category
stringclasses 5
values | question
stringlengths 20
555
| answer
stringlengths 1
20
| solution_abst
stringlengths 1
287
| solution_code
stringlengths 27
5.97k
|
|---|---|---|---|---|
Arithmetic calculation | An item was wrapped with tape measuring 16 meters (m) in length. If 5 meters (m) were used to wrap the 1 item, how many meters (m) of tape are left after wrapping 2 items? | 6 | 16 5 2 [OP_MUL] [OP_SUB] | var_a = 16
var_b = 5
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
print(int(var_e)) |
Arithmetic calculation | It costs 30 won to eat an apple. If you eat 25 apples, how much do you need? | 750 | 30 25 [OP_MUL] | var_a = 30
var_b = 25
var_c = var_a * var_b
print(int(var_c)) |
Possibility | You want to distribute 10 apples among 4 students. Given that at least one apple is given to each student, find the number of possible cases. | 84 | 1 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 10
var_g = 0
var_f = int(var_f)
for i in list_c:
i = int(i)
if i == var_f:
var_g = var_g + 1
print(int(var_g)) |
Correspondence | Find B to satisfy 57A-B14=364. | 2 | 57A-B14=364 B [OP_DIGIT_UNK_SOLVER] | var_a = '57A-B14=364'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | Jimin had 12 tangerines. 7 of them were eaten. How many tangerines are left to Jimin? | 5 | 12 7 [OP_SUB] | var_a = 12
var_b = 7
var_c = var_a - var_b
print(int(var_c)) |
Geometry | The surface area of a rectangular cuboid is 442 square centimeters (cm2). If the width is 7 centimeters (cm) and the length is 8 centimeters (cm), how many centimeters (cm) is the height? | 11 | 442 2 [OP_DIV] 7 8 [OP_MUL] [OP_SUB] 7 8 [OP_ADD] [OP_DIV] | var_a = 442
var_b = 2
var_c = var_a / var_b
var_d = 7
var_e = 8
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 7
var_i = 8
var_j = var_h + var_i
var_k = var_g / var_j
print(int(var_k)) |
Arithmetic calculation | Your younger brother is 1.1 meters (m) taller, you are 0.2 meters (m) taller than your younger brother, and your older brother is 1/10 meter (m) taller than you. How tall is your brother in meters (m)? | 1.4 | 0.2 1.1 [OP_ADD] 1/10 [OP_ADD] | var_a = 0.2
var_b = 1.1
var_c = var_a + var_b
var_d = 0.1
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Possibility | You want to find the difference between the third smallest and the second smallest number of three number cards. If you have cards with 1, 6, and 8 written on them, what is the difference? | 432 | [OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB] | var_a = 1
var_b = 6
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 3
list_c=list_b.copy()
list_c.sort()
var_f = list_c[var_e-1]
var_g = 2
list_d=list_b.copy()
list_d.sort()
var_h = list_d[var_g-1]
var_i = var_f - var_h
print(int(var_i)) |
Geometry | When the toy train was completely submerged in a cuboid-shaped water tank whose two sides of the bottom is 44 centimeters (cm) and 35 centimeters (cm), respectively, the height of the water increased by 7 centimeters (cm). And then the toy car was completely submerged, which increased the height of the water by 3 centimeters (cm). Find the sum of the volumes of the toy train and the car in cubic centimeters (cm3). | 15400 | 44 35 [OP_MUL] 7 3 [OP_ADD] [OP_MUL] | var_a = 44
var_b = 35
var_c = var_a * var_b
var_d = 7
var_e = 3
var_f = var_d + var_e
var_g = var_c * var_f
print(int(var_g)) |
Correspondence | 66 is the result of mistakenly subtracting 3 and adding 49 when should have multiplifed the number by 3 and adding 49. Find the difference between the incorrectly calculated value and the correct calculated value. | 43 | 66 49 [OP_SUB] 3 [OP_ADD] 3 [OP_MUL] 49 [OP_ADD] 66 [OP_SUB] | var_a = 66
var_b = 49
var_c = var_a - var_b
var_d = 3
var_e = var_c + var_d
var_f = 3
var_g = var_e * var_f
var_h = 49
var_i = var_g + var_h
var_j = 66
var_k = var_i - var_j
print(int(var_k)) |
Possibility | Find the product of the largest three-digit number and the smallest three-digit number when numbers can be formed of 4 number cards 1, 3, 5, and 8 allowing the duplicates. | 98568 | [OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL] | var_a = 1
var_b = 3
var_c = 5
var_d = 8
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 1
list_d=list_b.copy()
list_d.sort()
var_i = list_d[var_h-1]
var_j = var_g * var_i
print(int(var_j)) |
Comparison | Jimin, Taehyung, and Hoseok each bought and ate a bag of the same candy. Jimin ate 1/9 of the total, Taehyung ate 1/3 of the total, and Hoseok ate 1/6 of the total. Who has the most candy left? | Jimin | [OP_LIST_SOL] Jimin Taehyung Hoseok [OP_LIST_EOL] [OP_LIST_SOL] 1/9 1/3 1/6 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jimin'
var_b = 'Taehyung'
var_c = 'Hoseok'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.1111111111111111
var_e = 0.3333333333333333
var_f = 0.16666666666666666
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Possibility | Using the four digits 1, 4, 5, and 9 once, find the second large three-digit number with 9 in the tens place. | 591 | [OP_LIST_SOL] 1 4 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 9 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX] | var_a = 1
