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math_qa__FPDi2YfHP13z6iLM | A pupil's marks were wrongly entered as 67 instead of 45. Due to that the average marks for the class got increased by half. The number of pupils in the class is : Choose the correct choice from the following answers:
A) 30
B) 80
C) 44
D) 25
E) 26 | <gadget id="calculator">67 - 45</gadget>
<output>22</output>
<gadget id="calculator">22 * 2</gadget>
<output>44</output>
<result>C</result> | C | 44 | A pupil's marks were wrongly entered as 67 instead of 45. Due to that the average marks for the class got increased by half. The number of pupils in the class is : | {
"A": "30",
"B": "80",
"C": "44",
"D": "25",
"E": "26"
} | multiply(subtract(67, 45), const_2) | subtract(n0,n1)|multiply(#0,const_2)| | "let there be x pupils in the class . total increase in marks = ( x * 1 / 2 ) = x / 2 . x / 2 = ( 67 - 45 ) = > x / 2 = 22 = > x = 44 . answer : c" | general |
math_qa__a3aguC8M3LsbtXOH | A marketing survey of Anytown found that the ratio of trucks to sedans to motorcycles was 3:7:2, respectively. Given that there are 9,100 sedans in Anytown, how many motorcycles are there? Choices:
A) 1260 B) 2600 C) 3600 D) 4200 E) 5200 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 1_000</gadget>
<output>9_000</output>
<gadget id="calculator">9_000 + 100</gadget>
<output>9_100</output>
<gadget id="calculator">9_100 / 7</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 * 2</gadget>
<output>2_600</output>
<result>B</result> | B | 2,600 | A marketing survey of Anytown found that the ratio of trucks to sedans to motorcycles was 3:7:2, respectively. Given that there are 9,100 sedans in Anytown, how many motorcycles are there? | {
"A": "1260",
"B": "2600",
"C": "3600",
"D": "4200",
"E": "5200"
} | multiply(divide(add(multiply(multiply(const_3, const_3), const_1000), const_100), 7), 2) | multiply(const_3,const_3)|multiply(#0,const_1000)|add(#1,const_100)|divide(#2,n1)|multiply(n2,#3) | let the total number of trucks = 3 x total number of sedans = 7 x total number of motorcycles = 2 x total number of sedans = 9100 = > 7 x = 9100 = > x = 1300 total number of motorcycles = 2 x = 2 * 1300 = 2600 answer b | other |
math_qa__QwcXf6gtuptOuBZz | In a particular state, 60% of the counties received some rain on Monday, and 55% of the counties received some rain on Tuesday. No rain fell either day in 25% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday? Choose the correct choice from the following:
A) 12.5 % B) 40 % C) 50 % D) 60 % E) 67.5 % | <gadget id="calculator">60 + 55</gadget>
<output>115</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">115 - 75</gadget>
<output>40</output>
<result>B</result> | B | 40 | In a particular state, 60% of the counties received some rain on Monday, and 55% of the counties received some rain on Tuesday. No rain fell either day in 25% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday? | {
"A": "12.5 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "67.5 %"
} | subtract(add(60, 55), subtract(const_100, 25)) | add(n0,n1)|subtract(const_100,n2)|subtract(#0,#1)| | "60 + 55 + 25 = 140 % the number is 40 % above 100 % because 40 % of the counties were counted twice . the answer is b ." | gain |
math_qa__m5akEOoJvDobJV5n | Triathlete Dan runs along a 2-mile stretch of river and then swims back along the same route. If Dan runs at a rate of 10 miles per hour and swims at a rate of 5 miles per hour, what is his average rate for the entire trip in miles per minute?
Options
A) 1 / 9
B) 2 / 15
C) 3 / 15
D) 1 / 4
E) 3 / 8 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 60</gadget>
<output>24</output>
<gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 60</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">4 / 36</gadget>
<output>1/9 = around 0.111111</output>
<result>A</result> | A | 0.111111 | Triathlete Dan runs along a 2-mile stretch of river and then swims back along the same route. If Dan runs at a rate of 10 miles per hour and swims at a rate of 5 miles per hour, what is his average rate for the entire trip in miles per minute? | {
"A": "1 / 9",
"B": "2 / 15",
"C": "3 / 15",
"D": "1 / 4",
"E": "3 / 8"
} | divide(add(2, 2), add(multiply(divide(2, 5), const_60), multiply(divide(2, 10), const_60))) | add(n0,n0)|divide(n0,n2)|divide(n0,n1)|multiply(#1,const_60)|multiply(#2,const_60)|add(#3,#4)|divide(#0,#5) | dan travels 4 miles round trip . running part : ( 2 / 10 = 1 / 5 * 60 = 12 minutes ) swimming part : ( 2 / 5 = 2 / 5 * 60 = 24 minutes ) 4 miles in ( 12 + 24 ) minutes 4 / 36 = 1 / 9 mile per minute answer : 1 / 9 mile per minute | physics |
math_qa__PxZVnnZoXYw5805e | What is the smallest number which when increased by 3 is divisible by 12, 15, 35, and 40? Select the correct option
A) 837 B) 947 C) 1027 D) 1155 E) 1231 | <gadget id="calculator">lcm(12, 15)</gadget>
<output>60</output>
<gadget id="calculator">lcm(35, 40)</gadget>
<output>280</output>
<gadget id="calculator">lcm(60, 280)</gadget>
<output>840</output>
<gadget id="calculator">840 + 3</gadget>
<output>843</output>
<result>A</result> | A | 837 | What is the smallest number which when increased by 3 is divisible by 12, 15, 35, and 40? | {
"A": "837",
"B": "947",
"C": "1027",
"D": "1155",
"E": "1231"
} | add(lcm(lcm(12, 15), lcm(35, 40)), 3) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)| | "factor each of the numbers 8 , 15 , 35 , and 40 into primes : 12 = 2 * 2 * 3 ; 15 = 3 * 5 ; 35 = 5 * 7 ; 40 = 2 * 2 * 2 * 5 the smallest number divisible by all of them is thus 2 * 2 * 2 * 3 * 5 * 7 = 840 837 + 3 = 840 a" | general |
math_qa__nSptbTPT5pPC101E | On a race track a maximum of 5 horses can race together at a time. There are a total of 25 horses. There is no way of timing the races. What is the minimum number R of races we need to conduct to get the top 3 fastest horses?
Select the correct option.
A) 5 B) 7 C) 8 D) 10 E) 11 | <gadget id="calculator">25 / 5</gadget>
<output>5</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<result>B</result> | B | 7 | On a race track a maximum of 5 horses can race together at a time. There are a total of 25 horses. There is no way of timing the races. What is the minimum number R of races we need to conduct to get the top 3 fastest horses? | {
"A": "5",
"B": "7",
"C": "8",
"D": "10",
"E": "11"
} | add(divide(25, 5), const_2) | divide(n1,n0)|add(#0,const_2)| | "r = 7 is the correct answer . good solution buneul . b" | general |
math_qa__F6bQK6pqoQeY0cwP | If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/2 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? Select the correct option:
A) 1 / 4 B) 1 / 2 C) 10 / 3 D) 2 E) 4 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(2/5) * (1/2)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(2/5) + (1/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) / 2</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 / (3/10)</gadget>
<output>10/3 = around 3.333333</output>
<result>C</result> | C | 3.333333 | If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/2 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? | {
"A": "1 / 4",
"B": "1 / 2",
"C": "10 / 3",
"D": "2",
"E": "4"
} | divide(1, divide(add(divide(2, 5), multiply(divide(2, 5), divide(1, 2))), const_2)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)|add(#0,#2)|divide(#3,const_2)|divide(n2,#4)| | "n = 2 d / 5 j = n / 2 = d / 5 the average of november and january is ( n + j ) / 2 = 3 d / 5 / 2 = 3 d / 10 d is 10 / 3 times the average of november and january . the answer is c ." | general |
math_qa__5YPeiOBhMGV9Naph | 7 people average age is 30. youngest person age is 5. find average of the people when youngest was born.
Choose the correct choice from the following options: A) 23 B) 24 C) 25 D) 26 E) 27 | <gadget id="calculator">30 * 7</gadget>
<output>210</output>
<gadget id="calculator">5 * 7</gadget>
<output>35</output>
<gadget id="calculator">210 - 35</gadget>
<output>175</output>
<gadget id="calculator">175 / 7</gadget>
<output>25</output>
<result>C</result> | C | 25 | 7 people average age is 30. youngest person age is 5. find average of the people when youngest was born. | {
"A": "23",
"B": "24",
"C": "25",
"D": "26",
"E": "27"
} | divide(subtract(multiply(30, 7), multiply(5, 7)), 7) | multiply(n0,n1)|multiply(n0,n2)|subtract(#0,#1)|divide(#2,n0) | average age of people = 30 so have total age = 210 before 7 years we have to deduct each person age by seven years 210 - 35 = 161 so average age would be 175 / 7 = 25 answer : c | general |
math_qa__QbzpgJuSqGCmiAYh | Linda spent 3/5 of her savings on furniture and the rest on a TV. If the TV cost her $400, what were her original savings? Choose the correct choice from the following choices:
A) $ 900 B) $ 300 C) $ 600 D) $ 1000 E) $ 800 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">400 / (2/5)</gadget>
<output>1_000</output>
<result>D</result> | D | 1,000 | Linda spent 3/5 of her savings on furniture and the rest on a TV. If the TV cost her $400, what were her original savings? | {
"A": "$ 900",
"B": "$ 300",
"C": "$ 600",
"D": "$ 1000",
"E": "$ 800"
} | divide(400, subtract(const_1, divide(3, 5))) | divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1)| | "if linda spent 3 / 5 of her savings on furnitute , the rest 5 / 5 - 3 / 5 = 2 / 5 on a tv but the tv cost her $ 400 . so 2 / 5 of her savings is $ 400 . so her original savings are 5 / 2 times $ 400 = $ 2000 / 2 = $ 1000 correct answer d" | general |
math_qa__r7n1IQUzLeBkwONa | A man buys an item at Rs. 1300 and sells it at the loss of 20 percent. Then what is the selling price of that item Choose the correct choice from the following choices.
A) rs . 660 B) rs . 760 C) rs . 860 D) rs . 1040 E) none of these | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1_300 * (4/5)</gadget>
<output>1_040</output>
<result>D</result> | D | 1,040 | A man buys an item at Rs. 1300 and sells it at the loss of 20 percent. Then what is the selling price of that item | {
"A": "rs . 660",
"B": "rs . 760",
"C": "rs . 860",
"D": "rs . 1040",
"E": "none of these"
} | multiply(1300, subtract(const_1, divide(20, const_100))) | divide(n1,const_100)|subtract(const_1,#0)|multiply(n0,#1) | explanation : here always remember , when ever x % loss , it means s . p . = ( 100 - x ) % of c . p when ever x % profit , it means s . p . = ( 100 + x ) % of c . p so here will be ( 100 - x ) % of c . p . = 80 % of 1300 = 80 / 100 * 1300 = 1040 option d | gain |
math_qa__UBXKSzAUOjViIkHN | Two different primes may be said torhymearound an integer if they are the same distance from the integer on the number line. For instance, 3 and 7 rhyme around 5. What integer W between 1 and 20, inclusive, has the greatest number of distinct rhyming primes around it?
Select the correct option
A) 12 B) 15 C) 17 D) w = 18 E) 20 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<result>D</result> | D | 18 | Two different primes may be said torhymearound an integer if they are the same distance from the integer on the number line. For instance, 3 and 7 rhyme around 5. What integer W between 1 and 20, inclusive, has the greatest number of distinct rhyming primes around it? | {
"A": "12",
"B": "15",
"C": "17",
"D": "w = 18",
"E": "20"
} | multiply(multiply(3, const_2), 3) | multiply(const_2,n0)|multiply(n0,#0)| | "since we are concerned with integers w between 1 and 20 , write down the primes till 40 . 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 23 , 29 , 31 , 37 ( you should be very comfortable with the first few primes . . . ) 2 , 3 , 5 , 7 , 11,12 , 13 , 17 , 19 , 23 , 29 , 31 , 37 - three pairs ( 11,13 ) , ( 7,17 ) , ( 5 , 19 ) 2 , 3 , 5 , 7 , 11 , 13 , 15,17 , 19 , 23 , 29 , 31 , 37 - three pairs ( 13 , 17 ) , ( 11 , 19 ) , ( 7 , 23 ) 2 , 3 , 5 , 7 , 11 , 13,17 , 19 , 23 , 29 , 31 , 37 - three pairs ( 11 , 23 ) , ( 5 , 29 ) , ( 3 , 31 ) 2 , 3 , 5 , 7 , 11 , 13 , 17 , 18,19 , 23 , 29 , 31 , 37 - four pairs ( 17 , 19 ) , ( 13 , 23 ) , ( 7 , 29 ) , ( 5 , 31 ) 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 20,23 , 29 , 31 , 37 - definitely can not be more than 4 since there are only 4 primes more than 20 . so must be less than 4 pairs . ignore . answer ( d ) ." | physics |
math_qa__3YfM2d8JVPiT9rrv | A sum of money lent out at S.I. amounts to Rs. 850 after 2 years and to Rs. 1020 after a further period of 5 years. The sum is? Select the correct option.
A) s . 440 B) s . 500 C) s . 540 D) s . 782 E) s . 840 | <gadget id="calculator">1_020 - 850</gadget>
<output>170</output>
<gadget id="calculator">170 / 5</gadget>
<output>34</output>
<gadget id="calculator">34 * 2</gadget>
<output>68</output>
<gadget id="calculator">850 - 68</gadget>
<output>782</output>
<result>D</result> | D | 782 | A sum of money lent out at S.I. amounts to Rs. 850 after 2 years and to Rs. 1020 after a further period of 5 years. The sum is? | {
"A": "s . 440",
"B": "s . 500",
"C": "s . 540",
"D": "s . 782",
"E": "s . 840"
} | subtract(850, multiply(divide(subtract(1020, 850), 5), 2)) | subtract(n2,n0)|divide(#0,n3)|multiply(n1,#1)|subtract(n0,#2)| | "s . i for 5 years = ( 1020 - 850 ) = rs . 170 . s . i . for 2 years = 170 / 5 * 2 = rs . 68 . principal = ( 850 - 68 ) = rs . 782 . answer : d" | general |
math_qa__alpNbq1OzR2G3rCd | On dividing 15698 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor? Options.
