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100B
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stringlengths 7
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math_qa__XOPXNSBoZHABEQ3r | 6 women can do 75 unit of work in 8 days by working 5hr/day in how many days 4 women do 30 units of work by working 8hr/day
Choose the correct choice from the following.
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">75 / 6</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) / 8</gadget>
<output>25/16 = around 1.5625</output>
<gadget id="calculator">(25/16) / 5</gadget>
<output>5/16 = around 0.3125</output>
<gadget id="calculator">(5/16) * 8</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 4</gadget>
<output>10</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<result>A</result> | A | 3 | 6 women can do 75 unit of work in 8 days by working 5hr/day in how many days 4 women do 30 units of work by working 8hr/day | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(30, multiply(multiply(divide(divide(divide(75, 6), 8), 5), 8), 4)) | divide(n1,n0)|divide(#0,n2)|divide(#1,n3)|multiply(n2,#2)|multiply(n4,#3)|divide(n5,#4) | ( 6 x 8 x 5 ) / 75 = ( ax 4 x 8 ) / 30 a = 3 answer : a | physics |
math_qa__PWp7XV7R3jTNIqmn | 50% of a number is more than 20% of 650 by 190. Find the number?
Choose the most appropriate option
A) 640 B) 278 C) 800 D) 267 E) 121 | <gadget id="calculator">650 * 20</gadget>
<output>13_000</output>
<gadget id="calculator">13_000 / 100</gadget>
<output>130</output>
<gadget id="calculator">130 + 190</gadget>
<output>320</output>
<gadget id="calculator">320 * 100</gadget>
<output>32_000</output>
<gadget id="calculator">32_000 / 50</gadget>
<output>640</output>
<result>A</result> | A | 640 | 50% of a number is more than 20% of 650 by 190. Find the number? | {
"A": "640",
"B": "278",
"C": "800",
"D": "267",
"E": "121"
} | divide(multiply(add(divide(multiply(650, 20), const_100), 190), const_100), 50) | multiply(n1,n2)|divide(#0,const_100)|add(n3,#1)|multiply(#2,const_100)|divide(#3,n0)| | "( 50 / 100 ) * x â € “ ( 20 / 100 ) * 650 = 190 1 / 2 x = 320 x = 640 answer : a" | gain |
math_qa__sKqIz4VPuQMLsxAi | When XYZ Co discontinued an agency arrangement with John, management held his commission of Rs. 25000/- for one month. Earlier John had availed an advance agency fees of 8280/- from company. But Robert forgot that. After one month John asked his fees and accountant gives Rs.18500/- to him. What is the incentive amount given to John ? Choose one.
A) 1780
B) 1250
C) 10780
D) 10500
E) 8600 | <gadget id="calculator">8_280 + 18_500</gadget>
<output>26_780</output>
<gadget id="calculator">26_780 - 25_000</gadget>
<output>1_780</output>
<result>A</result> | A | 1,780 | When XYZ Co discontinued an agency arrangement with John, management held his commission of Rs. 25000/- for one month. Earlier John had availed an advance agency fees of 8280/- from company. But Robert forgot that. After one month John asked his fees and accountant gives Rs.18500/- to him. What is the incentive amount given to John ? | {
"A": "1780",
"B": "1250",
"C": "10780",
"D": "10500",
"E": "8600"
} | subtract(add(8280, 18500), 25000) | add(n1,n2)|subtract(#0,n0) | total fees = rs . 25000 / - advance fees = 8280 / - balance fees = 25000 - 8280 = 16720 paid amount = 18500 / - incentive amount = 18500 - 16720 = 1780 / - answer is a | general |
math_qa__Zz7wKGf0CZ3OzaeO | Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 9/49, what is the probability that the next one she draws will be pink? Choices:
A) 1 / 49 B) 4 / 7 C) 3 / 7 D) 16 / 49 E) 40 / 49 | <gadget id="calculator">9 / 49</gadget>
<output>9/49 = around 0.183673</output>
<gadget id="calculator">(9/49) ** (1/2)</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">1 - (3/7)</gadget>
<output>4/7 = around 0.571429</output>
<result>B</result> | B | 0.571429 | Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 9/49, what is the probability that the next one she draws will be pink? | {
"A": "1 / 49",
"B": "4 / 7",
"C": "3 / 7",
"D": "16 / 49",
"E": "40 / 49"
} | subtract(const_1, sqrt(divide(9, 49))) | divide(n0,n1)|sqrt(#0)|subtract(const_1,#1) | the probability of drawing a pink gumball both times is the same . the probability that she drew two blue gumballs = 9 / 49 = ( 3 / 7 ) * ( 3 / 7 ) therefore probability that the next one she draws is pink = 4 / 7 option ( b ) | general |
math_qa__coLkfyDW06QogX0E | A sum was put a simple interest at a certain rate for 2 years. Had it been put at 4% higher rate, it would have fetched Rs. 60 more. The sum is:
Choose the correct answer:
A) rs . 750
B) rs . 700
C) rs . 820
D) rs . 940
E) rs . 900 | <gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 / 4</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 100</gadget>
<output>750</output>
<result>A</result> | A | 750 | A sum was put a simple interest at a certain rate for 2 years. Had it been put at 4% higher rate, it would have fetched Rs. 60 more. The sum is: | {
"A": "rs . 750",
"B": "rs . 700",
"C": "rs . 820",
"D": "rs . 940",
"E": "rs . 900"
} | multiply(divide(divide(60, 2), 4), const_100) | divide(n2,n0)|divide(#0,n1)|multiply(#1,const_100)| | "explanation : let the sub be rs . x and the initial rate be r % . then x × ( r + 4 ) × 2 / 100 − x × r × 2 / 100 = 60 ⇒ x × 4 × 2 / 100 = 60 ⇒ x × 2 / 100 = 15 ⇒ 2 x = 1500 ⇒ x = 750 answer : option a" | gain |
math_qa__QOEduSHeO6Oodv4S | Three coins are tossed. Find the probability of at least 2 tails ? Options.
A) 1 / 2
B) 2 / 3
C) 1 / 4
D) 1 / 8
E) 3 / 8 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">2 / 4</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | Three coins are tossed. Find the probability of at least 2 tails ? | {
"A": "1 / 2",
"B": "2 / 3",
"C": "1 / 4",
"D": "1 / 8",
"E": "3 / 8"
} | divide(2, power(const_2, 2)) | power(const_2,n0)|divide(n0,#0)| | "n ( s ) = 2 ^ 3 = 8 let e is the event of getting at least 2 tails n ( e ) = ttt , tth , htt , tht = 4 p ( e ) = n ( e ) / n ( s ) = 4 / 8 = 1 / 2 ans - a" | probability |
math_qa__2VXPceV7aXVNAO15 | A train can travel 50% faster than a car. Both start from point A at the same time and reach point B at 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is? Choose the correct choice from the following choices
A) 2387 B) 267 C) 120 D) 277 E) 271 | <gadget id="calculator">12.5 * 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 1</gadget>
<output>24</output>
<gadget id="calculator">24 * 25</gadget>
<output>600</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">600 / 5</gadget>
<output>120</output>
<result>C</result> | C | 120 | A train can travel 50% faster than a car. Both start from point A at the same time and reach point B at 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is? | {
"A": "2387",
"B": "267",
"C": "120",
"D": "277",
"E": "271"
} | divide(multiply(subtract(multiply(12.5, const_2), const_1), multiply(12.5, const_2)), add(const_4, const_1)) | add(const_1,const_4)|multiply(n2,const_2)|subtract(#1,const_1)|multiply(#1,#2)|divide(#3,#0)| | "let speed of the car be x km / hr . then , speed of the train = 150 / 100 x = 3 / 2 x km / hr . 75 / x - 75 / ( 3 / 2 x ) = 125 / ( 10 * 60 ) 75 / x - 50 / x = 5 / 24 = 120 km / hr . answer : c" | physics |
math_qa__YJLqSPpt5iHp0jL1 | TOM traveled the entire 60 miles trip. If he did the first 12 miles of at a constant rate 24 miles per hour and the remaining trip of at a constant rate 48 miles per hour, what is the his average speed, in miles per hour?
Choose the correct choice from the following answers:
A) 20 mph B) 24 mph C) 30 mph D) 40 mph E) 42 mph | <gadget id="calculator">60 - 12</gadget>
<output>48</output>
<gadget id="calculator">48 / 48</gadget>
<output>1</output>
<gadget id="calculator">12 / 24</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">60 / (3/2)</gadget>
<output>40</output>
<result>D</result> | D | 40 | TOM traveled the entire 60 miles trip. If he did the first 12 miles of at a constant rate 24 miles per hour and the remaining trip of at a constant rate 48 miles per hour, what is the his average speed, in miles per hour? | {
"A": "20 mph",
"B": "24 mph",
"C": "30 mph",
"D": "40 mph",
"E": "42 mph"
} | divide(60, add(divide(48, subtract(60, 12)), divide(12, 24))) | divide(n1,n2)|subtract(n0,n1)|divide(n3,#1)|add(#2,#0)|divide(n0,#3)| | "avg speed = total distance / total time = ( d 1 + d 2 ) / ( t 1 + t 2 ) = ( 12 + 48 ) / ( ( 12 / 24 ) + ( 48 / 48 ) ) = 60 * 2 / 3 = 40 mph d" | physics |
math_qa__0gzt6hArOyKHPL6B | A grocer has a sale of Rs. 2435, Rs. 2920, Rs. 2855, Rs. 3230 and Rs. 2560 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 2500? Choose the correct choice from the following options:
A) 5000 B) 4000 C) 1000 D) 6000 E) 8000 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 2_500</gadget>
<output>15_000</output>
<gadget id="calculator">2_435 + 2_920</gadget>
<output>5_355</output>
<gadget id="calculator">5_355 + 2_855</gadget>
<output>8_210</output>
<gadget id="calculator">8_210 + 3_230</gadget>
<output>11_440</output>
<gadget id="calculator">11_440 + 2_560</gadget>
<output>14_000</output>
<gadget id="calculator">15_000 - 14_000</gadget>
<output>1_000</output>
<result>C</result> | C | 1,000 | A grocer has a sale of Rs. 2435, Rs. 2920, Rs. 2855, Rs. 3230 and Rs. 2560 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 2500? | {
"A": "5000",
"B": "4000",
"C": "1000",
"D": "6000",
"E": "8000"
} | subtract(multiply(add(5, const_1), 2500), add(add(add(add(2435, 2920), 2855), 3230), 2560)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "total sale for 5 months = rs . ( 2435 + 2920 + 2855 + 3230 + 2560 ) = rs . 14000 . required sale = rs . [ ( 2500 x 6 ) - 14000 ] = rs . ( 15000 - 14000 ) = rs . 1000 answer : option c" | general |
math_qa__kJvDrJUmJLb50KCJ | What sum of money put at C.I amounts in 2 years to Rs.8840 and in 3 years to Rs.9261?
Choose the correct choice from the following answers:
A) 8054
B) 8877
C) 2877
D) 2678
E) 1011 | <gadget id="calculator">9_261 / 8_840</gadget>
<output>9_261/8_840 = around 1.047624</output>
<gadget id="calculator">(9_261/8_840) - 1</gadget>
<output>421/8_840 = around 0.047624</output>
<gadget id="calculator">(421/8_840) + 1</gadget>
<output>9_261/8_840 = around 1.047624</output>
<gadget id="calculator">(9_261/8_840) ** 2</gadget>
<output>85_766_121/78_145_600 = around 1.097517</output>
<gadget id="calculator">8_840 / (85_766_121/78_145_600)</gadget>
<output>690_807_104_000/85_766_121 = around 8_054.545267</output>
<result>A</result> | A | 8,054 | What sum of money put at C.I amounts in 2 years to Rs.8840 and in 3 years to Rs.9261? | {
"A": "8054",
"B": "8877",
"C": "2877",
"D": "2678",
"E": "1011"
} | divide(8840, power(add(subtract(divide(9261, 8840), const_1), const_1), 2)) | divide(n3,n1)|subtract(#0,const_1)|add(#1,const_1)|power(#2,n0)|divide(n1,#3)| | "8840 - - - - 421 100 - - - - ? = > 4.76 % x * 104.76 / 100 * 104.76 / 100 = 8840 x * 1.0975 = 8840 x = 8840 / 1.0975 = > 8054.54 answer : a" | general |
math_qa__X1OjMelweFAr5Adj | If square-root of 15 is 3.87. Then find the value of square-root of (5/3)
Choose one: A) 1.29 B) 1.39 C) 1.49 D) 1.59 E) 1.69 | <gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) ** (1/2)</gadget>
<output>sqrt(15)/3 = around 1.290994</output>
<result>A</result> | A | 1.29 | If square-root of 15 is 3.87. Then find the value of square-root of (5/3) | {
"A": "1.29",
"B": "1.39",
"C": "1.49",
"D": "1.59",
"E": "1.69"
} | sqrt(divide(5, 3)) | divide(n2,n3)|sqrt(#0) | = > root 5 / root 3 = ( root 5 / root 3 ) * ( root 3 / root 3 ) = root 15 / root 9 = 3.87 / 3 = 1.29 answer : a | general |
math_qa__LsNIYUL1dDIjHla6 | A salesman sold twice as much pears in the afternoon than in the morning. If he sold $480 kilograms of pears that day, how many kilograms did he sell in the afternoon?
