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stringlengths 7
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math_qa__mjHsyvrXLXab6v5P | 12 times a positive integer is more than its square by 36, then the positive integer is Choose the correct choice from the following:
A) 6
B) 10
C) 11
D) 12
E) 14 | <gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">36 * 4</gadget>
<output>144</output>
<gadget id="calculator">144 - 144</gadget>
<output>0</output>
<gadget id="calculator">12 + 0</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>A</result> | A | 6 | 12 times a positive integer is more than its square by 36, then the positive integer is | {
"A": "6",
"B": "10",
"C": "11",
"D": "12",
"E": "14"
} | divide(add(12, subtract(power(12, const_2), multiply(36, const_4))), const_2) | multiply(n1,const_4)|power(n0,const_2)|subtract(#1,#0)|add(n0,#2)|divide(#3,const_2)| | "explanation : let the number be x . then , 12 x = x 2 + 36 = > x 2 - 12 x + 36 = 0 = > ( x - 6 ) ( x - 6 ) = 0 = > x = 6 answer : a" | general |
math_qa__rGROKBVWj7tMy9e9 | Renu can do a piece of work in 8 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone? Choose one.
A) 8
B) 12
C) 14
D) 15
E) 17 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/4) - (1/8)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<result>A</result> | A | 8 | Renu can do a piece of work in 8 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone? | {
"A": "8",
"B": "12",
"C": "14",
"D": "15",
"E": "17"
} | inverse(subtract(divide(const_1, 4), divide(const_1, 8))) | divide(const_1,n1)|divide(const_1,n0)|subtract(#0,#1)|inverse(#2)| | "renu â € ™ s one day â € ™ s work = 1 / 8 suma â € ™ s one day â € ™ s work = 1 / 4 - 1 / 8 = 1 / 8 suma can do it alone in 8 days . answer : a" | physics |
math_qa__mDTsVzYYLYjBZxVq | 90 percent of the members of a study group are women, and 60 percent of those women are lawyers. If one member of the study group is to be selected at random, what is the probability that the member selected is a woman lawyer?
Choose the correct choice from the following answers: A) 0.34 B) 0.44 C) 0.54 D) 0.64 E) 0.74 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 4</gadget>
<output>100</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(9/10) * (3/5)</gadget>
<output>27/50 = around 0.54</output>
<result>C</result> | C | 0.54 | 90 percent of the members of a study group are women, and 60 percent of those women are lawyers. If one member of the study group is to be selected at random, what is the probability that the member selected is a woman lawyer? | {
"A": "0.34",
"B": "0.44",
"C": "0.54",
"D": "0.64",
"E": "0.74"
} | multiply(divide(90, multiply(multiply(const_5, const_5), const_4)), divide(60, multiply(multiply(const_5, const_5), const_4))) | multiply(const_5,const_5)|multiply(#0,const_4)|divide(n0,#1)|divide(n1,#1)|multiply(#2,#3)| | "say there are 100 people in that group , then there would be 0.9 * 0.60 * 100 = 54 women lawyers , which means that the probability that the member selected is a woman lawyer is favorable / total = 54 / 100 . answer : c" | gain |
math_qa__RRfkljmbFm8T7dfw | X and Y started a business by investing Rs.5000/- and Rs.15000/- respectively. Find the X’s share out of a total profit of Rs.1600:
Choose the correct choice from the following answers
A) 200 B) 250 C) 300 D) 350 E) 400 | <gadget id="calculator">5_000 + 15_000</gadget>
<output>20_000</output>
<gadget id="calculator">1_600 / 20_000</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">5_000 * (2/25)</gadget>
<output>400</output>
<result>E</result> | E | 400 | X and Y started a business by investing Rs.5000/- and Rs.15000/- respectively. Find the X’s share out of a total profit of Rs.1600: | {
"A": "200",
"B": "250",
"C": "300",
"D": "350",
"E": "400"
} | multiply(5000, divide(1600, add(5000, 15000))) | add(n0,n1)|divide(n2,#0)|multiply(n0,#1) | x = rs . 5000 / - y = rs . 15000 / - x share 1 part & y share 3 parts total 4 parts - - - - - > rs . 1600 / - - - - - > 1 part - - - - - - - > rs . 400 / - x share = 1 part - - - - - > rs . 400 / - e | general |
math_qa__sY9cfLVZhAIcAdUc | 5 men are equal to as many women as are equal to 7 boys. All of them earn Rs.90 only. Men’s wages are? Choose the correct choice from the following answers
A) 8 rs .
B) 7 rs .
C) 6 rs .
D) 4 rs .
E) 5 rs . | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">90 / 15</gadget>
<output>6</output>
<result>C</result> | C | 6 | 5 men are equal to as many women as are equal to 7 boys. All of them earn Rs.90 only. Men’s wages are? | {
"A": "8 rs .",
"B": "7 rs .",
"C": "6 rs .",
"D": "4 rs .",
"E": "5 rs ."
} | divide(90, multiply(const_3, 5)) | multiply(n0,const_3)|divide(n2,#0) | 5 m = xw = 7 b 5 m + xw + 7 b - - - - - 90 rs . 5 m + 5 m + 5 m - - - - - 90 rs . 15 m - - - - - - 90 rs . = > 1 m = 6 rs . answer : c | general |
math_qa__qySY2D4PzcHqRbzk | The area of a triangle is with base 8.4m and height 5.8m?
Choose the correct choice from the following answers:
A) 11.36 m 2 B) 10.36 m 2 C) 18.36 m 2 D) 19.36 m 2 E) 24.36 m 2 | <gadget id="calculator">(8.4 * 5.8) / 2</gadget>
<output>24.36</output>
<result>E</result> | E | 24.36 | The area of a triangle is with base 8.4m and height 5.8m? | {
"A": "11.36 m 2",
"B": "10.36 m 2",
"C": "18.36 m 2",
"D": "19.36 m 2",
"E": "24.36 m 2"
} | triangle_area(8.4, 5.8) | triangle_area(n0,n1)| | "1 / 2 * 8.4 * 5.8 = 24.36 m 2 answer : e" | geometry |
math_qa__c9rwOUzYvOgdv7Za | If P(A) = 8/15, P(B) = 4/15, and P(A ∪ B) = 16/15 Find P(B|A) Options
A) 1 / 2 B) 2 / 3 C) 3 / 2 D) 2 E) 4 / 7 | <gadget id="calculator">16 / 15</gadget>
<output>16/15 = around 1.066667</output>
<gadget id="calculator">8 / 15</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">(16/15) / (8/15)</gadget>
<output>2</output>
<result>D</result> | D | 2 | If P(A) = 8/15, P(B) = 4/15, and P(A ∪ B) = 16/15 Find P(B|A) | {
"A": "1 / 2",
"B": "2 / 3",
"C": "3 / 2",
"D": "2",
"E": "4 / 7"
} | divide(divide(16, 15), divide(8, 15)) | divide(n4,n1)|divide(n0,n1)|divide(#0,#1)| | "p ( b | a ) = p ( a â ˆ ª b ) / p ( a ) p ( b | a ) = ( 16 / 15 ) / ( 8 / 15 ) = 2 . d" | general |
math_qa__d0FTDBQWM996vrN9 | The speed of a car is 90 km in the first hour and 42 km in the second hour. What is the average speed of the car? Choose the most appropriate option:
A) 89 kmph B) 92 kmph C) 75 kmph D) 65 kmph E) 66 kmph | <gadget id="calculator">90 + 42</gadget>
<output>132</output>
<gadget id="calculator">132 / 2</gadget>
<output>66</output>
<result>E</result> | E | 66 | The speed of a car is 90 km in the first hour and 42 km in the second hour. What is the average speed of the car? | {
"A": "89 kmph",
"B": "92 kmph",
"C": "75 kmph",
"D": "65 kmph",
"E": "66 kmph"
} | divide(add(90, 42), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 90 + 42 ) / 2 = 66 kmph e" | physics |
math_qa__EWlbhUcMhLqOWNCi | If w is 40 percent less than x, x is 40 percent less than y, and z is 46 percent less than y, then z is greater than w by what percent of w? Choose the correct option:
A) 4 % B) 18 % C) 36 % D) 40 % E) 50 % | <gadget id="calculator">46 / 100</gadget>
<output>23/50 = around 0.46</output>
<gadget id="calculator">1 - (23/50)</gadget>
<output>27/50 = around 0.54</output>
<gadget id="calculator">(27/50) * 100</gadget>
<output>54</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 60</gadget>
<output>24</output>
<gadget id="calculator">60 - 24</gadget>
<output>36</output>
<gadget id="calculator">54 - 36</gadget>
<output>18</output>
<gadget id="calculator">18 / 36</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>E</result> | E | 50 | If w is 40 percent less than x, x is 40 percent less than y, and z is 46 percent less than y, then z is greater than w by what percent of w? | {
"A": "4 %",
"B": "18 %",
"C": "36 %",
"D": "40 %",
"E": "50 %"
} | multiply(divide(subtract(multiply(subtract(const_1, divide(46, const_100)), const_100), subtract(subtract(const_100, 40), multiply(divide(40, const_100), subtract(const_100, 40)))), subtract(subtract(const_100, 40), multiply(divide(40, const_100), subtract(const_100, 40)))), const_100) | divide(n2,const_100)|divide(n0,const_100)|subtract(const_100,n0)|multiply(#1,#2)|subtract(const_1,#0)|multiply(#4,const_100)|subtract(#2,#3)|subtract(#5,#6)|divide(#7,#6)|multiply(#8,const_100) | given w = 0.6 x , x = 0.6 y , z = 0.54 y , substituting , w = 2 / 3 z - - - - > z = 1.5 w and thus z is 50 % greater than w . e is the correct answer . | general |
math_qa__DjB67N4GORtPoEGe | The amount of principal Rs.8000 at compound interest at the ratio of 5% p.a. for 5 years is Pick one.
A) s . 9621
B) s . 6921
C) s . 10210
D) s . 6261
E) s . 6361 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 5</gadget>
<output>4_084_101/3_200_000 = around 1.276282</output>
<gadget id="calculator">8_000 * (4_084_101/3_200_000)</gadget>
<output>4_084_101/400 = around 10_210.2525</output>
<result>C</result> | C | 10,210 | The amount of principal Rs.8000 at compound interest at the ratio of 5% p.a. for 5 years is | {
"A": "s . 9621",
"B": "s . 6921",
"C": "s . 10210",
"D": "s . 6261",
"E": "s . 6361"
} | multiply(8000, power(add(const_1, divide(5, const_100)), 5)) | divide(n1,const_100)|add(#0,const_1)|power(#1,n2)|multiply(n0,#2)| | "c . i = p ( 1 + r / 100 ) ^ n = 8000 ( 1 + 5 / 100 ) ^ 5 = rs 10210 answer : c" | gain |
math_qa__gV3JYZri6GeXMD69 | Pencils, Pens and Exercise books in a shop are in the ratio of 14: 4 : 3. If there are 140 pencils, the number of exercise books in the shop is: Choices:
A) 30 B) 27 C) 35 D) 33 E) 37 | <gadget id="calculator">140 / 14</gadget>
<output>10</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<result>A</result> | A | 30 | Pencils, Pens and Exercise books in a shop are in the ratio of 14: 4 : 3. If there are 140 pencils, the number of exercise books in the shop is: | {
"A": "30",
"B": "27",
"C": "35",
"D": "33",
"E": "37"
} | multiply(divide(140, 14), 3) | divide(n3,n0)|multiply(n2,#0) | explanation : let pencils = 14 x , pens = 4 x & exercise books = 3 x . now , 14 x = 140 hence x = 10 number of exercise books = 3 x = 30 answer : a | other |
math_qa__32UG1U0kRTwoXhpI | A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 16 seconds. What is the length of the platform in meters?
Choose the correct answer:
A) 240 meters
B) 360 meters
C) 280 meters
D) 600 meters
E) can not be determined | <gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">20 * 30</gadget>
<output>600</output>
<gadget id="calculator">20 * 16</gadget>
<output>320</output>
<gadget id="calculator">600 - 320</gadget>
<output>280</output>
<result>C</result> | C | 280 | A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 16 seconds. What is the length of the platform in meters? | {
"A": "240 meters",
"B": "360 meters",
"C": "280 meters",
"D": "600 meters",
"E": "can not be determined"
} | subtract(multiply(divide(multiply(72, const_1000), const_3600), 30), multiply(divide(multiply(72, const_1000), const_3600), 16)) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)|multiply(n2,#1)|subtract(#2,#3)| | "speed of the train in metres / sec = 72000 / 3600 = 20 distance travelled by train to cross the platform = 30 * 20 = 600 = length of train + length of platform distance travelled by train to cross the man = 16 * 20 = 320 = length of train length of platform = 600 - 320 = 280 answer : c" | physics |
math_qa__3rHPCd8tIsPuXULm | The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/2 of the area of the field. What is the length of the field? Pick:
A) 13 B) 16 C) 34 D) 43 E) 42 | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">64 * 2</gadget>
<output>128</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">128 / (1/2)</gadget>
<output>256</output>
<gadget id="calculator">256 ** (1/2)</gadget>
<output>16</output>
<result>B</result> | B | 16 | The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/2 of the area of the field. What is the length of the field? | {
"A": "13",
"B": "16",
"C": "34",
"D": "43",
"E": "42"
} | sqrt(divide(multiply(square_area(8), 2), inverse(const_2))) | inverse(const_2)|square_area(n0)|multiply(n2,#1)|divide(#2,#0)|sqrt(#3)| | "explanation : a / 2 = 8 * 8 = > a = 8 * 8 * 2 x * 2 x = 8 * 8 * 2 x = 8 = > 2 x = 16 answer : option b" | geometry |
math_qa__ttpPrcqqtuzsaqOh | In one hour, a boat goes 11 km along the stream and 5 km against the stream. the sped of the boat in still water (in km/hr) is :
Choose the correct option:
A) 3 B) 5 C) 8 D) 9 E) 10 | <gadget id="calculator">11 + 5</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>C</result> | C | 8 | In one hour, a boat goes 11 km along the stream and 5 km against the stream. the sped of the boat in still water (in km/hr) is : | {
"A": "3",
"B": "5",
"C": "8",
"D": "9",
"E": "10"
} | divide(add(11, 5), const_2) | add(n0,n1)|divide(#0,const_2)| | "solution speed in still water = 1 / 2 ( 11 + 5 ) km / hr = 8 kmph . answer c" | gain |
math_qa__b4Xflg3KSGei2Yts | Arnold and Danny are two twin brothers that are celebrating their birthday. The product of their ages today is smaller by 5 from the product of their ages a year from today. What is their age today? Choose the correct choice from the following
A) 2 . B) 4 . C) 5 . D) 7 . E) 9 . | <gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>A</result> | A | 2 | Arnold and Danny are two twin brothers that are celebrating their birthday. The product of their ages today is smaller by 5 from the product of their ages a year from today. What is their age today? | {
"A": "2 .",
"B": "4 .",
"C": "5 .",
"D": "7 .",
"E": "9 ."
