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float64 -4,212
100B
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stringlengths 6
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stringlengths 7
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stringlengths 8
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math_qa__i5HaEZNwlLK7U66Q | A 1200 m long train crosses a tree in 80 sec, how much time will I take to pass a platform 1000 m long? Select
A) 288 B) 146.66 C) 188 D) 180 E) 12 | <gadget id="calculator">1_200 + 1_000</gadget>
<output>2_200</output>
<gadget id="calculator">1_200 / 80</gadget>
<output>15</output>
<gadget id="calculator">2_200 / 15</gadget>
<output>440/3 = around 146.666667</output>
<result>B</result> | B | 146.66 | A 1200 m long train crosses a tree in 80 sec, how much time will I take to pass a platform 1000 m long? | {
"A": "288",
"B": "146.66",
"C": "188",
"D": "180",
"E": "12"
} | divide(add(1200, 1000), divide(1200, 80)) | add(n0,n2)|divide(n0,n1)|divide(#0,#1)| | "l = s * t s = 1200 / 80 s = 15 m / sec . total length ( d ) = 2200 m t = d / s t = 2200 / 15 t = 146.66 sec answer : b" | physics |
math_qa__RBu6gQ9A07K7GXdi | How many shots of 1cm radius can be prepared from a sphere of 7cm radius? Choose the correct choice from the following answers.
A) 343 B) 388 C) 327 D) 88 E) 99 | <gadget id="calculator">7 ** 2</gadget>
<output>49</output>
<gadget id="calculator">49 * 7</gadget>
<output>343</output>
<result>A</result> | A | 343 | How many shots of 1cm radius can be prepared from a sphere of 7cm radius? | {
"A": "343",
"B": "388",
"C": "327",
"D": "88",
"E": "99"
} | multiply(power(7, const_2), 7) | power(n1,const_2)|multiply(n1,#0)| | "4 / 3 ï € * 7 * 7 * 7 = 4 / 3 ï € * 1 * 1 * 1 * x x = 343 answer : a" | physics |
math_qa__jFRimCQAhMRvRTLl | A river boat leaves Silver Town and travels upstream to Gold Town at an average speed of 6 kilometers per hour. It returns by the same route at an average speed of 3 kilometers per hour. What is the average speed for the round-trip in kilometers per hour? Choose one.
A) 4.0 B) 3.8 C) 7.2 D) 7.5 E) 8.0 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">36 / 9</gadget>
<output>4</output>
<result>A</result> | A | 4 | A river boat leaves Silver Town and travels upstream to Gold Town at an average speed of 6 kilometers per hour. It returns by the same route at an average speed of 3 kilometers per hour. What is the average speed for the round-trip in kilometers per hour? | {
"A": "4.0",
"B": "3.8",
"C": "7.2",
"D": "7.5",
"E": "8.0"
} | divide(multiply(multiply(6, 3), const_2), add(6, 3)) | add(n0,n1)|multiply(n0,n1)|multiply(#1,const_2)|divide(#2,#0)| | "pick a number which is lcm of 3 and 6 = 12 . upstream time = 12 / 6 = 2 hrs downstream time = 12 / 3 = 4 hrs total time = 6 hrs total distance = 24 average speed = 24 / 6 = 4.0 km / hr" | physics |
math_qa__lJXXPnolxcrtU0O7 | ABCD is a square where AB =√4008. Let X be a point on AB and Y be a point on CD such that AX = CY . Compute the area of trapezoid AXYD. Choose the correct choice from the following: A) 3008 B) 2004 C) 1008 D) 2016 E) 3000 | <gadget id="calculator">4_008 / 2</gadget>
<output>2_004</output>
<result>B</result> | B | 2,004 | ABCD is a square where AB =√4008. Let X be a point on AB and Y be a point on CD such that AX = CY . Compute the area of trapezoid AXYD. | {
"A": "3008",
"B": "2004",
"C": "1008",
"D": "2016",
"E": "3000"
} | divide(4008, const_2) | divide(n0,const_2)| | "note that trapezoids axy d and bxy c are congruent , so the area of axy d is always 4008 / 2 = 2004 . correct answer b" | geometry |
math_qa__3jQpwzcDHXWUx04q | Points X, Y, and Z lie, in that order, on a straight railroad track. The distance from point X to point Y is twice the distance from point Y to point Z. A train traveled from point X to point Z without stopping. The train's average speed when traveling from point X to point Y was 300 miles per hour and the train's average speed when traveling from point Y to point Z was 100 miles per hour. What was the train's average speed, in miles per hour, when traveling from point X to point Z? Choices.
A) 200 B) 220 C) 240 D) 180 E) 260 | <gadget id="calculator">300 / 100</gadget>
<output>3</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) + 1</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">3 / (5/3)</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) * 100</gadget>
<output>180</output>
<result>D</result> | D | 180 | Points X, Y, and Z lie, in that order, on a straight railroad track. The distance from point X to point Y is twice the distance from point Y to point Z. A train traveled from point X to point Z without stopping. The train's average speed when traveling from point X to point Y was 300 miles per hour and the train's average speed when traveling from point Y to point Z was 100 miles per hour. What was the train's average speed, in miles per hour, when traveling from point X to point Z? | {
"A": "200",
"B": "220",
"C": "240",
"D": "180",
"E": "260"
} | multiply(divide(const_3, add(divide(const_2, divide(300, 100)), const_1)), 100) | divide(n0,n1)|divide(const_2,#0)|add(#1,const_1)|divide(const_3,#2)|multiply(n1,#3) | average speed = distance / time because we are looking for average speed we can pick a distance for the variable d . speed x - y = 300 speed y - z = 100 average speed = total distance / total rate rate = distance / time x = = = = = = = = = = = = = = = = = = = = y = = = = = = = = = = z if x - y is twice the length of y - z then let x - y = 2 d and let y - z = d average speed = 3 d / ( 2 d / 300 ) + ( d / 100 ) 3 d / ( 2 d / 300 ) + ( 3 d / 300 ) 3 d / ( 5 d / 300 ) 900 d / 5 d average speed = 180 answer : d | physics |
math_qa__rDkQW24UBsejKzyo | A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
Select the correct option
A) 220 meter B) 225 meter C) 230 meter D) 235 meter E) none of these | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">(500/9) * 9</gadget>
<output>500</output>
<gadget id="calculator">500 - 270</gadget>
<output>230</output>
<result>C</result> | C | 230 | A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train? | {
"A": "220 meter",
"B": "225 meter",
"C": "230 meter",
"D": "235 meter",
"E": "none of these"
} | subtract(multiply(multiply(add(120, 80), const_0_2778), 9), 270) | add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)| | "explanation : as trains are running in opposite directions so their relative speed will get added so , relative speed = 120 + 80 = 200 kmph = 200 * ( 5 / 18 ) = 500 / 9 m / sec let the length of other train is x meter then x + 270 / 9 = 500 / 9 = > x + 270 = 500 = > x = 230 so the length of the train is 230 meters option c" | physics |
math_qa__dnpKP36WvR6APxLE | There is rain at a rate of 12 centimeters per hour all over New Jersey. Somewhere downtown in New Jersey a group of students are waiting for the rain to stop. If the rain filled a tank the with a base area of 250 square centimeters and a depth of 6 centimeters, how long did the students wait for the rain to stop? Pick.
A) 8 hours
B) 4 hours 25 minutes
C) 3 hours 15 minutes
D) 6 hours
E) 2 hours | <gadget id="calculator">250 * 6</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 12</gadget>
<output>125</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">125 / 60</gadget>
<output>25/12 = around 2.083333</output>
<result>E</result> | E | 2 | There is rain at a rate of 12 centimeters per hour all over New Jersey. Somewhere downtown in New Jersey a group of students are waiting for the rain to stop. If the rain filled a tank the with a base area of 250 square centimeters and a depth of 6 centimeters, how long did the students wait for the rain to stop? | {
"A": "8 hours",
"B": "4 hours 25 minutes",
"C": "3 hours 15 minutes",
"D": "6 hours",
"E": "2 hours"
} | divide(divide(multiply(250, 6), 12), multiply(6, const_10)) | multiply(n1,n2)|multiply(n2,const_10)|divide(#0,n0)|divide(#2,#1) | answer is : e , 4 hours and 30 mins the volume of the tank is irrelevant and only height matters since rain fell all over the city . thus , it takes only . 12 / 6 = 2 hours of rain to fill the tank . | physics |
math_qa__hTmd6dVGbWJCeFaL | During a sale, the price of a pair of shoes is marked down 14% from the regular price. After the sale ends, the price goes back to the original price. What is the percent of increase to the nearest percent from the sale price back to the regular price for the shoes? Pick
A) 9 %
B) 10 %
C) 11 %
D) 16 %
E) 90 % | <gadget id="calculator">14 * 100</gadget>
<output>1_400</output>
<gadget id="calculator">100 - 14</gadget>
<output>86</output>
<gadget id="calculator">1_400 / 86</gadget>
<output>700/43 = around 16.27907</output>
<result>D</result> | D | 16 | During a sale, the price of a pair of shoes is marked down 14% from the regular price. After the sale ends, the price goes back to the original price. What is the percent of increase to the nearest percent from the sale price back to the regular price for the shoes? | {
"A": "9 %",
"B": "10 %",
"C": "11 %",
"D": "16 %",
"E": "90 %"
} | divide(multiply(14, const_100), subtract(const_100, 14)) | multiply(n0,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "assume the price = 100 price during sale = 86 price after sale = 100 percent increase = 14 / 86 * 100 = 16 % approx . correct option : d" | gain |
math_qa__p72v6NCCoQRmX1Nn | Two trains of length 60 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? Pick: A) 10 sec B) 32 sec C) 17 sec D) 20 sec E) 89 sec | <gadget id="calculator">60 + 280</gadget>
<output>340</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">340 / 20</gadget>
<output>17</output>
<result>C</result> | C | 17 | Two trains of length 60 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "10 sec",
"B": "32 sec",
"C": "17 sec",
"D": "20 sec",
"E": "89 sec"
} | divide(add(60, 280), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 60 + 280 = 400 m . the time required = d / s = 340 / 20 = 20 sec . answer : c" | physics |
math_qa__QbjkgiQ8SB7QUfug | one 100 gallons of fuel are purchased at $ 0.70 per gallon . the fuel is consumed at a rate of $ 0.40 worth of fuel per hour . at this rate , how many hours are required to consume the 100 gallons of fuel ? Choose the correct option:
A) 150
B) 175
C) 200
D) 225
E) 250 | <gadget id="calculator">0.7 * 100</gadget>
<output>70</output>
<gadget id="calculator">70 / 0.4</gadget>
<output>175</output>
<result>B</result> | B | 175 | one 100 gallons of fuel are purchased at $ 0.70 per gallon . the fuel is consumed at a rate of $ 0.40 worth of fuel per hour . at this rate , how many hours are required to consume the 100 gallons of fuel ? | {
"A": "150",
"B": "175",
"C": "200",
"D": "225",
"E": "250"
} | divide(multiply(0.7, 100), 0.4) | multiply(n0,n1)|divide(#0,n2) | the fuel is consumed at this rate : $ 0.40 / $ 0.70 = 4 / 7 gallons per hour . the time it takes to consume 100 gallons is : 100 / ( 4 / 7 ) = 175 hours . the answer is b . | gain |
math_qa__bxVvssfeR2qDdg1u | A chemist mixes one liter of pure water with x liters of a 75% salt solution, and the resulting mixture is a 15% salt solution. What is the value of x? Select.
A) 1 / 4
B) 1 / 3
C) 1 / 2
D) 1
E) 3 | <gadget id="calculator">75 - 15</gadget>
<output>60</output>
<gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<result>A</result> | A | 0.25 | A chemist mixes one liter of pure water with x liters of a 75% salt solution, and the resulting mixture is a 15% salt solution. What is the value of x? | {
"A": "1 / 4",
"B": "1 / 3",
"C": "1 / 2",
"D": "1",
"E": "3"
} | divide(15, subtract(75, 15)) | subtract(n0,n1)|divide(n1,#0)| | "concentration of salt in pure solution = 0 concentration of salt in salt solution = 75 % concentration of salt in the mixed solution = 15 % the pure solution and the salt solution is mixed in the ratio of - - > ( 75 - 15 ) / ( 15 - 0 ) = 4 / 1 1 / x = 4 / 1 x = 1 / 4 answer : a" | gain |
math_qa__gcGKiJD8YBDwJ8WO | If 5% more is gained by selling an article for Rs. 600 than by selling it for Rs. 580, the cost of the article is? Options:
A) 127
B) 688
C) 400
D) 121
E) 123 | <gadget id="calculator">600 - 580</gadget>
<output>20</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">20 / (1/20)</gadget>
<output>400</output>
<result>C</result> | C | 400 | If 5% more is gained by selling an article for Rs. 600 than by selling it for Rs. 580, the cost of the article is? | {
"A": "127",
"B": "688",
"C": "400",
"D": "121",
"E": "123"
} | divide(subtract(600, 580), divide(5, const_100)) | divide(n0,const_100)|subtract(n1,n2)|divide(#1,#0)| | "let c . p . be rs . x . then , 5 % of x = 600 - 580 = 20 x / 20 = 20 = > x = 400 answer : c" | gain |
math_qa__QptLiY3nSGThSWsQ | a , b , c subscribe rs . 50000 for a business . if a subscribes rs . 4000 more than b and b rs . 5000 more than c , out of a total profit of rs . 36000 , what will be the amount a receives ?
