id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__jYWtqaKurw06jbWC
|
Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.740 in 2 years? Options:
A) 221
B) 287
C) 400
D) 288
E) 671
|
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">740 / (441/400)</gadget>
<output>296_000/441 = around 671.201814</output>
<result>E</result>
|
E
| 671 |
Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.740 in 2 years?
|
{
"A": "221",
"B": "287",
"C": "400",
"D": "288",
"E": "671"
}
|
divide(740, power(add(const_1, divide(5, const_100)), 2))
|
divide(n0,const_100)|add(#0,const_1)|power(#1,n2)|divide(n1,#2)|
|
"explanation : 740 = p ( 21 / 20 ) 2 p = 671 answer : e"
|
general
|
math_qa__zQvhXULkPriuqQ8E
|
The Income of a man increase consistently by 2% per year. If his present income is Rs. 12000 then what will his income be after 1 year ? Choose the correct choice from the following answers
A) 12040
B) 12140
C) 12240
D) 12340
E) 12440
|
<gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 12_000</gadget>
<output>240</output>
<gadget id="calculator">240 + 12_000</gadget>
<output>12_240</output>
<result>C</result>
|
C
| 12,240 |
The Income of a man increase consistently by 2% per year. If his present income is Rs. 12000 then what will his income be after 1 year ?
|
{
"A": "12040",
"B": "12140",
"C": "12240",
"D": "12340",
"E": "12440"
}
|
add(multiply(divide(2, const_100), 12000), 12000)
|
divide(n0,const_100)|multiply(n1,#0)|add(n1,#1)
|
explanation : income = 12000 x 1.02 = 12240 answer : option c
|
gain
|
math_qa__Qccl2HRlj7WF2vvZ
|
When a number is divided by 6 &then multiply by 12 the answer is 18 what is the no.? Choose the correct option:
A) 4.5
B) 5
C) 5.6
D) 5.7
E) 9
|
<gadget id="calculator">18 / 12</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 6</gadget>
<output>9</output>
<result>E</result>
|
E
| 9 |
When a number is divided by 6 &then multiply by 12 the answer is 18 what is the no.?
|
{
"A": "4.5",
"B": "5",
"C": "5.6",
"D": "5.7",
"E": "9"
}
|
multiply(divide(18, 12), 6)
|
divide(n2,n1)|multiply(n0,#0)|
|
"if $ x $ is the number , x / 6 * 12 = 18 = > 2 x = 18 = > x = 9 e"
|
general
|
math_qa__buQhvxMcH78l1T0I
|
Donovan and Michael are racing around a circular 400-meter track. If Donovan runs each lap in 48 seconds and Michael runs each lap in 40 seconds, how many laps will Michael have to complete in order to pass Donovan, assuming they start at the same time? Select the correct option: A) 5 B) 7 C) 8 D) 9 E) 6
|
<gadget id="calculator">400 / 40</gadget>
<output>10</output>
<gadget id="calculator">400 / 48</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">10 - (25/3)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">400 / (5/3)</gadget>
<output>240</output>
<gadget id="calculator">240 / 40</gadget>
<output>6</output>
<result>E</result>
|
E
| 6 |
Donovan and Michael are racing around a circular 400-meter track. If Donovan runs each lap in 48 seconds and Michael runs each lap in 40 seconds, how many laps will Michael have to complete in order to pass Donovan, assuming they start at the same time?
|
{
"A": "5",
"B": "7",
"C": "8",
"D": "9",
"E": "6"
}
|
divide(divide(400, subtract(divide(400, 40), divide(400, 48))), 40)
|
divide(n0,n2)|divide(n0,n1)|subtract(#0,#1)|divide(n0,#2)|divide(#3,n2)|
|
"one way of approaching this question is by relative speed method 1 . speed / rate of donovan = distance / time = > 400 / 48 = > 50 / 6 2 . speed / rate of michael = distance / time = > 400 / 40 = > 10 relative speed between them = 10 - 50 / 6 = > 10 / 6 ( we subtract the rates if moving in the same direction and add the rates if moving in the opposite direction ) in order to pass donovan - distance to be covered = 400 , relative rate = 10 / 6 total time taken by micheal to surpass donovan = distance / rate = > 400 * 6 / 10 = > 2400 / 10 = > 240 no . of laps taken by michael = total time / michael ' s rate = > 240 / 40 = > 6 hence correct answer is 6 laps . e"
|
physics
|
math_qa__tTJuhznBEf9Q1ISg
|
A cistern 6 m long and 4 m wide contains water up to a breadth of 1 m 25 cm. Find the total area of the wet surface. Options.
A) 66 m square B) 49 m square C) 77 m square D) 44 m square E) 33 m square
|
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 4</gadget>
<output>5</output>
<gadget id="calculator">(5/4) * 6</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">5 + (15/2)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">2 * (25/2)</gadget>
<output>25</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">25 + 24</gadget>
<output>49</output>
<result>B</result>
|
B
| 49 |
A cistern 6 m long and 4 m wide contains water up to a breadth of 1 m 25 cm. Find the total area of the wet surface.
|
{
"A": "66 m square",
"B": "49 m square",
"C": "77 m square",
"D": "44 m square",
"E": "33 m square"
}
|
add(multiply(const_2, add(multiply(add(divide(25, const_100), 1), 4), multiply(add(divide(25, const_100), 1), 6))), multiply(4, 6))
|
divide(n3,const_100)|multiply(n0,n1)|add(n2,#0)|multiply(n1,#2)|multiply(n0,#2)|add(#3,#4)|multiply(#5,const_2)|add(#6,#1)|
|
"area of the wet surface = 2 [ lb + bh + hl ] - lb = 2 [ bh + hl ] + lb = 2 [ ( 4 * 1.25 + 6 * 1.25 ) ] + 6 * 4 = 49 m square answer : b"
|
physics
|
math_qa__sFU7MaLROEQsNACL
|
65% of the employees of a company are men. 60% of the men in the company speak French and 40% of the employees of the company speak French. What is % of the women in the company who do not speak French? Choose the correct choice from the following choices
A) 4 %
B) 10 %
C) 97.14 %
D) 90.14 %
E) 20 %
|
<gadget id="calculator">100 - 65</gadget>
<output>35</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(13/20) * (3/5)</gadget>
<output>39/100 = around 0.39</output>
<gadget id="calculator">(2/5) - (39/100)</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(7/20) - (1/100)</gadget>
<output>17/50 = around 0.34</output>
<gadget id="calculator">(17/50) / (7/20)</gadget>
<output>34/35 = around 0.971429</output>
<gadget id="calculator">(34/35) * 100</gadget>
<output>680/7 = around 97.142857</output>
<result>C</result>
|
C
| 97.14 |
65% of the employees of a company are men. 60% of the men in the company speak French and 40% of the employees of the company speak French. What is % of the women in the company who do not speak French?
|
{
"A": "4 %",
"B": "10 %",
"C": "97.14 %",
"D": "90.14 %",
"E": "20 %"
}
|
multiply(divide(subtract(divide(subtract(const_100, 65), const_100), subtract(divide(40, const_100), multiply(divide(65, const_100), divide(60, const_100)))), divide(subtract(const_100, 65), const_100)), const_100)
|
divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(const_100,n0)|divide(#3,const_100)|multiply(#1,#2)|subtract(#0,#5)|subtract(#4,#6)|divide(#7,#4)|multiply(#8,const_100)|
|
"no of employees = 100 ( say ) men = 65 women = 35 men speaking french = 0.60 * 65 = 39 employees speaking french = 0.4 * 100 = 40 therefore women speaking french = 40 - 39 = 1 and women not speaking french = 35 - 1 = 34 % of women not speaking french = 34 / 35 * 100 = 97.14 % answer c"
|
gain
|
math_qa__uDEpxr7F7sfIq3ju
|
A can do a piece of work in 6 days. B can do it in 6 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it? Answers
A) 8 days B) 2 days C) 6 days D) 7 days E) 4 days
|
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">36 / 6</gadget>
<output>6</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">36 - 24</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>C</result>
|
C
| 6 |
A can do a piece of work in 6 days. B can do it in 6 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
|
{
"A": "8 days",
"B": "2 days",
"C": "6 days",
"D": "7 days",
"E": "4 days"
}
|
divide(multiply(6, 6), divide(subtract(multiply(6, 6), multiply(add(divide(multiply(6, 6), 6), divide(multiply(6, 6), 6)), 2)), 2))
|
multiply(n0,n1)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)|multiply(n2,#3)|subtract(#0,#4)|divide(#5,n2)|divide(#0,#6)|
|
"c = 1 / 2 - 1 / 6 - 1 / 6 = 1 / 6 = > 6 days answer : c"
|
physics
|
math_qa__FvOg83NCtlgGAE7M
|
What is the median of a set of consecutive integers if the sum of nth number from the beginning and nth number from the end is 200?
Choose the correct choice from the following choices:
A) 10
B) 25
C) 50
D) 75
E) 100
|
<gadget id="calculator">200 / 2</gadget>
<output>100</output>
<result>E</result>
|
E
| 100 |
What is the median of a set of consecutive integers if the sum of nth number from the beginning and nth number from the end is 200?
|
{
"A": "10",
"B": "25",
"C": "50",
"D": "75",
"E": "100"
}
|
divide(200, const_2)
|
divide(n0,const_2)|
|
"surprisingly no one answered this easy one . property of a set of consecutive integerz . mean = median = ( first element + last element ) / 2 = ( second element + last but one element ) / 2 = ( third element + third last element ) / 2 etc . etc . so mean = median = 200 / 2 = 100 answer is e"
|
general
|
math_qa__GxH5MwSSVC5fuA5c
|
57+58=115. How many such 2 consecutive numbers are there less than 1500 when added gives a sum which is divisible by 5? Choose the most appropriate option:
A) 100 B) 200 C) 300 D) 400 E) 500
|
<gadget id="calculator">1_500 / 5</gadget>
<output>300</output>
<result>C</result>
|
C
| 300 |
57+58=115. How many such 2 consecutive numbers are there less than 1500 when added gives a sum which is divisible by 5?
|
{
"A": "100",
"B": "200",
"C": "300",
"D": "400",
"E": "500"
}
|
divide(1500, 5)
|
divide(n4,n5)|
|
"since 2 + 3 = 5 & 7 + 8 = 15 any combination with these no be will give u desirable result . . . so total no in 100 will be 20 & that ' s why in 1000 , it will be 20 x 15 = 300 . answer : c"
|
general
|
math_qa__cnLgxs5KEs5STlSI
|
The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned Options: A) 19828.88 B) 19828.8 C) 19828.87 D) 19828.81 E) 19828.82
|
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">1 + (2/25)</gadget>
<output>27/25 = around 1.08</output>
<gadget id="calculator">(27/25) ** 2</gadget>
<output>729/625 = around 1.1664</output>
<gadget id="calculator">(729/625) - 1</gadget>
<output>104/625 = around 0.1664</output>
<gadget id="calculator">2_828.8 / (104/625)</gadget>
<output>17_000</output>
<gadget id="calculator">17_000 + 2_828.8</gadget>
<output>19_828.8</output>
<result>B</result>
|
B
| 19,828.8 |
The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned
|
{
"A": "19828.88",
"B": "19828.8",
"C": "19828.87",
"D": "19828.81",
"E": "19828.82"
}
|
add(divide(2828.80, subtract(power(add(const_1, divide(8, const_100)), const_2), const_1)), 2828.80)
|
divide(n0,const_100)|add(#0,const_1)|power(#1,const_2)|subtract(#2,const_1)|divide(n1,#3)|add(n1,#4)|
|
"let the sum be rs . p p { [ 1 + 8 / 100 ] 2 - 1 } = 2828.80 p ( 8 / 100 ) ( 2 + 8 / 100 ) = 2828.80 [ a 2 - b 2 = ( a - b ) ( a + b ) ] p = 2828.80 / ( 0.08 ) ( 2.08 ) = 1360 / 0.08 = 17000 principal + interest = rs . 19828.80 answer : b"
|
gain
|
math_qa__XaowAD2FCRAgUX71
|
The diameter of a garden roller is 1.4 m and it is 2 m long. How much area will it cover in 5 revolutions ? (use Ο = 22β7)
Choose the correct choice from the following answers
A) 40 m 2 B) 44 m 2 C) 48 m 2 D) 36 m 2 E) none of these
|
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">2 * (22/7)</gadget>
<output>44/7 = around 6.285714</output>
<gadget id="calculator">1.4 / 2</gadget>
<output>0.7</output>
<gadget id="calculator">(44/7) * 0.7</gadget>
<output>4.4</output>
<gadget id="calculator">4.4 * 2</gadget>
<output>8.8</output>
<gadget id="calculator">5 * 8.8</gadget>
<output>44</output>
<result>B</result>
|
B
| 44 |
The diameter of a garden roller is 1.4 m and it is 2 m long. How much area will it cover in 5 revolutions ? (use Ο = 22β7)
|
{
"A": "40 m 2",
"B": "44 m 2",
"C": "48 m 2",
"D": "36 m 2",
"E": "none of these"
}
|
multiply(5, multiply(multiply(multiply(2, divide(22, 7)), divide(1.4, 2)), 2))
|
divide(n0,n1)|divide(n3,n4)|multiply(#1,n1)|multiply(#0,#2)|multiply(n1,#3)|multiply(n2,#4)|
|
"required area covered in 5 revolutions = 5 Γ 2 Ο rh = 5 Γ 2 Γ 22 β 7 Γ 0.7 Γ 2 = 44 m 2 answer b"
|
general
|
math_qa__AvcRT3eYZ6zvpH0b
|
What is the dividend. divisor 16, the quotient is 8 and the remainder is 4 Choose the correct answer
A) 127 B) 128 C) 130 D) 131 E) 132
|
<gadget id="calculator">16 * 8</gadget>
<output>128</output>
<gadget id="calculator">128 + 4</gadget>
<output>132</output>
<result>E</result>
|
E
| 132 |
What is the dividend. divisor 16, the quotient is 8 and the remainder is 4
|
{
"A": "127",
"B": "128",
"C": "130",
"D": "131",
"E": "132"
}
|
add(multiply(16, 8), 4)
|
multiply(n0,n1)|add(n2,#0)|
|
"e = d * q + r e = 16 * 8 + 4 e = 128 + 4 e = 132"
|
general
|
math_qa__UepKhF6w0yOS4nfJ
|
If A, B and C together can finish a piece of work in 4 days. A alone in 36 days and B in 18 days, then C alone can do it in?
