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Possibility | You chose two of the five numbers 0, 1, 2, 3, 4, and 5 to make two-digit numbers. If you can use the same number multiple times, how many numbers can you make in total? | 30 | [OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
var_f = 5
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_g))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_h = len(list_b)
print(int(var_h)) |
Arithmetic calculation | From 1 to 100, A is the sum of all even numbers, and B is the sum of all odd numbers. What is the difference of A and B? | 50 | 1 100 [OP_LIST_EVEN] [OP_LIST_SUM] 1 100 [OP_LIST_ODD] [OP_LIST_SUM] [OP_SUB] | var_a = 1
var_b = 100
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
list_a = [float(i) for i in list_a]
var_c = sum(list_a)
var_d = 1
var_e = 100
list_b = []
if var_d%2==0:
for i in range(var_d+1, var_e+1, 2):
list_b.append(i)
else:
for i in range(var_d, var_e+1, 2):
list_b.append(i)
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
var_g = var_c - var_f
print(int(var_g)) |
Geometry | There are 8 rectangular fields with a length of 300 meters (m). If the area of each field is the same and the total area of the fields is 0.6 square kilometers (km2), how many meters (m) is the width of the field? | 250 | 0.6 1000 1000 [OP_MUL] [OP_MUL] 8 [OP_DIV] 300 [OP_DIV] | var_a = 0.6
var_b = 1000
var_c = 1000
var_d = var_b * var_c
var_e = var_a * var_d
var_f = 8
var_g = var_e / var_f
var_h = 300
var_i = var_g / var_h
print(int(var_i)) |
Arithmetic calculation | Seonho has 2,500 won after spending 1/4 of the money in his wallet to buy snacks and 2/3 of the remaining money to buy food. How much money is in his wallet? | 10000 | 2500 1 1/4 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV] | var_a = 2500
var_b = 1
var_c = 0.25
var_d = var_b - var_c
var_e = var_a / var_d
var_f = 1
var_g = 0.6666666666666666
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i)) |
Arithmetic calculation | Yoojung folded two fingers, and Yuna folded five. How many fingers do two people fold? | 7 | 2 5 [OP_ADD] | var_a = 2
var_b = 5
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | Hoseok's average score in Korean and Mathematics is 88 points. If the average score of Korean, Mathematics, and English is 90, what is Hoseok's English score? | 94 | 90 3 [OP_MUL] 88 2 [OP_MUL] [OP_SUB] | var_a = 90
var_b = 3
var_c = var_a * var_b
var_d = 88
var_e = 2
var_f = var_d * var_e
var_g = var_c - var_f
print(int(var_g)) |
Arithmetic calculation | Three 217 centimeters (cm) long strings are tied together. If the length of the string at the tied part is the same and the length of the tied string is 627 centimeters (cm), find how many centimeters (cm) is the length of one part of the tied part. | 12 | 217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV] | var_a = 217
var_b = 3
var_c = var_a * var_b
var_d = 627
var_e = var_c - var_d
var_f = 3
var_g = 1
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i)) |
Arithmetic calculation | 48 objects which weigh a one-metric ton (m/t) have to be moved. How many moves are needed to make if trucks can carry up to 4 metric tons (m/t) at a time and 6 trucks move at once? | 2 | 48 4 6 [OP_MUL] [OP_DIV] | var_a = 48
var_b = 4
var_c = 6
var_d = var_b * var_c
var_e = var_a / var_d
print(int(var_e)) |
Correspondence | When you multiply a number by 17, you get 493. Find the number. | 29 | 493 17 [OP_DIV] | var_a = 493
var_b = 17
var_c = var_a / var_b
print(int(var_c)) |
Geometry | The area of a circle is equal to four times the area of the other circle with a radius of 2 cm. Find the size of the radius of the other circle. | 4 | 4 2 2 [OP_POW] [OP_MUL] 1/2 [OP_POW] | var_a = 4
var_b = 2
var_c = 2
var_d = var_b ** var_c
var_e = var_a * var_d
var_f = 0.5
var_g = var_e ** var_f
print(int(var_g)) |
Possibility | If there are 3 types of pencils, 2 types of erasers, and 5 types of notebooks, find how many ways there are to buy 1 type of pencil, 1 type of eraser, and 1 type of notebook. | 30 | 3 2 [OP_MUL] 5 [OP_MUL] | var_a = 3
var_b = 2
var_c = var_a * var_b
var_d = 5
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | There is a train that runs at 400 meters (m) per minute. How many minutes does it take to completely cross the 1.625 kilometer (km) bridge? The length of the train is 115 meters (m). | 4.35 | 115 1.625 1000 [OP_MUL] [OP_ADD] 400 [OP_DIV] | var_a = 115
var_b = 1.625
var_c = 1000
var_d = var_b * var_c
var_e = var_a + var_d
var_f = 400
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Possibility | If there are 6 citizens A, B, C, D, E, and F, find the number of ways to elect 3 members for the National Assembly. | 20 | [OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_COMB] | var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
var_e = 'E'
var_f = 'F'
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = len(list_a)
var_h = 3
var_i = 1
