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Arithmetic calculation | Moving any decimal point two places to the right increases it by 29.7. Find the original decimal. | 0.3 | 29.7 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV] | var_a = 29.7
var_b = 10
var_c = 2
var_d = var_b ** var_c
var_e = 1
var_f = var_d - var_e
var_g = var_a / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Arithmetic calculation | There are 3 watermelons and 7 apples. How many melons are there when the number of melons is twice the sum of the number of watermelons and apples? | 20 | 3 7 [OP_ADD] 2 [OP_MUL] | var_a = 3
var_b = 7
var_c = var_a + var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Possibility | You want to create a three-digit number by drawing three from 0, 2, 4, and 6 and using them only once. Find the sum of the largest and smallest possible numbers. | 846 | [OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD] | var_a = 0
var_b = 2
var_c = 4
var_d = 6
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 1
list_d=list_b.copy()
list_d.sort()
var_i = list_d[var_h-1]
var_j = var_g + var_i
print(int(var_j)) |
Comparison | Yuna was 77th in line at a market, there were 15 people between Yuna and Yoojeong, who was ahead of Yuna. In what place is Yoojeong standing in line? Express in ordinal number. | 61 | 77 15 [OP_SUB] 1 [OP_SUB] | var_a = 77
var_b = 15
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Correspondence | Hoseok subtracted 7 from a number to get 9, then multiplied this number by 3. What is the result Hoseok would get? | 48 | 9 7 [OP_ADD] 3 [OP_MUL] | var_a = 9
var_b = 7
var_c = var_a + var_b
var_d = 3
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | Shinyoung saved 1/2 of her mother's pocket money and bought school supplies with the remaining 3/8, leaving 2,500 won. How much money does Shinyoung save? | 4000 | 2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL] | var_a = 2500
var_b = 1
var_c = 0.375
var_d = var_b - var_c
var_e = var_a / var_d
var_f = 0.5
var_g = var_e / var_f
var_h = 0.5
var_i = var_g * var_h
print(int(var_i)) |
Correspondence | If a number multiplied by -2/3 and divided by -4/5 equals -1/2, what number is it? | -0.6 | -1/2 -4/5 [OP_MUL] -2/3 [OP_DIV] | var_a = -0.5
var_b = -0.8
var_c = var_a * var_b
var_d = -0.6666666666666666
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Possibility | There are 4 female students and 3 male students. If one female student and one male student want to be in charge of weekly duty, in how many ways can you choose students to be in charge of weekly duty? | 12 | 4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL] | var_a = 4
var_b = 1
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
var_d = 3
var_e = 1
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
for i, elem in enumerate(range(var_e)):
var_f = var_f / (i+1)
var_g = var_c * var_f
print(int(var_g)) |
Arithmetic calculation | What is the sum of 1.48, 2.32, and 8.45? | 12.25 | 1.48 2.32 [OP_ADD] 8.45 [OP_ADD] | var_a = 1.48
var_b = 2.32
var_c = var_a + var_b
var_d = 8.45
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | It is said that water comes out of the faucet at 36.6 liters (L) per minute. It is also said that 2.4 liters (L) of water evaporates per minute. If there were 10 liters (L) of water at the beginning, how many liters (L) will there be after 7 minutes and 45 seconds? | 275.05 | 10 36.6 2.4 [OP_SUB] 7 45 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_ADD] | var_a = 10
var_b = 36.6
var_c = 2.4
var_d = var_b - var_c
var_e = 7
var_f = 45
var_g = 60
var_h = var_f / var_g
var_i = var_e + var_h
var_j = var_d * var_i
var_k = var_a + var_j
print('{:.2f}'.format(round(var_k+1e-10,2))) |
Arithmetic calculation | Moving the decimal point of a decimal number three digits left makes it 2.71 smaller than it originally was. Find the original decimal number. | 2.71 | 2.71 1 0.1 3 [OP_POW] [OP_SUB] [OP_DIV] | var_a = 2.71
var_b = 1
var_c = 0.1
var_d = 3
var_e = var_c ** var_d
var_f = var_b - var_e
var_g = var_a / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Arithmetic calculation | Taehyung solved the workbook with 161 problems for 7 days. Find the average number of problems Taehyung solved per day. | 23 | 161 7 [OP_DIV] | var_a = 161
var_b = 7
var_c = var_a / var_b
print(int(var_c)) |
Correspondence | A number minus 8 equals 5 times 7 plus 12. Find the value of the number. | 55 | 5 7 [OP_MUL] 12 [OP_ADD] 8 [OP_ADD] | var_a = 5
var_b = 7
var_c = var_a * var_b
var_d = 12
var_e = var_c + var_d
var_f = 8
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | Yoongi's school has 280 students, 127 of which are female students. Find how many more male students than female students in Yoongi's school. | 26 | 280 127 [OP_SUB] 127 [OP_SUB] | var_a = 280
var_b = 127
var_c = var_a - var_b
var_d = 127
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | Mingi's math test covers from page 8 to page 21 of the textbook. How many pages is it in total? | 14 | 8 21 1 [OP_LIST_ARANGE] [OP_LIST_LEN] | var_a = 8
