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math_qa__J6EHFnNQ6fPHfoSJ | On a certain day, Tim invested $500 at 10 percent annual interest, compounded annually, and Lana invested 900 at 5 percent annual interest, compounded annually.The total amount of interest earned by Tim’s investment in the first 2 years was how much greater than the total amount of interest earned by Lana’s investment in the first 2 years? Choose the correct choice from the following answers:
A) $ 5 B) $ 12.75 C) $ 51.75 D) $ 100.75 E) $ 105 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 2</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">500 * (121/100)</gadget>
<output>605</output>
<gadget id="calculator">605 - 500</gadget>
<output>105</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">(441/400) * 900</gadget>
<output>3_969/4 = around 992.25</output>
<gadget id="calculator">(3_969/4) - 900</gadget>
<output>369/4 = around 92.25</output>
<gadget id="calculator">105 - (369/4)</gadget>
<output>51/4 = around 12.75</output>
<result>B</result> | B | 12.75 | On a certain day, Tim invested $500 at 10 percent annual interest, compounded annually, and Lana invested 900 at 5 percent annual interest, compounded annually.The total amount of interest earned by Tim’s investment in the first 2 years was how much greater than the total amount of interest earned by Lana’s investment in the first 2 years? | {
"A": "$ 5",
"B": "$ 12.75",
"C": "$ 51.75",
"D": "$ 100.75",
"E": "$ 105"
} | subtract(subtract(multiply(500, power(add(const_1, divide(10, const_100)), 2)), 500), subtract(multiply(power(add(const_1, divide(5, const_100)), 2), 900), 900)) | divide(n1,const_100)|divide(n3,const_100)|add(#0,const_1)|add(#1,const_1)|power(#2,n4)|power(#3,n4)|multiply(n0,#4)|multiply(n2,#5)|subtract(#6,n0)|subtract(#7,n2)|subtract(#8,#9)| | "compounded annually means that the interest is applied once per year . one can have 10 % annual interest compounded monthly - in this case 10 % / 12 would be applied each month , or 10 % annual interest compounded daily etc . with respect to the problem at hand , at the end of two years , tim would have 500 ( 1.10 ) ^ 2 = 500 ( 1.21 ) = 605 and lana would have 900 ( 1.05 ) ^ 2 = 900 ( 1.1025 ) = 992.25 thus , tim earned 105 dollars , while lana earned 92.25 dollars the difference is $ 12.75 and the answer is b ." | gain |
math_qa__GsSBJ6DcTman6QlR | A cube of sides 9 is first painted red and then cut into smaller cubes of side 3. How many of the smaller cube have painted on exactly 2 sides? Pick:
A) 30
B) 24
C) 12
D) 8
E) 9 | <gadget id="calculator">9 * 3</gadget>
<output>27</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">27 - 7</gadget>
<output>20</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">20 - 8</gadget>
<output>12</output>
<result>C</result> | C | 12 | A cube of sides 9 is first painted red and then cut into smaller cubes of side 3. How many of the smaller cube have painted on exactly 2 sides? | {
"A": "30",
"B": "24",
"C": "12",
"D": "8",
"E": "9"
} | subtract(subtract(multiply(9, 3), add(3, const_4)), multiply(const_4, 2)) | add(n1,const_4)|multiply(n0,n1)|multiply(n2,const_4)|subtract(#1,#0)|subtract(#3,#2) | n = side of big cube / side of small cube and no . of smaller cubes with two surfaces painted is ( n - 2 ) * 12 ( 3 - 2 ) * 12 = 12 ans answer : c | geometry |
math_qa__MSze4vsfZDdHqezV | A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in: Choose one.
A) 33 / 7 B) 43 / 7 C) 24 / 7 D) 19 / 7 E) none | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/24) + (1/6)</gadget>
<output>5/24 = around 0.208333</output>
<gadget id="calculator">(1/12) + (5/24)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">1 / (7/24)</gadget>
<output>24/7 = around 3.428571</output>
<result>C</result> | C | 3.428571 | A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in: | {
"A": "33 / 7",
"B": "43 / 7",
"C": "24 / 7",
"D": "19 / 7",
"E": "none"
} | inverse(add(inverse(12), add(inverse(24), inverse(6)))) | inverse(n0)|inverse(n1)|inverse(n2)|add(#0,#1)|add(#3,#2)|inverse(#4) | if a can do a piece of work in n days , then a ' s 1 day ' s work = 1 / n ( a + b + c ) ' s 1 day ' s work = 1 / 24 + 1 / 6 + 1 / 12 = 7 / 24 so , all the three together will complete the job in = 24 / 7 days answer : c | physics |
math_qa__GNbhxYbUXwPWXfzn | A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Choose the correct choice:
A) 35
B) 36
C) 37
D) 40
E) 45 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">12 / 1</gadget>
<output>12</output>
<gadget id="calculator">40 / 60</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">12 * (2/3)</gadget>
<output>8</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">8 * 5</gadget>
<output>40</output>
<result>D</result> | D | 40 | A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is: | {
"A": "35",
"B": "36",
"C": "37",
"D": "40",
"E": "45"
} | multiply(multiply(divide(multiply(multiply(2, 3), 2), subtract(3, 2)), divide(40, const_60)), add(const_1, divide(divide(multiply(multiply(2, 3), 2), subtract(3, 2)), 3))) | divide(n1,const_60)|multiply(n0,n2)|subtract(n0,n2)|multiply(n2,#1)|divide(#3,#2)|divide(#4,n0)|multiply(#4,#0)|add(#5,const_1)|multiply(#7,#6)| | "according to given condition vt = ( v + 3 ) ( t - 2 / 3 ) vt = ( v - 2 ) ( t + 2 / 3 ) here v is velocity in kmph , t is time in hours and 2 / 3 is value of 40 min in hour on solving we will get t = 10 / 3 and and v = 12 so distance = ( 10 / 3 ) * 12 = 40 kms answer : d" | physics |
math_qa__SO2rMW799Qrnxx40 | A shoe merchant has declared a 10% rebate in prices. How much rebate would one get if he purchases 5 pairs of shoes at Rs.28 each?
Choose the correct choice from the following options.
A) 11
B) 12
C) 13
D) 14
E) 15 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">5 * 28</gadget>
<output>140</output>
<gadget id="calculator">(1/10) * 140</gadget>
<output>14</output>
<result>D</result> | D | 14 | A shoe merchant has declared a 10% rebate in prices. How much rebate would one get if he purchases 5 pairs of shoes at Rs.28 each? | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | multiply(divide(10, const_100), multiply(5, 28)) | divide(n0,const_100)|multiply(n1,n2)|multiply(#0,#1) | explanation : 5 shirts * rs . 28 = rs . 140 rebate = 10 % * 140 = 14 correct option : d | gain |
math_qa__vHK4mOxkKyRqoHi6 | If the average of 8 digits is 20 and the average of 5 of them is 12, calculate the average of the remaining 3 numbers?
Pick: A) 13.3 B) 38.3 C) 35.3 D) 31.3 E) 33.3 | <gadget id="calculator">8 * 20</gadget>
<output>160</output>
<gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">160 - 60</gadget>
<output>100</output>
<gadget id="calculator">100 / 3</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33.3 | If the average of 8 digits is 20 and the average of 5 of them is 12, calculate the average of the remaining 3 numbers? | {
"A": "13.3",
"B": "38.3",
"C": "35.3",
"D": "31.3",
"E": "33.3"
} | divide(subtract(multiply(8, 20), multiply(5, 12)), 3) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)|divide(#2,n4)| | "explanation : total of the 8 digits - 8 * 20 = 160 total of the 5 digits - 5 * 12 = 60 total of the remaining 3 digits - 160 - 60 = 100 average of the remaining 3 numbers = 100 / 3 = 33.3 answer : e" | general |
math_qa__8p8Lsj1bWlQRiIEU | In a restaurant, the profit is 120% of the cost. If the cost increases by 12% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Choose the correct choice from the following answers:
A) 30 % B) 49 % C) 90 % D) 100 % E) none of these | <gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">100 * (6/5)</gadget>
<output>120</output>
<gadget id="calculator">120 + 100</gadget>
<output>220</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 + (3/25)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">100 * (28/25)</gadget>
<output>112</output>
<gadget id="calculator">220 - 112</gadget>
<output>108</output>
<gadget id="calculator">108 / 220</gadget>
<output>27/55 = around 0.490909</output>
<gadget id="calculator">100 * (27/55)</gadget>
<output>540/11 = around 49.090909</output>
<result>B</result> | B | 49 | In a restaurant, the profit is 120% of the cost. If the cost increases by 12% but the selling price remains constant, approximately what percentage of the selling price is the profit? | {
"A": "30 %",
"B": "49 %",
"C": "90 %",
"D": "100 %",
"E": "none of these"
} | multiply(const_100, divide(subtract(add(multiply(const_100, divide(120, const_100)), const_100), multiply(const_100, add(const_1, divide(12, const_100)))), add(multiply(const_100, divide(120, const_100)), const_100))) | divide(n0,const_100)|divide(n1,const_100)|add(#1,const_1)|multiply(#0,const_100)|add(#3,const_100)|multiply(#2,const_100)|subtract(#4,#5)|divide(#6,#4)|multiply(#7,const_100)| | "explanation : let c . p . = rs . 100 . then , profit = rs . 120 , s . p . = rs . 220 . new c . p . = 112 % of rs . 100 = rs . 112 new s . p . = rs . 220 . profit = rs . ( 220 - 112 ) = rs . 108 . required percentage = ( 108 / 220 * 100 ) % = 49 % appox answer : b" | gain |
math_qa__SS9iXImgUIOubStu | A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
Choose the correct choice from the following choices.
A) 278 B) 277 C) 278 D) 450 E) 272 | <gadget id="calculator">10 * 150</gadget>
<output>1_500</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">300 + 750</gadget>
<output>1_050</output>
<gadget id="calculator">1_500 - 1_050</gadget>
<output>450</output>
<result>D</result> | D | 450 | A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? | {
"A": "278",
"B": "277",
"C": "278",
"D": "450",
"E": "272"
} | subtract(multiply(const_10, 150), add(multiply(3, 100), multiply(5, 150))) | multiply(n3,const_10)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|subtract(#0,#3)| | "10 * 150 = 1500 3 * 100 + 5 * 150 = 1050 1500 – 1050 = 450 answer : d" | general |
math_qa__jKcMJJoCExFeSp6I | A shop owner sells 30mtr of cloth and gains SP of 10 mtrs. Find the gain %?
Choose the correct choice from the following:
A) 30 % B) 40 % C) 50 % D) 60 % E) 70 % | <gadget id="calculator">30 - 10</gadget>
<output>20</output>
<gadget id="calculator">10 / 20</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | A shop owner sells 30mtr of cloth and gains SP of 10 mtrs. Find the gain %? | {
"A": "30 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "70 %"
} | multiply(divide(10, subtract(30, 10)), const_100) | subtract(n0,n1)|divide(n1,#0)|multiply(#1,const_100)| | "here , selling price of 10 m cloth is obtained as profit . profit of 10 m cloth = ( s . p . of 30 m cloth ) – ( c . p . of 30 m cloth ) selling price of 20 m cloth = selling price of 30 m of cloth let cost of each metre be rs . 100 . therefore , cost price of 20 m cloth = rs . 2000 and s . p . of 20 m cloth = rs . rs . 3000 profit % = 10 × 100 = 50 % 20 profit of 50 % was made by the merchant . c" | gain |
math_qa__aQTl09ifhDM4xxFh | A certain Dark Blue paint contains 40 percent blue pigment and 60 percent red pigment by weight. A certain green paint contains 40 percent blue pigment and 60 percent yellow pigment. When these paints are mixed to produce a brown paint, the brown paint contains 40 percent blue pigment. If the brown paint weighs 10 grams, then the red pigment contributes how many grams of that weight? Choose the correct choice from the following:
A) 3.5 B) 4 C) 4.5 D) 3 E) 5 | <gadget id="calculator">10 * 40</gadget>
<output>400</output>
<gadget id="calculator">400 / 100</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">60 / 40</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">2 * (3/2)</gadget>
<output>3</output>
<result>D</result> | D | 3 | A certain Dark Blue paint contains 40 percent blue pigment and 60 percent red pigment by weight. A certain green paint contains 40 percent blue pigment and 60 percent yellow pigment. When these paints are mixed to produce a brown paint, the brown paint contains 40 percent blue pigment. If the brown paint weighs 10 grams, then the red pigment contributes how many grams of that weight? | {
"A": "3.5",
"B": "4",
"C": "4.5",
"D": "3",
"E": "5"
} | multiply(divide(divide(multiply(const_10, 40), const_100), const_2), divide(60, 40)) | divide(n1,n0)|multiply(n0,const_10)|divide(#1,const_100)|divide(#2,const_2)|multiply(#3,#0) | 10 grams of combined mixture and 40 % blue pigment means that the mixtures were mixed 50 % each . thus 5 grams a piece . out of the 5 grams of the dark blue paint , 60 % is red . therefore , 5 * . 6 = 3 grams of red pigment | gain |
math_qa__ea7svabSnpsNf8HS | In Goshawk-Eurasian nature reserve 30 percent of the birds are Hawks, and 40 percent of the non-Hawks are Paddyfield-Warblers. If there are 25 percent as many Kingfishers as Paddyfield-Warblers in the reserve, then what percent of the birds X in the nature reserve are not Hawks, Paddyfield-Warblers, or Kingfishers? Pick.
A) 25 % B) 35 % C) 45 % D) 70 % E) 80 % | <gadget id="calculator">25 + 25</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">10 + 25</gadget>
<output>35</output>
<result>B</result> | B | 35 | In Goshawk-Eurasian nature reserve 30 percent of the birds are Hawks, and 40 percent of the non-Hawks are Paddyfield-Warblers. If there are 25 percent as many Kingfishers as Paddyfield-Warblers in the reserve, then what percent of the birds X in the nature reserve are not Hawks, Paddyfield-Warblers, or Kingfishers? | {
"A": "25 %",
"B": "35 %",
"C": "45 %",
"D": "70 %",
"E": "80 %"
} | add(const_10, divide(add(25, 25), const_2)) | add(n2,n2)|divide(#0,const_2)|add(#1,const_10)| | "1 . we are given the following percentages : 30 ( 70 ) , 40 ( 60 ) , 25 ( 75 ) . there are two threads from here . first starts at 30 % and finishes there . second one starts at 70 , then 40 , and then 25 . we need a value that is divisible by 7 , 2 , and 5 at least once . lets pick a number now , say 700 . so say if non hawks are 700 ( this is 70 % of the total , so total = 1000 ) , then paddy warbs are 2 / 5 x 700 = 1400 / 5 = 280 . kingfishers , therefore , are 280 / 4 = 70 . lets add them up . 300 hawks + 280 peddy warbs + 70 kingsifhers = 650 . so all others are 1000 - 650 = 350 or 35 % of total birds . the main job here to to identify the smart number to start the question with . this can be time consuming , but once identified , this question can be solved fairly quickly . 2 . another method : if x is total - - > non hawks = 0.7 x - - > warbs = 0.4 ( 0.7 x ) - - > kfs = 0.25 ( 0.4 ( 0.7 x ) ) . our job is to find out x : ( 0.3 x + 0.28 x + 0.07 x ) / x . or 0.65 x / x = 0.65 . we need to find 1 - 0.65 = 0.35 or 35 % . b" | general |
math_qa__VZDFvNwnJO1tDdj2 | Rahul can done a work in 5 days and meena can done a work in 10 days.In how many days that both are work together? Choose the correct option.
