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stringlengths 7
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math_qa__yakvu6VpPzKiEWNq | The cross-section of a stream is a trapezium in shape. If the stream is 10 m wide at the top and the area of cross-section is 640 sq m, the depth of stream is 80m and width at the bottom is? Choose the correct choice from the following:
A) 2 m
B) 6 m
C) 4 m
D) 8 m
E) 9 m | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">80 * (1/2)</gadget>
<output>40</output>
<gadget id="calculator">40 * 10</gadget>
<output>400</output>
<gadget id="calculator">640 - 400</gadget>
<output>240</output>
<gadget id="calculator">240 / 40</gadget>
<output>6</output>
<result>B</result> | B | 6 | The cross-section of a stream is a trapezium in shape. If the stream is 10 m wide at the top and the area of cross-section is 640 sq m, the depth of stream is 80m and width at the bottom is? | {
"A": "2 m",
"B": "6 m",
"C": "4 m",
"D": "8 m",
"E": "9 m"
} | divide(subtract(640, multiply(multiply(80, divide(const_1, const_2)), 10)), multiply(80, divide(const_1, const_2))) | divide(const_1,const_2)|multiply(n2,#0)|multiply(n0,#1)|subtract(n1,#2)|divide(#3,#1) | 1 / 2 * 80 ( 10 + b ) = 640 b = 6 m answer : b | physics |
math_qa__hKnRIde2jcYxNvNx | The cost of 2 books and 2 magazines is $26. The cost of 1 book and 3 magazines is $27. How much does 1 magazine cost? Choose the correct choice:
A) 8 B) 5 C) 7 D) 4 E) 6 | <gadget id="calculator">2 * 27</gadget>
<output>54</output>
<gadget id="calculator">54 - 26</gadget>
<output>28</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">28 / 4</gadget>
<output>7</output>
<result>C</result> | C | 7 | The cost of 2 books and 2 magazines is $26. The cost of 1 book and 3 magazines is $27. How much does 1 magazine cost? | {
"A": "8",
"B": "5",
"C": "7",
"D": "4",
"E": "6"
} | divide(subtract(multiply(2, 27), 26), subtract(multiply(2, 3), 2)) | multiply(n0,n5)|multiply(n0,n4)|subtract(#0,n2)|subtract(#1,n0)|divide(#2,#3) | let the cost of 1 book = x , let the cost of 1 magazine = y 2 x + 2 y = 26 x = ( 26 - 2 y ) / 2 x = 13 - y again , ( 13 - y ) + 3 y = 27 13 + 2 y = 27 2 y = 14 y = 7 answer : c | general |
math_qa__vdFwvEW4z8Vuzgzd | The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this year actually decreased by 20 percent. What percent of the projected attendance was the actual attendance? Choose the most appropriate option.
A) 45 %
B) 56 %
C) 64 %
D) 75 %
E) 80 % | <gadget id="calculator">20 * 4</gadget>
<output>80</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">80 / 125</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">(16/25) * 100</gadget>
<output>64</output>
<result>C</result> | C | 64 | The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this year actually decreased by 20 percent. What percent of the projected attendance was the actual attendance? | {
"A": "45 %",
"B": "56 %",
"C": "64 %",
"D": "75 %",
"E": "80 %"
} | multiply(divide(multiply(20, const_4), add(const_100, 25)), const_100) | add(n0,const_100)|multiply(n1,const_4)|divide(#1,#0)|multiply(#2,const_100) | last year attendance = 100 ( assume ) ; projected attendance = 125 ; actual attendance = 80 . the actual attendance therefore was ( actual ) / ( project ) = 80 / 125 * 100 = 64 $ of the projected attendance . answer : c . | general |
math_qa__j6LksEWSK51Xy1r2 | If x+y=270, x-y=200, for integers of x and y, y=? Choose the correct choice from the following choices
A) 200
B) 235
C) 50
D) 115
E) 150 | <gadget id="calculator">270 + 200</gadget>
<output>470</output>
<gadget id="calculator">470 / 2</gadget>
<output>235</output>
<result>B</result> | B | 235 | If x+y=270, x-y=200, for integers of x and y, y=? | {
"A": "200",
"B": "235",
"C": "50",
"D": "115",
"E": "150"
} | divide(add(270, 200), const_2) | add(n0,n1)|divide(#0,const_2)| | "x + y = 270 x - y = 200 2 x = 70 x = 35 y = 235 answer is b" | general |
math_qa__HTobOSoCCEunDXSn | A and B together can do a piece of work in 6 days and A alone can do it in 11 days. In how many days can B alone can do it? Choose the correct choice from the following: A) 12 days B) 15 days C) 66 / 5 days D) 21 days E) 22 / 5 days | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 11</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/6) - (1/11)</gadget>
<output>5/66 = around 0.075758</output>
<gadget id="calculator">1 / (5/66)</gadget>
<output>66/5 = around 13.2</output>
<result>C</result> | C | 13.2 | A and B together can do a piece of work in 6 days and A alone can do it in 11 days. In how many days can B alone can do it? | {
"A": "12 days",
"B": "15 days",
"C": "66 / 5 days",
"D": "21 days",
"E": "22 / 5 days"
} | inverse(subtract(inverse(6), inverse(11))) | inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2)| | "explanation : a and b can do work 1 / 6 in 1 day a alone can do 1 / 11 work in 1 day b alone can do ( 1 / 6 - 1 / 11 ) = 5 / 66 work in 1 day = > complete work can be done in 66 / 5 days by b answer : option c" | physics |
math_qa__Rr2CCzoQEpyNJ9gZ | The average weight of 22 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class. Choose the correct choice from the following answers: A) 48.89 B) 42.25 C) 50 D) 51.25 E) 52.25 | <gadget id="calculator">22 * 50.25</gadget>
<output>1_105.5</output>
<gadget id="calculator">8 * 45.15</gadget>
<output>361.2</output>
<gadget id="calculator">1_105.5 + 361.2</gadget>
<output>1_466.7</output>
<gadget id="calculator">22 + 8</gadget>
<output>30</output>
<gadget id="calculator">1_466.7 / 30</gadget>
<output>48.89</output>
<result>A</result> | A | 48.89 | The average weight of 22 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class. | {
"A": "48.89",
"B": "42.25",
"C": "50",
"D": "51.25",
"E": "52.25"
} | divide(add(multiply(22, 50.25), multiply(8, 45.15)), add(22, 8)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0) | explanation : average weight of 22 boys = 50.25 total weight of 22 boys = 50.25 × 22 average weight of remaining 8 boys = 45.15 total weight of remaining 8 boys = 45.15 × 8 total weight of all boys in the class = ( 50.25 × 16 ) + ( 45.15 × 8 ) total boys = 22 + 8 = 30 average weight of all the boys = ( ( 50.25 × 22 ) + ( 45.15 × 8 ) ) / 30 = 48.89 answer : option a | general |
math_qa__03IAFp55Fv5PQJql | Profits in the partnership of Bess, Bill and Bob are shared in the ratio 1 : 2 : 3. If Bill's share of the profits is $300, what is Bob's share? Pick one.
A) $ 150 B) $ 900 C) $ 600 D) $ 450 E) none | <gadget id="calculator">300 / 1</gadget>
<output>300</output>
<gadget id="calculator">300 / 2</gadget>
<output>150</output>
<gadget id="calculator">300 + 150</gadget>
<output>450</output>
<gadget id="calculator">450 + 150</gadget>
<output>600</output>
<gadget id="calculator">600 + 300</gadget>
<output>900</output>
<result>B</result> | B | 900 | Profits in the partnership of Bess, Bill and Bob are shared in the ratio 1 : 2 : 3. If Bill's share of the profits is $300, what is Bob's share? | {
"A": "$ 150",
"B": "$ 900",
"C": "$ 600",
"D": "$ 450",
"E": "none"
} | add(add(add(divide(300, 1), divide(300, 2)), divide(300, 2)), divide(300, 1)) | divide(n3,n0)|divide(n3,n1)|add(#0,#1)|add(#2,#1)|add(#3,#0) | ans is d given profit ratio , bess : bill : bob = 1 : 2 : 3 to make bill ' s portion $ 300 , multiply by $ 150 = > bess : bill : bob = $ 150 : $ 300 : $ 450 = > bob ' s share = $ 450 | other |
math_qa__MwdkdVzpsD9z1ncg | A sporting goods store sold 60 Frisbees in one week, some for $3 and the rest for $4 each. If receipts from Frisbee sales for the week totaled $204, what is the fewest number of $4 Frisbees that could have been sold? Choose the correct choice from the following options
A) 24 B) 12 C) 8 D) 4 E) 2 | <gadget id="calculator">60 * 3</gadget>
<output>180</output>
<gadget id="calculator">204 - 180</gadget>
<output>24</output>
<result>A</result> | A | 24 | A sporting goods store sold 60 Frisbees in one week, some for $3 and the rest for $4 each. If receipts from Frisbee sales for the week totaled $204, what is the fewest number of $4 Frisbees that could have been sold? | {
"A": "24",
"B": "12",
"C": "8",
"D": "4",
"E": "2"
} | subtract(204, multiply(60, 3)) | multiply(n0,n1)|subtract(n3,#0)| | "in this question however , because we are told that exactly 64 frisbees have been sold and revenue was exactly $ 204 , there is only one possible solution for the number of $ 3 and $ 4 frisbees sold . to solve , we have 2 equations and 2 unknowns let x = number of $ 3 frisbees sold let y = number of $ 4 frisbees sold x + y = 60 3 x + 4 y = 204 x = 60 - y 3 ( 60 - y ) + 4 y = 204 180 - 3 y + 4 y = 204 y = 24 answer : a" | general |
math_qa__UZbOpEF4uBMtoppd | Patrick purchased 90 pencils and sold them at a loss equal to the selling price of 40 pencils. The cost of 90 pencils is how many times the selling price of 90 pencils? Select the correct option.
A) 0.75 B) 0.8 C) 1 D) 1.2 E) 1.44 | <gadget id="calculator">90 + 40</gadget>
<output>130</output>
<gadget id="calculator">90 / 130</gadget>
<output>9/13 = around 0.692308</output>
<gadget id="calculator">1 / (9/13)</gadget>
<output>13/9 = around 1.444444</output>
<result>E</result> | E | 1.44 | Patrick purchased 90 pencils and sold them at a loss equal to the selling price of 40 pencils. The cost of 90 pencils is how many times the selling price of 90 pencils? | {
"A": "0.75",
"B": "0.8",
"C": "1",
"D": "1.2",
"E": "1.44"
} | inverse(divide(90, add(90, 40))) | add(n0,n1)|divide(n0,#0)|inverse(#1)| | "say the cost price of 90 pencils was $ 90 ( $ 1 per pencil ) and the selling price of 1 pencil was p . selling at a loss : 90 - 90 p = 40 p - - > p = 9 / 13 . ( cost price ) / ( selling price ) = 1 / ( 9 / 13 ) = 13 / 9 = 1.44 . answer : e ." | general |
math_qa__n0JocOd2KiTkLUix | Tom purchased 8kg of apples at the rate of 70 per kg and 9 kg of mangoes at the rate of 75 per kg. How much amount did he pay to the shopkeeper?
Choose the correct answer:
A) 1040 B) 1045 C) 1055 D) 1060 E) 1235 | <gadget id="calculator">8 * 70</gadget>
<output>560</output>
<gadget id="calculator">9 * 75</gadget>
<output>675</output>
<gadget id="calculator">560 + 675</gadget>
<output>1_235</output>
<result>E</result> | E | 1,235 | Tom purchased 8kg of apples at the rate of 70 per kg and 9 kg of mangoes at the rate of 75 per kg. How much amount did he pay to the shopkeeper? | {
"A": "1040",
"B": "1045",
"C": "1055",
"D": "1060",
"E": "1235"
} | add(multiply(8, 70), multiply(9, 75)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1) | cost of 8 kg apples = 70 × 8 = 560 . cost of 9 kg of mangoes = 75 × 9 = 675 . total cost he has to pay = 560 + 675 = 1235 . e ) | gain |
math_qa__29j5ikva6FJ8Z2cr | It takes Joey the postman 1 hours to run a 6 mile long route every day. He delivers packages and then returns to the post office along the same path. If the average speed of the round trip is 8 mile/hour, what is the speed with which Joey returns? Choose the correct choice from the following choices:
A) 11
B) 12
C) 13
D) 14
E) 15 | <gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">12 / 8</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">6 / (1/2)</gadget>
<output>12</output>
<result>B</result> | B | 12 | It takes Joey the postman 1 hours to run a 6 mile long route every day. He delivers packages and then returns to the post office along the same path. If the average speed of the round trip is 8 mile/hour, what is the speed with which Joey returns? | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | divide(6, subtract(divide(multiply(const_2, 6), 8), 1)) | multiply(n1,const_2)|divide(#0,n2)|subtract(#1,n0)|divide(n1,#2)| | "let his speed for one half of the journey be 6 miles an hour let the other half be x miles an hour now , avg speed = 8 mile an hour 2 * 6 * x / 6 + x = 8 12 x = 8 x + 48 = > x = 12 b" | physics |
math_qa__WCcKbJp4oITL4tMA | If (A-B-C+D = 18) and (A+B-C-D = 6), what is the value of (B-D)^2? Choose the correct choice from the following answers:
A) 4 .
B) 8 .
C) 12 .
D) 16 .
E) 36 . | <gadget id="calculator">18 + 6</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">6 - 12</gadget>
<output>-6</output>
<gadget id="calculator">(-6) ** 2</gadget>
<output>36</output>
<result>E</result> | E | 36 | If (A-B-C+D = 18) and (A+B-C-D = 6), what is the value of (B-D)^2? | {
"A": "4 .",
"B": "8 .",
"C": "12 .",
"D": "16 .",
"E": "36 ."
} | power(subtract(6, divide(add(18, 6), 2)), 2) | add(n0,n1)|divide(#0,n2)|subtract(n1,#1)|power(#2,n2)| | "eq 1 : a - b - c + d = 18 eq 2 : a + b - c - d = 6 ( 1 ) subtract eq 1 from eq 2 a - b - c + d = 18 - a + b - c - d = 6 - - - - - - - - - - - - - - - - - - - - - - - - - 2 b + 2 d = 12 ( 2 ) simplify - b + d = 6 b - d = - 6 ( b - d ) ^ 2 = ( - 6 ) ^ 2 = 36 my answer : e" | general |
math_qa__9P1m1WJLQVtyF4oy | A car traveling at a certain constant speed takes 5 seconds longer to travel 1 km than it would take to travel 1 km at 60 km/hour. At what speed, in km/hr, is the car traveling? Choose the correct choice:
A) 70 B) 72 C) 74 D) 75 E) 55 | <gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">3_600 * (1/60)</gadget>
<output>60</output>
<gadget id="calculator">60 + 5</gadget>
<output>65</output>
<gadget id="calculator">65 / 3_600</gadget>
<output>13/720 = around 0.018056</output>
<gadget id="calculator">1 / (13/720)</gadget>
<output>720/13 = around 55.384615</output>
<result>E</result> | E | 55 | A car traveling at a certain constant speed takes 5 seconds longer to travel 1 km than it would take to travel 1 km at 60 km/hour. At what speed, in km/hr, is the car traveling? | {
"A": "70",
"B": "72",
"C": "74",
"D": "75",
"E": "55"
} | divide(1, divide(add(multiply(const_3600, divide(1, 60)), 5), const_3600)) | divide(n1,n3)|multiply(#0,const_3600)|add(n0,#1)|divide(#2,const_3600)|divide(n1,#3)| | "time to cover 1 kilometer at 80 kilometers per hour is 1 / 60 hours = 3,600 / 60 seconds = 60 seconds ; time to cover 1 kilometer at regular speed is 60 + 5 = 65 seconds = 65 / 3,600 hours = 1 / 55 hours ; so , we get that to cover 1 kilometer 1 / 55 hours is needed - - > regular speed 55 kilometers per hour ( rate is a reciprocal of time or rate = distance / time ) . answer : e" | physics |
math_qa__5CgNsd98RqrSL08y | If W is the set of all the integers between 10 and 332, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers?
