id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__92nrzdzBaxrtYKii | let raj be 3 years older than ravi and hema be two years younger than ravi . raj is 3 times as old as rahul who is hema ’ s brother . the ratio of the ages of hema and her brother is 3 : 2 . find by how much percentage raj ’ s age is more than hema ’ s when raj will be 20 years old . Choose the most appropriate option.
A) 33.33
B) 27.33
C) 28.38
D) 29.37
E) 28.31 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">3 - (3/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">5 / (3/2)</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">3 * (10/3)</gadget>
<output>10</output>
<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">5 + 10</gadget>
<output>15</output>
<gadget id="calculator">5 / 15</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>A</result> | A | 33.33 | let raj be 3 years older than ravi and hema be two years younger than ravi . raj is 3 times as old as rahul who is hema ’ s brother . the ratio of the ages of hema and her brother is 3 : 2 . find by how much percentage raj ’ s age is more than hema ’ s when raj will be 20 years old . | {
"A": "33.33",
"B": "27.33",
"C": "28.38",
"D": "29.37",
"E": "28.31"
} | multiply(divide(add(3, const_2), add(subtract(multiply(3, divide(add(3, const_2), subtract(3, divide(3, 2)))), add(3, const_2)), subtract(20, multiply(3, divide(add(3, const_2), subtract(3, divide(3, 2))))))), const_100) | add(n0,const_2)|divide(n0,n3)|subtract(n0,#1)|divide(#0,#2)|multiply(n0,#3)|subtract(#4,#0)|subtract(n4,#4)|add(#5,#6)|divide(#0,#7)|multiply(#8,const_100) | answer : 33.33 | general |
math_qa__5QmWBpKFZwGT4svh | The salaries of A and B together amount to $6000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary? Answers
A) $ 1000 B) $ 1250 C) $ 2500 D) $ 4500 E) $ 5200 | <gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">100 - 95</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">6_000 / 4</gadget>
<output>1_500</output>
<gadget id="calculator">6_000 - 1_500</gadget>
<output>4_500</output>
<result>D</result> | D | 4,500 | The salaries of A and B together amount to $6000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary? | {
"A": "$ 1000",
"B": "$ 1250",
"C": "$ 2500",
"D": "$ 4500",
"E": "$ 5200"
} | subtract(6000, divide(6000, add(divide(subtract(const_100, 85), subtract(const_100, 95)), const_1))) | subtract(const_100,n2)|subtract(const_100,n1)|divide(#0,#1)|add(#2,const_1)|divide(n0,#3)|subtract(n0,#4)| | "let a ' s salary is x b ' s salary = 6000 - x ( 100 - 95 ) % of x = ( 100 - 85 ) % of ( 6000 - x ) x = $ 4500 answer is d" | gain |
math_qa__9tgNaHgDLKt0jhxz | Gopi gives Rs. 90 plus one turban as salary to his servant for one year. The servant leaves after 9 months and receives Rs. 50 and the turban. Find the price of the turban.
Answers:
A) 27 B) 36 C) 29 D) 10 E) 70 | <gadget id="calculator">90 - 50</gadget>
<output>40</output>
<gadget id="calculator">12 - 9</gadget>
<output>3</output>
<gadget id="calculator">40 / 3</gadget>
<output>40/3 = around 13.333333</output>
<gadget id="calculator">(40/3) * 12</gadget>
<output>160</output>
<gadget id="calculator">160 - 90</gadget>
<output>70</output>
<result>E</result> | E | 70 | Gopi gives Rs. 90 plus one turban as salary to his servant for one year. The servant leaves after 9 months and receives Rs. 50 and the turban. Find the price of the turban. | {
"A": "27",
"B": "36",
"C": "29",
"D": "10",
"E": "70"
} | subtract(multiply(divide(subtract(90, 50), subtract(const_12, 9)), const_12), 90) | subtract(n0,n2)|subtract(const_12,n1)|divide(#0,#1)|multiply(#2,const_12)|subtract(#3,n0)| | "let the price of turban be x . thus , for one year the salary = ( 90 + x ) for 9 months he should earn 3434 ( 90 + x ) . now he gets one turban and rs . 50 . thus , 3434 ( 90 + x ) = 50 + x or 270 + 3 x = 200 + 4 x or x = 70 answer : e" | general |
math_qa__E61wcl9kZCvg5qU4 | The diagonal of a rectangle is cm and its area is 20 sq. cm. The perimeter of the rectangle must be: Choose the correct choice from the following answers:
A) 18 B) 77 C) 625 D) 276 E) 191 | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">40 + 1</gadget>
<output>41</output>
<gadget id="calculator">40 + 41</gadget>
<output>81</output>
<gadget id="calculator">81 ** (1/2)</gadget>
<output>9</output>
<gadget id="calculator">2 * 9</gadget>
<output>18</output>
<result>A</result> | A | 18 | The diagonal of a rectangle is cm and its area is 20 sq. cm. The perimeter of the rectangle must be: | {
"A": "18",
"B": "77",
"C": "625",
"D": "276",
"E": "191"
} | multiply(const_2, sqrt(add(add(20, 20), add(add(20, 20), const_1)))) | add(n0,n0)|add(#0,const_1)|add(#0,#1)|sqrt(#2)|multiply(#3,const_2) | explanation : ( or ) { \ color { black } l ^ { 2 } + b ^ { 2 } = 41 } also , { \ color { black } ( l + b ) ^ { 2 } = l ^ { 2 } + b ^ { 2 } + 2 lb } = 41 + 40 = 81 ( l + b ) = 9 . perimeter = 2 ( l + b ) = 18 cm . answer : a ) 18 | geometry |
math_qa__iCzPkKz0H7yNRdLG | An empty fuel tank with a capacity of 214 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added?
Choose one: A) 160 B) 150 C) 100 D) 80 E) 106 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">214 * (4/25)</gadget>
<output>856/25 = around 34.24</output>
<gadget id="calculator">(856/25) - 30</gadget>
<output>106/25 = around 4.24</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(4/25) - (3/25)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(106/25) / (1/25)</gadget>
<output>106</output>
<result>E</result> | E | 106 | An empty fuel tank with a capacity of 214 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added? | {
"A": "160",
"B": "150",
"C": "100",
"D": "80",
"E": "106"
} | divide(subtract(multiply(214, divide(16, const_100)), 30), subtract(divide(16, const_100), divide(12, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n3)|divide(#4,#3) | say there are a gallons of fuel a in the tank , then there would be 214 - a gallons of fuel b . the amount of ethanol in a gallons of fuel a is 0.12 a ; the amount of ethanol in 214 - a gallons of fuel b is 0.16 ( 214 - a ) ; since the total amount of ethanol is 30 gallons then 0.12 a + 0.16 ( 214 - a ) = 30 - - > a = 106 . answer : e . | gain |
math_qa__AZBNcyZ6RVGUfOtR | If 27.5% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class?
Choose the correct choice from the following:
A) 638 B) 330 C) 550 D) 430 E) 880 | <gadget id="calculator">880 / 100</gadget>
<output>44/5 = around 8.8</output>
<gadget id="calculator">100 - 27.5</gadget>
<output>72.5</output>
<gadget id="calculator">(44/5) * 72.5</gadget>
<output>638</output>
<result>A</result> | A | 638 | If 27.5% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class? | {
"A": "638",
"B": "330",
"C": "550",
"D": "430",
"E": "880"
} | multiply(divide(880, const_100), subtract(const_100, 27.5)) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)| | "students enrolled in biology are 27.5 % and therefore not enrolled are 72.5 % . so of 880 is 880 * . 225 = 638 answer is a 638" | other |
math_qa__TLCuFRFhSC34yJon | the ratio of local and international calls made by amy this week is 5 to 2 . if the ratio changes to 5 to 3 after amy makes 3 more international calls , how many local calls did amy make this week ? Choose the most appropriate option
A) 3 B) 5 C) 10 D) 15 E) 21 | <gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">3 / 1</gadget>
<output>3</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<result>D</result> | D | 15 | the ratio of local and international calls made by amy this week is 5 to 2 . if the ratio changes to 5 to 3 after amy makes 3 more international calls , how many local calls did amy make this week ? | {
"A": "3",
"B": "5",
"C": "10",
"D": "15",
"E": "21"
} | multiply(divide(3, subtract(3, 2)), 5) | subtract(n3,n1)|divide(n3,#0)|multiply(n0,#1) | the ratio of local and international calls made by amy this week is 5 to 2 let the current ratio be 5 x / 2 x the ratio changes to 5 to 3 after amy makes three more international calls 5 x / ( 2 x + 3 ) = 5 / 3 solving we get x = 3 initial ratio 15 : 6 ( 5 : 2 ) final ratio 15 : ( 6 + 3 ) = 15 : 9 = 5 : 3 so total number of local calls = 15 answer : d | other |
math_qa__B39AWhW78nzKbHiU | What is the ratio between perimeters of two squares one having 4 times the diagonal then the other? Choose the correct choice.
A) 3 : 8 B) 3 : 6 C) 3 : 7 D) 4 : 1 E) 3 : 3 | <gadget id="calculator">4 / 4</gadget>
<output>1</output>
<gadget id="calculator">4 / 1</gadget>
<output>4</output>
<result>D</result> | D | 4 | What is the ratio between perimeters of two squares one having 4 times the diagonal then the other? | {
"A": "3 : 8",
"B": "3 : 6",
"C": "3 : 7",
"D": "4 : 1",
"E": "3 : 3"
} | divide(4, divide(4, 4)) | divide(n0,n0)|divide(n0,#0)| | "d = 4 d d = d a √ 2 = 4 d a √ 2 = d a = 4 d / √ 2 a = d / √ 2 = > 4 : 1 answer : d" | geometry |
math_qa__5zIko1gJo5FAVPig | What is the distance covered by a train if it travels with a speed of 150 kmh for 8 hours?
Choose the correct choice from the following options.
A) 1000 km
B) 700 km
C) 800 km
D) 1400 km
E) 1200 km | <gadget id="calculator">150 * 8</gadget>
<output>1_200</output>
<result>E</result> | E | 1,200 | What is the distance covered by a train if it travels with a speed of 150 kmh for 8 hours? | {
"A": "1000 km",
"B": "700 km",
"C": "800 km",
"D": "1400 km",
"E": "1200 km"
} | multiply(150, 8) | multiply(n0,n1)| | "distance = time x speed distance = 150 x 8 = 1200 answer : e" | physics |
math_qa__eKLBdLPLgckjigBV | Following an increase in prices, the price of a candy box was 10 pounds and the price of a can of soda was 12 pounds. If the price of a candy box was raised by 25%, and the price of a can of soda was raised by 50%. What was the price of a box of candy plus a can of soda before prices were raised?
Choose the correct choice from the following answers: A) 11 . B) 12 . C) 16 . D) 14 . E) 14.5 | <gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">1_000 / 125</gadget>
<output>8</output>
<gadget id="calculator">12 * 100</gadget>
<output>1_200</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">1_200 / 150</gadget>
<output>8</output>
<gadget id="calculator">8 + 8</gadget>
<output>16</output>
<result>C</result> | C | 16 | Following an increase in prices, the price of a candy box was 10 pounds and the price of a can of soda was 12 pounds. If the price of a candy box was raised by 25%, and the price of a can of soda was raised by 50%. What was the price of a box of candy plus a can of soda before prices were raised? | {
"A": "11 .",
"B": "12 .",
"C": "16 .",
"D": "14 .",
"E": "14.5"
} | add(divide(multiply(10, const_100), add(const_100, 25)), divide(multiply(12, const_100), add(const_100, 50))) | add(n2,const_100)|add(n3,const_100)|multiply(n0,const_100)|multiply(n1,const_100)|divide(#2,#0)|divide(#3,#1)|add(#4,#5)| | "price of candy before price increase = 10 / 1.25 = 8 price of soda before price increase = 12 / 1.5 = 8 total price = 8 + 8 = 16 c is the answer" | general |
math_qa__OqJqgdD4Iy9QLyLd | Of the 120 passengers on Flight 750, 55% are female. 10% of the passengers sit in first class, and the rest of the passengers sit in coach class. If 1/3 of the passengers in first class are male, how many females are there in coach class?
Choose the correct choice from the following:
A) 44
B) 48
C) 50
D) 52
E) 58 | <gadget id="calculator">55 / 100</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">120 * (11/20)</gadget>
<output>66</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">120 * (1/10)</gadget>
<output>12</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">66 - 8</gadget>
<output>58</output>
<result>E</result> | E | 58 | Of the 120 passengers on Flight 750, 55% are female. 10% of the passengers sit in first class, and the rest of the passengers sit in coach class. If 1/3 of the passengers in first class are male, how many females are there in coach class? | {
"A": "44",
"B": "48",
"C": "50",
"D": "52",
"E": "58"
} | subtract(multiply(120, divide(55, const_100)), subtract(multiply(120, divide(10, const_100)), divide(multiply(120, divide(10, const_100)), 3))) | divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#0)|multiply(n0,#1)|divide(#3,n5)|subtract(#3,#4)|subtract(#2,#5) | number of passengers on flight = 120 number of female passengers = . 5 * 120 = 66 number of passengers in first class = ( 10 / 100 ) * 120 = 12 number of passengers in coach class = ( 90 / 100 ) * 120 = 108 number of male passengers in first class = 1 / 3 * 12 = 4 number of female passengers in first class = 12 - 4 = 8 number of female passengers in coach class = 66 - 8 = 58 answer e | gain |
math_qa__pgYzdYI9isSMh4Q2 | A, B and C started a partnership business by investing Rs.24000, Rs.32000, Rs.36000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit?
