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math_qa__nHMJkkIGHF2vE1GS | How many kg of pure salt must be added to 100kg of 10% solution of salt and water to increase it to a 25% solution? Select
A) 6.7 B) 1.3 C) 9.6 D) 20 E) 7.9 | <gadget id="calculator">25 - 10</gadget>
<output>15</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">15 / (3/4)</gadget>
<output>20</output>
<result>D</result> | D | 20 | How many kg of pure salt must be added to 100kg of 10% solution of salt and water to increase it to a 25% solution? | {
"A": "6.7",
"B": "1.3",
"C": "9.6",
"D": "20",
"E": "7.9"
} | divide(subtract(25, 10), subtract(const_1, divide(25, 100))) | divide(n2,n0)|subtract(n2,n1)|subtract(const_1,#0)|divide(#1,#2)| | "amount salt in 100 kg solution = 10 * 100 / 100 = 10 kg let x kg of pure salt be added then ( 10 + x ) / ( 100 + x ) = 25 / 100 40 + 4 x = 100 + x 3 x = 60 x = 20 answer is d" | general |
math_qa__64598uy0c5eZmXat | My grandson is about as many days as my son in weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 140 years. Can you tell me my age in years? Pick
A) 80 B) 90 C) 85 D) 84 E) 89 | <gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">140 / 20</gadget>
<output>7</output>
<gadget id="calculator">7 * 12</gadget>
<output>84</output>
<result>D</result> | D | 84 | My grandson is about as many days as my son in weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 140 years. Can you tell me my age in years? | {
"A": "80",
"B": "90",
"C": "85",
"D": "84",
"E": "89"
} | multiply(divide(140, add(const_10, const_10)), const_12) | add(const_10,const_10)|divide(n0,#0)|multiply(#1,const_12) | let the age of the man = x years so according to the given condition age of my grandson = x / 12 years and age of my son = x 30 / 52 = 15 x / 26 and x + ( x / 12 ) + ( 15 x / 26 ) = 140 or ( 156 x + 13 x + 90 x ) / 156 = 140 or 259 x = 156 * 140 or x = 156 * 140 / 259 = 84 answer : d | physics |
math_qa__g44WBtzZQFpaE6ZX | a chartered bank offers a 5 - year escalator guaranteed investment certificate . in successive years it pays annual interest rates of 4 % , 4.5 % , 5 % , 5.5 % , and 6 % , respectively , compounded at the end of each year . the bank also offers regular 5 - year gics paying a fixed rate of 5 % compounded annually . calculate and compare the maturity values of $ 1000 invested in each type of gic . ( note that 5 % is the average of the 5 successive one - year rates paid on the escalator gic . ) Choose the correct option
A) 1276.28 B) 1276.22 C) 1276.29 D) 1276.21 E) 1276.23 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 5</gadget>
<output>4_084_101/3_200_000 = around 1.276282</output>
<gadget id="calculator">(4_084_101/3_200_000) * 1_000</gadget>
<output>4_084_101/3_200 = around 1_276.281563</output>
<result>A</result> | A | 1,276.28 | a chartered bank offers a 5 - year escalator guaranteed investment certificate . in successive years it pays annual interest rates of 4 % , 4.5 % , 5 % , 5.5 % , and 6 % , respectively , compounded at the end of each year . the bank also offers regular 5 - year gics paying a fixed rate of 5 % compounded annually . calculate and compare the maturity values of $ 1000 invested in each type of gic . ( note that 5 % is the average of the 5 successive one - year rates paid on the escalator gic . ) | {
"A": "1276.28",
"B": "1276.22",
"C": "1276.29",
"D": "1276.21",
"E": "1276.23"
} | multiply(power(add(divide(5, const_100), const_1), 5), 1000) | divide(n0,const_100)|add(#0,const_1)|power(#1,n0)|multiply(n8,#2) | explanation : fv = $ 1000 ( 1.04 ) ( 1.045 ) ( 1.05 ) ( 1.055 ) ( 1.06 ) = $ 1276.14 the maturity value of the regular gic is fv = $ = $ 1276.28 answer : a ) 1276.28 | gain |
math_qa__nLK8ouqXCdSS7UXf | On a trip covering 350 km, a bicyclist travels the first 200 km at 20 km per hour and the remainder of the distance at 15 km per hour. What is the average speed, in km per hour, for the entire trip? Options
A) 15.5 B) 16.0 C) 17.5 D) 19.0 E) 18.5 | <gadget id="calculator">200 / 20</gadget>
<output>10</output>
<gadget id="calculator">350 - 200</gadget>
<output>150</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">350 / 20</gadget>
<output>35/2 = around 17.5</output>
<result>C</result> | C | 17.5 | On a trip covering 350 km, a bicyclist travels the first 200 km at 20 km per hour and the remainder of the distance at 15 km per hour. What is the average speed, in km per hour, for the entire trip? | {
"A": "15.5",
"B": "16.0",
"C": "17.5",
"D": "19.0",
"E": "18.5"
} | speed(350, add(divide(200, 20), divide(subtract(350, 200), 15))) | divide(n1,n2)|subtract(n0,n1)|divide(#1,n3)|add(#0,#2)|speed(n0,#3)| | "time 1 = 200 / 20 = 10 hours time 2 = 150 / 15 = 10 hours total time = 20 hours average speed = 350 / 20 = 17.5 km / hr the answer is c ." | physics |
math_qa__tAwzhK85QdKO4CHD | How many seconds will a 1200 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? Pick one
A) 26 sec B) 65 sec C) 55 sec D) 19 sec E) 72 sec | <gadget id="calculator">63 - 3</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">1_200 / (50/3)</gadget>
<output>72</output>
<result>E</result> | E | 72 | How many seconds will a 1200 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr? | {
"A": "26 sec",
"B": "65 sec",
"C": "55 sec",
"D": "19 sec",
"E": "72 sec"
} | divide(1200, multiply(subtract(63, 3), const_0_2778)) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 63 - 3 = 60 km / hr . = 60 * 5 / 18 = 50 / 3 m / sec . time taken to pass the man = 1200 * 3 / 50 = 72 sec . answer : e" | physics |
math_qa__Vb1m3dx9nV9CDmJG | The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.30 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
Select the correct option.
A) 399 B) 272 C) 865.8 D) 277 E) 311 | <gadget id="calculator">3_136 ** (1/2)</gadget>
<output>56</output>
<gadget id="calculator">56 * 4</gadget>
<output>224</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">224 - 2</gadget>
<output>222</output>
<gadget id="calculator">222 * 1.3</gadget>
<output>288.6</output>
<gadget id="calculator">288.6 * 3</gadget>
<output>865.8</output>
<result>C</result> | C | 865.8 | The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.30 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost? | {
"A": "399",
"B": "272",
"C": "865.8",
"D": "277",
"E": "311"
} | multiply(multiply(subtract(multiply(sqrt(3136), const_4), multiply(const_2, 1)), 1.30), 3) | multiply(n3,const_2)|sqrt(n0)|multiply(#1,const_4)|subtract(#2,#0)|multiply(n2,#3)|multiply(#4,n1)| | "answer : option c explanation : a 2 = 3136 = > a = 56 56 * 4 * 3 = 672 Γ’ β¬ β 6 = 666 * 1.3 = 865.8 answer : c" | physics |
math_qa__d0Z2wni01dI3DQ71 | 25 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work? Choose the correct choice from the following options.
A) 8 days B) 6 days C) 7 days D) 9 days E) 10 days | <gadget id="calculator">25 * 7</gadget>
<output>175</output>
<gadget id="calculator">5 / 175</gadget>
<output>1/35 = around 0.028571</output>
<gadget id="calculator">25 * 14</gadget>
<output>350</output>
<gadget id="calculator">25 / 350</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">(1/35) + (1/14)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / (1/10)</gadget>
<output>10</output>
<result>E</result> | E | 10 | 25 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work? | {
"A": "8 days",
"B": "6 days",
"C": "7 days",
"D": "9 days",
"E": "10 days"
} | inverse(add(divide(5, multiply(25, 7)), divide(25, multiply(25, 14)))) | multiply(n0,n1)|multiply(n0,n3)|divide(n4,#0)|divide(n0,#1)|add(#2,#3)|inverse(#4)| | "1 women ' s 1 day work = 1 / 175 1 child ' s 1 day work = 1 / 140 ( 5 women + 10 children ) ' s 1 day work = ( 5 / 175 + 10 / 140 ) = 1 / 10 5 women and 10 children will complete the work in 10 days . answer : e" | physics |
math_qa__QWU7aPlFpeZ4QpnK | in arun ' s company 60 % of the employees earn less than $ 50000 a year , 60 % of the employees earn more than $ 40000 a year , 11 % of the employees earn $ 43000 a year and 5 % of the employees earn $ 49000 a year . what is the median salary for the company ? Select
A) 43.0 B) 45.5 C) 46.0 D) 49.0 E) 50.0 | <gadget id="calculator">2 * 43_000</gadget>
<output>86_000</output>
<gadget id="calculator">86_000 / 2</gadget>
<output>43_000</output>
<gadget id="calculator">43_000 / 100</gadget>
<output>430</output>
<gadget id="calculator">430 / 10</gadget>
<output>43</output>
<result>A</result> | A | 43 | in arun ' s company 60 % of the employees earn less than $ 50000 a year , 60 % of the employees earn more than $ 40000 a year , 11 % of the employees earn $ 43000 a year and 5 % of the employees earn $ 49000 a year . what is the median salary for the company ? | {
"A": "43.0",
"B": "45.5",
"C": "46.0",
"D": "49.0",
"E": "50.0"
} | divide(divide(divide(multiply(const_2, 43000), const_2), const_100), const_10) | multiply(n5,const_2)|divide(#0,const_2)|divide(#1,const_100)|divide(#2,const_10) | in arun ' s company 60 % of the employees earn less than $ 50,000 a year , 50 and 51 employee will be each 43 k . hence median = ( 43 k + 43 k ) / 2 | general |
math_qa__JuwJkIY3uto51Aox | 50 square stone slabs of equal size were needed to cover a floor area of 72 sq.m. Find the length of each stone slab?
Choices
A) 120 cm B) 767 cm C) 88 cm D) 666 cm E) 776 cm | <gadget id="calculator">72 / 50</gadget>
<output>36/25 = around 1.44</output>
<gadget id="calculator">(36/25) ** (1/2)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 100</gadget>
<output>120</output>
<result>A</result> | A | 120 | 50 square stone slabs of equal size were needed to cover a floor area of 72 sq.m. Find the length of each stone slab? | {
"A": "120 cm",
"B": "767 cm",
"C": "88 cm",
"D": "666 cm",
"E": "776 cm"
} | multiply(sqrt(divide(72, 50)), const_100) | divide(n1,n0)|sqrt(#0)|multiply(#1,const_100)| | "area of each slab = 72 / 50 m 2 = 1.44 m 2 length of each slab β 1.44 = 1.2 m = 120 cm" | geometry |
math_qa__nR8vxhzF5Uov5DAn | A certain company reported that the revenue on sales increased 40 % from 2000 to 2003, and increased 90 % from 2000 to 2005. What was the approximate percent increase in revenue for this store from 2003 to 2005? Choose the correct option
A) 50 % B) 36 % C) 30 % D) 32 % E) 29 % | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 + (9/10)</gadget>
<output>19/10 = around 1.9</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(19/10) - (7/5)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) / (7/5)</gadget>
<output>5/14 = around 0.357143</output>
<gadget id="calculator">(5/14) * 100</gadget>
<output>250/7 = around 35.714286</output>
<result>B</result> | B | 36 | A certain company reported that the revenue on sales increased 40 % from 2000 to 2003, and increased 90 % from 2000 to 2005. What was the approximate percent increase in revenue for this store from 2003 to 2005? | {
"A": "50 %",
"B": "36 %",
"C": "30 %",
"D": "32 %",
"E": "29 %"
} | multiply(divide(subtract(add(const_1, divide(90, const_100)), add(const_1, divide(40, const_100))), add(const_1, divide(40, const_100))), const_100) | divide(n3,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|subtract(#2,#3)|divide(#4,#3)|multiply(#5,const_100)| | "assume the revenue in 2000 to be 100 . then in 2003 it would be 140 and and in 2005 190 , so from 2003 to 2005 it increased by ( 190 - 140 ) / 140 = 50 / 140 = ~ 29 % . answer : b" | gain |
math_qa__bEnITuygqJjEw8BG | The number of the members of a club is more than 20 and less than 50. When 5 people sit at a table, other people exactly divided to 6-people groups (6 people sit at a table) or 7-people groups (7 people sit at a table). If the members are divided to 8-people groups, how many people will be left? Choices: A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">lcm(6, 7)</gadget>
<output>42</output>
<gadget id="calculator">42 + 5</gadget>
<output>47</output>
<gadget id="calculator">47 % 8</gadget>
<output>7</output>
<result>E</result> | E | 7 | The number of the members of a club is more than 20 and less than 50. When 5 people sit at a table, other people exactly divided to 6-people groups (6 people sit at a table) or 7-people groups (7 people sit at a table). If the members are divided to 8-people groups, how many people will be left? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | reminder(add(lcm(6, 7), 5), 8) | lcm(n3,n5)|add(n2,#0)|reminder(#1,n7) | the number of members is 7 k + 5 = 6 j + 5 the only number in this range which satisfies this is 47 . 47 / 8 = 5 ( 8 ) + 7 the answer is e . | general |
math_qa__AfY2SbJK2JIpwJ7y | A train 300 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
Choose the correct option
A) 5 sec
B) 9 sec
C) 12 sec
D) 18 sec
E) 19 sec | <gadget id="calculator">68 - 8</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">300 / (50/3)</gadget>
<output>18</output>
<result>D</result> | D | 18 | A train 300 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? | {
"A": "5 sec",
"B": "9 sec",
"C": "12 sec",
"D": "18 sec",
"E": "19 sec"
} | divide(300, multiply(subtract(68, 8), const_0_2778)) | subtract(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of the train relative to man = ( 68 - 8 ) kmph = ( 60 * 5 / 18 ) m / sec = ( 50 / 3 ) m / sec time taken by the train to cross the man = time taken by it to cover 300 m at 50 / 3 m / sec = 300 * 3 / 50 sec = 18 sec answer : d ." | physics |
math_qa__i4ev01RBNz0mdvwQ | At the store opening, Larry's Grocery had 50 Lemons and 60 Oranges. By closing, the store at 20 Lemons and 40 Oranges left. By approximately what percent did the ratio of Lemons to Orange decrease from opening to closing. Choose the correct choice from the following options:
A) 50.0 % B) 40.0 % C) 30.0 % D) 20.0 % E) 10.0 % | <gadget id="calculator">50 / 60</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">20 / 40</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(5/6) - (1/2)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) / (5/6)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>B</result> | B | 40 | At the store opening, Larry's Grocery had 50 Lemons and 60 Oranges. By closing, the store at 20 Lemons and 40 Oranges left. By approximately what percent did the ratio of Lemons to Orange decrease from opening to closing. | {
"A": "50.0 %",
"B": "40.0 %",
"C": "30.0 %",
"D": "20.0 %",
"E": "10.0 %"
} | multiply(divide(subtract(divide(50, 60), divide(20, 40)), divide(50, 60)), const_100) | divide(n0,n1)|divide(n2,n3)|subtract(#0,#1)|divide(#2,#0)|multiply(#3,const_100) | opening : lemons / oranges = 50 / 60 = 100 / 120 closing : lemons / oranges = 20 / 40 = 60 / 120 aside : it ' s useful to write both ratios with the same denominator . this allows us to ignore the denominator and focus solely on the numerators . so , our ratio went from 100 / 120 to 60 / 120 ignoring the denominators , we went from 100 to 60 the percent change = 100 ( difference in values ) / ( original value ) = ( 100 ) ( 100 - 60 ) / 100 = ( 100 ) ( 40 ) / 100 ) = 40 answer : b | general |
math_qa__UcE12mSX70kJYcbk | If x is a positive integer with fewer than 3 digits, what is the probability that Z x*(x + 1) is a multiple of either 4 or 5? Choose one.
