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math_qa__9676qfgGGQCQTI6i | One week, a certain truck rental lot had a total of 20 trucks, all of which were on the lot Monday morning. If 50% of the trucks that were rented out during the week were returned to the lot on or before Saturday morning of that week, and if there were at least 10 trucks on the lot that Saturday morning, what is the greatest number of different trucks that could have been rented out during the week? Choose the correct option: A) 18 B) 20 C) 12 D) 8 E) 4 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">20 * (1/2)</gadget>
<output>10</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<result>B</result> | B | 20 | One week, a certain truck rental lot had a total of 20 trucks, all of which were on the lot Monday morning. If 50% of the trucks that were rented out during the week were returned to the lot on or before Saturday morning of that week, and if there were at least 10 trucks on the lot that Saturday morning, what is the greatest number of different trucks that could have been rented out during the week? | {
"A": "18",
"B": "20",
"C": "12",
"D": "8",
"E": "4"
} | add(10, multiply(20, divide(50, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n2,#1)| | "n - not rented trucks ; r - rented trucks n + r = 20 n + r / 2 = 10 r = 20 b" | general |
math_qa__Wls4emnIm4761Acc | The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 47. The corrected new mean is? Choose the correct choice from the following answers:
A) 36.7
B) 36.1
C) 36.5
D) 36.02
E) 36.3 | <gadget id="calculator">36 * 50</gadget>
<output>1_800</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">48 - 47</gadget>
<output>1</output>
<gadget id="calculator">1_800 + 1</gadget>
<output>1_801</output>
<gadget id="calculator">1_801 / 50</gadget>
<output>1_801/50 = around 36.02</output>
<result>D</result> | D | 36.02 | The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 47. The corrected new mean is? | {
"A": "36.7",
"B": "36.1",
"C": "36.5",
"D": "36.02",
"E": "36.3"
} | divide(add(multiply(36, 50), subtract(subtract(50, const_2), 47)), 50) | multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,n3)|add(#0,#2)|divide(#3,n0)| | "correct sum = ( 36 * 50 + 48 - 47 ) = 1801 . correct mean = 1801 / 50 = 36.02 answer : d" | general |
math_qa__nZUmLczAcRppx8pU | hillary and eddy are climbing to the summit of mt . everest from a base camp 5000 ft from the summit . when they depart for the summit at 06 : 00 , hillary climbs at a rate of 800 ft / hr with eddy lagging behind at a slower rate of 500 ft / hr . if hillary stops 1000 ft short of the summit and then descends at a rate of 1000 ft / hr , at what time do hillary and eddy pass each other on her return trip ? Options:
A) 11.0
B) 12.0
C) 13.0
D) 14.0
E) 15.0 | <gadget id="calculator">5_000 - 1_000</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 / 800</gadget>
<output>5</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">11 + 1</gadget>
<output>12</output>
<result>B</result> | B | 12 | hillary and eddy are climbing to the summit of mt . everest from a base camp 5000 ft from the summit . when they depart for the summit at 06 : 00 , hillary climbs at a rate of 800 ft / hr with eddy lagging behind at a slower rate of 500 ft / hr . if hillary stops 1000 ft short of the summit and then descends at a rate of 1000 ft / hr , at what time do hillary and eddy pass each other on her return trip ? | {
"A": "11.0",
"B": "12.0",
"C": "13.0",
"D": "14.0",
"E": "15.0"
} | add(add(6, divide(subtract(5000, 1000), 800)), const_1) | subtract(n0,n5)|divide(#0,n3)|add(n1,#1)|add(#2,const_1) | solution : h stopped 1000 ft before reaching the final point , time taken to reach 4000 ft = 4000 / 800 = 5 hrs . this means she reached there at 11 : 00 . speed difference between them is 800 - 500 = 300 ft / hr so by the time h stops they have 1500 ft of distance so now here we use relative speed formula they both are travelling toward each other with speed of 1000 and 500 total 1500 ft / hr and distance bwn them is 1500 ft so time taken to meet = 1 hr from 11 : 00 means 12 : 00 is the answer . b | general |
math_qa__UdiMY5b4Cc1K9SeQ | $200 is divided amongst A,B and C so that A may get 2/3 as much as B and C together, B may get 6/9 as much as A and C together, then the share of A is Choose the correct choice from the following options.
A) $ 80 B) $ 50 C) $ 25 D) $ 200 E) $ 50 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) + 1</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">200 / (5/3)</gadget>
<output>120</output>
<gadget id="calculator">120 * (2/3)</gadget>
<output>80</output>
<result>A</result> | A | 80 | $200 is divided amongst A,B and C so that A may get 2/3 as much as B and C together, B may get 6/9 as much as A and C together, then the share of A is | {
"A": "$ 80",
"B": "$ 50",
"C": "$ 25",
"D": "$ 200",
"E": "$ 50"
} | multiply(divide(200, add(divide(2, 3), const_1)), divide(2, 3)) | divide(n1,n2)|add(#0,const_1)|divide(n0,#1)|multiply(#2,#0)| | "a : ( b + c ) = 2 : 3 a ' s share = 200 * 2 / 5 = $ 80 answer is a" | general |
math_qa__9bvSXiupNyHMaAWv | The base of a right triangle is 8 and hypotenuse is 10. Its area is? Choices.
A) 12
B) 80
C) 59
D) 24
E) 25 | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">8 * 8</gadget>
<output>64</output>
<gadget id="calculator">100 - 64</gadget>
<output>36</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<result>D</result> | D | 24 | The base of a right triangle is 8 and hypotenuse is 10. Its area is? | {
"A": "12",
"B": "80",
"C": "59",
"D": "24",
"E": "25"
} | divide(multiply(sqrt(subtract(multiply(10, 10), multiply(8, 8))), 8), const_2) | multiply(n1,n1)|multiply(n0,n0)|subtract(#0,#1)|sqrt(#2)|multiply(n0,#3)|divide(#4,const_2) | explanation : h 2 = ( 10 ) 2 - ( 8 ) 2 - ( 6 ) 2 - > h = 6 1 / 2 * 8 * 6 = 24 answer is d | geometry |
math_qa__LSX7ldBg9ZDRxpS2 | Jack and Jill work at a hospital with 3 other workers. For an internal review, 2 of the 5 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen? Pick:
A) 1 / 3 B) 1 / 10 C) 1 / 15 D) 3 / 8 E) 2 / 3 | <gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">120 / 12</gadget>
<output>10</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<result>B</result> | B | 0.1 | Jack and Jill work at a hospital with 3 other workers. For an internal review, 2 of the 5 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen? | {
"A": "1 / 3",
"B": "1 / 10",
"C": "1 / 15",
"D": "3 / 8",
"E": "2 / 3"
} | inverse(divide(factorial(5), multiply(factorial(2), factorial(3)))) | factorial(n2)|factorial(n1)|factorial(n0)|multiply(#1,#2)|divide(#0,#3)|inverse(#4) | 1 / 5 c 2 = 1 / 10 . answer : b . | physics |
math_qa__KvIO9YuvKIQZBYCh | A river 2m deep and 45 m wide is flowing at the rate of 4 kmph the amount of water that runs into the sea per minute is?
Choices:
A) 6000 m 3
B) 4580 m 3
C) 18500 m 3
D) 4900 m 3
E) 4700 m 3 | <gadget id="calculator">2 * 45</gadget>
<output>90</output>
<gadget id="calculator">4 * 1_000</gadget>
<output>4_000</output>
<gadget id="calculator">90 * 4_000</gadget>
<output>360_000</output>
<gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">360_000 / 60</gadget>
<output>6_000</output>
<result>A</result> | A | 6,000 | A river 2m deep and 45 m wide is flowing at the rate of 4 kmph the amount of water that runs into the sea per minute is? | {
"A": "6000 m 3",
"B": "4580 m 3",
"C": "18500 m 3",
"D": "4900 m 3",
"E": "4700 m 3"
} | divide(multiply(multiply(2, 45), multiply(4, const_1000)), multiply(const_1, const_60)) | multiply(n0,n1)|multiply(n2,const_1000)|multiply(const_1,const_60)|multiply(#0,#1)|divide(#3,#2)| | "explanation : ( 4000 * 2 * 45 ) / 60 = 6000 m 3 answer : option a" | physics |
math_qa__MURngsUIYMxmdZ7a | A sum of $1000 amounts to $1500 in 5 years at simple interest. If the interest rate is increased by 5% it would amount to how much ? Choose the correct answer:
A) $ 1000
B) $ 750
C) $ 1541
D) $ 1478
E) $ 1750 | <gadget id="calculator">1_500 - 1_000</gadget>
<output>500</output>
<gadget id="calculator">500 / 5</gadget>
<output>100</output>
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 1_000</gadget>
<output>10</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1_000 * (3/20)</gadget>
<output>150</output>
<gadget id="calculator">150 * 5</gadget>
<output>750</output>
<gadget id="calculator">1_000 + 750</gadget>
<output>1_750</output>
<result>E</result> | E | 1,750 | A sum of $1000 amounts to $1500 in 5 years at simple interest. If the interest rate is increased by 5% it would amount to how much ? | {
"A": "$ 1000",
"B": "$ 750",
"C": "$ 1541",
"D": "$ 1478",
"E": "$ 1750"
} | add(1000, multiply(multiply(1000, divide(add(divide(multiply(divide(subtract(1500, 1000), 5), const_100), 1000), 5), const_100)), 5)) | subtract(n1,n0)|divide(#0,n2)|multiply(#1,const_100)|divide(#2,n0)|add(n2,#3)|divide(#4,const_100)|multiply(n0,#5)|multiply(n2,#6)|add(n0,#7)| | "s . i = 1500 - 1000 = 500 p = $ 1000 t = 5 years r = 100 * 500 / 1000 * 5 = 10 % new rate = 10 + 5 = 15 % new s . i . = 1000 * 15 * 5 / 100 = $ 750 new amount = 1000 + 750 = $ 1750 answer is e" | gain |
math_qa__HCFnX6EYSlDCnXT7 | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.3 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is: Choose the correct option
A) 2 : 5 B) 2 : 3 C) 2 : 4 D) 4 : 5 E) 2 : 9 | <gadget id="calculator">15.8 - 15.4</gadget>
<output>0.4</output>
<gadget id="calculator">16.3 - 15.8</gadget>
<output>0.5</output>
<gadget id="calculator">0.4 / 0.5</gadget>
<output>0.8</output>
<result>D</result> | D | 0.8 | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.3 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is: | {
"A": "2 : 5",
"B": "2 : 3",
"C": "2 : 4",
"D": "4 : 5",
"E": "2 : 9"
} | divide(subtract(15.8, 15.4), subtract(16.3, 15.8)) | subtract(n0,n2)|subtract(n1,n0)|divide(#0,#1)| | "let the ratio be k : 1 . then , k * 16.3 + 1 * 15.4 = ( k + 1 ) * 15.8 = ( 16.3 - 15.8 ) k = ( 15.8 - 15.4 ) = k = 0.4 / 0.5 = 4 / 5 required ratio = 4 / 5 : 1 = 4 : 5 . answer : d" | general |
math_qa__FQmyOr9JJWEVtsGM | A man whose bowling average is 12.4, takes 8 wickets for 26 runs and there by decreases his average by 0.4. the number of wickets taken by him before his last match is? Choose the correct choice from the following answers: A) 173 B) 174 C) 175 D) 176 E) 177 | <gadget id="calculator">floor(12.4)</gadget>
<output>12</output>
<gadget id="calculator">12 * 8</gadget>
<output>96</output>
<gadget id="calculator">96 - 26</gadget>
<output>70</output>
<gadget id="calculator">12.4 - 12</gadget>
<output>0.4</output>
<gadget id="calculator">70 / 0.4</gadget>
<output>175</output>
<result>C</result> | C | 175 | A man whose bowling average is 12.4, takes 8 wickets for 26 runs and there by decreases his average by 0.4. the number of wickets taken by him before his last match is? | {
"A": "173",
"B": "174",
"C": "175",
"D": "176",
"E": "177"
} | divide(subtract(multiply(floor(12.4), 8), 26), subtract(12.4, floor(12.4))) | floor(n0)|multiply(n1,#0)|subtract(n0,#0)|subtract(#1,n2)|divide(#3,#2)| | "12.4 * x + 26 = ( 8 + x ) 12 solve equation x = 175 answer : c" | general |
math_qa__0HRI39UzL9HsBRt7 | A number when divided by 342 gives a remainder 47.When the same
number is divided by 19 what would be the remainder? Pick one.
A) 0 B) 9 C) 19 D) 29 E) 18 | <gadget id="calculator">47 % 19</gadget>
<output>9</output>
<result>B</result> | B | 9 | A number when divided by 342 gives a remainder 47.When the same
number is divided by 19 what would be the remainder? | {
"A": "0",
"B": "9",
"C": "19",
"D": "29",
"E": "18"
} | reminder(47, 19) | reminder(n1,n2) | number = 342 k + 47 = 19 * 18 k + 19 * 2 + 9 = 19 ( 18 k + 2 ) + 9 . the given number when divided by 19 gives 18 k + 2 as quotient and 9 as remainder . answer b 9 | general |
math_qa__XRsA7aCDQBfZ5WV6 | A, B and C enter into a partnership by investing $7000, $11000 and $18000 respectively. At the end of 8 months, B receives $2200 as his share. Find the share of A. Select the correct option:
A) $ 1200 B) $ 1300 C) $ 1400 D) $ 1500 E) $ 1600 | <gadget id="calculator">11_000 * 8</gadget>
<output>88_000</output>
<gadget id="calculator">88_000 / 100</gadget>
<output>880</output>
<gadget id="calculator">2_200 / 880</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">7_000 * (5/2)</gadget>
<output>17_500</output>
<gadget id="calculator">17_500 * 8</gadget>
<output>140_000</output>
<gadget id="calculator">140_000 / 100</gadget>
<output>1_400</output>
<result>C</result> | C | 1,400 | A, B and C enter into a partnership by investing $7000, $11000 and $18000 respectively. At the end of 8 months, B receives $2200 as his share. Find the share of A. | {
"A": "$ 1200",
"B": "$ 1300",
"C": "$ 1400",
"D": "$ 1500",
"E": "$ 1600"
} | divide(multiply(multiply(7000, divide(2200, divide(multiply(11000, 8), const_100))), 8), const_100) | multiply(n1,n3)|divide(#0,const_100)|divide(n4,#1)|multiply(n0,#2)|multiply(n3,#3)|divide(#4,const_100)| | "the ratio of capital of a , b and c = 7000 : 11000 : 18000 = 7 : 11 : 18 a ' s share = ( 7 / 11 ) * 2200 = $ 1400 the answer is c ." | gain |
math_qa__kEvtagsthvGoK7Ok | If 40% of a certain number is 160, then what is 10% of that number? Choose the correct option.