Choose the correct choice from the following answers
A) 70000 B) 60000 C) 80000 D) 92000 E) 50000 | <gadget id="calculator">24_000 / 36_000</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 36_000</gadget>
<output>24_000</output>
<gadget id="calculator">32_000 / 36_000</gadget>
<output>8/9 = around 0.888889</output>
<gadget id="calculator">(8/9) * 36_000</gadget>
<output>32_000</output>
<gadget id="calculator">24_000 + 32_000</gadget>
<output>56_000</output>
<gadget id="calculator">56_000 + 36_000</gadget>
<output>92_000</output>
<result>D</result> | D | 92,000 | A, B and C started a partnership business by investing Rs.24000, Rs.32000, Rs.36000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit? | {
"A": "70000",
"B": "60000",
"C": "80000",
"D": "92000",
"E": "50000"
} | add(add(multiply(divide(24000, 36000), 36000), multiply(divide(32000, 36000), 36000)), 36000) | divide(n0,n2)|divide(n1,n2)|multiply(n3,#0)|multiply(n3,#1)|add(#2,#3)|add(n3,#4)| | "a : b : c = 24000 : 32000 : 36000 = 6 : 8 : 9 let total profit = p then p ã — 9 / 23 = 36000 p = ( 36000 ã — 23 ) / 9 = 92000 answer is d ." | gain |
math_qa__4y6YtphlI6Otq25j | The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 60/kg. how much did a kg of coffee cost in june ? Choose the correct answer:
A) 40 B) 45 C) 50 D) 55 E) 60 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(4/5) * (6/5)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">60 / (24/25)</gadget>
<output>125/2 = around 62.5</output>
<result>E</result> | E | 60 | The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 60/kg. how much did a kg of coffee cost in june ? | {
"A": "40",
"B": "45",
"C": "50",
"D": "55",
"E": "60"
} | divide(60, multiply(subtract(const_1, divide(20, const_100)), add(divide(20, const_100), const_1))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|divide(n2,#4)| | "let the price of tea and coffee be x per kg in june . price of tea in july = 1.2 x price of coffee in july = 0.8 x . in july the price of 1 / 2 kg ( 500 gm ) of tea and 1 / 2 kg ( 500 gm ) of coffee ( equal quantities ) = 50 1.2 x ( 1 / 2 ) + 0.8 x ( 1 / 2 ) = 60 = > x = 60 e" | general |
math_qa__CnAaneGO3cHXc43h | The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 28 years. The ratio of their ages after 5 years will be Choose the correct choice from the following options:
A) 22 : 17 B) 9 : 11 C) 5 : 4 D) 4 : 5 E) 8 : 11 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">28 / 7</gadget>
<output>4</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 + 5</gadget>
<output>21</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 5</gadget>
<output>17</output>
<gadget id="calculator">21 / 17</gadget>
<output>21/17 = around 1.235294</output>
<result>A</result> | A | 1.294118 | The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 28 years. The ratio of their ages after 5 years will be | {
"A": "22 : 17",
"B": "9 : 11",
"C": "5 : 4",
"D": "4 : 5",
"E": "8 : 11"
} | divide(add(multiply(4, divide(28, add(4, 3))), 5), add(multiply(3, divide(28, add(4, 3))), 5)) | add(n0,n1)|divide(n2,#0)|multiply(n0,#1)|multiply(n1,#1)|add(n3,#2)|add(n3,#3)|divide(#4,#5)| | "let mini ’ s age = 4 x and minakshi ’ s age = 3 x then 4 x + 3 x = 28 x = 4 mini ’ s age = 16 years and minakshi ’ s age = 12 years ratio of their ages after 8 years = ( 16 + 5 ) : ( 12 + 5 ) = 22 : 17 answer : a" | general |
math_qa__SZdHEvVjzaSiUpZ2 | There is an antique clock exhibition. So many clock are piled up with distinct numbers tagged with them. The person managing it hangs different clocks numbers periodically on the main wall. At 9:20 am, he hung the clock number 200; at 11:00 am, he hung the clock number 30; at 4:00 pm, he hung the clock number 240.
Which numbered clock will he hang on the wall when the time is 7:30pm ?
Select the correct option: A) 313 B) 314 C) 315 D) 316 E) 317 | <gadget id="calculator">12 * 10</gadget>
<output>120</output>
<gadget id="calculator">120 * 3</gadget>
<output>360</output>
<gadget id="calculator">7 * 30</gadget>
<output>210</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">360 / 12</gadget>
<output>30</output>
<gadget id="calculator">6 * 30</gadget>
<output>180</output>
<gadget id="calculator">210 - 180</gadget>
<output>30</output>
<gadget id="calculator">360 - 30</gadget>
<output>330</output>
<result>C</result> | C | 315 | There is an antique clock exhibition. So many clock are piled up with distinct numbers tagged with them. The person managing it hangs different clocks numbers periodically on the main wall. At 9:20 am, he hung the clock number 200; at 11:00 am, he hung the clock number 30; at 4:00 pm, he hung the clock number 240.
Which numbered clock will he hang on the wall when the time is 7:30pm ? | {
"A": "313",
"B": "314",
"C": "315",
"D": "316",
"E": "317"
} | subtract(multiply(multiply(const_12, const_10), const_3), subtract(multiply(7, 30), multiply(divide(30, add(const_4, const_1)), divide(multiply(multiply(const_12, const_10), const_3), const_12)))) | add(const_1,const_4)|multiply(const_10,const_12)|multiply(n5,n9)|divide(n5,#0)|multiply(#1,const_3)|divide(#4,const_12)|multiply(#3,#5)|subtract(#2,#6)|subtract(#4,#7) | solution : he will hang clock number 315 at 7 : 30 pm . the person has been hanging the clock number which corresponds with the angle between the hour hand and the minute hand of the clock at that time . answer c | general |
math_qa__22GNvvijKbO8hBDJ | The mean of 30 values was 150. It was detected on rechecking that one value 165 was wrongly copied as 135 for the computation of the mean. Find the correct mean. Choose the correct choice from the following answers:
A) 151 B) 149 C) 152 D) 148 E) none of the above | <gadget id="calculator">30 * 150</gadget>
<output>4_500</output>
<gadget id="calculator">165 - 135</gadget>
<output>30</output>
<gadget id="calculator">4_500 + 30</gadget>
<output>4_530</output>
<gadget id="calculator">4_530 / 30</gadget>
<output>151</output>
<result>A</result> | A | 151 | The mean of 30 values was 150. It was detected on rechecking that one value 165 was wrongly copied as 135 for the computation of the mean. Find the correct mean. | {
"A": "151",
"B": "149",
"C": "152",
"D": "148",
"E": "none of the above"
} | divide(add(multiply(30, 150), subtract(165, 135)), 30) | multiply(n0,n1)|subtract(n2,n3)|add(#0,#1)|divide(#2,n0)| | "corrected mean = 150 × 30 − 135 + 165 / 30 = 4500 − 135 + 165 / 30 = 4530 / 30 = 151 answer a" | general |
math_qa__apnm0xsDWhCO9WGO | a man spends rs . 1700 per month on an average for the first 3 months , rs 1550 for next 4 months and rs . 1800 per month for the last 5 months and saves rs . 5200 a year . what is his average monthly income ? Choose the correct answer.
A) 2025 B) 2125 C) 2225 D) 2325 E) 2425 | <gadget id="calculator">1_700 * 3</gadget>
<output>5_100</output>
<gadget id="calculator">1_550 * 4</gadget>
<output>6_200</output>
<gadget id="calculator">5_100 + 6_200</gadget>
<output>11_300</output>
<gadget id="calculator">1_800 * 5</gadget>
<output>9_000</output>
<gadget id="calculator">11_300 + 9_000</gadget>
<output>20_300</output>
<gadget id="calculator">20_300 + 5_200</gadget>
<output>25_500</output>
<gadget id="calculator">25_500 / 12</gadget>
<output>2_125</output>
<result>B</result> | B | 2,125 | a man spends rs . 1700 per month on an average for the first 3 months , rs 1550 for next 4 months and rs . 1800 per month for the last 5 months and saves rs . 5200 a year . what is his average monthly income ? | {
"A": "2025",
"B": "2125",
"C": "2225",
"D": "2325",
"E": "2425"
} | divide(add(add(add(multiply(1700, 3), multiply(1550, 4)), multiply(1800, 5)), 5200), const_12) | multiply(n0,n1)|multiply(n2,n3)|multiply(n4,n5)|add(#0,#1)|add(#3,#2)|add(n6,#4)|divide(#5,const_12) | explanation : total expenditure for the first 3 months = 3 ã — 1700 = 5100 total expenditure for 4 months = 4 ã — 1550 = 6200 total expenditure for 5 months = 5 ã — 1800 = 9000 total expenditure and saving ( which is income for one year ) = 5100 + 6200 + 9000 + 5200 = rs . 25500 so , average monthly income = 25500 / 12 = rs . 2125 answer b | general |
math_qa__oET6E4LSIWOGUEyZ | The sale price sarees listed for Rs.400 after successive discount is 20% and 15% is? Choose the correct choice from the following answers: A) 297 B) 272 C) 342 D) 762 E) 269 | <gadget id="calculator">400 * 20</gadget>
<output>8_000</output>
<gadget id="calculator">8_000 / 100</gadget>
<output>80</output>
<gadget id="calculator">400 - 80</gadget>
<output>320</output>
<gadget id="calculator">320 * 15</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 100</gadget>
<output>48</output>
<gadget id="calculator">320 - 48</gadget>
<output>272</output>
<result>B</result> | B | 272 | The sale price sarees listed for Rs.400 after successive discount is 20% and 15% is? | {
"A": "297",
"B": "272",
"C": "342",
"D": "762",
"E": "269"
} | subtract(subtract(400, divide(multiply(400, 20), const_100)), divide(multiply(subtract(400, divide(multiply(400, 20), const_100)), 15), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "400 * ( 80 / 100 ) * ( 85 / 100 ) = 272 answer : b" | gain |
math_qa__NPltdRUnlbPSDFBU | A bag contains 3 blue and 5 white marbles. One by one, marbles are drawn out randomly until only two are left in the bag. What is the probability Q that out of the two, one is white and one is blue?
Choose the correct answer:
A) 15 / 56
B) 41 / 56
C) 13 / 28
D) 15 / 28
E) 5 / 14 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">8 * 7</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<gadget id="calculator">15 / 28</gadget>
<output>15/28 = around 0.535714</output>
<result>D</result> | D | 0.535714 | A bag contains 3 blue and 5 white marbles. One by one, marbles are drawn out randomly until only two are left in the bag. What is the probability Q that out of the two, one is white and one is blue? | {
"A": "15 / 56",
"B": "41 / 56",
"C": "13 / 28",
"D": "15 / 28",
"E": "5 / 14"
} | divide(multiply(3, 5), divide(multiply(add(3, 5), add(5, const_2)), const_2)) | add(n0,n1)|add(n1,const_2)|multiply(n0,n1)|multiply(#0,#1)|divide(#3,const_2)|divide(#2,#4) | the required probability q = probability of choosing 6 balls out of the total 8 in such a way that we remove 4 out of 5 white and 2 out of 3 blue balls . ways to select 6 out of total 8 = 8 c 6 ways to select 4 out of 5 white balls = 5 c 4 ways to select 2 out of 3 blue balls = 3 c 2 thus the required probability = ( 5 c 4 * 3 c 2 ) / 8 c 6 = 15 / 28 . d is thus the correct answer . | probability |
math_qa__9NVDPuzhAVgwi6tw | In what proportion must rice at Rs 3.10 per kg be mixed with rice at Rs 3.60 per kg, so that the mixture be worth Rs 3.25 a kg?
Choose the correct choice from the following options
A) 3 / 5 B) 3 / 2 C) 5 / 3 D) 5 / 7 E) 7 / 3 | <gadget id="calculator">3.6 - 3.25</gadget>
<output>0.35</output>
<gadget id="calculator">3.25 - 3.1</gadget>
<output>0.15</output>
<gadget id="calculator">0.35 / 0.15</gadget>
<output>2.333333</output>
<result>E</result> | E | 2.333333 | In what proportion must rice at Rs 3.10 per kg be mixed with rice at Rs 3.60 per kg, so that the mixture be worth Rs 3.25 a kg? | {
"A": "3 / 5",
"B": "3 / 2",
"C": "5 / 3",
"D": "5 / 7",
"E": "7 / 3"
} | divide(subtract(3.60, 3.25), subtract(3.25, 3.10)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "c . p of 1 kg of cheaper rice = rs 3.10 c . p of 1 kg of expensive rice = rs 3.60 the mixture be worth for 1 kg = rs 3.25 by the alligation rule : quantity of cheaper rice / quantity of expensive rice = ( 3.6 - 3.25 ) / ( 3.25 - 3.10 ) = ( 0.35 ) / ( 0.15 ) = 7 / 3 e" | general |
math_qa__6vy4qF3txQDdMeLx | Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. what percent of the families in City X owned a personal computer in 1998? Options.
A) 50 % B) 52 % C) 56 % D) 70 % E) 74 % | <gadget id="calculator">30 + 100</gadget>
<output>130</output>
<gadget id="calculator">130 * 40</gadget>
<output>5_200</output>
<gadget id="calculator">5_200 / 100</gadget>
<output>52</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">52 / 104</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">100 * (1/2)</gadget>
<output>50</output>
<result>A</result> | A | 50 | Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. what percent of the families in City X owned a personal computer in 1998? | {
"A": "50 %",
"B": "52 %",
"C": "56 %",
"D": "70 %",
"E": "74 %"
} | multiply(const_100, divide(divide(multiply(add(30, const_100), 40), const_100), add(const_100, 4))) | add(n3,const_100)|add(n5,const_100)|multiply(n1,#0)|divide(#2,const_100)|divide(#3,#1)|multiply(#4,const_100)| | "say a 100 families existed in 1994 then the number of families owning a computer in 1994 - 40 number of families owning computer in 1998 = 40 * 130 / 100 = 52 number of families in 1998 = 104 the percentage = 52 / 104 * 100 = 50 % . answer : a" | general |
math_qa__wkUFxXF0FjPxWGai | One-third less than 35% of 180 is equal to:
Select the correct option
A) 15 B) 30 C) 35 D) 42 E) 45 | <gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) * 180</gadget>
<output>63</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 63</gadget>
<output>21</output>
<gadget id="calculator">63 - 21</gadget>
<output>42</output>
<result>D</result> | D | 42 | One-third less than 35% of 180 is equal to: | {
"A": "15",
"B": "30",
"C": "35",
"D": "42",
"E": "45"
} | subtract(multiply(divide(35, const_100), 180), multiply(divide(const_1, const_3), multiply(divide(35, const_100), 180))) | divide(n0,const_100)|divide(const_1,const_3)|multiply(n1,#0)|multiply(#1,#2)|subtract(#2,#3) | lots of ways to tackle this . 35 % of 180 = 63 1 / 3 of 63 = 21 so , 1 / 3 less than 63 is equal to 63 - 21 = 42 answer : d | general |
math_qa__K4UCeTWEb9gaO60X | Country X imported approximately $1.44 billion of goods in 1996. If Country X imported $420 million of goods in the first two months of 1997 and continued to import goods at the same rate for the rest of the year, by how much would Country Xs 1997 imports exceed those of 1996? Choose one.
A) $ 214 million
B) $ 1120 million
C) $ 1144 million
D) $ 1240 million
E) $ 1080 million | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">420 * 6</gadget>
<output>2_520</output>
<gadget id="calculator">1.44 * 1_000</gadget>
<output>1_440</output>
<gadget id="calculator">2_520 - 1_440</gadget>
<output>1_080</output>
<result>E</result> | E | 1,080 | Country X imported approximately $1.44 billion of goods in 1996. If Country X imported $420 million of goods in the first two months of 1997 and continued to import goods at the same rate for the rest of the year, by how much would Country Xs 1997 imports exceed those of 1996? | {
"A": "$ 214 million",
"B": "$ 1120 million",
"C": "$ 1144 million",
"D": "$ 1240 million",
"E": "$ 1080 million"
} | subtract(multiply(420, divide(const_12, const_2)), multiply(1.44, const_1000)) | divide(const_12,const_2)|multiply(n0,const_1000)|multiply(n2,#0)|subtract(#2,#1)| | "convert units to millions as answer is in millions 1996 imports = $ 1.44 bill = $ 1440 mill i . e . 1440 / 12 = $ 120 mill / month 1997 imports = $ 420 mill / 2 month i . e . $ 210 mill / month difference / month = 210 - 120 = 90 difference / year = $ 90 mill * 12 = $ 1080 mill answer : e" | general |
math_qa__clFlQN2H0T2JpAxO | A company produces 65000 bottles of water everyday. If a case can hold 13 bottles of water .How many cases are required by the company to hold its one day production Answers.
