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stringlengths 7
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stringlengths 8
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math_qa__HODtEVFjTXL4E0VK | What is the ratio between perimeters of two squares one having 5 times the diagonal then the other?
Choose the correct choice from the following choices
A) 5 : 1 B) 3 : 1 C) 5 : 8 D) 3 : 2 E) 8 : 3 | <gadget id="calculator">5 / 5</gadget>
<output>1</output>
<gadget id="calculator">5 / 1</gadget>
<output>5</output>
<result>A</result> | A | 5 | What is the ratio between perimeters of two squares one having 5 times the diagonal then the other? | {
"A": "5 : 1",
"B": "3 : 1",
"C": "5 : 8",
"D": "3 : 2",
"E": "8 : 3"
} | divide(5, divide(5, 5)) | divide(n0,n0)|divide(n0,#0)| | "d = 5 d d = d a √ 2 = 5 d a √ 2 = d a = 5 d / √ 2 a = d / √ 2 = > 5 : 1 answer : a" | geometry |
math_qa__hhwh57X7k5V7vQUC | Find the area of a parallelogram with base 48 cm and height 36 cm? Pick
A) 1730 cm 2 B) 1728 cm 2 C) 1870 cm 2 D) 1890 cm 2 E) 668 cm 2 | <gadget id="calculator">48 * 36</gadget>
<output>1_728</output>
<result>B</result> | B | 1,728 | Find the area of a parallelogram with base 48 cm and height 36 cm? | {
"A": "1730 cm 2",
"B": "1728 cm 2",
"C": "1870 cm 2",
"D": "1890 cm 2",
"E": "668 cm 2"
} | multiply(48, 36) | multiply(n0,n1)| | "area of a parallelogram = base * height = 48 * 36 = 1728 cm 2 answer : b" | geometry |
math_qa__zmXHJgQNcZYzfAT2 | A question paper has 2parts, A & B, each containing 10 questions. If a student has to choose 8 from part A &5 from part B, in how many ways can he choose the questions?
Choose the correct choice from the following answers:
A) 1100
B) 1200
C) 1235
D) 1354
E) 1140 | <gadget id="calculator">binomial(10, 8)</gadget>
<output>45</output>
<gadget id="calculator">binomial(10, 5)</gadget>
<output>252</output>
<gadget id="calculator">45 * 252</gadget>
<output>11_340</output>
<gadget id="calculator">11_340 / 10</gadget>
<output>1_134</output>
<result>E</result> | E | 1,140 | A question paper has 2parts, A & B, each containing 10 questions. If a student has to choose 8 from part A &5 from part B, in how many ways can he choose the questions? | {
"A": "1100",
"B": "1200",
"C": "1235",
"D": "1354",
"E": "1140"
} | divide(multiply(choose(10, 8), choose(10, 5)), 10) | choose(n1,n2)|choose(n1,n3)|multiply(#0,#1)|divide(#2,n1) | there 10 questions in part a out of which 8 question can be chosen as = 10 c 8 . similarly , 5 questions can be chosen from 10 questions of part b as = 10 c 5 . hence , total number of ways , = 10 c 8 * 10 c 5 = [ 10 ! / ( 2 ! 8 ! ) ] * [ 10 ! / ( 5 ! * 5 ) ] = { 10 * 9 / 2 } * { 10 * 9 * 8 * 7 * 6 / ( 5 * 4 * 3 * 2 * 1 ) } = 1140 . e | probability |
math_qa__H9yw5mBp9gSe8N6e | What must be added to each term of the ratio 4 : 15, so that it may become equal to 3 : 4? Pick: A) 18 B) 29 C) 39 D) 49 E) 59 | <gadget id="calculator">3 * 15</gadget>
<output>45</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">45 - 16</gadget>
<output>29</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">29 / 1</gadget>
<output>29</output>
<result>B</result> | B | 29 | What must be added to each term of the ratio 4 : 15, so that it may become equal to 3 : 4? | {
"A": "18",
"B": "29",
"C": "39",
"D": "49",
"E": "59"
} | divide(subtract(multiply(3, 15), multiply(4, 4)), subtract(4, 3)) | multiply(n1,n2)|multiply(n0,n3)|subtract(n3,n2)|subtract(#0,#1)|divide(#3,#2)| | "let x be added to each term of the ratio 4 : 15 . new ratio becomes ( 4 + x ) / ( 15 + x ) , which is given to be equal to 3 : 4 . this means , ( 4 + x ) / ( 15 + x ) = 3 / 4 solving we get , x = 29 . ans b" | general |
math_qa__QNO7WF1O4fMYazTv | What is the greatest prime factor of (11! × 10! + 10! × 9!)/111? Choose the correct option
A) 2 B) 3 C) 5 D) 7 E) 11 | <gadget id="calculator">11 * 10</gadget>
<output>110</output>
<gadget id="calculator">110 + 1</gadget>
<output>111</output>
<gadget id="calculator">111 / 111</gadget>
<output>1</output>
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<result>D</result> | D | 7 | What is the greatest prime factor of (11! × 10! + 10! × 9!)/111? | {
"A": "2",
"B": "3",
"C": "5",
"D": "7",
"E": "11"
} | add(add(divide(add(multiply(11, 10), const_1), 111), const_3), const_3) | multiply(n0,n1)|add(#0,const_1)|divide(#1,n4)|add(#2,const_3)|add(#3,const_3) | ( 11 ! × 10 ! + 10 ! × 9 ! ) / 111 in numerator take out 10 ! * 9 ! as common term 10 ! ∗ 9 ! ( 11 × 10 + 1 ) / 111 10 ! ∗ 9 ! ∗ 111 / 111 10 ! ∗ 9 ! 10 ! has 7 as the greatest prime factor , so ans is 7 answer : d | general |
math_qa__d36Ji4hkubtDmtwN | There are 11 teams in a soccer league and each team plays each of the other teams once. How many games will be played in total? Pick one.
A) 40 B) 45 C) 50 D) 55 E) 60 | <gadget id="calculator">factorial(11)</gadget>
<output>39_916_800</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">362_880 * 2</gadget>
<output>725_760</output>
<gadget id="calculator">39_916_800 / 725_760</gadget>
<output>55</output>
<result>D</result> | D | 55 | There are 11 teams in a soccer league and each team plays each of the other teams once. How many games will be played in total? | {
"A": "40",
"B": "45",
"C": "50",
"D": "55",
"E": "60"
} | divide(factorial(11), multiply(factorial(subtract(11, const_2)), factorial(const_2))) | factorial(n0)|factorial(const_2)|subtract(n0,const_2)|factorial(#2)|multiply(#3,#1)|divide(#0,#4)| | "11 c 2 = 55 the answer is d ." | general |
math_qa__1RwHUNj2kbuOuD2R | The average of 10 numbers was calculated as 17. It is discovered later on that while calculating the average, one number, namely 56, was incorrectly read as 26. What is the correct average? Pick one
A) 19 B) 20 C) 21 D) 22 E) 23 | <gadget id="calculator">10 * 17</gadget>
<output>170</output>
<gadget id="calculator">56 - 26</gadget>
<output>30</output>
<gadget id="calculator">170 + 30</gadget>
<output>200</output>
<gadget id="calculator">200 / 10</gadget>
<output>20</output>
<result>B</result> | B | 20 | The average of 10 numbers was calculated as 17. It is discovered later on that while calculating the average, one number, namely 56, was incorrectly read as 26. What is the correct average? | {
"A": "19",
"B": "20",
"C": "21",
"D": "22",
"E": "23"
} | divide(add(multiply(10, 17), subtract(56, 26)), 10) | multiply(n0,n1)|subtract(n2,n3)|add(#0,#1)|divide(#2,n0) | 10 * 17 - 26 + 56 = 200 200 / 10 = 20 the answer is b . | general |
math_qa__mz8FkMGvkXC8nEl2 | The average of 6 observations is 15. A new observation is included and the new average is decreased by 1. The seventh observation is? Choices: A) 1 B) 8 C) 5 D) 6 E) 7 | <gadget id="calculator">15 - 1</gadget>
<output>14</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">14 * 7</gadget>
<output>98</output>
<gadget id="calculator">15 * 6</gadget>
<output>90</output>
<gadget id="calculator">98 - 90</gadget>
<output>8</output>
<result>B</result> | B | 8 | The average of 6 observations is 15. A new observation is included and the new average is decreased by 1. The seventh observation is? | {
"A": "1",
"B": "8",
"C": "5",
"D": "6",
"E": "7"
} | subtract(multiply(subtract(15, 1), add(6, 1)), multiply(15, 6)) | add(n0,n2)|multiply(n0,n1)|subtract(n1,n2)|multiply(#0,#2)|subtract(#3,#1)| | "let seventh observation = x . then , according to the question we have = > ( 90 + x ) / 7 = 14 = > x = 8 hence , the seventh observation is 8 answer : b" | general |
math_qa__v112xJZOD0AUNRLt | A motorcyclist goes from Bombay to Pune, a distance of 288 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car? Answers.
A) 1 : 2 B) 1 : 5 C) 1 : 4 D) 2 : 3 E) 1 : 8 | <gadget id="calculator">288 / 32</gadget>
<output>9</output>
<gadget id="calculator">288 / 9</gadget>
<output>32</output>
<gadget id="calculator">9 - 3</gadget>
<output>6</output>
<gadget id="calculator">288 / 6</gadget>
<output>48</output>
<gadget id="calculator">32 / 48</gadget>
<output>2/3 = around 0.666667</output>
<result>D</result> | D | 0.666667 | A motorcyclist goes from Bombay to Pune, a distance of 288 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car? | {
"A": "1 : 2",
"B": "1 : 5",
"C": "1 : 4",
"D": "2 : 3",
"E": "1 : 8"
} | divide(divide(288, divide(288, 32)), divide(288, subtract(divide(288, 32), const_3))) | divide(n0,n1)|divide(n0,#0)|subtract(#0,const_3)|divide(n0,#2)|divide(#1,#3)| | "t = 288 / 32 = 9 h t = 9 - 3 = 6 time ratio = 9 : 6 = 3 : 2 speed ratio = 2 : 3 answer : d" | physics |
math_qa__BUUg6sPj7Sk0w9R6 | What is the area of square field whose side of length 5 m?
Choose one.
A) 80 sq m
B) 26 sq m
C) 25 sq m
D) 45 sq m
E) 96 sq m | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<result>C</result> | C | 25 | What is the area of square field whose side of length 5 m? | {
"A": "80 sq m",
"B": "26 sq m",
"C": "25 sq m",
"D": "45 sq m",
"E": "96 sq m"
} | square_area(5) | square_area(n0)| | "5 * 5 = 25 sq m answer : c" | geometry |
math_qa__HUTkL7gKUTQAa4He | If 25% of x is 30 less than 15% of 1500, then x is?
Choose the most appropriate option: A) 872 B) 738 C) 837 D) 780 E) 83 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1_500 * (3/20)</gadget>
<output>225</output>
<gadget id="calculator">225 - 30</gadget>
<output>195</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">195 / (1/4)</gadget>
<output>780</output>
<result>D</result> | D | 780 | If 25% of x is 30 less than 15% of 1500, then x is? | {
"A": "872",
"B": "738",
"C": "837",
"D": "780",
"E": "83"
} | divide(subtract(multiply(1500, divide(15, const_100)), 30), divide(25, const_100)) | divide(n2,const_100)|divide(n0,const_100)|multiply(n3,#0)|subtract(#2,n1)|divide(#3,#1)| | "25 % of x = x / 4 ; 15 % of 1500 = 15 / 100 * 1500 = 225 given that , x / 4 = 225 - 30 = > x / 4 = 195 = > x = 780 . answer : d" | general |
math_qa__iQ9yBFPG2qMCE2ds | By selling an article at Rs.1000, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%? Choices
A) s . 600 B) s . 480 C) s . 500 D) s . 450 E) s . 550 | <gadget id="calculator">1_000 * 100</gadget>
<output>100_000</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">100_000 / 125</gadget>
<output>800</output>
<gadget id="calculator">800 * 25</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 100</gadget>
<output>200</output>
<gadget id="calculator">800 - 200</gadget>
<output>600</output>
<result>A</result> | A | 600 | By selling an article at Rs.1000, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%? | {
"A": "s . 600",
"B": "s . 480",
"C": "s . 500",
"D": "s . 450",
"E": "s . 550"
} | subtract(divide(multiply(1000, const_100), add(25, const_100)), divide(multiply(divide(multiply(1000, const_100), add(25, const_100)), 25), const_100)) | add(n1,const_100)|multiply(n0,const_100)|divide(#1,#0)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "sp = 1000 profit = 25 % cp = ( sp ) * [ 100 / ( 100 + p ) ] = 1000 * [ 100 / 125 ] = 800 loss = 25 % = 25 % of 800 = rs . 200 sp = cp - loss = 800 - 200 = rs . 600 answer : a" | gain |
math_qa__vm2l69CIuIM1YKZE | Albert is 2 times Mary’s age and 4 times as old as Betty. Mary is 22 years younger than Albert. How old is Betty? Select the correct option.
A) 8 B) 9 C) 11 D) 15 E) 18 | <gadget id="calculator">2 * 22</gadget>
<output>44</output>
<gadget id="calculator">44 / 4</gadget>
<output>11</output>
<result>C</result> | C | 11 | Albert is 2 times Mary’s age and 4 times as old as Betty. Mary is 22 years younger than Albert. How old is Betty? | {
"A": "8",
"B": "9",
"C": "11",
"D": "15",
"E": "18"
} | divide(multiply(2, 22), 4) | multiply(n0,n2)|divide(#0,n1)| | "a = 2 m = m + 22 m = 22 a = 44 a = 4 b , and so b = 11 the answer is c ." | general |
math_qa__ItTPjhT601h2FKiO | The perimeter of a triangle is 32 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle Choose the correct choice from the following answers
A) 40 B) 828 C) 729 D) 34 E) 35 | <gadget id="calculator">(2.5 * 32) / 2</gadget>
<output>40</output>
<result>A</result> | A | 40 | The perimeter of a triangle is 32 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle | {
"A": "40",
"B": "828",
"C": "729",
"D": "34",
"E": "35"
} | triangle_area(2.5, 32) | triangle_area(n0,n1)| | "explanation : area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 2.5 * 32 / 2 = 40 cm 2 answer : option a" | geometry |
math_qa__65kUPjtzFrspXSZ4 | Two brother X and Y appeared for an exam. The probability of selection of X is 1/5 and that of B is 2/3. Find the probability that both of them are selected. Choose the correct answer:
A) 2 / 69
B) 2 / 20
C) 2 / 18
D) 2 / 29
E) 2 / 15 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(1/5) * (2/3)</gadget>
<output>2/15 = around 0.133333</output>
<result>E</result> | E | 0.133333 | Two brother X and Y appeared for an exam. The probability of selection of X is 1/5 and that of B is 2/3. Find the probability that both of them are selected. | {
"A": "2 / 69",
"B": "2 / 20",
"C": "2 / 18",
"D": "2 / 29",
"E": "2 / 15"
} | multiply(divide(1, 5), divide(2, 3)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)| | "explanation : let a be the event that x is selected and b is the event that y is selected . p ( a ) = 1 / 5 , p ( b ) = 2 / 3 . let c be the event that both are selected . p ( c ) = p ( a ) ã — p ( b ) as a and b are independent events : = ( 1 / 5 ) ã — ( 2 / 3 ) = 2 / 15 answer : e ) 2 / 15" | general |
math_qa__w9mmZSAN1do7yK5u | What is the smallest number which when increased by 7 is divisible by 25, 49, 15, and 21? Choose the correct answer.
