id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__XSPZryAETifJte7U | 18 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? Choose the correct choice from the following choices
A) 230
B) 274
C) 306
D) 354
E) 424 | <gadget id="calculator">18 - 1</gadget>
<output>17</output>
<gadget id="calculator">18 * 17</gadget>
<output>306</output>
<result>C</result> | C | 306 | 18 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? | {
"A": "230",
"B": "274",
"C": "306",
"D": "354",
"E": "424"
} | multiply(18, subtract(18, const_1)) | subtract(n0,const_1)|multiply(n0,#0)| | "2 * 18 c 2 = 2 * 153 = 306 the answer is c ." | general |
math_qa__VWFFzJEyELwLeXaz | A 6-liter solution is 40% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol? Choose the correct option: A) 1.2 B) 1.5 C) 1.8 D) 2.1 E) 2.4 | <gadget id="calculator">6 * 40</gadget>
<output>240</output>
<gadget id="calculator">240 / 100</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 2</gadget>
<output>24/5 = around 4.8</output>
<gadget id="calculator">6 - (24/5)</gadget>
<output>6/5 = around 1.2</output>
<result>A</result> | A | 1.2 | A 6-liter solution is 40% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol? | {
"A": "1.2",
"B": "1.5",
"C": "1.8",
"D": "2.1",
"E": "2.4"
} | subtract(6, multiply(divide(multiply(6, 40), const_100), const_2)) | multiply(n0,n1)|divide(#0,const_100)|multiply(#1,const_2)|subtract(n0,#2) | let x be the amount of pure alcohol required . 0.4 ( 6 ) + x = 0.5 ( x + 6 ) 0.5 x = 3 - 2.4 x = 1.2 liters the answer is a . | general |
math_qa__jfzKcZ6KGDNwPkWy | When the positive integer x is divided by 9,the remainder is 5.What is the remainder when 7x is divided by 9? Select: A) 0 B) 1 C) 3 D) 4 E) 8 | <gadget id="calculator">5 * 7</gadget>
<output>35</output>
<gadget id="calculator">35 % 9</gadget>
<output>8</output>
<result>E</result> | E | 8 | When the positive integer x is divided by 9,the remainder is 5.What is the remainder when 7x is divided by 9? | {
"A": "0",
"B": "1",
"C": "3",
"D": "4",
"E": "8"
} | reminder(multiply(5, 7), 9) | multiply(n1,n2)|reminder(#0,n0) | i tried plugging in numbers x = 9 q + 5 x = 14 7 x = 98 7 x / 9 = 9 * 10 + 8 remainder is 8 answer is e . | general |
math_qa__QdGKQB1b2uwFrN0c | An alloy weighing 26 ounces is 70 percent gold. How many ounces of pure gold must be added to create an alloy that is 90 percent gold?
Choose the correct choice from the following answers.
A) 6 B) 9 C) 12 D) 34 E) 48 | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 26</gadget>
<output>117/5 = around 23.4</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(117/5) / (7/10)</gadget>
<output>234/7 = around 33.428571</output>
<result>D</result> | D | 34 | An alloy weighing 26 ounces is 70 percent gold. How many ounces of pure gold must be added to create an alloy that is 90 percent gold? | {
"A": "6",
"B": "9",
"C": "12",
"D": "34",
"E": "48"
} | divide(multiply(divide(90, const_100), 26), divide(70, const_100)) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|divide(#2,#1) | in 24 ounces , gold is 26 * ( 70 / 100 ) = 18.2 ounces . now we add x ounces of pure gold to make it 90 % gold . so 18.2 + x = ( 24 + x ) * 90 / 100 = > x = 34 . answer is d . | gain |
math_qa__Rpwp62AAQtd79Tr0 | An inspector rejects 10% of the meters as defective. How many will he examine to reject 15?
Choose the correct option.
A) 100
B) 150
C) 250
D) 200
E) 160 | <gadget id="calculator">15 * 100</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 10</gadget>
<output>150</output>
<result>B</result> | B | 150 | An inspector rejects 10% of the meters as defective. How many will he examine to reject 15? | {
"A": "100",
"B": "150",
"C": "250",
"D": "200",
"E": "160"
} | divide(multiply(15, const_100), 10) | multiply(n1,const_100)|divide(#0,n0)| | "then , 10 % of x = 15 ( 10 / 100 ) x = 15 x = ( 15 * 100 * ) / 10 = 150 answer is b" | gain |
math_qa__bJWucMpXBffuZfDr | The sale price sarees listed for Rs.400 after successive discount is 25% and 20% is? Pick.
A) 297 B) 879 C) 342 D) 240 E) 269 | <gadget id="calculator">400 * 25</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 100</gadget>
<output>100</output>
<gadget id="calculator">400 - 100</gadget>
<output>300</output>
<gadget id="calculator">300 * 20</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 100</gadget>
<output>60</output>
<gadget id="calculator">300 - 60</gadget>
<output>240</output>
<result>D</result> | D | 240 | The sale price sarees listed for Rs.400 after successive discount is 25% and 20% is? | {
"A": "297",
"B": "879",
"C": "342",
"D": "240",
"E": "269"
} | subtract(subtract(400, divide(multiply(400, 25), const_100)), divide(multiply(subtract(400, divide(multiply(400, 25), const_100)), 20), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "400 * ( 75 / 100 ) * ( 80 / 100 ) = 240 answer : d" | gain |
math_qa__yazRgQfOnB7niS9o | Two trains of length 120 m and 210 m are 80 m apart. They start moving towards each other on parallel tracks, at speeds 69 kmph and 82 kmph. After how much time will the trains meet? Pick one: A) 15 / 10 B) 19 / 10 C) 20 / 19 D) 16 / 10 E) 27 / 10 | <gadget id="calculator">69 + 82</gadget>
<output>151</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">151 * (5/18)</gadget>
<output>755/18 = around 41.944444</output>
<gadget id="calculator">80 / (755/18)</gadget>
<output>288/151 = around 1.907285</output>
<result>B</result> | B | 1.9 | Two trains of length 120 m and 210 m are 80 m apart. They start moving towards each other on parallel tracks, at speeds 69 kmph and 82 kmph. After how much time will the trains meet? | {
"A": "15 / 10",
"B": "19 / 10",
"C": "20 / 19",
"D": "16 / 10",
"E": "27 / 10"
} | divide(80, multiply(add(69, 82), const_0_2778)) | add(n3,n4)|multiply(#0,const_0_2778)|divide(n2,#1)| | "they are moving in opposite directions , relative speed is equal to the sum of their speeds . relative speed = ( 69 + 82 ) * 5 / 18 = 41.9 mps . the time required = d / s = 80 / 41.9 = 19 / 10 sec . answer : b" | physics |
math_qa__OikuGV18BdTfsEHu | A and B can finish a work in 16 days while A alone can do the same work in 24 days. In how many days B alone will complete the work?
Choose the correct choice from the following choices: A) 76 days B) 48 days C) 98 days D) 31 days E) 22 days | <gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/16) - (1/24)</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">1 / (1/48)</gadget>
<output>48</output>
<result>B</result> | B | 48 | A and B can finish a work in 16 days while A alone can do the same work in 24 days. In how many days B alone will complete the work? | {
"A": "76 days",
"B": "48 days",
"C": "98 days",
"D": "31 days",
"E": "22 days"
} | inverse(subtract(inverse(16), inverse(24))) | inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2)| | "b = 1 / 16 – 1 / 24 = 1 / 48 = > 48 days answer : b" | physics |
math_qa__TXlMOi2UPzbpurQN | A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
Pick one
A) 200 m B) 700 m C) 800 m D) 100 metre E) 1004 m | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 + (1/2)</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(9/2) / 5</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 - (9/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 1_000</gadget>
<output>100</output>
<result>D</result> | D | 100 | A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat? | {
"A": "200 m",
"B": "700 m",
"C": "800 m",
"D": "100 metre",
"E": "1004 m"
} | multiply(subtract(const_1, divide(add(4, divide(1, 2)), 5)), const_1000) | divide(n1,n2)|add(n0,#0)|divide(#1,n3)|subtract(const_1,#2)|multiply(#3,const_1000) | explanation : a can give b ( 5 min - 4 1 / 2 min ) = 30 sec start . the distance covered by b in 5 min = 1000 m . distance covered in 30 sec = ( 1000 * 30 ) / 300 = 100 m . a can give b 100 m start . answer : d | physics |
math_qa__XiruBS83LTqHUdu3 | When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 42, what is the remainder when k is divided by 7?
Answers:
A) 5
B) 3
C) 6
D) 7
E) 10 | <gadget id="calculator">12 + 5</gadget>
<output>17</output>
<gadget id="calculator">17 % 7</gadget>
<output>3</output>
<result>B</result> | B | 3 | When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 42, what is the remainder when k is divided by 7? | {
"A": "5",
"B": "3",
"C": "6",
"D": "7",
"E": "10"
} | reminder(add(const_12, 5), 7) | add(n0,const_12)|reminder(#0,n5)| | "cant think of a straight approach but here is how i solved it : k is divided by 5 and remainder is 2 . this means k = 5 n + 2 ( n is an integer ) so the possible values of k = { 2 , 7 , 12 , 17 , 22 , 27 , 32 , 37 } ( less than 42 ) secondly , if k is divided by 6 , the remainder is 5 = > k = 6 m + 5 so the possible value set for k = { 5 , 11 , 17 , 23 , 29 , 35,41 } ( less than 42 ) 17 is the only common number in both the sets . hence k = 17 answer : b" | general |
math_qa__96QnIMQBJoXpPM2o | A student chose a number, multiplied it by 6, then subtracted 138 from the result and got 102. What was the number he chose? Options:
A) 40
B) 120
C) 130
D) 140
E) 150 | <gadget id="calculator">102 + 138</gadget>
<output>240</output>
<gadget id="calculator">240 / 6</gadget>
<output>40</output>
<result>A</result> | A | 40 | A student chose a number, multiplied it by 6, then subtracted 138 from the result and got 102. What was the number he chose? | {
"A": "40",
"B": "120",
"C": "130",
"D": "140",
"E": "150"
} | divide(add(102, 138), 6) | add(n1,n2)|divide(#0,n0)| | "solution : let xx be the number he chose , then 6 ⋅ x − 138 = 102 6 x = 240 x = 40 answer a" | general |
math_qa__9wSaTV3zFwlpZ079 | 10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is : Choose the correct choice from the following
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">24 * 6</gadget>
<output>144</output>
<gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">96 + 40</gadget>
<output>136</output>
<gadget id="calculator">144 - 136</gadget>
<output>8</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>C</result> | C | 3 | 10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is : | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(subtract(subtract(multiply(24, add(4, 2)), add(multiply(24, 4), multiply(10, 4))), 2), 2) | add(n1,n3)|multiply(n1,n2)|multiply(n0,n1)|add(#1,#2)|multiply(n2,#0)|subtract(#4,#3)|subtract(#5,n3)|divide(#6,n3)| | "explanation : total age of 4 members , 10 years ago = ( 24 x 4 ) years = 96 years . total age of 4 members now = [ 96 + ( 10 x 4 ) ] years = 136 years . total age of 6 members now = ( 24 x 6 ) years = 144 years . sum of the ages of 2 children = ( 144 - 136 ) years = 8 years . let the age of the younger child be x years . then , age of the elder child = ( x + 2 ) years . so , x + ( x + 2 ) = 8 ⇔ x = 3 age of younger child = 3 years . answer : c" | general |
math_qa__GLoNPWbbYKIgEuWj | If it takes 70 workers 3 hours to disassemble the exhibition rides at a small amusement park, how many hours would it take 30 workers to do this same job? Choose one: A) 40 / 3 B) 11 C) 7 D) 7 / 3 E) 9 / 7 | <gadget id="calculator">70 * 3</gadget>
<output>210</output>
<gadget id="calculator">210 / 30</gadget>
<output>7</output>
<result>C</result> | C | 7 | If it takes 70 workers 3 hours to disassemble the exhibition rides at a small amusement park, how many hours would it take 30 workers to do this same job? | {
"A": "40 / 3",
"B": "11",
"C": "7",
"D": "7 / 3",
"E": "9 / 7"
} | divide(multiply(70, 3), 30) | multiply(n0,n1)|divide(#0,n2) | 70 workers = 3 hours then , 1 worker = 3 * 70 hours 30 workers = ( 3 * 70 ) / ( 30 ) = 7 answer : c | physics |
math_qa__esPZM3jJ2vWHpQGG | The average monthly salary of 8 workers and one supervisor in a factory was 430.@SSWhen@SSthe@SSsupervisor@CC@SSwhose@SSsalary@SSwas@SS430.@SSWhen@SSthe@SSsupervisor@CC@SSwhose@SSsalary@SSwas@SS430.Whenthesupervisor,whosesalarywas430. When the supervisor, whose salary was 870 per month, retired, a new person was appointed and then the average salary of 9 people was $$390 per month. The salary of the new supervisor is:
Select the correct option:
A) 233
B) 600
C) 510
D) 771
E) 191 | <gadget id="calculator">390 * 9</gadget>
<output>3_510</output>
<gadget id="calculator">430 * 9</gadget>
<output>3_870</output>
<gadget id="calculator">3_870 - 870</gadget>
<output>3_000</output>
<gadget id="calculator">3_510 - 3_000</gadget>
<output>510</output>
<result>C</result> | C | 510 | The average monthly salary of 8 workers and one supervisor in a factory was 430.@SSWhen@SSthe@SSsupervisor@CC@SSwhose@SSsalary@SSwas@SS430.@SSWhen@SSthe@SSsupervisor@CC@SSwhose@SSsalary@SSwas@SS430.Whenthesupervisor,whosesalarywas430. When the supervisor, whose salary was 870 per month, retired, a new person was appointed and then the average salary of 9 people was $$390 per month. The salary of the new supervisor is: | {
"A": "233",
"B": "600",
"C": "510",
"D": "771",
"E": "191"
} | subtract(multiply(390, 9), subtract(multiply(430, 9), 870)) | multiply(n6,n7)|multiply(n1,n6)|subtract(#1,n5)|subtract(#0,#2)| | "explanation : total salary of 8 workers and supervisor together = 9 ã — 430 = 3870 now total salary of 8 workers = 3870 â ˆ ’ 870 = 3000 total salary of 9 workers including the new supervisor = 9 ã — 390 = 3510 salary of the new supervisor = 3510 â ˆ ’ 3000 = 510 answer : c" | general |
math_qa__81skG91BLEmDcZzY | A invested $400 in a business after 6 months B invested $200 in the business. End of the year if they got $100 as profit. Find A shares? Select
A) $ 100 B) $ 75 C) $ 20 D) $ 120 E) $ 80 | <gadget id="calculator">200 / 2</gadget>
<output>100</output>
<gadget id="calculator">400 + 100</gadget>
<output>500</output>
<gadget id="calculator">100 / 500</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">100 * (4/5)</gadget>
<output>80</output>
<result>E</result> | E | 80 | A invested $400 in a business after 6 months B invested $200 in the business. End of the year if they got $100 as profit. Find A shares? | {
"A": "$ 100",
"B": "$ 75",
"C": "$ 20",
"D": "$ 120",
"E": "$ 80"
} | multiply(100, subtract(const_1, divide(divide(200, const_2), add(400, divide(200, const_2))))) | divide(n2,const_2)|add(n0,#0)|divide(#0,#1)|subtract(const_1,#2)|multiply(n3,#3) | a : b = 400 * 12 : 200 * 6 a : b = 4 : 1 a ' s share = 100 * 4 / 5 = $ 80 answer is e | gain |
math_qa__kiJcOtcNpo8klRvM | Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 62 km along the main road. What would be the distance between two cars at this point? Choices
A) 65 B) 38 C) 20 D) 28 E) 21 | <gadget id="calculator">150 - 62</gadget>
<output>88</output>
<gadget id="calculator">25 + 25</gadget>
<output>50</output>
<gadget id="calculator">88 - 50</gadget>
<output>38</output>
<result>B</result> | B | 38 | Two cars start from the opposite places of a main road, 150 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 62 km along the main road. What would be the distance between two cars at this point? | {
"A": "65",
"B": "38",
"C": "20",
"D": "28",
"E": "21"
} | subtract(subtract(150, 62), add(25, 25)) | add(n1,n1)|subtract(n0,n4)|subtract(#1,#0) | answer : b ) 38 km | physics |
math_qa__7HaNHznl1MsITgwt | A’s speed is 17/15 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat?