Select
A) 111 B) 28 C) 160 D) 213 E) 107 | <gadget id="calculator">332 - 10</gadget>
<output>322</output>
<gadget id="calculator">322 / 3</gadget>
<output>322/3 = around 107.333333</output>
<gadget id="calculator">floor(322/3)</gadget>
<output>107</output>
<gadget id="calculator">322 / 2</gadget>
<output>161</output>
<gadget id="calculator">107 + 161</gadget>
<output>268</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">322 / 6</gadget>
<output>161/3 = around 53.666667</output>
<gadget id="calculator">floor(161/3)</gadget>
<output>53</output>
<gadget id="calculator">268 - 53</gadget>
<output>215</output>
<result>D</result> | D | 213 | If W is the set of all the integers between 10 and 332, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers? | {
"A": "111",
"B": "28",
"C": "160",
"D": "213",
"E": "107"
} | subtract(add(floor(divide(subtract(332, 10), 3)), divide(subtract(332, 10), 2)), floor(divide(subtract(332, 10), multiply(2, 3)))) | multiply(n3,n2)|subtract(n1,n0)|divide(#1,n3)|divide(#1,n2)|divide(#1,#0)|floor(#3)|floor(#4)|add(#2,#5)|subtract(#7,#6)| | "official solution : number of multiples of 3 step 1 . subtract the extreme multiples of 3 within the range ( the greatest is 330 , the smallest is 12 ) : 330 - 12 = 318 step 2 . divide by 3 : 318 / 3 = 106 step 3 . add 1 : 106 + 1 = 107 . so there are 107 multiples of 3 within the range : examples are 51 , 54 , 57 , 60 , etc . number of multiples of 2 step 1 . subtract the extreme multiples of 2 within the range ( the greatest is 330 , the smallest is 12 ) : 330 - 12 = 318 step 2 . divide by 2 : 318 / 2 = 159 step 3 . add 1 : 159 + 1 = 160 . so there are 160 multiples of 2 within the range : examples are 50 , 52 , 54 , 56 , 58 , 60 etc . add the 107 multiples of 3 and the 160 multiples of 2 : 107 + 160 = 267 . however , by adding the multiples of 2 and the multiples of 3 , we are effectively counting several numbers twice : for example , 54 and 60 are parts of both the lists above . so we ca n ' t just take 107 + 160 = 267 . find the number of multiples of 6 ( which are the double counted , as 6 is divisible by both 2 and 3 ) , and subtract it from 25 : step 1 . subtract the extreme multiples of 6 within the range ( the greatest is 72 , the smallest is 54 ) : 330 - 12 = 318 step 2 . divide by 6 : 318 / 6 = 53 step 3 . add 1 : 53 + 1 = 54 . so there are 54 multiples of 6 within the range : we counted 54 numbers twice . subtract the 54 multiples of 6 from the sum of the multiples of 2 and 3 : = 107 + 160 - 54 = 267 - 54 = 213 therefore , the final number of multiples of 2 , 3 or 6 is 213 . hence , this is the correct answer . ( d )" | other |
math_qa__ZlhMQamEV9PFSLCm | A tank with a volume of 30 cubic feet has one inlet pipe and 2 outlet pipes. The inlet pipe fills water into the tank at the rate of 3 cubic inches/min and the 2 outlet pipes empty it out at the rates of 12 cubic inches/min and 6 cubic inches/min respectively. If all 3 pipes are opened when the tank is full, how many minutes does it take to empty the tank? (1 foot = 12 inches) Choose the most appropriate option.
A) 2345 B) 3456 C) 4567 D) 5678 E) 6789 | <gadget id="calculator">12 ** 3</gadget>
<output>1_728</output>
<gadget id="calculator">30 * 1_728</gadget>
<output>51_840</output>
<gadget id="calculator">12 + 6</gadget>
<output>18</output>
<gadget id="calculator">18 - 3</gadget>
<output>15</output>
<gadget id="calculator">51_840 / 15</gadget>
<output>3_456</output>
<result>B</result> | B | 3,456 | A tank with a volume of 30 cubic feet has one inlet pipe and 2 outlet pipes. The inlet pipe fills water into the tank at the rate of 3 cubic inches/min and the 2 outlet pipes empty it out at the rates of 12 cubic inches/min and 6 cubic inches/min respectively. If all 3 pipes are opened when the tank is full, how many minutes does it take to empty the tank? (1 foot = 12 inches) | {
"A": "2345",
"B": "3456",
"C": "4567",
"D": "5678",
"E": "6789"
} | divide(multiply(30, power(12, const_3)), subtract(add(12, 6), 3)) | add(n4,n5)|power(n4,const_3)|multiply(n0,#1)|subtract(#0,n2)|divide(#2,#3) | the tank is emptied at this rate : 12 + 6 - 3 = 15 cubic inches / min the tank has a volume of 30 * 12 * 12 * 12 = 51840 cubic inches . the time it takes to empty the tank is 51840 / 15 = 3456 minutes . the answer is b . | physics |
math_qa__fzHiaKFRRWZxk7bW | An investment yields an interest payment of $231 each month. If the simple annual interest rate is 9%, what is the amount of the investment? Choose the correct choice from the following:
A) $ 28,300 B) $ 30,800 C) $ 31,300 D) $ 32,500 E) $ 35,100 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">231 / (3/4)</gadget>
<output>308</output>
<gadget id="calculator">308 * 100</gadget>
<output>30_800</output>
<result>B</result> | B | 30,800 | An investment yields an interest payment of $231 each month. If the simple annual interest rate is 9%, what is the amount of the investment? | {
"A": "$ 28,300",
"B": "$ 30,800",
"C": "$ 31,300",
"D": "$ 32,500",
"E": "$ 35,100"
} | multiply(divide(231, divide(9, multiply(const_3, const_4))), const_100) | multiply(const_3,const_4)|divide(n1,#0)|divide(n0,#1)|multiply(#2,const_100)| | "let the principal amount = p simple annual interest = 9 % simple monthly interest = ( 9 / 12 ) = ( 3 / 4 ) % ( 3 / 4 ) * ( p / 100 ) = 230 = > p = ( 231 * 4 * 10 ^ 2 ) / 3 = 77 * 4 * 10 ^ 2 = 308 * 10 ^ 2 = 30800 answer b" | gain |
math_qa__XZAaecSSfWBKCtxX | If the price of sugar rises from Rs. 6 per kg to Rs. 7.50 per kg, a person, to have no increase in the expenditure on sugar, will have to reduce his consumption of sugar by Choose the correct choice from the following choices:
A) 15 % B) 20 % C) 25 % D) 30 % E) none | <gadget id="calculator">1 * 6</gadget>
<output>6</output>
<gadget id="calculator">6 / 7.5</gadget>
<output>0.8</output>
<gadget id="calculator">1 - 0.8</gadget>
<output>0.2</output>
<gadget id="calculator">0.2 * 100</gadget>
<output>20</output>
<result>B</result> | B | 20 | If the price of sugar rises from Rs. 6 per kg to Rs. 7.50 per kg, a person, to have no increase in the expenditure on sugar, will have to reduce his consumption of sugar by | {
"A": "15 %",
"B": "20 %",
"C": "25 %",
"D": "30 %",
"E": "none"
} | multiply(subtract(const_1, divide(multiply(const_1, 6), 7.50)), const_100) | multiply(n0,const_1)|divide(#0,n1)|subtract(const_1,#1)|multiply(#2,const_100)| | "sol . let the original consumption = 100 kg and new consumption = x kg . so , 100 x 6 = x × 7.50 = x = 80 kg . ∴ reduction in consumption = 20 % . answer b" | general |
math_qa__DPE7g7xdNe1KQz1m | Natasha climbs up a hill, and descends along the same way she went up. It takes her 4 hours to reach the top and 2 hours to come back down. If her average speed along the whole journey is 3.5 kilometers per hour, what was her average speed (in kilometers per hour) while climbing to the top? Choose the correct choice
A) 2.125 B) 2.375 C) 2.625 D) 2.675 E) 2.825 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 3.5</gadget>
<output>21</output>
<gadget id="calculator">21 / 2</gadget>
<output>21/2 = around 10.5</output>
<gadget id="calculator">(21/2) / 4</gadget>
<output>21/8 = around 2.625</output>
<result>C</result> | C | 2.625 | Natasha climbs up a hill, and descends along the same way she went up. It takes her 4 hours to reach the top and 2 hours to come back down. If her average speed along the whole journey is 3.5 kilometers per hour, what was her average speed (in kilometers per hour) while climbing to the top? | {
"A": "2.125",
"B": "2.375",
"C": "2.625",
"D": "2.675",
"E": "2.825"
} | divide(divide(multiply(add(4, 2), 3.5), 2), 4) | add(n0,n1)|multiply(n2,#0)|divide(#1,n1)|divide(#2,n0)| | "let the distance to the top be x , so the total distance traveled by natasha is 2 x . the total time is 4 + 2 = 6 hours the average speed = total distance / total time taken = 2 x / 6 = x / 3 the average speed of the complete journey is 3.5 km / hour x / 3 = 3.5 x = 10.5 km the average speed while climbing = distance / time = 10.5 / 4 = 2.625 km / h the answer is c ." | physics |
math_qa__yIPNpJmWLo0HRPpI | How many positive integers D between 200 and 300 (both inclusive) are not divisible by 2, 3 or 5?
Choose the correct choice:
A) 3 B) 16 C) 75 D) 24 E) 26 | <gadget id="calculator">100 + 1</gadget>
<output>101</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">50 + 1</gadget>
<output>51</output>
<gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">99 / 3</gadget>
<output>33</output>
<gadget id="calculator">33 + 1</gadget>
<output>34</output>
<gadget id="calculator">51 + 34</gadget>
<output>85</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">85 + 21</gadget>
<output>106</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">90 / 30</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">106 + 4</gadget>
<output>110</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">100 - 6</gadget>
<output>94</output>
<gadget id="calculator">94 / 6</gadget>
<output>47/3 = around 15.666667</output>
<gadget id="calculator">(47/3) + 1</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">90 / 15</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">(50/3) + 7</gadget>
<output>71/3 = around 23.666667</output>
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">(71/3) + 11</gadget>
<output>104/3 = around 34.666667</output>
<gadget id="calculator">110 - (104/3)</gadget>
<output>226/3 = around 75.333333</output>
<gadget id="calculator">101 - (226/3)</gadget>
<output>77/3 = around 25.666667</output>
<result>E</result> | E | 26 | How many positive integers D between 200 and 300 (both inclusive) are not divisible by 2, 3 or 5? | {
"A": "3",
"B": "16",
"C": "75",
"D": "24",
"E": "26"
} | subtract(add(const_100, const_1), subtract(add(add(add(add(divide(const_100, const_2), const_1), add(divide(subtract(const_100, const_1), const_3), const_1)), add(divide(const_100, 5), const_1)), add(divide(subtract(const_100, const_10), multiply(multiply(3, 5), 2)), const_1)), add(add(add(divide(subtract(const_100, multiply(const_3, const_2)), multiply(const_3, const_2)), const_1), add(divide(subtract(const_100, const_10), multiply(3, 5)), const_1)), add(divide(const_100, const_10), const_1)))) | add(const_1,const_100)|divide(const_100,const_2)|divide(const_100,n4)|divide(const_100,const_10)|multiply(n3,n4)|multiply(const_2,const_3)|subtract(const_100,const_1)|subtract(const_100,const_10)|add(#1,const_1)|add(#2,const_1)|add(#3,const_1)|divide(#6,const_3)|divide(#7,#4)|multiply(n2,#4)|subtract(const_100,#5)|add(#11,const_1)|add(#12,const_1)|divide(#7,#13)|divide(#14,#5)|add(#8,#15)|add(#17,const_1)|add(#18,const_1)|add(#19,#9)|add(#21,#16)|add(#22,#20)|add(#23,#10)|subtract(#24,#25)|subtract(#0,#26) | 1 ) i figured there are 101 integers ( 300 - 200 + 1 = 101 ) . since the set begins with an even and ends with an even , there are 51 evens . 2 ) question says integers are not divisible by 2 , leaving all of the odds ( 101 - 51 = 50 integers ) . 3 ) question says integers are not divisible by 5 , removing all the integers ending in 5 ( already took out those ending in 0 ) . take out 10 integers ( 2 ? 5 , ? = 0 to 9 ) , leaving us with 40 integers . 4 ) now the painstaking part . we have to remove the remaining numbers that are multiples of 3 . those are 201 , 207 , 213 , 219 , 231 , 237 , 243 , 249 , 261 , 267 , 273 , 279 , 291 , and 297 . . . a total of 14 numbers . 26 numbers left ! 6 ) answer choice e . | other |
math_qa__recKlMI6ns0ex5Ov | The number of the members of a club is more than 50 and less than 80. When 5 people sit at a table, other people exactly divided to 8-people groups (8 people sit at a table) or 7-people groups (7 people sit at a table). If the members are divided to 9-people groups, how many people will be left? Select the correct option:
A) 4
B) 5
C) 6
D) 7
E) 8 | <gadget id="calculator">lcm(8, 7)</gadget>
<output>56</output>
<gadget id="calculator">56 + 5</gadget>
<output>61</output>
<gadget id="calculator">61 % 9</gadget>
<output>7</output>
<result>D</result> | D | 7 | The number of the members of a club is more than 50 and less than 80. When 5 people sit at a table, other people exactly divided to 8-people groups (8 people sit at a table) or 7-people groups (7 people sit at a table). If the members are divided to 9-people groups, how many people will be left? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | reminder(add(lcm(8, 7), 5), 9) | lcm(n3,n5)|add(n2,#0)|reminder(#1,n7)| | "the number of members is 7 k + 5 = 8 j + 5 the only number in this range which satisfies this is 61 . 61 / 9 = 6 ( 9 ) + 7 the answer is d ." | general |
math_qa__ZlxlVVQnflOldyYI | in a certain flower shop , which stocks 4 types of flowers , there are 1 / 3 as many violets as carnations , and 1 / 3 as many tulips as violets . if there are equal numbers of roses and tulips , what percent of the flowers in the shop are carnations ? Choose the most appropriate option
A) 63
B) 64.28
C) 65
D) 66
E) 68 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/9) + (1/9)</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(2/9) + 1</gadget>
<output>11/9 = around 1.222222</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(11/9) + (1/3)</gadget>
<output>14/9 = around 1.555556</output>
<gadget id="calculator">100 / (14/9)</gadget>
<output>450/7 = around 64.285714</output>
<result>B</result> | B | 64.28 | in a certain flower shop , which stocks 4 types of flowers , there are 1 / 3 as many violets as carnations , and 1 / 3 as many tulips as violets . if there are equal numbers of roses and tulips , what percent of the flowers in the shop are carnations ? | {
"A": "63",
"B": "64.28",
"C": "65",
"D": "66",
"E": "68"
} | divide(const_100, add(add(add(divide(const_1, multiply(3, 3)), divide(const_1, multiply(3, 3))), const_1), const_0_33)) | multiply(n2,n2)|divide(const_1,#0)|add(#1,#1)|add(#2,const_1)|add(#3,const_0_33)|divide(const_100,#4) | given : - violets - c / 3 carnations - c tulip - c / 9 rose - c / 9 total flowers in terms of c = c / 3 + c + c / 9 + c / 9 = 14 c / 9 percentage of carnations = c / 14 c / 9 * 100 = 64.28 % answer b | general |
