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stringlengths 7
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math_qa__179uk9MXWU9dITEB | In one alloy there is 15% chromium while in another alloy it is 8%. 15 kg of the first alloy was melted together with 35 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy. Choices
A) 8.8 % B) 9 % C) 10.1 % D) 8.6 % E) 8.4 % | <gadget id="calculator">15 * 15</gadget>
<output>225</output>
<gadget id="calculator">225 / 100</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">8 * 35</gadget>
<output>280</output>
<gadget id="calculator">280 / 100</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">(9/4) + (14/5)</gadget>
<output>101/20 = around 5.05</output>
<gadget id="calculator">15 + 35</gadget>
<output>50</output>
<gadget id="calculator">(101/20) / 50</gadget>
<output>101/1_000 = around 0.101</output>
<gadget id="calculator">(101/1_000) * 100</gadget>
<output>101/10 = around 10.1</output>
<result>C</result> | C | 10.1 | In one alloy there is 15% chromium while in another alloy it is 8%. 15 kg of the first alloy was melted together with 35 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy. | {
"A": "8.8 %",
"B": "9 %",
"C": "10.1 %",
"D": "8.6 %",
"E": "8.4 %"
} | multiply(divide(add(divide(multiply(15, 15), const_100), divide(multiply(8, 35), const_100)), add(15, 35)), const_100) | add(n2,n3)|multiply(n0,n2)|multiply(n1,n3)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100)| | "the amount of chromium in the new 15 + 35 = 50 kg alloy is 0.15 * 15 + 0.08 * 35 = 5.05 kg , so the percentage is 5.05 / 50 * 100 = 10.1 % . answer : c ." | gain |
math_qa__t5FFhmPwcJRDWlyF | Working alone, sawyer finishes cleaning half the house in a third of the time it takes Nick to clean the entire house alone. sawyer alone cleans the entire house in 6 hours. How many hours will it take Nick and sawyer to clean the entire house if they work together? Choose the correct choice from the following choices: A) 1.5 B) 2 C) 2.4 D) 3 E) 3.6 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/6) + (1/9)</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">1 / (5/18)</gadget>
<output>18/5 = around 3.6</output>
<result>E</result> | E | 3.6 | Working alone, sawyer finishes cleaning half the house in a third of the time it takes Nick to clean the entire house alone. sawyer alone cleans the entire house in 6 hours. How many hours will it take Nick and sawyer to clean the entire house if they work together? | {
"A": "1.5",
"B": "2",
"C": "2.4",
"D": "3",
"E": "3.6"
} | inverse(add(divide(const_1, 6), divide(const_1, multiply(divide(6, const_2), const_3)))) | divide(const_1,n0)|divide(n0,const_2)|multiply(#1,const_3)|divide(const_1,#2)|add(#0,#3)|inverse(#4) | answer is 3.6 hours . sawyer does the complete house in 6 hours while nick does it in 9 hours . 1 / ( 1 / 6 + 1 / 9 ) = 3.6 answer is e | physics |
math_qa__uydkSRIoJQuT3GlN | If x is 30 percent greater than 88, then x = Choose the correct choice: A) 68 B) 70.4 C) 86 D) 114.4 E) 108 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 88</gadget>
<output>132/5 = around 26.4</output>
<gadget id="calculator">88 + (132/5)</gadget>
<output>572/5 = around 114.4</output>
<result>D</result> | D | 114.4 | If x is 30 percent greater than 88, then x = | {
"A": "68",
"B": "70.4",
"C": "86",
"D": "114.4",
"E": "108"
} | add(88, multiply(divide(30, const_100), 88)) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1)| | "x = 88 * 1.3 = 114.4 so the answer is d ." | general |
math_qa__KlpVHskGhPqD28B9 | find value for x from below equation? x + 1 = 5
Pick one
A) - 5
B) - 4
C) 4
D) 3
E) 2 | <gadget id="calculator">5 - 1</gadget>
<output>4</output>
<result>C</result> | C | 4 | find value for x from below equation? x + 1 = 5 | {
"A": "- 5",
"B": "- 4",
"C": "4",
"D": "3",
"E": "2"
} | subtract(5, 1) | subtract(n1,n0) | 1 . subtract 1 from both sides : x + 1 - 1 = 5 - 1 2 . simplify both sides : x = 4 c | general |
math_qa__M65FyyKypeu72BBn | What least number should be added to 1015, so that the sum is completely divisible by 25? Choose the correct choice.
A) 4 B) 3 C) 2 D) 10 E) 5 | <gadget id="calculator">1_015 % 25</gadget>
<output>15</output>
<gadget id="calculator">25 - 15</gadget>
<output>10</output>
<result>D</result> | D | 10 | What least number should be added to 1015, so that the sum is completely divisible by 25? | {
"A": "4",
"B": "3",
"C": "2",
"D": "10",
"E": "5"
} | subtract(25, reminder(1015, 25)) | reminder(n0,n1)|subtract(n1,#0)| | "1015 ã · 25 = 40 with remainder = 15 15 + 10 = 25 . hence 10 should be added to 1015 so that the sum will be divisible by 25 answer : option d" | general |
math_qa__10BO0zRxCJ5xca8V | The population of a city increases @ 4% p.a. There is an additional annual increase of 4% of the population due to the influx of job seekers, find the % increase in population after 2 years ? Choose the correct answer
A) 14.64 % B) 15.64 % C) 16.64 % D) 17.64 % E) 18.64 % | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<result>C</result> | C | 16.64 | The population of a city increases @ 4% p.a. There is an additional annual increase of 4% of the population due to the influx of job seekers, find the % increase in population after 2 years ? | {
"A": "14.64 %",
"B": "15.64 %",
"C": "16.64 %",
"D": "17.64 %",
"E": "18.64 %"
} | multiply(add(4, 4), 2) | add(n0,n0)|multiply(n2,#0) | total annual increament in population = 4 + 4 = 8 % let the population be x population after 2 years = 1.08 x + . 0864 x population increase = 1.08 x + . 0864 x - x % increase = ( ( 1.08 x + . 0864 x - x ) / x ) * 100 = ( 1.08 + . 0864 - 1 ) * 100 = . 1664 * 100 = 16.64 % answer : c | general |
math_qa__p9Li13ObyVGMpZ19 | The sum of even numbers between 1 and 31 is: Choose the correct choice from the following options.
A) 240 B) 789 C) 520 D) 879 E) 456 | <gadget id="calculator">31 + 1</gadget>
<output>32</output>
<gadget id="calculator">31 / 2</gadget>
<output>31/2 = around 15.5</output>
<gadget id="calculator">floor(31/2)</gadget>
<output>15</output>
<gadget id="calculator">15 / 2</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">32 * (15/2)</gadget>
<output>240</output>
<result>A</result> | A | 240 | The sum of even numbers between 1 and 31 is: | {
"A": "240",
"B": "789",
"C": "520",
"D": "879",
"E": "456"
} | multiply(add(31, 1), divide(floor(divide(31, const_2)), const_2)) | add(n0,n1)|divide(n1,const_2)|floor(#1)|divide(#2,const_2)|multiply(#0,#3) | explanation : let sn = ( 2 + 4 + 6 + . . . + 30 ) . this is an a . p . in which a = 2 , d = 2 and l = 30 let the number of terms be n . then a + ( n - 1 ) d = 30 = > 2 + ( n - 1 ) x 2 = 30 n = 15 . sn = n / 2 ( a + l ) = 15 / 2 x ( 2 + 30 ) = ( 15 x 16 ) = 240 . answer : a | general |
math_qa__cr4wJZTL0Sxbxdud | A whale goes on a feeding frenzy that lasts for 9 hours. For the first hour he catches and eats x kilos of plankton. In every hour after the first, it consumes 3 kilos of plankton more than it consumed in the previous hour. If by the end of the frenzy the whale will have consumed a whopping accumulated total 450 kilos of plankton, how many kilos did he consume on the sixth hour? Choose the correct choice from the following answers:
A) 38 B) 47 C) 50 D) 53 E) 62 | <gadget id="calculator">450 / 9</gadget>
<output>50</output>
<gadget id="calculator">50 + 3</gadget>
<output>53</output>
<result>D</result> | D | 53 | A whale goes on a feeding frenzy that lasts for 9 hours. For the first hour he catches and eats x kilos of plankton. In every hour after the first, it consumes 3 kilos of plankton more than it consumed in the previous hour. If by the end of the frenzy the whale will have consumed a whopping accumulated total 450 kilos of plankton, how many kilos did he consume on the sixth hour? | {
"A": "38",
"B": "47",
"C": "50",
"D": "53",
"E": "62"
} | add(divide(450, 9), 3) | divide(n2,n0)|add(n1,#0)| | "suppose food eaten in first hour : x the ap is : x , x + 3 , x + 6 , . . . . [ number of terms ' n ' = 9 ] therefore , 9 / 2 [ 2 x + ( 9 - 1 ) * 3 ] = 450 . solving for x , x = 38 . now , 6 th term will be : x + ( 6 - 1 ) * d = 38 + 5 * 3 = 53 . hence d ! !" | general |
math_qa__Br1IwRG6eQeeblQb | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 55 kg. What might be the weight of the new person? Choose the correct choice from the following options.
A) 56 kg
B) 90 kg
C) 75 kg
D) data inadequate
E) none of these | <gadget id="calculator">8 * 2.5</gadget>
<output>20</output>
<gadget id="calculator">20 + 55</gadget>
<output>75</output>
<result>C</result> | C | 75 | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 55 kg. What might be the weight of the new person? | {
"A": "56 kg",
"B": "90 kg",
"C": "75 kg",
"D": "data inadequate",
"E": "none of these"
} | add(multiply(8, 2.5), 55) | multiply(n0,n1)|add(n2,#0)| | "c 75 kg total weight increased = ( 8 x 2.5 ) kg = 20 kg . weight of new person = ( 55 + 20 ) kg = 75 kg ." | general |
math_qa__yScNyyvLzSeMRuri | Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 17000, then find his savings? Choose the correct choice from the following options:
A) 3600
B) 3400
C) 3608
D) 3602
E) 3603 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 17_000</gadget>
<output>13_600</output>
<gadget id="calculator">17_000 - 13_600</gadget>
<output>3_400</output>
<result>B</result> | B | 3,400 | Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 17000, then find his savings? | {
"A": "3600",
"B": "3400",
"C": "3608",
"D": "3602",
"E": "3603"
} | subtract(17000, multiply(divide(4, 5), 17000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | "let the income and the expenditure of the person be rs . 5 x and rs . 4 x respectively . income , 5 x = 17000 = > x = 3400 savings = income - expenditure = 5 x - 4 x = x so , savings = rs . 3400 . answer : b" | other |
math_qa__EHyS1gGByYK14Y8q | A store reduced the price of all items in the store by 8% on the first day and by another 10% on the second day. The price of items on the second day was what percent of the price before the first reduction took place? Choose one:
A) 80.0
B) 80.9
C) 81.0
D) 81.1
E) 82.8 | <gadget id="calculator">100 - 8</gadget>
<output>92</output>
<gadget id="calculator">92 / 100</gadget>
<output>23/25 = around 0.92</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(23/25) * (9/10)</gadget>
<output>207/250 = around 0.828</output>
<gadget id="calculator">(207/250) * 100</gadget>
<output>414/5 = around 82.8</output>
<result>E</result> | E | 82.8 | A store reduced the price of all items in the store by 8% on the first day and by another 10% on the second day. The price of items on the second day was what percent of the price before the first reduction took place? | {
"A": "80.0",
"B": "80.9",
"C": "81.0",
"D": "81.1",
"E": "82.8"
} | multiply(multiply(divide(subtract(const_100, 8), const_100), divide(subtract(const_100, 10), const_100)), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|multiply(#4,const_100) | consider price of the all items as $ 100 after a initial reduction of 8 % price becomes = 0.92 * 100 = $ 92 after the final reduction of 10 % price becomes = 0.9 * 92 = $ 82.8 price of all items on second day is 82.8 % of price on first day correct answer option e | gain |
math_qa__02OKudERHLkL97TI | Out of 470 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ?
Select: A) 80 B) 150 C) 100 D) 180 E) 220 | <gadget id="calculator">175 + 325</gadget>
<output>500</output>
<gadget id="calculator">470 - 50</gadget>
<output>420</output>
<gadget id="calculator">500 - 420</gadget>
<output>80</output>
<result>A</result> | A | 80 | Out of 470 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ? | {
"A": "80",
"B": "150",
"C": "100",
"D": "180",
"E": "220"
} | subtract(add(175, 325), subtract(470, 50)) | add(n1,n2)|subtract(n0,n3)|subtract(#0,#1)| | "n ( a ) = 325 , n ( b ) = 175 , n ( aub ) = 470 - 50 = 420 . required number = n ( anb ) = n ( a ) + n ( b ) - n ( aub ) = 325 + 175 - 420 = 80 . answer is a" | other |
math_qa__XFahsH3UXUrKIoOB | In a class of 60 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course? Choose the correct choice from the following: A) 6 B) 15 C) 24 D) 33 E) 54 | <gadget id="calculator">41 + 22</gadget>
<output>63</output>
<gadget id="calculator">63 - 9</gadget>
<output>54</output>
<gadget id="calculator">60 - 54</gadget>
<output>6</output>
<result>A</result> | A | 6 | In a class of 60 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course? | {
"A": "6",
"B": "15",
"C": "24",
"D": "33",
"E": "54"
} | subtract(60, subtract(add(41, 22), 9)) | add(n1,n2)|subtract(#0,n3)|subtract(n0,#1)| | "formula for calculating two overlapping sets : a + b - both + not ( a or b ) = total so in our task we have equation : 41 ( french ) + 22 ( german ) - 9 ( both ) + not = 60 54 + not = 60 not = 60 - 54 = 6 so answer is a" | other |
math_qa__xwFkbtAcLwTlgY3C | Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 4 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 9 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?
Choose the correct answer
A) 60 B) 72 C) 84 D) 90 E) 216 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">9 - 8</gadget>
<output>1</output>
<gadget id="calculator">4 / 1</gadget>
<output>4</output>
<gadget id="calculator">9 - 4</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">4 - (2/5)</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">(18/5) * 60</gadget>
<output>216</output>
<result>E</result> | E | 216 | Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 4 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 9 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered? | {
"A": "60",
"B": "72",
"C": "84",
"D": "90",
"E": "216"
} | multiply(subtract(divide(multiply(const_2, const_2), subtract(9, multiply(const_2, 4))), divide(const_2, subtract(9, 4))), const_60) | multiply(const_2,const_2)|multiply(n0,const_2)|subtract(n1,n0)|divide(const_2,#2)|subtract(n1,#1)|divide(#0,#4)|subtract(#5,#3)|multiply(#6,const_60) | e is the answer . . . . d = ts where d = distance , t = time and s = speed to travel half distance , ( 2 + 4 t ) = 9 t = = > t = 2 / 5 = = > 24 minutes to travel double distance , 2 ( 2 + 4 t ) = 9 t = = > 4 = = > 240 minutes difference , 216 minutes e | physics |
math_qa__QCpUiSpaXV2tDw1X | In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 10 percent of revenues. The profits in 1999 were what percent of the profits in 1998?
