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25
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stringlengths 45
1.01k
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stringlengths 75
4.11k
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float64 -4,212
100B
| question_without_options
stringlengths 6
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stringlengths 7
6.48k
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stringlengths 8
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math_qa__cFGXMwblx9CK9re4 | If the sum of two numbers is 18 and the sum of their squares is 220, then the product of the numbers is Pick one:
A) 40 B) 44 C) 52 D) 88 E) 90 | <gadget id="calculator">18 ** 2</gadget>
<output>324</output>
<gadget id="calculator">324 - 220</gadget>
<output>104</output>
<gadget id="calculator">104 / 2</gadget>
<output>52</output>
<result>C</result> | C | 52 | If the sum of two numbers is 18 and the sum of their squares is 220, then the product of the numbers is | {
"A": "40",
"B": "44",
"C": "52",
"D": "88",
"E": "90"
} | divide(subtract(power(18, const_2), 220), const_2) | power(n0,const_2)|subtract(#0,n1)|divide(#1,const_2)| | "sol . let the numbers be x and y . then , ( x + y ) = 18 and x 2 + y 2 = 220 . now , 2 xy = ( x + y ) 2 - ( x 2 + y 2 ) = ( 18 ) 2 - 220 = 324 - 220 = 104 xy = 52 . answer c" | general |
math_qa__h9TWvNeuk9AKrklk | How many positive integers less than 10,000 are there in which the sum of the digits equals 5? Choose the most appropriate option
A) 31 B) 51 C) 56 D) 62 E) 93 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<result>C</result> | C | 56 | How many positive integers less than 10,000 are there in which the sum of the digits equals 5? | {
"A": "31",
"B": "51",
"C": "56",
"D": "62",
"E": "93"
} | divide(factorial(subtract(add(const_4, 5), const_1)), multiply(factorial(5), factorial(subtract(const_4, const_1)))) | add(n1,const_4)|factorial(n1)|subtract(const_4,const_1)|factorial(#2)|subtract(#0,const_1)|factorial(#4)|multiply(#1,#3)|divide(#5,#6) | basically , the question asks how many 4 digit numbers ( including those in the form 0 xxx , 00 xx , and 000 x ) have digits which add up to 5 . think about the question this way : we know that there is a total of 5 to be spread among the 4 digits , we just have to determine the number of ways it can be spread . let x represent a sum of 1 , and | represent a separator between two digits . as a result , we will have 5 x ' s ( digits add up to the 5 ) , and 3 | ' s ( 3 digit separators ) . so , for example : xx | x | x | x = 2111 | | xxx | xx = 0032 etc . there are 8 c 3 ways to determine where to place the separators . hence , the answer is 8 c 3 = 56 . answer : c | general |
math_qa__mwoPbSY5Cc9MCnOo | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 20 percent. The enrollment on January 1, 1993, was 50 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ?
Choose the correct answer:
A) 38 B) 39 C) 40 D) 41 E) 42 | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 / 120</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(5/6) * 50</gadget>
<output>125/3 = around 41.666667</output>
<result>E</result> | E | 42 | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 20 percent. The enrollment on January 1, 1993, was 50 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ? | {
"A": "38",
"B": "39",
"C": "40",
"D": "41",
"E": "42"
} | multiply(divide(const_100, add(const_100, 20)), 50) | add(n4,const_100)|divide(const_100,#0)|multiply(n7,#1) | 1.20 x = 50 - - > 6 / 5 * x = 50 - - > x = 50 * 5 / 6 = 250 / 6 = ~ 42 . answer : e . | gain |
math_qa__kF7BqSmnKaUhR4w2 | If the remainder is 7 when positive integer n is divided by 10, what is the remainder when n is divided by 5? Pick one
A) 0 B) 1 C) 2 D) 3 E) 2 | <gadget id="calculator">10 / 5</gadget>
<output>2</output>
<result>E</result> | E | 2 | If the remainder is 7 when positive integer n is divided by 10, what is the remainder when n is divided by 5? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "2"
} | divide(10, 5) | divide(n1,n2)| | "assume x is quotient here , n = 10 x + 7 - - - - - - - - - - ( 1 ) and n = 5 x + ? we can also write equation ( 1 ) as : n = ( 10 x + 5 ) + 2 . ie 5 ( 2 x + 1 ) + 1 ie the first term is perfectly divisible by 5 . so , the remainder left is 2 so , answer ( e ) is right choice ." | general |
math_qa__lf4jYa4PbO3xcUWj | On a sum of money, the simple interest for 2 years is Rs. 330, while the compound interest is Rs. 340, the rate of interest being the same in both the cases. The rate of interest is Choose the correct choice from the following options:
A) 15 %
B) 14.25 %
C) 6.06 %
D) 10.5 %
E) 11.5 % | <gadget id="calculator">330 / 2</gadget>
<output>165</output>
<gadget id="calculator">340 - 165</gadget>
<output>175</output>
<gadget id="calculator">175 - 165</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 165</gadget>
<output>200/33 = around 6.060606</output>
<result>C</result> | C | 6.06 | On a sum of money, the simple interest for 2 years is Rs. 330, while the compound interest is Rs. 340, the rate of interest being the same in both the cases. The rate of interest is | {
"A": "15 %",
"B": "14.25 %",
"C": "6.06 %",
"D": "10.5 %",
"E": "11.5 %"
} | divide(multiply(const_100, subtract(subtract(340, divide(330, 2)), divide(330, 2))), divide(330, 2)) | divide(n1,n0)|subtract(n2,#0)|subtract(#1,#0)|multiply(#2,const_100)|divide(#3,#0)| | "explanation : the difference between compound interest and simple interest on rs . p for 2 years at r % per annum = ( r ã — si ) / ( 2 ã — 100 ) difference between the compound interest and simple interest = 340 - 330 = 10 ( r ã — si ) / ( 2 ã — 100 ) = 10 ( r ã — 330 ) / ( 2 ã — 100 ) = 10 r = 6.06 % answer : option c" | gain |
math_qa__iMWmrYUJr7yIIEfd | What must be added to each term of the ratio 7:11, So as to make it equal to 3:4? Choose one:
A) 8 B) 7.5 C) 6.5 D) 5 E) 6 | <gadget id="calculator">3 * 11</gadget>
<output>33</output>
<gadget id="calculator">4 * 7</gadget>
<output>28</output>
<gadget id="calculator">33 - 28</gadget>
<output>5</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">5 / 1</gadget>
<output>5</output>
<result>D</result> | D | 5 | What must be added to each term of the ratio 7:11, So as to make it equal to 3:4? | {
"A": "8",
"B": "7.5",
"C": "6.5",
"D": "5",
"E": "6"
} | divide(subtract(multiply(3, 11), multiply(4, 7)), subtract(4, 3)) | multiply(n1,n2)|multiply(n0,n3)|subtract(n3,n2)|subtract(#0,#1)|divide(#3,#2)| | "solution : let x be added to each term . according to question , ( 7 + x ) / ( 11 + x ) = 3 / 4 ; or , 33 + 3 x = 28 + 4 x ; or , x = 5 . answer : option d" | general |
math_qa__wbzTaYdcbsL5q7MF | The water level in a rectangular swimming pool measuring 60 feet by 20 feet is to be lowered by 6 inches. How many gallons of water must be removed? (1 cu ft = 7.5 gallons)
Pick: A) 100 B) 250 C) 4500 D) 1200 E) 5625 | <gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">60 * 20 * (1/2)</gadget>
<output>600</output>
<gadget id="calculator">600 * 7.5</gadget>
<output>4_500</output>
<result>C</result> | C | 4,500 | The water level in a rectangular swimming pool measuring 60 feet by 20 feet is to be lowered by 6 inches. How many gallons of water must be removed? (1 cu ft = 7.5 gallons) | {
"A": "100",
"B": "250",
"C": "4500",
"D": "1200",
"E": "5625"
} | multiply(volume_rectangular_prism(60, 20, divide(6, add(const_10, const_2))), 7.5) | add(const_10,const_2)|divide(n2,#0)|volume_rectangular_prism(n0,n1,#1)|multiply(n4,#2)| | "6 inches = 1 / 2 feet ( there are 12 inches in a foot . ) , so 60 * 20 * 1 / 2 = 600 feet ^ 3 of water must be removed , which equals to 600 * 7.5 = 4500 gallons . answer : c ." | geometry |
math_qa__ZUfpCCbguMIJPD1B | What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 57? Choose the correct option:
A) 3944
B) 920
C) 7290
D) 3876
E) 3729 | <gadget id="calculator">289 ** (1/2)</gadget>
<output>17</output>
<gadget id="calculator">4 * 17</gadget>
<output>68</output>
<gadget id="calculator">68 * 57</gadget>
<output>3_876</output>
<result>D</result> | D | 3,876 | What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 57? | {
"A": "3944",
"B": "920",
"C": "7290",
"D": "3876",
"E": "3729"
} | multiply(square_perimeter(sqrt(289)), 57) | sqrt(n0)|square_perimeter(#0)|multiply(n1,#1)| | "explanation : let the side of the square plot be a ft . a 2 = 289 = > a = 17 length of the fence = perimeter of the plot = 4 a = 68 ft . cost of building the fence = 68 * 57 = rs . 3876 . answer : option d" | geometry |
math_qa__rDqCIaaQmyTzpvK0 | 3 friends alice , bond and charlie divide $ 1105 amongs them in such a way that if $ 10 , $ 20 and $ 15 are removed from the sums that alice , bond and charlie received respectively , then the share of the sums that they got will be in the ratio of 11 : 18 : 24 . how much did charlie receive ?
Choices: A) $ 495 B) $ 510 C) $ 480 D) $ 375 E) $ 360 | <gadget id="calculator">10 + 20</gadget>
<output>30</output>
<gadget id="calculator">30 + 15</gadget>
<output>45</output>
<gadget id="calculator">1_105 - 45</gadget>
<output>1_060</output>
<gadget id="calculator">11 + 18</gadget>
<output>29</output>
<gadget id="calculator">29 + 24</gadget>
<output>53</output>
<gadget id="calculator">1_060 / 53</gadget>
<output>20</output>
<gadget id="calculator">20 * 24</gadget>
<output>480</output>
<gadget id="calculator">480 + 15</gadget>
<output>495</output>
<result>A</result> | A | 495 | 3 friends alice , bond and charlie divide $ 1105 amongs them in such a way that if $ 10 , $ 20 and $ 15 are removed from the sums that alice , bond and charlie received respectively , then the share of the sums that they got will be in the ratio of 11 : 18 : 24 . how much did charlie receive ? | {
"A": "$ 495",
"B": "$ 510",
"C": "$ 480",
"D": "$ 375",
"E": "$ 360"
} | add(multiply(divide(subtract(1105, add(add(10, 20), 15)), add(add(11, 18), 24)), 24), 15) | add(n2,n3)|add(n5,n6)|add(n4,#0)|add(n7,#1)|subtract(n1,#2)|divide(#4,#3)|multiply(n7,#5)|add(n4,#6) | explanatory answer let the sums of money received by a , b and c be x , y and z respectively . then x - 10 : y - 20 : z - 15 is 11 a : 18 a : 24 a when $ 10 , $ 20 and $ 15 are removed , we are removing a total of $ 45 from $ 1105 . therefore , 11 a + 18 a + 24 a = 1105 - 45 = 1060 i . e . , 53 a = 1060 or a = 20 . we know that z - 15 = 24 a = 24 * 20 = 480 therefore , z = 480 + 15 = $ 495 correct choice is ( a ) | general |
math_qa__lfRKNp3Gip8yvb2b | Mother,her daughter and her grand child weighs 150 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter?
Answers: A) 46 B) 47 C) 42 D) 49 E) 50 | <gadget id="calculator">150 - 60</gadget>
<output>90</output>
<gadget id="calculator">90 / 5</gadget>
<output>18</output>
<gadget id="calculator">60 - 18</gadget>
<output>42</output>
<result>C</result> | C | 42 | Mother,her daughter and her grand child weighs 150 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter? | {
"A": "46",
"B": "47",
"C": "42",
"D": "49",
"E": "50"
} | subtract(60, divide(subtract(150, 60), 5)) | subtract(n0,n1)|divide(#0,n3)|subtract(n1,#1)| | "mother + daughter + child = 150 kg daughter + child = 60 kg mother = 150 - 60 = 90 kg child = 1 / 5 th of mother = ( 1 / 5 ) * 90 = 18 kg so now daughter = 120 - ( mother + child ) = 150 - ( 90 + 18 ) = 42 kg answer : c" | general |
math_qa__LmozWkiLix6nMuBe | In a weight-lifting competition, the total weight of Joe's two lifts was 900 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift? Answers.
A) 225
B) 275
C) 325
D) 350
E) 400 | <gadget id="calculator">900 + 300</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 3</gadget>
<output>400</output>
<result>E</result> | E | 400 | In a weight-lifting competition, the total weight of Joe's two lifts was 900 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift? | {
"A": "225",
"B": "275",
"C": "325",
"D": "350",
"E": "400"
} | divide(add(900, 300), const_3) | add(n0,n1)|divide(#0,const_3)| | "this problem is a general word translation . we first define variables and then set up equations . we can define the following variables : f = the weight of the first lift s = the weight of the second lift we are given that the total weight of joe ' s two lifts was 900 pounds . we sum the two variables to obtain : f + s = 900 we are also given that twice the weight of his first lift was 300 pounds more than the weight of his second lift . we express this as : 2 f = 300 + s 2 f – 300 = s we can now plug in ( 2 f – 300 ) for s into the first equation , so we have : f + 2 f – 300 = 900 3 f = 1,200 f = 400 answer is e ." | general |
math_qa__xz8udjDxFL4v3tdJ | The H.C.F. of two numbers is 25 and the other two factors of their L.C.M. are 14 and 16. The larger of the two numbers is Choose the correct choice from the following choices
A) 276 B) 299 C) 312 D) 400 E) none | <gadget id="calculator">25 * 16</gadget>
<output>400</output>
<result>D</result> | D | 400 | The H.C.F. of two numbers is 25 and the other two factors of their L.C.M. are 14 and 16. The larger of the two numbers is | {
"A": "276",
"B": "299",
"C": "312",
"D": "400",
"E": "none"
} | multiply(25, 16) | multiply(n0,n2)| | "solution clearly , the numbers are ( 25 x 14 ) and ( 25 x 16 ) . larger number = ( 25 x 16 ) = 400 . answer d" | other |
math_qa__msMbBNiE45mNiUkx | In what time will a train 180 meters long cross an electric pole, if its speed is 154 km/hr
Choose the correct choice:
A) 5 seconds B) 4.3 seconds C) 3 seconds D) 2.5 seconds E) none of these | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">154 * (5/18)</gadget>
<output>385/9 = around 42.777778</output>
<gadget id="calculator">180 / (385/9)</gadget>
<output>324/77 = around 4.207792</output>
<result>B</result> | B | 4.3 | In what time will a train 180 meters long cross an electric pole, if its speed is 154 km/hr | {
"A": "5 seconds",
"B": "4.3 seconds",
"C": "3 seconds",
"D": "2.5 seconds",
"E": "none of these"
} | divide(180, multiply(154, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "explanation : first convert speed into m / sec speed = 154 * ( 5 / 18 ) = 42 m / sec time = distance / speed = 180 / 42 = 4.3 seconds option b" | physics |
math_qa__8xrredF0y7QsmtQb | A cycle is bought for Rs.900 and sold for Rs.1150, find the gain percent?