var_g = int(var_g)
var_h = int(var_h)
for i, elem in enumerate(range(var_h)):
var_i = var_i * (var_g-i)
for i, elem in enumerate(range(var_h)):
var_i = var_i / (i+1)
print(int(var_i)) |
Possibility | Find the number of natural numbers that can be made by picking four of the number cards 0, 1, 2, 4, and 9. | 96 | [OP_LIST_SOL] 0 1 2 4 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
var_d = 4
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = len(list_b)
print(int(var_g)) |
Arithmetic calculation | There are five numbers 10, 11, 12, 13, and 14. What is the remainder when the 3rd smallest number is divided by the 2nd smallest number? | 1 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MOD] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b=list_a.copy()
list_b.sort()
var_g = list_b[var_f-1]
var_h = 2
list_c=list_a.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = var_g % var_i
print(int(var_j)) |
Correspondence | When 132.6 kilograms (kg) of apples harvested from the orchard were divided into equal weights in each truck, each truck loaded 13.26 kilograms (kg). If 6.4 kilograms (kg) of bananas are divided among these trucks, how many kilograms (kg) of bananas will be loaded per truck? | 0.64 | 6.4 132.6 13.26 [OP_DIV] [OP_DIV] | var_a = 6.4
var_b = 132.6
var_c = 13.26
var_d = var_b / var_c
var_e = var_a / var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Correspondence | 63 is the result of subtracting 29 from a number. Find the value which is 47 less than this number. | 45 | 63 29 [OP_ADD] 47 [OP_SUB] | var_a = 63
var_b = 29
var_c = var_a + var_b
var_d = 47
var_e = var_c - var_d
print(int(var_e)) |
Geometry | A rectangle has a sum of four sides equal to 52 centimeters (cm). If the length of one of the sides is 11 centimeters (cm), what is the area? | 165 | 11 52 2 [OP_DIV] 11 [OP_SUB] [OP_MUL] | var_a = 11
var_b = 52
var_c = 2
var_d = var_b / var_c
var_e = 11
var_f = var_d - var_e
var_g = var_a * var_f
print(int(var_g)) |
Possibility | A set of boxes contains 2 balls. With a set of 3, how many balls are there? | 6 | 2 3 [OP_MUL] | var_a = 2
var_b = 3
var_c = var_a * var_b
print(int(var_c)) |
Correspondence | 3/10 of this number minus 8 is 12. Find what 1/5 of this number is. | 13.33 | 12 8 [OP_ADD] 3/10 [OP_DIV] 1/5 [OP_MUL] | var_a = 12
var_b = 8
var_c = var_a + var_b
var_d = 0.3
var_e = var_c / var_d
var_f = 0.2
var_g = var_e * var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Possibility | What is the sum of the smallest and third smallest numbers that can be formed by moving each digit in 168? | 786 | 168 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD] | var_a = 168
list_a = []
var_a = int(var_a)
while var_a//10 > 0:
list_a.append(var_a%10)
var_a = var_a//10
list_a.append(var_a%10)
list_a = list_a[::-1]
var_b = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_b))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_c = 1
list_c=list_b.copy()
list_c.sort()
var_d = list_c[var_c-1]
var_e = 3
list_d=list_b.copy()
list_d.sort()
var_f = list_d[var_e-1]
var_g = var_d + var_f
print(int(var_g)) |
Comparison | Nine people are standing in a row in order from the short person. Hoseok is standing in second place from the back, and Yuna is standing right behind Hoseok. If you line up again starting with the tall person, which place will Yuna stand from the front? | 1 | 4 3 [OP_SUB] | var_a = 4
var_b = 3
var_c = var_a - var_b
print(int(var_c)) |
Possibility | Find the number of three-digit integers that can be made by drawing 3 cards from 5 cards each containing the numbers 0, 1, 2, 3, 4. | 48 | [OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = len(list_b)
print(int(var_g)) |
Correspondence | A rice store bought 750 kilograms (kg) of rice. The first week they bought rice, they sold a few kilograms of rice, the next week they sold 3/5 of the remaining rice, and the next week they sold 5/8 of the remaining rice. 75 kg (kg) of rice was left 75 kg (kg) at the end. How many kilograms (kg) of rice did they sell in the first week? | 250 | 750 75 1 5/8 [OP_SUB] [OP_DIV] 1 3/5 [OP_SUB] [OP_DIV] [OP_SUB] | var_a = 750
var_b = 75
var_c = 1
var_d = 0.625
var_e = var_c - var_d
var_f = var_b / var_e
var_g = 1
var_h = 0.6
var_i = var_g - var_h
var_j = var_f / var_i
var_k = var_a - var_j
print(int(var_k)) |
Arithmetic calculation | There are 58 roses. The number of tulips is 15 less than the number of roses and the number of lilies is 25 more than the number of roses. What is the total number of roses, tulips, and lilies? | 184 | 58 58 15 [OP_SUB] [OP_ADD] 58 25 [OP_ADD] [OP_ADD] | var_a = 58
var_b = 58
var_c = 15
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 58
var_g = 25
var_h = var_f + var_g
var_i = var_e + var_h
print(int(var_i)) |
Geometry | The height of a rectangular parallelepiped with a volume of 49 square centimeters (cm2) is 7 centimeters (cm). Find the area of the base. | 7 | 49 7 [OP_DIV] | var_a = 49
var_b = 7