A) 3 / 10 B) 10 / 3 C) 1 / 3 D) 5 E) 6 / 3 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/5) + (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 / (3/10)</gadget>
<output>10/3 = around 3.333333</output>
<result>B</result> | B | 3.333333 | Rahul can done a work in 5 days and meena can done a work in 10 days.In how many days that both are work together? | {
"A": "3 / 10",
"B": "10 / 3",
"C": "1 / 3",
"D": "5",
"E": "6 / 3"
} | inverse(add(divide(const_1, 5), divide(const_1, 10))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2) | a ' s one day work = 1 / 5 b ' s one day work = 1 / 10 a + b = 1 / 5 + 1 / 10 = 10 + 5 / 50 = 10 / 3 days ans : option b | physics |
math_qa__a1MvRSgZ8aApQNTR | A bicycle wheel has a diameter of 0.75m. How many complete revolutions does it make in 1km? Pick:
A) 424 B) 448 C) 1408 D) 710 E) 223 | <gadget id="calculator">1_000 * 1</gadget>
<output>1_000</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">3 + (7/50)</gadget>
<output>157/50 = around 3.14</output>
<gadget id="calculator">(157/50) * 0.75</gadget>
<output>2.355</output>
<gadget id="calculator">1_000 / 2.355</gadget>
<output>424.62845</output>
<result>A</result> | A | 424 | A bicycle wheel has a diameter of 0.75m. How many complete revolutions does it make in 1km? | {
"A": "424",
"B": "448",
"C": "1408",
"D": "710",
"E": "223"
} | divide(multiply(const_1000, 1), multiply(add(const_3, divide(add(multiply(const_3, const_4), const_2), power(add(multiply(const_4, const_2), const_2), const_2))), 0.75)) | multiply(n1,const_1000)|multiply(const_3,const_4)|multiply(const_2,const_4)|add(#1,const_2)|add(#2,const_2)|power(#4,const_2)|divide(#3,#5)|add(#6,const_3)|multiply(n0,#7)|divide(#0,#8)| | "1 revolution = 3.14 * diameter . number of revolutions in 1 km = 1000 m / ( 3.14 * 0.75 m ) = 424.6 . hence 424 complete revolutions . answer a" | physics |
math_qa__GPBkCQSV6zZEuFdZ | Country X taxes each of its citizens an amount equal to 15 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income?
Pick: A) $ 40,000 B) $ 50,000 C) $ 64,000 D) $ 66,667 E) $ 80,000 | <gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 * 1_000</gadget>
<output>40_000</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 1_000</gadget>
<output>8_000</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 40_000</gadget>
<output>6_000</output>
<gadget id="calculator">8_000 - 6_000</gadget>
<output>2_000</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2_000 / (1/5)</gadget>
<output>10_000</output>
<gadget id="calculator">40_000 + 10_000</gadget>
<output>50_000</output>
<result>B</result> | B | 50,000 | Country X taxes each of its citizens an amount equal to 15 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income? | {
"A": "$ 40,000",
"B": "$ 50,000",
"C": "$ 64,000",
"D": "$ 66,667",
"E": "$ 80,000"
} | add(multiply(multiply(const_4, const_10), const_1000), divide(subtract(multiply(multiply(const_4, const_2), const_1000), multiply(divide(15, const_100), multiply(multiply(const_4, const_10), const_1000))), divide(20, const_100))) | divide(n0,const_100)|divide(n2,const_100)|multiply(const_2,const_4)|multiply(const_10,const_4)|multiply(#2,const_1000)|multiply(#3,const_1000)|multiply(#0,#5)|subtract(#4,#6)|divide(#7,#1)|add(#8,#5) | equation is correct , so math must be a problem . 0.15 * 40,000 + 0.2 * ( x - 40,000 ) = 8,000 - - > 6,000 + 0.2 x - 8,000 = 8,000 - - > 0.2 x = 10,000 - - > x = 50,000 . answer : b . | general |
math_qa__IVZmFEnEzNaEaQid | A, B, C, D and E are 5 consecutive points on a straight line. If BC = 2CD, DE = 8, AB = 5 and AC = 11, what is the length of AE? Choose the correct option.
A) 18
B) 20
C) 22
D) 24
E) 26 | <gadget id="calculator">11 - 5</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">11 + 3</gadget>
<output>14</output>
<gadget id="calculator">14 + 8</gadget>
<output>22</output>
<result>C</result> | C | 22 | A, B, C, D and E are 5 consecutive points on a straight line. If BC = 2CD, DE = 8, AB = 5 and AC = 11, what is the length of AE? | {
"A": "18",
"B": "20",
"C": "22",
"D": "24",
"E": "26"
} | add(add(11, divide(subtract(11, 5), 2)), 8) | subtract(n4,n0)|divide(#0,n1)|add(n4,#1)|add(n2,#2)| | "ac = 11 and ab = 5 , so bc = 6 . bc = 2 cd so cd = 3 . the length of ae is ab + bc + cd + de = 5 + 6 + 3 + 8 = 22 the answer is c ." | physics |
math_qa__1HMYW42lNsZv3rER | On a windy day, out of every 3 sand dunes formed, only 1 remains. Out of 5 blown-out
sand-dunes, 1 has treasure and only 2 out of 3 sand dunes formed have lucky coupons. Find
the probability that the blown-out sand dune will contain both the things. Choose the correct choice from the following answers.
A) 2 / 25 B) 4 / 75 C) 7 / 75 D) 3 / 5 E) 4 / 45 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(2/3) * (1/5)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/3) * (2/15)</gadget>
<output>4/45 = around 0.088889</output>
<result>E</result> | E | 0.088889 | On a windy day, out of every 3 sand dunes formed, only 1 remains. Out of 5 blown-out
sand-dunes, 1 has treasure and only 2 out of 3 sand dunes formed have lucky coupons. Find
the probability that the blown-out sand dune will contain both the things. | {
"A": "2 / 25",
"B": "4 / 75",
"C": "7 / 75",
"D": "3 / 5",
"E": "4 / 45"
} | multiply(subtract(const_1, divide(1, 3)), multiply(divide(2, 3), divide(1, 5))) | divide(n4,n0)|divide(n1,n2)|divide(n1,n0)|multiply(#0,#1)|subtract(const_1,#2)|multiply(#3,#4) | probability of sand dune blown out = 2 / 3 probability that it has treasure = 1 / 5 probability that it has lucky coupon = 2 / 3 total probability = 2 / 3 * 1 / 5 * 2 / 3 = 4 / 45 answer : e | probability |
math_qa__wWEWcfQ2YndT139u | In the faculty of Reverse-Engineering, 250 second year students study numeric methods, 423 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 80% of the total? Select:
A) 515 . B) 545 . C) 618 . D) 674 . E) 666 . | <gadget id="calculator">250 + 423</gadget>
<output>673</output>
<result>D</result> | D | 674 | In the faculty of Reverse-Engineering, 250 second year students study numeric methods, 423 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 80% of the total? | {
"A": "515 .",
"B": "545 .",
"C": "618 .",
"D": "674 .",
"E": "666 ."
} | add(250, 423) | add(n0,n1)| | "answer is d : 674 solution : total number of students studying both are 423 + 250 - 134 = 539 ( subtracting the 134 since they were included in the both the other numbers already ) . so 80 % of total is 539 , so 100 % is approx . 674 ." | general |
math_qa__KInNTTpgROwgcIOL | The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is Choose the correct choice from the following answers:
A) rs . 3800 B) rs . 3900 C) rs . 4000 D) rs . 4200 E) rs . 4400 | <gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">15 * (2/5)</gadget>
<output>6</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">4_000 / 8</gadget>
<output>500</output>
<gadget id="calculator">500 * 3</gadget>
<output>1_500</output>
<gadget id="calculator">(2/5) * 500</gadget>
<output>200</output>
<gadget id="calculator">200 * 12</gadget>
<output>2_400</output>
<gadget id="calculator">1_500 + 2_400</gadget>
<output>3_900</output>
<result>B</result> | B | 3,900 | The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is | {
"A": "rs . 3800",
"B": "rs . 3900",
"C": "rs . 4000",
"D": "rs . 4200",
"E": "rs . 4400"
} | add(multiply(divide(4000, add(multiply(15, divide(4, 10)), 2)), 3), multiply(multiply(divide(4, 10), divide(4000, add(multiply(15, divide(4, 10)), 2))), 12)) | divide(n1,n0)|multiply(n2,#0)|add(n3,#1)|divide(n4,#2)|multiply(n6,#3)|multiply(#0,#3)|multiply(n5,#5)|add(#4,#6)| | "let the cost of a chair and that of a table be rs . x and rs . y respectively . then , 10 x = 4 y or y = 5 x . 2 15 x + 2 y = 4000 15 x + 2 x 5 x = 4000 2 20 x = 4000 x = 200 . so , y = 5 x 200 = 500 . 2 hence , the cost of 12 chairs and 3 tables = 12 x + 3 y = rs . ( 2400 + 1500 ) = rs . 3900 . b" | general |
math_qa__0kgCh8ITQN1HUtJ8 | Instead of multiplying a number by 2, the number is divided by 10. What is the percentage of error obtained ?
Choose one
A) 94 % B) 92 % C) 95 % D) 93 % E) 97 % | <gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 100</gadget>
<output>5</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<result>C</result> | C | 95 | Instead of multiplying a number by 2, the number is divided by 10. What is the percentage of error obtained ? | {
"A": "94 %",
"B": "92 %",
"C": "95 %",
"D": "93 %",
"E": "97 %"
} | subtract(const_100, multiply(divide(divide(10, 10), multiply(2, const_10)), const_100)) | divide(n1,n1)|multiply(n0,const_10)|divide(#0,#1)|multiply(#2,const_100)|subtract(const_100,#3) | let the number be x the right number is 2 x the wrong number is x / 10 error is ( 2 x - x / 10 ) = 19 x / 10 percentage of error is ( ( 19 x / 10 ) / 2 x ) * 100 = 95 % answer : c | general |
math_qa__GjScB4akaMzOnR3E | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 90 units raises the average to 54 units per day, what is the value of n ? Pick.
A) 30
B) 18
C) 10
D) 9
E) 7 | <gadget id="calculator">90 - 50</gadget>
<output>40</output>
<gadget id="calculator">54 - 50</gadget>
<output>4</output>
<gadget id="calculator">40 / 4</gadget>
<output>10</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<result>D</result> | D | 9 | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 90 units raises the average to 54 units per day, what is the value of n ? | {
"A": "30",
"B": "18",
"C": "10",
"D": "9",
"E": "7"
} | subtract(divide(subtract(90, 50), subtract(54, 50)), const_1) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,#1)|subtract(#2,const_1)| | "( average production for n days ) * n = ( total production for n days ) - - > 50 n = ( total production for n days ) ; ( total production for n days ) + 90 = ( average production for n + 1 days ) * ( n + 1 ) - - > 50 n + 90 = 54 * ( n + 1 ) - - > n = 9 . or as 40 extra units increased the average for n + 1 days by 4 units per day then 40 / ( n + 1 ) = 4 - - > n = 9 . answer d ." | general |
math_qa__uhnUhwQseNDbYTiS | The cash difference between the selling prices of an article at a profit of 2% and 4% is Rs 3. The ratio of two selling prices is
Choose the correct choice: A) 51 : 52 B) 52 : 53 C) 53 : 54 D) 54 : 55 E) 51 : 52 | <gadget id="calculator">100 + 2</gadget>
<output>102</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">102 / 104</gadget>
<output>51/52 = around 0.980769</output>
<result>E</result> | E | 0.980769 | The cash difference between the selling prices of an article at a profit of 2% and 4% is Rs 3. The ratio of two selling prices is | {
"A": "51 : 52",
"B": "52 : 53",
"C": "53 : 54",
"D": "54 : 55",
"E": "51 : 52"
} | divide(add(const_100, 2), add(const_100, 4)) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)| | "explanation : let the cost price of article is rs . x required ratio = ( 102 % of x ) / ( 104 % of x ) = 102 / 104 = 51 / 52 = 51 : 52 . answer : e" | gain |
math_qa__qBpjw2NmiTkYsyxn | Jose completes a piece of work in 10 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is
Choose one: A) 5 days B) 6 days C) 8 days D) 10 days E) 12 days | <gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/40) + (1/10)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<result>C</result> | C | 8 | Jose completes a piece of work in 10 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is | {
"A": "5 days",
"B": "6 days",
"C": "8 days",
"D": "10 days",
"E": "12 days"
} | inverse(add(inverse(40), inverse(10))) | inverse(n1)|inverse(n0)|add(#0,#1)|inverse(#2) | if a can complete a work in x days and b can complete the same work in y days , then , both of them together can complete the work in x y / x + y days . that is , the required no . of days = 10 × 40 / 50 = 8 days . c ) | physics |
math_qa__tUIRItOOWRcT4Cx8 | 5 men and 12 boys finish a piece of work in 4 days, 7 men and 6 boys do it in 5 days. The ratio between the efficiencies of a man and boy is? Pick:
A) 6 : 8
B) 6 : 4
C) 6 : 2
D) 6 : 5
E) 6 : 2 | <gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">48 - 30</gadget>
<output>18</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">35 - 20</gadget>
<output>15</output>
<gadget id="calculator">18 / 15</gadget>
<output>6/5 = around 1.2</output>
<result>D</result> | D | 1.2 | 5 men and 12 boys finish a piece of work in 4 days, 7 men and 6 boys do it in 5 days. The ratio between the efficiencies of a man and boy is? | {
"A": "6 : 8",
"B": "6 : 4",
"C": "6 : 2",
"D": "6 : 5",
"E": "6 : 2"
} | divide(subtract(multiply(12, 4), multiply(6, 5)), subtract(multiply(7, 5), multiply(5, 4))) | multiply(n1,n2)|multiply(n0,n4)|multiply(n0,n3)|multiply(n0,n2)|subtract(#0,#1)|subtract(#2,#3)|divide(#4,#5) | 5 m + 12 b - - - - - 4 days 7 m + 6 b - - - - - - - 5 days 20 m + 48 b = 35 m + 30 b 18 b = 15 m = > 5 m = 6 b m : b = 6 : 5 answer : d | physics |
math_qa__9JxRfZs6jGNHrlWk | The volume of the largest right circular cone that can be cut out of a cube of edge 7 cm is: Options
A) 89.8 cm ³ B) 92.5 cm ³ C) 132.8 cm ³ D) 144.5 cm ³ E) none | <gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 1</gadget>
<output>22</output>
<gadget id="calculator">1 * 22</gadget>
<output>22</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">22 * (7/2)</gadget>
<output>77</output>
<gadget id="calculator">77 * (7/2)</gadget>
<output>539/2 = around 269.5</output>
<gadget id="calculator">(539/2) * 7</gadget>
<output>3_773/2 = around 1_886.5</output>
<gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">(3_773/2) / 21</gadget>
<output>539/6 = around 89.833333</output>
<result>A</result> | A | 89.8 | The volume of the largest right circular cone that can be cut out of a cube of edge 7 cm is: | {
"A": "89.8 cm ³",
"B": "92.5 cm ³",
"C": "132.8 cm ³",
"D": "144.5 cm ³",
"E": "none"
} | divide(multiply(multiply(multiply(multiply(const_1, add(multiply(7, const_3), const_1)), divide(7, const_2)), divide(7, const_2)), 7), multiply(const_3, 7)) | divide(n0,const_2)|multiply(n0,const_3)|add(#1,const_1)|multiply(#2,const_1)|multiply(#0,#3)|multiply(#0,#4)|multiply(n0,#5)|divide(#6,#1) | sol . volume of the block = ( 10 * 5 * 2 ) cm ³ . volume of the cone carved out = [ 1 / 3 * 22 / 7 * 3 * 3 * 7 ] cm ³ = 66 cm ³ ∴ wood wasted = ( 100 - 66 ) % = 34 % . answer a | geometry |
math_qa__URF6IzdxsDcrq8aH | Two trains of length 100 meters and 200 meters are 140 meters apart. They are moving towards each other on parallel tracks, at speeds of 54 km/h and 72 km/h. After how many seconds will the trains meet? Pick one
A) 2
B) 4
C) 6
D) 8
E) 10 | <gadget id="calculator">54 + 72</gadget>
<output>126</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">126 * (5/18)</gadget>
<output>35</output>
<gadget id="calculator">140 / 35</gadget>
<output>4</output>
<result>B</result> | B | 4 | Two trains of length 100 meters and 200 meters are 140 meters apart. They are moving towards each other on parallel tracks, at speeds of 54 km/h and 72 km/h. After how many seconds will the trains meet? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | divide(140, multiply(add(54, 72), const_0_2778)) | add(n3,n4)|multiply(#0,const_0_2778)|divide(n2,#1)| | "the speeds are 54000 / 3600 = 15 m / s and 72000 / 3600 = 20 m / s the relative speed is 35 m / s . time = 140 / 35 = 4 seconds the answer is b ." | physics |
math_qa__0gTbIOuUlWrTN7ow | Two trains start simultaneously from opposite ends of a 140-km route and travel toward each other on parallel tracks. Train X, traveling at a constant rate, completes the 140-km trip in 4 hours. Train Y, travelling at a constant rate, completes the 140-km trip in 3 hours. How many kilometers had Train X traveled when it met Train Y?