A) 743
B) 154
C) 852
D) 176
E) 785 | <gadget id="calculator">15_698 - 14</gadget>
<output>15_684</output>
<gadget id="calculator">15_684 / 89</gadget>
<output>15_684/89 = around 176.224719</output>
<result>D</result> | D | 176 | On dividing 15698 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor? | {
"A": "743",
"B": "154",
"C": "852",
"D": "176",
"E": "785"
} | divide(subtract(15698, 14), 89) | subtract(n0,n2)|divide(#0,n1)| | "divisor * quotient + remainder = dividend divisor = ( dividend ) - ( remainder ) / quotient ( 15698 - 14 ) / 89 = 176 answer ( d )" | general |
math_qa__IsuI08wadaJBL1I5 | Income and expenditure of a person are in the ratio 4 : 3. If the income of the person is Rs. 20000, then find his savings? Choose one.
A) rs . 3600 B) rs . 3603 C) rs . 3639 D) rs . 3632 E) rs . 5000 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 20_000</gadget>
<output>15_000</output>
<gadget id="calculator">20_000 - 15_000</gadget>
<output>5_000</output>
<result>E</result> | E | 5,000 | Income and expenditure of a person are in the ratio 4 : 3. If the income of the person is Rs. 20000, then find his savings? | {
"A": "rs . 3600",
"B": "rs . 3603",
"C": "rs . 3639",
"D": "rs . 3632",
"E": "rs . 5000"
} | subtract(20000, multiply(divide(3, 4), 20000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | "let the income and the expenditure of the person be rs . 4 x and rs . 3 x respectively . income , 4 x = 20000 = > x = 5000 savings = income - expenditure = 4 x - 3 x = x so , savings = rs . 5000 answer : e" | other |
math_qa__jp0lLJzgOhezea4x | Given that 268x74= 19832, find the value of 2.68x.74. Choose the correct choice: A) 1.9832 B) 1.0025 C) 1.5693 D) 1.0266 E) none | <gadget id="calculator">268 / 100</gadget>
<output>67/25 = around 2.68</output>
<gadget id="calculator">74 / 100</gadget>
<output>37/50 = around 0.74</output>
<gadget id="calculator">(67/25) * (37/50)</gadget>
<output>2_479/1_250 = around 1.9832</output>
<result>A</result> | A | 1.9832 | Given that 268x74= 19832, find the value of 2.68x.74. | {
"A": "1.9832",
"B": "1.0025",
"C": "1.5693",
"D": "1.0266",
"E": "none"
} | multiply(divide(268, const_100), divide(74, const_100)) | divide(n0,const_100)|divide(n1,const_100)|multiply(#0,#1) | solution sum of decimals places = ( 2 + 2 ) = 4 . therefore , = 2.68 × . 74 = 1.9832 answer a | general |
math_qa__CzgOQp6UDCnglhko | the ratio of investments of two partners p and q is 7 : 5.00001 and the ratio of their profits is 7.00001 : 10 . if p invested the money for 5 months , find for how much time did q invest the money ? Pick one: A) 28 B) 10 C) 288 D) 277 E) 211 | <gadget id="calculator">7 / 5.00001</gadget>
<output>1.399997</output>
<gadget id="calculator">10 / 7.00001</gadget>
<output>1.428569</output>
<gadget id="calculator">1.399997 * 1.428569</gadget>
<output>1.999992</output>
<gadget id="calculator">1.999992 * 5</gadget>
<output>9.99996</output>
<result>B</result> | B | 10 | the ratio of investments of two partners p and q is 7 : 5.00001 and the ratio of their profits is 7.00001 : 10 . if p invested the money for 5 months , find for how much time did q invest the money ? | {
"A": "28",
"B": "10",
"C": "288",
"D": "277",
"E": "211"
} | multiply(multiply(divide(7, 5.00001), divide(10, 7.00001)), 5) | divide(n0,n1)|divide(n3,n2)|multiply(#0,#1)|multiply(n4,#2) | 7 * 5 : 5 * x = 7 : 10 x = 10 answer : b | gain |
math_qa__1mbktQ5pL6D6q91J | The speed of a boat in still water is 20 km/hr and the rate of current is 5 km/hr. The distance traveled downstream in 15 minutes is: Choose the correct choice from the following options:
A) 9.25 B) 5.25 C) 7.25 D) 6.25 E) 5.1 | <gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">(1/4) * 25</gadget>
<output>25/4 = around 6.25</output>
<result>D</result> | D | 6.25 | The speed of a boat in still water is 20 km/hr and the rate of current is 5 km/hr. The distance traveled downstream in 15 minutes is: | {
"A": "9.25",
"B": "5.25",
"C": "7.25",
"D": "6.25",
"E": "5.1"
} | multiply(divide(15, const_60), add(20, 5)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "explanation : speed downstream = ( 20 + 5 ) kmph = 25 kmph distance travelled = ( 25 * ( 15 / 60 ) ) km = 6.25 km . answer : d" | physics |
math_qa__sXQvshmNFhxLm7Jv | By selling 80 pens, a trader gains the cost of 20 pens. Find his gain percentage? Answers:
A) 25 %
B) 30 %
C) 35 %
D) 40 %
E) 50 % | <gadget id="calculator">20 / 80</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>A</result> | A | 25 | By selling 80 pens, a trader gains the cost of 20 pens. Find his gain percentage? | {
"A": "25 %",
"B": "30 %",
"C": "35 %",
"D": "40 %",
"E": "50 %"
} | multiply(divide(20, 80), const_100) | divide(n1,n0)|multiply(#0,const_100)| | "let the cp of each pen be rs . 1 . cp of 80 pens = rs . 80 profit = cost of 20 pens = rs . 20 profit % = 20 / 80 * 100 = 25 % answer : a" | gain |
math_qa__hjS3LjGlv1HahMoU | A salt manufacturing company produced a total of 1000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year? Choose the correct choice from the following choices
A) 1750
B) 2789
C) 2500
D) 1550
E) 2000 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">100 * 11</gadget>
<output>1_100</output>
<gadget id="calculator">1_000 + 1_100</gadget>
<output>2_100</output>
<gadget id="calculator">1_000 + 2_100</gadget>
<output>3_100</output>
<gadget id="calculator">3_100 * 12</gadget>
<output>37_200</output>
<gadget id="calculator">37_200 / 2</gadget>
<output>18_600</output>
<gadget id="calculator">18_600 / 12</gadget>
<output>1_550</output>
<result>D</result> | D | 1,550 | A salt manufacturing company produced a total of 1000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year? | {
"A": "1750",
"B": "2789",
"C": "2500",
"D": "1550",
"E": "2000"
} | divide(divide(multiply(add(1000, add(1000, multiply(100, add(const_10, const_1)))), const_12), const_2), const_12) | add(const_1,const_10)|multiply(n1,#0)|add(n0,#1)|add(n0,#2)|multiply(#3,const_12)|divide(#4,const_2)|divide(#5,const_12) | total production of salt by the company in that year = 1000 + 1100 + 1200 + . . . . + 2100 = 18600 . average monthly production of salt for that year = 18600 / 12 = 1550 . answer : d | general |
math_qa__OSfFbAmsDEGsvbkZ | A batsman in his 11th inning makes a score of 69 and their by increasing his average by 1. What is his average after the 11th inning? Options:
A) 58
B) 59
C) 68
D) 69
E) 78 | <gadget id="calculator">1 * 11</gadget>
<output>11</output>
<gadget id="calculator">69 - 11</gadget>
<output>58</output>
<gadget id="calculator">58 + 1</gadget>
<output>59</output>
<result>B</result> | B | 59 | A batsman in his 11th inning makes a score of 69 and their by increasing his average by 1. What is his average after the 11th inning? | {
"A": "58",
"B": "59",
"C": "68",
"D": "69",
"E": "78"
} | add(subtract(69, multiply(1, 11)), 1) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1)| | "10 x + 69 = 11 ( x + 1 ) x = 58 + 1 = 59 answer : b" | general |
math_qa__I0QTKlijlLGisdsG | John makes $40 a week from his job. He earns a raise andnow makes $55 a week. What is the % increase? Choose the correct option:
A) 15 %
B) 16.66 %
C) 17.8 %
D) 19 %
E) 37.5 % | <gadget id="calculator">55 - 40</gadget>
<output>15</output>
<gadget id="calculator">15 / 40</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(3/8) * 100</gadget>
<output>75/2 = around 37.5</output>
<result>E</result> | E | 37.5 | John makes $40 a week from his job. He earns a raise andnow makes $55 a week. What is the % increase? | {
"A": "15 %",
"B": "16.66 %",
"C": "17.8 %",
"D": "19 %",
"E": "37.5 %"
} | multiply(divide(subtract(55, 40), 40), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 15 / 40 ) * 100 = 37.5 % . e" | gain |
math_qa__mWJu0bNnJdlKqT6T | The list price of an article is Rs.70. A customer pays Rs.61.74 for it. He was given two successive discounts, one of them being 10%. The other discount is? Pick one
A) 8 %
B) 7 %
C) 10 %
D) 2 %
E) 4 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">70 * (1/10)</gadget>
<output>7</output>
<gadget id="calculator">70 - 7</gadget>
<output>63</output>
<gadget id="calculator">63 - 61.74</gadget>
<output>1.26</output>
<gadget id="calculator">1.26 / 63</gadget>
<output>0.02</output>
<gadget id="calculator">0.02 * 100</gadget>
<output>2</output>
<result>D</result> | D | 2 | The list price of an article is Rs.70. A customer pays Rs.61.74 for it. He was given two successive discounts, one of them being 10%. The other discount is? | {
"A": "8 %",
"B": "7 %",
"C": "10 %",
"D": "2 %",
"E": "4 %"
} | multiply(divide(subtract(subtract(70, multiply(70, divide(10, const_100))), 61.74), subtract(70, multiply(70, divide(10, const_100)))), const_100) | divide(n2,const_100)|multiply(n0,#0)|subtract(n0,#1)|subtract(#2,n1)|divide(#3,#2)|multiply(#4,const_100)| | "explanation : 70 * ( 90 / 100 ) * ( ( 100 - x ) / 100 ) = 61.74 x = 2 % option d" | gain |
math_qa__9GGVTOlGy0GEAtKz | What is the smallest integer b for which 27^b> 3^24? Choices:
A) 7
B) 8
C) 9
D) 10
E) 12 | <gadget id="calculator">24 / 3</gadget>
<output>8</output>
<gadget id="calculator">floor(8)</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<result>C</result> | C | 9 | What is the smallest integer b for which 27^b> 3^24? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "12"
} | add(floor(divide(24, const_3)), const_1) | divide(n2,const_3)|floor(#0)|add(#1,const_1)| | "27 ^ b > 3 ^ 24 converting into the same bases : 27 ^ b > 27 ^ 8 therefore for the equation to hold true , b > 8 or b = 9 option c" | general |
math_qa__HmJuuoWyaU8OuXz3 | A man was engaged on a job for 30 days on the condition that he would get a wage of Rs. 10 for the day he works, but he have to pay a fine of Rs. 2 for each day of his absence. If he gets Rs. 216 at the end, he was absent for work for ... days. Options
A) 7 days B) 5 days C) 3 days D) 4 days E) 8 days | <gadget id="calculator">30 * 10</gadget>
<output>300</output>
<gadget id="calculator">300 - 216</gadget>
<output>84</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">84 / 12</gadget>
<output>7</output>
<result>A</result> | A | 7 | A man was engaged on a job for 30 days on the condition that he would get a wage of Rs. 10 for the day he works, but he have to pay a fine of Rs. 2 for each day of his absence. If he gets Rs. 216 at the end, he was absent for work for ... days. | {
"A": "7 days",
"B": "5 days",
"C": "3 days",
"D": "4 days",
"E": "8 days"
} | divide(subtract(multiply(30, 10), 216), add(10, 2)) | add(n1,n2)|multiply(n0,n1)|subtract(#1,n3)|divide(#2,#0) | the equation portraying the given problem is : 10 * x – 2 * ( 30 – x ) = 216 where x is the number of working days . solving this we get x = 23 number of days he was absent was 7 ( 30 - 23 ) days . answer : a | physics |
math_qa__h4KdsjJR85gyc9lA | If 9^y = 3^16, what is y? Choose the correct choice from the following answers.
A) 2 B) 3 C) 4 D) 6 E) 8 | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>E</result> | E | 8 | If 9^y = 3^16, what is y? | {
"A": "2",
"B": "3",
"C": "4",
"D": "6",
"E": "8"
} | divide(16, const_2) | divide(n2,const_2)| | "9 ^ y = 3 ^ 2 y = 3 ^ 16 2 y = 16 y = 8 the answer is e ." | general |
math_qa__W2waHRLksoHkj8tw | the average age of 3 boys is 15 years and their ages are in proportion 3 : 5 : 7 . what is the age in years of the eldest boy ? Choose the most appropriate option.
A) 6 B) 9 C) 16 D) 4 E) 21 | <gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">45 / 15</gadget>
<output>3</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<result>E</result> | E | 21 | the average age of 3 boys is 15 years and their ages are in proportion 3 : 5 : 7 . what is the age in years of the eldest boy ? | {
"A": "6",
"B": "9",
"C": "16",
"D": "4",
"E": "21"
} | multiply(7, divide(multiply(15, 3), 15)) | multiply(n0,n1)|divide(#0,n1)|multiply(n4,#1) | 3 x + 5 x + 7 x = 45 x = 3 7 x = 21 answer : e | general |
math_qa__Ipv7ZftvYiCGCoUr | A certain manufacturer of cake, muffin, and bread mixes has 100 buyers, of whom 50 purchases cake mix, 40 purchase muffin mix, and 19 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix? Choose the correct choice from the following answers.