A) 3,551 B) 3,668 C) 3,733 D) 3,822 E) 3,957 | <gadget id="calculator">lcm(25, 49)</gadget>
<output>1_225</output>
<gadget id="calculator">lcm(15, 21)</gadget>
<output>105</output>
<gadget id="calculator">lcm(1_225, 105)</gadget>
<output>3_675</output>
<gadget id="calculator">3_675 + 7</gadget>
<output>3_682</output>
<result>B</result> | B | 3,668 | What is the smallest number which when increased by 7 is divisible by 25, 49, 15, and 21? | {
"A": "3,551",
"B": "3,668",
"C": "3,733",
"D": "3,822",
"E": "3,957"
} | add(lcm(lcm(25, 49), lcm(15, 21)), 7) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)| | "first factor each of 25 , 49 , 15 , and 21 into primes : 25 = 5 * 5 ; 49 = 7 * 7 ; 15 = 3 * 5 ; 21 = 3 * 7 the smallest number divisible by each of the numbers is 3 * 5 * 5 * 7 * 7 = 3,675 3,675 - 7 = 3,668 thus 3,668 + 7 is the smallest number divisible by 25 , 49 , 15 , and 21 b" | general |
math_qa__0NqK7yTodk7qw1Gh | At the opening of a trading day at a certain stock exchange, the price per share of stock K was $10. If the price per share of stock K was $15 at the closing of the day, what was the percent increase in the price per share of stock K for that day? Options.
A) 1.4 % B) 50 % C) 11.1 % D) 12.5 % E) 23.6 % | <gadget id="calculator">15 / 10</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>B</result> | B | 50 | At the opening of a trading day at a certain stock exchange, the price per share of stock K was $10. If the price per share of stock K was $15 at the closing of the day, what was the percent increase in the price per share of stock K for that day? | {
"A": "1.4 %",
"B": "50 %",
"C": "11.1 %",
"D": "12.5 %",
"E": "23.6 %"
} | multiply(subtract(divide(15, 10), const_1), const_100) | divide(n1,n0)|subtract(#0,const_1)|multiply(#1,const_100) | opening = 10 closing = 15 rise in price = 5 so , percent increase = 5 / 10 * 100 = 50 % answer : b | general |
math_qa__I7sMmXm9ACrwQ1BE | A can give B 100 meters start and C 150 meters start in a kilometer race. How much start can B give C in a kilometer race? Choose the correct answer.
A) 10.55 meters B) 11.55 meters C) 33.55 meters D) 55.55 meters E) none of these | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 150</gadget>
<output>850</output>
<gadget id="calculator">1_000 * 850</gadget>
<output>850_000</output>
<gadget id="calculator">1_000 - 100</gadget>
<output>900</output>
<gadget id="calculator">850_000 / 900</gadget>
<output>8_500/9 = around 944.444444</output>
<gadget id="calculator">1_000 - (8_500/9)</gadget>
<output>500/9 = around 55.555556</output>
<result>D</result> | D | 55.55 | A can give B 100 meters start and C 150 meters start in a kilometer race. How much start can B give C in a kilometer race? | {
"A": "10.55 meters",
"B": "11.55 meters",
"C": "33.55 meters",
"D": "55.55 meters",
"E": "none of these"
} | subtract(multiply(const_100, const_10), divide(multiply(multiply(const_100, const_10), subtract(multiply(const_100, const_10), 150)), subtract(multiply(const_100, const_10), 100))) | multiply(const_10,const_100)|subtract(#0,n1)|subtract(#0,n0)|multiply(#0,#1)|divide(#3,#2)|subtract(#0,#4)| | "explanation : a runs 1000 meters while b runs 900 meters and c runs 850 meters . therefore , b runs 900 meters while c runs 850 meters . so , the number of meters that c runs when b runs 1000 meters = ( 1000 x 850 ) / 900 = 944.44 meters thus , b can give c ( 1000 - 944.44 ) = 55.55 meters start answer : d" | physics |
math_qa__fo151K60WaTLOOqv | If 213 × 16 = 3408, then 1.6 × 2.13 is equal to : Pick.
A) 0.3408 B) 3.408 C) 34.08 D) 340.8 E) none of these | <gadget id="calculator">1.6 * 2.13</gadget>
<output>3.408</output>
<result>B</result> | B | 3.408 | If 213 × 16 = 3408, then 1.6 × 2.13 is equal to : | {
"A": "0.3408",
"B": "3.408",
"C": "34.08",
"D": "340.8",
"E": "none of these"
} | multiply(1.6, 2.13) | multiply(n4,n3)| | "solution 1.6 × 2.13 = ( 16 / 10 x 213 / 100 ) = ( 16 x 213 / 1000 ) = 3408 / 100 = 3.408 . answer b" | general |
math_qa__JLb4iaKswSO0jcWP | The owner of a furniture shop charges his customer 25% more than the cost price. If a customer paid Rs. 8340 for a computer table, then what was the cost price of the computer table? Choose the correct choice.
A) rs . 6672 B) rs . 6727 C) rs . 6908 D) rs . 6725 E) rs . 6728 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">8_340 / (5/4)</gadget>
<output>6_672</output>
<result>A</result> | A | 6,672 | The owner of a furniture shop charges his customer 25% more than the cost price. If a customer paid Rs. 8340 for a computer table, then what was the cost price of the computer table? | {
"A": "rs . 6672",
"B": "rs . 6727",
"C": "rs . 6908",
"D": "rs . 6725",
"E": "rs . 6728"
} | divide(8340, add(const_1, divide(25, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "cp = sp * ( 100 / ( 100 + profit % ) ) = 8340 ( 100 / 125 ) = rs . 6672 . answer : a" | gain |
math_qa__PT6clGZQKkJuVZOV | Everyone shakes hands with everyone else in a room. Total number of handshakes is 78. Number of persons=?
Choose the correct choice
A) 13 B) 12 C) 11 D) 15 E) 16 | <gadget id="calculator">78 * 2</gadget>
<output>156</output>
<gadget id="calculator">156 / 3</gadget>
<output>52</output>
<gadget id="calculator">52 / 4</gadget>
<output>13</output>
<result>A</result> | A | 13 | Everyone shakes hands with everyone else in a room. Total number of handshakes is 78. Number of persons=? | {
"A": "13",
"B": "12",
"C": "11",
"D": "15",
"E": "16"
} | divide(divide(multiply(78, const_2), const_3), const_4) | multiply(n0,const_2)|divide(#0,const_3)|divide(#1,const_4) | in a room of n people , the number of possible handshakes is c ( n , 2 ) or n ( n - 1 ) / 2 so n ( n - 1 ) / 2 = 78 or n ( n - 1 ) = 156 or n = 13 answer is ( a ) | general |
math_qa__m1H962YvWqWZlseC | In a group of 400 players some are outdoor players, some are indoor players and some plays both. 350 plays outdoors and 110 plays indoor. How many plays indoor as well as outdoor games.
Choose the correct choice from the following choices:
A) 70
B) 60
C) 90
D) 100
E) 110 | <gadget id="calculator">350 + 110</gadget>
<output>460</output>
<gadget id="calculator">460 - 400</gadget>
<output>60</output>
<result>B</result> | B | 60 | In a group of 400 players some are outdoor players, some are indoor players and some plays both. 350 plays outdoors and 110 plays indoor. How many plays indoor as well as outdoor games. | {
"A": "70",
"B": "60",
"C": "90",
"D": "100",
"E": "110"
} | subtract(add(350, 110), 400) | add(n1,n2)|subtract(#0,n0) | consider total number of players n ( o u i ) = 400 players who plays outdoors n ( o ) = 350 players who plays indoors n ( i ) = 110 players who plays both n ( o â ˆ © i ) = ? n ( o u i ) = n ( o ) + n ( i ) - n ( o â ˆ © i ) 400 = 350 + 110 - n ( o â ˆ © i ) n ( o â ˆ © i ) = 460 - 400 n ( o â ˆ © i ) = 60 so people read both science fiction and literacy works are 60 answer : b | other |
math_qa__vrOw9Vhpb12iCvBu | If 50% of x equals the sum of y and 20, then what is the value of x–2y? Select: A) 20 B) 40 C) 60 D) 80 E) 90 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">20 / (1/2)</gadget>
<output>40</output>
<result>B</result> | B | 40 | If 50% of x equals the sum of y and 20, then what is the value of x–2y? | {
"A": "20",
"B": "40",
"C": "60",
"D": "80",
"E": "90"
} | divide(20, divide(50, const_100)) | divide(n0,const_100)|divide(n1,#0) | explanation : given , 50 % of x equals the sum of y and 20 . = > ( 50 / 100 ) × x = y + 20 . = > x / 2 = y + 20 . = > x = 2 y + 40 . = > x – 2 y = 40 . answer : b | general |
math_qa__WXMIB9lbdozToOsz | Weights of two friends Ram and Shyam are in the ratio of 4 : 5. Ram’s weight increases by 10% and the total weight of Ram and Shyam together becomes 82.8 kg, with an increase of 15%. By what per cent did the weight of Shyam increase? Choose the correct option.
A) 12.5 % B) 17.5 % C) 19 % D) 21 % E) none of these | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">(4/5) * 5</gadget>
<output>4</output>
<gadget id="calculator">4 + 15</gadget>
<output>19</output>
<result>C</result> | C | 19 | Weights of two friends Ram and Shyam are in the ratio of 4 : 5. Ram’s weight increases by 10% and the total weight of Ram and Shyam together becomes 82.8 kg, with an increase of 15%. By what per cent did the weight of Shyam increase? | {
"A": "12.5 %",
"B": "17.5 %",
"C": "19 %",
"D": "21 %",
"E": "none of these"
} | add(multiply(divide(4, 5), subtract(15, 10)), 15) | divide(n0,n1)|subtract(n4,n2)|multiply(#0,#1)|add(n4,#2) | let the weights of ram and shyam be 4 x and 5 x . now , according to question , 4 x × 110 / 100 + shyam ? snewwt 4 x × 110100 + shyam ? s new wt = 82.8 . . . . . . . . ( i ) and 4 x + 5 x = 9 x + 115 / 100 = 82.8 . . . . . . . . ( ii ) from ( ii ) , x = 8 putting in ( i ) , we get shyam ’ s new wt = ( 82.8 – 35.2 ) = 47.6 % increase in shyam ’ s wt = ( 47.6 − 40 / 40 × 100 ) = 19 answer c | general |
math_qa__k7DawgAk5x1s8GeO | Barbata invests $2400 in the National Bank at 4%. How much additional money must she invest at 8% so that the total annual income will be equal to 6% of her entire investment?
Select.
A) 1200
B) 3000
C) 2400
D) 3600
E) 2450 | <gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 2_400</gadget>
<output>144</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">2_400 * (1/25)</gadget>
<output>96</output>
<gadget id="calculator">144 - 96</gadget>
<output>48</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(2/25) - (3/50)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">48 / (1/50)</gadget>
<output>2_400</output>
<result>C</result> | C | 2,400 | Barbata invests $2400 in the National Bank at 4%. How much additional money must she invest at 8% so that the total annual income will be equal to 6% of her entire investment? | {
"A": "1200",
"B": "3000",
"C": "2400",
"D": "3600",
"E": "2450"
} | divide(subtract(multiply(divide(6, const_100), 2400), multiply(2400, divide(4, const_100))), subtract(divide(8, const_100), divide(6, const_100))) | divide(n3,const_100)|divide(n1,const_100)|divide(n2,const_100)|multiply(n0,#0)|multiply(n0,#1)|subtract(#2,#0)|subtract(#3,#4)|divide(#6,#5)| | "let the additional invested amount for 8 % interest be x ; equation will be ; 2400 + 0.04 * 2400 + x + 0.08 x = 2400 + x + 0.06 ( 2400 + x ) 0.04 * 2400 + 0.08 x = 0.06 x + 0.06 * 2400 0.02 x = 2400 ( 0.06 - 0.04 ) x = 2400 * 0.02 / 0.02 = 2400 ans : c" | general |
math_qa__nXiYbxOks6qk0BVc | If m is an integer such that (-2)^2m=2^(12-m) then m=? Choose the correct choice from the following.
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<result>D</result> | D | 4 | If m is an integer such that (-2)^2m=2^(12-m) then m=? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(12, add(2, const_1)) | add(n0,const_1)|divide(n3,#0)| | "2 m = 12 - m 3 m = 12 m = 4 the answer is d ." | general |
math_qa__5UFNVP9XKg4qfmn7 | P and Q are the only two applicants qualified for a short-term research project that pays 540 dollars in total. Candidate P has more experience and, if hired, would be paid 50 percent more per hour than candidate Q would be paid. Candidate Q, if hired, would require 10 hours more than candidate P to do the job. Candidate P’s hourly wage is how many dollars greater than candidate Q’s hourly wage? Choose the correct choice from the following answers.
A) $ 9 B) $ 15 C) $ 18 D) $ 21 E) $ 27 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">10 / (1/2)</gadget>
<output>20</output>
<gadget id="calculator">540 / 20</gadget>
<output>27</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">540 / 30</gadget>
<output>18</output>
<gadget id="calculator">27 - 18</gadget>
<output>9</output>
<result>A</result> | A | 9 | P and Q are the only two applicants qualified for a short-term research project that pays 540 dollars in total. Candidate P has more experience and, if hired, would be paid 50 percent more per hour than candidate Q would be paid. Candidate Q, if hired, would require 10 hours more than candidate P to do the job. Candidate P’s hourly wage is how many dollars greater than candidate Q’s hourly wage? | {
"A": "$ 9",
"B": "$ 15",
"C": "$ 18",
"D": "$ 21",
"E": "$ 27"
} | subtract(divide(540, divide(10, subtract(divide(const_3, const_2), const_1))), divide(540, add(divide(10, subtract(divide(const_3, const_2), const_1)), 10))) | divide(const_3,const_2)|subtract(#0,const_1)|divide(n2,#1)|add(n2,#2)|divide(n0,#2)|divide(n0,#3)|subtract(#4,#5)| | "let q ' s hourly wage be x , then p ' s hourly wage is 1.5 x let t be the number of hours that q needs , then p needs t - 10 hours to do the job . since they both are paid an equal total amount of $ 540 : x * t = 1.5 x * ( t - 10 ) t = 30 hours and q ' s hourly wage is 540 / 30 = $ 18 p ' s hourly wage is 540 / ( t - 10 ) = $ 27 which is $ 9 per hour more . the answer is a ." | general |
math_qa__ATPngmbXoR0Ocib3 | The average of the marks of 12 students in a class is 50. If the marks of each student are doubled, find the new average?