Choose the correct option:
A) 60 B) 64 C) 68 D) 72 E) 76 | <gadget id="calculator">140 / 4</gadget>
<output>35</output>
<gadget id="calculator">140 / 3</gadget>
<output>140/3 = around 46.666667</output>
<gadget id="calculator">35 + (140/3)</gadget>
<output>245/3 = around 81.666667</output>
<gadget id="calculator">140 / (245/3)</gadget>
<output>12/7 = around 1.714286</output>
<gadget id="calculator">35 * (12/7)</gadget>
<output>60</output>
<result>A</result> | A | 60 | Two trains start simultaneously from opposite ends of a 140-km route and travel toward each other on parallel tracks. Train X, traveling at a constant rate, completes the 140-km trip in 4 hours. Train Y, travelling at a constant rate, completes the 140-km trip in 3 hours. How many kilometers had Train X traveled when it met Train Y? | {
"A": "60",
"B": "64",
"C": "68",
"D": "72",
"E": "76"
} | multiply(divide(140, 4), divide(140, add(divide(140, 4), divide(140, 3)))) | divide(n0,n2)|divide(n0,n4)|add(#0,#1)|divide(n0,#2)|multiply(#0,#3)| | "if the two trains cover a total distance d , then train x travels ( 3 / 7 ) * d while train y travels ( 4 / 7 ) * d . if the trains travel 140 km to the meeting point , then train x travels ( 3 / 7 ) * 140 = 60 km . the answer is a ." | physics |
math_qa__T7d9CvsIPTmg0BLa | The year next to 1991 having the same calendar as that of 1990 is – Choose the correct choice from the following options:
A) 1998
B) 2001
C) 2002
D) 2003
E) none of these | <gadget id="calculator">1_991 - 1_990</gadget>
<output>1</output>
<gadget id="calculator">1_991 + 1</gadget>
<output>1_992</output>
<result>C</result> | C | 2,002 | The year next to 1991 having the same calendar as that of 1990 is – | {
"A": "1998",
"B": "2001",
"C": "2002",
"D": "2003",
"E": "none of these"
} | add(1991, subtract(1991, 1990)) | subtract(n0,n1)|add(n0,#0) | we go on counting the odd days from 1991 onward still the sum is divisible by 7 . the number of such days are 14 upto the year 2001 . so , the calender for 1991 will be repeated in the year 2002 . answer c | general |
math_qa__yajsnG330TL68UyP | Find (7x + 6y ) / (x-2y) if x/2y = 3/2 ?
Choose the correct answer.
A) 24 B) 25 C) 26 D) 27 E) 29 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">21 + 6</gadget>
<output>27</output>
<gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">27 / 1</gadget>
<output>27</output>
<result>D</result> | D | 27 | Find (7x + 6y ) / (x-2y) if x/2y = 3/2 ? | {
"A": "24",
"B": "25",
"C": "26",
"D": "27",
"E": "29"
} | divide(add(multiply(multiply(divide(3, 2), 2), 7), 6), subtract(multiply(divide(3, 2), 2), 2)) | divide(n4,n2)|multiply(n2,#0)|multiply(n0,#1)|subtract(#1,n2)|add(n1,#2)|divide(#4,#3)| | "x / 2 y = 3 / 2 = > x = 6 y / 2 = 3 y = > ( 7 x + 6 y ) / ( x - 2 y ) = ( ( 7 * ( 3 y ) ) + 6 y ) / ( 3 y - 2 y ) = > 27 y / y = 27 answer : d" | general |
math_qa__d2vqXAebwlVzaJyU | A car was driving at 72 Km/h for 20 minutes, and then at 81 Km/h for another 40 minutes. What was its average speed? Pick one
A) 76 .
B) 77 .
C) 78 .
D) 79 .
E) 80 . | <gadget id="calculator">20 + 40</gadget>
<output>60</output>
<gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 72</gadget>
<output>24</output>
<gadget id="calculator">40 / 60</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 81</gadget>
<output>54</output>
<gadget id="calculator">24 + 54</gadget>
<output>78</output>
<gadget id="calculator">60 / 60</gadget>
<output>1</output>
<gadget id="calculator">78 / 1</gadget>
<output>78</output>
<result>A</result> | A | 76 | A car was driving at 72 Km/h for 20 minutes, and then at 81 Km/h for another 40 minutes. What was its average speed? | {
"A": "76 .",
"B": "77 .",
"C": "78 .",
"D": "79 .",
"E": "80 ."
} | divide(add(multiply(divide(20, add(20, 40)), 72), multiply(divide(40, add(20, 40)), 81)), divide(add(20, 40), const_60)) | add(n1,n3)|divide(n1,#0)|divide(n3,#0)|divide(#0,const_60)|multiply(n0,#1)|multiply(n2,#2)|add(#4,#5)|divide(#6,#3) | driving at 72 km / h for 20 minutes , distance covered = 72 * 1 / 3 = 24 km driving at 90 km / h for 40 minutes , distance covered = 81 * 2 / 3 = 54 km average speed = total distance / total time = 78 / 1 = 78 km / h answer : a | general |
math_qa__g7LoFRTT7RGZ8V5c | A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed? Choose the correct answer.
A) 33 B) 77 C) 66 D) 11 E) 99 | <gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/24) + (1/30)</gadget>
<output>3/40 = around 0.075</output>
<gadget id="calculator">(3/40) * 4</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">5 * 8</gadget>
<output>40</output>
<gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(1/40) + (3/40)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(7/10) / (1/10)</gadget>
<output>7</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<result>D</result> | D | 11 | A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed? | {
"A": "33",
"B": "77",
"C": "66",
"D": "11",
"E": "99"
} | add(divide(subtract(const_1, multiply(add(divide(const_1, 24), divide(const_1, 30)), 4)), add(divide(const_1, multiply(add(const_2, const_3), multiply(const_2, 4))), add(divide(const_1, 24), divide(const_1, 30)))), 4) | add(const_2,const_3)|divide(const_1,n0)|divide(const_1,n1)|multiply(const_2,n3)|add(#1,#2)|multiply(#0,#3)|divide(const_1,#5)|multiply(n3,#4)|add(#4,#6)|subtract(const_1,#7)|divide(#9,#8)|add(n3,#10)| | "one day work of a , b and c = 1 / 24 + 1 / 30 + 1 / 40 = 1 / 10 work done by a and b together in the last 4 days = 4 * ( 1 / 24 + 1 / 30 ) = 3 / 10 remaining work = 7 / 10 the number of days required for this initial work = 7 days . the total number of days required = 4 + 7 = 11 days . answer : d" | physics |
math_qa__ocTFAGA3Vn4zcdM8 | Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 36 meter head start. If Cristina runs at a pace of 4 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? Choose the correct option.
A) 15 seconds B) 18 seconds C) 25 seconds D) 36 seconds E) 45 seconds | <gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">36 / 1</gadget>
<output>36</output>
<result>D</result> | D | 36 | Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 36 meter head start. If Cristina runs at a pace of 4 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? | {
"A": "15 seconds",
"B": "18 seconds",
"C": "25 seconds",
"D": "36 seconds",
"E": "45 seconds"
} | divide(36, subtract(const_4, const_3)) | subtract(const_4,const_3)|divide(n0,#0) | used pluging in method say t is the time for cristina to catch up with nicky , the equation will be as under : for nicky = n = 3 * t + 36 for cristina = c = 5 * t @ t = 36 , n = 144 c = 144 right answer ans : d | physics |
math_qa__rcwKJ6ZCPEbPTjwV | What is the largest integral value of 'k' for which the quadratic equation x2 - 6x + k = 0 will have two real and distinct roots? Choose the correct choice from the following options
A) 9 B) 7 C) 3 D) 8 E) 12 | <gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<result>D</result> | D | 8 | What is the largest integral value of 'k' for which the quadratic equation x2 - 6x + k = 0 will have two real and distinct roots? | {
"A": "9",
"B": "7",
"C": "3",
"D": "8",
"E": "12"
} | subtract(divide(power(6, const_2), power(2, const_2)), const_1) | power(n1,const_2)|power(n0,const_2)|divide(#0,#1)|subtract(#2,const_1) | explanatory answer any quadratic equation will have real and distinct roots if the discriminant d > 0 the discriminant ' d ' of a quadratic equation ax 2 + bx + c = 0 is given by b 2 - 4 ac in this question , the value of d = 62 - 4 * 1 * k if d > 0 , then 36 > 4 k or k < 9 . therefore , the highest integral value that k can take is 8 . correct choice is ( d ) | general |
math_qa__m6mW5kBDuQrCWa7q | A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $20 more than that received by B, find the total amount shared by A, B and C. Choose one.
A) $ 320 B) $ 420 C) $ 720 D) $ 220 E) $ 200 | <gadget id="calculator">3 * 20</gadget>
<output>60</output>
<gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">2 * 20</gadget>
<output>40</output>
<gadget id="calculator">120 + 40</gadget>
<output>160</output>
<gadget id="calculator">160 + 20</gadget>
<output>180</output>
<gadget id="calculator">160 + 180</gadget>
<output>340</output>
<gadget id="calculator">180 * 3</gadget>
<output>540</output>
<gadget id="calculator">540 - 160</gadget>
<output>380</output>
<gadget id="calculator">340 + 380</gadget>
<output>720</output>
<result>C</result> | C | 720 | A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $20 more than that received by B, find the total amount shared by A, B and C. | {
"A": "$ 320",
"B": "$ 420",
"C": "$ 720",
"D": "$ 220",
"E": "$ 200"
} | add(add(add(multiply(multiply(const_3, 20), const_2), multiply(const_2, 20)), add(add(multiply(multiply(const_3, 20), const_2), multiply(const_2, 20)), 20)), subtract(multiply(add(add(multiply(multiply(const_3, 20), const_2), multiply(const_2, 20)), 20), const_3), add(multiply(multiply(const_3, 20), const_2), multiply(const_2, 20)))) | multiply(n0,const_3)|multiply(n0,const_2)|multiply(#0,const_2)|add(#2,#1)|add(n0,#3)|add(#3,#4)|multiply(#4,const_3)|subtract(#6,#3)|add(#5,#7)| | "a = 1 / 3 ( b + c ) = > c = 3 a - b - - - ( 1 ) b = 2 / 7 ( a + c ) = > c = 3.5 b - a - - ( b ) a - b = $ 20 a = 20 + b ( 1 ) = = = > c = 60 + 3 b - b = 2 b + 60 = = > 2 b - c = - 60 - - - ( 3 ) ( 2 ) = = = > c = 3.5 b - b - 20 = 2.5 b - 20 = = > 2.5 b - c = 20 - - - ( 4 ) from ( 4 ) and ( 3 ) 0.5 b = 80 b = $ 160 a = $ 180 c = 540 - 160 = $ 380 total amount = 180 + 160 + 380 = $ 720 answer : c" | general |
math_qa__ABodiN0HjNri17v0 | In an electric circuit, two resistors with resistances 8 ohms and 9 ohms are connected in parallel. In this case, if R is the combined resistance of these two resistors, then the reciprocal of R is equal to the sum of the reciprocals of two resistors. What is R value ?
Select: A) 17 B) 45 / 78 C) 72 / 17 D) 17 / 72 E) 72 | <gadget id="calculator">8 * 9</gadget>
<output>72</output>
<gadget id="calculator">8 + 9</gadget>
<output>17</output>
<gadget id="calculator">72 / 17</gadget>
<output>72/17 = around 4.235294</output>
<result>C</result> | C | 4.235294 | In an electric circuit, two resistors with resistances 8 ohms and 9 ohms are connected in parallel. In this case, if R is the combined resistance of these two resistors, then the reciprocal of R is equal to the sum of the reciprocals of two resistors. What is R value ? | {
"A": "17",
"B": "45 / 78",
"C": "72 / 17",
"D": "17 / 72",
"E": "72"
} | divide(multiply(8, 9), add(8, 9)) | add(n0,n1)|multiply(n0,n1)|divide(#1,#0) | the wording is a bit confusing , though basically we are told that 1 / r = 1 / 8 + 1 / 9 , from which it follows that r = 72 / 17 . answer : c . | geometry |
math_qa__gXyQOIPNFMB3TTTY | The average of runs of a cricket player of 10 innings was 35. How many runs must he make in his next innings so as to increase his average of runs by 4 ? Choose the correct choice from the following
A) 76 B) 79 C) 85 D) 87 E) 89 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">4 + 35</gadget>
<output>39</output>
<gadget id="calculator">11 * 39</gadget>
<output>429</output>
<gadget id="calculator">10 * 35</gadget>
<output>350</output>
<gadget id="calculator">429 - 350</gadget>
<output>79</output>
<result>B</result> | B | 79 | The average of runs of a cricket player of 10 innings was 35. How many runs must he make in his next innings so as to increase his average of runs by 4 ? | {
"A": "76",
"B": "79",
"C": "85",
"D": "87",
"E": "89"
} | subtract(multiply(add(10, const_1), add(4, 35)), multiply(10, 35)) | add(n0,const_1)|add(n1,n2)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "explanation : average = total runs / no . of innings = 35 so , total = average x no . of innings = 35 x 10 = 350 . now increase in avg = 4 runs . so , new avg = 35 + 4 = 39 runs total runs = new avg x new no . of innings = 39 x 11 = 429 runs made in the 11 th inning = 429 - 350 = 79 answer : b" | general |
math_qa__rson6GV2DuvskPzM | The side of a square is increased by 10% then how much % does its area increases? Select the correct option
A) 21
B) 56.25
C) 50.75
D) 42.75
E) 52.75 | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 ** 2</gadget>
<output>12_100</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">12_100 - 10_000</gadget>
<output>2_100</output>
<gadget id="calculator">2_100 * 100</gadget>
<output>210_000</output>
<gadget id="calculator">210_000 / 10_000</gadget>
<output>21</output>
<result>A</result> | A | 21 | The side of a square is increased by 10% then how much % does its area increases? | {
"A": "21",
"B": "56.25",
"C": "50.75",
"D": "42.75",
"E": "52.75"
} | divide(multiply(subtract(square_area(add(const_100, 10)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)| | "a = 100 a 2 = 10000 a = 110 a 2 = 12100 - - - - - - - - - - - - - - - - 10000 - - - - - - - - - 2100 100 - - - - - - - ? = > 21 % answer : a" | geometry |
math_qa__7AcUB3YW1H9Rj0Lh | On dividing 161 by a number, the quotient is 10 and the remainder is 1. Find the divisor. Choose the correct choice from the following
A) 12 B) 14 C) 16 D) 18 E) 22 | <gadget id="calculator">161 / 10</gadget>
<output>161/10 = around 16.1</output>
<gadget id="calculator">floor(161/10)</gadget>
<output>16</output>
<result>C</result> | C | 16 | On dividing 161 by a number, the quotient is 10 and the remainder is 1. Find the divisor. | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "22"
} | floor(divide(161, 10)) | divide(n0,n1)|floor(#0)| | "d = ( d - r ) / q = ( 161 - 1 ) / 10 = 160 / 10 = 16 c )" | general |
math_qa__FdfhoxIPE4u5BWOB | 16 boys or 24 girls can construct the wall in 6 days. the number of days that 8 boys and 6 girls Will take to construct? Select the correct option:
A) 7 days
B) 14 days
C) 6 days
D) 8 days
E) 9 days | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) / 24</gadget>
<output>1/144 = around 0.006944</output>
<gadget id="calculator">6 * (1/144)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/6) / 16</gadget>
<output>1/96 = around 0.010417</output>
<gadget id="calculator">8 * (1/96)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/24) + (1/12)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<result>D</result> | D | 8 | 16 boys or 24 girls can construct the wall in 6 days. the number of days that 8 boys and 6 girls Will take to construct? | {
"A": "7 days",
"B": "14 days",
"C": "6 days",
"D": "8 days",
"E": "9 days"
} | divide(const_1, add(multiply(6, divide(divide(const_1, 6), 24)), multiply(8, divide(divide(const_1, 6), 16)))) | divide(const_1,n2)|divide(#0,n1)|divide(#0,n0)|multiply(n4,#1)|multiply(n3,#2)|add(#3,#4)|divide(const_1,#5)| | "explanation : 16 boys = 24 girls , 1 boy = 24 / 16 girls 1 boy = 6 / 4 girls 8 boys + 6 girls = 8 ã — 6 / 4 + 12 = 12 + 6 = 18 girls 8 days to complete the work answer : option d" | physics |
math_qa__EC3jxih5W7AnTX5z | A square of side 8 cm has been made to a rectangle by combining it with a rectangle of dimensions of length 8cm and breadth 4cm. What is the perimeter of the newly formed rectangle? Choose the correct choice from the following answers.
