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stringlengths 7
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math_qa__6NS0NQewZ4D7u3TI | Effective annual rate of interest corresponding to nominal rate of 6% per annum compounded half yearly will be Pick:
A) 6.09 % B) 6.10 % C) 6.12 % D) 6.14 % E) none of these | <gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">(3/100) + 1</gadget>
<output>103/100 = around 1.03</output>
<gadget id="calculator">(103/100) ** 2</gadget>
<output>10_609/10_000 = around 1.0609</output>
<gadget id="calculator">(10_609/10_000) * 100</gadget>
<output>10_609/100 = around 106.09</output>
<gadget id="calculator">(10_609/100) - 100</gadget>
<output>609/100 = around 6.09</output>
<result>A</result> | A | 6.09 | Effective annual rate of interest corresponding to nominal rate of 6% per annum compounded half yearly will be | {
"A": "6.09 %",
"B": "6.10 %",
"C": "6.12 %",
"D": "6.14 %",
"E": "none of these"
} | subtract(multiply(power(add(divide(divide(6, const_2), const_100), const_1), const_2), const_100), const_100) | divide(n0,const_2)|divide(#0,const_100)|add(#1,const_1)|power(#2,const_2)|multiply(#3,const_100)|subtract(#4,const_100) | explanation : let the amount rs 100 for 1 year when compounded half yearly , n = 2 , rate = 6 / 2 = 3 % amount = 100 ( 1 + 3 / 100 ) 2 = 106.09 effective rate = ( 106.09 - 100 ) % = 6.09 % option a | gain |
math_qa__388DXDj0hc65iLvI | The average age of 3 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is
Choose one: A) 22 B) 30 C) 25 D) 38 E) 27 | <gadget id="calculator">21 + 23</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<gadget id="calculator">1 * 3</gadget>
<output>3</output>
<gadget id="calculator">22 + 3</gadget>
<output>25</output>
<result>C</result> | C | 25 | The average age of 3 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is | {
"A": "22",
"B": "30",
"C": "25",
"D": "38",
"E": "27"
} | add(divide(add(21, 23), const_2), multiply(const_1, 3)) | add(n1,n2)|multiply(n0,const_1)|divide(#0,const_2)|add(#2,#1)| | "total age increased = ( 3 * 2 ) years = 6 years . sum of ages of two new men = ( 21 + 23 + 6 ) years = 50 years average age of two new men = ( 50 / 2 ) years = 25 years . answer : c" | general |
math_qa__PizsFtDUkutAtLQ4 | Points A, B, and, C have xy-coordinates (2,0), (8,12), and (14,0), respectively. Points X, Y, and Z have xy-coordinates (6,0), (8,4), and (10,0), respectively. What fraction S of the area of triangle ABC is the area of triangle XYZ?
Answers
A) 1 / 9 B) 1 / 8 C) 1 / 6 D) 1 / 5 E) 1 / 3 | <gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">144 / 2</gadget>
<output>72</output>
<gadget id="calculator">8 / 72</gadget>
<output>1/9 = around 0.111111</output>
<result>A</result> | A | 0.111111 | Points A, B, and, C have xy-coordinates (2,0), (8,12), and (14,0), respectively. Points X, Y, and Z have xy-coordinates (6,0), (8,4), and (10,0), respectively. What fraction S of the area of triangle ABC is the area of triangle XYZ? | {
"A": "1 / 9",
"B": "1 / 8",
"C": "1 / 6",
"D": "1 / 5",
"E": "1 / 3"
} | divide(divide(power(const_4, const_2), const_2), divide(power(add(const_10, const_2), const_2), const_2)) | add(const_10,const_2)|power(const_4,const_2)|divide(#1,const_2)|power(#0,const_2)|divide(#3,const_2)|divide(#2,#4)| | "if you notice , both triangles abc and xyz have a side on x axis . we can take these sides as bases for each triangle , therefore area of abc is 1 / 2 * 12 * 12 ( height of abc is the y coordinate of the third point ( 8,12 ) ) similarly area of xyz is 1 / 2 * 4 * 4 dividing area of xyz with that of abc gives s = 1 / 9 . a" | geometry |
math_qa__nW8iy4hRVjcV75w4 | A van takes 6 hours to cover a distance of 270 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Choose the correct choice from the following answers:
A) 50 kmph
B) 30 kmph
C) 70 kmph
D) 80 kmph
E) 90 kmph | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 6</gadget>
<output>9</output>
<gadget id="calculator">270 / 9</gadget>
<output>30</output>
<result>B</result> | B | 30 | A van takes 6 hours to cover a distance of 270 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "50 kmph",
"B": "30 kmph",
"C": "70 kmph",
"D": "80 kmph",
"E": "90 kmph"
} | divide(270, multiply(divide(3, 2), 6)) | divide(n2,n3)|multiply(n0,#0)|divide(n1,#1)| | "time = 6 distence = 270 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 270 / 9 = 30 kmph b" | physics |
math_qa__Gb9qHkJeQmSlxQDV | Working together, printer A and printer B would finish the task in 40 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 4 pages a minute more than printer A ?
Choose the most appropriate option
A) 250 B) 375 C) 450 D) 480 E) 500 | <gadget id="calculator">60 / 40</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 / (1/2)</gadget>
<output>8</output>
<gadget id="calculator">8 * 60</gadget>
<output>480</output>
<result>D</result> | D | 480 | Working together, printer A and printer B would finish the task in 40 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 4 pages a minute more than printer A ? | {
"A": "250",
"B": "375",
"C": "450",
"D": "480",
"E": "500"
} | multiply(divide(4, subtract(divide(60, 40), const_1)), const_60) | divide(n1,n0)|subtract(#0,const_1)|divide(n2,#1)|multiply(#2,const_60) | 40 * a + 40 * b = x pages in 40 mins printer a will print = 40 / 60 * x pages = 2 / 3 * x pages thus in 40 mins printer printer b will print x - 2 / 3 * x = 1 / 3 * x pages also it is given that printer b prints 4 more pages per min that printer a . in 40 mins printer b will print 160 more pages than printer a thus 2 / 3 * x - 1 / 3 * x = 160 = > x = 480 pages answer : d | physics |
math_qa__o8kHTmxK7bqo2Uzu | If 36 men do a work in 70 days, in how many days will 40 men do it? Choose the correct choice: A) 64 B) 63 C) 65 D) 66 E) 67 | <gadget id="calculator">36 * 70</gadget>
<output>2_520</output>
<gadget id="calculator">2_520 / 40</gadget>
<output>63</output>
<result>B</result> | B | 63 | If 36 men do a work in 70 days, in how many days will 40 men do it? | {
"A": "64",
"B": "63",
"C": "65",
"D": "66",
"E": "67"
} | divide(multiply(36, 70), 40) | multiply(n0,n1)|divide(#0,n2)| | "36 * 70 = 40 * x x = 63 days answer : b" | physics |
math_qa__ZZtkxJjCG2q1sKkz | Last year, for every 100 million vehicles that traveled on a certain highway, 75 vehicles were involved in accidents. If 6 billion vehicles traveled on the highway last year, how many of those vehicles were involved in accidents? (1 billion = 1,000,000,000) Choices
A) 2500
B) 4500
C) 3500
D) 4000
E) 1300 | <gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">75 * 60</gadget>
<output>4_500</output>
<result>B</result> | B | 4,500 | Last year, for every 100 million vehicles that traveled on a certain highway, 75 vehicles were involved in accidents. If 6 billion vehicles traveled on the highway last year, how many of those vehicles were involved in accidents? (1 billion = 1,000,000,000) | {
"A": "2500",
"B": "4500",
"C": "3500",
"D": "4000",
"E": "1300"
} | multiply(75, multiply(6, const_10)) | multiply(n2,const_10)|multiply(n1,#0)| | "to solve we will set up a proportion . we know that “ 100 million vehicles is to 75 accidents as 6 billion vehicles is to x accidents ” . to express everything in terms of “ millions ” , we can use 6,000 million rather than 6 billion . creating a proportion we have : 100 / 75 = 6,000 / x cross multiplying gives us : 100 x = 6,000 * 75 x = 60 * 75 = 4500 answer : b" | general |
math_qa__STkvVAnk0T1udSqt | On a certain road, 10% of the motorists exceed the posted speed limit and receive speeding tickets, but 60% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit? Choose the correct choice from the following
A) 10.5 % B) 12.5 % C) 15 % D) 25 % E) 30 % | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">10 / 40</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>D</result> | D | 25 | On a certain road, 10% of the motorists exceed the posted speed limit and receive speeding tickets, but 60% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit? | {
"A": "10.5 %",
"B": "12.5 %",
"C": "15 %",
"D": "25 %",
"E": "30 %"
} | multiply(divide(10, subtract(const_100, 60)), const_100) | subtract(const_100,n1)|divide(n0,#0)|multiply(#1,const_100)| | "suppose there are x motorists . 10 % of them exceeded the speed limit and received the ticket , i . e . x / 10 . again , suppose total no . of motorists who exceeded the speed limit are y . 60 % of y exceeded the speed limit but did n ' t received the ticket , i . e . 3 y / 5 . it means 2 y / 5 received the ticket . hence , 2 y / 5 = x / 10 or y / x = 1 / 4 or y / x * 100 = 1 / 4 * 100 = 25 % d" | gain |
math_qa__IAI5Q9mHHeDlejcS | A and B can do a piece of work in 48 days, A and C can do it in 60 days, b and c can do it 72 days. In what time can c alone do it?
Choices: A) 84 days B) 84 ½ days C) 85 days D) 87 days E) 89 days | <gadget id="calculator">72 - 48</gadget>
<output>24</output>
<gadget id="calculator">24 + 60</gadget>
<output>84</output>
<result>C</result> | C | 85 | A and B can do a piece of work in 48 days, A and C can do it in 60 days, b and c can do it 72 days. In what time can c alone do it? | {
"A": "84 days",
"B": "84 ½ days",
"C": "85 days",
"D": "87 days",
"E": "89 days"
} | add(subtract(72, 48), 60) | subtract(n2,n0)|add(n1,#0) | explanation : ( a + b ) 1 day work = 1 / 48 ( b + c ) 1 day work = 1 / 72 ( a + c ) 1 day work = 1 / 60 by adding 2 ( a + b + c ) = 1 / 48 + 1 / 72 + 1 / 60 = 37 / 720 ( a + b + c ) 1 day work = 37 / 1440 a 1 day work = 37 / 1440 – 1 / 72 = 17 / 1440 = 85 days ( approximately ) answer : option c | physics |
math_qa__Fdxc9O68ZIuzdkEh | If x is an integer such that 1 < x < 9, 2 < x < 15, 7 > x > –1, 4 > x > 0, and x + 1 < 5, then x is Choose the correct option.
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<result>A</result> | A | 3 | If x is an integer such that 1 < x < 9, 2 < x < 15, 7 > x > –1, 4 > x > 0, and x + 1 < 5, then x is | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | subtract(subtract(5, 1), 1) | subtract(n9,n8)|subtract(#0,n8)| | "1 < x < 9 , 2 < x < 15 , - 1 < x < 7 0 < x < 4 x + 1 < 5 from above : 2 < x < 4 - - > x = 3 . answer : a ." | general |
math_qa__WMiCbsGCH29r6691 | A train 300 m long can cross an electric pole in 10 sec and then find the speed of the train?
Choose the correct choice from the following choices
A) 88 kmph B) 89 kmph C) 72 kmph D) 16 kmph E) 108 kmph | <gadget id="calculator">300 / 1_000</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">10 / 3_600</gadget>
<output>1/360 = around 0.002778</output>
<gadget id="calculator">(3/10) / (1/360)</gadget>
<output>108</output>
<result>E</result> | E | 108 | A train 300 m long can cross an electric pole in 10 sec and then find the speed of the train? | {
"A": "88 kmph",
"B": "89 kmph",
"C": "72 kmph",
"D": "16 kmph",
"E": "108 kmph"
} | divide(divide(300, const_1000), divide(10, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 300 / 10 s = 30 m / sec speed = 30 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 108 kmph answer : e" | physics |
math_qa__3sPMNSQdOrXmSlmy | The average of marks obtained by 120candidates was 35. If the avg of marks of passed candidates was 39 & that of failed candidates was 39 and that of failed candidates was 15, the no.of candidateswho passed the examination is?
Select the correct option.
A) 50 B) 90 C) 100 D) 120 E) 140 | <gadget id="calculator">120 * 35</gadget>
<output>4_200</output>
<gadget id="calculator">120 * 15</gadget>
<output>1_800</output>
<gadget id="calculator">4_200 - 1_800</gadget>
<output>2_400</output>
<gadget id="calculator">39 - 15</gadget>
<output>24</output>
<gadget id="calculator">2_400 / 24</gadget>
<output>100</output>
<result>C</result> | C | 100 | The average of marks obtained by 120candidates was 35. If the avg of marks of passed candidates was 39 & that of failed candidates was 39 and that of failed candidates was 15, the no.of candidateswho passed the examination is? | {
"A": "50",
"B": "90",
"C": "100",
"D": "120",
"E": "140"
} | divide(subtract(multiply(120, 35), multiply(120, 15)), subtract(39, 15)) | multiply(n0,n1)|multiply(n0,n4)|subtract(n2,n4)|subtract(#0,#1)|divide(#3,#2)| | "let the number of candidate who passed = y then , 39 y + 15 ( 120 - y ) = 120 x 35 ⇒ 24 y = 4200 - 1800 ∴ y = 2400 / 24 = 100 c" | general |
math_qa__AIzjppo1VLcizMTL | A squirrel runs up a cylindrical post , in a perfect spiral path making one circuit for each rise of 4 feet . How many feet does the squirrel travels if the post is 16 feet tall and 2 feet in circumference?
