id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__tA4Kn667hMQPor2K | Mary can do a piece of work in 11 days. Rosy is 10% more efficient than Mary. The number of days taken by Rosy to do the same piece of work is? Select:
A) 10 B) 15 C) 20 D) 25 E) 30 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">11 / (11/10)</gadget>
<output>10</output>
<result>A</result> | A | 10 | Mary can do a piece of work in 11 days. Rosy is 10% more efficient than Mary. The number of days taken by Rosy to do the same piece of work is? | {
"A": "10",
"B": "15",
"C": "20",
"D": "25",
"E": "30"
} | divide(11, add(const_1, divide(10, const_100))) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)| | "ratio of times taken by mary and rosy = 110 : 100 = 11 : 10 suppose rosy takes x days to do the work . 11 : 10 : : 11 : x = > x = 10 days . hence , rosy takes 10 days to complete the work . answer : a" | physics |
math_qa__Z273n88c4IxN1Tdc | 24 oz of juice P and 25 oz of juice V are mixed to make smothies M and Y . The ratio of p to V in smothie M is 4 is to 1 and that in Y is 1is to 5.How many ounces of juice P are contained in the smothie M? Answers.
A) 5 B) 10 C) 15 D) 20 E) 25 | <gadget id="calculator">24 * 5</gadget>
<output>120</output>
<gadget id="calculator">120 - 25</gadget>
<output>95</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">20 - 1</gadget>
<output>19</output>
<gadget id="calculator">95 / 19</gadget>
<output>5</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<result>D</result> | D | 20 | 24 oz of juice P and 25 oz of juice V are mixed to make smothies M and Y . The ratio of p to V in smothie M is 4 is to 1 and that in Y is 1is to 5.How many ounces of juice P are contained in the smothie M? | {
"A": "5",
"B": "10",
"C": "15",
"D": "20",
"E": "25"
} | multiply(divide(subtract(multiply(24, 5), 25), subtract(multiply(4, 5), 1)), 4) | multiply(n0,n5)|multiply(n2,n5)|subtract(#0,n1)|subtract(#1,n3)|divide(#2,#3)|multiply(n2,#4) | the ratio of p to v in smothie m is 4 is to 1 and that in y is 1 is to 5 . p 1 + p 2 = 24 v 1 + v 2 = 25 p 1 = 4 v 1 p 2 = v 2 / 5 4 v 1 + v 2 / 5 = 24 v 1 + v 2 = 25 4 v 2 - v 2 / 5 = 76 19 v 2 / 5 = 76 = > v 2 = 20 = > v 1 = 5 = > p 1 = 20 answer - d | other |
math_qa__dKLY96vCRC3altMD | A volume of 10940 l water is in a container of sphere. How many hemisphere of volume 4l each will be required to transfer all the water into the small hemispheres? Answers.
A) 2812 B) 8231 C) 2734 D) 2735 E) 4254 | <gadget id="calculator">10_940 / 4</gadget>
<output>2_735</output>
<result>D</result> | D | 2,735 | A volume of 10940 l water is in a container of sphere. How many hemisphere of volume 4l each will be required to transfer all the water into the small hemispheres? | {
"A": "2812",
"B": "8231",
"C": "2734",
"D": "2735",
"E": "4254"
} | divide(10940, 4) | divide(n0,n1)| | "a volume of 4 l can be kept in 1 hemisphere therefore , a volume of 10940 l can be kept in ( 10940 / 4 ) hemispheres ans . 2735 answer : d" | geometry |
math_qa__60VumfPra7zPUTKL | A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 80 kmph. When and at what distance from Mumbai do the two trains meet? Answers: A) 87 B) 279 C) 80 D) 278 E) 379 | <gadget id="calculator">40 * 1</gadget>
<output>40</output>
<gadget id="calculator">80 - 40</gadget>
<output>40</output>
<gadget id="calculator">40 / 40</gadget>
<output>1</output>
<gadget id="calculator">1 * 80</gadget>
<output>80</output>
<result>C</result> | C | 80 | A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 80 kmph. When and at what distance from Mumbai do the two trains meet? | {
"A": "87",
"B": "279",
"C": "80",
"D": "278",
"E": "379"
} | multiply(divide(multiply(40, const_1), subtract(80, 40)), 80) | multiply(n1,const_1)|subtract(n2,n1)|divide(#0,#1)|multiply(n2,#2)| | "when the second train leaves mumbai the first train covers 40 * 1 = 40 km so , the distance between first train and second train is 40 km at 10.00 am time taken by the trains to meet = distance / relative speed = 40 / ( 80 - 40 ) = 1 hours so , the two trains meet at 11 a . m . the two trains meet 1 * 80 = 80 km away from mumbai . answer : c" | physics |
math_qa__tICtoKYv5cXEA02B | Virginia, Adrienne, and Dennis have taught history for a combined total of 93 years. If Virginia has taught for 9 more years than Adrienne and for 9 fewer years than Dennis, for how many years has Dennis taught?
Choose the correct choice from the following choices:
A) 23 B) 32 C) 40 D) 41 E) 44 | <gadget id="calculator">9 + 9</gadget>
<output>18</output>
<gadget id="calculator">18 + 9</gadget>
<output>27</output>
<gadget id="calculator">93 - 27</gadget>
<output>66</output>
<gadget id="calculator">66 / 3</gadget>
<output>22</output>
<gadget id="calculator">22 + 18</gadget>
<output>40</output>
<result>C</result> | C | 40 | Virginia, Adrienne, and Dennis have taught history for a combined total of 93 years. If Virginia has taught for 9 more years than Adrienne and for 9 fewer years than Dennis, for how many years has Dennis taught? | {
"A": "23",
"B": "32",
"C": "40",
"D": "41",
"E": "44"
} | add(divide(subtract(93, add(add(9, 9), 9)), const_3), add(9, 9)) | add(n1,n2)|add(n1,#0)|subtract(n0,#1)|divide(#2,const_3)|add(#0,#3)| | "let number of years taught by virginia = v number of years taught by adrienne = a number of years taught by dennis = d v + a + d = 96 v = a + 9 = > a = v - 9 v = d - 9 = > a = ( d - 9 ) - 9 = d - 18 d - 9 + d - 18 + d = 93 = > 3 d = 93 + 27 = 120 = > d = 40 answer c" | general |
math_qa__wRcCAuNnOyTf9mOd | If the simple interest on a certain sum of money for 5 years is one–fifth of the sum, then the rate of interest per annum is Choose the correct choice from the following:
A) 4 % B) 7 % C) 6 % D) 4 % E) 3 % | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<result>D</result> | D | 4 | If the simple interest on a certain sum of money for 5 years is one–fifth of the sum, then the rate of interest per annum is | {
"A": "4 %",
"B": "7 %",
"C": "6 %",
"D": "4 %",
"E": "3 %"
} | divide(divide(const_100, add(const_1, const_4)), 5) | add(const_1,const_4)|divide(const_100,#0)|divide(#1,n0)| | "explanation : let the principal ( p ) be x then , simple interest ( si ) = x / 5 time ( t ) = 5 years rate of interest per annum ( r ) = ( 100 × si ) / pt = ( 100 × ( x / 5 ) / ( x × 5 ) = 20 / 5 = 4 % answer : option d" | gain |
math_qa__XQDAAgo5PjOQugtZ | A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 10% so that the customer could not buy the required amount of the product. The customer managed to buy only 90% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase? Options.