A) 10 B) 20 C) 40 D) 60 E) 80 | <gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">2 * (12 + 8)</gadget>
<output>40</output>
<result>C</result> | C | 40 | A square of side 8 cm has been made to a rectangle by combining it with a rectangle of dimensions of length 8cm and breadth 4cm. What is the perimeter of the newly formed rectangle? | {
"A": "10",
"B": "20",
"C": "40",
"D": "60",
"E": "80"
} | rectangle_perimeter(add(8, 4), 8) | add(n0,n2)|rectangle_perimeter(n0,#0) | dimensions of newly formed rectangle , length = 8 + 4 = 12 cm breadth = 8 cm perimeter of the new rectangle = 2 x ( 12 = 8 ) = 40 cm answer : c | geometry |
math_qa__sN8kFbHVZZpvLi4P | the average of 11 numbers is 10.7 . if the average of first 6 is 10.5 and that of the last 6.00001 is 11.4 the sixth number is ? Choose the correct choice:
A) 9
B) 9.2
C) 10
D) 13.7
E) 12 | <gadget id="calculator">11.4 * 6</gadget>
<output>68.4</output>
<gadget id="calculator">10.5 * 6</gadget>
<output>63</output>
<gadget id="calculator">68.4 + 63</gadget>
<output>131.4</output>
<gadget id="calculator">11 * 10.7</gadget>
<output>117.7</output>
<gadget id="calculator">131.4 - 117.7</gadget>
<output>13.7</output>
<result>D</result> | D | 13.7 | the average of 11 numbers is 10.7 . if the average of first 6 is 10.5 and that of the last 6.00001 is 11.4 the sixth number is ? | {
"A": "9",
"B": "9.2",
"C": "10",
"D": "13.7",
"E": "12"
} | subtract(add(multiply(11.4, 6), multiply(10.5, 6)), multiply(11, 10.7)) | multiply(n2,n5)|multiply(n2,n3)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2) | explanation : 1 to 11 = 11 * 10.7 = 117.7 1 to 6 = 6 * 10.5 = 63 6 to 11 = 6 * 11.4 = 68.4 63 + 68.4 = 131.4 – 117.7 = 13.7 6 th number = 13.7 d ) | general |
math_qa__JfQd4dsgKXxIp2fU | A 425 meter long train crosses a platform in 55 seconds while it crosses a signal pole in 40 seconds. What is the length of the platform? Choose the correct choice from the following answers: A) 155.68 B) 160 C) 159.38 D) 180 E) 175 | <gadget id="calculator">425 / 40</gadget>
<output>85/8 = around 10.625</output>
<gadget id="calculator">(85/8) * 55</gadget>
<output>4_675/8 = around 584.375</output>
<gadget id="calculator">(4_675/8) - 425</gadget>
<output>1_275/8 = around 159.375</output>
<result>C</result> | C | 159.38 | A 425 meter long train crosses a platform in 55 seconds while it crosses a signal pole in 40 seconds. What is the length of the platform? | {
"A": "155.68",
"B": "160",
"C": "159.38",
"D": "180",
"E": "175"
} | subtract(multiply(divide(425, 40), 55), 425) | divide(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = [ 425 / 40 m / sec = 42.5 / 4 m / sec . let the length of the platform be x meters . then , x + 425 / 55 = 42.5 / 4 4 ( x + 425 ) = 2337.5 è x = 159.38 m . answer : c" | physics |
math_qa__9Z6NXmjAIxz9sC3K | A train running at the speed of 60 km/hr crosses a pole in 8 seconds. Find the length of the train. Choices: A) 133.33 B) 882 C) 772 D) 252 E) 121 | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 8</gadget>
<output>400/3 = around 133.333333</output>
<result>A</result> | A | 133.33 | A train running at the speed of 60 km/hr crosses a pole in 8 seconds. Find the length of the train. | {
"A": "133.33",
"B": "882",
"C": "772",
"D": "252",
"E": "121"
} | multiply(divide(multiply(60, const_1000), const_3600), 8) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 * ( 5 / 18 ) m / sec = 50 / 3 m / sec length of train ( distance ) = speed * time ( 50 / 3 ) * 8 = 133.33 meter . answer : a" | physics |
math_qa__EvguJON5Igs95STm | Annika hikes at a constant rate of 12 minutes per kilometer. She has hiked 2.75 kilometers east from the start of a hiking trail when she realizes that she has to be back at the start of the trail in 40 minutes. If Annika continues east, then turns around and retraces her path to reach the start of the trail in exactly 40 minutes, for how many kilometers total did she hike east? Options
A) 3.625
B) 3.5
C) 3
D) 3.04
E) 4 | <gadget id="calculator">40 / 12</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(10/3) - 2.75</gadget>
<output>0.583333</output>
<gadget id="calculator">0.583333 / 2</gadget>
<output>0.291666</output>
<gadget id="calculator">0.291666 + 2.75</gadget>
<output>3.041666</output>
<result>D</result> | D | 3.04 | Annika hikes at a constant rate of 12 minutes per kilometer. She has hiked 2.75 kilometers east from the start of a hiking trail when she realizes that she has to be back at the start of the trail in 40 minutes. If Annika continues east, then turns around and retraces her path to reach the start of the trail in exactly 40 minutes, for how many kilometers total did she hike east? | {
"A": "3.625",
"B": "3.5",
"C": "3",
"D": "3.04",
"E": "4"
} | add(divide(subtract(divide(40, 12), 2.75), const_2), 2.75) | divide(n2,n0)|subtract(#0,n1)|divide(#1,const_2)|add(n1,#2)| | "set up two r x t = d cases . 1 . 1 / 12 km / min x t = 2.75 from which t = 33 mins . we know total journey time now is 40 + 33 = 73 . the rate is the same ie 1 / 12 km / min . set up second r x t = d case . 1 / 12 km / min x 73 = 6.08 km now the total journey would be halved as distance would be same in each direction . 6.08 / 2 = 3.04 d ." | physics |
math_qa__9jvshQmPsQmvKSGG | Tom and Jerry enter into a partnership by investing $700 and $300 respectively. At the end of one year, they divided their profits such that a third of the profit is divided equally for the efforts they have put into the business and the remaining amount of profit is divided in the ratio of the investments they made in the business. If Tom received $800 more than Jerry did, what was the profit made by their business in that year? Choose the correct answer:
A) 3000
B) 4000
C) 5000
D) 6900
E) 6677 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">700 + 300</gadget>
<output>1_000</output>
<gadget id="calculator">(2/3) / 1_000</gadget>
<output>1/1_500 = around 0.000667</output>
<gadget id="calculator">700 * (1/1_500)</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">(1/3) / 2</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(7/15) + (1/6)</gadget>
<output>19/30 = around 0.633333</output>
<gadget id="calculator">300 * (1/1_500)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + (1/6)</gadget>
<output>11/30 = around 0.366667</output>
<gadget id="calculator">(19/30) - (11/30)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">800 / (4/15)</gadget>
<output>3_000</output>
<result>A</result> | A | 3,000 | Tom and Jerry enter into a partnership by investing $700 and $300 respectively. At the end of one year, they divided their profits such that a third of the profit is divided equally for the efforts they have put into the business and the remaining amount of profit is divided in the ratio of the investments they made in the business. If Tom received $800 more than Jerry did, what was the profit made by their business in that year? | {
"A": "3000",
"B": "4000",
"C": "5000",
"D": "6900",
"E": "6677"
} | divide(800, subtract(add(multiply(700, divide(subtract(const_1, divide(const_1, const_3)), add(700, 300))), divide(divide(const_1, const_3), const_2)), add(multiply(300, divide(subtract(const_1, divide(const_1, const_3)), add(700, 300))), divide(divide(const_1, const_3), const_2)))) | add(n0,n1)|divide(const_1,const_3)|divide(#1,const_2)|subtract(const_1,#1)|divide(#3,#0)|multiply(n0,#4)|multiply(n1,#4)|add(#2,#5)|add(#2,#6)|subtract(#7,#8)|divide(n2,#9) | say the profit was $ x . tom share = x / 6 ( half of the third ) + ( x - x / 3 ) * 0.7 jerry share = x / 6 ( half of the third ) + ( x - x / 3 ) * 0.3 thus ( x - x / 3 ) * 0.7 - ( x - x / 3 ) * 0.3 = 800 - - > x = 3000 . answer is a | general |
math_qa__AY7KNbRrLjJ1zAVc | Simplify: 0.72*0.43+0.12*0.34 Pick.
A) 0.3504 B) 0.4209 C) 0.4889 D) 0.6412 E) 0.4612 | <gadget id="calculator">0.72 * 0.43</gadget>
<output>0.3096</output>
<gadget id="calculator">0.12 * 0.34</gadget>
<output>0.0408</output>
<gadget id="calculator">0.3096 + 0.0408</gadget>
<output>0.3504</output>
<result>A</result> | A | 0.3504 | Simplify: 0.72*0.43+0.12*0.34 | {
"A": "0.3504",
"B": "0.4209",
"C": "0.4889",
"D": "0.6412",
"E": "0.4612"
} | add(multiply(0.72, 0.43), multiply(0.12, 0.34)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1) | given exp . = 0.72 * 0.43 + ( 0.12 * 0.34 ) = 0.3096 + 0.0408 = 0.3504 answer is a | general |
math_qa__yRRYtbHwYyDOE3OT | A jeep takes 8 hours to cover a distance of 280 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Choose the correct choice:
A) 28 kmph
B) 52 kmph
C) 20 kmph
D) 23 kmph
E) 65 kmph | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 8</gadget>
<output>12</output>
<gadget id="calculator">280 / 12</gadget>
<output>70/3 = around 23.333333</output>
<result>D</result> | D | 23 | A jeep takes 8 hours to cover a distance of 280 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "28 kmph",
"B": "52 kmph",
"C": "20 kmph",
"D": "23 kmph",
"E": "65 kmph"
} | divide(280, multiply(divide(3, 2), 8)) | divide(n2,n3)|multiply(n0,#0)|divide(n1,#1)| | "time = 8 distance = 280 3 / 2 of 8 hours = 8 * 3 / 2 = 12 hours required speed = 280 / 12 = 23 kmph d )" | physics |
math_qa__mMBMIpONyELBgGI7 | The simple interest on Rs. 34 for 8 months at the rate of 6 paise per rupeeper month is Select:
A) 16.32 B) 16.9 C) 12.25 D) 13.21 E) none | <gadget id="calculator">34 * 8</gadget>
<output>272</output>
<gadget id="calculator">272 * 6</gadget>
<output>1_632</output>
<gadget id="calculator">1_632 / 100</gadget>
<output>408/25 = around 16.32</output>
<result>A</result> | A | 16.32 | The simple interest on Rs. 34 for 8 months at the rate of 6 paise per rupeeper month is | {
"A": "16.32",
"B": "16.9",
"C": "12.25",
"D": "13.21",
"E": "none"
} | divide(multiply(multiply(34, 8), 6), const_100) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_100)| | "sol . s . i . = rs . [ 34 * 6 / 100 * 8 ] = rs . 16.32 answer a" | gain |
math_qa__un4ZGULq2XXw0BPZ | A swimmer can swim in still water at 4 km/h. If the speed of the water current is 2 km/h, how many hours will the swimmer take to swim against the current for 3 km? Select the correct option.
A) 1.5 B) 1.75 C) 2.0 D) 2.25 E) 2.5 | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<result>A</result> | A | 1.5 | A swimmer can swim in still water at 4 km/h. If the speed of the water current is 2 km/h, how many hours will the swimmer take to swim against the current for 3 km? | {
"A": "1.5",
"B": "1.75",
"C": "2.0",
"D": "2.25",
"E": "2.5"
} | divide(3, subtract(4, 2)) | subtract(n0,n1)|divide(n2,#0)| | "the swimmer can swim against the current at a speed of 4 - 2 = 2 km / h . the time it will take is 3 / 2 = 1.5 hours . the answer is a ." | physics |
math_qa__TG4qLGDnxmnkm54S | What sum of money put at C.I amounts in 2 years to Rs.8880 and in 3 years to Rs.9261?
Choices.
A) 8164 B) 8877 C) 2877 D) 2678 E) 1011 | <gadget id="calculator">9_261 / 8_880</gadget>
<output>3_087/2_960 = around 1.042905</output>
<gadget id="calculator">(3_087/2_960) - 1</gadget>
<output>127/2_960 = around 0.042905</output>
<gadget id="calculator">(127/2_960) + 1</gadget>
<output>3_087/2_960 = around 1.042905</output>
<gadget id="calculator">(3_087/2_960) ** 2</gadget>
<output>9_529_569/8_761_600 = around 1.087652</output>
<gadget id="calculator">8_880 / (9_529_569/8_761_600)</gadget>
<output>25_934_336_000/3_176_523 = around 8_164.378473</output>
<result>A</result> | A | 8,164 | What sum of money put at C.I amounts in 2 years to Rs.8880 and in 3 years to Rs.9261? | {
"A": "8164",
"B": "8877",
"C": "2877",
"D": "2678",
"E": "1011"
} | divide(8880, power(add(subtract(divide(9261, 8880), const_1), const_1), 2)) | divide(n3,n1)|subtract(#0,const_1)|add(#1,const_1)|power(#2,n0)|divide(n1,#3)| | "8880 - - - - 381 100 - - - - ? = > 4.29 % x * 104.29 / 100 * 104.29 / 100 = 8880 x * 1.0876 = 8880 x = 8880 / 1.0876 = > 8164.38 answer : a" | general |
math_qa__2XeZqELZrwbEyCt9 | How many seconds will a 400 metre long train take to cross a man running with a speed of 6 km/hr in the direction of the moving train if the speed of the train is 30 km/hr?