A) 100 B) 40 C) 80 D) 120 E) 110 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">160 / (2/5)</gadget>
<output>400</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">400 * (1/10)</gadget>
<output>40</output>
<result>B</result> | B | 40 | If 40% of a certain number is 160, then what is 10% of that number? | {
"A": "100",
"B": "40",
"C": "80",
"D": "120",
"E": "110"
} | multiply(divide(160, divide(40, const_100)), divide(10, const_100)) | divide(n0,const_100)|divide(n2,const_100)|divide(n1,#0)|multiply(#2,#1) | explanation : 40 % = 40 * 4 = 160 10 % = 10 * 4 = 40 answer : option b | gain |
math_qa__NA9vFoPT4GUTsRcn | A man took loan from a bank at the rate of 12% p.a. S.I. After 20 years he had to pay Rs. 2100 interest only for the period. The principal amount borrowed by him was?
Select
A) 600 B) 715 C) 600 D) 875 E) 900 | <gadget id="calculator">2_100 * 100</gadget>
<output>210_000</output>
<gadget id="calculator">210_000 / 20</gadget>
<output>10_500</output>
<gadget id="calculator">10_500 / 12</gadget>
<output>875</output>
<result>D</result> | D | 875 | A man took loan from a bank at the rate of 12% p.a. S.I. After 20 years he had to pay Rs. 2100 interest only for the period. The principal amount borrowed by him was? | {
"A": "600",
"B": "715",
"C": "600",
"D": "875",
"E": "900"
} | divide(divide(multiply(2100, const_100), 20), 12) | multiply(n2,const_100)|divide(#0,n1)|divide(#1,n0)| | "principal = ( 100 * 2100 ) / ( 12 * 20 ) = rs . 875 answer : d" | gain |
math_qa__blmT5rLWNkvS3alb | The average (arithmetic mean) of 24, 35, and 58 is 6 more than the average of 19, 51, and x. What is x?
Choose the correct choice from the following answers
A) 26 B) 27 C) 28 D) 29 E) 30 | <gadget id="calculator">24 + 35</gadget>
<output>59</output>
<gadget id="calculator">59 + 58</gadget>
<output>117</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 + 19</gadget>
<output>37</output>
<gadget id="calculator">37 + 51</gadget>
<output>88</output>
<gadget id="calculator">117 - 88</gadget>
<output>29</output>
<result>D</result> | D | 29 | The average (arithmetic mean) of 24, 35, and 58 is 6 more than the average of 19, 51, and x. What is x? | {
"A": "26",
"B": "27",
"C": "28",
"D": "29",
"E": "30"
} | subtract(add(add(24, 35), 58), add(add(multiply(6, const_3), 19), 51)) | add(n0,n1)|multiply(n3,const_3)|add(n2,#0)|add(n4,#1)|add(n5,#3)|subtract(#2,#4)| | "the average of 24 , 35 , and 58 is 39 . the average of 19 , 51 and x is 33 . then 19 + 51 + x = 99 . x = 29 . the answer is d ." | general |
math_qa__ZOU7j32pgw8xIFab | Instead of multiplying a number by 5, the number is divided by 5. What is the percentage of error obtained ? Choose the most appropriate option.
A) 98 %
B) 97 %
C) 96 %
D) 99 %
E) 95 % | <gadget id="calculator">5 / 5</gadget>
<output>1</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) * 100</gadget>
<output>4</output>
<gadget id="calculator">100 - 4</gadget>
<output>96</output>
<result>C</result> | C | 96 | Instead of multiplying a number by 5, the number is divided by 5. What is the percentage of error obtained ? | {
"A": "98 %",
"B": "97 %",
"C": "96 %",
"D": "99 %",
"E": "95 %"
} | subtract(const_100, multiply(divide(divide(5, 5), multiply(5, 5)), const_100)) | divide(n1,n1)|multiply(n0,n1)|divide(#0,#1)|multiply(#2,const_100)|subtract(const_100,#3)| | "let the number be x the right number is 5 x the wrong number is x / 5 error is ( 5 x - x / 5 ) = 24 x / 5 percentage of error is ( ( 24 x / 5 ) / 5 x ) * 100 = 96 % answer : c" | general |
math_qa__oUgR33NZowhSV0L2 | A person crosses a 600 m long street in 5 minutes, What is his speed in km per hour? Choose the correct choice from the following options
A) 4.3 B) 7.2 C) 2.3 D) 3.2 E) 1.1 | <gadget id="calculator">600 / 1_000</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">5 * 60</gadget>
<output>300</output>
<gadget id="calculator">300 / 3_600</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(3/5) / (1/12)</gadget>
<output>36/5 = around 7.2</output>
<result>B</result> | B | 7.2 | A person crosses a 600 m long street in 5 minutes, What is his speed in km per hour? | {
"A": "4.3",
"B": "7.2",
"C": "2.3",
"D": "3.2",
"E": "1.1"
} | divide(divide(600, const_1000), divide(multiply(5, const_60), const_3600)) | divide(n0,const_1000)|multiply(n1,const_60)|divide(#1,const_3600)|divide(#0,#2)| | "explanation : speed = { \ color { blue } \ left ( \ frac { 600 } { 5 \ times 60 } \ right ) m / sec = 2 m / sec = \ left ( 2 \ times \ frac { 18 } { 5 } \ right ) km / hr = 7.2 km / hr } answer : b" | physics |
math_qa__oi0G07LA29uEGUEv | The length of a train and that of a platform are equal. If with a speed of 72 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is? Choose the correct choice from the following choices:
A) 299
B) 266
C) 299
D) 750
E) 600 | <gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">60 / 1</gadget>
<output>60</output>
<gadget id="calculator">72_000 / 60</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 2</gadget>
<output>600</output>
<result>E</result> | E | 600 | The length of a train and that of a platform are equal. If with a speed of 72 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is? | {
"A": "299",
"B": "266",
"C": "299",
"D": "750",
"E": "600"
} | divide(divide(multiply(72, const_1000), divide(const_60, const_1)), const_2) | divide(const_60,const_1)|multiply(n0,const_1000)|divide(#1,#0)|divide(#2,const_2)| | "speed = [ 72 * 5 / 18 ] m / sec = 20 m / sec ; time = 1 min . = 60 sec . let the length of the train and that of the platform be x meters . then , 2 x / 60 = 20 = > x = 20 * 60 / 2 = 600 answer : e" | physics |
math_qa__RmFUUsaSsNEOocAq | Square A has an area of 81 square centimeters. Square B has a perimeter of 32 centimeters. If square B is placed within square A and a random point is chosen within square A, what is the probability the point is not within square B? Select the correct option:
A) 17 / 64
B) 17 / 81
C) 16 / 25
D) 3 / 5
E) 6 / 25 | <gadget id="calculator">32 / 4</gadget>
<output>8</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">81 - 64</gadget>
<output>17</output>
<gadget id="calculator">17 / 81</gadget>
<output>17/81 = around 0.209877</output>
<result>B</result> | B | 0.209877 | Square A has an area of 81 square centimeters. Square B has a perimeter of 32 centimeters. If square B is placed within square A and a random point is chosen within square A, what is the probability the point is not within square B? | {
"A": "17 / 64",
"B": "17 / 81",
"C": "16 / 25",
"D": "3 / 5",
"E": "6 / 25"
} | divide(subtract(81, power(divide(32, const_4), const_2)), 81) | divide(n1,const_4)|power(#0,const_2)|subtract(n0,#1)|divide(#2,n0) | i guess it ' s mean that square b is placed within square aentirely . since , the perimeter of b is 32 , then its side is 32 / 4 = 8 and the area is 4 ^ 2 = 64 ; empty space between the squares is 81 - 64 = 17 square centimeters , so if a random point is in this area then it wo n ' t be within square b : p = favorable / total = 17 / 81 . answer : b | geometry |
math_qa__zt7MuJcoVbjYt02y | One hour after Yolanda started walking from X to Y, a distance of 60 miles, Bob started walking along the same road from Y to X. If Yolandaâs walking rate was 5 miles per hour and Bobâs was 6 miles per hour, how many miles had Bob walked when they met? Choose the correct option.
A) 40
B) 25
C) 28
D) 30
E) 30.5 | <gadget id="calculator">60 - 5</gadget>
<output>55</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">55 / 11</gadget>
<output>5</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<result>D</result> | D | 30 | One hour after Yolanda started walking from X to Y, a distance of 60 miles, Bob started walking along the same road from Y to X. If Yolandaâs walking rate was 5 miles per hour and Bobâs was 6 miles per hour, how many miles had Bob walked when they met? | {
"A": "40",
"B": "25",
"C": "28",
"D": "30",
"E": "30.5"
} | multiply(divide(subtract(60, 5), add(5, 6)), 6) | add(n1,n2)|subtract(n0,n1)|divide(#1,#0)|multiply(n2,#2)| | "let t be the number of hours that bob had walked when he met yolanda . then , when they met , bob had walked 4 t miles and yolanda had walked 5 ( t + 1 ) miles . these distances must sum to 60 miles , so 6 t + 5 ( t + 1 ) = 60 , which may be solved for t as follows 6 t + 5 ( t + 1 ) = 60 6 t + 5 t + 5 = 60 11 t = 55 t = 5 ( hours ) therefore , bob had walked 6 t = 6 ( 5 ) = 30 miles when they met . the best answer is d ." | physics |
math_qa__Piw6CFWaDShBF7LB | in a class of 25 students, 15 play hockey and 16 play basketball. if there are 4 students who play neither sport, determine the number of students who play both hockey and basketball? Choose the correct choice from the following options.
A) 10 B) 11 C) 13 D) 14 E) 15 | <gadget id="calculator">15 + 16</gadget>
<output>31</output>
<gadget id="calculator">25 - 4</gadget>
<output>21</output>
<gadget id="calculator">31 - 21</gadget>
<output>10</output>
<result>A</result> | A | 10 | in a class of 25 students, 15 play hockey and 16 play basketball. if there are 4 students who play neither sport, determine the number of students who play both hockey and basketball? | {
"A": "10",
"B": "11",
"C": "13",
"D": "14",
"E": "15"
} | subtract(add(15, 16), subtract(25, 4)) | add(n1,n2)|subtract(n0,n3)|subtract(#0,#1) | let the number of who play both be x number of students who play sports 25 - 4 = 21 use venn diagram ( 15 - x ) + x + ( 16 - x ) = 21 which gives x = 10 answer is a 10 play both sport | other |
math_qa__P14wFs9Zcb8XCz2J | What is the difference between 80% of 170 and 35% of 300. Options
A) 30 B) 29 C) 37 D) 36 E) 31 | <gadget id="calculator">80 * 170</gadget>
<output>13_600</output>
<gadget id="calculator">13_600 / 100</gadget>
<output>136</output>
<gadget id="calculator">35 * 300</gadget>
<output>10_500</output>
<gadget id="calculator">10_500 / 100</gadget>
<output>105</output>
<gadget id="calculator">136 - 105</gadget>
<output>31</output>
<result>E</result> | E | 31 | What is the difference between 80% of 170 and 35% of 300. | {
"A": "30",
"B": "29",
"C": "37",
"D": "36",
"E": "31"
} | subtract(divide(multiply(80, 170), const_100), divide(multiply(35, 300), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|subtract(#2,#3)| | "( 80 / 100 ) * 170 â € “ ( 35 / 100 ) * 300 136 - 105 = 31 answer : e" | gain |
math_qa__oNgZrL5stYqIq3Xe | A car travels first 160 km at 90 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour? Options: A) 71.11 B) 84.7 C) 71.1 D) 71.17 E) 71.13 | <gadget id="calculator">160 / 90</gadget>
<output>16/9 = around 1.777778</output>
<gadget id="calculator">160 / 80</gadget>
<output>2</output>
<gadget id="calculator">(16/9) + 2</gadget>
<output>34/9 = around 3.777778</output>
<gadget id="calculator">1 / (34/9)</gadget>
<output>9/34 = around 0.264706</output>
<gadget id="calculator">320 * (9/34)</gadget>
<output>1_440/17 = around 84.705882</output>
<result>B</result> | B | 84.7 | A car travels first 160 km at 90 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour? | {
"A": "71.11",
"B": "84.7",
"C": "71.1",
"D": "71.17",
"E": "71.13"
} | multiply(320, divide(const_1, add(divide(160, 90), divide(160, 80)))) | divide(n0,n1)|divide(n0,n3)|add(#0,#1)|divide(const_1,#2)|multiply(n4,#3)| | "car travels first 160 km at 90 km / hr time taken to travel first 160 km = distancespeed = 160 / 90 car travels next 160 km at 80 km / hr time taken to travel next 160 km = distancespeed = 160 / 80 total distance traveled = 160 + 160 = 2 × 160 total time taken = 160 / 90 + 160 / 80 average speed = total distance traveled / total time taken = 320 / ( 160 / 90 + 160 / 80 ) = 84.7 km / hr answer : b" | general |
math_qa__ifw5WhUpeysSk6Vy | A water tank which could be filled in 5 hours takes one more hour to be filled as a result of a leak in its bottom. If the tank is full calculate the time it will take for the leak empty it? Choose the correct answer.
A) 32 hours
B) 30 hours
C) 34 hours
D) 31 hours
E) 33 hours | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">5 / (1/6)</gadget>
<output>30</output>
<result>B</result> | B | 30 | A water tank which could be filled in 5 hours takes one more hour to be filled as a result of a leak in its bottom. If the tank is full calculate the time it will take for the leak empty it? | {
"A": "32 hours",
"B": "30 hours",
"C": "34 hours",
"D": "31 hours",
"E": "33 hours"
} | divide(5, divide(const_1, add(5, const_1))) | add(n0,const_1)|divide(const_1,#0)|divide(n0,#1) | part filled without leak in 1 hour = 1 / 5 part filled with leak in 1 hour = 1 / 6 work done by leak in 1 hour = 1 / 5 â ˆ ’ 1 / 6 = 30 hours answer : b | physics |
math_qa__MnD9G0ZIdqPqZgjE | Country X taxes each of its citizens an amount equal to 10 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income? Choose the correct option.