Choose one:
A) 10 feet B) 8 feet C) 13 feet D) 15 feet E) 18 feet | <gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<result>B</result> | B | 8 | A squirrel runs up a cylindrical post , in a perfect spiral path making one circuit for each rise of 4 feet . How many feet does the squirrel travels if the post is 16 feet tall and 2 feet in circumference? | {
"A": "10 feet",
"B": "8 feet",
"C": "13 feet",
"D": "15 feet",
"E": "18 feet"
} | multiply(divide(16, 4), 2) | divide(n1,n0)|multiply(n2,#0)| | "total circuit = 16 / 4 = 4 total feet squirrel travels = 4 * 2 = 8 feet answer : b" | geometry |
math_qa__NEp1YmdswcGjg26Q | What will be the cost of building a fence around a rectangular plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 50? Answers
A) rs . 3944 B) rs . 3948 C) rs . 3519.5 D) rs . 3949 E) rs . 3923 | <gadget id="calculator">289 ** (1/2)</gadget>
<output>17</output>
<gadget id="calculator">4 * 17</gadget>
<output>68</output>
<gadget id="calculator">68 * 50</gadget>
<output>3_400</output>
<result>C</result> | C | 3,519.5 | What will be the cost of building a fence around a rectangular plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 50? | {
"A": "rs . 3944",
"B": "rs . 3948",
"C": "rs . 3519.5",
"D": "rs . 3949",
"E": "rs . 3923"
} | multiply(square_perimeter(sqrt(289)), 50) | sqrt(n0)|square_perimeter(#0)|multiply(n1,#1) | let the side of the rectangle plot be a ft . a * b = 289 = > 1.7 b * b = 289 b = 13.03 a = 22.17 length of the fence = perimeter of the plot = 2 ( a + b ) = 70.39 ft . cost of building the fence = 70.39 * 50 = rs . 3519.5 answer : c | geometry |
math_qa__N1yFQ9oqS8iasb5c | . In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 70 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ?
Choose the correct answer: A) 50 % B) 53 % C) 54 % D) 55 % E) 57 % | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">60 * (7/10)</gadget>
<output>42</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">40 * (1/5)</gadget>
<output>8</output>
<gadget id="calculator">42 + 8</gadget>
<output>50</output>
<result>A</result> | A | 50 | . In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 70 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ? | {
"A": "50 %",
"B": "53 %",
"C": "54 %",
"D": "55 %",
"E": "57 %"
} | add(multiply(60, divide(70, const_100)), multiply(subtract(const_100, 60), divide(20, const_100))) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_100,n0)|multiply(n0,#0)|multiply(#1,#2)|add(#3,#4) | registered voters = 100 d = 60 r = 40 70 % of d ( 60 ) = 42 20 % of r ( 40 ) = 8 total voter % of registered voters = 50 / 100 50 % ans a | gain |
math_qa__cjM7ESz75o8ZplS3 | In a market, a dozen eggs cost as much as a pound of rice, and a half-liter of kerosene costs as much as 8 eggs. If the cost of each pound of rice is $0.33, then how many F cents does a liter of kerosene cost? [One dollar has 100 cents.] Select: A) 0.33 B) 0.44 C) 0.55 D) 44 E) 55 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">8 / (1/2)</gadget>
<output>16</output>
<gadget id="calculator">16 / 12</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">0.33 * 100</gadget>
<output>33</output>
<gadget id="calculator">(4/3) * 33</gadget>
<output>44</output>
<result>D</result> | D | 44 | In a market, a dozen eggs cost as much as a pound of rice, and a half-liter of kerosene costs as much as 8 eggs. If the cost of each pound of rice is $0.33, then how many F cents does a liter of kerosene cost? [One dollar has 100 cents.] | {
"A": "0.33",
"B": "0.44",
"C": "0.55",
"D": "44",
"E": "55"
} | multiply(divide(divide(8, divide(const_1, const_2)), const_12), multiply(0.33, 100)) | divide(const_1,const_2)|multiply(n1,n2)|divide(n0,#0)|divide(#2,const_12)|multiply(#3,#1)| | "main thing to remember is answer is asked in cents , however when we calculate , it comes up as 0.44 $ just multiply by 100 , answer f = 44 . d" | general |
math_qa__3QfqSHnonwIQMfFG | Paulson spends 75% of his income. His income is increased by 20% and he increased his expenditure by 10%.Find the percentage increase in his savings Choose the most appropriate option:
A) 30 % B) 35 % C) 40 % D) 45 % E) 50 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(11/10) * (3/4)</gadget>
<output>33/40 = around 0.825</output>
<gadget id="calculator">(6/5) - (33/40)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(3/8) - (1/4)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) / (1/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>E</result> | E | 50 | Paulson spends 75% of his income. His income is increased by 20% and he increased his expenditure by 10%.Find the percentage increase in his savings | {
"A": "30 %",
"B": "35 %",
"C": "40 %",
"D": "45 %",
"E": "50 %"
} | multiply(divide(subtract(subtract(add(const_1, divide(20, const_100)), multiply(add(const_1, divide(10, const_100)), divide(75, const_100))), subtract(const_1, divide(75, const_100))), subtract(const_1, divide(75, const_100))), const_100) | divide(n1,const_100)|divide(n2,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|subtract(const_1,#2)|multiply(#4,#2)|subtract(#3,#6)|subtract(#7,#5)|divide(#8,#5)|multiply(#9,const_100)| | "let the original income = rs . 100 . then , expenditure = rs . 75 and savings = rs . 25 new income = rs . 120 , new expenditure = rs . ( ( 110 / 100 ) * 75 ) = rs . 165 / 2 new savings = rs . ( 120 - ( 165 / 2 ) ) = rs . 75 / 2 increase in savings = rs . ( ( 75 / 2 ) - 25 ) = rs . 25 / 2 increase % = ( ( 25 / 2 ) * ( 1 / 25 ) * 100 ) % = 50 % . answer e 50 %" | general |
math_qa__584y2S8PeUIzcVjY | In a college, the ratio of the number of boys to girls is 8 : 5. If there are 160 girls, the total number of students in the college is
Choose the correct choice from the following answers:
A) 2447 B) 377 C) 667 D) 416 E) 871 | <gadget id="calculator">160 / 5</gadget>
<output>32</output>
<gadget id="calculator">32 * 8</gadget>
<output>256</output>
<gadget id="calculator">160 + 256</gadget>
<output>416</output>
<result>D</result> | D | 416 | In a college, the ratio of the number of boys to girls is 8 : 5. If there are 160 girls, the total number of students in the college is | {
"A": "2447",
"B": "377",
"C": "667",
"D": "416",
"E": "871"
} | add(160, multiply(divide(160, 5), 8)) | divide(n2,n1)|multiply(n0,#0)|add(n2,#1)| | "explanation : let the number of boys and girls be 8 x and 5 x . total number of students = 13 x = 13 * 32 = 416 . answer : d" | other |
math_qa__Ixu8MURZ9jZOb9ay | The average weight of 5 students decreases by 12 kg when one of them weighing 72 kg is replaced by a new student. The weight of the student is Options.
A) 12 kg B) 10 kg C) 20 kg D) 72 kg E) none of these | <gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">72 - 60</gadget>
<output>12</output>
<result>A</result> | A | 12 | The average weight of 5 students decreases by 12 kg when one of them weighing 72 kg is replaced by a new student. The weight of the student is | {
"A": "12 kg",
"B": "10 kg",
"C": "20 kg",
"D": "72 kg",
"E": "none of these"
} | subtract(72, multiply(5, 12)) | multiply(n0,n1)|subtract(n2,#0)| | "explanation : let the weight of student be x kg . given , difference in average weight = 12 kg = > ( 72 - x ) / 5 = 12 = > x = 12 answer : a" | general |
math_qa__QnXPT1q1awdPgAga | find the least multiple of 23 , which when divided by 1821 and 24 leaves remainders 710 and 13 respectively . Choose the correct answer.
A) 3002 B) 3013 C) 3024 D) 3036 E) none of these | <gadget id="calculator">24 * 10</gadget>
<output>240</output>
<gadget id="calculator">240 + 240</gadget>
<output>480</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">480 + 24</gadget>
<output>504</output>
<gadget id="calculator">13 - 10</gadget>
<output>3</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">504 * 6</gadget>
<output>3_024</output>
<result>B</result> | B | 3,013 | find the least multiple of 23 , which when divided by 1821 and 24 leaves remainders 710 and 13 respectively . | {
"A": "3002",
"B": "3013",
"C": "3024",
"D": "3036",
"E": "none of these"
} | multiply(add(add(multiply(24, const_10), multiply(24, const_10)), multiply(add(const_4, const_4), const_3)), add(subtract(13, const_10), const_3)) | add(const_4,const_4)|multiply(n2,const_10)|subtract(n4,const_10)|add(#1,#1)|add(#2,const_3)|multiply(#0,const_3)|add(#3,#5)|multiply(#6,#4) | solution here ( 18 - 7 ) = 11 , ( 21 - 10 ) = 11 and ( 24 - 13 ) = 11 . l . c . m . of 1821 and 24 is 504 . let required number be 504 k - 11 . least value of k for which ( 504 k - 11 ) is divisible 23 is k = 6 . so , required number = 504 × 6 - 11 = 3024 - 11 = 3013 . answer b | general |
math_qa__4a6qUdLtn2VT0u4j | A boy is travelling from his home to school at 5 km/hr and reached 7 min late. Next day he traveled at 10 km/hr and reached 8 min early. Distance between home and school? Choose the correct choice from the following answers:
A) 2.5 km
B) 3.5 km
C) 4.5 km
D) 5.5 km
E) 6.5 km | <gadget id="calculator">7 / 60</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">8 / 60</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(7/60) + (2/15)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/4) / (1/10)</gadget>
<output>5/2 = around 2.5</output>
<result>A</result> | A | 2.5 | A boy is travelling from his home to school at 5 km/hr and reached 7 min late. Next day he traveled at 10 km/hr and reached 8 min early. Distance between home and school? | {
"A": "2.5 km",
"B": "3.5 km",
"C": "4.5 km",
"D": "5.5 km",
"E": "6.5 km"
} | divide(add(divide(7, const_60), divide(8, const_60)), divide(const_1, 10)) | divide(n1,const_60)|divide(n3,const_60)|divide(const_1,n2)|add(#0,#1)|divide(#3,#2) | let the distance be x t 1 = x / 5 hr t 2 = x / 10 hr difference in time = 7 + 8 = 15 = 1 / 4 hr x / 5 - x / 10 = 1 / 4 x / 10 = 1 / 4 x = 2.5 km answer is a | physics |
math_qa__P6SxPdyD000vmhS3 | A pipe can fill a cistern in 77 minutes. Find the time in which 1/11 part of the cistern will be filled? Choose one:
A) 5 min
B) 2 min
C) 3 min
D) 1 min
E) 7 min | <gadget id="calculator">1 / 11</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">77 * (1/11)</gadget>
<output>7</output>
<result>E</result> | E | 7 | A pipe can fill a cistern in 77 minutes. Find the time in which 1/11 part of the cistern will be filled? | {
"A": "5 min",
"B": "2 min",
"C": "3 min",
"D": "1 min",
"E": "7 min"
} | multiply(77, divide(1, 11)) | divide(n1,n2)|multiply(n0,#0)| | "full cistern filled in = 77 minutes 1 / 11 part filled in = 77 * 1 / 11 = 7 minutes answer is e" | physics |
math_qa__KihYZXXO1RN8avb3 | A can do a job in 10days and B in 20days. If they work on it together for 4 days, then the fraction of the work that is left is?