A) 4 / 99
B) 2 / 25
C) 8 / 99
D) 49 / 100
E) 86 / 99 | <gadget id="calculator">100 / 4</gadget>
<output>25</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">50 + 40</gadget>
<output>90</output>
<gadget id="calculator">90 - 4</gadget>
<output>86</output>
<gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">86 / 99</gadget>
<output>86/99 = around 0.868687</output>
<result>E</result> | E | 0.868687 | If x is a positive integer with fewer than 3 digits, what is the probability that Z x*(x + 1) is a multiple of either 4 or 5? | {
"A": "4 / 99",
"B": "2 / 25",
"C": "8 / 99",
"D": "49 / 100",
"E": "86 / 99"
} | divide(subtract(add(multiply(divide(const_100, 4), const_2), multiply(divide(const_100, 5), const_2)), 4), subtract(const_100, 1)) | divide(const_100,n2)|divide(const_100,n3)|subtract(const_100,n1)|multiply(#0,const_2)|multiply(#1,const_2)|add(#3,#4)|subtract(#5,n2)|divide(#6,#2)| | "interesting question ! also one that we should be able to answer very quickly be keeping an eye on our best friends , the answer choices . we know that x belongs to the set { 1 , 2 , 3 , . . . , 99 } . we want to know the probability z that x ( x + 1 ) is a multiple of either 4 or 5 . when will this happen ? if either x or ( x + 1 ) is a multiple of 4 or 5 . since 4 * 5 is 20 , let ' s look at the first 20 numbers to get a rough idea of how often this happens . out of the numbers from 1 to 20 : 4 , 5 , 6 , 8 , 9 , 10 , 11 , 12 , 13 , 15 , 16 , 17 , 20 so , 14 out of the first 20 numbers match our criteria . since : probability = ( # of desired outcomes ) / ( total # of possibilities ) , we guesstimate the answer to be 14 / 20 . since ( e ) is the only answer greater than 1 / 2 , we go with ( e ) ." | general |
math_qa__C233apeeWN9fuFp4 | The cash realised on selling a 14% stock is Rs.108.25, brokerage being 1/4% is Answers
A) 123
B) 106
C) 108
D) 156
E) 240 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">108.25 - (1/4)</gadget>
<output>108</output>
<result>C</result> | C | 108 | The cash realised on selling a 14% stock is Rs.108.25, brokerage being 1/4% is | {
"A": "123",
"B": "106",
"C": "108",
"D": "156",
"E": "240"
} | subtract(108.25, divide(1, 4)) | divide(n2,n3)|subtract(n1,#0)| | "explanation : cash realised = rs . ( 108.25 - 0.25 ) = rs . 108 . answer : c" | general |
math_qa__b8JstQ88F2aixUJX | If y is 40% greater than x, than x is what % less than y? Choices.
A) 24.4 % B) 28.6 % C) 32.3 % D) 36.5 % E) 40.9 % | <gadget id="calculator">40 + 100</gadget>
<output>140</output>
<gadget id="calculator">40 / 140</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(2/7) * 100</gadget>
<output>200/7 = around 28.571429</output>
<result>B</result> | B | 28.6 | If y is 40% greater than x, than x is what % less than y? | {
"A": "24.4 %",
"B": "28.6 %",
"C": "32.3 %",
"D": "36.5 %",
"E": "40.9 %"
} | multiply(divide(40, add(40, const_100)), const_100) | add(n0,const_100)|divide(n0,#0)|multiply(#1,const_100)| | "y = 1.4 x x = y / 1.4 = 10 y / 14 = 5 y / 7 x is 2 / 7 less which is 28.6 % less than y . the answer is b ." | general |
math_qa__4AoxDySqdU7Wd19s | A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 16 heads and 41 legs. How many cats does the ship host? Choose the correct option:
A) 5 B) 6 C) 4 D) 7 E) 8 | <gadget id="calculator">41 - 1</gadget>
<output>40</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
<gadget id="calculator">15 * 4</gadget>
<output>60</output>
<gadget id="calculator">60 - 30</gadget>
<output>30</output>
<gadget id="calculator">10 / 30</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 15</gadget>
<output>5</output>
<result>A</result> | A | 5 | A luxury liner, Queen Marry II, is transporting several cats as well as the crew (sailors, a cook, and one-legged captain) to a nearby port. Altogether, these passengers have 16 heads and 41 legs. How many cats does the ship host? | {
"A": "5",
"B": "6",
"C": "4",
"D": "7",
"E": "8"
} | multiply(divide(subtract(subtract(41, const_1), multiply(subtract(16, const_1), const_2)), subtract(multiply(subtract(16, const_1), const_4), multiply(subtract(16, const_1), const_2))), subtract(16, const_1)) | subtract(n1,const_1)|subtract(n0,const_1)|multiply(#1,const_2)|multiply(#1,const_4)|subtract(#0,#2)|subtract(#3,#2)|divide(#4,#5)|multiply(#6,#1) | sa ' s + co + ca + cats = 16 . sa ' s + 1 + 1 + cats = 16 or sa ' s + cats = 14 . sa ' s ( 2 ) + 2 + 1 + cats * 4 = 41 sa ' s * 2 + cats * 4 = 38 or sa ' s + cats * 2 = 19 or 14 - cats + cat * 2 = 19 then cats = 5 a | general |
math_qa__VH2UJ4nkB1wUCM96 | In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.85$. Assuming that a company owns 12 cars and that every fuel tank contains 55 liters and they are all empty, how much money total will it cost to fuel all cars? Choose the correct choice from the following answers.
A) 320 $ B) 420 $ C) 582 $ D) 650 $ E) 780 $ | <gadget id="calculator">0.85 * 55</gadget>
<output>46.75</output>
<gadget id="calculator">46.75 * 12</gadget>
<output>561</output>
<result>C</result> | C | 582 | In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.85$. Assuming that a company owns 12 cars and that every fuel tank contains 55 liters and they are all empty, how much money total will it cost to fuel all cars? | {
"A": "320 $",
"B": "420 $",
"C": "582 $",
"D": "650 $",
"E": "780 $"
} | multiply(multiply(0.85, 55), 12) | multiply(n1,n3)|multiply(n2,#0)| | 12 * 1.75 + 0.85 * 12 * 55 = 582 hence - c | general |
math_qa__4UVPBh1JkEylNUBC | What sum of money will produce Rs.75 as simple interest in 4 years at 3 1/2 percent? Choose the correct choice: A) 337 B) 500 C) 266 D) 288 E) 536 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + (1/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">4 * (7/2)</gadget>
<output>14</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">75 / (7/50)</gadget>
<output>3_750/7 = around 535.714286</output>
<result>E</result> | E | 536 | What sum of money will produce Rs.75 as simple interest in 4 years at 3 1/2 percent? | {
"A": "337",
"B": "500",
"C": "266",
"D": "288",
"E": "536"
} | divide(75, divide(multiply(4, add(3, divide(1, 2))), const_100)) | divide(n3,n4)|add(n2,#0)|multiply(n1,#1)|divide(#2,const_100)|divide(n0,#3)| | "75 = ( p * 4 * 7 / 2 ) / 100 p = 536 answer : e" | gain |
math_qa__H37MinEdRhE6s8sN | Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 16000, then find his savings? Select the correct option
A) 3600 B) 3607 C) 3200 D) 3602 E) 3603 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 16_000</gadget>
<output>12_800</output>
<gadget id="calculator">16_000 - 12_800</gadget>
<output>3_200</output>
<result>C</result> | C | 3,200 | Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 16000, then find his savings? | {
"A": "3600",
"B": "3607",
"C": "3200",
"D": "3602",
"E": "3603"
} | subtract(16000, multiply(divide(4, 5), 16000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | "let the income and the expenditure of the person be rs . 5 x and rs . 4 x respectively . income , 5 x = 16000 = > x = 3200 savings = income - expenditure = 5 x - 4 x = x so , savings = rs . 3200 . answer : c" | other |
math_qa__FRwtKVcv5JgWxkgS | A certain car increased its average speed by 5 miles per hour in each successive 5-minute interval after the first interval. If in the first 5-minute interval its average speed was 38 miles per hour, how many miles did the car travel in the third 5-minute interval?
Choose the correct choice from the following answers: A) 1.0 B) 1.5 C) 2.0 D) 2.5 E) 4.0 | <gadget id="calculator">38 + 5</gadget>
<output>43</output>
<gadget id="calculator">43 + 5</gadget>
<output>48</output>
<gadget id="calculator">5 / 60</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">48 * (1/12)</gadget>
<output>4</output>
<result>E</result> | E | 4 | A certain car increased its average speed by 5 miles per hour in each successive 5-minute interval after the first interval. If in the first 5-minute interval its average speed was 38 miles per hour, how many miles did the car travel in the third 5-minute interval? | {
"A": "1.0",
"B": "1.5",
"C": "2.0",
"D": "2.5",
"E": "4.0"
} | multiply(add(add(38, 5), 5), divide(5, const_60)) | add(n0,n3)|divide(n0,const_60)|add(n0,#0)|multiply(#2,#1)| | "in the third time interval the average speed of the car was 38 + 5 + 5 = 30 miles per hour ; in 5 minutes ( 1 / 12 hour ) at that speed car would travel 48 * 1 / 12 = 4 miles . answer : e ." | physics |
math_qa__zDUMsLBiFFXHLOIA | Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 1/7 and that of Ravi is 1/5. Find the probability that both of them are selected. Choose the correct answer.
A) 1 / 35 B) 2 / 3 C) 7 / 35 D) 5 / 7 E) 7 / 5 | <gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/7) * (1/5)</gadget>
<output>1/35 = around 0.028571</output>
<result>A</result> | A | 0.028571 | Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 1/7 and that of Ravi is 1/5. Find the probability that both of them are selected. | {
"A": "1 / 35",
"B": "2 / 3",
"C": "7 / 35",
"D": "5 / 7",
"E": "7 / 5"
} | multiply(divide(1, 7), divide(1, 5)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)| | "let a be the event that ram is selected and b is the event that ravi is selected . p ( a ) = 1 / 7 p ( b ) = 1 / 5 let c be the event that both are selected . p ( c ) = p ( a ) x p ( b ) as a and b are independent events : = 1 / 7 x 1 / 5 = 1 / 35 answer : a" | general |
math_qa__XE7SPQMygyK70aRm | If the ratio of apples to bananas is 5 to 2 and the ratio of bananas to cucumbers is 1 to 2, what is the ratio of apples to cucumbers? Choose the correct choice from the following:
A) 6 : 5 B) 1 : 4 C) 4 : 3 D) 2 : 3 E) 5 : 4 | <gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) / 2</gadget>
<output>5/4 = around 1.25</output>
<result>E</result> | E | 1.25 | If the ratio of apples to bananas is 5 to 2 and the ratio of bananas to cucumbers is 1 to 2, what is the ratio of apples to cucumbers? | {
"A": "6 : 5",
"B": "1 : 4",
"C": "4 : 3",
"D": "2 : 3",
"E": "5 : 4"
} | divide(divide(5, 2), 2) | divide(n0,n1)|divide(#0,n3)| | "the ratio of bananas to cucumbers is 1 to 2 which equals 2 to 4 . the ratio of apples to bananas to cucumbers is 5 to 2 to 4 . the ratio of apples to cucumbers is 5 to 4 . the answer is e ." | other |
math_qa__UBJXOY7rx4ty0vH9 | When 242 is divided by a certain divisor the remainder obtained is 6. When 698 is divided by the same divisor the remainder obtained is 13. However, when the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 5. What is the value of the divisor? Choose the correct choice from the following: A) 11 B) 14 C) 18 D) 23 E) none of these | <gadget id="calculator">6 + 13</gadget>
<output>19</output>
<gadget id="calculator">19 - 5</gadget>
<output>14</output>
<result>B</result> | B | 14 | When 242 is divided by a certain divisor the remainder obtained is 6. When 698 is divided by the same divisor the remainder obtained is 13. However, when the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 5. What is the value of the divisor? | {
"A": "11",
"B": "14",
"C": "18",
"D": "23",
"E": "none of these"
} | subtract(add(6, 13), 5) | add(n1,n3)|subtract(#0,n6)| | "let that divisor be x since remainder is 6 or 13 it means divisor is greater than 13 . now 242 - 6 = 236 = kx ( k is an integer and 234 is divisble by x ) similarly 698 - 13 = 685 = lx ( l is an integer and 689 is divisible by x ) adding both 698 and 242 = ( 236 + 685 ) + 6 + 13 = x ( k + l ) + 19 when we divide this number by x then remainder will be equal to remainder of ( 19 divided by x ) = 5 hence x = 19 - 5 = 14 hence b" | general |
math_qa__32OIsr9SlBxlp9my | In a river flowing at 2 km/hr, a boat travels 56 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time. Pick one.
A) 10 hours B) 12 hours C) 14 hours D) 21 hours E) none of these | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">56 / 4</gadget>
<output>14</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">56 / 8</gadget>
<output>7</output>
<gadget id="calculator">14 + 7</gadget>
<output>21</output>
<result>D</result> | D | 21 | In a river flowing at 2 km/hr, a boat travels 56 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time. | {
"A": "10 hours",
"B": "12 hours",
"C": "14 hours",
"D": "21 hours",
"E": "none of these"
} | add(divide(56, subtract(6, 2)), divide(56, add(6, 2))) | add(n0,n2)|subtract(n2,n0)|divide(n1,#1)|divide(n1,#0)|add(#2,#3)| | "explanation : speed of the boat = 6 km / hr speed downstream = ( 6 + 2 ) = 8 km / hr speed upstream = ( 6 - 2 ) = 4 km / hr distance travelled downstream = distance travelled upstream = 56 km total time taken = time taken downstream + time taken upstream = ( 56 / 8 ) + ( 56 / 4 ) = 21 hr . answer : option d" | general |
math_qa__C1WScRjAE7P6jehy | A certain rectangular crate measures 8 feet by 12 feet by 14 feet. A cylindrical gas tank is to be made for shipment in the crate and will stand upright when the crate is placed on one of its six faces. What should the radius of the tank be if it is to be of the largest possible volume?