var_b = 4
var_c = 5
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 10
var_g = 9
list_c = []
var_f = int(var_f)
var_g = int(var_g)
for i in list_b:
i = int(i)
if (i//var_f)%10 == var_g:
list_c.append(i)
var_h = 2
list_d=list_c.copy()
list_d.sort()
var_i = list_d[-var_h]
print(int(var_i)) |
Geometry | Find the area of a rectangular wall whose sides are 5 meters (m) long and 17/20 meters (m) wide. | 4.25 | 5 17/20 [OP_MUL] | var_a = 5
var_b = 0.85
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | There are 28 notebooks. I gave 1/4 of the 28 books to Yeonju, and 3/7 of the 28 books to Minji. Find how many notebooks are left. | 9 | 28 1 1/4 [OP_SUB] 3/7 [OP_SUB] [OP_MUL] | var_a = 28
var_b = 1
var_c = 0.25
var_d = var_b - var_c
var_e = 0.42857142857142855
var_f = var_d - var_e
var_g = var_a * var_f
print(int(var_g)) |
Geometry | People are standing in 5 rows of 5 people. How many people are standing on the circumference? | 16 | 5 4 [OP_MUL] 4 [OP_SUB] | var_a = 5
var_b = 4
var_c = var_a * var_b
var_d = 4
var_e = var_c - var_d
print(int(var_e)) |
Comparison | There are 28 students in Jungkook's class, and each is a different height. If you line up these students in order of height, Jungkook will be 14th from the front and Eunji will be 20th from the front. How many students are standing between Jungkook and Eunji? | 5 | 20 14 [OP_SUB] 1 [OP_SUB] | var_a = 20
var_b = 14
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Possibility | Find the sum of all numbers that are divisible by 3 and 5 when choosing three different numbers from 2, 3, 5, and 7 to make a three-digit number. | 1110 | [OP_LIST_SOL] 2 5 3 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_SUM] | var_a = 2
var_b = 5
var_c = 3
var_d = 7
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 3
list_c = []
var_f = int(var_f)
for i in list_b:
i = int(i)
if i % var_f == 0:
list_c.append(i)
var_g = 5
list_d = []
var_g = int(var_g)
for i in list_c:
i = int(i)
if i % var_g == 0:
list_d.append(i)
list_d = [float(i) for i in list_d]
var_h = sum(list_d)
print(int(var_h)) |
Arithmetic calculation | Some apartment complex has 1 to 22 apartment buildings, each with up to 6 floors. If there are 5 apartments on each floor, how many apartments can live in this apartment complex? | 660 | 22 6 [OP_MUL] 5 [OP_MUL] | var_a = 22
var_b = 6
var_c = var_a * var_b
var_d = 5
var_e = var_c * var_d
print(int(var_e)) |
Correspondence | 55 is a number obtained by adding 45 to some number and subtracting 62 from it. What is the result when 7 is multiplied by this number? | 504 | 55 45 [OP_SUB] 62 [OP_ADD] 7 [OP_MUL] | var_a = 55
var_b = 45
var_c = var_a - var_b
var_d = 62
var_e = var_c + var_d
var_f = 7
var_g = var_e * var_f
print(int(var_g)) |
Comparison | Students are standing in a line. Yoojeong is standing at the very back. When 8 people are standing in front of Yoojeong, how many students are standing in the line? | 9 | 8 1 [OP_ADD] | var_a = 8
var_b = 1
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | You want to plant trees on one side of a road that is 156 meters (m) long at 6 meters (m) intervals. How many trees will you need if you plant trees at the beginning and at the end? | 27 | 156 6 [OP_DIV] 1 [OP_ADD] | var_a = 156
var_b = 6
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | I am going to sell 200 carnations parceling into 25 bundles. If 1 carnation is 500 won, how much is a bundle? | 4000 | 200 25 [OP_DIV] 500 [OP_MUL] | var_a = 200
var_b = 25
var_c = var_a / var_b
var_d = 500
var_e = var_c * var_d
print(int(var_e)) |
Geometry | Gasoline was filled in a cuboid-shaped oil tank with dimensions of 350 centimeters (cm), 260 centimeters (cm), and 165 centimeters (cm) in width, length, and height, respectively. If gasoline is 1,600 won per liter (L), how much money is needed to fill the gas tank? | 24024000 | 350 260 [OP_MUL] 165 [OP_MUL] 1000 [OP_DIV] 1600 [OP_MUL] | var_a = 350
var_b = 260
var_c = var_a * var_b
var_d = 165
var_e = var_c * var_d
var_f = 1000
var_g = var_e / var_f
var_h = 1600
var_i = var_g * var_h
print(int(var_i)) |
Possibility | Find the number of ways where numbers from 1 to 100 are smaller than 40 and each digit is not equal to one another and consists of only 1, 3, 7, and 8? | 6 | [OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | var_a = 1
var_b = 3
var_c = 7
var_d = 8
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 40
list_c = []
for i in list_b:
if i <= var_f:
list_c.append(i)
var_g = len(list_c)
print(int(var_g)) |
Arithmetic calculation | Yuna and her grandmother are 12 and 72 years old, respectively. A few years later, grandmother's age is 5 times Yuna's age. How old is your grandmother at that year? | 75 | 72 12 [OP_SUB] 5 [OP_MUL] 5 1 [OP_SUB] [OP_DIV] | var_a = 72
var_b = 12
var_c = var_a - var_b
var_d = 5
var_e = var_c * var_d
var_f = 5
var_g = 1
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i)) |
Arithmetic calculation | Yuna threaded 380 beads and Eunji threaded 325 beads in 1 hour. How many beads did Yuna thread more than Eunji when the two of them threaded at a constant speed for 8 hours? | 440 | 380 325 [OP_SUB] 8 [OP_MUL] | var_a = 380