Choose the correct option
A) 120 B) 180 C) 240 D) 280 E) 320 | <gadget id="calculator">480 / 3</gadget>
<output>160</output>
<gadget id="calculator">160 * 2</gadget>
<output>320</output>
<result>E</result> | E | 320 | A salesman sold twice as much pears in the afternoon than in the morning. If he sold $480 kilograms of pears that day, how many kilograms did he sell in the afternoon? | {
"A": "120",
"B": "180",
"C": "240",
"D": "280",
"E": "320"
} | multiply(divide(480, const_3), const_2) | divide(n0,const_3)|multiply(#0,const_2)| | "3 x = 480 x = 160 therefore , the salesman sold 160 kg in the morning and 2 ⋅ 160 = 320 kg in the afternoon . so answer is e ." | other |
math_qa__CQmTRTBEBzoQYL6l | On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 3 cups of tea. Last week Mo drank a total of 20 cups of tea and hot chocolate together. If during that week Mo drank 10 more tea cups than hot chocolate cups, then how many rainy days were there last week? Choose the correct choice from the following options:
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">7 - 5</gadget>
<output>2</output>
<result>A</result> | A | 2 | On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 3 cups of tea. Last week Mo drank a total of 20 cups of tea and hot chocolate together. If during that week Mo drank 10 more tea cups than hot chocolate cups, then how many rainy days were there last week? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | subtract(add(const_4, const_3), divide(divide(add(20, 10), const_2), 3)) | add(const_3,const_4)|add(n1,n2)|divide(#1,const_2)|divide(#2,n0)|subtract(#0,#3) | t = the number of cups of tea c = the number of cups of hot chocolate t + c = 20 t - c = 10 - > t = 15 . c = 5 . mo drinks 3 cups of tea a day then number of days that are not rainy = 15 / 3 = 5 so number of rainy days = 7 - 5 = 2 a is the answer . | general |
math_qa__4MPk1KkcdqL6ZRXu | How long will a boy take to run round a square field of side 50 meters, if he runs at the rate of 10km/hr? Choose the correct option
A) 52 sec B) 45 sec C) 72 sec D) 25 sec E) 39 sec | <gadget id="calculator">50 * 4</gadget>
<output>200</output>
<gadget id="calculator">1_000 / 3_600</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">10 * (5/18)</gadget>
<output>25/9 = around 2.777778</output>
<gadget id="calculator">200 / (25/9)</gadget>
<output>72</output>
<result>C</result> | C | 72 | How long will a boy take to run round a square field of side 50 meters, if he runs at the rate of 10km/hr? | {
"A": "52 sec",
"B": "45 sec",
"C": "72 sec",
"D": "25 sec",
"E": "39 sec"
} | divide(multiply(50, const_4), multiply(10, divide(const_1000, const_3600))) | divide(const_1000,const_3600)|multiply(n0,const_4)|multiply(n1,#0)|divide(#1,#2)| | "speed = 10 km / hr = 10 * 5 / 18 = 25 / 9 m / sec distance = 50 * 4 = 200 m time taken = 200 * 9 / 25 = 72 sec answer is c" | gain |
math_qa__Gtbi8OgSNdAul81R | The roof of an apartment building is rectangular and its length is 3 times longer than its width. If the area of the roof is 675 feet squared, what is the difference between the length and the width of the roof?
Choose one: A) 38 . B) 30 . C) 42 . D) 44 . E) 46 . | <gadget id="calculator">675 / 3</gadget>
<output>225</output>
<gadget id="calculator">225 ** (1/2)</gadget>
<output>15</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">45 - 15</gadget>
<output>30</output>
<result>B</result> | B | 30 | The roof of an apartment building is rectangular and its length is 3 times longer than its width. If the area of the roof is 675 feet squared, what is the difference between the length and the width of the roof? | {
"A": "38 .",
"B": "30 .",
"C": "42 .",
"D": "44 .",
"E": "46 ."
} | subtract(multiply(sqrt(divide(675, 3)), 3), sqrt(divide(675, 3))) | divide(n1,n0)|sqrt(#0)|multiply(#1,n0)|subtract(#2,#1)| | "let the width = x x * 3 x = 675 x ^ 2 = 225 x = 15 length = 3 * 15 = 45 difference = 45 - 15 = 30 b is the answer" | geometry |
math_qa__PhrVGj0gxXyxLJty | A grocery shop has a sale of Rs. 6235, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? Pick one:
A) 4857 B) 4184 C) 4012 D) 5191 E) 5291 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6_500 * 6</gadget>
<output>39_000</output>
<gadget id="calculator">6_235 + 6_927</gadget>
<output>13_162</output>
<gadget id="calculator">6_855 + 13_162</gadget>
<output>20_017</output>
<gadget id="calculator">20_017 + 7_230</gadget>
<output>27_247</output>
<gadget id="calculator">27_247 + 6_562</gadget>
<output>33_809</output>
<gadget id="calculator">39_000 - 33_809</gadget>
<output>5_191</output>
<result>D</result> | D | 5,191 | A grocery shop has a sale of Rs. 6235, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? | {
"A": "4857",
"B": "4184",
"C": "4012",
"D": "5191",
"E": "5291"
} | subtract(multiply(6500, add(5, const_1)), add(add(add(6855, add(6235, 6927)), 7230), 6562)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "let the sale in the sixth month = x then ( 6235 + 6927 + 6855 + 7230 + 6562 + x ) / 6 = 6500 = > 6235 + 6927 + 6855 + 7230 + 6562 + x = 6 × 6500 = > 33809 + x = 39000 = > x = 39000 − 33809 = 5191 answer : d" | general |
math_qa__qzjXFk4e33gUCggu | The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 45 years, was replaced by a new person. Find the age of the new person? Select the correct option.
A) 18 B) 56 C) 12 D) 15 E) 14 | <gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">45 - 30</gadget>
<output>15</output>
<result>D</result> | D | 15 | The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 45 years, was replaced by a new person. Find the age of the new person? | {
"A": "18",
"B": "56",
"C": "12",
"D": "15",
"E": "14"
} | subtract(45, multiply(10, 3)) | multiply(n0,n1)|subtract(n2,#0) | initial average age of the 10 persons be p . age of the new person q . sum of the ages of the initial 10 persons = 10 p new average = ( p - 3 ) 10 ( p - 3 ) = 10 p - 45 + q = > q = 15 answer : d | general |
math_qa__UybZAJGd8pow7tQL | If 20 men can build a wall 66 metres long in 15 days, what length of a similar can be built by 86 men in 8 days? Choose the correct option:
A) 151.36 mtrs B) 378.4 mtrs C) 478.4 mtrs D) 488.4 mtrs E) 578.4 mtrs | <gadget id="calculator">86 * 8</gadget>
<output>688</output>
<gadget id="calculator">20 * 15</gadget>
<output>300</output>
<gadget id="calculator">688 / 300</gadget>
<output>172/75 = around 2.293333</output>
<gadget id="calculator">66 * (172/75)</gadget>
<output>3_784/25 = around 151.36</output>
<result>A</result> | A | 151.36 | If 20 men can build a wall 66 metres long in 15 days, what length of a similar can be built by 86 men in 8 days? | {
"A": "151.36 mtrs",
"B": "378.4 mtrs",
"C": "478.4 mtrs",
"D": "488.4 mtrs",
"E": "578.4 mtrs"
} | multiply(66, divide(multiply(86, 8), multiply(20, 15))) | multiply(n3,n4)|multiply(n0,n2)|divide(#0,#1)|multiply(n1,#2)| | "if 20 men can build a wall 66 metres long in 15 days , length of a similar wall that can be built by 86 men in 8 days = ( 66 * 86 * 8 ) / ( 15 * 20 ) = 151.36 mtrs answer : a" | physics |
math_qa__bB72kBJs0OsCtCdm | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price per glass on the second day? Select the correct option: A) $ 0.15 B) $ 0.20 C) $ 0.30 D) $ 0.40 E) $ 0.45 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 0.6</gadget>
<output>1.2</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">1.2 / 3</gadget>
<output>0.4</output>
<result>D</result> | D | 0.4 | On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price per glass on the second day? | {
"A": "$ 0.15",
"B": "$ 0.20",
"C": "$ 0.30",
"D": "$ 0.40",
"E": "$ 0.45"
} | divide(multiply(add(const_1, const_1), 0.60), add(const_1, const_2)) | add(const_1,const_1)|add(const_1,const_2)|multiply(n0,#0)|divide(#2,#1)| | "we are given that orangeade is made on day 1 with an equal amount of water and orange juice . we can set this information up into a ratio using a variable multiplier : w : oj = x : x thus , orangeade quantity = amount of water + amount of oj = x + x = 2 x we are next given that orangeade on day 2 was made by mixing the same amount of orange juice with twice the amount of water . we can set this information up into a ratio using a variable multiplier : w : oj = 2 x : x thus , orangeade quantity = amount of water + amount of oj = 2 x + x = 3 x we also know that all orangeade made was sold and that the revenue on both days was the same . we can therefore set up the following equation : day 1 revenue = day 2 revenue that is , ( quantity sold day 1 ) ( price per glass day 1 ) = ( quantity sold day 2 ) ( price per glass day 2 ) let a be the amount of orangeade a glass can hold , then quantity sold day 1 = the number of glasses of orangeade sold on day 1 = 2 x / a similarly , quantity sold day 2 = the number of glasses of orangeade sold on day 2 = 3 x / a we also know that the price per glass on day 1 = $ 0.6 but we don ’ t know the price per glass on day 2 , so let ’ s label it as variable p . we now have : ( 2 x / a ) ( 0.6 ) = ( 3 x / a ) ( p ) multiplying both sides by a , we have : ( 2 x ) ( 0.6 ) = ( 3 x ) ( p ) 1.2 x = 3 xp 1.2 = 3 p p = 0.4 thus , each glass of orangeade was sold for $ 0.40 on day 2 . answer d ." | general |
math_qa__c9IdFqp0NpETIRm1 | Two consultants can type up a report in 12.5 hours and edit it in 7.5 hours. If Mary needs 30 hours to type the report and Jim needs 12 hours to edit it alone, how many R hours will it take if Jim types the report and Mary edits it immediately after he is done? Choose the correct choice from the following.
A) 41.4 B) 34.1 C) 13.4 D) 12.4 E) 10.8 | <gadget id="calculator">1 / 12.5</gadget>
<output>0.08</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">0.08 - (1/30)</gadget>
<output>0.046667</output>
<gadget id="calculator">1 / 0.046667</gadget>
<output>21.428418</output>
<gadget id="calculator">1 / 7.5</gadget>
<output>0.133333</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">0.133333 - (1/12)</gadget>
<output>0.05</output>
<gadget id="calculator">1 / 0.05</gadget>
<output>20</output>
<gadget id="calculator">21.428418 + 20</gadget>
<output>41.428418</output>
<result>A</result> | A | 41.4 | Two consultants can type up a report in 12.5 hours and edit it in 7.5 hours. If Mary needs 30 hours to type the report and Jim needs 12 hours to edit it alone, how many R hours will it take if Jim types the report and Mary edits it immediately after he is done? | {
"A": "41.4",
"B": "34.1",
"C": "13.4",
"D": "12.4",
"E": "10.8"
} | add(inverse(subtract(divide(const_1, 12.5), divide(const_1, 30))), inverse(subtract(divide(const_1, 7.5), divide(const_1, 12)))) | divide(const_1,n0)|divide(const_1,n2)|divide(const_1,n1)|divide(const_1,n3)|subtract(#0,#1)|subtract(#2,#3)|inverse(#4)|inverse(#5)|add(#6,#7)| | "break down the problem into two pieces : typing and editing . mary needs 30 hours to type the report - - > mary ' s typing rate = 1 / 30 ( rate reciprocal of time ) ( point 1 in theory below ) ; mary and jim can type up a report in 12.5 and - - > 1 / 30 + 1 / x = 1 / 12.5 = 2 / 25 ( where x is the time needed for jim to type the report alone ) ( point 23 in theory below ) - - > x = 150 / 7 ; jim needs 12 hours to edit the report - - > jim ' s editing rate = 1 / 12 ; mary and jim can edit a report in 7.5 and - - > 1 / y + 1 / 12 = 1 / 7.5 = 2 / 15 ( where y is the time needed for mary to edit the report alone ) - - > y = 20 ; how many r hours will it take if jim types the report and mary edits it immediately after he is done - - > x + y = 150 / 7 + 20 = ~ 41.4 answer : a ." | physics |
math_qa__lqKomOO9iad55Yy9 | The number 1254 is divisible by which number? Choose the correct choice from the following
A) 8 B) 7 C) 4 D) 5 E) 6 | <gadget id="calculator">100 + 100</gadget>
<output>200</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">200 + 9</gadget>
<output>209</output>
<gadget id="calculator">1_254 / 209</gadget>
<output>6</output>
<result>E</result> | E | 6 | The number 1254 is divisible by which number? | {
"A": "8",
"B": "7",
"C": "4",
"D": "5",
"E": "6"
} | divide(1254, add(add(const_100, const_100), subtract(const_10, const_1))) | add(const_100,const_100)|subtract(const_10,const_1)|add(#0,#1)|divide(n0,#2) | last 3 digit can not divisible by 8 so , reject option a 1254 is not divisible by 7 last number is not 0 or 5 , so neglect 4 is not divide 1254 divisibility rule of 6 is a number divisible both by 3 and 2 . 1254 attains both divisible . so the number is divisible by 6 option e | general |
math_qa__Y1WRCywLmJqbl3k5 | A certain no. when divided by 35leaves a remainder 25, what is the remainder if the same no.be divided by 15? Options:
A) 1 B) 3 C) 4 D) 6 E) 8 | <gadget id="calculator">35 - 25</gadget>
<output>10</output>
<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">6 - 2</gadget>
<output>4</output>
<result>C</result> | C | 4 | A certain no. when divided by 35leaves a remainder 25, what is the remainder if the same no.be divided by 15? | {
"A": "1",
"B": "3",
"C": "4",
"D": "6",
"E": "8"
} | subtract(subtract(subtract(35, 25), const_4), const_2) | subtract(n0,n1)|subtract(#0,const_4)|subtract(#1,const_2) | explanation : 35 + 25 = 60 / 15 = 4 ( remainder ) c | general |
math_qa__Sh94wcxTw1iHA8S8 | On a certain road, 40% of the motorists exceed the posted speed limit and receive speeding tickets, but 20% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit? Choose the most appropriate option
A) 10.5 % B) 12.5 % C) 15 % D) 22 % E) 50 % | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">40 / 80</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>E</result> | E | 50 | On a certain road, 40% of the motorists exceed the posted speed limit and receive speeding tickets, but 20% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on that road exceed the posted speed limit? | {
"A": "10.5 %",
"B": "12.5 %",
"C": "15 %",
"D": "22 %",
"E": "50 %"
