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stringlengths 7
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math_qa__MgJ03sGH4GfMnmEw | Two trains each 170m in length each, are running on two parallel lines in opposite directions. If one goes at the speed of 55km/h while the other travels at 50km/h. how long will it take for them to pass each other completely.
Select the correct option:
A) 15 sec B) 11.6 sec C) 31.6 sec D) 12.6 sec E) 23 sec | <gadget id="calculator">170 + 170</gadget>
<output>340</output>
<gadget id="calculator">340 / 1_000</gadget>
<output>17/50 = around 0.34</output>
<gadget id="calculator">55 + 50</gadget>
<output>105</output>
<gadget id="calculator">(17/50) / 105</gadget>
<output>17/5_250 = around 0.003238</output>
<gadget id="calculator">3_600 * (17/5_250)</gadget>
<output>408/35 = around 11.657143</output>
<result>B</result> | B | 11.6 | Two trains each 170m in length each, are running on two parallel lines in opposite directions. If one goes at the speed of 55km/h while the other travels at 50km/h. how long will it take for them to pass each other completely. | {
"A": "15 sec",
"B": "11.6 sec",
"C": "31.6 sec",
"D": "12.6 sec",
"E": "23 sec"
} | multiply(const_3600, divide(divide(add(170, 170), const_1000), add(55, 50))) | add(n0,n0)|add(n1,n2)|divide(#0,const_1000)|divide(#2,#1)|multiply(#3,const_3600) | explanation : d = 170 m + 170 m = 340 m rs = 55 + 50 = 105 * 5 / 18 = 146 / 5 t = 340 * 5 / 146 = 11.6 sec answer : option b | physics |
math_qa__9ebTpYXd4To3s3iy | 8 cups of water are to be poured into a 4-cup bottle and a 8-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of water should be poured into the 8-cup bottle? Choose the correct choice from the following: A) 2 / 3 B) 7 / 3 C) 5 / 2 D) 8 / 3 E) 16 / 3 | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">16 / 6</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">(8/3) * 2</gadget>
<output>16/3 = around 5.333333</output>
<result>E</result> | E | 5.333333 | 8 cups of water are to be poured into a 4-cup bottle and a 8-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of water should be poured into the 8-cup bottle? | {
"A": "2 / 3",
"B": "7 / 3",
"C": "5 / 2",
"D": "8 / 3",
"E": "16 / 3"
} | multiply(divide(multiply(8, const_2), add(4, const_2)), const_2) | add(n1,const_2)|multiply(n0,const_2)|divide(#1,#0)|multiply(#2,const_2) | let x be the # of cups going into the 8 cup bottle . so . . . . x / 8 = ( ( 8 - x ) / 4 ) 64 - 8 x = 4 x 64 = 12 x x = 16 / 3 . answer : e | general |
math_qa__PLRwgiM4Mj4wiGOn | A candidate got 30% of the votes polled and he lost to his rival by 4000 votes. How many votes were cast? Options:
A) 7500 B) 2028 C) 2775 D) 10000 E) 6851 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) - (3/10)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">4_000 / (2/5)</gadget>
<output>10_000</output>
<result>D</result> | D | 10,000 | A candidate got 30% of the votes polled and he lost to his rival by 4000 votes. How many votes were cast? | {
"A": "7500",
"B": "2028",
"C": "2775",
"D": "10000",
"E": "6851"
} | divide(4000, subtract(subtract(const_1, divide(30, const_100)), divide(30, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n1,#2)| | "30 % - - - - - - - - - - - l 70 % - - - - - - - - - - - w - - - - - - - - - - - - - - - - - - 40 % - - - - - - - - - - 4000 100 % - - - - - - - - - ? = > 10000 answer : d" | gain |
math_qa__rXDWLOeuVymaxaQY | The average age of a group of n people is 14 years old. One more person aged 32 joins the group and the new average is 15 years old. What is the value of n?
Choose the correct answer.
A) 13 B) 14 C) 15 D) 16 E) 17 | <gadget id="calculator">32 - 15</gadget>
<output>17</output>
<gadget id="calculator">15 - 14</gadget>
<output>1</output>
<gadget id="calculator">17 / 1</gadget>
<output>17</output>
<result>E</result> | E | 17 | The average age of a group of n people is 14 years old. One more person aged 32 joins the group and the new average is 15 years old. What is the value of n? | {
"A": "13",
"B": "14",
"C": "15",
"D": "16",
"E": "17"
} | divide(subtract(32, 15), subtract(15, 14)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "14 n + 32 = 15 ( n + 1 ) n = 17 the answer is e ." | general |
math_qa__QpQF7hJlG22MsJ3f | The average of 7 numbers is 26. If each number be multiplied by 5. Find the average of new set of numbers? Options: A) 110 B) 122 C) 120 D) 125 E) 130 | <gadget id="calculator">26 * 5</gadget>
<output>130</output>
<result>E</result> | E | 130 | The average of 7 numbers is 26. If each number be multiplied by 5. Find the average of new set of numbers? | {
"A": "110",
"B": "122",
"C": "120",
"D": "125",
"E": "130"
} | multiply(26, 5) | multiply(n1,n2)| | "explanation : average of new numbers = 26 * 5 = 130 answer : option e" | general |
math_qa__wDWFiXXBJitQRFwz | If 5% more is gained by selling an article for Rs. 350 than by selling it for Rs. 345, the cost of the article is
Choose the correct choice from the following answers:
A) 289 B) 231 C) 100 D) 288 E) 111 | <gadget id="calculator">350 - 345</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">5 / (1/20)</gadget>
<output>100</output>
<result>C</result> | C | 100 | If 5% more is gained by selling an article for Rs. 350 than by selling it for Rs. 345, the cost of the article is | {
"A": "289",
"B": "231",
"C": "100",
"D": "288",
"E": "111"
} | divide(subtract(350, 345), divide(5, const_100)) | divide(n0,const_100)|subtract(n1,n2)|divide(#1,#0)| | "explanation : let c . p . be rs . x . then , 5 % of x = 350 - 345 = 5 x / 20 = 5 = > x = 100 answer : c" | gain |
math_qa__tSKTN9l1FgLpUcbl | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 4. If the sum of their ages is 88, what is the difference between the ages of Patrick and Monica? Options
A) 22 B) 48 C) 45 D) 72 E) 18 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">9 + 15</gadget>
<output>24</output>
<gadget id="calculator">24 + 20</gadget>
<output>44</output>
<gadget id="calculator">88 / 44</gadget>
<output>2</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">40 - 18</gadget>
<output>22</output>
<result>A</result> | A | 22 | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 4. If the sum of their ages is 88, what is the difference between the ages of Patrick and Monica? | {
"A": "22",
"B": "48",
"C": "45",
"D": "72",
"E": "18"
} | subtract(multiply(multiply(4, 5), divide(88, add(add(multiply(3, 3), multiply(3, 5)), multiply(4, 5)))), multiply(multiply(3, 3), divide(88, add(add(multiply(3, 3), multiply(3, 5)), multiply(4, 5))))) | multiply(n0,n0)|multiply(n1,n0)|multiply(n1,n3)|add(#0,#1)|add(#3,#2)|divide(n4,#4)|multiply(#5,#2)|multiply(#5,#0)|subtract(#6,#7)| | "ages of p and mi = 3 x : 5 x ages of mi and mo = 3 x : 4 x rationalizing their ages . ratio of their ages will be 9 x : 15 x : 20 x sum = 44 x = 88 x = 2 difference if ages of pa and mo = 20 x - 9 x = 11 x = 11 * 2 = 22 answer a" | general |
math_qa__vNf5FLjOiyEJK1Kd | 14 business executives and 7 chairmen meet at a conference. If each business executive shakes the hand of every other business executive and every chairman once, and each chairman shakes the hand of each of the business executives but not the other chairmen, how many handshakes would take place?
Choose one.
A) 144
B) 131
C) 115
D) 189
E) 45 | <gadget id="calculator">14 - 1</gadget>
<output>13</output>
<gadget id="calculator">14 * 13</gadget>
<output>182</output>
<gadget id="calculator">182 / 2</gadget>
<output>91</output>
<gadget id="calculator">14 * 7</gadget>
<output>98</output>
<gadget id="calculator">91 + 98</gadget>
<output>189</output>
<result>D</result> | D | 189 | 14 business executives and 7 chairmen meet at a conference. If each business executive shakes the hand of every other business executive and every chairman once, and each chairman shakes the hand of each of the business executives but not the other chairmen, how many handshakes would take place? | {
"A": "144",
"B": "131",
"C": "115",
"D": "189",
"E": "45"
} | add(divide(multiply(14, subtract(14, const_1)), const_2), multiply(14, 7)) | multiply(n0,n1)|subtract(n0,const_1)|multiply(n0,#1)|divide(#2,const_2)|add(#3,#0)| | "there are 14 business exec and in each handshake 2 business execs are involved . hence 14 c 2 = 91 also , each of 14 exec will shake hand with every 7 other chairmen for total of 98 handshake . total = 91 + 98 = 189 ans : d" | geometry |
math_qa__vZbkywr5K44wBUWg | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 11 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled? Pick:
A) 6.24
B) 7.4
C) 7.92
D) 6.28
E) 7.24 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 11</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/4) - (1/11)</gadget>
<output>7/44 = around 0.159091</output>
<gadget id="calculator">1 / (7/44)</gadget>
<output>44/7 = around 6.285714</output>
<result>D</result> | D | 6.28 | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 11 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled? | {
"A": "6.24",
"B": "7.4",
"C": "7.92",
"D": "6.28",
"E": "7.24"
} | divide(const_1, subtract(divide(const_1, 4), divide(const_1, 11))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)| | "net part filled in 1 hour = ( 1 / 4 - 1 / 11 ) = 7 / 44 the cistern will be filled in 44 / 7 hrs i . e . , 6.28 hrs . answer : d" | physics |
math_qa__IYCsAnkM32il5GXM | What is 3/7 of 7/8 of 1/3?
Choose the correct choice from the following answers.
A) 1 / 4 B) 3 / 8 C) 9 / 16 D) 1 / 8 E) 16 / 9 | <gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(7/8) * (1/3)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">(3/7) * (7/24)</gadget>
<output>1/8 = around 0.125</output>
<result>D</result> | D | 0.125 | What is 3/7 of 7/8 of 1/3? | {
"A": "1 / 4",
"B": "3 / 8",
"C": "9 / 16",
"D": "1 / 8",
"E": "16 / 9"
} | multiply(divide(3, 7), multiply(divide(7, 8), divide(1, 3))) | divide(n0,n1)|divide(n1,n3)|divide(n4,n0)|multiply(#1,#2)|multiply(#0,#3) | 3 / 7 * 7 / 8 * 1 / 3 = 1 / 8 answer : d | general |
math_qa__8Hy3bZka8lMPj4PC | The least number which should be added to 2400 so that the sum is exactly divisible by 5,6,4 and 3 is : Choose the correct option
A) 3 B) 13 C) 20 D) 33 E) 43 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">2_400 / 60</gadget>
<output>40</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<result>C</result> | C | 20 | The least number which should be added to 2400 so that the sum is exactly divisible by 5,6,4 and 3 is : | {
"A": "3",
"B": "13",
"C": "20",
"D": "33",
"E": "43"
} | subtract(multiply(multiply(multiply(const_2, const_2), 5), 3), divide(2400, multiply(multiply(multiply(const_2, const_2), 5), 3))) | multiply(const_2,const_2)|multiply(n1,#0)|multiply(n3,#1)|divide(n0,#2)|subtract(#2,#3) | solution l . c . m . of 5 , 6,4 and 3 = 60 . on dividing 2400 by 60 , the remainder is 40 . ∴ number to be added = ( 60 - 40 ) = 20 . answer c | general |
math_qa__Q6Xi94a2UJyjFq3f | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 82 more candidates got selected than A. What was the number of candidates appeared from each State? Choose the correct choice from the following answers: A) 8400 B) 8200 C) 6000 D) 5000 E) 4000 | <gadget id="calculator">7 - 6</gadget>
<output>1</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">82 / (1/100)</gadget>
<output>8_200</output>
<result>B</result> | B | 8,200 | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 82 more candidates got selected than A. What was the number of candidates appeared from each State? | {
"A": "8400",
"B": "8200",
"C": "6000",
"D": "5000",
"E": "4000"
} | divide(82, divide(subtract(7, 6), const_100)) | subtract(n1,n0)|divide(#0,const_100)|divide(n2,#1)| | "state a and state b had an equal number of candidates appeared . in state a , 6 % candidates got selected from the total appeared candidates in state b , 7 % candidates got selected from the total appeared candidates but in state b , 82 more candidates got selected than state a from these , it is clear that 1 % of the total appeared candidates in state b = 82 = > total appeared candidates in state b = 82 x 100 = 8200 = > total appeared candidates in state a = total appeared candidates in state b = 8200" | general |
math_qa__7xO533fqoWxago5m | A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 100 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Choices:
A) 28 sec B) 16 sec C) 34 sec D) 18 sec E) 17 sec | <gadget id="calculator">240 + 100</gadget>
<output>340</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">5 / 18</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">340 / 10</gadget>
<output>34</output>
<result>C</result> | C | 34 | A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 100 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? | {
"A": "28 sec",
"B": "16 sec",
"C": "34 sec",
"D": "18 sec",
"E": "17 sec"
} | divide(add(240, 100), multiply(subtract(45, 9), divide(divide(const_10, const_2), divide(subtract(45, 9), const_2)))) | add(n1,n2)|divide(const_10,const_2)|subtract(n3,n0)|divide(#2,const_2)|divide(#1,#3)|multiply(#4,#2)|divide(#0,#5)| | "speed of train relative to jogger = 45 - 9 = 36 km / hr . = 36 * 5 / 18 = 10 m / sec . distance to be covered = 240 + 100 = 340 m . time taken = 340 / 10 = 34 sec . answer : c" | general |
math_qa__hhzV84WrOrVVY7wc | In an election between two candidates A and B, the number of valid votes received by A exceeds those received by B by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 8720 votes were polled, then how many valid votes did B get? Answers.
A) 1888 B) 2999 C) 2834 D) 2777 E) 2991 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 8_720</gadget>
<output>6_976</output>
<gadget id="calculator">15 * 8_720</gadget>
<output>130_800</output>
<gadget id="calculator">130_800 / 100</gadget>
<output>1_308</output>
<gadget id="calculator">6_976 - 1_308</gadget>
<output>5_668</output>
<gadget id="calculator">5_668 / 2</gadget>
<output>2_834</output>
<result>C</result> | C | 2,834 | In an election between two candidates A and B, the number of valid votes received by A exceeds those received by B by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 8720 votes were polled, then how many valid votes did B get? | {
"A": "1888",
"B": "2999",
"C": "2834",
"D": "2777",
"E": "2991"
} | divide(subtract(multiply(subtract(const_1, divide(20, const_100)), 8720), divide(multiply(15, 8720), const_100)), const_2) | divide(n1,const_100)|multiply(n0,n2)|divide(#1,const_100)|subtract(const_1,#0)|multiply(n2,#3)|subtract(#4,#2)|divide(#5,const_2)| | "let the total number of votes polled in the election be 100 k . number of valid votes = 100 k - 20 % ( 100 k ) = 80 k let the number of votes polled in favour of a and b be a and b respectively . a - b = 15 % ( 100 k ) = > a = b + 15 k = > a + b = b + 15 k + b now , 2 b + 15 k = 80 k and hence b = 32.5 k it is given that 100 k = 8720 32.5 k = 32.5 k / 100 k * 8720 = 2834 the number of valid votes polled in favour of b is 2834 . answer : c" | general |
math_qa__3iCG0ZHcqGaSkh5C | What will be the difference between simple and compound interest at 16% per annum on a sum of Rs. 1000 after 4 years?
