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math_qa__WKMYaDJVxzB4acWs | A shopkeeper sold 50articles at the cost price of 60 articles. Then find the profit% or lost% Choose the correct choice from the following options: A) 20 % B) 22 % C) 25 % D) 30 % E) 35 % | <gadget id="calculator">60 - 50</gadget>
<output>10</output>
<gadget id="calculator">10 / 50</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>A</result> | A | 20 | A shopkeeper sold 50articles at the cost price of 60 articles. Then find the profit% or lost% | {
"A": "20 %",
"B": "22 %",
"C": "25 %",
"D": "30 %",
"E": "35 %"
} | multiply(divide(subtract(60, 50), 50), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "here 50 articles selling price = 60 articles cost price so the difference = 60 - 50 = 10 % of profit = 10 * 100 / 50 = 20 % correct option is a" | gain |
math_qa__KwMvErFYGJPdB6Wy | The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 3000 for a computer table, then what was the cost price of the computer table? Choose the correct choice.
A) 2500 B) 2772 C) 1991 D) 6725 E) 2099 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">3_000 / (6/5)</gadget>
<output>2_500</output>
<result>A</result> | A | 2,500 | The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 3000 for a computer table, then what was the cost price of the computer table? | {
"A": "2500",
"B": "2772",
"C": "1991",
"D": "6725",
"E": "2099"
} | divide(3000, add(const_1, divide(20, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "cp = sp * ( 100 / ( 100 + profit % ) ) = 3000 ( 100 / 120 ) = rs . 2500 . answer : a" | gain |
math_qa__DUtm1mxAignhZ7eQ | Suresh can complete a job in 15 hours. Ashutosh alone can complete the same job in 20 hours. Suresh works for 9 hours and then the remaining job is completed by Ashutosh. How many hours will it take Ashutosh to complete the remaining job alone? Choose the correct choice.
A) 4 B) 5 C) 8 D) 12 E) none of these | <gadget id="calculator">9 / 15</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 20</gadget>
<output>8</output>
<result>C</result> | C | 8 | Suresh can complete a job in 15 hours. Ashutosh alone can complete the same job in 20 hours. Suresh works for 9 hours and then the remaining job is completed by Ashutosh. How many hours will it take Ashutosh to complete the remaining job alone? | {
"A": "4",
"B": "5",
"C": "8",
"D": "12",
"E": "none of these"
} | multiply(subtract(const_1, divide(9, 15)), 20) | divide(n2,n0)|subtract(const_1,#0)|multiply(n1,#1) | the part of job that suresh completes in 9 hours = 9 â „ 15 = 3 â „ 5 remaining job = 1 - 3 â „ 5 = 2 â „ 5 remaining job can be done by ashutosh in 2 â „ 5 ã — 20 = 8 hours answer c | physics |
math_qa__FPGX9ebeBrS0pO7H | Sonika deposited Rs.9000 which amounted to Rs.10200 after 3 years at simple interest. Had the interest been 2% more. She would get how much?
Choose the correct choice from the following choices.
A) 9680
B) 2277
C) 2999
D) 10700
E) 10740 | <gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">10_200 - 9_000</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 3</gadget>
<output>400</output>
<gadget id="calculator">400 / 9_000</gadget>
<output>2/45 = around 0.044444</output>
<gadget id="calculator">(1/50) + (2/45)</gadget>
<output>29/450 = around 0.064444</output>
<gadget id="calculator">(29/450) * 9_000</gadget>
<output>580</output>
<gadget id="calculator">580 * 3</gadget>
<output>1_740</output>
<gadget id="calculator">1_740 + 9_000</gadget>
<output>10_740</output>
<result>E</result> | E | 10,740 | Sonika deposited Rs.9000 which amounted to Rs.10200 after 3 years at simple interest. Had the interest been 2% more. She would get how much? | {
"A": "9680",
"B": "2277",
"C": "2999",
"D": "10700",
"E": "10740"
} | add(multiply(multiply(add(divide(2, const_100), divide(divide(subtract(10200, 9000), 3), 9000)), 9000), 3), 9000) | divide(n3,const_100)|subtract(n1,n0)|divide(#1,n2)|divide(#2,n0)|add(#0,#3)|multiply(n0,#4)|multiply(n2,#5)|add(n0,#6)| | "( 9000 * 3 * 2 ) / 100 = 540 10200 - - - - - - - - 10740 answer : e" | gain |
math_qa__ZaNfRiZtDiiqOMos | Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 85. If Jerry wants to raise his average by 3 points, what score must he earn on the fourth test? Choose the correct option.
A) 97 B) 89 C) 90 D) 93 E) 95 | <gadget id="calculator">85 + 3</gadget>
<output>88</output>
<gadget id="calculator">4 * 88</gadget>
<output>352</output>
<gadget id="calculator">85 * 3</gadget>
<output>255</output>
<gadget id="calculator">352 - 255</gadget>
<output>97</output>
<result>A</result> | A | 97 | Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 85. If Jerry wants to raise his average by 3 points, what score must he earn on the fourth test? | {
"A": "97",
"B": "89",
"C": "90",
"D": "93",
"E": "95"
} | subtract(multiply(4, add(85, 3)), multiply(85, 3)) | add(n2,n3)|multiply(n0,n2)|multiply(n1,#0)|subtract(#2,#1)| | "total score on 3 tests = 85 * 3 = 255 jerry wants the average to be = 88 hence total score on 4 tests should be = 88 * 4 = 352 score required on the fourth test = 352 - 255 = 97 option a" | general |
math_qa__dyJCLBsBCiXQftul | Calculate how much time could be saved if the train would run at its usual speed, given that it ran at 4/9 of its own speed and got to its destination in 13 hours? Choose the most appropriate option
A) 1.22 hrs B) 2.22 hrs C) 5.22 hrs D) 6.22 hrs E) 7.22 hrs | <gadget id="calculator">13 * 60</gadget>
<output>780</output>
<gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">13 * (4/9)</gadget>
<output>52/9 = around 5.777778</output>
<gadget id="calculator">(52/9) * 60</gadget>
<output>1_040/3 = around 346.666667</output>
<gadget id="calculator">780 - (1_040/3)</gadget>
<output>1_300/3 = around 433.333333</output>
<gadget id="calculator">(1_300/3) % 60</gadget>
<output>40/3 = around 13.333333</output>
<gadget id="calculator">(40/3) / 100</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(1_300/3) / 60</gadget>
<output>65/9 = around 7.222222</output>
<gadget id="calculator">floor(65/9)</gadget>
<output>7</output>
<gadget id="calculator">(2/15) + 7</gadget>
<output>107/15 = around 7.133333</output>
<result>E</result> | E | 7.22 | Calculate how much time could be saved if the train would run at its usual speed, given that it ran at 4/9 of its own speed and got to its destination in 13 hours? | {
"A": "1.22 hrs",
"B": "2.22 hrs",
"C": "5.22 hrs",
"D": "6.22 hrs",
"E": "7.22 hrs"
} | add(divide(reminder(subtract(multiply(13, const_60), multiply(multiply(13, divide(4, 9)), const_60)), const_60), const_100), floor(divide(subtract(multiply(13, const_60), multiply(multiply(13, divide(4, 9)), const_60)), const_60))) | divide(n0,n1)|multiply(n2,const_60)|multiply(n2,#0)|multiply(#2,const_60)|subtract(#1,#3)|divide(#4,const_60)|reminder(#4,const_60)|divide(#6,const_100)|floor(#5)|add(#7,#8)| | "new speed = 4 / 9 of usual speed new time = 4 / 9 of usual time 4 / 9 of usual time = 13 hrs usual time = 13 * 4 / 9 = 5.78 hrs time saved = 13 - 5.78 = 7.22 hrs answer is e" | physics |
math_qa__ob4M1jlnRHgKQgTD | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.3 years. The ration of the number of boys to the number of girls in the class is?
Choose the correct choice from the following
A) 5 : 6 B) 2 : 3 C) 2 : 5 D) 2 : 1 E) 2 : 4 | <gadget id="calculator">15.8 - 15.3</gadget>
<output>0.5</output>
<gadget id="calculator">16.4 - 15.8</gadget>
<output>0.6</output>
<gadget id="calculator">0.5 / 0.6</gadget>
<output>0.833333</output>
<result>A</result> | A | 0.833333 | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.3 years. The ration of the number of boys to the number of girls in the class is? | {
"A": "5 : 6",
"B": "2 : 3",
"C": "2 : 5",
"D": "2 : 1",
"E": "2 : 4"
} | divide(subtract(15.8, 15.3), subtract(16.4, 15.8)) | subtract(n0,n2)|subtract(n1,n0)|divide(#0,#1)| | "let the ratio be k : 1 . then , k * 16.4 + 1 * 15.3 = ( k + 1 ) * 15.8 = ( 16.4 - 15.8 ) k = ( 15.8 - 15.3 ) = k = 0.5 / 0.6 = 5 / 6 required ratio = 5 / 6 : 1 = 5 : 6 . answer : a" | general |
math_qa__DRTlUs9nHDPB76Gn | A boy is travelling from his home to school at 6km/hr and reached 7min late. Next day he travelled at 12km/hr and reached 8min early. Distance between home and school?
Choose the correct choice from the following choices:
A) 2 km
B) 3 km
C) 4 km
D) 5 km
E) 6 km | <gadget id="calculator">7 / 60</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">8 / 60</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(7/60) + (2/15)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/4) / (1/12)</gadget>
<output>3</output>
<result>B</result> | B | 3 | A boy is travelling from his home to school at 6km/hr and reached 7min late. Next day he travelled at 12km/hr and reached 8min early. Distance between home and school? | {
"A": "2 km",
"B": "3 km",
"C": "4 km",
"D": "5 km",
"E": "6 km"
} | divide(add(divide(7, const_60), divide(8, const_60)), divide(const_1, 12)) | divide(n1,const_60)|divide(n3,const_60)|divide(const_1,n2)|add(#0,#1)|divide(#3,#2)| | "let the distance be x t 1 = x / 6 hr t 2 = x / 12 hr difference in time = 7 + 8 = 15 = 1 / 4 hr x / 6 - x / 12 = 1 / 4 x / 12 = 1 / 4 x = 3 km answer is b" | physics |
math_qa__uY6NZK4Jpur4cPxW | 44 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be : Choose the correct choice from the following:
A) 56 m
B) 88 m
C) 120 m
D) 137 m
E) none | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * pi</gadget>
<output>pi/4 = around 0.785398</output>
<gadget id="calculator">44 / (pi/4)</gadget>
<output>176/pi = around 56.02254</output>
<result>A</result> | A | 56 | 44 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be : | {
"A": "56 m",
"B": "88 m",
"C": "120 m",
"D": "137 m",
"E": "none"
} | divide(44, multiply(power(divide(1, const_2), const_2), const_pi)) | divide(n1,const_2)|power(#0,const_2)|multiply(#1,const_pi)|divide(n0,#2)| | "sol . let the length of the wire b h . radius = 1 / 2 mm = 1 / 20 cm . then , 22 / 7 * 1 / 20 * 1 / 20 * h = 44 ⇔ = [ 44 * 20 * 20 * 7 / 22 ] = 5600 cm = 56 m . answer a" | physics |
math_qa__xsrD9xM8XbceHii6 | A boat can travel with a speed of 24 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 84 km downstream
Pick one.
A) 3 hours
B) 4 hours
C) 5 hours
D) 6 hours
E) 7 hours | <gadget id="calculator">24 + 4</gadget>
<output>28</output>
<gadget id="calculator">84 / 28</gadget>
<output>3</output>
<result>A</result> | A | 3 | A boat can travel with a speed of 24 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 84 km downstream | {
"A": "3 hours",
"B": "4 hours",
"C": "5 hours",
"D": "6 hours",
"E": "7 hours"
} | divide(84, add(24, 4)) | add(n0,n1)|divide(n2,#0)| | "explanation : speed of the boat in still water = 24 km / hr speed of the stream = 4 km / hr speed downstream = ( 22 + 5 ) = 28 km / hr distance travelled downstream = 84 km time taken = distance / speed = 84 / 28 = 3 hours answer : option a" | physics |
math_qa__doPE2jfHUF6OWkpF | If 75 % of a boys answered the first question on a certain test correctly, 55 % answered the second question on the test correctly, and 20 % answered neither of the questions correctly, what % answered both correctly? Pick: A) 10 % B) ( 8 ) 20 % C) 50 % D) 60 % E) 65 % | <gadget id="calculator">75 + 55</gadget>
<output>130</output>
<gadget id="calculator">130 + 20</gadget>
<output>150</output>
<gadget id="calculator">150 - 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | If 75 % of a boys answered the first question on a certain test correctly, 55 % answered the second question on the test correctly, and 20 % answered neither of the questions correctly, what % answered both correctly? | {
"A": "10 %",
"B": "( 8 ) 20 %",
"C": "50 %",
"D": "60 %",
"E": "65 %"
} | subtract(add(add(75, 55), 20), const_100) | add(n0,n1)|add(n2,#0)|subtract(#1,const_100) | { total } = { first } + { second } - { both } + { neither } 100 % = 75 % + 55 % - { both } + 20 % - - > { both } = 50 % . answer : c | other |
math_qa__L0YEdHAvDqWPlSDU | The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child? Select:
A) 9 B) 8 C) 7 D) 6 E) 4 | <gadget id="calculator">50 / 5</gadget>
<output>10</output>
<gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">7 - 3</gadget>
<output>4</output>
<result>E</result> | E | 4 | The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child? | {
"A": "9",
"B": "8",
"C": "7",
"D": "6",
"E": "4"
} | subtract(subtract(divide(50, 5), 3), 3) | divide(n2,n0)|subtract(#0,n1)|subtract(#1,n1) | let the age of the youngest child = x then , the ages of 5 children can be written as x , ( x + 3 ) , ( x + 6 ) , ( x + 9 ) and ( x + 12 ) x + ( x + 3 ) + ( x + 6 ) + ( x + 9 ) + ( x + 12 ) = 50 ⇒ 5 x + 30 = 50 ⇒ 5 x = 20 ⇒ x = 205 = 4 answer is e . | general |
math_qa__x6Pq21VrckOrPxYK | A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 6x km. Choose the correct choice from the following options.