Pick one: A) 1 B) 7 C) 8 D) 9 E) 6
|
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 36</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">(1/4) - (1/36)</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(2/9) - (1/18)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>E</result>
|
E
| 6 |
If A, B and C together can finish a piece of work in 4 days. A alone in 36 days and B in 18 days, then C alone can do it in?
|
{
"A": "1",
"B": "7",
"C": "8",
"D": "9",
"E": "6"
}
|
divide(const_1, subtract(subtract(const_0_25, divide(const_1, 36)), divide(const_1, 18)))
|
divide(const_1,n1)|divide(const_1,n2)|subtract(const_0_25,#0)|subtract(#2,#1)|divide(const_1,#3)|
|
"c = 1 / 4 - 1 / 36 β 1 / 18 = 1 / 6 = > 6 days ' answer : e"
|
physics
|
math_qa__D7QpTWTIS0j2dWnf
|
In a coconut grove, (x + 1) trees yield 60 nuts per year, x trees yield 120 nuts per year and (x β 1) trees yield 180 nuts per year. If the average yield per year per tree be 100, find x. Choices
A) 2 B) 4 C) 5 D) 6 E) none of the above
|
<gadget id="calculator">180 * 1</gadget>
<output>180</output>
<gadget id="calculator">60 * 1</gadget>
<output>60</output>
<gadget id="calculator">180 - 60</gadget>
<output>120</output>
<gadget id="calculator">60 + 120</gadget>
<output>180</output>
<gadget id="calculator">180 + 180</gadget>
<output>360</output>
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<gadget id="calculator">360 - 300</gadget>
<output>60</output>
<gadget id="calculator">120 / 60</gadget>
<output>2</output>
<result>A</result>
|
A
| 2 |
In a coconut grove, (x + 1) trees yield 60 nuts per year, x trees yield 120 nuts per year and (x β 1) trees yield 180 nuts per year. If the average yield per year per tree be 100, find x.
|
{
"A": "2",
"B": "4",
"C": "5",
"D": "6",
"E": "none of the above"
}
|
divide(subtract(multiply(180, 1), multiply(60, 1)), subtract(add(add(60, 120), 180), multiply(100, const_3)))
|
add(n1,n2)|multiply(n0,n4)|multiply(n0,n1)|multiply(n5,const_3)|add(n4,#0)|subtract(#1,#2)|subtract(#4,#3)|divide(#5,#6)|
|
"( x + 1 ) Γ 60 + x Γ 120 + ( x β 1 ) Γ 180 / ( x + 1 ) + x + ( x β 1 ) = 100 β 360 x β 120 / 3 x = 100 β 60 x = 120 β x = 2 answer a"
|
general
|
math_qa__2PmpE3aqcHhZ2H7r
|
The area of a circular field is 17.56 hectares. Find the cost of fencing it at the rate of Rs. 3 per metre approximately Pick.
A) 4457 B) 4567 C) 4235 D) 4547 E) 4675
|
<gadget id="calculator">17.56 / pi</gadget>
<output>17.56/pi = around 5.589522</output>
<gadget id="calculator">(17.56/pi) ** (1/2)</gadget>
<output>4.19046536795139/sqrt(pi) = around 2.364217</output>
<gadget id="calculator">(4.19046536795139/sqrt(pi)) * 100</gadget>
<output>419.046536795139/sqrt(pi) = around 236.421691</output>
<gadget id="calculator">2 * pi * (419.046536795139/sqrt(pi))</gadget>
<output>838.093073590278*sqrt(pi) = around 1_485.481296</output>
<gadget id="calculator">(838.093073590278*sqrt(pi)) * 3</gadget>
<output>2514.27922077083*sqrt(pi) = around 4_456.443887</output>
<result>A</result>
|
A
| 4,457 |
The area of a circular field is 17.56 hectares. Find the cost of fencing it at the rate of Rs. 3 per metre approximately
|
{
"A": "4457",
"B": "4567",
"C": "4235",
"D": "4547",
"E": "4675"
}
|
multiply(circumface(multiply(sqrt(divide(17.56, const_pi)), const_100)), const_3)
|
divide(n0,const_pi)|sqrt(#0)|multiply(#1,const_100)|circumface(#2)|multiply(#3,const_3)
|
explanation : area = ( 17.56 x 10000 ) m 2 = 175600 m 2 . Ο r 2 = 175600 β ( r ) 2 = ( 175600 x ( 7 / 22 ) ) β r = 236.37 m . circumference = 2 Ο r = ( 2 x ( 22 / 7 ) x 236.37 ) m = 1485.78 m . cost of fencing = rs . ( 1485.78 x 3 ) = rs . 4457 . answer : option a
|
geometry
|
math_qa__zHICWP7K900ZSzcN
|
A certain no. when divided by 35leaves a remainder 25, what is the remainder if the same no.be divided by 15?
Answers
A) 2
B) 4
C) 7
D) 8
E) 9
|
<gadget id="calculator">35 + 25</gadget>
<output>60</output>
<gadget id="calculator">60 / 15</gadget>
<output>4</output>
<result>B</result>
|
B
| 4 |
A certain no. when divided by 35leaves a remainder 25, what is the remainder if the same no.be divided by 15?
|
{
"A": "2",
"B": "4",
"C": "7",
"D": "8",
"E": "9"
}
|
divide(add(35, 25), 15)
|
add(n0,n1)|divide(#0,n2)
|
explanation : 35 + 25 = 60 / 15 = 4 ( remainder ) b
|
general
|
math_qa__RGInKZrNfDeaQBiS
|
There is a point P on the circle. A and B started running in two constant different speeds. A in Clockwise and B in Anti-clockwise. First time 500 m in Clockwise from P then 400 Anti-clockwise. If B is yet to complete one round, What is the circumference of the circle? Choose the most appropriate option: A) 700 B) 800 C) 900 D) 1000 E) 1100
|
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">2 * 500</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 + 400</gadget>
<output>1_400</output>
<gadget id="calculator">1_400 / 2</gadget>
<output>700</output>
<result>A</result>
|
A
| 700 |
There is a point P on the circle. A and B started running in two constant different speeds. A in Clockwise and B in Anti-clockwise. First time 500 m in Clockwise from P then 400 Anti-clockwise. If B is yet to complete one round, What is the circumference of the circle?
|
{
"A": "700",
"B": "800",
"C": "900",
"D": "1000",
"E": "1100"
}
|
divide(add(multiply(multiply(const_1, const_2), 500), 400), const_2)
|
multiply(const_1,const_2)|multiply(n0,#0)|add(n1,#1)|divide(#2,const_2)
|
let the speeds of a & b be u and v resp . and let circumference be c . let their first meeting be after time t then ut + vt = c and ut = 500 β΄ vt = c β 500 and u / v = 500 / ( c β 500 ) for their second meeting after time t , ut + vt = 2 c and vt = 400 β΄ ut = 2 c β 400 and u / v = ( 2 c β 400 ) / 400 hence 500 / ( c β 500 ) = ( 2 c β 400 ) / 400 simplifying , 100000 = ( c β 200 ) ( c β 500 ) = c Β² β 700 c + 100000 β c = 700 answer : a
|
physics
|
math_qa__KNdoz5rqPJNZP1TA
|
Carina has 55 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have? Choose the correct choice from the following answers:
A) 7
B) 6
C) 5
D) 4
E) 3
|
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">55 - 10</gadget>
<output>45</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">45 / 15</gadget>
<output>3</output>
<result>E</result>
|
E
| 3 |
Carina has 55 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have?
|
{
"A": "7",
"B": "6",
"C": "5",
"D": "4",
"E": "3"
}
|
divide(subtract(55, multiply(5, 2)), add(10, 5))
|
add(n1,n2)|multiply(n1,n3)|subtract(n0,#1)|divide(#2,#0)
|
lets say 5 and 10 ounce packages be x and y respectively . given that , 5 x + 10 y = 55 and x = y + 2 . what is the value of y . substituting the x in first equation , 5 y + 10 + 10 y = 55 - > y = 45 / 15 . = 3 e
|
general
|
math_qa__oqd0lSNNv7gmJJXf
|
A computer manufacturer produces a certain electronic component at a cost of $50 per component. Shipping costs for delivering the components are $8 per unit. Further, the manufacturer has costs of $16,000 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 200 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues? Choices
A) 135 B) 129 C) 131 D) 138 E) 141
|
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 1_000</gadget>
<output>16_000</output>
<gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">16_000 + 800</gadget>
<output>16_800</output>
<gadget id="calculator">50 + 8</gadget>
<output>58</output>
<gadget id="calculator">58 * 200</gadget>
<output>11_600</output>
<gadget id="calculator">16_800 + 11_600</gadget>
<output>28_400</output>
<gadget id="calculator">28_400 / 200</gadget>
<output>142</output>
<result>D</result>
|
D
| 138 |
A computer manufacturer produces a certain electronic component at a cost of $50 per component. Shipping costs for delivering the components are $8 per unit. Further, the manufacturer has costs of $16,000 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 200 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues?
|
{
"A": "135",
"B": "129",
"C": "131",
"D": "138",
"E": "141"
}
|
divide(add(add(multiply(multiply(const_4, const_4), const_1000), multiply(8, const_100)), multiply(add(50, 8), 200)), 200)
|
add(n0,n1)|multiply(const_4,const_4)|multiply(n1,const_100)|multiply(#1,const_1000)|multiply(n3,#0)|add(#3,#2)|add(#5,#4)|divide(#6,n3)|
|
"$ 16000 is a fixed cost each component is $ 58 ( $ 50 to produce , $ 8 to ship ) manufacturer will be producing and selling 200 components so therefore the equation to find price would be 200 * p = 16000 + ( 200 * 50 ) + ( 200 * 8 ) p = ( 16000 + 10000 + 1600 ) / 200 p = 138 answer : d"
|
general
|
math_qa__iSkft29iamcbGv7w
|
The radius of a circle is increased by 1%. Find how much % does its area increases? Select.
A) 2.21 % B) 2.07 % C) 2.08 % D) 2.01 % E) 2.11 %
|
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 + 1</gadget>
<output>201</output>
<gadget id="calculator">201 / 100</gadget>
<output>201/100 = around 2.01</output>
<result>D</result>
|
D
| 2.01 |
The radius of a circle is increased by 1%. Find how much % does its area increases?
|
{
"A": "2.21 %",
"B": "2.07 %",
"C": "2.08 %",
"D": "2.01 %",
"E": "2.11 %"
}
|
divide(add(multiply(const_2, const_100), 1), const_100)
|
multiply(const_100,const_2)|add(n0,#0)|divide(#1,const_100)
|
r = 100 r = 101 r 2 = 10000 r 2 = 10201 10000 - - - - 201 100 - - - - ? = > 2.01 % answer : d
|
geometry
|
math_qa__sYTawUAXMgmi8BYD
|
In Gabriel's sheep herd, every sheep has either fleas or lice or both. Half of the sheep have lice, and 84 sheep have both pests. If 94 sheep have lice, how many sheep have only fleas? Choose the correct choice.
A) 10
B) 20
C) 84
D) 94
E) 178
|
<gadget id="calculator">94 - 84</gadget>
<output>10</output>
<result>A</result>
|
A
| 10 |
In Gabriel's sheep herd, every sheep has either fleas or lice or both. Half of the sheep have lice, and 84 sheep have both pests. If 94 sheep have lice, how many sheep have only fleas?
|
{
"A": "10",
"B": "20",
"C": "84",
"D": "94",
"E": "178"
}
|
subtract(94, 84)
|
subtract(n1,n0)
|
n ( lice ) = n ( only lice ) + n ( both lice and fleas ) n ( both lice and fleas ) = 84 n ( lice ) = 94 n ( only lice ) = 94 - 84 = 10 since , it is also said that exactly half the sheep have lice , it can be inferred that half the number of sheep is 94 . therefore , the total number of sheep having only fleas is 10 ans : ( option a )
|
other
|
math_qa__KOcqiZS7PTHWvc5y
|
Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 7 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B? Options:
A) 56 % B) 80 % C) 100 % D) 120 % E) 125 %
|
<gadget id="calculator">8 / 10</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) ** 2</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">(16/25) * (7/8)</gadget>
<output>14/25 = around 0.56</output>
<gadget id="calculator">(14/25) * 100</gadget>
<output>56</output>
<result>A</result>
|
A
| 56 |
Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 7 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B?
|
{
"A": "56 %",
"B": "80 %",
"C": "100 %",
"D": "120 %",
"E": "125 %"
}
|
multiply(multiply(power(divide(8, 10), const_2), divide(7, 8)), const_100)
|
divide(n0,n2)|divide(n1,n3)|power(#1,const_2)|multiply(#0,#2)|multiply(#3,const_100)|
|
"for a , r = 8 / 2 pi . its capacity = ( 4 pi ) ^ 2 * 7 = 112 pi for b , r = 10 / pi . its capacity = ( 5 pi ) ^ 2 * 8 = 200 pi a / b = 112 pi / 200 pi = 0.56 a"
|
physics
|
math_qa__b3FGLyQSAga51l4N
|
The speed of a subway train is represented by the equation z=s^2+2s for all situations where 0β€sβ€7, where z is the rate of speed in kilometers per hour and s is the time in seconds from the moment the train starts moving. In kilometers per hour, how much faster is the subway train moving after 6 seconds than it was moving after 3 seconds? Pick: A) 4 B) 9 C) 15 D) 48 E) 33
|
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">36 + 12</gadget>
<output>48</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">9 + 6</gadget>
<output>15</output>
<gadget id="calculator">48 - 15</gadget>
<output>33</output>
<result>E</result>
|
E
| 33 |
The speed of a subway train is represented by the equation z=s^2+2s for all situations where 0β€sβ€7, where z is the rate of speed in kilometers per hour and s is the time in seconds from the moment the train starts moving. In kilometers per hour, how much faster is the subway train moving after 6 seconds than it was moving after 3 seconds?
|
{
"A": "4",
"B": "9",
"C": "15",
"D": "48",
"E": "33"
}
|
subtract(add(power(6, 2), multiply(6, 2)), add(power(3, const_2), multiply(3, 2)))
|
multiply(n0,n4)|multiply(n0,n5)|power(n4,n0)|power(n5,const_2)|add(#0,#2)|add(#1,#3)|subtract(#4,#5)
|
given : z = s ^ 2 + 2 s for 0 β€ s β€ 7 z ( 3 ) = 3 ^ 2 + 2 * 3 = 15 z ( 6 ) = 6 ^ 2 + 2 * 6 = 48 therefore z ( 7 ) - z ( 3 ) = 48 - 15 = 33 km / hr option e
|
physics
|
math_qa__shZfNQ03OEdW42Qr
|
notebooks are sold in packages of 4 or 7 only . if wilson bought 69 notebooks exactly , what could be the number of large packs wilson bought ? Choose the correct choice from the following.
A) 3
B) 4
C) 7
D) 8
E) 9
|
<gadget id="calculator">69 - 4</gadget>
<output>65</output>
<gadget id="calculator">65 - 4</gadget>
<output>61</output>
<gadget id="calculator">61 - 4</gadget>
<output>57</output>
<gadget id="calculator">57 - 4</gadget>
<output>53</output>
<gadget id="calculator">53 - 4</gadget>
<output>49</output>
<gadget id="calculator">49 / 7</gadget>
<output>7</output>
<result>C</result>
|
C
| 7 |
notebooks are sold in packages of 4 or 7 only . if wilson bought 69 notebooks exactly , what could be the number of large packs wilson bought ?
|
{
"A": "3",
"B": "4",
"C": "7",
"D": "8",
"E": "9"
}
|
divide(subtract(subtract(subtract(subtract(subtract(69, 4), 4), 4), 4), 4), 7)
|
subtract(n2,n0)|subtract(#0,n0)|subtract(#1,n0)|subtract(#2,n0)|subtract(#3,n0)|divide(#4,n1)
|
let number of packs of four = f let number of packs of seven = s 4 f + 7 s = 69 now , we need to test for values of s . since sum 69 is odd and 4 f will always be even , e ca n ' t be even . now , we can test for values e = 3 , 7 and 9 4 * 5 + 7 * 7 = 20 + 49 = 69 answer c
|
general
|
math_qa__57XHM4lHbnxeRoML
|
A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.340 less than the sum lent. What was the sum lent? Choose the correct choice from the following choices.
