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stringlengths 45
1.01k
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float64 -4,212
100B
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stringlengths 6
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stringlengths 7
6.48k
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stringlengths 8
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math_qa__icaFkh6tHndGpHr6 | The Malibu Country Club needs to drain its pool for refinishing. The hose they use to drain it can remove 60 cubic feet of water per minute. If the pool is 50 feet wide by 150 feet long by 10 feet deep and is currently at 80% capacity, how long will it take to drain the pool? Choices: A) 1000 min B) 1200 min C) 1300 min D) 1400 min E) 1600 min | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">50 * 150</gadget>
<output>7_500</output>
<gadget id="calculator">7_500 * 10</gadget>
<output>75_000</output>
<gadget id="calculator">(4/5) * 75_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 60</gadget>
<output>1_000</output>
<result>A</result> | A | 1,000 | The Malibu Country Club needs to drain its pool for refinishing. The hose they use to drain it can remove 60 cubic feet of water per minute. If the pool is 50 feet wide by 150 feet long by 10 feet deep and is currently at 80% capacity, how long will it take to drain the pool? | {
"A": "1000 min",
"B": "1200 min",
"C": "1300 min",
"D": "1400 min",
"E": "1600 min"
} | divide(multiply(divide(80, const_100), multiply(multiply(50, 150), 10)), 60) | divide(n4,const_100)|multiply(n1,n2)|multiply(n3,#1)|multiply(#0,#2)|divide(#3,n0) | volume of pool = 50 * 150 * 10 cu . ft , 80 % full = 50 * 150 * 10 * 0.8 cu . ft water is available to drain . draining capacity = 60 cu . ft / min therefore time taken = 50 * 150 * 10 * 0.8 / 60 min = 1000 min a | gain |
math_qa__Js09mO7j2xiVRu5T | If a is an integer greater than 9 but less than 26 and b is an integer greater than 14 but less than 31, what is the range of a/b? Choose the correct choice from the following: A) 1 B) 1 / 2 C) 5 / 6 D) 2 / 3 E) 4 / 3 | <gadget id="calculator">26 - 1</gadget>
<output>25</output>
<gadget id="calculator">14 + 1</gadget>
<output>15</output>
<gadget id="calculator">25 / 15</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">31 - 1</gadget>
<output>30</output>
<gadget id="calculator">10 / 30</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(5/3) - (1/3)</gadget>
<output>4/3 = around 1.333333</output>
<result>E</result> | E | 1.333333 | If a is an integer greater than 9 but less than 26 and b is an integer greater than 14 but less than 31, what is the range of a/b? | {
"A": "1",
"B": "1 / 2",
"C": "5 / 6",
"D": "2 / 3",
"E": "4 / 3"
} | subtract(divide(subtract(26, const_1), add(14, const_1)), divide(add(9, const_1), subtract(31, const_1))) | add(n2,const_1)|add(n0,const_1)|subtract(n1,const_1)|subtract(n3,const_1)|divide(#2,#0)|divide(#1,#3)|subtract(#4,#5)| | "range of a / b = max ( a / b ) - min ( a / b ) to get max ( a / b ) = > max ( a ) / min ( b ) = 25 / 15 to get min ( a / b ) = > min ( a ) / max ( b ) = 10 / 30 range = 25 / 15 - 10 / 30 = 4 / 3" | general |
math_qa__M9p9jgnrgXQjYela | If the cost price is 40% of selling price. Then what is the profit percent.
Options.
A) 150 % B) 120 % C) 130 % D) 200 % E) none of these | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">60 / 40</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 100</gadget>
<output>150</output>
<result>A</result> | A | 150 | If the cost price is 40% of selling price. Then what is the profit percent. | {
"A": "150 %",
"B": "120 %",
"C": "130 %",
"D": "200 %",
"E": "none of these"
} | multiply(divide(subtract(const_100, 40), 40), const_100) | subtract(const_100,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : let the s . p = 100 then c . p . = 40 profit = 60 profit % = ( 60 / 40 ) * 100 = 150 % . answer : a" | gain |
math_qa__elBMucSB8UFBIlVg | When positive integer x is divided by positive integer y, the remainder is 12. If x/y = 75.12, what is the value of y? Choose the correct choice from the following choices
A) 84
B) 98
C) 51
D) 65
E) 100 | <gadget id="calculator">floor(75.12)</gadget>
<output>75</output>
<gadget id="calculator">75.12 - 75</gadget>
<output>0.12</output>
<gadget id="calculator">12 / 0.12</gadget>
<output>100</output>
<result>E</result> | E | 100 | When positive integer x is divided by positive integer y, the remainder is 12. If x/y = 75.12, what is the value of y? | {
"A": "84",
"B": "98",
"C": "51",
"D": "65",
"E": "100"
} | divide(12, subtract(75.12, floor(75.12))) | floor(n1)|subtract(n1,#0)|divide(n0,#1)| | "when positive integer x is divided by positive integer y , the remainder is 12 - - > x = qy + 12 ; x / y = 75.12 - - > x = 75 y + 0.12 y ( so q above equals to 75 ) ; 0.12 y = 12 - - > y = 100 . answer : e ." | general |
math_qa__7DMTTXgjI2m0UNIM | The cost to park a car in a certain parking garage is $20.00 for up to 2 hours of parking and $1.75 for each hour in excess of 2 hours. What is the average (arithmetic mean) cost per hour to park a car in the parking garage for 9 hours? Options.
A) $ 3.58 B) $ 1.67 C) $ 2.25 D) $ 2.37 E) $ 2.50 | <gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">1.75 * 7</gadget>
<output>12.25</output>
<gadget id="calculator">20 + 12.25</gadget>
<output>32.25</output>
<gadget id="calculator">32.25 / 9</gadget>
<output>3.583333</output>
<result>A</result> | A | 3.58 | The cost to park a car in a certain parking garage is $20.00 for up to 2 hours of parking and $1.75 for each hour in excess of 2 hours. What is the average (arithmetic mean) cost per hour to park a car in the parking garage for 9 hours? | {
"A": "$ 3.58",
"B": "$ 1.67",
"C": "$ 2.25",
"D": "$ 2.37",
"E": "$ 2.50"
} | divide(add(20.00, multiply(1.75, subtract(9, 2))), 9) | subtract(n4,n1)|multiply(n2,#0)|add(n0,#1)|divide(#2,n4)| | "total cost of parking for 9 hours = 20 $ for the first 2 hours and then 1.75 for ( 9 - 2 ) hours = 20 + 7 * 1.75 = 32.25 thus the average parking price = 32.25 / 9 = 3.58 $ a is the correct answer ." | general |
math_qa__sVynDD2KWc1RhlYi | Two trains are moving in opposite directions with speed of 150 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. the slower train cross the faster train in --- seconds Choices: A) 56 B) 48 C) 47 D) 30 E) 25 | <gadget id="calculator">1.1 + 0.9</gadget>
<output>2</output>
<gadget id="calculator">150 + 90</gadget>
<output>240</output>
<gadget id="calculator">2 / 240</gadget>
<output>1/120 = around 0.008333</output>
<gadget id="calculator">(1/120) * 3_600</gadget>
<output>30</output>
<result>D</result> | D | 30 | Two trains are moving in opposite directions with speed of 150 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. the slower train cross the faster train in --- seconds | {
"A": "56",
"B": "48",
"C": "47",
"D": "30",
"E": "25"
} | multiply(divide(add(1.10, 0.9), add(150, 90)), const_3600) | add(n2,n3)|add(n0,n1)|divide(#0,#1)|multiply(#2,const_3600)| | "explanation : relative speed = 150 + 90 = 240 km / hr ( since both trains are moving in opposite directions ) total distance = 1.1 + . 9 = 2 km time = 2 / 240 hr = 1 / 120 hr = 3600 / 120 seconds = 30 seconds answer : option d" | physics |
math_qa__CYB1qHEjBCeBWMH2 | If the sum and difference of two numbers are 20 and 10 respectively, then the difference of their square is: Answers:
A) 12
B) 28
C) 160
D) 200
E) 18 | <gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 ** 2</gadget>
<output>225</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">225 - 25</gadget>
<output>200</output>
<result>D</result> | D | 200 | If the sum and difference of two numbers are 20 and 10 respectively, then the difference of their square is: | {
"A": "12",
"B": "28",
"C": "160",
"D": "200",
"E": "18"
} | subtract(power(divide(add(20, 10), const_2), const_2), power(subtract(20, divide(add(20, 10), const_2)), const_2)) | add(n0,n1)|divide(#0,const_2)|power(#1,const_2)|subtract(n0,#1)|power(#3,const_2)|subtract(#2,#4)| | "let the numbers be x and y . then , x + y = 20 and x - y = 8 x 2 - y 2 = ( x + y ) ( x - y ) = 20 * 10 = 200 . answer : d" | general |
math_qa__voVhuK98kt2dOVUm | A 340-liter solution of Kola is made from 75% water, 5% concentrated Kola and the rest is made from sugar. If 3.2 liters of sugar, 12 liter of water and 6.8 liters of concentrated Kola were added to the solution, what percent of the solution is made from sugar? Select the correct option:
A) 6 % .
B) 7.5 % .
C) 19.6 % .
D) 10.5 % .
E) 11 % . | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">340 * (3/4)</gadget>
<output>255</output>
<gadget id="calculator">340 - 255</gadget>
<output>85</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">340 * (1/20)</gadget>
<output>17</output>
<gadget id="calculator">85 - 17</gadget>
<output>68</output>
<gadget id="calculator">68 + 3.2</gadget>
<output>71.2</output>
<gadget id="calculator">340 + 3.2</gadget>
<output>343.2</output>
<gadget id="calculator">343.2 + 12</gadget>
<output>355.2</output>
<gadget id="calculator">355.2 + 6.8</gadget>
<output>362</output>
<gadget id="calculator">71.2 / 362</gadget>
<output>0.196685</output>
<gadget id="calculator">0.196685 * 100</gadget>
<output>19.6685</output>
<result>C</result> | C | 19.6 | A 340-liter solution of Kola is made from 75% water, 5% concentrated Kola and the rest is made from sugar. If 3.2 liters of sugar, 12 liter of water and 6.8 liters of concentrated Kola were added to the solution, what percent of the solution is made from sugar? | {
"A": "6 % .",
"B": "7.5 % .",
"C": "19.6 % .",
"D": "10.5 % .",
"E": "11 % ."
} | multiply(divide(add(subtract(subtract(340, multiply(340, divide(75, const_100))), multiply(340, divide(5, const_100))), 3.2), add(add(add(340, 3.2), 12), 6.8)), const_100) | add(n0,n3)|divide(n1,const_100)|divide(n2,const_100)|add(n4,#0)|multiply(n0,#1)|multiply(n0,#2)|add(n5,#3)|subtract(n0,#4)|subtract(#7,#5)|add(n3,#8)|divide(#9,#6)|multiply(#10,const_100)| | "denominator : 340 + 12 + 3.2 + 6.8 = 362 numerator : 340 ( 1 - . 75 - . 05 ) + 3.2 340 ( 0.2 ) + 3.2 68 + 3.2 71.2 ratio : 71.2 / 362 = 0.196 answer : c" | gain |
math_qa__1pYgo2lnsiQZQFtn | The average mark of the students of a class in a particular exam is 90. If 2 students whose average mark in that exam is 45 are excluded, the average mark of the remaining will be 95. Find the number of students who wrote the exam? Select
A) 10
B) 40
C) 20
D) 30
E) 25 | <gadget id="calculator">95 * 2</gadget>
<output>190</output>
<gadget id="calculator">2 * 45</gadget>
<output>90</output>
<gadget id="calculator">190 - 90</gadget>
<output>100</output>
<gadget id="calculator">95 - 90</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<result>C</result> | C | 20 | The average mark of the students of a class in a particular exam is 90. If 2 students whose average mark in that exam is 45 are excluded, the average mark of the remaining will be 95. Find the number of students who wrote the exam? | {
"A": "10",
"B": "40",
"C": "20",
"D": "30",
"E": "25"
} | divide(subtract(multiply(95, 2), multiply(2, 45)), subtract(95, 90)) | multiply(n1,n3)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)| | "let the number of students who wrote the exam be x . total marks of students = 90 x . total marks of ( x - 2 ) students = 95 ( x - 2 ) 90 x - ( 2 * 45 ) = 95 ( x - 2 ) 100 = 5 x = > x = 20 answer : c" | general |
math_qa__vbKYJca3GrDja8wa | A, B and C invest in the ratio of 3 : 4: 5. The percentage of return on their investments are in the ratio of 6 : 5 : 4. Find the total earnings, If B earns Rs. 250 more than A :
Choose the correct choice from the following answers: A) 2348 B) 7250 C) 2767 D) 1998 E) 2771 | <gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">18 + 20</gadget>
<output>38</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">38 + 20</gadget>
<output>58</output>
<gadget id="calculator">20 - 18</gadget>
<output>2</output>
<gadget id="calculator">250 / 2</gadget>
<output>125</output>
<gadget id="calculator">58 * 125</gadget>
<output>7_250</output>
<result>B</result> | B | 7,250 | A, B and C invest in the ratio of 3 : 4: 5. The percentage of return on their investments are in the ratio of 6 : 5 : 4. Find the total earnings, If B earns Rs. 250 more than A : | {
"A": "2348",
"B": "7250",
"C": "2767",
"D": "1998",
"E": "2771"
} | multiply(add(add(multiply(3, 6), multiply(4, 5)), multiply(5, 4)), divide(250, subtract(multiply(4, 5), multiply(3, 6)))) | multiply(n0,n3)|multiply(n1,n2)|add(#0,#1)|subtract(#1,#0)|add(#2,#1)|divide(n6,#3)|multiply(#4,#5)| | "explanation : a b c investment 3 x 4 x 5 x rate of return 6 y % 5 y % 4 y % return \ inline \ frac { 18 xy } { 100 } \ inline \ frac { 20 xy } { 100 } \ inline \ frac { 20 xy } { 100 } total = ( 18 + 20 + 20 ) = \ inline \ frac { 58 xy } { 100 } b ' s earnings - a ' s earnings = \ inline \ frac { 2 xy } { 100 } = 250 total earning = \ inline \ frac { 58 xy } { 100 } = 7250 answer : b ) rs . 7250" | general |
math_qa__Eq2zsOQVafbQ8pen | A copy machine, working at a constant rate, makes 35 copies per minute. A second copy machine, working at a constant rate, makes 75 copies per minute. Working together at their respective rates, how many copies do the two machines make in half an hour ? Select.
