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math_qa__ohbMTNfuWZteiaRD | in a group of 68 students , each student is registered for at least one of 3 classes – history , math and english . 20 - one students are registered for history , 20 - 6 students are registered for math , and thirty - 4 students are registered for english . if only 3 students are registered for all 3 classes , how many students are registered for exactly two classes ?
Choose the correct choice from the following answers:
A) 13 B) 10 C) 9 D) 8 E) 7 | <gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">20 + 6</gadget>
<output>26</output>
<gadget id="calculator">21 + 26</gadget>
<output>47</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">30 + 4</gadget>
<output>34</output>
<gadget id="calculator">47 + 34</gadget>
<output>81</output>
<gadget id="calculator">81 - 68</gadget>
<output>13</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">13 - 6</gadget>
<output>7</output>
<result>E</result> | E | 7 | in a group of 68 students , each student is registered for at least one of 3 classes – history , math and english . 20 - one students are registered for history , 20 - 6 students are registered for math , and thirty - 4 students are registered for english . if only 3 students are registered for all 3 classes , how many students are registered for exactly two classes ? | {
"A": "13",
"B": "10",
"C": "9",
"D": "8",
"E": "7"
} | subtract(subtract(add(add(add(20, const_1), add(20, 6)), add(add(20, const_10), 4)), 68), multiply(const_2, 3)) | add(n2,const_1)|add(n2,n4)|add(n2,const_10)|multiply(n1,const_2)|add(#0,#1)|add(n5,#2)|add(#4,#5)|subtract(#6,n0)|subtract(#7,#3) | a u b u c = a + b + c - ab - bc - ac + abc 68 = 21 + 26 + 34 - ab - bc - ac + 3 = > ab + bc + ac = 16 exactly two classes = ab + bc + ac - 3 abc = 16 - 3 * 3 = 7 hence e | general |
math_qa__QrFM6Y7SntBD8Hnc | 210 reputed college students were asked in a survey if they preferred Windows or Mac brand computers. 60 Students claimed that they preferred Mac to Windows brand computers. One third as many of the students who preferred Mac to Windows, equally preferred both brands. 90 of the students had no preference. How many of the students in the survey preferred Windows to Mac brand computers?
Choose the correct answer:
A) 25
B) 40
C) 50
D) 60
E) 75 | <gadget id="calculator">60 + 90</gadget>
<output>150</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<gadget id="calculator">150 + 20</gadget>
<output>170</output>
<gadget id="calculator">210 - 170</gadget>
<output>40</output>
<result>B</result> | B | 40 | 210 reputed college students were asked in a survey if they preferred Windows or Mac brand computers. 60 Students claimed that they preferred Mac to Windows brand computers. One third as many of the students who preferred Mac to Windows, equally preferred both brands. 90 of the students had no preference. How many of the students in the survey preferred Windows to Mac brand computers? | {
"A": "25",
"B": "40",
"C": "50",
"D": "60",
"E": "75"
} | subtract(210, add(add(60, 90), divide(60, const_3))) | add(n1,n2)|divide(n1,const_3)|add(#0,#1)|subtract(n0,#2) | we are told that 60 students claimed that they preferred mac to windows , which means that 60 preferred mac but not windows , so # of students who preferred mac ( p ( a ) as you wrote ) , does not equal to 60 , it equals to 60 + 20 ( 20 is # of students who equally preferred both brands ) . also we are asked to find # of the students who preferred windows to mac , so if you denote x as those who prefer windows then you should calculate x - 20 . so , if we use your formula it should be : 210 = { mac } + { windows } - { both } + { neither } = ( 60 + 20 ) + x - 20 + 90 - - > x = 60 ( # of student who prefer windows ) - - > # of the students who preferred windows to mac is x - 20 = 40 . | other |
math_qa__27izTCrf9vG6hCvN | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 18 kmph, find the speed of the stream?
Options:
A) 8 kmph B) 9 kmph C) 7 kmph D) 6 kmph E) 5 kmph | <gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">36 / 3</gadget>
<output>12</output>
<gadget id="calculator">18 - 12</gadget>
<output>6</output>
<result>D</result> | D | 6 | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 18 kmph, find the speed of the stream? | {
"A": "8 kmph",
"B": "9 kmph",
"C": "7 kmph",
"D": "6 kmph",
"E": "5 kmph"
} | subtract(18, divide(multiply(18, const_2), const_3)) | multiply(n0,const_2)|divide(#0,const_3)|subtract(n0,#1)| | "the ratio of the times taken is 2 : 1 . the ratio of the speed of the boat in still water to the speed of the stream = ( 2 + 1 ) / ( 2 - 1 ) = 3 / 1 = 3 : 1 speed of the stream = 18 / 3 = 6 kmph . answer : d" | physics |
math_qa__WorxSSebXQ36PQEp | A mathematics teacher tabulated the marks secured by 35 students of 8th class. The average of their marks was 62. If the marks secured by Reema was written as 50 instead of 85 then find the correct average marks up to two decimal places. Choose the correct choice from the following.
A) 63 B) 74.31 C) 72.43 D) 73.43 E) can not be determined | <gadget id="calculator">35 * 62</gadget>
<output>2_170</output>
<gadget id="calculator">85 - 50</gadget>
<output>35</output>
<gadget id="calculator">2_170 - 35</gadget>
<output>2_135</output>
<gadget id="calculator">2_135 / 35</gadget>
<output>61</output>
<result>A</result> | A | 63 | A mathematics teacher tabulated the marks secured by 35 students of 8th class. The average of their marks was 62. If the marks secured by Reema was written as 50 instead of 85 then find the correct average marks up to two decimal places. | {
"A": "63",
"B": "74.31",
"C": "72.43",
"D": "73.43",
"E": "can not be determined"
} | divide(subtract(multiply(35, 62), subtract(85, 50)), 35) | multiply(n0,n2)|subtract(n4,n3)|subtract(#0,#1)|divide(#2,n0)| | "total marks = 35 x 62 = 2170 corrected total marks = 2170 - 50 + 85 = 2205 correct average = 2205 / 35 = 63 answer : a" | general |
math_qa__04Fm3uVLMlZ6Hwta | 63 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day?
Pick one:
A) 87
B) 77
C) 66
D) 55
E) 97 | <gadget id="calculator">63 * 8</gadget>
<output>504</output>
<gadget id="calculator">504 / 30</gadget>
<output>84/5 = around 16.8</output>
<gadget id="calculator">(84/5) * 50</gadget>
<output>840</output>
<gadget id="calculator">840 / 6</gadget>
<output>140</output>
<gadget id="calculator">140 - 63</gadget>
<output>77</output>
<result>B</result> | B | 77 | 63 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day? | {
"A": "87",
"B": "77",
"C": "66",
"D": "55",
"E": "97"
} | subtract(divide(multiply(divide(multiply(63, 8), 30), 50), 6), 63) | multiply(n0,n1)|divide(#0,n2)|multiply(n3,#1)|divide(#2,n4)|subtract(#3,n0)| | "( 63 * 8 ) / 30 = ( x * 6 ) / 50 = > x = 140 140 – 63 = 77 answer : b" | physics |
math_qa__cB3k40II1V2e98p0 | If x is to be chosen at random from the set {1, 2, 3, 4} and y is to be chosen at random from the set {5, 6, 7}, what is the probability that xy will be odd? Choose one:
A) 1 / 6 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 5 / 6 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">binomial(4, 2)</gadget>
<output>6</output>
<gadget id="calculator">binomial(2, 1)</gadget>
<output>2</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">4 / 12</gadget>
<output>1/3 = around 0.333333</output>
<result>B</result> | B | 0.333333 | If x is to be chosen at random from the set {1, 2, 3, 4} and y is to be chosen at random from the set {5, 6, 7}, what is the probability that xy will be odd? | {
"A": "1 / 6",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "5 / 6"
} | divide(power(2, 2), multiply(choose(4, 2), choose(2, 1))) | choose(n3,n1)|choose(n1,n0)|power(n1,n1)|multiply(#0,#1)|divide(#2,#3)| | "probably the best way to solve would be to use 1 - p ( opposite event ) = 1 - p ( odd ) = 1 - p ( odd ) * p ( odd ) = 1 - 2 / 4 * 2 / 3 = 8 / 12 = 1 / 3 . answer : b ." | probability |
math_qa__PcZeTfns33BnEYYh | In march Mrs Bil's earnings were 80 percent of the Bil family's total income. In april Mrs Bil earned 10 percent more than in May. If the rest of the family's income was the same both months, then, in June, Mrs Bil's earnings were approximately what percent of the Bil family's total income ? Choose the correct answer:
A) 83 B) 56 C) 34 D) 12 E) 26 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 80</gadget>
<output>72</output>
<gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">20 + 72</gadget>
<output>92</output>
<gadget id="calculator">72 / 92</gadget>
<output>18/23 = around 0.782609</output>
<gadget id="calculator">(18/23) * 100</gadget>
<output>1_800/23 = around 78.26087</output>
<gadget id="calculator">(1_800/23) + 4</gadget>
<output>1_892/23 = around 82.26087</output>
<result>A</result> | A | 83 | In march Mrs Bil's earnings were 80 percent of the Bil family's total income. In april Mrs Bil earned 10 percent more than in May. If the rest of the family's income was the same both months, then, in June, Mrs Bil's earnings were approximately what percent of the Bil family's total income ? | {
"A": "83",
"B": "56",
"C": "34",
"D": "12",
"E": "26"
} | add(multiply(divide(multiply(divide(subtract(const_100, 10), const_100), 80), add(subtract(const_100, 80), multiply(divide(subtract(const_100, 10), const_100), 80))), const_100), const_4) | subtract(const_100,n1)|subtract(const_100,n0)|divide(#0,const_100)|multiply(n0,#2)|add(#3,#1)|divide(#3,#4)|multiply(#5,const_100)|add(#6,const_4) | lets say the family income is 100 in may , lee earned 80 family income is 20 in june , lee earned 20 % more than may , so it is ( 80 + 20 * 80 / 100 = 96 ) family income is same 20 in june lee ' s income percent is 96 * 100 / 116 ~ 83 ans is a | general |
math_qa__lFplNOG8SWBUns9B | How many prime numbers are between 29/4 and 87/5? Choices: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">floor(2)</gadget>
<output>2</output>
<result>B</result> | B | 2 | How many prime numbers are between 29/4 and 87/5? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | floor(const_2) | floor(const_2) | 29 / 4 = 7 . xxx 87 / 5 = 17 . xxx so we need to find prime numbers between 7 ( exclusive ) - 16 ( inclusive ) there are 2 prime numbers 1113 hence answer will be ( b ) 2 b | general |
math_qa__fhtx7EcMsNEz3W10 | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 48 kmph, find the speed of the stream?
Choose the correct choice from the following.
A) 16 kmph B) 19 kmph C) 14 kmph D) 11 kmph E) 13 kmph | <gadget id="calculator">48 * 2</gadget>
<output>96</output>
<gadget id="calculator">96 / 3</gadget>
<output>32</output>
<gadget id="calculator">48 - 32</gadget>
<output>16</output>
<result>A</result> | A | 16 | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 48 kmph, find the speed of the stream? | {
"A": "16 kmph",
"B": "19 kmph",
"C": "14 kmph",
"D": "11 kmph",
"E": "13 kmph"
} | subtract(48, divide(multiply(48, const_2), const_3)) | multiply(n0,const_2)|divide(#0,const_3)|subtract(n0,#1)| | "the ratio of the times taken is 2 : 1 . the ratio of the speed of the boat in still water to the speed of the stream = ( 2 + 1 ) / ( 2 - 1 ) = 3 / 1 = 3 : 1 speed of the stream = 48 / 3 = 16 kmph . answer : a" | physics |
math_qa__0ndqrhae3taX8aLZ | What is the total number of integers between 100 and 500(exclusive) that are divisible by 5? Select:
A) 51
B) 63
C) 79
D) 66
E) 42 | <gadget id="calculator">500 - 100</gadget>
<output>400</output>
<gadget id="calculator">400 / 5</gadget>
<output>80</output>
<gadget id="calculator">80 + 1</gadget>
<output>81</output>
<result>C</result> | C | 79 | What is the total number of integers between 100 and 500(exclusive) that are divisible by 5? | {
"A": "51",
"B": "63",
"C": "79",
"D": "66",
"E": "42"
} | add(divide(subtract(500, 100), 5), const_1) | subtract(n1,n0)|divide(#0,n2)|add(#1,const_1) | 105 , 110 , 115 , . . . , 490,495 this is an equally spaced list ; you can use the formula : n = ( largest - smallest ) / ( ' space ' ) + 1 = ( 495 - 105 ) / ( 5 ) + 1 = 78 + 1 = 79 answer is c | general |
math_qa__vNKcjQD1wBhgir7p | A shopkeeper sold 10 articles at the cost price of 12 articles. Then find the profit% or lost%
Choose the correct choice from the following answers:
A) - 10 %
B) 10 %
C) 15 %
D) 20 %
E) 25 % | <gadget id="calculator">12 - 10</gadget>
<output>2</output>
<gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>D</result> | D | 20 | A shopkeeper sold 10 articles at the cost price of 12 articles. Then find the profit% or lost% | {
"A": "- 10 %",
"B": "10 %",
"C": "15 %",
"D": "20 %",
"E": "25 %"
} | multiply(divide(subtract(12, 10), 10), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100) | here 10 articles selling price = 12 articles cost price so the difference = 12 - 10 = 2 % of profit = 2 * 100 / 10 = 20 % correct option is d | gain |
math_qa__8aRmGQXHrgugCd5N | Venus travels around the sun at a speed of approximately 21.9 miles per second. The approximate speed is how many miles per hour? Select the correct option: A) 64,420 B) 78,840 C) 83,160 D) 88,970 E) 94,320 | <gadget id="calculator">21.9 * 3_600</gadget>
<output>78_840</output>
<result>B</result> | B | 78,840 | Venus travels around the sun at a speed of approximately 21.9 miles per second. The approximate speed is how many miles per hour? | {
"A": "64,420",
"B": "78,840",
"C": "83,160",
"D": "88,970",
"E": "94,320"
} | multiply(21.9, const_3600) | multiply(n0,const_3600) | 21.9 * 3600 = 78,840 the answer is b . | physics |
math_qa__1HVchTd6fVY4mCZt | 150 ml of 30% sulphuric acid was added to approximate 400 ml of 12% sulphuric acid solution. Find the approximate concentration of the acid in the mixture? Select the correct option
A) 1 / 2
B) 1 / 3
C) 1 / 4
D) 1 / 6
E) 1 / 5 | <gadget id="calculator">150 * 30</gadget>
<output>4_500</output>
<gadget id="calculator">4_500 / 100</gadget>
<output>45</output>
<gadget id="calculator">400 * 12</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 100</gadget>
<output>48</output>
<gadget id="calculator">45 + 48</gadget>
<output>93</output>
<gadget id="calculator">150 + 400</gadget>
<output>550</output>
<gadget id="calculator">93 / 550</gadget>
<output>93/550 = around 0.169091</output>
<result>D</result> | D | 0.166667 | 150 ml of 30% sulphuric acid was added to approximate 400 ml of 12% sulphuric acid solution. Find the approximate concentration of the acid in the mixture? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 6",
"E": "1 / 5"
} | divide(add(divide(multiply(150, 30), const_100), divide(multiply(400, 12), const_100)), add(150, 400)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0) | 150 ml solution contains 45 ml sulphuric acid 400 ml solution contains 48 ml sulphuric acid adding 550 ml solution contains 93 ml sulphuric acid 93 / 550 ≈ 90 / 540 = 1 / 6 answer is d | general |
math_qa__k0ruRcnBlchrZQkD | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 18 years. What is Deepak present age? Choose the correct choice from the following answers.