Choose the correct choice from the following:
A) 164.19
B) 164.12
C) 170.6
D) 167.1
E) 165.11 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) + 1</gadget>
<output>29/25 = around 1.16</output>
<gadget id="calculator">(29/25) ** 4</gadget>
<output>707_281/390_625 = around 1.810639</output>
<gadget id="calculator">1_000 * (707_281/390_625)</gadget>
<output>5_658_248/3_125 = around 1_810.63936</output>
<gadget id="calculator">(5_658_248/3_125) - 1_000</gadget>
<output>2_533_248/3_125 = around 810.63936</output>
<gadget id="calculator">1_000 * (4/25)</gadget>
<output>160</output>
<gadget id="calculator">160 * 4</gadget>
<output>640</output>
<gadget id="calculator">(2_533_248/3_125) - 640</gadget>
<output>533_248/3_125 = around 170.63936</output>
<result>C</result> | C | 170.6 | What will be the difference between simple and compound interest at 16% per annum on a sum of Rs. 1000 after 4 years? | {
"A": "164.19",
"B": "164.12",
"C": "170.6",
"D": "167.1",
"E": "165.11"
} | subtract(subtract(multiply(1000, power(add(divide(16, const_100), const_1), 4)), 1000), multiply(multiply(1000, divide(16, const_100)), 4)) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|multiply(n2,#2)|power(#1,n2)|multiply(n1,#4)|subtract(#5,n1)|subtract(#6,#3)| | "s . i . = ( 1000 * 16 * 4 ) / 100 = rs . 640 c . i . = [ 1000 * ( 1 + 16 / 100 ) 4 - 1000 ] = rs . 810.6 difference = ( 810.6 - 640 ) = rs . 170.6 answer : c" | gain |
math_qa__xIgFQAMrQamGzHsY | In what time will a train 350 m long cross an electric pole, it its speed be 144 km/hr? Options.
A) 2.5 sec B) 2.95 sec C) 1.3 sec D) 8.75 sec E) 1.85 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">350 / 40</gadget>
<output>35/4 = around 8.75</output>
<result>D</result> | D | 8.75 | In what time will a train 350 m long cross an electric pole, it its speed be 144 km/hr? | {
"A": "2.5 sec",
"B": "2.95 sec",
"C": "1.3 sec",
"D": "8.75 sec",
"E": "1.85 sec"
} | divide(350, multiply(144, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 144 * 5 / 18 = 40 m / sec time taken = 100 / 40 = 8.75 sec . answer : d" | physics |
math_qa__UCuaFZjqhpyokLLF | An aeroplane covers a certain distance of 530 Kmph in 5 hours. to cover the same distance in 3 2/3 hours, it Must travel at a speed of
Choose the most appropriate option: A) 440 B) 540 C) 640 D) 722 E) 250 | <gadget id="calculator">530 * 5</gadget>
<output>2_650</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 2</gadget>
<output>11</output>
<gadget id="calculator">11 / 3</gadget>
<output>11/3 = around 3.666667</output>
<gadget id="calculator">2_650 / (11/3)</gadget>
<output>7_950/11 = around 722.727273</output>
<result>D</result> | D | 722 | An aeroplane covers a certain distance of 530 Kmph in 5 hours. to cover the same distance in 3 2/3 hours, it Must travel at a speed of | {
"A": "440",
"B": "540",
"C": "640",
"D": "722",
"E": "250"
} | divide(multiply(530, 5), divide(add(multiply(3, 3), 2), 3)) | multiply(n0,n1)|multiply(n2,n4)|add(n3,#1)|divide(#2,n4)|divide(#0,#3)| | "speed of aeroplane = 530 kmph distance travelled in 5 hours = 530 * 5 = 2650 km speed of aeroplane to acver 2650 km in 11 / 3 = 2650 * 3 / 11 = 722 km answer d" | physics |
math_qa__Fk8t0lp0thA18Mwj | There are 4 red books and 4 blue books on a shelf. If 2 books are selected at random from the shelf, what is the probability that both books selected are red books? Pick.
A) 2 / 7
B) 3 / 7
C) 3 / 14
D) 5 / 28
E) 9 / 28 | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">4 / 8</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(1/2) * (3/7)</gadget>
<output>3/14 = around 0.214286</output>
<result>C</result> | C | 0.214286 | There are 4 red books and 4 blue books on a shelf. If 2 books are selected at random from the shelf, what is the probability that both books selected are red books? | {
"A": "2 / 7",
"B": "3 / 7",
"C": "3 / 14",
"D": "5 / 28",
"E": "9 / 28"
} | multiply(divide(4, add(4, 4)), divide(subtract(4, const_1), subtract(add(4, 4), const_1))) | add(n0,n0)|subtract(n0,const_1)|divide(n0,#0)|subtract(#0,const_1)|divide(#1,#3)|multiply(#2,#4) | the number of ways of choosing 2 books from the shelf is 8 c 2 = 28 . the number of ways of choosing 2 red books is 4 c 2 = 6 . p ( 2 red books ) = 6 / 28 = 3 / 14 . the answer is c . | other |
math_qa__MCnlPSbn9jxj7eYx | On a ranch, a rancher can place a loop of rope, called a lasso, once in every 2 throws around a cow’s neck. What is the probability that the rancher will be able to place a lasso around a cow’s neck at least once in 4 attempts? Choose one:
A) 3 / 4 B) 5 / 8 C) 7 / 8 D) 11 / 16 E) 15 / 16 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 4</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">1 - (1/16)</gadget>
<output>15/16 = around 0.9375</output>
<result>E</result> | E | 0.9375 | On a ranch, a rancher can place a loop of rope, called a lasso, once in every 2 throws around a cow’s neck. What is the probability that the rancher will be able to place a lasso around a cow’s neck at least once in 4 attempts? | {
"A": "3 / 4",
"B": "5 / 8",
"C": "7 / 8",
"D": "11 / 16",
"E": "15 / 16"
} | subtract(const_1, power(divide(const_1, 2), 4)) | divide(const_1,n0)|power(#0,n1)|subtract(const_1,#1) | p ( missing all 4 ) = ( 1 / 2 ) ^ 4 = 1 / 16 p ( success on at least one attempt ) = 1 - 1 / 16 = 15 / 16 the answer is e . | probability |
math_qa__S5h4XAd47SB3yH5U | The ratio of the arithmetic mean of two numbers to one of the numbers is 4:7. What is the ratio of the smaller number to the larger number?
Answers:
A) 1 : 8
B) 1 : 7
C) 1 : 6
D) 1 : 5
E) 1 : 4 | <gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(4/7) - (1/2)</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">(1/14) * 2</gadget>
<output>1/7 = around 0.142857</output>
<result>B</result> | B | 0.142857 | The ratio of the arithmetic mean of two numbers to one of the numbers is 4:7. What is the ratio of the smaller number to the larger number? | {
"A": "1 : 8",
"B": "1 : 7",
"C": "1 : 6",
"D": "1 : 5",
"E": "1 : 4"
} | multiply(subtract(divide(4, 7), divide(const_1, const_2)), const_2) | divide(n0,n1)|divide(const_1,const_2)|subtract(#0,#1)|multiply(#2,const_2)| | "for two numbers , the arithmetic mean is the middle of the two numbers . the ratio of the mean to the larger number is 4 : 7 , thus the smaller number must have a ratio of 1 . the ratio of the smaller number to the larger number is 1 : 7 . the answer is b ." | other |
math_qa__UWql1J7FxDOiAQES | When magnified 1,000 times by an electron microscope, the image of a certain circular piece of tissue has a diameter of 5 centimeter. The actual diameter of the tissue, in centimeters, is Choose the correct choice:
A) 0.005
B) 0.002
C) 0.001
D) 0.0005
E) 0.0002 | <gadget id="calculator">5 / 1_000</gadget>
<output>1/200 = around 0.005</output>
<result>A</result> | A | 0.005 | When magnified 1,000 times by an electron microscope, the image of a certain circular piece of tissue has a diameter of 5 centimeter. The actual diameter of the tissue, in centimeters, is | {
"A": "0.005",
"B": "0.002",
"C": "0.001",
"D": "0.0005",
"E": "0.0002"
} | divide(5, 1,000) | divide(n1,n0)| | "it is very easy if x is the diameter , then the magnified length is 1000 x . ince 1000 x = 5 then x = 5 / 1000 = 0.005 . the answer is a" | geometry |
math_qa__7zVfNJbVZ7TSJlaV | A fill pipe can fill 1/2 of cistern in 30 minutes. In how many minutes, it can fill 1/2 of the cistern? Select the correct option:
A) 15 min B) 20 min C) 25 min D) 30 min E) 35 min | <gadget id="calculator">30 / 1</gadget>
<output>30</output>
<result>D</result> | D | 30 | A fill pipe can fill 1/2 of cistern in 30 minutes. In how many minutes, it can fill 1/2 of the cistern? | {
"A": "15 min",
"B": "20 min",
"C": "25 min",
"D": "30 min",
"E": "35 min"
} | divide(30, 1) | divide(n2,n0)| | "required time = 30 * 2 * 1 / 2 = 30 minutes answer is d" | physics |
math_qa__EO5P30RUhrKLzpC0 | The value of (4.7×13.26 + 4.7×9.43+4.7×77.31) is Choose one.
A) 0.47 B) 47 C) 470 D) 4700 E) none | <gadget id="calculator">13.26 + 9.43</gadget>
<output>22.69</output>
<gadget id="calculator">22.69 + 77.31</gadget>
<output>100</output>
<gadget id="calculator">4.7 * 100</gadget>
<output>470</output>
<result>C</result> | C | 470 | The value of (4.7×13.26 + 4.7×9.43+4.7×77.31) is | {
"A": "0.47",
"B": "47",
"C": "470",
"D": "4700",
"E": "none"
} | multiply(4.7, add(add(13.26, 9.43), 77.31)) | add(n1,n3)|add(n5,#0)|multiply(n0,#1)| | "solution given expression = 4.7 × ( 13.26 + 9.43 + 77.31 ) = 4.7 × 100 = 470 . answer c" | general |
math_qa__eIZBilv74ZysjZRs | A is 30% more efficient than B. How much time will they working together take to complete a job which A alone could have done in 23 days? Choose the correct choice from the following answers.
A) 11 B) 13 C) 20 3 / 17 D) 14 E) none of these | <gadget id="calculator">1 / 23</gadget>
<output>1/23 = around 0.043478</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) + 1</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">(13/10) * 23</gadget>
<output>299/10 = around 29.9</output>
<gadget id="calculator">1 / (299/10)</gadget>
<output>10/299 = around 0.033445</output>
<gadget id="calculator">(1/23) + (10/299)</gadget>
<output>1/13 = around 0.076923</output>
<gadget id="calculator">1 / (1/13)</gadget>
<output>13</output>
<result>B</result> | B | 13 | A is 30% more efficient than B. How much time will they working together take to complete a job which A alone could have done in 23 days? | {
"A": "11",
"B": "13",
"C": "20 3 / 17",
"D": "14",
"E": "none of these"
} | inverse(add(divide(const_1, 23), divide(const_1, multiply(add(divide(30, const_100), const_1), 23)))) | divide(const_1,n1)|divide(n0,const_100)|add(#1,const_1)|multiply(n1,#2)|divide(const_1,#3)|add(#0,#4)|inverse(#5) | explanation : ratio of times taken by a and b = 100 : 130 = 10 : 13 suppose b takes x days to work the 10 : 13 : : 23 : x = > x = 23 x 13 / 10 = 299 / 10 a ’ s one day work = 1 / 23 and b ’ s is 10 / 299 then a + b ‘ s work = 1 / 23 + 10 / 299 = 23 / 299 = 1 / 13 = > 13 days answer : option b | physics |
math_qa__3IbxTENsvMTimq3i | A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2445? Choose the correct choice from the following options.
A) s . 800 B) s . 810 C) s . 815 D) s . 900 E) s . 920 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2_445 * (1/3)</gadget>
<output>815</output>
<result>C</result> | C | 815 | A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2445? | {
"A": "s . 800",
"B": "s . 810",
"C": "s . 815",
"D": "s . 900",
"E": "s . 920"
} | multiply(2445, divide(1, 3)) | divide(n0,n1)|multiply(n6,#0)| | "2445 * 1 / 3 = 815 option c" | general |
math_qa__nMzJlqKpgRvAnzTH | Gwen drove an average speed of 15 miles per hour for the first 40 miles of a tripthen at a average speed of 30 miles/hr for the remaining 40 miles of the trip if she made no stops during the trip what was Gwen's avg speed in miles/hr for the entire trip Choose the correct choice from the following answers:
A) 35 B) 20 C) 45 D) 50 E) 55 | <gadget id="calculator">40 + 40</gadget>
<output>80</output>
<gadget id="calculator">40 / 15</gadget>
<output>8/3 = around 2.666667</output>
<gadget id="calculator">40 / 30</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(8/3) + (4/3)</gadget>
<output>4</output>
<gadget id="calculator">80 / 4</gadget>
<output>20</output>
<result>B</result> | B | 20 | Gwen drove an average speed of 15 miles per hour for the first 40 miles of a tripthen at a average speed of 30 miles/hr for the remaining 40 miles of the trip if she made no stops during the trip what was Gwen's avg speed in miles/hr for the entire trip | {
"A": "35",
"B": "20",
"C": "45",
"D": "50",
"E": "55"
} | divide(add(40, 40), add(divide(40, 15), divide(40, 30))) | add(n1,n1)|divide(n1,n0)|divide(n1,n2)|add(#1,#2)|divide(#0,#3) | avg . speed = total distance / total time total distance = 80 miles total time = 40 / 15 + 40 / 30 = 4 avg . speed = 20 . answer - b | physics |
math_qa__aCua6efwAEbZsS5I | A boat M leaves shore A and at the same time boat B leaves shore B. They move across the river. They met at 500 yards away from A and after that they met 300 yards away from shore B without halting at shores. Find the distance between the shore A & B. Answers:
A) 1100 yards B) 1200 yards C) 1300 yards D) 1400 yards E) 1000 yards | <gadget id="calculator">300 * 4</gadget>
<output>1_200</output>
<result>B</result> | B | 1,200 | A boat M leaves shore A and at the same time boat B leaves shore B. They move across the river. They met at 500 yards away from A and after that they met 300 yards away from shore B without halting at shores. Find the distance between the shore A & B. | {
"A": "1100 yards",
"B": "1200 yards",
"C": "1300 yards",
"D": "1400 yards",
"E": "1000 yards"
} | multiply(300, const_4) | multiply(n1,const_4)| | "if x is the distance , a is speed of a and b is speed of b , then ; 500 / a = ( x - 500 ) / b and ( x + 300 ) / a = ( 2 x - 300 ) / b , solving it , we get x = 1200 yards answer : b" | physics |
math_qa__9v8P4MxFnC9HrNE8 | The average salary/head of all the workers in a workshop is Rs.1000, if the average salary/head of 10 technician is Rs.1200 and the average salary/head of the rest is Rs.820, the total no. of workers in the work-shop is ? Pick:
A) 120 / 9
B) 140 / 9
C) 150 / 9
D) 190 / 9
E) 170 / 9 | <gadget id="calculator">10 * 1_200</gadget>
<output>12_000</output>
<gadget id="calculator">820 * 10</gadget>
<output>8_200</output>
<gadget id="calculator">12_000 - 8_200</gadget>
<output>3_800</output>
<gadget id="calculator">1_000 - 820</gadget>
<output>180</output>
<gadget id="calculator">3_800 / 180</gadget>
<output>190/9 = around 21.111111</output>
<result>D</result> | D | 21.111111 | The average salary/head of all the workers in a workshop is Rs.1000, if the average salary/head of 10 technician is Rs.1200 and the average salary/head of the rest is Rs.820, the total no. of workers in the work-shop is ? | {
"A": "120 / 9",
"B": "140 / 9",
"C": "150 / 9",
"D": "190 / 9",
"E": "170 / 9"
} | divide(subtract(multiply(10, 1200), multiply(820, 10)), subtract(1000, 820)) | multiply(n1,n2)|multiply(n1,n3)|subtract(n0,n3)|subtract(#0,#1)|divide(#3,#2)| | let the total number of workers be y . so sum of salary for all workers = sum of salary of 10 technician + sum of salary for other y - 10 workers . 10 x 1200 + 820 ( y - 10 ) = 1000 y ⇒ 12000 + 820 y - 8200 = 1000 y ⇒ 180 y = 3800 ∴ y = 190 / 9 so total number of workers = 190 / 9 d | general |
math_qa__9KklId9RDxXzGsju | The maximum number of student amoung them 1080 pens and 920 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : Choose the correct choice.