} | divide(subtract(5, const_1), const_2) | subtract(n0,const_1)|divide(#0,const_2)| | "ad = ( a + 1 ) ( d + 1 ) - 5 0 = a + d - 4 a + d = 4 a = d ( as they are twin brothers ) a = d = 2 a is the answer" | general |
math_qa__zL0SxKuXYia1FKmg | A and B go around a circular track of length 900m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point? Choose the correct choice from the following: A) 120 sec B) 165 sec C) 186 sec D) 180 sec E) 168 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">900 / 5</gadget>
<output>180</output>
<result>D</result> | D | 180 | A and B go around a circular track of length 900m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point? | {
"A": "120 sec",
"B": "165 sec",
"C": "186 sec",
"D": "180 sec",
"E": "168 sec"
} | divide(900, subtract(multiply(54, const_0_2778), multiply(36, const_0_2778))) | multiply(n2,const_0_2778)|multiply(n1,const_0_2778)|subtract(#0,#1)|divide(n0,#2)| | "time taken to meet for the first time at the starting point = lcm { length of the track / speed of a , length of the track / speed of b } = lcm { 900 / ( 36 * 5 / 18 ) , 900 / ( 54 * 5 / 18 ) } = lcm ( 90 , 60 ) = 180 sec . answer : d" | physics |
math_qa__N8Y86y3ByA2ODGEq | Working together, Jose and Jane can complete an assigned task in 12 days. However, if Jose worked alone and complete half the work and then Jane takes over the task and completes the second half of the task, the task will be completed in 48 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose Choose the correct choice from the following answers
A) 25 days B) 30 days C) 60 days D) 65 days E) 36 days | <gadget id="calculator">3 * 12</gadget>
<output>36</output>
<result>E</result> | E | 36 | Working together, Jose and Jane can complete an assigned task in 12 days. However, if Jose worked alone and complete half the work and then Jane takes over the task and completes the second half of the task, the task will be completed in 48 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose | {
"A": "25 days",
"B": "30 days",
"C": "60 days",
"D": "65 days",
"E": "36 days"
} | multiply(const_3, 12) | multiply(n0,const_3) | assume : jose does 1 job in x days , so jose does 1 / x job in a day jane does 1 job in y days , so jane does 1 / y job in a day together , they does ( x + y ) / xy job in a day . this is equals to 1 / 20 . so ( x + y ) / xy = 1 / 12 12 ( x + y ) = xy next , we ' re told 1 job takes 48 days to complete if jose and jane each does half the work . so since jose does 1 job in x days , he wil need x / 2 days to do half the job . jane similarly will need y / 2 days to do the other half . x / 2 + y / 2 = 48 x + y = 96 so xy = 1152 the answer choices are : 25 days 30 days 60 days 65 days 36 days from the answer choices , so i ' ll go for 36 days for jose and 32 days for jane . answer : e | physics |
math_qa__8pEfS4kACevmFyPA | One fourth of one third of two fifth of a number is 15. What will be the 40% of that number is? Choose the correct answer:
A) 120 B) 130 C) 150 D) 180 E) 250 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/4) * (1/3)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/12) * (2/5)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">15 / (1/30)</gadget>
<output>450</output>
<gadget id="calculator">450 * 40</gadget>
<output>18_000</output>
<gadget id="calculator">18_000 / 100</gadget>
<output>180</output>
<result>D</result> | D | 180 | One fourth of one third of two fifth of a number is 15. What will be the 40% of that number is? | {
"A": "120",
"B": "130",
"C": "150",
"D": "180",
"E": "250"
} | divide(multiply(divide(15, multiply(multiply(divide(const_1, const_4), divide(const_1, const_3)), divide(const_2, add(const_2, const_3)))), 40), const_100) | add(const_2,const_3)|divide(const_1,const_4)|divide(const_1,const_3)|divide(const_2,#0)|multiply(#1,#2)|multiply(#3,#4)|divide(n0,#5)|multiply(n1,#6)|divide(#7,const_100)| | "( 1 / 4 ) * ( 1 / 3 ) * ( 2 / 5 ) * x = 15 then x = 15 * 30 = 450 40 % of 450 = 180 answer d" | gain |
math_qa__FcVwNXjMiuR0ULH6 | The ages of Ashley and Mary are in the ratio 4:7. The sum of their ages is 22. Find the ages of Ashley . Choose the correct choice from the following options: A) 7 B) 8 C) 9 D) 10 E) 11 | <gadget id="calculator">4 + 7</gadget>
<output>11</output>
<gadget id="calculator">22 / 11</gadget>
<output>2</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<result>B</result> | B | 8 | The ages of Ashley and Mary are in the ratio 4:7. The sum of their ages is 22. Find the ages of Ashley . | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | multiply(divide(22, add(4, 7)), 4) | add(n0,n1)|divide(n2,#0)|multiply(n0,#1) | a : m = 4 : 7 let the ages of a & m be x & 22 - x x / 22 - x = 4 / 7 x = 8 a = 8 yrs answer : b | general |
math_qa__eFmJ5s5nGg6tVSLe | Two cyclist start on a circular track from a given point but in opposite direction with speeds of 7m/s and 8m/s. If the circumference of the circle is 180meters, after what time will they meet at the starting point? Choose the correct choice from the following answers:
A) 20 sec B) 12 sec C) 30 sec D) 50 sec E) 1 min | <gadget id="calculator">8 + 7</gadget>
<output>15</output>
<gadget id="calculator">180 / 15</gadget>
<output>12</output>
<result>B</result> | B | 12 | Two cyclist start on a circular track from a given point but in opposite direction with speeds of 7m/s and 8m/s. If the circumference of the circle is 180meters, after what time will they meet at the starting point? | {
"A": "20 sec",
"B": "12 sec",
"C": "30 sec",
"D": "50 sec",
"E": "1 min"
} | divide(180, add(8, 7)) | add(n0,n1)|divide(n2,#0)| | "they meet every 180 / 7 + 8 = 12 sec answer is b" | physics |
math_qa__C4tWZf2GBgXjZztD | What will be the cost of building a fence around a square plot with area equal to 36 sq ft, if the price per foot of building the fence is Rs. 58?
Select the correct option.
A) 3944 B) 2882 C) 2999 D) 2667 E) 1392 | <gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">24 * 58</gadget>
<output>1_392</output>
<result>E</result> | E | 1,392 | What will be the cost of building a fence around a square plot with area equal to 36 sq ft, if the price per foot of building the fence is Rs. 58? | {
"A": "3944",
"B": "2882",
"C": "2999",
"D": "2667",
"E": "1392"
} | multiply(square_perimeter(sqrt(36)), 58) | sqrt(n0)|square_perimeter(#0)|multiply(n1,#1)| | "let the side of the square plot be a ft . a 2 = 36 = > a = 6 length of the fence = perimeter of the plot = 4 a = 24 ft . cost of building the fence = 24 * 58 = rs . 1392 . answer : e" | geometry |
math_qa__qCUc8aDKPNbnHmVT | If the price of a certain computer increased 30 percent from y dollars to 351 dollars, then 2y =
Choose the correct choice: A) 540 B) 570 C) 619 D) 649 E) 700 | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 / 100</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">351 / (13/10)</gadget>
<output>270</output>
<gadget id="calculator">270 * 2</gadget>
<output>540</output>
<result>A</result> | A | 540 | If the price of a certain computer increased 30 percent from y dollars to 351 dollars, then 2y = | {
"A": "540",
"B": "570",
"C": "619",
"D": "649",
"E": "700"
} | multiply(divide(351, divide(add(const_100, 30), const_100)), 2) | add(n0,const_100)|divide(#0,const_100)|divide(n1,#1)|multiply(n2,#2)| | "before price increase price = y after 30 % price increase price = y + ( 30 / 100 ) * y = 1.3 y = 351 ( given ) i . e . y = 351 / 1.3 = $ 270 i . e . 2 y = 2 * 270 = 540 answer : option a" | general |
math_qa__MCnkWFDFq3REdhBD | if price of t.v set is reduced by 22%, then its sale increases by 86%, find net effect on sale value Choose the correct choice from the following options:
A) 44
B) 45
C) 46
D) 47
E) 48 | <gadget id="calculator">100 - 22</gadget>
<output>78</output>
<gadget id="calculator">78 / 100</gadget>
<output>39/50 = around 0.78</output>
<gadget id="calculator">100 + 86</gadget>
<output>186</output>
<gadget id="calculator">186 / 100</gadget>
<output>93/50 = around 1.86</output>
<gadget id="calculator">(39/50) * (93/50)</gadget>
<output>3_627/2_500 = around 1.4508</output>
<gadget id="calculator">(3_627/2_500) - 1</gadget>
<output>1_127/2_500 = around 0.4508</output>
<gadget id="calculator">(1_127/2_500) * 100</gadget>
<output>1_127/25 = around 45.08</output>
<result>B</result> | B | 45 | if price of t.v set is reduced by 22%, then its sale increases by 86%, find net effect on sale value | {
"A": "44",
"B": "45",
"C": "46",
"D": "47",
"E": "48"
} | multiply(subtract(multiply(divide(subtract(const_100, 22), const_100), divide(add(const_100, 86), const_100)), const_1), const_100) | add(n1,const_100)|subtract(const_100,n0)|divide(#1,const_100)|divide(#0,const_100)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "- a + b + ( ( - a ) ( b ) / 100 ) = - 22 + 86 + ( - 22 * 86 ) / 100 = - 22 + 86 - 19 = 45 answer : b" | gain |
math_qa__kjl6FYU7WhEqlaEA | Each month, after Jill pays for rent, utilities, food, and other necessary expenses, she has one fifth of her net monthly salary left as discretionary income. Of this discretionary income, she puts 30% into a vacation fund, 20% into savings, and spends 35% on eating out and socializing. This leaves her with $99 dollar, which she typically uses for gifts and charitable causes. What is Jill’s net monthly salary? Options: A) $ 2400 B) $ 3300 C) $ 6000 D) $ 6400 E) $ 9600 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">100 * 5</gadget>
<output>500</output>
<gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">50 + 35</gadget>
<output>85</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">99 / 15</gadget>
<output>33/5 = around 6.6</output>
<gadget id="calculator">500 * (33/5)</gadget>
<output>3_300</output>
<result>B</result> | B | 3,300 | Each month, after Jill pays for rent, utilities, food, and other necessary expenses, she has one fifth of her net monthly salary left as discretionary income. Of this discretionary income, she puts 30% into a vacation fund, 20% into savings, and spends 35% on eating out and socializing. This leaves her with $99 dollar, which she typically uses for gifts and charitable causes. What is Jill’s net monthly salary? | {
"A": "$ 2400",
"B": "$ 3300",
"C": "$ 6000",
"D": "$ 6400",
"E": "$ 9600"
} | multiply(multiply(const_100, add(const_3, const_2)), divide(99, subtract(const_100, add(add(30, 20), 35)))) | add(n0,n1)|add(const_2,const_3)|add(n2,#0)|multiply(#1,const_100)|subtract(const_100,#2)|divide(n3,#4)|multiply(#5,#3)| | "let x be the monthly salary 15 % of 1 / 5 * x = 99 x = 3300 answer b" | gain |
math_qa__Hlecd0CrrNCTcl9y | A goat is tied to one corner of a square plot of side 12m by a rope 7m long. Find the area it can graze? Choose the correct answer
A) 32 B) 36.5 C) 38.5 D) 39 E) 39.5 | <gadget id="calculator">pi * (7 ** 2)</gadget>
<output>49*pi = around 153.93804</output>
<gadget id="calculator">(49*pi) / 4</gadget>
<output>49*pi/4 = around 38.48451</output>
<result>C</result> | C | 38.5 | A goat is tied to one corner of a square plot of side 12m by a rope 7m long. Find the area it can graze? | {
"A": "32",
"B": "36.5",
"C": "38.5",
"D": "39",
"E": "39.5"
} | divide(circle_area(7), const_4) | circle_area(n1)|divide(#0,const_4) | area covered by goat = pi * r ^ 2 / 4 ( here we divide by 4 because rope is tied at the corner of the plot and only 1 / 4 part , the goat can graze ) where r = 7 m = length of rope so area = ( 22 / 7 ) * 7 * 7 / 4 = 38.5 sq m answer : c | geometry |
math_qa__r02qzURVr0rN6r0U | A retailer bought a hat at wholesale and marked it up 60% to its initial price of $24. By how many more dollars does he need to increase the price to achieve a 100% markup? Choose the correct choice from the following
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">160 / 100</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">24 / (8/5)</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">30 - 24</gadget>
<output>6</output>
<result>D</result> | D | 6 | A retailer bought a hat at wholesale and marked it up 60% to its initial price of $24. By how many more dollars does he need to increase the price to achieve a 100% markup? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | subtract(multiply(divide(24, divide(add(100, 60), 100)), const_2), 24) | add(n0,n2)|divide(#0,n2)|divide(n1,#1)|multiply(#2,const_2)|subtract(#3,n1)| | "let x be the wholesale price . then 1.6 x = 24 and x = 24 / 1.6 = 15 . to achieve a 100 % markup , the price needs to be $ 30 . the retailer needs to increase the price by $ 6 more . the answer is d ." | general |
math_qa__N3uMs4xw0nhG4sDb | The cube root of .000343 is Choose the correct choice from the following answers:
A) 0.7 B) 0.07 C) 0.007 D) 7 E) none of these | <gadget id="calculator">343 / 1_000</gadget>
<output>343/1_000 = around 0.343</output>
<gadget id="calculator">(343/1_000) / 1_000</gadget>
<output>343/1_000_000 = around 0.000343</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(343/1_000_000) ** (1/3)</gadget>
<output>7/100 = around 0.07</output>
<result>B</result> | B | 0.07 | The cube root of .000343 is | {
"A": "0.7",
"B": "0.07",
"C": "0.007",
"D": "7",
"E": "none of these"
} | power(divide(divide(000343, const_1000), const_1000), divide(const_1, const_3)) | divide(n0,const_1000)|divide(const_1,const_3)|divide(#0,const_1000)|power(#2,#1)| | "explanation : ( . 000343 ) 1 / 3 = ( 343 / 106 ) 1 / 3 = ( 7 * 7 * 7 / 102 * 102 * 102 ) 1 / 3 = 7 / 102 = 7 / 100 = 0.07 answer b" | geometry |
math_qa__gPqAtaj4eVJdd26s | A crow leaves its nest, and flies back and forth from its nest to a nearby ditch to gather worms. The distance between the nest and the ditch is 200 meters. In one and a half hours, the crow manages to bring worms to its nest 15 times. What is the speed of the crow in kilometers per hour? Choose the correct option: A) 1 B) 2 C) 3 D) 4 E) 6 | <gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">200 * 30</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 1_000</gadget>
<output>6</output>
<gadget id="calculator">15 / 10</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">6 / (3/2)</gadget>
<output>4</output>
<result>D</result> | D | 4 | A crow leaves its nest, and flies back and forth from its nest to a nearby ditch to gather worms. The distance between the nest and the ditch is 200 meters. In one and a half hours, the crow manages to bring worms to its nest 15 times. What is the speed of the crow in kilometers per hour? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "6"
} | divide(divide(multiply(200, multiply(15, const_2)), const_1000), divide(15, const_10)) | divide(n1,const_10)|multiply(n1,const_2)|multiply(n0,#1)|divide(#2,const_1000)|divide(#3,#0)| | "the distance between the nest and the ditch is 200 meters . 15 times mean = a crow leaves its nest , and flies back ( going and coming back ) i . e . 2 times we get total 30 rounds . so the distance is 30 * 200 = 6000 . d = st 6000 / 1.5 = t , i think we can take 6000 meters as 6 km , then only we get t = 4 . ( 1000 meters = 1 km ) d )" | physics |
math_qa__2mkln7YjNUudnx28 | 3 seventh of a number is 12 more than 40 % of that number . what will be the 30 % of that number ? Select
A) 148 B) 210 C) 63 D) 248 E) 258 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/7) - (2/5)</gadget>
<output>1/35 = around 0.028571</output>
<gadget id="calculator">12 / (1/35)</gadget>
<output>420</output>
<gadget id="calculator">(3/10) * 420</gadget>
<output>126</output>
<gadget id="calculator">126 / 2</gadget>
<output>63</output>
<result>C</result> | C | 63 | 3 seventh of a number is 12 more than 40 % of that number . what will be the 30 % of that number ? | {
"A": "148",
"B": "210",
"C": "63",
"D": "248",
"E": "258"
} | divide(multiply(divide(30, const_100), divide(12, subtract(divide(3, add(const_3, const_4)), divide(40, const_100)))), const_2) | add(const_3,const_4)|divide(n3,const_100)|divide(n2,const_100)|divide(n0,#0)|subtract(#3,#2)|divide(n1,#4)|multiply(#1,#5)|divide(#6,const_2) | 3 / 7 x – 40 / 100 x = 12 x = 35 * 12 35 * 12 * 30 / 100 = 126 / 2 = 63 answer : c | gain |
math_qa__Am0hUlhKZZAZZeX1 | find last digits of (1023^3923)+(3081^3921) Select.