Choose the correct choice.
A) 6 B) 5 C) 6 D) 8 E) 10 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">pi * (6 ** 2) * 8</gadget>
<output>288*pi = around 904.778684</output>
<gadget id="calculator">pi * 8</gadget>
<output>8*pi = around 25.132741</output>
<gadget id="calculator">(288*pi) / (8*pi)</gadget>
<output>36</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<result>A</result> | A | 6 | A certain rectangular crate measures 8 feet by 12 feet by 14 feet. A cylindrical gas tank is to be made for shipment in the crate and will stand upright when the crate is placed on one of its six faces. What should the radius of the tank be if it is to be of the largest possible volume? | {
"A": "6",
"B": "5",
"C": "6",
"D": "8",
"E": "10"
} | sqrt(divide(volume_cylinder(divide(12, const_2), 8), multiply(const_pi, 8))) | divide(n1,const_2)|multiply(n0,const_pi)|volume_cylinder(#0,n0)|divide(#2,#1)|sqrt(#3)| | "ans is ` ` b ' ' . for max volume of cylinder ( pi * r ^ 2 * h ) we need to max out r ^ 2 * h . we do n ' t know what the dimensions of the crate refer to . so to maximize the above eqn , radius may be of 9 , 10,12 one of the base area ( 8 x 12 , 14 x 12 or 8 x 14 ) r is maximum for base 14 x 12 and 12 can be maximum value so r = 10 / 2 = 6 a" | geometry |
math_qa__jqE5ZV9h0TraWP4p | There are 640 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school? Answers:
A) 320 B) 345 C) 375 D) 380 E) 400 | <gadget id="calculator">640 / 5</gadget>
<output>128</output>
<gadget id="calculator">128 * 3</gadget>
<output>384</output>
<result>E</result> | E | 400 | There are 640 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school? | {
"A": "320",
"B": "345",
"C": "375",
"D": "380",
"E": "400"
} | multiply(divide(640, 5), 3) | divide(n0,n2)|multiply(n1,#0)| | "in order to obtain a ratio of boys to girls equal to 3 : 5 , the number of boys has to be written as 3 x and the number of girls as 5 x where x is a common factor to the number of girls and the number of boys . the total number of boys and girls is 640 . hence 3 x + 5 x = 640 solve for x 8 x = 640 x = 80 number of boys 3 x = 3 Γ 80 = 240 number of girls 5 x = 5 Γ 80 = 400 e" | other |
math_qa__C3OGWdRj2JzTKwPn | A ratio between two numbers is 5:4 and their L.C.M. is 80. The first number is
Choose the correct choice from the following choices: A) 60 B) 45 C) 20 D) 15 E) none | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">80 / 20</gadget>
<output>4</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<result>C</result> | C | 20 | A ratio between two numbers is 5:4 and their L.C.M. is 80. The first number is | {
"A": "60",
"B": "45",
"C": "20",
"D": "15",
"E": "none"
} | multiply(divide(80, multiply(5, 4)), 5) | multiply(n0,n1)|divide(n2,#0)|multiply(n0,#1)| | "sol . let the required numbers be 5 x and 4 x . then , their l . c . m . is 20 x . β΄ 20 x = 80 β x = 4 . hence , the first number is 20 . answer c" | other |
math_qa__R5rfbIrw340XilUo | What is the least number that should be added to 1055, so the sum of the number is divisible by 23? Options:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">1_055 / 23</gadget>
<output>1_055/23 = around 45.869565</output>
<gadget id="calculator">floor(1_055/23)</gadget>
<output>45</output>
<gadget id="calculator">1 + 45</gadget>
<output>46</output>
<gadget id="calculator">46 - (1_055/23)</gadget>
<output>3/23 = around 0.130435</output>
<gadget id="calculator">(3/23) * 23</gadget>
<output>3</output>
<result>C</result> | C | 3 | What is the least number that should be added to 1055, so the sum of the number is divisible by 23? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | multiply(subtract(add(const_1, floor(divide(1055, 23))), divide(1055, 23)), 23) | divide(n0,n1)|floor(#0)|add(#1,const_1)|subtract(#2,#0)|multiply(n1,#3)| | "( 1055 / 23 ) gives a remainder 20 so we need to add 3 . the answer is c ." | general |
math_qa__7utTFx0EjPKGVT6J | An entry in an unshaded square is obtained by adding the entries connected to it from the row above (11 is one such number). Write the value of n ?
Answers.
A) 10 B) 11 C) 12 D) 9 E) 8 | <gadget id="calculator">11 * 3</gadget>
<output>33</output>
<gadget id="calculator">33 - 3</gadget>
<output>30</output>
<gadget id="calculator">30 / 3</gadget>
<output>10</output>
<result>A</result> | A | 10 | An entry in an unshaded square is obtained by adding the entries connected to it from the row above (11 is one such number). Write the value of n ? | {
"A": "10",
"B": "11",
"C": "12",
"D": "9",
"E": "8"
} | divide(subtract(multiply(11, const_3), const_3), const_3) | multiply(n0,const_3)|subtract(#0,const_3)|divide(#1,const_3) | see the values row wise 5 6 n 7 11 6 + n 7 + n 11 + 6 + n 6 + n + 7 + n 60 hence 11 + 6 + n + 6 + n + 7 + n = 60 n = 10 answer : a | geometry |
math_qa__MfvMrr8BvYImMu2n | A computer factory produces 3024 computers per month at a constant rate, how many computers are built every 30 minutes assuming that there are 28 days in one month?
Choose the correct option:
A) 2.25 . B) 3.125 . C) 4.5 . D) 5.225 . E) 6.25 . | <gadget id="calculator">3_024 / 28</gadget>
<output>108</output>
<gadget id="calculator">28 - 4</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">108 / 48</gadget>
<output>9/4 = around 2.25</output>
<result>A</result> | A | 2.25 | A computer factory produces 3024 computers per month at a constant rate, how many computers are built every 30 minutes assuming that there are 28 days in one month? | {
"A": "2.25 .",
"B": "3.125 .",
"C": "4.5 .",
"D": "5.225 .",
"E": "6.25 ."
} | divide(divide(3024, 28), multiply(subtract(28, const_4), const_2)) | divide(n0,n2)|subtract(n2,const_4)|multiply(#1,const_2)|divide(#0,#2)| | "number of hours in 28 days = 28 * 24 number of 30 mins in 28 days = 28 * 24 * 2 number of computers built every 30 mins = 3024 / ( 28 * 24 * 2 ) = 2.25 answer a" | physics |
math_qa__Ib38DTfaJW5s4yjX | a man has rs . 400 in the denominations of one - rupee notes , 5 - rupee notes and 10 rupee notes . the number of notes of each denomination is equal . what is the total number of notes that he has ?
Pick.
A) 45 B) 60 C) 75 D) 90 E) 95 | <gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">6 + 10</gadget>
<output>16</output>
<gadget id="calculator">400 / 16</gadget>
<output>25</output>
<gadget id="calculator">25 * 3</gadget>
<output>75</output>
<result>C</result> | C | 75 | a man has rs . 400 in the denominations of one - rupee notes , 5 - rupee notes and 10 rupee notes . the number of notes of each denomination is equal . what is the total number of notes that he has ? | {
"A": "45",
"B": "60",
"C": "75",
"D": "90",
"E": "95"
} | multiply(divide(400, add(add(const_1, 5), 10)), const_3) | add(n1,const_1)|add(n2,#0)|divide(n0,#1)|multiply(#2,const_3) | let number of notes of each denomination be x . then x + 5 x + 10 x = 400 16 x = 400 x = 25 . hence , total number of notes = 3 x = 75 answer : option c | general |
math_qa__zImSpxyC9tq6fsqs | In a sports club with 30 members, 17 play badminton and 17 play tennis and 2 do not play either. How many members play both badminton and tennis? Select:
A) 7 B) 6 C) 9 D) 10 E) 11 | <gadget id="calculator">17 + 17</gadget>
<output>34</output>
<gadget id="calculator">34 + 2</gadget>
<output>36</output>
<gadget id="calculator">36 - 30</gadget>
<output>6</output>
<result>B</result> | B | 6 | In a sports club with 30 members, 17 play badminton and 17 play tennis and 2 do not play either. How many members play both badminton and tennis? | {
"A": "7",
"B": "6",
"C": "9",
"D": "10",
"E": "11"
} | subtract(add(add(17, 17), 2), 30) | add(n1,n2)|add(n3,#0)|subtract(#1,n0)| | "let x play both badminton and tennis so 17 - x play only badminton and 17 - x play only tennis . 2 play none and there are total 30 students . hence , ( 17 - x ) + ( 17 - x ) + x + 2 = 30 36 - 2 x + x = 30 36 - x = 30 x = 6 so 6 members play both badminton and tennis . b" | other |
math_qa__yvfYbReaTPtLKmL0 | 3/4 of 1/2 of 2/5 of 5000 = ? Choose one: A) 392 B) 229 C) 753 D) 750 E) 540 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/4) * (1/2)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/8) * (2/5)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 5_000</gadget>
<output>750</output>
<result>D</result> | D | 750 | 3/4 of 1/2 of 2/5 of 5000 = ? | {
"A": "392",
"B": "229",
"C": "753",
"D": "750",
"E": "540"
} | multiply(multiply(multiply(divide(3, 4), divide(1, 2)), divide(2, 5)), 5000) | divide(n3,n5)|divide(n0,n1)|divide(n2,n3)|multiply(#1,#2)|multiply(#0,#3)|multiply(n6,#4)| | "d 750 ? = 5000 * ( 2 / 5 ) * ( 1 / 2 ) * ( 3 / 4 ) = 750" | general |
math_qa__C9Z05inmG6c7lz9w | In a sample of associates at a law firm, 25 percent are second-year associates, and 75 percent are not first-year associates. What percentage of the associates at the law firm have been there for more than two years?
Choose one:
A) 0 B) 25 C) 50 D) 75 E) 100 | <gadget id="calculator">75 - 25</gadget>
<output>50</output>
<result>C</result> | C | 50 | In a sample of associates at a law firm, 25 percent are second-year associates, and 75 percent are not first-year associates. What percentage of the associates at the law firm have been there for more than two years? | {
"A": "0",
"B": "25",
"C": "50",
"D": "75",
"E": "100"
} | subtract(75, 25) | subtract(n1,n0)| | "75 percent are not first - year associates - - > this means 75 percent associates are either two or more than two years already , we know % of second - year associates = 25 % so , % of associates there for more than two years = 75 % - 25 % = 50 % . . = > ( c ) . . is it correct ?" | general |
math_qa__M8oaLMf3BOzKFgKf | If (2 to the x) - (2 to the (x-2)) = 3 (2 to the 10), what is the value of x? Options:
A) 9 B) 11 C) 13 D) 12 E) 17 | <gadget id="calculator">10 + 2</gadget>
<output>12</output>
<result>D</result> | D | 12 | If (2 to the x) - (2 to the (x-2)) = 3 (2 to the 10), what is the value of x? | {
"A": "9",
"B": "11",
"C": "13",
"D": "12",
"E": "17"
} | add(10, 2) | add(n0,n5)| | "( 2 to the power x ) - ( 2 to the power ( x - 2 ) ) = 3 ( 2 to the power 10 ) 2 ^ x - 2 ^ ( x - 2 ) = 3 . 2 ^ 10 hence x = 12 . answer is d" | general |
math_qa__bvIArHquYd7629As | In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability R this college graduate has a graduate degree? Pick one
A) 1 / 11 B) 1 / 12 C) 1 / 13 D) 3 / 19 E) 3 / 43 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(1/8) / (2/3)</gadget>
<output>3/16 = around 0.1875</output>
<gadget id="calculator">(3/16) + 1</gadget>
<output>19/16 = around 1.1875</output>
<gadget id="calculator">(3/16) / (19/16)</gadget>
<output>3/19 = around 0.157895</output>
<result>D</result> | D | 0.157895 | In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability R this college graduate has a graduate degree? | {
"A": "1 / 11",
"B": "1 / 12",
"C": "1 / 13",
"D": "3 / 19",
"E": "3 / 43"
} | divide(divide(divide(1, 8), divide(2, 3)), add(divide(divide(1, 8), divide(2, 3)), 1)) | divide(n0,n1)|divide(n2,n3)|divide(#0,#1)|add(#2,n0)|divide(#2,#3)| | "in believe the answer is d . please see below for explanation . 0 ) we are told the following ratios cgd - college graduate with degree ncg - non college graduate cgn - college graduate no degree cgd ncg cgn 1 8 3 2 in order to make cgd and cgn comparable we need to find the least common multiple of 8 and 3 and that is 24 multiplying the first ratio by 3 and the second ratio by 8 we get cgd ncg cgn 3 24 16 if one picks a random college graduate at this large company , what is the probability this college graduate has a graduate degree ? nr of cgd = 3 nr of cg = 3 + 16 = 19 probability r of cgd / ( cg ) - > 3 / 19 answer d" | other |
math_qa__S59VuMJUfJ7oi0hL | If a/b = 5/4, Then (4a + 3b) / (4a - 3b) = ? Choose the correct choice from the following answers: A) 7 B) 6 C) 3 D) 5 E) 4 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">20 + 12</gadget>
<output>32</output>
<gadget id="calculator">20 - 12</gadget>
<output>8</output>
<gadget id="calculator">32 / 8</gadget>
<output>4</output>
<result>E</result> | E | 4 | If a/b = 5/4, Then (4a + 3b) / (4a - 3b) = ? | {
"A": "7",
"B": "6",
"C": "3",
"D": "5",
"E": "4"
} | divide(add(multiply(4, 5), multiply(3, 4)), subtract(multiply(4, 5), multiply(3, 4))) | multiply(n0,n1)|multiply(n1,n3)|add(#0,#1)|subtract(#0,#1)|divide(#2,#3)| | "answer dividing numerator as well as denominator by b , we get given exp . = ( 4 a + 3 b ) / ( 4 a - 3 b ) = ( 4 a / b + 3 ) / ( 4 a / b - 3 ) since a / b = 5 / 4 this implies that = [ ( 4 * 5 ) / 4 + 3 ] / [ ( 4 * 5 ) / 4 - 3 ) ] = ( 5 + 3 ) / ( 5 - 3 ) = 4 option : e" | general |
math_qa__FcEpvxkmm42uOW7u | total 63 matches are conducted in Knockout match type. How many players will be participated in that tournament? Choose the correct choice
A) 60 B) 61 C) 62 D) 63 E) 64 | <gadget id="calculator">63 + 1</gadget>
<output>64</output>
<result>E</result> | E | 64 | total 63 matches are conducted in Knockout match type. How many players will be participated in that tournament? | {
"A": "60",
"B": "61",
"C": "62",
"D": "63",
"E": "64"
} | add(63, const_1) | add(n0,const_1)| | "64 players answer : e" | general |
math_qa__Ryyg8fkrsSyILZFt | If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2012) = ? Choose the correct option:
A) 2013
B) 2088
C) 270
D) 1881
E) 1781 | <gadget id="calculator">1 + 2_012</gadget>
<output>2_013</output>
<result>A</result> | A | 2,013 | If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2012) = ? | {
"A": "2013",
"B": "2088",
"C": "270",
"D": "1881",
"E": "1781"
} | add(1, 2012) | add(n3,n4)| | "f ( f ( 0 ) ) + f ( 0 ) = 2 ( 0 ) + 3 β β f ( 1 ) = 3 - 1 = 2 , f ( 1 ) = 2 f ( f ( 1 ) ) + f ( 1 ) = 2 ( 1 ) + 3 β β f ( 2 ) = 5 - 2 = 3 , f ( 2 ) = 3 f ( f ( 2 ) ) + f ( 2 ) = 2 ( 2 ) + 3 β β f ( 3 ) = 7 - 3 = 4 , f ( 3 ) = 4 . . . . . . . . . . . . . . f ( 2012 ) = 2013 ans : a" | general |
math_qa__u5T98KrtejohNOE5 | What is (21^7+21) / 21? Choose the correct choice from the following:
A) 82216043 B) 83786095 C) 84316108 D) 85766122 E) 86426237 | <gadget id="calculator">21 ** 7</gadget>
<output>1_801_088_541</output>
<gadget id="calculator">1_801_088_541 + 21</gadget>
<output>1_801_088_562</output>
<gadget id="calculator">1_801_088_562 / 21</gadget>
<output>85_766_122</output>
<result>D</result> | D | 85,766,122 | What is (21^7+21) / 21? | {
"A": "82216043",
"B": "83786095",
"C": "84316108",
"D": "85766122",
"E": "86426237"
} | divide(add(power(21, 7), 21), 21) | power(n0,n1)|add(n0,#0)|divide(#1,n0) | ( 21 ^ 7 + 21 ) / 21 = 21 * ( 21 ^ 6 + 1 ) / 21 = 21 ^ 6 + 1 clearly this is a number which ends with a 2 in the units place . the answer is d . | general |
math_qa__Nrgv9k9XqujpqU4d | In an examination 35% of the students passed and 520 failed. How many students appeared for the examination?