A) 1 / 10
B) 3 / 10
C) 1 / 2
D) 7 / 10
E) 29 / 100 | <gadget id="calculator">50 + 40</gadget>
<output>90</output>
<gadget id="calculator">90 - 19</gadget>
<output>71</output>
<gadget id="calculator">100 - 71</gadget>
<output>29</output>
<gadget id="calculator">29 / 100</gadget>
<output>29/100 = around 0.29</output>
<result>E</result> | E | 0.29 | A certain manufacturer of cake, muffin, and bread mixes has 100 buyers, of whom 50 purchases cake mix, 40 purchase muffin mix, and 19 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix? | {
"A": "1 / 10",
"B": "3 / 10",
"C": "1 / 2",
"D": "7 / 10",
"E": "29 / 100"
} | divide(subtract(100, subtract(add(50, 40), 19)), 100) | add(n1,n2)|subtract(#0,n3)|subtract(n0,#1)|divide(#2,n0)| | "c + m + b - cm - mb - cb - 2 cmb = 100 c - cake buyers , m - muffin and b - bread buyers . cm , mb , cb and cmb are intersecting regions . the question asks for people who have bought only bread mixes = b - cb - mb - 2 cmb has to be found out . 50 + 40 + b - cb - mb - 19 - 2 cmb = 100 b - cb - mb - 2 cmb = 29 hence the probability = 29 / 100 . e" | other |
math_qa__9FaOJd4PzT3M2h0f | A towel, when bleached, lost 30% of its length and 15% of its breadth. What is the percentage decrease in area? Choose one:
A) 24 % B) 40.5 % C) 44 % D) 54 % E) 64 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">70 * 85</gadget>
<output>5_950</output>
<gadget id="calculator">10_000 - 5_950</gadget>
<output>4_050</output>
<gadget id="calculator">4_050 / 100</gadget>
<output>81/2 = around 40.5</output>
<result>B</result> | B | 40.5 | A towel, when bleached, lost 30% of its length and 15% of its breadth. What is the percentage decrease in area? | {
"A": "24 %",
"B": "40.5 %",
"C": "44 %",
"D": "54 %",
"E": "64 %"
} | divide(subtract(multiply(const_100, const_100), multiply(subtract(const_100, 30), subtract(const_100, 15))), const_100) | multiply(const_100,const_100)|subtract(const_100,n0)|subtract(const_100,n1)|multiply(#1,#2)|subtract(#0,#3)|divide(#4,const_100)| | "percentage change in area = ( − 30 − 15 + ( 30 × 15 ) / 100 ) % = − 40.5 % i . e . , area is decreased by 40.5 % answer : b" | gain |
math_qa__3vvpFq7vTd6ydG6S | If A, B and C together can finish a piece of work in 4 days. A alone in 12 days and B in 24 days, then C alone can do it in? Choose the correct choice from the following choices:
A) 1
B) 7
C) 8
D) 9
E) 6 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/4) - (1/12)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/6) - (1/24)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<result>C</result> | C | 8 | If A, B and C together can finish a piece of work in 4 days. A alone in 12 days and B in 24 days, then C alone can do it in? | {
"A": "1",
"B": "7",
"C": "8",
"D": "9",
"E": "6"
} | divide(const_1, subtract(subtract(const_0_25, divide(const_1, 12)), divide(const_1, 24))) | divide(const_1,n1)|divide(const_1,n2)|subtract(const_0_25,#0)|subtract(#2,#1)|divide(const_1,#3) | c = 1 / 4 - 1 / 12 – 1 / 24 = 1 / 8 = > 8 days ' answer : c | physics |
math_qa__rOnYieGC6QYQFOKs | The average weight of 10 persons increases by 7.2 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? Select
A) 120 kg
B) 130 kg
C) 137 kg
D) 190 kg
E) none | <gadget id="calculator">10 * 7.2</gadget>
<output>72</output>
<gadget id="calculator">65 + 72</gadget>
<output>137</output>
<result>C</result> | C | 137 | The average weight of 10 persons increases by 7.2 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? | {
"A": "120 kg",
"B": "130 kg",
"C": "137 kg",
"D": "190 kg",
"E": "none"
} | add(65, multiply(10, 7.2)) | multiply(n0,n1)|add(n2,#0)| | "solution total weight increased = ( 10 x 7.2 ) kg = 72 kg . weight of new person = ( 65 + 72 ) kg = 137 kg . answer c" | general |
math_qa__qHwhKfruuf5wlrCX | A fold density is 19 times greater than the water and for copper it is 9 times. At what ratio you can mix gold
and copper to get 15 times denser than water. ? Choose the correct choice from the following options
A) 3 : 1 B) 3 : 2 C) 3 : 5 D) 3 : 8 E) 3 : 7 | <gadget id="calculator">15 - 9</gadget>
<output>6</output>
<gadget id="calculator">19 - 15</gadget>
<output>4</output>
<gadget id="calculator">6 / 4</gadget>
<output>3/2 = around 1.5</output>
<result>B</result> | B | 1.5 | A fold density is 19 times greater than the water and for copper it is 9 times. At what ratio you can mix gold
and copper to get 15 times denser than water. ? | {
"A": "3 : 1",
"B": "3 : 2",
"C": "3 : 5",
"D": "3 : 8",
"E": "3 : 7"
} | divide(subtract(15, 9), subtract(19, 15)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1) | suppose x units of gold are mixed with y units of copper to make ( x + y ) units of alloy which is 15 times denser than water . then 19 * x + 9 * y = 15 * ( x + y ) = > 19 * x - 15 * x = 15 * y - 9 * y = > 4 * x = 6 * y = > x / y = 3 / 2 so gold and copper should be mixed respectively in the ratio of 3 : 2 answer : b | general |
math_qa__qgkAE9wj8wX8LCVU | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 45, what is the total amount? Choose the correct option:
A) 115 B) 116 C) 195 D) 118 E) 119 | <gadget id="calculator">100 / 45</gadget>
<output>20/9 = around 2.222222</output>
<gadget id="calculator">(20/9) * 45</gadget>
<output>100</output>
<gadget id="calculator">50 / 45</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">(10/9) * 45</gadget>
<output>50</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">150 + 45</gadget>
<output>195</output>
<result>C</result> | C | 195 | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 45, what is the total amount? | {
"A": "115",
"B": "116",
"C": "195",
"D": "118",
"E": "119"
} | add(add(multiply(divide(const_100, 45), 45), multiply(divide(50, 45), 45)), 45) | divide(const_100,n0)|divide(n1,n0)|multiply(n2,#0)|multiply(n2,#1)|add(#2,#3)|add(n2,#4)| | "x : y : z = 100 : 45 : 50 20 : 9 : 10 9 - - - 45 39 - - - ? = > 195 answer : c" | general |
math_qa__14oFMSugI9iMp4iX | A jar contains a mixture of two liquids Acid( nitric acid) and Base(ammonium chloride) in the ratio 4 : 1. When 10 litres of the mixture is taken out and 10 litres of liquid Base is poured into the jar, the ratio becomes 2 : 3. How many litres of liquid Acid was contained in the jar?
Choose the correct answer:
A) 14 lts
B) 18 lts
C) 20 lts
D) 16 lts
E) 26 lts | <gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">20 * 4</gadget>
<output>80</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">80 / 5</gadget>
<output>16</output>
<result>D</result> | D | 16 | A jar contains a mixture of two liquids Acid( nitric acid) and Base(ammonium chloride) in the ratio 4 : 1. When 10 litres of the mixture is taken out and 10 litres of liquid Base is poured into the jar, the ratio becomes 2 : 3. How many litres of liquid Acid was contained in the jar? | {
"A": "14 lts",
"B": "18 lts",
"C": "20 lts",
"D": "16 lts",
"E": "26 lts"
} | divide(multiply(add(10, 10), 4), add(1, 4)) | add(n2,n2)|add(n0,n1)|multiply(n0,#0)|divide(#2,#1) | % age of liquid base in the original mixture = 1 / 5 x 100 = 20 % in the final mixture % of the liquid base = 3 / 5 x 100 = 60 % now using the rule of allegation hence reduced quantity of the first mixture and the quantity of mixture b which is to be added are the same . total mixture = 10 + 10 = 20 liters and quantity of liquid a = 20 / 5 x 4 = 16 lts answer : d | other |
math_qa__eBA7UAIvfLmIBTpX | If x+y=4, x-y=36, for integers of x and y, x=? Choices.
A) 20 B) 15 C) 25 D) 13 E) 42 | <gadget id="calculator">4 + 36</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<result>A</result> | A | 20 | If x+y=4, x-y=36, for integers of x and y, x=? | {
"A": "20",
"B": "15",
"C": "25",
"D": "13",
"E": "42"
} | divide(add(4, 36), const_2) | add(n0,n1)|divide(#0,const_2)| | "x + y = 4 x - y = 36 2 x = 40 x = 20 answer is a" | general |
math_qa__IIj1duSU6Ism6bt4 | A certain bus driver is paid a regular rate of $16 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $864 in total compensation, how many total hours did he work that week? Select
A) 36
B) 40
C) 44
D) 48
E) 52 | <gadget id="calculator">16 * 40</gadget>
<output>640</output>
<gadget id="calculator">864 - 640</gadget>
<output>224</output>
<gadget id="calculator">100 + 75</gadget>
<output>175</output>
<gadget id="calculator">16 * 175</gadget>
<output>2_800</output>
<gadget id="calculator">2_800 / 100</gadget>
<output>28</output>
<gadget id="calculator">224 / 28</gadget>
<output>8</output>
<gadget id="calculator">40 + 8</gadget>
<output>48</output>
<result>D</result> | D | 48 | A certain bus driver is paid a regular rate of $16 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $864 in total compensation, how many total hours did he work that week? | {
"A": "36",
"B": "40",
"C": "44",
"D": "48",
"E": "52"
} | add(40, divide(subtract(864, multiply(16, 40)), divide(multiply(16, add(const_100, 75)), const_100))) | add(n3,const_100)|multiply(n0,n1)|multiply(n0,#0)|subtract(n4,#1)|divide(#2,const_100)|divide(#3,#4)|add(n1,#5)| | "for 40 hrs = 40 * 16 = 640 excess = 864 - 640 = 224 for extra hours = . 75 ( 16 ) = 12 + 16 = 28 number of extra hrs = 224 / 28 = 56 / 7 = 8 total hrs = 40 + 8 = 48 answer d 48" | general |
math_qa__pv1WWqSzdf0gurAX | Praveen starts business with Rs.3500 and after 5 months, Hari joins with Praveen as his partner. After a year, the profit is divided in the ratio 2 : 3. What is Hari’s contribution in the capital? Answers.
A) rs . 7500
B) rs . 8000
C) rs . 8500
D) rs . 9000
E) rs . 6000 | <gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">1 - (5/12)</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">3_500 / (7/12)</gadget>
<output>6_000</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">6_000 / (2/3)</gadget>
<output>9_000</output>
<result>D</result> | D | 9,000 | Praveen starts business with Rs.3500 and after 5 months, Hari joins with Praveen as his partner. After a year, the profit is divided in the ratio 2 : 3. What is Hari’s contribution in the capital? | {
"A": "rs . 7500",
"B": "rs . 8000",
"C": "rs . 8500",
"D": "rs . 9000",
"E": "rs . 6000"
} | divide(divide(3500, subtract(const_1, divide(5, const_12))), divide(2, 3)) | divide(n1,const_12)|divide(n2,n3)|subtract(const_1,#0)|divide(n0,#2)|divide(#3,#1)| | "let hari ’ s capital be rs . x . then , 3500 * 12 / 7 x = 2 / 3 = > 14 x = 126000 = > x = 9000 . answer : d" | other |
math_qa__mMV41a5YXeuYNxCg | Harkamal purchased 8kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 50 per kg. How much amount did he pay to the shopkeeper? Pick one
A) 1000 B) 1010 C) 1065 D) 1075 E) 1080 | <gadget id="calculator">8 * 70</gadget>
<output>560</output>
<gadget id="calculator">9 * 50</gadget>
<output>450</output>
<gadget id="calculator">560 + 450</gadget>
<output>1_010</output>
<result>B</result> | B | 1,010 | Harkamal purchased 8kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 50 per kg. How much amount did he pay to the shopkeeper? | {
"A": "1000",
"B": "1010",
"C": "1065",
"D": "1075",
"E": "1080"
} | add(multiply(8, 70), multiply(9, 50)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "cost of 8 kg grapes = 70 × 8 = 560 . cost of 9 kg of mangoes = 50 × 9 = 450 . total cost he has to pay = 560 + 450 = 1010 . b )" | gain |
math_qa__X9BdmM05A0WxIAhl | In a group of 250 readers who read science fiction or literacy works or both, 180 read science fiction and 88 read literacy works. How many read both science fiction and literacy works? Choose the correct choice from the following options: A) 268 B) 180 C) 150 D) 18 E) 88 | <gadget id="calculator">180 + 88</gadget>
<output>268</output>
<gadget id="calculator">268 - 250</gadget>
<output>18</output>
<result>D</result> | D | 18 | In a group of 250 readers who read science fiction or literacy works or both, 180 read science fiction and 88 read literacy works. How many read both science fiction and literacy works? | {
"A": "268",
"B": "180",
"C": "150",
"D": "18",
"E": "88"
} | subtract(add(180, 88), 250) | add(n1,n2)|subtract(#0,n0)| | "consider total number of reader n ( s u l ) = 250 people who read science fiction n ( s ) = 180 people who read literacy works n ( l ) = 88 both science fiction and literacy n ( s â ˆ © l ) = ? n ( s u l ) = n ( s ) + n ( l ) - n ( s â ˆ © l ) 250 = 180 + 88 - n ( s â ˆ © l ) n ( s â ˆ © l ) = 268 - 250 n ( s â ˆ © l ) = 18 so people read both science fiction and literacy works are 18 answer : d" | other |
math_qa__WmU2ZrfXJcRLMB57 | In a certain circle there are 10 points. What is the number of the triangles connecting 5 points of the 10 points? Pick:
A) 80 B) 96 C) 108 D) 120 E) 252 | <gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">120 * 120</gadget>
<output>14_400</output>
<gadget id="calculator">3_628_800 / 14_400</gadget>
<output>252</output>
<result>E</result> | E | 252 | In a certain circle there are 10 points. What is the number of the triangles connecting 5 points of the 10 points? | {
"A": "80",
"B": "96",
"C": "108",
"D": "120",
"E": "252"
} | divide(factorial(10), multiply(factorial(divide(const_10, const_2)), factorial(5))) | divide(const_10,const_2)|factorial(n0)|factorial(n1)|factorial(#0)|multiply(#3,#2)|divide(#1,#4)| | "imo : e here we have to select 5 points out of 10 points . order is not important so the answer will be 10 c 5 = 252 answer e" | geometry |
math_qa__Q0Uu3aqGw26Eiily | Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 14 percent alcohol by volume? Choose the correct choice from the following options.
A) 50
B) 100
C) 150
D) 200
E) 250 | <gadget id="calculator">14 - 10</gadget>
<output>4</output>
<gadget id="calculator">30 - 14</gadget>
<output>16</output>
<gadget id="calculator">4 / 16</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 200</gadget>
<output>50</output>
<result>A</result> | A | 50 | Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 14 percent alcohol by volume? | {
"A": "50",
"B": "100",
"C": "150",
"D": "200",
"E": "250"
} | multiply(divide(subtract(14, 10), subtract(30, 14)), 200) | subtract(n3,n0)|subtract(n1,n3)|divide(#0,#1)|multiply(n2,#2)| | "14 % is 4 % - points higher than 10 % but 16 % - points lower than 30 % . thus there should be 4 parts of solution x for 1 part of solution y . we should add 50 ml of solution y . the answer is a ." | general |
math_qa__axYkWKsqbv6DnOR0 | Patrick purchased 80 pencils and sold them at a loss equal to the selling price of 16 pencils. The cost of 80 pencils is how many times the selling price of 80 pencils?