var_b = 325
var_c = var_a - var_b
var_d = 8
var_e = var_c * var_d
print(int(var_e)) |
Geometry | Find the number of faces of a square pillar. | 6 | 4 2 [OP_ADD] | var_a = 4
var_b = 2
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | There are persimmons of the same size and weight. Five persimmons weigh 1 kilogram (kg). How many persimmons are there if all persimmons are 3 kg (kg)? | 15 | 5 1 [OP_MUL] 3 [OP_MUL] | var_a = 5
var_b = 1
var_c = var_a * var_b
var_d = 3
var_e = var_c * var_d
print(int(var_e)) |
Geometry | A rectangular parallelepiped barrel with the lengths of the bottom two sides measuring 6 meters (m) 40 centimeters (cm) and 9 meters (m) respectively and the height measuring 5 meters (m) 20 centimeters (cm) is filled with sand. We want to divide this sand into several barrels whose volume is one cubic meter (m3). Find at least how many barrels you need. | 300 | 6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL] | var_a = 6
var_b = 40
var_c = 100
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 9
var_g = var_e * var_f
var_h = 5
var_i = 20
var_j = 100
var_k = var_i / var_j
var_l = var_h + var_k
var_m = var_g * var_l
var_n = 1
var_o = var_m / var_n
var_p = 1
var_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))
print(int(var_q)) |
Correspondence | A number multiplied by 2 subtracted by 3 equals 7. Find the number. | 5 | 7 3 [OP_ADD] 2 [OP_DIV] | var_a = 7
var_b = 3
var_c = var_a + var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | When I cut wire into pieces of 7 centimeters (cm), it becomes 12 pieces leaving 4 centimeters (cm). If you cut this wire into pieces of 3 centimeters (cm), how many centimeters (cm) remains? | 1 | 7 12 [OP_MUL] 4 [OP_ADD] 3 [OP_MOD] | var_a = 7
var_b = 12
var_c = var_a * var_b
var_d = 4
var_e = var_c + var_d
var_f = 3
var_g = var_e % var_f
print(int(var_g)) |
Arithmetic calculation | There are five numbers 10, 11, 12, 13, and 14. What is the remainder of the second largest number divided by the second smallest number? | 2 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MOD] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 2
list_b=list_a.copy()
list_b.sort()
var_g = list_b[-var_f]
var_h = 2
list_c=list_a.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = var_g % var_i
print(int(var_j)) |
Geometry | I made a square by arranging go stones without gaps. If the number of go stones on the perimeter is 52, how many go stones are on the outermost of one side? | 14 | 52 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD] | var_a = 52
var_b = 4
var_c = var_a - var_b
var_d = 4
var_e = var_c / var_d
var_f = 2
var_g = var_e + var_f
print(int(var_g)) |
Geometry | How many square centimeters (cm2) is the sum of the widths of two squares, every 11 centimeters (cm) and 5 centimeters (cm) long?
| 146 | 11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] | var_a = 11
var_b = 2
var_c = var_a ** var_b
var_d = 5
var_e = 2
var_f = var_d ** var_e
var_g = var_c + var_f
print(int(var_g)) |
Possibility | There are one card 5, one card 1, one card 7, and one card 6 in the pocket. When you want to make decimal numbers with three decimal places bigger than 7 with all of each card, how many can you make? | 6 | [OP_LIST_SOL] 5 1 7 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 7 10 4 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 5
var_b = 1
var_c = 7
var_d = 6
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 7
var_g = 10
var_h = 4
var_i = 1
var_j = var_h - var_i
var_k = var_g ** var_j
var_l = var_f * var_k
list_c = []
for i in list_b:
if i > var_l:
list_c.append(i)
var_m = len(list_c)
print(int(var_m)) |
Comparison | A is the sum of 4 groups of 10 and 8 units. B is 50 minus 1. C is 40 plus 7. Which of the three numbers A, B, and C is the greatest? | B | [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 10 4 [OP_MUL] 8 [OP_ADD] 50 1 [OP_SUB] 40 7 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 10
var_e = 4
var_f = var_d * var_e
var_g = 8
var_h = var_f + var_g
var_i = 50
var_j = 1
var_k = var_i - var_j
var_l = 40
var_m = 7
var_n = var_l + var_m
list_b= []
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
list_b.reverse()
var_o = 1
list_c=list_b.copy()
list_c.sort()
var_p = list_c[-var_o]
var_q = list_b.index(var_p)+1
var_r = list_a[var_q-1]
print(var_r) |
Arithmetic calculation | Ji-yeon bought tteokbokki with 1/2 of her pocket money. And she used 3/8 of the rest to buy pencils. How much is the tteokbokki Jiyeon bought when the remaining money is 2,500 won? | 4000 | 2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL] | var_a = 2500
var_b = 1
var_c = 0.375
var_d = var_b - var_c
var_e = var_a / var_d
var_f = 0.5
var_g = var_e / var_f
var_h = 0.5
var_i = var_g * var_h
print(int(var_i)) |
Geometry | I made a rectangular parallelepiped by attaching certain cubes, and the length and width of its base were twice the height. If the sum of the lengths of all the edges of this rectangular parallelepiped is 100 centimeters (cm), what is the surface area of this rectangular parallelepiped? | 400 | 100 4 [OP_DIV] 2 2 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_POW] 2 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] [OP_ADD] [OP_MUL] | var_a = 100
