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math_qa__YJALcvlamKWibtQm | Find the area of a parallelogram with base 18 cm and height 10 cm? Select the correct option
A) 281 B) 284 C) 288 D) 255 E) 180 | <gadget id="calculator">18 * 10</gadget>
<output>180</output>
<result>E</result> | E | 180 | Find the area of a parallelogram with base 18 cm and height 10 cm? | {
"A": "281",
"B": "284",
"C": "288",
"D": "255",
"E": "180"
} | multiply(18, 10) | multiply(n0,n1)| | "area of a parallelogram = base * height = 18 * 10 = 180 cm 2 answer : e" | geometry |
math_qa__XGpXiOnVucuv8BiN | The parameter of a square is equal to the perimeter of a rectangle of length 24 cm and breadth 16 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places) Answers:
A) 77.14 cm
B) 47.14 cm
C) 84.92 cm
D) 94.94 cm
E) 31.42 cm | <gadget id="calculator">2 * (24 + 16)</gadget>
<output>80</output>
<gadget id="calculator">80 / 4</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">2 * pi * 10</gadget>
<output>20*pi = around 62.831853</output>
<gadget id="calculator">(20*pi) / 2</gadget>
<output>10*pi = around 31.415927</output>
<result>E</result> | E | 31.42 | The parameter of a square is equal to the perimeter of a rectangle of length 24 cm and breadth 16 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places) | {
"A": "77.14 cm",
"B": "47.14 cm",
"C": "84.92 cm",
"D": "94.94 cm",
"E": "31.42 cm"
} | divide(circumface(divide(square_edge_by_perimeter(rectangle_perimeter(24, 16)), const_2)), const_2) | rectangle_perimeter(n0,n1)|square_edge_by_perimeter(#0)|divide(#1,const_2)|circumface(#2)|divide(#3,const_2)| | "let the side of the square be a cm . parameter of the rectangle = 2 ( 24 + 16 ) = 80 cm parameter of the square = 80 cm i . e . 4 a = 80 a = 20 diameter of the semicircle = 20 cm circimference of the semicircle = 1 / 2 ( ∏ ) ( 20 ) = 1 / 2 ( 22 / 7 ) ( 20 ) = 440 / 14 = 31.42 cm to two decimal places answer : e" | geometry |
math_qa__tZ9h8IJ2NB8SGRUR | acme ’ s manufacturing costs for sets of horseshoes include a $ 12450 initial outlay , and $ 20.75 per set . they can sell the sets $ 50 . if profit is revenue from sales minus manufacturing costs , and the company producessells 950 sets of horseshoes , what was their profit ? Choose the correct choice from the following answers
A) $ 15300 B) $ 14300 C) $ 15337.50 D) $ 16300 E) $ 15800 | <gadget id="calculator">50 - 20.75</gadget>
<output>29.25</output>
<gadget id="calculator">950 * 29.25</gadget>
<output>27_787.5</output>
<gadget id="calculator">27_787.5 - 12_450</gadget>
<output>15_337.5</output>
<result>C</result> | C | 15,337.5 | acme ’ s manufacturing costs for sets of horseshoes include a $ 12450 initial outlay , and $ 20.75 per set . they can sell the sets $ 50 . if profit is revenue from sales minus manufacturing costs , and the company producessells 950 sets of horseshoes , what was their profit ? | {
"A": "$ 15300",
"B": "$ 14300",
"C": "$ 15337.50",
"D": "$ 16300",
"E": "$ 15800"
} | subtract(multiply(950, subtract(50, 20.75)), 12450) | subtract(n2,n1)|multiply(n3,#0)|subtract(#1,n0) | total manufacturing cost = 12,450 + 950 * 20.75 = 32162.5 total selling cost = 950 * 50 = 47500 profit = 47500 - 32162.50 = 15337.50 answer : c | gain |
math_qa__UIGBRf4vLWxU655D | The average of 9 numbers is 104. Average of the first 5 of them is 99 and that of the last 5 is 100. Find the 5th number? Pick:
A) 46 B) 59 C) 63 D) 75 E) 88 | <gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">9 * 104</gadget>
<output>936</output>
<gadget id="calculator">99 * 5</gadget>
<output>495</output>
<gadget id="calculator">936 - 495</gadget>
<output>441</output>
<gadget id="calculator">500 - 441</gadget>
<output>59</output>
<result>B</result> | B | 59 | The average of 9 numbers is 104. Average of the first 5 of them is 99 and that of the last 5 is 100. Find the 5th number? | {
"A": "46",
"B": "59",
"C": "63",
"D": "75",
"E": "88"
} | subtract(multiply(5, 100), subtract(multiply(9, 104), multiply(99, 5))) | multiply(n5,n6)|multiply(n0,n1)|multiply(n2,n3)|subtract(#1,#2)|subtract(#0,#3)| | sum of all the 9 numbers = 9 * 104 = 936 sum of the first 5 of them = 5 * 99 = 495 sum of the last 5 of them = 5 * 100 = 500 so , the 5 th number = 495 + 500 - 936 = 59 . answer : b | general |
math_qa__dgsjocjYedlUlcXE | The cash realised on selling a 14% stock is Rs.101.25, brokerage being 1/4% is Select:
A) 123
B) 106
C) 100
D) 101
E) 240 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">101.25 - (1/4)</gadget>
<output>101</output>
<result>D</result> | D | 101 | The cash realised on selling a 14% stock is Rs.101.25, brokerage being 1/4% is | {
"A": "123",
"B": "106",
"C": "100",
"D": "101",
"E": "240"
} | subtract(101.25, divide(1, 4)) | divide(n2,n3)|subtract(n1,#0)| | "explanation : cash realised = rs . ( 101.25 - 0.25 ) = rs . 101 . answer : d" | general |
math_qa__Ntg22a6jEMjYMTqG | In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by: Choose the correct choice from the following:
A) 60 m
B) 20 m
C) 43 m
D) 20 m
E) 23 m | <gadget id="calculator">500 - 140</gadget>
<output>360</output>
<gadget id="calculator">360 * 4</gadget>
<output>1_440</output>
<gadget id="calculator">1_440 / 3</gadget>
<output>480</output>
<gadget id="calculator">500 - 480</gadget>
<output>20</output>
<result>D</result> | D | 20 | In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by: | {
"A": "60 m",
"B": "20 m",
"C": "43 m",
"D": "20 m",
"E": "23 m"
} | subtract(500, divide(multiply(subtract(500, 140), 4), 3)) | subtract(n0,n3)|multiply(n2,#0)|divide(#1,n1)|subtract(n0,#2)| | "to reach the winning post a will have to cover a distance of ( 500 - 140 ) m , i . e . , 360 m . while a covers 3 m , b covers 4 m . while a covers 360 m , b covers 4 x 360 m = 480 m . 3 thus , when a reaches the winning post , b covers 480 m and therefore remains 20 m behind . a wins by 20 m . answer : d" | physics |
math_qa__QPtHLlpE2e6WrCeY | Tom read a book containing 100 pages by reading the same number of pages each day. If he would have finished the book 10 days earlier by reading 30 pages a day more, how many days did Tom spend reading the book? Choose the correct choice from the following: A) 7 B) 7.68 C) 8 D) 9 E) 10 | <gadget id="calculator">30 * 10</gadget>
<output>300</output>
<gadget id="calculator">300 * 4</gadget>
<output>1_200</output>
<gadget id="calculator">30 ** 2</gadget>
<output>900</output>
<gadget id="calculator">1_200 + 900</gadget>
<output>2_100</output>
<gadget id="calculator">2_100 ** (1/2)</gadget>
<output>10*sqrt(21) = around 45.825757</output>
<gadget id="calculator">(10*sqrt(21)) - 30</gadget>
<output>-30 + 10*sqrt(21) = around 15.825757</output>
<gadget id="calculator">(-30 + 10*sqrt(21)) / 2</gadget>
<output>-15 + 5*sqrt(21) = around 7.912878</output>
<result>B</result> | B | 7.68 | Tom read a book containing 100 pages by reading the same number of pages each day. If he would have finished the book 10 days earlier by reading 30 pages a day more, how many days did Tom spend reading the book? | {
"A": "7",
"B": "7.68",
"C": "8",
"D": "9",
"E": "10"
} | divide(subtract(sqrt(add(multiply(multiply(30, 10), const_4), power(30, const_2))), 30), const_2) | multiply(n1,n2)|power(n2,const_2)|multiply(#0,const_4)|add(#2,#1)|sqrt(#3)|subtract(#4,n2)|divide(#5,const_2) | actually u can set up 2 equation p - - stands for the pages d - - stands for the days 1 ) p * d = 100 ( we want to find the days , sop = 100 / d ) 2 ) ( p + 30 ) ( d - 10 ) = 100 = > pd - 10 p + 30 d - 300 = 100 as the 1 ) stated u can put 1 ) into 2 ) = > 100 - 10 p + 30 d - 300 = 100 = > 30 d - 10 p = 100 put the bold one into it = > 30 d - 10 ( 100 / d ) = 100 the we get the final equation 30 d ^ 2 - 1000 = 100 d ( divide 16 ) = > d ^ 2 - 5 d - 150 = 0 ( d - 15 ) ( d + 10 ) = 0 so d = 7.68 days . ans : ( b ) | general |
math_qa__kco4jHTigxfVWevl | The speed of a boat in still water is 18 km/hr and the rate of current is 4 km/hr. The distance travelled downstream in 14 minutes is Choose the correct choice from the following options: A) 1.6 km B) 2 km C) 5.1 km D) 4 km E) none of these | <gadget id="calculator">14 / 60</gadget>
<output>7/30 = around 0.233333</output>
<gadget id="calculator">18 + 4</gadget>
<output>22</output>
<gadget id="calculator">(7/30) * 22</gadget>
<output>77/15 = around 5.133333</output>
<result>C</result> | C | 5.1 | The speed of a boat in still water is 18 km/hr and the rate of current is 4 km/hr. The distance travelled downstream in 14 minutes is | {
"A": "1.6 km",
"B": "2 km",
"C": "5.1 km",
"D": "4 km",
"E": "none of these"
} | multiply(divide(14, const_60), add(18, 4)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "explanation : speed downstreams = ( 18 + 4 ) kmph = 22 kmph . distance travelled = ( 22 x 14 / 60 ) km = 5.1 km option c" | physics |
math_qa__Fev42gFaEquojJoo | The present worth of Rs.169 due in 2 years at 4% per annum compound interest is Choose the correct option.
A) rs . 150.50 B) rs . 154.75 C) rs . 156.25 D) rs . 158 E) none | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) + 1</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">169 / (676/625)</gadget>
<output>625/4 = around 156.25</output>
<result>C</result> | C | 156.25 | The present worth of Rs.169 due in 2 years at 4% per annum compound interest is | {
"A": "rs . 150.50",
"B": "rs . 154.75",
"C": "rs . 156.25",
"D": "rs . 158",
"E": "none"
} | divide(169, power(add(divide(4, const_100), const_1), 2)) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|divide(n0,#2)| | "solution present worth = rs . [ 169 / ( 1 + 4 / 100 ) ² ] = rs . ( 169 x 25 / 26 x 25 / 26 ) = rs . 156.25 answer c" | gain |
math_qa__Rhajmz19mzy6mq0p | A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition. Choose the correct choice from the following options:
A) 87.8 % B) 87.9 % C) 37.8 % D) 87.7 % E) 22.8 % | <gadget id="calculator">600 + 400</gadget>
<output>1_000</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">600 * (3/20)</gadget>
<output>90</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">400 * (2/25)</gadget>
<output>32</output>
<gadget id="calculator">90 + 32</gadget>
<output>122</output>
<gadget id="calculator">1_000 - 122</gadget>
<output>878</output>
<gadget id="calculator">878 / 1_000</gadget>
<output>439/500 = around 0.878</output>
<gadget id="calculator">(439/500) * 100</gadget>
<output>439/5 = around 87.8</output>
<result>A</result> | A | 87.8 | A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition. | {
"A": "87.8 %",
"B": "87.9 %",
"C": "37.8 %",
"D": "87.7 %",
"E": "22.8 %"
} | multiply(divide(subtract(add(600, 400), add(multiply(600, divide(15, const_100)), multiply(400, divide(8, const_100)))), add(600, 400)), const_100) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|subtract(#0,#5)|divide(#6,#0)|multiply(#7,const_100)| | "otal number of fruits shopkeeper bought = 600 + 400 = 1000 number of rotten oranges = 15 % of 600 = 15 / 100 × 600 = 9000 / 100 = 90 number of rotten bananas = 8 % of 400 = 8 / 100 × 400 = 3200 / 100 = 32 therefore , total number of rotten fruits = 90 + 32 = 122 therefore number of fruits in good condition = 1000 - 122 = 878 therefore percentage of fruits in good condition = ( 878 / 1000 × 100 ) % = ( 87800 / 1000 ) % = 87.8 % answer : a" | gain |
math_qa__jC1YDvOljGknkJxz | Reema took a loan of Rs 1800 with simple interest for as many years as the rate of interest. If she paid Rs. 632 as interest at the end of the loan period, what was the rate of interest.
Pick one:
A) 5.925 %
B) 5.253 %
C) 7 %
D) 6.52 %
E) 5.200 % | <gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">632 / 18</gadget>
<output>316/9 = around 35.111111</output>
<gadget id="calculator">(316/9) ** (1/2)</gadget>
<output>2*sqrt(79)/3 = around 5.925463</output>
<result>A</result> | A | 5.925 | Reema took a loan of Rs 1800 with simple interest for as many years as the rate of interest. If she paid Rs. 632 as interest at the end of the loan period, what was the rate of interest. | {
"A": "5.925 %",
"B": "5.253 %",
"C": "7 %",
"D": "6.52 %",
"E": "5.200 %"
} | sqrt(divide(632, divide(1800, const_100))) | divide(n0,const_100)|divide(n1,#0)|sqrt(#1)| | "explanation : let rate = r % then time = r years . = > 1800 ∗ r ∗ r / 100 = 632 = > r 2 = 35.11 = > r = 5.925 % option a" | gain |
math_qa__10JxLZakvfEFdOl8 | 12 points lie on a circle. How many cyclic quadrilaterals can be drawn by using these points? Choose the correct choice from the following choices.