Select.
A) 25 B) 30 C) 45 D) 64 E) 60 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">30 - 6</gadget>
<output>24</output>
<gadget id="calculator">(5/18) * 24</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">400 / (20/3)</gadget>
<output>60</output>
<result>E</result> | E | 60 | How many seconds will a 400 metre long train take to cross a man running with a speed of 6 km/hr in the direction of the moving train if the speed of the train is 30 km/hr? | {
"A": "25",
"B": "30",
"C": "45",
"D": "64",
"E": "60"
} | divide(400, multiply(const_0_2778, subtract(30, 6))) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "explanation : speed of train relatively to man = ( 30 - 6 ) km / hr = 24 km / hr = ( 24 x 5 / 18 ) m / sec = 6.66 m / sec time taken to pass the man = ( 400 / 6.66 ) sec = 60 sec . answer : e" | physics |
math_qa__vJJKw0EdAGzfoHc5 | What is the maximum number of pieces of birthday cake of size 4” by 4” that can be cut from a cake 16” by 16”?
Choose the correct choice
A) 5
B) 4
C) 16
D) 20
E) 25 | <gadget id="calculator">16 * 16</gadget>
<output>256</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">256 / 16</gadget>
<output>16</output>
<result>C</result> | C | 16 | What is the maximum number of pieces of birthday cake of size 4” by 4” that can be cut from a cake 16” by 16”? | {
"A": "5",
"B": "4",
"C": "16",
"D": "20",
"E": "25"
} | divide(multiply(16, 16), multiply(4, 4)) | multiply(n2,n2)|multiply(n0,n0)|divide(#0,#1)| | "the prompt is essentially asking for the maximum number of 4 x 4 squares that can be cut from a larger 16 by 16 square . since each ' row ' and each ' column ' of the larger square can be sub - divided into 4 ' pieces ' each , we have ( 4 ) ( 4 ) = 16 total smaller squares ( at maximum ) . c" | physics |
math_qa__dZpTu5IoWKhHTdPd | A student needs 30% of the marks on a test to pass the test. If the student gets 80 marks and fails the test by 10 marks, find the maximum marks set for the test. Choose the correct choice from the following answers:
A) 240 B) 300 C) 360 D) 420 E) 480 | <gadget id="calculator">80 + 10</gadget>
<output>90</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">90 / (3/10)</gadget>
<output>300</output>
<result>B</result> | B | 300 | A student needs 30% of the marks on a test to pass the test. If the student gets 80 marks and fails the test by 10 marks, find the maximum marks set for the test. | {
"A": "240",
"B": "300",
"C": "360",
"D": "420",
"E": "480"
} | divide(add(80, 10), divide(30, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "30 % = 90 marks 1 % = 3 marks 100 % = 300 marks the answer is b ." | gain |
math_qa__xu9n8UwnfL6QAZgR | in a class , 6 students can speak gujarati , 15 can speak hindi and 6 can speak marathi . if two students can speak two languages and one student can speak all the 3 languages , then how many students are there in the class
Options.
A) 21
B) 22
C) 23
D) 24
E) 25 | <gadget id="calculator">15 + 6</gadget>
<output>21</output>
<gadget id="calculator">21 + 1</gadget>
<output>22</output>
<result>B</result> | B | 22 | in a class , 6 students can speak gujarati , 15 can speak hindi and 6 can speak marathi . if two students can speak two languages and one student can speak all the 3 languages , then how many students are there in the class | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | add(add(15, 6), const_1) | add(n0,n1)|add(#0,const_1) | n ( aubuc ) = 6 + 15 + 6 - 2 - 2 - 2 + 1 = 22 answer : b | general |
math_qa__YwIe2bWuqaHgFvUM | Jack and Jill are marathon runners. Jack can finish a marathon (41 km) in 4.5 hours and Jill can run a marathon in 4.1 hours.What is the ratio of their average running speed? (Jack: Jill) Choose the correct choice from the following options:
A) 41 / 45 B) 15 / 14 C) 4 / 5 D) 5 / 4 E) can not be determined | <gadget id="calculator">41 / 4.5</gadget>
<output>9.111111</output>
<gadget id="calculator">41 / 4.1</gadget>
<output>10</output>
<gadget id="calculator">9.111111 / 10</gadget>
<output>0.911111</output>
<result>A</result> | A | 0.911111 | Jack and Jill are marathon runners. Jack can finish a marathon (41 km) in 4.5 hours and Jill can run a marathon in 4.1 hours.What is the ratio of their average running speed? (Jack: Jill) | {
"A": "41 / 45",
"B": "15 / 14",
"C": "4 / 5",
"D": "5 / 4",
"E": "can not be determined"
} | divide(divide(41, 4.5), divide(41, 4.1)) | divide(n0,n1)|divide(n0,n2)|divide(#0,#1)| | "average speed of jack = distance / time = 41 / ( 9 / 2 ) = 82 / 9 average speed of jill = 41 / ( 4.1 ) = 10 ratio of average speed of jack to jill = ( 82 / 9 ) / 10 = 82 / 90 = 41 / 45 answer a" | physics |
math_qa__7e120xmo3idyzRe9 | If the selling price of 100 articles is equal to the cost price of 40 articles, then the loss or gain percent is: Choices
A) 25 %
B) 40 %
C) 60 %
D) 65 %
E) 50 % | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<result>C</result> | C | 60 | If the selling price of 100 articles is equal to the cost price of 40 articles, then the loss or gain percent is: | {
"A": "25 %",
"B": "40 %",
"C": "60 %",
"D": "65 %",
"E": "50 %"
} | subtract(100, 40) | subtract(n0,n1) | let c . p . of each article be re . 1 . then , c . p . of 100 articles = rs . 100 ; s . p . of 100 articles = rs . 40 . loss % = 60 / 100 * 100 = 60 % answer : c | gain |
math_qa__Uti2p5jiK44L9qbr | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 6 m, the volume of the box (in m3) is: Choose the correct choice: A) 4830 B) 5184 C) 6420 D) 8960 E) 7960 | <gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">48 - 12</gadget>
<output>36</output>
<gadget id="calculator">36 - 12</gadget>
<output>24</output>
<gadget id="calculator">36 * 24 * 6</gadget>
<output>5_184</output>
<result>B</result> | B | 5,184 | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 6 m, the volume of the box (in m3) is: | {
"A": "4830",
"B": "5184",
"C": "6420",
"D": "8960",
"E": "7960"
} | volume_rectangular_prism(subtract(48, multiply(6, const_2)), subtract(36, multiply(6, const_2)), 6) | multiply(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|volume_rectangular_prism(n2,#1,#2)| | "clearly , l = ( 48 - 12 ) m = 36 m , b = ( 36 - 12 ) m = 24 m , h = 8 m . volume of the box = ( 36 x 24 x 12 ) m 3 = 5184 m 3 . answer : option b" | geometry |
math_qa__nXHTzupPqOmgjAnO | In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 700 newborn members of the population, approximately how many would be expected to survive the first 3 months of life? Choose the correct choice from the following choices
A) 511 B) 546 C) 552 D) 562 E) 570 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">700 * (9/10)</gadget>
<output>630</output>
<gadget id="calculator">630 * (9/10)</gadget>
<output>567</output>
<gadget id="calculator">567 * (9/10)</gadget>
<output>5_103/10 = around 510.3</output>
<result>A</result> | A | 511 | In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 700 newborn members of the population, approximately how many would be expected to survive the first 3 months of life? | {
"A": "511",
"B": "546",
"C": "552",
"D": "562",
"E": "570"
} | multiply(multiply(multiply(700, subtract(1, divide(1, 10))), subtract(1, divide(1, 10))), subtract(1, divide(1, 10))) | divide(n1,n2)|subtract(n1,#0)|multiply(n3,#1)|multiply(#2,#1)|multiply(#3,#1)| | "number of newborns that can die in first month = 1 / 10 * 700 = 70 survived = 630 number of newborns that can die in second month = 1 / 10 * 630 = 63 survived = 567 number of newborns that can die in third month = 1 / 10 * 567 = 56 survived = 511 answer : a" | probability |
math_qa__E4fNW2Knj2PxyVNg | The ratio, by volume, of bleach to detergent to water in a certain solution is 2 : 40 : 100. The solution will be altered so that the ratio of bleach(B) to detergent is tripled while the ratio of detergent to water is halved. If the altered solution will contain 300 liters of water, how many liters of detergent will it contain? Choose the correct choice: A) 40 B) 60 C) 50 D) 30 E) 70 | <gadget id="calculator">300 / 100</gadget>
<output>3</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">3 * 20</gadget>
<output>60</output>
<result>B</result> | B | 60 | The ratio, by volume, of bleach to detergent to water in a certain solution is 2 : 40 : 100. The solution will be altered so that the ratio of bleach(B) to detergent is tripled while the ratio of detergent to water is halved. If the altered solution will contain 300 liters of water, how many liters of detergent will it contain? | {
"A": "40",
"B": "60",
"C": "50",
"D": "30",
"E": "70"
} | multiply(divide(300, 100), divide(40, const_2)) | divide(n3,n2)|divide(n1,const_2)|multiply(#0,#1)| | "b : d : w = 2 : 40 : 100 bnew / dnew = ( 1 / 3 ) * ( 2 / 40 ) = ( 1 / 60 ) dnew / wnew = ( 1 / 2 ) * ( 40 / 100 ) = ( 1 / 5 ) wnew = 300 dnew = wnew / 5 = 300 / 5 = 60 so , answer will be b b" | other |
math_qa__LGxzhdVsWMjk298v | Jack and Jill work at a hospital with 5 other workers. For an internal review, 2 of the 7 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen? Pick.
A) 1 / 3 B) 1 / 4 C) 1 / 21 D) 3 / 8 E) 2 / 3 | <gadget id="calculator">factorial(7)</gadget>
<output>5_040</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">2 * 120</gadget>
<output>240</output>
<gadget id="calculator">5_040 / 240</gadget>
<output>21</output>
<gadget id="calculator">1 / 21</gadget>
<output>1/21 = around 0.047619</output>
<result>C</result> | C | 0.047619 | Jack and Jill work at a hospital with 5 other workers. For an internal review, 2 of the 7 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen? | {
"A": "1 / 3",
"B": "1 / 4",
"C": "1 / 21",
"D": "3 / 8",
"E": "2 / 3"
} | inverse(divide(factorial(7), multiply(factorial(2), factorial(5)))) | factorial(n2)|factorial(n1)|factorial(n0)|multiply(#1,#2)|divide(#0,#3)|inverse(#4)| | "1 / 7 c 2 = 1 / 21 . answer : c ." | physics |
math_qa__8prm4hCcCBkqHQkS | The surface area of a sphere is same as the curved surface area of a right circular cylinder whose height and diameter are 10 cm each. The radius of the sphere is Select the correct option.
A) 3 cm B) 5 cm C) 6 cm D) 8 cm E) none | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">pi * 50</gadget>
<output>50*pi = around 157.079633</output>
<gadget id="calculator">(50*pi) * 2</gadget>
<output>100*pi = around 314.159265</output>
<gadget id="calculator">pi * 4</gadget>
<output>4*pi = around 12.566371</output>
<gadget id="calculator">(100*pi) / (4*pi)</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<result>B</result> | B | 5 | The surface area of a sphere is same as the curved surface area of a right circular cylinder whose height and diameter are 10 cm each. The radius of the sphere is | {
"A": "3 cm",
"B": "5 cm",
"C": "6 cm",
"D": "8 cm",
"E": "none"
} | sqrt(divide(multiply(multiply(const_pi, multiply(10, divide(10, const_2))), const_2), multiply(const_pi, const_4))) | divide(n0,const_2)|multiply(const_4,const_pi)|multiply(n0,#0)|multiply(#2,const_pi)|multiply(#3,const_2)|divide(#4,#1)|sqrt(#5)| | "solution 4 î r 2 = 2 î 5 x 10 â ‡ ’ r 2 = ( 5 x 10 / 2 ) â ‡ ’ 25 â ‡ ’ r = 5 cm . answer b" | geometry |
math_qa__wikkdPhbThdgHyy3 | find a number such that it exceeds 18 by 3 times the number by which it is less than 86 ? Pick one
A) 67 B) 68 C) 69 D) 70 E) 71 | <gadget id="calculator">3 * 86</gadget>
<output>258</output>
<gadget id="calculator">18 + 258</gadget>
<output>276</output>
<gadget id="calculator">276 / 4</gadget>
<output>69</output>
<result>C</result> | C | 69 | find a number such that it exceeds 18 by 3 times the number by which it is less than 86 ? | {
"A": "67",
"B": "68",
"C": "69",
"D": "70",
"E": "71"
} | divide(add(18, multiply(3, 86)), const_4) | multiply(n1,n2)|add(n0,#0)|divide(#1,const_4) | x - 18 = 3 [ 86 - x ] x = 69 answer : c | general |
math_qa__J0LKoQMreRNlBtXv | of the 3600 employees of company x , 12 / 25 are clerical . if the clerical staff were to be reduced by 1 / 4 , what percent of the total number of the remaining employees would then be clerical ? Choose the most appropriate option:
A) 40 % B) 22.2 % C) 20 % D) 12.5 % E) 11.1 % | <gadget id="calculator">3_600 * 12</gadget>
<output>43_200</output>
<gadget id="calculator">43_200 / 25</gadget>
<output>1_728</output>
<gadget id="calculator">1_728 / 4</gadget>
<output>432</output>
<gadget id="calculator">1_728 - 432</gadget>
<output>1_296</output>
<gadget id="calculator">3_600 - 432</gadget>
<output>3_168</output>
<gadget id="calculator">1_296 / 3_168</gadget>
<output>9/22 = around 0.409091</output>
<gadget id="calculator">(9/22) * 100</gadget>
<output>450/11 = around 40.909091</output>
<result>A</result> | A | 40 | of the 3600 employees of company x , 12 / 25 are clerical . if the clerical staff were to be reduced by 1 / 4 , what percent of the total number of the remaining employees would then be clerical ? | {
"A": "40 %",
"B": "22.2 %",
"C": "20 %",
"D": "12.5 %",
"E": "11.1 %"
} | multiply(divide(subtract(divide(multiply(3600, 12), 25), divide(divide(multiply(3600, 12), 25), 4)), subtract(3600, divide(divide(multiply(3600, 12), 25), 4))), const_100) | multiply(n0,n1)|divide(#0,n2)|divide(#1,n4)|subtract(#1,#2)|subtract(n0,#2)|divide(#3,#4)|multiply(#5,const_100) | let ' s see , the way i did it was 12 / 25 are clerical out of 3600 so 1728 are clerical 1728 reduced by 1 / 4 is 1728 * 1 / 4 so it reduced 432 people , so there is 1296 clerical people left but since 432 people left , it also reduced from the total of 3600 so there are 3168 people total since 1296 clerical left / 3168 people total you get ( a ) 40 % | general |
math_qa__ASiG2jlEJ8ebBKGC | For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 40 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated? Choose one: A) 12 % B) 26 % C) 29 % D) 31 % E) 60 % | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 300</gadget>
<output>75</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 200</gadget>
<output>80</output>
<gadget id="calculator">75 + 80</gadget>
<output>155</output>
<gadget id="calculator">300 + 200</gadget>
<output>500</output>
<gadget id="calculator">155 / 500</gadget>
<output>31/100 = around 0.31</output>
<gadget id="calculator">(31/100) * 100</gadget>
<output>31</output>
<result>D</result> | D | 31 | For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 40 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated? | {
"A": "12 %",
"B": "26 %",
"C": "29 %",
"D": "31 %",
"E": "60 %"
} | multiply(divide(add(multiply(divide(25, const_100), 300), multiply(divide(40, const_100), 200)), add(300, 200)), const_100) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100)| | "in the first plot 25 % of 300 seeds germinated , so 0.25 x 300 = 75 seeds germinated . in the second plot , 40 % of 200 seeds germinated , so 0.4 x 200 = 80 seeds germinated . since 75 + 80 = 155 seeds germinated out of a total of 300 + 200 = 500 seeds , the percent of seeds that germinated is ( 155 / 500 ) x 100 % , or 31 % . answer : d ." | general |
math_qa__VHYAvkeCkeHbyzS4 | An equilateral triangle T2 is formed by joining the mid points of the sides of another equilateral triangle T1. A third equilateral triangle T3 is formed by joining the mid-points of T2 and this process is continued indefinitely. If each side of T1 is 60 cm, find the sum of the perimeters of all the triangles.