var_b = 21
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = len(list_a)
print(int(var_d)) |
Correspondence | In the three-digit addition expression 7A5+B7C=D38, A through D are different numbers. How much is D? | 9 | 7A5+B7C=D38 D [OP_DIGIT_UNK_SOLVER] | var_a = '7A5+B7C=D38'
var_b = 'D'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Comparison | In the swimming competition, my sister crossed the finish line in 51st place, and my grandfather crossed the finish line in 53rd place. I was better than my grandfather but worse than my sister. What is my rank? | 52 | 51 53 [OP_ADD] 2 [OP_FDIV] | var_a = 51
var_b = 53
var_c = var_a + var_b
var_d = 2
var_e = var_c // var_d
print(int(var_e)) |
Arithmetic calculation | When there are five different numbers: 10, 11, 12, 13, and 14, what is the quotient of the largest number divided by the smallest number? | 1 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
list_b=list_a.copy()
list_b.sort()
var_g = list_b[-var_f]
var_h = 1
list_c=list_a.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = var_g // var_i
print(int(var_j)) |
Comparison | Yoongi has 4, and Yuna has 5, and Jungkook has 6 minus 3. Who has the biggest number? | Yuna | [OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Yuna'
var_c = 'Jungkook'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 5
var_f = 6
var_g = 3
var_h = var_f - var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | What is the sum of 15.58, 21.32, 642.51, and 51.51? | 730.92 | 15.58 21.32 [OP_ADD] 642.51 [OP_ADD] 51.51 [OP_ADD] | var_a = 15.58
var_b = 21.32
var_c = var_a + var_b
var_d = 642.51
var_e = var_c + var_d
var_f = 51.51
var_g = var_e + var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Comparison | 20 students are waiting for the bus. Jungkook came before Yoongi, and there are 5 students between Yoongi and Jungkook. There are 6 students standing in front of Jungkook. How many students are standing behind Yoongi? | 7 | 20 6 [OP_SUB] 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB] | var_a = 20
var_b = 6
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
var_f = 5
var_g = var_e - var_f
var_h = 1
var_i = var_g - var_h
print(int(var_i)) |
Possibility | If there are 5 people, A, B, C, D, and E, find the number of ways to put C and D next to each other. | 48 | [OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL] | var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
var_e = 'E'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 'C'
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
list_c = list(set(list_a) - set(list_b))
var_g = len(list_c)
var_h = len(list_c)
var_i = 1
var_g = int(var_g)
var_h = int(var_h)
for i, elem in enumerate(range(var_h)):
var_i = var_i * (var_g-i)
var_j = 'C'
var_k = 'D'
list_d= []
if "/" in str(var_k):
var_k = eval(str(var_k))
list_d.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_d.append(var_j)
list_d.reverse()
var_l = len(list_d)
var_m = len(list_d)
var_n = 1
var_l = int(var_l)
var_m = int(var_m)
for i, elem in enumerate(range(var_m)):
var_n = var_n * (var_l-i)
var_o = var_i * var_n
print(int(var_o)) |
Correspondence | When Hyejin's age is multiplied by Hyejin's younger sister's age, and the result is 12, how many possible numbers can there be with Hyejin's age? | 3 | 12 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_FDIV] | var_a = 12
list_a = []
num_sqrt = int(math.sqrt(var_a))
for i in range(1, num_sqrt+1):
if var_a % i == 0:
list_a.append(i)
list_a.append(int(var_a/i))
list_a = sorted(set(list_a))
var_b = len(list_a)
var_c = 2
var_d = var_b // var_c
print(int(var_d)) |
Possibility | Find the number of natural numbers that can be made with three of the number cards 1, 2, 4, 8, and 9. | 60 | [OP_LIST_SOL] 1 2 4 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 1
var_b = 2
var_c = 4
var_d = 8
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = len(list_b)
print(int(var_g)) |
Comparison | In a PE class, if there are 5 and 6 rows of students on either side of Mijoo, and 6 and 7 rows of students in front of and behind her, respectively, and the number of students in each row is the same, how many students are in PE class in total? | 168 | 5 6 [OP_ADD] 1 [OP_ADD] 6 7 [OP_ADD] 1 [OP_ADD] [OP_MUL] | var_a = 5
var_b = 6
var_c = var_a + var_b
var_d = 1
var_e = var_c + var_d
var_f = 6
var_g = 7
var_h = var_f + var_g
var_i = 1
var_j = var_h + var_i
var_k = var_e * var_j
print(int(var_k)) |
Comparison | There are 40 baskets of tangerines, 28 each, and 65 baskets of plums, 15 each. Which one has the bigger number among tangerines and plums? | tangerines | [OP_LIST_SOL] tangerines plums [OP_LIST_EOL] [OP_LIST_SOL] 28 40 [OP_MUL] 15 65 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'tangerines'
var_b = 'plums'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 28
var_d = 40
var_e = var_c * var_d
var_f = 15
var_g = 65