A) 91 B) 40 C) 80 D) 90 E) none of these | <gadget id="calculator">gcd(1_080, 920)</gadget>
<output>40</output>
<result>B</result> | B | 40 | The maximum number of student amoung them 1080 pens and 920 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : | {
"A": "91",
"B": "40",
"C": "80",
"D": "90",
"E": "none of these"
} | gcd(1080, 920) | gcd(n0,n1)| | "solution required number of student = h . c . f of 1080 and 920 = 40 . answer b" | general |
math_qa__G8haXfKQscTH9dz8 | 76^77 /7
remainder is ? Choose the correct choice from the following
A) 5 B) 6 C) 7 D) 8 E) 9 | <gadget id="calculator">76 - 77</gadget>
<output>-1</output>
<gadget id="calculator">7 + (-1)</gadget>
<output>6</output>
<result>B</result> | B | 6 | 76^77 /7
remainder is ? | {
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "9"
} | add(7, subtract(76, 77)) | subtract(n0,n1)|add(n2,#0) | as , 4 ^ 3 / 3 = 64 / 3 remainder = 1 and also 4 / 3 = 1 and 5 ^ 3 / 3 remainder = 2 and also 5 / 3 = 2 so it does not matter on the power value so the answer will be 76 / 7 remainder = 6 answer : b | general |
math_qa__gAVrGfAqTZirGPQP | 20 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played?
Select:
A) 380 B) 470 C) 560 D) 650 E) 740 | <gadget id="calculator">20 - 1</gadget>
<output>19</output>
<gadget id="calculator">20 * 19</gadget>
<output>380</output>
<result>A</result> | A | 380 | 20 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? | {
"A": "380",
"B": "470",
"C": "560",
"D": "650",
"E": "740"
} | multiply(20, subtract(20, const_1)) | subtract(n0,const_1)|multiply(n0,#0)| | "2 * 20 c 2 = 2 * 190 = 380 the answer is a ." | general |
math_qa__m18mZGaXs4Y5dvX2 | Working alone, A can complete a certain kind of job in 15 hours. A and D, working together at their respective rates, can complete one of these jobs in 10 hours. In how many hours can D, working alone, complete one of these jobs? Pick:
A) 20 B) 24 C) 26 D) 28 E) 30 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) - (1/15)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / (1/30)</gadget>
<output>30</output>
<result>E</result> | E | 30 | Working alone, A can complete a certain kind of job in 15 hours. A and D, working together at their respective rates, can complete one of these jobs in 10 hours. In how many hours can D, working alone, complete one of these jobs? | {
"A": "20",
"B": "24",
"C": "26",
"D": "28",
"E": "30"
} | inverse(subtract(inverse(10), inverse(15))) | inverse(n1)|inverse(n0)|subtract(#0,#1)|inverse(#2)| | "let total time taken by d to complete the job = d total time taken by a to complete the job = 15 work done by a in an hour 1 / a = 1 / 15 working together a and d can complete the job in 10 hours 1 / a + 1 / d = 1 / 10 = > 1 / d = 1 / 10 - 1 / 15 = 1 / 10 - 1 / 15 = 1 / 30 = > d = 30 hours answer e" | physics |
math_qa__pRAyvVSNQnbVRaL9 | Fresh grapes contain 80% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 40 kg of fresh grapes? Choose one: A) 10 kg B) 12 kg C) 15 kg D) 16 kg E) 20 kg | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">20 * 40</gadget>
<output>800</output>
<gadget id="calculator">800 / 100</gadget>
<output>8</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">8 / 80</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>
<result>A</result> | A | 10 | Fresh grapes contain 80% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 40 kg of fresh grapes? | {
"A": "10 kg",
"B": "12 kg",
"C": "15 kg",
"D": "16 kg",
"E": "20 kg"
} | multiply(divide(divide(multiply(subtract(const_100, 80), 40), const_100), subtract(const_100, 20)), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|multiply(n2,#0)|divide(#2,const_100)|divide(#3,#1)|multiply(#4,const_100)| | "from the question we know : 40 kg * 80 % = 32 kg of water in the fresh grapes 40 kg - 32 kg of water = 8 kg of non - water mass we are looking for the weight of the dry grapes ( x ) . since the question tells us that 20 % of the weight of the dry graps is water and we know that 8 kg is non - water mass we can set up the following equation : x = 1 / 5 ( x ) + 8 kg 4 / 5 ( x ) = 8 kg x = 10 kg answer - a" | gain |
math_qa__tVkiBPJ2stO9Yi4U | In a neighborhood having 90 households, 11 did not have either a car or a bike. If 14 households had a both a car and a bike and 44 had a car, how many had bike only?
Choose the correct answer: A) 30 B) 35 C) 20 D) 18 E) 10 | <gadget id="calculator">90 - 11</gadget>
<output>79</output>
<gadget id="calculator">79 + 14</gadget>
<output>93</output>
<gadget id="calculator">93 - 44</gadget>
<output>49</output>
<gadget id="calculator">49 - 14</gadget>
<output>35</output>
<result>B</result> | B | 35 | In a neighborhood having 90 households, 11 did not have either a car or a bike. If 14 households had a both a car and a bike and 44 had a car, how many had bike only? | {
"A": "30",
"B": "35",
"C": "20",
"D": "18",
"E": "10"
} | subtract(subtract(add(subtract(90, 11), 14), 44), 14) | subtract(n0,n1)|add(n2,#0)|subtract(#1,n3)|subtract(#2,n2)| | "{ total } = { car } + { bike } - { both } + { neither } - - > 90 = 44 + { bike } - 14 + 11 - - > { bike } = 49 - - > # those who have bike only is { bike } - { both } = 49 - 14 = 35 . answer : b ." | other |
math_qa__nXSCFbqlWWIIf13F | If the product of two numbers is 62216 and their H.C.F. is 22, find their L.C.M.
Select.
A) 2828 B) 2850 C) 1365 D) 1574 E) none of these | <gadget id="calculator">62_216 / 22</gadget>
<output>2_828</output>
<result>A</result> | A | 2,828 | If the product of two numbers is 62216 and their H.C.F. is 22, find their L.C.M. | {
"A": "2828",
"B": "2850",
"C": "1365",
"D": "1574",
"E": "none of these"
} | divide(62216, 22) | divide(n0,n1)| | "explanation : hcf * lcm = 62216 , because we know product of two numbers = product of hcf and lcm lcm = 62216 / 22 = 2828 option a" | physics |
math_qa__2K3tHxp1HiAxPZlY | Sides of a rectangular park are in the ratio 3: 2 and its area is 4704 sq m, the cost of fencing it at 50 ps per meter is? Choose the most appropriate option.
A) 287 B) 1287 C) 140 D) 988 E) 271 | <gadget id="calculator">4_704 * 2</gadget>
<output>9_408</output>
<gadget id="calculator">9_408 / 3</gadget>
<output>3_136</output>
<gadget id="calculator">3_136 ** (1/2)</gadget>
<output>56</output>
<gadget id="calculator">4_704 / 56</gadget>
<output>84</output>
<gadget id="calculator">2 * (56 + 84)</gadget>
<output>280</output>
<gadget id="calculator">50 * 280</gadget>
<output>14_000</output>
<gadget id="calculator">14_000 / 100</gadget>
<output>140</output>
<result>C</result> | C | 140 | Sides of a rectangular park are in the ratio 3: 2 and its area is 4704 sq m, the cost of fencing it at 50 ps per meter is? | {
"A": "287",
"B": "1287",
"C": "140",
"D": "988",
"E": "271"
} | divide(multiply(50, rectangle_perimeter(sqrt(divide(multiply(4704, 2), 3)), divide(4704, sqrt(divide(multiply(4704, 2), 3))))), const_100) | multiply(n1,n2)|divide(#0,n0)|sqrt(#1)|divide(n2,#2)|rectangle_perimeter(#3,#2)|multiply(n3,#4)|divide(#5,const_100)| | "3 x * 2 x = 4704 = > x = 28 2 ( 84 + 56 ) = 280 m 280 * 1 / 2 = rs . 140 answer : c" | physics |
math_qa__ZAN0rL7VwsJmolyb | In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 12 percent of revenues. The profits in 2009 were what percent of the profits in 2008? Select the correct option:
A) 80 %
B) 105 %
C) 120 %
D) 96 %
E) 138 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">12 * (4/5)</gadget>
<output>48/5 = around 9.6</output>
<gadget id="calculator">(48/5) / 10</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">(24/25) * 100</gadget>
<output>96</output>
<result>D</result> | D | 96 | In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 12 percent of revenues. The profits in 2009 were what percent of the profits in 2008? | {
"A": "80 %",
"B": "105 %",
"C": "120 %",
"D": "96 %",
"E": "138 %"
} | multiply(divide(multiply(12, subtract(const_1, divide(20, const_100))), 10), const_100) | divide(n3,const_100)|subtract(const_1,#0)|multiply(n4,#1)|divide(#2,n1)|multiply(#3,const_100)| | "x = profits r = revenue x / r = 0,1 x = 10 r = 100 2009 : r = 80 x / 80 = 0,12 = 12 / 100 x = 80 * 12 / 100 x = 9.6 9.6 / 10 = 0.96 = 96 % , answer d" | gain |
math_qa__FxMzDQdmwenfZA21 | A train crosses a tunnel of 1200 m in 45 sec, same train crosses another platform of length 180 m in 15 sec. then find the length of the train? Choose the correct answer.
A) 350 m B) 400 m C) 272 m D) 330 m E) 267 m | <gadget id="calculator">45 / 15</gadget>
<output>3</output>
<gadget id="calculator">3 * 180</gadget>
<output>540</output>
<gadget id="calculator">1_200 - 540</gadget>
<output>660</output>
<gadget id="calculator">660 / 2</gadget>
<output>330</output>
<result>D</result> | D | 330 | A train crosses a tunnel of 1200 m in 45 sec, same train crosses another platform of length 180 m in 15 sec. then find the length of the train? | {
"A": "350 m",
"B": "400 m",
"C": "272 m",
"D": "330 m",
"E": "267 m"
} | divide(subtract(1200, multiply(divide(45, 15), 180)), const_2) | divide(n1,n3)|multiply(n2,#0)|subtract(n0,#1)|divide(#2,const_2) | length of the train be ‘ x ’ ( x + 1200 ) / 45 = ( x + 180 ) / 15 x + 1200 = 3 x + 540 2 x = 660 x = 330 m answer : d | physics |
math_qa__rAGwm9jf2qjp6W55 | If 8 men or 12 women can do a piece of work in 40 days, in how many days can the same work be done by 6 men and 11 women? Choices
A) 10 days B) 11 days C) 13 days D) 15 days E) 24 days | <gadget id="calculator">8 * 40</gadget>
<output>320</output>
<gadget id="calculator">6 / 320</gadget>
<output>3/160 = around 0.01875</output>
<gadget id="calculator">12 * 40</gadget>
<output>480</output>
<gadget id="calculator">11 / 480</gadget>
<output>11/480 = around 0.022917</output>
<gadget id="calculator">(3/160) + (11/480)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<result>E</result> | E | 24 | If 8 men or 12 women can do a piece of work in 40 days, in how many days can the same work be done by 6 men and 11 women? | {
"A": "10 days",
"B": "11 days",
"C": "13 days",
"D": "15 days",
"E": "24 days"
} | inverse(add(divide(6, multiply(8, 40)), divide(11, multiply(12, 40)))) | multiply(n0,n2)|multiply(n1,n2)|divide(n3,#0)|divide(n4,#1)|add(#2,#3)|inverse(#4)| | "8 men = 12 women ( i . e 2 men = 3 women ) 12 women 1 day work = 1 / 40 soln : 6 men ( 9 women ) + 11 women = 20 women = ? 1 women 1 day work = 12 * 40 = 1 / 480 so , 20 women work = 20 / 480 = 1 / 24 ans : 24 days answer : e" | physics |
math_qa__PqVTyQkxnfyajLgE | If the sides of a triangle are 21 cm, 19 cm and 5 cm, what is its area? Choose the correct choice.
A) 42.25 cm 2 B) 57.5 cm 2 C) 42.5 cm 2 D) 47.5 cm 2 E) 52.5 cm 2 | <gadget id="calculator">19 * 5</gadget>
<output>95</output>
<gadget id="calculator">95 / 2</gadget>
<output>95/2 = around 47.5</output>
<result>D</result> | D | 47.5 | If the sides of a triangle are 21 cm, 19 cm and 5 cm, what is its area? | {
"A": "42.25 cm 2",
"B": "57.5 cm 2",
"C": "42.5 cm 2",
"D": "47.5 cm 2",
"E": "52.5 cm 2"
} | divide(multiply(19, 5), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 21 cm , 19 cm and 5 cm is right angled , where the hypotenuse is 21 cm . area of the triangle = 1 / 2 * 19 * 5 = 47.5 cm 2 answer : d" | geometry |
math_qa__NxTryHI2CXlGj4Oi | Excluding stoppages, the speed of a bus is 90 km/hr and including stoppages, it is 84 km/hr. For how many minutes does the bus stop per hour?