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">3_923 % 4</gadget>
<output>3</output>
<gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<result>A</result> | A | 8 | find last digits of (1023^3923)+(3081^3921) | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | add(subtract(const_10, reminder(3923, const_4)), const_1) | reminder(n1,const_4)|subtract(const_10,#0)|add(#1,const_1) | we have ( 1023 ^ 3923 ) + ( 3081 ^ 3921 ) ( 3923 / 4 ) = 4 n + 3 ( 3921 / 4 ) = 4 n + 1 where n can be any integer now through cyclicity we can obtain or you can learn the chart from arun sharma number ending in 4 n + 1 4 n + 2 4 n + 3 4 n 1 1 1 1 1 2 2 4 8 6 3 3 9 7 1 in this way 7 + 1 = 8 is the unit ' s place digit answer : a | general |
math_qa__qm8lHN2c09YuNxop | the sum of 4 consecutive even numbers is 36 . find the sum of the squares of these numbers ? Choose the correct option:
A) 296
B) 252
C) 344
D) 388
E) none of these | <gadget id="calculator">4 + 10</gadget>
<output>14</output>
<gadget id="calculator">14 ** 2</gadget>
<output>196</output>
<gadget id="calculator">12 * 12</gadget>
<output>144</output>
<gadget id="calculator">196 + 144</gadget>
<output>340</output>
<result>C</result> | C | 344 | the sum of 4 consecutive even numbers is 36 . find the sum of the squares of these numbers ? | {
"A": "296",
"B": "252",
"C": "344",
"D": "388",
"E": "none of these"
} | add(power(add(4, const_10), const_2), multiply(const_12, const_12)) | add(n0,const_10)|multiply(const_12,const_12)|power(#0,const_2)|add(#1,#2) | let the four numbers be x , x + 2 , x + 4 and x + 6 . = > x + x + 2 + x + 4 + x + 6 = 36 = > 4 x + 12 = 36 = > x = 6 the numbers are 6 , 8 , 10 and 12 . sum of their squares = 62 + 82 + 102 + 122 = 36 + 64 + 100 + 144 = 344 . answer : c | physics |
math_qa__F1bY7MWlvWlzqCZf | Two trains, each 150 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is? Choose the correct choice from the following choices
A) 90 B) 98 C) 60 D) 88 E) 12 | <gadget id="calculator">150 + 150</gadget>
<output>300</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">300 / 24</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 2</gadget>
<output>25</output>
<gadget id="calculator">25 * 3_600</gadget>
<output>90_000</output>
<gadget id="calculator">90_000 / 1_000</gadget>
<output>90</output>
<result>A</result> | A | 90 | Two trains, each 150 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is? | {
"A": "90",
"B": "98",
"C": "60",
"D": "88",
"E": "12"
} | divide(multiply(multiply(divide(add(150, 150), multiply(8, add(const_1, const_2))), const_2), const_3600), const_1000) | add(n0,n0)|add(const_1,const_2)|multiply(n1,#1)|divide(#0,#2)|multiply(#3,const_2)|multiply(#4,const_3600)|divide(#5,const_1000)| | "let the speed of the slower train be x m / sec . then , speed of the train = 2 x m / sec . relative speed = ( x + 2 x ) = 3 x m / sec . ( 150 + 150 ) / 8 = 3 x = > x = 25 / 2 . so , speed of the faster train = 50 / 2 = 25 * 18 / 5 = 90 km / hr . answer : a" | physics |
math_qa__7Q93TcRr7ngHuPFp | With an average speed of 40 km/hr a car reaches its destination on time. If it goes with an average speed of 35 km/h, it is late by 15 minutes. The total journey is? Choose the correct choice:
A) 30 km
B) 40 km
C) 70 km
D) 80 km
E) 90 km | <gadget id="calculator">gcd(40, 35)</gadget>
<output>5</output>
<gadget id="calculator">40 / 5</gadget>
<output>8</output>
<gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">8 * (1/4)</gadget>
<output>2</output>
<gadget id="calculator">35 * 2</gadget>
<output>70</output>
<result>C</result> | C | 70 | With an average speed of 40 km/hr a car reaches its destination on time. If it goes with an average speed of 35 km/h, it is late by 15 minutes. The total journey is? | {
"A": "30 km",
"B": "40 km",
"C": "70 km",
"D": "80 km",
"E": "90 km"
} | multiply(35, multiply(divide(40, gcd(40, 35)), divide(15, const_60))) | divide(n2,const_60)|gcd(n0,n1)|divide(n0,#1)|multiply(#2,#0)|multiply(n1,#3) | let the total journey be x km . x / 35 - x / 40 = 15 / 60 solving for x , we get x = 70 therefore , total journey = 70 km . answer : c | general |
math_qa__VUsQU8khXbTDLC8g | Find the remainder Q when 12^190 is divided by 1729 ? Choose the correct choice from the following options: A) 12 B) 1 C) 1728 D) 1717 E) 4 | <gadget id="calculator">1_729 - 12</gadget>
<output>1_717</output>
<result>D</result> | D | 1,717 | Find the remainder Q when 12^190 is divided by 1729 ? | {
"A": "12",
"B": "1",
"C": "1728",
"D": "1717",
"E": "4"
} | subtract(1729, 12) | subtract(n2,n0) | 12 ^ ( 190 ) can be written as . ( ( 12 ^ 3 ) ^ 63 ) * 12 . 12 ^ 3 when divided by 1729 gives a remainder q - 1 . so in the numerator we have - 12 . now acccording to remainder theorm the answer will be 1729 - 12 = 1717 . d | general |
math_qa__ChSQlrzpN79JwomX | How much 70% of 100 is greater than 60% of 80? Select the correct option
A) 18 B) 99 C) 22 D) 26 E) 71 | <gadget id="calculator">70 * 100</gadget>
<output>7_000</output>
<gadget id="calculator">7_000 / 100</gadget>
<output>70</output>
<gadget id="calculator">60 * 80</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 100</gadget>
<output>48</output>
<gadget id="calculator">70 - 48</gadget>
<output>22</output>
<result>C</result> | C | 22 | How much 70% of 100 is greater than 60% of 80? | {
"A": "18",
"B": "99",
"C": "22",
"D": "26",
"E": "71"
} | subtract(divide(multiply(70, 100), const_100), divide(multiply(60, 80), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|subtract(#2,#3)| | "( 70 / 100 ) * 100 – ( 60 / 100 ) * 80 70 - 48 = 22 answer : c" | gain |
math_qa__pilvznSPRJhFrPht | The main line train starts at 5.00AM and the harbor line train starts at 5.02AM.Each train has the frequency of 10 minutes. If a guy goes in the morning at a random time what is the probability of he getting main line train? Choose the correct choice from the following: A) . 5 B) 0.6 C) 0.4 D) 0.7 E) 0.8 | <gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">8 / 10</gadget>
<output>4/5 = around 0.8</output>
<result>E</result> | E | 0.8 | The main line train starts at 5.00AM and the harbor line train starts at 5.02AM.Each train has the frequency of 10 minutes. If a guy goes in the morning at a random time what is the probability of he getting main line train? | {
"A": ". 5",
"B": "0.6",
"C": "0.4",
"D": "0.7",
"E": "0.8"
} | divide(subtract(10, const_2), 10) | subtract(n2,const_2)|divide(#0,n2) | out of 10 minutes there is only 2 minutes chance of getting harbour line train and there is 8 minutes chance for getting main line train . so , probability = 8 / 10 = 0.8 answer : e | probability |
math_qa__0FAq1PvBBWJbh0E3 | An uneducated retailer marks all his goods at 60% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales? Choose the correct option
A) 20 % B) 13.50 % C) 14 % D) 14.50 % E) none | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 + (3/5)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(8/5) * (1/4)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(8/5) - (2/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) - 1</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>A</result> | A | 20 | An uneducated retailer marks all his goods at 60% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales? | {
"A": "20 %",
"B": "13.50 %",
"C": "14 %",
"D": "14.50 %",
"E": "none"
} | multiply(subtract(subtract(add(const_1, divide(60, const_100)), multiply(add(const_1, divide(60, const_100)), divide(25, const_100))), const_1), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|multiply(#2,#1)|subtract(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "sol . let c . p . = rs . 100 . then , marked price = rs . 160 . s . p . = 75 % of rs . 160 = rs . 120 . ∴ gain % = 20 % . answer a" | gain |
math_qa__s0zmgSql8Jh2Pn2N | A plane flies 420 miles with the wind and 350 miles against the wind in the same length of time. If the speed of the wind is 23 mph, what is the speed of the plain in still air? Choose the correct option
A) 253 mph .
B) 275 mph .
C) 296 mph .
D) 278 mph .
E) 235 mph . | <gadget id="calculator">350 * 23</gadget>
<output>8_050</output>
<gadget id="calculator">420 * 23</gadget>
<output>9_660</output>
<gadget id="calculator">8_050 + 9_660</gadget>
<output>17_710</output>
<gadget id="calculator">420 - 350</gadget>
<output>70</output>
<gadget id="calculator">17_710 / 70</gadget>
<output>253</output>
<result>A</result> | A | 253 | A plane flies 420 miles with the wind and 350 miles against the wind in the same length of time. If the speed of the wind is 23 mph, what is the speed of the plain in still air? | {
"A": "253 mph .",
"B": "275 mph .",
"C": "296 mph .",
"D": "278 mph .",
"E": "235 mph ."