Pick one:
A) 2 / 5
B) 8 / 15
C) 3 / 11
D) 1 / 12
E) 6 / 13 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/10) + (1/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">4 * (3/20)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<result>A</result> | A | 0.4 | A can do a job in 10days and B in 20days. If they work on it together for 4 days, then the fraction of the work that is left is? | {
"A": "2 / 5",
"B": "8 / 15",
"C": "3 / 11",
"D": "1 / 12",
"E": "6 / 13"
} | subtract(const_1, multiply(4, add(divide(const_1, 10), divide(const_1, 20)))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)| | "a ' s 1 day work = 1 / 10 b ' s 1 day work = 1 / 20 a + b 1 day work = 1 / 10 + 1 / 20 = 3 / 20 a + b 4 days work = 3 / 20 * 4 = 3 / 5 remaining work = 1 - 3 / 5 = 2 / 5 answer is a" | physics |
math_qa__I91D2avAKGd2z2LP | Sahil purchased a machine at Rs 10000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it. Pick
A) rs . 22000
B) rs . 24000
C) rs . 26000
D) rs . 28000
E) none of these | <gadget id="calculator">10_000 + 5_000</gadget>
<output>15_000</output>
<gadget id="calculator">15_000 + 1_000</gadget>
<output>16_000</output>
<gadget id="calculator">16_000 / 100</gadget>
<output>160</output>
<gadget id="calculator">160 * 50</gadget>
<output>8_000</output>
<gadget id="calculator">16_000 + 8_000</gadget>
<output>24_000</output>
<result>B</result> | B | 24,000 | Sahil purchased a machine at Rs 10000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it. | {
"A": "rs . 22000",
"B": "rs . 24000",
"C": "rs . 26000",
"D": "rs . 28000",
"E": "none of these"
} | add(add(add(10000, 5000), 1000), multiply(divide(add(add(10000, 5000), 1000), const_100), 50)) | add(n0,n1)|add(n2,#0)|divide(#1,const_100)|multiply(n3,#2)|add(#1,#3)| | "explanation : question seems a bit tricky , but it is very simple . just calculate all cost price , then get 150 % of cp . c . p . = 10000 + 5000 + 1000 = 16000 150 % of 16000 = 150 / 100 * 16000 = 24000 option b" | gain |
math_qa__zddnMa8qlrrgXcOC | Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 38 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:18, at what time will they be reading the same page? Select:
A) 7 : 48 B) 8 : 18 C) 8 : 48 D) 9 : 18 E) 9 : 48 | <gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">18 - 30</gadget>
<output>-12</output>
<gadget id="calculator">(-12) / 60</gadget>
<output>-1/5 = around -0.2</output>
<gadget id="calculator">1 + (-1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 30</gadget>
<output>24</output>
<gadget id="calculator">38 - 30</gadget>
<output>8</output>
<gadget id="calculator">24 / 8</gadget>
<output>3</output>
<gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">8 / 18</gadget>
<output>4/9 = around 0.444444</output>
<result>B</result> | B | 0.444444 | Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 38 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:18, at what time will they be reading the same page? | {
"A": "7 : 48",
"B": "8 : 18",
"C": "8 : 48",
"D": "9 : 18",
"E": "9 : 48"
} | divide(add(5, divide(multiply(add(subtract(5, 4), divide(subtract(18, 30), const_60)), 30), subtract(38, 30))), 18) | subtract(n5,n3)|subtract(n4,n2)|subtract(n1,n0)|divide(#0,const_60)|add(#3,#1)|multiply(n0,#4)|divide(#5,#2)|add(n4,#6)|divide(#7,n5)| | "since tom reads an average of 1 page every 2 minutes , tom will read 24 pages in the first 48 minutes . jan can catch tom at a rate of 8 pages per hour , so it will take 3 hours to catch tom . the answer is b ." | general |
math_qa__Mj6o6R1b1dMFGahe | A searchlight on top of the watch-tower makes 2 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 5 seconds? Choose the most appropriate option
A) 1 / 4 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 5 / 6 | <gadget id="calculator">60 * 1</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">5 / 30</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 - (1/6)</gadget>
<output>5/6 = around 0.833333</output>
<result>E</result> | E | 0.833333 | A searchlight on top of the watch-tower makes 2 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 5 seconds? | {
"A": "1 / 4",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "5 / 6"
} | subtract(const_1, divide(5, divide(multiply(const_60, const_1), 2))) | multiply(const_1,const_60)|divide(#0,n0)|divide(n1,#1)|subtract(const_1,#2) | 2 revolutions per minute = 1 revolution every 30 seconds so no matter what anybody appearing at the tower can not stay in the dark for more than 30 seconds . this will be our total number of possibilities i . e the denominator . p ( man in dark for at least 5 seconds ) = 1 - p ( man in dark for max of 5 seconds ) = 1 - 5 / 30 = 1 - 1 / 6 = 5 / 6 or the other way would be : p ( man in dark for at least 5 seconds ) is like saying he can be in dark for 5 , 6,7 . . . all the way to 30 seconds because that is the max . in this approach it would be 25 / 30 seconds = 5 / 6 . answer is e | physics |
math_qa__EA91T2uxw1JiFJuh | {-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number selected will be a solution of the equation (x-5)(x+10)(2x-5) = 0? Choose the correct choice:
A) 1 / 12 B) 1 / 6 C) 1 / 4 D) 1 / 3 E) 1 / 2 | <gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">2 / 12</gadget>
<output>1/6 = around 0.166667</output>
<result>B</result> | B | 0.166667 | {-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number selected will be a solution of the equation (x-5)(x+10)(2x-5) = 0? | {
"A": "1 / 12",
"B": "1 / 6",
"C": "1 / 4",
"D": "1 / 3",
"E": "1 / 2"
} | divide(2, multiply(6, 2)) | multiply(n1,n14)|divide(n14,#0) | roots of the equation ( x - 5 ) ( x + 10 ) ( 2 x - 5 ) = 0 are x = 5 , x = - 10 and x = 5 / 2 = 2.5 . so , two solutions present in our set of 12 distinct numbers , therefore p = 2 / 12 = 1 / 6 . answer : b . | general |
math_qa__2N1HlMSFlsG8eHeo | A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability Y that all 3 jellybeans removed from the bag are blue? Choose the correct choice from the following answers:
A) 9 / 100
B) 2 / 19
C) 1 / 8
D) 3 / 20
E) 3 / 10 | <gadget id="calculator">binomial(10, 3)</gadget>
<output>120</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">binomial(20, 3)</gadget>
<output>1_140</output>
<gadget id="calculator">120 / 1_140</gadget>
<output>2/19 = around 0.105263</output>
<result>B</result> | B | 0.105263 | A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability Y that all 3 jellybeans removed from the bag are blue? | {
"A": "9 / 100",
"B": "2 / 19",
"C": "1 / 8",
"D": "3 / 20",
"E": "3 / 10"
} | divide(choose(10, 3), choose(add(10, 10), 3)) | add(n0,n0)|choose(n0,n2)|choose(#0,n2)|divide(#1,#2)| | "method - 1 10 red jellybeans and 10 blue jellybeans total outcomes = no . of ways to choose 3 jelly bean at random out of a total 20 jellybeans = 20 c 3 = 1140 favourable outcomes = no . of ways to choose 3 jelly bean such that they are all blue out of 10 blue = 10 c 3 = 120 probability = favourable outcomes / total outcomes = 10 c 3 / 20 c 3 probability y = 120 / 1140 = 2 / 19 answer : option b method - 2 probability of first jelly bean to be blue = 10 / 20 [ total 10 blue out of total 20 jellybeans ] probability of second jelly bean to be blue = 9 / 19 [ total 9 blue remaining out of total 19 jellybeans remaining ] probability of third jelly bean to be blue = 8 / 18 [ total 8 blue remaining out of total 18 jellybeans remaining ] required probability = ( 10 / 20 ) * ( 9 / 19 ) * ( 8 / 18 ) = 2 / 19 answer : option b" | probability |
math_qa__U5IdSeltRaD1hfaT | When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 40% water?
Choose the correct option:
A) 1.2 kg
B) 1.5 kg
C) 1.7 kg
D) 1.9 kg
E) none of these | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/5) / (1/2)</gadget>
<output>6/5 = around 1.2</output>
<result>A</result> | A | 1.2 | When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 40% water? | {
"A": "1.2 kg",
"B": "1.5 kg",
"C": "1.7 kg",
"D": "1.9 kg",
"E": "none of these"
} | divide(divide(subtract(const_100, 40), const_100), divide(50, const_100)) | divide(n1,const_100)|subtract(const_100,n2)|divide(#1,const_100)|divide(#2,#0)| | "explanation : flower - nectar contains 50 % of non - water part . in honey this non - water part constitutes 60 % ( 100 - 40 ) . therefore 0.5 x amount of flower - nectar = 0.60 x amount of honey = 0.60 x 1 kg therefore amount of flower - nectar needed = ( 0.60 / 0.51 ) kg = 1.2 kgs answer : a" | general |
math_qa__L4tQafznTBw6VRho | The number of sailors on a ship is 50% more than the number of officers. The ratio of sailors to officers would be Answers
A) 33 : 25 B) 47 : 20 C) 3 : 2 D) 22 : 25 E) 97 : 50 | <gadget id="calculator">50 + 100</gadget>
<output>150</output>
<gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<result>C</result> | C | 1.5 | The number of sailors on a ship is 50% more than the number of officers. The ratio of sailors to officers would be | {
"A": "33 : 25",
"B": "47 : 20",
"C": "3 : 2",
"D": "22 : 25",
"E": "97 : 50"
} | divide(add(50, const_100), const_100) | add(n0,const_100)|divide(#0,const_100)| | "sailor = 1.50 * officer sailor / officer = 1.50 / 1 = 150 / 100 = 3 / 2 answer will be c" | other |
math_qa__itPkDhDpLsxKmyeg | In the x- y plane, there are 4 points (0,0), (0,4), (5,4), and (5,0). If these 4 points makes a rectangle, what is the probability that x+y<4?
Pick one
A) 2 / 3 B) 2 / 5 C) 3 / 4 D) 3 / 7 E) 5 / 8 | <gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">8 / 20</gadget>
<output>2/5 = around 0.4</output>
<result>B</result> | B | 0.4 | In the x- y plane, there are 4 points (0,0), (0,4), (5,4), and (5,0). If these 4 points makes a rectangle, what is the probability that x+y<4? | {
"A": "2 / 3",
"B": "2 / 5",
"C": "3 / 4",
"D": "3 / 7",
"E": "5 / 8"
} | divide(divide(multiply(4, 4), const_2), multiply(4, add(const_1, const_4))) | add(const_1,const_4)|multiply(n0,n0)|divide(#1,const_2)|multiply(n0,#0)|divide(#2,#3) | the line y = - x + 4 intersects the rectangle and these three points of intersection ( 0,0 ) , ( 0,4 ) and ( 4,0 ) form a triangle . the points below the line y = - x + 4 satisfy x + y < 4 . the area of this triangle is ( 1 / 2 ) ( 4 ) ( 4 ) = 8 the area of the rectangle is 20 . p ( x + y < 4 ) = 8 / 20 = 2 / 5 the answer is b . | general |
math_qa__PT5Gfhz4CgrAQwVl | We define that K@J is the product of j number from k in increasing order for positive integers K, J. For example, 6@4=6*7*8*9. If A=2020and B=2120, what is the value Q of the ratio A/B? Select the correct option:
A) 1 / 2 B) 1 / 3 C) 2 / 3 D) 1 / 4 E) 1 / 5 | <gadget id="calculator">2_020 / 2_020</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | We define that K@J is the product of j number from k in increasing order for positive integers K, J. For example, 6@4=6*7*8*9. If A=2020and B=2120, what is the value Q of the ratio A/B? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "2 / 3",
"D": "1 / 4",
"E": "1 / 5"
} | divide(divide(2020, 2020), add(divide(2020, 2020), divide(2020, 2020))) | divide(n6,n6)|add(#0,#0)|divide(#0,#1) | q - > a / b = 20 * 21 * … … * 39 / 21 * 22 * … . * 39 * 40 = 20 / 40 = 1 / 2 . therefore , the answer is a . | general |
math_qa__FMHeN5UN16uSfSMD | 3 numbers are in the ratio of 2 : 3 : 4 . if the sum of the squares of the extremes is 180 , then the middle number is : Choose the correct choice from the following answers:
A) 6
B) 12
C) 15
D) 9
E) 7 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">4 + 16</gadget>
<output>20</output>
<gadget id="calculator">180 / 20</gadget>
<output>9</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<result>D</result> | D | 9 | 3 numbers are in the ratio of 2 : 3 : 4 . if the sum of the squares of the extremes is 180 , then the middle number is : | {
"A": "6",
"B": "12",
"C": "15",
"D": "9",
"E": "7"
} | multiply(3, sqrt(divide(180, add(power(2, const_2), power(4, const_2))))) | power(n1,const_2)|power(n3,const_2)|add(#0,#1)|divide(n4,#2)|sqrt(#3)|multiply(n0,#4) | number be = 2 x , 3 x , 4 x , ( 2 x ) 2 + ( 4 x ) 2 = 180 20 x = 180 ⇒ x = 9 ⇒ x = 3 , midline number = 3 × 3 = 9 answer : d | general |
math_qa__CHSGytHkQ4jFJ2d4 | 20 men do a work in 20days. How many men are needed to finish the work in 5days?
Pick one:
A) 50
B) 20
C) 80
D) 10
E) 15 | <gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">400 / 5</gadget>
<output>80</output>
<result>C</result> | C | 80 | 20 men do a work in 20days. How many men are needed to finish the work in 5days? | {
"A": "50",
"B": "20",
"C": "80",
"D": "10",
"E": "15"
} | divide(multiply(20, 20), 5) | multiply(n0,n1)|divide(#0,n2)| | "men required to finish the work in 5 days = 20 * 20 / 5 = 80 answer is c" | physics |
math_qa__cdGDaYqPqA0csNTx | A man can row his boat with the stream at 22 km/h and against the stream in 10 km/h. The man's rate is? Choose the correct choice from the following answers.
A) 1 kmph B) 6 kmph C) 7 kmph D) 4 kmph E) 9 kmph | <gadget id="calculator">22 - 10</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>B</result> | B | 6 | A man can row his boat with the stream at 22 km/h and against the stream in 10 km/h. The man's rate is? | {
"A": "1 kmph",
"B": "6 kmph",
"C": "7 kmph",
"D": "4 kmph",
"E": "9 kmph"
} | divide(subtract(22, 10), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "explanation : ds = 22 us = 10 s = ? s = ( 22 - 10 ) / 2 = 6 kmph answer : b" | gain |
math_qa__fFepM6bDmtdH0UZ2 | Roja and Pooja start moving in the opposite directions from a pole. They are moving at the speeds of 7 km/hr and 3 km/hr respectively. After 4 hours what will be the distance between them? Choices.
A) 22 km
B) 40 km
C) 65 km
D) 18 km
E) 16 km | <gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<result>B</result> | B | 40 | Roja and Pooja start moving in the opposite directions from a pole. They are moving at the speeds of 7 km/hr and 3 km/hr respectively. After 4 hours what will be the distance between them? | {
"A": "22 km",
"B": "40 km",
"C": "65 km",
"D": "18 km",
"E": "16 km"
} | multiply(add(7, 3), 4) | add(n0,n1)|multiply(n2,#0)| | "distance = relative speed * time = ( 7 + 3 ) * 4 = 40 km [ they are travelling in the opposite direction , relative speed = sum of the speeds ] . answer : b" | physics |
math_qa__9itfWq9N74J3FTMR | If XY denotes X is raised to the power Y, Find the last two digits of 19413846+ 19614181 Choose the most appropriate option
A) 67 B) 74 C) 82 D) 98 E) 34 | <gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">19_614_181 % 10_000</gadget>
<output>4_181</output>
<gadget id="calculator">4_181 % 100</gadget>
<output>81</output>
<gadget id="calculator">81 - 10</gadget>
<output>71</output>
<gadget id="calculator">71 - 10</gadget>
<output>61</output>
<gadget id="calculator">19_413_846 / 10_000</gadget>
<output>9_706_923/5_000 = around 1_941.3846</output>
<gadget id="calculator">floor(9_706_923/5_000)</gadget>
<output>1_941</output>
<gadget id="calculator">1_941 % 100</gadget>
<output>41</output>
<gadget id="calculator">61 + 41</gadget>
<output>102</output>
<gadget id="calculator">102 - 10</gadget>
<output>92</output>
<gadget id="calculator">92 - 10</gadget>
<output>82</output>
<result>C</result> | C | 82 | If XY denotes X is raised to the power Y, Find the last two digits of 19413846+ 19614181 | {
"A": "67",
"B": "74",
"C": "82",
"D": "98",
"E": "34"
} | subtract(subtract(add(subtract(subtract(reminder(reminder(19614181, power(const_100, const_2)), const_100), const_10), const_10), reminder(floor(divide(19413846, power(const_100, const_2))), const_100)), const_10), const_10) | power(const_100,const_2)|divide(n0,#0)|reminder(n1,#0)|floor(#1)|reminder(#2,const_100)|reminder(#3,const_100)|subtract(#4,const_10)|subtract(#6,const_10)|add(#5,#7)|subtract(#8,const_10)|subtract(#9,const_10) | 1941 ^ 3846 unit digit = 1 ^ 4 = 1 10 th digit = 4 * 6 = 24 = 2 means last two digit = 41 and 1972 ^ 4181 unit digit = 1 10 th digit = 7 * 2 = 14 mean last two digit = 41 hence , 41 + 41 = 82 | general |
math_qa__s89owvlGDYimxMbq | All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 156 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A?