var_c = var_a / var_b
print(int(var_c)) |
Comparison | Which one has the greater volume, a card holder in the shape of a cuboid with a base area of 8 square centimeters (cm2) and a height of 3 centimeters (cm), or a dice with a side length of 6 centimeters (cm)? | dice | [OP_LIST_SOL] holder dice [OP_LIST_EOL] [OP_LIST_SOL] 8 3 [OP_MUL] 5 5 [OP_MUL] 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'holder'
var_b = 'dice'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 8
var_d = 3
var_e = var_c * var_d
var_f = 5
var_g = 5
var_h = var_f * var_g
var_i = 5
var_j = var_h * var_i
list_b= []
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_k = 1
list_c=list_b.copy()
list_c.sort()
var_l = list_c[-var_k]
var_m = list_b.index(var_l)+1
var_n = list_a[var_m-1]
print(var_n) |
Correspondence | Hansol is going to Busan by train. On the way, 263 passengers got off and 419 got on. When he counted the number of passengers arriving at his destination, Busan, there were 725 passengers. How many passengers were on the train at first? | 569 | 725 419 [OP_SUB] 263 [OP_ADD] | var_a = 725
var_b = 419
var_c = var_a - var_b
var_d = 263
var_e = var_c + var_d
print(int(var_e)) |
Comparison | Which of the four numbers among 5, 8, 3, 2 is the smallest? | 2 | [OP_LIST_SOL] 5 8 3 2 [OP_LIST_EOL] 1 [OP_LIST_MIN] | var_a = 5
var_b = 8
var_c = 3
var_d = 2
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 1
list_b=list_a.copy()
list_b.sort()
var_f = list_b[var_e-1]
print(int(var_f)) |
Possibility | If you make two-digit numbers by picking two out of six number cards 8, 3, 6, 5, 0, 7, the second largest number is A and the third largest number is B. Find (A-B)×6. | 6 | [OP_LIST_SOL] 8 3 6 5 0 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB] 6 [OP_MUL] | var_a = 8
var_b = 3
var_c = 6
var_d = 5
var_e = 0
var_f = 7
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_g))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_h = 2
list_c=list_b.copy()
list_c.sort()
var_i = list_c[-var_h]
var_j = 3
list_d=list_b.copy()
list_d.sort()
var_k = list_d[-var_j]
var_l = var_i - var_k
var_m = 6
var_n = var_l * var_m
print(int(var_n)) |
Correspondence | I multiplied a particular number by 25, when I should have divided that particular number by 4. As a result, I got 812. Find the correct calculated value. | 8.12 | 812 25 [OP_DIV] 4 [OP_DIV] | var_a = 812
var_b = 25
var_c = var_a / var_b
var_d = 4
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Correspondence | One year before my older brother was 10, my younger brother was 7 years old, and my mother was 32 when my younger brother was 5 years old. Find the sum of the ages of the younger brother and mother when the older brother is 12 years old. | 46 | 12 7 10 1 [OP_SUB] [OP_SUB] [OP_ADD] 12 7 10 [OP_SUB] [OP_ADD] 32 5 [OP_SUB] [OP_ADD] [OP_ADD] | var_a = 12
var_b = 7
var_c = 10
var_d = 1
var_e = var_c - var_d
var_f = var_b - var_e
var_g = var_a + var_f
var_h = 12
var_i = 7
var_j = 10
var_k = var_i - var_j
var_l = var_h + var_k
var_m = 32
var_n = 5
var_o = var_m - var_n
var_p = var_l + var_o
var_q = var_g + var_p
print(int(var_q)) |
Possibility | If 6 soccer teams play with each other once, how many matches will take place in total? | 15 | 6 2 [OP_COMB] | var_a = 6
var_b = 2
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c)) |
Comparison | The distance from the house to the park is 150 meters (m) more than 3 kilometers (km), and the distance from the house to the bank is 3095 meters (m). Which is farther from home, the park or the bank? | park | [OP_LIST_SOL] park bank [OP_LIST_EOL] [OP_LIST_SOL] 3 1000 [OP_MUL] 150 [OP_ADD] 3096 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'park'
var_b = 'bank'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 3
var_d = 1000
var_e = var_c * var_d
var_f = 150
var_g = var_e + var_f
var_h = 3096
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Geometry | 5 rows of 8 square-shaped checkerboards that are each 30 centimeters (cm) wide and 30 centimeters (cm) long were attached on the floor. Find the area of the plane on the checkerboard in square centimeters (m2). | 3.6 | 30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL] | var_a = 30
var_b = 100
var_c = var_a / var_b
var_d = 2
var_e = var_c ** var_d
var_f = 8
var_g = var_e * var_f
var_h = 5
var_i = var_g * var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Arithmetic calculation | The sum of 3 consecutive odd numbers is 52 greater than the largest odd number of 3 odd numbers. Write down the smallest one of the three odd numbers. | 25 | 52 2 1 [OP_MUL] 2 2 [OP_MUL] [OP_ADD] [OP_ADD] 3 1 [OP_SUB] [OP_DIV] 2 2 [OP_MUL] [OP_SUB] | var_a = 52
var_b = 2
var_c = 1
var_d = var_b * var_c
var_e = 2
var_f = 2
var_g = var_e * var_f
var_h = var_d + var_g
var_i = var_a + var_h
var_j = 3
var_k = 1
var_l = var_j - var_k
var_m = var_i / var_l
var_n = 2
var_o = 2
var_p = var_n * var_o
var_q = var_m - var_p
print(int(var_q)) |