A) 40 kmph B) 45 kmph C) 48 kmph D) 50 kmph E) 55 kmph | <gadget id="calculator">40 * 6</gadget>
<output>240</output>
<gadget id="calculator">40 / 40</gadget>
<output>1</output>
<gadget id="calculator">2 * 40</gadget>
<output>80</output>
<gadget id="calculator">80 / 20</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">240 / 5</gadget>
<output>48</output>
<result>C</result> | C | 48 | A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 6x km. | {
"A": "40 kmph",
"B": "45 kmph",
"C": "48 kmph",
"D": "50 kmph",
"E": "55 kmph"
} | divide(multiply(40, 6), add(divide(40, 40), divide(multiply(2, 40), 20))) | divide(n0,n0)|multiply(n0,n3)|multiply(n0,n1)|divide(#2,n2)|add(#0,#3)|divide(#1,#4)| | "total time taken = x / 40 + 2 x / 20 hours = 5 x / 40 = x / 8 hours average speed = 6 x / ( x / 8 ) = 48 kmph answer : c" | general |
math_qa__E4YddEIMmWpVdV7r | Mary works in a restaurant a maximum of 45 hours. For the first 20 hours, she is paid $8 per hour. For each overtime hour, she is paid at a rate which is 25% higher than her regular rate. How much Mary can earn in a week? Options: A) 300 B) 420 C) 410 D) 320 E) 400 | <gadget id="calculator">45 * 8</gadget>
<output>360</output>
<gadget id="calculator">45 - 20</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">8 * (1/4)</gadget>
<output>2</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">360 + 50</gadget>
<output>410</output>
<result>C</result> | C | 410 | Mary works in a restaurant a maximum of 45 hours. For the first 20 hours, she is paid $8 per hour. For each overtime hour, she is paid at a rate which is 25% higher than her regular rate. How much Mary can earn in a week? | {
"A": "300",
"B": "420",
"C": "410",
"D": "320",
"E": "400"
} | add(multiply(45, 8), multiply(subtract(45, 20), multiply(8, divide(25, const_100)))) | divide(n3,const_100)|multiply(n0,n2)|subtract(n0,n1)|multiply(n2,#0)|multiply(#3,#2)|add(#1,#4)| | "mary receives $ 8 ( 20 ) = $ 160 for the first 20 hours . for the 25 overtime hours , she receives $ 8 ( 0.25 ) + $ 8 = $ 10 per hour , that is $ 10 ( 25 ) = $ 250 . the total amount is $ 160 + $ 250 = $ 410 answer c 410 ." | gain |
math_qa__zF3ooV1V7eNSmctb | A 20% stock yielding 8% is quoted at? Pick one
A) 165 B) 170 C) 250 D) 180 E) 185 | <gadget id="calculator">100 / 8</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 20</gadget>
<output>250</output>
<result>C</result> | C | 250 | A 20% stock yielding 8% is quoted at? | {
"A": "165",
"B": "170",
"C": "250",
"D": "180",
"E": "185"
} | multiply(divide(const_100, 8), 20) | divide(const_100,n1)|multiply(n0,#0)| | "assume that face value = rs . 100 as it is not given to earn rs . 8 , money invested = rs . 100 to earn rs . 20 , money invested = 100 × 20 / 8 = rs . 250 ie , market value of the stock = rs . 250 answer is c ." | gain |
math_qa__HmMIdaYPvkgoDgBu | When n is divided by 5 the remainder is 3. What is the remainder when (n-1)^2 is divided by 5? Choose the correct choice from the following answers:
A) 0
B) 1
C) 2
D) 3
E) 4 | <gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 ** 2</gadget>
<output>49</output>
<gadget id="calculator">49 / 5</gadget>
<output>49/5 = around 9.8</output>
<gadget id="calculator">floor(49/5)</gadget>
<output>9</output>
<gadget id="calculator">9 * 5</gadget>
<output>45</output>
<gadget id="calculator">49 - 45</gadget>
<output>4</output>
<result>E</result> | E | 4 | When n is divided by 5 the remainder is 3. What is the remainder when (n-1)^2 is divided by 5? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | subtract(power(subtract(add(5, 3), 1), 2), multiply(floor(divide(power(subtract(add(5, 3), 1), 2), 5)), 5)) | add(n0,n1)|subtract(#0,n2)|power(#1,n3)|divide(#2,n0)|floor(#3)|multiply(n0,#4)|subtract(#2,#5) | n = 5 x + 3 , for some integer x ( n - 1 ) ^ 2 = ( 5 x + 2 ) ^ 2 = 5 y + 4 , for some integer y when we divide this by 5 , the remainder is 4 . the answer is e . | general |
math_qa__wsi3s6ihSGJ3HJzb | How many 1/12s are there in 37 1/2? Answers:
A) 350
B) 450
C) 500
D) 650
E) 700 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">37 + (1/2)</gadget>
<output>75/2 = around 37.5</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(75/2) / (1/12)</gadget>
<output>450</output>
<result>B</result> | B | 450 | How many 1/12s are there in 37 1/2? | {
"A": "350",
"B": "450",
"C": "500",
"D": "650",
"E": "700"
} | divide(add(37, divide(1, 2)), divide(1, 12)) | divide(n0,n4)|divide(n0,n1)|add(n2,#0)|divide(#2,#1)| | "required number = ( 75 / 2 ) / ( 1 / 12 ) = ( 75 / 2 x 12 / 1 ) = 450 . answer : b" | general |
math_qa__EVPS18DtRFU0zD3k | .The price of commodity P increases by 40 paise every year, while the price of commodity Q increases by 15 paise every year. If in 2001, the price of commodity P was Rs. 4.20 and that of Q was Rs. 6.30, in which year commodity P will cost 40 paise more than the commodity Q ? Answers.
A) 2008
B) 2009
C) 2010
D) 2011
E) none of these | <gadget id="calculator">6.3 - 4.2</gadget>
<output>2.1</output>
<gadget id="calculator">40 + 2.1</gadget>
<output>42.1</output>
<gadget id="calculator">40 - 15</gadget>
<output>25</output>
<gadget id="calculator">42.1 / 25</gadget>
<output>1.684</output>
<gadget id="calculator">2_001 + 1.684</gadget>
<output>2_002.684</output>
<result>D</result> | D | 2,011 | .The price of commodity P increases by 40 paise every year, while the price of commodity Q increases by 15 paise every year. If in 2001, the price of commodity P was Rs. 4.20 and that of Q was Rs. 6.30, in which year commodity P will cost 40 paise more than the commodity Q ? | {
"A": "2008",
"B": "2009",
"C": "2010",
"D": "2011",
"E": "none of these"
} | add(2001, divide(add(40, subtract(6.3, 4.2)), subtract(40, 15))) | subtract(n4,n3)|subtract(n0,n1)|add(n0,#0)|divide(#2,#1)|add(n2,#3) | explanation : let the commodity p costs 40 paise more than the commodity q after n years price of the commodity p in 2001 = rs . 4.20 since the price of the commodity p increases by rs 0.40 every year , price of the commodity p after n years from 2001 = rs . 4.20 + ( n × . 40 ) price of the commodity q in 2001 = rs . 6.30 since the price of the commodity q increases by rs 0.15 every year , price of the commodity q after n years from 2001 = rs . 6.30 + ( n × . 15 ) since the commodity p costs rs . 0.40 more that the commodity q after n years from 2001 , 4.20 + ( n × . 40 ) = 6.30 + ( n × . 15 ) + 0.40 = > ( 40 n - . 15 n ) = 6.30 - 4.20 + 0.40 = 2.5 = > . 25 n = 2.5 ⇒ n = 2.5 / . 25 = 250 / 25 = 101.15 ¯ = > commodity p costs rs . 0.40 more that the commodity q after 10 years from 2001 . i . e . , in 2011 . answer : option d | general |
math_qa__rX6pTxgoryyC3ukr | If a certain coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 6 times, what is the probability that it will land heads up on the first 3 flips but not on the last 3 flips?
Options
A) 1 / 8 B) 1 / 16 C) 1 / 32 D) 1 / 64 E) 1 / 128 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 6</gadget>
<output>1/64 = around 0.015625</output>
<result>D</result> | D | 0.015625 | If a certain coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 6 times, what is the probability that it will land heads up on the first 3 flips but not on the last 3 flips? | {
"A": "1 / 8",
"B": "1 / 16",
"C": "1 / 32",
"D": "1 / 64",
"E": "1 / 128"
} | power(divide(1, 2), 6) | divide(n0,n1)|power(#0,n2)| | "p ( hhhttt ) = 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 = 1 / 64 the answer is d ." | probability |
math_qa__JNrOQlixPkcutWQz | A merchant marks his goods up by 50% and then offers a discount of 20% on the marked price. What % profit does the merchant make after the discount? Select the correct option:
A) 20 % B) 25 % C) 69 % D) 31 % E) 19 % | <gadget id="calculator">50 + 100</gadget>
<output>150</output>
<gadget id="calculator">150 * 20</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 100</gadget>
<output>30</output>
<gadget id="calculator">150 - 30</gadget>
<output>120</output>
<gadget id="calculator">120 - 100</gadget>
<output>20</output>
<result>A</result> | A | 20 | A merchant marks his goods up by 50% and then offers a discount of 20% on the marked price. What % profit does the merchant make after the discount? | {
"A": "20 %",
"B": "25 %",
"C": "69 %",
"D": "31 %",
"E": "19 %"
} | subtract(subtract(add(50, const_100), divide(multiply(add(50, const_100), 20), const_100)), const_100) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(#3,const_100)| | "let the price be 100 . the price becomes 150 after a 50 % markup . now a discount of 20 % on 150 . profit = 120 - 100 20 % answer a" | gain |
math_qa__37qegZqGOz5gXWwF | A number when divided by a divisor leaves a remainder of 27. When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor? Select the correct option:
A) 12 B) 13 C) 35 D) 40 E) 59 | <gadget id="calculator">27 + 11</gadget>
<output>38</output>
<result>D</result> | D | 40 | A number when divided by a divisor leaves a remainder of 27. When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor? | {
"A": "12",
"B": "13",
"C": "35",
"D": "40",
"E": "59"
} | add(27, 11) | add(n0,n1)| | "let the number is n , the divisor = d , i will make the two equations - n = xd + 27 2 n = yd + 11 where x and y are integers solving them : d ( y - 2 x ) = 40 as d is also integer and 40 is a prime number , the d should be 40 to satisfy the above equation . hence answer is ' d '" | general |
math_qa__yJMpf76gykvb9ZG0 | In an office, totally there are 2200 employees and 40% of the total employees are males. 30% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years?
Choose the correct choice from the following options.
A) 661 B) 600 C) 620 D) 616 E) none of these | <gadget id="calculator">2_200 * 40</gadget>
<output>88_000</output>
<gadget id="calculator">88_000 / 100</gadget>
<output>880</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">880 * (7/10)</gadget>
<output>616</output>
<result>D</result> | D | 616 | In an office, totally there are 2200 employees and 40% of the total employees are males. 30% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years? | {
"A": "661",
"B": "600",
"C": "620",
"D": "616",
"E": "none of these"
} | multiply(divide(multiply(2200, 40), const_100), divide(subtract(const_100, 30), const_100)) | multiply(n0,n1)|subtract(const_100,n2)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)| | "number of male employees = 2200 * 40 / 100 = 880 required number of male employees who are less than 50 years old = 880 * ( 100 - 30 ) % = 880 * 75 / 100 = 616 . answer : d" | general |
math_qa__eR3lidCwQxxseoC3 | The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Choose the correct choice from the following
A) 4 B) 5 C) 9 D) 8 E) 10 | <gadget id="calculator">50 / 5</gadget>
<output>10</output>
<gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">7 - 3</gadget>
<output>4</output>
<result>A</result> | A | 4 | The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child? | {
"A": "4",
"B": "5",
"C": "9",
"D": "8",
"E": "10"
} | subtract(subtract(divide(50, 5), 3), 3) | divide(n2,n0)|subtract(#0,n1)|subtract(#1,n1)| | "the age of children x , ( x + 3 ) , ( x + 6 ) , ( x + 9 ) and ( x + 12 ) years . x + ( x + 3 ) + ( x + 6 ) + ( x + 9 ) + ( x + 12 ) = 50 5 x = 20 , x = 4 . correct answer ( a )" | general |
math_qa__LS2zwSZ6JWyR0pT8 | If Jake loses 35 pounds, he will weigh thrice as much as his sister. Together they now weigh 275 pounds. What is Jake's present weight, in pounds? Pick
A) 131 B) 135 C) 139 D) 147 E) 188 | <gadget id="calculator">2 * 275</gadget>
<output>550</output>
<gadget id="calculator">550 + 35</gadget>
<output>585</output>
<gadget id="calculator">585 / 3</gadget>
<output>195</output>
<result>E</result> | E | 188 | If Jake loses 35 pounds, he will weigh thrice as much as his sister. Together they now weigh 275 pounds. What is Jake's present weight, in pounds? | {
"A": "131",
"B": "135",
"C": "139",
"D": "147",
"E": "188"
} | divide(add(multiply(const_2, 275), 35), const_3) | multiply(n1,const_2)|add(n0,#0)|divide(#1,const_3) | j = jake ’ s current weight , in pounds s = sister ’ s current weight , in pounds we are told that “ if jake loses 8 pounds , he will weigh twice as much as his sister . we put this into an equation : j – 35 = 3 s j = 3 s + 35 ( equation 1 ) next , we are told that “ together they now weigh 275 pounds . ” we can also put this into an equation . j + s = 275 ( equation 2 ) to solve this equation , we can substitute 2 s + 8 from equation 1 for the variable j in equation 2 : 3 s + 35 = 275 - s 4 s = 240 s = 60 j + 60 = 275 j = 215 answer : e | general |
math_qa__tH7nJGM7WXiDdYXz | Pipe A fills a tank of capacity 900 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full? Pick one:
A) 42 minutes
B) 14 minutes
C) 54 minutes
D) 40 minutes 20 seconds
E) none of these | <gadget id="calculator">40 + 30</gadget>
<output>70</output>
<gadget id="calculator">70 - 20</gadget>
<output>50</output>
<gadget id="calculator">900 / 50</gadget>
<output>18</output>
<gadget id="calculator">18 * 3</gadget>
<output>54</output>
<result>C</result> | C | 54 | Pipe A fills a tank of capacity 900 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full? | {
"A": "42 minutes",
"B": "14 minutes",
"C": "54 minutes",
"D": "40 minutes 20 seconds",
"E": "none of these"
} | multiply(divide(900, subtract(add(40, 30), 20)), const_3) | add(n1,n2)|subtract(#0,n3)|divide(n0,#1)|multiply(#2,const_3)| | "in one cycle they fill 40 + 30 - 20 = 50 liters 900 = 50 * n = > n = 18 here n = number of cycles . total time = 18 * 3 = 54 as in one cycle there are 3 minutes . thus 54 minutes answer : c" | physics |
math_qa__cJpQwUIb71j595oe | How many even number in the range between 6 to 100 inclusive are not divisible by 3 Choose the correct answer:
A) 15 B) 30 C) 32 D) 33 E) 46 | <gadget id="calculator">100 - 6</gadget>
<output>94</output>
<gadget id="calculator">94 - 2</gadget>
<output>92</output>
<gadget id="calculator">92 / 2</gadget>
<output>46</output>
<gadget id="calculator">100 - 2</gadget>
<output>98</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">98 - 12</gadget>
<output>86</output>
<gadget id="calculator">86 - 3</gadget>
<output>83</output>
<gadget id="calculator">83 - 3</gadget>
<output>80</output>
<gadget id="calculator">80 / 3</gadget>
<output>80/3 = around 26.666667</output>
<gadget id="calculator">(80/3) / 2</gadget>
<output>40/3 = around 13.333333</output>
<gadget id="calculator">46 - (40/3)</gadget>
<output>98/3 = around 32.666667</output>
<result>C</result> | C | 32 | How many even number in the range between 6 to 100 inclusive are not divisible by 3 | {
"A": "15",
"B": "30",
"C": "32",
"D": "33",
"E": "46"
} | subtract(divide(subtract(subtract(100, 6), const_2), const_2), divide(divide(subtract(subtract(subtract(subtract(100, const_2), multiply(3, const_4)), 3), 3), 3), const_2)) | multiply(n2,const_4)|subtract(n1,n0)|subtract(n1,const_2)|subtract(#1,const_2)|subtract(#2,#0)|divide(#3,const_2)|subtract(#4,n2)|subtract(#6,n2)|divide(#7,n2)|divide(#8,const_2)|subtract(#5,#9)| | "we have to find the number of terms that are divisible by 2 but not by 6 ( as the question asks for the even numbers only which are not divisible by 3 ) for 2 , 6 , 8,10 , 12,14 . . . 100 using ap formula , we can say 100 = 10 + ( n - 1 ) * 2 or n = 48 . for 6 , 6 , 12,18 , . . . 96 using ap formula , we can say 96 = 12 + ( n - 1 ) * 6 or n = 16 . hence , only divisible by 2 but not 3 = 48 - 16 = 32 . hence , answer c" | general |
math_qa__4QLp5WkVqr3wJIo7 | 6 workers should finish a job in 8 days. After 3 days came 4 workers join them. How many days Z do they need to finish the same job? Choose the most appropriate option: A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">48 - 18</gadget>
<output>30</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<result>A</result> | A | 3 | 6 workers should finish a job in 8 days. After 3 days came 4 workers join them. How many days Z do they need to finish the same job? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(subtract(multiply(6, 8), multiply(3, 6)), add(6, 4)) | add(n0,n3)|multiply(n0,n1)|multiply(n0,n2)|subtract(#1,#2)|divide(#3,#0)| | "let rate of one worker be r = > ( 6 * r ) * 8 = 1 ( rate * time = work ) = > r = 1 / 48 = > work remaining after 3 days 1 - ( 3 * 6 ) / 48 = 30 / 48 after 4 ppl joined in ( ( 6 + 4 ) * time ) / 48 = 30 / 48 time z = 3 days to finish the task imo a" | physics |
math_qa__hd3k1m91h2GLdQtr | Of the diplomats who attended a summit conference: 20 spoke Latin, 32 did not speak Russian and 20% of the diplomats spoke neither Latin nor Russian. If 10% of the diplomats spoke both Latin and Russian, then how many diplomats attended the conference?