Options: A) 1 / 16 B) 2 / 15 C) 2 / 17 D) 1 / 8 E) 1 / 7 | <gadget id="calculator">17 - 15</gadget>
<output>2</output>
<gadget id="calculator">2 / 17</gadget>
<output>2/17 = around 0.117647</output>
<result>C</result> | C | 0.117647 | A’s speed is 17/15 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat? | {
"A": "1 / 16",
"B": "2 / 15",
"C": "2 / 17",
"D": "1 / 8",
"E": "1 / 7"
} | divide(subtract(17, 15), 17) | subtract(n0,n1)|divide(#0,n0)| | "let x be the fraction of the distance that b runs . let v be the speed at which b runs . the time should be the same for both runners . time = d / ( 17 v / 15 ) = xd / v ( 15 / 17 ) * d / v = x * d / v x = 15 / 17 b should have a head start of 2 / 17 of the full distance . the answer is c ." | general |
math_qa__CtQGqkxUiTx8xoTV | A factory produces 8000 toys per week. If the workers at this factory work 4 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? Choose the correct choice from the following answers
A) 4436 toys B) 5487 toys C) 2000 toys D) 2354 toys E) 1375 toys | <gadget id="calculator">8_000 / 4</gadget>
<output>2_000</output>
<result>C</result> | C | 2,000 | A factory produces 8000 toys per week. If the workers at this factory work 4 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? | {
"A": "4436 toys",
"B": "5487 toys",
"C": "2000 toys",
"D": "2354 toys",
"E": "1375 toys"
} | divide(8000, 4) | divide(n0,n1)| | "to find the number of toys produced every day , we divide the total number of toys produced in one week ( of 4 days ) by 4 . 8000 / 4 = 2000 toys correct answer c" | physics |
math_qa__bVT99bjFLd9se5jR | A store has 10 bottles of juice, including 6 bottles of apple juice. In the evening, 6 bottles of juice are sold one by one. What is the probability of selling 2 bottles of apple juice among the 6 bottles? Assume that every bottle has an equal chance of being bought. Choose the correct option
A) 1 / 7 B) 1 / 12 C) 1 / 14 D) 1 / 18 E) 1 / 21 | <gadget id="calculator">binomial(6, 2)</gadget>
<output>15</output>
<gadget id="calculator">binomial(10, 6)</gadget>
<output>210</output>
<gadget id="calculator">15 / 210</gadget>
<output>1/14 = around 0.071429</output>
<result>C</result> | C | 0.071429 | A store has 10 bottles of juice, including 6 bottles of apple juice. In the evening, 6 bottles of juice are sold one by one. What is the probability of selling 2 bottles of apple juice among the 6 bottles? Assume that every bottle has an equal chance of being bought. | {
"A": "1 / 7",
"B": "1 / 12",
"C": "1 / 14",
"D": "1 / 18",
"E": "1 / 21"
} | divide(choose(6, 2), choose(10, 6)) | choose(n1,n3)|choose(n0,n1)|divide(#0,#1) | the total number of ways to sell 6 bottles from 10 is 10 c 6 = 210 . the number of ways to sell 2 bottles of apple juice is 6 c 2 * 4 c 4 = 15 * 1 = 15 p ( selling 2 bottles of apple juice ) = 15 / 210 = 5 / 70 = 1 / 14 the answer is c . | probability |
math_qa__sVfyQsmWWUfUt4Q6 | If 1+2+3+...+n=n (n+1), then 3 (1+3+5+....+89)=? Select the correct option.
A) 6150 B) 6200 C) 6050 D) 6075 E) 5075 | <gadget id="calculator">89 + 1</gadget>
<output>90</output>
<gadget id="calculator">89 * 90</gadget>
<output>8_010</output>
<gadget id="calculator">8_010 / 2</gadget>
<output>4_005</output>
<gadget id="calculator">89 - 1</gadget>
<output>88</output>
<gadget id="calculator">88 / 2</gadget>
<output>44</output>
<gadget id="calculator">44 + 1</gadget>
<output>45</output>
<gadget id="calculator">44 * 45</gadget>
<output>1_980</output>
<gadget id="calculator">4_005 - 1_980</gadget>
<output>2_025</output>
<gadget id="calculator">2_025 * 3</gadget>
<output>6_075</output>
<result>D</result> | D | 6,075 | If 1+2+3+...+n=n (n+1), then 3 (1+3+5+....+89)=? | {
"A": "6150",
"B": "6200",
"C": "6050",
"D": "6075",
"E": "5075"
} | multiply(subtract(divide(multiply(89, add(89, 1)), 2), multiply(divide(subtract(89, 1), 2), add(divide(subtract(89, 1), 2), 1))), 3) | add(n8,n0)|subtract(n8,n0)|divide(#1,n1)|multiply(n8,#0)|add(#2,n0)|divide(#3,n1)|multiply(#4,#2)|subtract(#5,#6)|multiply(#7,n2)| | "explanation : to solve this use the formula of ap , sn = ( n / 2 ) ( a + l ) . . . . . . . . . . . . . . . . ( 1 ) to find n , use = > tn = a + ( n - 1 ) d = > 89 = 1 + ( n - 1 ) 2 = > n = 45 use value of n in ( 1 ) then , sn = ( 45 / 2 ) ( 1 + 89 ) = 2025 ans : - 3 ( sn ) = 6075 answer : d" | general |
math_qa__rM74TBOfsjlpPwub | In what time will a railway train 120 m long moving at the rate of 36 kmph pass a telegraph post on its way? Choose the correct answer:
A) 12 sec B) 7 sec C) 8 sec D) 9 sec E) 10 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">120 / 10</gadget>
<output>12</output>
<result>A</result> | A | 12 | In what time will a railway train 120 m long moving at the rate of 36 kmph pass a telegraph post on its way? | {
"A": "12 sec",
"B": "7 sec",
"C": "8 sec",
"D": "9 sec",
"E": "10 sec"
} | divide(120, multiply(36, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 120 / 36 * 18 / 5 = 12 sec answer : a" | physics |
math_qa__JxrgMX6rwPNyh0r2 | A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent Q of the distribution is less than m +d ? Options: A) 16 % B) 32 % C) 48 % D) 84 % E) 92 % | <gadget id="calculator">100 - 68</gadget>
<output>32</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<gadget id="calculator">100 - 16</gadget>
<output>84</output>
<result>D</result> | D | 84 | A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent Q of the distribution is less than m +d ? | {
"A": "16 %",
"B": "32 %",
"C": "48 %",
"D": "84 %",
"E": "92 %"
} | subtract(const_100, divide(subtract(const_100, 68), const_2)) | subtract(const_100,n0)|divide(#0,const_2)|subtract(const_100,#1)| | "d the prompt says that 68 % of the population lies between m - d and m + d . thus , 32 % of the population is less than m - d or greater than m + d . since the population is symmetric , half of this 32 % is less than m - d and half is greater than m + d . thus , q = ( 68 + 16 ) % or ( 100 - 16 ) % of the population is less than m + d ." | general |
math_qa__HyYVhK1EuBObaICW | The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 1400 per sq.metre. Choose the correct choice.
A) rs . 15,000 B) rs . 15,500 C) rs . 15,600 D) rs . 28,875 E) none | <gadget id="calculator">5.5 * 3.75</gadget>
<output>20.625</output>
<gadget id="calculator">1_400 * 20.625</gadget>
<output>28_875</output>
<result>D</result> | D | 28,875 | The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 1400 per sq.metre. | {
"A": "rs . 15,000",
"B": "rs . 15,500",
"C": "rs . 15,600",
"D": "rs . 28,875",
"E": "none"
} | multiply(1400, multiply(5.5, 3.75)) | multiply(n0,n1)|multiply(n2,#0)| | "solution area of the floor = ( 5.5 x 3.75 ) m ² = 20.635 m ² cost of paying = rs . ( 1400 x 20.625 ) = rs . 28875 . answer d" | physics |
math_qa__kQVkc7ZsRGiDkgc0 | Find the smallest positive integer n such that 11n - 1 is divisible by 105.
Select the correct option
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 105</gadget>
<output>630</output>
<gadget id="calculator">630 / 105</gadget>
<output>6</output>
<result>D</result> | D | 6 | Find the smallest positive integer n such that 11n - 1 is divisible by 105. | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(multiply(multiply(const_2, const_3), 105), 105) | multiply(const_2,const_3)|multiply(n2,#0)|divide(#1,n2) | the last digit of 11 n − 1 is 0 , so 5 always divides 11 n − 1 . also , checking the remainders when the powers of 11 are divided by 3 and 7 we get that 3 divides 11 n − 1 exactly when n is even , and 7 divides 11 n − 1 exactly when 3 divides n . correct answer d | general |
math_qa__VKxmFImI9F1vcSQO | There are 89 people that own pets. 15 people own only dogs, 10 people own only cats, 5 people own only cats and dogs, 3 people own cats, dogs and snakes. How many total snakes are there?
Choose the correct choice: A) 2 B) 4 C) 8 D) 59 E) 32 | <gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 5</gadget>
<output>30</output>
<gadget id="calculator">30 + 3</gadget>
<output>33</output>
<gadget id="calculator">89 - 33</gadget>
<output>56</output>
<gadget id="calculator">56 + 3</gadget>
<output>59</output>
<result>D</result> | D | 59 | There are 89 people that own pets. 15 people own only dogs, 10 people own only cats, 5 people own only cats and dogs, 3 people own cats, dogs and snakes. How many total snakes are there? | {
"A": "2",
"B": "4",
"C": "8",
"D": "59",
"E": "32"
} | add(subtract(89, add(add(add(15, 10), 5), 3)), 3) | add(n1,n2)|add(n3,#0)|add(n4,#1)|subtract(n0,#2)|add(n4,#3)| | "lets assign variables to all the areas in venn diagram of three . three different units are dog , cat , snake = total = 89 only dog = d = 15 only cat = c = 10 only snake = s exactly dog and cat = 5 exactly dog and snake = x exactly cat and snake = y all three = 3 so 89 = 15 + 10 + 5 + 3 + x + y + s we need to know total snakes = x + y + s + 3 = 59 answer : d" | general |
math_qa__vrn4Ln4j64kk4lru | A sum of Rs. 2691 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
Choose the correct choice.