Choose the correct choice from the following choices: A) 18 min B) 4 min C) 8 min D) 6 min E) 5 min | <gadget id="calculator">90 - 84</gadget>
<output>6</output>
<gadget id="calculator">6 / 90</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">60 * (1/15)</gadget>
<output>4</output>
<result>B</result> | B | 4 | Excluding stoppages, the speed of a bus is 90 km/hr and including stoppages, it is 84 km/hr. For how many minutes does the bus stop per hour? | {
"A": "18 min",
"B": "4 min",
"C": "8 min",
"D": "6 min",
"E": "5 min"
} | multiply(const_60, divide(subtract(90, 84), 90)) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)| | "due to stoppages , it covers 6 km less . time taken to cover 6 km = 6 / 90 * 60 = 4 min . answer : b" | physics |
math_qa__RYfhbJrp2IGlGcHp | Two persons A and B can complete a piece of work in 18 days and 24 days respectively. If they work together, what part of the work will be completed in 2 days? Select the correct option.
A) 7 / 36 B) 9 / 35 C) 4 / 37 D) 8 / 35 E) 5 / 3 | <gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/18) + (1/24)</gadget>
<output>7/72 = around 0.097222</output>
<gadget id="calculator">2 * (7/72)</gadget>
<output>7/36 = around 0.194444</output>
<result>A</result> | A | 0.194444 | Two persons A and B can complete a piece of work in 18 days and 24 days respectively. If they work together, what part of the work will be completed in 2 days? | {
"A": "7 / 36",
"B": "9 / 35",
"C": "4 / 37",
"D": "8 / 35",
"E": "5 / 3"
} | multiply(2, add(divide(const_1, 18), divide(const_1, 24))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)| | "a ' s one day ' s work = 1 / 18 b ' s one day ' s work = 1 / 24 ( a + b ) ' s one day ' s work = 1 / 18 + 1 / 24 = 7 / 72 the part of the work completed in 3 days = 2 ( 7 / 72 ) = 7 / 36 . answer : a" | physics |
math_qa__6qMEozmKobJ92td2 | present birth rate is 32 per 1000 while death rate is 11 per 1000 . what will be the percentage increase in the rate of population ? Choose the correct choice from the following: A) 0.21 % B) 21 % C) 0.021 % D) 2.1 % E) none of these | <gadget id="calculator">32 - 11</gadget>
<output>21</output>
<gadget id="calculator">21 / 1_000</gadget>
<output>21/1_000 = around 0.021</output>
<gadget id="calculator">(21/1_000) * 100</gadget>
<output>21/10 = around 2.1</output>
<result>D</result> | D | 2.1 | present birth rate is 32 per 1000 while death rate is 11 per 1000 . what will be the percentage increase in the rate of population ? | {
"A": "0.21 %",
"B": "21 %",
"C": "0.021 %",
"D": "2.1 %",
"E": "none of these"
} | multiply(divide(subtract(32, 11), 1000), const_100) | subtract(n0,n2)|divide(#0,n1)|multiply(#1,const_100) | birth rate = 32 / 1000 = 0.032 death rate = 11 / 1000 = 0.011 increase in population = 0.032 - 0.011 = 0.021 = 2.1 % answer : d | gain |
math_qa__QOhuFn4D2Q1ulpQV | On selling 11 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
Options:
A) s . 45 B) s . 50 C) s . 55 D) s . 60 E) s . 120 | <gadget id="calculator">11 - 5</gadget>
<output>6</output>
<gadget id="calculator">720 / 6</gadget>
<output>120</output>
<result>E</result> | E | 120 | On selling 11 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is: | {
"A": "s . 45",
"B": "s . 50",
"C": "s . 55",
"D": "s . 60",
"E": "s . 120"
} | divide(720, subtract(11, 5)) | subtract(n0,n2)|divide(n1,#0)| | "( c . p . of 11 balls ) - ( s . p . of 11 balls ) = ( c . p . of 5 balls ) c . p . of 6 balls = s . p . of 11 balls = rs . 720 . c . p . of 1 ball = rs . 720 / 6 = rs . 120 . answer : option e" | gain |
math_qa__YUeBGoN9PkJft70G | A lemonade stand sold only small and large cups of lemonade on Tuesday. 2/5 of the cups sold were small and the rest were large. If the large cups were sold for 7/6 as much as the small cups, what fraction of Tuesday's total revenue was from the sale of large cups? Choose the correct answer:
A) ( a ) 7 / 16 B) ( b ) 7 / 11 C) ( c ) 10 / 21 D) ( d ) 17 / 35 E) ( e ) 1 / 2 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 10</gadget>
<output>4</output>
<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">7 / 6</gadget>
<output>7/6 = around 1.166667</output>
<gadget id="calculator">(7/6) * 4</gadget>
<output>14/3 = around 4.666667</output>
<gadget id="calculator">6 * (14/3)</gadget>
<output>28</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 + 28</gadget>
<output>44</output>
<gadget id="calculator">28 / 44</gadget>
<output>7/11 = around 0.636364</output>
<result>B</result> | B | 0.636364 | A lemonade stand sold only small and large cups of lemonade on Tuesday. 2/5 of the cups sold were small and the rest were large. If the large cups were sold for 7/6 as much as the small cups, what fraction of Tuesday's total revenue was from the sale of large cups? | {
"A": "( a ) 7 / 16",
"B": "( b ) 7 / 11",
"C": "( c ) 10 / 21",
"D": "( d ) 17 / 35",
"E": "( e ) 1 / 2"
} | divide(multiply(subtract(const_10, multiply(divide(2, 5), const_10)), multiply(divide(7, 6), multiply(divide(2, 5), const_10))), add(multiply(multiply(divide(2, 5), const_10), multiply(divide(2, 5), const_10)), multiply(subtract(const_10, multiply(divide(2, 5), const_10)), multiply(divide(7, 6), multiply(divide(2, 5), const_10))))) | divide(n2,n3)|divide(n0,n1)|multiply(#1,const_10)|multiply(#0,#2)|multiply(#2,#2)|subtract(const_10,#2)|multiply(#3,#5)|add(#4,#6)|divide(#6,#7)| | "a simpler way i guess would be to think that in total 5 cups were sold . out of which 2 are small and 3 are large . now let the small ones cost $ 6 . so the large ones would cost $ 7 . so , 2 * 6 = 12 and 3 * 7 = 21 . total revenue was 12 + 21 = 33 and large cup sales as found above is 21 therefore answer is 21 / 33 i . e 7 / 11 b" | general |
math_qa__6aD7HTAp11Rajtl5 | A boy is travelling from his home to school at 3 km/hr and reached 7 min late. Next day he traveled at 6 km/hr and reached 8 min early. Distance between home and school? Choose one
A) 1.2 km
B) 1.3 km
C) 1.4 km
D) 1.5 km
E) 1.6 km | <gadget id="calculator">7 / 60</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">8 / 60</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(7/60) + (2/15)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/4) / (1/6)</gadget>
<output>3/2 = around 1.5</output>
<result>D</result> | D | 1.5 | A boy is travelling from his home to school at 3 km/hr and reached 7 min late. Next day he traveled at 6 km/hr and reached 8 min early. Distance between home and school? | {
"A": "1.2 km",
"B": "1.3 km",
"C": "1.4 km",
"D": "1.5 km",
"E": "1.6 km"
} | divide(add(divide(7, const_60), divide(8, const_60)), divide(const_1, 6)) | divide(n1,const_60)|divide(n3,const_60)|divide(const_1,n2)|add(#0,#1)|divide(#3,#2)| | "let the distance be x t 1 = x / 3 hr t 2 = x / 6 hr difference in time = 7 + 8 = 15 = 1 / 4 hr x / 3 - x / 6 = 1 / 4 x / 6 = 1 / 4 x = 1.5 km answer is d" | physics |
math_qa__UZ3Ss4WZ5uSUI0ce | The price of commodity X increases by 40 cents every year, while the price of commodity Y increases by 15 cents every year. In 2001, the price of commodity X was $4.20 and the price of commodity Y was $6.30. In which year will the price of commodity X be 15 cents more than the price of commodity Y? Select.
A) 2010 B) 2011 C) 2012 D) 2013 E) 2014 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">6.3 - 4.2</gadget>
<output>2.1</output>
<gadget id="calculator">(3/20) + 2.1</gadget>
<output>2.25</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) - 2.1</gadget>
<output>-1.7</output>
<gadget id="calculator">2.25 / (-1.7)</gadget>
<output>-1.323529</output>
<gadget id="calculator">2_001 + (-1.323529)</gadget>
<output>1_999.676471</output>
<result>A</result> | A | 2,010 | The price of commodity X increases by 40 cents every year, while the price of commodity Y increases by 15 cents every year. In 2001, the price of commodity X was $4.20 and the price of commodity Y was $6.30. In which year will the price of commodity X be 15 cents more than the price of commodity Y? | {
"A": "2010",
"B": "2011",
"C": "2012",
"D": "2013",
"E": "2014"
} | add(2001, divide(add(divide(15, const_100), subtract(6.30, 4.20)), subtract(divide(40, const_100), subtract(6.30, 4.20)))) | divide(n5,const_100)|divide(n0,const_100)|subtract(n4,n3)|add(#0,#2)|subtract(#1,#2)|divide(#3,#4)|add(n2,#5)| | "the price of commodity x increases 25 cents each year relative to commodity y . the price difference is $ 2.10 and commodity x needs to be 15 cents more than commodity y . $ 2.25 / 25 cents = 9 years the answer is 2001 + 9 years = 2010 . the answer is a ." | general |
math_qa__IQc28b23c0z3v13E | A 12% stock yielding 10% is quoted at : Answers: A) rs . 83.33 B) rs . 110 C) rs . 112 D) rs . 120 E) rs . 140 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">10 * 12</gadget>
<output>120</output>
<result>D</result> | D | 120 | A 12% stock yielding 10% is quoted at : | {
"A": "rs . 83.33",
"B": "rs . 110",
"C": "rs . 112",
"D": "rs . 120",
"E": "rs . 140"
} | multiply(divide(const_100, 10), 12) | divide(const_100,n1)|multiply(n0,#0) | income of rs 10 on investment of rs 100 income of rs 12 on investment of ? = ( 12 * 100 ) / 10 = 120 answer : d | gain |
math_qa__3ZrMWKsT7XOcwUoQ | Machine A takes 100 hours to complete a certain job and starts that job at 7AM. After two hour of working alone, machine A is joined by machine B and together they complete the job at 12PM. How long would it have taken machine B to complete the jobif it had worked alone for the entire job? Select the correct option:
A) 100.11
B) 10.98
C) 18.07
D) 45.01
E) 35.09 | <gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/100) * 2</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">1 - (1/50)</gadget>
<output>49/50 = around 0.98</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">24 - 7</gadget>
<output>17</output>
<gadget id="calculator">17 - 2</gadget>
<output>15</output>
<gadget id="calculator">(49/50) / 15</gadget>
<output>49/750 = around 0.065333</output>
<gadget id="calculator">(49/750) - (1/100)</gadget>
<output>83/1_500 = around 0.055333</output>
<gadget id="calculator">1 / (83/1_500)</gadget>
<output>1_500/83 = around 18.072289</output>
<result>C</result> | C | 18.07 | Machine A takes 100 hours to complete a certain job and starts that job at 7AM. After two hour of working alone, machine A is joined by machine B and together they complete the job at 12PM. How long would it have taken machine B to complete the jobif it had worked alone for the entire job? | {
"A": "100.11",
"B": "10.98",
"C": "18.07",
"D": "45.01",
"E": "35.09"
} | inverse(subtract(divide(subtract(const_1, multiply(inverse(100), const_2)), subtract(subtract(multiply(12, const_2), 7), const_2)), inverse(100))) | inverse(n0)|multiply(n2,const_2)|multiply(#0,const_2)|subtract(#1,n1)|subtract(const_1,#2)|subtract(#3,const_2)|divide(#4,#5)|subtract(#6,#0)|inverse(#7) | let us assume total job = 100 units a finishes 100 units in 100 hrs ( given ) hence a ( working rate ) = 1 units / hr now given that a works for 2 hr ( so 2 units done ) then a and b finish total work in 15 hours . hence a and b finish 98 units in 15 hours . of these 1 x 15 = 15 units were done by a . hence b did 83 units in 15 hours . hence b ( working rate ) = 83 / 15 units / hr hence b takes 100 x 15 / 83 = 18.07 hours to complete the job . answer c . | physics |
math_qa__7Hp3IiJWn0eUpJQd | Shopkeeper rise price by 32% and gives successive discount of 10% and 15%. What is overall % gain or loss? Choose the correct choice from the following choices.
A) 0.98 %
B) 4.98 %
C) 3.95 %
D) 6.98 %
E) 7.98 % | <gadget id="calculator">100 + 32</gadget>
<output>132</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">132 * (9/10)</gadget>
<output>594/5 = around 118.8</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(594/5) * (17/20)</gadget>
<output>5_049/50 = around 100.98</output>
<gadget id="calculator">(5_049/50) - 100</gadget>
<output>49/50 = around 0.98</output>
<result>A</result> | A | 0.98 | Shopkeeper rise price by 32% and gives successive discount of 10% and 15%. What is overall % gain or loss? | {
"A": "0.98 %",
"B": "4.98 %",
"C": "3.95 %",
"D": "6.98 %",
"E": "7.98 %"
} | subtract(multiply(multiply(add(const_100, 32), divide(subtract(const_100, 10), const_100)), divide(subtract(const_100, 15), const_100)), const_100) | add(n0,const_100)|subtract(const_100,n2)|subtract(const_100,n1)|divide(#1,const_100)|divide(#2,const_100)|multiply(#0,#4)|multiply(#3,#5)|subtract(#6,const_100)| | "let d initial price be 100 32 % rise now price = 132 / 100 * 100 = 132 10 % discount then price = 132 * 90 / 100 = 118.8 15 % discount then price = 118.8 * 85 / 100 = 100.98 so gain = 100.98 - 100 = 0.98 gain % = gain * 100 / cp = = > 0.98 * 100 / 100 = 0.98 % answer : a" | gain |
math_qa__ckhQqK984Qbi8Gcl | Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 20000, then find his savings? Choose the correct choice from the following answers.
A) rs . 3600 B) rs . 4000 C) rs . 3639 D) rs . 3632 E) rs . 3602 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 20_000</gadget>
<output>16_000</output>
<gadget id="calculator">20_000 - 16_000</gadget>
<output>4_000</output>
<result>B</result> | B | 4,000 | Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 20000, then find his savings? | {
"A": "rs . 3600",
"B": "rs . 4000",
"C": "rs . 3639",
"D": "rs . 3632",
"E": "rs . 3602"
} | subtract(20000, multiply(divide(4, 5), 20000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | "let the income and the expenditure of the person be rs . 5 x and rs . 4 x respectively . income , 5 x = 20000 = > x = 4000 savings = income - expenditure = 5 x - 4 x = x so , savings = rs . 4000 answer : b" | other |
math_qa__zJJB3OvBzHO2QF87 | One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 17 percent sugar by weight. The second solution was what percent sugar by weight? Options.