A) 334 B) 377 C) 495 D) 766 E) 261 | <gadget id="calculator">factorial(12)</gadget>
<output>479_001_600</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">24 * 40_320</gadget>
<output>967_680</output>
<gadget id="calculator">479_001_600 / 967_680</gadget>
<output>495</output>
<result>C</result> | C | 495 | 12 points lie on a circle. How many cyclic quadrilaterals can be drawn by using these points? | {
"A": "334",
"B": "377",
"C": "495",
"D": "766",
"E": "261"
} | divide(factorial(12), multiply(factorial(const_4), factorial(subtract(12, const_4)))) | factorial(n0)|factorial(const_4)|subtract(n0,const_4)|factorial(#2)|multiply(#1,#3)|divide(#0,#4) | explanation : for any set of 4 points we get a cyclic quadrilateral . number of ways of choosing 4 points out of 12 points is \ inline { \ color { black } 12 c _ 4 { } } = 495 . therefore , we can draw 495 quadrilaterals answer : c ) 495 | geometry |
math_qa__ot4Y3sReD2bZFiX2 | Farm Tax is levied on the 75% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. william. Mr. william paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is : Choose the correct choice from the following options
A) 15 %
B) 25 %
C) 0.125 %
D) 0.2083 %
E) 16.667 % | <gadget id="calculator">480 / 3_840</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 100</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 100</gadget>
<output>1_250</output>
<gadget id="calculator">1_250 / 75</gadget>
<output>50/3 = around 16.666667</output>
<result>E</result> | E | 16.667 | Farm Tax is levied on the 75% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. william. Mr. william paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is : | {
"A": "15 %",
"B": "25 %",
"C": "0.125 %",
"D": "0.2083 %",
"E": "16.667 %"
} | divide(multiply(multiply(divide(480, 3840), const_100), const_100), 75) | divide(n2,n1)|multiply(#0,const_100)|multiply(#1,const_100)|divide(#2,n0)| | "this will be equal to the percentage of total cultivated land he holds over the total cultivated land in the village . that leads to ( 480 / 3840 ) x 100 = 12.5 % in percentage terms . but the question asks ratio between his total land to total cultivated land . hence the answer is 12.5 % x ( 100 / 75 ) = 16.667 % the correct answer is ( e ) ." | general |
math_qa__Eu0Hgf5ABf8qz5PV | What is x if 2x - y = 14 and y = 2? Choose the correct choice from the following answers:
A) 6 B) 8 C) 10 D) 12 E) 14 | <gadget id="calculator">14 - 2</gadget>
<output>12</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<result>B</result> | B | 8 | What is x if 2x - y = 14 and y = 2? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "14"
} | subtract(subtract(14, 2), multiply(2, 2)) | multiply(n0,n0)|subtract(n1,n0)|subtract(#1,#0) | substitute y by 2 in 2 x - y = 14 2 x - 2 = 14 2 x = 16 if we substitute x by 8 , we have 2 ( 8 ) = 16 . hence x = 8 correct answer b | general |
math_qa__R0XX9adYLxjTDEan | the radius of the circle is reduced from 5cm to 4cm then the % change of area . Choose the correct answer
A) 36 % B) 37 % C) 35 % D) 38 % E) 39 % | <gadget id="calculator">pi * (4 ** 2)</gadget>
<output>16*pi = around 50.265482</output>
<gadget id="calculator">pi * (5 ** 2)</gadget>
<output>25*pi = around 78.539816</output>
<gadget id="calculator">(16*pi) / (25*pi)</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">100 * (16/25)</gadget>
<output>64</output>
<gadget id="calculator">100 - 64</gadget>
<output>36</output>
<result>A</result> | A | 36 | the radius of the circle is reduced from 5cm to 4cm then the % change of area . | {
"A": "36 %",
"B": "37 %",
"C": "35 %",
"D": "38 %",
"E": "39 %"
} | subtract(const_100, multiply(const_100, divide(circle_area(4), circle_area(5)))) | circle_area(n1)|circle_area(n0)|divide(#0,#1)|multiply(#2,const_100)|subtract(const_100,#3) | for 5 cm - > pi * r ^ 2 - - > 3.14 * 5 ^ 2 - > 78.539 for 4 cm - > pi * r ^ 2 - - > 3.14 * 4 ^ 2 - > 50.265 % change - > ( 1 - 50.265 / 78.539 ) * 100 = 36 ie 36 % answer : a | geometry |
math_qa__3RMHZqp9wkq1jHTf | In what time will a train 200 m long cross an electric pole, it its speed be 216 km/hr? Options
A) 2.5 sec B) 2.8 sec C) 8.5 sec D) 3.3 sec E) 4.5 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">216 * (5/18)</gadget>
<output>60</output>
<gadget id="calculator">200 / 60</gadget>
<output>10/3 = around 3.333333</output>
<result>D</result> | D | 3.3 | In what time will a train 200 m long cross an electric pole, it its speed be 216 km/hr? | {
"A": "2.5 sec",
"B": "2.8 sec",
"C": "8.5 sec",
"D": "3.3 sec",
"E": "4.5 sec"
} | divide(200, multiply(216, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 216 * 5 / 18 = 60 m / sec time taken = 200 / 60 = 3.3 sec . answer : d" | physics |
math_qa__nyLvv3WhElMVBg9m | if t = 1 / ( 1 * 2 ) + 1 / ( 2 * 3 ) + 1 / ( 3 * 4 ) + 1 / ( 4 * 5 ) + . . . . . . . . . 1 / [ n ( n + 1 ) ] , for some positive integer n , what is the smallest value of n such that t > 097 ? Options:
A) 29 B) 30 C) 31 D) 32 E) 33 | <gadget id="calculator">100 - 97</gadget>
<output>3</output>
<gadget id="calculator">97 / 3</gadget>
<output>97/3 = around 32.333333</output>
<result>E</result> | E | 33 | if t = 1 / ( 1 * 2 ) + 1 / ( 2 * 3 ) + 1 / ( 3 * 4 ) + 1 / ( 4 * 5 ) + . . . . . . . . . 1 / [ n ( n + 1 ) ] , for some positive integer n , what is the smallest value of n such that t > 097 ? | {
"A": "29",
"B": "30",
"C": "31",
"D": "32",
"E": "33"
} | divide(97, subtract(const_100, 97)) | subtract(const_100,n14)|divide(n14,#0) | we can break the t as : ( n + 1 - n ) / n ( n + 1 ) - - - - for n = 1 to n 1 / n - 1 / n + 1 plug value , 1,2 . . n we will get a pattern 1 - 1 / 2 - - - for 1 1 / 2 - 1 / 3 - - for 2 1 / 3 - 1 / 4 - - for 4 now work with options . . for 31 , t = 1 - 1 / 32 = 30 / 31 = 0.968 for 32 , t = 1 - 1 / 33 = 0,9696 for 33 , t = 1 - 1 / 34 = 33 / 34 - 0.97 so e is correct answer | general |
math_qa__f9JcW3OcaVwwmy2e | Jack and Jill work at a hospital with 6 other workers. For an internal review, 2 of the 8 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen? Choose the correct choice from the following answers
A) 1 / 3 B) 1 / 4 C) 1 / 15 D) 1 / 28 E) 2 / 3 | <gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">2 * 720</gadget>
<output>1_440</output>
<gadget id="calculator">40_320 / 1_440</gadget>
<output>28</output>
<gadget id="calculator">1 / 28</gadget>
<output>1/28 = around 0.035714</output>
<result>D</result> | D | 0.035714 | Jack and Jill work at a hospital with 6 other workers. For an internal review, 2 of the 8 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen? | {
"A": "1 / 3",
"B": "1 / 4",
"C": "1 / 15",
"D": "1 / 28",
"E": "2 / 3"
} | inverse(divide(factorial(8), multiply(factorial(2), factorial(6)))) | factorial(n2)|factorial(n1)|factorial(n0)|multiply(#1,#2)|divide(#0,#3)|inverse(#4)| | "1 / 8 c 2 = 1 / 28 . answer : d ." | physics |
math_qa__NvBBCsohM875TtbE | A pupil's marks were wrongly entered as 83 instead of 70. Due to the average marks for the class got increased by half. The number of pupils in the class is?
Choose one: A) 18 B) 82 C) 26 D) 27 E) 29 | <gadget id="calculator">83 - 70</gadget>
<output>13</output>
<gadget id="calculator">13 * 2</gadget>
<output>26</output>
<result>C</result> | C | 26 | A pupil's marks were wrongly entered as 83 instead of 70. Due to the average marks for the class got increased by half. The number of pupils in the class is? | {
"A": "18",
"B": "82",
"C": "26",
"D": "27",
"E": "29"
} | multiply(subtract(83, 70), const_2) | subtract(n0,n1)|multiply(#0,const_2)| | "let there be x pupils in the class . total increase in marks = ( x * 1 / 2 ) = x / 2 x / 2 = ( 83 - 70 ) = > x / 2 = 13 = > x = 26 . answer : c" | general |
math_qa__EmOXgmiugfbr9qtN | Calculate the average of all the numbers between 18 and 57 which are divisible by 7. Pick one
A) 36.9 B) 38.5 C) 18.5 D) 32.5 E) 28.5 | <gadget id="calculator">18 / 7</gadget>
<output>18/7 = around 2.571429</output>
<gadget id="calculator">floor(18/7)</gadget>
<output>2</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">57 / 7</gadget>
<output>57/7 = around 8.142857</output>
<gadget id="calculator">floor(57/7)</gadget>
<output>8</output>
<gadget id="calculator">3 + 8</gadget>
<output>11</output>
<gadget id="calculator">11 / 2</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">(11/2) * 7</gadget>
<output>77/2 = around 38.5</output>
<result>B</result> | B | 38.5 | Calculate the average of all the numbers between 18 and 57 which are divisible by 7. | {
"A": "36.9",
"B": "38.5",
"C": "18.5",
"D": "32.5",
"E": "28.5"
} | multiply(divide(add(add(floor(divide(18, 7)), const_1), floor(divide(57, 7))), const_2), 7) | divide(n0,n2)|divide(n1,n2)|floor(#0)|floor(#1)|add(#2,const_1)|add(#4,#3)|divide(#5,const_2)|multiply(n2,#6)| | "explanation : numbers divisible by 7 are 21,28 , 35,42 , 49,56 , average = ( 21 + 28 + 35 + 42 + 49 + 56 , ) / 6 = 231 / 6 = 38.5 answer : b" | general |
math_qa__7hCFGCGlfQKGrZWi | A trained covered x km at 50 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
Choose the correct choice from the following:
A) 22
B) 99
C) 25
D) 66
E) 887 | <gadget id="calculator">50 * 3</gadget>
<output>150</output>
<gadget id="calculator">50 / 50</gadget>
<output>1</output>
<gadget id="calculator">2 * 50</gadget>
<output>100</output>
<gadget id="calculator">100 / 20</gadget>
<output>5</output>
<gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">150 / 6</gadget>
<output>25</output>
<result>C</result> | C | 25 | A trained covered x km at 50 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km. | {
"A": "22",
"B": "99",
"C": "25",
"D": "66",
"E": "887"
} | divide(multiply(50, 3), add(divide(50, 50), divide(multiply(2, 50), 20))) | divide(n0,n0)|multiply(n0,n3)|multiply(n0,n1)|divide(#2,n2)|add(#0,#3)|divide(#1,#4)| | "total time taken = x / 50 + 2 x / 20 hours = 6 x / 50 = 3 x / 25 hours average speed = 3 x / ( 3 x / 25 ) = 25 kmph answer : c" | general |
math_qa__vs1c5kA7QnnJPOmJ | A drink vendor has 60 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required? Choose one:
A) 135 B) 137 C) 143 D) 310 E) 380 | <gadget id="calculator">gcd(60, 144)</gadget>
<output>12</output>
<gadget id="calculator">gcd(12, 368)</gadget>
<output>4</output>
<gadget id="calculator">368 / 4</gadget>
<output>92</output>
<gadget id="calculator">60 / 4</gadget>
<output>15</output>
<gadget id="calculator">144 / 4</gadget>
<output>36</output>
<gadget id="calculator">15 + 36</gadget>
<output>51</output>
<gadget id="calculator">92 + 51</gadget>
<output>143</output>
<result>C</result> | C | 143 | A drink vendor has 60 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required? | {
"A": "135",
"B": "137",
"C": "143",
"D": "310",
"E": "380"
} | add(divide(368, gcd(gcd(60, 144), 368)), add(divide(60, gcd(gcd(60, 144), 368)), divide(144, gcd(gcd(60, 144), 368)))) | gcd(n0,n1)|gcd(n2,#0)|divide(n0,#1)|divide(n1,#1)|divide(n2,#1)|add(#2,#3)|add(#5,#4)| | "the number of liters in each can = hcf of 60 , 144 and 368 = 4 liters . number of cans of maaza = 60 / 4 = 15 number of cans of pepsi = 144 / 4 = 36 number of cans of sprite = 368 / 4 = 92 the total number of cans required = 15 + 36 + 92 = 143 cans . answer : c" | general |
math_qa__ZZdNT0wRGVVssyIL | If 15% of 30% of 50% of a number is 99, then what is the number? Choose the correct choice from the following.
A) 4000 B) 3050 C) 4400 D) 4500 E) none of these | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(1/2) * (3/10)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * (3/20)</gadget>
<output>9/400 = around 0.0225</output>
<gadget id="calculator">99 / (9/400)</gadget>
<output>4_400</output>
<result>C</result> | C | 4,400 | If 15% of 30% of 50% of a number is 99, then what is the number? | {
"A": "4000",
"B": "3050",
"C": "4400",
"D": "4500",
"E": "none of these"
} | divide(99, multiply(multiply(divide(50, const_100), divide(30, const_100)), divide(15, const_100))) | divide(n0,const_100)|divide(n2,const_100)|divide(n1,const_100)|multiply(#1,#2)|multiply(#0,#3)|divide(n3,#4) | let the number be a given , 15 / 100 * 30 / 100 * 50 / 100 * a = 99 = > 3 / 20 * 3 / 10 * 1 / 2 * a = 99 = > a = 10 * 20 * 10 * 2 = 4400 . answer : c | gain |
math_qa__z4ynaHUYWkgg4EU4 | If a farmer wants to plough a farm field on time, he must plough 100 hectares a day. For technical reasons he ploughed only 85 hectares a day, hence he had to plough 2 more days than he planned and he still has 40 hectares left. What is the area of the farm field and how many days the farmer planned to work initially? Choose the correct choice from the following answers: A) 600 B) 490 C) 720 D) 1400 E) 1679 | <gadget id="calculator">2 * 85</gadget>
<output>170</output>
<gadget id="calculator">40 + 170</gadget>
<output>210</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">210 / 15</gadget>
<output>14</output>
<gadget id="calculator">14 * 100</gadget>
<output>1_400</output>
<result>D</result> | D | 1,400 | If a farmer wants to plough a farm field on time, he must plough 100 hectares a day. For technical reasons he ploughed only 85 hectares a day, hence he had to plough 2 more days than he planned and he still has 40 hectares left. What is the area of the farm field and how many days the farmer planned to work initially? | {
"A": "600",
"B": "490",
"C": "720",
"D": "1400",
"E": "1679"
} | multiply(divide(add(40, multiply(2, 85)), subtract(100, 85)), 100) | multiply(n1,n2)|subtract(n0,n1)|add(n3,#0)|divide(#2,#1)|multiply(n0,#3)| | "let x be the number of days in the initial plan . therefore , the whole field is 100 â ‹ … x hectares . the farmer had to work for x + 2 days , and he ploughed 85 ( x + 2 ) hectares , leaving 40 hectares unploughed . then we have the equation : 100 x = 85 ( x + 2 ) + 40 15 x = 210 x = 14 so the farmer planned to have the work done in 6 days , and the area of the farm field is 100 ( 14 ) = 1400 hectares correct answer d" | physics |
math_qa__BwcBhaWeqocaPvlL | in a certain town , the ratio of ny yankees fans to ny mets fans is 3 : 2 , and the ratio of ny mets fans to boston red sox fans is 4 : 5 . if there are 330 baseball fans in the town , each of whom is a fan of exactly one of those 3 teams , how many ny mets fans are there in this town ? Choose the most appropriate option.
