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math_qa__aTnaDMs4exMTS9Mw | A certain list consists of 21 different numbers. If n is in the list and n is 3 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list? Choose the correct choice from the following options:
A) 1 / 20 B) 1 / 6 C) 1 / 5 D) 4 / 21 E) 3 / 23 | <gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">20 / 3</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">(20/3) + 21</gadget>
<output>83/3 = around 27.666667</output>
<gadget id="calculator">(83/3) / 4</gadget>
<output>83/12 = around 6.916667</output>
<gadget id="calculator">(83/12) * 2</gadget>
<output>83/6 = around 13.833333</output>
<gadget id="calculator">(83/6) - 3</gadget>
<output>65/6 = around 10.833333</output>
<gadget id="calculator">(65/6) - 3</gadget>
<output>47/6 = around 7.833333</output>
<gadget id="calculator">1 / (47/6)</gadget>
<output>6/47 = around 0.12766</output>
<result>E</result> | E | 0.130435 | A certain list consists of 21 different numbers. If n is in the list and n is 3 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list? | {
"A": "1 / 20",
"B": "1 / 6",
"C": "1 / 5",
"D": "4 / 21",
"E": "3 / 23"
} | divide(multiply(const_1, const_1), subtract(subtract(multiply(divide(add(divide(20, 3), 21), const_4.0), const_2), 3), const_3)) | divide(n2,n1)|multiply(const_1,const_1)|add(n0,#0)|divide(#2,const_4.0)|multiply(#3,const_2)|subtract(#4,n1)|subtract(#5,const_3)|divide(#1,#6)| | "series : a 1 , a 2 . . . . a 20 , n sum of a 1 + a 2 + . . . + a 20 = 20 * x ( x = average ) so , n = 3 * x hence , a 1 + a 2 + . . + a 20 + n = 23 x so , the fraction asked = 3 x / 23 x = 3 / 23 answer e" | general |
math_qa__CAZwOG8P3E32xE5g | I chose a number and divide it by 8. Then I subtracted 100 from the result and got 6. What was the number I chose?
Pick.
A) 600 B) 700 C) 800 D) 900 E) 848 | <gadget id="calculator">100 + 6</gadget>
<output>106</output>
<gadget id="calculator">106 * 8</gadget>
<output>848</output>
<result>E</result> | E | 848 | I chose a number and divide it by 8. Then I subtracted 100 from the result and got 6. What was the number I chose? | {
"A": "600",
"B": "700",
"C": "800",
"D": "900",
"E": "848"
} | multiply(add(100, 6), 8) | add(n1,n2)|multiply(n0,#0)| | "solution : let x be the number i chose , then x / 8 â ˆ ’ 100 = 6 x / 8 = 106 x = 848 answer e" | general |
math_qa__rTQIUkrts5qZKd39 | The population of a bacteria colony doubles every day. If it was started 7 days ago with 2 bacteria and each bacteria lives for 12 days, how large is the colony today? Choose the correct choice from the following
A) 128
B) 256
C) 512
D) 1024
E) 2048 | <gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">2 ** 8</gadget>
<output>256</output>
<gadget id="calculator">256 - 1</gadget>
<output>255</output>
<result>B</result> | B | 256 | The population of a bacteria colony doubles every day. If it was started 7 days ago with 2 bacteria and each bacteria lives for 12 days, how large is the colony today? | {
"A": "128",
"B": "256",
"C": "512",
"D": "1024",
"E": "2048"
} | subtract(power(2, add(7, const_1)), const_1) | add(n0,const_1)|power(n1,#0)|subtract(#1,const_1) | 2 ^ 7 ( 2 ) = 2 ^ 8 = 256 the answer is b . | physics |
math_qa__D2mdw3kxcEBIe2S9 | Light glows for every 32 seconds . How many max. times did it glow between 1:57:58 and 3:20:47 am. Choose the correct choice from the following
A) 180 times B) 381 times C) 155 times D) 392 times E) 150 times | <gadget id="calculator">2 + 47</gadget>
<output>49</output>
<gadget id="calculator">2 + 60</gadget>
<output>62</output>
<gadget id="calculator">20 + 62</gadget>
<output>82</output>
<gadget id="calculator">82 * 60</gadget>
<output>4_920</output>
<gadget id="calculator">49 + 4_920</gadget>
<output>4_969</output>
<gadget id="calculator">4_969 / 32</gadget>
<output>4_969/32 = around 155.28125</output>
<result>C</result> | C | 155 | Light glows for every 32 seconds . How many max. times did it glow between 1:57:58 and 3:20:47 am. | {
"A": "180 times",
"B": "381 times",
"C": "155 times",
"D": "392 times",
"E": "150 times"
} | divide(add(add(const_2, 47), multiply(add(20, add(const_2, const_60)), const_60)), 32) | add(n6,const_2)|add(const_2,const_60)|add(n5,#1)|multiply(#2,const_60)|add(#0,#3)|divide(#4,n0)| | "time difference is 1 hr , 22 min , 49 sec = 4969 sec . so , light glows floor ( 4969 / 32 ) = 15582 times . answer : c" | general |
math_qa__Kaiax7JdhX3clUwO | If the height of a right cone C is 3 and the diameter of the base of C is 8, what is the distance from the apex of C to any point on the circumference of the base of C? Pick one: A) 3 √ 2 B) 5 C) 5 √ 2 D) √ ( 67 ) E) √ ( 73 ) | <gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">16 + 9</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<result>B</result> | B | 5 | If the height of a right cone C is 3 and the diameter of the base of C is 8, what is the distance from the apex of C to any point on the circumference of the base of C? | {
"A": "3 √ 2",
"B": "5",
"C": "5 √ 2",
"D": "√ ( 67 )",
"E": "√ ( 73 )"
} | sqrt(add(power(divide(8, const_2), const_2), power(3, const_2))) | divide(n1,const_2)|power(n0,const_2)|power(#0,const_2)|add(#2,#1)|sqrt(#3) | height of cone = 3 radius of base = 4 so the distance from the apex of c to any point on the circumference of the base of c will be a right angled triangle hence the distance is sqrt ( 3 ^ 2 + 4 ^ 2 ) = 5 answer : b | geometry |
math_qa__SbYgwLW7WIihCuB0 | A can copy 50 papers in 10 hrs, while A & B can copy 70 papers in 10 hrs. How many hours are required for B to copy 26 papers? Answers:
A) 11 hours B) 12 hours C) 13 hours D) 14 hours E) 18 hours | <gadget id="calculator">26 * 10</gadget>
<output>260</output>
<gadget id="calculator">70 - 50</gadget>
<output>20</output>
<gadget id="calculator">260 / 20</gadget>
<output>13</output>
<result>C</result> | C | 13 | A can copy 50 papers in 10 hrs, while A & B can copy 70 papers in 10 hrs. How many hours are required for B to copy 26 papers? | {
"A": "11 hours",
"B": "12 hours",
"C": "13 hours",
"D": "14 hours",
"E": "18 hours"
} | divide(multiply(26, 10), subtract(70, 50)) | multiply(n1,n4)|subtract(n2,n0)|divide(#0,#1) | a can copy 50 papers in 10 hrs , while a & b can copy 70 papers in 10 hrs . it means b can copy 20 papers in 10 hrs . then time taken by b to copy 26 papers = 26 * 10 / 20 = 13 hours answer : c | physics |
math_qa__AAZ2OoEmYx7HMDeL | Shanmukham buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods Choose the correct choice from the following answers: A) 6999.2 B) 6876.1 C) 6654 D) 7000 E) none of these | <gadget id="calculator">6_650 * 6</gadget>
<output>39_900</output>
<gadget id="calculator">39_900 / 100</gadget>
<output>399</output>
<gadget id="calculator">6_650 - 399</gadget>
<output>6_251</output>
<gadget id="calculator">6_251 * 10</gadget>
<output>62_510</output>
<gadget id="calculator">62_510 / 100</gadget>
<output>6_251/10 = around 625.1</output>
<gadget id="calculator">6_251 + (6_251/10)</gadget>
<output>68_761/10 = around 6_876.1</output>
<result>B</result> | B | 6,876.1 | Shanmukham buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods | {
"A": "6999.2",
"B": "6876.1",
"C": "6654",
"D": "7000",
"E": "none of these"
} | add(subtract(6650, divide(multiply(6650, 6), const_100)), divide(multiply(subtract(6650, divide(multiply(6650, 6), const_100)), const_10), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(#2,const_10)|divide(#3,const_100)|add(#4,#2) | explanation : rebate = 6 % of rs . 6650 = rs . 6 / 100 x 6650 = rs . 399 . sales tax = 10 % of rs . ( 6650 399 ) = rs . 10 / 100 x 6251 = rs . 625.10 final amount = rs . ( 6251 + 625.10 ) = rs . 6876.10 answer : b | gain |
math_qa__07dAkE66FXD17Hdn | The maximum numbers of students among them 781 pens and 710 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is Answers: A) 71 B) 910 C) 1001 D) 1911 E) none | <gadget id="calculator">781 - 710</gadget>
<output>71</output>
<result>A</result> | A | 71 | The maximum numbers of students among them 781 pens and 710 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is | {
"A": "71",
"B": "910",
"C": "1001",
"D": "1911",
"E": "none"
} | subtract(781, 710) | subtract(n0,n1)| | "olution required number of students . = h . c . f of 781 and 710 . â € ¹ = â € º 71 . answer a" | general |
math_qa__CoqiIya0fBJyCWZx | The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 3 years hence?
Choose the correct choice from the following answers.
A) 58 B) 59 C) 62 D) 66 E) 74 | <gadget id="calculator">60 / 3</gadget>
<output>20</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">40 + 3</gadget>
<output>43</output>
<gadget id="calculator">20 + 3</gadget>
<output>23</output>
<gadget id="calculator">43 + 23</gadget>
<output>66</output>
<result>D</result> | D | 66 | The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 3 years hence? | {
"A": "58",
"B": "59",
"C": "62",
"D": "66",
"E": "74"
} | add(add(multiply(divide(60, 3), const_2), const_3), add(divide(60, 3), const_3)) | divide(n0,n1)|add(#0,const_3)|multiply(#0,const_2)|add(#2,const_3)|add(#3,#1) | explanation : a + b = 60 , a = 2 b 2 b + b = 60 = > b = 20 then a = 40 . 3 years , their ages will be 43 and 23 . sum of their ages = 43 + 23 = 66 . d ) | general |
math_qa__rgOHmvnOJo3XFiTp | Two trains 120 m and 190 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? Choose one
A) 10.9 sec B) 11.6 sec C) 10.6 sec D) 10.8 sec E) 20.8 sec | <gadget id="calculator">120 + 190</gadget>
<output>310</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">310 / (250/9)</gadget>
<output>279/25 = around 11.16</output>
<result>B</result> | B | 11.6 | Two trains 120 m and 190 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "10.9 sec",
"B": "11.6 sec",
"C": "10.6 sec",
"D": "10.8 sec",
"E": "20.8 sec"
} | divide(add(120, 190), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 120 + 190 = 310 m . required time = 310 * 9 / 250 = 11.6 = 11.6 sec . answer : b" | physics |
math_qa__vU4gMIrRTbqqI43K | krishan and nandan jointly started a business . krishan invested 4 times as nandan did and invested his money for trible time as compared to nandan . if the gain is proportional to the money invested and the time for which the money is invested and the total gain was rs . 26000 , find the nandan ' s earning .
Choose the correct option
A) 4000 B) 1000 C) 5000 D) 3000 E) 2000 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 1</gadget>
<output>13</output>
<gadget id="calculator">26_000 / 13</gadget>
<output>2_000</output>
<result>E</result> | E | 2,000 | krishan and nandan jointly started a business . krishan invested 4 times as nandan did and invested his money for trible time as compared to nandan . if the gain is proportional to the money invested and the time for which the money is invested and the total gain was rs . 26000 , find the nandan ' s earning . | {
"A": "4000",
"B": "1000",
"C": "5000",
"D": "3000",
"E": "2000"
} | divide(26000, add(multiply(const_3, const_4), const_1)) | multiply(const_3,const_4)|add(#0,const_1)|divide(n1,#1) | 4 : 1 3 : 1 - - - - - - 12 : 1 13 - - - - - rs . 26000 1 - - - - - ? = > rs . 26000 / 13 = rs . 2000 answer : e | gain |
math_qa__K7oztCWDCMbAjwkm | Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 2/7 and that of Ravi is 1/5. Find the probability that both of them are selected.
Choices:
A) 2 / 35
B) 2 / 3
C) 7 / 35
D) 5 / 7
E) 7 / 5 | <gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(2/7) * (1/5)</gadget>
<output>2/35 = around 0.057143</output>
<result>A</result> | A | 0.057143 | Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 2/7 and that of Ravi is 1/5. Find the probability that both of them are selected. | {
"A": "2 / 35",
"B": "2 / 3",
"C": "7 / 35",
"D": "5 / 7",
"E": "7 / 5"
} | multiply(divide(2, 7), divide(1, 5)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)| | "let a be the event that ram is selected and b is the event that ravi is selected . p ( a ) = 2 / 7 p ( b ) = 1 / 5 let c be the event that both are selected . p ( c ) = p ( a ) x p ( b ) as a and b are independent events : = 2 / 7 x 1 / 5 = 2 / 35 answer : a" | general |
math_qa__rqYnFqf249GF4JIy | A cricket bat is sold for $900, making a profit of $75. The profit percentage would be
Choose the correct choice from the following
A) 9 % B) 12 % C) 10 % D) 36 % E) 40 % | <gadget id="calculator">900 - 75</gadget>
<output>825</output>
<gadget id="calculator">75 / 825</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/11) * 100</gadget>
<output>100/11 = around 9.090909</output>
<result>A</result> | A | 9 | A cricket bat is sold for $900, making a profit of $75. The profit percentage would be | {
"A": "9 %",
"B": "12 %",
"C": "10 %",
"D": "36 %",
"E": "40 %"
} | multiply(divide(75, subtract(900, 75)), const_100) | subtract(n0,n1)|divide(n1,#0)|multiply(#1,const_100)| | "75 / ( 900 - 75 ) = 75 / 825 = 0.9 bit more than 9 % . answer : a" | gain |
math_qa__V4kUfInA1IOfVxxh | If 4^(2x + 2) = 16^(3x − 1), what is the value of x ? Choose the correct choice
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">4 / 4</gadget>
<output>1</output>
<result>B</result> | B | 1 | If 4^(2x + 2) = 16^(3x − 1), what is the value of x ? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | divide(4, add(2, 2)) | add(n1,n1)|divide(n0,#0) | 2 ^ ( 4 x + 4 ) = 2 ^ ( 12 x - 4 ) 4 x + 4 = 12 x − 4 x = 1 answer b | general |
math_qa__maQMrGGhEAs9wSrF | You collect pens. Suppose you start out with 25. Mike gives you another 22 pens. Since her father makes pens, Cindy decides to double your pens. Since you're nice, you give Sharon 19 pens. How many pens do you have at the end?