A) 90 B) 2,700 C) 3,300 D) 5,400 E) 324,000 | <gadget id="calculator">35 + 75</gadget>
<output>110</output>
<gadget id="calculator">110 * 60</gadget>
<output>6_600</output>
<gadget id="calculator">6_600 / 2</gadget>
<output>3_300</output>
<result>C</result> | C | 3,300 | A copy machine, working at a constant rate, makes 35 copies per minute. A second copy machine, working at a constant rate, makes 75 copies per minute. Working together at their respective rates, how many copies do the two machines make in half an hour ? | {
"A": "90",
"B": "2,700",
"C": "3,300",
"D": "5,400",
"E": "324,000"
} | divide(multiply(add(35, 75), const_60), const_2) | add(n0,n1)|multiply(#0,const_60)|divide(#1,const_2)| | "together the two machines make 35 + 75 = 110 copies per minute . so , in half an hour they will make 110 * 30 = 3,300 copies . answer : c ." | physics |
math_qa__TIFegMTPKwfILWRF | The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 750 per sq. metre. Choose the correct choice from the following options: A) s . 15,550 B) s . 15,600 C) s . 16,500 D) s . 17,600 E) s . 17,900 | <gadget id="calculator">5.5 * 4</gadget>
<output>22</output>
<gadget id="calculator">750 * 22</gadget>
<output>16_500</output>
<result>C</result> | C | 16,500 | The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 750 per sq. metre. | {
"A": "s . 15,550",
"B": "s . 15,600",
"C": "s . 16,500",
"D": "s . 17,600",
"E": "s . 17,900"
} | multiply(750, multiply(5.5, 4)) | multiply(n0,n1)|multiply(n2,#0)| | "area of the floor = ( 5.5 ã — 4 ) m 2 = 22 m 2 . cost of paving = rs . ( 750 ã — 22 ) = rs . 16500 . answer : option c" | physics |
math_qa__vtCjRFtGeQL6m91x | A dishonest dealer professes to sell goods at the cost price but uses a weight of 950 grams per kg, what is his percent? Choose the correct choice:
A) 22 %
B) 25 %
C) 77 %
D) 5.26 %
E) 12 % | <gadget id="calculator">100 / 950</gadget>
<output>2/19 = around 0.105263</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">(2/19) * 1_000</gadget>
<output>2_000/19 = around 105.263158</output>
<gadget id="calculator">(2_000/19) - 100</gadget>
<output>100/19 = around 5.263158</output>
<result>D</result> | D | 5.26 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 950 grams per kg, what is his percent? | {
"A": "22 %",
"B": "25 %",
"C": "77 %",
"D": "5.26 %",
"E": "12 %"
} | subtract(multiply(divide(const_100, 950), multiply(const_100, multiply(add(const_3, const_2), const_2))), const_100) | add(const_2,const_3)|divide(const_100,n0)|multiply(#0,const_2)|multiply(#2,const_100)|multiply(#1,#3)|subtract(#4,const_100) | 950 - - - 50 100 - - - ? = > 5.26 % answer : d | gain |
math_qa__3phJLAiHetfNaJyp | n^(n/2)=4 is true when n=4 in the same way what is the value of n if n^(n/2) =8?
Choose the most appropriate option: A) 4 B) 8 C) 2 D) 6 E) 10 | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">64 / 8</gadget>
<output>8</output>
<result>B</result> | B | 8 | n^(n/2)=4 is true when n=4 in the same way what is the value of n if n^(n/2) =8? | {
"A": "4",
"B": "8",
"C": "2",
"D": "6",
"E": "10"
} | divide(power(8, 2), 8) | power(n4,n0)|divide(#0,n4)| | n ^ ( n / 2 ) = 8 apply log n / 2 logn = log 8 nlogn = 2 log 8 = log 8 ^ 2 = log 64 logn = log 64 now apply antilog n = 64 / n now n = 8 . answer : b | general |
math_qa__LstWQwSpH56uH2kd | If N = 2^0.25 and N^b = 8, b must equal
Choose the correct answer:
A) 3 / 80
B) 3 / 5
C) 12
D) 5 / 3
E) 80 / 3 | <gadget id="calculator">log(8)</gadget>
<output>log(8) = around 2.079442</output>
<gadget id="calculator">2 ** 0.25</gadget>
<output>1.189207</output>
<gadget id="calculator">log(1.189207)</gadget>
<output>0.173287</output>
<gadget id="calculator">log(8) / 0.173287</gadget>
<output>5.77077334133547*log(8) = around 11.999986</output>
<result>C</result> | C | 12 | If N = 2^0.25 and N^b = 8, b must equal | {
"A": "3 / 80",
"B": "3 / 5",
"C": "12",
"D": "5 / 3",
"E": "80 / 3"
} | divide(log(8), log(power(2, 0.25))) | log(n2)|power(n0,n1)|log(#1)|divide(#0,#2)| | "25 / 100 = 1 / 4 n = 2 ^ 1 / 4 n ^ b = 2 ^ 3 ( 2 ^ 1 / 4 ) ^ b = 2 ^ 3 b = 12 answer : c" | general |
math_qa__s3WJ6bgvl6pqUbNm | [( 3.242 x 15 ) / 100] = ? Choose the correct answer.
A) 0.045388 B) 4.5388 C) 453.88 D) 473.88 E) 0.04863 | <gadget id="calculator">3.242 * 15</gadget>
<output>48.63</output>
<gadget id="calculator">48.63 / 100</gadget>
<output>0.4863</output>
<gadget id="calculator">0.4863 / 10</gadget>
<output>0.04863</output>
<result>E</result> | E | 0.04863 | [( 3.242 x 15 ) / 100] = ? | {
"A": "0.045388",
"B": "4.5388",
"C": "453.88",
"D": "473.88",
"E": "0.04863"
} | divide(divide(multiply(3.242, 15), 100), const_10) | multiply(n0,n1)|divide(#0,n2)|divide(#1,const_10)| | "answer multiplying 3.242 x 15 = 4.863 now divide 4.863 by 100 so , 4.863 ÷ 100 = 0.04863 ∴ shift the decimal two places to the left as 100 correct option : e" | general |
math_qa__QtCPehZ56wm9W4NK | there are 41 students in a class , number of girls is one more than number of guys . we need to form a team of 4 students . all 4 in the team can not be from same gender . number of girls and guys in the team should not be equal . how many ways can such a team be made ? Options
A) 50540 ways
B) 60540 ways
C) 50840 ways
D) 40540 ways
E) 51540 ways | <gadget id="calculator">41 / 2</gadget>
<output>41/2 = around 20.5</output>
<gadget id="calculator">floor(41/2)</gadget>
<output>20</output>
<gadget id="calculator">41 - 20</gadget>
<output>21</output>
<gadget id="calculator">factorial(21)</gadget>
<output>51_090_942_171_709_440_000</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">51_090_942_171_709_440_000 / 6</gadget>
<output>8_515_157_028_618_240_000</output>
<gadget id="calculator">21 - 3</gadget>
<output>18</output>
<gadget id="calculator">factorial(18)</gadget>
<output>6_402_373_705_728_000</output>
<gadget id="calculator">8_515_157_028_618_240_000 / 6_402_373_705_728_000</gadget>
<output>1_330</output>
<gadget id="calculator">1_330 * 20</gadget>
<output>26_600</output>
<gadget id="calculator">factorial(20)</gadget>
<output>2_432_902_008_176_640_000</output>
<gadget id="calculator">20 - 3</gadget>
<output>17</output>
<gadget id="calculator">factorial(17)</gadget>
<output>355_687_428_096_000</output>
<gadget id="calculator">2_432_902_008_176_640_000 / 355_687_428_096_000</gadget>
<output>6_840</output>
<gadget id="calculator">6_840 / 6</gadget>
<output>1_140</output>
<gadget id="calculator">1_140 * 21</gadget>
<output>23_940</output>
<gadget id="calculator">26_600 + 23_940</gadget>
<output>50_540</output>
<result>A</result> | A | 50,540 | there are 41 students in a class , number of girls is one more than number of guys . we need to form a team of 4 students . all 4 in the team can not be from same gender . number of girls and guys in the team should not be equal . how many ways can such a team be made ? | {
"A": "50540 ways",
"B": "60540 ways",
"C": "50840 ways",
"D": "40540 ways",
"E": "51540 ways"
} | add(multiply(divide(divide(factorial(subtract(41, floor(divide(41, const_2)))), factorial(subtract(4, const_1))), factorial(subtract(subtract(41, floor(divide(41, const_2))), subtract(4, const_1)))), floor(divide(41, const_2))), multiply(divide(divide(factorial(floor(divide(41, const_2))), factorial(subtract(floor(divide(41, const_2)), subtract(4, const_1)))), factorial(subtract(4, const_1))), subtract(41, floor(divide(41, const_2))))) | divide(n0,const_2)|subtract(n1,const_1)|factorial(#1)|floor(#0)|factorial(#3)|subtract(n0,#3)|subtract(#3,#1)|factorial(#5)|factorial(#6)|subtract(#5,#1)|divide(#7,#2)|divide(#4,#8)|factorial(#9)|divide(#10,#12)|divide(#11,#2)|multiply(#13,#3)|multiply(#14,#5)|add(#15,#16) | boys = 20 and girls = 21 now the combinations are { girl , girl , girl , boy } or { boy , boy , boy , girl } so 21 c 3 * 20 c 1 + 20 c 3 * 21 c 1 = 50540 ways answer : a | general |
math_qa__S7UMZHVjA7rsJF0S | Find the total number of prime factors in the expression (4)^11 x (7)^5 x (11)^2 Choose the correct choice:
A) 26
B) 22
C) 25
D) 27
E) 29 | <gadget id="calculator">2 * 11</gadget>
<output>22</output>
<gadget id="calculator">22 + 5</gadget>
<output>27</output>
<gadget id="calculator">27 + 2</gadget>
<output>29</output>
<result>E</result> | E | 29 | Find the total number of prime factors in the expression (4)^11 x (7)^5 x (11)^2 | {
"A": "26",
"B": "22",
"C": "25",
"D": "27",
"E": "29"
} | add(add(multiply(2, 11), 5), 2) | multiply(n1,n5)|add(n3,#0)|add(n5,#1)| | "( 4 ) ^ 11 x ( 7 ) ^ 5 x ( 11 ) ^ 2 = ( 2 x 2 ) ^ 11 x ( 7 ) ^ 5 x ( 11 ) ^ 2 = 2 ^ 11 x 2 ^ 11 x 7 ^ 5 x 11 ^ 2 = 2 ^ 22 x 7 ^ 5 x 11 ^ 2 total number of prime factors = ( 22 + 5 + 2 ) = 29 . answer is e ." | general |
math_qa__5a9F28f4z8WSvHkP | Pipe P can drain the liquid from a tank in 3/4 the time that it takes pipe Q to drain it and in 3/3 the time that it takes pipe R to do it. If all 3 pipes operating simultaneously but independently are used to drain liquid from the tank, then pipe Q drains what portion of the liquid from the tank? Choose the correct answer
A) 9 / 29 B) 8 / 23 C) 3 / 8 D) 3 / 11 E) 3 / 4 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 9</gadget>
<output>33</output>
<gadget id="calculator">9 / 33</gadget>
<output>3/11 = around 0.272727</output>
<result>D</result> | D | 0.272727 | Pipe P can drain the liquid from a tank in 3/4 the time that it takes pipe Q to drain it and in 3/3 the time that it takes pipe R to do it. If all 3 pipes operating simultaneously but independently are used to drain liquid from the tank, then pipe Q drains what portion of the liquid from the tank? | {
"A": "9 / 29",
"B": "8 / 23",
"C": "3 / 8",
"D": "3 / 11",
"E": "3 / 4"
} | divide(multiply(3, 3), add(multiply(multiply(4, 3), const_2), multiply(3, 3))) | multiply(n0,n0)|multiply(n0,n1)|multiply(#1,const_2)|add(#2,#0)|divide(#0,#3) | suppose q can drain in 1 hr . so , rq = 1 / 1 = 1 so , rp = 1 / [ ( 3 / 4 ) rq ] = 4 / 3 also , rp = rr / ( 3 / 3 ) = > 4 / 3 = rr / ( 3 / 3 ) = > rr = 4 / 3 let h is the time it takes to drain by running all 3 pipes simultaneously so combined rate = rc = 1 / h = 1 + 4 / 3 + 4 / 3 = 11 / 3 = 1 / ( 3 / 11 ) thus running simultaneously , pipe q will drain 3 / 11 of the liquid . thus answer = d . | physics |
math_qa__67vd3kehoRxJ1HOz | Xavier starts from P towards Q at a speed of 40 kmph and after every 12 mins increases his speed by 20 kmph. If the distance between P and Q is 56 km, then how much time does he take to cover the distance?
Select: A) 40 B) 48 C) 44 D) 36 E) 30 | <gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">36 + 12</gadget>
<output>48</output>
<result>B</result> | B | 48 | Xavier starts from P towards Q at a speed of 40 kmph and after every 12 mins increases his speed by 20 kmph. If the distance between P and Q is 56 km, then how much time does he take to cover the distance? | {
"A": "40",
"B": "48",
"C": "44",
"D": "36",
"E": "30"
} | add(add(add(12, 12), 12), 12) | add(n1,n1)|add(n1,#0)|add(n1,#1)| | "first 12 min = 40 * 12 / 60 = 8 km 2 nd 12 min = 60 * 12 / 60 = 12 km 3 rd 12 min = 80 * 12 / 60 = 16 km 4 th 12 min = 100 * 12 / 60 = 20 km total time 12.4 = 48 min b" | physics |
math_qa__1tMBi6abvTCrDDO2 | In the next Cricket World Cup T-20, Team W has decided to score 200 runs only through 4s and 6s. In how many ways can the Team W score these 200 runs? Choose the correct choice from the following answers.
A) 13
B) 15
C) 16
D) 17
E) 18 | <gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">200 / 24</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">10 + (25/3)</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">(55/3) - 1</gadget>
<output>52/3 = around 17.333333</output>
<result>D</result> | D | 17 | In the next Cricket World Cup T-20, Team W has decided to score 200 runs only through 4s and 6s. In how many ways can the Team W score these 200 runs? | {
"A": "13",
"B": "15",
"C": "16",
"D": "17",
"E": "18"
} | subtract(add(const_10, divide(200, multiply(6, 4))), const_1) | multiply(n2,n3)|divide(n1,#0)|add(#1,const_10)|subtract(#2,const_1) | team w can score a maximum of 50 fours and a minimum of 2 fours with an interval or spacing of 3 units to accommodate the 6 ' s . so the number of fours scored forms an ap 2 , 5 , 8 , . . . 50 with a common difference of 3 . number of ways of scoring 200 only through 4 ' s and 6 ' s = ( 50 - 2 ) / 3 + 1 = 17 answer : d alternate solution : 4 x + 6 y = 200 - - > 2 x + 3 y = 100 x = ( 100 - 3 y ) / 2 - - > 100 - 3 y should be even . this is possible when 3 y is even . there are 17 even multiples of 3 between 0 and 100 . answer : d | general |
math_qa__Df8fEXNSrRAYFAZO | In a class of 50 students, 12 enrolled for both English and German. 22 enrolled for German. If the students of the class enrolled for at least one of the two subjects, then how many students enrolled for only English and not German? Choose the correct choice from the following options.