var_h = var_f * var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Comparison | The five numbers 1.4, 9/10, 1.1, 0.5, and 13/10 are written on the blackboard. How many of the numbers written on the board are greater than 0.9? | 3 | [OP_LIST_SOL] 1.4 9/10 1.1 0.5 13/10 [OP_LIST_EOL] 0.9 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 1.4
var_b = 0.9
var_c = 1.1
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 0.9
list_b = []
for i in list_a:
if i > var_f:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Arithmetic calculation | How many numbers that are greater than 50 and less than 100 have a remainder of 4 when divided by 8? | 7 | 50 100 1 [OP_LIST_ARANGE] 8 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN] | var_a = 50
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 8
var_e = 4
list_b = []
var_d = int(var_d)
var_e = int(var_e)
if var_e < 0:
var_e = var_e + var_d
for i in list_a:
i = int(i)
if i%var_d == var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Correspondence | If you divide the chopsticks used by 8 people into 4 groups, how many bundles will you get? | 4 | 8 2 [OP_MUL] 4 [OP_DIV] | var_a = 8
var_b = 2
var_c = var_a * var_b
var_d = 4
var_e = var_c / var_d
print(int(var_e)) |
Geometry | If the perimeter of a rectangle whose width is 3 centimeters (cm) longer than its length is 54 centimeters (cm), find the length of its width. | 15 | 54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD] | var_a = 54
var_b = 2
var_c = var_a / var_b
var_d = 3
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 3
var_i = var_g + var_h
print(int(var_i)) |
Possibility | How many three-digit integers can be made by drawing 3 out of 6 cards with the numbers 0, 1, 2, 3, 4, and 5 written on them? | 100 | [OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
var_f = 5
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_g))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_h = len(list_b)
print(int(var_h)) |
Correspondence | Seokgi gave 1/2 of the candies he had to Yeseul, and gave the remaining 1/3 to Dongmin, leaving 12 candies. How many candies did Seokgi originally have at first? | 36 | 12 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV] | var_a = 12
var_b = 1
var_c = 0.3333333333333333
var_d = var_b - var_c
var_e = var_a / var_d
var_f = 1
var_g = 0.5
var_h = var_f - var_g
var_i = var_e / var_h
print(int(eval('{:.2f}'.format(round(var_i+1e-10,2))))) |
Arithmetic calculation | A car needs 12.2 liters (L) of gasoline to run 366.8 kilometers (km), and the amount of gasoline in one oil drum is 3 liters (L). How many barrels of oil are needed to drive 533.32 kilometers (km)? | 6 | 12.2 366.8 [OP_DIV] 533.32 [OP_MUL] 3 [OP_DIV] 1 [OP_CEIL] | var_a = 12.2
var_b = 366.8
var_c = var_a / var_b
var_d = 533.32
var_e = var_c * var_d
var_f = 3
var_g = var_e / var_f
var_h = 1
var_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))
print(int(var_i)) |
Correspondence | There are two different numbers A and B. What is A+B when BBB+BBBB=8AA4? | 12 | 8AA4-BBB=BBBB A [OP_DIGIT_UNK_SOLVER] 8AA4-BBB=BBBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD] | var_a = '8AA4-BBB=BBBB'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = '8AA4-BBB=BBBB'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = var_c + var_f
print(int(var_g)) |
Arithmetic calculation | How many two-digit numbers are there that are between 45 and 54?
| 8 | 45 1 [OP_ADD] 54 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN] | var_a = 45
var_b = 1
var_c = var_a + var_b
var_d = 54
var_e = 1
var_f = var_d - var_e
var_g = 1
list_a = [i for i in range(var_c, var_f + 1, var_g)]
var_h = len(list_a)
print(int(var_h)) |
Arithmetic calculation | There are three numbers: 10, 11 and 12. What is the remainder when you divide the second largest number by the smallest number? | 1 | [OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MOD] | var_a = 10
var_b = 11
var_c = 12
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b=list_a.copy()
list_b.sort()
var_e = list_b[-var_d]
var_f = 1
list_c=list_a.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = var_e % var_g
print(int(var_h)) |
Geometry | The length of all four sides of a quadrilateral is the same and the sum of the lengths of the four sides is 32. What is the length of one side? | 8 | 32 4 [OP_DIV] | var_a = 32
var_b = 4
var_c = var_a / var_b
print(int(var_c)) |
Possibility | There are two ways to get to the playground from school. Find the number of cases in which Seung-a, Jeong-hyeok, and Hyeong-jun go from school to the playground. | 8 | 2 3 [OP_POW] | var_a = 2
var_b = 3
var_c = var_a ** var_b
print(int(var_c)) |
Geometry | If the horizontal length of the entire figure drawn by attaching several circles with a radius of 4 centimeters (cm) side by side is 24 centimeters (cm), how many circles are drawn? | 3 | 24 4 2 [OP_MUL] [OP_DIV] | var_a = 24
var_b = 4
var_c = 2
var_d = var_b * var_c
var_e = var_a / var_d
print(int(var_e)) |