var_b = 4
var_c = var_a / var_b
var_d = 2
var_e = 2
var_f = var_d + var_e
var_g = 1
var_h = var_f + var_g
var_i = var_c / var_h
var_j = 2
var_k = var_i ** var_j
var_l = 2
var_m = 2
var_n = var_l * var_m
var_o = 2
var_p = var_n * var_o
var_q = 1
var_r = 2
var_s = var_q * var_r
var_t = 2
var_u = var_s * var_t
var_v = 1
var_w = 2
var_x = var_v * var_w
var_y = 2
var_z = var_x * var_y
var_A = var_u + var_z
var_B = var_p + var_A
var_C = var_k * var_B
print(int(var_C)) |
Comparison | Nine students are standing in a line to get on the bus. How many students are standing between the student standing third from the front and the student standing second from the back? | 4 | 9 3 [OP_SUB] 2 [OP_SUB] | var_a = 9
var_b = 3
var_c = var_a - var_b
var_d = 2
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | Dohyeon is 1.46 meters (m) tall, and his older brother's height is 1.15 times of Dohyeon's. How tall is his brother in meters (m)? | 1.68 | 1.46 1.15 [OP_MUL] | var_a = 1.46
var_b = 1.15
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Geometry | If the area of a cube-shaped box is 600, what is the volume of this box? | 1000 | 600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW] | var_a = 600
var_b = 6
var_c = var_a / var_b
var_d = 0.5
var_e = var_c ** var_d
var_f = 3
var_g = var_e ** var_f
print(int(var_g)) |
Possibility | If 6 basketball teams play with each other once, how many matches will there be in total? | 15 | 6 2 [OP_COMB] | var_a = 6
var_b = 2
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c)) |
Correspondence | Yoongi wants to add a four-digit number to 57. Yoongi saw 9 in the ones place of a four-digit number wrong, and saw it as 6. When the sum Yoongi got is 1823, find this four-digit number. | 1769 | 1823 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] | var_a = 1823
var_b = 57
var_c = var_a - var_b
var_d = 6
var_e = 9
var_f = var_d - var_e
var_g = var_c - var_f
print(int(var_g)) |
Arithmetic calculation | When performing multiplication between two-digit numbers, when the tens digit of the multiplier is mistakenly considered as 6 instead of 2, the calculated value is 2496. However, the correct calculation yields 936. What is the sum of these two two-digit numbers? | 63 | [OP_LIST_SOL] 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 936 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] [OP_LIST_SUM] | var_a = 2496
var_b = 936
var_c = var_a - var_b
var_d = 6
var_e = 2
var_f = var_d - var_e
var_g = 10
var_h = var_f * var_g
var_i = var_c / var_h
var_j = 936
var_k = 2496
var_l = 936
var_m = var_k - var_l
var_n = 6
var_o = 2
var_p = var_n - var_o
var_q = 10
var_r = var_p * var_q
var_s = var_m / var_r
var_t = var_j / var_s
list_a= []
if "/" in str(var_t):
var_t = eval(str(var_t))
list_a.append(var_t)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_a.append(var_i)
list_a.reverse()
list_a = [float(i) for i in list_a]
var_u = sum(list_a)
print(int(var_u)) |
Arithmetic calculation | There are 8 boxes of soccer balls of 12 each, and 5 boxes of basketballs of 12 each. How many more soccer balls are there than basketballs? | 36 | 12 8 [OP_MUL] 12 5 [OP_MUL] [OP_SUB] | var_a = 12
var_b = 8
var_c = var_a * var_b
var_d = 12
var_e = 5
var_f = var_d * var_e
var_g = var_c - var_f
print(int(var_g)) |
Possibility | Find the number of ways when the value of one of the cards numbered from 1 to 9 is drawn and multiplied by 65, and is greater than the value of 57 multiplied by 7. | 6 | 1 9 1 [OP_LIST_ARANGE] 57 7 [OP_MUL] 65 [OP_DIV] [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 57
var_e = 7
var_f = var_d * var_e
var_g = 65
var_h = var_f / var_g
list_b = []
for i in list_a:
if i < var_h:
list_b.append(i)
var_i = len(list_b)
print(int(var_i)) |
Comparison | Choose a number greater than or equal to 1.1 from 1.4, 9/10, 1.2, 0.5, and 13/10, and count the number of selected numbers. | 3 | [OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN] | var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Arithmetic calculation | Hyeonsu went around the promenade for 4 hours. What is the ratio of the distance Hyeonsoo walked in 1 hour on the walking trail? | 0.25 | 1 4 [OP_DIV] | var_a = 1
var_b = 4
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Geometry | Miho has a field with a side measuring 6 meters (m). How big is this field? | 36 | 6 2 [OP_POW] | var_a = 6
var_b = 2
var_c = var_a ** var_b
print(int(var_c)) |
Possibility | What is the third largest three-digit number with 7 in the hundreds place using 2, 4, 7, and 9 once? | 749 | [OP_LIST_SOL] 2 4 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 7 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX] | var_a = 2
var_b = 4
var_c = 7
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 100
var_g = 7
list_c = []
var_f = int(var_f)
var_g = int(var_g)
for i in list_b:
i = int(i)
if (i//var_f)%10 == var_g:
list_c.append(i)
var_h = 3
list_d=list_c.copy()
list_d.sort()
var_i = list_d[-var_h]
print(int(var_i)) |
Geometry | The width of a monitor is 9 centimeters (cm). If the circumference is 46 centimeters (cm), how long is the length of a monitor in centimeters (cm)? | 14 | 46 2 [OP_DIV] 9 [OP_SUB] | var_a = 46
var_b = 2
var_c = var_a / var_b
var_d = 9
var_e = var_c - var_d
print(int(var_e)) |
Comparison | Seulgi has 9 pencils, and Hyeonjeong has 12 pencils. Who has more pencils? | Hyeonjeong | [OP_LIST_SOL] Seulgi Hyeonjeong [OP_LIST_EOL] [OP_LIST_SOL] 9 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Seulgi'
var_b = 'Hyeonjeong'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 9
var_d = 12
list_b= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = list_b.index(var_f)+1
var_h = list_a[var_g-1]
print(var_h) |
Possibility | There are one carrot, one cucumber, and one radish each. How many ways can you choose to buy 2 of these? | 3 | [OP_LIST_SOL] carrot cucumber radish [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB] | var_a = 'carrot'
var_b = 'cucumber'
var_c = 'radish'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 2
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
for i, elem in enumerate(range(var_e)):
var_f = var_f / (i+1)
print(int(var_f)) |
Comparison | There are circle-shaped pizzas (a), (b), (c), and (d). The area of the pizza (a) is 314 square centimeters (㎠) and the circumference of the pizza (b) is 99.2 centimeters (㎝). The diameter of the pizza (c) is 16 centimeters (cm) and the radius of the pizza (d) is 12 centimeters (cm). If the pizzas are sorted from the left in order from smallest to largest, find the pizza that is second from the right. It is assumed that the pi ratio is 3.1. | (a) | [OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] 314 99.2 3.1 [OP_DIV] 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 16 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 12 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = '(a)'
var_b = '(b)'
var_c = '(c)'
var_d = '(d)'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 314
var_f = 99.2
var_g = 3.1
var_h = var_f / var_g
var_i = 2
var_j = var_h / var_i
var_k = 2
var_l = var_j ** var_k
var_m = 3.1
var_n = var_l * var_m
var_o = 16
var_p = 2
var_q = var_o / var_p
var_r = 2
var_s = var_q ** var_r
var_t = 3.1
var_u = var_s * var_t
var_v = 12
var_w = 2
var_x = var_v ** var_w
var_y = 3.1
var_z = var_x * var_y
list_b= []
if "/" in str(var_z):
var_z = eval(str(var_z))
list_b.append(var_z)
if "/" in str(var_u):
var_u = eval(str(var_u))
list_b.append(var_u)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_A = 2
list_c=list_b.copy()
list_c.sort()
var_B = list_c[var_A-1]
var_C = list_b.index(var_B)+1
var_D = list_a[var_C-1]
print(var_D) |
Correspondence | 14A+B73=418. How much is A, where 14A and B73 are three-digit numbers? | 5 | 14A+B73=418 A [OP_DIGIT_UNK_SOLVER] | var_a = '14A+B73=418'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | There are four numbers 10, 11, 12, and 13. What is the quotient if you divide the 3rd smallest number by the 2nd smallest number? | 1 | [OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b=list_a.copy()
list_b.sort()
var_f = list_b[var_e-1]
var_g = 2
list_c=list_a.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = var_f // var_h
print(int(var_i)) |
Correspondence | You have to divide a number by 4 and add 16, but if you accidentally multiplied a number by 4 and added 16 to get 32. Find out how much it is if you calculate it correctly. | 17 | 32 16 [OP_SUB] 4 [OP_DIV] 4 [OP_DIV] 16 [OP_ADD] | var_a = 32
var_b = 16
var_c = var_a - var_b
var_d = 4
var_e = var_c / var_d
var_f = 4
var_g = var_e / var_f
var_h = 16
var_i = var_g + var_h
print(int(var_i)) |
Correspondence | Add 143 to a number and multiply it by 27 to get 9693. Find the number. | 216 | 9693 27 [OP_DIV] 143 [OP_SUB] | var_a = 9693
var_b = 27
var_c = var_a / var_b
var_d = 143
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | There is a scale that can weigh more than 2 kilograms (kg). If you have lifted 3 weights of 200 grams (g) so far, find how many more weights you need to lift to measure the weight. | 7 | 2 1000 [OP_MUL] 200 3 [OP_MUL] [OP_SUB] 200 [OP_DIV] 1 [OP_CEIL] | var_a = 2
var_b = 1000
var_c = var_a * var_b
var_d = 200
var_e = 3
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 200
var_i = var_g / var_h
var_j = 1
var_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))
print(int(var_k)) |
Arithmetic calculation | I plan to sell 254 erasers by packing 30 in each box. How many more erasers would you need to pack and sell if there should be no leftover erasers? | 16 | 30 254 30 [OP_MOD] [OP_SUB] | var_a = 30
var_b = 254
var_c = 30
var_d = var_b % var_c
var_e = var_a - var_d
print(int(var_e)) |
Comparison | Seonho has 1 more marble than Minjeong. Jinyoung has 3 fewer than Joohwan , Minjeong has 6 marbles, and Joohwan has 7 marbles. Which of these has the fewest marbles? | Jinyoung | [OP_LIST_SOL] Minjeong Joohwan Seonho Jinyoung [OP_LIST_EOL] [OP_LIST_SOL] 6 7 6 1 [OP_SUB] 7 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Minjeong'