Choose the correct choice from the following
A) 15
B) 20
C) 27.77
D) 40
E) 12 | <gadget id="calculator">1_150 - 900</gadget>
<output>250</output>
<gadget id="calculator">250 / 900</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 100</gadget>
<output>250/9 = around 27.777778</output>
<result>C</result> | C | 27.77 | A cycle is bought for Rs.900 and sold for Rs.1150, find the gain percent? | {
"A": "15",
"B": "20",
"C": "27.77",
"D": "40",
"E": "12"
} | multiply(divide(subtract(1150, 900), 900), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "900 - - - - 250 100 - - - - ? = > 27.77 % answer : c" | gain |
math_qa__JLNC0ADxwMcrNUFt | An employer pays Rs.20 for each day a worker works and for felts Rs.3 for each day is ideal at the end of sixty days a worker gets Rs.280 . for how many days did the worker remain ideal? Choose the correct choice from the following answers:
A) 10
B) 40
C) 30
D) 20
E) 50 | <gadget id="calculator">20 * 60</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 - 280</gadget>
<output>920</output>
<gadget id="calculator">-3</gadget>
<output>-3</output>
<gadget id="calculator">(-3) - 20</gadget>
<output>-23</output>
<gadget id="calculator">-(-23)</gadget>
<output>23</output>
<gadget id="calculator">920 / 23</gadget>
<output>40</output>
<result>B</result> | B | 40 | An employer pays Rs.20 for each day a worker works and for felts Rs.3 for each day is ideal at the end of sixty days a worker gets Rs.280 . for how many days did the worker remain ideal? | {
"A": "10",
"B": "40",
"C": "30",
"D": "20",
"E": "50"
} | divide(subtract(multiply(20, const_60), 280), negate(subtract(negate(3), 20))) | multiply(n0,const_60)|negate(n1)|subtract(#0,n2)|subtract(#1,n0)|negate(#3)|divide(#2,#4) | suppose a worker remained ideal for x days then he worked for 60 - x days 20 * ( 60 - x ) - 3 x = 280 1200 - 23 x = 280 23 x = 920 x = 40 answer is b . | physics |
math_qa__hSvdeipA1Rv1zlWR | A Train usually travels at a speed of 72 kmph crossing a pole in 7 sec, what would be the length of the train?
Pick: A) 140 m B) 142 m C) 146 m D) 152 m E) 158 m | <gadget id="calculator">1_000 * 72</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">20 * 7</gadget>
<output>140</output>
<result>A</result> | A | 140 | A Train usually travels at a speed of 72 kmph crossing a pole in 7 sec, what would be the length of the train? | {
"A": "140 m",
"B": "142 m",
"C": "146 m",
"D": "152 m",
"E": "158 m"
} | multiply(divide(multiply(const_1000, 72), const_3600), 7) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1) | explanation : d = 72 * 5 / 18 * 7 = 140 m answer : option a | physics |
math_qa__tzEekjcwPhcWYYtl | A man received a cheque. The amount in Rs. has been transposed for paise and vice versa. After spending Rs. 5 and 42 paise, he discovered he now had exactly 6 times the value of the correct cheque amount. What amount he should have received? Choose the correct choice:
A) rs 5.30 B) rs 6.44 C) rs 60.44 D) rs 16.44 E) none of these | <gadget id="calculator">42 / 5</gadget>
<output>42/5 = around 8.4</output>
<gadget id="calculator">(42/5) / 6</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) * 5</gadget>
<output>7</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">6 + (1/4)</gadget>
<output>25/4 = around 6.25</output>
<result>B</result> | B | 6.44 | A man received a cheque. The amount in Rs. has been transposed for paise and vice versa. After spending Rs. 5 and 42 paise, he discovered he now had exactly 6 times the value of the correct cheque amount. What amount he should have received? | {
"A": "rs 5.30",
"B": "rs 6.44",
"C": "rs 60.44",
"D": "rs 16.44",
"E": "none of these"
} | add(subtract(multiply(divide(divide(42, 5), 6), 5), const_1), const_0_25) | divide(n1,n0)|divide(#0,n2)|multiply(n0,#1)|subtract(#2,const_1)|add(#3,const_0_25) | explanation : option 4 : - on reversal will be 44 rs 16 ps , after spending 5 rs 42 ps , remaining will be around 40 rs which is not 6 times 16 rs 44 ps . option 3 : - on reversal will lead a smaller value . hence we can eliminate that as well . option 1 : - on reversal is 30 rs 5 paise , after spending 5 rs 42 ps , remaining will be 24 rs 63 paise , 24 rs 63 ps is not 6 times 5 rs 30 paise . option 2 on reversal is 44 rs 06 paise , after spending 5 rs 42 ps , remaining will be 38 rs 64 ps , which is 6 times 6 rs 44 paise . hence rs 6.44 is the answer . we need not even consider option 4 and option 3 as reversed number itself is not 6 times the original number . option 1 when reversed is odd , and when even ( 5 rs 42 ps ) is subtracted from odd , we get a odd number , and an odd number can not be 6 times another number answer : b | general |
math_qa__cLvLT2ZvNxQVrRDG | If 30% of (x-y) = 20% of (x+y), then what percent of x is y? Choose the correct choice from the following.
A) 50.5 % B) 44.4 % C) 22.2 % D) 33.3 % E) 20 % | <gadget id="calculator">30 - 20</gadget>
<output>10</output>
<gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">10 / 50</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>E</result> | E | 20 | If 30% of (x-y) = 20% of (x+y), then what percent of x is y? | {
"A": "50.5 %",
"B": "44.4 %",
"C": "22.2 %",
"D": "33.3 %",
"E": "20 %"
} | multiply(divide(subtract(30, 20), add(30, 20)), const_100) | add(n0,n1)|subtract(n0,n1)|divide(#1,#0)|multiply(#2,const_100)| | "30 % of ( x - y ) = 20 % of ( x + y ) 30 / 100 ( x - y ) = 20 / 100 ( x + y ) x = 5 y required percentage = y / x * 100 = y / 5 y * 100 = 20 % answer is e" | general |
math_qa__7MMBm2jztNbCsaDO | Alfred buys an old scooter for $4700 and spends $800 on its repairs. If he sells the scooter for $5800, his gain percent is?
Pick: A) 5.45 % B) 6.23 % C) 7 % D) 8.12 % E) 10 % | <gadget id="calculator">4_700 + 800</gadget>
<output>5_500</output>
<gadget id="calculator">5_800 - 5_500</gadget>
<output>300</output>
<gadget id="calculator">300 / 5_500</gadget>
<output>3/55 = around 0.054545</output>
<gadget id="calculator">(3/55) * 100</gadget>
<output>60/11 = around 5.454545</output>
<result>A</result> | A | 5.45 | Alfred buys an old scooter for $4700 and spends $800 on its repairs. If he sells the scooter for $5800, his gain percent is? | {
"A": "5.45 %",
"B": "6.23 %",
"C": "7 %",
"D": "8.12 %",
"E": "10 %"
} | multiply(divide(subtract(5800, add(4700, 800)), add(4700, 800)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "c . p . = 4700 + 800 = $ 5500 s . p . = $ 5800 gain = 5800 - 5500 = $ 300 gain % = 300 / 5500 * 100 = 5.45 % answer is a" | gain |
math_qa__HwDMKSzMavu8beb6 | A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 380 m long platform?
Select:
A) 50
B) 27
C) 29
D) 47
E) 28 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 36</gadget>
<output>10</output>
<gadget id="calculator">10 * 12</gadget>
<output>120</output>
<gadget id="calculator">380 + 120</gadget>
<output>500</output>
<gadget id="calculator">500 / 10</gadget>
<output>50</output>
<result>A</result> | A | 50 | A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 380 m long platform? | {
"A": "50",
"B": "27",
"C": "29",
"D": "47",
"E": "28"
} | divide(add(380, multiply(multiply(const_0_2778, 36), 12)), multiply(const_0_2778, 36)) | multiply(n0,const_0_2778)|multiply(n1,#0)|add(n2,#1)|divide(#2,#0)| | "let the length of the train be x m . when a train crosses an electric pole , the distance covered is its own length . so , x = 12 * 36 * 5 / 18 m = 120 m . time taken to cross the platform = ( 120 + 380 ) / 36 * 5 / 18 = 50 min . answer : a" | physics |
math_qa__Wzw7PRuG8h5jLW2c | If the height of a cone is increased by 160% then its volume is increased by? Options:
A) 100
B) 777
C) 998
D) 729
E) 160 | <gadget id="calculator">160 * 1</gadget>
<output>160</output>
<result>E</result> | E | 160 | If the height of a cone is increased by 160% then its volume is increased by? | {
"A": "100",
"B": "777",
"C": "998",
"D": "729",
"E": "160"
} | rectangle_area(160, const_1) | rectangle_area(n0,const_1)| | "160 % answer : e" | geometry |
math_qa__u2Yp6VQvzpJaz1g6 | If x is an integer and 2.134 × 10^x is less than 210,000, what is the greatest possible value for x? Choose the correct choice from the following choices:
A) 7 B) 6 C) 5 D) 4 E) 3 | <gadget id="calculator">210_000 / 2.134</gadget>
<output>98_406.747891</output>
<gadget id="calculator">log(98_406.747891)</gadget>
<output>11.496865</output>
<gadget id="calculator">log(10)</gadget>
<output>log(10) = around 2.302585</output>
<gadget id="calculator">11.496865 / log(10)</gadget>
<output>11.496865/log(10) = around 4.993025</output>
<gadget id="calculator">floor(11.496865/log(10))</gadget>
<output>4</output>
<result>D</result> | D | 4 | If x is an integer and 2.134 × 10^x is less than 210,000, what is the greatest possible value for x? | {
"A": "7",
"B": "6",
"C": "5",
"D": "4",
"E": "3"
} | floor(divide(log(divide(210,000, 2.134)), log(10))) | divide(n2,n0)|log(n1)|log(#0)|divide(#2,#1)|floor(#3)| | "21340 * 10 ^ - 4 * 10 ^ x < 210,000 , x = 4 because the next zero on the right side will make 21,340 > 210,000 answer d ," | general |
math_qa__jQgStGglRdiaFYoi | In a renowned city, the average birth rate is 4 people every two seconds and the death rate is 3 people every two seconds. Estimate the size of the population net increase that occurs in one day. Choose the correct choice from the following:
A) 43,100
B) 43,200
C) 43,300
D) 43,400
E) 43,450 | <gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">1 * 3_600</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 * 12</gadget>
<output>43_200</output>
<result>B</result> | B | 43,200 | In a renowned city, the average birth rate is 4 people every two seconds and the death rate is 3 people every two seconds. Estimate the size of the population net increase that occurs in one day. | {
"A": "43,100",
"B": "43,200",
"C": "43,300",
"D": "43,400",
"E": "43,450"
} | multiply(multiply(subtract(4, 3), const_3600), const_12) | subtract(n0,n1)|multiply(#0,const_3600)|multiply(#1,const_12)| | "this question can be modified so that the birth rate is given every m seconds and the death rate is given every n seconds . for this particular question : increase in the population every 2 seconds = 4 - 3 = 1 people . total 2 second interval in a day = 24 * 60 * 60 / 2 = 43,200 population increase = 43,200 * 1 = 43,200 . hence b ." | general |
math_qa__i2ZQ6SWFBwaew5uL | In an examination, 300 students appeared. Out of these students; 25 % got first division, 54 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. Choose the correct choice from the following:
A) 63 B) 37 C) 54 D) 99 E) 01 | <gadget id="calculator">25 + 54</gadget>
<output>79</output>
<gadget id="calculator">100 - 79</gadget>
<output>21</output>
<gadget id="calculator">300 * 21</gadget>
<output>6_300</output>
<gadget id="calculator">6_300 / 100</gadget>
<output>63</output>
<result>A</result> | A | 63 | In an examination, 300 students appeared. Out of these students; 25 % got first division, 54 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. | {
"A": "63",
"B": "37",
"C": "54",
"D": "99",
"E": "01"
} | divide(multiply(300, subtract(const_100, add(25, 54))), const_100) | add(n1,n2)|subtract(const_100,#0)|multiply(n0,#1)|divide(#2,const_100)| | "the number of students with first division = 25 % of 300 = 25 / 100 × 300 = 8400 / 100 = 75 and , the number of students with second division = 54 % of 300 = 54 / 100 × 300 = 16200 / 100 = 162 therefore , the number of students who just passed = 300 – ( 75 + 162 ) = 63 answer : a" | general |
math_qa__xZraayFvkTnhrZnl | Walking at 4/7 of its usual speed, a train is 9 minutes late. Find its usual time to cover the journey. Select: A) 8 min . B) 10 min . C) 12 min . D) 15 min . E) 17 min . | <gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">1 / (4/7)</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">(7/4) - 1</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">9 / (3/4)</gadget>
<output>12</output>
<result>C</result> | C | 12 | Walking at 4/7 of its usual speed, a train is 9 minutes late. Find its usual time to cover the journey. | {
"A": "8 min .",
"B": "10 min .",
"C": "12 min .",
"D": "15 min .",
"E": "17 min ."
} | divide(9, subtract(inverse(divide(4, 7)), const_1)) | divide(n0,n1)|inverse(#0)|subtract(#1,const_1)|divide(n2,#2) | explanation : solution : new speed = 4 / 7 of the usual speed . let usual time be x . . ' . new time taken = 7 / 4 of usual time = 7 x / 4 so , ( 7 x / 4 ) - x = 9 min . = > 3 x = 36 = > x = 12 min . answer : c | physics |
math_qa__fWSApeNfnw5fm89y | A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 25 as remainder. Find the no. is?