math_qa__nZ4YP8X5eicWnpI6 | Two brother X and Y appeared for an exam. The probability of selection of X is 1/5 and that of B is 2/7. Find the probability that both of them are selected. Options: A) 2 / 35 B) 2 / 30 C) 2 / 63 D) 2 / 29 E) 2 / 10 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(1/5) * (2/7)</gadget>
<output>2/35 = around 0.057143</output>
<result>A</result> | A | 0.057143 | Two brother X and Y appeared for an exam. The probability of selection of X is 1/5 and that of B is 2/7. Find the probability that both of them are selected. | {
"A": "2 / 35",
"B": "2 / 30",
"C": "2 / 63",
"D": "2 / 29",
"E": "2 / 10"
} | multiply(divide(1, 5), divide(2, 7)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)| | "explanation : let a be the event that x is selected and b is the event that y is selected . p ( a ) = 1 / 5 , p ( b ) = 2 / 7 . let c be the event that both are selected . p ( c ) = p ( a ) ã — p ( b ) as a and b are independent events : = ( 1 / 5 ) ã — ( 2 / 7 ) = 2 / 35 answer : a ) 2 / 35" | general |
math_qa__6Inf4SsoBDVzyBXz | The average of runs of a cricket player of 10 innings was 42. How many runs must he make in his next innings so as to increase his average of runs by 4? Choose the correct choice from the following choices
A) 87 B) 86 C) 28 D) 76 E) 80 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">4 + 42</gadget>
<output>46</output>
<gadget id="calculator">11 * 46</gadget>
<output>506</output>
<gadget id="calculator">10 * 42</gadget>
<output>420</output>
<gadget id="calculator">506 - 420</gadget>
<output>86</output>
<result>B</result> | B | 86 | The average of runs of a cricket player of 10 innings was 42. How many runs must he make in his next innings so as to increase his average of runs by 4? | {
"A": "87",
"B": "86",
"C": "28",
"D": "76",
"E": "80"
} | subtract(multiply(add(10, const_1), add(4, 42)), multiply(10, 42)) | add(n0,const_1)|add(n1,n2)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "average after 11 innings = 46 required number of runs = ( 46 * 11 ) - ( 42 * 10 ) = 506 - 420 = 86 . answer : b" | general |
math_qa__9rvYNCWDaDrjvvcV | In a survey of parents, exactly 9/10 of the mothers and 3/4 of the fathers held full-time jobs. If 40 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs? Choose the correct choice from the following choices:
A) 27 % B) 21 % C) 19 % D) 18 % E) 16 % | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 60</gadget>
<output>45</output>
<gadget id="calculator">60 - 45</gadget>
<output>15</output>
<gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 40</gadget>
<output>36</output>
<gadget id="calculator">40 - 36</gadget>
<output>4</output>
<gadget id="calculator">15 + 4</gadget>
<output>19</output>
<result>C</result> | C | 19 | In a survey of parents, exactly 9/10 of the mothers and 3/4 of the fathers held full-time jobs. If 40 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs? | {
"A": "27 %",
"B": "21 %",
"C": "19 %",
"D": "18 %",
"E": "16 %"
} | add(subtract(subtract(const_100, 40), multiply(divide(3, 4), subtract(const_100, 40))), subtract(40, multiply(divide(9, 10), 40))) | divide(n2,n3)|divide(n0,n1)|subtract(const_100,n4)|multiply(#0,#2)|multiply(n4,#1)|subtract(#2,#3)|subtract(n4,#4)|add(#5,#6)| | "fathers without full - time jobs are 1 / 4 * 3 / 5 = 3 / 20 of all the parents surveyed . mothers without full - time jobs are 1 / 10 * 2 / 5 = 2 / 50 of all the parents surveyed . the percent of parents without full - time jobs is 3 / 20 + 2 / 50 = 19 / 100 = 19 % the answer is c ." | general |
math_qa__jr4cxpBiuNVcUdcf | Cereal A is 8% sugar by weight, whereas healthier but less delicious Cereal B is 2% sugar by weight. To make a delicious and healthy mixture that is 4% sugar, what should be the ratio of Cereal A to Cereal B, by weight? Choices
A) 2 : 9 B) 2 : 7 C) 1 : 2 D) 1 : 4 E) 1 : 3 | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">2 / 4</gadget>
<output>1/2 = around 0.5</output>
<result>C</result> | C | 0.5 | Cereal A is 8% sugar by weight, whereas healthier but less delicious Cereal B is 2% sugar by weight. To make a delicious and healthy mixture that is 4% sugar, what should be the ratio of Cereal A to Cereal B, by weight? | {
"A": "2 : 9",
"B": "2 : 7",
"C": "1 : 2",
"D": "1 : 4",
"E": "1 : 3"
} | divide(subtract(4, 2), subtract(8, 4)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "( 8 / 100 ) a + ( 2 / 100 ) b = ( 4 / 100 ) ( a + b ) 4 a = 2 b = > a / b = 1 / 2 answer is c ." | general |
math_qa__XAoyIU2TWWHDpYBe | The ratio of boarders to day students at a school was originally 2 to 5. However, after a number of new boarders join the initial 120 boarders, the ratio changed to 1 to 2. If no boarders became day students and vice versa, and no students left the school, how many new boarders joined the school? Answers: A) 30 B) 50 C) 70 D) 80 E) 90 | <gadget id="calculator">120 / 2</gadget>
<output>60</output>
<gadget id="calculator">60 * 5</gadget>
<output>300</output>
<gadget id="calculator">300 / 2</gadget>
<output>150</output>
<gadget id="calculator">150 - 120</gadget>
<output>30</output>
<result>A</result> | A | 30 | The ratio of boarders to day students at a school was originally 2 to 5. However, after a number of new boarders join the initial 120 boarders, the ratio changed to 1 to 2. If no boarders became day students and vice versa, and no students left the school, how many new boarders joined the school? | {
"A": "30",
"B": "50",
"C": "70",
"D": "80",
"E": "90"
} | subtract(divide(multiply(divide(120, 2), 5), 2), 120) | divide(n2,n0)|multiply(n1,#0)|divide(#1,n4)|subtract(#2,n2)| | "let x be the number of new boarders . the ratio changed from 2 : 5 = 4 : 10 up to 1 : 2 = 5 : 10 . 120 / ( 120 + x ) = 4 / 5 x = 30 the answer is a ." | other |
math_qa__FoIwJlvLu7ygY06z | A 20 kg metal bar made of alloy of tin and silver lost 2 kg of its weight in the water. 10 kg of tin loses 1.375 kg in the water; 5 kg of silver loses 0.375 kg. What is the ratio of tin to silver in the bar?
Choose the correct option: A) 1 / 4 B) 2 / 5 C) 1 / 2 D) 3 / 5 E) 2 / 3 | <gadget id="calculator">0.375 / 5</gadget>
<output>0.075</output>
<gadget id="calculator">0.075 * 20</gadget>
<output>1.5</output>
<gadget id="calculator">2 - 1.5</gadget>
<output>0.5</output>
<gadget id="calculator">1.375 / 10</gadget>
<output>0.1375</output>
<gadget id="calculator">0.1375 - 0.075</gadget>
<output>0.0625</output>
<gadget id="calculator">0.5 / 0.0625</gadget>
<output>8</output>
<gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<result>E</result> | E | 0.666667 | A 20 kg metal bar made of alloy of tin and silver lost 2 kg of its weight in the water. 10 kg of tin loses 1.375 kg in the water; 5 kg of silver loses 0.375 kg. What is the ratio of tin to silver in the bar? | {
"A": "1 / 4",
"B": "2 / 5",
"C": "1 / 2",
"D": "3 / 5",
"E": "2 / 3"
} | divide(divide(subtract(2, multiply(divide(0.375, 5), 20)), subtract(divide(1.375, 10), divide(0.375, 5))), subtract(20, divide(subtract(2, multiply(divide(0.375, 5), 20)), subtract(divide(1.375, 10), divide(0.375, 5))))) | divide(n5,n4)|divide(n3,n2)|multiply(n0,#0)|subtract(#1,#0)|subtract(n1,#2)|divide(#4,#3)|subtract(n0,#5)|divide(#5,#6)| | "the bar lost certain percentage of its weight . we do n ' t know how much tin was lost and how much silver was lost but in all 2 kg was lost with is 10 % of its overall weight . tin loses 1.375 kg in 10 kg so 13.75 % of its weight when it is put in water . silver loses . 375 kg in 5 kg so . 375 / 5 * 100 = 7.5 % of its weight in water . now , we just need to use weighted averages : wt / ws = ( 7.5 - 10 ) / ( 10 - 13.75 ) = 2.5 / 3.75 = 2 / 3 answer ( e )" | other |
math_qa__q2mOeWAKYDAR6lvo | What amount does an investor receive if the investor invests $6000 at 10% p.a. compound interest for two years, compounding done annually? Choose the correct choice from the following choices.
A) $ 6980 B) $ 7070 C) $ 7120 D) $ 7260 E) $ 7340 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 2</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">6_000 * (121/100)</gadget>
<output>7_260</output>
<result>D</result> | D | 7,260 | What amount does an investor receive if the investor invests $6000 at 10% p.a. compound interest for two years, compounding done annually? | {
"A": "$ 6980",
"B": "$ 7070",
"C": "$ 7120",
"D": "$ 7260",
"E": "$ 7340"
} | multiply(6000, power(add(const_1, divide(10, const_100)), const_2)) | divide(n1,const_100)|add(#0,const_1)|power(#1,const_2)|multiply(n0,#2) | a = ( 1 + r / 100 ) ^ n * p ( 1.1 ) ^ 2 * 6000 = 1.21 * 6000 = 7260 the answer is d . | gain |
math_qa__7aglWfnDIWzikDZ5 | Three pipes, A, B, & C are attached to a tank. A & B can fill it in 20 & 30 minutes respectively while C can empty it in 15 minutes. If A, B & C are kept open successively for 2 minute each, how soon will the tank be filled?
Choices.
A) 2 hours B) 4 hours C) 3 hours D) 5 hours E) 6 hours | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<result>E</result> | E | 6 | Three pipes, A, B, & C are attached to a tank. A & B can fill it in 20 & 30 minutes respectively while C can empty it in 15 minutes. If A, B & C are kept open successively for 2 minute each, how soon will the tank be filled? | {
"A": "2 hours",
"B": "4 hours",
"C": "3 hours",
"D": "5 hours",
"E": "6 hours"
} | add(add(2, 2), 2) | add(n3,n3)|add(n3,#0)| | "in three minute 1 / 20 + 1 / 30 - 1 / 15 = 1 / 60 part is filled 6 min - - - - - - - - 1 / 60 parts x min - - - - - - - - - 1 part ( full ) x = 360 min = 6 hours answer : e" | physics |
math_qa__kdNQXUkO6Cy6qYJf | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 340 m long?
Options.
A) 38 sec B) 35 sec C) 44 sec D) 40 sec E) 56 | <gadget id="calculator">340 / 1_000</gadget>
<output>17/50 = around 0.34</output>
<gadget id="calculator">360 / 1_000</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(17/50) + (9/25)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) / 45</gadget>
<output>7/450 = around 0.015556</output>
<gadget id="calculator">(7/450) * 3_600</gadget>
<output>56</output>
<result>E</result> | E | 56 | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 340 m long? | {
"A": "38 sec",
"B": "35 sec",
"C": "44 sec",
"D": "40 sec",
"E": "56"
} | multiply(divide(add(divide(340, const_1000), divide(360, const_1000)), 45), const_3600) | divide(n2,const_1000)|divide(n0,const_1000)|add(#0,#1)|divide(#2,n1)|multiply(#3,const_3600)| | "speed = 45 km / hr = 45 ã — ( 5 / 18 ) m / s = 150 / 12 = 50 / 4 = 25 / 2 m / s total distance = length of the train + length of the platform = 360 + 340 = 700 meter time taken to cross the platform = 700 / ( 25 / 2 ) = 700 ã — 2 / 25 = 56 seconds answer : e" | physics |
math_qa__x4zLCkGClpmGHkn5 | In a certificate by mistake a candidate gave his height as 25% more than actual height. In the interview panel, he clarified that his height was 5 feet 6 nches. Find the % correction made by the candidate from his stated height to his actual height? Choose the most appropriate option
A) 15 B) 20 C) 18 D) 16.5 E) 25 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + (1/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">25 + (1/2)</gadget>
<output>51/2 = around 25.5</output>
<gadget id="calculator">(51/2) - 5</gadget>
<output>41/2 = around 20.5</output>
<gadget id="calculator">100 + (41/2)</gadget>
<output>241/2 = around 120.5</output>
<gadget id="calculator">(41/2) / (241/2)</gadget>
<output>41/241 = around 0.170124</output>
<gadget id="calculator">(41/241) * 100</gadget>
<output>4_100/241 = around 17.012448</output>
<result>D</result> | D | 16.5 | In a certificate by mistake a candidate gave his height as 25% more than actual height. In the interview panel, he clarified that his height was 5 feet 6 nches. Find the % correction made by the candidate from his stated height to his actual height? | {
"A": "15",
"B": "20",
"C": "18",
"D": "16.5",
"E": "25"
} | multiply(divide(subtract(add(25, add(const_0_25, const_0_25)), 5), add(const_100, subtract(add(25, add(const_0_25, const_0_25)), 5))), const_100) | add(const_0_25,const_0_25)|add(n0,#0)|subtract(#1,n1)|add(#2,const_100)|divide(#2,#3)|multiply(#4,const_100) | his height was = 5 feet 6 inch = 6 + 60 = 66 inch . required % correction = 66 * ( 1.25 - 1 ) = 16.5 d | gain |
math_qa__2DKRJi4hdG2iREQO | There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability Q that the both positions will be taken by members of just one party? Choose the correct choice from the following answers
A) 1 / 25 B) 12 / 49 C) 1 / 4 D) 24 / 49 E) 1 / 2 | <gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 1</gadget>
<output>24</output>
<gadget id="calculator">50 - 1</gadget>
<output>49</output>
<gadget id="calculator">24 / 49</gadget>
<output>24/49 = around 0.489796</output>
<gadget id="calculator">25 / 50</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(24/49) * (1/2)</gadget>
<output>12/49 = around 0.244898</output>
<gadget id="calculator">(12/49) * 2</gadget>
<output>24/49 = around 0.489796</output>
<result>D</result> | D | 0.489796 | There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability Q that the both positions will be taken by members of just one party? | {
"A": "1 / 25",
"B": "12 / 49",
"C": "1 / 4",
"D": "24 / 49",
"E": "1 / 2"
} | multiply(multiply(divide(subtract(divide(50, 2), const_1), subtract(50, const_1)), divide(divide(50, 2), 50)), 2) | divide(n1,n0)|subtract(n1,const_1)|divide(#0,n1)|subtract(#0,const_1)|divide(#3,#1)|multiply(#4,#2)|multiply(n0,#5)| | "q probability of one party having both spots : ( 1 / 2 ) * ( 24 / 49 ) = 12 / 49 ( 1 / 2 ) or ( 25 / 50 ) because it does not matter which party or which person gets the first spot . ( 24 / 49 ) because after one person from a particular party is chosen , there are 24 members of the same party left out of 49 total candidates . since this result can happen for both parties , ( 12 / 49 ) + ( 12 / 49 ) = ( 24 / 49 ) answer : d" | other |
math_qa__Qk9fRqDjYtvw40dY | There are 7 non-collinear points. How many triangles can be drawn by joining these points?