Choose the correct option.
A) 70 B) 96 C) 108 D) 120 E) 150 | <gadget id="calculator">32 - 20</gadget>
<output>12</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/5) - (1/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">12 / (1/10)</gadget>
<output>120</output>
<result>D</result> | D | 120 | Of the diplomats who attended a summit conference: 20 spoke Latin, 32 did not speak Russian and 20% of the diplomats spoke neither Latin nor Russian. If 10% of the diplomats spoke both Latin and Russian, then how many diplomats attended the conference? | {
"A": "70",
"B": "96",
"C": "108",
"D": "120",
"E": "150"
} | divide(subtract(32, 20), subtract(divide(20, const_100), divide(10, const_100))) | divide(n0,const_100)|divide(n3,const_100)|subtract(n1,n0)|subtract(#0,#1)|divide(#2,#3) | 2 x 2 matrix will be the easiest way to calculate this . text in black : given statements text in red : calculated values thus d = 120 is the correct answer | other |
math_qa__qbFdrSvLCHNdsKQ8 | A and B can do a work in 20days, B and C can do it in 30days; A,B and C together can finish it in 40days. A and C together will do it in? Select: A) 25 days B) 30 days C) 20 days D) 15 days E) 10 days | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(1/20) - (1/40)</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(1/30) - (1/40)</gadget>
<output>1/120 = around 0.008333</output>
<gadget id="calculator">(1/120) + (1/40)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / (1/30)</gadget>
<output>30</output>
<result>B</result> | B | 30 | A and B can do a work in 20days, B and C can do it in 30days; A,B and C together can finish it in 40days. A and C together will do it in? | {
"A": "25 days",
"B": "30 days",
"C": "20 days",
"D": "15 days",
"E": "10 days"
} | inverse(add(subtract(divide(const_1, 30), subtract(divide(const_1, 20), divide(const_1, 40))), subtract(divide(const_1, 20), divide(const_1, 40)))) | divide(const_1,n1)|divide(const_1,n0)|divide(const_1,n2)|subtract(#1,#2)|subtract(#0,#3)|add(#4,#3)|inverse(#5) | a + b + c 1 day work = 1 / 40 a + b 1 day work = 1 / 20 b + c 1 day work = 1 / 30 a + c 1 day work = 2 * 1 / 40 - 1 / 20 + 1 / 30 = 1 / 30 a and c together will do the work in 30 days . answer is b | physics |
math_qa__KJQttVSdIXfvst9E | Find the greatest number that will divide 54, 87 and 172 so as to leave the same remainder in each case Options
A) 13 B) 3 C) 15 D) 1 E) 2 | <gadget id="calculator">172 - 87</gadget>
<output>85</output>
<gadget id="calculator">85 - 54</gadget>
<output>31</output>
<gadget id="calculator">87 - 54</gadget>
<output>33</output>
<gadget id="calculator">gcd(31, 33)</gadget>
<output>1</output>
<gadget id="calculator">gcd(1, 85)</gadget>
<output>1</output>
<result>D</result> | D | 1 | Find the greatest number that will divide 54, 87 and 172 so as to leave the same remainder in each case | {
"A": "13",
"B": "3",
"C": "15",
"D": "1",
"E": "2"
} | gcd(gcd(subtract(subtract(172, 87), 54), subtract(87, 54)), subtract(172, 87)) | subtract(n2,n1)|subtract(n1,n0)|subtract(#0,n0)|gcd(#2,#1)|gcd(#3,#0) | explanation : required number = ( 87 - 54 ) , ( 172 - 87 ) , ( 172 - 54 ) = h . c . f of 33,85 and 118 is 1 answer : option d | general |
math_qa__5Nxs84XW5zqlISzu | Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/9 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent? Choose one.
A) 11 / 30 B) 29 / 60 C) 17 / 30 D) 13 / 18 E) 11 / 15 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/3) * (1/2)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/6) + (1/9)</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">1 - (5/18)</gadget>
<output>13/18 = around 0.722222</output>
<result>D</result> | D | 0.722222 | Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/9 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent? | {
"A": "11 / 30",
"B": "29 / 60",
"C": "17 / 30",
"D": "13 / 18",
"E": "11 / 15"
} | subtract(1, add(multiply(inverse(3), inverse(const_2)), inverse(9))) | inverse(n3)|inverse(n1)|inverse(const_2)|multiply(#1,#2)|add(#0,#3)|subtract(n0,#4)| | "let s assume the platinum card spending limit = x gold card spending limit will be = x / 2 balance on gold card is = x / 2 * 1 / 3 = x / 6 platinum card unspent limit is = x - 1 / 9 x = 8 / 9 x so if gold card balance is transferred then the rest unspent will be 8 / 9 x - x / 6 = 13 / 18 x so the ans is d" | general |
math_qa__GcCJ8GtyO3CgbXip | The number which exceeds 12% of it by 52.8 is: Choose the correct choice from the following choices.
A) 60 B) 77 C) 269 D) 26 E) 91 | <gadget id="calculator">52.8 * 100</gadget>
<output>5_280</output>
<gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">5_280 / 88</gadget>
<output>60</output>
<result>A</result> | A | 60 | The number which exceeds 12% of it by 52.8 is: | {
"A": "60",
"B": "77",
"C": "269",
"D": "26",
"E": "91"
} | divide(multiply(52.8, const_100), subtract(const_100, 12)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "explanation : let the number be x . then , x – 12 % of x = 52.8 x – ( 12 / 100 ) x = 52.8 x ( 1 – 12 / 100 ) = 52.8 ( 88 / 100 ) x = 52.8 x = ( 100 x 52.8 ) / 88 = 60 answer : a" | gain |
math_qa__hw71AVanvszxadFT | According to the directions on the can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12 ounces cans of the concentrate are required to prepare 360 6 ounces servings of orange juice?
Pick.
A) 45 B) 34 C) 50 D) 67 E) 100 | <gadget id="calculator">360 * 6</gadget>
<output>2_160</output>
<gadget id="calculator">2_160 / 12</gadget>
<output>180</output>
<gadget id="calculator">180 / 4</gadget>
<output>45</output>
<result>A</result> | A | 45 | According to the directions on the can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12 ounces cans of the concentrate are required to prepare 360 6 ounces servings of orange juice? | {
"A": "45",
"B": "34",
"C": "50",
"D": "67",
"E": "100"
} | divide(divide(multiply(360, 6), 12), const_4) | multiply(n3,n4)|divide(#0,n2)|divide(#1,const_4)| | "its a . total juice rquired = 360 * 6 = 2160 ounce 12 ounce concentate makes = 12 * 4 = 48 ounce juice total cans required = 2160 / 48 = 45 . answer a" | general |
math_qa__tpwQfiLUQS1c93pX | Two pipes P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 6 minutes the first is turned off. How many more minutes will it take for the cistern to fill after the first pipe is turned off? Choose one.
A) 1
B) 1.5
C) 2
D) 2.5
E) 3 | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/12) + (1/15)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 6</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 - (9/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 15</gadget>
<output>3/2 = around 1.5</output>
<result>B</result> | B | 1.5 | Two pipes P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 6 minutes the first is turned off. How many more minutes will it take for the cistern to fill after the first pipe is turned off? | {
"A": "1",
"B": "1.5",
"C": "2",
"D": "2.5",
"E": "3"
} | multiply(subtract(const_1, multiply(add(divide(const_1, 12), divide(const_1, 15)), 6)), 15) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(#2,n2)|subtract(const_1,#3)|multiply(n1,#4)| | "let x be the total time it takes for the cistern to fill . 6 / 12 + x / 15 = 1 x / 15 = 1 / 2 x = 7.5 after the first pipe is turned off , it takes 1.5 more minutes to fill the cistern . the answer is b ." | physics |
math_qa__x6iqs74bSq41DZ7k | The ratio of flour to water to sugar in a recipe is 11:5:2. The ratio in a new recipe calls for a doubling of the ratio of flour to water from the original recipe and a halving of the ratio of flour to sugar. If the new recipe calls for 7.5 cups of water, how much sugar is required?
Choose one.
A) 8
B) 9
C) 10
D) 11
E) 12 | <gadget id="calculator">7.5 / 5</gadget>
<output>1.5</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">1.5 * 8</gadget>
<output>12</output>
<result>E</result> | E | 12 | The ratio of flour to water to sugar in a recipe is 11:5:2. The ratio in a new recipe calls for a doubling of the ratio of flour to water from the original recipe and a halving of the ratio of flour to sugar. If the new recipe calls for 7.5 cups of water, how much sugar is required? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | multiply(divide(7.5, 5), multiply(const_4, 2)) | divide(n3,n1)|multiply(n2,const_4)|multiply(#0,#1) | the ratio of flour to water is 22 : 5 . the ratio of flour to sugar is 5.5 : 2 = 22 : 8 . the new ratio of flour to water to sugar is 22 : 5 : 8 if we need 7.5 cups of water , then we need 12 cups of sugar . the answer is e . | other |
math_qa__J7N6rx3s6Bjr4GIv | A merchant marks goods up by 60% and then offers a discount on the marked price. The profit that the merchant makes after offering the discount is 20%. What % discount did the merchant offer? Choices
A) 20 % B) 25 % C) 30 % D) 35 % E) 40 % | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 + (3/5)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(8/5) - 1</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/5) - (1/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) / (8/5)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>B</result> | B | 25 | A merchant marks goods up by 60% and then offers a discount on the marked price. The profit that the merchant makes after offering the discount is 20%. What % discount did the merchant offer? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "35 %",
"E": "40 %"
} | multiply(divide(subtract(subtract(add(const_1, divide(60, const_100)), const_1), divide(20, const_100)), add(const_1, divide(60, const_100))), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(#2,const_1)|subtract(#3,#1)|divide(#4,#2)|multiply(#5,const_100)| | "let p be the original price of the goods and let x be the rate after the markup . ( 1.6 p ) * x = 1.2 p x = 1.2 / 1.6 = 0.75 which is a discount of 25 % . the answer is b ." | gain |
math_qa__eXwJVEvjlXXBTnuS | A student scored an average of 65 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics? Choose the correct choice from the following choices
A) 86 B) 165 C) 76 D) 125 E) 26 | <gadget id="calculator">90 * 2</gadget>
<output>180</output>
<gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">180 + 140</gadget>
<output>320</output>
<gadget id="calculator">65 * 3</gadget>
<output>195</output>
<gadget id="calculator">320 - 195</gadget>
<output>125</output>
<result>D</result> | D | 125 | A student scored an average of 65 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics? | {
"A": "86",
"B": "165",
"C": "76",
"D": "125",
"E": "26"
} | subtract(add(multiply(90, const_2), multiply(70, const_2)), multiply(65, 3)) | multiply(n2,const_2)|multiply(n3,const_2)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2)| | "given m + p + c = 65 * 3 = 195 - - - ( 1 ) m + p = 90 * 2 = 180 - - - ( 2 ) p + c = 70 * 2 = 140 - - - ( 3 ) where m , p and c are marks obtained by the student in mathematics , physics and chemistry . p = ( 2 ) + ( 3 ) - ( 1 ) = 180 + 140 - 195 = 125 answer : d" | general |
math_qa__7xMGushe8PkegLpa | Find the number of trailing zeros in the product of (1^1)*(5^5)*(10^10)*(15^15) *(20^20)*(25^25)………. *(50^50). Select the correct option:
A) 150 B) 200 C) 250 D) 245 E) 225 | <gadget id="calculator">15 * 15</gadget>
<output>225</output>
<gadget id="calculator">225 + 25</gadget>
<output>250</output>
<result>C</result> | C | 250 | Find the number of trailing zeros in the product of (1^1)*(5^5)*(10^10)*(15^15) *(20^20)*(25^25)………. *(50^50). | {
"A": "150",
"B": "200",
"C": "250",
"D": "245",
"E": "225"
} | add(multiply(15, 15), 25) | multiply(n6,n6)|add(n10,#0) | looking at the numbers it looks like ( 1 x 5 ) ^ 5 ( 2 x 5 ) ^ 10 . . . ( 10 x 5 ) ^ 50 1 . determine the limiting factor . is it 2 or is it 5 ? we know that all the numbers are multiple of 5 but not of 2 . thus , the limiting factor in this case is 2 . let ' s drop all the 5 . then , we count factors of 2 of even multiples . 2 ^ 10 = 10 4 ^ 20 = 20 + 20 6 ^ 30 = 30 8 ^ 40 = 40 + 40 + 40 10 ^ 50 = 50 250 answer : c | general |
math_qa__dWTlhyHtahiij01E | The length of a bridge in meters, which a train 80-meters long and traveling at 45 km/hr can cross in 30 seconds is?