Choices:
A) 39 B) 40 C) 41 D) 75 E) 43 | <gadget id="calculator">22 + 25</gadget>
<output>47</output>
<gadget id="calculator">47 * 2</gadget>
<output>94</output>
<gadget id="calculator">94 - 19</gadget>
<output>75</output>
<result>D</result> | D | 75 | You collect pens. Suppose you start out with 25. Mike gives you another 22 pens. Since her father makes pens, Cindy decides to double your pens. Since you're nice, you give Sharon 19 pens. How many pens do you have at the end? | {
"A": "39",
"B": "40",
"C": "41",
"D": "75",
"E": "43"
} | subtract(multiply(add(22, 25), const_2), 19) | add(n0,n1)|multiply(#0,const_2)|subtract(#1,n2)| | "solution start with 25 pens . mike gives you 22 pens : 25 + 22 = 47 pens . cindy doubles the number of pens you have : 47 ã — 2 = 94 pens . sharon takes 19 pens from you : 94 - 19 = 75 pens . so you have 75 at the end . correct answer : d" | general |
math_qa__e1AbPyRNNxL3IBYw | In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of the sport formulation contains 1 ounces of corn syrup, how many ounces of water does it contain? Select the correct option
A) 15 B) 30 C) 45 D) 60 E) 90 | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 3</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) / 2</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/4) / (1/60)</gadget>
<output>15</output>
<gadget id="calculator">15 * 1</gadget>
<output>15</output>
<result>A</result> | A | 15 | In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of the sport formulation contains 1 ounces of corn syrup, how many ounces of water does it contain? | {
"A": "15",
"B": "30",
"C": "45",
"D": "60",
"E": "90"
} | multiply(divide(multiply(divide(1, 12), const_3), divide(divide(1, 30), const_2)), 1) | divide(n0,n1)|divide(n0,n2)|divide(#1,const_2)|multiply(#0,const_3)|divide(#3,#2)|multiply(n3,#4)| | "standard : fl : corn s : water = 1 : 12 : 30 sport : fl : corn s : water = 3 : 12 : 180 this simplifies to 1 : 4 : 60 if the large bottle has a capacity of x ounces , then 4 x / 65 = 1 . so , x = 65 / 4 ounces . water = ( 60 / 65 ) * ( 65 / 4 ) = 15 ounces . ans a" | other |
math_qa__NVvpDzTN7xNEDchU | In a certain animal shelter, the ratio of the number of dogs to the number of cats is 15 to 7. If 8 additional cats were to be taken in by the shelter, the ratio of the number of dogs to the number of cats would be 15 to 11. How many dogs are in the shelter?
Choose the most appropriate option:
A) 15 B) 25 C) 30 D) 45 E) 60 | <gadget id="calculator">7 * 8</gadget>
<output>56</output>
<gadget id="calculator">11 - 7</gadget>
<output>4</output>
<gadget id="calculator">56 / 4</gadget>
<output>14</output>
<gadget id="calculator">14 / 7</gadget>
<output>2</output>
<gadget id="calculator">2 * 15</gadget>
<output>30</output>
<result>C</result> | C | 30 | In a certain animal shelter, the ratio of the number of dogs to the number of cats is 15 to 7. If 8 additional cats were to be taken in by the shelter, the ratio of the number of dogs to the number of cats would be 15 to 11. How many dogs are in the shelter? | {
"A": "15",
"B": "25",
"C": "30",
"D": "45",
"E": "60"
} | multiply(divide(divide(multiply(7, 8), subtract(11, 7)), 7), 15) | multiply(n1,n2)|subtract(n4,n1)|divide(#0,#1)|divide(#2,n1)|multiply(n0,#3)| | "this ratio question can be solved in a couple of different ways . here ' s an algebraic approach . . . we ' re told that the ratio of the number of dogs to the number of cats is 15 : 7 . we ' re then told that 8 more cats are added to this group and the ratio becomes 15 : 11 . we ' re asked for the number of dogs . algebraically , since the number of dogs is a multiple of 15 and the number of cats is a multiple of 7 , we can write this initial relationship as . . . 15 x / 7 x when we add the 18 cats and factor in the ' ending ratio ' , we have an equation . . . . 15 x / ( 7 x + 8 ) = 15 / 11 here we have 1 variable and 1 equation , so we can solve for x . . . . ( 15 x ) ( 11 ) = ( 7 x + 8 ) ( 15 ) ( x ) ( 11 ) = ( 7 x + 8 ) ( 1 ) 11 x = 7 x + 8 4 x = 8 x = 2 with this x , we can figure out the initial number of dogs and cats . . . initial dogs = 15 x = 15 ( 2 ) = 30 final answer : c" | other |
math_qa__Gjq5Gwv1fIFwb7Wy | the number 523 fbc is divisible by 7 , 89 . then what is the value of f * b * c Choose the correct choice from the following options: A) 504 B) 532 C) 210 D) 180 E) 280 | <gadget id="calculator">523 / 4</gadget>
<output>523/4 = around 130.75</output>
<gadget id="calculator">(523/4) + (523/4)</gadget>
<output>523/2 = around 261.5</output>
<gadget id="calculator">(523/2) / 2</gadget>
<output>523/4 = around 130.75</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">(523/4) + 50</gadget>
<output>723/4 = around 180.75</output>
<result>D</result> | D | 180 | the number 523 fbc is divisible by 7 , 89 . then what is the value of f * b * c | {
"A": "504",
"B": "532",
"C": "210",
"D": "180",
"E": "280"
} | add(divide(add(divide(523, const_4), divide(523, const_4)), const_2), multiply(add(const_4, const_1), const_10)) | add(const_1,const_4)|divide(n0,const_4)|add(#1,#1)|multiply(#0,const_10)|divide(#2,const_2)|add(#4,#3) | lcm of 7 , 8 and 9 is 504 , thus 523 fbc must be divisible by 504 . 523 fbc = 523000 + fbc 523000 divided by 504 gives a remainder of 352 . hence , 352 + fbc = k * 504 . k = 1 fbc = 152 - - > f * b * c = 10 k = 2 fbc = 656 - - > f * b * c = 180 as fbc is three digit number k can not be more than 2 . two answers ? well only one is listed in answer choices , so d . answer : d . | general |
math_qa__7tV06QQLJVNsOI8R | The toll T, in dollars, for a truck using a certain bridge is given by the formula T = 1.50 + 0.50( x − 2), where x is the number of axles on the truck. What is the toll for an 18-wheel truck that has 2 wheels on its front axle and 2 wheels on each of its other axles?
Choices
A) $ 2.50 B) $ 3.00 C) $ 3.50 D) $ 4.00 E) $ 5.00 | <gadget id="calculator">18 - 2</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">0.5 * 7</gadget>
<output>3.5</output>
<gadget id="calculator">1.5 + 3.5</gadget>
<output>5</output>
<result>E</result> | E | 5 | The toll T, in dollars, for a truck using a certain bridge is given by the formula T = 1.50 + 0.50( x − 2), where x is the number of axles on the truck. What is the toll for an 18-wheel truck that has 2 wheels on its front axle and 2 wheels on each of its other axles? | {
"A": "$ 2.50",
"B": "$ 3.00",
"C": "$ 3.50",
"D": "$ 4.00",
"E": "$ 5.00"
} | add(1.50, multiply(0.50, subtract(add(divide(subtract(18, 2), 2), const_1), 2))) | subtract(n3,n2)|divide(#0,n5)|add(#1,const_1)|subtract(#2,n2)|multiply(n1,#3)|add(n0,#4)| | "number of wheels in truck = 18 number of wheels on its front axle = 2 number of wheels remaining = 16 number of axles remaining axles = 16 / 2 = 8 total number of axles = 9 t = 1.50 + 0.50 ( 9 − 2 ) = 1.50 + . 5 * 7 = 1.5 + 1.5 = 5 $ answer e" | general |
math_qa__N3DZqPbwGf7zPGLi | Indu gave Bindu Rs.5000 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest? Choose the most appropriate option:
A) 8 B) 2 C) 9 D) 5 E) 1 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">5_000 * (676/625)</gadget>
<output>5_408</output>
<gadget id="calculator">5_408 - 5_000</gadget>
<output>408</output>
<gadget id="calculator">5_000 * (1/25)</gadget>
<output>200</output>
<gadget id="calculator">200 * 2</gadget>
<output>400</output>
<gadget id="calculator">408 - 400</gadget>
<output>8</output>
<result>A</result> | A | 8 | Indu gave Bindu Rs.5000 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest? | {
"A": "8",
"B": "2",
"C": "9",
"D": "5",
"E": "1"
} | subtract(subtract(multiply(5000, power(add(const_1, divide(4, const_100)), 2)), 5000), multiply(multiply(5000, divide(4, const_100)), 2)) | divide(n2,const_100)|add(#0,const_1)|multiply(n0,#0)|multiply(n1,#2)|power(#1,n1)|multiply(n0,#4)|subtract(#5,n0)|subtract(#6,#3)| | "5000 = d ( 100 / 4 ) 2 d = 8 answer : a" | gain |
math_qa__pQ705gJTWr8NqZHV | A man walking at a rate of 10km/hr crosses a bridge in 3 minutes. The length of the bridge is?
Choose the most appropriate option: A) 500 B) 650 C) 250 D) 111 E) 236 | <gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 60</gadget>
<output>500/3 = around 166.666667</output>
<gadget id="calculator">(500/3) * 3</gadget>
<output>500</output>
<result>A</result> | A | 500 | A man walking at a rate of 10km/hr crosses a bridge in 3 minutes. The length of the bridge is? | {
"A": "500",
"B": "650",
"C": "250",
"D": "111",
"E": "236"
} | multiply(divide(multiply(10, const_1000), const_60), 3) | multiply(n0,const_1000)|divide(#0,const_60)|multiply(n1,#1)| | "speed = 10 * 5 / 18 = 50 / 18 m / sec distance covered in 5 minutes = 50 / 18 * 5 * 60 = 500 m answer is a" | gain |
math_qa__jOuZIg8AWwJmvzj1 | How many paying stones, each measuring 3 * 2 m are required to pave a rectangular court yard 15 m long and 6 m board?
Choices: A) 99 B) 18 C) 26 D) 15 E) 12 | <gadget id="calculator">15 * 6</gadget>
<output>90</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">90 / 6</gadget>
<output>15</output>
<result>D</result> | D | 15 | How many paying stones, each measuring 3 * 2 m are required to pave a rectangular court yard 15 m long and 6 m board? | {
"A": "99",
"B": "18",
"C": "26",
"D": "15",
"E": "12"
} | divide(rectangle_area(15, 6), rectangle_area(3, 2)) | rectangle_area(n2,n3)|rectangle_area(n0,n1)|divide(#0,#1)| | "15 * 6 = 3 * 2 * x = > x = 15 answer : d" | physics |
math_qa__CBA5nRIrMqhqnAcO | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction W of the total distance did he cover while the sun was shining on him? Choose the correct choice from the following choices
A) 1 / 4
B) 4 / 5
C) 1 / 5
D) 1 / 6
E) 1 / 7 | <gadget id="calculator">lcm(2, 3)</gadget>
<output>6</output>
<gadget id="calculator">6 / 2.8</gadget>
<output>2.142857</output>
<gadget id="calculator">2.142857 - 2</gadget>
<output>0.142857</output>
<result>E</result> | E | 0.142857 | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction W of the total distance did he cover while the sun was shining on him? | {
"A": "1 / 4",
"B": "4 / 5",
"C": "1 / 5",
"D": "1 / 6",
"E": "1 / 7"
} | subtract(divide(lcm(const_2, const_3), 2.8), const_2) | lcm(const_2,const_3)|divide(#0,n1)|subtract(#1,const_2)| | if s is an integer and we know that the average speed is 2.8 , s must be = 2 . that meanss + 1 = 3 . this implies that the ratio of time for s = 2 is 1 / 4 of the total time . the formula for distance / rate is d = rt . . . so the distance travelled when s = 2 is 2 t . the distance travelled for s + 1 = 3 is 3 * 4 t or 12 t . therefore , total distance covered while the sun was shining over him is w = 2 / 14 = 1 / 7 . answer : e | general |
math_qa__vHLROFzjP3j2KbLk | What number has a 15:1 ratio to the number 10? Choose the correct choice from the following answers:
A) 130 B) 100 C) 200 D) 150 E) 120 | <gadget id="calculator">10 * 15</gadget>
<output>150</output>
<result>D</result> | D | 150 | What number has a 15:1 ratio to the number 10? | {
"A": "130",
"B": "100",
"C": "200",
"D": "150",
"E": "120"
} | multiply(10, 15) | multiply(n0,n2)| | "15 : 1 = x : 10 x = 10 * 15 x = 150 answer : d" | other |
math_qa__YPGepVAqG5OFLoh6 | The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 17 terms of the arithmetic progression? Choices:
A) 300 B) 120 C) 150 D) 170 E) 270 | <gadget id="calculator">20 * 17</gadget>
<output>340</output>
<gadget id="calculator">340 / 2</gadget>
<output>170</output>
<result>D</result> | D | 170 | The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 17 terms of the arithmetic progression? | {
"A": "300",
"B": "120",
"C": "150",
"D": "170",
"E": "270"
} | divide(multiply(20, 17), const_2) | multiply(n0,n1)|divide(#0,const_2)| | "n th term of a . p . is given by a + ( n - 1 ) d 4 th term = a + 3 d 12 th term = a + 11 d given a + 3 d + a + 11 d = 20 - - > 2 a + 14 d = 20 - - > a + 7 d = 10 sum of n term of a . p = n / 2 [ 2 a + ( n - 1 ) d ] subsitiuing n = 17 . . . we get 17 / 2 [ 2 a + 14 d ] = 17 [ a + 7 d ] = 17 * 10 = 170 . . . answer is d . . ." | general |
math_qa__Uiqv1UYviG76cJsE | A cab driver 5days income was $400, $250, $650, $400 , $500. Then his average income is?
