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Comparison | At Ha-gyeom's school, there are 221 students who are taller than 150 centimeters (cm) and 255 students who are not taller than 150 centimeters (cm). At Myeonghun's school, there are 275 students who wear glasses and 226 students who do not wear glasses. Which school has more students? | Myeonghun | [OP_LIST_SOL] Ha-gyeom Myeonghun [OP_LIST_EOL] [OP_LIST_SOL] 221 255 [OP_ADD] 275 226 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Ha-gyeom'
var_b = 'Myeonghun'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 221
var_d = 255
var_e = var_c + var_d
var_f = 275
var_g = 226
var_h = var_f + var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | You want to multiply a number by 12. When you mistakenly multiplied by 14 to get 42, what is the correctly calculated value? | 36 | 42 14 [OP_DIV] 12 [OP_MUL] | var_a = 42
var_b = 14
var_c = var_a / var_b
var_d = 12
var_e = var_c * var_d
print(int(var_e)) |
Comparison | Choose a number greater than 1.1 among 1.4, 9/10, 1.2, 0.5, and 13/10, and count the number of selected numbers. | 3 | [OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i > var_f:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Possibility | Numbers are given: 2, 4, 5, 1, 3, 7, 6, and 0. Find the smallest number using all cards only once. | 10234567 | [OP_LIST_SOL] 2 4 5 1 3 7 6 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] | var_a = 2
var_b = 4
var_c = 5
var_d = 1
var_e = 3
var_f = 7
var_g = 6
var_h = 0
list_a= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_a.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_i = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_i))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_j = 1
list_c=list_b.copy()
list_c.sort()
var_k = list_c[var_j-1]
print(int(var_k)) |
Correspondence | 632-AB1=41 is valid. What is B? | 9 | 632-AB1=41 B [OP_DIGIT_UNK_SOLVER] | var_a = '632-AB1=41'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Possibility | Choose 3 of the number cards from 1 to 9 and find the number of combination of numbers that makes 19. | 30 | 1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 19
var_g = 0
var_f = int(var_f)
for i in list_c:
i = int(i)
if i == var_f:
var_g = var_g + 1
print(int(var_g)) |
Arithmetic calculation | Which five-digit number is the smallest common multiple of 3 and 5? | 10005 | 10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN] | var_a = 10000
var_b = 99999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 1
list_d=list_c.copy()
list_d.sort()
var_g = list_d[var_f-1]
print(int(var_g)) |
Possibility | 3 different boxes each contain 4 types of balls. Find the number of ways Yongwoo chooses the ball. | 12 | 3 4 [OP_MUL] | var_a = 3
var_b = 4
var_c = var_a * var_b
print(int(var_c)) |
Possibility | If A is the largest and B is the smallest three-digit number made by drawing three out of six number cards 8, 3, 6, 5, 0, 7, find the value of (A-B) × 6 . | 3426 | [OP_LIST_SOL] 8 3 6 5 0 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 6 [OP_MUL] | var_a = 8
var_b = 3
var_c = 6
var_d = 5
var_e = 0
var_f = 7
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_g))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_h = 1
list_c=list_b.copy()
list_c.sort()
var_i = list_c[-var_h]
var_j = 1
list_d=list_b.copy()
list_d.sort()
var_k = list_d[var_j-1]
var_l = var_i - var_k
var_m = 6
var_n = var_l * var_m
print(int(var_n)) |
Possibility | How many number of cases do you get a 4, 5, or 6 when you throw a die? | 3 | 1 6 1 [OP_LIST_ARANGE] [OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN] | var_a = 1
var_b = 6
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 4
var_e = 5
var_f = 6
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
list_c = list(set(list_a) & set(list_b))
var_g = len(list_c)
print(int(var_g)) |
Possibility | Find the largest four-digit number that can be formed by using the numbers 9, 4, 1, and 5 once each. | 9541 | [OP_LIST_SOL] 1 4 9 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] | var_a = 1
var_b = 4
var_c = 9
var_d = 5
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
print(int(var_g)) |
Comparison | Several children are standing in a circle equally spaced apart. Based on one child, the 6th child and the 11th child are standing facing each other in a clockwise direction. How many children are there in total? | 10 | 11 6 [OP_SUB] 2 [OP_MUL] | var_a = 11
var_b = 6
var_c = var_a - var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | When Haebin and 11 of his friends high-five each other once, how many high-fives are there? | 66 | 11 1 [OP_ADD] 11 [OP_MUL] 2 [OP_DIV] | var_a = 11
var_b = 1
var_c = var_a + var_b
var_d = 11
var_e = var_c * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Arithmetic calculation | Minhyung went for a run with his friends. If it takes 20 seconds for Minhyung to run 150 meters (m), find how many meters (m) he can run in 1 minute. | 450 | 1 60 [OP_MUL] 20 [OP_DIV] 150 [OP_MUL] | var_a = 1
var_b = 60
var_c = var_a * var_b
var_d = 20
var_e = var_c / var_d
var_f = 150
var_g = var_e * var_f
print(int(var_g)) |
Comparison | Eunji was the 10th to arrive at school. If Taehyung arrived after Eunji and then Namjoon arrived, in which order did Namjoon arrive at school? | 12 | 10 1 [OP_ADD] 1 [OP_ADD] | var_a = 10