A) $ 40,000 B) $ 56,000 C) $ 60,000 D) $ 66,667 E) $ 80,000 | <gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 * 1_000</gadget>
<output>40_000</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 1_000</gadget>
<output>8_000</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 40_000</gadget>
<output>4_000</output>
<gadget id="calculator">8_000 - 4_000</gadget>
<output>4_000</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">4_000 / (1/5)</gadget>
<output>20_000</output>
<gadget id="calculator">40_000 + 20_000</gadget>
<output>60_000</output>
<result>C</result> | C | 60,000 | Country X taxes each of its citizens an amount equal to 10 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income? | {
"A": "$ 40,000",
"B": "$ 56,000",
"C": "$ 60,000",
"D": "$ 66,667",
"E": "$ 80,000"
} | add(multiply(multiply(const_4, const_10), const_1000), divide(subtract(multiply(multiply(const_4, const_2), const_1000), multiply(divide(10, const_100), multiply(multiply(const_4, const_10), const_1000))), divide(20, const_100))) | divide(n0,const_100)|divide(n2,const_100)|multiply(const_2,const_4)|multiply(const_10,const_4)|multiply(#2,const_1000)|multiply(#3,const_1000)|multiply(#0,#5)|subtract(#4,#6)|divide(#7,#1)|add(#8,#5)| | "equation is correct , so math must be a problem . 0.10 * 40,000 + 0.2 * ( x - 40,000 ) = 8,000 - - > 4,000 + 0.2 x - 8,000 = 8,000 - - > 0.2 x = 12,000 - - > x = 60,000 . answer : c ." | general |
math_qa__Q7nPdifslfSXJC0n | Two trains of length 100 m and 200 m are 70 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet? Answers:
A) 2 sec B) 32 / 3 sec C) 20 / 7 sec D) 32 / 3 sec E) 53 / 2 sec | <gadget id="calculator">54 + 72</gadget>
<output>126</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">126 * (5/18)</gadget>
<output>35</output>
<gadget id="calculator">70 / 35</gadget>
<output>2</output>
<result>A</result> | A | 2 | Two trains of length 100 m and 200 m are 70 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet? | {
"A": "2 sec",
"B": "32 / 3 sec",
"C": "20 / 7 sec",
"D": "32 / 3 sec",
"E": "53 / 2 sec"
} | divide(70, multiply(add(54, 72), const_0_2778)) | add(n3,n4)|multiply(#0,const_0_2778)|divide(n2,#1)| | "they are moving in opposite directions , relative speed is equal to the sum of their speeds . relative speed = ( 54 + 72 ) * 5 / 18 = 7 * 5 = 35 mps . the time required = d / s = 70 / 35 = 2 sec . answer : a" | physics |
math_qa__GSxRLKIiDTkm4lWR | The area of a rectangular plot is 24 times its breadth. If the difference between the length and the breadth is 10 metres, what is its breadth? Choose the correct choice from the following options:
A) 14 metres B) 5 metres C) 7.5 metres D) data inadequate E) none of these | <gadget id="calculator">24 - 10</gadget>
<output>14</output>
<result>A</result> | A | 14 | The area of a rectangular plot is 24 times its breadth. If the difference between the length and the breadth is 10 metres, what is its breadth? | {
"A": "14 metres",
"B": "5 metres",
"C": "7.5 metres",
"D": "data inadequate",
"E": "none of these"
} | subtract(24, 10) | subtract(n0,n1) | l × b = 24 × b ∴ l = 24 m and l – b = 10 ∴ b = 24 – 10 = 14 m answer a | geometry |
math_qa__gjGFsXEnqa4HWoxj | Peter's average (arithmetic mean) test score on 4 tests is 78. What must be the student's score on a 5th test for the Peter's average score on the 5 tests to be 80? Pick:
A) 80 B) 82 C) 84 D) 86 E) 88 | <gadget id="calculator">5 * 80</gadget>
<output>400</output>
<gadget id="calculator">4 * 78</gadget>
<output>312</output>
<gadget id="calculator">400 - 312</gadget>
<output>88</output>
<result>E</result> | E | 88 | Peter's average (arithmetic mean) test score on 4 tests is 78. What must be the student's score on a 5th test for the Peter's average score on the 5 tests to be 80? | {
"A": "80",
"B": "82",
"C": "84",
"D": "86",
"E": "88"
} | subtract(multiply(5, 80), multiply(4, 78)) | multiply(n2,n4)|multiply(n0,n1)|subtract(#0,#1) | e . 88 peter must score at least an 80 for sure . if he scores an 8 , then he will need to score 2 pots for each of the 4 other tests tomake upthe difference . they each were at 78 ( at least the average is , but this is a small point and does n ' t matter to the answer ) . so 4 tests that were each 2 points short of the 80 average that is desired means the next test must be 8 points higher than the desired average , so 80 + 8 = 88 . | general |
math_qa__GInkDKjAdZONnx92 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 14 sec. What is the length of the platform? Choose the correct choice from the following choices
A) 287 m B) 350 m C) 267 m D) 535.71 m E) 656 m | <gadget id="calculator">300 / 14</gadget>
<output>150/7 = around 21.428571</output>
<gadget id="calculator">(150/7) * 39</gadget>
<output>5_850/7 = around 835.714286</output>
<gadget id="calculator">(5_850/7) - 300</gadget>
<output>3_750/7 = around 535.714286</output>
<result>D</result> | D | 535.71 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 14 sec. What is the length of the platform? | {
"A": "287 m",
"B": "350 m",
"C": "267 m",
"D": "535.71 m",
"E": "656 m"
} | subtract(multiply(speed(300, 14), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 14 = 150 / 7 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 150 / 7 = > x = 535.71 m . answer : d" | physics |
math_qa__uS50vgkV3H5rN2Cq | A type of extra-large SUV averages 12.2 miles per gallon (mpg) on the highway, but only 7.6 mpg in the city. What is the maximum distance, in miles, that this SUV could be driven on 21 gallons of gasoline? Choose the correct choice from the following choices:
A) 190 B) 284.6 C) 300 D) 256 E) 312 | <gadget id="calculator">12.2 * 21</gadget>
<output>256.2</output>
<result>D</result> | D | 256 | A type of extra-large SUV averages 12.2 miles per gallon (mpg) on the highway, but only 7.6 mpg in the city. What is the maximum distance, in miles, that this SUV could be driven on 21 gallons of gasoline? | {
"A": "190",
"B": "284.6",
"C": "300",
"D": "256",
"E": "312"
} | multiply(12.2, 21) | multiply(n0,n2)| | "so 12.2 * 21 = 256 . . imo option d is correct answer . ." | general |
math_qa__qN9ZusaP9ZducBcg | Find the 15th term of an arithmetic progression whose first term is 2 and the common difference is 3.
Select
A) 45 B) 38 C) 44 D) 40 E) 46 | <gadget id="calculator">15 - 1</gadget>
<output>14</output>
<gadget id="calculator">14 * 3</gadget>
<output>42</output>
<gadget id="calculator">42 + 2</gadget>
<output>44</output>
<result>C</result> | C | 44 | Find the 15th term of an arithmetic progression whose first term is 2 and the common difference is 3. | {
"A": "45",
"B": "38",
"C": "44",
"D": "40",
"E": "46"
} | add(multiply(subtract(15, const_1), 3), 2) | subtract(n0,const_1)|multiply(n2,#0)|add(n1,#1)| | "n th term of a . p = a + ( n - 1 ) * d = 2 + ( 15 - 1 ) * 3 , = 2 + 42 = 44 . answer : c" | general |
math_qa__bRiZm5jGbjen7fSo | A fill pipe can fill 1/2 of cistern in 15 minutes. In how many minutes, it can fill 1/2 of the cistern? Choose the correct option.
A) 1 min B) 5 min C) 10 min D) 15 min E) 20 min | <gadget id="calculator">15 / 1</gadget>
<output>15</output>
<result>D</result> | D | 15 | A fill pipe can fill 1/2 of cistern in 15 minutes. In how many minutes, it can fill 1/2 of the cistern? | {
"A": "1 min",
"B": "5 min",
"C": "10 min",
"D": "15 min",
"E": "20 min"
} | divide(15, 1) | divide(n2,n0)| | "required time = 15 * 2 * 1 / 2 = 15 minutes answer is d" | physics |
math_qa__N7niaVWDWJiJ3o4n | A train passes a platform in 30 seconds. The same train passes a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, The length of the platform is Choices
A) 150 meter
B) 240 meter
C) 200 meter
D) 260 meter
E) none of these | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 54</gadget>
<output>15</output>
<gadget id="calculator">30 - 20</gadget>
<output>10</output>
<gadget id="calculator">15 * 10</gadget>
<output>150</output>
<result>A</result> | A | 150 | A train passes a platform in 30 seconds. The same train passes a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, The length of the platform is | {
"A": "150 meter",
"B": "240 meter",
"C": "200 meter",
"D": "260 meter",
"E": "none of these"
} | multiply(multiply(const_0_2778, 54), subtract(30, 20)) | multiply(n2,const_0_2778)|subtract(n0,n1)|multiply(#0,#1)| | "explanation : speed of the train = 54 km / hr = ( 54 × 10 ) / 30 m / s = 15 m / s length of the train = speed × time taken to cross the man = 15 × 20 = 300 m let the length of the platform = l time taken to cross the platform = ( 300 + l ) / 15 = > ( 300 + l ) / 15 = 30 = > 300 + l = 15 × 30 = 450 = > l = 450 - 300 = 150 meter answer : option a" | physics |
math_qa__UuacODYD6lIIY3Ye | Kiran has 85 currency notes in all, some of which were of Rs. 100 denomination and the remaining of Rs. 50 denomination. The total amount of all these currency notes was Rs.5000. How much amount did she have in the denomination of Rs. 50? Answers: A) 1900 B) 3500 C) 4000 D) 4200 E) 4450 | <gadget id="calculator">50 * 85</gadget>
<output>4_250</output>
<gadget id="calculator">5_000 - 4_250</gadget>
<output>750</output>
<gadget id="calculator">750 / 50</gadget>
<output>15</output>
<gadget id="calculator">85 - 15</gadget>
<output>70</output>
<gadget id="calculator">70 * 50</gadget>
<output>3_500</output>
<result>B</result> | B | 3,500 | Kiran has 85 currency notes in all, some of which were of Rs. 100 denomination and the remaining of Rs. 50 denomination. The total amount of all these currency notes was Rs.5000. How much amount did she have in the denomination of Rs. 50? | {
"A": "1900",
"B": "3500",
"C": "4000",
"D": "4200",
"E": "4450"
} | multiply(subtract(85, divide(subtract(5000, multiply(50, 85)), 50)), 50) | multiply(n0,n2)|subtract(n3,#0)|divide(#1,n2)|subtract(n0,#2)|multiply(n2,#3)| | "let the number of 50 – rupee notes be x . then , the number of 100 - rupee notes = ( 85 – x ) 50 x + 100 ( 85 – x ) = 5000 = x + 2 ( 85 – x ) = 100 = x = 70 so , required amount = rs . ( 50 x 70 ) = rs . 3500 answer : option b" | general |
math_qa__kmdB4ryz6sz17HZR | A 250 meter long train crosses a platform in 40 seconds while it crosses a signal pole in 20 seconds. What is the length of the platform?
Choose the most appropriate option
A) 500
B) 1000
C) 350
D) 250
E) 20 | <gadget id="calculator">250 / 20</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 40</gadget>
<output>500</output>
<gadget id="calculator">500 - 250</gadget>
<output>250</output>
<result>D</result> | D | 250 | A 250 meter long train crosses a platform in 40 seconds while it crosses a signal pole in 20 seconds. What is the length of the platform? | {
"A": "500",
"B": "1000",
"C": "350",
"D": "250",
"E": "20"
} | subtract(multiply(divide(250, 20), 40), 250) | divide(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = [ 250 / 20 ] m / sec = 25 / 2 m / sec . let the length of the platform be x meters . then , x + 250 / 40 = 25 / 2 2 ( x + 250 ) = 1000 è x = 250 m . answer : d" | physics |
math_qa__hHycfv33qY8I5HB0 | in a 4 person race , medals are awarded to the fastest 3 runners . the first - place runner receives a gold medal , the second - place runner receives a silver medal , and the third - place runner receives a bronze medal . in the event of a tie , the tied runners receive the same color medal . ( for example , if there is a two - way tie for first - place , the top two runners receive gold medals , the next - fastest runner receives a silver medal , and no bronze medal is awarded ) . assuming that exactly 3 medals are awarded , and that the 3 medal winners stand together with their medals to form a victory circle , how many different victory circles are possible ? Pick one: A) 24 B) 52 C) 96 D) 144 E) 648 | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">24 * 4</gadget>
<output>96</output>
<result>C</result> | C | 96 | in a 4 person race , medals are awarded to the fastest 3 runners . the first - place runner receives a gold medal , the second - place runner receives a silver medal , and the third - place runner receives a bronze medal . in the event of a tie , the tied runners receive the same color medal . ( for example , if there is a two - way tie for first - place , the top two runners receive gold medals , the next - fastest runner receives a silver medal , and no bronze medal is awarded ) . assuming that exactly 3 medals are awarded , and that the 3 medal winners stand together with their medals to form a victory circle , how many different victory circles are possible ? | {
"A": "24",
"B": "52",
"C": "96",
"D": "144",
"E": "648"
} | multiply(factorial(4), 4) | factorial(n0)|multiply(n0,#0) | gold can be awarded in 4 ways , then silver can be awarded in 3 ways and bronze in 2 ways . therefore the total number of ways are : 4 * 3 * 2 = 24 ways of awarding the medals and the same number of ways of forming the circle . this is when there is no tie . and if there is tie , for example all three receive the gold or the silver or the bronze , then there are 4 more cases . which implies 24 * 4 = 96 . ans : c | general |
math_qa__ZZdFgRtbjVa1xLqW | A goods train runs at the speed of 72 kmph and crosses a 350 m long platform in 26 seconds. What is the length of the goods train? Choose the correct choice
A) 230 m B) 140 m C) 160 m D) 170 m E) none of these | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 72</gadget>
<output>20</output>
<gadget id="calculator">350 / 20</gadget>
<output>35/2 = around 17.5</output>
<gadget id="calculator">26 - (35/2)</gadget>
<output>17/2 = around 8.5</output>
<gadget id="calculator">(17/2) * 20</gadget>
<output>170</output>
<result>D</result> | D | 170 | A goods train runs at the speed of 72 kmph and crosses a 350 m long platform in 26 seconds. What is the length of the goods train? | {
"A": "230 m",
"B": "140 m",
"C": "160 m",
"D": "170 m",
"E": "none of these"
} | multiply(subtract(26, divide(350, multiply(const_0_2778, 72))), multiply(const_0_2778, 72)) | multiply(n0,const_0_2778)|divide(n1,#0)|subtract(n2,#1)|multiply(#0,#2) | explanation : speed = [ 72 x ( 5 / 18 ) ] m / sec = 20 m / sec . time = 26 sec . let the length of the train be x metres . then , [ ( x + 350 ) / 26 ] = 20 = > x + 350 = 520 = > x = 170 . answer : d | physics |
math_qa__1JbRePCZHCSjXGmb | On increasing the price of T.V. sets by 80%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ? Options:
A) 44 B) 5 C) 56 D) 2 E) 7 | <gadget id="calculator">100 + 80</gadget>
<output>180</output>
<gadget id="calculator">180 * 20</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 / 100</gadget>
<output>36</output>
<gadget id="calculator">36 + 100</gadget>
<output>136</output>
<gadget id="calculator">180 - 136</gadget>
<output>44</output>
<result>A</result> | A | 44 | On increasing the price of T.V. sets by 80%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ? | {
"A": "44",
"B": "5",
"C": "56",
"D": "2",
"E": "7"
} | subtract(add(const_100, 80), add(divide(multiply(add(const_100, 80), 20), const_100), const_100)) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|add(#2,const_100)|subtract(#0,#3)| | "explanation : let the price be = rs . 100 , and number of units sold = 100 then , sale value = rs . ( 100 × 100 ) = rs . 10000 new sale value = rs . ( 180 × 80 ) = rs . 14400 increase % = 4400 / 10000 × 100 = 44 % answer : a" | gain |
math_qa__zSrl4O2ljX1CwfjR | In a hostel, the number of students decreased by 15% and the price of food increased by 20% over the previous year. If each student consumes the same amount of food then By how much should the consumption of food be cut short by every student, so that the total cost of the food remains the same as that of the previous year?
