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stringlengths 45
1.01k
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stringlengths 75
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float64 -4,212
100B
| question_without_options
stringlengths 6
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stringlengths 7
6.48k
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stringlengths 8
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stringlengths 1
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math_qa__i0ABKwDakX1PHd4q | If a is an integer greater than 2 but less than 7 and b is an integer greater than 4 but less than 13, what is the range of a/b? Choose the most appropriate option
A) 23 / 34
B) 57 / 60
C) 51 / 67
D) 19 / 71
E) 75 / 64 | <gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">6 / 5</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">13 - 1</gadget>
<output>12</output>
<gadget id="calculator">3 / 12</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(6/5) - (1/4)</gadget>
<output>19/20 = around 0.95</output>
<result>B</result> | B | 0.95 | If a is an integer greater than 2 but less than 7 and b is an integer greater than 4 but less than 13, what is the range of a/b? | {
"A": "23 / 34",
"B": "57 / 60",
"C": "51 / 67",
"D": "19 / 71",
"E": "75 / 64"
} | subtract(divide(subtract(7, const_1), add(4, const_1)), divide(add(2, const_1), subtract(13, const_1))) | add(n2,const_1)|add(n0,const_1)|subtract(n1,const_1)|subtract(n3,const_1)|divide(#2,#0)|divide(#1,#3)|subtract(#4,#5)| | "the way to approach this problem is 2 < a < 7 and 4 < b < 13 minimum possible value of a is 3 and maximum is 6 minimum possible value of b is 5 and maximum is 12 range = max a / min b - min a / max b ( highest - lowest ) 6 / 5 - 3 / 12 = 57 / 60 hence b" | general |
math_qa__XyN2L9zYCdB0voZZ | All factors of a positive integer A are multiplied and the product obtained is A^3. If A is greater than 1, how many factors does A have? Choose the most appropriate option: A) 2 B) 3 C) 5 D) 6 E) 8 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<result>D</result> | D | 6 | All factors of a positive integer A are multiplied and the product obtained is A^3. If A is greater than 1, how many factors does A have? | {
"A": "2",
"B": "3",
"C": "5",
"D": "6",
"E": "8"
} | divide(multiply(multiply(multiply(multiply(const_2, const_2), const_2), const_2), 3), multiply(multiply(const_2, const_2), const_2)) | multiply(const_2,const_2)|multiply(#0,const_2)|multiply(#1,const_2)|multiply(n0,#2)|divide(#3,#1) | answer = d = 6 number . . . . . . . . . . . . . . . . factors . . . . . . . . . . . . . . . . . . . . . . . . product 2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 2 , 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 8 5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5 6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 2 , 3 , 6 . . . . . . . . . . . . . . . . . . . . . . . . . 36 7 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 7 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7 8 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 2 , 4 , 8 . . . . . . . . . . . . . . . . . . . . . . . . . . . 64 9 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 3 , 9 . . . . . . . . . . . . . . . . . . . . . . . . . . . . 27 10 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 2 , 5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . 10 11 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 11 . . . . . . . . . . . . . . . . . . . . . . . . . . . 11 12 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 , 2 , 3 , 4 , 6 , 12 . . . . . . . . . . . . . . . . . 12 * 12 * 12 number which we are looking for = 12 answer = d | general |
math_qa__PDhnGI4D8Hh5AECZ | Express 22 mps in kmph? Choose the most appropriate option.
A) 79.2 kmph
B) 89.2 kmph
C) 79.6 kmph
D) 99.2 kmph
E) 69.2 kmph | <gadget id="calculator">22 / 1_000</gadget>
<output>11/500 = around 0.022</output>
<gadget id="calculator">(11/500) * 3_600</gadget>
<output>396/5 = around 79.2</output>
<result>A</result> | A | 79.2 | Express 22 mps in kmph? | {
"A": "79.2 kmph",
"B": "89.2 kmph",
"C": "79.6 kmph",
"D": "99.2 kmph",
"E": "69.2 kmph"
} | multiply(divide(22, const_1000), const_3600) | divide(n0,const_1000)|multiply(#0,const_3600)| | "22 * 18 / 5 = 79.2 kmph answer : a" | physics |
math_qa__A4WDHvmdqvPhxPl1 | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 90 units raises the average to 58 units per day, what is the value of n ? Choose the correct choice from the following answers:
A) 30
B) 18
C) 10
D) 9
E) 4 | <gadget id="calculator">90 - 50</gadget>
<output>40</output>
<gadget id="calculator">58 - 50</gadget>
<output>8</output>
<gadget id="calculator">40 / 8</gadget>
<output>5</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<result>E</result> | E | 4 | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 90 units raises the average to 58 units per day, what is the value of n ? | {
"A": "30",
"B": "18",
"C": "10",
"D": "9",
"E": "4"
} | subtract(divide(subtract(90, 50), subtract(58, 50)), const_1) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,#1)|subtract(#2,const_1)| | "( average production for n days ) * n = ( total production for n days ) - - > 50 n = ( total production for n days ) ; ( total production for n days ) + 90 = ( average production for n + 1 days ) * ( n + 1 ) - - > 50 n + 90 = 58 * ( n + 1 ) - - > n = 4 . or as 40 extra units increased the average for n + 1 days by 8 units per day then 40 / ( n + 1 ) = 8 - - > n = 4 . answer : e ." | general |
math_qa__z4NaNRTddedOx2Tt | The manager at a health foods store mixes a unique superfruit juice cocktail that costs $1399.45 per litre to make. The cocktail includes mixed fruit juice and açai berry juice, which cost $262.85 per litre and $3104.35 per litre, respectively. The manager has already opened 32 litres of the mixed fruit juice. How many litres of the açai berry juice does he need to add? Choose the most appropriate option
A) 17 litres B) 21.3 litres C) 11 litres D) 07 litres E) 38 litres | <gadget id="calculator">32 * 1_399.45</gadget>
<output>44_782.4</output>
<gadget id="calculator">32 * 262.85</gadget>
<output>8_411.2</output>
<gadget id="calculator">44_782.4 - 8_411.2</gadget>
<output>36_371.2</output>
<gadget id="calculator">3_104.35 - 1_399.45</gadget>
<output>1_704.9</output>
<gadget id="calculator">36_371.2 / 1_704.9</gadget>
<output>21.333333</output>
<result>B</result> | B | 21.3 | The manager at a health foods store mixes a unique superfruit juice cocktail that costs $1399.45 per litre to make. The cocktail includes mixed fruit juice and açai berry juice, which cost $262.85 per litre and $3104.35 per litre, respectively. The manager has already opened 32 litres of the mixed fruit juice. How many litres of the açai berry juice does he need to add? | {
"A": "17 litres",
"B": "21.3 litres",
"C": "11 litres",
"D": "07 litres",
"E": "38 litres"
} | divide(subtract(multiply(32, 1399.45), multiply(32, 262.85)), subtract(3104.35, 1399.45)) | multiply(n0,n3)|multiply(n1,n3)|subtract(n2,n0)|subtract(#0,#1)|divide(#3,#2)| | "262.85 ( 32 ) + 3 , 104.35 x = 1 , 399.45 ( 32 + x ) solve the equation . 262.85 ( 32 ) + 3 , 104.35 x = 1 , 399.45 ( 32 + x ) 8 , 411.2 + 3 , 104.35 x = 44 , 782.4 + 1 , 399.45 x 8 , 411.2 + 1 , 704.9 x = 44 , 782.4 1 , 704.9 x = 36 , 371.2 x ≈ 21.3 answer is b ." | general |
math_qa__hnMLUG6ZLRJMQyfs | the sum of the squares of 3 numbers is 241 , while the sum of their products taken two at a time is 100 . their sum is : Pick: A) 20 B) 11 C) 21 D) 41 E) none of these | <gadget id="calculator">100 * 2</gadget>
<output>200</output>
<gadget id="calculator">241 + 200</gadget>
<output>441</output>
<gadget id="calculator">441 ** (1/2)</gadget>
<output>21</output>
<result>C</result> | C | 21 | the sum of the squares of 3 numbers is 241 , while the sum of their products taken two at a time is 100 . their sum is : | {
"A": "20",
"B": "11",
"C": "21",
"D": "41",
"E": "none of these"
} | sqrt(add(241, multiply(100, const_2))) | multiply(n2,const_2)|add(n1,#0)|sqrt(#1) | x ^ + y ^ 2 + z ^ 2 = 241 xy + yz + zx = 100 as we know . . ( x + y + z ) ^ 2 = x ^ 2 + y ^ 2 + z ^ 2 + 2 ( xy + yz + zx ) so ( x + y + z ) ^ 2 = 241 + ( 2 * 100 ) ( x + y + z ) ^ 2 = 441 so x + y + z = 21 answer : c | general |
math_qa__zBzFml9keFQC2Vnw | Two goods trains each 720 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one? Choices
A) 22 sec B) 88 sec C) 48 sec D) 18 sec E) 72 sec | <gadget id="calculator">45 + 30</gadget>
<output>75</output>
<result>E</result> | E | 72 | Two goods trains each 720 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one? | {
"A": "22 sec",
"B": "88 sec",
"C": "48 sec",
"D": "18 sec",
"E": "72 sec"
} | add(45, 30) | add(n1,n2)| | "relative speed = 45 + 30 = 75 km / hr . 75 * 5 / 18 = 125 / 6 m / sec . distance covered = 750 + 750 = 1500 m . required time = 1500 * 6 / 125 = 72 sec . answer : e" | physics |
math_qa__oRXRTdHDkKzxSYZG | If w/x = 1/6 and w/y = 1/5, then (x + y)/y = Choose the correct choice from the following choices:
A) 4 / 5 B) 6 / 5 C) 7 / 5 D) 11 / 5 E) 9 / 5 | <gadget id="calculator">1 / 1</gadget>
<output>1</output>
<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">1 / (5/6)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) + 1</gadget>
<output>11/5 = around 2.2</output>
<result>D</result> | D | 2.2 | If w/x = 1/6 and w/y = 1/5, then (x + y)/y = | {
"A": "4 / 5",
"B": "6 / 5",
"C": "7 / 5",
"D": "11 / 5",
"E": "9 / 5"
} | add(divide(divide(1, 1), divide(5, 6)), const_1) | divide(n2,n0)|divide(n3,n1)|divide(#0,#1)|add(#2,const_1)| | "w / x = 1 / 6 = > x = 6 w and w / y = 1 / 5 = > y = 5 w ( x + y ) / y = ( 6 w + 5 w ) / 5 w = 11 w / 5 w = 11 / 5 correct option : d" | general |
math_qa__yjw138F2jhmbtGyh | 35 liters of a mixture is created by mixing Liquid P and Liquid Q in the ratio 4:3. How many liters of Liquid Q must be added to make the ratio 5:7?
Select the correct option:
A) 10 B) 11 C) 12 D) 13 E) 14 | <gadget id="calculator">5 + 7</gadget>
<output>12</output>
<gadget id="calculator">35 * 4</gadget>
<output>140</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">140 / 7</gadget>
<output>20</output>
<gadget id="calculator">12 * 20</gadget>
<output>240</output>
<gadget id="calculator">240 / 5</gadget>
<output>48</output>
<gadget id="calculator">48 * 7</gadget>
<output>336</output>
<gadget id="calculator">336 / 12</gadget>
<output>28</output>
<gadget id="calculator">35 * 3</gadget>
<output>105</output>
<gadget id="calculator">105 / 7</gadget>
<output>15</output>
<gadget id="calculator">28 - 15</gadget>
<output>13</output>
<result>D</result> | D | 13 | 35 liters of a mixture is created by mixing Liquid P and Liquid Q in the ratio 4:3. How many liters of Liquid Q must be added to make the ratio 5:7? | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | subtract(divide(multiply(divide(multiply(add(5, 7), divide(multiply(35, 4), add(4, 3))), 5), 7), add(5, 7)), divide(multiply(35, 3), add(4, 3))) | add(n3,n4)|add(n1,n2)|multiply(n0,n1)|multiply(n0,n2)|divide(#2,#1)|divide(#3,#1)|multiply(#0,#4)|divide(#6,n3)|multiply(n4,#7)|divide(#8,#0)|subtract(#9,#5) | let x be the amount of liquid q to be added . ( 3 / 7 ) * 35 + x = ( 7 / 12 ) * ( 35 + x ) 1260 + 84 x = 1715 + 49 x 35 x = 455 x = 13 the answer is d . | general |
math_qa__cXfkt6QEtjtnJ85u | A Jar contains a mixture of AB in the ratio 4:1. When 20 L of Mixture is replaced with liquid B, ratio becomes 2:3. How many liters of liquid A was present in mixture initially. Select.
A) 12
B) 15
C) 32
D) 20
E) 25 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">40 / 5</gadget>
<output>8</output>
<gadget id="calculator">8 * 4</gadget>
<output>32</output>
<result>C</result> | C | 32 | A Jar contains a mixture of AB in the ratio 4:1. When 20 L of Mixture is replaced with liquid B, ratio becomes 2:3. How many liters of liquid A was present in mixture initially. | {
"A": "12",
"B": "15",
"C": "32",
"D": "20",
"E": "25"
} | multiply(divide(multiply(add(multiply(3, 2), multiply(2, 2)), divide(20, subtract(multiply(3, 2), 1))), add(4, 1)), 4) | add(n0,n1)|multiply(n4,n3)|multiply(n3,n3)|add(#1,#2)|subtract(#1,n1)|divide(n2,#4)|multiply(#3,#5)|divide(#6,#0)|multiply(n0,#7)| | "20 litres of mixture that is replaced will contain 16 litres of a and 4 litres of b ( as a : b = 4 : 1 ) let the initial volume of the mixture be 4 k + 1 k = 5 k so by condition , [ 4 k - 16 ] / [ k - 4 + 20 ] = 2 / 3 = > 12 k - 48 = 2 k - 8 + 40 = > 10 k = 80 solve for k which is k = 8 so initial volume of liquid a = 4 k = 32 litres answer : c" | other |
math_qa__6JJH07ZoOKBO8FT7 | Two trains 140m and 160m long run at the speed of 60kmph and 40kmph in opposite directions in parallel tracks. The time which they take to cross each other is? Select: A) 5.6 sec B) 8.9 sec C) 10.8 sec D) 12.6 sec E) 15 sec | <gadget id="calculator">140 + 160</gadget>
<output>300</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">300 / (250/9)</gadget>
<output>54/5 = around 10.8</output>
<result>C</result> | C | 10.8 | Two trains 140m and 160m long run at the speed of 60kmph and 40kmph in opposite directions in parallel tracks. The time which they take to cross each other is? | {
"A": "5.6 sec",
"B": "8.9 sec",
"C": "10.8 sec",
"D": "12.6 sec",
"E": "15 sec"
} | divide(add(140, 160), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 kmph * 5 / 18 = 250 / 9 m / s distance covered in crossing each other = 140 + 160 = 300 m required time = 300 * 9 / 250 = 54 / 5 = 10.8 sec answer is c" | physics |
math_qa__hEQOHxIk6KsVn8CZ | For a certain exam,a score of 60 was 2 standard deviations below mean and a score of 100 was 3 standard deviations above mean.What was the mean score for the exam? Choose the correct choice from the following options.