var_b = 1
var_c = var_a + var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | Jungkook owns 3 balls and Yoongi owns 2 balls. How many balls are the two players owning? | 5 | 3 2 [OP_ADD] | var_a = 3
var_b = 2
var_c = var_a + var_b
print(int(var_c)) |
Geometry | A square was made by arranging 12 beads of the same size, 12 by 12, without gaps. How many marbles are on one side? | 12 | 12 | var_a = 12
print(int(var_a)) |
Arithmetic calculation | On the road, cars stand equally spaced from the front to the back. If the distance between the first car and the last car is 242 meters (m), and the distance between the cars is 5.5 meters (m), how many cars are there in the street? | 45 | 242 5.5 [OP_FDIV] 1 [OP_ADD] | var_a = 242
var_b = 5.5
var_c = var_a // var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Possibility | From a fruit basket containing apple, peach, pear and melon, when a total of 3 fruits are taken out in order, allowing picking the same type of fruit, how many possible cases are there? | 64 | [OP_LIST_SOL] apple peach pear melon [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_POW] | var_a = 'apple'
var_b = 'peach'
var_c = 'pear'
var_d = 'melon'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = len(list_a)
var_f = 3
var_g = var_e ** var_f
print(int(var_g)) |
Possibility | Seung-a had a group assignment with 5 friends and had to choose 1 leader, 1 secretary, and 2 presenters. Find the number of cases in which Seung-a becomes a clerk. | 12 | 5 1 [OP_SUB] 1 1 1 [OP_SUB] [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV] | var_a = 5
var_b = 1
var_c = var_a - var_b
var_d = 1
var_e = 1
var_f = 1
var_g = var_e - var_f
var_h = var_d + var_g
var_i = 2
var_j = var_h + var_i
var_k = 1
var_c = int(var_c)
var_j = int(var_j)
for i, elem in enumerate(range(var_j)):
var_k = var_k * (var_c-i)
var_l = 2
var_m = 2
var_n = 1
var_l = int(var_l)
var_m = int(var_m)
for i, elem in enumerate(range(var_m)):
var_n = var_n * (var_l-i)
var_o = var_k / var_n
print(int(var_o)) |
Arithmetic calculation | If the elements of set A are 1/2, 1/3, 1/5 and the elements of set B are 0.2, 0.4, 0.5, 0.7, find the number of elements in the intersection of set A and B. | 2 | [OP_LIST_SOL] 1/2 1/3 1/5 [OP_LIST_EOL] [OP_LIST_SOL] 0.2 0.4 0.5 0.7 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN] | var_a = 0.5
var_b = 0.3333333333333333
var_c = 0.2
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.2
var_e = 0.4
var_f = 0.5
var_g = 0.7
list_b= []
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
list_c = list(set(list_a) & set(list_b))
var_h = len(list_c)
print(int(var_h)) |
Possibility | I want to choose 15 fruits from 4 types of fruits: apples, persimmons, pears, and tangerines. When I am trying to choose at least two from each type of fruit, how many ways can i choose? | 120 | 4 15 [OP_ADD] 4 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 15 4 2 [OP_MUL] [OP_SUB] [OP_COMB] | var_a = 4
var_b = 15
var_c = var_a + var_b
var_d = 4
var_e = 2
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 1
var_i = var_g - var_h
var_j = 15
var_k = 4
var_l = 2
var_m = var_k * var_l
var_n = var_j - var_m
var_o = 1
var_i = int(var_i)
var_n = int(var_n)
for i, elem in enumerate(range(var_n)):
var_o = var_o * (var_i-i)
for i, elem in enumerate(range(var_n)):
var_o = var_o / (i+1)
print(int(var_o)) |
Geometry | If there is a quadrangular pyramid, what is the number of faces? | 5 | 4 1 [OP_ADD] | var_a = 4
var_b = 1
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | There are 16, 22, 30, 26, 18, and 20 candies each of the 6 members of the Si-gyeong's group have. On average, how many candies does Si-gyeong's group have? | 22 | [OP_LIST_SOL] 16 22 30 26 18 20 [OP_LIST_EOL] [OP_LIST_MEAN] | var_a = 16
var_b = 22
var_c = 30
var_d = 26
var_e = 18
var_f = 20
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
list_a = [float(i) for i in list_a]
var_g = sum(list_a)/len(list_a)
print(int(var_g)) |
Comparison | Students are standing in a line to get tested for corona. Yeonji stands right behind Jeongsu, Jeongsu stands 24th from the back, and Yeonji stands 18th from the front. Find how many students are in line. | 42 | 18 24 [OP_ADD] | var_a = 18
var_b = 24
var_c = var_a + var_b
print(int(var_c)) |
Comparison | 20 students were lined up, and Jungkook took the first place in the line. Yoongi stood right behind Jungkook. Find the number of students standing behind Yoongi. | 18 | 20 1 [OP_SUB] 1 [OP_SUB] | var_a = 20
var_b = 1
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | There are eight 15-story buildings in Joa's apartment complex. Half of these buildings have four families per floor, and the rest have five families per floor. If each household has two emergency flashlights installed, find out how many emergency flashlights are installed in Joa's apartment complex. | 1080 | 15 8 [OP_MUL] 2 [OP_DIV] 4 [OP_MUL] 15 8 [OP_MUL] 2 [OP_DIV] 5 [OP_MUL] [OP_ADD] 2 [OP_MUL] | var_a = 15
var_b = 8
var_c = var_a * var_b
var_d = 2
var_e = var_c / var_d
var_f = 4
var_g = var_e * var_f
var_h = 15
var_i = 8
var_j = var_h * var_i
var_k = 2
var_l = var_j / var_k
var_m = 5
var_n = var_l * var_m
var_o = var_g + var_n
var_p = 2
var_q = var_o * var_p
print(int(var_q)) |