Choose the correct choice from the following answers: A) 70 % B) 105 % C) 120 % D) 124.2 % E) 138 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(7/10) * (1/10)</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">(7/100) / (1/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 100</gadget>
<output>70</output>
<result>A</result> | A | 70 | In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 10 percent of revenues. The profits in 1999 were what percent of the profits in 1998? | {
"A": "70 %",
"B": "105 %",
"C": "120 %",
"D": "124.2 %",
"E": "138 %"
} | multiply(divide(multiply(subtract(const_1, divide(30, const_100)), divide(10, const_100)), divide(10, const_100)), const_100) | divide(n4,const_100)|divide(n3,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(#0,#3)|divide(#4,#2)|multiply(#5,const_100)| | "0,07 r = x / 100 * 0.1 r answer a" | gain |
math_qa__EErN4dm62JhGfabg | P is able to do a piece of work in 15 days and Q can do the same work in 20 days. If they can work together for 4 days, what is the fraction of work left?
Answers:
A) 8 / 15
B) 7 / 15
C) 1 / 15
D) 3 / 15
E) none of these | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/20) + (1/15)</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">(7/60) * 4</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">1 - (7/15)</gadget>
<output>8/15 = around 0.533333</output>
<result>A</result> | A | 0.533333 | P is able to do a piece of work in 15 days and Q can do the same work in 20 days. If they can work together for 4 days, what is the fraction of work left? | {
"A": "8 / 15",
"B": "7 / 15",
"C": "1 / 15",
"D": "3 / 15",
"E": "none of these"
} | subtract(const_1, multiply(add(divide(const_1, 20), divide(const_1, 15)), 4)) | divide(const_1,n1)|divide(const_1,n0)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3) | explanation : p ' s 1 - day work = 1 / 15 q ' s 1 - day work = 1 / 20 work done by ( p + q ) in 1 day = 1 / 15 + 1 / 20 = 7 / 60 . work done by them in 4 days = ( 7 / 60 ) * 4 = 7 / 15 . work left = 1 - ( 7 / 15 ) = 8 / 15 . answer is a | physics |
math_qa__0uR0LjCPIwbYHJnH | When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 30% water? Options:
A) 1.2 kg
B) 1.5 kg
C) 1.4 kg
D) 1.9 kg
E) none of these | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(7/10) / (1/2)</gadget>
<output>7/5 = around 1.4</output>
<result>C</result> | C | 1.4 | When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 30% water? | {
"A": "1.2 kg",
"B": "1.5 kg",
"C": "1.4 kg",
"D": "1.9 kg",
"E": "none of these"
} | divide(divide(subtract(const_100, 30), const_100), divide(50, const_100)) | divide(n1,const_100)|subtract(const_100,n2)|divide(#1,const_100)|divide(#2,#0)| | "explanation : flower - nectar contains 50 % of non - water part . in honey this non - water part constitutes 70 % ( 100 - 30 ) . therefore 0.5 x amount of flower - nectar = 0.70 x amount of honey = 0.70 x 1 kg therefore amount of flower - nectar needed = ( 0.70 / 0.51 ) kg = 1.4 kgs answer : c" | general |
math_qa__xLEGbC2XHUtYlOBK | Excluding stoppages, the speed of a train is 50 kmph and including stoppages it is 30 kmph. Of how many minutes does the train stop per hour? Choose the correct option:
A) 82 B) 17 C) 12 D) 24 E) 18 | <gadget id="calculator">30 / 50</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">60 * (3/5)</gadget>
<output>36</output>
<gadget id="calculator">60 - 36</gadget>
<output>24</output>
<result>D</result> | D | 24 | Excluding stoppages, the speed of a train is 50 kmph and including stoppages it is 30 kmph. Of how many minutes does the train stop per hour? | {
"A": "82",
"B": "17",
"C": "12",
"D": "24",
"E": "18"
} | subtract(const_60, multiply(const_60, divide(30, 50))) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "explanation : t = 20 / 50 * 60 = 24 answer : option d" | physics |
math_qa__2q01n0wLiPmzINrp | Find the constant k so that : -x2 - (k + 9)x - 8 = -(x - 2)(x - 4) Choose the correct choice.
A) 11 B) 12 C) 15 D) 14 E) 19 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">9 + 6</gadget>
<output>15</output>
<result>C</result> | C | 15 | Find the constant k so that : -x2 - (k + 9)x - 8 = -(x - 2)(x - 4) | {
"A": "11",
"B": "12",
"C": "15",
"D": "14",
"E": "19"
} | add(9, add(4, 2)) | add(n0,n4)|add(n1,#0) | - x 2 - ( k + 9 ) x - 8 = - ( x - 2 ) ( x - 4 ) : given - x 2 - ( k + 9 ) x - 8 = - x 2 + 6 x - 8 - ( k + 9 ) = 6 : two polynomials are equal if their corresponding coefficients are equal . k = - 15 : solve the above for k correct answer c | general |
math_qa__WlpHkxqxMsEuydZE | A 230 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? Choices: A) 230 B) 270 C) 260 D) 256 E) 298 | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">(500/9) * 9</gadget>
<output>500</output>
<gadget id="calculator">500 - 230</gadget>
<output>270</output>
<result>B</result> | B | 270 | A 230 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? | {
"A": "230",
"B": "270",
"C": "260",
"D": "256",
"E": "298"
} | subtract(multiply(multiply(add(120, 80), const_0_2778), 9), 230) | add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)| | "relative speed = 120 + 80 = 200 km / hr . = 200 * 5 / 18 = 500 / 9 m / sec . let the length of the other train be x m . then , ( x + 2340 ) / 9 = 500 / 9 = > x = 270 . answer : b" | physics |
math_qa__AOjs5aaxIPs1bmBk | A candidate who gets 40% of the marks fails by 40 marks. But another candidate who gets 60% marks gets 20 marks more than necessary for passing. Find the number of marks for passing? Choices.
A) 100 marks B) 200 marks C) 160 marks D) 371 marks E) 827 marks | <gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/5) - (2/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">60 / (1/5)</gadget>
<output>300</output>
<gadget id="calculator">300 * (2/5)</gadget>
<output>120</output>
<gadget id="calculator">120 + 40</gadget>
<output>160</output>
<result>C</result> | C | 160 | A candidate who gets 40% of the marks fails by 40 marks. But another candidate who gets 60% marks gets 20 marks more than necessary for passing. Find the number of marks for passing? | {
"A": "100 marks",
"B": "200 marks",
"C": "160 marks",
"D": "371 marks",
"E": "827 marks"
} | add(multiply(divide(add(40, 20), subtract(divide(60, const_100), divide(40, const_100))), divide(40, const_100)), 40) | add(n1,n3)|divide(n2,const_100)|divide(n0,const_100)|subtract(#1,#2)|divide(#0,#3)|multiply(#4,#2)|add(n1,#5)| | "40 % - - - - - - - - - - - - 40 60 % - - - - - - - - - - - - 20 - - - - - - - - - - - - - - - - - - - - - - 20 % - - - - - - - - - - - - - 60 40 % - - - - - - - - - - - - - - ? 120 + 40 = 160 marks answer : c" | gain |
math_qa__qWRL1Hwei0FZuGHL | The length of the bridge, which a train 100 metres long and travelling at 45 km/hr can cross in 30 seconds, is: Select the correct option: A) 230 B) 240 C) 245 D) 250 E) 275 | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 100</gadget>
<output>275</output>
<result>E</result> | E | 275 | The length of the bridge, which a train 100 metres long and travelling at 45 km/hr can cross in 30 seconds, is: | {
"A": "230",
"B": "240",
"C": "245",
"D": "250",
"E": "275"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 100) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "speed = [ 45 x 5 / 18 ] m / sec = [ 25 / 2 ] m / sec time = 30 sec let the length of bridge be x metres . then , ( 100 + x ) / 30 = 25 / 2 = > 2 ( 100 + x ) = 750 = > x = 275 m . answer : option e" | physics |
math_qa__B2AIPfenkEwbqPXu | A train running at the speed of 90 km/hr crosses a pole in 9 sec. What is the length of the train? Choose the correct choice from the following:
A) 288
B) 225
C) 277
D) 272
E) 150 | <gadget id="calculator">90 * 1_000</gadget>
<output>90_000</output>
<gadget id="calculator">90_000 / 3_600</gadget>
<output>25</output>
<gadget id="calculator">25 * 9</gadget>
<output>225</output>
<result>B</result> | B | 225 | A train running at the speed of 90 km/hr crosses a pole in 9 sec. What is the length of the train? | {
"A": "288",
"B": "225",
"C": "277",
"D": "272",
"E": "150"
} | multiply(divide(multiply(90, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 90 * 5 / 18 = 25 m / sec length of the train = speed * time = 25 * 9 = 225 m answer : b" | physics |
math_qa__OYlB2AKs2C4jK5Ep | We bought 85 hats at the store. Blue hats cost $6 and green hats cost $7. The total price was $550. How many green hats did we buy? Choose the correct choice from the following: A) 36 B) 40 C) 41 D) 42 E) 44 | <gadget id="calculator">85 * 6</gadget>
<output>510</output>
<gadget id="calculator">550 - 510</gadget>
<output>40</output>
<result>B</result> | B | 40 | We bought 85 hats at the store. Blue hats cost $6 and green hats cost $7. The total price was $550. How many green hats did we buy? | {
"A": "36",
"B": "40",
"C": "41",
"D": "42",
"E": "44"
} | subtract(550, multiply(85, 6)) | multiply(n0,n1)|subtract(n3,#0)| | "let b be the number of blue hats and let g be the number of green hats . b + g = 85 . b = 85 - g . 6 b + 7 g = 550 . 6 ( 85 - g ) + 7 g = 550 . 510 - 6 g + 7 g = 550 . g = 550 - 510 = 40 . the answer is b ." | general |
math_qa__Gde0ylzTTcjAlrmD | Jackie has two solutions that are 2 percent sulfuric acid and 12 percent sulfuric acid by volume, respectively. If these solutions are mixed in appropriate quantities to produce 60 liters of a solution that is 5 percent sulfuric acid, approximately how many liters of the 12 percent solution will be required? Select:
A) 18 B) 20 C) 24 D) 36 E) 42 | <gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<result>A</result> | A | 18 | Jackie has two solutions that are 2 percent sulfuric acid and 12 percent sulfuric acid by volume, respectively. If these solutions are mixed in appropriate quantities to produce 60 liters of a solution that is 5 percent sulfuric acid, approximately how many liters of the 12 percent solution will be required? | {
"A": "18",
"B": "20",
"C": "24",
"D": "36",
"E": "42"
} | multiply(const_3, divide(60, const_10)) | divide(n2,const_10)|multiply(#0,const_3) | let a = amount of 2 % acid and b = amount of 12 % acid . now , the equation translates to , 0.02 a + . 12 b = . 05 ( a + b ) but a + b = 60 therefore . 02 a + . 12 b = . 05 ( 60 ) = > 2 a + 12 b = 300 but b = 60 - a therefore 2 a + 12 ( 60 - a ) = 300 = > 10 a = 420 hence a = 42 . , b = 60 - 42 = 18 answer : a | gain |
math_qa__PLlYf7FWWfoZn8tr | Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour? Choose the most appropriate option.
A) 16 B) 17 C) 12 D) 16 E) 16 | <gadget id="calculator">36 / 45</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">60 * (4/5)</gadget>
<output>48</output>
<gadget id="calculator">60 - 48</gadget>
<output>12</output>
<result>C</result> | C | 12 | Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour? | {
"A": "16",
"B": "17",
"C": "12",
"D": "16",
"E": "16"
} | subtract(const_60, multiply(const_60, divide(36, 45))) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "t = 9 / 45 * 60 12 answer : c" | physics |
math_qa__gEqbIblemkMKfexl | One-fourth of a number is greater than one-fifth of the number succeeding it by 1. Find the number. Choose the correct choice from the following.
A) 24 B) 42 C) 36 D) 48 E) 50 | <gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) - (1/5)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(6/5) / (1/20)</gadget>
<output>24</output>
<result>A</result> | A | 24 | One-fourth of a number is greater than one-fifth of the number succeeding it by 1. Find the number. | {
"A": "24",
"B": "42",
"C": "36",
"D": "48",
"E": "50"
} | divide(add(divide(const_2, const_10), 1), subtract(divide(1, const_4), divide(const_2, const_10))) | divide(const_2,const_10)|divide(n0,const_4)|add(n0,#0)|subtract(#1,#0)|divide(#2,#3) | number is 24 as 1 / 4 th of 24 = 6 1 / 5 th of 25 ( 24 + 1 ) = 5 6 = 5 + 1 answer : a | general |
math_qa__fpyD6duK1bOHEkgr | Working at their respective constant rates, machine A makes 100 copies in 20 minutes and machine B makes 150 copies in 10 minutes. If these machines work simultaneously at their respective rates for 30 minutes, what is the total number of copies that they will produce? Choices:
A) 250 B) 425 C) 675 D) 700 E) 600 | <gadget id="calculator">100 / 20</gadget>
<output>5</output>
<gadget id="calculator">150 / 10</gadget>
<output>15</output>
<gadget id="calculator">5 + 15</gadget>
<output>20</output>
<gadget id="calculator">20 * 30</gadget>
<output>600</output>
<result>E</result> | E | 600 | Working at their respective constant rates, machine A makes 100 copies in 20 minutes and machine B makes 150 copies in 10 minutes. If these machines work simultaneously at their respective rates for 30 minutes, what is the total number of copies that they will produce? | {
"A": "250",
"B": "425",
"C": "675",
"D": "700",
"E": "600"
} | multiply(add(divide(100, 20), divide(150, 10)), 30) | divide(n0,n1)|divide(n2,n3)|add(#0,#1)|multiply(n4,#2)| | "machine a can produce 100 * 30 / 20 = 150 copies and , machine b can produce 150 * 30 / 10 = 450 copies total producing 600 copies . e is the answer" | physics |
math_qa__Zgnx9ZjvZKUlmwaI | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 160 kilometers? Choose the correct choice from the following
A) 8 gallons B) 4 gallons C) 6 gallons D) 5.5 gallons E) 10 gallons | <gadget id="calculator">160 / 40</gadget>
<output>4</output>
<result>B</result> | B | 4 | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 160 kilometers? | {
"A": "8 gallons",
"B": "4 gallons",
"C": "6 gallons",
"D": "5.5 gallons",
"E": "10 gallons"
} | divide(160, 40) | divide(n1,n0)| | "each 40 kilometers , 1 gallon is needed . we need to know how many 40 kilometers are there in 160 kilometers ? 160 / 40 = 4 * 1 gallon = 4 gallons correct answer b" | physics |
math_qa__Kzx1Wdc30xFlNrBY | A vessel of capacity 2 litre has 25% of alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture? Select the correct option:
A) 31 % .