A) 2000 B) 4500 C) 5000 D) 8000 E) 9000 | <gadget id="calculator">65_000 / 13</gadget>
<output>5_000</output>
<result>C</result> | C | 5,000 | A company produces 65000 bottles of water everyday. If a case can hold 13 bottles of water .How many cases are required by the company to hold its one day production | {
"A": "2000",
"B": "4500",
"C": "5000",
"D": "8000",
"E": "9000"
} | divide(65000, 13) | divide(n0,n1)| | "number of bottles that can be held in a case = 13 number of cases required to hold 65000 bottles = 65000 / 13 = 5000 cases . so the answer is c = 5000" | physics |
math_qa__pY1tHOXNMwjjfPbL | Calculate the area of a triangle, if the sides are 13 cm, 12 cm and 5 cm, what is its area? Choose the correct choice from the following choices
A) 36 cm 2 B) 35 cm 2 C) 30 cm 2 D) 32 cm 2 E) 31 cm 2 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<result>C</result> | C | 30 | Calculate the area of a triangle, if the sides are 13 cm, 12 cm and 5 cm, what is its area? | {
"A": "36 cm 2",
"B": "35 cm 2",
"C": "30 cm 2",
"D": "32 cm 2",
"E": "31 cm 2"
} | multiply(divide(12, const_2), 5) | divide(n1,const_2)|multiply(n2,#0) | the triangle with sides 13 cm , 12 cm and 5 cm is right angled , where the hypotenuse is 13 cm . area of the triangle = 1 / 2 * 12 * 5 = 30 cm 2 answer : c | geometry |
math_qa__TSm3TKWgQ9Apvp8c | A certain mixture of nuts consists of 5 parts almonds to 2 parts walnuts, by weight. What is the number of pounds of almonds in 210 pounds of the mixture ? Options.
A) 150 B) 84 C) 40 D) 28 E) 20 | <gadget id="calculator">5 * 210</gadget>
<output>1_050</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">1_050 / 7</gadget>
<output>150</output>
<result>A</result> | A | 150 | A certain mixture of nuts consists of 5 parts almonds to 2 parts walnuts, by weight. What is the number of pounds of almonds in 210 pounds of the mixture ? | {
"A": "150",
"B": "84",
"C": "40",
"D": "28",
"E": "20"
} | divide(multiply(5, 210), add(5, 2)) | add(n0,n1)|multiply(n0,n2)|divide(#1,#0)| | "almonds : walnuts = 5 : 2 total mixture has 7 parts in a 210 pound mixture , almonds are 5 / 7 ( total mixture ) = 5 / 7 * 210 = 150 pounds answer ( a )" | general |
math_qa__ntQKtP0va3vCOoGI | The simple interest on a sum of money will be Rs.1200 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? Pick: A) 8981 B) 3799 C) 1200 D) 2400 E) 1732 | <gadget id="calculator">1_200 / 10</gadget>
<output>120</output>
<gadget id="calculator">120 * 5</gadget>
<output>600</output>
<gadget id="calculator">600 * 3</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 + 600</gadget>
<output>2_400</output>
<result>D</result> | D | 2,400 | The simple interest on a sum of money will be Rs.1200 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? | {
"A": "8981",
"B": "3799",
"C": "1200",
"D": "2400",
"E": "1732"
} | add(multiply(multiply(divide(1200, 10), 5), const_3), multiply(divide(1200, 10), 5)) | divide(n0,n1)|multiply(n2,#0)|multiply(#1,const_3)|add(#2,#1)| | "p - - - 10 - - - - 1200 p - - - 5 - - - - - 600 3 p - - - 5 - - - - - 1800 - - - - - - = > 2400 answer : d" | general |
math_qa__LBjGONYW75WvwNx7 | A number whose fifth part increased by 4 is equal to its fourth part diminished by 4 is ? Choices: A) 160 B) 180 C) 200 D) 220 E) none | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/4) - (1/5)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">8 / (1/20)</gadget>
<output>160</output>
<result>A</result> | A | 160 | A number whose fifth part increased by 4 is equal to its fourth part diminished by 4 is ? | {
"A": "160",
"B": "180",
"C": "200",
"D": "220",
"E": "none"
} | divide(add(4, 4), subtract(divide(const_1, 4), divide(const_1, add(const_1, 4)))) | add(n0,n1)|add(const_1,n0)|divide(const_1,n0)|divide(const_1,#1)|subtract(#2,#3)|divide(#0,#4)| | "answer let the number be n . then , ( n / 5 ) + 4 = ( n / 4 ) - 4 â ‡ ’ ( n / 4 ) - ( n / 5 ) = 8 â ‡ ’ ( 5 n - 4 n ) / 20 = 8 â ˆ ´ n = 160 option : a" | general |
math_qa__UzIedQF0VJku9IWR | A,B,C together can earn $600 per day. while A and C together earn $400 and B and C together can earn $300. The daily earnings of C?
Pick one
A) $ 100 B) $ 200 C) $ 250 D) $ 300 E) $ 500 | <gadget id="calculator">600 - 400</gadget>
<output>200</output>
<gadget id="calculator">300 - 200</gadget>
<output>100</output>
<result>A</result> | A | 100 | A,B,C together can earn $600 per day. while A and C together earn $400 and B and C together can earn $300. The daily earnings of C? | {
"A": "$ 100",
"B": "$ 200",
"C": "$ 250",
"D": "$ 300",
"E": "$ 500"
} | subtract(300, subtract(600, 400)) | subtract(n0,n1)|subtract(n2,#0) | b ' s daily earnings = 600 - 400 = $ 200 a ' s daily earnings = 600 - 300 = $ 300 c ' s daily earnings = 600 - 200 - 300 = $ 100 answer is a | physics |
math_qa__ylR2s3AUJuyukHlB | A can do a piece of work in 3 days of 5 hours each and B alone can do it in 5 days of 3 hours each.how long will they take it to do working together
3/4 hours a day? Options
A) 6 days
B) 5 days
C) 10 days
D) 9 days
E) 8 days | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) + (1/15)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">1 / (2/15)</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(15/2) / (3/4)</gadget>
<output>10</output>
<result>C</result> | C | 10 | A can do a piece of work in 3 days of 5 hours each and B alone can do it in 5 days of 3 hours each.how long will they take it to do working together
3/4 hours a day? | {
"A": "6 days",
"B": "5 days",
"C": "10 days",
"D": "9 days",
"E": "8 days"
} | divide(divide(const_1, add(divide(const_1, multiply(3, 5)), divide(const_1, multiply(3, 5)))), divide(3, 4)) | divide(n0,n5)|multiply(n0,n1)|divide(const_1,#1)|add(#2,#2)|divide(const_1,#3)|divide(#4,#0) | a ' s work per hour = 1 / 15 b ' s work per hour = 1 / 15 a & b ' s work per hour together = ( 1 / 15 ) + ( 1 / 15 ) = 2 / 15 so a & b together complete the work in 15 / 2 hours . . . if they work 2 1 / 2 = 5 / 2 hours a day , it will take ( 15 / 2 ) / ( 3 / 4 ) days = 10 days . . . answer : c | physics |
math_qa__FAT7DzQxOZztL9xs | If the price of a certain bond on May 1st was 3/4 the price of the bond on June 1st and the price of the bond on July 1st was 50% greater than the price of the bond on May 1st. then the price of the bond on June 1st st was what percent of the average (arithmetic mean) price of the bond on May 1st and July 1st? Pick: A) 50 % B) 114.28 % C) 120 % D) 133 1 / 3 % E) 150 % | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">50 * (1/3)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">100 + (1/3)</gadget>
<output>301/3 = around 100.333333</output>
<gadget id="calculator">(50/3) + (301/3)</gadget>
<output>117</output>
<result>B</result> | B | 114.28 | If the price of a certain bond on May 1st was 3/4 the price of the bond on June 1st and the price of the bond on July 1st was 50% greater than the price of the bond on May 1st. then the price of the bond on June 1st st was what percent of the average (arithmetic mean) price of the bond on May 1st and July 1st? | {
"A": "50 %",
"B": "114.28 %",
"C": "120 %",
"D": "133 1 / 3 %",
"E": "150 %"
} | add(multiply(50, const_0_33), add(const_100, const_0_33)) | add(const_0_33,const_100)|multiply(n5,const_0_33)|add(#0,#1) | the price on june 1 st = 12 ( assume ) ; the price on may 1 st = 3 / 4 * 12 = 9 ; the price on july 1 st = 8 * 1.5 = 12 . the average price of the bond on may 1 st and july 1 st = ( 9 + 12 ) / 2 = 10.5 . the price of the bond on june 1 st ( 12 ) is 24 / 21 times ( 114.28 % ) the average price of the bond on may 1 st and july 1 st . answer : b . | general |
math_qa__quvAVMNAgmsyPiRt | A 300 m long train crosses a platform in 40 sec while it crosses a signal pole in 18 sec. What is the length of the platform? Choose the correct option:
A) 288
B) 350
C) 889
D) 367
E) 234 | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 40</gadget>
<output>2_000/3 = around 666.666667</output>
<gadget id="calculator">(2_000/3) - 300</gadget>
<output>1_100/3 = around 366.666667</output>
<result>D</result> | D | 367 | A 300 m long train crosses a platform in 40 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | {
"A": "288",
"B": "350",
"C": "889",
"D": "367",
"E": "234"
} | subtract(multiply(speed(300, 18), 40), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 18 = 50 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 40 = 50 / 3 3 x + 900 = 2000 = > x = 367 m . answer : d" | physics |
math_qa__VAs3YLPVgGSaYJ6d | The average age of a class of 25 students is 26 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher? Choose the correct choice from the following answers:
A) 40
B) 41
C) 52
D) 62
E) 73 | <gadget id="calculator">25 + 1</gadget>
<output>26</output>
<gadget id="calculator">26 + 1</gadget>
<output>27</output>
<gadget id="calculator">26 * 27</gadget>
<output>702</output>
<gadget id="calculator">25 * 26</gadget>
<output>650</output>
<gadget id="calculator">702 - 650</gadget>
<output>52</output>
<result>C</result> | C | 52 | The average age of a class of 25 students is 26 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher? | {
"A": "40",
"B": "41",
"C": "52",
"D": "62",
"E": "73"
} | subtract(multiply(add(25, 1), add(26, 1)), multiply(25, 26)) | add(n0,n2)|add(n1,n2)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "total age of all students = 25 ã — 26 total age of all students + age of the teacher = 26 ã — 27 age of the teacher = 27 ã — 26 â ˆ ’ 25 ã — 26 = 26 ( 27 â ˆ ’ 25 ) = 26 ã — 2 = 52 answer is c ." | general |
math_qa__PAfw1yD2Wwww77mX | The difference between two numbers is 1356. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number is Choose the most appropriate option: A) 240 B) 270 C) 295 D) 360 E) 340 | <gadget id="calculator">1_356 - 15</gadget>
<output>1_341</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">1_341 / 5</gadget>
<output>1_341/5 = around 268.2</output>
<result>B</result> | B | 270 | The difference between two numbers is 1356. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number is | {
"A": "240",
"B": "270",
"C": "295",
"D": "360",
"E": "340"
} | divide(subtract(1356, 15), subtract(6, const_1)) | subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)| | "let the smaller number be x . then larger number = ( x + 1365 ) . x + 1365 = 6 x + 15 5 x = 1350 x = 270 smaller number = 270 answer : b" | general |
math_qa__2tqItLC4qTeFBsXG | On a test, the boys in the class averaged 90 points and the girls in the class averaged 96 points. If the overall class average was 94 points, what is the ratio of boys to girls in the class?
Choose the correct option
A) 1 / 2 B) 2 / 3 C) 3 / 4 D) 3 / 5 E) 4 / 5 | <gadget id="calculator">96 - 94</gadget>
<output>2</output>
<gadget id="calculator">94 - 90</gadget>
<output>4</output>
<gadget id="calculator">2 / 4</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | On a test, the boys in the class averaged 90 points and the girls in the class averaged 96 points. If the overall class average was 94 points, what is the ratio of boys to girls in the class? | {
"A": "1 / 2",
"B": "2 / 3",
"C": "3 / 4",
"D": "3 / 5",
"E": "4 / 5"
} | divide(subtract(96, 94), subtract(94, 90)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1) | ( 96 g + 90 b ) / ( g + b ) = 94 96 g + 90 b = 94 ( g + b ) 2 g = 4 b b / g = 1 / 2 the answer is a . | general |
math_qa__g2NQ6mzi547cyW9M | 9 - 3 ÷ 1/3 + 3 = ? Pick
A) 1 B) 3 C) 6 D) 9 E) 12 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">3 / (1/3)</gadget>
<output>9</output>
<gadget id="calculator">9 - 9</gadget>
<output>0</output>
<gadget id="calculator">0 + 3</gadget>
<output>3</output>
<result>B</result> | B | 3 | 9 - 3 ÷ 1/3 + 3 = ? | {
"A": "1",
"B": "3",
"C": "6",
"D": "9",
"E": "12"
} | add(subtract(9, divide(3, divide(1, 3))), 3) | divide(n2,n1)|divide(n1,#0)|subtract(n0,#1)|add(n1,#2) | 9 - 3 1 / 3 + 3 = 9 - 3 ÷ 1 / 3 + 3 = 9 - ( 3 x 3 ) + 3 = 9 - 9 + 3 = 3 correct answer : b | general |
math_qa__ayz01MvMtWAVgcwP | Find the ones digit of 73^355 Choose the correct option: A) 3 B) 5 C) 6 D) 7 E) 9 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">73 - 70</gadget>
<output>3</output>
<gadget id="calculator">355 / 4</gadget>
<output>355/4 = around 88.75</output>
<gadget id="calculator">floor(355/4)</gadget>
<output>88</output>
<gadget id="calculator">88 * 4</gadget>
<output>352</output>
<gadget id="calculator">355 - 352</gadget>
<output>3</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">27 - 20</gadget>
<output>7</output>
<result>D</result> | D | 7 | Find the ones digit of 73^355 | {
"A": "3",
"B": "5",
"C": "6",
"D": "7",
"E": "9"
} | subtract(power(subtract(73, multiply(add(const_3, const_4), const_10)), subtract(355, multiply(floor(divide(355, const_4)), const_4))), multiply(const_2, const_10)) | add(const_3,const_4)|divide(n1,const_4)|multiply(const_10,const_2)|floor(#1)|multiply(#0,const_10)|multiply(#3,const_4)|subtract(n0,#4)|subtract(n1,#5)|power(#6,#7)|subtract(#8,#2) | the units digit of 73 ^ 355 will be the same as the units digit of 3 ^ 355 . 3 ^ 1 = 3 - - > the units digit is 3 ; 3 ^ 2 = 9 - - > the units digit is 9 ; 3 ^ 3 = 27 - - > the units digit is 7 ; 3 ^ 4 = 81 - - > the units digit is 1 ; 3 ^ 5 = 243 - - > the units digit is 3 again ; . . . so , as you can see the units digit repeats in blocks of 4 : { 3 , 9 , 7 , 1 } , { 3 , 9 , 7 , 1 } , . . . now , since 355 = 352 + 3 = ( multiple of 4 ) + 2 , then the units digit of 3 ^ 355 will be the third number in the pattern thus 7 . answer : d . | general |
math_qa__ZmcL4sAF1r5ffef2 | How long will it take a train travelling at 98kmph to pass an electric pole if the train is 140 m long Choose the most appropriate option.