A) 228 B) 278 C) 289 D) 500 E) 821
|
<gadget id="calculator">4 * 8</gadget>
<output>32</output>
<gadget id="calculator">32 / 100</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">1 - (8/25)</gadget>
<output>17/25 = around 0.68</output>
<gadget id="calculator">340 / (17/25)</gadget>
<output>500</output>
<result>D</result>
|
D
| 500 |
A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.340 less than the sum lent. What was the sum lent?
|
{
"A": "228",
"B": "278",
"C": "289",
"D": "500",
"E": "821"
}
|
divide(340, subtract(const_1, divide(multiply(4, 8), const_100)))
|
multiply(n0,n1)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2)|
|
"p - 340 = ( p * 4 * 8 ) / 100 p = 500 answer : d"
|
gain
|
math_qa__1HaOJWarESuFyvpX
|
A contractor isengaged for 30days on the condition that he receives Rs.25 for eachday he works & fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many days was heabsent?
Choices:
A) 8
B) 10
C) 15
D) 17
E) 21
|
<gadget id="calculator">25 * 30</gadget>
<output>750</output>
<gadget id="calculator">750 - 425</gadget>
<output>325</output>
<gadget id="calculator">25 + 7.5</gadget>
<output>32.5</output>
<gadget id="calculator">325 / 32.5</gadget>
<output>10</output>
<result>B</result>
|
B
| 10 |
A contractor isengaged for 30days on the condition that he receives Rs.25 for eachday he works & fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many days was heabsent?
|
{
"A": "8",
"B": "10",
"C": "15",
"D": "17",
"E": "21"
}
|
divide(subtract(multiply(25, 30), 425), add(25, 7.5))
|
add(n1,n2)|multiply(n0,n1)|subtract(#1,n3)|divide(#2,#0)
|
30 * 25 = 750 425 - - - - - - - - - - - 325 25 + 7.50 = 32.5 325 / 32.5 = b
|
physics
|
math_qa__rdND9FQz2mNDR1dv
|
A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 30 days more. What is the reinforcement? Choose the correct choice from the following answers:
A) 1800 men B) 3900 men C) 600 men D) 3800 men E) 900 men
|
<gadget id="calculator">2_000 * 54</gadget>
<output>108_000</output>
<gadget id="calculator">2_000 * 15</gadget>
<output>30_000</output>
<gadget id="calculator">108_000 - 30_000</gadget>
<output>78_000</output>
<gadget id="calculator">78_000 / 30</gadget>
<output>2_600</output>
<gadget id="calculator">2_600 - 2_000</gadget>
<output>600</output>
<result>C</result>
|
C
| 600 |
A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 30 days more. What is the reinforcement?
|
{
"A": "1800 men",
"B": "3900 men",
"C": "600 men",
"D": "3800 men",
"E": "900 men"
}
|
subtract(divide(subtract(multiply(2000, 54), multiply(2000, 15)), 30), 2000)
|
multiply(n0,n1)|multiply(n0,n2)|subtract(#0,#1)|divide(#2,n3)|subtract(#3,n0)|
|
"2000 - - - - 54 2000 - - - - 39 x - - - - - 20 x * 30 = 2000 * 39 x = 2600 2000 - - - - - - - 600 answer : c"
|
physics
|
math_qa__AdXONrTXNRFn0m82
|
The ages of two person differ by 20 years. If 4 years ago, the elder one be 5 times as old as the younger one, their present ages(in years) are respectively Choose the correct choice from the following answers: A) 30 , 10 B) 25 , 5 C) 29 , 9 D) 50 , 30 E) 20,10
|
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 - 4</gadget>
<output>16</output>
<gadget id="calculator">20 + 16</gadget>
<output>36</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<gadget id="calculator">9 + 20</gadget>
<output>29</output>
<result>C</result>
|
C
| 29 |
The ages of two person differ by 20 years. If 4 years ago, the elder one be 5 times as old as the younger one, their present ages(in years) are respectively
|
{
"A": "30 , 10",
"B": "25 , 5",
"C": "29 , 9",
"D": "50 , 30",
"E": "20,10"
}
|
add(divide(add(multiply(5, 4), subtract(20, 4)), subtract(5, const_1)), 20)
|
multiply(n1,n2)|subtract(n0,n1)|subtract(n2,const_1)|add(#0,#1)|divide(#3,#2)|add(n0,#4)|
|
"let their ages be x and ( x + 20 ) years . then , 5 ( x - 4 ) = ( x + 20 - 4 ) = > 4 x = 36 = > x = 9 their present ages are 29 years and 9 year . answer : c"
|
general
|
math_qa__cvlc4pXTifbeIMVT
|
28 machines can do a work in 10days. How many machines are needed to complete the work in 40days?
Choose the most appropriate option:
A) 10 B) 6 C) 4 D) 7 E) 5
|
<gadget id="calculator">28 * 10</gadget>
<output>280</output>
<gadget id="calculator">280 / 40</gadget>
<output>7</output>
<result>D</result>
|
D
| 7 |
28 machines can do a work in 10days. How many machines are needed to complete the work in 40days?
|
{
"A": "10",
"B": "6",
"C": "4",
"D": "7",
"E": "5"
}
|
divide(multiply(28, 10), 40)
|
multiply(n0,n1)|divide(#0,n2)|
|
"required number of machines = 28 * 10 / 40 = 7 answer is d"
|
physics
|
math_qa__ZRdwEmxOiXbgZ91Z
|
Sandy buys an old scooter for $800 and spends $200 on its repairs. If Sandy sells the scooter for $1400, what is the gain percent? Choose the correct choice from the following choices:
A) 20 % B) 30 % C) 40 % D) 50 % E) 60 %
|
<gadget id="calculator">200 + 800</gadget>
<output>1_000</output>
<gadget id="calculator">1_400 - 1_000</gadget>
<output>400</output>
<gadget id="calculator">400 / 1_000</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>C</result>
|
C
| 40 |
Sandy buys an old scooter for $800 and spends $200 on its repairs. If Sandy sells the scooter for $1400, what is the gain percent?
|
{
"A": "20 %",
"B": "30 %",
"C": "40 %",
"D": "50 %",
"E": "60 %"
}
|
multiply(divide(subtract(1400, add(200, 800)), add(200, 800)), const_100)
|
add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)|
|
"selling price / total cost = 1400 / 1000 = 1.4 the gain percent is 40 % . the answer is c ."
|
gain
|
math_qa__LvV4G69OeKLZ58AX
|
A jogger running at 9 kmph alongside a railway track in 240 meters ahead of the engine of a 120 metres long train running at 45 kmph in the same direction . in how much time will the train pass the jogger ? Select: A) 18 seconds B) 26 seconds C) 36 seconds D) 16 seconds E) 46 seconds
|
<gadget id="calculator">240 + 120</gadget>
<output>360</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">360 / 10</gadget>
<output>36</output>
<result>C</result>
|
C
| 36 |
A jogger running at 9 kmph alongside a railway track in 240 meters ahead of the engine of a 120 metres long train running at 45 kmph in the same direction . in how much time will the train pass the jogger ?
|
{
"A": "18 seconds",
"B": "26 seconds",
"C": "36 seconds",
"D": "16 seconds",
"E": "46 seconds"
}
|
divide(add(240, 120), multiply(subtract(45, 9), const_0_2778))
|
add(n1,n2)|subtract(n3,n0)|multiply(#1,const_0_2778)|divide(#0,#2)
|
total distance ( d ) = 240 + 120 = 360 meter relative speed ( s ) = 45 - 9 = 36 kmph = 36 * 5 / 18 = 10 mps d = s * t 360 = 10 * t t = 36 seconds answer : c
|
physics
|
math_qa__hVYg2HgacMAzbOCl
|
A woman complete a journey in 15 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km. Choose the correct choice from the following choices
A) 336 km .
B) 216 km .
C) 314 km .
D) 224 km .
E) 544 km .
|
<gadget id="calculator">15 * 24</gadget>
<output>360</output>
<gadget id="calculator">24 + 21</gadget>
<output>45</output>
<gadget id="calculator">360 / 45</gadget>
<output>8</output>
<gadget id="calculator">8 * 21</gadget>
<output>168</output>
<gadget id="calculator">168 * 2</gadget>
<output>336</output>
<result>A</result>
|
A
| 336 |
A woman complete a journey in 15 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
|
{
"A": "336 km .",
"B": "216 km .",
"C": "314 km .",
"D": "224 km .",
"E": "544 km ."
}
|
multiply(multiply(divide(multiply(15, 24), add(24, 21)), 21), const_2)
|
add(n1,n2)|multiply(n0,n2)|divide(#1,#0)|multiply(n1,#2)|multiply(#3,const_2)|
|
"0.5 x / 21 + 0.5 x / 24 = 15 - - > x / 21 + x / 24 = 30 - - > x = 336 km . a"
|
physics
|
math_qa__zf65CKHoP2NvomKN
|
how many 3 - digit integers exist such that all their digits are odd ?
Select the correct option.
A) 80
B) 100
C) 120
D) 125
E) 135
|
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<result>D</result>
|
D
| 125 |
how many 3 - digit integers exist such that all their digits are odd ?
|
{
"A": "80",
"B": "100",
"C": "120",
"D": "125",
"E": "135"
}
|
power(add(3, const_2), 3)
|
add(n0,const_2)|power(#0,n0)
|
so last digit can be filled in 5 ways - 1 , 3,5 , 7,9 there are 5 possibilities . the answer is 5 β 5 β 5 = 125 the correct answer is d
|
general
|
math_qa__STw0u2lbs4cPitxO
|
Matt gets a $1,300 commission on a big sale. This commission alone raises his average commission by $150. If Matt's new average commission is $400, how many sales has Matt made?
Select:
A) 3 B) 4 C) 5 D) 6 E) 7
|
<gadget id="calculator">1_000 - 100</gadget>
<output>900</output>
<gadget id="calculator">400 - 150</gadget>
<output>250</output>
<gadget id="calculator">400 - 250</gadget>
<output>150</output>
<gadget id="calculator">900 / 150</gadget>
<output>6</output>
<result>D</result>
|
D
| 6 |
Matt gets a $1,300 commission on a big sale. This commission alone raises his average commission by $150. If Matt's new average commission is $400, how many sales has Matt made?
|
{
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
}
|
divide(subtract(const_1000, const_100), subtract(400, subtract(400, 150)))
|
subtract(const_1000,const_100)|subtract(n2,n1)|subtract(n2,#1)|divide(#0,#2)|
|
"let , average commission = x no . of items sold = y total commission = xy new commission = xy + 1300 new average = ( xy + 1300 ) / ( y + 1 ) = 150 + x i . e . ( xy + 1300 ) = ( y + 1 ) * ( 150 + x ) i . e . ( xy + 1300 ) = ( xy + x + 150 y + 150 ) i . e . ( 1150 ) = ( x + 150 y ) new commission = 400 = 150 + x i . e . x = 250 i . e . y = 6 new sales = y + 1 = 7 answer : option d"
|
general
|
math_qa__flrEiJLkgAD88BeA
|
a student reached his school late by 20mins by travelling at a speed of 9kmph.if he had travelled at a speed of 12kmph,he would have reached his school 20mins early.what is the distance between house and school? Choose the correct choice from the following options:
A) 24
B) 25
C) 26
D) 27
E) 28
|
<gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) + (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">12 * 9</gadget>
<output>108</output>
<gadget id="calculator">12 - 9</gadget>
<output>3</output>
<gadget id="calculator">108 / 3</gadget>
<output>36</output>
<gadget id="calculator">(2/3) * 36</gadget>
<output>24</output>
<result>A</result>
|
A
| 24 |
a student reached his school late by 20mins by travelling at a speed of 9kmph.if he had travelled at a speed of 12kmph,he would have reached his school 20mins early.what is the distance between house and school?
|
{
"A": "24",
"B": "25",
"C": "26",
"D": "27",
"E": "28"
}
|
multiply(add(divide(20, const_60), divide(20, const_60)), divide(multiply(12, 9), subtract(12, 9)))
|
divide(n0,const_60)|multiply(n1,n2)|subtract(n2,n1)|add(#0,#0)|divide(#1,#2)|multiply(#3,#4)
|
distance = distance either student reaches school before time or after time 9 ( t + 20 / 60 ) = 12 ( t - 20 / 60 ) i . e 9 ( t + 1 / 3 ) = 12 ( t - 1 / 3 ) 9 ( 3 t + 1 ) = 12 ( 3 t - 1 ) t = 7 / 3 put t value in any of distance equation put t = 7 / 3 in 9 ( t + 1 / 3 ) we get 24 km answer : a
|
physics
|
math_qa__20kr4mtZwa8XRfxJ
|
A student is ranked 13th from right and 8th from left.how many are there? Choices.
A) 18 B) 19 C) 20 D) 21 E) 22
|
<gadget id="calculator">13 + 8</gadget>
<output>21</output>
<gadget id="calculator">21 - 1</gadget>
<output>20</output>
<result>C</result>
|
C
| 20 |
A student is ranked 13th from right and 8th from left.how many are there?
|
{
"A": "18",
"B": "19",
"C": "20",
"D": "21",
"E": "22"
}
|
subtract(add(13, 8), const_1)
|
add(n0,n1)|subtract(#0,const_1)|
|
"13 th from right means = x + 12 8 th from left means = 7 + x total = 12 + 7 + 1 = 20 answer : c"
|
general
|
math_qa__CLs9EcRg1YLJIo7H
|
how many 4 - digit odd numbers do not use any digit more than once ?