A) 1629 B) 1656 C) 1277 D) 6298 E) 1279 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 * 2_691</gadget>
<output>40_365</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">15 + 24</gadget>
<output>39</output>
<gadget id="calculator">40_365 / 39</gadget>
<output>1_035</output>
<gadget id="calculator">2_691 - 1_035</gadget>
<output>1_656</output>
<result>B</result> | B | 1,656 | A sum of Rs. 2691 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum? | {
"A": "1629",
"B": "1656",
"C": "1277",
"D": "6298",
"E": "1279"
} | subtract(2691, divide(multiply(multiply(3, 5), 2691), add(multiply(3, 5), multiply(8, 3)))) | multiply(n2,n4)|multiply(n1,n2)|add(#0,#1)|multiply(n0,#0)|divide(#3,#2)|subtract(n0,#4)| | "( x * 8 * 3 ) / 100 = ( ( 2691 - x ) * 3 * 5 ) / 100 24 x / 100 = 40365 / 100 - 15 x / 100 39 x = 40365 = > x = 1035 second sum = 2691 â € “ 1035 = 1656 answer : b" | gain |
math_qa__pDDJ33DyorHxTKA5 | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 12-inch boxes. If the university pays $0.50 for every box, and if the university needs 2.16 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? Pick
A) $ 155 B) $ 225 C) $ 510 D) $ 850 E) $ 1250 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">2.16 * 1_000_000</gadget>
<output>2_160_000</output>
<gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">400 * 12</gadget>
<output>4_800</output>
<gadget id="calculator">2_160_000 / 4_800</gadget>
<output>450</output>
<gadget id="calculator">450 * 0.5</gadget>
<output>225</output>
<result>B</result> | B | 225 | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 12-inch boxes. If the university pays $0.50 for every box, and if the university needs 2.16 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? | {
"A": "$ 155",
"B": "$ 225",
"C": "$ 510",
"D": "$ 850",
"E": "$ 1250"
} | multiply(divide(multiply(2.16, multiply(const_1000, const_1000)), multiply(multiply(20, 20), 12)), 0.50) | multiply(const_1000,const_1000)|multiply(n0,n0)|multiply(n4,#0)|multiply(n2,#1)|divide(#2,#3)|multiply(n3,#4)| | "the volume of each box is 20 * 20 * 12 = 4800 cubic inches . number of boxes = 2 , 160,000 / 4800 = 450 boxes total cost = 450 × $ 0.5 = $ 225 the answer is b ." | general |
math_qa__YHRb7u9AIt0mZZyl | A is half good a work man as B and together they finish a job in 10 days. In how many days working alone B finish the job?
Answers: A) 23 B) 22 C) 15 D) 36 E) 48 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">10 * (3/2)</gadget>
<output>15</output>
<result>C</result> | C | 15 | A is half good a work man as B and together they finish a job in 10 days. In how many days working alone B finish the job? | {
"A": "23",
"B": "22",
"C": "15",
"D": "36",
"E": "48"
} | multiply(10, divide(const_3, const_2)) | divide(const_3,const_2)|multiply(n0,#0)| | "c 15 wc = 1 : 2 2 x + x = 1 / 10 = > x = 1 / 30 2 x = 1 / 15 = > 15 days" | physics |
math_qa__bdxCPSYMSFfGZ4xB | Rohit walked 25 m towards south. Then he turned to his left and walked 20 m. He then turned to his left and walked 25 m. He again turned to his right and walked 15 m. At what distance is he from the starting point and in which direction? Pick one: A) 35 m east B) 35 m north C) 30 m west D) 45 m east E) 55 m east | <gadget id="calculator">20 + 15</gadget>
<output>35</output>
<result>A</result> | A | 35 | Rohit walked 25 m towards south. Then he turned to his left and walked 20 m. He then turned to his left and walked 25 m. He again turned to his right and walked 15 m. At what distance is he from the starting point and in which direction? | {
"A": "35 m east",
"B": "35 m north",
"C": "30 m west",
"D": "45 m east",
"E": "55 m east"
} | add(20, 15) | add(n1,n3) | ! 20 ! - - - > 15 ! ! ! - - - > ! 20 + 15 = 35 answer : a | physics |
math_qa__AQKjOSksZGweYYOx | If the numerator of a fraction be increased by 20% and its denominator be diminished by 10%, the value of the fraction is 20/21. Find the original fraction ? Pick
A) 1 / 2 B) 3 / 5 C) 4 / 7 D) 5 / 7 E) 7 / 9 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 * 20</gadget>
<output>1_800</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 * 21</gadget>
<output>2_520</output>
<gadget id="calculator">1_800 / 2_520</gadget>
<output>5/7 = around 0.714286</output>
<result>D</result> | D | 0.714286 | If the numerator of a fraction be increased by 20% and its denominator be diminished by 10%, the value of the fraction is 20/21. Find the original fraction ? | {
"A": "1 / 2",
"B": "3 / 5",
"C": "4 / 7",
"D": "5 / 7",
"E": "7 / 9"
} | divide(multiply(subtract(const_100, 10), 20), multiply(add(const_100, 20), 21)) | add(n0,const_100)|subtract(const_100,n1)|multiply(n2,#1)|multiply(n3,#0)|divide(#2,#3)| | "let the original fraction be x / y then , 120 % of x / 90 % of y = 20 / 21 120 x / 90 y = 20 / 21 x / y = 5 / 7 answer is d" | general |
math_qa__1kisuJzBADiR9hLe | The ratio of a to b is 4 to 5, where a and b are positive. If x equals a increased by 25 percent of a, and m equals b decreased by 80 percent of b, what is the value of m/x? Choose the correct choice from the following choices
A) 1 / 5 B) 3 / 4 C) 4 / 5 D) 5 / 4 E) 3 / 2 | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">20 / 125</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(4/25) * (5/4)</gadget>
<output>1/5 = around 0.2</output>
<result>A</result> | A | 0.2 | The ratio of a to b is 4 to 5, where a and b are positive. If x equals a increased by 25 percent of a, and m equals b decreased by 80 percent of b, what is the value of m/x? | {
"A": "1 / 5",
"B": "3 / 4",
"C": "4 / 5",
"D": "5 / 4",
"E": "3 / 2"
} | multiply(divide(subtract(const_100, 80), add(const_100, 25)), divide(5, 4)) | add(n2,const_100)|divide(n1,n0)|subtract(const_100,n3)|divide(#2,#0)|multiply(#3,#1)| | "a / b = 4 / 5 m / x = ( 1 / 5 ) * 5 / ( 5 / 4 ) * 4 = 1 / 5 the answer is a ." | general |
math_qa__ibYzMa5348UOGWIM | A man saves 10% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 10%, he is only able to save Rs. 200 per month. What is his monthly salary? Choose the most appropriate option:
A) rs . 22,000
B) rs . 21,000
C) rs . 20,000
D) rs . 23,000
E) rs . 24,000 | <gadget id="calculator">200 * 100</gadget>
<output>20_000</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">90 * (1/10)</gadget>
<output>9</output>
<gadget id="calculator">90 + 9</gadget>
<output>99</output>
<gadget id="calculator">100 - 99</gadget>
<output>1</output>
<gadget id="calculator">20_000 / 1</gadget>
<output>20_000</output>
<result>C</result> | C | 20,000 | A man saves 10% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 10%, he is only able to save Rs. 200 per month. What is his monthly salary? | {
"A": "rs . 22,000",
"B": "rs . 21,000",
"C": "rs . 20,000",
"D": "rs . 23,000",
"E": "rs . 24,000"
} | divide(multiply(200, const_100), subtract(const_100, add(subtract(const_100, 10), multiply(subtract(const_100, 10), divide(10, const_100))))) | divide(n1,const_100)|multiply(n2,const_100)|subtract(const_100,n0)|multiply(#0,#2)|add(#3,#2)|subtract(const_100,#4)|divide(#1,#5)| | "income = rs . 100 expenditure = rs . 90 savings = rs . 10 present expenditure 90 + 90 * ( 10 / 100 ) = rs . 99 present savings = 100 – 99 = rs . 1 if savings is rs . 1 , salary = rs . 100 if savings is rs . 200 , salary = 100 / 1 * 200 = 20000 answer : c" | general |
math_qa__WIsKT2o8pMjqSlmZ | 4 different children have jelly beans : aaron has 5 , bianca has 7 , callie has 8 , and dante has 9 . how many jelly beans must dante give to aaron to ensure that no child has more than 1 fewer jelly beans than any other child ? Choose the correct choice from the following answers.
A) 1
B) 3
C) 4
D) 5
E) 6 | <gadget id="calculator">9 - 8</gadget>
<output>1</output>
<result>A</result> | A | 1 | 4 different children have jelly beans : aaron has 5 , bianca has 7 , callie has 8 , and dante has 9 . how many jelly beans must dante give to aaron to ensure that no child has more than 1 fewer jelly beans than any other child ? | {
"A": "1",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | subtract(9, 8) | subtract(n4,n3) | since bianca and callie are both within 1 jelly bean of each other and aaron has 5 , dante must provide 3 of his 9 jelly beans so each child has no more than 1 fewer jelly bean than any other child . dante + aaron = 9 + 5 = 14 / 2 = 7 9 - 8 = 1 so dante must provide 3 jelly beans to aaron . answer ( a ) | general |
math_qa__L3bODBKzIS725Ida | A present value of a machine is $128000. Its value depletiation rate is 25% per annum then find the machine value after 3 years? Answers.
A) $ 54000 B) $ 48000 C) $ 36520 D) $ 32450 E) $ 42500 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) ** 3</gadget>
<output>27/64 = around 0.421875</output>
<gadget id="calculator">128_000 * (27/64)</gadget>
<output>54_000</output>
<result>A</result> | A | 54,000 | A present value of a machine is $128000. Its value depletiation rate is 25% per annum then find the machine value after 3 years? | {
"A": "$ 54000",
"B": "$ 48000",
"C": "$ 36520",
"D": "$ 32450",
"E": "$ 42500"
} | multiply(128000, power(subtract(const_1, divide(25, const_100)), 3)) | divide(n1,const_100)|subtract(const_1,#0)|power(#1,n2)|multiply(n0,#2)| | "p = $ 128000 r = 25 % t = 3 years machine value after 3 years = p / ( 1 - r / 100 ) ^ t = 128000 * 3 / 4 * 3 / 4 * 3 / 4 = $ 54000 answer is a" | gain |
math_qa__octKUBmArD7T4zTD | When 2/9 of the votes on a certain resolution have been counted, 3/4 of those counted are in favor of the resolution. What fraction f of the remaining votes must be against the resolution so that the total count will result in a vote of 2 to 1 against the resolution? Select:
A) 11 / 14
B) 13 / 18
C) 4 / 7
D) 3 / 7
E) 3 / 14 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(2/9) * (3/4)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(2/9) - (1/6)</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(2/3) - (1/18)</gadget>
<output>11/18 = around 0.611111</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>
<gadget id="calculator">(11/18) / (7/9)</gadget>
<output>11/14 = around 0.785714</output>
<result>A</result> | A | 0.785714 | When 2/9 of the votes on a certain resolution have been counted, 3/4 of those counted are in favor of the resolution. What fraction f of the remaining votes must be against the resolution so that the total count will result in a vote of 2 to 1 against the resolution? | {
"A": "11 / 14",
"B": "13 / 18",
"C": "4 / 7",
"D": "3 / 7",
"E": "3 / 14"
} | divide(subtract(divide(2, add(1, 2)), subtract(divide(2, 9), multiply(divide(2, 9), divide(3, 4)))), divide(subtract(9, 2), 9)) | add(n0,n5)|divide(n0,n1)|divide(n2,n3)|subtract(n1,n0)|divide(n0,#0)|divide(#3,n1)|multiply(#1,#2)|subtract(#1,#6)|subtract(#4,#7)|divide(#8,#5)| | "if we use variable for total votes there will be too many fractions to manipulate with , so pick some smart # : let set total # of votes is 18 . 2 / 9 of the votes on a certain resolution have been counted - - > 4 counted and 18 - 4 = 14 votes left to be counted ; 3 / 4 of those counted are in favor of the resolution - - > 3 in favor and 1 against ; ratio of those who voted against to those who voted for to be 2 to 1 there should be total of 18 * 2 / 3 = 12 people who voted against , so in the remaining 14 votes there should be 12 - 1 = 11 people who voted against . thus f = 11 / 14 of the remaining votes must be against . answer : a ." | general |
math_qa__ApDv8FKZROkHMsWh | when 1 / 20 % of 8000 is subtracted from 1 / 10 of 8000 , the difference is
Answers
A) 50 B) 200 C) 380 D) 798 E) 400 | <gadget id="calculator">8_000 / 10</gadget>
<output>800</output>
<gadget id="calculator">20 * 100</gadget>
<output>2_000</output>
<gadget id="calculator">8_000 / 2_000</gadget>
<output>4</output>
<gadget id="calculator">800 - 4</gadget>
<output>796</output>
<result>D</result> | D | 798 | when 1 / 20 % of 8000 is subtracted from 1 / 10 of 8000 , the difference is | {
"A": "50",
"B": "200",
"C": "380",
"D": "798",
"E": "400"
} | subtract(divide(8000, 10), divide(8000, multiply(20, const_100))) | divide(n2,n4)|multiply(n1,const_100)|divide(n2,#1)|subtract(#0,#2) | 1 / 20 % of 8000 = 4 1 / 10 of 8000 = 800 800 - 2 = 798 ans : d | general |
math_qa__fsZGoytDtklxoedX | There are 100 students in a class. If 14% are absent on a particular day, find the number of students present in the class. Choose the correct choice
A) 43 B) 36 C) 86 D) 129 E) 11 | <gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">1 - (7/50)</gadget>
<output>43/50 = around 0.86</output>
<gadget id="calculator">(43/50) * 100</gadget>
<output>86</output>
<result>C</result> | C | 86 | There are 100 students in a class. If 14% are absent on a particular day, find the number of students present in the class. | {
"A": "43",
"B": "36",
"C": "86",
"D": "129",
"E": "11"
} | multiply(subtract(const_1, divide(14, 100)), const_100) | divide(n1,n0)|subtract(const_1,#0)|multiply(#1,const_100) | number of students absent on a particular day = 14 % of 100 i . e . , 14 / 100 × 100 = 14 therefore , the number of students present = 100 - 14 = 86 students . answer : c | gain |
math_qa__LpaIlOPmpHiN7cRX | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 72° of the circle, what percentage of MegaTek employees are in manufacturing? Choose the correct choice from the following answers:
A) 20 % B) 25 % C) 30 % D) 35 % E) 72 % | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">72 / 360</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>A</result> | A | 20 | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 72° of the circle, what percentage of MegaTek employees are in manufacturing? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "35 %",
"E": "72 %"
} | multiply(divide(72, divide(const_3600, const_10)), const_100) | divide(const_3600,const_10)|divide(n0,#0)|multiply(#1,const_100)| | "72 ° divided by 360 ° equals 0.2 , therefore the sector is equal to 20 % of the total answer : a" | physics |
math_qa__lqYsgUjdTc1hS9iL | If the median of a list of numbers is m, the first quartile of the list is the median of the numbers in the list that are less than m. What is the first quartile of the list of numbers 42, 24, 30, 28, 26, 19, 33 and 35 ?