Choose the correct choice from the following answers: A) 145646 B) 236578 C) 645353 D) 456546 E) 220025 | <gadget id="calculator">555 + 445</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 2</gadget>
<output>2_000</output>
<gadget id="calculator">555 - 445</gadget>
<output>110</output>
<gadget id="calculator">2_000 * 110</gadget>
<output>220_000</output>
<gadget id="calculator">220_000 + 25</gadget>
<output>220_025</output>
<result>E</result> | E | 220,025 | A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 25 as remainder. Find the no. is? | {
"A": "145646",
"B": "236578",
"C": "645353",
"D": "456546",
"E": "220025"
} | add(multiply(multiply(add(555, 445), 2), subtract(555, 445)), 25) | add(n0,n1)|subtract(n0,n1)|multiply(n2,#0)|multiply(#2,#1)|add(n3,#3)| | "( 555 + 445 ) * 2 * 110 + 25 = 220000 + 25 = 220025 e" | general |
math_qa__M9UNewyePlX9P6DH | A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 32 now, the son age 5 years back was Choose the correct choice:
A) 11 B) 17 C) 11 D) 19 E) 99 | <gadget id="calculator">32 / 2</gadget>
<output>16</output>
<gadget id="calculator">16 - 5</gadget>
<output>11</output>
<result>A</result> | A | 11 | A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 32 now, the son age 5 years back was | {
"A": "11",
"B": "17",
"C": "11",
"D": "19",
"E": "99"
} | subtract(divide(32, const_2), 5) | divide(n0,const_2)|subtract(#0,n1) | let the son ' s present age be x years . then , ( 32 - x ) = x x = 16 . son ' s age 5 years back = ( 16 - 5 ) = 11 years answer : a | general |
math_qa__5x5qQsaFVb73Ez1h | The current in a river is 8 mph. A boat can travel 20 mph in still water. How far up the river can the boat travel if the round trip is to take 10 hours? Choose the correct choice from the following:
A) 69 miles B) 84 miles C) 96 miles D) 100 miles E) 112 miles | <gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">20 + 8</gadget>
<output>28</output>
<gadget id="calculator">12 * 28</gadget>
<output>336</output>
<gadget id="calculator">336 * 10</gadget>
<output>3_360</output>
<gadget id="calculator">28 + 12</gadget>
<output>40</output>
<gadget id="calculator">3_360 / 40</gadget>
<output>84</output>
<result>B</result> | B | 84 | The current in a river is 8 mph. A boat can travel 20 mph in still water. How far up the river can the boat travel if the round trip is to take 10 hours? | {
"A": "69 miles",
"B": "84 miles",
"C": "96 miles",
"D": "100 miles",
"E": "112 miles"
} | divide(multiply(multiply(subtract(20, 8), add(20, 8)), 10), add(add(20, 8), subtract(20, 8))) | add(n0,n1)|subtract(n1,n0)|add(#0,#1)|multiply(#0,#1)|multiply(n2,#3)|divide(#4,#2)| | "upstream speed = 20 - 8 = 12 mph downstream speed = 20 + 8 = 28 mph d / 12 + d / 28 = 10 hours solving for d we get d = 84 answer : b" | physics |
math_qa__966JNG22ofNXhrOv | To asphalt 1km road, 30 men spent 12 days working 8 hours per day. How many days, 20 men will spend to asphalt a road of 2km working 9 hours a day? Choose the most appropriate option: A) 34 B) 36 C) 32 D) 40 E) 44 | <gadget id="calculator">30 * 12</gadget>
<output>360</output>
<gadget id="calculator">360 * 8</gadget>
<output>2_880</output>
<gadget id="calculator">2_880 * 2</gadget>
<output>5_760</output>
<gadget id="calculator">20 * 9</gadget>
<output>180</output>
<gadget id="calculator">5_760 / 180</gadget>
<output>32</output>
<result>C</result> | C | 32 | To asphalt 1km road, 30 men spent 12 days working 8 hours per day. How many days, 20 men will spend to asphalt a road of 2km working 9 hours a day? | {
"A": "34",
"B": "36",
"C": "32",
"D": "40",
"E": "44"
} | divide(multiply(multiply(multiply(30, 12), 8), 2), multiply(20, 9)) | multiply(n1,n2)|multiply(n4,n6)|multiply(n3,#0)|multiply(n5,#2)|divide(#3,#1)| | "man - hours required to asphalt 1 km road = 30 * 12 * 8 = 2880 man - hours required to asphalt 2 km road = 2880 * 2 = 5760 man - hours available per day = 20 * 9 = 180 therefore number of days = 5760 / 180 = 32 days ans = c" | physics |
math_qa__jYpsuEYSsb1YQCt6 | In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 56 as quotient. What is the correct quotient ? Choose the correct choice from the following options:
A) 0
B) 12
C) 32
D) 20
E) 25 | <gadget id="calculator">12 * 56</gadget>
<output>672</output>
<gadget id="calculator">672 / 21</gadget>
<output>32</output>
<result>C</result> | C | 32 | In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 56 as quotient. What is the correct quotient ? | {
"A": "0",
"B": "12",
"C": "32",
"D": "20",
"E": "25"
} | divide(multiply(12, 56), 21) | multiply(n1,n3)|divide(#0,n2)| | "12 * 56 = 672 672 % 21 = 32 answer : c" | general |
math_qa__KzzotCAu2dEy30xy | A group of 55 adults and 70 children go for trekking. If there is meal for either 70 adults or 90 children and if 21 adults have their meal, find the total number of children that can be catered with the remaining food. Choose the correct option.
A) 33 B) 54 C) 63 D) 17 E) 01 | <gadget id="calculator">70 - 21</gadget>
<output>49</output>
<gadget id="calculator">90 / 70</gadget>
<output>9/7 = around 1.285714</output>
<gadget id="calculator">49 * (9/7)</gadget>
<output>63</output>
<result>C</result> | C | 63 | A group of 55 adults and 70 children go for trekking. If there is meal for either 70 adults or 90 children and if 21 adults have their meal, find the total number of children that can be catered with the remaining food. | {
"A": "33",
"B": "54",
"C": "63",
"D": "17",
"E": "01"
} | multiply(subtract(70, 21), divide(90, 70)) | divide(n3,n1)|subtract(n1,n4)|multiply(#0,#1)| | "explanation : as there is meal for 70 adults and 21 have their meal , the meal left can be catered to 49 adults . now , 70 adults = 90 children 7 adults = 9 children therefore , 49 adults = 63 children hence , the meal can be catered to 63 children . answer : c" | general |
math_qa__Wgy7osbHqG7OynjX | Rahim bought 42 books for Rs.520 from one shop and 22 books for Rs.248 from another. What is the average price he paid per book ? Choose the correct choice from the following options
A) s . 17 B) s . 18 C) s . 12 D) s . 11 E) s . 10 | <gadget id="calculator">520 + 248</gadget>
<output>768</output>
<gadget id="calculator">42 + 22</gadget>
<output>64</output>
<gadget id="calculator">768 / 64</gadget>
<output>12</output>
<result>C</result> | C | 12 | Rahim bought 42 books for Rs.520 from one shop and 22 books for Rs.248 from another. What is the average price he paid per book ? | {
"A": "s . 17",
"B": "s . 18",
"C": "s . 12",
"D": "s . 11",
"E": "s . 10"
} | divide(add(520, 248), add(42, 22)) | add(n1,n3)|add(n0,n2)|divide(#0,#1)| | "average price per book = ( 520 + 248 ) / ( 42 + 22 ) = 768 / 64 = rs . 12 answer : c" | general |
math_qa__AyqAgYHIoXgUPLEP | A train running at the speed of 52 km/hr crosses a pole in 18 seconds. What is the length of the train? Pick one.
A) 120 metres B) 180 metres C) 260 metres D) 150 metres E) 100 meters | <gadget id="calculator">52 * 1_000</gadget>
<output>52_000</output>
<gadget id="calculator">52_000 / 3_600</gadget>
<output>130/9 = around 14.444444</output>
<gadget id="calculator">(130/9) * 18</gadget>
<output>260</output>
<result>C</result> | C | 260 | A train running at the speed of 52 km/hr crosses a pole in 18 seconds. What is the length of the train? | {
"A": "120 metres",
"B": "180 metres",
"C": "260 metres",
"D": "150 metres",
"E": "100 meters"
} | multiply(divide(multiply(52, const_1000), const_3600), 18) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 52 x 5 / 18 m / sec = 130 / 9 m / sec . length of the train = ( speed x time ) . length of the train = 130 / 9 x 18 m = 260 m . answer : c" | physics |
math_qa__Z5Q5EXqvM8Ka4iNb | Tom opened a shop investing Rs.30000. Jose joined him 2 months later, investing Rs.45000. They earned a profit of Rs.45000 after completion of one year. What will be Jose's share of profit?
Choose the correct choice from the following answers: A) 20000 B) 10000 C) 25000 D) 34000 E) 30000 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">30_000 * 12</gadget>
<output>360_000</output>
<gadget id="calculator">12 - 2</gadget>
<output>10</output>
<gadget id="calculator">45_000 * 10</gadget>
<output>450_000</output>
<gadget id="calculator">450_000 + 360_000</gadget>
<output>810_000</output>
<gadget id="calculator">360_000 / 810_000</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">1 - (4/9)</gadget>
<output>5/9 = around 0.555556</output>
<gadget id="calculator">45_000 * (5/9)</gadget>
<output>25_000</output>
<result>C</result> | C | 25,000 | Tom opened a shop investing Rs.30000. Jose joined him 2 months later, investing Rs.45000. They earned a profit of Rs.45000 after completion of one year. What will be Jose's share of profit? | {
"A": "20000",
"B": "10000",
"C": "25000",
"D": "34000",
"E": "30000"
} | multiply(45000, subtract(const_1, divide(multiply(30000, multiply(2, multiply(2, const_3))), add(multiply(45000, subtract(multiply(2, multiply(2, const_3)), 2)), multiply(30000, multiply(2, multiply(2, const_3))))))) | multiply(n1,const_3)|multiply(#0,n1)|multiply(n0,#1)|subtract(#1,n1)|multiply(n2,#3)|add(#4,#2)|divide(#2,#5)|subtract(const_1,#6)|multiply(n3,#7)| | "sol = ~ s - so anju ’ s share = [ 5 / 9 ] x 45000 = 25000 c" | gain |
math_qa__xAw4xNuO8PXlpnoR | A train running at the speed of 300 km/hr crosses a pole in 33 seconds. What is the length of the train? Pick one:
A) 2750 B) 2850 C) 2950 D) 3050 E) 3150 | <gadget id="calculator">300 * 1_000</gadget>
<output>300_000</output>
<gadget id="calculator">300_000 / 3_600</gadget>
<output>250/3 = around 83.333333</output>
<gadget id="calculator">(250/3) * 33</gadget>
<output>2_750</output>
<result>A</result> | A | 2,750 | A train running at the speed of 300 km/hr crosses a pole in 33 seconds. What is the length of the train? | {
"A": "2750",
"B": "2850",
"C": "2950",
"D": "3050",
"E": "3150"
} | multiply(divide(multiply(300, const_1000), const_3600), 33) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = ( 300 x ( 5 / 18 ) m / sec = ( 250 / 3 ) m / sec . length of the train = ( speed x time ) . length of the train = ( ( 250 / 3 ) x 33 ) m = 2750 m a" | physics |
math_qa__lFsmESO3cypjFMMu | a rectangle having length 105 cm and width 40 cm . if the length of the rectangle is increased by 20 5 percent then how much percent the breadth should be decreased so as to maintain the same area .
Choose one:
A) 25 % B) 19.23 % C) 40 % D) 75 % E) none of these | <gadget id="calculator">105 * 40</gadget>
<output>4_200</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 + 5</gadget>
<output>205</output>
<gadget id="calculator">205 / 100</gadget>
<output>41/20 = around 2.05</output>
<gadget id="calculator">105 * (41/20)</gadget>
<output>861/4 = around 215.25</output>
<gadget id="calculator">4_200 / (861/4)</gadget>
<output>800/41 = around 19.512195</output>
<result>B</result> | B | 19.23 | a rectangle having length 105 cm and width 40 cm . if the length of the rectangle is increased by 20 5 percent then how much percent the breadth should be decreased so as to maintain the same area . | {
"A": "25 %",
"B": "19.23 %",
"C": "40 %",
"D": "75 %",
"E": "none of these"
} | divide(multiply(105, 40), multiply(105, divide(add(multiply(const_2, const_100), 5), const_100))) | multiply(n0,n1)|multiply(const_100,const_2)|add(n3,#1)|divide(#2,const_100)|multiply(n0,#3)|divide(#0,#4) | explanation : solution : ( 25 / ( 105 + 25 ) * 100 ) % = 19.23 % answer : b | geometry |
math_qa__xbc5TpNbNWM7Jgrc | If 40% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class?
Pick:
A) 540 B) 528 C) 530 D) 520 E) 510 | <gadget id="calculator">880 / 100</gadget>
<output>44/5 = around 8.8</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">(44/5) * 60</gadget>
<output>528</output>
<result>B</result> | B | 528 | If 40% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class? | {
"A": "540",
"B": "528",
"C": "530",
"D": "520",
"E": "510"
} | multiply(divide(880, const_100), subtract(const_100, 40)) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)| | "we know 37.5 % people study biology , therefore the no of people not studying = 100 - 40 = 60 % > therefore the people not studying biology out of a total 880 people are = 60 % of 880 > ( 60 / 100 ) * 880 = 528 people b" | other |
math_qa__ix3Y0zePZ854SOhZ | The smallest number which when diminished by 3, is divisible by 12, 16, 18, 21 and 28 is Choose the correct choice from the following options:
A) 1008
B) 1011
C) 1022
D) 1032
E) 1043 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">9 * 16</gadget>
<output>144</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">144 * 7</gadget>
<output>1_008</output>
<gadget id="calculator">1_008 + 3</gadget>
<output>1_011</output>
<result>B</result> | B | 1,011 | The smallest number which when diminished by 3, is divisible by 12, 16, 18, 21 and 28 is | {
"A": "1008",
"B": "1011",
"C": "1022",
"D": "1032",
"E": "1043"
} | add(multiply(multiply(power(const_3, const_2.0), power(const_2.0, const_4)), add(const_3, const_4)), 3) | add(const_3,const_4)|power(const_3,const_2.0)|power(const_2.0,const_4)|multiply(#1,#2)|multiply(#0,#3)|add(#4,n0)| | "required number = ( l . c . m of 12 , 16 , 18 , 21,28 ) + 3 = 1008 + 3 = 1011 answer : b" | general |
math_qa__ZWfuUSd8Ort5uxms | A rectangular lawn of dimensions 80 m * 50 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m? Choose the correct choice from the following answers.