Comparison | There are 28 identical bookcases in the library. Each bookcase has 6 shelves, and the number of books on each shelf is the same at 19. How many books are there in the library? | 3192 | 28 6 [OP_MUL] 19 [OP_MUL] | var_a = 28
var_b = 6
var_c = var_a * var_b
var_d = 19
var_e = var_c * var_d
print(int(var_e)) |
Geometry | We are trying to divide red beans filled in a rectangular parallelepiped container with two side lengths of the bottom each 6 meters (m) 40 centimeters (cm) and 9 meters (m) into several boxes whose volume is 1 cubic meter (m3). Find at least how many boxes you need. | 300 | 6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL] | var_a = 6
var_b = 40
var_c = 100
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 9
var_g = var_e * var_f
var_h = 5
var_i = 20
var_j = 100
var_k = var_i / var_j
var_l = var_h + var_k
var_m = var_g * var_l
var_n = 1
var_o = var_m / var_n
var_p = 1
var_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))
print(int(var_q)) |
Correspondence | There are 82 apples, 90 pears, 88 tangerines, and 84 melons at the fruit store, and the number of watermelons is unknown. If you divide the total number of fruits in the fruit store by 88, the quotient is 5 with no remainder. Find the number of watermelons. | 96 | 88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB] | var_a = 88
var_b = 5
var_c = var_a * var_b
var_d = 82
var_e = var_c - var_d
var_f = 90
var_g = var_e - var_f
var_h = 88
var_i = var_g - var_h
var_j = 84
var_k = var_i - var_j
print(int(var_k)) |
Geometry | I have a picture frame in the shape of a rectangle measuring 59.6 square centimeters (cm²). When four photos of the same size are inserted into this frame without overlapping, find the maximum size in square centimeters (cm2) of one photo. | 14.9 | 59.6 4 [OP_DIV] | var_a = 59.6
var_b = 4
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | 20 students were lined up. Eleven students are standing in front of Yoongi, and Hoseok is standing right in front of Yoongi. How many students are standing behind Hoseok? | 10 | 20 11 [OP_SUB] 1 [OP_ADD] | var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Possibility | What is the value of the smallest subtracted from the largest two-digit number that can be formed by drawing two different numbers from 1, 4, 7, and 9? | 83 | [OP_LIST_SOL] 1 4 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 1
var_b = 4
var_c = 7
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 1
list_d=list_b.copy()
list_d.sort()
var_i = list_d[var_h-1]
var_j = var_g - var_i
print(int(var_j)) |
Correspondence | A number that is multiplied by 7 and subtracted 14 was 115.15. How much is it when this number is divided by 7? | 2.64 | 115.15 14 [OP_ADD] 7 [OP_DIV] 7 [OP_DIV] | var_a = 115.15
var_b = 14
var_c = var_a + var_b
var_d = 7
var_e = var_c / var_d
var_f = 7
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Arithmetic calculation | How many out of 18, 15, 11, 19, and 10 are less than 15? | 2 | [OP_LIST_SOL] 18 15 11 19 10 [OP_LIST_EOL] 15 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 18
var_b = 15
var_c = 11
var_d = 19
var_e = 10
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 15
list_b = []
for i in list_a:
if i < var_f:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Geometry | A quadrilateral has a pair of parallel sides. If the length of one of the two parallel sides is 23 centimeters (cm), the distance between the two sides is 12 centimeters (cm), and the area of this rectangle is 222 square cm (cm2), how many centimeters (cm) is the length of the other side? | 14 | 222 2 [OP_MUL] 12 [OP_DIV] 23 [OP_SUB] | var_a = 222
var_b = 2
var_c = var_a * var_b
var_d = 12
var_e = var_c / var_d
var_f = 23
var_g = var_e - var_f
print(int(var_g)) |
Geometry | What is the volume of the largest cube that can be made by cutting a cuboid measuring 4 centimeters (cm) wide by 6 centimeters (cm) long by 5 centimeters (cm) high? | 64 | [OP_LIST_SOL] 4 6 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MIN] 3 [OP_POW] | var_a = 4
var_b = 6
var_c = 4
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
list_b=list_a.copy()
list_b.sort()
var_e = list_b[var_d-1]
var_f = 1
list_c=list_a.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = 3
var_i = var_g ** var_h
print(int(var_i)) |
Correspondence | Seojun misunderstood the teacher's words to bring a 7/3 pizza from the next class and gave the 7/3 pizza to the next class. After giving the pizza, Seojun now has 3/2 pizza. If Seojun did the teacher's errand correctly, how many pizzas should Seojun have? | 6.17 | 3/2 7/3 [OP_ADD] 7/3 [OP_ADD] | var_a = 1.5
var_b = 2.3333333333333335
var_c = var_a + var_b
var_d = 2.3333333333333335
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | There are 3 kilograms (kg) and 300 grams (g) of strawberries. How many grams (g) of strawberries will be left if you give 1 kg (kg) and 900 grams (g) to your friend? | 1400 | 3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB] | var_a = 3
var_b = 1000
var_c = var_a * var_b
var_d = 300
var_e = var_c + var_d
var_f = 1
var_g = 1000
var_h = var_f * var_g
var_i = 900
var_j = var_h + var_i
var_k = var_e - var_j
print(int(var_k)) |