Choose the correct option: A) 1248 B) 1723 C) 1129 D) 2613 E) 1372 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">62.5 / 100</gadget>
<output>0.625</output>
<gadget id="calculator">1 - 0.625</gadget>
<output>0.375</output>
<gadget id="calculator">(1/2) - 0.375</gadget>
<output>0.125</output>
<gadget id="calculator">156 / 0.125</gadget>
<output>1_248</output>
<result>A</result> | A | 1,248 | All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 156 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A? | {
"A": "1248",
"B": "1723",
"C": "1129",
"D": "2613",
"E": "1372"
} | divide(156, subtract(inverse(const_2), subtract(const_1, divide(62.5, const_100)))) | divide(n0,const_100)|inverse(const_2)|subtract(const_1,#0)|subtract(#1,#2)|divide(n1,#3)| | "a b has 62.5 % or ( 5 / 8 ) of the milk in a . therefore , let the quantity of milk in container a ( initially ) be 8 k . quantity of milk in b = 8 k - 5 k = 3 k . quantity of milk in container c = 8 k - 3 k = 5 k container : a b c quantity of milk : 8 k 3 k 5 k it is given that if 156 liters was transferred from container c to container b , then both the containers would have equal quantities of milk . 5 k - 156 = 3 k + 156 = > 2 k = 312 = > k = 156 the initial quantity of milk in a = 8 k = 8 * 156 = 1248 liters ." | general |
math_qa__lhsv1DTcCoMoFbtK | The chance of rain on any given day in Tel-Aviv is 50%. What is the probability A that it rained in Tel-Aviv on exactly 4 out of 6 randomly chosen days? Choose the most appropriate option: A) 15 / 64 B) 30 / 64 C) 1 / 2 D) 1 / 4 E) 52 / 64 | <gadget id="calculator">binomial(6, 4)</gadget>
<output>15</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 4</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">(1/2) ** 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/16) * (1/4)</gadget>
<output>1/64 = around 0.015625</output>
<gadget id="calculator">1 / (1/64)</gadget>
<output>64</output>
<gadget id="calculator">15 / 64</gadget>
<output>15/64 = around 0.234375</output>
<result>A</result> | A | 0.234375 | The chance of rain on any given day in Tel-Aviv is 50%. What is the probability A that it rained in Tel-Aviv on exactly 4 out of 6 randomly chosen days? | {
"A": "15 / 64",
"B": "30 / 64",
"C": "1 / 2",
"D": "1 / 4",
"E": "52 / 64"
} | divide(choose(6, 4), inverse(multiply(power(divide(const_1, const_2), 4), power(divide(const_1, const_2), const_2)))) | choose(n2,n1)|divide(const_1,const_2)|power(#1,n1)|power(#1,const_2)|multiply(#2,#3)|inverse(#4)|divide(#0,#5)| | "chances of rain on exactly 4 days and not rain on 2 days = ( 1 / 2 ) ^ 4 * ( 1 / 2 ) ^ 2 = 1 / 64 chosing 4 days out of 6 = 6 ! / ( 4 ! * 2 ! ) = 15 chances of rain on exactly 4 days out of 6 days a = 15 / 64 ans a it is ." | probability |
math_qa__DZ6NRRQ0fN1mBrGv | A 300 m long train crosses a platform in 27 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
Choose the correct choice
A) 286 m
B) 350 m
C) 277 m
D) 278 m
E) 150 m | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 27</gadget>
<output>450</output>
<gadget id="calculator">450 - 300</gadget>
<output>150</output>
<result>E</result> | E | 150 | A 300 m long train crosses a platform in 27 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | {
"A": "286 m",
"B": "350 m",
"C": "277 m",
"D": "278 m",
"E": "150 m"
} | subtract(multiply(speed(300, 18), 27), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 18 = 50 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 27 = 50 / 3 x = 150 m . answer : e" | physics |
math_qa__TBnwXStF8uq1CZKb | Of 67 players on a cricket team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total?
Choose the correct choice from the following.
A) 54 B) 55 C) 57 D) 71 E) 92 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">67 - 37</gadget>
<output>30</output>
<gadget id="calculator">(2/3) * 30</gadget>
<output>20</output>
<gadget id="calculator">37 + 20</gadget>
<output>57</output>
<result>C</result> | C | 57 | Of 67 players on a cricket team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? | {
"A": "54",
"B": "55",
"C": "57",
"D": "71",
"E": "92"
} | add(37, multiply(subtract(const_1, divide(const_1, const_3)), subtract(67, 37))) | divide(const_1,const_3)|subtract(n0,n1)|subtract(const_1,#0)|multiply(#2,#1)|add(n1,#3)| | "total = 67 thrower = 37 rest = 67 - 37 = 30 left handed = 30 / 3 = 10 right handed = 20 if all thrower are right handed then total right handed is 30 + 20 = 57 so c . 57 is the right answer" | general |
math_qa__54q9TejdE74df9KL | If n = 2.0823 and n* is the decimal obtained by rounding n to the nearest hundredth, what is the value of n* – n?
Choose the correct answer
A) - 0.0053
B) - 0.0023
C) 0.0007
D) 0.0047
E) 0.0153 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 3</gadget>
<output>23</output>
<gadget id="calculator">23 / 100</gadget>
<output>23/100 = around 0.23</output>
<gadget id="calculator">(23/100) / 100</gadget>
<output>23/10_000 = around 0.0023</output>
<gadget id="calculator">2.0823 - (23/10_000)</gadget>
<output>2.08</output>
<gadget id="calculator">2.08 - 2.0823</gadget>
<output>-0.0023</output>
<result>B</result> | B | -0.0023 | If n = 2.0823 and n* is the decimal obtained by rounding n to the nearest hundredth, what is the value of n* – n? | {
"A": "- 0.0053",
"B": "- 0.0023",
"C": "0.0007",
"D": "0.0047",
"E": "0.0153"
} | subtract(subtract(2.0823, divide(divide(add(multiply(const_2, const_10), const_3), const_100), const_100)), 2.0823) | multiply(const_10,const_2)|add(#0,const_3)|divide(#1,const_100)|divide(#2,const_100)|subtract(n0,#3)|subtract(#4,n0)| | "n * = 2.08 n * - n = 2.08 - 2.0823 - 0.0023 answer : b" | general |
math_qa__fLByNw3nR22wI0vD | If Jack walked 7 miles in 1 hour and 15 minutes, what was his rate of walking in miles per hour? Pick one:
A) 4
B) 4.5
C) 5.6
D) 6.25
E) 15 | <gadget id="calculator">7 * 60</gadget>
<output>420</output>
<gadget id="calculator">15 + 60</gadget>
<output>75</output>
<gadget id="calculator">420 / 75</gadget>
<output>28/5 = around 5.6</output>
<result>C</result> | C | 5.6 | If Jack walked 7 miles in 1 hour and 15 minutes, what was his rate of walking in miles per hour? | {
"A": "4",
"B": "4.5",
"C": "5.6",
"D": "6.25",
"E": "15"
} | divide(multiply(7, const_60), add(15, const_60)) | add(n2,const_60)|multiply(n0,const_60)|divide(#1,#0)| | "distance walked in 1 hour and 15 mins = 7 miles speed per hour = distance / time = 7 / ( 5 / 4 ) = 5.6 miles per hour answer c" | physics |
math_qa__UZjycFVvtcRJMmN8 | A grocery shop has a sale of Rs. 6635, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? Choose the correct choice from the following answers:
A) 4857 B) 4184 C) 4012 D) 4791 E) 5291 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6_500 * 6</gadget>
<output>39_000</output>
<gadget id="calculator">6_635 + 6_927</gadget>
<output>13_562</output>
<gadget id="calculator">6_855 + 13_562</gadget>
<output>20_417</output>
<gadget id="calculator">20_417 + 7_230</gadget>
<output>27_647</output>
<gadget id="calculator">27_647 + 6_562</gadget>
<output>34_209</output>
<gadget id="calculator">39_000 - 34_209</gadget>
<output>4_791</output>
<result>D</result> | D | 4,791 | A grocery shop has a sale of Rs. 6635, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? | {
"A": "4857",
"B": "4184",
"C": "4012",
"D": "4791",
"E": "5291"
} | subtract(multiply(6500, add(5, const_1)), add(add(add(6855, add(6635, 6927)), 7230), 6562)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5) | let the sale in the sixth month = x then ( 6635 + 6927 + 6855 + 7230 + 6562 + x ) / 6 = 6500 = > 6635 + 6927 + 6855 + 7230 + 6562 + x = 6 × 6500 = > 34209 + x = 39000 = > x = 39000 − 34209 = 4791 answer : d | general |
math_qa__Lh2ysZpnKQX1BeaA | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 150 kilometers? Answers:
A) 3.5 gallons
B) 2.7 gallons
C) 5.75 gallons
D) 3.75 gallons
E) 7.50 gallons | <gadget id="calculator">150 / 40</gadget>
<output>15/4 = around 3.75</output>
<result>D</result> | D | 3.75 | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 150 kilometers? | {
"A": "3.5 gallons",
"B": "2.7 gallons",
"C": "5.75 gallons",
"D": "3.75 gallons",
"E": "7.50 gallons"
} | divide(150, 40) | divide(n1,n0)| | "each 40 kilometers , 1 gallon is needed . we need to know how many 40 kilometers are there in 150 kilometers ? 150 ã · 40 = 3.75 ã — 1 gallon = 3.75 gallons correct answer is d ) 3.75 gallons" | physics |
math_qa__1yosQBcielfRNelY | A fellow borrowed a certain sum of money at 5% per annum at simple interest and in 5 years the interest amounted to Rs.2250 less than the sum lent. What was the sum lent? Choose the correct choice:
A) 1050 B) 1220 C) 1250 D) 1060 E) 3000 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">2_250 / (3/4)</gadget>
<output>3_000</output>
<result>E</result> | E | 3,000 | A fellow borrowed a certain sum of money at 5% per annum at simple interest and in 5 years the interest amounted to Rs.2250 less than the sum lent. What was the sum lent? | {
"A": "1050",
"B": "1220",
"C": "1250",
"D": "1060",
"E": "3000"
} | divide(2250, subtract(const_1, divide(multiply(5, 5), const_100))) | multiply(n0,n0)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2)| | "p - 2250 = ( p * 5 * 5 ) / 100 p = 3000 answer : e" | gain |
math_qa__5eCtWBBaYl7ksjQA | In a certain country 1/3 of 4 = 8. Assuming the same proportion, what would be the value of 1/8 of 4 ? Choose the correct option:
A) 2 B) 6 C) 5 D) 4 E) 3 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 4</gadget>
<output>3</output>
<result>E</result> | E | 3 | In a certain country 1/3 of 4 = 8. Assuming the same proportion, what would be the value of 1/8 of 4 ? | {
"A": "2",
"B": "6",
"C": "5",
"D": "4",
"E": "3"
} | multiply(divide(3, 4), 4) | divide(n1,n2)|multiply(n6,#0)| | "e 3" | general |
math_qa__EdP2t4rDmsCgCBYd | Golu started from his house towards North. After covering a distance of 8 km. he turned towards left and covered a distance of 6 km. What is the shortest distance now from his house? Choose the correct choice from the following options.
A) 10 km . B) 16 km . C) 14 km D) 2 km . E) 4 km . | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">64 + 36</gadget>
<output>100</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<result>A</result> | A | 10 | Golu started from his house towards North. After covering a distance of 8 km. he turned towards left and covered a distance of 6 km. What is the shortest distance now from his house? | {
"A": "10 km .",
"B": "16 km .",
"C": "14 km",
"D": "2 km .",
"E": "4 km ."
} | sqrt(add(power(8, const_2), power(6, const_2))) | power(n0,const_2)|power(n1,const_2)|add(#0,#1)|sqrt(#2) | c - - - - - - - - - - - - - b ! ! ! ! ! a ab = 8 km bc = 6 km ac = sqrtof ( 8 ^ 2 + 6 ^ 2 ) ac = 10 km answer : a | physics |
math_qa__kWwdiGvumM5xnToC | A tank can be filled by a tap in 20 minutes and by another tap in 60 minutes. Both the taps are kept open for 10 minutes and then the first tap is shut off. After this, the tank will be completely filled in what time ?
Choose the correct choice from the following choices.
A) 10 mins B) 15 mins C) 20 mins D) 25 mins E) 30 mins | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/20) + (1/60)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">10 * (1/15)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) / (1/60)</gadget>
<output>20</output>
<result>C</result> | C | 20 | A tank can be filled by a tap in 20 minutes and by another tap in 60 minutes. Both the taps are kept open for 10 minutes and then the first tap is shut off. After this, the tank will be completely filled in what time ? | {
"A": "10 mins",
"B": "15 mins",
"C": "20 mins",
"D": "25 mins",
"E": "30 mins"
} | divide(subtract(const_1, multiply(10, add(divide(const_1, 20), divide(const_1, 60)))), divide(const_1, 60)) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)|divide(#4,#1) | explanation : how we can solve this question ? first we will calculate the work done for 10 mins , then we will get the remaining work , then we will find answer with one tap work , as part filled by tap a in 1 min = 1 / 20 part filled by tap b in 1 min = 1 / 60 ( a + b ) ' s 10 mins work = 10 ∗ ( 1 / 20 + 1 / 60 ) = 10 ∗ 4 / 60 = 2 / 3 remaining work = 1 − 2 / 3 = 1 / 3 method 1 = > 1 / 60 : 1 / 3 = 1 : x = > x = 20 method 2 1 / 60 part filled by b in = 1 min 1 / 3 part will be filled in = 1 / 3 / 1 / 60 = 60 / 3 = 20 option c | physics |
math_qa__gkZ2LxIkBE2ll7m3 | Renu can do a piece of work in 6 days, but with the help of her friend Suma , she can do it in 3 days. In what time Suma can do it alone? Choose the correct choice from the following options: A) 6 B) 12 C) 14 D) 15 E) 17 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/3) - (1/6)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>A</result> | A | 6 | Renu can do a piece of work in 6 days, but with the help of her friend Suma , she can do it in 3 days. In what time Suma can do it alone? | {
"A": "6",
"B": "12",
"C": "14",
"D": "15",
"E": "17"
} | inverse(subtract(divide(const_1, 3), divide(const_1, 6))) | divide(const_1,n1)|divide(const_1,n0)|subtract(#0,#1)|inverse(#2)| | "renu â € ™ s one day â € ™ s work = 1 / 6 suma â € ™ s one day â € ™ s work = 1 / 3 - 1 / 6 = 1 / 6 suma can do it alone in 6 days . answer : a" | physics |
math_qa__yMb9jcuORrgXrWN8 | An engineer undertakes a project to build a road 15 km long in 300 days and employs 50 men for the purpose. After 100 days, he finds only 2.5 km of the road has been completed. Find the (approximate) number of extra men he must employ to finish the work in time. Choose the correct option.