} | divide(add(multiply(350, 23), multiply(420, 23)), subtract(420, 350)) | multiply(n1,n2)|multiply(n0,n2)|subtract(n0,n1)|add(#0,#1)|divide(#3,#2) | the speed of the plane in still air = x miles / hour the speed of the wind is 23 mph speed with the wind = ( x + 23 ) mph speed against the wind = ( x – 23 ) mph time = distance / speed according to the problem , 420 / ( x + 23 ) = 350 / ( x – 23 ) 420 ( x – 23 ) = 350 ( x + 23 ) 420 x – 9660 = 350 x + 805 420 x – 350 x = 8050 + 9660 70 x = 17710 x = 17710 / 70 x = 253 therefore , the speed of the plane in still air = 253 mph . correct answer a | physics |
math_qa__p2x13Bp7ngIwYL7u | Rs 80000 is divided into two parts One part is given to a person with 10% interest and another part is given to a person with 20 % interest. At the end of first year he gets profit 9000 Find money given by 10%? Pick: A) 30000 B) 40000 C) 50000 D) 60000 E) 70000 | <gadget id="calculator">80_000 * 20</gadget>
<output>1_600_000</output>
<gadget id="calculator">1_600_000 / 100</gadget>
<output>16_000</output>
<gadget id="calculator">16_000 - 9_000</gadget>
<output>7_000</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">7_000 / (1/10)</gadget>
<output>70_000</output>
<result>E</result> | E | 70,000 | Rs 80000 is divided into two parts One part is given to a person with 10% interest and another part is given to a person with 20 % interest. At the end of first year he gets profit 9000 Find money given by 10%? | {
"A": "30000",
"B": "40000",
"C": "50000",
"D": "60000",
"E": "70000"
} | divide(subtract(divide(multiply(80000, 20), const_100), 9000), divide(10, const_100)) | divide(n1,const_100)|multiply(n0,n2)|divide(#1,const_100)|subtract(#2,n3)|divide(#3,#0)| | "let first parrt is x and second part is y then x + y = 80000 - - - - - - - - - - eq 1 total profit = profit on x + profit on y 9000 = ( x * 10 * 1 ) / 100 + ( y * 20 * 1 ) / 100 90000 = x + 2 y - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - eq 2 90000 = 80000 + y so y = 10000 then x = 80000 - 10000 = 70000 first part = 70000 answer : e" | gain |
math_qa__bADXKfJSYbzNrxBu | At the end of year X, automobile installment credit accounted for 43% of all outstanding consumer installment credit. At that time automobile finance companies extended $50 billion of credit, or 1/4 of the automobile installment credit. How many billion dollars of consumer installment credit was outstanding at that time? Choose one:
A) 450
B) 465.12
C) 475
D) 500.15
E) 200 | <gadget id="calculator">50 * 4</gadget>
<output>200</output>
<gadget id="calculator">43 / 100</gadget>
<output>43/100 = around 0.43</output>
<gadget id="calculator">200 / (43/100)</gadget>
<output>20_000/43 = around 465.116279</output>
<result>B</result> | B | 465.12 | At the end of year X, automobile installment credit accounted for 43% of all outstanding consumer installment credit. At that time automobile finance companies extended $50 billion of credit, or 1/4 of the automobile installment credit. How many billion dollars of consumer installment credit was outstanding at that time? | {
"A": "450",
"B": "465.12",
"C": "475",
"D": "500.15",
"E": "200"
} | divide(multiply(50, 4), divide(43, const_100)) | divide(n0,const_100)|multiply(n1,n3)|divide(#1,#0) | system of equations a = ( 43 / 100 ) c ( 1 / 4 ) a = 50 - - > a = 200 substitution 200 = ( 43 / 100 ) c c = ( 100 / 43 ) 200 calculate 200 / 43 * 100 - the the correct answer is 465.12 . the correct answer is b . | general |
math_qa__knAy1W543OJYINmO | A courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100 grams or part thereof. What could be the weight in grams of a package for which the charge is $1.85? Choose the correct choice from the following answers
A) 1680 B) 1420 C) 1120 D) 970 E) 740 | <gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">1.85 - (13/20)</gadget>
<output>1.2</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) / 100</gadget>
<output>1/1_000 = around 0.001</output>
<gadget id="calculator">(1/1_000) * 250</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1.2 + (1/4)</gadget>
<output>1.45</output>
<gadget id="calculator">1.45 / (1/1_000)</gadget>
<output>1_450</output>
<result>B</result> | B | 1,420 | A courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100 grams or part thereof. What could be the weight in grams of a package for which the charge is $1.85? | {
"A": "1680",
"B": "1420",
"C": "1120",
"D": "970",
"E": "740"
} | divide(add(subtract(1.85, divide(65, 100)), multiply(divide(divide(10, 100), 100), 250)), divide(divide(10, 100), 100)) | divide(n2,n3)|divide(n0,n3)|divide(#0,n3)|subtract(n4,#1)|multiply(n1,#2)|add(#4,#3)|divide(#5,#2)| | "the charge is 65 cents for the first 250 grams . this leaves a charge of $ 1.85 - $ 0.65 = $ 1.20 the charge for the next 1100 grams is $ 1.10 which leaves a charge of $ 0.10 the weight is somewhere between 1350 and 1450 . the answer is b ." | general |
math_qa__aJ5Etol4LfsYwHMT | A fruit seller sells mangoes at the rate of Rs.9 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5%
Choose one
A) rs 8.81
B) rs 9.81
C) rs 10.81
D) rs 11.81
E) none of these | <gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">9 * 105</gadget>
<output>945</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">945 / 80</gadget>
<output>189/16 = around 11.8125</output>
<result>D</result> | D | 11.81 | A fruit seller sells mangoes at the rate of Rs.9 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5% | {
"A": "rs 8.81",
"B": "rs 9.81",
"C": "rs 10.81",
"D": "rs 11.81",
"E": "none of these"
} | divide(multiply(9, add(const_100, 5)), subtract(const_100, 20)) | add(n2,const_100)|subtract(const_100,n1)|multiply(n0,#0)|divide(#2,#1)| | "explanation : 85 : 9 = 105 : x x = ( 9 × 105 / 85 ) = rs 11.81 option d" | gain |
math_qa__xi9ILx4MCt707BtL | If 21/22 = 0.95.45, what is the 57th digit to the right of the decimal point of the fraction? Choose the correct option: A) 1 B) 4 C) 5 D) 7 E) 9 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<result>B</result> | B | 4 | If 21/22 = 0.95.45, what is the 57th digit to the right of the decimal point of the fraction? | {
"A": "1",
"B": "4",
"C": "5",
"D": "7",
"E": "9"
} | multiply(const_2, const_2) | multiply(const_2,const_2) | we are not concerned what 21 / 22 means . . we have to look at the decimal . . 0.9544 means 0.95454545 . . . . so leaving first digit to the right of decimal , all odd numbered digits are 4 and all even numbered are 5 . . here 57 is odd , so ans is 4 answer is b | general |
math_qa__SbBrgkXlJodknfDu | How many multiples of 5 are there between 50 and 500 ? Answers
A) 128 B) 91 C) 89 D) 61 E) 60 | <gadget id="calculator">500 - 50</gadget>
<output>450</output>
<gadget id="calculator">450 / 5</gadget>
<output>90</output>
<gadget id="calculator">90 + 1</gadget>
<output>91</output>
<result>C</result> | C | 89 | How many multiples of 5 are there between 50 and 500 ? | {
"A": "128",
"B": "91",
"C": "89",
"D": "61",
"E": "60"
} | add(divide(subtract(500, 50), 5), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "it should be mentioned whether 50 and 500 are inclusive . if 50 and 500 are inclusive , then the answer is ( 500 - 50 ) / 5 + 1 = 91 . if 50 and 500 are not inclusive , then the answer is ( 495 - 55 ) / 5 + 1 = 89 . since oa is c , then we have not inclusive case ." | general |
math_qa__E1R6sxU9dwsr7DdD | The height of the wall is 6 times its width and lenght of the wall is 7 times its height .if the volume of the wall be 16128 cu.m.its width is Choose the correct choice from the following.
A) 4 m B) 5 m C) 6 m D) 7 m E) 8 m | <gadget id="calculator">6 * 7</gadget>
<output>42</output>
<gadget id="calculator">42 * 6</gadget>
<output>252</output>
<gadget id="calculator">16_128 / 252</gadget>
<output>64</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>
<result>A</result> | A | 4 | The height of the wall is 6 times its width and lenght of the wall is 7 times its height .if the volume of the wall be 16128 cu.m.its width is | {
"A": "4 m",
"B": "5 m",
"C": "6 m",
"D": "7 m",
"E": "8 m"
} | power(divide(16128, multiply(multiply(6, 7), 6)), divide(const_1, const_3)) | divide(const_1,const_3)|multiply(n0,n1)|multiply(n0,#1)|divide(n2,#2)|power(#3,#0) | explanation : let width = x then , height = 6 x and length = 42 x 42 x × 6 x × x = 16128 x = 4 answer : a | physics |
math_qa__sTdxZDDZPqaxelZM | Two stations P and Q are 110 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet? Choices:
A) 10.30
B) 10
C) 8.45
D) 9.3
E) 11 | <gadget id="calculator">110 + 25</gadget>
<output>135</output>
<gadget id="calculator">20 + 25</gadget>
<output>45</output>
<gadget id="calculator">135 / 45</gadget>
<output>3</output>
<gadget id="calculator">3 + 7</gadget>
<output>10</output>
<result>B</result> | B | 10 | Two stations P and Q are 110 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet? | {
"A": "10.30",
"B": "10",
"C": "8.45",
"D": "9.3",
"E": "11"
} | add(divide(add(110, 25), add(20, 25)), 7) | add(n0,n4)|add(n2,n4)|divide(#0,#1)|add(n1,#2)| | "explanation : assume both trains meet after x hours after 7 am distance covered by train starting from p in x hours = 20 x km distance covered by train starting from q in ( x - 1 ) hours = 25 ( x - 1 ) total distance = 110 = > 20 x + 25 ( x - 1 ) = 110 = > 45 x = 135 = > x = 3 means , they meet after 3 hours after 7 am , ie , they meet at 10 am . answer : b" | physics |
math_qa__xja1U2XtnDdIK1PW | If * stands for /, / stands for -, + stands for * and - stands for +, then
9/8*7+5-10 = ? Choose the correct option: A) 13.3 B) 10.8 C) 10.7 D) 11.4 E) 12.5 | <gadget id="calculator">8 / 7</gadget>
<output>8/7 = around 1.142857</output>
<gadget id="calculator">(8/7) * 5</gadget>
<output>40/7 = around 5.714286</output>
<gadget id="calculator">9 - (40/7)</gadget>
<output>23/7 = around 3.285714</output>
<gadget id="calculator">10 + (23/7)</gadget>
<output>93/7 = around 13.285714</output>
<result>A</result> | A | 13.3 | If * stands for /, / stands for -, + stands for * and - stands for +, then
9/8*7+5-10 = ? | {
"A": "13.3",
"B": "10.8",
"C": "10.7",
"D": "11.4",
"E": "12.5"
} | add(10, subtract(9, multiply(divide(8, 7), 5))) | divide(n1,n2)|multiply(n3,#0)|subtract(n0,#1)|add(n4,#2) | 9 / 8 * 7 + 5 - 10 this expression becomes 9 - 8 / 7 * 5 + 10 after exchanging the symbols then the values for it would be 9 - 1.142 * 5 + 10 = 13.290 ( app ) = 13.3 answer : a | general |
math_qa__cNAqEgLuaCjacMVn | HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is? Choose the correct choice from the following options:
A) 36 B) 66 C) 132 D) 264 E) 152 | <gadget id="calculator">12 * 396</gadget>
<output>4_752</output>
<gadget id="calculator">4_752 / 36</gadget>
<output>132</output>
<result>C</result> | C | 132 | HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is? | {
"A": "36",
"B": "66",
"C": "132",
"D": "264",
"E": "152"
} | divide(multiply(12, 396), 36) | multiply(n0,n1)|divide(#0,n2)| | "12 * 396 = 36 * x x = 132 answer : c" | physics |
math_qa__XaDdjSf6LORR7SeY | a 4 digit number is such that the product of all of its digits is 126 . the sum of all the digits is equal to the 2 digit number formed by using thousands digit and tens digit ( 1000 digit in tens place & 10 digit in units place ) which in turn is equal to 19 . then difference of units and 1000 place of the number is , given that this difference is positive .
Pick one
A) 1692 B) 1792 C) 1795 D) 1892 E) 1992 | <gadget id="calculator">19 - 10</gadget>
<output>9</output>
<gadget id="calculator">126 / 9</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">7 * 100</gadget>
<output>700</output>
<gadget id="calculator">1_000 + 700</gadget>
<output>1_700</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">1_700 + 90</gadget>
<output>1_790</output>
<gadget id="calculator">1_790 + 2</gadget>
<output>1_792</output>
<result>B</result> | B | 1,792 | a 4 digit number is such that the product of all of its digits is 126 . the sum of all the digits is equal to the 2 digit number formed by using thousands digit and tens digit ( 1000 digit in tens place & 10 digit in units place ) which in turn is equal to 19 . then difference of units and 1000 place of the number is , given that this difference is positive . | {
"A": "1692",
"B": "1792",
"C": "1795",
"D": "1892",
"E": "1992"
} | add(add(add(const_1000, multiply(divide(divide(126, subtract(19, const_10)), 2), const_100)), multiply(subtract(19, const_10), const_10)), 2) | subtract(n5,const_10)|divide(n1,#0)|multiply(#0,const_10)|divide(#1,n2)|multiply(#3,const_100)|add(#4,const_1000)|add(#5,#2)|add(n2,#6) | the number is 1792 . let the number be represented as 1000 x + 100 y + 10 z + t acc to ques , xyzt = 126 x + y + z + t = 10 x + z = 19 so , number in thousands and tens place are 1 and 9 respectively . the remaining factor is 14 which is 7 * 2 so the number is 1792 . answer : b | general |
math_qa__ZwE7MAMIILDch9B0 | A man loses 1/3rd of his money, then wins Rs. 10 loses 1/3rd of what he has and wins Rs. 20 and finds that he has exactly what be had at the beginning. What was the amount he originally bad ?
Select: A) 25 B) 36 C) 10 D) 48 E) 45 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 10</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">(20/3) + 20</gadget>
<output>80/3 = around 26.666667</output>
<gadget id="calculator">(2/3) * (2/3)</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">1 - (4/9)</gadget>
<output>5/9 = around 0.555556</output>
<gadget id="calculator">(80/3) / (5/9)</gadget>
<output>48</output>
<result>D</result> | D | 48 | A man loses 1/3rd of his money, then wins Rs. 10 loses 1/3rd of what he has and wins Rs. 20 and finds that he has exactly what be had at the beginning. What was the amount he originally bad ? | {
"A": "25",
"B": "36",
"C": "10",
"D": "48",
"E": "45"
} | divide(add(multiply(subtract(const_1, divide(1, 3)), 10), 20), subtract(const_1, multiply(subtract(const_1, divide(1, 3)), subtract(const_1, divide(1, 3))))) | divide(n0,n1)|subtract(const_1,#0)|multiply(n2,#1)|multiply(#1,#1)|add(n5,#2)|subtract(const_1,#3)|divide(#4,#5) | let x be that amount so accordind to question , eqn will be like : ( ( ( x - x / 3 ) + 10 ) - ( ( ( x - x / 3 ) + 10 ) / 3 ) ) + 20 = x = > ( ( 2 x / 3 + 10 ) - ( ( 2 x / 3 + 10 ) / 3 ) ) + 20 = x = > 3 x - 4 x / 3 = 80 = > x = 48 answer : d | general |
math_qa__OrskFS115esODTC7 | A carpenter worked alone for 1 day on a job that would take him 6 more days to finish. He and another carpenter completed the job in 7 more days. How many days would it have taken the second carpenter to do the complete job working alone? Choose the correct choice from the following answers.
A) 4.5 B) 7.5 C) 9.5 D) 14.5 E) 24.5 | <gadget id="calculator">1 + 6</gadget>
<output>7</output>
<gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">49 / 2</gadget>
<output>49/2 = around 24.5</output>
<result>E</result> | E | 24.5 | A carpenter worked alone for 1 day on a job that would take him 6 more days to finish. He and another carpenter completed the job in 7 more days. How many days would it have taken the second carpenter to do the complete job working alone? | {
"A": "4.5",
"B": "7.5",
"C": "9.5",
"D": "14.5",
"E": "24.5"
} | divide(multiply(7, add(1, 6)), const_2) | add(n0,n1)|multiply(n2,#0)|divide(#1,const_2)| | "a carpenter worked only 1 day on something that takes him 6 more days . means ; carpenter finishes his work in 7 days . let his buddy finish the same task in x days . respective rates per day : 1 / 7 and 1 / x to complete 1 work : first guy worked for 5 days @ rate = 1 / 7 per day . second one worked for 7 days @ rate = 1 / x per day expression : days * rate = work 5 * 1 / 7 + 7 * 1 / x = 1 5 x + 49 = 7 x 2 x = 49 x = 24.5 days . ans : e" | physics |
math_qa__Fi7yzgpqYOWaid2u | For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 35 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated?