A) 72 B) 88 C) 95 D) 120 E) 135 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">330 / 15</gadget>
<output>22</output>
<gadget id="calculator">22 * 4</gadget>
<output>88</output>
<result>B</result> | B | 88 | in a certain town , the ratio of ny yankees fans to ny mets fans is 3 : 2 , and the ratio of ny mets fans to boston red sox fans is 4 : 5 . if there are 330 baseball fans in the town , each of whom is a fan of exactly one of those 3 teams , how many ny mets fans are there in this town ? | {
"A": "72",
"B": "88",
"C": "95",
"D": "120",
"E": "135"
} | multiply(divide(330, multiply(5, 3)), 4) | multiply(n0,n3)|divide(n4,#0)|multiply(n2,#1) | the ratio of yankees : mets : red sox = 6 : 4 : 5 the mets fans are 4 / 15 of the population . ( 4 / 15 ) * 330 = 88 the answer is b . | other |
math_qa__kG4kCFxTmuAUDbLq | A retailer sells 5 shirts. He sells first 2 shirts for $30 and $20. If the retailer wishes to sell the 5 shirts for an overall average price of over $30, what must be the minimum average price of the remaining 3 shirts? Options.
A) $ 28.50 B) $ 30.50 C) $ 33.33 D) $ 40.50 E) $ 50.00 | <gadget id="calculator">30 * 5</gadget>
<output>150</output>
<gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">150 - 50</gadget>
<output>100</output>
<gadget id="calculator">100 / 3</gadget>
<output>100/3 = around 33.333333</output>
<result>C</result> | C | 33.33 | A retailer sells 5 shirts. He sells first 2 shirts for $30 and $20. If the retailer wishes to sell the 5 shirts for an overall average price of over $30, what must be the minimum average price of the remaining 3 shirts? | {
"A": "$ 28.50",
"B": "$ 30.50",
"C": "$ 33.33",
"D": "$ 40.50",
"E": "$ 50.00"
} | divide(subtract(multiply(30, 5), add(30, 20)), 3) | add(n2,n3)|multiply(n0,n2)|subtract(#1,#0)|divide(#2,n6) | first 2 shirts are sold for $ 30 and $ 20 = $ 50 . to get average price of $ 30 , total sale should be 5 * $ 30 = $ 150 so remaining 3 shirts to be sold for $ 150 - $ 50 = $ 100 answer should be 100 / 3 = $ 33.33 that is c | general |
math_qa__Bu93v0cwexvzWNkq | Ratio between Rahul and Deepak is 4:3, After 10 Years Rahul age will be 26 years. What is Deepak present age. Choose the correct choice from the following
A) 12
B) 15
C) 20
D) 22
E) 24 | <gadget id="calculator">26 - 10</gadget>
<output>16</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 / 4</gadget>
<output>12</output>
<result>A</result> | A | 12 | Ratio between Rahul and Deepak is 4:3, After 10 Years Rahul age will be 26 years. What is Deepak present age. | {
"A": "12",
"B": "15",
"C": "20",
"D": "22",
"E": "24"
} | divide(multiply(subtract(26, 10), 3), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0) | explanation : present age is 4 x and 3 x , = > 4 x + 10 = 26 = > x = 16 so deepak age is = 3 ( 4 ) = 12 option a | other |
math_qa__ann8DI9T9qbfrPos | If a clock strikes 12 in 33 seconds, it will strike 6 in how many seconds?
Choose the correct choice from the following answers
A) 33 ⁄ 2
B) 15
C) 12
D) 22
E) none of these | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">33 / 11</gadget>
<output>3</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<result>B</result> | B | 15 | If a clock strikes 12 in 33 seconds, it will strike 6 in how many seconds? | {
"A": "33 ⁄ 2",
"B": "15",
"C": "12",
"D": "22",
"E": "none of these"
} | multiply(subtract(6, const_1), divide(33, subtract(12, const_1))) | subtract(n0,const_1)|subtract(n2,const_1)|divide(n1,#0)|multiply(#2,#1) | in order to strike 12 , there are 11 intervals of equal time = 33 ⁄ 11 = 3 seconds each therefore , to strike 6 it has 5 equal intervals , it requires 5 × 3 = 15 sec . answer b | physics |
math_qa__MEuAmSxUUIFHBsiQ | Car A runs at the speed of 50km/hr & reaches its destination in 8hr. Car B runs at the speed of 25 km/h & reaches its destination in 4h. What is the respective ratio of distances covered by Car A & Car B? Choose the correct choice from the following answers:
A) 4 : 1 B) 11 : 8 C) 13 : 7 D) 15 : 7 E) 16 : 9 | <gadget id="calculator">50 * 8</gadget>
<output>400</output>
<gadget id="calculator">25 * 4</gadget>
<output>100</output>
<gadget id="calculator">400 / 100</gadget>
<output>4</output>
<result>A</result> | A | 4 | Car A runs at the speed of 50km/hr & reaches its destination in 8hr. Car B runs at the speed of 25 km/h & reaches its destination in 4h. What is the respective ratio of distances covered by Car A & Car B? | {
"A": "4 : 1",
"B": "11 : 8",
"C": "13 : 7",
"D": "15 : 7",
"E": "16 : 9"
} | divide(multiply(50, 8), multiply(25, 4)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "sol . distance travelled by car a = 50 × 8 = 400 km distance travelled by car b = 25 × 4 = 100 km ratio = 400 / 100 = 4 : 1 answer : a" | physics |
math_qa__T7xNsgdRfliJoDIt | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 25 percent. The enrollment on January 1, 1993, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ? Select the correct option
A) 36 B) 39 C) 40 D) 41 E) 42 | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">100 / 125</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 45</gadget>
<output>36</output>
<result>A</result> | A | 36 | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 25 percent. The enrollment on January 1, 1993, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ? | {
"A": "36",
"B": "39",
"C": "40",
"D": "41",
"E": "42"
} | multiply(divide(const_100, add(const_100, 25)), 45) | add(n4,const_100)|divide(const_100,#0)|multiply(n7,#1)| | "1.25 x = 45 - - > 5 / 4 * x = 45 - - > x = 45 * 4 / 5 = 180 / 5 = 36 . answer : a ." | gain |
math_qa__hNXjQ2gZxNXiPG1o | If 3 people a,b,c can do a work simultaneously in 6 days. a and b can do work in 10 days. b and c can do work in 15 days. c and a can do the same work in 20 days.In how many days that a can complete the same work alone?
Pick one
A) 20
B) 25
C) 30
D) 24
E) 19 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) + (1/15)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/6) + (1/20)</gadget>
<output>13/60 = around 0.216667</output>
<gadget id="calculator">(13/60) / 2</gadget>
<output>13/120 = around 0.108333</output>
<gadget id="calculator">(13/120) - (1/15)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<result>D</result> | D | 24 | If 3 people a,b,c can do a work simultaneously in 6 days. a and b can do work in 10 days. b and c can do work in 15 days. c and a can do the same work in 20 days.In how many days that a can complete the same work alone? | {
"A": "20",
"B": "25",
"C": "30",
"D": "24",
"E": "19"
} | divide(const_1, subtract(divide(add(add(divide(const_1, 10), divide(const_1, 15)), divide(const_1, 20)), const_2), divide(const_1, 15))) | divide(const_1,n2)|divide(const_1,n3)|divide(const_1,n4)|add(#0,#1)|add(#3,#2)|divide(#4,const_2)|subtract(#5,#1)|divide(const_1,#6) | a + b + c = 1 / 6 ( one day work ) a + b = 1 / 10 ; b + c = 1 / 15 ; c + a + 1 / 20 b = 1 / 15 - c ; c = 1 / 20 - a ; - - - - - - - - - ( 2 ) substitute equation 2 in a + b = 1 / 10 a = 1 / 10 - b ; a = 1 / 10 - 1 / 15 + c ; a = 1 / 10 - 1 / 15 + 1 / 20 - a ; 2 a = 1 / 10 - 1 / 15 + 1 / 20 ; a = 1 / 24 ( one day work ) that is the no of days that a can work alone is 24 days the option d is answer | physics |
math_qa__yUo73i4s2iuIYiio | A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 170, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?
Choose the correct choice from the following options.
A) 30 B) 33 C) 55 D) 77 E) 88 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/10) + (3/4)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">170 / (17/20)</gadget>
<output>200</output>
<gadget id="calculator">200 - 170</gadget>
<output>30</output>
<result>A</result> | A | 30 | A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 170, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala? | {
"A": "30",
"B": "33",
"C": "55",
"D": "77",
"E": "88"
} | subtract(divide(170, add(divide(10, const_100), divide(3, 4))), 170) | divide(n0,const_100)|divide(n2,n3)|add(#0,#1)|divide(n1,#2)|subtract(#3,n1)| | "let f = pure fuji , g = pure gala and c - cross pollinated . c = 10 % of x where x is total trees . c = . 1 x also 3 x / 4 = f and c + f = 170 = > . 1 x + 3 / 4 x = 170 = > x = 200 200 - 170 = pure gala = 30 . answer a" | general |
math_qa__0HExnMhiGyartyhK | A man is 46 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is: Options.
A) 44 years B) 18 years C) 20 years D) 22 years E) 16 years | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">46 - 2</gadget>
<output>44</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">44 / 1</gadget>
<output>44</output>
<result>A</result> | A | 44 | A man is 46 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is: | {
"A": "44 years",
"B": "18 years",
"C": "20 years",
"D": "22 years",
"E": "16 years"
} | divide(subtract(46, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1)) | multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)| | "let the son ' s present age be x years . then , man ' s present age = ( x + 24 ) years . ( x + 46 ) + 2 = 2 ( x + 2 ) x + 48 = 2 x + 4 x = 44 . answer : a" | general |
math_qa__8gpBglSOLEPXhNV5 | Pipe A that can fill a tank in an hour and pipe B that can fill the tank in half an hour are opened simultaneously when the tank is empty. Pipe B is shut 10 minutes before the tank overflows. When will the tank overflow?
Pick
A) 37 mins B) 35 mins C) 40 mins D) 32 mins E) 36 mins | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">60 * 30</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 30</gadget>
<output>60</output>
<gadget id="calculator">1_800 / 60</gadget>
<output>30</output>
<gadget id="calculator">60 + 30</gadget>
<output>90</output>
<gadget id="calculator">90 * 10</gadget>
<output>900</output>
<gadget id="calculator">900 / 30</gadget>
<output>30</output>
<gadget id="calculator">30 + 10</gadget>
<output>40</output>
<gadget id="calculator">40 - 3</gadget>
<output>37</output>
<result>A</result> | A | 37 | Pipe A that can fill a tank in an hour and pipe B that can fill the tank in half an hour are opened simultaneously when the tank is empty. Pipe B is shut 10 minutes before the tank overflows. When will the tank overflow? | {
"A": "37 mins",
"B": "35 mins",
"C": "40 mins",
"D": "32 mins",
"E": "36 mins"
} | subtract(add(divide(multiply(add(divide(multiply(multiply(const_1, const_60), divide(multiply(const_1, const_60), const_2)), divide(multiply(const_1, const_60), const_2)), divide(multiply(multiply(const_1, const_60), divide(multiply(const_1, const_60), const_2)), multiply(const_1, const_60))), 10), divide(multiply(multiply(const_1, const_60), divide(multiply(const_1, const_60), const_2)), multiply(const_1, const_60))), 10), const_3) | multiply(const_1,const_60)|divide(#0,const_2)|multiply(#1,#0)|divide(#2,#1)|divide(#2,#0)|add(#3,#4)|multiply(n0,#5)|divide(#6,#4)|add(n0,#7)|subtract(#8,const_3) | the last 10 minutes only pipe a was open . since it needs 1 hour to fill the tank , then in 10 minutes it fills 1 / 5 th of the tank , thus 5 / 6 of the tank is filled with both pipes open . the combined rate of two pipes is 1 + 2 = 3 tanks / hour , therefore to fill 5 / 6 th of the tank they need ( time ) = ( work ) / ( rate ) = ( 5 / 6 ) / 3 = 5 / 18 hours = 27 minutes . total time = 10 + 27 = 37 minutes . answer : a . | physics |
math_qa__WJLW3AIuZXNcdE6x | what is the maximum value of vx - yz . if the value of v , x , y , z have to be chosen from the set a where a ( - 3 , - 2 , - 1 , 01 , 23 ) Pick one: A) 15 B) 66 C) 25 D) 88 E) 17 | <gadget id="calculator">-3</gadget>
<output>-3</output>
<gadget id="calculator">(-3) ** 2</gadget>
<output>9</output>
<gadget id="calculator">(-3) * 2</gadget>
<output>-6</output>
<gadget id="calculator">9 - (-6)</gadget>
<output>15</output>
<result>A</result> | A | 15 | what is the maximum value of vx - yz . if the value of v , x , y , z have to be chosen from the set a where a ( - 3 , - 2 , - 1 , 01 , 23 ) | {
"A": "15",
"B": "66",
"C": "25",
"D": "88",
"E": "17"
} | subtract(power(negate(3), 2), multiply(negate(3), 2)) | negate(n0)|multiply(n1,#0)|power(#0,n1)|subtract(#2,#1) | explanation : to maximize the value of vx - yz , we make yz negative and vx as maximum as possible using given value . vx − yz = ( − 3 ) 2 − ( − 3 × 2 ) vx − yz = ( − 3 ) 2 − ( − 3 × 2 ) = 15 answer : a | general |
math_qa__jaYJcGs5YYxVf8wK | X and Y are two towns. Ganesh covers the distance from X to Y at an average speed of 54 Km/hr. However, he covers the distance from Y to X at an average speed of 36 Km/hr. His average speed during the whole journey in km/hr. is : Select:
A) 34
B) 43.2
C) 40
D) 38
E) 29 | <gadget id="calculator">54 - 10</gadget>
<output>44</output>
<gadget id="calculator">44 + 100</gadget>
<output>144</output>
<gadget id="calculator">144 + 144</gadget>
<output>288</output>
<gadget id="calculator">144 / 54</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">144 / 36</gadget>
<output>4</output>
<gadget id="calculator">(8/3) + 4</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">288 / (20/3)</gadget>
<output>216/5 = around 43.2</output>
<result>B</result> | B | 43.2 | X and Y are two towns. Ganesh covers the distance from X to Y at an average speed of 54 Km/hr. However, he covers the distance from Y to X at an average speed of 36 Km/hr. His average speed during the whole journey in km/hr. is : | {
"A": "34",
"B": "43.2",
"C": "40",
"D": "38",
"E": "29"
} | divide(add(add(subtract(54, const_10), const_100), add(subtract(54, const_10), const_100)), add(divide(add(subtract(54, const_10), const_100), 54), divide(add(subtract(54, const_10), const_100), 36))) | subtract(n0,const_10)|add(#0,const_100)|add(#1,#1)|divide(#1,n0)|divide(#1,n1)|add(#3,#4)|divide(#2,#5)| | "solution : average speed = 2 xy / x + y = 2 * 54 * 36 / 54 + 36 = 43.2 answer : b" | general |
math_qa__sjWovuuWOyonGrTF | P runs 20% faster than Q so P gives Q a 50 meter head start. If the race ends in a tie, how far (in meters) did P run in the race? Choose the correct choice from the following answers
A) 250 B) 300 C) 350 D) 400 E) 450 | <gadget id="calculator">50 * 100</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 / 20</gadget>
<output>250</output>
<gadget id="calculator">250 + 50</gadget>
<output>300</output>
<result>B</result> | B | 300 | P runs 20% faster than Q so P gives Q a 50 meter head start. If the race ends in a tie, how far (in meters) did P run in the race? | {
"A": "250",
"B": "300",
"C": "350",
"D": "400",
"E": "450"
} | add(divide(multiply(50, const_100), 20), 50) | multiply(n1,const_100)|divide(#0,n0)|add(n1,#1) | let d be the race distance that p ran . let t be the time it took to complete the race . let v be q ' s speed . t = d / 1.2 v = ( d - 50 ) / v d = 1.2 d - 60 0.2 d = 60 d = 300 meters . the answer is b . | gain |
math_qa__BcVLqAz2vHIEScBv | Suppose 10 monkeys take 10 minutes to eat 10 bananas. How many monkeys would it take to eat 70 bananas in 70 minutes?