B) 71 % .
C) 49 % .
D) 29 % .
E) 51 % . | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 6</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(1/2) + (12/5)</gadget>
<output>29/10 = around 2.9</output>
<gadget id="calculator">(29/10) / 10</gadget>
<output>29/100 = around 0.29</output>
<gadget id="calculator">(29/100) * 100</gadget>
<output>29</output>
<result>D</result> | D | 29 | A vessel of capacity 2 litre has 25% of alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture? | {
"A": "31 % .",
"B": "71 % .",
"C": "49 % .",
"D": "29 % .",
"E": "51 % ."
} | multiply(divide(add(multiply(divide(25, const_100), 2), multiply(divide(40, const_100), 6)), 10), const_100) | divide(n1,const_100)|divide(n3,const_100)|multiply(n0,#0)|multiply(n2,#1)|add(#2,#3)|divide(#4,n5)|multiply(#5,const_100) | 25 % of 2 litres = 0.5 litres 40 % of 6 litres = 2.4 litres therefore , total quantity of alcohol is 2.9 litres . this mixture is in a 10 litre vessel . hence , the concentration of alcohol in this 10 litre vessel is 29 % answer : d | general |
math_qa__F8NAAwGTG9smH9bq | Cole drove from home to work at an average speed of 75 kmh. He then returned home at an average speed of 105 kmh. If the round trip took a total of 6 hours, how many minutes did it take Cole to drive to work? Choose the correct choice from the following answers
A) 84
B) 136
C) 172
D) 210
E) 478 | <gadget id="calculator">105 * 6</gadget>
<output>630</output>
<gadget id="calculator">75 + 105</gadget>
<output>180</output>
<gadget id="calculator">630 / 180</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) * 60</gadget>
<output>210</output>
<result>D</result> | D | 210 | Cole drove from home to work at an average speed of 75 kmh. He then returned home at an average speed of 105 kmh. If the round trip took a total of 6 hours, how many minutes did it take Cole to drive to work? | {
"A": "84",
"B": "136",
"C": "172",
"D": "210",
"E": "478"
} | multiply(divide(multiply(105, 6), add(75, 105)), const_60) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)|multiply(#2,const_60)| | "first round distance travelled ( say ) = d speed = 75 k / h time taken , t 2 = d / 75 hr second round distance traveled = d ( same distance ) speed = 105 k / h time taken , t 2 = d / 105 hr total time taken = 6 hrs therefore , 6 = d / 75 + d / 105 lcm of 75 and 105 = 525 6 = d / 75 + d / 105 = > 6 = 7 d / 525 + 5 d / 525 = > d = 525 / 2 km therefore , t 1 = d / 75 = > t 1 = 525 / ( 2 x 75 ) = > t 1 = ( 7 x 60 ) / 2 - - in minutes = > t 1 = 210 minutes . d" | physics |
math_qa__g8cLaaol81uHoGLS | If the population of a certain country increases at the rate of one person every 15 seconds, by how many persons does the population increase in 40 minutes?
Choose the correct choice.
A) 80 B) 100 C) 160 D) 240 E) 300 | <gadget id="calculator">60 / 15</gadget>
<output>4</output>
<gadget id="calculator">4 * 40</gadget>
<output>160</output>
<result>C</result> | C | 160 | If the population of a certain country increases at the rate of one person every 15 seconds, by how many persons does the population increase in 40 minutes? | {
"A": "80",
"B": "100",
"C": "160",
"D": "240",
"E": "300"
} | multiply(divide(const_60, 15), 40) | divide(const_60,n0)|multiply(n1,#0)| | "since the population increases at the rate of 1 person every 15 seconds , it increases by 4 people every 60 seconds , that is , by 4 people every minute . thus , in 40 minutes the population increases by 40 x 4 = 160 people . answer . c ." | physics |
math_qa__gMXvhYKdz2qsZYxZ | What is the maximum number Q of 27 cubic centimetre cubes that can fit in a rectangular box measuring 8 centimetre x 9 centimetre x 12 centimetre ? Choose the correct choice from the following options.
A) 36 B) 32 C) 24 D) 21 E) 15 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 9 * 12</gadget>
<output>648</output>
<gadget id="calculator">648 / 27</gadget>
<output>24</output>
<result>C</result> | C | 24 | What is the maximum number Q of 27 cubic centimetre cubes that can fit in a rectangular box measuring 8 centimetre x 9 centimetre x 12 centimetre ? | {
"A": "36",
"B": "32",
"C": "24",
"D": "21",
"E": "15"
} | divide(volume_rectangular_prism(multiply(const_2, const_3), 9, 12), 27) | multiply(const_2,const_3)|volume_rectangular_prism(n2,n3,#0)|divide(#1,n0) | 27 cubic centimetre cubes gives side = 3 cm so if : l * w * h is 9 * 12 * 8 , then max . cube we can have are 3 * 4 * 2 = 24 l * w * h is 9 * 8 * 12 , then max . cube we can have are 3 * 2 * 4 = 24 l * w * h is 12 * 8 * 9 , then max . cube we can have are 4 * 2 * 3 = 24 l * w * h is 12 * 9 * 8 , then max . cube we can have are 4 * 3 * 2 = 24 l * w * h is 8 * 12 * 9 , then max . cube we can have are 2 * 4 * 3 = 24 l * w * h is 8 * 9 * 12 , then max . cube we can have are 2 * 3 * 4 = 24 in all cases we get q = 24 cubes . ans . c | geometry |
math_qa__ZWmbTGz7gAidJKR6 | Two trains of length 100 m and 120 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? Choose the correct choice from the following answers
A) 11 sec
B) 70 sec
C) 21 sec
D) 20 sec
E) 19 sec | <gadget id="calculator">100 + 120</gadget>
<output>220</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">220 / 20</gadget>
<output>11</output>
<result>A</result> | A | 11 | Two trains of length 100 m and 120 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "11 sec",
"B": "70 sec",
"C": "21 sec",
"D": "20 sec",
"E": "19 sec"
} | divide(add(100, 120), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 100 + 120 = 220 m . the time required = d / s = 220 / 20 = 11 sec . answer : a" | physics |
math_qa__WPP8OSNe1L5ECNnH | What is the % change in the area of a rectangle when its length increases by 30% and its width decreases by30%? Choose the correct choice.
A) 0 %
B) 20 % increase
C) 20 % decrease
D) 9 % decrease
E) insufficient data | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">130 * 70</gadget>
<output>9_100</output>
<gadget id="calculator">9_100 / 100</gadget>
<output>91</output>
<gadget id="calculator">100 - 91</gadget>
<output>9</output>
<result>D</result> | D | 9 | What is the % change in the area of a rectangle when its length increases by 30% and its width decreases by30%? | {
"A": "0 %",
"B": "20 % increase",
"C": "20 % decrease",
"D": "9 % decrease",
"E": "insufficient data"
} | subtract(const_100, divide(multiply(add(const_100, 30), subtract(const_100, 30)), const_100)) | add(n0,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|subtract(const_100,#3)| | "( 13 / 10 ) * ( 7 / 10 ) = 91 / 100 of original area 91 / 100 is a 9 % decrease from 100 / 100 - > d" | geometry |
math_qa__e1UchpguTvz3BgEC | What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58? Choose the correct choice:
A) rs . 3944
B) rs . 3942
C) rs . 3987
D) rs . 3929
E) rs . 3938 | <gadget id="calculator">289 ** (1/2)</gadget>
<output>17</output>
<gadget id="calculator">4 * 17</gadget>
<output>68</output>
<gadget id="calculator">68 * 58</gadget>
<output>3_944</output>
<result>A</result> | A | 3,944 | What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58? | {
"A": "rs . 3944",
"B": "rs . 3942",
"C": "rs . 3987",
"D": "rs . 3929",
"E": "rs . 3938"
} | multiply(square_perimeter(sqrt(289)), 58) | sqrt(n0)|square_perimeter(#0)|multiply(n1,#1) | let the side of the square plot be a ft . a 2 = 289 = > a = 17 length of the fence = perimeter of the plot = 4 a = 68 ft . cost of building the fence = 68 * 58 = rs . 3944 . answer : a | geometry |
math_qa__BDENv6EEA133ygR5 | Robert is travelling on his cycle andhas calculated to reach point A at 2 PM. if he travels at 10 kmph, he will reach there at 12Pm if he travels at 15 kmph. At what speed musthe travel to reach A at 1 PM? Choose the correct choice from the following options:
A) 8 kmph
B) 10 kmph
C) 12 kmph
D) 14 kmph
E) 16 kmph | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) - (1/15)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">2 / (1/30)</gadget>
<output>60</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<result>C</result> | C | 12 | Robert is travelling on his cycle andhas calculated to reach point A at 2 PM. if he travels at 10 kmph, he will reach there at 12Pm if he travels at 15 kmph. At what speed musthe travel to reach A at 1 PM? | {
"A": "8 kmph",
"B": "10 kmph",
"C": "12 kmph",
"D": "14 kmph",
"E": "16 kmph"
} | divide(divide(2, subtract(divide(1, 10), divide(1, 15))), subtract(divide(divide(2, subtract(divide(1, 10), divide(1, 15))), 10), 1)) | divide(n4,n1)|divide(n4,n3)|subtract(#0,#1)|divide(n0,#2)|divide(#3,n1)|subtract(#4,n4)|divide(#3,#5)| | "let the distance travelled by x km . then , x - x = 2 10 15 3 x - 2 x = 60 x = 60 km . time taken to travel 60 km at 10 km / hr = 60 hrs = 6 hrs . 10 so , robert started 6 hours before 2 p . m . i . e . , at 8 a . m . required speed = 60 kmph . = 12 kmph . 5 c" | physics |
math_qa__ZShZnycnlCCTmCog | Find the value of m 32519 x 9999 = m? Choose the correct choice from the following answers: A) 724533811 B) 353654655 C) 545463251 D) 725117481 E) 325157481 | <gadget id="calculator">9_999 - 4</gadget>
<output>9_995</output>
<gadget id="calculator">9_995 * 32_519</gadget>
<output>325_027_405</output>
<result>E</result> | E | 325,157,481 | Find the value of m 32519 x 9999 = m? | {
"A": "724533811",
"B": "353654655",
"C": "545463251",
"D": "725117481",
"E": "325157481"
} | multiply(subtract(9999, const_4), 32519) | subtract(n1,const_4)|multiply(#0,n0)| | "32519 x 9999 = 32519 x ( 10000 - 1 ) = 32519 x 10000 - 32519 x 1 = 325190000 - 32519 = 325157481 e" | general |
math_qa__PJluZCjiSbKLjxiM | Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $252 per week. How much does she earn in dollars per hour?
Choices: A) 11 B) 10 C) 9 D) 8 E) 7 | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">252 / 36</gadget>
<output>7</output>
<result>E</result> | E | 7 | Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $252 per week. How much does she earn in dollars per hour? | {
"A": "11",
"B": "10",
"C": "9",
"D": "8",
"E": "7"
} | divide(252, add(multiply(8, const_3), multiply(6, const_2))) | multiply(n0,const_3)|multiply(n1,const_2)|add(#0,#1)|divide(n2,#2)| | "let sheila earn x dollars per hour so , on monday , wednesday and friday , she earns 8 x each and , on tuesday and thursday , she earns 6 x each in total , over the week she should earn , 3 ( 8 x ) + 2 ( 6 x ) = 36 x she earns $ 252 per week 36 x = 252 x = 7 correct option : e" | physics |
math_qa__KisqzPomrBbBMTCX | A can run 4 times as fast as B and gives B a start of 66 m. How long should the race course be so that A and B might reach in the same time? Choose the correct answer
A) 88 m
B) 60 m
C) 80 m
D) 65 m
E) 75 m | <gadget id="calculator">66 / 4</gadget>
<output>33/2 = around 16.5</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">(33/2) / 3</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">4 * (11/2)</gadget>
<output>22</output>
<gadget id="calculator">22 + 66</gadget>
<output>88</output>
<result>A</result> | A | 88 | A can run 4 times as fast as B and gives B a start of 66 m. How long should the race course be so that A and B might reach in the same time? | {
"A": "88 m",
"B": "60 m",
"C": "80 m",
"D": "65 m",
"E": "75 m"
} | add(multiply(4, divide(divide(66, 4), subtract(4, const_1))), 66) | divide(n1,n0)|subtract(n0,const_1)|divide(#0,#1)|multiply(n0,#2)|add(n1,#3) | speed of a : speed of b = 4 : 1 means in a race of 4 m a gains 3 m . then in a race of 66 m he gains 66 * ( 4 / 3 ) i . e 88 m answer : a | physics |
math_qa__1lBGn3a27WJ8BbSF | The ratio of male to female in a class is 2:3. the career preference of the students in the class are to be represented in a circle graph. If the area of the graph allocated to each career preference is to be proportional to the number of students who have that career preference, how many degrees of the circle should be used to represent a career that is preferred by one of the males and one of the females in the class? Choose one
A) 160 degree
B) 168 degree
C) 191 degree
D) 72 degree
E) 204 degree | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 360</gadget>
<output>216</output>
<gadget id="calculator">(1/3) * 216</gadget>
<output>72</output>
<result>D</result> | D | 72 | The ratio of male to female in a class is 2:3. the career preference of the students in the class are to be represented in a circle graph. If the area of the graph allocated to each career preference is to be proportional to the number of students who have that career preference, how many degrees of the circle should be used to represent a career that is preferred by one of the males and one of the females in the class? | {
"A": "160 degree",
"B": "168 degree",
"C": "191 degree",
"D": "72 degree",
"E": "204 degree"
} | multiply(divide(const_1, 3), multiply(divide(3, add(2, 3)), const_360)) | add(n0,n1)|divide(const_1,n1)|divide(n1,#0)|multiply(#2,const_360)|multiply(#1,#3) | let the common ratio be x . . so m = 2 x and f = 3 x and total = 5 x 1 of m = 2 x and 1 of f = 3 x . . total preferring that carrer = 5 x now 5 x = 360 , so x = 360 / 5 = 72 . . so x * 8 / 3 = 72 * 8 / 3 = 192 d | geometry |
math_qa__KP1yWMypZ3Q8cKmZ | By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 20%? Choose the correct choice from the following answers.