Choose the correct choice from the following
A) 12 % B) 26 % C) 29 % D) 30 % E) 60 % | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 300</gadget>
<output>75</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) * 200</gadget>
<output>70</output>
<gadget id="calculator">75 + 70</gadget>
<output>145</output>
<gadget id="calculator">300 + 200</gadget>
<output>500</output>
<gadget id="calculator">145 / 500</gadget>
<output>29/100 = around 0.29</output>
<gadget id="calculator">(29/100) * 100</gadget>
<output>29</output>
<result>C</result> | C | 29 | For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 35 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated? | {
"A": "12 %",
"B": "26 %",
"C": "29 %",
"D": "30 %",
"E": "60 %"
} | multiply(divide(add(multiply(divide(25, const_100), 300), multiply(divide(35, const_100), 200)), add(300, 200)), const_100) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100) | in the first plot 25 % of 300 seeds germinated , so 0.25 x 300 = 75 seeds germinated . in the second plot , 35 % of 200 seeds germinated , so 0.35 x 200 = 70 seeds germinated . since 75 + 70 = 145 seeds germinated out of a total of 300 + 200 = 500 seeds , the percent of seeds that germinated is ( 145 / 500 ) x 100 % , or 29 % . answer : c . | general |
math_qa__pZ8aaVyvZtME3gWp | On the first day of her vacation, Louisa traveled 240 miles. On the second day, traveling at the same average speed, she traveled 420 miles. If the 240-mile trip took 3 hours less than the 420-mile trip, what was the average speed, in miles per hour? Choose the correct choice from the following.
A) 65
B) 50
C) 55
D) 60
E) 58 | <gadget id="calculator">420 - 240</gadget>
<output>180</output>
<gadget id="calculator">180 / 3</gadget>
<output>60</output>
<result>D</result> | D | 60 | On the first day of her vacation, Louisa traveled 240 miles. On the second day, traveling at the same average speed, she traveled 420 miles. If the 240-mile trip took 3 hours less than the 420-mile trip, what was the average speed, in miles per hour? | {
"A": "65",
"B": "50",
"C": "55",
"D": "60",
"E": "58"
} | divide(subtract(420, 240), 3) | subtract(n1,n0)|divide(#0,n3)| | "( time ) * ( rate ) = ( distance ) - - > ( rate ) = ( distance ) / ( time ) - - > given : ( rate ) = 240 / t = 420 / ( t + 3 ) - - > 4 / t = 7 / ( t + 3 ) - - > 4 t + 12 = 7 t - - - - > 3 t = 12 . t = 4 - - - - > ( rate ) = 240 / 4 = 60 answer : d" | physics |
math_qa__BbT0ZVxCGjRvc4Xv | The number of positive integers n in the range 12 ≤ n ≤ 40 such that the product
(n − 1)(n − 2)...3.2.1 is not divisible by n is Pick one:
A) 5 B) 7 C) 13 D) 14 E) 16 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<result>B</result> | B | 7 | The number of positive integers n in the range 12 ≤ n ≤ 40 such that the product
(n − 1)(n − 2)...3.2.1 is not divisible by n is | {
"A": "5",
"B": "7",
"C": "13",
"D": "14",
"E": "16"
} | add(add(3, 2), 2) | add(n3,n4)|add(n3,#0) | explanation : ( n - 1 ) ! is always divisible by n unless and untill n is a prime number e . g . ( 5 - 1 ) ! = 4 ! which is not divisible by 5 bcuz 5 is a prime number therefore , find all prime numbers in the range of 12 to 40 i . e 13 , 17 , 19 , 23 , 29 , 31 and 37 hence , the number of positive integers n is 7 . answer : b | general |
math_qa__xCSceN6Ppeetic5j | A sum was put at simple interest at certain rate for 3 years. Had it been put at 1% higher rate it would have fetched Rs. 72 more. The sum is: A. Rs. 2,400 B. Rs. 2,100 C. Rs. 2,200 D.Rs. 2,480 Choose the correct choice from the following answers.
A) 2000 B) 2100 C) 2200 D) 2300 E) 2400 | <gadget id="calculator">72 / 3</gadget>
<output>24</output>
<gadget id="calculator">24 * 100</gadget>
<output>2_400</output>
<result>E</result> | E | 2,400 | A sum was put at simple interest at certain rate for 3 years. Had it been put at 1% higher rate it would have fetched Rs. 72 more. The sum is: A. Rs. 2,400 B. Rs. 2,100 C. Rs. 2,200 D.Rs. 2,480 | {
"A": "2000",
"B": "2100",
"C": "2200",
"D": "2300",
"E": "2400"
} | multiply(divide(72, 3), const_100) | divide(n2,n0)|multiply(#0,const_100) | 1 percent for 3 years = 72 1 percent for 1 year = 24 = > 100 percent = 2400 answer : e | gain |
math_qa__3rDKO79JuQtIbcXK | A man is 26 years older than his studen. In two years, his age will be twice the age of his student. The present age of his student is: Answers: A) 20 B) 21 C) 22 D) 23 E) 24 | <gadget id="calculator">26 - 2</gadget>
<output>24</output>
<result>E</result> | E | 24 | A man is 26 years older than his studen. In two years, his age will be twice the age of his student. The present age of his student is: | {
"A": "20",
"B": "21",
"C": "22",
"D": "23",
"E": "24"
} | subtract(26, const_2) | subtract(n0,const_2) | let the student ' s present age be x years . then , man ' s present age = ( x + 26 ) years . ( x + 26 ) + 2 = 2 ( x + 2 ) x + 28 = 2 x + 4 x = 24 . answer : e | general |
math_qa__Jv2p7Vt4yYv48MgK | A = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set A and one integer from set B. What is the probability T that the sum of the two integers will equal 9 ? Choose the most appropriate option: A) 0.15 B) 0.20 C) 0.25 D) 0.30 E) 0.33 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">4 / 20</gadget>
<output>1/5 = around 0.2</output>
<result>B</result> | B | 0.2 | A = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set A and one integer from set B. What is the probability T that the sum of the two integers will equal 9 ? | {
"A": "0.15",
"B": "0.20",
"C": "0.25",
"D": "0.30",
"E": "0.33"
} | divide(4, multiply(4, 5)) | multiply(n2,n3)|divide(n2,#0) | rearrange the first set : a = { 54 , 32 } b = { 45 , 67 , 8 } as you can see numbers in each column ( the numbers of the same color ) give the sum of 9 . so there are 4 such pares possible , total # of pairs is 4 * 5 = 20 . t = favorable / total = 4 / 20 = 0.2 . answer : b . or : we can select any number from set a ( 4 / 4 = 1 ) but in this case we must select its matching pair from set b ( the number of the same color ) and since there are only one matching pair of this particular number in b then the probability of this is 1 / 5 . so , overall : t = 1 * 1 / 5 . answer : b . | general |
math_qa__3XZNmmtZ7H9nYZv1 | How many pieces can a square pizza be cut into by making 4 linear cuts? Pick one:
A) 10 B) 11 C) 12 D) 13 E) 14 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<result>B</result> | B | 11 | How many pieces can a square pizza be cut into by making 4 linear cuts? | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | subtract(multiply(4, const_3), const_1) | multiply(n0,const_3)|subtract(#0,const_1) | 1 cut makes two pieces a second cut can make 4 pieces by cutting through 2 of the pieces a third cut can make 7 pieces by cutting through 3 of the pieces a fourth cut can make 11 pieces by cutting through 4 of the pieces b | geometry |
math_qa__DZHoe1yRxWDOO9Cx | Two trains of length 220 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? Choose the correct choice from the following.
A) 28 B) 266 C) 990 D) 25 E) 11 | <gadget id="calculator">220 + 280</gadget>
<output>500</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">500 / 20</gadget>
<output>25</output>
<result>D</result> | D | 25 | Two trains of length 220 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "28",
"B": "266",
"C": "990",
"D": "25",
"E": "11"
} | divide(add(220, 280), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 220 + 280 = 500 m . the time required = d / s = 500 / 20 = 25 sec . answer : d" | physics |
math_qa__LHP44UmfqRuw6U3N | We bought orange juice and apple juice at the store. A bottle of orange juice costs 70 cents and a bottle of apple juice costs 60 cents. We bought a total of 70 bottles for $46.20. How many bottles of orange juice did we buy? Choose the most appropriate option
A) 32
B) 36
C) 38
D) 42
E) 48 | <gadget id="calculator">46.2 * 100</gadget>
<output>4_620</output>
<gadget id="calculator">60 * 70</gadget>
<output>4_200</output>
<gadget id="calculator">4_620 - 4_200</gadget>
<output>420</output>
<gadget id="calculator">70 - 60</gadget>
<output>10</output>
<gadget id="calculator">420 / 10</gadget>
<output>42</output>
<result>D</result> | D | 42 | We bought orange juice and apple juice at the store. A bottle of orange juice costs 70 cents and a bottle of apple juice costs 60 cents. We bought a total of 70 bottles for $46.20. How many bottles of orange juice did we buy? | {
"A": "32",
"B": "36",
"C": "38",
"D": "42",
"E": "48"
} | divide(subtract(multiply(46.2, const_100), multiply(60, 70)), subtract(70, 60)) | multiply(n3,const_100)|multiply(n0,n1)|subtract(n0,n1)|subtract(#0,#1)|divide(#3,#2) | let oj be the bottles of orange juice and let aj be the bottles of apple juice . ( oj ) + aj = 70 . aj = 70 - ( oj ) . 70 ( oj ) + 60 aj = 4620 . 70 ( oj ) + 60 ( 70 - oj ) = 4620 . 10 ( oj ) + 4200 = 4620 . oj = 42 . the answer is d . | general |
math_qa__SfoyZtlWKAfmUcZZ | a basketball player practices 2 hours a day monday through friday . how many hours must he practice saturday and sunday combined if he wants to practice an average ( arithmetic mean ) of 3 hours a day for the 7 day week ? Select.
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">21 - 10</gadget>
<output>11</output>
<result>D</result> | D | 11 | a basketball player practices 2 hours a day monday through friday . how many hours must he practice saturday and sunday combined if he wants to practice an average ( arithmetic mean ) of 3 hours a day for the 7 day week ? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | subtract(multiply(3, 7), multiply(add(2, 3), 2)) | add(n0,n1)|multiply(n1,n2)|multiply(n0,#0)|subtract(#1,#2) | total number of hours practiced mon through fri : 5 * 2 = 10 total number of hours that will be practiced in a 7 day week considering 3 hours a day average : 7 * 3 = 21 thus 21 - 10 = 11 hours still need to be practiced ( on sat and sun combined ) d | general |
math_qa__BmGWYcW7FXntL2Oc | When the positive integer k is divided by the positive integer n , the remainder is 11. If k/n = 83.2 , what is the value of n? Choose the correct choice from the following answers.
A) 9 B) 20 C) 55 D) 70 E) 81 | <gadget id="calculator">83.2 * 10</gadget>
<output>832</output>
<gadget id="calculator">832 - 2</gadget>
<output>830</output>
<gadget id="calculator">830 / 10</gadget>
<output>83</output>
<gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">11 / (1/5)</gadget>
<output>55</output>
<gadget id="calculator">83 * 55</gadget>
<output>4_565</output>
<gadget id="calculator">4_565 + 11</gadget>
<output>4_576</output>
<gadget id="calculator">4_576 / 55</gadget>
<output>416/5 = around 83.2</output>
<result>E</result> | E | 81 | When the positive integer k is divided by the positive integer n , the remainder is 11. If k/n = 83.2 , what is the value of n? | {
"A": "9",
"B": "20",
"C": "55",
"D": "70",
"E": "81"
} | divide(add(multiply(divide(subtract(multiply(83.2, const_10), const_2), const_10), divide(11, divide(const_2, const_10))), 11), divide(11, divide(const_2, const_10))) | divide(const_2,const_10)|multiply(n1,const_10)|divide(n0,#0)|subtract(#1,const_2)|divide(#3,const_10)|multiply(#4,#2)|add(n0,#5)|divide(#6,#2) | here ' s an approach that ' s based on number properties and a bit ofbrute forcemath : we ' re told that k and n are both integers . since k / n = 81.2 , we can say that k = 81.2 ( n ) n has tomultiply outthe . 2 so that k becomes an integer . with the answers that we have to work with , n has to be a multiple of 5 . eliminate a and e . with the remaining answers , we can test the answers and find the one that fits the rest of the info ( k / n = 81.2 and k / n has a remainder of 11 ) answer b : if n = 20 , then k = 1624 ; 1624 / 20 has a remainder of 4 not a match answer c : if n = 55 , then k = 4466 ; 4466 / 55 has a remainder of 11 match . final answer : e | general |
math_qa__D1CDXGa6GX3RTzyi | What sum of money will produce Rs.90 as simple interest in 4 years at 4 1/2 percent? Choose the correct option.