Choose one.
A) $ 400
B) $ 420
C) $ 440
D) $ 460
E) $ 480 | <gadget id="calculator">400 + 250</gadget>
<output>650</output>
<gadget id="calculator">650 + 650</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 + 400</gadget>
<output>1_700</output>
<gadget id="calculator">1_700 + 500</gadget>
<output>2_200</output>
<gadget id="calculator">2_200 / 5</gadget>
<output>440</output>
<result>C</result> | C | 440 | A cab driver 5days income was $400, $250, $650, $400 , $500. Then his average income is? | {
"A": "$ 400",
"B": "$ 420",
"C": "$ 440",
"D": "$ 460",
"E": "$ 480"
} | divide(add(add(add(add(400, 250), 650), 400), 500), 5) | add(n1,n2)|add(n3,#0)|add(n4,#1)|add(n5,#2)|divide(#3,n0)| | "avg = sum of observations / number of observations avg income = ( 400 + 250 + 650 + 400 + 500 ) / 5 = 440 answer is c" | general |
math_qa__v5hMLMgQetiiVKdv | The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 540. What is the banker's discount?
Choose the correct choice from the following options.
A) 1240 B) 1120 C) 1190 D) 1290 E) none of these | <gadget id="calculator">540 * 100</gadget>
<output>54_000</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<gadget id="calculator">54_000 / 72</gadget>
<output>750</output>
<gadget id="calculator">540 + 750</gadget>
<output>1_290</output>
<result>D</result> | D | 1,290 | The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 540. What is the banker's discount? | {
"A": "1240",
"B": "1120",
"C": "1190",
"D": "1290",
"E": "none of these"
} | add(540, divide(multiply(540, const_100), multiply(12, 6))) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2)| | "explanation : td = ( bg × 100 ) / tr = ( 540 × 100 ) / ( 6 × 12 ) = ( 90 × 100 ) / 12 = ( 15 × 100 ) 2 / = rs . 750 bg = bd – td = > 540 = bd - 750 = > bd = 540 + 750 = 1290 answer : option d" | gain |
math_qa__DWsZy5Kn1b6CMBod | If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 246 m, what is its area?
Answers:
A) 2510 B) 3650 C) 2530 D) 2515 E) 2520 | <gadget id="calculator">2 * 23</gadget>
<output>46</output>
<gadget id="calculator">246 - 46</gadget>
<output>200</output>
<gadget id="calculator">200 / 4</gadget>
<output>50</output>
<gadget id="calculator">50 + 23</gadget>
<output>73</output>
<gadget id="calculator">73 * 50</gadget>
<output>3_650</output>
<result>B</result> | B | 3,650 | If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 246 m, what is its area? | {
"A": "2510",
"B": "3650",
"C": "2530",
"D": "2515",
"E": "2520"
} | rectangle_area(add(divide(subtract(246, multiply(const_2, 23)), const_4), 23), divide(subtract(246, multiply(const_2, 23)), const_4)) | multiply(n0,const_2)|subtract(n1,#0)|divide(#1,const_4)|add(n0,#2)|rectangle_area(#3,#2)| | "length = breadth + 23 . therefore , 4 × breadth + 2 × 23 = 246 m ⇒ breadth = 50 m length = 50 + 23 = 73 m area = 73 × 50 = 3650 m 2 answer is b ." | geometry |
math_qa__uzKm7Cik6pmZrMWX | A and B can together finish a work in 30days. They worked together for 20days and then B left. After another 20days, A finished the remaining work. In how many days A alone can finish the job?
Choose one: A) 40 B) 50 C) 54 D) 60 E) none of these | <gadget id="calculator">20 * 30</gadget>
<output>600</output>
<gadget id="calculator">30 - 20</gadget>
<output>10</output>
<gadget id="calculator">600 / 10</gadget>
<output>60</output>
<result>D</result> | D | 60 | A and B can together finish a work in 30days. They worked together for 20days and then B left. After another 20days, A finished the remaining work. In how many days A alone can finish the job? | {
"A": "40",
"B": "50",
"C": "54",
"D": "60",
"E": "none of these"
} | divide(multiply(20, 30), subtract(30, 20)) | multiply(n0,n2)|subtract(n0,n1)|divide(#0,#1)| | "( a + b ) ' s 20 days work = ( 1 / 30 * 20 ) = 2 / 3 . remaining work = ( 1 - 2 / 3 ) = 1 / 3 . now , 1 / 3 work is done by a in 20 days . whole work will be done by a in ( 20 * 3 ) = 60 days . correct option : d" | physics |
math_qa__nQvjJdekHwlD7SZD | How many numbers between 190 and 580 are divisible by 4,5 and 6? Select
A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">lcm(4, 5)</gadget>
<output>20</output>
<gadget id="calculator">lcm(20, 6)</gadget>
<output>60</output>
<gadget id="calculator">580 / 60</gadget>
<output>29/3 = around 9.666667</output>
<gadget id="calculator">floor(29/3)</gadget>
<output>9</output>
<gadget id="calculator">190 / 60</gadget>
<output>19/6 = around 3.166667</output>
<gadget id="calculator">floor(19/6)</gadget>
<output>3</output>
<gadget id="calculator">9 - 3</gadget>
<output>6</output>
<result>A</result> | A | 6 | How many numbers between 190 and 580 are divisible by 4,5 and 6? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | subtract(floor(divide(580, lcm(lcm(const_4, add(const_4, const_1)), 6))), floor(divide(190, lcm(lcm(const_4, add(const_4, const_1)), 6)))) | add(const_1,const_4)|lcm(#0,const_4)|lcm(n3,#1)|divide(n1,#2)|divide(n0,#2)|floor(#3)|floor(#4)|subtract(#5,#6) | every such number must be divisible by l . c . m of 4 , 5,6 i . e , 60 . such numbers are 240,300 , 360,420 , 480,540 . clearly , there are 6 such numbers answer : a | general |
math_qa__bhLhv3QdlMjq6lcJ | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 24 sec. What is the length of the platform? Pick
A) 389 m B) 350 m C) 187.5 m D) 299 m E) 219.5 m | <gadget id="calculator">300 / 24</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 39</gadget>
<output>975/2 = around 487.5</output>
<gadget id="calculator">(975/2) - 300</gadget>
<output>375/2 = around 187.5</output>
<result>C</result> | C | 187.5 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 24 sec. What is the length of the platform? | {
"A": "389 m",
"B": "350 m",
"C": "187.5 m",
"D": "299 m",
"E": "219.5 m"
} | subtract(multiply(speed(300, 24), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 24 = 25 / 2 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 25 / 2 = > x = 187.5 m . answer : c" | physics |
math_qa__MVFAcQvHvJxjGHPr | What percent is 3% of 5% ? Choose the most appropriate option: A) 60 % B) 50 % C) 75 % D) 45 % E) 30 % | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>A</result> | A | 60 | What percent is 3% of 5% ? | {
"A": "60 %",
"B": "50 %",
"C": "75 %",
"D": "45 %",
"E": "30 %"
} | multiply(divide(3, 5), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "required percentage = 3 % / 5 % * 100 = 3 / 5 * 100 = 60 % answer is a" | gain |
math_qa__IDcDiPpVh96h0lyv | Perimeter of an equilateral and isosceles is 45 and 40 respectively. At least one of the sides of isosceles is equal to the equilateral. What's the base of isosceles triangle? Pick one
A) 7 B) 8 C) 9 D) 10 E) 11 | <gadget id="calculator">45 / 3</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
<result>D</result> | D | 10 | Perimeter of an equilateral and isosceles is 45 and 40 respectively. At least one of the sides of isosceles is equal to the equilateral. What's the base of isosceles triangle? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | subtract(40, multiply(divide(45, const_3), const_2)) | divide(n0,const_3)|multiply(#0,const_2)|subtract(n1,#1) | 10 units as other 2 sides will be 15,15 units . answer : d | geometry |
math_qa__y1kQMYiEqDH0951w | Kamal obtained 76, 60, 82, 67 and 85 marks(out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? Choose the correct choice from the following choices
A) 65 B) 69 C) 74 D) 75 E) none | <gadget id="calculator">76 + 60</gadget>
<output>136</output>
<gadget id="calculator">136 + 82</gadget>
<output>218</output>
<gadget id="calculator">218 + 67</gadget>
<output>285</output>
<gadget id="calculator">285 + 85</gadget>
<output>370</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">370 / 5</gadget>
<output>74</output>
<result>C</result> | C | 74 | Kamal obtained 76, 60, 82, 67 and 85 marks(out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? | {
"A": "65",
"B": "69",
"C": "74",
"D": "75",
"E": "none"
} | divide(add(add(add(add(76, 60), 82), 67), 85), add(const_1, const_4)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "sol . average = 76 + 60 + 82 + 67 + 85 / 5 ) = ( 375 / 5 ) = 74 . answer c" | general |
math_qa__fmUrKyhEaOrNEJqZ | If 12 men and 16 boys can do a piece of work in 5 days and 13 men together will 24 boys can do it in 4 days. Compare the daily work done by a man with that of a boy.
Choices: A) 2 : 9 B) 2 : 1 C) 2 : 7 D) 2 : 5 E) 2 : 2 | <gadget id="calculator">4 * 24</gadget>
<output>96</output>
<gadget id="calculator">5 * 16</gadget>
<output>80</output>
<gadget id="calculator">96 - 80</gadget>
<output>16</output>
<gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">4 * 13</gadget>
<output>52</output>
<gadget id="calculator">60 - 52</gadget>
<output>8</output>
<gadget id="calculator">16 / 8</gadget>
<output>2</output>
<result>B</result> | B | 2 | If 12 men and 16 boys can do a piece of work in 5 days and 13 men together will 24 boys can do it in 4 days. Compare the daily work done by a man with that of a boy. | {
"A": "2 : 9",
"B": "2 : 1",
"C": "2 : 7",
"D": "2 : 5",
"E": "2 : 2"
} | divide(subtract(multiply(4, 24), multiply(5, 16)), subtract(multiply(5, 12), multiply(4, 13))) | multiply(n4,n5)|multiply(n1,n2)|multiply(n0,n2)|multiply(n3,n5)|subtract(#0,#1)|subtract(#2,#3)|divide(#4,#5)| | "12 m + 16 b - - - - - 5 days 13 m + 24 b - - - - - - - 4 days 60 m + 80 b = 52 m + 96 b 8 m = 16 b = > 1 m = 2 b m : b = 2 : 1 answer : b" | physics |
math_qa__wHUabSitfZXb6ueS | The probability that a number selected at random from the first 50 natural numbers is a composite number is ?
Choose one:
A) 17 / 65 B) 17 / 25 C) 17 / 28 D) 17 / 65 E) 17 / 39 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 - 1</gadget>
<output>17</output>
<gadget id="calculator">17 * 2</gadget>
<output>34</output>
<gadget id="calculator">34 / 50</gadget>
<output>17/25 = around 0.68</output>
<result>B</result> | B | 0.68 | The probability that a number selected at random from the first 50 natural numbers is a composite number is ? | {
"A": "17 / 65",
"B": "17 / 25",
"C": "17 / 28",
"D": "17 / 65",
"E": "17 / 39"
} | divide(multiply(subtract(multiply(const_6, const_3), const_1), const_2), 50) | multiply(const_3,const_6)|subtract(#0,const_1)|multiply(#1,const_2)|divide(#2,n0)| | "the number of exhaustive events = ⁵ ⁰ c ₁ = 50 . we have 15 primes from 1 to 50 . number of favourable cases are 34 . required probability = 34 / 50 = 17 / 25 . answer : b" | probability |
math_qa__yjl5DgBwjliJzOKA | If x : y = 4 : 7, find the value of (6x + 2y) : (5x – y) Choose the correct option:
A) 7 : 13 B) 38 : 7 C) 3 : 13 D) 2 : 3 E) 38 : 13 | <gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">36 + 2</gadget>
<output>38</output>
<gadget id="calculator">4 + 7</gadget>
<output>11</output>
<gadget id="calculator">11 + 2</gadget>
<output>13</output>
<gadget id="calculator">38 / 13</gadget>
<output>38/13 = around 2.923077</output>
<result>E</result> | E | 2.923077 | If x : y = 4 : 7, find the value of (6x + 2y) : (5x – y) | {
"A": "7 : 13",
"B": "38 : 7",
"C": "3 : 13",
"D": "2 : 3",
"E": "38 : 13"
} | divide(add(power(6, 2), 2), add(add(4, 7), 2)) | add(n0,n1)|power(n2,n3)|add(n3,#1)|add(n3,#0)|divide(#2,#3) | explanation : given : x / y = 4 / 7 ( 6 x + 2 y ) : ( 5 x – y ) = ( 6 * 4 + 2 * 7 ) : ( 5 * 4 – 7 ) 38 : 13 answer : e | general |
math_qa__7a8KrEg8Pv26YCaR | If x+y=14, x-y=60, for integers of x and y, x=? Choose the correct answer
A) 37 B) 35 C) 25 D) 20 E) 42 | <gadget id="calculator">14 + 60</gadget>
<output>74</output>
<gadget id="calculator">74 / 2</gadget>
<output>37</output>
<result>A</result> | A | 37 | If x+y=14, x-y=60, for integers of x and y, x=? | {
"A": "37",
"B": "35",
"C": "25",
"D": "20",
"E": "42"
} | divide(add(14, 60), const_2) | add(n0,n1)|divide(#0,const_2)| | "x + y = 14 x - y = 60 2 x = 74 x = 37 answer is a" | general |
math_qa__Ep4SCEsMZB4SuHoD | If in a race of 100m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by:
Select
A) 20 m B) 16 m C) 11 m D) 10 m E) 15 m | <gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">5 / 25</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>A</result> | A | 20 | If in a race of 100m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by: | {
"A": "20 m",
"B": "16 m",
"C": "11 m",
"D": "10 m",
"E": "15 m"
} | multiply(divide(subtract(25, 20), 25), 100) | subtract(n2,n1)|divide(#0,n2)|multiply(n0,#1)| | "explanation : the difference in the timing of a and b is 5 seconds . hence , a beats b by 5 seconds . the distance covered by b in 5 seconds = ( 100 * 5 ) / 25 = 20 m hence , a beats b by 20 m . answer a" | physics |
math_qa__pODN2n3mHgBb5e6f | The speed of a car is 90 km in the first hour and 30 km in the second hour. What is the average speed of the car?
