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stringclasses 5
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Geometry | Find the number of vertices of a pentagonal prism. | 10 | 5 2 [OP_MUL] | var_a = 5
var_b = 2
var_c = var_a * var_b
print(int(var_c)) |
Possibility | Choose 3 of the following number cards 5, 3, 6, 8 to form a three-digit number. When writing the numbers in order from smallest, find the 10th number. | 568 | [OP_LIST_SOL] 5 3 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 [OP_LIST_MIN] | var_a = 5
var_b = 3
var_c = 6
var_d = 8
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 10
list_c=list_b.copy()
list_c.sort()
var_g = list_c[var_f-1]
print(int(var_g)) |
Correspondence | A number needs to be multiplied by 3, but you accidentally multiplied it by 6 and it ended up being 42. What is the correct calculation result? | 21 | 42 6 [OP_DIV] 3 [OP_MUL] | var_a = 42
var_b = 6
var_c = var_a / var_b
var_d = 3
var_e = var_c * var_d
print(int(var_e)) |
Correspondence | How many A's are there when 3×4<3×A<40, and 4/3>4/A>4/6? | 1 | 3×4<3×A<40 A [OP_NUM_UNK_SOLVER] 4/3>4/A>4/6 A [OP_NUM_UNK_SOLVER] [OP_SET_INTERSECT] [OP_LIST_LEN] | var_a = '3×4<3×A<40'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = []
candidate_num = [i for i in range(51)]
candi = list(itertools.product(candidate_num, repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
if term_list[i] == '':
new_eq += str(term_list[i])+op_list[i]
else:
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:
new_eq=new_eq.replace('==','=')
new_eq=new_eq.replace('>','')
new_eq=new_eq.replace('<','')
new_eq=new_eq.split('=')
for i in range(len(new_eq)-1):
eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))
if not eval_result:
break
else:
eval_result = eval(new_eq)
except:
eval_result = False
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k].append(int(c[i]))
list_a = list(set(ans_dict[var_b]))
var_c = '4/3>4/A>4/6'
var_d = 'A'
ans_dict = dict()
var_c = var_c.replace('×','*')
var_c = var_c.replace('x','*')
var_c = var_c.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_c):
if v in variable_candi:
ans_dict[v] = []
candidate_num = [i for i in range(51)]
candi = list(itertools.product(candidate_num, repeat=len(ans_dict)))
for c in candi:
temp = var_c
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
if term_list[i] == '':
new_eq += str(term_list[i])+op_list[i]
else:
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:
new_eq=new_eq.replace('==','=')
new_eq=new_eq.replace('>','')
new_eq=new_eq.replace('<','')
new_eq=new_eq.split('=')
for i in range(len(new_eq)-1):
eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))
if not eval_result:
break
else:
eval_result = eval(new_eq)
except:
eval_result = False
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k].append(int(c[i]))
list_b = list(set(ans_dict[var_d]))
list_c = list(set(list_a) & set(list_b))
var_e = len(list_c)
print(int(var_e)) |
Correspondence | There are pigs and chickens on Seungwoo's farm. Chickens outnumber pigs by 12. Also, the sum of the number of chickens and the number of pigs is 40 more than 12. Find the product of the number of chickens and the number of pigs. | 640 | 40 2 [OP_DIV] 12 [OP_ADD] 40 2 [OP_DIV] [OP_MUL] | var_a = 40
var_b = 2
var_c = var_a / var_b
var_d = 12
var_e = var_c + var_d
var_f = 40
var_g = 2
var_h = var_f / var_g
var_i = var_e * var_h
print(int(var_i)) |
Correspondence | Hyejin's monthly evaluation score is 82 for ethics, 90 for Korean language, 88 for science, and 84 for social studies. The score for mathematics is unknown. When the average score is 88, what is the score for mathematics? | 96 | 88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB] | var_a = 88
var_b = 5
var_c = var_a * var_b
var_d = 82
var_e = var_c - var_d
var_f = 90
var_g = var_e - var_f
var_h = 88
var_i = var_g - var_h
var_j = 84
var_k = var_i - var_j
print(int(var_k)) |
Comparison | Jisoo and Yoongi rode bicycles. The two started from the same place, Yoongi ran 22 kilometers (km) in one hour, and Jisoo ran 19,000 meters (m) in one hour. Who rode more? | Jisoo | [OP_LIST_SOL] Jisoo Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 22 1000 [OP_MUL] 19000 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jisoo'
var_b = 'Yoongi'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 22
var_d = 1000
var_e = var_c * var_d
var_f = 19000
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Geometry | Some polygons are said to have six diagonals drawn from one vertex. How many vertices does this polygon have? | 9 | 6 3 [OP_ADD] | var_a = 6
var_b = 3
var_c = var_a + var_b
print(int(var_c)) |
Geometry | There is a bill with a width of 3 centimeters (cm) and an area of 1.77 square centimeters (cm2). How many centimeters (cm) is the length of this bill? | 0.59 | 1.77 3 [OP_DIV] | var_a = 1.77
var_b = 3
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | Three of the number cards from 1 to 9 were drawn to make the number 735. How many number cards drawn have a value greater than 4? | 2 | 735 [OP_NUM2LIST] 4 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 735
list_a = []
var_a = int(var_a)
while var_a//10 > 0:
list_a.append(var_a%10)
var_a = var_a//10