A) rs . 550 B) rs . 650 C) rs . 600 D) rs . 500 E) rs . 700 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 + (1/2)</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">4 * (9/2)</gadget>
<output>18</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">90 / (9/50)</gadget>
<output>500</output>
<result>D</result> | D | 500 | What sum of money will produce Rs.90 as simple interest in 4 years at 4 1/2 percent? | {
"A": "rs . 550",
"B": "rs . 650",
"C": "rs . 600",
"D": "rs . 500",
"E": "rs . 700"
} | divide(90, divide(multiply(4, add(4, divide(1, 2))), const_100)) | divide(n3,n4)|add(n2,#0)|multiply(n1,#1)|divide(#2,const_100)|divide(n0,#3)| | "explanation : 90 = ( p * 4 * 9 / 2 ) / 100 90 = 36 p / 100 p = 500 answer : option d" | gain |
math_qa__7mqoOPfurEoFwEkq | Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/8 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21? Choices: A) 24 B) 35 C) 39 D) 60 E) 65 | <gadget id="calculator">7 * 8</gadget>
<output>56</output>
<gadget id="calculator">56 * 3</gadget>
<output>168</output>
<gadget id="calculator">168 / 7</gadget>
<output>24</output>
<result>A</result> | A | 24 | Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/8 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21? | {
"A": "24",
"B": "35",
"C": "39",
"D": "60",
"E": "65"
} | divide(multiply(multiply(7, 8), 3), 7) | multiply(n1,n4)|multiply(n0,#0)|divide(#1,n1)| | "the total number of the people in the room must be a multiple of both 7 and 8 ( in order 3 / 7 and 5 / 8 of the number to be an integer ) , thus the total number of the people must be a multiple of lcm of 7 and 8 , which is 56 . since , the total number of the people in the room is greater than 50 and less than 100 , then there are 56 people in the room . therefore there are 3 / 7 * 56 = 24 people in the room under the age of 21 . answer : a ." | general |
math_qa__sbaCicNwOqQuznDW | Alice picked a number of pears, each of which she sold, canned, or poached. She canned 20 percent more than she poached, and she poached 50 percent less than she sold. If there were a total of 42 pears, then how many pears did she sell? Choose the correct choice: A) 20 B) 21 C) 22 D) 23 E) 24 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(1/2) * (6/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(1/2) + (3/5)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">1 + (11/10)</gadget>
<output>21/10 = around 2.1</output>
<gadget id="calculator">42 / (21/10)</gadget>
<output>20</output>
<result>A</result> | A | 20 | Alice picked a number of pears, each of which she sold, canned, or poached. She canned 20 percent more than she poached, and she poached 50 percent less than she sold. If there were a total of 42 pears, then how many pears did she sell? | {
"A": "20",
"B": "21",
"C": "22",
"D": "23",
"E": "24"
} | divide(42, add(const_1, add(divide(50, const_100), multiply(divide(50, const_100), add(const_1, divide(20, const_100)))))) | divide(n1,const_100)|divide(n0,const_100)|add(#1,const_1)|multiply(#2,#0)|add(#0,#3)|add(#4,const_1)|divide(n2,#5) | let x be the amount of pears that she sold . then she poached 0.5 x . then she canned 1.2 * 0.5 x = 0.6 x . the total amount of pears is x + 0.5 x + 0.6 x = 2.1 x the fraction of pears that she sold is 1 / 2.1 = 10 / 21 . the number of pears she sold is ( 10 / 21 ) * 42 = 20 . the answer is a . | general |
math_qa__uuf4AWvVwsJI6hO1 | The value of x + x(x^x) when x = 10 is Options.
A) 100000000010 B) 10000000010 C) 10000000000 D) 1200000000 E) 12000000010 | <gadget id="calculator">10 ** 10</gadget>
<output>10_000_000_000</output>
<gadget id="calculator">10 * 10_000_000_000</gadget>
<output>100_000_000_000</output>
<gadget id="calculator">100_000_000_000 + 10</gadget>
<output>100_000_000_010</output>
<result>A</result> | A | 100,000,000,010 | The value of x + x(x^x) when x = 10 is | {
"A": "100000000010",
"B": "10000000010",
"C": "10000000000",
"D": "1200000000",
"E": "12000000010"
} | add(multiply(10, power(10, 10)), 10) | power(n0,n0)|multiply(n0,#0)|add(n0,#1) | solution : x + x ( x ^ x ) put the value of x = 10 in the above expression we get , 10 + 10 ( 10 ^ 10 ) = 10 + 10 ( 10 ã — 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 ) = 10 + 10 ( 10000000000 ) = 10 + 100000000000 = 100000000010 answer : ( a ) | general |
math_qa__8SJS1TvZJeL4Mdlx | if k is a non - negative integer and 30 ^ k is a divisor of 929260 then 3 ^ k - k ^ 3 = Choose the correct answer.
A) 0 B) 1 C) 45 D) 130 E) 520 | <gadget id="calculator">3 / 3</gadget>
<output>1</output>
<result>B</result> | B | 1 | if k is a non - negative integer and 30 ^ k is a divisor of 929260 then 3 ^ k - k ^ 3 = | {
"A": "0",
"B": "1",
"C": "45",
"D": "130",
"E": "520"
} | divide(3, 3) | divide(n2,n2) | 9 + 2 + 9 + 2 + 6 + 0 = 28 , so this number is not divisible by 3 and thus not divisible by 30 . therefore , k = 0 3 ^ k - k ^ 3 = 1 - 0 = 1 the answer is b . | general |
math_qa__F5yL4LNBd0aao8zG | A sum was put at simple interest at a certain rate for 4 years Had it been put at 2% higher rate, it would have fetched 56 more. Find the sum. Pick one: A) 500 B) 600 C) 700 D) 800 E) none of these | <gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 4</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">56 / (2/25)</gadget>
<output>700</output>
<result>C</result> | C | 700 | A sum was put at simple interest at a certain rate for 4 years Had it been put at 2% higher rate, it would have fetched 56 more. Find the sum. | {
"A": "500",
"B": "600",
"C": "700",
"D": "800",
"E": "none of these"
} | divide(56, multiply(divide(2, const_100), 4)) | divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1)| | "difference in s . i . = p × t / 100 ( r 1 − r 2 ) ⇒ 56 = p × 4 × 2 / 100 ( ∵ r 1 - r 2 = 2 ) ⇒ p = 56 × 100 / 4 × 2 = 700 answer c" | gain |
math_qa__wxe1lWrzBQS6iFzz | a vending machine randomly dispenses 4 different types of fruit candy . there are twice as many apple candies as orange candies , twice as many strawberry candies as grape candies , and twice as many apple candies as strawberry candies . if each candy cost $ 0.1 , and there are exactly 90 candies , what is the minimum amount of money required to guarantee that you would buy at least 3 of each type of candy ? Choose the correct choice from the following options:
A) $ 8.30
B) $ 20.75
C) $ 22.50
D) $ 42.75
E) $ 45.00 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 + (1/2)</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">90 / (9/2)</gadget>
<output>20</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">60 + 20</gadget>
<output>80</output>
<gadget id="calculator">80 + 3</gadget>
<output>83</output>
<gadget id="calculator">0.1 * 83</gadget>
<output>8.3</output>
<result>A</result> | A | 8.3 | a vending machine randomly dispenses 4 different types of fruit candy . there are twice as many apple candies as orange candies , twice as many strawberry candies as grape candies , and twice as many apple candies as strawberry candies . if each candy cost $ 0.1 , and there are exactly 90 candies , what is the minimum amount of money required to guarantee that you would buy at least 3 of each type of candy ? | {
"A": "$ 8.30",
"B": "$ 20.75",
"C": "$ 22.50",
"D": "$ 42.75",
"E": "$ 45.00"
} | multiply(0.1, add(add(add(multiply(divide(90, add(4, divide(const_1, const_2))), const_2), divide(90, add(4, divide(const_1, const_2)))), divide(90, add(4, divide(const_1, const_2)))), 3)) | divide(const_1,const_2)|add(n0,#0)|divide(n2,#1)|multiply(#2,const_2)|add(#2,#3)|add(#4,#2)|add(n3,#5)|multiply(n1,#6) | let number of apple , orange , strawberry and grape candies be a , o , s and g respectively . a = 2 o s = 2 g a = 2 s a = 4 g a + o + s + g = 90 = > a + a / 2 + a / 2 + a / 4 = 90 = > 9 a / 4 = 90 = > a = 40 o = 20 s = 20 g = 10 cost of each candy = . 1 $ mininum amount of money required to guarantee that you would buy at least three of each type of candy we can buy 40 apple candies , 20 orange candies , 20 strawberry candies and 3 grape candies to ensure atleast 3 of each type of candies . total = 83 candies amount required = 83 * . 1 = 8.30 $ answer a | general |
math_qa__C33LjY86rN8XbrRw | The tax on a commodity is diminished by 20% and its consumption increased by 25%. The effect on revenue is? Pick
A) 2 % decrease B) 8 % decrease C) 9 % decrease D) 0 % no change E) 2 % decrease | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(5/4) * (4/5)</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<gadget id="calculator">100 - 100</gadget>
<output>0</output>
<result>D</result> | D | 0 | The tax on a commodity is diminished by 20% and its consumption increased by 25%. The effect on revenue is? | {
"A": "2 % decrease",
"B": "8 % decrease",
"C": "9 % decrease",
"D": "0 % no change",
"E": "2 % decrease"
} | subtract(const_100, multiply(multiply(add(const_1, divide(25, const_100)), subtract(const_1, divide(20, const_100))), const_100)) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)|subtract(const_100,#5)| | "100 * 100 = 10000 80 * 125 = 10000 - - - - - - - - - - - 10000 - - - - - - - - - - - 0 100 - - - - - - - - - - - ? = > 0 % no change answer : d" | general |
math_qa__iCFeHiPC3LAuTqUD | A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3680. They completed the work in 3 days with the help of C. How much is to be paid to C? Pick one: A) s . 380 B) s . 600 C) s . 460 D) s . 400 E) s . 480 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/6) + (1/8)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">(1/3) - (7/24)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">3 * (1/24)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 3_680</gadget>
<output>460</output>
<result>C</result> | C | 460 | A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3680. They completed the work in 3 days with the help of C. How much is to be paid to C? | {
"A": "s . 380",
"B": "s . 600",
"C": "s . 460",
"D": "s . 400",
"E": "s . 480"
} | multiply(multiply(3, subtract(divide(const_1, 3), add(divide(const_1, 6), divide(const_1, 8)))), 3680) | divide(const_1,n3)|divide(const_1,n0)|divide(const_1,n1)|add(#1,#2)|subtract(#0,#3)|multiply(n3,#4)|multiply(n2,#5)| | "explanation : amount of work a can do in 1 day = 1 / 6 amount of work b can do in 1 day = 1 / 8 amount of work a + b can do in 1 day = 1 / 6 + 1 / 8 = 7 / 24 amount of work a + b + c can do = 1 / 3 amount of work c can do in 1 day = 1 / 3 - 7 / 24 = 1 / 24 work a can do in 1 day : work b can do in 1 day : work c can do in 1 day = 1 / 6 : 1 / 8 : 1 / 24 = 4 : 3 : 1 amount to be paid to c = 3680 × ( 1 / 8 ) = 460 answer : option c" | physics |
math_qa__xH2r6u9yKooQ3bXw | In what time will a train 100 meters long cross an electric pole, if its speed is 36 km/hr
Choose the correct choice: A) 8.5 seconds B) 10 seconds C) 3.5 seconds D) 2.5 seconds E) 2.6 seconds | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<result>B</result> | B | 10 | In what time will a train 100 meters long cross an electric pole, if its speed is 36 km/hr | {
"A": "8.5 seconds",
"B": "10 seconds",
"C": "3.5 seconds",
"D": "2.5 seconds",
"E": "2.6 seconds"
} | divide(100, multiply(36, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "first convert speed into m / sec speed = 36 * ( 5 / 18 ) = 10 m / sec time = distance / speed = 100 / 10 = 10 seconds answer : b" | physics |
math_qa__v8OkyX3caoH8t14k | If x/(12p) is an odd prime number, where x is a positive integer and p is a prime number, what is the least value of x?
Choose the correct choice from the following.
A) 22 B) 33 C) 44 D) 66 E) 72 | <gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">36 * 2</gadget>
<output>72</output>
<result>E</result> | E | 72 | If x/(12p) is an odd prime number, where x is a positive integer and p is a prime number, what is the least value of x? | {
"A": "22",
"B": "33",
"C": "44",
"D": "66",
"E": "72"
} | multiply(multiply(const_3, 12), const_2) | multiply(n0,const_3)|multiply(#0,const_2)| | "x / ( 12 p ) = odd prime number x = odd prime number * 11 p least value of x = lowest odd prime number * 11 * lowest value of p = 3 * 12 * 2 = 72 answer e" | general |
math_qa__1tBnefY0A2vtogsZ | Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 16 = f(x – 6) ? Pick: A) 1 B) 4 C) 6 D) 7 E) 13 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 16</gadget>
<output>26</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">18 + 5</gadget>
<output>23</output>
<gadget id="calculator">26 - 23</gadget>
<output>3</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">3 * 1</gadget>
<output>3</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">3 / 3</gadget>
<output>1</output>
<result>A</result> | A | 1 | Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 16 = f(x – 6) ? | {
"A": "1",
"B": "4",
"C": "6",
"D": "7",
"E": "13"
} | divide(subtract(add(multiply(2, 5), 16), add(multiply(3, 6), 5)), subtract(multiply(2, 3), multiply(3, const_1))) | multiply(n1,n2)|multiply(n4,n0)|multiply(n0,n2)|multiply(n0,const_1)|add(n3,#0)|add(n1,#1)|subtract(#2,#3)|subtract(#4,#5)|divide(#7,#6)| | "2 ( 3 x - 5 ) - 16 = 3 ( x - 6 ) - 5 3 x = 3 x = 1 the answer is a ." | general |
math_qa__awXP4yM09lHLecM1 | A batsman in his 12th innings makes a score of 80 and thereby increases his average by 3 runs. What is his average after the 12th innings if he had never been ‘not out’?
Choose the most appropriate option.