Correspondence | You were supposed to divide a certain number by 8 and add 7, but you mistakenly multiply by 8 and add 8, and you get 56. If you calculate correctly, find a value indicating the number to two decimal places. | 7.75 | 56 8 [OP_SUB] 8 [OP_DIV] 8 [OP_DIV] 7 [OP_ADD] | var_a = 56
var_b = 8
var_c = var_a - var_b
var_d = 8
var_e = var_c / var_d
var_f = 8
var_g = var_e / var_f
var_h = 7
var_i = var_g + var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Arithmetic calculation | If an elevator starts at 120 meters (m) above the ground and descends at a speed of 4 meters (m) per second without stopping once, find the height of the elevator 20 seconds after starting in meters (m). | 40 | 120 4 20 [OP_MUL] [OP_SUB] | var_a = 120
var_b = 4
var_c = 20
var_d = var_b * var_c
var_e = var_a - var_d
print(int(var_e)) |
Geometry | You drew a right triangle on drawing paper. If the length of one non-hypotenuse is 5 and the length of the other non-hypotenuse is 12, how much would the hypotenuse's length be? | 13 | 12 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] 1/2 [OP_POW] | var_a = 12
var_b = 2
var_c = var_a ** var_b
var_d = 5
var_e = 2
var_f = var_d ** var_e
var_g = var_c + var_f
var_h = 0.5
var_i = var_g ** var_h
print(int(var_i)) |
Correspondence | A number added to 9/7 is 13/5. What do you get when 13/5 is added to the number? | 3.91 | 13/5 9/7 [OP_SUB] 13/5 [OP_ADD] | var_a = 2.6
var_b = 1.2857142857142858
var_c = var_a - var_b
var_d = 2.6
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | A total of 55 students participated in the game, and when counted the number of students who participated in A and B game, there were 38 and 42 students respectively. Find how many students participated in both A and B game. | 25 | 38 42 [OP_ADD] 55 [OP_SUB] | var_a = 38
var_b = 42
var_c = var_a + var_b
var_d = 55
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | There are four numbers: 10, 11, 12, and 13. What is the sum of the smallest number and the second smallest number? | 21 | [OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 1
list_b=list_a.copy()
list_b.sort()
var_f = list_b[var_e-1]
var_g = 2
list_c=list_a.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = var_f + var_h
print(int(var_i)) |
Correspondence | What is the largest multiple of 12, a three-digit number with 5 in the hundreds place? | 588 | 5 100 [OP_MUL] 5 1 [OP_ADD] 100 [OP_MUL] 1 [OP_SUB] 1 [OP_LIST_ARANGE] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] | var_a = 5
var_b = 100
var_c = var_a * var_b
var_d = 5
var_e = 1
var_f = var_d + var_e
var_g = 100
var_h = var_f * var_g
var_i = 1
var_j = var_h - var_i
var_k = 1
list_a = [i for i in range(var_c, var_j + 1, var_k)]
var_l = 12
list_b = []
var_l = int(var_l)
for i in list_a:
i = int(i)
if i % var_l == 0:
list_b.append(i)
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[-var_m]
print(int(var_n)) |
Correspondence | ABC+ABC+ABC+ABC=1436. Find A+B+C when A, B, and C are three different numbers. | 17 | [OP_LIST_SOL] ABC+ABC+ABC+ABC=1436 A [OP_DIGIT_UNK_SOLVER] ABC+ABC+ABC+ABC=1436 B [OP_DIGIT_UNK_SOLVER] ABC+ABC+ABC+ABC=1436 C [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST_SUM] | var_a = 'ABC+ABC+ABC+ABC=1436'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = 'ABC+ABC+ABC+ABC=1436'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = 'ABC+ABC+ABC+ABC=1436'
var_h = 'C'
ans_dict = dict()
var_g = var_g.replace('×','*')
var_g = var_g.replace('x','*')
var_g = var_g.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_g):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_g
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_g):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_i = ans_dict[var_h]
list_a= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_a.append(var_i)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
list_a.reverse()
list_a = [float(i) for i in list_a]
var_j = sum(list_a)
print(int(var_j)) |
Arithmetic calculation | There are 52 hens on the farm. Hens are 16 fewer than roosters. How many chickens are there on the farm? | 120 | 52 52 16 [OP_ADD] [OP_ADD] | var_a = 52
var_b = 52
var_c = 16
var_d = var_b + var_c
var_e = var_a + var_d
print(int(var_e)) |
Geometry | When a cuboid-shaped block of wood measuring 18 centimeters (cm) wide, 6 centimeters (cm) long, and 6 cm (height) is cut into three cubes with a side of 6 centimeters (cm) long, How many the surface area cm2 does it increase? | 288 | 3 6 3 [OP_POW] [OP_MUL] 18 6 [OP_MUL] 6 6 [OP_MUL] [OP_ADD] 6 6 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_SUB] | var_a = 3
var_b = 6
var_c = 3
var_d = var_b ** var_c
var_e = var_a * var_d
var_f = 18
var_g = 6
var_h = var_f * var_g
var_i = 6
var_j = 6
var_k = var_i * var_j
var_l = var_h + var_k
var_m = 6
var_n = 6
var_o = var_m * var_n
var_p = var_l + var_o
var_q = 2
var_r = var_p * var_q
var_s = var_e - var_r
print(int(var_s)) |
Geometry | You built a cuboid-shaped pond with a length of 18 meters (m), a width of 10 meters (m), and a height of 2 meters (m). If you are going to paint the inner side of the pond, how many square meters (㎡) of the pond could be painted? | 292 | 18 10 [OP_MUL] 10 2 [OP_MUL] 2 18 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_ADD] | var_a = 18
var_b = 10
var_c = var_a * var_b
var_d = 10
var_e = 2
var_f = var_d * var_e
var_g = 2
var_h = 18
var_i = var_g * var_h
var_j = var_f + var_i
var_k = 2
var_l = var_j * var_k
var_m = var_c + var_l