Pick one:
A) 50 kmph
B) 60 kmph
C) 75 kmph
D) 85 kmph
E) 90 kmph | <gadget id="calculator">90 + 30</gadget>
<output>120</output>
<gadget id="calculator">120 / 2</gadget>
<output>60</output>
<result>B</result> | B | 60 | The speed of a car is 90 km in the first hour and 30 km in the second hour. What is the average speed of the car? | {
"A": "50 kmph",
"B": "60 kmph",
"C": "75 kmph",
"D": "85 kmph",
"E": "90 kmph"
} | divide(add(90, 30), const_2) | add(n0,n1)|divide(#0,const_2)| | "explanation : s = ( 90 + 30 ) / 2 = 60 kmph b )" | physics |
math_qa__6mlWcvuXhYkC6IXD | The speed of a boat in still water in 65 km/hr and the rate of current is 15 km/hr. The distance travelled downstream in 25 minutes is: Choose the correct choice from the following choices.
A) 55.55 km
B) 44.44 km
C) 33.33 km
D) 22.22 km
E) 11.11 km | <gadget id="calculator">65 + 15</gadget>
<output>80</output>
<gadget id="calculator">25 / 60</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">80 * (5/12)</gadget>
<output>100/3 = around 33.333333</output>
<result>C</result> | C | 33.33 | The speed of a boat in still water in 65 km/hr and the rate of current is 15 km/hr. The distance travelled downstream in 25 minutes is: | {
"A": "55.55 km",
"B": "44.44 km",
"C": "33.33 km",
"D": "22.22 km",
"E": "11.11 km"
} | multiply(add(65, 15), divide(25, const_60)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "explanation : speed downstream = ( 65 + 15 ) = 80 kmph time = 25 minutes = 25 / 60 hour = 5 / 12 hour distance travelled = time × speed = ( 2 / 5 ) × 80 = 33.33 km answer : option c" | physics |
math_qa__PGdRorEoJNRl056v | (√27+√243)/√48=? Options
A) 2 √ 2
B) 2 √ 3
C) 3 √ 2
D) 3 √ 3
E) 3 | <gadget id="calculator">27 ** (1/2)</gadget>
<output>3*sqrt(3) = around 5.196152</output>
<gadget id="calculator">243 ** (1/2)</gadget>
<output>9*sqrt(3) = around 15.588457</output>
<gadget id="calculator">(3*sqrt(3)) + (9*sqrt(3))</gadget>
<output>12*sqrt(3) = around 20.78461</output>
<gadget id="calculator">48 ** (1/2)</gadget>
<output>4*sqrt(3) = around 6.928203</output>
<gadget id="calculator">(12*sqrt(3)) / (4*sqrt(3))</gadget>
<output>3</output>
<result>E</result> | E | 3 | (√27+√243)/√48=? | {
"A": "2 √ 2",
"B": "2 √ 3",
"C": "3 √ 2",
"D": "3 √ 3",
"E": "3"
} | divide(add(sqrt(27), sqrt(243)), sqrt(48)) | sqrt(n0)|sqrt(n1)|sqrt(n2)|add(#0,#1)|divide(#3,#2)| | "( √ 27 + √ 243 ) / √ 48 = ( 3 √ 3 + 9 √ 3 ) / 4 √ 3 = 12 √ 3 / 4 √ 3 = 3 . hence , the correct answer is e ." | general |
math_qa__1mb7cGCCkiyru51G | Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is? Pick one.
A) 2887 B) 444 C) 877 D) 278 E) 178 | <gadget id="calculator">21 - 16</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">12 * 16</gadget>
<output>192</output>
<gadget id="calculator">12 * 21</gadget>
<output>252</output>
<gadget id="calculator">192 + 252</gadget>
<output>444</output>
<result>B</result> | B | 444 | Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is? | {
"A": "2887",
"B": "444",
"C": "877",
"D": "278",
"E": "178"
} | add(multiply(divide(60, subtract(21, 16)), 16), multiply(divide(60, subtract(21, 16)), 21)) | subtract(n1,n0)|divide(n2,#0)|multiply(n0,#1)|multiply(n1,#1)|add(#2,#3)| | "1 h - - - - - 5 ? - - - - - - 60 12 h rs = 16 + 21 = 37 t = 12 d = 37 * 12 = 444 answer : b" | physics |
math_qa__KoM3gILnrFW4Q4PV | The volume of a cube is 1728 cc. Find its surface? Choose one: A) 864 B) 209 C) 278 D) 276 E) 280 | <gadget id="calculator">1_728 ** (1/3)</gadget>
<output>12</output>
<gadget id="calculator">6 * (12 ** 2)</gadget>
<output>864</output>
<result>A</result> | A | 864 | The volume of a cube is 1728 cc. Find its surface? | {
"A": "864",
"B": "209",
"C": "278",
"D": "276",
"E": "280"
} | surface_cube(cube_edge_by_volume(1728)) | cube_edge_by_volume(n0)|surface_cube(#0) | a 3 = 1728 = > a = 12 6 a 2 = 6 * 12 * 12 = 864 answer : a | geometry |
math_qa__ubYyLQj1PbuL3NOi | 18 litres of mixture contains 20% alcohol and the rest water. If 3litres of water be mixed with it, the percentage of alcohol in the new mixture would be? Pick one
A) 16.67 %
B) 17.14 %
C) 18.3 %
D) 19.75 %
E) 21.23 % | <gadget id="calculator">18 + 3</gadget>
<output>21</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 18</gadget>
<output>72/5 = around 14.4</output>
<gadget id="calculator">(72/5) + 3</gadget>
<output>87/5 = around 17.4</output>
<gadget id="calculator">21 - (87/5)</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">(18/5) / 21</gadget>
<output>6/35 = around 0.171429</output>
<gadget id="calculator">(6/35) * 100</gadget>
<output>120/7 = around 17.142857</output>
<result>B</result> | B | 17.14 | 18 litres of mixture contains 20% alcohol and the rest water. If 3litres of water be mixed with it, the percentage of alcohol in the new mixture would be? | {
"A": "16.67 %",
"B": "17.14 %",
"C": "18.3 %",
"D": "19.75 %",
"E": "21.23 %"
} | multiply(divide(subtract(add(18, 3), add(multiply(divide(subtract(const_100, 20), const_100), 18), 3)), add(18, 3)), const_100) | add(n0,n2)|subtract(const_100,n1)|divide(#1,const_100)|multiply(n0,#2)|add(n2,#3)|subtract(#0,#4)|divide(#5,#0)|multiply(#6,const_100)| | "alcohol in the 18 litres of mix . = 20 % of 18 litres = ( 20 * 18 / 100 ) = 3.6 litres water in it = 18 - 3.6 = 14.4 litres new quantity of mix . = 18 + 3 = 21 litres quantity of alcohol in it = 3.6 litres percentage of alcohol in new mix . = 3.6 * 100 / 21 = 17.14 % answer is b" | gain |
math_qa__wgFq8eTM6Un1wJzv | Two isosceles Triangles have equal vertical angles and their areas are in the ratio 4:9. Find the ratio of their corresponding heights . Choose the correct answer
A) 4 / 5 B) 5 / 4 C) 3 / 2 D) 5 / 7 E) 2 / 3 | <gadget id="calculator">4 ** (1/2)</gadget>
<output>2</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<result>E</result> | E | 0.666667 | Two isosceles Triangles have equal vertical angles and their areas are in the ratio 4:9. Find the ratio of their corresponding heights . | {
"A": "4 / 5",
"B": "5 / 4",
"C": "3 / 2",
"D": "5 / 7",
"E": "2 / 3"
} | divide(sqrt(const_4), sqrt(9)) | sqrt(const_4)|sqrt(n1)|divide(#0,#1) | we are basically given that the triangles are similar . in two similar triangles , the ratio of their areas is the square of the ratio of their sides and also , the square of the ratio of their corresponding heights . therefore , area / area = height ^ 2 / height ^ 2 = 4 / 9 - - > height / height = 2 / 3 . answer : e . | geometry |
math_qa__0XFr0NxgHMTpK42b | In a certain company, the ratio of male to female employees is 7:8. If 3 more men were hired, this ratio would increase to 8:9. How many male employees are there in the company? Choose the correct option: A) 6 B) 21 C) 27 D) 189 E) 192 | <gadget id="calculator">8 / 9</gadget>
<output>8/9 = around 0.888889</output>
<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">(8/9) - (7/8)</gadget>
<output>1/72 = around 0.013889</output>
<gadget id="calculator">3 / (1/72)</gadget>
<output>216</output>
<gadget id="calculator">216 * 7</gadget>
<output>1_512</output>
<gadget id="calculator">1_512 / 8</gadget>
<output>189</output>
<result>D</result> | D | 189 | In a certain company, the ratio of male to female employees is 7:8. If 3 more men were hired, this ratio would increase to 8:9. How many male employees are there in the company? | {
"A": "6",
"B": "21",
"C": "27",
"D": "189",
"E": "192"
} | divide(multiply(divide(3, subtract(divide(8, 9), divide(7, 8))), 7), 8) | divide(n1,n4)|divide(n0,n1)|subtract(#0,#1)|divide(n2,#2)|multiply(n0,#3)|divide(#4,n1) | another approach is to use two variables . let m = present number of males let f = present number of females the ratio of male to female employees is 7 : 8 so , m / f = 7 / 8 cross multiply to get 7 f = 8 m if 3 more men were hired , this ratio would increase to 8 : 9 so , ( m + 3 ) / f = 8 / 9 cross multiply to get 9 ( m + 3 ) = 8 f expand : 9 m + 27 = 8 f we now have a system of two equations and two variables : 7 f = 8 m 9 m + 27 = 8 f solve to get : m = 189 and f = 216 answer : d | general |
math_qa__jEDFoCKfHldqohJw | a guy was asked to specify his age in years . he said , “ take my age 5 years hence , multiply it by 5 and subtract 5 times of my age 5 years ago and you will know my age . ” what was the age of that guy ?
Choices: A) 18 B) 15 C) 33 D) 39 E) 50 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 + 25</gadget>
<output>50</output>
<result>E</result> | E | 50 | a guy was asked to specify his age in years . he said , “ take my age 5 years hence , multiply it by 5 and subtract 5 times of my age 5 years ago and you will know my age . ” what was the age of that guy ? | {
"A": "18",
"B": "15",
"C": "33",
"D": "39",
"E": "50"
} | add(multiply(5, 5), multiply(5, 5)) | multiply(n0,n0)|add(#0,#0) | current age of the guy = a years . then , 5 ( a + 5 ) – 5 ( a – 5 ) = a ( 5 a + 25 ) – ( 5 a – 25 ) = a a = 50 e | general |
math_qa__JsRmrpUsGhUeL8c5 | Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 17 boys and 43 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad? Select the correct option:
A) 5 B) 4 C) 6 D) 8 E) 10 | <gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">17 - 6</gadget>
<output>11</output>
<gadget id="calculator">11 - 6</gadget>
<output>5</output>
<result>A</result> | A | 5 | Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 17 boys and 43 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad? | {
"A": "5",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | subtract(subtract(17, subtract(10, 4)), 6) | subtract(n2,n7)|subtract(n4,#0)|subtract(#1,n6)| | "venn diagrams are useful for multiple values of a single variable e . g . state of mind - happy / sad / neither . when you have two or more variables such as here where you have gender - boy / girl too , it becomes unwieldy . in this case , either use the table or logic . table method is shown above ; here is how you will use logic : there are 6 happy boys . there are 4 sad girls but total 10 sad children . so rest 6 sad children must be sad boys . we have 6 happy boys and 6 sad boys . total we have 17 boys . so 17 - 6 - 6 = 5 boys must be neither happy nor sad . answer ( a )" | other |
math_qa__3esPZh2wGhB28gQ7 | Ram, who is half as efficient as Krish, will take 27 days to complete a task if he worked alone. If Ram and Krish worked together, how long will they take to complete the task? Choose one
A) 16 days B) 12 days C) 9 days D) 6 days E) 18 days | <gadget id="calculator">1 / 27</gadget>
<output>1/27 = around 0.037037</output>
<gadget id="calculator">27 / 2</gadget>
<output>27/2 = around 13.5</output>
<gadget id="calculator">1 / (27/2)</gadget>
<output>2/27 = around 0.074074</output>
<gadget id="calculator">(1/27) + (2/27)</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">1 / (1/9)</gadget>
<output>9</output>
<result>C</result> | C | 9 | Ram, who is half as efficient as Krish, will take 27 days to complete a task if he worked alone. If Ram and Krish worked together, how long will they take to complete the task? | {
"A": "16 days",
"B": "12 days",
"C": "9 days",
"D": "6 days",
"E": "18 days"
} | inverse(add(divide(const_1, 27), divide(const_1, divide(27, const_2)))) | divide(const_1,n0)|divide(n0,const_2)|divide(const_1,#1)|add(#0,#2)|inverse(#3) | number of days taken by ram to complete task = 27 since ram is half as efficient as krish , amount of work done by krish in 1 day = amount of work done by ram in 2 days if total work done by ram in 27 days is 27 w amount of work done by ram in 1 day = w amount of work done by krish in 1 day = 2 w total amount of work done by krish and ram in a day = 3 w total amount of time needed by krish and ram to complete task = 27 w / 3 w = 9 days answer c | physics |
math_qa__HyqFf8LxjiwaqkLt | Two persons A and B can complete a piece of work in 40 days and 60 days respectively. If they work together, what part of the work will be completed in 6 days?