A) 34 % B) 24 % C) 22 % D) 38 % E) 8.5 % | <gadget id="calculator">17 / 100</gadget>
<output>17/100 = around 0.17</output>
<gadget id="calculator">100 * (17/100)</gadget>
<output>17</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">75 * (1/10)</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">17 - (15/2)</gadget>
<output>19/2 = around 9.5</output>
<gadget id="calculator">(19/2) / 25</gadget>
<output>19/50 = around 0.38</output>
<gadget id="calculator">(19/50) * 100</gadget>
<output>38</output>
<result>D</result> | D | 38 | One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 17 percent sugar by weight. The second solution was what percent sugar by weight? | {
"A": "34 %",
"B": "24 %",
"C": "22 %",
"D": "38 %",
"E": "8.5 %"
} | multiply(divide(subtract(multiply(const_100, divide(17, const_100)), multiply(subtract(const_100, multiply(divide(const_1, const_4), const_100)), divide(10, const_100))), multiply(divide(const_1, const_4), const_100)), const_100) | divide(n1,const_100)|divide(n0,const_100)|divide(const_1,const_4)|multiply(#0,const_100)|multiply(#2,const_100)|subtract(const_100,#4)|multiply(#1,#5)|subtract(#3,#6)|divide(#7,#4)|multiply(#8,const_100)| | "instead of using complex calculations and remembering formulae , why dont u directly get to weighted average . 3 parts of 10 % + 1 part of x ( unknown ) % = 4 parts of 17 % = > x % = 68 % - 30 % = 38 % ans d it is ." | gain |
math_qa__yqdqjxVcgBlujcFp | A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3.5t seconds, then what is the length of the platform? Choose the correct choice: A) 0.5 l B) 1.5 l C) 2.5 l D) 3.5 l E) 4.5 l | <gadget id="calculator">3.5 - 1</gadget>
<output>2.5</output>
<result>C</result> | C | 2.5 | A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3.5t seconds, then what is the length of the platform? | {
"A": "0.5 l",
"B": "1.5 l",
"C": "2.5 l",
"D": "3.5 l",
"E": "4.5 l"
} | subtract(3.5, const_1) | subtract(n0,const_1)| | "the train passes a pole in t seconds , so velocity v = l / t ( l + p ) / v = 3.5 t ( l + p ) / ( l / t ) = 3.5 t p = 2.5 l the answer is c ." | physics |
math_qa__maPQWlizpONyNgxJ | Tom purchased 8kg of apples at the rate of 70 per kg and 9 kg of mangoes at the rate of 70 per kg. How much amount did he pay to the shopkeeper? Select
A) 1040 B) 1045 C) 1055 D) 1190 E) 1075 | <gadget id="calculator">8 * 70</gadget>
<output>560</output>
<gadget id="calculator">9 * 70</gadget>
<output>630</output>
<gadget id="calculator">560 + 630</gadget>
<output>1_190</output>
<result>D</result> | D | 1,190 | Tom purchased 8kg of apples at the rate of 70 per kg and 9 kg of mangoes at the rate of 70 per kg. How much amount did he pay to the shopkeeper? | {
"A": "1040",
"B": "1045",
"C": "1055",
"D": "1190",
"E": "1075"
} | add(multiply(8, 70), multiply(9, 70)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "cost of 8 kg apples = 70 × 8 = 560 . cost of 9 kg of mangoes = 70 × 9 = 630 . total cost he has to pay = 560 + 630 = 1190 . d )" | gain |
math_qa__IMkDMbn80CjGE877 | A cycle is bought for Rs.840 and sold for Rs.1220, find the gain percent? Pick one.
A) 70 %
B) 45 %
C) 48 %
D) 30 %
E) 40 % | <gadget id="calculator">1_220 - 840</gadget>
<output>380</output>
<gadget id="calculator">380 / 840</gadget>
<output>19/42 = around 0.452381</output>
<gadget id="calculator">(19/42) * 100</gadget>
<output>950/21 = around 45.238095</output>
<result>B</result> | B | 45 | A cycle is bought for Rs.840 and sold for Rs.1220, find the gain percent? | {
"A": "70 %",
"B": "45 %",
"C": "48 %",
"D": "30 %",
"E": "40 %"
} | multiply(divide(subtract(1220, 840), 840), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : 840 - - - - 380 100 - - - - ? = > 45 % answer : b" | gain |
math_qa__C3Vle08wsHwwkqrE | The ratio of length to width of a rectangular showroom window is 3.3 to 2. If the width of the window is 8 feet, what is the approximate length of the display in feet? Choose the correct choice from the following choices
A) 7 B) 11 C) 13 D) 16 E) 26 | <gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">3.3 * 4</gadget>
<output>13.2</output>
<result>C</result> | C | 13 | The ratio of length to width of a rectangular showroom window is 3.3 to 2. If the width of the window is 8 feet, what is the approximate length of the display in feet? | {
"A": "7",
"B": "11",
"C": "13",
"D": "16",
"E": "26"
} | multiply(3.3, divide(8, 2)) | divide(n2,n1)|multiply(n0,#0) | explanation : letting l be the length of the window , the proportion for the ratio of the length to the width can be expressed in the following equation : 3.3 / 2 = l / 8 26.4 = 2 l 13.2 = l answer : option c | other |
math_qa__0fK0lBMfUyAPzGnc | A wholesaler wishes to sell 100 pounds of mixed nuts at $2.50 a pound. She mixes peanuts worth $3.50 a pound with cashews worth $4.00 a pound. How many pounds of cashews must she use? Choose the correct choice
A) 40 B) 45 C) 50 D) 55 E) 60 | <gadget id="calculator">4 - 2.5</gadget>
<output>1.5</output>
<gadget id="calculator">1.5 * 100</gadget>
<output>150</output>
<gadget id="calculator">150 / 2.5</gadget>
<output>60</output>
<result>E</result> | E | 60 | A wholesaler wishes to sell 100 pounds of mixed nuts at $2.50 a pound. She mixes peanuts worth $3.50 a pound with cashews worth $4.00 a pound. How many pounds of cashews must she use? | {
"A": "40",
"B": "45",
"C": "50",
"D": "55",
"E": "60"
} | divide(multiply(subtract(4, 2.5), 100), 2.5) | subtract(n3,n1)|multiply(n0,#0)|divide(#1,n1) | from the question stem we know that we need a mixture of 100 pounds of peanuts and cashews . if we represent peanuts as x and cashews as y , we get x + y = 100 . since the wholesaler wants to sell the mixture of 100 pounds @ $ 2.50 , we can write this as : $ 2.5 * ( x + y ) = $ 1.5 x + $ 4 y from the equation x + y = 100 , we can rewrite y as y = 100 - x and substitute this into our equation to get : $ 2.5 * ( x + 100 - x ) = $ 1.5 x + $ 4 ( 100 - x ) if you solve for x , you will get x = 60 , and therefore y = 40 . so the wholesaler must use 40 pounds of cashews . you can substitute into the original equation to see that : $ 250 = $ 1.5 ( 60 ) + $ 4 ( 40 ) answer is e | general |
math_qa__PZ2D79C1QppXHD2i | Find the area of a rhombus having each side equal to 13 cm and one of whose diagonal is 24 cm. Pick one:
A) 150 sq . cm
B) 120 sq . cm
C) 130 sq . cm
D) 125 sq . cm
E) 110 sq . cm | <gadget id="calculator">13 ** 2</gadget>
<output>169</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">169 - 144</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">(24 * 10) / 2</gadget>
<output>120</output>
<result>B</result> | B | 120 | Find the area of a rhombus having each side equal to 13 cm and one of whose diagonal is 24 cm. | {
"A": "150 sq . cm",
"B": "120 sq . cm",
"C": "130 sq . cm",
"D": "125 sq . cm",
"E": "110 sq . cm"
} | rhombus_area(24, multiply(sqrt(subtract(power(13, const_2), power(divide(24, const_2), const_2))), const_2)) | divide(n1,const_2)|power(n0,const_2)|power(#0,const_2)|subtract(#1,#2)|sqrt(#3)|multiply(#4,const_2)|rhombus_area(n1,#5) | let abcd is a rhombus with diagonals ac and bd which intersect each other at o . ac = 24 ⇒ ao = 12 let bo = x and ab = 13 cm ( given ) by pythagorean theorem c 2 = a 2 + b 2 13 2 = 12 2 + x 2 169 = 144 + x 2 x 2 = 169 – 144 x 2 = 25 x = 5 cm bo = 5 cm diagonal bd = 2 x 5 = 10 cm . area = ½ x [ product of diagonals ] = ½ x 24 x 10 area = 120 sq . cm answer is b | geometry |
math_qa__7Ao2TC5Gr7Zy3fMA | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 83 more candidates got selected than A. What was the number of candidates appeared from each State? Choose the correct answer:
A) 7000 B) 8300 C) 6000 D) 5000 E) 4000 | <gadget id="calculator">7 - 6</gadget>
<output>1</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">83 / (1/100)</gadget>
<output>8_300</output>
<result>B</result> | B | 8,300 | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 83 more candidates got selected than A. What was the number of candidates appeared from each State? | {
"A": "7000",
"B": "8300",
"C": "6000",
"D": "5000",
"E": "4000"
} | divide(83, divide(subtract(7, 6), const_100)) | subtract(n1,n0)|divide(#0,const_100)|divide(n2,#1)| | "state a and state b had an equal number of candidates appeared . in state a , 6 % candidates got selected from the total appeared candidates in state b , 7 % candidates got selected from the total appeared candidates but in state b , 83 more candidates got selected than state a from these , it is clear that 1 % of the total appeared candidates in state b = 83 = > total appeared candidates in state b = 83 x 100 = 8300 = > total appeared candidates in state a = total appeared candidates in state b = 8300" | general |
math_qa__rW62ASC9Q0IvTUKJ | Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is: Choose the correct choice from the following answers.
A) 16 hours B) 18 hours C) 20 hours D) 24 hours E) 26 hours | <gadget id="calculator">9 + 1.5</gadget>
<output>10.5</output>
<gadget id="calculator">105 / 10.5</gadget>
<output>10</output>
<gadget id="calculator">9 - 1.5</gadget>
<output>7.5</output>
<gadget id="calculator">105 / 7.5</gadget>
<output>14</output>
<gadget id="calculator">10 + 14</gadget>
<output>24</output>
<result>D</result> | D | 24 | Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is: | {
"A": "16 hours",
"B": "18 hours",
"C": "20 hours",
"D": "24 hours",
"E": "26 hours"
} | add(divide(105, add(9, 1.5)), divide(105, subtract(9, 1.5))) | add(n0,n1)|subtract(n0,n1)|divide(n2,#0)|divide(n2,#1)|add(#2,#3)| | "speed of upstream = 9 - 1.5 = 7.5 kmph speed of down stream = 9 + 1.5 = 10.5 kmph total time = ( 105 / 7.5 ) + ( 105 / 10.5 ) = 24 hrs answer : d" | physics |
math_qa__zyJwgspjZIw4gMgs | For any integer k > 1, the term “length of an integer” refers to the number of positive prime factors, not necessarily distinct, whose product is equal to k. For example, if k = 24, the length of k is equal to 4, since 24 = 2 × 2 × 2 × 3. If x and y are positive integers such that x > 1, y > 1, and x + 3y < 902, what is the maximum possible sum of the length of x and the length of y? Choose the correct choice from the following choices.