Options: A) 15120 B) 14500 C) 14900 D) 14300 E) 14000 | <gadget id="calculator">5_000 + 4_000</gadget>
<output>9_000</output>
<gadget id="calculator">9_000 + 5_000</gadget>
<output>14_000</output>
<gadget id="calculator">50_000 - 14_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 3</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 + 9_000</gadget>
<output>21_000</output>
<gadget id="calculator">21_000 / 50_000</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">(21/50) * 36_000</gadget>
<output>15_120</output>
<result>A</result> | A | 15,120 | a , b , c subscribe rs . 50000 for a business . if a subscribes rs . 4000 more than b and b rs . 5000 more than c , out of a total profit of rs . 36000 , what will be the amount a receives ? | {
"A": "15120",
"B": "14500",
"C": "14900",
"D": "14300",
"E": "14000"
} | multiply(divide(add(divide(subtract(50000, add(add(5000, 4000), 5000)), const_3), add(5000, 4000)), 50000), 36000) | add(n1,n2)|add(n2,#0)|subtract(n0,#1)|divide(#2,const_3)|add(#0,#3)|divide(#4,n0)|multiply(n3,#5) | total amount invested = 50000 assume that investment of c = x . then investment of b = 5000 + x , investment of a = 4000 + 5000 + x = 9000 + x x + 5000 + x + 9000 + x = 50000 ⇒ 3 x + 14000 = 50000 ⇒ 3 x = 50000 – 14000 = 36000 ⇒ x = 36000 / 3 = 12000 investment of c = x = 12000 investment of b = 5000 + x = 17000 investment of a = 9000 + x = 21000 ratio of the investment of a , b and c = 21000 : 17000 : 12000 = 21 : 17 : 12 share of a = total profit × 21 / 50 = 36000 × 21 / 50 = 15,120 answer is a . | general |
math_qa__RDmBRioOKzYw6Lts | When sold at a 60% discount, a sweater nets the merchant a 35% profit on the wholesale cost at which he initially purchased the item. By what % is the sweater marked up from wholesale at its normal retail price? Choose the correct option: A) 20 % B) 40 % C) 50 % D) 70.38 % E) 100 % | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">1 + (7/20)</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">40 / (27/20)</gadget>
<output>800/27 = around 29.62963</output>
<gadget id="calculator">100 - (800/27)</gadget>
<output>1_900/27 = around 70.37037</output>
<result>D</result> | D | 70.38 | When sold at a 60% discount, a sweater nets the merchant a 35% profit on the wholesale cost at which he initially purchased the item. By what % is the sweater marked up from wholesale at its normal retail price? | {
"A": "20 %",
"B": "40 %",
"C": "50 %",
"D": "70.38 %",
"E": "100 %"
} | subtract(const_100, divide(subtract(const_100, 60), add(const_1, divide(35, const_100)))) | divide(n1,const_100)|subtract(const_100,n0)|add(#0,const_1)|divide(#1,#2)|subtract(const_100,#3)| | "we should be careful about what are we measuring % on / what is the base . . let the marked up price = 100 . . selling price = 100 - 60 % of 100 = 40 . . profit = 35 % . . therefore the wholesale purchase cost = x . . . . 1.35 x = 40 or x = 29.62 . . . marked price was 100 so . . . so answer is 70.38 % . . d" | gain |
math_qa__iDVNaUAnsXjSMWFO | From a group of 3 women and 3 girls, 4 are to be randomly selected. What is the probability that equal numbers of women and girls will be selected?
Pick:
A) 3 / 5 B) 1 / 5 C) 2 / 5 D) 4 / 5 E) 1 | <gadget id="calculator">binomial(3, 2)</gadget>
<output>3</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">binomial(6, 4)</gadget>
<output>15</output>
<gadget id="calculator">9 / 15</gadget>
<output>3/5 = around 0.6</output>
<result>A</result> | A | 0.6 | From a group of 3 women and 3 girls, 4 are to be randomly selected. What is the probability that equal numbers of women and girls will be selected? | {
"A": "3 / 5",
"B": "1 / 5",
"C": "2 / 5",
"D": "4 / 5",
"E": "1"
} | divide(multiply(choose(3, const_2), choose(3, const_2)), choose(add(3, 3), 4)) | add(n0,n0)|choose(n0,const_2)|choose(#0,n2)|multiply(#1,#1)|divide(#3,#2) | using the first example , here is the probability of that exact sequence occurring : wwgg = ( 3 / 6 ) ( 2 / 5 ) ( 3 / 4 ) ( 2 / 3 ) = 36 / 360 = 1 / 10 each of the other 5 options will yield the exact same probability . . . . wgwg = ( 3 / 6 ) ( 3 / 5 ) ( 2 / 4 ) ( 2 / 3 ) = 36 / 360 = 1 / 10 so we have 6 different options that each produce a 1 / 10 chance of occurring . 6 ( 1 / 10 ) = 6 / 10 = 3 / 5 final answer : a | probability |
math_qa__QrG5QkCjavsSATBw | An integer n between 1 and 99, inclusive, is to be chosen at random. What is the probability that n(n+1) will be divisible by 2 ? Choose one:
A) 1 / 9
B) 1 / 3
C) 1 / 2
D) 2 / 3
E) 5 / 6 | <gadget id="calculator">99 / 3</gadget>
<output>33</output>
<gadget id="calculator">33 / 99</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 2</gadget>
<output>2/3 = around 0.666667</output>
<result>D</result> | D | 0.666667 | An integer n between 1 and 99, inclusive, is to be chosen at random. What is the probability that n(n+1) will be divisible by 2 ? | {
"A": "1 / 9",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "5 / 6"
} | multiply(divide(divide(99, const_3), 99), const_2.0) | divide(n1,const_3)|divide(#0,n1)|multiply(const_2.0,#1)| | "n ( n + 1 ) to be divisible by 2 either n or n + 1 must be a multiples of 2 . in each following group of numbers : { 1 , 2 , 3 } , { 4 , 5 , 6 } , { 7 , 8 , 9 } , . . . , { 97 , 98 , 99 } there are exactly 2 numbers out of 3 satisfying the above condition . for example in { 1 , 2 , 3 } n can be : 2 , or 3 . thus , the overall probability is 2 / 3 . answer : d ." | general |
math_qa__XbVsbDq9nnxyCA09 | The S.I. on a certain sum of money for 4 years at 12% per annum is half the C.I. on Rs. 6000 for 2 years at 15% per annum. The sum placed on S.I. is? Select the correct option.
A) 2019.625 B) 2017.625 C) 2013.625 D) 2015.625 E) 2011.625 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(23/20) ** 2</gadget>
<output>529/400 = around 1.3225</output>
<gadget id="calculator">6_000 * (529/400)</gadget>
<output>7_935</output>
<gadget id="calculator">7_935 - 6_000</gadget>
<output>1_935</output>
<gadget id="calculator">1_935 / 2</gadget>
<output>1_935/2 = around 967.5</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">4 * (3/25)</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">(1_935/2) / (12/25)</gadget>
<output>16_125/8 = around 2_015.625</output>
<result>D</result> | D | 2,015.625 | The S.I. on a certain sum of money for 4 years at 12% per annum is half the C.I. on Rs. 6000 for 2 years at 15% per annum. The sum placed on S.I. is? | {
"A": "2019.625",
"B": "2017.625",
"C": "2013.625",
"D": "2015.625",
"E": "2011.625"
} | divide(divide(subtract(multiply(6000, power(add(const_1, divide(15, const_100)), 2)), 6000), 2), multiply(4, divide(12, const_100))) | divide(n4,const_100)|divide(n1,const_100)|add(#0,const_1)|multiply(n0,#1)|power(#2,n3)|multiply(n2,#4)|subtract(#5,n2)|divide(#6,n3)|divide(#7,#3)| | c . i . = [ 6000 * ( 1 + 15 / 100 ) 2 - 6000 ] = ( 6000 * 23 / 20 * 23 / 20 - 6000 ) = rs . 1935 . sum = ( 967.5 * 100 ) / ( 4 * 12 ) = rs . 2015.625 answer : d | gain |
math_qa__ArIol9vccI3JfNZz | Of the 80 people in a room, 1/4 are women. If 3/4 of the people are married, what is the maximum number of women in the room who could be unmarried? Answers.
A) 20 B) 24 C) 26 D) 28 E) 30 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">80 * (1/4)</gadget>
<output>20</output>
<result>A</result> | A | 20 | Of the 80 people in a room, 1/4 are women. If 3/4 of the people are married, what is the maximum number of women in the room who could be unmarried? | {
"A": "20",
"B": "24",
"C": "26",
"D": "28",
"E": "30"
} | multiply(80, divide(1, 4)) | divide(n1,n2)|multiply(n0,#0)| | "women = 1 / 4 * 80 = 20 married = 3 / 4 * 80 = 60 unmarried = 20 max ( un - married women ) = 20 answer a" | general |
math_qa__c9M61K9k42y0Mefu | If the mean of numbers 12, x, 42, 78 and 104 is 62, then what is the mean of 128, 255, 511, 1023 and x? Choose the most appropriate option
A) 395
B) 275
C) 355
D) 415
E) 398.2 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">62 * 5</gadget>
<output>310</output>
<gadget id="calculator">12 + 42</gadget>
<output>54</output>
<gadget id="calculator">54 + 78</gadget>
<output>132</output>
<gadget id="calculator">132 + 104</gadget>
<output>236</output>
<gadget id="calculator">310 - 236</gadget>
<output>74</output>
<gadget id="calculator">74 + 128</gadget>
<output>202</output>
<gadget id="calculator">202 + 255</gadget>
<output>457</output>
<gadget id="calculator">457 + 511</gadget>
<output>968</output>
<gadget id="calculator">968 + 1_023</gadget>
<output>1_991</output>
<gadget id="calculator">1_991 / 5</gadget>
<output>1_991/5 = around 398.2</output>
<result>E</result> | E | 398.2 | If the mean of numbers 12, x, 42, 78 and 104 is 62, then what is the mean of 128, 255, 511, 1023 and x? | {
"A": "395",
"B": "275",
"C": "355",
"D": "415",
"E": "398.2"
} | divide(add(add(add(add(subtract(multiply(62, add(const_4, const_1)), add(add(add(12, 42), 78), 104)), 128), 255), 511), 1023), add(const_4, const_1)) | add(const_1,const_4)|add(n0,n1)|add(n2,#1)|multiply(n4,#0)|add(n3,#2)|subtract(#3,#4)|add(n5,#5)|add(n6,#6)|add(n7,#7)|add(n8,#8)|divide(#9,#0)| | "the mean of numbers 12 , x , 42 , 78 and 104 is 62 : 12 + x + 42 + 78 + 104 = 62 * 5 - - > x = 74 ; so , the mean of 128 , 255 , 511 , 1023 and x is ( 128 + 255 + 511 + 1023 + 74 ) / 5 = 398.2 . answer : e ." | general |
math_qa__kGg4vNld9y5Qrt6i | If the perimeter of square region Q and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3 then the ratio of the area of R to the area of Q
Choose the correct answer
A) 25 : 16
B) 24 : 25
C) 5 : 6
D) 4 : 5
E) 4 : 9 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 / 4</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) ** 2</gadget>
<output>25/4 = around 6.25</output>
<gadget id="calculator">6 / (25/4)</gadget>
<output>24/25 = around 0.96</output>
<result>B</result> | B | 0.96 | If the perimeter of square region Q and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3 then the ratio of the area of R to the area of Q | {
"A": "25 : 16",
"B": "24 : 25",
"C": "5 : 6",
"D": "4 : 5",
"E": "4 : 9"
} | divide(rectangle_area(2, 3), square_area(divide(multiply(add(2, 3), const_2), const_4))) | add(n0,n1)|rectangle_area(n0,n1)|multiply(#0,const_2)|divide(#2,const_4)|square_area(#3)|divide(#1,#4) | we know perimeter of a square ( pq ) = 4 * side perimeter of a rectangle ( pr ) = 2 ( length + breath ) let us assume 40 to be the perimeter of the square ( since we know each side of a square is equal and the perimeter is divisible by 4 , also take in to account the length and breadth of the rectangle is in the ration 2 k : 3 k = 5 k ; we can assume such a number ) therefore , pq = pr = 40 area of the square = 100 sq . units we know 2 ( length + breadth ) = 40 i . e . length + breadth = 20 ( or 5 k = 20 given that l : b ( or b : l ) = 2 : 3 ) therefore length = 8 , breath = 12 area of the rectangle = 8 * 12 = 96 sq . units question asked = area of the rectangle : area of the square = 96 : 100 = = > 24 : 25 = b | geometry |
math_qa__oAVjqaeWCgJrl74r | The ratio of the present ages of Ramesh and mahesh is 2:5. 10 years hence, the ratio of their ages will be 10:15. Find the difference in their present ages? Select the correct option.
A) 7.5
B) 6
C) 5.5
D) 6.5
E) 5 | <gadget id="calculator">15 / 2</gadget>
<output>15/2 = around 7.5</output>
<result>A</result> | A | 7.5 | The ratio of the present ages of Ramesh and mahesh is 2:5. 10 years hence, the ratio of their ages will be 10:15. Find the difference in their present ages? | {
"A": "7.5",
"B": "6",
"C": "5.5",
"D": "6.5",
"E": "5"
} | divide(15, 2) | divide(n4,n0) | let the present ages of ramesh and mahesh be 2 x and 5 x years respectively . ( 2 x + 10 ) / ( 5 x + 10 ) = 10 / 15 6 x + 30 = 10 x + 20 = > x = 2.5 difference in their ages will be the same at all times . this difference = difference of their present ages = > 5 x - 2 x = 3 x = > 7.5 years answer : a | general |
math_qa__kvbeZHE42HsaiJkW | One boss decided to increase the salary of an employee by 5%. How much will he get if his salary was Rs.2000? Choose one.
A) 2200 B) 2000 C) 2100 D) 2300 E) none | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">2_000 * (1/20)</gadget>
<output>100</output>
<gadget id="calculator">2_000 + 100</gadget>
<output>2_100</output>
<result>C</result> | C | 2,100 | One boss decided to increase the salary of an employee by 5%. How much will he get if his salary was Rs.2000? | {
"A": "2200",
"B": "2000",
"C": "2100",
"D": "2300",
"E": "none"
} | add(2000, multiply(2000, divide(5, const_100))) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1) | solution : actual salary is 2000 rupees 5 % of 2000 = 2000 * 5 / 100 = 100 so 100 rupees increased = 2000 + 100 = 2100 he will get salary of 2100 answer c | general |
math_qa__G0CVAFH34ioVtbRM | In a certain accounting class of 100 students, 70% of the students took the final exam on the assigned day while the rest of the students took the exam on a make-up date. If the students on the assigned day had an average score of 60%, and the students on the make-up date had an average score of 80%, what was the average score for the entire class? Choose the correct choice from the following answers
A) 64 % B) 66 % C) 68 % D) 70 % E) 72 % | <gadget id="calculator">70 * 60</gadget>
<output>4_200</output>
<gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">80 * 30</gadget>
<output>2_400</output>
<gadget id="calculator">4_200 + 2_400</gadget>
<output>6_600</output>
<gadget id="calculator">6_600 / 100</gadget>
<output>66</output>
<result>B</result> | B | 66 | In a certain accounting class of 100 students, 70% of the students took the final exam on the assigned day while the rest of the students took the exam on a make-up date. If the students on the assigned day had an average score of 60%, and the students on the make-up date had an average score of 80%, what was the average score for the entire class? | {
"A": "64 %",
"B": "66 %",
"C": "68 %",
"D": "70 %",
"E": "72 %"
} | divide(add(multiply(70, 60), multiply(80, subtract(100, 70))), const_100) | multiply(n1,n2)|subtract(n0,n1)|multiply(n3,#1)|add(#0,#2)|divide(#3,const_100) | 70 % of the class scored 60 % and 30 % of the class scored 80 % . the difference between 60 % and 80 % is 20 % . the average will be 60 % + 0.3 ( 20 % ) = 66 % . the answer is b . | general |
math_qa__DzcVWqR4vaCIN8XE | If P(32, 6) = kC (32, 6), then what is the value of k? Choose the correct choice
A) 6 B) 32 C) 120 D) 720 E) 820 | <gadget id="calculator">factorial(32)</gadget>
<output>263_130_836_933_693_530_167_218_012_160_000_000</output>
<gadget id="calculator">32 - 6</gadget>
<output>26</output>
<gadget id="calculator">factorial(26)</gadget>
<output>403_291_461_126_605_635_584_000_000</output>
<gadget id="calculator">263_130_836_933_693_530_167_218_012_160_000_000 / 403_291_461_126_605_635_584_000_000</gadget>
<output>652_458_240</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">720 * 403_291_461_126_605_635_584_000_000</gadget>
<output>290_369_852_011_156_057_620_480_000_000</output>
<gadget id="calculator">263_130_836_933_693_530_167_218_012_160_000_000 / 290_369_852_011_156_057_620_480_000_000</gadget>
<output>906_192</output>
<gadget id="calculator">652_458_240 / 906_192</gadget>
<output>720</output>
<result>D</result> | D | 720 | If P(32, 6) = kC (32, 6), then what is the value of k? | {
"A": "6",
"B": "32",
"C": "120",
"D": "720",
"E": "820"
} | divide(divide(factorial(32), factorial(subtract(32, 6))), divide(factorial(32), multiply(factorial(6), factorial(subtract(32, 6))))) | factorial(n0)|factorial(n1)|subtract(n0,n1)|factorial(#2)|divide(#0,#3)|multiply(#1,#3)|divide(#0,#5)|divide(#4,#6) | solution since 32 p 6 = k 32 c 6 ⇒ 32 ! / ( 32 - 6 ) ! = k 32 ! / ( 32 - 6 ) ! ⇒ k = 6 ! = 720 . answer d | general |
math_qa__Ri0ROXRsHFUH1ein | For how many values of Q, is |||Q - 5| -10| -5| = 2?