Comparison | There are 6 numbers 1, 4, 25, 16, 22, and 14. What is the 2nd smallest number? | 4 | [OP_LIST_SOL] 1 4 25 16 22 14 [OP_LIST_EOL] 2 [OP_LIST_MIN] | var_a = 1
var_b = 4
var_c = 25
var_d = 16
var_e = 22
var_f = 14
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 2
list_b=list_a.copy()
list_b.sort()
var_h = list_b[var_g-1]
print(int(var_h)) |
Comparison | The distance from the house to the orchard is 396 meters (m) and the distance from the house to the market is 0.389 kilometers (km). Which is closer to the house, the orchard or the market? | mart | [OP_LIST_SOL] orchard mart [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'orchard'
var_b = 'mart'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 396
var_d = 0.389
var_e = 1000
var_f = var_d * var_e
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Correspondence | Divide 244.8 by some number to get 51. Find the value multiplied by 15. | 72 | 244.8 51 [OP_DIV] 15 [OP_MUL] | var_a = 244.8
var_b = 51
var_c = var_a / var_b
var_d = 15
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | Each gift box contains 156 candies. How many candies will you need in total if you are going to distribute each gift box to 20 children? | 3120 | 156 20 [OP_MUL] | var_a = 156
var_b = 20
var_c = var_a * var_b
print(int(var_c)) |
Geometry | A trapezoid is a quadrilateral with one pair of opposite sides parallel to each other. A triangle shape was cut out of this trapezoid so that the remaining opposite sides were parallel. If the base of a shape made like this is 9.51 centimeters (cm) and the height is 4.8 centimeters (cm), what is the area? | 45.65 | 9.51 4.8 [OP_MUL] | var_a = 9.51
var_b = 4.8
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | Find the sum of the following six natural numbers. 36, 17, 32, 54, 28, 3. | 170 | [OP_LIST_SOL] 36 17 32 54 28 3 [OP_LIST_EOL] [OP_LIST_SUM] | var_a = 36
var_b = 17
var_c = 32
var_d = 54
var_e = 28
var_f = 3
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
list_a = [float(i) for i in list_a]
var_g = sum(list_a)
print(int(var_g)) |
Arithmetic calculation | To make ribbons in Dayeon's class, 10 students divided the ribbon tapes by 0.84 meters (m). If the ribbon tape had 50 centimeters (cm) left after it was divided, how many meters (m) were it before it was divided? | 8.9 | 0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD] | var_a = 0.84
var_b = 10
var_c = var_a * var_b
var_d = 50
var_e = 100
var_f = var_d / var_e
var_g = var_c + var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Arithmetic calculation | There are three numbers 10, 11, and 12. What is the largest number divided by the second smallest number? | 1.09 | [OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV] | var_a = 10
var_b = 11
var_c = 12
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
list_b=list_a.copy()
list_b.sort()
var_e = list_b[-var_d]
var_f = 2
list_c=list_a.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = var_e / var_g
print('{:.2f}'.format(round(var_h+1e-10,2))) |
Possibility | Using the number cards 1, 6, and 8 all at least once, find the difference between the largest three-digit number and the third largest three-digit number. | 243 | [OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_SUB] [OP_ABS] | var_a = 1
var_b = 6
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = 3
var_h = list_b[var_g-1]
var_i = var_f - var_h
var_j = abs(var_i)
print(int(var_j)) |
Arithmetic calculation | What is the largest number that is a multiple of 4 and a factor of 108? | 108 | 108 [OP_LIST_GET_DIVISOR] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] | var_a = 108
list_a = []
num_sqrt = int(math.sqrt(var_a))
for i in range(1, num_sqrt+1):
if var_a % i == 0:
list_a.append(i)
list_a.append(int(var_a/i))
list_a = sorted(set(list_a))
var_b = 4
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = 1
list_c=list_b.copy()
list_c.sort()
var_d = list_c[-var_c]
print(int(var_d)) |
Geometry | I have decided to mark two lines every 4 meters (m) on a 68 meter (m) line. How many marks are there? (Note that both ends of the string are also marked). | 36 | 68 4 [OP_DIV] 2 [OP_MUL] 2 [OP_ADD] | var_a = 68
var_b = 4
var_c = var_a / var_b
var_d = 2
var_e = var_c * var_d
var_f = 2
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | There are even numbers from 2 to 20. What is the 3rd largest number minus the 4th smallest number? | 8 | 2 20 [OP_LIST_EVEN] 3 [OP_LIST_MAX] 4 [OP_LIST_MIN] [OP_SUB] | var_a = 2
var_b = 20
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 3
list_b=list_a.copy()
list_b.sort()
var_d = list_b[-var_c]
var_e = 4
list_c=list_a.copy()
list_c.sort()
var_f = list_c[var_e-1]
var_g = var_d - var_f
print(int(var_g)) |
Correspondence | The quotient of 59 divided by the natural number A is 6 and the remainder is 5. What is the value of A? | 9 | 59 5 [OP_SUB] 6 [OP_DIV] | var_a = 59
var_b = 5
var_c = var_a - var_b
var_d = 6