A) 3820 B) 930 C) 9309 D) 3600 E) 8302 | <gadget id="calculator">80 + 50</gadget>
<output>130</output>
<gadget id="calculator">130 - 10</gadget>
<output>120</output>
<gadget id="calculator">120 * 10</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 * 3</gadget>
<output>3_600</output>
<result>D</result> | D | 3,600 | A rectangular lawn of dimensions 80 m * 50 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m? | {
"A": "3820",
"B": "930",
"C": "9309",
"D": "3600",
"E": "8302"
} | multiply(multiply(subtract(add(80, 50), 10), 10), 3) | add(n0,n1)|subtract(#0,n2)|multiply(n2,#1)|multiply(n3,#2)| | "explanation : area = ( l + b – d ) d ( 80 + 50 – 10 ) 10 = > 1200 m 2 1200 * 3 = rs . 3600 answer : option d" | geometry |
math_qa__N9AldxrRd18qrLK0 | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.2 years, The ratio of the number of boys to the number of girls in the class is Pick.
A) 7 : 3 B) 2 : 3 C) 9 : 3 D) 6 : 3 E) 1 : 1 | <gadget id="calculator">15.8 - 15.2</gadget>
<output>0.6</output>
<gadget id="calculator">16.4 - 15.8</gadget>
<output>0.6</output>
<gadget id="calculator">0.6 / 0.6</gadget>
<output>1</output>
<result>E</result> | E | 1 | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.2 years, The ratio of the number of boys to the number of girls in the class is | {
"A": "7 : 3",
"B": "2 : 3",
"C": "9 : 3",
"D": "6 : 3",
"E": "1 : 1"
} | divide(subtract(15.8, 15.2), subtract(16.4, 15.8)) | subtract(n0,n2)|subtract(n1,n0)|divide(#0,#1)| | "explanation : let the ratio be k : 1 . then , k * 16.4 + 1 * 15.2 = ( k + 1 ) * 15.8 < = > ( 16.4 - 15.8 ) k = ( 15.8 - 15.2 ) < = > k = 0.6 / 0.6 = 1 / 1 . required ratio = 1 / 1 : 1 = 1 : 1 . answer : e" | general |
math_qa__urcexCHIlnZwXa3t | 3 candidates in an election and received 1000, 2000 and 4000 votes respectively. What % of the total votes did the winning candidate got in that election? Choose the correct answer: A) 45 % B) 50 % C) 57.14 % D) 60 % E) 65.12 % | <gadget id="calculator">1_000 + 2_000</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 + 4_000</gadget>
<output>7_000</output>
<gadget id="calculator">4_000 / 7_000</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">(4/7) * 100</gadget>
<output>400/7 = around 57.142857</output>
<result>C</result> | C | 57.14 | 3 candidates in an election and received 1000, 2000 and 4000 votes respectively. What % of the total votes did the winning candidate got in that election? | {
"A": "45 %",
"B": "50 %",
"C": "57.14 %",
"D": "60 %",
"E": "65.12 %"
} | multiply(divide(4000, add(add(1000, 2000), 4000)), const_100) | add(n1,n2)|add(n3,#0)|divide(n3,#1)|multiply(#2,const_100)| | "total number of votes polled = ( 1000 + 2000 + 4000 ) = 7000 so , required percentage = 4000 / 7000 * 100 = 57.14 % c" | gain |
math_qa__vlRRkPtNhQakHUIe | A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 45%? Choose the correct choice from the following answers: A) 600 B) 887 C) 256 D) 654 E) 725 | <gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">500 * (9/20)</gadget>
<output>225</output>
<gadget id="calculator">500 + 225</gadget>
<output>725</output>
<result>E</result> | E | 725 | A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 45%? | {
"A": "600",
"B": "887",
"C": "256",
"D": "654",
"E": "725"
} | add(500, multiply(500, divide(45, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | "cost price = rs . 500 profit = 45 % of 500 = rs . 225 selling price = cost price + profit = 500 + 225 = 725 answer : e" | gain |
math_qa__AyBY43fEQTAqKzS5 | The ratio of the amount of the oil bill for the month of February to the amount of the oil bill for the month of January was 3:2. If the oil bill for February had been $20 more, the corresponding ratio would have been 5:3. How much was the oil bill for January?
Choose the correct choice from the following
A) $ 100 B) $ 120 C) $ 140 D) $ 160 E) $ 180 | <gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(5/3) - (3/2)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">20 / (1/6)</gadget>
<output>120</output>
<result>B</result> | B | 120 | The ratio of the amount of the oil bill for the month of February to the amount of the oil bill for the month of January was 3:2. If the oil bill for February had been $20 more, the corresponding ratio would have been 5:3. How much was the oil bill for January? | {
"A": "$ 100",
"B": "$ 120",
"C": "$ 140",
"D": "$ 160",
"E": "$ 180"
} | divide(20, subtract(divide(5, 3), divide(3, 2))) | divide(n3,n4)|divide(n0,n1)|subtract(#0,#1)|divide(n2,#2)| | "3 : 2 = 9 : 6 and 5 : 3 = 10 : 6 . an increase in $ 20 increases the ratio by 1 : 6 . therefore , january ' s bill was 6 ( $ 20 ) = $ 120 . the answer is b ." | general |
math_qa__WBPcrMCPrAdf8DeA | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 15 inches by 20 inches and Jordan's rectangle is 6 inches long, how wide is Jordan's rectangle, in inches? Pick.
A) 20 B) 30 C) 40 D) 50 E) 60 | <gadget id="calculator">15 * 20</gadget>
<output>300</output>
<gadget id="calculator">300 / 6</gadget>
<output>50</output>
<result>D</result> | D | 50 | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 15 inches by 20 inches and Jordan's rectangle is 6 inches long, how wide is Jordan's rectangle, in inches? | {
"A": "20",
"B": "30",
"C": "40",
"D": "50",
"E": "60"
} | divide(rectangle_area(15, 20), 6) | rectangle_area(n0,n1)|divide(#0,n2)| | "area of first rectangle is 15 * 20 = 300 hence area of second would be 6 x = 300 x x = 50 answer is d" | geometry |
math_qa__qscXSZNdWumhJNSl | The purchase price of an article is $48. In order to include 15% of cost for overhead and to provide $12 of net profit, the markup should be Choose the most appropriate option.
A) 15 %
B) 25 %
C) 35 %
D) 40 %
E) 45 % | <gadget id="calculator">12 / 48</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<gadget id="calculator">25 + 15</gadget>
<output>40</output>
<result>D</result> | D | 40 | The purchase price of an article is $48. In order to include 15% of cost for overhead and to provide $12 of net profit, the markup should be | {
"A": "15 %",
"B": "25 %",
"C": "35 %",
"D": "40 %",
"E": "45 %"
} | add(multiply(divide(12, 48), const_100), 15) | divide(n2,n0)|multiply(#0,const_100)|add(n1,#1)| | "cost price of article = 48 $ % of overhead cost = 15 net profit = 12 $ we need to calculate % markup net profit as % of cost price = ( 12 / 48 ) * 100 = 25 % total markup should be = 25 + 15 = 40 % answer d" | gain |
math_qa__HDLTXWy8IPQVjZBl | In a garment industry, 12 men working 8 hours per day complete a piece of work in 10 days. To complete the same work in 8 days, working 13.33 hours a day, the number of men required is: Select the correct option.
A) 4 B) 5 C) 6 D) 8 E) 9 | <gadget id="calculator">12 * 8</gadget>
<output>96</output>
<gadget id="calculator">96 * 10</gadget>
<output>960</output>
<gadget id="calculator">960 / 13.33</gadget>
<output>72.018005</output>
<gadget id="calculator">72.018005 / 8</gadget>
<output>9.002251</output>
<result>E</result> | E | 9 | In a garment industry, 12 men working 8 hours per day complete a piece of work in 10 days. To complete the same work in 8 days, working 13.33 hours a day, the number of men required is: | {
"A": "4",
"B": "5",
"C": "6",
"D": "8",
"E": "9"
} | divide(divide(multiply(multiply(12, 8), 10), 13.33), 8) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n4)|divide(#2,n1)| | "explanation : let the required number of men be x . less days , more men ( indirect proportion ) more working hrs per day , less men ( indirect proportion ) days 8 : 10 working hrs 13.33 : 8 : : 12 : x = > 8 x 13.33 x x = 10 x 8 x 12 = > x = 10 x 8 x 12 / ( 8 x 13.33 ) = > x = 9 answer : e" | physics |
math_qa__gy3Q8l5ZArvj2zAh | papaya , a popular soft drink , contains only 4 ingredients . soda water comprise 4 / 7 of papaya and natural lemon juice makes 1 / 3 of papaya . the amounts of sugar and papaya puree in papaya are equal . due to a malfunction , the mixing machine mixes double the regular amount of lemon juice and 3 times the regular amount of papaya puree . if no other changes were made to the relative quantities of the ingredients , what is the fractional portion of soda water in the drink that comes out of the malfunctioning machine ?
Choose the correct choice.
A) 7 / 30 B) 7 / 21 C) 2 / 5 D) 12 / 29 E) 4 / 7 | <gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">(4/7) * 21</gadget>
<output>12</output>
<gadget id="calculator">2 * 7</gadget>
<output>14</output>
<gadget id="calculator">14 + 12</gadget>
<output>26</output>
<gadget id="calculator">3 * 1</gadget>
<output>3</output>
<gadget id="calculator">26 + 3</gadget>
<output>29</output>
<gadget id="calculator">29 + 1</gadget>
<output>30</output>
<gadget id="calculator">12 / 30</gadget>
<output>2/5 = around 0.4</output>
<result>C</result> | C | 0.4 | papaya , a popular soft drink , contains only 4 ingredients . soda water comprise 4 / 7 of papaya and natural lemon juice makes 1 / 3 of papaya . the amounts of sugar and papaya puree in papaya are equal . due to a malfunction , the mixing machine mixes double the regular amount of lemon juice and 3 times the regular amount of papaya puree . if no other changes were made to the relative quantities of the ingredients , what is the fractional portion of soda water in the drink that comes out of the malfunctioning machine ? | {
"A": "7 / 30",
"B": "7 / 21",
"C": "2 / 5",
"D": "12 / 29",
"E": "4 / 7"
} | divide(multiply(divide(4, 7), multiply(7, 3)), add(add(add(multiply(const_2, 7), multiply(divide(4, 7), multiply(7, 3))), multiply(3, 1)), 1)) | divide(n0,n2)|multiply(n2,n4)|multiply(n2,const_2)|multiply(n3,n4)|multiply(#0,#1)|add(#2,#4)|add(#5,#3)|add(n3,#6)|divide(#4,#7) | soda water = 12 / 21 natural lemon juice = 7 / 21 the quantities of sugar and papaya puree are equal . total units are 21 of which 12 + 7 = 19 are used up by above two . remaining is 2 which is equally divided between sugar and papaya puree : sugar = 1 / 21 papaya puree = 1 / 21 thus ratio of soda : lemon : sugar : puree = 12 : 7 : 1 : 1 now , lemon is doubled , puree is three times and remaining are the same . resultant ratio is = 12 : 14 : 1 : 3 ratio of soda water in the resultant mixture = 12 / ( 12 + 14 + 1 + 3 ) = 12 / 30 = 2 / 5 answer : c | general |
math_qa__JqGPxmrbWpDHrdyv | How long does a train 130 m long running at the speed of 80 km/hr takes to cross a bridge 140 m length? Options
A) 13.9 sec B) 12.3 sec C) 17.9 sec D) 61.9 sec E) 47.98 sec | <gadget id="calculator">130 + 140</gadget>
<output>270</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">80 * (5/18)</gadget>
<output>200/9 = around 22.222222</output>
<gadget id="calculator">270 / (200/9)</gadget>
<output>243/20 = around 12.15</output>
<result>B</result> | B | 12.3 | How long does a train 130 m long running at the speed of 80 km/hr takes to cross a bridge 140 m length? | {
"A": "13.9 sec",
"B": "12.3 sec",
"C": "17.9 sec",
"D": "61.9 sec",
"E": "47.98 sec"
} | divide(add(130, 140), multiply(80, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 80 * 5 / 18 = 22 m / sec total distance covered = 130 + 140 = 270 m . required time = 270 / 22 = 12.3 sec . answer : b" | physics |
math_qa__xWcf05P2aKXbtVXH | Ramesh, xyz and Rajeev put a partnership. profit is 36000, if Ramesh and xyz ratio is 5 : 4 and xyz and Rajeev 8:9. Find Rajeev's share. Select the correct option:
A) 14000 B) 15000 C) 16000 D) 12000 E) 17000 | <gadget id="calculator">5 * 8</gadget>
<output>40</output>
<gadget id="calculator">40 / 4</gadget>
<output>10</output>
<gadget id="calculator">10 + 8</gadget>
<output>18</output>
<gadget id="calculator">18 + 9</gadget>
<output>27</output>
<gadget id="calculator">9 / 27</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">36_000 * (1/3)</gadget>
<output>12_000</output>
<result>D</result> | D | 12,000 | Ramesh, xyz and Rajeev put a partnership. profit is 36000, if Ramesh and xyz ratio is 5 : 4 and xyz and Rajeev 8:9. Find Rajeev's share. | {
"A": "14000",
"B": "15000",
"C": "16000",
"D": "12000",
"E": "17000"
} | multiply(36000, divide(9, add(add(divide(multiply(5, 8), 4), 8), 9))) | multiply(n1,n3)|divide(#0,n2)|add(n3,#1)|add(n4,#2)|divide(n4,#3)|multiply(n0,#4) | ramesh : xyz = 5 : 4 xyz : rajeev = 8 : 9 then ramesh : xyz / rajeev : xyz = 5 : 4 / 9 : 8 ramesh / rajeev = 10 / 9 therefore ramesh : xyz : rajeev = 10 : 8 : 9 then rajeev share = ( 9 / 27 ) * 36000 = 12000 answer : d | other |
math_qa__H9gDirYtOGseOsuq | A trader cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 10% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 30% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage. Choose the correct answer: A) 20 % B) 43 % C) 99.33 % D) 75.109 % E) 47 % | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 / 100</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">(13/10) * 110</gadget>
<output>143</output>
<gadget id="calculator">143 - 100</gadget>
<output>43</output>
<result>B</result> | B | 43 | A trader cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 10% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 30% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage. | {
"A": "20 %",
"B": "43 %",
"C": "99.33 %",
"D": "75.109 %",
"E": "47 %"
} | subtract(multiply(divide(add(const_100, 30), const_100), add(const_100, 10)), const_100) | add(n0,const_100)|add(n1,const_100)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,const_100) | anyways , one can infer that he ' steals ' 10 % from suppliers and then charges 30 % extra to customers so basically 1.1 * 1.3 = 1.43 given that 1 is start point , we get 43 % more hence answer is b | gain |
math_qa__vpZTGA4q79hNL50C | In measuring the sides of a rectangle, one side is taken 14% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements. Choose the correct choice from the following options:
A) 3.5 % B) 2.4 % C) 8.3 % D) 5 % E) 2.6 % | <gadget id="calculator">14 - 5</gadget>
<output>9</output>
<gadget id="calculator">14 * 5</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">9 - (7/10)</gadget>
<output>83/10 = around 8.3</output>
<result>C</result> | C | 8.3 | In measuring the sides of a rectangle, one side is taken 14% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements. | {
"A": "3.5 %",
"B": "2.4 %",
"C": "8.3 %",
"D": "5 %",
"E": "2.6 %"
} | subtract(subtract(14, 5), divide(multiply(14, 5), const_100)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,const_100)|subtract(#1,#2)| | "say both sides of the rectangle are equal to 100 ( so consider that we have a square ) . in this case the area is 100 * 100 = 10,000 . now , the area obtained with wrong measurements would be 114 * 95 = 10,830 , which is 8.3 % greater than the actual area . answer : c ." | geometry |
math_qa__hWVKG33WxkfCxXr6 | In an office, totally there are 5200 employees and 45% of the total employees are males. 50% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years? Pick one
A) 1040 B) 1170 C) 1150 D) 4160 E) none of these | <gadget id="calculator">5_200 * 45</gadget>
<output>234_000</output>
<gadget id="calculator">234_000 / 100</gadget>
<output>2_340</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2_340 * (1/2)</gadget>
<output>1_170</output>
<result>B</result> | B | 1,170 | In an office, totally there are 5200 employees and 45% of the total employees are males. 50% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years? | {
"A": "1040",
"B": "1170",
"C": "1150",
"D": "4160",
"E": "none of these"
} | multiply(divide(multiply(5200, 45), const_100), divide(subtract(const_100, 50), const_100)) | multiply(n0,n1)|subtract(const_100,n2)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)| | "number of male employees = 5200 * 45 / 100 = 2340 required number of male employees who are less than 50 years old = 4160 * ( 100 - 50 ) % = 2340 * 50 / 100 = 1170 . answer : b" | general |
math_qa__rooQC2Xw9ckm7yqj | A lady builds 12cm length, 16cm width, and 6cm height box using 3cubic cm cubes. What is the minimum number of cubes required to build the box? Choose the correct choice from the following answers.