Choose the correct choice from the following:
A) 540
B) 400
C) 800
D) 650
E) 840 | <gadget id="calculator">520 * 100</gadget>
<output>52_000</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">52_000 / 65</gadget>
<output>800</output>
<result>C</result> | C | 800 | In an examination 35% of the students passed and 520 failed. How many students appeared for the examination? | {
"A": "540",
"B": "400",
"C": "800",
"D": "650",
"E": "840"
} | divide(multiply(520, const_100), subtract(const_100, 35)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "let the number of students appeared be x then , 65 % of x = 520 65 x / 100 = 520 x = 520 * 100 / 65 = 800 answer is c" | gain |
math_qa__ESVm5E932iQpnHAb | A cube has a volume of 343 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is? Pick
A) 24 B) 48 C) 64 D) 2744 E) 100 | <gadget id="calculator">343 ** (1/3)</gadget>
<output>7</output>
<gadget id="calculator">2 * 7</gadget>
<output>14</output>
<gadget id="calculator">14 ** 3</gadget>
<output>2_744</output>
<result>D</result> | D | 2,744 | A cube has a volume of 343 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is? | {
"A": "24",
"B": "48",
"C": "64",
"D": "2744",
"E": "100"
} | volume_cube(multiply(const_2, cube_edge_by_volume(343))) | cube_edge_by_volume(n0)|multiply(#0,const_2)|volume_cube(#1)| | "volume = 343 = side ^ 3 i . e . side of cube = 7 new cube has dimensions 14 , 14 , and 14 as all sides are twice of teh side of first cube volume = 14 * 14 * 14 = 2744 square feet answer : option d" | geometry |
math_qa__qQmUjocIpbtgL4bK | A train crosses a platform of 170 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train? Choose the most appropriate option
A) 70 B) 88 C) 167 D) 197 E) 161 | <gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">250 * 3</gadget>
<output>750</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">170 * 4</gadget>
<output>680</output>
<gadget id="calculator">750 - 680</gadget>
<output>70</output>
<result>A</result> | A | 70 | A train crosses a platform of 170 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train? | {
"A": "70",
"B": "88",
"C": "167",
"D": "197",
"E": "161"
} | subtract(multiply(250, divide(15, divide(15, const_3))), multiply(170, divide(20, divide(15, const_3)))) | divide(n1,const_3)|divide(n1,#0)|divide(n3,#0)|multiply(n2,#1)|multiply(n0,#2)|subtract(#3,#4)| | "length of the train be β x β x + 170 / 15 = x + 250 / 20 20 x + 3400 = 15 x + 3750 5 x = 350 x = 70 m answer : a" | physics |
math_qa__2YDuEpPKA4Q0plzO | A 6 litre sol is 25% alcohol .How many litres of pure alcohol must be added to produce a sol that is 50% alcohol ? Choose the correct choice from the following answers
A) a . 0.6 B) b . 1 C) c . 2.1 D) d . 3 E) e . 5.4 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 6</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">2 * (3/2)</gadget>
<output>3</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<result>D</result> | D | 3 | A 6 litre sol is 25% alcohol .How many litres of pure alcohol must be added to produce a sol that is 50% alcohol ? | {
"A": "a . 0.6",
"B": "b . 1",
"C": "c . 2.1",
"D": "d . 3",
"E": "e . 5.4"
} | subtract(6, multiply(const_2, multiply(divide(25, const_100), 6))) | divide(n1,const_100)|multiply(n0,#0)|multiply(#1,const_2)|subtract(n0,#2)| | "25 % of 6 = 1.5 50 % of 6 = 3 shortage is 1.5 so we need to have 1.5 / 50 % to get 50 % alcohol content . = 3 d" | gain |
math_qa__rlkyLrJkHiEWbf4v | Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 40 ps per meter is? Options:
A) 287 B) 369 C) 100 D) 279 E) 361 | <gadget id="calculator">3_750 * 2</gadget>
<output>7_500</output>
<gadget id="calculator">7_500 / 3</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 ** (1/2)</gadget>
<output>50</output>
<gadget id="calculator">3_750 / 50</gadget>
<output>75</output>
<gadget id="calculator">2 * (50 + 75)</gadget>
<output>250</output>
<gadget id="calculator">40 * 250</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 100</gadget>
<output>100</output>
<result>C</result> | C | 100 | Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 40 ps per meter is? | {
"A": "287",
"B": "369",
"C": "100",
"D": "279",
"E": "361"
} | divide(multiply(40, rectangle_perimeter(sqrt(divide(multiply(3750, 2), 3)), divide(3750, sqrt(divide(multiply(3750, 2), 3))))), const_100) | multiply(n1,n2)|divide(#0,n0)|sqrt(#1)|divide(n2,#2)|rectangle_perimeter(#3,#2)|multiply(n3,#4)|divide(#5,const_100)| | "3 x * 2 x = 3750 = > x = 25 2 ( 75 + 50 ) = 250 m 250 * 0.40 = rs . 100 answer : c" | physics |
math_qa__kegNNWZxQyrrIIBr | The ratio of incomes of two person P1 and P2 is 5 : 4 and the ratio of their expenditures is 3 : 2. If at the end of the year, each saves Rs.2000, then what is the income of P1?
Choose the correct option
A) s . 5000 B) s . 2400 C) s . 4000 D) s . 3200 E) s . 4200 | <gadget id="calculator">2_000 / 2</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 3</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 - 2_000</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 5</gadget>
<output>5_000</output>
<result>A</result> | A | 5,000 | The ratio of incomes of two person P1 and P2 is 5 : 4 and the ratio of their expenditures is 3 : 2. If at the end of the year, each saves Rs.2000, then what is the income of P1? | {
"A": "s . 5000",
"B": "s . 2400",
"C": "s . 4000",
"D": "s . 3200",
"E": "s . 4200"
} | multiply(subtract(multiply(divide(2000, 2), 3), 2000), 5) | divide(n6,n1)|multiply(n4,#0)|subtract(#1,n6)|multiply(n2,#2)| | "let the income of p 1 and p 2 be rs . 5 x and rs . 4 x respectively and let their expenditures be rs . 3 y and 2 y respectively . then , 5 x β 3 y = 2000 β¦ ( i ) and 4 x β 2 y = 2000 β¦ β¦ . . ( ii ) on multiplying ( i ) by 2 , ( ii ) by 3 and subtracting , we get : 2 x = 2000 - > x = 1000 p 1 β s income = rs 5 * 1000 = rs . 5000 answer : a" | other |
math_qa__Rz15vAF7ABlvQoIs | Cubes with each side one inch long are glued together to form a larger cube. The larger cube's face is painted with red color and the entire assembly is taken apart. 26 small cubes are found with no paints on them . How many of unit cubes have at least one face that is painted red? Choose one: A) 64 B) 72 C) 86 D) 98 E) 99 | <gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<gadget id="calculator">125 - 26</gadget>
<output>99</output>
<result>E</result> | E | 99 | Cubes with each side one inch long are glued together to form a larger cube. The larger cube's face is painted with red color and the entire assembly is taken apart. 26 small cubes are found with no paints on them . How many of unit cubes have at least one face that is painted red? | {
"A": "64",
"B": "72",
"C": "86",
"D": "98",
"E": "99"
} | subtract(power(add(const_1, add(const_1, const_3)), const_3), 26) | add(const_1,const_3)|add(#0,const_1)|power(#1,const_3)|subtract(#2,n0)| | "use the options . the options which after getting added to 26 shows a cube of a number could be right . here 64 + 26 = 90 72 + 26 = 98 86 + 26 = 112 98 + 26 + 124 99 + 26 = 125 - - - ( 5 * 5 * 5 ) so we have 99 as the answer ! e" | geometry |
math_qa__E3CSYZcFhERAcFfT | Rahim bought 32 books for Rs.1500 from one shop and 60 books for Rs.340 from another. What is the average price he paid per book ? Answers:
A) s . 17
B) s . 18
C) s . 12
D) s . 11
E) s . 20 | <gadget id="calculator">1_500 + 340</gadget>
<output>1_840</output>
<gadget id="calculator">32 + 60</gadget>
<output>92</output>
<gadget id="calculator">1_840 / 92</gadget>
<output>20</output>
<result>E</result> | E | 20 | Rahim bought 32 books for Rs.1500 from one shop and 60 books for Rs.340 from another. What is the average price he paid per book ? | {
"A": "s . 17",
"B": "s . 18",
"C": "s . 12",
"D": "s . 11",
"E": "s . 20"
} | divide(add(1500, 340), add(32, 60)) | add(n1,n3)|add(n0,n2)|divide(#0,#1)| | "average price per book = ( 1500 + 340 ) / ( 32 + 60 ) = 1840 / 92 = rs . 20 answer : e" | general |
math_qa__V3LlRBr0Gu06APTB | There are 16 teams in a tournament. If during the first round, each team plays every other team exactly once, how many games will be played in the first round? Choose the correct choice from the following options:
A) 15 B) 30 C) 120 D) 240 E) 256 | <gadget id="calculator">factorial(16)</gadget>
<output>20_922_789_888_000</output>
<gadget id="calculator">16 - 2</gadget>
<output>14</output>
<gadget id="calculator">factorial(14)</gadget>
<output>87_178_291_200</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">87_178_291_200 * 2</gadget>
<output>174_356_582_400</output>
<gadget id="calculator">20_922_789_888_000 / 174_356_582_400</gadget>
<output>120</output>
<result>C</result> | C | 120 | There are 16 teams in a tournament. If during the first round, each team plays every other team exactly once, how many games will be played in the first round? | {
"A": "15",
"B": "30",
"C": "120",
"D": "240",
"E": "256"
} | divide(factorial(16), multiply(factorial(subtract(16, const_2)), factorial(const_2))) | factorial(n0)|factorial(const_2)|subtract(n0,const_2)|factorial(#2)|multiply(#3,#1)|divide(#0,#4) | number of ways to pick 2 teams from a total of 16 = 16 c 2 = 16 ! / 14 ! * 2 ! = 120 . hence c . | general |
math_qa__Bi4V7ju4KsjbEYIn | There are 193 items that are members of set U. Of these items, 49 are members of set B, 59 are not members of either of set A or set B, and 25 are members of both sets A and B. How many of the members of set U are members of set A ?
Choose the most appropriate option.
A) 72 B) 85 C) 110 D) 98 E) 108 | <gadget id="calculator">193 - 59</gadget>
<output>134</output>
<gadget id="calculator">134 + 25</gadget>
<output>159</output>
<gadget id="calculator">159 - 49</gadget>
<output>110</output>
<result>C</result> | C | 110 | There are 193 items that are members of set U. Of these items, 49 are members of set B, 59 are not members of either of set A or set B, and 25 are members of both sets A and B. How many of the members of set U are members of set A ? | {
"A": "72",
"B": "85",
"C": "110",
"D": "98",
"E": "108"
} | subtract(add(subtract(193, 59), 25), 49) | subtract(n0,n2)|add(n3,#0)|subtract(#1,n1) | you had the answer almost right . the x = 85 refers to only set a . however what ' s being asked is how many members are part of set a . this will include : 1 . only set a 2 . set a and set b so the answer is set a = 85 + set ab = 85 + 25 = 110 c | other |
math_qa__caFOXQTqBHZR199E | What is the probability that the sum of two dice will yield a 8, and then when both are thrown again, their sum will again yield a 8? assume that each die has 7 sides with faces numbered 1 to 7.
Choose the correct option.
A) 1 / 144
B) 1 / 36
C) 1 / 12
D) 1 / 6
E) 1 / 49 | <gadget id="calculator">7 ** 2</gadget>
<output>49</output>
<gadget id="calculator">7 / 49</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/7) * (1/7)</gadget>
<output>1/49 = around 0.020408</output>
<result>E</result> | E | 0.020408 | What is the probability that the sum of two dice will yield a 8, and then when both are thrown again, their sum will again yield a 8? assume that each die has 7 sides with faces numbered 1 to 7. | {
"A": "1 / 144",
"B": "1 / 36",
"C": "1 / 12",
"D": "1 / 6",
"E": "1 / 49"
} | multiply(divide(7, power(7, const_2)), divide(7, power(7, const_2))) | power(n2,const_2)|divide(n2,#0)|multiply(#1,#1)| | "solution - rolling dices is an independent event . the combinations to get 8 are ( 1,7 ) , ( 7,1 ) , ( 2,6 ) , ( 6,2 ) , ( 3,5 ) , ( 5,3 ) , ( 4 , , 4 ) and total combinations of both dices is 49 . the probability of getting 8 in first attempt is 7 / 49 = 1 / 7 . probability of getting 8 again in second attempt = ( 1 / 7 ) * ( 1 / 7 ) = 1 / 49 . ans e" | probability |
math_qa__8nrcSCWO0izcAsqi | Sandy bought 65 books for $1480 from one shop and 55 books for $920 from another shop. What is the average price that Sandy paid per book? Choose the correct choice from the following answers.