A) 74 B) 76 C) 78 D) 80 E) 82 | <gadget id="calculator">60 * 3</gadget>
<output>180</output>
<gadget id="calculator">100 * 2</gadget>
<output>200</output>
<gadget id="calculator">180 + 200</gadget>
<output>380</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">380 / 5</gadget>
<output>76</output>
<result>B</result> | B | 76 | For a certain exam,a score of 60 was 2 standard deviations below mean and a score of 100 was 3 standard deviations above mean.What was the mean score for the exam? | {
"A": "74",
"B": "76",
"C": "78",
"D": "80",
"E": "82"
} | divide(add(multiply(60, 3), multiply(100, 2)), add(2, 3)) | add(n1,n3)|multiply(n0,n3)|multiply(n1,n2)|add(#1,#2)|divide(#3,#0)| | "mean - 2 sd = 60 mean + 3 sd = 100 by solving above we get , sd ( absolute value ) = 8 mean = 76 ans . b" | general |
math_qa__jVP53OS8Tt2furHb | The sum of the present age of Henry and Jill is 48. What is their present ages if 9 years ago Henry was twice the age of Jill? Choose the correct choice from the following options.
A) and 27 B) and 24 C) and 22 D) and 29 E) of these | <gadget id="calculator">48 + 9</gadget>
<output>57</output>
<gadget id="calculator">57 / 3</gadget>
<output>19</output>
<gadget id="calculator">48 - 19</gadget>
<output>29</output>
<result>D</result> | D | 29 | The sum of the present age of Henry and Jill is 48. What is their present ages if 9 years ago Henry was twice the age of Jill? | {
"A": "and 27",
"B": "and 24",
"C": "and 22",
"D": "and 29",
"E": "of these"
} | subtract(48, divide(add(48, 9), const_3)) | add(n0,n1)|divide(#0,const_3)|subtract(n0,#1)| | "let the age of jill 9 years ago be x , age of henry be 2 x x + 9 + 2 x + 9 = 48 x = 10 present ages will be 19 and 29 answer : d" | general |
math_qa__AI9nhVHrsE8vwISV | What is the area of a square field whose diagonal of length 16 m? Choose the correct choice from the following options:
A) 128
B) 289
C) 200
D) 112
E) 178 | <gadget id="calculator">16 ** 2</gadget>
<output>256</output>
<gadget id="calculator">256 / 2</gadget>
<output>128</output>
<result>A</result> | A | 128 | What is the area of a square field whose diagonal of length 16 m? | {
"A": "128",
"B": "289",
"C": "200",
"D": "112",
"E": "178"
} | divide(square_area(16), const_2) | square_area(n0)|divide(#0,const_2)| | "d 2 / 2 = ( 16 * 16 ) / 2 = 128 answer : a" | geometry |
math_qa__A5pdYaPsAjVr7eKG | The avg age of an adult class is 40years. 12new students with an avg age of 32years join the class. Therefore decreasingthe avg by 4year. Find what was the original strength of class? Choose the correct choice from the following: A) 8 B) 12 C) 15 D) 16 E) 19 | <gadget id="calculator">32 - 12</gadget>
<output>20</output>
<gadget id="calculator">40 - 32</gadget>
<output>8</output>
<gadget id="calculator">20 - 8</gadget>
<output>12</output>
<result>B</result> | B | 12 | The avg age of an adult class is 40years. 12new students with an avg age of 32years join the class. Therefore decreasingthe avg by 4year. Find what was the original strength of class? | {
"A": "8",
"B": "12",
"C": "15",
"D": "16",
"E": "19"
} | subtract(subtract(32, 12), subtract(40, 32)) | subtract(n2,n1)|subtract(n0,n2)|subtract(#0,#1) | let original strength = y then , 40 y + 12 x 32 = ( y + 12 ) x 36 ⇒ 40 y + 384 = 36 y + 432 ⇒ 4 y = 48 ∴ y = 12 b | general |
math_qa__JqgL3B67GfVjgyzh | What distance will be covered by a bus moving at 108 kmph in 30 seconds? Choose the correct answer
A) 287 B) 600 C) 289 D) 276 E) 900 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">108 * (5/18)</gadget>
<output>30</output>
<gadget id="calculator">30 * 30</gadget>
<output>900</output>
<result>E</result> | E | 900 | What distance will be covered by a bus moving at 108 kmph in 30 seconds? | {
"A": "287",
"B": "600",
"C": "289",
"D": "276",
"E": "900"
} | multiply(multiply(108, const_0_2778), 30) | multiply(n0,const_0_2778)|multiply(n1,#0)| | "108 kmph = 108 * 5 / 18 = 30 mps d = speed * time = 30 * 30 = 900 m . answer : e" | physics |
math_qa__dbAlGixwOa2tPW2P | Vijay sells a cupboard at 12% below cost price. Had he got Rs.1500 more, he would have made a profit of 12%. What is the cost price of the cupboard? Choose the correct choice from the following answers:
A) 7450
B) 14900
C) 6250
D) 6000
E) none of these | <gadget id="calculator">100 + 12</gadget>
<output>112</output>
<gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">112 - 88</gadget>
<output>24</output>
<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">1_500 / (6/25)</gadget>
<output>6_250</output>
<result>C</result> | C | 6,250 | Vijay sells a cupboard at 12% below cost price. Had he got Rs.1500 more, he would have made a profit of 12%. What is the cost price of the cupboard? | {
"A": "7450",
"B": "14900",
"C": "6250",
"D": "6000",
"E": "none of these"
} | divide(1500, divide(subtract(add(const_100, 12), subtract(const_100, 12)), const_100)) | add(n0,const_100)|subtract(const_100,n0)|subtract(#0,#1)|divide(#2,const_100)|divide(n1,#3)| | "explanation : cost price = 1500 / ( 0.12 + 0.12 ) = 1500 / 0.24 = rs . 6250 answer c" | gain |
math_qa__1KQuNR8hoMwIshOT | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 30 men in 3 days? Choose the correct choice from the following options:
A) 65 mtr . B) 84 mtr C) 70 mtr . D) 78 mtr . E) 17 mtr . | <gadget id="calculator">30 * 3</gadget>
<output>90</output>
<gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">90 / 120</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">112 * (3/4)</gadget>
<output>84</output>
<result>B</result> | B | 84 | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 30 men in 3 days? | {
"A": "65 mtr .",
"B": "84 mtr",
"C": "70 mtr .",
"D": "78 mtr .",
"E": "17 mtr ."
} | multiply(112, divide(multiply(30, 3), multiply(20, 6))) | multiply(n3,n4)|multiply(n0,n2)|divide(#0,#1)|multiply(n1,#2) | 20 men is 6 days can build 112 metres 30 men in 3 days can build = 112 * ( 30 / 20 ) x ( 3 / 6 ) = 84 meters answer : b . | physics |
math_qa__BDzTLDxCNwkZhO5W | If the speed of a man is 57 km per hour, then what is the distance traveled by him in 30 seconds ?
Answers: A) 275 m B) 360 m C) 475 m D) 420 m E) 440 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">57 * (5/18)</gadget>
<output>95/6 = around 15.833333</output>
<gadget id="calculator">(95/6) * 30</gadget>
<output>475</output>
<result>C</result> | C | 475 | If the speed of a man is 57 km per hour, then what is the distance traveled by him in 30 seconds ? | {
"A": "275 m",
"B": "360 m",
"C": "475 m",
"D": "420 m",
"E": "440 m"
} | multiply(multiply(57, const_0_2778), 30) | multiply(n0,const_0_2778)|multiply(n1,#0)| | "the distance traveled in 30 sec = 57 * ( 5 / 18 ) * 30 = 475 m answer : c" | physics |
math_qa__PayQYhLTmX2lX7KQ | Victor gets 90% marks in examinations. If these are 405 marks, find the maximum marks.
Choose the correct choice from the following choices: A) 334 B) 500 C) 376 D) 450 E) 271 | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">405 / (9/10)</gadget>
<output>450</output>
<result>D</result> | D | 450 | Victor gets 90% marks in examinations. If these are 405 marks, find the maximum marks. | {
"A": "334",
"B": "500",
"C": "376",
"D": "450",
"E": "271"
} | divide(405, divide(90, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "let the maximum marks be m then 90 % of m = 405 ⇒ 90 / 100 × m = 405 ⇒ m = ( 405 × 100 ) / 90 ⇒ m = 40500 / 90 ⇒ m = 450 therefore , maximum marks in the examinations are 450 answer : d" | gain |
math_qa__DyJWfkMoo7jAkM7E | Find the circumference and area of radius 13 cm. Choose the correct answer: A) 124 cm ² B) 531 cm ² C) 354 cm ² D) 584 cm ² E) 594 cm ² | <gadget id="calculator">pi * (13 ** 2)</gadget>
<output>169*pi = around 530.929158</output>
<result>B</result> | B | 531 | Find the circumference and area of radius 13 cm. | {
"A": "124 cm ²",
"B": "531 cm ²",
"C": "354 cm ²",
"D": "584 cm ²",
"E": "594 cm ²"
} | circle_area(13) | circle_area(n0)| | "area of circle = π r ² = 22 / 7 × 13 × 13 cm ² = 531 cm ² answer : b" | geometry |
math_qa__VMfWdCnqABom8tdd | (0.0048)(3.5) / (0.05)(0.1)(0.004)= Select the correct option
A) 8.4 B) 840 C) 84.0 D) 0.84 E) 0.084 | <gadget id="calculator">0.0048 * 3.5</gadget>
<output>0.0168</output>
<gadget id="calculator">0.05 * 0.1</gadget>
<output>0.005</output>
<gadget id="calculator">0.005 * 0.004</gadget>
<output>0.00002</output>
<gadget id="calculator">0.0168 / 0.00002</gadget>
<output>840</output>
<result>B</result> | B | 840 | (0.0048)(3.5) / (0.05)(0.1)(0.004)= | {
"A": "8.4",
"B": "840",
"C": "84.0",
"D": "0.84",
"E": "0.084"
} | divide(multiply(0.0048, 3.5), multiply(multiply(0.05, 0.1), 0.004)) | multiply(n0,n1)|multiply(n2,n3)|multiply(n4,#1)|divide(#0,#2) | ( 0.0048 ) ( 3.5 ) / ( 0.05 ) ( 0.1 ) ( 0.004 ) = 0.0048 * 350 / 5 ( 0.1 ) ( 0.004 ) = 0.048 * 70 / 1 ( 0.004 ) = 48 * 70 / 4 = 12 * 70 = 840 answer : b | general |
math_qa__Y57EJwq1bNrRTTR8 | A batsman in his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after the 17th innings? He had never been ’not out’. Options.
A) 47
B) 37
C) 39
D) 43
E) 42 | <gadget id="calculator">3 * 17</gadget>
<output>51</output>
<gadget id="calculator">85 - 51</gadget>
<output>34</output>
<gadget id="calculator">34 + 3</gadget>
<output>37</output>
<result>B</result> | B | 37 | A batsman in his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after the 17th innings? He had never been ’not out’. | {
"A": "47",
"B": "37",
"C": "39",
"D": "43",
"E": "42"
} | add(subtract(85, multiply(3, 17)), 3) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1) | average score before 17 th innings = 85 - 3 × 17 = 34 average score after 17 th innings = > 34 + 3 = 37 answer : b | general |
math_qa__3nhoHTnYNVNeKVoA | A hiker walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day she walked the same number of hours as on the first day, but at the same speed as on the second day. How many miles in total did she walk? Choose the correct option
A) 24 B) 44 C) 58 D) 60 E) 62 | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">18 + 20</gadget>
<output>38</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">38 + 24</gadget>
<output>62</output>
<result>E</result> | E | 62 | A hiker walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day she walked the same number of hours as on the first day, but at the same speed as on the second day. How many miles in total did she walk? | {
"A": "24",
"B": "44",
"C": "58",
"D": "60",
"E": "62"
} | add(add(18, multiply(add(3, const_1), subtract(divide(18, 3), const_1))), multiply(divide(18, 3), add(3, const_1))) | add(n0,const_1)|divide(n1,n0)|multiply(#0,#1)|subtract(#1,const_1)|multiply(#0,#3)|add(n1,#4)|add(#5,#2) | first day - 18 miles with 3 miles per hours then total - 6 hours for that day second day - 4 miles per hour and 5 hours - 20 miles third day - 4 miles per hour and 6 hours - 24 miles total 18 + 20 + 24 - 62 answer : option e . | physics |
math_qa__BZ2CeBjur2JAyYhT | A runner runs the 40 miles from Marathon to Athens at a constant speed. Halfway through the run she injures her foot, and continues to run at half her previous speed. If the second half takes her 4 hours longer than the first half, how many hours did it take the runner to run the second half? Select the correct option:
A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">40 / 5</gadget>
<output>8</output>
<result>C</result> | C | 8 | A runner runs the 40 miles from Marathon to Athens at a constant speed. Halfway through the run she injures her foot, and continues to run at half her previous speed. If the second half takes her 4 hours longer than the first half, how many hours did it take the runner to run the second half? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | divide(40, divide(divide(40, const_2), 4)) | divide(n0,const_2)|divide(#0,n1)|divide(n0,#1)| | "the runner runs the first 20 miles at speed v and the second 20 miles at speed v / 2 . the time t 2 to run the second half must be twice the time t 1 to run the first half . t 2 = 2 * t 1 = t 1 + 4 t 1 = 4 and so t 2 = 8 . the answer is c ." | physics |
math_qa__ur9iMgf22sq7pWZJ | A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together?
Choices.
A) 6.4 days B) 4.4 days C) 5.4 days D) 8.4 days E) 2.4 days | <gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/15) + (1/20)</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">(1/25) + (7/60)</gadget>
<output>47/300 = around 0.156667</output>
<gadget id="calculator">1 / (47/300)</gadget>
<output>300/47 = around 6.382979</output>
<result>A</result> | A | 6.4 | A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together? | {
"A": "6.4 days",
"B": "4.4 days",
"C": "5.4 days",
"D": "8.4 days",
"E": "2.4 days"
} | divide(const_1, add(divide(const_1, 25), add(divide(const_1, 15), divide(const_1, 20)))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#3,#2)|divide(const_1,#4) | a 6.4 days 1 day work of the three persons = ( 1 / 15 + 1 / 20 + 1 / 25 ) = 47 / 300 so , all three together will complete the work in 300 / 47 = 6.4 days . - | physics |
math_qa__OOkJc6dwlrigcbk8 | Cricket match is conducted in US. The run rate of a cricket game was only 3.2 in first 10 over. What should be the run rate in the remaining 40 overs to reach the target of 272 runs? Choose the correct option.