Pick.
A) 180 cm
B) 220 cm
C) 240 cm
D) 270 cm
E) 360 cm | <gadget id="calculator">60 + 60 + 60</gadget>
<output>180</output>
<gadget id="calculator">180 + 180</gadget>
<output>360</output>
<result>E</result> | E | 360 | An equilateral triangle T2 is formed by joining the mid points of the sides of another equilateral triangle T1. A third equilateral triangle T3 is formed by joining the mid-points of T2 and this process is continued indefinitely. If each side of T1 is 60 cm, find the sum of the perimeters of all the triangles. | {
"A": "180 cm",
"B": "220 cm",
"C": "240 cm",
"D": "270 cm",
"E": "360 cm"
} | add(triangle_perimeter(60, 60, 60), triangle_perimeter(60, 60, 60)) | triangle_perimeter(n5,n5,n5)|add(#0,#0)| | "we have 60 for first triangle , when we join mid - points of first triangle we get the second equilateral triangle then the length of second one is 30 and continues . so we have 60 , 30,15 , . . . we have ratio = 1 / 2 , and it is gp type . sum of infinite triangle is a / 1 - r = 60 / 1 - ( 1 / 2 ) = 120 equilateral triangle perimeter is 3 a = 3 * 120 = 360 . so option e ." | geometry |
math_qa__Lf9DT0mMjTu4bvxf | In an election, candidate Douglas won 66 percent of the total vote in Counties X and Y. He won 74 percent of the vote in County X. If the ratio of people who voted in County X to County Y is 2: 1, what percent of the vote did candidate Douglas win in County Y?
Choose the correct choice from the following choices: A) 25 % B) 30 % C) 50 % D) 75 % E) 80 % | <gadget id="calculator">66 / 100</gadget>
<output>33/50 = around 0.66</output>
<gadget id="calculator">74 / 100</gadget>
<output>37/50 = around 0.74</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(37/50) * (2/3)</gadget>
<output>37/75 = around 0.493333</output>
<gadget id="calculator">(33/50) - (37/75)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/6) / (1/3)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | In an election, candidate Douglas won 66 percent of the total vote in Counties X and Y. He won 74 percent of the vote in County X. If the ratio of people who voted in County X to County Y is 2: 1, what percent of the vote did candidate Douglas win in County Y? | {
"A": "25 %",
"B": "30 %",
"C": "50 %",
"D": "75 %",
"E": "80 %"
} | multiply(divide(subtract(divide(66, const_100), multiply(divide(74, const_100), divide(2, const_3))), divide(1, const_3)), const_100) | divide(n0,const_100)|divide(n1,const_100)|divide(n2,const_3)|divide(n3,const_3)|multiply(#1,#2)|subtract(#0,#4)|divide(#5,#3)|multiply(#6,const_100) | given voters in ratio 2 : 1 let x has 200 votersy has 100 voters for x 66 % voted means 74 * 200 = 148 votes combined for xy has 300 voters and voted 66 % so total votes = 198 balance votes = 198 - 148 = 50 as y has 100 voters so 50 votes means 50 % of votes required ans c | general |
math_qa__GmgrpK9bD1q1q3pt | Amithab's average expenditure for the January to June is Rs. 4200 and he spends Rs.1200 in January and Rs.1500 in july.The average expenditure for the months of febraury to July is
Choose the correct option.
A) rs . 4250 B) rs . 4228 C) rs . 4128 D) rs . 4988 E) rs . 4192 | <gadget id="calculator">1_500 - 1_200</gadget>
<output>300</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">300 / 6</gadget>
<output>50</output>
<gadget id="calculator">4_200 + 50</gadget>
<output>4_250</output>
<result>A</result> | A | 4,250 | Amithab's average expenditure for the January to June is Rs. 4200 and he spends Rs.1200 in January and Rs.1500 in july.The average expenditure for the months of febraury to July is | {
"A": "rs . 4250",
"B": "rs . 4228",
"C": "rs . 4128",
"D": "rs . 4988",
"E": "rs . 4192"
} | add(4200, divide(subtract(1500, 1200), multiply(const_2, const_3))) | multiply(const_2,const_3)|subtract(n2,n1)|divide(#1,#0)|add(n0,#2) | amithab ' s total expenditure for jan - june = 4200 x 6 = 25200 expenditure for feb - june = 25200 - 1200 = 24000 expenditure for the months of feb - july = 24000 + 1500 = 25500 the average expenditure = { 25500 } / { 6 } = 4250 answer : a | general |
math_qa__T7hO6gM8Tq4dRAXR | A person walks from one end to the other of a 80-meter long moving walkway at a constant rate in 40 seconds, assisted by the walkway. When this person reaches the end, they reverse direction and continue walking with the same speed, but this time it takes 120 seconds because the person is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take this person to walk from one end of the walkway to the other? Choose the most appropriate option.
A) 56
B) 60
C) 64
D) 68
E) 72 | <gadget id="calculator">80 / 40</gadget>
<output>2</output>
<gadget id="calculator">80 / 120</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">2 + (2/3)</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">(8/3) / 2</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">80 / (4/3)</gadget>
<output>60</output>
<result>B</result> | B | 60 | A person walks from one end to the other of a 80-meter long moving walkway at a constant rate in 40 seconds, assisted by the walkway. When this person reaches the end, they reverse direction and continue walking with the same speed, but this time it takes 120 seconds because the person is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take this person to walk from one end of the walkway to the other? | {
"A": "56",
"B": "60",
"C": "64",
"D": "68",
"E": "72"
} | divide(80, divide(add(divide(80, 40), divide(80, 120)), const_2)) | divide(n0,n1)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)|divide(n0,#3)| | "let v be the speed of the person and let x be the speed of the walkway . 40 ( v + x ) = 80 then 120 ( v + x ) = 240 120 ( v - x ) = 80 when we add the two equations : 240 v = 320 v = 4 / 3 time = 80 / ( 4 / 3 ) = 60 seconds the answer is b ." | physics |
math_qa__2EgEt4e6aqc3VVao | neha ' s mother was 4 times her age 12 years ago . she will be twice as old as neha 12 years from now . what is the present age of neha ' s mother ?
Answers
A) 60 years B) 33 C) 77 D) 66 E) 101 | <gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">2 * 24</gadget>
<output>48</output>
<gadget id="calculator">48 - 24</gadget>
<output>24</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">4 * 12</gadget>
<output>48</output>
<gadget id="calculator">48 + 12</gadget>
<output>60</output>
<result>A</result> | A | 60 | neha ' s mother was 4 times her age 12 years ago . she will be twice as old as neha 12 years from now . what is the present age of neha ' s mother ? | {
"A": "60 years",
"B": "33",
"C": "77",
"D": "66",
"E": "101"
} | add(multiply(4, divide(subtract(multiply(const_2, add(12, 12)), add(12, 12)), subtract(4, const_2))), 12) | add(n1,n1)|subtract(n0,const_2)|multiply(#0,const_2)|subtract(#2,#0)|divide(#3,#1)|multiply(n0,#4)|add(n1,#5) | explanation : let neha ' s present age be ' x ' years . her age 12 years ago = ( x – 12 ) years therefore , her mother ' s age 12 years ago = 4 ( x – 12 ) her mother ' s present age = 4 x – 48 + 12 = 4 x – 36 neha ' s age after 12 years = x + 12 her mother ' s age after 12 years = 4 x – 36 + 12 = 4 x – 24 4 x – 24 = 2 ( x + 12 ) 4 x – 2 x = 24 + 24 x = 24 therefore , neha ' s present age = 24 her mother ' s present age = 4 x – 36 = 4 ( 24 ) – 36 = 60 years answer : a | general |
math_qa__7atExAZ9mCh3E2sh | A mathematics teacher tabulated the marks secured by 35 students of 8th class. The average of their marks was 72. If the marks secured by Reema was written as 46 instead of 96 then find the correct average marks up to two decimal places.
Answers.
A) 73.41 B) 74.31 C) 73.42 D) 73.43 E) can not be determined | <gadget id="calculator">35 * 72</gadget>
<output>2_520</output>
<gadget id="calculator">96 - 46</gadget>
<output>50</output>
<gadget id="calculator">2_520 - 50</gadget>
<output>2_470</output>
<gadget id="calculator">2_470 / 35</gadget>
<output>494/7 = around 70.571429</output>
<result>C</result> | C | 73.42 | A mathematics teacher tabulated the marks secured by 35 students of 8th class. The average of their marks was 72. If the marks secured by Reema was written as 46 instead of 96 then find the correct average marks up to two decimal places. | {
"A": "73.41",
"B": "74.31",
"C": "73.42",
"D": "73.43",
"E": "can not be determined"
} | divide(subtract(multiply(35, 72), subtract(96, 46)), 35) | multiply(n0,n2)|subtract(n4,n3)|subtract(#0,#1)|divide(#2,n0)| | "total marks = 35 x 72 = 2520 corrected total marks = 2520 - 46 + 96 = 2570 correct average = 2570 / 35 = 73.42 answer : c" | general |
math_qa__FHnS0s8AJHT1n9VC | If the sides of a triangle are 36 cm, 34 cm and 20 cm, what is its area? Choose the correct choice from the following answers.
A) 320 cm 2
B) 360 cm 2
C) 340 cm 2
D) 310 cm 2
E) 300 cm 2 | <gadget id="calculator">34 * 20</gadget>
<output>680</output>
<gadget id="calculator">680 / 2</gadget>
<output>340</output>
<result>C</result> | C | 340 | If the sides of a triangle are 36 cm, 34 cm and 20 cm, what is its area? | {
"A": "320 cm 2",
"B": "360 cm 2",
"C": "340 cm 2",
"D": "310 cm 2",
"E": "300 cm 2"
} | divide(multiply(34, 20), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 36 cm , 34 cm and 20 cm is right angled , where the hypotenuse is 36 cm . area of the triangle = 1 / 2 * 34 * 20 = 340 cm 2 answer : c" | geometry |
math_qa__k0sN9XCssTa4U9wU | A group of hikers is planning a trip that will take them up a mountain using one route and back down using another route. They plan to travel down the mountain at a rate of one and a half times the rate they will use on the way up, but the time each route will take is the same. If they will go up the mountain at a rate of 3 miles per day and it will take them two days, how many miles long is the route down the mountain? Answers
A) 7 B) 8 C) 9 D) 10 E) 11 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">6 * (3/2)</gadget>
<output>9</output>
<result>C</result> | C | 9 | A group of hikers is planning a trip that will take them up a mountain using one route and back down using another route. They plan to travel down the mountain at a rate of one and a half times the rate they will use on the way up, but the time each route will take is the same. If they will go up the mountain at a rate of 3 miles per day and it will take them two days, how many miles long is the route down the mountain? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | multiply(multiply(3, const_2), divide(const_3, const_2)) | divide(const_3,const_2)|multiply(n0,const_2)|multiply(#0,#1)| | "on the way down , the rate is 1.5 * 3 = 4.5 miles per day . the distance of the route down the mountain is 2 * 4.5 = 9 miles . the answer is c ." | physics |
math_qa__cQXs3F1NrARKcL0D | How many ounces of a 60% salt solution must be added to 70 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt?
Options
A) 16.67 B) 30 C) 50 D) 60.33 E) 70 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 70</gadget>
<output>28</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 70</gadget>
<output>14</output>
<gadget id="calculator">28 - 14</gadget>
<output>14</output>
<gadget id="calculator">(2/5) - (1/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">14 / (1/5)</gadget>
<output>70</output>
<result>E</result> | E | 70 | How many ounces of a 60% salt solution must be added to 70 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt? | {
"A": "16.67",
"B": "30",
"C": "50",
"D": "60.33",
"E": "70"
} | divide(subtract(multiply(divide(40, const_100), 70), multiply(divide(20, const_100), 70)), subtract(divide(40, const_100), divide(20, const_100))) | divide(n3,const_100)|divide(n2,const_100)|multiply(n1,#0)|multiply(n1,#1)|subtract(#0,#1)|subtract(#2,#3)|divide(#5,#4) | let x = ounces of 60 % salt solution to be added . 2 * 70 + . 6 x = . 4 ( 70 + x ) x = 70 answer e | gain |
math_qa__DSgOMmKr4dPKF0tD | How many plants will be there in a circular bed whose outer edge measure 33 cms, allowing 4 cm2 for each plant ? Choose the correct answer: A) 18 B) 750 C) 21 D) 120 E) none of these | <gadget id="calculator">2 * pi</gadget>
<output>2*pi = around 6.283185</output>
<gadget id="calculator">33 / (2*pi)</gadget>
<output>33/(2*pi) = around 5.252113</output>
<gadget id="calculator">pi * ((33/(2*pi)) ** 2)</gadget>
<output>1089/(4*pi) = around 86.659867</output>
<gadget id="calculator">(1089/(4*pi)) / 4</gadget>
<output>1089/(16*pi) = around 21.664967</output>
<result>C</result> | C | 21 | How many plants will be there in a circular bed whose outer edge measure 33 cms, allowing 4 cm2 for each plant ? | {
"A": "18",
"B": "750",
"C": "21",
"D": "120",
"E": "none of these"
} | divide(circle_area(divide(33, multiply(2, const_pi))), 4) | multiply(n2,const_pi)|divide(n0,#0)|circle_area(#1)|divide(#2,n1)| | "circumference of circular bed = 33 cm area of circular bed = ( 33 ) 2 â „ 4 ï € space for each plant = 4 cm 2 â ˆ ´ required number of plants = ( 33 ) 2 â „ 4 ï € ã · 4 = 21.65 = 21 ( approx ) answer c" | physics |
math_qa__ASo7vS2gTu5ZPUcy | Rectangle A has sides a and b, and rectangle B has sides c and d. If a/c=b/d=4/5, what is the ratio of rectangle A’s area to rectangle B’s area? Choose the correct choice: A) 5 / 4 B) 25 / 16 C) 4 / 5 D) 16 / 25 E) 16 / 5 | <gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">16 / 25</gadget>
<output>16/25 = around 0.64</output>
<result>D</result> | D | 0.64 | Rectangle A has sides a and b, and rectangle B has sides c and d. If a/c=b/d=4/5, what is the ratio of rectangle A’s area to rectangle B’s area? | {
"A": "5 / 4",
"B": "25 / 16",
"C": "4 / 5",
"D": "16 / 25",
"E": "16 / 5"
} | divide(power(4, const_2), power(5, const_2)) | power(n0,const_2)|power(n1,const_2)|divide(#0,#1)| | "the area of rectangle a is ab . c = 5 a / 4 and d = 5 b / 4 . the area of rectangle b is cd = 25 ab / 16 . the ratio of rectangle a ' s area to rectangle b ' s area is ab / ( 25 ab / 16 ) = 16 / 25 . the answer is d ." | geometry |
math_qa__gUID17f5Bn4lUcT6 | A student multiplied a number by 3/5 instead of 5/3, What is the percentage error in the calculation ? Options: A) 22 B) 64 C) 365 D) 29 E) 36 | <gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(5/3) - (3/5)</gadget>
<output>16/15 = around 1.066667</output>
<gadget id="calculator">(16/15) / (5/3)</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">(16/25) * 100</gadget>
<output>64</output>
<result>B</result> | B | 64 | A student multiplied a number by 3/5 instead of 5/3, What is the percentage error in the calculation ? | {
"A": "22",
"B": "64",
"C": "365",
"D": "29",
"E": "36"
} | multiply(divide(subtract(divide(5, 3), divide(3, 5)), divide(5, 3)), const_100) | divide(n1,n0)|divide(n0,n1)|subtract(#0,#1)|divide(#2,#0)|multiply(#3,const_100)| | "let the number be x . then , ideally he should have multiplied by x by 5 / 3 . hence correct result was . by mistake he multiplied x by 3 / 5 . hence the result with error = then , error = error % = = 64 % answer : b" | general |
math_qa__bapAYC9bRP2Do0Lk | a team of 6 entered for a shooting competition . the best marks man scored 85 points . if he had scored 92 points , the average scores for . the team would have been 84 . how many points altogether did the team score ?