print(int(var_m)) |
Comparison | Jungkook puts 4 and 4 together. Jimin puts 3 and 6 together. Who has the greater number? | Jimin | [OP_LIST_SOL] Jungkook Jimin [OP_LIST_EOL] [OP_LIST_SOL] 4 4 [OP_ADD] 3 6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Jimin'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 4
var_d = 4
var_e = var_c + var_d
var_f = 3
var_g = 6
var_h = var_f + var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Comparison | Joo-hee and Jun-seong want to share 25 chocolates. Find how many chocolates Joo-hee ate when Joo-hee ate 1 more chocolate than twice Jun-seong ate. | 17 | 25 1 [OP_SUB] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] 1 [OP_ADD] | var_a = 25
var_b = 1
var_c = var_a - var_b
var_d = 2
var_e = 1
var_f = var_d + var_e
var_g = var_c / var_f
var_h = 2
var_i = var_g * var_h
var_j = 1
var_k = var_i + var_j
print(int(var_k)) |
Geometry | The diamond-shaped roof drawn by Jaewoong has a diagonal of 16 centimeters (cm) and an area of 80 square centimeters (cm2). How many centimeters (cm) is the length of the other diagonal of this roof? | 10 | 80 2 [OP_MUL] 16 [OP_DIV] | var_a = 80
var_b = 2
var_c = var_a * var_b
var_d = 16
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | How many two-digit numbers are less than 36 and greater than 29? | 6 | 29 1 [OP_ADD] 36 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN] | var_a = 29
var_b = 1
var_c = var_a + var_b
var_d = 36
var_e = 1
var_f = var_d - var_e
var_g = 1
list_a = [i for i in range(var_c, var_f + 1, var_g)]
var_h = len(list_a)
print(int(var_h)) |
Correspondence | A is a single-digit number. Find A when the multiplication of single-digit numbers A×A×A is the same as 21A. | 6 | A×A×A=21A A [OP_DIGIT_UNK_SOLVER] | var_a = 'A×A×A=21A'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | There are 194 men and 235 women in the museum, and 68 of them got free admission. Find how many more people paid for admission to the museum than those who got free admission. | 293 | 194 235 [OP_ADD] 68 [OP_SUB] 68 [OP_SUB] | var_a = 194
var_b = 235
var_c = var_a + var_b
var_d = 68
var_e = var_c - var_d
var_f = 68
var_g = var_e - var_f
print(int(var_g)) |
Comparison | Find the number of numbers greater than 0.4 among 0.8, 1/2, 0.3, and 1/3. | 2 | [OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 0.8
var_b = 0.5
var_c = 0.3
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 0.4
list_b = []
for i in list_a:
if i > var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Correspondence | If the four numbers A, B, C, and D satisfy the four-digit subtraction formula A05B-1C04=30D8, find the value of A+B-C+D. | 10 | A05B-1C04=30D8 A [OP_DIGIT_UNK_SOLVER] A05B-1C04=30D8 B [OP_DIGIT_UNK_SOLVER] [OP_ADD] A05B-1C04=30D8 C [OP_DIGIT_UNK_SOLVER] [OP_SUB] A05B-1C04=30D8 D [OP_DIGIT_UNK_SOLVER] [OP_ADD] | var_a = 'A05B-1C04=30D8'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = 'A05B-1C04=30D8'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = var_c + var_f
var_h = 'A05B-1C04=30D8'
var_i = 'C'
ans_dict = dict()
var_h = var_h.replace('×','*')
var_h = var_h.replace('x','*')
var_h = var_h.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_h):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_h
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_h):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_j = ans_dict[var_i]
var_k = var_g - var_j
var_l = 'A05B-1C04=30D8'
var_m = 'D'
ans_dict = dict()
var_l = var_l.replace('×','*')
var_l = var_l.replace('x','*')
var_l = var_l.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_l):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_l
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_l):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_n = ans_dict[var_m]
var_o = var_k + var_n
print(int(var_o)) |
Possibility | There are 3 blue balls and 5 red balls in the box. When 2 red balls are placed inside the box, how many blue balls are in the box? | 3 | 3 | var_a = 3
print(int(var_a)) |
Correspondence | Yeongsoo gave Hyogeun 200 won, Hyogeun gave Woong 500 won, and Woong gave Yeongsoo 1000 won. As a result, they have 2000 won respectively. How much money did Yeongsoo have at first? | 1200 | 2000 1000 [OP_SUB] 200 [OP_ADD] | var_a = 2000
var_b = 1000
var_c = var_a - var_b
var_d = 200
var_e = var_c + var_d
print(int(var_e)) |
Geometry | Given a map with a scale of 1/250000, find the distance in centimeters (cm) on the map of two points whose actual distance is 5 kilometers (km). | 2 | 5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL] | var_a = 5
var_b = 100
var_c = 1000
var_d = var_b * var_c
var_e = var_a * var_d
var_f = 4e-06
var_g = var_e * var_f
print(int(var_g)) |
Geometry | If you multiply a number by 2 and divide it by 16, the quotient is 25. Find what the number is. | 200 | 25 16 [OP_MUL] 2 [OP_DIV] | var_a = 25
var_b = 16
var_c = var_a * var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Geometry | There is a rectangular farm. The length of the long side is 1 kilometer (km), and the length of the short side is 2/8 km (km) shorter than the length of the long side. How many kilometers (km) will you have to walk if you walk around the farm once? | 3.5 | 1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL] | var_a = 1
var_b = 1
var_c = 0.25