A) 345 B) 384 C) 378 D) 398 E) 300 | <gadget id="calculator">12 * 16</gadget>
<output>192</output>
<gadget id="calculator">192 * 6</gadget>
<output>1_152</output>
<gadget id="calculator">1_152 / 3</gadget>
<output>384</output>
<result>B</result> | B | 384 | A lady builds 12cm length, 16cm width, and 6cm height box using 3cubic cm cubes. What is the minimum number of cubes required to build the box? | {
"A": "345",
"B": "384",
"C": "378",
"D": "398",
"E": "300"
} | divide(multiply(multiply(12, 16), 6), 3) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n3)| | "number of cubes required = volume of box / volume of cube = 12 * 16 * 6 / 3 = 384 cubes answer : b" | geometry |
math_qa__iP4qtIY1JZNUEjo8 | The perimeter of a semi circle is 121 cm then the radius is? Pick one
A) 17
B) 28
C) 24
D) 26
E) 12 | <gadget id="calculator">2 + pi</gadget>
<output>2 + pi = around 5.141593</output>
<gadget id="calculator">121 / (2 + pi)</gadget>
<output>121/(2 + pi) = around 23.533564</output>
<result>C</result> | C | 24 | The perimeter of a semi circle is 121 cm then the radius is? | {
"A": "17",
"B": "28",
"C": "24",
"D": "26",
"E": "12"
} | divide(121, add(const_2, const_pi)) | add(const_2,const_pi)|divide(n0,#0)| | "36 / 7 r = 121 = > r = 24 answer : c" | physics |
math_qa__41GlBvXSiIJeSmFl | If you write down all the numbers from 1 to 100, then how many multiples of 3 ? Choose the correct choice
A) 32 B) 38 C) 30 D) 31 E) 33 | <gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">99 / 3</gadget>
<output>33</output>
<result>E</result> | E | 33 | If you write down all the numbers from 1 to 100, then how many multiples of 3 ? | {
"A": "32",
"B": "38",
"C": "30",
"D": "31",
"E": "33"
} | divide(subtract(100, const_1), 3) | subtract(n1,const_1)|divide(#0,n2) | division rule for 3 - sum of all digits is multiple of 3 3 6 9 12 15 18 21 24 27 30 33 36 39 42 45 48 51 54 57 60 63 66 69 72 75 78 81 84 87 90 93 96 99 ans - e | general |
math_qa__mMl4dK9Tz2SZPGkG | If x + (1/x) = 5, what is the value Q of x^2 + (1/x)^2? Options
A) q = 21 B) q = 22 C) q = 23 D) 24 E) 27 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 2</gadget>
<output>23</output>
<result>C</result> | C | 23 | If x + (1/x) = 5, what is the value Q of x^2 + (1/x)^2? | {
"A": "q = 21",
"B": "q = 22",
"C": "q = 23",
"D": "24",
"E": "27"
} | subtract(power(5, 2), 2) | power(n1,n2)|subtract(#0,n2) | squaring on both sides , x ^ 2 + ( 1 / x ) ^ 2 + 2 ( x ) ( 1 / x ) = 5 ^ 2 x ^ 2 + ( 1 / x ) ^ 2 = 23 answer : c | general |
math_qa__LNY0gZQGhpyIbyAu | if 2 ^ 4 , 3 ^ 3 , and 13 ^ 3 are factors of the product of 1452 and w , where w is a positive integer , what is the smallest possible value of w ? Choose the correct choice:
A) 198
B) 288
C) 363
D) 396
E) 468 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">4 * 9</gadget>
<output>36</output>
<gadget id="calculator">36 * 13</gadget>
<output>468</output>
<result>E</result> | E | 468 | if 2 ^ 4 , 3 ^ 3 , and 13 ^ 3 are factors of the product of 1452 and w , where w is a positive integer , what is the smallest possible value of w ? | {
"A": "198",
"B": "288",
"C": "363",
"D": "396",
"E": "468"
} | multiply(multiply(power(2, 2), power(3, 2)), 13) | power(n0,n0)|power(n2,n0)|multiply(#0,#1)|multiply(n4,#2) | i will go with e ( pending elements to match is 2 ^ 2 * 3 ^ 2 * 13 ^ 1 = 468 | general |
math_qa__dNDTXPulcYLUYMtf | In a certain egg-processing plant, every egg must be inspected, and is either accepted for processing or rejected. For every 96 eggs accepted for processing, 4 eggs are rejected. If, on a particular day, 12 additional eggs were accepted, but the overall number of eggs inspected remained the same, the ratio of those accepted to those rejected would be 99 to 1. How many W eggs does the plant process per day? Pick: A) 100 B) 300 C) 400 D) 3,000 E) 4,000 | <gadget id="calculator">99 - 96</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<result>C</result> | C | 400 | In a certain egg-processing plant, every egg must be inspected, and is either accepted for processing or rejected. For every 96 eggs accepted for processing, 4 eggs are rejected. If, on a particular day, 12 additional eggs were accepted, but the overall number of eggs inspected remained the same, the ratio of those accepted to those rejected would be 99 to 1. How many W eggs does the plant process per day? | {
"A": "100",
"B": "300",
"C": "400",
"D": "3,000",
"E": "4,000"
} | multiply(divide(12, subtract(99, 96)), const_100) | subtract(n3,n0)|divide(n2,#0)|multiply(#1,const_100)| | "straight pluggin in for me . as usual , i started with c and got the answer . lets ' back calculate and see what we get let us consider eggs processed each day to be 400 so initial ratio of eggs processed and rejected is 96 : 4 or 24 : 1 so out of 400 eggs , there will be 384 eggs processed and 16 rejected . now if the no . of eggs inspected remain and 12 more eggs get accepted that means there w = 384 + 12 = 396 eggs accepted and 4 rejected . . . and the ratio will be 99 : 1 bingo . . . this is what the questions says . . . . its always a good idea to start with c ." | general |
math_qa__Rna2Ewvs30WvGxB2 | The compound ratio of 2:3, 3:4 and 4:5? Select the correct option: A) 1 : 2 B) 2 : 5 C) 3 : 4 D) 3 : 5 E) 3 : 9 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">12 / 10</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(1/2) / (6/5)</gadget>
<output>5/12 = around 0.416667</output>
<result>B</result> | B | 0.4 | The compound ratio of 2:3, 3:4 and 4:5? | {
"A": "1 : 2",
"B": "2 : 5",
"C": "3 : 4",
"D": "3 : 5",
"E": "3 : 9"
} | divide(divide(multiply(2, 3), multiply(3, 4)), divide(multiply(3, 4), multiply(const_2.0, 5))) | multiply(n0,n2)|multiply(n1,n3)|multiply(n2,n4)|multiply(const_2.0,n5)|divide(#0,#1)|divide(#2,#3)|divide(#4,#5)| | 2 / 3 * 3 / 4 * 4 / 5 = 2 / 5 2 : 5 answer : b | other |
math_qa__94MAncNX2lkHIywq | The probability that event B occurs is 0.4, and the probability that events A and B both occur is 0.25. If the probability that either event A or event B occurs is 0.6, what is the probability that event A will occur? Choose the correct choice from the following choices.
A) 0.05
B) 0.45
C) 0.15
D) 0.5
E) 0.55 | <gadget id="calculator">0.25 + 0.6</gadget>
<output>0.85</output>
<gadget id="calculator">0.85 - 0.4</gadget>
<output>0.45</output>
<result>B</result> | B | 0.45 | The probability that event B occurs is 0.4, and the probability that events A and B both occur is 0.25. If the probability that either event A or event B occurs is 0.6, what is the probability that event A will occur? | {
"A": "0.05",
"B": "0.45",
"C": "0.15",
"D": "0.5",
"E": "0.55"
} | subtract(add(0.25, 0.6), 0.4) | add(n1,n2)|subtract(#0,n0)| | "p ( a or b ) = p ( a ) + p ( b ) - p ( a n b ) 0.6 = 0.4 + p ( a ) - 0.25 p ( a ) = 0.45 ans : b" | other |
math_qa__fu2uFvBGz3Obihl2 | When anunfaircoin is tossed twice, the probability of getting one tails and one heads is 1/2. What is the probability of getting two heads and two tails if the coin is tossed 4 times? Choose the correct choice:
A) 2 / 3
B) 1 / 3
C) 1 / 4
D) 1 / 6
E) 1 / 9 | <gadget id="calculator">1 / 1</gadget>
<output>1</output>
<gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<result>E</result> | E | 0.111111 | When anunfaircoin is tossed twice, the probability of getting one tails and one heads is 1/2. What is the probability of getting two heads and two tails if the coin is tossed 4 times? | {
"A": "2 / 3",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 6",
"E": "1 / 9"
} | divide(divide(1, const_1), multiply(add(multiply(1, const_1), 2), const_3)) | divide(n0,const_1)|multiply(n0,const_1)|add(n1,#1)|multiply(#2,const_3)|divide(#0,#3) | let the probability of heads be x and the probability of tails be 1 - x . so , we are given that p ( one tails and one heads ) = 2 * x * ( 1 - x ) = 1 / 2 . p ( two heads and two tails ) = 4 ! / ( 2 ! 2 ! ) * x ^ 2 * ( 1 - x ) ^ 2 = 6 * ( x * ( 1 - x ) ) ^ 2 . we are multiplying by 4 ! / ( 2 ! 2 ! ) because hhtt scenario can occur in several ways : hhtt , htht , thht , . . . ( permutation of 4 letters hhtt where 2 t ' s and 2 h ' s are the same ) . since from 2 * x * ( 1 - x ) = 1 / 2 it follows that x * ( 1 - x ) = 1 / 4 , then 4 * ( x * ( 1 - x ) ) ^ 2 = 4 * ( 1 / 6 ) ^ 2 = 1 / 9 . answer : e . | general |
math_qa__ARUjh1Vz4CxMbbWE | Amar takes as much time in running 15 meters as a car takes in covering 40 meters. What will be the distance covered by Amar during the time the car covers 1.9 km? Answers: A) 700 m B) 720 m C) 712 m D) 600 m E) 640 m | <gadget id="calculator">1.9 * 1_000</gadget>
<output>1_900</output>
<gadget id="calculator">15 * 1_900</gadget>
<output>28_500</output>
<gadget id="calculator">28_500 / 40</gadget>
<output>1_425/2 = around 712.5</output>
<result>C</result> | C | 712 | Amar takes as much time in running 15 meters as a car takes in covering 40 meters. What will be the distance covered by Amar during the time the car covers 1.9 km? | {
"A": "700 m",
"B": "720 m",
"C": "712 m",
"D": "600 m",
"E": "640 m"
} | divide(multiply(15, multiply(1.9, const_1000)), 40) | multiply(n2,const_1000)|multiply(n0,#0)|divide(#1,n1) | distance covered by amar = 15 / 40 ( 1.9 km ) = 3 / 8 ( 1900 ) = 712 m answer : c | physics |
math_qa__ZskJRf9xKM3KNnGt | At the end of the first quarter, the share price of a certain mutual fund was 25 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 55 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? Choose the correct choice from the following options:
A) 24 % B) 25 % C) 30 % D) 33 % E) 40 % | <gadget id="calculator">100 + 55</gadget>
<output>155</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">155 / 125</gadget>
<output>31/25 = around 1.24</output>
<gadget id="calculator">(31/25) - 1</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">(6/25) * 100</gadget>
<output>24</output>
<result>A</result> | A | 24 | At the end of the first quarter, the share price of a certain mutual fund was 25 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 55 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? | {
"A": "24 %",
"B": "25 %",
"C": "30 %",
"D": "33 %",
"E": "40 %"
} | multiply(subtract(divide(add(const_100, 55), add(const_100, 25)), const_1), const_100) | add(n1,const_100)|add(n0,const_100)|divide(#0,#1)|subtract(#2,const_1)|multiply(#3,const_100)| | "another method is to use the formula for 2 successive percentage changes : total = a + b + ab / 100 55 = 25 + b + 25 b / 100 b = 24 answer ( a )" | gain |
math_qa__IQnYuSq0H09Mc00i | A marketing firm determined that, of 200 households surveyed, 80 used neither Brand E nor Brand B soap, 60 used only Brand E soap, and for every household that used both brands of soap, 3 used only Brand B soap. How many of the 200 households surveyed used both brands of soap? Choose the correct choice from the following answers.