(Those ls are mods)
Choose the correct choice from the following answers.
A) 0 B) 2 C) 4 D) 8 E) more than 8 | <gadget id="calculator">10 - 5</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<result>D</result> | D | 8 | For how many values of Q, is |||Q - 5| -10| -5| = 2?
(Those ls are mods) | {
"A": "0",
"B": "2",
"C": "4",
"D": "8",
"E": "more than 8"
} | subtract(add(subtract(10, 5), 5), 2) | subtract(n1,n0)|add(n0,#0)|subtract(#1,n3) | i think its 8 | | | q - 5 | - 10 | - 5 | = 2 let | q - 5 | = a which makes above | | a - 10 | - 5 | = 2 let | a - 10 | = b which makes | b - 5 | = 2 now for the above b can take 3 , 7 for every b = 3 a can have 13 , 7 and for b = 7 a can have 17 and 3 so ' a ' has four solutions 13 , 7 , 17 and 3 for a = 13 ; q has 18 or - 8 thus has 2 for every combination hence 4 x 2 = 8 answer d | general |
math_qa__ur5lyVK1673LGDcC | At Joes Steakhouse the hourly wage for a chef is 25% greater than that of a dishwasher, and the hourly wage of a dishwasher is half as much as the hourly wage of a manager. If a managers wage is $8.50 per hour, how much less than a manager does a chef earn each hour? Choices.
A) $ 1.40 B) $ 2.40 C) $ 3.40 D) $ 3.19 E) $ 5.40 | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(5/4) * (1/2)</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">1 - (5/8)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(3/8) * 8.5</gadget>
<output>3.1875</output>
<result>D</result> | D | 3.19 | At Joes Steakhouse the hourly wage for a chef is 25% greater than that of a dishwasher, and the hourly wage of a dishwasher is half as much as the hourly wage of a manager. If a managers wage is $8.50 per hour, how much less than a manager does a chef earn each hour? | {
"A": "$ 1.40",
"B": "$ 2.40",
"C": "$ 3.40",
"D": "$ 3.19",
"E": "$ 5.40"
} | multiply(subtract(const_1, multiply(divide(add(const_100, 25), const_100), divide(const_1, const_2))), 8.50) | add(n0,const_100)|divide(const_1,const_2)|divide(#0,const_100)|multiply(#2,#1)|subtract(const_1,#3)|multiply(n1,#4)| | "manager wages per hour = $ 8.50 dishwasher wages per hour = half of manager ' s wages . = 1 / 2 ( $ 8.50 ) = = > $ 4.25 chef wages per hour = 25 % greater than dishwasher wages - - > 25 % of $ 4.25 = ( 25 * ( $ 4.25 ) ) / 100 - - > ( $ 106.25 ) / 100 - - > $ 1.06 therefore , chef wages per hour = $ 4.25 + $ 1.06 = = > $ 5.31 difference of wages between manager and chef = $ 8.50 - $ 5.31 = = > $ 3.19 answer : d" | general |
math_qa__0SvKlQsOlVDusAuF | A manufacturer sells a pair of glasses to a wholesale dealer at a profit of 18%. The wholesaler sells the same to retailer at a profit of 20%. The retailer in turn sells them to a customer for Rs. 30.09, there by earning a profit of 25%. The cost price for the manufacturer is? Choose the correct choice from the following options
A) 33 B) 29 C) 17 D) 10 E) 16 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">30 + (9/100)</gadget>
<output>3_009/100 = around 30.09</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(3_009/100) / (5/4)</gadget>
<output>3_009/125 = around 24.072</output>
<gadget id="calculator">20 + 100</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(3_009/125) / (6/5)</gadget>
<output>1_003/50 = around 20.06</output>
<gadget id="calculator">100 + 18</gadget>
<output>118</output>
<gadget id="calculator">118 / 100</gadget>
<output>59/50 = around 1.18</output>
<gadget id="calculator">(1_003/50) / (59/50)</gadget>
<output>17</output>
<result>C</result> | C | 17 | A manufacturer sells a pair of glasses to a wholesale dealer at a profit of 18%. The wholesaler sells the same to retailer at a profit of 20%. The retailer in turn sells them to a customer for Rs. 30.09, there by earning a profit of 25%. The cost price for the manufacturer is? | {
"A": "33",
"B": "29",
"C": "17",
"D": "10",
"E": "16"
} | divide(divide(divide(add(multiply(add(const_1, const_2), divide(20, const_2)), divide(multiply(const_3, const_3), const_100)), divide(add(const_100, 25), const_100)), divide(add(20, const_100), const_100)), divide(add(const_100, 18), const_100)) | add(const_1,const_2)|add(n3,const_100)|add(n1,const_100)|add(n0,const_100)|divide(n1,const_2)|multiply(const_3,const_3)|divide(#5,const_100)|divide(#1,const_100)|divide(#2,const_100)|divide(#3,const_100)|multiply(#0,#4)|add(#6,#10)|divide(#11,#7)|divide(#12,#8)|divide(#13,#9)| | "explanation : let the cost price for the manufacturer be rs . x . then , 125 % of 120 % of 118 % of x = 30.09 . 125 / 100 * 120 / 100 * 118 / 100 * x = 3009 / 100 177 / 100 x = 3009 / 100 = > x = 17 answer : c" | gain |
math_qa__D1Wamv5h1l7PCPqN | In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is? Select the correct option:
A) 39 yr B) 42 yr C) 45 yr D) 32 yr E) 50 yr | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">30 + 9</gadget>
<output>39</output>
<result>A</result> | A | 39 | In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is? | {
"A": "39 yr",
"B": "42 yr",
"C": "45 yr",
"D": "32 yr",
"E": "50 yr"
} | add(add(multiply(const_2, 10), 10), 9) | multiply(n0,const_2)|add(n0,#0)|add(n2,#1)| | "let b ' s present age = x years then a ' s present age = x + 9 years x + 9 + 10 = 2 ( x - 10 ) x + 19 = 2 x - 20 x = 39 years answer is a" | general |
math_qa__egrcuEQ1KbHu7dmx | Little Krish had $200.50. He spent $35.25 on sweets and gave to his two friends $25.20 each. How much money was left?
Choose the correct answer:
A) $ 220.85 B) $ 214.85 C) $ 114.85 D) $ 314.85 E) $ 104.85 | <gadget id="calculator">200.5 - 35.25</gadget>
<output>165.25</output>
<gadget id="calculator">25.2 * 2</gadget>
<output>50.4</output>
<gadget id="calculator">165.25 - 50.4</gadget>
<output>114.85</output>
<result>C</result> | C | 114.85 | Little Krish had $200.50. He spent $35.25 on sweets and gave to his two friends $25.20 each. How much money was left? | {
"A": "$ 220.85",
"B": "$ 214.85",
"C": "$ 114.85",
"D": "$ 314.85",
"E": "$ 104.85"
} | subtract(subtract(200.5, 35.25), multiply(25.2, const_2)) | multiply(n2,const_2)|subtract(n0,n1)|subtract(#1,#0) | krish spent and gave to his two friends a total of 35.25 + 25.20 + 25.20 = $ 85.65 money left 200.50 - 85.65 = $ 114.85 correct answer is c ) $ 114.85 | general |
math_qa__tiEWzuy0rAyc4X2Z | Pat, Kate, and Mark charged a total of 117 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate? Options:
A) 18 B) 36 C) 72 D) 90 E) 65 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 + (1/3)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(4/3) + (1/6)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">117 / (3/2)</gadget>
<output>78</output>
<gadget id="calculator">78 / 6</gadget>
<output>13</output>
<gadget id="calculator">78 - 13</gadget>
<output>65</output>
<result>E</result> | E | 65 | Pat, Kate, and Mark charged a total of 117 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate? | {
"A": "18",
"B": "36",
"C": "72",
"D": "90",
"E": "65"
} | subtract(divide(117, add(add(1, divide(1, 3)), divide(1, multiply(3, const_2)))), divide(divide(117, add(add(1, divide(1, 3)), divide(1, multiply(3, const_2)))), multiply(3, const_2))) | divide(n1,n2)|multiply(n2,const_2)|add(n1,#0)|divide(n1,#1)|add(#2,#3)|divide(n0,#4)|divide(#5,#1)|subtract(#5,#6)| | "65 all u do is do 2 : 1 : 6 = > 2 x + x + 6 x = 117 = > x = 13 26 : 13 : 78 78 - 13 = 65 answer e" | general |
math_qa__G28vEwNuTGpGMLRA | A school has 4 section of Chemistry in Class X having 65, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student. Answers.
A) 50.25 B) 52.25 C) 51.95 D) 53.25 E) none of the above | <gadget id="calculator">65 * 50</gadget>
<output>3_250</output>
<gadget id="calculator">35 * 60</gadget>
<output>2_100</output>
<gadget id="calculator">3_250 + 2_100</gadget>
<output>5_350</output>
<gadget id="calculator">45 * 55</gadget>
<output>2_475</output>
<gadget id="calculator">5_350 + 2_475</gadget>
<output>7_825</output>
<gadget id="calculator">42 * 45</gadget>
<output>1_890</output>
<gadget id="calculator">7_825 + 1_890</gadget>
<output>9_715</output>
<gadget id="calculator">65 + 35</gadget>
<output>100</output>
<gadget id="calculator">100 + 45</gadget>
<output>145</output>
<gadget id="calculator">145 + 42</gadget>
<output>187</output>
<gadget id="calculator">9_715 / 187</gadget>
<output>9_715/187 = around 51.951872</output>
<result>C</result> | C | 51.95 | A school has 4 section of Chemistry in Class X having 65, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student. | {
"A": "50.25",
"B": "52.25",
"C": "51.95",
"D": "53.25",
"E": "none of the above"
} | divide(add(add(add(multiply(65, 50), multiply(35, 60)), multiply(45, 55)), multiply(42, 45)), add(add(add(65, 35), 45), 42)) | add(n1,n2)|multiply(n1,n5)|multiply(n2,n6)|multiply(n3,n7)|multiply(n3,n4)|add(#1,#2)|add(n3,#0)|add(#5,#3)|add(n4,#6)|add(#7,#4)|divide(#9,#8) | required average marks = 65 ã — 50 + 35 ã — 60 + 45 ã — 55 + 42 ã — 45 / 65 + 35 + 45 + 42 = 3250 + 2100 + 2475 + 1890 / 187 = 9715 â „ 187 = 51.95 answer c | general |
math_qa__z4V95n4e1Y5lce6c | What would be the perimeter of the square whose side is equal to the diameter of the circle whose perimeter is 52.5 cm? Choose the correct choice
A) 52.5 B) 60.2 C) 66.8 D) 74.25 E) 80.12 | <gadget id="calculator">52.5 / pi</gadget>
<output>52.5/pi = around 16.711269</output>
<gadget id="calculator">4 * (52.5/pi)</gadget>
<output>210.0/pi = around 66.845076</output>
<result>C</result> | C | 66.8 | What would be the perimeter of the square whose side is equal to the diameter of the circle whose perimeter is 52.5 cm? | {
"A": "52.5",
"B": "60.2",
"C": "66.8",
"D": "74.25",
"E": "80.12"
} | square_perimeter(divide(52.5, const_pi)) | divide(n0,const_pi)|square_perimeter(#0) | diameter of the circle = perimeter / ï € = 52.5 x 7 / 22 = 16.70 perimeter of the square = 16.70 x 4 = 66.8 cm answer : c | geometry |
math_qa__Z7ZThBIcC7eqXgqe | A basket of 1430 apples is divided equally among a group of apple lovers. If 45 people join the group, each apple lover would receive 9 apples less. How many apples did each person get before 45 people joined the feast? Choose the correct choice:
A) 20 . B) 21 C) 22 D) 23 E) 24 | <gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">1_430 / 22</gadget>
<output>65</output>
<gadget id="calculator">65 + 45</gadget>
<output>110</output>
<gadget id="calculator">1_430 / 110</gadget>
<output>13</output>
<gadget id="calculator">13 + 9</gadget>
<output>22</output>
<result>C</result> | C | 22 | A basket of 1430 apples is divided equally among a group of apple lovers. If 45 people join the group, each apple lover would receive 9 apples less. How many apples did each person get before 45 people joined the feast? | {
"A": "20 .",
"B": "21",
"C": "22",
"D": "23",
"E": "24"
} | add(divide(1430, add(divide(1430, add(add(const_10, const_10), const_2)), 45)), 9) | add(const_10,const_10)|add(#0,const_2)|divide(n0,#1)|add(n1,#2)|divide(n0,#3)|add(n2,#4) | if 1430 is divisible by anyone of the answer choices . a . 1430 / 20 = 143 / 2 b 1430 / 21 = 1430 / 21 c 1430 / 22 = 65 if 1430 apple was divided among 65 people , each would have received 22 . after addition of 45 people the answer should be 13 . 1430 / 110 = 13 . c is the answer . | general |
math_qa__ZChUGBApoKfARsJo | A merchant purchased a jacket for $42 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 30 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale? Choose the correct choice:
A) $ 0
B) $ 3
C) $ 6
D) $ 12
E) $ 15 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">42 / (7/10)</gadget>
<output>60</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">60 * (4/5)</gadget>
<output>48</output>
<gadget id="calculator">48 - 42</gadget>
<output>6</output>
<result>C</result> | C | 6 | A merchant purchased a jacket for $42 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 30 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale? | {
"A": "$ 0",
"B": "$ 3",
"C": "$ 6",
"D": "$ 12",
"E": "$ 15"
} | subtract(multiply(divide(42, subtract(const_1, divide(30, const_100))), subtract(const_1, divide(20, const_100))), 42) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|divide(n0,#2)|multiply(#4,#3)|subtract(#5,n0) | actual cost = $ 42 sp = actual cost + mark up = actual cost + 30 % sp = 42 * 100 / 70 on sale sp = 80 / 100 ( 42 * 100 / 70 ) = 48 gross profit = $ 6 answer is c | gain |
math_qa__LepMRDyE7wGQqwMi | Running at their respective constant rate, machine X takes 2 days longer to produce w widgets than machines Y. AT these rates, if the two machines together produce 5w/4 widgets in 3 days, how many days would it take machine X alone to produce 5w widgets. Choose the correct option: A) 4 B) 6 C) 8 D) 30 E) 12 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<result>D</result> | D | 30 | Running at their respective constant rate, machine X takes 2 days longer to produce w widgets than machines Y. AT these rates, if the two machines together produce 5w/4 widgets in 3 days, how many days would it take machine X alone to produce 5w widgets. | {
"A": "4",
"B": "6",
"C": "8",
"D": "30",
"E": "12"
} | multiply(multiply(5, 2), 3) | multiply(n0,n4)|multiply(n3,#0)| | "i am getting 12 . e . hope havent done any calculation errors . . approach . . let y = no . of days taken by y to do w widgets . then x will take y + 2 days . 1 / ( y + 2 ) + 1 / y = 5 / 12 ( 5 / 12 is because ( 5 / 4 ) w widgets are done in 3 days . so , x widgets will be done in 12 / 5 days or 5 / 12 th of a widget in a day ) solving , we have y = 4 = > x takes 6 days to doing x widgets . so , he will take 30 days to doing 5 w widgets . answer : d" | general |
math_qa__ScIRnMz4kMfUpTgy | Two employees X and Y are paid a total of Rs. 616 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? Choose the most appropriate option.