Choose the correct choice from the following answers: A) 19 % B) 15 % C) 25 % D) 40 % E) 1.96 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">85 * 120</gadget>
<output>10_200</output>
<gadget id="calculator">10_000 / 10_200</gadget>
<output>50/51 = around 0.980392</output>
<gadget id="calculator">1 - (50/51)</gadget>
<output>1/51 = around 0.019608</output>
<gadget id="calculator">(1/51) * 100</gadget>
<output>100/51 = around 1.960784</output>
<result>E</result> | E | 1.96 | In a hostel, the number of students decreased by 15% and the price of food increased by 20% over the previous year. If each student consumes the same amount of food then By how much should the consumption of food be cut short by every student, so that the total cost of the food remains the same as that of the previous year? | {
"A": "19 %",
"B": "15 %",
"C": "25 %",
"D": "40 %",
"E": "1.96 %"
} | multiply(subtract(const_1, divide(multiply(const_100, const_100), multiply(subtract(const_100, 15), add(const_100, 20)))), const_100) | add(n1,const_100)|multiply(const_100,const_100)|subtract(const_100,n0)|multiply(#0,#2)|divide(#1,#3)|subtract(const_1,#4)|multiply(#5,const_100)| | "cost of food ( c ) = food consumed per student ( f ) * number of students ( n ) * price of food ( p ) originally , c = fnp when number of students decrease by 15 % , and the price of food increases by 20 % , c = f ( new ) * ( 0.85 n ) * ( 1.2 p ) = > f ( new ) = f / ( 0.85 * 1.2 ) = > f ( new ) = 0.9804 f therefore the new cost of food must be 98.04 % of the old cost , or the cost of food must decrease by 1.96 % ( option e )" | general |
math_qa__SISWtClIQ92T7PKc | A bag contains 5 red, 6 blue and 4 green balls. If 2 ballsare picked at random, what is the probability that both are red? Choose the correct choice
A) 2 / 15
B) 2 / 21
C) 5 / 26
D) 3 / 29
E) 4 / 27 | <gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">11 + 4</gadget>
<output>15</output>
<gadget id="calculator">binomial(15, 2)</gadget>
<output>105</output>
<gadget id="calculator">10 / 105</gadget>
<output>2/21 = around 0.095238</output>
<result>B</result> | B | 0.095238 | A bag contains 5 red, 6 blue and 4 green balls. If 2 ballsare picked at random, what is the probability that both are red? | {
"A": "2 / 15",
"B": "2 / 21",
"C": "5 / 26",
"D": "3 / 29",
"E": "4 / 27"
} | divide(choose(5, 2), choose(add(add(5, 6), 4), 2)) | add(n0,n1)|choose(n0,n3)|add(n2,#0)|choose(#2,n3)|divide(#1,#3) | p ( both are red ) , = 5 c 215 c 2 = 5 c 215 c 2 = 10 / 105 = 2 / 21 b | other |
math_qa__LcGXkg8lTyhDiBQW | Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 27 percent ryegrass, what percent of the weight of this mixture is X ?
Options: A) 10 % B) 13.33 % C) 40 % D) 50 % E) 66.66 % | <gadget id="calculator">27 - 25</gadget>
<output>2</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(2/5) - (1/4)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">2 / (3/20)</gadget>
<output>40/3 = around 13.333333</output>
<result>B</result> | B | 13.33 | Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 27 percent ryegrass, what percent of the weight of this mixture is X ? | {
"A": "10 %",
"B": "13.33 %",
"C": "40 %",
"D": "50 %",
"E": "66.66 %"
} | divide(subtract(27, 25), subtract(divide(40, const_100), divide(25, const_100))) | divide(n0,const_100)|divide(n2,const_100)|subtract(n4,n2)|subtract(#0,#1)|divide(#2,#3)| | "- - - - - - - - - - - - - - - - > ryegrass x - - - - - - - - - - - - - - > 40 % y - - - - - - - - - - - - - - > 25 % m ( mixture ) - - - - > 27 % 0.4 x + ( m - x ) 0.25 = 0.27 m 0.15 x = 0.02 m x = 0.1333 m x = 13.33 % of m b" | gain |
math_qa__xaBXw1tERyyYDeSH | a , b , c , d , e , f are the only 6 families in indira nagar . a , b , c , d , e and f has 7 , 8 , 10 , 13 , 6 , and 10 member in their families respectively . if 1 member from all the 6 families left their respective families to accommodate themselves in the hostel of iim lucknow , then the average number of member now in each family of indira nagar is
Select the correct option.
A) 8 B) 9 C) 10 D) 13 E) 15 | <gadget id="calculator">10 - 2</gadget>
<output>8</output>
<result>A</result> | A | 8 | a , b , c , d , e , f are the only 6 families in indira nagar . a , b , c , d , e and f has 7 , 8 , 10 , 13 , 6 , and 10 member in their families respectively . if 1 member from all the 6 families left their respective families to accommodate themselves in the hostel of iim lucknow , then the average number of member now in each family of indira nagar is | {
"A": "8",
"B": "9",
"C": "10",
"D": "13",
"E": "15"
} | subtract(10, const_2) | subtract(n3,const_2) | answer required average = ( ( 7 - 1 ) + ( 8 - 1 ) + ( 10 - 1 ) + ( 13 - 1 ) + ( 6 - 1 ) + ( 10 - 1 ) ) / 6 = ( 7 + 8 + 10 + 13 + 6 + 10 ) / 6 - ( 6 x 1 ) / 6 = 9 - 1 = 8 correct option : a | general |
math_qa__0XiSCwR1QF5epnUH | A rectangular grass field is 75 m * 40 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m? Pick.
A) s . 1350
B) s . 1327
C) s . 1200
D) s . 1397
E) s . 1927 | <gadget id="calculator">2.5 * 2</gadget>
<output>5</output>
<gadget id="calculator">75 + 5</gadget>
<output>80</output>
<gadget id="calculator">40 + 5</gadget>
<output>45</output>
<gadget id="calculator">80 * 45</gadget>
<output>3_600</output>
<gadget id="calculator">75 * 40</gadget>
<output>3_000</output>
<gadget id="calculator">3_600 - 3_000</gadget>
<output>600</output>
<gadget id="calculator">600 * 2</gadget>
<output>1_200</output>
<result>C</result> | C | 1,200 | A rectangular grass field is 75 m * 40 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m? | {
"A": "s . 1350",
"B": "s . 1327",
"C": "s . 1200",
"D": "s . 1397",
"E": "s . 1927"
} | multiply(subtract(rectangle_area(add(75, multiply(2.5, const_2)), add(40, multiply(2.5, const_2))), rectangle_area(75, 40)), 2) | multiply(n2,const_2)|rectangle_area(n0,n1)|add(n0,#0)|add(n1,#0)|rectangle_area(#2,#3)|subtract(#4,#1)|multiply(n3,#5) | area = ( l + b + 2 d ) 2 d = ( 75 + 40 + 2.5 * 2 ) 2 * 2.5 = > 600 600 * 2 = rs . 1200 answer : c | geometry |
math_qa__yD2tREkzDSqkjmf1 | In a river flowing at 2 km/hr, a boat travels 72 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time. Choose the most appropriate option.
A) 10 hours B) 12 hours C) 14 hours D) 27 hours E) none of these | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">72 / 4</gadget>
<output>18</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">72 / 8</gadget>
<output>9</output>
<gadget id="calculator">18 + 9</gadget>
<output>27</output>
<result>D</result> | D | 27 | In a river flowing at 2 km/hr, a boat travels 72 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time. | {
"A": "10 hours",
"B": "12 hours",
"C": "14 hours",
"D": "27 hours",
"E": "none of these"
} | add(divide(72, subtract(6, 2)), divide(72, add(6, 2))) | add(n0,n2)|subtract(n2,n0)|divide(n1,#1)|divide(n1,#0)|add(#2,#3) | explanation : speed of the boat = 6 km / hr speed downstream = ( 6 + 2 ) = 8 km / hr speed upstream = ( 6 - 2 ) = 4 km / hr distance travelled downstream = distance travelled upstream = 72 km total time taken = time taken downstream + time taken upstream = ( 72 / 8 ) + ( 72 / 4 ) = 27 hr . answer : option d | general |
math_qa__g1Pc70rBlwpVkTws | The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.3.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost? Options.
A) s . 1014 B) s . 1140 C) s . 999 D) s . 1085 E) s . 2331 | <gadget id="calculator">3_136 ** (1/2)</gadget>
<output>56</output>
<gadget id="calculator">56 * 4</gadget>
<output>224</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">224 - 2</gadget>
<output>222</output>
<gadget id="calculator">222 * 3.5</gadget>
<output>777</output>
<gadget id="calculator">777 * 3</gadget>
<output>2_331</output>
<result>E</result> | E | 2,331 | The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.3.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost? | {
"A": "s . 1014",
"B": "s . 1140",
"C": "s . 999",
"D": "s . 1085",
"E": "s . 2331"
} | multiply(multiply(subtract(multiply(sqrt(3136), const_4), multiply(const_2, 1)), 3.50), 3) | multiply(n3,const_2)|sqrt(n0)|multiply(#1,const_4)|subtract(#2,#0)|multiply(n2,#3)|multiply(#4,n1)| | "a 2 = 3136 = > a = 56 56 * 4 * 3 = 672 – 6 = 666 * 3.5 = 2331 answer : e" | physics |
math_qa__hVx8OsW2nUatAe6u | If a - b = 5 and a2 + b2 = 29, find the value of ab. Options.
A) 6 B) 8 C) 10 D) 11 E) 2 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">29 - 25</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>E</result> | E | 2 | If a - b = 5 and a2 + b2 = 29, find the value of ab. | {
"A": "6",
"B": "8",
"C": "10",
"D": "11",
"E": "2"
} | divide(subtract(29, power(5, 2)), 2) | power(n0,n1)|subtract(n3,#0)|divide(#1,n1) | 2 ab = ( a 2 + b 2 ) - ( a - b ) 2 = 29 - 25 = 4 ab = 2 . answer : e | general |
math_qa__CBMGqtgtyuq2LWM9 | 60 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work? Choose the correct choice from the following.
A) 8 days B) 6 days C) 7 days D) 9 days E) 12 days | <gadget id="calculator">60 * 7</gadget>
<output>420</output>
<gadget id="calculator">5 / 420</gadget>
<output>1/84 = around 0.011905</output>
<gadget id="calculator">60 * 14</gadget>
<output>840</output>
<gadget id="calculator">60 / 840</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">(1/84) + (1/14)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>E</result> | E | 12 | 60 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work? | {
"A": "8 days",
"B": "6 days",
"C": "7 days",
"D": "9 days",
"E": "12 days"
} | inverse(add(divide(5, multiply(60, 7)), divide(60, multiply(60, 14)))) | multiply(n0,n1)|multiply(n0,n3)|divide(n4,#0)|divide(n0,#1)|add(#2,#3)|inverse(#4)| | "1 women ' s 1 day work = 1 / 420 1 child ' s 1 day work = 1 / 140 ( 5 women + 10 children ) ' s 1 day work = ( 5 / 420 + 10 / 140 ) = 1 / 12 5 women and 10 children will complete the work in 12 days . answer : e" | physics |
math_qa__ToyaUQDu5m0yrEWv | In how many years Rs 200 will produce the same interest at 10% as Rs. 400 produce in 5 years at 12% Choose the correct choice: A) 16 B) 13 C) 12 D) 14 E) 15 | <gadget id="calculator">400 * 12</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 100</gadget>
<output>48</output>
<gadget id="calculator">48 * 5</gadget>
<output>240</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 200</gadget>
<output>20</output>
<gadget id="calculator">240 / 20</gadget>
<output>12</output>
<result>C</result> | C | 12 | In how many years Rs 200 will produce the same interest at 10% as Rs. 400 produce in 5 years at 12% | {
"A": "16",
"B": "13",
"C": "12",
"D": "14",
"E": "15"
} | divide(multiply(divide(multiply(400, 12), const_100), 5), multiply(divide(10, const_100), 200)) | divide(n1,const_100)|multiply(n2,n4)|divide(#1,const_100)|multiply(n0,#0)|multiply(n3,#2)|divide(#4,#3)| | "explanation : clue : firstly we need to calculate the si with prinical 400 , time 5 years and rate 12 % , it will be rs . 240 then we can get the time as time = ( 100 * 240 ) / ( 200 * 10 ) = 12 option c" | gain |
math_qa__vR5Uelfpu86x8oE3 | A watch was sold at a loss of 10%. If it was sold for Rs.196 more, there would have been a gain of 4%. What is the cost price?
Choose the correct option: A) s : 1000 B) s : 1067 C) s : 1278 D) s : 1028 E) s : 1400 | <gadget id="calculator">196 * 100</gadget>
<output>19_600</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">104 - 90</gadget>
<output>14</output>
<gadget id="calculator">19_600 / 14</gadget>
<output>1_400</output>
<result>E</result> | E | 1,400 | A watch was sold at a loss of 10%. If it was sold for Rs.196 more, there would have been a gain of 4%. What is the cost price? | {
"A": "s : 1000",
"B": "s : 1067",
"C": "s : 1278",
"D": "s : 1028",
"E": "s : 1400"
} | divide(multiply(196, const_100), subtract(add(const_100, 4), subtract(const_100, 10))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "90 % 104 % - - - - - - - - 14 % - - - - 196 100 % - - - - ? = > rs : 1400 answer : e" | gain |
math_qa__pgy5Rapldzfj1wwK | Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixture Y is 25% ryegrass and 75% fescue. If a mixture of X and Y contains 37% ryegrass, what percent of the weight of the mixture is from mixture X? Choose the correct choice from the following answers:
A) 20 % B) 40 % C) 50 % D) 60 % E) 80 % | <gadget id="calculator">25 + 1</gadget>
<output>26</output>
<gadget id="calculator">37 - 26</gadget>
<output>11</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">26 / 100</gadget>
<output>13/50 = around 0.26</output>
<gadget id="calculator">(2/5) - (13/50)</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">11 / (7/50)</gadget>
<output>550/7 = around 78.571429</output>
<result>E</result> | E | 80 | Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixture Y is 25% ryegrass and 75% fescue. If a mixture of X and Y contains 37% ryegrass, what percent of the weight of the mixture is from mixture X? | {
"A": "20 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "80 %"
} | divide(subtract(37, add(25, const_1)), subtract(divide(40, const_100), divide(add(25, const_1), const_100))) | add(n2,const_1)|divide(n0,const_100)|divide(#0,const_100)|subtract(n4,#0)|subtract(#1,#2)|divide(#3,#4)| | "37 % is 12 % - points above 25 % and 3 % - points below 40 % . thus the ratio of mixture y to mixture x is 1 : 4 . the percent of mixture x is 4 / 5 = 80 % . the answer is e ." | gain |
math_qa__nc2nfF2SIlcs9jUm | How many cubes of 10 cm edge can be put in a cubical box of 1 m edge. Choose the most appropriate option:
A) 10000 cubes B) 1000 cubes C) 100 cubes D) 50 cubes E) none of these | <gadget id="calculator">1 ** 3</gadget>
<output>1</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) ** 3</gadget>
<output>1/1_000 = around 0.001</output>
<gadget id="calculator">1 / (1/1_000)</gadget>
<output>1_000</output>
<result>B</result> | B | 1,000 | How many cubes of 10 cm edge can be put in a cubical box of 1 m edge. | {
"A": "10000 cubes",
"B": "1000 cubes",
"C": "100 cubes",
"D": "50 cubes",
"E": "none of these"
} | divide(volume_cube(1), volume_cube(divide(10, const_100))) | divide(n0,const_100)|volume_cube(n1)|volume_cube(#0)|divide(#1,#2)| | "explanation : number of cubes = 100 ∗ 100 ∗ 100 / 10 ∗ 10 ∗ 10 = 1000 note : 1 m = 100 cm option b" | physics |
math_qa__sXToI5u9MuUKBPkA | The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 35 kms. what was the total distance travelled in 12 hours? Pick one
A) 456 kms B) 482 kms C) 552 kms D) 556 kms E) none of these | <gadget id="calculator">2 * 35</gadget>
<output>70</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">70 + 22</gadget>
<output>92</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">92 * 6</gadget>
<output>552</output>
<result>C</result> | C | 552 | The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 35 kms. what was the total distance travelled in 12 hours? | {
"A": "456 kms",
"B": "482 kms",
"C": "552 kms",
"D": "556 kms",
"E": "none of these"
} | multiply(add(multiply(2, 35), multiply(subtract(12, const_1), 2)), divide(12, 2)) | divide(n2,n0)|multiply(n0,n1)|subtract(n2,const_1)|multiply(n0,#2)|add(#1,#3)|multiply(#4,#0)| | "explanation : total distance travelled in 12 hours = ( 35 + 37 + 39 + . . . . . upto 12 terms ) this is an a . p with first term , a = 35 , number of terms , n = 12 , d = 2 . required distance = 12 / 2 [ 2 × 35 + { 12 - 1 ) × 2 ] = 6 ( 70 + 23 ) = 552 kms . answer : c" | physics |
math_qa__2YPWHHKORIyIYu69 | A and B together can do a piece of work in 10 days. B alone can finish it in 20 days. In how many days can A alone finish the work ?