A) 6.15 B) 5.15 C) 3.15 D) 1.15 E) 7.15 | <gadget id="calculator">140 / 1_000</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/50) / 98</gadget>
<output>1/700 = around 0.001429</output>
<gadget id="calculator">(1/700) * 3_600</gadget>
<output>36/7 = around 5.142857</output>
<result>B</result> | B | 5.15 | How long will it take a train travelling at 98kmph to pass an electric pole if the train is 140 m long | {
"A": "6.15",
"B": "5.15",
"C": "3.15",
"D": "1.15",
"E": "7.15"
} | multiply(divide(divide(140, const_1000), 98), const_3600) | divide(n1,const_1000)|divide(#0,n0)|multiply(#1,const_3600)| | "sol . speed = [ 98 x 5 / 18 ] m / sec = 27.2 m / sec . time taken = ( 140 / 27.2 ) sec = 5.15 sec . answer b" | physics |
math_qa__TSUZmfKUQPyt2YO4 | A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is: Choose the correct choice from the following options:
A) 120 kmph B) 150 kmph C) 50 kmph D) 80 kmph E) 75 kmph | <gadget id="calculator">12.5 * 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 1</gadget>
<output>24</output>
<gadget id="calculator">24 * 25</gadget>
<output>600</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">600 / 5</gadget>
<output>120</output>
<result>A</result> | A | 120 | A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is: | {
"A": "120 kmph",
"B": "150 kmph",
"C": "50 kmph",
"D": "80 kmph",
"E": "75 kmph"
} | divide(multiply(subtract(multiply(12.5, const_2), const_1), multiply(12.5, const_2)), add(const_4, const_1)) | add(const_1,const_4)|multiply(n2,const_2)|subtract(#1,const_1)|multiply(#1,#2)|divide(#3,#0)| | "let speed of the car be x kmph . then , speed of the train = 150 / 100 x = 3 / 2 x kmph . 75 / x - 75 / ( 3 / 2 ) x = 125 / 10 x 60 75 / x - 50 / x = 5 / 24 x = 25 x 24 / 5 = 120 kmph . answer : a" | physics |
math_qa__KpXfu1QelnY24Mde | By approximately what percent is x greater than 1/2 if (1/2)(x) = 1? Choose one
A) 732 % B) 560 % C) 641 % D) 370 % E) 300 % | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 - (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) / (1/2)</gadget>
<output>3</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<result>E</result> | E | 300 | By approximately what percent is x greater than 1/2 if (1/2)(x) = 1? | {
"A": "732 %",
"B": "560 %",
"C": "641 %",
"D": "370 %",
"E": "300 %"
} | multiply(divide(subtract(2, divide(1, 2)), divide(1, 2)), const_100) | divide(n0,n1)|subtract(n1,#0)|divide(#1,#0)|multiply(#2,const_100)| | "what percent is x greater than 1 / 2 if ( 1 / 2 ) ( x ) = 1 ? = > x = 2 % change = [ ( 2 - 1 / 2 ) / ( 1 / 2 ) ] * 100 = ( 4 - 1 ) * 100 = 300 % approx ans , e" | general |
math_qa__m6F3KY7f7JGzs6BJ | Set X consists of all two-digit primes and set Y consists of all positive multiples of 6 less than 100. If the two sets are combined into one, what will be the range of the new set? Choose the correct choice from the following options:
A) 84
B) 89
C) 90
D) 92
E) 91 | <gadget id="calculator">100 - 3</gadget>
<output>97</output>
<gadget id="calculator">97 - 6</gadget>
<output>91</output>
<result>E</result> | E | 91 | Set X consists of all two-digit primes and set Y consists of all positive multiples of 6 less than 100. If the two sets are combined into one, what will be the range of the new set? | {
"A": "84",
"B": "89",
"C": "90",
"D": "92",
"E": "91"
} | subtract(subtract(100, const_3), 6) | subtract(n1,const_3)|subtract(#0,n0)| | "set x = { 11 , 13 , 17 , . . . . . . . . . . . . . , 83 , 89 , 97 } set y = { 6 , 12 , 18 , . . . . . . . . . . . . . . . , 84 , 90 , 96 } combining two sets , say set z set z = { 6 , 11 , 12 , 13 , 17 , 18 , . . . . . . . . . . . . . . . . . . . , 83 , 84 , 89 , 90 , 96,97 } range = max value - min value range ( z ) = 97 - 6 = 91 oa e is the answer ." | general |
math_qa__uCC064EBVSNZLfOG | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg? Answers.
A) 40 B) 60 C) 70 D) 80 E) 20 | <gadget id="calculator">800 * 25</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 100</gadget>
<output>200</output>
<gadget id="calculator">200 / 5</gadget>
<output>40</output>
<result>A</result> | A | 40 | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg? | {
"A": "40",
"B": "60",
"C": "70",
"D": "80",
"E": "20"
} | divide(divide(multiply(800, 25), const_100), 5) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "a 800 * ( 25 / 100 ) = 200 - - - - 5 ? - - - - 1 = > rs . 40" | gain |
math_qa__XkMqmKz2d2Y07e5U | 37. If the cost price of 15 tables be equal to the selling price of 20 tables, the loss per cent is ? Choose the correct choice from the following:
A) 20 %
B) 30 %
C) 25 %
D) 37.5 %
E) 38 % | <gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">5 / 20</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | 37. If the cost price of 15 tables be equal to the selling price of 20 tables, the loss per cent is ? | {
"A": "20 %",
"B": "30 %",
"C": "25 %",
"D": "37.5 %",
"E": "38 %"
} | multiply(divide(subtract(20, 15), 20), const_100) | subtract(n2,n1)|divide(#0,n2)|multiply(#1,const_100) | let c . p . of each table = re . 1 c . p . of 20 tables = rs . 20 s . p . of 20 table = c . p . of 15 tables = rs . 15 loss = ( 5 / 20 ) x 100 % = 25 % answer : c | gain |
math_qa__y1CW6U7nV7k5Jzyk | In a certain circle there are 9 points. What is the number of the triangles connecting 4 points of the 9 points? Options
A) 80 B) 96 C) 108 D) 126 E) 132 | <gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">120 * 24</gadget>
<output>2_880</output>
<gadget id="calculator">362_880 / 2_880</gadget>
<output>126</output>
<result>D</result> | D | 126 | In a certain circle there are 9 points. What is the number of the triangles connecting 4 points of the 9 points? | {
"A": "80",
"B": "96",
"C": "108",
"D": "126",
"E": "132"
} | divide(factorial(9), multiply(factorial(divide(const_10, const_2)), factorial(4))) | divide(const_10,const_2)|factorial(n0)|factorial(n1)|factorial(#0)|multiply(#3,#2)|divide(#1,#4) | imo : d here we have to select 4 points out of 9 points . order is not important so the answer will be 9 c 4 = 126 answer d | geometry |
math_qa__QRydKTNeL0UWOBnJ | Find the amount on Rs.5000 in 2 years, the rate of interest being 5% per first year and 6% for the second year? Choose the most appropriate option.
A) 3377 B) 2678 C) 5565 D) 1976 E) 1671 | <gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">5_000 * 105</gadget>
<output>525_000</output>
<gadget id="calculator">525_000 / 100</gadget>
<output>5_250</output>
<gadget id="calculator">100 + 6</gadget>
<output>106</output>
<gadget id="calculator">5_250 * 106</gadget>
<output>556_500</output>
<gadget id="calculator">556_500 / 100</gadget>
<output>5_565</output>
<result>C</result> | C | 5,565 | Find the amount on Rs.5000 in 2 years, the rate of interest being 5% per first year and 6% for the second year? | {
"A": "3377",
"B": "2678",
"C": "5565",
"D": "1976",
"E": "1671"
} | divide(multiply(divide(multiply(5000, add(const_100, 5)), const_100), add(const_100, 6)), const_100) | add(n3,const_100)|add(n2,const_100)|multiply(n0,#1)|divide(#2,const_100)|multiply(#0,#3)|divide(#4,const_100)| | "5000 * 105 / 100 * 106 / 100 = > 5565 answer : c" | gain |
math_qa__2NJ15eSTlLks8CRV | A club wants to mix 30 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used? Answers:
A) 30
B) 40
C) 50
D) 60
E) 70 | <gadget id="calculator">30 * 8</gadget>
<output>240</output>
<gadget id="calculator">6 * 30</gadget>
<output>180</output>
<gadget id="calculator">240 - 180</gadget>
<output>60</output>
<result>D</result> | D | 60 | A club wants to mix 30 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used? | {
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "70"
} | subtract(multiply(30, 8.00), multiply(6.00, 30)) | multiply(n0,n1)|multiply(n0,n3)|subtract(#0,#1)| | "let number of pounds of 5 $ candy to be used be w 6 = ( 30 * 8 + 5 * w ) / ( 30 + w ) = > 180 + 6 w = 240 + 5 w = > w = 60 answer d" | general |
math_qa__aNpNkeigo62TbAwk | Rs.1070 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share? Pick
A) rs . 190 B) rs . 260 C) rs . 493 D) rs . 393 E) rs . 593 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">1_070 / 9</gadget>
<output>1_070/9 = around 118.888889</output>
<gadget id="calculator">4 * (1_070/9)</gadget>
<output>4_280/9 = around 475.555556</output>
<result>C</result> | C | 493 | Rs.1070 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share? | {
"A": "rs . 190",
"B": "rs . 260",
"C": "rs . 493",
"D": "rs . 393",
"E": "rs . 593"
} | multiply(4, divide(1070, add(add(4, 2), const_3))) | add(n1,n2)|add(#0,const_3)|divide(n0,#1)|multiply(n1,#2)| | "a + b + c = 1070 4 a = 3 b = 2 c = x a : b : c = 1 / 4 : 1 / 3 : 1 / 2 = 3 : 4 : 6 6 / 13 * 1070 = rs . 493 answer : c" | general |
math_qa__Ux6wqY4UBh5bxxkV | Nancy obtained 66, 75, 52, 68 and 89 marks (out of 100) in American Literature, History, Home Economics, Physical Education and Art. Calculate her average marks ?
Pick.
A) 50
B) 80
C) 70
D) 60
E) 71 | <gadget id="calculator">66 + 75</gadget>
<output>141</output>
<gadget id="calculator">141 + 52</gadget>
<output>193</output>
<gadget id="calculator">193 + 68</gadget>
<output>261</output>
<gadget id="calculator">261 + 89</gadget>
<output>350</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">350 / 5</gadget>
<output>70</output>
<result>C</result> | C | 70 | Nancy obtained 66, 75, 52, 68 and 89 marks (out of 100) in American Literature, History, Home Economics, Physical Education and Art. Calculate her average marks ? | {
"A": "50",
"B": "80",
"C": "70",
"D": "60",
"E": "71"
} | divide(add(add(add(add(66, 75), 52), 68), 89), add(const_4, const_1)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1) | explanation : average = ( 66 + 75 + 52 + 68 + 89 ) / 5 = 70 . answer : c ) 70 | general |
math_qa__L0B3LFAUqqlWOAhO | A textile manufacturing firm employees 80 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 80 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is:
Choices.
A) 13000 B) 7000 C) 10000 D) 4375 E) none of these | <gadget id="calculator">5 * 1_000</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 * 100</gadget>
<output>500_000</output>
<gadget id="calculator">75_000 * 2</gadget>
<output>150_000</output>
<gadget id="calculator">150_000 + 75_000</gadget>
<output>225_000</output>
<gadget id="calculator">500_000 - 225_000</gadget>
<output>275_000</output>
<gadget id="calculator">80 - 1</gadget>
<output>79</output>
<gadget id="calculator">79 / 80</gadget>
<output>79/80 = around 0.9875</output>
<gadget id="calculator">(79/80) * 500_000</gadget>
<output>493_750</output>
<gadget id="calculator">150_000 * (79/80)</gadget>
<output>148_125</output>
<gadget id="calculator">493_750 - 148_125</gadget>
<output>345_625</output>
<gadget id="calculator">345_625 - 75_000</gadget>
<output>270_625</output>
<gadget id="calculator">275_000 - 270_625</gadget>
<output>4_375</output>
<result>D</result> | D | 4,375 | A textile manufacturing firm employees 80 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 80 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is: | {
"A": "13000",
"B": "7000",
"C": "10000",
"D": "4375",
"E": "none of these"
} | subtract(subtract(multiply(multiply(5, const_1000), const_100), add(multiply(75000, const_2), 75000)), subtract(subtract(multiply(divide(subtract(80, 1), 80), multiply(multiply(5, const_1000), const_100)), multiply(multiply(75000, const_2), divide(subtract(80, 1), 80))), 75000)) | multiply(n2,const_1000)|multiply(n6,const_2)|subtract(n0,n4)|add(n6,#1)|divide(#2,n0)|multiply(#0,const_100)|multiply(#4,#5)|multiply(#4,#1)|subtract(#5,#3)|subtract(#6,#7)|subtract(#9,n6)|subtract(#8,#10)| | "explanation : profit = 5 , 00,000 â ˆ ’ ( 1 , 50,000 + 75,000 ) = rs . 2 , 75,000 . since , such loom contributes equally to sales and manufacturing expenses . but the monthly charges are fixed at rs 75,000 . if one loan breaks down sales and expenses will decrease . new profit : - = > 500000 ã — ( 79 / 80 ) â ˆ ’ 150000 ã — ( 79 / 80 ) â ˆ ’ 75000 . = > rs 2 , 70,625 . decrease in profit = > 2 , 75,000 â ˆ ’ 2 , 70,625 = > rs . 4,375 answer : d" | general |
math_qa__Hby26bfCrovvF7iu | A hiker walking at a constant rate of 4 kilometers per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 12 kilometers per hour. The cyclist stops and waits for the hiker 5 minutes after passing her while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up? Choose one
A) 10 B) 15 C) 20 D) 25 E) 30 | <gadget id="calculator">5 / 60</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">12 * (1/12)</gadget>
<output>1</output>
<gadget id="calculator">4 * (1/12)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) / 4</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 60</gadget>
<output>10</output>
<result>A</result> | A | 10 | A hiker walking at a constant rate of 4 kilometers per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 12 kilometers per hour. The cyclist stops and waits for the hiker 5 minutes after passing her while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up? | {
"A": "10",
"B": "15",
"C": "20",
"D": "25",
"E": "30"
} | multiply(divide(subtract(multiply(12, divide(5, const_60)), multiply(4, divide(5, const_60))), 4), const_60) | divide(n2,const_60)|multiply(n1,#0)|multiply(n0,#0)|subtract(#1,#2)|divide(#3,n0)|multiply(#4,const_60)| | "in 5 minutes , the cyclist travels a distance of ( 5 / 60 ) * 12 = 1 km . the time it takes the hiker to complete this distance is 1 / 4 hours = 15 minutes the cyclist needs to wait 15 - 5 = 10 minutes the answer is a ." | physics |
math_qa__EPmxdLdbBHTx9yc1 | A milk man has 30 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk.If the cost of pure milk is Rs.18 per liter,then the profit of the milkman, when he sells all the mixture at cost price is: Choices:
A) 20 % B) 25 % C) 33.33 % D) 35 % E) none of these | <gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">25 + 10</gadget>
<output>35</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) + 3</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">35 + (11/2)</gadget>
<output>81/2 = around 40.5</output>
<gadget id="calculator">(81/2) * 18</gadget>
<output>729</output>
<gadget id="calculator">30 * 18</gadget>
<output>540</output>
<gadget id="calculator">729 - 540</gadget>
<output>189</output>
<gadget id="calculator">189 / 540</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) * 100</gadget>
<output>35</output>
<result>D</result> | D | 35 | A milk man has 30 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk.If the cost of pure milk is Rs.18 per liter,then the profit of the milkman, when he sells all the mixture at cost price is: | {
"A": "20 %",
"B": "25 %",
"C": "33.33 %",
"D": "35 %",
"E": "none of these"
} | multiply(divide(subtract(multiply(add(add(add(20, 5), const_10), add(divide(5, const_2), const_3)), 18), multiply(30, 18)), multiply(30, 18)), const_100) | add(n1,n2)|divide(n1,const_2)|multiply(n0,n3)|add(#0,const_10)|add(#1,const_3)|add(#3,#4)|multiply(n3,#5)|subtract(#6,#2)|divide(#7,#2)|multiply(#8,const_100) | explanation : when the water is freely available and all the water is sold at the price of the milk , then the water gives the profit on the cost of 30 liters of milk . therefore , profit percentage = 35 % . answer : d | gain |
math_qa__Clsblsm4ZBpq2r7S | Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 180 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond? Pick one.