Arithmetic calculation | There are 5 times as many blue marbles as red marbles, and yellow marbles are three times more than red marbles. If the total number of blue marbles and yellow marbles is 160, how many red marbles are there? | 20 | 160 5 3 [OP_ADD] [OP_DIV] | var_a = 160
var_b = 5
var_c = 3
var_d = var_b + var_c
var_e = var_a / var_d
print(int(var_e)) |
Arithmetic calculation | I made 8640 of (a) items. I put 12 items in each small box, and put 6 of these small boxes in a big box. How many big boxes did I pack in total? | 120 | 8640 12 [OP_DIV] 6 [OP_DIV] | var_a = 8640
var_b = 12
var_c = var_a / var_b
var_d = 6
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | There are 40 ducks and 30 rabbits on the farm. Also, the number of hens is 20 more than ducks, and the number of roosters is 10 fewer than rabbits. How many chickens are there in the farm totally? | 80 | 40 20 [OP_ADD] 30 10 [OP_SUB] [OP_ADD] | var_a = 40
var_b = 20
var_c = var_a + var_b
var_d = 30
var_e = 10
var_f = var_d - var_e
var_g = var_c + var_f
print(int(var_g)) |
Arithmetic calculation | The younger brother is 28 centimeters (cm) shorter than Minkyung, and the father is 35 centimeters (cm) taller than Minkyung. If the father's height is 1 meter (m) 72 centimeters (cm), how tall is the younger brother in centimeters (cm)? | 109 | 1 100 [OP_MUL] 72 [OP_ADD] 35 [OP_SUB] 28 [OP_SUB] | var_a = 1
var_b = 100
var_c = var_a * var_b
var_d = 72
var_e = var_c + var_d
var_f = 35
var_g = var_e - var_f
var_h = 28
var_i = var_g - var_h
print(int(var_i)) |
Correspondence | For the natural number A, find all sums of A such that 3<2×A<19 | 44 | 3<2×A<19 A [OP_NUM_UNK_SOLVER] [OP_LIST_SUM] | var_a = '3<2×A<19'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = []
candidate_num = [i for i in range(51)]
candi = list(itertools.product(candidate_num, repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
if term_list[i] == '':
new_eq += str(term_list[i])+op_list[i]
else:
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:
new_eq=new_eq.replace('==','=')
new_eq=new_eq.replace('>','')
new_eq=new_eq.replace('<','')
new_eq=new_eq.split('=')
for i in range(len(new_eq)-1):
eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))
if not eval_result:
break
else:
eval_result = eval(new_eq)
except:
eval_result = False
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k].append(int(c[i]))
list_a = list(set(ans_dict[var_b]))
list_a = [float(i) for i in list_a]
var_c = sum(list_a)
print(int(var_c)) |
Possibility | Donghyun chooses three different number cards from 0 to 9 and uses them all to make a three-digit number. This time, he made the third smallest number where the tens digit of this number is 1. What is the sum of the hundreds digit and the ones digit? | 4 | 0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] [OP_NUM2LIST] 2 [OP_LIST_GET] 3 [OP_LIST_GET] [OP_ADD] | var_a = 0
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 3
list_c=list_b.copy()
list_c.sort()
var_f = list_c[var_e-1]
list_d = []
var_f = int(var_f)
while var_f//10 > 0:
list_d.append(var_f%10)
var_f = var_f//10
list_d.append(var_f%10)
list_d = list_d[::-1]
var_g = 2
var_h = list_d[var_g-1]
var_i = 3
var_j = list_d[var_i-1]
var_k = var_h + var_j
print(int(var_k)) |
Arithmetic calculation | Mingyu bought 3 erasers for 350 won each and 2 pencils for 180 won each at the stationery store and paid 2,000 won. Find how much change Mingyu should receive. | 590 | 2000 350 3 [OP_MUL] 180 2 [OP_MUL] [OP_ADD] [OP_SUB] | var_a = 2000
var_b = 350
var_c = 3
var_d = var_b * var_c
var_e = 180
var_f = 2
var_g = var_e * var_f
var_h = var_d + var_g
var_i = var_a - var_h
print(int(var_i)) |
Possibility | How many fractions of the same size as 7/8 have two-digit denominators? | 11 | 10 99 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 10
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 8
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = len(list_b)
print(int(var_e)) |
Arithmetic calculation | How many two-digit numbers are both multiples of 3 and multiples of 5? | 6 | 10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 10
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = len(list_c)
print(int(var_f)) |
Arithmetic calculation | 72 students in total are participating in after-school activities. Of these, one-fourth are taking the after-school English class, and one-third of the students taking the after-school English classes are 6th-grade students. How many 6th-grade students are taking the after-school English class? | 6 | 72 1 4 [OP_DIV] [OP_MUL] 1 3 [OP_DIV] [OP_MUL] | var_a = 72
var_b = 1
var_c = 4
var_d = var_b / var_c
var_e = var_a * var_d
var_f = 1
var_g = 3
var_h = var_f / var_g
var_i = var_e * var_h
print(int(var_i)) |
Geometry | A square was created by arranging 12 coins of the same size regularly, horizontally and vertically, without any gaps. How many coins are placed around the perimeter? | 44 | 12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD] | var_a = 12
var_b = 2
var_c = var_a - var_b
var_d = 4
var_e = var_c * var_d