A) a . 43
B) b . 45
C) c . 75
D) d . 68
E) e . 60 | <gadget id="calculator">15 - 2.5</gadget>
<output>12.5</output>
<gadget id="calculator">50 * 12.5</gadget>
<output>625</output>
<gadget id="calculator">625 * 100</gadget>
<output>62_500</output>
<gadget id="calculator">300 - 100</gadget>
<output>200</output>
<gadget id="calculator">2.5 * 200</gadget>
<output>500</output>
<gadget id="calculator">62_500 / 500</gadget>
<output>125</output>
<gadget id="calculator">125 - 50</gadget>
<output>75</output>
<result>C</result> | C | 75 | An engineer undertakes a project to build a road 15 km long in 300 days and employs 50 men for the purpose. After 100 days, he finds only 2.5 km of the road has been completed. Find the (approximate) number of extra men he must employ to finish the work in time. | {
"A": "a . 43",
"B": "b . 45",
"C": "c . 75",
"D": "d . 68",
"E": "e . 60"
} | subtract(divide(multiply(multiply(50, subtract(15, 2.5)), 100), multiply(2.5, subtract(300, 100))), 50) | subtract(n0,n4)|subtract(n1,n3)|multiply(n2,#0)|multiply(n4,#1)|multiply(n3,#2)|divide(#4,#3)|subtract(#5,n2)| | "50 workers working already let x be the total men required to finish the task in next 200 days 2.5 km done hence remaining is 12.5 km also , work has to be completed in next 200 days ( 300 - 100 = 200 ) we know that , proportion of men to distance is direct proportion and , proportion of men to days is inverse proportion hence , x = ( 50 * 12.5 * 100 ) / ( 2.5 * 200 ) thus , x = 125 thus , more men needed to finish the task = 125 - 50 = 75 hence answer is c" | physics |
math_qa__LEGlIppVQ8ZSfjZt | A train running at the speed of 60 km/hr crosses a pole in 12 seconds. What is the length of the train? Options.
A) 187 m
B) 278 m
C) 876 m
D) 200 m
E) 267 m | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 12</gadget>
<output>200</output>
<result>D</result> | D | 200 | A train running at the speed of 60 km/hr crosses a pole in 12 seconds. What is the length of the train? | {
"A": "187 m",
"B": "278 m",
"C": "876 m",
"D": "200 m",
"E": "267 m"
} | multiply(divide(multiply(60, const_1000), const_3600), 12) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = ( 60 * 5 / 18 ) m / sec = ( 50 / 3 ) m / sec length of the train = ( speed x time ) = ( 50 / 3 * 12 ) m = 200 m . answer : d" | physics |
math_qa__oZKXFdhqtcMzEBlS | A is twice as fast as B. If B alone can do a piece of work in 24 days, in what time can A and B together complete the work? Choose the correct choice from the following.
A) 10
B) 12
C) 6
D) 2
E) 8 | <gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/24) * 2</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/24) + (1/12)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<result>E</result> | E | 8 | A is twice as fast as B. If B alone can do a piece of work in 24 days, in what time can A and B together complete the work? | {
"A": "10",
"B": "12",
"C": "6",
"D": "2",
"E": "8"
} | inverse(add(divide(const_1, 24), multiply(divide(const_1, 24), const_2))) | divide(const_1,n0)|multiply(#0,const_2)|add(#0,#1)|inverse(#2) | a can do the work in 24 / 2 i . e . , 12 days . a and b ' s one day ' s work = 1 / 12 + 1 / 24 = ( 2 + 1 ) / 24 = 1 / 8 so a and b together can do the work in 8 days . answer : e | physics |
math_qa__TPEwz88EAgJsBGBa | The owner of a furniture shop charges his customer 32% more than the cost price. If a customer paid Rs. 5400 for a computer table, then what was the cost price of the computer table? Choose the correct choice from the following answers:
A) rs . 4090
B) rs . 4067
C) rs . 6290
D) rs . 6725
E) rs . 6708 | <gadget id="calculator">32 / 100</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">1 + (8/25)</gadget>
<output>33/25 = around 1.32</output>
<gadget id="calculator">5_400 / (33/25)</gadget>
<output>45_000/11 = around 4_090.909091</output>
<result>A</result> | A | 4,090 | The owner of a furniture shop charges his customer 32% more than the cost price. If a customer paid Rs. 5400 for a computer table, then what was the cost price of the computer table? | {
"A": "rs . 4090",
"B": "rs . 4067",
"C": "rs . 6290",
"D": "rs . 6725",
"E": "rs . 6708"
} | divide(5400, add(const_1, divide(32, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "cp = sp * ( 100 / ( 100 + profit % ) ) = 5400 ( 100 / 132 ) = rs . 4090 . answer : a" | gain |
math_qa__W4k99ZEnZU7TdSGH | A vendor buys 10 t-shirts at an average price of $14 per t-shirt. He then buys 15 more t-shirts at an average price of $11 per t-shirt. What is the average price B per t-shirt that the vendor paid for these purchases?
Pick one:
A) $ 12.20
B) $ 12.50
C) $ 12.55
D) $ 12.70
E) $ 13.00 | <gadget id="calculator">10 + 14</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + (1/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">12 + (1/2)</gadget>
<output>25/2 = around 12.5</output>
<result>A</result> | A | 12.2 | A vendor buys 10 t-shirts at an average price of $14 per t-shirt. He then buys 15 more t-shirts at an average price of $11 per t-shirt. What is the average price B per t-shirt that the vendor paid for these purchases? | {
"A": "$ 12.20",
"B": "$ 12.50",
"C": "$ 12.55",
"D": "$ 12.70",
"E": "$ 13.00"
} | add(divide(add(10, 14), const_2), add(const_0_25, const_0_25)) | add(const_0_25,const_0_25)|add(n0,n1)|divide(#1,const_2)|add(#0,#2) | correct answer : a explanation : the relevant formula for this problem is average b = ( sum ) / ( number of terms ) . another way to look at the formula is sum = average x number of terms . for the first purchase , the vendor ' s sum ( total cost ) was $ 140 , since 14 x 10 = 140 . for the second purchase , the vendor ' s cost was $ 165 , since 11 x 15 = 165 . the grand sum is then $ 140 + $ 165 , which equals $ 305 . the total number of shirts purchased was 25 , so to get the average price per shirt , we divide 305 by 25 , which equals $ 12.20 . as a result , the correct answer is a . note : a relative understanding of weighted average offers a shortcut to this problem . because the true average of 11 and 14 is 12.5 , but the vendor sells more shirts at the lower price than at the higher price , the weighted average must be less than $ 12.50 ; only answer choice a is a possibility . | general |
math_qa__rhtIXoJQ875P9rAY | A cylinder is 6 cms in diameter and 6 cms in height. If spheres of the same size are made from the material obtained, what is the diameter of each sphere? Choices
A) 5 cms
B) 2 cms
C) 3 cms
D) 4 cms
E) 6 cms | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 6</gadget>
<output>54</output>
<gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">(4/3) * 12</gadget>
<output>16</output>
<gadget id="calculator">54 / 16</gadget>
<output>27/8 = around 3.375</output>
<gadget id="calculator">floor(27/8)</gadget>
<output>3</output>
<result>C</result> | C | 3 | A cylinder is 6 cms in diameter and 6 cms in height. If spheres of the same size are made from the material obtained, what is the diameter of each sphere? | {
"A": "5 cms",
"B": "2 cms",
"C": "3 cms",
"D": "4 cms",
"E": "6 cms"
} | floor(divide(multiply(multiply(const_3, const_3), 6), multiply(divide(const_4, const_3), multiply(6, const_2)))) | divide(const_4,const_3)|multiply(const_3,const_3)|multiply(n0,const_2)|multiply(n0,#1)|multiply(#0,#2)|divide(#3,#4)|floor(#5) | since the sphere is made out of the cylinder material their volume will be same volume of cylinder = pi * 3 ^ 2 * 6 volume of one sphere = 4 / 3 * pi * r ^ 3 ( where r is radius of sphere ) so if there are n such sphere ' s equating the volumes , pi * r ^ 2 * h = n * ( 4 / 3 ) * pi * r ^ 3 n is the number of spheres , substituting the , r and h 9 * 6 = n * ( 4 / 3 ) * ( d / 2 ) ^ 3 d is the diameter of a sphere , n = ( 9 * 6 * 3 * 8 ) / ( 4 * d ^ 3 ) n = 324 / d ^ 3 now substitute the given answers for d and find the values for n , since a n has to be an integer only value fit for d is 3 , answer : c | physics |
math_qa__JBw84dBLZ0pyfE51 | A number x is 8 times another number y. The percentage that y is less than x is Choose the correct choice.
A) 12.5 % B) 87.5 % C) 80 % D) 11 % E) 1 % | <gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">(7/8) * 100</gadget>
<output>175/2 = around 87.5</output>
<result>B</result> | B | 87.5 | A number x is 8 times another number y. The percentage that y is less than x is | {
"A": "12.5 %",
"B": "87.5 %",
"C": "80 %",
"D": "11 %",
"E": "1 %"
} | multiply(divide(subtract(8, const_1), 8), const_100) | subtract(n0,const_1)|divide(#0,n0)|multiply(#1,const_100)| | "say y = 1 and x = 8 . then y = 1 is less than x = 8 by ( 8 - 1 ) / 8 * 100 = 7 / 8 * 100 = 87.5 % . answer : b ." | general |
math_qa__yPneFU9ZWlc8UNhd | If 20 typists can type 44 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour? Choose the correct choice from the following answers: A) 63 B) 72 C) 198 D) 216 E) 400 | <gadget id="calculator">44 * 3</gadget>
<output>132</output>
<gadget id="calculator">132 / 20</gadget>
<output>33/5 = around 6.6</output>
<gadget id="calculator">(33/5) * 30</gadget>
<output>198</output>
<result>C</result> | C | 198 | If 20 typists can type 44 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour? | {
"A": "63",
"B": "72",
"C": "198",
"D": "216",
"E": "400"
} | multiply(divide(multiply(44, const_3), 20), 30) | multiply(n1,const_3)|divide(#0,n0)|multiply(n3,#1)| | "20 typists can type 44 letters , so 30 typists can type = 44 * 30 / 20 44 * 30 / 20 letters can be typed in 20 mins . in 60 mins typist can type = 44 * 30 * 60 / 20 * 20 = 198 c is the answer" | physics |
math_qa__lloNbpPuX72ESSPY | Amithab's average expenditure for the January to June is Rs. 4200 and he spends Rs.1200 in January and Rs.1500 in july.The average expenditure for the months of febraury to July is: Pick one.
A) rs . 4250 B) rs . 4288 C) rs . 4227 D) rs . 4218 E) rs . 4219 | <gadget id="calculator">1_500 - 1_200</gadget>
<output>300</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">300 / 6</gadget>
<output>50</output>
<gadget id="calculator">4_200 + 50</gadget>
<output>4_250</output>
<result>A</result> | A | 4,250 | Amithab's average expenditure for the January to June is Rs. 4200 and he spends Rs.1200 in January and Rs.1500 in july.The average expenditure for the months of febraury to July is: | {
"A": "rs . 4250",
"B": "rs . 4288",
"C": "rs . 4227",
"D": "rs . 4218",
"E": "rs . 4219"
} | add(4200, divide(subtract(1500, 1200), multiply(const_2, const_3))) | multiply(const_2,const_3)|subtract(n2,n1)|divide(#1,#0)|add(n0,#2)| | "explanation : amithab ' s total expenditure for jan - june = 4200 x 6 = 25200 expenditure for feb - june = 25200 - 1200 = 24000 expenditure for the months of feb - july = 24000 + 1500 = 25500 the average expenditure = { 25500 } { 6 } = 4250 answer : a" | general |
math_qa__BTRA6SDbUJP0Sqay | How many factors of 220 are odd numbers greater than 1? Choose the correct choice.
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">60 / 20</gadget>
<output>3</output>
<result>A</result> | A | 3 | How many factors of 220 are odd numbers greater than 1? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(const_60.0, multiply(const_10, const_2)) | multiply(const_10,const_2)|divide(const_60.0,#0)| | when factorized , 220 has 4 prime factors . of these prime factors 2 are odd and 2 are even . hence total number of odd factors is 2 * 2 ( 4 ) , which includes 1 . the total number of odd factors greater than 1 are 3 . ( option a ) | other |
math_qa__NxHbz9sJBcgYuWbv | In xyz business school,88% are taking their specialization as finance at the same time 76% taking their specialization as marketing.If 90% are taking their specialization as finance then, what is % of marketing specialization students? Choose the correct choice from the following answers
A) 55 B) 75 C) 43 D) 52 E) 45 | <gadget id="calculator">90 - 76</gadget>
<output>14</output>
<gadget id="calculator">88 - 14</gadget>
<output>74</output>
<gadget id="calculator">74 / 3</gadget>
<output>74/3 = around 24.666667</output>
<gadget id="calculator">(74/3) + (74/3)</gadget>
<output>148/3 = around 49.333333</output>
<gadget id="calculator">(148/3) - 3</gadget>
<output>139/3 = around 46.333333</output>
<gadget id="calculator">(148/3) - (139/3)</gadget>
<output>3</output>
<gadget id="calculator">(139/3) - 3</gadget>
<output>130/3 = around 43.333333</output>
<result>C</result> | C | 43 | In xyz business school,88% are taking their specialization as finance at the same time 76% taking their specialization as marketing.If 90% are taking their specialization as finance then, what is % of marketing specialization students? | {
"A": "55",
"B": "75",
"C": "43",
"D": "52",
"E": "45"
} | subtract(subtract(add(divide(subtract(88, subtract(90, 76)), const_3), divide(subtract(88, subtract(90, 76)), const_3)), const_3), subtract(add(divide(subtract(88, subtract(90, 76)), const_3), divide(subtract(88, subtract(90, 76)), const_3)), subtract(add(divide(subtract(88, subtract(90, 76)), const_3), divide(subtract(88, subtract(90, 76)), const_3)), const_3))) | subtract(n2,n1)|subtract(n0,#0)|divide(#1,const_3)|add(#2,#2)|subtract(#3,const_3)|subtract(#3,#4)|subtract(#4,#5) | percentage of finance specialization = 88 ; percentage of marketing specialization = 75 % ; total = 90 * 100 ; percentage of finance specialization = 90 - 88 = 2 ; percentage of marketing specialization = 100 - 75 = 25 ; then percentage of marketing specialization = 0.75 * 24 = 18 . then total percentage of marketing specialization = 25 + 18 = 43 . answer : c | gain |
math_qa__bTsOCBKFOcMelpRr | In the rectangular coordinate system, points (4, 0) and (– 4, 0) both lie on circle C. What is the maximum possible value of the radius of C Choose the most appropriate option
A) 2 B) 4 C) 8 D) 16 E) none of the above | <gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<result>B</result> | B | 4 | In the rectangular coordinate system, points (4, 0) and (– 4, 0) both lie on circle C. What is the maximum possible value of the radius of C | {
"A": "2",
"B": "4",
"C": "8",
"D": "16",
"E": "none of the above"
} | sqrt(power(4, const_2)) | power(n0,const_2)|sqrt(#0)| | "it takes 3 distinct points to define a circle . only 2 are given here . the two points essentially identify a single chord of the circle c . since no other information is provided , however , the radius of the circle can essentially be anything . all this information tell us is that the radius isgreater 4 b" | geometry |
math_qa__7nOGP37bLNji8O6F | On a map, 3 centimeters represents 33 kilometers. Two cities 209 kilometers apart would be separated on the map by how many centimeters?