A) 280
B) 400
C) 540
D) 900
E) 840 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">180 / (2/5)</gadget>
<output>450</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">450 / (3/4)</gadget>
<output>600</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">600 / (2/3)</gadget>
<output>900</output>
<result>D</result> | D | 900 | Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 180 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond? | {
"A": "280",
"B": "400",
"C": "540",
"D": "900",
"E": "840"
} | divide(divide(divide(180, subtract(const_1, divide(3, 5))), divide(3, 4)), divide(2, 3)) | divide(n1,n5)|divide(n1,n3)|divide(n0,n1)|subtract(const_1,#0)|divide(n6,#3)|divide(#4,#1)|divide(#5,#2)| | "of the goose eggs laid at a certain pond , 2 / 3 hatched and 3 / 4 of the geese that hatched from those eggs survived the first month : 2 / 3 * 3 / 4 = 1 / 2 survived the first month . of the geese that survived the first month , 3 / 5 did not survive the first year : ( 1 - 3 / 5 ) * 1 / 2 = 1 / 5 survived the first year . 180 geese survived the first year : 1 / 5 * ( total ) = 180 - - > ( total ) = 900 . answer : d ." | general |
math_qa__a9IUVOwYTvJBr34V | 20 litres of mixture of acid and water contain 10% water. How much water should be added so that percentage of water becomes 20% in this mixture? Choose one.
A) 2 l
B) 3 l
C) 2.5 l
D) 4 l
E) 5 l | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">20 * (1/10)</gadget>
<output>2</output>
<result>A</result> | A | 2 | 20 litres of mixture of acid and water contain 10% water. How much water should be added so that percentage of water becomes 20% in this mixture? | {
"A": "2 l",
"B": "3 l",
"C": "2.5 l",
"D": "4 l",
"E": "5 l"
} | multiply(20, divide(const_10, const_100)) | divide(const_10,const_100)|multiply(n0,#0) | total mixture = 20 ltr water contain = 10 % of 20 ltr = > 2 ltr water it means 18 ltr is acid in that mixture we have to make 20 % water so . . 20 % of 20 = 4 ltr water must be there in the new mixture we have already 2 ltr water so we have to add 2 ltr more answer : a | general |
math_qa__F6B0GGs1yYIUbOoj | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 64 hours respectively. The ratio of their speeds is? Select: A) 4 : 5 B) 8 : 3 C) 8 : 4 D) 4 : 8 E) 4 : 1 | <gadget id="calculator">64 ** (1/2)</gadget>
<output>8</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">8 / 3</gadget>
<output>8/3 = around 2.666667</output>
<result>B</result> | B | 2.666667 | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 64 hours respectively. The ratio of their speeds is? | {
"A": "4 : 5",
"B": "8 : 3",
"C": "8 : 4",
"D": "4 : 8",
"E": "4 : 1"
} | divide(sqrt(64), sqrt(9)) | sqrt(n1)|sqrt(n0)|divide(#0,#1) | let us name the trains a and b . then , ( a ' s speed ) : ( b ' s speed ) = √ b : √ a = √ 64 : √ 9 = 8 : 3 answer : b | physics |
math_qa__iJWFLkqNbU5H5u0C | The ratio between the present ages of A and B is 6:3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1:1. What is the ratio between A's age 4 years hence and B's age 4 years ago? Choose the correct choice from the following options
A) 5 : 4 B) 3 : 0 C) 5 : 1 D) 3 : 2 E) 3 : 7 | <gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">24 + 6</gadget>
<output>30</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">30 / 6</gadget>
<output>5</output>
<result>C</result> | C | 5 | The ratio between the present ages of A and B is 6:3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1:1. What is the ratio between A's age 4 years hence and B's age 4 years ago? | {
"A": "5 : 4",
"B": "3 : 0",
"C": "5 : 1",
"D": "3 : 2",
"E": "3 : 7"
} | divide(add(multiply(6, divide(add(6, 6), subtract(6, 3))), 6), subtract(multiply(3, divide(add(6, 6), subtract(6, 3))), 6)) | add(n0,n0)|subtract(n0,n1)|divide(#0,#1)|multiply(n0,#2)|multiply(n1,#2)|add(n0,#3)|subtract(#4,n0)|divide(#5,#6)| | "let the present ages of a and b be 6 x and 3 x years respectively . then , ( 6 x - 4 ) / ( 3 x + 4 ) = 1 / 1 3 x = 8 = > x = 2.67 required ratio = ( 5 x + 4 ) : ( 3 x - 4 ) = 20 : 4 = 5 : 1 . answer : c" | other |
math_qa__eLyIOZylbeTLWzm0 | If the height of a cone is increased by 100% then its volume is increased by? Choose one:
A) 200 %
B) 300 %
C) 100 %
D) 500 %
E) 350 % | <gadget id="calculator">100 * 1</gadget>
<output>100</output>
<result>C</result> | C | 100 | If the height of a cone is increased by 100% then its volume is increased by? | {
"A": "200 %",
"B": "300 %",
"C": "100 %",
"D": "500 %",
"E": "350 %"
} | rectangle_area(100, const_1) | rectangle_area(n0,const_1)| | "height of = > 100 % so increased by 100 % answer c" | geometry |
math_qa__sIU2aPXoSHi0Y2ot | A watch was sold at a loss of 10%. If it was sold for Rs.225 more, there would have been a gain of 5%. What is the cost price? Select the correct option:
A) 1000
B) 1500
C) 2778
D) 2788
E) 2991 | <gadget id="calculator">225 * 100</gadget>
<output>22_500</output>
<gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">105 - 90</gadget>
<output>15</output>
<gadget id="calculator">22_500 / 15</gadget>
<output>1_500</output>
<result>B</result> | B | 1,500 | A watch was sold at a loss of 10%. If it was sold for Rs.225 more, there would have been a gain of 5%. What is the cost price? | {
"A": "1000",
"B": "1500",
"C": "2778",
"D": "2788",
"E": "2991"
} | divide(multiply(225, const_100), subtract(add(const_100, 5), subtract(const_100, 10))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "90 % 105 % - - - - - - - - 15 % - - - - 225 100 % - - - - ? = > rs . 1500 answer : b" | gain |
math_qa__qXHvCZ1nFKduYVUL | In what time will a train 60 m long cross an electric pole, it its speed be 144 km/hr?
Choose the correct choice from the following choices:
A) 2.5 sec
B) 2.8 sec
C) 7.5 sec
D) 2.3 sec
E) 1.5 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">60 / 40</gadget>
<output>3/2 = around 1.5</output>
<result>E</result> | E | 1.5 | In what time will a train 60 m long cross an electric pole, it its speed be 144 km/hr? | {
"A": "2.5 sec",
"B": "2.8 sec",
"C": "7.5 sec",
"D": "2.3 sec",
"E": "1.5 sec"
} | divide(60, multiply(144, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 144 * 5 / 18 = 40 m / sec time taken = 60 / 40 = 1.5 sec . answer : e" | physics |
math_qa__douCEgz7QqDuh7Hq | How much is 50% of 40 is greater than 4/5 of 25? Select the correct option:
A) 0
B) 67
C) 88
D) 12
E) 66 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">40 * (1/2)</gadget>
<output>20</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 25</gadget>
<output>20</output>
<gadget id="calculator">20 - 20</gadget>
<output>0</output>
<result>A</result> | A | 0 | How much is 50% of 40 is greater than 4/5 of 25? | {
"A": "0",
"B": "67",
"C": "88",
"D": "12",
"E": "66"
} | subtract(multiply(40, divide(50, const_100)), multiply(divide(4, 5), 25)) | divide(n0,const_100)|divide(n2,n3)|multiply(n1,#0)|multiply(n4,#1)|subtract(#2,#3)| | "( 50 / 100 ) * 40 – ( 4 / 5 ) * 25 = 0 answer : a" | general |
math_qa__Po6B2E57k9TZ70v3 | A certain telescope increases the visual range at a particular location from 80 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? Pick
A) 30 % B) 33 1 / 2 % C) 40 % D) 60 % E) 87.5 % | <gadget id="calculator">150 - 80</gadget>
<output>70</output>
<gadget id="calculator">70 / 80</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">(7/8) * 100</gadget>
<output>175/2 = around 87.5</output>
<result>E</result> | E | 87.5 | A certain telescope increases the visual range at a particular location from 80 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? | {
"A": "30 %",
"B": "33 1 / 2 %",
"C": "40 %",
"D": "60 %",
"E": "87.5 %"
} | multiply(divide(subtract(150, 80), 80), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "original visual range = 80 km new visual range = 150 km percent increase in the visual range by using the telescope = ( 150 - 80 ) / 80 * 100 % = 7 / 8 * 100 % = 87.5 % answer e" | general |
math_qa__SnzkRR0aQ21Q0gnW | 34. The side surface of a cylinder is rolled with a rectangle. If the height of a cylinder is 16 feet and the perimeter of the circular base. Is 12 feet, what is the diagonal of the rectangle? Choose the correct choice from the following answers
A) 16 B) 20 C) 18 D) 22 E) 21 | <gadget id="calculator">16 * 16</gadget>
<output>256</output>
<gadget id="calculator">12 * 12</gadget>
<output>144</output>
<gadget id="calculator">256 + 144</gadget>
<output>400</output>
<gadget id="calculator">400 ** (1/2)</gadget>
<output>20</output>
<result>B</result> | B | 20 | 34. The side surface of a cylinder is rolled with a rectangle. If the height of a cylinder is 16 feet and the perimeter of the circular base. Is 12 feet, what is the diagonal of the rectangle? | {
"A": "16",
"B": "20",
"C": "18",
"D": "22",
"E": "21"
} | sqrt(add(multiply(16, 16), multiply(12, 12))) | multiply(n1,n1)|multiply(n2,n2)|add(#0,#1)|sqrt(#2) | think of an aluminum can can . if you took off the bottom and top and cut a slit down the length , it would flatten to a rectangle . the dimensions of the rectangle are the height of the can and the circumference of the circle . since you know both , use pythagoreans theorem or properties of 3 - 4 - 5 triangles to solve for the hypothenuse , 20 . ( correct answer b ) | geometry |
math_qa__KLhQZLYxxTkhOUtL | If (x + yi) / i = ( 7 + 9i ) , where x and y are real, what is the value of (x + yi)(x - yi)? Pick.
A) 110 B) 120 C) 130 D) 140 E) 150 | <gadget id="calculator">7 * 9</gadget>
<output>63</output>
<gadget id="calculator">63 * 2</gadget>
<output>126</output>
<result>C</result> | C | 130 | If (x + yi) / i = ( 7 + 9i ) , where x and y are real, what is the value of (x + yi)(x - yi)? | {
"A": "110",
"B": "120",
"C": "130",
"D": "140",
"E": "150"
} | multiply(multiply(7, 9), const_2) | multiply(n0,n1)|multiply(#0,const_2) | ( x + yi ) / i = ( 7 + 9 i ) ( x + yi ) = i ( 7 + 9 i ) = - 9 + 7 i ( x + yi ) ( x - yi ) = ( - 9 + 7 i ) ( - 9 - 7 i ) = 81 + 49 = 130 correct answer is c 0130 | general |
math_qa__N9TZ2Qk8hHTRijBc | How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 240 m in length? Choose the correct answer.
A) 18.9 sec B) 88.9 sec C) 22.9 sec D) 21.00 sec E) 72.0 sec | <gadget id="calculator">110 + 240</gadget>
<output>350</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">350 / (50/3)</gadget>
<output>21</output>
<result>D</result> | D | 21 | How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 240 m in length? | {
"A": "18.9 sec",
"B": "88.9 sec",
"C": "22.9 sec",
"D": "21.00 sec",
"E": "72.0 sec"
} | divide(add(110, 240), multiply(60, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "d = 110 + 240 = 350 m s = 60 * 5 / 18 = 50 / 3 t = 350 * 3 / 50 = 21.00 sec answer : d" | physics |
math_qa__QjFEWo1pT9a9uRDz | It takes 40 identical printing presses 12 hours to print 500,000 papers. How many hours would it take 30 of these printing presses to print 500,000 papers? Choose the correct choice from the following answers: A) 14 B) 15 C) 16 D) 18 E) 20 | <gadget id="calculator">1_000 / 2</gadget>
<output>500</output>
<gadget id="calculator">500 * 1_000</gadget>
<output>500_000</output>
<gadget id="calculator">500_000 / 40</gadget>
<output>12_500</output>
<gadget id="calculator">12_500 / 12</gadget>
<output>3_125/3 = around 1_041.666667</output>
<gadget id="calculator">(3_125/3) * 30</gadget>
<output>31_250</output>
<gadget id="calculator">500_000 / 31_250</gadget>
<output>16</output>
<result>C</result> | C | 16 | It takes 40 identical printing presses 12 hours to print 500,000 papers. How many hours would it take 30 of these printing presses to print 500,000 papers? | {
"A": "14",
"B": "15",
"C": "16",
"D": "18",
"E": "20"
} | divide(multiply(divide(const_1000, const_2), const_1000), multiply(divide(divide(multiply(divide(const_1000, const_2), const_1000), 40), 12), 30)) | divide(const_1000,const_2)|multiply(#0,const_1000)|divide(#1,n0)|divide(#2,n1)|multiply(n3,#3)|divide(#1,#4)| | "40 printing presses can do 1 / 12 of the job each hour . 30 printing presses can do 3 / 4 * 1 / 12 = 1 / 16 of the job each hour . the answer is c ." | physics |
math_qa__iNMtj52TGB6Ong0W | A certain company reported that the revenue on sales increased 60 % from 2000 to 2003, and increased 80 % from 2000 to 2005. What was the approximate percent increase in revenue for this store from 2003 to 2005?