list_a.append(var_a%10)
list_a = list_a[::-1]
var_b = 4
list_b = []
for i in list_a:
if i > var_b:
list_b.append(i)
var_c = len(list_b)
print(int(var_c)) |
Geometry | One piece of colored paper is a square with sides measuring 30 centimeters (cm). What is the area of this piece of colored paper? | 900 | 30 2 [OP_POW] | var_a = 30
var_b = 2
var_c = var_a ** var_b
print(int(var_c)) |
Correspondence | The equation A85-2B=364 makes. What number should go in A? | 3 | A85-2B=364 A [OP_DIGIT_UNK_SOLVER] | var_a = 'A85-2B=364'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Geometry | The diameter of a circle is 26 centimeters (cm). Then how long is the radius in centimeters (cm)? | 13 | 26 2 [OP_DIV] | var_a = 26
var_b = 2
var_c = var_a / var_b
print(int(var_c)) |
Comparison | 4 students said one number each. The sum is 531, and the sum of the numbers uttered by the first student and the second student is 31 greater than the sum of the numbers spoken by the third and fourth students, and the third student said a number 22 greater than that of the fourth student. What number did the third student say? | 136 | 531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD] | var_a = 531
var_b = 31
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 22
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
var_j = 22
var_k = var_i + var_j
print(int(var_k)) |
Arithmetic calculation | If we divide the father's age by the son's age, the result was 3, 7 years ago. Their ages will combine to 74 after 8 years. What will be the age of the father in 8 years' time? | 48 | 74 8 2 [OP_MUL] [OP_SUB] 7 2 [OP_MUL] [OP_SUB] 3 1 [OP_ADD] [OP_FDIV] 3 [OP_MUL] 7 [OP_ADD] 8 [OP_ADD] | var_a = 74
var_b = 8
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 7
var_g = 2
var_h = var_f * var_g
var_i = var_e - var_h
var_j = 3
var_k = 1
var_l = var_j + var_k
var_m = var_i // var_l
var_n = 3
var_o = var_m * var_n
var_p = 7
var_q = var_o + var_p
var_r = 8
var_s = var_q + var_r
print(int(var_s)) |
Correspondence | I need to subtract 32 from a certain number, but I mistakenly subtracted 23, so I got 14. Find the number. | 37 | 14 23 [OP_ADD] | var_a = 14
var_b = 23
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | What number must be in B to make A3B-41=591? | 2 | A3B-41=591 B [OP_DIGIT_UNK_SOLVER] | var_a = 'A3B-41=591'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Geometry | There are three points that are not on a straight line. How many straight lines are possible with these three points? | 3 | 3 2 [OP_COMB] | var_a = 3
var_b = 2
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c)) |
Possibility | What is the largest number that can be made by using the number cards 7 and 3 all once? | 73 | [OP_LIST_SOL] 7 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] | var_a = 7
var_b = 3
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = 1
list_c=list_b.copy()
list_c.sort()
var_e = list_c[-var_d]
print(int(var_e)) |
Correspondence | If you multiply a variable by 5 and then by 7, you get 5 and 4/9. Find the variable to two decimal places. | 0.16 | 5 4/9 [OP_ADD] 7 [OP_DIV] 5 [OP_DIV] | var_a = 5
var_b = 0.4444444444444444
var_c = var_a + var_b
var_d = 7
var_e = var_c / var_d
var_f = 5
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Arithmetic calculation | What is the largest two-digit number that is both a multiple of 3 and a multiple of 5? | 90 | 10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] | var_a = 10
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 1
list_d=list_c.copy()
list_d.sort()
var_g = list_d[-var_f]
print(int(var_g)) |
Possibility | Among the single-digit natural numbers A, B, and C, count the number of A, B, and C that satisfies A + B + C < 7. | 20 | 1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 7 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 7
list_d = []
for i in list_c:
if i < var_f:
list_d.append(i)
var_g = len(list_d)
print(int(var_g)) |
Geometry | There is a flower garden in the shape of a rectangle measuring 5 meters (m) long and 17/20 meters (m) wide. Find the area in square centimeters (cm2) of this flower field. | 42500 | 5 17/20 [OP_MUL] 100 100 [OP_MUL] [OP_MUL] | var_a = 5
var_b = 0.85
var_c = var_a * var_b
var_d = 100
var_e = 100
var_f = var_d * var_e
var_g = var_c * var_f
print(int(var_g)) |
Arithmetic calculation | There are six numbers 3/2, 2.3, 1/5, 1.1, 5/2, 4/5. How many of these numbers are greater than 1 and less than 2? | 2 | [OP_LIST_SOL] 3/2 2.3 1/5 1.1 5/2 4/5 [OP_LIST_EOL] 1 [OP_LIST_MORE] 2 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 1.5
var_b = 2.3
var_c = 0.2
var_d = 1.1
var_e = 2.5
var_f = 0.8
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 1
list_b = []
for i in list_a:
if i > var_g:
list_b.append(i)
var_h = 2
list_c = []
for i in list_b:
if i < var_h:
list_c.append(i)
var_i = len(list_c)
print(int(var_i)) |
Correspondence | Find the value, including the decimal point, of subtracting the possible smallest from the largest of the two decimal numbers that becomes 1.7 when rounded to two decimal places. | 0.09 | 1.74 1.65 [OP_SUB] | var_a = 1.74
var_b = 1.65