Choose the correct option
A) 33 B) 28 C) 27 D) 25 E) 23 | <gadget id="calculator">24 + 26</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>D</result> | D | 25 | If the median of a list of numbers is m, the first quartile of the list is the median of the numbers in the list that are less than m. What is the first quartile of the list of numbers 42, 24, 30, 28, 26, 19, 33 and 35 ? | {
"A": "33",
"B": "28",
"C": "27",
"D": "25",
"E": "23"
} | divide(add(24, 26), const_2) | add(n1,n4)|divide(#0,const_2)| | "it is given that a quartile is the middle number of all numbers less than median . . so lets arrange the number in ascending order - 42 , 24 , 30 , 28 , 26 , 19 , 33 and 35 19 , 24 , 26 , 28 , 30 , 33 , 35 , 42 . . . numbers less than median are 19 , 24 , 26 , 28 . . the median of these numbers = center of 24 and 26 = 25 d" | general |
math_qa__f7mtptRvPa1vCbsz | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1.5 cm when a man gets on it. The mass of man is Choose the correct choice
A) 12 kg B) 90 kg C) 72 kg D) 96 kg E) none | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1.5 / 100</gadget>
<output>0.015</output>
<gadget id="calculator">6 * 0.015</gadget>
<output>0.09</output>
<gadget id="calculator">0.09 * 1_000</gadget>
<output>90</output>
<result>B</result> | B | 90 | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1.5 cm when a man gets on it. The mass of man is | {
"A": "12 kg",
"B": "90 kg",
"C": "72 kg",
"D": "96 kg",
"E": "none"
} | multiply(multiply(multiply(3, 2), divide(1.5, const_100)), const_1000) | divide(n2,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(#2,const_1000)| | "solution volume of water displaced = ( 3 x 2 x 0.015 ) m 3 = 0.09 m 3 . mass of man = volume of water displaced × density of water = ( 0.09 × 1000 ) kg = 90 kg . answer b" | physics |
math_qa__bG8noOWYONsnbaBa | How many 3 digit positive integers R exist that when divided by 7 leave a remainder of 5? Choose the correct choice from the following options.
A) 128 B) 142 C) 143 D) 141 E) 129 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 1</gadget>
<output>999</output>
<gadget id="calculator">10 + 4</gadget>
<output>14</output>
<gadget id="calculator">14 * 7</gadget>
<output>98</output>
<gadget id="calculator">98 + 5</gadget>
<output>103</output>
<gadget id="calculator">999 - 103</gadget>
<output>896</output>
<gadget id="calculator">896 / 7</gadget>
<output>128</output>
<result>E</result> | E | 129 | How many 3 digit positive integers R exist that when divided by 7 leave a remainder of 5? | {
"A": "128",
"B": "142",
"C": "143",
"D": "141",
"E": "129"
} | divide(subtract(subtract(multiply(const_100, const_10), const_1), add(multiply(add(const_10, const_4), 7), 5)), 7) | add(const_10,const_4)|multiply(const_10,const_100)|multiply(n1,#0)|subtract(#1,const_1)|add(n2,#2)|subtract(#3,#4)|divide(#5,n1)| | "minimum three digit number is 100 and maximum three digit number is 999 . the first three digit number that leaves remainder 5 when divided by 7 is 103 . 14 * 7 = 98 + 5 = 103 the second three digit number that leaves remainder 5 when divided by 7 is 110 . 15 * 7 = 105 + 5 = 110 the third three digit number that leaves remainder 5 when divided by 7 is 117 and so on the last three digit number that leaves remainder 5 when divided by 7 is 999 142 * 7 = 994 + 5 = 999 therefore , we identify the sequence 103 , 110,117 . . . . . 999 use the formula of last term last term = first term + ( n - 1 ) * common difference you will get the answer 129 that is definitely e ." | general |
math_qa__SyvnGz7hVAS9uYOD | The average weight of a group of persons increased from 48 kg to 51 kg, when two persons weighing 88 kg and 93 kg join the group. Find the initial number of members in the group?
Options:
A) 23 B) 24 C) 25 D) 26 E) 27 | <gadget id="calculator">88 + 93</gadget>
<output>181</output>
<gadget id="calculator">51 * 2</gadget>
<output>102</output>
<gadget id="calculator">181 - 102</gadget>
<output>79</output>
<gadget id="calculator">51 - 48</gadget>
<output>3</output>
<gadget id="calculator">79 / 3</gadget>
<output>79/3 = around 26.333333</output>
<result>D</result> | D | 26 | The average weight of a group of persons increased from 48 kg to 51 kg, when two persons weighing 88 kg and 93 kg join the group. Find the initial number of members in the group? | {
"A": "23",
"B": "24",
"C": "25",
"D": "26",
"E": "27"
} | divide(subtract(add(88, 93), multiply(51, const_2)), subtract(51, 48)) | add(n2,n3)|multiply(n1,const_2)|subtract(n1,n0)|subtract(#0,#1)|divide(#3,#2)| | "let the initial number of members in the group be n . initial total weight of all the members in the group = n ( 48 ) from the data , 48 n + 88 + 93 = 51 ( n + 2 ) = > 51 n - 48 n = 79 = > n = 26 therefore there were 26 members in the group initially . answer : d" | general |
math_qa__eI11NQtjk7cEbXz9 | Two trains 121 meters and 153 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
Choose the most appropriate option:
A) 7.19
B) 6.8
C) 7.2
D) 7.15
E) 7.11 | <gadget id="calculator">121 + 153</gadget>
<output>274</output>
<gadget id="calculator">80 + 65</gadget>
<output>145</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">145 * (5/18)</gadget>
<output>725/18 = around 40.277778</output>
<gadget id="calculator">274 / (725/18)</gadget>
<output>4_932/725 = around 6.802759</output>
<result>B</result> | B | 6.8 | Two trains 121 meters and 153 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? | {
"A": "7.19",
"B": "6.8",
"C": "7.2",
"D": "7.15",
"E": "7.11"
} | divide(add(121, 153), multiply(add(80, 65), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "t = ( 121 + 153 ) / ( 80 + 65 ) * 18 / 5 t = 6.8 answer : b" | physics |
math_qa__HKYxDEwgJpFSfICH | The price of 3 chudi and 6 tops is Rs. 1500. With the same money one can buy 1 chudi and 12 tops. If one wants to buy 5 tops, how much shall she have to pay ? Select:
A) 500
B) 1000
C) 1200
D) 1300
E) 1500 | <gadget id="calculator">100 * 5</gadget>
<output>500</output>
<result>A</result> | A | 500 | The price of 3 chudi and 6 tops is Rs. 1500. With the same money one can buy 1 chudi and 12 tops. If one wants to buy 5 tops, how much shall she have to pay ? | {
"A": "500",
"B": "1000",
"C": "1200",
"D": "1300",
"E": "1500"
} | multiply(const_100, 5) | multiply(n5,const_100) | let the price of a chudi and a top be rs . x and rs . y respectively . then , 3 x + 6 y = 1500 . . . . ( i ) and x + 12 y = 1500 . . . . ( ii ) divide equation ( i ) by 3 , we get the below equation . = x + 2 y = 500 . - - - ( iii ) now subtract ( iii ) from ( ii ) x + 12 y = 1500 ( - ) x + 2 y = 500 - - - - - - - - - - - - - - - - 10 y = 1000 - - - - - - - - - - - - - - - - cost of 5 tops = 5 * 100 = 500 answer : a | general |
math_qa__hiB5u8z2ednV2o51 | The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 10%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output? Choose the correct answer: A) 17 % B) 24 % C) 30 % D) 32 % E) 79 % | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) * (11/10)</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">(121/100) - 1</gadget>
<output>21/100 = around 0.21</output>
<gadget id="calculator">(21/100) / (121/100)</gadget>
<output>21/121 = around 0.173554</output>
<gadget id="calculator">(21/121) * 100</gadget>
<output>2_100/121 = around 17.355372</output>
<result>A</result> | A | 17 | The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 10%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output? | {
"A": "17 %",
"B": "24 %",
"C": "30 %",
"D": "32 %",
"E": "79 %"
} | multiply(divide(subtract(multiply(divide(add(const_100, 10), const_100), divide(add(const_100, 10), const_100)), const_1), multiply(divide(add(const_100, 10), const_100), divide(add(const_100, 10), const_100))), const_100) | add(n0,const_100)|add(n1,const_100)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|subtract(#4,const_1)|divide(#5,#4)|multiply(#6,const_100)| | "take it as original output = 100 . to meet demand increase by 10 % , then output = 110 . to meet holiday demand , new output increase by 10 % then output equals 121 to restore new holidy demand output to original 100 . final - initial / final * 100 = 21 / 121 * 100 = 8 / 33 * 100 = 17 % approxiamately . option a is correct ." | general |
math_qa__PfQG9M549cWQPcMN | A bag contains 3 red, 4 blue and 4 green balls. If 2 ballsare picked at random, what is the probability that both are red?
Choices.
A) 2 / 15
B) 2 / 21
C) 3 / 55
D) 3 / 29
E) 4 / 27 | <gadget id="calculator">binomial(3, 2)</gadget>
<output>3</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<gadget id="calculator">binomial(11, 2)</gadget>
<output>55</output>
<gadget id="calculator">3 / 55</gadget>
<output>3/55 = around 0.054545</output>
<result>C</result> | C | 0.054545 | A bag contains 3 red, 4 blue and 4 green balls. If 2 ballsare picked at random, what is the probability that both are red? | {
"A": "2 / 15",
"B": "2 / 21",
"C": "3 / 55",
"D": "3 / 29",
"E": "4 / 27"
} | divide(choose(3, 2), choose(add(add(3, 4), 4), 2)) | add(n0,n1)|choose(n0,n3)|add(n2,#0)|choose(#2,n3)|divide(#1,#3)| | "p ( both are red ) , = 3 c 211 c 2 = 3 c 211 c 2 = 3 / 55 c" | other |
math_qa__0cGLjlWYvpmupd0q | Let f(x,y) be defined as the remainder when (x–y)! is divided by x. If x=24, what is the maximum value of y for which f(x,y)=0? Choose the correct option
A) 12 B) 15 C) 18 D) 20 E) 21 | <gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">2 * (12/5)</gadget>
<output>24/5 = around 4.8</output>
<gadget id="calculator">24 - (24/5)</gadget>
<output>96/5 = around 19.2</output>
<result>D</result> | D | 20 | Let f(x,y) be defined as the remainder when (x–y)! is divided by x. If x=24, what is the maximum value of y for which f(x,y)=0? | {
"A": "12",
"B": "15",
"C": "18",
"D": "20",
"E": "21"
} | subtract(24, multiply(const_2, divide(divide(24, const_2), add(const_1, const_4)))) | add(const_1,const_4)|divide(n0,const_2)|divide(#1,#0)|multiply(#2,const_2)|subtract(n0,#3)| | "the question is finding y such that ( 24 - y ) ! is a multiple of 24 . that means we need to have 2 ^ 3 * 3 in ( 24 - y ) ! 4 ! is the smallest factorial number with 2 ^ 3 * 3 as a factor . 24 - y = 4 y = 20 the answer is d ." | general |
math_qa__9tw1h5RB5Rgd2utL | For every X, the action [X] is defined: [X] is the greatest integer less than or equal to X. What is the value of [6.5] x [2/3] + [2] x 7.2 + [8.4] - 6.5? Choose the correct choice.
A) 12.6 . B) 14.4 . C) 15.8 . D) 15.7 . E) 16.4 . | <gadget id="calculator">2 * 7.2</gadget>
<output>14.4</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">8.4 - (2/5)</gadget>
<output>8</output>
<gadget id="calculator">14.4 + 8</gadget>
<output>22.4</output>
<gadget id="calculator">22.4 - 6.5</gadget>
<output>15.9</output>
<result>D</result> | D | 15.7 | For every X, the action [X] is defined: [X] is the greatest integer less than or equal to X. What is the value of [6.5] x [2/3] + [2] x 7.2 + [8.4] - 6.5? | {
"A": "12.6 .",
"B": "14.4 .",
"C": "15.8 .",
"D": "15.7 .",
"E": "16.4 ."
} | subtract(add(multiply(2, 7.2), subtract(8.4, divide(const_4, const_10))), 6.5) | divide(const_4,const_10)|multiply(n1,n4)|subtract(n5,#0)|add(#1,#2)|subtract(#3,n6)| | "[ 6.5 ] x [ 2 / 3 ] + [ 2 ] x 7.2 + [ 8.4 ] - 6.5 = 6 * 0 + 2 * 7.2 + 8 - 6.5 = 0 + 14.4 + 1.5 15.7 answer d" | general |
math_qa__F9ZHX7QmtFEOAOdq | When a certain number X is divided by 63, the remainder is 27. What is the remainder when X is divided by 8? Choose the correct choice from the following options:
A) 2
B) 3
C) 4
D) 5
E) 6 | <gadget id="calculator">27 % 8</gadget>
<output>3</output>
<result>B</result> | B | 3 | When a certain number X is divided by 63, the remainder is 27. What is the remainder when X is divided by 8? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | reminder(27, 8) | reminder(n1,n2)| | "when a certain number x is divided by 63 , the remainder is 27 . what is the remainder when x is divided by 8 ? putting a value say x = 27 we get remainder as 27 when divided by 63 . when 27 divided by 8 we get 3 as remainder . b is the answer ." | general |
math_qa__qh9Gq74Bzxj6o1Vk | On dividing 100 by a number, the quotient is 9 and the remainder is 1. Find the divisor? Pick one
A) 10 B) 11 C) 12 D) 13 E) 14 | <gadget id="calculator">100 / 9</gadget>
<output>100/9 = around 11.111111</output>
<gadget id="calculator">floor(100/9)</gadget>
<output>11</output>
<result>B</result> | B | 11 | On dividing 100 by a number, the quotient is 9 and the remainder is 1. Find the divisor? | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | floor(divide(100, 9)) | divide(n0,n1)|floor(#0)| | "d = ( d - r ) / q = ( 100 - 1 ) / 9 = 99 / 9 = 11 b )" | general |
math_qa__LBMNiSl4qK2ZFunD | A can do a work in 15 days and B in 20 days. If they work on it together for 5 days, then the fraction of the work that is left is :
Choose the correct choice from the following.