A) s . 250 B) s . 280 C) s . 290 D) s . 299 E) s . 300 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">616 * 10</gadget>
<output>6_160</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">6_160 / 22</gadget>
<output>280</output>
<result>B</result> | B | 280 | Two employees X and Y are paid a total of Rs. 616 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? | {
"A": "s . 250",
"B": "s . 280",
"C": "s . 290",
"D": "s . 299",
"E": "s . 300"
} | divide(multiply(616, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4)| | "let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 616 but x = 120 % of y = 120 y / 100 = 12 y / 10 ∴ 12 y / 10 + y = 616 ⇒ y [ 12 / 10 + 1 ] = 616 ⇒ 22 y / 10 = 616 ⇒ 22 y = 6160 ⇒ y = 6160 / 22 = 560 / 2 = rs . 280 b" | general |
math_qa__teQCS5RLdhbpvtrG | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 5 inches by 24 inches and Jordan's rectangle is 8 inches long, how wide is Jordan's rectangle, in inches? Choose the most appropriate option
A) 25 B) 23 C) 22 D) 15 E) 18 | <gadget id="calculator">5 * 24</gadget>
<output>120</output>
<gadget id="calculator">120 / 8</gadget>
<output>15</output>
<result>D</result> | D | 15 | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 5 inches by 24 inches and Jordan's rectangle is 8 inches long, how wide is Jordan's rectangle, in inches? | {
"A": "25",
"B": "23",
"C": "22",
"D": "15",
"E": "18"
} | divide(rectangle_area(5, 24), 8) | rectangle_area(n0,n1)|divide(#0,n2)| | "area of carol ' s rectangle = 24 * 5 = 120 let width of jordan ' s rectangle = w since , the areas are equal 8 w = 120 = > w = 15 answer d" | geometry |
math_qa__KfAO9TtmdyoaR46w | A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 546 pounds after processing, how many pounds did it weigh before processing? Pick one.
A) 191 B) 355 C) 737 D) 840 E) 1,560 | <gadget id="calculator">546 * 100</gadget>
<output>54_600</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">54_600 / 65</gadget>
<output>840</output>
<result>D</result> | D | 840 | A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 546 pounds after processing, how many pounds did it weigh before processing? | {
"A": "191",
"B": "355",
"C": "737",
"D": "840",
"E": "1,560"
} | divide(multiply(546, const_100), subtract(const_100, 35)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "let weight of side of beef before processing = x ( 65 / 100 ) * x = 546 = > x = ( 546 * 100 ) / 65 = 840 answer d" | gain |
math_qa__jWze2FeISdceBMPZ | Jacob is now 14 years younger than Michael. If 9 years from now Michael will be twice as old as Jacob, how old will Jacob be in 4 years? Choose the correct choice from the following choices.
A) 3 B) 7 C) 9 D) 21 E) 25 | <gadget id="calculator">14 + 9</gadget>
<output>23</output>
<gadget id="calculator">2 * 9</gadget>
<output>18</output>
<gadget id="calculator">23 - 18</gadget>
<output>5</output>
<gadget id="calculator">4 + 5</gadget>
<output>9</output>
<result>C</result> | C | 9 | Jacob is now 14 years younger than Michael. If 9 years from now Michael will be twice as old as Jacob, how old will Jacob be in 4 years? | {
"A": "3",
"B": "7",
"C": "9",
"D": "21",
"E": "25"
} | add(4, subtract(add(14, 9), multiply(const_2, 9))) | add(n0,n1)|multiply(n1,const_2)|subtract(#0,#1)|add(n2,#2)| | "jacob = x years , michael = x + 14 years 9 years from now , 2 ( x + 9 ) = x + 23 2 x + 18 = x + 23 x = 5 x + 4 = 9 years answer c" | general |
math_qa__FtjaWNxBuhKwZ4bG | A bag consists of 60 marbles, of which 5 are blue, 9 are red, and the remainder are white. If Lisa is to select a marble from the bag at random, what is the probability that the marble will be red or white? Options: A) 11 / 12 B) 2 / 4 C) 1 / 4 D) 1 / 8 E) 1 / 16 | <gadget id="calculator">5 + 9</gadget>
<output>14</output>
<gadget id="calculator">60 - 14</gadget>
<output>46</output>
<gadget id="calculator">46 + 9</gadget>
<output>55</output>
<gadget id="calculator">55 / 60</gadget>
<output>11/12 = around 0.916667</output>
<result>A</result> | A | 0.916667 | A bag consists of 60 marbles, of which 5 are blue, 9 are red, and the remainder are white. If Lisa is to select a marble from the bag at random, what is the probability that the marble will be red or white? | {
"A": "11 / 12",
"B": "2 / 4",
"C": "1 / 4",
"D": "1 / 8",
"E": "1 / 16"
} | divide(add(subtract(60, add(5, 9)), 9), 60) | add(n1,n2)|subtract(n0,#0)|add(n2,#1)|divide(#2,n0) | bag consists of 60 marbles , of which 5 are blue , 9 are red remainder are white . so , white = 60 - 5 - 9 = 46 . probability that the marble will be red or white = probability that the marble will be red + probability that the marble will be white probability that the marble will be red or white = 9 / 60 + 46 / 60 = 55 / 60 = 11 / 12 hence , answer will be a . | probability |
math_qa__xh2DbXBm2X9cqA8S | If 6 women can color 360 m long cloth in 3 days, then 5 women can color 100 m long cloth in? Choose the correct choice from the following answers:
A) 2 days B) 3 days C) 2.5 days D) 4 days E) 1 day | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">360 / 18</gadget>
<output>20</output>
<gadget id="calculator">5 * 20</gadget>
<output>100</output>
<gadget id="calculator">100 / 100</gadget>
<output>1</output>
<result>E</result> | E | 1 | If 6 women can color 360 m long cloth in 3 days, then 5 women can color 100 m long cloth in? | {
"A": "2 days",
"B": "3 days",
"C": "2.5 days",
"D": "4 days",
"E": "1 day"
} | divide(100, multiply(5, divide(360, multiply(6, 3)))) | multiply(n0,n2)|divide(n1,#0)|multiply(n3,#1)|divide(n4,#2)| | "the length of cloth painted by one woman in one day = 360 / 6 × 3 = 20 m no . of days required to paint 100 m cloth by 5 women = 100 / 5 × 20 = 1 day answer : e" | physics |
math_qa__F4o5GJMuVk4j3ca9 | When a certain number X is divided by 95, the remainder is 31. What is the remainder when X is divided by 19? Choose the correct choice from the following answers
A) 10 B) 11 C) 12 D) 15 E) 17 | <gadget id="calculator">31 % 19</gadget>
<output>12</output>
<result>C</result> | C | 12 | When a certain number X is divided by 95, the remainder is 31. What is the remainder when X is divided by 19? | {
"A": "10",
"B": "11",
"C": "12",
"D": "15",
"E": "17"
} | reminder(31, 19) | reminder(n1,n2)| | "let possible value of x is 126 least possible value of x / 19 is 126 / 19 = > 6 quotient with remainder 12 thus answer is ( c ) 12" | general |
math_qa__R3vYQOOd3jcHdT4V | Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles? Options:
A) 2000 B) 2888 C) 2667 D) 2999 E) 2122 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">990 * (1/10)</gadget>
<output>99</output>
<gadget id="calculator">990 + 99</gadget>
<output>1_089</output>
<gadget id="calculator">990 - 99</gadget>
<output>891</output>
<gadget id="calculator">1_089 + 891</gadget>
<output>1_980</output>
<result>A</result> | A | 2,000 | Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles? | {
"A": "2000",
"B": "2888",
"C": "2667",
"D": "2999",
"E": "2122"
} | add(add(990, multiply(990, divide(10, const_100))), subtract(990, multiply(990, divide(10, const_100)))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)|subtract(n0,#1)|add(#2,#3) | ( 10 * 10 ) / 100 = 1 % loss 100 - - - 99 ? - - - 1980 = > rs . 2000 answer : a | gain |
math_qa__M7Zv0V1uAP6jFOKE | A company produces 72000 bottles of water everyday. If a case can hold 9 bottles of water .How many cases are required by the company to hold its one day production Pick one.
A) 2000 B) 4500 C) 5000 D) 8000 E) 9000 | <gadget id="calculator">72_000 / 9</gadget>
<output>8_000</output>
<result>D</result> | D | 8,000 | A company produces 72000 bottles of water everyday. If a case can hold 9 bottles of water .How many cases are required by the company to hold its one day production | {
"A": "2000",
"B": "4500",
"C": "5000",
"D": "8000",
"E": "9000"
} | divide(72000, 9) | divide(n0,n1)| | "number of bottles that can be held in a case = 9 . number of cases required to hold 72000 bottles = 72000 / 9 = 8000 cases . so the answer is d = 8000" | physics |
math_qa__75BOjjCEmm5wVJtL | A number is doubled and 5 is added. If the resultant is trebled, it becomes 135. What is that number? Choose the correct answer
A) 12 B) 29 C) 20 D) 15 E) 99 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">135 - 15</gadget>
<output>120</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">120 / 6</gadget>
<output>20</output>
<result>C</result> | C | 20 | A number is doubled and 5 is added. If the resultant is trebled, it becomes 135. What is that number? | {
"A": "12",
"B": "29",
"C": "20",
"D": "15",
"E": "99"
} | divide(subtract(135, multiply(const_3, 5)), multiply(const_3, const_2)) | multiply(n0,const_3)|multiply(const_2,const_3)|subtract(n1,#0)|divide(#2,#1)| | "explanation : let the number be x . therefore , 3 ( 2 x + 5 ) = 135 6 x + 15 = 135 6 x = 120 x = 20 answer : c" | general |
math_qa__gphbAdvdilFR4ZqH | The average (arithmetic mean) of 10, 30, and 50 is 8 more than the average of 20, 40, and x. What is x? Pick
A) 2 B) 4 C) 6 D) 8 E) 10 | <gadget id="calculator">10 + 30</gadget>
<output>40</output>
<gadget id="calculator">40 + 50</gadget>
<output>90</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 + 20</gadget>
<output>44</output>
<gadget id="calculator">44 + 40</gadget>
<output>84</output>
<gadget id="calculator">90 - 84</gadget>
<output>6</output>
<result>C</result> | C | 6 | The average (arithmetic mean) of 10, 30, and 50 is 8 more than the average of 20, 40, and x. What is x? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | subtract(add(add(10, 30), 50), add(add(multiply(8, const_3), 20), 40)) | add(n0,n1)|multiply(n3,const_3)|add(n2,#0)|add(n4,#1)|add(n5,#3)|subtract(#2,#4)| | "the average of 10 , 30 , and 50 is 30 . the average of 20 , 40 and x is 22 . then 20 + 40 + x = 66 . x = 6 . the answer is c ." | general |
math_qa__PyI303XUSXQQKzZ6 | What is the square root of 625, divided by 5? Pick one.
A) 9 B) 36 C) 5 D) 6 E) 1 | <gadget id="calculator">625 ** (1/2)</gadget>
<output>25</output>
<gadget id="calculator">25 / 5</gadget>
<output>5</output>
<result>C</result> | C | 5 | What is the square root of 625, divided by 5? | {
"A": "9",
"B": "36",
"C": "5",
"D": "6",
"E": "1"
} | divide(sqrt(625), 5) | sqrt(n0)|divide(#0,n1) | square root is a number times itself square root of 625 = 25 , 25 / 5 = 5 ( c ) 5 | other |
math_qa__pr38nbM8hnjqTlfw | Calculate the sum of first 39 natural numbers.
Answers.