A) 22 B) 15 C) 77 D) 9 E) 182 | <gadget id="calculator">18 - 6</gadget>
<output>12</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<result>D</result> | D | 9 | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 18 years. What is Deepak present age? | {
"A": "22",
"B": "15",
"C": "77",
"D": "9",
"E": "182"
} | divide(multiply(subtract(18, 6), 3), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)| | "present age is 4 x and 3 x , = > 4 x + 6 = 18 = > x = 3 so deepak age is = 3 ( 3 ) = 9 answer : d" | other |
math_qa__zfS0YVA4VP3kIuBo | A and B can do a piece of work in 8 days. B and C can do it in 12 days and A and C in 16 days. Working together they will complete the work in how many days? Choose the correct option:
A) 3.33 days
B) 8.33 days
C) 3.99 days
D) 7.38 days
E) 2.88 days | <gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/8) + (1/12)</gadget>
<output>5/24 = around 0.208333</output>
<gadget id="calculator">(1/16) + (5/24)</gadget>
<output>13/48 = around 0.270833</output>
<gadget id="calculator">(13/48) / 2</gadget>
<output>13/96 = around 0.135417</output>
<gadget id="calculator">1 / (13/96)</gadget>
<output>96/13 = around 7.384615</output>
<result>D</result> | D | 7.38 | A and B can do a piece of work in 8 days. B and C can do it in 12 days and A and C in 16 days. Working together they will complete the work in how many days? | {
"A": "3.33 days",
"B": "8.33 days",
"C": "3.99 days",
"D": "7.38 days",
"E": "2.88 days"
} | inverse(divide(add(inverse(16), add(inverse(8), inverse(12))), const_2)) | inverse(n0)|inverse(n1)|inverse(n2)|add(#0,#1)|add(#3,#2)|divide(#4,const_2)|inverse(#5) | a + b = 1 / 8 b + c = 1 / 12 c + a = 1 / 16 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - 2 ( a + b + c ) = 1 / 8 + 1 / 12 + 1 / 16 = 13 / 48 a + b + c = 13 / 96 96 / 13 = 7.38 days answer : d | physics |
math_qa__2tRs9R5VH3DVMmc8 | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 14% microphotonics; 19% home electronics; 10% food additives; 24% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? Answers.
A) 8 ° B) 90 ° C) 18 ° D) 36 ° E) 52 ° | <gadget id="calculator">14 + 19</gadget>
<output>33</output>
<gadget id="calculator">33 + 10</gadget>
<output>43</output>
<gadget id="calculator">43 + 24</gadget>
<output>67</output>
<gadget id="calculator">67 + 8</gadget>
<output>75</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">25 * 360</gadget>
<output>9_000</output>
<gadget id="calculator">9_000 / 100</gadget>
<output>90</output>
<result>B</result> | B | 90 | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 14% microphotonics; 19% home electronics; 10% food additives; 24% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? | {
"A": "8 °",
"B": "90 °",
"C": "18 °",
"D": "36 °",
"E": "52 °"
} | divide(multiply(subtract(const_100, add(add(add(add(14, 19), 10), 24), 8)), divide(const_3600, const_10)), const_100) | add(n0,n1)|divide(const_3600,const_10)|add(n2,#0)|add(n3,#2)|add(n4,#3)|subtract(const_100,#4)|multiply(#1,#5)|divide(#6,const_100)| | "14 % microphotonics ; 19 % home electronics ; 10 % food additives ; 24 % genetically modified microorganisms ; 8 % industrial lubricants ; 100 - ( 14 + 19 + 10 + 24 + 8 ) = 25 % basic astrophysics . 25 % of 360 ° is 90 ° . answer : b ." | gain |
math_qa__t58wde9HbW16tvhS | a will was written such that an estate would be divided among 4 beneficiaries with the remainder donated to charity . one stipulation in the will is that no one beneficiary can receive an amount within 20 % of another ' s amount . if one of the beneficiaries received $ 40000 , what is the smallest possible range between the highest and lowest amounts ( rounded to the nearest dollar ) among the 4 beneficiaries ?
Choose the correct option.
A) $ 12436 B) $ 13344 C) $ 71234 D) $ 15736 E) $ 19403 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">40_000 * (4/5)</gadget>
<output>32_000</output>
<gadget id="calculator">32_000 * (4/5)</gadget>
<output>25_600</output>
<gadget id="calculator">25_600 * (4/5)</gadget>
<output>20_480</output>
<gadget id="calculator">40_000 - 20_480</gadget>
<output>19_520</output>
<result>E</result> | E | 19,403 | a will was written such that an estate would be divided among 4 beneficiaries with the remainder donated to charity . one stipulation in the will is that no one beneficiary can receive an amount within 20 % of another ' s amount . if one of the beneficiaries received $ 40000 , what is the smallest possible range between the highest and lowest amounts ( rounded to the nearest dollar ) among the 4 beneficiaries ? | {
"A": "$ 12436",
"B": "$ 13344",
"C": "$ 71234",
"D": "$ 15736",
"E": "$ 19403"
} | subtract(40000, multiply(multiply(multiply(40000, subtract(const_1, divide(20, const_100))), subtract(const_1, divide(20, const_100))), subtract(const_1, divide(20, const_100)))) | divide(n1,const_100)|subtract(const_1,#0)|multiply(n2,#1)|multiply(#2,#1)|multiply(#3,#1)|subtract(n2,#4) | 1 st - 40,000 . 2 nd - 0.8 * 40,000 = 32,000 3 rd - 0.8 * 32,000 = 25,600 4 th - 0.8 * 25,600 = ~ 20,480 range = 40,000 - 20,480 = 19520 answer : e . | general |
math_qa__zEPe9v6yKV7x3vHL | A box contains 2 red balls and 5 black balls. One by one, every ball is selected at random without replacement. What is the probability that the fourth ball selected is black? Pick:
A) 1 / 4
B) 7 / 5
C) 1 / 2
D) 5 / 8
E) 2 / 3 | <gadget id="calculator">2 + 5</gadget>
<output>7</output>
<gadget id="calculator">7 / 5</gadget>
<output>7/5 = around 1.4</output>
<result>B</result> | B | 1.4 | A box contains 2 red balls and 5 black balls. One by one, every ball is selected at random without replacement. What is the probability that the fourth ball selected is black? | {
"A": "1 / 4",
"B": "7 / 5",
"C": "1 / 2",
"D": "5 / 8",
"E": "2 / 3"
} | divide(add(2, 5), 5) | add(n0,n1)|divide(#0,n1)| | "my complicated version of your simple approach let the 5 black balls be bbbbb and 2 red balls be rrr they can be arranged in 8 slots _ _ _ _ _ _ _ _ in ( 7 ! ) / ( 5 ! x 2 ! ) if the fourth slot is black ball then the arrangement will be to fill _ _ _ b _ _ _ _ we have 6 slots and 4 black ( bbbb ) and 2 red ( rrr ) they can be arranged in ( 7 ! ) / ( 4 ! x 2 ! ) hence required probability = [ ( 7 ! ) / ( 5 ! x 2 ! ) ] / [ ( 6 ! ) / ( 4 ! x 2 ! ) ] = 7 / 5 b" | probability |
math_qa__zJjFPGrNWwubpm8t | The L.C.M. of two numbers is 36. The numbers are in the ratio 2 : 3. Then sum of the number is:
Options.
A) 28 B) 30 C) 40 D) 53 E) 54 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">36 / 6</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">18 + 12</gadget>
<output>30</output>
<result>B</result> | B | 30 | The L.C.M. of two numbers is 36. The numbers are in the ratio 2 : 3. Then sum of the number is: | {
"A": "28",
"B": "30",
"C": "40",
"D": "53",
"E": "54"
} | add(multiply(divide(36, multiply(2, 3)), 3), multiply(divide(36, multiply(2, 3)), 2)) | multiply(n1,n2)|divide(n0,#0)|multiply(n2,#1)|multiply(n1,#1)|add(#2,#3)| | "let the numbers be 2 x and 3 x . then , their l . c . m . = 6 x . so , 6 x = 36 or x = 6 . the numbers are 12 and 18 . hence , required sum = ( 12 + 18 ) = 30 . answer : option b" | other |
math_qa__Nsu8mRf9gzw1KCjP | A man can do a piece of work in 6 days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone? Choose one:
A) 5 B) 7 C) 6 D) 8 E) 9 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">18 / 3</gadget>
<output>6</output>
<result>C</result> | C | 6 | A man can do a piece of work in 6 days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone? | {
"A": "5",
"B": "7",
"C": "6",
"D": "8",
"E": "9"
} | divide(multiply(6, 3), subtract(6, 3)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "son ' s 1 day ' s work = ( 1 / 3 ) - ( 1 / 6 ) = 1 / 6 the son alone can do the work in 6 days answer is c" | physics |
math_qa__laAppk57727fH2xd | A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 70 square feet of the wall, and no tiles overlap, what is the area of the entire wall? Choose the correct choice:
A) 160 B) 240 C) 385 D) 440 E) 560 | <gadget id="calculator">70 * 3</gadget>
<output>210</output>
<gadget id="calculator">210 / 2</gadget>
<output>105</output>
<gadget id="calculator">105 * 3</gadget>
<output>315</output>
<gadget id="calculator">70 + 315</gadget>
<output>385</output>
<result>C</result> | C | 385 | A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 70 square feet of the wall, and no tiles overlap, what is the area of the entire wall? | {
"A": "160",
"B": "240",
"C": "385",
"D": "440",
"E": "560"
} | add(70, multiply(divide(multiply(70, 3), const_2), 3)) | multiply(n2,n1)|divide(#0,const_2)|multiply(n1,#1)|add(n2,#2)| | "the number of jumbo tiles = x . the number of regular tiles = 2 x . assume the ratio of the dimensions of a regular tile is a : a - - > area = a ^ 2 . the dimensions of a jumbo tile is 3 a : 3 a - - > area = 9 a ^ 2 . the area of regular tiles = 2 x * a ^ 2 = 70 . the area of jumbo tiles = x * 9 a ^ 2 = 4.5 ( 2 x * a ^ 2 ) = 4.5 * 70 = 315 . total area = 70 + 315 = 385 answer : c ." | geometry |
math_qa__Rtks6LsO9wjpq3yF | the sum of the present ages of a , b , c is 57 years . 3 years ago their ages were in the ratio 1 : 2 : 3 . what is the present age of a ?
Options
A) 8
B) 9
C) 10
D) 11
E) 12 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">57 - 9</gadget>
<output>48</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">48 / 6</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<result>D</result> | D | 11 | the sum of the present ages of a , b , c is 57 years . 3 years ago their ages were in the ratio 1 : 2 : 3 . what is the present age of a ? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | add(divide(subtract(57, multiply(3, const_3)), add(add(1, 2), 3)), 3) | add(n2,n3)|multiply(n1,const_3)|add(n1,#0)|subtract(n0,#1)|divide(#3,#2)|add(n1,#4) | three years ago : a : b : c = 1 : 2 : 3 let a = 1 x , b = 2 x , and c = 3 x . today : ( x + 3 ) + ( 2 x + 3 ) + ( 3 x + 3 ) = 57 x = 8 so the present age of a is x + 3 = 11 the answer is d . | general |
math_qa__xCZzACNVS20visxM | The profit earned by selling an article for Rs.753 is equal to the loss incurred when the same article is sold for Rs.455.What should be the sale price for making 50% profit ? Choose one: A) 706 B) 786 C) 906 D) 896 E) 696 | <gadget id="calculator">753 - 455</gadget>
<output>298</output>
<gadget id="calculator">298 / 2</gadget>
<output>149</output>
<gadget id="calculator">753 - 149</gadget>
<output>604</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">604 * (3/2)</gadget>
<output>906</output>
<result>C</result> | C | 906 | The profit earned by selling an article for Rs.753 is equal to the loss incurred when the same article is sold for Rs.455.What should be the sale price for making 50% profit ? | {
"A": "706",
"B": "786",
"C": "906",
"D": "896",
"E": "696"
} | multiply(subtract(753, divide(subtract(753, 455), const_2)), add(const_1, divide(50, const_100))) | divide(n2,const_100)|subtract(n0,n1)|add(#0,const_1)|divide(#1,const_2)|subtract(n0,#3)|multiply(#2,#4)| | "let c . p = rs . x then as given , ( 753 - x ) = ( x - 455 ) 2 x = 1208 x = 604 there fore s . p = 150 % of 604 = > rs . = rs . 906 answer : c" | gain |
math_qa__2Qo6RPiLtrXAa63f | 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2,__ ?
Choose the correct answer
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">3 * 1</gadget>
<output>3</output>
<result>C</result> | C | 3 | 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2,__ ? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | multiply(const_3.0, 1) | multiply(n5,n0)| | "1,1 , 2,1 , 2,3 , 1,2 , 3,4 , 1,2 , __ ? looking at the series 1 12 123 1234 12 ( 3 ) 45 so the answer is 3 . answer : c" | general |
math_qa__pL2Q9CPOdIPJLsQm | The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 756. What is the banker's discount? Choose one.