Answers: A) 288 B) 497 C) 168 D) 127 E) 664 | <gadget id="calculator">84 * 6</gadget>
<output>504</output>
<gadget id="calculator">92 - 85</gadget>
<output>7</output>
<gadget id="calculator">504 - 7</gadget>
<output>497</output>
<result>B</result> | B | 497 | a team of 6 entered for a shooting competition . the best marks man scored 85 points . if he had scored 92 points , the average scores for . the team would have been 84 . how many points altogether did the team score ? | {
"A": "288",
"B": "497",
"C": "168",
"D": "127",
"E": "664"
} | subtract(multiply(84, 6), subtract(92, 85)) | multiply(n0,n3)|subtract(n2,n1)|subtract(#0,#1) | explanation : 6 * 84 = 504 - 7 = 497 answer : b | general |
math_qa__j9BqFJKlczmgiINP | If 60 percent of 500 is 50 percent of x, then x=?
Choose the correct choice from the following options
A) 600
B) 620
C) 650
D) 700
E) 720 | <gadget id="calculator">60 * 500</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 / 50</gadget>
<output>600</output>
<result>A</result> | A | 600 | If 60 percent of 500 is 50 percent of x, then x=? | {
"A": "600",
"B": "620",
"C": "650",
"D": "700",
"E": "720"
} | divide(multiply(60, 500), 50) | multiply(n0,n1)|divide(#0,n2)| | "0.6 * 500 = 0.5 * x x = 6 / 5 * 500 = 600" | general |
math_qa__JHQajcgRjf90JKTk | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 220 kilometers? Choose the correct choice from the following options
A) 4.5 B) 5.5 C) 6.5 D) 7.5 E) 8.5 | <gadget id="calculator">220 / 40</gadget>
<output>11/2 = around 5.5</output>
<result>B</result> | B | 5.5 | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 220 kilometers? | {
"A": "4.5",
"B": "5.5",
"C": "6.5",
"D": "7.5",
"E": "8.5"
} | divide(220, 40) | divide(n1,n0)| | "each 40 kilometers , 1 gallon is needed . we need to know how many 40 kilometers are there in 220 kilometers ? 220 ÷ 40 = 5.5 × 1 gallon = 5.5 gallons correct answer b" | physics |
math_qa__5bJAOL9xtfQyNwkY | the sum of 3 numbers is 98 . if the ratio between first and second be 2 : 3 and that between second and third be 5 : 8 , then the second number is ? Choose the correct choice from the following choices
A) 30
B) 20
C) 58
D) 48
E) 68 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) + 1</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">8 / 5</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(5/3) + (8/5)</gadget>
<output>49/15 = around 3.266667</output>
<gadget id="calculator">98 / (49/15)</gadget>
<output>30</output>
<result>A</result> | A | 30 | the sum of 3 numbers is 98 . if the ratio between first and second be 2 : 3 and that between second and third be 5 : 8 , then the second number is ? | {
"A": "30",
"B": "20",
"C": "58",
"D": "48",
"E": "68"
} | divide(98, add(add(divide(2, 3), const_1), divide(8, 5))) | divide(n2,n0)|divide(n5,n4)|add(#0,const_1)|add(#2,#1)|divide(n1,#3) | let the numbers be x , y and z . then , x + y + z = 98 , x / y = 2 / 3 and y / z = 5 / 8 therefore , x = 2 y / 3 and z = 8 y / 5 . so , 2 y / 3 + y + 8 y / 5 = 98 . 49 y / 15 = 98 y = 30 . answer : a | other |
math_qa__gBPn9ePatOdLv0yw | A courtyard is 25 meter long and 18 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is? Choose the correct answer
A) 22877
B) 27778
C) 20000
D) 22500
E) 17799 | <gadget id="calculator">25 * 100</gadget>
<output>2_500</output>
<gadget id="calculator">18 * 100</gadget>
<output>1_800</output>
<gadget id="calculator">2_500 * 1_800</gadget>
<output>4_500_000</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">4_500_000 / 200</gadget>
<output>22_500</output>
<result>D</result> | D | 22,500 | A courtyard is 25 meter long and 18 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is? | {
"A": "22877",
"B": "27778",
"C": "20000",
"D": "22500",
"E": "17799"
} | divide(multiply(multiply(25, const_100), multiply(18, const_100)), multiply(20, 10)) | multiply(n0,const_100)|multiply(n1,const_100)|multiply(n2,n3)|multiply(#0,#1)|divide(#3,#2)| | "number of bricks = courtyard area / 1 brick area = ( 2500 × 1800 / 20 × 10 ) = 22500 answer : d" | physics |
math_qa__98NI24XiQr34SqoW | The perimeter of one square is 24m & that of another is 32m. Perimeter of a square whose area is equal to the sum of the areas of the 2 squares will be
Choose the most appropriate option
A) 20 m
B) 24 m
C) 28 m
D) 40 m
E) 43 m | <gadget id="calculator">24 / 4</gadget>
<output>6</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">32 / 4</gadget>
<output>8</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">36 + 64</gadget>
<output>100</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<result>D</result> | D | 40 | The perimeter of one square is 24m & that of another is 32m. Perimeter of a square whose area is equal to the sum of the areas of the 2 squares will be | {
"A": "20 m",
"B": "24 m",
"C": "28 m",
"D": "40 m",
"E": "43 m"
} | multiply(const_4, sqrt(add(square_area(divide(24, const_4)), square_area(divide(32, const_4))))) | divide(n0,const_4)|divide(n1,const_4)|square_area(#0)|square_area(#1)|add(#2,#3)|sqrt(#4)|multiply(#5,const_4) | perimeter of square = 4 * side perimeter of first square = 24 m . side of first square = ∴ area of first square = perimeter of second square = 32 m . side of second square = ∴ area of second square = sum of the areas of two squares = 36 + 64 = 100 m 2 ∴ side of square = ∴ perimeter of square = 4 * 10 = 40 m . d | geometry |
math_qa__LPZa1Iq8hGHcWmra | The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 2500 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation? Select the correct option:
A) 500
B) 625
C) 1,000
D) 1,500
E) 2,500 | <gadget id="calculator">2_500 / 2</gadget>
<output>1_250</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1_250 * (1/2)</gadget>
<output>625</output>
<result>B</result> | B | 625 | The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 2500 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation? | {
"A": "500",
"B": "625",
"C": "1,000",
"D": "1,500",
"E": "2,500"
} | multiply(divide(2500, 2), divide(const_1, 2)) | divide(n8,n3)|divide(const_1,n3)|multiply(#0,#1)| | "x 13 : ( t , d , s ) y 14 : ( t , 3 d , s + 2500 mi / hour ) z 15 : ( t + 2 seconds , s , 5 d ) d = ? distance = speed * time x 13 : d = s * t x 14 : 3 d = ( s + 2500 ) * t = = = > 3 d = ts + 2500 t z 15 : 5 d = s * ( t + 2 t ) = = = > 5 d = st + 2 st = = = > 5 d - 2 st = st 3 d = 5 d - 2 st + 2500 t - 2 d = - 2 st + 2500 t 2 d = 2 st - 2500 t d = st - 1250 t x 13 : d = s * t st - 1250 t = s * t s - 1250 = s - 625 = s i got to this point and could n ' t go any further . this seems like a problem where i can set up individual d = r * t formulas and solve but it appears that ' s not the case . for future reference how would i know not to waste my time setting up this problem in the aforementioned way ? thanks ! ! ! the distance of z 15 is equal to five times the distance of x 13 ( we established that x 13 is the baseline and thus , it ' s measurements are d , s , t ) s ( t + 2 ) = 5 ( s * t ) what clues would i have to know to set up the equation in this fashion ? is it because i am better off setting two identical distances together ? st + 2 s = 5 st t + 2 = 5 t 2 = 4 t t = 1 / 2 we are looking for distance ( d = s * t ) so we need to solve for speed now that we have time . speed y 14 - speed x 13 speed = d / t 3 d / t - d / t = 2500 ( remember , t is the same because both asteroids were observed for the same amount of time ) 2 d = 2500 2 = 1250 d = s * t d = 1250 * ( 1 / 2 ) d = 625 answer : b" | physics |
math_qa__8LVChiA41eLSq0rE | Find the simple interest on the Rs. 2000 at 25/4% per annum for the period from 4th Feb 2005 to 18th April 2005 Pick
A) rs 25
B) rs 30
C) rs 35
D) rs 40
E) none of these | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">70 + 3</gadget>
<output>73</output>
<gadget id="calculator">60 * 60</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">360 + 5</gadget>
<output>365</output>
<gadget id="calculator">73 / 365</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 2_000</gadget>
<output>400</output>
<gadget id="calculator">400 * 25</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 4</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 100</gadget>
<output>25</output>
<result>A</result> | A | 25 | Find the simple interest on the Rs. 2000 at 25/4% per annum for the period from 4th Feb 2005 to 18th April 2005 | {
"A": "rs 25",
"B": "rs 30",
"C": "rs 35",
"D": "rs 40",
"E": "none of these"
} | divide(divide(multiply(multiply(divide(add(multiply(add(const_4, const_3), multiply(add(const_4, const_1), const_2)), const_3), add(divide(multiply(const_60, const_60), multiply(add(const_4, const_1), const_2)), add(const_4, const_1))), 2000), 25), const_4), const_100) | add(const_3,const_4)|add(const_1,const_4)|multiply(const_60,const_60)|multiply(#1,const_2)|divide(#2,#3)|multiply(#0,#3)|add(#5,const_3)|add(#1,#4)|divide(#6,#7)|multiply(n0,#8)|multiply(n1,#9)|divide(#10,const_4)|divide(#11,const_100) | explanation : one thing which is tricky in this question is to calculate the number of days . always remember that the day on which money is deposited is not counted while the day on which money is withdrawn is counted . so lets calculate the number of days now , time = ( 24 + 31 + 18 ) days = 73 / 365 years = 1 / 5 years p = 2000 r = 25 / 4 % s . i . = = 2000 × 254 × 5 × 100 = 25 answer : a | gain |
math_qa__VLeRdms6Hzfa2ZFz | Volume of a right circular cylinder is 6o L. If radius of cylinder is doubled, then what will be the increase in volume?
Choose the correct choice: A) 120 l B) 180 l C) 240 l D) 300 l E) 360 l | <gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">240 - 60</gadget>
<output>180</output>
<result>B</result> | B | 180 | Volume of a right circular cylinder is 6o L. If radius of cylinder is doubled, then what will be the increase in volume? | {
"A": "120 l",
"B": "180 l",
"C": "240 l",
"D": "300 l",
"E": "360 l"
} | subtract(multiply(multiply(6, const_10), const_4), multiply(6, const_10)) | multiply(n0,const_10)|multiply(#0,const_4)|subtract(#1,#0) | pi ∗ r ^ 2 ∗ h = 60 double the radius . . . . . pi ∗ ( 2 r ) ^ 2 ∗ h = pi ∗ 4 ∗ r ^ 2 ∗ h = 4 ∗ 60 = 240 important . . we are looking at the increase so 240 - 60 = 180 answer : b | geometry |
math_qa__AXmb16ID9ocS15MX | You enter a weight loss challenge game and manage to lose 10% of your body weight. For the final weigh in you are forced to wear clothes that add 2% to your weight. What percentage of weight loss is measured at the final weigh in? Choose the most appropriate option:
A) 13 % B) 8.2 % C) 9 % D) 14 % E) 12 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">1 + (1/50)</gadget>
<output>51/50 = around 1.02</output>
<gadget id="calculator">(9/10) * (51/50)</gadget>
<output>459/500 = around 0.918</output>
<gadget id="calculator">1 - (459/500)</gadget>
<output>41/500 = around 0.082</output>
<gadget id="calculator">(41/500) * 100</gadget>
<output>41/5 = around 8.2</output>
<result>B</result> | B | 8.2 | You enter a weight loss challenge game and manage to lose 10% of your body weight. For the final weigh in you are forced to wear clothes that add 2% to your weight. What percentage of weight loss is measured at the final weigh in? | {
"A": "13 %",
"B": "8.2 %",
"C": "9 %",
"D": "14 %",
"E": "12 %"
} | multiply(subtract(const_1, multiply(subtract(const_1, divide(10, const_100)), add(const_1, divide(2, const_100)))), const_100) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|subtract(const_1,#4)|multiply(#5,const_100)| | "( 100 % - 10 % ) * ( 100 % + 2 % ) = 0.90 * 1.02 = 8.2 % the weigh in records your weight loss at 8.2 % ! the answer is b" | gain |
math_qa__RbicAYrekpQD9XFf | A person was asked to state his age in years. His reply was , "Take my age 5 years hence, multiply it by 3 and subtract 3 times my age 5 years ago and you will know how old I am." What was the age of the person ?