Choose the correct choice from the following options
A) 1 / 8 B) 1 / 3 C) 1 / 6 D) 1 / 2 E) 1 / 4 | <gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/40) + (1/60)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">6 * (1/24)</gadget>
<output>1/4 = around 0.25</output>
<result>E</result> | E | 0.25 | Two persons A and B can complete a piece of work in 40 days and 60 days respectively. If they work together, what part of the work will be completed in 6 days? | {
"A": "1 / 8",
"B": "1 / 3",
"C": "1 / 6",
"D": "1 / 2",
"E": "1 / 4"
} | multiply(6, add(divide(const_1, 40), divide(const_1, 60))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)| | "a ' s one day ' s work = 1 / 40 b ' s one day ' s work = 1 / 60 ( a + b ) ' s one day ' s work = 1 / 40 + 1 / 60 = 1 / 24 the part of the work completed in 6 days = 6 ( 1 / 24 ) = 1 / 4 . answer : e" | physics |
math_qa__U6SdP6X2dpnvo2Nz | At what price must an article costing Rs.95 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price? Select: A) 130 B) 125 C) 145 D) 135 E) 144 | <gadget id="calculator">95 * 25</gadget>
<output>2_375</output>
<gadget id="calculator">2_375 / 100</gadget>
<output>95/4 = around 23.75</output>
<gadget id="calculator">95 + (95/4)</gadget>
<output>475/4 = around 118.75</output>
<gadget id="calculator">(475/4) * 100</gadget>
<output>11_875</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">11_875 / 95</gadget>
<output>125</output>
<result>B</result> | B | 125 | At what price must an article costing Rs.95 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price? | {
"A": "130",
"B": "125",
"C": "145",
"D": "135",
"E": "144"
} | divide(multiply(add(95, divide(multiply(95, 25), const_100)), const_100), subtract(const_100, 5)) | multiply(n0,n2)|subtract(const_100,n1)|divide(#0,const_100)|add(n0,#2)|multiply(#3,const_100)|divide(#4,#1)| | "cp = 95 sp = 47.50 * ( 125 / 100 ) = 118.125 mp * ( 95 / 100 ) = 118.125 mp = 125 answer : b" | gain |
math_qa__FnW71fqm3phH17az | A person travels from P to Q a speed of 60 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips? Choose one:
A) 33
B) 75
C) 48
D) 99
E) 21 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">60 * (3/2)</gadget>
<output>90</output>
<gadget id="calculator">90 + 60</gadget>
<output>150</output>
<gadget id="calculator">150 / 2</gadget>
<output>75</output>
<result>B</result> | B | 75 | A person travels from P to Q a speed of 60 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips? | {
"A": "33",
"B": "75",
"C": "48",
"D": "99",
"E": "21"
} | divide(add(multiply(60, add(const_1, divide(50, const_100))), 60), const_2) | divide(n1,const_100)|add(#0,const_1)|multiply(n0,#1)|add(n0,#2)|divide(#3,const_2) | speed on return trip = 150 % of 60 = 90 km / hr . average speed of trip = 60 + 90 / 2 = 150 / 2 = 75 km / hr answer : b | general |
math_qa__XbdZQpCMBA0Dyhuk | How much is 85% of 40 is greater than 4/5 of 25? Choose the correct choice from the following choices
A) 22 B) 14 C) 88 D) 12 E) 66 | <gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">40 * (17/20)</gadget>
<output>34</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 25</gadget>
<output>20</output>
<gadget id="calculator">34 - 20</gadget>
<output>14</output>
<result>B</result> | B | 14 | How much is 85% of 40 is greater than 4/5 of 25? | {
"A": "22",
"B": "14",
"C": "88",
"D": "12",
"E": "66"
} | subtract(multiply(40, divide(85, const_100)), multiply(divide(4, 5), 25)) | divide(n0,const_100)|divide(n2,n3)|multiply(n1,#0)|multiply(n4,#1)|subtract(#2,#3)| | "( 85 / 100 ) * 40 – ( 4 / 5 ) * 25 = 14 answer : b" | general |
math_qa__gNk1LRXyNYYKtJZ3 | In a fuel station the service costs $2.10 per vehicle and every liter of fuel costs $0.70. Assuming that you fill up 3 mini-vans and 2 trucks, what will be the total cost, if a mini-van's tank is 65 liters and a truck's tank is 120% bigger and they are all empty? Choose the most appropriate option:
A) $ 338.50
B) $ 341.40
C) $ 344.30
D) $ 347.20
E) $ 350.10 | <gadget id="calculator">120 * 65</gadget>
<output>7_800</output>
<gadget id="calculator">7_800 / 100</gadget>
<output>78</output>
<gadget id="calculator">78 + 65</gadget>
<output>143</output>
<gadget id="calculator">143 * 2</gadget>
<output>286</output>
<gadget id="calculator">286 * 0.7</gadget>
<output>200.2</output>
<gadget id="calculator">3 * 65</gadget>
<output>195</output>
<gadget id="calculator">195 * 0.7</gadget>
<output>136.5</output>
<gadget id="calculator">200.2 + 136.5</gadget>
<output>336.7</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">2.1 * 5</gadget>
<output>10.5</output>
<gadget id="calculator">336.7 + 10.5</gadget>
<output>347.2</output>
<result>D</result> | D | 347.2 | In a fuel station the service costs $2.10 per vehicle and every liter of fuel costs $0.70. Assuming that you fill up 3 mini-vans and 2 trucks, what will be the total cost, if a mini-van's tank is 65 liters and a truck's tank is 120% bigger and they are all empty? | {
"A": "$ 338.50",
"B": "$ 341.40",
"C": "$ 344.30",
"D": "$ 347.20",
"E": "$ 350.10"
} | add(add(multiply(multiply(add(divide(multiply(120, 65), const_100), 65), 2), 0.7), multiply(multiply(3, 65), 0.7)), multiply(2.1, add(3, 2))) | add(n2,n3)|multiply(n4,n5)|multiply(n2,n4)|divide(#1,const_100)|multiply(n1,#2)|multiply(n0,#0)|add(n4,#3)|multiply(n3,#6)|multiply(n1,#7)|add(#8,#4)|add(#9,#5) | the service cost of 3 vans and 2 trucks is 5 * 2.10 $ 10.50 the fuel in 3 vans is 3 * 65 = 195 liters the fuel in 2 trucks is 2 * 65 * 2.2 = 286 liters the total fuel ( vans + trucks ) = 481 liters the total fuel cost is 481 * 0.7 = $ 336.70 the total cost is $ 336.70 + $ 10.50 = $ 347.20 the answer is d . | general |
math_qa__aZHwEnskSxHy6nmi | Following an increase in prices, the price of a candy box was 10 pounds and the price of a can of soda was 15 pounds. If the price of a candy box was raised by 25%, and the price of a can of soda was raised by 50%. What was the price of a box of candy plus a can of soda before prices were raised? Choose the correct answer
A) 11 . B) 12 . C) 13 . D) 18 . E) 14.5 | <gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">1_000 / 125</gadget>
<output>8</output>
<gadget id="calculator">15 * 100</gadget>
<output>1_500</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">1_500 / 150</gadget>
<output>10</output>
<gadget id="calculator">8 + 10</gadget>
<output>18</output>
<result>D</result> | D | 18 | Following an increase in prices, the price of a candy box was 10 pounds and the price of a can of soda was 15 pounds. If the price of a candy box was raised by 25%, and the price of a can of soda was raised by 50%. What was the price of a box of candy plus a can of soda before prices were raised? | {
"A": "11 .",
"B": "12 .",
"C": "13 .",
"D": "18 .",
"E": "14.5"
} | add(divide(multiply(10, const_100), add(const_100, 25)), divide(multiply(15, const_100), add(const_100, 50))) | add(n2,const_100)|add(n3,const_100)|multiply(n0,const_100)|multiply(n1,const_100)|divide(#2,#0)|divide(#3,#1)|add(#4,#5) | price of candy before price increase = 10 / 1.25 = 8 price of soda before price increase = 15 / 1.5 = 10 total price = 8 + 10 = 18 d is the answer | general |
math_qa__LqELhdStN4UX43fg | The population of a bacteria colony doubles every day. If it was started 9 days ago with 2 bacteria and each bacteria lives for 11 days, how large is the colony today? Select the correct option: A) 512 B) 768 C) 4096 D) 2048 E) 1024 | <gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">2 ** 10</gadget>
<output>1_024</output>
<gadget id="calculator">1_024 - 1</gadget>
<output>1_023</output>
<result>E</result> | E | 1,024 | The population of a bacteria colony doubles every day. If it was started 9 days ago with 2 bacteria and each bacteria lives for 11 days, how large is the colony today? | {
"A": "512",
"B": "768",
"C": "4096",
"D": "2048",
"E": "1024"
} | subtract(power(2, add(9, const_1)), const_1) | add(n0,const_1)|power(n1,#0)|subtract(#1,const_1)| | "9 days ago - 2 8 days ago - 4 7 days ago - 8 6 days ago - 16 5 days ago - 32 4 days ago - 64 3 days ago - 128 2 days ago - 256 yesterday - 512 today - 1024 ans : e" | physics |
math_qa__IXm9Roc4qaNB9dhE | In how many ways can an answer key for a quiz be written if the quiz contains 4 true-false questions followed by 2 multiples-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same? Choose the correct choice from the following answers: A) 120 B) 190 C) 224 D) 298 E) 256 | <gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">16 - 2</gadget>
<output>14</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">14 * 16</gadget>
<output>224</output>
<result>C</result> | C | 224 | In how many ways can an answer key for a quiz be written if the quiz contains 4 true-false questions followed by 2 multiples-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same? | {
"A": "120",
"B": "190",
"C": "224",
"D": "298",
"E": "256"
} | multiply(subtract(power(2, 4), 2), multiply(4, 4)) | multiply(n2,n2)|power(n1,n0)|subtract(#1,n1)|multiply(#0,#2)| | "there are 2 ^ 4 = 16 possibilities for the true - false answers . however we need to remove two cases for tttt and ffff . there are 4 * 4 = 16 possibilities for the multiple choice questions . the total number of possibilities is 14 * 16 = 224 . the answer is c ." | general |
math_qa__s9xRA86fkdaN7CMo | In what time will a train 135 m long cross an electric pole, it its speed be 140 km/hr? Choose the correct answer.