Choose the correct choice from the following options
A) 9 B) 17 C) 11 D) 10 E) 13 | <gadget id="calculator">70 / 10</gadget>
<output>7</output>
<gadget id="calculator">70 / 7</gadget>
<output>10</output>
<result>D</result> | D | 10 | Suppose 10 monkeys take 10 minutes to eat 10 bananas. How many monkeys would it take to eat 70 bananas in 70 minutes? | {
"A": "9",
"B": "17",
"C": "11",
"D": "10",
"E": "13"
} | divide(70, divide(70, 10)) | divide(n3,n0)|divide(n3,#0)| | "one monkey takes 10 min to eat 1 banana , so in 70 mins 1 monkey will eat 7 bananas , so for 70 bananas in 70 min we need 70 / 7 = 10 monkeys answer : d" | physics |
math_qa__SXAmoCyjQ5jFiVj7 | A man walks at a rate of 10 mph. After every ten miles, he rests for 5 minutes. How much time does he take to walk 50 miles? Choose the correct choice from the following answers.
A) 300 B) 318 C) 320 D) 324 E) 330 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<gadget id="calculator">5 * 60</gadget>
<output>300</output>
<gadget id="calculator">20 + 300</gadget>
<output>320</output>
<result>C</result> | C | 320 | A man walks at a rate of 10 mph. After every ten miles, he rests for 5 minutes. How much time does he take to walk 50 miles? | {
"A": "300",
"B": "318",
"C": "320",
"D": "324",
"E": "330"
} | add(multiply(5, const_4), multiply(divide(50, 10), const_60)) | divide(n2,n0)|multiply(n1,const_4)|multiply(#0,const_60)|add(#1,#2) | to cover 50 miles the man needs ( time ) = ( distance ) / ( rate ) = 50 / 10 = 5 hours = 300 minutes . he will also rest 4 times ( after 10 , 20 , 30 and 40 miles ) , so total resting time = 4 * 5 = 20 minutes . total time = 300 + 20 = 320 minutes . answer : c . | physics |
math_qa__mkonIo1fv4PJfUeG | On a map, 4.5 inches represent 45 miles. How many miles approximately is the distance if you measured 254 centimeters assuming that 1-inch is 2.54 centimeters? Choose the correct choice from the following choices
A) 1000 B) 1100 C) 1200 D) 1250 E) 1300 | <gadget id="calculator">254 / 2.54</gadget>
<output>100</output>
<gadget id="calculator">45 / 4.5</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<result>A</result> | A | 1,000 | On a map, 4.5 inches represent 45 miles. How many miles approximately is the distance if you measured 254 centimeters assuming that 1-inch is 2.54 centimeters? | {
"A": "1000",
"B": "1100",
"C": "1200",
"D": "1250",
"E": "1300"
} | multiply(divide(254, 2.54), divide(45, 4.5)) | divide(n2,n4)|divide(n1,n0)|multiply(#0,#1)| | "1 inch = 2.54 cm 4.5 inch = 2.54 * 4.5 cm 11.43 cm = 45 miles 254 cms = 45 / 11.43 * 254 = 1000 miles answer : a" | physics |
math_qa__dwtORXx6a3qdaqva | John bought 9.25m of cloth for $416.25. Find the cost price per metre. Choices: A) 46 B) 47 C) 45 D) 56 E) 54 | <gadget id="calculator">416.25 / 9.25</gadget>
<output>45</output>
<result>C</result> | C | 45 | John bought 9.25m of cloth for $416.25. Find the cost price per metre. | {
"A": "46",
"B": "47",
"C": "45",
"D": "56",
"E": "54"
} | divide(416.25, 9.25) | divide(n1,n0)| | "cloth bought by john = 9.25 m cost of 9.25 m = $ 416.25 cost per metre = 416.25 ÷ 9.25 the cost of the cloth per metre = $ 45 answers : c" | physics |
math_qa__HlzFqOMkNKbqDdcD | If P is a prime number greater than 3, find the remainder when P^2 + 12 is divided by 12. Choose the correct choice from the following answers
A) 6 B) 1 C) 0 D) 8 E) 7 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">12 + 25</gadget>
<output>37</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">37 - 36</gadget>
<output>1</output>
<result>B</result> | B | 1 | If P is a prime number greater than 3, find the remainder when P^2 + 12 is divided by 12. | {
"A": "6",
"B": "1",
"C": "0",
"D": "8",
"E": "7"
} | subtract(add(12, power(add(const_1, const_4), 2)), multiply(12, 3)) | add(const_1,const_4)|multiply(n0,n3)|power(#0,n1)|add(n2,#2)|subtract(#3,#1)| | "every prime number greater than 3 can be written 6 n + 1 or 6 n - 1 . if p = 6 n + 1 , then p ^ 2 + 13 = 36 n ^ 2 + 12 n + 1 + 12 = 36 n ^ 2 + 12 n + 12 + 1 if p = 6 n - 1 , then p ^ 2 + 13 = 36 n ^ 2 - 12 n + 1 + 12 = 36 n ^ 2 - 12 n + 12 + 1 when divided by 12 , it must leave a remainder of 1 . the answer is b ." | general |
math_qa__RqoyWqGxgdC2lTxw | What is the rate percent when the simple interest on Rs.910 amount to Rs.260 in 4 Years? Choose the correct choice: A) 7.14 B) 6.14 C) 5.14 D) 3.14 E) 2.14 | <gadget id="calculator">100 * 260</gadget>
<output>26_000</output>
<gadget id="calculator">910 * 4</gadget>
<output>3_640</output>
<gadget id="calculator">26_000 / 3_640</gadget>
<output>50/7 = around 7.142857</output>
<result>A</result> | A | 7.14 | What is the rate percent when the simple interest on Rs.910 amount to Rs.260 in 4 Years? | {
"A": "7.14",
"B": "6.14",
"C": "5.14",
"D": "3.14",
"E": "2.14"
} | divide(multiply(const_100, 260), multiply(910, 4)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)| | "260 = ( 910 * 4 * r ) / 100 r = 7.14 % answer : a" | gain |
math_qa__m53qBDxo7934XaWY | In 1979 approximately 1/3 of the 37.3 million airline passengers traveling to or from the United States used Kennedy Airport. If the number of such passengers that used Miami Airport was 1/4 the number that used Kennedy Airport and 3 times the number that used Logan Airport, approximately how many millions of these passengers used Logan Airport that year? Choose the correct choice from the following: A) 18.6 B) 9.3 C) 6.2 D) 3.1 E) 1.03 | <gadget id="calculator">37.3 / 3</gadget>
<output>12.433333</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12.433333 / 12</gadget>
<output>1.036111</output>
<result>E</result> | E | 1.03 | In 1979 approximately 1/3 of the 37.3 million airline passengers traveling to or from the United States used Kennedy Airport. If the number of such passengers that used Miami Airport was 1/4 the number that used Kennedy Airport and 3 times the number that used Logan Airport, approximately how many millions of these passengers used Logan Airport that year? | {
"A": "18.6",
"B": "9.3",
"C": "6.2",
"D": "3.1",
"E": "1.03"
} | divide(divide(37.3, 3), multiply(3, 4)) | divide(n3,n2)|multiply(n5,n6)|divide(#0,#1)| | "number of passengers using kennedy airport = 37 / 3 = ~ 12.43 passengers using miami airport = 12.43 / 4 = ~ 3.1 passengers using logan airport = 3.1 / 3 = ~ 1.03 so e" | general |
math_qa__QIZKuCH06LuizJFs | If a(a - 4) = 5 and b(b -4) = 5, where a ≠ b, then a + b = Pick one.
A) − 48 B) − 4 C) 4 D) 9 E) 48 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">4 - 5</gadget>
<output>-1</output>
<gadget id="calculator">9 + (-1)</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<result>C</result> | C | 4 | If a(a - 4) = 5 and b(b -4) = 5, where a ≠ b, then a + b = | {
"A": "− 48",
"B": "− 4",
"C": "4",
"D": "9",
"E": "48"
} | subtract(subtract(subtract(subtract(add(add(4, 5), subtract(4, 5)), const_1), const_1), const_1), const_1) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|subtract(#2,const_1)|subtract(#3,const_1)|subtract(#4,const_1)|subtract(#5,const_1)| | "i . e . if a = - 1 then b = 5 or if a = 5 then b = - 1 but in each case a + b = - 1 + 5 = 4 answer : option c" | general |
math_qa__T9T2UWjgn6sp0L8v | In a software company 4/10 of people know C++, 2/4 of them know java, 2/8 of them know neither,find the total possibility to know C++?
Choose the correct choice from the following choices:
A) 1 / 4 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 3 / 4 | <gadget id="calculator">2 / 8</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">2 / 4</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/4) - (1/2)</gadget>
<output>1/4 = around 0.25</output>
<result>A</result> | A | 0.25 | In a software company 4/10 of people know C++, 2/4 of them know java, 2/8 of them know neither,find the total possibility to know C++? | {
"A": "1 / 4",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "3 / 4"
} | subtract(subtract(const_1, divide(2, 8)), divide(2, 4)) | divide(n2,n5)|divide(n2,n0)|subtract(const_1,#0)|subtract(#2,#1) | assume 100 persons in a company person knows c + + = 4 / 10 = 100 * 4 / 100 = 20 persons person knows java = 2 / 4 = 100 * 2 / 4 = 50 persons neither = 2 / 8 = 100 * 2 / 8 = 25 persons according to our assumption 100 person = 20 + 50 + 25 = 95 person covered ( 5 remaining ) so , total possibility = 20 person ( c + + ) + 5 ( remaining ) = 25 persons which is 25 / 100 = 1 / 4 answer : a | general |
math_qa__mogq1qGPZJP300f6 | The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 10 years. Find the average age of the women?
Choices.
A) 87 B) 98 C) 30 D) 28 E) 23 | <gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">30 + 16</gadget>
<output>46</output>
<gadget id="calculator">46 / 2</gadget>
<output>23</output>
<result>E</result> | E | 23 | The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 10 years. Find the average age of the women? | {
"A": "87",
"B": "98",
"C": "30",
"D": "28",
"E": "23"
} | divide(add(add(20, 10), multiply(8, 2)), const_2) | add(n2,n3)|multiply(n0,n1)|add(#0,#1)|divide(#2,const_2)| | "20 + 10 + 8 * 2 = 46 / 2 = 23 answer : e" | general |
math_qa__Yj9lhVpEoO1ETf9h | The number 0.8 is how much greater than 1/2 ? Choose the correct choice from the following answers:
A) ½
B) 3 / 10
C) 1 / 50
D) 1 / 500
E) 2 / 500 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">0.8 - (1/2)</gadget>
<output>0.3</output>
<result>B</result> | B | 0.3 | The number 0.8 is how much greater than 1/2 ? | {
"A": "½",
"B": "3 / 10",
"C": "1 / 50",
"D": "1 / 500",
"E": "2 / 500"
} | subtract(0.8, divide(1, 2)) | divide(n1,n2)|subtract(n0,#0)| | "let x be the difference then . 8 - 1 / 2 = x 8 / 10 - 1 / 2 = x x = 3 / 10 ans b" | general |
math_qa__LPFJFizlSA44lchX | Two trains running in opposite directions cross a man standing on the platform in 20 seconds and 18 seconds respectively and they cross each other in 19 seconds. The ratio of their speeds is:
Choose the correct choice:
A) 1 : 1
B) 3 : 2
C) 3 : 8
D) 3 : 25
E) 3 : 4 | <gadget id="calculator">20 - 19</gadget>
<output>1</output>
<gadget id="calculator">19 - 18</gadget>
<output>1</output>
<gadget id="calculator">1 / 1</gadget>
<output>1</output>
<result>A</result> | A | 1 | Two trains running in opposite directions cross a man standing on the platform in 20 seconds and 18 seconds respectively and they cross each other in 19 seconds. The ratio of their speeds is: | {
"A": "1 : 1",
"B": "3 : 2",
"C": "3 : 8",
"D": "3 : 25",
"E": "3 : 4"
} | divide(subtract(20, 19), subtract(19, 18)) | subtract(n0,n2)|subtract(n2,n1)|divide(#0,#1)| | "let the speeds of the two trains be x m / sec and y m / sec respectively . then , length of the first train = 20 x meters , and length of the second train = 18 y meters . ( 20 x + 15 y ) / ( x + y ) = 19 = = > 20 x + 18 y = 19 x + 19 y = = > x = y = = > x / y = 1 / 1 answer : option a" | physics |
math_qa__75A4PNCmx9lpTr7C | Cindy has her eye on a sundress but thinks it is too expensive. It goes on sale for 15% less than the original price. Before Cindy can buy the dress, however, the store raises the new price by 25%. If the dress cost $68 after it went on sale for 15% off, what is the difference between the original price and the final price? Choose the correct choice from the following options.
A) $ 0.00 B) $ 1.00 C) $ 3.40 D) $ 5.00 E) $ 6.80 | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">68 * (5/4)</gadget>
<output>85</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">68 / (17/20)</gadget>
<output>80</output>
<gadget id="calculator">85 - 80</gadget>
<output>5</output>
<result>D</result> | D | 5 | Cindy has her eye on a sundress but thinks it is too expensive. It goes on sale for 15% less than the original price. Before Cindy can buy the dress, however, the store raises the new price by 25%. If the dress cost $68 after it went on sale for 15% off, what is the difference between the original price and the final price? | {
"A": "$ 0.00",
"B": "$ 1.00",
"C": "$ 3.40",
"D": "$ 5.00",
"E": "$ 6.80"
} | subtract(multiply(68, divide(add(const_100, 25), const_100)), divide(68, divide(subtract(const_100, 15), const_100))) | add(n1,const_100)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,const_100)|divide(n2,#3)|multiply(n2,#2)|subtract(#5,#4) | 0.85 * { original price } = $ 68 - - > { original price } = $ 80 . { final price } = $ 68 * 1.25 = $ 85 . the difference = $ 85 - $ 85 = $ 5 . answer : d . | general |
math_qa__PjPXpMSdLP08bUBe | The cost per pound of milk powder and coffee were the same in June. In July, the price of coffee shot up by 200% and that of milk powder dropped by 60%. If in July, a mixture containing equal quantities of milk powder and coffee costs $5.10 for 3lbs, how much did a pound of milk powder cost in July?