A) 5 % B) 4 % C) 3 % D) 2 % E) 1 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(11/10) * (9/10)</gadget>
<output>99/100 = around 0.99</output>
<gadget id="calculator">1 - (99/100)</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/100) * 100</gadget>
<output>1</output>
<result>E</result> | E | 1 | A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 10% so that the customer could not buy the required amount of the product. The customer managed to buy only 90% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase? | {
"A": "5 %",
"B": "4 %",
"C": "3 %",
"D": "2 %",
"E": "1 %"
} | multiply(subtract(const_1, multiply(add(divide(10, const_100), const_1), divide(90, const_100))), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|multiply(#2,#1)|subtract(const_1,#3)|multiply(#4,const_100)| | "let x be the amount of money paid for the first purchase . the second time , the customer paid 0.9 ( 1.1 x ) = 0.99 x . the difference is 1 % . the answer is e ." | general |
math_qa__tCGM0kahMOq2OeY3 | In what time will a train 100 m long cross an electric pole, it its speed be 126 km/hr? Pick: A) 2.5 B) 2.9 C) 2.4 D) 2.85 E) 2.1 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">126 * (5/18)</gadget>
<output>35</output>
<gadget id="calculator">100 / 35</gadget>
<output>20/7 = around 2.857143</output>
<result>D</result> | D | 2.85 | In what time will a train 100 m long cross an electric pole, it its speed be 126 km/hr? | {
"A": "2.5",
"B": "2.9",
"C": "2.4",
"D": "2.85",
"E": "2.1"
} | divide(100, multiply(126, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 126 * 5 / 18 = 35 m / sec time taken = 100 / 35 = 2.85 sec . answer : d" | physics |
math_qa__l4y61dHHGShovLkk | Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 8 minutes more to walk to work than to ride his bike to work, then x equals? Choose the correct choice from the following answers:
A) 4 B) 7 C) 12 D) 15 E) 20 | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<result>C</result> | C | 12 | Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 8 minutes more to walk to work than to ride his bike to work, then x equals? | {
"A": "4",
"B": "7",
"C": "12",
"D": "15",
"E": "20"
} | divide(multiply(8, const_3), const_2) | multiply(n2,const_3)|divide(#0,const_2)| | "please follow posting guidelines , link is in my signatures . as for your question , x / 60 = blocks / time / block = block ^ 2 / time . this is not what you want . you are given x blocks and 60 seconds per block . thus you need to put it as 60 * x to give you units of seconds as you are equating this to 480 ( which is time in seconds . ) . thus the correct equation is : 60 * x - 20 * x = 480 - - - - > 40 x = 480 - - > x = 12 . option c" | physics |
math_qa__F8iHenXu0Mij4ZdF | There are two names given JOHNSON and JONES. If one letter is picked from both simultaneously at random, then find the probability that the letter is same? Choose the correct choice
A) 24 / 35 B) 17 / 35 C) 8 / 25 D) 6 / 35 E) 1 / 25 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/7) * (1/5)</gadget>
<output>1/35 = around 0.028571</output>
<gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(2/7) * (1/5)</gadget>
<output>2/35 = around 0.057143</output>
<gadget id="calculator">(1/35) + (2/35)</gadget>
<output>3/35 = around 0.085714</output>
<gadget id="calculator">(3/35) * 2</gadget>
<output>6/35 = around 0.171429</output>
<result>D</result> | D | 0.171429 | There are two names given JOHNSON and JONES. If one letter is picked from both simultaneously at random, then find the probability that the letter is same? | {
"A": "24 / 35",
"B": "17 / 35",
"C": "8 / 25",
"D": "6 / 35",
"E": "1 / 25"
} | multiply(add(multiply(divide(const_1, add(const_3, const_4)), divide(const_1, const_5)), multiply(divide(const_2, add(const_3, const_4)), divide(const_1, const_5))), const_2) | add(const_3,const_4)|divide(const_1,const_5)|divide(const_1,#0)|divide(const_2,#0)|multiply(#2,#1)|multiply(#3,#1)|add(#4,#5)|multiply(#6,const_2) | this question can also be solved by using ' brute force ' - you just have to ' map out ' the possibilities . the namejohnsonhas 7 letters and the namejoneshas 5 letters , so there are ( 7 ) ( 5 ) = 35 possible pairings of letters that can occur . of those 35 , the pairings that include the same letter both times are : j and j 1 st o and o 1 st n and n s and s 2 nd o and o 2 nd n and n total : 6 so the probability that the two randomly selected letters will match is 6 / 35 . d | other |
math_qa__OLjbUMHwj5EaTdb6 | The expression (11.98 × 11.98 + 11.98 × x + 0.02 × 0.02) will be a perfect square for x equal to Select the correct option:
A) 0.02
B) 0.2
C) 0.04
D) 0.4
E) 4 | <gadget id="calculator">0.02 * 2</gadget>
<output>0.04</output>
<result>C</result> | C | 0.04 | The expression (11.98 × 11.98 + 11.98 × x + 0.02 × 0.02) will be a perfect square for x equal to | {
"A": "0.02",
"B": "0.2",
"C": "0.04",
"D": "0.4",
"E": "4"
} | multiply(0.02, const_2) | multiply(n3,const_2)| | "solution given expression = ( 11.98 ) 2 + ( 0.02 ) 2 + 11.98 × x . for the given express to be a perfect square , we must have 11.98 × x = 2 × 11.98 × 0.02 or x = 0.04 . answer c" | general |
math_qa__769dLGYN28Q25mGn | Tom opened a shop investing Rs.30000. Jose joined him 2 months later, investing Rs.45000. They earned a profit of Rs.72000 after completion of one year. What will be Jose's share of profit? Choose the correct choice: A) 20000 B) 10000 C) 25000 D) 34000 E) 40000 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">30_000 * 12</gadget>
<output>360_000</output>
<gadget id="calculator">12 - 2</gadget>
<output>10</output>
<gadget id="calculator">45_000 * 10</gadget>
<output>450_000</output>
<gadget id="calculator">450_000 + 360_000</gadget>
<output>810_000</output>
<gadget id="calculator">360_000 / 810_000</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">1 - (4/9)</gadget>
<output>5/9 = around 0.555556</output>
<gadget id="calculator">72_000 * (5/9)</gadget>
<output>40_000</output>
<result>E</result> | E | 40,000 | Tom opened a shop investing Rs.30000. Jose joined him 2 months later, investing Rs.45000. They earned a profit of Rs.72000 after completion of one year. What will be Jose's share of profit? | {
"A": "20000",
"B": "10000",
"C": "25000",
"D": "34000",
"E": "40000"
} | multiply(72000, subtract(const_1, divide(multiply(30000, multiply(2, multiply(2, const_3))), add(multiply(45000, subtract(multiply(2, multiply(2, const_3)), 2)), multiply(30000, multiply(2, multiply(2, const_3))))))) | multiply(n1,const_3)|multiply(#0,n1)|multiply(n0,#1)|subtract(#1,n1)|multiply(n2,#3)|add(#4,#2)|divide(#2,#5)|subtract(const_1,#6)|multiply(n3,#7)| | "sol = ~ s - so anju ’ s share = [ 5 / 9 ] x 72000 = 40000 e" | gain |
math_qa__eCYic1ftUG4iaXLH | The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).