A) 780 B) 891 C) 812 D) 847 E) 890 | <gadget id="calculator">39 + 1</gadget>
<output>40</output>
<gadget id="calculator">39 / 2</gadget>
<output>39/2 = around 19.5</output>
<gadget id="calculator">40 * (39/2)</gadget>
<output>780</output>
<result>A</result> | A | 780 | Calculate the sum of first 39 natural numbers. | {
"A": "780",
"B": "891",
"C": "812",
"D": "847",
"E": "890"
} | multiply(add(39, const_1), divide(39, const_2)) | add(n0,const_1)|divide(n0,const_2)|multiply(#0,#1)| | "solution we know that ( 1 + 2 + 3 + . . . . . + 39 ) = n ( n + 1 ) / 2 therefore ( 1 + 2 + 3 + . . . . + 39 ) = ( 39 × 40 / 2 ) = 780 . answer a" | general |
math_qa__SbpebvtBUupF6TaO | If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
Choose the correct option:
A) 120 cm 2 B) 130 cm 2 C) 312 cm 2 D) 315 cm 2 E) none of these | <gadget id="calculator">24 * 10</gadget>
<output>240</output>
<gadget id="calculator">240 / 2</gadget>
<output>120</output>
<result>A</result> | A | 120 | If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area? | {
"A": "120 cm 2",
"B": "130 cm 2",
"C": "312 cm 2",
"D": "315 cm 2",
"E": "none of these"
} | divide(multiply(24, 10), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 26 cm , 24 cm and 10 cm is right angled , where the hypotenuse is 26 cm . area of the triangle = 1 / 2 * 24 * 10 = 120 cm 2 answer : a" | geometry |
math_qa__hAoEWKYytzLez6N9 | N and M are each 3-digit integers. Each of the numbers 1, 2, 3,4,5 and 6 is a digit of either N or M. What is the smallest possible positive difference between N and M? Choose the correct option
A) 59 B) 49 C) 58 D) 113 E) 131 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 - 1</gadget>
<output>49</output>
<result>B</result> | B | 49 | N and M are each 3-digit integers. Each of the numbers 1, 2, 3,4,5 and 6 is a digit of either N or M. What is the smallest possible positive difference between N and M? | {
"A": "59",
"B": "49",
"C": "58",
"D": "113",
"E": "131"
} | subtract(subtract(const_100, multiply(subtract(6, 1), const_10)), const_1) | subtract(n5,n1)|multiply(#0,const_10)|subtract(const_100,#1)|subtract(#2,const_1)| | "you have 6 digits : 1,2 , 3 , 4 , 5 , 6 each digit needs to be used to make two 3 digit numbers . this means that we will use each of the digits only once and in only one of the numbers . the numbers need to be as close to each other as possible . the numbers can not be equal so the greater number needs to be as small as possible and the smaller number needs to be as large as possible to be close to each other . the first digit ( hundreds digit ) of both numbers should be consecutive integers now let ' s think about the next digit ( the tens digit ) . to minimize the difference between the numbers , the tens digit of the greater number should be as small as possible and the tens digit of the smaller number should be as large as possible . so let ' s not use 1 and 6 in the hundreds places and reserve them for the tens places now what are the options ? try and make a pair with ( 2 * * and 3 * * ) . make the 2 * * number as large as possible and make the 3 * * number as small as possible . 265 and 314 ( difference is 49 ) or try and make a pair with ( 4 * * and 5 * * ) . make the 4 * * number as large as possible and make the 5 * * number as small as possible . we get 463 and 512 ( difference is 49 ) b" | general |
math_qa__U7LdPvVuLii8z2mh | Of the 150 people at a party, 70 were women, and 40 women tried the appetizer. If 50 people did not try the appetizer, what is the total number of men who tried the appetizer? Pick one.
A) 40 B) 50 C) 60 D) 70 E) 80 | <gadget id="calculator">150 - 50</gadget>
<output>100</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<result>C</result> | C | 60 | Of the 150 people at a party, 70 were women, and 40 women tried the appetizer. If 50 people did not try the appetizer, what is the total number of men who tried the appetizer? | {
"A": "40",
"B": "50",
"C": "60",
"D": "70",
"E": "80"
} | subtract(subtract(150, 50), 40) | subtract(n0,n3)|subtract(#0,n2)| | "total people at party = 150 women = 70 so men 150 - 70 = 80 no . of pple who tried appetizer = 150 - 50 ( given info ) = 100 no of women who tried appetizer = 40 so remaining ppl ( men ) who tried the appetizer = 100 - 40 = 60 correct option c" | general |
math_qa__yq7N9vwGAso3fD6U | The breath of a rectangular landscape is 6 times its length. There is a playground in it whose area is 4200 square mtr & which is 1/7 th of the total landscape. What is the breath of the landscape? Choose the correct choice from the following options:
A) 520
B) 420
C) 320
D) 550
E) 450 | <gadget id="calculator">4_200 * 7</gadget>
<output>29_400</output>
<gadget id="calculator">29_400 / 6</gadget>
<output>4_900</output>
<gadget id="calculator">4_900 ** (1/2)</gadget>
<output>70</output>
<gadget id="calculator">70 * 6</gadget>
<output>420</output>
<result>B</result> | B | 420 | The breath of a rectangular landscape is 6 times its length. There is a playground in it whose area is 4200 square mtr & which is 1/7 th of the total landscape. What is the breath of the landscape? | {
"A": "520",
"B": "420",
"C": "320",
"D": "550",
"E": "450"
} | multiply(sqrt(divide(multiply(4200, 7), 6)), 6) | multiply(n1,n3)|divide(#0,n0)|sqrt(#1)|multiply(n0,#2)| | "sol . 6 x * x = 7 * 4200 x = 70 length = 6 * 70 = 420 b" | geometry |
math_qa__50xNsM8ZVyAc9hlU | A farmer divides his herd of x cows among his 4 sons so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 7 cows. Then x is equal to Choose the correct choice from the following answers
A) 100
B) 140
C) 180
D) 160
E) 120 | <gadget id="calculator">7 * 4</gadget>
<output>28</output>
<gadget id="calculator">28 * 4</gadget>
<output>112</output>
<gadget id="calculator">112 + 12</gadget>
<output>124</output>
<gadget id="calculator">10 + 124</gadget>
<output>134</output>
<result>B</result> | B | 140 | A farmer divides his herd of x cows among his 4 sons so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 7 cows. Then x is equal to | {
"A": "100",
"B": "140",
"C": "180",
"D": "160",
"E": "120"
} | add(const_10, add(multiply(multiply(7, 4), const_4), const_12)) | multiply(n0,n1)|multiply(#0,const_4)|add(#1,const_12)|add(#2,const_10) | no . of cows : : x 1 st son : x / 2 2 nd son : x / 4 3 rd son : x / 5 4 th son : 7 ( x ) + ( x / 4 ) + ( x / 5 ) + 7 = x = > x - ( 19 x / 20 ) = 7 = > ( 20 x - 19 x ) / 20 = 7 = > x = 140 answer : b | general |
math_qa__Did2m4QsWCI1w4on | A trained covered x km at 40 kmph and another 4x km at 20 kmph. Find the average speed of the train in covering the entire 3x km. Choose the correct choice from the following answers: A) 11.33 kmph B) 12.33 kmph C) 13.33 kmph D) 14.33 kmph E) 23.33 kmph | <gadget id="calculator">40 * 3</gadget>
<output>120</output>
<gadget id="calculator">40 / 40</gadget>
<output>1</output>
<gadget id="calculator">4 * 40</gadget>
<output>160</output>
<gadget id="calculator">160 / 20</gadget>
<output>8</output>
<gadget id="calculator">1 + 8</gadget>
<output>9</output>
<gadget id="calculator">120 / 9</gadget>
<output>40/3 = around 13.333333</output>
<result>C</result> | C | 13.33 | A trained covered x km at 40 kmph and another 4x km at 20 kmph. Find the average speed of the train in covering the entire 3x km. | {
"A": "11.33 kmph",
"B": "12.33 kmph",
"C": "13.33 kmph",
"D": "14.33 kmph",
"E": "23.33 kmph"
} | divide(multiply(40, 3), add(divide(40, 40), divide(multiply(4, 40), 20))) | divide(n0,n0)|multiply(n0,n3)|multiply(n0,n1)|divide(#2,n2)|add(#0,#3)|divide(#1,#4)| | "total time taken = x / 40 + 4 x / 20 hours = 9 x / 40 hours average speed = 3 x / ( 9 x / 40 ) = 13.33 kmph answer : c" | general |
math_qa__NlbtpKQ4D6xoUnNj | The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $93 per day. What was his wage on the 8th day?
Options: A) $ 83 B) $ 90 C) $ 92 D) $ 97 E) $ 104 | <gadget id="calculator">90 * 15</gadget>
<output>1_350</output>
<gadget id="calculator">87 * 7</gadget>
<output>609</output>
<gadget id="calculator">93 * 7</gadget>
<output>651</output>
<gadget id="calculator">609 + 651</gadget>
<output>1_260</output>
<gadget id="calculator">1_350 - 1_260</gadget>
<output>90</output>
<result>B</result> | B | 90 | The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $93 per day. What was his wage on the 8th day? | {
"A": "$ 83",
"B": "$ 90",
"C": "$ 92",
"D": "$ 97",
"E": "$ 104"
} | subtract(multiply(90, 15), add(multiply(87, 7), multiply(93, 7))) | multiply(n0,n1)|multiply(n2,n3)|multiply(n2,n5)|add(#1,#2)|subtract(#0,#3)| | "average daily wage of a worker for 15 consecutive working days = 90 $ during the first 7 days , the daily average daily wage = 87 $ during the last 7 days , the daily average daily wage = 93 $ wage on 8 th day = 90 * 15 - ( 87 * 7 + 93 * 7 ) = 1350 - ( 609 + 651 ) = 1350 - 1260 = 90 answer b" | physics |
math_qa__iVA1VnILeRpCHpNR | A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 8 managers, if there are 2 managers who refuse to attend the meeting together. Choose the correct choice from the following
A) 48
B) 55
C) 58
D) 62
E) 70 | <gadget id="calculator">binomial(8, 4)</gadget>
<output>70</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">binomial(6, 2)</gadget>
<output>15</output>
<gadget id="calculator">70 - 15</gadget>
<output>55</output>
<result>B</result> | B | 55 | A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 8 managers, if there are 2 managers who refuse to attend the meeting together. | {
"A": "48",
"B": "55",
"C": "58",
"D": "62",
"E": "70"
} | subtract(choose(8, 4), choose(subtract(8, 2), 2)) | choose(n1,n0)|subtract(n1,n2)|choose(#1,n2)|subtract(#0,#2)| | "the total number of ways to choose 4 managers is 8 c 4 = 70 we need to subtract the number of groups which include the two managers , which is 6 c 2 = 15 . 70 - 15 = 55 the answer is b ." | probability |
math_qa__nJUFHbcQbVAKXdtQ | A factory produces 6000 toys per week. If the workers at this factory work 4 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? Choose the correct choice from the following options
A) 4436 toys B) 1500 toys C) 6113 toys D) 2354 toys E) 1375 toys | <gadget id="calculator">6_000 / 4</gadget>
<output>1_500</output>
<result>B</result> | B | 1,500 | A factory produces 6000 toys per week. If the workers at this factory work 4 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? | {
"A": "4436 toys",
"B": "1500 toys",
"C": "6113 toys",
"D": "2354 toys",
"E": "1375 toys"
} | divide(6000, 4) | divide(n0,n1)| | "to find the number of toys produced every day , we divide the total number of toys produced in one week ( of 4 days ) by 4 . 6000 / 4 = 1500 toys correct answer b" | physics |
math_qa__dJzoVLTPmYyNxaZs | a box contains 100 balls , numbered from 1 to 100 . if 3 balls are selected at random and with replacement from the box , what is the probability that the sum of the 3 numbers on the balls selected from the box will be odd ?
Choose one.
A) 1 / 4 B) 3 / 8 C) 1 / 2 D) 5 / 8 E) 3 / 4 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 3</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/2) ** 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">3 * (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * (1/2)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(1/8) + (3/8)</gadget>
<output>1/2 = around 0.5</output>
<result>C</result> | C | 0.5 | a box contains 100 balls , numbered from 1 to 100 . if 3 balls are selected at random and with replacement from the box , what is the probability that the sum of the 3 numbers on the balls selected from the box will be odd ? | {
"A": "1 / 4",
"B": "3 / 8",
"C": "1 / 2",
"D": "5 / 8",
"E": "3 / 4"
} | add(power(divide(1, const_2), const_3), multiply(multiply(3, power(divide(1, const_2), const_2)), divide(1, const_2))) | divide(n1,const_2)|power(#0,const_2)|power(#0,const_3)|multiply(n3,#1)|multiply(#0,#3)|add(#4,#2) | the sum of the three numbers on the balls selected from the box to be odd one should select either three odd numbered balls ( odd + odd + odd = odd ) or two even numbered balls and one odd numbered ball ( even + even + odd = odd ) ; p ( ooo ) = ( 1 / 2 ) ^ 3 ; p ( eeo ) = 3 * ( 1 / 2 ) ^ 2 * 1 / 2 = 3 / 8 ( you should multiply by 3 as the scenario of two even numbered balls and one odd numbered ball can occur in 3 different ways : eeo , eoe , or oee ) ; so finally p = 1 / 8 + 3 / 8 = 1 / 2 . answer : c . | general |
math_qa__QdckwRk4Vvfw8X5Y | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 2 litres from vessel P is mixed with 8 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? Select the correct option.
A) 33 : 1 B) 33 : 7 C) 33 : 8 D) 33 : 5 E) 33 : 2 | <gadget id="calculator">62.5 * 2</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">87.5 * 8</gadget>
<output>700</output>
<gadget id="calculator">700 / 100</gadget>
<output>7</output>
<gadget id="calculator">(5/4) + 7</gadget>
<output>33/4 = around 8.25</output>
<gadget id="calculator">2 - (5/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">8 - 7</gadget>
<output>1</output>
<gadget id="calculator">(3/4) + 1</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">(33/4) / (7/4)</gadget>
<output>33/7 = around 4.714286</output>
<result>B</result> | B | 4.714286 | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 2 litres from vessel P is mixed with 8 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? | {
"A": "33 : 1",
"B": "33 : 7",
"C": "33 : 8",
"D": "33 : 5",
"E": "33 : 2"
} | divide(add(divide(multiply(62.5, 2), const_100), divide(multiply(87.5, 8), const_100)), add(subtract(2, divide(multiply(62.5, 2), const_100)), subtract(8, divide(multiply(87.5, 8), const_100)))) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|subtract(n2,#2)|subtract(n3,#3)|add(#5,#6)|divide(#4,#7)| | "quantity of alcohol in vessel p = 62.5 / 100 * 2 = 5 / 4 litres quantity of alcohol in vessel q = 87.5 / 100 * 4 = 7 / 1 litres quantity of alcohol in the mixture formed = 5 / 4 + 7 / 1 = 33 / 4 = 8.25 litres as 10 litres of mixture is formed , ratio of alcohol and water in the mixture formed = 8.25 : 1.75 = 33 : 7 . answer : b" | other |
math_qa__XQ0bBgcXB3tufj2G | A man can row 5 kmph in still water. When the river is running at 2.3 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
Choices
A) 2.91 B) 3.48 C) 2.98 D) 3.78 E) 4.21 | <gadget id="calculator">5 + 2.3</gadget>
<output>7.3</output>
<gadget id="calculator">5 - 2.3</gadget>
<output>2.7</output>
<gadget id="calculator">7.3 * 2.7</gadget>
<output>19.71</output>
<gadget id="calculator">7.3 + 2.7</gadget>
<output>10</output>
<gadget id="calculator">19.71 / 10</gadget>
<output>1.971</output>
<gadget id="calculator">1.971 * 2</gadget>
<output>3.942</output>
<result>D</result> | D | 3.78 | A man can row 5 kmph in still water. When the river is running at 2.3 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man? | {
"A": "2.91",
"B": "3.48",
"C": "2.98",
"D": "3.78",
"E": "4.21"
} | multiply(divide(multiply(add(5, 2.3), subtract(5, 2.3)), add(add(5, 2.3), subtract(5, 2.3))), const_2) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|multiply(#0,#1)|divide(#3,#2)|multiply(#4,const_2)| | "m = 5 s = 2.3 ds = 6.3 us = 2.7 x / 6.3 + x / 2.7 = 1 x = 1.89 d = 1.89 * 2 = 3.78 answer : d" | physics |
math_qa__YWuZ55o67kuqOlNh | If 4 (P's Capital) = 6 (Q's Capital) = 10 (R's Capital), then out of the total profit of Rs 4650, how much R will receive? Choose the correct choice from the following options:
A) 300
B) 600
C) 900
D) 800
E) 500 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 6</gadget>
<output>31</output>
<gadget id="calculator">6 / 31</gadget>
<output>6/31 = around 0.193548</output>
<gadget id="calculator">4_650 * (6/31)</gadget>
<output>900</output>
<result>C</result> | C | 900 | If 4 (P's Capital) = 6 (Q's Capital) = 10 (R's Capital), then out of the total profit of Rs 4650, how much R will receive? | {
"A": "300",
"B": "600",
"C": "900",
"D": "800",
"E": "500"
} | multiply(4650, divide(6, add(add(add(10, add(4, const_1)), 10), 6))) | add(n0,const_1)|add(n2,#0)|add(n2,#1)|add(n1,#2)|divide(n1,#3)|multiply(n3,#4)| | "let p ' s capital be p , q ' s capital be q , and r ' s capital be r then 4 p = 6 q = 10 r 2 p = 3 q = 5 r ⋯ ( a ) from ( a ) , q = 2 p / 3 ⋯ ( 1 ) r = 2 p / 5 ⋯ ( 2 ) p : q : r = p : 2 p / 3 : 2 p / 5 = 15 : 10 : 6 r ' s share = 4650 × 6 / 31 = 150 × 6 = 900 answer is c ." | general |
math_qa__AivgJOrOLERIrgSZ | A 260 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? Options.