Select:
A) 19 B) 7 C) 13 D) 110 E) 180 | <gadget id="calculator">3 / 33</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/11) * 209</gadget>
<output>19</output>
<result>A</result> | A | 19 | On a map, 3 centimeters represents 33 kilometers. Two cities 209 kilometers apart would be separated on the map by how many centimeters? | {
"A": "19",
"B": "7",
"C": "13",
"D": "110",
"E": "180"
} | multiply(divide(3, 33), 209) | divide(n0,n1)|multiply(n2,#0)| | "1 centimeter represents 11 kilometers ( 33 / 3 ) x = 209 / 11 = 19 answer : a" | gain |
math_qa__Cl9cB5AiDgTDR2gh | A boat can travel with a speed of 5km/hr in still water. If the speed of the stream is 5km/hr, find the time taken by the boat to go 100km downstream. Choose the correct choice from the following.
A) 1 hr
B) 2 hrs
C) 3 hrs
D) 4 hrs
E) 10 hrs | <gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<result>E</result> | E | 10 | A boat can travel with a speed of 5km/hr in still water. If the speed of the stream is 5km/hr, find the time taken by the boat to go 100km downstream. | {
"A": "1 hr",
"B": "2 hrs",
"C": "3 hrs",
"D": "4 hrs",
"E": "10 hrs"
} | divide(100, add(5, 5)) | add(n0,n1)|divide(n2,#0)| | "speed downstream = ( 5 + 5 ) km / hr = 10 km / hr . time taken to travel 100 km downstream = 100 / 10 hrs = 10 hrs . answer : e" | physics |
math_qa__e2KYXunMZYShz1xR | When f is divided by 5, the remainder is 3. When y is divided by 5, the remainder is 4. What is the remainder when f + y is divided by 5? Answers
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 % 5</gadget>
<output>2</output>
<result>C</result> | C | 2 | When f is divided by 5, the remainder is 3. When y is divided by 5, the remainder is 4. What is the remainder when f + y is divided by 5? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | reminder(add(3, 4), 5) | add(n1,n3)|reminder(#0,n0) | in my view the answer should be c f / 5 has remainder = 3 - > f = 5 x q + 3 y / 5 has a remainder = 4 - > y = 5 x q + 3 combining both ( ( 5 x q 1 + 3 ) + ( 5 x q 2 + 3 ) ) / 5 = 5 ( q 1 + q 2 ) / 5 + 7 / 5 = q 1 + q 2 + 7 / 5 7 / 5 = 1 + 2 / 5 = > remainder 2 answer c | general |
math_qa__VWz5TTpIBMHuo0c6 | The side of a rhombus is 24 m and length of one of its diagonals is 18 m. The area of the rhombus is?
Answers: A) 410.47 B) 403.47 C) 420.47 D) 400.47 E) 300.47 | <gadget id="calculator">2 * 24</gadget>
<output>48</output>
<gadget id="calculator">48 ** 2</gadget>
<output>2_304</output>
<gadget id="calculator">18 ** 2</gadget>
<output>324</output>
<gadget id="calculator">2_304 - 324</gadget>
<output>1_980</output>
<gadget id="calculator">1_980 ** (1/2)</gadget>
<output>6*sqrt(55) = around 44.497191</output>
<gadget id="calculator">18 * (6*sqrt(55))</gadget>
<output>108*sqrt(55) = around 800.949437</output>
<gadget id="calculator">(108*sqrt(55)) / 2</gadget>
<output>54*sqrt(55) = around 400.474718</output>
<result>D</result> | D | 400.47 | The side of a rhombus is 24 m and length of one of its diagonals is 18 m. The area of the rhombus is? | {
"A": "410.47",
"B": "403.47",
"C": "420.47",
"D": "400.47",
"E": "300.47"
} | divide(multiply(18, sqrt(subtract(power(multiply(const_2, 24), const_2), power(18, const_2)))), const_2) | multiply(n0,const_2)|power(n1,const_2)|power(#0,const_2)|subtract(#2,#1)|sqrt(#3)|multiply(n1,#4)|divide(#5,const_2)| | "area of the rhombus = 1 / 2 * p * √ 4 ( a ) 2 - ( p ) 2 a = 24 ; p = 18 a = 1 / 2 * 18 * √ 4 ( 24 ) 2 - ( 18 ) 2 = 1 / 2 * 18 * √ 2304 - 324 = 1 / 2 * 18 * √ 1980 a = 400.47 answer : d" | geometry |
math_qa__4ohWTN2EPhUjI7af | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is: Choose the correct choice from the following answers:
A) 21
B) 20
C) 22
D) 25
E) 40 | <gadget id="calculator">12_000 - 8_000</gadget>
<output>4_000</output>
<gadget id="calculator">7 * 4_000</gadget>
<output>28_000</output>
<gadget id="calculator">8_000 - 6_000</gadget>
<output>2_000</output>
<gadget id="calculator">28_000 / 2_000</gadget>
<output>14</output>
<gadget id="calculator">7 + 14</gadget>
<output>21</output>
<result>A</result> | A | 21 | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is: | {
"A": "21",
"B": "20",
"C": "22",
"D": "25",
"E": "40"
} | add(7, divide(multiply(7, subtract(12000, 8000)), subtract(8000, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3)| | "let the total number of workers be x . then , 8000 x = ( 12000 * 7 ) + 6000 ( x - 7 ) = 2000 x = 42000 = x = 21 . answer a" | general |
math_qa__PanOHiZPfu73MRDr | A car travels at a speed of 55 miles per hour. How far will it travel in 5 hours? Choose the correct choice from the following choices.
A) 425 miles B) 625 miles C) 325 miles D) 225 miles E) 275 miles | <gadget id="calculator">55 * 5</gadget>
<output>275</output>
<result>E</result> | E | 275 | A car travels at a speed of 55 miles per hour. How far will it travel in 5 hours? | {
"A": "425 miles",
"B": "625 miles",
"C": "325 miles",
"D": "225 miles",
"E": "275 miles"
} | multiply(55, 5) | multiply(n0,n1)| | "during each hour , the car travels 55 miles . for 5 hours it will travel 55 + 55 + 55 + 55 + 55 = 5 * 55 = 275 miles correct answer e" | physics |
math_qa__miHYigSxOqSzMoDP | Every second Saturday and all Sundays are holidays. How many working days will be there in a
month of 30 days beginning on a Saturday? Choices: A) 24 B) 23 C) 18 D) 21 E) 22 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">2 + 5</gadget>
<output>7</output>
<gadget id="calculator">30 - 7</gadget>
<output>23</output>
<result>B</result> | B | 23 | Every second Saturday and all Sundays are holidays. How many working days will be there in a
month of 30 days beginning on a Saturday? | {
"A": "24",
"B": "23",
"C": "18",
"D": "21",
"E": "22"
} | subtract(30, add(add(const_1, const_1), add(const_3, const_2))) | add(const_1,const_1)|add(const_2,const_3)|add(#0,#1)|subtract(n0,#2) | explanation : mentioned month has begins on a saturday and has 30 days sundays = 2 nd , 9 th , 16 th , 23 rd , 30 th = > total sundays = 5 second saturdays = 8 th and 22 nd total second saturdays = 2 total holidays = total sundays + total second saturdays = 5 + 2 = 7 total days in the month = 30 total working days = 30 - 7 = 23 answer : option b | physics |
math_qa__SBLEauyJqPeiRK5G | the present age of a father is 3 years more than 3 times the age of his son . 3 years hence , father ’ s age will be 10 years more than twice athe age of the son . find the present age of the father .
Pick.
A) 33 B) 34 C) 35 D) 36 E) 37 | <gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">3 + 30</gadget>
<output>33</output>
<result>A</result> | A | 33 | the present age of a father is 3 years more than 3 times the age of his son . 3 years hence , father ’ s age will be 10 years more than twice athe age of the son . find the present age of the father . | {
"A": "33",
"B": "34",
"C": "35",
"D": "36",
"E": "37"
} | add(3, multiply(10, 3)) | multiply(n0,n3)|add(n0,#0) | sol . let the son ’ s present age be x years . then , father ’ s present age = ( 3 x + 3 ) years . therefore ( 3 x + 3 + 3 ) = 2 ( x + 3 ) + 10 ‹ = › 3 x + 6 = 2 x + 16 ‹ = › x = 10 hence , father ’ s present age = ( 3 x + 3 ) = ( 3 x 10 + 3 ) years = 33 years . answer a | general |
math_qa__lbS1EK49LAgCWshS | A cricket bat is sold for $850, making a profit of $230. The profit percentage would be
Answers.
A) 24 % B) 25 % C) 30 % D) 37 % E) 40 % | <gadget id="calculator">850 - 230</gadget>
<output>620</output>
<gadget id="calculator">230 / 620</gadget>
<output>23/62 = around 0.370968</output>
<gadget id="calculator">(23/62) * 100</gadget>
<output>1_150/31 = around 37.096774</output>
<result>D</result> | D | 37 | A cricket bat is sold for $850, making a profit of $230. The profit percentage would be | {
"A": "24 %",
"B": "25 %",
"C": "30 %",
"D": "37 %",
"E": "40 %"
} | multiply(divide(230, subtract(850, 230)), const_100) | subtract(n0,n1)|divide(n1,#0)|multiply(#1,const_100)| | "230 / ( 850 - 230 ) = 230 / 620 = 23 / 62 = 37 % answer : d ." | gain |
math_qa__hVkOLQ7qpLInGFl8 | A factory produces 5500 toys per week. If the workers at this factory work 4 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? Options:
A) 4436 toys B) 5487 toys C) 6113 toys D) 2354 toys E) 1375 toys | <gadget id="calculator">5_500 / 4</gadget>
<output>1_375</output>
<result>E</result> | E | 1,375 | A factory produces 5500 toys per week. If the workers at this factory work 4 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? | {
"A": "4436 toys",
"B": "5487 toys",
"C": "6113 toys",
"D": "2354 toys",
"E": "1375 toys"
} | divide(5500, 4) | divide(n0,n1)| | "to find the number of toys produced every day , we divide the total number of toys produced in one week ( of 4 days ) by 4 . 5500 / 4 = 1375 toys correct answer e" | physics |
math_qa__3MBR2O3jLU0xz7zq | if g is the smallest positive integer such that 3150 multiplied by g is the square of an integer , then g must be Choices:
A) 2 B) 5 C) 6 D) 7 E) 14 | <gadget id="calculator">3_150 / 2</gadget>
<output>1_575</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">1_575 / 5</gadget>
<output>315</output>
<gadget id="calculator">315 / 5</gadget>
<output>63</output>
<gadget id="calculator">63 / 3</gadget>
<output>21</output>
<gadget id="calculator">21 / 3</gadget>
<output>7</output>
<gadget id="calculator">2 * 7</gadget>
<output>14</output>
<result>E</result> | E | 14 | if g is the smallest positive integer such that 3150 multiplied by g is the square of an integer , then g must be | {
"A": "2",
"B": "5",
"C": "6",
"D": "7",
"E": "14"
} | multiply(const_2, divide(divide(divide(divide(divide(3150, const_2), add(const_2, const_3)), add(const_2, const_3)), const_3), const_3)) | add(const_2,const_3)|divide(n0,const_2)|divide(#1,#0)|divide(#2,#0)|divide(#3,const_3)|divide(#4,const_3)|multiply(#5,const_2) | solution : this problem is testing us on the rule that when we express a perfect square by its unique prime factors , every prime factor ' s exponent is an even number . let ’ s start by prime factorizing 3150 . 3150 = 315 x 10 = 5 x 63 x 10 = 5 x 7 x 3 x 3 x 5 x 2 3150 = 2 ^ 1 x 3 ^ 2 x 5 ^ 2 x 7 ^ 1 ( notice that the exponents of both 2 and 7 are not even numbers . this tells us that 3150 itself is not a perfect square . ) we also are given that 3150 multiplied by g is the square of an integer . we can write this as : 2 ^ 1 x 3 ^ 2 x 5 ^ 2 x 7 ^ 1 x g = square of an integer according to our rule , we need all unique prime factors ' exponents to be even numbers . thus , we need one more 2 and one more 7 . therefore , g = 7 x 2 = 14 answer is e . | geometry |
math_qa__DehrewE3NIuO1cqA | The total age of A and B is 13 years more than the total age of B and C. C is how many year younger than A
Choose the correct choice from the following answers: A) 11 B) 12 C) 13 D) 14 E) 15 | <gadget id="calculator">13 * 1</gadget>
<output>13</output>
<result>C</result> | C | 13 | The total age of A and B is 13 years more than the total age of B and C. C is how many year younger than A | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | multiply(13, const_1) | multiply(n0,const_1)| | "explanation : given that a + b = 13 + b + c = > a – c = 13 + b – b = 13 = > c is younger than a by 13 years answer : option c" | general |
math_qa__GtvkUkg6wCQmpOnt | ?% of 360 = 108.0 Choose the correct choice from the following:
A) 277 B) 36 C) 64 D) 72 E) 30 | <gadget id="calculator">108 * 100</gadget>
<output>10_800</output>
<gadget id="calculator">10_800 / 360</gadget>
<output>30</output>
<result>E</result> | E | 30 | ?% of 360 = 108.0 | {
"A": "277",
"B": "36",
"C": "64",
"D": "72",
"E": "30"
} | divide(multiply(108.0, const_100), 360) | multiply(n1,const_100)|divide(#0,n0)| | "? % of 360 = 108.0 or , ? = 108.0 × 100 / 360 = 30 answer e" | gain |
math_qa__SdikYN8TqfyHD2cu | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 175, then how much amount should C pay as his share of rent? Choose the correct choice from the following options.