Choose the correct answer:
A) 20 B) 10 C) 15 D) 5 E) 7 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/10) - (1/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / (1/20)</gadget>
<output>20</output>
<result>A</result> | A | 20 | A and B together can do a piece of work in 10 days. B alone can finish it in 20 days. In how many days can A alone finish the work ? | {
"A": "20",
"B": "10",
"C": "15",
"D": "5",
"E": "7"
} | inverse(subtract(inverse(10), inverse(20))) | inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2) | time taken by a to finish the work = xy / ( y - x ) = 10 x 20 / ( 20 - 10 ) = 200 / 10 = 20 days answer : a | physics |
math_qa__TRgHR5J3GlJRgxn2 | The ratio of pens to pencils is 5 to 6. There are 7 more pencils than pens. How many pencils are there? Choose the correct choice from the following options:
A) 36
B) 42
C) 48
D) 55
E) 64 | <gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">35 + 7</gadget>
<output>42</output>
<result>B</result> | B | 42 | The ratio of pens to pencils is 5 to 6. There are 7 more pencils than pens. How many pencils are there? | {
"A": "36",
"B": "42",
"C": "48",
"D": "55",
"E": "64"
} | add(multiply(7, 5), 7) | multiply(n0,n2)|add(n2,#0)| | "let the number of pens be 5 x and the number of pencils be 6 x . 6 x - 5 x = 7 x = 7 the number of pencils is 42 . the answer is b ." | other |
math_qa__YxdLJORVI9dxE8RL | the average score of a cricketer for 10 matches is 38.9 runs . if the average for the first 6 matches is 42 , then find the average for the last 4 matches . Choose the correct answer
A) 33.5
B) 33.5
C) 34.25
D) 35
E) none of these | <gadget id="calculator">10 * 38.9</gadget>
<output>389</output>
<gadget id="calculator">6 * 42</gadget>
<output>252</output>
<gadget id="calculator">389 - 252</gadget>
<output>137</output>
<gadget id="calculator">137 / 4</gadget>
<output>137/4 = around 34.25</output>
<result>C</result> | C | 34.25 | the average score of a cricketer for 10 matches is 38.9 runs . if the average for the first 6 matches is 42 , then find the average for the last 4 matches . | {
"A": "33.5",
"B": "33.5",
"C": "34.25",
"D": "35",
"E": "none of these"
} | divide(subtract(multiply(10, 38.9), multiply(6, 42)), 4) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)|divide(#2,n4) | solution required average = ( 38.9 x 10 ) - ( 42 x 6 ) / 4 = 137 / 4 = 34.25 answer c | general |
math_qa__0woKG3OT8MZ28rME | The distance between A&B is 600km. A person is traveling from A to B at 70km/hr started at 10AM and another person is traveling from B to A at 80km/hr and started at same time. Then at what time they meet together. Select the correct option:
A) 2 pm
B) 4 pm
C) 1 pm
D) 3 pm
E) 5 pm | <gadget id="calculator">70 + 80</gadget>
<output>150</output>
<gadget id="calculator">150 + 10</gadget>
<output>160</output>
<gadget id="calculator">160 / 80</gadget>
<output>2</output>
<result>A</result> | A | 2 | The distance between A&B is 600km. A person is traveling from A to B at 70km/hr started at 10AM and another person is traveling from B to A at 80km/hr and started at same time. Then at what time they meet together. | {
"A": "2 pm",
"B": "4 pm",
"C": "1 pm",
"D": "3 pm",
"E": "5 pm"
} | divide(add(add(70, 80), 10), 80) | add(n1,n3)|add(n2,#0)|divide(#1,n3) | let x hours be they will meet together distance covered by 1 st person + distance covered by 2 nd person = 600 km 70 x + 80 x = 600 x = 4 hr they will meet = 10 am + 4 hr = 2 pm answer is a | physics |
math_qa__mrFUOZ8JhK3oY3HW | Of 55 players on a cricket team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? Choices:
A) 49
B) 55
C) 59
D) 71
E) 92 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">55 - 37</gadget>
<output>18</output>
<gadget id="calculator">(2/3) * 18</gadget>
<output>12</output>
<gadget id="calculator">37 + 12</gadget>
<output>49</output>
<result>A</result> | A | 49 | Of 55 players on a cricket team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? | {
"A": "49",
"B": "55",
"C": "59",
"D": "71",
"E": "92"
} | add(37, multiply(subtract(const_1, divide(const_1, const_3)), subtract(55, 37))) | divide(const_1,const_3)|subtract(n0,n1)|subtract(const_1,#0)|multiply(#2,#1)|add(n1,#3)| | "total = 55 thrower = 37 rest = 55 - 37 = 18 left handed = 18 / 3 = 6 right handed = 12 if all thrower are right handed then total right handed is 37 + 12 = 49 so a . 49 is the right answer" | general |
math_qa__Ng04wQ1yw2ojpD4z | A person want to give his money of $900 to his 3 children A,B,C in the ratio 2:3:4. What is the B's share? Choices: A) $ 400 B) $ 300 C) $ 500 D) $ 180 E) $ 200 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">3 / 9</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 900</gadget>
<output>300</output>
<result>B</result> | B | 300 | A person want to give his money of $900 to his 3 children A,B,C in the ratio 2:3:4. What is the B's share? | {
"A": "$ 400",
"B": "$ 300",
"C": "$ 500",
"D": "$ 180",
"E": "$ 200"
} | multiply(divide(3, add(add(2, 3), 4)), 900) | add(n1,n2)|add(n4,#0)|divide(n1,#1)|multiply(n0,#2)| | "b ' s share = 900 * 3 / 9 = $ 300 answer is b" | other |
math_qa__vGvIUmv45qnssTA7 | If a and b are the two values of t that satisfy
the equation t^2 – 12t + 20 = 0, with a > b, what is the value of a – b?
Pick:
A) 2 B) 4 C) 6 D) 8 E) 10 | <gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<result>D</result> | D | 8 | If a and b are the two values of t that satisfy
the equation t^2 – 12t + 20 = 0, with a > b, what is the value of a – b? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | subtract(divide(20, 2), 2) | divide(n2,n0)|subtract(#0,n0) | factor the left side of the equation : t ^ 2 â € “ 12 t + 20 = 0 ( t â € “ 2 ) ( t â € “ 10 ) = 0 t = 2 , t = 10 thus , a = 10 and b = 2 . so a â € “ b = 10 â € “ 2 = 8 . the answer is d . | general |
math_qa__O1yDHnlxbUZSF5oX | The average (arithmetic mean) of 4 different integers is 74. If the largest integer is 90, what is the least possible value of the smallest integer? Choose the correct choice:
A) 1
B) 19
C) 29
D) 30
E) 33 | <gadget id="calculator">74 * 4</gadget>
<output>296</output>
<gadget id="calculator">296 - 90</gadget>
<output>206</output>
<gadget id="calculator">90 - 1</gadget>
<output>89</output>
<gadget id="calculator">206 - 89</gadget>
<output>117</output>
<gadget id="calculator">90 - 2</gadget>
<output>88</output>
<gadget id="calculator">117 - 88</gadget>
<output>29</output>
<result>C</result> | C | 29 | The average (arithmetic mean) of 4 different integers is 74. If the largest integer is 90, what is the least possible value of the smallest integer? | {
"A": "1",
"B": "19",
"C": "29",
"D": "30",
"E": "33"
} | subtract(subtract(subtract(multiply(74, 4), 90), subtract(90, const_1)), subtract(90, const_2)) | multiply(n0,n1)|subtract(n2,const_1)|subtract(n2,const_2)|subtract(#0,n2)|subtract(#3,#1)|subtract(#4,#2)| | "total of integers = 74 * 4 = 296 lowest of the least possible integer is when the middle 2 intergers are at the maximum or equal to the highest possible integer . but all integers are distinct . so if the largest integer is 90 , then the middle 2 will be 88 and 89 lowest of least possible integer = 296 - ( 90 + 89 + 88 ) = 296 - 267 = 29 answer : c" | general |
math_qa__u8v3DUZIdrVkKtGN | If W is the set of all the integers between 35 and 64, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers? Select:
A) 18 B) 19 C) 61 D) 31 E) 11 | <gadget id="calculator">64 - 35</gadget>
<output>29</output>
<gadget id="calculator">29 / 3</gadget>
<output>29/3 = around 9.666667</output>
<gadget id="calculator">floor(29/3)</gadget>
<output>9</output>
<gadget id="calculator">29 / 2</gadget>
<output>29/2 = around 14.5</output>
<gadget id="calculator">9 + (29/2)</gadget>
<output>47/2 = around 23.5</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">29 / 6</gadget>
<output>29/6 = around 4.833333</output>
<gadget id="calculator">floor(29/6)</gadget>
<output>4</output>
<gadget id="calculator">(47/2) - 4</gadget>
<output>39/2 = around 19.5</output>
<result>B</result> | B | 19 | If W is the set of all the integers between 35 and 64, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers? | {
"A": "18",
"B": "19",
"C": "61",
"D": "31",
"E": "11"
} | subtract(add(floor(divide(subtract(64, 35), 3)), divide(subtract(64, 35), 2)), floor(divide(subtract(64, 35), multiply(2, 3)))) | multiply(n3,n2)|subtract(n1,n0)|divide(#1,n3)|divide(#1,n2)|divide(#1,#0)|floor(#3)|floor(#4)|add(#2,#5)|subtract(#7,#6)| | "official solution : number of multiples of 3 step 1 . subtract the extreme multiples of 3 within the range ( the greatest is 63 , the smallest is 36 ) : 63 - 36 = 27 step 2 . divide by 3 : 27 / 3 = 9 step 3 . add 1 : 9 + 1 = 10 . so there are 10 multiples of 3 within the range : examples are 51 , 54 , 57 , 60 , etc . number of multiples of 2 step 1 . subtract the extreme multiples of 2 within the range ( the greatest is 64 , the smallest is 36 ) : 64 - 36 = 28 step 2 . divide by 2 : 28 / 2 = 14 step 3 . add 1 : 14 + 1 = 15 . so there are 15 multiples of 2 within the range : examples are 50 , 52 , 54 , 56 , 58 , 60 etc . add the 10 multiples of 3 and the 15 multiples of 2 : 10 + 15 = 25 . however , by adding the multiples of 2 and the multiples of 3 , we are effectively counting several numbers twice : for example , 54 and 60 are parts of both the lists above . so we ca n ' t just take 10 + 15 = 25 . find the number of multiples of 6 ( which are the double counted , as 6 is divisible by both 2 and 3 ) , and subtract it from 25 : step 1 . subtract the extreme multiples of 6 within the range ( the greatest is 72 , the smallest is 54 ) : 60 - 30 = 30 step 2 . divide by 6 : 30 / 6 = 5 step 3 . add 1 : 5 + 1 = 6 . so there are 6 multiples of 6 within the range : we counted 6 numbers twice . subtract the 6 multiples of 6 from the sum of the multiples of 2 and 3 : = 10 + 15 - 6 = 25 - 6 = 19 therefore , the final number of multiples of 2 , 3 or 6 is 19 . hence , this is the correct answer . ( b )" | other |
math_qa__gxYi9fVGXYYWgLYz | 4 milkmen rented a pasture . a grazed 24 cows for 3 months ; b 10 for 5 months ; c 35 cows for 4 months and d 21 cows for 3 months . if a ' s share of rent is rs . 1440 , find the total rent of the field .
Choose the correct choice from the following answers.
A) 6500 B) 3550 C) 4250 D) 2250 E) 3250 | <gadget id="calculator">24 * 3</gadget>
<output>72</output>
<gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">72 + 50</gadget>
<output>122</output>
<gadget id="calculator">35 * 4</gadget>
<output>140</output>
<gadget id="calculator">122 + 140</gadget>
<output>262</output>
<gadget id="calculator">21 * 3</gadget>
<output>63</output>
<gadget id="calculator">262 + 63</gadget>
<output>325</output>
<gadget id="calculator">325 / 72</gadget>
<output>325/72 = around 4.513889</output>
<gadget id="calculator">(325/72) * 1_440</gadget>
<output>6_500</output>
<result>A</result> | A | 6,500 | 4 milkmen rented a pasture . a grazed 24 cows for 3 months ; b 10 for 5 months ; c 35 cows for 4 months and d 21 cows for 3 months . if a ' s share of rent is rs . 1440 , find the total rent of the field . | {
"A": "6500",
"B": "3550",
"C": "4250",
"D": "2250",
"E": "3250"
} | multiply(divide(add(add(add(multiply(24, 3), multiply(10, 5)), multiply(35, 4)), multiply(21, 3)), multiply(24, 3)), 1440) | multiply(n1,n2)|multiply(n3,n4)|multiply(n0,n5)|multiply(n2,n7)|add(#0,#1)|add(#4,#2)|add(#5,#3)|divide(#6,#0)|multiply(n9,#7) | ratio of shares of a , b , c , d = ( 24 x 3 ) : ( 10 x 5 ) : ( 35 x 4 ) : ( 21 x 3 ) = 72 : 50 : 140 : 63 . let total rent be rs . x . then , a ’ s share = rs . ( 72 x ) / 325 ( 72 x ) / 325 = 1440 = x = ( 1440 x 325 ) / 72 = 6500 hence , total rent of the field is rs . 6500 . answer is a . | general |
math_qa__uqN4U95VqN79Jx9T | How many multiples of 4 are there between 12 and 108, inclusive? Choose the correct choice from the following choices
A) 21 B) 22 C) 23 D) 24 E) 25 | <gadget id="calculator">108 - 12</gadget>
<output>96</output>
<gadget id="calculator">96 / 4</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<result>E</result> | E | 25 | How many multiples of 4 are there between 12 and 108, inclusive? | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | add(divide(subtract(108, 12), 4), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "the multiples of 4 are from 4 * 3 up to 4 * 27 . 27 - 3 + 1 = 25 . the answer is e ." | general |
math_qa__xDYqDrQYzESDUff9 | An inspector rejects 0.02% of the meters as defective. How many will he examine to reject 2?