Choose the most appropriate option.
A) 215 B) 235 C) 255 D) 275 E) 295 | <gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 80</gadget>
<output>295</output>
<result>E</result> | E | 295 | The length of a bridge in meters, which a train 80-meters long and traveling at 45 km/hr can cross in 30 seconds is? | {
"A": "215",
"B": "235",
"C": "255",
"D": "275",
"E": "295"
} | subtract(multiply(divide(multiply(45, const_1000), const_3600), 30), 80) | multiply(n1,const_1000)|divide(#0,const_3600)|multiply(n2,#1)|subtract(#2,n0)| | "45 km / h = 45000 m / 3600 s = 12.5 m / s in 30 seconds , the train can go 30 ( 12.5 ) = 375 meters let x be the length of the bridge . x + 80 = 375 meters x = 295 meters the answer is e ." | physics |
math_qa__QrUOxLzSxVTokA8g | A, B, C, D and E are 5 consecutive points on a straight line. If BC = 2CD, DE = 4, AB = 5 and AC = 11, what is the length of AE? Choose the correct choice from the following answers:
A) 21 B) 26 C) 30 D) 18 E) 16 | <gadget id="calculator">11 - 5</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">11 + 3</gadget>
<output>14</output>
<gadget id="calculator">14 + 4</gadget>
<output>18</output>
<result>D</result> | D | 18 | A, B, C, D and E are 5 consecutive points on a straight line. If BC = 2CD, DE = 4, AB = 5 and AC = 11, what is the length of AE? | {
"A": "21",
"B": "26",
"C": "30",
"D": "18",
"E": "16"
} | add(add(11, divide(subtract(11, 5), 2)), 4) | subtract(n4,n0)|divide(#0,n1)|add(n4,#1)|add(n2,#2)| | "a - - - - - b - - - - c - - - - - - - - d - - - - e given : de = 4 - ( i ) ab = 5 - ( ii ) ac = 11 - ( iii ) bc = 2 cd - ( iv ) from ( ii ) and ( iii ) , bc = 6 from ( iv ) , cd = 3 length of ae = ac + cd + de = 11 + 3 + 4 = 18 correct option : d" | physics |
math_qa__IrVBc89OaHnAFD1N | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction T of the total distance did he cover while the sun was shining on him? Select
A) 1 / 4 B) 4 / 5 C) 1 / 5 D) 1 / 6 E) 1 / 7 | <gadget id="calculator">lcm(2, 3)</gadget>
<output>6</output>
<gadget id="calculator">6 / 2.8</gadget>
<output>2.142857</output>
<gadget id="calculator">2.142857 - 2</gadget>
<output>0.142857</output>
<result>E</result> | E | 0.142857 | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction T of the total distance did he cover while the sun was shining on him? | {
"A": "1 / 4",
"B": "4 / 5",
"C": "1 / 5",
"D": "1 / 6",
"E": "1 / 7"
} | subtract(divide(lcm(const_2, const_3), 2.8), const_2) | lcm(const_2,const_3)|divide(#0,n1)|subtract(#1,const_2)| | if s is an integer and we know that the average speed is 2.8 , s must be = 2 . that meanss + 1 = 3 . this implies that the ratio of time for s = 2 is 1 / 4 of the total time . the formula for distance / rate is d = rt . . . so the distance travelled when s = 2 is 2 t . the distance travelled for s + 1 = 3 is 3 * 4 t or 12 t . therefore , total distance covered while the sun was shining over him is t = 2 / 14 = 1 / 7 . answer : e | general |
math_qa__HPrs6QlMTzj5I6g0 | A train leaves Delhi at 9 a.m. at a speed of 35 kmph. Another train leaves at 2 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet? Choose the correct choice from the following: A) 229 B) 288 C) 600 D) 888 E) 1400 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">35 * 5</gadget>
<output>175</output>
<gadget id="calculator">40 - 35</gadget>
<output>5</output>
<gadget id="calculator">175 / 5</gadget>
<output>35</output>
<gadget id="calculator">35 * 40</gadget>
<output>1_400</output>
<result>E</result> | E | 1,400 | A train leaves Delhi at 9 a.m. at a speed of 35 kmph. Another train leaves at 2 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet? | {
"A": "229",
"B": "288",
"C": "600",
"D": "888",
"E": "1400"
} | multiply(divide(multiply(35, add(const_3, 2)), subtract(40, 35)), 40) | add(n2,const_3)|subtract(n3,n1)|multiply(n1,#0)|divide(#2,#1)|multiply(n3,#3)| | "d = 35 * 5 = 175 rs = 40 – 35 = 5 t = 175 / 5 = 35 d = 40 * 35 = 1400 km answer : e" | physics |
math_qa__VrEk928uq74BGLmj | Rohan spends 40% of his salary on food, 20% on house rent, 10% on entertainment and 10% on conveyance. If his savings at the end of a month are Rs. 2000. then his monthly salary is Choose the correct choice.
A) rs . 10000 B) rs . 6000 C) rs . 8000 D) rs . 4000 E) rs . 2000 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">2_000 * 5</gadget>
<output>10_000</output>
<result>A</result> | A | 10,000 | Rohan spends 40% of his salary on food, 20% on house rent, 10% on entertainment and 10% on conveyance. If his savings at the end of a month are Rs. 2000. then his monthly salary is | {
"A": "rs . 10000",
"B": "rs . 6000",
"C": "rs . 8000",
"D": "rs . 4000",
"E": "rs . 2000"
} | multiply(2000, add(const_4, const_1)) | add(const_1,const_4)|multiply(n4,#0) | sol . saving = [ 100 - ( 40 + 20 + 10 + 10 ] % = 20 % . let the monthly salary be rs . x . then , 20 % of x = 2000 â ‡ ” 20 / 100 x = 2000 â ‡ ” x = 2000 ã — 5 = 10000 . answer a | gain |
math_qa__zMy5bjhsKIpvx7wZ | Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 42 kmph. Of how many minutes does the train stop per hour? Choose the correct choice from the following answers.
A) 16 B) 4 C) 15 D) 18 E) 12 | <gadget id="calculator">42 / 45</gadget>
<output>14/15 = around 0.933333</output>
<gadget id="calculator">60 * (14/15)</gadget>
<output>56</output>
<gadget id="calculator">60 - 56</gadget>
<output>4</output>
<result>B</result> | B | 4 | Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 42 kmph. Of how many minutes does the train stop per hour? | {
"A": "16",
"B": "4",
"C": "15",
"D": "18",
"E": "12"
} | subtract(const_60, multiply(const_60, divide(42, 45))) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "t = 3 / 45 * 60 = 4 answer : b" | physics |
math_qa__i2Qnl8HIzcSBxFgR | A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $17000 left with him. find salary..
Choose one.
A) $ 10700 B) $ 17000 C) $ 180000 D) $ 1700 E) $ 170000 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/5) + (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/10) + (3/5)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 - (9/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">17_000 / (1/10)</gadget>
<output>170_000</output>
<result>E</result> | E | 170,000 | A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $17000 left with him. find salary.. | {
"A": "$ 10700",
"B": "$ 17000",
"C": "$ 180000",
"D": "$ 1700",
"E": "$ 170000"
} | divide(17000, subtract(1, add(add(divide(1, 5), divide(1, 10)), divide(3, 5)))) | divide(n0,n1)|divide(n0,n3)|divide(n4,n1)|add(#0,#1)|add(#3,#2)|subtract(n0,#4)|divide(n6,#5)| | "[ 1 / ( x 1 / y 1 + x 2 / y 2 + x 3 / y 3 ) ] * total amount = balance amount [ 1 - ( 1 / 5 + 1 / 10 + 3 / 5 ) } * total salary = $ 17000 , = [ 1 - 9 / 10 ] * total salary = $ 17000 , total salary = $ 17000 * 10 = $ 180000 , correct answer ( e )" | general |
math_qa__SvCJzM0ooRZlifV7 | Tara bought 19 cartons of ice cream and 4 cartons of yoghurt. Each carton of ice cream cost $7 and each carton of yoghurt cost $1. How much more did Tara spend on ice cream than on yoghurt?
Choose the correct choice from the following choices.
A) $ 144 B) $ 130 C) $ 80 D) $ 110 E) $ 129 | <gadget id="calculator">19 * 7</gadget>
<output>133</output>
<gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">133 - 4</gadget>
<output>129</output>
<result>E</result> | E | 129 | Tara bought 19 cartons of ice cream and 4 cartons of yoghurt. Each carton of ice cream cost $7 and each carton of yoghurt cost $1. How much more did Tara spend on ice cream than on yoghurt? | {
"A": "$ 144",
"B": "$ 130",
"C": "$ 80",
"D": "$ 110",
"E": "$ 129"
} | subtract(multiply(19, 7), multiply(4, 1)) | multiply(n0,n2)|multiply(n1,n3)|subtract(#0,#1) | step 1 : find the cost of the ice cream . 19 × $ 7 = $ 133 step 2 : find the cost of the yoghurt . 4 × $ 1 = $ 4 step 3 : find how much more the ice cream cost than the yoghurt . $ 133 – $ 4 = $ 129 tara spent $ 129 more on ice cream . answer is e . | general |
math_qa__x3kxr2ZmrUmbY12O | If 9 boys meet at a reunion and each boy shakes hands exactly once with each of the others, then what is the total number of handshakes Pick
A) 41 B) 42 C) 36 D) 44 E) 45 | <gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">factorial(7)</gadget>
<output>5_040</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">5_040 * 2</gadget>
<output>10_080</output>
<gadget id="calculator">362_880 / 10_080</gadget>
<output>36</output>
<result>C</result> | C | 36 | If 9 boys meet at a reunion and each boy shakes hands exactly once with each of the others, then what is the total number of handshakes | {
"A": "41",
"B": "42",
"C": "36",
"D": "44",
"E": "45"
} | divide(factorial(9), multiply(factorial(subtract(9, const_2)), factorial(const_2))) | factorial(n0)|factorial(const_2)|subtract(n0,const_2)|factorial(#2)|multiply(#3,#1)|divide(#0,#4)| | "n ( n - 1 ) / 2 = 9 * 8 / 2 = 36 answer : c" | general |
math_qa__IU7T67RhzMvOVExL | Car A runs at the speed of 50 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 65 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B? Choose one:
A) 3 : 7
B) 4 : 9
C) 20 : 13
D) 5 : 7
E) 6 : 11 | <gadget id="calculator">50 * 8</gadget>
<output>400</output>
<gadget id="calculator">65 * 4</gadget>
<output>260</output>
<gadget id="calculator">400 / 260</gadget>
<output>20/13 = around 1.538462</output>
<result>C</result> | C | 1.538462 | Car A runs at the speed of 50 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 65 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B? | {
"A": "3 : 7",
"B": "4 : 9",
"C": "20 : 13",
"D": "5 : 7",
"E": "6 : 11"
} | divide(multiply(50, 8), multiply(65, 4)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "car a travels 50 × 8 = 400 km car b travels 65 × 4 = 260 km the ratio is 400 : 260 = 40 : 26 = 20 : 13 the answer is c ." | physics |
math_qa__3knS7oxawB7VY0uo | A grocer is storing soap boxes in cartons that measure 25 inches by 48 inches by 60 inches. If the measurement of each soap box is 8 inches by 6 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton? Select:
A) 210 B) 252 C) 280 D) 320 E) 300 | <gadget id="calculator">25 * 48</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 * 60</gadget>
<output>72_000</output>
<gadget id="calculator">8 * 6</gadget>
<output>48</output>
<gadget id="calculator">48 * 5</gadget>
<output>240</output>
<gadget id="calculator">72_000 / 240</gadget>
<output>300</output>
<result>E</result> | E | 300 | A grocer is storing soap boxes in cartons that measure 25 inches by 48 inches by 60 inches. If the measurement of each soap box is 8 inches by 6 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton? | {
"A": "210",
"B": "252",
"C": "280",
"D": "320",
"E": "300"
} | divide(multiply(multiply(25, 48), 60), multiply(multiply(8, 6), 5)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|multiply(n5,#1)|divide(#2,#3)| | "however the process of dividing the volume of box by the volume of a soap seems flawed but it does work in this case due to the numbers dimensions of the box = 25 * 48 * 60 dimensions of the soap = 5 * 6 * 8 we get = 5 x 6 x 10 = 300 so the question is why this particular arrangement , in order to maximize number of soaps we need to minimize the space wasted and this is the only config where we dont waste any space so we can expect the maximum number the answer is ( e )" | general |
math_qa__1z9KVnFJYD4v0qGt | What is the greatest 5-digit number when divided by 6, 7 ,8 , 9, and 10 leaves a remainder of 4, 5, 6, 7, and 9 respectively? Pick one.