var_c = var_a - var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | What is the sum of 8 groups of 100 and 7 groups of 10 and count it 5 jumps in increments of 10? | 920 | 100 8 [OP_MUL] 10 7 [OP_MUL] [OP_ADD] 10 5 [OP_MUL] [OP_ADD] | var_a = 100
var_b = 8
var_c = var_a * var_b
var_d = 10
var_e = 7
var_f = var_d * var_e
var_g = var_c + var_f
var_h = 10
var_i = 5
var_j = var_h * var_i
var_k = var_g + var_j
print(int(var_k)) |
Arithmetic calculation | How many natural numbers from 1 to 100 have a remainder of 2 when divided by 5? | 20 | 1 100 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN] | var_a = 1
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 5
var_e = 2
list_b = []
var_d = int(var_d)
var_e = int(var_e)
if var_e < 0:
var_e = var_e + var_d
for i in list_a:
i = int(i)
if i%var_d == var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Arithmetic calculation | Machine A makes 8 products per minute, and machine B makes 10 products per minute. When started making products at the same time, machine B made 100 products. How many more products did machine B make than machine A? | 20 | 100 100 10 [OP_DIV] 8 [OP_MUL] [OP_SUB] | var_a = 100
var_b = 100
var_c = 10
var_d = var_b / var_c
var_e = 8
var_f = var_d * var_e
var_g = var_a - var_f
print(int(var_g)) |
Comparison | Jungkook collected 6 divided by 3, Yoongi collected 4, and Yuna collected 5. Who got the biggest number? | Yuna | [OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Yoongi'
var_c = 'Yuna'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 6
var_e = 3
var_f = var_d // var_e
var_g = 4
var_h = 5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Comparison | There are 15 consecutive natural numbers between 52 and a certain number. If the certain number is greater than 52, which number is in the middle between 52 and the certain number? | 60 | 52 15 [OP_ADD] 1 [OP_ADD] 52 [OP_ADD] 2 [OP_DIV] | var_a = 52
var_b = 15
var_c = var_a + var_b
var_d = 1
var_e = var_c + var_d
var_f = 52
var_g = var_e + var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Comparison | The academy is on the 7th floor. The reading room is 4 floors higher than the academy, and the bookstore is 9 floors lower than the reading room. What floor is the bookstore on? | 2 | 7 4 [OP_ADD] 9 [OP_SUB] | var_a = 7
var_b = 4
var_c = var_a + var_b
var_d = 9
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | The number of questions answered by 6 people in Dongwoo's group is 16, 22, 30, 26, 18, and 20. On average, how many questions did Dongwoo's group get right? | 22 | [OP_LIST_SOL] 16 22 30 26 18 20 [OP_LIST_EOL] [OP_LIST_MEAN] | var_a = 16
var_b = 22
var_c = 30
var_d = 26
var_e = 18
var_f = 20
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
list_a = [float(i) for i in list_a]
var_g = sum(list_a)/len(list_a)
print(int(var_g)) |
Correspondence | The four-digit number 2A3A is a multiple of 9. What is A? | 2 | 2A3A [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] 2A3A A [OP_LIST_FIND_UNK] | var_a = '2A3A'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 9
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = '2A3A'
var_d = 'A'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
var_e = 0
for elem in list_b:
elem = str(elem)
var_e = int(elem[unk_idx])
print(int(var_e)) |
Correspondence | Subtract 263 from a certain number and add 419, resulting in 725. Find the number. | 569 | 725 419 [OP_SUB] 263 [OP_ADD] | var_a = 725
var_b = 419
var_c = var_a - var_b
var_d = 263
var_e = var_c + var_d
print(int(var_e)) |
Correspondence | A factory is trying to pack pencils, but if you pack them in 5 units, 4 will remain, if you pack in 7 units, 6 units will remain, and if you pack in 8 units, 7 units will remain. If the number of pencils made by this factory is the smallest natural number between 1000 and 9999, how many pencils are there? | 1119 | 1000 9999 1 [OP_LIST_ARANGE] 8 7 [OP_LIST_DIVIDE_AND_REMAIN] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 5 -1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN] | var_a = 1000
var_b = 9999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 8
var_e = 7
list_b = []
var_d = int(var_d)
var_e = int(var_e)
if var_e < 0:
var_e = var_e + var_d
for i in list_a:
i = int(i)
if i%var_d == var_e:
list_b.append(i)
var_f = 7
var_g = 6
list_c = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_b:
i = int(i)
if i%var_f == var_g:
list_c.append(i)
var_h = 5
var_i = -1
list_d = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_c:
i = int(i)
if i%var_h == var_i:
list_d.append(i)
var_j = 1
list_e=list_d.copy()
list_e.sort()
var_k = list_e[var_j-1]
print(int(var_k)) |
Geometry | A friend gave the following problem to Taewon. "One of the edges of the regular hexagonal pyramid is 8 centimeters (cm) and the other is 13 centimeters (cm). So what is the sum of all the edges of the regular hexagonal pyramid?" What should Taewon answer to get the problem right? | 126 | 13 6 [OP_MUL] 8 6 [OP_MUL] [OP_ADD] | var_a = 13
var_b = 6
var_c = var_a * var_b
var_d = 8
var_e = 6
var_f = var_d * var_e
var_g = var_c + var_f
print(int(var_g)) |
Comparison | Four students: Jimin, Yoongi, Taehyung, and Namjoon, are standing in a line. Yoongi stands ahead of Namjoon, and Jimin is ahead of Yoongi. If Taehyung is behind Namjoon, who stands at the very last? | Taehyung | [OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jimin Yoongi > Taehyung Namjoon < Yoongi Namjoon > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET] | var_a = 'Jimin'