A) 228 B) 480 C) 512 D) 288 E) 276 | <gadget id="calculator">800 * 100</gadget>
<output>80_000</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">80_000 / 125</gadget>
<output>640</output>
<gadget id="calculator">640 * 20</gadget>
<output>12_800</output>
<gadget id="calculator">12_800 / 100</gadget>
<output>128</output>
<gadget id="calculator">640 - 128</gadget>
<output>512</output>
<result>C</result> | C | 512 | By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 20%? | {
"A": "228",
"B": "480",
"C": "512",
"D": "288",
"E": "276"
} | subtract(divide(multiply(800, const_100), add(25, const_100)), divide(multiply(divide(multiply(800, const_100), add(25, const_100)), 20), const_100)) | add(n1,const_100)|multiply(n0,const_100)|divide(#1,#0)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4) | sp = 800 profit = 25 % cp = ( sp ) * [ 100 / ( 100 + p ) ] = 800 * [ 100 / 125 ] = 640 loss = 25 % = 25 % of 640 = rs . 128 sp = cp - loss = 640 - 128 = rs . 512 answer : c | gain |
math_qa__olbvZn6jTRbo2QPi | What is the greatest of 3 consecutive integers whose sum is 36?
Choose the correct choice from the following answers:
A) 12
B) 13
C) 14
D) 15
E) 16 | <gadget id="calculator">36 - 3</gadget>
<output>33</output>
<gadget id="calculator">33 / 3</gadget>
<output>11</output>
<gadget id="calculator">11 + 2</gadget>
<output>13</output>
<result>B</result> | B | 13 | What is the greatest of 3 consecutive integers whose sum is 36? | {
"A": "12",
"B": "13",
"C": "14",
"D": "15",
"E": "16"
} | add(divide(subtract(36, 3), 3), const_2) | subtract(n1,n0)|divide(#0,n0)|add(#1,const_2)| | "36 / 3 = 12 the three numbers are 11 , 12 , and 13 . the answer is b ." | physics |
math_qa__9LtwKyu4xJ80VzEo | Xavier starts from P towards Q at a speed of 60 kmph and after every 12 mins increases his speed by 10 kmph. If the distance between P and Q is 60km, then how much time does he take to cover the distance? Choose the correct choice
A) 48
B) 59
C) 60
D) 56
E) 50 | <gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">36 + 12</gadget>
<output>48</output>
<result>A</result> | A | 48 | Xavier starts from P towards Q at a speed of 60 kmph and after every 12 mins increases his speed by 10 kmph. If the distance between P and Q is 60km, then how much time does he take to cover the distance? | {
"A": "48",
"B": "59",
"C": "60",
"D": "56",
"E": "50"
} | add(add(add(12, 12), 12), 12) | add(n1,n1)|add(n1,#0)|add(n1,#1)| | "first 12 min = 60 * 12 / 60 = 12 km 2 nd 12 min = 70 * 12 / 60 = 14 km 3 rd 12 min = 80 * 12 / 60 = 16 km 4 th 12 min = 90 * 12 / 60 = 18 km total time 12.4 = 48 min a" | physics |
math_qa__fiXGv8jOuHw0q8Ay | A & B started a partnership business. A's investment was thrice the investment of B and the period of his investment was two times the period of investments of B. If B received Rs 6000 as profit , what is their total profit? Pick
A) 28000 B) 30000 C) 42000 D) 34000 E) none of these | <gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">6_000 / (1/7)</gadget>
<output>42_000</output>
<result>C</result> | C | 42,000 | A & B started a partnership business. A's investment was thrice the investment of B and the period of his investment was two times the period of investments of B. If B received Rs 6000 as profit , what is their total profit? | {
"A": "28000",
"B": "30000",
"C": "42000",
"D": "34000",
"E": "none of these"
} | divide(6000, divide(multiply(const_1, const_1), add(multiply(const_3, const_2), multiply(const_1, const_1)))) | multiply(const_1,const_1)|multiply(const_2,const_3)|add(#1,#0)|divide(#0,#2)|divide(n0,#3) | explanation : suppose b ' s investment = x . then a ' s investment = 3 x suppose bs period of investment = y , then a ' s period of investment = 2 y a : b = 3 x * 2 y : xy = 6 : 1 total profit * 1 / 7 = 6000 = > total profit = 6000 * 7 = 42000 . answer : option c | general |
math_qa__nDAXmFZBrfX7X8tP | The average of 5 quantities is 11. The average of 3 of them is 4. What is the average of remaining 2 numbers? Choose the correct answer: A) 21.5 B) 10.6 C) 8 D) 9.5 E) none of these | <gadget id="calculator">5 * 11</gadget>
<output>55</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">55 - 12</gadget>
<output>43</output>
<gadget id="calculator">43 / 2</gadget>
<output>43/2 = around 21.5</output>
<result>A</result> | A | 21.5 | The average of 5 quantities is 11. The average of 3 of them is 4. What is the average of remaining 2 numbers? | {
"A": "21.5",
"B": "10.6",
"C": "8",
"D": "9.5",
"E": "none of these"
} | divide(subtract(multiply(5, 11), multiply(3, 4)), 2) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)|divide(#2,n4)| | "answer : a ( 5 x 11 - 3 x 4 ) / 2 = 21.5" | general |
math_qa__WhZ1LwbotIkAGQZK | if 4 x + y + z = 80 , 2 x - y - z = 4003 x + y - z = 20 for integers of x , y and z , find x = ? Choices:
A) 10 B) 20 C) 15 D) 26 E) 18 | <gadget id="calculator">80 / 4</gadget>
<output>20</output>
<result>B</result> | B | 20 | if 4 x + y + z = 80 , 2 x - y - z = 4003 x + y - z = 20 for integers of x , y and z , find x = ? | {
"A": "10",
"B": "20",
"C": "15",
"D": "26",
"E": "18"
} | divide(80, 4) | divide(n1,n0) | 4 x + y + z = 80 - - - - - - - - - - 1 ) 2 x - y - z = 40 - - - - - - - - - - - - - 2 ) 3 x + y - z = 20 - - - - - - - - - - - - 3 ) from 1 ) and 2 ) 6 x = 120 x = 20 answer is b | general |
math_qa__hlZdOJCdxrEW93LF | Calculate how much time could be saved if the train would run at its usual speed, given that it ran at 5/7 of its own speed and got to its destination in 15 hours?
Select:
A) 1.29 hrs
B) 2.29 hrs
C) 4.29 hrs
D) 5.29 hrs
E) 3.29 hrs | <gadget id="calculator">15 * 60</gadget>
<output>900</output>
<gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">15 * (5/7)</gadget>
<output>75/7 = around 10.714286</output>
<gadget id="calculator">(75/7) * 60</gadget>
<output>4_500/7 = around 642.857143</output>
<gadget id="calculator">900 - (4_500/7)</gadget>
<output>1_800/7 = around 257.142857</output>
<gadget id="calculator">(1_800/7) % 60</gadget>
<output>120/7 = around 17.142857</output>
<gadget id="calculator">(120/7) / 100</gadget>
<output>6/35 = around 0.171429</output>
<gadget id="calculator">(1_800/7) / 60</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<gadget id="calculator">(6/35) + 4</gadget>
<output>146/35 = around 4.171429</output>
<result>C</result> | C | 4.29 | Calculate how much time could be saved if the train would run at its usual speed, given that it ran at 5/7 of its own speed and got to its destination in 15 hours? | {
"A": "1.29 hrs",
"B": "2.29 hrs",
"C": "4.29 hrs",
"D": "5.29 hrs",
"E": "3.29 hrs"
} | add(divide(reminder(subtract(multiply(15, const_60), multiply(multiply(15, divide(5, 7)), const_60)), const_60), const_100), floor(divide(subtract(multiply(15, const_60), multiply(multiply(15, divide(5, 7)), const_60)), const_60))) | divide(n0,n1)|multiply(n2,const_60)|multiply(n2,#0)|multiply(#2,const_60)|subtract(#1,#3)|divide(#4,const_60)|reminder(#4,const_60)|divide(#6,const_100)|floor(#5)|add(#7,#8)| | "new speed = 5 / 7 of usual speed new time = 5 / 7 of usual time 5 / 7 of usual time = 15 hrs usual time = 15 * 5 / 7 = 10.71 hrs time saved = 15 - 10.71 = 4.29 hrs answer is c" | physics |
math_qa__Ryn5OoHluLtcnx0F | John makes $30 a week from his job. He earns a raise andnow makes $40 a week. What is the % increase?
Answers:
A) 16 % B) 16.66 % C) 18 % D) 21 % E) 33.33 % | <gadget id="calculator">40 - 30</gadget>
<output>10</output>
<gadget id="calculator">10 / 30</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33.33 | John makes $30 a week from his job. He earns a raise andnow makes $40 a week. What is the % increase? | {
"A": "16 %",
"B": "16.66 %",
"C": "18 %",
"D": "21 %",
"E": "33.33 %"
} | multiply(divide(subtract(40, 30), 30), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 10 / 30 ) * 100 = 33.33 % . e" | gain |
math_qa__1cCPqcrSDdtjluI7 | A truck covers a distance of 550 metres in 1 minute whereas a bus covers a distance of 33kms in 45minutes. The ratio of their speeds is? Choose the correct answer.
A) 1 : 2 B) 3 : 4 C) 2 : 5 D) 3 : 7 E) 1 : 3 | <gadget id="calculator">33 / 45</gadget>
<output>11/15 = around 0.733333</output>
<gadget id="calculator">(11/15) * 1_000</gadget>
<output>2_200/3 = around 733.333333</output>
<gadget id="calculator">550 / (2_200/3)</gadget>
<output>3/4 = around 0.75</output>
<result>B</result> | B | 0.75 | A truck covers a distance of 550 metres in 1 minute whereas a bus covers a distance of 33kms in 45minutes. The ratio of their speeds is? | {
"A": "1 : 2",
"B": "3 : 4",
"C": "2 : 5",
"D": "3 : 7",
"E": "1 : 3"
} | divide(550, multiply(divide(33, 45), const_1000)) | divide(n2,n3)|multiply(#0,const_1000)|divide(n0,#1) | ratio of speeds = ( 550 / 60 ) 18 / 5 : 60 * 33 / 45 = 33 : 44 = 3 : 4 answer is b | physics |
math_qa__0gM5hTs2pIxbBSQ1 | A particular library has 150 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 122 books in the special collection at that time, how many books of the special collection were loaned out during that month?
Pick one
A) 40 B) 60 C) 80 D) 100 E) 120 | <gadget id="calculator">150 - 122</gadget>
<output>28</output>
<gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">1 - (13/20)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">28 / (7/20)</gadget>
<output>80</output>
<result>C</result> | C | 80 | A particular library has 150 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 122 books in the special collection at that time, how many books of the special collection were loaned out during that month? | {
"A": "40",
"B": "60",
"C": "80",
"D": "100",
"E": "120"
} | divide(subtract(150, 122), subtract(const_1, divide(65, const_100))) | divide(n1,const_100)|subtract(n0,n2)|subtract(const_1,#0)|divide(#1,#2)| | "the total number of books is 150 . let x be the number of books which were loaned out . 65 % of books that were loaned out are returned . 35 % of books that were loaned out are not returned . now , there are 122 books , thus the number of un - returned books is 150 - 122 = 28 books . 0.35 x = 28 x = 80 the answer is c ." | gain |
math_qa__E8Q66ffzo9Gm4qPX | A batsman in his 12th innings makes a score of 48 and thereby increases his average by 2 runs. What is his average after the 12th innings if he had never been ‘not out’? Answers.