A) 1 / 3
B) 7 / 12
C) 5 / 12
D) 2 / 3
E) 1 / 2 | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/15) + (1/20)</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">(7/60) * 5</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">1 - (7/12)</gadget>
<output>5/12 = around 0.416667</output>
<result>C</result> | C | 0.416667 | A can do a work in 15 days and B in 20 days. If they work on it together for 5 days, then the fraction of the work that is left is : | {
"A": "1 / 3",
"B": "7 / 12",
"C": "5 / 12",
"D": "2 / 3",
"E": "1 / 2"
} | subtract(const_1, multiply(add(divide(const_1, 15), divide(const_1, 20)), 5)) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)| | "ans is : c a ' s 1 day ' s work = 1 / 15 b ' s 1 day ' s work = 1 / 20 ( a + b ) ' s 1 day ' s work = ( 1 / 15 + 1 / 20 ) = 7 / 60 ( a + b ) ' s 5 day ' s work = ( 7 / 60 * 5 ) = 7 / 12 therefore , remaining work = ( 1 - 7 / 12 ) = 5 / 12 . answer : c" | physics |
math_qa__GpFYXh7Cb2262AWY | What will be the reminder when (67^67+67) is divided by 68?
Options.
A) 1 B) 63 C) 66 D) 67 E) none of these | <gadget id="calculator">67 ** 67</gadget>
<output>222_337_020_242_360_576_812_569_226_538_683_753_874_082_408_437_758_291_741_262_115_823_894_811_650_848_346_334_502_642_370_010_973_465_496_690_788_650_052_277_723</output>
<gadget id="calculator">222_337_020_242_360_576_812_569_226_538_683_753_874_082_408_437_758_291_741_262_115_823_894_811_650_848_346_334_502_642_370_010_973_465_496_690_788_650_052_277_723 + 67</gadget>
<output>222_337_020_242_360_576_812_569_226_538_683_753_874_082_408_437_758_291_741_262_115_823_894_811_650_848_346_334_502_642_370_010_973_465_496_690_788_650_052_277_790</output>
<gadget id="calculator">222_337_020_242_360_576_812_569_226_538_683_753_874_082_408_437_758_291_741_262_115_823_894_811_650_848_346_334_502_642_370_010_973_465_496_690_788_650_052_277_790 / 68</gadget>
<output>111_168_510_121_180_288_406_284_613_269_341_876_937_041_204_218_879_145_870_631_057_911_947_405_825_424_173_167_251_321_185_005_486_732_748_345_394_325_026_138_895/34 = around 3_269_662_062_387_655_290_842_926_231_522_829_521_657_907_308_700_460_106_370_185_854_057_238_649_377_933_760_585_894_998_029_596_939_065_472_965_682_606_899_200</output>
<gadget id="calculator">floor(111_168_510_121_180_288_406_284_613_269_341_876_937_041_204_218_879_145_870_631_057_911_947_405_825_424_173_167_251_321_185_005_486_732_748_345_394_325_026_138_895/34)</gadget>
<output>3_269_662_062_387_655_541_361_312_154_980_643_439_324_741_300_555_268_996_195_031_115_057_276_641_924_240_387_272_097_681_911_926_080_374_951_335_127_206_651_143</output>
<gadget id="calculator">68 * 3_269_662_062_387_655_541_361_312_154_980_643_439_324_741_300_555_268_996_195_031_115_057_276_641_924_240_387_272_097_681_911_926_080_374_951_335_127_206_651_143</gadget>
<output>222_337_020_242_360_576_812_569_226_538_683_753_874_082_408_437_758_291_741_262_115_823_894_811_650_848_346_334_502_642_370_010_973_465_496_690_788_650_052_277_724</output>
<gadget id="calculator">222_337_020_242_360_576_812_569_226_538_683_753_874_082_408_437_758_291_741_262_115_823_894_811_650_848_346_334_502_642_370_010_973_465_496_690_788_650_052_277_790 - 222_337_020_242_360_576_812_569_226_538_683_753_874_082_408_437_758_291_741_262_115_823_894_811_650_848_346_334_502_642_370_010_973_465_496_690_788_650_052_277_724</gadget>
<output>66</output>
<result>C</result> | C | 66 | What will be the reminder when (67^67+67) is divided by 68? | {
"A": "1",
"B": "63",
"C": "66",
"D": "67",
"E": "none of these"
} | subtract(add(power(67, 67), 67), multiply(68, floor(divide(add(power(67, 67), 67), 68)))) | power(n0,n0)|add(n0,#0)|divide(#1,n3)|floor(#2)|multiply(n3,#3)|subtract(#1,#4)| | "( x ^ n + 1 ) will be divisible by ( x + 1 ) only when n is odd ; ( 67 ^ 67 + 1 ) will be divisible by ( 67 + 1 ) ; ( 67 ^ 67 + 1 ) + 66 when divided by 68 will give 66 as remainder . correct option : c" | general |
math_qa__s5drquaVpHCgtb0Q | If Leo gains 10 pounds, he will weigh 50% more than his sister Kendra. Currently their combined weight is 140 pounds. What is Leo's current weight? Answers: A) 80 B) 90 C) 100 D) 110 E) 120 | <gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">140 * (3/2)</gadget>
<output>210</output>
<gadget id="calculator">210 - 10</gadget>
<output>200</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">200 / (5/2)</gadget>
<output>80</output>
<result>A</result> | A | 80 | If Leo gains 10 pounds, he will weigh 50% more than his sister Kendra. Currently their combined weight is 140 pounds. What is Leo's current weight? | {
"A": "80",
"B": "90",
"C": "100",
"D": "110",
"E": "120"
} | divide(subtract(multiply(140, divide(add(const_100, 50), const_100)), 10), add(divide(add(const_100, 50), const_100), const_1)) | add(n1,const_100)|divide(#0,const_100)|add(#1,const_1)|multiply(n2,#1)|subtract(#3,n0)|divide(#4,#2)| | "l + k = 140 and so k = 140 - l l + 10 = 1.5 k = 1.5 ( 140 - l ) 2.5 l = 200 l = 80 the answer is a ." | gain |
math_qa__S8pIp3syasZxz3IT | Aunt Marge is giving candy to each of her nephews and nieces. She has 20 pieces of candy and she gives all the candy to the children according to her wish. If Robert gets 2 more pieces than Kate, Bill gets 6 less than Mary, Mary gets 2 more pieces than Robert, and Kate gets 2 more pieces than Bill, how many pieces of candy does Kate get?
Answers: A) 2 B) 4 C) 6 D) 8 E) 10 | <gadget id="calculator">20 - 6</gadget>
<output>14</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">14 - 10</gadget>
<output>4</output>
<result>B</result> | B | 4 | Aunt Marge is giving candy to each of her nephews and nieces. She has 20 pieces of candy and she gives all the candy to the children according to her wish. If Robert gets 2 more pieces than Kate, Bill gets 6 less than Mary, Mary gets 2 more pieces than Robert, and Kate gets 2 more pieces than Bill, how many pieces of candy does Kate get? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | subtract(subtract(20, 6), multiply(add(divide(6, 2), 2), 2)) | divide(n2,n1)|subtract(n0,n2)|add(n1,#0)|multiply(n1,#2)|subtract(#1,#3) | use the initial letter of each name as a variable : r = k + 2 b = m − 6 m = r + 2 k = 2 + bk = = r − 2 b = k − 2 = ( r − 2 ) − 2 = r − 4 m = r + 2 r + b + m + k = 20 r + r − 4 + r + 2 + r − 2 = 20 r = 6 k = r − 2 = 6 − 2 = 4 answer : b | general |
math_qa__LEz0oo5Gu8TazyfO | In the list 3, 3, 4, 4, 5, 5, 5, 5, 7, 11, 21, what fraction of the data is less than the mode? Choose the correct choice from the following answers.
A) 2 / 9 B) 1 / 3 C) 4 / 11 D) 2 / 3 E) 7 / 9 | <gadget id="calculator">4 / 11</gadget>
<output>4/11 = around 0.363636</output>
<result>C</result> | C | 0.363636 | In the list 3, 3, 4, 4, 5, 5, 5, 5, 7, 11, 21, what fraction of the data is less than the mode? | {
"A": "2 / 9",
"B": "1 / 3",
"C": "4 / 11",
"D": "2 / 3",
"E": "7 / 9"
} | divide(4, 11) | divide(n2,n9) | mode : the mode of any set is the term which has the highest frequency ( occurrence ) highest frequent term in the set is 5 ( with frequency 4 ) hence mode = 5 two terms ( 3 , 3 , 4 , 4 ) out of a total of 11 terms are less than mode of the set . fraction of set that are less than mode of set = 4 / 11 answer : option c | general |
math_qa__5JmLloRIvfHF6rL9 | A man can row a boat at 10 kmph in still water and the speed of the stream is 8 kmph. What is then time taken to row a distance of 90 km down the stream ? Select.
A) 8 hrs B) 5 hrs C) 15 hrs D) 15 hrs E) 20 hrs | <gadget id="calculator">10 + 8</gadget>
<output>18</output>
<gadget id="calculator">90 / 18</gadget>
<output>5</output>
<result>B</result> | B | 5 | A man can row a boat at 10 kmph in still water and the speed of the stream is 8 kmph. What is then time taken to row a distance of 90 km down the stream ? | {
"A": "8 hrs",
"B": "5 hrs",
"C": "15 hrs",
"D": "15 hrs",
"E": "20 hrs"
} | divide(90, add(10, 8)) | add(n0,n1)|divide(n2,#0) | speed in down stream = 10 + 8 = 18 time taken to cover 90 km down stream = 90 / 18 = 5 hrs . answer : b | physics |
math_qa__ExOfFLfko7Q20ros | In order to obtain an income of Rs. 15000 from 80% stock at Rs. 200, one must make an investment of Choose the correct choice from the following choices
A) rs . 30000 B) rs . 37000 C) rs . 37500 D) rs . 40000 E) rs . 40500 | <gadget id="calculator">200 / 80</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 15_000</gadget>
<output>37_500</output>
<result>C</result> | C | 37,500 | In order to obtain an income of Rs. 15000 from 80% stock at Rs. 200, one must make an investment of | {
"A": "rs . 30000",
"B": "rs . 37000",
"C": "rs . 37500",
"D": "rs . 40000",
"E": "rs . 40500"
} | multiply(divide(200, 80), 15000) | divide(n2,n1)|multiply(n0,#0)| | "explanation : market value = rs . 200 . required income = rs . 15000 . here face value is not given . take face value as rs . 100 if it is not given in the question to obtain rs . 80 ( ie , 80 % of the face value 100 ) , investment = rs . 200 to obtain rs . 15000 , investment = 200 / 80 ã — 15000 = rs . 37500 answer : option c" | gain |
math_qa__rANB46DW2IQ5WGpl | The area of sector of a circle whose radius is 12 metro and whose angle at the center is 40° is? Choose the correct choice from the following choices:
A) 53 m 2
B) 51 m 2
C) 50.2 m 2
D) 45 m 2
E) 40 m 2 | <gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">144 * (22/7)</gadget>
<output>3_168/7 = around 452.571429</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">40 / 360</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(3_168/7) * (1/9)</gadget>
<output>352/7 = around 50.285714</output>
<result>C</result> | C | 50.2 | The area of sector of a circle whose radius is 12 metro and whose angle at the center is 40° is? | {
"A": "53 m 2",
"B": "51 m 2",
"C": "50.2 m 2",
"D": "45 m 2",
"E": "40 m 2"
} | multiply(multiply(power(12, const_2), divide(add(multiply(const_2, const_10), const_2), add(const_4, const_3))), divide(40, divide(const_3600, const_10))) | add(const_3,const_4)|divide(const_3600,const_10)|multiply(const_10,const_2)|power(n0,const_2)|add(#2,const_2)|divide(n1,#1)|divide(#4,#0)|multiply(#6,#3)|multiply(#5,#7)| | "40 / 360 * 22 / 7 * 12 * 12 = 50.2 m 2 answer : c" | geometry |
math_qa__coNFB1mPSkuw2Q5v | The average runs scored by a batsman in 22 matches is 28. In the next 13 matches the batsman scored an average of 15 runs. Find his average in all the 35 matches?