Choose the most appropriate option:
A) 178.89 cm
B) 178.29 cm
C) 178.79 cm
D) 177.89 cm
E) 178.69 cm | <gadget id="calculator">35 * 180</gadget>
<output>6_300</output>
<gadget id="calculator">6_300 - 166</gadget>
<output>6_134</output>
<gadget id="calculator">6_134 + 106</gadget>
<output>6_240</output>
<gadget id="calculator">6_240 / 35</gadget>
<output>1_248/7 = around 178.285714</output>
<gadget id="calculator">floor(1_248/7)</gadget>
<output>178</output>
<result>B</result> | B | 178.29 | The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places). | {
"A": "178.89 cm",
"B": "178.29 cm",
"C": "178.79 cm",
"D": "177.89 cm",
"E": "178.69 cm"
} | floor(divide(add(subtract(multiply(35, 180), 166), 106), 35)) | multiply(n0,n1)|subtract(#0,n2)|add(n3,#1)|divide(#2,n0)|floor(#3) | calculated average height of 35 boys = 180 cm . wrong total height of 35 boys = 180 * 35 cm . this was as a result of an actual height of 106 cm being wrongly written as 166 cm . correct total height of 35 boys = 180 * 35 cm - 166 cm + 106 cm = 180 * 35 cm - 166 cm + 106 cm / 35 = 180 cm - 60 / 35 cm = 180 cm - 1.71 cm = 178.29 cm . answer : b | general |
math_qa__DVSbME53DS2IMMjZ | a+2b=6,ab=4
2/a + 1/b=? Choose the most appropriate option.
A) 3 / 2
B) 5 / 2
C) 7 / 2
D) 9 / 2
E) 11 / 2 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<result>A</result> | A | 1.5 | a+2b=6,ab=4
2/a + 1/b=? | {
"A": "3 / 2",
"B": "5 / 2",
"C": "7 / 2",
"D": "9 / 2",
"E": "11 / 2"
} | divide(add(2, 1), 2) | add(n0,n4)|divide(#0,n0) | 2 / 2 + 1 / 2 = 1 + 1 / 2 = 3 / 2 answer : a | general |
math_qa__iOBvT2uYTgj8W9Py | A man saves a certain portion of his income during a year and spends the remaining portion on his personal expenses. Next year his income increases by 20% but his savings increase by 100%. If his total expenditure in 2 years is double his expenditure in 1st year, What %age of his income in the first year did he save? Choose the correct choice from the following answers
A) 15 % B) 18 % C) 20 % D) 25 % E) 26 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 + 100</gadget>
<output>220</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">220 - 200</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>C</result> | C | 20 | A man saves a certain portion of his income during a year and spends the remaining portion on his personal expenses. Next year his income increases by 20% but his savings increase by 100%. If his total expenditure in 2 years is double his expenditure in 1st year, What %age of his income in the first year did he save? | {
"A": "15 %",
"B": "18 %",
"C": "20 %",
"D": "25 %",
"E": "26 %"
} | multiply(divide(subtract(add(add(100, 20), 100), multiply(2, 100)), 100), 100) | add(n0,n1)|multiply(n1,n2)|add(n1,#0)|subtract(#2,#1)|divide(#3,n1)|multiply(#4,n1)| | "1 st year income = i 1 st year savings = s 1 st year expense = e 1 2 nd year income = 1.2 i 2 nd year savings = 2 s ( 100 % increase ) 2 nd year expense = e 2 e 1 + e 2 = 2 e 1 e 2 = e 1 that means expenses are same during both years . with increase of 20 % income the savings increased by 100 % . or s = . 2 i or s = 20 % of income c is the answer" | general |
math_qa__oHOAgXGjsODbDPCW | A fair 2 sided coin is flipped 6 times. What is the probability that tails will be the result at least twice, but not more than 5 times? Pick.
A) 5 / 8 B) 3 / 4 C) 7 / 8 D) 57 / 64 E) 15 / 16 | <gadget id="calculator">2 ** 6</gadget>
<output>64</output>
<gadget id="calculator">1 / 64</gadget>
<output>1/64 = around 0.015625</output>
<gadget id="calculator">(1/64) * 6</gadget>
<output>3/32 = around 0.09375</output>
<gadget id="calculator">(1/64) + (1/64)</gadget>
<output>1/32 = around 0.03125</output>
<gadget id="calculator">(3/32) + (1/32)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 - (1/8)</gadget>
<output>7/8 = around 0.875</output>
<result>C</result> | C | 0.875 | A fair 2 sided coin is flipped 6 times. What is the probability that tails will be the result at least twice, but not more than 5 times? | {
"A": "5 / 8",
"B": "3 / 4",
"C": "7 / 8",
"D": "57 / 64",
"E": "15 / 16"
} | subtract(const_1, add(multiply(inverse(power(2, 6)), 6), add(inverse(power(2, 6)), inverse(power(2, 6))))) | power(n0,n1)|inverse(#0)|add(#1,#1)|multiply(n1,#1)|add(#2,#3)|subtract(const_1,#4) | it would be easier to calculate the probability of opposite event and subtract it from 1 . opposite event : 0 tail , 1 tail , 6 tails . probability of getting no tails : 1 / 2 ^ 6 = 1 / 64 probability of getting 1 tail : 6 c 1 ∗ 1 / 2 ^ 6 = 6 / 64 , we must multiply by 6 c 1 or by 6 as tail can occur for any flip from 6 , hence in 6 ways ; probability of getting 6 tails : 1 / 2 ^ 6 = 1 / 6 ^ 4 p = 1 − ( 1 / 64 + 6 / 64 + 1 / 64 ) = 56 / 64 = 7 / 8 answer : c . | general |
math_qa__pxALBLk87euLDdWk | A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 4 litres a minute. When the tank is full, the inlet is opened and due to the leak the tank is empty in 8 hours. The capacity of the tank (in litres) is Choose the correct choice from the following: A) 5780 litres B) 5770 litres C) 5760 litres D) 5750 litres E) 5740 litres | <gadget id="calculator">8 * 60</gadget>
<output>480</output>
<gadget id="calculator">4 * 480</gadget>
<output>1_920</output>
<gadget id="calculator">6 * 60</gadget>
<output>360</output>
<gadget id="calculator">480 / 360</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) - 1</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1_920 / (1/3)</gadget>
<output>5_760</output>
<result>C</result> | C | 5,760 | A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 4 litres a minute. When the tank is full, the inlet is opened and due to the leak the tank is empty in 8 hours. The capacity of the tank (in litres) is | {
"A": "5780 litres",
"B": "5770 litres",
"C": "5760 litres",
"D": "5750 litres",
"E": "5740 litres"
} | divide(multiply(4, multiply(8, const_60)), subtract(divide(multiply(8, const_60), multiply(6, const_60)), const_1)) | multiply(n2,const_60)|multiply(n0,const_60)|divide(#0,#1)|multiply(n1,#0)|subtract(#2,const_1)|divide(#3,#4)| | "explanation : work done by the inlet in 1 hour = 1 / 6 − 1 / 8 = 1 / 24 work done by inlet in 1 min = 1 / 24 ∗ 1 / 60 = 1 / 1440 = > volume of 1 / 1440 part = 4 liters volume of whole = ( 1440 * 4 ) litres = 5760 litres . option c" | physics |