Choose the correct choice from the following answers: A) $ 4 B) $ 0.4 C) $ 1 D) $ 3 E) $ 1.65 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<result>B</result> | B | 0.4 | The cost per pound of milk powder and coffee were the same in June. In July, the price of coffee shot up by 200% and that of milk powder dropped by 60%. If in July, a mixture containing equal quantities of milk powder and coffee costs $5.10 for 3lbs, how much did a pound of milk powder cost in July? | {
"A": "$ 4",
"B": "$ 0.4",
"C": "$ 1",
"D": "$ 3",
"E": "$ 1.65"
} | subtract(const_1, divide(60, const_100)) | divide(n1,const_100)|subtract(const_1,#0)| | "lets assume price of coffee in june = 100 x price of tea in june = 100 x price of coffee in july = 300 x ( because of 200 % increase in price ) price of tea in july = 40 x ( because of 60 % decrease in price ) price of 1.5 pound of coffee 1.5 pound of tea in july will be = 450 x + 60 x = 510 x as per question 510 x = 5.10 $ x = 0.01 s so the price of tea in july = 40 x = 40 x 0.01 = 0.4 $ / pound answer b" | general |
math_qa__7nZFozdLlvrtjOql | Each of the 55 points is placed either inside or on the surface of a perfect sphere. If 60% or fewer of the points touch the surface, what is the maximum number of segments which, if connected from those points to form chords, could be the diameter of the sphere?
Select the correct option:
A) 7 B) 11 C) 13 D) 16 E) 38 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">55 * (3/5)</gadget>
<output>33</output>
<gadget id="calculator">33 / 2</gadget>
<output>33/2 = around 16.5</output>
<result>D</result> | D | 16 | Each of the 55 points is placed either inside or on the surface of a perfect sphere. If 60% or fewer of the points touch the surface, what is the maximum number of segments which, if connected from those points to form chords, could be the diameter of the sphere? | {
"A": "7",
"B": "11",
"C": "13",
"D": "16",
"E": "38"
} | divide(multiply(55, divide(60, const_100)), const_2) | divide(n1,const_100)|multiply(n0,#0)|divide(#1,const_2) | maximum number of points on the surface is 60 % * 55 = 33 now note that if two points form a diameter , they can not be part of any other diameter . so in the best case we can pair up the points we have 33 points , so at best we can form 16 pairs ( 32 ) . so , answer is ( d ) | geometry |
math_qa__8kNl2jxxmTm69D2r | A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 60 kmph. When and at what distance from Mumbai do the two trains meet?
Choose the correct choice from the following answers.
A) 187 B) 279 C) 120 D) 278 E) 379 | <gadget id="calculator">40 * 1</gadget>
<output>40</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">40 / 20</gadget>
<output>2</output>
<gadget id="calculator">2 * 60</gadget>
<output>120</output>
<result>C</result> | C | 120 | A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 60 kmph. When and at what distance from Mumbai do the two trains meet? | {
"A": "187",
"B": "279",
"C": "120",
"D": "278",
"E": "379"
} | multiply(divide(multiply(40, const_1), subtract(60, 40)), 60) | multiply(n1,const_1)|subtract(n2,n1)|divide(#0,#1)|multiply(n2,#2)| | "when the second train leaves mumbai the first train covers 40 * 1 = 40 km so , the distance between first train and second train is 40 km at 10.00 am time taken by the trains to meet = distance / relative speed = 40 / ( 60 - 40 ) = 2 hours so , the two trains meet at 12 a . m . the two trains meet 2 * 60 = 120 km away from mumbai . answer : c" | physics |
math_qa__GkWyIWmPx9ojjO2Z | For any number Z, Z* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.30 – 6.30*? Choose the correct answer:
A) 1.5 B) 0.5 C) 6.25 D) 0.25 E) 0.3 | <gadget id="calculator">floor(6.3)</gadget>
<output>6</output>
<gadget id="calculator">6.3 - 6</gadget>
<output>0.3</output>
<result>E</result> | E | 0.3 | For any number Z, Z* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.30 – 6.30*? | {
"A": "1.5",
"B": "0.5",
"C": "6.25",
"D": "0.25",
"E": "0.3"
} | subtract(6.30, floor(6.30)) | floor(n0)|subtract(n0,#0)| | "since z * is defined as the greatest positive even integer less than or equal to z , then 6.30 * = 6 ( the greatest positive even integer less than or equal to 6.30 is 6 ) . hence , 6.30 – 6.30 * = 6.30 - 6 = 0.30 answer : e ." | general |
math_qa__TFcq4eKsp9xL7rlF | The Guests at a football banquet consumed a total of 406 pounds of food. if no individual guest consumed more than 2.5 pounds of food, What is the minimum number of guests that could have attended the banquet? Choose the correct choice from the following options.
A) 160 B) 161 C) 162 D) 163 E) 164 | <gadget id="calculator">406 / 2.5</gadget>
<output>162.4</output>
<gadget id="calculator">floor(162.4)</gadget>
<output>162</output>
<gadget id="calculator">162 + 1</gadget>
<output>163</output>
<result>D</result> | D | 163 | The Guests at a football banquet consumed a total of 406 pounds of food. if no individual guest consumed more than 2.5 pounds of food, What is the minimum number of guests that could have attended the banquet? | {
"A": "160",
"B": "161",
"C": "162",
"D": "163",
"E": "164"
} | add(floor(divide(406, 2.5)), const_1) | divide(n0,n1)|floor(#0)|add(#1,const_1)| | "to minimize one quantity maximize other . 162 * 2.5 ( max possible amount of food a guest could consume ) = 405 pounds , so there must be more than 162 guests , next integer is 163 . answer : d ." | general |
math_qa__gzWvfcRvYgyYu3te | If daily wages of a man is double to that of a woman, how many men should work for 20 days to earn Rs.14400? Given that wages for 40 women for 30 days are Rs.21600. Pick.
A) 12 B) 14 C) 16 D) 18 E) 20 | <gadget id="calculator">40 * 30</gadget>
<output>1_200</output>
<gadget id="calculator">21_600 / 1_200</gadget>
<output>18</output>
<gadget id="calculator">2 * 18</gadget>
<output>36</output>
<gadget id="calculator">20 * 36</gadget>
<output>720</output>
<gadget id="calculator">14_400 / 720</gadget>
<output>20</output>
<result>E</result> | E | 20 | If daily wages of a man is double to that of a woman, how many men should work for 20 days to earn Rs.14400? Given that wages for 40 women for 30 days are Rs.21600. | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "20"
} | divide(14400, multiply(20, multiply(const_2, divide(21600, multiply(40, 30))))) | multiply(n2,n3)|divide(n4,#0)|multiply(#1,const_2)|multiply(n0,#2)|divide(n1,#3)| | "explanation : wages of 1 woman for 1 day = 21600 / 40 ã — 30 wages of 1 man for 1 day = 21600 ã — 2 / 40 ã — 30 wages of 1 man for 20 days = 21600 ã — 2 ã — 20 / 40 ã — 30 number of men = 14400 / ( 21600 ã — 2 ã — 20 / 40 ã — 30 ) = 144 / ( 216 ã — 40 / 40 ã — 30 ) = 20 answer : option e" | physics |
math_qa__sk2Jz5dIayXL2bUE | Persons A and B. Person A picks a random no. from 1 to 1000.Then person B picks a random no. from 1 to 1000. What is the probability of B getting no. greater then what A has picked. Choose the correct choice from the following:
A) 0.3995
B) 0.4995
C) 0.5995
D) 0.6995
E) 0.7995 | <gadget id="calculator">1 / 1_000</gadget>
<output>1/1_000 = around 0.001</output>
<gadget id="calculator">1 - (1/1_000)</gadget>
<output>999/1_000 = around 0.999</output>
<gadget id="calculator">(999/1_000) / 2</gadget>
<output>999/2_000 = around 0.4995</output>
<result>B</result> | B | 0.4995 | Persons A and B. Person A picks a random no. from 1 to 1000.Then person B picks a random no. from 1 to 1000. What is the probability of B getting no. greater then what A has picked. | {
"A": "0.3995",
"B": "0.4995",
"C": "0.5995",
"D": "0.6995",
"E": "0.7995"
} | divide(subtract(const_1, divide(1, 1000)), const_2) | divide(n0,n1)|subtract(const_1,#0)|divide(#1,const_2) | probability of a choosing 1 and b greater = ( 1 / 1000 ) * ( 999 / 1000 ) ; probability of a choosing 2 and b greater = ( 1 / 1000 ) * ( 998 / 1000 ) ; probability of a choosing 3 and b greater = ( 1 / 1000 ) * ( 997 / 1000 ) ; . . . ; probability of a choosing 998 and b greater = ( 1 / 1000 ) * ( 2 / 1000 ) ; probability of a choosing 999 and b greater = ( 1 / 1000 ) * ( 1 / 1000 ) ; total = ( 1 / 1000 ) * ( 1 / 1000 ) * ( 999 + 998 + 997 + . . . + 2 + 1 ) = ( 1 / 1000 ) * ( 1 / 1000 ) * ( 999 * 1000 / 2 ) = 0.4995 answer : b | probability |
math_qa__am700uNcLecb3Ygz | Cole drove from home to work at an average speed of 50 kmh. He then returned home at an average speed of 110 kmh. If the round trip took a total of 2 hours, how many minutes did it take Cole to drive to work? Choose the most appropriate option:
A) 66.5
B) 70.5
C) 72.5
D) 75.5
E) 82.5 | <gadget id="calculator">110 * 2</gadget>
<output>220</output>
<gadget id="calculator">50 + 110</gadget>
<output>160</output>
<gadget id="calculator">220 / 160</gadget>
<output>11/8 = around 1.375</output>
<gadget id="calculator">(11/8) * 60</gadget>
<output>165/2 = around 82.5</output>
<result>E</result> | E | 82.5 | Cole drove from home to work at an average speed of 50 kmh. He then returned home at an average speed of 110 kmh. If the round trip took a total of 2 hours, how many minutes did it take Cole to drive to work? | {
"A": "66.5",
"B": "70.5",
"C": "72.5",
"D": "75.5",
"E": "82.5"
} | multiply(divide(multiply(110, 2), add(50, 110)), const_60) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)|multiply(#2,const_60)| | "let the distance one way be x time from home to work = x / 50 time from work to home = x / 110 total time = 2 hrs ( x / 50 ) + ( x / 110 ) = 2 solving for x , we get x = 275 / 4 time from home to work in minutes = ( 275 / 4 ) * 60 / 50 = 82.5 minutes ans = e" | physics |
math_qa__aC16WMi6gVoKxK4k | An equal number of desks and bookcases are to be placed along a library wall that is 15 meters long. Each desk is 2 meters long, and each bookshelf is 1.5 meters long. If the maximum possible number of desks and bookcases are to be placed along the wall, then the space along the wall that is left over will be how many G meters long? Choose the correct answer.
A) 0.5
B) 1
C) 1.5
D) 2
E) 3 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">4 * 1.5</gadget>
<output>6</output>
<gadget id="calculator">8 + 6</gadget>
<output>14</output>
<gadget id="calculator">15 - 14</gadget>
<output>1</output>
<result>B</result> | B | 1 | An equal number of desks and bookcases are to be placed along a library wall that is 15 meters long. Each desk is 2 meters long, and each bookshelf is 1.5 meters long. If the maximum possible number of desks and bookcases are to be placed along the wall, then the space along the wall that is left over will be how many G meters long? | {
"A": "0.5",
"B": "1",
"C": "1.5",
"D": "2",
"E": "3"
} | subtract(15, add(multiply(const_4, 2), multiply(const_4, 1.5))) | multiply(n1,const_4)|multiply(n2,const_4)|add(#0,#1)|subtract(n0,#2)| | "let x be the number of desks and bookcases that are placed along the library wall . 2 x + 1.5 x < 15 3.5 x < 15 since x is a non negative integer , the largest number x can be is 4 . when x is 4 , the desks and bookcases take up 3.5 * 4 = 14 m , leaving 1 m of empty space . thus , i believe the answer is b ) 1" | general |
math_qa__mk9c35sLH5tn2Pin | -88 × 39 + 312 = ? Choose the correct choice from the following.
A) - 3200 B) 3120 C) - 3120 D) 3200 E) 3208 | <gadget id="calculator">-88</gadget>
<output>-88</output>
<gadget id="calculator">(-88) * 39</gadget>
<output>-3_432</output>
<gadget id="calculator">(-3_432) + 312</gadget>
<output>-3_120</output>
<result>C</result> | C | -3,120 | -88 × 39 + 312 = ? | {
"A": "- 3200",
"B": "3120",
"C": "- 3120",
"D": "3200",
"E": "3208"
} | add(multiply(negate(88), 39), 312) | negate(n0)|multiply(n1,#0)|add(n2,#1) | - 88 × 39 + 312 = - 88 × ( 40 - 1 ) + 312 = - 88 × 40 + 88 + 312 = - 3520 + 88 + 312 = - 3120 answer is c | general |
math_qa__1hDj2GPdNVNayDMu | What will be the cost of building a fence around a square plot with area equal to 25 sq ft, if the price per foot of building the fence is Rs. 58? Options
A) 1160
B) 1251
C) 1102
D) 1352
E) 1450 | <gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 58</gadget>
<output>1_160</output>
<result>A</result> | A | 1,160 | What will be the cost of building a fence around a square plot with area equal to 25 sq ft, if the price per foot of building the fence is Rs. 58? | {
"A": "1160",
"B": "1251",
"C": "1102",
"D": "1352",
"E": "1450"
} | multiply(square_perimeter(sqrt(25)), 58) | sqrt(n0)|square_perimeter(#0)|multiply(n1,#1)| | "let the side of the square plot be a ft . a 2 = 25 = > a = 5 length of the fence = perimeter of the plot = 4 a = 20 ft . cost of building the fence = 20 * 58 = rs . 1160 . answer : a" | geometry |
math_qa__rkcbHDho2uEjkoks | A train 280 m long, running with a speed of 63 km / hr will pass a tree in Choices:
A) 15 sec .
B) 16 sec .
C) 18 sec .
D) 20 sec .
E) none | <gadget id="calculator">63 * 1_000</gadget>
<output>63_000</output>
<gadget id="calculator">280 / 63_000</gadget>
<output>1/225 = around 0.004444</output>
<gadget id="calculator">(1/225) * 3_600</gadget>
<output>16</output>
<result>B</result> | B | 16 | A train 280 m long, running with a speed of 63 km / hr will pass a tree in | {
"A": "15 sec .",
"B": "16 sec .",
"C": "18 sec .",
"D": "20 sec .",
"E": "none"
} | multiply(divide(280, multiply(63, const_1000)), const_3600) | multiply(n1,const_1000)|divide(n0,#0)|multiply(#1,const_3600)| | "solution speed = ( 63 x 5 / 18 ) m / sec = 35 / 2 msec time taken = ( 280 x 2 / 35 ) m / sec = 16 sec . answer b" | physics |
math_qa__EPwwOycPY9kiebpw | A shop owner sells 15mtr of cloth and gains SP of 10 mtrs. Find the gain %? Choose the correct choice from the following answers:
A) 30 % B) 40 % C) 50 % D) 100 % E) 200 % | <gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">10 / 5</gadget>
<output>2</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<result>E</result> | E | 200 | A shop owner sells 15mtr of cloth and gains SP of 10 mtrs. Find the gain %? | {
"A": "30 %",
"B": "40 %",
"C": "50 %",
"D": "100 %",
"E": "200 %"
} | multiply(divide(10, subtract(15, 10)), const_100) | subtract(n0,n1)|divide(n1,#0)|multiply(#1,const_100)| | "here , selling price of 10 m cloth is obtained as profit . profit of 10 m cloth = ( s . p . of 15 m cloth ) – ( c . p . of 15 m cloth ) selling price of 5 m cloth = selling price of 15 m of cloth let cost of each metre be rs . 100 . therefore , cost price of 5 m cloth = rs . 500 and s . p . of 5 m cloth = rs . rs . 1500 profit % = 1000 / 500 × 100 = 200 % profit of 200 % was made by the merchant . e" | gain |
math_qa__prPjjNlVr0GffLvY | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 348 votes. Find the number of votes casted to the winning candidate? Select
A) 456 B) 744 C) 899 D) 1200 E) 1400 | <gadget id="calculator">100 - 62</gadget>
<output>38</output>
<gadget id="calculator">62 - 38</gadget>
<output>24</output>
<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">348 / (6/25)</gadget>
<output>1_450</output>
<gadget id="calculator">1_450 * 62</gadget>
<output>89_900</output>
<gadget id="calculator">89_900 / 100</gadget>
<output>899</output>
<result>C</result> | C | 899 | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 348 votes. Find the number of votes casted to the winning candidate? | {
"A": "456",
"B": "744",
"C": "899",
"D": "1200",
"E": "1400"
} | divide(multiply(divide(348, divide(subtract(62, subtract(const_100, 62)), const_100)), 62), const_100) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)| | "w = 62 % l = 38 % 62 % - 38 % = 24 % 24 % - - - - - - - - 348 62 % - - - - - - - - ? = > 899 answer : c" | gain |
math_qa__RyqqNa9v1HhPfe83 | What is the rate percent when the simple interest on Rs.4000 amount to Rs.640 in 2 Years?