A) 40
B) 45
C) 49
D) 51
E) 43 | <gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">70 + 60</gadget>
<output>130</output>
<gadget id="calculator">130 + 45</gadget>
<output>175</output>
<gadget id="calculator">45 / 175</gadget>
<output>9/35 = around 0.257143</output>
<gadget id="calculator">175 * (9/35)</gadget>
<output>45</output>
<result>B</result> | B | 45 | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 175, then how much amount should C pay as his share of rent? | {
"A": "40",
"B": "45",
"C": "49",
"D": "51",
"E": "43"
} | multiply(175, divide(multiply(15, 3), add(add(multiply(10, 7), multiply(12, 5)), multiply(15, 3)))) | multiply(n4,n5)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|add(#3,#0)|divide(#0,#4)|multiply(n6,#5)| | "a : b : c = 10 × 7 : 12 × 5 : 15 × 3 = 2 × 7 : 12 × 1 : 3 × 3 = 14 : 12 : 9 amount that c should pay = 175 × ( 9 / 35 ) = 5 × 9 = 45 answer is b ." | general |
math_qa__emkAexM3ArEkgbjx | A grocer purchased a quantity of bananas at 3 pounds for $0.50 and sold the entire quantity at 4 pounds for $1.00. How many pounds did the grocer purchase if the profit from selling the bananas was $7.00? Choose the correct choice from the following choices: A) 40 B) 84 C) 90 D) 120 E) 240 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">0.5 / 3</gadget>
<output>0.166667</output>
<gadget id="calculator">(1/4) - 0.166667</gadget>
<output>0.083333</output>
<gadget id="calculator">7 / 0.083333</gadget>
<output>84.000336</output>
<result>B</result> | B | 84 | A grocer purchased a quantity of bananas at 3 pounds for $0.50 and sold the entire quantity at 4 pounds for $1.00. How many pounds did the grocer purchase if the profit from selling the bananas was $7.00? | {
"A": "40",
"B": "84",
"C": "90",
"D": "120",
"E": "240"
} | divide(7, subtract(divide(1, 4), divide(0.5, const_3))) | divide(n3,n2)|divide(n1,const_3)|subtract(#0,#1)|divide(n4,#2) | cost price of 1 pound of bananas = 0.5 / 3 = 1 / 6 selling price of 1 pound of bananas = 1 / 4 profit per pound = ( 1 / 4 - 1 / 6 ) = ( 1 / 12 ) total profit is given as 7 ( 1 / 12 ) * x = 7 x = 84 answer : b | gain |
math_qa__SFqHdh7AjqlCHeFw | In a triangle ABC,point D is on side AB and point E is on side AC,such that BCED is a trapezium.DE:BC =3:5.Calculate the ratio of the area of triangle ADE and the trapezium BCED. Choices:
A) 9 / 16
B) 8 / 16
C) 7 / 16
D) 6 / 16
E) 5 / 16 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 9</gadget>
<output>16</output>
<gadget id="calculator">9 / 16</gadget>
<output>9/16 = around 0.5625</output>
<result>A</result> | A | 0.5625 | In a triangle ABC,point D is on side AB and point E is on side AC,such that BCED is a trapezium.DE:BC =3:5.Calculate the ratio of the area of triangle ADE and the trapezium BCED. | {
"A": "9 / 16",
"B": "8 / 16",
"C": "7 / 16",
"D": "6 / 16",
"E": "5 / 16"
} | divide(power(3, const_2), subtract(power(5, const_2), power(3, const_2))) | power(n0,const_2)|power(n1,const_2)|subtract(#1,#0)|divide(#0,#2) | area of tri ( ade ) / area of tri ( abc ) = de ^ 2 / bc ^ 2 since tri ( ade ) - tri ( abc ) area of tri ( ade ) / area of tri ( abc ) = 9 / 25 area of tri ( abc ) / area of tri ( ade ) = 25 / 9 area of tri ( abc ) = area of tri ( ade ) + area of trap ( bcde ) ( area of tri ( ade ) + area of trap ( bcde ) ) / area of tri ( ade ) = 25 / 9 1 + area of trap ( bcde ) / area of tri ( ade ) = 25 / 9 take 1 on both sides area of trap ( bcde ) / area of tri ( ade ) = ( 25 / 9 ) - 1 = 16 / 9 since question is asking for area of tri ( ade ) / area of trap ( bcde ) = 9 / 16 answer : a | geometry |
math_qa__7bGn1Fx4P0RXQdPS | 96% of the population of a village is 23040. The total population of the village is?
Choose the correct choice from the following options: A) 26799 B) 24000 C) 26682 D) 29973 E) 12312 | <gadget id="calculator">100 / 96</gadget>
<output>25/24 = around 1.041667</output>
<gadget id="calculator">(25/24) * 23_040</gadget>
<output>24_000</output>
<result>B</result> | B | 24,000 | 96% of the population of a village is 23040. The total population of the village is? | {
"A": "26799",
"B": "24000",
"C": "26682",
"D": "29973",
"E": "12312"
} | multiply(divide(const_100, 96), 23040) | divide(const_100,n0)|multiply(n1,#0)| | "x * ( 96 / 100 ) = 23040 x = 240 * 100 x = 24000 answer : b" | general |
math_qa__QlhNmh9bIDH0tjB8 | Solve the equation for x : 6x - 87 + 3x = 4 + 9 - x Options:
A) 12 B) 5 C) 10 D) 9 E) 3 | <gadget id="calculator">87 + 4</gadget>
<output>91</output>
<gadget id="calculator">3 + 6</gadget>
<output>9</output>
<gadget id="calculator">91 / 9</gadget>
<output>91/9 = around 10.111111</output>
<result>C</result> | C | 10 | Solve the equation for x : 6x - 87 + 3x = 4 + 9 - x | {
"A": "12",
"B": "5",
"C": "10",
"D": "9",
"E": "3"
} | divide(add(87, 4), add(3, 6)) | add(n1,n3)|add(n2,n0)|divide(#0,#1)| | "c 10 9 x + x = 13 + 87 10 x = 100 = > x = 10" | general |
math_qa__IFuXY4nxdNdaunE8 | The average monthly salary of 20 employees in an organisation is Rs. 1200. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ? Choose the correct choice from the following options
A) 3600
B) 3890
C) 3300
D) 2789
E) 2891 | <gadget id="calculator">1_200 + 100</gadget>
<output>1_300</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">1_300 * 21</gadget>
<output>27_300</output>
<gadget id="calculator">1_200 * 20</gadget>
<output>24_000</output>
<gadget id="calculator">27_300 - 24_000</gadget>
<output>3_300</output>
<result>C</result> | C | 3,300 | The average monthly salary of 20 employees in an organisation is Rs. 1200. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ? | {
"A": "3600",
"B": "3890",
"C": "3300",
"D": "2789",
"E": "2891"
} | subtract(multiply(add(1200, 100), add(20, const_1)), multiply(1200, 20)) | add(n1,n2)|add(n0,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "explanation : manager ' s monthly salary rs . ( 1300 * 21 - 1200 * 20 ) = rs . 3300 . answer : c" | general |
math_qa__RdqlT7EM66Bi1RQF | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 141, what is the difference between the ages of Patrick and Monica? Choose one
A) 27 B) 48 C) 45 D) 72 E) 18 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">9 + 15</gadget>
<output>24</output>
<gadget id="calculator">24 + 25</gadget>
<output>49</output>
<gadget id="calculator">141 / 49</gadget>
<output>141/49 = around 2.877551</output>
<gadget id="calculator">25 * (141/49)</gadget>
<output>3_525/49 = around 71.938776</output>
<gadget id="calculator">9 * (141/49)</gadget>
<output>1_269/49 = around 25.897959</output>
<gadget id="calculator">(3_525/49) - (1_269/49)</gadget>
<output>2_256/49 = around 46.040816</output>
<result>B</result> | B | 48 | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 141, what is the difference between the ages of Patrick and Monica? | {
"A": "27",
"B": "48",
"C": "45",
"D": "72",
"E": "18"
} | subtract(multiply(multiply(5, 5), divide(141, add(add(multiply(3, 3), multiply(3, 5)), multiply(5, 5)))), multiply(multiply(3, 3), divide(141, add(add(multiply(3, 3), multiply(3, 5)), multiply(5, 5))))) | multiply(n0,n0)|multiply(n1,n0)|multiply(n1,n3)|add(#0,#1)|add(#3,#2)|divide(n4,#4)|multiply(#5,#2)|multiply(#5,#0)|subtract(#6,#7)| | "ages of p and mi = 3 x + 5 x ages of mi and mo = 3 x : 5 x rationalizing their ages . ratio of their ages will be 9 x : 15 x : 25 x sum = 47 x = 141 x = 3 difference if ages of pa and mo = 25 x - 9 x = 16 x = 16 * 3 = 48 answer b" | general |
math_qa__QsPhr5jGVRvJlMCe | There are 408 boys and 288 girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed. Pick one: A) 31 B) 32 C) 35 D) 30 E) 29 | <gadget id="calculator">408 + 288</gadget>
<output>696</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">696 / 24</gadget>
<output>29</output>
<result>E</result> | E | 29 | There are 408 boys and 288 girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed. | {
"A": "31",
"B": "32",
"C": "35",
"D": "30",
"E": "29"
} | divide(add(408, 288), multiply(multiply(multiply(const_2, const_2), const_2), const_3)) | add(n0,n1)|multiply(const_2,const_2)|multiply(#1,const_2)|multiply(#2,const_3)|divide(#0,#3) | explanation : hcf ( 408 , 288 ) = 24 the number of boys or girls that can be placed in a section = 24 . thus the total number of sections is given by 408 / 24 + 288 / 24 = 17 + 12 = 29 answer : e | general |
math_qa__Ck0TlWBGEESCvhVF | If a no. when divided by 44, gives 432 as quotient and 0 as remainder. What will be the remainder when dividing the same no. by 35 Pick.
A) 1
B) 3
C) 5
D) 7
E) 9 | <gadget id="calculator">432 * 44</gadget>
<output>19_008</output>
<gadget id="calculator">19_008 % 35</gadget>
<output>3</output>
<result>B</result> | B | 3 | If a no. when divided by 44, gives 432 as quotient and 0 as remainder. What will be the remainder when dividing the same no. by 35 | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | reminder(multiply(432, 44), 35) | multiply(n0,n1)|reminder(#0,n3)| | "p ã · 44 = 432 = > p = 432 * 44 = 19008 p / 35 = 19008 / 35 = 543 , remainder = 3 b" | general |
math_qa__0UYBjPy6aTrAhz34 | In how many years will a sum of money doubles itself at 5% per annum on simple interest?
Select: A) 33 B) 20 C) 88 D) 66 E) 21 | <gadget id="calculator">100 / 5</gadget>
<output>20</output>
<result>B</result> | B | 20 | In how many years will a sum of money doubles itself at 5% per annum on simple interest? | {
"A": "33",
"B": "20",
"C": "88",
"D": "66",
"E": "21"
} | divide(const_100, 5) | divide(const_100,n0)| | "p = ( p * 5 * r ) / 100 r = 20 % answer : b" | gain |
math_qa__dhJ3qDU1P56It2bY | How many different ways can 2 students be seated in a row of 7 desks, so that there is always at least one empty desk between the students? Choose one
A) 2 B) 3 C) 30 D) 6 E) 12 | <gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">factorial(6) / factorial(6 - 2)</gadget>
<output>30</output>
<result>C</result> | C | 30 | How many different ways can 2 students be seated in a row of 7 desks, so that there is always at least one empty desk between the students? | {
"A": "2",
"B": "3",
"C": "30",
"D": "6",
"E": "12"
} | permutation(subtract(7, const_1), 2) | subtract(n1,const_1)|permutation(#0,n0) | 15 ways to seat the students : with two empty seats between 1 empty w / one student on the left most 1 empty . . . . right most two students can be interchanged 15 x 2 = 30 c | probability |
math_qa__5SRic0DL58PzhXf5 | What is the greatest possible length which can be used to measure exactly the lengths 180 m, 500 m and 15m 20 cm?