A) 6 B) 6.25 C) 7.25 D) 7.5 E) 8 | <gadget id="calculator">3.2 * 10</gadget>
<output>32</output>
<gadget id="calculator">272 - 32</gadget>
<output>240</output>
<gadget id="calculator">240 / 40</gadget>
<output>6</output>
<result>A</result> | A | 6 | Cricket match is conducted in US. The run rate of a cricket game was only 3.2 in first 10 over. What should be the run rate in the remaining 40 overs to reach the target of 272 runs? | {
"A": "6",
"B": "6.25",
"C": "7.25",
"D": "7.5",
"E": "8"
} | divide(subtract(272, multiply(3.2, 10)), 40) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2) | required run rate = 272 - ( 3.2 x 10 ) = 240 = 6 40 40 a | gain |
math_qa__YBNKXGfFkpcpBgUK | Of the total amount that Jill spent on a shopping trip, excluding taxes, she spent 50 percent on clothing, 20 percent on food, and 30 percent on other items. If Jill paid a 5 percent tax on the clothing, no tax on the food, and an 10 percent tax on all other items, then the total tax that she paid was what percent of the total amount that she spent, excluding taxes? Choose the correct choice from the following choices:
A) 5.5 % B) 3.6 % C) 4.4 % D) 5.2 % E) 6.0 % | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">50 * (1/20)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">30 * (1/10)</gadget>
<output>3</output>
<gadget id="calculator">(5/2) + 3</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">(11/2) / 100</gadget>
<output>11/200 = around 0.055</output>
<gadget id="calculator">(11/200) * 100</gadget>
<output>11/2 = around 5.5</output>
<result>A</result> | A | 5.5 | Of the total amount that Jill spent on a shopping trip, excluding taxes, she spent 50 percent on clothing, 20 percent on food, and 30 percent on other items. If Jill paid a 5 percent tax on the clothing, no tax on the food, and an 10 percent tax on all other items, then the total tax that she paid was what percent of the total amount that she spent, excluding taxes? | {
"A": "5.5 %",
"B": "3.6 %",
"C": "4.4 %",
"D": "5.2 %",
"E": "6.0 %"
} | multiply(divide(add(multiply(50, divide(5, const_100)), multiply(30, divide(10, const_100))), const_100), const_100) | divide(n3,const_100)|divide(n4,const_100)|multiply(n0,#0)|multiply(n2,#1)|add(#2,#3)|divide(#4,const_100)|multiply(#5,const_100)| | "let amount spent by jill = 100 clothing = 50 , food = 20 , others = 30 tax on clothing = 2.5 tax on others = 3 percentage = 5.5 / 100 = 5.5 % answer : a" | general |
math_qa__AGhdZ6MR9BLxI9M4 | In a certain warehouse, 70 percent of the packages weigh less than 75 pounds, and a total of 48 packages weigh less than 25 pounds. If 80 percent of the packages weigh at least 25 pounds, how many of the packages weigh at least 25 pounds but less than 75 pounds? Choose the correct choice from the following answers.
A) 8 B) 64 C) 120 D) 102 E) 144 | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">48 / 20</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 100</gadget>
<output>240</output>
<gadget id="calculator">240 * 70</gadget>
<output>16_800</output>
<gadget id="calculator">16_800 / 100</gadget>
<output>168</output>
<gadget id="calculator">168 - 48</gadget>
<output>120</output>
<result>C</result> | C | 120 | In a certain warehouse, 70 percent of the packages weigh less than 75 pounds, and a total of 48 packages weigh less than 25 pounds. If 80 percent of the packages weigh at least 25 pounds, how many of the packages weigh at least 25 pounds but less than 75 pounds? | {
"A": "8",
"B": "64",
"C": "120",
"D": "102",
"E": "144"
} | subtract(divide(multiply(multiply(divide(48, subtract(const_100, 80)), const_100), 70), const_100), 48) | subtract(const_100,n4)|divide(n2,#0)|multiply(#1,const_100)|multiply(n0,#2)|divide(#3,const_100)|subtract(#4,n2) | if 80 % of the packages weigh at least 25 pounds this means that 20 % of the packages weigh less than 25 pounds let t = total number of packages so , 20 % of t = # of packages that weigh less than 25 pounds 48 packages weigh less than 25 pounds great . so , 20 % of t = 48 rewrite to get : 0.2 t = 48 solve : t = 240 70 % of the packages weigh less than 75 pounds so , 70 % oft = number of packages that weigh less than 75 pounds 70 % of 240 = 168 , so 168 packages weigh less than 75 pounds of those 168 packages that weigh less than 75 pounds , 48 packages weigh less than 25 pounds . so , the number of packages that weight between 25 and 75 pounds = 168 - 48 = 120 = c | general |
math_qa__YGzkF3rf7ylwvZ71 | in the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30 . in the sport formulation , the ratio of flavoring to corn syrup is 3 times as great as in the standard formulation , and the ratio of flavoring to water is half that of the standard formulation . if a large bottle of the sport formulation contains 2 ounces of corn syrup , how many ounces of water does it contain ? Choose the correct answer:
A) 15 B) 30 C) 45 D) 60 E) 90 | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 3</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">(1/2) * 60</gadget>
<output>30</output>
<result>B</result> | B | 30 | in the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30 . in the sport formulation , the ratio of flavoring to corn syrup is 3 times as great as in the standard formulation , and the ratio of flavoring to water is half that of the standard formulation . if a large bottle of the sport formulation contains 2 ounces of corn syrup , how many ounces of water does it contain ? | {
"A": "15",
"B": "30",
"C": "45",
"D": "60",
"E": "90"
} | multiply(multiply(multiply(divide(1, 12), 3), const_2), multiply(30, 2)) | divide(n0,n1)|multiply(n2,n4)|multiply(n3,#0)|multiply(#2,const_2)|multiply(#3,#1) | standard : fl : corn s : water = 1 : 12 : 30 sport : fl : corn s : water = 3 : 12 : 180 this simplifies to 1 : 4 : 60 if the large bottle has a capacity of x ounces , then 4 x / 65 = 2 . so , x = 32.5 ounces . water = ( 60 / 65 ) * ( 65 / 2 ) = = 30 ounces . ans b | other |
math_qa__Iwdbp4LLGYiVJi1q | A machine, working at a constant rate, manufactures 18 pens in 30 minutes. How many pens does it make in 1 hr 45 min?
Select the correct option.
A) 63
B) 65
C) 62
D) 60
E) 45 | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">60 + 45</gadget>
<output>105</output>
<gadget id="calculator">105 / 30</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) * 18</gadget>
<output>63</output>
<result>A</result> | A | 63 | A machine, working at a constant rate, manufactures 18 pens in 30 minutes. How many pens does it make in 1 hr 45 min? | {
"A": "63",
"B": "65",
"C": "62",
"D": "60",
"E": "45"
} | multiply(divide(add(multiply(1, const_60), 45), 30), 18) | multiply(n2,const_60)|add(n3,#0)|divide(#1,n1)|multiply(n0,#2) | change 1 hr 45 min to 105 min . for this , we need to set up a simple proportion of pens per time 18 / 30 = s / 105 the absolutely worst thing you could do at this point in the problem is to cross - multiply . that would be a supremely unstrategic move . instead , cancel before you multiply . for what we can see this post . we can cancel 18 / 30 as 6 / 10 6 / 10 = s / 105 we can cross - multiply . 10 * s = 6 * 105 = 630 if we divide both sides by 10 , s = 63 the machine would be 63 pens in 1 hr 45 min . answer : a | physics |
math_qa__2Ma2YCCo1ug5ioGZ | A car traveling at a certain constant speed takes 2 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 225 kilometers per hour. At what speed, in kilometers per hour, is the car traveling? Select the correct option: A) 220 B) 200 C) 210 D) 225 E) 230 | <gadget id="calculator">1 / 225</gadget>
<output>1/225 = around 0.004444</output>
<gadget id="calculator">3_600 * (1/225)</gadget>
<output>16</output>
<gadget id="calculator">16 + 2</gadget>
<output>18</output>
<gadget id="calculator">18 / 3_600</gadget>
<output>1/200 = around 0.005</output>
<gadget id="calculator">1 / (1/200)</gadget>
<output>200</output>
<result>B</result> | B | 200 | A car traveling at a certain constant speed takes 2 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 225 kilometers per hour. At what speed, in kilometers per hour, is the car traveling? | {
"A": "220",
"B": "200",
"C": "210",
"D": "225",
"E": "230"
} | divide(1, divide(add(multiply(const_3600, divide(1, 225)), 2), const_3600)) | divide(n1,n3)|multiply(#0,const_3600)|add(n0,#1)|divide(#2,const_3600)|divide(n1,#3)| | "b 225 * t = 1 km = > t = 1 / 225 km / h v * ( t + 2 / 3600 ) = 1 v ( 1 / 225 + 2 / 3600 ) = 1 = > v = 200 km / h" | physics |
math_qa__XoMNTjCznMTxQYML | (51+52+53+………+100) is equal to: Choose the correct answer.
A) 2525 B) 2975 C) 3225 D) 3775 E) 3885 | <gadget id="calculator">100 + 1</gadget>
<output>101</output>
<gadget id="calculator">100 * 101</gadget>
<output>10_100</output>
<gadget id="calculator">10_100 / 2</gadget>
<output>5_050</output>
<gadget id="calculator">51 - 1</gadget>
<output>50</output>
<gadget id="calculator">50 * 51</gadget>
<output>2_550</output>
<gadget id="calculator">2_550 / 2</gadget>
<output>1_275</output>
<gadget id="calculator">5_050 - 1_275</gadget>
<output>3_775</output>
<result>D</result> | D | 3,775 | (51+52+53+………+100) is equal to: | {
"A": "2525",
"B": "2975",
"C": "3225",
"D": "3775",
"E": "3885"
} | subtract(divide(multiply(100, add(100, const_1)), const_2), divide(multiply(subtract(51, const_1), 51), const_2)) | add(n3,const_1)|subtract(n0,const_1)|multiply(n3,#0)|multiply(n0,#1)|divide(#2,const_2)|divide(#3,const_2)|subtract(#4,#5)| | "( 51 + 52 + 53 + … … … + 100 ) = ( 1 + 2 + 3 + … … . + 100 ) - ( 1 + 2 + 3 + 4 + … … + 50 ) = ( 100 * 101 ) / 2 - ( 50 * 51 ) / 2 = ( 5050 - 1275 ) = 3775 . answer : d" | general |
math_qa__dBzfoLznNt2HTN3l | The mean of 50 observations was 30. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is Choose the correct choice from the following options.
A) 35.2
B) 36.1
C) 30.5
D) 39.1
E) none | <gadget id="calculator">30 * 50</gadget>
<output>1_500</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">48 - 23</gadget>
<output>25</output>
<gadget id="calculator">1_500 + 25</gadget>
<output>1_525</output>
<gadget id="calculator">1_525 / 50</gadget>
<output>61/2 = around 30.5</output>
<result>C</result> | C | 30.5 | The mean of 50 observations was 30. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is | {
"A": "35.2",
"B": "36.1",
"C": "30.5",
"D": "39.1",
"E": "none"
} | divide(add(multiply(30, 50), subtract(subtract(50, const_2), 23)), 50) | multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,n3)|add(#0,#2)|divide(#3,n0)| | "sol . therefore correct sum = ( 30 × 50 + 48 – 23 ) = 1525 . therefore correct mean = 1525 / 50 = 30.5 . answer c" | general |
math_qa__EjLoRvtft4loQO0F | A train running at the speed of 60 km/hr crosses a pole in 42 seconds. What is the length of the train? Choose the correct choice from the following.
A) 120 metres
B) 700 metres
C) 324 metres
D) 828 metres
E) 600 metres | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 42</gadget>
<output>700</output>
<result>B</result> | B | 700 | A train running at the speed of 60 km/hr crosses a pole in 42 seconds. What is the length of the train? | {
"A": "120 metres",
"B": "700 metres",
"C": "324 metres",
"D": "828 metres",
"E": "600 metres"
} | multiply(divide(multiply(60, const_1000), const_3600), 42) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 x 5 / 18 m / sec = 50 / 3 m / sec . length of the train = ( speed x time ) . length of the train = 50 / 3 x 42 m = 150 m . option b" | physics |
math_qa__N4O1vM89y0T0vnYS | The average weight of 6 person's increases by 3.5 kg when a new person comes in place of one of them weighing 47 kg. What might be the weight of the new person? Choose the correct choice from the following.
A) 60 kg B) 75 kg C) 68 kg D) 85 kg E) 90 kg | <gadget id="calculator">6 * 3.5</gadget>
<output>21</output>
<gadget id="calculator">21 + 47</gadget>
<output>68</output>
<result>C</result> | C | 68 | The average weight of 6 person's increases by 3.5 kg when a new person comes in place of one of them weighing 47 kg. What might be the weight of the new person? | {
"A": "60 kg",
"B": "75 kg",
"C": "68 kg",
"D": "85 kg",
"E": "90 kg"
} | add(multiply(6, 3.5), 47) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 6 x 3.5 ) kg = 21 kg . weight of new person = ( 47 + 21 ) kg = 68 kg option c" | general |
math_qa__hO86dDGbsjne9Ub3 | Ajay can walk 6km in 1 hour. In how many hours he can walk 70km?
Choose the correct choice from the following answers: A) 5 hrs B) 11.6 hrs C) 15.6 hrs D) 20.1 hrs E) 30 hrs | <gadget id="calculator">70 / 6</gadget>
<output>35/3 = around 11.666667</output>
<result>B</result> | B | 11.6 | Ajay can walk 6km in 1 hour. In how many hours he can walk 70km? | {
"A": "5 hrs",
"B": "11.6 hrs",
"C": "15.6 hrs",
"D": "20.1 hrs",
"E": "30 hrs"
} | divide(70, 6) | divide(n2,n0)| | "1 hour he walk 6 km he walk 70 km in = 70 / 6 * 1 = 11.6 hours answer is b" | physics |
math_qa__hHd4IDrd1xPfb2N8 | Find the simple interest on Rs. 71,000 at 16 2/3% per year for 9 months. Choose the correct choice from the following answers
A) 7500 B) 6500 C) 8875 D) 9500 E) none of them | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 * 100</gadget>
<output>60_000</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 100</gadget>
<output>900</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">900 * 10</gadget>
<output>9_000</output>
<gadget id="calculator">60_000 + 9_000</gadget>
<output>69_000</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 + 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 3</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">69_000 * (50/3)</gadget>
<output>1_150_000</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1_150_000 * (3/4)</gadget>
<output>862_500</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">862_500 * (1/100)</gadget>
<output>8_625</output>
<result>C</result> | C | 8,875 | Find the simple interest on Rs. 71,000 at 16 2/3% per year for 9 months. | {
"A": "7500",
"B": "6500",
"C": "8875",
"D": "9500",
"E": "none of them"
} | multiply(multiply(multiply(add(multiply(multiply(multiply(2, 3), const_100), const_100), multiply(multiply(multiply(3, 3), const_100), multiply(add(3, 2), 2))), divide(add(multiply(16, 3), 2), 3)), divide(multiply(3, 3), multiply(2, multiply(2, 3)))), divide(const_1, const_100)) | add(n2,n3)|divide(const_1,const_100)|multiply(n3,n3)|multiply(n2,n3)|multiply(n1,n3)|add(n2,#4)|multiply(n2,#3)|multiply(#3,const_100)|multiply(#2,const_100)|multiply(#0,n2)|divide(#2,#6)|divide(#5,n3)|multiply(#7,const_100)|multiply(#8,#9)|add(#12,#13)|multiply(#14,#11)|multiply(#10,#15)|multiply(#1,#16)| | "p = rs . 71000 , r = 50 / 3 % p . a and t = 9 / 12 years = 3 / 4 years . simple interest = ( p * r * t ) / 100 = rs . ( 71,000 * ( 50 / 3 ) * ( 3 / 4 ) * ( 1 / 100 ) ) = rs . 8875 answer is c ." | gain |
math_qa__9iImmXkxrGl2nKUn | John makes $65 a week from his job. He earns a raise andnow makes $72 a week. What is the % increase? Choose the correct choice from the following choices:
A) 16 % B) 10.76 % C) 10.69 % D) 10.98 % E) 10 % | <gadget id="calculator">72 - 65</gadget>
<output>7</output>
<gadget id="calculator">7 / 65</gadget>
<output>7/65 = around 0.107692</output>
<gadget id="calculator">(7/65) * 100</gadget>
<output>140/13 = around 10.769231</output>
<result>B</result> | B | 10.76 | John makes $65 a week from his job. He earns a raise andnow makes $72 a week. What is the % increase? | {
"A": "16 %",
"B": "10.76 %",
"C": "10.69 %",
"D": "10.98 %",
"E": "10 %"
} | multiply(divide(subtract(72, 65), 65), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 7 / 65 ) * 100 = ( 7 / 65 ) * 100 = 10.76 % . b" | gain |
math_qa__fAxp059fmFJB4r8B | If 20 men take 15 days to to complete a job, in how many days can 20 men finish that work?