} | multiply(divide(40, subtract(const_100, 20)), const_100) | subtract(const_100,n1)|divide(n0,#0)|multiply(#1,const_100)| | "suppose there are x motorists . 40 % of them exceeded the speed limit and received the ticket , i . e . 2 x / 5 . again , suppose total no . of motorists who exceeded the speed limit are y . 20 % of y exceeded the speed limit but did n ' t received the ticket , i . e . y / 5 . it means 4 y / 5 received the ticket . hence , 4 y / 5 = 2 x / 5 or y / x = 1 / 2 or y / x * 100 = 1 / 2 * 100 = 50 % e" | gain |
math_qa__fnf2H8GpkAuVDIyJ | If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56. If $2,000 is the total amount invested, how much is invested at 8 percent? Choices
A) $ 280
B) $ 800
C) $ 892
D) $ 1,108
E) $ 1,200 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 2</gadget>
<output>2_000</output>
<gadget id="calculator">10 * 8</gadget>
<output>80</output>
<gadget id="calculator">80 * 2</gadget>
<output>160</output>
<gadget id="calculator">160 + 56</gadget>
<output>216</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(1/10) + (2/25)</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">216 / (9/50)</gadget>
<output>1_200</output>
<gadget id="calculator">2_000 - 1_200</gadget>
<output>800</output>
<result>B</result> | B | 800 | If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56. If $2,000 is the total amount invested, how much is invested at 8 percent? | {
"A": "$ 280",
"B": "$ 800",
"C": "$ 892",
"D": "$ 1,108",
"E": "$ 1,200"
} | subtract(multiply(multiply(const_100, 10), const_2), divide(add(multiply(multiply(10, 8), const_2), 56), add(divide(10, const_100), divide(8, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|multiply(n0,const_100)|multiply(n0,n1)|add(#0,#1)|multiply(#2,const_2)|multiply(#3,const_2)|add(n4,#6)|divide(#7,#4)|subtract(#5,#8)| | "( a ) $ 280 ( b ) $ 800 ( c ) $ 892 ( d ) $ 1,108 ( e ) $ 1,200 y = 2000 - x . 1 x - . 08 ( 2000 - x ) = 56 . - 160 + . 18 x = 56 x = 1200 and y = 800 answer : b" | general |
math_qa__YYY4OonBac2VByC5 | Amit and Ananthu can do a work in 15 days and 45 days respectively. Amit started the work and left after 3 days. Ananthu took over and completed the work. In how many days was the total work completed? Choose the correct choice from the following
A) 28 days B) 30 days C) 33 days D) 35 days E) 39 days | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) * 3</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">(4/5) / (1/45)</gadget>
<output>36</output>
<gadget id="calculator">36 + 3</gadget>
<output>39</output>
<result>E</result> | E | 39 | Amit and Ananthu can do a work in 15 days and 45 days respectively. Amit started the work and left after 3 days. Ananthu took over and completed the work. In how many days was the total work completed? | {
"A": "28 days",
"B": "30 days",
"C": "33 days",
"D": "35 days",
"E": "39 days"
} | add(divide(subtract(const_1, multiply(inverse(15), 3)), inverse(45)), 3) | inverse(n0)|inverse(n1)|multiply(#0,n2)|subtract(const_1,#2)|divide(#3,#1)|add(#4,n2)| | "amit ’ s one day ’ s work = 1 / 15 amit ’ s 3 day ’ s work = 1 / 15 * 3 = 1 / 5 work left = 1 - 1 / 5 = 4 / 5 ananthu ’ s one day ’ s work = 1 / 45 ananthu can do work in = 4 / 5 * 45 = 36 days so total days = 36 + 3 = 39 days answer : e" | physics |
math_qa__GT2ZjRnRerOyV3V2 | A pet store holds cats and dogs. If the difference between the number of cats and the number of dogs is 5. What could be the ratio of Cats to dogs in the pet store? Choose the correct option: A) 1 : 3 B) 20 : 25 C) 1 : 5 D) 2 : 5 E) 4 : 6 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">20 / 25</gadget>
<output>4/5 = around 0.8</output>
<result>B</result> | B | 0.8 | A pet store holds cats and dogs. If the difference between the number of cats and the number of dogs is 5. What could be the ratio of Cats to dogs in the pet store? | {
"A": "1 : 3",
"B": "20 : 25",
"C": "1 : 5",
"D": "2 : 5",
"E": "4 : 6"
} | divide(multiply(5, const_4), add(multiply(5, const_4), 5)) | multiply(n0,const_4)|add(n0,#0)|divide(#0,#1)| | "say theratioof cats to dogs is a / b . then thenumberof cats would be ax and thenumberof dogs bx , for some positive integer x . we are told that ax - bx = 5 - - > x ( a - b ) = 5 . since 5 is a prime number it could be broken into the product of two positive multiples only in one way : x ( a - b ) = 1 * 5 . the above implies that either x = 1 and a - b = 5 or x = 5 and a - b = 1 . therefore the correct answer should have the difference between numerator and denominator equal to 1 or 13 . for the original question only option which fits is e , 4 : 5 . cats = 5 * 4 = 20 and dogs = 5 * 5 = 25 . answer : b ." | other |
math_qa__Hf654RFmzVCkFC5p | A number is said to be prime saturated if the product of all the different positive prime factors of w is less than the square root of w. What is the greatest two digit prime saturated integer ? Choose the correct choice: A) 99 B) 98 C) 97 D) 96 E) 95 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">6 + 90</gadget>
<output>96</output>
<result>D</result> | D | 96 | A number is said to be prime saturated if the product of all the different positive prime factors of w is less than the square root of w. What is the greatest two digit prime saturated integer ? | {
"A": "99",
"B": "98",
"C": "97",
"D": "96",
"E": "95"
} | add(multiply(const_2, const_3), subtract(const_100, const_10)) | multiply(const_2,const_3)|subtract(const_100,const_10)|add(#0,#1)| | "w 96 = 3 * 32 = 3 * 2 ^ 5 answer is d ." | other |
math_qa__CqrL30eF8GNLueWo | 54 is to be divided into two parts such that the sum of 10 times the first and 22 times the second is 780. The bigger part is Choose one:
A) 24 B) 30 C) 32 D) 34 E) 36 | <gadget id="calculator">54 * 10</gadget>
<output>540</output>
<gadget id="calculator">780 - 540</gadget>
<output>240</output>
<gadget id="calculator">22 - 10</gadget>
<output>12</output>
<gadget id="calculator">240 / 12</gadget>
<output>20</output>
<gadget id="calculator">54 - 20</gadget>
<output>34</output>
<result>D</result> | D | 34 | 54 is to be divided into two parts such that the sum of 10 times the first and 22 times the second is 780. The bigger part is | {
"A": "24",
"B": "30",
"C": "32",
"D": "34",
"E": "36"
} | subtract(54, divide(subtract(780, multiply(54, 10)), subtract(22, 10))) | multiply(n0,n1)|subtract(n2,n1)|subtract(n3,#0)|divide(#2,#1)|subtract(n0,#3)| | "solution let the two parts be ( 54 - x ) and x . then , 10 ( 54 - x ) + 22 x = 780 = 12 x = 240 ‹ = › x = 20 . therefore bigger part = ( 54 - x ) = 34 . answer d" | general |
math_qa__rz6TtV2u7H36S47o | A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was? Choose the most appropriate option:
A) 18
B) 20
C) 22
D) 24
E) 26 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">9 - 6</gadget>
<output>3</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<result>B</result> | B | 20 | A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was? | {
"A": "18",
"B": "20",
"C": "22",
"D": "24",
"E": "26"
} | divide(multiply(multiply(3, const_2), 10), subtract(9, multiply(3, const_2))) | multiply(n1,const_2)|multiply(n2,#0)|subtract(n0,#0)|divide(#1,#2)| | "explanation : x - - - - - - - 9 ( x + 10 ) - - - - 6 x * 9 = ( x + 10 ) 6 x = 20 answer : b" | physics |
math_qa__JHltlSZN5C3PXOvF | If the compound interest on a certain sum of money for 6 years at 10% per annum be Rs. 993, what would be the simple interest?
Select the correct option
A) rs . 880 B) rs . 890 C) rs . 1800 D) rs . 900 E) none | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">300 * 10</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 * 10</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 * 6</gadget>
<output>180_000</output>
<gadget id="calculator">180_000 / 100</gadget>
<output>1_800</output>
<result>C</result> | C | 1,800 | If the compound interest on a certain sum of money for 6 years at 10% per annum be Rs. 993, what would be the simple interest? | {
"A": "rs . 880",
"B": "rs . 890",
"C": "rs . 1800",
"D": "rs . 900",
"E": "none"
} | divide(multiply(multiply(multiply(multiply(const_3.0, const_100), 10), 10), 6), const_100) | multiply(const_3.0,const_100)|multiply(n1,#0)|multiply(n1,#1)|multiply(n0,#2)|divide(#3,const_100)| | "let p = principal a - amount we have a = p ( 1 + r / 100 ) 3 and ci = a - p atq 993 = p ( 1 + r / 100 ) 3 - p ? p = 3000 / - now si @ 10 % on 3000 / - for 6 yrs = ( 3000 x 10 x 6 ) / 100 = 1800 / - answer : c ." | gain |
math_qa__ctLHaeAdDkj4VHOi | A bicycle wheel has a diameter of 0.66m. How many complete revolutions does it make in 1km?
Options:
A) 246 B) 448 C) 1408 D) 482 E) 223 | <gadget id="calculator">1_000 * 1</gadget>
<output>1_000</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">3 + (7/50)</gadget>
<output>157/50 = around 3.14</output>
<gadget id="calculator">(157/50) * 0.66</gadget>
<output>2.0724</output>
<gadget id="calculator">1_000 / 2.0724</gadget>
<output>482.53233</output>
<result>D</result> | D | 482 | A bicycle wheel has a diameter of 0.66m. How many complete revolutions does it make in 1km? | {
"A": "246",
"B": "448",
"C": "1408",
"D": "482",
"E": "223"
} | divide(multiply(const_1000, 1), multiply(add(const_3, divide(add(multiply(const_3, const_4), const_2), power(add(multiply(const_4, const_2), const_2), const_2))), 0.66)) | multiply(n1,const_1000)|multiply(const_3,const_4)|multiply(const_2,const_4)|add(#1,const_2)|add(#2,const_2)|power(#4,const_2)|divide(#3,#5)|add(#6,const_3)|multiply(n0,#7)|divide(#0,#8)| | "1 revolution = 3.14 * diameter . number of revolutions in 1 km = 1000 m / ( 3.14 * 0.66 m ) = 482.5 . hence 482 complete revolutions . answer d" | physics |
math_qa__DXI2GrQ6LnRFZFUA | A sum of money amounts to Rs. 9800 after 5 years and Rs. 12015 after 8 years at the same rate of simple interest. The rate of interest per annum is? Choose one: A) 12.05 % B) 5 % C) 13.05 % D) 22.05 % E) 18.05 % | <gadget id="calculator">12_015 - 9_800</gadget>
<output>2_215</output>
<gadget id="calculator">9_800 * 8</gadget>
<output>78_400</output>
<gadget id="calculator">5 * 12_015</gadget>
<output>60_075</output>
<gadget id="calculator">78_400 - 60_075</gadget>
<output>18_325</output>
<gadget id="calculator">2_215 / 18_325</gadget>
<output>443/3_665 = around 0.120873</output>
<gadget id="calculator">(443/3_665) * 100</gadget>
<output>8_860/733 = around 12.087312</output>
<result>A</result> | A | 12.05 | A sum of money amounts to Rs. 9800 after 5 years and Rs. 12015 after 8 years at the same rate of simple interest. The rate of interest per annum is? | {
"A": "12.05 %",
"B": "5 %",
"C": "13.05 %",
"D": "22.05 %",
"E": "18.05 %"
} | multiply(divide(subtract(12015, 9800), subtract(multiply(9800, 8), multiply(5, 12015))), const_100) | multiply(n0,n3)|multiply(n1,n2)|subtract(n2,n0)|subtract(#0,#1)|divide(#2,#3)|multiply(#4,const_100) | s . i . for 3 years = ( 12015 - 9800 ) = rs . 2215 s . i . for 5 years = rs . 2215 / 3 * 5 = rs . 3691 . principal = ( 9800 - 3675 ) = rs . 6108 hence , rate = ( 100 * 3691 ) / ( 6125 * 5 ) = 12.05 % answer : a | gain |
math_qa__Wel0lQTl8GZuA1JA | A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 2, 4 and 8, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created? Choose the correct choice:
A) 20 B) 22 C) 24 D) 27 E) 30 | <gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">27 - 1</gadget>
<output>26</output>
<result>D</result> | D | 27 | A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 2, 4 and 8, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created? | {
"A": "20",
"B": "22",
"C": "24",
"D": "27",
"E": "30"
} | subtract(power(3, 3), const_1) | power(n0,n0)|subtract(#0,const_1)| | "total # of codes possible is 3 * 3 * 3 = 27 . oit of those 27 codes answer : d ." | general |
math_qa__FpttJ6nCD2IHOALn | The average age of one class strength 32 students is 16 yrs. if the staff's age is also included, the average increases by one year. Find the age of the staff
Options:
A) 50
B) 52
C) 49
D) 32
E) 35 | <gadget id="calculator">32 + 1</gadget>
<output>33</output>
<gadget id="calculator">16 + 1</gadget>
<output>17</output>
<gadget id="calculator">33 * 17</gadget>
<output>561</output>
<gadget id="calculator">32 * 16</gadget>
<output>512</output>
<gadget id="calculator">561 - 512</gadget>
<output>49</output>
<result>C</result> | C | 49 | The average age of one class strength 32 students is 16 yrs. if the staff's age is also included, the average increases by one year. Find the age of the staff | {
"A": "50",
"B": "52",
"C": "49",
"D": "32",
"E": "35"
} | subtract(multiply(add(32, const_1), add(16, const_1)), multiply(32, 16)) | add(n0,const_1)|add(n1,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2) | total age of students = > 32 × 16 = 512 yrs total age inclusive staff = 33 × ( 16 + 1 ) = 561 = > staff ' s age 561 - 512 = 49 yrs answer c | general |
math_qa__3GvxPyK403MXxC0B | A man purchased 5 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? Pick: A) 250 B) 350 C) 450 D) 470 E) 500 | <gadget id="calculator">10 * 150</gadget>
<output>1_500</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">500 + 750</gadget>
<output>1_250</output>
<gadget id="calculator">1_500 - 1_250</gadget>
<output>250</output>
<result>A</result> | A | 250 | A man purchased 5 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? | {
"A": "250",
"B": "350",
"C": "450",
"D": "470",
"E": "500"
} | subtract(multiply(const_10, 150), add(multiply(5, 100), multiply(5, 150))) | multiply(n3,const_10)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|subtract(#0,#3)| | "explanation : 10 * 150 = 1500 5 * 100 + 5 * 150 = 1250 1500 – 1250 = 250 a" | general |
math_qa__FRkdlXyc2743n2ow | Working simultaneously and independently at an identical constant rate, 5 machines of a certain type can produce a total of x units of product P in 8 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 3x units of product P in 4 days?