Choose the most appropriate option:
A) 22
B) 38
C) 35
D) 29
E) 18 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<result>C</result> | C | 35 | There are 7 non-collinear points. How many triangles can be drawn by joining these points? | {
"A": "22",
"B": "38",
"C": "35",
"D": "29",
"E": "18"
} | multiply(7, add(const_4, const_1)) | add(const_1,const_4)|multiply(n0,#0) | explanation : a triangle is formed by joining any three non - collinear points in pairs . there are 7 non - collinear points the number of triangles formed = \ inline { \ color { black } 7 c _ { 3 } } = 35 answer : c ) 35 | geometry |
math_qa__AsX5YKuhUocgZ1Sy | A man buys 58 pens at marked price of 46 pens from a whole seller. If he sells these pens giving a discount of 1% , what is the profit percent? Pick one:
A) 7.6 % B) 7.7 % C) 24.82 % D) 13.6 % E) 27.82 % | <gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">58 * 99</gadget>
<output>5_742</output>
<gadget id="calculator">46 * 100</gadget>
<output>4_600</output>
<gadget id="calculator">5_742 - 4_600</gadget>
<output>1_142</output>
<gadget id="calculator">1_142 / 4_600</gadget>
<output>571/2_300 = around 0.248261</output>
<gadget id="calculator">100 * (571/2_300)</gadget>
<output>571/23 = around 24.826087</output>
<result>C</result> | C | 24.82 | A man buys 58 pens at marked price of 46 pens from a whole seller. If he sells these pens giving a discount of 1% , what is the profit percent? | {
"A": "7.6 %",
"B": "7.7 %",
"C": "24.82 %",
"D": "13.6 %",
"E": "27.82 %"
} | multiply(const_100, divide(subtract(multiply(58, subtract(const_100, 1)), multiply(46, const_100)), multiply(46, const_100))) | multiply(n1,const_100)|subtract(const_100,n2)|multiply(n0,#1)|subtract(#2,#0)|divide(#3,#0)|multiply(#4,const_100)| | "explanation : let marked price be re . 1 each c . p . of 58 pens = rs . 46 s . p . of 58 pens = 99 % of rs . 58 = rs . 57.42 profit % = ( profit / c . p . ) x 100 profit % = ( 11.42 / 46 ) x 100 = 24.82 % answer : c" | gain |
math_qa__dhbvVj08zylR37Dx | The sale price sarees listed for Rs.200 after successive discount is 10% and 5% is? Choose the most appropriate option:
A) 187
B) 169
C) 172
D) 178
E) 171 | <gadget id="calculator">200 * 10</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 100</gadget>
<output>20</output>
<gadget id="calculator">200 - 20</gadget>
<output>180</output>
<gadget id="calculator">180 * 5</gadget>
<output>900</output>
<gadget id="calculator">900 / 100</gadget>
<output>9</output>
<gadget id="calculator">180 - 9</gadget>
<output>171</output>
<result>E</result> | E | 171 | The sale price sarees listed for Rs.200 after successive discount is 10% and 5% is? | {
"A": "187",
"B": "169",
"C": "172",
"D": "178",
"E": "171"
} | subtract(subtract(200, divide(multiply(200, 10), const_100)), divide(multiply(subtract(200, divide(multiply(200, 10), const_100)), 5), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "200 * ( 90 / 100 ) * ( 95 / 100 ) = 171 answer : e" | gain |
math_qa__t0Ve5YvU6D1cICxi | if josh , doug , and brad have a total of $ 68 between them , and josh has two times as much money as brad but only 3 - fourths as much as doug , how much money does doug have ? Choices:
A) $ 8
B) $ 9
C) $ 27
D) $ 32
E) $ 36 | <gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">1 + (4/3)</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(7/3) + (1/2)</gadget>
<output>17/6 = around 2.833333</output>
<gadget id="calculator">68 / (17/6)</gadget>
<output>24</output>
<gadget id="calculator">24 * (4/3)</gadget>
<output>32</output>
<result>D</result> | D | 32 | if josh , doug , and brad have a total of $ 68 between them , and josh has two times as much money as brad but only 3 - fourths as much as doug , how much money does doug have ? | {
"A": "$ 8",
"B": "$ 9",
"C": "$ 27",
"D": "$ 32",
"E": "$ 36"
} | multiply(divide(68, add(add(const_1, divide(const_4, const_3)), divide(const_1, const_2))), divide(const_4, const_3)) | divide(const_4,const_3)|divide(const_1,const_2)|add(#0,const_1)|add(#2,#1)|divide(n0,#3)|multiply(#4,#0) | josh + doug + brad = 68 ; josh = 2 brad , josh = 3 / 4 doug josh + 1 / 2 josh + 4 / 3 josh = 68 ( substituted the given values ) josh = 24 . 24 = 3 / 4 doug = > doug = 32 answer is d . | general |
math_qa__JtEtoOdJhxgrbY9G | The bankers discount of a certain sum of money is Rs. 144 and the true discount on the same sum for the same time is Rs. 120. The sum due is: Choose the correct choice from the following:
A) 715 B) 716 C) 718 D) 720 E) 722 | <gadget id="calculator">120 * 144</gadget>
<output>17_280</output>
<gadget id="calculator">144 - 120</gadget>
<output>24</output>
<gadget id="calculator">17_280 / 24</gadget>
<output>720</output>
<result>D</result> | D | 720 | The bankers discount of a certain sum of money is Rs. 144 and the true discount on the same sum for the same time is Rs. 120. The sum due is: | {
"A": "715",
"B": "716",
"C": "718",
"D": "720",
"E": "722"
} | divide(multiply(120, 144), subtract(144, 120)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1) | sum = ( b . d * t . d ) / ( b . d - t . d ) ( 144 * 120 ) / 144 - 120 ; 720 answer : d | gain |
math_qa__eThOkrz5oNLd6LTY | Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day, she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many T kilometers per hour did Tammy walk on the second day? Choose the correct answer:
A) 3
B) 3.5
C) 4
D) 4.5
E) 6 | <gadget id="calculator">14 + 2</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">52 - 3</gadget>
<output>49</output>
<gadget id="calculator">6 + 8</gadget>
<output>14</output>
<gadget id="calculator">49 / 14</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(7/2) + (1/2)</gadget>
<output>4</output>
<result>C</result> | C | 4 | Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day, she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many T kilometers per hour did Tammy walk on the second day? | {
"A": "3",
"B": "3.5",
"C": "4",
"D": "4.5",
"E": "6"
} | add(divide(subtract(52, divide(subtract(divide(add(14, 2), 2), 2), 2)), add(subtract(divide(add(14, 2), 2), 2), divide(add(14, 2), 2))), divide(const_1, 2)) | add(n0,n1)|divide(const_1,n1)|divide(#0,n1)|subtract(#2,n1)|add(#2,#3)|divide(#3,n1)|subtract(n2,#5)|divide(#6,#4)|add(#7,#1)| | "ans : c total time = 14 hrs let time traveled during 1 st day = x let time traveled during 2 nd day = x - 2 total time = 14 x + x - 2 = 14 x = 8 speed * time = distance s * 8 + ( s + 0.5 ) ( 8 - 2 ) = 52 solving s = 4.5 now speed for 2 nd day is 0.5 less than the 1 st day which is 4.5 thus speed for 2 nd day = 4 its simple algebra for s * 8 + ( s + 0.5 ) ( 8 - 2 ) = 52 but for some reason im getting 3.5 and not 4.5 . 8 s + 6 s + 3 = 52 14 s = 49 s = 3.5" | physics |
math_qa__DSmUmAnCjZHOcDsJ | Two trains of length 120 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
Options.
A) 22 B) 12 C) 67 D) 20 E) 81 | <gadget id="calculator">120 + 280</gadget>
<output>400</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">400 / 20</gadget>
<output>20</output>
<result>D</result> | D | 20 | Two trains of length 120 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "22",
"B": "12",
"C": "67",
"D": "20",
"E": "81"
} | divide(add(120, 280), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 120 + 280 = 400 m . the time required = d / s = 400 / 20 = 20 sec . answer : d" | physics |
math_qa__tGoAnUAlxevg0azw | Pipe A fills a tank of capacity 950 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full? Choose the correct choice from the following options:
A) 57 minutes
B) 14 minutes
C) 39 minutes
D) 40 minutes 20 seconds
E) none of these | <gadget id="calculator">40 + 30</gadget>
<output>70</output>
<gadget id="calculator">70 - 20</gadget>
<output>50</output>
<gadget id="calculator">950 / 50</gadget>
<output>19</output>
<gadget id="calculator">19 * 3</gadget>
<output>57</output>
<result>A</result> | A | 57 | Pipe A fills a tank of capacity 950 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full? | {
"A": "57 minutes",
"B": "14 minutes",
"C": "39 minutes",
"D": "40 minutes 20 seconds",
"E": "none of these"
} | multiply(divide(950, subtract(add(40, 30), 20)), const_3) | add(n1,n2)|subtract(#0,n3)|divide(n0,#1)|multiply(#2,const_3) | in one cycle they fill 40 + 30 - 20 = 50 liters 950 = 50 * n = > n = 19 here n = number of cycles . total time = 19 * 3 = 57 as in one cycle there are 3 minutes . thus 57 minutes answer : a | physics |
math_qa__fzcohAJIyCenZ02U | During a sale, the price of a pair of shoes is marked down 12% from the regular price. After the sale ends, the price goes back to the original price. What is the percent of increase to the nearest percent from the sale price back to the regular price for the shoes? Choose the most appropriate option.
A) 9 % B) 10 % C) 11 % D) 14 % E) 90 % | <gadget id="calculator">12 * 100</gadget>
<output>1_200</output>
<gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">1_200 / 88</gadget>
<output>150/11 = around 13.636364</output>
<result>D</result> | D | 14 | During a sale, the price of a pair of shoes is marked down 12% from the regular price. After the sale ends, the price goes back to the original price. What is the percent of increase to the nearest percent from the sale price back to the regular price for the shoes? | {
"A": "9 %",
"B": "10 %",
"C": "11 %",
"D": "14 %",
"E": "90 %"
} | divide(multiply(12, const_100), subtract(const_100, 12)) | multiply(n0,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "assume the price = 100 price during sale = 88 price after sale = 100 percent increase = 12 / 88 * 100 = 14 % approx . correct option : d" | gain |
math_qa__z45whGkcEnizkvTg | If p/q = 5/4 , then 2p+q= ?
Choose one:
A) 12
B) 14
C) 13
D) 15
E) 16 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 4</gadget>
<output>14</output>
<result>B</result> | B | 14 | If p/q = 5/4 , then 2p+q= ? | {
"A": "12",
"B": "14",
"C": "13",
"D": "15",
"E": "16"
} | add(multiply(5, 2), 4) | multiply(n0,n2)|add(n1,#0)| | "let p = 5 , q = 4 then 2 * 5 + 4 = 14 so 2 p + q = 14 . answer : b" | general |
math_qa__EGKypiuhoybubOiD | Find the missing figures: 0.75% of ? = 0.06
Choose the correct choice from the following choices.
A) 4 B) 6 C) 8 D) 10 E) 12 | <gadget id="calculator">0.75 / 100</gadget>
<output>0.0075</output>
<gadget id="calculator">0.06 / 0.0075</gadget>
<output>8</output>
<result>C</result> | C | 8 | Find the missing figures: 0.75% of ? = 0.06 | {
"A": "4",
"B": "6",
"C": "8",
"D": "10",
"E": "12"
} | divide(0.06, divide(0.75, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "let 0.75 % of x = 0.06 . then , 0.75 * x / 100 = 0.06 x = [ ( 0.06 * 100 ) / 0.75 ] = 8 . answer is c ." | gain |
math_qa__3zvpUiOxOP1g8XvN | M is 30% of Q. Q is 20% of P. N is 50% of P. Find M:N ratio
Pick: A) 1 : 25 B) 2 : 25 C) 3 : 25 D) 4 : 25 E) 5 : 25 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/10) * (1/5)</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/50) / (1/2)</gadget>
<output>3/25 = around 0.12</output>
<result>C</result> | C | 0.12 | M is 30% of Q. Q is 20% of P. N is 50% of P. Find M:N ratio | {
"A": "1 : 25",
"B": "2 : 25",
"C": "3 : 25",
"D": "4 : 25",
"E": "5 : 25"
} | divide(multiply(divide(30, const_100), divide(20, const_100)), divide(50, const_100)) | divide(n0,const_100)|divide(n1,const_100)|divide(n2,const_100)|multiply(#0,#1)|divide(#3,#2) | let p be 100 n = 50 % of 100 ( p = 100 ) = 50 q = 20 % of 100 ( p = 100 ) = 20 m = 30 % of 20 ( q = 20 ) = 6 m : n = 6 : 50 m : n = 3 : 25 answer : c | other |
math_qa__grWN8uTpuYxfHk0p | A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 5000. With the help of C, they completed the work in 3 days. How much is to be paid to C? Answers
A) s . 375 B) s . 425 C) s . 625 D) s . 800 E) s . 850 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/8) + (1/6)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">(1/3) - (7/24)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/24) * 5_000</gadget>
<output>625/3 = around 208.333333</output>
<gadget id="calculator">(625/3) * 3</gadget>
<output>625</output>
<result>C</result> | C | 625 | A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 5000. With the help of C, they completed the work in 3 days. How much is to be paid to C? | {
"A": "s . 375",
"B": "s . 425",
"C": "s . 625",
"D": "s . 800",
"E": "s . 850"
} | multiply(multiply(subtract(inverse(3), add(inverse(8), inverse(6))), 5000), 3) | inverse(n3)|inverse(n1)|inverse(n0)|add(#1,#2)|subtract(#0,#3)|multiply(n2,#4)|multiply(n3,#5)| | "c ' s 1 day ' s work = 1 / 3 - ( 1 / 6 + 1 / 8 ) = 1 / 3 - 7 / 24 = 1 / 24 a ' s wages : b ' s wages : c ' s wages = 1 / 6 : 1 / 8 : 1 / 24 = 4 : 3 : 1 c ' s share ( for 3 days ) = rs . ( 3 * 1 / 24 * 5000 ) = rs . 625 answer = c" | physics |
math_qa__JpCsVma5Y8GKAGOr | A box contains 9 pairs of shoes (18 shoes in total). If two shoes are selected at random, what it is the probability that they are matching shoes?
Choose the correct choice from the following answers
A) 1 / 190 B) 1 / 17 C) 1 / 19 D) 1 / 10 E) 1 / 9 | <gadget id="calculator">18 - 1</gadget>
<output>17</output>
<gadget id="calculator">1 / 17</gadget>
<output>1/17 = around 0.058824</output>
<result>B</result> | B | 0.058824 | A box contains 9 pairs of shoes (18 shoes in total). If two shoes are selected at random, what it is the probability that they are matching shoes? | {
"A": "1 / 190",
"B": "1 / 17",
"C": "1 / 19",
"D": "1 / 10",
"E": "1 / 9"
} | divide(const_1, subtract(18, const_1)) | subtract(n1,const_1)|divide(const_1,#0)| | "the problem with your solution is that we do n ' t choose 1 shoe from 18 , but rather choose the needed one after we just took one and need the second to be the pair of it . so , the probability would simply be : 1 / 1 * 1 / 17 ( as after taking one at random there are 17 shoes left and only one is the pair of the first one ) = 1 / 17 answer : b ." | general |
math_qa__rEiomfGs8xdRZJRV | A marching band of 240 musicians are to march in a rectangular formation with s rows of exactly t musicians each. There can be no less than 8 musicians per row and no more than 30 musicians per row. How many different rectangular formations X are possible?
Choose the correct choice.