math_qa__JigwpdSYMmUAAv85 | How many digits will be there to the right of the decimal point in the product of 95 and .02554 ? Choose the correct option:
A) 6
B) 7
C) 4
D) 5
E) 8 | <gadget id="calculator">100 - 95</gadget>
<output>5</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<result>C</result> | C | 4 | How many digits will be there to the right of the decimal point in the product of 95 and .02554 ? | {
"A": "6",
"B": "7",
"C": "4",
"D": "5",
"E": "8"
} | subtract(subtract(const_100, 95), const_1) | subtract(const_100,n0)|subtract(#0,const_1) | product of 95 and . 02554 is 2.4263 . therefore number of digits to right of decimal point is 4 answer is c . | general |
math_qa__9PXdyo824rHfwyPF | Dacid obtained 86, 85, 92, 87 and 95 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? Choose the correct choice from the following answers:
A) 67
B) 26
C) 89
D) 26
E) 75 | <gadget id="calculator">86 + 85</gadget>
<output>171</output>
<gadget id="calculator">171 + 92</gadget>
<output>263</output>
<gadget id="calculator">263 + 87</gadget>
<output>350</output>
<gadget id="calculator">350 + 95</gadget>
<output>445</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">445 / 5</gadget>
<output>89</output>
<result>C</result> | C | 89 | Dacid obtained 86, 85, 92, 87 and 95 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? | {
"A": "67",
"B": "26",
"C": "89",
"D": "26",
"E": "75"
} | divide(add(add(add(add(86, 85), 92), 87), 95), divide(const_10, const_2)) | add(n0,n1)|divide(const_10,const_2)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "average = ( 86 + 85 + 92 + 87 + 95 ) / 5 = 445 / 5 = 89 . answer : c" | general |
math_qa__hDa93gnV653ZVPKg | David and ANDREW can finish the work 12 days if they work together. They worked together for 8 days and then ANDREW left. David finished the remaining work in another 8 days. In how many days David alone can finish the work? Pick:
A) 30 days B) 60 days C) 70 days D) 80 days E) 24 days | <gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">8 / 4</gadget>
<output>2</output>
<gadget id="calculator">2 * 12</gadget>
<output>24</output>
<result>E</result> | E | 24 | David and ANDREW can finish the work 12 days if they work together. They worked together for 8 days and then ANDREW left. David finished the remaining work in another 8 days. In how many days David alone can finish the work? | {
"A": "30 days",
"B": "60 days",
"C": "70 days",
"D": "80 days",
"E": "24 days"
} | multiply(divide(8, subtract(12, 8)), 12) | subtract(n0,n1)|divide(n1,#0)|multiply(n0,#1) | amount of work done by david and andrew in 1 day = 1 / 12 amount of work done by david and andrew in 8 days = 8 ã — ( 1 / 12 ) = 2 / 3 remaining work â € “ 1 â € “ 2 / 3 = 1 / 3 david completes 1 / 3 work in 8 days amount of work david can do in 1 day = ( 1 / 3 ) / 8 = 1 / 24 = > david can complete the work in 24 days answer : e | physics |
math_qa__cjFt2fcrLfkQLRKI | A firm is comprised of partners and associates in a ratio of 2:63. If 45 more associates were hired, the ratio of partners to associates would be 1:34. How many partners are currently in the firm? Pick:
A) 12 B) 14 C) 16 D) 18 E) 20 | <gadget id="calculator">34 * 2</gadget>
<output>68</output>
<gadget id="calculator">68 - 63</gadget>
<output>5</output>
<gadget id="calculator">45 / 5</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<result>D</result> | D | 18 | A firm is comprised of partners and associates in a ratio of 2:63. If 45 more associates were hired, the ratio of partners to associates would be 1:34. How many partners are currently in the firm? | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "20"
} | multiply(divide(45, subtract(multiply(34, 2), 63)), 2) | multiply(n0,n4)|subtract(#0,n1)|divide(n2,#1)|multiply(n0,#2)| | "the ratio 1 : 34 = 2 : 68 so the ratio changed from 2 : 63 to 2 : 68 . 68 - 63 = 5 which is 1 / 9 of the increase in 45 associates . the ratio changed from 18 : 567 to 18 : 612 . thus the number of partners is 18 . the answer is d ." | other |
math_qa__Gcm4rNZ1ITUTxk6h | A, B and C started a partnership business by investing Rs.27000, Rs.72000, Rs.81000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit? Choose the correct choice from the following answers:
A) 70000 B) 60000 C) 80000 D) 90000 E) 50000 | <gadget id="calculator">27_000 / 81_000</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 36_000</gadget>
<output>12_000</output>
<gadget id="calculator">72_000 / 81_000</gadget>
<output>8/9 = around 0.888889</output>
<gadget id="calculator">(8/9) * 36_000</gadget>
<output>32_000</output>
<gadget id="calculator">12_000 + 32_000</gadget>
<output>44_000</output>
<gadget id="calculator">44_000 + 36_000</gadget>
<output>80_000</output>
<result>C</result> | C | 80,000 | A, B and C started a partnership business by investing Rs.27000, Rs.72000, Rs.81000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit? | {
"A": "70000",
"B": "60000",
"C": "80000",
"D": "90000",
"E": "50000"
} | add(add(multiply(divide(27000, 81000), 36000), multiply(divide(72000, 81000), 36000)), 36000) | divide(n0,n2)|divide(n1,n2)|multiply(n3,#0)|multiply(n3,#1)|add(#2,#3)|add(n3,#4) | a : b : c = 27000 : 72000 : 81000 = 3 : 8 : 9 let total profit = p then p × 9 / 20 = 36000 p = ( 36000 × 20 ) / 9 = 80000 answer is c . | gain |
math_qa__mErKSuUtCnx3aJCe | Shop Offered 32% offer for every Shirt, Smith bought a shirt at Rs. 650. and What was the shop's original selling Price? Choose the correct choice from the following
A) 955 B) 550 C) 600 D) 700 E) 750 | <gadget id="calculator">32 / 100</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">1 - (8/25)</gadget>
<output>17/25 = around 0.68</output>
<gadget id="calculator">650 / (17/25)</gadget>
<output>16_250/17 = around 955.882353</output>
<result>A</result> | A | 955 | Shop Offered 32% offer for every Shirt, Smith bought a shirt at Rs. 650. and What was the shop's original selling Price? | {
"A": "955",
"B": "550",
"C": "600",
"D": "700",
"E": "750"
} | divide(650, subtract(const_1, divide(32, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1)| | "sp * ( 68 / 100 ) = 650 sp = 9.55 * 100 = > cp = 955 answer : a" | gain |
math_qa__2UAMMCTcrPNShp4H | Each of the cucumbers in 100 pounds of cucumbers is composed of 99% water, by weight. After some of the water evaporates, the cucumbers are now 96% water by weight. What is the new weight of the cucumbers, in pounds? Choose the correct option.