A) 42 B) 43 C) 44 D) 45 E) 47 | <gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">80 - 36</gadget>
<output>44</output>
<gadget id="calculator">44 + 3</gadget>
<output>47</output>
<result>E</result> | E | 47 | A batsman in his 12th innings makes a score of 80 and thereby increases his average by 3 runs. What is his average after the 12th innings if he had never been ‘not out’? | {
"A": "42",
"B": "43",
"C": "44",
"D": "45",
"E": "47"
} | add(subtract(80, multiply(12, 3)), 3) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1) | let ‘ x ’ be the average score after 12 th innings ⇒ 12 x = 11 × ( x – 3 ) + 80 ∴ x = 47 answer e | general |
math_qa__1fPH4Y0sZKv4FFqe | Each of the three people individually can complete a certain job in 4, 5, and 8 hours, respectively. What is the lowest fraction of the job that can be done in 1 hour by 2 of the people working together at their respective rates? Pick:
A) 9 / 20 B) 11 / 20 C) 11 / 32 D) 13 / 40 E) 17 / 40 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/5) + (1/8)</gadget>
<output>13/40 = around 0.325</output>
<result>D</result> | D | 0.325 | Each of the three people individually can complete a certain job in 4, 5, and 8 hours, respectively. What is the lowest fraction of the job that can be done in 1 hour by 2 of the people working together at their respective rates? | {
"A": "9 / 20",
"B": "11 / 20",
"C": "11 / 32",
"D": "13 / 40",
"E": "17 / 40"
} | add(divide(1, 5), divide(1, 8)) | divide(n3,n1)|divide(n3,n2)|add(#0,#1)| | "the two slowest people work at rates of 1 / 5 and 1 / 8 of the job per hour . the sum of these rates is 1 / 5 + 1 / 8 = 13 / 40 of the job per hour . the answer is d ." | physics |
math_qa__yvG6azlkfcCzg54v | If the ratio of a to b is 4 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? Pick one:
A) 4 / 15 B) 1 / 3 C) 2 / 5 D) 4 / 5 E) 7 / 6 | <gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">4 / 15</gadget>
<output>4/15 = around 0.266667</output>
<result>A</result> | A | 0.266667 | If the ratio of a to b is 4 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? | {
"A": "4 / 15",
"B": "1 / 3",
"C": "2 / 5",
"D": "4 / 5",
"E": "7 / 6"
} | divide(multiply(4, 1), multiply(3, 5)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1) | a : b = 4 : 3 - - 1 b : c = 1 : 5 = > b : c = 3 : 15 - - 2 from 1 and 2 , we get a : c = 4 : 15 answer a | other |
math_qa__WlxpYz6uIPVYTfXa | The H.C.F. of two numbers is 63 and the other two factors of their L.C.M. are 11 and 17. The larger of the two numbers is: Choose the correct answer:
A) 3421
B) 2132
C) 1111
D) 4323
E) 1071 | <gadget id="calculator">63 * 17</gadget>
<output>1_071</output>
<result>E</result> | E | 1,071 | The H.C.F. of two numbers is 63 and the other two factors of their L.C.M. are 11 and 17. The larger of the two numbers is: | {
"A": "3421",
"B": "2132",
"C": "1111",
"D": "4323",
"E": "1071"
} | multiply(63, 17) | multiply(n0,n2)| | ": explanation : clearly , the numbers are ( 63 x 11 ) and ( 63 x 17 ) . { \ color { blue } \ therefore } larger number = ( 63 x 17 ) = 1071 . answer : e ) 1071" | other |
math_qa__LfD2xki68brZztyQ | A rectangular swimming pool is 10 feet by 12 feet. A deck that has uniform width surrounds the pool. The total area of the pool and deck is 360 square feet. What is the width of the deck?
Select
A) 7 B) 2 C) 3 D) 4 E) 6 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 ** 2</gadget>
<output>121</output>
<gadget id="calculator">10 * 12</gadget>
<output>120</output>
<gadget id="calculator">360 - 120</gadget>
<output>240</output>
<gadget id="calculator">121 + 240</gadget>
<output>361</output>
<gadget id="calculator">361 ** (1/2)</gadget>
<output>19</output>
<gadget id="calculator">19 - 11</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>D</result> | D | 4 | A rectangular swimming pool is 10 feet by 12 feet. A deck that has uniform width surrounds the pool. The total area of the pool and deck is 360 square feet. What is the width of the deck? | {
"A": "7",
"B": "2",
"C": "3",
"D": "4",
"E": "6"
} | divide(subtract(sqrt(add(power(subtract(12, const_1), const_2), subtract(360, rectangle_area(10, 12)))), subtract(12, const_1)), const_2) | rectangle_area(n0,n1)|subtract(n1,const_1)|power(#1,const_2)|subtract(n2,#0)|add(#2,#3)|sqrt(#4)|subtract(#5,#1)|divide(#6,const_2)| | "let the width = w total area of the pool and deck = ( 2 w + 10 ) ( 2 w + 12 ) we can test the answer choices along with unit digit method a ) 2 feet . . . . . . . . . . . 14 * 16 has unit digit 4 . . . . . . . . . . eliminate b ) 2.5 feet . . . . . . . . . 15 * 17 has unit digit 5 . . . . . . . . . . eliminate c ) 3 feet . . . . . . . . . . . . 16 * 18 has unit digit 8 . . . . . . . . . . . eliminate d ) 4 feet . . . . . . . . . . . . 18 * 20 has unit digit 0 . . . . . . . . . . . hold e ) 5 feet . . . . . . . . . . . . 20 * 22 has unit digit 0 . . . . . . . . . . . eliminate ( bigger size ) answer : d w = 4" | geometry |
math_qa__pOXs7D7IAiLvFC76 | A copy machine, working at a constant rate, makes 25 copies per minute. A second copy machine, working at a constant rate, makes 55 copies per minute. Working together at their respective rates, how many copies do the two machines make in half an hour ? Choose the correct answer
A) 90 B) 2,400 C) 4,500 D) 5,400 E) 324,000 | <gadget id="calculator">25 + 55</gadget>
<output>80</output>
<gadget id="calculator">80 * 60</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 2</gadget>
<output>2_400</output>
<result>B</result> | B | 2,400 | A copy machine, working at a constant rate, makes 25 copies per minute. A second copy machine, working at a constant rate, makes 55 copies per minute. Working together at their respective rates, how many copies do the two machines make in half an hour ? | {
"A": "90",
"B": "2,400",
"C": "4,500",
"D": "5,400",
"E": "324,000"
} | divide(multiply(add(25, 55), const_60), const_2) | add(n0,n1)|multiply(#0,const_60)|divide(#1,const_2)| | "together the two machines make 25 + 55 = 80 copies per minute . so , in half an hour they will make 80 * 30 = 2,400 copies . answer : b ." | physics |
math_qa__YTOWVjmcxDt2FnSY | A student multiplied a number by 3/5 instead of 5/3. What is the percentage error. Choose the correct choice from the following choices.
A) 64 % B) 65 % C) 66 % D) 67 % E) none of these | <gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(5/3) - (3/5)</gadget>
<output>16/15 = around 1.066667</output>
<gadget id="calculator">(16/15) / (5/3)</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">(16/25) * 100</gadget>
<output>64</output>
<result>A</result> | A | 64 | A student multiplied a number by 3/5 instead of 5/3. What is the percentage error. | {
"A": "64 %",
"B": "65 %",
"C": "66 %",
"D": "67 %",
"E": "none of these"
} | multiply(divide(subtract(divide(5, 3), divide(3, 5)), divide(5, 3)), const_100) | divide(n1,n0)|divide(n0,n1)|subtract(#0,#1)|divide(#2,#0)|multiply(#3,const_100)| | "explanation : let the number be x , then , 5 / 3 − 3 / 5 = 16 / 15 x error % = ( 16 / 15 x ∗ 3 / 5 ∗ 100 ) option a" | general |
math_qa__4mbzRAHqwQKXzZtt | solve the given equation 9^y = 3^12, what is y? Options:
A) 1 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">log(9)</gadget>
<output>log(9) = around 2.197225</output>
<gadget id="calculator">log(3)</gadget>
<output>log(3) = around 1.098612</output>
<gadget id="calculator">log(9) / log(3)</gadget>
<output>log(9)/log(3) = around 2</output>
<gadget id="calculator">12 / (log(9)/log(3))</gadget>
<output>12*log(3)/log(9) = around 6</output>
<result>E</result> | E | 6 | solve the given equation 9^y = 3^12, what is y? | {
"A": "1",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(12, divide(log(9), log(3))) | log(n0)|log(n1)|divide(#0,#1)|divide(n2,#2) | 3 ^ 2 y = 3 ^ 12 2 y = 12 , therefore y = 6 e | general |
math_qa__dqH4G4Jt6Y5mcWL4 | The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each? Choose the correct choice from the following options.
A) 2277 B) 2977 C) 2677 D) 4530 E) 1971 | <gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">15 + 25</gadget>
<output>40</output>
<gadget id="calculator">24 * 40</gadget>
<output>960</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">960 - 18</gadget>
<output>942</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">942 - 36</gadget>
<output>906</output>
<gadget id="calculator">906 * 5</gadget>
<output>4_530</output>
<result>D</result> | D | 4,530 | The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each? | {
"A": "2277",
"B": "2977",
"C": "2677",
"D": "4530",
"E": "1971"
} | multiply(subtract(subtract(multiply(multiply(const_2, 12), add(15, 25)), multiply(6, 3)), multiply(3, multiply(4, 3))), 5) | add(n0,n1)|multiply(n2,const_2)|multiply(n4,n5)|multiply(n5,n6)|multiply(#0,#1)|multiply(n5,#3)|subtract(#4,#2)|subtract(#6,#5)|multiply(n3,#7)| | "area of the four walls = 2 h ( l + b ) since there are doors and windows , area of the walls = 2 * 12 ( 15 + 25 ) - ( 6 * 3 ) - 3 ( 4 * 3 ) = 906 sq . ft . total cost = 906 * 5 = rs . 4530 answer : d" | geometry |
math_qa__FllaXtIMLJPcN9dx | A, B and C started a partnership business by investing Rs.30000, Rs.45000, Rs.50000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit?
Select the correct option
A) 70000
B) 60000
C) 80000
D) 90000
E) 50000 | <gadget id="calculator">30_000 / 50_000</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 36_000</gadget>
<output>21_600</output>
<gadget id="calculator">45_000 / 50_000</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 36_000</gadget>
<output>32_400</output>
<gadget id="calculator">21_600 + 32_400</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 + 36_000</gadget>
<output>90_000</output>
<result>D</result> | D | 90,000 | A, B and C started a partnership business by investing Rs.30000, Rs.45000, Rs.50000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit? | {
"A": "70000",
"B": "60000",
"C": "80000",
"D": "90000",
"E": "50000"
} | add(add(multiply(divide(30000, 50000), 36000), multiply(divide(45000, 50000), 36000)), 36000) | divide(n0,n2)|divide(n1,n2)|multiply(n3,#0)|multiply(n3,#1)|add(#2,#3)|add(n3,#4)| | "a : b : c = 30000 : 45000 : 50000 = 6 : 9 : 10 let total profit = p then p ã — 10 / 25 = 36000 p = ( 36000 ã — 25 ) / 10 = 90000 answer is d ." | gain |
math_qa__gHX5cHjdPkwsdhhN | If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 4 is subtracted and divided by 10? Pick
A) 4 B) 7 C) 8 D) 5 E) 3 | <gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">49 + 5</gadget>
<output>54</output>
<gadget id="calculator">54 - 4</gadget>
<output>50</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<result>D</result> | D | 5 | If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 4 is subtracted and divided by 10? | {
"A": "4",
"B": "7",
"C": "8",
"D": "5",
"E": "3"
} | divide(subtract(add(multiply(7, 7), 5), 4), 10) | multiply(n1,n1)|add(n0,#0)|subtract(#1,n3)|divide(#2,n4)| | "explanation : let the number be x . then , ( x - 5 ) / 7 = 7 = > x - 5 = 49 x = 54 . : ( x - 4 ) / 10 = ( 54 - 4 ) / 10 = 5 answer : option d" | general |
math_qa__HAOYE25lTDCTujWR | Integer m has 4 different prime factors and n has 3 different prime factors. If m and n has the greatest common factor of 15, how many different prime factors does mn have? Choices
A) 4
B) 5
C) 6
D) 7
E) 8 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<result>B</result> | B | 5 | Integer m has 4 different prime factors and n has 3 different prime factors. If m and n has the greatest common factor of 15, how many different prime factors does mn have? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | add(4, const_1) | add(n0,const_1) | as m and n has gcf of 15 , 3 * 5 should be common factor for both m and n . m = 3 * 5 * p 1 * p 2 n = 3 * 5 * p 3 mn = 3 ^ 2 * 5 ^ 2 * p 1 * p 2 * p 3 mn has prime numbers of 3,5 , p 1 , p 2 p 3 b | other |
math_qa__i5EHj1H0eB0PjaGC | On a sum of money, the S.I. for 2 years is $600, while the C.I. is $609, the rate of interest being the same in both the cases. The rate of interest is?
Select the correct option:
A) 2 % B) 3 % C) 4 % D) 5 % E) 6 % | <gadget id="calculator">609 - 600</gadget>
<output>9</output>
<gadget id="calculator">100 * 9</gadget>
<output>900</output>
<gadget id="calculator">600 / 2</gadget>
<output>300</output>
<gadget id="calculator">900 / 300</gadget>
<output>3</output>
<result>B</result> | B | 3 | On a sum of money, the S.I. for 2 years is $600, while the C.I. is $609, the rate of interest being the same in both the cases. The rate of interest is? | {
"A": "2 %",
"B": "3 %",
"C": "4 %",
"D": "5 %",
"E": "6 %"
} | divide(multiply(const_100, subtract(609, 600)), divide(600, 2)) | divide(n1,n0)|subtract(n2,n1)|multiply(#1,const_100)|divide(#2,#0)| | "difference in c . i . and s . i for 2 years = $ 609 - $ 600 = $ 9 s . i for one year = $ 300 s . i . on $ 300 for 1 year = $ 9 rate = ( 100 * 9 ) / ( 300 ) = 3 % the answer is b ." | gain |
math_qa__LB1YwoBtT1At8sPy | In Arun's opinion, his weight is greater than 62 kg but leas than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 65 kg. If all of them are correct in their estimation, what is the average of diferent probable weights of Arun ? Choose the correct choice from the following choices:
A) 86.5 kg B) 63.5 kg C) 46.5 kg D) 26.5 kg E) 16.5 kg | <gadget id="calculator">62 + 1</gadget>
<output>63</output>
<gadget id="calculator">65 + 63</gadget>
<output>128</output>
<gadget id="calculator">128 / 2</gadget>
<output>64</output>
<result>B</result> | B | 63.5 | In Arun's opinion, his weight is greater than 62 kg but leas than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 65 kg. If all of them are correct in their estimation, what is the average of diferent probable weights of Arun ? | {
"A": "86.5 kg",
"B": "63.5 kg",
"C": "46.5 kg",
"D": "26.5 kg",
"E": "16.5 kg"
} | divide(add(65, add(62, const_1)), const_2) | add(n0,const_1)|add(n4,#0)|divide(#1,const_2)| | "let arun ' s weight be x kg . according to arun , 62 < x < 72 . according to arun ' s brother , 60 < x < 70 . according to arun ' s mother , x < 65 . the values satisfying all the above conditions are 63 and 64 . required average = ( 63 + 64 ) / 2 = 63.5 kg answer : b" | general |
math_qa__1fWH79DA8KmYyJ4t | X and Y are two towns. Ganesh covers the distance from X to Y at an average speed of 60 Km/hr. However, he covers the distance from Y to X at an average speed of 36 Km/hr. His average speed during the whole journey in km/hr. is :
Answers:
A) 45 B) 43 C) 40 D) 38 E) 29 | <gadget id="calculator">60 - 10</gadget>
<output>50</output>
<gadget id="calculator">50 + 100</gadget>
<output>150</output>
<gadget id="calculator">150 + 150</gadget>
<output>300</output>
<gadget id="calculator">150 / 60</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">150 / 36</gadget>
<output>25/6 = around 4.166667</output>
<gadget id="calculator">(5/2) + (25/6)</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">300 / (20/3)</gadget>
<output>45</output>
<result>A</result> | A | 45 | X and Y are two towns. Ganesh covers the distance from X to Y at an average speed of 60 Km/hr. However, he covers the distance from Y to X at an average speed of 36 Km/hr. His average speed during the whole journey in km/hr. is : | {
"A": "45",
"B": "43",
"C": "40",
"D": "38",
"E": "29"
} | divide(add(add(subtract(60, const_10), const_100), add(subtract(60, const_10), const_100)), add(divide(add(subtract(60, const_10), const_100), 60), divide(add(subtract(60, const_10), const_100), 36))) | subtract(n0,const_10)|add(#0,const_100)|add(#1,#1)|divide(#1,n0)|divide(#1,n1)|add(#3,#4)|divide(#2,#5) | solution : average speed = 2 xy / x + y = 2 * 60 * 36 / 60 + 36 = 45 answer : a | general |
math_qa__9eemDQ5QhBmdd4su | Two cylinders are of the same height. Their radii are in the ratio 1: 3. If the volume of the first cylinder is 40 cc. Find the volume of the second cylinder? Pick: A) 360 cc B) 60 cc C) 300 cc D) 36 cc E) 39 cc | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">40 * 9</gadget>
<output>360</output>
<result>A</result> | A | 360 | Two cylinders are of the same height. Their radii are in the ratio 1: 3. If the volume of the first cylinder is 40 cc. Find the volume of the second cylinder? | {
"A": "360 cc",
"B": "60 cc",
"C": "300 cc",
"D": "36 cc",
"E": "39 cc"
} | multiply(40, multiply(3, 3)) | multiply(n1,n1)|multiply(n2,#0) | r 1 = x r 2 = 3 x π * x 2 * h = 40 π 9 x 2 h = 40 * 9 = 360 answer : a | geometry |
math_qa__bgVOdUxNgeAmshrq | A grocer has a sale of Rs. 2500, Rs. 4000, Rs. 3540 for 3 consecutive months. How much sale must he have in the fourth month so that he gets an average sale of Rs. 2890?