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | When you divide a certain number by 3, you get a result equal to the number you divided. What number is it? | 9 | 3 3 [OP_MUL] | var_a = 3
var_b = 3
var_c = var_a * var_b
print(int(var_c)) |
Geometry | If the height of a parallelogram with an area of 108 square centimeters is 9 centimeters (cm), what is the length of the base in centimeters (cm)? | 12 | 108 9 [OP_DIV] | var_a = 108
var_b = 9
var_c = var_a / var_b
print(int(var_c)) |
Arithmetic calculation | Watermelons of the same size and weight were filled in a basket, and the basket weighed 63 kilograms (kg). After removing half of the watermelons, the basket weighed 34 kilograms (kg). What was the weight of the watermelons without the basket before they were removed? | 58 | 63 34 [OP_SUB] 2 [OP_MUL] | var_a = 63
var_b = 34
var_c = var_a - var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Comparison | Jiwoo is 1.32 meters (m) tall and Heejin is 1.3 meters (m) tall. If the class numbers students from the shortest to the tallest, which of Jiwoo's and Heejin's numbers is higher? | Jiwoo | [OP_LIST_SOL] Jiwoo Heejin [OP_LIST_EOL] [OP_LIST_SOL] 1.32 1.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jiwoo'
var_b = 'Heejin'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 1.32
var_d = 1.3
list_b= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = list_b.index(var_f)+1
var_h = list_a[var_g-1]
print(var_h) |
Comparison | When 45 boxes of different sizes are arranged in order from smallest to largest, the red box is 29th from the right. If the boxes are arranged in order of size starting from the largest, how far from the right should the red box be? | 17 | 45 29 [OP_SUB] 1 [OP_ADD] | var_a = 45
var_b = 29
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Geometry | How many diagonals are there in a figure composed of ten angles? | 35 | 10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 10
var_b = 10
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Arithmetic calculation | Yuna's family drank 0.4 of the milk today, and the amount of milk was 0.69 liters (L). Find how many liters (L) of milk were in the beginning. | 1.73 | 0.69 0.4 [OP_DIV] | var_a = 0.69
var_b = 0.4
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | If the sum of two consecutive natural numbers is 39, find the larger of the two natural numbers. | 20 | 39 1 [OP_ADD] 2 [OP_DIV] | var_a = 39
var_b = 1
var_c = var_a + var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | There are 3 tulips and 4 carnations in the flower bed. How many flowers are there in the flower bed in total? | 7 | 3 4 [OP_ADD] | var_a = 3
var_b = 4
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | When a number is divided by 30, it leaves a remainder of 14, when divided by 50, it leaves a remainder of 24, and when divided by 70, it leaves a remainder of 34. Find the smallest number that satisfies this condition. | 524 | 0 9999 1 [OP_LIST_ARANGE] 30 14 [OP_LIST_DIVIDE_AND_REMAIN] 50 24 [OP_LIST_DIVIDE_AND_REMAIN] 70 34 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN] | var_a = 0
var_b = 9999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 30
var_e = 14
list_b = []
var_d = int(var_d)
var_e = int(var_e)
if var_e < 0:
var_e = var_e + var_d
for i in list_a:
i = int(i)
if i%var_d == var_e:
list_b.append(i)
var_f = 50
var_g = 24
list_c = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_b:
i = int(i)
if i%var_f == var_g:
list_c.append(i)
var_h = 70
var_i = 34
list_d = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_c:
i = int(i)
if i%var_h == var_i:
list_d.append(i)
var_j = 1
list_e=list_d.copy()
list_e.sort()
var_k = list_e[var_j-1]
print(int(var_k)) |
Possibility | Dongbin uses 6, 2, and 5 to make a three-digit number. What is the difference between the largest number and the smallest number Dongbin can make? | 396 | [OP_LIST_SOL] 6 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 6
var_b = 2
var_c = 5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = 1
list_d=list_b.copy()
list_d.sort()
var_h = list_d[var_g-1]
var_i = var_f - var_h
print(int(var_i)) |
Arithmetic calculation | Jimin got 87 points in Korean and 98 points in math. How many English points should Jimin get in order to get an average point of 95 on the Korean, Math, and English tests? | 100 | 95 3 [OP_MUL] 98 [OP_SUB] 87 [OP_SUB] | var_a = 95
var_b = 3
var_c = var_a * var_b
var_d = 98
var_e = var_c - var_d
var_f = 87
var_g = var_e - var_f
print(int(var_g)) |
Arithmetic calculation | There were 15 pigeons. After a while, a few more pigeons flew in, bringing the total to 21. How many pigeons flew by? | 6 | 21 15 [OP_SUB] | var_a = 21
var_b = 15
var_c = var_a - var_b
print(int(var_c)) |
Possibility | You are going to create a two-digit number using the numbers 3 and 5 only once. How many two-digit numbers can you make? | 2 | [OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 3
var_b = 5