A) 1240 B) 1120 C) 1190 D) 1806 E) none of these | <gadget id="calculator">756 * 100</gadget>
<output>75_600</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<gadget id="calculator">75_600 / 72</gadget>
<output>1_050</output>
<gadget id="calculator">756 + 1_050</gadget>
<output>1_806</output>
<result>D</result> | D | 1,806 | The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 756. What is the banker's discount? | {
"A": "1240",
"B": "1120",
"C": "1190",
"D": "1806",
"E": "none of these"
} | add(756, divide(multiply(756, const_100), multiply(12, 6))) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2)| | "explanation : td = ( bg × 100 ) / tr = ( 756 × 100 ) / ( 6 × 12 ) = rs . 1050 bg = bd – td = > 756 = bd - 1050 = > bd = 1050 + 756 = 1806 answer : option d" | gain |
math_qa__QhZgOGt5S18m4Jwy | One fourth of one third of two fifth of a number is 35. What will be40% of that number Choose the correct option:
A) 140
B) 420
C) 180
D) 200
E) 220 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/4) * (1/3)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/12) * (2/5)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">35 / (1/30)</gadget>
<output>1_050</output>
<gadget id="calculator">1_050 * 40</gadget>
<output>42_000</output>
<gadget id="calculator">42_000 / 100</gadget>
<output>420</output>
<result>B</result> | B | 420 | One fourth of one third of two fifth of a number is 35. What will be40% of that number | {
"A": "140",
"B": "420",
"C": "180",
"D": "200",
"E": "220"
} | divide(multiply(divide(35, multiply(multiply(divide(const_1, const_4), divide(const_1, const_3)), divide(const_2, add(const_2, const_3)))), 40), const_100) | add(const_2,const_3)|divide(const_1,const_4)|divide(const_1,const_3)|divide(const_2,#0)|multiply(#1,#2)|multiply(#3,#4)|divide(n0,#5)|multiply(n1,#6)|divide(#7,const_100)| | "explanation : ( 1 / 4 ) * ( 1 / 3 ) * ( 2 / 5 ) * x = 35 then x = 35 * 30 = 1050 40 % of 1050 = 420 answer : option b" | gain |
math_qa__ff68lITD5D1DFe93 | A flagstaff 17.5 m high casts a shadow of length 40.25 m. What will be the height of a building, which casts a shadow of length 28.75 m under similar conditions? Choose the correct choice from the following answers: A) 12.5 m B) 10.5 m C) 14 D) 12 E) 10 | <gadget id="calculator">17.5 / 40.25</gadget>
<output>0.434783</output>
<gadget id="calculator">28.75 * 0.434783</gadget>
<output>12.500011</output>
<result>A</result> | A | 12.5 | A flagstaff 17.5 m high casts a shadow of length 40.25 m. What will be the height of a building, which casts a shadow of length 28.75 m under similar conditions? | {
"A": "12.5 m",
"B": "10.5 m",
"C": "14",
"D": "12",
"E": "10"
} | multiply(28.75, divide(17.5, 40.25)) | divide(n0,n1)|multiply(n2,#0) | explanation : let the required height of the building be x meter more shadow length , more height ( direct proportion ) hence we can write as ( shadow length ) 40.25 : 28.75 : : 17.5 : x ⇒ 40.25 × x = 28.75 × 17.5 ⇒ x = 28.75 × 17.5 / 40.25 = 2875 × 175 / 40250 = 2875 × 7 / 1610 = 2875 / 230 = 575 / 46 = 12.5 answer : option a | physics |
math_qa__nsvFa8AtPAqrDNbC | In a party every person shakes hands with every other person. If there were a total of 153 handshakes in the party then what is the number of persons present in the party ? Choose the correct choice from the following options
A) 15 B) 16 C) 17 D) 18 E) 19 | <gadget id="calculator">153 * 2</gadget>
<output>306</output>
<gadget id="calculator">306 * 4</gadget>
<output>1_224</output>
<gadget id="calculator">1_224 + 1</gadget>
<output>1_225</output>
<gadget id="calculator">1_225 ** (1/2)</gadget>
<output>35</output>
<gadget id="calculator">35 + 1</gadget>
<output>36</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<result>D</result> | D | 18 | In a party every person shakes hands with every other person. If there were a total of 153 handshakes in the party then what is the number of persons present in the party ? | {
"A": "15",
"B": "16",
"C": "17",
"D": "18",
"E": "19"
} | divide(add(sqrt(add(multiply(multiply(153, const_2), const_4), const_1)), const_1), const_2) | multiply(n0,const_2)|multiply(#0,const_4)|add(#1,const_1)|sqrt(#2)|add(#3,const_1)|divide(#4,const_2)| | "explanation : let the number of persons be n â ˆ ´ total handshakes = nc 2 = 153 n ( n - 1 ) / 2 = 153 â ˆ ´ n = 18 answer : option d" | general |
math_qa__irsaj9KxMxxWhcJA | In the xy-coordinate system, if (m, n) and (m + 1, n + k) are two points on the line with the equation x = 2y + 5, then k = Choose the correct choice from the following options: A) 1 / 2 B) 1 C) 2 D) 5 / 2 E) 4 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 - 5</gadget>
<output>1</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | In the xy-coordinate system, if (m, n) and (m + 1, n + k) are two points on the line with the equation x = 2y + 5, then k = | {
"A": "1 / 2",
"B": "1",
"C": "2",
"D": "5 / 2",
"E": "4"
} | divide(subtract(add(5, 1), 5), 2) | add(n0,n2)|subtract(#0,n2)|divide(#1,n1)| | "since ( m , n ) and ( m + 2 , n + k ) are two points on the line with the equation x = 2 y + 5 they should satisfy m = 2 n + 5 and m + 1 = 2 * ( n + k ) + 5 . by 1 st equation we have m - 2 n = 5 and by 2 nd equation m - 2 n = 2 k + 4 - - - > 5 = 2 k + 4 - - - > k = 1 / 2 . the answer is , therefore , ( a ) ." | general |
math_qa__TSvwOWYg2HT0iz89 | If A lends Rs.25000 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?
Answers: A) 1125 B) 1225 C) 1325 D) 1145 E) 2125 | <gadget id="calculator">25_000 * 11.5</gadget>
<output>287_500</output>
<gadget id="calculator">287_500 * 3</gadget>
<output>862_500</output>
<gadget id="calculator">862_500 / 100</gadget>
<output>8_625</output>
<gadget id="calculator">25_000 * 10</gadget>
<output>250_000</output>
<gadget id="calculator">250_000 * 3</gadget>
<output>750_000</output>
<gadget id="calculator">750_000 / 100</gadget>
<output>7_500</output>
<gadget id="calculator">8_625 - 7_500</gadget>
<output>1_125</output>
<result>A</result> | A | 1,125 | If A lends Rs.25000 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is? | {
"A": "1125",
"B": "1225",
"C": "1325",
"D": "1145",
"E": "2125"
} | subtract(divide(multiply(multiply(25000, 11.5), 3), const_100), divide(multiply(multiply(25000, 10), 3), const_100)) | multiply(n0,n2)|multiply(n0,n1)|multiply(#0,n3)|multiply(n3,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,#5)| | "( 25000 * 1.5 * 3 ) / 100 = > 1125 answer : a" | gain |
math_qa__Wk2ubnPmU1nuNoQx | 50 is what percent of 125? Pick one.
A) 35 % B) 40 % C) 45 % D) 50 % E) 55 % | <gadget id="calculator">50 / 125</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>B</result> | B | 40 | 50 is what percent of 125? | {
"A": "35 %",
"B": "40 %",
"C": "45 %",
"D": "50 %",
"E": "55 %"
} | multiply(divide(50, 125), const_100) | divide(n0,n1)|multiply(#0,const_100)| | 50 / 125 × 100 = 50 % answer : b | gain |
math_qa__iz0kQW8Q8IgZGjXX | In a certain corporation, there are 300 male employees and 150 female employees. It is known that 10% of the male employees have advanced degrees and 40% of the females have advanced degrees. If one of the 450 employees is chosen at random, what is the probability this employee has an advanced degree or is female? Choose one.
A) 1 / 5 B) 5 / 15 C) 6 / 15 D) 3 / 10 E) 4 / 15 | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 150</gadget>
<output>90</output>
<gadget id="calculator">90 / 450</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 300</gadget>
<output>30</output>
<gadget id="calculator">(2/5) * 150</gadget>
<output>60</output>
<gadget id="calculator">30 + 60</gadget>
<output>90</output>
<gadget id="calculator">(1/5) + (1/5)</gadget>
<output>2/5 = around 0.4</output>
<result>C</result> | C | 0.4 | In a certain corporation, there are 300 male employees and 150 female employees. It is known that 10% of the male employees have advanced degrees and 40% of the females have advanced degrees. If one of the 450 employees is chosen at random, what is the probability this employee has an advanced degree or is female? | {
"A": "1 / 5",
"B": "5 / 15",
"C": "6 / 15",
"D": "3 / 10",
"E": "4 / 15"
} | add(divide(multiply(subtract(const_1, divide(40, multiply(10, 10))), 150), 450), divide(add(multiply(divide(10, multiply(10, 10)), 300), multiply(divide(40, multiply(10, 10)), 150)), 450)) | multiply(n2,n2)|divide(n3,#0)|divide(n2,#0)|multiply(n0,#2)|multiply(n1,#1)|subtract(const_1,#1)|add(#3,#4)|multiply(n1,#5)|divide(#7,n4)|divide(#6,n4)|add(#8,#9) | p ( female ) = 150 / 450 = 1 / 3 p ( male with advanced degree ) = 0.1 * 300 / 450 = 30 / 450 = 1 / 15 the sum of the probabilities is 6 / 15 = 2 / 5 the answer is c . | other |
math_qa__DfK5Pl9dC9DeQnii | The least number by which 72 must be multiplied in order to produce a multiple of 112, is Choices:
A) 6
B) 12
C) 14
D) 18
E) 20 | <gadget id="calculator">gcd(72, 112)</gadget>
<output>8</output>
<gadget id="calculator">112 / 8</gadget>
<output>14</output>
<result>C</result> | C | 14 | The least number by which 72 must be multiplied in order to produce a multiple of 112, is | {
"A": "6",
"B": "12",
"C": "14",
"D": "18",
"E": "20"
} | divide(112, gcd(72, 112)) | gcd(n0,n1)|divide(n1,#0)| | "solution required numbers is divisible by 72 as well as by 112 , if it is divisible by their lcm , which is 1008 . now , 1008 when divided by 72 , gives quotient = 14 . required number = 14 . answer c" | general |
math_qa__NI6HH9pn79dqtfTi | find the number, difference between number and its 3/5 is 58. Choices.
A) 140 B) 143 C) 144 D) 145 E) 146 | <gadget id="calculator">58 / 2</gadget>
<output>29</output>
<gadget id="calculator">29 * 5</gadget>
<output>145</output>
<result>D</result> | D | 145 | find the number, difference between number and its 3/5 is 58. | {
"A": "140",
"B": "143",
"C": "144",
"D": "145",
"E": "146"
} | multiply(divide(58, const_2), 5) | divide(n2,const_2)|multiply(n1,#0)| | "explanation : let the number = x , then , x - ( 3 / 5 ) x = 58 , = > ( 2 / 5 ) x = 58 = > 2 x = 58 * 5 , = > x = 145 answer : option d" | general |
math_qa__73dGTYWZEHN7Vze1 | When Jessica withdrew $200 from her bank account, her account balance decreased by 2/5. If she deposits an amount equal to 1/5 of the remaining balance, what will be the final balance in her bank account? Choose the correct choice from the following:
A) 300
B) 360
C) 400
D) 500
E) 575 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">200 / (2/5)</gadget>
<output>500</output>
<gadget id="calculator">500 - 200</gadget>
<output>300</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">300 * (6/5)</gadget>
<output>360</output>
<result>B</result> | B | 360 | When Jessica withdrew $200 from her bank account, her account balance decreased by 2/5. If she deposits an amount equal to 1/5 of the remaining balance, what will be the final balance in her bank account? | {
"A": "300",
"B": "360",
"C": "400",
"D": "500",
"E": "575"
} | multiply(subtract(divide(200, subtract(1, divide(const_3, 5))), 200), add(1, divide(1, 5))) | divide(n3,n4)|divide(const_3,n2)|add(n3,#0)|subtract(n3,#1)|divide(n0,#3)|subtract(#4,n0)|multiply(#2,#5)| | "as per the question 200 = 2 a / 5 thus - a which is the total amount = 500 the amount thus left = 300 she then deposited 1 / 5 of 300 = 60 total amount in her account = 360 answer b" | general |
math_qa__RyBR79HLLnnX56xf | In a certain company, the ratio of the number of managers to the number of non-managers in any department must always be greater than 7 : 32. In the company, what is the maximum number of non-managers in a department that has 9 managers? Select.
A) 39 B) 40 C) 41 D) 42 E) 43 | <gadget id="calculator">32 * 9</gadget>
<output>288</output>
<gadget id="calculator">288 / 7</gadget>
<output>288/7 = around 41.142857</output>
<gadget id="calculator">floor(288/7)</gadget>
<output>41</output>
<result>C</result> | C | 41 | In a certain company, the ratio of the number of managers to the number of non-managers in any department must always be greater than 7 : 32. In the company, what is the maximum number of non-managers in a department that has 9 managers? | {
"A": "39",
"B": "40",
"C": "41",
"D": "42",
"E": "43"
} | floor(divide(multiply(32, 9), 7)) | multiply(n1,n2)|divide(#0,n0)|floor(#1)| | "9 / 7 * 32 = 41.1 the answer is c ." | general |
math_qa__pCivC9Iu8fSAloRu | A man's speed with the current is 22 km/hr and the speed of the current is 5 km/hr. The man's speed against the current is Choices.
A) 9 B) 10 C) 11 D) 12 E) 13 | <gadget id="calculator">22 - 5</gadget>
<output>17</output>
<gadget id="calculator">17 - 5</gadget>
<output>12</output>
<result>D</result> | D | 12 | A man's speed with the current is 22 km/hr and the speed of the current is 5 km/hr. The man's speed against the current is | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "13"
} | subtract(subtract(22, 5), 5) | subtract(n0,n1)|subtract(#0,n1)| | "man ' s rate in still water = ( 22 - 5 ) km / hr = 17 km / hr . man ' s rate against the current = ( 17 - 5 ) km / hr = 12 km / hr . answer : d" | gain |
math_qa__2Mw7AgD4uqqrtuh1 | Machine Z takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine Z to make 40 widgets?