A) $ 38 B) $ 18 C) $ 99 D) $ 27 E) $ 20 | <gadget id="calculator">1_480 + 920</gadget>
<output>2_400</output>
<gadget id="calculator">65 + 55</gadget>
<output>120</output>
<gadget id="calculator">2_400 / 120</gadget>
<output>20</output>
<result>E</result> | E | 20 | Sandy bought 65 books for $1480 from one shop and 55 books for $920 from another shop. What is the average price that Sandy paid per book? | {
"A": "$ 38",
"B": "$ 18",
"C": "$ 99",
"D": "$ 27",
"E": "$ 20"
} | divide(add(1480, 920), add(65, 55)) | add(n1,n3)|add(n0,n2)|divide(#0,#1)| | "average price per book = ( 1480 + 920 ) / ( 65 + 55 ) = 2400 / 120 = $ 20 the answer is e ." | general |
math_qa__bojInWDscIZKoUBY | Calculate 1307 x 1307 =? Choose the correct choice.
A) 1601249
B) 1607249
C) 1701249
D) 1708249
E) none | <gadget id="calculator">1_307 * 1_307</gadget>
<output>1_708_249</output>
<result>D</result> | D | 1,708,249 | Calculate 1307 x 1307 =? | {
"A": "1601249",
"B": "1607249",
"C": "1701249",
"D": "1708249",
"E": "none"
} | multiply(1307, 1307) | multiply(n0,n1)| | "answer 1307 x 1307 = ( 1307 ) 2 = ( 1300 + 7 ) 2 = ( 1300 ) 2 + ( 7 ) 2 + 2 x 1300 x 7 = 1690000 + 49 + 18200 = 1708249 option : d" | general |
math_qa__dfDZN6dU5SUURmqa | The HCF and LCM of two numbers m and n are respectively 6 and 210. If m + n = 80, then 1/m + 1/n is equal to Choose the correct option
A) 1 / 35 B) 3 / 35 C) 5 / 37 D) 4 / 63 E) none | <gadget id="calculator">6 * 210</gadget>
<output>1_260</output>
<gadget id="calculator">80 / 1_260</gadget>
<output>4/63 = around 0.063492</output>
<result>D</result> | D | 0.063492 | The HCF and LCM of two numbers m and n are respectively 6 and 210. If m + n = 80, then 1/m + 1/n is equal to | {
"A": "1 / 35",
"B": "3 / 35",
"C": "5 / 37",
"D": "4 / 63",
"E": "none"
} | divide(80, multiply(6, 210)) | multiply(n0,n1)|divide(n2,#0)| | "answer we have , m x n = 6 x 210 = 1260 Γ’ Λ Β΄ 1 / m + 1 / n = ( m + n ) / mn = 80 / 1260 = 4 / 63 correct option : d" | general |
math_qa__yJOD4Be6AF5QEqgG | In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 250 newborn members of the population, approximately how many would be expected to survive the first 3 months of life?
Choose the correct choice from the following answers:
A) 140 B) 146 C) 152 D) 162 E) 183 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">250 * (9/10)</gadget>
<output>225</output>
<gadget id="calculator">225 * (9/10)</gadget>
<output>405/2 = around 202.5</output>
<gadget id="calculator">(405/2) * (9/10)</gadget>
<output>729/4 = around 182.25</output>
<result>E</result> | E | 183 | In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 250 newborn members of the population, approximately how many would be expected to survive the first 3 months of life? | {
"A": "140",
"B": "146",
"C": "152",
"D": "162",
"E": "183"
} | multiply(multiply(multiply(250, subtract(1, divide(1, 10))), subtract(1, divide(1, 10))), subtract(1, divide(1, 10))) | divide(n1,n2)|subtract(n1,#0)|multiply(n3,#1)|multiply(#2,#1)|multiply(#3,#1)| | "the probability of survival for each of the first 3 months of life is 1 - 1 / 10 = 9 / 10 , so of 250 newborn 250 * 9 / 10 * 9 / 10 * 9 / 10 = ~ 183 is expected to survive . answer : e ." | probability |
math_qa__QjR6otyIO5H43yM5 | If 3a = 4b and ab β 0, what is the ratio of a/4 to b/3? Choose the correct choice from the following options.
A) 64 / 27 B) 9 / 16 C) 1 D) 6 / 8 E) 8 / 6 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 / 12</gadget>
<output>1</output>
<result>C</result> | C | 1 | If 3a = 4b and ab β 0, what is the ratio of a/4 to b/3? | {
"A": "64 / 27",
"B": "9 / 16",
"C": "1",
"D": "6 / 8",
"E": "8 / 6"
} | divide(multiply(3, 4), multiply(4, 3)) | multiply(n0,n1)|divide(#0,#0)| | "a nice fast approach is the first find a pair of numbers that satisfy the given equation : 3 a = 4 b here ' s one pair : a = 4 and b = 3 what is the ratio of a / 9 to b / 8 ? in other words , what is the value of ( a / 4 ) / ( b / 3 ) ? plug in values to get : ( a / 4 ) / ( b / 3 ) = ( 4 / 4 ) / ( 3 / 3 ) = 1 / 1 = 1 c" | general |
math_qa__f6NPETWonf2se3lr | What is the smallest integer X such that 2X+2 is divisible by 33, 44, 55, and 666? Choices
A) x = 53186760 B) x = 26593379 C) x = 73260 D) x = 36629 E) x = 6666 | <gadget id="calculator">lcm(33, 44)</gadget>
<output>132</output>
<gadget id="calculator">lcm(132, 55)</gadget>
<output>660</output>
<gadget id="calculator">lcm(660, 666)</gadget>
<output>73_260</output>
<gadget id="calculator">73_260 - 2</gadget>
<output>73_258</output>
<gadget id="calculator">73_258 / 2</gadget>
<output>36_629</output>
<result>D</result> | D | 36,629 | What is the smallest integer X such that 2X+2 is divisible by 33, 44, 55, and 666? | {
"A": "x = 53186760",
"B": "x = 26593379",
"C": "x = 73260",
"D": "x = 36629",
"E": "x = 6666"
} | divide(subtract(lcm(lcm(lcm(33, 44), 55), 666), 2), 2) | lcm(n2,n3)|lcm(n4,#0)|lcm(n5,#1)|subtract(#2,n0)|divide(#3,n0) | 33 = 3 * 11 44 = 2 * 2 * 11 55 = 5 * 11 666 = 2 * 3 * 3 * 37 so 2 x + 2 = 2 * 2 * 3 * 3 * 5 * 11 * 37 = 73260 , and x = ( 73260 - 2 ) / 2 = 36629 , which is option d . | general |
math_qa__AE9zizLlyhCrn8Kz | If 12 men do a work in 80 days, in how many days will 20 men do it? Choose the correct option:
A) 18 days
B) 38 days
C) 42 days
D) 48 days
E) 44 days | <gadget id="calculator">12 * 80</gadget>
<output>960</output>
<gadget id="calculator">960 / 20</gadget>
<output>48</output>
<result>D</result> | D | 48 | If 12 men do a work in 80 days, in how many days will 20 men do it? | {
"A": "18 days",
"B": "38 days",
"C": "42 days",
"D": "48 days",
"E": "44 days"
} | divide(multiply(12, 80), 20) | multiply(n0,n1)|divide(#0,n2)| | "12 * 80 = 20 * x x = 48 days answer : d" | physics |
math_qa__YZBEx9iJ0GyqfgFC | If the ratio of the sum of the first 6 terms of a G.P. to the sum of the first 3 terms of the G.P. is 126, what is the common ratio of the G.P? Choose the correct choice:
A) 3 B) 1 / 3 C) 2 D) 5 E) 1 / 5 | <gadget id="calculator">126 - 1</gadget>
<output>125</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">125 ** (1/3)</gadget>
<output>5</output>
<result>D</result> | D | 5 | If the ratio of the sum of the first 6 terms of a G.P. to the sum of the first 3 terms of the G.P. is 126, what is the common ratio of the G.P? | {
"A": "3",
"B": "1 / 3",
"C": "2",
"D": "5",
"E": "1 / 5"
} | power(subtract(126, const_1), divide(const_1, 3)) | divide(const_1,n1)|subtract(n2,const_1)|power(#1,#0)| | "126 = ( a 1 + a 2 + a 3 + a 4 + a 5 + a 6 ) / ( a 1 + a 2 + a 3 ) factorize the same terms 126 = 1 + ( a 4 + a 5 + a 6 ) / ( a 1 + a 2 + a 3 ) write every term with respect to r a 1 = a 1 a 2 = a 1 * r ^ 1 a 3 = a 1 * r ^ 2 . . . . . . . . . 126 = 1 + ( a 1 ( r ^ 3 + r ^ 4 + r ^ 5 ) ) / ( a 1 ( 1 + r ^ 1 + r ^ 2 ) ) 125 = ( r ^ 3 ( 1 + r ^ 1 + r ^ 2 ) ) / ( ( 1 + r ^ 1 + r ^ 2 ) ) 125 = r ^ 3 r = 5 d" | other |
math_qa__rU0Asetn8keeyucQ | There are 6 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 15 other amateurs, what is the total number of chess games possible to be played in the tournament? Select the correct option: A) 10 B) 20 C) 45 D) 60 E) 120 | <gadget id="calculator">6 * 15</gadget>
<output>90</output>
<gadget id="calculator">90 / 2</gadget>
<output>45</output>
<result>C</result> | C | 45 | There are 6 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 15 other amateurs, what is the total number of chess games possible to be played in the tournament? | {
"A": "10",
"B": "20",
"C": "45",
"D": "60",
"E": "120"
} | divide(multiply(6, 15), const_2) | multiply(n0,n1)|divide(#0,const_2)| | "each person is one participant of 6 games . so there are in all 6 * 15 = 90 instances of one participant games . but each game has 2 participants so total number of games = 90 / 2 = 45 c" | general |
math_qa__LYMtGSAUIW0EYHv7 | tough and tricky questions : probability . medical analysts predict that a quarter of all people who are infected by a certain biological agent could be expected to be killed for each day that passes during which they have not received an antidote . what fraction of a group of 1000 people could be expected to be killed if infected and not treated for 3 full days ? Choose the correct choice from the following:
A) 37 / 64
B) 8 / 27
C) 2 / 3
D) 19 / 27
E) 65 / 81 | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * (1/4)</gadget>
<output>3/16 = around 0.1875</output>
<gadget id="calculator">(1/4) + (3/16)</gadget>
<output>7/16 = around 0.4375</output>
<gadget id="calculator">(3/16) + (1/4)</gadget>
<output>7/16 = around 0.4375</output>
<gadget id="calculator">1 - (7/16)</gadget>
<output>9/16 = around 0.5625</output>
<gadget id="calculator">(9/16) * (1/4)</gadget>
<output>9/64 = around 0.140625</output>
<gadget id="calculator">(7/16) + (9/64)</gadget>
<output>37/64 = around 0.578125</output>
<result>A</result> | A | 0.578125 | tough and tricky questions : probability . medical analysts predict that a quarter of all people who are infected by a certain biological agent could be expected to be killed for each day that passes during which they have not received an antidote . what fraction of a group of 1000 people could be expected to be killed if infected and not treated for 3 full days ? | {
"A": "37 / 64",
"B": "8 / 27",
"C": "2 / 3",
"D": "19 / 27",
"E": "65 / 81"
} | add(add(divide(const_1, add(3, const_1)), multiply(subtract(const_1, divide(const_1, add(3, const_1))), divide(const_1, add(3, const_1)))), multiply(subtract(const_1, add(multiply(subtract(const_1, divide(const_1, add(3, const_1))), divide(const_1, add(3, const_1))), divide(const_1, add(3, const_1)))), divide(const_1, add(3, const_1)))) | add(n1,const_1)|divide(const_1,#0)|subtract(const_1,#1)|multiply(#1,#2)|add(#1,#3)|subtract(const_1,#4)|multiply(#1,#5)|add(#4,#6) | at the end of each day we will have 3 / 4 alive . so after 3 days we will have ( 3 / 4 ) ^ 3 people alive . therefore , fraction of dead people will be 1 - ( 3 / 4 ) ^ 3 = 37 / 64 . the correct answer is a . | general |
math_qa__1u6GbiajkBC9URNF | If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 10800 ? Choose the most appropriate option: A) 11 B) 13 C) 14 D) 18 E) 10 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) + 3</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) + 3</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(7/2) - (10/3)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 10_800</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<result>D</result> | D | 18 | If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 10800 ? | {
"A": "11",
"B": "13",
"C": "14",
"D": "18",
"E": "10"
} | divide(multiply(subtract(add(divide(1, 2), 3), add(divide(1, 3), 3)), 10800), const_100) | divide(n1,n2)|divide(n1,n0)|add(n0,#0)|add(n0,#1)|subtract(#2,#3)|multiply(n6,#4)|divide(#5,const_100)| | "required difference = [ 3 Β½ % of rs . 10800 ] β [ 3 1 / 3 % of rs . 10800 ] = [ ( 7 / 20 - ( 10 / 3 ) ] % of rs . 10800 = 1 / 6 % of rs . 10800 = rs . [ ( 1 / 6 ) 8 ( 1 / 100 ) * 10800 ] = rs . 18 . answer is d ." | general |
math_qa__R7ODkfP1K2VGIr3g | In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 20 percent. If the companyβs revenue from the sale of the shoes in 1986 was $3.0 million, what was the approximate revenue from the sale of the shoes in 1985 ?
