 meters 16 centimeters in length and 4 meters 32 centimeters in Width. Find the least number of square tiles of equal size required to cover the entire floor of the room. | {
"A": "107",
"B": "153",
"C": "178",
"D": "198",
"E": "165"
} | divide(multiply(add(multiply(8, const_100), 16), add(multiply(4, const_100), 32)), multiply(gcd(add(multiply(8, const_100), 16), add(multiply(4, const_100), 32)), gcd(add(multiply(8, const_100), 16), add(multiply(4, const_100), 32)))) | multiply(n0,const_100)|multiply(n2,const_100)|add(n1,#0)|add(n3,#1)|gcd(#2,#3)|multiply(#2,#3)|multiply(#4,#4)|divide(#5,#6)| | "let us calculate both the length and width of the room in centimeters . length = 8 meters and 16 centimeters = 816 cm width = 4 meters and 32 centimeters = 432 cm as we want the least number of square tiles required , it means the length of each square tile should be as large as possible . further , the length of each square tile should be a factor of both the length and width of the room . hence , the length of each square tile will be equal to the hcf of the length and width of the room = hcf of 816 and 432 = 48 thus , the number of square tiles required = ( 816 x 432 ) / ( 48 x 48 ) = 17 x 9 = 153 answer : b" | general |
math_qa__y5QZRPk0Dc0QHk6v | Victor gets 92 % marks in examinations. If these are 460 marks, find the maximum marks.
Choose the correct answer.
A) 334 B) 500 C) 376 D) 288 E) 271 | <gadget id="calculator">92 / 100</gadget>
<output>23/25 = around 0.92</output>
<gadget id="calculator">460 / (23/25)</gadget>
<output>500</output>
<result>B</result> | B | 500 | Victor gets 92 % marks in examinations. If these are 460 marks, find the maximum marks. | {
"A": "334",
"B": "500",
"C": "376",
"D": "288",
"E": "271"
} | divide(460, divide(92, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "let the maximum marks be m then 92 % of m = 460 ⇒ 92 / 100 × m = 460 ⇒ m = ( 460 × 100 ) / 92 ⇒ m = 46000 / 92 ⇒ m = 500 therefore , maximum marks in the examinations are 500 . answer : b" | gain |
math_qa__gU7CzyNScmuvFXMK | Max planned to buy bike, sales man advised him to buy within this month, If he purchase next month means State Tax will be increasing 10% than its cost and it would be 82500. What is the bike's Selling price in this month
Select:
A) 70000 B) 73000 C) 75000 D) 77000 E) 79000 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">82_500 / (11/10)</gadget>
<output>75_000</output>
<result>C</result> | C | 75,000 | Max planned to buy bike, sales man advised him to buy within this month, If he purchase next month means State Tax will be increasing 10% than its cost and it would be 82500. What is the bike's Selling price in this month | {
"A": "70000",
"B": "73000",
"C": "75000",
"D": "77000",
"E": "79000"
} | divide(82500, add(divide(10, const_100), const_1)) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1) | sp * ( 110 / 100 ) = 82500 sp = 750 * 100 = > sp = 75000 answer : c | general |
math_qa__Q1OADtwjZX3oGw9e | A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming. The distance between his house and school is? Choose the correct choice from the following answers
A) 3 B) 4 C) 6 D) 5 E) 7 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">5 / (5/2)</gadget>
<output>2</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<result>C</result> | C | 6 | A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming. The distance between his house and school is? | {
"A": "3",
"B": "4",
"C": "6",
"D": "5",
"E": "7"
} | multiply(divide(5, add(divide(3, 2), const_1)), 3) | divide(n0,n1)|add(#0,const_1)|divide(n2,#1)|multiply(n0,#2)| | "average speed = ( 2 * 3 * 2 ) / ( 3 + 2 ) = 12 / 5 km / hr . distance traveled = 12 / 5 * 5 = 12 km . distance between house and school = 12 / 2 = 6 km . answer : c" | physics |
math_qa__TYaUgmwgqbDA5cft | Find the perimeter of a triangle with sides measuring 7 centimeters, 10 centimeters and 15 centimeters. Choose the correct choice:
A) 10 cm
B) 15 cm
C) 32 cm
D) 35 cm
E) 20 cm | <gadget id="calculator">7 + 10 + 15</gadget>
<output>32</output>
<result>C</result> | C | 32 | Find the perimeter of a triangle with sides measuring 7 centimeters, 10 centimeters and 15 centimeters. | {
"A": "10 cm",
"B": "15 cm",
"C": "32 cm",
"D": "35 cm",
"E": "20 cm"
} | triangle_perimeter(7, 10, 15) | triangle_perimeter(n0,n1,n2) | perimeter of triangle = a + b + c perimeter = 7 cm + 10 cm + 15 cm = 32 cm answer : c . | geometry |
math_qa__Kt6GQHj65yUgIqlg | In a 500 m race, Ravi beats Ramesh by 5 seconds or 100 m. They decide to run another race and this time Ravi gives Ramesh a head tart of 200 m. If Ravi’s speed is twice his previous speed and Ramesh’s speed is one and half times his previous speed, how far from the starting point should the winning post be so that they finish at the same time? Choose one:
A) 500 m B) 1000 m C) 1500 m D) 2000 m E) 2500 m | <gadget id="calculator">500 * 1</gadget>
<output>500</output>
<result>A</result> | A | 500 | In a 500 m race, Ravi beats Ramesh by 5 seconds or 100 m. They decide to run another race and this time Ravi gives Ramesh a head tart of 200 m. If Ravi’s speed is twice his previous speed and Ramesh’s speed is one and half times his previous speed, how far from the starting point should the winning post be so that they finish at the same time? | {
"A": "500 m",
"B": "1000 m",
"C": "1500 m",
"D": "2000 m",
"E": "2500 m"
} | multiply(500, const_1) | multiply(n0,const_1) | ravi beats ramesh by 5 sec or 100 mtr . . . . means ramesh cover 100 mtr in 5 sec . . . . by this we can get ramesh speed in 20 m / sec 20 . . . . . . . . . . . . . in 1 sec 500 . . . . . . . . in 500 / 20 = 25 sec ( ramesh ' s time ) so ravi take 20 sec to cover 500 mtr . . . . . . by this we can get that ravis speed is 25 m / sec now assume x be the distance from staring line where we need to put the winning post . according to question ravi ’ s speed will be 25 * 2 = 50 m / sec & ramesh ’ s speed will be 20 * 1.5 = 30 m / sec now assume x be the distance from staring line where we need to put the winning post . they will take same time to reach the wining post . as ravi gives ramesh a 200 m ahead start so he has to accede x meter and ramesh has to accede ( x - 200 ) meter hence we may write , x / 50 = ( x - 200 ) / 30 x = 500 meter answer : a | physics |
math_qa__Vn9JsQfyZg2cjXvQ | Two isosceles Triangles have equal vertical angles and their areas are in the ratio 25:49. Find the ratio of their corresponding heights . Choose the most appropriate option.