A) 3.5 B) 2.7 C) 2.9 D) 2.3 E) 2.1 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">140 * (5/18)</gadget>
<output>350/9 = around 38.888889</output>
<gadget id="calculator">135 / (350/9)</gadget>
<output>243/70 = around 3.471429</output>
<result>A</result> | A | 3.5 | In what time will a train 135 m long cross an electric pole, it its speed be 140 km/hr? | {
"A": "3.5",
"B": "2.7",
"C": "2.9",
"D": "2.3",
"E": "2.1"
} | divide(135, multiply(140, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 140 * 5 / 18 = 38.8 m / sec time taken = 135 / 38.8 = 3.5 sec . answer : a" | physics |
math_qa__a4qZTvcaYlHvVWxa | A man buys a cycle for Rs. 1200 and sells it at a loss of 10%. What is the selling price of the cycle? Choose the correct choice
A) s . 1080 B) s . 1140 C) s . 1090 D) s . 1202 E) s . 1092 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 * 1_200</gadget>
<output>108_000</output>
<gadget id="calculator">108_000 / 100</gadget>
<output>1_080</output>
<result>A</result> | A | 1,080 | A man buys a cycle for Rs. 1200 and sells it at a loss of 10%. What is the selling price of the cycle? | {
"A": "s . 1080",
"B": "s . 1140",
"C": "s . 1090",
"D": "s . 1202",
"E": "s . 1092"
} | divide(multiply(subtract(const_100, 10), 1200), const_100) | subtract(const_100,n1)|multiply(n0,#0)|divide(#1,const_100)| | "s . p . = 90 % of rs . 1200 = rs . 90 x 1200 / 100 = rs . 1080 answer : option a" | gain |
math_qa__rmuVJN6PJHeS5BAr | The average age of 30 students in a class is 14 years. If the age of teacher is also included, the average becomes 15 years, find the age of the teacher. Choose the correct choice from the following options:
A) 43 B) 44 C) 45 D) 47 E) 48 | <gadget id="calculator">30 * 14</gadget>
<output>420</output>
<gadget id="calculator">420 + 15</gadget>
<output>435</output>
<gadget id="calculator">435 + 30</gadget>
<output>465</output>
<gadget id="calculator">465 - 420</gadget>
<output>45</output>
<result>C</result> | C | 45 | The average age of 30 students in a class is 14 years. If the age of teacher is also included, the average becomes 15 years, find the age of the teacher. | {
"A": "43",
"B": "44",
"C": "45",
"D": "47",
"E": "48"
} | subtract(add(add(multiply(30, 14), 15), 30), multiply(30, 14)) | multiply(n0,n1)|add(n2,#0)|add(n0,#1)|subtract(#2,#0) | explanation : if teacher ' s age is 14 years , there is no change in the average . but teacher has contributed 1 year to all the students along with maintaining his age at 15 . age of teacher = average age of all + total increase in age = 15 + ( 1 x 30 ) = 45 years answer : c | general |
math_qa__kduUIKaCGv7i9yhW | John and Lewis leave City A for City B simultaneously at 6 A.M in the morning driving in two cars at speeds of 40 mph and 60 mph respectively. As soon as Lewis reaches City B, he returns back to City A along the same route and meets John on the way back. If the distance between the two cities is 240 miles, how far from City A did John and Lewis meet? Choose one: A) 150 miles B) 160 miles C) 140 miles D) 170 miles E) 200 miles | <gadget id="calculator">240 / 60</gadget>
<output>4</output>
<gadget id="calculator">40 * 4</gadget>
<output>160</output>
<result>B</result> | B | 160 | John and Lewis leave City A for City B simultaneously at 6 A.M in the morning driving in two cars at speeds of 40 mph and 60 mph respectively. As soon as Lewis reaches City B, he returns back to City A along the same route and meets John on the way back. If the distance between the two cities is 240 miles, how far from City A did John and Lewis meet? | {
"A": "150 miles",
"B": "160 miles",
"C": "140 miles",
"D": "170 miles",
"E": "200 miles"
} | multiply(40, divide(240, 60)) | divide(n3,n2)|multiply(n1,#0) | time taken by lewis to reach city b = 240 / 60 = 4 hours in 4 hours , john travels 40 * 4 = 160 miles so distance at which they meet should be greater than 160 miles . only b satisfies . answer is b . | physics |
math_qa__liXCeWh3ToJCpE07 | The average weight of 8 persons increases by 3 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ? Choose the correct choice from the following choices
A) 75 kg B) 65 kg C) 55 kg D) 89 kg E) 25 kg | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">65 + 24</gadget>
<output>89</output>
<result>D</result> | D | 89 | The average weight of 8 persons increases by 3 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ? | {
"A": "75 kg",
"B": "65 kg",
"C": "55 kg",
"D": "89 kg",
"E": "25 kg"
} | add(65, multiply(8, 3)) | multiply(n0,n1)|add(n2,#0) | total weight increased = ( 8 x 3 ) kg = 24 kg . weight of new person = ( 65 + 24 ) kg = 89 kg . answer : d | general |
math_qa__hVKVvePIhwHYUplA | in a village of 100 households , 85 have at least one dvd player , 90 have at least one cell phone , and 55 have at least one mp 3 player . if x and y are respectively the greatest and lowest possible number of households that have all 3 of these devices , x – y is : Pick:
A) 65
B) 55
C) 45
D) 35
E) 25 | <gadget id="calculator">100 - 55</gadget>
<output>45</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">100 - 90</gadget>
<output>10</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">45 + 25</gadget>
<output>70</output>
<gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">55 - 30</gadget>
<output>25</output>
<result>E</result> | E | 25 | in a village of 100 households , 85 have at least one dvd player , 90 have at least one cell phone , and 55 have at least one mp 3 player . if x and y are respectively the greatest and lowest possible number of households that have all 3 of these devices , x – y is : | {
"A": "65",
"B": "55",
"C": "45",
"D": "35",
"E": "25"
} | subtract(55, subtract(100, add(subtract(100, 55), add(subtract(100, 85), subtract(100, 90))))) | subtract(n0,n1)|subtract(n0,n2)|subtract(n0,n3)|add(#0,#1)|add(#3,#2)|subtract(n0,#4)|subtract(n3,#5) | am i missing something here ? ? ? it seems straightforward . . . . . . the obvious maximum that have all 3 is 55 , because you are limited by the smallest number . the minimum is simply the sum of the max of each people who dont have the product , so : 100 - 90 = 10 do n ' t have cell 100 - 85 = 15 do n ' t have dvd and 100 - 55 = 45 do n ' t have mp 3 so a total of 10 + 15 + 45 = 70 combined who might not have some combination of the 3 products . so subtract that from 100 , to give you the minimum of the people who could have all 3 and you get 100 - 70 = 30 . 55 - 30 = 25 e | general |
math_qa__mCTF8Yy2jkrn2z1k | Of the diplomats attending a summit conference, 14 speak French, 32 do not speak Russian, and 20% of the diplomats speak neither French nor Russian. If 10% of the diplomats speak both languages, then how many diplomats attended the conference? Pick: A) 72 B) 96 C) 108 D) 120 E) 180 | <gadget id="calculator">32 - 14</gadget>
<output>18</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/5) - (1/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">18 / (1/10)</gadget>
<output>180</output>
<result>E</result> | E | 180 | Of the diplomats attending a summit conference, 14 speak French, 32 do not speak Russian, and 20% of the diplomats speak neither French nor Russian. If 10% of the diplomats speak both languages, then how many diplomats attended the conference? | {
"A": "72",
"B": "96",
"C": "108",
"D": "120",
"E": "180"
} | divide(subtract(32, 14), subtract(divide(20, const_100), divide(10, const_100))) | divide(n2,const_100)|divide(n3,const_100)|subtract(n1,n0)|subtract(#0,#1)|divide(#2,#3) | { total } = { french } + { russian } - { both } + { neither } { total } = 14 + ( { total } - 32 ) - ( 0.1 * { total } ) + 0.2 * { total } solving gives { total } = 180 . answer : e . | other |
math_qa__9fBLPQzOl9Glz7mr | In a certain pond, 80 fish were caught, tagged, and returned to the pond. A few days later, 80 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond?
Choose the correct choice:
A) 400
B) 625
C) 1250
D) 3200
E) 10 000 | <gadget id="calculator">2 / 80</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">80 / (1/40)</gadget>
<output>3_200</output>
<result>D</result> | D | 3,200 | In a certain pond, 80 fish were caught, tagged, and returned to the pond. A few days later, 80 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond? | {
"A": "400",
"B": "625",
"C": "1250",
"D": "3200",
"E": "10 000"
} | divide(80, divide(2, 80)) | divide(n2,n1)|divide(n0,#0)| | "the percent of tagged fish in the second catch is 2 / 80 * 100 = 2.5 % . we are told that 2.5 % approximates the percent of tagged fish in the pond . since there are 80 tagged fish , then we have 0.025 x = 80 - - > x = 3,200 . answer : d ." | gain |
math_qa__gVFqxKRmOxs0PCYD | The cost price of an article is 25% of the marked price. Calculate the gain percent after allowing a discount of 50%. Choose one:
A) 25 % B) 50 % C) 100 % D) 150 % E) none | <gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 25</gadget>
<output>2</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>C</result> | C | 100 | The cost price of an article is 25% of the marked price. Calculate the gain percent after allowing a discount of 50%. | {
"A": "25 %",
"B": "50 %",
"C": "100 %",
"D": "150 %",
"E": "none"
} | multiply(subtract(divide(subtract(const_100, 50), 25), const_1), const_100) | subtract(const_100,n1)|divide(#0,n0)|subtract(#1,const_1)|multiply(#2,const_100)| | "sol . let marked price = rs . 100 . then , c . p . = rs . 25 . s . p = rs . 50 . â ˆ ´ gain % = [ 25 / 25 * 100 ] % = 100.0 % . answer c" | gain |
math_qa__Fa6pnFNAe5BaVlpR | The total marks obtained by a student in Mathematics and Physics is 40 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together. Choices:
A) 40 B) 26 C) 27 D) 28 E) 30 | <gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>E</result> | E | 30 | The total marks obtained by a student in Mathematics and Physics is 40 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together. | {
"A": "40",
"B": "26",
"C": "27",
"D": "28",
"E": "30"
} | divide(add(40, 20), const_2) | add(n0,n1)|divide(#0,const_2)| | "let the marks obtained by the student in mathematics , physics and chemistry be m , p and c respectively . given , m + c = 40 and c - p = 20 m + c / 2 = [ ( m + p ) + ( c - p ) ] / 2 = ( 40 + 20 ) / 2 = 30 . answer : e" | general |
math_qa__ygMM4gfyRdCZUnCb | a light flashes every 20 seconds, how many times will it flash in ? of an hour? Select the correct option: A) 550 B) 600 C) 650 D) 180 E) 750 | <gadget id="calculator">3_600 / 20</gadget>
<output>180</output>
<result>D</result> | D | 180 | a light flashes every 20 seconds, how many times will it flash in ? of an hour? | {
"A": "550",
"B": "600",
"C": "650",
"D": "180",
"E": "750"
} | divide(const_3600, 20) | divide(const_3600,n0)| | "1 flash = 20 sec for 1 min = 3 flashes so for 1 hour = 3 * 60 = 180 flashes . answer : d" | physics |
math_qa__NjDdajNMsmtSlFSN | The cost of 3 pens and 5 pencils is Rs.240. Also the cost of one pen and one pencil is in the ratio of 5:1 respectively. What is the cost of one dozen pens?
Select the correct option: A) rs . 200 B) rs . 720 C) rs . 300 D) rs . 150 E) none of these | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">240 / 4</gadget>
<output>60</output>
<gadget id="calculator">12 * 60</gadget>
<output>720</output>
<result>B</result> | B | 720 | The cost of 3 pens and 5 pencils is Rs.240. Also the cost of one pen and one pencil is in the ratio of 5:1 respectively. What is the cost of one dozen pens? | {
"A": "rs . 200",
"B": "rs . 720",
"C": "rs . 300",
"D": "rs . 150",
"E": "none of these"
} | multiply(multiply(3, const_4), divide(240, add(3, 1))) | add(n0,n4)|multiply(n0,const_4)|divide(n2,#0)|multiply(#2,#1)| | "explanation : let the cost of one pen is ‘ 5 x ’ and pencil is ‘ x ’ 3 x 5 x + 5 x = rs . 240 15 x + 5 x = rs . 240 x = 240 / 20 = 12 : . cost of 1 pen = 5 x = 5 x 12 = 60 : . cost of 12 pens , i . e . ( one dozen ) = 60 x 12 = rs . 720 answer : option b" | other |
math_qa__E0Ufxtidjjk1n0XP | The regular price per can of a certain brand of soda is $0.55. If the regular price per can is discounted 25 percent when the soda is purchased in 24-can cases, what is the price of 70 cans of this brand of soda purchased in 24-can cases? Choose the most appropriate option:
A) $ 16.32
B) $ 18.00
C) $ 21.60
D) $ 24.48
E) $ 28.87 | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">0.55 * 70</gadget>
<output>38.5</output>
<gadget id="calculator">(3/4) * 38.5</gadget>
<output>28.875</output>
<result>E</result> | E | 28.87 | The regular price per can of a certain brand of soda is $0.55. If the regular price per can is discounted 25 percent when the soda is purchased in 24-can cases, what is the price of 70 cans of this brand of soda purchased in 24-can cases? | {
"A": "$ 16.32",
"B": "$ 18.00",
"C": "$ 21.60",
"D": "$ 24.48",
"E": "$ 28.87"
} | multiply(divide(subtract(const_100, 25), const_100), multiply(0.55, 70)) | multiply(n0,n3)|subtract(const_100,n1)|divide(#1,const_100)|multiply(#2,#0)| | "the discounted price of one can of soda is ( 0.75 ) ( $ 0.55 ) , or $ 0.4125 therefore , the price of 70 cans of soda at the discounted price would be ( 70 ) ( $ 0.4125 ) = 28.875 answer : e" | gain |
math_qa__0TQRRFHUBQ3G6F82 | The ratio between the number of sheep and the number of horses at the Stewart farm is 2 to 7, If each horse is fed 230 ounces of horse food per day and the farm needs a total 12,880 ounces of horse food per day, what is the number of sheep in the farm? Pick one: A) 18 B) 16 C) 32 D) 56 E) 60 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 10</gadget>
<output>80</output>
<gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">80 + 800</gadget>
<output>880</output>
<gadget id="calculator">12 * 1_000</gadget>
<output>12_000</output>
<gadget id="calculator">880 + 12_000</gadget>
<output>12_880</output>
<gadget id="calculator">12_880 / 230</gadget>
<output>56</output>
<gadget id="calculator">56 / 7</gadget>
<output>8</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<result>B</result> | B | 16 | The ratio between the number of sheep and the number of horses at the Stewart farm is 2 to 7, If each horse is fed 230 ounces of horse food per day and the farm needs a total 12,880 ounces of horse food per day, what is the number of sheep in the farm? | {
"A": "18",
"B": "16",
"C": "32",
"D": "56",
"E": "60"
} | multiply(divide(divide(add(add(multiply(multiply(const_4, const_2), const_10), multiply(multiply(const_4, const_2), const_100)), multiply(const_12, const_1000)), 230), 7), 2) | multiply(const_2,const_4)|multiply(const_1000,const_12)|multiply(#0,const_10)|multiply(#0,const_100)|add(#2,#3)|add(#4,#1)|divide(#5,n2)|divide(#6,n1)|multiply(n0,#7)| | "let the number of sheeps and horses be 4 x and 7 x . now total number of horses = total consumption of horse food / consumption per horse = 12880 / 230 = 56 , which is equal to 7 x . = > x = 8 sheeps = 2 x = 2 * 8 = 16 . hence b" | other |
math_qa__ggOyycpgCSpWtslz | The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary? Choose the correct option.