Pick.
A) 8.2 % B) 8 % C) 8.5 % D) 9 % E) 9.5 % | <gadget id="calculator">100 * 640</gadget>
<output>64_000</output>
<gadget id="calculator">4_000 * 2</gadget>
<output>8_000</output>
<gadget id="calculator">64_000 / 8_000</gadget>
<output>8</output>
<result>B</result> | B | 8 | What is the rate percent when the simple interest on Rs.4000 amount to Rs.640 in 2 Years? | {
"A": "8.2 %",
"B": "8 %",
"C": "8.5 %",
"D": "9 %",
"E": "9.5 %"
} | divide(multiply(const_100, 640), multiply(4000, 2)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)| | "interest for 1 year = 640 / 2 = 320 interest on rs 4000 p / a = 320 interest rate = 320 / 4000 * 100 = 8 % answer : b" | gain |
math_qa__MXdq5AObXOUPzoSx | If 2x + y = 7 and x + 2y = 8, then (x + y)/3 = Choose the correct choice from the following.
A) 1 B) 4 / 3 C) 17 / 5 D) 18 / 5 E) 5 / 3 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">14 - 8</gadget>
<output>6</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">7 - 4</gadget>
<output>3</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<result>E</result> | E | 1.666667 | If 2x + y = 7 and x + 2y = 8, then (x + y)/3 = | {
"A": "1",
"B": "4 / 3",
"C": "17 / 5",
"D": "18 / 5",
"E": "5 / 3"
} | divide(add(divide(subtract(multiply(7, 2), 8), subtract(multiply(2, 2), const_1)), subtract(7, multiply(2, divide(subtract(multiply(7, 2), 8), subtract(multiply(2, 2), const_1))))), 3) | multiply(n0,n1)|multiply(n0,n0)|subtract(#0,n3)|subtract(#1,const_1)|divide(#2,#3)|multiply(n0,#4)|subtract(n1,#5)|add(#4,#6)|divide(#7,n4)| | "we have two equations : 2 x + y = 7 x + 2 y = 8 notice that something nice happens when we add them . we get : 3 x + 3 y = 15 divide both sides by 3 to get : x + y = 5 so , ( x + y ) / 3 = 5 / 3 answer : e" | general |
math_qa__MN90H4jD3yW2AlDA | Farm Tax is levied on the 90% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. william. Mr. william paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is : Pick: A) 15 % B) 25 % C) 0.125 % D) 13.88 % E) none | <gadget id="calculator">480 / 3_840</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 100</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 100</gadget>
<output>1_250</output>
<gadget id="calculator">1_250 / 90</gadget>
<output>125/9 = around 13.888889</output>
<result>D</result> | D | 13.88 | Farm Tax is levied on the 90% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. william. Mr. william paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is : | {
"A": "15 %",
"B": "25 %",
"C": "0.125 %",
"D": "13.88 %",
"E": "none"
} | divide(multiply(multiply(divide(480, 3840), const_100), const_100), 90) | divide(n2,n1)|multiply(#0,const_100)|multiply(#1,const_100)|divide(#2,n0)| | "this will be equal to the percentage of total cultivated land he holds over the total cultivated land in the village . that leads to ( 480 / 3840 ) x 100 = 12.5 % in percentage terms . but the question asks ratio between his total land to total cultivated land . hence the answer is 12.5 % x ( 100 / 90 ) = 13.88 % the correct answer is ( d ) ." | general |
math_qa__DgljaUN3gSqZbCxi | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8500. If his salary for the month of May is Rs.6500, find his salary for the month of January? Choose the correct choice from the following answers
A) 2177 B) 2876 C) 4500 D) 2981 E) 2711 | <gadget id="calculator">8_000 * 4</gadget>
<output>32_000</output>
<gadget id="calculator">8_500 * 4</gadget>
<output>34_000</output>
<gadget id="calculator">34_000 - 6_500</gadget>
<output>27_500</output>
<gadget id="calculator">32_000 - 27_500</gadget>
<output>4_500</output>
<result>C</result> | C | 4,500 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8500. If his salary for the month of May is Rs.6500, find his salary for the month of January? | {
"A": "2177",
"B": "2876",
"C": "4500",
"D": "2981",
"E": "2711"
} | subtract(multiply(8000, const_4), subtract(multiply(8500, const_4), 6500)) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#1,n2)|subtract(#0,#2)| | "sum of the salaries of the person for the months of january , february , march and april = 4 * 8000 = 32000 - - - - ( 1 ) sum of the salaries of the person for the months of february , march , april and may = 4 * 8500 = 34000 - - - - ( 2 ) ( 2 ) - ( 1 ) i . e . may - jan = 2000 salary of may is rs . 6500 salary of january = rs . 4500 . answer : c" | general |
math_qa__XzIbV3PZ710Hf8jW | don and his wife each receive an 8 percent annual raise. if don receives a raise rs.800 and his wife receives a raise of rs. 840, what is the difference between their annual income after their raises? Pick one:
A) 40
B) 460
C) 500
D) 540
E) 150 | <gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">840 / (2/25)</gadget>
<output>10_500</output>
<gadget id="calculator">10_500 + 840</gadget>
<output>11_340</output>
<gadget id="calculator">800 / (2/25)</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 + 800</gadget>
<output>10_800</output>
<gadget id="calculator">11_340 - 10_800</gadget>
<output>540</output>
<result>D</result> | D | 540 | don and his wife each receive an 8 percent annual raise. if don receives a raise rs.800 and his wife receives a raise of rs. 840, what is the difference between their annual income after their raises? | {
"A": "40",
"B": "460",
"C": "500",
"D": "540",
"E": "150"
} | subtract(add(divide(840, divide(8, const_100)), 840), add(divide(800, divide(8, const_100)), 800)) | divide(n0,const_100)|divide(n2,#0)|divide(n1,#0)|add(n2,#1)|add(n1,#2)|subtract(#3,#4) | don salary 8 % = 800 ; therefore , 100 % = 10000 his wife salary 8 % = 840 ; therefore , 100 % = 10500 after raise 8 % , don salary = 10000 + 800 = 10800 and his wife salary = 10500 + 840 = 11340 difference = 11340 - 10800 = 540 answer : d | gain |
math_qa__8YtLOptHquG5Oy8i | If the simple interest on a sum of money for 2 years at 5% per annum is Rs.50, what will be the compound interest on same values Options:
A) rs . 51.75 B) rs 51.50 C) rs 51.25 D) rs 51 E) none of these | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">50 / (1/10)</gadget>
<output>500</output>
<gadget id="calculator">500 * 5</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 100</gadget>
<output>25</output>
<gadget id="calculator">25 + 500</gadget>
<output>525</output>
<gadget id="calculator">525 * 5</gadget>
<output>2_625</output>
<gadget id="calculator">2_625 / 100</gadget>
<output>105/4 = around 26.25</output>
<gadget id="calculator">525 + (105/4)</gadget>
<output>2_205/4 = around 551.25</output>
<gadget id="calculator">(2_205/4) - 500</gadget>
<output>205/4 = around 51.25</output>
<result>C</result> | C | 51.25 | If the simple interest on a sum of money for 2 years at 5% per annum is Rs.50, what will be the compound interest on same values | {
"A": "rs . 51.75",
"B": "rs 51.50",
"C": "rs 51.25",
"D": "rs 51",
"E": "none of these"
} | subtract(add(add(divide(multiply(divide(50, multiply(divide(5, const_100), 2)), 5), const_100), divide(50, multiply(divide(5, const_100), 2))), divide(multiply(add(divide(multiply(divide(50, multiply(divide(5, const_100), 2)), 5), const_100), divide(50, multiply(divide(5, const_100), 2))), 5), const_100)), divide(50, multiply(divide(5, const_100), 2))) | divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1)|multiply(n1,#2)|divide(#3,const_100)|add(#4,#2)|multiply(n1,#5)|divide(#6,const_100)|add(#5,#7)|subtract(#8,#2)| | "explanation : s . i . = p ∗ r ∗ t / 100 p = 50 ∗ 100 / 5 ∗ 2 = 500 amount = 500 ( 1 + 5100 ) 2 500 ( 21 / 20 ∗ 21 / 20 ) = 551.25 c . i . = 551.25 − 500 = 51.25 option c" | gain |
math_qa__UoDRYsgdzqCXKcxW | If x+y=300, x-y=200, for integers of x and y, y=? Select:
A) 200 B) 250 C) 50 D) 115 E) 150 | <gadget id="calculator">300 + 200</gadget>
<output>500</output>
<gadget id="calculator">500 / 2</gadget>
<output>250</output>
<result>B</result> | B | 250 | If x+y=300, x-y=200, for integers of x and y, y=? | {
"A": "200",
"B": "250",
"C": "50",
"D": "115",
"E": "150"
} | divide(add(300, 200), const_2) | add(n0,n1)|divide(#0,const_2)| | "x + y = 300 x - y = 200 2 x = 100 x = 50 y = 250 answer is b" | general |
math_qa__wk4lPMC3qXwDmAow | Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 66900. What is his profit percent? Choose the correct choice from the following choices.
A) 22 B) 77 C) 18 D) 21.6 E) 88 | <gadget id="calculator">42_000 + 13_000</gadget>
<output>55_000</output>
<gadget id="calculator">66_900 - 55_000</gadget>
<output>11_900</output>
<gadget id="calculator">11_900 / 55_000</gadget>
<output>119/550 = around 0.216364</output>
<gadget id="calculator">(119/550) * 100</gadget>
<output>238/11 = around 21.636364</output>
<result>D</result> | D | 21.6 | Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 66900. What is his profit percent? | {
"A": "22",
"B": "77",
"C": "18",
"D": "21.6",
"E": "88"
} | multiply(divide(subtract(66900, add(42000, 13000)), add(42000, 13000)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "total cp = rs . 42000 + rs . 13000 = rs . 55000 and sp = rs . 66900 profit ( % ) = ( 66900 - 55000 ) / 55000 * 100 = 21.6 % answer : d" | gain |
math_qa__2knRzJ4WxxegWESJ | A can do a work in 8 days. B can do the same work in 16 days. If both A & B are working together in how many days they will finish the work? Answers: A) 3 days B) 16 / 3 days C) 3 / 4 days D) 9 / 12 days E) 5 / 7 days | <gadget id="calculator">8 * 16</gadget>
<output>128</output>
<gadget id="calculator">8 + 16</gadget>
<output>24</output>
<gadget id="calculator">128 / 24</gadget>
<output>16/3 = around 5.333333</output>
<result>B</result> | B | 5.333333 | A can do a work in 8 days. B can do the same work in 16 days. If both A & B are working together in how many days they will finish the work? | {
"A": "3 days",
"B": "16 / 3 days",
"C": "3 / 4 days",
"D": "9 / 12 days",
"E": "5 / 7 days"
} | divide(multiply(8, 16), add(8, 16)) | add(n0,n1)|multiply(n0,n1)|divide(#1,#0)| | "a rate = 1 / 8 b rate = 1 / 16 ( a + b ) rate = ( 1 / 8 ) + ( 1 / 16 ) = 3 / 16 a & b finish the work in 16 / 3 days correct option is b" | physics |
math_qa__6A2BGWosr3SsV76M | If (1 – 1.25)N = 5, then N =
Choose the correct answer.