Choose the correct choice from the following choices:
A) 30 B) 18 C) 16 D) 12 E) 8 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">8 / 4</gadget>
<output>2</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<result>A</result> | A | 30 | Working simultaneously and independently at an identical constant rate, 5 machines of a certain type can produce a total of x units of product P in 8 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 3x units of product P in 4 days? | {
"A": "30",
"B": "18",
"C": "16",
"D": "12",
"E": "8"
} | multiply(multiply(5, 3), divide(8, 4)) | divide(n1,n3)|multiply(n0,n2)|multiply(#0,#1) | 5 machines do x units in 8 days we have x / 8 = > rate of the 5 machines we know that we need to have 3 x units in 4 days therefore , we need to get to 3 x / 4 rate of the machines . rate of one machine is x / 8 * 1 / 5 = x / 40 . now , we need to know how many machines need to work simultaneously , to get 3 x done in 4 days . 3 x / 4 work needs to be done by machines that work at x / 40 rate . let ' s assign a constant y for the number of machines : ( x / 40 ) * y = 3 x / 4 y = 3 x / 4 * 40 / x cancel 4 with 40 , and x with x and get - > 30 . answer choice a | general |
math_qa__FfQwYOqDXtRUDEGC | On a Saturday night, each of the rooms at a certain motel was rented for either $40 or $60. If 10 of the rooms that were rented for $60 had instead been rented for $40, then the total rent the motel charged for that night would have been reduced by 10 percent. What was the total rent the motel actually charged for that night ?
Options:
A) $ 600
B) $ 800
C) $ 1,000
D) $ 1,600
E) $ 2,000 | <gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">10 * 20</gadget>
<output>200</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">200 / (1/10)</gadget>
<output>2_000</output>
<result>E</result> | E | 2,000 | On a Saturday night, each of the rooms at a certain motel was rented for either $40 or $60. If 10 of the rooms that were rented for $60 had instead been rented for $40, then the total rent the motel charged for that night would have been reduced by 10 percent. What was the total rent the motel actually charged for that night ? | {
"A": "$ 600",
"B": "$ 800",
"C": "$ 1,000",
"D": "$ 1,600",
"E": "$ 2,000"
} | divide(multiply(10, subtract(60, 40)), divide(10, const_100)) | divide(n5,const_100)|subtract(n1,n0)|multiply(n2,#1)|divide(#2,#0)| | "let total rent the motel charge for all rooms = x if 10 rooms that were rented for 60 $ had instead been rented for 40 $ , then total difference in prices = 20 $ * 10 = 200 $ total rent the motel charged would have been reduced by 10 % . 10 x = 200 = > x = 2000 answer e" | gain |
math_qa__2Itc2PEmumPSPvB3 | There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 50% Select the correct option: A) 40.8 B) 19.75 C) 20.75 D) 21.75 E) 22.75 | <gadget id="calculator">100 / 50</gadget>
<output>2</output>
<gadget id="calculator">60 * 84</gadget>
<output>5_040</output>
<gadget id="calculator">5_040 / 100</gadget>
<output>252/5 = around 50.4</output>
<gadget id="calculator">2 * (252/5)</gadget>
<output>504/5 = around 100.8</output>
<gadget id="calculator">(504/5) - 60</gadget>
<output>204/5 = around 40.8</output>
<result>A</result> | A | 40.8 | There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 50% | {
"A": "40.8",
"B": "19.75",
"C": "20.75",
"D": "21.75",
"E": "22.75"
} | subtract(multiply(divide(const_100, 50), divide(multiply(60, 84), const_100)), 60) | divide(const_100,n2)|multiply(n0,n1)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,n0)| | "60 * 84 / 100 = 50.40 lit milk that is 9.60 lit water let x lit water will be added then ( 60 + x ) * 50 / 100 = 50.40 so x = 40.8 answer : a" | gain |
math_qa__KdiMq57bYRoEjXY5 | Jill invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. Approximately how much Q does she have in her account after two years? Pick one.
A) $ 10079.44 B) q = $ 10815.83 C) $ 12652.61 D) $ 14232.14 E) $ 20598.11 | <gadget id="calculator">3.96 / 100</gadget>
<output>0.0396</output>
<gadget id="calculator">0.0396 / 2</gadget>
<output>0.0198</output>
<gadget id="calculator">1 + 0.0198</gadget>
<output>1.0198</output>
<gadget id="calculator">1.0198 ** 4</gadget>
<output>1.081583</output>
<gadget id="calculator">10_000 * 1.081583</gadget>
<output>10_815.83</output>
<result>B</result> | B | 10,815.83 | Jill invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. Approximately how much Q does she have in her account after two years? | {
"A": "$ 10079.44",
"B": "q = $ 10815.83",
"C": "$ 12652.61",
"D": "$ 14232.14",
"E": "$ 20598.11"
} | multiply(10000, power(add(const_1, divide(divide(3.96, const_100), const_2)), const_4)) | divide(n1,const_100)|divide(#0,const_2)|add(#1,const_1)|power(#2,const_4)|multiply(n0,#3)| | "ps . i guess one can use simple interest to solve cause the answer choices are quite spread between you can easily arrive at something near 8 % hence b the answer" | gain |
math_qa__xP6pmnrnBNPqh0h2 | Machine P and Machine Q are each used to manufacture 440 sprockets. It takes Machine P 10 hours longer to produce 440 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce?
Choose the most appropriate option: A) 2 B) 4 C) 6 D) 8 E) 10 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">440 / (11/10)</gadget>
<output>400</output>
<gadget id="calculator">440 - 400</gadget>
<output>40</output>
<gadget id="calculator">40 / 10</gadget>
<output>4</output>
<result>B</result> | B | 4 | Machine P and Machine Q are each used to manufacture 440 sprockets. It takes Machine P 10 hours longer to produce 440 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | divide(subtract(440, divide(440, add(divide(10, const_100), const_1))), 10) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)|divide(#3,n1)| | "p makes x sprockets per hour . then q makes 1.1 x sprockets per hour . 440 / x = 440 / 1.1 x + 10 1.1 ( 440 ) = 440 + 11 x 11 x = 44 x = 4 the answer is b ." | gain |
math_qa__dm3CWuqLhIvNbIC1 | A retailer buys 100 pens at the market price of 36 pens from a wholesaler, if he sells these pens giving a discount of 1%, what is the profit % ? Choose the most appropriate option:
A) 110 B) 175 C) 212 D) 218 E) 220 | <gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">1 - (1/100)</gadget>
<output>99/100 = around 0.99</output>
<gadget id="calculator">36 / 100</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(99/100) - (9/25)</gadget>
<output>63/100 = around 0.63</output>
<gadget id="calculator">(63/100) / (9/25)</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">100 * (7/4)</gadget>
<output>175</output>
<result>B</result> | B | 175 | A retailer buys 100 pens at the market price of 36 pens from a wholesaler, if he sells these pens giving a discount of 1%, what is the profit % ? | {
"A": "110",
"B": "175",
"C": "212",
"D": "218",
"E": "220"
} | multiply(const_100, divide(subtract(subtract(1, divide(1, const_100)), divide(36, 100)), divide(36, 100))) | divide(n2,const_100)|divide(n1,n0)|subtract(n2,#0)|subtract(#2,#1)|divide(#3,#1)|multiply(#4,const_100)| | "let the market price of each pen be $ 1 then , cost price of 100 pens = $ 36 selling price of 100 pens = 99 % of $ 100 = $ 99 profit % = ( ( 63 * 100 ) / 36 ) % = 175 % answer b" | gain |
math_qa__VBVkJAqASPDY6TL4 | 3 litre of water is added to 11 litre of a solution containing 42% of alcohol in the water. The percentage of alcohol in the new mixture is? Choose the correct choice from the following answers:
A) 30 % B) 33 % C) 35 % D) 40 % E) 45 % | <gadget id="calculator">11 * 42</gadget>
<output>462</output>
<gadget id="calculator">462 / 100</gadget>
<output>231/50 = around 4.62</output>
<gadget id="calculator">3 + 11</gadget>
<output>14</output>
<gadget id="calculator">(231/50) / 14</gadget>
<output>33/100 = around 0.33</output>
<gadget id="calculator">(33/100) * 100</gadget>
<output>33</output>
<result>B</result> | B | 33 | 3 litre of water is added to 11 litre of a solution containing 42% of alcohol in the water. The percentage of alcohol in the new mixture is? | {
"A": "30 %",
"B": "33 %",
"C": "35 %",
"D": "40 %",
"E": "45 %"
} | multiply(divide(divide(multiply(11, 42), const_100), add(3, 11)), const_100) | add(n0,n1)|multiply(n1,n2)|divide(#1,const_100)|divide(#2,#0)|multiply(#3,const_100) | we have a 11 litre solution containing 42 % of alcohol in the water . = > quantity of alcohol in the solution = 11 × 42 100 = 11 × 42100 now 3 litre of water is added to the solution . = > total quantity of the new solution = 11 + 3 = 14 percentage of alcohol in the new solution = 11 × 42 100 14 × 100 = 11 × 4210014 × 100 = 11 × 3 100 = 33 % b ) | general |
math_qa__ABxoMGcqA7oilQEF | A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 10 per metre of cloth. What is the cost price of one metre of cloth? Choose the correct choice from the following answers:
A) 26
B) 95
C) 90
D) 42
E) 22 | <gadget id="calculator">8_925 / 85</gadget>
<output>105</output>
<gadget id="calculator">105 - 10</gadget>
<output>95</output>
<result>B</result> | B | 95 | A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 10 per metre of cloth. What is the cost price of one metre of cloth? | {
"A": "26",
"B": "95",
"C": "90",
"D": "42",
"E": "22"
} | subtract(divide(8925, 85), 10) | divide(n1,n0)|subtract(#0,n2)| | "sp of 1 m of cloth = 8925 / 85 = rs . 105 cp of 1 m of cloth = sp of 1 m of cloth - profit on 1 m of cloth = rs . 105 - rs . 10 = rs . 95 answer : b" | physics |
math_qa__1AYpdLf1lFnqlMYQ | A trailer carries 3, 4 and 5 crates on a trip. Each crate weighs no less than 120 kg. What is the maximum weight of the crates on a single trip? Choices.
A) 1250 B) 625 C) 600 D) 7500 E) 375 | <gadget id="calculator">5 * 120</gadget>
<output>600</output>
<result>C</result> | C | 600 | A trailer carries 3, 4 and 5 crates on a trip. Each crate weighs no less than 120 kg. What is the maximum weight of the crates on a single trip? | {
"A": "1250",
"B": "625",
"C": "600",
"D": "7500",
"E": "375"
} | multiply(5, 120) | multiply(n2,n3) | max no . of crates = 5 . max weight = 120 kg max . weight carried = 5 * 120 = 600 kg = c | general |
math_qa__JQzY8xrxzXbty7ma | A student completes a 3 part exam as follows. The student completes sections A in 24 minutes and takes an equal time to complete the two remaining sections. What is the ratio of time spent on section C to section A if the total duration is 1 hour? Choose the correct choice from the following options: A) 7 : 8 B) 6 : 7 C) 5 : 6 D) 4 : 5 E) 3 : 4 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<result>E</result> | E | 0.75 | A student completes a 3 part exam as follows. The student completes sections A in 24 minutes and takes an equal time to complete the two remaining sections. What is the ratio of time spent on section C to section A if the total duration is 1 hour? | {
"A": "7 : 8",
"B": "6 : 7",
"C": "5 : 6",
"D": "4 : 5",
"E": "3 : 4"
} | divide(const_3, const_4) | divide(const_3,const_4) | the time spent on section b and section c is 18 minutes each . the ratio of c to a is 18 : 24 = 3 : 4 the answer is e . | physics |
math_qa__mRCqvAWbSGg4BcMg | the average of first 3 prime numbers greater than 20 is ? Pick.