Choose the correct choice from the following options:
A) 1728
B) 2160
C) 2240
D) 2268
E) 2520
|
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 * 8</gadget>
<output>64</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">64 * 7</gadget>
<output>448</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">448 * 5</gadget>
<output>2_240</output>
<result>D</result>
|
D
| 2,268 |
how many 4 - digit odd numbers do not use any digit more than once ?
|
{
"A": "1728",
"B": "2160",
"C": "2240",
"D": "2268",
"E": "2520"
}
|
multiply(multiply(multiply(multiply(const_2, const_4), multiply(const_2, const_4)), add(const_4, const_3)), add(const_1, const_4))
|
add(const_1,const_4)|add(const_3,const_4)|multiply(const_2,const_4)|multiply(#2,#2)|multiply(#1,#3)|multiply(#0,#4)
|
let a 4 - digit number be represented by abcd here a can have any value between 1 to 9 - so total 9 b can have any value between 0 to 9 , but not a - so total 9 c can have any value between 0 to 9 , but not a or b - so total 8 d can have any value between 0 to 9 , but not a , b or c - so total 7 no . of all possible 4 - digit nos ( without repeating any digit ) = 9 * 9 * 8 * 7 = 4536 half of these would be odd . therefor , no . of odd possible 4 - digit nos ( without repeating any digit ) = 4536 / 2 = 2268 answer should be d .
|
general
|
math_qa__L2ntrd0kbb2rSDpS
|
a is older than b by 5 years . 7 years hence , thrice a ' s age shall be equal to 4 times that of b . find their present ages . Choose the correct choice from the following choices
A) 14 , 7 B) 10 , 5 C) 13 , 8 D) 12 , 8 E) 8 , 12
|
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">15 + 21</gadget>
<output>36</output>
<gadget id="calculator">4 * 7</gadget>
<output>28</output>
<gadget id="calculator">36 - 28</gadget>
<output>8</output>
<gadget id="calculator">8 + 5</gadget>
<output>13</output>
<result>C</result>
|
C
| 13 |
a is older than b by 5 years . 7 years hence , thrice a ' s age shall be equal to 4 times that of b . find their present ages .
|
{
"A": "14 , 7",
"B": "10 , 5",
"C": "13 , 8",
"D": "12 , 8",
"E": "8 , 12"
}
|
add(subtract(add(multiply(const_3, 5), multiply(const_3, 7)), multiply(4, 7)), 5)
|
multiply(n0,const_3)|multiply(n1,const_3)|multiply(n1,n2)|add(#0,#1)|subtract(#3,#2)|add(n0,#4)
|
explanation : let the present ages of a and b be ' a ' and ' b ' respectively . 3 ( a + 7 ) = 4 ( ( b + 7 ) - - - ( 1 ) = > 3 a - 4 b = 7 - - - - - - - ( 1 ) a - b = 5 - - - - - - - ( 2 ) solving ( 1 ) and ( 2 ) we get b = 8 substituting b = 8 in second equation , we get a = 13 . answer : c = > 2 a = 32 = > a = 16 . answer : c
|
general
|
math_qa__ngXx2abzIY2sWtFE
|
What is x if x + 2y = 20 and y = 5? Choose the correct answer:
A) 10
B) 8
C) 6
D) 4
E) 2
|
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<result>A</result>
|
A
| 10 |
What is x if x + 2y = 20 and y = 5?
|
{
"A": "10",
"B": "8",
"C": "6",
"D": "4",
"E": "2"
}
|
subtract(20, multiply(2, 5))
|
multiply(n0,n2)|subtract(n1,#0)|
|
"x = 20 - 2 y x = 20 - 10 . x = 10 answer : a"
|
general
|
math_qa__YnXFpjwOrHia62ry
|
Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 48 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
Pick one.
A) 15 seconds B) 18 seconds C) 24 seconds D) 30 seconds E) 45 seconds
|
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<result>C</result>
|
C
| 24 |
Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 48 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
|
{
"A": "15 seconds",
"B": "18 seconds",
"C": "24 seconds",
"D": "30 seconds",
"E": "45 seconds"
}
|
divide(48, subtract(5, 3))
|
subtract(n1,n2)|divide(n0,#0)|
|
"used pluging in method say t is the time for cristina to catch up with nicky , the equation will be as under : for nicky = n = 3 * t + 48 for cristina = c = 5 * t @ t = 24 , n = 120 c = 120 right answer ans : c"
|
physics
|
math_qa__W3Xf0RwzaKY2tFg0
|
A walks at 10 kmph and 6 hours after his start, B cycles after him at 20 kmph. How far from the start does B catch up with A?
Choose the most appropriate option
A) 100 km
B) 150 km
C) 50 km
D) 120 km
E) 200 km
|
<gadget id="calculator">6 * 20</gadget>
<output>120</output>
<result>D</result>
|
D
| 120 |
A walks at 10 kmph and 6 hours after his start, B cycles after him at 20 kmph. How far from the start does B catch up with A?
|
{
"A": "100 km",
"B": "150 km",
"C": "50 km",
"D": "120 km",
"E": "200 km"
}
|
multiply(6, 20)
|
multiply(n1,n2)
|
suppose after x km from the start b catches up with a . then , the difference in the time taken by a to cover x km and that taken by b to cover x km is 6 hours . x / 10 - x / 20 = 6 x = 120 km answer is d
|
physics
|
math_qa__twpIFHahOiOJgCT5
|
Mary works in a restaurant a maximum of 80 hours. For the first 20 hours, she is paid $8 per hour. For each overtime hour, she is paid at a rate which is 25% higher than her regular rate. How much Mary can earn in a week? Choices:
A) 600 B) 720 C) 760 D) 620 E) 700
|
<gadget id="calculator">80 * 8</gadget>
<output>640</output>
<gadget id="calculator">80 - 20</gadget>
<output>60</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">8 * (1/4)</gadget>
<output>2</output>
<gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">640 + 120</gadget>
<output>760</output>
<result>C</result>
|
C
| 760 |
Mary works in a restaurant a maximum of 80 hours. For the first 20 hours, she is paid $8 per hour. For each overtime hour, she is paid at a rate which is 25% higher than her regular rate. How much Mary can earn in a week?
|
{
"A": "600",
"B": "720",
"C": "760",
"D": "620",
"E": "700"
}
|
add(multiply(80, 8), multiply(subtract(80, 20), multiply(8, divide(25, const_100))))
|
divide(n3,const_100)|multiply(n0,n2)|subtract(n0,n1)|multiply(n2,#0)|multiply(#3,#2)|add(#1,#4)|
|
"mary receives $ 8 ( 20 ) = $ 160 for the first 20 hours . for the 60 overtime hours , she receives $ 8 ( 0.25 ) + $ 8 = $ 10 per hour , that is $ 10 ( 60 ) = $ 600 . the total amount is $ 160 + $ 600 = $ 760 answer c 360 ."
|
gain
|
math_qa__vo46lXO825t9qHYm
|
If 2x + y = 4 and x + 2y = 5, then (x + y)/3 = Choose the correct choice from the following answers:
A) 1
B) 4 / 3
C) 17 / 5
D) 18 / 5
E) 4
|
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 - 5</gadget>
<output>3</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">3 / 3</gadget>
<output>1</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<result>A</result>
|
A
| 1 |
If 2x + y = 4 and x + 2y = 5, then (x + y)/3 =
|
{
"A": "1",
"B": "4 / 3",
"C": "17 / 5",
"D": "18 / 5",
"E": "4"
}
|
divide(add(divide(subtract(multiply(4, 2), 5), subtract(multiply(2, 2), const_1)), subtract(4, multiply(2, divide(subtract(multiply(4, 2), 5), subtract(multiply(2, 2), const_1))))), 3)
|
multiply(n0,n1)|multiply(n0,n0)|subtract(#0,n3)|subtract(#1,const_1)|divide(#2,#3)|multiply(n0,#4)|subtract(n1,#5)|add(#4,#6)|divide(#7,n4)|
|
"we have two equations : 2 x + y = 4 x + 2 y = 5 notice that something nice happens when we add them . we get : 3 x + 3 y = 9 divide both sides by 3 to get : x + y = 3 so , ( x + y ) / 3 = 3 / 3 = 1 answer : a"
|
general
|
math_qa__Zk8dqU9eGWvHtfrQ
|
The least number which when increased by 6 each divisible by each one of 24, 32, 36 and 54 is : Choose the correct choice:
A) 858
B) 859
C) 869
D) 4320
E) none of these
|
<gadget id="calculator">lcm(24, 32)</gadget>
<output>96</output>
<gadget id="calculator">lcm(96, 36)</gadget>
<output>288</output>
<gadget id="calculator">lcm(288, 54)</gadget>
<output>864</output>
<gadget id="calculator">864 - 6</gadget>
<output>858</output>
<result>A</result>
|
A
| 858 |
The least number which when increased by 6 each divisible by each one of 24, 32, 36 and 54 is :
|
{
"A": "858",
"B": "859",
"C": "869",
"D": "4320",
"E": "none of these"
}
|
subtract(lcm(lcm(lcm(24, 32), 36), 54), 6)
|
lcm(n1,n2)|lcm(n3,#0)|lcm(n4,#1)|subtract(#2,n0)|
|
"solution required number = ( l . c . m . of 24 , 32 , 36 , 54 ) - 5 = 864 - 6 = 858 . answer a"
|
general
|
math_qa__MrLb84pDe0n1E7ox
|
Find the mean proportional between 81 & 100? Choose the correct choice from the following choices.
A) 59 B) 61 C) 63 D) 65 E) 90
|
<gadget id="calculator">81 + 100</gadget>
<output>181</output>
<gadget id="calculator">181 / 2</gadget>
<output>181/2 = around 90.5</output>
<result>E</result>
|
E
| 90 |
Find the mean proportional between 81 & 100?
|
{
"A": "59",
"B": "61",
"C": "63",
"D": "65",
"E": "90"
}
|
divide(add(81, 100), const_2)
|
add(n0,n1)|divide(#0,const_2)|
|
"formula = β a Γ b a = 81 and b = 100 β 81 Γ 100 = 9 Γ 10 = 90 e"
|
general
|
math_qa__6CT44r6Wnu9UXcFG
|
A man can row upstream at 30 kmph and downstream at 60 kmph, and then find the speed of the man in still water? Select the correct option
A) 27
B) 29
C) 30
D) 20
E) 45
|
<gadget id="calculator">30 + 60</gadget>
<output>90</output>
<gadget id="calculator">90 / 2</gadget>
<output>45</output>
<result>E</result>
|
E
| 45 |
A man can row upstream at 30 kmph and downstream at 60 kmph, and then find the speed of the man in still water?
|
{
"A": "27",
"B": "29",
"C": "30",
"D": "20",
"E": "45"
}
|
divide(add(30, 60), const_2)
|
add(n0,n1)|divide(#0,const_2)|
|
"us = 30 ds = 60 m = ( 30 + 60 ) / 2 = 45 answer : e"
|
physics
|
math_qa__TfuquDX1k4YMpzRm
|
A group of students was interviewed for that if it was asked whether or not they speak French and / or English. Among those who speak French, 10 speak English well, while 40 of them do not speak English. If 75% of students do not speak French, how many students were surveyed? Choose the correct option
A) 210 B) 225 C) 200 D) 250 E) 300
|
<gadget id="calculator">10 + 40</gadget>
<output>50</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">50 / (1/4)</gadget>
<output>200</output>
<result>C</result>
|
C
| 200 |
A group of students was interviewed for that if it was asked whether or not they speak French and / or English. Among those who speak French, 10 speak English well, while 40 of them do not speak English. If 75% of students do not speak French, how many students were surveyed?
|
{
"A": "210",
"B": "225",
"C": "200",
"D": "250",
"E": "300"
}
|
divide(add(10, 40), divide(subtract(const_100, 75), const_100))
|
add(n0,n1)|subtract(const_100,n2)|divide(#1,const_100)|divide(#0,#2)|
|
"number of students who speak french are 40 + 10 = 50 of total students , the percentage of students who do not speak french was 75 % - - > percentage of who do is 25 % 50 - - - - - - - 25 % x - - - - - - - 100 % x = 50 * 100 / 25 = 200 = number of all students answer is c"
|
gain
|
math_qa__IO2LMtmekgEtc642
|
A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
Choose the correct choice from the following answers:
A) 150 m B) 270 m C) 180 m D) 158 m E) 350 m
|
<gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">250 * 3</gadget>
<output>750</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">120 * 4</gadget>
<output>480</output>
<gadget id="calculator">750 - 480</gadget>
<output>270</output>
<result>B</result>
|
B
| 270 |
A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
|
{
"A": "150 m",
"B": "270 m",
"C": "180 m",
"D": "158 m",
"E": "350 m"
}
|
subtract(multiply(250, divide(15, divide(15, const_3))), multiply(120, divide(20, divide(15, const_3))))
|
divide(n1,const_3)|divide(n1,#0)|divide(n3,#0)|multiply(n2,#1)|multiply(n0,#2)|subtract(#3,#4)|
|
"length of the train be β x β x + 120 / 15 = x + 250 / 20 4 x + 480 = 3 x + 750 x = 270 m answer : b"
|
physics
|
math_qa__havL12BGYBdTCvBb
|
In what time will a train 120 m long cross an electric pole, it its speed be 144 km/hr?
Choose the correct choice.
A) 2.5 sec B) 3 sec C) 8.9 sec D) 6.9 sec E) 2.9 sec
|
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">120 / 40</gadget>
<output>3</output>
<result>B</result>
|
B
| 3 |
In what time will a train 120 m long cross an electric pole, it its speed be 144 km/hr?
|
{
"A": "2.5 sec",
"B": "3 sec",
"C": "8.9 sec",
"D": "6.9 sec",
"E": "2.9 sec"
}
|
divide(120, multiply(144, const_0_2778))
|
multiply(n1,const_0_2778)|divide(n0,#0)|
|
"speed = 144 * 5 / 18 = 40 m / sec time taken = 120 / 40 = 3 sec . answer : b"
|
physics
|
math_qa__ASJjR3K2OYLKnKNL
|
Evaluate: 1234562- 12*3*2 = ? Pick:
A) 32435453
B) 1234554
C) 76768786
D) 97979797
E) 75868656
|
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">36 * 2</gadget>
<output>72</output>
<gadget id="calculator">1_234_562 - 72</gadget>
<output>1_234_490</output>
<result>B</result>
|
B
| 1,234,554 |
Evaluate: 1234562- 12*3*2 = ?
|
{
"A": "32435453",
"B": "1234554",
"C": "76768786",
"D": "97979797",
"E": "75868656"
}
|
subtract(1234562, multiply(multiply(12, 3), 2))
|
multiply(n1,n2)|multiply(n3,#0)|subtract(n0,#1)|
|
"according to order of operations , 12 ? 3 ? 2 ( division and multiplication ) is done first from left to right 12 * * 2 = 4 * 2 = 8 hence 1234562 - 12 * 3 * 2 = 1234562 - 8 = 1234554 correct answer b"
|
general
|
math_qa__iVjGB8KY8A0byndi
|
33 1/3% OF 360? Answers
A) 80 B) 90 C) 110 D) 120 E) 130
|
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">33 + (1/3)</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(100/3) * 360</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 / 100</gadget>
<output>120</output>
<result>D</result>
|
D
| 120 |
33 1/3% OF 360?
|
{
"A": "80",
"B": "90",
"C": "110",
"D": "120",
"E": "130"
}
|
divide(multiply(add(33, divide(1, 3)), 360), const_100)
|
divide(n1,n2)|add(n0,#0)|multiply(n3,#1)|divide(#2,const_100)|
|
"33 1 / 3 % = 1 / 3 1 / 3 Γ 360 = 120 d )"
|
gain
|
math_qa__pBKq5VJPMRbv20l5
|
X can do a piece of work in 40days. He works at it for 8days and then Y finished it in 32 days. How long will Y take to complete the work? Options.