A) 240 mts B) 270 mts C) 260 mts D) 250 mts E) none of these | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">(500/9) * 9</gadget>
<output>500</output>
<gadget id="calculator">500 - 260</gadget>
<output>240</output>
<result>A</result> | A | 240 | A 260 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? | {
"A": "240 mts",
"B": "270 mts",
"C": "260 mts",
"D": "250 mts",
"E": "none of these"
} | subtract(multiply(multiply(add(120, 80), const_0_2778), 9), 260) | add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0) | explanation : relative speed = 120 + 80 = 200 km / hr . = 200 x 5 / 18 = 500 / 9 m / sec . let the length of the other train be l mts . then , ( l + 260 ) / 9 = 500 / 9 = > l = 240 mts . answer is a | physics |
math_qa__MNWK9orfh0Lci2Q3 | Find the number of divisors of 1080 excluding the divisors which are perfect squares. Choose the correct choice from the following answers
A) 28 B) 29 C) 30 D) 31 E) 32 | <gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 2</gadget>
<output>32</output>
<gadget id="calculator">32 - 3</gadget>
<output>29</output>
<result>A</result> | A | 28 | Find the number of divisors of 1080 excluding the divisors which are perfect squares. | {
"A": "28",
"B": "29",
"C": "30",
"D": "31",
"E": "32"
} | subtract(multiply(multiply(const_4, const_4), const_2), const_3) | multiply(const_4,const_4)|multiply(#0,const_2)|subtract(#1,const_3) | 1080 = 2 ^ 3 * 3 ^ 3 * 5 ^ 1 total no . of divisors = ( 3 + 1 ) * ( 3 + 1 ) * ( 1 + 1 ) = 32 only 4 divisors 1 , 2 ^ 2 = 4 , 3 ^ 2 = 9 & 2 ^ 2 * 3 ^ 2 = 36 are perfect squares so , number of divisors excluding perfect squares divisors = 32 - 4 = 28 answer : a | geometry |
math_qa__LsWjBD4Eb9HNVHdv | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $0.70 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? Choose the most appropriate option.
A) $ 255
B) $ 357
C) $ 510
D) $ 1,250
E) $ 2,550 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">3.06 * 1_000_000</gadget>
<output>3_060_000</output>
<gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">400 * 15</gadget>
<output>6_000</output>
<gadget id="calculator">3_060_000 / 6_000</gadget>
<output>510</output>
<gadget id="calculator">510 * 0.7</gadget>
<output>357</output>
<result>B</result> | B | 357 | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $0.70 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? | {
"A": "$ 255",
"B": "$ 357",
"C": "$ 510",
"D": "$ 1,250",
"E": "$ 2,550"
} | multiply(divide(multiply(3.06, multiply(const_1000, const_1000)), multiply(multiply(20, 20), 15)), 0.70) | multiply(const_1000,const_1000)|multiply(n0,n0)|multiply(n4,#0)|multiply(n2,#1)|divide(#2,#3)|multiply(n3,#4)| | "total no . of boxes = 3060000 / ( 20 × 20 × 15 ) = 510 total cost = 510 × $ 0.7 = $ 357 answer b" | general |
math_qa__ZtVAdCFUenXi1qz1 | On a race track a maximum of 5 horses can race together at a time. There are a total of 25 horses. There is no way of timing the races. What is the minimum number Y of races we need to conduct to get the top 3 fastest horses? Answers:
A) 5 B) 7 C) 8 D) 10 E) 11 | <gadget id="calculator">25 / 5</gadget>
<output>5</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<result>B</result> | B | 7 | On a race track a maximum of 5 horses can race together at a time. There are a total of 25 horses. There is no way of timing the races. What is the minimum number Y of races we need to conduct to get the top 3 fastest horses? | {
"A": "5",
"B": "7",
"C": "8",
"D": "10",
"E": "11"
} | add(divide(25, 5), const_2) | divide(n1,n0)|add(#0,const_2)| | "y = 7 is the correct answer . good solution buneul . b" | general |
math_qa__syXN6clTidq6tVje | A fruit seller sells mangoes at the rate of Rs.6 per kg and thereby loses 15%. At what price per kg, he should have sold them to make a profit of 5% Choose the correct answer.
A) rs 7.41
B) rs 9.81
C) rs 10.41
D) rs 11.81
E) none of these | <gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">6 * 105</gadget>
<output>630</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">630 / 85</gadget>
<output>126/17 = around 7.411765</output>
<result>A</result> | A | 7.41 | A fruit seller sells mangoes at the rate of Rs.6 per kg and thereby loses 15%. At what price per kg, he should have sold them to make a profit of 5% | {
"A": "rs 7.41",
"B": "rs 9.81",
"C": "rs 10.41",
"D": "rs 11.81",
"E": "none of these"
} | divide(multiply(6, add(const_100, 5)), subtract(const_100, 15)) | add(n2,const_100)|subtract(const_100,n1)|multiply(n0,#0)|divide(#2,#1)| | "explanation : 85 : 6 = 105 : x x = ( 6 × 105 / 85 ) = rs 7.41 option a" | gain |
math_qa__cqVAjpBUG3hCYkVK | The salaries of A and B together amount to $5000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary? Select:
A) $ 1000 B) $ 1250 C) $ 2500 D) $ 3500 E) $ 3750 | <gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">100 - 95</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">5_000 / 4</gadget>
<output>1_250</output>
<gadget id="calculator">5_000 - 1_250</gadget>
<output>3_750</output>
<result>E</result> | E | 3,750 | The salaries of A and B together amount to $5000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary? | {
"A": "$ 1000",
"B": "$ 1250",
"C": "$ 2500",
"D": "$ 3500",
"E": "$ 3750"
} | subtract(5000, divide(5000, add(divide(subtract(const_100, 85), subtract(const_100, 95)), const_1))) | subtract(const_100,n2)|subtract(const_100,n1)|divide(#0,#1)|add(#2,const_1)|divide(n0,#3)|subtract(n0,#4)| | "let a ' s salary is x b ' s salary = 5000 - x ( 100 - 95 ) % of x = ( 100 - 85 ) % of ( 5000 - x ) x = $ 3750 answer is e" | gain |
math_qa__0eXWV40ppOjiUjUK | When tossed, a certain coin has an equal probability of landing on either side. If the coin is tossed 4 times, what is the probability that it will land on the same side each time? Choose the correct option
A) 1 / 4 B) 1 / 6 C) 1 / 8 D) 1 / 12 E) 1 / 16 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 4</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">(1/16) + (1/16)</gadget>
<output>1/8 = around 0.125</output>
<result>C</result> | C | 0.125 | When tossed, a certain coin has an equal probability of landing on either side. If the coin is tossed 4 times, what is the probability that it will land on the same side each time? | {
"A": "1 / 4",
"B": "1 / 6",
"C": "1 / 8",
"D": "1 / 12",
"E": "1 / 16"
} | add(power(divide(const_1, const_2), 4), power(divide(const_1, const_2), 4)) | divide(const_1,const_2)|power(#0,n0)|add(#1,#1) | on the first toss , the coin will land on one side or the other . on the second toss , the probability of landing on the same side is 1 / 2 . on the third toss , the probability of landing on the same side is 1 / 2 . on the fourth toss , the probability of landing on the same side is 1 / 2 . p ( same side all four times ) = 1 / 2 * 1 / 2 * 1 / 2 = 1 / 8 . the answer is c . | probability |
math_qa__c8MPDSO2BvUoXzcH | Bob wants to run a mile in the same time as his sister. If Bob’s time for a mile is currently 10 minutes 40 seconds and his sister’s time is currently 9 minutes 42 seconds, by what percent does Bob need to improve his time in order run a mile in the same time as his sister? Answers: A) 3 % B) 5 % C) 8 % D) 9 % E) 12 % | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">9 * 60</gadget>
<output>540</output>
<gadget id="calculator">540 + 42</gadget>
<output>582</output>
<gadget id="calculator">10 * 60</gadget>
<output>600</output>
<gadget id="calculator">600 + 40</gadget>
<output>640</output>
<gadget id="calculator">582 / 640</gadget>
<output>291/320 = around 0.909375</output>
<gadget id="calculator">1 - (291/320)</gadget>
<output>29/320 = around 0.090625</output>
<gadget id="calculator">100 * (29/320)</gadget>
<output>145/16 = around 9.0625</output>
<result>D</result> | D | 9 | Bob wants to run a mile in the same time as his sister. If Bob’s time for a mile is currently 10 minutes 40 seconds and his sister’s time is currently 9 minutes 42 seconds, by what percent does Bob need to improve his time in order run a mile in the same time as his sister? | {
"A": "3 %",
"B": "5 %",
"C": "8 %",
"D": "9 %",
"E": "12 %"
} | multiply(multiply(10, 10), subtract(const_1, divide(add(multiply(9, const_60), 42), add(multiply(10, const_60), 40)))) | multiply(n0,n0)|multiply(n2,const_60)|multiply(n0,const_60)|add(n3,#1)|add(n1,#2)|divide(#3,#4)|subtract(const_1,#5)|multiply(#0,#6)| | "bob ' s time = 640 secs . his sis ' time = 582 secs . percent increase needed = ( 640 - 582 / 640 ) * 100 = 58 / 640 * 100 = 9 % . ans ( d ) ." | physics |
math_qa__0vLws4LEpXb2N48k | The average weight of 5 person's increases by 4 kg when a new person comes in place of one of them weighing 50kg. What is the weight of the new person? Choose the correct choice from the following answers
A) 70 B) 86.5 C) 80 D) 88.5 E) 75 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 + 50</gadget>
<output>70</output>
<result>A</result> | A | 70 | The average weight of 5 person's increases by 4 kg when a new person comes in place of one of them weighing 50kg. What is the weight of the new person? | {
"A": "70",
"B": "86.5",
"C": "80",
"D": "88.5",
"E": "75"
} | add(multiply(5, 4), 50) | multiply(n0,n1)|add(n2,#0)| | "total increase in weight = 5 × 4 = 20 if x is the weight of the new person , total increase in weight = x − 50 = > 20 = x - 50 = > x = 20 + 50 = 70 answer : a" | general |
math_qa__QmBqHNLPfnmJppCV | The average age of 15 students of a class is 15 years. Out of these, the average age of 8 students is 14 years and that of the other 6 students is 16 years. The age of the 15th student is Choose the correct option
A) 9 years B) 11 years C) 17 years D) 21 years E) 25 years | <gadget id="calculator">15 * 15</gadget>
<output>225</output>
<gadget id="calculator">8 * 14</gadget>
<output>112</output>
<gadget id="calculator">6 * 16</gadget>
<output>96</output>
<gadget id="calculator">112 + 96</gadget>
<output>208</output>
<gadget id="calculator">225 - 208</gadget>
<output>17</output>
<result>C</result> | C | 17 | The average age of 15 students of a class is 15 years. Out of these, the average age of 8 students is 14 years and that of the other 6 students is 16 years. The age of the 15th student is | {
"A": "9 years",
"B": "11 years",
"C": "17 years",
"D": "21 years",
"E": "25 years"
} | subtract(multiply(15, 15), add(multiply(8, 14), multiply(6, 16))) | multiply(n0,n0)|multiply(n2,n3)|multiply(n4,n5)|add(#1,#2)|subtract(#0,#3)| | "solution age of the 15 th student = [ 15 x 15 - ( 14 x 8 + 16 x 6 ) ] = ( 225 - 208 ) = 17 years . answer c" | general |
math_qa__lZW7WAiCGYLAOJaR | Jerry went to a shop and bought things worth Rs. 35, out of which 30 % went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items? Pick one: A) 19 B) 19.7 C) 21.3 D) 21.5 E) 29.7 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">100 / 6</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(3/10) * (50/3)</gadget>
<output>5</output>
<gadget id="calculator">5 + (3/10)</gadget>
<output>53/10 = around 5.3</output>
<gadget id="calculator">35 - (53/10)</gadget>
<output>297/10 = around 29.7</output>
<result>E</result> | E | 29.7 | Jerry went to a shop and bought things worth Rs. 35, out of which 30 % went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items? | {
"A": "19",
"B": "19.7",
"C": "21.3",
"D": "21.5",
"E": "29.7"
} | subtract(35, add(multiply(divide(30, const_100), divide(const_100, 6)), divide(30, const_100))) | divide(n1,const_100)|divide(const_100,n2)|multiply(#0,#1)|add(#0,#2)|subtract(n0,#3)| | "total cost of the items he purchased = rs . 35 given that out of this rs . 35 , 30 % is given as tax = > total tax incurred = 30 % = rs . 30 / 100 let the cost of the tax free items = x given that tax rate = 6 % ∴ ( 35 − 30 / 100 − x ) 6 / 100 = 30 / 100 ⇒ 6 ( 35 − 0.3 − x ) = 30 ⇒ ( 35 − 0.3 − x ) = 5 ⇒ x = 35 − 0.3 − 5 = 29.7 e )" | gain |
math_qa__jcDhYvFK6NjSfDpj | How long does a train 110 m long running at the speed of 36 km/hr takes to cross a bridge 132 m length? Choose the correct option
A) 82.1 sec B) 12.1 sec C) 24.2 sec D) 13.1 sec E) 12.15 sec | <gadget id="calculator">110 + 132</gadget>
<output>242</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">242 / 10</gadget>
<output>121/5 = around 24.2</output>
<result>C</result> | C | 24.2 | How long does a train 110 m long running at the speed of 36 km/hr takes to cross a bridge 132 m length? | {
"A": "82.1 sec",
"B": "12.1 sec",
"C": "24.2 sec",
"D": "13.1 sec",
"E": "12.15 sec"
} | divide(add(110, 132), multiply(36, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 36 * 5 / 18 = 10 m / sec total distance covered = 110 + 132 = 242 m . required time = 242 / 10 = 24.2 sec . answer : c" | physics |
math_qa__P9eKZXIZAqcOmFCT | 1200 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now? Choose the most appropriate option: A) 12.85 B) 12.62 C) 12.5 D) 12.24 E) 12.1 | <gadget id="calculator">15 * 1_200</gadget>
<output>18_000</output>
<gadget id="calculator">1_200 + 200</gadget>
<output>1_400</output>
<gadget id="calculator">18_000 / 1_400</gadget>
<output>90/7 = around 12.857143</output>
<result>A</result> | A | 12.85 | 1200 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now? | {
"A": "12.85",
"B": "12.62",
"C": "12.5",
"D": "12.24",
"E": "12.1"
} | divide(multiply(15, 1200), add(1200, 200)) | add(n0,n2)|multiply(n0,n1)|divide(#1,#0)| | "1200 * 15 = 1400 * x x = 12.85 . answer : a" | physics |
math_qa__pO6W5IjQYDnDV6FA | The average (arithmetic mean) of 4 positive integers is 50. If the average of 2 of these integers is 35, what is the greatest possible value that one of the other 2 integers can have? Choose the correct answer: A) 55 B) 65 C) 100 D) 109 E) 129 | <gadget id="calculator">50 * 4</gadget>
<output>200</output>
<gadget id="calculator">35 * 2</gadget>
<output>70</output>
<gadget id="calculator">200 - 70</gadget>
<output>130</output>
<result>E</result> | E | 129 | The average (arithmetic mean) of 4 positive integers is 50. If the average of 2 of these integers is 35, what is the greatest possible value that one of the other 2 integers can have? | {
"A": "55",
"B": "65",
"C": "100",
"D": "109",
"E": "129"
} | subtract(multiply(50, 4), multiply(35, 2)) | multiply(n0,n1)|multiply(n2,n3)|subtract(#0,#1)| | "a + b + c + d = 200 a + b = 70 c + d = 130 greatest possible = 129 ( just less than 1 ) answer = e" | general |
math_qa__ALRSou1fwRcKC7f0 | Find the amount on Rs.6000 in 2 years, the rate of interest being 4% per first year and 5% for the second year?