A) 10 B) 20 C) 30 D) 27.7 E) 50 | <gadget id="calculator">20 + 3</gadget>
<output>23</output>
<gadget id="calculator">23 + 4</gadget>
<output>27</output>
<gadget id="calculator">27 + 2</gadget>
<output>29</output>
<gadget id="calculator">23 + 29</gadget>
<output>52</output>
<gadget id="calculator">29 + 2</gadget>
<output>31</output>
<gadget id="calculator">52 + 31</gadget>
<output>83</output>
<gadget id="calculator">83 / 3</gadget>
<output>83/3 = around 27.666667</output>
<result>D</result> | D | 27.7 | the average of first 3 prime numbers greater than 20 is ? | {
"A": "10",
"B": "20",
"C": "30",
"D": "27.7",
"E": "50"
} | divide(add(add(add(20, const_3), add(add(add(20, const_3), const_4), const_2)), add(add(add(add(20, const_3), const_4), const_2), const_2)), 3) | add(n1,const_3)|add(#0,const_4)|add(#1,const_2)|add(#0,#2)|add(#2,const_2)|add(#3,#4)|divide(#5,n0) | 23 + 29 + 31 = 83 / 3 = 27.7 answer : d | general |
math_qa__utXVFpF6BA7vAkB5 | If x and y are integers, what is the least positive number of 24x+16y? Options
A) 3 B) 4 C) 5 D) 6 E) 8 | <gadget id="calculator">24 - 16</gadget>
<output>8</output>
<result>E</result> | E | 8 | If x and y are integers, what is the least positive number of 24x+16y? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "8"
} | subtract(24, 16) | subtract(n0,n1)| | "24 x + 16 y = 8 ( 3 x + 2 y ) which will be a minimum positive number when 3 x + 2 y = 1 . 3 ( 1 ) + 2 ( - 1 ) = 1 then 8 ( 3 x + 2 y ) can have a minimum positive value of 8 . the answer is e ." | general |
math_qa__gaB9yyDYsQ5TcNxT | A certain company retirement plan has arule of 70provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1987 on her 32nd birthday first be eligible to retire under this provision? Choose the correct option
A) 2003
B) 2004
C) 2005
D) 2006
E) 2007 | <gadget id="calculator">70 - 32</gadget>
<output>38</output>
<gadget id="calculator">38 / 2</gadget>
<output>19</output>
<gadget id="calculator">1_987 + 19</gadget>
<output>2_006</output>
<result>D</result> | D | 2,006 | A certain company retirement plan has arule of 70provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1987 on her 32nd birthday first be eligible to retire under this provision? | {
"A": "2003",
"B": "2004",
"C": "2005",
"D": "2006",
"E": "2007"
} | add(1987, divide(subtract(70, 32), const_2)) | subtract(n0,n3)|divide(#0,const_2)|add(n2,#1)| | "she must gain at least 70 points , now she has 32 and every year gives her two more points : one for age and one for additional year of employment , so 32 + 2 * ( # of years ) = 70 - - > ( # of years ) = 19 - - > 1987 + 19 = 2006 . answer : d ." | general |
math_qa__6XobUFt93KPdowJG | A cistern is filled by a tap in 3 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how long will it take the leak to empty it? Choose the correct choice from the following answers:
A) 11
B) 12
C) 29
D) 28
E) 29 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + (1/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">1 / (7/2)</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(2/7) - (1/4)</gadget>
<output>1/28 = around 0.035714</output>
<gadget id="calculator">1 / (1/28)</gadget>
<output>28</output>
<result>D</result> | D | 28 | A cistern is filled by a tap in 3 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how long will it take the leak to empty it? | {
"A": "11",
"B": "12",
"C": "29",
"D": "28",
"E": "29"
} | divide(const_1, subtract(divide(const_1, add(3, divide(1, 2))), divide(1, const_4))) | divide(n1,n2)|divide(n1,const_4)|add(n0,#0)|divide(const_1,#2)|subtract(#3,#1)|divide(const_1,#4) | 2 / 7 - 1 / x = 1 / 4 x = 28 answer : d | physics |
math_qa__rTl1K2E5QGUJiFVe | If 10 boys meet at a reunion and each boy shakes hands exactly once with each of the others, then what is the total number of handshakes Choose the correct choice
A) 41
B) 42
C) 43
D) 44
E) 45 | <gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">40_320 * 2</gadget>
<output>80_640</output>
<gadget id="calculator">3_628_800 / 80_640</gadget>
<output>45</output>
<result>E</result> | E | 45 | If 10 boys meet at a reunion and each boy shakes hands exactly once with each of the others, then what is the total number of handshakes | {
"A": "41",
"B": "42",
"C": "43",
"D": "44",
"E": "45"
} | divide(factorial(10), multiply(factorial(subtract(10, const_2)), factorial(const_2))) | factorial(n0)|factorial(const_2)|subtract(n0,const_2)|factorial(#2)|multiply(#3,#1)|divide(#0,#4) | n ( n - 1 ) / 2 = 10 * 9 / 2 = 45 answer : e | general |
math_qa__cbxGkkgB4kXnjtg6 | 6x – 5y + 3z = 22
4x + 8y – 11z = 7
5x – 6y + 2z = 12
Given the equations above, x + y + z = ? Choose the correct choice
A) 10 B) 12 C) 13 D) 14 E) 15 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<result>A</result> | A | 10 | 6x – 5y + 3z = 22
4x + 8y – 11z = 7
5x – 6y + 2z = 12
Given the equations above, x + y + z = ? | {
"A": "10",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | multiply(5, const_2) | multiply(n1,const_2) | ( 6 x – 5 y + 3 z ) - ( 5 x – 6 y + 2 z ) = 22 - 12 or , x + y + z = 10 option a is the ans | general |
math_qa__2zN3cZQIOQ1igl2g | The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 60%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output? Choose the correct option: A) 20 % B) 24 % C) 30 % D) 43 % E) 79 % | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">160 / 100</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(11/10) * (8/5)</gadget>
<output>44/25 = around 1.76</output>
<gadget id="calculator">(44/25) - 1</gadget>
<output>19/25 = around 0.76</output>
<gadget id="calculator">(19/25) / (44/25)</gadget>
<output>19/44 = around 0.431818</output>
<gadget id="calculator">(19/44) * 100</gadget>
<output>475/11 = around 43.181818</output>
<result>D</result> | D | 43 | The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 60%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output? | {
"A": "20 %",
"B": "24 %",
"C": "30 %",
"D": "43 %",
"E": "79 %"
} | multiply(divide(subtract(multiply(divide(add(const_100, 10), const_100), divide(add(const_100, 60), const_100)), const_1), multiply(divide(add(const_100, 10), const_100), divide(add(const_100, 60), const_100))), const_100) | add(n0,const_100)|add(n1,const_100)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|subtract(#4,const_1)|divide(#5,#4)|multiply(#6,const_100)| | "take it as original output = 100 . to meet demand increase by 10 % , then output = 110 . to meet holiday demand , new output increase by 60 % then output equals 176 to restore new holidy demand output to original 100 . final - initial / final * 100 = 76 / 176 * 100 = 8 / 33 * 100 = 43 % approxiamately . option d is correct ." | general |
math_qa__SR9oKEedwRaxH6yG | Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 38 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped?
Select the correct option:
A) 405
B) 420
C) 440
D) 447
E) 490 | <gadget id="calculator">72 / 60</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 35</gadget>
<output>42</output>
<gadget id="calculator">38 - 35</gadget>
<output>3</output>
<gadget id="calculator">42 / 3</gadget>
<output>14</output>
<gadget id="calculator">35 * 14</gadget>
<output>490</output>
<result>E</result> | E | 490 | Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 38 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped? | {
"A": "405",
"B": "420",
"C": "440",
"D": "447",
"E": "490"
} | multiply(35, divide(multiply(divide(72, const_60), 35), subtract(38, 35))) | divide(n1,const_60)|subtract(n2,n0)|multiply(n0,#0)|divide(#2,#1)|multiply(n0,#3)| | "car y began travelling after 72 minutes or 1.2 hours . let t be the time for which car y travelled before it stopped . both cars stop when they have travelled the same distance . so , 35 ( t + 1.2 ) = 38 t t = 14 distance traveled by car x from the time car y began traveling until both cars stopped is 35 x 14 = 490 miles answer : - e" | physics |
math_qa__9SgWtm6onVuCz3rq | Jerry travels 8 miles at an average speed of 40 miles per hour, stops for 15 minutes, and then travels another 20 miles at an average speed of 60 miles per hour. What is Jerry’s average speed, in miles per hour, for this trip? Select:
A) 35 B) 42.5 C) 44 D) 50 E) 52.5 | <gadget id="calculator">8 + 20</gadget>
<output>28</output>
<gadget id="calculator">8 / 40</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/5) + (1/4)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(9/20) + (1/3)</gadget>
<output>47/60 = around 0.783333</output>
<gadget id="calculator">28 / (47/60)</gadget>
<output>1_680/47 = around 35.744681</output>
<result>A</result> | A | 35 | Jerry travels 8 miles at an average speed of 40 miles per hour, stops for 15 minutes, and then travels another 20 miles at an average speed of 60 miles per hour. What is Jerry’s average speed, in miles per hour, for this trip? | {
"A": "35",
"B": "42.5",
"C": "44",
"D": "50",
"E": "52.5"
} | divide(add(8, 20), add(add(divide(8, 40), divide(15, const_60)), divide(20, 60))) | add(n0,n3)|divide(n0,n1)|divide(n2,const_60)|divide(n3,n4)|add(#1,#2)|add(#4,#3)|divide(#0,#5) | total time taken by jerry = ( 8 / 40 ) * 60 minutes + 15 minutes + ( 20 / 60 ) * 60 minutes = 47 minutes average speed = total distance / total time = ( 8 + 20 ) miles / ( 47 / 60 ) hours = 28 * 60 / 47 = 35 miles per hour answer : option a | physics |
math_qa__fiwPxM61DUZvTt5t | John makes $40 a week from his job. He earns a raise and now makes $60 a week. What is the % increase? Choose the correct answer.
A) 16 % B) 16.66 % C) 18 % D) 21 % E) 50 % | <gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">20 / 40</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>E</result> | E | 50 | John makes $40 a week from his job. He earns a raise and now makes $60 a week. What is the % increase? | {
"A": "16 %",
"B": "16.66 %",
"C": "18 %",
"D": "21 %",
"E": "50 %"
} | multiply(divide(subtract(60, 40), 40), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 20 / 40 ) * 100 = 50 % . e" | gain |
math_qa__tt87g4w9eIgaCiDc | -69*39+450=? Choose the correct choice from the following choices.
A) 2736
B) 2309
C) - 2801
D) - 2241
E) none of these | <gadget id="calculator">-69</gadget>
<output>-69</output>
<gadget id="calculator">(-69) * 39</gadget>
<output>-2_691</output>
<gadget id="calculator">(-2_691) + 450</gadget>
<output>-2_241</output>
<result>D</result> | D | -2,241 | -69*39+450=? | {
"A": "2736",
"B": "2309",
"C": "- 2801",
"D": "- 2241",
"E": "none of these"
} | add(multiply(negate(69), 39), 450) | negate(n0)|multiply(n1,#0)|add(n2,#1)| | "= > - 69 * ( 40 - 1 ) + 450 ; = > - ( 69 * 40 ) + 69 + 450 ; = > - 2760 + 519 = - 2241 . correct option : d" | general |
math_qa__vejEFL1snGqgprWl | Two pipes A and B can separately fill a cistern in 45 minutes and 60 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 40 minutes. In how much time, the third pipe alone can empty the cistern? Choices:
A) 90 min
B) 100 min
C) 72 min
D) 75 min
E) 130 min | <gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/45) + (1/60)</gadget>
<output>7/180 = around 0.038889</output>
<gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(7/180) - (1/40)</gadget>
<output>1/72 = around 0.013889</output>
<gadget id="calculator">1 / (1/72)</gadget>
<output>72</output>
<result>C</result> | C | 72 | Two pipes A and B can separately fill a cistern in 45 minutes and 60 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 40 minutes. In how much time, the third pipe alone can empty the cistern? | {
"A": "90 min",
"B": "100 min",
"C": "72 min",
"D": "75 min",
"E": "130 min"
} | inverse(subtract(add(inverse(45), inverse(60)), inverse(40))) | inverse(n0)|inverse(n1)|inverse(n2)|add(#0,#1)|subtract(#3,#2)|inverse(#4)| | "1 / 40 - ( 1 / 45 + 1 / 60 ) = - 1 / 72 third pipe can empty in 72 minutes answer : c" | physics |
math_qa__iBUBCm5sxzrXQEK2 | A car takes 6 hours to cover a distance of 450 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Choose the correct choice: A) 60 B) 50 C) 40 D) 70 E) 65 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">450 / 9</gadget>
<output>50</output>
<result>B</result> | B | 50 | A car takes 6 hours to cover a distance of 450 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "60",
"B": "50",
"C": "40",
"D": "70",
"E": "65"
} | divide(450, divide(multiply(6, 3), 2)) | multiply(n0,n2)|divide(#0,n3)|divide(n1,#1)| | "time = 6 distance = 450 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 450 / 9 = 50 kmph answer b ." | physics |
math_qa__1gle3UaK8xAjuvkc | a letter lock consists of 3 rings each marked with 6 different letters . the number of distinct unsuccessful attempts to open the lock is at the most - . Select:
A) 216 B) 243 C) 215 D) 729 E) 728 | <gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">36 * 6</gadget>
<output>216</output>
<gadget id="calculator">216 - 1</gadget>
<output>215</output>
<result>C</result> | C | 215 | a letter lock consists of 3 rings each marked with 6 different letters . the number of distinct unsuccessful attempts to open the lock is at the most - . | {
"A": "216",
"B": "243",
"C": "215",
"D": "729",
"E": "728"
} | subtract(multiply(multiply(6, 6), 6), const_1) | multiply(n1,n1)|multiply(n1,#0)|subtract(#1,const_1) | since each ring consists of six different letters , the total number of attempts possible with the three rings is = 6 * 6 * 6 = 216 . of these attempts , one of them is a successful attempt . maximum number of unsuccessful attempts = 216 - 1 = 215 . answer : c | probability |
math_qa__DbVV5TXihXIdLxQl | Average of money that group of 4 friends pay for rent each month is $800.After one persons rent is increased by 16% the new mean is $850.What was original rent of friend whose rent is increased? Choose the correct choice from the following
A) 800 B) 900 C) 1000 D) 1100 E) 1250 | <gadget id="calculator">850 - 800</gadget>
<output>50</output>
<gadget id="calculator">50 * 4</gadget>
<output>200</output>
<gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">200 / (4/25)</gadget>
<output>1_250</output>
<result>E</result> | E | 1,250 | Average of money that group of 4 friends pay for rent each month is $800.After one persons rent is increased by 16% the new mean is $850.What was original rent of friend whose rent is increased? | {
"A": "800",
"B": "900",
"C": "1000",
"D": "1100",
"E": "1250"
} | divide(multiply(subtract(850, 800), 4), divide(16, const_100)) | divide(n2,const_100)|subtract(n3,n1)|multiply(n0,#1)|divide(#2,#0)| | "0.16 x = 4 ( 850 - 800 ) 0.16 x = 200 x = 1250 answer e" | general |
math_qa__boEoonafEPSX4m1P | A person started from point A to point B and returned back to A with a speed of 60 kmh. If the distance between A and B is 120km, calculate the time he travelled Choose the correct choice from the following: A) 4 hours B) 2 hours C) 3 hours D) 6 hours E) 5 hours | <gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">240 / 60</gadget>
<output>4</output>
<result>A</result> | A | 4 | A person started from point A to point B and returned back to A with a speed of 60 kmh. If the distance between A and B is 120km, calculate the time he travelled | {
"A": "4 hours",
"B": "2 hours",
"C": "3 hours",
"D": "6 hours",
"E": "5 hours"
} | divide(multiply(120, const_2), 60) | multiply(n1,const_2)|divide(#0,n0) | time = distance / speed total distance = ( from a - > b and from b - > a ) = 120 + 120 = 240 km speed = 60 kmh 240 / 60 = 4 answer : a | physics |
math_qa__NUiGRBT35H2enLAq | A meeting has to be conducted with 5 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together.