A) 30 B) 10 C) 18 D) 28 E) 32 | <gadget id="calculator">50 + 12</gadget>
<output>62</output>
<gadget id="calculator">62 - 22</gadget>
<output>40</output>
<gadget id="calculator">40 - 12</gadget>
<output>28</output>
<result>D</result> | D | 28 | In a class of 50 students, 12 enrolled for both English and German. 22 enrolled for German. If the students of the class enrolled for at least one of the two subjects, then how many students enrolled for only English and not German? | {
"A": "30",
"B": "10",
"C": "18",
"D": "28",
"E": "32"
} | subtract(subtract(add(50, 12), 22), 12) | add(n0,n1)|subtract(#0,n2)|subtract(#1,n1)| | "total = english + german - both + neither - - > 50 = english + 22 - 12 + 0 - - > english = 40 - - > only english = english - both = 40 - 12 = 28 . answer : d ." | other |
math_qa__jLWQq452kmvagTvh | The perimeter of a triangle is 20 cm and the inradius of the triangle is 3 cm. What is the area of the triangle? Choose the correct choice from the following options
A) 22 B) 30 C) 77 D) 54 E) 23 | <gadget id="calculator">(3 * 20) / 2</gadget>
<output>30</output>
<result>B</result> | B | 30 | The perimeter of a triangle is 20 cm and the inradius of the triangle is 3 cm. What is the area of the triangle? | {
"A": "22",
"B": "30",
"C": "77",
"D": "54",
"E": "23"
} | triangle_area(3, 20) | triangle_area(n0,n1)| | "area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 3 * 20 / 2 = 30 cm 2 answer : b" | geometry |
math_qa__YRokWqXYNLR1HqPI | A train 130 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is Choose the correct option.
A) 54 kmph B) 60 kmph C) 66 kmph D) 72 kmph E) 82 kmph | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">6 * (5/18)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 6</gadget>
<output>10</output>
<gadget id="calculator">130 - 10</gadget>
<output>120</output>
<gadget id="calculator">120 / 6</gadget>
<output>20</output>
<gadget id="calculator">20 / (5/18)</gadget>
<output>72</output>
<result>D</result> | D | 72 | A train 130 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is | {
"A": "54 kmph",
"B": "60 kmph",
"C": "66 kmph",
"D": "72 kmph",
"E": "82 kmph"
} | divide(divide(subtract(130, multiply(multiply(6, const_0_2778), 6)), 6), const_0_2778) | multiply(n1,const_0_2778)|multiply(n1,#0)|subtract(n0,#1)|divide(#2,n1)|divide(#3,const_0_2778)| | "speed of train relative to man : 130 / 6 * 18 / 5 km / hr = 78 km / hr let speed of train = x therefore x + 6 = 78 x = 78 - 6 x = 72 km / hr answer : d" | physics |
math_qa__dRvgaGuwSZYG6VeF | A barrel full of beer has 2 taps one midway,,which draw a litre in 6 minutes and the other at the bottom,which draws a litre in 4 minutes. The lower tap is lower normally used after the level of beer in the barrel is lower than midway.The capacity of the barrel is 36 litres. A new assistant opens the lower tap when the barrel is full and draws out some beer. As a result the lower tap has been used 24 minutes before the usual time. For how long was the beer drawn out by the new assistant ?
Options
A) 15 minutes B) 16 minutes C) 17 minutes D) 18 minutes E) none of these | <gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">18 * 6</gadget>
<output>108</output>
<gadget id="calculator">108 - 24</gadget>
<output>84</output>
<gadget id="calculator">84 / 6</gadget>
<output>14</output>
<gadget id="calculator">18 - 14</gadget>
<output>4</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<result>B</result> | B | 16 | A barrel full of beer has 2 taps one midway,,which draw a litre in 6 minutes and the other at the bottom,which draws a litre in 4 minutes. The lower tap is lower normally used after the level of beer in the barrel is lower than midway.The capacity of the barrel is 36 litres. A new assistant opens the lower tap when the barrel is full and draws out some beer. As a result the lower tap has been used 24 minutes before the usual time. For how long was the beer drawn out by the new assistant ? | {
"A": "15 minutes",
"B": "16 minutes",
"C": "17 minutes",
"D": "18 minutes",
"E": "none of these"
} | multiply(4, subtract(divide(36, const_2), divide(subtract(multiply(divide(36, const_2), 6), 24), 6))) | divide(n3,const_2)|multiply(n1,#0)|subtract(#1,n4)|divide(#2,n1)|subtract(#0,#3)|multiply(n2,#4) | sol . the top tab is operational till 18 litres is drawn out . ∴ time after which the lower tap is usually open = 18 × 6 = 108 minutes ∴ time after which it is open now = 108 – 24 = 84 minutes ∴ litres drawn = 84 / 6 = 14 litres ∴ 18 – 14 = 4 litres were drawn by the new assistant . ∴ time = 4 × 4 = 16 minutes answer b | physics |
math_qa__VFWumstgWJahHdzM | If a cube has a volume of 125, what is the surface area of one side? Choose the correct choice from the following options.
A) 5 B) 25 C) 50 D) 150 E) 625 | <gadget id="calculator">125 ** (1/3)</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<result>B</result> | B | 25 | If a cube has a volume of 125, what is the surface area of one side? | {
"A": "5",
"B": "25",
"C": "50",
"D": "150",
"E": "625"
} | square_area(cube_edge_by_volume(125)) | cube_edge_by_volume(n0)|square_area(#0) | volume of a cube = side ^ 3 125 = side ^ 3 so side = 5 area of one side of the cube = side ^ 2 = 5 ^ 2 = 25 correct answer - b | geometry |
math_qa__302PLKYdOFOWfcMA | xy=1 then what is (6^(x+y)^2) / (6^(x-y)^2)
Pick.
A) 1296
B) 4
C) 8
D) 16
E) 32 | <gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">6 ** 4</gadget>
<output>1_296</output>
<result>A</result> | A | 1,296 | xy=1 then what is (6^(x+y)^2) / (6^(x-y)^2) | {
"A": "1296",
"B": "4",
"C": "8",
"D": "16",
"E": "32"
} | power(6, multiply(const_4, 1)) | multiply(n0,const_4)|power(n1,#0)| | "( x + y ) ^ 2 - ( x - y ) ^ 2 ( x + y + x - y ) ( x + y - x + y ) ( 2 x ) ( 2 y ) 4 xy 4 6 ^ 4 = 1296 answer a" | general |
math_qa__g4W2MkdMpptUcoZT | Reena took a loan of $. 1200 with simple interest for as many years as the rate of interest. If she paid $ 192 as interest at the end of the loan period, what was the rate of interest?
Choose the correct choice from the following choices.
A) 3.6 B) 6 C) 4 D) can not be determined E) none of these | <gadget id="calculator">192 * 100</gadget>
<output>19_200</output>
<gadget id="calculator">19_200 / 1_200</gadget>
<output>16</output>
<gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<result>C</result> | C | 4 | Reena took a loan of $. 1200 with simple interest for as many years as the rate of interest. If she paid $ 192 as interest at the end of the loan period, what was the rate of interest? | {
"A": "3.6",
"B": "6",
"C": "4",
"D": "can not be determined",
"E": "none of these"
} | sqrt(divide(multiply(192, const_100), 1200)) | multiply(n1,const_100)|divide(#0,n0)|sqrt(#1)| | "let rate = r % and time = r years . then , 1200 x r x r / 100 = 192 12 r 2 = 192 r 2 = 16 r = 4 . answer : c" | gain |
math_qa__D8xVe8q7vuqlLYYU | √(25)^2 Choose the correct choice.
A) 5 B) 14 C) 25 D) 21 E) none of these | <gadget id="calculator">25 ** 2</gadget>
<output>625</output>
<gadget id="calculator">625 ** (1/2)</gadget>
<output>25</output>
<result>C</result> | C | 25 | √(25)^2 | {
"A": "5",
"B": "14",
"C": "25",
"D": "21",
"E": "none of these"
} | sqrt(power(25, 2)) | power(n0,n1)|sqrt(#0)| | "explanation √ ( 25 ) ^ 2 = ? or , ? = 25 answer c" | general |
math_qa__eVVR8aXpWbMit4Y0 | What is the sum of 20 consecutive integers from -9 inclusive, in a increasing order? Choose the correct choice from the following answers.
A) - 9 B) 9 C) - 10 D) 10 E) 20 | <gadget id="calculator">9 + 1</gadget>
<output>10</output>
<result>D</result> | D | 10 | What is the sum of 20 consecutive integers from -9 inclusive, in a increasing order? | {
"A": "- 9",
"B": "9",
"C": "- 10",
"D": "10",
"E": "20"
} | add(9, const_1) | add(n1,const_1)| | "from - 9 to - 1 - - > 9 nos . zero - - > 1 number from + 1 to + 9 - - > 9 nos . when we add up nos . from - 9 to + 9 sum will be zero . total 19 nos will be added . 20 th number will be 10 . sum of these 20 nos . = 10 . d is the answer ." | general |
math_qa__TgKWVTAaMemk1cVH | last year the range of the annual yield on equal amount of investments in 100 mutual funds was $ 10000 . if the annual yield this year for each of the 100 mutual funds has improved by 15 percent this year than it was last year , what is the range of the annual yield on mutual funds this year ? Choose the correct choice from the following answers:
A) $ 12700 B) $ 13000 C) $ 23000 D) $ 11500 E) $ 33000 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">10_000 * (3/20)</gadget>
<output>1_500</output>
<gadget id="calculator">10_000 + 1_500</gadget>
<output>11_500</output>
<result>D</result> | D | 11,500 | last year the range of the annual yield on equal amount of investments in 100 mutual funds was $ 10000 . if the annual yield this year for each of the 100 mutual funds has improved by 15 percent this year than it was last year , what is the range of the annual yield on mutual funds this year ? | {
"A": "$ 12700",
"B": "$ 13000",
"C": "$ 23000",
"D": "$ 11500",
"E": "$ 33000"
} | add(10000, multiply(10000, divide(15, 100))) | divide(n3,n0)|multiply(n1,#0)|add(n1,#1) | let the lowest yield be x . therefore , highest yield is x + 10000 . now yield of each mutual fund investment is improved by 10 % . therefore the yields will remain arranged in the same order as before . or lowest yield = 1.15 x and highest = 1.15 * ( x + 10000 ) or range = highest - lowest = 1.15 * ( x + 10000 ) - 1.15 x = 11500 , hence , d | gain |
math_qa__h6WOCoOJu5lk3FgP | Two trains A and B starting from two points and travelling in opposite directions, reach their destinations 9 hours and 4 hours respectively after meeting each other. If the train A travels at 100kmph, find the rate at which the train B runs.
Choices
A) 40 B) 60 C) 150 D) 80 E) 100 | <gadget id="calculator">9 / 4</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">(9/4) ** (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">100 * (3/2)</gadget>
<output>150</output>
<result>C</result> | C | 150 | Two trains A and B starting from two points and travelling in opposite directions, reach their destinations 9 hours and 4 hours respectively after meeting each other. If the train A travels at 100kmph, find the rate at which the train B runs. | {
"A": "40",
"B": "60",
"C": "150",
"D": "80",
"E": "100"
} | multiply(100, sqrt(divide(9, 4))) | divide(n0,n1)|sqrt(#0)|multiply(n2,#1)| | "if two objects a and b start simultaneously from opposite points and , after meeting , reach their destinations in ‘ a ’ and ‘ b ’ hours respectively ( i . e . a takes ‘ a hrs ’ to travel from the meeting point to his destination and b takes ‘ b hrs ’ to travel from the meeting point to his destination ) , then the ratio of their speeds is given by : sa / sb = √ ( b / a ) i . e . ratio of speeds is given by the square root of the inverse ratio of time taken . sa / sb = √ ( 4 / 9 ) = 2 / 3 this gives us that the ratio of the speed of a : speed of b as 2 : 3 . since speed of a is 100 kmph , speed of b must be 100 * ( 3 / 2 ) = 150 kmph answer c" | physics |
math_qa__66exK62rG36v2wP7 | A soft drink company had 6000 small and 15000 big bottles in storage. If 12% of small 14% of big bottles have been sold, then the total bottles remaining in storage is Choose the correct choice:
A) 15360
B) 16010
C) 18180
D) 14930
E) 16075 | <gadget id="calculator">6_000 + 15_000</gadget>
<output>21_000</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">6_000 * (3/25)</gadget>
<output>720</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/50) * 15_000</gadget>
<output>2_100</output>
<gadget id="calculator">720 + 2_100</gadget>
<output>2_820</output>
<gadget id="calculator">21_000 - 2_820</gadget>
<output>18_180</output>
<result>C</result> | C | 18,180 | A soft drink company had 6000 small and 15000 big bottles in storage. If 12% of small 14% of big bottles have been sold, then the total bottles remaining in storage is | {
"A": "15360",
"B": "16010",
"C": "18180",
"D": "14930",
"E": "16075"
} | subtract(add(6000, 15000), add(multiply(6000, divide(12, const_100)), multiply(divide(14, const_100), 15000))) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|subtract(#0,#5)| | "6000 + 15000 - ( 0.12 * 6000 + 0.14 * 15000 ) = 18180 . answer : c ." | general |
math_qa__vtNnFqtplsDHNHg1 | In a box of 10 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective? Choose the correct option: A) 1 / 12 B) 7 / 15 C) 2 / 13 D) 2 / 15 E) 1 / 17 | <gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">factorial(7)</gadget>
<output>5_040</output>
<gadget id="calculator">5_040 * 6</gadget>
<output>30_240</output>
<gadget id="calculator">3_628_800 / 30_240</gadget>
<output>120</output>
<gadget id="calculator">56 / 120</gadget>
<output>7/15 = around 0.466667</output>
<result>B</result> | B | 0.466667 | In a box of 10 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective? | {
"A": "1 / 12",
"B": "7 / 15",
"C": "2 / 13",
"D": "2 / 15",
"E": "1 / 17"
} | divide(divide(factorial(subtract(10, 2)), multiply(factorial(subtract(subtract(10, 2), 3)), factorial(3))), divide(factorial(10), multiply(factorial(subtract(10, 3)), factorial(3)))) | factorial(n2)|factorial(n0)|subtract(n0,n1)|subtract(n0,n2)|factorial(#2)|factorial(#3)|subtract(#2,n2)|factorial(#6)|multiply(#5,#0)|divide(#1,#8)|multiply(#7,#0)|divide(#4,#10)|divide(#11,#9)| | "first , there are 8 c 3 ways you can select 3 good pencils from 4 good ones . second , there are 10 c 3 ways you select 3 pencils from 6 ones in the box . then , the probability that neither pen will be defective is : 8 c 3 / 10 c 3 = 56 / 120 = 7 / 15 answer is b" | general |
math_qa__1NyhcJpthy5WN3wI | Company workers decided to raise Rs. 3 lakhs by equal contribution from each. Had they contributed Rs. 50 each extra, the contribution would have been Rs. 3.25 lakhs. How many workers were they?