var_b = 'Joohwan'
var_c = 'Seonho'
var_d = 'Jinyoung'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 6
var_f = 7
var_g = 6
var_h = 1
var_i = var_g - var_h
var_j = 7
var_k = 3
var_l = var_j - var_k
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[var_m-1]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p) |
Arithmetic calculation | You want to divide 10.4 kilograms (kg) of flour into 0.8 kilograms (kg) of each bowl. How many bowls do you need? | 13 | 10.4 0.8 [OP_DIV] 1 [OP_CEIL] | var_a = 10.4
var_b = 0.8
var_c = var_a / var_b
var_d = 1
var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))
print(int(var_e)) |
Correspondence | ABC+ABC+ABC=888. If A, B, and C are all different single digit numbers, what is A? | 2 | ABC+ABC+ABC=888 A [OP_DIGIT_UNK_SOLVER] | var_a = 'ABC+ABC+ABC=888'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | You mistakenly distributed colored papers equally to 5 people instead of to 4 people, and each person got 15 papers and 2 papers were left. If you divide these papers equally to 4 people, how many papers will each person recieve at the maximum? | 19 | 5 15 [OP_MUL] 2 [OP_ADD] 4 [OP_FDIV] | var_a = 5
var_b = 15
var_c = var_a * var_b
var_d = 2
var_e = var_c + var_d
var_f = 4
var_g = var_e // var_f
print(int(var_g)) |
Geometry | When the go stones are lined up without gaps to form a large square, there are three go stones left. It is said that 44 more go stones are needed to increase each horizontal and vertical side of the square by 2 columns. How many go stones are there in all? | 103 | 44 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD] | var_a = 44
var_b = 4
var_c = var_a - var_b
var_d = 4
var_e = var_c / var_d
var_f = 2
var_g = var_e ** var_f
var_h = 3
var_i = var_g + var_h
print(int(var_i)) |
Arithmetic calculation | There are 445 yellow fish, which is 38 fewer than blue fish. How many yellow and blue fish are there altogether? | 928 | 445 445 38 [OP_ADD] [OP_ADD] | var_a = 445
var_b = 445
var_c = 38
var_d = var_b + var_c
var_e = var_a + var_d
print(int(var_e)) |
Possibility | Find the difference between the largest even number and the smallest odd number when forming a four-digit number using each of the four numbers 0, 1, 2, 3, 4, 5, and 6 only once. | 5519 | [OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] [OP_SET_DIFFERENCE] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
var_f = 5
var_g = 6
list_a= []
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_h = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_h))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_i = 2
list_c = []
var_i = int(var_i)
for i in list_b:
i = int(i)
if i % var_i == 0:
list_c.append(i)
var_j = 1
list_d=list_c.copy()
list_d.sort()
var_k = list_d[-var_j]
list_e = list(set(list_b) - set(list_c))
var_l = 1
list_f=list_e.copy()
list_f.sort()
var_m = list_f[var_l-1]
var_n = var_k - var_m
print(int(var_n)) |
Correspondence | When this number is divided by 9, the result came out as 8. What do you get when you add 11 to this number? | 83 | 8 9 [OP_MUL] 11 [OP_ADD] | var_a = 8
var_b = 9
var_c = var_a * var_b
var_d = 11
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | There are 5 boxes of 14 red marbles per box and 9 boxes of 14 blue marbles per box. How many more blue marbles are there than red marbles? | 56 | 14 9 [OP_MUL] 14 5 [OP_MUL] [OP_SUB] | var_a = 14
var_b = 9
var_c = var_a * var_b
var_d = 14
var_e = 5
var_f = var_d * var_e
var_g = var_c - var_f
print(int(var_g)) |
Comparison | Students are standing in a line at the bus stop. When Minseok is standing 12th from the front and Junho is standing 9th from the back, Junho is standing right behind Minseok. Find the total number of students standing in line at the bus stop. | 21 | 12 9 [OP_ADD] | var_a = 12
var_b = 9
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | There were 8 marbles before, but only 6 are in the bag now. How many marbles are lost? | 2 | 8 6 [OP_SUB] | var_a = 8
var_b = 6
var_c = var_a - var_b
print(int(var_c)) |
Geometry | How many boxes are needed to make a cube by stacking cuboid-shaped boxes with a width of 18 centimeters (cm), a length of 12 centimeters (cm), and a height of 9 centimeters (cm), in minimum? | 24 | 18 12 [OP_LCM] 9 [OP_LCM] 18 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 12 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 9 [OP_DIV] [OP_MUL] [OP_MUL] | var_a = 18
var_b = 12
var_c = var_b * var_a / math.gcd(int(var_b), int(var_a))
var_d = 9
var_e = var_d * var_c / math.gcd(int(var_d), int(var_c))
var_f = 18
var_g = var_e / var_f
var_h = 18
var_i = 12
var_j = var_i * var_h / math.gcd(int(var_i), int(var_h))
var_k = 9
var_l = var_k * var_j / math.gcd(int(var_k), int(var_j))
var_m = 12
var_n = var_l / var_m
var_o = 18
var_p = 12
var_q = var_p * var_o / math.gcd(int(var_p), int(var_o))
var_r = 9
var_s = var_r * var_q / math.gcd(int(var_r), int(var_q))
var_t = 9
var_u = var_s / var_t
var_v = var_n * var_u
var_w = var_g * var_v
print(int(var_w)) |