Choose the correct option
A) 6 B) 8 C) 10 D) 11 E) 15 | <gadget id="calculator">binomial(7, 5)</gadget>
<output>21</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">21 - 10</gadget>
<output>11</output>
<result>D</result> | D | 11 | A meeting has to be conducted with 5 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together. | {
"A": "6",
"B": "8",
"C": "10",
"D": "11",
"E": "15"
} | subtract(choose(7, 5), choose(subtract(7, 2), 2)) | choose(n1,n0)|subtract(n1,n2)|choose(#1,n2)|subtract(#0,#2)| | "the total number of ways to choose 5 managers is 7 c 5 = 21 we need to subtract the number of groups which include the two managers , which is 5 c 3 = 10 . 21 - 10 = 11 the answer is d ." | probability |
math_qa__RJ20tML7zdy1SrYc | On a Saturday night, each of the rooms at a certain motel was rented for either $50 or $60. If 10 of the rooms that were rented for $60 had instead been rented for $50, then the total rent the motel charged for that night would have been reduced by 25 percent. What was the total rent the motel actually charged for that night ? Select the correct option
A) $ 400
B) $ 800
C) $ 1,000
D) $ 1,600
E) $ 2,400 | <gadget id="calculator">60 - 50</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">100 / (1/4)</gadget>
<output>400</output>
<result>A</result> | A | 400 | On a Saturday night, each of the rooms at a certain motel was rented for either $50 or $60. If 10 of the rooms that were rented for $60 had instead been rented for $50, then the total rent the motel charged for that night would have been reduced by 25 percent. What was the total rent the motel actually charged for that night ? | {
"A": "$ 400",
"B": "$ 800",
"C": "$ 1,000",
"D": "$ 1,600",
"E": "$ 2,400"
} | divide(multiply(10, subtract(60, 50)), divide(25, const_100)) | divide(n5,const_100)|subtract(n1,n0)|multiply(n2,#1)|divide(#2,#0) | let total rent the motel charge for all rooms = x if 10 rooms that were rented for 60 $ had instead been rented for 50 $ , then total difference in prices = 10 $ * 10 = 100 $ total rent the motel charged would have been reduced by 25 % . 25 x = 100 = > x = 400 answer a | gain |
math_qa__uwVwWT8fbgL4tGu9 | if price of t.v set is reduced by 10%, then its sale increases by 85%, find net effect on sale value Pick: A) 44 B) 45 C) 46 D) 67 E) 48 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">100 + 85</gadget>
<output>185</output>
<gadget id="calculator">185 / 100</gadget>
<output>37/20 = around 1.85</output>
<gadget id="calculator">(9/10) * (37/20)</gadget>
<output>333/200 = around 1.665</output>
<gadget id="calculator">(333/200) - 1</gadget>
<output>133/200 = around 0.665</output>
<gadget id="calculator">(133/200) * 100</gadget>
<output>133/2 = around 66.5</output>
<result>D</result> | D | 67 | if price of t.v set is reduced by 10%, then its sale increases by 85%, find net effect on sale value | {
"A": "44",
"B": "45",
"C": "46",
"D": "67",
"E": "48"
} | multiply(subtract(multiply(divide(subtract(const_100, 10), const_100), divide(add(const_100, 85), const_100)), const_1), const_100) | add(n1,const_100)|subtract(const_100,n0)|divide(#1,const_100)|divide(#0,const_100)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100) | - a + b + ( ( - a ) ( b ) / 100 ) = - 10 + 85 + ( - 10 * 85 ) / 100 = - 10 + 85 - 8.5 = 67 answer : d | gain |
math_qa__W4L7dUABYOSwTStu | A retailer buys a radio for Rs 225. His overhead expenses are Rs 20. He sellis the radio for Rs 300. The profit percent of the retailer is Choose the correct choice.
A) 22.4 %
B) 50 %
C) 25 %
D) 52 %
E) none of these | <gadget id="calculator">225 + 20</gadget>
<output>245</output>
<gadget id="calculator">300 / 245</gadget>
<output>60/49 = around 1.22449</output>
<gadget id="calculator">(60/49) * 100</gadget>
<output>6_000/49 = around 122.44898</output>
<gadget id="calculator">(6_000/49) - 100</gadget>
<output>1_100/49 = around 22.44898</output>
<result>A</result> | A | 22.4 | A retailer buys a radio for Rs 225. His overhead expenses are Rs 20. He sellis the radio for Rs 300. The profit percent of the retailer is | {
"A": "22.4 %",
"B": "50 %",
"C": "25 %",
"D": "52 %",
"E": "none of these"
} | subtract(multiply(divide(300, add(225, 20)), const_100), const_100) | add(n0,n1)|divide(n2,#0)|multiply(#1,const_100)|subtract(#2,const_100)| | "explanation : cost price = ( 225 + 20 ) = 245 sell price = 300 gain = ( 55 / 245 ) * 100 = 22.4 % . answer : a" | gain |
math_qa__gMGYCsJOJbS2d2LX | Which number should replace both the asterisks in (* /18) x (*/162) = 1 ? Select the correct option: A) 27 B) 36 C) 54 D) 72 E) 90 | <gadget id="calculator">162 * 18</gadget>
<output>2_916</output>
<gadget id="calculator">2_916 ** (1/2)</gadget>
<output>54</output>
<result>C</result> | C | 54 | Which number should replace both the asterisks in (* /18) x (*/162) = 1 ? | {
"A": "27",
"B": "36",
"C": "54",
"D": "72",
"E": "90"
} | sqrt(multiply(162, 18)) | multiply(n0,n1)|sqrt(#0) | let ( y / 18 ) x ( y / 162 ) = 1 y ^ 2 = 18 x 162 = 18 x 18 x 9 y = ( 18 x 3 ) = 54 the answer is c . | general |
math_qa__CFOgikOTyWzadaPw | Anne bought doughnuts for a class breakfast party. She bought 5 chocolate doughnuts, 6 coconut doughnuts, and 11 jam-filled doughnuts. How many doughnuts did Anne buy in all? Choices:
A) 22 B) 36 C) 39 D) 21 E) 11 | <gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">11 + 11</gadget>
<output>22</output>
<result>A</result> | A | 22 | Anne bought doughnuts for a class breakfast party. She bought 5 chocolate doughnuts, 6 coconut doughnuts, and 11 jam-filled doughnuts. How many doughnuts did Anne buy in all? | {
"A": "22",
"B": "36",
"C": "39",
"D": "21",
"E": "11"
} | add(add(5, 6), 11) | add(n0,n1)|add(n2,#0)| | "add the numbers of doughnuts . 5 + 6 + 11 = 22 . answer is a ." | general |
math_qa__iKJ9oCATEeLzrTH4 | A man is walking at the rate of 10 km/hr crosses a bridge in 15 minutes. The length of the bridge is
Choose the most appropriate option: A) 1000 meters B) 1050 meters C) 1200 meters D) 1250 meters E) 2500 meters | <gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">10 * (1/4)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 1_000</gadget>
<output>2_500</output>
<result>E</result> | E | 2,500 | A man is walking at the rate of 10 km/hr crosses a bridge in 15 minutes. The length of the bridge is | {
"A": "1000 meters",
"B": "1050 meters",
"C": "1200 meters",
"D": "1250 meters",
"E": "2500 meters"
} | multiply(multiply(10, divide(15, const_60)), const_1000) | divide(n1,const_60)|multiply(n0,#0)|multiply(#1,const_1000)| | "explanation : we need to get the answer in meters . so we will first of change distance from km / hour to meter / sec by multiplying it with 5 / 18 and also change 15 minutes to seconds by multiplying it with 60 . speed = 10 â ˆ — 5 / 18 = 25 / 9 m / sec time = 15 â ˆ — 60 seconds = 900 seconds distance = time â ˆ — speed / distance = 25 / 9 â ˆ — 900 = 2500 meter option e" | gain |
math_qa__psls44ORf9ZzL35l | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 144° of the circle, what percentage of MegaTek employees are in manufacturing? Pick one
A) 20 % B) 25 % C) 30 % D) 40 % E) 72 % | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">144 / 360</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>D</result> | D | 40 | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 144° of the circle, what percentage of MegaTek employees are in manufacturing? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "40 %",
"E": "72 %"
} | multiply(divide(144, divide(const_3600, const_10)), const_100) | divide(const_3600,const_10)|divide(n0,#0)|multiply(#1,const_100)| | answer : d 144 ° divided by 360 ° equals 0.4 , therefore the sector is equal to 40 % of the total | physics |
math_qa__cPQ82MZunYWENBt4 | Gopi gives Rs. 90 plus one turban as salary to his servant for one year. The servant leaves after 9 months and receives Rs. 55 and the turban. Find the price of the turban.
Choose the most appropriate option:
A) 27 B) 36 C) 29 D) 50 E) 11 | <gadget id="calculator">90 - 55</gadget>
<output>35</output>
<gadget id="calculator">12 - 9</gadget>
<output>3</output>
<gadget id="calculator">35 / 3</gadget>
<output>35/3 = around 11.666667</output>
<gadget id="calculator">(35/3) * 12</gadget>
<output>140</output>
<gadget id="calculator">140 - 90</gadget>
<output>50</output>
<result>D</result> | D | 50 | Gopi gives Rs. 90 plus one turban as salary to his servant for one year. The servant leaves after 9 months and receives Rs. 55 and the turban. Find the price of the turban. | {
"A": "27",
"B": "36",
"C": "29",
"D": "50",
"E": "11"
} | subtract(multiply(divide(subtract(90, 55), subtract(const_12, 9)), const_12), 90) | subtract(n0,n2)|subtract(const_12,n1)|divide(#0,#1)|multiply(#2,const_12)|subtract(#3,n0) | let the price of turban be x . thus , for one year the salary = ( 90 + x ) for 9 months he should earn 3434 ( 90 + x ) . now he gets one turban and rs . 55 . thus , 3434 ( 90 + x ) = 55 + x or 270 + 3 x = 220 + 4 x or x = 50 answer : d | general |
math_qa__VnOs0XGmS6U1nds8 | Before leaving home for the town of Madison, Pete checks a map which shows that Madison is 5 inches from his current location, Gardensquare. Pete arrives in Madison 1.5 hours later and drove at an average speed of 60 miles per hour. At what scale, in inches per mile, is the map drawn?
Choose the correct choice from the following:
A) 1 / 3 B) 1 / 18 C) 1 / 10 D) 2 E) 30 | <gadget id="calculator">1.5 / 5</gadget>
<output>0.3</output>
<gadget id="calculator">0.3 * 60</gadget>
<output>18</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<result>B</result> | B | 0.055556 | Before leaving home for the town of Madison, Pete checks a map which shows that Madison is 5 inches from his current location, Gardensquare. Pete arrives in Madison 1.5 hours later and drove at an average speed of 60 miles per hour. At what scale, in inches per mile, is the map drawn? | {
"A": "1 / 3",
"B": "1 / 18",
"C": "1 / 10",
"D": "2",
"E": "30"
} | divide(const_1, multiply(divide(1.5, 5), 60)) | divide(n1,n0)|multiply(#0,n2)|divide(const_1,#1)| | "pete covered 1.5 * 60 = 90 miles which correspond to 5 inches on the map - - > scale in inches per mile is 5 / 90 = 1 / 18 . answer : b ." | physics |
math_qa__CQfCngaAms0qCQ4S | The average of 50 numbers is 38. If two numbers 45 and 55 are discarded, the average of the remaining set of numbers is
Choose the correct option: A) 38.5 B) 37.5 C) 37.0 D) 36.5 E) none of these | <gadget id="calculator">50 * 38</gadget>
<output>1_900</output>
<gadget id="calculator">1_900 - 45</gadget>
<output>1_855</output>
<gadget id="calculator">1_855 - 55</gadget>
<output>1_800</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">1_800 / 48</gadget>
<output>75/2 = around 37.5</output>
<result>B</result> | B | 37.5 | The average of 50 numbers is 38. If two numbers 45 and 55 are discarded, the average of the remaining set of numbers is | {
"A": "38.5",
"B": "37.5",
"C": "37.0",
"D": "36.5",
"E": "none of these"
} | divide(subtract(subtract(multiply(50, 38), 45), 55), subtract(50, const_2)) | multiply(n0,n1)|subtract(n0,const_2)|subtract(#0,n2)|subtract(#2,n3)|divide(#3,#1) | average of the remaining set of numbers [ 50 x 38 - ( 45 + 55 ) ] / ( 50 - 2 ) = ( 1900 - 100 ) / 48 = 37.5 answer : b | general |
math_qa__FEJR7CvoHWNHUnem | I bought two books; for Rs.420. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss? Choose one.
A) 197 B) 245 C) 189 D) 278 E) 268 | <gadget id="calculator">100 + 19</gadget>
<output>119</output>
<gadget id="calculator">420 * 119</gadget>
<output>49_980</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 + 119</gadget>
<output>204</output>
<gadget id="calculator">49_980 / 204</gadget>
<output>245</output>
<result>B</result> | B | 245 | I bought two books; for Rs.420. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss? | {
"A": "197",
"B": "245",
"C": "189",
"D": "278",
"E": "268"
} | divide(multiply(420, add(const_100, 19)), add(subtract(const_100, 15), add(const_100, 19))) | add(n2,const_100)|subtract(const_100,n1)|add(#0,#1)|multiply(n0,#0)|divide(#3,#2)| | "x * ( 85 / 100 ) = ( 420 - x ) 119 / 100 x = 245 answer : b" | gain |
math_qa__5Pq17G8L16p5zqzg | The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 28 years. The ratio of their ages after 6 years will be Choose the correct choice: A) 2 : 3 B) 7 : 11 C) 5 : 4 D) 4 : 5 E) 11 : 9 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">28 / 7</gadget>
<output>4</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 + 6</gadget>
<output>22</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 6</gadget>
<output>18</output>
<gadget id="calculator">22 / 18</gadget>
<output>11/9 = around 1.222222</output>
<result>E</result> | E | 1.222222 | The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 28 years. The ratio of their ages after 6 years will be | {
"A": "2 : 3",
"B": "7 : 11",
"C": "5 : 4",
"D": "4 : 5",
"E": "11 : 9"
} | divide(add(multiply(4, divide(28, add(4, 3))), 6), add(multiply(3, divide(28, add(4, 3))), 6)) | add(n0,n1)|divide(n2,#0)|multiply(n0,#1)|multiply(n1,#1)|add(n3,#2)|add(n3,#3)|divide(#4,#5)| | "let mini ’ s age = 4 x and minakshi ’ s age = 3 x then 4 x + 3 x = 28 x = 4 mini ’ s age = 16 years and minakshi ’ s age = 12 years ratio of their ages after 8 years = ( 16 + 6 ) : ( 12 + 6 ) = 22 : 18 = 11 : 9 answer : e" | general |
math_qa__xWF1GYMtXPGnSCPG | If the price of petrol increases by 20, by how much must a user cut down his consumption so that his expenditure on petrol remains constant? Choose the most appropriate option: A) 16.7 % B) 20 % C) 24.67 % D) 33.33 % E) none of these | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 / 120</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">1 - (5/6)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 100</gadget>
<output>50/3 = around 16.666667</output>
<result>A</result> | A | 16.7 | If the price of petrol increases by 20, by how much must a user cut down his consumption so that his expenditure on petrol remains constant? | {
"A": "16.7 %",
"B": "20 %",
"C": "24.67 %",
"D": "33.33 %",
"E": "none of these"
} | multiply(subtract(const_1, divide(const_100, add(const_100, 20))), const_100) | add(n0,const_100)|divide(const_100,#0)|subtract(const_1,#1)|multiply(#2,const_100)| | "explanation : let us assume before increase the petrol will be rs . 100 . after increase it will be rs ( 100 + 20 ) i . e 120 . now , his consumption should be reduced to : - = ( 120 − 100 ) / 120 ∗ 100 . hence , the consumption should be reduced to 16.7 % . answer : a" | general |
math_qa__esnB5MvhxMxE3cri | Thirty percent of the women in a college class are science majors, and the non-science majors make up 60% of the class. What percentage of the men are science majors if 40% of the class are men? Choose the correct choice from the following answers.