Choose the correct answer
A) 300
B) 400
C) 500
D) 600
E) 700 | <gadget id="calculator">100 * 1_000</gadget>
<output>100_000</output>
<gadget id="calculator">3.25 * 100_000</gadget>
<output>325_000</output>
<gadget id="calculator">3 * 100_000</gadget>
<output>300_000</output>
<gadget id="calculator">325_000 - 300_000</gadget>
<output>25_000</output>
<gadget id="calculator">25_000 / 50</gadget>
<output>500</output>
<result>C</result> | C | 500 | Company workers decided to raise Rs. 3 lakhs by equal contribution from each. Had they contributed Rs. 50 each extra, the contribution would have been Rs. 3.25 lakhs. How many workers were they? | {
"A": "300",
"B": "400",
"C": "500",
"D": "600",
"E": "700"
} | divide(subtract(multiply(3.25, multiply(const_100, const_1000)), multiply(3, multiply(const_100, const_1000))), 50) | multiply(const_100,const_1000)|multiply(n2,#0)|multiply(n0,#0)|subtract(#1,#2)|divide(#3,n1) | explanation : n * 50 = ( 325000 - 300000 ) = 25000 n = 25000 / 50 = 500 option c | general |
math_qa__jcjiGkLetqJMGUHU | The average of 7 numbers is 20. If each number be multiplied by 5. Find the average of new set of numbers? Choices:
A) 100
B) 122
C) 120
D) 125
E) 145 | <gadget id="calculator">20 * 5</gadget>
<output>100</output>
<result>A</result> | A | 100 | The average of 7 numbers is 20. If each number be multiplied by 5. Find the average of new set of numbers? | {
"A": "100",
"B": "122",
"C": "120",
"D": "125",
"E": "145"
} | multiply(20, 5) | multiply(n1,n2)| | "explanation : average of new numbers = 20 * 5 = 100 answer : option a" | general |
math_qa__ZKD2f2nOWOSTqK0P | Right triangle PQR is the base of the prism in the figure above. If PQ=PR=√5 and the height of the prism is 10, what is the volume of the prism? Pick:
A) 5 B) 10 C) 15 D) 20 E) 25 | <gadget id="calculator">5 ** (1/2)</gadget>
<output>sqrt(5) = around 2.236068</output>
<gadget id="calculator">((sqrt(5)) * (sqrt(5))) / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 10</gadget>
<output>25</output>
<result>E</result> | E | 25 | Right triangle PQR is the base of the prism in the figure above. If PQ=PR=√5 and the height of the prism is 10, what is the volume of the prism? | {
"A": "5",
"B": "10",
"C": "15",
"D": "20",
"E": "25"
} | multiply(triangle_area(sqrt(5), sqrt(5)), 10) | sqrt(n0)|triangle_area(#0,#0)|multiply(n1,#1) | volume of prism = area of base * height = 1 / 2 * ( square root of 5 ) * ( square root of 5 ) * 10 = 25 answer : e | geometry |
math_qa__canE3DxUlD6sELEx | each of the positive integers a and c is a 4 - digit integer . if each of the digits 0 through 9 appears in one of these 3 integers , what is the maximum possible value of the sum of a and c ?
Choices
A) 18695 B) 18325 C) 18365 D) 18395 E) 18485 | <gadget id="calculator">9 * 1_000</gadget>
<output>9_000</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 100</gadget>
<output>700</output>
<gadget id="calculator">9_000 + 700</gadget>
<output>9_700</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">9_700 + 50</gadget>
<output>9_750</output>
<gadget id="calculator">9_750 + 3</gadget>
<output>9_753</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 1_000</gadget>
<output>8_000</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">8_000 + 600</gadget>
<output>8_600</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">8_600 + 40</gadget>
<output>8_640</output>
<gadget id="calculator">8_640 + 2</gadget>
<output>8_642</output>
<gadget id="calculator">9_753 + 8_642</gadget>
<output>18_395</output>
<result>D</result> | D | 18,395 | each of the positive integers a and c is a 4 - digit integer . if each of the digits 0 through 9 appears in one of these 3 integers , what is the maximum possible value of the sum of a and c ? | {
"A": "18695",
"B": "18325",
"C": "18365",
"D": "18395",
"E": "18485"
} | add(add(add(add(multiply(9, const_1000), multiply(add(3, 4), const_100)), multiply(add(4, const_1), const_10)), 3), add(add(add(multiply(multiply(4, const_2), const_1000), multiply(multiply(3, const_2), const_100)), multiply(4, const_10)), const_2)) | add(n0,n3)|add(n0,const_1)|multiply(n2,const_1000)|multiply(n0,const_2)|multiply(n3,const_2)|multiply(n0,const_10)|multiply(#0,const_100)|multiply(#1,const_10)|multiply(#3,const_1000)|multiply(#4,const_100)|add(#2,#6)|add(#8,#9)|add(#10,#7)|add(#11,#5)|add(n3,#12)|add(#13,const_2)|add(#14,#15) | according to the stem we should use the digits 0 through 9 to construct 2 four - digit integers , so that their sum is as big as possible . to maximize the sum , maximize the thousands digits of a and c , so make them 9 and 8 . next , maximize hundreds digits . make them 7 and 6 . next maximize 10 ' s digit place by 5 and 4 use the remaining digits ( 3 , and 2 ) for units digits . so , a would be 9753 , and c would be 8642 . 9753 + 8642 = 18395 answer : d . | general |
math_qa__We4TSDiR1JOsJ487 | Riya and Priya set on a journey. Riya moves eastward at a speed of 18kmph and Priya moves westward at a speed of 24 kmph.How far will be priya from Riya after 15 minutes Choose one
A) 25 kms
B) 11 kms
C) 50 kms
D) 30 kms
E) 40 kms | <gadget id="calculator">18 + 24</gadget>
<output>42</output>
<gadget id="calculator">42 / 60</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 15</gadget>
<output>21/2 = around 10.5</output>
<result>B</result> | B | 11 | Riya and Priya set on a journey. Riya moves eastward at a speed of 18kmph and Priya moves westward at a speed of 24 kmph.How far will be priya from Riya after 15 minutes | {
"A": "25 kms",
"B": "11 kms",
"C": "50 kms",
"D": "30 kms",
"E": "40 kms"
} | multiply(speed(add(18, 24), const_60), 15) | add(n0,n1)|speed(#0,const_60)|multiply(n2,#1) | total eastward distance = 18 kmph * 1 / 4 hr = 4.5 km total westward distance = 24 kmph * 1 / 4 hr = 6 km total distn betn them = 4.5 + 6 = 10.5 m ans 11 km answer : b | physics |
math_qa__jnvphgGmeXj9Mb2J | 36 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work? Choose the correct choice from the following
A) 12
B) 16
C) 13
D) 18
E) 19 | <gadget id="calculator">36 * 12</gadget>
<output>432</output>
<gadget id="calculator">432 * 5</gadget>
<output>2_160</output>
<gadget id="calculator">30 * 6</gadget>
<output>180</output>
<gadget id="calculator">2_160 / 180</gadget>
<output>12</output>
<result>A</result> | A | 12 | 36 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work? | {
"A": "12",
"B": "16",
"C": "13",
"D": "18",
"E": "19"
} | divide(multiply(multiply(36, 12), 5), multiply(30, 6)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|divide(#2,#1)| | "let the required number of days be x . less persons , more days ( indirect proportion ) more working hours per day , less days ( indirect proportion ) persons 30 : 36 : : 12 : x working hours / day 6 : 5 30 x 6 x x = 36 x 5 x 12 x = ( 36 x 5 x 12 ) / ( 30 x 6 ) x = 12 answer a" | physics |
math_qa__fOehUAsIsYej4IBA | A shopkeeper buys two articles for Rs.1000 each and then sells them, making 10% profit on the first article and 10% loss on second article. Find the net profit or loss percent? Choose the correct choice from the following: A) 200 B) 278 C) 100 D) 202 E) 270 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">100 / 90</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">(10/9) * 1_000</gadget>
<output>10_000/9 = around 1_111.111111</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">100 / 110</gadget>
<output>10/11 = around 0.909091</output>
<gadget id="calculator">(10/11) * 1_000</gadget>
<output>10_000/11 = around 909.090909</output>
<gadget id="calculator">(10_000/9) + (10_000/11)</gadget>
<output>200_000/99 = around 2_020.20202</output>
<gadget id="calculator">1_000 + 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">(200_000/99) - 2_000</gadget>
<output>2_000/99 = around 20.20202</output>
<gadget id="calculator">(2_000/99) * 100</gadget>
<output>200_000/99 = around 2_020.20202</output>
<gadget id="calculator">(200_000/99) / (200_000/99)</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>C</result> | C | 100 | A shopkeeper buys two articles for Rs.1000 each and then sells them, making 10% profit on the first article and 10% loss on second article. Find the net profit or loss percent? | {
"A": "200",
"B": "278",
"C": "100",
"D": "202",
"E": "270"
} | multiply(divide(multiply(subtract(add(multiply(divide(const_100, subtract(const_100, 10)), 1000), multiply(divide(const_100, add(const_100, 10)), 1000)), add(1000, 1000)), const_100), add(multiply(divide(const_100, subtract(const_100, 10)), 1000), multiply(divide(const_100, add(const_100, 10)), 1000))), const_100) | add(n1,const_100)|add(n0,n0)|subtract(const_100,n1)|divide(const_100,#2)|divide(const_100,#0)|multiply(n0,#3)|multiply(n0,#4)|add(#5,#6)|subtract(#7,#1)|multiply(#8,const_100)|divide(#9,#7)|multiply(#10,const_100) | profit on first article = 10 % of 1000 = 100 . this is equal to the loss he makes on the second article . that , is he makes neither profit nor loss . answer : c | gain |
math_qa__IInvJxT8ys5eOc9n | A can run 4 times as fast as B and gives B a start of 63 m. How long should the race course be so that A and B might reach in the same time? Choose the correct answer:
A) 70 m B) 60 m C) 80 m D) 65 m E) 84 m | <gadget id="calculator">63 / 4</gadget>
<output>63/4 = around 15.75</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">(63/4) / 3</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">4 * (21/4)</gadget>
<output>21</output>
<gadget id="calculator">21 + 63</gadget>
<output>84</output>
<result>E</result> | E | 84 | A can run 4 times as fast as B and gives B a start of 63 m. How long should the race course be so that A and B might reach in the same time? | {
"A": "70 m",
"B": "60 m",
"C": "80 m",
"D": "65 m",
"E": "84 m"
} | add(multiply(4, divide(divide(63, 4), subtract(4, const_1))), 63) | divide(n1,n0)|subtract(n0,const_1)|divide(#0,#1)|multiply(n0,#2)|add(n1,#3)| | "speed of a : speed of b = 4 : 1 means in a race of 4 m a gains 3 m . then in a race of 63 m he gains 63 * ( 4 / 3 ) i . e 84 m answer : e" | physics |
math_qa__E7DSMrUNGSVPiQd8 | If c is 25% of a and 10% of b, what percent of a is b? Choose the correct choice from the following:
A) 2.5 % B) 15 % C) 25 % D) 35 % E) 250 % | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/4) / (1/10)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 100</gadget>
<output>250</output>
<result>E</result> | E | 250 | If c is 25% of a and 10% of b, what percent of a is b? | {
"A": "2.5 %",
"B": "15 %",
"C": "25 %",
"D": "35 %",
"E": "250 %"
} | multiply(divide(divide(25, const_100), divide(10, const_100)), const_100) | divide(n0,const_100)|divide(n1,const_100)|divide(#0,#1)|multiply(#2,const_100)| | "c is 25 % of a - - > c = a / 4 ; c is 10 % of b - - > c = b / 10 ; thus a / 4 = b / 10 - - > b = 5 / 2 * a = 2.5 a . therefore , b is 250 % of a . answer : e" | gain |
math_qa__bMS3WKIzJFBTEAtH | Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 40 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped? Choices: A) 205 B) 220 C) 240 D) 247 E) 294 | <gadget id="calculator">72 / 60</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 35</gadget>
<output>42</output>
<gadget id="calculator">40 - 35</gadget>
<output>5</output>
<gadget id="calculator">42 / 5</gadget>
<output>42/5 = around 8.4</output>
<gadget id="calculator">35 * (42/5)</gadget>
<output>294</output>
<result>E</result> | E | 294 | Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 40 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped? | {
"A": "205",
"B": "220",
"C": "240",
"D": "247",
"E": "294"
} | multiply(35, divide(multiply(divide(72, const_60), 35), subtract(40, 35))) | divide(n1,const_60)|subtract(n2,n0)|multiply(n0,#0)|divide(#2,#1)|multiply(n0,#3)| | "car y began travelling after 72 minutes or 1.2 hours . let t be the time for which car y travelled before it stopped . both cars stop when they have travelled the same distance . so , 35 ( t + 1.2 ) = 40 t t = 8.4 distance traveled by car x from the time car y began traveling until both cars stopped is 35 x 8.4 = 294 miles answer : - e" | physics |
math_qa__jGOBVhDDK89cuVUX | What is the ratio between perimeters of two squares one having 2.5 times the diagonal then the other? Choose the correct choice from the following answers:
A) 4 : 5 B) 1 : 3 C) 2.5 : 1 D) 3.5 : 1 E) 3 : 2 | <gadget id="calculator">2.5 / 2.5</gadget>
<output>1</output>
<gadget id="calculator">2.5 / 1</gadget>
<output>2.5</output>
<result>C</result> | C | 2.5 | What is the ratio between perimeters of two squares one having 2.5 times the diagonal then the other? | {
"A": "4 : 5",
"B": "1 : 3",
"C": "2.5 : 1",
"D": "3.5 : 1",
"E": "3 : 2"
} | divide(2.5, divide(2.5, 2.5)) | divide(n0,n0)|divide(n0,#0)| | "d = 2.5 d d = d a √ 2 = 2.5 d a √ 2 = d a = 2.5 d / √ 2 a = d / √ 2 = > 2.5 : 1 answer : c" | geometry |
math_qa__4j7apX4AExMxdHBV | a number when divided by 899 gives a remainder 63. what remainder will be obtained by dividing the same number by 29 Options: A) 8 B) 5 C) 7 D) 6 E) 9 | <gadget id="calculator">29 * 2</gadget>
<output>58</output>
<gadget id="calculator">63 - 58</gadget>
<output>5</output>
<result>B</result> | B | 5 | a number when divided by 899 gives a remainder 63. what remainder will be obtained by dividing the same number by 29 | {
"A": "8",
"B": "5",
"C": "7",
"D": "6",
"E": "9"
} | subtract(63, multiply(29, const_2)) | multiply(n2,const_2)|subtract(n1,#0)| | 63 / 29 , thereforerequired number is : 5 , correct answer ( b ) | general |
math_qa__XrA7hcblgD0O2nQi | 17 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?