A) − 20 B) − 140 C) − 4 D) 4 E) 400 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">-20</gadget>
<output>-20</output>
<result>A</result> | A | -20 | If (1 – 1.25)N = 5, then N = | {
"A": "− 20",
"B": "− 140",
"C": "− 4",
"D": "4",
"E": "400"
} | negate(multiply(5, const_4)) | multiply(n2,const_4)|negate(#0)| | "( 1 – 1.25 ) n = 5 simplify to get : - 0.25 n = 5 rewrite as ( - 1 / 4 ) n = 5 multiply both sides by - 4 to get : n = - 20 answer : a" | general |
math_qa__xqXOzs3R3SANTpVZ | If in a race of 70m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by:
Pick one:
A) 20 m
B) 16 m
C) 14 m
D) 10 m
E) 15 m | <gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">5 / 25</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 70</gadget>
<output>14</output>
<result>C</result> | C | 14 | If in a race of 70m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by: | {
"A": "20 m",
"B": "16 m",
"C": "14 m",
"D": "10 m",
"E": "15 m"
} | multiply(divide(subtract(25, 20), 25), 70) | subtract(n2,n1)|divide(#0,n2)|multiply(n0,#1)| | "explanation : the difference in the timing of a and b is 5 seconds . hence , a beats b by 5 seconds . the distance covered by b in 5 seconds = ( 70 * 5 ) / 25 = 14 m hence , a beats b by 14 m . answer c" | physics |
math_qa__mhHV9lHxO07qgoyz | A bus covered a distance of 250 km, partly at an average speed of 40 kmph and partly at 60 kmph. If the total time taken is 5.2 hours, then the distance covered at 40 kmph is
Select:
A) 130 km B) 120 km C) 100 km D) 124 km E) none of these | <gadget id="calculator">60 * 5.2</gadget>
<output>312</output>
<gadget id="calculator">312 - 250</gadget>
<output>62</output>
<gadget id="calculator">40 - 60</gadget>
<output>-20</output>
<gadget id="calculator">-(-20)</gadget>
<output>20</output>
<gadget id="calculator">62 / 20</gadget>
<output>31/10 = around 3.1</output>
<gadget id="calculator">(31/10) * 40</gadget>
<output>124</output>
<result>D</result> | D | 124 | A bus covered a distance of 250 km, partly at an average speed of 40 kmph and partly at 60 kmph. If the total time taken is 5.2 hours, then the distance covered at 40 kmph is | {
"A": "130 km",
"B": "120 km",
"C": "100 km",
"D": "124 km",
"E": "none of these"
} | multiply(divide(subtract(multiply(60, 5.2), 250), negate(subtract(40, 60))), 40) | multiply(n2,n3)|subtract(n1,n2)|negate(#1)|subtract(#0,n0)|divide(#3,#2)|multiply(n1,#4)| | "let the partial distance covered at 40 kmph be x let the another partial distance covered at 60 kmph be ( 250 - x ) thus , x / 40 - ( 250 - x ) / 60 = 5.2 or , x / 40 + ( 250 - x ) / 60 = 5.2 or , ( 3 x + 500 - 2 x ) / / 120 = 5.2 or 500 + x = 624 x = 124 answer : d" | physics |
math_qa__QTQ5LVxmqN0gMYrZ | jane and ashley take 13 1 / 3 days and 40 days respectively to complete a project when they work on it alone . they thought if they worked on the project together , they would take fewer days to complete it . during the period that they were working together , jane took an 8 day leave from work . this led to jane ' s working for 4 extra days on her own to complete the project . how long did it take to finish the project ? Options:
A) 10 days B) 15 days C) 16 days D) 17 days E) 20 days | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">4 * (1/3)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">1 / (4/3)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 40</gadget>
<output>30</output>
<gadget id="calculator">30 - 13</gadget>
<output>17</output>
<result>D</result> | D | 17 | jane and ashley take 13 1 / 3 days and 40 days respectively to complete a project when they work on it alone . they thought if they worked on the project together , they would take fewer days to complete it . during the period that they were working together , jane took an 8 day leave from work . this led to jane ' s working for 4 extra days on her own to complete the project . how long did it take to finish the project ? | {
"A": "10 days",
"B": "15 days",
"C": "16 days",
"D": "17 days",
"E": "20 days"
} | subtract(multiply(inverse(multiply(4, divide(1, 3))), 40), 13) | divide(n1,n2)|multiply(n5,#0)|inverse(#1)|multiply(n3,#2)|subtract(#3,n0) | let us assume that the work is laying 40 bricks . jane = 3 bricks per day ashley = 1 brick per day together = 4 bricks per day let ' s say first 8 days ashley works alone , no of bricks = 8 last 4 days jane works alone , no . of bricks = 12 remaining bricks = 40 - 20 = 20 so together , they would take 20 / 4 = 5 total no . of days = 8 + 4 + 5 = 17 answer is d | physics |
math_qa__JRu2F7jgVd1p9v3N | The average (arithmetic mean) of all scores on a certain algebra test was 90. If the average of the 8 male students’ grades was 82, and the average of the female students’ grades was 92, how many female students took the test? Choose the correct choice:
A) 8 B) 9 C) 10 D) 21 E) 32 | <gadget id="calculator">90 * 8</gadget>
<output>720</output>
<gadget id="calculator">82 * 8</gadget>
<output>656</output>
<gadget id="calculator">720 - 656</gadget>
<output>64</output>
<gadget id="calculator">92 - 90</gadget>
<output>2</output>
<gadget id="calculator">64 / 2</gadget>
<output>32</output>
<result>E</result> | E | 32 | The average (arithmetic mean) of all scores on a certain algebra test was 90. If the average of the 8 male students’ grades was 82, and the average of the female students’ grades was 92, how many female students took the test? | {
"A": "8",
"B": "9",
"C": "10",
"D": "21",
"E": "32"
} | divide(subtract(multiply(90, 8), multiply(82, 8)), subtract(92, 90)) | multiply(n0,n1)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)| | "total marks of male = m total marks of female = f number of males = 8 number of females = f given : ( m + f ) / ( 8 + f ) = 90 - - - - - - - - - - - - - 1 also given , m / 8 = 82 thus m = 656 - - - - - - - - - 2 also , f / f = 92 thus f = 92 f - - - - - - - - - 3 put 2 and 3 in 1 : we get ( 656 + 92 f ) / ( 8 + f ) = 90 solving this we get f = 32 ans : e" | general |
math_qa__qgDRRhY0iKgm5QXq | If the length of the longest chord of a certain circle is 24, what is the radius of that certain circle?
Choose the correct choice from the following options.
A) 12 B) 5 C) 10 D) 15 E) 20 | <gadget id="calculator">24 / 2</gadget>
<output>12</output>
<result>A</result> | A | 12 | If the length of the longest chord of a certain circle is 24, what is the radius of that certain circle? | {
"A": "12",
"B": "5",
"C": "10",
"D": "15",
"E": "20"
} | divide(24, const_2) | divide(n0,const_2)| | "longest chord of a circle is the diameter of the circle diameter = 2 * radius if diameter of the circle is given as 24 = 2 * 12 so radius of the circle = 12 correct answer - a" | geometry |
math_qa__A4wPxFwaXRyrsxkP | A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 4 liters per minute. When the tank is full in inlet is opened and due to the leak the tank is empties in 8 hours. The capacity of the tank is? Choose the correct choice from the following choices.
A) 5768
B) 5760
C) 5762
D) 5766
E) 5712 | <gadget id="calculator">8 * 60</gadget>
<output>480</output>
<gadget id="calculator">4 * 480</gadget>
<output>1_920</output>
<gadget id="calculator">6 * 60</gadget>
<output>360</output>
<gadget id="calculator">480 / 360</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) - 1</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1_920 / (1/3)</gadget>
<output>5_760</output>
<result>B</result> | B | 5,760 | A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 4 liters per minute. When the tank is full in inlet is opened and due to the leak the tank is empties in 8 hours. The capacity of the tank is? | {
"A": "5768",
"B": "5760",
"C": "5762",
"D": "5766",
"E": "5712"
} | divide(multiply(4, multiply(8, const_60)), subtract(divide(multiply(8, const_60), multiply(6, const_60)), const_1)) | multiply(n2,const_60)|multiply(n0,const_60)|divide(#0,#1)|multiply(n1,#0)|subtract(#2,const_1)|divide(#3,#4)| | "1 / x - 1 / 6 = - 1 / 8 x = 24 hrs 24 * 60 * 4 = 5760 answer : b" | physics |
math_qa__c2CAMEWwnpDT9hpi | The class mean score on a test was 60, and the standard deviation was 10. If Jack's score was within 2 standard deviations of the mean, what is the lowest score he could have received?
Choose the correct choice from the following options.
A) 30
B) 31
C) 45
D) 90
E) 20 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<result>E</result> | E | 20 | The class mean score on a test was 60, and the standard deviation was 10. If Jack's score was within 2 standard deviations of the mean, what is the lowest score he could have received? | {
"A": "30",
"B": "31",
"C": "45",
"D": "90",
"E": "20"
} | multiply(2, 10) | multiply(n1,n2) | 1 sd from the mean is adding and subtrating the amount if standard deviation from the mean one time . 2 sd from the mean is adding and subtracting twice . 1 sd from the mean ranges from 70 to 50 , where 70 is within sd above the mean and 50 within 1 sd below the mean 2 sd = 10 twice = 20 from the the mean , which is 80 to 40 , where 80 is within 2 sd above the mean and 20 is within 2 sd below the mean . answer = e | general |
math_qa__Wx85evEX4wHgIQ5b | The ratio of buses to cars on River Road is 1 to 10. If there are 90 fewer buses than cars on River Road, how many cars are on River Road?
Pick one
A) 50
B) 40
C) 100
D) 30
E) 20 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">90 / 9</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<result>C</result> | C | 100 | The ratio of buses to cars on River Road is 1 to 10. If there are 90 fewer buses than cars on River Road, how many cars are on River Road? | {
"A": "50",
"B": "40",
"C": "100",
"D": "30",
"E": "20"
} | multiply(divide(90, subtract(10, 1)), 10) | subtract(n1,n0)|divide(n2,#0)|multiply(n1,#1)| | "b / c = 1 / 10 c - b = 90 . . . . . . . . . > b = c - 90 ( c - 90 ) / c = 1 / 10 testing answers . clearly eliminate abde put c = 100 . . . . . . . . . > ( 100 - 90 ) / 100 = 10 / 100 = 1 / 10 answer : c" | other |
math_qa__4FzlCmASSqKzqiH2 | A merchant marks goods up by 75% and then offers a discount on the marked price. The profit that the merchant makes after offering the discount is 57.5%. What % discount did the merchant offer? Pick: A) 10 % B) 15 % C) 20 % D) 25 % E) 30 % | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 + (3/4)</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">(7/4) - 1</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">57.5 / 100</gadget>
<output>0.575</output>
<gadget id="calculator">(3/4) - 0.575</gadget>
<output>0.175</output>
<gadget id="calculator">0.175 / (7/4)</gadget>
<output>0.1</output>
<gadget id="calculator">0.1 * 100</gadget>
<output>10</output>
<result>A</result> | A | 10 | A merchant marks goods up by 75% and then offers a discount on the marked price. The profit that the merchant makes after offering the discount is 57.5%. What % discount did the merchant offer? | {
"A": "10 %",
"B": "15 %",
"C": "20 %",
"D": "25 %",
"E": "30 %"
} | multiply(divide(subtract(subtract(add(const_1, divide(75, const_100)), const_1), divide(57.5, const_100)), add(const_1, divide(75, const_100))), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(#2,const_1)|subtract(#3,#1)|divide(#4,#2)|multiply(#5,const_100)| | "let p be the original price of the goods and let x be the rate after the markup . ( 1.75 p ) * x = 1.575 p x = 1.575 / 1.75 = 0.9 which is a discount of 10 % . the answer is a ." | gain |
math_qa__p3iSUsBDXL5ShRmz | A certain roller coaster has 5 cars, and a passenger is equally likely to ride in any 1 of the 5 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 5 times, what is the probability that the passenger will ride in each of the 5 cars?
Choices:
A) 0 B) 24 / 625 C) 2 / 9 D) 1 / 3 E) 1 | <gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) ** 5</gadget>
<output>1/3_125 = around 0.00032</output>
<gadget id="calculator">120 * (1/3_125)</gadget>
<output>24/625 = around 0.0384</output>
<result>B</result> | B | 0.0384 | A certain roller coaster has 5 cars, and a passenger is equally likely to ride in any 1 of the 5 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 5 times, what is the probability that the passenger will ride in each of the 5 cars? | {
"A": "0",
"B": "24 / 625",
"C": "2 / 9",
"D": "1 / 3",
"E": "1"
} | multiply(factorial(5), power(divide(1, 5), 5)) | divide(n1,n0)|factorial(n0)|power(#0,n0)|multiply(#1,#2)| | "if he is to ride 5 times and since he can choose any of the 5 cars each time , total number of ways is = 5 * 5 * 5 * 5 * 5 = 3125 now the number of ways if he is to choose a different car each time is = 5 * 4 * 3 * 2 * 1 = 120 so the probability is = 120 / 3125 = 24 / 625 answer : b" | general |
math_qa__IavqRa8Je9NeEvVK | Jane and Ashley take 10 days and 40 days respectively to complete a project when they work on it alone. They thought if they worked on the project together, they would take fewer days to complete it. During the period that they were working together, Jane took an eight day leave from work. This led to Jane's working for four extra days on her own to complete the project. How long did it take to finish the project ?
Choose the correct option.
A) 10.2 days B) 15.2 days C) 16.2 days D) 18 days E) 20 days | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">4 * (1/10)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">8 * (1/40)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/5) - (1/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/10) + (1/40)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(2/5) / (1/8)</gadget>
<output>16/5 = around 3.2</output>
<gadget id="calculator">(16/5) + 8</gadget>
<output>56/5 = around 11.2</output>
<gadget id="calculator">(56/5) + 4</gadget>
<output>76/5 = around 15.2</output>
<result>B</result> | B | 15.2 | Jane and Ashley take 10 days and 40 days respectively to complete a project when they work on it alone. They thought if they worked on the project together, they would take fewer days to complete it. During the period that they were working together, Jane took an eight day leave from work. This led to Jane's working for four extra days on her own to complete the project. How long did it take to finish the project ? | {
"A": "10.2 days",
"B": "15.2 days",
"C": "16.2 days",
"D": "18 days",
"E": "20 days"
} | add(add(divide(subtract(subtract(const_1, multiply(const_4, divide(const_1, 10))), multiply(add(const_4, const_4), divide(const_1, 40))), add(divide(const_1, 10), divide(const_1, 40))), add(const_4, const_4)), const_4) | add(const_4,const_4)|divide(const_1,n0)|divide(const_1,n1)|add(#1,#2)|multiply(#1,const_4)|multiply(#0,#2)|subtract(const_1,#4)|subtract(#6,#5)|divide(#7,#3)|add(#0,#8)|add(#9,const_4) | let us assume that the work is laying 40 bricks . jane = 4 bricks per day ashley = 1 brick per day together = 5 bricks per day let ' s say first 8 days ashley works alone , no of bricks = 8 last 4 days jane works alone , no . of bricks = 16 remaining bricks = 40 - 24 = 16 so together , they would take 16 / 5 = 3.2 total no . of days = 8 + 4 + 3.2 = 15.2 answer is b | physics |
math_qa__APuqsoHpCVdkCutR | If John covers a certain distance in 1 hr. 24 min. by covering two third of the distance at 4 kmph and the rest at 5 kmph, then find the total distance. Choose the correct choice from the following choices
A) 9 km B) 2 km C) 1 km D) 6 km E) 7 km | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">24 / 60</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(2/3) * (7/5)</gadget>
<output>14/15 = around 0.933333</output>
<gadget id="calculator">4 * (14/15)</gadget>
<output>56/15 = around 3.733333</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * (7/5)</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">(7/15) * 5</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">(56/15) + (7/3)</gadget>
<output>91/15 = around 6.066667</output>
<result>D</result> | D | 6 | If John covers a certain distance in 1 hr. 24 min. by covering two third of the distance at 4 kmph and the rest at 5 kmph, then find the total distance. | {
"A": "9 km",
"B": "2 km",
"C": "1 km",
"D": "6 km",
"E": "7 km"
} | add(multiply(4, multiply(divide(const_2, const_3), add(1, divide(24, const_60)))), multiply(multiply(subtract(1, divide(const_2, const_3)), add(1, divide(24, const_60))), 5)) | divide(n1,const_60)|divide(const_2,const_3)|add(n0,#0)|subtract(n0,#1)|multiply(#2,#1)|multiply(#2,#3)|multiply(n2,#4)|multiply(n3,#5)|add(#6,#7)| | "explanation : let the total distance be y km . then , ( 2 / 3 ) y / 4 + ( 1 / 3 ) y / 5 = 7 / 5 y / 6 + y / 15 = 7 / 5 7 y = 42 y = 6 km answer : d" | physics |
math_qa__UqHolF2NsJIax7oU | A certain club has 10 members, including Jarry. One of the 10 members is chosen at random to be the president, one of the remaining 9 members is to be chosen at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that Jarry will be either the member chose to be secretary or the member chose to be treasurer? Choose one:
A) 1 / 720
B) 1 / 80
C) 1 / 10
D) 1 / 9
E) 1 / 5 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">8 / 9</gadget>
<output>8/9 = around 0.888889</output>
<gadget id="calculator">(9/10) * (8/9)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">(4/5) * (7/8)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(1/10) + (7/10)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<result>E</result> | E | 0.2 | A certain club has 10 members, including Jarry. One of the 10 members is chosen at random to be the president, one of the remaining 9 members is to be chosen at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that Jarry will be either the member chose to be secretary or the member chose to be treasurer? | {
"A": "1 / 720",
"B": "1 / 80",
"C": "1 / 10",
"D": "1 / 9",
"E": "1 / 5"
} | subtract(const_1, add(divide(const_1, 10), multiply(multiply(divide(9, 10), divide(8, 9)), divide(subtract(8, const_1), 8)))) | divide(const_1,n0)|divide(n2,n0)|divide(n3,n2)|subtract(n3,const_1)|divide(#3,n3)|multiply(#1,#2)|multiply(#4,#5)|add(#0,#6)|subtract(const_1,#7) | in order to become a secretary the person can not be chosen as a president . this can be done in 9 / 10 ways . then to become a secretary this person ' s probability is 1 / 9 probability to become a secretary = ( 9 / 10 * 1 / 9 ) = 1 / 10 similar concept for treasurer . probability of not president = 9 / 10 , probability of not secretary = 8 / 9 , probability of treasurer 1 / 8 probability to become a treasurer = ( 9 / 10 * 8 / 9 * 1 / 8 ) = 1 / 10 since , the problem is saying jarry secretary or treasurer it is addition : 1 / 10 + 1 / 10 = 1 / 5 = e | probability |
math_qa__y8z2W3AsXg04J48n | Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is not an even ?