A) 8
B) 10
C) 12
D) 14
E) 16 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">7 + 9</gadget>
<output>16</output>
<result>E</result> | E | 16 | For any integer k > 1, the term “length of an integer” refers to the number of positive prime factors, not necessarily distinct, whose product is equal to k. For example, if k = 24, the length of k is equal to 4, since 24 = 2 × 2 × 2 × 3. If x and y are positive integers such that x > 1, y > 1, and x + 3y < 902, what is the maximum possible sum of the length of x and the length of y? | {
"A": "8",
"B": "10",
"C": "12",
"D": "14",
"E": "16"
} | add(add(4, 3), add(add(4, 4), 1)) | add(n2,n7)|add(n2,n2)|add(n0,#1)|add(#0,#2)| | "we know that : x > 1 , y > 1 , and x + 3 y < 902 , and it is given that length means no of factors . for any value of x and y , the max no of factors can be obtained only if factor is smallest no all factors are equal . hence , lets start with smallest no 2 . 2 ^ 1 = 2 2 ^ 2 = 4 2 ^ 3 = 8 2 ^ 4 = 16 2 ^ 5 = 32 2 ^ 6 = 64 2 ^ 7 = 128 2 ^ 8 = 256 2 ^ 9 = 512 2 ^ 10 = 1024 ( it exceeds 1000 , so , x ca n ' t be 2 ^ 10 ) so , max value that x can take is 2 ^ 9 , for which has length of integer is 9 . now , since x = 512 , x + 3 y < 902 so , 3 y < 390 = = > y < 130 so , y can take any value which is less than 130 . and to get the maximum no of factors of smallest integer , we can say y = 2 ^ 7 for 2 ^ 7 has length of integer is 7 . so , combined together : 9 + 7 = 16 . e" | general |
math_qa__ICbmYjtzxLj8uZvx | Alice is now 10 years older than Bob. If in 6 years Alice will be twice as old as Bob, how old will Alice be in 5 years? Answers: A) 19 B) 21 C) 23 D) 25 E) 27 | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">25 - 6</gadget>
<output>19</output>
<result>A</result> | A | 19 | Alice is now 10 years older than Bob. If in 6 years Alice will be twice as old as Bob, how old will Alice be in 5 years? | {
"A": "19",
"B": "21",
"C": "23",
"D": "25",
"E": "27"
} | subtract(add(multiply(10, const_2), 5), 6) | multiply(n0,const_2)|add(n2,#0)|subtract(#1,n1) | a = b + 10 so b = a - 10 . a + 6 = 2 ( b + 6 ) . a + 6 = 2 ( a - 10 + 6 ) . a + 6 = 2 a - 8 . a = 14 . in 5 years , alice will be 19 years old . the answer is a . | general |
math_qa__dUvFm8VBdNnU1q8j | Thabo owns exactly 180 books, and each book is either paperback fiction, paperback nonfiction, or hardcover nonfiction. If he owns 20 more paperback nonfiction books than hardcover nonfiction books, and twice as many paperback fiction books as paperback nonfiction books, how many hardcover books nonfiction books does Thabo own? Choose the correct choice from the following
A) 10 B) 20 C) 30 D) 40 E) 50 | <gadget id="calculator">180 + 20</gadget>
<output>200</output>
<gadget id="calculator">200 / 4</gadget>
<output>50</output>
<gadget id="calculator">50 - 20</gadget>
<output>30</output>
<result>C</result> | C | 30 | Thabo owns exactly 180 books, and each book is either paperback fiction, paperback nonfiction, or hardcover nonfiction. If he owns 20 more paperback nonfiction books than hardcover nonfiction books, and twice as many paperback fiction books as paperback nonfiction books, how many hardcover books nonfiction books does Thabo own? | {
"A": "10",
"B": "20",
"C": "30",
"D": "40",
"E": "50"
} | subtract(divide(add(180, 20), const_4), 20) | add(n0,n1)|divide(#0,const_4)|subtract(#1,n1)| | "i think we can use double - matrix method and solve using only one variable . our goal is to find the number of hardcover nonfiction books . let that number be x . we are given that all 140 books are either paperback fiction , paperback nonfiction , or hardcover nonfiction . this implies that number of hardcover fiction books is 0 . double - matrix : p = paperback ; h = hardcover ; f = fiction ; nf = nonfiction p h total f 2 x + 40 0 nf x + 20 x total 3 x + 60 x 180 3 x + 60 + x = 180 x = 30 answer ( c . )" | general |
math_qa__9IU4SjN0zhGPFCc4 | a school has 7 maths 6 physics and 5 chemistry teachers each teacher can teach 3 subjects max what is he minimum number of teachers required
Choose the correct choice from the following choices:
A) 3
B) 5
C) 6
D) 7
E) 8 | <gadget id="calculator">7 + 6</gadget>
<output>13</output>
<gadget id="calculator">13 + 5</gadget>
<output>18</output>
<gadget id="calculator">18 / 3</gadget>
<output>6</output>
<result>C</result> | C | 6 | a school has 7 maths 6 physics and 5 chemistry teachers each teacher can teach 3 subjects max what is he minimum number of teachers required | {
"A": "3",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | divide(add(add(7, 6), 5), 3) | add(n0,n1)|add(n2,#0)|divide(#1,n3) | total subjects = 7 + 6 + 5 = 18 max subjects by 1 teacher = 3 so , min of teachers required = 18 / 3 = 6 answer : c | general |
math_qa__vyHKoCLSlXKy6cLg | In a market, a dozen eggs cost as much as a pound of rice, and a half-liter of kerosene costs as much as 8 eggs. If the cost of each pound of rice is $0.36, then how many cents does a liter of kerosene cost? [One dollar has 100 cents.] Choices: A) 0.33 B) 0.44 C) 0.48 D) 44 E) 48 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">8 / (1/2)</gadget>
<output>16</output>
<gadget id="calculator">16 / 12</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">0.36 * 100</gadget>
<output>36</output>
<gadget id="calculator">(4/3) * 36</gadget>
<output>48</output>
<result>E</result> | E | 48 | In a market, a dozen eggs cost as much as a pound of rice, and a half-liter of kerosene costs as much as 8 eggs. If the cost of each pound of rice is $0.36, then how many cents does a liter of kerosene cost? [One dollar has 100 cents.] | {
"A": "0.33",
"B": "0.44",
"C": "0.48",
"D": "44",
"E": "48"
} | multiply(divide(divide(8, divide(const_1, const_2)), const_12), multiply(0.36, 100)) | divide(const_1,const_2)|multiply(n1,n2)|divide(n0,#0)|divide(#2,const_12)|multiply(#3,#1)| | "a dozen eggs cost as much as a pound of rice - - > 12 eggs = 1 pound of rice = 36 cents ; a half - liter of kerosene costs as much as 8 eggs - - > 8 eggs = 1 / 2 liters of kerosene . how many cents does a liter of kerosene cost - - > 1 liter of kerosene = 16 eggs = 16 / 12 * 36 = 48 cents . answer : e ." | general |
math_qa__hcnXGaunK1SNga9I | At a certain high school, the senior class is twice the size of the junior class. If 3/8 of the seniors and 1/4 of the juniors study Japanese, what fraction of the students in both classes study Japanese? Choose the correct choice from the following answers.
A) 1 / 2 B) 2 / 3 C) 1 / 4 D) 1 / 3 E) 3 / 4 | <gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">4 / 12</gadget>
<output>1/3 = around 0.333333</output>
<result>D</result> | D | 0.333333 | At a certain high school, the senior class is twice the size of the junior class. If 3/8 of the seniors and 1/4 of the juniors study Japanese, what fraction of the students in both classes study Japanese? | {
"A": "1 / 2",
"B": "2 / 3",
"C": "1 / 4",
"D": "1 / 3",
"E": "3 / 4"
} | divide(4, add(8, 4)) | add(n1,n3)|divide(n3,#0)| | "start by deciding on a number of students to represent the number of students in the senior class . for this example i will choose 200 students . that would make the number of students in the junior class 100 . then we can find out how many students are taking japanese in each grade and add them together . ( 3 / 8 ) * 200 = 75 and ( 1 / 4 ) * 100 = 25 . 75 + 25 = 100 . there are a total of 300 students in the junior class and senior class combined ( 100 + 200 = 300 ) , and there are 100 total students in japanese , so 100 students in japanese / 300 total students equals 1 / 3 of the students in both classes that study japanese . answer : d" | general |
math_qa__n6cZhLtKA7ILJyLi | In a school with 604 students, the average age of the boys is 12 years and that of the girls is 11 years. If the average age of the school is 11 years 9 months, then the number of girls in the school is Select:
A) 150 B) 151 C) 250 D) 350 E) none | <gadget id="calculator">12 * 604</gadget>
<output>7_248</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">11 + (3/4)</gadget>
<output>47/4 = around 11.75</output>
<gadget id="calculator">(47/4) * 604</gadget>
<output>7_097</output>
<gadget id="calculator">7_248 - 7_097</gadget>
<output>151</output>
<result>B</result> | B | 151 | In a school with 604 students, the average age of the boys is 12 years and that of the girls is 11 years. If the average age of the school is 11 years 9 months, then the number of girls in the school is | {
"A": "150",
"B": "151",
"C": "250",
"D": "350",
"E": "none"
} | subtract(multiply(12, 604), multiply(add(11, divide(9, 12)), 604)) | divide(n4,n1)|multiply(n0,n1)|add(n2,#0)|multiply(n0,#2)|subtract(#1,#3)| | "sol . let the number of grils be x . then , number of boys = ( 600 - x ) . then , ( 11 3 / 4 × 604 ) ⇔ 11 x + 12 ( 604 - x ) ⇔ x = 7248 - 7097 ⇔ 151 . answer b" | general |
math_qa__gbKRB3bv8Vmp6cFM | When the price of an article was reduced by 20% its sale increased by 80%. What was the net effect on the sale? Answers: A) 44 % increase B) 44 % decrease C) 60 % increase D) 66 % increase E) 66 % decrease | <gadget id="calculator">80 + 100</gadget>
<output>180</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">180 * 80</gadget>
<output>14_400</output>
<gadget id="calculator">14_400 / 100</gadget>
<output>144</output>
<gadget id="calculator">144 - 100</gadget>
<output>44</output>
<result>A</result> | A | 44 | When the price of an article was reduced by 20% its sale increased by 80%. What was the net effect on the sale? | {
"A": "44 % increase",
"B": "44 % decrease",
"C": "60 % increase",
"D": "66 % increase",
"E": "66 % decrease"
} | subtract(divide(multiply(add(80, const_100), subtract(const_100, 20)), const_100), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|subtract(#3,const_100)| | "if n items are sold for $ p each , revenue is $ np . if we reduce the price by 20 % , the new price is 0.8 p . if we increase the number sold by 80 % , the new number sold is 1.8 n . so the new revenue is ( 0.8 p ) ( 1.8 n ) = 1.44 np , which is 1.44 times the old revenue , so is 44 % greater . answer : a" | gain |
math_qa__nSGfBEUQvEAa0wbj | A 110 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be? Choose the most appropriate option:
A) 35
B) 20
C) 47
D) 36
E) 31 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) + 1</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">110 / (7/5)</gadget>
<output>550/7 = around 78.571429</output>
<gadget id="calculator">110 - (550/7)</gadget>
<output>220/7 = around 31.428571</output>
<result>E</result> | E | 31 | A 110 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be? | {
"A": "35",
"B": "20",
"C": "47",
"D": "36",
"E": "31"
} | subtract(110, divide(110, add(divide(2, 5), const_1))) | divide(n1,n2)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)| | "1 : 2 / 5 = 5 : 2 2 / 7 * 110 = 31 answer : e" | physics |
math_qa__h2nOthcsUiOxmMQH | Sachin is younger than Rahul by 8 years. If the ratio of their ages is 7:9, find the age of Sachin
Choose the correct choice from the following answers: A) 24.58 B) 24.5 C) 26 D) 27 E) 28 | <gadget id="calculator">9 - 7</gadget>
<output>2</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 7</gadget>
<output>28</output>
<result>E</result> | E | 28 | Sachin is younger than Rahul by 8 years. If the ratio of their ages is 7:9, find the age of Sachin | {
"A": "24.58",
"B": "24.5",
"C": "26",
"D": "27",
"E": "28"
} | multiply(divide(8, subtract(9, 7)), 7) | subtract(n2,n1)|divide(n0,#0)|multiply(n1,#1)| | "if rahul age is x , then sachin age is x - 8 , so ( x - 8 ) / x = 7 / 9 = > 9 x - 72 = 7 x = > 2 x = 72 = > x = 36 so sachin age is 36 - 8 = 28 answer : e" | other |
math_qa__Lt6qSSTKU9Z1P6mS | How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length Choose the correct choice from the following choices.
A) 12 B) 12.1 C) 13 D) 14 E) 15 | <gadget id="calculator">110 + 132</gadget>
<output>242</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">242 / 20</gadget>
<output>121/10 = around 12.1</output>
<result>B</result> | B | 12.1 | How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length | {
"A": "12",
"B": "12.1",
"C": "13",
"D": "14",
"E": "15"
} | divide(add(110, 132), multiply(72, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 72 * 5 / 18 = 20 m / sec total distance covered = 110 + 132 = 242 m . required time = 242 / 20 = 12.1 sec . answer : option b" | physics |
math_qa__wZAVGh6ckRlaHkr1 | A dishonest dealer claims to sell a product at its cost price. He uses a counterfeit weight which is 20% less than the real weight. Further greed overtook him and he added 25% impurities to the product. Find the net profit percentage of the dealer? Choose the correct choice.
A) 44 % B) 40 % C) 50 % D) 56.25 % E) 36.25 % | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">125 / 80</gadget>
<output>25/16 = around 1.5625</output>
<gadget id="calculator">(25/16) - 1</gadget>
<output>9/16 = around 0.5625</output>
<gadget id="calculator">(9/16) * 100</gadget>
<output>225/4 = around 56.25</output>
<result>D</result> | D | 56.25 | A dishonest dealer claims to sell a product at its cost price. He uses a counterfeit weight which is 20% less than the real weight. Further greed overtook him and he added 25% impurities to the product. Find the net profit percentage of the dealer? | {
"A": "44 %",
"B": "40 %",
"C": "50 %",
"D": "56.25 %",
"E": "36.25 %"
} | multiply(subtract(divide(add(const_100, 25), subtract(const_100, 20)), const_1), const_100) | add(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)|subtract(#2,const_1)|multiply(#3,const_100)| | "the dealer uses weight which is 20 % less than the real weight . or ( 1 - 1 / 5 ) or 4 / 5 of real weight . it means that he is selling $ 4 worth of product for $ 5 . the dealer then further added 25 % impurities to the product . it means that he is selling $ 5 worth of product for $ 6.25 . so his profit is $ 6.25 - $ 4 = $ 2.25 and his profit percent is ( 2.25 / 4 ) * 100 = 56.25 % answer : - d" | general |
math_qa__aXB4PEH67d13gZB7 | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 110 mph. On the way home, I flew 90 mph. What was my average speed for the trip? Options.
A) 198 mph B) 110 mph C) 88 mph D) 100 mph E) 99 mph | <gadget id="calculator">110 + 90</gadget>
<output>200</output>
<gadget id="calculator">200 / 2</gadget>
<output>100</output>
<result>D</result> | D | 100 | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 110 mph. On the way home, I flew 90 mph. What was my average speed for the trip? | {
"A": "198 mph",
"B": "110 mph",
"C": "88 mph",
"D": "100 mph",
"E": "99 mph"
} | divide(add(110, 90), const_2) | add(n0,n1)|divide(#0,const_2) | ( 110 mph + 90 mph ) / 2 = 100 mph correct answer is : d | physics |
math_qa__9izgAZpNklqzdKV1 | In 30 years, A will be twice as old as B was 30 years ago. If A is now 5 years older than B, the present age of B is?
Choices: A) 85 yrs B) 95 yrs C) 93 yrs D) 82 yrs E) 90 yrs | <gadget id="calculator">2 * 30</gadget>
<output>60</output>
<gadget id="calculator">60 + 30</gadget>
<output>90</output>
<gadget id="calculator">90 + 5</gadget>
<output>95</output>
<result>B</result> | B | 95 | In 30 years, A will be twice as old as B was 30 years ago. If A is now 5 years older than B, the present age of B is? | {
"A": "85 yrs",
"B": "95 yrs",
"C": "93 yrs",
"D": "82 yrs",
"E": "90 yrs"
} | add(add(multiply(const_2, 30), 30), 5) | multiply(n0,const_2)|add(n0,#0)|add(n2,#1)| | "let b ' s present age = x years then a ' s present age = x + 5 years x + 5 + 30 = 2 ( x - 30 ) x + 35 = 2 x - 60 x = 95 years answer is b" | general |
math_qa__hbCVUkZ3kdblRyKe | A jogger running at 9 kmph along side a railway track is 280 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger? Select the correct option
A) 3.6 sec B) 40 sec C) 36 sec D) 72 sec E) none of these | <gadget id="calculator">280 + 120</gadget>
<output>400</output>
<gadget id="calculator">400 / 1_000</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">(2/5) / 36</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">(1/90) * 60</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 60</gadget>
<output>40</output>
<result>B</result> | B | 40 | A jogger running at 9 kmph along side a railway track is 280 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger? | {
"A": "3.6 sec",
"B": "40 sec",
"C": "36 sec",
"D": "72 sec",
"E": "none of these"
} | multiply(multiply(divide(divide(add(280, 120), const_1000), subtract(45, 9)), const_60), const_60) | add(n1,n2)|subtract(n3,n0)|divide(#0,const_1000)|divide(#2,#1)|multiply(#3,const_60)|multiply(#4,const_60)| | "speed of train relative to jogger = ( 45 – 9 ) km / h = 36 km / h = ( 36 × 5 ⁄ 18 ) m / sec = 10 m / sec distance to be covered = ( 280 + 120 ) m = 400 m . ∴ time taken = ( 400 ⁄ 10 ) sec = 40 sec . answer b" | physics |
math_qa__qzHMOdlOIyjJOQ54 | An escalator moves towards the top level at the rate of 7 ft.sec and its length is 180 feet. If a person walks on the moving escalator at the rate of 2 feet per second towards the top level, how much time does he take to cover the entire length. Choose the correct choice.