Choose the correct answer.
A) 0.75 B) 1.2 C) 1.8 D) 2.4 E) 4.25 | <gadget id="calculator">80 + 16</gadget>
<output>96</output>
<gadget id="calculator">80 / 96</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">1 / (5/6)</gadget>
<output>6/5 = around 1.2</output>
<result>B</result> | B | 1.2 | Patrick purchased 80 pencils and sold them at a loss equal to the selling price of 16 pencils. The cost of 80 pencils is how many times the selling price of 80 pencils? | {
"A": "0.75",
"B": "1.2",
"C": "1.8",
"D": "2.4",
"E": "4.25"
} | inverse(divide(80, add(80, 16))) | add(n0,n1)|divide(n0,#0)|inverse(#1)| | "say the cost price of 80 pencils was $ 80 ( $ 1 per pencil ) and the selling price of 1 pencil was p . selling at a loss : 80 - 80 p = 16 p - - > p = 5 / 6 . ( cost price ) / ( selling price ) = 1 / ( 5 / 6 ) = 6 / 5 = 1.2 . answer : b ." | general |
math_qa__SaluTM9esbvGrgfw | if 6 women take an hour to dig a ditch, then how long should 18 women take a dig to ditch of the same type? Choose the correct choice from the following answers.
A) 25 min B) 20 min C) 28 min D) 15 min E) 10 min | <gadget id="calculator">18 / 6</gadget>
<output>3</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<result>B</result> | B | 20 | if 6 women take an hour to dig a ditch, then how long should 18 women take a dig to ditch of the same type? | {
"A": "25 min",
"B": "20 min",
"C": "28 min",
"D": "15 min",
"E": "10 min"
} | divide(const_60, divide(18, 6)) | divide(n1,n0)|divide(const_60,#0) | if 6 women take an hour to dig a ditch , then 18 men will take 6 * 60 / 18 = 20 mins to dig a ditch of the same type . answer : b | physics |
math_qa__ppHgIcXiAf6JDfIT | If the price of a book is first decreased by 50% and then increased by 60%, then the net change in the price will be? Choose the correct option:
A) 20 % decrease
B) 10 % increase
C) 10 % decrease
D) 15 % increase
E) 25 % decrease | <gadget id="calculator">100 * 50</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 / 100</gadget>
<output>50</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">100 * 60</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 100</gadget>
<output>60</output>
<gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">160 / 100</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(1/2) * (8/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<gadget id="calculator">100 - 80</gadget>
<output>20</output>
<result>A</result> | A | 20 | If the price of a book is first decreased by 50% and then increased by 60%, then the net change in the price will be? | {
"A": "20 % decrease",
"B": "10 % increase",
"C": "10 % decrease",
"D": "15 % increase",
"E": "25 % decrease"
} | subtract(const_100, multiply(multiply(divide(subtract(const_100, divide(multiply(const_100, 50), const_100)), const_100), divide(add(const_100, divide(multiply(const_100, 60), const_100)), const_100)), const_100)) | multiply(n0,const_100)|multiply(n1,const_100)|divide(#0,const_100)|divide(#1,const_100)|add(#3,const_100)|subtract(const_100,#2)|divide(#5,const_100)|divide(#4,const_100)|multiply(#6,#7)|multiply(#8,const_100)|subtract(const_100,#9)| | "let the original price be $ 100 new final price = 160 % of ( 50 % of $ 100 ) = 160 / 100 * 50 / 100 * 100 = $ 80 decrease is 20 % answer is a" | general |
math_qa__3gQeZCNFhNFn6RUU | A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability Q that all 3 jellybeans removed from the bag are blue? Select:
A) 9 / 100 B) 2 / 19 C) 1 / 8 D) 3 / 20 E) 3 / 10 | <gadget id="calculator">binomial(10, 3)</gadget>
<output>120</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">binomial(20, 3)</gadget>
<output>1_140</output>
<gadget id="calculator">120 / 1_140</gadget>
<output>2/19 = around 0.105263</output>
<result>B</result> | B | 0.105263 | A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability Q that all 3 jellybeans removed from the bag are blue? | {
"A": "9 / 100",
"B": "2 / 19",
"C": "1 / 8",
"D": "3 / 20",
"E": "3 / 10"
} | divide(choose(10, 3), choose(add(10, 10), 3)) | add(n0,n0)|choose(n0,n2)|choose(#0,n2)|divide(#1,#2)| | "method - 1 10 red jellybeans and 10 blue jellybeans total outcomes = no . of ways to choose 3 jelly bean at random out of a total 20 jellybeans = 20 c 3 = 1140 favourable outcomes = no . of ways to choose 3 jelly bean such that they are all blue out of 10 blue = 10 c 3 = 120 probability = favourable outcomes / total outcomes = 10 c 3 / 20 c 3 probability q = 120 / 1140 = 2 / 19 answer : option b method - 2 probability of first jelly bean to be blue = 10 / 20 [ total 10 blue out of total 20 jellybeans ] probability of second jelly bean to be blue = 9 / 19 [ total 9 blue remaining out of total 19 jellybeans remaining ] probability of third jelly bean to be blue = 8 / 18 [ total 8 blue remaining out of total 18 jellybeans remaining ] required probability = ( 10 / 20 ) * ( 9 / 19 ) * ( 8 / 18 ) = 2 / 19 answer : option b" | probability |
math_qa__zTXQ2rtDteHKx4oU | Find the value of x from this equation? 7(x - 1) = 21
Choose the correct choice from the following
A) 2 B) 4 C) 6 D) 8 E) 10 | <gadget id="calculator">21 / 7</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<result>B</result> | B | 4 | Find the value of x from this equation? 7(x - 1) = 21 | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | add(divide(21, 7), 1) | divide(n2,n0)|add(n1,#0) | 1 . divide both sides by 7 : 2 . simplify both sides : x - 1 = 3 3 . add 1 to both sides : x - 1 + 1 = 3 + 1 4 . simplify both sides : x = 4 b | general |
math_qa__4810nBRUM0dfNjNq | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 27, what is the total amount? Choose the correct choice from the following answers.
A) 388
B) 105
C) 288
D) 266
E) 281 | <gadget id="calculator">100 / 45</gadget>
<output>20/9 = around 2.222222</output>
<gadget id="calculator">(20/9) * 27</gadget>
<output>60</output>
<gadget id="calculator">30 / 45</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 27</gadget>
<output>18</output>
<gadget id="calculator">60 + 18</gadget>
<output>78</output>
<gadget id="calculator">78 + 27</gadget>
<output>105</output>
<result>B</result> | B | 105 | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 27, what is the total amount? | {
"A": "388",
"B": "105",
"C": "288",
"D": "266",
"E": "281"
} | add(add(multiply(divide(const_100, 45), 27), multiply(divide(30, 45), 27)), 27) | divide(const_100,n0)|divide(n1,n0)|multiply(n2,#0)|multiply(n2,#1)|add(#2,#3)|add(n2,#4) | x : y : z = 100 : 45 : 30 20 : 9 : 6 9 - - - 27 35 - - - ? = > 105 answer : b | general |
math_qa__TXHeSoZv4jrnvbF1 | There are 28 stations between Kolkatta and Chennai. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station?
Choose the correct choice from the following options: A) 870 B) 970 C) 1070 D) 1000 E) 800 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 * 28</gadget>
<output>840</output>
<result>A</result> | A | 870 | There are 28 stations between Kolkatta and Chennai. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station? | {
"A": "870",
"B": "970",
"C": "1070",
"D": "1000",
"E": "800"
} | multiply(multiply(const_3, const_10), 28) | multiply(const_10,const_3)|multiply(n0,#0) | the total number of stations = 30 from 30 stations we have to choose any two stations and the direction of travel ( i . e . , kolkatta to chennai is different from chennai to kolkatta ) in 30 p 2 ways . 30 p 2 = 30 * 29 = 870 answer : a | physics |
math_qa__3lrsCMcrKbkOyaob | A contractor is engaged for 30days on the condition that he receives Rs.25 for each day he works &is fined Rs.7.50 for each day is absent. He gets Rs.490 in all. For how many days was he absent?
Choose the correct option
A) 8
B) 10
C) 15
D) 17
E) 19 | <gadget id="calculator">30 * 7.5</gadget>
<output>225</output>
<gadget id="calculator">225 + 490</gadget>
<output>715</output>
<gadget id="calculator">25 + 7.5</gadget>
<output>32.5</output>
<gadget id="calculator">715 / 32.5</gadget>
<output>22</output>
<gadget id="calculator">30 - 22</gadget>
<output>8</output>
<result>A</result> | A | 8 | A contractor is engaged for 30days on the condition that he receives Rs.25 for each day he works &is fined Rs.7.50 for each day is absent. He gets Rs.490 in all. For how many days was he absent? | {
"A": "8",
"B": "10",
"C": "15",
"D": "17",
"E": "19"
} | subtract(30, divide(add(multiply(30, 7.5), 490), add(25, 7.5))) | add(n1,n2)|multiply(n0,n2)|add(n3,#1)|divide(#2,#0)|subtract(n0,#3) | 30 * 25 = 750 490 - - - - - - - - - - - 260 25 + 7.50 = 32.5 260 / 32.5 = 8 a | physics |
math_qa__gvEM9CIu6MoZOaLX | What is the area of a rectangle whose length is twice its width and whose perimeter is equal to that of a square whose area is 1? Choose the correct choice from the following answers:
A) 1 / 9 sq units . B) 4 / 9 sq units . C) 8 / 9 sq units . D) 7 / 9 sq units . E) 6 / 9 sq units . | <gadget id="calculator">1 * 4</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 2</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(2/3) * (4/3)</gadget>
<output>8/9 = around 0.888889</output>
<result>C</result> | C | 0.888889 | What is the area of a rectangle whose length is twice its width and whose perimeter is equal to that of a square whose area is 1? | {
"A": "1 / 9 sq units .",
"B": "4 / 9 sq units .",
"C": "8 / 9 sq units .",
"D": "7 / 9 sq units .",
"E": "6 / 9 sq units ."
} | rectangle_area(divide(divide(multiply(1, const_4), const_2), const_3), multiply(divide(divide(multiply(1, const_4), const_2), const_3), const_2)) | multiply(n0,const_4)|divide(#0,const_2)|divide(#1,const_3)|multiply(#2,const_2)|rectangle_area(#2,#3) | area will be 2 / 3 * 4 / 3 = 8 / 9 sq units . answer : c | geometry |
math_qa__yTuPz3GWBJmRsnQ7 | Albert is 2 times Mary’s age and 4 times as old as Betty. Mary is 10 years younger than Albert. How old is Betty?
Choose the correct choice from the following answers:
A) 5 B) 8 C) 10 D) 12 E) 15 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<result>A</result> | A | 5 | Albert is 2 times Mary’s age and 4 times as old as Betty. Mary is 10 years younger than Albert. How old is Betty? | {
"A": "5",
"B": "8",
"C": "10",
"D": "12",
"E": "15"
} | divide(multiply(2, 10), 4) | multiply(n0,n2)|divide(#0,n1)| | "a = 2 m = m + 10 m = 10 a = 20 a = 4 b , and so b = 5 the answer is a ." | general |
math_qa__JQnZv7y9HuY4xClI | a worker is paid rs . 20 / - for a full days work . he works 11 / 32 / 31 / 8.3 / 4 days in a week . what is the total amount paid for that worker ? Pick
A) 56.5 rupees B) 58.5 rupees C) 57.5 rupees D) 59.5 rupees E) 55.5 rupees | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 + (1/3)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(4/3) + (2/3)</gadget>
<output>2</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">2 + (1/8)</gadget>
<output>17/8 = around 2.125</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(17/8) + (3/4)</gadget>
<output>23/8 = around 2.875</output>
<gadget id="calculator">(23/8) * 20</gadget>
<output>115/2 = around 57.5</output>
<result>C</result> | C | 57.5 | a worker is paid rs . 20 / - for a full days work . he works 11 / 32 / 31 / 8.3 / 4 days in a week . what is the total amount paid for that worker ? | {
"A": "56.5 rupees",
"B": "58.5 rupees",
"C": "57.5 rupees",
"D": "59.5 rupees",
"E": "55.5 rupees"
} | multiply(add(add(add(add(const_1, divide(const_1, const_3)), divide(const_2, const_3)), divide(const_1, multiply(const_2, const_4))), divide(const_3, 4)), 20) | divide(const_1,const_3)|divide(const_2,const_3)|divide(const_3,n5)|multiply(const_2,const_4)|add(#0,const_1)|divide(const_1,#3)|add(#4,#1)|add(#6,#5)|add(#7,#2)|multiply(n0,#8) | the total days worked = 1 + 0.333 + 0.667 + 0.125 + 0.75 = 2.875 days amount for 2.875 days is ( 2.875 * 20 ) 57.5 rupees answer : c | general |
math_qa__12Vtv2A3iIArSmyO | Find a number such that when 15 is subtracted from 7 times the number, the results is more than twice the number?
Answers:
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">25 / 5</gadget>
<output>5</output>
<result>D</result> | D | 5 | Find a number such that when 15 is subtracted from 7 times the number, the results is more than twice the number? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(add(15, const_10), subtract(7, const_2)) | add(n0,const_10)|subtract(n1,const_2)|divide(#0,#1) | solution let the number be x . = then , 7 x - 15 = 2 x + 10 = 5 x = 25 ‹ = › x = 5 . hence the required number is 5 . answer d | general |
math_qa__MYQrzpO3BkVLRsEn | Having received his weekly allowance, a student spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $1.00 at the candy store. What is this student’s weekly allowance? Choose the correct choice from the following: A) $ 2.75 B) $ 3.25 C) $ 3.75 D) $ 4.25 E) $ 4.75 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 * 1</gadget>
<output>15</output>
<gadget id="calculator">15 / 4</gadget>
<output>15/4 = around 3.75</output>
<result>C</result> | C | 3.75 | Having received his weekly allowance, a student spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $1.00 at the candy store. What is this student’s weekly allowance? | {
"A": "$ 2.75",
"B": "$ 3.25",
"C": "$ 3.75",
"D": "$ 4.25",
"E": "$ 4.75"
} | divide(multiply(multiply(3, 5), 1.00), const_4) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_4)| | "let x be the value of the weekly allowance . ( 2 / 3 ) ( 2 / 5 ) x = 100 cents ( 4 / 15 ) x = 100 x = $ 3.75 the answer is c ." | general |
math_qa__1t8aKODdmWUNrOUJ | If 2|2 –e| = 5, what is the sum of all the possible values for e ?
Choose the correct answer.