Choose the correct choice from the following choices
A) $ 2.4 million
B) $ 2.9 million
C) $ 3.0 million
D) $ 3.1 million
E) $ 3.6 million | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 - 20</gadget>
<output>60</output>
<gadget id="calculator">60 / 20</gadget>
<output>3</output>
<result>D</result> | D | 3.1 | In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 20 percent. If the companyβs revenue from the sale of the shoes in 1986 was $3.0 million, what was the approximate revenue from the sale of the shoes in 1985 ? | {
"A": "$ 2.4 million",
"B": "$ 2.9 million",
"C": "$ 3.0 million",
"D": "$ 3.1 million",
"E": "$ 3.6 million"
} | divide(subtract(subtract(const_100, 20), 20), 20) | subtract(const_100,n2)|subtract(#0,n2)|divide(#1,n2) | let the number of pairs of shoes sold in 1985 = n let price per pair of shoe sold in 1985 = p in 1986 , number of pairs of shoes sold decreased by 20 % = . 8 n price per pair increased by 20 % = 1.2 p company ' s revenue from sale of shoes in 1986 = 3 million $ = > . 8 n * 1.2 p = 3 = > . 96 np = 3 = > np = 3 / . 96 = 3.125 million $ answer d | general |
math_qa__5xv23M5fPGyrwVhf | A company has two types of machines, type R and type S. Operating at a constant rate a machine of R does a certain job in 36 hours and a machine of type S does the job in 2 hours. If the company used the same number of each type of machine to do job in 12 hours,how many machine R were used? Choose the correct choice from the following options
A) 3 / 4 B) 4 C) 18 / 19 D) 9 E) 12 | <gadget id="calculator">1 / 36</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/36) + (1/2)</gadget>
<output>19/36 = around 0.527778</output>
<gadget id="calculator">2 * (19/36)</gadget>
<output>19/18 = around 1.055556</output>
<gadget id="calculator">1 / (19/18)</gadget>
<output>18/19 = around 0.947368</output>
<result>C</result> | C | 0.947368 | A company has two types of machines, type R and type S. Operating at a constant rate a machine of R does a certain job in 36 hours and a machine of type S does the job in 2 hours. If the company used the same number of each type of machine to do job in 12 hours,how many machine R were used? | {
"A": "3 / 4",
"B": "4",
"C": "18 / 19",
"D": "9",
"E": "12"
} | divide(const_1, multiply(2, add(divide(const_1, 36), divide(const_1, 2)))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n1,#2)|divide(const_1,#3) | yes there is a typo in the question , i got the same ques on my gmat prep last week , and the questions goes as : a company has two types of machines , type r and type s . operating at a constant rate a machine of r does a certain job in 36 hours and a machine of type s does the job in 2 hours . if the company used the same number of each type of machine to do job in 2 hours , how many machine r were used ? so for a job to be done in 2 hours r = 1 / 2 r _ a ( rate of machine r ) = 1 / 36 r _ s ( rate of machine s ) = 1 / 2 lets say x machines are used to attain the desired rate , thus x / 36 + x / 2 = 1 / 2 ( desired r = 1 / 2 i . e . to complete the job in 2 hours ) ( x + 18 x ) / 36 = 1 / 2 19 x / 36 = 1 / 2 x = 18 / 19 . qa = 18 / 19 ( answer c ) | gain |
math_qa__TzIEZ58FZdDr4J1A | The difference between compound and simple interest on a particular sum of money for 3 years at 6 and 2/3% p.a is Rs.184. What is the sum? Select.
A) 13000 B) 13500 C) 14000 D) 14500 E) 15000 | <gadget id="calculator">184 * 3</gadget>
<output>552</output>
<gadget id="calculator">552 * 3</gadget>
<output>1_656</output>
<gadget id="calculator">1_656 * 3</gadget>
<output>4_968</output>
<gadget id="calculator">4_968 * 6</gadget>
<output>29_808</output>
<gadget id="calculator">29_808 / 2</gadget>
<output>14_904</output>
<gadget id="calculator">14_904 - 1_000</gadget>
<output>13_904</output>
<result>B</result> | B | 13,500 | The difference between compound and simple interest on a particular sum of money for 3 years at 6 and 2/3% p.a is Rs.184. What is the sum? | {
"A": "13000",
"B": "13500",
"C": "14000",
"D": "14500",
"E": "15000"
} | subtract(divide(multiply(multiply(multiply(multiply(184, 3), 3), 3), 6), 2), const_1000) | multiply(n0,n4)|multiply(n0,#0)|multiply(n0,#1)|multiply(n1,#2)|divide(#3,n2)|subtract(#4,const_1000)| | "p = ( 184 * 10 ^ 6 ) / ( 6 2 / 3 * 6 2 / 3 * ( 300 * 6 2 / 3 ) ) = = > 13500 answer b" | general |
math_qa__1nGKT5U8wp8KsfRh | Triangle XYZ is an isosceles right triangle. If side XY is longer than side YZ, and the area of the triangle is 36, what is the measure of side XY? Choose the correct choice from the following choices
A) 4 B) 4 β 2 C) 12 D) 8 β 2 E) can not be determined from the information provided | <gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">2 ** (1/2)</gadget>
<output>sqrt(2) = around 1.414214</output>
<gadget id="calculator">6 * (sqrt(2))</gadget>
<output>6*sqrt(2) = around 8.485281</output>
<gadget id="calculator">(6*sqrt(2)) ** 2</gadget>
<output>72</output>
<gadget id="calculator">72 + 72</gadget>
<output>144</output>
<gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<result>C</result> | C | 12 | Triangle XYZ is an isosceles right triangle. If side XY is longer than side YZ, and the area of the triangle is 36, what is the measure of side XY? | {
"A": "4",
"B": "4 β 2",
"C": "12",
"D": "8 β 2",
"E": "can not be determined from the information provided"
} | sqrt(add(power(multiply(sqrt(36), sqrt(const_2)), const_2), power(multiply(sqrt(36), sqrt(const_2)), const_2))) | sqrt(n0)|sqrt(const_2)|multiply(#0,#1)|power(#2,const_2)|add(#3,#3)|sqrt(#4)| | "ans c . . 12 . . xy being larger means it is the hyp . . area = ( 1 / 2 ) * ( yz ) ^ 2 = 36 or yz = 3 * \ sqrt { 2 } . . therefore hyp = xy = 12" | geometry |
math_qa__38WTrvj0hqw3cbEc | At 6β²o a clock ticks 6 times. The time between first and last ticks is 40 seconds. How long does it tick at 12β²o clock Choices
A) 47 B) 88 C) 28 D) 66 E) 11 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">40 / 5</gadget>
<output>8</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">8 * 11</gadget>
<output>88</output>
<result>B</result> | B | 88 | At 6β²o a clock ticks 6 times. The time between first and last ticks is 40 seconds. How long does it tick at 12β²o clock | {
"A": "47",
"B": "88",
"C": "28",
"D": "66",
"E": "11"
} | multiply(divide(40, subtract(6, const_1)), subtract(12, const_1)) | subtract(n0,const_1)|subtract(n3,const_1)|divide(n2,#0)|multiply(#2,#1)| | "explanation : for ticking 6 times , there are 5 intervals . each interval has time duration of 40 / 5 = 8 secs at 12 o ' clock , there are 11 intervals , so total time for 11 intervals = 11 Γ 8 = 88 secs . answer : b" | physics |
math_qa__cZz2s1uZzfkOBHgx | The balance of a trader weighs 20% less than it should. Still the trader marks up his goods to get an overall profit of 30%. What is the mark up on the cost price?
Choose the correct choice from the following answers
A) 4 % B) 8 % C) 25 % D) 16.66 % E) 9 % | <gadget id="calculator">4 * 20</gadget>
<output>80</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">80 * (3/10)</gadget>
<output>24</output>
<gadget id="calculator">24 + 80</gadget>
<output>104</output>
<gadget id="calculator">104 - 100</gadget>
<output>4</output>
<result>A</result> | A | 4 | The balance of a trader weighs 20% less than it should. Still the trader marks up his goods to get an overall profit of 30%. What is the mark up on the cost price? | {
"A": "4 %",
"B": "8 %",
"C": "25 %",
"D": "16.66 %",
"E": "9 %"
} | subtract(add(multiply(multiply(const_4, 20), divide(30, const_100)), multiply(const_4, 20)), const_100) | divide(n1,const_100)|multiply(n0,const_4)|multiply(#0,#1)|add(#2,#1)|subtract(#3,const_100) | the most natural way to deal with ' weights ' questions is by assuming values . say the trader ' s balance shows 100 gms . it is actually 80 gms because it weighs 20 % less . say , the cost price is $ 80 ( $ 1 / gm ) . since he gets a profit of 30 % , the selling price must be 80 + ( 30 / 100 ) * 80 = $ 104 since the cost price is actually supposed to be $ 100 ( for 100 gms ) and the selling price is $ 104 , the mark up is simply 4 % . ans : a | gain |
math_qa__iPhzmADhXWyxDkA5 | Find the number, difference between number and its 3/5 is 50. Pick: A) 120 B) 123 C) 124 D) 125 E) 359 | <gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 * 5</gadget>
<output>125</output>
<result>D</result> | D | 125 | Find the number, difference between number and its 3/5 is 50. | {
"A": "120",
"B": "123",
"C": "124",
"D": "125",
"E": "359"
} | multiply(divide(50, const_2), 5) | divide(n2,const_2)|multiply(n1,#0)| | "explanation : let the number = x , then , x - ( 3 / 5 ) x = 50 , = > ( 2 / 5 ) x = 50 = > 2 x = 50 * 5 , = > x = 125 option d" | general |
math_qa__2Vv0jxmcgUbvn5iS | In a coconut grove, (x + 3) trees yield 60 nuts per year, x trees yield 120 nuts per year and (x β 3) trees yield 180 nuts per year. If the average yield per year per tree be 100, find x. Answers
A) 3 B) 4 C) 5 D) 6 E) none of the above | <gadget id="calculator">180 * 3</gadget>
<output>540</output>
<gadget id="calculator">60 * 3</gadget>
<output>180</output>
<gadget id="calculator">540 - 180</gadget>
<output>360</output>
<gadget id="calculator">60 + 120</gadget>
<output>180</output>
<gadget id="calculator">180 + 180</gadget>
<output>360</output>
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<gadget id="calculator">360 - 300</gadget>
<output>60</output>
<gadget id="calculator">360 / 60</gadget>
<output>6</output>
<result>D</result> | D | 6 | In a coconut grove, (x + 3) trees yield 60 nuts per year, x trees yield 120 nuts per year and (x β 3) trees yield 180 nuts per year. If the average yield per year per tree be 100, find x. | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "none of the above"
} | divide(subtract(multiply(180, 3), multiply(60, 3)), subtract(add(add(60, 120), 180), multiply(100, const_3))) | add(n1,n2)|multiply(n0,n4)|multiply(n0,n1)|multiply(n5,const_3)|add(n4,#0)|subtract(#1,#2)|subtract(#4,#3)|divide(#5,#6)| | "( x + 3 ) Γ 60 + x Γ 120 + ( x β 3 ) Γ 180 / ( x + 3 ) + x + ( x β 3 ) = 100 β 360 x β 360 / 3 x = 100 β 60 x = 360 β x = 6 answer d" | general |
math_qa__5JweMczZV0ylkutB | Jill invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. Approximately how much W does she have in her account after two years? Choose the correct choice from the following answers.
A) $ 10079.44 B) w = $ 10815.83 C) $ 12652.61 D) $ 14232.14 E) $ 20598.11 | <gadget id="calculator">3.96 / 100</gadget>
<output>0.0396</output>
<gadget id="calculator">0.0396 / 2</gadget>
<output>0.0198</output>
<gadget id="calculator">1 + 0.0198</gadget>
<output>1.0198</output>
<gadget id="calculator">1.0198 ** 4</gadget>
<output>1.081583</output>
<gadget id="calculator">10_000 * 1.081583</gadget>
<output>10_815.83</output>
<result>B</result> | B | 10,815.83 | Jill invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. Approximately how much W does she have in her account after two years? | {
"A": "$ 10079.44",
"B": "w = $ 10815.83",
"C": "$ 12652.61",
"D": "$ 14232.14",
"E": "$ 20598.11"
} | multiply(10000, power(add(const_1, divide(divide(3.96, const_100), const_2)), const_4)) | divide(n1,const_100)|divide(#0,const_2)|add(#1,const_1)|power(#2,const_4)|multiply(n0,#3)| | "ps . i guess one can use simple interest to solve cause the answer choices are quite spread between you can easily arrive at something near 8 % hence b the answer" | gain |
math_qa__s1ZpsUstD0TNtV8T | A 290 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train? Choose the correct choice from the following answers:
A) 230 m B) 210 m C) 260 m D) 320 m E) 330 m | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">(500/9) * 9</gadget>
<output>500</output>
<gadget id="calculator">500 - 290</gadget>
<output>210</output>
<result>B</result> | B | 210 | A 290 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train? | {
"A": "230 m",
"B": "210 m",
"C": "260 m",
"D": "320 m",
"E": "330 m"
} | subtract(multiply(multiply(add(120, 80), const_0_2778), 9), 290) | add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)| | "relative speed = ( 120 + 80 ) km / hr = ( 200 x ( 5 / 18 ) ) m / sec = ( 500 / 9 ) m / sec . let the length of the other train be x metres . then , ( x + 290 ) / 9 = 500 / 9 x + 290 = 500 x = 210 . b" | physics |
math_qa__YsgbPjSQI9IZAXqH | Find the average of all prime numbers between 4 and 15. Select the correct option: A) 30 B) 4 C) 9 D) 8 E) none | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">5 + 7</gadget>
<output>12</output>
<gadget id="calculator">15 - 4</gadget>
<output>11</output>
<gadget id="calculator">15 - 2</gadget>
<output>13</output>
<gadget id="calculator">11 + 13</gadget>
<output>24</output>
<gadget id="calculator">12 + 24</gadget>
<output>36</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<result>C</result> | C | 9 | Find the average of all prime numbers between 4 and 15. | {
"A": "30",
"B": "4",
"C": "9",
"D": "8",
"E": "none"
} | divide(add(add(add(4, const_1), add(add(4, const_1), const_2)), add(subtract(15, 4), subtract(15, const_2))), const_4) | add(n0,const_1)|subtract(n1,n0)|subtract(n1,const_2)|add(#0,const_2)|add(#1,#2)|add(#0,#3)|add(#5,#4)|divide(#6,const_4) | sol . there are four prime numbers between 4 and 15 . they are 5 , 7 , 11 , 13 Γ’ Λ Β΄ required average = [ 5 + 7 + 11 + 13 / 4 ] = 36 / 4 = 9 answer c | general |
math_qa__YbAWYUSHGWvabjsX | 100 people are attending a newspaper conference. 40 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? Choices:
A) 21
B) 24
C) 28
D) 30
E) 32 | <gadget id="calculator">38 + 1</gadget>
<output>39</output>
<gadget id="calculator">39 + 40</gadget>
<output>79</output>
<gadget id="calculator">100 - 79</gadget>
<output>21</output>
<result>A</result> | A | 21 | 100 people are attending a newspaper conference. 40 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? | {
"A": "21",
"B": "24",
"C": "28",
"D": "30",
"E": "32"
} | subtract(100, add(add(38, const_1), 40)) | add(n2,const_1)|add(n1,#0)|subtract(n0,#1)| | "{ total } = { writers } + { editors } - { both } + { neither } . { total } = 100 ; { writers } = 40 ; { editors } > 38 ; { both } = x ; { neither } = 2 x ; 100 = 40 + { editors } - x + 2 x - - > x = 60 - { editors } . we want to maximize x , thus we should minimize { editors } , minimum possible value of { editors } is 39 , thus x = { both } = 60 - 39 = 21 . answer : a ." | other |
math_qa__iJjXnPOUzwtYVZAr | A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. What is the profit percentage? Pick: A) 166.69 % B) 166.66 % C) 166.76 % D) 136.66 % E) 566.66 % | <gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">16 / 6</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">(8/3) - 1</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 100</gadget>
<output>500/3 = around 166.666667</output>
<result>B</result> | B | 166.66 | A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. What is the profit percentage? | {
"A": "166.69 %",
"B": "166.66 %",
"C": "166.76 %",
"D": "136.66 %",
"E": "566.66 %"
} | multiply(subtract(divide(multiply(add(6, 2), 2), 6), const_1), const_100) | add(n0,n2)|multiply(n0,#0)|divide(#1,n2)|subtract(#2,const_1)|multiply(#3,const_100) | let the cost price of 1 litre pure milk be re . 1 , then \ inline \ begin { bmatrix } 6 & litres ( milk ) & \ rightarrow & cp = rs . 6 \ \ 2 & litres ( water ) & \ rightarrow & cp = rs . 0 \ end { bmatrix } \ rightarrow cp = rs . 6 only and 8 litre mixture \ rightarrow sp \ rightarrow 8 x 2 = rs . 16 profit % = % answer : b | gain |
math_qa__hw8sjLSR5FZoQJKs | A AND B CAN DO A WORK IN 12 DAYS, B AND C IN 15 DAYS, C AND A IN 20 DAYS. IF A, B AND C WORK TOGETHER, THEY WILL COMPLETE THE WORK IN: Answers: A) 5 days B) 7 5 / 6 days C) 10 days D) 15 2 / 3 days E) none of these | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/12) + (1/15)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(3/20) + (1/20)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / (1/10)</gadget>
<output>10</output>
<result>C</result> | C | 10 | A AND B CAN DO A WORK IN 12 DAYS, B AND C IN 15 DAYS, C AND A IN 20 DAYS. IF A, B AND C WORK TOGETHER, THEY WILL COMPLETE THE WORK IN: | {
"A": "5 days",
"B": "7 5 / 6 days",
"C": "10 days",
"D": "15 2 / 3 days",
"E": "none of these"
} | divide(const_1, divide(add(add(inverse(12), inverse(15)), inverse(20)), const_2)) | inverse(n0)|inverse(n1)|inverse(n2)|add(#0,#1)|add(#3,#2)|divide(#4,const_2)|divide(const_1,#5)| | "( a + b ) ' s 1 day ' s work = 1 / 12 , ( b + c ) ' s 1 day ' s work = 1 / 15 ; ( a + c ) ' s 1 day ' s work = 1 / 20 adding , we get : 2 ( a + b + c ) ' s 1 day ' s work = ( 1 / 12 + 1 / 15 + 1 / 20 ) = 12 / 60 = 1 / 5 ( a + b + c ) ' s 1 day ' s work = 1 / 10 so , a , b and c together can complete the work in 10 days . correct option : c" | physics |
math_qa__T6O1sCPpuSH7KrVN | A person distributed 15% of his income to his 3 children each. He deposited 30% of his income to his wife's account. He donated 10% of remaining amount to an orphan house.Finally he has $40000. Find his total income?