Arithmetic calculation | There are 15 cucumbers in the mart. There are three times as many radishes as there are cucumbers. There are 9 carrots. How many times the number of radishes is equal to the number of carrots? | 5 | 15 3 [OP_MUL] 9 [OP_DIV] | var_a = 15
var_b = 3
var_c = var_a * var_b
var_d = 9
var_e = var_c / var_d
print(int(var_e)) |
Possibility | How many ways are there to line up 5 students? | 120 | 5 5 [OP_PERM] | var_a = 5
var_b = 5
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
print(int(var_c)) |
Correspondence | A is a number from 1 to 9, and B is a number from 0 to 9, and AB40C is a multiple of 45. How many five-digit numbers like this can you think of? | 20 | AB40C [OP_GEN_POSSIBLE_LIST] 45 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 'AB40C'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 45
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = len(list_b)
print(int(var_c)) |
Arithmetic calculation | There are five numbers 10, 11, 12, 13, and 14. What is the quotient of the largest number divided by the second largest number? | 1 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
list_b=list_a.copy()
list_b.sort()
var_g = list_b[-var_f]
var_h = 2
list_c=list_a.copy()
list_c.sort()
var_i = list_c[-var_h]
var_j = var_g // var_i
print(int(var_j)) |
Arithmetic calculation | It takes 6.64 kg (kg) of glutinous rice flour to make one glutinous rice cake. How many glutinous rice cakes can you make with 212.48 kg (kg) of glutinous rice flour? | 32 | 212.48 6.64 [OP_FDIV] | var_a = 212.48
var_b = 6.64
var_c = var_a // var_b
print(int(var_c)) |
Comparison | The distance from Ahyeon's house to grandma's house is 7150 meters (m), and the distance to aunt's house is 6 kilometers (km) and 720 meters (m). Find out which of grandmother's house or aunt's house is closer to Ahyeon's house. | aunt | [OP_LIST_SOL] grandma aunt [OP_LIST_EOL] [OP_LIST_SOL] 7150 6 1000 [OP_MUL] 720 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'grandma'
var_b = 'aunt'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 7150
var_d = 6
var_e = 1000
var_f = var_d * var_e
var_g = 720
var_h = var_f + var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | Joonyoung jumped rope 56 times a month for 3 months and Namyoung did 35 times a month for 4 months. How many times did Junyoung and Namyeong jump rope? | 308 | 56 3 [OP_MUL] 35 4 [OP_MUL] [OP_ADD] | var_a = 56
var_b = 3
var_c = var_a * var_b
var_d = 35
var_e = 4
var_f = var_d * var_e
var_g = var_c + var_f
print(int(var_g)) |
Comparison | Suppose there are seven numbers 1.7, 1/5, 1/5, 1, 3/5, 3/8, and 1.4. Which of these numbers is the fourth largest? | 0.6 | [OP_LIST_SOL] 1.7 1/5 1/5 1 3/5 3/8 1.4 [OP_LIST_EOL] 4 [OP_LIST_MAX] | var_a = 1.7
var_b = 0.2
var_c = 0.2
var_d = 1
var_e = 0.6
var_f = 0.375
var_g = 1.4
list_a= []
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_h = 4
list_b=list_a.copy()
list_b.sort()
var_i = list_b[-var_h]
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Geometry | Five rows of eight square tiles each measuring 30 centimeters (cm) in width and 30 centimeters (cm) in length were attached to the floor. How many square meters (m2) is the tiled floor? | 3.6 | 30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL] | var_a = 30
var_b = 100
var_c = var_a / var_b
var_d = 2
var_e = var_c ** var_d
var_f = 8
var_g = var_e * var_f
var_h = 5
var_i = var_g * var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Possibility | You are to pick 2 cards at the same time out of 9 cards numbered 1 through 9. Find how many ways there are the sum of the two cards is 3. | 1 | 1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 3 [OP_LIST_FIND_NUM] 2 [OP_DIV] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 3
var_g = 0
var_f = int(var_f)
for i in list_c:
i = int(i)
if i == var_f:
var_g = var_g + 1
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Arithmetic calculation | Twelve students are about to line up on the playground. The total length of the playground is 200 meters (m) and students must keep 20 meters (m) apart. How many students can line up in total? | 2 | 12 200 20 [OP_DIV] [OP_SUB] | var_a = 12
var_b = 200
var_c = 20
var_d = var_b / var_c
var_e = var_a - var_d
print(int(var_e)) |
Arithmetic calculation | Ho-seok and Min-yeong ran 34 laps around the playground. How many more laps does Min-yeong have to make to equal the number of times Hoseok ran? | 17 | 51 34 [OP_SUB] | var_a = 51
var_b = 34
var_c = var_a - var_b
print(int(var_c)) |
Geometry | Mijin made a regular pentagon with a side of 16 centimeters (cm) long using wire. When she stretches out this wire again and uses all of it to make a regular octagon, find the length of one side of this regular octagon. | 10 | 16 5 [OP_MUL] 8 [OP_DIV] | var_a = 16
var_b = 5
var_c = var_a * var_b
var_d = 8
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | Find the number between 4 and 9 that is less than 6. | 4 | 4 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_LESS] 1 [OP_LIST_GET] | var_a = 4
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 6
list_b = []
for i in list_a:
if i < var_d:
list_b.append(i)