var_f = 4
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | Yoongi has 5 dogs and 2 cats, respectively. How many dogs and cats do Yoongi have? | 7 | 5 2 [OP_ADD] | var_a = 5
var_b = 2
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | There is a four-digit number 7AA1 that is divisible by 9 without any remainder. Find the possible four digit number. | 7551 | 7AA1 [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] | var_a = '7AA1'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 9
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c=""
for i in list_b:
i = str(i)
var_c = var_c + i
print(int(var_c)) |
Geometry | You are trying to wrap a cube-shaped side dish container. In order to wrap this side dish container without overlapping, wrapping paper with a width of 600 is required. Find the volume of this side dish container. | 1000 | 600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW] | var_a = 600
var_b = 6
var_c = var_a / var_b
var_d = 0.5
var_e = var_c ** var_d
var_f = 3
var_g = var_e ** var_f
print(int(var_g)) |
Arithmetic calculation | How many times does the number 8 appear in the numbers 10 through 99? | 19 | 10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM] | var_a = 10
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
list_b = []
var_d = int(var_d)
while var_d//10 > 0:
list_b.append(var_d%10)
var_d = var_d//10
list_b.append(var_d%10)
list_b = list_b[::-1]
var_e = 8
var_f = 0
var_e = int(var_e)
for i in list_b:
i = int(i)
if i == var_e:
var_f = var_f + 1
print(int(var_f)) |
Correspondence | If you fill the pool full of water, it will take 8050 liters (L). If the currently empty swimming pool is filled with 80.5 liters (L) of water, find how full the pool is. | 0.01 | 80.5 8050 [OP_DIV] | var_a = 80.5
var_b = 8050
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | Multiples of 4 that are greater than 0 and less than 100 are written sequentially. How many natural numbers are between the 5th number and the 8th number? | 11 | 0 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_MIN] 8 [OP_LIST_MAX] [OP_LIST_LESS] [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = var_a + var_b
var_d = 100
var_e = 1
var_f = var_d - var_e
var_g = 1
list_a = [i for i in range(var_c, var_f + 1, var_g)]
var_h = 4
list_b = []
var_h = int(var_h)
for i in list_a:
i = int(i)
if i % var_h == 0:
list_b.append(i)
var_i = 5
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = 8
list_d=list_b.copy()
list_d.sort()
var_l = list_d[-var_k]
list_e = []
for i in list_b:
if i < var_l:
list_e.append(i)
list_f = []
for i in list_e:
if i > var_j:
list_f.append(i)
var_m = len(list_f)
print(int(var_m)) |
Arithmetic calculation | How many five-digit numbers are common multiples of 2, 3, 8, and 9? | 1250 | 10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 10000
var_b = 99999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 2
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 3
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 8
list_d = []
var_f = int(var_f)
for i in list_c:
i = int(i)
if i % var_f == 0:
list_d.append(i)
var_g = 9
list_e = []
var_g = int(var_g)
for i in list_d:
i = int(i)
if i % var_g == 0:
list_e.append(i)
var_h = len(list_e)
print(int(var_h)) |
Arithmetic calculation | The marbles were divided into 8 bags. If six of these bags held 6 marbles, but the other two bags each held 7 marbles, what would be a total number of marbles? | 50 | 6 6 [OP_MUL] 2 7 [OP_MUL] [OP_ADD] | var_a = 6
var_b = 6
var_c = var_a * var_b
var_d = 2
var_e = 7
var_f = var_d * var_e
var_g = var_c + var_f
print(int(var_g)) |
Arithmetic calculation | Yeongchan's group consists of 7 people. One person can fold two paper cranes in one minute. How many minutes will it take Yeongchan's group to fold 182 paper cranes? | 13 | 182 7 2 [OP_MUL] [OP_DIV] | var_a = 182
var_b = 7
var_c = 2
var_d = var_b * var_c
var_e = var_a / var_d
print(int(var_e)) |
Possibility | Father, Mother, Minji and younger brother went to take pictures. Mother says she will take pictures with the younger brother on her back. How many different ways are there to take pictures side by side? | 6 | [OP_LIST_SOL] Father Mother Minji [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] | var_a = 'Father'
var_b = 'Mother'
var_c = 'Minji'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = len(list_a)
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
print(int(var_f)) |
Arithmetic calculation | Of the 36 students, 24 fewer students wear glasses than students who do not wear glasses. How many students wear glasses? | 6 | 36 24 [OP_SUB] 2 [OP_DIV] | var_a = 36
var_b = 24
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | There are four numbers 53, 98, 69, and 84. What is the difference between the largest number and the smallest number? | 45 | [OP_LIST_SOL] 53 98 69 84 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 53
var_b = 98
var_c = 69
var_d = 84
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 1
list_b=list_a.copy()