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 2
var_g = var_e * var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Geometry | Mihyang cut the colored paper into regular hexagons so that each side is 5 centimeters (cm) long. What is the perimeter of this regular hexagon in centimeters (cm)? | 30 | 5 6 [OP_MUL] | var_a = 5
var_b = 6
var_c = var_a * var_b
print(int(var_c)) |
Geometry | There is a rhombus with an area of 24.48 square centimeters (cm2). If one diagonal of this rhombus is 8 centimeters (cm), find the difference between the length of this diagonal and the other diagonal. | 1.88 | 8 24.48 2 [OP_MUL] 8 [OP_DIV] [OP_SUB] [OP_ABS] | var_a = 8
var_b = 24.48
var_c = 2
var_d = var_b * var_c
var_e = 8
var_f = var_d / var_e
var_g = var_a - var_f
var_h = abs(var_g)
print('{:.2f}'.format(round(var_h+1e-10,2))) |
Comparison | There are a total of 4 numbers: 0.8, 1/2, 0.5, 1/3. What is the largest of these numbers that are less than 3? | 0.8 | [OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] 1 [OP_LIST_MAX] | var_a = 0.8
var_b = 0.5
var_c = 0.5
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = []
for i in list_a:
if i < var_e:
list_b.append(i)
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Comparison | Seokjin and Taehyung jumped ropes for two days yesterday and today. Seokjin did 15 more today than yesterday, and Taehyung did 12 fewer today than yesterday. If Seokjin and Taehyung jumped ropes 32 times and 58 times respectively yesterday, then find out who skipped more ropes today. | Seokjin | [OP_LIST_SOL] Seokjin Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 32 15 [OP_ADD] 58 12 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Seokjin'
var_b = 'Taehyung'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 32
var_d = 15
var_e = var_c + var_d
var_f = 58
var_g = 12
var_h = var_f - var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | The box, which had 12 identical children's books inside, weighed 11.48 kilograms (kg). When 4 children's books were removed from the box, it weighed 8.12 kilograms (kg). What is the weight of the empty box in kilograms (kg)? | 1.4 | 11.48 11.48 8.12 [OP_SUB] 4 [OP_DIV] 12 [OP_MUL] [OP_SUB] | var_a = 11.48
var_b = 11.48
var_c = 8.12
var_d = var_b - var_c
var_e = 4
var_f = var_d / var_e
var_g = 12
var_h = var_f * var_g
var_i = var_a - var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Comparison | Find out how many three-digit prime numbers exist, which are less than 3.01 but greater than 3, and have 3 as its units digit, 0 and 6 as the 1st and 2nd decimal place, and 6 as the 3rd decimal place. | 3 | 0 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 0
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 6
list_b = []
for i in list_a:
if i > var_d:
list_b.append(i)
var_e = len(list_b)
print(int(var_e)) |
Arithmetic calculation | If you write down the numbers 1 through 50 once on a piece of paper, find how many times you write 1. | 15 | 1 50 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 50
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
list_b = []
var_d = int(var_d)
while var_d//10 > 0:
list_b.append(var_d%10)
var_d = var_d//10
list_b.append(var_d%10)
list_b = list_b[::-1]
var_e = 1
var_f = 0
var_e = int(var_e)
for i in list_b:
i = int(i)
if i == var_e:
var_f = var_f + 1
print(int(var_f)) |
Possibility | Jungkook bought two boxes each containing three red balls. How many red balls does Jungkook have? | 6 | 3 2 [OP_MUL] | var_a = 3
var_b = 2
var_c = var_a * var_b
print(int(var_c)) |
Arithmetic calculation | You are trying to pack 24 tangerines and 18 apples in one box. If there are no remaining apples or tangerines and each box contains the same number, find the maximum number of boxes you can make. | 6 | 24 18 [OP_GCD] | var_a = 24
var_b = 18
var_c = math.gcd(int(var_b), int(var_a))
print(int(var_c)) |
Geometry | Junyoung has a hoop with a diameter of 50 centimeters (cm). After rolling this hoop several times, it moved forward by 6 meters (m) and 28 centimeters (cm). If the pi is 3.14, how many times does the hoop need to be rolled? | 4 | 6 100 [OP_MUL] 28 [OP_ADD] 50 3.14 [OP_MUL] [OP_DIV] | var_a = 6
var_b = 100
var_c = var_a * var_b
var_d = 28
var_e = var_c + var_d
var_f = 50
var_g = 3.14
var_h = var_f * var_g
var_i = var_e / var_h
print(int(var_i)) |
Arithmetic calculation | Aunt Yujeong gave three carrots to her nephew, Yoongi. Yoongi's older sister received 4, but she gave 2 to Yoongi again. How many carrots does Yoongi have? | 5 | 3 2 [OP_ADD] | var_a = 3
var_b = 2
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | Jimin is trying to subtract a number from 34. If the result of mistakenly dividing 96 by a number is 6, find the correct result. | 18 | 34 96 6 [OP_DIV] [OP_SUB] | var_a = 34
var_b = 96
var_c = 6
var_d = var_b / var_c
var_e = var_a - var_d
print(int(var_e)) |
Possibility | Four non-overlapping numbers from 0 to 9 were drawn and made a four-digit number. What is the difference between the second largest and the second smallest possible cases? | 8851 | 0 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB] | var_a = 0
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 2
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = 2
list_d=list_b.copy()
list_d.sort()
var_h = list_d[var_g-1]
var_i = var_f - var_h