Pick one.
A) 50 % B) 40 % C) 35 % D) 32 % E) 13 % | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 + (4/5)</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 + (3/5)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(9/5) - (8/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / (8/5)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 100</gadget>
<output>25/2 = around 12.5</output>
<result>E</result> | E | 13 | A certain company reported that the revenue on sales increased 60 % from 2000 to 2003, and increased 80 % from 2000 to 2005. What was the approximate percent increase in revenue for this store from 2003 to 2005? | {
"A": "50 %",
"B": "40 %",
"C": "35 %",
"D": "32 %",
"E": "13 %"
} | multiply(divide(subtract(add(const_1, divide(80, const_100)), add(const_1, divide(60, const_100))), add(const_1, divide(60, const_100))), const_100) | divide(n3,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|subtract(#2,#3)|divide(#4,#3)|multiply(#5,const_100)| | "assume the revenue in 2000 to be 100 . then in 2003 it would be 160 and and in 2005 180 , so from 2003 to 2005 it increased by ( 180 - 160 ) / 160 = 20 / 160 = 13 % answer : e ." | gain |
math_qa__CYAR39bQNC9X5rN6 | if the price of a book is first decreased by 25% and then increased by 20%, then the net change in the price will be : Choose the correct option.
A) 10 B) 388 C) 37 D) 29 E) 22 | <gadget id="calculator">100 * 25</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 100</gadget>
<output>25</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">100 * 20</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 100</gadget>
<output>20</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(3/4) * (6/5)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 100</gadget>
<output>90</output>
<gadget id="calculator">100 - 90</gadget>
<output>10</output>
<result>A</result> | A | 10 | if the price of a book is first decreased by 25% and then increased by 20%, then the net change in the price will be : | {
"A": "10",
"B": "388",
"C": "37",
"D": "29",
"E": "22"
} | subtract(const_100, multiply(multiply(divide(subtract(const_100, divide(multiply(const_100, 25), const_100)), const_100), divide(add(const_100, divide(multiply(const_100, 20), const_100)), const_100)), const_100)) | multiply(n0,const_100)|multiply(n1,const_100)|divide(#0,const_100)|divide(#1,const_100)|add(#3,const_100)|subtract(const_100,#2)|divide(#5,const_100)|divide(#4,const_100)|multiply(#6,#7)|multiply(#8,const_100)|subtract(const_100,#9)| | "explanation : let the original price be rs . 100 . new final price = 120 % of ( 75 % of rs . 100 ) = rs . ( 120 / 100 * 75 / 100 * 100 ) = rs . 90 . decrease = 10 % answer : a ) 10" | general |
math_qa__1PwISLiTZzAJMQE0 | P runs 20% faster than Q so P gives Q a 300 meter head start. If the race ends in a tie, how far (in meters) did P run in the race? Choose the correct choice from the following choices:
A) 1500 B) 1600 C) 1700 D) 1800 E) 1900 | <gadget id="calculator">300 * 100</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 / 20</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 + 300</gadget>
<output>1_800</output>
<result>D</result> | D | 1,800 | P runs 20% faster than Q so P gives Q a 300 meter head start. If the race ends in a tie, how far (in meters) did P run in the race? | {
"A": "1500",
"B": "1600",
"C": "1700",
"D": "1800",
"E": "1900"
} | add(divide(multiply(300, const_100), 20), 300) | multiply(n1,const_100)|divide(#0,n0)|add(n1,#1)| | "let d be the race distance that p ran . let t be the time it took to complete the race . let v be q ' s speed . t = d / 1.2 v = ( d - 300 ) / v d = 1.2 d - 360 0.2 d = 360 d = 1800 meters . the answer is d ." | gain |
math_qa__TeYPZlul3V73MwgC | If a certain number is divided by 11, the quotient, dividend, and divisor, added together, will amount to 71. What is the number? Pick one
A) 18
B) 28
C) 48
D) 38
E) 55 | <gadget id="calculator">71 - 11</gadget>
<output>60</output>
<gadget id="calculator">60 * 11</gadget>
<output>660</output>
<gadget id="calculator">11 + 1</gadget>
<output>12</output>
<gadget id="calculator">660 / 12</gadget>
<output>55</output>
<result>E</result> | E | 55 | If a certain number is divided by 11, the quotient, dividend, and divisor, added together, will amount to 71. What is the number? | {
"A": "18",
"B": "28",
"C": "48",
"D": "38",
"E": "55"
} | divide(multiply(subtract(71, 11), 11), add(11, const_1)) | add(n0,const_1)|subtract(n1,n0)|multiply(n0,#1)|divide(#2,#0)| | "let x = the number sought . then x / 11 + x + 11 = 71 and x = 55 . e" | general |
math_qa__GAewgyWA8Mm127ak | The population of a town increases 25% and 30% respectively in two consecutive years. After the growth the present population of the town is 1950. Then what is the population of the town 2 years ago? Choose the correct answer
A) 800 B) 900 C) 1000 D) 1100 E) 1200 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">(5/4) * (13/10)</gadget>
<output>13/8 = around 1.625</output>
<gadget id="calculator">1_950 / (13/8)</gadget>
<output>1_200</output>
<result>E</result> | E | 1,200 | The population of a town increases 25% and 30% respectively in two consecutive years. After the growth the present population of the town is 1950. Then what is the population of the town 2 years ago? | {
"A": "800",
"B": "900",
"C": "1000",
"D": "1100",
"E": "1200"
} | divide(1950, multiply(add(const_1, divide(25, const_100)), add(const_1, divide(30, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|divide(n2,#4)| | "explanation : formula : ( after = 100 denominator ago = 100 numerator ) 1950 * 100 / 125 * 100 / 130 = 1200 answer : option e" | gain |
math_qa__3AsJ1ihsFoM2KLty | The number 0.127 is how much greater than 1/8 ? Pick
A) 1 / 100
B) 1 / 1500
C) 1 / 2
D) 1 / 500
E) 1 / 600 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">0.127 - (1/8)</gadget>
<output>0.002</output>
<result>D</result> | D | 0.002 | The number 0.127 is how much greater than 1/8 ? | {
"A": "1 / 100",
"B": "1 / 1500",
"C": "1 / 2",
"D": "1 / 500",
"E": "1 / 600"
} | subtract(0.127, divide(1, 8)) | divide(n1,n2)|subtract(n0,#0)| | "explanation : 0.127 expressed as a fraction = 127 / 1000 1 / 8 can also be expressed as ( 1 x 125 ) / ( 8 x 125 ) = 125 / 1000 the difference is 2 / 1000 , which is 1 / 500 answer is d" | general |
math_qa__LVOKAE5ldoE8HNCP | A retailer purchases shirts from a wholesaler and then sells the shirts in her store at a retail price that is 80 percent greater than the wholesale price. If the retailer decreases the retail price by 25 percent this will have the same effect as increasing the wholesale price by what percent? Choose the correct choice from the following answers:
A) 26 B) 37.5 C) 35 D) 44 E) 50 | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 + (4/5)</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(9/5) * (3/4)</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">(27/20) - 1</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) * 100</gadget>
<output>35</output>
<result>C</result> | C | 35 | A retailer purchases shirts from a wholesaler and then sells the shirts in her store at a retail price that is 80 percent greater than the wholesale price. If the retailer decreases the retail price by 25 percent this will have the same effect as increasing the wholesale price by what percent? | {
"A": "26",
"B": "37.5",
"C": "35",
"D": "44",
"E": "50"
} | multiply(subtract(multiply(add(const_1, divide(80, const_100)), subtract(const_1, divide(25, const_100))), const_1), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "answer : c = 35 . assume rs . 100 to be the price at which the retailer buys from wholesaler . 80 % increase makes retail price = 180 . now 25 % decrease - > ( 1 - 25 / 100 ) * 180 = 135 . now compared to the wholesale price of 100 , 35 % increase is what will have the same effect as increasing the wholesale price ." | gain |
math_qa__uHZqc1aoyz4sjZaj | A cistern which could be filled in 4 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it? Pick: A) 76 hrs B) 99 hrs C) 55 hrs D) 20 / 3 hrs E) 11 hrs | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/4) - (1/10)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 / (3/20)</gadget>
<output>20/3 = around 6.666667</output>
<result>D</result> | D | 6.666667 | A cistern which could be filled in 4 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it? | {
"A": "76 hrs",
"B": "99 hrs",
"C": "55 hrs",
"D": "20 / 3 hrs",
"E": "11 hrs"
} | inverse(subtract(divide(const_1, 4), divide(const_1, const_10))) | divide(const_1,n0)|divide(const_1,const_10)|subtract(#0,#1)|inverse(#2)| | "1 / 4 - 1 / x = 1 / 10 = > 20 / 3 hrs answer : d" | physics |
math_qa__P2Msx8hwlT8469ej | Let p be a prime number. If N = 7P, how many divisors does N have? Choices:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) - 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(1/2) + (3/2)</gadget>
<output>2</output>
<result>B</result> | B | 2 | Let p be a prime number. If N = 7P, how many divisors does N have? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | add(divide(const_1, const_2), subtract(divide(7, const_2), const_2)) | divide(const_1,const_2)|divide(n0,const_2)|subtract(#1,const_2)|add(#0,#2) | two . n = 7 * p , and both 7 and p are prime . so the answer is b . | general |
math_qa__rx7mcStJZ2ZTjuLq | in a factory there are 3 types of machine m 1 , m 2 and m which produces 25 % , 35 % and 40 % of the total products respectively . m 1 , m 2 and m 3 produces 2 % , 4 % and 5 % defective products , respectively . what is the percentage of non - defective products ? Choose the correct choice from the following:
A) 89 % B) 97.1 % C) 96.1 % D) 86.1 % E) none of these | <gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 25</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) * 35</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(1/2) + (7/5)</gadget>
<output>19/10 = around 1.9</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 40</gadget>
<output>2</output>
<gadget id="calculator">(19/10) + 2</gadget>
<output>39/10 = around 3.9</output>
<gadget id="calculator">100 - (39/10)</gadget>
<output>961/10 = around 96.1</output>
<result>C</result> | C | 96.1 | in a factory there are 3 types of machine m 1 , m 2 and m which produces 25 % , 35 % and 40 % of the total products respectively . m 1 , m 2 and m 3 produces 2 % , 4 % and 5 % defective products , respectively . what is the percentage of non - defective products ? | {
"A": "89 %",
"B": "97.1 %",
"C": "96.1 %",
"D": "86.1 %",
"E": "none of these"
} | subtract(const_100, add(add(multiply(divide(2, const_100), 25), multiply(divide(4, const_100), 35)), multiply(divide(5, const_100), 40))) | divide(n2,const_100)|divide(n10,const_100)|divide(n11,const_100)|multiply(n3,#0)|multiply(n4,#1)|multiply(n5,#2)|add(#3,#4)|add(#6,#5)|subtract(const_100,#7) | solution : non - defective products , { [ ( 25 * 0.98 ) + ( 35 * 0.96 ) + ( 40 * 0.95 ) ] / 100 } * 100 = 96.1 % . answer : option c | general |
math_qa__7djn65nrMwAgcPWm | 6 animals of a circus has to be placed inside in 6 cages one in each cage . if 4 of the cage are too small for 6 of the animal then find the number of ways of caging the animal . Answers.
A) a . 240
B) b . 808250
C) c . 502450
D) d . 784200
E) e . 302400 | <gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">24 * 10</gadget>
<output>240</output>
<result>A</result> | A | 240 | 6 animals of a circus has to be placed inside in 6 cages one in each cage . if 4 of the cage are too small for 6 of the animal then find the number of ways of caging the animal . | {
"A": "a . 240",
"B": "b . 808250",
"C": "c . 502450",
"D": "d . 784200",
"E": "e . 302400"
} | multiply(multiply(6, 4), const_10) | multiply(n0,n2)|multiply(#0,const_10) | ways for cages that are too small = 5 * 4 * 3 * 2 = 120 since we have 2 cages and 2 animal left therefore ways for 2 cages = 2 ! total ways = 120 * 2 ! = 604800 answer a | probability |
math_qa__excWJOOkh6vwgX8w | A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 30 seconds. What is the length of the goods train? Choose the correct option.
A) 230 m B) 350 m C) 260 m D) 270 m E) none of these | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 72</gadget>
<output>20</output>
<gadget id="calculator">250 / 20</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">30 - (25/2)</gadget>
<output>35/2 = around 17.5</output>
<gadget id="calculator">(35/2) * 20</gadget>
<output>350</output>
<result>B</result> | B | 350 | A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 30 seconds. What is the length of the goods train? | {
"A": "230 m",
"B": "350 m",
"C": "260 m",
"D": "270 m",
"E": "none of these"
} | multiply(subtract(30, divide(250, multiply(const_0_2778, 72))), multiply(const_0_2778, 72)) | multiply(n0,const_0_2778)|divide(n1,#0)|subtract(n2,#1)|multiply(#0,#2)| | "explanation : speed = [ 72 x ( 5 / 18 ) ] m / sec = 20 m / sec . time = 30 sec . let the length of the train be x metres . then , [ ( x + 250 ) / 30 ] = 20 = > x + 250 = 600 = > x = 350 . answer : b" | physics |
math_qa__RmBvNcFHMQ4MebSI | The speed at which a man can row a boat in still water is 6 km/hr. If he rows downstream, where the speed of current is 3 km/hr, how many seconds will he take to cover 80 meters?