Choose the correct choice from the following answers: A) 31.23 B) 25.12 C) 36.25 D) 23.17 E) 27.66 | <gadget id="calculator">28 * 22</gadget>
<output>616</output>
<gadget id="calculator">15 * 13</gadget>
<output>195</output>
<gadget id="calculator">616 + 195</gadget>
<output>811</output>
<gadget id="calculator">22 + 13</gadget>
<output>35</output>
<gadget id="calculator">811 / 35</gadget>
<output>811/35 = around 23.171429</output>
<result>D</result> | D | 23.17 | The average runs scored by a batsman in 22 matches is 28. In the next 13 matches the batsman scored an average of 15 runs. Find his average in all the 35 matches? | {
"A": "31.23",
"B": "25.12",
"C": "36.25",
"D": "23.17",
"E": "27.66"
} | divide(add(multiply(28, 22), multiply(15, 13)), add(22, 13)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | total score of the batsman in 22 matches = 616 . total score of the batsman in the next 13 matches = 195 . total score of the batsman in the 35 matches = 811 . average score of the batsman = 811 / 35 = 23.17 . answer : d | general |
math_qa__DRq8FK2cntjYcsfp | The sum of the numbers is 330. If the first number be twice the second and third number be one-third of the first, then the second number is: Choose one
A) 48
B) 54
C) 72
D) 84
E) 90 | <gadget id="calculator">330 * 3</gadget>
<output>990</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">990 / 11</gadget>
<output>90</output>
<result>E</result> | E | 90 | The sum of the numbers is 330. If the first number be twice the second and third number be one-third of the first, then the second number is: | {
"A": "48",
"B": "54",
"C": "72",
"D": "84",
"E": "90"
} | divide(multiply(330, const_3), add(const_10, const_1)) | add(const_1,const_10)|multiply(n0,const_3)|divide(#1,#0)| | "let the second number be x . then , first number = 2 x and third number = 2 x / 3 . 2 x + x + 2 x / 3 = 330 11 x / 3 = 330 x = 90 answer : e" | general |
math_qa__AGhXDhs4iPAPn9BY | A trailer carries 3, 4 and 5 crates on a trip. Each crate weighs no less than 150 kg. What is the maximum weight of the crates on a single trip? Choose the correct choice from the following options
A) 1250 B) 625 C) 600 D) 750 E) 375 | <gadget id="calculator">5 * 150</gadget>
<output>750</output>
<result>D</result> | D | 750 | A trailer carries 3, 4 and 5 crates on a trip. Each crate weighs no less than 150 kg. What is the maximum weight of the crates on a single trip? | {
"A": "1250",
"B": "625",
"C": "600",
"D": "750",
"E": "375"
} | multiply(5, 150) | multiply(n2,n3)| | "max no . of crates = 5 . max weight = 150 kg max . weight carried = 5 * 150 = 750 kg = d" | general |
math_qa__aOvRURI6PH3Za3A2 | The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar? Choose one:
A) 1 / 5 B) 1 / 3 C) 2 / 5 D) 1 / 2 E) 2 / 3 | <gadget id="calculator">60 - 20</gadget>
<output>40</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">40 / 80</gadget>
<output>1/2 = around 0.5</output>
<result>D</result> | D | 0.5 | The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar? | {
"A": "1 / 5",
"B": "1 / 3",
"C": "2 / 5",
"D": "1 / 2",
"E": "2 / 3"
} | divide(subtract(60, 20), subtract(const_100, 20)) | subtract(n1,n0)|subtract(const_100,n0)|divide(#0,#1)| | "let weight of jar filled with beans = 100 g weight of jar = 20 g weight of coffee beans = 80 g weight of jar and remaining beans = 60 g weight of remaining beans = 40 g fraction remaining = 40 / 80 = 1 / 2 answer is d ." | gain |
math_qa__WhcC9JIwW7DgDzIw | The diagonals of a rhombus are 16 cm and 20 cm. Find its area? Answers.
A) 160 B) 288 C) 150 D) 238 E) 31 | <gadget id="calculator">(16 * 20) / 2</gadget>
<output>160</output>
<result>A</result> | A | 160 | The diagonals of a rhombus are 16 cm and 20 cm. Find its area? | {
"A": "160",
"B": "288",
"C": "150",
"D": "238",
"E": "31"
} | rhombus_area(16, 20) | rhombus_area(n0,n1)| | "1 / 2 * 16 * 20 = 160 answer : a" | geometry |
math_qa__7HPXFQU86LdgPchA | Carmen made a sculpture from small pieces of wood. The sculpture is 2 feet 10 inches tall.Carmen places her sculpture on a base that is 6 inches tall. How tall are the sculpture andbase together? Select.
A) 3.1 feet B) 3.2 feet C) 3.3 feet D) 3.4 feet E) 3.5 feet | <gadget id="calculator">2 + 10</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 10</gadget>
<output>34</output>
<gadget id="calculator">34 + 6</gadget>
<output>40</output>
<gadget id="calculator">40 / 12</gadget>
<output>10/3 = around 3.333333</output>
<result>C</result> | C | 3.3 | Carmen made a sculpture from small pieces of wood. The sculpture is 2 feet 10 inches tall.Carmen places her sculpture on a base that is 6 inches tall. How tall are the sculpture andbase together? | {
"A": "3.1 feet",
"B": "3.2 feet",
"C": "3.3 feet",
"D": "3.4 feet",
"E": "3.5 feet"
} | divide(add(add(multiply(add(2, 10), 2), 10), 6), add(2, 10)) | add(n0,n1)|multiply(n0,#0)|add(#1,n1)|add(n2,#2)|divide(#3,#0)| | "we know 1 feet = 12 inch then 2 feet = 24 inch 24 + 10 = 34 then 34 + 6 = 40 40 / 12 = 3.3 feet answer : c" | geometry |
math_qa__aTHI0ttudM0x9iqC | xy=2 then what is (2^(x+y)^2) / (2^(x-y)^2)
Choose the correct answer.
A) 2 B) 4 C) 8 D) 16 E) 256 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">2 ** 8</gadget>
<output>256</output>
<result>E</result> | E | 256 | xy=2 then what is (2^(x+y)^2) / (2^(x-y)^2) | {
"A": "2",
"B": "4",
"C": "8",
"D": "16",
"E": "256"
} | power(2, multiply(const_4, 2)) | multiply(n0,const_4)|power(n0,#0) | ( x + y ) ^ 2 - ( x - y ) ^ 2 ( x + y + x - y ) ( x + y - x + y ) ( 2 x ) ( 2 y ) 4 xy 8 2 ^ 8 = 256 answer e | general |
math_qa__lE5xfQGsHvNjfxHE | In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 5.5), (8, 0), (0, -5.5), (-8, 0)? Answers.
A) 56 B) 88 C) 112 D) 116 E) 120 | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">5.5 * 2</gadget>
<output>11</output>
<gadget id="calculator">(16 * 11) / 2</gadget>
<output>88</output>
<result>B</result> | B | 88 | In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 5.5), (8, 0), (0, -5.5), (-8, 0)? | {
"A": "56",
"B": "88",
"C": "112",
"D": "116",
"E": "120"
} | rhombus_area(multiply(8, const_2), multiply(5.5, const_2)) | multiply(n2,const_2)|multiply(n1,const_2)|rhombus_area(#0,#1) | ares of rhombus = 1 / 2 * d 1 * d 2 length of 1 st diagonal = 8 + 8 = 16 length of 2 nd diagonal = 5.5 + 5.5 = 11 area = 1 / 2 * 16 * 11 = 88 b is the answer | geometry |
math_qa__y9VlWyNQa4Jyjqss | A sum of money becomes 7/6 of itself in 5 years at a certain rate of simple interest. The rate per annum is?
Choose the correct choice from the following options:
A) 20 / 7 B) 20 / 3 C) 23 / 6 D) 10 / 3 E) 10 / 7 | <gadget id="calculator">7 / 6</gadget>
<output>7/6 = around 1.166667</output>
<gadget id="calculator">(7/6) - 1</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) / 5</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) * 100</gadget>
<output>10/3 = around 3.333333</output>
<result>D</result> | D | 3.333333 | A sum of money becomes 7/6 of itself in 5 years at a certain rate of simple interest. The rate per annum is? | {
"A": "20 / 7",
"B": "20 / 3",
"C": "23 / 6",
"D": "10 / 3",
"E": "10 / 7"
} | multiply(divide(subtract(divide(7, 6), const_1), 5), const_100) | divide(n0,n1)|subtract(#0,const_1)|divide(#1,n2)|multiply(#2,const_100)| | "let sum = x . then , amount = 7 x / 6 s . i . = 7 x / 6 - x = x / 6 ; time = 5 years . rate = ( 100 * x ) / ( x * 6 * 5 ) = 10 / 3 % . answer : d" | gain |
math_qa__TjfxbOB9hMzmzVDL | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 22, then how old is B? Choices: A) 17 years B) 19 years C) 29 years D) 8 years E) 12 years | <gadget id="calculator">22 - 2</gadget>
<output>20</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">40 / 5</gadget>
<output>8</output>
<result>D</result> | D | 8 | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 22, then how old is B? | {
"A": "17 years",
"B": "19 years",
"C": "29 years",
"D": "8 years",
"E": "12 years"
} | divide(multiply(subtract(22, const_2), const_2), add(const_4, const_1)) | add(const_1,const_4)|subtract(n0,const_2)|multiply(#1,const_2)|divide(#2,#0)| | "let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 22 5 x = 20 = > x = 4 hence , b ' s age = 2 x = 8 years . answer : d" | general |
math_qa__DR5Fs9rp1vRwbfrw | All the students of class are told to sit in circle shape. Here the boy at the 6 th position is exactly opposite to 16 th boy. Total number of boys in the class? Choose the correct choice from the following choices:
A) 10 B) 15 C) 20 D) 25 E) 30 | <gadget id="calculator">16 - 6</gadget>
<output>10</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<result>C</result> | C | 20 | All the students of class are told to sit in circle shape. Here the boy at the 6 th position is exactly opposite to 16 th boy. Total number of boys in the class? | {
"A": "10",
"B": "15",
"C": "20",
"D": "25",
"E": "30"
} | multiply(subtract(16, 6), const_2) | subtract(n1,n0)|multiply(#0,const_2) | as half the circle shape consist of 16 - 6 = 10 boys , so total number of boys in full circle = 2 * 10 = 20 answer : c | general |
math_qa__Nqmdz0txxPq9HIsm | The area of a square is 4624 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square. Choose the most appropriate option.
A) 5 : 28 B) 5 : 19 C) 5 : 12 D) 5 : 13 E) 11 : 34 | <gadget id="calculator">4_624 ** (1/2)</gadget>
<output>68</output>
<gadget id="calculator">68 - 24</gadget>
<output>44</output>
<gadget id="calculator">68 * 2</gadget>
<output>136</output>
<gadget id="calculator">44 / 136</gadget>
<output>11/34 = around 0.323529</output>
<result>E</result> | E | 0.323529 | The area of a square is 4624 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square. | {
"A": "5 : 28",
"B": "5 : 19",
"C": "5 : 12",
"D": "5 : 13",
"E": "11 : 34"
} | divide(subtract(sqrt(4624), 24), multiply(sqrt(4624), const_2)) | sqrt(n0)|multiply(#0,const_2)|subtract(#0,n1)|divide(#2,#1)| | "let the length and the breadth of the rectangle be l cm and b cm respectively . let the side of the square be a cm . a 2 = 4624 a 68 l = 2 a and b = a - 24 b : l = a - 24 : 2 a = 44 : 136 = 11 : 34 answer : e" | geometry |
math_qa__6wR8d9xlNMcx0EpU | In what time will a train 100 meters long cross an electric pole, if its speed is 162 km/hr Choices:
A) 8.5 seconds B) 2.22 seconds C) 3.5 seconds D) 2.5 seconds E) 2.6 seconds | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">162 * (5/18)</gadget>
<output>45</output>
<gadget id="calculator">100 / 45</gadget>
<output>20/9 = around 2.222222</output>
<result>B</result> | B | 2.22 | In what time will a train 100 meters long cross an electric pole, if its speed is 162 km/hr | {
"A": "8.5 seconds",
"B": "2.22 seconds",
"C": "3.5 seconds",
"D": "2.5 seconds",
"E": "2.6 seconds"
} | divide(100, multiply(162, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "first convert speed into m / sec speed = 162 * ( 5 / 18 ) = 45 m / sec time = distance / speed = 100 / 45 = 2.22 seconds answer : b" | physics |
math_qa__d4nfYlfPHhXXljh2 | Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.2120? Choose one
A) rs . 1000.15 B) rs . 1100.95 C) rs . 1892.85 D) rs . 1050.85 E) rs . 1200.25 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 5</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) + 1</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">2_120 / (28/25)</gadget>
<output>13_250/7 = around 1_892.857143</output>
<result>C</result> | C | 1,892.85 | Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.2120? | {
"A": "rs . 1000.15",
"B": "rs . 1100.95",
"C": "rs . 1892.85",
"D": "rs . 1050.85",
"E": "rs . 1200.25"
} | divide(2120, add(divide(multiply(divide(add(multiply(2, 5), 2), 5), 5), const_100), const_1)) | multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)| | "2120 = p [ 1 + ( 5 * 12 / 5 ) / 100 ] p = 1892.85 answer : c" | general |
math_qa__RYx5IK0k0kYrEgzD | The average age of an adult class is 40years. 8 new students with an avg age of 32years join the class. Therefore decreasing the average by 4year. Find what was theoriginal strength of class? Pick.
A) 8
B) 12
C) 15
D) 17
E) 18 | <gadget id="calculator">40 - 4</gadget>
<output>36</output>
<gadget id="calculator">8 * 36</gadget>
<output>288</output>
<gadget id="calculator">8 * 32</gadget>
<output>256</output>
<gadget id="calculator">288 - 256</gadget>
<output>32</output>
<gadget id="calculator">32 / 4</gadget>
<output>8</output>
<result>A</result> | A | 8 | The average age of an adult class is 40years. 8 new students with an avg age of 32years join the class. Therefore decreasing the average by 4year. Find what was theoriginal strength of class? | {
"A": "8",
"B": "12",
"C": "15",
"D": "17",
"E": "18"
} | divide(subtract(multiply(8, subtract(40, 4)), multiply(8, 32)), 4) | multiply(n1,n2)|subtract(n0,n3)|multiply(n1,#1)|subtract(#2,#0)|divide(#3,n3)| | "let original strength = y then , 40 y + 8 x 32 = ( y + 8 ) x 36 â ‡ ’ 40 y + 256 = 36 y + 288 â ‡ ’ 4 y = 32 â ˆ ´ y = 8 a" | general |
math_qa__XjBAF81WEYWhqtzm | What least number should be added to 1056,So that the sum is completely divisible by 23? Choose the correct choice from the following answers: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">1_056 % 23</gadget>
<output>21</output>
<gadget id="calculator">23 - 21</gadget>
<output>2</output>
<result>B</result> | B | 2 | What least number should be added to 1056,So that the sum is completely divisible by 23? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(23, reminder(1056, 23)) | reminder(n0,n1)|subtract(n1,#0)| | "that is 1056 / 23 = 45 remainder = 21 = > 21 + 2 = 23 hence 2 should be added to 1056 so that the sum will be divisible by 23 answer is option b" | general |
math_qa__ccxPe0wgSa8cL56U | At a restaurant, glasses are stored in two different-sized boxes. One box contains 12 glasses, and the other contains 16 glasses. If the average number of glasses per box is 15, and there are 16 more of the larger boxes, what is the total number of glasses T at the restaurant? (Assume that all boxes are filled to capacity.)