Choose one
A) 18 B) 92 C) 27 D) 26 E) 30 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 + 15</gadget>
<output>30</output>
<result>E</result> | E | 30 | A person was asked to state his age in years. His reply was , "Take my age 5 years hence, multiply it by 3 and subtract 3 times my age 5 years ago and you will know how old I am." What was the age of the person ? | {
"A": "18",
"B": "92",
"C": "27",
"D": "26",
"E": "30"
} | add(multiply(5, 3), multiply(5, 3)) | multiply(n0,n1)|add(#0,#0)| | "explanation : let the present age of person be x years . then , 3 ( x + 5 ) - 3 ( x - 5 ) = x < = > ( 3 x + 15 ) - ( 3 x - 15 ) = x < = > x = 30 . . answer : e" | general |
math_qa__82sxBMbfxxwYXVPb | The radius of a semi circle is 6.3 cm then its perimeter is? Choose the correct choice from the following options:
A) 32.9 B) 32.4 C) 32.2 D) 32.1 E) 32.7 | <gadget id="calculator">2 * pi * 6.3</gadget>
<output>12.6*pi = around 39.584067</output>
<gadget id="calculator">(12.6*pi) / 2</gadget>
<output>6.3*pi = around 19.792034</output>
<gadget id="calculator">6.3 * 2</gadget>
<output>12.6</output>
<gadget id="calculator">(6.3*pi) + 12.6</gadget>
<output>12.6 + 6.3*pi = around 32.392034</output>
<result>B</result> | B | 32.4 | The radius of a semi circle is 6.3 cm then its perimeter is? | {
"A": "32.9",
"B": "32.4",
"C": "32.2",
"D": "32.1",
"E": "32.7"
} | add(divide(circumface(6.3), const_2), multiply(6.3, const_2)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "36 / 7 r = 6.3 = 32.4 answer : b" | physics |
math_qa__jZiSCpzM903pqIL8 | A train is 300 meter long is running at a speed of 54 km/hour. In what time will it pass a tunnel of 1200 meter length? Pick one
A) 90 seconds
B) 85 seconds
C) 40 seconds
D) 100 seconds
E) 120 seconds | <gadget id="calculator">300 + 1_200</gadget>
<output>1_500</output>
<gadget id="calculator">54 * 1_000</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 / 3_600</gadget>
<output>15</output>
<gadget id="calculator">1_500 / 15</gadget>
<output>100</output>
<result>D</result> | D | 100 | A train is 300 meter long is running at a speed of 54 km/hour. In what time will it pass a tunnel of 1200 meter length? | {
"A": "90 seconds",
"B": "85 seconds",
"C": "40 seconds",
"D": "100 seconds",
"E": "120 seconds"
} | divide(add(300, 1200), divide(multiply(54, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2) | speed = 54 km / hr = 54 * ( 5 / 18 ) m / sec = 15 m / sec total distance = 300 + 1200 = 1500 meter time = distance / speed = 1500 * ( 15 ) = 100 seconds answer : d | physics |
math_qa__8WTu846X1TpHoqvM | In a single throw of a die, what is probability of getting a number greater than 4? Choose the correct answer:
A) 2 / 3 B) 3 / 5 C) 4 / 7 D) 8 / 9 E) 1 / 3 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<result>E</result> | E | 0.333333 | In a single throw of a die, what is probability of getting a number greater than 4? | {
"A": "2 / 3",
"B": "3 / 5",
"C": "4 / 7",
"D": "8 / 9",
"E": "1 / 3"
} | divide(const_2, add(4, const_2)) | add(n0,const_2)|divide(const_2,#0)| | "e = { 5,6 } n ( e ) = 2 p ( s ) = n ( e ) / n ( s ) = 2 / 6 = 1 / 3 ans : e" | probability |
math_qa__nvVJ8XwZTdSm2hUD | A certain bag contains 60 balls — 22 white, 18 green, 8 yellow, 5 red, and 7 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?
Choose the correct choice.
A) 0.09
B) 0.15
C) 0.54
D) 0.8
E) 0.91 | <gadget id="calculator">22 + 18</gadget>
<output>40</output>
<gadget id="calculator">40 + 8</gadget>
<output>48</output>
<gadget id="calculator">48 / 60</gadget>
<output>4/5 = around 0.8</output>
<result>D</result> | D | 0.8 | A certain bag contains 60 balls — 22 white, 18 green, 8 yellow, 5 red, and 7 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple? | {
"A": "0.09",
"B": "0.15",
"C": "0.54",
"D": "0.8",
"E": "0.91"
} | divide(add(add(22, 18), 8), 60) | add(n1,n2)|add(n3,#0)|divide(#1,n0)| | "according to the stem the ball can be white , green or yellow , so the probability is ( white + green + yellow ) / ( total ) = ( 22 + 18 + 8 ) / 60 = 48 / 60 = 0.8 . answer : d ." | other |
math_qa__gUdLVAtrXWygoL01 | A 10 meter long wire is cut into two pieces. If the longer piece is then used to form a perimeter of a square, what is the probability that the area of the square will be more than 4 if the original wire was cut at an arbitrary point?
Choose the correct choice from the following options.
A) 1 / 6 B) 1 / 5 C) 3 / 10 D) 1 / 3 E) 4 / 10 | <gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2 * (1/5)</gadget>
<output>2/5 = around 0.4</output>
<result>E</result> | E | 0.4 | A 10 meter long wire is cut into two pieces. If the longer piece is then used to form a perimeter of a square, what is the probability that the area of the square will be more than 4 if the original wire was cut at an arbitrary point? | {
"A": "1 / 6",
"B": "1 / 5",
"C": "3 / 10",
"D": "1 / 3",
"E": "4 / 10"
} | multiply(const_2, divide(const_2, 10)) | divide(const_2,n0)|multiply(#0,const_2) | a square with an area of 4 has a perimeter of 8 . for the area to be > 4 , the longer piece must be > 8 . the wire must be cut within 2 meters from either end . the probability of this is 4 / 10 = 2 / 5 . the answer is e . | geometry |
math_qa__PJOYF6IVaj5EoX4q | The mean of 50 observations was 40. It was found later that an observation 45 was wrongly taken as15 The corrected new mean is Choose the correct choice from the following answers: A) 40 B) 36.5 C) 46.5 D) 20.5 E) 40.6 | <gadget id="calculator">40 * 50</gadget>
<output>2_000</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">48 - 15</gadget>
<output>33</output>
<gadget id="calculator">2_000 + 33</gadget>
<output>2_033</output>
<gadget id="calculator">2_033 / 50</gadget>
<output>2_033/50 = around 40.66</output>
<result>E</result> | E | 40.6 | The mean of 50 observations was 40. It was found later that an observation 45 was wrongly taken as15 The corrected new mean is | {
"A": "40",
"B": "36.5",
"C": "46.5",
"D": "20.5",
"E": "40.6"
} | divide(add(multiply(40, 50), subtract(subtract(50, const_2), 15)), 50) | multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,n3)|add(#0,#2)|divide(#3,n0)| | "explanation : correct sum = ( 40 * 50 + 45 - 15 ) = 2030 correct mean = = 2030 / 50 = 40.6 answer : e" | general |
math_qa__WnaRlFo7r4CE4Wlq | A money lender lent Rs. 1000 at 3% per year and Rs. 1400 at 5% per year. The amount should be returned to him when the total interest comes to Rs. 350. Find the number of years. Choices:
A) 3.5 B) 3.75 C) 4 D) 4.25 E) 4.5 | <gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 100</gadget>
<output>30</output>
<gadget id="calculator">1_400 * 5</gadget>
<output>7_000</output>
<gadget id="calculator">7_000 / 100</gadget>
<output>70</output>
<gadget id="calculator">30 + 70</gadget>
<output>100</output>
<gadget id="calculator">350 / 100</gadget>
<output>7/2 = around 3.5</output>
<result>A</result> | A | 3.5 | A money lender lent Rs. 1000 at 3% per year and Rs. 1400 at 5% per year. The amount should be returned to him when the total interest comes to Rs. 350. Find the number of years. | {
"A": "3.5",
"B": "3.75",
"C": "4",
"D": "4.25",
"E": "4.5"
} | divide(350, add(divide(multiply(3, 1000), const_100), divide(multiply(1400, 5), const_100))) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|divide(n4,#4)| | ( 1000 xtx 3 / 100 ) + ( 1400 xtx 5 / 100 ) = 350 → t = 3.5 answer a | gain |
math_qa__kUYR6ZLu6mHSHfWA | Caleb spends $70.50 on 50 hamburgers for the marching band. If single burgers cost $1.00 each and double burgers cost $1.50 each, how many double burgers did he buy? Choices
A) 5 B) 10 C) 20 D) 41 E) 45 | <gadget id="calculator">70.5 - 50</gadget>
<output>20.5</output>
<gadget id="calculator">1.5 - 1</gadget>
<output>0.5</output>
<gadget id="calculator">20.5 / 0.5</gadget>
<output>41</output>
<result>D</result> | D | 41 | Caleb spends $70.50 on 50 hamburgers for the marching band. If single burgers cost $1.00 each and double burgers cost $1.50 each, how many double burgers did he buy? | {
"A": "5",
"B": "10",
"C": "20",
"D": "41",
"E": "45"
} | divide(subtract(70.50, 50), subtract(1.50, 1.00)) | subtract(n0,n1)|subtract(n3,n2)|divide(#0,#1)| | "solution - lets say , single hamburgersxand double hamburgersy given that , x + y = 50 and 1 x + 1.5 y = 70.50 . by solving the equations y = 41 . ans d ." | general |
math_qa__XxZtWzInFpSknh6w | TOM traveled the entire 100 miles trip. If he did the first 50 miles of at a constant rate 20miles per hour and the remaining trip of at a constant rate 50 miles per hour, what is the his average speed, in miles per hour? Choices:
A) 28.36 mph B) 26.55 mph C) 28.57 mph D) 25.56 mph E) 28.45 mph | <gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 50</gadget>
<output>1</output>
<gadget id="calculator">50 / 20</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">1 + (5/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">100 / (7/2)</gadget>
<output>200/7 = around 28.571429</output>
<result>C</result> | C | 28.57 | TOM traveled the entire 100 miles trip. If he did the first 50 miles of at a constant rate 20miles per hour and the remaining trip of at a constant rate 50 miles per hour, what is the his average speed, in miles per hour? | {
"A": "28.36 mph",
"B": "26.55 mph",
"C": "28.57 mph",
"D": "25.56 mph",
"E": "28.45 mph"
} | divide(100, add(divide(50, subtract(100, 50)), divide(50, 20))) | divide(n1,n2)|subtract(n0,n1)|divide(n3,#1)|add(#2,#0)|divide(n0,#3)| | "avg speed = total distance / total time = ( d 1 + d 2 ) / ( t 1 + t 2 ) = ( 50 + 50 ) / ( ( 50 / 20 ) + ( 50 / 50 ) ) = 60 * 2 / 3 = 28.57 mph c" | physics |
math_qa__vDXHl6Q6FCDCGGSs | When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 6, the quotient is 3y and the remainder is 5. What is the value of 7y – x ? Select the correct option:
A) 2 B) 1 C) 0 D) - 1 E) - 2 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 - 5</gadget>
<output>3</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">2 * 11</gadget>
<output>22</output>
<gadget id="calculator">18 - 22</gadget>
<output>-4</output>
<gadget id="calculator">3 / (-4)</gadget>
<output>-3/4 = around -0.75</output>
<gadget id="calculator">7 * (-3/4)</gadget>
<output>-21/4 = around -5.25</output>
<gadget id="calculator">11 * (-3/4)</gadget>
<output>-33/4 = around -8.25</output>
<gadget id="calculator">(-33/4) + 4</gadget>
<output>-17/4 = around -4.25</output>
<gadget id="calculator">(-21/4) - (-17/4)</gadget>
<output>-1</output>
<result>D</result> | D | -1 | When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 6, the quotient is 3y and the remainder is 5. What is the value of 7y – x ? | {
"A": "2",
"B": "1",
"C": "0",
"D": "- 1",
"E": "- 2"
} | subtract(multiply(7, divide(subtract(multiply(2, 4), 5), subtract(multiply(6, 3), multiply(2, 11)))), add(multiply(11, divide(subtract(multiply(2, 4), 5), subtract(multiply(6, 3), multiply(2, 11)))), 4)) | multiply(n1,n2)|multiply(n3,n4)|multiply(n0,n2)|subtract(#0,n5)|subtract(#1,#2)|divide(#3,#4)|multiply(n6,#5)|multiply(n0,#5)|add(n1,#7)|subtract(#6,#8)| | "( 1 ) x = 11 y + 4 ( 2 ) 2 x = 18 y + 5 let ' s subtract equation ( 1 ) from equation ( 2 ) . 7 y + 1 = x 7 y - x = - 1 the answer is d ." | general |
math_qa__pHCc5AHUEuCay7yM | How much 60% of 50 is greater than 40% of 30?
Select the correct option:
A) 18
B) 28
C) 26
D) 27
E) 23 | <gadget id="calculator">60 * 50</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 100</gadget>
<output>30</output>
<gadget id="calculator">40 * 30</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 100</gadget>
<output>12</output>
<gadget id="calculator">30 - 12</gadget>
<output>18</output>
<result>A</result> | A | 18 | How much 60% of 50 is greater than 40% of 30? | {
"A": "18",
"B": "28",
"C": "26",
"D": "27",
"E": "23"
} | subtract(divide(multiply(60, 50), const_100), divide(multiply(40, 30), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|subtract(#2,#3)| | "( 60 / 100 ) * 50 – ( 40 / 100 ) * 30 30 - 12 = 18 answer : a" | gain |
math_qa__yyXPkOms7ZypXBXI | You and your friend spent a total of $19 for lunch. Your friend spent $3 more than you. How much did your friend spend on their lunch? Select
A) $ 9 B) $ 3 C) $ 4 D) $ 6 E) $ 11 | <gadget id="calculator">19 - 3</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<result>E</result> | E | 11 | You and your friend spent a total of $19 for lunch. Your friend spent $3 more than you. How much did your friend spend on their lunch? | {
"A": "$ 9",
"B": "$ 3",
"C": "$ 4",
"D": "$ 6",
"E": "$ 11"
} | add(divide(subtract(19, 3), const_2), 3) | subtract(n0,n1)|divide(#0,const_2)|add(n1,#1) | my lunch = l , my friends lunch = l + 3 ( l ) + ( l + 3 ) = 19 l + l + 3 - 3 = 19 - 3 2 l = 16 l = 8 my friends lunch l + 3 = 8 + 3 = $ 11 , the answer is e | general |
math_qa__7jJqXozpcgReg6L7 | By selling 90 pens, a trader gains the cost of 30 pens. Find his gain percentage?
Choices
A) 33.3 % B) 32.3 % C) 31.3 % D) 30.3 % E) 29.3 % | <gadget id="calculator">30 / 90</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>A</result> | A | 33.3 | By selling 90 pens, a trader gains the cost of 30 pens. Find his gain percentage? | {
"A": "33.3 %",
"B": "32.3 %",
"C": "31.3 %",
"D": "30.3 %",
"E": "29.3 %"
} | multiply(divide(30, 90), const_100) | divide(n1,n0)|multiply(#0,const_100)| | "let the cp of each pen be rs . 1 . cp of 90 pens = rs . 90 profit = cost of 30 pens = rs . 30 profit % = 30 / 90 * 100 = 33.3 % answer : a" | gain |
math_qa__BxXg87NQgol4OPms | A cistern is normally filled in 2 hrs,but takes 2 hrs longer to fill because of a leak on its bottom,if Cistern is full ,how much time citern would empty? Choose one:
A) 4 hours B) 20 hours C) 30 hours D) 40 hours E) 50 hours | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/2) - (1/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<result>A</result> | A | 4 | A cistern is normally filled in 2 hrs,but takes 2 hrs longer to fill because of a leak on its bottom,if Cistern is full ,how much time citern would empty? | {
"A": "4 hours",
"B": "20 hours",
"C": "30 hours",
"D": "40 hours",
"E": "50 hours"
} | inverse(subtract(divide(const_1, 2), divide(const_1, add(2, 2)))) | add(n0,n1)|divide(const_1,n0)|divide(const_1,#0)|subtract(#1,#2)|inverse(#3)| | "if leakage / hour = 1 / x , then 1 / 2 - 1 / x = 1 / 4 , solving 1 / x = 1 / 4 so in 4 hours full cistern will be empty . answer : a" | physics |
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