A) 1 / 2 B) 2 C) 5 / 2 D) 4 E) 5 | <gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">2 - (5/2)</gadget>
<output>-1/2 = around -0.5</output>
<gadget id="calculator">(5/2) + 2</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(-1/2) + (9/2)</gadget>
<output>4</output>
<result>D</result> | D | 4 | If 2|2 –e| = 5, what is the sum of all the possible values for e ? | {
"A": "1 / 2",
"B": "2",
"C": "5 / 2",
"D": "4",
"E": "5"
} | add(subtract(2, divide(5, 2)), add(divide(5, 2), 2)) | divide(n2,n0)|add(n0,#0)|subtract(n0,#0)|add(#1,#2) | if e < 2 , then 2 - e = 5 / 2 ; e = - 1 / 2 if e > 2 , then e - 2 = 5 / 2 ; e = 9 / 2 9 / 2 - 1 / 2 = 8 / 2 = 4 = d | general |
math_qa__NPN66R7pugZBVwsJ | The market value of a certain machine decreased by 10 percent of its purchase price each year. If the machine was purchased in 1982 for its market value of $8,000, what was its market value two years later?
Choose the correct choice from the following:
A) $ 8,000 B) $ 5,600 C) $ 3,200 D) $ 6,400 E) $ 800 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">1_000 * 8</gadget>
<output>8_000</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 2</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">8_000 * (1/5)</gadget>
<output>1_600</output>
<gadget id="calculator">8_000 - 1_600</gadget>
<output>6_400</output>
<result>D</result> | D | 6,400 | The market value of a certain machine decreased by 10 percent of its purchase price each year. If the machine was purchased in 1982 for its market value of $8,000, what was its market value two years later? | {
"A": "$ 8,000",
"B": "$ 5,600",
"C": "$ 3,200",
"D": "$ 6,400",
"E": "$ 800"
} | subtract(multiply(multiply(const_100, const_10), multiply(const_2, const_4)), multiply(multiply(multiply(const_100, const_10), multiply(const_2, const_4)), multiply(divide(10, const_100), const_2))) | divide(n0,const_100)|multiply(const_10,const_100)|multiply(const_2,const_4)|multiply(#1,#2)|multiply(#0,const_2)|multiply(#3,#4)|subtract(#3,#5) | d market value in 1982 = $ 8000 market value in 1983 = $ 8000 - ( $ 8000 x 10 / 100 ) = 8000 - 800 = $ 7200 market value in 1984 = market value in 1983 - ( 10 % of $ 8000 ) = 7200 - 800 = $ 6400 | gain |
math_qa__9VzekqGs4dSf6VM2 | Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $5 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discounts rates is 18 percent, what is the discount rate on Pony jeans? Choices
A) 9 % B) 10 % C) 34.4 % D) 12 % E) 15 % | <gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">(9/50) * 36</gadget>
<output>162/25 = around 6.48</output>
<gadget id="calculator">5 - (162/25)</gadget>
<output>-37/25 = around -1.48</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">45 - 36</gadget>
<output>9</output>
<gadget id="calculator">(-37/25) / 9</gadget>
<output>-37/225 = around -0.164444</output>
<gadget id="calculator">(9/50) - (-37/225)</gadget>
<output>31/90 = around 0.344444</output>
<gadget id="calculator">(31/90) * 100</gadget>
<output>310/9 = around 34.444444</output>
<result>C</result> | C | 34.4 | Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $5 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discounts rates is 18 percent, what is the discount rate on Pony jeans? | {
"A": "9 %",
"B": "10 %",
"C": "34.4 %",
"D": "12 %",
"E": "15 %"
} | multiply(subtract(divide(18, const_100), divide(subtract(5, multiply(divide(18, const_100), multiply(18, 2))), subtract(multiply(15, 3), multiply(18, 2)))), const_100) | divide(n6,const_100)|multiply(n1,n5)|multiply(n0,n4)|multiply(#0,#1)|subtract(#2,#1)|subtract(n2,#3)|divide(#5,#4)|subtract(#0,#6)|multiply(#7,const_100)| | "you know that fox jeans costs $ 15 , and pony jeans costs $ 18 , you also know that 3 pairs of fox jeans and 2 pairs of pony jeans were purchased . so 3 ( 15 ) = 45 - fox 2 ( 18 ) = 36 - pony the total discount discount is $ 5 and you are asked to find the percent discount of pony jeans , so 45 ( 18 - x ) / 100 + 36 ( x ) / 100 = 5 or 45 * 18 - 45 * x + 36 * x = 5 * 100 or 9 x = - 5 * 100 + 45 * 18 x = 310 / 9 = 34.4 c" | gain |
math_qa__jLHUAX1SBYYJLeQp | If |y + 5| = 8, what is the sum of all the possible values of y? Select: A) - 14 B) - 13 C) - 8 D) - 12 E) - 10 | <gadget id="calculator">8 - 5</gadget>
<output>3</output>
<gadget id="calculator">-8</gadget>
<output>-8</output>
<gadget id="calculator">(-8) - 5</gadget>
<output>-13</output>
<gadget id="calculator">3 + (-13)</gadget>
<output>-10</output>
<result>E</result> | E | -10 | If |y + 5| = 8, what is the sum of all the possible values of y? | {
"A": "- 14",
"B": "- 13",
"C": "- 8",
"D": "- 12",
"E": "- 10"
} | add(subtract(8, 5), subtract(negate(8), 5)) | negate(n1)|subtract(n1,n0)|subtract(#0,n0)|add(#1,#2)| | "there will be two cases y + 5 = 8 or y + 5 = - 8 = > y = 3 or y = - 13 sum of both the values will be - 13 + 3 = - 10 answer : e" | general |
math_qa__jwgIGgyzxuFHWghF | Let n~ be defined for all positive integers n as the remainder when (n - 1)! is divided by n.
What is the value of 30~ ? Choose the correct option
A) 1 B) 0 C) 2 D) 8 E) 31 | <gadget id="calculator">30 - 1</gadget>
<output>29</output>
<gadget id="calculator">factorial(29)</gadget>
<output>8_841_761_993_739_701_954_543_616_000_000</output>
<gadget id="calculator">8_841_761_993_739_701_954_543_616_000_000 % 30</gadget>
<output>0</output>
<result>B</result> | B | 0 | Let n~ be defined for all positive integers n as the remainder when (n - 1)! is divided by n.
What is the value of 30~ ? | {
"A": "1",
"B": "0",
"C": "2",
"D": "8",
"E": "31"
} | reminder(factorial(subtract(30, 1)), 30) | subtract(n1,n0)|factorial(#0)|reminder(#1,n1) | n ~ = ( n - 1 ) ! so 30 ~ = ( 30 - 1 ) ! = 29 ! when 29 ! / 30 we have 16 * 2 inside 29 ! hence 30 gets cancelled and we get remainder as 0 b | general |
math_qa__ce9RHrQgtZAPFspp | A and B complete a work in 10 days. A alone can do it in 14 days. If both together can do the work in how many days? Choose the correct choice from the following answers:
A) 5.8 days B) 4.78 days C) 6.25 days D) 3.15 days E) 2.75 days | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 14</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">(1/10) + (1/14)</gadget>
<output>6/35 = around 0.171429</output>
<gadget id="calculator">1 / (6/35)</gadget>
<output>35/6 = around 5.833333</output>
<result>A</result> | A | 5.8 | A and B complete a work in 10 days. A alone can do it in 14 days. If both together can do the work in how many days? | {
"A": "5.8 days",
"B": "4.78 days",
"C": "6.25 days",
"D": "3.15 days",
"E": "2.75 days"
} | inverse(add(inverse(10), inverse(14))) | inverse(n0)|inverse(n1)|add(#0,#1)|inverse(#2) | 1 / 10 + 1 / 14 = 6 / 35 35 / 6 = 5.8 days answer : a | physics |
math_qa__YUYkx55bbhIEz85E | If Jake loses 33 pounds, he will weigh twice as much as his sister. Together they now weigh 153 pounds. What is Jake's present weight, in pounds?
Select the correct option.
A) 131 B) 135 C) 113 D) 147 E) 188 | <gadget id="calculator">153 - 33</gadget>
<output>120</output>
<gadget id="calculator">120 / 3</gadget>
<output>40</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">80 + 33</gadget>
<output>113</output>
<result>C</result> | C | 113 | If Jake loses 33 pounds, he will weigh twice as much as his sister. Together they now weigh 153 pounds. What is Jake's present weight, in pounds? | {
"A": "131",
"B": "135",
"C": "113",
"D": "147",
"E": "188"
} | add(multiply(divide(subtract(153, 33), const_3), const_2), 33) | subtract(n1,n0)|divide(#0,const_3)|multiply(#1,const_2)|add(n0,#2)| | "j = jake ’ s current weight , in pounds s = sister ’ s current weight , in pounds we are told that “ if jake loses 8 pounds , he will weigh twice as much as his sister . we put this into an equation : j – 33 = 2 s j = 2 s + 33 ( equation 1 ) next , we are told that “ together they now weigh 153 pounds . ” we can also put this into an equation . j + s = 153 ( equation 2 ) to solve this equation , we can substitute 2 s + 8 from equation 1 for the variable j in equation 2 : 2 s + 33 = 153 - s 3 s = 120 s = 40 j + 40 = 153 j = 113 answer : c" | general |
math_qa__e9cNm4ajnMG3bStF | The value of a machine depreciates at 24% per annum. If its present value is $1,50,000, at what price should it be sold after two years such that a profit of $24,000 is made? Options.
A) $ 250640 B) $ 430640 C) $ 120640 D) $ 110640 E) $ 150640 | <gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">1 - (6/25)</gadget>
<output>19/25 = around 0.76</output>
<gadget id="calculator">(19/25) * (19/25)</gadget>
<output>361/625 = around 0.5776</output>
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">10_000 * 10</gadget>
<output>100_000</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">500 * 100</gadget>
<output>50_000</output>
<gadget id="calculator">100_000 + 50_000</gadget>
<output>150_000</output>
<gadget id="calculator">(361/625) * 150_000</gadget>
<output>86_640</output>
<gadget id="calculator">24 + 2</gadget>
<output>26</output>
<gadget id="calculator">26 * 100</gadget>
<output>2_600</output>
<gadget id="calculator">2_600 * 10</gadget>
<output>26_000</output>
<gadget id="calculator">86_640 + 26_000</gadget>
<output>112_640</output>
<result>D</result> | D | 110,640 | The value of a machine depreciates at 24% per annum. If its present value is $1,50,000, at what price should it be sold after two years such that a profit of $24,000 is made? | {
"A": "$ 250640",
"B": "$ 430640",
"C": "$ 120640",
"D": "$ 110640",
"E": "$ 150640"
} | add(multiply(multiply(subtract(1, divide(24, const_100)), subtract(1, divide(24, const_100))), add(multiply(multiply(const_100, const_100), sqrt(const_100)), multiply(multiply(divide(sqrt(const_100), const_2), const_100), const_100))), multiply(multiply(add(24, const_2), const_100), sqrt(const_100))) | add(n0,const_2)|divide(n0,const_100)|multiply(const_100,const_100)|sqrt(const_100)|divide(#3,const_2)|multiply(#2,#3)|multiply(#0,const_100)|subtract(n1,#1)|multiply(#4,const_100)|multiply(#7,#7)|multiply(#6,#3)|multiply(#8,const_100)|add(#5,#11)|multiply(#12,#9)|add(#13,#10)| | "the value of the machine after two years = 0.76 * 0.76 * 1 , 50,000 = $ 86,640 sp such that a profit of $ 24,000 is made = 86,640 + 24,000 = $ 1 , 10,640 d" | gain |
math_qa__xyExbPFpHSFKAPvp | A vendor buys 10 t-shirts at an average price of $14 per t-shirt. He then buys 15 more t-shirts at an average price of $11 per t-shirt. What is the average price V per t-shirt that the vendor paid for these purchases? Choose the most appropriate option.
A) $ 12.20
B) $ 12.50
C) $ 12.55
D) $ 12.70
E) $ 13.00 | <gadget id="calculator">10 + 14</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + (1/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">12 + (1/2)</gadget>
<output>25/2 = around 12.5</output>
<result>A</result> | A | 12.2 | A vendor buys 10 t-shirts at an average price of $14 per t-shirt. He then buys 15 more t-shirts at an average price of $11 per t-shirt. What is the average price V per t-shirt that the vendor paid for these purchases? | {
"A": "$ 12.20",
"B": "$ 12.50",
"C": "$ 12.55",
"D": "$ 12.70",
"E": "$ 13.00"
} | add(divide(add(10, 14), const_2), add(const_0_25, const_0_25)) | add(const_0_25,const_0_25)|add(n0,n1)|divide(#1,const_2)|add(#0,#2)| | "correct answer : a explanation : the relevant formula for this problem is average v = ( sum ) / ( number of terms ) . another way to look at the formula is sum = average x number of terms . for the first purchase , the vendor ' s sum ( total cost ) was $ 140 , since 14 x 10 = 140 . for the second purchase , the vendor ' s cost was $ 165 , since 11 x 15 = 165 . the grand sum is then $ 140 + $ 165 , which equals $ 305 . the total number of shirts purchased was 25 , so to get the average price per shirt , we divide 305 by 25 , which equals $ 12.20 . as a result , the correct answer is a . note : a relative understanding of weighted average offers a shortcut to this problem . because the true average of 11 and 14 is 12.5 , but the vendor sells more shirts at the lower price than at the higher price , the weighted average must be less than $ 12.50 ; only answer choice a is a possibility ." | general |
math_qa__VgQWrTOXiZy5Bvb7 | If 5 machines can produce 20 units in 10 hours, how long would it take 20 machines to produce 120 units?
Choose the correct choice from the following choices
A) 50 hours B) 40 hours C) 15 hours D) 12 hours E) 8 hours | <gadget id="calculator">20 / 10</gadget>
<output>2</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 20</gadget>
<output>8</output>
<gadget id="calculator">120 / 8</gadget>
<output>15</output>
<result>C</result> | C | 15 | If 5 machines can produce 20 units in 10 hours, how long would it take 20 machines to produce 120 units? | {
"A": "50 hours",
"B": "40 hours",
"C": "15 hours",
"D": "12 hours",
"E": "8 hours"
} | divide(120, multiply(divide(divide(20, 10), 5), 20)) | divide(n1,n2)|divide(#0,n0)|multiply(n1,#1)|divide(n4,#2)| | "here , we ' re told that 5 machines can produce 20 units in 10 hours . . . . that means that each machine works for 10 hours apiece . since there are 5 machines ( and we ' re meant to assume that each machine does the same amount of work ) , then the 5 machines equally created the 20 units . 20 units / 5 machines = 4 units are made by each machine every 10 hours now that we know how long it takes each machine to make 4 units , we can break this down further if we choose to . . . 10 hours / 4 units = 2.5 hours per unit when 1 machine is working . the prompt asks us how long would it take 20 machines to produce 120 units . if 20 machines each work for 2.5 hours , then we ' ll have 20 units . since 120 units is ' 6 times ' 20 , we need ' 6 times ' more time . ( 2.5 hours ) ( 6 times ) = 15 hours final answer : [ reveal ] spoiler : c" | physics |
math_qa__AjgsyDMghGMnj1zw | 66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length if the wire in meters will be: Options.