A) 35 % B) 45 % C) 55 % D) 65 % E) 75 % | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">(3/10) * 60</gadget>
<output>18</output>
<gadget id="calculator">40 - 18</gadget>
<output>22</output>
<gadget id="calculator">22 / 40</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">(11/20) * 100</gadget>
<output>55</output>
<result>C</result> | C | 55 | Thirty percent of the women in a college class are science majors, and the non-science majors make up 60% of the class. What percentage of the men are science majors if 40% of the class are men? | {
"A": "35 %",
"B": "45 %",
"C": "55 %",
"D": "65 %",
"E": "75 %"
} | multiply(divide(subtract(subtract(const_100, 60), multiply(divide(multiply(const_10, const_3), const_100), subtract(const_100, 40))), 40), const_100) | multiply(const_10,const_3)|subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,const_100)|multiply(#3,#2)|subtract(#1,#4)|divide(#5,n1)|multiply(#6,const_100) | science majors make up 0.4 of the class . 60 % of the class are women and 0.3 * 0.6 = 0.18 of the class are female science majors . then 0.22 of the class are male science majors . 0.4 x = 0.22 x = 0.55 = 55 % the answer is c . | gain |
math_qa__S01qnYIcZjBzWvmr | a cargo ship carrying 4 kinds of items , doohickies , geegaws , widgets , and yamyams , arrives at the port . each item weighs 2 , 11 , 5 , and 7 pounds , respectively , and each item is weighed as it is unloaded . if , in the middle of the unloading process , the product of the individual weights of the unloaded items equals 104 , 350400 pounds , how many widgets have been unloaded ? Choices:
A) 2 B) 3 C) 4 D) 25 E) 20 , 870,080 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<result>A</result> | A | 2 | a cargo ship carrying 4 kinds of items , doohickies , geegaws , widgets , and yamyams , arrives at the port . each item weighs 2 , 11 , 5 , and 7 pounds , respectively , and each item is weighed as it is unloaded . if , in the middle of the unloading process , the product of the individual weights of the unloaded items equals 104 , 350400 pounds , how many widgets have been unloaded ? | {
"A": "2",
"B": "3",
"C": "4",
"D": "25",
"E": "20 , 870,080"
} | add(const_1, const_1) | add(const_1,const_1) | we need to know the number of widgets ( which weigh 5 pounds each ) . the number of times that 5 divides the number is related to the number of times that 10 divides the number . when we divide 104 , 350,400 by 100 , we get 104 , 350,400 = 1 , 043,504 * 5 ^ 2 * 2 ^ 2 . 1 , 043,504 is not divisible by 5 , thus there are 2 widgets . the answer is a . | general |
math_qa__v0xZVpZmUmbvmrru | What is the sum of all the composite numbers up to 18?
Choose the correct option
A) 228
B) 112
C) 80
D) 96
E) 100 | <gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">14 + 1</gadget>
<output>15</output>
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">10 + 9</gadget>
<output>19</output>
<gadget id="calculator">19 + 10</gadget>
<output>29</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">29 + 12</gadget>
<output>41</output>
<gadget id="calculator">14 + 41</gadget>
<output>55</output>
<gadget id="calculator">15 + 55</gadget>
<output>70</output>
<gadget id="calculator">15 + 1</gadget>
<output>16</output>
<gadget id="calculator">70 + 16</gadget>
<output>86</output>
<gadget id="calculator">86 + 18</gadget>
<output>104</output>
<gadget id="calculator">104 + 6</gadget>
<output>110</output>
<result>B</result> | B | 112 | What is the sum of all the composite numbers up to 18? | {
"A": "228",
"B": "112",
"C": "80",
"D": "96",
"E": "100"
} | add(add(add(add(add(add(const_12, const_2), const_1), add(add(const_12, const_2), add(add(add(add(add(const_2, const_4), const_4), subtract(const_10, const_1)), add(add(const_2, const_4), const_4)), add(const_10, const_2)))), add(add(add(const_12, const_2), const_1), const_1)), 18), add(const_2, const_4)) | add(const_12,const_2)|add(const_2,const_4)|add(const_10,const_2)|subtract(const_10,const_1)|add(#0,const_1)|add(#1,const_4)|add(#5,#3)|add(#4,const_1)|add(#6,#5)|add(#8,#2)|add(#0,#9)|add(#4,#10)|add(#11,#7)|add(n0,#12)|add(#13,#1) | explanation : 4 + 6 + 8 + 9 + 10 + 12 + 14 + 15 + 16 + 18 = 112 answer : b | general |
math_qa__xkvtRWHmzL2EaLUl | In measuring the sides of a rectangle, one side is taken 5% in excess, and the other 4% in deficit. Find the error percent in the area calculated from these measurements. Choose the correct choice.
A) 0.2 % B) 0.4 % C) 0.6 % D) 0.8 % E) 1 % | <gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<result>D</result> | D | 0.8 | In measuring the sides of a rectangle, one side is taken 5% in excess, and the other 4% in deficit. Find the error percent in the area calculated from these measurements. | {
"A": "0.2 %",
"B": "0.4 %",
"C": "0.6 %",
"D": "0.8 %",
"E": "1 %"
} | subtract(subtract(5, 4), divide(multiply(5, 4), const_100)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,const_100)|subtract(#1,#2)| | "let x and y be the sides of the rectangle . then , correct area = xy . calculated area = ( 105 / 100 ) * x * ( 96 / 100 ) * y = ( 504 / 500 ) ( xy ) error in measurement = ( 504 / 500 ) xy - xy = ( 4 / 500 ) xy error % = [ ( 4 / 500 ) xy * ( 1 / xy ) * 100 ] % = ( 4 / 5 ) % = 0.8 % . answer d 0.8 %" | geometry |
math_qa__3KZocn3Uf8MvkH6X | A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability G that the first ball picked up is odd numbered? Choose the correct choice from the following answers.
A) 0 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 1 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<result>D</result> | D | 0.666667 | A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability G that the first ball picked up is odd numbered? | {
"A": "0",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "1"
} | divide(const_2, 3) | divide(const_2,n3)| | "answer - d selecting the balls either even or odd is having probability 50 / 100 = 1 / 2 we have already selected 3 balls with 2 odd numbers and 1 even number . so we have 3 combinations ooe , oeo , eoo . we have 3 outcomes and 2 are favourable as in 2 cases 1 st number is odd . so probability g is 2 / 3 . d" | probability |
math_qa__xFW0ywWNrs7R1KUn | Bert left the house with N dollars. He spent 1/4 of this at the hardware store, then $9 at the dry cleaners, and then half of what was left at the grocery store. When he got home, he had $15 left in his pocket. What was the value of N?
Pick one: A) $ 36 B) $ 44 C) $ 52 D) $ 60 E) $ 68 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / (3/4)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(9/2) + 15</gadget>
<output>39/2 = around 19.5</output>
<gadget id="calculator">(4/3) * (39/2)</gadget>
<output>26</output>
<gadget id="calculator">26 * 2</gadget>
<output>52</output>
<result>C</result> | C | 52 | Bert left the house with N dollars. He spent 1/4 of this at the hardware store, then $9 at the dry cleaners, and then half of what was left at the grocery store. When he got home, he had $15 left in his pocket. What was the value of N? | {
"A": "$ 36",
"B": "$ 44",
"C": "$ 52",
"D": "$ 60",
"E": "$ 68"
} | multiply(multiply(inverse(subtract(1, divide(1, 4))), add(divide(9, const_2), 15)), const_2) | divide(n2,const_2)|divide(n0,n1)|add(n3,#0)|subtract(n0,#1)|inverse(#3)|multiply(#2,#4)|multiply(#5,const_2) | started to test answer c if he had 52 , then he spent 13 at hardware store now he was left with 39 $ he spent 9 dollars on cleaning , thus he remained with 30 $ he then spent 1 / 2 of 30 , or 15 , and was left with 15 . hence , the only option that can be right is c . | general |
math_qa__twNPP1zeLvU6aC5n | a company has $ 329864 in its account . what is the least amount of money ( in whole number of dollars ) that it must add to the account if the money is paid evenly among 9 of its vendors ? Choose the most appropriate option
A) $ 1 B) $ 2 C) $ 3 D) $ 4 E) $ 6 | <gadget id="calculator">329_864 % 9</gadget>
<output>5</output>
<gadget id="calculator">9 - 5</gadget>
<output>4</output>
<result>D</result> | D | 4 | a company has $ 329864 in its account . what is the least amount of money ( in whole number of dollars ) that it must add to the account if the money is paid evenly among 9 of its vendors ? | {
"A": "$ 1",
"B": "$ 2",
"C": "$ 3",
"D": "$ 4",
"E": "$ 6"
} | subtract(9, reminder(329864, 9)) | reminder(n0,n1)|subtract(n1,#0) | to find the least amount that must be added to the account to split the money evenly among 9 of its vendors , the total divisible by 9 simply add the individual digits of the total = 3 + 2 + 9 + 8 + 6 + 4 = 32 if you add 4 , the number is divisible by 9 ( 32 + 4 ) correct option : d | general |
math_qa__yDR179dHMCmkmZdY | An escalator moves towards the top level at the rate of 10 ft.sec and its length is 112 feet. If a person walks on the moving escalator at the rate of 4 feet per second towards the top level, how much time does he take to cover the entire length. Answers
A) 14 sec
B) 10 sec
C) 12 sec
D) 8 sec
E) 9 sec | <gadget id="calculator">10 + 4</gadget>
<output>14</output>
<gadget id="calculator">112 / 14</gadget>
<output>8</output>
<result>D</result> | D | 8 | An escalator moves towards the top level at the rate of 10 ft.sec and its length is 112 feet. If a person walks on the moving escalator at the rate of 4 feet per second towards the top level, how much time does he take to cover the entire length. | {
"A": "14 sec",
"B": "10 sec",
"C": "12 sec",
"D": "8 sec",
"E": "9 sec"
} | divide(112, add(10, 4)) | add(n0,n2)|divide(n1,#0)| | "time taken to cover the entire length = tot . dist / resultant speed = 112 / ( 10 + 4 ) = 8 sec answer : d" | gain |
math_qa__4OTfaBUHdpcD9KaD | What is the total surface area in square meters of a rectangular solid whose length is 5 meters, width is 4 meters, and depth is 1 meters? Choices: A) 48 m 2 B) 40 m 2 C) 50 m 2 D) 58 m 2 E) 62 m 2 | <gadget id="calculator">2 * (4 * 5 + 5 * 1 + 4 * 1)</gadget>
<output>58</output>
<result>D</result> | D | 58 | What is the total surface area in square meters of a rectangular solid whose length is 5 meters, width is 4 meters, and depth is 1 meters? | {
"A": "48 m 2",
"B": "40 m 2",
"C": "50 m 2",
"D": "58 m 2",
"E": "62 m 2"
} | surface_rectangular_prism(4, 5, 1) | surface_rectangular_prism(n0,n1,n2)| | "surface area of a cuboid = 2 ( lb + bh + lh ) = 2 ( 5 * 4 + 4 * 1 + 5 * 1 ) = 2 ( 20 + 4 + 5 ) = 2 * 29 = 58 m 2 answer : d" | geometry |
math_qa__O5zp0LZUrigBCxFb | In a group of ducks and cows, the total number of legs are 34 more than twice the no. of heads. Find the total no.of buffaloes. Select: A) 11 B) 12 C) 14 D) 17 E) 18 | <gadget id="calculator">34 / 2</gadget>
<output>17</output>
<result>D</result> | D | 17 | In a group of ducks and cows, the total number of legs are 34 more than twice the no. of heads. Find the total no.of buffaloes. | {
"A": "11",
"B": "12",
"C": "14",
"D": "17",
"E": "18"
} | divide(34, const_2) | divide(n0,const_2)| | "let the number of buffaloes be x and the number of ducks be y = > 4 x + 2 y = 2 ( x + y ) + 34 = > 2 x = 34 = > x = 17 d" | general |
math_qa__FkFBpxPWTPYNAEpV | In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 63 as quotient. What is the correct quotient ?
Choose the correct answer.
A) 0 B) 36 C) 13 D) 20 E) 25 | <gadget id="calculator">12 * 63</gadget>
<output>756</output>
<gadget id="calculator">756 / 21</gadget>
<output>36</output>
<result>B</result> | B | 36 | In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 63 as quotient. What is the correct quotient ? | {
"A": "0",
"B": "36",
"C": "13",
"D": "20",
"E": "25"
} | divide(multiply(12, 63), 21) | multiply(n1,n3)|divide(#0,n2)| | "12 * 63 = 756 756 % 21 = 36 answer : b" | general |
math_qa__yOjwESZwui9zFiL4 | A cube is painted red on all faces. It is then cut into 27 equal smaller cubes. How many V cubes are painted on only 2 faces?