A) 5 sec B) 25 sec C) 20 sec D) 15 sec E) 10 sec | <gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">180 / 9</gadget>
<output>20</output>
<result>C</result> | C | 20 | An escalator moves towards the top level at the rate of 7 ft.sec and its length is 180 feet. If a person walks on the moving escalator at the rate of 2 feet per second towards the top level, how much time does he take to cover the entire length. | {
"A": "5 sec",
"B": "25 sec",
"C": "20 sec",
"D": "15 sec",
"E": "10 sec"
} | divide(180, add(7, 2)) | add(n0,n2)|divide(n1,#0)| | "explanation : time taken to cover the entire length = tot . dist / resultant speed = 180 / ( 7 + 2 ) = 20 sec answer : c" | gain |
math_qa__qcV7vj3z3IAWAeyC | Anil grows tomatoes in his backyard which is in the shape of a square. Each tomato takes 1 cm2 in his backyard. This year, he has been able to grow 131 more tomatoes than last year. The shape of the backyard remained a square. How many tomatoes did Anil produce this year? Choose the correct choice.
A) 4225 B) 4096 C) 4356 D) insufficient data E) none of these | <gadget id="calculator">131 + 1</gadget>
<output>132</output>
<gadget id="calculator">132 / 2</gadget>
<output>66</output>
<gadget id="calculator">66 ** 2</gadget>
<output>4_356</output>
<result>C</result> | C | 4,356 | Anil grows tomatoes in his backyard which is in the shape of a square. Each tomato takes 1 cm2 in his backyard. This year, he has been able to grow 131 more tomatoes than last year. The shape of the backyard remained a square. How many tomatoes did Anil produce this year? | {
"A": "4225",
"B": "4096",
"C": "4356",
"D": "insufficient data",
"E": "none of these"
} | power(divide(add(131, 1), const_2), const_2) | add(n0,n2)|divide(#0,const_2)|power(#1,const_2) | detailed solution let the area of backyard be x 2 this year and y 2 last year ∴ x 2 - y 2 = 131 = ) ( x + y ) ( x - y ) = 131 now , 131 is a prime number ( a unique one too . check out its properties on google ) . also , always identify the prime number given in a question . might be helpful in cracking the solution . = ) ( x + y ) ( x - y ) = 131 x 1 = ) x + y = 131 x - y = 1 = ) 2 x = 132 = ) x = 66 and y = 65 ∴ number of tomatoes produced this year = 662 = 4356 correct choice ( c ) | physics |
math_qa__Okn6QNUDCkZVX0oe | A sum of money at simple interest amounts to Rs. 1717 in 1 year and to Rs. 1734 in 2 years. The sum is: Choose the correct choice from the following choices
A) rs . 1200
B) rs . 1690
C) rs . 1600
D) rs . 1700
E) rs . 1500 | <gadget id="calculator">1_734 - 1_717</gadget>
<output>17</output>
<gadget id="calculator">17 * 1</gadget>
<output>17</output>
<gadget id="calculator">17 / 2</gadget>
<output>17/2 = around 8.5</output>
<gadget id="calculator">1_717 - (17/2)</gadget>
<output>3_417/2 = around 1_708.5</output>
<result>D</result> | D | 1,700 | A sum of money at simple interest amounts to Rs. 1717 in 1 year and to Rs. 1734 in 2 years. The sum is: | {
"A": "rs . 1200",
"B": "rs . 1690",
"C": "rs . 1600",
"D": "rs . 1700",
"E": "rs . 1500"
} | subtract(1717, divide(multiply(subtract(1734, 1717), 1), 2)) | subtract(n2,n0)|multiply(n1,#0)|divide(#1,n3)|subtract(n0,#2)| | "s . i . for 1 year = rs . ( 1734 - 1717 ) = rs . 17 . principal = rs . ( 1717 - 17 ) = rs . 1700 . answer : option d" | gain |
math_qa__euk8HHJUM2aLLHe1 | if remainder is 8 , quotient is 43 and dividend is 997 then what is divisor ? Choices:
A) 21 B) 20 C) 23 D) 27 E) 31 | <gadget id="calculator">997 - 8</gadget>
<output>989</output>
<gadget id="calculator">989 / 43</gadget>
<output>23</output>
<result>C</result> | C | 23 | if remainder is 8 , quotient is 43 and dividend is 997 then what is divisor ? | {
"A": "21",
"B": "20",
"C": "23",
"D": "27",
"E": "31"
} | divide(subtract(997, 8), 43) | subtract(n2,n0)|divide(#0,n1) | we know dividend = divisor * quotient + remainder = = = > 997 = divisor * 43 + 8 = = = = = > 989 / 43 = divisor = = = > divisor = 23 ans - c | general |
math_qa__tnHySzkqhRcfYhiv | Victor gets 80 % marks in examinations. If these are 240 marks, find the maximum marks. Pick.
A) 334
B) 300
C) 376
D) 288
E) 271 | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">240 / (4/5)</gadget>
<output>300</output>
<result>B</result> | B | 300 | Victor gets 80 % marks in examinations. If these are 240 marks, find the maximum marks. | {
"A": "334",
"B": "300",
"C": "376",
"D": "288",
"E": "271"
} | divide(240, divide(80, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "let the maximum marks be m then 80 % of m = 240 ⇒ 80 / 100 × m = 240 ⇒ m = ( 240 × 100 ) / 80 ⇒ m = 24000 / 80 ⇒ m = 300 therefore , maximum marks in the examinations are 300 answer : b" | gain |
math_qa__5fRjDab0AtlN7y2Y | The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 10800 sq. m, the cost of fencing the field @ 25 paise per metre is Answers
A) rs . 55.50 B) rs . 67.50 C) rs . 86.50 D) rs . 105.00 E) none of these | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">10_800 / 12</gadget>
<output>900</output>
<gadget id="calculator">900 ** (1/2)</gadget>
<output>30</output>
<gadget id="calculator">3 * 30</gadget>
<output>90</output>
<gadget id="calculator">4 * 30</gadget>
<output>120</output>
<gadget id="calculator">2 * (90 + 120)</gadget>
<output>420</output>
<gadget id="calculator">420 * 25</gadget>
<output>10_500</output>
<gadget id="calculator">10_500 / 100</gadget>
<output>105</output>
<result>D</result> | D | 105 | The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 10800 sq. m, the cost of fencing the field @ 25 paise per metre is | {
"A": "rs . 55.50",
"B": "rs . 67.50",
"C": "rs . 86.50",
"D": "rs . 105.00",
"E": "none of these"
} | divide(multiply(rectangle_perimeter(multiply(3, sqrt(divide(10800, multiply(3, 4)))), multiply(4, sqrt(divide(10800, multiply(3, 4))))), 25), const_100) | multiply(n0,n1)|divide(n2,#0)|sqrt(#1)|multiply(n0,#2)|multiply(n1,#2)|rectangle_perimeter(#3,#4)|multiply(n3,#5)|divide(#6,const_100)| | "solution let length = ( 3 x ) metres and breadth = ( 4 x ) metres . then , 3 x × 4 x = 10800 ⇔ 12 x 2 = 10800 ⇔ x 2 = 900 ⇔ x = 30 . so , length = 90 m and breadth = 120 m . perimeter = [ 2 ( 90 + 120 ) ] m = 420 m . ∴ cost of fencing = rs . ( 0.25 × 420 ) = rs . 105.00 . answer d" | physics |
math_qa__hQtBZAiOoYdIC5G3 | Q and R are two-digit positive integers that have the same digits but in reverse order. If the positive difference between Q and R is less than 60, what is the greatest possible value of Q minus R? Choose the correct choice.
A) 52 B) 54 C) 55 D) 56 E) 58 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">60 % 9</gadget>
<output>6</output>
<gadget id="calculator">6 * 9</gadget>
<output>54</output>
<result>B</result> | B | 54 | Q and R are two-digit positive integers that have the same digits but in reverse order. If the positive difference between Q and R is less than 60, what is the greatest possible value of Q minus R? | {
"A": "52",
"B": "54",
"C": "55",
"D": "56",
"E": "58"
} | multiply(reminder(60, subtract(const_10, const_1)), subtract(const_10, const_1)) | subtract(const_10,const_1)|reminder(n0,#0)|multiply(#1,#0)| | "a two - digit integer ` ` ab ' ' can be expressed algebraically as 10 a + b . q - r = ( 10 a + b ) - ( 10 b + a ) = 9 ( a - b ) < 60 . the greatest multiple of 9 which is less than 60 is 54 . the answer is b ." | general |
math_qa__McdAlp74EwsmX8zO | There were 35 students in a hostel. Due to the admission of 7 new students the expenses of the mess were increased by Rs.84 per day while the average expenditure per head diminished by Re 1. What was the original expenditure of the mess? Select the correct option.
A) rs 450 B) rs 920 C) rs 550 D) rs . 630 E) none of these | <gadget id="calculator">35 + 7</gadget>
<output>42</output>
<gadget id="calculator">84 + 42</gadget>
<output>126</output>
<gadget id="calculator">126 / 7</gadget>
<output>18</output>
<gadget id="calculator">18 * 35</gadget>
<output>630</output>
<result>D</result> | D | 630 | There were 35 students in a hostel. Due to the admission of 7 new students the expenses of the mess were increased by Rs.84 per day while the average expenditure per head diminished by Re 1. What was the original expenditure of the mess? | {
"A": "rs 450",
"B": "rs 920",
"C": "rs 550",
"D": "rs . 630",
"E": "none of these"
} | multiply(divide(add(84, add(35, 7)), 7), 35) | add(n0,n1)|add(n2,#0)|divide(#1,n1)|multiply(n0,#2) | explanation : let the original average expenditure be rs . x then , 42 ( x - 1 ) - 35 x = 84 ? 7 x = 126 ? x = 18 therefore original expenditure = rs . ( 35 18 ) = rs . 630 . answer : d | general |
math_qa__yYfrsd6Qbpt8fiDS | A 480 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 620 m in ? Choose one.
A) 41.1 sec B) 72 sec C) 31.8 sec D) 50.4 sec E) none of the above | <gadget id="calculator">480 + 620</gadget>
<output>1_100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">55 * (5/18)</gadget>
<output>275/18 = around 15.277778</output>
<gadget id="calculator">1_100 / (275/18)</gadget>
<output>72</output>
<result>B</result> | B | 72 | A 480 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 620 m in ? | {
"A": "41.1 sec",
"B": "72 sec",
"C": "31.8 sec",
"D": "50.4 sec",
"E": "none of the above"
} | divide(add(480, 620), multiply(55, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 55 km / hr ( to convert km / hr in to m / s ) = 55 x 5 / 18 m / s distance = 480 m + 620 m ( if questions is about train crossing a post you need to consider only the length of train , ) = 1100 m time = distance / speed = 1100 x 18 / ( 5 x 55 ) = 72 sec ans is : b" | physics |
math_qa__jxn8tcPxlXXDBg2S | If the sum and difference of two numbers are 15 and 10 respectively, then the difference of their square is: Choose the correct option.
A) 12 B) 150 C) 160 D) 180 E) 18 | <gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 / 2</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) ** 2</gadget>
<output>625/4 = around 156.25</output>
<gadget id="calculator">15 - (25/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) ** 2</gadget>
<output>25/4 = around 6.25</output>
<gadget id="calculator">(625/4) - (25/4)</gadget>
<output>150</output>
<result>B</result> | B | 150 | If the sum and difference of two numbers are 15 and 10 respectively, then the difference of their square is: | {
"A": "12",
"B": "150",
"C": "160",
"D": "180",
"E": "18"
} | subtract(power(divide(add(15, 10), const_2), const_2), power(subtract(15, divide(add(15, 10), const_2)), const_2)) | add(n0,n1)|divide(#0,const_2)|power(#1,const_2)|subtract(n0,#1)|power(#3,const_2)|subtract(#2,#4)| | "let the numbers be x and y . then , x + y = 15 and x - y = 10 x 2 - y 2 = ( x + y ) ( x - y ) = 15 * 10 = 150 . answer : b" | general |
math_qa__73Uo1iUwzsRkm8yG | A shopkeeper sold an article at $100 with 45% profit. Then find its cost price? Choose the correct choice from the following choices.
A) $ 120 B) $ 100 C) $ 91 D) $ 72 E) $ 69 | <gadget id="calculator">100 + 45</gadget>
<output>145</output>
<gadget id="calculator">100 / 145</gadget>
<output>20/29 = around 0.689655</output>
<gadget id="calculator">100 * (20/29)</gadget>
<output>2_000/29 = around 68.965517</output>
<result>E</result> | E | 69 | A shopkeeper sold an article at $100 with 45% profit. Then find its cost price? | {
"A": "$ 120",
"B": "$ 100",
"C": "$ 91",
"D": "$ 72",
"E": "$ 69"
} | multiply(100, divide(100, add(100, 45))) | add(n1,n0)|divide(n0,#0)|multiply(n0,#1)| | "cost price = selling price * 100 / ( 100 + profit ) c . p . = 100 * 100 / 145 = $ 69 ( approximately ) answer is e" | gain |
math_qa__u2MXHPBpTcn29G8z | The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 17%, then the cost price of the article is: Choose the most appropriate option:
A) 500 B) 334 C) 555 D) 664 E) 526 | <gadget id="calculator">616 * 100</gadget>
<output>61_600</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">61_600 / 110</gadget>
<output>560</output>
<gadget id="calculator">560 * 110</gadget>
<output>61_600</output>
<gadget id="calculator">100 + 17</gadget>
<output>117</output>
<gadget id="calculator">61_600 / 117</gadget>
<output>61_600/117 = around 526.495726</output>
<result>E</result> | E | 526 | The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 17%, then the cost price of the article is: | {
"A": "500",
"B": "334",
"C": "555",
"D": "664",
"E": "526"
} | divide(multiply(divide(multiply(616, const_100), add(const_100, 10)), add(const_100, 10)), add(const_100, 17)) | add(n1,const_100)|add(n2,const_100)|multiply(n0,const_100)|divide(#2,#0)|multiply(#0,#3)|divide(#4,#1) | 110 % of s . p . = 616 s . p . = ( 616 * 100 ) / 110 = rs . 560 c . p = ( 110 * 560 ) / 117 = rs . 526 answer : option e | gain |
math_qa__Wvh5rx9UmRdl61Lw | A 35 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be? Choose the correct choice from the following: A) 10 B) 20 C) 88 D) 77 E) 14 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) + 1</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">35 / (7/5)</gadget>
<output>25</output>
<gadget id="calculator">35 - 25</gadget>
<output>10</output>
<result>A</result> | A | 10 | A 35 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be? | {
"A": "10",
"B": "20",
"C": "88",
"D": "77",
"E": "14"
} | subtract(35, divide(35, add(divide(2, 5), const_1))) | divide(n1,n2)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)| | "1 : 2 / 5 = 5 : 2 2 / 7 * 35 = 10 answer : a" | physics |
math_qa__tW51WI4MpKj95UdQ | Car A is 30 miles behind car B, which is traveling in the same direction along the same route as Car A.Car A is traveling at a constant speed of 58 miles per hour and Car Bis traveling at a constant speed of 50miles per hour.How many hours will it take for Car A to overtake and drive 8 miles ahead of Car B? Choose one.