Choose the correct choice:
A) 1500 B) 10000 C) 2500 D) 3000 E) 3100 | <gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 / 0.02</gadget>
<output>10_000</output>
<result>B</result> | B | 10,000 | An inspector rejects 0.02% of the meters as defective. How many will he examine to reject 2? | {
"A": "1500",
"B": "10000",
"C": "2500",
"D": "3000",
"E": "3100"
} | divide(multiply(2, const_100), 0.02) | multiply(n1,const_100)|divide(#0,n0)| | "let the number of meters to be examined be x then , 0.02 % of x = 2 ( 2 / 100 ) * ( ( 1 / 100 ) * x = 2 x = 10000 answer is b" | gain |
math_qa__G2JLp4xgCoKgqIm6 | If a-b= 10 and a^2+b^2=150, find the value of ab Choose the correct choice:
A) 10 B) 12 C) 25 D) 18 E) 19 | <gadget id="calculator">150 ** (1/2)</gadget>
<output>5*sqrt(6) = around 12.247449</output>
<gadget id="calculator">(5*sqrt(6)) - 10</gadget>
<output>-10 + 5*sqrt(6) = around 2.247449</output>
<gadget id="calculator">(-10 + 5*sqrt(6)) / 2</gadget>
<output>-5 + 5*sqrt(6)/2 = around 1.123724</output>
<gadget id="calculator">10 + (-5 + 5*sqrt(6)/2)</gadget>
<output>5 + 5*sqrt(6)/2 = around 11.123724</output>
<gadget id="calculator">(5 + 5*sqrt(6)/2) * (-5 + 5*sqrt(6)/2)</gadget>
<output>(-5 + 5*sqrt(6)/2)*(5 + 5*sqrt(6)/2) = around 12.5</output>
<gadget id="calculator">((-5 + 5*sqrt(6)/2)*(5 + 5*sqrt(6)/2)) * 2</gadget>
<output>2*(-5 + 5*sqrt(6)/2)*(5 + 5*sqrt(6)/2) = around 25</output>
<result>C</result> | C | 25 | If a-b= 10 and a^2+b^2=150, find the value of ab | {
"A": "10",
"B": "12",
"C": "25",
"D": "18",
"E": "19"
} | multiply(multiply(add(10, divide(subtract(sqrt(150), 10), 2)), divide(subtract(sqrt(150), 10), 2)), 2) | sqrt(n3)|subtract(#0,n0)|divide(#1,n1)|add(n0,#2)|multiply(#3,#2)|multiply(n1,#4)| | "2 ab = ( a ^ 2 + b ^ 2 ) - ( a - b ) ^ 2 = 150 - 100 = 50 = > ab = 25 answer : c" | general |
math_qa__L80c8qWKthgRfQsq | Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 900 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy) Choose the correct choice from the following answers
A) 8 / 3
B) 3 / 8
C) 8 / 5
D) 4 / 1
E) 5 / 3 | <gadget id="calculator">900 / 3</gadget>
<output>300</output>
<gadget id="calculator">300 / 4</gadget>
<output>75</output>
<gadget id="calculator">300 / 75</gadget>
<output>4</output>
<result>D</result> | D | 4 | Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 900 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy) | {
"A": "8 / 3",
"B": "3 / 8",
"C": "8 / 5",
"D": "4 / 1",
"E": "5 / 3"
} | divide(divide(900, 3), divide(300, 4)) | divide(n2,n0)|divide(n3,n1)|divide(#0,#1)| | "distance traveled by eddy = 900 km time taken by eddy = 3 hours average speed of eddy = 900 / 3 = 300 km / hour distance traveled by freddy = 300 km time taken by freddy = 4 hours average speed of freddy = 300 / 4 = 75 km / hour ratio of average speed of eddy to freddy = 300 / 75 = 4 / 1 answer d" | physics |
math_qa__RI6ycLrcZVJtvOgb | If 40 honey bees make 40 grams of honey in 40 days, then 1 honey bee will make 1 gram of honey in how many days?
Choose the correct option
A) 1
B) 3.5
C) 40
D) 49
E) 30 | <gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">1 / (1/40)</gadget>
<output>40</output>
<result>C</result> | C | 40 | If 40 honey bees make 40 grams of honey in 40 days, then 1 honey bee will make 1 gram of honey in how many days? | {
"A": "1",
"B": "3.5",
"C": "40",
"D": "49",
"E": "30"
} | divide(1, divide(1, 40)) | divide(n3,n0)|divide(n3,#0)| | "explanation : let the required number days be x . less honey bees , more days ( indirect proportion ) less honey , less days ( direct proportion ) honey bees 1 : 40 : : 40 : x honey 40 : 1 = > 1 x 40 x x = 40 x 1 x 40 = > x = 40 . answer : c" | physics |
math_qa__WCMrtvRsy0bj7Ksm | A dog takes 5 leaps for every 8 leaps of a hare. If one leap of the dog is equal to 5 leaps of the hare, the ratio of the speed of the dog to that of the hare is : Answers:
A) 25 : 10 B) 25 : 8 C) 25 : 9 D) 8 : 25 E) 24 : 8 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 / 8</gadget>
<output>25/8 = around 3.125</output>
<result>B</result> | B | 3.125 | A dog takes 5 leaps for every 8 leaps of a hare. If one leap of the dog is equal to 5 leaps of the hare, the ratio of the speed of the dog to that of the hare is : | {
"A": "25 : 10",
"B": "25 : 8",
"C": "25 : 9",
"D": "8 : 25",
"E": "24 : 8"
} | divide(multiply(5, 5), 8) | multiply(n0,n2)|divide(#0,n1)| | "explanation : dog : hare = ( 5 * 5 ) leaps of hare : 8 leaps of hare = 25 : 8 answer : b" | other |
math_qa__DzmAyoO4yGXztOmy | Of the families in City X in 2001, 25 percent owned a personal computer. The number of families in City X owning a computer in 2008 was 15 percent greater than it was in 2001, and the total number of families in City X was 6 percent greater in 2008 than it was in 2001. what percent of the families in City X owned a personal computer in 2008? Choose the correct option.
A) 27.12 % B) 23.12 % C) 25.55 % D) 31.22 % E) 56.22 % | <gadget id="calculator">15 + 100</gadget>
<output>115</output>
<gadget id="calculator">115 * 25</gadget>
<output>2_875</output>
<gadget id="calculator">2_875 / 100</gadget>
<output>115/4 = around 28.75</output>
<gadget id="calculator">100 + 6</gadget>
<output>106</output>
<gadget id="calculator">(115/4) / 106</gadget>
<output>115/424 = around 0.271226</output>
<gadget id="calculator">100 * (115/424)</gadget>
<output>2_875/106 = around 27.122642</output>
<result>A</result> | A | 27.12 | Of the families in City X in 2001, 25 percent owned a personal computer. The number of families in City X owning a computer in 2008 was 15 percent greater than it was in 2001, and the total number of families in City X was 6 percent greater in 2008 than it was in 2001. what percent of the families in City X owned a personal computer in 2008? | {
"A": "27.12 %",
"B": "23.12 %",
"C": "25.55 %",
"D": "31.22 %",
"E": "56.22 %"
} | multiply(const_100, divide(divide(multiply(add(15, const_100), 25), const_100), add(const_100, 6))) | add(n3,const_100)|add(n5,const_100)|multiply(n1,#0)|divide(#2,const_100)|divide(#3,#1)|multiply(#4,const_100)| | "say a 100 families existed in 1994 then the number of families owning a computer in 1994 - 25 number of families owning computer in 1998 = 25 * 115 / 100 = 28.75 number of families in 1998 = 106 the percentage = 28.75 / 106 * 100 = 27.12 % . answer : a" | general |
math_qa__uOnXvRRTKNZdzo9K | The mass of 1 cubic meter of a substance is 100 kg under certain conditions. What is the volume in cubic centimeters of 1 gram of this substance under these conditions? (1 kg =1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters) Options: A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">100 * 1_000</gadget>
<output>100_000</output>
<gadget id="calculator">1_000_000 / 100_000</gadget>
<output>10</output>
<result>C</result> | C | 10 | The mass of 1 cubic meter of a substance is 100 kg under certain conditions. What is the volume in cubic centimeters of 1 gram of this substance under these conditions? (1 kg =1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters) | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | divide(multiply(1,000, 1,000), multiply(100, 1,000)) | multiply(n4,n4)|multiply(n1,n4)|divide(#0,#1)| | "100 kg - 1 cubic meter ; 100,000 g - 1 cubic meter ; 100,000 g - 1 , 000,000 cubic centimeters ; 1 g - 1 , 000,000 / 100,000 = 10 / 1 = 10 cubic centimeters . answer : c ." | geometry |
math_qa__VHFl9UNhTRdUtTJL | The ratio between the number of sheep and the number of horses at the Stewar farm is 3 to 7. If each of horse is fed 230 ounces of horse food per day and the farm needs a total 12880 ounces of horse food per day. what is number sheep in the form?? Choose the correct option: A) 24 B) 28 C) 32 D) 56 E) 58 | <gadget id="calculator">12_880 / 230</gadget>
<output>56</output>
<gadget id="calculator">56 / 7</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<result>A</result> | A | 24 | The ratio between the number of sheep and the number of horses at the Stewar farm is 3 to 7. If each of horse is fed 230 ounces of horse food per day and the farm needs a total 12880 ounces of horse food per day. what is number sheep in the form?? | {
"A": "24",
"B": "28",
"C": "32",
"D": "56",
"E": "58"
} | multiply(divide(divide(12880, 230), 7), 3) | divide(n3,n2)|divide(#0,n1)|multiply(n0,#1) | et no of sheep and horses are 3 k and 7 k no of horses = 12880 / 230 = 56 now 7 k = 56 and k = 8 no of sheep = ( 3 * 8 ) = 24 answer : a | other |
math_qa__M1d5xfPqsAEUSBGu | A pump can fill a tank with a water in 2 hours. Because of a leak, it took 2 and 4/5 hours to fill the tank. The leak can drain all the water of the full tank in how many hours?
Choose the correct choice: A) 4 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">2 + (4/5)</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">1 / (14/5)</gadget>
<output>5/14 = around 0.357143</output>
<gadget id="calculator">(1/2) - (5/14)</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">1 / (1/7)</gadget>
<output>7</output>
<result>D</result> | D | 7 | A pump can fill a tank with a water in 2 hours. Because of a leak, it took 2 and 4/5 hours to fill the tank. The leak can drain all the water of the full tank in how many hours? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | divide(const_1, subtract(divide(const_1, 2), divide(const_1, add(2, divide(4, 5))))) | divide(const_1,n0)|divide(n2,n3)|add(n0,#1)|divide(const_1,#2)|subtract(#0,#3)|divide(const_1,#4) | the rate of the pump + leak = 5 / 14 1 / 2 - leak ' s rate = 5 / 14 leak ' s rate = 1 / 2 - 5 / 14 = 1 / 7 the leak will empty the tank in 7 hours . the answer is d . | physics |
math_qa__bJIxSYSd7dDcbCkD | The sum of number of boys and girls in a school is 100. If the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is? Choose the correct choice from the following answers:
A) 50
B) 40
C) 60
D) 100
E) 70 | <gadget id="calculator">100 / 100</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<result>A</result> | A | 50 | The sum of number of boys and girls in a school is 100. If the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is? | {
"A": "50",
"B": "40",
"C": "60",
"D": "100",
"E": "70"
} | divide(100, add(divide(100, const_100), const_1)) | divide(n0,const_100)|add(#0,const_1)|divide(n0,#1)| | "we have x + x % of 100 = 100 x + x / 100 * 100 = 100 2 * x = 100 x = 50 answer is a" | general |
math_qa__fAZK0uf0Zmc6zg97 | the food in a camp lasts for 20 men for 50 days . if 20 more men join , how many days will the food last ? Choose the correct choice from the following.