A) 76 m B) 80 m C) 84 m D) 88 m E) none of these | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * pi</gadget>
<output>pi/4 = around 0.785398</output>
<gadget id="calculator">66 / (pi/4)</gadget>
<output>264/pi = around 84.03381</output>
<result>C</result> | C | 84 | 66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length if the wire in meters will be: | {
"A": "76 m",
"B": "80 m",
"C": "84 m",
"D": "88 m",
"E": "none of these"
} | divide(66, multiply(power(divide(1, const_2), const_2), const_pi)) | divide(n1,const_2)|power(#0,const_2)|multiply(#1,const_pi)|divide(n0,#2) | explanation : let the length of the wire be h radius = 1 / 2 mm = 120 cm π r 2 h = 66 22 / 7 ∗ 1 / 20 ∗ 1 / 20 ∗ h = 66 = > h = 66 ∗ 20 ∗ 20 ∗ 7 / 22 = 8400 cm = 84 m option c | physics |
math_qa__qefKYTtc2zNt9NpP | A certain sum of money is divided among A, B and C so that for each Rs. A has, B has 65 paisa and C 40 paisa. If C's share is Rs.48, find the sum of money? Choose the correct choice from the following choices
A) 288 B) 262 C) 246 D) 205 E) 267 | <gadget id="calculator">48 / 40</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">100 + 65</gadget>
<output>165</output>
<gadget id="calculator">165 + 40</gadget>
<output>205</output>
<gadget id="calculator">(6/5) * 205</gadget>
<output>246</output>
<result>C</result> | C | 246 | A certain sum of money is divided among A, B and C so that for each Rs. A has, B has 65 paisa and C 40 paisa. If C's share is Rs.48, find the sum of money? | {
"A": "288",
"B": "262",
"C": "246",
"D": "205",
"E": "267"
} | multiply(divide(48, 40), add(add(const_100, 65), 40)) | add(n0,const_100)|divide(n2,n1)|add(n1,#0)|multiply(#2,#1)| | "a : b : c = 100 : 65 : 40 = 20 : 13 : 8 8 - - - - 48 41 - - - - ? = > rs . 246 answer : c" | general |
math_qa__wTZhnIwQRKPcVTZ6 | A is four times as fast as B. If B alone can do a piece of work in 60 days, in what time can A and B together complete the work? Select the correct option.
A) 10 B) 12 C) 22 D) 28 E) 20 | <gadget id="calculator">60 / 4</gadget>
<output>15</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/15) + (1/60)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>B</result> | B | 12 | A is four times as fast as B. If B alone can do a piece of work in 60 days, in what time can A and B together complete the work? | {
"A": "10",
"B": "12",
"C": "22",
"D": "28",
"E": "20"
} | inverse(add(inverse(divide(60, const_4)), inverse(60))) | divide(n0,const_4)|inverse(n0)|inverse(#0)|add(#2,#1)|inverse(#3) | a can do the work in 60 / 4 i . e . , 15 days . a and b ' s one day ' s work = 1 / 15 + 1 / 60 = ( 4 + 1 ) / 60 = 1 / 12 so a and b together can do the work in 12 days . answer : b | physics |
math_qa__tud0b3mrkwO1EvkW | 8 men can do a piece of work in 12 days. 4 women can do it in 48 days and 10 children can do it in 24 days. In how many days can 10 men, 4 women and 10 children together complete the piece of work? Choose the correct choice.
A) 5 days
B) 15 days
C) 28 days
D) 6 days
E) 7 days | <gadget id="calculator">24 * 10</gadget>
<output>240</output>
<gadget id="calculator">1 / 240</gadget>
<output>1/240 = around 0.004167</output>
<gadget id="calculator">10 * (1/240)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">12 * 8</gadget>
<output>96</output>
<gadget id="calculator">1 / 96</gadget>
<output>1/96 = around 0.010417</output>
<gadget id="calculator">(1/96) * 10</gadget>
<output>5/48 = around 0.104167</output>
<gadget id="calculator">48 * 4</gadget>
<output>192</output>
<gadget id="calculator">1 / 192</gadget>
<output>1/192 = around 0.005208</output>
<gadget id="calculator">(1/192) * 4</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">(5/48) + (1/48)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/24) + (1/8)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>D</result> | D | 6 | 8 men can do a piece of work in 12 days. 4 women can do it in 48 days and 10 children can do it in 24 days. In how many days can 10 men, 4 women and 10 children together complete the piece of work? | {
"A": "5 days",
"B": "15 days",
"C": "28 days",
"D": "6 days",
"E": "7 days"
} | inverse(add(multiply(10, inverse(multiply(24, 10))), add(multiply(inverse(multiply(12, 8)), 10), multiply(inverse(multiply(48, 4)), 4)))) | multiply(n0,n1)|multiply(n2,n3)|multiply(n4,n5)|inverse(#0)|inverse(#1)|inverse(#2)|multiply(n4,#3)|multiply(n2,#4)|multiply(n4,#5)|add(#6,#7)|add(#9,#8)|inverse(#10) | explanation : 1 man ’ s 1 day ’ s work = 1 / 8 × 12 = 1 / 96 10 men ’ s 1 day ’ s work = 1 × 10 / 96 = 5 / 48 1 woman ’ s 1 day ’ s work = 1 / 192 4 women ’ s 1 day ’ s work = 1 / 192 × 4 = 1 / 48 1 child ’ s 1 day ’ s work = 1 / 240 10 children ’ s 1 day ’ s work = 1 / 24 therefore , ( 10 men + 4 women + 10 children ) ’ s 1 day ’ s work = 5 / 48 + 1 / 48 + 1 / 24 = 8 / 48 = 1 / 6 the required no . of days = 6 days answer : option d | physics |
math_qa__PBCY3wE5b8PvvklJ | If a positive integer n has 211 factors,then how many prime factors does n have? Choose the correct choice from the following answers
A) 3
B) 2
C) can not be determined
D) 4
E) 1 | <gadget id="calculator">211 / 211</gadget>
<output>1</output>
<result>E</result> | E | 1 | If a positive integer n has 211 factors,then how many prime factors does n have? | {
"A": "3",
"B": "2",
"C": "can not be determined",
"D": "4",
"E": "1"
} | divide(211, 211) | divide(n0,n0) | let the factor be a ^ x * b ^ y . . . . . so ( x + 1 ) ( y + 1 ) . . . . . = 211 . . now 211 is a prime number . . . so only one variable x or y is 210 and the others are 0 . . ( 210 + 1 ) ( 0 + 1 ) . . . so the number becomes a ^ 210 . . thus only one prime factor is there . | other |
math_qa__tGTJiSw8wufHbAbn | Rahim bought 65 books for Rs.1150 from one shop and 50 books for Rs.920 from another. What is the average price he paid per book ? Select.
A) rs . 17 B) rs . 18 C) rs . 12 D) rs . 11 E) rs . 10 | <gadget id="calculator">1_150 + 920</gadget>
<output>2_070</output>
<gadget id="calculator">65 + 50</gadget>
<output>115</output>
<gadget id="calculator">2_070 / 115</gadget>
<output>18</output>
<result>B</result> | B | 18 | Rahim bought 65 books for Rs.1150 from one shop and 50 books for Rs.920 from another. What is the average price he paid per book ? | {
"A": "rs . 17",
"B": "rs . 18",
"C": "rs . 12",
"D": "rs . 11",
"E": "rs . 10"
} | divide(add(1150, 920), add(65, 50)) | add(n1,n3)|add(n0,n2)|divide(#0,#1)| | "average price per book = ( 1150 + 920 ) / ( 65 + 50 ) = 2070 / 115 = rs . 18 answer : b" | general |
math_qa__7DJepH6dWb6YtgNJ | A cistern 10 m long and 6 m wide contains water up to a breadth of 1 m 35 cm. Find the total area of the wet surface. Pick one.
A) 100 m sqaure B) 103 m sqaure C) 152 m sqaure D) 164 m sqaure E) none of these | <gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) + 1</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">(27/20) * 6</gadget>
<output>81/10 = around 8.1</output>
<gadget id="calculator">(27/20) * 10</gadget>
<output>27/2 = around 13.5</output>
<gadget id="calculator">(81/10) + (27/2)</gadget>
<output>108/5 = around 21.6</output>
<gadget id="calculator">2 * (108/5)</gadget>
<output>216/5 = around 43.2</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">(216/5) + 60</gadget>
<output>516/5 = around 103.2</output>
<result>B</result> | B | 103 | A cistern 10 m long and 6 m wide contains water up to a breadth of 1 m 35 cm. Find the total area of the wet surface. | {
"A": "100 m sqaure",
"B": "103 m sqaure",
"C": "152 m sqaure",
"D": "164 m sqaure",
"E": "none of these"
} | add(multiply(const_2, add(multiply(add(divide(35, const_100), 1), 6), multiply(add(divide(35, const_100), 1), 10))), multiply(6, 10)) | divide(n3,const_100)|multiply(n0,n1)|add(n2,#0)|multiply(n1,#2)|multiply(n0,#2)|add(#3,#4)|multiply(#5,const_2)|add(#6,#1)| | "explanation : area of the wet surface = 2 [ lb + bh + hl ] - lb = 2 [ bh + hl ] + lb = 2 [ ( 6 * 1.35 + 10 * 1.35 ) ] + 10 * 6 = 103 m square option b" | physics |
math_qa__tycoqDYYEB6Rgoms | Car Q and Car Y traveled the same 80-mile route. If Car Q took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car Q, how many hours did it take Car Y to travel the route?
Choose the correct choice from the following choices: A) 2 / 3 B) 1 C) 4 / 3 D) 8 / 5 E) 3 | <gadget id="calculator">80 / 2</gadget>
<output>40</output>
<gadget id="calculator">40 * 50</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 100</gadget>
<output>20</output>
<gadget id="calculator">20 + 40</gadget>
<output>60</output>
<gadget id="calculator">80 / 60</gadget>
<output>4/3 = around 1.333333</output>
<result>C</result> | C | 1.333333 | Car Q and Car Y traveled the same 80-mile route. If Car Q took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car Q, how many hours did it take Car Y to travel the route? | {
"A": "2 / 3",
"B": "1",
"C": "4 / 3",
"D": "8 / 5",
"E": "3"
} | divide(80, add(divide(multiply(divide(80, 2), 50), const_100), divide(80, 2))) | divide(n0,n1)|multiply(n2,#0)|divide(#1,const_100)|add(#2,#0)|divide(n0,#3) | the speed of car q is ( distance ) / ( time ) = 80 / 2 = 40 miles per hour . the speed of car y = 3 / 2 * 40 = 60 miles per hour - - > ( time ) = ( distance ) / ( speed ) = 80 / 60 = 4 / 3 hours . answer : c . or : to cover the same distance at 3 / 2 as fast rate 2 / 3 as much time is needed - - > ( time ) * 2 / 3 = 2 * 2 / 3 = 4 / 3 hours . answer : c . | physics |
math_qa__RlEFKGNx7hKETA5H | 3 pig’s and 10 hens are brought for Rs.1200. If the average price of a hen be Rs.30. What is the average price of a pig. Choose the correct answer
A) 300
B) 350
C) 400
D) 425
E) 275 | <gadget id="calculator">10 * 30</gadget>
<output>300</output>
<gadget id="calculator">1_200 - 300</gadget>
<output>900</output>
<gadget id="calculator">900 / 3</gadget>
<output>300</output>
<result>A</result> | A | 300 | 3 pig’s and 10 hens are brought for Rs.1200. If the average price of a hen be Rs.30. What is the average price of a pig. | {
"A": "300",
"B": "350",
"C": "400",
"D": "425",
"E": "275"
} | divide(subtract(1200, multiply(10, 30)), 3) | multiply(n1,n3)|subtract(n2,#0)|divide(#1,n0) | explanation : average price of a hen = rs . 30 total price of 10 hens = 10 * 30 = rs . 300 but total price of 3 pigs and 10 hens = rs . 1200 total price of 3 pigs is = 1200 - 300 = 900 average price of a pig = 900 / 3 = rs . 300 answer : a | general |
math_qa__beNcy9909UElBQoQ | Mr Yadav spends 60% of his monthly salary on consumable items and 50% of the remaining on clothes and transport. He saves the remaining amount. If his savings at the end of the year were 46800, how much amount per month would he have spent on clothes and transport? Choose the correct choice from the following
A) 4038
B) 8076
C) 9691.2
D) 4845.6
E) 3900 | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 * 50</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 100</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">46_800 / (1/5)</gadget>
<output>234_000</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">234_000 / 12</gadget>
<output>19_500</output>
<gadget id="calculator">19_500 * (1/5)</gadget>
<output>3_900</output>
<result>E</result> | E | 3,900 | Mr Yadav spends 60% of his monthly salary on consumable items and 50% of the remaining on clothes and transport. He saves the remaining amount. If his savings at the end of the year were 46800, how much amount per month would he have spent on clothes and transport? | {
"A": "4038",
"B": "8076",
"C": "9691.2",
"D": "4845.6",
"E": "3900"
} | multiply(divide(divide(46800, divide(divide(multiply(subtract(const_100, 60), 50), const_100), const_100)), multiply(const_3, const_4)), divide(divide(multiply(subtract(const_100, 60), 50), const_100), const_100)) | multiply(const_3,const_4)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,const_100)|divide(#3,const_100)|divide(n2,#4)|divide(#5,#0)|multiply(#6,#4)| | "∵ amount , he have spent in 1 month on clothes transport = amount spent on saving per month ∵ amount , spent on clothes and transport = 46800 ⁄ 12 = 3900 answer e" | general |
math_qa__QiCAKpIYr4ZpyoWx | A train 605 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
Select:
A) 81 B) 16 C) 33 D) 54 E) 12 | <gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">66 * (5/18)</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">605 / (55/3)</gadget>
<output>33</output>
<result>C</result> | C | 33 | A train 605 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? | {
"A": "81",
"B": "16",
"C": "33",
"D": "54",
"E": "12"
} | divide(605, multiply(add(60, 6), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 60 + 6 = 66 km / hr . = 66 * 5 / 18 = 55 / 3 m / sec . time taken to pass the men = 605 * 3 / 55 = 33 sec . answer : c" | physics |
math_qa__Cut0AVQEDxpsnyST | Tom opened a shop investing Rs.3000. Jose joined him 2 months later, investing Rs.4500. They earned a profit of Rs.6300 after completion of one year. What will be Jose's share of profit? Choose the correct option.