A) 3600
B) 2988
C) 2789
D) 2887
E) 1297 | <gadget id="calculator">1_500 + 100</gadget>
<output>1_600</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">1_600 * 21</gadget>
<output>33_600</output>
<gadget id="calculator">1_500 * 20</gadget>
<output>30_000</output>
<gadget id="calculator">33_600 - 30_000</gadget>
<output>3_600</output>
<result>A</result> | A | 3,600 | The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary? | {
"A": "3600",
"B": "2988",
"C": "2789",
"D": "2887",
"E": "1297"
} | subtract(multiply(add(1500, 100), add(20, const_1)), multiply(1500, 20)) | add(n1,n2)|add(n0,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "manager ' s monthly salary rs . ( 1600 * 21 - 1500 * 20 ) = rs . 3600 . answer : a" | general |
math_qa__xfpXQwrSKG1kuqLo | A call center has two teams. Each member of Team A was able to process 6/5 calls as compared to each member of Team B. If Team A has 5/8 as many number of call center agents as Team B, what fraction of the total calls was processed by Team B? Choose the correct option:
A) 3 / 2 B) 3 / 4 C) 4 / 7 D) 1 / 2 E) 1 / 5 | <gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">40 + 30</gadget>
<output>70</output>
<gadget id="calculator">40 / 70</gadget>
<output>4/7 = around 0.571429</output>
<result>C</result> | C | 0.571429 | A call center has two teams. Each member of Team A was able to process 6/5 calls as compared to each member of Team B. If Team A has 5/8 as many number of call center agents as Team B, what fraction of the total calls was processed by Team B? | {
"A": "3 / 2",
"B": "3 / 4",
"C": "4 / 7",
"D": "1 / 2",
"E": "1 / 5"
} | divide(multiply(8, 5), add(multiply(8, 5), multiply(5, 6))) | multiply(n1,n3)|multiply(n0,n1)|add(#0,#1)|divide(#0,#2)| | "let team b has 8 agents , so team a has 5 agents let each agent of team b picked up 5 calls , so total calls by team b = 40 so , each agent in team a picked up 6 calls , so total calls for team a = 30 fraction for team b = 40 / ( 40 + 30 ) = 4 / 7 = answer = c" | general |
math_qa__XqcAFX6sXcZcBYU2 | After decreasing 24% in the price of an article costs Rs.1064. Find the actual cost of an article? Choices:
A) 1667
B) 6789
C) 1200
D) 6151
E) 1400 | <gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">1 - (6/25)</gadget>
<output>19/25 = around 0.76</output>
<gadget id="calculator">1_064 / (19/25)</gadget>
<output>1_400</output>
<result>E</result> | E | 1,400 | After decreasing 24% in the price of an article costs Rs.1064. Find the actual cost of an article? | {
"A": "1667",
"B": "6789",
"C": "1200",
"D": "6151",
"E": "1400"
} | divide(1064, subtract(const_1, divide(24, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1)| | "cp * ( 76 / 100 ) = 1064 cp = 14 * 100 = > cp = 1400 answer : e" | gain |
math_qa__ntdbg6x1289xn5Ml | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is:
Choose the correct choice from the following: A) 4830 B) 5120 C) 6420 D) 8960 E) none | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">48 - 16</gadget>
<output>32</output>
<gadget id="calculator">36 - 16</gadget>
<output>20</output>
<gadget id="calculator">32 * 20 * 8</gadget>
<output>5_120</output>
<result>B</result> | B | 5,120 | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is: | {
"A": "4830",
"B": "5120",
"C": "6420",
"D": "8960",
"E": "none"
} | volume_rectangular_prism(subtract(48, multiply(8, const_2)), subtract(36, multiply(8, const_2)), 8) | multiply(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|volume_rectangular_prism(n2,#1,#2)| | "explanation clearly , l = ( 48 – 16 ) m = 32 m , b = ( 36 - 16 ) m = 20 m , h = 8 m . volume of the box = ( 32 x 20 x 8 ) m 3 = 5120 m 3 . answer b" | geometry |
math_qa__fG0KvHNnl1y4fFw3 | 300 × ? + (12 + 4) × 1/8 = 602 Choose the correct choice from the following options: A) 4 B) 3 C) 5 D) 2 E) 8 | <gadget id="calculator">12 + 4</gadget>
<output>16</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">16 * (1/8)</gadget>
<output>2</output>
<gadget id="calculator">602 - 2</gadget>
<output>600</output>
<gadget id="calculator">600 / 300</gadget>
<output>2</output>
<result>D</result> | D | 2 | 300 × ? + (12 + 4) × 1/8 = 602 | {
"A": "4",
"B": "3",
"C": "5",
"D": "2",
"E": "8"
} | divide(subtract(602, multiply(add(12, 4), divide(1, 8))), 300) | add(n1,n2)|divide(n3,n4)|multiply(#0,#1)|subtract(n5,#2)|divide(#3,n0) | explanation : = > 300 × ? + ( 12 + 4 ) × 1 / 8 = 602 = > 300 × ? = 602 - ( 12 + 4 ) × 1 / 8 = > 300 × ? = 602 - 2 = 600 = > ? = 600 / 300 = 2 answer : option d | general |
math_qa__2c15sLY3zETfEvsn | Girl and Boy together can complete a piece of work in 35 days while Girl alone can complete the same work in 60 days. Boy alone will be able to complete the same working in: Choose the correct answer:
A) 72
B) 75
C) 84
D) 88
E) 90 | <gadget id="calculator">1 / 35</gadget>
<output>1/35 = around 0.028571</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/35) - (1/60)</gadget>
<output>1/84 = around 0.011905</output>
<gadget id="calculator">1 / (1/84)</gadget>
<output>84</output>
<gadget id="calculator">84 - 10</gadget>
<output>74</output>
<result>B</result> | B | 75 | Girl and Boy together can complete a piece of work in 35 days while Girl alone can complete the same work in 60 days. Boy alone will be able to complete the same working in: | {
"A": "72",
"B": "75",
"C": "84",
"D": "88",
"E": "90"
} | subtract(inverse(subtract(inverse(35), inverse(60))), const_10) | inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2)|subtract(#3,const_10) | subtraction of fraction ab − cd = ad − cbbd girl and boy finish one work with company = 35 days ( girl + boy ) ′ s one day ’ s work = 135 girl alone finish the same work = 60 days girl ′ s one day ’ s work = 160 b ′ s one day ’ s work = ( a + b ) ′ s one day ’ s work - a ′ s one day ’ s work 135 − 160 = 184 hence b alone can complete the work in 84 days | physics |
math_qa__lVhyLrwuQWJZijKS | Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%? Pick.
A) 2288 B) 27669 C) 1766 D) 1000 E) 2871 | <gadget id="calculator">6 * 2_500</gadget>
<output>15_000</output>
<gadget id="calculator">15_000 / 100</gadget>
<output>150</output>
<gadget id="calculator">140 - 150</gadget>
<output>-10</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(1/20) - (3/50)</gadget>
<output>-1/100 = around -0.01</output>
<gadget id="calculator">(-10) / (-1/100)</gadget>
<output>1_000</output>
<result>D</result> | D | 1,000 | Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%? | {
"A": "2288",
"B": "27669",
"C": "1766",
"D": "1000",
"E": "2871"
} | divide(subtract(140, divide(multiply(6, 2500), const_100)), subtract(divide(5, const_100), divide(6, const_100))) | divide(n1,const_100)|divide(n2,const_100)|multiply(n0,n2)|divide(#2,const_100)|subtract(#0,#1)|subtract(n3,#3)|divide(#5,#4)| | "( x * 5 * 1 ) / 100 + [ ( 2500 - x ) * 6 * 1 ] / 100 = 140 x = 1000 answer : d" | gain |
math_qa__sEwhFJOuJ1ErNWT8 | The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 42, what is the greatest possible value of the median of the 5 integers? Choose the correct option
A) 17
B) 18
C) 19
D) 20
E) 22 | <gadget id="calculator">16 * 5</gadget>
<output>80</output>
<gadget id="calculator">80 - 42</gadget>
<output>38</output>
<gadget id="calculator">38 / 2</gadget>
<output>19</output>
<gadget id="calculator">19 - 2</gadget>
<output>17</output>
<result>A</result> | A | 17 | The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 42, what is the greatest possible value of the median of the 5 integers? | {
"A": "17",
"B": "18",
"C": "19",
"D": "20",
"E": "22"
} | subtract(divide(subtract(multiply(16, 5), 42), const_2), const_2) | multiply(n0,n1)|subtract(#0,n2)|divide(#1,const_2)|subtract(#2,const_2) | we need to find the median which is the third value when the numbers are in increasing order . since k < m < r < s < t , the median would be r . the average of the positive integers is 16 which means that in effect , all numbers are equal to 16 . if the largest number is 42 , it is 26 more than 16 . we need r to be maximum so k and m should be as small as possible to get the average of 16 . since all the numbers are positive integers , k and m can not be less than 1 and 2 respectively . 1 is 15 less than 16 and 2 is 14 less than 16 which means k and m combined are 29 less than the average . 42 is already 26 more than 16 and hence we only have 29 - 26 = 3 extra to distribute between r and s . since s must be greater than r , r can be 16 + 1 = 17 and s can be 16 + 2 = 18 . so r is 17 . answer ( a ) | general |
math_qa__VnXtEnhxctegEIxT | A cycle is bought for Rs.600 and sold for Rs.1080, find the gain percent? Answers
A) 22 B) 20 C) 90 D) 80 E) 11 | <gadget id="calculator">1_080 - 600</gadget>
<output>480</output>
<gadget id="calculator">480 / 600</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<result>D</result> | D | 80 | A cycle is bought for Rs.600 and sold for Rs.1080, find the gain percent? | {
"A": "22",
"B": "20",
"C": "90",
"D": "80",
"E": "11"
} | multiply(divide(subtract(1080, 600), 600), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "600 - - - - 180 100 - - - - ? = > 80 % answer : d" | gain |
math_qa__byYXp3m1mQyHgqzs | How many integers are between 3 and 86/7, inclusive? Select the correct option
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">86 / 7</gadget>
<output>86/7 = around 12.285714</output>
<gadget id="calculator">(86/7) - 3</gadget>
<output>65/7 = around 9.285714</output>
<gadget id="calculator">(65/7) + 1</gadget>
<output>72/7 = around 10.285714</output>
<result>C</result> | C | 10 | How many integers are between 3 and 86/7, inclusive? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | add(subtract(divide(86, 7), 3), const_1) | divide(n1,n2)|subtract(#0,n0)|add(#1,const_1)| | "86 / 7 = 12 . xx we are not concerned about the exact value of 86 / 7 as we just need the integers . since the values are small , we can write down the integers . the different integers between 3 and 86 / 7 would be 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 total number of integers = 10 option c if we need to find the number of integers between two numbers n and m , where m > n the number of integers = m - n + 1 in the given question , the number of integers = 12 - 3 + 1 = 10 answer : c" | general |
math_qa__PQNu7d0XQrVxFk7y | A man goes downstream at 15 kmph, and upstream8 kmph. The speed of the stream is Choose the most appropriate option.
A) 0 kmph B) 3.5 kmph C) 16 kmph D) 2.5 kmph E) 26 kmph | <gadget id="calculator">15 - 8</gadget>
<output>7</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<result>B</result> | B | 3.5 | A man goes downstream at 15 kmph, and upstream8 kmph. The speed of the stream is | {
"A": "0 kmph",
"B": "3.5 kmph",
"C": "16 kmph",
"D": "2.5 kmph",
"E": "26 kmph"
} | divide(subtract(15, 8), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "speed of the stream = 1 / 2 ( 15 - 8 ) kmph = 3.5 kmph . correct option : b" | physics |
math_qa__F9YdoTM6FZ0D2M4k | If 12 people contributed a total of $20.00 toward a gift and each of them contributed at least $1.00, then the maximum possible amount any one person could have contributed is
Select: A) $ 1.00 B) $ 1.25 C) $ 5.00 D) $ 9.00 E) $ 20.00 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 1</gadget>
<output>11</output>
<gadget id="calculator">20 - 11</gadget>
<output>9</output>
<result>D</result> | D | 9 | If 12 people contributed a total of $20.00 toward a gift and each of them contributed at least $1.00, then the maximum possible amount any one person could have contributed is | {
"A": "$ 1.00",
"B": "$ 1.25",
"C": "$ 5.00",
"D": "$ 9.00",
"E": "$ 20.00"
} | subtract(20, multiply(subtract(12, const_1), 1)) | subtract(n0,const_1)|multiply(n2,#0)|subtract(n1,#1) | d for me 11 people with 1 $ each - > maximum = 9 | general |
math_qa__sEmUu7mZiAa2CECD | The diagonals of a rhombus are 12 cm and 20 cm. Find its area? Pick.
A) 329 B) 288 C) 120 D) 238 E) 31 | <gadget id="calculator">(12 * 20) / 2</gadget>
<output>120</output>
<result>C</result> | C | 120 | The diagonals of a rhombus are 12 cm and 20 cm. Find its area? | {
"A": "329",
"B": "288",
"C": "120",
"D": "238",
"E": "31"
} | rhombus_area(12, 20) | rhombus_area(n0,n1)| | "1 / 2 * 12 * 20 = 120 answer : c" | geometry |
math_qa__X8sDFoluVR5fq6Dy | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 20 overs to reach the target of 282 runs? Choose the correct choice.
A) 6.25 B) 5.5 C) 7.4 D) 5 E) 12.5 | <gadget id="calculator">10 * 3.2</gadget>
<output>32</output>
<gadget id="calculator">282 - 32</gadget>
<output>250</output>
<gadget id="calculator">250 / 20</gadget>
<output>25/2 = around 12.5</output>
<result>E</result> | E | 12.5 | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 20 overs to reach the target of 282 runs? | {
"A": "6.25",
"B": "5.5",
"C": "7.4",
"D": "5",
"E": "12.5"
} | divide(subtract(282, multiply(10, 3.2)), 20) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)| | "explanation : runs scored in the first 10 overs = 10 × 3.2 = 32 total runs = 282 remaining runs to be scored = 282 - 32 = 250 remaining overs = 20 run rate needed = 250 / 20 = 12.5 answer : option e" | gain |
math_qa__o1QmPh7gdnZAkGh9 | A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 12 km, if the person completes half of the distance by walking and the other half by running? Choose the correct choice from the following:
A) 1.25 B) 1.75 C) 2.25 D) 2.75 E) 3.25 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 4</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">6 / 8</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/2) + (3/4)</gadget>
<output>9/4 = around 2.25</output>
<result>C</result> | C | 2.25 | A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 12 km, if the person completes half of the distance by walking and the other half by running? | {
"A": "1.25",
"B": "1.75",
"C": "2.25",
"D": "2.75",
"E": "3.25"
} | add(divide(divide(12, const_2), 4), divide(divide(12, const_2), 8)) | divide(n2,const_2)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)| | "time = 6 / 4 + 6 / 8 = 18 / 8 = 2.25 hours the answer is c ." | physics |
math_qa__LZlS5GE8s9Ofk63t | If the number is divided by 3, it reduced by 48. The number is Choose the correct choice
A) 51 B) 50 C) 45 D) 72 E) 36 | <gadget id="calculator">48 * 3</gadget>
<output>144</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">144 / 2</gadget>
<output>72</output>
<result>D</result> | D | 72 | If the number is divided by 3, it reduced by 48. The number is | {
"A": "51",
"B": "50",
"C": "45",
"D": "72",
"E": "36"
} | divide(multiply(48, 3), subtract(3, const_1)) | multiply(n0,n1)|subtract(n0,const_1)|divide(#0,#1)| | "explanation : let the number be x . then , x - ( x / 3 ) = 48 = > 2 x / 3 = 48 = > x = 72 answer : option d" | general |
math_qa__uSMVbVCAe582axtF | An equilateral triangle T2 is formed by joining the mid points of the sides of another equilateral triangle T1. A third equilateral triangle T3 is formed by joining the mid-points of T2 and this process is continued indefinitely. If each side of T1 is 80 cm, find the sum of the perimeters of all the triangles. Answers.