Options:
A) 96
B) 240
C) t = 256
D) t = 384
E) t = 480 | <gadget id="calculator">16 * 2</gadget>
<output>32</output>
<gadget id="calculator">32 * 15</gadget>
<output>480</output>
<result>E</result> | E | 480 | At a restaurant, glasses are stored in two different-sized boxes. One box contains 12 glasses, and the other contains 16 glasses. If the average number of glasses per box is 15, and there are 16 more of the larger boxes, what is the total number of glasses T at the restaurant? (Assume that all boxes are filled to capacity.) | {
"A": "96",
"B": "240",
"C": "t = 256",
"D": "t = 384",
"E": "t = 480"
} | multiply(multiply(16, const_2), 15) | multiply(n1,const_2)|multiply(n2,#0)| | "most test takers would recognize the system of equations in this prompt and just do algebra to get to the solution ( and that ' s fine ) . the wording of the prompt and the ' spread ' of the answer choices actually provide an interesting ' brute force ' shortcut that you can take advantage of to eliminate the 4 wrong answers . . . . we ' re told that there are 2 types of boxes : those that hold 12 glasses and those that hold 16 glasses . since the average number of boxes is 15 , we know that there must be at least some of each . we ' re also told that that there are 16 more of the larger boxes . this means , at the minimum , we have . . . 1 small box and 17 large boxes = 1 ( 12 ) + 17 ( 16 ) = 12 + 272 = 284 glasses at the minimum since the question asks for the total number of glasses , we can now eliminate answers a , b and c . . . . the difference in the number of boxes must be 16 though , so we could have . . . . 2 small boxes and 18 large boxes 3 small boxes and 19 large boxes etc . with every additional small box + large box that we add , we add 12 + 16 = 28 more glasses . thus , we can justadd 28 suntil we hit the correct answer . . . . 284 + 28 = 312 312 + 28 = 340 340 + 28 = 368 368 + 28 = 396 at this point , we ' ve ' gone past ' answer d , so the correct answer must be answer e . . . . . but here ' s the proof . . . . 396 + 28 = 424 424 + 28 = 452 452 + 28 = 480 final answer : e" | general |
math_qa__oTYHABTNgYVvuCD7 | A train 550 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
Choose the correct choice from the following answers: A) 5 B) 6 C) 7 D) 8 E) 30 | <gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">66 * (5/18)</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">550 / (55/3)</gadget>
<output>30</output>
<result>E</result> | E | 30 | A train 550 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? | {
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "30"
} | divide(550, multiply(add(60, 6), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 60 + 6 = 66 km / hr . = 66 * 5 / 18 = 55 / 3 m / sec . time taken to pass the men = 550 * 3 / 55 = 30 sec . answer : option e" | physics |
math_qa__B6tLhD9jX0AYZfpM | Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 186 cms. What was the ratio of men to women?
Choose the correct option: A) 5 : 2 B) 5 : 1 C) 5 : 3 D) 4 : 1 E) 3 : 1 | <gadget id="calculator">180 - 170</gadget>
<output>10</output>
<gadget id="calculator">186 - 180</gadget>
<output>6</output>
<gadget id="calculator">10 / 6</gadget>
<output>5/3 = around 1.666667</output>
<result>C</result> | C | 1.666667 | Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 186 cms. What was the ratio of men to women? | {
"A": "5 : 2",
"B": "5 : 1",
"C": "5 : 3",
"D": "4 : 1",
"E": "3 : 1"
} | divide(subtract(180, 170), subtract(186, 180)) | subtract(n0,n1)|subtract(n2,n0)|divide(#0,#1)| | "we ' re given a few facts to work with : 1 ) the average height of the females is 170 cm 2 ) the average height of the males is 186 cm 3 ) the average of the group is 180 cm we ' re asked for the ratio of men to women . w = number of women m = number of men ( 170 w + 186 m ) / ( w + m ) = 180 170 w + 186 m = 180 w + 180 m 6 m = 10 w 3 m = 5 w m / w = 5 / 3 the ratio of men to women is 5 to 3 . c" | general |
math_qa__Vv68VUt1epH69XlL | How many digits are used to number a book containg 300 pages. Choices:
A) 694 B) 792 C) 698 D) 784 E) 789 | <gadget id="calculator">300 * 2</gadget>
<output>600</output>
<gadget id="calculator">600 + 100</gadget>
<output>700</output>
<gadget id="calculator">100 - 4</gadget>
<output>96</output>
<gadget id="calculator">96 - 4</gadget>
<output>92</output>
<gadget id="calculator">700 + 92</gadget>
<output>792</output>
<result>B</result> | B | 792 | How many digits are used to number a book containg 300 pages. | {
"A": "694",
"B": "792",
"C": "698",
"D": "784",
"E": "789"
} | add(add(multiply(300, const_2), const_100), subtract(subtract(const_100, const_4), const_4)) | multiply(n0,const_2)|subtract(const_100,const_4)|add(#0,const_100)|subtract(#1,const_4)|add(#2,#3) | explanation : number of digits in 1 digit numbers = 1 to 9 = 9 number of digits in 2 digit numbers = 10 to 99 = 90 ( 2 ) = 180 number of digits in 3 digit numbers = 100 to 300 = 201 ( 3 ) = 603 total = 792 answer : option b | general |
math_qa__T64iZuk0P3ct6A5O | Barbata invests $2800 in the National Bank at 5%. How much additional money must she invest at 8% so that the total annual income will be equal to 6% of her entire investment? Choices:
A) 1200 B) 3000 C) 1000 D) 1400 E) 2400 | <gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 2_800</gadget>
<output>168</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">2_800 * (1/20)</gadget>
<output>140</output>
<gadget id="calculator">168 - 140</gadget>
<output>28</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/25) - (3/50)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">28 / (1/50)</gadget>
<output>1_400</output>
<result>D</result> | D | 1,400 | Barbata invests $2800 in the National Bank at 5%. How much additional money must she invest at 8% so that the total annual income will be equal to 6% of her entire investment? | {
"A": "1200",
"B": "3000",
"C": "1000",
"D": "1400",
"E": "2400"
} | divide(subtract(multiply(divide(6, const_100), 2800), multiply(2800, divide(5, const_100))), subtract(divide(8, const_100), divide(6, const_100))) | divide(n3,const_100)|divide(n1,const_100)|divide(n2,const_100)|multiply(n0,#0)|multiply(n0,#1)|subtract(#2,#0)|subtract(#3,#4)|divide(#6,#5)| | "let the additional invested amount for 8 % interest be x ; equation will be ; 2800 + 0.05 * 2800 + x + 0.08 x = 2800 + x + 0.06 ( 2800 + x ) 0.05 * 2800 + 0.08 x = 0.06 x + 0.06 * 2800 0.02 x = 2800 ( 0.06 - 0.05 ) x = 2800 * 0.01 / 0.02 = 1400 ans : ` ` d ' '" | general |
math_qa__f1oyKJEwMS5GlrNx | At what rate percent on simple interest will Rs.600 amount to Rs.950 in 5 years? Options.
A) 3.33 %
B) 5.93 %
C) 4.33 %
D) 9.33 %
E) 11.67 % | <gadget id="calculator">950 - 600</gadget>
<output>350</output>
<gadget id="calculator">350 / 600</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">(7/12) / 5</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">(7/60) * 100</gadget>
<output>35/3 = around 11.666667</output>
<result>E</result> | E | 11.67 | At what rate percent on simple interest will Rs.600 amount to Rs.950 in 5 years? | {
"A": "3.33 %",
"B": "5.93 %",
"C": "4.33 %",
"D": "9.33 %",
"E": "11.67 %"
} | multiply(divide(divide(subtract(950, 600), 600), 5), const_100) | subtract(n1,n0)|divide(#0,n0)|divide(#1,n2)|multiply(#2,const_100)| | "350 = ( 600 * 5 * r ) / 100 r = 11.67 % answer : e" | gain |
math_qa__2YdYRw0i5n2LFx8n | A, B and C can do a work in 90, 45 and 6 days respectively. If they work together, in how many days will they complete the work? Pick one.
A) 5 B) 6 C) 7 D) 8 E) 11 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 90</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">(1/90) + (1/45)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/6) + (1/30)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / (1/5)</gadget>
<output>5</output>
<result>A</result> | A | 5 | A, B and C can do a work in 90, 45 and 6 days respectively. If they work together, in how many days will they complete the work? | {
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "11"
} | inverse(add(divide(const_1, 6), add(divide(const_1, 90), divide(const_1, 45)))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#3,#2)|inverse(#4) | one days ' s work of a , b and c = 1 / 90 + 1 / 45 + 1 / 6 = ( 1 + 2 + 15 ) / 90 = 1 / 5 a , b and c together can do the work in 5 days . answer : a | physics |
math_qa__D1MDMuP52oCRcD92 | A man can row upstream at 25 kmph and downstream at 41 kmph, and then find the speed of the man in still water?
Choose the correct answer:
A) 33 B) 67 C) 30 D) 15 E) 17 | <gadget id="calculator">25 + 41</gadget>
<output>66</output>
<gadget id="calculator">66 / 2</gadget>
<output>33</output>
<result>A</result> | A | 33 | A man can row upstream at 25 kmph and downstream at 41 kmph, and then find the speed of the man in still water? | {
"A": "33",
"B": "67",
"C": "30",
"D": "15",
"E": "17"
} | divide(add(25, 41), const_2) | add(n0,n1)|divide(#0,const_2)| | "us = 25 ds = 41 m = ( 41 + 25 ) / 2 = 33 answer : a" | physics |
math_qa__SqrQdqz7l4kZffS0 | I bought two books; for Rs.450. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss? Choose the correct option.
A) 337 B) 262.5 C) 299.5 D) 266.5 E) 299 | <gadget id="calculator">100 + 19</gadget>
<output>119</output>
<gadget id="calculator">450 * 119</gadget>
<output>53_550</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 + 119</gadget>
<output>204</output>
<gadget id="calculator">53_550 / 204</gadget>
<output>525/2 = around 262.5</output>
<result>B</result> | B | 262.5 | I bought two books; for Rs.450. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss? | {
"A": "337",
"B": "262.5",
"C": "299.5",
"D": "266.5",
"E": "299"
} | divide(multiply(450, add(const_100, 19)), add(subtract(const_100, 15), add(const_100, 19))) | add(n2,const_100)|subtract(const_100,n1)|add(#0,#1)|multiply(n0,#0)|divide(#3,#2)| | "x * ( 85 / 100 ) = ( 450 - x ) 119 / 100 x = 262.5 answer : b" | gain |
math_qa__lyErLKE573ouFNft | How many multiples of 5 are there between 1 and 100 (both are inclusive)? Select the correct option:
A) 1.2
B) 20.8
C) 2.3
D) 6.7
E) 8.2 | <gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">99 / 5</gadget>
<output>99/5 = around 19.8</output>
<gadget id="calculator">(99/5) + 1</gadget>
<output>104/5 = around 20.8</output>
<result>B</result> | B | 20.8 | How many multiples of 5 are there between 1 and 100 (both are inclusive)? | {
"A": "1.2",
"B": "20.8",
"C": "2.3",
"D": "6.7",
"E": "8.2"
} | add(divide(subtract(100, 1), 5), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "the answer is ( 100 - 1 ) / 5 + 1 = 20.8 answer is b" | other |
math_qa__0FqRRdDhnwiogY5n | In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 14 percent of revenues. The profits in 1999 were what percent of the profits in 1998? Choose the correct choice from the following options: A) 80 % B) 105 % C) 120 % D) 124.2 % E) 98 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/10) * (7/50)</gadget>
<output>49/500 = around 0.098</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(49/500) / (1/10)</gadget>
<output>49/50 = around 0.98</output>
<gadget id="calculator">(49/50) * 100</gadget>
<output>98</output>
<result>E</result> | E | 98 | In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 14 percent of revenues. The profits in 1999 were what percent of the profits in 1998? | {
"A": "80 %",
"B": "105 %",
"C": "120 %",
"D": "124.2 %",
"E": "98 %"
} | multiply(divide(multiply(subtract(const_1, divide(30, const_100)), divide(14, const_100)), divide(10, const_100)), const_100) | divide(n4,const_100)|divide(n3,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(#0,#3)|divide(#4,#2)|multiply(#5,const_100) | 0,098 r = x / 100 * 0.1 r answer e | gain |
math_qa__zKwXecQhXvndUZC7 | The speed of a train is 110 kmph. What is the distance covered by it in 11 minutes? Choose the correct choice from the following answers.