Answers:
A) 266666.7 B) 562000 C) 800000 D) 500000 E) 652000 | <gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">45 + 30</gadget>
<output>75</output>
<gadget id="calculator">75 + 10</gadget>
<output>85</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">40_000 / 15</gadget>
<output>8_000/3 = around 2_666.666667</output>
<gadget id="calculator">(8_000/3) * 100</gadget>
<output>800_000/3 = around 266_666.666667</output>
<result>A</result> | A | 266,666.7 | A person distributed 15% of his income to his 3 children each. He deposited 30% of his income to his wife's account. He donated 10% of remaining amount to an orphan house.Finally he has $40000. Find his total income? | {
"A": "266666.7",
"B": "562000",
"C": "800000",
"D": "500000",
"E": "652000"
} | multiply(divide(40000, subtract(const_100, add(add(multiply(15, 3), 30), 10))), const_100) | multiply(n0,n1)|add(n2,#0)|add(n3,#1)|subtract(const_100,#2)|divide(n4,#3)|multiply(#4,const_100) | 3 children got = 3 * 15 % = 45 % wife got = 30 % orphan house = 10 % total = 45 + 30 + 10 = 85 % remaining = 100 - 85 = 15 % 15 % = 40000 100 % = 40000 * 100 / 15 = $ 266666.7 answer is a | gain |
math_qa__BeNJ6glPB9HleHsK | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 240 m long? Options.
A) 38 sec B) 35 sec C) 44 sec D) 48 sec E) none of these | <gadget id="calculator">240 / 1_000</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">360 / 1_000</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(6/25) + (9/25)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) / 45</gadget>
<output>1/75 = around 0.013333</output>
<gadget id="calculator">(1/75) * 3_600</gadget>
<output>48</output>
<result>D</result> | D | 48 | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 240 m long? | {
"A": "38 sec",
"B": "35 sec",
"C": "44 sec",
"D": "48 sec",
"E": "none of these"
} | multiply(divide(add(divide(240, const_1000), divide(360, const_1000)), 45), const_3600) | divide(n2,const_1000)|divide(n0,const_1000)|add(#0,#1)|divide(#2,n1)|multiply(#3,const_3600) | speed = 45 km / hr = 45 Γ£ β ( 5 / 18 ) m / s = 150 / 12 = 50 / 4 = 25 / 2 m / s total distance = length of the train + length of the platform = 360 + 240 = 600 meter time taken to cross the platform = 600 / ( 25 / 2 ) = 600 Γ£ β 2 / 25 = 48 seconds answer : d | physics |
math_qa__0rms9o1aSV2MBEbX | A train 300 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is? Choose the most appropriate option.
A) 32 B) 48 C) 29 D) 27 E) 21 | <gadget id="calculator">300 + 300</gadget>
<output>600</output>
<gadget id="calculator">600 / 1_000</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">45 / 3_600</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">(3/5) / (1/80)</gadget>
<output>48</output>
<result>B</result> | B | 48 | A train 300 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is? | {
"A": "32",
"B": "48",
"C": "29",
"D": "27",
"E": "21"
} | divide(divide(add(300, 300), const_1000), divide(45, const_3600)) | add(n0,n1)|divide(n2,const_3600)|divide(#0,const_1000)|divide(#2,#1)| | "s = ( 300 + 300 ) / 45 = 600 / 45 * 18 / 5 = 48 answer : b" | physics |
math_qa__gwHTYiVE73ZbDYmd | How long does a train 165 meters long running at the rate of 72 kmph take to cross a bridge 660 meters in length? Choose the correct choice:
A) 28
B) 41.25
C) 55
D) 18
E) 12 | <gadget id="calculator">165 + 660</gadget>
<output>825</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">825 / 20</gadget>
<output>165/4 = around 41.25</output>
<result>B</result> | B | 41.25 | How long does a train 165 meters long running at the rate of 72 kmph take to cross a bridge 660 meters in length? | {
"A": "28",
"B": "41.25",
"C": "55",
"D": "18",
"E": "12"
} | divide(add(165, 660), multiply(72, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "t = ( 660 + 165 ) / 72 * 18 / 5 t = 41.25 answer : b" | physics |
math_qa__Fu42NcepBHtSuL0Q | What sum of money put at C.I amounts in 2 years to Rs.8800 and in 3 years to Rs.9261? Choose the correct choice from the following answers:
A) 7945 B) 8877 C) 2877 D) 2678 E) 1011 | <gadget id="calculator">9_261 / 8_800</gadget>
<output>9_261/8_800 = around 1.052386</output>
<gadget id="calculator">(9_261/8_800) - 1</gadget>
<output>461/8_800 = around 0.052386</output>
<gadget id="calculator">(461/8_800) + 1</gadget>
<output>9_261/8_800 = around 1.052386</output>
<gadget id="calculator">(9_261/8_800) ** 2</gadget>
<output>85_766_121/77_440_000 = around 1.107517</output>
<gadget id="calculator">8_800 / (85_766_121/77_440_000)</gadget>
<output>681_472_000_000/85_766_121 = around 7_945.701543</output>
<result>A</result> | A | 7,945 | What sum of money put at C.I amounts in 2 years to Rs.8800 and in 3 years to Rs.9261? | {
"A": "7945",
"B": "8877",
"C": "2877",
"D": "2678",
"E": "1011"
} | divide(8800, power(add(subtract(divide(9261, 8800), const_1), const_1), 2)) | divide(n3,n1)|subtract(#0,const_1)|add(#1,const_1)|power(#2,n0)|divide(n1,#3)| | "8800 - - - - 461 100 - - - - ? = > 5.238 % x * 105.238 / 100 * 105.238 / 100 = 8800 x * 1.1075 = 8800 x = 8800 / 1.1075 = > 7945.70 answer : a" | general |
math_qa__QNQnPyQ8ajDWJRWJ | Find the value of x. (47% of 1442 - 36% of 1412) + 63 = x? Choose the correct option:
A) 1
B) 5
C) 3
D) 6
E) 7 | <gadget id="calculator">47 / 100</gadget>
<output>47/100 = around 0.47</output>
<gadget id="calculator">(47/100) * 1_442</gadget>
<output>33_887/50 = around 677.74</output>
<gadget id="calculator">36 / 100</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(9/25) * 1_412</gadget>
<output>12_708/25 = around 508.32</output>
<gadget id="calculator">(33_887/50) - (12_708/25)</gadget>
<output>8_471/50 = around 169.42</output>
<gadget id="calculator">(8_471/50) + 63</gadget>
<output>11_621/50 = around 232.42</output>
<gadget id="calculator">(11_621/50) % 10</gadget>
<output>121/50 = around 2.42</output>
<gadget id="calculator">(121/50) + 1</gadget>
<output>171/50 = around 3.42</output>
<gadget id="calculator">floor(171/50)</gadget>
<output>3</output>
<result>C</result> | C | 3 | Find the value of x. (47% of 1442 - 36% of 1412) + 63 = x? | {
"A": "1",
"B": "5",
"C": "3",
"D": "6",
"E": "7"
} | floor(add(reminder(add(subtract(multiply(divide(47, const_100), 1442), multiply(divide(36, const_100), 1412)), 63), const_10), const_1)) | divide(n0,const_100)|divide(n2,const_100)|multiply(n1,#0)|multiply(n3,#1)|subtract(#2,#3)|add(n4,#4)|reminder(#5,const_10)|add(#6,const_1)|floor(#7)| | c ) 3 | general |
math_qa__iZiAT0EXTd0gxsFU | If in a certain code "RANGE" is coded as 12345 and "RANDOM" is coded as 123678. Then the code for the word
"GONE" would be Answers.
A) 3569 B) 1552 C) 4573 D) 4735 E) 5235 | <gadget id="calculator">1_000 / 2</gadget>
<output>500</output>
<gadget id="calculator">12_345 / 3</gadget>
<output>4_115</output>
<gadget id="calculator">500 + 4_115</gadget>
<output>4_615</output>
<result>D</result> | D | 4,735 | If in a certain code "RANGE" is coded as 12345 and "RANDOM" is coded as 123678. Then the code for the word
"GONE" would be | {
"A": "3569",
"B": "1552",
"C": "4573",
"D": "4735",
"E": "5235"
} | add(divide(const_1000, const_2), divide(12345, const_3)) | divide(const_1000,const_2)|divide(n0,const_3)|add(#0,#1) | g - 4 o - 7 n - 3 e - 5 so for mango the code is 4735 answer : d | general |
math_qa__pOU0MUnYg5TeXeG9 | If Henry were to add 4 gallons of water to a tank that is already 3/4 full of water, the tank would be 7/8 full. How many gallons of water would the tank hold if it were full?
Choose the correct choice from the following:
A) 32
B) 40
C) 64
D) 80
E) 96 | <gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(7/8) - (3/4)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<gadget id="calculator">4 * 8</gadget>
<output>32</output>
<result>A</result> | A | 32 | If Henry were to add 4 gallons of water to a tank that is already 3/4 full of water, the tank would be 7/8 full. How many gallons of water would the tank hold if it were full? | {
"A": "32",
"B": "40",
"C": "64",
"D": "80",
"E": "96"
} | multiply(4, divide(const_1, subtract(divide(7, 8), divide(3, 4)))) | divide(n3,n4)|divide(n1,n2)|subtract(#0,#1)|divide(const_1,#2)|multiply(n0,#3)| | "7 / 8 x - 3 / 4 x = 4 galls 1 / 8 * x = 4 gallons x = 32 gallons answer a" | general |
math_qa__JUp0VEp9OdjfKM71 | A train 120 m long crosses a platform with a speed of 60 kmph in 15 sec; find the length of the platform? Choose the correct option:
A) 110 B) 130 C) 120 D) 125 E) 135 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">15 * (50/3)</gadget>
<output>250</output>
<gadget id="calculator">250 - 120</gadget>
<output>130</output>
<result>B</result> | B | 130 | A train 120 m long crosses a platform with a speed of 60 kmph in 15 sec; find the length of the platform? | {
"A": "110",
"B": "130",
"C": "120",
"D": "125",
"E": "135"
} | subtract(multiply(15, multiply(60, const_0_2778)), 120) | multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0) | d = 120 + x t = 15 s = 120 + x / 15 * 18 / 5 = 60 kmph . = > ( 120 + x ) * 18 = 4500 = > 120 + x = 250 = > x = 130 m answer : b | physics |
math_qa__eW59UUM5wgyn4E1Z | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 5% p.a. in 5 years. What is the sum? Pick one.
A) 12021
B) 14520
C) 16065
D) 18925
E) 12887 | <gadget id="calculator">4_016.25 * 100</gadget>
<output>401_625</output>
<gadget id="calculator">401_625 / 5</gadget>
<output>80_325</output>
<gadget id="calculator">80_325 / 5</gadget>
<output>16_065</output>
<result>C</result> | C | 16,065 | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 5% p.a. in 5 years. What is the sum? | {
"A": "12021",
"B": "14520",
"C": "16065",
"D": "18925",
"E": "12887"
} | divide(divide(multiply(4016.25, const_100), 5), 5) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "principal = ( 100 * 4016.25 ) / ( 5 * 5 ) = rs . 16065 . answer : c" | gain |
math_qa__3jd6Xh62HnmWpPbo | A man rows his boat 84 km downstream and 48 km upstream, taking 2 hours each time. Find the speed of the stream?