Pick
A) 5 B) 6 C) 8 D) 10 E) 12 | <gadget id="calculator">40 / 20</gadget>
<output>2</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<result>E</result> | E | 12 | Machine Z takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine Z to make 40 widgets? | {
"A": "5",
"B": "6",
"C": "8",
"D": "10",
"E": "12"
} | multiply(divide(40, 20), multiply(2, 3)) | divide(n4,n1)|multiply(n0,n3)|multiply(#0,#1) | i approached this one by plugging in numbers . . . started with c . if 40 are made in 8 hours , then 20 are made in 4 hours . so time of z is 4 , and time of b is 2 . rate together : 20 / 4 + 20 / 2 = 5 + 10 = 15 . so in 1 hour , together make 15 widgets . in 3 hours = 45 . way too much . we can eliminate right away c , b , and a - because b and a reduces the time - the total # of widgets made will be even higher . now between d and e - > try only one . . if it does n ' t work , then the other one is the answer . i picked e : 12 h to make 40 widgets , and 6 hours to make 20 . this is the time of z . time of b = 4 hours . 20 / 6 + 20 / 4 = 10 / 3 + 20 / 4 find lcm of 3 and 4 = 12 . multiply first by 4 , and second by 3 : 40 + 60 / 12 = 100 / 12 divide by 4 : 25 / 3 so this is the rate given . e is the correct answer | physics |
math_qa__QheTEzI5iZEAzOvr | A certain pair of used shoes can be repaired for $13.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $32.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes? Pick one: A) 17.69 B) 14.85 C) 21.3 D) 16.5 E) 18.51 | <gadget id="calculator">13.5 * 2</gadget>
<output>27</output>
<gadget id="calculator">32 - 27</gadget>
<output>5</output>
<gadget id="calculator">5 / 27</gadget>
<output>5/27 = around 0.185185</output>
<gadget id="calculator">100 * (5/27)</gadget>
<output>500/27 = around 18.518519</output>
<result>E</result> | E | 18.51 | A certain pair of used shoes can be repaired for $13.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $32.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes? | {
"A": "17.69",
"B": "14.85",
"C": "21.3",
"D": "16.5",
"E": "18.51"
} | multiply(const_100, divide(subtract(32.00, multiply(13.50, 2)), multiply(13.50, 2))) | multiply(n0,n3)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "1 ) cost of repairing = 13.5 ( for one year ) , therefore for 2 years it would be $ 27 . 2 ) cost of new pair which will last for 2 years is $ 32 . percentage change formula = ( final value - initial value ) / ( initial value ) * 100 . in this case the final value would be the price of new shoe initial value would be the cost of repairing the old shoe . i . e ( 32 - 27 ) / ( 27 ) * 100 = 18.51 % . ans is e" | general |
math_qa__scRJy84xZBX8dzmz | If x = 55 + 2q and y = 4q + 41, then for what value of q, x is equal to y ? Choose the correct choice from the following options
A) - 14 B) 14 C) - 7 D) 7 E) 0 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">2 * 7</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<result>D</result> | D | 7 | If x = 55 + 2q and y = 4q + 41, then for what value of q, x is equal to y ? | {
"A": "- 14",
"B": "14",
"C": "- 7",
"D": "7",
"E": "0"
} | divide(multiply(2, add(const_4, const_3)), 2) | add(const_3,const_4)|multiply(n1,#0)|divide(#1,n1) | explanation : x = y < = > 55 + 2 q = 4 q + 41 < = > 2 q = 14 < = > q = 7 . answer : d | general |
math_qa__VGvvcpuci2f3REWL | A sum fetched a total simple interest of Rs. 100 at the rate of 5 p.c.p.a. in 4 years. What is the sum? Choose the correct option
A) 800 B) 600 C) 500 D) 1000 E) 300 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 5</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 4</gadget>
<output>500</output>
<result>C</result> | C | 500 | A sum fetched a total simple interest of Rs. 100 at the rate of 5 p.c.p.a. in 4 years. What is the sum? | {
"A": "800",
"B": "600",
"C": "500",
"D": "1000",
"E": "300"
} | divide(divide(multiply(100, const_100), 5), 4) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "sol . principal = rs . [ 100 * 100 / 5 * 4 ] = rs . [ 10000 / 20 ] = rs . 500 . answer c" | gain |
math_qa__vHLIYZZceoKiSKgi | If one person completes a journey in 10 hrs. He travels 1st half of the journey at the rate of 21 km/hr and 2nd half at therate of 24 km/hr. Find the total journey in km. Options.
A) 200 km B) 212 km C) 224 km D) 230 km E) 256 km | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">21 * 5</gadget>
<output>105</output>
<gadget id="calculator">24 * 5</gadget>
<output>120</output>
<gadget id="calculator">105 + 120</gadget>
<output>225</output>
<result>C</result> | C | 224 | If one person completes a journey in 10 hrs. He travels 1st half of the journey at the rate of 21 km/hr and 2nd half at therate of 24 km/hr. Find the total journey in km. | {
"A": "200 km",
"B": "212 km",
"C": "224 km",
"D": "230 km",
"E": "256 km"
} | add(multiply(21, divide(10, 2)), multiply(24, divide(10, 2))) | divide(n0,n3)|multiply(n2,#0)|multiply(n4,#0)|add(#1,#2) | distance = speed x time let time taken to travel the first half = x hr then time taken to travel the second half = ( 10 - x ) hr distance covered in the the first half = 21 x distance covered in the the second half = 24 ( 10 - x ) but distance covered in the the first half = distance covered in the the second half = > 21 x = 24 ( 10 - x ) = > 21 x = 240 - 24 x = > 45 x = 240 = > 9 x = 48 = > 3 x = 16 ⇒ x = 163 hence distance covered in the the first half = 21 x = 21 × 163 = 7 × 16 = 112 kmtotal distance = 2 × 112 = 224 km c | general |
math_qa__YDnTXn4RIukBVB5o | M = {-6, -5, -4, -3, -2, -1}
T = {-5, -4, -3, -2, -1, 0, 1, 2}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative? Choose the correct choice from the following choices:
A) 0 B) 1 / 4 C) 2 / 5 D) 1 / 2 E) 3 / 5 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">2 / 8</gadget>
<output>1/4 = around 0.25</output>
<result>B</result> | B | 0.25 | M = {-6, -5, -4, -3, -2, -1}
T = {-5, -4, -3, -2, -1, 0, 1, 2}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative? | {
"A": "0",
"B": "1 / 4",
"C": "2 / 5",
"D": "1 / 2",
"E": "3 / 5"
} | divide(2, multiply(4, 2)) | multiply(n2,n4)|divide(n4,#0) | we will have a negative product only if 1 or 2 are selected from set t . p ( negative product ) = 2 / 8 = 1 / 4 the answer is b . | general |
math_qa__VTDagqwYoiEYL2LP | What is the tenth digit of (5!*5! - 5!*3!)/5? Choose the correct answer.
A) 1 B) 2 C) 0 D) 6 E) 7 | <gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">120 * 120</gadget>
<output>14_400</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">14_400 - 720</gadget>
<output>13_680</output>
<gadget id="calculator">13_680 / 5</gadget>
<output>2_736</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">2_736 / 1_000</gadget>
<output>342/125 = around 2.736</output>
<gadget id="calculator">floor(342/125)</gadget>
<output>2</output>
<result>B</result> | B | 2 | What is the tenth digit of (5!*5! - 5!*3!)/5? | {
"A": "1",
"B": "2",
"C": "0",
"D": "6",
"E": "7"
} | floor(divide(divide(subtract(multiply(factorial(5), factorial(5)), multiply(factorial(5), factorial(3))), 5), multiply(const_100, const_10))) | factorial(n0)|factorial(n3)|multiply(const_10,const_100)|multiply(#0,#0)|multiply(#0,#1)|subtract(#3,#4)|divide(#5,n0)|divide(#6,#2)|floor(#7) | ( 5 ! * 5 ! + 5 ! * 3 ! ) / 5 = 5 ! ( 5 ! + 3 ! ) / 5 = 120 ( 120 + 6 ) / 5 = 3024 units digit of the above product will be equal to 2 answer b | general |
math_qa__cCaL0RdMcLAKmeVR | 30 pens and 75 pencils were purchased for 570. If the average price of a pencil was 2.00, find the average price of a pen. Pick.
A) 10 B) 11 C) 12 D) 13 E) 14 | <gadget id="calculator">75 * 2</gadget>
<output>150</output>
<gadget id="calculator">570 - 150</gadget>
<output>420</output>
<gadget id="calculator">420 / 30</gadget>
<output>14</output>
<result>E</result> | E | 14 | 30 pens and 75 pencils were purchased for 570. If the average price of a pencil was 2.00, find the average price of a pen. | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | divide(subtract(570, multiply(75, 2.00)), 30) | multiply(n1,n3)|subtract(n2,#0)|divide(#1,n0)| | "since average price of a pencil = 2 ∴ price of 75 pencils = 150 ∴ price of 30 pens = ( 570 – 150 ) = 360 ∴ average price of a pen = 420 ⁄ 60 = 14 answer e" | general |
math_qa__TNhi9XdSqWS7EI8b | If 20 typists can type 42 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour?
Choose the most appropriate option:
A) 189 B) 72 C) 144 D) 216 E) 400 | <gadget id="calculator">42 * 3</gadget>
<output>126</output>
<gadget id="calculator">126 / 20</gadget>
<output>63/10 = around 6.3</output>
<gadget id="calculator">(63/10) * 30</gadget>
<output>189</output>
<result>A</result> | A | 189 | If 20 typists can type 42 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour? | {
"A": "189",
"B": "72",
"C": "144",
"D": "216",
"E": "400"
} | multiply(divide(multiply(42, const_3), 20), 30) | multiply(n1,const_3)|divide(#0,n0)|multiply(n3,#1)| | "20 typists can type 42 letters , so 30 typists can type = 42 * 30 / 20 42 * 30 / 20 letters can be typed in 20 mins . in 60 mins typist can type = 42 * 30 * 60 / 20 * 20 = 189 a is the answer" | physics |
math_qa__oevh0AavkuUCYpSK | A certain electric-company plan offers customers reduced rates for electricity used between 8 p.m. and 8 a.m. weekdays and 24 hours a day Saturdays and Sundays. Under this plan, the reduced rates Q apply to what fraction of a week? Options.
A) 1 / 2
B) 5 / 8
C) 9 / 14
D) 16 / 21
E) 9 / 10 | <gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">60 + 48</gadget>
<output>108</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">24 * 7</gadget>
<output>168</output>
<gadget id="calculator">108 / 168</gadget>
<output>9/14 = around 0.642857</output>
<result>C</result> | C | 0.642857 | A certain electric-company plan offers customers reduced rates for electricity used between 8 p.m. and 8 a.m. weekdays and 24 hours a day Saturdays and Sundays. Under this plan, the reduced rates Q apply to what fraction of a week? | {
"A": "1 / 2",
"B": "5 / 8",
"C": "9 / 14",
"D": "16 / 21",
"E": "9 / 10"
} | divide(add(multiply(divide(24, const_2), add(const_2, const_3)), multiply(24, const_2)), multiply(24, add(const_3, const_4))) | add(const_2,const_3)|add(const_3,const_4)|divide(n2,const_2)|multiply(n2,const_2)|multiply(#0,#2)|multiply(n2,#1)|add(#4,#3)|divide(#6,#5)| | "number of hours between 8 pm to 8 am = 12 number of hours with reduced rates = ( 12 * 5 ) + ( 24 * 2 ) hours with reduced rates q / total number of hours in a week = ( 12 * 5 ) + ( 24 * 2 ) / ( 24 * 7 ) = 108 / ( 24 * 7 ) = 9 / 14 answer : c" | physics |
math_qa__NcwyYLRevJLzUAyF | In a neighborhood having 90 households, 11 did not have either a car or a bike. If 18 households had a both a car and a bike and 44 had a car, how many had bike only? Choose the correct choice from the following choices
A) 30
B) 35
C) 20
D) 18
E) 10 | <gadget id="calculator">90 - 11</gadget>
<output>79</output>
<gadget id="calculator">79 + 18</gadget>
<output>97</output>
<gadget id="calculator">97 - 44</gadget>
<output>53</output>
<gadget id="calculator">53 - 18</gadget>
<output>35</output>
<result>B</result> | B | 35 | In a neighborhood having 90 households, 11 did not have either a car or a bike. If 18 households had a both a car and a bike and 44 had a car, how many had bike only? | {
"A": "30",
"B": "35",
"C": "20",
"D": "18",
"E": "10"
} | subtract(subtract(add(subtract(90, 11), 18), 44), 18) | subtract(n0,n1)|add(n2,#0)|subtract(#1,n3)|subtract(#2,n2)| | "{ total } = { car } + { bike } - { both } + { neither } - - > 90 = 44 + { bike } - 18 + 11 - - > { bike } = 53 - - > # those who have bike only is { bike } - { both } = 53 - 18 = 35 . answer : b ." | other |
math_qa__BJmXhd1Pis45M1YW | Two trains of equal are running on parallel lines in the same direction at 42 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is? Choices
A) 30 m
B) 72 m
C) 80 m
D) 82 m
E) 84 m | <gadget id="calculator">42 - 36</gadget>
<output>6</output>
<gadget id="calculator">6 * 1_000</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 3_600</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">36 * (5/3)</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>A</result> | A | 30 | Two trains of equal are running on parallel lines in the same direction at 42 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is? | {
"A": "30 m",
"B": "72 m",
"C": "80 m",
"D": "82 m",
"E": "84 m"
} | divide(multiply(36, divide(multiply(subtract(42, 36), const_1000), const_3600)), const_2) | subtract(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n2,#2)|divide(#3,const_2)| | "let the length of each train be x m . then , distance covered = 2 x m . relative speed = 42 - 36 = 6 km / hr . = 6 * 5 / 18 = 5 / 3 m / sec . 2 x / 36 = 5 / 3 = > x = 30 . answer : a" | general |
math_qa__IIhTaDt0HiQyJldp | A customer pays 70 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffe maker?
Select the correct option
A) 50 B) 40 C) 90 D) 60 E) 20 | <gadget id="calculator">70 + 20</gadget>
<output>90</output>
<result>C</result> | C | 90 | A customer pays 70 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffe maker? | {
"A": "50",
"B": "40",
"C": "90",
"D": "60",
"E": "20"
} | add(70, 20) | add(n0,n1) | let x be the original price . x - 20 = 70 x - 20 + 20 = 70 + 20 x + 0 = 90 x = 90 answer is c | gain |
math_qa__M6Kqw1Xswtg6hCWz | If 40% of a certain number is 160, then what is 50% of that number? Answers
A) 270 B) 380 C) 200 D) 360 E) 290 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">160 / (2/5)</gadget>
<output>400</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">400 * (1/2)</gadget>
<output>200</output>
<result>C</result> | C | 200 | If 40% of a certain number is 160, then what is 50% of that number? | {
"A": "270",
"B": "380",
"C": "200",
"D": "360",
"E": "290"
} | multiply(divide(160, divide(40, const_100)), divide(50, const_100)) | divide(n0,const_100)|divide(n2,const_100)|divide(n1,#0)|multiply(#2,#1)| | "explanation : 40 % = 40 * 4 = 160 50 % = 50 * 4 = 200 answer : option c" | gain |
math_qa__IOvusiWE3wu5O934 | A man can row his boat with the stream at 12 km/h and against the stream in 4 km/h. The man's rate is? Pick one.