A) 3
B) 4
C) 5
D) 6
E) x = 8 | <gadget id="calculator">240 / 30</gadget>
<output>8</output>
<result>E</result> | E | 8 | A marching band of 240 musicians are to march in a rectangular formation with s rows of exactly t musicians each. There can be no less than 8 musicians per row and no more than 30 musicians per row. How many different rectangular formations X are possible? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "x = 8"
} | divide(240, 30) | divide(n0,n2) | the combinations could be { ( 1,240 ) , ( 2,120 ) , ( 3,80 ) , ( 4,60 ) , ( 5,48 ) , ( 6,40 ) , ( 8,30 ) , ( 10,24 ) , ( 12,20 ) , ) 15,16 ) , ( 16,15 ) , ( 20,12 ) , ( 24,10 ) , ( 30,8 ) , ( 40,6 ) , ( 48,5 ) , ( 60,4 ) , ( 80,3 ) , ( 120,2 ) , ( 240,1 ) } of these we are told 8 < = t < = 30 so we can remove these pairs , and we are left only with . { ( 8,30 , ( 10,24 ) , ( 12,20 ) , ( 15,16 ) , ( 16,15 ) , ( 20,12 ) , ( 24,10 ) , ( 30,8 ) } hence 8 . e | general |
math_qa__RqKXFho8DoqvH7VK | The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.5225.What was his original salary? Choose one:
A) 2277 B) 5000 C) 1000 D) 2651 E) 1971 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 - (1/20)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(11/10) * (19/20)</gadget>
<output>209/200 = around 1.045</output>
<gadget id="calculator">5_225 / (209/200)</gadget>
<output>5_000</output>
<result>B</result> | B | 5,000 | The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.5225.What was his original salary? | {
"A": "2277",
"B": "5000",
"C": "1000",
"D": "2651",
"E": "1971"
} | divide(5225, multiply(add(const_1, divide(10, const_100)), subtract(const_1, divide(5, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|divide(n2,#4)| | "x * ( 110 / 100 ) * ( 95 / 100 ) = 5225 x * ( 11 / 10 ) * ( 1 / 100 ) = 55 x = 5000 answer : b" | gain |
math_qa__0wiEeeC8BXck2ZWz | The regular price per can of a certain brand of soda is $0.15. If the regular price per can is discounted 10 percent when the soda is purchased in 24-can cases, what is the price of 75 cans of this brand of soda purchased in 24-can cases? Pick:
A) $ 16.32
B) $ 18.00
C) $ 10.125
D) $ 24.48
E) $ 28.80 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">0.15 * 75</gadget>
<output>11.25</output>
<gadget id="calculator">(9/10) * 11.25</gadget>
<output>10.125</output>
<result>C</result> | C | 10.125 | The regular price per can of a certain brand of soda is $0.15. If the regular price per can is discounted 10 percent when the soda is purchased in 24-can cases, what is the price of 75 cans of this brand of soda purchased in 24-can cases? | {
"A": "$ 16.32",
"B": "$ 18.00",
"C": "$ 10.125",
"D": "$ 24.48",
"E": "$ 28.80"
} | multiply(divide(subtract(const_100, 10), const_100), multiply(0.15, 75)) | multiply(n0,n3)|subtract(const_100,n1)|divide(#1,const_100)|multiply(#2,#0) | the discounted price of one can of soda is ( 0.9 ) ( $ 0.15 ) , or $ 0.135 therefore , the price of 75 cans of soda at the discounted price would be ( 75 ) ( $ 0.135 ) = 10.125 answer : c . | gain |
math_qa__cUT3EQJ0lxtcnRTI | Solve:-
666 x 666 x 666 + 555 x 555 x 555 = ?(666 x 666 - 666 x 555 + 555 x 555) Choose the correct choice from the following choices:
A) 888 B) 333 C) 555 D) 1221 E) 889 | <gadget id="calculator">666 * 666</gadget>
<output>443_556</output>
<gadget id="calculator">443_556 * 666</gadget>
<output>295_408_296</output>
<gadget id="calculator">555 * 555</gadget>
<output>308_025</output>
<gadget id="calculator">308_025 * 555</gadget>
<output>170_953_875</output>
<gadget id="calculator">295_408_296 + 170_953_875</gadget>
<output>466_362_171</output>
<gadget id="calculator">443_556 + 308_025</gadget>
<output>751_581</output>
<gadget id="calculator">666 * 555</gadget>
<output>369_630</output>
<gadget id="calculator">751_581 - 369_630</gadget>
<output>381_951</output>
<gadget id="calculator">466_362_171 / 381_951</gadget>
<output>1_221</output>
<result>D</result> | D | 1,221 | Solve:-
666 x 666 x 666 + 555 x 555 x 555 = ?(666 x 666 - 666 x 555 + 555 x 555) | {
"A": "888",
"B": "333",
"C": "555",
"D": "1221",
"E": "889"
} | divide(add(multiply(multiply(666, 666), 666), multiply(multiply(555, 555), 555)), subtract(add(multiply(666, 666), multiply(555, 555)), multiply(666, 555))) | multiply(n0,n0)|multiply(n3,n3)|multiply(n0,n3)|add(#0,#1)|multiply(n0,#0)|multiply(n3,#1)|add(#4,#5)|subtract(#3,#2)|divide(#6,#7) | given exp . = ( a 3 + b 3 ) = ( a + b ) = ( 666 + 555 ) = 1221 ( a 2 - ab + b 2 ) answer d | general |
math_qa__Q5CsJceL24AFExbV | When positive integer X is divided by positive integer Y, the remainder is 11.52. If X/Y = 96.12, what is the value of Y? Choose the correct choice from the following options: A) 96 B) 75 C) 48 D) 25 E) 12 | <gadget id="calculator">floor(96.12)</gadget>
<output>96</output>
<gadget id="calculator">96.12 - 96</gadget>
<output>0.12</output>
<gadget id="calculator">11.52 / 0.12</gadget>
<output>96</output>
<result>A</result> | A | 96 | When positive integer X is divided by positive integer Y, the remainder is 11.52. If X/Y = 96.12, what is the value of Y? | {
"A": "96",
"B": "75",
"C": "48",
"D": "25",
"E": "12"
} | divide(11.52, subtract(96.12, floor(96.12))) | floor(n1)|subtract(n1,#0)|divide(n0,#1)| | "when positive integer x is divided by positive integer y , the remainder is 11.52 - - > x = qy + 11.52 ; x / y = 96.12 - - > x = 96 y + 0.12 y ( so q above equals to 96 ) ; 0.12 y = 11.52 - - > y = 96 . answer : a ." | general |
math_qa__LAeSpHhNlqafKdvd | If 213 × 16 = 3408, then 0.016 × 2.13 is equal to : Select.
A) 0.3408
B) 3.408
C) 34.08
D) 340.8
E) 0.03408 | <gadget id="calculator">0.016 * 2.13</gadget>
<output>0.03408</output>
<result>E</result> | E | 0.03408 | If 213 × 16 = 3408, then 0.016 × 2.13 is equal to : | {
"A": "0.3408",
"B": "3.408",
"C": "34.08",
"D": "340.8",
"E": "0.03408"
} | multiply(0.016, 2.13) | multiply(n4,n3)| | "solution 0.016 × 2.13 = ( 16 / 1000 x 213 / 100 ) = ( 16 / 1000 x 213 / 100 ) = 3408 / 100000 = 0.03408 . answer e" | general |
math_qa__yb3iA9zKzRYjaULa | In a certain accounting class of 90 students, 70% of the students took the final exam on the assigned day while the rest of the students took the exam on a make-up date. If the students on the assigned day had an average score of 65%, and the students on the make-up date had an average score of 85%, what was the average score for the entire class?
Choose the correct choice from the following: A) 68 % B) 71 % C) 73 % D) 75 % E) 79 % | <gadget id="calculator">70 * 65</gadget>
<output>4_550</output>
<gadget id="calculator">90 - 70</gadget>
<output>20</output>
<gadget id="calculator">85 * 20</gadget>
<output>1_700</output>
<gadget id="calculator">4_550 + 1_700</gadget>
<output>6_250</output>
<gadget id="calculator">6_250 / 90</gadget>
<output>625/9 = around 69.444444</output>
<result>B</result> | B | 71 | In a certain accounting class of 90 students, 70% of the students took the final exam on the assigned day while the rest of the students took the exam on a make-up date. If the students on the assigned day had an average score of 65%, and the students on the make-up date had an average score of 85%, what was the average score for the entire class? | {
"A": "68 %",
"B": "71 %",
"C": "73 %",
"D": "75 %",
"E": "79 %"
} | divide(add(multiply(70, 65), multiply(85, subtract(90, 70))), 90) | multiply(n1,n2)|subtract(n0,n1)|multiply(n3,#1)|add(#0,#2)|divide(#3,n0)| | "70 % of the students took the final exam on the assigned day - - > 0.7 * 90 = 63 students took the final exam on the assigned day , with an average score of 65 . the rest of the students took the exam on a make - up date - - > 90 - 63 = 27 students took the exam on a make - up date , with an average score of 85 . ( average score ) = ( sum of the scores ) / ( total students ) = ( 63 * 65 + 27 * 85 ) / 90 = 71 . answer : b ." | general |
math_qa__Z9OlqbHe6lesQNcF | 75 boys can complete a work in 36 days.how many men need to complete twice the work in 20 days Choose the correct choice from the following options:
A) 160 B) 170 C) 270 D) 190 E) 200 | <gadget id="calculator">36 * 2</gadget>
<output>72</output>
<gadget id="calculator">75 * 72</gadget>
<output>5_400</output>
<gadget id="calculator">5_400 / 20</gadget>
<output>270</output>
<result>C</result> | C | 270 | 75 boys can complete a work in 36 days.how many men need to complete twice the work in 20 days | {
"A": "160",
"B": "170",
"C": "270",
"D": "190",
"E": "200"
} | divide(multiply(75, multiply(36, const_2)), 20) | multiply(n1,const_2)|multiply(n0,#0)|divide(#1,n2) | one man can complete the work in 36 * 75 = 2700 days = one time work to complete the work twice it will be completed in let m be the no . of worker assign for this therefore the eqn becomes m * 20 = 2 * 2700 m = 270 workers answer : c | physics |
math_qa__XjddDtncpFxdaZRv | Ratio of the earnings of A and B is 4:7. If the earnings of A increases by 50% and those of B decreased by 25%, the new ratio of their earnings becomes 8:7. What are A's earnings? Pick one: A) 8 : 6 B) 8 : 9 C) 8 : 3 D) 8 : 7 E) 8 : 1 | <gadget id="calculator">8 / 7</gadget>
<output>8/7 = around 1.142857</output>
<result>D</result> | D | 1.142857 | Ratio of the earnings of A and B is 4:7. If the earnings of A increases by 50% and those of B decreased by 25%, the new ratio of their earnings becomes 8:7. What are A's earnings? | {
"A": "8 : 6",
"B": "8 : 9",
"C": "8 : 3",
"D": "8 : 7",
"E": "8 : 1"
} | divide(8, 7) | divide(n4,n1) | let the original earnings of a and b be rs . 4 x and rs . 7 x . new earnings of a = 150 % 0 f rs . 4 x = ( 150 / 100 * 4 x ) = rs . 6 x new earnings of b = 75 % of rs . 7 x = ( 75 / 100 * 7 x ) = rs . 21 x / 4 6 x : 21 x / 4 = 8 : 7 this does not give x . so , the given data is inadequate . answer : d | general |
math_qa__wYbpmcJRBERXB4GI | What is the square root of 144, divided by 6? Choose the correct choice from the following: A) 9 B) 36 C) 2 D) 6 E) 1 | <gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<gadget id="calculator">12 / 6</gadget>
<output>2</output>
<result>C</result> | C | 2 | What is the square root of 144, divided by 6? | {
"A": "9",
"B": "36",
"C": "2",
"D": "6",
"E": "1"
} | divide(sqrt(144), 6) | sqrt(n0)|divide(#0,n1)| | "square root is a number times itself square root of 144 = 12 , 12 / 6 = 2 ( c ) 2" | other |
math_qa__RGLmxWMgT4Y0HwsK | The diameter of the driving wheel of a bus in 140 cm. How many revolutions per minute must the wheel make in order to keep a speed of 20 kmph?
Choose one.
A) 21.21 B) 20.25 C) 32.25 D) 75.75 E) 62.61 | <gadget id="calculator">20 * 1_000</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 60</gadget>
<output>1_000/3 = around 333.333333</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">(22/7) * 2</gadget>
<output>44/7 = around 6.285714</output>
<gadget id="calculator">140 / 100</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) / 2</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(44/7) * (7/10)</gadget>
<output>22/5 = around 4.4</output>
<gadget id="calculator">(1_000/3) / (22/5)</gadget>
<output>2_500/33 = around 75.757576</output>
<result>D</result> | D | 75.75 | The diameter of the driving wheel of a bus in 140 cm. How many revolutions per minute must the wheel make in order to keep a speed of 20 kmph? | {
"A": "21.21",
"B": "20.25",
"C": "32.25",
"D": "75.75",
"E": "62.61"
} | divide(divide(multiply(20, const_1000), const_60), multiply(multiply(divide(add(20, const_2), add(const_4, const_3)), const_2), divide(divide(140, const_100), const_2))) | add(n1,const_2)|add(const_3,const_4)|divide(n0,const_100)|multiply(n1,const_1000)|divide(#3,const_60)|divide(#2,const_2)|divide(#0,#1)|multiply(#6,const_2)|multiply(#5,#7)|divide(#4,#8) | distance covered in 1 min = ( 20 * 1000 ) / 60 = 333.33 m circumference of the wheel = ( 2 * ( 22 / 7 ) * . 70 ) = 4.4 m no of revolution per min = 333.33 / 4.4 = 75.75 answer : d | physics |
math_qa__PiycTFZZYgU6u96M | A grocer has 400 pounds of coffee in stock, 30 percent of which is decaffeinated. If the grocer buys another 100 pounds of coffee of which 60 percent is decaffeinated, what percent, by weight, of the grocer’s stock of coffee is decaffeinated? Choose the correct choice from the following answers:
A) 28 % B) 30 % C) 36 % D) 36 % E) 40 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 400</gadget>
<output>120</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">100 * (3/5)</gadget>
<output>60</output>
<gadget id="calculator">120 + 60</gadget>
<output>180</output>
<gadget id="calculator">400 + 100</gadget>
<output>500</output>
<gadget id="calculator">180 / 500</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(9/25) * 100</gadget>
<output>36</output>
<result>D</result> | D | 36 | A grocer has 400 pounds of coffee in stock, 30 percent of which is decaffeinated. If the grocer buys another 100 pounds of coffee of which 60 percent is decaffeinated, what percent, by weight, of the grocer’s stock of coffee is decaffeinated? | {
"A": "28 %",
"B": "30 %",
"C": "36 %",
"D": "36 %",
"E": "40 %"
} | multiply(divide(add(multiply(divide(30, 100), 400), multiply(100, divide(60, 100))), add(400, 100)), 100) | add(n0,n2)|divide(n1,n2)|divide(n3,n2)|multiply(n0,#1)|multiply(n2,#2)|add(#3,#4)|divide(#5,#0)|multiply(#6,n2)| | "1 . 30 % of 400 = 120 pounds of decaffeinated coffee 2 . 60 % of 100 = 60 pounds of decaffeinated coffee 3 . wt have 180 pounds of decaffeinated out of 500 pounds , that means 180 / 500 * 100 % = 36 % . the correct answer is d ." | gain |
math_qa__zglCrb5kgYNFquil | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets into it. The mass of the man is ?
Choose the correct choice from the following:
A) 77 kg
B) 60 kg
C) 77 kg
D) 55 kg
E) 47 kg | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">6 * (1/100)</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 1_000</gadget>
<output>60</output>
<result>B</result> | B | 60 | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets into it. The mass of the man is ? | {
"A": "77 kg",
"B": "60 kg",
"C": "77 kg",
"D": "55 kg",
"E": "47 kg"
} | multiply(multiply(multiply(3, 2), divide(1, const_100)), const_1000) | divide(n2,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(#2,const_1000)| | "in this type of question , first we will calculate the volume of water displaces then will multiply with the density of water . volume of water displaced = 3 * 2 * 0.01 = 0.06 m cube mass of man = volume of water displaced * density of water = 0.06 * 1000 = 60 kg answer : b" | physics |
math_qa__r94AfJ2sK5wJW5rE | the number n is 76 h 4 , where h represents the 10 ' s digit . if n is divisible by 9 , what is the value of h ? Choose the correct choice from the following options
A) 1 B) 3 C) 5 D) 7 E) 9 | <gadget id="calculator">76 * 100</gadget>
<output>7_600</output>
<gadget id="calculator">7_600 + 4</gadget>
<output>7_604</output>
<gadget id="calculator">7_604 % 9</gadget>
<output>8</output>
<gadget id="calculator">9 - 8</gadget>
<output>1</output>
<result>A</result> | A | 1 | the number n is 76 h 4 , where h represents the 10 ' s digit . if n is divisible by 9 , what is the value of h ? | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | subtract(9, reminder(add(multiply(76, const_100), 4), 9)) | multiply(n0,const_100)|add(n1,#0)|reminder(#1,n3)|subtract(n3,#2) | integer is divisible by 9 - sum of digits is divisible by 9 answer : a | general |
math_qa__v2Cn2svyU0MJfi1z | If a boat is rowed downstream for 96 km in 3 hours and upstream for 88 km in 11 hours, what is the speed of the boat and the river? Answers
A) 12 , 20 B) 20 , 20 C) 20 , 11 D) 20 , 12 E) 12 , 12 | <gadget id="calculator">88 / 11</gadget>
<output>8</output>
<gadget id="calculator">96 / 3</gadget>
<output>32</output>
<gadget id="calculator">8 + 32</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<result>D</result> | D | 20 | If a boat is rowed downstream for 96 km in 3 hours and upstream for 88 km in 11 hours, what is the speed of the boat and the river? | {
"A": "12 , 20",
"B": "20 , 20",
"C": "20 , 11",
"D": "20 , 12",
"E": "12 , 12"
} | divide(add(divide(88, 11), divide(96, 3)), const_2) | divide(n2,n3)|divide(n0,n1)|add(#0,#1)|divide(#2,const_2) | explanation : if x : speed of boats man in still water y : speed of the river downstream speed ( ds ) = x + y upstream speed ( us ) = x â € “ y x = ( ds + us ) / 2 y = ( ds â € “ us ) / 2 in the above problem ds = 32 ; us = 8 x = ( 32 + 8 ) / 2 = 40 / 2 = 20 km / hr y = ( 32 - 8 ) / 2 = 24 / 2 = 12 km / hr answer : d | physics |
math_qa__6kfDBi09ZIVALDRC | A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be Answers.