Select:
A) 6 kmph
B) 5 kmph
C) 9 kmph
D) 8 kmph
E) 1 kmph | <gadget id="calculator">84 / 2</gadget>
<output>42</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<gadget id="calculator">42 - 24</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<result>C</result> | C | 9 | A man rows his boat 84 km downstream and 48 km upstream, taking 2 hours each time. Find the speed of the stream? | {
"A": "6 kmph",
"B": "5 kmph",
"C": "9 kmph",
"D": "8 kmph",
"E": "1 kmph"
} | divide(subtract(divide(84, 2), divide(48, 2)), const_2) | divide(n0,n2)|divide(n1,n2)|subtract(#0,#1)|divide(#2,const_2)| | "speed downstream = d / t = 84 / ( 2 ) = 42 kmph speed upstream = d / t = 48 / ( 2 ) = 24 kmph the speed of the stream = ( 42 - 24 ) / 2 = 9 kmph answer : c" | physics |
math_qa__lDyWn1OhmWDeTKmN | Ratio between length and breath of a rectangle is 25:16. The area of the rectangle is same with a square whose side is 200. Find the breadth and length of the rectangle? Select the correct option:
A) 150,200 B) 140,300 C) 100,300 D) 160,250 E) 100,200 | <gadget id="calculator">200 ** 2</gadget>
<output>40_000</output>
<gadget id="calculator">25 * 16</gadget>
<output>400</output>
<gadget id="calculator">40_000 / 400</gadget>
<output>100</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">10 * 16</gadget>
<output>160</output>
<gadget id="calculator">1_000 * 160</gadget>
<output>160_000</output>
<gadget id="calculator">10 * 25</gadget>
<output>250</output>
<gadget id="calculator">160_000 + 250</gadget>
<output>160_250</output>
<result>D</result> | D | 160,250 | Ratio between length and breath of a rectangle is 25:16. The area of the rectangle is same with a square whose side is 200. Find the breadth and length of the rectangle? | {
"A": "150,200",
"B": "140,300",
"C": "100,300",
"D": "160,250",
"E": "100,200"
} | add(multiply(const_1000, multiply(sqrt(divide(square_area(200), multiply(25, 16))), 16)), multiply(sqrt(divide(square_area(200), multiply(25, 16))), 25)) | multiply(n0,n1)|square_area(n2)|divide(#1,#0)|sqrt(#2)|multiply(n1,#3)|multiply(n0,#3)|multiply(#4,const_1000)|add(#6,#5) | let length l = 25 x and breadth b = 16 x area of the square = 200 ^ 2 = 40000 16 x * 25 x = 40000 400 x ^ 2 = 40000 x ^ 2 = 100 x = 10 length = 25 * 10 = 250 breadth = 16 * 10 = 160 answer : d | geometry |
math_qa__2PDqPXtyFb2tAR3R | What number has a 20:1 ratio to the number 10? Choose the correct choice from the following answers:
A) 130 B) 100 C) 200 D) 150 E) 120 | <gadget id="calculator">10 * 20</gadget>
<output>200</output>
<result>C</result> | C | 200 | What number has a 20:1 ratio to the number 10? | {
"A": "130",
"B": "100",
"C": "200",
"D": "150",
"E": "120"
} | multiply(10, 20) | multiply(n0,n2)| | "20 : 1 = x : 10 x = 10 * 20 x = 150 answer : c" | other |
math_qa__hkx4drLzXBJWBlzM | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 146, what is the difference between the ages of Patrick and Monica?
Choose the correct choice.
A) 27 B) 48 C) 45 D) 72 E) 18 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">9 + 15</gadget>
<output>24</output>
<gadget id="calculator">24 + 25</gadget>
<output>49</output>
<gadget id="calculator">146 / 49</gadget>
<output>146/49 = around 2.979592</output>
<gadget id="calculator">25 * (146/49)</gadget>
<output>3_650/49 = around 74.489796</output>
<gadget id="calculator">9 * (146/49)</gadget>
<output>1_314/49 = around 26.816327</output>
<gadget id="calculator">(3_650/49) - (1_314/49)</gadget>
<output>2_336/49 = around 47.673469</output>
<result>B</result> | B | 48 | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 146, what is the difference between the ages of Patrick and Monica? | {
"A": "27",
"B": "48",
"C": "45",
"D": "72",
"E": "18"
} | subtract(multiply(multiply(5, 5), divide(146, add(add(multiply(3, 3), multiply(3, 5)), multiply(5, 5)))), multiply(multiply(3, 3), divide(146, add(add(multiply(3, 3), multiply(3, 5)), multiply(5, 5))))) | multiply(n0,n0)|multiply(n1,n0)|multiply(n1,n3)|add(#0,#1)|add(#3,#2)|divide(n4,#4)|multiply(#5,#2)|multiply(#5,#0)|subtract(#6,#7)| | "ages of p and mi = 3 x + 5 x ages of mi and mo = 3 x : 5 x rationalizing their ages . ratio of their ages will be 9 x : 15 x : 25 x sum = 47 x = 146 x = 3 difference if ages of pa and mo = 25 x - 9 x = 16 x = 16 * 3 = 48 answer b" | general |
math_qa__yFXTYaTVmsC9cMT1 | Mark bought a set of 6 flower pots of different sizes at a total cost of $8.25. Each pot cost 0.3 more than the next one below it in size. What was the cost, in dollars, of the largest pot? Choose the correct choice from the following options
A) $ 1.75 B) $ 1.85 C) $ 2.00 D) $ 2.12 E) $ 2.30 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 * 0.3</gadget>
<output>4.5</output>
<gadget id="calculator">8.25 - 4.5</gadget>
<output>3.75</output>
<gadget id="calculator">3.75 / 6</gadget>
<output>0.625</output>
<gadget id="calculator">5 * 0.3</gadget>
<output>1.5</output>
<gadget id="calculator">0.625 + 1.5</gadget>
<output>2.125</output>
<result>D</result> | D | 2.12 | Mark bought a set of 6 flower pots of different sizes at a total cost of $8.25. Each pot cost 0.3 more than the next one below it in size. What was the cost, in dollars, of the largest pot? | {
"A": "$ 1.75",
"B": "$ 1.85",
"C": "$ 2.00",
"D": "$ 2.12",
"E": "$ 2.30"
} | add(divide(subtract(8.25, multiply(divide(multiply(subtract(6, const_1), 6), const_2), 0.3)), 6), multiply(subtract(6, const_1), 0.3)) | subtract(n0,const_1)|multiply(n0,#0)|multiply(n2,#0)|divide(#1,const_2)|multiply(n2,#3)|subtract(n1,#4)|divide(#5,n0)|add(#6,#2)| | "this question can be solved with a handful of different algebra approaches ( as has been shown in the various posts ) . since the question asks for the price of the largest pot , and the answers are prices , we can test the answers . we ' re told that there are 6 pots and that each pot costs 30 cents more than the next . the total price of the pots is $ 8.25 . we ' re asked for the price of the largest ( most expensive ) pot . since the total price is $ 8.25 ( a 30 - cent increment ) and the the difference in sequential prices of the pots is 30 cents , the largest pot probably has a price that is a 30 - cent increment . from the answer choices , i would then test answer d if . . . . the largest pot = $ 2.125 the other 5 pots are . . . . 0.625 0.925 1.225 1.525 1.825 2.125 total = $ 8.25 so this must be the answer . d" | general |
math_qa__xdgkiC7EMRuCuL97 | What quantity of water should taken out to concentrate 15 liters of 40% acidic liquid to 60% acidic liquid? Select: A) 5 liters B) 10 liters C) 15 liters D) 8 liters E) 6 liters | <gadget id="calculator">15 * 40</gadget>
<output>600</output>
<gadget id="calculator">600 / 60</gadget>
<output>10</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<result>A</result> | A | 5 | What quantity of water should taken out to concentrate 15 liters of 40% acidic liquid to 60% acidic liquid? | {
"A": "5 liters",
"B": "10 liters",
"C": "15 liters",
"D": "8 liters",
"E": "6 liters"
} | subtract(15, divide(multiply(15, 40), 60)) | multiply(n0,n1)|divide(#0,n2)|subtract(n0,#1) | required answer is = 15 ( 60 - 40 ) / 60 = 5 liters answer is a | gain |
math_qa__m1rOTMZi0zWunUd9 | A trained covered x km at 65 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km. Select: A) 22 B) 99 C) 26 D) 66 E) 887 | <gadget id="calculator">65 * 3</gadget>
<output>195</output>
<gadget id="calculator">65 / 65</gadget>
<output>1</output>
<gadget id="calculator">2 * 65</gadget>
<output>130</output>
<gadget id="calculator">130 / 20</gadget>
<output>13/2 = around 6.5</output>
<gadget id="calculator">1 + (13/2)</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">195 / (15/2)</gadget>
<output>26</output>
<result>C</result> | C | 26 | A trained covered x km at 65 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km. | {
"A": "22",
"B": "99",
"C": "26",
"D": "66",
"E": "887"
} | divide(multiply(65, 3), add(divide(65, 65), divide(multiply(2, 65), 20))) | divide(n0,n0)|multiply(n0,n3)|multiply(n0,n1)|divide(#2,n2)|add(#0,#3)|divide(#1,#4)| | "total time taken = x / 65 + 2 x / 20 hours = 3 x / 26 hours average speed = 3 x / ( 3 x / 26 ) = 26 kmph answer : c" | general |
math_qa__HJVxJp5hNMye6DKB | Ms. Lopez deposits $ 140 in an account that pays 20% interest, compounded semiannually. How much money will there be in the account at the end of one year? Choose the correct choice from the following answers.
A) $ 118.00
B) $ 120.00
C) $ 169.40
D) $ 122.00
E) $ 140.00 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 2</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">140 * (121/100)</gadget>
<output>847/5 = around 169.4</output>
<result>C</result> | C | 169.4 | Ms. Lopez deposits $ 140 in an account that pays 20% interest, compounded semiannually. How much money will there be in the account at the end of one year? | {
"A": "$ 118.00",
"B": "$ 120.00",
"C": "$ 169.40",
"D": "$ 122.00",
"E": "$ 140.00"
} | multiply(140, power(add(const_1, divide(divide(20, const_100), const_2)), const_2)) | divide(n1,const_100)|divide(#0,const_2)|add(#1,const_1)|power(#2,const_2)|multiply(n0,#3) | using formula - a = p ( 1 + r / n ) ^ nt given p = 140 n = 2 t = 1 r = 0.2 substituting value in formula a = 140 ( 1 + 0.2 / 2 ) ^ 2 a = 169.40 $ = c | gain |
math_qa__BCLSl2GkQpQZjiIc | A train running at the speed of 72 km/hr crosses a pole in 9 seconds. What is the length of the train? Choose the correct choice from the following: A) 286 B) 278 C) 255 D) 180 E) 287 | <gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">20 * 9</gadget>
<output>180</output>
<result>D</result> | D | 180 | A train running at the speed of 72 km/hr crosses a pole in 9 seconds. What is the length of the train? | {
"A": "286",
"B": "278",
"C": "255",
"D": "180",
"E": "287"
} | multiply(divide(multiply(72, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = ( 72 * 5 / 18 ) m / sec = ( 20 ) m / sec length of the train = ( speed x time ) = ( 20 * 9 ) m = 180 m . answer : d" | physics |
math_qa__zdSt2KlxZKgJx3wW | The speed at which a man can row a boat in still water is 20 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres? Choose the correct choice from the following answers: A) 16 seconds B) 76 seconds C) 26 seconds D) 9.4 seconds E) 18 seconds | <gadget id="calculator">20 + 3</gadget>
<output>23</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">23 * (5/18)</gadget>
<output>115/18 = around 6.388889</output>
<gadget id="calculator">60 / (115/18)</gadget>
<output>216/23 = around 9.391304</output>
<result>D</result> | D | 9.4 | The speed at which a man can row a boat in still water is 20 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres? | {
"A": "16 seconds",
"B": "76 seconds",
"C": "26 seconds",
"D": "9.4 seconds",
"E": "18 seconds"
} | divide(60, multiply(add(20, 3), const_0_2778)) | add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1)| | "speed of the boat downstream = 20 + 3 = 23 kmph = 23 * 5 / 18 = 115 / 18 m / s hence time taken to cover 60 m = 60 * 18 / 115 = 9.4 seconds . answer : d" | physics |
math_qa__ZgYRfbPX7CS3l0fB | A 16% stock yielding 14% is quoted at: Pick:
A) s . 83.33 B) s . 110 C) s . 114 D) s . 120 E) s . 140 | <gadget id="calculator">100 / 14</gadget>
<output>50/7 = around 7.142857</output>
<gadget id="calculator">(50/7) * 16</gadget>
<output>800/7 = around 114.285714</output>
<result>C</result> | C | 114 | A 16% stock yielding 14% is quoted at: | {
"A": "s . 83.33",
"B": "s . 110",
"C": "s . 114",
"D": "s . 120",
"E": "s . 140"
} | multiply(divide(const_100, 14), 16) | divide(const_100,n1)|multiply(n0,#0)| | "income of rs 14 on investment of rs 100 income of rs 16 on investment of ? = ( 16 * 100 ) / 14 = 114 answer : c" | gain |
math_qa__ReoHUINaJIvehSMX | In filling a lot with sand, that is 40 m * 20 m * 2m the volumes of the sand filled will be?
Choose the correct option
A) 1200 cu . m B) 2200 cu . m C) 4800 cu . m D) 1600 cu . m E) 4000 cu . m | <gadget id="calculator">40 * 20 * 2</gadget>
<output>1_600</output>
<result>D</result> | D | 1,600 | In filling a lot with sand, that is 40 m * 20 m * 2m the volumes of the sand filled will be? | {
"A": "1200 cu . m",
"B": "2200 cu . m",
"C": "4800 cu . m",
"D": "1600 cu . m",
"E": "4000 cu . m"
} | volume_rectangular_prism(40, 20, 2) | volume_rectangular_prism(n0,n1,n2) | 40 * 20 * 2 = 1600 answer : d | physics |
math_qa__Ty6EtfsTZToAZEhW | The value of ((x β y)Β³ + (y - z)Β³ + (z β x)Β³)/(15 (x β y) (y β z) (z β x))
is equal to : Pick one
A) 0
B) 1 / 12
C) 1
D) 1 / 5
E) 1 / 3 | <gadget id="calculator">3 / 15</gadget>
<output>1/5 = around 0.2</output>
<result>D</result> | D | 0.2 | The value of ((x β y)Β³ + (y - z)Β³ + (z β x)Β³)/(15 (x β y) (y β z) (z β x))
is equal to : | {
"A": "0",
"B": "1 / 12",
"C": "1",
"D": "1 / 5",
"E": "1 / 3"
} | divide(const_3, 15) | divide(const_3,n0) | since ( x β y ) + ( y β z ) + ( z β x ) = 0 , so ( x β y ) Β³ + ( y β z ) Β³ + ( z β x ) Β³ = 3 ( x β y ) ( y β z ) ( z β x ) . ( 3 ( x β y ) ( y β z ) ( z β x ) ) / ( 15 ( x β y ) ( y β z ) ( z β x ) ) = 1 / 5 . answer : d | general |
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