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = len(list_b)
print(int(var_d)) |
Comparison | A rabbit and a tortoise are racing. During the same time, the rabbit ran 1/100 of 10.2 kilometers (km), and the tortoise ran 100 meters (m). Who ran more, the rabbit or the tortoise? | rabbit | [OP_LIST_SOL] rabbit tortoise [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'rabbit'
var_b = 'tortoise'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 10.2
var_d = 1000
var_e = var_c * var_d
var_f = 0.01
var_g = var_e * var_f
var_h = 100
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | Find the number of odd numbers from 1 to 9. | 5 | 1 9 [OP_LIST_ODD] [OP_LIST_LEN] | var_a = 1
var_b = 9
list_a = []
if var_a%2==0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = len(list_a)
print(int(var_c)) |
Possibility | How many ways can you wear 3 different shirts and 4 pants in combination? | 12 | 3 4 [OP_MUL] | var_a = 3
var_b = 4
var_c = var_a * var_b
print(int(var_c)) |
Arithmetic calculation | You surveyed regarding the number of elementary school students in one area of Seoul, and found out that there are 786 students at (A) school, 777 for (B) school, 762 for (C) school, 819 for (D) school, and 493 for (E) school. How many schools have an even number of students? | 2 | [OP_LIST_SOL] 786 777 762 819 493 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 786
var_b = 777
var_c = 762
var_d = 819
var_e = 493
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 2
list_b = []
var_f = int(var_f)
for i in list_a:
i = int(i)
if i % var_f == 0:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Arithmetic calculation | Hoseok ate 8 apples, 5 pears, 12 tangerines, 17 lemons, and 10 watermelons. Find the number of lemons eaten minus the number of pears eaten. | 12 | 17 5 [OP_SUB] | var_a = 17
var_b = 5
var_c = var_a - var_b
print(int(var_c)) |
Arithmetic calculation | There are five numbers 10, 11, 12, 13, and 14. What is the largest number divided by the smallest number? | 1.4 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
list_b=list_a.copy()
list_b.sort()
var_g = list_b[-var_f]
var_h = 1
list_c=list_a.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = var_g / var_i
print('{:.2f}'.format(round(var_j+1e-10,2))) |
Arithmetic calculation | You will need 4 meters (m) of wire to draw one circle. If Taemin's wire is 105.8 meters (m) long, how many circles can he draw? | 26 | 105.8 4 [OP_FDIV] | var_a = 105.8
var_b = 4
var_c = var_a // var_b
print(int(var_c)) |
Correspondence | If A85-2B=364, what number should go in B? | 1 | A85-2B=364 B [OP_DIGIT_UNK_SOLVER] | var_a = 'A85-2B=364'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Correspondence | You had to multiply 2 by a number but mistakenly multiplied 5 by the number instead to get 40. Find the correctly calculated value. | 16 | 40 5 [OP_DIV] 2 [OP_MUL] | var_a = 40
var_b = 5
var_c = var_a / var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Geometry | You have a rectangle with a perimeter of 54 centimeters (cm). If the vertical length is 3 centimeters (cm) shorter than the horizontal length, what is the horizontal length? | 15 | 54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD] | var_a = 54
var_b = 2
var_c = var_a / var_b
var_d = 3
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 3
var_i = var_g + var_h
print(int(var_i)) |
Geometry | Given a hexahedron, find the number of its faces. | 6 | 6 | var_a = 6
print(int(var_a)) |
Geometry | Three points are not in a straight line. How many rays are there for these three points? | 6 | 3 2 [OP_PERM] | var_a = 3
var_b = 2
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
print(int(var_c)) |
Arithmetic calculation | There is a centipede that travels 5 meters (m) in 3 minutes and an earthworm that travels 5 meters (m) in 2 minutes at a constant speed. If this centipede started 20 meters (m) ahead of the worm in the same direction at the same time, find out what time in minutes the centipede and the worm meet. | 24 | 20 5 2 [OP_DIV] 5 3 [OP_DIV] [OP_SUB] [OP_DIV] | var_a = 20
var_b = 5
var_c = 2
var_d = var_b / var_c
var_e = 5
var_f = 3
var_g = var_e / var_f
var_h = var_d - var_g
var_i = var_a / var_h
print(int(eval('{:.2f}'.format(round(var_i+1e-10,2))))) |
Arithmetic calculation | There are 43, 92, 71, and 64. What is the largest number minus the smallest number? | 49 | [OP_LIST_SOL] 43 92 71 64 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 43
var_b = 92
var_c = 71
var_d = 64
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 1
list_b=list_a.copy()
list_b.sort()
var_f = list_b[-var_e]
var_g = 1
list_c=list_a.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = var_f - var_h
print(int(var_i)) |
Possibility | There are 5 number cards, one each with a number from 1 to 5 written on it. What is the number of all cases that can come out when taking out three of these and calculating the sum of each number? | 60 | 1 5 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] [OP_LIST_LEN] | var_a = 1