Options: A) 160 B) 120 C) 100 D) 150 E) 170 | <gadget id="calculator">50 * 2</gadget>
<output>100</output>
<result>C</result> | C | 100 | The average of the marks of 12 students in a class is 50. If the marks of each student are doubled, find the new average? | {
"A": "160",
"B": "120",
"C": "100",
"D": "150",
"E": "170"
} | multiply(50, const_2) | multiply(n1,const_2)| | "sum of the marks for the 12 students = 12 * 50 = 600 . the marks of each student are doubled , the sum also will be doubled . the new sum = 600 * 2 = 1200 . so , the new average = 1200 / 12 = 100 . answer : c" | general |
math_qa__rRTbHw8ASn1li4Va | If 75 percent of a class answered the first question on a certain test correctly, 25 percent answered the second question on the test correctly, and 20 percent answered neither of the questions correctly, what percent answered both correctly?
Choose the correct choice.
A) 10 %
B) 20 %
C) 30 %
D) 50 %
E) 65 % | <gadget id="calculator">75 + 25</gadget>
<output>100</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 - 100</gadget>
<output>20</output>
<result>B</result> | B | 20 | If 75 percent of a class answered the first question on a certain test correctly, 25 percent answered the second question on the test correctly, and 20 percent answered neither of the questions correctly, what percent answered both correctly? | {
"A": "10 %",
"B": "20 %",
"C": "30 %",
"D": "50 %",
"E": "65 %"
} | subtract(add(add(75, 25), 20), const_100) | add(n0,n1)|add(n2,#0)|subtract(#1,const_100)| | "{ total } = { first } + { second } - { both } + { neither } 100 % = 75 % + 25 % - { both } + 20 % - - > { both } = 20 % . answer : b ." | other |
math_qa__k67NPUBelvNcBMJH | Pipe A can fill a tank in 6 hours. Due to a leak at the bottom, it takes 8 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
Choose the correct choice from the following choices: A) 13 B) 24 C) 18 D) 19 E) 12 | <gadget id="calculator">8 * 6</gadget>
<output>48</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<result>B</result> | B | 24 | Pipe A can fill a tank in 6 hours. Due to a leak at the bottom, it takes 8 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank? | {
"A": "13",
"B": "24",
"C": "18",
"D": "19",
"E": "12"
} | divide(multiply(8, 6), subtract(8, 6)) | multiply(n0,n1)|subtract(n1,n0)|divide(#0,#1)| | "let the leak can empty the full tank in x hours 1 / 6 - 1 / x = 1 / 8 = > 1 / x = 1 / 6 - 1 / 8 = ( 4 - 3 ) / 24 = 1 / 24 = > x = 24 . answer : b" | physics |
math_qa__yei7TWPt44sGUZb0 | If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: Choose the correct choice from the following: A) 11 / 122 B) 11 / 120 C) 11 / 121 D) 11 / 140 E) 11 / 111 | <gadget id="calculator">55 / 5</gadget>
<output>11</output>
<gadget id="calculator">11 / 120</gadget>
<output>11/120 = around 0.091667</output>
<result>B</result> | B | 0.091667 | If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: | {
"A": "11 / 122",
"B": "11 / 120",
"C": "11 / 121",
"D": "11 / 140",
"E": "11 / 111"
} | divide(divide(55, 5), 120) | divide(n0,n1)|divide(#0,n2) | explanation : let the numbers be a and b . then , a + b = 55 and ab = 5 x 120 = 600 . the required sum answer : b ) 11 / 120 | general |
math_qa__AUoF2YR0dSNplyfs | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8200. If his salary for the month of May is Rs.6500, find his salary for the month of January?
Select the correct option:
A) 2177
B) 2876
C) 4500
D) 5700
E) 6711 | <gadget id="calculator">8_000 * 4</gadget>
<output>32_000</output>
<gadget id="calculator">8_200 * 4</gadget>
<output>32_800</output>
<gadget id="calculator">32_800 - 6_500</gadget>
<output>26_300</output>
<gadget id="calculator">32_000 - 26_300</gadget>
<output>5_700</output>
<result>D</result> | D | 5,700 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8200. If his salary for the month of May is Rs.6500, find his salary for the month of January? | {
"A": "2177",
"B": "2876",
"C": "4500",
"D": "5700",
"E": "6711"
} | subtract(multiply(8000, const_4), subtract(multiply(8200, const_4), 6500)) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#1,n2)|subtract(#0,#2)| | "sum of the salaries of the person for the months of january , february , march and april = 4 * 8000 = 32000 - - - - ( 1 ) sum of the salaries of the person for the months of february , march , april and may = 4 * 8200 = 32800 - - - - ( 2 ) ( 2 ) - ( 1 ) i . e . may - jan = 800 salary of may is rs . 6500 salary of january = rs . 5700 . answer : d" | general |
math_qa__VYkg5tlrvGXy5ZdP | The average age of 15 students of a class is 15 years. Out of these, the average age of 5 students is 12 years and that of the other 9 students is 16 years. The age of the 15th student is? Choose the correct choice:
A) 11 years
B) 17 years
C) 21 years
D) 14 years
E) 12 years | <gadget id="calculator">15 * 15</gadget>
<output>225</output>
<gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">9 * 16</gadget>
<output>144</output>
<gadget id="calculator">60 + 144</gadget>
<output>204</output>
<gadget id="calculator">225 - 204</gadget>
<output>21</output>
<result>C</result> | C | 21 | The average age of 15 students of a class is 15 years. Out of these, the average age of 5 students is 12 years and that of the other 9 students is 16 years. The age of the 15th student is? | {
"A": "11 years",
"B": "17 years",
"C": "21 years",
"D": "14 years",
"E": "12 years"
} | subtract(multiply(15, 15), add(multiply(5, 12), multiply(9, 16))) | multiply(n0,n0)|multiply(n2,n3)|multiply(n4,n5)|add(#1,#2)|subtract(#0,#3)| | "age of the 15 th student = [ 15 * 15 - ( 12 * 5 + 16 * 9 ) ] = ( 225 - 204 ) = 21 years . answer : c" | general |
math_qa__wS77FonfhwHtY0Nk | The width of a rectangular hall is ½ of its length. If the area of the hall is 800 sq.m, what is the difference between its length and breadth? Select.
A) 8 m B) 10 m C) 12 m D) 20 m E) 17 m | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">800 / (1/2)</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 ** (1/2)</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<result>D</result> | D | 20 | The width of a rectangular hall is ½ of its length. If the area of the hall is 800 sq.m, what is the difference between its length and breadth? | {
"A": "8 m",
"B": "10 m",
"C": "12 m",
"D": "20 m",
"E": "17 m"
} | divide(sqrt(divide(800, divide(const_1, const_2))), const_2) | divide(const_1,const_2)|divide(n0,#0)|sqrt(#1)|divide(#2,const_2)| | "let the length of the hall be x m breadth of the hall = 1 x / 2 m area of the hall = length * breadth 800 = x * 1 x / 2 x ² = 1600 x = 40 difference between the length and breadth of the hall = x - 1 x / 2 = x / 2 = 40 / 2 = 20 m answer : d" | geometry |
math_qa__FAp4PSnNZq7udsFs | A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is. Choose the correct choice from the following answers
A) 30 km B) 60 km C) 80 km D) 20 km E) 40 km | <gadget id="calculator">100 * 40</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 / 40</gadget>
<output>100</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<result>E</result> | E | 40 | A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is. | {
"A": "30 km",
"B": "60 km",
"C": "80 km",
"D": "20 km",
"E": "40 km"
} | subtract(divide(multiply(const_100, 40), 40), multiply(divide(40, 2), const_3)) | divide(n1,n2)|multiply(n1,const_100)|divide(#1,n1)|multiply(#0,const_3)|subtract(#2,#3) | e 40 km let distance = x m usual rate = y kmph x / y – x / y + 3 = 40 / 60 hr 2 y ( y + 3 ) = 9 x - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - ( 1 ) x / y - 2 – x / y = 40 / 60 hr y ( y - 2 ) = 3 x - - - - - - - - - - - ( 2 ) divide 1 & 2 equations by solving we get x = 40 km | physics |
math_qa__TafnLs50omgisdsT | P is 50% more efficient than Q. P can complete a work in 25 days. If P and Q work together, how many days will it take to complete the same work? Answers
A) 11
B) 13
C) 15
D) 17
E) 19 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) + 1</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 25</gadget>
<output>75/2 = around 37.5</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(75/2) / (5/2)</gadget>
<output>15</output>
<result>C</result> | C | 15 | P is 50% more efficient than Q. P can complete a work in 25 days. If P and Q work together, how many days will it take to complete the same work? | {
"A": "11",
"B": "13",
"C": "15",
"D": "17",
"E": "19"
} | divide(multiply(add(divide(50, const_100), const_1), 25), add(add(divide(50, const_100), const_1), const_1)) | divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(n1,#1)|divide(#3,#2)| | "the work done by p in 1 day = 1 / 25 let work done by q in 1 day = q q × ( 150 / 100 ) = 1 / 25 q = 100 / ( 25 × 150 ) = 10 / ( 25 × 15 ) the work done by p and q in 1 day = 1 / 25 + 10 / ( 25 × 15 ) = 25 / ( 25 × 15 ) = 1 / 15 p and q together can do the work in 15 days . the answer is c ." | physics |
math_qa__sgw9PMqOIQwWu77d | A can do a piece of work in 4 hours . A and C together can do it in just 2 hours, while B and C together need 3 hours to finish the same work. B alone can complete the work in --- hours. Options: A) 65 B) 85 C) 48 D) 12 E) 25 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/2) - (1/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) - (1/4)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>D</result> | D | 12 | A can do a piece of work in 4 hours . A and C together can do it in just 2 hours, while B and C together need 3 hours to finish the same work. B alone can complete the work in --- hours. | {
"A": "65",
"B": "85",
"C": "48",
"D": "12",
"E": "25"
} | inverse(subtract(inverse(3), subtract(inverse(2), inverse(4)))) | inverse(n2)|inverse(n1)|inverse(n0)|subtract(#1,#2)|subtract(#0,#3)|inverse(#4) | explanation : work done by a in 1 hour = 1 / 4 work done by b and c in 1 hour = 1 / 3 work done by a and c in 1 hour = 1 / 2 work done by a , b and c in 1 hour = 1 / 4 + 1 / 3 = 7 / 12 work done by b in 1 hour = 7 / 12 – 1 / 2 = 1 / 12 = > b alone can complete the work in 12 hours answer : d | physics |
math_qa__gZMEBiz6NZtsONG9 | Beginning in Town A, Biker Bob rides his bike 12 miles west, 6 miles north, 4 miles east, and then 12 miles north, to Town B. How far apart are Town A and Town B? (Ignore the curvature of the earth.)
Choices.
A) 18.97 miles B) 20 miles C) 22 miles D) 23 miles E) 25 miles | <gadget id="calculator">6 + 12</gadget>
<output>18</output>
<gadget id="calculator">18 ** 2</gadget>
<output>324</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">324 + 16</gadget>
<output>340</output>
<gadget id="calculator">340 ** (1/2)</gadget>
<output>2*sqrt(85) = around 18.439089</output>
<result>A</result> | A | 18.97 | Beginning in Town A, Biker Bob rides his bike 12 miles west, 6 miles north, 4 miles east, and then 12 miles north, to Town B. How far apart are Town A and Town B? (Ignore the curvature of the earth.) | {
"A": "18.97 miles",
"B": "20 miles",
"C": "22 miles",
"D": "23 miles",
"E": "25 miles"
} | sqrt(add(power(add(6, 12), const_2), power(4, const_2))) | add(n1,n3)|power(n2,const_2)|power(#0,const_2)|add(#2,#1)|sqrt(#3)| | "using pythagoras we have one side i , e total distance traveled in north direction = 12 + 6 = 18 m other being the base ie distance traveled west - distance traveled eat = 12 - 6 = 6 m now this third side or the distance between town a and town b = 18 ^ 2 + 6 ^ 2 = sq root 360 = 18.97 mile answer : a" | physics |
math_qa__WszWNzPVAMLPgfFe | The average (arithmetic mean) of 16 students first quiz scores in a difficult English class is 60.5. When one student dropped the class, the average of the remaining scores increased to 64.0. What is the quiz score of the student who dropped the class?
Choose the correct choice from the following.
A) 8 B) 25 C) 40 D) 55 E) 70 | <gadget id="calculator">16 * 60.5</gadget>
<output>968</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<gadget id="calculator">15 * 64</gadget>
<output>960</output>
<gadget id="calculator">968 - 960</gadget>
<output>8</output>
<result>A</result> | A | 8 | The average (arithmetic mean) of 16 students first quiz scores in a difficult English class is 60.5. When one student dropped the class, the average of the remaining scores increased to 64.0. What is the quiz score of the student who dropped the class? | {
"A": "8",
"B": "25",
"C": "40",
"D": "55",
"E": "70"
} | subtract(multiply(16, 60.5), multiply(subtract(16, const_1), 64.0)) | multiply(n0,n1)|subtract(n0,const_1)|multiply(n2,#1)|subtract(#0,#2)| | "total score of 16 students is 16 * 60.50 = 968 total score of 15 students is 15 * 64 = 960 so , the score of the person who left is 8 ( 968 - 960 ) answer will be ( a" | general |
math_qa__eFdJN1QBcfc6VVHQ | median w of price of the car is 52000 . which could be the median of the other two . 35000 , 44000 , x , y , 57000 .