A) 12.5 m B) 10 m C) 17.5 m D) 21.25 m E) 9.8 m | <gadget id="calculator">17.5 / 40.25</gadget>
<output>0.434783</output>
<gadget id="calculator">28.75 * 0.434783</gadget>
<output>12.500011</output>
<result>A</result> | A | 12.5 | A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be | {
"A": "12.5 m",
"B": "10 m",
"C": "17.5 m",
"D": "21.25 m",
"E": "9.8 m"
} | multiply(28.75, divide(17.5, 40.25)) | divide(n0,n1)|multiply(n2,#0)| | "let the height of the building x metres . less lengthy shadow , less in the height ( direct proportion ) 40.25 : 28.75 : : 17.5 : x 40.25 * x = 28.75 * 17.5 x = ( 28.75 x 17.5 ) / 40.25 x = 12.5 answer is a ." | physics |
math_qa__ud5bsNpYbBX9HJuy | A line has a slope of 3/4 and intersects the point R (-12, -39). At which point does this line intersect the x-axis? Choose the correct choice from the following choices: A) ( 40,0 ) B) ( 30,0 ) C) ( 0,40 ) D) ( 40,30 ) E) ( 0,30 ) | <gadget id="calculator">-39</gadget>
<output>-39</output>
<gadget id="calculator">-12</gadget>
<output>-12</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(-12) * (3/4)</gadget>
<output>-9</output>
<gadget id="calculator">(-39) - (-9)</gadget>
<output>-30</output>
<gadget id="calculator">(-30) / (3/4)</gadget>
<output>-40</output>
<gadget id="calculator">-(-40)</gadget>
<output>40</output>
<gadget id="calculator">40 * 10</gadget>
<output>400</output>
<result>A</result> | A | 400 | A line has a slope of 3/4 and intersects the point R (-12, -39). At which point does this line intersect the x-axis? | {
"A": "( 40,0 )",
"B": "( 30,0 )",
"C": "( 0,40 )",
"D": "( 40,30 )",
"E": "( 0,30 )"
} | multiply(negate(divide(subtract(negate(39), multiply(negate(12), divide(3, 4))), divide(3, 4))), const_10) | divide(n0,n1)|negate(n3)|negate(n2)|multiply(#0,#2)|subtract(#1,#3)|divide(#4,#0)|negate(#5)|multiply(#6,const_10)| | "assume that the equation of the line is y = mx + c , where m and c are the slope and y - intercept . you are also given that the line crosses the point ( - 12 , - 39 ) , this means that this point will also lie on the line above . thus you get - 39 = m * ( - 12 ) + c , with m = 3 / 4 as the slope is given to be 3 / 4 . after substituting the above values , you get c = - 30 . thus the equation of the line is y = 0.75 * x - 30 and the point where it will intersect the x - axis will be with y coordinate = 0 . put y = 0 in the above equation of the line and you will get , x = 40 . thus , the point r of intersection is ( 40,0 ) . a is the correct answer ." | general |
math_qa__WU9Kgr9W1pMW9Cfb | A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length? Answers.
A) 15 B) 44 C) 40 D) 27 E) 12 | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">500 / (25/2)</gadget>
<output>40</output>
<result>C</result> | C | 40 | A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length? | {
"A": "15",
"B": "44",
"C": "40",
"D": "27",
"E": "12"
} | divide(add(360, 140), divide(multiply(45, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 45 km / hr = 45 * ( 5 / 18 ) m / sec = 25 / 2 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 * ( 2 / 25 ) = 40 seconds answer : c" | physics |
math_qa__Xy0gWmeqGQyth20F | What is the dividend. divisor 14, the quotient is 9 and the remainder is 5?
Choose the correct choice from the following options:
A) 130 B) 131 C) 148 D) 158 E) 160 | <gadget id="calculator">14 * 9</gadget>
<output>126</output>
<gadget id="calculator">126 + 5</gadget>
<output>131</output>
<result>B</result> | B | 131 | What is the dividend. divisor 14, the quotient is 9 and the remainder is 5? | {
"A": "130",
"B": "131",
"C": "148",
"D": "158",
"E": "160"
} | add(multiply(14, 9), 5) | multiply(n0,n1)|add(n2,#0)| | "d = d * q + r d = 14 * 9 + 5 d = 126 + 5 d = 131 answer b" | general |
math_qa__EExokX9uBzq2VKS7 | Shop Offered 30% offer for every Shirt, Smith bought a shirt at Rs. 560. and What was the shop's original selling Price?
Choices
A) 500 B) 800 C) 600 D) 700 E) 750 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">560 / (7/10)</gadget>
<output>800</output>
<result>B</result> | B | 800 | Shop Offered 30% offer for every Shirt, Smith bought a shirt at Rs. 560. and What was the shop's original selling Price? | {
"A": "500",
"B": "800",
"C": "600",
"D": "700",
"E": "750"
} | divide(560, subtract(const_1, divide(30, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1)| | "sp * ( 70 / 100 ) = 560 sp = 8 * 100 = > cp = 800 answer : b" | gain |
math_qa__yO33LebK0ImhBiMa | If Q = {1, 7, 18, 20, 29, 33}, how much less is the mean of the numbers in Q than the median of the numbers in Q?
Choose the correct answer.
A) 1.0 B) 1.5 C) 2.0 D) 2.5 E) 3.0 | <gadget id="calculator">18 + 20</gadget>
<output>38</output>
<gadget id="calculator">38 / 2</gadget>
<output>19</output>
<gadget id="calculator">1 + 7</gadget>
<output>8</output>
<gadget id="calculator">8 + 18</gadget>
<output>26</output>
<gadget id="calculator">26 + 20</gadget>
<output>46</output>
<gadget id="calculator">46 + 29</gadget>
<output>75</output>
<gadget id="calculator">75 + 33</gadget>
<output>108</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">108 / 6</gadget>
<output>18</output>
<gadget id="calculator">19 - 18</gadget>
<output>1</output>
<result>A</result> | A | 1 | If Q = {1, 7, 18, 20, 29, 33}, how much less is the mean of the numbers in Q than the median of the numbers in Q? | {
"A": "1.0",
"B": "1.5",
"C": "2.0",
"D": "2.5",
"E": "3.0"
} | subtract(divide(add(18, 20), const_2), divide(add(add(add(add(add(1, 7), 18), 20), 29), 33), multiply(const_2, const_3))) | add(n2,n3)|add(n0,n1)|multiply(const_2,const_3)|add(n2,#1)|divide(#0,const_2)|add(n3,#3)|add(n4,#5)|add(n5,#6)|divide(#7,#2)|subtract(#4,#8) | this is a good question to understand the difference between mean and median . mean : average of all the numbers . ( sum of all the elements divided by the number of elements ) median : arrange the elements of the set in increasing order . if the number of terms is odd , the middle term is the median . if the number of terms is even , the average of middle two terms is the median coming to this question , mean = ( 1 + 7 + 18 + 20 + 29 + 33 ) / 6 = 18 median = ( 18 + 20 ) / 2 = 19 difference = 1 option a | general |
math_qa__nuK3LtxY8KRpDlXH | Company KW is being sold, and both Company A and Company B were considering the purchase. The price of Company KW is 20% more than Company A has in assets, and this same price is also 100% more than Company B has in assets. If Companies A and B were to merge and combine their assets, the price of Company KW would be approximately what percent of these combined assets? Choose the correct choice from the following options:
A) 66 %
B) 75 %
C) 86 %
D) 116 %
E) 150 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 2</gadget>
<output>60</output>
<gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">120 / 160</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 100</gadget>
<output>75</output>
<result>B</result> | B | 75 | Company KW is being sold, and both Company A and Company B were considering the purchase. The price of Company KW is 20% more than Company A has in assets, and this same price is also 100% more than Company B has in assets. If Companies A and B were to merge and combine their assets, the price of Company KW would be approximately what percent of these combined assets? | {
"A": "66 %",
"B": "75 %",
"C": "86 %",
"D": "116 %",
"E": "150 %"
} | multiply(divide(add(100, 20), add(100, divide(add(100, 20), const_2))), 100) | add(n0,n1)|divide(#0,const_2)|add(n1,#1)|divide(#0,#2)|multiply(#3,n1)| | "let the price of company a ' s assets be 100 price of assets of kw is 20 % more than company a ' s assets which is 120 price of assets of kw is 100 % more than company b ' s assets which means price of company b ' s assets is half the price of kw = 60 a + b = 160 kw = 120 kw / ( a + b ) * 100 = 120 / 160 * 100 = 75 % b" | gain |
math_qa__rMiC4BF47oRyX4wa | A bowl of fruit contains 12 apples and 23 oranges. How many oranges must be removed so that 60% of the pieces of fruit in the bowl will be apples? Pick.
A) 3 B) 6 C) 15 D) 17 E) 20 | <gadget id="calculator">12 + 23</gadget>
<output>35</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">35 * (3/5)</gadget>
<output>21</output>
<gadget id="calculator">21 - 12</gadget>
<output>9</output>
<gadget id="calculator">9 / (3/5)</gadget>
<output>15</output>
<result>C</result> | C | 15 | A bowl of fruit contains 12 apples and 23 oranges. How many oranges must be removed so that 60% of the pieces of fruit in the bowl will be apples? | {
"A": "3",
"B": "6",
"C": "15",
"D": "17",
"E": "20"
} | divide(subtract(multiply(add(12, 23), divide(60, const_100)), 12), divide(60, const_100)) | add(n0,n1)|divide(n2,const_100)|multiply(#0,#1)|subtract(#2,n0)|divide(#3,#1)| | "number of apples = 14 number of oranges = 23 let number of oranges that must be removed so that 60 % of pieces of fruit in bowl will be apples = x total number of fruits after x oranges are removed = 12 + ( 23 - x ) = 35 - x 12 / ( 35 - x ) = 6 / 10 = > 20 = 35 - x = > x = 15 answer c" | gain |
math_qa__C3A4LlOBeXkdp8WR | One ton has 2100 pounds, and one pound has 16 ounces. How many packets containing wheat weighing 16 pounds and 4 ounces each would totally fill a gunny bag of capacity 13 tons? Pick.
A) 1680
B) 1700
C) 2350
D) 2500
E) 8000 | <gadget id="calculator">13 * 2_100</gadget>
<output>27_300</output>
<gadget id="calculator">27_300 * 16</gadget>
<output>436_800</output>
<gadget id="calculator">16 * 16</gadget>
<output>256</output>
<gadget id="calculator">256 + 4</gadget>
<output>260</output>
<gadget id="calculator">436_800 / 260</gadget>
<output>1_680</output>
<result>A</result> | A | 1,680 | One ton has 2100 pounds, and one pound has 16 ounces. How many packets containing wheat weighing 16 pounds and 4 ounces each would totally fill a gunny bag of capacity 13 tons? | {
"A": "1680",
"B": "1700",
"C": "2350",
"D": "2500",
"E": "8000"
} | divide(multiply(multiply(13, 2100), 16), add(multiply(16, 16), 4)) | multiply(n0,n4)|multiply(n1,n1)|add(n3,#1)|multiply(n1,#0)|divide(#3,#2)| | "16 pounds and 4 ounces = 16 * 16 + 4 = 260 ounces . 13 tons = 13 * 2100 pound = 13 * 2100 * 16 ounces . hence the answer is ( 13 * 2100 * 16 ) / 260 = 1680 . answer : a ." | general |
math_qa__WSpdoLZnNZ7qnrWQ | The salary of a worker is first increased by 25% and afterwards reduced by 25%. What is the net change in the worker's salary?
Choose one
A) 3.25 % increase B) 3.25 % decrease C) 6.25 % increase D) 6.25 % decrease E) no change | <gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">125 * 25</gadget>
<output>3_125</output>
<gadget id="calculator">3_125 / 100</gadget>
<output>125/4 = around 31.25</output>
<gadget id="calculator">125 - (125/4)</gadget>
<output>375/4 = around 93.75</output>
<gadget id="calculator">100 - (375/4)</gadget>
<output>25/4 = around 6.25</output>
<result>D</result> | D | 6.25 | The salary of a worker is first increased by 25% and afterwards reduced by 25%. What is the net change in the worker's salary? | {
"A": "3.25 % increase",
"B": "3.25 % decrease",
"C": "6.25 % increase",
"D": "6.25 % decrease",
"E": "no change"
} | subtract(const_100, subtract(add(25, const_100), divide(multiply(add(25, const_100), 25), const_100))) | add(n0,const_100)|multiply(n0,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(const_100,#3)| | "let x be the original salary . the final salary is 0.75 ( 1.25 x ) = 0.9375 x the answer is d ." | gain |
math_qa__WE4jFAyBex9v9sYu | Perimeter of front wheel =30, back wheel = 20. If front wheel revolves 240 times. How many revolutions will the back wheel take?
Choose the correct option
A) 120 B) 180 C) 240 D) 360 E) 480 | <gadget id="calculator">30 * 240</gadget>
<output>7_200</output>
<gadget id="calculator">7_200 / 20</gadget>
<output>360</output>
<result>D</result> | D | 360 | Perimeter of front wheel =30, back wheel = 20. If front wheel revolves 240 times. How many revolutions will the back wheel take? | {
"A": "120",
"B": "180",
"C": "240",
"D": "360",
"E": "480"
} | divide(multiply(30, 240), 20) | multiply(n0,n2)|divide(#0,n1) | sice the distance covered by both the wheels should be same so let x be the no . of revolutions by the back wheel so 240 * 2 * pie * 30 = x * 2 * pie * 20 so x = 360 . answer : d | general |
math_qa__Ya8nIZj87r7Xf2yP | 15 litres of mixture contains 25% alcohol and the rest water. If 3litres of water be mixed with it, the percentage of alcohol in the new mixture would be? Choose the correct choice from the following:
A) 20.83 % B) 23 % C) 18.3 % D) 19.75 % E) 21.23 % | <gadget id="calculator">15 + 3</gadget>
<output>18</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 15</gadget>
<output>45/4 = around 11.25</output>
<gadget id="calculator">(45/4) + 3</gadget>
<output>57/4 = around 14.25</output>
<gadget id="calculator">18 - (57/4)</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">(15/4) / 18</gadget>
<output>5/24 = around 0.208333</output>
<gadget id="calculator">(5/24) * 100</gadget>
<output>125/6 = around 20.833333</output>
<result>A</result> | A | 20.83 | 15 litres of mixture contains 25% alcohol and the rest water. If 3litres of water be mixed with it, the percentage of alcohol in the new mixture would be? | {
"A": "20.83 %",
"B": "23 %",
"C": "18.3 %",
"D": "19.75 %",
"E": "21.23 %"
} | multiply(divide(subtract(add(15, 3), add(multiply(divide(subtract(const_100, 25), const_100), 15), 3)), add(15, 3)), const_100) | add(n0,n2)|subtract(const_100,n1)|divide(#1,const_100)|multiply(n0,#2)|add(n2,#3)|subtract(#0,#4)|divide(#5,#0)|multiply(#6,const_100) | alcohol in the 15 litres of mix . = 25 % of 15 litres = ( 25 * 15 / 100 ) = 3.75 litres water in it = 15 - 3.75 = 11.25 litres new quantity of mix . = 15 + 3 = 18 litres quantity of alcohol in it = 3.75 litres percentage of alcohol in new mix . = 3.75 * 100 / 18 = 20.83 % answer is a | gain |
math_qa__QhjSbwxFlcHDCnss | Rs. 800 becomes Rs. 956 in 3 years at a certain rate of simple interest.If the rate of interest is increased by 4% ,What amount will Rs. 800 become in 3 years ? Choose the correct choice from the following options.