A) 56780 B) 78910 C) 97479 D) 97918 E) 97920 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">1_000_000 / 10</gadget>
<output>100_000</output>
<result>C</result> | C | 97,479 | What is the greatest 5-digit number when divided by 6, 7 ,8 , 9, and 10 leaves a remainder of 4, 5, 6, 7, and 9 respectively? | {
"A": "56780",
"B": "78910",
"C": "97479",
"D": "97918",
"E": "97920"
} | divide(multiply(const_1000, const_1000), const_10) | multiply(const_1000,const_1000)|divide(#0,const_10) | when you divide a positive integer by 10 , the remainder will just be the units digit . we know the remainder is 9 when we divide by 10 , so c is the only possible answer . | general |
math_qa__MBgfoByknmsp39qI | A rower can row 6 km/h in still water. When the river is running at 2 km/h, it takes the rower 1 hour to row to Big Rock and back. How many kilometers is it to Big Rock? Options: A) 2.21 B) 2.45 C) 2.67 D) 2.83 E) 2.95 | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">4 / 12</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 8</gadget>
<output>8/3 = around 2.666667</output>
<result>C</result> | C | 2.67 | A rower can row 6 km/h in still water. When the river is running at 2 km/h, it takes the rower 1 hour to row to Big Rock and back. How many kilometers is it to Big Rock? | {
"A": "2.21",
"B": "2.45",
"C": "2.67",
"D": "2.83",
"E": "2.95"
} | multiply(divide(subtract(6, 2), add(add(6, 2), subtract(6, 2))), add(6, 2)) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|divide(#1,#2)|multiply(#0,#3)| | "let x be the distance to big rock . time = x / 4 + x / 8 = 1 x = 32 / 12 = 2.67 km the answer is c ." | physics |
math_qa__MIK7jdMRjP0EHKkV | 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.75 only. Men’s wages are? Choose one.
A) 6 rs B) 7 rs C) 8 rs D) 5 rs E) 1 rs | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">75 / 15</gadget>
<output>5</output>
<result>D</result> | D | 5 | 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.75 only. Men’s wages are? | {
"A": "6 rs",
"B": "7 rs",
"C": "8 rs",
"D": "5 rs",
"E": "1 rs"
} | divide(75, multiply(const_3, 5)) | multiply(n0,const_3)|divide(n2,#0)| | "5 m = xw = 8 b 5 m + xw + 8 b - - - - - 75 rs . 5 m + 5 m + 5 m - - - - - 75 rs . 15 m - - - - - - 75 rs . = > 1 m = 5 rs . answer : d" | general |
math_qa__qyIppheARIph14Ta | The radius of a cylindrical vessel is 7cm and height is 6cm. Find the whole surface of the cylinder? Pick one
A) 281 B) 771 C) 440 D) 767 E) 572 | <gadget id="calculator">2 * pi * 7 * (7 + 6)</gadget>
<output>182*pi = around 571.769863</output>
<result>E</result> | E | 572 | The radius of a cylindrical vessel is 7cm and height is 6cm. Find the whole surface of the cylinder? | {
"A": "281",
"B": "771",
"C": "440",
"D": "767",
"E": "572"
} | surface_cylinder(7, 6) | surface_cylinder(n0,n1)| | "r = 7 h = 6 2 π r ( h + r ) = 2 * 22 / 7 * 7 ( 13 ) = 572 answer : e" | geometry |
math_qa__iBcgfWOYkbDeUPRW | Elvin's monthly telephone bill is the sum of the charge for the calls he made during the month and a fixed monthly charge for Internet service. Elvin's total telephone bill for January was $40 and Elvin's total telephone bill for February was 76$. If Elvin's charge for the calls he made in February was twice the charge for the calls he made in January, what is Elvin's fixed monthly charge for Internet service?
Choose the correct choice from the following choices: A) $ 5 B) $ 10 C) $ 14 D) $ 4 E) $ 28 | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">80 - 76</gadget>
<output>4</output>
<result>D</result> | D | 4 | Elvin's monthly telephone bill is the sum of the charge for the calls he made during the month and a fixed monthly charge for Internet service. Elvin's total telephone bill for January was $40 and Elvin's total telephone bill for February was 76$. If Elvin's charge for the calls he made in February was twice the charge for the calls he made in January, what is Elvin's fixed monthly charge for Internet service? | {
"A": "$ 5",
"B": "$ 10",
"C": "$ 14",
"D": "$ 4",
"E": "$ 28"
} | subtract(multiply(40, const_2), 76) | multiply(n0,const_2)|subtract(#0,n1) | bill = fixed charge + charge of calls made in jan , bill = fixed charge ( let , y ) + charge of calls made in jan ( let , x ) = $ 40 in feb , bill = fixed charge ( let , y ) + charge of calls made in feb ( then , 2 x ) = $ 76 i . e . x + y = 40 and 2 x + y = 76 take the difference if two equations i . e . ( 2 x + y ) - ( x + y ) = 76 - 40 i . e . x = 36 i . e . fixed monthly charge , y = 4 answer : option d | general |
math_qa__IHulWjxWPxAWInjd | How many seconds does Puja take to cover a distance of 500 m, if she runs at a speed of 30 km/hr?
Choose the correct choice from the following answers
A) 60 sec B) 82 sec C) 95 sec D) 100 sec E) 120 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">30 * (5/18)</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">500 / (25/3)</gadget>
<output>60</output>
<result>A</result> | A | 60 | How many seconds does Puja take to cover a distance of 500 m, if she runs at a speed of 30 km/hr? | {
"A": "60 sec",
"B": "82 sec",
"C": "95 sec",
"D": "100 sec",
"E": "120 sec"
} | divide(500, multiply(30, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0) | hint : time = distance / speed we see that the distance is given in metres while the speed is given in km / hr and the answer is asked in seconds . so , convert km / hr into m / s by multiplying 5 / 18 m / s to the given value of speed . 30 km / hr = 30 x 5 / 18 = 75 / 9 m / sec i . e . place these values in the formula : time = 500 x 9 / 75 = 60 sec answer is a | physics |
math_qa__TceuThV2rhtfOgQN | The sum of the ages 4 members of a family 5years ago was 94.Today,when the daughter has been married off and replaced by a daughter-in-law,the sum of their ages is 100.Assuming that there has been no other change in the family structure and all members are alive,what is the difference in the ages of daughter and daughter-in-law ? Pick
A) 22 B) 11 C) 25 D) 14 E) 16 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 + 94</gadget>
<output>114</output>
<gadget id="calculator">114 - 100</gadget>
<output>14</output>
<result>D</result> | D | 14 | The sum of the ages 4 members of a family 5years ago was 94.Today,when the daughter has been married off and replaced by a daughter-in-law,the sum of their ages is 100.Assuming that there has been no other change in the family structure and all members are alive,what is the difference in the ages of daughter and daughter-in-law ? | {
"A": "22",
"B": "11",
"C": "25",
"D": "14",
"E": "16"
} | subtract(add(multiply(5, 4), 94), 100) | multiply(n0,n1)|add(n2,#0)|subtract(#1,n3) | solution : sum of ages of 4 members 5 years ago = 94 = > sum of present ages of 4 members = 94 + 4 * 5 = 114 difference in the sum of the ages = difference in the ages of daughter and daughter - in - law difference in the sum of the ages = 114 - 100 = 14 = > difference in the ages of daughter and daughter - in - law = 14 answer d | general |
math_qa__hSkzXKm1z4SJIZUr | 35 binders can bind 1400 books in 21 days. How many binders will be required to bind 1600 books in 20 days?
Choose the correct option:
A) 87 B) 18 C) 42 D) 16 E) 10 | <gadget id="calculator">1_600 / 20</gadget>
<output>80</output>
<gadget id="calculator">35 * 21</gadget>
<output>735</output>
<gadget id="calculator">1_400 / 735</gadget>
<output>40/21 = around 1.904762</output>
<gadget id="calculator">80 / (40/21)</gadget>
<output>42</output>
<result>C</result> | C | 42 | 35 binders can bind 1400 books in 21 days. How many binders will be required to bind 1600 books in 20 days? | {
"A": "87",
"B": "18",
"C": "42",
"D": "16",
"E": "10"
} | divide(divide(1600, 20), divide(1400, multiply(35, 21))) | divide(n3,n4)|multiply(n0,n2)|divide(n1,#1)|divide(#0,#2)| | "binders books days 35 1400 21 x 1600 20 x / 35 = ( 1600 / 1400 ) * ( 21 / 20 ) = > x = 42 answer : c" | physics |
math_qa__O4nBRZRY8AO44TuW | 40 × ? + (12 + 8) × 3/5 = 1212
Select.
A) 7 B) 5 C) 4 D) 18 E) 30 | <gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">20 * (3/5)</gadget>
<output>12</output>
<gadget id="calculator">1_212 - 12</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 40</gadget>
<output>30</output>
<result>E</result> | E | 30 | 40 × ? + (12 + 8) × 3/5 = 1212 | {
"A": "7",
"B": "5",
"C": "4",
"D": "18",
"E": "30"
} | divide(subtract(1212, multiply(add(12, 8), divide(3, 5))), 40) | add(n1,n2)|divide(n3,n4)|multiply(#0,#1)|subtract(n5,#2)|divide(#3,n0)| | "explanation : = > 40 × ? + ( 12 + 8 ) × 3 / 5 = 1212 = > 40 × ? = 1212 - ( 12 + 8 ) × 3 / 5 = > 40 × ? = 1212 - 20 × 3 / 5 = > 40 × ? = 1212 - 20 × 3 / 5 = 1200 = > ? = 1200 / 40 = 30 answer : option e" | general |
math_qa__2vfAijVzFdjNY6Ke | In how many ways 4 boys and 5 girls can be seated in a row so that they are alternate.
Choose the correct choice from the following.
A) 144 B) 288 C) 12 D) 256 E) 2880 | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">24 * 120</gadget>
<output>2_880</output>
<result>E</result> | E | 2,880 | In how many ways 4 boys and 5 girls can be seated in a row so that they are alternate. | {
"A": "144",
"B": "288",
"C": "12",
"D": "256",
"E": "2880"
} | multiply(factorial(4), factorial(5)) | factorial(n0)|factorial(n1)|multiply(#0,#1)| | "solution : let the arrangement be , g b g b g b g b g 4 boys can be seated in 4 ! ways . girl can be seated in 3 ! ways . required number of ways , = 4 ! * 5 ! = 2880 . answer : option e" | probability |
math_qa__moJLKkiy0A95Q5t3 | f(x) is a function such that f(x) + 3f(8 - x) = x for all real numbers x. Find the value of f(2)
Choose the correct choice from the following options:
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">2 - 18</gadget>
<output>-16</output>
<gadget id="calculator">1 - 9</gadget>
<output>-8</output>
<gadget id="calculator">(-16) / (-8)</gadget>
<output>2</output>
<result>C</result> | C | 2 | f(x) is a function such that f(x) + 3f(8 - x) = x for all real numbers x. Find the value of f(2) | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | divide(subtract(2, multiply(multiply(3, 3), 2)), subtract(const_1, multiply(3, 3))) | multiply(n0,n0)|multiply(#0,n2)|subtract(const_1,#0)|subtract(n2,#1)|divide(#3,#2)| | "f ( x ) + 3 f ( 8 - x ) = f ( 2 ) + 3 f ( 6 ) = 2 : x = 2 above f ( 6 ) + 3 f ( 2 ) = 6 : x = 6 above f ( 6 ) = 6 - 3 f ( 2 ) : solve equation c for f ( 6 ) f ( 2 ) + 3 ( 6 - 3 f ( 2 ) ) = 2 : substitute f ( 2 ) = 2 : solve above equation correct answer c" | general |
math_qa__KWqUHNB2xW8zO2cG | Two cubes of their volumes in the ratio 64 : 1331. The ratio of their surface area is: Answers:
A) 1.5 : 5
B) 2 : 5
C) 3 : 5
D) 4 : 11
E) 4 : 5 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>
<gadget id="calculator">1_331 ** (1/3)</gadget>
<output>11</output>
<gadget id="calculator">4 / 11</gadget>
<output>4/11 = around 0.363636</output>
<result>D</result> | D | 0.363636 | Two cubes of their volumes in the ratio 64 : 1331. The ratio of their surface area is: | {
"A": "1.5 : 5",
"B": "2 : 5",
"C": "3 : 5",
"D": "4 : 11",
"E": "4 : 5"
} | divide(power(64, const_0_33), power(1331, const_0_33)) | power(n0,const_0_33)|power(n1,const_0_33)|divide(#0,#1)| | "the ratio of their surface area is 64 : 1331 4 : 11 answer is d ." | geometry |
math_qa__QDjlTeCrH0YFEkP0 | At Joel’s bookstore, the current inventory is 30% historical fiction. Of the historical fiction books, 30% are new releases, while 40% of the other books are new releases. What fraction of all new releases are the historical fiction new releases? Pick one
A) 4 / 25 B) 9 / 37 C) 2 / 5 D) 8 / 15 E) 2 / 3 | <gadget id="calculator">30 * 30</gadget>
<output>900</output>
<gadget id="calculator">900 / 100</gadget>
<output>9</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">40 * 70</gadget>
<output>2_800</output>
<gadget id="calculator">2_800 / 100</gadget>
<output>28</output>
<gadget id="calculator">9 + 28</gadget>
<output>37</output>
<gadget id="calculator">9 / 37</gadget>
<output>9/37 = around 0.243243</output>
<result>B</result> | B | 0.243243 | At Joel’s bookstore, the current inventory is 30% historical fiction. Of the historical fiction books, 30% are new releases, while 40% of the other books are new releases. What fraction of all new releases are the historical fiction new releases? | {
"A": "4 / 25",
"B": "9 / 37",
"C": "2 / 5",
"D": "8 / 15",
"E": "2 / 3"
} | divide(divide(multiply(30, 30), const_100), add(divide(multiply(30, 30), const_100), divide(multiply(40, subtract(const_100, 30)), const_100))) | multiply(n0,n1)|subtract(const_100,n0)|divide(#0,const_100)|multiply(n2,#1)|divide(#3,const_100)|add(#2,#4)|divide(#2,#5)| | "let there be 100 books in all historic fiction books = 30 % of total = 30 other books = 70 new historic fiction = 30 % of 30 = 9 other new books = 40 % of 70 = 28 total new books = 37 fraction = 9 / 37 ans : b" | gain |
math_qa__4C1ONup8gPOaI3rN | A teacher grades students’ tests by subtracting twice the number of incorrect responses from the number of correct responses. If Student B answers each of the 100 questions on her test and receives a score of 73, how many questions did Student B answer correctly? Select the correct option
A) 55 B) 60 C) 73 D) 82 E) 91 | <gadget id="calculator">100 - 73</gadget>
<output>27</output>
<gadget id="calculator">27 / 3</gadget>
<output>9</output>
<gadget id="calculator">100 - 9</gadget>
<output>91</output>
<result>E</result> | E | 91 | A teacher grades students’ tests by subtracting twice the number of incorrect responses from the number of correct responses. If Student B answers each of the 100 questions on her test and receives a score of 73, how many questions did Student B answer correctly? | {
"A": "55",
"B": "60",
"C": "73",
"D": "82",
"E": "91"
} | subtract(100, divide(subtract(100, 73), const_3)) | subtract(n0,n1)|divide(#0,const_3)|subtract(n0,#1)| | "a score of 73 brings to mind that it is an odd number even though you are subtracting an even number ( twice the incorrect responses ) out of the correct responses score . so the correct responses score must be an odd number too ( odd - even = odd ) . since the overall score is 73 , the number of correct responses must be more than 73 since the student answered all questions . only 91 satisfies both these conditions . answer ( e )" | general |
math_qa__1Yfc12wbodghCazI | A box measuring 30 inches long by 48 inches wide by 12 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective? Select.