Options
A) 34 B) 87 C) 30 D) 99 E) 77 | <gadget id="calculator">21 * 8</gadget>
<output>168</output>
<gadget id="calculator">17 * 3</gadget>
<output>51</output>
<gadget id="calculator">168 * 51</gadget>
<output>8_568</output>
<gadget id="calculator">21 * 2</gadget>
<output>42</output>
<gadget id="calculator">42 * 6</gadget>
<output>252</output>
<gadget id="calculator">8_568 / 252</gadget>
<output>34</output>
<gadget id="calculator">floor(34)</gadget>
<output>34</output>
<gadget id="calculator">34 + 1</gadget>
<output>35</output>
<result>A</result> | A | 34 | 17 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men? | {
"A": "34",
"B": "87",
"C": "30",
"D": "99",
"E": "77"
} | add(floor(divide(multiply(multiply(21, 8), multiply(17, 3)), multiply(multiply(21, 2), 6))), const_1) | multiply(n1,n2)|multiply(n0,n5)|multiply(n4,n6)|multiply(#0,#1)|multiply(n3,#2)|divide(#3,#4)|floor(#5)|add(#6,const_1)| | "3 w = 2 m 17 m - - - - - - 21 * 8 hours 21 w - - - - - - x * 6 hours 14 m - - - - - - x * 6 17 * 21 * 8 = 14 * x * 6 x = 34 answer : a" | physics |
math_qa__OimLkW0ikjZCZExy | If xy=9, x/y=36, for positive numbers x and y, y=? Answers: A) 1 / 2 B) 2 C) 1 / 3 D) 3 E) 1 / 6 | <gadget id="calculator">9 / 36</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) ** (1/2)</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | If xy=9, x/y=36, for positive numbers x and y, y=? | {
"A": "1 / 2",
"B": "2",
"C": "1 / 3",
"D": "3",
"E": "1 / 6"
} | sqrt(divide(9, 36)) | divide(n0,n1)|sqrt(#0) | very easy question . 2 variables and 2 easy equations . xy = 9 - - - > x = 9 / y - ( i ) x / y = 36 - - - > replacing ( i ) here - - - > 9 / ( y ^ 2 ) = 36 - - - > y ^ 2 = 9 / 36 = 1 / 4 - - - > y = 1 / 2 or - 1 / 2 the question states that x and y are positive integers . therefore , y = 1 / 2 is the answer . answer a . | general |
math_qa__fqa7CXzkHd2tatEQ | In one year, the population, of a village increased by 20% and in the next year, it decreased by 20%. If at the end of 2nd year, the population was 9600, what was it in the beginning? Choose the correct choice from the following answers: A) 10000 B) 8000 C) 1988 D) 1277 E) 2081 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">9_600 / (4/5)</gadget>
<output>12_000</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">12_000 / (6/5)</gadget>
<output>10_000</output>
<result>A</result> | A | 10,000 | In one year, the population, of a village increased by 20% and in the next year, it decreased by 20%. If at the end of 2nd year, the population was 9600, what was it in the beginning? | {
"A": "10000",
"B": "8000",
"C": "1988",
"D": "1277",
"E": "2081"
} | divide(divide(9600, subtract(const_1, divide(20, const_100))), add(const_1, divide(20, const_100))) | divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#0)|divide(n3,#2)|divide(#3,#1) | x * 120 / 100 * 80 / 100 = 9600 x * 0.96 = 9600 x = 9600 / 0.96 = > 10000 answer : a | general |
math_qa__dFjj2lRNe5lJj1li | A bag contains 7 red, 5 blue and 4 green balls. If 2 ballsare picked at random, what is the probability that both are red?
Choose the correct choice from the following:
A) 2 / 15 B) 2 / 21 C) 7 / 40 D) 3 / 29 E) 4 / 27 | <gadget id="calculator">binomial(7, 2)</gadget>
<output>21</output>
<gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">12 + 4</gadget>
<output>16</output>
<gadget id="calculator">binomial(16, 2)</gadget>
<output>120</output>
<gadget id="calculator">21 / 120</gadget>
<output>7/40 = around 0.175</output>
<result>C</result> | C | 0.175 | A bag contains 7 red, 5 blue and 4 green balls. If 2 ballsare picked at random, what is the probability that both are red? | {
"A": "2 / 15",
"B": "2 / 21",
"C": "7 / 40",
"D": "3 / 29",
"E": "4 / 27"
} | divide(choose(7, 2), choose(add(add(7, 5), 4), 2)) | add(n0,n1)|choose(n0,n3)|add(n2,#0)|choose(#2,n3)|divide(#1,#3)| | "p ( both are red ) , = 7 c 216 c 2 = 7 c 216 c 2 = 21 / 120 = 7 / 40 c" | other |
math_qa__itmIGA664gop8Eln | A boat can travel with a speed of 22 km/hr in still water. If the speed of the stream is 5 km/hr, find the time taken by the boat to go 216 km downstream Select:
A) 5 hours B) 4 hours C) 3 hours D) 2 hours E) 8 hours | <gadget id="calculator">22 + 5</gadget>
<output>27</output>
<gadget id="calculator">216 / 27</gadget>
<output>8</output>
<result>E</result> | E | 8 | A boat can travel with a speed of 22 km/hr in still water. If the speed of the stream is 5 km/hr, find the time taken by the boat to go 216 km downstream | {
"A": "5 hours",
"B": "4 hours",
"C": "3 hours",
"D": "2 hours",
"E": "8 hours"
} | divide(216, add(22, 5)) | add(n0,n1)|divide(n2,#0)| | "explanation : speed of the boat in still water = 22 km / hr speed of the stream = 5 km / hr speed downstream = ( 22 + 5 ) = 27 km / hr distance travelled downstream = 216 km time taken = distance / speed = 216 / 27 = 8 hours . answer : option e" | physics |
math_qa__159pQVIikKXdN0rv | A certain company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio W of revenue from car sales in 1996 to revenue from truck sales in 1996? Select
A) 1 : 2 B) 4 : 5 C) 1 : 1 D) 3 : 2 E) 5 : 3 | <gadget id="calculator">100 + 7</gadget>
<output>107</output>
<gadget id="calculator">100 + 1</gadget>
<output>101</output>
<gadget id="calculator">107 - 101</gadget>
<output>6</output>
<gadget id="calculator">100 - 11</gadget>
<output>89</output>
<gadget id="calculator">101 - 89</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | A certain company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio W of revenue from car sales in 1996 to revenue from truck sales in 1996? | {
"A": "1 : 2",
"B": "4 : 5",
"C": "1 : 1",
"D": "3 : 2",
"E": "5 : 3"
} | divide(subtract(add(const_100, 7), add(const_100, 1)), subtract(add(const_100, 1), subtract(const_100, 11))) | add(n3,const_100)|add(n6,const_100)|subtract(const_100,n1)|subtract(#0,#1)|subtract(#1,#2)|divide(#3,#4)| | a . . i have probably solved this question 3 - 4 times by now . . remember the answer . . 1 : 2 | other |
math_qa__tWomUOLvbJw3TsNi | In 1979 approximately 1/3 of the 37.3 million airline passengers traveling to or from the United States used Kennedy Airport. If the number of such passengers that used Miami Airport was 1/2 the number that used Kennedy Airport and 5 times the number that used Logan Airport, approximately how many millions of these passengers used Logan Airport that year?
Select: A) 18.6 B) 9.3 C) 1.2 D) 3.1 E) 1.6 | <gadget id="calculator">37.3 / 3</gadget>
<output>12.433333</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">12.433333 / 10</gadget>
<output>1.243333</output>
<result>C</result> | C | 1.2 | In 1979 approximately 1/3 of the 37.3 million airline passengers traveling to or from the United States used Kennedy Airport. If the number of such passengers that used Miami Airport was 1/2 the number that used Kennedy Airport and 5 times the number that used Logan Airport, approximately how many millions of these passengers used Logan Airport that year? | {
"A": "18.6",
"B": "9.3",
"C": "1.2",
"D": "3.1",
"E": "1.6"
} | divide(divide(37.3, 3), multiply(5, 2)) | divide(n3,n2)|multiply(n5,n6)|divide(#0,#1)| | "number of passengers using kennedy airport = 37 / 3 = ~ 12.43 passengers using miami airport = 12.43 / 2 = ~ 6.2 passengers using logan airport = 6.2 / 5 = ~ 1.24 so c" | general |
math_qa__7XqAHhwprJQNKK3m | In covering a distance of 18 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is: Choose the correct choice from the following answers: A) 3 kmph B) 6 kmph C) 6.25 kmph D) 7.5 kmph E) 7.8 kmph | <gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">18 - 9</gadget>
<output>9</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">9 / 3</gadget>
<output>3</output>
<result>A</result> | A | 3 | In covering a distance of 18 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is: | {
"A": "3 kmph",
"B": "6 kmph",
"C": "6.25 kmph",
"D": "7.5 kmph",
"E": "7.8 kmph"
} | divide(subtract(18, divide(18, 2)), add(1, 2)) | add(n1,n2)|divide(n0,n1)|subtract(n0,#1)|divide(#2,#0) | let abhay ' s speed be x km / hr . then , 18 / x - 18 / 2 x = 3 6 x = 18 x = 3 km / hr . answer : option a | physics |
math_qa__N7ys7pMP9sQMoG3a | A portion of the 50% solution of chemicals was replaced with an equal amount of 60% solution of chemicals. As a result, 55% solution of chemicals resulted. What part of the original solution was replaced? Choose the correct answer.
A) 3 / 4 B) 1 / 4 C) 3 / 4 D) 2 / 5 E) 1 / 2 | <gadget id="calculator">50 - 55</gadget>
<output>-5</output>
<gadget id="calculator">50 - 60</gadget>
<output>-10</output>
<gadget id="calculator">(-5) / (-10)</gadget>
<output>1/2 = around 0.5</output>
<result>E</result> | E | 0.5 | A portion of the 50% solution of chemicals was replaced with an equal amount of 60% solution of chemicals. As a result, 55% solution of chemicals resulted. What part of the original solution was replaced? | {
"A": "3 / 4",
"B": "1 / 4",
"C": "3 / 4",
"D": "2 / 5",
"E": "1 / 2"
} | divide(subtract(50, 55), subtract(50, 60)) | subtract(n0,n2)|subtract(n0,n1)|divide(#0,#1)| | "this is a weighted average question . say x % of the solution was replaced - - > equate the amount of chemicals : 0.5 ( 1 - x ) + 0.6 * x = 0.55 - - > x = 1 / 2 . answer : e ." | gain |
math_qa__N5BtbFSPmOyHc7Wl | Ram get 450 marks in his exam which is 90% of total marks. What is the total marks? Answers.
A) 475 B) 600 C) 550 D) 500 E) 525 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">450 + 50</gadget>
<output>500</output>
<result>D</result> | D | 500 | Ram get 450 marks in his exam which is 90% of total marks. What is the total marks? | {
"A": "475",
"B": "600",
"C": "550",
"D": "500",
"E": "525"
} | add(450, multiply(add(const_3, const_2), const_10)) | add(const_2,const_3)|multiply(#0,const_10)|add(n0,#1) | x * ( 90 / 100 ) = 450 x = 5 * 100 x = 500 answer : d | general |
math_qa__GCBmpQLRP8cpTK9o | All the faces of a cube are painted with blue colour. Then it is cut into 125 small equal cubes.
How many small cubes will be formed having only one face coloured ? Choose the most appropriate option.
A) 54 B) 8 C) 16 D) 24 E) 34 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">125 ** (1/3)</gadget>
<output>5</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">9 * 60</gadget>
<output>540</output>
<gadget id="calculator">540 / 10</gadget>
<output>54</output>
<result>A</result> | A | 54 | All the faces of a cube are painted with blue colour. Then it is cut into 125 small equal cubes.
How many small cubes will be formed having only one face coloured ? | {
"A": "54",
"B": "8",
"C": "16",
"D": "24",
"E": "34"
} | divide(multiply(power(subtract(power(125, divide(const_1, const_3)), const_2), const_2), const_60), const_10) | divide(const_1,const_3)|power(n0,#0)|subtract(#1,const_2)|power(#2,const_2)|multiply(#3,const_60)|divide(#4,const_10) | no . of small cubes will have only one face painted = ( x - 2 ) 2 * 6 here x = side of the small cube = 5 therfore ( x - 2 ) 2 * 6 = 54 answer : a | geometry |
math_qa__X9Knw4FobWTys7cb | In a certain country 1/7 of 8 = 5. Assuming the same proportion, what would be the value of 1/5 of 40 ? Pick:
A) 54
B) 25
C) 45
D) 35
E) 52 | <gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">(7/8) * 40</gadget>
<output>35</output>
<result>D</result> | D | 35 | In a certain country 1/7 of 8 = 5. Assuming the same proportion, what would be the value of 1/5 of 40 ? | {
"A": "54",
"B": "25",
"C": "45",
"D": "35",
"E": "52"
} | multiply(divide(7, 8), 40) | divide(n1,n2)|multiply(n6,#0)| | "d 35" | general |
math_qa__EGFVAvLAdvpIWDrn | Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 30 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast? Choose the correct option:
A) 10 %
B) 12 %
C) 15 %
D) 29 %
E) 20 % | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(1/2) - (3/10)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(1/5) / (7/10)</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(2/7) * 100</gadget>
<output>200/7 = around 28.571429</output>
<result>D</result> | D | 29 | Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 30 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast? | {
"A": "10 %",
"B": "12 %",
"C": "15 %",
"D": "29 %",
"E": "20 %"
} | multiply(divide(subtract(divide(50, const_100), divide(30, const_100)), subtract(const_1, divide(30, const_100))), const_100) | divide(n2,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(const_1,#1)|divide(#2,#3)|multiply(#4,const_100) | let me try a simpler one . lets assume that candidate got 30 % votes and total votes is 100 . candidate won = 30 remaining = 70 to get 50 % , candidate requires 20 votes from 100 which is 20 % and 20 votes from 70 . 20 / 70 = 2 / 7 = . 285 = 28.5 % which is approx 29 % . hence the answer is d . | general |
math_qa__POosaAeW1rDM8wyn | If f(x) = x^4 - 4x^3 - 2x^2 + 5x , then f(-1) = Choose the correct choice from the following answers: A) - 4 B) - 2 C) - 1 D) 1 E) 2 | <gadget id="calculator">-1</gadget>
<output>-1</output>
<gadget id="calculator">(-1) ** 4</gadget>
<output>1</output>
<gadget id="calculator">(-1) ** 3</gadget>
<output>-1</output>
<gadget id="calculator">4 * (-1)</gadget>
<output>-4</output>
<gadget id="calculator">1 - (-4)</gadget>
<output>5</output>
<gadget id="calculator">(-1) ** 2</gadget>
<output>1</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">5 * (-1)</gadget>
<output>-5</output>
<gadget id="calculator">3 + (-5)</gadget>
<output>-2</output>
<result>B</result> | B | -2 | If f(x) = x^4 - 4x^3 - 2x^2 + 5x , then f(-1) = | {
"A": "- 4",
"B": "- 2",
"C": "- 1",
"D": "1",
"E": "2"
} | add(subtract(subtract(power(negate(1), const_4), multiply(4, power(negate(1), const_3))), multiply(2, power(negate(1), const_2))), multiply(5, negate(1))) | negate(n6)|multiply(n5,#0)|power(#0,const_4)|power(#0,const_3)|power(#0,const_2)|multiply(n0,#3)|multiply(n3,#4)|subtract(#2,#5)|subtract(#7,#6)|add(#1,#8) | f ( - 1 ) = ( - 1 ) ^ 4 - 4 ( - 1 ) ^ 3 - 2 ( - 1 ) ^ 2 + 5 ( - 1 ) = 1 + 4 - 2 - 5 = - 2 the answer is b . | general |
math_qa__3ySkOiD6xBdLEfn5 | In the junior basketball league there are 18 teams, 2/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad?