A) 26 B) 43 C) 44 D) 45 E) 46 | <gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">48 - 24</gadget>
<output>24</output>
<gadget id="calculator">24 + 2</gadget>
<output>26</output>
<result>A</result> | A | 26 | A batsman in his 12th innings makes a score of 48 and thereby increases his average by 2 runs. What is his average after the 12th innings if he had never been ‘not out’? | {
"A": "26",
"B": "43",
"C": "44",
"D": "45",
"E": "46"
} | add(subtract(48, multiply(12, 2)), 2) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1)| | "let ‘ x ’ be the average score after 12 th innings ⇒ 12 x = 11 × ( x – 2 ) + 48 ∴ x = 26 answer a" | general |
math_qa__iUJOF68LwLZbI25u | The size of a flat-screen television is given as the length of the screen’s diagonal. How many square inches greater is the screen of a square 24-inch flat-screen television than a square 17-inch flat-screen television? Choose the correct choice from the following choices:
A) 143.5
B) 154
C) 160
D) 148.75
E) 142.25 | <gadget id="calculator">24 ** 2</gadget>
<output>576</output>
<gadget id="calculator">576 / 2</gadget>
<output>288</output>
<gadget id="calculator">17 ** 2</gadget>
<output>289</output>
<gadget id="calculator">289 / 2</gadget>
<output>289/2 = around 144.5</output>
<gadget id="calculator">288 - (289/2)</gadget>
<output>287/2 = around 143.5</output>
<result>A</result> | A | 143.5 | The size of a flat-screen television is given as the length of the screen’s diagonal. How many square inches greater is the screen of a square 24-inch flat-screen television than a square 17-inch flat-screen television? | {
"A": "143.5",
"B": "154",
"C": "160",
"D": "148.75",
"E": "142.25"
} | subtract(divide(power(24, const_2), const_2), divide(power(17, const_2), const_2)) | power(n0,const_2)|power(n1,const_2)|divide(#0,const_2)|divide(#1,const_2)|subtract(#2,#3)| | "if we take a square with side length x and draw a diagonal , we get two isosceles right triangles . if we focus on one such right triangle , we see that the legs have length x . square 24 - inch flat - screen television the diagonal ( hypotenuse ) = 24 so , we can apply the pythagorean theorem to get x ² + x ² = 24 ² simplify : 2 x ² = 24 ² divide both sides by 2 to get : x ² = 24 ² / 2 since the area of the square = x ² , we can see that the area of this square is 24 ² / 2 square 17 - inch flat - screen television the diagonal ( hypotenuse ) = 17 so , we can apply the pythagorean theorem to get x ² + x ² = 17 ² simplify : 2 x ² = 17 ² divide both sides by 2 to get : x ² = 17 ² / 2 since the area of the square = x ² , we can see that the area of this square is 17 ² / 2 difference in areas = 24 ² / 2 - 17 ² / 2 = 288 - 144.5 i . e = 143.5 a" | geometry |
math_qa__4YjwQKY0iTPgySSb | The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ? Choose the correct option:
A) 76 kg B) 76.5 kg C) 85 kg D) 90 kg E) none | <gadget id="calculator">8 * 2.5</gadget>
<output>20</output>
<gadget id="calculator">65 + 20</gadget>
<output>85</output>
<result>C</result> | C | 85 | The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ? | {
"A": "76 kg",
"B": "76.5 kg",
"C": "85 kg",
"D": "90 kg",
"E": "none"
} | add(65, multiply(8, 2.5)) | multiply(n0,n1)|add(n2,#0)| | "sol . total weight increased = ( 8 × 2.5 ) kg = 20 kg . weight of new person = ( 65 + 20 ) kg = 85 kg . answer c" | general |
math_qa__dQpyAAJxWnWWvbYQ | a, b, and c are integers and a<b<c. S is the set of all integers from a to b, inclusive. Q is the set of all integers from b to c, inclusive. The median of set S is (3/4)*b. The median of set Q is (6/8)*c. If R is the set of all integers from a to c, inclusive, what fraction of c is the median of set R? Choose the correct choice from the following options:
A) 3 / 8 B) 1 / 2 C) 11 / 16 D) 5 / 8 E) 3 / 4 | <gadget id="calculator">6 / 8</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / (1/2)</gadget>
<output>2</output>
<gadget id="calculator">(1/2) / 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) / 2</gadget>
<output>5/8 = around 0.625</output>
<result>D</result> | D | 0.625 | a, b, and c are integers and a<b<c. S is the set of all integers from a to b, inclusive. Q is the set of all integers from b to c, inclusive. The median of set S is (3/4)*b. The median of set Q is (6/8)*c. If R is the set of all integers from a to c, inclusive, what fraction of c is the median of set R? | {
"A": "3 / 8",
"B": "1 / 2",
"C": "11 / 16",
"D": "5 / 8",
"E": "3 / 4"
} | divide(add(const_1, divide(subtract(multiply(divide(6, 8), const_2), const_1), divide(const_1, subtract(multiply(divide(3, 4), const_2), const_1)))), const_2) | divide(n2,n3)|divide(n0,n1)|multiply(#0,const_2)|multiply(#1,const_2)|subtract(#2,const_1)|subtract(#3,const_1)|divide(const_1,#5)|divide(#4,#6)|add(#7,const_1)|divide(#8,const_2)| | "the answer isc : 11 / 16 . the key to this problem is remembering that the median for a consecutive set of numbers is equivalent to its mean . for example , the mean and median of a set consisting of x , x + 1 , x + 2 , . . . , y will always be ( x + y ) / 2 . for set s , consisting of numbers ( a , a + 1 , . . . , b ) , the median is given to be 3 / 4 * b : ( a + b ) / 2 = ( 3 / 4 ) * b a = b / 2 for set q , consisting of numbers ( b , b + 1 , . . . , c ) , the median is given to be 6 / 8 * c : ( b + c ) / 2 = ( 6 / 8 ) * c b = ( 1 / 2 ) * c for set r , consisting of numbers ( a , a + 1 , . . . c ) , the median needs to be found : a = b / 2 = ( 1 / 2 * c ) / 2 = ( 1 / 4 ) * c median = ( a + c ) / 2 = ( 1 / 4 * c + c ) / 2 = ( 5 / 4 ) * c / 2 = ( 5 / 8 ) * c ( answer d )" | general |
math_qa__bW65LWw4KmrZxpR3 | A rectangular tank needs to be coated with insulation. The tank has dimensions of 3 feet, 5 feet, and 2 feet. Each square foot of insulation costs $20. How much will it cost to cover the surface of the tank with insulation? Pick
A) $ 1100
B) $ 1240
C) $ 1360
D) $ 1480
E) $ 1550 | <gadget id="calculator">2 * (3 * 5 + 5 * 2 + 3 * 2)</gadget>
<output>62</output>
<gadget id="calculator">62 * 20</gadget>
<output>1_240</output>
<result>B</result> | B | 1,240 | A rectangular tank needs to be coated with insulation. The tank has dimensions of 3 feet, 5 feet, and 2 feet. Each square foot of insulation costs $20. How much will it cost to cover the surface of the tank with insulation? | {
"A": "$ 1100",
"B": "$ 1240",
"C": "$ 1360",
"D": "$ 1480",
"E": "$ 1550"
} | multiply(surface_rectangular_prism(3, 5, 2), 20) | surface_rectangular_prism(n0,n1,n2)|multiply(n3,#0)| | "the total surface area is 2 ( 2 * 3 + 3 * 5 + 2 * 5 ) = 62 square feet the total cost is 62 * $ 20 = $ 1240 the answer is b ." | geometry |
math_qa__IAPCkl1PIGBbqmt3 | Two concentric circles form a ring. The inner and outer circumference of the ring are 352/7 m and 528/7m respectively.Find the width of the ring.
Choose the correct choice from the following answers
A) 2 B) 4 C) 5 D) 6 E) 78 | <gadget id="calculator">528 / 7</gadget>
<output>528/7 = around 75.428571</output>
<gadget id="calculator">(528/7) / 2</gadget>
<output>264/7 = around 37.714286</output>
<gadget id="calculator">(264/7) / pi</gadget>
<output>264/(7*pi) = around 12.00483</output>
<gadget id="calculator">352 / 7</gadget>
<output>352/7 = around 50.285714</output>
<gadget id="calculator">(352/7) / 2</gadget>
<output>176/7 = around 25.142857</output>
<gadget id="calculator">(176/7) / pi</gadget>
<output>176/(7*pi) = around 8.00322</output>
<gadget id="calculator">(264/(7*pi)) - (176/(7*pi))</gadget>
<output>88/(7*pi) = around 4.00161</output>
<result>B</result> | B | 4 | Two concentric circles form a ring. The inner and outer circumference of the ring are 352/7 m and 528/7m respectively.Find the width of the ring. | {
"A": "2",
"B": "4",
"C": "5",
"D": "6",
"E": "78"
} | subtract(divide(divide(divide(528, 7), const_2), const_pi), divide(divide(divide(352, 7), const_2), const_pi)) | divide(n2,n1)|divide(n0,n1)|divide(#0,const_2)|divide(#1,const_2)|divide(#2,const_pi)|divide(#3,const_pi)|subtract(#4,#5) | explanation : let the inner and outer radii be r and r meters then , \ inline { \ color { black } 2 \ prod r } = 352 / 7 = > r = ( 352 / 7 ) * ( 7 / 22 ) * ( 1 / 2 ) = 8 m \ inline { \ color { black } 2 \ prod r } = 528 / 7 = > r = ( 528 / 7 ) * ( 7 / 22 ) * ( 1 / 2 ) = 12 m width of the ring = r - r = 12 - 8 = 4 m answer : b ) 4 | physics |
math_qa__rAZmZerOhXjVpjXs | in a recent election , geoff received 0.5 percent of the 6000 votes cast . to win the election , a candidate needed to receive more than x % of the vote . if geoff needed exactly 3000 more votes to win the election , what is the value of x ? Pick one
A) 50 B) 50.5 C) 56 D) 60 E) 63 | <gadget id="calculator">6_000 * 0.5</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 100</gadget>
<output>30</output>
<gadget id="calculator">3_000 + 30</gadget>
<output>3_030</output>
<gadget id="calculator">3_030 / 6_000</gadget>
<output>101/200 = around 0.505</output>
<gadget id="calculator">(101/200) * 100</gadget>
<output>101/2 = around 50.5</output>
<result>B</result> | B | 50.5 | in a recent election , geoff received 0.5 percent of the 6000 votes cast . to win the election , a candidate needed to receive more than x % of the vote . if geoff needed exactly 3000 more votes to win the election , what is the value of x ? | {
"A": "50",
"B": "50.5",
"C": "56",
"D": "60",
"E": "63"
} | multiply(divide(add(3000, divide(multiply(6000, 0.5), const_100)), 6000), const_100) | multiply(n0,n1)|divide(#0,const_100)|add(n2,#1)|divide(#2,n1)|multiply(#3,const_100) | word problems are tricky in somehow more than other problem because you have the additional step to translate . breaking the problem : geoff how many votes he receives ? ? 30 votes he needs 3571 more votes so : 30 + 3000 = 3030 now what ' s the problem wants ? ? a x % . . . . . . . . 3030 is what % of total votes 6000 . . . . . . . . translating : 3030 = x / 100 * 6000 - - - x = 50.5 % . . . . . . . . . . b | gain |
math_qa__IgqC28qhgptYecin | A certain electric-company plan offers customers reduced rates for electricity used between 8 p.m. and 8 a.m. weekdays and 24 hours a day Saturdays and Sundays. Under this plan, the reduced rates W apply to what fraction of a week? Select.
A) 1 / 2
B) 5 / 8
C) 9 / 14
D) 16 / 21
E) 9 / 10 | <gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">60 + 48</gadget>
<output>108</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">24 * 7</gadget>
<output>168</output>
<gadget id="calculator">108 / 168</gadget>
<output>9/14 = around 0.642857</output>
<result>C</result> | C | 0.642857 | A certain electric-company plan offers customers reduced rates for electricity used between 8 p.m. and 8 a.m. weekdays and 24 hours a day Saturdays and Sundays. Under this plan, the reduced rates W apply to what fraction of a week? | {
"A": "1 / 2",
"B": "5 / 8",
"C": "9 / 14",
"D": "16 / 21",
"E": "9 / 10"
} | divide(add(multiply(divide(24, const_2), add(const_2, const_3)), multiply(24, const_2)), multiply(24, add(const_3, const_4))) | add(const_2,const_3)|add(const_3,const_4)|divide(n2,const_2)|multiply(n2,const_2)|multiply(#0,#2)|multiply(n2,#1)|add(#4,#3)|divide(#6,#5)| | "number of hours between 8 pm to 8 am = 12 number of hours with reduced rates = ( 12 * 5 ) + ( 24 * 2 ) hours with reduced rates w / total number of hours in a week = ( 12 * 5 ) + ( 24 * 2 ) / ( 24 * 7 ) = 108 / ( 24 * 7 ) = 9 / 14 answer : c" | physics |
math_qa__RclgA39ARHpZKrbk | If difference between compound interest and simple interest on a sum at 10% P.a. for 2 years is Rs.36 then sum is Choices
A) s . 5000
B) s . 5100
C) s . 5800
D) s . 6000
E) s . 3600 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * (1/10)</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">36 / (1/100)</gadget>
<output>3_600</output>
<result>E</result> | E | 3,600 | If difference between compound interest and simple interest on a sum at 10% P.a. for 2 years is Rs.36 then sum is | {
"A": "s . 5000",
"B": "s . 5100",
"C": "s . 5800",
"D": "s . 6000",
"E": "s . 3600"
} | divide(36, multiply(divide(10, const_100), divide(10, const_100))) | divide(n0,const_100)|multiply(#0,#0)|divide(n2,#1)| | "p ( r / 100 ) ^ 2 = c . i - s . i p ( 10 / 100 ) ^ 2 = 36 3600 answer : e" | gain |
math_qa__7YLwMt4nwjyc76ek | The ratio of ducks and frogs in a pond is 31 : 39 respectively. The average number of ducks and frogs in the pond is 152. What is the number of frogs in the pond ? Choose the correct choice.
A) 148 B) 152 C) 156 D) 169 E) none | <gadget id="calculator">31 + 39</gadget>
<output>70</output>
<gadget id="calculator">70 + 2</gadget>
<output>72</output>
<gadget id="calculator">72 / 2</gadget>
<output>36</output>
<gadget id="calculator">152 / 36</gadget>
<output>38/9 = around 4.222222</output>
<gadget id="calculator">39 * (38/9)</gadget>
<output>494/3 = around 164.666667</output>
<result>D</result> | D | 169 | The ratio of ducks and frogs in a pond is 31 : 39 respectively. The average number of ducks and frogs in the pond is 152. What is the number of frogs in the pond ? | {
"A": "148",
"B": "152",
"C": "156",
"D": "169",
"E": "none"
} | multiply(39, divide(152, divide(add(add(31, 39), const_2), const_2))) | add(n0,n1)|add(#0,const_2)|divide(#1,const_2)|divide(n2,#2)|multiply(n1,#3)| | "solution : ratio of ducks and frogs in pond , = 31 : 39 . average of ducks and frogs in pond , = 152 . so , total number of ducks and frogs in the pond , = 2 * 152 = 304 . therefore , number of frogs , = ( 304 * 39 ) / 70 = 169 . answer : option d" | general |
math_qa__E4abk4JtNvI3Mhaj | X is a positive number which when increased by 17 is equal to 60 times the reciprocal of the number. Find value of X?
Choices.
A) 3
B) 4
C) 6
D) 7
E) 8 | <gadget id="calculator">-17</gadget>
<output>-17</output>
<gadget id="calculator">17 ** 2</gadget>
<output>289</output>
<gadget id="calculator">-60</gadget>
<output>-60</output>
<gadget id="calculator">1 * (-60)</gadget>
<output>-60</output>
<gadget id="calculator">4 * (-60)</gadget>
<output>-240</output>
<gadget id="calculator">289 - (-240)</gadget>
<output>529</output>
<gadget id="calculator">529 ** (1/2)</gadget>
<output>23</output>
<gadget id="calculator">(-17) + 23</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>A</result> | A | 3 | X is a positive number which when increased by 17 is equal to 60 times the reciprocal of the number. Find value of X? | {
"A": "3",
"B": "4",
"C": "6",
"D": "7",
"E": "8"
} | divide(add(negate(17), sqrt(subtract(power(17, const_2), multiply(const_4, multiply(const_1, negate(60)))))), const_2) | negate(n0)|negate(n1)|power(n0,const_2)|multiply(#1,const_1)|multiply(#3,const_4)|subtract(#2,#4)|sqrt(#5)|add(#0,#6)|divide(#7,const_2) | let the number be x . then , x + 17 = 60 x x 2 + 17 x - 60 = 0 ( x + 20 ) ( x - 3 ) = 0 x = 3 a | general |
math_qa__EEt49Hm8NPdr2G4U | The LCM of two numbers is 2310 and HCF is 47. If one of the numbers is 210. Then what is the other number ? Choose the correct choice from the following choices: A) 715 B) 825 C) 330 D) 582 E) 517 | <gadget id="calculator">2_310 * 47</gadget>
<output>108_570</output>
<gadget id="calculator">108_570 / 210</gadget>
<output>517</output>
<result>E</result> | E | 517 | The LCM of two numbers is 2310 and HCF is 47. If one of the numbers is 210. Then what is the other number ? | {
"A": "715",
"B": "825",
"C": "330",
"D": "582",
"E": "517"
} | divide(multiply(2310, 47), 210) | multiply(n0,n1)|divide(#0,n2) | first number * second number = lcm * hcf other number = 2310 * 47 / 210 = 11 * 47 = 517 answer : e | physics |
math_qa__WhAwuF1mwF3y9XpI | A retailer purchases shirts from a wholesaler and then sells the shirts in her store at a retail price that is 70 percent greater than the wholesale price. If the retailer decreases the retail price by 30 percent this will have the same effect as increasing the wholesale price by what percent? Choose the correct choice
A) 26 B) 37.5 C) 42 D) 19 E) 50 | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">1 + (7/10)</gadget>
<output>17/10 = around 1.7</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(17/10) * (7/10)</gadget>
<output>119/100 = around 1.19</output>
<gadget id="calculator">(119/100) - 1</gadget>
<output>19/100 = around 0.19</output>
<gadget id="calculator">(19/100) * 100</gadget>
<output>19</output>
<result>D</result> | D | 19 | A retailer purchases shirts from a wholesaler and then sells the shirts in her store at a retail price that is 70 percent greater than the wholesale price. If the retailer decreases the retail price by 30 percent this will have the same effect as increasing the wholesale price by what percent? | {
"A": "26",
"B": "37.5",
"C": "42",
"D": "19",
"E": "50"
} | multiply(subtract(multiply(add(const_1, divide(70, const_100)), subtract(const_1, divide(30, const_100))), const_1), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "answer : d = 19 . assume rs . 100 to be the price at which the retailer buys from wholesaler . 70 % increase makes retail price = 170 . now 30 % decrease - > ( 1 - 30 / 100 ) * 170 = 119 . now compared to the wholesale price of 100 , 19 % increase is what will have the same effect as increasing the wholesale price ." | gain |
math_qa__Yg8C6kGIyCw7Nn5g | Machine P and Machine Q are each used to manufacture 220 sprockets. It takes Machine P 10 hours longer to produce 220 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce? Options:
A) 5
B) 2
C) 55
D) 95
E) 125 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">220 / (11/10)</gadget>
<output>200</output>
<gadget id="calculator">220 - 200</gadget>
<output>20</output>
<gadget id="calculator">20 / 10</gadget>
<output>2</output>
<result>B</result> | B | 2 | Machine P and Machine Q are each used to manufacture 220 sprockets. It takes Machine P 10 hours longer to produce 220 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce? | {
"A": "5",
"B": "2",
"C": "55",
"D": "95",
"E": "125"
} | divide(subtract(220, divide(220, add(divide(10, const_100), const_1))), 10) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)|divide(#3,n1)| | "p makes x sprockets per hour . then q makes 1.1 x sprockets per hour . 220 / x = 220 / 1.1 x + 10 1.1 ( 220 ) = 220 + 11 x 11 x = 22 x = 2 the answer is b ." | gain |
math_qa__wbidbigNAFhpMGRO | The average mark of the students of a class in a particular exam is 65. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam. Choose the correct answer.