A) 78 B) 80 C) 85 D) 88 E) 90 | <gadget id="calculator">30 * 48</gadget>
<output>1_440</output>
<gadget id="calculator">1_440 * 12</gadget>
<output>17_280</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">6 ** 3</gadget>
<output>216</output>
<gadget id="calculator">17_280 / 216</gadget>
<output>80</output>
<result>B</result> | B | 80 | A box measuring 30 inches long by 48 inches wide by 12 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective? | {
"A": "78",
"B": "80",
"C": "85",
"D": "88",
"E": "90"
} | divide(multiply(multiply(30, 48), 12), volume_cube(divide(12, const_2))) | divide(n2,const_2)|multiply(n0,n1)|multiply(n2,#1)|volume_cube(#0)|divide(#2,#3)| | "least number of cubes will be required when the cubes that could fit in are biggest . 6 is the biggest number that could divide all three , 30 , 48 and 12 . thus side of cube must be 6 , and total number of cubes = 30 / 6 * 48 / 6 * 12 / 6 = 80 ans b ." | geometry |
math_qa__nm8V9fn3PTQpUN0o | A man can row downstream at the rate of 24 Kmph and upstream at 7 Kmph. Find the man’s rate in still water and rate of current? Choose one: A) 8.5 B) 8.0 C) 9.5 D) 9.0 E) 8.25 | <gadget id="calculator">24 - 7</gadget>
<output>17</output>
<gadget id="calculator">17 / 2</gadget>
<output>17/2 = around 8.5</output>
<result>A</result> | A | 8.5 | A man can row downstream at the rate of 24 Kmph and upstream at 7 Kmph. Find the man’s rate in still water and rate of current? | {
"A": "8.5",
"B": "8.0",
"C": "9.5",
"D": "9.0",
"E": "8.25"
} | divide(subtract(24, 7), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "rate of still water = 1 / 2 ( down stream + upstream ) = 1 / 2 ( 24 + 7 ) = 15.5 kmph rate of current = 1 / 2 ( down stream - upstream ) = 1 / 2 ( 24 - 7 ) = 1 / 2 ( 17 ) = 8.5 kmph answer is a ." | gain |
math_qa__HzSPeL64mgcA3URq | The average weight of 5 persons increases by 1.5 kg. If a person weighing 65 kg is replaced by a new person, what could be the weight of the new person?
Pick
A) 76 kg B) 77 kg C) 72.5 kg D) data inadequate E) none of these | <gadget id="calculator">5 * 1.5</gadget>
<output>7.5</output>
<gadget id="calculator">65 + 7.5</gadget>
<output>72.5</output>
<result>C</result> | C | 72.5 | The average weight of 5 persons increases by 1.5 kg. If a person weighing 65 kg is replaced by a new person, what could be the weight of the new person? | {
"A": "76 kg",
"B": "77 kg",
"C": "72.5 kg",
"D": "data inadequate",
"E": "none of these"
} | add(65, multiply(5, 1.5)) | multiply(n0,n1)|add(n2,#0)| | "total weight increases = 5 × 1.5 = 7.5 kg so the weight of new person = 65 + 7.5 = 72.5 kg answer c" | general |
math_qa__dxIUHzKFSXZrT7yd | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 4 hours and 16 hours respectively. The ratio of their speeds is? Choose the correct answer
A) 4 : 5 B) 4 : 2 C) 4 : 4 D) 4 : 8 E) 4 : 1 | <gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">4 ** (1/2)</gadget>
<output>2</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>B</result> | B | 2 | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 4 hours and 16 hours respectively. The ratio of their speeds is? | {
"A": "4 : 5",
"B": "4 : 2",
"C": "4 : 4",
"D": "4 : 8",
"E": "4 : 1"
} | divide(sqrt(16), sqrt(4)) | sqrt(n1)|sqrt(n0)|divide(#0,#1)| | "let us name the trains a and b . then , ( a ' s speed ) : ( b ' s speed ) = √ b : √ a = √ 16 : √ 4 = 4 : 2 answer : b" | physics |
math_qa__MHBQMdU5VoEMTva2 | On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent E of thatbeforeJuly 1 last year? Choose the correct choice from the following options: A) 90 % B) 99 % C) 100 % D) 101 % E) 110 % | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<result>B</result> | B | 99 | On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent E of thatbeforeJuly 1 last year? | {
"A": "90 %",
"B": "99 %",
"C": "100 %",
"D": "101 %",
"E": "110 %"
} | multiply(10, 10) | multiply(n1,n1)| | "the total number of employees = n the average salary = x total salary to all emplyoees = xn after the total number of employees = n - 0.1 n = 0.9 n the average salary = x + 10 % of x = 1.1 x total salary to all emplyoees = 0.9 n ( 1.1 x ) total salary after as a % of total salary before e = [ 0.9 n ( 1.1 x ) ] / xn = 0.99 or 99 % = b" | general |
math_qa__Gte23pn2OUDTsA1n | A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in : Choose the correct choice from the following choices:
A) 4 days B) 6 days C) 8 days D) 18 days E) 28 days | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 * (1/12)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/12) + (1/6)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<result>A</result> | A | 4 | A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in : | {
"A": "4 days",
"B": "6 days",
"C": "8 days",
"D": "18 days",
"E": "28 days"
} | inverse(add(divide(const_1, 12), multiply(const_2, divide(const_1, 12)))) | divide(const_1,n0)|multiply(#0,const_2)|add(#0,#1)|inverse(#2)| | "explanation : ratio of rates of working of a and b = 2 : 1 . so , ratio of times taken = 1 : 2 . b ' s 1 day ' s work = 1 / 12 a ' s 1 day ' s work = 1 / 6 ; ( 2 times of b ' s work ) ( a + b ) ' s 1 day ' s work = ( 1 / 6 + 1 / 12 ) = 3 / 12 = 1 / 4 so , a and b together can finish the work in 4 days . answer is a" | physics |
math_qa__UaGLJiinZP6BF6qe | If a student loses 5 kilograms, he will weigh twice as much as his sister. Together they now weigh 104 kilograms. What is the student's present weight in kilograms?
Options: A) 70 B) 71 C) 72 D) 73 E) 74 | <gadget id="calculator">104 - 5</gadget>
<output>99</output>
<gadget id="calculator">99 / 3</gadget>
<output>33</output>
<gadget id="calculator">104 - 33</gadget>
<output>71</output>
<result>B</result> | B | 71 | If a student loses 5 kilograms, he will weigh twice as much as his sister. Together they now weigh 104 kilograms. What is the student's present weight in kilograms? | {
"A": "70",
"B": "71",
"C": "72",
"D": "73",
"E": "74"
} | subtract(104, divide(subtract(104, 5), const_3)) | subtract(n1,n0)|divide(#0,const_3)|subtract(n1,#1)| | "let x be the weight of the sister . then the student ' s weight is 2 x + 5 . x + ( 2 x + 5 ) = 104 3 x = 99 x = 33 kg then the student ' s weight is 71 kg . the answer is b ." | other |
math_qa__DHCiJV4TXTJx8vOz | A football team lost 5 yards and then gained 13. What is the team's progress? Options
A) 2 B) 4 C) 5 D) 6 E) 8 | <gadget id="calculator">13 - 5</gadget>
<output>8</output>
<result>E</result> | E | 8 | A football team lost 5 yards and then gained 13. What is the team's progress? | {
"A": "2",
"B": "4",
"C": "5",
"D": "6",
"E": "8"
} | subtract(13, 5) | subtract(n1,n0)| | "for lost , use negative . for gain , use positive . progress = - 5 + 13 = 8 yards e" | gain |
math_qa__UFpdLqap1W7G6Xwy | find the last digit of 322^369 Pick one
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">322 % 10</gadget>
<output>2</output>
<gadget id="calculator">369 % 10</gadget>
<output>9</output>
<gadget id="calculator">2 ** 9</gadget>
<output>512</output>
<gadget id="calculator">512 % 10</gadget>
<output>2</output>
<result>B</result> | B | 2 | find the last digit of 322^369 | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | reminder(power(reminder(322, const_10), reminder(369, const_10)), const_10) | reminder(n0,const_10)|reminder(n1,const_10)|power(#0,#1)|reminder(#2,const_10) | for calculating the unit place of these type of question ( exponent ) as the power of 2 repeats after 4 , so we will divide the exponent by 4 e . g , 2 ^ 1 = 2 and 2 ^ ( 4 + 1 ) = 32 , both have same unit place 369 / 4 gives the remainder as 1 so we can write 322 ^ 369 = 2 ^ 1 = 2 so , the unit place will be 2 answer : b | general |
math_qa__HfqKz4NDeBpQNYBs | If x is equal to the sum of the even integers from 40 to 60 inclusive, and y is the number of even integers from 40 to 60 inclusive, what is the value of x+y? Choose the correct choice from the following: A) 550 B) 551 C) 560 D) 561 E) 572 | <gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">2 * 40</gadget>
<output>80</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">80 + 20</gadget>
<output>100</output>
<gadget id="calculator">11 * 100</gadget>
<output>1_100</output>
<gadget id="calculator">1_100 / 2</gadget>
<output>550</output>
<gadget id="calculator">550 + 11</gadget>
<output>561</output>
<result>D</result> | D | 561 | If x is equal to the sum of the even integers from 40 to 60 inclusive, and y is the number of even integers from 40 to 60 inclusive, what is the value of x+y? | {
"A": "550",
"B": "551",
"C": "560",
"D": "561",
"E": "572"
} | add(divide(multiply(add(divide(subtract(60, 40), const_2), const_1), add(multiply(const_2, 40), multiply(divide(subtract(60, 40), const_2), const_2))), const_2), add(divide(subtract(60, 40), const_2), const_1)) | multiply(n0,const_2)|subtract(n1,n0)|divide(#1,const_2)|add(#2,const_1)|multiply(#2,const_2)|add(#0,#4)|multiply(#3,#5)|divide(#6,const_2)|add(#3,#7) | this is a perfect example of why you should not use formulas without understanding them properly . if you understand them , you will not make a mistake and will save time . the formula quoted by the original poster : n ( n + 1 ) is absolutely fine . but one needs to understand that n is the number of even terms starting from the first even term . ( i discuss why this is so here : sum of even numbers from 40 to 60 using this formula will be : 30 * 31 - 19 * 20 = 10 ( 3 * 31 - 19 * 2 ) = 550 since number of terms is 11 , required sum is 561 but , i would not use this formula for this question and would do it the way many of you have done : average = 50 ( it is the middle number ) , number of terms = 11 ( no formula again . any 10 consecutive integers have 5 even and 5 odd numbers . 41 to 60 will have 10 even integers and 40 is the 11 th one ) sum = 50 * 11 + 11 = 561 answer is d | general |
math_qa__NWZBmjK4EPQvTWNC | A monkey start climbing up a tree 17 ft tall.Each hour it hops 3 ft and slips back 2 ft. How much time would it take the monkey to reach the top. Choose the correct choice from the following choices.
A) 15 hrs
B) 18 hrs
C) 19 hrs
D) 17 hrs
E) 16 hrs | <gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">17 / 1</gadget>
<output>17</output>
<gadget id="calculator">17 - 2</gadget>
<output>15</output>
<result>A</result> | A | 15 | A monkey start climbing up a tree 17 ft tall.Each hour it hops 3 ft and slips back 2 ft. How much time would it take the monkey to reach the top. | {
"A": "15 hrs",
"B": "18 hrs",
"C": "19 hrs",
"D": "17 hrs",
"E": "16 hrs"
} | subtract(divide(17, subtract(3, 2)), 2) | subtract(n1,n2)|divide(n0,#0)|subtract(#1,n2)| | "if monkey hops 3 ft and slips back 2 ft in a hour , it means the monkey hops ( 3 ft - 2 ft ) = 1 ft / hr . similarly in 14 hrs it wil be 14 ft . bt since the height of the tree is 17 ft , so if the monkey hops up the tree in the next hr i . e 15 th hr then it reaches at the top of the tree . hence it takes 15 hrs for monkey to reach at the top answer : a" | physics |
math_qa__kPP228hPgc9ndjc2 | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 79 more candidates got selected than A. What was the number of candidates appeared from each State? Options: A) 7000 B) 7900 C) 6000 D) 5000 E) 4000 | <gadget id="calculator">7 - 6</gadget>
<output>1</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">79 / (1/100)</gadget>
<output>7_900</output>
<result>B</result> | B | 7,900 | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 79 more candidates got selected than A. What was the number of candidates appeared from each State? | {
"A": "7000",
"B": "7900",
"C": "6000",
"D": "5000",
"E": "4000"
} | divide(79, divide(subtract(7, 6), const_100)) | subtract(n1,n0)|divide(#0,const_100)|divide(n2,#1)| | "state a and state b had an equal number of candidates appeared . in state a , 6 % candidates got selected from the total appeared candidates in state b , 7 % candidates got selected from the total appeared candidates but in state b , 79 more candidates got selected than state a from these , it is clear that 1 % of the total appeared candidates in state b = 79 = > total appeared candidates in state b = 79 x 100 = 7900 = > total appeared candidates in state a = total appeared candidates in state b = 7900" | general |
math_qa__6IKNOpeGYUe8zqqg | The price ratio of oranges to lemons is 2:3. The price ratio of grapefruits to lemons is 3:5. What is the ratio, by price, of grapefruit to oranges? Select:
A) 18 : 20
B) 10 : 9
C) 2 : 5
D) 5 : 2
E) 3 : 2 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 3</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 3</gadget>
<output>2</output>
<gadget id="calculator">(9/5) / 2</gadget>
<output>9/10 = around 0.9</output>
<result>A</result> | A | 0.9 | The price ratio of oranges to lemons is 2:3. The price ratio of grapefruits to lemons is 3:5. What is the ratio, by price, of grapefruit to oranges? | {
"A": "18 : 20",
"B": "10 : 9",
"C": "2 : 5",
"D": "5 : 2",
"E": "3 : 2"
} | divide(multiply(divide(3, 5), 3), multiply(divide(const_2, const_3), const_3)) | divide(n1,n3)|divide(const_2,const_3)|multiply(n1,#0)|multiply(#1,const_3)|divide(#2,#3) | let price of lemons be 30 ( since that is common ) so , price of oranges = 20 & price of lemons is = 30 further price of grapefruit will be 6 * 3 = 18 thus price , of grapefruit to oranges = 18 : 20 answer : a | other |
math_qa__6HX8Cuviz3r0nDMx | 20 carrots on a scale weigh 3.64 kg. When 4 carrots are removed from the scale, the average weight of the 16 carrots is 180 grams. What is the average weight (in grams) of the 4 carrots which were removed? Choose the correct answer.