A) 15 kmph B) 11 kmph C) 88 kmph D) 20 kmph E) 12 kmph | <gadget id="calculator">11 / 60</gadget>
<output>11/60 = around 0.183333</output>
<gadget id="calculator">(11/60) * 110</gadget>
<output>121/6 = around 20.166667</output>
<result>D</result> | D | 20 | The speed of a train is 110 kmph. What is the distance covered by it in 11 minutes? | {
"A": "15 kmph",
"B": "11 kmph",
"C": "88 kmph",
"D": "20 kmph",
"E": "12 kmph"
} | multiply(divide(11, const_60), 110) | divide(n1,const_60)|multiply(n0,#0)| | "110 * 11 / 60 = 20 kmph answer : d" | physics |
math_qa__T7tOEw0UuMiXBGgV | A sum of money at simple interest amounts to Rs. 2240 in 2 years and to Rs. 2600 in 5 years. The sum is: Choose the correct choice from the following answers
A) rs . 1500 B) rs . 2000 C) rs . 1000 D) rs . 1200 E) rs . 1800 | <gadget id="calculator">2_600 - 2_240</gadget>
<output>360</output>
<gadget id="calculator">360 * 2</gadget>
<output>720</output>
<gadget id="calculator">720 / 5</gadget>
<output>144</output>
<gadget id="calculator">2_240 - 144</gadget>
<output>2_096</output>
<result>B</result> | B | 2,000 | A sum of money at simple interest amounts to Rs. 2240 in 2 years and to Rs. 2600 in 5 years. The sum is: | {
"A": "rs . 1500",
"B": "rs . 2000",
"C": "rs . 1000",
"D": "rs . 1200",
"E": "rs . 1800"
} | subtract(2240, divide(multiply(subtract(2600, 2240), 2), 5)) | subtract(n2,n0)|multiply(n1,#0)|divide(#1,n3)|subtract(n0,#2)| | "s . i . for 3 years = rs . ( 2600 - 2240 ) = rs . 360 . s . i . for 1 year = rs . 360 / 3 = rs . 120 . s . i . for 2 years = rs . ( 120 x 2 ) = rs . 240 . principal = rs . ( 2240 - 240 ) = rs . 2000 . answer : option b" | gain |
math_qa__lJv4dbl0jdpEi2RQ | Mother,her daughter and her grand child weighs 120 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter?
Choose the correct choice from the following answers.
A) 46 B) 47 C) 48 D) 49 E) 50 | <gadget id="calculator">120 - 60</gadget>
<output>60</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">60 - 12</gadget>
<output>48</output>
<result>C</result> | C | 48 | Mother,her daughter and her grand child weighs 120 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter? | {
"A": "46",
"B": "47",
"C": "48",
"D": "49",
"E": "50"
} | subtract(60, divide(subtract(120, 60), 5)) | subtract(n0,n1)|divide(#0,n3)|subtract(n1,#1)| | "mother + daughter + child = 120 kg daughter + child = 60 kg mother = 120 - 60 = 60 kg child = 1 / 5 th of mother = ( 1 / 5 ) * 60 = 12 kg so now daughter = 120 - ( mother + child ) = 120 - ( 60 + 12 ) = 48 kg answer : c" | general |
math_qa__AkresDgT1Eog1ClH | 150 is what percent of 60 ? Choose the correct choice from the following choices
A) 250 % B) 20 % C) 50 % D) 200 % E) 500 % | <gadget id="calculator">150 / 60</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 100</gadget>
<output>250</output>
<result>A</result> | A | 250 | 150 is what percent of 60 ? | {
"A": "250 %",
"B": "20 %",
"C": "50 %",
"D": "200 %",
"E": "500 %"
} | multiply(divide(150, 60), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "60 * x = 150 - - > x = 2.5 - - > 2.5 expressed as percent is 250 % . answer : a ." | gain |
math_qa__B9iy68PY6Q2hRD4F | In a class of students, 1/2 of the number of girls is equal to 1/5 of the total number of students. What is the ratio of boys to girls in the class? Select the correct option.
A) 1 / 2 B) 3 / 2 C) 1 / 3 D) 2 / 3 E) 4 / 3 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/2) - (1/5)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) / (1/5)</gadget>
<output>3/2 = around 1.5</output>
<result>B</result> | B | 1.5 | In a class of students, 1/2 of the number of girls is equal to 1/5 of the total number of students. What is the ratio of boys to girls in the class? | {
"A": "1 / 2",
"B": "3 / 2",
"C": "1 / 3",
"D": "2 / 3",
"E": "4 / 3"
} | divide(subtract(divide(1, 2), divide(1, 5)), divide(1, 5)) | divide(n0,n1)|divide(n2,n3)|subtract(#0,#1)|divide(#2,#1)| | "( 1 / 2 ) g = ( 1 / 5 ) ( b + g ) 5 g = 2 b + 2 g 3 g = 2 b b / g = 3 / 2 . the answer is b ." | general |
math_qa__SfYE35oLvUtEJK8W | For a positive integer n, if 5^n is a factor of 20!, but 5^n+1 is not a factor of 20!, what is the value of n? Choose the correct choice from the following answers.
A) 4
B) 6
C) 7
D) 8
E) 9 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<result>A</result> | A | 4 | For a positive integer n, if 5^n is a factor of 20!, but 5^n+1 is not a factor of 20!, what is the value of n? | {
"A": "4",
"B": "6",
"C": "7",
"D": "8",
"E": "9"
} | subtract(subtract(multiply(5, 5), 20), 1) | multiply(n0,n0)|subtract(#0,n1)|subtract(#1,n3) | 20 ! has four 5 ' s 20 / 5 = 4 thus 5 ^ 4 can completely divide 20 ! and 5 ^ 5 can not divide 20 ! so , answer will be ( a ) 4 | other |
math_qa__aUyZZUjICnYkvTfk | A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 570 pounds after processing, how many pounds did it weigh before processing? Choose the correct choice from the following choices: A) 191 B) 355 C) 737 D) 876 E) 1,560 | <gadget id="calculator">570 * 100</gadget>
<output>57_000</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">57_000 / 65</gadget>
<output>11_400/13 = around 876.923077</output>
<result>D</result> | D | 876 | A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 570 pounds after processing, how many pounds did it weigh before processing? | {
"A": "191",
"B": "355",
"C": "737",
"D": "876",
"E": "1,560"
} | divide(multiply(570, const_100), subtract(const_100, 35)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "let weight of side of beef before processing = x ( 65 / 100 ) * x = 570 = > x = ( 570 * 100 ) / 65 = 876 answer d" | gain |
math_qa__MXL2ZLcpJ2MGuaJM | In what time will a railway train 96 m long moving at the rate of 45 kmph pass a telegraph post on its way?
Choose the most appropriate option.
A) 3 sec
B) 8 sec
C) 5 sec
D) 6 sec
E) 7 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">45 * (5/18)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">96 / (25/2)</gadget>
<output>192/25 = around 7.68</output>
<result>B</result> | B | 8 | In what time will a railway train 96 m long moving at the rate of 45 kmph pass a telegraph post on its way? | {
"A": "3 sec",
"B": "8 sec",
"C": "5 sec",
"D": "6 sec",
"E": "7 sec"
} | divide(96, multiply(45, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 96 / 45 * 18 / 5 = 8 sec answer : b" | physics |
math_qa__l3Rf2ukg0tAyJN9n | What is x if x + 2y = 10 and y = 3?
Choose the correct answer
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">10 - 6</gadget>
<output>4</output>
<result>D</result> | D | 4 | What is x if x + 2y = 10 and y = 3? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(10, multiply(2, 3)) | multiply(n0,n2)|subtract(n1,#0)| | "substitute y by 3 in x + 2 y = 10 x + 2 ( 3 ) = 10 x + 6 = 10 if we substitute x by 4 in x + 6 = 10 , we have 4 + 6 = 10 . hence x = 4 correct answer d" | general |
math_qa__EOLutO2usVo56ZQ0 | If 10a = 6b = 20, then 120ab = Choose the correct choice from the following answers:
A) 800 B) 1000 C) 1200 D) 1400 E) 1600 | <gadget id="calculator">20 / 10</gadget>
<output>2</output>
<gadget id="calculator">20 / 6</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">2 * (10/3)</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">120 * (20/3)</gadget>
<output>800</output>
<result>A</result> | A | 800 | If 10a = 6b = 20, then 120ab = | {
"A": "800",
"B": "1000",
"C": "1200",
"D": "1400",
"E": "1600"
} | multiply(120, multiply(divide(20, 10), divide(20, 6))) | divide(n2,n0)|divide(n2,n1)|multiply(#0,#1)|multiply(n3,#2)| | "10 a * 6 b = 20 * 20 = 400 60 ab = 400 i . e . 120 ab = 800 answer : option a" | general |
math_qa__izfO8yrTYf0Vw7sB | Which number need to add to 7844213 to get a number exactly divisible by 549? Options
A) 418
B) 148
C) 448
D) 248
E) 348 | <gadget id="calculator">7_844_213 / 549</gadget>
<output>7_844_213/549 = around 14_288.183971</output>
<gadget id="calculator">floor(7_844_213/549)</gadget>
<output>14_288</output>
<gadget id="calculator">14_288 + 1</gadget>
<output>14_289</output>
<gadget id="calculator">14_289 - (7_844_213/549)</gadget>
<output>448/549 = around 0.816029</output>
<gadget id="calculator">549 * (448/549)</gadget>
<output>448</output>
<result>C</result> | C | 448 | Which number need to add to 7844213 to get a number exactly divisible by 549? | {
"A": "418",
"B": "148",
"C": "448",
"D": "248",
"E": "348"
} | multiply(549, subtract(add(floor(divide(7844213, 549)), const_1), divide(7844213, 549))) | divide(n0,n1)|floor(#0)|add(#1,const_1)|subtract(#2,#0)|multiply(n1,#3)| | "7844213 / 549 = 14288 and reminder = 101 . 549 - 101 = 448 so , the next number divisible by 549 is 448 places in front of 7844213 which means 448 + 7844213 = 7844661 448 should be added to 7844213 c" | general |
math_qa__AfpSJj8WfBNO9NAY | A scale 7 ft. 12 inches long is divided into 4 equal parts. Find the length of each part. Choices.
A) 20 inches
B) 77 inches
C) 24 inches
D) 97 inches
E) 66 inches | <gadget id="calculator">7 * 12</gadget>
<output>84</output>
<gadget id="calculator">84 + 12</gadget>
<output>96</output>
<gadget id="calculator">96 / 4</gadget>
<output>24</output>
<result>C</result> | C | 24 | A scale 7 ft. 12 inches long is divided into 4 equal parts. Find the length of each part. | {
"A": "20 inches",
"B": "77 inches",
"C": "24 inches",
"D": "97 inches",
"E": "66 inches"
} | divide(add(multiply(7, const_12), 12), 4) | multiply(n0,const_12)|add(n1,#0)|divide(#1,n2)| | "explanation : total length of scale in inches = ( 7 * 12 ) + 12 = 96 inches length of each of the 4 parts = 96 / 4 = 24 inches answer : c" | general |
math_qa__LU6v3hxLZEBAAZFD | The population of a town increases 10% and 20% respectively in two consecutive years. After the growth the present population of the town is 1320. Then what is the population of the town 2 years ago?
Choose the correct choice from the following answers:
A) 1100 B) 1001 C) 1010 D) 1000 E) 1002 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(11/10) * (6/5)</gadget>
<output>33/25 = around 1.32</output>
<gadget id="calculator">1_320 / (33/25)</gadget>
<output>1_000</output>
<result>D</result> | D | 1,000 | The population of a town increases 10% and 20% respectively in two consecutive years. After the growth the present population of the town is 1320. Then what is the population of the town 2 years ago? | {
"A": "1100",
"B": "1001",
"C": "1010",
"D": "1000",
"E": "1002"
} | divide(1320, multiply(add(const_1, divide(10, const_100)), add(const_1, divide(20, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|divide(n2,#4)| | "explanation : formula : ( after = 100 denominator ago = 100 numerator ) 1320 * 100 / 110 * 100 / 120 = 1000 answer : option d" | gain |
math_qa__PTo9XX16MAG93JLg | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 408 votes. Find the number of votes casted to the winning candidate?
Pick one: A) 288 B) 1054 C) 788 D) 298 E) 177 | <gadget id="calculator">100 - 62</gadget>
<output>38</output>
<gadget id="calculator">62 - 38</gadget>
<output>24</output>
<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">408 / (6/25)</gadget>
<output>1_700</output>
<gadget id="calculator">1_700 * 62</gadget>
<output>105_400</output>
<gadget id="calculator">105_400 / 100</gadget>
<output>1_054</output>
<result>B</result> | B | 1,054 | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 408 votes. Find the number of votes casted to the winning candidate? | {
"A": "288",
"B": "1054",
"C": "788",
"D": "298",
"E": "177"
} | divide(multiply(divide(408, divide(subtract(62, subtract(const_100, 62)), const_100)), 62), const_100) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)| | "w = 62 % l = 38 % 62 % - 38 % = 24 % 24 % - - - - - - - - 408 62 % - - - - - - - - ? = > 1054 answer : b" | gain |
math_qa__d8MJMhkkOCf0BgKr | 20 beavers, working together in a constant pace, can build a dam in 3 hours. How many V hours will it take 12 beavers that work at the same pace, to build the same dam? Select the correct option:
A) 2 .
B) v = 4 .
C) v = 5 .
D) v = 6 .
E) 8 . | <gadget id="calculator">3 * 20</gadget>
<output>60</output>
<gadget id="calculator">60 / 12</gadget>
<output>5</output>
<result>C</result> | C | 5 | 20 beavers, working together in a constant pace, can build a dam in 3 hours. How many V hours will it take 12 beavers that work at the same pace, to build the same dam? | {
"A": "2 .",
"B": "v = 4 .",
"C": "v = 5 .",
"D": "v = 6 .",
"E": "8 ."
} | divide(multiply(3, 20), 12) | multiply(n0,n1)|divide(#0,n2)| | "c . 5 hrs if there were 10 beavers it qould have taken double v = 6 hrs . . so closest to that option is 5 ." | physics |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.