A) 14 B) 25 C) 35 D) 45 E) 55 | <gadget id="calculator">90 * 5</gadget>
<output>450</output>
<gadget id="calculator">5 * 20</gadget>
<output>100</output>
<gadget id="calculator">450 - 100</gadget>
<output>350</output>
<gadget id="calculator">90 - 65</gadget>
<output>25</output>
<gadget id="calculator">350 / 25</gadget>
<output>14</output>
<result>A</result> | A | 14 | The average mark of the students of a class in a particular exam is 65. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam. | {
"A": "14",
"B": "25",
"C": "35",
"D": "45",
"E": "55"
} | divide(subtract(multiply(90, 5), multiply(5, 20)), subtract(90, 65)) | multiply(n1,n3)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)| | "let the number of students who wrote the exam be x . total marks of students = 75 x . total marks of ( x - 5 ) students = 90 ( x - 5 ) 65 x - ( 5 * 20 ) = 90 ( x - 5 ) 350 = 25 x = > x = 14 answer : a" | general |
math_qa__Udv9Yzkh8qkQaEmx | Fred and Sam are standing 35 miles apart and they start walking in a straight line toward each other at the same time. If Fred walks at a constant speed of 2 miles per hour and Sam walks at a constant speed of 5 miles per hour, how many miles has Sam walked when they meet? Choose the correct answer: A) 5 B) 9 C) 25 D) 30 E) 45 | <gadget id="calculator">2 + 5</gadget>
<output>7</output>
<gadget id="calculator">35 / 7</gadget>
<output>5</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<result>C</result> | C | 25 | Fred and Sam are standing 35 miles apart and they start walking in a straight line toward each other at the same time. If Fred walks at a constant speed of 2 miles per hour and Sam walks at a constant speed of 5 miles per hour, how many miles has Sam walked when they meet? | {
"A": "5",
"B": "9",
"C": "25",
"D": "30",
"E": "45"
} | multiply(5, divide(35, add(2, 5))) | add(n1,n2)|divide(n0,#0)|multiply(n2,#1) | relative distance = 35 miles relative speed = 2 + 5 = 7 miles per hour time taken = 35 / 7 = 5 hours distance travelled by sam = 5 * 5 = 25 miles = c | physics |
math_qa__XWY2FCKd2fe59Y9F | A camera lens filter kit containing 5 filters sells for $72.50. If the filters are purchased individually, 2 of them are priced at $12.45 each, 2 at $14.05 each, 1 at $11.50. The amount saved by purchasing the kit is what percent of the total price of the 5 filters purchased individually? Pick one.
A) 10.03 % B) 11.03 % C) 12.03 % D) 13.03 % E) 11 % | <gadget id="calculator">2 * 12.45</gadget>
<output>24.9</output>
<gadget id="calculator">2 * 14.05</gadget>
<output>28.1</output>
<gadget id="calculator">24.9 + 28.1</gadget>
<output>53</output>
<gadget id="calculator">11.5 + 53</gadget>
<output>64.5</output>
<gadget id="calculator">72.5 - 64.5</gadget>
<output>8</output>
<gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">800 / 72.5</gadget>
<output>11.034483</output>
<result>B</result> | B | 11.03 | A camera lens filter kit containing 5 filters sells for $72.50. If the filters are purchased individually, 2 of them are priced at $12.45 each, 2 at $14.05 each, 1 at $11.50. The amount saved by purchasing the kit is what percent of the total price of the 5 filters purchased individually? | {
"A": "10.03 %",
"B": "11.03 %",
"C": "12.03 %",
"D": "13.03 %",
"E": "11 %"
} | divide(multiply(subtract(72.5, add(11.5, add(multiply(2, 12.45), multiply(2, 14.05)))), const_100), 72.5) | multiply(n2,n3)|multiply(n2,n5)|add(#0,#1)|add(n7,#2)|subtract(n1,#3)|multiply(#4,const_100)|divide(#5,n1) | cost of kit = $ 72.50 if filters are purchased individually - $ 12.45 * 2 + $ 14.05 * 2 + $ 11.50 = $ 64.50 amount saved = $ 72.50 - $ 64.50 = $ 8 required % age = ( $ 8 / $ 72.50 ) * 100 = 11.03 % so , the correct answer is b . | general |
math_qa__qAcmQnyJSKRuD7Gk | Every student in a room is either a junior or a senior. There is at least one junior and at least one senior in the room. If 1/2 of the juniors is equal to 2/3 of the seniors, what fraction of the students in the room are juniors?
Choose the correct option
A) 4 / 7 B) 1 / 3 C) 5 / 3 D) 12 / 7 E) 17 / 20 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<result>A</result> | A | 0.571429 | Every student in a room is either a junior or a senior. There is at least one junior and at least one senior in the room. If 1/2 of the juniors is equal to 2/3 of the seniors, what fraction of the students in the room are juniors? | {
"A": "4 / 7",
"B": "1 / 3",
"C": "5 / 3",
"D": "12 / 7",
"E": "17 / 20"
} | divide(multiply(2, 2), add(3, multiply(2, 2))) | multiply(n1,n1)|add(n3,#0)|divide(#0,#1) | let total number of juniors = j total number of seniors = s ( 1 / 2 ) j = ( 2 / 3 ) s = > s = 3 / 4 j total number of students = j + s = ( 7 / 4 ) j fraction of the students in the room are juniors = j / ( j + s ) = j / [ ( 7 / 4 ) j ] = 4 / 7 answer a | general |
math_qa__DWjgPRRBPu5A6wkd | In a certain alphabet, 10 letters contain a dot and a straight line. 24 letters contain a straight line but do not contain a dot. If that alphabet has 40 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line?
Choose one.
A) 6 B) 8 C) 14 D) 20 E) 28 | <gadget id="calculator">10 + 24</gadget>
<output>34</output>
<gadget id="calculator">40 - 34</gadget>
<output>6</output>
<result>A</result> | A | 6 | In a certain alphabet, 10 letters contain a dot and a straight line. 24 letters contain a straight line but do not contain a dot. If that alphabet has 40 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line? | {
"A": "6",
"B": "8",
"C": "14",
"D": "20",
"E": "28"
} | subtract(40, add(10, 24)) | add(n0,n1)|subtract(n2,#0) | we are told that all of the letters contain either a dot or a straight line or both , which implies that there are no letters without a dot and a line ( no line / no dot box = 0 ) . first we find the total # of letters with lines : 10 + 24 = 34 ; next , we find the total # of letters without line : 40 - 34 = 6 ; finally , we find the # of letters that contain a dot but do not contain a straight line : 6 - 0 = 6 . a | other |
math_qa__2rNAgakU0kICEt2E | A certain manufacturer increased its gross profit on a product from 10 percent of the cost of the product to 15 percent of the cost by changing the selling price. If the new selling price was $92.00 and the cost of the product remained the same, what was the old selling price?
Choose one.
A) $ 77.40 B) $ 80.00 C) $ 83.64 D) $ 87.40 E) $ 88.00 | <gadget id="calculator">10 + 100</gadget>
<output>110</output>
<gadget id="calculator">15 + 100</gadget>
<output>115</output>
<gadget id="calculator">110 / 115</gadget>
<output>22/23 = around 0.956522</output>
<gadget id="calculator">(22/23) * 92</gadget>
<output>88</output>
<result>E</result> | E | 88 | A certain manufacturer increased its gross profit on a product from 10 percent of the cost of the product to 15 percent of the cost by changing the selling price. If the new selling price was $92.00 and the cost of the product remained the same, what was the old selling price? | {
"A": "$ 77.40",
"B": "$ 80.00",
"C": "$ 83.64",
"D": "$ 87.40",
"E": "$ 88.00"
} | multiply(divide(add(10, const_100), add(15, const_100)), 92) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)|multiply(n2,#2) | given that { cost of the product } * 1.15 = $ 92 - - > { cost of the product } = $ 80 . the old price was $ 80 * 1.1 = $ 88 . answer : e . | gain |
math_qa__rYwQbu2HXhTsnssu | In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 65 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ?
Choose the correct choice from the following.
A) 50 %
B) 53 %
C) 54 %
D) 55 %
E) 47 % | <gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">60 * (13/20)</gadget>
<output>39</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">40 * (1/5)</gadget>
<output>8</output>
<gadget id="calculator">39 + 8</gadget>
<output>47</output>
<result>E</result> | E | 47 | In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 65 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ? | {
"A": "50 %",
"B": "53 %",
"C": "54 %",
"D": "55 %",
"E": "47 %"
} | add(multiply(60, divide(65, const_100)), multiply(subtract(const_100, 60), divide(20, const_100))) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_100,n0)|multiply(n0,#0)|multiply(#1,#2)|add(#3,#4)| | "say there are total of 100 registered voters in that city . thus 60 are democrats and 40 are republicans . 60 * 0.65 = 39 democrats are expected to vote for candidate a ; 40 * 0.20 = 8 republicans are expected to vote for candidate a . thus total of 39 + 8 = 47 registered voters are expected to vote for candidate a , which is 47 % of the total number of registered voters . answer : e ." | gain |
math_qa__OlBpq0QYEu8rnicN | The smallest number when increased by "2 " is exactly divisible by 12, 30, 48, 74 and 100 is: Choose the correct answer.
A) 14439 B) 44398 C) 44400 D) 44402 E) 15005 | <gadget id="calculator">lcm(12, 30)</gadget>
<output>60</output>
<gadget id="calculator">lcm(48, 74)</gadget>
<output>1_776</output>
<gadget id="calculator">lcm(60, 1_776)</gadget>
<output>8_880</output>
<gadget id="calculator">lcm(8_880, 100)</gadget>
<output>44_400</output>
<gadget id="calculator">44_400 + 2</gadget>
<output>44_402</output>
<result>B</result> | B | 44,398 | The smallest number when increased by "2 " is exactly divisible by 12, 30, 48, 74 and 100 is: | {
"A": "14439",
"B": "44398",
"C": "44400",
"D": "44402",
"E": "15005"
} | add(lcm(lcm(lcm(12, 30), lcm(48, 74)), 100), 2) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|lcm(n5,#2)|add(n0,#3)| | "lcm = 44400 44400 - 2 = 44398 answer : b" | general |
math_qa__w0g40bvEX5NTVljy | how many integers between 1 and 1400 are divisible by 25 , and 35 ? Choose the correct choice from the following options.
A) 4 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">lcm(25, 35)</gadget>
<output>175</output>
<gadget id="calculator">1_400 / 175</gadget>
<output>8</output>
<result>E</result> | E | 8 | how many integers between 1 and 1400 are divisible by 25 , and 35 ? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | divide(1400, lcm(25, 35)) | lcm(n2,n3)|divide(n1,#0) | lcm of the given numbers = 175 therefore , number of integers = 1400 / 175 = 8 answer is option e | general |
math_qa__nIh03jNDvQ3Twq0B | A semicircular cubicle has a radius of 14. What is the approximate perimeter of the cubicle? Choose the correct choice from the following answers
A) 55 B) 86 C) 25 D) 72 E) 35 | <gadget id="calculator">pi * 14</gadget>
<output>14*pi = around 43.982297</output>
<gadget id="calculator">2 * 14</gadget>
<output>28</output>
<gadget id="calculator">(14*pi) + 28</gadget>
<output>28 + 14*pi = around 71.982297</output>
<result>D</result> | D | 72 | A semicircular cubicle has a radius of 14. What is the approximate perimeter of the cubicle? | {
"A": "55",
"B": "86",
"C": "25",
"D": "72",
"E": "35"
} | add(multiply(const_pi, 14), multiply(const_2, 14)) | multiply(n0,const_pi)|multiply(n0,const_2)|add(#0,#1) | perimeter of a circle = 2 pi * r perimeter of a semicircle = pi * r + 2 r aprox perimiter = 3.14 * 14 + 2 * 14 = 71.96 approximately 72 answer d | geometry |
math_qa__mESatSIyffyKWQZM | A works thrice as much as B. If A takes 60 days less than B to do a work then find the number of days it would take to complete the work if both work together?
Options: A) 22.5 days B) 21.5 days C) 23.5 days D) 24.5 days E) 25.5 days | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">3 * 30</gadget>
<output>90</output>
<gadget id="calculator">1 / 90</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/90) + (1/30)</gadget>
<output>2/45 = around 0.044444</output>
<gadget id="calculator">1 / (2/45)</gadget>
<output>45/2 = around 22.5</output>
<result>A</result> | A | 22.5 | A works thrice as much as B. If A takes 60 days less than B to do a work then find the number of days it would take to complete the work if both work together? | {
"A": "22.5 days",
"B": "21.5 days",
"C": "23.5 days",
"D": "24.5 days",
"E": "25.5 days"
} | inverse(add(inverse(multiply(const_3, divide(60, subtract(const_3, const_1)))), inverse(divide(60, subtract(const_3, const_1))))) | subtract(const_3,const_1)|divide(n0,#0)|inverse(#1)|multiply(#1,const_3)|inverse(#3)|add(#4,#2)|inverse(#5) | if a finishes the job in x days b finishes it in 3 x days 3 x = x + 60 thus x = 30 in one hour 1 / t = 1 / 30 + 1 / 90 = 4 / 90 where t is the number of days they finish the job together . t = 90 / 4 = 22.5 days answer : a | physics |
math_qa__eTDrC2VifhuzhIkr | A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price t of the machine?