A) 3500 B) 2800 C) 3251 D) 4251 E) 3508 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">3_000 * 12</gadget>
<output>36_000</output>
<gadget id="calculator">12 - 2</gadget>
<output>10</output>
<gadget id="calculator">4_500 * 10</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 + 36_000</gadget>
<output>81_000</output>
<gadget id="calculator">36_000 / 81_000</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">1 - (4/9)</gadget>
<output>5/9 = around 0.555556</output>
<gadget id="calculator">6_300 * (5/9)</gadget>
<output>3_500</output>
<result>A</result> | A | 3,500 | Tom opened a shop investing Rs.3000. Jose joined him 2 months later, investing Rs.4500. They earned a profit of Rs.6300 after completion of one year. What will be Jose's share of profit? | {
"A": "3500",
"B": "2800",
"C": "3251",
"D": "4251",
"E": "3508"
} | multiply(6300, subtract(const_1, divide(multiply(3000, multiply(2, multiply(2, const_3))), add(multiply(4500, subtract(multiply(2, multiply(2, const_3)), 2)), multiply(3000, multiply(2, multiply(2, const_3))))))) | multiply(n1,const_3)|multiply(#0,n1)|multiply(n0,#1)|subtract(#1,n1)|multiply(n2,#3)|add(#4,#2)|divide(#2,#5)|subtract(const_1,#6)|multiply(n3,#7)| | "sol = ~ s - so anju ’ s share = [ 5 / 9 ] x 6300 = 3500 a" | gain |
math_qa__UxjodGQyoexcGrFM | A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is ?
Choose the correct choice from the following choices:
A) 25 %
B) 26 %
C) 27 %
D) 28 %
E) 29 % | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(4/5) * (9/10)</gadget>
<output>18/25 = around 0.72</output>
<gadget id="calculator">1 - (18/25)</gadget>
<output>7/25 = around 0.28</output>
<gadget id="calculator">(7/25) * 100</gadget>
<output>28</output>
<result>D</result> | D | 28 | A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is ? | {
"A": "25 %",
"B": "26 %",
"C": "27 %",
"D": "28 %",
"E": "29 %"
} | multiply(subtract(const_1, multiply(divide(subtract(const_100, 20), const_100), divide(subtract(const_100, 10), const_100))), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|subtract(const_1,#4)|multiply(#5,const_100)| | "explanation : let original length = x and original width = y decrease in area will be = xy − ( 80 x / 100 × 90 y / 100 ) = ( xy − 18 / 25 xy ) = 7 / 25 xy decrease = ( 7 xy / 25 xy × 100 ) % = 28 option d" | gain |
math_qa__j1CiwpeL5xQhPezb | Gold is 10 times as heavy as water and copper is 5 times as heavy as water. In what ratio should these be mixed to get an alloy 6 times as heavy as water? Choose the most appropriate option.
A) 3 : 2 B) 1 : 4 C) 3 : 1 D) 5 : 2 E) 4 : 3 | <gadget id="calculator">6 - 5</gadget>
<output>1</output>
<gadget id="calculator">10 - 6</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<result>B</result> | B | 0.25 | Gold is 10 times as heavy as water and copper is 5 times as heavy as water. In what ratio should these be mixed to get an alloy 6 times as heavy as water? | {
"A": "3 : 2",
"B": "1 : 4",
"C": "3 : 1",
"D": "5 : 2",
"E": "4 : 3"
} | divide(subtract(6, 5), subtract(10, 6)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1) | g = 10 w c = 5 w let 1 gm of gold mixed with x gm of copper to get 1 + x gm of the alloy 1 gm gold + x gm copper = x + 1 gm of alloy 10 w + 5 wx = x + 1 * 6 w 10 + 5 x = 6 ( x + 1 ) x = 4 ratio of gold with copper = 1 : 4 = 1 : 4 answer is b | general |
math_qa__QkT2Ipk2XZBnHNfV | Calculate how many days it will take for 8 boys to paint a 50 m long wall if 6 boys can paint a 60 m long wall in 5 days,
Choose the most appropriate option:
A) 4.13 days
B) 3.13 days
C) 513 days
D) 9.13 days
E) 2 days | <gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 50</gadget>
<output>1_500</output>
<gadget id="calculator">60 * 8</gadget>
<output>480</output>
<gadget id="calculator">1_500 / 480</gadget>
<output>25/8 = around 3.125</output>
<result>B</result> | B | 3.13 | Calculate how many days it will take for 8 boys to paint a 50 m long wall if 6 boys can paint a 60 m long wall in 5 days, | {
"A": "4.13 days",
"B": "3.13 days",
"C": "513 days",
"D": "9.13 days",
"E": "2 days"
} | divide(multiply(multiply(6, 5), 50), multiply(60, 8)) | multiply(n2,n4)|multiply(n0,n3)|multiply(n1,#0)|divide(#2,#1) | the length of wall painted by one boy in one day = 60 / 6 * 1 / 5 = 2 m no . of days required to paint 50 m cloth by 8 boys = 50 / 8 * 1 / 2 = 3.13 days . b | physics |
math_qa__S04I33vK4DwfOBph | A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is:
Choose the correct choice from the following answers: A) 10 B) 13 C) 12 D) 18 E) 19 | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 * 20</gadget>
<output>2_200</output>
<gadget id="calculator">2_200 / 100</gadget>
<output>22</output>
<gadget id="calculator">110 - 22</gadget>
<output>88</output>
<gadget id="calculator">100 - 88</gadget>
<output>12</output>
<result>C</result> | C | 12 | A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is: | {
"A": "10",
"B": "13",
"C": "12",
"D": "18",
"E": "19"
} | subtract(const_100, subtract(add(const_100, 10), divide(multiply(add(const_100, 10), 20), const_100))) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(const_100,#3)| | "c 12 % suppose he has 100 items . let c . p . of each item be $ 1 . total cost = $ 100 . number of items left after theft = 80 . s . p . of each item = $ 1.10 total sale = 1.10 * 80 = $ 88 hence , loss % = 12 / 100 * 100 = 12 %" | gain |
math_qa__UtwmbMit8E9SXAB7 | Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is: Choose one: A) rs . 2007 B) rs . 2000 C) rs . 2089 D) rs . 2067 E) rs . 2098 | <gadget id="calculator">20 * 100</gadget>
<output>2_000</output>
<result>B</result> | B | 2,000 | Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is: | {
"A": "rs . 2007",
"B": "rs . 2000",
"C": "rs . 2089",
"D": "rs . 2067",
"E": "rs . 2098"
} | multiply(20, const_100) | multiply(n4,const_100)| | "let c . p . of each horse be rs . x and c . p . of each cow be rs . y . then , 4 x + 9 y = 13400 - - ( i ) and , 10 % of 4 x + 20 % of 9 y = 1880 2 / 5 x + 9 / 5 y = 1880 = > 2 x + 9 y = 9400 - - ( ii ) solving ( i ) and ( ii ) , we get : x = 2000 and y = 600 . cost price of each horse = rs . 2000 . answer : b" | gain |
math_qa__U446LHYR9m2nhsyx | Two motor bikes cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower bike takes 1 hour more than the faster bike ? Select the correct option:
A) 860 km B) 870 km C) 960 km D) 260 km E) 840 km | <gadget id="calculator">64 - 60</gadget>
<output>4</output>
<gadget id="calculator">60 / 4</gadget>
<output>15</output>
<gadget id="calculator">15 + 1</gadget>
<output>16</output>
<gadget id="calculator">60 * 16</gadget>
<output>960</output>
<result>C</result> | C | 960 | Two motor bikes cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower bike takes 1 hour more than the faster bike ? | {
"A": "860 km",
"B": "870 km",
"C": "960 km",
"D": "260 km",
"E": "840 km"
} | multiply(60, add(divide(60, subtract(64, 60)), 1)) | subtract(n1,n0)|divide(n0,#0)|add(n2,#1)|multiply(n0,#2) | explanation : 60 ( x + 1 ) = 64 x x = 15 60 x 16 = 960 km answer : c | physics |
math_qa__kdcB0AQW2yushQ3Q | The edge of a cube is 7a cm. Find its surface? Choose one
A) 24 a 8 B) 24 a 4 C) 24 a 1 D) 24 a 2 E) 294 a 2 | <gadget id="calculator">6 * (7 ** 2)</gadget>
<output>294</output>
<result>E</result> | E | 294 | The edge of a cube is 7a cm. Find its surface? | {
"A": "24 a 8",
"B": "24 a 4",
"C": "24 a 1",
"D": "24 a 2",
"E": "294 a 2"
} | surface_cube(7) | surface_cube(n0) | 6 a 2 = 6 * 7 a * 7 a = 294 a 2 answer : e | geometry |
math_qa__6erlDE2s0nf8ScBv | If x < y < z and y - x > 5, where x is an even integer and y and z are odd integers, what is the least possible value S of z - x? Pick:
A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<result>D</result> | D | 9 | If x < y < z and y - x > 5, where x is an even integer and y and z are odd integers, what is the least possible value S of z - x? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | add(add(5, const_2), const_2) | add(n0,const_2)|add(#0,const_2)| | "x < y < z to find the least possible value for z - x ; we need to find the values for z and x that can be closest to each other . if x is some even number , then what could be minimum possible odd z . if x is some even number y - x > 5 ; y > x + 5 ; minimum value for y = x + 5 + 2 = x + 7 [ note : x + 5 is as even + odd = odd and nearest odd greater than x + 5 is x + 5 + 2 ] minimum value for z = y + 2 = x + 7 + 2 = x + 9 [ note : z = y + 2 because both z and y are odd . difference between two odd numbers is 2 ] s = z - x = x + 9 - x = 9 ans : d" | general |
math_qa__ybTR9xGA1MNGvH2S | If Renee earns a raise of between 5% and 10%, non-inclusive, by what fraction could her salary have increased? Choose the correct choice from the following answers.
A) 1 / 4 B) 1 / 5 C) 1 / 10 D) 2 / 25 E) 1 / 20 | <gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">4 / 50</gadget>
<output>2/25 = around 0.08</output>
<result>D</result> | D | 0.08 | If Renee earns a raise of between 5% and 10%, non-inclusive, by what fraction could her salary have increased? | {
"A": "1 / 4",
"B": "1 / 5",
"C": "1 / 10",
"D": "2 / 25",
"E": "1 / 20"
} | divide(subtract(5, const_1), multiply(5, const_10)) | multiply(n0,const_10)|subtract(n0,const_1)|divide(#1,#0) | 5 % is 5 / 100 = 1 / 20 10 % is 10 / 100 = 1 / 10 the increase must be greater than 1 / 20 and less than 1 / 10 . 1 / 4 , 1 / 5 , and 1 / 10 are not less than 1 / 10 . 1 / 20 is not greater than 1 / 20 . the only option left is 2 / 25 , which is in the specified range . answer : d | general |
math_qa__BmiMJNkcgnBZBja4 | An engine moves at the speed of 90 kmph without any coaches attached to it.Speed of the train reduces at the rate that varies directly as the square root of the number of coaches attached.When 4 coaches are attached speed decreases to 78 kmph.What will be the speed of train when 16 coaches are attached. Choose the correct choice from the following.
A) 66 B) 72 C) 80 D) 68 E) 73 | <gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">90 - 78</gadget>
<output>12</output>
<gadget id="calculator">4 ** (1/2)</gadget>
<output>2</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">90 - 24</gadget>
<output>66</output>
<result>A</result> | A | 66 | An engine moves at the speed of 90 kmph without any coaches attached to it.Speed of the train reduces at the rate that varies directly as the square root of the number of coaches attached.When 4 coaches are attached speed decreases to 78 kmph.What will be the speed of train when 16 coaches are attached. | {
"A": "66",
"B": "72",
"C": "80",
"D": "68",
"E": "73"
} | subtract(90, multiply(sqrt(16), divide(subtract(90, 78), sqrt(4)))) | sqrt(n1)|sqrt(n3)|subtract(n0,n2)|divide(#2,#0)|multiply(#3,#1)|subtract(n0,#4)| | "1 . no . of coaches = 4 sqr root = 2 speed decreases by 12 12 = k * 2 k = 6 no . of coaches = 16 swr root = 4 decrease = 4 * 6 = 24 new speed = 90 - 24 = 66 a" | physics |
math_qa__DopwOMF0KaPtXgvS | At what rate percent of simple interest will a sum of money double itself in 77 years? Choose the correct choice.
A) 6.54 % B) 2.54 % C) 8 . 2 % D) 4.94 % E) 1.29 % | <gadget id="calculator">100 / 77</gadget>
<output>100/77 = around 1.298701</output>
<result>E</result> | E | 1.29 | At what rate percent of simple interest will a sum of money double itself in 77 years? | {
"A": "6.54 %",
"B": "2.54 %",
"C": "8 . 2 %",
"D": "4.94 %",
"E": "1.29 %"
} | divide(const_100, 77) | divide(const_100,n0) | let sum = x . then , s . i . = x . rate = ( 100 * s . i . ) / ( p * t ) = ( 100 * x ) / ( x * 77 ) = 100 / 77 = 1.29 % answer : e | gain |
math_qa__91e3H1ITaPwcf6Hc | Dacid obtained 73, 69, 92, 64 and 82 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? Choose the correct choice from the following.
A) 79
B) 99
C) 88
D) 88
E) 76 | <gadget id="calculator">73 + 69</gadget>
<output>142</output>
<gadget id="calculator">142 + 92</gadget>
<output>234</output>
<gadget id="calculator">234 + 64</gadget>
<output>298</output>
<gadget id="calculator">298 + 82</gadget>
<output>380</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">380 / 5</gadget>
<output>76</output>
<result>E</result> | E | 76 | Dacid obtained 73, 69, 92, 64 and 82 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? | {
"A": "79",
"B": "99",
"C": "88",
"D": "88",
"E": "76"
} | divide(add(add(add(add(73, 69), 92), 64), 82), divide(const_10, const_2)) | add(n0,n1)|divide(const_10,const_2)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "average = ( 73 + 69 + 92 + 64 + 82 ) / 5 = 380 / 5 = 76 answer : e" | general |
math_qa__3Gyr5lNoT5DgKdBZ | R and S together can plough a field in 10 hours but by himself R requires 15 hours. How long would S take to plough the same field? Choose the correct answer.