A) 2 B) 25 C) 92 D) 96 E) 98 | <gadget id="calculator">100 - 99</gadget>
<output>1</output>
<gadget id="calculator">100 - 96</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>B</result> | B | 25 | Each of the cucumbers in 100 pounds of cucumbers is composed of 99% water, by weight. After some of the water evaporates, the cucumbers are now 96% water by weight. What is the new weight of the cucumbers, in pounds? | {
"A": "2",
"B": "25",
"C": "92",
"D": "96",
"E": "98"
} | multiply(divide(subtract(100, 99), subtract(100, 96)), const_100) | subtract(n0,n1)|subtract(n0,n2)|divide(#0,#1)|multiply(#2,const_100) | out of 100 pounds 99 % or 99 pounds is water and 1 pound is non - water . after somewaterevaporates the cucumbers become 96 % water and 4 % of non - water , so now 1 pound of non - water composes 4 % of cucucmbers , which means that the new weight of cucumbers is 1 / 0.04 = 25 pounds . answer : b . | gain |
math_qa__1kwNngUZZOIOLJqU | Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. The distance between P and Q is? Options.
A) 900 km B) 300 km C) 700 km D) 800 km E) 100 km | <gadget id="calculator">100 * 40</gadget>
<output>4_000</output>
<gadget id="calculator">50 - 40</gadget>
<output>10</output>
<gadget id="calculator">4_000 / 10</gadget>
<output>400</output>
<gadget id="calculator">400 + 100</gadget>
<output>500</output>
<gadget id="calculator">500 + 400</gadget>
<output>900</output>
<result>A</result> | A | 900 | Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. The distance between P and Q is? | {
"A": "900 km",
"B": "300 km",
"C": "700 km",
"D": "800 km",
"E": "100 km"
} | add(add(divide(multiply(100, 40), subtract(50, 40)), 100), divide(multiply(100, 40), subtract(50, 40))) | multiply(n1,n2)|subtract(n0,n1)|divide(#0,#1)|add(n2,#2)|add(#3,#2) | a 900 km at the time of meeting , let the distance traveled by the second train be x km . then , distance covered by the first train is ( x + 100 ) km . x / 40 = ( x + 100 ) / 50 50 x = 40 x + 4000 = > x = 400 so , distance between p and q = ( x + x + 100 ) km = 900 km . | physics |
math_qa__hn1sKMwvnp4lugMt | If grapes are 92% water and raisins are 20% water, then how many kilograms did a quantity of raisins, which currently weighs 5 kilograms, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.) Choose the most appropriate option:
A) 50 B) 54 C) 55 D) 56 E) 60 | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 5</gadget>
<output>4</output>
<gadget id="calculator">100 - 92</gadget>
<output>8</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">4 / (2/25)</gadget>
<output>50</output>
<result>A</result> | A | 50 | If grapes are 92% water and raisins are 20% water, then how many kilograms did a quantity of raisins, which currently weighs 5 kilograms, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.) | {
"A": "50",
"B": "54",
"C": "55",
"D": "56",
"E": "60"
} | divide(multiply(divide(subtract(const_100, 20), const_100), 5), divide(subtract(const_100, 92), const_100)) | subtract(const_100,n1)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,const_100)|multiply(n2,#2)|divide(#4,#3)| | "let x be the original weight . the weight of the grape pulp was 0.08 x . since the grape pulp is 80 % of the raisins , 0.08 x = 0.8 ( 5 ) . then x = 50 kg . the answer is a ." | general |
math_qa__Mtl7hZBKnhJUruWr | A teacher grades students’ tests by subtracting twice the number of incorrect responses from the number of correct responses. If Student A answers each of the 100 questions on her test and receives a score of 70, how many questions did Student A answer correctly? Choose the correct choice from the following.
A) 55 B) 90 C) 73 D) 82 E) 91 | <gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">30 / 3</gadget>
<output>10</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<result>B</result> | B | 90 | A teacher grades students’ tests by subtracting twice the number of incorrect responses from the number of correct responses. If Student A answers each of the 100 questions on her test and receives a score of 70, how many questions did Student A answer correctly? | {
"A": "55",
"B": "90",
"C": "73",
"D": "82",
"E": "91"
} | subtract(100, divide(subtract(100, 70), const_3)) | subtract(n0,n1)|divide(#0,const_3)|subtract(n0,#1)| | "let the number of correct responses be x then the number of incorrect responses = 100 - x according to question x - 2 ( 100 - x ) = 70 ( subtracting twice of incorrect from correct ) 3 x = 270 x = 90 answer : b" | general |
math_qa__Iu8Lh2pOJOxPPGLC | REDO’s manufacturing costs for sets of horseshoes include a $10,000 initial outlay, and $20 per set. They can sell the sets $50. If profit is revenue from sales minus manufacturing costs, and the company producessells 500 sets of horseshoes, what was their profit? Choose the correct choice: A) $ 4500 B) $ 3500 C) $ 5500 D) $ 5000 E) $ 6300 | <gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">50 - 40</gadget>
<output>10</output>
<gadget id="calculator">10 * 500</gadget>
<output>5_000</output>
<result>D</result> | D | 5,000 | REDO’s manufacturing costs for sets of horseshoes include a $10,000 initial outlay, and $20 per set. They can sell the sets $50. If profit is revenue from sales minus manufacturing costs, and the company producessells 500 sets of horseshoes, what was their profit? | {
"A": "$ 4500",
"B": "$ 3500",
"C": "$ 5500",
"D": "$ 5000",
"E": "$ 6300"
} | multiply(subtract(50, multiply(20, const_2)), 500) | multiply(n1,const_2)|subtract(n2,#0)|multiply(n3,#1) | total manufacturing cost = 10000 + 500 * 20 = 20000 total selling cost = 500 * 50 = 25000 profit = 25000 - 20000 = 5000 answer : d | gain |
math_qa__izllzg3eWrL033Vk | A 300 meter long train crosses a plaƞorm in 39 seconds while it crosses a signal pole in 18 seconds.
What is the length of the plaƞorm. Choose the correct choice:
A) 310 meter B) 335 meter C) 345 meter D) 350 meter E) none of these | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 39</gadget>
<output>650</output>
<gadget id="calculator">650 - 300</gadget>
<output>350</output>
<result>D</result> | D | 350 | A 300 meter long train crosses a plaƞorm in 39 seconds while it crosses a signal pole in 18 seconds.
What is the length of the plaƞorm. | {
"A": "310 meter",
"B": "335 meter",
"C": "345 meter",
"D": "350 meter",
"E": "none of these"
} | subtract(multiply(divide(300, 18), 39), 300) | divide(n0,n2)|multiply(n1,#0)|subtract(#1,n0) | explanation : speed = distance / ɵ me = 300 / 18 = 50 / 3 m / sec let the length of the pla ƞ orm be x meters then distance = speed ∗ timex + 300 = 503 ∗ 39 = > 3 ( x + 300 ) = 1950 = > x = 350 meters answer : d | physics |
math_qa__B1F1OzRiSw7KWcVg | 18 men shake hands with each other. Maximum no of handshakes without cyclic handshakes.
Options.