var_b = 5
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = len(list_c)
print(int(var_f)) |
Arithmetic calculation | Divide 13 by A, and you get 4 as the quotient and B as the remainder. Both A, B are natural numbers. Find the smallest possible value of B. | 1 | 1 | var_a = 1
print(int(var_a)) |
Arithmetic calculation | 21 liters (L) of ethanol was added to the flask for 6 minutes. The flask took 22 minutes and 30 seconds to be filled, with 0.3 liters (L) of ethanol draining out per minute. Find how many liters (L) the volume of the first flask was. | 72 | 21 6 [OP_DIV] 0.3 [OP_SUB] 22 30 60 [OP_DIV] [OP_ADD] [OP_MUL] | var_a = 21
var_b = 6
var_c = var_a / var_b
var_d = 0.3
var_e = var_c - var_d
var_f = 22
var_g = 30
var_h = 60
var_i = var_g / var_h
var_j = var_f + var_i
var_k = var_e * var_j
print(int(var_k)) |
Correspondence | Chowon used 1/5 of the entire tape yesterday while packing the box for two days, and used 3/4 of the remaining tape today. If the length of the remaining tape is 1 meter (m) and 50 centimeters (cm), how long is the length of the tape that Chowon originally had in meters (m)? | 7.5 | 1 50 100 [OP_DIV] [OP_ADD] 1 3/4 [OP_SUB] [OP_DIV] 1 1/5 [OP_SUB] [OP_DIV] | var_a = 1
var_b = 50
var_c = 100
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 1
var_g = 0.75
var_h = var_f - var_g
var_i = var_e / var_h
var_j = 1
var_k = 0.2
var_l = var_j - var_k
var_m = var_i / var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
Arithmetic calculation | When it comes to mountain climbing, there are two routes. One is a shorter route, and the other one is 2 kilometers (km) longer than the short one. When you went up, you walked at 3 kilometers (km) per hour on a short path, and a long path at 4 kilometers (km) per hour on the way down. If it took 4 hours in total, how many kilometers (km) did you walk? | 14 | 4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_MUL] 2 [OP_ADD] | var_a = 4
var_b = 2
var_c = 4
var_d = var_b / var_c
var_e = var_a - var_d
var_f = 1
var_g = 3
var_h = var_f / var_g
var_i = 1
var_j = 4
var_k = var_i / var_j
var_l = var_h + var_k
var_m = var_e / var_l
var_n = 2
var_o = var_m * var_n
var_p = 2
var_q = var_o + var_p
print(int(eval('{:.2f}'.format(round(var_q+1e-10,2))))) |
Arithmetic calculation | Of the 30 students in the class, 4 have math scores of 90, 85, 88, and 80, respectively, and the average math score of the other 26 is 82. What is the average score in math for the whole class? Answer including decimal points. | 82.5 | 26 82 [OP_MUL] 90 [OP_ADD] 85 [OP_ADD] 88 [OP_ADD] 80 [OP_ADD] 30 [OP_DIV] | var_a = 26
var_b = 82
var_c = var_a * var_b
var_d = 90
var_e = var_c + var_d
var_f = 85
var_g = var_e + var_f
var_h = 88
var_i = var_g + var_h
var_j = 80
var_k = var_i + var_j
var_l = 30
var_m = var_k / var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
Correspondence | Yulgi spent 300 won more than 2/5 of the money he had yesterday, and 200 won less than 1/2 of the rest today. If the remaining money is 800 won, how much money did Yulgi have yesterday? | 2500 | 800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV] | var_a = 800
var_b = 200
var_c = var_a - var_b
var_d = 1
var_e = 0.5
var_f = var_d - var_e
var_g = var_c / var_f
var_h = 300
var_i = var_g + var_h
var_j = 1
var_k = 0.4
var_l = var_j - var_k
var_m = var_i / var_l
print(int(var_m)) |
Possibility | You want to form a three-digit number by picking three out of 1, 0, 5, 8, and 6 and using them only once. Find the difference between the largest number and the fourth smallest number that can be made. | 715 | [OP_LIST_SOL] 1 0 5 8 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 4 [OP_LIST_MIN] [OP_SUB] [OP_ABS] | var_a = 1
var_b = 0
var_c = 5
var_d = 8
var_e = 6
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 4
list_d=list_b.copy()
list_d.sort()
var_j = list_d[var_i-1]
var_k = var_h - var_j
var_l = abs(var_k)
print(int(var_l)) |
Possibility | Using 1, 7, 4, and 3 only once, find the difference between the largest three-digit number whose tens digit is 3 and the third largest three-digit number. | 297 | [OP_LIST_SOL] 1 7 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB] [OP_ABS] | var_a = 1
var_b = 7
var_c = 4
var_d = 3
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 10
var_g = 3
list_c = []
var_f = int(var_f)
var_g = int(var_g)
for i in list_b:
i = int(i)
if (i//var_f)%10 == var_g:
list_c.append(i)
var_h = 1
list_d=list_c.copy()
list_d.sort()
var_i = list_d[-var_h]
var_j = 3
list_e=list_c.copy()
list_e.sort()
var_k = list_e[-var_j]
var_l = var_i - var_k
var_m = abs(var_l)
print(int(var_m)) |
Arithmetic calculation | Five people are sitting at a round table. If 5 people shake hands with people who are not next to each other, how many handshakes will they make? | 5 | 5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 5
var_b = 5