var_b = 'Yoongi'
var_c = 'Taehyung'
var_d = 'Namjoon'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 'Jimin'
var_f = 'Yoongi'
var_g = '>'
var_h = 'Taehyung'
var_i = 'Namjoon'
var_j = '<'
var_k = 'Yoongi'
var_l = 'Namjoon'
var_m = '>'
list_b= []
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_n = len(list_c)
var_o = list_c[var_n-1]
print(var_o) |
Arithmetic calculation | On Halloween, Jimin gave 25 candies to Yuna and gave all the remaining 13 candies to her sister. How many candies did Jimin have at first? | 38 | 13 25 [OP_ADD] | var_a = 13
var_b = 25
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | Rounding 6AB3 to the nearest hundred results in 6200. What does 'A' refer to? | 1 | 6AB3 [OP_GEN_POSSIBLE_LIST] 6200 100 [OP_SUB] [OP_LIST_MORE] 6200 [OP_LIST_LESS_EQUAL] 6AB3 A [OP_LIST_FIND_UNK] | var_a = '6AB3'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 6200
var_c = 100
var_d = var_b - var_c
list_b = []
for i in list_a:
if i > var_d:
list_b.append(i)
var_e = 6200
list_c = []
for i in list_b:
if i <= var_e:
list_c.append(i)
var_f = '6AB3'
var_g = 'A'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_c:
elem = str(elem)
var_h = int(elem[unk_idx])
print(int(var_h)) |
Comparison | Dongwoo, Minyeop, and Seongjeong each received a cookie box containing equal amounts of cookies. If Dongwoo shared it with 7 meals, Minyeop with 8 meals, and Seongjeong with 5 meals, who ate the most cookies at one time? | Seongjeong | [OP_LIST_SOL] Dongwoo Minyeop Seongjeong [OP_LIST_EOL] [OP_LIST_SOL] 1 7 [OP_DIV] 1 8 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Dongwoo'
var_b = 'Minyeop'
var_c = 'Seongjeong'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
var_e = 7
var_f = var_d / var_e
var_g = 1
var_h = 8
var_i = var_g / var_h
var_j = 1
var_k = 5
var_l = var_j / var_k
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[-var_m]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p) |
Comparison | Yuna is having a total of 20 days of summer vacation. If the number of vacation days excluding today is 11, how many vacation days are left excluding today? | 8 | 20 11 [OP_SUB] 1 [OP_SUB] | var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Geometry | If a brick is 9 centimeters (cm) wide, 4 centimeters (cm) long, and 7 centimeters (cm) high, how many cubic centimeters (cm3) of volume does it have? | 252 | 9 4 [OP_MUL] 7 [OP_MUL] | var_a = 9
var_b = 4
var_c = var_a * var_b
var_d = 7
var_e = var_c * var_d
print(int(var_e)) |
Correspondence | If the quotient of the four-digit number A614 divided by 6 is a four-digit number, find how many numbers fit in A. | 4 | A614 [OP_GEN_POSSIBLE_LIST] 6000 [OP_LIST_MORE_EQUAL] 60000 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 'A614'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 6000
list_b = []
for i in list_a:
if i >= var_b:
list_b.append(i)
var_c = 60000
list_c = []
for i in list_b:
if i < var_c:
list_c.append(i)
var_d = len(list_c)
print(int(var_d)) |
Comparison | If the common multiples of 27 and 45 are written in order from smallest to largest, what is the product of all the numbers between the 7th and 10th numbers from the left? | 1312200 | 27 45 [OP_LCM] 8 [OP_MUL] 27 45 [OP_LCM] 9 [OP_MUL] [OP_MUL] | var_a = 27
var_b = 45
var_c = var_b * var_a / math.gcd(int(var_b), int(var_a))
var_d = 8
var_e = var_c * var_d
var_f = 27
var_g = 45
var_h = var_g * var_f / math.gcd(int(var_g), int(var_f))
var_i = 9
var_j = var_h * var_i
var_k = var_e * var_j
print(int(var_k)) |
Comparison | A car runs at 92 kilometers (km) per hour, and B car runs at 1500 meters (m) per minute. Which of the two is faster? | A | [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 92
var_d = 1500
var_e = 1000
var_f = var_d / var_e
var_g = 60
var_h = var_f * var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | When a number is divided by 5, the quotient is 248 and the remainder is 4. When this number is divided by 9, what is the sum of the quotient and the remainder? | 140 | 248 5 [OP_MUL] 4 [OP_ADD] 9 [OP_FDIV] 248 5 [OP_MUL] 4 [OP_ADD] 9 [OP_MOD] [OP_ADD] | var_a = 248
var_b = 5
var_c = var_a * var_b
var_d = 4
var_e = var_c + var_d
var_f = 9
var_g = var_e // var_f
var_h = 248
var_i = 5
var_j = var_h * var_i
var_k = 4
var_l = var_j + var_k
var_m = 9
var_n = var_l % var_m
var_o = var_g + var_n
print(int(var_o)) |
Possibility | Hyeonjeong, Seulgi, Miran, and Hocheol are trying to stand in one line. How many different ways are there to line up? | 24 | [OP_LIST_SOL] Hyeonjeong Seulgi Miran Hocheol [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM] | var_a = 'Hyeonjeong'
var_b = 'Seulgi'
var_c = 'Miran'
var_d = 'Hocheol'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = len(list_a)
var_f = 4
var_g = 1
var_e = int(var_e)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_e-i)
print(int(var_g)) |
Arithmetic calculation | When writing the numbers 10 through 99, find how many times the number 8 is written. | 19 | 10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM] | var_a = 10