A) 190 B) 153 C) 210 D) 220 E) 230 | <gadget id="calculator">18 - 1</gadget>
<output>17</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">17 * 9</gadget>
<output>153</output>
<result>B</result> | B | 153 | 18 men shake hands with each other. Maximum no of handshakes without cyclic handshakes. | {
"A": "190",
"B": "153",
"C": "210",
"D": "220",
"E": "230"
} | multiply(subtract(18, const_1), divide(18, const_2)) | divide(n0,const_2)|subtract(n0,const_1)|multiply(#0,#1)| | "1 st person will shake hand with 17 people 2 nd person will shake hand with 16 people 3 rd person will shake hand with 15 people . . . . . . total no . of handshakes = 17 + . . . + 3 + 2 + 1 = 17 * ( 17 + 1 ) / 2 = 153 or , if there are n persons then no . of shakehands = nc 2 = 18 c 2 = 153 answer : b" | general |
math_qa__mmBl9M7fKhdzCDzR | A dishonest dealer professes to sell goods at the cost price but uses a weight of 700 grams per kg, what is his percent? Choose the correct option:
A) 42.8 % B) 25 % C) 55 % D) 28 % E) 55 % | <gadget id="calculator">100 / 700</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">(1/7) * 1_000</gadget>
<output>1_000/7 = around 142.857143</output>
<gadget id="calculator">(1_000/7) - 100</gadget>
<output>300/7 = around 42.857143</output>
<result>A</result> | A | 42.8 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 700 grams per kg, what is his percent? | {
"A": "42.8 %",
"B": "25 %",
"C": "55 %",
"D": "28 %",
"E": "55 %"
} | subtract(multiply(divide(const_100, 700), multiply(const_100, multiply(add(const_3, const_2), const_2))), const_100) | add(const_2,const_3)|divide(const_100,n0)|multiply(#0,const_2)|multiply(#2,const_100)|multiply(#1,#3)|subtract(#4,const_100)| | "700 - - - 300 100 - - - ? = > 42.8 % answer : a" | gain |
math_qa__f6a5k7Te5rokVmK9 | ? x 120 = 173 x 240 Pick.
A) 545 B) 685 C) 865 D) 495 E) 346 | <gadget id="calculator">173 * 240</gadget>
<output>41_520</output>
<gadget id="calculator">41_520 / 120</gadget>
<output>346</output>
<result>E</result> | E | 346 | ? x 120 = 173 x 240 | {
"A": "545",
"B": "685",
"C": "865",
"D": "495",
"E": "346"
} | divide(multiply(173, 240), 120) | multiply(n1,n2)|divide(#0,n0) | let y x 120 = 173 x 240 then y = ( 173 x 240 ) / 120 = 346 . answer : e | general |
math_qa__C9JTp4jMt0xzei7C | in a soap company a soap is manufactured with 11 parts.for making one soap you will get 1 part as scrap.at the end of the day you have 251 such scraps.from that how many soaps can be manufactured? Select.
A) 24 B) 25 C) 26 D) 27 E) 28 | <gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">251 - 9</gadget>
<output>242</output>
<gadget id="calculator">242 / 11</gadget>
<output>22</output>
<gadget id="calculator">22 + 9</gadget>
<output>31</output>
<gadget id="calculator">31 - 9</gadget>
<output>22</output>
<gadget id="calculator">22 / 11</gadget>
<output>2</output>
<gadget id="calculator">9 + 2</gadget>
<output>11</output>
<gadget id="calculator">11 / 11</gadget>
<output>1</output>
<gadget id="calculator">22 + 2</gadget>
<output>24</output>
<gadget id="calculator">1 + 24</gadget>
<output>25</output>
<result>B</result> | B | 25 | in a soap company a soap is manufactured with 11 parts.for making one soap you will get 1 part as scrap.at the end of the day you have 251 such scraps.from that how many soaps can be manufactured? | {
"A": "24",
"B": "25",
"C": "26",
"D": "27",
"E": "28"
} | add(divide(add(subtract(11, const_2), divide(subtract(add(divide(subtract(251, subtract(11, const_2)), 11), subtract(11, const_2)), subtract(11, const_2)), 11)), add(subtract(11, const_2), divide(subtract(add(divide(subtract(251, subtract(11, const_2)), 11), subtract(11, const_2)), subtract(11, const_2)), 11))), add(divide(subtract(251, subtract(11, const_2)), 11), divide(subtract(add(divide(subtract(251, subtract(11, const_2)), 11), subtract(11, const_2)), subtract(11, const_2)), 11))) | subtract(n0,const_2)|subtract(n2,#0)|divide(#1,n0)|add(#2,#0)|subtract(#3,#0)|divide(#4,n0)|add(#2,#5)|add(#5,#0)|divide(#7,#7)|add(#6,#8) | using 251 scraps we make = 22 soaps . ( i . e . , 11 * 22 = 242 ) remaining scraps = 9 . again , 22 soaps produce = 22 scraps . so , now we have 22 + 9 = 31 scraps remaining . using 31 scraps we make 2 soaps and 2 scraps remaining . ( i . e . , 2 * 11 = 22 ) again , that 2 soaps produce = 2 scraps . and already we have 9 scraps . total 9 + 2 = 11 sscraps . by using 11 scraps , we make 1 soap . so , total = 22 + 2 + 1 = 25 soaps we produce . answer : b | physics |
math_qa__w7vPHXZ5TfHAY3Uo | A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum? Answers:
A) 1888
B) 1640
C) 2768
D) 2976
E) 2691 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 * 2_665</gadget>
<output>39_975</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">15 + 24</gadget>
<output>39</output>
<gadget id="calculator">39_975 / 39</gadget>
<output>1_025</output>
<gadget id="calculator">2_665 - 1_025</gadget>
<output>1_640</output>
<result>B</result> | B | 1,640 | A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum? | {
"A": "1888",
"B": "1640",
"C": "2768",
"D": "2976",
"E": "2691"
} | subtract(2665, divide(multiply(multiply(3, 5), 2665), add(multiply(3, 5), multiply(8, 3)))) | multiply(n2,n4)|multiply(n1,n2)|add(#0,#1)|multiply(n0,#0)|divide(#3,#2)|subtract(n0,#4)| | "( x * 8 * 3 ) / 100 = ( ( 2665 - x ) * 3 * 5 ) / 100 24 x / 100 = 39975 / 100 - 15 x / 100 39 x = 39975 = > x = 1025 second sum = 2665 – 1025 = 1640 answer : b" | gain |
math_qa__yZ2JMAwmghwviRfN | In a survey of parents, exactly 3/4 of the mothers and 9/10 of the fathers held full-time jobs. If 40 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs? Options.