A) 4 / 5 B) 5 / 4 C) 3 / 2 D) 5 / 7 E) 2 / 3 | <gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">49 ** (1/2)</gadget>
<output>7</output>
<gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<result>D</result> | D | 0.714286 | Two isosceles Triangles have equal vertical angles and their areas are in the ratio 25:49. Find the ratio of their corresponding heights . | {
"A": "4 / 5",
"B": "5 / 4",
"C": "3 / 2",
"D": "5 / 7",
"E": "2 / 3"
} | divide(sqrt(25), sqrt(49)) | sqrt(n0)|sqrt(n1)|divide(#0,#1)| | "we are basically given that the triangles are similar . in two similar triangles , the ratio of their areas is the square of the ratio of their sides and also , the square of the ratio of their corresponding heights . therefore , area / area = height ^ 2 / height ^ 2 = 25 / 49 - - > height / height = 5 / 7 . answer : d ." | geometry |
math_qa__3TkLV68P12xmyMim | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 280, then how much amount should C pay as his share of rent? Choose the correct choice from the following answers
A) 35 B) 45 C) 25 D) 72 E) 55 | <gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">70 + 60</gadget>
<output>130</output>
<gadget id="calculator">130 + 45</gadget>
<output>175</output>
<gadget id="calculator">45 / 175</gadget>
<output>9/35 = around 0.257143</output>
<gadget id="calculator">280 * (9/35)</gadget>
<output>72</output>
<result>D</result> | D | 72 | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 280, then how much amount should C pay as his share of rent? | {
"A": "35",
"B": "45",
"C": "25",
"D": "72",
"E": "55"
} | multiply(280, divide(multiply(15, 3), add(add(multiply(10, 7), multiply(12, 5)), multiply(15, 3)))) | multiply(n4,n5)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|add(#3,#0)|divide(#0,#4)|multiply(n6,#5) | a : b : c = 10 × 7 : 12 × 5 : 15 × 3 = 2 × 7 : 12 × 1 : 3 × 3 = 14 : 12 : 9 amount that c should pay = 280 × 9 / 35 = 8 × 9 = 72 answer is d | general |
math_qa__VXHnCcctYeHHbYHS | Exactly 30% of the reporters for a certain wire service cover local politics in Country X. If 25% of the reporters who cover politics for the wire service do not cover local politics in Country X, what percent of the reporters for the wire service do not cover politics? Options
A) 20 % B) 42 % C) 60 % D) 80 % E) 84 % | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">30 / 75</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>C</result> | C | 60 | Exactly 30% of the reporters for a certain wire service cover local politics in Country X. If 25% of the reporters who cover politics for the wire service do not cover local politics in Country X, what percent of the reporters for the wire service do not cover politics? | {
"A": "20 %",
"B": "42 %",
"C": "60 %",
"D": "80 %",
"E": "84 %"
} | multiply(subtract(const_1, divide(30, subtract(const_100, 25))), const_100) | subtract(const_100,n1)|divide(n0,#0)|subtract(const_1,#1)|multiply(#2,const_100) | let ' s assume there are 100 reporters - - > 30 reporters cover local politics . now , as 25 % of the reporters who cover all politics do not cover local politics then the rest 75 % of the reporters who cover politics do cover local politics , so if there are x reporters who cover politics then 75 % of them equal to 30 ( # of reporters who cover local politics ) : 0.75 x = 30 - - > x = 40 , hence 40 reporters cover politics and the rest 100 - 40 = 60 reporters do not cover politics at all . answer : c . | gain |
math_qa__Z9qiGQp6XT9KXhXK | Excluding stoppages, the speed of a train is 48 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour? Choose the correct choice
A) 16 B) 17 C) 15 D) 18 E) 12 | <gadget id="calculator">36 / 48</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">60 * (3/4)</gadget>
<output>45</output>
<gadget id="calculator">60 - 45</gadget>
<output>15</output>
<result>C</result> | C | 15 | Excluding stoppages, the speed of a train is 48 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour? | {
"A": "16",
"B": "17",
"C": "15",
"D": "18",
"E": "12"
} | subtract(const_60, multiply(const_60, divide(36, 48))) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "t = 12 / 48 * 60 = 15 answer : c" | physics |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.