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
list_b = []
var_d = int(var_d)
while var_d//10 > 0:
list_b.append(var_d%10)
var_d = var_d//10
list_b.append(var_d%10)
list_b = list_b[::-1]
var_e = 8
var_f = 0
var_e = int(var_e)
for i in list_b:
i = int(i)
if i == var_e:
var_f = var_f + 1
print(int(var_f)) |
Comparison | Yena and Yesol are following a dietary plan. Within a month, Yena lost 0.41 times 6 kilograms (kg) and Yesol lost 2.3 kilograms (kg). Which of them has lost more weight? | Yena | [OP_LIST_SOL] Yena Yesol [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yena'
var_b = 'Yesol'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 6
var_d = 0.41
var_e = var_c * var_d
var_f = 2.3
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Geometry | In a factory, cuboid-shaped parts boxes measuring 8 centimeters (cm) in width, 12 centimeters (cm) in length, and 30 centimeters (cm) in height were stacked tightly to fill a cube-shaped room. At this time, if the size of the room is the smallest possible size, find how many boxes are stacked. | 600 | 8 12 [OP_LCM] 30 [OP_LCM] 8 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 12 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 30 [OP_DIV] [OP_MUL] [OP_MUL] | var_a = 8
var_b = 12
var_c = var_b * var_a / math.gcd(int(var_b), int(var_a))
var_d = 30
var_e = var_d * var_c / math.gcd(int(var_d), int(var_c))
var_f = 8
var_g = var_e / var_f
var_h = 8
var_i = 12
var_j = var_i * var_h / math.gcd(int(var_i), int(var_h))
var_k = 30
var_l = var_k * var_j / math.gcd(int(var_k), int(var_j))
var_m = 12
var_n = var_l / var_m
var_o = 8
var_p = 12
var_q = var_p * var_o / math.gcd(int(var_p), int(var_o))
var_r = 30
var_s = var_r * var_q / math.gcd(int(var_r), int(var_q))
var_t = 30
var_u = var_s / var_t
var_v = var_n * var_u
var_w = var_g * var_v
print(int(var_w)) |
Possibility | There are cards with numbers from 1 to 6. Find the number of ways Yuni chooses a card with an even number inscribed. | 3 | 3 | var_a = 3
print(int(var_a)) |
Geometry | I am trying to make the smallest square by arranging rectangular cards that are 5 centimeters (cm) wide and 7 centimeters (cm) tall without overlapping them. How many centimeters (cm) is one side of this square? | 35 | 5 7 [OP_LCM] | var_a = 5
var_b = 7
var_c = var_b * var_a / math.gcd(int(var_b), int(var_a))
print(int(var_c)) |
Geometry | There is a regular octagonal prism whose sum of the lengths of its edges is 240 centimeters (cm). If the height of this prism is 12 centimeters (cm), what is the length of one side of the base? | 9 | 240 12 8 [OP_MUL] [OP_SUB] 8 [OP_DIV] 2 [OP_DIV] | var_a = 240
var_b = 12
var_c = 8
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 8
var_g = var_e / var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Comparison | Among five numbers of 1.4, 9/10, 1, 0.5, 13/10, how many are greater than 1? | 2 | [OP_LIST_SOL] 1.4 9/10 1 0.5 13/10 [OP_LIST_EOL] 1 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 1.4
var_b = 0.9
var_c = 1
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
list_b = []
for i in list_a:
if i > var_f:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Possibility | You want to create a three-digit number by drawing three of 2, 0, 5, 9, and 6 and using them only once. Find the product of the largest number and the smallest number that can be made. | 197825 | [OP_LIST_SOL] 2 0 5 9 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL] | var_a = 2
var_b = 0
var_c = 5
var_d = 9
var_e = 6
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 1
list_d=list_b.copy()
list_d.sort()
var_j = list_d[var_i-1]
var_k = var_h * var_j
print(int(var_k)) |
Arithmetic calculation | You will need a 40 centimeters (cm) block of wood. If you have a block of wood which is 2 meters (m) 80 centimeters (cm) long, how many times do you have to cut it? | 6 | 2 100 [OP_MUL] 80 [OP_ADD] 40 [OP_DIV] 1 [OP_SUB] | var_a = 2
var_b = 100
var_c = var_a * var_b
var_d = 80
var_e = var_c + var_d
var_f = 40
var_g = var_e / var_f
var_h = 1
var_i = var_g - var_h
print(int(var_i)) |
Comparison | In the multiplication of two-digit numbers, the 5 in the ones place of the number was misinterpreted as 2, so you mismultiplied it, resulting 704. If the correctly calculated value is 800, write the larger digit of the two two-digit numbers. | 32 | [OP_LIST_SOL] 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] 800 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] | var_a = 704
var_b = 800
var_c = var_a - var_b
var_d = 2
var_e = 5
var_f = var_d - var_e
var_g = var_c / var_f
var_h = 800
var_i = 704
var_j = 800
var_k = var_i - var_j
var_l = 2
var_m = 5
var_n = var_l - var_m
var_o = var_k / var_n
var_p = var_h / var_o
list_a= []
if "/" in str(var_p):
var_p = eval(str(var_p))
list_a.append(var_p)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
list_a.reverse()
var_q = 1
list_b=list_a.copy()
list_b.sort()
var_r = list_b[-var_q]
print(int(var_r)) |
Arithmetic calculation | Eunji solved 12 questions in the exam A and 15 questions in the exam B. She got 4 questions wrong in the exam A, and got 2 more questions right in exam B than in exam A. How many questions did Eunji get wrong in exam A and exam B in total? | 9 | 4 15 12 4 [OP_SUB] 2 [OP_ADD] [OP_SUB] [OP_ADD] | var_a = 4