A) 22 days B) 25 days C) 28 days D) 16 days E) 27 days | <gadget id="calculator">20 * 50</gadget>
<output>1_000</output>
<gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">1_000 / 40</gadget>
<output>25</output>
<result>B</result> | B | 25 | the food in a camp lasts for 20 men for 50 days . if 20 more men join , how many days will the food last ? | {
"A": "22 days",
"B": "25 days",
"C": "28 days",
"D": "16 days",
"E": "27 days"
} | divide(multiply(20, 50), add(20, 20)) | add(n0,n0)|multiply(n0,n1)|divide(#1,#0) | one man can consume the same food in 20 * 50 = 1000 days . 20 more men join , the total number of men = 40 the number of days the food will last = 1000 / 40 = 25 days . answer : b | physics |
math_qa__m2HP7s0oryN9mEnn | In a class of students, 1/2 of the number of girls is equal to 1/3 of the total number of students. What is the ratio of boys to girls in the class? Pick one:
A) 1 / 2 B) 1 / 3 C) 2 / 3 D) 1 / 4 E) 3 / 4 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/2) - (1/3)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) / (1/3)</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | In a class of students, 1/2 of the number of girls is equal to 1/3 of the total number of students. What is the ratio of boys to girls in the class? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "2 / 3",
"D": "1 / 4",
"E": "3 / 4"
} | divide(subtract(divide(1, 2), divide(1, 3)), divide(1, 3)) | divide(n0,n1)|divide(n2,n3)|subtract(#0,#1)|divide(#2,#1)| | "( 1 / 2 ) g = ( 1 / 3 ) ( b + g ) 3 g = 2 b + 2 g g = 2 b b / g = 1 / 2 . the answer is a ." | general |
math_qa__u7vY7BV6LxH9X3oH | Two circles are there one with arc area 60digree equal to 45digree of another circle find the area of circle1:circle2 ratio Choose the correct choice from the following answers:
A) 3 : 4
B) 1 : 4
C) 1 : 2
D) 2 : 3
E) 1 : 3 | <gadget id="calculator">45 / 360</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * pi</gadget>
<output>pi/4 = around 0.785398</output>
<gadget id="calculator">60 / 360</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 2</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * pi</gadget>
<output>pi/3 = around 1.047198</output>
<gadget id="calculator">(pi/4) / (pi/3)</gadget>
<output>3/4 = around 0.75</output>
<result>A</result> | A | 0.75 | Two circles are there one with arc area 60digree equal to 45digree of another circle find the area of circle1:circle2 ratio | {
"A": "3 : 4",
"B": "1 : 4",
"C": "1 : 2",
"D": "2 : 3",
"E": "1 : 3"
} | divide(multiply(multiply(divide(45, const_360), 2), const_pi), multiply(multiply(divide(60, const_360), const_2), const_pi)) | divide(n1,const_360)|divide(n0,const_360)|multiply(n3,#0)|multiply(#1,const_2)|multiply(#2,const_pi)|multiply(#3,const_pi)|divide(#4,#5) | area for first circle = ( 3.14 * r ^ 2 ) / 6 area of second circke = ( 3.14 * r ^ 2 ) / 8 therefore , ratio = 3 : 4 answer : a | geometry |
math_qa__tMu8y8VRGwmmcbMi | A train 300 m long can cross an electric pole in 30 sec and then find the speed of the train? Choose the correct choice
A) 76 kmph B) 54 kmph C) 72 kmph D) 36 kmph E) 91 kmph | <gadget id="calculator">300 / 1_000</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">30 / 3_600</gadget>
<output>1/120 = around 0.008333</output>
<gadget id="calculator">(3/10) / (1/120)</gadget>
<output>36</output>
<result>D</result> | D | 36 | A train 300 m long can cross an electric pole in 30 sec and then find the speed of the train? | {
"A": "76 kmph",
"B": "54 kmph",
"C": "72 kmph",
"D": "36 kmph",
"E": "91 kmph"
} | divide(divide(300, const_1000), divide(30, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 300 / 30 s = 10 m / sec speed = 10 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 36 kmph answer : d" | physics |
math_qa__kMpu6XbUKcxSLNQp | At what rate percent of simple interest will a sum of money double itself in 66 years? Choose one.
A) 6.54 % B) 4.54 % C) 1.51 % D) 1.94 % E) 5.54 % | <gadget id="calculator">100 / 66</gadget>
<output>50/33 = around 1.515152</output>
<result>C</result> | C | 1.51 | At what rate percent of simple interest will a sum of money double itself in 66 years? | {
"A": "6.54 %",
"B": "4.54 %",
"C": "1.51 %",
"D": "1.94 %",
"E": "5.54 %"
} | divide(const_100, 66) | divide(const_100,n0)| | "let sum = x . then , s . i . = x . rate = ( 100 * s . i . ) / ( p * t ) = ( 100 * x ) / ( x * 66 ) = 100 / 66 = 1.51 % answer : c" | gain |
math_qa__slFiAECyWbj5Eo7Q | An = 2An-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If A5 = Q4 and A7 = 316, what is the first value of n for which Qn is an integer?
Select the correct option
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">7 - 4</gadget>
<output>3</output>
<result>C</result> | C | 3 | An = 2An-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If A5 = Q4 and A7 = 316, what is the first value of n for which Qn is an integer? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(7, 4) | subtract(n9,n2) | assuming i have understood the symbols used correctly answer is c - 3 a 7 = 2 s 6 + 4 = 316 a 6 = 312 / 2 = 156 = 2 a 5 + 4 a 5 = 152 / 2 = 76 = q 4 q 4 = 4 q 3 + 8 = 76 q 3 = 68 / 4 = 17 q 3 = 4 q 2 + 8 = 17 q 2 = 9 / 4 = 2.25 q 2 = 4 q 1 + 8 q 1 will not be integer = c | general |
math_qa__H4M0BorJdw14id1S | courtyard 3.78 meters long 5.95 meters wide is to be paved exactly with square tiles, all of the same size. what is the largest size of the tile which could be used for the purpose? Choose the correct choice from the following answers
A) 22 B) 77 C) 877 D) 99 E) 88 | <gadget id="calculator">5.95 * 3.78</gadget>
<output>22.491</output>
<gadget id="calculator">22.491 * 3</gadget>
<output>67.473</output>
<gadget id="calculator">67.473 + 10</gadget>
<output>77.473</output>
<result>B</result> | B | 77 | courtyard 3.78 meters long 5.95 meters wide is to be paved exactly with square tiles, all of the same size. what is the largest size of the tile which could be used for the purpose? | {
"A": "22",
"B": "77",
"C": "877",
"D": "99",
"E": "88"
} | add(multiply(multiply(5.95, 3.78), const_3), const_10) | multiply(n0,n1)|multiply(#0,const_3)|add(#1,const_10) | 3.78 meters = 378 cm = 2 × 3 × 3 × 3 × 7 5.25 meters = 525 cm = 5 × 5 × 3 × 7 hence common factors are 3 and 7 hence lcm = 3 × 7 = 21 hence largest size of square tiles that can be paved exactly with square tiles is 77 cm . answer : b | physics |
math_qa__JNWTFCSRaD9WYyeY | In a college the ratio of the numbers of boys to the girls is 8:5. If there are 160 girls, the total number of students in the college is? Choose the correct choice
A) 562
B) 356
C) 452
D) 416
E) 512 | <gadget id="calculator">8 / 5</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(8/5) * 160</gadget>
<output>256</output>
<gadget id="calculator">256 + 160</gadget>
<output>416</output>
<result>D</result> | D | 416 | In a college the ratio of the numbers of boys to the girls is 8:5. If there are 160 girls, the total number of students in the college is? | {
"A": "562",
"B": "356",
"C": "452",
"D": "416",
"E": "512"
} | add(multiply(divide(8, 5), 160), 160) | divide(n0,n1)|multiply(n2,#0)|add(n2,#1)| | "let the number of boys and girls be 8 x and 5 x then , 5 x = 160 x = 32 total number of students = 13 x = 13 * 32 = 416 answer is d" | other |
math_qa__XSmPSHGmjUNmSrp1 | tough and tricky questions : word problems . a salesman ' s income consists of commission and base salary . his weekly income totals over the past 5 weeks have been $ 406 , $ 413 , $ 420 , $ 436 and $ 395 . what must his average ( arithmetic mean ) income over the next 5 weeks be to increase his average weekly income to $ 500 over the 10 - week period ? Pick
A) $ 570 B) $ 586 C) $ 630 D) $ 686 E) $ 715 | <gadget id="calculator">406 + 413</gadget>
<output>819</output>
<gadget id="calculator">819 + 420</gadget>
<output>1_239</output>
<gadget id="calculator">1_239 + 436</gadget>
<output>1_675</output>
<gadget id="calculator">1_675 + 395</gadget>
<output>2_070</output>
<gadget id="calculator">2_070 / 5</gadget>
<output>414</output>
<gadget id="calculator">500 - 414</gadget>
<output>86</output>
<gadget id="calculator">500 + 86</gadget>
<output>586</output>
<result>B</result> | B | 586 | tough and tricky questions : word problems . a salesman ' s income consists of commission and base salary . his weekly income totals over the past 5 weeks have been $ 406 , $ 413 , $ 420 , $ 436 and $ 395 . what must his average ( arithmetic mean ) income over the next 5 weeks be to increase his average weekly income to $ 500 over the 10 - week period ? | {
"A": "$ 570",
"B": "$ 586",
"C": "$ 630",
"D": "$ 686",
"E": "$ 715"
} | add(500, subtract(500, divide(add(add(add(add(406, 413), 420), 436), 395), 5))) | add(n1,n2)|add(n3,#0)|add(n4,#1)|add(n5,#2)|divide(#3,n0)|subtract(n7,#4)|add(n7,#5) | official solution : ( b ) first , we need to add up the wages over the past 5 weeks : $ 406 + $ 413 + $ 420 + $ 436 + $ 395 = $ 2070 . to average $ 500 over 10 weeks , the salesman would need to earn : $ 500 × 10 = $ 5000 . subtract $ 2070 from $ 5000 to determine how much he would need to earn , in total , over the next 5 weeks to average $ 500 for the 10 weeks : $ 5000 – $ 2070 = $ 2930 . dividing $ 2930 by 5 will give us the amount he needs to earn on average over the next 5 weeks : $ 2930 / 5 = $ 586 . the correct answer is choice ( b ) . | general |
math_qa__D0Qqg4jzib7tkKC6 | If 16% of 40% of a number is 6, then the number is Pick:
A) 200 B) 225 C) 93.75 D) 320 E) none of these | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(4/25) * (2/5)</gadget>
<output>8/125 = around 0.064</output>
<gadget id="calculator">6 / (8/125)</gadget>
<output>375/4 = around 93.75</output>
<result>C</result> | C | 93.75 | If 16% of 40% of a number is 6, then the number is | {
"A": "200",
"B": "225",
"C": "93.75",
"D": "320",
"E": "none of these"
} | divide(6, multiply(divide(16, const_100), divide(40, const_100))) | divide(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|divide(n2,#2) | explanation : let 16 / 100 × 40 / 100 × a = 6 a = 6 × 100 × 100 / 16 × 40 = 93.75 correct option : c | gain |
math_qa__LSt59ZRO3tXwu7Mn | A certain number when divided by 39 leaves a remainder 19, what is the remainder when the same number is divided by 13?
Answers:
A) 7
B) 8
C) 9
D) 6
E) 4 | <gadget id="calculator">19 % 13</gadget>
<output>6</output>
<result>D</result> | D | 6 | A certain number when divided by 39 leaves a remainder 19, what is the remainder when the same number is divided by 13? | {
"A": "7",
"B": "8",
"C": "9",
"D": "6",
"E": "4"
} | reminder(19, 13) | reminder(n1,n2) | explanation : 39 + 19 = 58 / 13 = 6 ( remainder ) answer : d | general |
math_qa__tLZoGAsUo6andA00 | If the price of gasoline increases by 20% and a driver intends to spend only 8% more on gasoline, by how much percent should the driver reduce the quantity of gasoline that he buys? Choose the most appropriate option
A) 4 %
B) 5 %
C) 6 %
D) 8 %
E) 10 % | <gadget id="calculator">20 + 100</gadget>
<output>120</output>
<gadget id="calculator">8 + 100</gadget>
<output>108</output>
<gadget id="calculator">120 - 108</gadget>
<output>12</output>
<gadget id="calculator">12 / 120</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>
<result>E</result> | E | 10 | If the price of gasoline increases by 20% and a driver intends to spend only 8% more on gasoline, by how much percent should the driver reduce the quantity of gasoline that he buys? | {
"A": "4 %",
"B": "5 %",
"C": "6 %",
"D": "8 %",
"E": "10 %"
} | multiply(divide(subtract(add(20, const_100), add(8, const_100)), add(20, const_100)), const_100) | add(n0,const_100)|add(n1,const_100)|subtract(#0,#1)|divide(#2,#0)|multiply(#3,const_100)| | "let x be the amount of gasoline the driver buys originally . let y be the new amount of gasoline the driver should buy . let p be the original price per liter . ( 1.2 * p ) y = 1.08 ( p * x ) y = ( 1.08 / 1.2 ) x = 0.9 x which is a reduction of 10 % . the answer is e ." | general |
math_qa__qxaZL4cHBoTL16hC | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 50 kg. What might be the weight of the new person? Select the correct option
A) 70 kg B) 80 kg C) 85 kg D) 90 kg E) 95 kg | <gadget id="calculator">8 * 2.5</gadget>
<output>20</output>
<gadget id="calculator">20 + 50</gadget>
<output>70</output>
<result>A</result> | A | 70 | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 50 kg. What might be the weight of the new person? | {
"A": "70 kg",
"B": "80 kg",
"C": "85 kg",
"D": "90 kg",
"E": "95 kg"
} | add(multiply(8, 2.5), 50) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 8 x 2.5 ) kg = 20 kg . weight of new person = ( 50 + 20 ) kg = 70 kg . a )" | general |
math_qa__h2WHx4fktwreV9cC | Machine A can finish a job in 4 hours, Machine В can finish the job in 2 hours, and Machine С can finish the job in 6 hours. How many hours will it take for A, B, and С together to finish the job?
Choose the correct choice from the following answers
A) 4 / 3
B) 6 / 5
C) 8 / 7
D) 10 / 9
E) 12 / 11 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) + (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(3/4) + (1/6)</gadget>
<output>11/12 = around 0.916667</output>
<gadget id="calculator">1 / (11/12)</gadget>
<output>12/11 = around 1.090909</output>
<result>E</result> | E | 1.090909 | Machine A can finish a job in 4 hours, Machine В can finish the job in 2 hours, and Machine С can finish the job in 6 hours. How many hours will it take for A, B, and С together to finish the job? | {
"A": "4 / 3",
"B": "6 / 5",
"C": "8 / 7",
"D": "10 / 9",
"E": "12 / 11"
} | inverse(add(add(inverse(4), inverse(2)), inverse(6))) | inverse(n0)|inverse(n1)|inverse(n2)|add(#0,#1)|add(#3,#2)|inverse(#4)| | "the combined rate is 1 / 4 + 1 / 2 + 1 / 6 = 11 / 12 of the job per hour . the time to complete the job is 12 / 11 hours . the answer is e ." | physics |
math_qa__Et2aMBttMiAQezLO | A cubical block of metal weighs 3 pounds. How much will another cube of the same metal weigh if its sides are twice as long?
Choose the correct answer:
A) 48
B) 32
C) 24
D) 18
E) 12 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">3 * 8</gadget>
<output>24</output>
<result>C</result> | C | 24 | A cubical block of metal weighs 3 pounds. How much will another cube of the same metal weigh if its sides are twice as long? | {
"A": "48",
"B": "32",
"C": "24",
"D": "18",
"E": "12"
} | multiply(3, multiply(const_2, const_4)) | multiply(const_2,const_4)|multiply(n0,#0)| | "for example our cube have a side 1 meter , so we have 1 cubical meter in this cube and this cubical meter weigth 3 pounds if we take cube with side 2 meters we will have 8 cubical meters in this cube 8 meters * 3 pounds = 24 pounds so answer is c and similar but more theoretical approach : if we have sides a and b than they have equal ration with their areas : a / b = a ^ 2 / b ^ 2 and they have equal ration with their volumes : a / b = a ^ 3 / b ^ 3 we have two sides 1 / 2 so their volume will be in ratio 1 / 8 weight of one cube * volume of another cube 3 * 8 = 24 so answer is c" | geometry |
math_qa__HopKLMQRZNhgo5as | A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 35 per metre of cloth. What is the cost price of one metre of cloth? Choose the correct choice from the following answers: A) 21 B) 28 C) 90 D) 26 E) 70 | <gadget id="calculator">8_925 / 85</gadget>
<output>105</output>
<gadget id="calculator">105 - 35</gadget>
<output>70</output>
<result>E</result> | E | 70 | A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 35 per metre of cloth. What is the cost price of one metre of cloth? | {
"A": "21",
"B": "28",
"C": "90",
"D": "26",
"E": "70"
} | subtract(divide(8925, 85), 35) | divide(n1,n0)|subtract(#0,n2)| | "explanation : sp of 1 m of cloth = 8925 / 85 = rs . 105 cp of 1 m of cloth = sp of 1 m of cloth - profit on 1 m of cloth = rs . 105 - rs . 35 = rs . 70 . answer : e" | physics |
math_qa__P6dPkFDd9qKifPZ8 | How many seconds will a train 200 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph? Pick
A) 22 sec
B) 35 sec
C) 25 sec
D) 18 sec
E) 17 sec | <gadget id="calculator">150 + 200</gadget>
<output>350</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">350 / 10</gadget>
<output>35</output>
<result>B</result> | B | 35 | How many seconds will a train 200 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph? | {
"A": "22 sec",
"B": "35 sec",
"C": "25 sec",
"D": "18 sec",
"E": "17 sec"
} | divide(add(150, 200), multiply(36, const_0_2778)) | add(n0,n1)|multiply(n2,const_0_2778)|divide(#0,#1)| | "d = 200 + 150 = 350 s = 36 * 5 / 18 = 10 mps t = 350 / 10 = 35 sec answer : b" | physics |
math_qa__1fq31rLWvN44CBTa | A sum of Rs. 427 is to be divided among A, B and C in such a way that 3 times A’s share, 4 times B’s share and 7 times C’s share are all equal. The share of C is Select the correct option.