A) 10
B) 40
C) 15
D) 18
E) 20
|
<gadget id="calculator">8 / 40</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 / (4/5)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">32 * (5/4)</gadget>
<output>40</output>
<result>B</result>
|
B
| 40 |
X can do a piece of work in 40days. He works at it for 8days and then Y finished it in 32 days. How long will Y take to complete the work?
|
{
"A": "10",
"B": "40",
"C": "15",
"D": "18",
"E": "20"
}
|
multiply(32, inverse(subtract(const_1, divide(8, 40))))
|
divide(n1,n0)|subtract(const_1,#0)|inverse(#1)|multiply(n2,#2)|
|
"work done by x in 8 days = 8 * 1 / 40 = 1 / 5 remaining work = 1 - 1 / 5 = 4 / 5 4 / 5 work is done by y in 32 days whole work will be done by y in 32 * 5 / 4 = 40 days answer is b"
|
physics
|
math_qa__P8weZqjEfHW7L2YF
|
If k is a non-negative integer and 12^k is a divisor of 856,736 then 3^k - k^3 =
Choose the correct answer:
A) 0
B) 1
C) 36
D) 120
E) 524
|
<gadget id="calculator">1 - 1</gadget>
<output>0</output>
<gadget id="calculator">3 ** 0</gadget>
<output>1</output>
<gadget id="calculator">0 ** 3</gadget>
<output>0</output>
<gadget id="calculator">1 - 0</gadget>
<output>1</output>
<result>B</result>
|
B
| 1 |
If k is a non-negative integer and 12^k is a divisor of 856,736 then 3^k - k^3 =
|
{
"A": "0",
"B": "1",
"C": "36",
"D": "120",
"E": "524"
}
|
subtract(power(3, subtract(const_1, const_1)), power(subtract(const_1, const_1), 3))
|
subtract(const_1,const_1)|power(n2,#0)|power(#0,n2)|subtract(#1,#2)|
|
"8 + 5 + 6 + 7 + 3 + 6 = 35 , so this number is not divisible by 3 and thus not divisible by 12 . therefore , k = 0 3 ^ k - k ^ 3 = 1 - 0 = 1 the answer is b ."
|
general
|
math_qa__WvbZVhYBv9Yr90AE
|
The length of a rectangular plot is 10mtr more than its width. The cost of fencing the plot along its perimeter at the rate of Rs. 6.5mtr is Rs.1950. The perimeter of the plot is? Choose the correct choice from the following options:
A) 126 B) 156 C) 190 D) 300 E) 260
|
<gadget id="calculator">1_950 / 6.5</gadget>
<output>300</output>
<gadget id="calculator">300 / 2</gadget>
<output>150</output>
<gadget id="calculator">150 - 10</gadget>
<output>140</output>
<gadget id="calculator">140 / 2</gadget>
<output>70</output>
<gadget id="calculator">70 + 10</gadget>
<output>80</output>
<gadget id="calculator">70 + 80</gadget>
<output>150</output>
<gadget id="calculator">150 * 2</gadget>
<output>300</output>
<result>D</result>
|
D
| 300 |
The length of a rectangular plot is 10mtr more than its width. The cost of fencing the plot along its perimeter at the rate of Rs. 6.5mtr is Rs.1950. The perimeter of the plot is?
|
{
"A": "126",
"B": "156",
"C": "190",
"D": "300",
"E": "260"
}
|
multiply(add(divide(subtract(divide(divide(1950, 6.5), const_2), const_10), const_2), add(divide(subtract(divide(divide(1950, 6.5), const_2), const_10), const_2), const_10)), const_2)
|
divide(n2,n1)|divide(#0,const_2)|subtract(#1,const_10)|divide(#2,const_2)|add(#3,const_10)|add(#4,#3)|multiply(#5,const_2)
|
sol . let width = x , length = ( 10 + x ) perimeter = 2 ( x + ( 10 + x ) ) = 2 ( 2 x = 10 ) & 2 ( 2 x + 10 ) * 6.5 = 1950 x = 70 required perimeter = 2 ( 70 + 80 ) = 300 d
|
geometry
|
math_qa__S7Ac0wQL8dksK8Nr
|
A can do a piece of work in 8 days. B can do it in 6 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it? Choose the correct choice from the following options: A) 8.7 days B) 2.0 days C) 6.6 days D) 7.7 days E) 4.8 days
|
<gadget id="calculator">8 * 6</gadget>
<output>48</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<gadget id="calculator">48 / 6</gadget>
<output>8</output>
<gadget id="calculator">6 + 8</gadget>
<output>14</output>
<gadget id="calculator">14 * 2</gadget>
<output>28</output>
<gadget id="calculator">48 - 28</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">48 / 10</gadget>
<output>24/5 = around 4.8</output>
<result>E</result>
|
E
| 4.8 |
A can do a piece of work in 8 days. B can do it in 6 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
|
{
"A": "8.7 days",
"B": "2.0 days",
"C": "6.6 days",
"D": "7.7 days",
"E": "4.8 days"
}
|
divide(multiply(8, 6), divide(subtract(multiply(8, 6), multiply(add(divide(multiply(8, 6), 8), divide(multiply(8, 6), 6)), 2)), 2))
|
multiply(n0,n1)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)|multiply(n2,#3)|subtract(#0,#4)|divide(#5,n2)|divide(#0,#6)|
|
"c = 1 / 2 - 1 / 8 - 1 / 8 = 5 / 24 = > 4.8 days answer : e"
|
physics
|
math_qa__ehZ9swV3NvB4pV3I
|
The maximum number of students among them 1230 pens and 920 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: Choose the correct answer
A) 91 B) 10 C) 1001 D) 1911 E) none of these
|
<gadget id="calculator">gcd(1_230, 920)</gadget>
<output>10</output>
<result>B</result>
|
B
| 10 |
The maximum number of students among them 1230 pens and 920 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:
|
{
"A": "91",
"B": "10",
"C": "1001",
"D": "1911",
"E": "none of these"
}
|
gcd(1230, 920)
|
gcd(n0,n1)|
|
"explanation : required number of students = h . c . f of 1230 and 920 = 10 . answer : b"
|
general
|
math_qa__4qmJiZ4RdahbeLA1
|
The length of a room is 7 m and width is 4.75 m. What is the cost of paying the floor by slabs at the rate of Rs. 900 per sq. metre.
Select the correct option:
A) 25650 B) 25750 C) 26550 D) 26750 E) 29925
|
<gadget id="calculator">7 * 4.75</gadget>
<output>33.25</output>
<gadget id="calculator">900 * 33.25</gadget>
<output>29_925</output>
<result>E</result>
|
E
| 29,925 |
The length of a room is 7 m and width is 4.75 m. What is the cost of paying the floor by slabs at the rate of Rs. 900 per sq. metre.
|
{
"A": "25650",
"B": "25750",
"C": "26550",
"D": "26750",
"E": "29925"
}
|
multiply(900, multiply(7, 4.75))
|
multiply(n0,n1)|multiply(n2,#0)|
|
"area = 7 Γ 4.75 sq . metre . cost for 1 sq . metre . = rs . 900 hence total cost = 7 Γ 4.75 Γ 900 = 7 Γ 4275 = rs . 29925 answer is e"
|
physics
|
math_qa__rR0fx7cb4Dsr9yuT
|
A train 110 m long is running with a speed of 27 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? Choose the correct answer: A) 7 sec B) 6 sec C) 8 sec D) 4 sec E) 12 sec
|
<gadget id="calculator">27 + 6</gadget>
<output>33</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">33 * (5/18)</gadget>
<output>55/6 = around 9.166667</output>
<gadget id="calculator">110 / (55/6)</gadget>
<output>12</output>
<result>E</result>
|
E
| 12 |
A train 110 m long is running with a speed of 27 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
|
{
"A": "7 sec",
"B": "6 sec",
"C": "8 sec",
"D": "4 sec",
"E": "12 sec"
}
|
divide(110, multiply(add(27, 6), const_0_2778))
|
add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)|
|
"speed of train relative to man = 27 + 6 = 33 km / hr . = 33 * 5 / 18 = 9.1667 m / sec . time taken to pass the men = 110 / 9.1667 = 12 sec . answer : e"
|
physics
|
math_qa__yKns6uc6ukaKdfPh
|
A, B and C can do a piece of work in 24 days, 30 days and 60 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed? Choose the correct choice from the following options:
A) 10 days B) 11 days C) 13 days D) 21 days E) 31 days
|
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/24) + (1/30)</gadget>
<output>3/40 = around 0.075</output>
<gadget id="calculator">(3/40) * 4</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">5 * 8</gadget>
<output>40</output>
<gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(1/40) + (3/40)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(7/10) / (1/10)</gadget>
<output>7</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<result>B</result>
|
B
| 11 |
A, B and C can do a piece of work in 24 days, 30 days and 60 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed?
|
{
"A": "10 days",
"B": "11 days",
"C": "13 days",
"D": "21 days",
"E": "31 days"
}
|
add(divide(subtract(const_1, multiply(add(divide(const_1, 24), divide(const_1, 30)), 4)), add(divide(const_1, multiply(add(const_2, const_3), multiply(const_2, const_4))), add(divide(const_1, 24), divide(const_1, 30)))), 4)
|
add(const_2,const_3)|divide(const_1,n0)|divide(const_1,n1)|multiply(const_2,const_4)|add(#1,#2)|multiply(#0,#3)|divide(const_1,#5)|multiply(n3,#4)|add(#4,#6)|subtract(const_1,#7)|divide(#9,#8)|add(n3,#10)
|
one day work of a , b and c = 1 / 24 + 1 / 30 + 1 / 60 = 11 / 120 work done by a and b together in the last 4 days = 4 * ( 1 / 24 + 1 / 30 ) = 3 / 10 remaining work = 7 / 10 the number of days required for this initial work = 7 days . the total number of days required = 4 + 7 = 11 days . answer : b
|
physics
|
math_qa__cyVX8Cj9GiiXZwh7
|
Machine P and Machine Q are each used to manufacture 550 sprockets. It takes Machine P 10 hours longer to produce 550 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce?
Choose the correct choice from the following.
A) 5 B) 15 C) 55 D) 95 E) 125
|
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">550 / (11/10)</gadget>
<output>500</output>
<gadget id="calculator">550 - 500</gadget>
<output>50</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<result>A</result>
|
A
| 5 |
Machine P and Machine Q are each used to manufacture 550 sprockets. It takes Machine P 10 hours longer to produce 550 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce?
|
{
"A": "5",
"B": "15",
"C": "55",
"D": "95",
"E": "125"
}
|
divide(subtract(550, divide(550, add(divide(10, const_100), const_1))), 10)
|
divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)|divide(#3,n1)|
|
"p makes x sprockets per hour . then q makes 1.1 x sprockets per hour . 550 / x = 550 / 1.1 x + 10 1.1 ( 550 ) = 550 + 11 x 11 x = 55 x = 5 the answer is a ."
|
gain
|
math_qa__q7Dbxiu2YBWKI9cG
|
What percent of a day is 7 hours? Select the correct option: A) 29.2 % B) 12.5 % C) 13 % D) 11.3 % E) none of these
|
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">7 / 24</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">(7/24) * 100</gadget>
<output>175/6 = around 29.166667</output>
<result>A</result>
|
A
| 29.2 |
What percent of a day is 7 hours?
|
{
"A": "29.2 %",
"B": "12.5 %",
"C": "13 %",
"D": "11.3 %",
"E": "none of these"
}
|
multiply(divide(7, multiply(multiply(const_4, const_3), const_2)), const_100)
|
multiply(const_3,const_4)|multiply(#0,const_2)|divide(n0,#1)|multiply(#2,const_100)
|
explanation : solution : required percentage = ( 7 / 100 * 24 ) = 29.2 % answer : a
|
physics
|
math_qa__HnnzmSvZS5geyzey
|
If 4XZ + YW = 5 and XW + YZ = 10, what is the value of the expression (2X + Y)(2Z + W)?
Choose the correct choice from the following: A) 9 . B) 12 . C) 15 . D) 16 . E) 25
|
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">4 + 20</gadget>
<output>24</output>
<result>E</result>
|
E
| 25 |
If 4XZ + YW = 5 and XW + YZ = 10, what is the value of the expression (2X + Y)(2Z + W)?
|
{
"A": "9 .",
"B": "12 .",
"C": "15 .",
"D": "16 .",
"E": "25"
}
|
add(4, multiply(10, 2))
|
multiply(n2,n3)|add(n0,#0)|
|
"( 2 x + y ) * ( 2 z + w ) = 5 + 2 ( 10 ) = 25 answer : e"
|
general
|
math_qa__rL6Q44DCCd2abbYF
|
A circular ground whose diameter is 34 metres, has a 2 metre-broad garden around it. What is the area of the garden in square metres?
Choose the correct option.
A) 226.3 B) 226.2 C) 228.2 D) 227 E) 226
|
<gadget id="calculator">34 / 2</gadget>
<output>17</output>
<gadget id="calculator">17 + 2</gadget>
<output>19</output>
<gadget id="calculator">pi * (19 ** 2)</gadget>
<output>361*pi = around 1_134.114948</output>
<gadget id="calculator">pi * (17 ** 2)</gadget>
<output>289*pi = around 907.920277</output>
<gadget id="calculator">(361*pi) - (289*pi)</gadget>
<output>72*pi = around 226.194671</output>
<result>A</result>
|
A
| 226.3 |
A circular ground whose diameter is 34 metres, has a 2 metre-broad garden around it. What is the area of the garden in square metres?
|
{
"A": "226.3",
"B": "226.2",
"C": "228.2",
"D": "227",
"E": "226"
}
|
subtract(circle_area(add(divide(34, const_2), 2)), circle_area(divide(34, const_2)))
|
divide(n0,const_2)|add(n1,#0)|circle_area(#0)|circle_area(#1)|subtract(#3,#2)
|
req . area = Γ― β¬ [ ( 19 ) 2 Γ’ β¬ β ( 17 ) 2 ] = 22 Γ’ Β β 7 Γ£ β ( 36 Γ£ β 2 ) [ since a 2 - b 2 = ( a + b ) ( a - b ) ] = ( 22 Γ£ β 36 Γ£ β 2 ) / 7 = 226.3 sq m answer a
|
geometry
|
math_qa__MXbXvPdjgYZ1VOQk
|
3889 + 12.808 - ? = 3854.002 Choose the most appropriate option
A) 47.095 B) 47.752 C) 47.806 D) 47.95 E) of the above
|
<gadget id="calculator">3_889 + 12.808</gadget>
<output>3_901.808</output>
<gadget id="calculator">3_901.808 - 3_854.002</gadget>
<output>47.806</output>
<result>C</result>
|
C
| 47.806 |
3889 + 12.808 - ? = 3854.002
|
{
"A": "47.095",
"B": "47.752",
"C": "47.806",
"D": "47.95",
"E": "of the above"
}
|
subtract(add(3889, 12.808), 3854.002)
|
add(n0,n1)|subtract(#0,n2)
|
let 3889 + 12.808 - x = 3854.002 . then x = ( 3889 + 12.808 ) - 3854.002 = 3901.808 - 3854.002 = 47.806 . answer = c
|
general
|
math_qa__PnZ3XcwPyTnJ9BSG
|
A sum of money is sufficient to pay A's wages for 20 days and B's wages for 30 days. The same money is sufficient to pay the wages of both for?