A) 160 B) 170 C) 180 D) 190 E) 200 | <gadget id="calculator">16 * 180</gadget>
<output>2_880</output>
<gadget id="calculator">2_880 / 1_000</gadget>
<output>72/25 = around 2.88</output>
<gadget id="calculator">3.64 - (72/25)</gadget>
<output>0.76</output>
<gadget id="calculator">0.76 / 4</gadget>
<output>0.19</output>
<gadget id="calculator">0.19 * 1_000</gadget>
<output>190</output>
<result>D</result> | D | 190 | 20 carrots on a scale weigh 3.64 kg. When 4 carrots are removed from the scale, the average weight of the 16 carrots is 180 grams. What is the average weight (in grams) of the 4 carrots which were removed? | {
"A": "160",
"B": "170",
"C": "180",
"D": "190",
"E": "200"
} | multiply(divide(subtract(3.64, divide(multiply(16, 180), const_1000)), 4), const_1000) | multiply(n3,n4)|divide(#0,const_1000)|subtract(n1,#1)|divide(#2,n2)|multiply(#3,const_1000)| | "16 * 180 = 2880 . the other 4 carrots weigh a total of 760 grams . the average weight is 760 / 4 = 190 grams . the answer is d ." | general |
math_qa__wTXXVGPRFD9sDees | A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3200. They completed the work in 3 days with the help of C. How much is to be paid to C? Choose the correct choice:
A) rs . 380 B) rs . 600 C) rs . 420 D) rs . 400 E) rs . 480 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/6) + (1/8)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">(1/3) - (7/24)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">3 * (1/24)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 3_200</gadget>
<output>400</output>
<result>D</result> | D | 400 | A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3200. They completed the work in 3 days with the help of C. How much is to be paid to C? | {
"A": "rs . 380",
"B": "rs . 600",
"C": "rs . 420",
"D": "rs . 400",
"E": "rs . 480"
} | multiply(multiply(3, subtract(divide(const_1, 3), add(divide(const_1, 6), divide(const_1, 8)))), 3200) | divide(const_1,n3)|divide(const_1,n0)|divide(const_1,n1)|add(#1,#2)|subtract(#0,#3)|multiply(n3,#4)|multiply(n2,#5)| | "explanation : amount of work a can do in 1 day = 1 / 6 amount of work b can do in 1 day = 1 / 8 amount of work a + b can do in 1 day = 1 / 6 + 1 / 8 = 7 / 24 amount of work a + b + c can do = 1 / 3 amount of work c can do in 1 day = 1 / 3 - 7 / 24 = 1 / 24 work a can do in 1 day : work b can do in 1 day : work c can do in 1 day = 1 / 6 : 1 / 8 : 1 / 24 = 4 : 3 : 1 amount to be paid to c = 3200 × ( 1 / 8 ) = 400 answer : option d" | physics |
math_qa__zgmmaC3VZefsSi3w | How many multiples of 7 are there between 700 and 1000, inclusive?
Pick one
A) 43 B) 42 C) 22 D) 21 E) 20 | <gadget id="calculator">1_000 - 700</gadget>
<output>300</output>
<gadget id="calculator">300 / 7</gadget>
<output>300/7 = around 42.857143</output>
<gadget id="calculator">(300/7) + 1</gadget>
<output>307/7 = around 43.857143</output>
<result>A</result> | A | 43 | How many multiples of 7 are there between 700 and 1000, inclusive? | {
"A": "43",
"B": "42",
"C": "22",
"D": "21",
"E": "20"
} | add(divide(subtract(1000, 700), 7), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "there are exactly 301 numbers between 700 to 1000 . . 701 to 800 = 100 801 to 1000 = 200 . . . total 300 numbers , count 700 too . . 301 / 7 = 43 . . . ans option a ." | general |
math_qa__jWvEYPsCXwiLe8DR | an unbaised coin is tossed until it shows up the same face in 2 consicative throws wat is the probability that the no of tosses is not more than 4. Choose one.
A) 3 / 4 B) 1 / 4 C) 7 / 8 D) 1 / 8 E) 6 / 8 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 - (1/8)</gadget>
<output>7/8 = around 0.875</output>
<result>C</result> | C | 0.875 | an unbaised coin is tossed until it shows up the same face in 2 consicative throws wat is the probability that the no of tosses is not more than 4. | {
"A": "3 / 4",
"B": "1 / 4",
"C": "7 / 8",
"D": "1 / 8",
"E": "6 / 8"
} | negate_prob(divide(const_1, multiply(4, 2))) | multiply(n0,n1)|divide(const_1,#0)|negate_prob(#1) | using 0 and 1 for head and tail respectively and considering binary system , we find that out of 16 possibilities , 14 are desired options . then probability = 14 / 16 = 7 / 8 answer : c | probability |
math_qa__L56L4DRKs5VDPxgL | At a certain bowling alley, it costs $0.50 to rent bowling shoes for the day and $2 to bowl 1 game. If a person has $12.80 and must rent shoes, what is the greatest number of complete games that person can bowl in one day? Choose the correct answer
A) 7 B) 8 C) 6 D) 10 E) 11 | <gadget id="calculator">12.8 - 0.5</gadget>
<output>12.3</output>
<gadget id="calculator">12.3 / 2</gadget>
<output>6.15</output>
<result>C</result> | C | 6 | At a certain bowling alley, it costs $0.50 to rent bowling shoes for the day and $2 to bowl 1 game. If a person has $12.80 and must rent shoes, what is the greatest number of complete games that person can bowl in one day? | {
"A": "7",
"B": "8",
"C": "6",
"D": "10",
"E": "11"
} | divide(subtract(12.8, 0.5), 2) | subtract(n3,n0)|divide(#0,n1) | after renting bowling shoes the person is left with $ 12.80 - $ 0.5 = $ 12.30 , which is enough for 12.3 / 2 < 7 = ~ 6 . answer : c . | physics |
math_qa__yGnG11zfzIbd6tke | If a*b*c=130, b*c*d = 65, c*d*e=750 and d*e*f=250 the (a*f)/(c*d) = ? Choose the most appropriate option
A) 1 / 2
B) 2 / 3
C) 3 / 4
D) 4 / 3
E) none of these | <gadget id="calculator">130 * 250</gadget>
<output>32_500</output>
<gadget id="calculator">750 * 65</gadget>
<output>48_750</output>
<gadget id="calculator">32_500 / 48_750</gadget>
<output>2/3 = around 0.666667</output>
<result>B</result> | B | 0.666667 | If a*b*c=130, b*c*d = 65, c*d*e=750 and d*e*f=250 the (a*f)/(c*d) = ? | {
"A": "1 / 2",
"B": "2 / 3",
"C": "3 / 4",
"D": "4 / 3",
"E": "none of these"
} | divide(multiply(130, 250), multiply(750, 65)) | multiply(n0,n3)|multiply(n1,n2)|divide(#0,#1)| | "explanation : a â ˆ — b â ˆ — c / b â ˆ — c â ˆ — d = 130 / 65 = > a / d = 2 d â ˆ — e â ˆ — f / c â ˆ — d â ˆ — e = 250 / 750 = > f / c = 1 / 3 a / d * f / c = 2 * 1 / 3 = 2 / 3 answer : b" | general |
math_qa__LfptWtQagt4MsgbX | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time cistern will get filled ? Options: A) 7 hours B) 7.1 hours C) 7.2 hours D) 7.3 hours E) none of these | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/4) - (1/9)</gadget>
<output>5/36 = around 0.138889</output>
<gadget id="calculator">1 / (5/36)</gadget>
<output>36/5 = around 7.2</output>
<result>C</result> | C | 7.2 | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time cistern will get filled ? | {
"A": "7 hours",
"B": "7.1 hours",
"C": "7.2 hours",
"D": "7.3 hours",
"E": "none of these"
} | divide(const_1, subtract(divide(const_1, 4), divide(const_1, 9))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)| | "explanation : when we have question like one is filling the tank and other is empting it , then we subtraction as , filled in 1 hour = 1 / 4 empties in 1 hour = 1 / 9 net filled in 1 hour = 1 / 4 - 1 / 9 = 5 / 36 so cistern will be filled in 36 / 5 hours i . e . 7.2 hours option c" | physics |
math_qa__cmw0sajMfHz9uMT1 | In a class of students, 2/3 of the number of girls is equal to 1/4 of the total number of students. What is the ratio of boys to girls in the class? Choose the correct answer: A) 1 / 3 B) 2 / 3 C) 4 / 3 D) 5 / 3 E) 7 / 3 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(2/3) - (1/4)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) / (1/4)</gadget>
<output>5/3 = around 1.666667</output>
<result>D</result> | D | 1.666667 | In a class of students, 2/3 of the number of girls is equal to 1/4 of the total number of students. What is the ratio of boys to girls in the class? | {
"A": "1 / 3",
"B": "2 / 3",
"C": "4 / 3",
"D": "5 / 3",
"E": "7 / 3"
} | divide(subtract(divide(2, 3), divide(1, 4)), divide(1, 4)) | divide(n0,n1)|divide(n2,n3)|subtract(#0,#1)|divide(#2,#1)| | "( 2 / 3 ) g = ( 1 / 4 ) ( b + g ) 8 g = 3 b + 3 g 5 g = 3 b b / g = 5 / 3 . the answer is d ." | general |
math_qa__BheeyKUciWWcWUVK | A portion of the 85% solution of chemicals was replaced with an equal amount of 20% solution of chemicals. As a result, 40% solution of chemicals resulted. What part of the original solution was replaced?
Choose the most appropriate option:
A) 5 / 13
B) 6 / 13
C) 9 / 13
D) 13 / 9
E) 13 / 6 | <gadget id="calculator">85 - 40</gadget>
<output>45</output>
<gadget id="calculator">85 - 20</gadget>
<output>65</output>
<gadget id="calculator">45 / 65</gadget>
<output>9/13 = around 0.692308</output>
<result>C</result> | C | 0.692308 | A portion of the 85% solution of chemicals was replaced with an equal amount of 20% solution of chemicals. As a result, 40% solution of chemicals resulted. What part of the original solution was replaced? | {
"A": "5 / 13",
"B": "6 / 13",
"C": "9 / 13",
"D": "13 / 9",
"E": "13 / 6"
} | divide(subtract(85, 40), subtract(85, 20)) | subtract(n0,n2)|subtract(n0,n1)|divide(#0,#1)| | "let the original amount of 85 percent solution = x and amount replaced be y 0.85 ( x - y ) + 0.2 y = 0.4 x 0.85 x - 0.85 y + 0.2 y = 0.4 x 0.45 x = 0.65 y 9 x = 13 y y = 9 x / 13 so , amount replaced = 9 / 13 of original amount answer : c" | gain |
math_qa__dWLz0hPXJnc6jAjv | Rain is falling at a rate of 10 centimeters per hour all over North Carolina. Somewhere downtown in North Carolina a group of people are waiting for the rain to stop. If the rain filled a round puddle the with a base area of 300 square centimeters and a depth of 30 centimeters, how long did the people wait for the rain to stop? Choose the correct answer.