Select the correct option.
A) 15
B) 16
C) 17
D) 18
E) 19 | <gadget id="calculator">20 * 15</gadget>
<output>300</output>
<gadget id="calculator">300 / 20</gadget>
<output>15</output>
<result>A</result> | A | 15 | If 20 men take 15 days to to complete a job, in how many days can 20 men finish that work? | {
"A": "15",
"B": "16",
"C": "17",
"D": "18",
"E": "19"
} | divide(multiply(20, 15), 20) | multiply(n0,n1)|divide(#0,n2)| | ans . 15 days | physics |
math_qa__F3thzeYSUjiQ2QGS | A can do a piece of work 40 days. B can do work in 60 days. In how many days they will complete the work together?
Answers
A) 15 days
B) 16 days
C) 19 days
D) 17 days
E) 24 days | <gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/40) + (1/60)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<result>E</result> | E | 24 | A can do a piece of work 40 days. B can do work in 60 days. In how many days they will complete the work together? | {
"A": "15 days",
"B": "16 days",
"C": "19 days",
"D": "17 days",
"E": "24 days"
} | divide(const_1, add(divide(const_1, 40), divide(const_1, 60))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)| | "lcm = 120 , ratio = 40 : 60 = 2 : 3 no of days = 120 / ( 2 + 3 ) = 90 / 5 = 24 days answer : e" | physics |
math_qa__Nv7lnO8LqLBd6fbC | A profit of Rs. 800 is divided between X and Y in the ratio of 1/2:1/3 . What is the difference between their profit shares ? Pick one:
A) s . 260 B) s . 160 C) s . 360 D) s . 50 E) s . 90 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/2) + (1/3)</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">800 / (5/6)</gadget>
<output>960</output>
<gadget id="calculator">960 / 2</gadget>
<output>480</output>
<gadget id="calculator">960 / 3</gadget>
<output>320</output>
<gadget id="calculator">480 - 320</gadget>
<output>160</output>
<result>B</result> | B | 160 | A profit of Rs. 800 is divided between X and Y in the ratio of 1/2:1/3 . What is the difference between their profit shares ? | {
"A": "s . 260",
"B": "s . 160",
"C": "s . 360",
"D": "s . 50",
"E": "s . 90"
} | subtract(divide(divide(800, add(divide(1, 2), divide(1, 3))), 2), divide(divide(800, add(divide(1, 2), divide(1, 3))), 3)) | divide(n1,n2)|divide(n1,n4)|add(#0,#1)|divide(n0,#2)|divide(#3,n2)|divide(#3,n4)|subtract(#4,#5)| | "a profit of rs . 800 is divided between x and y in the ratio of 1 / 2 : 1 / 3 or 3 : 2 . so profits are 480 and 320 . difference in profit share = 480 - 320 = 160 answer : b" | general |
math_qa__yuuzOkwmK5aUW7Hc | A book is bought for $60 and sold for $78. What is the profit in percentage? Choose one
A) 10
B) 20
C) 30
D) 40
E) 50 | <gadget id="calculator">78 - 60</gadget>
<output>18</output>
<gadget id="calculator">18 / 60</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 100</gadget>
<output>30</output>
<result>C</result> | C | 30 | A book is bought for $60 and sold for $78. What is the profit in percentage? | {
"A": "10",
"B": "20",
"C": "30",
"D": "40",
"E": "50"
} | multiply(divide(subtract(78, 60), 60), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "78 / 60 = 1.3 the answer is c ." | gain |
math_qa__4cwlCTlyBmcOOxNP | a is a positive integer and multiple of 2; p = 4^a, what is the remainder when p is divided by 10? Choose the correct choice from the following.
A) 10 B) 6 C) 4 D) 0 E) it can not be determined | <gadget id="calculator">4 ** 4</gadget>
<output>256</output>
<gadget id="calculator">256 % 10</gadget>
<output>6</output>
<result>B</result> | B | 6 | a is a positive integer and multiple of 2; p = 4^a, what is the remainder when p is divided by 10? | {
"A": "10",
"B": "6",
"C": "4",
"D": "0",
"E": "it can not be determined"
} | reminder(power(const_4, const_4), 10) | power(const_4,const_4)|reminder(#0,n2) | it is essential to recognize that the remainder when an integer is divided by 10 is simply the units digit of that integer . to help see this , consider the following examples : 4 / 10 is 0 with a remainder of 4 14 / 10 is 1 with a remainder of 4 5 / 10 is 0 with a remainder of 5 105 / 10 is 10 with a remainder of 5 it is also essential to remember that the a is a positive integer and multiple of 2 . any integer that is a multiple of 2 is an even number . so , a must be a positive even integer . with these two observations , the question can be simplified to : what is the units digit of 4 raised to an even positive integer ? the units digit of 4 raised to an integer follows a specific repeating pattern : 4 ^ 1 = 4 4 ^ 2 = 16 4 ^ 3 = 64 4 ^ 4 = 256 4 ^ ( odd number ) - - > units digit of 4 4 ^ ( even number ) - - > units digit of 6 there is a clear pattern regarding the units digit . 4 raised to any odd integer has a units digit of 4 while 4 raised to any even integer has a units digit of 6 . since a must be an even integer , the units digit of p = 4 ^ a will always be 6 . consequently , the remainder when p = 4 ^ a is divided by 10 will always be 6 . in case this is too theoretical , consider the following examples : a = 2 - - > p = 4 ^ a = 16 - - > p / 10 = 1 with a remainder of 6 a = 4 - - > p = 4 ^ a = 256 - - > p / 10 = 25 with a remainder of 6 a = 6 - - > p = 4 ^ a = 4096 - - > p / 10 = 409 with a remainder of 6 a = 8 - - > p = 4 ^ a = 65536 - - > p / 10 = 6553 with a remainder of 6 answer : b . | general |
math_qa__Nme7kN2uzlbFVt8m | Product of two natural numbers is 7. Then, the sum of reciprocals of their squares is Choose the correct choice from the following answers
A) 50 / 49 B) 1 / 289 C) 290 / 90 D) 290 / 19 E) none of these | <gadget id="calculator">1 / 1</gadget>
<output>1</output>
<gadget id="calculator">1 ** 2</gadget>
<output>1</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/7) ** 2</gadget>
<output>1/49 = around 0.020408</output>
<gadget id="calculator">1 + (1/49)</gadget>
<output>50/49 = around 1.020408</output>
<result>A</result> | A | 1.020408 | Product of two natural numbers is 7. Then, the sum of reciprocals of their squares is | {
"A": "50 / 49",
"B": "1 / 289",
"C": "290 / 90",
"D": "290 / 19",
"E": "none of these"
} | add(power(divide(const_1, const_1), const_2), power(divide(const_1, 7), const_2)) | divide(const_1,const_1)|divide(const_1,n0)|power(#0,const_2)|power(#1,const_2)|add(#2,#3)| | "explanation : if the numbers are a , b , then ab = 7 , as 17 is a prime number , so a = 1 , b = 7 . 1 / a 2 + 1 / b 2 = 1 / 1 ( 2 ) + 1 / 7 ( 2 ) = 50 / 49 option a" | general |
math_qa__AFUswSeRlAJTdjiX | A, Band C can do a piece of work in 11 days, 20 days and 67 days respectively, working alone. How soon can the work be done if A is assisted by Band C on alternate days? Select
A) 7.1 days
B) 8.1 days
C) 9.1 days
D) 10 days
E) 11 days | <gadget id="calculator">67 / 11</gadget>
<output>67/11 = around 6.090909</output>
<gadget id="calculator">67 / 20</gadget>
<output>67/20 = around 3.35</output>
<gadget id="calculator">(67/11) + (67/20)</gadget>
<output>2_077/220 = around 9.440909</output>
<gadget id="calculator">67 / 67</gadget>
<output>1</output>
<gadget id="calculator">(67/11) + 1</gadget>
<output>78/11 = around 7.090909</output>
<gadget id="calculator">(2_077/220) + (78/11)</gadget>
<output>3_637/220 = around 16.531818</output>
<gadget id="calculator">(3_637/220) / 2</gadget>
<output>3_637/440 = around 8.265909</output>
<gadget id="calculator">67 / (3_637/440)</gadget>
<output>29_480/3_637 = around 8.105582</output>
<result>B</result> | B | 8.1 | A, Band C can do a piece of work in 11 days, 20 days and 67 days respectively, working alone. How soon can the work be done if A is assisted by Band C on alternate days? | {
"A": "7.1 days",
"B": "8.1 days",
"C": "9.1 days",
"D": "10 days",
"E": "11 days"
} | divide(67, divide(add(add(divide(67, 11), divide(67, 20)), add(divide(67, 11), divide(67, 67))), const_2)) | divide(n2,n0)|divide(n2,n1)|divide(n2,n2)|add(#0,#1)|add(#0,#2)|add(#3,#4)|divide(#5,const_2)|divide(n2,#6)| | "( a + b ) ' s 1 day ' s work = 1 / 11 + 1 / 20 = 31 / 220 ( a + c ) ' s 1 day ' s work = 1 / 11 + 1 / 67 = 78 / 737 work done in 2 day ' s = 31 / 220 + 78 / 737 = 19 / 77 19 / 77 th work done in 2 days work done = 77 / 19 * 2 = 8.1 days answer : b" | physics |
math_qa__ulCpZJPNI3H7D4vS | A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 6, 4 and 3, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created? Choices
A) 20 B) 22 C) 26 D) 24 E) 30 | <gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">27 - 1</gadget>
<output>26</output>
<result>C</result> | C | 26 | A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 6, 4 and 3, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created? | {
"A": "20",
"B": "22",
"C": "26",
"D": "24",
"E": "30"
} | subtract(power(3, 3), const_1) | power(n0,n0)|subtract(#0,const_1)| | "total # of codes possible is 3 * 3 * 3 = 27 . oit of those 27 codes only the product of 333 and will be odd , the remaining 26 will have either 2 or 4 in them , which ensures that their product will be even . therefore the number of codes where the product of the digits is even = ( total ) - ( restriction ) = 27 - 1 = 26 . answer : c" | general |
math_qa__iRbaNkK44v66JIjr | Find the C.I. on a sum of Rs.10000 for 6 months at 25% per annum, interest being compounded quarterly? Select:
A) 10290
B) 5290
C) 1289
D) 1290
E) 2290 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / 4</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">1 + (1/16)</gadget>
<output>17/16 = around 1.0625</output>
<gadget id="calculator">(17/16) * (17/16)</gadget>
<output>289/256 = around 1.128906</output>
<gadget id="calculator">10_000 * (289/256)</gadget>
<output>180_625/16 = around 11_289.0625</output>
<gadget id="calculator">(180_625/16) - 10_000</gadget>
<output>20_625/16 = around 1_289.0625</output>
<result>C</result> | C | 1,289 | Find the C.I. on a sum of Rs.10000 for 6 months at 25% per annum, interest being compounded quarterly? | {
"A": "10290",
"B": "5290",
"C": "1289",
"D": "1290",
"E": "2290"
} | subtract(multiply(10000, multiply(add(const_1, divide(const_0_25, const_4)), add(const_1, divide(const_0_25, const_4)))), 10000) | divide(const_0_25,const_4)|add(#0,const_1)|multiply(#1,#1)|multiply(n0,#2)|subtract(#3,n0) | c . i . = 2000 ( 21 / 20 ) ^ 2 - 1800 = 1289 answer : c | gain |
math_qa__LpktLNUSKvXRIqbZ | You collect pens. Suppose you start out with 5. Mike gives you another 20 pens. Since her father makes pens, Cindy decides to double your pens. Since you're nice, you give Sharon 10 pens. How many pens do you have at the end? Choose one
A) 39 B) 40 C) 41 D) 42 E) 43 | <gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">50 - 10</gadget>
<output>40</output>
<result>B</result> | B | 40 | You collect pens. Suppose you start out with 5. Mike gives you another 20 pens. Since her father makes pens, Cindy decides to double your pens. Since you're nice, you give Sharon 10 pens. How many pens do you have at the end? | {
"A": "39",
"B": "40",
"C": "41",
"D": "42",
"E": "43"
} | subtract(multiply(add(20, 5), const_2), 10) | add(n0,n1)|multiply(#0,const_2)|subtract(#1,n2)| | "solution start with 5 pens . mike gives you 20 pens : 5 + 20 = 25 pens . cindy doubles the number of pens you have : 25 ã — 2 = 50 pens . sharon takes 10 pens from you : 50 - 10 = 40 pens . so you have 40 at the end . correct answer : b" | general |
math_qa__IRCfDp2RrrLRKSYh | A sum of money at simple interest amounts to Rs. 1560 in 4 years and to Rs. 1590 in 6 years. The sum is: Pick.