Choices:
A) 12 days
B) 15 days
C) 20 days
D) 18 days
E) 22 days
|
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/20) + (1/30)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>A</result>
|
A
| 12 |
A sum of money is sufficient to pay A's wages for 20 days and B's wages for 30 days. The same money is sufficient to pay the wages of both for?
|
{
"A": "12 days",
"B": "15 days",
"C": "20 days",
"D": "18 days",
"E": "22 days"
}
|
divide(const_1, add(divide(const_1, 20), divide(const_1, 30)))
|
divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)|
|
"let the total money be $ x a ' s 1 day work = $ x / 20 b ' s 1 day work = $ x / 30 a + b 1 day work = $ x / 12 money is sufficient to pay the wages of both for 12 days answer is a"
|
general
|
math_qa__gSbxiQ2LLADdNTFr
|
A river boat leaves Silver Town and travels upstream to Gold Town at an average speed of 6 kilometers per hour. It returns by the same route at an average speed of 8 kilometers per hour. What is the average speed for the round-trip in kilometers per hour? Choose the correct answer:
A) 6.8
B) 7.1
C) 7.2
D) 7.5
E) 8.0
|
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">48 * 2</gadget>
<output>96</output>
<gadget id="calculator">6 + 8</gadget>
<output>14</output>
<gadget id="calculator">96 / 14</gadget>
<output>48/7 = around 6.857143</output>
<result>A</result>
|
A
| 6.8 |
A river boat leaves Silver Town and travels upstream to Gold Town at an average speed of 6 kilometers per hour. It returns by the same route at an average speed of 8 kilometers per hour. What is the average speed for the round-trip in kilometers per hour?
|
{
"A": "6.8",
"B": "7.1",
"C": "7.2",
"D": "7.5",
"E": "8.0"
}
|
divide(multiply(multiply(6, 8), const_2), add(6, 8))
|
add(n0,n1)|multiply(n0,n1)|multiply(#1,const_2)|divide(#2,#0)|
|
"pick a number which is lcm of 8 and 6 = 24 . upstream time = 24 / 6 = 4 hrs downstream time = 24 / 8 = 3 hrs total time = 7 hrs total distance = 48 average speed = 48 / 7 = 6.8 km / hr"
|
physics
|
math_qa__uKTsT2r9kUkTHPgG
|
The sides of a square region, measured to the nearest centimeter, are 7 centimeters long. The least possible value of the actual area of the square region is
Choose the correct choice:
A) 42.25 sq cm B) 45.25 sq cm C) 43.25 sq cm D) 50.25 sq cm E) 52.25 sq cm
|
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">7 - (1/4)</gadget>
<output>27/4 = around 6.75</output>
<gadget id="calculator">(27/4) - (1/4)</gadget>
<output>13/2 = around 6.5</output>
<gadget id="calculator">(13/2) ** 2</gadget>
<output>169/4 = around 42.25</output>
<result>A</result>
|
A
| 42.25 |
The sides of a square region, measured to the nearest centimeter, are 7 centimeters long. The least possible value of the actual area of the square region is
|
{
"A": "42.25 sq cm",
"B": "45.25 sq cm",
"C": "43.25 sq cm",
"D": "50.25 sq cm",
"E": "52.25 sq cm"
}
|
power(subtract(subtract(7, const_0_25), const_0_25), const_2)
|
subtract(n0,const_0_25)|subtract(#0,const_0_25)|power(#1,const_2)
|
though there might be some technicalities concerning the termnearest ( as 6.5 is equidistant from both 6 and 7 ) the answer still should be a : 6.5 ^ 2 = 42.25 . answer : a
|
geometry
|
math_qa__tWDoPmudDXKJkAYT
|
A box contains 6 white, 5 red and 8 white marbles. 5 marbles are drawn from the box at random. What is the probability that both the marbles are of the same color? Select
A) 19 / 11628 B) 36 / 11628 C) 613 / 11628 D) 6113 / 11628 E) 63 / 11628
|
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">720 / 120</gadget>
<output>6</output>
<gadget id="calculator">120 / 120</gadget>
<output>1</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">8 - 5</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">6 * 120</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<gadget id="calculator">7 + 56</gadget>
<output>63</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">11 + 8</gadget>
<output>19</output>
<gadget id="calculator">factorial(19)</gadget>
<output>121_645_100_408_832_000</output>
<gadget id="calculator">19 - 5</gadget>
<output>14</output>
<gadget id="calculator">factorial(14)</gadget>
<output>87_178_291_200</output>
<gadget id="calculator">120 * 87_178_291_200</gadget>
<output>10_461_394_944_000</output>
<gadget id="calculator">121_645_100_408_832_000 / 10_461_394_944_000</gadget>
<output>11_628</output>
<gadget id="calculator">63 / 11_628</gadget>
<output>7/1_292 = around 0.005418</output>
<result>E</result>
|
E
| 0.005418 |
A box contains 6 white, 5 red and 8 white marbles. 5 marbles are drawn from the box at random. What is the probability that both the marbles are of the same color?
|
{
"A": "19 / 11628",
"B": "36 / 11628",
"C": "613 / 11628",
"D": "6113 / 11628",
"E": "63 / 11628"
}
|
divide(add(add(divide(factorial(6), factorial(5)), divide(factorial(5), factorial(5))), divide(factorial(8), multiply(factorial(subtract(8, 5)), factorial(5)))), divide(factorial(add(add(6, 5), 8)), multiply(factorial(5), factorial(subtract(add(add(6, 5), 8), 5)))))
|
add(n0,n1)|factorial(n0)|factorial(n1)|factorial(n2)|subtract(n2,n1)|add(n2,#0)|divide(#1,#2)|divide(#2,#2)|factorial(#4)|add(#6,#7)|factorial(#5)|multiply(#8,#2)|subtract(#5,n1)|divide(#3,#11)|factorial(#12)|add(#9,#13)|multiply(#2,#14)|divide(#10,#16)|divide(#15,#17)
|
explanation : total marbles in a box = 6 black + 5 red + 8 green marbles = 19 marbles 5 marbles are drawn from 19 marbles at random . therefore , n ( s ) = 19 c 5 = 11628 ways let a be the event that 2 marbles drawn at random are of the same color . number of cases favorable to the event a is n ( a ) = 6 c 5 + 5 c 5 + 8 c 5 = 6 + 1 + 56 = 63 therefore , by definition of probability of event a , p ( a ) = n ( a ) / n ( s ) = 63 / 11628 answer : e
|
other
|
math_qa__l0mg7cvDbCyowyzV
|
What will be the reminder when (43^43+43) is divided by 44?
Pick
A) 32 B) 42 C) 83 D) 71 E) 92
|
<gadget id="calculator">43 ** 43</gadget>
<output>17_343_773_367_030_267_519_903_781_288_812_032_158_308_062_539_012_091_953_077_767_198_995_507</output>
<gadget id="calculator">17_343_773_367_030_267_519_903_781_288_812_032_158_308_062_539_012_091_953_077_767_198_995_507 + 43</gadget>
<output>17_343_773_367_030_267_519_903_781_288_812_032_158_308_062_539_012_091_953_077_767_198_995_550</output>
<gadget id="calculator">17_343_773_367_030_267_519_903_781_288_812_032_158_308_062_539_012_091_953_077_767_198_995_550 / 44</gadget>
<output>8_671_886_683_515_133_759_951_890_644_406_016_079_154_031_269_506_045_976_538_883_599_497_775/22 = around 394_176_667_432_506_064_273_999_167_600_066_127_909_447_676_131_363_347_384_442_057_392_128</output>
<gadget id="calculator">floor(8_671_886_683_515_133_759_951_890_644_406_016_079_154_031_269_506_045_976_538_883_599_497_775/22)</gadget>
<output>394_176_667_432_506_079_997_813_211_109_364_367_234_274_148_613_911_180_751_767_436_340_807</output>
<gadget id="calculator">44 * 394_176_667_432_506_079_997_813_211_109_364_367_234_274_148_613_911_180_751_767_436_340_807</gadget>
<output>17_343_773_367_030_267_519_903_781_288_812_032_158_308_062_539_012_091_953_077_767_198_995_508</output>
<gadget id="calculator">17_343_773_367_030_267_519_903_781_288_812_032_158_308_062_539_012_091_953_077_767_198_995_550 - 17_343_773_367_030_267_519_903_781_288_812_032_158_308_062_539_012_091_953_077_767_198_995_508</gadget>
<output>42</output>
<result>B</result>
|
B
| 42 |
What will be the reminder when (43^43+43) is divided by 44?
|
{
"A": "32",
"B": "42",
"C": "83",
"D": "71",
"E": "92"
}
|
subtract(add(power(43, 43), 43), multiply(44, floor(divide(add(power(43, 43), 43), 44))))
|
power(n0,n0)|add(n0,#0)|divide(#1,n3)|floor(#2)|multiply(n3,#3)|subtract(#1,#4)|
|
"( x ^ n + 1 ) will be divisible by ( x + 1 ) only when n is odd ; ( 43 ^ 43 + 1 ) will be divisible by ( 43 + 1 ) ; ( 43 ^ 43 + 1 ) + 42 when divided by 44 will give 42 as remainder . correct option : b"
|
general
|
math_qa__4PBIdtUGv9V7sL44
|
The total of 342 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is Choose the correct choice from the following options:
A) 238 B) 290 C) 278 D) 200 E) 288
|
<gadget id="calculator">342 * 25</gadget>
<output>8_550</output>
<gadget id="calculator">71 * 100</gadget>
<output>7_100</output>
<gadget id="calculator">8_550 - 7_100</gadget>
<output>1_450</output>
<gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">1_450 / 5</gadget>
<output>290</output>
<result>B</result>
|
B
| 290 |
The total of 342 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is
|
{
"A": "238",
"B": "290",
"C": "278",
"D": "200",
"E": "288"
}
|
divide(subtract(multiply(342, 25), multiply(71, const_100)), subtract(25, 20))
|
multiply(n0,n2)|multiply(n3,const_100)|subtract(n2,n1)|subtract(#0,#1)|divide(#3,#2)|
|
"explanation : let the number of 20 paise coins be x . then the no of 25 paise coins = ( 342 - x ) . 0.20 * ( x ) + 0.25 ( 342 - x ) = 71 = > x = 290 . . answer : b ) 290"
|
general
|
math_qa__NtDbgnln4j0czwBo
|
A retailer buys a radio for Rs 225. His overhead expenses are Rs 15. He sellis the radio for Rs 350. The profit percent of the retailer is Choose the correct option.
A) 10 % B) 45.8 % C) 25 % D) 52 % E) none of these
|
<gadget id="calculator">225 + 15</gadget>
<output>240</output>
<gadget id="calculator">350 / 240</gadget>
<output>35/24 = around 1.458333</output>
<gadget id="calculator">(35/24) * 100</gadget>
<output>875/6 = around 145.833333</output>
<gadget id="calculator">(875/6) - 100</gadget>
<output>275/6 = around 45.833333</output>
<result>B</result>
|
B
| 45.8 |
A retailer buys a radio for Rs 225. His overhead expenses are Rs 15. He sellis the radio for Rs 350. The profit percent of the retailer is
|
{
"A": "10 %",
"B": "45.8 %",
"C": "25 %",
"D": "52 %",
"E": "none of these"
}
|
subtract(multiply(divide(350, add(225, 15)), const_100), const_100)
|
add(n0,n1)|divide(n2,#0)|multiply(#1,const_100)|subtract(#2,const_100)|
|
"explanation : cost price = ( 225 + 15 ) = 240 sell price = 350 gain = ( 110 / 240 ) * 100 = 45.8 % . answer : b"
|
gain
|
math_qa__qBJ7pKpZnW0oFDJX
|
A man can row upstream at 35 kmph and downstream at 45 kmph, and then find the speed of the man in still water?
Choices: A) 32 kmph B) 34 kmph C) 40 kmph D) 45 kmph E) 65 kmph
|
<gadget id="calculator">35 + 45</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>C</result>
|
C
| 40 |
A man can row upstream at 35 kmph and downstream at 45 kmph, and then find the speed of the man in still water?
|
{
"A": "32 kmph",
"B": "34 kmph",
"C": "40 kmph",
"D": "45 kmph",
"E": "65 kmph"
}
|
divide(add(35, 45), const_2)
|
add(n0,n1)|divide(#0,const_2)|
|
"us = 35 ds = 45 m = ( 35 + 45 ) / 2 = 40 answer : c"
|
physics
|
math_qa__gLyyYyBdaq0LIlLJ
|
A 220 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train? Choose the correct choice from the following answers:
A) 230 m
B) 240 m
C) 250 m
D) 260 m
E) 280 m
|
<gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">(500/9) * 9</gadget>
<output>500</output>
<gadget id="calculator">500 - 220</gadget>
<output>280</output>
<result>E</result>
|
E
| 280 |
A 220 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
|
{
"A": "230 m",
"B": "240 m",
"C": "250 m",
"D": "260 m",
"E": "280 m"
}
|
subtract(multiply(multiply(add(120, 80), const_0_2778), 9), 220)
|
add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)
|
speed = ( 120 + 80 ) km / h ( because direction is opposite hence relative velocity is added ) = 500 / 9 m / s time = 9 sec let the lenght of second train is x total distance covered = 220 + x therefore , d = speed * time thus 220 + x = 500 / 9 * 9 x = 500 - 220 = 280 m answer : e
|
physics
|
math_qa__wvCUMPt1TAUarmsh
|
If 80 lamps can be lighted 5 hours per day for 10 days for Rs. 21.25,then the number of lamps which can be lighted 4 hours daily for 30days for Rs. 76.50, is?
Choose the correct choice from the following answers: A) 100 B) 110 C) 120 D) 130 E) none of these
|
<gadget id="calculator">5 * 76.5</gadget>
<output>382.5</output>
<gadget id="calculator">382.5 * 10</gadget>
<output>3_825</output>
<gadget id="calculator">3_825 * 80</gadget>
<output>306_000</output>
<gadget id="calculator">21.25 * 30</gadget>
<output>637.5</output>
<gadget id="calculator">637.5 * 4</gadget>
<output>2_550</output>
<gadget id="calculator">306_000 / 2_550</gadget>
<output>120</output>
<result>C</result>
|
C
| 120 |
If 80 lamps can be lighted 5 hours per day for 10 days for Rs. 21.25,then the number of lamps which can be lighted 4 hours daily for 30days for Rs. 76.50, is?
|
{
"A": "100",
"B": "110",
"C": "120",
"D": "130",
"E": "none of these"
}
|
divide(multiply(multiply(multiply(5, 76.5), 10), 80), multiply(multiply(21.25, 30), 4))
|
multiply(n1,n6)|multiply(n3,n5)|multiply(n2,#0)|multiply(n4,#1)|multiply(n0,#2)|divide(#4,#3)
|
explanation : ( hrs / day 4 : 5 ) : ( money 21.25 : 76.50 ) : ( days 30 : 10 ) : : 80 : x 4 * 21.25 * 30 * x = 5 * 76.50 * 10 * 80 so x = 120 answer : c
|
physics
|
math_qa__hze5ANOxB4Jtx0Tq
|
In a group of ducks and cows, the total number of legs are 20 more than twice the no. of heads. Find the total no.of buffaloes. Choose the correct choice from the following answers: A) 10 B) 12 C) 13 D) 15 E) 16
|
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>A</result>
|
A
| 10 |
In a group of ducks and cows, the total number of legs are 20 more than twice the no. of heads. Find the total no.of buffaloes.