var_b = 15
var_c = 12
var_d = 4
var_e = var_c - var_d
var_f = 2
var_g = var_e + var_f
var_h = var_b - var_g
var_i = var_a + var_h
print(int(var_i)) |
Arithmetic calculation | Jimin has 41 pieces of colored paper, and Jimin has 1 more than Seokjin. How many pieces of colored paper does Seokjin have? | 40 | 41 1 [OP_SUB] | var_a = 41
var_b = 1
var_c = var_a - var_b
print(int(var_c)) |
Arithmetic calculation | Namjoon gave Yoongi 18 candies, and there are 16 left over. How many candies did Namjoon have in the beginning? | 34 | 18 16 [OP_ADD] | var_a = 18
var_b = 16
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | Yeonjeong and Donghun started at the same place and walked in opposite directions around the circumference of the lake with a circumference of 3 kilometers (km). If Yeonjeong walks at a speed of 100 meters (m) per minute and Donghun walks at a speed of 150 meters (m) per minute, find how many minutes later they meet again for the first time. | 12 | 3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV] | var_a = 3
var_b = 100
var_c = 1000
var_d = var_b / var_c
var_e = 150
var_f = 1000
var_g = var_e / var_f
var_h = var_d + var_g
var_i = var_a / var_h
print(int(var_i)) |
Possibility | Minji wants to choose a top and a bottom to wear on a field trip. If there are 3 types of tops and 5 types of bottoms, choose how many combinations of clothes Minji can wear. | 15 | 3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL] | var_a = 3
var_b = 1
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
var_d = 5
var_e = 1
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
for i, elem in enumerate(range(var_e)):
var_f = var_f / (i+1)
var_g = var_c * var_f
print(int(var_g)) |
Possibility | Round up the smallest six-digit number that you can make by using the six number cards 0, 1, 3, 5, 7, and 9 once, to the thousandth place. | 104000 | [OP_LIST_SOL] 0 1 3 5 7 9 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_CEIL] | var_a = 0
var_b = 1
var_c = 3
var_d = 5
var_e = 7
var_f = 9
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 6
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_g))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_h = 1
list_c=list_b.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = 4
var_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))
print(int(var_k)) |
Arithmetic calculation | There are 4 crates with 16 sweets each. How many sweets are there in all? | 64 | 16 4 [OP_MUL] | var_a = 16
var_b = 4
var_c = var_a * var_b
print(int(var_c)) |
Possibility | There is one volleyball, one soccerball, one basketball, and one baseball. How many different ways can there be to choose 2 different balls out of 4 balls? | 6 | [OP_LIST_SOL] volleyball soccerball basketball baseball [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB] | var_a = 'volleyball'
var_b = 'soccerball'
var_c = 'basketball'
var_d = 'baseball'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = len(list_a)
var_f = 2
var_g = 1
var_e = int(var_e)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_e-i)
for i, elem in enumerate(range(var_f)):
var_g = var_g / (i+1)
print(int(var_g)) |
Arithmetic calculation | Jungkook's average score in Korean, math, and science is 92 points. If Jungkook's average score increased by 2 points after taking the English test, what is Jungkook's English score? | 100 | 92 2 [OP_ADD] 4 [OP_MUL] 92 3 [OP_MUL] [OP_SUB] | var_a = 92
var_b = 2
var_c = var_a + var_b
var_d = 4
var_e = var_c * var_d
var_f = 92
var_g = 3
var_h = var_f * var_g
var_i = var_e - var_h
print(int(var_i)) |
Correspondence | The number of sheep is 6/11 of chickens, and the number of cows is 1/8 of sheeps in the farm. If there are 48 chickens, how many cows are there? | 11 | 48 6/11 [OP_DIV] 1/8 [OP_MUL] | var_a = 48
var_b = 0.5454545454545454
var_c = var_a / var_b
var_d = 0.125
var_e = var_c * var_d
print(int(var_e)) |
Possibility | I am trying to draw two different numbers at the same time from the natural numbers from 1 to 9. Find the number of cases the sum of two numbers is less than 9. | 24 | 1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 9
list_d = []
for i in list_c:
if i < var_f:
list_d.append(i)
var_g = len(list_d)
print(int(var_g)) |
Geometry | There are several cuboids. When the sum of the number of edges and the number of faces of all cuboids is 216, find the sum of the number of vertices of all cuboids. | 96 | 216 12 6 [OP_ADD] [OP_DIV] 8 [OP_MUL] | var_a = 216
var_b = 12
var_c = 6
var_d = var_b + var_c
var_e = var_a / var_d
var_f = 8
var_g = var_e * var_f
print(int(var_g)) |
Arithmetic calculation | There are 240 third grade students at Heesu's school. If the number of third grade students who were glasses is 3/5 of the number of students who do not were glasses, how may third grade students do not were glasses? | 150 | 240 1 3/5 [OP_ADD] [OP_DIV] | var_a = 240
var_b = 1
var_c = 0.6
var_d = var_b + var_c
var_e = var_a / var_d
print(int(var_e)) |
Arithmetic calculation | Five chrysanthemums and two roses are in the pot. How many flowers are in the pot? | 7 | 5 2 [OP_ADD] | var_a = 5
var_b = 2
var_c = var_a + var_b
print(int(var_c)) |