A) 27 % B) 21 % C) 19 % D) 18 % E) 16 % | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 60</gadget>
<output>54</output>
<gadget id="calculator">60 - 54</gadget>
<output>6</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 40</gadget>
<output>30</output>
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
<gadget id="calculator">6 + 10</gadget>
<output>16</output>
<result>E</result> | E | 16 | In a survey of parents, exactly 3/4 of the mothers and 9/10 of the fathers held full-time jobs. If 40 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs? | {
"A": "27 %",
"B": "21 %",
"C": "19 %",
"D": "18 %",
"E": "16 %"
} | add(subtract(subtract(const_100, 40), multiply(divide(9, 10), subtract(const_100, 40))), subtract(40, multiply(divide(3, 4), 40))) | divide(n2,n3)|divide(n0,n1)|subtract(const_100,n4)|multiply(#0,#2)|multiply(n4,#1)|subtract(#2,#3)|subtract(n4,#4)|add(#5,#6)| | "let the total number of parents = 100 number of women = 40 number of men = 60 number of mothers who held full time jobs = 3 / 4 * 40 = 30 number of fathers who held full time jobs = 9 / 10 * 60 = 54 total number of parents who held full time jobs = 84 total number of parents who did not hold jobs = 100 - 84 = 16 alternatively , percentage of women = 40 % percentage of women who did not hold full time jobs = ( 1 - 3 / 4 ) * 100 % = 25 % of all mothers did not have full time jobs 25 % of 40 % - - > 10 % of the total parents percentage of men = 60 % percentage of men who held full time jobs = ( 1 - 9 / 10 ) * 100 % = 10 % of all fathers did not have full time jobs 10 % of 60 % - - > 6 % of the total parents therefore , percentage of parents who did not hold full time jobs = 10 + 6 = 16 % answer e - 16 %" | general |
math_qa__J3iqMA8CbJc46iMn | A garrison of 1850 men has provisions for 28 days. At the end of 12 days, a reinforcement arrives, and it is now found that the provisions will last only for 10 days more. What is the reinforcement? Pick
A) 1850 B) 2960 C) 3000 D) 1110 E) 1712 | <gadget id="calculator">1_850 * 28</gadget>
<output>51_800</output>
<gadget id="calculator">1_850 * 12</gadget>
<output>22_200</output>
<gadget id="calculator">51_800 - 22_200</gadget>
<output>29_600</output>
<gadget id="calculator">29_600 / 10</gadget>
<output>2_960</output>
<gadget id="calculator">2_960 - 1_850</gadget>
<output>1_110</output>
<result>D</result> | D | 1,110 | A garrison of 1850 men has provisions for 28 days. At the end of 12 days, a reinforcement arrives, and it is now found that the provisions will last only for 10 days more. What is the reinforcement? | {
"A": "1850",
"B": "2960",
"C": "3000",
"D": "1110",
"E": "1712"
} | subtract(divide(subtract(multiply(1850, 28), multiply(1850, 12)), 10), 1850) | multiply(n0,n1)|multiply(n0,n2)|subtract(#0,#1)|divide(#2,n3)|subtract(#3,n0)| | "1850 - - - - 28 1850 - - - - 16 x - - - - - 10 x * 10 = 1850 * 16 x = 2960 1850 - - - - - - - 1110 answer : d" | physics |
math_qa__M6qpXJ93SM0Ri8FG | A certain sum is invested at simple interest at 18% p.a. for two years instead of investing at 12% p.a. for the same time period. Therefore the interest received is more by Rs. 240. Find the sum? Options
A) 7000 B) 7029 C) 2778 D) 2800 E) 2000 | <gadget id="calculator">18 - 12</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">240 / (3/25)</gadget>
<output>2_000</output>
<result>E</result> | E | 2,000 | A certain sum is invested at simple interest at 18% p.a. for two years instead of investing at 12% p.a. for the same time period. Therefore the interest received is more by Rs. 240. Find the sum? | {
"A": "7000",
"B": "7029",
"C": "2778",
"D": "2800",
"E": "2000"
} | divide(240, divide(multiply(subtract(18, 12), const_2), const_100)) | subtract(n0,n1)|multiply(#0,const_2)|divide(#1,const_100)|divide(n2,#2)| | "let the sum be rs . x . ( x * 18 * 2 ) / 100 - ( x * 12 * 2 ) / 100 = 240 = > 36 x / 100 - 24 x / 100 = 240 = > 12 x / 100 = 240 = > x = 2000 . answer : e" | gain |
math_qa__Kn2ZE0ScQyCpZDfd | A train 150 m long is running at a speed of 62 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? Choose the correct choice from the following answers: A) 5 sec B) 10 sec C) 12 sec D) 18 sec E) 15 sec | <gadget id="calculator">62 - 8</gadget>
<output>54</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<result>B</result> | B | 10 | A train 150 m long is running at a speed of 62 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? | {
"A": "5 sec",
"B": "10 sec",
"C": "12 sec",
"D": "18 sec",
"E": "15 sec"
} | divide(150, multiply(subtract(62, 8), const_0_2778)) | subtract(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "answer : b . speed of the train relative to man = ( 62 - 8 ) kmph = ( 54 * 5 / 18 ) m / sec = 15 m / sec time taken by the train to cross the man = time taken by it to cover 150 m at 15 m / sec = 150 * 1 / 15 sec = 10 sec" | physics |
math_qa__E6BkUoGB8t8KzhTl | The radius of a cone is 10 m, height 21 m. The volume of the cone is: Choices:
A) 2200
B) 1100
C) 5500
D) 3300
E) 1050 | <gadget id="calculator">pi * (10 ** 2) * 21 / 3</gadget>
<output>700*pi = around 2_199.114858</output>
<result>A</result> | A | 2,200 | The radius of a cone is 10 m, height 21 m. The volume of the cone is: | {
"A": "2200",
"B": "1100",
"C": "5500",
"D": "3300",
"E": "1050"
} | volume_cone(10, 21) | volume_cone(n0,n1) | 1 / 3 π rh = 1 / 3 × 22 / 7 × 100 × 21 = 2200 m ( power 3 ) answer is a . | geometry |
math_qa__SMaMwJFvvspNc4gz | Jamshid can paint a fence in 50 percent less time than Taimour can when each works alone. When they work together, they can paint the fence in 5 hours. How long would it take Taimour to paint the fence alone? Choose the correct choice from the following answers:
A) 6 hours B) 8 hours C) 15 hours D) 24 hours E) 32 hours | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<result>C</result> | C | 15 | Jamshid can paint a fence in 50 percent less time than Taimour can when each works alone. When they work together, they can paint the fence in 5 hours. How long would it take Taimour to paint the fence alone? | {
"A": "6 hours",
"B": "8 hours",
"C": "15 hours",
"D": "24 hours",
"E": "32 hours"
} | multiply(5, const_3) | multiply(n1,const_3)| | "i believe the answer is c . please see below for explanation . if jamshid can paint a dence in 50 percent less time then taimour we can infer the following rate j = 2 t if working together they can do the job in 8 hours we can infer 1 = 2 t + t * 5 = > 1 / 15 working alone taimour can do the job in 1 = 1 / 15 * hours = > 15 answer c" | physics |
math_qa__KBQWD4LsEhVVTGD3 | A man can row upstream at 15 kmph and downstream at 25 kmph, and then find the speed of the man in still water? Choose the most appropriate option: A) 27 B) 29 C) 30 D) 20 E) 24 | <gadget id="calculator">15 + 25</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<result>D</result> | D | 20 | A man can row upstream at 15 kmph and downstream at 25 kmph, and then find the speed of the man in still water? | {
"A": "27",
"B": "29",
"C": "30",
"D": "20",
"E": "24"
} | divide(add(15, 25), const_2) | add(n0,n1)|divide(#0,const_2)| | "us = 15 ds = 25 m = ( 15 + 25 ) / 2 = 20 answer : d" | physics |
math_qa__PmXnUAIN9RVE6acF | workers decided to raise Rs.3 lacs by equal contribution from each. Had they contributed Rs.50 eachextra, the contribution would have been Rs.3.60 lacs . How many workers were they? Options
A) 220 B) 230 C) 1200 D) 560 E) 590 | <gadget id="calculator">3.6 - 3</gadget>
<output>0.6</output>
<gadget id="calculator">0.6 * 1_000</gadget>
<output>600</output>
<gadget id="calculator">600 * 100</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 50</gadget>