A) rs . 1400 B) rs . 1450 C) rs . 1500 D) rs . 1550 E) rs . 1525 | <gadget id="calculator">1_590 - 1_560</gadget>
<output>30</output>
<gadget id="calculator">30 * 4</gadget>
<output>120</output>
<gadget id="calculator">120 / 6</gadget>
<output>20</output>
<gadget id="calculator">1_560 - 20</gadget>
<output>1_540</output>
<result>C</result> | C | 1,500 | A sum of money at simple interest amounts to Rs. 1560 in 4 years and to Rs. 1590 in 6 years. The sum is: | {
"A": "rs . 1400",
"B": "rs . 1450",
"C": "rs . 1500",
"D": "rs . 1550",
"E": "rs . 1525"
} | subtract(1560, divide(multiply(subtract(1590, 1560), 4), 6)) | subtract(n2,n0)|multiply(n1,#0)|divide(#1,n3)|subtract(n0,#2)| | "s . i . for 2 years = rs . ( 1590 - 1560 ) = rs . 30 . s . i . for 4 years = rs . ( 30 x 2 ) = rs . 60 . principal = rs . ( 1560 - 60 ) = rs . 1500 . answer : option c" | gain |
math_qa__u7EvnoPeC1hpx2GC | A lady has fine gloves and hats in her closet - 18 blue, 32 red, and 25 yellow. The lights are out and it is totally dark. In spite of darkness, she can make out the difference between a hat and a glove. She takes out an item out of the closet only if she is sure that it is a glove. How many gloves must she take out to make sure she has a pair of each color? Choose the correct option:
A) 60
B) 65
C) 70
D) 75
E) 80 | <gadget id="calculator">25 + 32</gadget>
<output>57</output>
<gadget id="calculator">57 + 2</gadget>
<output>59</output>
<result>A</result> | A | 60 | A lady has fine gloves and hats in her closet - 18 blue, 32 red, and 25 yellow. The lights are out and it is totally dark. In spite of darkness, she can make out the difference between a hat and a glove. She takes out an item out of the closet only if she is sure that it is a glove. How many gloves must she take out to make sure she has a pair of each color? | {
"A": "60",
"B": "65",
"C": "70",
"D": "75",
"E": "80"
} | add(add(25, 32), const_2) | add(n1,n2)|add(#0,const_2)| | "32 r + 24 y + 1 y + 1 b + 2 b = 60 answer : a" | general |
math_qa__3tTyo9F1Mmj0eCkW | Of the total amount that Jill spent on a shopping trip, excluding taxes, she spent 40 percent on clothing, 30 percent on food, and 30 percent on other items. If Jill paid a 4 percent tax on the clothing, no tax on the food, and an 8 percent tax on all other items, then the total tax that she paid was what percent of the total amount that she spent, excluding taxes? Choose the most appropriate option:
A) 2.8 % B) 3.6 % C) 4 % D) 5.2 % E) 6.0 % | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">40 * (1/25)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">30 * (2/25)</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(8/5) + (12/5)</gadget>
<output>4</output>
<gadget id="calculator">(1/25) * 100</gadget>
<output>4</output>
<result>C</result> | C | 4 | Of the total amount that Jill spent on a shopping trip, excluding taxes, she spent 40 percent on clothing, 30 percent on food, and 30 percent on other items. If Jill paid a 4 percent tax on the clothing, no tax on the food, and an 8 percent tax on all other items, then the total tax that she paid was what percent of the total amount that she spent, excluding taxes? | {
"A": "2.8 %",
"B": "3.6 %",
"C": "4 %",
"D": "5.2 %",
"E": "6.0 %"
} | multiply(divide(add(multiply(40, divide(4, const_100)), multiply(30, divide(8, const_100))), const_100), const_100) | divide(n3,const_100)|divide(n4,const_100)|multiply(n0,#0)|multiply(n2,#1)|add(#2,#3)|divide(#4,const_100)|multiply(#5,const_100)| | "let amount spent by jill = 100 clothing = 40 , food = 30 , others = 30 tax on clothing = 1.6 tax on others = 2.4 percentage = 4 / 100 = 4 % answer : c" | general |
math_qa__L7zBlJHBEMay3GKr | A student chose a number, multiplied it by 5, then subtracted 138 from the result and got 102. What was the number he chose? Choose the most appropriate option
A) 48 B) 120 C) 130 D) 140 E) 150 | <gadget id="calculator">102 + 138</gadget>
<output>240</output>
<gadget id="calculator">240 / 5</gadget>
<output>48</output>
<result>A</result> | A | 48 | A student chose a number, multiplied it by 5, then subtracted 138 from the result and got 102. What was the number he chose? | {
"A": "48",
"B": "120",
"C": "130",
"D": "140",
"E": "150"
} | divide(add(102, 138), 5) | add(n1,n2)|divide(#0,n0)| | "solution : let xx be the number he chose , then 5 ⋅ x − 138 = 102 5 x = 240 x = 48 answer a" | general |
math_qa__At2AoMCyDya1pvjz | Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/8 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent? Choose the correct choice from the following answers: A) 11 / 30 B) 29 / 60 C) 17 / 24 D) 19 / 30 E) 11 / 15 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/3) * (1/2)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/6) + (1/8)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">1 - (7/24)</gadget>
<output>17/24 = around 0.708333</output>
<result>C</result> | C | 0.708333 | Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/8 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent? | {
"A": "11 / 30",
"B": "29 / 60",
"C": "17 / 24",
"D": "19 / 30",
"E": "11 / 15"
} | subtract(1, add(multiply(inverse(3), inverse(const_2)), inverse(8))) | inverse(n3)|inverse(n1)|inverse(const_2)|multiply(#1,#2)|add(#0,#3)|subtract(n0,#4) | let s assume the platinum card spending limit = x gold card spending limit will be = x / 2 balance on gold card is = x / 2 * 1 / 3 = x / 6 platinum card unspent limit is = x - 1 / 8 x = 7 / 8 x so if gold card balance is transferred then the rest unspent will be 7 / 8 x - x / 6 = 17 / 24 x so the ans is c | general |
math_qa__94wlrJGKPIh4ipWY | Robert spent $100 in buying raw materials, $125 in buying machinery and 10% of the total amount he had as cash with him. What was the total amount? Choose the correct answer.
A) $ 150 B) $ 210 C) $ 250 D) $ 160 E) $ 200 | <gadget id="calculator">125 + 125</gadget>
<output>250</output>
<result>C</result> | C | 250 | Robert spent $100 in buying raw materials, $125 in buying machinery and 10% of the total amount he had as cash with him. What was the total amount? | {
"A": "$ 150",
"B": "$ 210",
"C": "$ 250",
"D": "$ 160",
"E": "$ 200"
} | add(125, 125) | add(n1,n1) | let the total amount be x then , ( 100 - 10 ) % of x = 100 + 125 90 % of x = 225 90 x / 100 = 225 x = $ 250 answer is c | gain |
math_qa__KTiR6C3YwO8OdJwr | A 12% stock yields 8%.The market value of the stock is :
Choose the correct choice from the following options.
A) rs . 72 B) rs . 150 C) rs . 112.50 D) rs . 116.50 E) none of these | <gadget id="calculator">100 / 8</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 12</gadget>
<output>150</output>
<result>B</result> | B | 150 | A 12% stock yields 8%.The market value of the stock is : | {
"A": "rs . 72",
"B": "rs . 150",
"C": "rs . 112.50",
"D": "rs . 116.50",
"E": "none of these"
} | multiply(divide(const_100, 8), 12) | divide(const_100,n1)|multiply(n0,#0)| | "solution to obtain rs . 8 , investment = rs . 100 . to obtain rs . 12 , investment = rs . ( 100 / 8 x 12 ) = rs . 150 ∴ market value of rs . 100 stock = rs . 150 answer b" | gain |
math_qa__vE3aMIMfgXIwMDxv | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 5500. What is the share of B ? Choose the correct choice from the following answers:
A) 1000 B) 800 C) 1400 D) 1200 E) none of them | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 3</gadget>
<output>2</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<gadget id="calculator">2 / 11</gadget>
<output>2/11 = around 0.181818</output>
<gadget id="calculator">5_500 * (2/11)</gadget>
<output>1_000</output>
<result>A</result> | A | 1,000 | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 5500. What is the share of B ? | {
"A": "1000",
"B": "800",
"C": "1400",
"D": "1200",
"E": "none of them"
} | multiply(5500, divide(const_2, add(add(multiply(const_2, 3), multiply(divide(const_2, 3), 3)), 3))) | divide(const_2,n0)|multiply(const_2,n0)|multiply(#0,n0)|add(#1,#2)|add(#3,n0)|divide(const_2,#4)|multiply(n1,#5)| | "let c ' s capital = rs . x . then , b ' s capital = rs . ( 2 / 3 ) x a ’ s capital = rs . ( 3 x ( 2 / 3 ) . x ) = rs . 2 x . ratio of their capitals = 2 x : ( 2 / 3 ) x : x = 6 : 2 : 3 . hence , b ' s share = rs . ( 5500 x ( 2 / 11 ) ) = rs . 1000 . answer is a" | gain |
math_qa__CLKicEEqXNz8wrM2 | If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {14} + {12}? Choose the correct choice from the following answers:
A) 23
B) 20
C) 15
D) 5
E) 2 | <gadget id="calculator">14 + 12</gadget>
<output>26</output>
<gadget id="calculator">26 / 2</gadget>
<output>13</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">13 + 2</gadget>
<output>15</output>
<result>C</result> | C | 15 | If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {14} + {12}? | {
"A": "23",
"B": "20",
"C": "15",
"D": "5",
"E": "2"
} | add(divide(add(14, 12), const_2), multiply(1, const_2)) | add(n1,n2)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "soln : { 14 } + { 12 } = 14 * { 12 } + { 12 } = 15 * { 12 } answer : c" | general |
math_qa__joomC77XcV95G8fM | If x + (1/x) = 5, what is the value of W= x^2 + (1/x)^2?
Choose one:
A) w = 21 B) w = 22 C) w = 23 D) w = 24 E) 27 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 2</gadget>
<output>23</output>
<result>C</result> | C | 23 | If x + (1/x) = 5, what is the value of W= x^2 + (1/x)^2? | {
"A": "w = 21",
"B": "w = 22",
"C": "w = 23",
"D": "w = 24",
"E": "27"
} | subtract(power(5, 2), 2) | power(n1,n2)|subtract(#0,n2)| | "squaring on both sides , x ^ 2 + ( 1 / x ) ^ 2 + 2 ( x ) ( 1 / x ) = 5 ^ 2 x ^ 2 + ( 1 / x ) ^ 2 = 23 answer : c" | general |
math_qa__4bMNXy4Zaienwm9n | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 7 m, the volume of the box (in m3) is:
Pick.
A) 4830 B) 5236 C) 6420 D) 8960 E) 7960 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">48 - 14</gadget>
<output>34</output>
<gadget id="calculator">36 - 14</gadget>
<output>22</output>
<gadget id="calculator">34 * 22 * 7</gadget>
<output>5_236</output>
<result>B</result> | B | 5,236 | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 7 m, the volume of the box (in m3) is: | {
"A": "4830",
"B": "5236",
"C": "6420",
"D": "8960",
"E": "7960"
} | volume_rectangular_prism(subtract(48, multiply(7, const_2)), subtract(36, multiply(7, const_2)), 7) | multiply(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|volume_rectangular_prism(n2,#1,#2)| | "clearly , l = ( 48 - 14 ) m = 34 m , b = ( 36 - 14 ) m = 22 m , h = 8 m . volume of the box = ( 34 x 22 x 7 ) m 3 = 5236 m 3 . answer : option b" | geometry |
math_qa__NkvQFYqOuU0t9Q6l | If the price of a certain computer increased 30 percent from d dollars to 351 dollars, then 2d = Choose the correct choice:
A) 540
B) 570
C) 619
D) 649
E) 700 | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 / 100</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">351 / (13/10)</gadget>
<output>270</output>
<gadget id="calculator">270 * 2</gadget>
<output>540</output>
<result>A</result> | A | 540 | If the price of a certain computer increased 30 percent from d dollars to 351 dollars, then 2d = | {
"A": "540",
"B": "570",
"C": "619",
"D": "649",
"E": "700"
} | multiply(divide(351, divide(add(const_100, 30), const_100)), 2) | add(n0,const_100)|divide(#0,const_100)|divide(n1,#1)|multiply(n2,#2)| | "before price increase price = d after 30 % price increase price = d + ( 30 / 100 ) * d = 1.3 d = 351 ( given ) i . e . d = 351 / 1.3 = $ 270 i . e . 2 d = 2 * 270 = 540 answer : option a" | general |
math_qa__wGPyCbmLci2iHPRG | A certain bag contains 60 balls — 22 white, 18 green, 17 yellow, 3 red, and 1 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple? Choose one:
A) 0.09 B) 0.15 C) 0.54 D) 0.85 E) 0.95 | <gadget id="calculator">22 + 18</gadget>
<output>40</output>
<gadget id="calculator">40 + 17</gadget>
<output>57</output>
<gadget id="calculator">57 / 60</gadget>
<output>19/20 = around 0.95</output>
<result>E</result> | E | 0.95 | A certain bag contains 60 balls — 22 white, 18 green, 17 yellow, 3 red, and 1 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple? | {
"A": "0.09",
"B": "0.15",
"C": "0.54",
"D": "0.85",
"E": "0.95"
} | divide(add(add(22, 18), 17), 60) | add(n1,n2)|add(n3,#0)|divide(#1,n0)| | "according to the stem the ball can be white , green or yellow , so the probability is ( white + green + yellow ) / ( total ) = ( 22 + 18 + 17 ) / 60 = 57 / 60 = 0.95 . answer : e ." | other |
math_qa__SUiu6As4LQ5grO0j | Find the cost of fencing around a circular field of diameter 36 m at the rate of Rs.3.50 a meter?
Choose the most appropriate option
A) 438
B) 395
C) 378
D) 279
E) 222 | <gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">2 * pi * 18</gadget>
<output>36*pi = around 113.097336</output>
<gadget id="calculator">(36*pi) * 3.5</gadget>
<output>126.0*pi = around 395.840674</output>
<result>B</result> | B | 395 | Find the cost of fencing around a circular field of diameter 36 m at the rate of Rs.3.50 a meter? | {
"A": "438",
"B": "395",
"C": "378",
"D": "279",
"E": "222"
} | multiply(circumface(divide(36, const_2)), 3.50) | divide(n0,const_2)|circumface(#0)|multiply(n1,#1)| | "2 * 22 / 7 * 18 = 113 113 * 3 1 / 2 = rs . 395 answer : b" | physics |
math_qa__aXksZHjXXjWuYElm | A number when divided by 342 gives a remainder 47. When the same number ift divided by 19, what would be the remainder ? Answers
A) 7 B) 8 C) 9 D) 21 E) 14 | <gadget id="calculator">19 * 2</gadget>
<output>38</output>
<gadget id="calculator">47 - 38</gadget>
<output>9</output>
<result>C</result> | C | 9 | A number when divided by 342 gives a remainder 47. When the same number ift divided by 19, what would be the remainder ? | {
"A": "7",
"B": "8",
"C": "9",
"D": "21",
"E": "14"
} | subtract(47, multiply(19, const_2)) | multiply(n2,const_2)|subtract(n1,#0)| | "sol . on dividing the given number by 342 , let k be the quotient and 47 as remainder . then , number – 342 k + 47 = ( 19 x 18 k + 19 x 2 + 9 ) = 19 ( 18 k + 2 ) + 9 . the given number when divided by 19 , gives ( 18 k + 2 ) as quotient and 9 as remainder . option c" | general |
math_qa__JBgyf94viORJyMQx | Two integers are in the ratio of 1 to 4. If 12 is added to the smaller number, the ratio becomes 1 to 1. Find the larger integer. Choose the correct choice from the following answers.