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Arithmetic calculation | Minyoung bought 9 apples, 3 pears, and 5 persimmons, and Yoojeong bought 2 more fruits than Minyoung. If Yoojeong bought 7 apples and bought 2 fewer pears than persimmons, how many pears did Yoojeong buy? | 7 | 9 3 [OP_ADD] 5 [OP_ADD] 2 [OP_ADD] 7 [OP_SUB] 2 [OP_DIV] 1 [OP_ADD] | var_a = 9
var_b = 3
var_c = var_a + var_b
var_d = 5
var_e = var_c + var_d
var_f = 2
var_g = var_e + var_f
var_h = 7
var_i = var_g - var_h
var_j = 2
var_k = var_i / var_j
var_l = 1
var_m = var_k + var_l
print(int(var_m)) |
Geometry | Toss 2 coins high into the sky. How many numbers of cases are there for both coins to land on heads? | 1 | 1 | var_a = 1
print(int(var_a)) |
Geometry | A square is made by arranging 12 marbles of the same size without gaps in both the width and length. How many marbles are placed around the perimeter? | 44 | 12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD] | var_a = 12
var_b = 2
var_c = var_a - var_b
var_d = 4
var_e = var_c * var_d
var_f = 4
var_g = var_e + var_f
print(int(var_g)) |
Geometry | You have used a piece of wire to make a cube whose side is 10 centimetres (cm) long. If you use the same wire to make a cube that is 8 cm long and 5 cm wide, what is its height in centimetres (cm)? | 17 | 10 12 [OP_MUL] 8 4 [OP_MUL] [OP_SUB] 5 4 [OP_MUL] [OP_SUB] 4 [OP_DIV] | var_a = 10
var_b = 12
var_c = var_a * var_b
var_d = 8
var_e = 4
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 5
var_i = 4
var_j = var_h * var_i
var_k = var_g - var_j
var_l = 4
var_m = var_k / var_l
print(int(var_m)) |
Comparison | Bank, school, stationery store, convenience store, and park is in the order of distance that is closest. Which building is the second closest? | school | [OP_LIST_SOL] Bank school stationery convenience park [OP_LIST_EOL] 2 [OP_LIST_GET] | var_a = 'Bank'
var_b = 'school'
var_c = 'stationery'
var_d = 'convenience'
var_e = 'park'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 2
var_g = list_a[var_f-1]
print(var_g) |
Comparison | The truck is loaded with two boxes, (a) and (b). Box (a) is smaller than box (b). Which of the two boxes is the larger one? | (b) | [OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = '(a)'
var_b = '(b)'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = '(a)'
var_d = '(b)'
var_e = '<'
list_b= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_f = 1
var_g = list_c[var_f-1]
print(var_g) |
Possibility | Sehun wants to make a three-digit number by using the single-digit natural numbers 0, 2, and 9 once each. How many total can he make? | 4 | [OP_LIST_SOL] 0 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 2
var_c = 9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Geometry | There are regular hexagonal prisms and square pyramids with the same edges. The sum of the lengths of all the edges of the hexagonal prism is 81 centimeters (cm). What is the sum of the lengths of all the edges of the pyramid in centimeters (cm)? | 36 | 81 6 3 [OP_MUL] [OP_DIV] 4 2 [OP_MUL] [OP_MUL] | var_a = 81
var_b = 6
var_c = 3
var_d = var_b * var_c
var_e = var_a / var_d
var_f = 4
var_g = 2
var_h = var_f * var_g
var_i = var_e * var_h
print(int(var_i)) |
Comparison | While Yoongi, Jungkook, and Yuna have following numbers: 4, 6 minus 3, and 5, who has the smallest number? | Jungkook | [OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Jungkook'
var_c = 'Yuna'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 6
var_f = 3
var_g = var_e - var_f
var_h = 5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Comparison | There are numbers 0.8, 1/2, 0.9, and 1/3. Find the smallest number that is greater than or equal to 0.6. | 0.8 | [OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.6 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN] | var_a = 0.8
var_b = 0.5
var_c = 0.9
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 0.6
list_b = []
for i in list_a:
if i >= var_e:
list_b.append(i)
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[var_f-1]
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Correspondence | What number is A in 56-1A=39? | 7 | 56-1A=39 A [OP_DIGIT_UNK_SOLVER] | var_a = '56-1A=39'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | There are two buckets of water. The left bucket holds 2800 litres (L) of water and the right bucket holds 1500 L of water. When the water in the left bucket was transferred to the right bucket, the left bucket contained 360 litres (L) more water than the right bucket. Find the number of litres (L) of water transferred to the right bucket. | 470 | 2800 1500 [OP_SUB] 360 [OP_SUB] 2 [OP_DIV] | var_a = 2800
var_b = 1500
var_c = var_a - var_b
var_d = 360
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Correspondence | 6A5+B03=748. How much is A? | 4 | 6A5+B03=748 A [OP_DIGIT_UNK_SOLVER] | var_a = '6A5+B03=748'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
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