A) rs . 1020.80 B) rs . 1025 C) rs . 1052 D) data inadequate E) none of these | <gadget id="calculator">956 - 800</gadget>
<output>156</output>
<gadget id="calculator">156 * 100</gadget>
<output>15_600</output>
<gadget id="calculator">800 * 3</gadget>
<output>2_400</output>
<gadget id="calculator">15_600 / 2_400</gadget>
<output>13/2 = around 6.5</output>
<gadget id="calculator">(13/2) + 4</gadget>
<output>21/2 = around 10.5</output>
<gadget id="calculator">800 * (21/2)</gadget>
<output>8_400</output>
<gadget id="calculator">8_400 * 3</gadget>
<output>25_200</output>
<gadget id="calculator">25_200 / 100</gadget>
<output>252</output>
<gadget id="calculator">800 + 252</gadget>
<output>1_052</output>
<result>C</result> | C | 1,052 | Rs. 800 becomes Rs. 956 in 3 years at a certain rate of simple interest.If the rate of interest is increased by 4% ,What amount will Rs. 800 become in 3 years ? | {
"A": "rs . 1020.80",
"B": "rs . 1025",
"C": "rs . 1052",
"D": "data inadequate",
"E": "none of these"
} | add(800, divide(multiply(multiply(800, add(divide(multiply(subtract(956, 800), const_100), multiply(800, 3)), 4)), 3), const_100)) | multiply(n0,n2)|subtract(n1,n0)|multiply(#1,const_100)|divide(#2,#0)|add(n3,#3)|multiply(n0,#4)|multiply(n2,#5)|divide(#6,const_100)|add(n0,#7)| | "solution s . i . = rs . ( 956 - 800 ) = rs . 156 rate = ( 100 x 156 / 800 x 3 ) = 6 1 / 2 % new rate = ( 6 1 / 2 + 4 ) % = 10 1 / 2 % new s . i . = rs . ( 800 x 21 / 2 x 3 / 100 ) rs . 252 . ∴ new amount = rs . ( 800 + 252 ) = rs . 1052 . answer c" | gain |
math_qa__IYQDVVOhDrR4DQZ5 | A certain college's enrollment at the beginning of 1992 was 20 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 15 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ? Options
A) 17.5 % B) 24 % C) 30 % D) 35 % E) 38 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 / 100</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">120 * (23/20)</gadget>
<output>138</output>
<gadget id="calculator">138 - 100</gadget>
<output>38</output>
<result>E</result> | E | 38 | A certain college's enrollment at the beginning of 1992 was 20 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 15 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ? | {
"A": "17.5 %",
"B": "24 %",
"C": "30 %",
"D": "35 %",
"E": "38 %"
} | subtract(multiply(add(const_100, 20), divide(add(const_100, 15), const_100)), const_100) | add(n1,const_100)|add(n4,const_100)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,const_100)| | "suppose enrollment in 1991 was 100 then enrollment in 1992 will be 120 and enrollment in 1993 will be 120 * 1.15 = 138 increase in 1993 from 1991 = 138 - 100 = 38 answer : e" | gain |
math_qa__qDzl97v8AtRtu19B | Sonika deposited Rs.6200 which amounted to Rs.7200 after 5 years at simple interest. Had the interest been 3% more. She would get how much? Select the correct option
A) 9680 B) 8130 C) 8134 D) 8556 E) 9808 | <gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">7_200 - 6_200</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 5</gadget>
<output>200</output>
<gadget id="calculator">200 / 6_200</gadget>
<output>1/31 = around 0.032258</output>
<gadget id="calculator">(3/100) + (1/31)</gadget>
<output>193/3_100 = around 0.062258</output>
<gadget id="calculator">(193/3_100) * 6_200</gadget>
<output>386</output>
<gadget id="calculator">386 * 5</gadget>
<output>1_930</output>
<gadget id="calculator">1_930 + 6_200</gadget>
<output>8_130</output>
<result>B</result> | B | 8,130 | Sonika deposited Rs.6200 which amounted to Rs.7200 after 5 years at simple interest. Had the interest been 3% more. She would get how much? | {
"A": "9680",
"B": "8130",
"C": "8134",
"D": "8556",
"E": "9808"
} | add(multiply(multiply(add(divide(3, const_100), divide(divide(subtract(7200, 6200), 5), 6200)), 6200), 5), 6200) | divide(n3,const_100)|subtract(n1,n0)|divide(#1,n2)|divide(#2,n0)|add(#0,#3)|multiply(n0,#4)|multiply(n2,#5)|add(n0,#6)| | "( 6200 * 5 * 3 ) / 100 = 930 7200 - - - - - - - - 8130 answer : b" | gain |
math_qa__2N02kohdn8yyTuDc | If x is a positive integer, then the least value of x for which x! is divisible by 100,000 is?
Can someone please explain intuitively what the question is asking? Select.
A) 5
B) 9
C) 12
D) 20
E) 30 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<result>D</result> | D | 20 | If x is a positive integer, then the least value of x for which x! is divisible by 100,000 is?
Can someone please explain intuitively what the question is asking? | {
"A": "5",
"B": "9",
"C": "12",
"D": "20",
"E": "30"
} | multiply(divide(const_10, const_2), const_4) | divide(const_10,const_2)|multiply(#0,const_4) | in order x ! to be divisible by 1,000 , it should have at least 3 trailing zeros . a trailing 0 in factorial of a number is produced by 2 and 5 in it : 2 * 5 = 10 . so , we need 10 to be in x ! at least in power of 3 . 5 ! = 120 has 1 trailing zeros . 10 ! will have 2 trailing zeros . 15 ! will have 3 trailing zeros . 20 ! will have 5 trailing zeros . answer : d . | general |
math_qa__yzV9bdazh2lTDZq1 | There is enough provisions for 600 men in an army camp for 25 days. If there were 200 men less, how long will the provision last? Choose one: A) 50 days B) 60 days C) 70 days D) 75 days E) 90 days | <gadget id="calculator">600 * 25</gadget>
<output>15_000</output>
<gadget id="calculator">15_000 / 200</gadget>
<output>75</output>
<result>D</result> | D | 75 | There is enough provisions for 600 men in an army camp for 25 days. If there were 200 men less, how long will the provision last? | {
"A": "50 days",
"B": "60 days",
"C": "70 days",
"D": "75 days",
"E": "90 days"
} | divide(multiply(600, 25), 200) | multiply(n0,n1)|divide(#0,n2) | exp : we have , m 1 d 1 = m 2 d 2 600 * 25 = 200 * d 2 d 2 = 600 * 25 / 200 = 75 days . answer : d | physics |
math_qa__NWiBP6Kq76XOqUJe | When x is multiplied by 3, the result is 26 more than the result of subtracting x from 62. What is the value of x? Pick one.
A) - 4 B) - 2 C) 11 D) 13 E) 22 | <gadget id="calculator">62 + 26</gadget>
<output>88</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">88 / 4</gadget>
<output>22</output>
<result>E</result> | E | 22 | When x is multiplied by 3, the result is 26 more than the result of subtracting x from 62. What is the value of x? | {
"A": "- 4",
"B": "- 2",
"C": "11",
"D": "13",
"E": "22"
} | divide(add(62, 26), add(3, const_1)) | add(n1,n2)|add(const_1,n0)|divide(#0,#1)| | "the equation that can be formed is : 3 x - 26 = 62 - x or , 4 x = 88 or , x = 22 . answer : e" | general |
math_qa__dYW71PnmwdcxLiQF | Find the principle on a certain sum of money at 6% per annum for 2 2/5 years if the amount being Rs.1120? Options
A) 979 B) 1288 C) 2778 D) 2682 E) 1021 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 6</gadget>
<output>72/5 = around 14.4</output>
<gadget id="calculator">(72/5) / 100</gadget>
<output>18/125 = around 0.144</output>
<gadget id="calculator">(18/125) + 1</gadget>
<output>143/125 = around 1.144</output>
<gadget id="calculator">1_120 / (143/125)</gadget>
<output>140_000/143 = around 979.020979</output>
<result>A</result> | A | 979 | Find the principle on a certain sum of money at 6% per annum for 2 2/5 years if the amount being Rs.1120? | {
"A": "979",
"B": "1288",
"C": "2778",
"D": "2682",
"E": "1021"
} | divide(1120, add(divide(multiply(divide(add(multiply(2, 5), 2), 5), 6), const_100), const_1)) | multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)| | "1120 = p [ 1 + ( 6 * 12 / 5 ) / 100 ] p = 979 answer : a" | general |
math_qa__vN0txkcF9QTsVIo3 | My watch gains 5 min every hour. How many degrees the second hand moves in every min? Pick one
A) 300 B) 350 C) 390 D) 400 E) 450 | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">5 + 60</gadget>
<output>65</output>
<gadget id="calculator">360 * 65</gadget>
<output>23_400</output>
<gadget id="calculator">23_400 / 60</gadget>
<output>390</output>
<result>C</result> | C | 390 | My watch gains 5 min every hour. How many degrees the second hand moves in every min? | {
"A": "300",
"B": "350",
"C": "390",
"D": "400",
"E": "450"
} | divide(multiply(divide(const_3600, const_10), add(5, const_60)), const_60) | add(n0,const_60)|divide(const_3600,const_10)|multiply(#0,#1)|divide(#2,const_60) | gain 5 min every 1 hr degrees moves = = > 390 answer c | physics |
math_qa__RsGMnFfIYkc2TBNp | If 5 cats can kill 5 rats in 5 minutes, how long will it take 100 cats to kill 100 rats? Answers: A) 1 minutes B) 2 minutes C) 3 minutes D) 4 minutes E) 5 minutes | <gadget id="calculator">5 * 1</gadget>
<output>5</output>
<result>E</result> | E | 5 | If 5 cats can kill 5 rats in 5 minutes, how long will it take 100 cats to kill 100 rats? | {
"A": "1 minutes",
"B": "2 minutes",
"C": "3 minutes",
"D": "4 minutes",
"E": "5 minutes"
} | multiply(5, const_1) | multiply(n0,const_1)| | "it will take 5 minutes for 100 cats to kill 100 rats . 1 cat can kill 1 rat in 5 minutes , so 100 cats can kill 100 rats in 5 minutes answer e" | physics |
math_qa__g9m7Lxy61OjZUhuA | In a digital circuit which was to implement (A B) + (A)XOR(B), the designer implements (A B) (A)XOR(B) What is the probability of error in it ? Choose the correct choice from the following:
A) 25 %
B) 35 %
C) 75 %
D) 45 %
E) 55 % | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 100</gadget>
<output>75</output>
<result>C</result> | C | 75 | In a digital circuit which was to implement (A B) + (A)XOR(B), the designer implements (A B) (A)XOR(B) What is the probability of error in it ? | {
"A": "25 %",
"B": "35 %",
"C": "75 %",
"D": "45 %",
"E": "55 %"
} | multiply(divide(const_3, const_4), const_100) | divide(const_3,const_4)|multiply(#0,const_100) | a b ab a xor b ( ab ) + ( a xor b ) ( ab ) ( a xor b ) 0 0 0 0 0 0 0 1 0 1 1 0 1 0 0 1 1 0 1 1 1 0 1 0 so , we are getting 3 wrong answers out of 4 probability of error is 3 / 4 = 75 % answer : c | general |
math_qa__49aExht9IIGmea96 | If 4 men can colour 48 m long cloth in 2 days, then 5 men can colour 36 m long cloth in Choose the correct choice from the following choices:
A) 1.2 day B) 2.0 days C) 3 days D) 4.2 days E) 5 days | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">36 / 30</gadget>
<output>6/5 = around 1.2</output>
<result>A</result> | A | 1.2 | If 4 men can colour 48 m long cloth in 2 days, then 5 men can colour 36 m long cloth in | {
"A": "1.2 day",
"B": "2.0 days",
"C": "3 days",
"D": "4.2 days",
"E": "5 days"
} | divide(36, multiply(divide(48, multiply(4, 2)), 5)) | multiply(n0,n2)|divide(n1,#0)|multiply(n3,#1)|divide(n4,#2) | the length of cloth painted by one man in one day = 48 / 4 × 2 = 6 m no . of days required to paint 36 m cloth by 6 men = 36 / 6 × 5 = 1.2 day . a | physics |
math_qa__bgWHH8OiPVn3LqTb | Man1 does a work in 10 days and Man2 does the same work in 15 days. In how many days they together will do the same work ? Choices:
A) 10 days B) 5 days C) 6 days D) 7 days E) 8 days | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) + (1/15)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>C</result> | C | 6 | Man1 does a work in 10 days and Man2 does the same work in 15 days. In how many days they together will do the same work ? | {
"A": "10 days",
"B": "5 days",
"C": "6 days",
"D": "7 days",
"E": "8 days"
} | divide(const_1, add(divide(const_1, 10), divide(const_1, 15))) | divide(const_1,n1)|divide(const_1,n3)|add(#0,#1)|divide(const_1,#2) | man 1 day work = 1 / 10 man 2 day work = 1 / 15 both work = 1 / 10 + 1 / 15 = = = > 3 + 2 / 30 = = > 1 / 6 answer c | physics |
math_qa__5Mg4A2JfQV9vW9eE | From a container having pure milk, 20% is replaced by water and the process is repeated thrice. At the end of the third operation, the milk is Choose the correct choice from the following options:
A) 40 % pure B) 50 % pure C) 51.2 % pure D) 58.8 % pure E) none | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) ** 3</gadget>
<output>64/125 = around 0.512</output>
<gadget id="calculator">(64/125) * 100</gadget>
<output>256/5 = around 51.2</output>
<result>C</result> | C | 51.2 | From a container having pure milk, 20% is replaced by water and the process is repeated thrice. At the end of the third operation, the milk is | {
"A": "40 % pure",
"B": "50 % pure",
"C": "51.2 % pure",
"D": "58.8 % pure",
"E": "none"
} | multiply(power(divide(subtract(const_100, 20), const_100), const_3), const_100) | subtract(const_100,n0)|divide(#0,const_100)|power(#1,const_3)|multiply(#2,const_100)| | "solution let total quantity of original milk = 100 gm . milk after first operation = 80 % of 1000 ‹ = › 800 gm . milk after second operation = 80 % of 800 ‹ = › 640 gm . milk after third operation = 80 % of 640 ‹ = › 512 gm . strength of final mixtures = 51.2 % . answer c" | other |
math_qa__lWbHp3qlRTIHeKBi | A man invested Rs. 4940 in Rs. 10 shares quoted at Rs. 9.50. If the rate of dividend be 14%, his annual income is Choose the correct choice from the following choices: A) 708 B) 718 C) 738 D) 748 E) 728 | <gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">4_940 / 9.5</gadget>
<output>520</output>
<gadget id="calculator">520 * 10</gadget>
<output>5_200</output>
<gadget id="calculator">(7/50) * 5_200</gadget>
<output>728</output>
<result>E</result> | E | 728 | A man invested Rs. 4940 in Rs. 10 shares quoted at Rs. 9.50. If the rate of dividend be 14%, his annual income is | {
"A": "708",
"B": "718",
"C": "738",
"D": "748",
"E": "728"
} | multiply(divide(14, const_100), multiply(divide(4940, 9.50), 10)) | divide(n3,const_100)|divide(n0,n2)|multiply(n1,#1)|multiply(#0,#2)| | "market value of a share = rs . 9.50 investment = rs . 4940 number of shares = 4940 / 9.50 = 520 face value of a share = rs . 10 dividend = 14 % dividend per share = ( 10 × 14 ) / 100 = rs . 1.4 his annual income = 520 × 1.4 = rs . 728 answer is e ." | gain |
math_qa__ry7m0JoV2tQx9Bl1 | If 20 gallons of grape juice are added to 40 gallons of a mixture, which contains 10 percent grape juice then what percent of the resulting mixture is grape juice?