Choose the correct choice from the following answers:
A) 4 . B) 6 . C) 7 . D) 8 . E) 10 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">18 * (1/2)</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<result>E</result> | E | 10 | In the junior basketball league there are 18 teams, 2/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad? | {
"A": "4 .",
"B": "6 .",
"C": "7 .",
"D": "8 .",
"E": "10"
} | add(multiply(18, divide(const_1, const_2)), const_1) | divide(const_1,const_2)|multiply(n0,#0)|add(#1,const_1) | otal teams = 18 bad teams = ( 2 / 3 ) * 18 = 12 rich teams = 9 so maximum value that the both rich and bad can take will be 9 . so e = 10 can not be that value . answer : e | general |
math_qa__9viB57jiE2t66BGc | Working alone, John finishes cleaning half the house in a third of the time it takes Nick to clean the entire house alone. John alone cleans the entire house in 6 hours. How many hours will it take Nick and John to clean the entire house if they work together?
Choose the correct answer:
A) 1.5 B) 2 C) 2.4 D) 3 E) 3.6 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 6</gadget>
<output>9</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/6) + (1/9)</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">1 / (5/18)</gadget>
<output>18/5 = around 3.6</output>
<result>E</result> | E | 3.6 | Working alone, John finishes cleaning half the house in a third of the time it takes Nick to clean the entire house alone. John alone cleans the entire house in 6 hours. How many hours will it take Nick and John to clean the entire house if they work together? | {
"A": "1.5",
"B": "2",
"C": "2.4",
"D": "3",
"E": "3.6"
} | inverse(add(inverse(6), inverse(multiply(divide(const_3, const_2), 6)))) | divide(const_3,const_2)|inverse(n0)|multiply(n0,#0)|inverse(#2)|add(#1,#3)|inverse(#4) | answer is 3.6 hours . john does the complete house in 6 hours while nick does it in 9 hours . 1 / ( 1 / 6 + 1 / 9 ) = 3.6 answer is e | physics |
math_qa__JctsJTouHNswUKsZ | The total of 344 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is Choose the correct choice from the following
A) 238
B) 277
C) 278
D) 200
E) 300 | <gadget id="calculator">344 * 25</gadget>
<output>8_600</output>
<gadget id="calculator">71 * 100</gadget>
<output>7_100</output>
<gadget id="calculator">8_600 - 7_100</gadget>
<output>1_500</output>
<gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">1_500 / 5</gadget>
<output>300</output>
<result>E</result> | E | 300 | The total of 344 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is | {
"A": "238",
"B": "277",
"C": "278",
"D": "200",
"E": "300"
} | divide(subtract(multiply(344, 25), multiply(71, const_100)), subtract(25, 20)) | multiply(n0,n2)|multiply(n3,const_100)|subtract(n2,n1)|subtract(#0,#1)|divide(#3,#2) | explanation : let the number of 20 paise coins be x . then the no of 25 paise coins = ( 344 - x ) . 0.20 * ( x ) + 0.25 ( 344 - x ) = 71 = > x = 300 . . answer : e ) 300 | general |
math_qa__dC6fUzhV1kdi0DYh | A man buys a cycle for Rs. 800 and sells it at a loss of 15%. What is the selling price of the cycle? Choose the correct choice from the following options: A) s . 1090 B) s . 1160 C) s . 680 D) s . 520 E) s . 700 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 * 800</gadget>
<output>68_000</output>
<gadget id="calculator">68_000 / 100</gadget>
<output>680</output>
<result>C</result> | C | 680 | A man buys a cycle for Rs. 800 and sells it at a loss of 15%. What is the selling price of the cycle? | {
"A": "s . 1090",
"B": "s . 1160",
"C": "s . 680",
"D": "s . 520",
"E": "s . 700"
} | divide(multiply(subtract(const_100, 15), 800), const_100) | subtract(const_100,n1)|multiply(n0,#0)|divide(#1,const_100)| | "s . p . = 85 % of rs . 800 = rs . 85 / 100 x 800 = rs . 680 answer : c" | gain |
math_qa__sCcX69V8h9GOlHeK | If a * b * c =(√(a + 2)(b + 3)) / (c + 1), find the value of 6 * 15 * 7. Pick one.
A) 8 B) 5 C) 11 D) 3 E) 1.5 | <gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">15 + 3</gadget>
<output>18</output>
<gadget id="calculator">8 * 18</gadget>
<output>144</output>
<gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">12 / 8</gadget>
<output>3/2 = around 1.5</output>
<result>E</result> | E | 1.5 | If a * b * c =(√(a + 2)(b + 3)) / (c + 1), find the value of 6 * 15 * 7. | {
"A": "8",
"B": "5",
"C": "11",
"D": "3",
"E": "1.5"
} | divide(sqrt(multiply(add(6, 2), add(15, 3))), add(7, 1)) | add(n0,n3)|add(n1,n4)|add(n2,n5)|multiply(#0,#1)|sqrt(#3)|divide(#4,#2)| | "6 * 15 * 3 = ( √ ( 6 + 2 ) ( 15 + 3 ) ) / ( 7 + 1 ) = ( √ 8 * 18 ) / 8 = ( √ 144 ) / 8 = 12 / 8 = 1.5 answer is e" | general |
math_qa__KbRi6827PVEeX2zh | How many bricks each measuring 21cm x 10cm x 8cm, will be needed to build a wall 9m x 5m x 18.5m Choose the correct option: A) 4955 B) 4899 C) 4650 D) 7200 E) none of these | <gadget id="calculator">9 * 5</gadget>
<output>45</output>
<gadget id="calculator">45 * 18.5</gadget>
<output>832.5</output>
<gadget id="calculator">21 * 10</gadget>
<output>210</output>
<gadget id="calculator">210 * 8</gadget>
<output>1_680</output>
<gadget id="calculator">1_680 / 100</gadget>
<output>84/5 = around 16.8</output>
<gadget id="calculator">(84/5) / 100</gadget>
<output>21/125 = around 0.168</output>
<gadget id="calculator">832.5 / (21/125)</gadget>
<output>4_955.357143</output>
<result>A</result> | A | 4,955 | How many bricks each measuring 21cm x 10cm x 8cm, will be needed to build a wall 9m x 5m x 18.5m | {
"A": "4955",
"B": "4899",
"C": "4650",
"D": "7200",
"E": "none of these"
} | divide(multiply(multiply(9, 5), 18.5), divide(divide(multiply(multiply(21, 10), 8), const_100), const_100)) | multiply(n3,n4)|multiply(n0,n1)|multiply(n5,#0)|multiply(n2,#1)|divide(#3,const_100)|divide(#4,const_100)|divide(#2,#5)| | "explanation : no . of bricks = volume of the wall / volume of 1 brick = ( 900 x 500 x 18.5 ) / ( 21 x 10 x 8 ) = 4955 answer : a" | physics |
math_qa__5GlbCynt340iYELR | At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price? Select: A) 62.5 B) 62.8 C) 62.1 D) 62.9 E) 32.5 | <gadget id="calculator">47.5 * 25</gadget>
<output>1_187.5</output>
<gadget id="calculator">1_187.5 / 100</gadget>
<output>11.875</output>
<gadget id="calculator">47.5 + 11.875</gadget>
<output>59.375</output>
<gadget id="calculator">59.375 * 100</gadget>
<output>5_937.5</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">5_937.5 / 95</gadget>
<output>62.5</output>
<result>A</result> | A | 62.5 | At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price? | {
"A": "62.5",
"B": "62.8",
"C": "62.1",
"D": "62.9",
"E": "32.5"
} | divide(multiply(add(47.50, divide(multiply(47.50, 25), const_100)), const_100), subtract(const_100, 5)) | multiply(n0,n2)|subtract(const_100,n1)|divide(#0,const_100)|add(n0,#2)|multiply(#3,const_100)|divide(#4,#1)| | "explanation : cp = 47.50 sp = 47.50 * ( 125 / 100 ) = 59.375 mp * ( 95 / 100 ) = 59.375 mp = 62.5 answer : a" | gain |
math_qa__4DUzISqrRGyxCmzY | During a certain two-week period, 64 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 5 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period? Choose the correct choice from the following answers
A) 10 a B) 12 a C) 14 a D) 16 a E) 18 a | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">64 / 6</gadget>
<output>32/3 = around 10.666667</output>
<gadget id="calculator">floor(32/3)</gadget>
<output>10</output>
<result>A</result> | A | 10 | During a certain two-week period, 64 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 5 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period? | {
"A": "10 a",
"B": "12 a",
"C": "14 a",
"D": "16 a",
"E": "18 a"
} | floor(divide(64, add(5, const_1))) | add(n1,const_1)|divide(n0,#0)|floor(#1) | total movies = 100 . comedies = 64 . action + drama = 36 . since there were 5 times as many dramas as action movies , then action + 5 * action = 36 - - > action = a = 6 . comedies = 60 = 10 a . a | general |
math_qa__AKV1jgdMp1AQhFGq | find the greatest 4 digit number which leaves respective remainders of 2 and 5 when divided by 15 and 24 . a . 9974 Pick.
A) 388 B) 282 C) 378 D) 292 E) 281 | <gadget id="calculator">15 * 24</gadget>
<output>360</output>
<gadget id="calculator">5 * 15</gadget>
<output>75</output>
<gadget id="calculator">360 - 75</gadget>
<output>285</output>
<gadget id="calculator">285 - 4</gadget>
<output>281</output>
<result>E</result> | E | 281 | find the greatest 4 digit number which leaves respective remainders of 2 and 5 when divided by 15 and 24 . a . 9974 | {
"A": "388",
"B": "282",
"C": "378",
"D": "292",
"E": "281"
} | subtract(subtract(multiply(15, 24), multiply(5, 15)), const_4) | multiply(n3,n4)|multiply(n2,n3)|subtract(#0,#1)|subtract(#2,const_4) | explanation : since the difference between the divisors and the respective remainders is not constant , back substitution is the convenient method . none of the given numbers is satisfying the condition . answer : e | general |
math_qa__CwPdQgfh29MgieHj | P has $35 more than what Q and R together would have had if both B and C had 1/7 of what P has. How much does P have? Choose the correct choice from the following choices
A) $ 45 B) $ 47 C) $ 49 D) $ 51 E) $ 53 | <gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/7) * 2</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">1 - (2/7)</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">35 / (5/7)</gadget>
<output>49</output>
<result>C</result> | C | 49 | P has $35 more than what Q and R together would have had if both B and C had 1/7 of what P has. How much does P have? | {
"A": "$ 45",
"B": "$ 47",
"C": "$ 49",
"D": "$ 51",
"E": "$ 53"
} | divide(35, subtract(1, multiply(divide(1, 7), const_2))) | divide(n1,n2)|multiply(#0,const_2)|subtract(n1,#1)|divide(n0,#2)| | "p = ( 2 / 7 ) * p + 35 ( 5 / 7 ) * p = 35 p = 49 the answer is c ." | general |
math_qa__6WiRdIhRXXmcGcTk | A can do a work in 20 days and B in 30 days. If they work on it together for 4 days, then the fraction of the work that is left is : Choose the correct option.
A) 1 / 3 B) 2 / 3 C) 4 / 3 D) 5 / 3 E) 7 / 3 | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/20) + (1/30)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 4</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<result>B</result> | B | 0.666667 | A can do a work in 20 days and B in 30 days. If they work on it together for 4 days, then the fraction of the work that is left is : | {
"A": "1 / 3",
"B": "2 / 3",
"C": "4 / 3",
"D": "5 / 3",
"E": "7 / 3"
} | subtract(const_1, multiply(add(divide(const_1, 20), divide(const_1, 30)), 4)) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)| | "ans is : b a ' s 1 day ' s work = 1 / 20 b ' s 1 day ' s work = 1 / 30 ( a + b ) ' s 1 day ' s work = ( 1 / 20 + 1 / 30 ) = 1 / 12 ( a + b ) ' s 4 day ' s work = ( 1 / 12 * 4 ) = 1 / 3 therefore , remaining work = ( 1 - 1 / 3 ) = 2 / 3" | physics |
math_qa__Pn0gA5zNsWYmiJo4 | 3 candidates in an election and received 1136, 7636 and 10628 votes respectively. What % of the total votes did the winning candidate gotin that election? Options:
A) 40 % B) 55 % C) 54.8 % D) 60 % E) 62 % | <gadget id="calculator">1_136 + 7_636</gadget>
<output>8_772</output>
<gadget id="calculator">8_772 + 10_628</gadget>
<output>19_400</output>
<gadget id="calculator">10_628 / 19_400</gadget>
<output>2_657/4_850 = around 0.547835</output>
<gadget id="calculator">(2_657/4_850) * 100</gadget>
<output>5_314/97 = around 54.783505</output>
<result>C</result> | C | 54.8 | 3 candidates in an election and received 1136, 7636 and 10628 votes respectively. What % of the total votes did the winning candidate gotin that election? | {
"A": "40 %",
"B": "55 %",
"C": "54.8 %",
"D": "60 %",
"E": "62 %"
} | multiply(divide(10628, add(add(1136, 7636), 10628)), const_100) | add(n1,n2)|add(n3,#0)|divide(n3,#1)|multiply(#2,const_100)| | "total number of votes polled = ( 1136 + 7636 + 10628 ) = 19400 so , required percentage = 10628 / 19400 * 100 = 54.8 % c" | gain |
math_qa__5VU5HkqG7DPDVRxL | a is the hundreds digit of the 3 digit integer x , b is the tens digit of x , and c is the units digit of x . 4 a = 2 b = c , and a > 0 . what is the difference between the two greatest possible values of x ? tip : dont stop till you have exhausted all answer choices to arrive at the correct one . Answers.