A) 82 B) 83 C) 84 D) 85 E) 86 | <gadget id="calculator">7 / 7</gadget>
<output>1</output>
<gadget id="calculator">7 / 3</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">7 / 4</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">(7/3) + (7/4)</gadget>
<output>49/12 = around 4.083333</output>
<gadget id="calculator">1 + (49/12)</gadget>
<output>61/12 = around 5.083333</output>
<gadget id="calculator">427 / (61/12)</gadget>
<output>84</output>
<result>C</result> | C | 84 | A sum of Rs. 427 is to be divided among A, B and C in such a way that 3 times A’s share, 4 times B’s share and 7 times C’s share are all equal. The share of C is | {
"A": "82",
"B": "83",
"C": "84",
"D": "85",
"E": "86"
} | divide(427, add(divide(7, 7), add(divide(7, 3), divide(7, 4)))) | divide(n3,n1)|divide(n3,n2)|divide(n3,n3)|add(#0,#1)|add(#3,#2)|divide(n0,#4)| | "a + b + c = 427 3 a = 4 b = 7 c = > ( 7 c / 3 ) + ( 7 c / 4 ) + c = 427 = > c = 84 answer : c" | general |
math_qa__EN7li4NvMJs5iYyN | There is a rectangular prism made of 1 in cubes that has been covered in tin foil. There are exactly 128 cubes that are not touching any tin foil on any of their sides. If the width of the figure created by these 128 cubes is twice the length and twice the height, what is the p measure in inches of the width of the foil covered prism? Select the correct option:
A) 4 B) 6 C) 8 D) 9 E) 10 | <gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">128 / 2</gadget>
<output>64</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<result>E</result> | E | 10 | There is a rectangular prism made of 1 in cubes that has been covered in tin foil. There are exactly 128 cubes that are not touching any tin foil on any of their sides. If the width of the figure created by these 128 cubes is twice the length and twice the height, what is the p measure in inches of the width of the foil covered prism? | {
"A": "4",
"B": "6",
"C": "8",
"D": "9",
"E": "10"
} | add(multiply(power(divide(128, multiply(1, multiply(1, const_2))), inverse(const_3)), multiply(1, const_2)), multiply(1, const_2)) | inverse(const_3)|multiply(n0,const_2)|multiply(n0,#1)|divide(n1,#2)|power(#3,#0)|multiply(#1,#4)|add(#5,#1)| | "if the width is w , then length and height would be w / 2 . so , w * w / 2 * w / 2 = 128 = > w ^ 3 = ( 2 ^ 3 ) * 64 = ( 2 ^ 3 ) * ( 4 ^ 3 ) = > w = 2 * 4 = 8 in . along the width of the cuboid , 8 cubes do n ' t touch the tin foil . so the actual width will be non - touching cubes + touching cubes = 8 + 2 = p = 10 ans e ." | geometry |
math_qa__Zn6RQxSkCUYIvGrV | If 15 students in a class average 80% on an English exam and 10 students average 90% on the same exam, what is the average in percent for all 25 students? Select: A) 83 % B) 83 1 ⁄ 2 % C) 84 % D) 85 % E) 86 2 ⁄ 3 % | <gadget id="calculator">15 * 80</gadget>
<output>1_200</output>
<gadget id="calculator">10 * 90</gadget>
<output>900</output>
<gadget id="calculator">1_200 + 900</gadget>
<output>2_100</output>
<gadget id="calculator">2_100 / 25</gadget>
<output>84</output>
<result>C</result> | C | 84 | If 15 students in a class average 80% on an English exam and 10 students average 90% on the same exam, what is the average in percent for all 25 students? | {
"A": "83 %",
"B": "83 1 ⁄ 2 %",
"C": "84 %",
"D": "85 %",
"E": "86 2 ⁄ 3 %"
} | divide(add(multiply(15, 80), multiply(10, 90)), 25) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)|divide(#2,n4) | the average percentage = ( 15 x 80 % + 10 x 90 % ) / 25 = ( 15 x 80 % + 10 x 80 % + 10 x 10 % ) / 25 . . . . . . ( as 90 % = 10 % + 80 % ) = ( 25 x 80 % + 10 x 10 % ) / 25 = 80 % + 10 x 10 % / 25 = 80 % + 4 % = 84 % answer : c | general |
math_qa__wlg72r6X4pW32vlz | If the simple interest on $2000 increase by $40,when the time increase by 4 years. Find the rate percent per annum. Select the correct option
A) 1.2 % B) 0.5 % C) 0.7 % D) 0.9 % E) 0.3 % | <gadget id="calculator">40 / 4</gadget>
<output>10</output>
<gadget id="calculator">10 / 2_000</gadget>
<output>1/200 = around 0.005</output>
<gadget id="calculator">(1/200) * 100</gadget>
<output>1/2 = around 0.5</output>
<result>B</result> | B | 0.5 | If the simple interest on $2000 increase by $40,when the time increase by 4 years. Find the rate percent per annum. | {
"A": "1.2 %",
"B": "0.5 %",
"C": "0.7 %",
"D": "0.9 %",
"E": "0.3 %"
} | multiply(divide(divide(40, 4), 2000), const_100) | divide(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "applying the above formula , we have 40 = 2000 * r * 4 / 100 r = 40 * 100 / 2000 * 4 = 0.5 % . answer is b" | gain |
math_qa__EJZwgyAqGm9Jdi0x | In a room filled with 7 people, 4 people have exactly 1 sibling in the room and 3 people have exactly 2 siblings in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings? Choose the correct choice from the following answers:
A) 5 / 21 B) 3 / 7 C) 4 / 7 D) 5 / 7 E) 16 / 21 | <gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(4/7) * (5/6)</gadget>
<output>10/21 = around 0.47619</output>
<gadget id="calculator">7 - 4</gadget>
<output>3</output>
<gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(4/7) * (1/2)</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(10/21) + (2/7)</gadget>
<output>16/21 = around 0.761905</output>
<result>E</result> | E | 0.761905 | In a room filled with 7 people, 4 people have exactly 1 sibling in the room and 3 people have exactly 2 siblings in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings? | {
"A": "5 / 21",
"B": "3 / 7",
"C": "4 / 7",
"D": "5 / 7",
"E": "16 / 21"
} | add(multiply(divide(4, 7), divide(subtract(7, 2), subtract(7, 1))), multiply(divide(4, 7), divide(subtract(7, 4), subtract(7, 1)))) | divide(n1,n0)|subtract(n0,n4)|subtract(n0,n2)|subtract(n0,n1)|divide(#1,#2)|divide(#3,#2)|multiply(#0,#4)|multiply(#0,#5)|add(#6,#7)| | "# of selections of 2 out of 7 - c 27 = 21 c 72 = 21 ; # of selections of 2 people which are not siblings - c 12 ∗ c 12 c 21 ∗ c 21 ( one from first pair of siblings * one from second pair of siblings ) + c 12 ∗ c 13 c 21 ∗ c 31 ( one from first pair of siblings * one from triple ) + c 1 ^ _ 2 * c ^ 1 _ 3 ( one from second pair of siblings * one from triple ) = 4 + 6 + 6 = 16 = 4 + 6 + 6 = 16 . p = 16 / 21 answer : e" | general |
math_qa__Yao6Dfn0MIwG8nWY | Working at their respective constant rates, machine A makes 100 copies in 12 minutes and machine B makes 150 copies in 15 minutes. If these machines work simultaneously at their respective rates for 30 minutes, what is the total number of copies that they will produce? Choose the most appropriate option:
A) 250 B) 425 C) 550 D) 700 E) 750 | <gadget id="calculator">100 / 12</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<gadget id="calculator">(25/3) + 10</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">(55/3) * 30</gadget>
<output>550</output>
<result>C</result> | C | 550 | Working at their respective constant rates, machine A makes 100 copies in 12 minutes and machine B makes 150 copies in 15 minutes. If these machines work simultaneously at their respective rates for 30 minutes, what is the total number of copies that they will produce? | {
"A": "250",
"B": "425",
"C": "550",
"D": "700",
"E": "750"
} | multiply(add(divide(100, 12), divide(150, 15)), 30) | divide(n0,n1)|divide(n2,n3)|add(#0,#1)|multiply(n4,#2) | machine a can produce 100 * 30 / 12 = 250 copies and , machine b can produce 150 * 30 / 15 = 300 copies total producing 550 copies . c is the answer | physics |
math_qa__29pH7QOeL8kT1IUT | Which number can we add to 897326 to get a number exactly divisible by 456?
Choose the correct answer.
A) 58 B) 66 C) 74 D) 82 E) 90 | <gadget id="calculator">897_326 % 456</gadget>
<output>374</output>
<gadget id="calculator">456 - 374</gadget>
<output>82</output>
<result>D</result> | D | 82 | Which number can we add to 897326 to get a number exactly divisible by 456? | {
"A": "58",
"B": "66",
"C": "74",
"D": "82",
"E": "90"
} | subtract(456, reminder(897326, 456)) | reminder(n0,n1)|subtract(n1,#0) | 897326 / 456 = 1967 with a remainder of 374 . we need to add 456 - 374 = 82 the answer is d . | general |
math_qa__rlCUz5sTmdCjQBDm | When two dice are rolled, what is the probability that the sum is either 7 or 11? Select: A) 1 / 4 B) 1 / 9 C) 4 / 3 D) 3 / 9 E) 2 / 9 | <gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">8 / 36</gadget>
<output>2/9 = around 0.222222</output>
<result>E</result> | E | 0.222222 | When two dice are rolled, what is the probability that the sum is either 7 or 11? | {
"A": "1 / 4",
"B": "1 / 9",
"C": "4 / 3",
"D": "3 / 9",
"E": "2 / 9"
} | divide(add(7, const_1), multiply(const_6, const_6)) | add(n0,const_1)|multiply(const_6,const_6)|divide(#0,#1) | total number of outcomes possible = 36 probability of getting sum of 7 = 6 / 36 probability of getting sum of 11 = 2 / 36 probability that the sum is either 7 or 11 = 6 / 36 + 2 / 36 = 2 / 9 answer : e | probability |
math_qa__A3ZrMUIAgk6dLe1d | The radius of a wheel is 24.2 cm. What is the distance covered by the wheel in making 500 resolutions? Pick one:
A) 708 m B) 704 m C) 774 m D) 760.57 m E) 744 m | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 1</gadget>
<output>22</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">(22/7) * 24.2</gadget>
<output>76.057143</output>
<gadget id="calculator">76.057143 * 2</gadget>
<output>152.114286</output>
<gadget id="calculator">152.114286 * 500</gadget>
<output>76_057.143</output>
<gadget id="calculator">76_057.143 / 100</gadget>
<output>760.57143</output>
<result>D</result> | D | 760.57 | The radius of a wheel is 24.2 cm. What is the distance covered by the wheel in making 500 resolutions? | {
"A": "708 m",
"B": "704 m",
"C": "774 m",
"D": "760.57 m",
"E": "744 m"
} | divide(multiply(multiply(multiply(divide(add(multiply(add(const_3, const_4), const_3), const_1), add(const_3, const_4)), 24.2), const_2), 500), const_100) | add(const_3,const_4)|multiply(#0,const_3)|add(#1,const_1)|divide(#2,#0)|multiply(n0,#3)|multiply(#4,const_2)|multiply(n1,#5)|divide(#6,const_100)| | "in one resolution , the distance covered by the wheel is its own circumference . distance covered in 500 resolutions . = 500 * 2 * 22 / 7 * 24.2 = 76057 cm = 760.57 m answer : d" | physics |
math_qa__Qhomjnoe9YD7i3qb | After spending Rs. 5000 on rent, Rs. 1500 on milk, Rs. 4500 on groceries, Rs.2500 On childrens education Rs. 2000 on petrol and Rs. 3940 on miscellaneous expenses, Mr. Kishore saved 10% of his monthly salary. How much did he save in Rs. ? Select the correct option: A) 2160 B) 2350 C) 2000 D) 2300 E) none of these | <gadget id="calculator">5_000 + 1_500</gadget>
<output>6_500</output>
<gadget id="calculator">6_500 + 4_500</gadget>
<output>11_000</output>
<gadget id="calculator">11_000 + 2_500</gadget>
<output>13_500</output>
<gadget id="calculator">13_500 + 2_000</gadget>
<output>15_500</output>
<gadget id="calculator">15_500 + 3_940</gadget>
<output>19_440</output>
<gadget id="calculator">19_440 * 100</gadget>
<output>1_944_000</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">1_944_000 / 90</gadget>
<output>21_600</output>
<gadget id="calculator">21_600 - 19_440</gadget>
<output>2_160</output>
<result>A</result> | A | 2,160 | After spending Rs. 5000 on rent, Rs. 1500 on milk, Rs. 4500 on groceries, Rs.2500 On childrens education Rs. 2000 on petrol and Rs. 3940 on miscellaneous expenses, Mr. Kishore saved 10% of his monthly salary. How much did he save in Rs. ? | {
"A": "2160",
"B": "2350",
"C": "2000",
"D": "2300",
"E": "none of these"
} | subtract(divide(multiply(add(add(add(add(add(5000, 1500), 4500), 2500), 2000), 3940), const_100), subtract(const_100, 10)), add(add(add(add(add(5000, 1500), 4500), 2500), 2000), 3940)) | add(n0,n1)|subtract(const_100,n6)|add(n2,#0)|add(n3,#2)|add(n4,#3)|add(n5,#4)|multiply(#5,const_100)|divide(#6,#1)|subtract(#7,#5)| | "explanation : total exp = 5000 + 1500 + 4500 + 2500 + 2000 + 3940 = 19440 exp in % = 100 - 10 = 90 % , 19440 = 90 % saving = 10 % = 19440 x 10 / 90 = rs . 2160 answer : a" | general |
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