list_b.sort()
var_f = list_b[-var_e]
var_g = 1
list_c=list_a.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = var_f - var_h
print(int(var_i)) |
Correspondence | The value of the multiplication of the six-digit number ABCDEF and 5 is 665655. Find the sum of A, B, C, D, E, and F. | 12 | 665655 5 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM] | var_a = 665655
var_b = 5
var_c = var_a / var_b
list_a = []
var_c = int(var_c)
while var_c//10 > 0:
list_a.append(var_c%10)
var_c = var_c//10
list_a.append(var_c%10)
list_a = list_a[::-1]
list_a = [float(i) for i in list_a]
var_d = sum(list_a)
print(int(var_d)) |
Possibility | You can only get to home from school by bus or subway. There are a total of 7 ways to get there, and 4 for them is to take the bus. How many ways are there to take subway? | 3 | 7 4 [OP_SUB] | var_a = 7
var_b = 4
var_c = var_a - var_b
print(int(var_c)) |
Correspondence | Among 16, 18, 20, and 25, find the number that is divisible by 2 and 5 and is greater than 17. | 20 | [OP_LIST_SOL] 16 18 20 25 [OP_LIST_EOL] 17 [OP_LIST_MORE] 2 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET] | var_a = 16
var_b = 18
var_c = 20
var_d = 25
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 17
list_b = []
for i in list_a:
if i > var_e:
list_b.append(i)
var_f = 2
list_c = []
var_f = int(var_f)
for i in list_b:
i = int(i)
if i % var_f == 0:
list_c.append(i)
var_g = 5
list_d = []
var_g = int(var_g)
for i in list_c:
i = int(i)
if i % var_g == 0:
list_d.append(i)
var_h = 1
var_i = list_d[var_h-1]
print(int(var_i)) |
Geometry | What is the volume of a cube with a side of an area of 64 square centimeters (cm2) in cubic centimeters (cm3)? | 512 | 64 1/2 [OP_POW] 3 [OP_POW] | var_a = 64
var_b = 0.5
var_c = var_a ** var_b
var_d = 3
var_e = var_c ** var_d
print(int(var_e)) |
Correspondence | When you divide a number by 3, you get 3. Find this number. | 9 | 3 3 [OP_MUL] | var_a = 3
var_b = 3
var_c = var_a * var_b
print(int(var_c)) |
Possibility | How many integers less than 12 are multiples of 3? | 3 | 1 11 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 1
var_b = 11
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = len(list_b)
print(int(var_e)) |
Comparison | Taehyung, Namjoon, and Jimin bought apples at the fruit shop. If Taehyung bought more apples than Namjoon and Jimin bought more apples than Taehyung, who bought the most apples? | Jimin | [OP_LIST_SOL] Taehyung Namjoon Jimin [OP_LIST_EOL] [OP_LIST_SOL] Taehyung Namjoon > Jimin Taehyung > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'Taehyung'
var_b = 'Namjoon'
var_c = 'Jimin'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'Taehyung'
var_e = 'Namjoon'
var_f = '>'
var_g = 'Jimin'
var_h = 'Taehyung'
var_i = '>'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = 1
var_k = list_c[var_j-1]
print(var_k) |
Arithmetic calculation | The rental fee for a comic book is 4,000 won for 30 minutes. 6 students want to borrow 4 books in total for 3 hours. If all of these students are willing to pay the same amount, find the amount of money that a student should pay. | 16000 | 3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV] | var_a = 3
var_b = 60
var_c = var_a * var_b
var_d = 30
var_e = var_c / var_d
var_f = 4000
var_g = var_e * var_f
var_h = 4
var_i = var_g * var_h
var_j = 6
var_k = var_i / var_j
print(int(var_k)) |
Geometry | The sum of 4 sides of a rectangle equals 50 centimeters (cm). If the length of this rectangle is 13 centimeters (cm), what is the length of its width in centimeters (cm)? | 12 | 50 2 [OP_DIV] 13 [OP_SUB] | var_a = 50
var_b = 2
var_c = var_a / var_b
var_d = 13
var_e = var_c - var_d
print(int(var_e)) |
Correspondence | There are some numbers smaller than 20 that are not divisible by 2. Which number is it among 16, 18, 19, and 21? | 19 | [OP_LIST_SOL] 16 18 19 21 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 20 [OP_LIST_LESS] 1 [OP_LIST_GET] | var_a = 16
var_b = 18
var_c = 19
var_d = 21
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = []
var_e = int(var_e)
for i in list_a:
i = int(i)
if i % var_e == 0:
list_b.append(i)
list_c = list(set(list_a) - set(list_b))
var_f = 20
list_d = []
for i in list_c:
if i < var_f:
list_d.append(i)
var_g = 1
var_h = list_d[var_g-1]
print(int(var_h)) |
Arithmetic calculation | Jeongyeon and Joohyun have their heights measured. Jeongyeon's height is 1.06 times that of Joohyun, and Joohyun's height is 134.5 cm (cm). How tall is Jeongyeon? | 142.57 | 134.5 1.06 [OP_MUL] | var_a = 134.5
var_b = 1.06
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | When you round a 3-digit decimal to one decimal place, you get 3.5. Find the sum of the largest and smallest of these decimal numbers, including the decimal point. | 6.99 | 3.54 3.45 [OP_ADD] | var_a = 3.54
var_b = 3.45
var_c = var_a + var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | If you give 6 snacks to each of the 18 students, it's left, and if you give 7 snacks to each student, it's not enough. What is the maximum number of snacks? | 125 | 18 7 [OP_MUL] 1 [OP_SUB] | var_a = 18