A) 1 kmph B) 4 kmph C) 98 kmph D) 6 kmph E) 4 kmph | <gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>E</result> | E | 4 | A man can row his boat with the stream at 12 km/h and against the stream in 4 km/h. The man's rate is? | {
"A": "1 kmph",
"B": "4 kmph",
"C": "98 kmph",
"D": "6 kmph",
"E": "4 kmph"
} | divide(subtract(12, 4), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "ds = 12 s = ? s = ( 12 - 4 ) / 2 = 4 kmph answer : e" | gain |
math_qa__5a4vmeunMfomD1oE | The circumferences of two circles are 132 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles? Choose the correct choice from the following answers.
A) 2996 sq m B) 2897 sq m C) 4312 sq m D) 5768 sq m E) 8470 sq m | <gadget id="calculator">2 * pi</gadget>
<output>2*pi = around 6.283185</output>
<gadget id="calculator">352 / (2*pi)</gadget>
<output>176/pi = around 56.02254</output>
<gadget id="calculator">pi * ((176/pi) ** 2)</gadget>
<output>30976/pi = around 9_859.967034</output>
<gadget id="calculator">132 / (2*pi)</gadget>
<output>66/pi = around 21.008452</output>
<gadget id="calculator">pi * ((66/pi) ** 2)</gadget>
<output>4356/pi = around 1_386.557864</output>
<gadget id="calculator">(30976/pi) - (4356/pi)</gadget>
<output>26620/pi = around 8_473.40917</output>
<result>E</result> | E | 8,470 | The circumferences of two circles are 132 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles? | {
"A": "2996 sq m",
"B": "2897 sq m",
"C": "4312 sq m",
"D": "5768 sq m",
"E": "8470 sq m"
} | subtract(circle_area(divide(352, multiply(const_2, const_pi))), circle_area(divide(132, multiply(const_2, const_pi)))) | multiply(const_2,const_pi)|divide(n1,#0)|divide(n0,#0)|circle_area(#1)|circle_area(#2)|subtract(#3,#4)| | "let the radii of the smaller and the larger circles be s m and l m respectively . 2 ∏ s = 132 and 2 ∏ l = 352 s = 132 / 2 ∏ and l = 352 / 2 ∏ difference between the areas = ∏ l ^ 2 - ∏ s ^ 2 = ∏ { 66 ^ 2 / ∏ ^ 2 - 132 ^ 2 / ∏ ^ 2 } = 66 ^ 2 / ∏ - 132 ^ 2 / ∏ = ( 66 - 132 ) ( 66 + 132 ) / ∏ = ( 110 ) ( 242 ) / ( 22 / 7 ) = 8470 sq m answer : e" | geometry |
math_qa__8bN4P8trzDkDDkrq | The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Steve and Dinley have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies? Choose the correct answer.
A) $ 0.32 B) $ 0.40 C) $ 0.45 D) $ 0.48 E) $ 0.54 | <gadget id="calculator">80 * 0.02</gadget>
<output>1.6</output>
<gadget id="calculator">2 * 1.6</gadget>
<output>3.2</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">160 * (3/4)</gadget>
<output>120</output>
<gadget id="calculator">120 * 0.02</gadget>
<output>2.4</output>
<gadget id="calculator">3.2 - 2.4</gadget>
<output>0.8</output>
<gadget id="calculator">0.8 / 2</gadget>
<output>0.4</output>
<result>B</result> | B | 0.4 | The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Steve and Dinley have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies? | {
"A": "$ 0.32",
"B": "$ 0.40",
"C": "$ 0.45",
"D": "$ 0.48",
"E": "$ 0.54"
} | divide(subtract(multiply(const_2, multiply(80, 0.02)), multiply(multiply(160, divide(subtract(100, 25), 100)), 0.02)), const_2) | multiply(n0,n3)|subtract(n2,n1)|divide(#1,n2)|multiply(#0,const_2)|multiply(n4,#2)|multiply(n0,#4)|subtract(#3,#5)|divide(#6,const_2)| | "if steve and dinley submit separate orders , each would be smaller than 100 photocopies , so no discount . each would pay ( 80 ) * ( $ 0.02 ) = $ 1.60 , or together , a cost of $ 3.20 - - - that ' s the combinedno discount cost . if they submit things together as one big order , they get a discount off of that $ 3.20 price - - - - 25 % or 1 / 4 of that is $ 0.80 , the discount on the combined sale . they each effective save half that amount , or $ 0.40 . answer = ( b ) ." | gain |
math_qa__QtS6AA66S1ISehpJ | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 16000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is: Choose the correct choice from the following.
A) 22 B) 21 C) 35 D) 37 E) 29 | <gadget id="calculator">16_000 - 8_000</gadget>
<output>8_000</output>
<gadget id="calculator">7 * 8_000</gadget>
<output>56_000</output>
<gadget id="calculator">8_000 - 6_000</gadget>
<output>2_000</output>
<gadget id="calculator">56_000 / 2_000</gadget>
<output>28</output>
<gadget id="calculator">7 + 28</gadget>
<output>35</output>
<result>C</result> | C | 35 | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 16000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is: | {
"A": "22",
"B": "21",
"C": "35",
"D": "37",
"E": "29"
} | add(7, divide(multiply(7, subtract(16000, 8000)), subtract(8000, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3)| | "explanation : lot the total number of workers be v then , 8 ooov = ( 16000 * 7 ) + 6000 ( v - 7 ) < = > 2000 v = 70000 < = > v = 35 answer : c ) 35" | general |
math_qa__qtIB0bzi7CD0iPI3 | When positive integer w is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180? Choose the correct choice from the following.
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">13 * 7</gadget>
<output>91</output>
<gadget id="calculator">91 % 8</gadget>
<output>3</output>
<gadget id="calculator">3 - 2</gadget>
<output>1</output>
<result>B</result> | B | 1 | When positive integer w is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | subtract(reminder(multiply(13, add(5, 2)), 8), 2) | add(n1,n3)|multiply(n0,#0)|reminder(#1,n2)|subtract(#2,n1) | the equation that can be formed w is 13 x + 2 = 8 y + 5 . . 13 x - 3 = 8 y . . . as we can see x can take only odd values as the rhs will always be even . . also x can take values till 13 as 13 * 14 > 180 . . now we have to substitue x as 1 , 35 , 79 , 1113 . . . once we find 7 fitting in , any other value need not be checked as every 4 th value will give us answer so next value will be 15 . . ans 1 . . b | general |
math_qa__4XVfTtgnwm3YFGGE | A certain box has 11 cards and each card has one of the integers from 1 to 11 inclusive. Each card has a different number. If 2 different cards are selected at random, what is the probability that the sum of the numbers written on the 2 cards is less than the average (arithmetic mean) of all the numbers written on the 11 cards?
Choose the correct choice
A) 1 / 11 B) 2 / 11 C) 2 / 33 D) 4 / 55 E) 5 / 66 | <gadget id="calculator">factorial(11)</gadget>
<output>39_916_800</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">2 * 362_880</gadget>
<output>725_760</output>
<gadget id="calculator">39_916_800 / 725_760</gadget>
<output>55</output>
<gadget id="calculator">4 / 55</gadget>
<output>4/55 = around 0.072727</output>
<result>D</result> | D | 0.072727 | A certain box has 11 cards and each card has one of the integers from 1 to 11 inclusive. Each card has a different number. If 2 different cards are selected at random, what is the probability that the sum of the numbers written on the 2 cards is less than the average (arithmetic mean) of all the numbers written on the 11 cards? | {
"A": "1 / 11",
"B": "2 / 11",
"C": "2 / 33",
"D": "4 / 55",
"E": "5 / 66"
} | divide(const_4, divide(factorial(11), multiply(factorial(2), factorial(subtract(11, 2))))) | factorial(n0)|factorial(n3)|subtract(n0,n3)|factorial(#2)|multiply(#1,#3)|divide(#0,#4)|divide(const_4,#5) | the average of the numbers is 6 the total number of ways to choose 2 cards from 11 cards is 11 c 2 = 55 . the ways to choose 2 cards with a sum less than the average are : { 1,2 } , { 1,3 } , { 1,4 } , { 2,3 } the probability is 4 / 55 the answer is d . | general |
math_qa__XOuZkGdqlhb6XFzO | If a2 + b2 + c2 = 281 and ab + bc + ca =4, then a + b + c is Choose the correct choice from the following: A) 16 B) 18 C) 22 D) 17 E) 20 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">281 + 8</gadget>
<output>289</output>
<gadget id="calculator">289 ** (1/2)</gadget>
<output>17</output>
<result>D</result> | D | 17 | If a2 + b2 + c2 = 281 and ab + bc + ca =4, then a + b + c is | {
"A": "16",
"B": "18",
"C": "22",
"D": "17",
"E": "20"
} | sqrt(add(281, multiply(4, 2))) | multiply(n4,n0)|add(n3,#0)|sqrt(#1)| | "by formula , ( a + b + c ) ^ 2 = a ^ 2 + b ^ 2 + c ^ 2 + 2 ( ab + bc + ca ) , since , a ^ 2 + b ^ 2 + c ^ 2 = 281 and ab + bc + ca = 4 , ( a + b + c ) ^ 2 = 281 + 2 ( 4 ) = 289 = 17 ^ 2 therefore : a + b + c = 17 answer : d" | general |
math_qa__5kB6lxXdnBGK4F30 | Pradeep has to obtain 25% of the total marks to pass. He got 185 marks and failed by 25 marks. The maximum marks are Pick.
A) 840 B) 600 C) 800 D) 1000 E) 900 | <gadget id="calculator">185 + 25</gadget>
<output>210</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">210 / (1/4)</gadget>
<output>840</output>
<result>A</result> | A | 840 | Pradeep has to obtain 25% of the total marks to pass. He got 185 marks and failed by 25 marks. The maximum marks are | {
"A": "840",
"B": "600",
"C": "800",
"D": "1000",
"E": "900"
} | divide(add(185, 25), divide(25, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "explanation : let their maximum marks be x . then , 25 % of x = 185 + 25 = > 25 / 100 x = 210 x = ( 210100 / 25 ) x = 840 . answer : a" | general |
math_qa__ZNExgxiSkNJ4Za1q | 9 men went to a theater . 8 of them spent rs . 3 each over their tickets and the ninth spent rs . 2 more than the average expenditure of all the 9 . determine the total money spent by them ? Choose the correct choice from the following answers:
A) 29 B) 29.25 C) 31 D) 31.23 E) 32 | <gadget id="calculator">3 * 8</gadget>
<output>24</output>
<gadget id="calculator">24 + 2</gadget>
<output>26</output>
<gadget id="calculator">26 / 8</gadget>
<output>13/4 = around 3.25</output>
<gadget id="calculator">(13/4) * 9</gadget>
<output>117/4 = around 29.25</output>
<result>B</result> | B | 29.25 | 9 men went to a theater . 8 of them spent rs . 3 each over their tickets and the ninth spent rs . 2 more than the average expenditure of all the 9 . determine the total money spent by them ? | {
"A": "29",
"B": "29.25",
"C": "31",
"D": "31.23",
"E": "32"
} | multiply(divide(add(multiply(3, 8), 2), 8), 9) | multiply(n1,n2)|add(n3,#0)|divide(#1,n1)|multiply(n0,#2) | average of 9 = x 9 x = 8 * 3 + x * 2 x = 3.25 total = 9 * 3.25 = 29.25 b | general |
math_qa__OxNc1KEbt9xEIFn8 | A runs 1 2/3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time? Options.