A) 4 hours
B) 11 hours
C) 7 hours 15 minutes
D) 3 hours
E) 14 hours | <gadget id="calculator">30 / 10</gadget>
<output>3</output>
<result>D</result> | D | 3 | Rain is falling at a rate of 10 centimeters per hour all over North Carolina. Somewhere downtown in North Carolina a group of people are waiting for the rain to stop. If the rain filled a round puddle the with a base area of 300 square centimeters and a depth of 30 centimeters, how long did the people wait for the rain to stop? | {
"A": "4 hours",
"B": "11 hours",
"C": "7 hours 15 minutes",
"D": "3 hours",
"E": "14 hours"
} | divide(30, 10) | divide(n2,n0) | answer is : d , 3 hours the volume of the puddle is irrelevant and only height matters since rain fell all over the city . thus , it takes only 30 / 10 = 3 hours of rain to fill the puddle | geometry |
math_qa__CTArEk409d7SJG9g | The greatest number which on dividing 1442 and 1816 leaves remainders 12 and 6 respectively, is: Choose the correct choice
A) 123 B) 127 C) 235 D) 305 E) 10 | <gadget id="calculator">1_816 - 6</gadget>
<output>1_810</output>
<gadget id="calculator">1_442 - 12</gadget>
<output>1_430</output>
<gadget id="calculator">gcd(1_810, 1_430)</gadget>
<output>10</output>
<result>E</result> | E | 10 | The greatest number which on dividing 1442 and 1816 leaves remainders 12 and 6 respectively, is: | {
"A": "123",
"B": "127",
"C": "235",
"D": "305",
"E": "10"
} | gcd(subtract(1816, 6), subtract(1442, 12)) | subtract(n1,n3)|subtract(n0,n2)|gcd(#0,#1) | explanation : required number = h . c . f . of ( 1442 - 12 ) and ( 1816 - 6 ) = h . c . f . of 1430 and 1810 = 10 . answer : e | general |
math_qa__w809DNURLEERmZqy | A wooden box of dimensions 4 m x 2 m x 4 m is to carry rectangularboxes of dimensions 4 cm x 2 cm x 2 cm. The maximum number ofboxes that can be carried in the wooden box, is Choose the correct choice from the following answers:
A) 9800000 B) 2000000 C) 7500000 D) 1200000 E) none of these | <gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">400 * 200</gadget>
<output>80_000</output>
<gadget id="calculator">80_000 * 400</gadget>
<output>32_000_000</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">32_000_000 / 16</gadget>
<output>2_000_000</output>
<result>B</result> | B | 2,000,000 | A wooden box of dimensions 4 m x 2 m x 4 m is to carry rectangularboxes of dimensions 4 cm x 2 cm x 2 cm. The maximum number ofboxes that can be carried in the wooden box, is | {
"A": "9800000",
"B": "2000000",
"C": "7500000",
"D": "1200000",
"E": "none of these"
} | divide(multiply(multiply(multiply(4, const_100), multiply(2, const_100)), multiply(4, const_100)), multiply(multiply(4, 2), 2)) | multiply(n0,const_100)|multiply(n1,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(n1,#2)|multiply(#3,#0)|divide(#5,#4) | explanation : number = ( 400 * 200 * 400 ) / 4 * 2 * 2 = 2000000 answer : b | physics |
math_qa__nbRsk662ElJwjBiS | If two projectiles are launched at the same moment from 1182 km apart and travel directly towards each other at 460 km per hour and 525 km per hour respectively, how many minutes will it take for them to meet? Answers
A) 68 B) 72 C) 76 D) 80 E) 84 | <gadget id="calculator">460 + 525</gadget>
<output>985</output>
<gadget id="calculator">1_182 / 985</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 60</gadget>
<output>72</output>
<result>B</result> | B | 72 | If two projectiles are launched at the same moment from 1182 km apart and travel directly towards each other at 460 km per hour and 525 km per hour respectively, how many minutes will it take for them to meet? | {
"A": "68",
"B": "72",
"C": "76",
"D": "80",
"E": "84"
} | multiply(divide(1182, add(460, 525)), const_60) | add(n1,n2)|divide(n0,#0)|multiply(#1,const_60) | the projectiles travel a total of 985 km per hour . the time to meet is 1182 / 985 = 1.2 hours = 72 minutes the answer is b . | physics |
math_qa__psfDJ8oiHaHYD6A6 | A metallic sphere of radius 12 cm is melted and drawn into a wire, whose radius of cross section is 8 cm. What is the length of the wire? Choose the correct choice from the following answers: A) 16 cm B) 24 cm C) 28 cm D) 36 cm E) 39 cm | <gadget id="calculator">12 ** 3</gadget>
<output>1_728</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">1_728 / 64</gadget>
<output>27</output>
<gadget id="calculator">4 * 27</gadget>
<output>108</output>
<gadget id="calculator">108 / 3</gadget>
<output>36</output>
<result>D</result> | D | 36 | A metallic sphere of radius 12 cm is melted and drawn into a wire, whose radius of cross section is 8 cm. What is the length of the wire? | {
"A": "16 cm",
"B": "24 cm",
"C": "28 cm",
"D": "36 cm",
"E": "39 cm"
} | divide(multiply(const_4, divide(power(12, const_3), power(8, const_2))), const_3) | power(n0,const_3)|power(n1,const_2)|divide(#0,#1)|multiply(#2,const_4)|divide(#3,const_3)| | "volume of the wire ( in cylindrical shape ) is equal to the volume of the sphere . π ( 8 ) ^ 2 * h = ( 4 / 3 ) π ( 12 ) ^ 3 = > h = 36 cm answer : d" | physics |
math_qa__WOJVgbhl35d1uob8 | If 0.4 of a number is equal to 0.06 of another number, the ratio of the numbers is :
Choose the correct choice from the following answers
A) 2 : 3 B) 3 : 4 C) 3 : 20 D) 20 : 3 E) 22 : 1 | <gadget id="calculator">0.06 * 100</gadget>
<output>6</output>
<gadget id="calculator">0.4 * 100</gadget>
<output>40</output>
<gadget id="calculator">6 / 40</gadget>
<output>3/20 = around 0.15</output>
<result>C</result> | C | 0.15 | If 0.4 of a number is equal to 0.06 of another number, the ratio of the numbers is : | {
"A": "2 : 3",
"B": "3 : 4",
"C": "3 : 20",
"D": "20 : 3",
"E": "22 : 1"
} | divide(multiply(0.06, const_100), multiply(0.4, const_100)) | multiply(n1,const_100)|multiply(n0,const_100)|divide(#0,#1)| | "expl : 0.4 a = 0.06 b - > a / b = 0.06 / 0.40 = 6 / 40 = 3 / 20 : . a : b = 3 : 20 answer : c" | other |
math_qa__wMW6ZJ5brSR4k0S6 | A group of people participate in some curriculum, 25 of them practice Yoga, 18 study cooking, 10 study weaving, 4 of them study cooking only, 5 of them study both the cooking and yoga, 4 of them participate all curriculums. How many people study both cooking and weaving? Choose one
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">18 - 5</gadget>
<output>13</output>
<gadget id="calculator">13 - 4</gadget>
<output>9</output>
<gadget id="calculator">9 - 4</gadget>
<output>5</output>
<result>E</result> | E | 5 | A group of people participate in some curriculum, 25 of them practice Yoga, 18 study cooking, 10 study weaving, 4 of them study cooking only, 5 of them study both the cooking and yoga, 4 of them participate all curriculums. How many people study both cooking and weaving? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(subtract(subtract(18, 5), 4), 4) | subtract(n1,n4)|subtract(#0,n5)|subtract(#1,n3)| | "both cooking and weaving = 18 - ( 4 + 4 + 5 ) = 5 so , the correct answer is e ." | other |
math_qa__JjqM4CJOkkfaRvFY | A $500 investment and a $1,500 investment have a combined yearly return of 22 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? Choose the correct choice from the following
A) 29 % B) 20 % C) 27 % D) 25 % E) 12 % | <gadget id="calculator">3 * 500</gadget>
<output>1_500</output>
<gadget id="calculator">500 + 1_500</gadget>
<output>2_000</output>
<gadget id="calculator">22 / 100</gadget>
<output>11/50 = around 0.22</output>
<gadget id="calculator">2_000 * (11/50)</gadget>
<output>440</output>
<gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">500 * (7/100)</gadget>
<output>35</output>
<gadget id="calculator">440 - 35</gadget>
<output>405</output>
<gadget id="calculator">405 / 1_500</gadget>
<output>27/100 = around 0.27</output>
<gadget id="calculator">(27/100) * 100</gadget>
<output>27</output>
<result>C</result> | C | 27 | A $500 investment and a $1,500 investment have a combined yearly return of 22 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? | {
"A": "29 %",
"B": "20 %",
"C": "27 %",
"D": "25 %",
"E": "12 %"
} | multiply(divide(subtract(multiply(add(500, multiply(const_3, 500)), divide(22, const_100)), multiply(500, divide(7, const_100))), multiply(const_3, 500)), const_100) | divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_3)|add(n0,#2)|multiply(n0,#1)|multiply(#3,#0)|subtract(#5,#4)|divide(#6,#2)|multiply(#7,const_100)| | "the equation we can form the question : return on total investment = sum of individual investments ( 500 + 1500 ) ( 22 ) = ( 500 â ˆ — 7 ) + ( 1500 x ) , where x is the return on investment of 1500 . solving the equation , we get x = 27 % ( option c ) answer : c" | gain |
math_qa__1s21LxT9QGQgjBC9 | Joe went on a diet 3 months ago when he weighed 222 pounds. If he now weighs 198 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 170 pounds? Select the correct option:
A) 3 B) 3.5 C) 4 D) 4.5 E) 5 | <gadget id="calculator">198 - 170</gadget>
<output>28</output>
<gadget id="calculator">222 - 198</gadget>
<output>24</output>
<gadget id="calculator">24 / 3</gadget>
<output>8</output>
<gadget id="calculator">28 / 8</gadget>
<output>7/2 = around 3.5</output>
<result>B</result> | B | 3.5 | Joe went on a diet 3 months ago when he weighed 222 pounds. If he now weighs 198 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 170 pounds? | {
"A": "3",
"B": "3.5",
"C": "4",
"D": "4.5",
"E": "5"
} | divide(subtract(198, 170), divide(subtract(222, 198), 3)) | subtract(n2,n3)|subtract(n1,n2)|divide(#1,n0)|divide(#0,#2)| | "222 - 198 = 24 pounds lost in 3 months 24 / 3 = 8 , so joe is losing weight at a rate of 8 pounds per month . . . . in approximately how many months will he weigh 170 pounds ? a simple approach is to just list the weights . now : 198 lbs in 1 month : 190 lbs in 2 months : 182 lbs in 3 months : 174 lbs in 4 months : 166 lbs since 170 pounds is halfway between 174 and 166 , the correct answer must be 3.5 months . answer : b" | general |
math_qa__F4ljKBvpPbZXaLwr | Two cars are traveling in the same direction along the same route. The red car travels at a constant speed of 40 miles per hour, and the black car is traveling at a constant speed of 50 miles per hour. If the red car is 30 miles ahead of the black car, how many hours will it take the black car to overtake the red car? Choose the correct choice from the following answers:
A) 0.1 B) 0.6 C) 1 D) 1.2 E) 3 | <gadget id="calculator">50 - 40</gadget>
<output>10</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<result>E</result> | E | 3 | Two cars are traveling in the same direction along the same route. The red car travels at a constant speed of 40 miles per hour, and the black car is traveling at a constant speed of 50 miles per hour. If the red car is 30 miles ahead of the black car, how many hours will it take the black car to overtake the red car? | {
"A": "0.1",
"B": "0.6",
"C": "1",
"D": "1.2",
"E": "3"
} | divide(30, subtract(50, 40)) | subtract(n1,n0)|divide(n2,#0) | option e 20 + 40 t = 50 t t = 3 | physics |
math_qa__BfNPQldrdxjMoOHf | In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 70 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ? Choose the correct choice from the following:
A) 50 %
B) 53 %
C) 54 %
D) 55 %
E) 57 % | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">60 * (7/10)</gadget>
<output>42</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">40 * (1/5)</gadget>
<output>8</output>
<gadget id="calculator">42 + 8</gadget>
<output>50</output>
<result>A</result> | A | 50 | In a certain city, 60 percent of the registered voters are Democrats and the rest are Republicans. In a mayoral race, if 70 percent of the registered voters who are Democrats and 20 percent of the registered voters who are Republicans are expected to vote for Candidate A, what percent of the registered voters are expected to vote for Candidate A ? | {
"A": "50 %",
"B": "53 %",
"C": "54 %",
"D": "55 %",
"E": "57 %"
} | add(multiply(60, divide(70, const_100)), multiply(subtract(const_100, 60), divide(20, const_100))) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_100,n0)|multiply(n0,#0)|multiply(#1,#2)|add(#3,#4)| | "say there are total of 100 registered voters in that city . thus 60 are democrats and 40 are republicans . 60 * 0.70 = 42 democrats are expected to vote for candidate a ; 40 * 0.20 = 8 republicans are expected to vote for candidate a . thus total of 42 + 8 = 50 registered voters are expected to vote for candidate a , which is 50 % of the total number of registered voters . answer : a" | gain |
math_qa__rX0H0mHDDOh8Q7zw | A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 98 are wrong and other digits are correct, then the correct answer would be:
Choices.
A) 553681
B) 555181
C) 555681
D) 556581
E) 555581 | <gadget id="calculator">559_981 / 987</gadget>
<output>559_981/987 = around 567.356636</output>
<gadget id="calculator">(559_981/987) - 4</gadget>
<output>556_033/987 = around 563.356636</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(556_033/987) - (1/3)</gadget>
<output>555_704/987 = around 563.023303</output>
<gadget id="calculator">(555_704/987) * 987</gadget>
<output>555_704</output>
<result>C</result> | C | 555,681 | A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 98 are wrong and other digits are correct, then the correct answer would be: | {
"A": "553681",
"B": "555181",
"C": "555681",
"D": "556581",
"E": "555581"
} | multiply(subtract(subtract(divide(559981, 987), const_4), const_0_33), 987) | divide(n1,n0)|subtract(#0,const_4)|subtract(#1,const_0_33)|multiply(n0,#2)| | "987 = 3 x 7 x 47 . so , the required number must be divisible by each one of 3 , 7 , 47 553681 - - > sum of digits = 28 , not divisible by 3 555181 sum of digits = 25 , not divisible by 3 555681 is divisible by each one of 3 , 7 , 47 . 556581 sum of digits = 30 , not divisible by 7 555581 sum of digits = 29 , not divisible by 3 so the answer is c ." | other |
math_qa__JILyEin8h186mtTh | Given f(x) = 2x – 3, for what value of x does 2*[f(x)] – 11 = f(x – 2) ? Choose the correct choice from the following:
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 + 11</gadget>
<output>17</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">17 - 7</gadget>
<output>10</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>D</result> | D | 5 | Given f(x) = 2x – 3, for what value of x does 2*[f(x)] – 11 = f(x – 2) ? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(subtract(add(multiply(2, 3), 11), add(multiply(2, 2), 3)), subtract(multiply(2, 2), multiply(2, const_1))) | multiply(n1,n2)|multiply(n4,n0)|multiply(n0,n2)|multiply(n0,const_1)|add(n3,#0)|add(n1,#1)|subtract(#2,#3)|subtract(#4,#5)|divide(#7,#6)| | "2 ( 2 x - 3 ) - 11 = 2 ( x - 2 ) - 3 2 x = 10 x = 5 the answer is d ." | general |
math_qa__jJazwv9IjVKDRl1a | Pipe A fills a tank of capacity 750 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full? Choices.
A) 45 minutes B) 14 minutes C) 39 minutes D) 40 minutes 20 seconds E) none of these | <gadget id="calculator">40 + 30</gadget>
<output>70</output>
<gadget id="calculator">70 - 20</gadget>
<output>50</output>
<gadget id="calculator">750 / 50</gadget>
<output>15</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<result>A</result> | A | 45 | Pipe A fills a tank of capacity 750 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full? | {
"A": "45 minutes",
"B": "14 minutes",
"C": "39 minutes",
"D": "40 minutes 20 seconds",
"E": "none of these"
} | multiply(divide(750, subtract(add(40, 30), 20)), const_3) | add(n1,n2)|subtract(#0,n3)|divide(n0,#1)|multiply(#2,const_3)| | "in one cycle they fill 40 + 30 - 20 = 50 liters 750 = 50 * n = > n = 15 here n = number of cycles . total time = 15 * 3 = 45 as in one cycle there are 3 minutes . thus 45 minutes answer : a" | physics |
math_qa__RiWlnLloFRUTYfKb | All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 150 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A? Choose the most appropriate option:
A) 1200
B) 1723
C) 1129
D) 2613
E) 1372 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">62.5 / 100</gadget>
<output>0.625</output>
<gadget id="calculator">1 - 0.625</gadget>
<output>0.375</output>
<gadget id="calculator">(1/2) - 0.375</gadget>
<output>0.125</output>
<gadget id="calculator">150 / 0.125</gadget>
<output>1_200</output>
<result>A</result> | A | 1,200 | All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 150 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A? | {
"A": "1200",
"B": "1723",
"C": "1129",
"D": "2613",
"E": "1372"
} | divide(150, subtract(inverse(const_2), subtract(const_1, divide(62.5, const_100)))) | divide(n0,const_100)|inverse(const_2)|subtract(const_1,#0)|subtract(#1,#2)|divide(n1,#3)| | "a b has 62.5 % or ( 5 / 8 ) of the milk in a . therefore , let the quantity of milk in container a ( initially ) be 8 k . quantity of milk in b = 8 k - 5 k = 3 k . quantity of milk in container c = 8 k - 3 k = 5 k container : a b c quantity of milk : 8 k 3 k 5 k it is given that if 150 liters was transferred from container c to container b , then both the containers would have equal quantities of milk . 5 k - 150 = 3 k + 150 = > 2 k = 300 = > k = 150 the initial quantity of milk in a = 8 k = 8 * 150 = 1200 liters ." | general |
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