Choose the most appropriate option: A) 38000 B) 47000 C) 48000 D) 51000 E) 56000 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">57_000 - 1_000</gadget>
<output>56_000</output>
<result>E</result> | E | 56,000 | median w of price of the car is 52000 . which could be the median of the other two . 35000 , 44000 , x , y , 57000 . | {
"A": "38000",
"B": "47000",
"C": "48000",
"D": "51000",
"E": "56000"
} | subtract(57000, multiply(const_100, const_10)) | multiply(const_10,const_100)|subtract(n3,#0) | median of the car is 52000 therefore 52000 is the middle number . assuming y > = x , x will have to be the median value i . e . 52000 . therefore the remaining value would have to be between 52000 and 57000 inclusive . the only answer choice that fits is w = 56000 . e | general |
math_qa__req0Aij2a3My7Bsr | each man in a gang of 100 investors has investments ineither equities or securities or both. Exactly 2525 of the investors in equities haveinvestments in securities, exactly 4040 of the investorsin securities have investments inequities. How many have investmentsin equities? Choose the correct choice from the following answers: A) 70 B) 80 C) 90 D) 100 E) 120 | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(2/5) / (1/4)</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">1 + (8/5)</gadget>
<output>13/5 = around 2.6</output>
<gadget id="calculator">(13/5) - (2/5)</gadget>
<output>11/5 = around 2.2</output>
<gadget id="calculator">110 / (11/5)</gadget>
<output>50</output>
<gadget id="calculator">50 * (8/5)</gadget>
<output>80</output>
<result>B</result> | B | 80 | each man in a gang of 100 investors has investments ineither equities or securities or both. Exactly 2525 of the investors in equities haveinvestments in securities, exactly 4040 of the investorsin securities have investments inequities. How many have investmentsin equities? | {
"A": "70",
"B": "80",
"C": "90",
"D": "100",
"E": "120"
} | multiply(divide(add(100, const_10), subtract(add(const_1, divide(divide(multiply(const_4, const_10), const_100), divide(multiply(add(const_2, const_3), add(const_2, const_3)), const_100))), divide(multiply(const_4, const_10), const_100))), divide(divide(multiply(const_4, const_10), const_100), divide(multiply(add(const_2, const_3), add(const_2, const_3)), const_100))) | add(n0,const_10)|add(const_2,const_3)|multiply(const_10,const_4)|divide(#2,const_100)|multiply(#1,#1)|divide(#4,const_100)|divide(#3,#5)|add(#6,const_1)|subtract(#7,#3)|divide(#0,#8)|multiply(#9,#6) | the investors can be categorized into three groups : ( 1 ) those who have investments in equities only . ( 2 ) those who have investments in securities only . ( 3 ) those who have investments in both equities and securities . let xx , yy , and zz denote the number of people in the respective categories . since the total number of investors is 110 , we have x + y + z = 110 x + y + z = 110 - - - - - - - - - - - - - ( 1 ) also , the number of people with investments in equities is x + zx + z and the number of people with investments in securities is y + zy + z . since exactly 25 % 25 % of the investors in equities have investments in securities , we have the equation 25100 × ( x + z ) = z 25100 × ( x + z ) = z 25100 × x = 25100 × z 25100 × x = 25100 × z x = 3 zx = 3 z - - - - - - - - - - - - - - - - - - - ( 2 ) since exactly 40 % 40 % of the investors in securities have investments in equities , we have the equation 40100 × ( y + z ) = z 40100 × ( y + z ) = z ( y + z ) = 5 z 2 ( y + z ) = 5 z 2 y = 3 z 2 y = 3 z 2 substituting equations ( 2 ) and ( 3 ) into equation ( 1 ) yields 3 z + 3 z 2 + z = 1103 z + 3 z 2 + z = 110 11 z 2 = 11011 z 2 = 110 z = 110 × 211 = 20 z = 110 × 211 = 20 hence , the number of people with investments in equities is : x + z = 3 z + z = 3 × 20 + 20 = 60 + 20 x + z = 3 z + z = 3 × 20 + 20 = 60 + 20 = 80 b | other |
math_qa__N8e34bEVwQFzrJr1 | A certain country had a total annual expenditure of $9.6 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure? Pick
A) $ 500
B) $ 1,000
C) $ 2,000
D) $ 3,000
E) $ 4,000 | <gadget id="calculator">10 ** 11</gadget>
<output>100_000_000_000</output>
<gadget id="calculator">9.6 * 100_000_000_000</gadget>
<output>960_000_000_000</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">10 ** 6</gadget>
<output>1_000_000</output>
<gadget id="calculator">240 * 1_000_000</gadget>
<output>240_000_000</output>
<gadget id="calculator">960_000_000_000 / 240_000_000</gadget>
<output>4_000</output>
<result>E</result> | E | 4,000 | A certain country had a total annual expenditure of $9.6 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure? | {
"A": "$ 500",
"B": "$ 1,000",
"C": "$ 2,000",
"D": "$ 3,000",
"E": "$ 4,000"
} | divide(multiply(9.6, power(10, 11)), multiply(240, power(10, add(const_4, const_2)))) | add(const_2,const_4)|power(n1,n2)|multiply(n0,#1)|power(n1,#0)|multiply(n3,#3)|divide(#2,#4) | total expenditure / population = per capita expenditure hence , ( 9,6 x 10 ^ 11 ) / 240 000 000 = ( 9,6 x 10 ^ 11 ) / ( 2,4 x 10 ^ 8 ) = 4 x 10 ^ ( 11 - 8 ) = 4 x 10 ^ 3 = 4000 . answer is e . | general |
math_qa__kcmEfQSYzFEQpmBa | In the manufacture of a certain product, 6 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale? Answers.
A) 0.125 % B) 0.24 % C) 0.8 % D) 1.25 % E) 2.0 % | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">6 * (1/25)</gadget>
<output>6/25 = around 0.24</output>
<result>B</result> | B | 0.24 | In the manufacture of a certain product, 6 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale? | {
"A": "0.125 %",
"B": "0.24 %",
"C": "0.8 %",
"D": "1.25 %",
"E": "2.0 %"
} | multiply(6, divide(4, const_100)) | divide(n1,const_100)|multiply(n0,#0)| | "percent of defective produced = 6 % percent of the defective units that are shipped for sale = 4 % percent of units produced are defective units that are shipped for sale = ( 4 / 100 ) * ( 6 / 100 ) * 100 % = ( 24 / 10000 ) * 100 % = ( 24 / 100 ) % = . 24 % answer b" | gain |
math_qa__rdAIHt7zxXuvfmUX | The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.10 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
Choose the correct choice from the following:
A) 399
B) 272
C) 732.6
D) 277
E) 311 | <gadget id="calculator">3_136 ** (1/2)</gadget>
<output>56</output>
<gadget id="calculator">56 * 4</gadget>
<output>224</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">224 - 2</gadget>
<output>222</output>
<gadget id="calculator">222 * 1.1</gadget>
<output>244.2</output>
<gadget id="calculator">244.2 * 3</gadget>
<output>732.6</output>
<result>C</result> | C | 732.6 | The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.10 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost? | {
"A": "399",
"B": "272",
"C": "732.6",
"D": "277",
"E": "311"
} | multiply(multiply(subtract(multiply(sqrt(3136), const_4), multiply(const_2, 1)), 1.10), 3) | multiply(n3,const_2)|sqrt(n0)|multiply(#1,const_4)|subtract(#2,#0)|multiply(n2,#3)|multiply(#4,n1)| | "answer : option c explanation : a 2 = 3136 = > a = 56 56 * 4 * 3 = 672 â € “ 6 = 666 * 1.1 = 732.6 answer : c" | physics |
math_qa__1J7h5nyLzFZyzTsf | Car A runs at the speed of 65km/hr & reaches its destination in 8hr. Car B runs at the speed of 70 km/h & reaches its destination in 5h. What is the respective ratio of distances covered by Car A & Car B?
Choose the correct choice from the following options: A) 11 : 6 B) 52 : 35 C) 13 : 7 D) 15 : 6 E) 13 : 6 | <gadget id="calculator">65 * 8</gadget>
<output>520</output>
<gadget id="calculator">70 * 5</gadget>
<output>350</output>
<gadget id="calculator">520 / 350</gadget>
<output>52/35 = around 1.485714</output>
<result>B</result> | B | 1.485714 | Car A runs at the speed of 65km/hr & reaches its destination in 8hr. Car B runs at the speed of 70 km/h & reaches its destination in 5h. What is the respective ratio of distances covered by Car A & Car B? | {
"A": "11 : 6",
"B": "52 : 35",
"C": "13 : 7",
"D": "15 : 6",
"E": "13 : 6"
} | divide(multiply(65, 8), multiply(70, 5)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "sol . distance travelled by car a = 65 ã — 8 = 520 km distance travelled by car b = 70 ã — 5 = 350 km ratio = 520 / 350 = 52 : 35 b" | physics |
math_qa__mV44S8wbaWOyGtGF | Find the least number must be subtracted from 568219 so that remaining no.is divisible by 5? Answers:
A) 0
B) 1
C) 2
D) 3
E) 4 | <gadget id="calculator">568_219 / 5</gadget>
<output>568_219/5 = around 113_643.8</output>
<gadget id="calculator">floor(568_219/5)</gadget>
<output>113_643</output>
<gadget id="calculator">113_643 * 5</gadget>
<output>568_215</output>
<gadget id="calculator">568_219 - 568_215</gadget>
<output>4</output>
<result>E</result> | E | 4 | Find the least number must be subtracted from 568219 so that remaining no.is divisible by 5? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | subtract(568219, multiply(floor(divide(568219, 5)), 5)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)| | "on dividing 568219 by 5 we get the remainder 4 , so 4 should be subtracted e" | general |
math_qa__LaUQR3NeHO2RIz5a | If the cost price of 40 articles is equal to the selling price of 25 articles, what is the % profit or loss made by the merchant? Choose the correct choice from the following choices: A) 25 % loss B) 25 % profit C) 20 % loss D) 60 % profit E) 75 % profit | <gadget id="calculator">100 * 25</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 40</gadget>
<output>125/2 = around 62.5</output>
<gadget id="calculator">100 - (125/2)</gadget>
<output>75/2 = around 37.5</output>
<gadget id="calculator">(75/2) / (125/2)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">100 * (3/5)</gadget>
<output>60</output>
<result>D</result> | D | 60 | If the cost price of 40 articles is equal to the selling price of 25 articles, what is the % profit or loss made by the merchant? | {
"A": "25 % loss",
"B": "25 % profit",
"C": "20 % loss",
"D": "60 % profit",
"E": "75 % profit"
} | multiply(const_100, divide(subtract(const_100, divide(multiply(const_100, 25), 40)), divide(multiply(const_100, 25), 40))) | multiply(n1,const_100)|divide(#0,n0)|subtract(const_100,#1)|divide(#2,#1)|multiply(#3,const_100)| | "let the cost price of 1 article be $ 1 . therefore , cost price of 40 articles = 40 * 1 = $ 40 the selling price of 25 articles = cost price of 40 articles = $ 40 . now , we know the selling price of 25 articles . let us find the cost price of 25 articles . cost price of 25 articles = 25 * 1 = $ 25 . therefore , profit made on sale of 25 articles = selling price of 25 articles - cost price of 25 articles = 40 - 25 = $ 15 . as the profit is in the positive , the merchant has made a profit of $ 15 . therefore , % loss = loss / cp * 100 % loss = 15 / 25 * 100 = 60 % profit . d" | gain |
math_qa__4DFyyOwNbqvVmzZv | The numbers 272738 and 232342, when divided by n, a two digit number, leave a remainder of 13 and 17 respectively. Find the sum of the digits of n?
Choose the correct option.
A) 7 B) 8 C) 9 D) 4 E) 5 | <gadget id="calculator">272_738 - 13</gadget>
<output>272_725</output>
<gadget id="calculator">232_342 - 17</gadget>
<output>232_325</output>
<gadget id="calculator">gcd(272_725, 232_325)</gadget>
<output>25</output>
<gadget id="calculator">25 % 10</gadget>
<output>5</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<result>A</result> | A | 7 | The numbers 272738 and 232342, when divided by n, a two digit number, leave a remainder of 13 and 17 respectively. Find the sum of the digits of n? | {
"A": "7",
"B": "8",
"C": "9",
"D": "4",
"E": "5"
} | add(reminder(gcd(subtract(272738, 13), subtract(232342, 17)), const_10), const_2) | subtract(n0,n2)|subtract(n1,n3)|gcd(#0,#1)|reminder(#2,const_10)|add(#3,const_2) | from the given information , ( 272738 - 13 , 232342 - 17 ) are exactly divisible by that two digit number . we have to find the hcf of the given numbers 272725 , 232325 . hcf = 25 . so sum of the digits = 7 . answer : a | general |
math_qa__Ul4552HZL3xDXw6G | Find the area of a parallelogram with base 36 cm and height 18 cm? Choices:
A) 287 cm 2 B) 887 cm 2 C) 384 cm 2 D) 268 cm 2 E) 648 cm 2 | <gadget id="calculator">36 * 18</gadget>
<output>648</output>
<result>E</result> | E | 648 | Find the area of a parallelogram with base 36 cm and height 18 cm? | {
"A": "287 cm 2",
"B": "887 cm 2",
"C": "384 cm 2",
"D": "268 cm 2",
"E": "648 cm 2"
} | multiply(36, 18) | multiply(n0,n1)| | "area of a parallelogram = base * height = 36 * 18 = 648 cm 2 answer : e" | geometry |
math_qa__EqzgvK343yBBB31I | If the number is divided by 3, it reduced by 42. The number is
Select:
A) 51
B) 63
C) 45
D) 40
E) 36 | <gadget id="calculator">42 * 3</gadget>
<output>126</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">126 / 2</gadget>
<output>63</output>
<result>B</result> | B | 63 | If the number is divided by 3, it reduced by 42. The number is | {
"A": "51",
"B": "63",
"C": "45",
"D": "40",
"E": "36"
} | divide(multiply(42, 3), subtract(3, const_1)) | multiply(n0,n1)|subtract(n0,const_1)|divide(#0,#1)| | "explanation : let the number be x . then , x - ( x / 3 ) = 42 = > 2 x / 3 = 42 = > x = 63 answer : option b" | general |
math_qa__B4Vfk0vhlSUXiVpm | When y is divided by 288, the remainder is 45. What is the remainder when the same y is divided by 24? Choices
A) 20 B) 21 C) 23 D) 25 E) 26 | <gadget id="calculator">45 % 24</gadget>
<output>21</output>
<result>B</result> | B | 21 | When y is divided by 288, the remainder is 45. What is the remainder when the same y is divided by 24? | {
"A": "20",
"B": "21",
"C": "23",
"D": "25",
"E": "26"
} | reminder(45, 24) | reminder(n1,n2)| | "y = 288 * a + 45 = ( 24 * 12 ) * a + 24 + 21 the answer is b ." | general |
math_qa__JyIvwPhibinKtRFY | What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 6?