Choose one:
A) 28
B) 32
C) 36
D) 40
E) 44 | <gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">9 * (5/18)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">80 / (5/2)</gadget>
<output>32</output>
<result>B</result> | B | 32 | The speed at which a man can row a boat in still water is 6 km/hr. If he rows downstream, where the speed of current is 3 km/hr, how many seconds will he take to cover 80 meters? | {
"A": "28",
"B": "32",
"C": "36",
"D": "40",
"E": "44"
} | divide(80, multiply(add(6, 3), const_0_2778)) | add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1)| | "the speed of the boat downstream = 6 + 3 = 9 km / hr 9 km / hr * 5 / 18 = 2.5 m / s the time taken to cover 80 meters = 80 / 2.5 = 32 seconds . the answer is b ." | physics |
math_qa__wnQRSl2i9zOLMvbB | A retailer buys a radio for Rs 225. His overhead expenses are Rs 15. He sellis the radio for Rs 300. The profit percent of the retailer is Choices
A) 10 % B) 50 % C) 25 % D) 52 % E) none of these | <gadget id="calculator">225 + 15</gadget>
<output>240</output>
<gadget id="calculator">300 / 240</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 100</gadget>
<output>125</output>
<gadget id="calculator">125 - 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | A retailer buys a radio for Rs 225. His overhead expenses are Rs 15. He sellis the radio for Rs 300. The profit percent of the retailer is | {
"A": "10 %",
"B": "50 %",
"C": "25 %",
"D": "52 %",
"E": "none of these"
} | subtract(multiply(divide(300, add(225, 15)), const_100), const_100) | add(n0,n1)|divide(n2,#0)|multiply(#1,const_100)|subtract(#2,const_100)| | "explanation : cost price = ( 225 + 15 ) = 240 sell price = 300 gain = ( 60 / 240 ) * 100 = 25 % . answer : c" | gain |
math_qa__AeOmeVaoEYRnBDPh | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction R of the total distance did he cover while the sun was shining on him? Choose the correct choice from the following
A) 1 / 4
B) 4 / 5
C) 1 / 5
D) 1 / 6
E) 1 / 7 | <gadget id="calculator">lcm(2, 3)</gadget>
<output>6</output>
<gadget id="calculator">6 / 2.8</gadget>
<output>2.142857</output>
<gadget id="calculator">2.142857 - 2</gadget>
<output>0.142857</output>
<result>E</result> | E | 0.142857 | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction R of the total distance did he cover while the sun was shining on him? | {
"A": "1 / 4",
"B": "4 / 5",
"C": "1 / 5",
"D": "1 / 6",
"E": "1 / 7"
} | subtract(divide(lcm(const_2, const_3), 2.8), const_2) | lcm(const_2,const_3)|divide(#0,n1)|subtract(#1,const_2)| | if s is an integer and we know that the average speed is 2.8 , s must be = 2 . that meanss + 1 = 3 . this implies that the ratio of time for s = 2 is 1 / 4 of the total time . the formula for distance / rate is d = rt . . . so the distance travelled when s = 2 is 2 t . the distance travelled for s + 1 = 3 is 3 * 4 t or 12 t . therefore , total distance covered while the sun was shining over him is r = 2 / 14 = 1 / 7 . answer : e | general |
math_qa__8CRwx2HSKCt309db | Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 5 kg of fresh grapes?
Choose the correct choice:
A) 2 kg
B) 2.4 kg
C) 2.5 kg
D) 10 kg
E) 0.625 | <gadget id="calculator">100 - 90</gadget>
<output>10</output>
<gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">(1/2) / 80</gadget>
<output>1/160 = around 0.00625</output>
<gadget id="calculator">(1/160) * 100</gadget>
<output>5/8 = around 0.625</output>
<result>E</result> | E | 0.625 | Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 5 kg of fresh grapes? | {
"A": "2 kg",
"B": "2.4 kg",
"C": "2.5 kg",
"D": "10 kg",
"E": "0.625"
} | multiply(divide(divide(multiply(subtract(const_100, 90), 5), const_100), subtract(const_100, 20)), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|multiply(n2,#0)|divide(#2,const_100)|divide(#3,#1)|multiply(#4,const_100)| | "the weight of non - water in 5 kg of fresh grapes ( which is 100 - 90 = 10 % of whole weight ) will be the same as the weight of non - water in x kg of dried grapes ( which is 100 - 20 = 80 % of whole weight ) , so 5 â ˆ — 0.1 = x â ˆ — 0.8 - - > x = 0.625 answer : e ." | gain |
math_qa__IRAYKRQ3zxmZtbgz | In a certain state, the ratio of registered Republicans to registered Democrats is 3 to 2, and every registered voter is either a Republican or a Democrat. If 80 percent of the Republicans and 25 percent of the Democrats are expected to vote for Candidate X, and everyone else is expected to vote for Candidate Y, by what percent is Candidate X expected to win the election? Select:
A) 2 % B) 5 % C) 16 % D) 20 % E) 25 % | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 3</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(1/2) + (12/5)</gadget>
<output>29/10 = around 2.9</output>
<gadget id="calculator">3 - (12/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">2 - (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/5) + (3/2)</gadget>
<output>21/10 = around 2.1</output>
<gadget id="calculator">(29/10) - (21/10)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">(4/5) / 5</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * 100</gadget>
<output>16</output>
<result>C</result> | C | 16 | In a certain state, the ratio of registered Republicans to registered Democrats is 3 to 2, and every registered voter is either a Republican or a Democrat. If 80 percent of the Republicans and 25 percent of the Democrats are expected to vote for Candidate X, and everyone else is expected to vote for Candidate Y, by what percent is Candidate X expected to win the election? | {
"A": "2 %",
"B": "5 %",
"C": "16 %",
"D": "20 %",
"E": "25 %"
} | multiply(divide(subtract(add(multiply(divide(25, const_100), 2), multiply(divide(80, const_100), 3)), add(subtract(3, multiply(divide(80, const_100), 3)), subtract(2, multiply(divide(25, const_100), 2)))), add(3, 2)), const_100) | add(n0,n1)|divide(n3,const_100)|divide(n2,const_100)|multiply(n1,#1)|multiply(n0,#2)|add(#3,#4)|subtract(n0,#4)|subtract(n1,#3)|add(#6,#7)|subtract(#5,#8)|divide(#9,#0)|multiply(#10,const_100)| | "since we were expected to find a percentage figure - it thought that it might be easier to pick a ' smart number ' to represent the total number of voters ( republicans and democrats ) . therefore , i picked 100 ( as the total number of voters ) and thus 30 : 20 represents the number ratio of republicans : democrats . if 80 % of republicans ( which is ( 60 * 0.8 ) = 48 ) and 25 % of democrats ( 40 * 0.25 = 10 ) voted for candidate x , means that out of total of 100 voters ; 58 ( 48 + 10 ) voters voted for candidate x and 42 voted for candidate y . thus we can infer that candidate x is expected to win the election by 16 ( 58 - 42 ) votes . therefore candidate x is expected to win the election by ( 16 / 100 ) votes which is equivalent to 16 % . i think the answer is c ." | other |
math_qa__kRcPJHC2yfPy01KR | The simple interest on a certain sum of money at the rate of 5% p.a. for 8 years is Rs. 840.At what rate of interest the same amount of interest can be received on the same sum after 5 years ? Options:
A) 6 %
B) 8 %
C) 9 %
D) 10 %
E) none | <gadget id="calculator">840 / 5</gadget>
<output>168</output>
<gadget id="calculator">840 / 8</gadget>
<output>105</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">105 / (1/20)</gadget>
<output>2_100</output>
<gadget id="calculator">168 / 2_100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/25) * 100</gadget>
<output>8</output>
<result>B</result> | B | 8 | The simple interest on a certain sum of money at the rate of 5% p.a. for 8 years is Rs. 840.At what rate of interest the same amount of interest can be received on the same sum after 5 years ? | {
"A": "6 %",
"B": "8 %",
"C": "9 %",
"D": "10 %",
"E": "none"
} | multiply(divide(divide(840, 5), divide(divide(840, 8), divide(5, const_100))), const_100) | divide(n2,n0)|divide(n2,n1)|divide(n0,const_100)|divide(#1,#2)|divide(#0,#3)|multiply(#4,const_100)| | "solution s . i . = rs . 840 , r = 5 % , t = 8 years . principal = rs . ( 800 x 840 / 5 x 8 ) = rs . 2100 . now , p = rs . 2100 , s . i . = rs . 840 , t = 5 years . ∴ rate = ( 100 x 840 / 2100 x 5 ) = 8 % . answer b" | gain |
math_qa__bhUQT5orSha88PfQ | What is the rate percent when the simple interest on Rs.1200 amount to Rs.400 in 4 Years? Choose the correct choice from the following answers
A) 8.33 %
B) 6 %
C) 2 %
D) 95 %
E) 1 % | <gadget id="calculator">100 * 400</gadget>
<output>40_000</output>
<gadget id="calculator">1_200 * 4</gadget>
<output>4_800</output>
<gadget id="calculator">40_000 / 4_800</gadget>
<output>25/3 = around 8.333333</output>
<result>A</result> | A | 8.33 | What is the rate percent when the simple interest on Rs.1200 amount to Rs.400 in 4 Years? | {
"A": "8.33 %",
"B": "6 %",
"C": "2 %",
"D": "95 %",
"E": "1 %"
} | divide(multiply(const_100, 400), multiply(1200, 4)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)| | "interest for 4 yrs = 400 interest for 1 yr = 100 interest rate = 100 / 1200 x 100 = 8.33 % answer : a" | gain |
math_qa__O0HPnzqQ42i5cyxE | The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is?
Choose the correct choice from the following choices
A) 24 kg B) 62 kg C) 34 kg D) 31 kg E) 37 kg | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">43 * 2</gadget>
<output>86</output>
<gadget id="calculator">80 + 86</gadget>
<output>166</output>
<gadget id="calculator">45 * 3</gadget>
<output>135</output>
<gadget id="calculator">166 - 135</gadget>
<output>31</output>
<result>D</result> | D | 31 | The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is? | {
"A": "24 kg",
"B": "62 kg",
"C": "34 kg",
"D": "31 kg",
"E": "37 kg"
} | subtract(add(multiply(40, const_2), multiply(43, const_2)), multiply(45, const_3)) | multiply(n1,const_2)|multiply(n2,const_2)|multiply(n0,const_3)|add(#0,#1)|subtract(#3,#2)| | "let a , b , c represent their respective weights . then , we have : a + b + c = ( 45 * 3 ) = 135 - - - ( i ) a + b = ( 40 * 2 ) = 80 - - - ( ii ) b + c = ( 43 * 2 ) = 86 - - - ( iii ) adding ( ii ) and ( iii ) , we get : a + 2 b + c = 166 - - - ( iv ) subtracting ( i ) from ( iv ) , we get : b = 31 b ' s weight = 31 kg . answer : d" | general |
math_qa__OOog5CDaBOZstaaj | 400 students took a mock exam in Delhi, 60% of the boys and 80% of the girls cleared the cut off in the examination. If the total percentage of students qualifying is 65%, how many girls appeared in the examination? Choose the correct option.
A) 50 B) 100 C) 120 D) 140 E) 180 | <gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">400 * (13/20)</gadget>
<output>260</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">400 * (3/5)</gadget>
<output>240</output>
<gadget id="calculator">260 - 240</gadget>
<output>20</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) - (3/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">20 / (1/5)</gadget>
<output>100</output>
<result>B</result> | B | 100 | 400 students took a mock exam in Delhi, 60% of the boys and 80% of the girls cleared the cut off in the examination. If the total percentage of students qualifying is 65%, how many girls appeared in the examination? | {
"A": "50",
"B": "100",
"C": "120",
"D": "140",
"E": "180"
} | divide(subtract(multiply(400, divide(65, const_100)), multiply(400, divide(60, const_100))), subtract(divide(80, const_100), divide(60, const_100))) | divide(n3,const_100)|divide(n1,const_100)|divide(n2,const_100)|multiply(n0,#0)|multiply(n0,#1)|subtract(#2,#1)|subtract(#3,#4)|divide(#6,#5) | 60 % * x + 80 % * ( 400 - x ) = 65 % * 400 ans = 100 answer : b | general |
math_qa__HJWwE0AbOMKJaHm1 | What is the greater of the two numbers whose product is 2688, given that the sum of the two numbers exceeds their difference by 64? Choose the correct choice:
A) 84 B) 104 C) 110 D) 72 E) of these | <gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 2</gadget>
<output>32</output>
<gadget id="calculator">2_688 / 32</gadget>
<output>84</output>
<result>A</result> | A | 84 | What is the greater of the two numbers whose product is 2688, given that the sum of the two numbers exceeds their difference by 64? | {
"A": "84",
"B": "104",
"C": "110",
"D": "72",
"E": "of these"
} | divide(2688, multiply(power(const_2, const_4), const_2)) | power(const_2,const_4)|multiply(#0,const_2)|divide(n0,#1)| | "let the greater and the smaller number be g and s respectively . gs = 2560 g + s exceeds g - s by 64 i . e . , g + s - ( g - s ) = 64 i . e . , 2 s = 64 = > s = 32 . g = 2688 / s = 84 . answer : a" | general |
math_qa__kMvVh7NkoOIa6VqM | The proportion of copper and zinc in the brass is 3:7. How much zinc will there be in 100 kg of brass?
Choose the correct choice from the following answers
A) 70 B) 50 C) 40 D) 270 E) 170 | <gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">7 / 10</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 100</gadget>
<output>70</output>
<result>A</result> | A | 70 | The proportion of copper and zinc in the brass is 3:7. How much zinc will there be in 100 kg of brass? | {
"A": "70",
"B": "50",
"C": "40",
"D": "270",
"E": "170"
} | multiply(divide(7, add(7, 3)), 100) | add(n0,n1)|divide(n1,#0)|multiply(n2,#1)| | "7 / 10 * 100 = 70 answer : a" | general |
math_qa__oodgeCUIkU97YmJq | A contractor undertakes to do a job within 100 days and hires 10 people to do it. After 20 days, he realizes that one fourth of the work is done so he fires 2 people. In how many more days Q will the work get over?
Choose the correct choice:
A) q = 60 B) q = 70 C) q = 75 D) 80 E) 100 | <gadget id="calculator">10 * 20</gadget>
<output>200</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">200 / (1/4)</gadget>
<output>800</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">800 * (3/4)</gadget>
<output>600</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">600 / 8</gadget>
<output>75</output>
<result>C</result> | C | 75 | A contractor undertakes to do a job within 100 days and hires 10 people to do it. After 20 days, he realizes that one fourth of the work is done so he fires 2 people. In how many more days Q will the work get over? | {
"A": "q = 60",
"B": "q = 70",
"C": "q = 75",
"D": "80",
"E": "100"
} | divide(multiply(divide(multiply(10, 20), const_0_25), subtract(const_1, const_0_25)), subtract(10, 2)) | multiply(n1,n2)|subtract(const_1,const_0_25)|subtract(n1,n3)|divide(#0,const_0_25)|multiply(#3,#1)|divide(#4,#2) | we can also use the concept of man - days here 100 days - - > 10 men so the job includes 100 * 10 = 1000 man - days after 20 days 1 / 4 of job is completed so 1 / 4 x 1000 man - days = 250 man - days job is done now the balance job = 1000 - 250 = 750 man - days worth of job since 2 men are fired so b / l men = 8 therefore total no . of days of job = 750 man - day / 8 days = 375 / 4 = 94 days ( approx . ) now since this is total and ques . is asking for additional no . of days , so 94 - 20 = 74 days the nearest approx . to answer is 75 ans : c ( 75 days ) | physics |
math_qa__ZaP1mrZOnl7fW9E3 | Find the value of c from (8)^3 x 9^3 ÷ 679 = c. Select.