Comparison | The height of the seven students in Hyungjun's class is 161.5 centimeters (cm), 154.3 centimeters (cm), 143.7 centimeters (cm), 160.1 centimeters (cm), 158.0 centimeters (cm), 153.5 centimeters (cm), 147.8 centimeters (cm) Find out how many of these students are over 1 meter (m) and 50 centimeters (cm). | 5 | [OP_LIST_SOL] 161.5 154.3 143.7 160.1 158.0 153.5 147.8 [OP_LIST_EOL] 1 100 [OP_MUL] 50 [OP_ADD] [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 161.5
var_b = 154.3
var_c = 143.7
var_d = 160.1
var_e = 158
var_f = 153.5
var_g = 147.8
list_a= []
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_h = 1
var_i = 100
var_j = var_h * var_i
var_k = 50
var_l = var_j + var_k
list_b = []
for i in list_a:
if i > var_l:
list_b.append(i)
var_m = len(list_b)
print(int(var_m)) |
Geometry | We are going to make a rectangular parallelepiped 10 centimeters (cm) wide, 8 centimeters (cm) long, and 5 centimeters (cm) high with wire. At least how many centimeters (cm) of wire do you need? | 92 | 10 4 [OP_MUL] 8 4 [OP_MUL] [OP_ADD] 5 4 [OP_MUL] [OP_ADD] | var_a = 10
var_b = 4
var_c = var_a * var_b
var_d = 8
var_e = 4
var_f = var_d * var_e
var_g = var_c + var_f
var_h = 5
var_i = 4
var_j = var_h * var_i
var_k = var_g + var_j
print(int(var_k)) |
Geometry | I drew the smallest circle enclosing a rhombus and the smallest square enclosing the circle. If the side of this square is 16 centimeters (cm), what is the area of the rhombus? | 128 | 16 16 [OP_MUL] 2 [OP_DIV] | var_a = 16
var_b = 16
var_c = var_a * var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | Subtract 74 from a number, multiply by 15, divide by 5, add 16, then subtract 15 to get 58. Find this number. | 93 | 58 15 [OP_ADD] 16 [OP_SUB] 5 [OP_MUL] 15 [OP_DIV] 74 [OP_ADD] | var_a = 58
var_b = 15
var_c = var_a + var_b
var_d = 16
var_e = var_c - var_d
var_f = 5
var_g = var_e * var_f
var_h = 15
var_i = var_g / var_h
var_j = 74
var_k = var_i + var_j
print(int(var_k)) |
Arithmetic calculation | In Yuna's house, there are 12 tangerines. If Yoo-jung ate 3 of them, how many tangerines are there at Yuna's house? | 9 | 12 3 [OP_SUB] | var_a = 12
var_b = 3
var_c = var_a - var_b
print(int(var_c)) |
Correspondence | It is said that the equation 632-AB1=41 holds. What number should be in A? | 5 | 632-AB1=41 A [OP_DIGIT_UNK_SOLVER] | var_a = '632-AB1=41'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | The red colored pencil is 5/9 of the total, and the blue colored pencil is 5/12 of the total. If the total number of colored pencils is 36, what is the number of red colored pencils minus the number of blue colored pencils? | 5 | 36 5/9 [OP_MUL] 36 5/12 [OP_MUL] [OP_SUB] | var_a = 36
var_b = 0.5555555555555556
var_c = var_a * var_b
var_d = 36
var_e = 0.4166666666666667
var_f = var_d * var_e
var_g = var_c - var_f
print(int(var_g)) |
Arithmetic calculation | We are trying to load 2153 chairs onto a truck. How many times should a truck carry at least if it can load up to 100 at a time? | 22 | 2153 100 [OP_DIV] 1 [OP_CEIL] | var_a = 2153
var_b = 100
var_c = var_a / var_b
var_d = 1
var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))
print(int(var_e)) |
Comparison | There are three people: Hyunsoo, Seungah, and Kiyoon. Hyunsoo is taller than Kiyoon, and Kiyoon is taller than Seungah. Who is the tallest? | Hyunsoo | [OP_LIST_SOL] Hyunsoo Seungah Kiyoon [OP_LIST_EOL] [OP_LIST_SOL] Hyunsoo Kiyoon > Kiyoon Seungah > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'Hyunsoo'
var_b = 'Seungah'
var_c = 'Kiyoon'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'Hyunsoo'
var_e = 'Kiyoon'
var_f = '>'
var_g = 'Kiyoon'
var_h = 'Seungah'
var_i = '>'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = 1
var_k = list_c[var_j-1]
print(var_k) |
Comparison | 8 people lined up. How many people are there between the person standing 4th from the back and the person standing 1st from the front? | 3 | 8 1 [OP_SUB] 4 [OP_SUB] | var_a = 8
var_b = 1
var_c = var_a - var_b
var_d = 4
var_e = var_c - var_d
print(int(var_e)) |
Geometry | A square was made from a piece of string that is 32 centimeters (cm) long. What is the maximum area of the rectangle created in square centimeters (cm2)? | 64 | 32 4 [OP_DIV] 2 [OP_POW] | var_a = 32
var_b = 4
var_c = var_a / var_b
var_d = 2
var_e = var_c ** var_d
print(int(var_e)) |
Arithmetic calculation | There are 2 boxes with 3 and 4 balls respectively. How many balls are there in both boxes? | 7 | 3 4 [OP_ADD] | var_a = 3
var_b = 4
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | For two natural numbers A and B, if the quotient of A divided by B is 9 and the remainder is 13, what is the remainder if A is divided by 9? | 4 | 13 9 [OP_MOD] | var_a = 13
var_b = 9
var_c = var_a % var_b
print(int(var_c)) |
Arithmetic calculation | My father has 45 chickens. If there are 8 fewer ducks than chickens, how many chickens and ducks does the father have? | 82 | 45 45 8 [OP_SUB] [OP_ADD] | var_a = 45
var_b = 45
var_c = 8
var_d = var_b - var_c
var_e = var_a + var_d
print(int(var_e)) |
Possibility | There are multiples of 123 that are greater than or equal to 1620006 and less than or equal to 1629996. Find the largest of these numbers. | 1629996 | 1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] | var_a = 1620006