Choose the correct choice from the following choices.
A) 5568 B) 6369 C) 5460 D) 5635 E) 6552 | <gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">6_000 * 104</gadget>
<output>624_000</output>
<gadget id="calculator">624_000 / 100</gadget>
<output>6_240</output>
<gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">6_240 * 105</gadget>
<output>655_200</output>
<gadget id="calculator">655_200 / 100</gadget>
<output>6_552</output>
<result>E</result> | E | 6,552 | Find the amount on Rs.6000 in 2 years, the rate of interest being 4% per first year and 5% for the second year? | {
"A": "5568",
"B": "6369",
"C": "5460",
"D": "5635",
"E": "6552"
} | divide(multiply(divide(multiply(6000, add(const_100, 4)), const_100), add(const_100, 5)), const_100) | add(n3,const_100)|add(n2,const_100)|multiply(n0,#1)|divide(#2,const_100)|multiply(#0,#3)|divide(#4,const_100)| | "6000 * 104 / 100 * 105 / 100 = > 6552 answer : e" | gain |
math_qa__pG4najDOfR0zBGja | A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 20% so that the customer could not buy the required amount of the product. The customer managed to buy only 70% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase? Options:
A) 16 % B) 18 % C) 20 % D) 22 % E) 24 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(6/5) * (7/10)</gadget>
<output>21/25 = around 0.84</output>
<gadget id="calculator">1 - (21/25)</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * 100</gadget>
<output>16</output>
<result>A</result> | A | 16 | A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 20% so that the customer could not buy the required amount of the product. The customer managed to buy only 70% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase? | {
"A": "16 %",
"B": "18 %",
"C": "20 %",
"D": "22 %",
"E": "24 %"
} | multiply(subtract(const_1, multiply(add(divide(20, const_100), const_1), divide(70, const_100))), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|multiply(#2,#1)|subtract(const_1,#3)|multiply(#4,const_100) | let x be the amount of money paid for the first purchase . the second time , the customer paid 0.7 ( 1.2 x ) = 0.84 x . the difference is 16 % . the answer is a . | general |
math_qa__Vjgklo2S8N66EGxN | A group of men decided to do a work in 10days, but 5 of them became absent. If the rest of the group did the work in 12days, Find the original number of men? Choose the correct choice from the following options.
A) 15 B) 20 C) 30 D) 25 E) 18 | <gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">12 - 10</gadget>
<output>2</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>C</result> | C | 30 | A group of men decided to do a work in 10days, but 5 of them became absent. If the rest of the group did the work in 12days, Find the original number of men? | {
"A": "15",
"B": "20",
"C": "30",
"D": "25",
"E": "18"
} | divide(multiply(5, 12), subtract(12, 10)) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1) | original number of men = 5 * 12 / ( 12 - 10 ) = 30 answer is c | physics |
math_qa__WvSU4IQBml6pCvRu | If x and y are both odd prime numbers and x < y, how many distinct positive integer factors does 2xy have? Choose the correct choice from the following answers
A) 3 B) 4 C) 6 D) 8 E) 12 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<result>D</result> | D | 8 | If x and y are both odd prime numbers and x < y, how many distinct positive integer factors does 2xy have? | {
"A": "3",
"B": "4",
"C": "6",
"D": "8",
"E": "12"
} | multiply(multiply(2, add(const_1, const_1)), add(const_1, const_1)) | add(const_1,const_1)|multiply(n0,#0)|multiply(#0,#1) | the solution should be the same for all numbers that fulfill the condition above . as x and y are odd prime numbers , they must be > 2 . also , they must be distinct as x < y . i choose x = 3 and y = 5 : how many factors does 2 x 3 x 5 = 30 have : 1 , 2 , 3 , 5 , 6 , 10 , 15 , 30 = 8 distinct positive integer factors . hence , the correct answer is d . | other |
math_qa__nmkblkVkLIpwEpWn | If 3 cats can kill 3 rats in 3 minutes, how long will it take 100 cats to kill 100 rats? Pick one
A) 1 minutes B) 2 minutes C) 3 minutes D) 4 minutes E) 5 minutes | <gadget id="calculator">3 * 1</gadget>
<output>3</output>
<result>C</result> | C | 3 | If 3 cats can kill 3 rats in 3 minutes, how long will it take 100 cats to kill 100 rats? | {
"A": "1 minutes",
"B": "2 minutes",
"C": "3 minutes",
"D": "4 minutes",
"E": "5 minutes"
} | multiply(3, const_1) | multiply(n0,const_1)| | "it will take 3 minutes for 100 cats to kill 100 rats . 1 cat can kill 1 rat in 3 minutes , so 100 cats can kill 100 rats in 3 minutes answer c" | physics |
math_qa__0wDLHLYjNk9LhhyA | A certain quantity of 80% solution is replaced with 25% solution such that the new concentration is 35%. What is the fraction of the solution that was replaced? Select:
A) 1 / 4 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 9 / 11 | <gadget id="calculator">35 - 25</gadget>
<output>10</output>
<gadget id="calculator">80 - 35</gadget>
<output>45</output>
<gadget id="calculator">10 / 45</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(2/9) + 1</gadget>
<output>11/9 = around 1.222222</output>
<gadget id="calculator">1 / (11/9)</gadget>
<output>9/11 = around 0.818182</output>
<result>E</result> | E | 0.818182 | A certain quantity of 80% solution is replaced with 25% solution such that the new concentration is 35%. What is the fraction of the solution that was replaced? | {
"A": "1 / 4",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "9 / 11"
} | inverse(add(divide(subtract(35, 25), subtract(80, 35)), const_1)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)|add(#2,const_1)|inverse(#3)| | "let ' s say that the total original mixture a is 100 ml the original mixture a thus has 50 ml of alcohol out of 100 ml of solution you want to replace some of that original mixture a with another mixture b that contains 25 ml of alcohol per 100 ml . thus , the difference between 80 ml and 25 ml is 55 ml per 100 ml of mixture . this means that every time you replace 100 ml of the original mixture a by 100 ml of mixture b , the original alcohol concentration will decrease by 25 % . the question says that the new mixture , let ' s call it c , must be 35 % alcohol , a decrease of only 45 % . therefore , 45 out of 55 is 9 / 11 and e is the answer ." | other |
math_qa__KGu6V8MXwkdwf5H2 | The number of diagonals of a polygon of n sides is given by the formula c=n(n-3)/2. If a polygon has twice as many diagonals as sides, how many sides does it have? Choose one:
A) 3 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<result>B</result> | B | 5 | The number of diagonals of a polygon of n sides is given by the formula c=n(n-3)/2. If a polygon has twice as many diagonals as sides, how many sides does it have? | {
"A": "3",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | add(3, 2) | add(n0,n1) | c = n ( n - 3 ) c = 2 * n 2 n = n ( n - 3 ) = > 2 = n - 3 = > n = 5 answer b | general |
math_qa__IdgwNUdoJzRkqv5y | 80 is increased by 50%. Find the final number. Select the correct option.
A) 100 B) 110 C) 120 D) 30 E) 160 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">80 * (1/2)</gadget>
<output>40</output>
<gadget id="calculator">80 + 40</gadget>
<output>120</output>
<result>C</result> | C | 120 | 80 is increased by 50%. Find the final number. | {
"A": "100",
"B": "110",
"C": "120",
"D": "30",
"E": "160"
} | add(80, multiply(80, divide(50, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | "final number = initial number + 50 % ( original number ) = 80 + 50 % ( 80 ) = 80 + 40 = 120 . answer c" | gain |
math_qa__EQsC9dl5GXf7eoCY | The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?
Options.
A) 12 B) 81 C) 77 D) 66 E) 73 | <gadget id="calculator">12 * 1</gadget>
<output>12</output>
<result>A</result> | A | 12 | The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A? | {
"A": "12",
"B": "81",
"C": "77",
"D": "66",
"E": "73"
} | multiply(12, const_1) | multiply(n0,const_1)| | "( a + b ) - ( b + c ) = 12 a - c = 12 answer : a" | general |
math_qa__CqCqW9X3sDEBpmRN | In a bag, there are 2400 ball, and their colors are red, green blue.. The ratio of the balls are 15:13:17.Then how many red color balls are available in the bag?
Choose the correct choice from the following:
A) 900 B) 1600 C) 750 D) 890 E) 1010 | <gadget id="calculator">15 + 13</gadget>
<output>28</output>
<gadget id="calculator">28 + 17</gadget>
<output>45</output>
<gadget id="calculator">17 / 45</gadget>
<output>17/45 = around 0.377778</output>
<gadget id="calculator">(17/45) * 2_400</gadget>
<output>2_720/3 = around 906.666667</output>
<result>A</result> | A | 900 | In a bag, there are 2400 ball, and their colors are red, green blue.. The ratio of the balls are 15:13:17.Then how many red color balls are available in the bag? | {
"A": "900",
"B": "1600",
"C": "750",
"D": "890",
"E": "1010"
} | multiply(divide(17, add(add(15, 13), 17)), 2400) | add(n1,n2)|add(n3,#0)|divide(n3,#1)|multiply(n0,#2) | red : green : blue = 15 + 13 + 17 = 45 ; ratio of the red balls = 15 / 40 simplify = 3 / 8 * 2400 = 900 . answer = a | other |
math_qa__1jTkmv7o81j0462J | An alloy is to contain copper and zinc in the ratio 9:4. The zinc required to be melted with 24kg of copper is? Select
A) 12 kg
B) 8.3 kg
C) 10.7 kg
D) 15.5 kg
E) 7 kg | <gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">96 / 9</gadget>
<output>32/3 = around 10.666667</output>
<result>C</result> | C | 10.7 | An alloy is to contain copper and zinc in the ratio 9:4. The zinc required to be melted with 24kg of copper is? | {
"A": "12 kg",
"B": "8.3 kg",
"C": "10.7 kg",
"D": "15.5 kg",
"E": "7 kg"
} | divide(multiply(24, 4), 9) | multiply(n1,n2)|divide(#0,n0)| | "let the required quantity of copper be x kg 9 : 4 : : 24 : x 9 x = 4 * 24 x = 10 2 / 3 kg = 32 / 3 = 10.7 kg answer is c" | other |
math_qa__3MVXzeWOMiyIOUWi | Two trains of equal lengths take 9 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? Choose the correct choice from the following choices
A) 10
B) 11.3
C) 13
D) 14
E) 15 | <gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">120 / 15</gadget>
<output>8</output>
<gadget id="calculator">120 / 9</gadget>
<output>40/3 = around 13.333333</output>
<gadget id="calculator">8 + (40/3)</gadget>
<output>64/3 = around 21.333333</output>
<gadget id="calculator">240 / (64/3)</gadget>
<output>45/4 = around 11.25</output>
<result>B</result> | B | 11.3 | Two trains of equal lengths take 9 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? | {
"A": "10",
"B": "11.3",
"C": "13",
"D": "14",
"E": "15"
} | divide(multiply(120, const_2), add(speed(120, 15), speed(120, 9))) | multiply(n2,const_2)|speed(n2,n1)|speed(n2,n0)|add(#1,#2)|divide(#0,#3)| | "speed of the first train = 120 / 9 = 13.3 m / sec . speed of the second train = 120 / 15 = 8 m / sec . relative speed = 13.3 + 8 = 21.3 m / sec . required time = ( 120 + 120 ) / 21.3 = 11.3 sec . answer : option b" | physics |
math_qa__g4X7l2HqO2YsGJgf | Trains A and B start simultaneously from stations 350 miles apart, and travel the same route toward each other on adjacent parallel tracks. If Train A and Train B travel at a constant rate of 40 miles per hour and 30 miles per hour, respectively, how many miles will Train A have traveled when the trains pass each other, to the nearest mile? Choose the correct choice from the following answers: A) 112 B) 133 C) 150 D) 167 E) 200 | <gadget id="calculator">40 + 30</gadget>
<output>70</output>
<gadget id="calculator">350 / 70</gadget>
<output>5</output>
<gadget id="calculator">40 * 5</gadget>
<output>200</output>
<result>E</result> | E | 200 | Trains A and B start simultaneously from stations 350 miles apart, and travel the same route toward each other on adjacent parallel tracks. If Train A and Train B travel at a constant rate of 40 miles per hour and 30 miles per hour, respectively, how many miles will Train A have traveled when the trains pass each other, to the nearest mile? | {
"A": "112",
"B": "133",
"C": "150",
"D": "167",
"E": "200"
} | multiply(40, divide(350, add(40, 30))) | add(n1,n2)|divide(n0,#0)|multiply(n1,#1) | since we know the distance ( 350 ) and the combined rate ( 70 ) , we plug it into the formula : distance = rate * time 350 = 70 * time we can solve for the time they will meet cause we added the rate of train a and train b together . so the time will be 350 / 70 from dividing 70 on both sides to isolate time in the equation above . time will be 5 hours so now you can plug that in for train a ’ s distance . distance = rate * time distance = 40 * 5 distance = 200 according to answer choice e . | physics |
math_qa__9PZqW9Lv9cxX6joQ | Harold works at a resort from the beginning of March to the end of September. During the month of August this past year, he made 6 times the average (arithmetic mean) of his monthly totals in tips for the other months. His total tips for August were what fraction of his total tips for all of the months he worked?