Options
A) 12 B) 8 C) 6 D) 10 E) 16 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">27 ** (1/3)</gadget>
<output>3</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<result>A</result> | A | 12 | A cube is painted red on all faces. It is then cut into 27 equal smaller cubes. How many V cubes are painted on only 2 faces? | {
"A": "12",
"B": "8",
"C": "6",
"D": "10",
"E": "16"
} | multiply(const_4, power(27, divide(const_1, const_3))) | divide(const_1,const_3)|power(n0,#0)|multiply(#1,const_4)| | "1 ) draw a simple cube 2 ) draw 9 squares on each face of the cube ( so that it looks like a rubik ' s cube ) - this is what the cube will look like when it ' s cut into 27 equal smaller cubes . 3 ) remember that the outside of the cube is the part that ' s painted . . . . the mini - cubes with 2 painted sides are all on the edge of the cube , in themiddleof the edge . there are 4 in front , 4 in back and 4 more on thestripthat runs around the left / top / right / bottom of the cube . v = 4 + 4 + 4 = 12 . answer a" | geometry |
math_qa__SZ5oizQTGUm7It3R | A tank can supply water to a village for 30 days. If a leak at the bottom of the tank drains out 15 liters per day, the supply lasts for 20 days only. For how many days will the supply last if the leak drains out 20 liters per day?
Pick one: A) 12 B) 14 C) 15 D) 16 E) 18 | <gadget id="calculator">15 * 20</gadget>
<output>300</output>
<gadget id="calculator">30 - 20</gadget>
<output>10</output>
<gadget id="calculator">300 / 10</gadget>
<output>30</output>
<gadget id="calculator">30 * 30</gadget>
<output>900</output>
<gadget id="calculator">20 + 30</gadget>
<output>50</output>
<gadget id="calculator">900 / 50</gadget>
<output>18</output>
<result>E</result> | E | 18 | A tank can supply water to a village for 30 days. If a leak at the bottom of the tank drains out 15 liters per day, the supply lasts for 20 days only. For how many days will the supply last if the leak drains out 20 liters per day? | {
"A": "12",
"B": "14",
"C": "15",
"D": "16",
"E": "18"
} | divide(multiply(divide(multiply(15, 20), subtract(30, 20)), 30), add(20, divide(multiply(15, 20), subtract(30, 20)))) | multiply(n1,n2)|subtract(n0,n2)|divide(#0,#1)|add(n3,#2)|multiply(n0,#2)|divide(#4,#3)| | "losing 15 liters per day results in a loss of 300 liters in 20 days . so , those 300 liters were for 10 days , making daily consumption of the village 30 liters per day . thus the capacity of the tank is 30 * 30 = 900 liters . losing 20 liters plus 30 liters gives 50 liters per day . at this rate the supply will last 900 / 50 = 18 days . the answer is e ." | physics |
math_qa__Y2O53n0ejBhU3nhx | How many times in a day, the hands of a clock are shows opposite directions ?
Choose the correct choice from the following answers
A) 12 B) 20 C) 21 D) 23 E) 22 | <gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">2 * 24</gadget>
<output>48</output>
<gadget id="calculator">48 - 4</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<result>E</result> | E | 22 | How many times in a day, the hands of a clock are shows opposite directions ? | {
"A": "12",
"B": "20",
"C": "21",
"D": "23",
"E": "22"
} | divide(subtract(multiply(const_2, multiply(const_2, const_12)), const_4), const_2) | multiply(const_12,const_2)|multiply(#0,const_2)|subtract(#1,const_4)|divide(#2,const_2)| | "sol . in 12 hours , the hands coincide or are in opposite direction 11 times . â ˆ ´ in 24 hours , the hands coincide or are in opposite direction 22 times a day . ( between 5 and 7 they point in opposite directions at 6 o ' clock only ) answer e" | physics |
math_qa__7HqERYRT3PUTpxbb | The difference between a positive proper fraction and its reciprocal is 9 / 20. Then the fraction is :
Choose the correct choice from the following answers.
A) 4 / 0 B) 4 / 1 C) 4 / 5 D) 4 / 2 E) 4 / 3 | <gadget id="calculator">9 - 4</gadget>
<output>5</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<result>C</result> | C | 0.8 | The difference between a positive proper fraction and its reciprocal is 9 / 20. Then the fraction is : | {
"A": "4 / 0",
"B": "4 / 1",
"C": "4 / 5",
"D": "4 / 2",
"E": "4 / 3"
} | divide(const_4, subtract(9, const_4)) | subtract(n0,const_4)|divide(const_4,#0)| | "explanation : let the required fraction be x . then , ( 1 / x ) - x = 9 / 20 1 - x ^ ( 2 ) / x = 9 / 20 = > 20 - 20 * x ^ ( 2 ) = 9 * x . 20 * x ^ ( 2 ) + 9 * x - 20 = 0 . = > ( 4 * x + 5 ) ( 5 * x - 4 ) = 0 . = > x = 4 / 5 . answer : c ) 4 / 5" | general |
math_qa__pqd4o2MhaxS07d94 | A sum of money is to be distributed among A, B, C, D in the proportion of 6 : 3 : 5 : 4. If C gets Rs. 1000 more than D, what is B's share? Options
A) 1500 B) 2000 C) 2500 D) 2800 E) 3000 | <gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">1 * 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 3</gadget>
<output>3_000</output>
<result>E</result> | E | 3,000 | A sum of money is to be distributed among A, B, C, D in the proportion of 6 : 3 : 5 : 4. If C gets Rs. 1000 more than D, what is B's share? | {
"A": "1500",
"B": "2000",
"C": "2500",
"D": "2800",
"E": "3000"
} | multiply(multiply(subtract(5, 4), 1000), const_3.0) | subtract(n2,n3)|multiply(n4,#0)|multiply(const_3.0,#1)| | "let the shares of a , b , c and d be rs . 5 x , rs . 3 x , rs . 5 x and rs . 4 x respectively . then , 5 x - 4 x = 1000 x = 1000 . b ' s share = rs . 3 x = rs . ( 3 x 1000 ) = rs . 3000 . answer : e" | general |
math_qa__PEkNgEuyYRleAdba | A sports equipment store sold ping pong rackets for a total of $686. If the average (arithmetic mean) price of a pair of rackets is $9.8, how many pairs were sold?
Choose the correct choice from the following options
A) 50 B) 100 C) 70 D) 500 E) 980 | <gadget id="calculator">686 / 9.8</gadget>
<output>70</output>
<result>C</result> | C | 70 | A sports equipment store sold ping pong rackets for a total of $686. If the average (arithmetic mean) price of a pair of rackets is $9.8, how many pairs were sold? | {
"A": "50",
"B": "100",
"C": "70",
"D": "500",
"E": "980"
} | divide(686, 9.8) | divide(n0,n1) | average price for a pair of rackets = $ 9.8 total cost = $ 9.8 * x = $ 686 x = 70 pairs were sold . answer : c | general |
math_qa__u0otsBFfHZqHyONH | The average weight of 8 person's increases by 3.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? Options
A) kg B) 70 kg C) 80 kg D) 90 kg E) 93 kg | <gadget id="calculator">8 * 3.5</gadget>
<output>28</output>
<gadget id="calculator">28 + 65</gadget>
<output>93</output>
<result>E</result> | E | 93 | The average weight of 8 person's increases by 3.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? | {
"A": "kg",
"B": "70 kg",
"C": "80 kg",
"D": "90 kg",
"E": "93 kg"
} | add(multiply(8, 3.5), 65) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 8 x 3.5 ) kg = 28 kg . weight of new person = ( 65 + 28 ) kg = 93 kg . e )" | general |
math_qa__o989ldwpID79YAkX | If xy > 0, 1/x + 1/y = 15, and 1/xy = 5, then (x+y)/5 = ? Select.
A) 1 / 25 B) 1 / 6 C) 3 / 5 D) 5 E) 6 | <gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<result>C</result> | C | 0.6 | If xy > 0, 1/x + 1/y = 15, and 1/xy = 5, then (x+y)/5 = ? | {
"A": "1 / 25",
"B": "1 / 6",
"C": "3 / 5",
"D": "5",
"E": "6"
} | divide(divide(15, 5), 5) | divide(n3,n5)|divide(#0,n5) | ( 1 / x + 1 / y ) = 15 canbe solved as { ( x + y ) / xy } = 5 . substituting for 1 / xy = 5 , we get x + y = 15 / 5 = = > ( x + y ) / 5 = 15 / ( 5 * 5 ) = 3 / 5 . c | general |
math_qa__2goAhCKUfayjNc5h | A bookseller sells his books at a 10% markup in price. If he sells a book for $11.00, how much did he pay for it? Select the correct option: A) $ 14.40 B) $ 14.00 C) $ 10.00 D) $ 9.60 E) $ 5.00 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 11</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">11 - (11/10)</gadget>
<output>99/10 = around 9.9</output>
<result>C</result> | C | 10 | A bookseller sells his books at a 10% markup in price. If he sells a book for $11.00, how much did he pay for it? | {
"A": "$ 14.40",
"B": "$ 14.00",
"C": "$ 10.00",
"D": "$ 9.60",
"E": "$ 5.00"
} | subtract(11.00, multiply(divide(10, const_100), 11.00)) | divide(n0,const_100)|multiply(n1,#0)|subtract(n1,#1)| | "let the cost price of book = x selling price of book = 11 $ markup % = 10 ( 110 / 100 ) x = 11 = > x = 10 answer c" | gain |
math_qa__a17rfT0FY74sEBqU | There are 60 doors marked with numbers 1 to 60. There are 60 individuals marked 1 to 60.
An operation on a door is defined as changing the status of the door from open to closed or vice versa. All the doors are closed to start with. One at a time, one randomly chosen individual goes and operates the doors. The individual however operates only those doors which are a multiple of the number he/she is carrying. For example, the individual marked with number 5 operates the doors marked with 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, and 60. If every individual in the group gets one turn, then how many doors are open at the end? Select:
A) 0 B) 2 C) 5 D) 7 E) 9 | <gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<result>D</result> | D | 7 | There are 60 doors marked with numbers 1 to 60. There are 60 individuals marked 1 to 60.
An operation on a door is defined as changing the status of the door from open to closed or vice versa. All the doors are closed to start with. One at a time, one randomly chosen individual goes and operates the doors. The individual however operates only those doors which are a multiple of the number he/she is carrying. For example, the individual marked with number 5 operates the doors marked with 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, and 60. If every individual in the group gets one turn, then how many doors are open at the end? | {
"A": "0",
"B": "2",
"C": "5",
"D": "7",
"E": "9"
} | add(divide(60, const_10), 1) | divide(n0,const_10)|add(n1,#0) | if a door is closed at the start , it requires an odd number of people to operate to be open at the end . only the perfect squares have an odd number of factors . the doors which are open at the end are : 1 , 4 , 9 , 16 , 25 , 36 , 49 for a total of 7 doors . the answer is d . | general |
math_qa__C5KpCUzo4DmIDRZk | The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.0 cm. What is the area of the triangle? Select the correct option:
A) 28 cm 2 B) 27 cm 2 C) 29 cm 2 D) 25 cm 2 E) 35 cm 2 | <gadget id="calculator">(2 * 28) / 2</gadget>
<output>28</output>
<result>A</result> | A | 28 | The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.0 cm. What is the area of the triangle? | {
"A": "28 cm 2",
"B": "27 cm 2",
"C": "29 cm 2",
"D": "25 cm 2",
"E": "35 cm 2"
} | triangle_area(2.0, 28) | triangle_area(n0,n1)| | "area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 2.0 * 28 / 2 = 28 cm 2 answer : a" | geometry |
math_qa__qnqrcYHcSvAWGeS9 | Due to construction, the speed limit along an 9-mile section of highway is reduced from 55 miles per hour to 20 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ? Pick.
A) 5.61
B) 8
C) 10
D) 17.19
E) 24 | <gadget id="calculator">55 + 9</gadget>
<output>64</output>
<gadget id="calculator">64 - 1</gadget>
<output>63</output>
<gadget id="calculator">9 / 20</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">9 / 55</gadget>
<output>9/55 = around 0.163636</output>
<gadget id="calculator">(9/20) - (9/55)</gadget>
<output>63/220 = around 0.286364</output>
<gadget id="calculator">63 * (63/220)</gadget>
<output>3_969/220 = around 18.040909</output>
<gadget id="calculator">max(3_969/220, 4)</gadget>
<output>3_969/220 = around 18.040909</output>
<result>D</result> | D | 17.19 | Due to construction, the speed limit along an 9-mile section of highway is reduced from 55 miles per hour to 20 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ? | {
"A": "5.61",
"B": "8",
"C": "10",
"D": "17.19",
"E": "24"
} | max(multiply(subtract(add(55, 9), const_1), subtract(divide(9, 20), divide(9, 55))), const_4) | add(n0,n1)|divide(n0,n2)|divide(n0,n1)|subtract(#0,const_1)|subtract(#1,#2)|multiply(#3,#4)|max(#5,const_4)| | "old time in minutes to cross 9 miles stretch = 9 * 60 / 55 = 9 * 12 / 11 = 9.81 new time in minutes to cross 9 miles stretch = 9 * 60 / 20 = 9 * 3 / 1 = 27 time difference = 17.19 ans : d" | physics |
math_qa__wKkXhQBAL3Iso8Cr | The area of a triangle will be when a = 1m, b = 2m, c = 7m, a, b, c being lengths of respective sides? Choose the correct choice: A) 3 B) 6 C) 5 D) 9 E) 1 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 7</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>C</result> | C | 5 | The area of a triangle will be when a = 1m, b = 2m, c = 7m, a, b, c being lengths of respective sides? | {
"A": "3",
"B": "6",
"C": "5",
"D": "9",
"E": "1"
} | divide(add(add(1, 2), 7), 2) | add(n0,n1)|add(n2,#0)|divide(#1,n1)| | s = ( 1 + 2 + 7 ) / 2 = 5 answer : c | geometry |
math_qa__OFYp9CEmS4YRVogH | A train 125m long takes 6 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train? Choose the correct choice from the following
A) 65 kmph B) 70 kmph C) 75 kmph D) 80 kmph E) 85 kmph | <gadget id="calculator">125 / 6</gadget>
<output>125/6 = around 20.833333</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(125/6) / (5/18)</gadget>
<output>75</output>
<gadget id="calculator">75 - 5</gadget>
<output>70</output>
<result>B</result> | B | 70 | A train 125m long takes 6 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train? | {
"A": "65 kmph",
"B": "70 kmph",
"C": "75 kmph",
"D": "80 kmph",
"E": "85 kmph"
} | subtract(divide(divide(125, 6), const_0_2778), 5) | divide(n0,n1)|divide(#0,const_0_2778)|subtract(#1,n2)| | "let the speed of the train be x kmph speed of the train relative to man = x + 5 = ( x + 5 ) * 5 / 18 m / sec 125 / [ ( x + 5 ) * 5 / 18 ] = 6 30 ( x + 5 ) = 2250 x = 70 kmph answer is b" | physics |
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