Choose the correct choice:
A) 82,650
B) 64,850
C) 64,749
D) 49,700
E) 56,720 | <gadget id="calculator">1_000 - 3</gadget>
<output>997</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">90 + 9</gadget>
<output>99</output>
<gadget id="calculator">99 + 3</gadget>
<output>102</output>
<gadget id="calculator">997 - 102</gadget>
<output>895</output>
<gadget id="calculator">895 / 6</gadget>
<output>895/6 = around 149.166667</output>
<gadget id="calculator">(895/6) + 1</gadget>
<output>901/6 = around 150.166667</output>
<gadget id="calculator">(901/6) / 2</gadget>
<output>901/12 = around 75.083333</output>
<gadget id="calculator">997 + 102</gadget>
<output>1_099</output>
<gadget id="calculator">(901/12) * 1_099</gadget>
<output>990_199/12 = around 82_516.583333</output>
<result>A</result> | A | 82,650 | What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 6? | {
"A": "82,650",
"B": "64,850",
"C": "64,749",
"D": "49,700",
"E": "56,720"
} | multiply(divide(add(divide(subtract(subtract(const_1000, 3), add(add(multiply(multiply(3, 3), const_10), multiply(3, 3)), 3)), 6), const_1), 2), add(subtract(const_1000, 3), add(add(multiply(multiply(3, 3), const_10), multiply(3, 3)), 3))) | multiply(n0,n0)|subtract(const_1000,n0)|multiply(#0,const_10)|add(#2,#0)|add(n0,#3)|add(#4,#1)|subtract(#1,#4)|divide(#6,n2)|add(#7,const_1)|divide(#8,n1)|multiply(#5,#9)| | "find the number , upon sum of 3 digits of a number gives a reminder 2 when it is divided by 6 seeing the options after dividing an finding the reminder of 2 my answer was a" | general |
math_qa__EUVEi1qQx5b0Lh5C | How many bricks, each measuring 50 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm? Pick.
A) 6400 B) 2400 C) 5500 D) 7400 E) 3200 | <gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">800 * 600</gadget>
<output>480_000</output>
<gadget id="calculator">480_000 * 22.5</gadget>
<output>10_800_000</output>
<gadget id="calculator">50 * 11.25</gadget>
<output>562.5</output>
<gadget id="calculator">562.5 * 6</gadget>
<output>3_375</output>
<gadget id="calculator">10_800_000 / 3_375</gadget>
<output>3_200</output>
<result>E</result> | E | 3,200 | How many bricks, each measuring 50 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm? | {
"A": "6400",
"B": "2400",
"C": "5500",
"D": "7400",
"E": "3200"
} | divide(multiply(multiply(multiply(8, const_100), multiply(6, const_100)), 22.5), multiply(multiply(50, 11.25), 6)) | multiply(n3,const_100)|multiply(n4,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(n2,#2)|multiply(n5,#3)|divide(#5,#4)| | "number of bricks = volume of the wall / volume of 1 brick = ( 800 x 600 x 22.5 ) / ( 50 x 11.25 x 6 ) = 3200 answer : e" | physics |
math_qa__hdxezYjGGldDkMa6 | If Teena is driving at 55 miles per hour and is currently 7.5 miles behind Yoe, who is driving at 40 miles per hour in the same direction then in how many minutes will Teena be 15 miles ahead of Yoe?
Choose the correct choice from the following
A) 15
B) 60
C) 75
D) 90
E) 105 | <gadget id="calculator">55 - 40</gadget>
<output>15</output>
<gadget id="calculator">15 + 7.5</gadget>
<output>22.5</output>
<gadget id="calculator">22.5 / 15</gadget>
<output>1.5</output>
<gadget id="calculator">1.5 * 60</gadget>
<output>90</output>
<result>D</result> | D | 90 | If Teena is driving at 55 miles per hour and is currently 7.5 miles behind Yoe, who is driving at 40 miles per hour in the same direction then in how many minutes will Teena be 15 miles ahead of Yoe? | {
"A": "15",
"B": "60",
"C": "75",
"D": "90",
"E": "105"
} | multiply(divide(add(subtract(55, 40), 7.5), subtract(55, 40)), const_60) | subtract(n0,n2)|add(n1,#0)|divide(#1,#0)|multiply(#2,const_60)| | "this type of questions should be solved without any complex calculations as these questions become imperative in gaining that extra 30 - 40 seconds for a difficult one . teena covers 55 miles in 60 mins . yoe covers 40 miles in 60 mins so teena gains 15 miles every 60 mins teena need to cover 7.5 + 15 miles . teena can cover 7.5 miles in 30 mins teena will cover 15 miles in 60 mins so answer 30 + 60 = 90 mins . d" | physics |
math_qa__CrWlx7hIfUwUuSpr | At a certain zoo, the ratio of lions to penguins is 3 to 11. If there are 82 more penguins than lions at the zoo, how many lions are there? Choose the correct option: A) 24 B) 30 C) 48 D) 72 E) 132 | <gadget id="calculator">11 - 3</gadget>
<output>8</output>
<gadget id="calculator">82 / 8</gadget>
<output>41/4 = around 10.25</output>
<gadget id="calculator">(41/4) * 3</gadget>
<output>123/4 = around 30.75</output>
<gadget id="calculator">floor(123/4)</gadget>
<output>30</output>
<result>B</result> | B | 30 | At a certain zoo, the ratio of lions to penguins is 3 to 11. If there are 82 more penguins than lions at the zoo, how many lions are there? | {
"A": "24",
"B": "30",
"C": "48",
"D": "72",
"E": "132"
} | floor(multiply(divide(82, subtract(11, 3)), 3)) | subtract(n1,n0)|divide(n2,#0)|multiply(n0,#1)|floor(#2) | 3 / 11 = x / x + 82 3 * 82 = 8 x x = 30 b . 30 | other |
math_qa__xkisQhjeiy4pkc4O | A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed Q of the train. Choose the correct choice:
A) 45
B) 33
C) 48
D) 55
E) 61 | <gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">96 / 3</gadget>
<output>32</output>
<gadget id="calculator">32 - 24</gadget>
<output>8</output>
<gadget id="calculator">35 - 25</gadget>
<output>10</output>
<gadget id="calculator">10 + 50</gadget>
<output>60</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">8 * 6</gadget>
<output>48</output>
<result>C</result> | C | 48 | A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed Q of the train. | {
"A": "45",
"B": "33",
"C": "48",
"D": "55",
"E": "61"
} | multiply(subtract(divide(multiply(24, 4), const_3), 24), divide(add(subtract(35, 25), 50), subtract(35, 25))) | multiply(n2,n4)|subtract(n3,n5)|add(n0,#1)|divide(#0,const_3)|divide(#2,#1)|subtract(#3,n4)|multiply(#4,#5) | let y be the balance distance to be covered and x be the former speed . a train after traveling for 50 km meets with an accident and then proceeds at 3 / 4 of its former speed and arrives at its destination 35 minutes late so , y / ( 3 x / 4 ) - y / x = 35 / 60 4 y / 3 x - y / x = 7 / 12 y / x ( 4 / 3 - 1 ) = 7 / 12 y / x * 1 / 3 = 7 / 12 y / x = 7 / 4 4 y - 7 x = 0 . . . . . . . . 1 had the accident occurred 24 km farther , it would have reached the destination only 25 minutes late so , ( y - 24 ) / ( 3 x / 4 ) - ( y - 24 ) / x = 25 / 60 4 ( y - 24 ) / 3 x - ( y - 24 ) / x = 5 / 12 ( y - 24 ) / x ( 4 / 3 - 1 ) = 5 / 12 ( y - 24 ) / x * 1 / 3 = 5 / 12 ( y - 24 ) * 12 = 3 x * 5 ( y - 24 ) * 4 = 5 x 4 y - 5 x = 96 . . . . . . . 2 eq 2 - eq 1 2 x = 96 x = 48 = q ans = c | physics |
math_qa__e6EF6gnYhPhwMEW4 | If 15% of 30% of 50% of a number is 117, then what is the number? Choose the correct answer
A) 5200 B) 3050 C) 4400 D) 4500 E) none of these | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(1/2) * (3/10)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * (3/20)</gadget>
<output>9/400 = around 0.0225</output>
<gadget id="calculator">117 / (9/400)</gadget>
<output>5_200</output>
<result>A</result> | A | 5,200 | If 15% of 30% of 50% of a number is 117, then what is the number? | {
"A": "5200",
"B": "3050",
"C": "4400",
"D": "4500",
"E": "none of these"
} | divide(117, multiply(multiply(divide(50, const_100), divide(30, const_100)), divide(15, const_100))) | divide(n0,const_100)|divide(n2,const_100)|divide(n1,const_100)|multiply(#1,#2)|multiply(#0,#3)|divide(n3,#4)| | "let the number be a given , 15 / 100 * 30 / 100 * 50 / 100 * a = 117 = > 3 / 20 * 3 / 10 * 1 / 2 * a = 117 = > a = 10 * 20 * 10 * 2 = 5200 . answer : a" | gain |
math_qa__LCmSDxKm0Dt6HYSm | Machine A produces 100 parts twice as fast as Machine B does. Machine B produces 100 parts in 20 minutes. If each machine produces parts at a constant rate, how many parts does Machine A produce in 8 minutes? Choose the correct answer:
A) 100 B) 90 C) 80 D) 30 E) 50 | <gadget id="calculator">100 / 20</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 8</gadget>
<output>80</output>
<result>C</result> | C | 80 | Machine A produces 100 parts twice as fast as Machine B does. Machine B produces 100 parts in 20 minutes. If each machine produces parts at a constant rate, how many parts does Machine A produce in 8 minutes? | {
"A": "100",
"B": "90",
"C": "80",
"D": "30",
"E": "50"
} | multiply(multiply(divide(100, 20), const_2), 8) | divide(n0,n2)|multiply(#0,const_2)|multiply(n3,#1)| | "machine b produces 100 part in 20 minutes . machine a produces 100 parts twice as fast as b , so machine a produces 100 parts in 20 / 2 = 10 minutes . now , machine a produces 100 parts in 10 minutes which is 100 / 10 = 10 parts / minute . 10 parts x a total of 8 minutes = 80 c" | gain |
math_qa__BP1I3oyunDp7M6lC | Cereal A is 10% sugar by weight, whereas healthier but less delicious Cereal B is 4% sugar by weight. To make a delicious and healthy mixture that is 6% sugar, what should be the ratio of Cereal A to Cereal B, by weight? Choose the correct option: A) 2 : 9 B) 2 : 7 C) 1 : 6 D) 1 : 4 E) 1 : 2 | <gadget id="calculator">6 - 4</gadget>
<output>2</output>
<gadget id="calculator">10 - 6</gadget>
<output>4</output>
<gadget id="calculator">2 / 4</gadget>
<output>1/2 = around 0.5</output>
<result>E</result> | E | 0.5 | Cereal A is 10% sugar by weight, whereas healthier but less delicious Cereal B is 4% sugar by weight. To make a delicious and healthy mixture that is 6% sugar, what should be the ratio of Cereal A to Cereal B, by weight? | {
"A": "2 : 9",
"B": "2 : 7",
"C": "1 : 6",
"D": "1 : 4",
"E": "1 : 2"
} | divide(subtract(6, 4), subtract(10, 6)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "ratio of a / ratio of b = ( average wt of mixture - wt of b ) / ( wt of a - average wt of mixture ) = > ratio of a / ratio of b = ( 6 - 4 ) / ( 10 - 6 ) = 2 / 4 = 1 / 2 so they should be mixed in the ratio 1 : 2 answer - e" | general |
math_qa__pWfID2FEEcD4TVoE | how many numbers between 190 and 580 are divisible by 45 and 6 ?
Pick:
A) 6
B) 7
C) 8
D) 9
E) 10 | <gadget id="calculator">580 - 190</gadget>
<output>390</output>
<gadget id="calculator">390 / 45</gadget>
<output>26/3 = around 8.666667</output>
<gadget id="calculator">floor(26/3)</gadget>
<output>8</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<result>A</result> | A | 6 | how many numbers between 190 and 580 are divisible by 45 and 6 ? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | subtract(floor(divide(subtract(580, 190), 45)), const_2) | subtract(n1,n0)|divide(#0,n2)|floor(#1)|subtract(#2,const_2) | every such number must be divisible by l . c . m of 4 , 5,6 i . e , 60 . such numbers are 240,300 , 360,420 , 480,540 . clearly , there are 6 such numbers answer : a | general |
math_qa__dDJ34rMujsiYkdhI | If the cost price of 50 articles is equal to the selling price of 28 articles, then the gain or loss percent is? Choose the correct answer
A) 22 B) 65 C) 78.57 D) 33 E) 25 | <gadget id="calculator">100 * 28</gadget>
<output>2_800</output>
<gadget id="calculator">2_800 / 50</gadget>
<output>56</output>
<gadget id="calculator">100 - 56</gadget>
<output>44</output>
<gadget id="calculator">44 / 56</gadget>
<output>11/14 = around 0.785714</output>
<gadget id="calculator">100 * (11/14)</gadget>
<output>550/7 = around 78.571429</output>
<result>C</result> | C | 78.57 | If the cost price of 50 articles is equal to the selling price of 28 articles, then the gain or loss percent is? | {
"A": "22",
"B": "65",
"C": "78.57",
"D": "33",
"E": "25"
} | multiply(const_100, divide(subtract(const_100, divide(multiply(const_100, 28), 50)), divide(multiply(const_100, 28), 50))) | multiply(n1,const_100)|divide(#0,n0)|subtract(const_100,#1)|divide(#2,#1)|multiply(#3,const_100)| | "given that , cost price of 50 article is equal to selling price of 28 articles . let cost price of one article = rs . 1 selling price of 28 articles = rs . 50 but cost price of 28 articles = rs . 28 therefore , the trader made profit . \ percentage of profit = 22 / 28 * 100 = 78.57 % answer : c" | gain |
math_qa__96xNewlYsQy6ScNg | Out of 420 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ? Select the correct option.
A) 120 B) 150 C) 130 D) 180 E) 220 | <gadget id="calculator">175 + 325</gadget>
<output>500</output>
<gadget id="calculator">420 - 50</gadget>
<output>370</output>
<gadget id="calculator">500 - 370</gadget>
<output>130</output>
<result>C</result> | C | 130 | Out of 420 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ? | {
"A": "120",
"B": "150",
"C": "130",
"D": "180",
"E": "220"
} | subtract(add(175, 325), subtract(420, 50)) | add(n1,n2)|subtract(n0,n3)|subtract(#0,#1)| | "n ( a ) = 325 , n ( b ) = 175 , n ( aub ) = 420 - 50 = 370 . required number = n ( anb ) = n ( a ) + n ( b ) - n ( aub ) = 325 + 175 - 370 = 130 . answer is c" | other |
math_qa__eXiW2HonpCfu261H | In a certain company, the ratio of the number of managers to the number of non-managers in any department must always be greater than 5 : 24. In the company, what is the maximum number of non-managers in a department that has 8 managers: Choose the correct choice from the following answers.