A) 124
B) 297
C) 394
D) 421
E) 842 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 * 10</gadget>
<output>120</output>
<gadget id="calculator">120 + 4</gadget>
<output>124</output>
<result>A</result> | A | 124 | a is the hundreds digit of the 3 digit integer x , b is the tens digit of x , and c is the units digit of x . 4 a = 2 b = c , and a > 0 . what is the difference between the two greatest possible values of x ? tip : dont stop till you have exhausted all answer choices to arrive at the correct one . | {
"A": "124",
"B": "297",
"C": "394",
"D": "421",
"E": "842"
} | add(multiply(multiply(4, 3), const_10), 4) | multiply(n0,n1)|multiply(#0,const_10)|add(n1,#1) | ratio of a : b : c = 1 : 2 : 4 two possible greatest single digit values for c are 8 and 4 if c is 8 , then x = 248 if c is 4 , then x = 124 difference = 248 - 124 = 124 a is the answer | general |
math_qa__5YqOiie4qVmPXP6c | If Albert’s monthly earnings rise by 27%, he would earn $567. If, instead, his earnings rise by only 26%, how much (in $) would he earn this month? Choose the correct answer:
A) 643 B) 652 C) 562 D) 578 E) 693 | <gadget id="calculator">27 / 100</gadget>
<output>27/100 = around 0.27</output>
<gadget id="calculator">1 + (27/100)</gadget>
<output>127/100 = around 1.27</output>
<gadget id="calculator">567 / (127/100)</gadget>
<output>56_700/127 = around 446.456693</output>
<gadget id="calculator">26 / 100</gadget>
<output>13/50 = around 0.26</output>
<gadget id="calculator">1 + (13/50)</gadget>
<output>63/50 = around 1.26</output>
<gadget id="calculator">(56_700/127) * (63/50)</gadget>
<output>71_442/127 = around 562.535433</output>
<result>C</result> | C | 562 | If Albert’s monthly earnings rise by 27%, he would earn $567. If, instead, his earnings rise by only 26%, how much (in $) would he earn this month? | {
"A": "643",
"B": "652",
"C": "562",
"D": "578",
"E": "693"
} | multiply(divide(567, add(const_1, divide(27, const_100))), add(const_1, divide(26, const_100))) | divide(n2,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|divide(n1,#3)|multiply(#2,#4)| | "= 567 / 1.27 ∗ 1.26 = 562 = 562 answer is c" | gain |
math_qa__xxOGUBjJuNxqTypm | Indu gave Bindu Rs.1250 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest? Choose the correct option.
A) 5 B) 2 C) 9 D) 5 E) 1 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">1_250 * (676/625)</gadget>
<output>1_352</output>
<gadget id="calculator">1_352 - 1_250</gadget>
<output>102</output>
<gadget id="calculator">1_250 * (1/25)</gadget>
<output>50</output>
<gadget id="calculator">50 * 2</gadget>
<output>100</output>
<gadget id="calculator">102 - 100</gadget>
<output>2</output>
<result>B</result> | B | 2 | Indu gave Bindu Rs.1250 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest? | {
"A": "5",
"B": "2",
"C": "9",
"D": "5",
"E": "1"
} | subtract(subtract(multiply(1250, power(add(const_1, divide(4, const_100)), 2)), 1250), multiply(multiply(1250, divide(4, const_100)), 2)) | divide(n2,const_100)|add(#0,const_1)|multiply(n0,#0)|multiply(n1,#2)|power(#1,n1)|multiply(n0,#4)|subtract(#5,n0)|subtract(#6,#3)| | "1250 = d ( 100 / 4 ) 2 d = 2 answer : b" | gain |
math_qa__7Ki5ymPo8FOSXs2d | When n is divided by 24, the remainder is 4. What is the remainder when 4n is divided by 8? Choose the correct option: A) 3 B) 4 C) 5 D) 0 E) 7 | <gadget id="calculator">4 % 8</gadget>
<output>4</output>
<gadget id="calculator">4 - 4</gadget>
<output>0</output>
<result>D</result> | D | 0 | When n is divided by 24, the remainder is 4. What is the remainder when 4n is divided by 8? | {
"A": "3",
"B": "4",
"C": "5",
"D": "0",
"E": "7"
} | subtract(4, reminder(4, 8)) | reminder(n2,n3)|subtract(n1,#0)| | "let n = 4 ( leaves a remainder of 4 when divided by 24 ) 4 n = 4 ( 4 ) = 16 , which leaves a remainder of 0 when divided by 8 . answer d" | general |
math_qa__q5w8eB4jNW6PrbhD | Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 3 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 8 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered? Choose the most appropriate option
A) 60 B) 72 C) 84 D) 96 E) 108 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">2 - (2/5)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(8/5) * 60</gadget>
<output>96</output>
<result>D</result> | D | 96 | Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 3 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 8 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered? | {
"A": "60",
"B": "72",
"C": "84",
"D": "96",
"E": "108"
} | multiply(subtract(divide(multiply(const_2, const_2), subtract(8, multiply(const_2, 3))), divide(const_2, subtract(8, 3))), const_60) | multiply(const_2,const_2)|multiply(n0,const_2)|subtract(n1,n0)|divide(const_2,#2)|subtract(n1,#1)|divide(#0,#4)|subtract(#5,#3)|multiply(#6,const_60)| | "d is the answer . . . . d = ts where d = distance , t = time and s = speed to travel half distance , ( 2 + 3 t ) = 8 t = = > t = 2 / 5 = = > 24 minutes to travel double distance , 2 ( 2 + 3 t ) = 8 t = = > 2 = = > 120 minutes difference , 96 minutes d" | physics |
math_qa__kr6fKlGYTvTBWhZs | 35 - [23 - {15 - x}] = 12 × 2 ÷ 1/2 Choose the correct choice
A) 34 B) 32 C) 17 D) 27 E) 28 | <gadget id="calculator">35 - 3</gadget>
<output>32</output>
<result>B</result> | B | 32 | 35 - [23 - {15 - x}] = 12 × 2 ÷ 1/2 | {
"A": "34",
"B": "32",
"C": "17",
"D": "27",
"E": "28"
} | subtract(35, const_3) | subtract(n0,const_3) | explanation : 35 - [ 23 - { 19 - ( 15 - x ) } ] = 12 × 2 × 2 = 48 = > 35 - 23 + ( 19 - 15 + x ) = 48 = > 12 + 4 + x = 48 = > x = 48 - ( 4 + 12 ) = 32 answer : option b | general |
math_qa__F6taM1lmgmgRmjIn | If n is an integer, f(n) = f(n-1) - n and f(4)=20. What is the value of f(6)? Choose the correct choice from the following options:
A) 9 B) 0 C) 1 D) 2 E) 4 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">20 - 5</gadget>
<output>15</output>
<gadget id="calculator">15 - 6</gadget>
<output>9</output>
<result>A</result> | A | 9 | If n is an integer, f(n) = f(n-1) - n and f(4)=20. What is the value of f(6)? | {
"A": "9",
"B": "0",
"C": "1",
"D": "2",
"E": "4"
} | subtract(subtract(20, add(1, 4)), 6) | add(n0,n1)|subtract(n2,#0)|subtract(#1,n3)| | "since f ( n ) = f ( n - 1 ) - n then : f ( 6 ) = f ( 5 ) - 6 and f ( 5 ) = f ( 4 ) - 5 . as given that f ( 4 ) = 20 then f ( 5 ) = 20 - 5 = 15 - - > substitute the value of f ( 5 ) back into the first equation : f ( 6 ) = f ( 5 ) - 6 = 15 - 6 = 9 . answer : a . questions on funtions to practice :" | general |
math_qa__53U8kQZJI1v9teWN | what is the smallest 5 digit number that is divisible by 15 , 32 , 45 , and 54 ? Choose the correct choice from the following options.
A) 11260 B) 11860 C) 12360 D) 12960 E) 13560 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">lcm(5, 15)</gadget>
<output>15</output>
<gadget id="calculator">lcm(15, 32)</gadget>
<output>480</output>
<gadget id="calculator">lcm(480, 45)</gadget>
<output>1_440</output>
<gadget id="calculator">lcm(1_440, 54)</gadget>
<output>4_320</output>
<gadget id="calculator">10_000 % 4_320</gadget>
<output>1_360</output>
<gadget id="calculator">4_320 - 1_360</gadget>
<output>2_960</output>
<gadget id="calculator">10_000 + 2_960</gadget>
<output>12_960</output>
<result>D</result> | D | 12,960 | what is the smallest 5 digit number that is divisible by 15 , 32 , 45 , and 54 ? | {
"A": "11260",
"B": "11860",
"C": "12360",
"D": "12960",
"E": "13560"
} | add(multiply(const_100, const_100), subtract(lcm(lcm(lcm(lcm(5, 15), 32), 45), 54), reminder(multiply(const_100, const_100), lcm(lcm(lcm(lcm(5, 15), 32), 45), 54)))) | lcm(n0,n1)|multiply(const_100,const_100)|lcm(n2,#0)|lcm(n3,#2)|lcm(n4,#3)|reminder(#1,#4)|subtract(#4,#5)|add(#1,#6) | 15 = 3 * 5 32 = 2 ^ 5 45 = 3 ^ 2 * 5 54 = 2 * 3 ^ 3 lcm = 2 ^ 5 * 3 ^ 3 * 5 = 4320 the smallest five - digit number that is a multiple of 4320 is 3 * 4320 = 12,960 the answer is d . | general |
math_qa__ooxqAQm4AreTO1On | Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 45 km/hr. For how many minutes does the bus stop per hour? Answers:
A) 15
B) 88
C) 77
D) 20
E) 99 | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">45 / 60</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 60</gadget>
<output>45</output>
<gadget id="calculator">60 - 45</gadget>
<output>15</output>
<result>A</result> | A | 15 | Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 45 km/hr. For how many minutes does the bus stop per hour? | {
"A": "15",
"B": "88",
"C": "77",
"D": "20",
"E": "99"
} | subtract(multiply(const_1, const_60), multiply(divide(45, 60), const_60)) | divide(n1,n0)|multiply(const_1,const_60)|multiply(#0,const_60)|subtract(#1,#2)| | "in 1 hr , the bus covers 60 km without stoppages and 45 km with stoppages . stoppage time = time take to travel ( 60 - 45 ) km i . e 15 km at 60 km / hr . stoppage time = 15 / 60 hrs = 15 min . answer : a" | general |
math_qa__UBsVaihJeV0dgUGK | A rectangular courty 3.78 metres long and 5.25 metres wide is to be paved exactly with square tiles, all of the same size. What is the largest size of the tile which could be used for the purpose ?
Choose the correct choice from the following
A) 14 cms B) 21 cms C) 42 cms D) none of these E) can not be determined | <gadget id="calculator">100 * 3.78</gadget>
<output>378</output>
<gadget id="calculator">378 / 3</gadget>
<output>126</output>
<gadget id="calculator">126 / 3</gadget>
<output>42</output>
<gadget id="calculator">42 / 3</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<result>B</result> | B | 21 | A rectangular courty 3.78 metres long and 5.25 metres wide is to be paved exactly with square tiles, all of the same size. What is the largest size of the tile which could be used for the purpose ? | {
"A": "14 cms",
"B": "21 cms",
"C": "42 cms",
"D": "none of these",
"E": "can not be determined"
} | multiply(divide(divide(divide(divide(multiply(const_100, 3.78), const_3), const_3), const_3), const_2), const_3) | multiply(n0,const_100)|divide(#0,const_3)|divide(#1,const_3)|divide(#2,const_3)|divide(#3,const_2)|multiply(#4,const_3) | solution largest size of the tile . h . c . f of 378 cm and 525 cm = 21 cms . answer b | geometry |
math_qa__EuCMvIKrPz6Bwnyi | The diagonal of a rhombus are 80 m and 120m. Its area is: Choose the correct option:
A) 4500
B) 4000
C) 4800
D) 4600
E) 4320 | <gadget id="calculator">(80 * 120) / 2</gadget>
<output>4_800</output>
<result>C</result> | C | 4,800 | The diagonal of a rhombus are 80 m and 120m. Its area is: | {
"A": "4500",
"B": "4000",
"C": "4800",
"D": "4600",
"E": "4320"
} | rhombus_area(80, 120) | rhombus_area(n0,n1)| | "area of the rhombus = 1 / 2 d 1 d 2 = ( 1 / 2 ã — 80 ã — 120 ) cm ( power ) 2 = 80 ã — 60 = 4800 cm ( power ) 2 answer is c ." | geometry |
math_qa__6bSEeGImjXBep5hQ | 3 bodies x , y and z start moving around a circular track of length 960 m from the same point simultaneously in the same direction at speeds of 12 m / s , 20 m / s and 36 m / s respectively . when will they meet for the first time after they started moving ? Choose the correct choice from the following answers.
A) 240 seconds B) 120 seconds C) 60 seconds D) 180 seconds E) 100 seconds | <gadget id="calculator">20 - 12</gadget>
<output>8</output>
<gadget id="calculator">960 / 8</gadget>
<output>120</output>
<result>B</result> | B | 120 | 3 bodies x , y and z start moving around a circular track of length 960 m from the same point simultaneously in the same direction at speeds of 12 m / s , 20 m / s and 36 m / s respectively . when will they meet for the first time after they started moving ? | {
"A": "240 seconds",
"B": "120 seconds",
"C": "60 seconds",
"D": "180 seconds",
"E": "100 seconds"
} | divide(960, subtract(20, 12)) | subtract(n3,n2)|divide(n1,#0) | if they all meet after t seconds , it means they covered the distances 12 t , 20 t , and 36 t respectively . since they all arrive to the same spot , it means that the differences taken pairwise between the distances must be positive integer multiples of the length of the track , which is 960 m . so , 8 t , 16 t , and 24 t must all be multiples of 960 . 8 t multiple of 960 means t multiple of 120 . the smallest t with this property is 120 and is on the list of answers . answer b . | physics |
math_qa__rkMzrUqwfHUzSQlQ | A part of certain sum of money is invested at 10% per annum and the rest at 12% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
Choose the correct choice from the following answers.
A) 4 : 2
B) 4 : 8
C) 4 : 3
D) 4 : 0
E) 6 : 5 | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) * 10</gadget>
<output>6/5 = around 1.2</output>
<result>E</result> | E | 1.2 | A part of certain sum of money is invested at 10% per annum and the rest at 12% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is? | {
"A": "4 : 2",
"B": "4 : 8",
"C": "4 : 3",
"D": "4 : 0",
"E": "6 : 5"
} | multiply(divide(12, const_100), 10) | divide(n1,const_100)|multiply(n0,#0)| | "12 : 10 = 6 : 5 answer : e" | gain |
math_qa__ubBf2BSLHDKNFZSf | Kelly and Chris are moving into a new city. Both of them love books and thus packed several boxes with books. If Chris packed 60% of the total number of boxes, what was the ratio of the number of boxes Kelly packed to the number of boxes Chris packed? Choose the correct choice from the following choices.