Choose the correct choice from the following:
A) 1 / 2 B) 1 / 4 C) 2 / 3 D) 2 / 5 E) 3 / 7 | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * (1/2)</gadget>
<output>1/4 = around 0.25</output>
<result>B</result> | B | 0.25 | Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is not an even ? | {
"A": "1 / 2",
"B": "1 / 4",
"C": "2 / 3",
"D": "2 / 5",
"E": "3 / 7"
} | multiply(divide(const_3, add(const_3, const_3)), divide(const_3, add(const_3, const_3))) | add(const_3,const_3)|divide(const_3,#0)|multiply(#1,#1) | total number of cases = 6 * 6 = 36 favourable cases = [ ( 1,3 ) , ( 1,5 ) , ( 1,1 ) , ( 3,1 ) , ( 3,3 ) , ( 3,5 ) , ( 5,1 ) , ( 5,3 ) , ( 5,5 ) ] = 9 so probability = 9 / 36 = 1 / 4 answer is b | probability |
math_qa__AqPn2veToS49YhgU | the elevator in an 11 - story office building travels at the rate of one floor per 1 / 4 minute , which allows time for picking up and discharging passengers . at the main floor and at the top floor , the operator stops for 1 minute . how many complete trips will an operator make during a 4 - hour period ? Select: A) 88 B) 56 C) 42 D) 34 E) 64 | <gadget id="calculator">4 * 60</gadget>
<output>240</output>
<gadget id="calculator">11 - 1</gadget>
<output>10</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">20 * (1/4)</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">240 / 7</gadget>
<output>240/7 = around 34.285714</output>
<result>D</result> | D | 34 | the elevator in an 11 - story office building travels at the rate of one floor per 1 / 4 minute , which allows time for picking up and discharging passengers . at the main floor and at the top floor , the operator stops for 1 minute . how many complete trips will an operator make during a 4 - hour period ? | {
"A": "88",
"B": "56",
"C": "42",
"D": "34",
"E": "64"
} | divide(multiply(4, const_60), add(add(multiply(add(subtract(11, 1), subtract(11, 1)), inverse(const_4)), 1), 1)) | inverse(const_4)|multiply(n2,const_60)|subtract(n0,n1)|add(#2,#2)|multiply(#3,#0)|add(n1,#4)|add(n1,#5)|divide(#1,#6) | complete trip = 10 floors up and 10 floors down = 20 floors = 20 * 1 / 4 = 5 minutes plus 2 minutes = 7 minutes . 4 hour = 240 minutes . in 240 minutes operator can make 240 / 7 = 34 trips . answer : d . | physics |
math_qa__VZYkDjbdWHTtL4Fd | A certain no. when divided by 35leaves a remainder 25, what is the remainder if the same no.be divided by 15? Choose the correct choice from the following answers
A) 2 B) 4 C) 7 D) 8 E) 9 | <gadget id="calculator">35 - 25</gadget>
<output>10</output>
<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">6 - 2</gadget>
<output>4</output>
<result>B</result> | B | 4 | A certain no. when divided by 35leaves a remainder 25, what is the remainder if the same no.be divided by 15? | {
"A": "2",
"B": "4",
"C": "7",
"D": "8",
"E": "9"
} | subtract(subtract(subtract(35, 25), const_4), const_2) | subtract(n0,n1)|subtract(#0,const_4)|subtract(#1,const_2)| | "explanation : 35 + 25 = 60 / 15 = 4 ( remainder ) b" | general |
math_qa__r5Z4pRMgRgsllSVD | You have a flashlight that takes 2 working batteries. You have 8 batteries but only 4 of them work.
What is the fewest number of pairs you need to test to guarantee you can get the flashlight on? Choose the correct choice from the following options:
A) 5
B) 8
C) 7
D) 6
E) 4 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<result>C</result> | C | 7 | You have a flashlight that takes 2 working batteries. You have 8 batteries but only 4 of them work.
What is the fewest number of pairs you need to test to guarantee you can get the flashlight on? | {
"A": "5",
"B": "8",
"C": "7",
"D": "6",
"E": "4"
} | add(multiply(add(2, const_1), 2), const_1) | add(n0,const_1)|multiply(n0,#0)|add(#1,const_1) | if you break the batteries into 3 groups : two groups of 3 and one group of 2 . by doing this you guarantee that one of the groups has 2 working batteries . both of the groups of 3 have 3 possible combinations of 2 batteries and the group of 2 only has 1 combination . so , 3 + 3 + 1 = 7 tries at most to find two working batteries . | physics |
math_qa__mZVjyVCNqK95mzFk | The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 40 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam? Answers
A) 22 B) 26 C) 25 D) 28 E) 12 | <gadget id="calculator">90 * 5</gadget>
<output>450</output>
<gadget id="calculator">5 * 40</gadget>
<output>200</output>
<gadget id="calculator">450 - 200</gadget>
<output>250</output>
<gadget id="calculator">90 - 80</gadget>
<output>10</output>
<gadget id="calculator">250 / 10</gadget>
<output>25</output>
<result>C</result> | C | 25 | The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 40 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam? | {
"A": "22",
"B": "26",
"C": "25",
"D": "28",
"E": "12"
} | divide(subtract(multiply(90, 5), multiply(5, 40)), subtract(90, 80)) | multiply(n1,n3)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)| | "let the number of students who wrote the exam be x . total marks of students = 80 x . total marks of ( x - 5 ) students = 90 ( x - 5 ) 80 x - ( 5 * 40 ) = 90 ( x - 5 ) 250 = 10 x = > x = 25 answer : c" | general |
math_qa__9tzTsh19eAIgeqDw | In a certain alphabet, 16 letters contain a dot and a straight line. 30 letters contain a straight line but do not contain a dot. If that alphabet has 50 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line? Choose the most appropriate option.
A) 4 B) 8 C) 12 D) 16 E) 20 | <gadget id="calculator">16 + 30</gadget>
<output>46</output>
<gadget id="calculator">50 - 46</gadget>
<output>4</output>
<result>A</result> | A | 4 | In a certain alphabet, 16 letters contain a dot and a straight line. 30 letters contain a straight line but do not contain a dot. If that alphabet has 50 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line? | {
"A": "4",
"B": "8",
"C": "12",
"D": "16",
"E": "20"
} | subtract(50, add(16, 30)) | add(n0,n1)|subtract(n2,#0)| | "we are told that all of the letters contain either a dot or a straight line or both , which implies that there are no letters without a dot and a line ( no line / no dot box = 0 ) . first we find the total # of letters with lines : 16 + 30 = 46 ; next , we find the total # of letters without line : 50 - 46 = 4 ; finally , we find the # of letters that contain a dot but do not contain a straight line : 4 - 0 = 4 . answer : a" | other |
math_qa__UzvBHGHjEO5XRlC2 | Evaluate: 13 + sqrt(- 4 + 5×3÷3) =? Options:
A) 12 B) 13 C) 14 D) 15 E) 16 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 / 3</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">(20/3) - 4</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">(8/3) ** (1/2)</gadget>
<output>2*sqrt(6)/3 = around 1.632993</output>
<gadget id="calculator">13 + (2*sqrt(6)/3)</gadget>
<output>2*sqrt(6)/3 + 13 = around 14.632993</output>
<result>C</result> | C | 14 | Evaluate: 13 + sqrt(- 4 + 5×3÷3) =? | {
"A": "12",
"B": "13",
"C": "14",
"D": "15",
"E": "16"
} | add(13, sqrt(subtract(divide(multiply(5, const_4.0), 3), 4))) | multiply(n3,n2)|divide(#0,n4)|subtract(#1,n1)|sqrt(#2)|add(n0,#3)| | "according to order of operations , inner brackets first where 5 x 3 ã · 3 is first calculated since it has a multiplication and a division . 5 ã — 3 ã · 3 = 15 ã · 3 = 5 hence 13 + sqrt ( - 4 + 5 ã — 3 ã · 3 ) = 13 + sqrt ( - 4 + 5 ) = 13 + sqrt ( 1 ) = 13 + 1 = 14 correct answer c ) 14" | general |
math_qa__Ksdr1bodbVcad8Ag | At what rate percent on simple interest will Rs.750 amount to Rs.1125 in 5 years? Choose the most appropriate option:
A) 2 B) 10 C) 4 D) 5 E) 6 | <gadget id="calculator">1_125 - 750</gadget>
<output>375</output>
<gadget id="calculator">375 / 750</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) / 5</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>
<result>B</result> | B | 10 | At what rate percent on simple interest will Rs.750 amount to Rs.1125 in 5 years? | {
"A": "2",
"B": "10",
"C": "4",
"D": "5",
"E": "6"
} | multiply(divide(divide(subtract(1125, 750), 750), 5), const_100) | subtract(n1,n0)|divide(#0,n0)|divide(#1,n2)|multiply(#2,const_100)| | "375 = ( 750 * 5 * r ) / 100 r = 10 % . answer : b" | gain |
math_qa__MQnGCKDJbJCbqmOA | If two positive numbers are in the ratio 1/6 : 1/5, then by what percent is the second number more than the first? Choose the correct choice from the following: A) 70 % B) 90 % C) 60 % D) 50 % E) 20 % | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>E</result> | E | 20 | If two positive numbers are in the ratio 1/6 : 1/5, then by what percent is the second number more than the first? | {
"A": "70 %",
"B": "90 %",
"C": "60 %",
"D": "50 %",
"E": "20 %"
} | multiply(divide(1, 5), const_100) | divide(n0,n3)|multiply(#0,const_100)| | "given ratio = 1 / 6 : 1 / 5 = 5 : 6 let first number be 5 x and the second number be 9 x . the second number is more than first number by 1 x . required percentage = x / 5 x * 100 = 20 % . answer : e" | general |
math_qa__FiQGKILSowqLAIL7 | Given two cylindrical containers--A and B. Cylinder A has a diameter of 12 meters and a height of 10 meters. Cylinder B has a radius of 2 meters and a height of 4 meters. If cylinder A is filled to capacity with water, how many cylinder B will be filled to capacity with the content of cylinder A? Choose the most appropriate option: A) 23 B) 22 C) 21 D) 25 E) 24 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">pi * (6 ** 2) * 10</gadget>
<output>360*pi = around 1_130.973355</output>
<gadget id="calculator">pi * (2 ** 2) * 4</gadget>
<output>16*pi = around 50.265482</output>
<gadget id="calculator">(360*pi) / (16*pi)</gadget>
<output>45/2 = around 22.5</output>
<result>B</result> | B | 22 | Given two cylindrical containers--A and B. Cylinder A has a diameter of 12 meters and a height of 10 meters. Cylinder B has a radius of 2 meters and a height of 4 meters. If cylinder A is filled to capacity with water, how many cylinder B will be filled to capacity with the content of cylinder A? | {
"A": "23",
"B": "22",
"C": "21",
"D": "25",
"E": "24"
} | divide(volume_cylinder(divide(12, 2), 10), volume_cylinder(2, 4)) | divide(n0,n2)|volume_cylinder(n2,n3)|volume_cylinder(#0,n1)|divide(#2,#1) | calculate the volume of the larger cylinder and divide it by the volume of the smaller cylinder . volume of cylinder = π r 2 h cylinder a volume = 1130.97 cylinder b volume = 50.27 therefore the number of cylinders b that can be filled to capacity = 1130.97 / 50.27 = 22.5 answer is b only 22 cylinders b can be filled to capacity . | geometry |
math_qa__1yLjK5HwbLql8ZeG | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 18° of the circle, what percentage of MegaTek employees are in manufacturing? Choose the correct option:
A) 5 %
B) 25 %
C) 30 %
D) 35 %
E) 72 % | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">18 / 360</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 100</gadget>
<output>5</output>
<result>A</result> | A | 5 | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 18° of the circle, what percentage of MegaTek employees are in manufacturing? | {
"A": "5 %",
"B": "25 %",
"C": "30 %",
"D": "35 %",
"E": "72 %"
} | multiply(divide(18, divide(const_3600, const_10)), const_100) | divide(const_3600,const_10)|divide(n0,#0)|multiply(#1,const_100) | answer : a 18 ° divided by 360 ° equals 0.05 , therefore the sector is equal to 5 % of the total | physics |
math_qa__FawLTC4uYQYOtXaN | A river 7m deep and 75 m wide is flowing at the rate of 4 kmph the amount of water that runs into the sea per minute is? Pick:
A) 54996.5 B) 32296.5 C) 34996.5 D) 34996.5 E) 31255.5 | <gadget id="calculator">7 * 75</gadget>
<output>525</output>
<gadget id="calculator">4 * 1_000</gadget>
<output>4_000</output>
<gadget id="calculator">525 * 4_000</gadget>
<output>2_100_000</output>
<gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">2_100_000 / 60</gadget>
<output>35_000</output>
<result>C</result> | C | 34,996.5 | A river 7m deep and 75 m wide is flowing at the rate of 4 kmph the amount of water that runs into the sea per minute is? | {
"A": "54996.5",
"B": "32296.5",
"C": "34996.5",
"D": "34996.5",
"E": "31255.5"
} | divide(multiply(multiply(7, 75), multiply(4, const_1000)), multiply(const_1, const_60)) | multiply(n0,n1)|multiply(n2,const_1000)|multiply(const_1,const_60)|multiply(#0,#1)|divide(#3,#2)| | "rate of water flow - 4 kmph - - 4000 / 60 - - 66.66 m / min depth of river - - 7 m width of river - - 75 m vol of water per min - - 66.66 * 7 * 75 - - - 34996.5 answer c" | physics |
math_qa__chanGLg6F67JFKme | What is the largest 4 digit number exactly divisible by 24? Choose the correct choice from the following choices
A) 4676
B) 4678
C) 8888
D) 9504
E) 9984 | <gadget id="calculator">10 ** 4</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 24</gadget>
<output>1_250/3 = around 416.666667</output>
<gadget id="calculator">floor(1_250/3)</gadget>
<output>416</output>
<gadget id="calculator">416 * 24</gadget>
<output>9_984</output>
<result>E</result> | E | 9,984 | What is the largest 4 digit number exactly divisible by 24? | {
"A": "4676",
"B": "4678",
"C": "8888",
"D": "9504",
"E": "9984"
} | multiply(floor(divide(power(const_10, 4), 24)), 24) | power(const_10,n0)|divide(#0,n1)|floor(#1)|multiply(n1,#2)| | "largest 4 digit number = 9999 9999 ÷ 24 = 416 , remainder = 15 hence largest 4 digit number exactly divisible by 24 = 9999 - 15 = 9984 answer : e" | general |
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