A) 1.5 B) 4.5 C) 4.75 D) 3.75 E) 3.5 | <gadget id="calculator">30 + 8</gadget>
<output>38</output>
<gadget id="calculator">58 - 50</gadget>
<output>8</output>
<gadget id="calculator">38 / 8</gadget>
<output>19/4 = around 4.75</output>
<result>C</result> | C | 4.75 | Car A is 30 miles behind car B, which is traveling in the same direction along the same route as Car A.Car A is traveling at a constant speed of 58 miles per hour and Car Bis traveling at a constant speed of 50miles per hour.How many hours will it take for Car A to overtake and drive 8 miles ahead of Car B? | {
"A": "1.5",
"B": "4.5",
"C": "4.75",
"D": "3.75",
"E": "3.5"
} | divide(add(30, 8), subtract(58, 50)) | add(n0,n3)|subtract(n1,n2)|divide(#0,#1)| | "relative speed of car a is 58 - 50 = 8 miles per hour , to catch up 30 miles and drive 8 miles ahead so to drive 38 miles it ' ll need 38 / 8 = 3.5 hours . answer : c" | physics |
math_qa__jbkkL6tfOFJCvyvy | If a car went the first third of the distance at 80 kmh, the second third at 18 kmh, and the last third at 48 kmh, what was the average speed of the car for the entire trip? Choose the correct choice from the following answers.
A) 34 kmh
B) 40 kmh
C) 42 kmh
D) 44 kmh
E) 50 kmh | <gadget id="calculator">1 / 80</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/80) + (1/18)</gadget>
<output>49/720 = around 0.068056</output>
<gadget id="calculator">1 / 48</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">(49/720) + (1/48)</gadget>
<output>4/45 = around 0.088889</output>
<gadget id="calculator">3 / (4/45)</gadget>
<output>135/4 = around 33.75</output>
<result>A</result> | A | 34 | If a car went the first third of the distance at 80 kmh, the second third at 18 kmh, and the last third at 48 kmh, what was the average speed of the car for the entire trip? | {
"A": "34 kmh",
"B": "40 kmh",
"C": "42 kmh",
"D": "44 kmh",
"E": "50 kmh"
} | divide(const_3, add(add(divide(const_1, 80), divide(const_1, 18)), divide(const_1, 48))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#3,#2)|divide(const_3,#4)| | "assume d / 3 = 720 ( this number is convenient because it is divisible by 80 , 18 and 48 ) so : 720 = 80 * t 1 = 9 hrs 720 = 18 * t 2 = 40 hrs 720 = 48 * t 3 = 15 hrs t = t 1 + t 2 + t 3 = 64 hrs d = rt ( 720 * 3 ) = r * 64 r = 33.75 answer : a" | physics |
math_qa__a3pQH69wkToXFZrC | In a group of ducks and cows, the total number of legs are 22 more than twice the no. of heads. Find the total no.of buffaloes.
Choose the correct choice from the following
A) 11 B) 12 C) 13 D) 15 E) 16 | <gadget id="calculator">22 / 2</gadget>
<output>11</output>
<result>A</result> | A | 11 | In a group of ducks and cows, the total number of legs are 22 more than twice the no. of heads. Find the total no.of buffaloes. | {
"A": "11",
"B": "12",
"C": "13",
"D": "15",
"E": "16"
} | divide(22, const_2) | divide(n0,const_2)| | "let the number of buffaloes be x and the number of ducks be y = > 4 x + 2 y = 2 ( x + y ) + 22 = > 2 x = 22 = > x = 11 a" | general |
math_qa__vUevFicz7iDjD27W | How long does a train 110 meters long running at the rate of 36km/hr take to cross a bridge 132 meters in length? Choose the correct choice from the following answers
A) 24.2 sec B) 30.6 sec C) 32.6 sec D) 28.1 sec E) 20.4 sec | <gadget id="calculator">110 + 132</gadget>
<output>242</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">242 / 10</gadget>
<output>121/5 = around 24.2</output>
<result>A</result> | A | 24.2 | How long does a train 110 meters long running at the rate of 36km/hr take to cross a bridge 132 meters in length? | {
"A": "24.2 sec",
"B": "30.6 sec",
"C": "32.6 sec",
"D": "28.1 sec",
"E": "20.4 sec"
} | divide(add(110, 132), multiply(36, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "distance = length of train + length of bridge = 110 + 132 = 242 speed = 36 km / hr = 36 * 5 / 18 = 10 m / s required time = 242 / 10 = 24.2 seconds answer is a" | gain |
math_qa__nIAX5ZfagtnbMJ2b | A certain airline's fleet consisted of 100 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet? Choose the correct choice from the following.
A) 14 B) 15 C) 16 D) 17 E) 18 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">100 / 7</gadget>
<output>100/7 = around 14.285714</output>
<result>B</result> | B | 15 | A certain airline's fleet consisted of 100 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet? | {
"A": "14",
"B": "15",
"C": "16",
"D": "17",
"E": "18"
} | divide(100, add(3, 4)) | add(n3,n4)|divide(n0,#0)| | "let x be the number of years . 4 x > 100 - 3 x 7 x > 100 x > 14 + 2 / 7 the answer is b ." | gain |
math_qa__GpZo1peqgIAWYh2W | On dividing 23 by a number, the quotient is 5 and the remainder is 3. Find the divisor.
Choose the correct choice.
A) 1
B) 2
C) 4
D) 6
E) 7 | <gadget id="calculator">23 / 5</gadget>
<output>23/5 = around 4.6</output>
<gadget id="calculator">floor(23/5)</gadget>
<output>4</output>
<result>C</result> | C | 4 | On dividing 23 by a number, the quotient is 5 and the remainder is 3. Find the divisor. | {
"A": "1",
"B": "2",
"C": "4",
"D": "6",
"E": "7"
} | floor(divide(23, 5)) | divide(n0,n1)|floor(#0) | d = ( d - r ) / q = ( 23 - 3 ) / 5 = 20 / 5 = 4 c | general |
math_qa__YOQdS2owUDQxr9On | (2^2+4^2+6^2+.....+14^2)=?
Choose the correct option:
A) 88 B) 560 C) 99 D) 550 E) 540 | <gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">2 * 7</gadget>
<output>14</output>
<gadget id="calculator">8 * 14</gadget>
<output>112</output>
<gadget id="calculator">14 + 1</gadget>
<output>15</output>
<gadget id="calculator">112 * 15</gadget>
<output>1_680</output>
<gadget id="calculator">1_680 / 3</gadget>
<output>560</output>
<result>B</result> | B | 560 | (2^2+4^2+6^2+.....+14^2)=? | {
"A": "88",
"B": "560",
"C": "99",
"D": "550",
"E": "540"
} | divide(multiply(multiply(add(add(6, const_1), const_1), multiply(2, add(6, const_1))), add(14, const_1)), const_3) | add(n6,const_1)|add(n4,const_1)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,#3)|multiply(#0,#4)|divide(#5,const_3) | = ( 1 x 2 ) ^ 2 + ( 2 x 2 ) ^ 2 , + ( 2 x 3 ) ^ 3 + . . . . . . ( 2 x 7 ) ^ 2 = 2 ^ 2 x ( 1 ^ 2 + 2 ^ 2 + 3 ^ 2 + . . . . . . . + 7 ^ 2 ) formula is = 1 / 6 n ( n + 1 ) ( 2 n + 1 ) = ( 4 x 1 / 6 x 7 x 8 x 15 ) = ( 4 x 140 ) = 560 answer is b | general |
math_qa__i04161CerDSb81Tf | Find large number from below question The difference of two numbers is 100. On dividing the larger number by the smaller, we get 9 as quotient and the 4 as remainder Choose the correct choice from the following answers
A) 120 B) 100 C) 112 D) 150 E) 105 | <gadget id="calculator">100 - 4</gadget>
<output>96</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">96 / 8</gadget>
<output>12</output>
<gadget id="calculator">12 * 9</gadget>
<output>108</output>
<result>C</result> | C | 112 | Find large number from below question The difference of two numbers is 100. On dividing the larger number by the smaller, we get 9 as quotient and the 4 as remainder | {
"A": "120",
"B": "100",
"C": "112",
"D": "150",
"E": "105"
} | multiply(divide(subtract(100, 4), subtract(9, const_1)), 9) | subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)| | "let the smaller number be x . then larger number = ( x + 100 ) . x + 100 = 9 x + 4 8 x = 96 x = 12 large number = 12 + 100 = 112 c" | general |
math_qa__PbUWl7THMGVOsIpB | Find the area of trapezium whose parallel sides are 18 cm and 12 cm long, and the distance between them is 14 cm? Choose the correct option: A) 288 cm 2 B) 277 cm 2 C) 224 cm 2 D) 226 cm 2 E) 227 cm 2 | <gadget id="calculator">(14 + 12) * 18 / 2</gadget>
<output>234</output>
<result>C</result> | C | 224 | Find the area of trapezium whose parallel sides are 18 cm and 12 cm long, and the distance between them is 14 cm? | {
"A": "288 cm 2",
"B": "277 cm 2",
"C": "224 cm 2",
"D": "226 cm 2",
"E": "227 cm 2"
} | quadrilateral_area(14, 12, 18) | quadrilateral_area(n2,n1,n0)| | "area of a trapezium = 1 / 2 ( sum of parallel sides ) * ( perpendicular distance between them ) = 1 / 2 ( 18 + 12 ) * ( 14 ) = 224 cm 2 answer : c" | physics |
math_qa__tddEFiMVAP4heOGn | The function f(x) = x + 4 is given. Solve the equation:
[3.f(x - 2)]/f(0) + 4 = f(2x + 1) Choose the correct choice:
A) 0.2 B) 0.3 C) 0.4 D) 0.5 E) none of these | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">6 + 16</gadget>
<output>22</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">22 - 20</gadget>
<output>2</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<result>C</result> | C | 0.4 | The function f(x) = x + 4 is given. Solve the equation:
[3.f(x - 2)]/f(0) + 4 = f(2x + 1) | {
"A": "0.2",
"B": "0.3",
"C": "0.4",
"D": "0.5",
"E": "none of these"
} | divide(subtract(add(multiply(3, subtract(4, 2)), multiply(4, 4)), multiply(4, add(1, 4))), subtract(multiply(4, 2), 3)) | add(n0,n6)|multiply(n0,n0)|multiply(n0,n2)|subtract(n0,n2)|multiply(n1,#3)|multiply(n0,#0)|subtract(#2,n1)|add(#4,#1)|subtract(#7,#5)|divide(#8,#6) | solution : we calculate f ( 0 ) , f ( x - 2 ) , f ( 2 x + 1 ) , namely f ( 0 ) = 0 + 4 = 4 ; f ( x - 2 ) = x - 2 + 4 = x + 2 ; f ( 2 x + 1 ) = 2 x + 1 + 4 = 2 x + 5 the equation gets this look [ 3 ( x + 2 ) ] / 4 + 4 = 2 x + 5 < = > 3 ( x + 2 ) + 16 = 4 ( 2 x + 5 ) < = > 3 x + 6 + 16 = 8 x + 20 < = > 22 - 20 = 8 x - 3 x < = > 2 = 5 x < = > x = 0.4 answer c | general |
math_qa__9HIM4yzKcy3j37I1 | A 340-liter solution of Kola is made from 80% water, 6% concentrated Kola and the rest is made from sugar. If 3.2 liters of sugar, 10 liter of water and 6.8 liters of concentrated Kola were added to the solution, what percent of the solution is made from sugar? Select: A) 6 % . B) 7.5 % . C) 9.2 % . D) 10.5 % . E) 14 % . | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">340 * (4/5)</gadget>
<output>272</output>
<gadget id="calculator">340 - 272</gadget>
<output>68</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">340 * (3/50)</gadget>
<output>102/5 = around 20.4</output>
<gadget id="calculator">68 - (102/5)</gadget>
<output>238/5 = around 47.6</output>
<gadget id="calculator">(238/5) + 3.2</gadget>
<output>50.8</output>
<gadget id="calculator">340 + 3.2</gadget>
<output>343.2</output>
<gadget id="calculator">343.2 + 10</gadget>
<output>353.2</output>
<gadget id="calculator">353.2 + 6.8</gadget>
<output>360</output>
<gadget id="calculator">50.8 / 360</gadget>
<output>0.141111</output>
<gadget id="calculator">0.141111 * 100</gadget>
<output>14.1111</output>
<result>E</result> | E | 14 | A 340-liter solution of Kola is made from 80% water, 6% concentrated Kola and the rest is made from sugar. If 3.2 liters of sugar, 10 liter of water and 6.8 liters of concentrated Kola were added to the solution, what percent of the solution is made from sugar? | {
"A": "6 % .",
"B": "7.5 % .",
"C": "9.2 % .",
"D": "10.5 % .",
"E": "14 % ."
} | multiply(divide(add(subtract(subtract(340, multiply(340, divide(80, const_100))), multiply(340, divide(6, const_100))), 3.2), add(add(add(340, 3.2), 10), 6.8)), const_100) | add(n0,n3)|divide(n1,const_100)|divide(n2,const_100)|add(n4,#0)|multiply(n0,#1)|multiply(n0,#2)|add(n5,#3)|subtract(n0,#4)|subtract(#7,#5)|add(n3,#8)|divide(#9,#6)|multiply(#10,const_100) | denominator : 340 + 10 + 3.2 + 6.8 = 360 numerator : 340 ( 1 - . 80 - . 06 ) + 3.2 340 ( 0.14 ) + 3.2 47.6 + 3.2 50.8 ratio : 50.8 / 360 = 0.14 answer : e | gain |
math_qa__lss2Wi6gBLAoRzIy | Find the largest 6 digit number which is exactly divisible by 88? Select: A) 998765 B) 998907 C) 999944 D) 999954 E) 999990 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">10_000 + 1_000</gadget>
<output>11_000</output>
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<gadget id="calculator">11_000 + 300</gadget>
<output>11_300</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">11_300 + 60</gadget>
<output>11_360</output>
<gadget id="calculator">11_360 + 3</gadget>
<output>11_363</output>
<gadget id="calculator">11_363 * 88</gadget>
<output>999_944</output>
<result>C</result> | C | 999,944 | Find the largest 6 digit number which is exactly divisible by 88? | {
"A": "998765",
"B": "998907",
"C": "999944",
"D": "999954",
"E": "999990"
} | multiply(add(add(add(add(multiply(const_100, const_100), multiply(const_100, const_10)), multiply(const_100, const_3)), multiply(6, const_10)), const_3), 88) | multiply(const_100,const_100)|multiply(const_10,const_100)|multiply(const_100,const_3)|multiply(n0,const_10)|add(#0,#1)|add(#4,#2)|add(#5,#3)|add(#6,const_3)|multiply(n1,#7) | largest 6 digit number is 999999 after doing 999999 ÷ 88 we get remainder 55 hence largest 6 digit number exactly divisible by 88 = 999999 - 55 = 999944 c | general |
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