A) 24 hours B) 5 hours C) 10 hours D) 15 hours E) 20 hours | <gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">15 + 5</gadget>
<output>20</output>
<result>E</result> | E | 20 | R and S together can plough a field in 10 hours but by himself R requires 15 hours. How long would S take to plough the same field? | {
"A": "24 hours",
"B": "5 hours",
"C": "10 hours",
"D": "15 hours",
"E": "20 hours"
} | add(15, subtract(15, 10)) | subtract(n1,n0)|add(n1,#0) | f r and s together can do a piece of work in x days and r alone can do the same work in y days , then s alone can do the same work in x y / y â € “ x days . the no . of hours required by s = 10 ã — 20 / 20 â € “ 10 = 200 / 10 = 20 hours e | physics |
math_qa__lEKbAlzfXcqwou8x | 36 is divided in 2 parts such that 8 times the first part added to 3 times the second part makes 203. What is the first part?
Answers:
A) 19
B) 88
C) 267
D) 26
E) 28 | <gadget id="calculator">36 * 3</gadget>
<output>108</output>
<gadget id="calculator">203 - 108</gadget>
<output>95</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">95 / 5</gadget>
<output>19</output>
<result>A</result> | A | 19 | 36 is divided in 2 parts such that 8 times the first part added to 3 times the second part makes 203. What is the first part? | {
"A": "19",
"B": "88",
"C": "267",
"D": "26",
"E": "28"
} | divide(subtract(203, multiply(36, 3)), subtract(8, 3)) | multiply(n0,n3)|subtract(n2,n3)|subtract(n4,#0)|divide(#2,#1) | explanation : let the first part be x . 8 x + 3 ( 36 – x ) = 203 8 x + 108 – 3 x = 203 5 x + 108 = 203 5 x = 95 x = 19 answer : a | general |
math_qa__P1NImwQ41aqmYIQC | Roy is now 8 years older than Julia and half of that amount older than Kelly. If in 2 years, Roy will be twice as old as Julia, then in 2 years what would be Roy’s age multiplied by Kelly’s age?
Answers:
A) 160
B) 168
C) 176
D) 184
E) 192 | <gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">8 + 6</gadget>
<output>14</output>
<gadget id="calculator">14 + 2</gadget>
<output>16</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">14 - 4</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">16 * 12</gadget>
<output>192</output>
<result>E</result> | E | 192 | Roy is now 8 years older than Julia and half of that amount older than Kelly. If in 2 years, Roy will be twice as old as Julia, then in 2 years what would be Roy’s age multiplied by Kelly’s age? | {
"A": "160",
"B": "168",
"C": "176",
"D": "184",
"E": "192"
} | multiply(add(add(8, subtract(8, 2)), 2), add(subtract(add(8, subtract(8, 2)), divide(8, const_2)), 2)) | divide(n0,const_2)|subtract(n0,n1)|add(n0,#1)|add(n1,#2)|subtract(#2,#0)|add(n1,#4)|multiply(#3,#5)| | "r = j + 8 = k + 4 r + 2 = 2 ( j + 2 ) ( j + 8 ) + 2 = 2 j + 4 j = 6 r = 14 k = 10 in 2 years ( r + 2 ) ( k + 2 ) = 16 * 12 = 192 the answer is e ." | general |
math_qa__UqbnMiUflzxJzs1x | The radius of a cylindrical vessel is 5cm and height is 3cm. Find the whole surface of the cylinder? Options.
A) 251.4 sq cm B) 220 sq cm C) 440 sq cm D) 132 sq cm E) 138 sq cm | <gadget id="calculator">2 * pi * 5 * (5 + 3)</gadget>
<output>80*pi = around 251.327412</output>
<result>A</result> | A | 251.4 | The radius of a cylindrical vessel is 5cm and height is 3cm. Find the whole surface of the cylinder? | {
"A": "251.4 sq cm",
"B": "220 sq cm",
"C": "440 sq cm",
"D": "132 sq cm",
"E": "138 sq cm"
} | surface_cylinder(5, 3) | surface_cylinder(n0,n1)| | "r = 5 h = 3 2 π r ( h + r ) = 2 * 22 / 7 * 5 ( 8 ) = 251.4 answer : a" | geometry |
math_qa__Xea9JcooviiZlS7O | Mike works at a science lab that conducts experiments on bacteria. The population of the bacteria multiplies at a constant rate, and his job is to notate the population of a certain group of bacteria each hour. At 1 p.m. on a certain day, he noted that the population was 500 and then he left the lab. He returned in time to take a reading at 4 p.m., by which point the population had grown to 62,500. Now he has to fill in the missing data for 2 p.m. and 3 p.m. What was the population at 3 p.m.? Choose the correct choice from the following
A) 13000
B) 12500
C) 13500
D) 14000
E) 15000 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">25 * 500</gadget>
<output>12_500</output>
<result>B</result> | B | 12,500 | Mike works at a science lab that conducts experiments on bacteria. The population of the bacteria multiplies at a constant rate, and his job is to notate the population of a certain group of bacteria each hour. At 1 p.m. on a certain day, he noted that the population was 500 and then he left the lab. He returned in time to take a reading at 4 p.m., by which point the population had grown to 62,500. Now he has to fill in the missing data for 2 p.m. and 3 p.m. What was the population at 3 p.m.? | {
"A": "13000",
"B": "12500",
"C": "13500",
"D": "14000",
"E": "15000"
} | multiply(power(add(const_2, const_3), 2), 500) | add(const_2,const_3)|power(#0,n4)|multiply(n1,#1) | let the rate be x , then population of the bacteria after each hour can be given as 500,500 x , 500 ( x ^ 2 ) , 500 ( x ^ 3 ) now population at 4 pm = 62,500 thus we have 500 ( x ^ 3 ) = 62,500 = 125 thus x = 5 therefore population at 3 pm = 500 ( 25 ) = 12500 answer : b | physics |
math_qa__G0iUBP2s8m1get4j | At a certain bowling alley, it costs $0.50 to rent bowling shoes for the day and $1.75 to bowl 1 game. If a person has $12.80 and must rent shoes, what is the greatest number of complete games that person can bowl in one day? Choose the correct choice from the following choices
A) 7
B) 8
C) 9
D) 10
E) 11 | <gadget id="calculator">12.8 - 0.5</gadget>
<output>12.3</output>
<gadget id="calculator">12.3 / 1.75</gadget>
<output>7.028571</output>
<result>A</result> | A | 7 | At a certain bowling alley, it costs $0.50 to rent bowling shoes for the day and $1.75 to bowl 1 game. If a person has $12.80 and must rent shoes, what is the greatest number of complete games that person can bowl in one day? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | divide(subtract(12.80, 0.50), 1.75) | subtract(n3,n0)|divide(#0,n1)| | "after renting bowling shoes the person is left with $ 12.80 - $ 0.5 = $ 12.30 , which is enough for 12.3 / 1.75 = 7.02 - > ~ 7 . answer : a ." | physics |
math_qa__P6W1f8vT9N710MgD | The arithmetic mean and standard deviation of a certain normal distribution are 14.5 and 1.5, respectively. What value is exactly 2 standard deviations less than the mean?
Select:
A) 10.5
B) 11
C) 11.5
D) 12
E) 12.5 | <gadget id="calculator">2 * 1.5</gadget>
<output>3</output>
<gadget id="calculator">14.5 - 3</gadget>
<output>11.5</output>
<result>C</result> | C | 11.5 | The arithmetic mean and standard deviation of a certain normal distribution are 14.5 and 1.5, respectively. What value is exactly 2 standard deviations less than the mean? | {
"A": "10.5",
"B": "11",
"C": "11.5",
"D": "12",
"E": "12.5"
} | subtract(14.5, multiply(2, 1.5)) | multiply(n1,n2)|subtract(n0,#0)| | "the value which isexactlytwo sd less than the mean is : mean - 2 * sd = 14.5 - 2 * 1.5 = 11.5 . answer : c ." | general |
math_qa__rxfua9LiPHT549od | A girl sitting in a train which is travelling at 100 kmph observes that a goods train travelling in a opposite direction, takes 6 seconds to pass him. If the goods train is 560 m long, find its speed.
Choose the correct choice:
A) 230 B) 232 C) 234 D) 236 E) 238 | <gadget id="calculator">560 / 6</gadget>
<output>280/3 = around 93.333333</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(280/3) / (5/18)</gadget>
<output>336</output>
<gadget id="calculator">336 - 100</gadget>
<output>236</output>
<result>E</result> | E | 238 | A girl sitting in a train which is travelling at 100 kmph observes that a goods train travelling in a opposite direction, takes 6 seconds to pass him. If the goods train is 560 m long, find its speed. | {
"A": "230",
"B": "232",
"C": "234",
"D": "236",
"E": "238"
} | subtract(divide(divide(560, 6), const_0_2778), 100) | divide(n2,n1)|divide(#0,const_0_2778)|subtract(#1,n0)| | "relative speed = ( 560 / 6 ) m / s = ( 560 / 6 ) * ( 18 / 5 ) = 336 kmph speed of goods train = 336 - 100 = 236 kmph answer is e" | physics |
math_qa__hZe9n70FzL3H3u2l | The average age of 15 students of a class is 15 years. Out of these, the average age of 4 students is 14 years and that of the other 9 students is 16 years. Tee age of the 15th student is? Choices:
A) 20 years B) 22 years C) 24 years D) 25 years E) 27 years | <gadget id="calculator">15 * 15</gadget>
<output>225</output>
<gadget id="calculator">4 * 14</gadget>
<output>56</output>
<gadget id="calculator">9 * 16</gadget>
<output>144</output>
<gadget id="calculator">56 + 144</gadget>
<output>200</output>
<gadget id="calculator">225 - 200</gadget>
<output>25</output>
<result>D</result> | D | 25 | The average age of 15 students of a class is 15 years. Out of these, the average age of 4 students is 14 years and that of the other 9 students is 16 years. Tee age of the 15th student is? | {
"A": "20 years",
"B": "22 years",
"C": "24 years",
"D": "25 years",
"E": "27 years"
} | subtract(multiply(15, 15), add(multiply(4, 14), multiply(9, 16))) | multiply(n0,n0)|multiply(n2,n3)|multiply(n4,n5)|add(#1,#2)|subtract(#0,#3)| | "age of the 15 th student = [ 15 * 15 - ( 14 * 4 + 16 * 9 ) ] = ( 225 - 200 ) = 25 years . answer : d" | general |
math_qa__vJnG4c9CHoyWOFu7 | A can do a piece of work in 10 days and B alone can do it in 15 days. How much time will both take to finish the work ? Choose the correct choice from the following answers
A) 2 days B) 7 days C) 6 days D) 9 days E) 3 days | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) + (1/15)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>C</result> | C | 6 | A can do a piece of work in 10 days and B alone can do it in 15 days. How much time will both take to finish the work ? | {
"A": "2 days",
"B": "7 days",
"C": "6 days",
"D": "9 days",
"E": "3 days"
} | divide(const_1, add(divide(const_1, 10), divide(const_1, 15))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)| | "c 6 days time taken to finish the job = xy / ( x + y ) = 10 x 15 / ( 10 + 15 ) = 150 / 25 = 6 days" | physics |
math_qa__8YMZac3urV7OWYbW | In a class of 25 students in an examination in maths 5 students scored 95 marks each, 3 get zero each and the average of the rest was 45. What is the average of the whole class?
Options: A) 47 B) 45.6 C) 44 D) 48 E) 49.6 | <gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">25 - 8</gadget>
<output>17</output>
<gadget id="calculator">45 * 17</gadget>
<output>765</output>
<gadget id="calculator">95 * 5</gadget>
<output>475</output>
<gadget id="calculator">765 + 475</gadget>
<output>1_240</output>
<gadget id="calculator">1_240 / 25</gadget>
<output>248/5 = around 49.6</output>
<result>E</result> | E | 49.6 | In a class of 25 students in an examination in maths 5 students scored 95 marks each, 3 get zero each and the average of the rest was 45. What is the average of the whole class? | {
"A": "47",
"B": "45.6",
"C": "44",
"D": "48",
"E": "49.6"
} | divide(add(multiply(45, subtract(25, add(3, 5))), multiply(95, 5)), 25) | add(n1,n3)|multiply(n1,n2)|subtract(n0,#0)|multiply(n4,#2)|add(#3,#1)|divide(#4,n0)| | "explanation : total marks obtained by a class of 25 students = 5 * 95 + 3 * 0 + 17 * 45 = 1240 average marks of whole class = 1240 / 25 = 49.6 answer : option e" | general |
math_qa__PQI5DrV4dTdOTPAw | How many positive integers between 1 and 400 are there such that they are multiples of 25? Select the correct option:
A) 12 B) 13 C) 16 D) 15 E) 11 | <gadget id="calculator">400 - 1</gadget>
<output>399</output>
<gadget id="calculator">399 / 25</gadget>
<output>399/25 = around 15.96</output>
<result>C</result> | C | 16 | How many positive integers between 1 and 400 are there such that they are multiples of 25? | {
"A": "12",
"B": "13",
"C": "16",
"D": "15",
"E": "11"
} | divide(subtract(400, 1), 25) | subtract(n1,n0)|divide(#0,n2)| | "multiples of 25 = 25 , 50,75 , - - - - - 400 number of multiples of 25 = > 25 * 16 = 400 answer is c" | general |
math_qa__1KYAOAAe548R5Mhm | if the range w of the 6 numbers 4 , 314 , 710 and x is 12 , what is the difference between the greatest possible value of x and least possible value of x ? Choose the correct choice from the following options.
A) 0
B) 2
C) 12
D) 13
E) 15 | <gadget id="calculator">12 + 3</gadget>
<output>15</output>
<gadget id="calculator">10 + 4</gadget>
<output>14</output>
<gadget id="calculator">14 - 12</gadget>
<output>2</output>
<gadget id="calculator">15 - 2</gadget>
<output>13</output>
<result>D</result> | D | 13 | if the range w of the 6 numbers 4 , 314 , 710 and x is 12 , what is the difference between the greatest possible value of x and least possible value of x ? | {
"A": "0",
"B": "2",
"C": "12",
"D": "13",
"E": "15"
} | subtract(add(12, const_3), subtract(add(const_10, 4), 12)) | add(n4,const_3)|add(n1,const_10)|subtract(#1,n4)|subtract(#0,#2) | the range w of a set is the difference between the largest and smallest elements of a set . without x , the difference between the largest and smallest elements of a set is 14 - 3 = 11 < 12 , which means that in order 12 to be the range of the set x must be either the smallest element so that 14 - x = 12 - - - > x = 2 or x must the largest element so that x - 3 = 12 - - > x = 15 . the the difference between the greatest possible value of x and least possible value of x is 15 - 2 = 13 . answer : d . | general |
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