A) 200 m
B) 300 m
C) 270 m
D) 160 m
E) 150 m | <gadget id="calculator">1 * 3</gadget>
<output>3</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 80</gadget>
<output>400</output>
<gadget id="calculator">400 / 2</gadget>
<output>200</output>
<result>A</result> | A | 200 | A runs 1 2/3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time? | {
"A": "200 m",
"B": "300 m",
"C": "270 m",
"D": "160 m",
"E": "150 m"
} | divide(multiply(add(multiply(1, 3), 2), 80), 2) | multiply(n0,n2)|add(n1,#0)|multiply(n3,#1)|divide(#2,n1) | explanation : ratio of the speeds of a and b = 5 : 1 = 5 : 3 thus , in race of 5 m , a gains 2 m over b . 2 m are gained by a in a race of 5 m . 80 m will be gained by a in race of 5 / 2 x 80 m = 200 m winning post is 200 m away from the starting point . answer is a | general |
math_qa__ZJ12KtCaeQZaesBY | If the perimeter and diagonal of a rectangle are 14 and 5 cms respectively, find its area. Choices: A) 12 cm 2 B) 16 cm 2 C) 20 cm 2 D) 24 cm E) none of these | <gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">7 ** 2</gadget>
<output>49</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">49 - 25</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<result>A</result> | A | 12 | If the perimeter and diagonal of a rectangle are 14 and 5 cms respectively, find its area. | {
"A": "12 cm 2",
"B": "16 cm 2",
"C": "20 cm 2",
"D": "24 cm",
"E": "none of these"
} | divide(subtract(power(divide(14, const_2), const_2), power(5, const_2)), const_2) | divide(n0,const_2)|power(n1,const_2)|power(#0,const_2)|subtract(#2,#1)|divide(#3,const_2) | in a rectangle , ( perimeter ) 2 / 4 = ( diagonal ) 2 + 2 × area ⇒ ( 14 ) 2 / 4 = 5 ( 2 ) + 2 × area 49 = 25 + 2 × area ∴ area = 49 − 25 / 2 = 24 / 2 = 12 cm 2 answer a | geometry |
math_qa__5nUifs9jujemNMKp | If two-third of a bucket is filled in 100 seconds then the time taken to fill the bucket completely will be . Select:
A) 90 seconds B) 150 seconds C) 60 seconds D) 100 seconds E) 120 seconds | <gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">50 * 3</gadget>
<output>150</output>
<result>B</result> | B | 150 | If two-third of a bucket is filled in 100 seconds then the time taken to fill the bucket completely will be . | {
"A": "90 seconds",
"B": "150 seconds",
"C": "60 seconds",
"D": "100 seconds",
"E": "120 seconds"
} | multiply(divide(100, const_2), const_3) | divide(n0,const_2)|multiply(#0,const_3) | 2 / 3 filled in 100 seconds 1 / 3 filled in 50 secs then 2 / 3 + 1 / 3 = 100 + 50 seconds = 150 seconds answer : b | physics |
math_qa__g23gkVXh8H9DtRGe | If the cost price is 81% of selling price then what is the profit percentage. Options:
A) 22.45 B) 23.45 C) 32.45 D) 23.54 E) 23.55 | <gadget id="calculator">100 - 81</gadget>
<output>19</output>
<gadget id="calculator">19 / 81</gadget>
<output>19/81 = around 0.234568</output>
<gadget id="calculator">(19/81) * 100</gadget>
<output>1_900/81 = around 23.45679</output>
<result>B</result> | B | 23.45 | If the cost price is 81% of selling price then what is the profit percentage. | {
"A": "22.45",
"B": "23.45",
"C": "32.45",
"D": "23.54",
"E": "23.55"
} | multiply(divide(subtract(const_100, 81), 81), const_100) | subtract(const_100,n0)|divide(#0,n0)|multiply(#1,const_100) | selling price = rs 100 : then cost price = rs 81 : profit = rs 19 . profit = { ( 19 / 81 ) * 100 } % = 23.45 % answer is b . | gain |
math_qa__UMYzvbfDmXlBdCsj | Farm Tax is levied on the 60% of the cultivated Land. The tax department collected total $ 5000 through the farm Tax from the village of Mr. william. Mr. william paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is :
Choose the correct option: A) 15 % B) 16 % C) 0.125 % D) 0.2083 % E) none | <gadget id="calculator">480 / 5_000</gadget>
<output>12/125 = around 0.096</output>
<gadget id="calculator">(12/125) * 100</gadget>
<output>48/5 = around 9.6</output>
<gadget id="calculator">(48/5) * 100</gadget>
<output>960</output>
<gadget id="calculator">960 / 60</gadget>
<output>16</output>
<result>B</result> | B | 16 | Farm Tax is levied on the 60% of the cultivated Land. The tax department collected total $ 5000 through the farm Tax from the village of Mr. william. Mr. william paid only $ 480 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is : | {
"A": "15 %",
"B": "16 %",
"C": "0.125 %",
"D": "0.2083 %",
"E": "none"
} | divide(multiply(multiply(divide(480, 5000), const_100), const_100), 60) | divide(n2,n1)|multiply(#0,const_100)|multiply(#1,const_100)|divide(#2,n0)| | "this will be equal to the percentage of total cultivated land he holds over the total cultivated land in the village . that leads to ( 480 / 5000 ) x 100 = 9.6 % in percentage terms . but the question asks ratio between his total land to total cultivated land . hence the answer is 9.6 % x ( 100 / 60 ) = 16 % the correct answer is ( b ) ." | general |
math_qa__97m6YCqWJMJvIVBs | in company j , the total monthly payroll for the 15 factory workers is $ 30000 and the total monthly payroll for the 30 office workers is $ 75000 . by how much does the average ( arithmetic mean ) monthly salary of an office worker exceed that of a factory worker in this company ? Answers:
A) $ 450 B) $ 500 C) $ 600 D) $ 650 E) $ 750 | <gadget id="calculator">30_000 / 30</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 2</gadget>
<output>500</output>
<result>B</result> | B | 500 | in company j , the total monthly payroll for the 15 factory workers is $ 30000 and the total monthly payroll for the 30 office workers is $ 75000 . by how much does the average ( arithmetic mean ) monthly salary of an office worker exceed that of a factory worker in this company ? | {
"A": "$ 450",
"B": "$ 500",
"C": "$ 600",
"D": "$ 650",
"E": "$ 750"
} | divide(divide(30000, 30), const_2) | divide(n1,n2)|divide(#0,const_2) | the average monthly salary of a factory worker is : $ 30000 / 15 = $ 2000 . the average monthly salary of an office worker is : $ 75000 / 30 = $ 2500 . the difference in average salary is : $ 2500 - $ 2000 = $ 500 . the answer is b . | general |
math_qa__XhMNECEiHZxnBarX | The average mark of the students of a class in a particular exam is 70. If 5 students whose average mark in that exam is 50 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam? Choose the correct choice from the following answers:
A) 20
B) 15
C) 10
D) 12
E) 25 | <gadget id="calculator">90 * 5</gadget>
<output>450</output>
<gadget id="calculator">5 * 50</gadget>
<output>250</output>
<gadget id="calculator">450 - 250</gadget>
<output>200</output>
<gadget id="calculator">90 - 70</gadget>
<output>20</output>
<gadget id="calculator">200 / 20</gadget>
<output>10</output>
<result>C</result> | C | 10 | The average mark of the students of a class in a particular exam is 70. If 5 students whose average mark in that exam is 50 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam? | {
"A": "20",
"B": "15",
"C": "10",
"D": "12",
"E": "25"
} | divide(subtract(multiply(90, 5), multiply(5, 50)), subtract(90, 70)) | multiply(n1,n3)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)| | "let the number of students who wrote the exam be x . total marks of students = 70 x . total marks of ( x - 5 ) students = 90 ( x - 5 ) 70 x - ( 5 * 50 ) = 90 ( x - 5 ) 200 = 20 x = > x = 10 answer : c" | general |
math_qa__LzhnZdQ7jGISmTSt | At Joel’s bookstore, the current inventory is 40% historical fiction. Of the historical fiction books, 40% are new releases, while 20% of the other books are new releases. What fraction of all new releases are the historical fiction new releases?
Select the correct option:
A) 4 / 25
B) 8 / 23
C) 2 / 5
D) 8 / 14
E) 2 / 3 | <gadget id="calculator">40 * 40</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 / 100</gadget>
<output>16</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">20 * 60</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 100</gadget>
<output>12</output>
<gadget id="calculator">16 + 12</gadget>
<output>28</output>
<gadget id="calculator">16 / 28</gadget>
<output>4/7 = around 0.571429</output>
<result>D</result> | D | 0.571429 | At Joel’s bookstore, the current inventory is 40% historical fiction. Of the historical fiction books, 40% are new releases, while 20% of the other books are new releases. What fraction of all new releases are the historical fiction new releases? | {
"A": "4 / 25",
"B": "8 / 23",
"C": "2 / 5",
"D": "8 / 14",
"E": "2 / 3"
} | divide(divide(multiply(40, 40), const_100), add(divide(multiply(40, 40), const_100), divide(multiply(20, subtract(const_100, 40)), const_100))) | multiply(n0,n1)|subtract(const_100,n0)|divide(#0,const_100)|multiply(n2,#1)|divide(#3,const_100)|add(#2,#4)|divide(#2,#5)| | "let there be 100 books in all historic fiction books = 40 % of total = 40 other books = 60 new historic fiction = 40 % of 40 = 16 other new books = 20 % of 60 = 12 total new books = 28 fraction = 16 / 28 = 8 / 14 ans : d" | gain |
math_qa__vHk3NpXsdBzVxnJC | A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is?
Choose the correct choice.
A) 26 B) 28 C) 80 D) 26 E) 21 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">40 * (11/10)</gadget>
<output>44</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">50 * (6/5)</gadget>
<output>60</output>
<gadget id="calculator">44 + 60</gadget>
<output>104</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">90 * (23/20)</gadget>
<output>207/2 = around 103.5</output>
<gadget id="calculator">104 - (207/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">40 / (1/2)</gadget>
<output>80</output>
<result>C</result> | C | 80 | A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is? | {
"A": "26",
"B": "28",
"C": "80",
"D": "26",
"E": "21"
} | divide(40, subtract(add(multiply(40, add(const_1, divide(10, const_100))), multiply(50, add(const_1, divide(20, const_100)))), multiply(90, add(const_1, divide(15, const_100))))) | divide(n2,const_100)|divide(n4,const_100)|divide(n5,const_100)|add(#0,const_1)|add(#1,const_1)|add(#2,const_1)|multiply(n1,#3)|multiply(n3,#4)|multiply(n0,#5)|add(#6,#7)|subtract(#9,#8)|divide(n1,#10)| | "let c . p . of clock be rs . x . then , c . p . of 90 clocks = rs . 90 x . [ ( 110 % of 40 x ) + ( 120 % of 50 x ) ] - ( 115 % of 90 x ) = 40 44 x + 60 x - 103.5 x = 40 0.5 x = 40 = > x = 80 answer : c" | gain |
math_qa__6q7sYnB8xSttptam | The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 39 degrees. Find the temperature on Friday? Pick one.
A) 65 degrees B) 73 degrees C) 31 degrees D) 34 degrees E) 74 degrees | <gadget id="calculator">48 * 4</gadget>
<output>192</output>
<gadget id="calculator">46 * 4</gadget>
<output>184</output>
<gadget id="calculator">192 - 184</gadget>
<output>8</output>
<gadget id="calculator">39 - 8</gadget>
<output>31</output>
<result>C</result> | C | 31 | The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 39 degrees. Find the temperature on Friday? | {
"A": "65 degrees",
"B": "73 degrees",
"C": "31 degrees",
"D": "34 degrees",
"E": "74 degrees"
} | subtract(39, subtract(multiply(48, const_4), multiply(46, const_4))) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#0,#1)|subtract(n2,#2)| | "m + tu + w + th = 4 * 48 = 192 tu + w + th + f = 4 * 46 = 184 m = 39 tu + w + th = 192 - 39 = 153 f = 184 – 153 = 31 answer : c" | general |
math_qa__s5Xy2OT55S3TLceV | It takes Joey the postman 1 hours to run a 2 mile long route every day. He delivers packages and then returns to the post office along the same path. If the average speed of the round trip is 3 mile/hour, what is the speed with which Joey returns? Choose the correct option: A) 1 B) 6 C) 13 D) 14 E) 15 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) - 1</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2 / (1/3)</gadget>
<output>6</output>
<result>B</result> | B | 6 | It takes Joey the postman 1 hours to run a 2 mile long route every day. He delivers packages and then returns to the post office along the same path. If the average speed of the round trip is 3 mile/hour, what is the speed with which Joey returns? | {
"A": "1",
"B": "6",
"C": "13",
"D": "14",
"E": "15"
} | divide(2, subtract(divide(multiply(const_2, 2), 3), 1)) | multiply(n1,const_2)|divide(#0,n2)|subtract(#1,n0)|divide(n1,#2)| | "let his speed for one half of the journey be 2 miles an hour let the other half be x miles an hour now , avg speed = 3 mile an hour 2 * 2 * x / 2 + x = 3 4 x = 3 x + 6 = > x = 6 b" | physics |
math_qa__KSXy5tDHU0GE5dVu | A man is 16 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is Choose the correct choice from the following answers
A) 21 years B) 14 years C) 16 years D) 18 years E) 26 years | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">16 - 2</gadget>
<output>14</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">14 / 1</gadget>
<output>14</output>
<result>B</result> | B | 14 | A man is 16 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is | {
"A": "21 years",
"B": "14 years",
"C": "16 years",
"D": "18 years",
"E": "26 years"
} | divide(subtract(16, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1)) | multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)| | "explanation : let ' s son age is x , then father age is x + 16 . = > 2 ( x + 2 ) = ( x + 16 + 2 ) = > 2 x + 4 = x + 18 = > x = 14 years option b" | general |
math_qa__LuTW9GNZR4WcijKj | A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is? Choose the correct choice from the following: A) 10 B) 20 C) 50 D) 30 E) 40 | <gadget id="calculator">15 - 2.5</gadget>
<output>12.5</output>
<gadget id="calculator">12.5 - 2.5</gadget>
<output>10</output>
<result>A</result> | A | 10 | A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is? | {
"A": "10",
"B": "20",
"C": "50",
"D": "30",
"E": "40"
} | subtract(subtract(15, 2.5), 2.5) | subtract(n0,n1)|subtract(#0,n1)| | "man ' s speed with the current = 15 km / hr = > speed of the man + speed of the current = 15 km / hr speed of the current is 2.5 km / hr hence , speed of the man = 15 - 2.5 = 12.5 km / hr man ' s speed against the current = speed of the man - speed of the current = 12.5 - 2.5 = 10 km / hr answer is a ." | gain |
math_qa__9S9oiwiloCvC8Pdn | A man's speed with the current is 21 km/hr and the speed of the current is 4.3 km/hr. The man's speed against the current is Options:
A) 9.2 B) 10.3 C) 11.5 D) 12.4 E) 13 | <gadget id="calculator">21 - 4.3</gadget>
<output>16.7</output>
<gadget id="calculator">16.7 - 4.3</gadget>
<output>12.4</output>
<result>D</result> | D | 12.4 | A man's speed with the current is 21 km/hr and the speed of the current is 4.3 km/hr. The man's speed against the current is | {
"A": "9.2",
"B": "10.3",
"C": "11.5",
"D": "12.4",
"E": "13"
} | subtract(subtract(21, 4.3), 4.3) | subtract(n0,n1)|subtract(#0,n1)| | "man ' s rate in still water = ( 21 - 4.3 ) km / hr = 16.7 km / hr . man ' s rate against the current = ( 16.7 - 4.3 ) km / hr = 12.4 km / hr . answer : d" | gain |
math_qa__Vt1jEpN5BASIOBNE | Three cubes of metal whose edges are 9, 12 and 15 cm respectively, are melted and one new cube is made. Find the edge of the new cube?