var_b = 7
var_c = var_a * var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Possibility | Find the difference between the largest number and the third smallest number that can be made by changing the order of the digits in each place of 168. | 243 | 168 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] | var_a = 168
list_a = []
var_a = int(var_a)
while var_a//10 > 0:
list_a.append(var_a%10)
var_a = var_a//10
list_a.append(var_a%10)
list_a = list_a[::-1]
var_b = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_b))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_c = 1
list_c=list_b.copy()
list_c.sort()
var_d = list_c[-var_c]
var_e = 3
list_d=list_b.copy()
list_d.sort()
var_f = list_d[var_e-1]
var_g = var_d - var_f
print(int(var_g)) |
Correspondence | It is said that a number plus 72 is equal to twice the number divided by 2/3. Find the number. | 36 | 72 2 1 2/3 [OP_DIV] [OP_MUL] 1 [OP_SUB] [OP_DIV] | var_a = 72
var_b = 2
var_c = 1
var_d = 0.6666666666666666
var_e = var_c / var_d
var_f = var_b * var_e
var_g = 1
var_h = var_f - var_g
var_i = var_a / var_h
print(int(var_i)) |
Arithmetic calculation | Sehee needs 15 liters of milk to make bread with friends. If Sehee currently has only 7 liters (L) and 200 milliliters (mL) of milk at home, how many 600 milliliters (mL) of milk should she buy at least? | 13 | 15 1000 [OP_MUL] 7 1000 [OP_MUL] 200 [OP_ADD] [OP_SUB] 600 [OP_DIV] 1 [OP_CEIL] | var_a = 15
var_b = 1000
var_c = var_a * var_b
var_d = 7
var_e = 1000
var_f = var_d * var_e
var_g = 200
var_h = var_f + var_g
var_i = var_c - var_h
var_j = 600
var_k = var_i / var_j
var_l = 1
var_m=int(((var_k+9*10**(var_l-2))//(10**(var_l-1)))*10**(var_l-1))
print(int(var_m)) |
Comparison | The length of one edge of a cube (a) is 5 centimeters (cm). A rectangular parallelepiped (b) is 4 centimeters (cm), 5 centimeters (cm), and 6 centimeters (cm) in width, length, and height, respectively. Which of the shapes (a) and (b) has the larger volume? | (a) | [OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] 5 3 [OP_POW] 4 5 6 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = '(a)'
var_b = '(b)'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 5
var_d = 3
var_e = var_c ** var_d
var_f = 4
var_g = 5
var_h = 6
var_i = var_g * var_h
var_j = var_f * var_i
list_b= []
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_k = 1
list_c=list_b.copy()
list_c.sort()
var_l = list_c[-var_k]
var_m = list_b.index(var_l)+1
var_n = list_a[var_m-1]
print(var_n) |
Arithmetic calculation | Juyeon runs 215 meters (m) a day. If Juyeon ran 0.32 times her usual speed today, how many meters (m) did she run today? | 68.8 | 215 0.32 [OP_MUL] | var_a = 215
var_b = 0.32
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Geometry | How many diagonals can you draw in an octagon? | 20 | 8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 8
var_b = 8
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Arithmetic calculation | There are four people sitting at a round table, and you want to shake hands with people who are not neighboring with you once. Find the number that you shake hands. | 2 | 4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 4
var_b = 4
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Possibility | You are planning a trip to five cities: Gyeongju, Pohang, Busan, Geoncheon, and Gimhae. If you visit each city only once, how many orders can you make to visit the city? However, Gyeongju must be visited first. | 24 | [OP_LIST_SOL] Gyeongju Pohang Busan Geoncheon Gimhae [OP_LIST_EOL] [OP_LIST_SOL] Gyeongju [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] | var_a = 'Gyeongju'
var_b = 'Pohang'
var_c = 'Busan'
var_d = 'Geoncheon'
var_e = 'Gimhae'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 'Gyeongju'
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
list_c = list(set(list_a) - set(list_b))
var_g = len(list_c)
var_h = len(list_c)
var_i = 1
var_g = int(var_g)
var_h = int(var_h)
for i, elem in enumerate(range(var_h)):
var_i = var_i * (var_g-i)
print(int(var_i)) |
Arithmetic calculation | Grandpa wants to buy 12 bottles of 3-liter (L) water and distribute 3/4 liter (L) to each student. How many students can he share? | 48 | 3 12 [OP_MUL] 3/4 [OP_FDIV] | var_a = 3
var_b = 12
var_c = var_a * var_b
var_d = 0.75
var_e = var_c // var_d
print(int(var_e)) |
Arithmetic calculation | Hansol's height is 134.5 centimeters (cm). If Hancho's height is 1.06 times Hansol's height, how tall is Hancho in centimeters (cm)? | 142.57 | 134.5 1.06 [OP_MUL] | var_a = 134.5
var_b = 1.06
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | There are five numbers 10, 11, 12, 13, and 14. Which number is the smallest? | 10 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
list_b=list_a.copy()
list_b.sort()
var_g = list_b[var_f-1]
print(int(var_g)) |