Choose the correct answer
A) 80 cm
B) 50 cm
C) 40 cm
D) 10 cm
E) 100 cm | <gadget id="calculator">20 * 4</gadget>
<output>80</output>
<result>A</result> | A | 80 | What is the greatest possible length which can be used to measure exactly the lengths 180 m, 500 m and 15m 20 cm? | {
"A": "80 cm",
"B": "50 cm",
"C": "40 cm",
"D": "10 cm",
"E": "100 cm"
} | multiply(20, const_4) | multiply(n3,const_4) | required length = hcf of 18000 cm , 50000 cm , 1520 cm = 80 cm answer is a | physics |
math_qa__kAihwVDm6k2rL9qm | If radius of a circle is diminished by 10% then its area is diminished by
Choose the correct choice from the following answers:
A) 22 B) 19 C) 877 D) 26 E) 271 | <gadget id="calculator">pi * (1 ** 2)</gadget>
<output>pi = around 3.141593</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">pi * ((9/10) ** 2)</gadget>
<output>81*pi/100 = around 2.54469</output>
<gadget id="calculator">pi - (81*pi/100)</gadget>
<output>19*pi/100 = around 0.596903</output>
<gadget id="calculator">(19*pi/100) / pi</gadget>
<output>19/100 = around 0.19</output>
<gadget id="calculator">(19/100) * 100</gadget>
<output>19</output>
<result>B</result> | B | 19 | If radius of a circle is diminished by 10% then its area is diminished by | {
"A": "22",
"B": "19",
"C": "877",
"D": "26",
"E": "271"
} | multiply(divide(subtract(circle_area(const_1), circle_area(subtract(const_1, divide(10, const_100)))), circle_area(const_1)), const_100) | circle_area(const_1)|divide(n0,const_100)|subtract(const_1,#1)|circle_area(#2)|subtract(#0,#3)|divide(#4,#0)|multiply(#5,const_100) | explanation : let old radius = 10 units . new radius is diminshed by 10 % . so new radius = 90 % ( 10 ) = 9 units . old area = π × r 2 = 100 π new area = π × 92 = 81 π change = 19 π / 100 π × 100 = 19 % answer : b | geometry |
math_qa__XDHVTS2dOjqiMpAa | The ratio of the areas of two squares, one having double its diagonal then the other is: Choose the correct choice:
A) 2 : 1
B) 1 : 2
C) 2 : 3
D) 1 : 4
E) 4 : 1 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 4</gadget>
<output>2</output>
<gadget id="calculator">2 / (1/2)</gadget>
<output>4</output>
<result>E</result> | E | 4 | The ratio of the areas of two squares, one having double its diagonal then the other is: | {
"A": "2 : 1",
"B": "1 : 2",
"C": "2 : 3",
"D": "1 : 4",
"E": "4 : 1"
} | divide(multiply(inverse(const_2), const_4), inverse(const_2)) | inverse(const_2)|multiply(#0,const_4)|divide(#1,#0) | lenth of the diagonals be 2 x and x units . areas are 1 / 2 × ( 2 x ) power 2 and ( 1 / 2 × ( xpower 2 ) ) required ratio = 1 / 2 × 4 x 2 : 1 / 2 x 2 = 4 : 1 answer is e . | geometry |
math_qa__Q68x8ieYoPZvOfGV | A group of people participate in some curriculum, 25 of them practice Yoga, 15 study cooking, 8 study weaving, 2 of them study cooking only, 7 of them study both the cooking and yoga, 3 of them participate all curriculums. How many people study both cooking and weaving?
Choose the correct answer:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">15 - 7</gadget>
<output>8</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<result>C</result> | C | 3 | A group of people participate in some curriculum, 25 of them practice Yoga, 15 study cooking, 8 study weaving, 2 of them study cooking only, 7 of them study both the cooking and yoga, 3 of them participate all curriculums. How many people study both cooking and weaving? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(subtract(subtract(15, 7), 3), 2) | subtract(n1,n4)|subtract(#0,n5)|subtract(#1,n3) | both cooking and weaving = 15 - ( 2 + 3 + 7 ) = 3 so , the correct answer is c . | other |
math_qa__uEjtftXSJV0FHIfp | A car travels first 160 km at 70 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour? Pick one:
A) 71.11 B) 71.12 C) 71.1 D) 74.66 E) 71.13 | <gadget id="calculator">160 / 70</gadget>
<output>16/7 = around 2.285714</output>
<gadget id="calculator">160 / 80</gadget>
<output>2</output>
<gadget id="calculator">(16/7) + 2</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">1 / (30/7)</gadget>
<output>7/30 = around 0.233333</output>
<gadget id="calculator">320 * (7/30)</gadget>
<output>224/3 = around 74.666667</output>
<result>D</result> | D | 74.66 | A car travels first 160 km at 70 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour? | {
"A": "71.11",
"B": "71.12",
"C": "71.1",
"D": "74.66",
"E": "71.13"
} | multiply(320, divide(const_1, add(divide(160, 70), divide(160, 80)))) | divide(n0,n1)|divide(n0,n3)|add(#0,#1)|divide(const_1,#2)|multiply(n4,#3)| | "car travels first 160 km at 70 km / hr time taken to travel first 160 km = distancespeed = 160 / 70 car travels next 160 km at 80 km / hr time taken to travel next 160 km = distancespeed = 160 / 80 total distance traveled = 160 + 160 = 2 × 160 total time taken = 160 / 70 + 160 / 80 average speed = total distance traveled / total time taken = 320 / ( 160 / 70 + 160 / 80 ) = 74.66 km / hr answer : d" | general |
math_qa__iqoU3Mh6b4j8qKxJ | In an election, candidate A got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favor of candidate. Pick
A) 330000 B) 340000 C) 347000 D) 356000 E) 357000 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">560_000 * (17/20)</gadget>
<output>476_000</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">476_000 * (3/4)</gadget>
<output>357_000</output>
<result>E</result> | E | 357,000 | In an election, candidate A got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favor of candidate. | {
"A": "330000",
"B": "340000",
"C": "347000",
"D": "356000",
"E": "357000"
} | multiply(multiply(560000, subtract(const_1, divide(15, const_100))), divide(75, const_100)) | divide(n0,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(n2,#2)|multiply(#0,#3)| | "total number of invalid votes = 15 % of 560000 = 15 / 100 × 560000 = 8400000 / 100 = 84000 total number of valid votes 560000 – 84000 = 476000 percentage of votes polled in favour of candidate a = 75 % therefore , the number of valid votes polled in favour of candidate a = 75 % of 476000 = 75 / 100 × 476000 = 35700000 / 100 = 357000 e )" | gain |
math_qa__yDy5xwvIlcPnLTBo | Joe’s average (arithmetic mean) test score across 4 equally weighted tests was 90. He was allowed to drop his lowest score. After doing so, his average test score improved to 95. What is the lowest test score that was dropped? Choose the correct choice from the following choices:
A) 20 B) 25 C) 55 D) 75 E) 80 | <gadget id="calculator">90 * 4</gadget>
<output>360</output>
<gadget id="calculator">95 * 3</gadget>
<output>285</output>
<gadget id="calculator">360 - 285</gadget>
<output>75</output>
<result>D</result> | D | 75 | Joe’s average (arithmetic mean) test score across 4 equally weighted tests was 90. He was allowed to drop his lowest score. After doing so, his average test score improved to 95. What is the lowest test score that was dropped? | {
"A": "20",
"B": "25",
"C": "55",
"D": "75",
"E": "80"
} | subtract(multiply(90, 4), multiply(95, const_3)) | multiply(n0,n1)|multiply(n2,const_3)|subtract(#0,#1)| | "the arithmetic mean of 4 equally weighted tests was 90 . so what we can assume is that we have 4 test scores , each 90 . he dropped his lowest score and the avg went to 95 . this means that the lowest score was not 90 and other three scores had given the lowest score 5 each to make it up to 90 too . when the lowest score was removed , the other 3 scores got their 5 back . so the lowest score was 3 * 5 = 15 less than 90 . so the lowest score = 90 - 15 = 75 answer ( d )" | general |
math_qa__sO47zoa6fayNGmlM | John found that the average of 15 numbers is 40. If 15 is added to each number then the mean of number is? Choices.
A) 55 B) 45 C) 65 D) 78 E) 64 | <gadget id="calculator">40 + 15</gadget>
<output>55</output>
<result>A</result> | A | 55 | John found that the average of 15 numbers is 40. If 15 is added to each number then the mean of number is? | {
"A": "55",
"B": "45",
"C": "65",
"D": "78",
"E": "64"
} | add(40, 15) | add(n1,n2)| | "( x + x 1 + . . . x 14 ) / 15 = 40 55 option a" | general |
math_qa__hvSROulcl0fbF9i3 | scott ' s average ( arithmetic mean ) golf score on his first 4 rounds was 78 . what score does he need on his fifth round to drop his average score by 2 points ? Choose the correct choice from the following answers:
A) 68 B) 72 C) 78 D) 88 E) 312 | <gadget id="calculator">78 - 2</gadget>
<output>76</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">76 * 5</gadget>
<output>380</output>
<gadget id="calculator">4 * 78</gadget>
<output>312</output>
<gadget id="calculator">380 - 312</gadget>
<output>68</output>
<result>A</result> | A | 68 | scott ' s average ( arithmetic mean ) golf score on his first 4 rounds was 78 . what score does he need on his fifth round to drop his average score by 2 points ? | {
"A": "68",
"B": "72",
"C": "78",
"D": "88",
"E": "312"
} | subtract(multiply(subtract(78, 2), add(4, const_1)), multiply(4, 78)) | add(n0,const_1)|multiply(n0,n1)|subtract(n1,n2)|multiply(#0,#2)|subtract(#3,#1) | average score for first 4 rounds = 78 average score after 5 rounds = 76 score scott needs on his 5 th round to drop average score by 2 points = 78 - ( 2 * 5 ) = 68 answer a alternatively , sum of scores of first 4 rounds = 78 * 4 = 312 sum of scores after 5 rounds = 76 * 5 = 380 score scott needs on his 5 th round to drop average score by 2 points = 380 - 312 = 68 answer a | general |
math_qa__sxhUbE2pKJu6bpDk | in 15 year ’ s time the combined age of my 4 brothers will be 107 . what will it be in the 6 year ’ s time ? Choose the most appropriate option.
A) 61
B) 78
C) 71
D) 68
E) 94 | <gadget id="calculator">15 * 4</gadget>
<output>60</output>
<gadget id="calculator">107 - 60</gadget>
<output>47</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">47 + 24</gadget>
<output>71</output>
<result>C</result> | C | 71 | in 15 year ’ s time the combined age of my 4 brothers will be 107 . what will it be in the 6 year ’ s time ? | {
"A": "61",
"B": "78",
"C": "71",
"D": "68",
"E": "94"
} | add(subtract(107, multiply(15, 4)), multiply(6, 4)) | multiply(n1,n3)|multiply(n0,n1)|subtract(n2,#1)|add(#0,#2) | c 71 combined age in 15 years = 107 . 4 × 15 = 60 , therefore combined age now is 107 – 60 = 47 . in 6 years time , therefore , combined age will be 47 + 24 ( 4 x 6 ) = 71 . | probability |
math_qa__vQsQy0UxoX8NEbVs | A, B and C have Rs.600 between them, A and C together have Rs.250 and B and C Rs.450. How much does C have? Choose the correct choice from the following: A) 70 B) 90 C) 120 D) 100 E) 140 | <gadget id="calculator">250 + 450</gadget>
<output>700</output>
<gadget id="calculator">700 - 600</gadget>
<output>100</output>
<result>D</result> | D | 100 | A, B and C have Rs.600 between them, A and C together have Rs.250 and B and C Rs.450. How much does C have? | {
"A": "70",
"B": "90",
"C": "120",
"D": "100",
"E": "140"
} | subtract(add(250, 450), 600) | add(n1,n2)|subtract(#0,n0)| | "a + b + c = 600 a + c = 250 b + c = 450 - - - - - - - - - - - - - - a + b + 2 c = 700 a + b + c = 600 - - - - - - - - - - - - - - - - c = 100 answer : d" | general |
math_qa__EZu5nwkSL9XZTm6O | A store reduced the price of all items in the store by 15% on the first day and by another 10% on the second day. The price of items on the second day was what percent of the price before the first reduction took place?
Choose one: A) 76.5 B) 80.9 C) 81.0 D) 81.1 E) 81.9 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(17/20) * (9/10)</gadget>
<output>153/200 = around 0.765</output>
<gadget id="calculator">(153/200) * 100</gadget>
<output>153/2 = around 76.5</output>
<result>A</result> | A | 76.5 | A store reduced the price of all items in the store by 15% on the first day and by another 10% on the second day. The price of items on the second day was what percent of the price before the first reduction took place? | {
"A": "76.5",
"B": "80.9",
"C": "81.0",
"D": "81.1",
"E": "81.9"
} | multiply(multiply(divide(subtract(const_100, 15), const_100), divide(subtract(const_100, 10), const_100)), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|multiply(#4,const_100)| | "consider price of the all items as $ 100 after a initial reduction of 15 % price becomes = 0.85 * 100 = $ 85 after the final reduction of 10 % price becomes = 0.9 * 85 = $ 76.5 price of all items on second day is 76.5 % of price on first day correct answer option a" | gain |
math_qa__9MrxYOYtimaYrnLF | Find the area of the quadrilateral of one of its diagonals is 40 cm and its off sets 9 cm and 6 cm?
Answers:
A) 189 cm 2 B) 300 cm 2 C) 127 cm 2 D) 177 cm 2 E) 187 cm 2 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">6 + 9</gadget>
<output>15</output>
<gadget id="calculator">(1/2) * 15</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 40</gadget>
<output>300</output>
<result>B</result> | B | 300 | Find the area of the quadrilateral of one of its diagonals is 40 cm and its off sets 9 cm and 6 cm? | {
"A": "189 cm 2",
"B": "300 cm 2",
"C": "127 cm 2",
"D": "177 cm 2",
"E": "187 cm 2"
} | multiply(multiply(divide(const_1, const_2), add(6, 9)), 40) | add(n1,n2)|divide(const_1,const_2)|multiply(#0,#1)|multiply(n0,#2) | 1 / 2 * 40 ( 9 + 6 ) = 300 cm 2 answer : b | geometry |
math_qa__JuQX2NL1t3ogQuAX | An equal number of desks and bookcases are to be placed along a library wall that is 15 meters long. Each desk is 2 meters long, and each bookshelf is 1.5 meters long. If the maximum possible number of desks and bookcases are to be placed along the wall, then the space along the wall that is left over will be how many meters K long? Pick one: A) 0.5 B) 1 C) 1.5 D) 2 E) 3 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">4 * 1.5</gadget>
<output>6</output>
<gadget id="calculator">8 + 6</gadget>
<output>14</output>
<gadget id="calculator">15 - 14</gadget>
<output>1</output>
<result>B</result> | B | 1 | An equal number of desks and bookcases are to be placed along a library wall that is 15 meters long. Each desk is 2 meters long, and each bookshelf is 1.5 meters long. If the maximum possible number of desks and bookcases are to be placed along the wall, then the space along the wall that is left over will be how many meters K long? | {
"A": "0.5",
"B": "1",
"C": "1.5",
"D": "2",
"E": "3"
} | subtract(15, add(multiply(const_4, 2), multiply(const_4, 1.5))) | multiply(n1,const_4)|multiply(n2,const_4)|add(#0,#1)|subtract(n0,#2)| | "let x be the number of desks and bookcases that are placed along the library wall . 2 x + 1.5 x < 15 3.5 x < 15 since x is a non negative integer , the largest number x can be is 4 . when x is 4 , the desks and bookcases take up 3.5 * 4 = 14 m = k , leaving 1 m of empty space . thus , i believe the answer is b ) 1" | general |
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