A) 15 B) 20 C) 30 D) 40 E) 45 | <gadget id="calculator">200 - 80</gadget>
<output>120</output>
<gadget id="calculator">120 / 3</gadget>
<output>40</output>
<result>D</result> | D | 40 | A marketing firm determined that, of 200 households surveyed, 80 used neither Brand E nor Brand B soap, 60 used only Brand E soap, and for every household that used both brands of soap, 3 used only Brand B soap. How many of the 200 households surveyed used both brands of soap? | {
"A": "15",
"B": "20",
"C": "30",
"D": "40",
"E": "45"
} | divide(subtract(200, 80), 3) | subtract(n0,n1)|divide(#0,n3) | solution for soap e and soap b ( d ) 40 | other |
math_qa__GwJZdh5jbKRW7g6u | Two employees X and Y are paid a total of Rs. 570 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? Choose the correct choice from the following answers: A) s . 259 B) s . 289 C) s . 299 D) s . 300 E) s . 389 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">570 * 10</gadget>
<output>5_700</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">5_700 / 22</gadget>
<output>2_850/11 = around 259.090909</output>
<result>A</result> | A | 259 | Two employees X and Y are paid a total of Rs. 570 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? | {
"A": "s . 259",
"B": "s . 289",
"C": "s . 299",
"D": "s . 300",
"E": "s . 389"
} | divide(multiply(570, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4) | let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 570 but x = 120 % of y = 120 y / 100 = 12 y / 10 ∴ 12 y / 10 + y = 570 ⇒ y [ 12 / 10 + 1 ] = 570 ⇒ 22 y / 10 = 570 ⇒ 22 y = 5700 ⇒ y = 5700 / 22 = rs . 259 a ) | general |
math_qa__SgX5zxLrD6A2JgOh | A train 390 metres long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in : Choose the correct choice from the following answers: A) 30 sec B) 32 sec C) 36 sec D) 38 sec E) 52 sec | <gadget id="calculator">390 / 1_000</gadget>
<output>39/100 = around 0.39</output>
<gadget id="calculator">25 + 2</gadget>
<output>27</output>
<gadget id="calculator">(39/100) / 27</gadget>
<output>13/900 = around 0.014444</output>
<gadget id="calculator">3_600 * (13/900)</gadget>
<output>52</output>
<result>E</result> | E | 52 | A train 390 metres long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in : | {
"A": "30 sec",
"B": "32 sec",
"C": "36 sec",
"D": "38 sec",
"E": "52 sec"
} | multiply(const_3600, divide(divide(390, const_1000), add(25, 2))) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_3600)| | "relative speed = ( 25 + 2 ) km / hr = 27 km / hr = ( 27 × 5 / 18 ) m / sec = 15 / 2 m / sec . time taken by the train to pass the man = ( 390 × 2 / 15 ) sec = 52 sec answer : e" | physics |
math_qa__Qld9ahSIIlNY9JpH | the average of 6 number is 3.95 . the average of two of them is 3.8 , while the average of the other two is 3.85 . what is the average of the remaining two number ? Choose the correct choice from the following.
A) 4.5 B) 4.2 C) 4.7 D) 4.8 E) none of these | <gadget id="calculator">3.95 * 6</gadget>
<output>23.7</output>
<gadget id="calculator">3.8 * 2</gadget>
<output>7.6</output>
<gadget id="calculator">3.85 * 2</gadget>
<output>7.7</output>
<gadget id="calculator">7.6 + 7.7</gadget>
<output>15.3</output>
<gadget id="calculator">23.7 - 15.3</gadget>
<output>8.4</output>
<gadget id="calculator">8.4 / 2</gadget>
<output>4.2</output>
<result>B</result> | B | 4.2 | the average of 6 number is 3.95 . the average of two of them is 3.8 , while the average of the other two is 3.85 . what is the average of the remaining two number ? | {
"A": "4.5",
"B": "4.2",
"C": "4.7",
"D": "4.8",
"E": "none of these"
} | divide(subtract(multiply(3.95, 6), add(multiply(3.8, const_2), multiply(3.85, const_2))), const_2) | multiply(n0,n1)|multiply(n2,const_2)|multiply(n3,const_2)|add(#1,#2)|subtract(#0,#3)|divide(#4,const_2) | solution : sum of the remaining two numbers = ( 3.95 × 6 ) - [ ( 3.8 × 2 ) + ( 3.85 × 2 ) ] = 23.70 - ( 7.6 + 7.7 ) = 23.70 - 15.3 = 8.4 . ∴ required average = 8.4 / 2 = 4.2 answer b | general |
math_qa__INuHdX7YBFf9ihwI | A basketball team composed of 12 players scored 100 points in a particular contest. If none of the individual players scored fewer than 7 points, what is the greatest number of points Q that an individual player might have scored? Choose the correct choice from the following answers: A) 7 B) 13 C) 16 D) 21 E) 23 | <gadget id="calculator">12 * 7</gadget>
<output>84</output>
<gadget id="calculator">100 - 84</gadget>
<output>16</output>
<gadget id="calculator">16 + 7</gadget>
<output>23</output>
<result>E</result> | E | 23 | A basketball team composed of 12 players scored 100 points in a particular contest. If none of the individual players scored fewer than 7 points, what is the greatest number of points Q that an individual player might have scored? | {
"A": "7",
"B": "13",
"C": "16",
"D": "21",
"E": "23"
} | add(subtract(100, multiply(12, 7)), 7) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1) | general rule for such kind of problems : to maximize one quantity , minimize the others ; to minimize one quantity , maximize the others . thus to maximize the number of points of one particular player minimize the number of points of all other 11 players . minimum number of points for a player is 7 , so the minimum number of points of 11 players is 7 * 11 = 77 . therefore , the maximum number of points q for 12 th player is 100 - 77 = 23 . answer : e . | general |
math_qa__WWefpjBMR2od372L | Jill has 7 gallons of water stored in quart, half-gallon, and one gallon jars. She has equal numbers of each size jar holding the liquid. What is the total number of water filled jars?
Pick one: A) 3 B) 6 C) 9 D) 12 E) 14 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) + (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 + (3/4)</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">7 / (7/4)</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<result>D</result> | D | 12 | Jill has 7 gallons of water stored in quart, half-gallon, and one gallon jars. She has equal numbers of each size jar holding the liquid. What is the total number of water filled jars? | {
"A": "3",
"B": "6",
"C": "9",
"D": "12",
"E": "14"
} | multiply(divide(7, add(const_1, add(const_0_25, divide(const_1, const_2)))), const_3) | divide(const_1,const_2)|add(#0,const_0_25)|add(#1,const_1)|divide(n0,#2)|multiply(#3,const_3) | let the number of each size of jar = w then 1 / 4 w + 1 / 2 w + w = 7 1 3 / 4 w = 7 w = 4 the total number of jars = 3 w = 12 answer : d | general |
math_qa__VOvUrJS6YikRjqL3 | The sum of ages of 5 children born 2 years different each is 50 yrs. What is the age of the Elder child? Choose one
A) 8
B) 14
C) 16
D) 17
E) 18 | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">20 + 50</gadget>
<output>70</output>
<gadget id="calculator">70 / 5</gadget>
<output>14</output>
<result>B</result> | B | 14 | The sum of ages of 5 children born 2 years different each is 50 yrs. What is the age of the Elder child? | {
"A": "8",
"B": "14",
"C": "16",
"D": "17",
"E": "18"
} | divide(add(add(add(add(2, const_4), add(2, const_4)), add(const_4, const_4)), 50), 5) | add(n1,const_4)|add(const_4,const_4)|add(#0,#0)|add(#2,#1)|add(n2,#3)|divide(#4,n0) | let the ages of children be x , ( x + 2 ) , ( x + 4 ) , ( x + 6 ) and ( x + 8 ) years . then , x + ( x + 2 ) + ( x + 4 ) + ( x + 6 ) + ( x + 8 ) = 50 5 x = 30 x = 6 x + 8 = 6 + 8 = 14 answer : b | general |
math_qa__VZHuc2N4BR1lTqFP | Vijay sells a cupboard at 14% below cost price. Had he got Rs.2086 more, he would have made a profit of 14%. What is the cost price of the cupboard? Choose the most appropriate option
A) 7458 B) 7456 C) 7450 D) 7454 E) 7453 | <gadget id="calculator">100 + 14</gadget>
<output>114</output>
<gadget id="calculator">100 - 14</gadget>
<output>86</output>
<gadget id="calculator">114 - 86</gadget>
<output>28</output>
<gadget id="calculator">28 / 100</gadget>
<output>7/25 = around 0.28</output>
<gadget id="calculator">2_086 / (7/25)</gadget>
<output>7_450</output>
<result>C</result> | C | 7,450 | Vijay sells a cupboard at 14% below cost price. Had he got Rs.2086 more, he would have made a profit of 14%. What is the cost price of the cupboard? | {
"A": "7458",
"B": "7456",
"C": "7450",
"D": "7454",
"E": "7453"
} | divide(2086, divide(subtract(add(const_100, 14), subtract(const_100, 14)), const_100)) | add(n0,const_100)|subtract(const_100,n0)|subtract(#0,#1)|divide(#2,const_100)|divide(n1,#3)| | "explanation : cost price = 2086 / ( 0.14 + 0.14 ) = 2086 / 0.28 = rs . 7450 answer : c" | gain |
math_qa__lGLTChPsDinoq0FU | We bought a total of 80 books at the store. Math books cost $4 and history books cost $5. The total price was $390. How many math books did we buy? Choose the correct answer:
A) 10 B) 20 C) 30 D) 40 E) 50 | <gadget id="calculator">80 * 4</gadget>
<output>320</output>
<gadget id="calculator">390 - 320</gadget>
<output>70</output>
<gadget id="calculator">80 - 70</gadget>
<output>10</output>
<result>A</result> | A | 10 | We bought a total of 80 books at the store. Math books cost $4 and history books cost $5. The total price was $390. How many math books did we buy? | {
"A": "10",
"B": "20",
"C": "30",
"D": "40",
"E": "50"
} | subtract(80, subtract(390, multiply(80, 4))) | multiply(n0,n1)|subtract(n3,#0)|subtract(n0,#1)| | "m + h = 80 h = 80 - m 4 m + 5 h = 390 4 m + 5 * ( 80 - m ) = 390 m = 10 the answer is a ." | general |
math_qa__Hb6ODWODlW4vBo9p | A hall 36m long and 15m broad is to be paved with stones, each measuring 6dm by 5 dm. The number of stones required is: Select the correct option: A) 180 B) 1800 C) 18 D) 18000 E) 1.8 | <gadget id="calculator">36 * 15</gadget>
<output>540</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">540 / (3/10)</gadget>
<output>1_800</output>
<result>B</result> | B | 1,800 | A hall 36m long and 15m broad is to be paved with stones, each measuring 6dm by 5 dm. The number of stones required is: | {
"A": "180",
"B": "1800",
"C": "18",
"D": "18000",
"E": "1.8"
} | divide(multiply(36, 15), divide(multiply(6, 5), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#1,const_100)|divide(#0,#2)| | "area of the hall = 3600 * 1500 area of each stone = ( 60 * 50 ) therefore , number of stones = ( 3600 * 1500 / 60 * 50 ) = 1800 answer : b" | physics |
math_qa__FyLgRrWLvCYeJjn7 | Walking with 4/5 of my usual speed, I arrive at the bus stop 10 minutes later than normal. How many minutes does it take to walk to the bus stop at my usual speed? Select the correct option.