A) 4 / 3
B) 2 / 3
C) 1 / 3
D) 3 / 4
E) 1 / 4 | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 / 60</gadget>
<output>2/3 = around 0.666667</output>
<result>B</result> | B | 0.666667 | Kelly and Chris are moving into a new city. Both of them love books and thus packed several boxes with books. If Chris packed 60% of the total number of boxes, what was the ratio of the number of boxes Kelly packed to the number of boxes Chris packed? | {
"A": "4 / 3",
"B": "2 / 3",
"C": "1 / 3",
"D": "3 / 4",
"E": "1 / 4"
} | divide(subtract(const_100, 60), 60) | subtract(const_100,n0)|divide(#0,n0) | the ratio of the number of boxes kelly packed to the number of boxes chris packed = 40 / 60 = 2 / 3 answer : b | other |
math_qa__FSovqVkhjFkKQcK1 | There are 6 more women than there are men on a local co-ed softball team. If there are a total of 24 players on the team, what is the ratio of men to women? Choose the correct answer:
A) 10 / 16 B) 9 / 15 C) 4 / 16 D) 6 / 10 E) 4 / 10 | <gadget id="calculator">24 - 6</gadget>
<output>18</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">9 + 6</gadget>
<output>15</output>
<gadget id="calculator">9 / 15</gadget>
<output>3/5 = around 0.6</output>
<result>B</result> | B | 0.6 | There are 6 more women than there are men on a local co-ed softball team. If there are a total of 24 players on the team, what is the ratio of men to women? | {
"A": "10 / 16",
"B": "9 / 15",
"C": "4 / 16",
"D": "6 / 10",
"E": "4 / 10"
} | divide(divide(subtract(24, 6), add(const_1, const_1)), add(divide(subtract(24, 6), add(const_1, const_1)), 6)) | add(const_1,const_1)|subtract(n1,n0)|divide(#1,#0)|add(n0,#2)|divide(#2,#3)| | "w = m + 6 w + m = 24 m + 6 + m = 24 2 m = 18 m = 9 w = 15 ratio : 9 : 15 ans : b" | general |
math_qa__5DY3oPg9Fe1OgNEg | Two cars start at the same time from opposite ends of a highway that is 60 miles long. One car is riding at 13 mph and the second car is riding at 17 mph. How long after they begin will they meet? Select the correct option
A) 0.75
B) 1
C) 1.25
D) 1.5
E) 2.0 | <gadget id="calculator">13 + 17</gadget>
<output>30</output>
<gadget id="calculator">60 / 30</gadget>
<output>2</output>
<result>E</result> | E | 2 | Two cars start at the same time from opposite ends of a highway that is 60 miles long. One car is riding at 13 mph and the second car is riding at 17 mph. How long after they begin will they meet? | {
"A": "0.75",
"B": "1",
"C": "1.25",
"D": "1.5",
"E": "2.0"
} | divide(60, add(13, 17)) | add(n1,n2)|divide(n0,#0)| | "as cars are moving in opposite directions their speeds will be added . so their relative speeds : 17 + 13 = 30 mph total distance to be covered = 60 miles . time taken would be : 60 miles / 30 mph = 2.0 hours e is the answer ." | physics |
math_qa__WpbcSdUXK2DfGg6s | (x + 6) is a factor in x^2 - mx - 42. What is the value of m? Pick: A) 2 B) 2.2 C) 1 D) 4 E) 5 | <gadget id="calculator">42 / 6</gadget>
<output>7</output>
<gadget id="calculator">7 - 6</gadget>
<output>1</output>
<result>C</result> | C | 1 | (x + 6) is a factor in x^2 - mx - 42. What is the value of m? | {
"A": "2",
"B": "2.2",
"C": "1",
"D": "4",
"E": "5"
} | subtract(divide(42, 6), 6) | divide(n2,n0)|subtract(#0,n0) | i solved the second degree equation and found it like this : x ^ 2 - mx - 42 = 0 ( x - 7 ) ( x + 6 ) = 0 x = 7 or x = - 6 substituting both values for x in the equation we find : x ^ 2 - mx - 42 = > ( - 6 ) ^ 2 - m ( - 6 ) = 42 = > 36 + 6 m = 42 = > 6 m = 42 - 36 = 6 = > m = 1 and with 7 , using a similar process we end up with : ( 7 ) ^ 2 - m ( 7 ) = 42 - 7 m = 42 - 49 = - 7 m = - 1 ao , ans c | general |
math_qa__MP5SfXdD563fRZLt | A rectangular field has a length 10 meters more than it is width. If the area of the field is 144, what is the length (in meters) of the rectangular field? Choose the most appropriate option.
A) 16 B) 18 C) 20 D) 22 E) 24 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">144 / 10</gadget>
<output>72/5 = around 14.4</output>
<gadget id="calculator">(72/5) / 2</gadget>
<output>36/5 = around 7.2</output>
<gadget id="calculator">(1/3) + (36/5)</gadget>
<output>113/15 = around 7.533333</output>
<gadget id="calculator">(1/4) + (113/15)</gadget>
<output>467/60 = around 7.783333</output>
<gadget id="calculator">10 + (467/60)</gadget>
<output>1_067/60 = around 17.783333</output>
<result>B</result> | B | 18 | A rectangular field has a length 10 meters more than it is width. If the area of the field is 144, what is the length (in meters) of the rectangular field? | {
"A": "16",
"B": "18",
"C": "20",
"D": "22",
"E": "24"
} | add(10, add(const_0_25, add(const_0_33, divide(divide(144, 10), const_2)))) | divide(n1,n0)|divide(#0,const_2)|add(#1,const_0_33)|add(#2,const_0_25)|add(n0,#3)| | "area = l * w = ( l ) * ( l - 10 ) = 171 trial and error : 20 * 10 = 200 ( too high ) 19 * 9 = 171 ( too high ) 18 * 8 = 144 the length is 18 meters . the answer is b ." | geometry |
math_qa__cZkSSbrsqmTApoed | add 15% of 25 and 12% of 45. Pick one.
A) 9.2 B) 10.5 C) 11.5 D) 12.3 E) 15 | <gadget id="calculator">15 * 25</gadget>
<output>375</output>
<gadget id="calculator">375 / 100</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">12 * 45</gadget>
<output>540</output>
<gadget id="calculator">540 / 100</gadget>
<output>27/5 = around 5.4</output>
<gadget id="calculator">(15/4) + (27/5)</gadget>
<output>183/20 = around 9.15</output>
<result>A</result> | A | 9.2 | add 15% of 25 and 12% of 45. | {
"A": "9.2",
"B": "10.5",
"C": "11.5",
"D": "12.3",
"E": "15"
} | add(divide(multiply(15, 25), const_100), divide(multiply(12, 45), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3) | 15 % of 25 + 12 % of 45 25 * 15 / 100 + 45 * 12 / 100 3.8 + 5.4 = 9.2 answer a | gain |
math_qa__HxtI883cFda1S1LN | An equilateral triangle T2 is formed by joining the mid points of the sides of another equilateral triangle T1. A third equilateral triangle T3 is formed by joining the mid-points of T2 and this process is continued indefinitely. If each side of T1 is 45 cm, find the sum of the perimeters of all the triangles.
Choose the correct answer:
A) 180 cm B) 220 cm C) 240 cm D) 270 cm E) 300 cm | <gadget id="calculator">45 + 45 + 45</gadget>
<output>135</output>
<gadget id="calculator">135 + 135</gadget>
<output>270</output>
<result>D</result> | D | 270 | An equilateral triangle T2 is formed by joining the mid points of the sides of another equilateral triangle T1. A third equilateral triangle T3 is formed by joining the mid-points of T2 and this process is continued indefinitely. If each side of T1 is 45 cm, find the sum of the perimeters of all the triangles. | {
"A": "180 cm",
"B": "220 cm",
"C": "240 cm",
"D": "270 cm",
"E": "300 cm"
} | add(triangle_perimeter(45, 45, 45), triangle_perimeter(45, 45, 45)) | triangle_perimeter(n5,n5,n5)|add(#0,#0)| | "we have 45 for first triangle , when we join mid - points of first triangle we get the second equilateral triangle then the length of second one is 22.5 and continues . so we have 45 , 22.5 , 11.25 , . . . we have ratio = 1 / 2 , and it is gp type . sum of infinite triangle is a / 1 - r = 45 / 1 - ( 1 / 2 ) = 90 equilateral triangle perimeter is 3 a = 3 * 90 = 270 . so option d ." | geometry |
math_qa__sZSjE5gRyKUnT7WG | If a 10 percent deposit that has been paid toward the purchase of a certain product is $120, how much more remains to be paid? Choose the most appropriate option.
A) $ 880 B) $ 990 C) $ 1,000 D) $ 1,100 E) $ 1,080 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">120 * 10</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 - 120</gadget>
<output>1_080</output>
<result>E</result> | E | 1,080 | If a 10 percent deposit that has been paid toward the purchase of a certain product is $120, how much more remains to be paid? | {
"A": "$ 880",
"B": "$ 990",
"C": "$ 1,000",
"D": "$ 1,100",
"E": "$ 1,080"
} | subtract(multiply(120, divide(const_100, 10)), 120) | divide(const_100,n0)|multiply(n1,#0)|subtract(#1,n1)| | "10 / 100 p = 120 > > p = 120 * 100 / 10 = 1200 1200 - 120 = 1080 answer : e" | general |
math_qa__817gHtWKVXVrKhrk | A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 2, 4 and 6, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created? Select
A) 27 B) 22 C) 24 D) 26 E) 30 | <gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">27 - 1</gadget>
<output>26</output>
<result>A</result> | A | 27 | A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 2, 4 and 6, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created? | {
"A": "27",
"B": "22",
"C": "24",
"D": "26",
"E": "30"
} | subtract(power(3, 3), const_1) | power(n0,n0)|subtract(#0,const_1)| | "total # of codes possible is 3 * 3 * 3 = 27 . oit of those 27 codes answer : a" | general |
math_qa__bM6fgRNH2Sx6wtJs | A is twice as good a workman as B and they took 6 days together to do the work B alone can do it in? Select the correct option:
A) 25 days B) 18 days C) 21 days D) 11 days E) 13 days | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<result>B</result> | B | 18 | A is twice as good a workman as B and they took 6 days together to do the work B alone can do it in? | {
"A": "25 days",
"B": "18 days",
"C": "21 days",
"D": "11 days",
"E": "13 days"
} | multiply(divide(multiply(6, add(const_2, const_1)), const_2), const_2) | add(const_1,const_2)|multiply(n0,#0)|divide(#1,const_2)|multiply(#2,const_2)| | "wc = 2 : 1 2 x + x = 1 / 6 x = 1 / 18 = > 18 days answer : b" | physics |
math_qa__BSuSoYfaywQ9ZoJw | How many even multiples of 15 are there between 149 and 301? Choose the correct option:
A) 5
B) 6
C) 9
D) 10
E) 11 | <gadget id="calculator">301 - 149</gadget>
<output>152</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">152 / 30</gadget>
<output>76/15 = around 5.066667</output>
<gadget id="calculator">(76/15) + 1</gadget>
<output>91/15 = around 6.066667</output>
<result>B</result> | B | 6 | How many even multiples of 15 are there between 149 and 301? | {
"A": "5",
"B": "6",
"C": "9",
"D": "10",
"E": "11"
} | add(divide(subtract(301, 149), multiply(15, const_2)), const_1) | multiply(n0,const_2)|subtract(n2,n1)|divide(#1,#0)|add(#2,const_1)| | "150 = 10 * 15 300 = 20 * 15 the even multiples are 15 multiplied by 10 , 12 , 14 , 16 , 18 , and 20 for a total of 6 . the answer is b ." | general |
math_qa__raH2hU4vDTgiRlaU | What least number should be added to 1101, so that the sum is completely divisible by 24 Choose the correct choice from the following
A) 4 B) 1 C) 2 D) 3 E) 5 | <gadget id="calculator">1_101 % 24</gadget>
<output>21</output>
<gadget id="calculator">24 - 21</gadget>
<output>3</output>
<result>D</result> | D | 3 | What least number should be added to 1101, so that the sum is completely divisible by 24 | {
"A": "4",
"B": "1",
"C": "2",
"D": "3",
"E": "5"
} | subtract(24, reminder(1101, 24)) | reminder(n0,n1)|subtract(n1,#0)| | "explanation : ( 1056 / 24 ) gives remainder 21 21 + 3 = 24 , so we need to add 3 . answer : option d" | general |
math_qa__4usf2ZFJfNLOIFhS | how many 3 digit no ' s are between 100 - 500 , where sum of two digit is 3 rd ? Choose the correct choice from the following choices: A) 24 B) 54 C) 60 D) 84 E) 94 | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">500 / 100</gadget>
<output>5</output>
<gadget id="calculator">8 - 5</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 + 8</gadget>
<output>12</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<result>C</result> | C | 60 | how many 3 digit no ' s are between 100 - 500 , where sum of two digit is 3 rd ? | {
"A": "24",
"B": "54",
"C": "60",
"D": "84",
"E": "94"
} | multiply(divide(multiply(add(add(subtract(add(const_4, const_4), divide(500, const_100)), const_1), add(const_4, const_4)), divide(500, const_100)), subtract(3, const_1)), const_2) | add(const_4,const_4)|divide(n2,const_100)|subtract(n0,const_1)|subtract(#0,#1)|add(#3,const_1)|add(#4,#0)|multiply(#5,#1)|divide(#6,#2)|multiply(#7,const_2) | total permutations possible = 18 + 16 + 14 + 12 = 60 answer : c | general |
math_qa__cUlcz8sFaY1cuW3f | Find the perimeter and area of a square of side 19 cm. Choose the correct choice from the following answers.
A) 324
B) 361
C) 400
D) 441
E) 484 | <gadget id="calculator">19 ** 2</gadget>
<output>361</output>
<result>B</result> | B | 361 | Find the perimeter and area of a square of side 19 cm. | {
"A": "324",
"B": "361",
"C": "400",
"D": "441",
"E": "484"
} | square_area(19) | square_area(n0)| | "we know that the perimeter of square = 4 ã — side side = 19 cm therefore , perimeter = 4 ã — 19 cm = 76 cm now , area of the square = ( side ã — side ) sq . units = 19 ã — 19 cm â ² = 361 cm â ² answer : b" | geometry |
math_qa__uDsoZeBaSHypcKxX | In a mixture of 45 litres the ratio of milk to water is 4:1. Additional 21 litres of water is added to the mixture. Find the ratio of milk to water in the resulting mixture. Choose the correct option
A) 2 / 1 B) 4 / 1 C) 6 / 5 D) 3 / 4 E) 3 / 2 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">45 / 5</gadget>
<output>9</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">9 + 21</gadget>
<output>30</output>
<gadget id="calculator">36 / 30</gadget>
<output>6/5 = around 1.2</output>
<result>C</result> | C | 1.2 | In a mixture of 45 litres the ratio of milk to water is 4:1. Additional 21 litres of water is added to the mixture. Find the ratio of milk to water in the resulting mixture. | {
"A": "2 / 1",
"B": "4 / 1",
"C": "6 / 5",
"D": "3 / 4",
"E": "3 / 2"
} | divide(subtract(45, divide(45, add(4, 1))), add(divide(45, add(4, 1)), 21)) | add(n1,n2)|divide(n0,#0)|add(n3,#1)|subtract(n0,#1)|divide(#3,#2)| | "given that milk / water = 4 x / x and 4 x + x = 45 - - > x = 9 . thus milk = 4 x = 36 liters and water = x = 9 liters . new ratio = 36 / ( 9 + 21 ) = 36 / 30 = 6 / 5 . answer : c ." | general |
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