Choose the correct choice from the following: A) rs . 3500 B) rs . 1520 C) rs . 4996 D) rs . 4000 E) rs . 900 | <gadget id="calculator">2_890 * 4</gadget>
<output>11_560</output>
<gadget id="calculator">11_560 - 2_500</gadget>
<output>9_060</output>
<gadget id="calculator">9_060 - 4_000</gadget>
<output>5_060</output>
<gadget id="calculator">5_060 - 3_540</gadget>
<output>1_520</output>
<result>B</result> | B | 1,520 | A grocer has a sale of Rs. 2500, Rs. 4000, Rs. 3540 for 3 consecutive months. How much sale must he have in the fourth month so that he gets an average sale of Rs. 2890? | {
"A": "rs . 3500",
"B": "rs . 1520",
"C": "rs . 4996",
"D": "rs . 4000",
"E": "rs . 900"
} | subtract(subtract(subtract(multiply(2890, const_4), 2500), 4000), 3540) | multiply(n4,const_4)|subtract(#0,n0)|subtract(#1,n1)|subtract(#2,n2) | total sale for 5 months = rs . ( 2500 + 4000 + 3540 ) = rs . 10040 . required sale = rs . [ ( 2890 x 4 ) - 10040 ] = rs . ( 11560 - 10040 ) = rs . 1520 . b ) | general |
math_qa__CLSnY6gLgSinqJOR | The volume of a cube is 3375 cc. Find its surface. Options
A) 1350 B) 1150 C) 1456 D) 1254 E) 1489 | <gadget id="calculator">3_375 ** (1/3)</gadget>
<output>15</output>
<gadget id="calculator">6 * (15 ** 2)</gadget>
<output>1_350</output>
<result>A</result> | A | 1,350 | The volume of a cube is 3375 cc. Find its surface. | {
"A": "1350",
"B": "1150",
"C": "1456",
"D": "1254",
"E": "1489"
} | surface_cube(cube_edge_by_volume(3375)) | cube_edge_by_volume(n0)|surface_cube(#0)| | a 3 = 3375 = > a = 15 6 a 2 = 6 * 15 * 15 = 1350 answer : a | geometry |
math_qa__ZvFX7mQT1x4wEWA1 | (0.76)(power 3) - (0.1)(power 3)/ (0.76)(power 2) + 0.076 + (0.1)(power 2) is: Pick: A) 0.66 B) 0.68 C) 0.96 D) 0.69 E) 0.76 | <gadget id="calculator">0.76 ** 3</gadget>
<output>0.438976</output>
<gadget id="calculator">0.1 ** 3</gadget>
<output>0.001</output>
<gadget id="calculator">0.438976 - 0.001</gadget>
<output>0.437976</output>
<gadget id="calculator">0.76 ** 2</gadget>
<output>0.5776</output>
<gadget id="calculator">0.5776 + 0.076</gadget>
<output>0.6536</output>
<gadget id="calculator">0.1 ** 2</gadget>
<output>0.01</output>
<gadget id="calculator">0.6536 + 0.01</gadget>
<output>0.6636</output>
<gadget id="calculator">0.437976 / 0.6636</gadget>
<output>0.66</output>
<result>A</result> | A | 0.66 | (0.76)(power 3) - (0.1)(power 3)/ (0.76)(power 2) + 0.076 + (0.1)(power 2) is: | {
"A": "0.66",
"B": "0.68",
"C": "0.96",
"D": "0.69",
"E": "0.76"
} | divide(subtract(power(0.76, 3), power(0.1, 3)), add(add(power(0.76, 2), 0.076), power(0.1, 2))) | power(n0,n1)|power(n2,n1)|power(n0,n5)|power(n2,n5)|add(n6,#2)|subtract(#0,#1)|add(#4,#3)|divide(#5,#6)| | "given expression = ( 0.76 ) ( power 3 ) - ( 0.1 ) ( power 3 ) / ( 0.76 ) ( power 2 ) + ( 0.76 x 0.1 ) + ( 0.1 ) ( power 2 ) = a ( power 3 ) - b ( power 3 ) / a ( power 2 ) + ab + b ( power 2 ) = ( a - b ) = ( 0.76 - 0.1 ) = 0.66 answer is a ." | general |
math_qa__AfeZh7qrYjLyL0lI | One-third of 1206 is what percent of 134 ? Select the correct option: A) 3 B) 30 C) 300 D) none of these E) can not be determined | <gadget id="calculator">1_206 / 3</gadget>
<output>402</output>
<gadget id="calculator">402 / 134</gadget>
<output>3</output>
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<result>C</result> | C | 300 | One-third of 1206 is what percent of 134 ? | {
"A": "3",
"B": "30",
"C": "300",
"D": "none of these",
"E": "can not be determined"
} | multiply(const_100, divide(divide(1206, const_3), 134)) | divide(n0,const_3)|divide(#0,n1)|multiply(#1,const_100)| | "answer let one - third of 1206 is n % of 134 . ∵ 1206 / 3 = ( n x 134 ) / 100 ∴ n = ( 402 x 100 ) / 134 = 300 correct option : c" | gain |
math_qa__3OpNRaJYJ7Y9C5MG | the digit sum of the year 2007 is 2 + 0 + 0 + 7 = 9 , which is a square number . how many years during the 20 - first century have a square digital sum ? Answers
A) 13 B) 14 C) 15 D) 16 E) 17 | <gadget id="calculator">9 + 7</gadget>
<output>16</output>
<result>D</result> | D | 16 | the digit sum of the year 2007 is 2 + 0 + 0 + 7 = 9 , which is a square number . how many years during the 20 - first century have a square digital sum ? | {
"A": "13",
"B": "14",
"C": "15",
"D": "16",
"E": "17"
} | add(9, 7) | add(n4,n5) | the twenty - first century runs from the year 2001 to 2100 inclusive , so with the exception of the year 2100 , for which the digital sum is three anyway , the first two digits of all the other years are fixed as 20 . hence for the sum of all the digits to be square the sum of the last two digits number be two less than a perfect square . as the maximum sum of the last two digits is 18 , the greatest sum will be 20 . therefore we can obtain digital sums of 4 , 9 , or 16 , with the last two digits adding to 2 , 7 , or 14 respectively . 4 : 2002 , 2011 , 2020 9 : 2007 , 2016 , 2025 , 2034 , 2043 , 2052 , 2061 , 2070 16 : 2059 , 2068 , 2077 , 2086 , 2095 that is , there are sixteen years during the twenty - first century for which the digital sum is square . answer : d | general |
math_qa__3DwRfkRYOvbxggEV | A certain automobile company’s best-selling model is the Speedster. The Speedster, like all of their other models, comes in coupe and convertible styles. 2/3 of the current inventory is Speedsters, of which 4/5 are convertibles. If there are 40 vehicles that are not Speedsters, how many Speedster convertibles are there? Choose the correct option: A) 30 B) 64 C) 60 D) 70 E) 90 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">40 / (1/3)</gadget>
<output>120</output>
<gadget id="calculator">120 * (2/3)</gadget>
<output>80</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">80 * (4/5)</gadget>
<output>64</output>
<result>B</result> | B | 64 | A certain automobile company’s best-selling model is the Speedster. The Speedster, like all of their other models, comes in coupe and convertible styles. 2/3 of the current inventory is Speedsters, of which 4/5 are convertibles. If there are 40 vehicles that are not Speedsters, how many Speedster convertibles are there? | {
"A": "30",
"B": "64",
"C": "60",
"D": "70",
"E": "90"
} | multiply(multiply(divide(40, subtract(const_1, divide(2, 3))), divide(2, 3)), divide(4, 5)) | divide(n2,n3)|divide(n0,n1)|subtract(const_1,#1)|divide(n4,#2)|multiply(#3,#1)|multiply(#0,#4) | total vehicle = 2 / 3 of speedster + 1 / 3 of others . speedster convertibles = 2 / 3 total vehicle * 4 / 5 given : 1 / 3 constitutes 40 vehicles . hence 2 / 3 constitutes 80 speedster convertibls = 80 * 4 / 5 = 64 b | physics |
math_qa__22DpMXgLbQnSUi2Q | Earl can stuff advertising circulars into envelopes at the rate of 36 envelopes per minutes and Ellen requires a minutes and half to stuff the same number of envelops.Working together,how long will it take Earl and Ellen to stuff 180 envelopes Choose the correct choice from the following options:
A) 6 minutes
B) 5 minutes
C) 7 minutes
D) 3 minutes
E) 4 minutes | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">36 / (3/2)</gadget>
<output>24</output>
<gadget id="calculator">36 + 24</gadget>
<output>60</output>
<gadget id="calculator">180 / 60</gadget>
<output>3</output>
<result>D</result> | D | 3 | Earl can stuff advertising circulars into envelopes at the rate of 36 envelopes per minutes and Ellen requires a minutes and half to stuff the same number of envelops.Working together,how long will it take Earl and Ellen to stuff 180 envelopes | {
"A": "6 minutes",
"B": "5 minutes",
"C": "7 minutes",
"D": "3 minutes",
"E": "4 minutes"
} | divide(180, add(36, divide(36, divide(const_3, const_2)))) | divide(const_3,const_2)|divide(n0,#0)|add(n0,#1)|divide(n1,#2) | earl takes 1 min . for 36 envelopes . ellen takes 3 / 2 mins for the same . so ellen can stuff ( ( 36 ) / ( 3 / 2 ) ) in 1 min . i . e . , 24 envelopes a min . so both of them when work together can stuff 36 + 24 = 60 envelopes in 1 min . for 180 envelopes they will take 180 / 60 mins . i . e . , 3 mins . answer : d | physics |
math_qa__IqD3z1IY5HdEwrWQ | Boy sells a book for Rs. 810 he gets a loss of 10 %, To gain 10%, what should be the SP? Choose the correct option:
A) 430
B) 990
C) 550
D) 590
E) 600 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">810 / (9/10)</gadget>
<output>900</output>
<gadget id="calculator">900 * (1/10)</gadget>
<output>90</output>
<gadget id="calculator">900 + 90</gadget>
<output>990</output>
<result>B</result> | B | 990 | Boy sells a book for Rs. 810 he gets a loss of 10 %, To gain 10%, what should be the SP? | {
"A": "430",
"B": "990",
"C": "550",
"D": "590",
"E": "600"
} | add(divide(810, subtract(const_1, divide(10, const_100))), multiply(divide(810, subtract(const_1, divide(10, const_100))), divide(10, const_100))) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_1,#0)|divide(n0,#2)|multiply(#3,#1)|add(#3,#4)| | "cost price = 810 / 90 x 100 = 900 to gain 10 % = 900 x 10 / 100 = 90 sp = cp + gain = 900 + 90 = 990 answer : b" | gain |
math_qa__krlWRPUzVNbnBoGR | How many pieces of 85 cm length can be cut from a rod of 34 meters long? Choose the correct choice from the following answers:
A) 50 B) 40 C) 30 D) 20 E) 10 | <gadget id="calculator">34 * 100</gadget>
<output>3_400</output>
<gadget id="calculator">3_400 / 85</gadget>
<output>40</output>
<result>B</result> | B | 40 | How many pieces of 85 cm length can be cut from a rod of 34 meters long? | {
"A": "50",
"B": "40",
"C": "30",
"D": "20",
"E": "10"
} | divide(multiply(34, const_100), 85) | multiply(n1,const_100)|divide(#0,n0)| | "number of pieces = 3400 / 85 = 40 the answer is b ." | physics |
math_qa__4df6HTd1mjWZ0KbT | If 525/999=0.525, what is the 81st digit to the right of the decimal point in the decimal equivalent of the fraction? Choose the correct choice from the following
A) - 1 B) 0 C) 3 D) 4 E) 5 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<result>E</result> | E | 5 | If 525/999=0.525, what is the 81st digit to the right of the decimal point in the decimal equivalent of the fraction? | {
"A": "- 1",
"B": "0",
"C": "3",
"D": "4",
"E": "5"
} | add(const_2, const_3) | add(const_2,const_3)| | "0 . [ u ] 125 [ / u = 0.525525525 . . . . . every 3 rd digit is 5 and every multiple of 3 will be the digit 5 . since 81 is multiple of 3 , the 81 st digit is 5 . answer e" | general |
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