A) 32 B) 36 C) 40 D) 44 E) 48 | <gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) - 1</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">10 / (1/4)</gadget>
<output>40</output>
<result>C</result> | C | 40 | Walking with 4/5 of my usual speed, I arrive at the bus stop 10 minutes later than normal. How many minutes does it take to walk to the bus stop at my usual speed? | {
"A": "32",
"B": "36",
"C": "40",
"D": "44",
"E": "48"
} | divide(10, subtract(divide(5, 4), const_1)) | divide(n1,n0)|subtract(#0,const_1)|divide(n2,#1)| | "let t = usual time = distance / usual speed t + 10 = distance / ( 4 * usual speed / 5 ) = ( 5 * distance ) / ( 4 * usual speed ) = 5 t / 4 t = 40 the answer is c ." | physics |
math_qa__qnpHDnv4YS7d9rf8 | Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 480 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)
Choose the correct option:
A) 32 / 15
B) 3 / 8
C) 8 / 5
D) 5 / 8
E) 5 / 3 | <gadget id="calculator">480 / 3</gadget>
<output>160</output>
<gadget id="calculator">300 / 4</gadget>
<output>75</output>
<gadget id="calculator">160 / 75</gadget>
<output>32/15 = around 2.133333</output>
<result>A</result> | A | 2.133333 | Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 480 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy) | {
"A": "32 / 15",
"B": "3 / 8",
"C": "8 / 5",
"D": "5 / 8",
"E": "5 / 3"
} | divide(divide(480, 3), divide(300, 4)) | divide(n2,n0)|divide(n3,n1)|divide(#0,#1)| | "distance traveled by eddy = 480 km time taken by eddy = 3 hours average speed of eddy = 480 / 3 = 160 km / hour distance traveled by freddy = 300 km time taken by freddy = 4 hours average speed of freddy = 300 / 4 = 75 km / hour ratio of average speed of eddy to freddy = 160 / 75 = 32 / 15 answer a" | physics |
math_qa__l91SU1LCbtIjPSh6 | Ram, who is half as efficient as Krish, will take 24 days to complete a task if he worked alone. If Ram and Krish worked together, how long will they take to complete the task? Select the correct option:
A) 16 days
B) 12 days
C) 8 days
D) 6 days
E) 18 days | <gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/24) + (1/12)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<result>C</result> | C | 8 | Ram, who is half as efficient as Krish, will take 24 days to complete a task if he worked alone. If Ram and Krish worked together, how long will they take to complete the task? | {
"A": "16 days",
"B": "12 days",
"C": "8 days",
"D": "6 days",
"E": "18 days"
} | inverse(add(divide(const_1, 24), divide(const_1, divide(24, const_2)))) | divide(const_1,n0)|divide(n0,const_2)|divide(const_1,#1)|add(#0,#2)|inverse(#3)| | "answer ram takes 24 days to complete the task , if he works alone . krish is twice as efficient as ram is . so , working alone , krish will take half the time to complete the task . i . e . , 12 days . ram will complete 1 / 24 th of the task in a day . krish will complete 1 / 12 th of the task in a day . when they work together , they will complete 1 / 24 + 1 / 12 = 1 / 8 th of the task in a day . therefore , when they work together they will complete the task in 8 days . choice c" | physics |
math_qa__NdULoKGvXXX8pvhH | I bought two books; for Rs.540. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss? Choose the correct choice from the following
A) 197 B) 280 C) 189 D) 278 E) 315 | <gadget id="calculator">100 + 19</gadget>
<output>119</output>
<gadget id="calculator">540 * 119</gadget>
<output>64_260</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 + 119</gadget>
<output>204</output>
<gadget id="calculator">64_260 / 204</gadget>
<output>315</output>
<result>E</result> | E | 315 | I bought two books; for Rs.540. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss? | {
"A": "197",
"B": "280",
"C": "189",
"D": "278",
"E": "315"
} | divide(multiply(540, add(const_100, 19)), add(subtract(const_100, 15), add(const_100, 19))) | add(n2,const_100)|subtract(const_100,n1)|add(#0,#1)|multiply(n0,#0)|divide(#3,#2)| | "x * ( 85 / 100 ) = ( 540 - x ) 119 / 100 x = 315 answer : e" | gain |
math_qa__YDMRbRnQqiwmNCtO | A sum of money deposited at C.I. amounts to Rs.1980 in 3 years and to Rs.2492 in 4 years. Find the rate percent? Choose the correct answer:
A) 30 % B) 10 % C) 25 % D) 19 % E) 50 % | <gadget id="calculator">2_492 - 1_980</gadget>
<output>512</output>
<gadget id="calculator">512 / 1_980</gadget>
<output>128/495 = around 0.258586</output>
<gadget id="calculator">(128/495) * 100</gadget>
<output>2_560/99 = around 25.858586</output>
<result>C</result> | C | 25 | A sum of money deposited at C.I. amounts to Rs.1980 in 3 years and to Rs.2492 in 4 years. Find the rate percent? | {
"A": "30 %",
"B": "10 %",
"C": "25 %",
"D": "19 %",
"E": "50 %"
} | multiply(divide(subtract(2492, 1980), 1980), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "1980 - - - 512 100 - - - ? = > 25 % answer : c" | gain |
math_qa__OY8PM2WkiJymOaOZ | A train 400 m long can cross an electric pole in 40 sec and then find the speed of the train? Choose the correct choice from the following
A) 36 kmph B) 40 kmph C) 42 kmph D) 45 kmph E) 38 kmph | <gadget id="calculator">400 / 1_000</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">40 / 3_600</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">(2/5) / (1/90)</gadget>
<output>36</output>
<result>A</result> | A | 36 | A train 400 m long can cross an electric pole in 40 sec and then find the speed of the train? | {
"A": "36 kmph",
"B": "40 kmph",
"C": "42 kmph",
"D": "45 kmph",
"E": "38 kmph"
} | divide(divide(400, const_1000), divide(40, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 400 / 40 s = 10 m / sec speed = 10 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 36 kmph answer : a" | physics |
math_qa__eNXKP9F9D7X65ZlH | The price of a certain painting increased by 10% during the first year and decreased by 15% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price? Choose one.
A) 102 %
B) 105 %
C) 95 %
D) 93.5 %
E) 90 % | <gadget id="calculator">10 - 15</gadget>
<output>-5</output>
<gadget id="calculator">15 * 10</gadget>
<output>150</output>
<gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(-5) - (3/2)</gadget>
<output>-13/2 = around -6.5</output>
<gadget id="calculator">(-13/2) + 100</gadget>
<output>187/2 = around 93.5</output>
<result>D</result> | D | 93.5 | The price of a certain painting increased by 10% during the first year and decreased by 15% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price? | {
"A": "102 %",
"B": "105 %",
"C": "95 %",
"D": "93.5 %",
"E": "90 %"
} | add(subtract(subtract(10, 15), divide(multiply(15, 10), const_100)), const_100) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,const_100)|subtract(#1,#2)|add(#3,const_100)| | "easiest thing to do : assume that price is 100 price at the end of yr 1 : 100 + 10 = 110 price at the end of year 2 = 110 - 110 * 0.15 = 110 * 0.85 = 93.5 hence required answer = ( 93.5 / 100 ) * 100 % = 93.5 % answer is d ." | general |
math_qa__RdImi4euo3DCTylu | In country Z, 10% of the people do not have a university diploma but have the job of their choice, and 15% of the people who do not have the job of their choice have a university diploma. If 40% of the people have the job of their choice, what percent of the people have a university diploma? Choose the correct choice from the following:
A) 39 % B) 45 % C) 55 % D) 65 % E) 75 % | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">15 * 60</gadget>
<output>900</output>
<gadget id="calculator">900 / 100</gadget>
<output>9</output>
<gadget id="calculator">40 - 10</gadget>
<output>30</output>
<gadget id="calculator">9 + 30</gadget>
<output>39</output>
<result>A</result> | A | 39 | In country Z, 10% of the people do not have a university diploma but have the job of their choice, and 15% of the people who do not have the job of their choice have a university diploma. If 40% of the people have the job of their choice, what percent of the people have a university diploma? | {
"A": "39 %",
"B": "45 %",
"C": "55 %",
"D": "65 %",
"E": "75 %"
} | add(divide(multiply(15, subtract(const_100, 40)), const_100), subtract(40, 10)) | subtract(const_100,n2)|subtract(n2,n0)|multiply(n1,#0)|divide(#2,const_100)|add(#3,#1)| | "setting up a matrix is how i solve this one . diploma no diploma totals job of choice w / diploma job of choice w / o diploma = 10 % job of choice total = 40 % not job of choice with diploma = . 15 x not job of choice w / o diploma = . 85 x total not job of choice = x total with diploma total without diploma total citizen = 100 if 40 % of people have their job of choice , then 60 % of people do not have their job of choice . 15 % of 60 % = 9 % . we can also see that 30 % of the people have their job of choice and a diploma ( 40 % - 10 % = 30 % ) . 30 % + 9 % = 39 % . therefore 39 % of the people in country z have a diploma . ans a" | gain |
math_qa__30clYmmRWQNhGyC9 | The present worth of Rs.676 due in 2 years at 4% per annum compound interest is Answers
A) rs . 150.50
B) rs . 154.75
C) rs . 156.25
D) rs . 625
E) none | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) + 1</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">676 / (676/625)</gadget>
<output>625</output>
<result>D</result> | D | 625 | The present worth of Rs.676 due in 2 years at 4% per annum compound interest is | {
"A": "rs . 150.50",
"B": "rs . 154.75",
"C": "rs . 156.25",
"D": "rs . 625",
"E": "none"
} | divide(676, power(add(divide(4, const_100), const_1), 2)) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|divide(n0,#2) | solution present worth = rs . [ 676 / ( 1 + 4 / 100 ) ² ] = rs . ( 676 x 25 / 26 x 25 / 26 ) = rs . 625 answer d | gain |
math_qa__3UolVf8RhxgfDnzD | Dacid obtained 86, 89, 82, 87 and 81 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
Answers.
A) 79
B) 99
C) 88
D) 85
E) 75 | <gadget id="calculator">86 + 89</gadget>
<output>175</output>
<gadget id="calculator">175 + 82</gadget>
<output>257</output>
<gadget id="calculator">257 + 87</gadget>
<output>344</output>
<gadget id="calculator">344 + 81</gadget>
<output>425</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">425 / 5</gadget>
<output>85</output>
<result>D</result> | D | 85 | Dacid obtained 86, 89, 82, 87 and 81 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? | {
"A": "79",
"B": "99",
"C": "88",
"D": "85",
"E": "75"
} | divide(add(add(add(add(86, 89), 82), 87), 81), divide(const_10, const_2)) | add(n0,n1)|divide(const_10,const_2)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "average = ( 86 + 89 + 82 + 87 + 81 ) / 5 = 425 / 5 = 85 . answer : d" | general |
math_qa__AtXZtZxLgXgjl8Xd | how many different 3 - digit multiples of 5 can be composed of digits 1 , 2 , 3 , 4 , and 5 if none of the digits is repeated ? Select the correct option.
A) 3 B) 6 C) 8 D) 12 E) 18 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<result>C</result> | C | 8 | how many different 3 - digit multiples of 5 can be composed of digits 1 , 2 , 3 , 4 , and 5 if none of the digits is repeated ? | {
"A": "3",
"B": "6",
"C": "8",
"D": "12",
"E": "18"
} | subtract(multiply(4, 3), 4) | multiply(n0,n5)|subtract(#0,n5) | can you explain your method . i solved it differently xyz , where z must be 5 . therefore 1 variation of digit in z . y can be any of the 4 possible choices . x can be any of the 3 possible choices . 4 + 3 + 1 = 8 c | general |
math_qa__kRTMMftENOxqStk6 | A student finds the sum 1 + 2 + 3 + ... as his patience runs out. He found the sum as 575. When the teacher declared the result wrong, the student realized that he missed a number. What was the number the student missed? Choose the correct choice from the following
A) 16 B) 18 C) 14 D) 20 E) 22 | <gadget id="calculator">575 * 2</gadget>
<output>1_150</output>
<gadget id="calculator">1_150 * 4</gadget>
<output>4_600</output>
<gadget id="calculator">4_600 + 1</gadget>
<output>4_601</output>
<gadget id="calculator">4_601 ** (1/2)</gadget>
<output>sqrt(4601) = around 67.830672</output>
<gadget id="calculator">(sqrt(4601)) - 1</gadget>
<output>-1 + sqrt(4601) = around 66.830672</output>
<gadget id="calculator">(-1 + sqrt(4601)) / 2</gadget>
<output>-1/2 + sqrt(4601)/2 = around 33.415336</output>
<gadget id="calculator">floor(-1/2 + sqrt(4601)/2)</gadget>
<output>33</output>
<gadget id="calculator">33 + 1</gadget>
<output>34</output>
<gadget id="calculator">34 + 1</gadget>
<output>35</output>
<gadget id="calculator">34 * 35</gadget>
<output>1_190</output>
<gadget id="calculator">1_190 / 2</gadget>
<output>595</output>
<gadget id="calculator">595 - 575</gadget>
<output>20</output>
<result>D</result> | D | 20 | A student finds the sum 1 + 2 + 3 + ... as his patience runs out. He found the sum as 575. When the teacher declared the result wrong, the student realized that he missed a number. What was the number the student missed? | {
"A": "16",
"B": "18",
"C": "14",
"D": "20",
"E": "22"
} | subtract(divide(multiply(add(floor(divide(subtract(sqrt(add(multiply(multiply(575, 2), const_4), 1)), 1), const_2)), 1), add(add(floor(divide(subtract(sqrt(add(multiply(multiply(575, 2), const_4), 1)), 1), const_2)), 1), 1)), 2), 575) | multiply(n1,n3)|multiply(#0,const_4)|add(n0,#1)|sqrt(#2)|subtract(#3,n0)|divide(#4,const_2)|floor(#5)|add(n0,#6)|add(n0,#7)|multiply(#7,#8)|divide(#9,n1)|subtract(#10,n3) | explanation : sum of 1 st 10 natural numbers ( 1 – 10 ) = 1 + 2 + … 10 = 55 . sum of next 10 natural numbers ( 11 – 20 ) = 10 + 11 + 12 + … 20 = 100 + 55 = 155 . sum of next 10 natural numbers ( 31 – 40 ) = 255 . sum of numbers from 31 – 40 = 355 and so on and on . so , we have here 55 + 155 + 255 = 465 . if we add 355 to 465 , it will be way more than 575 . so , we can add one by one . 465 + 31 + 32 + 33 = 561 . 465 + 31 + 32 + 33 + 34 = 595 . thus , the sum should be 595 instead of 575 , and the missing number is 20 . answer : d | general |
math_qa__UGuRszvf5Nnyomh3 | Dhoni spends $300 buying his favorite dolls. If he buys only small Monkey dolls, which are $2 cheaper than the large Monkey dolls, he could buy 25 more dolls than if he were to buy only large Monkey dolls. How much does a large Monkey doll cost?
Choose the correct choice from the following choices
A) $ 6.5 B) $ 6 C) $ 7 D) $ 8 E) $ 9 | <gadget id="calculator">300 / 25</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>B</result> | B | 6 | Dhoni spends $300 buying his favorite dolls. If he buys only small Monkey dolls, which are $2 cheaper than the large Monkey dolls, he could buy 25 more dolls than if he were to buy only large Monkey dolls. How much does a large Monkey doll cost? | {
"A": "$ 6.5",
"B": "$ 6",
"C": "$ 7",
"D": "$ 8",
"E": "$ 9"
} | divide(divide(300, 25), 2) | divide(n0,n2)|divide(#0,n1) | a is not an integer . so we start with b . if large doll costs $ 6 , then he can buy 300 / 6 = 50 large dolls and 300 / 4 = 75 small dolls . difference is 25 , which is we wanted . answer b . | general |
math_qa__7BE3wclMM6jynHb7 | Find the principle on a certain sum of money at 8% per annum for 2 2/5 years if the amount being Rs.1120?