Options.
A) 1 / 3 B) 2 / 5 C) 3 / 7 D) 1 / 2 E) 4 / 7 | <gadget id="calculator">6 * 1</gadget>
<output>6</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<result>D</result> | D | 0.5 | Harold works at a resort from the beginning of March to the end of September. During the month of August this past year, he made 6 times the average (arithmetic mean) of his monthly totals in tips for the other months. His total tips for August were what fraction of his total tips for all of the months he worked? | {
"A": "1 / 3",
"B": "2 / 5",
"C": "3 / 7",
"D": "1 / 2",
"E": "4 / 7"
} | divide(multiply(6, const_1), add(multiply(6, const_1), multiply(6, const_1))) | multiply(n0,const_1)|add(#0,#0)|divide(#0,#1) | the time from beginning of march to the end of september is 7 months . if x is the average monthly tip for all months other than august then his august month tip will be 6 * x his total tip for the 7 months = 6 * ( average tip for the months other than august ) + 6 x = 12 x august tips as a fraction of total tips = 6 x / 12 x = 1 / 2 . so d | general |
math_qa__zn32P7XmFB7htwWF | For how many values of N, is |||N - 5| -10| -5| = 2?
(Those ls are mods)
Choose the correct choice from the following answers
A) 0 B) 2 C) 4 D) 8 E) more than 8 | <gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<result>D</result> | D | 8 | For how many values of N, is |||N - 5| -10| -5| = 2?
(Those ls are mods) | {
"A": "0",
"B": "2",
"C": "4",
"D": "8",
"E": "more than 8"
} | power(2, const_3) | power(n3,const_3) | i think its 8 | | | n - 5 | - 10 | - 5 | = 2 let | n - 5 | = a which makes above | | a - 10 | - 5 | = 2 let | a - 10 | = b which makes | b - 5 | = 2 now for the above b can take 3 , 7 for every b = 3 a can have 13 , 7 and for b = 7 a can have 17 and 3 so ' a ' has four solutions 13 , 7 , 17 and 3 for a = 13 ; x has 18 or - 8 thus has 2 for every combination hence 4 x 2 = 8 answer d | general |
math_qa__mPmloFz63lFFuCu6 | Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 42 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast? Select
A) 10 % B) 12 % C) 14 % D) 17 % E) 20 % | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">42 / 100</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">(1/2) - (21/50)</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">1 - (21/50)</gadget>
<output>29/50 = around 0.58</output>
<gadget id="calculator">(2/25) / (29/50)</gadget>
<output>4/29 = around 0.137931</output>
<gadget id="calculator">(4/29) * 100</gadget>
<output>400/29 = around 13.793103</output>
<result>C</result> | C | 14 | Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 42 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast? | {
"A": "10 %",
"B": "12 %",
"C": "14 %",
"D": "17 %",
"E": "20 %"
} | multiply(divide(subtract(divide(50, const_100), divide(42, const_100)), subtract(const_1, divide(42, const_100))), const_100) | divide(n2,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(const_1,#1)|divide(#2,#3)|multiply(#4,const_100)| | "let me try a simpler one . lets assume that candidate got 42 % votes and total votes is 100 . candidate won = 42 remaining = 58 to get 50 % , candidate requires 8 votes from 100 which is 8 % and 8 votes from 58 . 8 / 58 = . 137 = 13.7 % which is approx 14 % . hence the answer is c ." | general |
math_qa__JCCfsf1aL1REmOhR | A certain bus driver is paid a regular rate of $15 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $976 in total compensation, how many total hours did he work that week? Choose the correct option.
A) 56 B) 51 C) 59 D) 54 E) 52 | <gadget id="calculator">15 * 40</gadget>
<output>600</output>
<gadget id="calculator">976 - 600</gadget>
<output>376</output>
<gadget id="calculator">100 + 75</gadget>
<output>175</output>
<gadget id="calculator">15 * 175</gadget>
<output>2_625</output>
<gadget id="calculator">2_625 / 100</gadget>
<output>105/4 = around 26.25</output>
<gadget id="calculator">376 / (105/4)</gadget>
<output>1_504/105 = around 14.32381</output>
<gadget id="calculator">40 + (1_504/105)</gadget>
<output>5_704/105 = around 54.32381</output>
<result>D</result> | D | 54 | A certain bus driver is paid a regular rate of $15 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $976 in total compensation, how many total hours did he work that week? | {
"A": "56",
"B": "51",
"C": "59",
"D": "54",
"E": "52"
} | add(40, divide(subtract(976, multiply(15, 40)), divide(multiply(15, add(const_100, 75)), const_100))) | add(n3,const_100)|multiply(n0,n1)|multiply(n0,#0)|subtract(n4,#1)|divide(#2,const_100)|divide(#3,#4)|add(n1,#5)| | "for 40 hrs = 40 * 15 = 600 excess = 976 - 600 = 376 for extra hours = . 75 ( 15 ) = 11.25 + 15 = 26.25 number of extra hrs = 376 / 26.25 = 14.3 = 14 approx . total hrs = 40 + 14 = 54 answer d" | general |
math_qa__AtYXH4PrsEnUOMgh | in a class , 6 students can speak tamil , 15 can speak gujarati and 6 can speak h . if two students can speak two languages and one student can speak all the 3 languages , then how many students are there in the class ? Select:
A) 20 B) 21 C) 22 D) 23 E) 24 | <gadget id="calculator">6 + 15</gadget>
<output>21</output>
<gadget id="calculator">6 + 21</gadget>
<output>27</output>
<gadget id="calculator">27 - 3</gadget>
<output>24</output>
<gadget id="calculator">24 - 2</gadget>
<output>22</output>
<result>D</result> | D | 23 | in a class , 6 students can speak tamil , 15 can speak gujarati and 6 can speak h . if two students can speak two languages and one student can speak all the 3 languages , then how many students are there in the class ? | {
"A": "20",
"B": "21",
"C": "22",
"D": "23",
"E": "24"
} | subtract(subtract(add(6, add(6, 15)), 3), const_2) | add(n0,n1)|add(n0,#0)|subtract(#1,n3)|subtract(#2,const_2) | t = 6 g = 15 h = 6 students can speak two languages ( suppose tamil & gujarati ) = 2 student can speak all the three languages = 1 student can speak only tamil language = 6 - 2 - 1 = 3 student can speak only gujarati language = 15 - 2 - 1 = 12 student can speak only h language = 6 - 1 = 5 so , total number of student = 2 + 1 + 3 + 12 + 5 = 23 answer : d | general |
math_qa__8hUot0ePPdl1ZqXo | What should be the least number to be added to the 3198 number to make it divisible by 8? Choose the correct choice from the following options
A) 12 B) 17 C) 2 D) 77 E) 26 | <gadget id="calculator">3_198 % 8</gadget>
<output>6</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<result>C</result> | C | 2 | What should be the least number to be added to the 3198 number to make it divisible by 8? | {
"A": "12",
"B": "17",
"C": "2",
"D": "77",
"E": "26"
} | subtract(8, reminder(3198, 8)) | reminder(n0,n1)|subtract(n1,#0)| | "answer : 2 option : c" | general |
math_qa__eKuczPjTs5sYyWTD | 10% people of a village in Sri Lanka died by bombardment, 20% of the remainder left the village on account of fear. If now the population is reduced to 3168, how much was it in the beginning? Choose the correct choice from the following answers:
A) 3800 B) 4200 C) 4400 D) 4500 E) 4600 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(9/10) * (4/5)</gadget>
<output>18/25 = around 0.72</output>
<gadget id="calculator">3_168 / (18/25)</gadget>
<output>4_400</output>
<gadget id="calculator">floor(4_400)</gadget>
<output>4_400</output>
<result>C</result> | C | 4,400 | 10% people of a village in Sri Lanka died by bombardment, 20% of the remainder left the village on account of fear. If now the population is reduced to 3168, how much was it in the beginning? | {
"A": "3800",
"B": "4200",
"C": "4400",
"D": "4500",
"E": "4600"
} | floor(divide(3168, multiply(divide(subtract(const_100, 10), const_100), divide(subtract(const_100, 20), const_100)))) | subtract(const_100,n0)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|divide(n2,#4)|floor(#5)| | "x * ( 90 / 100 ) * ( 80 / 100 ) = 3168 x = 4400 answer : c" | general |
math_qa__grqbD5zidDnr1Geq | 60 men shake hands with each other. Maximum no of handshakes without cyclic handshakes. Choose the correct choice.
A) 190
B) 200
C) 210
D) 1770
E) 230 | <gadget id="calculator">60 - 1</gadget>
<output>59</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">59 * 30</gadget>
<output>1_770</output>
<result>D</result> | D | 1,770 | 60 men shake hands with each other. Maximum no of handshakes without cyclic handshakes. | {
"A": "190",
"B": "200",
"C": "210",
"D": "1770",
"E": "230"
} | multiply(subtract(60, const_1), divide(60, const_2)) | divide(n0,const_2)|subtract(n0,const_1)|multiply(#0,#1)| | "1 st person will shake hand with 59 people 2 nd person will shake hand with 58 people 3 rd person will shake hand with 57 people . . . . . . total no . of handshakes = 59 + 58 + 57 + . . . + 3 + 2 + 1 = 19 * ( 19 + 1 ) / 2 = 1770 or , if there are n persons then no . of shakehands = nc 2 = 60 c 2 = 1770 answer : d" | general |
math_qa__ZKhn0MQ8koM5n0Jz | What is the difference between the C.I. on Rs. 4000 for 1 1/2 years at 4% per annum compounded yearly and half-yearly? Choose one.
A) s . 2.04
B) s . 2.08
C) s . 1.63
D) s . 2.83
E) s . 2.42 | <gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">1 + (1/50)</gadget>
<output>51/50 = around 1.02</output>
<gadget id="calculator">(51/50) * (51/50)</gadget>
<output>2_601/2_500 = around 1.0404</output>
<gadget id="calculator">(2_601/2_500) * (51/50)</gadget>
<output>132_651/125_000 = around 1.061208</output>
<gadget id="calculator">4_000 * (132_651/125_000)</gadget>
<output>530_604/125 = around 4_244.832</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(51/50) * (26/25)</gadget>
<output>663/625 = around 1.0608</output>
<gadget id="calculator">4_000 * (663/625)</gadget>
<output>21_216/5 = around 4_243.2</output>
<gadget id="calculator">(530_604/125) - (21_216/5)</gadget>
<output>204/125 = around 1.632</output>
<result>C</result> | C | 1.63 | What is the difference between the C.I. on Rs. 4000 for 1 1/2 years at 4% per annum compounded yearly and half-yearly? | {
"A": "s . 2.04",
"B": "s . 2.08",
"C": "s . 1.63",
"D": "s . 2.83",
"E": "s . 2.42"
} | subtract(multiply(4000, multiply(multiply(add(1, divide(2, const_100)), add(1, divide(2, const_100))), add(1, divide(2, const_100)))), multiply(4000, multiply(add(1, divide(2, const_100)), add(1, divide(4, const_100))))) | divide(n3,const_100)|divide(n4,const_100)|add(#0,n1)|add(#1,n1)|multiply(#2,#2)|multiply(#2,#3)|multiply(#2,#4)|multiply(n0,#5)|multiply(n0,#6)|subtract(#8,#7)| | "c . i . when interest is compounded yearly = [ 4000 * ( 1 + 4 / 100 ) * ( 1 + ( 1 / 2 * 4 ) / 100 ] = 4000 * 26 / 25 * 51 / 50 = rs . 4243.2 c . i . when interest is compounded half - yearly = [ 4000 * ( 1 + 2 / 100 ) 2 ] = ( 4000 * 51 / 50 * 51 / 50 * 51 / 50 ) = rs . 4244.83 difference = ( 4244.83 - 4243.2 ) = rs . 1.63 . answer : c" | general |
math_qa__8fDxHuC5j5FFnvSm | Approximately what percentage of the world’s forested area is represented by Finland given that Finland has 53.42 million hectares of forested land of the world’s 8.076 billion hectares of forested land. Choose the correct choice from the following options
A) 0.0066 % B) 0.066 % C) 0.66 % D) 6.6 % E) 66 % | <gadget id="calculator">53.42 / 3</gadget>
<output>17.806667</output>
<gadget id="calculator">17.806667 / 3</gadget>
<output>5.935556</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">5.935556 / 9</gadget>
<output>0.659506</output>
<result>C</result> | C | 0.66 | Approximately what percentage of the world’s forested area is represented by Finland given that Finland has 53.42 million hectares of forested land of the world’s 8.076 billion hectares of forested land. | {
"A": "0.0066 %",
"B": "0.066 %",
"C": "0.66 %",
"D": "6.6 %",
"E": "66 %"
} | divide(divide(divide(53.42, const_3), const_3), subtract(const_10, const_1)) | divide(n0,const_3)|subtract(const_10,const_1)|divide(#0,const_3)|divide(#2,#1) | since 1 billion is 1000 million soc changing all quantities to million finland forest area = 53.42 million hect . worlds ' s forest area = 8.076 billion hect . % = 53.42 * 100 / 8.076 * 1000 = 0.66 % answer c | general |
math_qa__Bbeej0waoWIWiVci | Two stations A and B are 65 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? Select:
A) 9 B) 10 C) 11 D) 12 E) 8 | <gadget id="calculator">65 - 20</gadget>
<output>45</output>
<gadget id="calculator">25 + 20</gadget>
<output>45</output>
<gadget id="calculator">45 / 45</gadget>
<output>1</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<result>A</result> | A | 9 | Two stations A and B are 65 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "8"
} | add(8, divide(subtract(65, 20), add(25, 20))) | add(n2,n4)|subtract(n0,n2)|divide(#1,#0)|add(n3,#2) | suppose they meet x hours after 7 a . m . distance covered by a in x hours = 20 x km . distance covered by b in ( x - 1 ) hours = 25 ( x - 1 ) km . therefore 20 x + 25 ( x - 1 ) = 65 45 x = 90 x = 2 . so , they meet at 9 a . m . answer : option a | physics |
math_qa__WWgZ2NXtPVGuLGMz | The total age of A and B is 13 years more than the total age of B and C. C is how many years younger than A.? Choose the correct answer:
A) 16 B) 12 C) 15 D) 20 E) 13 | <gadget id="calculator">13 * 1</gadget>
<output>13</output>
<result>E</result> | E | 13 | The total age of A and B is 13 years more than the total age of B and C. C is how many years younger than A.? | {
"A": "16",
"B": "12",
"C": "15",
"D": "20",
"E": "13"
} | multiply(13, const_1) | multiply(n0,const_1)| | "( a + b ) - ( b - c ) = 13 a - c = 13 answer is e" | general |
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