A) 36 B) 37 C) 38 D) 39 E) 40 | <gadget id="calculator">24 * 8</gadget>
<output>192</output>
<gadget id="calculator">192 / 5</gadget>
<output>192/5 = around 38.4</output>
<gadget id="calculator">floor(192/5)</gadget>
<output>38</output>
<result>C</result> | C | 38 | In a certain company, the ratio of the number of managers to the number of non-managers in any department must always be greater than 5 : 24. In the company, what is the maximum number of non-managers in a department that has 8 managers: | {
"A": "36",
"B": "37",
"C": "38",
"D": "39",
"E": "40"
} | floor(divide(multiply(24, 8), 5)) | multiply(n1,n2)|divide(#0,n0)|floor(#1)| | "m / nm > 5 x / 24 x m = 8 8 / nm > 5 x / 24 x 8 / nm - 5 x / 24 x > 0 ( 192 x - 5 x * nm ) / ( 24 x * nm ) > 0 192 x - 5 x * nm > 0 5 x * nm < 192 x nm < 192 x / 5 x nm < 38.4 maximum number of non managers = 38 answer : c" | general |
math_qa__Ru99IOVoAWTVh2ry | The average runs scored by a batsman in 15 matches is 30. In the next 20 matches the batsman scored an average of 15 runs. Find his average in all the 30 matches? Pick.
A) 31.56 B) 25.65 C) 21.43 D) 28.36 E) 27.96 | <gadget id="calculator">30 * 15</gadget>
<output>450</output>
<gadget id="calculator">15 * 20</gadget>
<output>300</output>
<gadget id="calculator">450 + 300</gadget>
<output>750</output>
<gadget id="calculator">15 + 20</gadget>
<output>35</output>
<gadget id="calculator">750 / 35</gadget>
<output>150/7 = around 21.428571</output>
<result>C</result> | C | 21.43 | The average runs scored by a batsman in 15 matches is 30. In the next 20 matches the batsman scored an average of 15 runs. Find his average in all the 30 matches? | {
"A": "31.56",
"B": "25.65",
"C": "21.43",
"D": "28.36",
"E": "27.96"
} | divide(add(multiply(30, 15), multiply(15, 20)), add(15, 20)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | total score of the batsman in 15 matches = 450 . total score of the batsman in the next 20 matches = 300 . total score of the batsman in the 35 matches = 750 . average score of the batsman = 750 / 35 = 21.43 . answer : c | general |
math_qa__wbnFAuURMn2fkhO5 | a goes to place x and b goes to place y.
after a travelled 180 km more than b they together meet at a point between xy. they together had their lunch for half an hour. after that a took 2 hrs to reach x and b took 4.5 hrs to reach y. find distance between x and y? Choose the correct choice from the following answers: A) 900 km B) 540 km C) 720 km D) 820 km E) 920 km | <gadget id="calculator">2 * 180</gadget>
<output>360</output>
<gadget id="calculator">360 * 2</gadget>
<output>720</output>
<gadget id="calculator">720 + 180</gadget>
<output>900</output>
<result>A</result> | A | 900 | a goes to place x and b goes to place y.
after a travelled 180 km more than b they together meet at a point between xy. they together had their lunch for half an hour. after that a took 2 hrs to reach x and b took 4.5 hrs to reach y. find distance between x and y? | {
"A": "900 km",
"B": "540 km",
"C": "720 km",
"D": "820 km",
"E": "920 km"
} | add(multiply(multiply(2, 180), 2), 180) | multiply(n0,n1)|multiply(n1,#0)|add(n0,#1) | let speed of a be - - - - - - - sa let speed of b be - - - - - - - - sb let the distance covered by b while going to position xy be - - - - - - - - - - - x so distance covered by a in same time while going to xy is - - - - - - - - - - 180 + x ( it ' s given in the question ) so total distance b / w x and y is = x + ( x + 180 ) while going to position xy : - time taken by a = time taken by b ( x + 180 ) / sa = x / sb sa / sb = ( x + 180 ) / x - - - - - - - - - - - - - - - - - - - - - 1 after lunch : - a . c . t ( according to question ) sa = x / 2 sb = ( x + 180 ) / 4.5 dividing sa / sb = ( x * 4.5 ) / ( ( x + 180 ) * 2 ) - - - - - - - - - - - - - - - - - - - - 2 equating equations 1 and 2 9 / 4 = ( x + 180 ) ^ 2 / x ^ 2 now taking square root on both sides we get 3 / 2 = ( x + 180 ) / x x = 360 therefore distance between x and y = x + ( x + 180 ) = 900 km answer : a | physics |
math_qa__flnnL0zwiQEbKRM4 | A train 140m long is running at 60kmph. In how much time will it pass a platform 260m long? Choose the correct answer.
A) 15 seconds B) 24 seconds C) 28 seconds D) 30 seconds E) 35 seconds | <gadget id="calculator">140 + 260</gadget>
<output>400</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">400 / (50/3)</gadget>
<output>24</output>
<result>B</result> | B | 24 | A train 140m long is running at 60kmph. In how much time will it pass a platform 260m long? | {
"A": "15 seconds",
"B": "24 seconds",
"C": "28 seconds",
"D": "30 seconds",
"E": "35 seconds"
} | divide(add(140, 260), multiply(60, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "distance travelled = 140 + 260 m = 400 m speed = 60 * 5 / 8 = 50 / 3 m time = 400 * 3 / 50 = 24 second answer : b" | physics |
math_qa__7sN8jMSlMeq3rGzp | With both valves open, the pool will be filled with water in 48 minutes. The first valve alone would fill the pool in 2 hours. If the second valve emits 50 cubic meters of water more than the first every minute, then what is the capacity R of the pool? Choices.
A) 9000 cubic meters B) 10500 cubic meters C) 11750 cubic meters D) 12000 cubic meters E) 12500 cubic meters | <gadget id="calculator">48 / 60</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">(4/5) * 5</gadget>
<output>4</output>
<gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">50 * 240</gadget>
<output>12_000</output>
<result>D</result> | D | 12,000 | With both valves open, the pool will be filled with water in 48 minutes. The first valve alone would fill the pool in 2 hours. If the second valve emits 50 cubic meters of water more than the first every minute, then what is the capacity R of the pool? | {
"A": "9000 cubic meters",
"B": "10500 cubic meters",
"C": "11750 cubic meters",
"D": "12000 cubic meters",
"E": "12500 cubic meters"
} | multiply(50, multiply(const_60, multiply(divide(48, const_60), add(const_4, const_1)))) | add(const_1,const_4)|divide(n0,const_60)|multiply(#0,#1)|multiply(#2,const_60)|multiply(n2,#3)| | "d . 12000 cubic meters . if both hte valves fill the pool in 48 minutes and valve 1 only fills in 120 minutes then valve 2 alone will fill the pool in ( 48 * 120 ) / ( 120 - 48 ) = 80 minutes . now , if valve 1 admits x cubic meter of water per minute then the capacity of pool will be 120 x and also 80 ( x + 50 ) . or , 120 x = 80 ( x + 50 ) . or x = 100 . hence , the capacity of pool = 120 x = 12000 cubic meters ." | physics |
math_qa__zdIeT204GDazkTqx | If the ratio of a to b is 2 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? Choose the correct answer.
A) 4 / 15 B) 1 / 3 C) 2 / 15 D) 4 / 5 E) 7 / 6 | <gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">2 / 15</gadget>
<output>2/15 = around 0.133333</output>
<result>C</result> | C | 0.133333 | If the ratio of a to b is 2 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? | {
"A": "4 / 15",
"B": "1 / 3",
"C": "2 / 15",
"D": "4 / 5",
"E": "7 / 6"
} | divide(multiply(2, 1), multiply(3, 5)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "a : b = 2 : 3 - - 1 b : c = 1 : 5 = > b : c = 3 : 15 - - 2 from 1 and 2 , we get a : c = 2 : 15 answer c" | other |
math_qa__ep7vQM8OeM20ylSN | A 290 meter long train running at the speed of 120 kmph crosses another train running in the opposite direction at the speed of 80 kmph in 9 seconds.What is the lenght of other train. Choose the correct choice from the following choices.
A) 210 m B) 220 m C) 230 m D) 240 m E) 250 m | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">9 * (500/9)</gadget>
<output>500</output>
<gadget id="calculator">500 - 290</gadget>
<output>210</output>
<result>A</result> | A | 210 | A 290 meter long train running at the speed of 120 kmph crosses another train running in the opposite direction at the speed of 80 kmph in 9 seconds.What is the lenght of other train. | {
"A": "210 m",
"B": "220 m",
"C": "230 m",
"D": "240 m",
"E": "250 m"
} | subtract(multiply(9, multiply(add(120, 80), const_0_2778)), 290) | add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)| | "relative speeds = ( 120 + 80 ) km / hr = 200 km / hr = ( 200 * 5 / 18 ) m / s = ( 500 / 9 ) m / s let length of train be xm x + 290 / 9 = 500 / 9 x = 210 ans is 210 m answer : a" | physics |
math_qa__B0Mq3oG0U60v3rbn | A man bought an article and sold it at a gain of 5 %. If he had bought it at 5% less and sold it for Re 8 less, he would have made a profit of 10%. The C.P. of the article was Select.
A) 1600 B) 1500 C) 1200 D) 1388 E) 1211 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">200 * 8</gadget>
<output>1_600</output>
<result>A</result> | A | 1,600 | A man bought an article and sold it at a gain of 5 %. If he had bought it at 5% less and sold it for Re 8 less, he would have made a profit of 10%. The C.P. of the article was | {
"A": "1600",
"B": "1500",
"C": "1200",
"D": "1388",
"E": "1211"
} | multiply(multiply(multiply(5, const_4.0), 10), 8) | multiply(n0,const_4.0)|multiply(n3,#0)|multiply(n2,#1)| | "explanation : let original cost price is x its selling price = ( 105 / 100 ) * x = 21 x / 20 new cost price = ( 95 / 100 ) * x = 19 x / 20 new selling price = ( 110 / 100 ) * ( 19 x / 20 ) = 209 x / 200 [ ( 21 x / 20 ) - ( 209 x / 200 ) ] = 8 = > x = 1600 answer : a ) rs 1600" | gain |
math_qa__4wrvLvxT0BI3yBF7 | Jacob is now 12 years younger than Michael. If 11 years from now Michael will be twice as old as Jacob, how old will Jacob be in 4 years?
Pick one
A) 3 B) 7 C) 15 D) 5 E) 25 | <gadget id="calculator">12 + 11</gadget>
<output>23</output>
<gadget id="calculator">2 * 11</gadget>
<output>22</output>
<gadget id="calculator">23 - 22</gadget>
<output>1</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<result>D</result> | D | 5 | Jacob is now 12 years younger than Michael. If 11 years from now Michael will be twice as old as Jacob, how old will Jacob be in 4 years? | {
"A": "3",
"B": "7",
"C": "15",
"D": "5",
"E": "25"
} | add(4, subtract(add(12, 11), multiply(const_2, 11))) | add(n0,n1)|multiply(n1,const_2)|subtract(#0,#1)|add(n2,#2) | jacob = x years , mike = x + 12 years 11 years from now , 2 ( x + 11 ) = x + 23 2 x + 22 = x + 23 x = 1 x + 4 = 5 years answer d | general |
math_qa__zDbUJMl4u5sMvHwu | The marks obtained by Vijay and Amith are in the ratio 2:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of? Select the correct option: A) 6 : 8 B) 3 : 1 C) 6 : 5 D) 3 : 2 E) 3 : 5 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">6 / 10</gadget>
<output>3/5 = around 0.6</output>
<result>E</result> | E | 0.6 | The marks obtained by Vijay and Amith are in the ratio 2:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of? | {
"A": "6 : 8",
"B": "3 : 1",
"C": "6 : 5",
"D": "3 : 2",
"E": "3 : 5"
} | divide(multiply(2, 3), multiply(5, 2)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "2 : 5 3 : 2 - - - - - - - 6 : 15 : 10 6 : 10 3 : 5 answer : e" | other |
math_qa__96L0x3JW6SIyzNgy | A soccer store typically sells replica jerseys at a discount of 30 percent to 50 percent off list price. During the annual summer sale, everything in the store is an additional 20 percent off the original list price. If a replica jersey's list price is $80, approximately what percent E of the list price is the lowest possible sale price? Choose the correct answer
A) 20
B) 25
C) 30
D) 40
E) 50 | <gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>D</result> | D | 40 | A soccer store typically sells replica jerseys at a discount of 30 percent to 50 percent off list price. During the annual summer sale, everything in the store is an additional 20 percent off the original list price. If a replica jersey's list price is $80, approximately what percent E of the list price is the lowest possible sale price? | {
"A": "20",
"B": "25",
"C": "30",
"D": "40",
"E": "50"
} | divide(80, const_2) | divide(n3,const_2)| | "let the list price be 2 x for min sale price , the first discount given should be 50 % , 2 x becomes x here now , during summer sale additional 20 % off is given ie sale price becomes 0.8 x it is given lise price is $ 80 = > 2 x = 80 = > x = 40 and 0.8 x = 32 so lowest sale price is 32 , which e is 40 % of 80 hence , d is the answer" | general |
math_qa__3WVgnEU0Wicg7S1d | The area of a rectangular field is 144 m2. If the length had been 6 metres more, the area would have been 54 m2 more. The original length of the field is Choose the correct option
A) 22 metres B) 18 metres C) 16 metres D) 24 metres E) none of these | <gadget id="calculator">6 * 144</gadget>
<output>864</output>
<gadget id="calculator">144 + 54</gadget>
<output>198</output>
<gadget id="calculator">198 - 144</gadget>
<output>54</output>
<gadget id="calculator">864 / 54</gadget>
<output>16</output>
<result>C</result> | C | 16 | The area of a rectangular field is 144 m2. If the length had been 6 metres more, the area would have been 54 m2 more. The original length of the field is | {
"A": "22 metres",
"B": "18 metres",
"C": "16 metres",
"D": "24 metres",
"E": "none of these"
} | divide(multiply(6, 144), subtract(add(144, 54), 144)) | add(n0,n3)|multiply(n0,n2)|subtract(#0,n0)|divide(#1,#2) | let the length and breadth of the original rectangular field be x m and y m respectively . area of the original field = x × y = 144 m 2 ∴ x = 144 ⁄ y . . . . . ( i ) if the length had been 6 m more , then area will be ( x + 6 ) y = 144 + 54 ⇒ ( x + 6 ) y = 198 … ( ii ) putting the value of x from eq ( i ) in eq ( ii ) , we get ( 144 ⁄ y + 6 ) y = 198 ⇒ 144 + 6 y = 198 ⇒ 6 y = 54 ⇒ y = 9 m putting the value of y in eq ( i ) we get x = 16 m answer c | physics |
math_qa__lkoJA7nbDMEZaB4G | Chris mixed 3 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 4 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture? Pick:
A) 1 / 7
B) 1 / 5
C) 1 / 4
D) 1 / 3
E) 3 / 19 | <gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 + 3</gadget>
<output>19</output>
<gadget id="calculator">3 / 19</gadget>
<output>3/19 = around 0.157895</output>
<result>E</result> | E | 0.157895 | Chris mixed 3 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 4 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture? | {
"A": "1 / 7",
"B": "1 / 5",
"C": "1 / 4",
"D": "1 / 3",
"E": "3 / 19"
} | divide(3, add(multiply(4, 4), 3)) | multiply(n1,n2)|add(n0,#0)|divide(n0,#1)| | "1 lbs of raisin = $ 1 3 lbs of raisin = $ 3 1 lbs of nuts = $ 4 4 lbs of nuts = $ 16 total value of mixture = 16 + 3 = 19 fraction of the value of raisin = 3 / 19 ans : e" | general |
math_qa__KQmOPA3IxBkc0w6e | 45 x ? = 45% of 900 Select the correct option.