A) 8 B) 16 C) 32 D) 48 E) 54 | <gadget id="calculator">1 * 12</gadget>
<output>12</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<result>B</result> | B | 16 | Two integers are in the ratio of 1 to 4. If 12 is added to the smaller number, the ratio becomes 1 to 1. Find the larger integer. | {
"A": "8",
"B": "16",
"C": "32",
"D": "48",
"E": "54"
} | multiply(divide(multiply(1, 12), subtract(4, 1)), 4) | multiply(n2,n4)|subtract(n1,n4)|divide(#0,#1)|multiply(n1,#2)| | "one option is to set up the equations and solve : if the ratio of two integers x and y is 1 to 4 , then 4 x = y , where x is the smaller integer . if adding 12 to the smaller integer makes the ratio 1 to 1 , then x + 12 = y . substituting y = 4 x into the second equation yields x + 12 = 4 x . so , x = 4 ( smaller integer ) and , y = 4 x = 16 ( larger integer ) so b is the correct answer . another option is to test the answer choices . a ) the larger number is 8 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 2 if 12 is added to the smaller number , the ratio becomes 1 to 1 if we add 12 to the smaller number ( 2 ) , we get 14 . so , the new ratio is 14 to 8 which is the same as 7 to 4 . no good . we want a resulting ratio of 1 to 1 eliminate a b ) the larger number is 16 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 4 if 12 is added to the smaller number , the ratio becomes 1 to 1 if we add 12 to the smaller number ( 4 ) , we get 16 so , the new ratio is 16 to 16 which is 1 to 1 . therefore ( b ) is correct . c ) the larger number is 32 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 8 if 12 is added to the smaller number , the ratio becomes 1 to 1 if we add 12 to the smaller number ( 8 ) , we get 20 so , the new ratio is 20 to 32 which is 5 to 8 . no good . we want a resulting ratio of 1 to 1 eliminate c d ) the larger number is 48 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 12 if 12 is added to the smaller number , the ratio becomes 1 to 1 if we add 12 to the smaller number ( 12 ) , we get 24 so , the new ratio is 24 to 48 . this is the same as the ratio of 1 to 2 no good . we want a resulting ratio of 1 to 1 eliminate d e ) the larger number is 54 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 13.5 ( which is not an integer ) since both numbers are integers , the larger number can not be 54 . eliminate e therefore b is the only correct choice ." | other |
math_qa__kBjqrtSLSYxeXBnt | The salaries of A and B together amount to $4000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary? Choose the correct option: A) $ 1000 B) $ 1250 C) $ 2500 D) $ 3000 E) $ 1200 | <gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">100 - 95</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4_000 / 4</gadget>
<output>1_000</output>
<gadget id="calculator">4_000 - 1_000</gadget>
<output>3_000</output>
<result>D</result> | D | 3,000 | The salaries of A and B together amount to $4000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary? | {
"A": "$ 1000",
"B": "$ 1250",
"C": "$ 2500",
"D": "$ 3000",
"E": "$ 1200"
} | subtract(4000, divide(4000, add(divide(subtract(const_100, 85), subtract(const_100, 95)), const_1))) | subtract(const_100,n2)|subtract(const_100,n1)|divide(#0,#1)|add(#2,const_1)|divide(n0,#3)|subtract(n0,#4) | let a ' s salary is x b ' s salary = 4000 - x ( 100 - 95 ) % of x = ( 100 - 85 ) % of ( 4000 - x ) x = $ 3000 answer is d | gain |
math_qa__WjPoNEkCEcVDybyP | 1/2+[(2/3*3/8)+4]-8/16=
Choose the correct option:
A) 29 / 16 B) 19 / 16 C) 15 / 16 D) 17 / 4 E) 0 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(2/3) * (3/8)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 4</gadget>
<output>17/4 = around 4.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(17/4) + (1/2)</gadget>
<output>19/4 = around 4.75</output>
<gadget id="calculator">8 / 16</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(19/4) - (1/2)</gadget>
<output>17/4 = around 4.25</output>
<result>D</result> | D | 4.25 | 1/2+[(2/3*3/8)+4]-8/16= | {
"A": "29 / 16",
"B": "19 / 16",
"C": "15 / 16",
"D": "17 / 4",
"E": "0"
} | subtract(add(add(multiply(divide(2, 3), divide(3, 8)), 4), divide(1, 2)), divide(8, 16)) | divide(n1,n3)|divide(n3,n5)|divide(n0,n1)|divide(n5,n8)|multiply(#0,#1)|add(n6,#4)|add(#5,#2)|subtract(#6,#3) | 1 / 2 + [ ( 2 / 3 * 3 / 8 ) + 4 ] - 8 / 16 = 1 / 2 + [ ( 1 / 4 ) + 4 ] - 8 / 16 = 1 / 2 + [ 17 / 4 ] - 9 / 16 = 8 / 16 + 68 / 16 - 8 / 16 = 68 / 16 = 17 / 4 d | general |
math_qa__dUBLft0EZ6TDQMQr | Michelle deposited a certain sum of money in a savings account on July 1st, 2007. She earns an 6% interest compounded semiannually. The sum of money in the account on December 31st, 2009 is approximately what percent of the initial deposit? Choose the most appropriate option: A) 117 % B) 120 % C) 121 % D) 135 % E) 140 % | <gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) / 2</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">1 + (3/100)</gadget>
<output>103/100 = around 1.03</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">(103/100) ** 5</gadget>
<output>11_592_740_743/10_000_000_000 = around 1.159274</output>
<gadget id="calculator">(11_592_740_743/10_000_000_000) * 100</gadget>
<output>11_592_740_743/100_000_000 = around 115.927407</output>
<result>A</result> | A | 117 | Michelle deposited a certain sum of money in a savings account on July 1st, 2007. She earns an 6% interest compounded semiannually. The sum of money in the account on December 31st, 2009 is approximately what percent of the initial deposit? | {
"A": "117 %",
"B": "120 %",
"C": "121 %",
"D": "135 %",
"E": "140 %"
} | multiply(power(add(1, divide(divide(6, const_100), const_2)), add(const_2, const_3)), const_100) | add(const_2,const_3)|divide(n2,const_100)|divide(#1,const_2)|add(#2,n0)|power(#3,#0)|multiply(#4,const_100)| | "since michelle earns 6 % interest compounded semiannually , then she earns 3 % interest every 6 months . now , the simple interest earned in 5 periods ( 30 months = 5 * 6 months ) would be 3 % * 5 = 15 % . but , since the interest iscompoundedevery 6 months , then there would be interest earned on interest ( very small amount ) thus the actual interest earned would be a little bit more than 15 % , only answer choice a fits . answer : a" | gain |
math_qa__IwGcgiXmbhoUBKfy | A company producing fruit juice changed its packaging from boxes measuring 5 x 10 x 20 centimeters to boxes measuring 6 x 10 x 20 centimeters. If the price of a box did not change and all boxes are full of juice, by approximately what percent did the price of the juice decrease? Select.
A) 12.00 % B) 16.67 % C) 18.33 % D) 20.00 % E) 21.50 % | <gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">50 * 20</gadget>
<output>1_000</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">60 * 20</gadget>
<output>1_200</output>
<gadget id="calculator">1_000 / 1_200</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">1 - (5/6)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 100</gadget>
<output>50/3 = around 16.666667</output>
<result>B</result> | B | 16.67 | A company producing fruit juice changed its packaging from boxes measuring 5 x 10 x 20 centimeters to boxes measuring 6 x 10 x 20 centimeters. If the price of a box did not change and all boxes are full of juice, by approximately what percent did the price of the juice decrease? | {
"A": "12.00 %",
"B": "16.67 %",
"C": "18.33 %",
"D": "20.00 %",
"E": "21.50 %"
} | multiply(subtract(const_1, divide(multiply(multiply(5, 10), 20), multiply(multiply(6, 10), 20))), const_100) | multiply(n0,n1)|multiply(n1,n3)|multiply(n2,#0)|multiply(n2,#1)|divide(#2,#3)|subtract(const_1,#4)|multiply(#5,const_100) | suppose when v = 5 x 10 x 20 = 1000 cm , the price is $ 1200 per cm price = $ 1.2 the price is $ 1200 if v = 6 x 10 x 20 = 1000 cm . per cm price = $ 1.0 so the price is decreased by $ 0.2 so the % price decreased by $ 0.2 / 1.20 = 16.67 % answer : b | general |
math_qa__T6TiH3ZdoiJBQHcO | A man can row 4.2 km/hr in still water. It takes him twice as long to row upstream as to row downstream. What is the rate of the current ? Choose the correct choice from the following: A) 1.9 B) 1.7 C) 1.4 D) 1.5 E) 1.1 | <gadget id="calculator">4.2 * 2</gadget>
<output>8.4</output>
<gadget id="calculator">8.4 - 4.2</gadget>
<output>4.2</output>
<gadget id="calculator">4.2 / 3</gadget>
<output>1.4</output>
<result>C</result> | C | 1.4 | A man can row 4.2 km/hr in still water. It takes him twice as long to row upstream as to row downstream. What is the rate of the current ? | {
"A": "1.9",
"B": "1.7",
"C": "1.4",
"D": "1.5",
"E": "1.1"
} | divide(subtract(multiply(4.2, const_2), 4.2), const_3) | multiply(n0,const_2)|subtract(#0,n0)|divide(#1,const_3)| | "speed of boat in still water ( b ) = 4.2 km / hr . speed of boat with stream ( down stream ) , d = b + u speed of boat against stream ( up stream ) , u = b – u it is given upstream time is twice to that of down stream . ⇒ downstream speed is twice to that of upstream . so b + u = 2 ( b – u ) ⇒ u = b / 3 = 1.4 km / hr . answer : c" | general |
math_qa__nbSb9c9zFk0TdJFL | divide rs . 116000 among 3 persons a , b and c such that the ratio of the shares of a and b is 3 : 4 and that of b : c is 5 : 6 . find the share of a ?
Answers
A) 29491
B) 28491
C) 39491
D) 49491
E) 59491 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">15 + 20</gadget>
<output>35</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">35 + 24</gadget>
<output>59</output>
<gadget id="calculator">15 / 59</gadget>
<output>15/59 = around 0.254237</output>
<gadget id="calculator">116_000 * (15/59)</gadget>
<output>1_740_000/59 = around 29_491.525424</output>
<result>A</result> | A | 29,491 | divide rs . 116000 among 3 persons a , b and c such that the ratio of the shares of a and b is 3 : 4 and that of b : c is 5 : 6 . find the share of a ? | {
"A": "29491",
"B": "28491",
"C": "39491",
"D": "49491",
"E": "59491"
} | multiply(116000, divide(multiply(3, 5), add(add(multiply(3, 5), multiply(4, 5)), multiply(4, 6)))) | multiply(n1,n4)|multiply(n3,n4)|multiply(n3,n5)|add(#0,#1)|add(#3,#2)|divide(#0,#4)|multiply(n0,#5) | compound ratio of a : b : c a : b = 3 : 4 b : c = 5 : 6 - - - - - - - - - - a : b : c = 15 : 20 : 24 we can divide rs . 116000 in this ratio . share of a = 15 / 59 * 116000 = 29491 answer : a | other |
math_qa__wcuAVUcnfmSCBV6h | The diagonal of a rhombus are 40 m and 30 m. Its area is: Options.
A) 600 B) 450 C) 350 D) 500 E) 620 | <gadget id="calculator">(40 * 30) / 2</gadget>
<output>600</output>
<result>A</result> | A | 600 | The diagonal of a rhombus are 40 m and 30 m. Its area is: | {
"A": "600",
"B": "450",
"C": "350",
"D": "500",
"E": "620"
} | rhombus_area(40, 30) | rhombus_area(n0,n1) | area of the rhombus = 1 / 2 d 1 d 2 = ( 1 / 2 ã — 40 ã — 30 ) cm ( power ) 2 = 40 ã — 15 = 600 cm ( power ) 2 answer is a . | geometry |
math_qa__vBZYDjGVVIu7sGyd | In a park there are two ponds with both brown ducks and green ducks. In the smaller pond there are 20 ducks and in the larger pond there are 80 ducks. If 20% of the ducks in the smaller pond are green and 15% of the ducks in the larger pond are green, then what percentage of ducks are green?
Choose the correct choice from the following:
A) 13 %
B) 14 %
C) 15 %
D) 16 %
E) 17 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">20 * (1/5)</gadget>
<output>4</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">80 * (3/20)</gadget>
<output>12</output>
<gadget id="calculator">4 + 12</gadget>
<output>16</output>
<gadget id="calculator">20 + 80</gadget>
<output>100</output>
<gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * 100</gadget>
<output>16</output>
<result>D</result> | D | 16 | In a park there are two ponds with both brown ducks and green ducks. In the smaller pond there are 20 ducks and in the larger pond there are 80 ducks. If 20% of the ducks in the smaller pond are green and 15% of the ducks in the larger pond are green, then what percentage of ducks are green? | {
"A": "13 %",
"B": "14 %",
"C": "15 %",
"D": "16 %",
"E": "17 %"
} | multiply(divide(add(multiply(20, divide(20, const_100)), multiply(80, divide(15, const_100))), add(20, 80)), const_100) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100)| | "number of ducks in small pond = 20 green ducks in small pond = 20 % of 20 = 4 ducks number of ducks in large pond = 80 green ducks in large pond = 15 % of 80 = 12 ducks total number of ducks = 20 + 80 = 100 total number of green ducks = 4 + 12 = 16 ducks percentage of green ducks = 16 / 100 * 100 = 16 % answer : d" | gain |
math_qa__apaohfZxq3WIQqFW | If two projectiles are launched at the same moment from 1386 km apart and travel directly towards each other at 445 km per hour and 545 km per hour respectively, how many minutes will it take for them to meet? Choose one:
A) 80 B) 82 C) 84 D) 86 E) 88 | <gadget id="calculator">445 + 545</gadget>
<output>990</output>
<gadget id="calculator">1_386 / 990</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) * 60</gadget>
<output>84</output>
<result>C</result> | C | 84 | If two projectiles are launched at the same moment from 1386 km apart and travel directly towards each other at 445 km per hour and 545 km per hour respectively, how many minutes will it take for them to meet? | {
"A": "80",
"B": "82",
"C": "84",
"D": "86",
"E": "88"
} | multiply(divide(1386, add(445, 545)), const_60) | add(n1,n2)|divide(n0,#0)|multiply(#1,const_60)| | "the projectiles travel a total of 990 km per hour . the time to meet is 1386 / 990 = 1.4 hours = 84 minutes the answer is c ." | physics |
math_qa__xxmc3N1zDvWHN2zv | Find the average of all the numbers between 11 and 21 which are divisible by 2. Pick:
A) 15
B) 18
C) 16
D) 22
E) none | <gadget id="calculator">11 + 4</gadget>
<output>15</output>
<gadget id="calculator">21 - 4</gadget>
<output>17</output>
<gadget id="calculator">15 + 17</gadget>
<output>32</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<result>C</result> | C | 16 | Find the average of all the numbers between 11 and 21 which are divisible by 2. | {
"A": "15",
"B": "18",
"C": "16",
"D": "22",
"E": "none"
} | divide(add(add(11, const_4), subtract(21, const_4)), const_2) | add(n0,const_4)|subtract(n1,const_4)|add(#0,#1)|divide(#2,const_2)| | "sol . average = ( 12 + 14 + 16 + 18 + 20 / 5 ) = 80 / 5 = 16 . answer c" | general |
math_qa__snUDid9C4QIZa57T | A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock? Choose the correct choice from the following options: A) rs . 25000 B) rs . 20000 C) rs . 15000 D) rs . 22000 E) none of these | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(1/20) * (4/5)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/10) * (1/5)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/25) - (1/50)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">400 / (1/50)</gadget>
<output>20_000</output>
<result>B</result> | B | 20,000 | A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock? | {
"A": "rs . 25000",
"B": "rs . 20000",
"C": "rs . 15000",
"D": "rs . 22000",
"E": "none of these"
} | divide(400, subtract(multiply(divide(5, const_100), divide(subtract(const_100, 20), const_100)), multiply(divide(10, const_100), divide(20, const_100)))) | divide(n2,const_100)|divide(n1,const_100)|divide(n0,const_100)|subtract(const_100,n0)|divide(#3,const_100)|multiply(#1,#2)|multiply(#0,#4)|subtract(#6,#5)|divide(n3,#7) | let the total worth of the stock be rs . x . the sp of 20 % of the stock = 1 / 5 * x * 1.1 = 11 x / 50 the sp of 80 % of the stock = 4 / 5 * x * 0.95 = 19 x / 25 = 38 x / 50 total sp = 11 x / 50 + 38 x / 50 = 49 x / 50 overall loss = x - 49 x / 50 = x / 50 x / 50 = 400 = > x = 20000 answer : b | gain |
math_qa__evstf9oKUCwvpX0F | The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 12 times the probability that both events A and B occur. What is the probability that event A occurs? Pick:
A) 21 / 26
B) 25 / 26
C) 11 / 26
D) 6 / 26
E) 22 / 33 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 2</gadget>
<output>26</output>
<gadget id="calculator">3 / 26</gadget>
<output>3/26 = around 0.115385</output>
<gadget id="calculator">(3/26) * 2</gadget>
<output>3/13 = around 0.230769</output>
<result>D</result> | D | 0.230769 | The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 12 times the probability that both events A and B occur. What is the probability that event A occurs? | {
"A": "21 / 26",
"B": "25 / 26",
"C": "11 / 26",
"D": "6 / 26",
"E": "22 / 33"
} | multiply(divide(add(const_2, const_1), add(multiply(12, const_2), const_2)), const_2) | add(const_1,const_2)|multiply(n1,const_2)|add(#1,const_2)|divide(#0,#2)|multiply(#3,const_2)| | "let us say probability of a occuring is a . let us say probability of b occuring is b . a = 2 b probability ( either a or b or both ) = 12 times probability ( a and b ) a * ( 1 - b ) + b * ( 1 - a ) + ab = 12 * ab substituting a = 2 b in the second equation : 2 b * ( 1 - b ) + b * ( 1 - 2 b ) + 2 b * b = 12 * 2 b * b 3 b - 2 b ^ 2 = 24 b ^ 2 3 b = 26 b ^ 2 b = 3 / 26 = 3 / 26 so , a = 2 b = 6 / 26 the correct answer is d ." | general |
math_qa__NiA8t4ys5XzxmbNS | A snooker tournament charges $40.00 for VIP seats and $15.00 for general admission (“regular” seats). On a certain night, a total of 320 tickets were sold, for a total cost of $7,500. How many fewer tickets were sold that night for VIP seats than for general admission seats? Options
A) 212 B) 200 C) 220 D) 230 E) 240 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 1_000</gadget>
<output>7_000</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">7_000 + 500</gadget>
<output>7_500</output>
<gadget id="calculator">320 * 15</gadget>
<output>4_800</output>
<gadget id="calculator">7_500 - 4_800</gadget>
<output>2_700</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">2_700 / 25</gadget>
<output>108</output>
<gadget id="calculator">320 - 108</gadget>
<output>212</output>
<result>A</result> | A | 212 | A snooker tournament charges $40.00 for VIP seats and $15.00 for general admission (“regular” seats). On a certain night, a total of 320 tickets were sold, for a total cost of $7,500. How many fewer tickets were sold that night for VIP seats than for general admission seats? | {
"A": "212",
"B": "200",
"C": "220",
"D": "230",
"E": "240"
} | subtract(320, divide(subtract(add(multiply(add(const_3, const_4), const_1000), multiply(add(const_2, const_3), const_100)), multiply(320, 15.00)), multiply(add(const_2, const_3), add(const_2, const_3)))) | add(const_3,const_4)|add(const_2,const_3)|multiply(n1,n2)|multiply(#0,const_1000)|multiply(#1,const_100)|multiply(#1,#1)|add(#3,#4)|subtract(#6,#2)|divide(#7,#5)|subtract(n2,#8)| | "let no of sits in vip enclosure is x then x * 40 + 15 ( 320 - x ) = 7500 or 25 x = 7500 - 4800 , x = 2700 / 25 = 108 vip = 108 general 212 a" | geometry |
math_qa__SbvhdfwHsZ6QUtx2 | A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money R did Bob receive? Choices.