Choose the correct choice from the following answers
A) 939.6 B) 928.8 C) 927.78 D) 926.82 E) 902.1 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 8</gadget>
<output>96/5 = around 19.2</output>
<gadget id="calculator">(96/5) / 100</gadget>
<output>24/125 = around 0.192</output>
<gadget id="calculator">(24/125) + 1</gadget>
<output>149/125 = around 1.192</output>
<gadget id="calculator">1_120 / (149/125)</gadget>
<output>140_000/149 = around 939.597315</output>
<result>A</result> | A | 939.6 | Find the principle on a certain sum of money at 8% per annum for 2 2/5 years if the amount being Rs.1120? | {
"A": "939.6",
"B": "928.8",
"C": "927.78",
"D": "926.82",
"E": "902.1"
} | divide(1120, add(divide(multiply(divide(add(multiply(2, 5), 2), 5), 8), const_100), const_1)) | multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)| | "1120 = p [ 1 + ( 8 * 12 / 5 ) / 100 ] p = 939.60 answer : a" | general |
math_qa__JDxUwbrDVThoKJ6Z | A shopkeeper sold an article offering a discount of 5% and earned a profit of 21.6%. What would have been the percentage of profit earned if no discount was offered?
Choose the correct answer
A) 60 % B) 28 % C) 30 % D) 56 % E) 73 % | <gadget id="calculator">100 + 21.6</gadget>
<output>121.6</output>
<gadget id="calculator">121.6 * 100</gadget>
<output>12_160</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">12_160 / 95</gadget>
<output>128</output>
<gadget id="calculator">128 - 100</gadget>
<output>28</output>
<result>B</result> | B | 28 | A shopkeeper sold an article offering a discount of 5% and earned a profit of 21.6%. What would have been the percentage of profit earned if no discount was offered? | {
"A": "60 %",
"B": "28 %",
"C": "30 %",
"D": "56 %",
"E": "73 %"
} | subtract(divide(multiply(add(const_100, 21.6), const_100), subtract(const_100, 5)), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,const_100)|divide(#2,#1)|subtract(#3,const_100)| | "let c . p . be rs . 100 . then , s . p . = rs . 121.60 let marked price be rs . x . then , 95 / 100 x = 121.60 x = 12160 / 95 = rs . 128 now , s . p . = rs . 128 , c . p . = rs . 100 profit % = 28 % . answer : b" | gain |
math_qa__g23FmImFk07KPf6N | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 10 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is :
Choose the correct choice:
A) 22 B) 21 C) 88 D) 30 E) 29 | <gadget id="calculator">12_000 - 8_000</gadget>
<output>4_000</output>
<gadget id="calculator">10 * 4_000</gadget>
<output>40_000</output>
<gadget id="calculator">8_000 - 6_000</gadget>
<output>2_000</output>
<gadget id="calculator">40_000 / 2_000</gadget>
<output>20</output>
<gadget id="calculator">10 + 20</gadget>
<output>30</output>
<result>D</result> | D | 30 | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 10 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is : | {
"A": "22",
"B": "21",
"C": "88",
"D": "30",
"E": "29"
} | add(10, divide(multiply(10, subtract(12000, 8000)), subtract(8000, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3)| | "explanation : lot the total number of workers be v then , 8 ooov = ( 12000 * 10 ) + 6000 ( v - 10 ) < = > 2000 v = 60000 < = > v = 30 answer : d ) 30" | general |
math_qa__KVBvrc0QINNqGt2w | In a kilometer race, A beats B by 100 meters or 10 seconds. What time does A take to complete the race? Select:
A) 90 sec B) 190 sec C) 290 sec D) 490 sec E) 390 sec | <gadget id="calculator">1 * 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">1_000 / 10</gadget>
<output>100</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<result>A</result> | A | 90 | In a kilometer race, A beats B by 100 meters or 10 seconds. What time does A take to complete the race? | {
"A": "90 sec",
"B": "190 sec",
"C": "290 sec",
"D": "490 sec",
"E": "390 sec"
} | subtract(divide(multiply(const_1, const_1000), divide(100, 10)), 10) | divide(n0,n1)|multiply(const_1,const_1000)|divide(#1,#0)|subtract(#2,n1)| | "time taken by b run 1000 meters = ( 1000 * 10 ) / 100 = 100 sec . time taken by a = 100 - 10 = 90 sec . answer : a" | physics |
math_qa__qHfxWuGDEGofEHDz | A space shuttle orbits the earth at about 4 kilometers per second. This speed is equal to how many kilometers per hour?
Choose the correct choice from the following options.
A) 480 B) 14,400 C) 24,200 D) 28,800 E) 48,000 | <gadget id="calculator">4 * 3_600</gadget>
<output>14_400</output>
<result>B</result> | B | 14,400 | A space shuttle orbits the earth at about 4 kilometers per second. This speed is equal to how many kilometers per hour? | {
"A": "480",
"B": "14,400",
"C": "24,200",
"D": "28,800",
"E": "48,000"
} | multiply(4, const_3600) | multiply(n0,const_3600)| | "seconds in 1 hours : 60 s in 1 min 60 min in 1 hr 60 * 60 = 3600 sec in 1 hr 4 * 3600 = 14,400 answer : b" | physics |
math_qa__7IBIGvVcSd1F8xSC | what is the remainder when 14452 × 15652 × 16781 is divided by 5 ?
Choose the correct answer
A) 0
B) 1
C) 2
D) 3
E) 4 | <gadget id="calculator">14_452 * 15_652</gadget>
<output>226_202_704</output>
<gadget id="calculator">226_202_704 * 16_781</gadget>
<output>3_795_907_575_824</output>
<gadget id="calculator">3_795_907_575_824 % 5</gadget>
<output>4</output>
<result>E</result> | E | 4 | what is the remainder when 14452 × 15652 × 16781 is divided by 5 ? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | reminder(multiply(multiply(14452, 15652), 16781), 5) | multiply(n0,n1)|multiply(n2,#0)|reminder(#1,n3) | only the unit ' s digit of the product will decide the remainder when divided by 5 . hence , 2 * 2 * 1 = will give units digit as 4 so , whatever be the number , if it ends in 4 , the remainder after dividing with 5 will be 4 . optione | general |
math_qa__5B6bxcnAfR0CKZx4 | There are 2 friends Peter and Paul. Peter age is twice as old as Paul when peter was as old as Paul is now. Sum of the present ages of Peter and Paul is 35.What is the present age of Peter? Options
A) 10 B) 15 C) 20 D) 25 E) 30 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">35 / 7</gadget>
<output>5</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<result>C</result> | C | 20 | There are 2 friends Peter and Paul. Peter age is twice as old as Paul when peter was as old as Paul is now. Sum of the present ages of Peter and Paul is 35.What is the present age of Peter? | {
"A": "10",
"B": "15",
"C": "20",
"D": "25",
"E": "30"
} | multiply(divide(35, add(const_4, const_3)), const_4) | add(const_3,const_4)|divide(n1,#0)|multiply(#1,const_4) | let pauls age be ' a ' and peters be ' e ' e + a = 35 ( given ) e = 35 - a - - - - - - eq 1 when peter was as old as paul that is when peter ' s age was ' a ' pauls age was a - ( e - a ) = 2 a - e now peters age is e = 2 ( 2 a - e ) e = 4 a - 2 e 3 e = 4 a 3 ( 35 - a ) = 4 a 105 - 3 a = 4 a a = 15 hence e = 20 answer : c | general |
math_qa__aBxnfZiTV0TkIieV | The area of a parallelogram is 162sq m and its altitude is twice the corresponding base. Then the length of the base is? Choose the correct answer
A) 8
B) 9
C) 7
D) 62
E) 2 | <gadget id="calculator">162 / 2</gadget>
<output>81</output>
<gadget id="calculator">81 ** (1/2)</gadget>
<output>9</output>
<result>B</result> | B | 9 | The area of a parallelogram is 162sq m and its altitude is twice the corresponding base. Then the length of the base is? | {
"A": "8",
"B": "9",
"C": "7",
"D": "62",
"E": "2"
} | sqrt(divide(162, const_2)) | divide(n0,const_2)|sqrt(#0)| | "2 x * x = 162 = > x = 9 answer : b" | geometry |
math_qa__zkLYpKLO1aCdaGrX | 8% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning? Select
A) 2988 B) 4543 C) 4400 D) 2871 E) 881 | <gadget id="calculator">100 - 8</gadget>
<output>92</output>
<gadget id="calculator">92 / 100</gadget>
<output>23/25 = around 0.92</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(23/25) * (17/20)</gadget>
<output>391/500 = around 0.782</output>
<gadget id="calculator">3_553 / (391/500)</gadget>
<output>104_500/23 = around 4_543.478261</output>
<gadget id="calculator">floor(104_500/23)</gadget>
<output>4_543</output>
<result>B</result> | B | 4,543 | 8% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning? | {
"A": "2988",
"B": "4543",
"C": "4400",
"D": "2871",
"E": "881"
} | floor(divide(3553, multiply(divide(subtract(const_100, 8), const_100), divide(subtract(const_100, 15), const_100)))) | subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|divide(n2,#4)|floor(#5)| | "x * ( 92 / 100 ) * ( 85 / 100 ) = 3553 x = 4543 answer : b" | general |
math_qa__pUbOm4ESY0i4coIz | 57 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work? Select the correct option:
A) 10 B) 13 C) 14 D) 15 E) 19 | <gadget id="calculator">57 * 12</gadget>
<output>684</output>
<gadget id="calculator">684 * 5</gadget>
<output>3_420</output>
<gadget id="calculator">30 * 6</gadget>
<output>180</output>
<gadget id="calculator">3_420 / 180</gadget>
<output>19</output>
<result>E</result> | E | 19 | 57 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work? | {
"A": "10",
"B": "13",
"C": "14",
"D": "15",
"E": "19"
} | divide(multiply(multiply(57, 12), 5), multiply(30, 6)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|divide(#2,#1)| | "according to the chain rule , m 1 x t 1 = m 2 x t 2 therefore , 57 x 12 x 5 = 30 x 6 x x x = 19 hence , the number of days = 19 . answer : e" | physics |
math_qa__w3QTv4ZI4xZvCMfI | How many plants will be there in a circular bed whose outer edge measure 30 cms, allowing 4 cm2 for each plant ? Choose the correct choice from the following options.
A) 18 B) 750 C) 24 D) 120 E) none of these | <gadget id="calculator">2 * pi</gadget>
<output>2*pi = around 6.283185</output>
<gadget id="calculator">30 / (2*pi)</gadget>
<output>15/pi = around 4.774648</output>
<gadget id="calculator">pi * ((15/pi) ** 2)</gadget>
<output>225/pi = around 71.619724</output>
<gadget id="calculator">(225/pi) / 4</gadget>
<output>225/(4*pi) = around 17.904931</output>
<result>A</result> | A | 18 | How many plants will be there in a circular bed whose outer edge measure 30 cms, allowing 4 cm2 for each plant ? | {
"A": "18",
"B": "750",
"C": "24",
"D": "120",
"E": "none of these"
} | divide(circle_area(divide(30, multiply(2, const_pi))), 4) | multiply(n2,const_pi)|divide(n0,#0)|circle_area(#1)|divide(#2,n1)| | "circumference of circular bed = 30 cm area of circular bed = ( 30 ) 2 ⁄ 4 π space for each plant = 4 cm 2 ∴ required number of plants = ( 30 ) 2 ⁄ 4 π ÷ 4 = 17.89 = 18 ( approx ) answer a" | physics |
math_qa__uPyE2W3j7pwYyRGX | A boat goes 100 km downstream in 10 hours, and 60 m upstream in 15 hours. The speed of the stream is? Choose the correct choice from the following answers: A) 3 B) 22 1 / 4 C) 22 1 / 2 D) 22 1 / 1 E) 22 1 / 3 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">60 / 15</gadget>
<output>4</output>
<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>A</result> | A | 3 | A boat goes 100 km downstream in 10 hours, and 60 m upstream in 15 hours. The speed of the stream is? | {
"A": "3",
"B": "22 1 / 4",
"C": "22 1 / 2",
"D": "22 1 / 1",
"E": "22 1 / 3"
} | divide(subtract(divide(100, 10), divide(60, 15)), const_2) | divide(n0,n1)|divide(n2,n3)|subtract(#0,#1)|divide(#2,const_2)| | "100 - - - 10 ds = 10 ? - - - - 1 60 - - - - 15 us = 4 ? - - - - - 1 s = ( 10 - 4 ) / 2 = 3 kmp answer : a" | physics |
math_qa__5SabnpHMUwCdGDMt | How many different values of positive integer x, for which |x+4|<x, are there?
Select the correct option.
A) 0 B) 2 C) 3 D) 8 E) 16 | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<result>D</result> | D | 8 | How many different values of positive integer x, for which |x+4|<x, are there? | {
"A": "0",
"B": "2",
"C": "3",
"D": "8",
"E": "16"
} | add(4, const_4) | add(n0,const_4) | answer d i opted to put the random value option . i used 0 , 4 , - 4 and the the extreme of 60 and - 60 . . i was able to solve it in 1 : 09 d | general |
math_qa__qoJopZVGKgyay8PO | At a certain resort, each of the 39 food service employees is trained to work in a minimum of 1 restaurant and a maximum of 3 restaurants. The 3 restaurants are the family buffet, the dining room, and the snack bar. Exactly 15 employees are trained to work in the family buffet, 18 are trained to work in the dining room, and 12 are trained to work in the snack bar. If 4 employees are trained to work in exactly 2 restaurants, how many employees are trained to work in all 3 restaurants? Answers
A) 2 B) 3 C) 4 D) 5 E) 1 | <gadget id="calculator">15 + 18</gadget>
<output>33</output>
<gadget id="calculator">33 + 12</gadget>
<output>45</output>
<gadget id="calculator">45 - 4</gadget>
<output>41</output>
<gadget id="calculator">41 - 39</gadget>
<output>2</output>
<gadget id="calculator">2 / 2</gadget>
<output>1</output>
<result>E</result> | E | 1 | At a certain resort, each of the 39 food service employees is trained to work in a minimum of 1 restaurant and a maximum of 3 restaurants. The 3 restaurants are the family buffet, the dining room, and the snack bar. Exactly 15 employees are trained to work in the family buffet, 18 are trained to work in the dining room, and 12 are trained to work in the snack bar. If 4 employees are trained to work in exactly 2 restaurants, how many employees are trained to work in all 3 restaurants? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "1"
} | divide(subtract(subtract(add(add(15, 18), 12), 4), 39), 2) | add(n4,n5)|add(n6,#0)|subtract(#1,n7)|subtract(#2,n0)|divide(#3,n8)| | "39 = 15 + 18 + 12 - 4 - 2 x 2 x = 15 + 18 + 12 - 4 - 39 = 41 - 39 = 2 x = 1 e" | physics |
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