|
{
"A": "10",
"B": "12",
"C": "13",
"D": "15",
"E": "16"
}
|
divide(20, const_2)
|
divide(n0,const_2)|
|
"let the number of buffaloes be x and the number of ducks be y = > 4 x + 2 y = 2 ( x + y ) + 20 = > 2 x = 20 = > x = 10 a"
|
general
|
math_qa__QvY1NgZahGG95hWr
|
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 41 kg, then the weight of B is: Choose the correct choice from the following: A) 27 kg B) 20 kg C) 26 kg D) 31 kg E) 35 kg
|
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">41 * 2</gadget>
<output>82</output>
<gadget id="calculator">80 + 82</gadget>
<output>162</output>
<gadget id="calculator">45 * 3</gadget>
<output>135</output>
<gadget id="calculator">162 - 135</gadget>
<output>27</output>
<result>A</result>
|
A
| 27 |
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 41 kg, then the weight of B is:
|
{
"A": "27 kg",
"B": "20 kg",
"C": "26 kg",
"D": "31 kg",
"E": "35 kg"
}
|
subtract(add(multiply(40, const_2), multiply(41, const_2)), multiply(45, const_3))
|
multiply(n1,const_2)|multiply(n2,const_2)|multiply(n0,const_3)|add(#0,#1)|subtract(#3,#2)|
|
"let d sum of a , b , c is 3 * 45 = 135 and sum of a and b s 2 * 40 = 80 sum of b and c is 2 * 41 = 82 hence 80 + 82 - 135 = 27 ans = 27 answer : a"
|
general
|
math_qa__mkLLA1QZ6eeFGwW2
|
I sold a book at a profit of 10%. Had I sold it for $100 more, 15% would have been gained. Find the cost price? Choose the correct choice from the following options:
A) $ 2000 B) $ 2500 C) $ 3000 D) $ 3120 E) $ 1540
|
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">1_000 / 5</gadget>
<output>200</output>
<gadget id="calculator">200 * 100</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 10</gadget>
<output>2_000</output>
<result>A</result>
|
A
| 2,000 |
I sold a book at a profit of 10%. Had I sold it for $100 more, 15% would have been gained. Find the cost price?
|
{
"A": "$ 2000",
"B": "$ 2500",
"C": "$ 3000",
"D": "$ 3120",
"E": "$ 1540"
}
|
divide(multiply(divide(multiply(100, 10), subtract(15, 10)), const_100), 10)
|
multiply(n0,n1)|subtract(n2,n0)|divide(#0,#1)|multiply(#2,const_100)|divide(#3,n0)|
|
"115 % of cost - 110 % of cost = $ 100 5 % of cost = $ 100 cost = 100 * 100 / 5 = $ 2000 answer is a"
|
gain
|
math_qa__tCJLZfgtlGp1d9Dk
|
An inspector rejects 0.08% of the meters as defective. How many will he examine to reject 2? Choose one:
A) 1200
B) 1240
C) 1852
D) 3200
E) 2500
|
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 / 0.08</gadget>
<output>2_500</output>
<result>E</result>
|
E
| 2,500 |
An inspector rejects 0.08% of the meters as defective. How many will he examine to reject 2?
|
{
"A": "1200",
"B": "1240",
"C": "1852",
"D": "3200",
"E": "2500"
}
|
divide(multiply(2, const_100), 0.08)
|
multiply(n1,const_100)|divide(#0,n0)|
|
"then , 0.08 % of x = 2 ( 8 / 100 ) * ( 1 / 100 ) x = 2 x = ( 2 * 100 * 100 ) / 8 = 2500 answer is e"
|
gain
|
math_qa__RhHNgWlU8uEBJiTs
|
The average age of a class is 15.8 years. The average age of the boys in the class is 16.4 years and that of the girls is 15.4 years. What is the ratio of boys to girls in the class? Pick.
A) 1 : 2 B) 3 : 4 C) 2 : 3 D) 3 : 2 E) none of these
|
<gadget id="calculator">15.8 - 15.4</gadget>
<output>0.4</output>
<gadget id="calculator">16.4 - 15.8</gadget>
<output>0.6</output>
<gadget id="calculator">0.4 / 0.6</gadget>
<output>0.666667</output>
<result>C</result>
|
C
| 0.666667 |
The average age of a class is 15.8 years. The average age of the boys in the class is 16.4 years and that of the girls is 15.4 years. What is the ratio of boys to girls in the class?
|
{
"A": "1 : 2",
"B": "3 : 4",
"C": "2 : 3",
"D": "3 : 2",
"E": "none of these"
}
|
divide(subtract(15.8, 15.4), subtract(16.4, 15.8))
|
subtract(n0,n2)|subtract(n1,n0)|divide(#0,#1)|
|
"let number of boys = x ; let number of girls = y total numbers of students = x + y ( x + y ) Γ 15.8 = 16.4 x + 15.4 y 0.6 x = 0.4 y x / y = 0.4 / 0.6 = 2 / 3 answer : c"
|
general
|
math_qa__juD22Zev99DCdeOA
|
In how many years will a sum of money doubles itself at 25% per annum on simple interest? Choose the correct choice: A) 4 % B) 8 % C) 10 % D) 12 % E) 15 %
|
<gadget id="calculator">100 / 25</gadget>
<output>4</output>
<result>A</result>
|
A
| 4 |
In how many years will a sum of money doubles itself at 25% per annum on simple interest?
|
{
"A": "4 %",
"B": "8 %",
"C": "10 %",
"D": "12 %",
"E": "15 %"
}
|
divide(const_100, 25)
|
divide(const_100,n0)|
|
"p = ( p * 25 * r ) / 100 r = 4 % answer : a"
|
gain
|
math_qa__LQtUAMKT6pWXSK45
|
log3 N+log7 N what is 3 digit number N that will be whole number Select:
A) 343 B) 729 C) 829 D) 929 E) 727
|
<gadget id="calculator">7 ** 3</gadget>
<output>343</output>
<result>A</result>
|
A
| 343 |
log3 N+log7 N what is 3 digit number N that will be whole number
|
{
"A": "343",
"B": "729",
"C": "829",
"D": "929",
"E": "727"
}
|
power(7, 3)
|
power(n1,n0)
|
no of values n can take is 1 7 ^ 3 = 343 answer : a
|
other
|
math_qa__vGz4jBvZlCkSNn13
|
At the A-Street Fish Market a vendor sells fresh caught fish. His store is filled with 2/7 bass, 1/5 tuna, 1/7 trout, and the rest are catfish. If a customer just bought 1/7 of all the tuna and 1/7 of all the catfish, and a fisherman arrived to restock the bass, doubling the number of bass, what proportion of fish now in the store are trout? Choices: A) 30 / 71 B) 4 / 7 C) 5 / 43 D) 1 / 2 E) 1 / 5
|
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(2/7) + (1/5)</gadget>
<output>17/35 = around 0.485714</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(17/35) + (1/7)</gadget>
<output>22/35 = around 0.628571</output>
<gadget id="calculator">1 - (22/35)</gadget>
<output>13/35 = around 0.371429</output>
<gadget id="calculator">(13/35) - (2/7)</gadget>
<output>3/35 = around 0.085714</output>
<gadget id="calculator">(1/5) - (3/35)</gadget>
<output>4/35 = around 0.114286</output>
<result>C</result>
|
C
| 0.116279 |
At the A-Street Fish Market a vendor sells fresh caught fish. His store is filled with 2/7 bass, 1/5 tuna, 1/7 trout, and the rest are catfish. If a customer just bought 1/7 of all the tuna and 1/7 of all the catfish, and a fisherman arrived to restock the bass, doubling the number of bass, what proportion of fish now in the store are trout?
|
{
"A": "30 / 71",
"B": "4 / 7",
"C": "5 / 43",
"D": "1 / 2",
"E": "1 / 5"
}
|
subtract(divide(1, 5), subtract(subtract(const_1, add(add(divide(2, 7), divide(1, 5)), divide(1, 7))), divide(2, 7)))
|
divide(n2,n3)|divide(n0,n1)|divide(n2,n1)|add(#1,#0)|add(#3,#2)|subtract(const_1,#4)|subtract(#5,#1)|subtract(#0,#6)
|
bass = 2 / 7 = 10 / 35 tuna = 1 / 5 = 7 / 35 trout = 1 / 7 = 5 / 35 catfish = 1 - ( 10 / 35 + 7 / 35 + 5 / 35 ) = 13 / 35 purchased : tuna = 7 / 35 - ( 7 / 35 ) ( 1 / 7 ) = 6 / 35 , and catfish = 13 / 35 - ( 13 / 35 ) ( 1 / 7 ) = 12 / 35 stocked : doubling the number of bass ( 2 ) ( 10 / 35 ) = 20 / 35 now : 20 + 6 + 5 + 12 = 43 trout proportion is now 5 / 43 . answer : c
|
general
|
math_qa__o4nlRUehwpfKC85h
|
The product of two positive integers is 323 and their difference is 2. What is the smaller number? Choose the correct choice from the following options
A) 17 B) 18 C) 16 D) 19 E) 14
|
<gadget id="calculator">323 / 2</gadget>
<output>323/2 = around 161.5</output>
<gadget id="calculator">323 / (323/2)</gadget>
<output>2</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 + 10</gadget>
<output>18</output>
<gadget id="calculator">18 - 1</gadget>
<output>17</output>
<result>A</result>
|
A
| 17 |
The product of two positive integers is 323 and their difference is 2. What is the smaller number?
|
{
"A": "17",
"B": "18",
"C": "16",
"D": "19",
"E": "14"
}
|
subtract(add(multiply(divide(323, divide(323, 2)), const_4), const_10), const_1)
|
divide(n0,n1)|divide(n0,#0)|multiply(#1,const_4)|add(#2,const_10)|subtract(#3,const_1)
|
let ' s use trial and error to find the two numbers . 20 * 18 = 360 ( too high ) 19 * 17 = 323 the answer is a .
|
general
|
math_qa__ZvjBuSK1GW3IkPSI
|
An alloy is to contain Steel and Iron in the ratio 5:2. The Iron required to be melted with 35kg of Steel is? Select: A) 12 kg B) 14 kg C) 15 kg D) 20 kg E) 18 kg
|
<gadget id="calculator">35 / 5</gadget>
<output>7</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<result>B</result>
|
B
| 14 |
An alloy is to contain Steel and Iron in the ratio 5:2. The Iron required to be melted with 35kg of Steel is?
|
{
"A": "12 kg",
"B": "14 kg",
"C": "15 kg",
"D": "20 kg",
"E": "18 kg"
}
|
multiply(divide(35, 5), 2)
|
divide(n2,n0)|multiply(n1,#0)
|
let the required quantity of steel be x kg 5 : 2 : : 35 : x 5 x = 2 * 35 x = 14 kg answer is b
|
other
|
math_qa__UPKYKuRTa4lJtrVr
|
A man complete a journey in 30 hours. He travels first half of the journey at the rate of 20 km/hr and second half at the rate of 10 km/hr. Find the total journey in km. Choose the correct choice from the following choices.
A) 220 km B) 224 km C) 230 km D) 400 km E) 234 km
|
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">200 * 30</gadget>
<output>6_000</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">6_000 / 30</gadget>
<output>200</output>
<gadget id="calculator">2 * 200</gadget>
<output>400</output>
<result>D</result>
|
D
| 400 |
A man complete a journey in 30 hours. He travels first half of the journey at the rate of 20 km/hr and second half at the rate of 10 km/hr. Find the total journey in km.
|
{
"A": "220 km",
"B": "224 km",
"C": "230 km",
"D": "400 km",
"E": "234 km"
}
|
multiply(const_2, divide(multiply(multiply(20, 10), 30), add(20, 10)))
|
add(n1,n2)|multiply(n1,n2)|multiply(n0,#1)|divide(#2,#0)|multiply(#3,const_2)
|
0.5 x / 20 + 0.5 x / 10 = 30 - - > x / 20 + x / 10 = 60 - - > 3 x = 20 x 60 - - > x = ( 60 x 20 ) / 3 = 400 km . answer : d
|
physics
|
math_qa__Tp7S05h4ZgSvDstL
|
It would take one machine 9 hours to complete a large production order and another machine 8 hours to complete the same order. How many hours would it take both machines, working simultaneously at their respective constant rates, to complete the order?
Choose the correct choice from the following choices:
A) 72 / 17 B) 17 / 72 C) 14 / 24 D) 24 / 56 E) 34 / 56
|
<gadget id="calculator">9 * 8</gadget>
<output>72</output>
<gadget id="calculator">9 + 8</gadget>
<output>17</output>
<gadget id="calculator">72 / 17</gadget>
<output>72/17 = around 4.235294</output>
<result>A</result>
|
A
| 4.235294 |
It would take one machine 9 hours to complete a large production order and another machine 8 hours to complete the same order. How many hours would it take both machines, working simultaneously at their respective constant rates, to complete the order?
|
{
"A": "72 / 17",
"B": "17 / 72",
"C": "14 / 24",
"D": "24 / 56",
"E": "34 / 56"
}
|
divide(multiply(9, 8), add(9, 8))
|
add(n0,n1)|multiply(n0,n1)|divide(#1,#0)
|
the rate of the first machine is 1 / 9 job per hour ; the rate of the second machine is 1 / 8 job per hour ; thus , the combined rate of the machines is 1 / 9 + 1 / 8 = 17 / 72 job per hour , which means that it takes 1 / ( 17 / 72 ) = 72 / 17 hours both machines to do the job . answer : a .
|
physics
|
math_qa__5v4FbSx1pLtvROcy
|
3034β(1002Γ·20.04)=? Choose the correct choice from the following choices
A) 1964 B) 1984 C) 2964 D) 2984 E) none of these
|
<gadget id="calculator">1_002 / 20.04</gadget>
<output>50</output>
<gadget id="calculator">3_034 - 50</gadget>
<output>2_984</output>
<result>D</result>
|
D
| 2,984 |
3034β(1002Γ·20.04)=?
|
{
"A": "1964",
"B": "1984",
"C": "2964",
"D": "2984",
"E": "none of these"
}
|
subtract(3034, divide(1002, 20.04))
|
divide(n1,n2)|subtract(n0,#0)|
|
"explanation : = 3034 β ( 1002 / 2004 Γ 100 ) = 3034 β 50 = 2984 option d"
|
general
|
math_qa__QwzCODKLsZqDsaU1
|
A number is doubled and 9 is added. If the resultant is trebled, it becomes 57. What is that number? Choose the correct choice from the following options:
A) 5
B) 6
C) 8
D) 7
E) 4
|
<gadget id="calculator">3 * 9</gadget>
<output>27</output>
<gadget id="calculator">57 - 27</gadget>
<output>30</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">30 / 6</gadget>
<output>5</output>
<result>A</result>
|
A
| 5 |
A number is doubled and 9 is added. If the resultant is trebled, it becomes 57. What is that number?
|
{
"A": "5",
"B": "6",
"C": "8",
"D": "7",
"E": "4"
}
|
divide(subtract(57, multiply(const_3, 9)), multiply(const_3, const_2))
|
multiply(n0,const_3)|multiply(const_2,const_3)|subtract(n1,#0)|divide(#2,#1)|
|
"let the number be x . then , 3 ( 2 x + 9 ) = 57 2 x = 10 = > x = 5 answer : a"
|
general
|
math_qa__8vlu6lgSL2wGirxA
|
Mark and Ann together were allocated n boxes of cookies to sell for a club project. Mark sold 9 boxes less than n and Ann sold 2 boxes less than n. If Mark and Ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n? Select the correct option:
A) 9
B) 10
C) 11
D) 12
E) 13
|
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<result>B</result>
|
B
| 10 |
Mark and Ann together were allocated n boxes of cookies to sell for a club project. Mark sold 9 boxes less than n and Ann sold 2 boxes less than n. If Mark and Ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n?