print(int(var_i)) |
Possibility | If there are 6 students in the auditorium, find the number of cases in which 1 class president, 1 moderator, 1 vice-president, and 1 assistant moderator are selected. | 360 | 6 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM] | var_a = 6
var_b = 1
var_c = 1
var_d = var_b + var_c
var_e = 1
var_f = var_d + var_e
var_g = 1
var_h = var_f + var_g
var_i = 1
var_a = int(var_a)
var_h = int(var_h)
for i, elem in enumerate(range(var_h)):
var_i = var_i * (var_a-i)
print(int(var_i)) |
Comparison | How many of 0.9, 5/10, 1, 7/10, and 1.2 are greater than 0.8? | 3 | [OP_LIST_SOL] 0.9 5/10 1 7/10 1.2 [OP_LIST_EOL] 0.8 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 0.9
var_b = 0.5
var_c = 1
var_d = 0.7
var_e = 1.2
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 0.8
list_b = []
for i in list_a:
if i > var_f:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Comparison | There are numbers 0.8, 1/2, and 0.9. Find the greatest number among the given numbers less than or equal to 0.6. | 0.5 | [OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.6 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX] | var_a = 0.8
var_b = 0.5
var_c = 0.9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.6
list_b = []
for i in list_a:
if i <= var_d:
list_b.append(i)
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Possibility | You took three number jellies from the vending machine and they were numbered 0, 1, and 5. If you use two out of three jellies, how many two-digit numbers can you create? | 4 | [OP_LIST_SOL] 0 1 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Geometry | What is the surface area of a cuboid that is 8 centimeters (cm) wide, 5 centimeters (cm) long, and 10 centimeters (cm) height? | 340 | 8 5 [OP_MUL] 8 10 [OP_MUL] [OP_ADD] 5 10 [OP_MUL] [OP_ADD] 2 [OP_MUL] | var_a = 8
var_b = 5
var_c = var_a * var_b
var_d = 8
var_e = 10
var_f = var_d * var_e
var_g = var_c + var_f
var_h = 5
var_i = 10
var_j = var_h * var_i
var_k = var_g + var_j
var_l = 2
var_m = var_k * var_l
print(int(var_m)) |
Comparison | Find the sum of the numbers that are greater than or equal to 1.1 among the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10. | 3.9 | [OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM] | var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_g = sum(list_b)
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Geometry | In a right triangle, if the length of the non-hypotenuse is 6 and the length of the hypotenuse is 10, what is the length of the other side? | 8 | 10 2 [OP_POW] 6 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] | var_a = 10
var_b = 2
var_c = var_a ** var_b
var_d = 6
var_e = 2
var_f = var_d ** var_e
var_g = var_c - var_f
var_h = 0.5
var_i = var_g ** var_h
print(int(var_i)) |
Arithmetic calculation | A truck travels 2.1 kilometers (km) in 1 minute at a constant speed, while a taxi covers 10.5 km in 4 minutes. Which vehicle is quicker, the taxi or truck, by how many times? | 1.25 | 10.5 4 [OP_DIV] 2.1 1 [OP_DIV] [OP_DIV] | var_a = 10.5
var_b = 4
var_c = var_a / var_b
var_d = 2.1
var_e = 1
var_f = var_d / var_e
var_g = var_c / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Correspondence | Subtracting 2 twice from a certain number results in 5. What is the certain number? | 9 | 5 2 [OP_ADD] 2 [OP_ADD] | var_a = 5
var_b = 2
var_c = var_a + var_b
var_d = 2
var_e = var_c + var_d
print(int(var_e)) |
Comparison | Seungmin picked up 4.56 kilograms (kg) of chestnuts and Hyein picked up 10 times as much as 462 grams (g). Who picked up more chestnuts, Seungmin or Hyein? | Hyein | [OP_LIST_SOL] Seungmin Hyein [OP_LIST_EOL] [OP_LIST_SOL] 4.56 462 10 [OP_MUL] 1000 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Seungmin'
var_b = 'Hyein'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 4.56
var_d = 462
var_e = 10
var_f = var_d * var_e
var_g = 1000
var_h = var_f / var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | While Yoongi was subtracting 57 from the four digit number, Yoongi mistakenly saw the 9 in the ones digit of the four digit number as 6. If Yoongi got 1819 from this, what is the correct calculation result? | 1822 | 1819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB] | var_a = 1819
var_b = 57
var_c = var_a + var_b
var_d = 6
var_e = 9
var_f = var_d - var_e
var_g = var_c - var_f
var_h = 57
var_i = var_g - var_h
print(int(var_i)) |
Geometry | Hosok bought a few centimeters (cm) of wire and cut a length equal to the circumference of an equilateral triangle with a side length of 19 centimeters (cm). If the wire left after cutting is 15 centimeters (cm), what is the length in centimeters (cm) of the wire that Hoseok bought? | 72 | 19 3 [OP_MUL] 15 [OP_ADD] | var_a = 19
var_b = 3
var_c = var_a * var_b
var_d = 15
var_e = var_c + var_d
print(int(var_e)) |
Comparison | Heejin and Heechul are collecting books. Heechul has 2 more books than Heejin. Dongkyun has fewer books than Heejin. Which of the three has the most books? | Heechul | [OP_LIST_SOL] Heejin Heechul Dongkyun [OP_LIST_EOL] [OP_LIST_SOL] Heechul Heejin > Dongkyun Heejin < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'Heejin'
var_b = 'Heechul'
var_c = 'Dongkyun'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'Heechul'
var_e = 'Heejin'
var_f = '>'