A) 180 cm B) 220 cm C) 240 cm D) 270 cm E) 480 cm | <gadget id="calculator">80 + 80 + 80</gadget>
<output>240</output>
<gadget id="calculator">240 + 240</gadget>
<output>480</output>
<result>E</result> | E | 480 | An equilateral triangle T2 is formed by joining the mid points of the sides of another equilateral triangle T1. A third equilateral triangle T3 is formed by joining the mid-points of T2 and this process is continued indefinitely. If each side of T1 is 80 cm, find the sum of the perimeters of all the triangles. | {
"A": "180 cm",
"B": "220 cm",
"C": "240 cm",
"D": "270 cm",
"E": "480 cm"
} | add(triangle_perimeter(80, 80, 80), triangle_perimeter(80, 80, 80)) | triangle_perimeter(n5,n5,n5)|add(#0,#0)| | "we have 80 for first triangle , when we join mid - points of first triangle we get the second equilateral triangle then the length of second one is 40 and continues . so we have 80 , 40,20 , . . . we have ratio = 1 / 2 , and it is gp type . sum of infinite triangle is a / 1 - r = 80 / 1 - ( 1 / 2 ) = 160 equilateral triangle perimeter is 3 a = 3 * 160 = 480 . so option e ." | geometry |
math_qa__dH7MTjw6zlrn6xU7 | If 2^2n + 2^2n + 2^2n + 2^2n = 4^26, then n =
Choose the correct choice.
A) 3 B) 6 C) 12 D) 23 E) 25 | <gadget id="calculator">26 * 2</gadget>
<output>52</output>
<gadget id="calculator">52 - 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>E</result> | E | 25 | If 2^2n + 2^2n + 2^2n + 2^2n = 4^26, then n = | {
"A": "3",
"B": "6",
"C": "12",
"D": "23",
"E": "25"
} | divide(subtract(multiply(26, 2), 2), 2) | multiply(n0,n9)|subtract(#0,n0)|divide(#1,n0)| | "2 ^ 2 n + 2 ^ 2 n + 2 ^ 2 n + 2 ^ 2 n = 4 ^ 26 = > 4 x 2 ^ 2 n = 4 ^ 26 = 2 ^ 52 = > 2 ^ 2 x 2 ^ 2 n = 2 ^ 52 = > 2 ^ ( 2 n + 2 ) = 2 ^ 52 = > 2 n + 2 = 52 = > n = 25 so . answer will be e" | general |
math_qa__ED7hhL4xtDGAII5d | If a - b = 5 and a2 + b2 = 34, find the value of ab. Pick.
A) 4.5 B) 12 C) 15 D) 18 E) 20 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">34 - 25</gadget>
<output>9</output>
<gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<result>A</result> | A | 4.5 | If a - b = 5 and a2 + b2 = 34, find the value of ab. | {
"A": "4.5",
"B": "12",
"C": "15",
"D": "18",
"E": "20"
} | divide(subtract(34, power(5, 2)), 2) | power(n0,n1)|subtract(n3,#0)|divide(#1,n1)| | "explanation : 2 ab = ( a 2 + b 2 ) - ( a - b ) 2 = 34 - 25 = 9 ab = 4.5 . answer : a" | general |
math_qa__Sxh595ZF5BCJ342c | John makes $60 a week from his job. He earns a raise and now makes $110 a week. What is the % increase? Pick:
A) 16 % B) 83.33 % C) 17 % D) 17.61 % E) 17.56 % | <gadget id="calculator">110 - 60</gadget>
<output>50</output>
<gadget id="calculator">50 / 60</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(5/6) * 100</gadget>
<output>250/3 = around 83.333333</output>
<result>B</result> | B | 83.33 | John makes $60 a week from his job. He earns a raise and now makes $110 a week. What is the % increase? | {
"A": "16 %",
"B": "83.33 %",
"C": "17 %",
"D": "17.61 %",
"E": "17.56 %"
} | multiply(divide(subtract(110, 60), 60), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 50 / 60 ) * 100 = ( 5 / 6 ) * 100 = 83.33 % . b" | gain |
math_qa__ukD8hpx2FPOX3O1T | A certain number of workers can do a work in 35 days. If there were 10 workers more it could be finished in 10 days less. How many workers are there?
Options:
A) 25 B) 30 C) 28 D) 24 E) 32 | <gadget id="calculator">35 - 10</gadget>
<output>25</output>
<gadget id="calculator">25 * 10</gadget>
<output>250</output>
<gadget id="calculator">35 - 25</gadget>
<output>10</output>
<gadget id="calculator">250 / 10</gadget>
<output>25</output>
<result>A</result> | A | 25 | A certain number of workers can do a work in 35 days. If there were 10 workers more it could be finished in 10 days less. How many workers are there? | {
"A": "25",
"B": "30",
"C": "28",
"D": "24",
"E": "32"
} | divide(multiply(subtract(35, 10), 10), subtract(35, subtract(35, 10))) | subtract(n0,n1)|multiply(n1,#0)|subtract(n0,#0)|divide(#1,#2)| | "number of workers = 10 * ( 35 - 10 ) / 10 = 25 answer is a" | physics |
math_qa__hEAve4h6c8IZxi3F | In the formula A = (2r)^3, if r is halved, then A is multiplied by ?
Choose the correct choice from the following:
A) 64
B) 1 / 8
C) 1
D) 8
E) 1 / 64 | <gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<result>B</result> | B | 0.125 | In the formula A = (2r)^3, if r is halved, then A is multiplied by ? | {
"A": "64",
"B": "1 / 8",
"C": "1",
"D": "8",
"E": "1 / 64"
} | divide(const_1, power(2, 3)) | power(n0,n1)|divide(const_1,#0) | say r = 2 = > a 1 = 64 when r = 1 ; v 2 = 8 v 2 = 1 / 8 * v 1 . answer : b | general |
math_qa__2Q3Jd1tsu06mGkLf | The value of a machine depreciates at 20% per annum. If its present value is Rs. 1,50,000, at what price should it be sold after two years such that a profit of Rs. 22,000 is made?
Select the correct option:
A) 328897
B) 120000
C) 118000
D) 277768
E) 188871 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * (4/5)</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">10_000 * 10</gadget>
<output>100_000</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">500 * 100</gadget>
<output>50_000</output>
<gadget id="calculator">100_000 + 50_000</gadget>
<output>150_000</output>
<gadget id="calculator">(16/25) * 150_000</gadget>
<output>96_000</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">22 * 100</gadget>
<output>2_200</output>
<gadget id="calculator">2_200 * 10</gadget>
<output>22_000</output>
<gadget id="calculator">96_000 + 22_000</gadget>
<output>118_000</output>
<result>C</result> | C | 118,000 | The value of a machine depreciates at 20% per annum. If its present value is Rs. 1,50,000, at what price should it be sold after two years such that a profit of Rs. 22,000 is made? | {
"A": "328897",
"B": "120000",
"C": "118000",
"D": "277768",
"E": "188871"
} | add(multiply(multiply(subtract(const_1, divide(20, const_100)), subtract(const_1, divide(20, const_100))), add(multiply(multiply(const_100, const_100), sqrt(const_100)), multiply(multiply(divide(sqrt(const_100), const_2), const_100), const_100))), multiply(multiply(add(20, const_2), const_100), sqrt(const_100))) | add(n0,const_2)|divide(n0,const_100)|multiply(const_100,const_100)|sqrt(const_100)|divide(#3,const_2)|multiply(#2,#3)|multiply(#0,const_100)|subtract(const_1,#1)|multiply(#4,const_100)|multiply(#7,#7)|multiply(#6,#3)|multiply(#8,const_100)|add(#5,#11)|multiply(#12,#9)|add(#13,#10) | the value of the machine after two years = 0.8 * 0.8 * 1 , 50,000 = rs . 96,000 sp such that a profit of rs . 22,000 is made = 96,000 + 24,000 = rs . 1 , 18,000 answer : c | gain |
math_qa__7gS4eFMPtyiGPr4p | A cycle is bought for Rs.900 and sold for Rs.1180, find the gain percent? Choose the correct choice from the following answers
A) 11 B) 31 C) 99 D) 77 E) 18 | <gadget id="calculator">1_180 - 900</gadget>
<output>280</output>
<gadget id="calculator">280 / 900</gadget>
<output>14/45 = around 0.311111</output>
<gadget id="calculator">(14/45) * 100</gadget>
<output>280/9 = around 31.111111</output>
<result>B</result> | B | 31 | A cycle is bought for Rs.900 and sold for Rs.1180, find the gain percent? | {
"A": "11",
"B": "31",
"C": "99",
"D": "77",
"E": "18"
} | multiply(divide(subtract(1180, 900), 900), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "900 - - - - 280 100 - - - - ? = > 31 % answer : b" | gain |
math_qa__0W9CfzEpnMLUULR5 | All the students of class are told to sit in circle shape. Here the boy at the 8 th position is exactly opposite to 33 th boy. Total number of boys in the class? Choose the correct choice:
A) 40 B) 50 C) 28 D) 38 E) 48 | <gadget id="calculator">33 - 8</gadget>
<output>25</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<result>B</result> | B | 50 | All the students of class are told to sit in circle shape. Here the boy at the 8 th position is exactly opposite to 33 th boy. Total number of boys in the class? | {
"A": "40",
"B": "50",
"C": "28",
"D": "38",
"E": "48"
} | multiply(subtract(33, 8), const_2) | subtract(n1,n0)|multiply(#0,const_2)| | "as half the circle shape consist of 33 - 8 = 25 boys , so total number of boys in full circle = 2 * 25 = 50 answer : b" | general |
math_qa__OoPuTK8UIlb8Siet | 45 girls and 60 boys are present at a party. There are 17 girl-boy are in relationship among them. If a girl and a boy is selected at random, what is the probability that they will be not a couple? Select
A) 17 / 2900
B) 2683 / 2700
C) 2496 / 2700
D) 2369 / 2700
E) 198 / 270 | <gadget id="calculator">binomial(45, 1)</gadget>
<output>45</output>
<gadget id="calculator">binomial(60, 1)</gadget>
<output>60</output>
<gadget id="calculator">45 * 60</gadget>
<output>2_700</output>
<gadget id="calculator">binomial(17, 1)</gadget>
<output>17</output>
<gadget id="calculator">2_700 - 17</gadget>
<output>2_683</output>
<gadget id="calculator">2_683 / 2_700</gadget>
<output>2_683/2_700 = around 0.993704</output>
<result>B</result> | B | 0.993704 | 45 girls and 60 boys are present at a party. There are 17 girl-boy are in relationship among them. If a girl and a boy is selected at random, what is the probability that they will be not a couple? | {
"A": "17 / 2900",
"B": "2683 / 2700",
"C": "2496 / 2700",
"D": "2369 / 2700",
"E": "198 / 270"
} | divide(subtract(multiply(choose(45, const_1), choose(60, const_1)), choose(17, const_1)), multiply(choose(45, const_1), choose(60, const_1))) | choose(n0,const_1)|choose(n1,const_1)|choose(n2,const_1)|multiply(#0,#1)|subtract(#3,#2)|divide(#4,#3) | in how many ways we can select a girl and a boy from 45 lady and 60 gentlemen ? in 45 * 60 = 2,700 ways . we have a total of 17 couples so , the probability of selecting a couple is 17 / 2,700 = 17 / 2700 . probability of there will not be a couple = 1 - ( 17 / 2700 ) = 2683 / 2700 ans - b | probability |
math_qa__G7ET7rMl56PzeeqG | How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 134 m length? Choose the correct choice from the following options: A) 82.1 sec . B) 12.2 sec C) 19.1 sec . D) 17.1 sec . E) 42.1 sec . | <gadget id="calculator">110 + 134</gadget>
<output>244</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">244 / 20</gadget>
<output>61/5 = around 12.2</output>
<result>B</result> | B | 12.2 | How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 134 m length? | {
"A": "82.1 sec .",
"B": "12.2 sec",
"C": "19.1 sec .",
"D": "17.1 sec .",
"E": "42.1 sec ."
} | divide(add(110, 134), multiply(72, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 72 * 5 / 18 = 20 m / sec total distance covered = 110 + 134 = 244 m . required time = 244 / 20 = 12.2 sec . answer : b" | physics |
math_qa__f7FShCQc375ajBJS | What percent is 70 of 280? Pick one
A) 12 % B) 25 % C) 26 % D) 27 % E) 28 % | <gadget id="calculator">70 / 280</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>B</result> | B | 25 | What percent is 70 of 280? | {
"A": "12 %",
"B": "25 %",
"C": "26 %",
"D": "27 %",
"E": "28 %"
} | multiply(divide(70, 280), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "70 / 280 = 1 / 4 1 / 4 × 100 = 25 % b" | gain |
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