Arithmetic calculation | How many three-digit numbers are greater than 137 and less than 285? | 147 | 137 1 [OP_ADD] 285 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN] | var_a = 137
var_b = 1
var_c = var_a + var_b
var_d = 285
var_e = 1
var_f = var_d - var_e
var_g = 1
list_a = [i for i in range(var_c, var_f + 1, var_g)]
var_h = len(list_a)
print(int(var_h)) |
Correspondence | There is a single digit number A. When 7A7 is rounded up to the tens place is 730. What is the right value for A? | 2 | 7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK] | var_a = '7A7'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 730
list_b = []
for i in list_a:
if i <= var_b:
list_b.append(i)
var_c = 730
var_d = 10
var_e = var_c - var_d
list_c = []
for i in list_b:
if i > var_e:
list_c.append(i)
var_f = '7A7'
var_g = 'A'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_c:
elem = str(elem)
var_h = int(elem[unk_idx])
print(int(var_h)) |
Arithmetic calculation | After the train departed, 29 people got off at the first station 17 people got on. At the second station, 27 people got off and 35 got on. There are 116 people on the train right now. How many people were on the train when it first departed? | 120 | 116 29 [OP_ADD] 17 [OP_SUB] 27 [OP_ADD] 35 [OP_SUB] | var_a = 116
var_b = 29
var_c = var_a + var_b
var_d = 17
var_e = var_c - var_d
var_f = 27
var_g = var_e + var_f
var_h = 35
var_i = var_g - var_h
print(int(var_i)) |
Possibility | Find the number of two-digit natural numbers that can be made by drawing two from the number cards 1, 2, and 3. | 6 | [OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 1
var_b = 2
var_c = 3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Geometry | There is a room in the shape of a cube. If the length of one side of this room is 5 meters (m), what is the circumference of the floor of this room in meters (m)? | 20 | 5 4 [OP_MUL] | var_a = 5
var_b = 4
var_c = var_a * var_b
print(int(var_c)) |
Comparison | There are 4 numbers: 0.8, 1/2, 0.5, and 1/3. What is the sum of all numbers greater than or equal to 0.1? | 2.13 | [OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM] | var_a = 0.8
var_b = 0.5
var_c = 0.5
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 0.1
list_b = []
for i in list_a:
if i >= var_e:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Arithmetic calculation | How many two-digit numbers are divisible by 3 and 5? | 6 | 10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 10
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = len(list_c)
print(int(var_f)) |
Correspondence | I need to add 22 to a number, but I mistakenly added 12 and got 48. Find the result of the correct calculation. | 58 | 48 12 [OP_SUB] 22 [OP_ADD] | var_a = 48
var_b = 12
var_c = var_a - var_b
var_d = 22
var_e = var_c + var_d
print(int(var_e)) |
Correspondence | Jimin has paint, and he used 4.3 liters (L) of each to paint his house and his friend's house, and the remaining paint is 8.8 liters (L). Find how many liters (L) of paint Jimin had at the beginning. | 17.4 | 8.8 4.3 [OP_ADD] 4.3 [OP_ADD] | var_a = 8.8
var_b = 4.3
var_c = var_a + var_b
var_d = 4.3
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Correspondence | It is 28 when you multiply a number by 7/8. How much is it when you add 16 to that number and multiply 5/16? | 15 | 28 8 7 [OP_DIV] [OP_MUL] 16 [OP_ADD] 5 16 [OP_DIV] [OP_MUL] | var_a = 28
var_b = 8
var_c = 7
var_d = var_b / var_c
var_e = var_a * var_d
var_f = 16
var_g = var_e + var_f
var_h = 5
var_i = 16
var_j = var_h / var_i
var_k = var_g * var_j
print(int(var_k)) |
Correspondence | Seongjun and Seungah are playing slap-match. It is said that the number of Seongjun's ttakji multiplied by 3/4 subtracted by 25 equals the number of Seunga's ttakji subtracted by 50 multiplied by 7. When Seunga has 100 ttakjis, find how many ttakji Seongjun has. | 500 | 100 50 [OP_SUB] 7 [OP_MUL] 25 [OP_ADD] 3/4 [OP_DIV] | var_a = 100
var_b = 50
var_c = var_a - var_b
var_d = 7
var_e = var_c * var_d
var_f = 25
var_g = var_e + var_f
var_h = 0.75
var_i = var_g / var_h
print(int(var_i)) |
Geometry | A rectangular slice of bread with an area of 59.6 square centimeters (cm2) is divided into 4 equal parts. What is the area of one part? | 14.9 | 59.6 4 [OP_DIV] | var_a = 59.6
var_b = 4
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | Divide 90.1 by some number to get 5.3. What is the number multiplied by 0.2? | 3.4 | 90.1 5.3 [OP_DIV] 0.2 [OP_MUL] | var_a = 90.1
var_b = 5.3
var_c = var_a / var_b
var_d = 0.2
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Comparison | There are two natural numbers whose difference is 480. If the larger number divided by the smaller number gives the quotient of 4 and the remainder of 30, find the larger number. | 630 | 480 30 [OP_SUB] 4 1 [OP_SUB] [OP_DIV] 4 [OP_MUL] 30 [OP_ADD] | var_a = 480
var_b = 30
var_c = var_a - var_b
var_d = 4
var_e = 1
var_f = var_d - var_e
var_g = var_c / var_f
var_h = 4
var_i = var_g * var_h
var_j = 30
var_k = var_i + var_j
print(int(var_k)) |
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