A) 20 B) 22 C) 24 D) 26 E) 52 | <gadget id="calculator">32 * 2</gadget>
<output>64</output>
<gadget id="calculator">64 / 3</gadget>
<output>64/3 = around 21.333333</output>
<result>B</result> | B | 22 | A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money R did Bob receive? | {
"A": "20",
"B": "22",
"C": "24",
"D": "26",
"E": "52"
} | divide(multiply(32, const_2), const_3) | multiply(n2,const_2)|divide(#0,const_3)| | "notice that we need not consider ann ' s portion in the solution . we can just let k = the money remaining after ann has received her portion and go from there . our equation will use the fact that , once we remove bob ' s portion , we have $ 32 for chloe . so , we getk - bob ' s $ = 32 bob received 4 dollars plus one - third of what remained once bob receives $ 4 , the amount remaining is k - 4 dollars . so , bob gets a 1 / 3 of that as well . 1 / 3 of k - 4 is ( k - 4 ) / 3 so altogether , bob receives 4 + ( k - 4 ) / 3 so , our equation becomes : k - [ 4 + ( k - 4 ) / 3 ] = 32 simplify to get : k - 4 - ( k - 4 ) / 3 = 32 multiply both sides by 3 to get : 3 k - 12 - k + 4 = 96 simplify : 2 k - 8 = 96 solve : k = 52 plug this k - value intok - bob ' s $ = 32 to get : 52 - bob ' s $ = 32 so , bob ' s $ r = 20 answer : b" | general |
math_qa__3wS1gQdfknxL6ma4 | Calculate the time it will take for a full tank to become completely empty due to a leak given that
the tank could be filled in 7 hours, but due to the leak in its bottom it takes 8 hours to be filled ? Choices.
A) 59 hours
B) 54 hours
C) 59 hours
D) 56 hours
E) 26 hours | <gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/7) - (1/8)</gadget>
<output>1/56 = around 0.017857</output>
<gadget id="calculator">1 / (1/56)</gadget>
<output>56</output>
<result>D</result> | D | 56 | Calculate the time it will take for a full tank to become completely empty due to a leak given that
the tank could be filled in 7 hours, but due to the leak in its bottom it takes 8 hours to be filled ? | {
"A": "59 hours",
"B": "54 hours",
"C": "59 hours",
"D": "56 hours",
"E": "26 hours"
} | inverse(subtract(divide(const_1, 7), divide(const_1, 8))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|inverse(#2) | part filled without leak in 1 hour = 1 / 7 part filled with leak in 1 hour = 1 / 8 work done by leak in 1 hour = 1 / 7 â ˆ ’ 1 / 8 = 56 hours answer : d | physics |
math_qa__aPtkj4ajGv6Q3RoA | A is 2 times as fast as B. A alone can do the work in 20 days. If A and B working together in how many days will the work be completed? Answers.
A) 23 B) 13 C) 21 D) 24 E) 25 | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) / 2</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(1/20) + (1/40)</gadget>
<output>3/40 = around 0.075</output>
<gadget id="calculator">1 / (3/40)</gadget>
<output>40/3 = around 13.333333</output>
<result>B</result> | B | 13 | A is 2 times as fast as B. A alone can do the work in 20 days. If A and B working together in how many days will the work be completed? | {
"A": "23",
"B": "13",
"C": "21",
"D": "24",
"E": "25"
} | divide(const_1, add(divide(const_1, 20), divide(divide(const_1, 20), 2))) | divide(const_1,n1)|divide(#0,n0)|add(#0,#1)|divide(const_1,#2)| | "a can finish 1 work in 20 days b can finish 1 / 2 work in 20 days - since a is 2 faster than b this means b can finish 1 work in 20 * 2 days = 40 days now using the awesome gmat formula when two machines work together they can finish the job in = ab / ( a + b ) = 20 * 40 / ( 20 + 40 ) = 13 days so answer is b" | physics |
math_qa__Sbb263S83P8AQd1k | A train leaves Mumabai at 9 am at a speed of 30 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 60 kmph. When and at what distance from Mumbai do the two trains meet? Select the correct option
A) 27 B) 279 C) 60 D) 278 E) 379 | <gadget id="calculator">30 * 1</gadget>
<output>30</output>
<gadget id="calculator">60 - 30</gadget>
<output>30</output>
<gadget id="calculator">30 / 30</gadget>
<output>1</output>
<gadget id="calculator">1 * 60</gadget>
<output>60</output>
<result>C</result> | C | 60 | A train leaves Mumabai at 9 am at a speed of 30 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 60 kmph. When and at what distance from Mumbai do the two trains meet? | {
"A": "27",
"B": "279",
"C": "60",
"D": "278",
"E": "379"
} | multiply(divide(multiply(30, const_1), subtract(60, 30)), 60) | multiply(n1,const_1)|subtract(n2,n1)|divide(#0,#1)|multiply(n2,#2) | when the second train leaves mumbai the first train covers 30 * 1 = 30 km so , the distance between first train and second train is 30 km at 10.00 am time taken by the trains to meet = distance / relative speed = 30 / ( 60 - 30 ) = 1 hours so , the two trains meet at 11 a . m . the two trains meet 1 * 60 = 60 km away from mumbai . answer : c | physics |
math_qa__WQZFdivIAoo3zXOH | A envelop weight 8.5 gm,if 800 of these envelop are sent with an advertisement mail. How much wieght?
Pick one:
A) 6.6 kg
B) 6.8 kg
C) 6.7 kg
D) 6.9 kg
E) 7.8 kg | <gadget id="calculator">8.5 * 800</gadget>
<output>6_800</output>
<gadget id="calculator">6_800 / 1_000</gadget>
<output>34/5 = around 6.8</output>
<result>B</result> | B | 6.8 | A envelop weight 8.5 gm,if 800 of these envelop are sent with an advertisement mail. How much wieght? | {
"A": "6.6 kg",
"B": "6.8 kg",
"C": "6.7 kg",
"D": "6.9 kg",
"E": "7.8 kg"
} | divide(multiply(8.5, 800), const_1000) | multiply(n0,n1)|divide(#0,const_1000)| | "800 * 8.5 6800.0 gm 6.8 kg answer : b" | general |
math_qa__U5TCrJOu0NAxf2Mq | In a City, 35% of the population is composed of migrants, 20% of whom are from rural areas. Of the local population, 48% is female while this figure for rural and urban migrants is 30% and 40% respectively. If the total population of the city is 728400, what is its female population ?
Choices: A) 324138 B) 248888 C) 378908 D) 277880 E) 379010 | <gadget id="calculator">728_400 * 35</gadget>
<output>25_494_000</output>
<gadget id="calculator">25_494_000 / 100</gadget>
<output>254_940</output>
<gadget id="calculator">728_400 - 254_940</gadget>
<output>473_460</output>
<gadget id="calculator">48 * 473_460</gadget>
<output>22_726_080</output>
<gadget id="calculator">22_726_080 / 100</gadget>
<output>1_136_304/5 = around 227_260.8</output>
<gadget id="calculator">254_940 * 20</gadget>
<output>5_098_800</output>
<gadget id="calculator">5_098_800 / 100</gadget>
<output>50_988</output>
<gadget id="calculator">30 * 50_988</gadget>
<output>1_529_640</output>
<gadget id="calculator">1_529_640 / 100</gadget>
<output>76_482/5 = around 15_296.4</output>
<gadget id="calculator">(1_136_304/5) + (76_482/5)</gadget>
<output>1_212_786/5 = around 242_557.2</output>
<gadget id="calculator">254_940 - 50_988</gadget>
<output>203_952</output>
<gadget id="calculator">40 * 203_952</gadget>
<output>8_158_080</output>
<gadget id="calculator">8_158_080 / 100</gadget>
<output>407_904/5 = around 81_580.8</output>
<gadget id="calculator">(1_212_786/5) + (407_904/5)</gadget>
<output>324_138</output>
<result>A</result> | A | 324,138 | In a City, 35% of the population is composed of migrants, 20% of whom are from rural areas. Of the local population, 48% is female while this figure for rural and urban migrants is 30% and 40% respectively. If the total population of the city is 728400, what is its female population ? | {
"A": "324138",
"B": "248888",
"C": "378908",
"D": "277880",
"E": "379010"
} | add(add(divide(multiply(48, subtract(728400, divide(multiply(728400, 35), const_100))), const_100), divide(multiply(30, divide(multiply(divide(multiply(728400, 35), const_100), 20), const_100)), const_100)), divide(multiply(40, subtract(divide(multiply(728400, 35), const_100), divide(multiply(divide(multiply(728400, 35), const_100), 20), const_100))), const_100)) | multiply(n0,n5)|divide(#0,const_100)|multiply(n1,#1)|subtract(n5,#1)|divide(#2,const_100)|multiply(n2,#3)|divide(#5,const_100)|multiply(n3,#4)|subtract(#1,#4)|divide(#7,const_100)|multiply(n4,#8)|add(#6,#9)|divide(#10,const_100)|add(#11,#12) | explanation : total population = 728400 migrants = 35 % of 728400 = 254940 local population = ( 728400 - 254940 ) = 473460 . rural migrants = 20 % of 254940 = 50988 urban migrants = ( 254940 - 50988 ) = 203952 female population = 48 % of 473460 + 30 % of 50988 + 40 % of 203952 = 324138 answer : a | gain |
math_qa__otP7v5UnxePnhc5K | A batsman scored 120 runs whichincluded 3 boundaries and 8sixes. What % of his total score did he make by running between the wickets? Answers.
A) 40 % B) 50 % C) 65 % D) 68 % E) 70 % | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">12 + 48</gadget>
<output>60</output>
<gadget id="calculator">60 / 120</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>B</result> | B | 50 | A batsman scored 120 runs whichincluded 3 boundaries and 8sixes. What % of his total score did he make by running between the wickets? | {
"A": "40 %",
"B": "50 %",
"C": "65 %",
"D": "68 %",
"E": "70 %"
} | multiply(divide(add(multiply(3, const_4), multiply(add(3, 3), 8)), 120), const_100) | add(n1,n1)|multiply(n1,const_4)|multiply(n2,#0)|add(#1,#2)|divide(#3,n0)|multiply(#4,const_100)| | "number of runs made by running = 110 - ( 3 x 4 + 8 x 6 ) = 120 - ( 60 ) = 60 now , we need to calculate 60 is what percent of 120 . = > 60 / 120 * 100 = 50 % b" | general |
math_qa__jibsns6PsWSEgnw5 | The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 3 times the probability that both events A and B occur. What is the probability that event A occurs? Choose the correct choice from the following:
A) 44 / 7 B) 9 / 8 C) 25 / 8 D) 3 / 4 E) 7 / 8 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(3/8) * 2</gadget>
<output>3/4 = around 0.75</output>
<result>D</result> | D | 0.75 | The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 3 times the probability that both events A and B occur. What is the probability that event A occurs? | {
"A": "44 / 7",
"B": "9 / 8",
"C": "25 / 8",
"D": "3 / 4",
"E": "7 / 8"
} | multiply(divide(add(const_2, const_1), add(multiply(3, const_2), const_2)), const_2) | add(const_1,const_2)|multiply(n1,const_2)|add(#1,const_2)|divide(#0,#2)|multiply(#3,const_2)| | "let us say probability of a occuring is a . let us say probability of b occuring is b . a = 2 b probability ( either a or b or both ) = 3 times probability ( a and b ) a * ( 1 - b ) + b * ( 1 - a ) + ab = 3 * ab substituting a = 2 b in the second equation : 2 b * ( 1 - b ) + b * ( 1 - 2 b ) + 2 b * b = 3 * 2 b * b 3 b - 2 b ^ 2 = 6 b ^ 2 3 b = 8 b ^ 2 b = 3 / 8 = 3 / 8 so , a = 2 b = 3 / 4 the correct answer is d ." | general |
math_qa__w0v6WPlQurfr5QMw | John goes to his office by car at a speed of 40kmph and reaches 8 minutes earlier. If he goes at a speed of 30kmph , he reaches 4mins late. What is the distance from his house to office? Select.
A) 18 km
B) 20 km
C) 22 km
D) 24 km
E) 30 km | <gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">12 / 60</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">30 * (1/5)</gadget>
<output>6</output>
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
<gadget id="calculator">6 / 10</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">40 * (3/5)</gadget>
<output>24</output>
<result>D</result> | D | 24 | John goes to his office by car at a speed of 40kmph and reaches 8 minutes earlier. If he goes at a speed of 30kmph , he reaches 4mins late. What is the distance from his house to office? | {
"A": "18 km",
"B": "20 km",
"C": "22 km",
"D": "24 km",
"E": "30 km"
} | multiply(40, divide(multiply(30, divide(add(8, 4), const_60)), subtract(40, 30))) | add(n1,n3)|subtract(n0,n2)|divide(#0,const_60)|multiply(n2,#2)|divide(#3,#1)|multiply(n0,#4) | let his office time be 10 a . m . he reaches office at 8 minutes earlier when he travels at 40 kmph = > he reaches at 9 : 52 a . m he reaches his office 4 minutes late when travels at 30 kmph speed = > he reaches at 10.04 a . m the time difference is ( 10.04 – 9.52 ) = 12 minutes let the distance be d and time = distance speed t 1 – t 2 = 12 minutes = 12 / 60 hours = 1 / 5 hours d / 30 – d / 40 = 1 / 5 ( 4 d - 3 d ) / 120 = 1 / 5 d = 24 km | physics |
math_qa__axaLNWtkLWwzHkI7 | Compound interest of Rs.4000 at 10% per annum for 1 1/2years will be (interest compounded half yearly). Answers.