var_b = 1629996
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 123
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print(int(var_f)) |
Arithmetic calculation | There are 23 males and 9 females. How many more men are there than women? | 14 | 23 9 [OP_SUB] | var_a = 23
var_b = 9
var_c = var_a - var_b
print(int(var_c)) |
Correspondence | You had to multiply a number by 2 but instead multiplied by 5 to get 40. Find the correctly calculated vlaue. | 16 | 40 5 [OP_DIV] 2 [OP_MUL] | var_a = 40
var_b = 5
var_c = var_a / var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Comparison | Naeun, Leejun, Yoonseo, Seohyun, and Soyul are interviewed in order. When Yoonseo and Seohyeon switched, who will be the 4th person being interviewed? | Yoonseo | [OP_LIST_SOL] Naeun Leejun Seohyun Yoonseo Soyul [OP_LIST_EOL] 4 [OP_LIST_GET] | var_a = 'Naeun'
var_b = 'Leejun'
var_c = 'Seohyun'
var_d = 'Yoonseo'
var_e = 'Soyul'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 4
var_g = list_a[var_f-1]
print(var_g) |
Arithmetic calculation | Seungchan used 3/5 of the money he had yesterday and used 2/3 of the remaining money today. How many fractions of the money he had left? | 0.13 | 1 3/5 [OP_SUB] 1 2/3 [OP_SUB] [OP_MUL] | var_a = 1
var_b = 0.6
var_c = var_a - var_b
var_d = 1
var_e = 0.6666666666666666
var_f = var_d - var_e
var_g = var_c * var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Possibility | How many times do you choose 3 subjects out of math, science, Korean, social studies, and music? | 10 | 5 3 [OP_COMB] | var_a = 5
var_b = 3
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c)) |
Correspondence | If 5A+13=64, what number should be in A? | 1 | 5A+13=64 A [OP_DIGIT_UNK_SOLVER] | var_a = '5A+13=64'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | It took 4 days to solve all the problems in the workbook. On the first day, I solved 1/2 of the total. On the second day, I solved 1/4 of the total. On the third day, I solved 1/6 of the total. When I solved 20 problems on the last day, find the total number of problems in the workbook. | 240 | 20 1 1/2 1/4 [OP_ADD] 1/6 [OP_ADD] [OP_SUB] [OP_DIV] | var_a = 20
var_b = 1
var_c = 0.5
var_d = 0.25
var_e = var_c + var_d
var_f = 0.16666666666666666
var_g = var_e + var_f
var_h = var_b - var_g
var_i = var_a / var_h
print(int(eval('{:.2f}'.format(round(var_i+1e-10,2))))) |
Correspondence | The number of mackerel is 6/11 of croakers in the fish shop, and the number of croakers is 1/8 of tunas in the fish market. Find how many tunas are there when there are 48 mackerels. | 704 | 48 6/11 [OP_DIV] 1/8 [OP_DIV] | var_a = 48
var_b = 0.5454545454545454
var_c = var_a / var_b
var_d = 0.125
var_e = var_c / var_d
print(int(var_e)) |
Possibility | How many different ways can you place 2 white and 1 black go stones in a row? | 3 | 2 1 [OP_ADD] 2 [OP_COMB] | var_a = 2
var_b = 1
var_c = var_a + var_b
var_d = 2
var_e = 1
var_c = int(var_c)
var_d = int(var_d)
for i, elem in enumerate(range(var_d)):
var_e = var_e * (var_c-i)
for i, elem in enumerate(range(var_d)):
var_e = var_e / (i+1)
print(int(var_e)) |
Possibility | At the airport, 3 foreigners and 2 Koreans are lining up at the checkpoint. At this time, when it is said that foreigners must pass continuously, find the number of cases. | 36 | 2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 3 3 [OP_PERM] [OP_MUL] | var_a = 2
var_b = 1
var_c = var_a + var_b
var_d = 2
var_e = 1
var_f = var_d + var_e
var_g = 1
var_c = int(var_c)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_c-i)
var_h = 3
var_i = 3
var_j = 1
var_h = int(var_h)
var_i = int(var_i)
for i, elem in enumerate(range(var_i)):
var_j = var_j * (var_h-i)
var_k = var_g * var_j
print(int(var_k)) |
Arithmetic calculation | There are 5, 1, 9, 0, 6, and 8. How many of them are between 4 and 8? | 3 | [OP_LIST_SOL] 5 1 9 0 6 8 [OP_LIST_EOL] 4 [OP_LIST_MORE_EQUAL] 8 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | var_a = 5
var_b = 1
var_c = 9
var_d = 0
var_e = 6
var_f = 8
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 4
list_b = []
for i in list_a:
if i >= var_g:
list_b.append(i)
var_h = 8
list_c = []
for i in list_b:
if i <= var_h:
list_c.append(i)
var_i = len(list_c)
print(int(var_i)) |
Geometry | Six sheets of colored paper in the shape of a square with a side length of 30 centimeters (cm) were overlapped in a row by 7 centimeters (cm) and painted with glue. Find the area of the connected colored paper in square centimeters (cm2). | 4350 | 30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL] | var_a = 30
var_b = 6
var_c = var_a * var_b
var_d = 7
var_e = 6
var_f = 1
var_g = var_e - var_f
var_h = var_d * var_g
var_i = var_c - var_h
var_j = 30
var_k = var_i * var_j
print(int(var_k)) |
Correspondence | When you divide a certain number by 10, the result is 6. What is the value of the certain number minus 15? | 45 | 6 10 [OP_MUL] 15 [OP_SUB] | var_a = 6
var_b = 10
var_c = var_a * var_b
var_d = 15
var_e = var_c - var_d
print(int(var_e)) |
Geometry | How many more bases are there in an octagonal prism than there are bases in a square prism? | 4 | 8 4 [OP_SUB] | var_a = 8
var_b = 4
var_c = var_a - var_b
print(int(var_c)) |
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