A) 16.2
B) 4
C) 5
D) 9
E) 11 | <gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(9/20) * 900</gadget>
<output>405</output>
<gadget id="calculator">405 / 45</gadget>
<output>9</output>
<result>D</result> | D | 9 | 45 x ? = 45% of 900 | {
"A": "16.2",
"B": "4",
"C": "5",
"D": "9",
"E": "11"
} | divide(multiply(divide(45, const_100), 900), 45) | divide(n1,const_100)|multiply(n2,#0)|divide(#1,n0)| | "answer let 45 x a = ( 25 x 900 ) / 100 ∴ a = ( 45 x 9 ) / 45 = 9 correct option : d" | general |
math_qa__wTpownVcMn7XULK6 | P,Q and R together earn Rs.1980 in 9 days. P and R can earn Rs.600 in 5 days. Q and R in 7 days can earn Rs.910. How much amount does R can earn per day? Choose one:
A) s . 30 B) s . 70 C) s . 90 D) s . 100 E) s . 120 | <gadget id="calculator">600 / 5</gadget>
<output>120</output>
<gadget id="calculator">910 / 7</gadget>
<output>130</output>
<gadget id="calculator">120 + 130</gadget>
<output>250</output>
<gadget id="calculator">1_980 / 9</gadget>
<output>220</output>
<gadget id="calculator">250 - 220</gadget>
<output>30</output>
<result>A</result> | A | 30 | P,Q and R together earn Rs.1980 in 9 days. P and R can earn Rs.600 in 5 days. Q and R in 7 days can earn Rs.910. How much amount does R can earn per day? | {
"A": "s . 30",
"B": "s . 70",
"C": "s . 90",
"D": "s . 100",
"E": "s . 120"
} | subtract(add(divide(600, 5), divide(910, 7)), divide(1980, 9)) | divide(n2,n3)|divide(n5,n4)|divide(n0,n1)|add(#0,#1)|subtract(#3,#2)| | "explanation : amount earned by p , q and r in 1 day = 1980 / 9 = 220 - - - ( 1 ) amount earned by p and r in 1 day = 600 / 5 = 120 - - - ( 2 ) amount earned by q and r in 1 day = 910 / 7 = 130 - - - ( 3 ) ( 2 ) + ( 3 ) - ( 1 ) = > amount earned by p , q and 2 r in 1 day - amount earned by p , q and r in 1 day = 120 + 130 - 220 = 30 = > amount earned by r in 1 day = 30 answer : option a" | physics |
math_qa__VusHwLmM2At27VEd | The cost price of a radio is Rs.1390 and it was sold for Rs.890, find the loss %? Choose the correct option: A) 18 % B) 12 % C) 22 % D) 35 % E) 21 % | <gadget id="calculator">1_390 - 890</gadget>
<output>500</output>
<gadget id="calculator">500 / 1_390</gadget>
<output>50/139 = around 0.359712</output>
<gadget id="calculator">(50/139) * 100</gadget>
<output>5_000/139 = around 35.971223</output>
<result>D</result> | D | 35 | The cost price of a radio is Rs.1390 and it was sold for Rs.890, find the loss %? | {
"A": "18 %",
"B": "12 %",
"C": "22 %",
"D": "35 %",
"E": "21 %"
} | multiply(divide(subtract(1390, 890), 1390), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "1390 - - - - 500 100 - - - - ? = > 35 % answer : d" | gain |
math_qa__0Xsi0NyhoYuYBVXE | A circular wire of radius 42cm is cut and bent into the form of a rectangle whose sides are in the ratio of 6:5. The smaller side of the rectangle is: Choose the correct choice from the following choices:
A) 30 cm B) 60 cm C) 72 cm D) 132 cm . E) 142 cm . | <gadget id="calculator">2 * pi * 42</gadget>
<output>84*pi = around 263.893783</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">2 * 11</gadget>
<output>22</output>
<gadget id="calculator">(84*pi) / 22</gadget>
<output>42*pi/11 = around 11.995172</output>
<gadget id="calculator">5 * (42*pi/11)</gadget>
<output>210*pi/11 = around 59.97586</output>
<result>B</result> | B | 60 | A circular wire of radius 42cm is cut and bent into the form of a rectangle whose sides are in the ratio of 6:5. The smaller side of the rectangle is: | {
"A": "30 cm",
"B": "60 cm",
"C": "72 cm",
"D": "132 cm .",
"E": "142 cm ."
} | multiply(5, divide(circumface(42), multiply(const_2, add(6, 5)))) | add(n1,n2)|circumface(n0)|multiply(#0,const_2)|divide(#1,#2)|multiply(n2,#3) | length of wire = circumference of circle of radius 42 cm = ( 2 * 22 / 7 * 42 ) = 264 cm . therefore , perimeter of rectangle = 264 cm . let , length = 6 x cm & breadth = 5 x cm . therefore , 2 ( 6 x + 5 x ) = 264 or x = 12 . therefore , smaller side = 60 cm answer : b | geometry |
math_qa__ffHgMr19h2TGPWSN | If 6 years are subtracted from the present age of Arun and the remainder is divided by 18, then the present age of his grandson Gokul is obtained.If Gokul is 2 years younger to Madan whose age is 5 years, then what is the age of Arun? Select the correct option: A) 48 B) 60 C) 84 D) 96 E) 69 | <gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 18</gadget>
<output>54</output>
<gadget id="calculator">54 + 6</gadget>
<output>60</output>
<result>B</result> | B | 60 | If 6 years are subtracted from the present age of Arun and the remainder is divided by 18, then the present age of his grandson Gokul is obtained.If Gokul is 2 years younger to Madan whose age is 5 years, then what is the age of Arun? | {
"A": "48",
"B": "60",
"C": "84",
"D": "96",
"E": "69"
} | add(multiply(subtract(5, 2), 18), 6) | subtract(n3,n2)|multiply(n1,#0)|add(n0,#1) | arun age x . ( x - 6 ) / 18 = y y is gokul age which is 3 x = 60 answer : b | general |
math_qa__yAPr8eVRI5gGuaJp | Solve for the given equation 121 x 54 =? Select: A) 68225 B) 75625 C) 76569 D) 45854 E) 45858 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 ** 4</gadget>
<output>625</output>
<gadget id="calculator">121 * 625</gadget>
<output>75_625</output>
<result>B</result> | B | 75,625 | Solve for the given equation 121 x 54 =? | {
"A": "68225",
"B": "75625",
"C": "76569",
"D": "45854",
"E": "45858"
} | multiply(121, power(add(const_4, const_1), const_4)) | add(const_1,const_4)|power(#0,const_4)|multiply(n0,#1) | explanation : this question can be solved by 2 approaches : = > direct multiplication = > numerical operations direct multiplication is quite time consuming and involves a lot of calculations . an easier approach is based on numerical operations . = > 121 x ( 10 / 2 ) 4 = 121 x 10000 / 16 = 75625 answer : b | general |
math_qa__HeuGptJUh6erfSCs | A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together. Answers:
A) 18
B) 21
C) 25
D) 30
E) 35 | <gadget id="calculator">binomial(7, 4)</gadget>
<output>35</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">35 - 10</gadget>
<output>25</output>
<result>C</result> | C | 25 | A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together. | {
"A": "18",
"B": "21",
"C": "25",
"D": "30",
"E": "35"
} | subtract(choose(7, 4), choose(subtract(7, 2), 2)) | choose(n1,n0)|subtract(n1,n2)|choose(#1,n2)|subtract(#0,#2) | the total number of ways to choose 4 managers is 7 c 4 = 35 we need to subtract the number of groups which include the two managers , which is 5 c 2 = 10 . 35 - 10 = 25 the answer is c . | probability |
math_qa__Y9Ui7vwXhvEuqUsx | Nitin ranks 23th in a class of 60 students. What is rank from the last ? Choose the correct answer.
A) 33 B) 38 C) 32 D) 28 E) 19 | <gadget id="calculator">60 - 23</gadget>
<output>37</output>
<result>B</result> | B | 38 | Nitin ranks 23th in a class of 60 students. What is rank from the last ? | {
"A": "33",
"B": "38",
"C": "32",
"D": "28",
"E": "19"
} | subtract(60, 23) | subtract(n1,n0) | explanation : number students behind the nitin in rank = ( 60 - 23 ) = 37 nitin is 38 nd from the last answer : b ) 38 | other |
math_qa__YsLJ9EwnbEAl1cP4 | In how many ways 4 boys and 1 girls can be seated in a row so that they are alternate. Choose the most appropriate option:
A) 144 B) 288 C) 24 D) 256 E) none | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(1)</gadget>
<output>1</output>
<gadget id="calculator">24 * 1</gadget>
<output>24</output>
<result>C</result> | C | 24 | In how many ways 4 boys and 1 girls can be seated in a row so that they are alternate. | {
"A": "144",
"B": "288",
"C": "24",
"D": "256",
"E": "none"
} | multiply(factorial(4), factorial(1)) | factorial(n0)|factorial(n1)|multiply(#0,#1) | solution : let the arrangement be , b b b b g 4 boys can be seated in 4 ! ways . girl can be seated in 1 ! ways . required number of ways , = 4 ! * 1 ! = 24 . answer : option c | probability |
math_qa__KaTCKDFaPfLIRgc5 | {-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number will be a solution to the equation (x3)(x+14)(2X+5) = 0? Choose the correct choice from the following choices.
A) 1 / 12
B) 1 / 6
C) 1 / 4
D) 1 / 3
E) 1 / 2 | <gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<result>A</result> | A | 0.083333 | {-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number will be a solution to the equation (x3)(x+14)(2X+5) = 0? | {
"A": "1 / 12",
"B": "1 / 6",
"C": "1 / 4",
"D": "1 / 3",
"E": "1 / 2"
} | divide(1, add(10, 2)) | add(n0,n14)|divide(n5,#0) | x = - 4 prob = 1 / 12 answer - a | general |
math_qa__iCbRZRNukh8BHF69 | The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly copied. The first is 19 greater than the actual number and the second number added is 13 instead of 31. Find the correct average.
Options: A) 40.2 B) 40.4 C) 40.6 D) 40.8 E) 40.1 | <gadget id="calculator">40.2 * 10</gadget>
<output>402</output>
<gadget id="calculator">13 + 19</gadget>
<output>32</output>
<gadget id="calculator">402 + 32</gadget>
<output>434</output>
<gadget id="calculator">434 - 31</gadget>
<output>403</output>
<gadget id="calculator">403 / 10</gadget>
<output>403/10 = around 40.3</output>
<result>E</result> | E | 40.1 | The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly copied. The first is 19 greater than the actual number and the second number added is 13 instead of 31. Find the correct average. | {
"A": "40.2",
"B": "40.4",
"C": "40.6",
"D": "40.8",
"E": "40.1"
} | divide(subtract(add(multiply(40.2, 10), add(13, 19)), 31), 10) | add(n2,n3)|multiply(n0,n1)|add(#0,#1)|subtract(#2,n4)|divide(#3,n0)| | "sum of 10 numbers = 402 corrected sum of 10 numbers = 402 – 13 + 31 – 19 = 401 hence , new average = 401 ⁄ 10 = 40.1 answer e" | general |
math_qa__M78aZ6sklhGc7SaL | The side of a rhombus is 22 m and length of one of its diagonals is 16 m. The area of the rhombus is? Choose the correct choice from the following
A) 327.9 B) 325.9 C) 347.7 D) 357.9 E) 327.9 | <gadget id="calculator">2 * 22</gadget>
<output>44</output>
<gadget id="calculator">44 ** 2</gadget>
<output>1_936</output>
<gadget id="calculator">16 ** 2</gadget>
<output>256</output>
<gadget id="calculator">1_936 - 256</gadget>
<output>1_680</output>
<gadget id="calculator">1_680 ** (1/2)</gadget>
<output>4*sqrt(105) = around 40.987803</output>
<gadget id="calculator">16 * (4*sqrt(105))</gadget>
<output>64*sqrt(105) = around 655.804849</output>
<gadget id="calculator">(64*sqrt(105)) / 2</gadget>
<output>32*sqrt(105) = around 327.902425</output>
<result>A</result> | A | 327.9 | The side of a rhombus is 22 m and length of one of its diagonals is 16 m. The area of the rhombus is? | {
"A": "327.9",
"B": "325.9",
"C": "347.7",
"D": "357.9",
"E": "327.9"
} | divide(multiply(16, sqrt(subtract(power(multiply(const_2, 22), const_2), power(16, const_2)))), const_2) | multiply(n0,const_2)|power(n1,const_2)|power(#0,const_2)|subtract(#2,#1)|sqrt(#3)|multiply(n1,#4)|divide(#5,const_2)| | "area of the rhombus = 1 / 2 * p * √ 4 ( a ) 2 - ( p ) 2 a = 22 ; p = 16 a = 1 / 2 * 16 * √ 4 ( 22 ) 2 - ( 16 ) 2 = 1 / 2 * 16 * √ 1936 - 256 = 1 / 2 * 16 * √ 1680 a = 327.9 answer : a" | geometry |
math_qa__T0j9mdDi03hmJYkN | Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.3795. What is the difference between Rohan’s and Sudhir’s share in the profit? Choose the correct choice from the following choices.