A) rs . 473 B) rs . 374 C) rs . 495 D) rs . 630 E) none of the above | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 2</gadget>
<output>3</output>
<gadget id="calculator">(21/20) ** 3</gadget>
<output>9_261/8_000 = around 1.157625</output>
<gadget id="calculator">4_000 * (9_261/8_000)</gadget>
<output>9_261/2 = around 4_630.5</output>
<gadget id="calculator">(9_261/2) - 4_000</gadget>
<output>1_261/2 = around 630.5</output>
<result>D</result> | D | 630 | Compound interest of Rs.4000 at 10% per annum for 1 1/2years will be (interest compounded half yearly). | {
"A": "rs . 473",
"B": "rs . 374",
"C": "rs . 495",
"D": "rs . 630",
"E": "none of the above"
} | subtract(multiply(4000, power(add(const_1, divide(divide(10, const_2), const_100)), multiply(add(1, divide(1, 2)), const_2))), 4000) | divide(n1,const_2)|divide(n2,n4)|add(n2,#1)|divide(#0,const_100)|add(#3,const_1)|multiply(#2,const_2)|power(#4,#5)|multiply(n0,#6)|subtract(#7,n0) | 10 % interest per annum will be 5 % interest half yearly for 3 terms ( 1 1 / 2 years ) so compound interest = 4000 [ 1 + ( 5 / 100 ) ] ^ 3 - 4000 = 4000 [ ( 21 / 20 ) ^ 3 - 1 ] = 4000 ( 9261 - 8000 ) / 8000 = 4 * 1261 / 8 = 630 answer : d | gain |
math_qa__4NXfjFLAXKCKyGsl | Find the length of the longest pole that can be placed in an indoor stadium 24 m long, 18 m wide and 16 m high
Choose the correct choice from the following answers:
A) 31
B) 32
C) 33
D) 34
E) 35 | <gadget id="calculator">16 ** 2</gadget>
<output>256</output>
<gadget id="calculator">24 ** 2</gadget>
<output>576</output>
<gadget id="calculator">18 ** 2</gadget>
<output>324</output>
<gadget id="calculator">576 + 324</gadget>
<output>900</output>
<gadget id="calculator">256 + 900</gadget>
<output>1_156</output>
<gadget id="calculator">1_156 ** (1/2)</gadget>
<output>34</output>
<result>D</result> | D | 34 | Find the length of the longest pole that can be placed in an indoor stadium 24 m long, 18 m wide and 16 m high | {
"A": "31",
"B": "32",
"C": "33",
"D": "34",
"E": "35"
} | sqrt(add(power(16, const_2), add(power(24, const_2), power(18, const_2)))) | power(n0,const_2)|power(n1,const_2)|power(n2,const_2)|add(#0,#1)|add(#3,#2)|sqrt(#4)| | "sqrt ( 1156 ) = 34 becoz max length is cuboid diagonal d = sqrt ( l ^ 2 + b ^ 2 + h ^ 2 ) where l lenght b breadth & h height answer : d" | physics |
math_qa__VT3G0sSevcWFXPjl | Sheela deposits Rs. 3800 in bank savings account. If this is 22% of her monthly income. What is her monthly income in? Choose the correct option.
A) 22000 B) 20000 C) 25123 D) 17272 E) none of these | <gadget id="calculator">3_800 * 100</gadget>
<output>380_000</output>
<gadget id="calculator">380_000 / 22</gadget>
<output>190_000/11 = around 17_272.727273</output>
<result>D</result> | D | 17,272 | Sheela deposits Rs. 3800 in bank savings account. If this is 22% of her monthly income. What is her monthly income in? | {
"A": "22000",
"B": "20000",
"C": "25123",
"D": "17272",
"E": "none of these"
} | divide(multiply(3800, const_100), 22) | multiply(n0,const_100)|divide(#0,n1)| | "explanation : 22 % of income = rs . 3800 100 % of income = 3800 x 100 / 22 = rs . 17272 answer : d" | gain |
math_qa__VZtobgQqlzrVfVK9 | 3 photographers , lisa , mike and norm , take photos of a wedding . the total of lisa and mikes photos is 60 less than the sum of mike ' s and norms . if norms photos number 10 more than twice the number of lisa ' s photos , then how many photos did norm take ? Pick
A) 40 B) 50 C) 60 D) 110 E) 80 | <gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">120 - 10</gadget>
<output>110</output>
<result>D</result> | D | 110 | 3 photographers , lisa , mike and norm , take photos of a wedding . the total of lisa and mikes photos is 60 less than the sum of mike ' s and norms . if norms photos number 10 more than twice the number of lisa ' s photos , then how many photos did norm take ? | {
"A": "40",
"B": "50",
"C": "60",
"D": "110",
"E": "80"
} | subtract(multiply(60, const_2), 10) | multiply(n1,const_2)|subtract(#0,n2) | l + m = m + n - 60 / n = 2 l + 10 60 = m + n - l - m 60 = n - l 60 = 2 l + 10 - l 50 = l 2 ( 50 ) + 10 = 110 d | general |
math_qa__PTxMzocrhVKchmS1 | The area of a rectangle is 360 Sq.m. If its length is increased by 10m and its width is decreased by 6m, then its area does not change. Find the perimeter of the original rectangle. Choose the correct option.
A) 74 m
B) 75 m
C) 76 m
D) 77 m
E) 78 m | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">360 / 18</gadget>
<output>20</output>
<gadget id="calculator">2 * (18 + 20)</gadget>
<output>76</output>
<result>C</result> | C | 76 | The area of a rectangle is 360 Sq.m. If its length is increased by 10m and its width is decreased by 6m, then its area does not change. Find the perimeter of the original rectangle. | {
"A": "74 m",
"B": "75 m",
"C": "76 m",
"D": "77 m",
"E": "78 m"
} | rectangle_perimeter(multiply(6, const_3), divide(360, multiply(6, const_3))) | multiply(n2,const_3)|divide(n0,#0)|rectangle_perimeter(#1,#0) | let l and b are the length and width of the original rectangle . since , l * b = 360 sq . m - ( 1 ) now , a / c to the problem ( l + 10 ) * ( b - 6 ) = 360 sq . m therefore , b = 6 ( 1 + l / 10 ) - ( 2 ) l * l + 10 l - 600 = 0 { by using equations 1 and 2 } thereafter , ( l - 20 ) ( l + 30 ) = 0 hence , l = 20 m b = 18 m { by using equation 2 } now , perimeter of the original rectangle = 2 ( l + b ) = 2 ( 20 + 18 ) = 76 m answer : c | geometry |
math_qa__9soua6EX768J18Wa | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 39 kmph, find the speed of the stream?
Answers
A) 12 kmph B) 13 kmph C) 14 kmph D) 15 kmph E) 16 kmph | <gadget id="calculator">39 * 2</gadget>
<output>78</output>
<gadget id="calculator">78 / 3</gadget>
<output>26</output>
<gadget id="calculator">39 - 26</gadget>
<output>13</output>
<result>B</result> | B | 13 | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 39 kmph, find the speed of the stream? | {
"A": "12 kmph",
"B": "13 kmph",
"C": "14 kmph",
"D": "15 kmph",
"E": "16 kmph"
} | subtract(39, divide(multiply(39, const_2), const_3)) | multiply(n0,const_2)|divide(#0,const_3)|subtract(n0,#1)| | "the ratio of the times taken is 2 : 1 . the ratio of the speed of the boat in still water to the speed of the stream = ( 2 + 1 ) / ( 2 - 1 ) = 3 / 1 = 3 : 1 speed of the stream = 39 / 3 = 13 kmph answer : b" | physics |
math_qa__PSsyHM9yhDjQKTZ2 | In measuring the sides of a rectangle, one side is taken 7% in excess, and the other 6% in deficit. Find the error percent in the area calculated from these measurements. Choose the correct choice from the following: A) 0.11 % B) 0.7 % C) 0.4 % D) 0.6 % E) 0.58 % | <gadget id="calculator">7 - 6</gadget>
<output>1</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">42 / 100</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">1 - (21/50)</gadget>
<output>29/50 = around 0.58</output>
<result>E</result> | E | 0.58 | In measuring the sides of a rectangle, one side is taken 7% in excess, and the other 6% in deficit. Find the error percent in the area calculated from these measurements. | {
"A": "0.11 %",
"B": "0.7 %",
"C": "0.4 %",
"D": "0.6 %",
"E": "0.58 %"
} | subtract(subtract(7, 6), divide(multiply(7, 6), const_100)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,const_100)|subtract(#1,#2)| | "let x and y be the sides of the rectangle . then , correct area = xy . calculated area = ( 61 / 57 ) x ( 47 / 50 ) y = ( 867 / 862 ) ( xy ) error in measurement = ( 867 / 862 ) xy - xy = ( 5 / 862 ) xy error percentage = [ ( 5 / 862 ) xy ( 1 / xy ) 100 ] % = ( 29 / 50 ) % = 0.58 % . answer is e ." | geometry |
math_qa__xX8eKR5qthkyuF25 | How many squares are there between 2011 to 2300 ???? Select:
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">2_300 ** (1/2)</gadget>
<output>10*sqrt(23) = around 47.958315</output>
<gadget id="calculator">floor(10*sqrt(23))</gadget>
<output>47</output>
<gadget id="calculator">2_011 ** (1/2)</gadget>
<output>sqrt(2011) = around 44.844175</output>
<gadget id="calculator">floor(sqrt(2011))</gadget>
<output>44</output>
<gadget id="calculator">47 - 44</gadget>
<output>3</output>
<result>A</result> | A | 3 | How many squares are there between 2011 to 2300 ???? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | subtract(floor(sqrt(2300)), floor(sqrt(2011))) | sqrt(n1)|sqrt(n0)|floor(#0)|floor(#1)|subtract(#2,#3) | nos . are 2025 , 2116 , 2209 answers is 3 answer : a | geometry |
math_qa__mCEXxohKnvvD2N24 | The average age of a group of 10 students is 14 years. If 5 more students join the group, the average age rises by 1 year. The average age of the new students is:
Options: A) 22 B) 38 C) 11 D) 17 E) 91 | <gadget id="calculator">14 + 1</gadget>
<output>15</output>
<gadget id="calculator">15 * 15</gadget>
<output>225</output>
<gadget id="calculator">14 * 10</gadget>
<output>140</output>
<gadget id="calculator">225 - 140</gadget>
<output>85</output>
<gadget id="calculator">85 / 5</gadget>
<output>17</output>
<result>D</result> | D | 17 | The average age of a group of 10 students is 14 years. If 5 more students join the group, the average age rises by 1 year. The average age of the new students is: | {
"A": "22",
"B": "38",
"C": "11",
"D": "17",
"E": "91"
} | divide(subtract(multiply(add(14, 1), add(14, 1)), multiply(14, 10)), 5) | add(n1,n3)|multiply(n0,n1)|multiply(#0,#0)|subtract(#2,#1)|divide(#3,n2) | explanation : total age of the 10 students = 10 × 14 = 140 total age of 15 students including the newly joined 5 students = 15 × 15 = 225 total age of the new students = 225 − 140 = 85 average age = 85 / 5 = 17 years answer : d | general |
math_qa__UZDoU9hnWXU5v8Pg | If the perimeter of a rectangular garden is 800 m, its length when its breadth is 100 m is? Select the correct option.
A) 286 m
B) 899 m
C) 300 m
D) 166 m
E) 187 m | <gadget id="calculator">800 / 2</gadget>
<output>400</output>
<gadget id="calculator">400 - 100</gadget>
<output>300</output>
<result>C</result> | C | 300 | If the perimeter of a rectangular garden is 800 m, its length when its breadth is 100 m is? | {
"A": "286 m",
"B": "899 m",
"C": "300 m",
"D": "166 m",
"E": "187 m"
} | subtract(divide(800, const_2), 100) | divide(n0,const_2)|subtract(#0,n1)| | "2 ( l + 100 ) = 800 = > l = 300 m answer : c" | physics |
math_qa__ItZxqdZhEMuYmZx8 | Two equal sums of money were invested, one at 4% and the other at 4.5%. At the end of 7 years, the simple interest received from the latter exceeded to that received from the former by 31.50. Each sum was : Options:
A) 1200 B) 600 C) 750 D) 900 E) none of these | <gadget id="calculator">4.5 - 4</gadget>
<output>0.5</output>
<gadget id="calculator">31.5 / 0.5</gadget>
<output>63</output>
<gadget id="calculator">63 * 100</gadget>
<output>6_300</output>
<gadget id="calculator">6_300 / 7</gadget>
<output>900</output>
<result>D</result> | D | 900 | Two equal sums of money were invested, one at 4% and the other at 4.5%. At the end of 7 years, the simple interest received from the latter exceeded to that received from the former by 31.50. Each sum was : | {
"A": "1200",
"B": "600",
"C": "750",
"D": "900",
"E": "none of these"
} | divide(multiply(divide(31.5, subtract(4.5, 4)), const_100), 7) | subtract(n1,n0)|divide(n3,#0)|multiply(#1,const_100)|divide(#2,n2) | difference of s . i . = √ 31.50 let each sum be x . then x × 4 1 / 2 × 7 / 100 − x × 4 × 7 / 100 = 31.50 or 7 ⁄ 100 x × 1 ⁄ 2 = 63 ⁄ 2 or x = 900 answer d | gain |
math_qa__DbcYiRrE2eizuXc8 | Shekar scored 76, 65, 82, 67 and 75 marks in Mathematics, Science, Social studies, English and Biology respectively. What are his average marks? Choose the correct choice from the following answers: A) 65 B) 69 C) 75 D) 85 E) 73 | <gadget id="calculator">76 + 65</gadget>
<output>141</output>
<gadget id="calculator">141 + 82</gadget>
<output>223</output>
<gadget id="calculator">223 + 67</gadget>
<output>290</output>
<gadget id="calculator">290 + 75</gadget>
<output>365</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">365 / 5</gadget>
<output>73</output>
<result>E</result> | E | 73 | Shekar scored 76, 65, 82, 67 and 75 marks in Mathematics, Science, Social studies, English and Biology respectively. What are his average marks? | {
"A": "65",
"B": "69",
"C": "75",
"D": "85",
"E": "73"
} | divide(add(add(add(add(76, 65), 82), 67), 75), add(const_1, const_4)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "explanation : average = ( 76 + 65 + 82 + 67 + 75 ) / 5 = 365 / 5 = 73 hence average = 73 answer : e" | general |
math_qa__Xg0LxblhO4iesdTV | A student chose a number, multiplied it by 2, then subtracted 152 from the result and got 102. What was the number he chose? Choose the correct choice from the following choices.
A) 127
B) 100
C) 129
D) 160
E) 200 | <gadget id="calculator">102 + 152</gadget>
<output>254</output>
<gadget id="calculator">254 / 2</gadget>
<output>127</output>
<result>A</result> | A | 127 | A student chose a number, multiplied it by 2, then subtracted 152 from the result and got 102. What was the number he chose? | {
"A": "127",
"B": "100",
"C": "129",
"D": "160",
"E": "200"
} | divide(add(102, 152), 2) | add(n1,n2)|divide(#0,n0)| | "solution : let x be the number he chose , then 2 * x * 152 = 102 2 x = 254 x = 127 correct answer a" | general |
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