Choose the correct answer
A) 14 % B) 25 % C) 28 % D) 34 % E) 40 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 40</gadget>
<output>4</output>
<gadget id="calculator">4 + 20</gadget>
<output>24</output>
<gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">24 / 60</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>E</result> | E | 40 | If 20 gallons of grape juice are added to 40 gallons of a mixture, which contains 10 percent grape juice then what percent of the resulting mixture is grape juice? | {
"A": "14 %",
"B": "25 %",
"C": "28 %",
"D": "34 %",
"E": "40 %"
} | multiply(divide(add(multiply(divide(10, const_100), 40), 20), add(40, 20)), const_100) | add(n0,n1)|divide(n2,const_100)|multiply(n1,#1)|add(n0,#2)|divide(#3,#0)|multiply(#4,const_100)| | "official solution : if we start with 40 gallons of a mixture that is 10 % grape juice , then we have : 40 × 0.10 = 4 gallons of grape juice . 40 × 0.90 = 36 gallons of other components . if we add 20 gallons of grape juice , we will end up with 24 gallons of grape juice and 36 gallons of other components , and we will have a total of 60 gallons of the mixture . so 24 / 60 of the new mixture is grape juice . now we convert this to a percent : percent grape juice = 40 / 100 = 40 % . the correct answer is choice ( e )" | general |
math_qa__g6RX6KmhNSUdL7ma | The L.C.M. of two numbers is 30. The numbers are in the ratio 2 : 3. Then sum of the number is: Choose the correct choice from the following answers: A) 25 B) 32 C) 40 D) 53 E) 54 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">30 / 6</gadget>
<output>5</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<result>A</result> | A | 25 | The L.C.M. of two numbers is 30. The numbers are in the ratio 2 : 3. Then sum of the number is: | {
"A": "25",
"B": "32",
"C": "40",
"D": "53",
"E": "54"
} | add(multiply(divide(30, multiply(2, 3)), 3), multiply(divide(30, multiply(2, 3)), 2)) | multiply(n1,n2)|divide(n0,#0)|multiply(n2,#1)|multiply(n1,#1)|add(#2,#3)| | "let the numbers be 2 x and 3 x . then , their l . c . m . = 6 x . so , 6 x = 30 or x = 5 . the numbers are 10 and 15 . hence , required sum = ( 10 + 15 ) = 25 . answer : option a" | other |
math_qa__rdRFVW0pCMyt5zDQ | A box has exactly 100 balls, and each ball is either red, blue, or white. If the box has 12 more blue balls than white balls, and twice as many red balls as blue balls, how many white balls does The box has ? Select.
A) 8
B) 10
C) 12
D) 14
E) 16 | <gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">100 - 36</gadget>
<output>64</output>
<gadget id="calculator">64 / 4</gadget>
<output>16</output>
<result>E</result> | E | 16 | A box has exactly 100 balls, and each ball is either red, blue, or white. If the box has 12 more blue balls than white balls, and twice as many red balls as blue balls, how many white balls does The box has ? | {
"A": "8",
"B": "10",
"C": "12",
"D": "14",
"E": "16"
} | divide(subtract(100, multiply(12, const_3)), const_4) | multiply(n1,const_3)|subtract(n0,#0)|divide(#1,const_4) | x = the number of red balls y = the number of blue balls z = the number of white balls from the first sentence we have equation # 1 : x + y + z = 100 . . . the box has 12 more blue balls than white balls . . . equation # 2 : y = 12 + z . . . thrice as many red balls as blue balls . . . equation # 3 : x = 2 y solve equation # 2 for z : z = y - 12 now , we can replace both x and z with y in equation # 1 2 y + y + ( y - 12 ) = 100 4 y - 12 = 100 4 y = 112 y = 28 there are 28 blue balls . this is 15 more than the number of white balls , so z = 16 . that ' s the answer . just as a check , x = 56 , and 56 + 28 + 16 = 100 . answer = 16 , ( e ) | general |
math_qa__1NfQ7B8LP9xvhsvu | bill and jane play a simple game involving two fair dice , each of which has 6 sides numbered from 1 to 6 ( with an equal chance of landing on any side ) . bill rolls the dice and his score is the total of the two dice . jane then rolls the dice and her score is the total of her two dice . if jane ’ s score is higher than bill ’ s , she wins the game . what is the probability the jane will win the game ?
Choose the correct answer.
A) 15 / 36
B) 175 / 432
C) 575 / 1296
D) 583 / 1296
E) 1 / 2 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">30 * 11</gadget>
<output>330</output>
<gadget id="calculator">330 / 6</gadget>
<output>55</output>
<gadget id="calculator">55 * 2</gadget>
<output>110</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">110 + 36</gadget>
<output>146</output>
<gadget id="calculator">36 ** 2</gadget>
<output>1_296</output>
<gadget id="calculator">146 / 1_296</gadget>
<output>73/648 = around 0.112654</output>
<gadget id="calculator">1 - (73/648)</gadget>
<output>575/648 = around 0.887346</output>
<gadget id="calculator">(575/648) / 2</gadget>
<output>575/1_296 = around 0.443673</output>
<result>C</result> | C | 0.443673 | bill and jane play a simple game involving two fair dice , each of which has 6 sides numbered from 1 to 6 ( with an equal chance of landing on any side ) . bill rolls the dice and his score is the total of the two dice . jane then rolls the dice and her score is the total of her two dice . if jane ’ s score is higher than bill ’ s , she wins the game . what is the probability the jane will win the game ? | {
"A": "15 / 36",
"B": "175 / 432",
"C": "575 / 1296",
"D": "583 / 1296",
"E": "1 / 2"
} | divide(subtract(1, divide(add(multiply(divide(multiply(multiply(subtract(6, 1), 6), add(multiply(subtract(6, 1), const_2), 1)), 6), const_2), multiply(6, 6)), power(multiply(6, 6), const_2))), const_2) | multiply(n0,n0)|subtract(n0,n1)|multiply(#1,const_2)|multiply(n0,#1)|power(#0,const_2)|add(n1,#2)|multiply(#5,#3)|divide(#6,n0)|multiply(#7,const_2)|add(#8,#0)|divide(#9,#4)|subtract(n1,#10)|divide(#11,const_2) | there are three possible outcomes in the game : 1 . b wins 2 . j wins 3 . draw so , 1 = p ( j ) + p ( b ) + p ( draw ) 1 = p ( j ) + p ( b ) + p ( draw ) the probability of b winning or j winning the game is same . so , 1 = 2 ∗ p ( j ) + p ( draw ) 1 = 2 ∗ p ( j ) + p ( draw ) so , we need to calculate the probability of a draw . a draw can happen when both will have the same sum . the possible sums are - 2 , 34 , 56 , 78 , 910 , 1112 prob . of each sum is - 2 - 11 - 1 / 36 3 - 1 2 , 2 1 - 2 / 36 4 - 1 3 , 2 2 , 3 1 - 3 / 36 5 - 1 4 , 2 3 , 3 2 , 41 - 4 / 36 6 - 1 5 , 2 4 , 3 3 , 4 2 , 5 1 - 5 / 36 7 - 1 6 , 2 5 , 3 4 , 4 3 , 5 2 , 61 - 6 / 36 8 - 2 6 , 3 5 , 4 4 , 5 3 , 6 2 , - 5 / 36 9 - 3 6 , 4 5 , 5 4 , 63 - 4 / 36 10 - 4 6 , 5 5 , 6 4 - 3 / 36 11 - 5 6 , 6 5 - 2 / 36 12 - 6 6 - 1 / 36 now , since both have to get the same sum , the probability will be same for both and the combined probability will be the square of the probabilities i . e . 2 - ( 1 / 36 ) ^ 2 3 - ( 2 / 36 ) ^ 2 etc . squaring the probabilities and adding them will give 146 / 1296 so , p ( d ) = 146 / 1296 1 = 2 * p ( j ) + p ( d ) 2 * p ( j ) = 1150 / 1296 p ( j ) = 575 / 1296 ans . c | probability |
math_qa__gUWpqBv56uASciXX | The total age of A and B is 11 years more than the total age of B and C. C is how many year younger than A Choose the correct choice from the following answers:
A) 11 B) 12 C) 13 D) 14 E) 15 | <gadget id="calculator">11 * 1</gadget>
<output>11</output>
<result>A</result> | A | 11 | The total age of A and B is 11 years more than the total age of B and C. C is how many year younger than A | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | multiply(11, const_1) | multiply(n0,const_1)| | "explanation : given that a + b = 11 + b + c = > a ? c = 11 + b ? b = 11 = > c is younger than a by 11 years answer : option a" | general |
math_qa__JMzICj2lr05yN44U | The area of an equilateral triangle is subtracted from its base, and the perimeter is then added to this total, the result is 4. What is the height of the equilateral triangle if its base is 2? Choose one:
A) 2
B) 3
C) 4
D) 5
E) 6 | <gadget id="calculator">2 - 4</gadget>
<output>-2</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">(-2) + 6</gadget>
<output>4</output>
<result>C</result> | C | 4 | The area of an equilateral triangle is subtracted from its base, and the perimeter is then added to this total, the result is 4. What is the height of the equilateral triangle if its base is 2? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | add(subtract(2, 4), multiply(2, const_3)) | multiply(n1,const_3)|subtract(n1,n0)|add(#0,#1) | an eqilateral triangle means all sides are equal ; therefore , base = side . the equation is ; base - area + perimeter = b - a + p = b - 1 / 2 bh + 3 b , and b = 2 . so , 2 - 2 / 2 h + 6 = 4 , and 8 - h = 4 . by plugging in the answers we can test the answers quickly ; then , 4 is the only possible answer . answer : c | geometry |
math_qa__pZfT405IqdlVTWoq | (6!-4!)/5!=?
Choose the most appropriate option.
A) 29 / 5
B) 28 / 3
C) 27 / 6
D) 25 / 4
E) 29 / 6 | <gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">720 - 24</gadget>
<output>696</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">696 / 120</gadget>
<output>29/5 = around 5.8</output>
<result>A</result> | A | 5.8 | (6!-4!)/5!=? | {
"A": "29 / 5",
"B": "28 / 3",
"C": "27 / 6",
"D": "25 / 4",
"E": "29 / 6"
} | divide(subtract(factorial(6), factorial(4)), factorial(5)) | factorial(n0)|factorial(n1)|factorial(n2)|subtract(#0,#1)|divide(#3,#2) | ( 6 ! - 4 ! ) / 5 ! ( 4 ! * 5 * 6 - 4 ! ) / 5 ! 4 ! ( 5 * 6 - 1 ) / 4 ! * 5 29 / 5 answer a | general |
math_qa__Qjabfe4hdSLuBsmZ | A sum of money is sufficient to pay P's wages for 24 days and Q's wages for 40 days. The same money is sufficient to pay the wages of both for? Choose the correct choice.
A) 12 B) 13 C) 14 D) 15 E) 16 | <gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(1/24) + (1/40)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / (1/15)</gadget>
<output>15</output>
<result>D</result> | D | 15 | A sum of money is sufficient to pay P's wages for 24 days and Q's wages for 40 days. The same money is sufficient to pay the wages of both for? | {
"A": "12",
"B": "13",
"C": "14",
"D": "15",
"E": "16"
} | divide(const_1, add(divide(const_1, 24), divide(const_1, 40))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2) | let the total money be $ x p ' s 1 day work = $ x / 24 q ' s 1 day work = $ x / 40 p + q 1 day work = $ x / 15 money is sufficient to pay the wages of both for 15 days answer is d | general |
math_qa__RKHmXkR4X50DPoF1 | Tom opened a shop investing Rs.30000. Jose joined him 2 months later, investing Rs.45000. They earned a profit of Rs.27000 after completion of one year. What will be Jose's share of profit? Choose the correct option:
A) 20000 B) 15000 C) 25000 D) 34000 E) 30000 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">30_000 * 12</gadget>
<output>360_000</output>
<gadget id="calculator">12 - 2</gadget>
<output>10</output>
<gadget id="calculator">45_000 * 10</gadget>
<output>450_000</output>
<gadget id="calculator">450_000 + 360_000</gadget>
<output>810_000</output>
<gadget id="calculator">360_000 / 810_000</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">1 - (4/9)</gadget>
<output>5/9 = around 0.555556</output>
<gadget id="calculator">27_000 * (5/9)</gadget>
<output>15_000</output>
<result>B</result> | B | 15,000 | Tom opened a shop investing Rs.30000. Jose joined him 2 months later, investing Rs.45000. They earned a profit of Rs.27000 after completion of one year. What will be Jose's share of profit? | {
"A": "20000",
"B": "15000",
"C": "25000",
"D": "34000",
"E": "30000"
} | multiply(27000, subtract(const_1, divide(multiply(30000, multiply(2, multiply(2, const_3))), add(multiply(45000, subtract(multiply(2, multiply(2, const_3)), 2)), multiply(30000, multiply(2, multiply(2, const_3))))))) | multiply(n1,const_3)|multiply(#0,n1)|multiply(n0,#1)|subtract(#1,n1)|multiply(n2,#3)|add(#4,#2)|divide(#2,#5)|subtract(const_1,#6)|multiply(n3,#7)| | "sol = ~ s - so anju ’ s share = [ 5 / 9 ] x 27000 = 15000 b" | gain |
math_qa__eH1UgYg1yh6LWKwc | A certain family has 3 sons: Richard is 6 years older than David, and David is 8 years older than Scott. If in 8 years, Richard will be twice as old as Scott, then how old was David 7 years ago? Choices: A) 8 B) 10 C) 12 D) 14 E) 7 | <gadget id="calculator">6 + 8</gadget>
<output>14</output>
<gadget id="calculator">14 - 7</gadget>
<output>7</output>
<result>E</result> | E | 7 | A certain family has 3 sons: Richard is 6 years older than David, and David is 8 years older than Scott. If in 8 years, Richard will be twice as old as Scott, then how old was David 7 years ago? | {
"A": "8",
"B": "10",
"C": "12",
"D": "14",
"E": "7"
} | subtract(add(6, 8), 7) | add(n1,n2)|subtract(#0,n4)| | "let ' s say age of richard is ` ` r ' ' age of david is ` ` d ' ' age of scott is ` ` s ' ' now richard is 6 years older than david , i . e . r = d + 6 david is 8 years older than scott i . e . d = s + 8 if in 8 years , richard will be twice as old as scott i . e . r + 8 = 2 x ( s + 8 ) i . e . r + 8 = 2 s + 16 i . e . r = 2 s + 8 but r = d + 6 = ( s + 8 ) + 6 = s + 14 therefore , 2 s + 8 = s + 14 i . e . s = 6 i . e . r = 20 i . e . d = 14 now , how old was david 7 years ago ? i . e . d - 7 = 14 - 7 = 7 years answer : e" | general |
math_qa__HZarr9QUskQNsSFZ | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 84 more candidates got selected than A. What was the number of candidates appeared from each State? Choose the correct answer: A) 7000 B) 8400 C) 6000 D) 5000 E) 4000 | <gadget id="calculator">7 - 6</gadget>
<output>1</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">84 / (1/100)</gadget>
<output>8_400</output>
<result>B</result> | B | 8,400 | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 84 more candidates got selected than A. What was the number of candidates appeared from each State? | {
"A": "7000",
"B": "8400",
"C": "6000",
"D": "5000",
"E": "4000"
} | divide(84, divide(subtract(7, 6), const_100)) | subtract(n1,n0)|divide(#0,const_100)|divide(n2,#1)| | "state a and state b had an equal number of candidates appeared . in state a , 6 % candidates got selected from the total appeared candidates in state b , 7 % candidates got selected from the total appeared candidates but in state b , 84 more candidates got selected than state a from these , it is clear that 1 % of the total appeared candidates in state b = 84 = > total appeared candidates in state b = 84 x 100 = 8400 = > total appeared candidates in state a = total appeared candidates in state b = 8400" | general |
math_qa__mHG3O5bt2M3URJ3z | Find the area of a parallelogram with base 34 cm and height 18 cm? Choose the correct choice from the following answers:
A) 198 cm 2 B) 384 cm 2 C) 510 cm 2 D) 612 cm 2 E) 680 cm 2 | <gadget id="calculator">34 * 18</gadget>
<output>612</output>
<result>D</result> | D | 612 | Find the area of a parallelogram with base 34 cm and height 18 cm? | {
"A": "198 cm 2",
"B": "384 cm 2",
"C": "510 cm 2",
"D": "612 cm 2",
"E": "680 cm 2"
} | multiply(34, 18) | multiply(n0,n1)| | "area of a parallelogram = base * height = 34 * 18 = 612 cm 2 answer : d" | geometry |
math_qa__FwqoDpkID3dVewFG | In a sports club with 35 members, 15 play badminton and 18 play tennis and 5 do not play either. How many members play both badminton and tennis? Choose one
A) 3 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">15 + 18</gadget>
<output>33</output>
<gadget id="calculator">33 + 5</gadget>
<output>38</output>
<gadget id="calculator">38 - 35</gadget>
<output>3</output>
<result>A</result> | A | 3 | In a sports club with 35 members, 15 play badminton and 18 play tennis and 5 do not play either. How many members play both badminton and tennis? | {
"A": "3",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | subtract(add(add(15, 18), 5), 35) | add(n1,n2)|add(n3,#0)|subtract(#1,n0)| | "15 + 18 = 33 but where as total number is 35 - 5 = 30 therefore answer is 33 - 30 = 3 hence answer is a" | other |
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