Select.
A) 81 B) 100 C) 120 D) 135 E) 160 | <gadget id="calculator">90 * 20</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">90 + 18</gadget>
<output>108</output>
<gadget id="calculator">108 * 100</gadget>
<output>10_800</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">10_800 / 90</gadget>
<output>120</output>
<result>C</result> | C | 120 | A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price t of the machine? | {
"A": "81",
"B": "100",
"C": "120",
"D": "135",
"E": "160"
} | divide(multiply(add(90, divide(multiply(90, 20), const_100)), const_100), multiply(multiply(const_3, const_3), 10)) | multiply(n0,n2)|multiply(const_3,const_3)|divide(#0,const_100)|multiply(n1,#1)|add(n0,#2)|multiply(#4,const_100)|divide(#5,#3)| | "since the wholesale price was $ 90 and the profit was 20 % of the wholesale price ( [ . 2 ] [ 90 ] = $ 18 ) , the retail price would have to be above $ 108 , but not that much greater than that . let ' s start by testing answer c : $ 120 . . . . if . . . . . retail price t = $ 120 10 % discount off = $ 120 - ( . 1 ) ( 120 ) = 120 - 12 = 108 20 % profit on wholesale price = 90 + ( . 2 ) ( 90 ) = 90 + 18 = 108 these two numbers match , so this must be the answer ! final answer : [ reveal ] spoiler : c" | gain |
math_qa__dBknBPXcJtWB3ehD | In a certain company, a third of the workers do not have a retirement plan. 20% of the workers who do not have a retirement plan are women, and 40% of the workers who do have a retirement plan are men. If 128 of the workers of that company are men, how many of the workers are women? Pick one.
A) 80 B) 95 C) 105 D) 112 E) 210 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/3) * (1/5)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/3) - (1/15)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/3) * (2/5)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">(4/15) + (4/15)</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">128 / (8/15)</gadget>
<output>240</output>
<gadget id="calculator">(2/3) - (4/15)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/15) + (2/5)</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">240 * (7/15)</gadget>
<output>112</output>
<result>D</result> | D | 112 | In a certain company, a third of the workers do not have a retirement plan. 20% of the workers who do not have a retirement plan are women, and 40% of the workers who do have a retirement plan are men. If 128 of the workers of that company are men, how many of the workers are women? | {
"A": "80",
"B": "95",
"C": "105",
"D": "112",
"E": "210"
} | multiply(divide(128, add(subtract(divide(const_1, const_3), multiply(divide(const_1, const_3), divide(20, const_100))), multiply(subtract(const_1, divide(const_1, const_3)), divide(40, const_100)))), add(multiply(divide(const_1, const_3), divide(20, const_100)), subtract(subtract(const_1, divide(const_1, const_3)), multiply(subtract(const_1, divide(const_1, const_3)), divide(40, const_100))))) | divide(const_1,const_3)|divide(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|subtract(const_1,#0)|multiply(#2,#4)|subtract(#0,#3)|add(#5,#6)|subtract(#4,#5)|add(#3,#8)|divide(n2,#7)|multiply(#9,#10)| | "set up equation : x = total number of workers 128 = 0,4 * 2 / 3 * x + 0,8 * 1 / 3 * x 128 = 16 / 30 x x = 240 240 - 128 = 112 answer d" | gain |
math_qa__fJnC9h8xro3nl60o | Calculate the number of urns of water needed to fill a tank of dimensions of 10x10x5m to 90% full, if the volume of the urn is 0.8m3 and can only be filled to 80%. Answers: A) 520 B) 650.2 C) 685.5 D) 703.1 E) 712.2 | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">100 * 5</gadget>
<output>500</output>
<gadget id="calculator">500 * 90</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 100</gadget>
<output>450</output>
<gadget id="calculator">0.8 * 80</gadget>
<output>64</output>
<gadget id="calculator">64 / 100</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">450 / (16/25)</gadget>
<output>5_625/8 = around 703.125</output>
<result>D</result> | D | 703.1 | Calculate the number of urns of water needed to fill a tank of dimensions of 10x10x5m to 90% full, if the volume of the urn is 0.8m3 and can only be filled to 80%. | {
"A": "520",
"B": "650.2",
"C": "685.5",
"D": "703.1",
"E": "712.2"
} | divide(divide(multiply(multiply(multiply(10, 10), 5), 90), const_100), divide(multiply(0.8, 80), const_100)) | multiply(n0,n0)|multiply(n4,n6)|divide(#1,const_100)|multiply(n2,#0)|multiply(n3,#3)|divide(#4,const_100)|divide(#5,#2) | volume of the tank that needed to be filled = 10 x 10 x 5 x 0.9 = 450 volume of the urn that can be filled = 0.8 x 0.8 = 0.64 no . of urns of water needed to fill the tank = 450 / 0.64 = 703.1 answer : d | physics |
math_qa__mWPOIFuWyao3tlfD | A batsman makes a score of 92 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning.
Pick:
A) 36 B) 39 C) 42 D) 44 E) none of the above | <gadget id="calculator">17 * 3</gadget>
<output>51</output>
<gadget id="calculator">92 - 51</gadget>
<output>41</output>
<gadget id="calculator">41 + 3</gadget>
<output>44</output>
<result>D</result> | D | 44 | A batsman makes a score of 92 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning. | {
"A": "36",
"B": "39",
"C": "42",
"D": "44",
"E": "none of the above"
} | add(subtract(92, multiply(17, 3)), 3) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "let the average after 17 th inning = x . then , average after 16 th inning = ( x – 3 ) . ∴ 16 ( x – 3 ) + 92 = 17 x or x = ( 92 – 48 ) = 44 . answer d" | general |
math_qa__cFzm819QycTPU65B | A tank can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tank from empty state if B is used for the first half time and then A and B fill it together for the other half. Select the correct option:
A) 15 mins B) 20 mins C) 25 mins D) 30 mins E) 35 mins | <gadget id="calculator">40 * 3</gadget>
<output>120</output>
<gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">240 / 8</gadget>
<output>30</output>
<result>D</result> | D | 30 | A tank can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tank from empty state if B is used for the first half time and then A and B fill it together for the other half. | {
"A": "15 mins",
"B": "20 mins",
"C": "25 mins",
"D": "30 mins",
"E": "35 mins"
} | divide(multiply(multiply(40, const_3), const_2), add(const_4, const_4)) | add(const_4,const_4)|multiply(n1,const_3)|multiply(#1,const_2)|divide(#2,#0) | explanation : let the total time be x mins . part filled in first half means in x / 2 = 1 / 40 part filled in second half means in x / 2 = 1 / 60 + 1 / 40 = 1 / 24 total = x / 2 x 1 / 40 + x / 2 x 1 / 24 = 1 x = 30 mins answer is d | physics |
math_qa__KdU79fI1q6kGCKgB | In a division sum, the quotient is 65, the divisor 24 and the remainder 5, find the dividend? Choices
A) 1595 B) 1569 C) 1265 D) 1555 E) 1565 | <gadget id="calculator">65 * 24</gadget>
<output>1_560</output>
<gadget id="calculator">1_560 + 5</gadget>
<output>1_565</output>
<result>E</result> | E | 1,565 | In a division sum, the quotient is 65, the divisor 24 and the remainder 5, find the dividend? | {
"A": "1595",
"B": "1569",
"C": "1265",
"D": "1555",
"E": "1565"
} | add(multiply(65, 24), 5) | multiply(n0,n1)|add(n2,#0)| | "explanation : 65 * 24 + 5 = 1565 answer : e" | general |
math_qa__rvhkVpBR6IS2SheT | The length of a rectangular field is 7/5 its width. If the perimeter of the field is 240 meters, what is the width of the field? Choose the correct choice from the following answers:
A) 50
B) 60
C) 70
D) 80
E) 90 | <gadget id="calculator">7 / 5</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) + (7/5)</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">(14/5) + 2</gadget>
<output>24/5 = around 4.8</output>
<gadget id="calculator">240 / (24/5)</gadget>
<output>50</output>
<result>A</result> | A | 50 | The length of a rectangular field is 7/5 its width. If the perimeter of the field is 240 meters, what is the width of the field? | {
"A": "50",
"B": "60",
"C": "70",
"D": "80",
"E": "90"
} | divide(240, add(add(divide(7, 5), divide(7, 5)), const_2)) | divide(n0,n1)|add(#0,#0)|add(#1,const_2)|divide(n2,#2)| | "let l be the length and w be the width . l = ( 7 / 5 ) w perimeter : 2 l + 2 w = 240 , 2 ( 7 / 5 ) w + 2 w = 240 solve the above equation to find : w = 50 m and l = 70 m . correct answer a ) 50" | geometry |
math_qa__4PdoHRQ7x7oRpu8e | At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 10 pencils and 8 charts have been brought to the meeting, how many people are present? Choose the correct choice from the following
A) 6
B) 7
C) 8
D) 9
E) 10 | <gadget id="calculator">8 + 10</gadget>
<output>18</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">18 / 3</gadget>
<output>6</output>
<result>A</result> | A | 6 | At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 10 pencils and 8 charts have been brought to the meeting, how many people are present? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | divide(add(8, 10), add(2, 1)) | add(n4,n5)|add(n0,n1)|divide(#0,#1)| | "say there are ' a ' associate professors . so we have 2 a pencils and a charts . say there are ' b ' assistant professors . so we have b pencils and 2 b charts . total pencils are 10 so 2 a + b = 10 total charts are 11 so a + 2 b = 8 add both : 3 a + 3 b = 18 so a + b = 6 total number of people = 6 a" | general |
math_qa__dD1JZeEj2vtGhs15 | It is the New Year and Mandy has made a resolution to lose weight this year. She plans to exercise and do yoga. For exercise she plans to workout at the gym and ride her bicycle in the ratio of 2:3 everyday. She will also do yoga in the ratio, yoga:exercise = 2:3. If she rides her bike for 14 minutes, how much time will she spend doing yoga? (rounded to minutes) Options
A) 10 min . B) 41 min . C) 17 min . D) 23 min . E) 25 min . | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">14 * (3/5)</gadget>
<output>42/5 = around 8.4</output>
<gadget id="calculator">(3/5) * (3/5)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(42/5) / (9/25)</gadget>
<output>70/3 = around 23.333333</output>
<result>D</result> | D | 23 | It is the New Year and Mandy has made a resolution to lose weight this year. She plans to exercise and do yoga. For exercise she plans to workout at the gym and ride her bicycle in the ratio of 2:3 everyday. She will also do yoga in the ratio, yoga:exercise = 2:3. If she rides her bike for 14 minutes, how much time will she spend doing yoga? (rounded to minutes) | {
"A": "10 min .",
"B": "41 min .",
"C": "17 min .",
"D": "23 min .",
"E": "25 min ."
} | divide(multiply(14, divide(3, add(2, 3))), multiply(divide(3, add(2, 3)), divide(3, add(2, 3)))) | add(n0,n1)|divide(n1,#0)|multiply(n4,#1)|multiply(#1,#1)|divide(#2,#3)| | "the ratio is 2 : 3 = gym : ride , so ( 14 ) ( 3 / 2 ) = 21 minutes at the gym , and 21 + 14 = 35 minutes exercise , so ( 2 / 3 ) ( 35 ) = 23 minutes yoga . answer : d" | physics |
math_qa__nvZnNvzWyzvL6v0o | Jim’s Taxi Service charges an initial fee of $2.25 at the beginning of a trip and an additional charge of $0.4 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles? Choose one
A) $ 3.15 B) $ 4.45 C) $ 4.80 D) $ 5.05 E) $ 5.85 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3.6 / (2/5)</gadget>
<output>9</output>
<gadget id="calculator">9 * 0.4</gadget>
<output>3.6</output>
<gadget id="calculator">3.6 + 2.25</gadget>
<output>5.85</output>
<result>E</result> | E | 5.85 | Jim’s Taxi Service charges an initial fee of $2.25 at the beginning of a trip and an additional charge of $0.4 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles? | {
"A": "$ 3.15",
"B": "$ 4.45",
"C": "$ 4.80",
"D": "$ 5.05",
"E": "$ 5.85"
} | add(multiply(divide(3.6, divide(2, 5)), 0.4), 2.25) | divide(n2,n3)|divide(n4,#0)|multiply(n1,#1)|add(n0,#2)| | "let the fixed charge of jim â € ™ s taxi service = 2.25 $ and charge per 2 / 5 mile ( . 4 mile ) = . 4 $ total charge for a trip of 3.6 miles = 2.25 + ( 3.6 / . 4 ) * . 4 = 2.25 + 9 * . 4 = 5.85 $ answer e" | general |
math_qa__rzoFDS8tXQxPacQr | In a market, a dozen eggs cost as much as a pound of rice, and a half-liter of kerosene costs as much as 8 eggs. If the cost of each pound of rice is $0.33, then how many W cents does a liter of kerosene cost? [One dollar has 100 cents.] Choices.