A) s . 345 B) s . 350 C) s . 352 D) s . 362 E) s . 368 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">12_000 * (3/4)</gadget>
<output>9_000</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">9_000 * (2/3)</gadget>
<output>6_000</output>
<gadget id="calculator">9_000 - 6_000</gadget>
<output>3_000</output>
<gadget id="calculator">18_000 + 9_000</gadget>
<output>27_000</output>
<gadget id="calculator">27_000 + 6_000</gadget>
<output>33_000</output>
<gadget id="calculator">3_795 / 33_000</gadget>
<output>23/200 = around 0.115</output>
<gadget id="calculator">3_000 * (23/200)</gadget>
<output>345</output>
<result>A</result> | A | 345 | Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.3795. What is the difference between Rohan’s and Sudhir’s share in the profit? | {
"A": "s . 345",
"B": "s . 350",
"C": "s . 352",
"D": "s . 362",
"E": "s . 368"
} | multiply(subtract(multiply(12000, divide(subtract(multiply(3, 4), 3), multiply(3, 4))), multiply(9000, divide(subtract(multiply(3, 4), 4), multiply(3, 4)))), divide(3795, add(add(18000, multiply(12000, divide(subtract(multiply(3, 4), 3), multiply(3, 4)))), multiply(9000, divide(subtract(multiply(3, 4), 4), multiply(3, 4)))))) | multiply(n1,n2)|subtract(#0,n1)|subtract(#0,n2)|divide(#1,#0)|divide(#2,#0)|multiply(n3,#3)|multiply(n4,#4)|add(n0,#5)|subtract(#5,#6)|add(#7,#6)|divide(n5,#9)|multiply(#10,#8)| | "suresh : rohan : sudhir ratio of their investments = 18000 × 12 : 12000 × 9 : 9000 × 8 = 6 : 3 : 2 the difference between rohan ’ s and sudhir ’ s share = 1 share : . i . e . = rs . 3795 × 1 / 11 = rs . 345 . a" | gain |
math_qa__ZVCpSvVGTVdwjxTS | For each 6-month period during a light bulb's life span, the odds of it not burning out from over-use are half what they were in the previous 6-month period. If the odds of a light bulb burning out during the first 6-month period following its purchase are 1/3, what are the odds of it burning out during the period from 6months to 1 year following its purchase? Choose the correct choice from the following options.
A) 5 / 27 B) 2 / 9 C) 1 / 3 D) 4 / 9 E) 2 / 3 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) / 1</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(2/3) * (2/3)</gadget>
<output>4/9 = around 0.444444</output>
<result>D</result> | D | 0.444444 | For each 6-month period during a light bulb's life span, the odds of it not burning out from over-use are half what they were in the previous 6-month period. If the odds of a light bulb burning out during the first 6-month period following its purchase are 1/3, what are the odds of it burning out during the period from 6months to 1 year following its purchase? | {
"A": "5 / 27",
"B": "2 / 9",
"C": "1 / 3",
"D": "4 / 9",
"E": "2 / 3"
} | multiply(subtract(1, divide(1, 3)), subtract(1, divide(subtract(1, divide(const_2.0, 3)), 1))) | divide(n3,n4)|subtract(n6,#0)|divide(#1,const_2.0)|subtract(n6,#2)|multiply(#1,#3)| | "probability of not burning out during the first 6 months 1 - 1 / 3 = 2 / 3 probability of not burning out during the next 6 months 2 / 3 / 2 = 1 / 3 , hence probability of burning out 1 - 1 / 3 = 2 / 3 . probability of burning out during the period from 6 months to 1 year = probability of not burning out in first 6 months * probability of burning out in next 6 months = 2 / 3 * 2 / 3 = 4 / 9 answer : d ." | general |
math_qa__P7TkSQtNIwswG0KM | A grocer has a sale of Rs. 5921, Rs. 5468, Rs. 5568, Rs. 6088 and Rs. 6433 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5900? Choices:
A) 4902 B) 4922 C) 5922 D) 5924 E) 5928 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 5_900</gadget>
<output>35_400</output>
<gadget id="calculator">5_921 + 5_468</gadget>
<output>11_389</output>
<gadget id="calculator">11_389 + 5_568</gadget>
<output>16_957</output>
<gadget id="calculator">16_957 + 6_088</gadget>
<output>23_045</output>
<gadget id="calculator">23_045 + 6_433</gadget>
<output>29_478</output>
<gadget id="calculator">35_400 - 29_478</gadget>
<output>5_922</output>
<result>C</result> | C | 5,922 | A grocer has a sale of Rs. 5921, Rs. 5468, Rs. 5568, Rs. 6088 and Rs. 6433 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5900? | {
"A": "4902",
"B": "4922",
"C": "5922",
"D": "5924",
"E": "5928"
} | subtract(multiply(add(5, const_1), 5900), add(add(add(add(5921, 5468), 5568), 6088), 6433)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "total sale for 5 months = rs . ( 5921 + 5468 + 5568 + 6088 + 6433 ) = rs . 29478 . required sale = rs . [ ( 5900 x 6 ) - 29478 ] = rs . ( 35400 - 29478 ) = rs . 5922 . answer : c" | general |
math_qa__yBt9nhBD2xHqDoji | Nelly made a part payment of $875 toward buying a brand new refrigerator, which represents 25% of the total cost of the refrigerator, how much remains to be paid? Choose the correct choice from the following.
A) $ 2225 B) $ 2782 C) $ 1625 D) $ 2629 E) $ 2625 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">875 / (1/4)</gadget>
<output>3_500</output>
<gadget id="calculator">3_500 - 875</gadget>
<output>2_625</output>
<result>E</result> | E | 2,625 | Nelly made a part payment of $875 toward buying a brand new refrigerator, which represents 25% of the total cost of the refrigerator, how much remains to be paid? | {
"A": "$ 2225",
"B": "$ 2782",
"C": "$ 1625",
"D": "$ 2629",
"E": "$ 2625"
} | subtract(divide(875, divide(25, const_100)), 875) | divide(n1,const_100)|divide(n0,#0)|subtract(#1,n0) | explanation : let ' s start with what the total price of the refrigerator would be . if 25 % is equal to $ 875 then 100 % equals $ x . we just have to multiply $ 875 by 4 to get total amount = $ 3500 . out of this amount we then need to deduct the amount already paid which was $ 875 so we have $ 3500 - $ 875 = $ 2625 answer : option e | general |
math_qa__8b9nEl6nmEes2d9t | 16 is what % of 90? Select the correct option.
A) 16
B) 17.78
C) 17
D) 18.5
E) 18.23 | <gadget id="calculator">16 / 90</gadget>
<output>8/45 = around 0.177778</output>
<gadget id="calculator">(8/45) * 100</gadget>
<output>160/9 = around 17.777778</output>
<result>B</result> | B | 17.78 | 16 is what % of 90? | {
"A": "16",
"B": "17.78",
"C": "17",
"D": "18.5",
"E": "18.23"
} | multiply(divide(16, 90), const_100) | divide(n0,n1)|multiply(#0,const_100) | we assume that 90 is 100 % assume ' x ' is value we looking for here , 90 = 100 % and x % = 16 therefore , 100 / x = 90 / 16 100 / x = 5.625 x = 17.78 b | gain |
math_qa__SAD5hY35WBKLcIGP | Amar takes as much time in running 12 meters as a car takes in covering 45 meters. What will be the distance covered by Amar during the time the car covers 1.4 km? Pick: A) 700 m B) 500 m C) 373 m D) 356 m E) 640 m | <gadget id="calculator">1.4 * 1_000</gadget>
<output>1_400</output>
<gadget id="calculator">12 * 1_400</gadget>
<output>16_800</output>
<gadget id="calculator">16_800 / 45</gadget>
<output>1_120/3 = around 373.333333</output>
<result>C</result> | C | 373 | Amar takes as much time in running 12 meters as a car takes in covering 45 meters. What will be the distance covered by Amar during the time the car covers 1.4 km? | {
"A": "700 m",
"B": "500 m",
"C": "373 m",
"D": "356 m",
"E": "640 m"
} | divide(multiply(12, multiply(1.4, const_1000)), 45) | multiply(n2,const_1000)|multiply(n0,#0)|divide(#1,n1)| | "distance covered by amar = 12 / 45 ( 1.4 km ) = 4 / 15 ( 1400 ) = 373 m answer : c" | physics |
math_qa__8nCJiR3n6AVjxv8v | The side of a square is increased by 15% then how much % does its area increases?
Choose the most appropriate option:
A) 52.65 B) 56.25 C) 50.75 D) 32.25 E) 52.75 | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 ** 2</gadget>
<output>13_225</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">13_225 - 10_000</gadget>
<output>3_225</output>
<gadget id="calculator">3_225 * 100</gadget>
<output>322_500</output>
<gadget id="calculator">322_500 / 10_000</gadget>
<output>129/4 = around 32.25</output>
<result>D</result> | D | 32.25 | The side of a square is increased by 15% then how much % does its area increases? | {
"A": "52.65",
"B": "56.25",
"C": "50.75",
"D": "32.25",
"E": "52.75"
} | divide(multiply(subtract(square_area(add(const_100, 15)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1) | a = 100 a 2 = 10000 a = 115 a 2 = 13225 - - - - - - - - - - - - - - - - 10000 - - - - - - - - - 3225 100 - - - - - - - ? = > 32.25 % answer : d | geometry |
math_qa__1pLnBgg4ZzLJu5is | A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.14200 after a year? Choose the correct choice from the following options
A) 3630 B) 9232 C) 4260 D) 2387 E) 2813 | <gadget id="calculator">6_300 + 4_200</gadget>
<output>10_500</output>
<gadget id="calculator">10_500 + 10_500</gadget>
<output>21_000</output>
<gadget id="calculator">6_300 / 21_000</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 14_200</gadget>
<output>4_260</output>
<result>C</result> | C | 4,260 | A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.14200 after a year? | {
"A": "3630",
"B": "9232",
"C": "4260",
"D": "2387",
"E": "2813"
} | multiply(divide(6300, add(add(6300, 4200), 10500)), 14200) | add(n0,n1)|add(n2,#0)|divide(n0,#1)|multiply(n3,#2)| | "6300 : 4200 : 10500 3 : 2 : 5 3 / 10 * 14200 = 4260 answer : c" | gain |
math_qa__x0AyesrcCq7SwlnI | When a certain number X is divided by 63, the remainder is 25. What is the remainder when X is divided by 8? Choose the correct choice from the following answers
A) 1 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">25 % 8</gadget>
<output>1</output>
<result>A</result> | A | 1 | When a certain number X is divided by 63, the remainder is 25. What is the remainder when X is divided by 8? | {
"A": "1",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | reminder(25, 8) | reminder(n1,n2)| | "when a certain number x is divided by 63 , the remainder is 25 . what is the remainder when x is divided by 8 ? putting a value say x = 255 we get remainder as 25 when divided by 63 . when 25 divided by 8 we get 1 as remainder . a is the answer ." | general |
math_qa__fFd1qNT52YMbbxxk | 5.02 can be expressed in terms of percentage as
Pick:
A) 5.02 % B) 50.2 % C) 209 % D) 502 % E) none of these | <gadget id="calculator">5.02 * 100</gadget>
<output>502</output>
<result>D</result> | D | 502 | 5.02 can be expressed in terms of percentage as | {
"A": "5.02 %",
"B": "50.2 %",
"C": "209 %",
"D": "502 %",
"E": "none of these"
} | multiply(5.02, const_100) | multiply(n0,const_100)| | "explanation : while calculation in terms of percentage we need to multiply by 100 , so 5.02 * 100 = 502 answer : option d" | general |
math_qa__aRSlGFXUFHZoHyrG | The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is? Pick one:
A) 36.6 B) 36.1 C) 36.5 D) 36.2 E) 36.9 | <gadget id="calculator">36 * 50</gadget>
<output>1_800</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">48 - 23</gadget>
<output>25</output>
<gadget id="calculator">1_800 + 25</gadget>
<output>1_825</output>
<gadget id="calculator">1_825 / 50</gadget>
<output>73/2 = around 36.5</output>
<result>C</result> | C | 36.5 | The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is? | {
"A": "36.6",
"B": "36.1",
"C": "36.5",
"D": "36.2",
"E": "36.9"
} | divide(add(multiply(36, 50), subtract(subtract(50, const_2), 23)), 50) | multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,n3)|add(#0,#2)|divide(#3,n0)| | "correct sum = ( 36 * 50 + 48 - 23 ) = 1825 . correct mean = 1825 / 50 = 36.5 answer : c" | general |
math_qa__8kXXetikTkVH0Piy | A, Band C can do a piece of work in 11 days, 45 days and 55 days respectively, working alone. How soon can the work be done if A is assisted by Band C on alternate days? Choose the correct choice from the following choices:
A) 7 days
B) 8 days
C) 9 days
D) 10 days
E) 11 days | <gadget id="calculator">55 / 11</gadget>
<output>5</output>
<gadget id="calculator">55 / 45</gadget>
<output>11/9 = around 1.222222</output>
<gadget id="calculator">5 + (11/9)</gadget>
<output>56/9 = around 6.222222</output>
<gadget id="calculator">55 / 55</gadget>
<output>1</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">(56/9) + 6</gadget>
<output>110/9 = around 12.222222</output>
<gadget id="calculator">(110/9) / 2</gadget>
<output>55/9 = around 6.111111</output>
<gadget id="calculator">55 / (55/9)</gadget>
<output>9</output>
<result>C</result> | C | 9 | A, Band C can do a piece of work in 11 days, 45 days and 55 days respectively, working alone. How soon can the work be done if A is assisted by Band C on alternate days? | {
"A": "7 days",
"B": "8 days",
"C": "9 days",
"D": "10 days",
"E": "11 days"
} | divide(55, divide(add(add(divide(55, 11), divide(55, 45)), add(divide(55, 11), divide(55, 55))), const_2)) | divide(n2,n0)|divide(n2,n1)|divide(n2,n2)|add(#0,#1)|add(#0,#2)|add(#3,#4)|divide(#5,const_2)|divide(n2,#6)| | "( a + b ) ' s 1 day ' s work = 1 / 11 + 1 / 45 = 56 / 495 ( a + c ) ' s 1 day ' s work = 1 / 11 + 1 / 55 = 6 / 55 work done in 2 day ' s = 56 / 495 + 6 / 55 = 2 / 9 2 / 9 th work done in 2 days work done = 9 / 2 * 2 = 9 days answer : c" | physics |
math_qa__Q5eZgfx9LrcmMV4b | What is x if x + 3y = 33 and y = 10? Choose the correct option
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">33 - 30</gadget>
<output>3</output>
<result>C</result> | C | 3 | What is x if x + 3y = 33 and y = 10? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(33, multiply(3, 10)) | multiply(n0,n2)|subtract(n1,#0)| | "substitute y by 10 in x + 3 y = 33 x + 3 ( 10 ) = 33 x + 30 = 33 if we substitute x by 3 in x + 30 = 33 , we have 3 + 30 = 33 . hence x = 3 correct answer c" | general |
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