var_e = 1
var_f = list_b[var_e-1]
print(int(var_f)) |
Comparison | Jinho and Youngsu have a pencil respectively. Jinho lost 3 out of 9 pencils, and Youngsu gave 7 out of 14 pencils to his younger brother. Who has more pencils between Jinho and Youngsu? | Youngsu | [OP_LIST_SOL] Jinho Youngsu [OP_LIST_EOL] [OP_LIST_SOL] 9 3 [OP_SUB] 14 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jinho'
var_b = 'Youngsu'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 9
var_d = 3
var_e = var_c - var_d
var_f = 14
var_g = 7
var_h = var_f - var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | Yuna went to the stationery store and bought a notebook with half of the money she took, and a pencil with half of the rest, and she had 800 won left. How much money did Yuna take with her in the beginning? | 3200 | 800 2 [OP_MUL] 2 [OP_MUL] | var_a = 800
var_b = 2
var_c = var_a * var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Comparison | Several children are sitting in a circle equally spaced. The 15th child sitting clockwise from a standard child is facing the child who is the standard. How many children are there in total? | 30 | 15 1 [OP_SUB] 2 [OP_MUL] 2 [OP_ADD] | var_a = 15
var_b = 1
var_c = var_a - var_b
var_d = 2
var_e = var_c * var_d
var_f = 2
var_g = var_e + var_f
print(int(var_g)) |
Correspondence | Given two different numbers A and B that satisfy 6A-B2=36, what is the value of subtracting B from A? | 5 | 6A-B2=36 A [OP_DIGIT_UNK_SOLVER] 6A-B2=36 B [OP_DIGIT_UNK_SOLVER] [OP_SUB] | var_a = '6A-B2=36'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = '6A-B2=36'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = var_c - var_f
print(int(var_g)) |
Possibility | There are 4 balls numbered 1, 2, 3 and 5. Find the sum of the numbers divisible by 7 when you pick two balls and use them only once to form a two-digit number. | 56 | [OP_LIST_SOL] 1 2 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] [OP_LIST_SUM] | var_a = 1
var_b = 2
var_c = 3
var_d = 5
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 7
list_c = []
var_f = int(var_f)
for i in list_b:
i = int(i)
if i % var_f == 0:
list_c.append(i)
list_c = [float(i) for i in list_c]
var_g = sum(list_c)
print(int(var_g)) |
Comparison | There is a refrigerator that has bowl A, B, and C full of food. Bowl B has more food than bowl A, and bowl C has more food than bowl B. When you try to empty the bowl with the least food in it, which bowl is emptied first? | A | [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] B A > C B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'B'
var_e = 'A'
var_f = '>'
var_g = 'C'
var_h = 'B'
var_i = '>'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = len(list_c)
var_k = list_c[var_j-1]
print(var_k) |
Arithmetic calculation | There are 6 giraffes, 8 pigs and 4 dogs. How many animals are there in total? | 18 | 6 8 [OP_ADD] 4 [OP_ADD] | var_a = 6
var_b = 8
var_c = var_a + var_b
var_d = 4
var_e = var_c + var_d
print(int(var_e)) |
Geometry | A rectangular prism with a volume of 252 cubic centimeters (cm3) was made by stacking 36 stacking blocks with a volume of 1 cubic centimeter (cm3). How many layers are there in this cuboid's stacking blocks? | 7 | 252 36 1 [OP_MUL] [OP_DIV] | var_a = 252
var_b = 36
var_c = 1
var_d = var_b * var_c
var_e = var_a / var_d
print(int(var_e)) |
Possibility | I am trying to create a two-digit number by using two numbers 1 and 9 allowing for repetition. How many two-digit numbers can you make? | 4 | [OP_LIST_SOL] 1 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN] | var_a = 1
var_b = 9
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = len(list_b)
print(int(var_d)) |
Possibility | If there are 6 students A, B, C, D, E, and F, find the number of ways to elect 1 president, 1 vice president, and 1 manager. | 120 | 6 1 1 [OP_ADD] 1 [OP_ADD] [OP_PERM] | var_a = 6
var_b = 1
var_c = 1
var_d = var_b + var_c
var_e = 1
var_f = var_d + var_e
var_g = 1
var_a = int(var_a)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_a-i)
print(int(var_g)) |
Geometry | Find the number of vertices of the regular hexagonal pyramid. | 7 | 6 1 [OP_ADD] | var_a = 6
var_b = 1
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | You want to buy cucumbers for 7,500 won. Cucumbers are currently sold at 300 won per 100 grams (g). Find how many kilograms (kg) of cucumbers you can buy with your current money, including the digits after the decimal point. | 2.5 | 7500 100 300 [OP_DIV] [OP_MUL] 1000 [OP_DIV] | var_a = 7500
var_b = 100
var_c = 300
var_d = var_b / var_c
var_e = var_a * var_d
var_f = 1000
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Geometry | The area of a trapezoid is 96.9 square centimeters (cm2). If the top side is 3.6 centimeters (cm) longer than the bottom side and the height is 5.2 centimeters (cm), what is the length of the bottom side in centimeters (cm)? | 16.85 | 96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV] | var_a = 96.98
var_b = 2
var_c = var_a * var_b
var_d = 5.2
var_e = var_c / var_d
var_f = 3.6
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.