A) 0.33 B) 0.44 C) 0.55 D) 44 E) 55 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">8 / (1/2)</gadget>
<output>16</output>
<gadget id="calculator">16 / 12</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">0.33 * 100</gadget>
<output>33</output>
<gadget id="calculator">(4/3) * 33</gadget>
<output>44</output>
<result>D</result> | D | 44 | In a market, a dozen eggs cost as much as a pound of rice, and a half-liter of kerosene costs as much as 8 eggs. If the cost of each pound of rice is $0.33, then how many W cents does a liter of kerosene cost? [One dollar has 100 cents.] | {
"A": "0.33",
"B": "0.44",
"C": "0.55",
"D": "44",
"E": "55"
} | multiply(divide(divide(8, divide(const_1, const_2)), const_12), multiply(0.33, 100)) | divide(const_1,const_2)|multiply(n1,n2)|divide(n0,#0)|divide(#2,const_12)|multiply(#3,#1)| | "main thing to remember is answer is asked in cents , however when we calculate , it comes up as 0.44 $ just multiply by 100 , answer w = 44 . d" | general |
math_qa__KSiDtlChP5BMUbo3 | A two digit number is 18 less than the square of the sum of its digits. How many such numbers are there? Choose the correct choice
A) 2233
B) 2222
C) 2211
D) 6382
E) 23,17 | <gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">50 * 10</gadget>
<output>500</output>
<gadget id="calculator">18 ** 3</gadget>
<output>5_832</output>
<gadget id="calculator">500 + 5_832</gadget>
<output>6_332</output>
<result>D</result> | D | 6,382 | A two digit number is 18 less than the square of the sum of its digits. How many such numbers are there? | {
"A": "2233",
"B": "2222",
"C": "2211",
"D": "6382",
"E": "23,17"
} | add(multiply(divide(const_100, const_2), const_10), power(18, const_3)) | divide(const_100,const_2)|power(n0,const_3)|multiply(#0,const_10)|add(#2,#1) | option 2 take n = 10 a + b . given that , ( 10 a + b ) + 18 = k 2 = ( a + b ) 2 given number = k 2 - 18 = ( 10 a + b ) that means , when we add 18 to the given number it should be a perfect square . so k 2 takes the following values . 1 , 4 , 9 , 16 , 25 , 36 , 49 , 64 , 81 , 100 , 121 , . . . . 1 to 16 are ruled out as if we subtract 18 from them , the resulting number is a single digit number . now 25 - 18 = 7 36 - 18 = 18 49 - 18 = 31 64 - 18 = 46 81 - 18 = 63 100 - 18 = 82 121 - 18 = 103 now 63 , 82 satisfies . answer : d | general |
math_qa__JONYi0ttWKNVSvIO | Two cubes of their volumes in the ratio 343 : 729. The ratio of their surface area is: Choose the correct choice from the following answers: A) 7 : 9 B) 2 : 5 C) 3 : 5 D) 1 : 5 E) 4 : 5 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">343 ** (1/3)</gadget>
<output>7</output>
<gadget id="calculator">729 ** (1/3)</gadget>
<output>9</output>
<gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>
<result>A</result> | A | 0.777778 | Two cubes of their volumes in the ratio 343 : 729. The ratio of their surface area is: | {
"A": "7 : 9",
"B": "2 : 5",
"C": "3 : 5",
"D": "1 : 5",
"E": "4 : 5"
} | divide(power(343, const_0_33), power(729, const_0_33)) | power(n0,const_0_33)|power(n1,const_0_33)|divide(#0,#1)| | "the ratio of their surface area is 343 : 729 7 : 9 answer is a ." | geometry |
math_qa__kL3LB40lSAjC4wCQ | A can complete a project in 20 days and B can complete the same project in 20 days. If A and B start working on the project together and A quits 10 days before the project is completed, in how many days will the project be completed? Pick one.
A) 18 days B) 27 days C) 26.67 days D) 16 days E) 15 days | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/20) + (1/20)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/2) / (1/10)</gadget>
<output>5</output>
<gadget id="calculator">5 + 10</gadget>
<output>15</output>
<result>E</result> | E | 15 | A can complete a project in 20 days and B can complete the same project in 20 days. If A and B start working on the project together and A quits 10 days before the project is completed, in how many days will the project be completed? | {
"A": "18 days",
"B": "27 days",
"C": "26.67 days",
"D": "16 days",
"E": "15 days"
} | add(divide(subtract(const_1, multiply(divide(const_1, 20), 10)), add(divide(const_1, 20), divide(const_1, 20))), 10) | divide(const_1,n1)|divide(const_1,n0)|add(#1,#0)|multiply(n2,#0)|subtract(const_1,#3)|divide(#4,#2)|add(n2,#5)| | "let x = the number of days taken to complete the project . the amount of work done by a is ( x - 10 ) * ( 1 / 20 ) . the amount of work done by b is ( x ) * ( 1 / 30 ) . ( 1 / 20 ) * ( x - 10 ) + ( 1 / 20 ) * ( x ) = 1 ( x / 20 ) + ( x / 20 ) - ( 10 / 20 ) = 1 x / 10 = 3 / 2 x = 15 therefore , the answer is e : 15 ." | physics |
math_qa__GiKdcADrJC2j69OF | A train 120 meters long takes 6 seconds to cross a man walking at 5 kmph in the direction opposite to that of the train. Find the speed of the train. Choose one: A) 67 kmph B) 50 kmph C) 55 kmph D) 60 kmph E) 70 kmph | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">6 * (5/18)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">120 / (5/3)</gadget>
<output>72</output>
<gadget id="calculator">72 - 5</gadget>
<output>67</output>
<result>A</result> | A | 67 | A train 120 meters long takes 6 seconds to cross a man walking at 5 kmph in the direction opposite to that of the train. Find the speed of the train. | {
"A": "67 kmph",
"B": "50 kmph",
"C": "55 kmph",
"D": "60 kmph",
"E": "70 kmph"
} | subtract(divide(120, multiply(6, const_0_2778)), 5) | multiply(n1,const_0_2778)|divide(n0,#0)|subtract(#1,n2)| | "explanation : let the speed of the train be x kmph . speed of the train relative to man = ( x + 5 ) kmph = ( x + 5 ) × 5 / 18 m / sec . therefore 120 / ( ( x + 5 ) × 5 / 18 ) = 6 < = > 30 ( x + 5 ) = 2160 < = > x = 67 speed of the train is 67 kmph . answer : option a" | physics |
math_qa__dg2TE53xIg53Ed3M | A small company reduced its faculty by approximately 13 percent to 195 employees. What was the original number of employees? Answers.
A) 182 B) 208 C) 220 D) 224 E) 302 | <gadget id="calculator">100 - 13</gadget>
<output>87</output>
<gadget id="calculator">87 / 100</gadget>
<output>87/100 = around 0.87</output>
<gadget id="calculator">195 / (87/100)</gadget>
<output>6_500/29 = around 224.137931</output>
<result>D</result> | D | 224 | A small company reduced its faculty by approximately 13 percent to 195 employees. What was the original number of employees? | {
"A": "182",
"B": "208",
"C": "220",
"D": "224",
"E": "302"
} | divide(195, divide(subtract(const_100, 13), const_100)) | subtract(const_100,n0)|divide(#0,const_100)|divide(n1,#1)| | "if x is the original number of employees , then after 13 % reduction in employees number is . 87 x but we are given . 87 x = 195 x = 224 so the original number of employees is 224 correct answer - d" | gain |
math_qa__Qb1MIYMPkuSk1dPr | Population is 22000. Population increases by 10% every year, then the population after 3 years is?
Choose the correct answer
A) 26630 B) 29282 C) 36620 D) 26620 E) 26820 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">22_000 * (13/10)</gadget>
<output>28_600</output>
<result>B</result> | B | 29,282 | Population is 22000. Population increases by 10% every year, then the population after 3 years is? | {
"A": "26630",
"B": "29282",
"C": "36620",
"D": "26620",
"E": "26820"
} | multiply(22000, add(const_1, divide(multiply(3, 10), const_100))) | multiply(n1,n2)|divide(#0,const_100)|add(#1,const_1)|multiply(n0,#2)| | "population after 1 st year = 22000 * 10 / 100 = 2200 = = = > 22000 + 2200 = 24000 population after 2 nd year = 24000 * 10 / 100 = 2400 = = = > 24000 + 2400 = 26620 population after 3 rd year = 26620 * 10 / 100 = 2662 = = = > 26620 + 2662 = 29282 answer : b" | gain |
math_qa__rs8d5emF8ppOGPVE | (26.3 * 12 * 20)/3+125 = ? Choices: A) 2339 B) 2229 C) 4429 D) 5529 E) 2669 | <gadget id="calculator">26.3 * 12</gadget>
<output>315.6</output>
<gadget id="calculator">315.6 * 20</gadget>
<output>6_312</output>
<gadget id="calculator">6_312 / 3</gadget>
<output>2_104</output>
<gadget id="calculator">2_104 + 125</gadget>
<output>2_229</output>
<result>B</result> | B | 2,229 | (26.3 * 12 * 20)/3+125 = ? | {
"A": "2339",
"B": "2229",
"C": "4429",
"D": "5529",
"E": "2669"
} | add(divide(multiply(multiply(26.3, 12), 20), const_3), 125) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_3)|add(n4,#2) | b 2229 ? = [ ( 26.3 * 12 * 20 ) / 3 ] + 125 ? = 2104 + 125 = 2229 | general |
math_qa__DAzDgxlBEk0ZG5Xx | Rectangular tile each of size 45cm by 50cm must be laid horizontally on a rectangular floor of size 250cm by 180cm,such that the tiles do not overlap and they are placed with edges jutting against each other on all edges. A tile can be placed in any orientation so long as its edges are parallel to the edges of floor. No tile should overshoot any edge of the floor. The maximum number of tiles that can be accommodated on the floor is:
Pick one:
A) 35 B) 40 C) 25 D) 18 E) 20 | <gadget id="calculator">250 * 180</gadget>
<output>45_000</output>
<gadget id="calculator">45 * 50</gadget>
<output>2_250</output>
<gadget id="calculator">45_000 / 2_250</gadget>
<output>20</output>
<result>E</result> | E | 20 | Rectangular tile each of size 45cm by 50cm must be laid horizontally on a rectangular floor of size 250cm by 180cm,such that the tiles do not overlap and they are placed with edges jutting against each other on all edges. A tile can be placed in any orientation so long as its edges are parallel to the edges of floor. No tile should overshoot any edge of the floor. The maximum number of tiles that can be accommodated on the floor is: | {
"A": "35",
"B": "40",
"C": "25",
"D": "18",
"E": "20"
} | divide(multiply(250, 180), multiply(45, 50)) | multiply(n2,n3)|multiply(n0,n1)|divide(#0,#1)| | "area of tile = 45 * 50 = 2250 area of floor = 250 * 180 = 45000 no of tiles = 45000 / 2250 = 20 so , the no of tile = 20 answer : e" | geometry |
math_qa__oFG2dC2SKV8byBGF | If 15 people contributed a total of $30.00 toward a gift and each of them contributed at least $1.00, then the maximum possible amount any one person could have contributed is Choose the correct choice from the following choices.
A) $ 1.00 B) $ 16 C) $ 5.00 D) $ 6.00 E) $ 20.00 | <gadget id="calculator">15 - 1</gadget>
<output>14</output>
<gadget id="calculator">14 * 1</gadget>
<output>14</output>
<gadget id="calculator">30 - 14</gadget>
<output>16</output>
<result>B</result> | B | 16 | If 15 people contributed a total of $30.00 toward a gift and each of them contributed at least $1.00, then the maximum possible amount any one person could have contributed is | {
"A": "$ 1.00",
"B": "$ 16",
"C": "$ 5.00",
"D": "$ 6.00",
"E": "$ 20.00"
} | subtract(30.00, multiply(subtract(15, 1.00), 1.00)) | subtract(n0,n2)|multiply(n2,#0)|subtract(n1,#1)| | "b for me 14 people with 1 $ each - > maximum = 16" | general |
math_qa__vXhRGir2cGnuI5Jg | A water tank, having the shape of a rectangular prism of base 100 square centimeters, is being filled at the rate of 1 liter per minute. Find the rate at which the height of the water in the water tank increases. Express your answer in centimeters per minute. Pick one.
A) 30 cm
B) 10 cm
C) 50 cm
D) 90 cm
E) 70 cm | <gadget id="calculator">1_000 / 100</gadget>
<output>10</output>
<result>B</result> | B | 10 | A water tank, having the shape of a rectangular prism of base 100 square centimeters, is being filled at the rate of 1 liter per minute. Find the rate at which the height of the water in the water tank increases. Express your answer in centimeters per minute. | {
"A": "30 cm",
"B": "10 cm",
"C": "50 cm",
"D": "90 cm",
"E": "70 cm"
} | divide(const_1000, 100) | divide(const_1000,n0) | the volume of a rectangular prism is given by area of base ? height the rate at which the tank is being filled is 1 liter per minute which we need to convert 1 liter = 1 dm 3 but 1 dm = 10 cm . hence 1 liter = ( 10 cm ) 3 = 1000 cm 3 the height h of the water is related to the volume by volume = area of base * h in one minute the volume increases by 1 liter or 1000 cm 3 and the height increases by h = volume / area of base = 1000 cm 3 / 100 cm 2 = 10 cm correct answer b | geometry |
math_qa__Z3q4TzzWStdMO0fg | The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 72. What is the difference between the two digits of that number? Choose the correct choice:
A) 4 B) 5 C) 6 D) 8 E) 9 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">72 / 9</gadget>
<output>8</output>
<result>D</result> | D | 8 | The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 72. What is the difference between the two digits of that number? | {
"A": "4",
"B": "5",
"C": "6",
"D": "8",
"E": "9"
} | divide(72, subtract(const_10, const_1)) | subtract(const_10,const_1)|divide(n0,#0)| | "sol . let the ten ’ s digit be x and unit ’ s digit be y , then , ( 10 x + y ) - ( 10 y + x ) = 72 ⇔ 9 ( x - y ) = 72 ⇔ x - y = 8 answer d" | general |
math_qa__RBKJEQubupMLvZSI | Machine A can put caps on a set of bottles in 8 hours at a constant rate. If Machine A does the job for 6 hours and Machine B does the rest of the job, which works at 1/4 constant rate of Machine A. How long will it take for Machine B alone to do the rest of the job? Choose one: A) 4 hrs B) 6 hrs C) 8 hrs D) 10 hrs E) 16 hrs | <gadget id="calculator">6 / 8</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/8) * (1/4)</gadget>
<output>1/32 = around 0.03125</output>
<gadget id="calculator">1 / (1/32)</gadget>
<output>32</output>
<gadget id="calculator">(1/4) * 32</gadget>
<output>8</output>
<result>C</result> | C | 8 | Machine A can put caps on a set of bottles in 8 hours at a constant rate. If Machine A does the job for 6 hours and Machine B does the rest of the job, which works at 1/4 constant rate of Machine A. How long will it take for Machine B alone to do the rest of the job? | {
"A": "4 hrs",
"B": "6 hrs",
"C": "8 hrs",
"D": "10 hrs",
"E": "16 hrs"
} | multiply(subtract(const_1, divide(6, 8)), inverse(multiply(inverse(8), inverse(4)))) | divide(n1,n0)|inverse(n0)|inverse(n3)|multiply(#1,#2)|subtract(const_1,#0)|inverse(#3)|multiply(#5,#4) | machine a will do 6 / 8 in 6 hrs , so a does 3 / 4 of the work . . therefore , b will do the remaining 1 / 4 th work alone . . as the speed of b is 1 / 4 rate of a , b will do the 1 / 4 th work in same time that a takes to complete full job . . . ans 8 c | physics |
math_qa__LKbVjbC6kt4taaPs | A’s speed is 16/15 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat? Pick.
A) 1 / 8 B) 1 / 16 C) 1 / 15 D) 1 / 32 E) 1 / 31 | <gadget id="calculator">16 - 15</gadget>
<output>1</output>
<gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<result>B</result> | B | 0.0625 | A’s speed is 16/15 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat? | {
"A": "1 / 8",
"B": "1 / 16",
"C": "1 / 15",
"D": "1 / 32",
"E": "1 / 31"
} | divide(subtract(16, 15), 16) | subtract(n0,n1)|divide(#0,n0)| | "let x be the fraction of the distance that b runs . let v be the speed at which b runs . the time should be the same for both runners . time = d / ( 16 v / 15 ) = xd / v ( 15 / 16 ) * d / v = x * d / v x = 15 / 16 b should have a head start of 1 / 16 of the full distance . the answer is b ." | general |
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