Choose the correct choice from the following options
A) 21 cm
B) 19 cm
C) 32 cm
D) 18 cm
E) 28 cm | <gadget id="calculator">9 ** 3</gadget>
<output>729</output>
<gadget id="calculator">12 ** 3</gadget>
<output>1_728</output>
<gadget id="calculator">729 + 1_728</gadget>
<output>2_457</output>
<gadget id="calculator">15 ** 3</gadget>
<output>3_375</output>
<gadget id="calculator">2_457 + 3_375</gadget>
<output>5_832</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">5_832 ** (1/3)</gadget>
<output>18</output>
<result>D</result> | D | 18 | Three cubes of metal whose edges are 9, 12 and 15 cm respectively, are melted and one new cube is made. Find the edge of the new cube? | {
"A": "21 cm",
"B": "19 cm",
"C": "32 cm",
"D": "18 cm",
"E": "28 cm"
} | power(add(add(volume_cube(9), volume_cube(12)), volume_cube(15)), const_0_33) | volume_cube(n0)|volume_cube(n1)|volume_cube(n2)|add(#0,#1)|add(#3,#2)|power(#4,const_0_33)| | "93 + 123 + 153 = a 3 = > a = 18 answer : d" | physics |
math_qa__OYgZQbvLLZoG7xbV | martin buys a pencil and a notebook for 80 cents . at the same store , gloria buys a notebook and an eraser for 85 cents , and zachary buys a pencil and an eraser for 45 cents . how many cents would it cost to buy 3 pencils , 3 notebooks , and 3 erasers ? ( assume that there is no volume discount . )
Choose the correct choice from the following choices
A) 300 B) 315 C) 330 D) 345 E) 360 | <gadget id="calculator">80 - 45</gadget>
<output>35</output>
<gadget id="calculator">85 + 35</gadget>
<output>120</output>
<gadget id="calculator">120 / 2</gadget>
<output>60</output>
<gadget id="calculator">80 - 60</gadget>
<output>20</output>
<gadget id="calculator">45 - 20</gadget>
<output>25</output>
<gadget id="calculator">25 * 3</gadget>
<output>75</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">75 + 60</gadget>
<output>135</output>
<gadget id="calculator">60 * 3</gadget>
<output>180</output>
<gadget id="calculator">135 + 180</gadget>
<output>315</output>
<result>B</result> | B | 315 | martin buys a pencil and a notebook for 80 cents . at the same store , gloria buys a notebook and an eraser for 85 cents , and zachary buys a pencil and an eraser for 45 cents . how many cents would it cost to buy 3 pencils , 3 notebooks , and 3 erasers ? ( assume that there is no volume discount . ) | {
"A": "300",
"B": "315",
"C": "330",
"D": "345",
"E": "360"
} | add(add(multiply(subtract(45, subtract(80, divide(add(85, subtract(80, 45)), const_2))), 3), multiply(subtract(80, divide(add(85, subtract(80, 45)), const_2)), 3)), multiply(divide(add(85, subtract(80, 45)), const_2), 3)) | subtract(n0,n2)|add(n1,#0)|divide(#1,const_2)|multiply(n3,#2)|subtract(n0,#2)|multiply(n3,#4)|subtract(n2,#4)|multiply(n3,#6)|add(#7,#5)|add(#8,#3) | pencil + notebook = 80 notebook + eraser = 85 pencil + eraser = 45 let ' s add all three equations . 2 pencils + 2 notebooks + 2 erasers = 210 cents the cost to buy 3 of each would be ( 3 / 2 ) ( 210 ) = 315 the answer is b . | gain |
math_qa__jafrzn6B5YmzruXD | A man buys a cycle for Rs.1400 and sells it at a loss of 25%. What is the selling price of the cycle? Choose the most appropriate option
A) s . 1050
B) s . 1160
C) s . 1190
D) s . 1202
E) s . 1204 | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 * 1_400</gadget>
<output>105_000</output>
<gadget id="calculator">105_000 / 100</gadget>
<output>1_050</output>
<result>A</result> | A | 1,050 | A man buys a cycle for Rs.1400 and sells it at a loss of 25%. What is the selling price of the cycle? | {
"A": "s . 1050",
"B": "s . 1160",
"C": "s . 1190",
"D": "s . 1202",
"E": "s . 1204"
} | divide(multiply(subtract(const_100, 25), 1400), const_100) | subtract(const_100,n1)|multiply(n0,#0)|divide(#1,const_100)| | "since , c . p = 1400 loss % = ( c . p - s . p ) / c . p * 100 25 = ( 1400 - s . p ) / 1400 * 100 so , after solving answer = 1050 . answer : a" | gain |
math_qa__h2laAoAliqTCSZEF | 1+3=2 2+3=10 3+3=30 4+3=68 5+3=?? Pick one: A) 110 B) 120 C) 130 D) 140 E) 150 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 + 1</gadget>
<output>26</output>
<gadget id="calculator">26 * 5</gadget>
<output>130</output>
<result>C</result> | C | 130 | 1+3=2 2+3=10 3+3=30 4+3=68 5+3=?? | {
"A": "110",
"B": "120",
"C": "130",
"D": "140",
"E": "150"
} | multiply(add(multiply(5, 5), 1), 5) | multiply(n12,n12)|add(n0,#0)|multiply(n12,#1) | 1 ^ 3 + 3 - 2 = 2 , 2 ^ 3 + 3 - 1 = 10 , 3 ^ 3 + 3 - 0 = 30 , 4 ^ 3 + 3 + 1 = 68 , 5 ^ 3 + 3 + 2 = 130 answer : c | general |
math_qa__qE7nf4p2zbrpMGZA | A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 90 square feet of the wall, and no tiles overlap, what is the area of the entire wall? Choose one.
A) 160 B) 240 C) 360 D) 495 E) 560 | <gadget id="calculator">90 * 3</gadget>
<output>270</output>
<gadget id="calculator">270 / 2</gadget>
<output>135</output>
<gadget id="calculator">135 * 3</gadget>
<output>405</output>
<gadget id="calculator">90 + 405</gadget>
<output>495</output>
<result>D</result> | D | 495 | A rectangular wall is covered entirely with two kinds of decorative tiles: regular and jumbo. 1/3 of the tiles are jumbo tiles, which have a length three times that of regular tiles and have the same ratio of length to width as the regular tiles. If regular tiles cover 90 square feet of the wall, and no tiles overlap, what is the area of the entire wall? | {
"A": "160",
"B": "240",
"C": "360",
"D": "495",
"E": "560"
} | add(90, multiply(divide(multiply(90, 3), const_2), 3)) | multiply(n2,n1)|divide(#0,const_2)|multiply(n1,#1)|add(n2,#2)| | "the number of jumbo tiles = x . the number of regular tiles = 2 x . assume the ratio of the dimensions of a regular tile is a : a - - > area = a ^ 2 . the dimensions of a jumbo tile is 3 a : 3 a - - > area = 9 a ^ 2 . the area of regular tiles = 2 x * a ^ 2 = 90 . the area of jumbo tiles = x * 9 a ^ 2 = 4.5 ( 2 x * a ^ 2 ) = 4.5 * 90 = 405 . total area = 90 + 405 = 495 answer : d ." | geometry |
math_qa__yC0asU5eSrV5foMY | What is the difference between the place value of 2 in the numeral 7669? Answers
A) 160
B) 165
C) 180
D) 190
E) 540 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">600 - 60</gadget>
<output>540</output>
<result>E</result> | E | 540 | What is the difference between the place value of 2 in the numeral 7669? | {
"A": "160",
"B": "165",
"C": "180",
"D": "190",
"E": "540"
} | subtract(multiply(multiply(2, const_3), const_100), multiply(multiply(2, const_3), const_10)) | multiply(n0,const_3)|multiply(#0,const_100)|multiply(#0,const_10)|subtract(#1,#2) | answer : option ' e ' 600 - 60 = 540 | general |
math_qa__5MrJ1OQAHqRpMIm3 | Machine A and machine B are each used to manufacture 770 sprockets. It takes machine A 10 hours longer to produce 770 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces? Choose the correct choice
A) 5 B) 7 C) 9 D) 10 E) 12 | <gadget id="calculator">10 * 770</gadget>
<output>7_700</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">7_700 * (11/10)</gadget>
<output>8_470</output>
<gadget id="calculator">770 * (11/10)</gadget>
<output>847</output>
<gadget id="calculator">847 - 770</gadget>
<output>77</output>
<gadget id="calculator">8_470 / 77</gadget>
<output>110</output>
<gadget id="calculator">770 / 110</gadget>
<output>7</output>
<result>B</result> | B | 7 | Machine A and machine B are each used to manufacture 770 sprockets. It takes machine A 10 hours longer to produce 770 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces? | {
"A": "5",
"B": "7",
"C": "9",
"D": "10",
"E": "12"
} | divide(770, divide(multiply(multiply(10, 770), divide(add(const_100, 10), const_100)), subtract(multiply(770, divide(add(const_100, 10), const_100)), 770))) | add(n1,const_100)|multiply(n0,n1)|divide(#0,const_100)|multiply(#2,#1)|multiply(n0,#2)|subtract(#4,n0)|divide(#3,#5)|divide(n0,#6)| | "machine b : takes x hours to produce 770 sprockets machine a : takes ( x + 10 ) hours to produce 770 sprockets machine b : in 1 hour , b makes 770 / x sprockets machine a : in 1 hour , a makes 770 / ( x + 10 ) sprockets equating : 1.1 ( 770 / ( x + 10 ) ) = 770 / x 847 / ( x + 10 ) = 770 / x 847 x = 770 x + 7700 77 x = 7700 x = 100 a makes 770 / ( 110 ) = 7 sprockets per hour answer : b" | gain |
math_qa__UQmVG0r8qTK9kGSf | If X gets 25% more than Y and Y gets 20% more than Z, the share of Z out of Rs. 370 will be: Choose the correct choice from the following.
A) rs . 300
B) rs . 200
C) rs . 100
D) rs . 350
E) none of these | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(5/4) * (6/5)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + (6/5)</gadget>
<output>27/10 = around 2.7</output>
<gadget id="calculator">(27/10) + 1</gadget>
<output>37/10 = around 3.7</output>
<gadget id="calculator">370 / (37/10)</gadget>
<output>100</output>
<result>C</result> | C | 100 | If X gets 25% more than Y and Y gets 20% more than Z, the share of Z out of Rs. 370 will be: | {
"A": "rs . 300",
"B": "rs . 200",
"C": "rs . 100",
"D": "rs . 350",
"E": "none of these"
} | divide(370, add(add(multiply(add(const_1, divide(25, const_100)), add(const_1, divide(20, const_100))), add(const_1, divide(20, const_100))), const_1)) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#3,#2)|add(#2,#4)|add(#5,const_1)|divide(n2,#6) | z share = z , y = 1.2 z x = 1.25 ã — 1.2 z , x + y + z = 740 ( 1.25 ã — 1.2 + 1.2 + 1 ) z = 37 3.7 z = 370 , z = 100 answer : . c | general |
math_qa__fT8qeJNZHIeBYi7H | Village X has a population of 70000, which is decreasing at the rate of 1200 per year. Village Y has a population of 42000, which is increasing at the rate of 800 per year .in how many years will the population of the two villages be equal?
Choose the correct choice.
A) 14 B) 19 C) 11 D) 18 E) 13 | <gadget id="calculator">70_000 - 42_000</gadget>
<output>28_000</output>
<gadget id="calculator">800 + 1_200</gadget>
<output>2_000</output>
<gadget id="calculator">28_000 / 2_000</gadget>
<output>14</output>
<result>A</result> | A | 14 | Village X has a population of 70000, which is decreasing at the rate of 1200 per year. Village Y has a population of 42000, which is increasing at the rate of 800 per year .in how many years will the population of the two villages be equal? | {
"A": "14",
"B": "19",
"C": "11",
"D": "18",
"E": "13"
} | divide(subtract(70000, 42000), add(800, 1200)) | add(n1,n3)|subtract(n0,n2)|divide(#1,#0)| | "let the population of two villages be equal after p years then , 70000 - 1200 p = 42000 + 800 p 2000 p = 28000 p = 14 answer is a ." | general |
math_qa__03M8GBNovcnj5zBJ | A,B,C can do a piece of work in 11days, 20days and 55days respectively, working alone. How soon can the work be done if A is assisted by B and C on alternate days?
Pick one:
A) 2 B) 4 C) 8 D) 10 E) 12 | <gadget id="calculator">1 / 11</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/11) + (1/20)</gadget>
<output>31/220 = around 0.140909</output>
<gadget id="calculator">1 / 55</gadget>
<output>1/55 = around 0.018182</output>
<gadget id="calculator">(1/11) + (1/55)</gadget>
<output>6/55 = around 0.109091</output>
<gadget id="calculator">(31/220) + (6/55)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">2 / (1/4)</gadget>
<output>8</output>
<result>C</result> | C | 8 | A,B,C can do a piece of work in 11days, 20days and 55days respectively, working alone. How soon can the work be done if A is assisted by B and C on alternate days? | {
"A": "2",
"B": "4",
"C": "8",
"D": "10",
"E": "12"
} | divide(const_2, add(add(divide(const_1, 11), divide(const_1, 20)), add(divide(const_1, 11), divide(const_1, 55)))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#0,#2)|add(#3,#4)|divide(const_2,#5) | a + b 1 day work = 1 / 11 + 1 / 20 = 31 / 220 a + c 1 day work = 1 / 11 + 1 / 55 = 6 / 55 work done in 2 days = 31 / 220 + 6 / 55 = 55 / 220 = 1 / 4 1 / 4 work is done by a in 2 days whole work will be done in 2 * 4 = 8 days answer is c | physics |
math_qa__CRau4LLS5HweAMba | A group of men decided to do a work in 8days, but 3 of them became absent. If the rest of the group did the work in 10days, Find the original number of men? Choose the correct choice: A) 15 B) 20 C) 30 D) 25 E) 18 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">10 - 8</gadget>
<output>2</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>A</result> | A | 15 | A group of men decided to do a work in 8days, but 3 of them became absent. If the rest of the group did the work in 10days, Find the original number of men? | {
"A": "15",
"B": "20",
"C": "30",
"D": "25",
"E": "18"
} | divide(multiply(3, 10), subtract(10, 8)) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "original number of men = 3 * 10 / ( 10 - 8 ) = 15 answer is a" | physics |
math_qa__BKxA2cDu364zikDL | ? x 24 = 173 x 240 Choose the correct option
A) 545 B) 685 C) 865 D) 1730 E) 534 | <gadget id="calculator">173 * 240</gadget>
<output>41_520</output>
<gadget id="calculator">41_520 / 24</gadget>
<output>1_730</output>
<result>D</result> | D | 1,730 | ? x 24 = 173 x 240 | {
"A": "545",
"B": "685",
"C": "865",
"D": "1730",
"E": "534"
} | divide(multiply(173, 240), 24) | multiply(n1,n2)|divide(#0,n0)| | "let y x 24 = 173 x 240 then y = ( 173 x 240 ) / 24 = 173 x 10 = 1730 answer : d" | general |
math_qa__4Sr4QOV4inXOmBpQ | A man sells a car to his friend at 11% loss. If the friend sells it for Rs.54000 and gains 20%, the original C.P.of the car was : Choose one
A) rs . 25561.80 B) rs . 37500.80 C) rs . 50561.80 D) rs . 60000 E) none of these | <gadget id="calculator">54_000 * 100</gadget>
<output>5_400_000</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">5_400_000 / 120</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 * 100</gadget>
<output>4_500_000</output>
<gadget id="calculator">100 - 11</gadget>
<output>89</output>
<gadget id="calculator">4_500_000 / 89</gadget>
<output>4_500_000/89 = around 50_561.797753</output>
<result>C</result> | C | 50,561.8 | A man sells a car to his friend at 11% loss. If the friend sells it for Rs.54000 and gains 20%, the original C.P.of the car was : | {
"A": "rs . 25561.80",
"B": "rs . 37500.80",
"C": "rs . 50561.80",
"D": "rs . 60000",
"E": "none of these"
} | divide(multiply(divide(multiply(54000, const_100), add(const_100, 20)), const_100), subtract(const_100, 11)) | add(n2,const_100)|multiply(n1,const_100)|subtract(const_100,n0)|divide(#1,#0)|multiply(#3,const_100)|divide(#4,#2) | explanation : s . p = rs . 54,000 . gain earned = 20 % c . p = rs . [ 100 / 120 ã — 54000 ] = rs . 45000 this is the price the first person sold to the second at at loss of 11 % . now s . p = rs . 45000 and loss = 11 % c . p . rs . [ 100 / 89 ã — 45000 ] = rs . 50561.80 . correct option : c | gain |
math_qa__0CLCOIHeveQX9fp9 | Given that 268x74= 19532, find the value of 2.68x.74.