|
{
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "13"
}
|
add(9, const_1)
|
add(n0,const_1)|
|
"if n = 10 mark sold 1 box and ann sold 8 boxes total 9 < 10 answer : b"
|
general
|
math_qa__MReohdp98UL8DG7V
|
135 liters of a mixture of milk and water contains in the ratio 3:2. How much water should now be added so that the ratio of milk and water becomes 3:4? Choose the correct choice from the following choices:
A) 12 liters
B) 32 liters
C) 41 liters
D) 54 liters
E) 34 liters
|
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">135 / 5</gadget>
<output>27</output>
<gadget id="calculator">27 * 2</gadget>
<output>54</output>
<result>D</result>
|
D
| 54 |
135 liters of a mixture of milk and water contains in the ratio 3:2. How much water should now be added so that the ratio of milk and water becomes 3:4?
|
{
"A": "12 liters",
"B": "32 liters",
"C": "41 liters",
"D": "54 liters",
"E": "34 liters"
}
|
multiply(divide(135, add(3, 2)), 2)
|
add(n1,n2)|divide(n0,#0)|multiply(n2,#1)|
|
"milk = 3 / 5 * 135 = 81 liters water = 54 liters 81 : ( 54 + p ) = 3 : 4 162 + 3 p = 324 = > p = 54 54 liters of water are to be added for the ratio become 3 : 4 . answer : d"
|
general
|
math_qa__r9HpPKQ6OE7Uj7fv
|
Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 480 square feet. How many feet offence does Frank use? Select
A) 14
B) 47
C) 54
D) 180
E) 64
|
<gadget id="calculator">480 / 40</gadget>
<output>12</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">24 + 40</gadget>
<output>64</output>
<result>E</result>
|
E
| 64 |
Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 480 square feet. How many feet offence does Frank use?
|
{
"A": "14",
"B": "47",
"C": "54",
"D": "180",
"E": "64"
}
|
add(add(divide(480, 40), divide(480, 40)), 40)
|
divide(n1,n0)|add(#0,#0)|add(n0,#1)
|
area = length x breadth 480 = 40 x breadth so , breadth = 12 units fencing required is - breadth + breadth + length 12 + 12 + 40 = > 64 feet answer must be ( e ) 64
|
geometry
|
math_qa__0o0QuhHwtwvMo1tB
|
The height of the wall is 6 times its width and length of the wall is 7 times its height .if the volume of the wall be 6804 cu.m.its width is
Choose the correct choice from the following answers: A) 3 m B) 5 m C) 6 m D) 7 m E) 8 m
|
<gadget id="calculator">6 * 7</gadget>
<output>42</output>
<gadget id="calculator">42 * 6</gadget>
<output>252</output>
<gadget id="calculator">6_804 / 252</gadget>
<output>27</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">27 ** (1/3)</gadget>
<output>3</output>
<result>A</result>
|
A
| 3 |
The height of the wall is 6 times its width and length of the wall is 7 times its height .if the volume of the wall be 6804 cu.m.its width is
|
{
"A": "3 m",
"B": "5 m",
"C": "6 m",
"D": "7 m",
"E": "8 m"
}
|
power(divide(6804, multiply(multiply(6, 7), 6)), divide(const_1, const_3))
|
divide(const_1,const_3)|multiply(n0,n1)|multiply(n0,#1)|divide(n2,#2)|power(#3,#0)|
|
"explanation : let width = x then , height = 6 x and length = 42 x 42 x Γ£ β 6 x Γ£ β x = 6804 x = 3 answer : a"
|
physics
|
math_qa__t0DN4JHH1NlEyK3B
|
90 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
Choose the correct option.
A) 66
B) 35
C) 42
D) 27
E) 11
|
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>
<gadget id="calculator">(7/9) * 90</gadget>
<output>70</output>
<gadget id="calculator">70 / 2</gadget>
<output>35</output>
<result>B</result>
|
B
| 35 |
90 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
|
{
"A": "66",
"B": "35",
"C": "42",
"D": "27",
"E": "11"
}
|
divide(multiply(divide(add(const_4, const_3), add(add(const_4, const_3), const_2)), 90), const_2)
|
add(const_3,const_4)|add(#0,const_2)|divide(#0,#1)|multiply(n0,#2)|divide(#3,const_2)
|
x / 7 = y / 9 = > x : y = 7 : 9 7 / 16 * 90 = 35 answer : b
|
general
|
math_qa__HSkbJZv54NgSNQ1C
|
The radius of a semi circle is 7 cm then its perimeter is? Choose the correct choice from the following answers: A) 32.8 B) 36 C) 32.1 D) 32.2 E) 32.9
|
<gadget id="calculator">2 * pi * 7</gadget>
<output>14*pi = around 43.982297</output>
<gadget id="calculator">(14*pi) / 2</gadget>
<output>7*pi = around 21.991149</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">(7*pi) + 14</gadget>
<output>14 + 7*pi = around 35.991149</output>
<result>B</result>
|
B
| 36 |
The radius of a semi circle is 7 cm then its perimeter is?
|
{
"A": "32.8",
"B": "36",
"C": "32.1",
"D": "32.2",
"E": "32.9"
}
|
add(divide(circumface(7), const_2), multiply(7, const_2))
|
circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)|
|
"radius = 7 cm then diameter = 14 cm 1 / 2 * 22 / 7 * 14 + 14 = 36 answer : b"
|
physics
|
math_qa__QxFNoHVbkQeV1xtp
|
two persons raj and ramu started working for a company in similar jobs on january 1 , 1991 . raj ' s initial monthly salary was rs 400 , which increases by rs 40 after every year . ramu ' s initial monthly salary was rs 500 which increases by rs 20 after every 6 months . if these arrangements continue till december 31 , 200 . find the total salary they received during that period . Choose the correct choice from the following options: A) rs 108000 B) rs 144000 C) rs 132000 D) rs 152400 E) none of these
|
<gadget id="calculator">2 * 400</gadget>
<output>800</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">40 * 9</gadget>
<output>360</output>
<gadget id="calculator">800 + 360</gadget>
<output>1_160</output>
<gadget id="calculator">1_160 * 12</gadget>
<output>13_920</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">13_920 * 5</gadget>
<output>69_600</output>
<gadget id="calculator">2 * 500</gadget>
<output>1_000</output>
<gadget id="calculator">20 - 1</gadget>
<output>19</output>
<gadget id="calculator">19 * 20</gadget>
<output>380</output>
<gadget id="calculator">1_000 + 380</gadget>
<output>1_380</output>
<gadget id="calculator">1_380 * 6</gadget>
<output>8_280</output>
<gadget id="calculator">8_280 * 10</gadget>
<output>82_800</output>
<gadget id="calculator">69_600 + 82_800</gadget>
<output>152_400</output>
<result>D</result>
|
D
| 152,400 |
two persons raj and ramu started working for a company in similar jobs on january 1 , 1991 . raj ' s initial monthly salary was rs 400 , which increases by rs 40 after every year . ramu ' s initial monthly salary was rs 500 which increases by rs 20 after every 6 months . if these arrangements continue till december 31 , 200 . find the total salary they received during that period .
|
{
"A": "rs 108000",
"B": "rs 144000",
"C": "rs 132000",
"D": "rs 152400",
"E": "none of these"
}
|
add(multiply(multiply(add(multiply(const_2, 400), multiply(40, subtract(const_10, const_1))), const_12), add(const_2, const_3)), multiply(multiply(add(multiply(const_2, 500), multiply(subtract(20, const_1), 20)), 6), const_10))
|
add(const_2,const_3)|multiply(n2,const_2)|multiply(n4,const_2)|subtract(const_10,const_1)|subtract(n5,const_1)|multiply(n3,#3)|multiply(n5,#4)|add(#1,#5)|add(#2,#6)|multiply(#7,const_12)|multiply(n6,#8)|multiply(#0,#9)|multiply(#10,const_10)|add(#11,#12)
|
explanation : raj ' s salary as on 1 jan 1991 is rs 400 per month . his increment in his month salary is rs 40 per annum his total salary from 1 jan 1991 to 31 st dec 2000 i . e . in ten years = > 12 [ 2 ( 400 ) + ( 10 β 1 ) 40 ] Γ 10 / 2 . = > rs 69600 . ramu ' s salary as on jan 1 st 1991 is rs 550 and his half yearly increment in his month salary is rs 20 . his total salary from 1 jan 1991 to dec 31 , 2000 = > 6 [ 2 ( 500 ) + ( 20 β 1 ) 20 ] Γ 20 / 2 . = > rs 82000 . total salary of raj and ramu in the ten year period : = > rs . 69600 + rs . 82800 . = > rs 1 , 52400 . answer : d
|
general
|
math_qa__zSZDmiQtzHxfcPZC
|
At a certain college, 80 percent of the total number of students are freshmen. If 60 percent of the fresh-men are enrolled in the school of liberal arts and, of these, 50 percent are psychology majors, what percent of the students at the college are freshmen psychology majors enrolled in the school of liberal arts? Choose the correct answer
A) 25 % B) 20 % C) 22 % D) 21 % E) 24 %
|
<gadget id="calculator">80 * 60</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 100</gadget>
<output>48</output>
<gadget id="calculator">48 * 50</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 / 100</gadget>
<output>24</output>
<result>E</result>
|
E
| 24 |
At a certain college, 80 percent of the total number of students are freshmen. If 60 percent of the fresh-men are enrolled in the school of liberal arts and, of these, 50 percent are psychology majors, what percent of the students at the college are freshmen psychology majors enrolled in the school of liberal arts?
|
{
"A": "25 %",
"B": "20 %",
"C": "22 %",
"D": "21 %",
"E": "24 %"
}
|
divide(multiply(divide(multiply(80, 60), const_100), 50), const_100)
|
multiply(n0,n1)|divide(#0,const_100)|multiply(n2,#1)|divide(#2,const_100)
|
let ' s say there is a total of 100 students at this college . 80 percent of the total number of students are freshmen . # of freshmen = 80 % of 100 = 80 60 percent of the fresh - men are enrolled in the school of liberal arts . . . number of liberal arts freshmen = 60 % of 80 = 48 . . . and , of these , 50 percent are psychology majors . . . number of liberal arts freshmen who are psychology majors = 50 % of 48 = 24 what percent of the students at the college are freshmen psychology majors enrolled in the school of liberal arts ? 24 / 100 = 24 % answer : e
|
general
|
math_qa__QbOFrk0WE6gcjt4H
|
Difference of two numbers is 1670. If 7.5% of the number is 12.5% of the other number , find the number ?
Choose the correct option:
A) 2660 , 1000
B) 3660 , 2000
C) 3000 , 4160
D) 2490 , 4150
E) 2505 , 4175
|
<gadget id="calculator">7.5 / 12.5</gadget>
<output>0.6</output>
<gadget id="calculator">1 - 0.6</gadget>
<output>0.4</output>
<gadget id="calculator">1_670 / 0.4</gadget>
<output>4_175</output>
<gadget id="calculator">0.6 * 4_175</gadget>
<output>2_505</output>
<result>E</result>
|
E
| 2,505 |
Difference of two numbers is 1670. If 7.5% of the number is 12.5% of the other number , find the number ?
|
{
"A": "2660 , 1000",
"B": "3660 , 2000",
"C": "3000 , 4160",
"D": "2490 , 4150",
"E": "2505 , 4175"
}
|
multiply(divide(7.5, 12.5), divide(1670, subtract(const_1, divide(7.5, 12.5))))
|
divide(n1,n2)|subtract(const_1,#0)|divide(n0,#1)|multiply(#0,#2)|
|
"let the numbers be x and y . then , 7.5 % of x = 12.5 % of y x = 125 * y / 75 = 5 * y / 3 . now , x - y = 1670 5 * y / 3 β y = 1670 2 * y / 3 = 1670 y = [ ( 1670 * 3 ) / 2 ] = 2505 . one number = 2505 , second number = 5 * y / 3 = 4175 . answer e ."
|
gain
|
math_qa__veUJdOnubutJgIB4
|
The ratio of flour to water to sugar in a recipe is 11:8:1. The ratio in a new recipe calls for a doubling of the ratio of flour to water from the original recipe and a halving of the ratio of flour to sugar. If the new recipe calls for 4 cups of water, how much sugar is required? Choose the correct choice from the following.
A) 5
B) 4
C) 3
D) 2
E) 1
|
<gadget id="calculator">4 / 8</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">(1/2) * 4</gadget>
<output>2</output>
<result>D</result>
|
D
| 2 |
The ratio of flour to water to sugar in a recipe is 11:8:1. The ratio in a new recipe calls for a doubling of the ratio of flour to water from the original recipe and a halving of the ratio of flour to sugar. If the new recipe calls for 4 cups of water, how much sugar is required?
|
{
"A": "5",
"B": "4",
"C": "3",
"D": "2",
"E": "1"
}
|
multiply(divide(4, 8), multiply(const_4, 1))
|
divide(n3,n1)|multiply(n2,const_4)|multiply(#0,#1)|
|
"the ratio of flour to water is 22 : 8 = 11 : 4 . the ratio of flour to sugar is 5.5 : 1 = 11 : 2 . the new ratio of flour to water to sugar is 11 : 4 : 2 if we need 4 cups of water , then we need 2 cups of sugar . the answer is d ."
|
other
|
math_qa__tHBfkLF5f6uv2a11
|
craig sells major appliances . for each appliance he sells , craig receives a commission of $ 50 plus 10 percent of the selling price . during one particular week craig sold 6 appliances for selling prices totaling $ 3620 . what was the total of craig ' s commissions for that week ? Choose the most appropriate option:
A) $ 412
B) $ 526
C) $ 585
D) $ 605
E) $ 662
|
<gadget id="calculator">3_620 / 10</gadget>
<output>362</output>
<gadget id="calculator">50 * 6</gadget>
<output>300</output>
<gadget id="calculator">362 + 300</gadget>
<output>662</output>
<result>E</result>
|
E
| 662 |
craig sells major appliances . for each appliance he sells , craig receives a commission of $ 50 plus 10 percent of the selling price . during one particular week craig sold 6 appliances for selling prices totaling $ 3620 . what was the total of craig ' s commissions for that week ?
|
{
"A": "$ 412",
"B": "$ 526",
"C": "$ 585",
"D": "$ 605",
"E": "$ 662"
}
|
add(divide(3620, 10), multiply(50, 6))
|
divide(n3,n1)|multiply(n0,n2)|add(#0,#1)
|
craig receives a commission of $ 50 on each appliance plus a 10 % commission on total sales , thus his commission was 6 * 50 + 0.1 * 3620 = 662 . answer : e .
|
general
|
math_qa__p5zeAGP56dlNfMDG
|
If 8^x = 2^9, what is x? Answers:
A) 2
B) 3
C) 4
D) 5
E) 6
|
<gadget id="calculator">9 / 3</gadget>
<output>3</output>
<result>B</result>
|
B
| 3 |
If 8^x = 2^9, what is x?
|
{
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
}
|
divide(9, const_3)
|
divide(n2,const_3)
|
2 ^ 3 x = 2 ^ 9 3 x = 9 , therefore x = 3 answer b
|
general
|
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