var_g = 'Dongkyun'
var_h = 'Heejin'
var_i = '<'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = 1
var_k = list_c[var_j-1]
print(var_k) |
Arithmetic calculation | Find how many grams (g) of water evaporated from 300 grams (g) of 4% sugar water to make 10% sugar water. | 180 | 300 300 4 100 [OP_DIV] [OP_MUL] 100 10 [OP_DIV] [OP_MUL] [OP_SUB] | var_a = 300
var_b = 300
var_c = 4
var_d = 100
var_e = var_c / var_d
var_f = var_b * var_e
var_g = 100
var_h = 10
var_i = var_g / var_h
var_j = var_f * var_i
var_k = var_a - var_j
print(int(var_k)) |
Geometry | If you double the length of each edge of a cube, how many times bigger does the cube's surface area become? | 4 | 2 2 [OP_POW] | var_a = 2
var_b = 2
var_c = var_a ** var_b
print(int(var_c)) |
Arithmetic calculation | What is the smallest five-digit number that is a multiple of 9 and a multiple of 6 and a multiple of 2? | 10008 | 10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN] | var_a = 10000
var_b = 99999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 9
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 6
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 2
list_d = []
var_f = int(var_f)
for i in list_c:
i = int(i)
if i % var_f == 0:
list_d.append(i)
var_g = 1
list_e=list_d.copy()
list_e.sort()
var_h = list_e[var_g-1]
print(int(var_h)) |
Arithmetic calculation | You have 200 grams (g) of salt water with a concentration of 25%, and 60 grams (g) of salt are dissolved in another 300 grams (g) of salt water. What is the percent concentration of the salt water when these two salt water are mixed? | 22 | 200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL] | var_a = 200
var_b = 25
var_c = 100
var_d = var_b / var_c
var_e = var_a * var_d
var_f = 60
var_g = var_e + var_f
var_h = 200
var_i = 300
var_j = var_h + var_i
var_k = var_g / var_j
var_l = 100
var_m = var_k * var_l
print(int(var_m)) |
Arithmetic calculation | The subway is moving 1.6 kilometers (km) per minute. If the distance between the previous station and this station is 4.85 kilometers (km), and it took 3 minutes and 15 seconds to pass this station completely from the previous station, how long is the subway in meters (m)? | 350 | 1.6 3 15 60 [OP_DIV] [OP_ADD] [OP_MUL] 4.85 [OP_SUB] 1000 [OP_MUL] | var_a = 1.6
var_b = 3
var_c = 15
var_d = 60
var_e = var_c / var_d
var_f = var_b + var_e
var_g = var_a * var_f
var_h = 4.85
var_i = var_g - var_h
var_j = 1000
var_k = var_i * var_j
print(int(eval('{:.2f}'.format(round(var_k+1e-10,2))))) |
Arithmetic calculation | Minseok started reading a storybook and read 1/3 of it yesterday and 2/5 of it today. What is the total number of unread parts? | 0.27 | 1 1/3 [OP_SUB] 2/5 [OP_SUB] | var_a = 1
var_b = 0.3333333333333333
var_c = var_a - var_b
var_d = 0.4
var_e = var_c - var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Correspondence | Subtracting 27 from a number gives 46. What is the number multiplied by 46? | 3358 | 27 46 [OP_ADD] 46 [OP_MUL] | var_a = 27
var_b = 46
var_c = var_a + var_b
var_d = 46
var_e = var_c * var_d
print(int(var_e)) |
Correspondence | Subtracting 174 from a number and multiplying it by 19 yields 3439. What is a number? | 355 | 3439 19 [OP_DIV] 174 [OP_ADD] | var_a = 3439
var_b = 19
var_c = var_a / var_b
var_d = 174
var_e = var_c + var_d
print(int(var_e)) |
Correspondence | There are different numbers A, B, C, and D. Given that A+A=6, BA=4, C+B=9, and D-C=7. Find out what D is. | 9 | A+A=6 A [OP_NUM_UNK_SOLVER] 4 [OP_ADD] 9 [OP_SUB] 7 [OP_SUB] -1 [OP_MUL] | var_a = 'A+A=6'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candidate_num = [i for i in range(51)]
candi = list(itertools.product(candidate_num, repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
if term_list[i] == '':
new_eq += str(term_list[i])+op_list[i]
else:
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:
new_eq=new_eq.replace('==','=')
new_eq=new_eq.replace('>','')
new_eq=new_eq.replace('<','')
new_eq=new_eq.split('=')
for i in range(len(new_eq)-1):
eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))
if not eval_result:
break
else:
eval_result = eval(new_eq)
except:
eval_result = False
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = 4
var_e = var_c + var_d
var_f = 9
var_g = var_e - var_f
var_h = 7
var_i = var_g - var_h
var_j = -1
var_k = var_i * var_j
print(int(var_k)) |
Correspondence | You can take 40 peaches and 34 cherries in separate bags. I am going to put 8 peaches and 5 cherries in bags, but I will not put the leftovers in bags. Find how many handles there are in the bags full of peaches and cherries. | 14 | 40 8 [OP_FDIV] 34 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL] | var_a = 40
var_b = 8
var_c = var_a // var_b
var_d = 34
var_e = 12
var_f = var_d // var_e
var_g = var_c + var_f
var_h = 2
var_i = var_g * var_h
print(int(var_i)) |
Possibility | If 5 students, 2 of whom are elementary school students, are lined up, how many ways can the elementary school students stand at either end? | 12 | 5 2 [OP_SUB] 5 2 [OP_SUB] [OP_PERM] 2 [OP_MUL] | var_a = 5
var_b = 2
var_c = var_a - var_b
var_d = 5
var_e = 2
var_f = var_d - var_e
var_g = 1
var_c = int(var_c)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_c-i)
var_h = 2
var_i = var_g * var_h
print(int(var_i)) |
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