Pick one
A) 1.9532 B) 1.0025 C) 1.5693 D) 1.0266 E) none | <gadget id="calculator">268 / 100</gadget>
<output>67/25 = around 2.68</output>
<gadget id="calculator">74 / 100</gadget>
<output>37/50 = around 0.74</output>
<gadget id="calculator">(67/25) * (37/50)</gadget>
<output>2_479/1_250 = around 1.9832</output>
<result>A</result> | A | 1.9532 | Given that 268x74= 19532, find the value of 2.68x.74. | {
"A": "1.9532",
"B": "1.0025",
"C": "1.5693",
"D": "1.0266",
"E": "none"
} | multiply(divide(268, const_100), divide(74, const_100)) | divide(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)| | "solution sum of decimals places = ( 2 + 2 ) = 4 . therefore , = 2.68 × . 74 = 1.9532 answer a" | general |
math_qa__I7cp2hrrWxk722ef | After a storm deposits 115 billion gallons of water into the city reservoir, the reservoir is 80% full. If the original contents of the reservoir totaled 245 billion gallons, the reservoir was approximately what percentage full before the storm? Pick.
A) 45 % B) 48 % C) 54 % D) 58 % E) 65 % | <gadget id="calculator">115 + 245</gadget>
<output>360</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">360 / (4/5)</gadget>
<output>450</output>
<gadget id="calculator">245 / 450</gadget>
<output>49/90 = around 0.544444</output>
<gadget id="calculator">(49/90) * 100</gadget>
<output>490/9 = around 54.444444</output>
<result>C</result> | C | 54 | After a storm deposits 115 billion gallons of water into the city reservoir, the reservoir is 80% full. If the original contents of the reservoir totaled 245 billion gallons, the reservoir was approximately what percentage full before the storm? | {
"A": "45 %",
"B": "48 %",
"C": "54 %",
"D": "58 %",
"E": "65 %"
} | multiply(divide(245, divide(add(115, 245), divide(80, const_100))), const_100) | add(n0,n2)|divide(n1,const_100)|divide(#0,#1)|divide(n2,#2)|multiply(#3,const_100)| | "when the storm deposited 115 billion gallons , volume of water in the reservoir = 245 + 115 = 360 billion gallons if this is only 80 % of the capacity of the reservoir , the total capacity of the reservoir = 360 / 0.8 = 450 billion gallons therefore percentage of reservoir that was full before the storm = ( 245 / 450 ) * 100 = 54.4 % option c" | general |
math_qa__RzfF1jJt1nx7Bim1 | The sum of the ages of 5 children born at the intervals of 2 years each is 50 years. what is the age of the youngest child ? Choose the correct choice from the following choices
A) 6 B) 18 C) 10 D) 99 E) 38 | <gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">50 / (5/2)</gadget>
<output>20</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>A</result> | A | 6 | The sum of the ages of 5 children born at the intervals of 2 years each is 50 years. what is the age of the youngest child ? | {
"A": "6",
"B": "18",
"C": "10",
"D": "99",
"E": "38"
} | divide(subtract(divide(50, divide(5, const_2)), multiply(subtract(5, const_1), 2)), const_2) | divide(n0,const_2)|subtract(n0,const_1)|divide(n2,#0)|multiply(n1,#1)|subtract(#2,#3)|divide(#4,const_2) | let x = the youngest child . each of the other four children will then be x + 2 , x + 4 , x + 6 , x + 8 . we know that the sum of their ages is 50 . so , x + ( x + 2 ) + ( x + 4 ) + ( x + 6 ) + ( x + 8 ) = 50 therefore the youngest child is 6 years old answer : a | general |
math_qa__Lfg0w3Pz9y26ew7e | An inspector rejects 0.08% of the meters as defective, How many meters he examine to reject 2 meteres
Choose the correct answer:
A) 1200
B) 2400
C) 1400
D) 2500
E) none of these | <gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 / 0.08</gadget>
<output>2_500</output>
<result>D</result> | D | 2,500 | An inspector rejects 0.08% of the meters as defective, How many meters he examine to reject 2 meteres | {
"A": "1200",
"B": "2400",
"C": "1400",
"D": "2500",
"E": "none of these"
} | divide(multiply(2, const_100), 0.08) | multiply(n1,const_100)|divide(#0,n0) | explanation : it means that 0.08 % of x = 2 = > ( 8 / 100 × 100 × x ) = 2 = > x = 2 × 100 × 100 / 8 = > x = 2500 option d | gain |
math_qa__ffIqyohiLN3pn1uj | Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 36/49, what is the probability that the next one she draws will be pink?
Choose the correct choice from the following:
A) 1 / 7 B) 4 / 7 C) 3 / 7 D) 16 / 49 E) 40 / 49 | <gadget id="calculator">36 / 49</gadget>
<output>36/49 = around 0.734694</output>
<gadget id="calculator">(36/49) ** (1/2)</gadget>
<output>6/7 = around 0.857143</output>
<gadget id="calculator">1 - (6/7)</gadget>
<output>1/7 = around 0.142857</output>
<result>A</result> | A | 0.142857 | Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 36/49, what is the probability that the next one she draws will be pink? | {
"A": "1 / 7",
"B": "4 / 7",
"C": "3 / 7",
"D": "16 / 49",
"E": "40 / 49"
} | subtract(const_1, sqrt(divide(36, 49))) | divide(n0,n1)|sqrt(#0)|subtract(const_1,#1)| | "the probability of drawing a pink gumball both times is the same . the probability that she drew two blue gumballs = 36 / 49 = ( 6 / 7 ) * ( 6 / 7 ) therefore probability that the next one she draws is pink = 1 / 7 option ( a )" | general |
math_qa__9nYQxMYg7Xbu1yxk | Increasing the original price of a certain item by 30 percent and then increasing the new price by 30 percent is equivalent to increasing the original price by what percent? Choose the correct choice from the following
A) 31.25
B) 37.5
C) 50.0
D) 52.5
E) 69.0 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) + 1</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">(13/10) * (13/10)</gadget>
<output>169/100 = around 1.69</output>
<gadget id="calculator">(169/100) - 1</gadget>
<output>69/100 = around 0.69</output>
<gadget id="calculator">(69/100) * 100</gadget>
<output>69</output>
<result>E</result> | E | 69 | Increasing the original price of a certain item by 30 percent and then increasing the new price by 30 percent is equivalent to increasing the original price by what percent? | {
"A": "31.25",
"B": "37.5",
"C": "50.0",
"D": "52.5",
"E": "69.0"
} | multiply(subtract(multiply(add(divide(30, const_100), const_1), add(divide(30, const_100), const_1)), const_1), const_100) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "we ' re told that the original price of an item is increased by 30 % and then that price is increased by 30 % . . . . if . . . . starting value = $ 100 + 30 % = 100 + . 30 ( 100 ) = 130 + 30 % = 130 + . 30 ( 130 ) = 130 + 39 = 169 the question asks how the final price relates to the original price . this is essentially about percentage change , which means we should use the percentage change formula : percentage change = ( new - old ) / old = difference / original doing either calculation will yield the same result : 59 / 100 = 69 % final answer : e" | gain |
math_qa__lYwzB55M6EfOrGNF | The area of a square garden is A square feet and the perimeter is p feet. If a=2p+15, what is the perimeter of the garden, in feet? Answers
A) 28 B) 36 C) 40 D) 56 E) 64 | <gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">10 + 30</gadget>
<output>40</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">40 - (1/4)</gadget>
<output>159/4 = around 39.75</output>
<gadget id="calculator">(159/4) - (1/4)</gadget>
<output>79/2 = around 39.5</output>
<result>C</result> | C | 40 | The area of a square garden is A square feet and the perimeter is p feet. If a=2p+15, what is the perimeter of the garden, in feet? | {
"A": "28",
"B": "36",
"C": "40",
"D": "56",
"E": "64"
} | subtract(subtract(add(const_10, multiply(15, 2)), const_0_25), const_0_25) | multiply(n0,n1)|add(#0,const_10)|subtract(#1,const_0_25)|subtract(#2,const_0_25)| | "perimeter of square = p side of square = p / 4 area of square = ( p ^ 2 ) / 16 = a given that a = 2 p + 15 ( p ^ 2 ) / 16 = 2 p + 15 p ^ 2 = 32 p + 240 p ^ 2 - 32 p - 240 = 0 p ^ 2 - 40 p + 6 p - 240 = 0 p ( p - 40 ) + 6 ( p + 40 ) = 0 ( p - 40 ) ( p + 6 ) = 0 p = 40 or - 6 discarding negative value , p = 40 answer is c" | geometry |
math_qa__uNGLSv2wa8uJnApQ | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 370 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school? Choose the most appropriate option:
A) 237
B) 287
C) 197
D) 740
E) 720 | <gadget id="calculator">370 * 2</gadget>
<output>740</output>
<result>D</result> | D | 740 | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 370 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school? | {
"A": "237",
"B": "287",
"C": "197",
"D": "740",
"E": "720"
} | multiply(370, const_2) | multiply(n0,const_2) | explanation : let the number of children in the school be x . since each child gets 2 bananas , total number of bananas = 2 x . 2 x / ( x - 370 ) = 2 + 2 ( extra ) = > 2 x - 740 = x = > x = 740 . answer : d | general |
math_qa__dHNy0ZmDmgUrpsGw | If the perimeter of a rectangular garden is 900 m, its length when its breadth is 190 m is?
Choose the most appropriate option:
A) 338 m
B) 778 m
C) 200 m
D) 260 m
E) 971 m | <gadget id="calculator">900 / 2</gadget>
<output>450</output>
<gadget id="calculator">450 - 190</gadget>
<output>260</output>
<result>D</result> | D | 260 | If the perimeter of a rectangular garden is 900 m, its length when its breadth is 190 m is? | {
"A": "338 m",
"B": "778 m",
"C": "200 m",
"D": "260 m",
"E": "971 m"
} | subtract(divide(900, const_2), 190) | divide(n0,const_2)|subtract(#0,n1)| | "2 ( l + 190 ) = 900 = > l = 260 m answer : d" | physics |
math_qa__YgBBnRqo15iyNH5j | Brenda and Sally run in opposite direction on a circular track, starting at diametrically opposite points. They first meet after Brenda has run 100 meters. They next meet after Sally has run 200 meters past their first meeting point. Each girl runs at a constant speed. What is the length of the track in meters? Choose the correct choice
A) 250 B) 300 C) 350 D) 400 E) 500 | <gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 + 200</gadget>
<output>400</output>
<result>D</result> | D | 400 | Brenda and Sally run in opposite direction on a circular track, starting at diametrically opposite points. They first meet after Brenda has run 100 meters. They next meet after Sally has run 200 meters past their first meeting point. Each girl runs at a constant speed. What is the length of the track in meters? | {
"A": "250",
"B": "300",
"C": "350",
"D": "400",
"E": "500"
} | add(multiply(const_2, 100), 200) | multiply(n0,const_2)|add(n1,#0)| | "nice problem . + 1 . first timetogetherthey run half of the circumference . second timetogetherthey run full circumference . first time brenda runs 100 meters , thus second time she runs 2 * 100 = 200 meters . since second time ( when they run full circumference ) brenda runs 200 meters and sally runs 200 meters , thus the circumference is 200 + 200 = 400 meters . answer : d ." | physics |
math_qa__OU1GurKfj2EtjRhb | If (2 to the x) - (2 to the (x-2)) = 3 (2 to the 11), what is the value of x? Options.
A) 9 B) 11 C) 13 D) 15 E) 17 | <gadget id="calculator">11 + 2</gadget>
<output>13</output>
<result>C</result> | C | 13 | If (2 to the x) - (2 to the (x-2)) = 3 (2 to the 11), what is the value of x? | {
"A": "9",
"B": "11",
"C": "13",
"D": "15",
"E": "17"
} | add(11, 2) | add(n0,n5)| | "( 2 to the power x ) - ( 2 to the power ( x - 2 ) ) = 3 ( 2 to the power 11 ) 2 ^ x - 2 ^ ( x - 2 ) = 3 . 2 ^ 11 hence x = 13 . answer is c" | general |
math_qa__jHMY6X6Ja2lSLDx6 | The vertex of a rectangle are (1, 0), (9, 0), (1, 2) and (9, 2) respectively. If line L passes through the origin and divided the rectangle into two identical quadrilaterals, what is the slope of line L? Choose one: A) 5 B) 4 C) 1 / 2 D) 1 / 5 E) 1 / 8 | <gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<result>D</result> | D | 0.2 | The vertex of a rectangle are (1, 0), (9, 0), (1, 2) and (9, 2) respectively. If line L passes through the origin and divided the rectangle into two identical quadrilaterals, what is the slope of line L? | {
"A": "5",
"B": "4",
"C": "1 / 2",
"D": "1 / 5",
"E": "1 / 8"
} | divide(const_1, divide(add(subtract(9, 1), const_2), const_2)) | subtract(n2,n0)|add(#0,const_2)|divide(#1,const_2)|divide(const_1,#2) | if line l divides the rectangle into two identical quadrilaterals , then it must pass through the center ( 5 , 1 ) . the slope of a line passing through ( 0,0 ) and ( 5 , 1 ) is 1 / 5 . the answer is d . | general |
math_qa__RZ1WDHk9xTi4LRNt | For each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to charity. In December, the worker earned N times his usual monthly salary and donated one-third of his earnings to charity. If the worker's charitable contributions totaled one-eighth of his earnings for the entire year, what is the value of N? Choose the correct choice from the following answers: A) 8 / 5 B) 5 / 2 C) 3 D) 33 / 25 E) 4 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">12 - 3</gadget>
<output>9</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/9) - (1/10)</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">11 * (1/90)</gadget>
<output>11/90 = around 0.122222</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) - (1/9)</gadget>
<output>4/45 = around 0.088889</output>
<gadget id="calculator">(11/90) / (4/45)</gadget>
<output>11/8 = around 1.375</output>
<result>D</result> | D | 1.32 | For each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to charity. In December, the worker earned N times his usual monthly salary and donated one-third of his earnings to charity. If the worker's charitable contributions totaled one-eighth of his earnings for the entire year, what is the value of N? | {
"A": "8 / 5",
"B": "5 / 2",
"C": "3",
"D": "33 / 25",
"E": "4"
} | divide(multiply(subtract(const_12, const_1), subtract(inverse(subtract(const_12, const_3)), inverse(const_10))), subtract(inverse(add(const_1, const_4)), inverse(subtract(const_12, const_3)))) | add(const_1,const_4)|inverse(const_10)|subtract(const_12,const_1)|subtract(const_12,const_3)|inverse(#3)|inverse(#0)|subtract(#4,#1)|subtract(#5,#4)|multiply(#2,#6)|divide(#8,#7)| | "let monthly salary for each of the 11 months except december was x , then 11 x * 1 / 10 + nx * 1 / 3 = 1 / 8 ( 11 x + nx ) ; 11 / 10 + n / 3 = 1 / 8 ( 11 + n ) 33 + 10 n / 30 = 11 + n / 8 = > 264 + 80 n = 330 + 30 n = > 50 n = 66 n = 66 / 50 = 33 / 25 answer : d ." | general |
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