A) 249.7 B) 529.7 C) 549.7 D) 594.7 E) 119.7 | <gadget id="calculator">8 ** 3</gadget>
<output>512</output>
<gadget id="calculator">9 ** 3</gadget>
<output>729</output>
<gadget id="calculator">512 * 729</gadget>
<output>373_248</output>
<gadget id="calculator">373_248 / 679</gadget>
<output>373_248/679 = around 549.702504</output>
<result>C</result> | C | 549.7 | Find the value of c from (8)^3 x 9^3 ÷ 679 = c. | {
"A": "249.7",
"B": "529.7",
"C": "549.7",
"D": "594.7",
"E": "119.7"
} | divide(multiply(power(8, 3), power(9, 3)), 679) | power(n0,n1)|power(n2,n1)|multiply(#0,#1)|divide(#2,n4) | given exp . = ( 8 ) ^ 3 x 9 ^ 3 ã · 679 = c = 512 x 729 ã · 679 = 549.7 c | general |
math_qa__g7HF4H1uIsAmEMCC | A man has $ 10,000 to invest. He invests $ 4000 at 5 % and $ 3500 at 4 %. In order to have a yearly income of $ 500, he must invest the remainder at Select the correct option
A) 6 % B) 6.1 % C) 6.2 % D) 6.3 % E) 6.4 % | <gadget id="calculator">4_000 / 100</gadget>
<output>40</output>
<gadget id="calculator">40 * 5</gadget>
<output>200</output>
<gadget id="calculator">500 - 200</gadget>
<output>300</output>
<gadget id="calculator">3_500 / 100</gadget>
<output>35</output>
<gadget id="calculator">35 * 4</gadget>
<output>140</output>
<gadget id="calculator">300 - 140</gadget>
<output>160</output>
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 - 4_000</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 - 3_500</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 100</gadget>
<output>25</output>
<gadget id="calculator">160 / 25</gadget>
<output>32/5 = around 6.4</output>
<result>E</result> | E | 6.4 | A man has $ 10,000 to invest. He invests $ 4000 at 5 % and $ 3500 at 4 %. In order to have a yearly income of $ 500, he must invest the remainder at | {
"A": "6 %",
"B": "6.1 %",
"C": "6.2 %",
"D": "6.3 %",
"E": "6.4 %"
} | divide(subtract(subtract(500, multiply(divide(4000, const_100), 5)), multiply(divide(3500, const_100), 4)), divide(subtract(subtract(multiply(const_100, const_100), 4000), 3500), const_100)) | divide(n1,const_100)|divide(n3,const_100)|multiply(const_100,const_100)|multiply(n2,#0)|multiply(n4,#1)|subtract(#2,n1)|subtract(n5,#3)|subtract(#5,n3)|divide(#7,const_100)|subtract(#6,#4)|divide(#9,#8) | income from $ 4000 at 5 % in one year = $ 4000 of 5 % . = $ 4000 × 5 / 100 . = $ 4000 × 0.05 . = $ 200 . income from $ 3500 at 4 % in one year = $ 3500 of 4 % . = $ 3500 × 4 / 100 . = $ 3500 × 0.04 . = $ 140 . total income from 4000 at 5 % and 3500 at 4 % = $ 200 + $ 140 = $ 340 . remaining income amount in order to have a yearly income of $ 500 = $ 500 - $ 340 . = $ 160 . total invested amount = $ 4000 + $ 3500 = $ 7500 . remaining invest amount = $ 10000 - $ 7500 = $ 2500 . we know that , interest = principal × rate × time interest = $ 160 , principal = $ 2500 , rate = r [ we need to find the value of r ] , time = 1 year . 160 = 2500 × r × 1 . 160 = 2500 r 160 / 2500 = 2500 r / 2500 [ divide both sides by 2500 ] 0.064 = r r = 0.064 change it to a percent by moving the decimal to the right two places r = 6.4 % therefore , he invested the remaining amount $ 2500 at 6.4 % in order to get $ 500 income every year . the answer is ( e ) | gain |
math_qa__bEV3mr0YRVRjVWnU | A train speeds past a pole in 11 seconds and a platform 120 m long in 22 seconds. Its length is? Choose the correct choice:
A) 128 B) 177 C) 199 D) 120 E) 150 | <gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">120 * 1</gadget>
<output>120</output>
<result>D</result> | D | 120 | A train speeds past a pole in 11 seconds and a platform 120 m long in 22 seconds. Its length is? | {
"A": "128",
"B": "177",
"C": "199",
"D": "120",
"E": "150"
} | multiply(120, subtract(const_2, const_1)) | subtract(const_2,const_1)|multiply(n1,#0) | let the length of the train be x meters and its speed be y m / sec . they , x / y = 11 = > y = x / 11 x + 120 / 22 = x / 11 x = 120 m . answer : d | physics |
math_qa__6GxQcmi4aPNIBJf5 | A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 180, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala? Choose the most appropriate option.
A) 31 B) 33 C) 55 D) 77 E) 88 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/10) + (3/4)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">180 / (17/20)</gadget>
<output>3_600/17 = around 211.764706</output>
<gadget id="calculator">(3_600/17) - 180</gadget>
<output>540/17 = around 31.764706</output>
<result>A</result> | A | 31 | A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 180, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala? | {
"A": "31",
"B": "33",
"C": "55",
"D": "77",
"E": "88"
} | subtract(divide(180, add(divide(10, const_100), divide(3, 4))), 180) | divide(n0,const_100)|divide(n2,n3)|add(#0,#1)|divide(n1,#2)|subtract(#3,n1)| | "let f = pure fuji , g = pure gala and c - cross pollinated . c = 10 % of x where x is total trees . c = . 1 x also 3 x / 4 = f and c + f = 180 = > . 1 x + 3 / 4 x = 180 = > x = 211 211 - 180 = pure gala = 31 . a" | general |
math_qa__w6WZ15GBzg6m5qa8 | The banker’s gain on a sum due 3 years hence at 12% per annum is Rs. 90. The banker’s discount is Options.
A) rs . 340
B) rs . 840
C) rs . 1020
D) rs . 760
E) none | <gadget id="calculator">90 * 100</gadget>
<output>9_000</output>
<gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">9_000 / 36</gadget>
<output>250</output>
<gadget id="calculator">250 + 90</gadget>
<output>340</output>
<result>A</result> | A | 340 | The banker’s gain on a sum due 3 years hence at 12% per annum is Rs. 90. The banker’s discount is | {
"A": "rs . 340",
"B": "rs . 840",
"C": "rs . 1020",
"D": "rs . 760",
"E": "none"
} | add(divide(multiply(90, const_100), multiply(3, 12)), 90) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2)| | "solution t . d = ( b . g x 100 / r x t ) = rs . ( 90 x 100 / 12 x 3 ) = rs . 250 . b . d = rs ( 250 + 90 ) = rs . 340 . answer a" | gain |
math_qa__e48Gl7Aenp1CDaXl | In the quadratic equation x2 - bx + 20 = 0, if the product of two roots is 20, what is the sum of the two roots? Choose the most appropriate option: A) 20 B) 12 C) 16 D) 14 E) 18 | <gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<result>B</result> | B | 12 | In the quadratic equation x2 - bx + 20 = 0, if the product of two roots is 20, what is the sum of the two roots? | {
"A": "20",
"B": "12",
"C": "16",
"D": "14",
"E": "18"
} | add(divide(20, 2), 2) | divide(n1,n0)|add(n0,#0) | explanation : the sum of the roots of the quadratic equation ax 2 + ax + c = 0 are ( - b / a ) and the product of the roots are ( c / a ) . thus , in the equation x 2 - ax + 20 = 0 , where a = 1 , b = - a and c = 20 . we get , product of the roots = 20 sum of the roots = - ( - 12 ) / 1 = 12 answer : b | general |
math_qa__ux9pZ2VoJ7qVX3Ee | A carpenter worked alone for 1 day on a job that would take him 7 more days to finish. He and another carpenter completed the job in 4 more days. How many days would it have taken the second carpenter to do the complete job working alone? Choose the correct choice from the following:
A) 16
B) 7
C) 9
D) 14
E) 24 | <gadget id="calculator">1 + 7</gadget>
<output>8</output>
<gadget id="calculator">4 * 8</gadget>
<output>32</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<result>A</result> | A | 16 | A carpenter worked alone for 1 day on a job that would take him 7 more days to finish. He and another carpenter completed the job in 4 more days. How many days would it have taken the second carpenter to do the complete job working alone? | {
"A": "16",
"B": "7",
"C": "9",
"D": "14",
"E": "24"
} | divide(multiply(4, add(1, 7)), const_2) | add(n0,n1)|multiply(n2,#0)|divide(#1,const_2)| | "a carpenter worked only 1 day on something that takes him 7 more days . means ; carpenter finishes his work in 8 days . let his buddy finish the same task in x days . respective rates per day : 1 / 8 and 1 / x to complete 1 work : first guy worked for 5 days @ rate = 1 / 8 per day . second one worked for 4 days @ rate = 1 / x per day expression : days * rate = work 5 * 1 / 8 + 4 * 1 / x = 1 5 x + 32 = 8 x 2 x = 32 x = 16 days . ans : a" | physics |
math_qa__LqcOr8XgOsKi7N83 | In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 55% of all the employees are men .What % of all the employee went to the picnic? Choices.
A) 29 % B) 34 % C) 35 % D) 36 % E) 37 % | <gadget id="calculator">55 / 100</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(11/20) * (1/5)</gadget>
<output>11/100 = around 0.11</output>
<gadget id="calculator">100 - 55</gadget>
<output>45</output>
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(9/20) * (2/5)</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(11/100) + (9/50)</gadget>
<output>29/100 = around 0.29</output>
<gadget id="calculator">(29/100) * 100</gadget>
<output>29</output>
<result>A</result> | A | 29 | In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 55% of all the employees are men .What % of all the employee went to the picnic? | {
"A": "29 %",
"B": "34 %",
"C": "35 %",
"D": "36 %",
"E": "37 %"
} | multiply(add(multiply(divide(55, const_100), divide(20, const_100)), multiply(divide(subtract(const_100, 55), const_100), divide(40, const_100))), const_100) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(const_100,n2)|divide(#3,const_100)|multiply(#0,#1)|multiply(#4,#2)|add(#5,#6)|multiply(#7,const_100)| | "total men in company 55 % means total women in company 45 % ( assume total people in company 100 % ) no of men employees attended picnic = 55 x ( 20 / 100 ) = 11 no of women employees attend picnic = 45 x ( 40 / 100 ) = 18 total percentage of employees attend the picnic = 11 + 18 = 29 % answer : a" | gain |
math_qa__wCqzq7A24gh3qOwv | If taxi fares were $10.00 for the first 1/5 mile and $1.00 for each 1/5 mile there after, then the taxi fare for a 10-mile ride was Options
A) $ 55.10 B) $ 59.20 C) $ 59.40 D) $ 59.00 E) $ 55.00 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">10 / (1/5)</gadget>
<output>50</output>
<gadget id="calculator">50 - 1</gadget>
<output>49</output>
<gadget id="calculator">49 * 1</gadget>
<output>49</output>
<gadget id="calculator">10 + 49</gadget>
<output>59</output>
<result>D</result> | D | 59 | If taxi fares were $10.00 for the first 1/5 mile and $1.00 for each 1/5 mile there after, then the taxi fare for a 10-mile ride was | {
"A": "$ 55.10",
"B": "$ 59.20",
"C": "$ 59.40",
"D": "$ 59.00",
"E": "$ 55.00"
} | add(10.00, multiply(subtract(divide(10.00, divide(1, 5)), 1), 1.00)) | divide(n1,n2)|divide(n0,#0)|subtract(#1,n1)|multiply(n3,#2)|add(n0,#3)| | "in 10 miles , initial 1 / 5 mile charge is $ 10 rest of the distance = 10 - ( 1 / 5 ) = 49 / 5 rest of the distance charge = 49 ( 1.00 ) = $ 49.00 ( as the charge is 1.00 for every 1 / 5 mile ) = > total charge for 4 miles = 10 + 49.00 = 59.00 answer is d" | general |
math_qa__mJ64KfuGOfykf2Yl | Two cubes of tire sides ratio 2 : 3. Find its cube volumes ratio? Choose the most appropriate option
A) 2 : 27 B) 3 : 27 C) 1 : 27 D) 8 : 27 E) 5 : 27 | <gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">8 / 27</gadget>
<output>8/27 = around 0.296296</output>
<result>D</result> | D | 0.296296 | Two cubes of tire sides ratio 2 : 3. Find its cube volumes ratio? | {
"A": "2 : 27",
"B": "3 : 27",
"C": "1 : 27",
"D": "8 : 27",
"E": "5 : 27"
} | divide(volume_cube(2), volume_cube(3)) | volume_cube(n0)|volume_cube(n1)|divide(#0,#1) | a ( power 3 ) : b ( power 3 ) = 2 ( power 3 ) : 3 ( power 3 ) = 8 : 27 answer is d . | geometry |
math_qa__GT58t1wxpZRb7PqX | The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 7000, brokerage being 1/4%, is: Select the correct option
A) 96.97 B) 114 C) 114.75 D) 124 E) 124.75 | <gadget id="calculator">7_000 / 756</gadget>
<output>250/27 = around 9.259259</output>
<gadget id="calculator">(250/27) * 10.5</gadget>
<output>97.222222</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">97.222222 - (1/4)</gadget>
<output>96.972222</output>
<result>A</result> | A | 96.97 | The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 7000, brokerage being 1/4%, is: | {
"A": "96.97",
"B": "114",
"C": "114.75",
"D": "124",
"E": "124.75"
} | subtract(multiply(divide(7000, 756), 10.5), divide(1, 4)) | divide(n2,n1)|divide(n3,n4)|multiply(n0,#0)|subtract(#2,#1)| | "face value = rs . 7000 . dividend = 10.5 % . annual income = rs . 756 . brokerage per rs . 100 = rs . 0.25 . dividend is always paid on the face value of a share . face value * dividend / ( market value + brokerage per rs . 100 ) = annual income . = 7000 * 10.5 / 756 = market value of rs . 100 stock + brokerage per rs . 100 . = market value of rs . 100 stock + brokerage per rs . 100 = rs . 97.22 . = market value of rs . 100 stock = rs . 97.22 - re . 0.25 . = market value of rs . 100 stock = rs . 96.97 answer : a" | gain |
math_qa__X9zjQiqe2ememPuY | A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3600. With the help of C, they completed the work in 3 days. How much is to be paid to C? Select.
A) s . 375 B) s . 450 C) s . 600 D) s . 800 E) s . 850 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/8) + (1/6)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">(1/3) - (7/24)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/24) * 3_600</gadget>
<output>150</output>
<gadget id="calculator">150 * 3</gadget>
<output>450</output>
<result>B</result> | B | 450 | A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3600. With the help of C, they completed the work in 3 days. How much is to be paid to C? | {
"A": "s . 375",
"B": "s . 450",
"C": "s . 600",
"D": "s . 800",
"E": "s . 850"
} | multiply(multiply(subtract(inverse(3), add(inverse(8), inverse(6))), 3600), 3) | inverse(n3)|inverse(n1)|inverse(n0)|add(#1,#2)|subtract(#0,#3)|multiply(n2,#4)|multiply(n3,#5) | c ' s 1 day ' s work = 1 / 3 - ( 1 / 6 + 1 / 8 ) = 1 / 3 - 7 / 24 = 1 / 24 a ' s wages : b ' s wages : c ' s wages = 1 / 6 : 1 / 8 : 1 / 24 = 4 : 3 : 1 c ' s share ( for 3 days ) = rs . ( 3 * 1 / 24 * 3600 ) = rs . 450 answer = b | physics |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.