<output>1_200</output>
<result>C</result> | C | 1,200 | workers decided to raise Rs.3 lacs by equal contribution from each. Had they contributed Rs.50 eachextra, the contribution would have been Rs.3.60 lacs . How many workers were they? | {
"A": "220",
"B": "230",
"C": "1200",
"D": "560",
"E": "590"
} | divide(multiply(multiply(subtract(3.60, 3), const_1000), const_100), 50) | subtract(n2,n0)|multiply(#0,const_1000)|multiply(#1,const_100)|divide(#2,n1)| | "n * 50 = ( 360000 - 300000 ) = 60000 n = 60000 / 50 = 1200 c" | general |
math_qa__9ZczzUSybFdXNgRU | If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land Tails up exectly twice in 3 consecutive flips ? Answers:
A) 0.375
B) 0.25
C) 0.325
D) 0.5
E) 0.666 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 3</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 3</gadget>
<output>3/8 = around 0.375</output>
<result>A</result> | A | 0.375 | If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land Tails up exectly twice in 3 consecutive flips ? | {
"A": "0.375",
"B": "0.25",
"C": "0.325",
"D": "0.5",
"E": "0.666"
} | multiply(power(divide(const_1, const_2), 3), 3) | divide(const_1,const_2)|power(#0,n0)|multiply(n0,#1)| | "total number of ways in which h or t can appear in 3 tosses of coin is = 2 * 2 * 2 = 8 ways for 2 t and 1 th thus probability is = p ( htt ) + p ( tth ) + p ( tht ) = 1 / 8 + 1 / 8 + 1 / 8 = 3 / 8 = . 375 answer : a" | general |
math_qa__qN943cyk9iIeZ56k | If the average (arithmetic mean) of 10 consecutive odd integers is 154, then the least of these integers is
Choose one
A) 51 B) 58 C) 145 D) 190 E) 210 | <gadget id="calculator">154 - 10</gadget>
<output>144</output>
<gadget id="calculator">144 + 1</gadget>
<output>145</output>
<result>C</result> | C | 145 | If the average (arithmetic mean) of 10 consecutive odd integers is 154, then the least of these integers is | {
"A": "51",
"B": "58",
"C": "145",
"D": "190",
"E": "210"
} | add(subtract(154, 10), const_1) | subtract(n1,n0)|add(#0,const_1)| | "a very helpful rule to know in arithmetic is the rule that in evenly spaced sets , average = median . because the average will equal the median in these sets , then we quickly know that the median of this set of consecutive odd integer numbers is 154 . there are 10 numbers in the set , and in a set with an even number of terms the median is just the average of the two most median terms ( here the 5 th and 6 th numbers in the set ) . this means that numbers 5 and 6 in this set are 153 and 155 . because we know that number 5 is 153 , we know that the smallest number is 4 odd numbers below this , which means that it is 4 * 2 = 8 below this ( every odd number is every other number ) . therefore 153 - 8 = 145 , answer choice c" | general |
math_qa__xE9N3tNsOcOjQk0k | each of 3 investments has a 20 % of becoming worthless within a year of purchase , independently of what happens to the other two investments . if simone invests an equal sum v in each of these 3 investments on january 1 , the approximate chance that by the end of the year , she loses no more than 1 / 3 of her original investment is
Select:
A) 90 % B) 80 % C) 70 % D) 60 % E) 40 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) ** 3</gadget>
<output>1/125 = around 0.008</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * (1/5)</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * (1/5)</gadget>
<output>4/125 = around 0.032</output>
<gadget id="calculator">(4/125) * 3</gadget>
<output>12/125 = around 0.096</output>
<gadget id="calculator">(1/125) + (12/125)</gadget>
<output>13/125 = around 0.104</output>
<gadget id="calculator">-(13/125)</gadget>
<output>-13/125 = around -0.104</output>
<gadget id="calculator">1 + (-13/125)</gadget>
<output>112/125 = around 0.896</output>
<gadget id="calculator">(112/125) * 100</gadget>
<output>448/5 = around 89.6</output>
<result>A</result> | A | 90 | each of 3 investments has a 20 % of becoming worthless within a year of purchase , independently of what happens to the other two investments . if simone invests an equal sum v in each of these 3 investments on january 1 , the approximate chance that by the end of the year , she loses no more than 1 / 3 of her original investment is | {
"A": "90 %",
"B": "80 %",
"C": "70 %",
"D": "60 %",
"E": "40 %"
} | multiply(add(1, negate(add(power(divide(20, const_100), 3), multiply(multiply(multiply(subtract(const_1, divide(20, const_100)), divide(20, const_100)), divide(20, const_100)), 3)))), const_100) | divide(n1,const_100)|power(#0,n0)|subtract(const_1,#0)|multiply(#0,#2)|multiply(#0,#3)|multiply(n0,#4)|add(#5,#1)|negate(#6)|add(n3,#7)|multiply(#8,const_100) | the problem asks for the approximate chance that no more than 1 / 3 of the original investment is lost . we can apply the “ 1 – x ” technique : what ’ s the chance that more than 1 / 3 of the original investment is lost ? there are two outcomes we have to separately measure : ( a ) all 3 investments become worthless . ( b ) 2 of the 3 investments become worthless , while 1 doesn ’ t . outcome ( a ) : the probability is ( 0.2 ) ( 0.2 ) ( 0.2 ) = 0.008 , or a little less than 1 % . outcome ( b ) : call the investments x , y , and z . the probability that x retains value , while y and z become worthless , is ( 0.8 ) ( 0.2 ) ( 0.2 ) = 0.032 . now , we have to do the same thing for the specific scenarios in which y retains value ( while x and z don ’ t ) and in which z retains value ( while x and y don ’ t ) . each of those scenarios results in the same math : 0.032 . thus , we can simply multiply 0.032 by 3 to get 0.096 , or a little less than 10 % . the sum of these two probabilities is 0.008 + 0.096 = 0.104 , or a little more than 10 % . finally , subtracting from 100 % and rounding , we find that the probability we were looking for is approximately 90 % . the correct answer is a . this problem illustrates the power of diversification in financial investments . all else being equal , it ’ s less risky to hold a third of your money in three uncorrelated ( independent ) but otherwise equivalent investments than to put all your eggs in one of the baskets . that said , be wary of historical correlations ! housing price changes in different us cities were not so correlated — and then they became highly correlated during the recent housing crisis ( they all fell together ) , fatally undermining spreadsheet models that assumed that these price changes were independent . | general |
math_qa__pH07yNhBvIZXQ7L9 | a man owns 2/3 of market reserch beauro buzness,and sells 3/4 of his shares for 75000rs,what is the value of buzness?
Choose the correct answer
A) 150000 B) 160000 C) 170000 D) 190000 E) 250000 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(2/3) * (3/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">75_000 / (1/2)</gadget>
<output>150_000</output>
<result>A</result> | A | 150,000 | a man owns 2/3 of market reserch beauro buzness,and sells 3/4 of his shares for 75000rs,what is the value of buzness? | {
"A": "150000",
"B": "160000",
"C": "170000",
"D": "190000",
"E": "250000"
} | divide(75000, multiply(divide(2, 3), divide(3, 4))) | divide(n0,n1)|divide(n1,n3)|multiply(#0,#1)|divide(n4,#2)| | "if value of business = x total sell ( 2 x / 3 ) ( 3 / 4 ) = 75000 - > x = 150000 answer : a" | general |
math_qa__LShnChWUHQPNw07r | on a certain day , joey , the ice - cream seller sold his ice creams to 4 different kids in a manner that each of the kids purchased half of the remaining ice creams and half ice - cream more . if we tell you that the fourth kid bought just a single ice cream , can you find out how many ice creams were sold by joey that day ?
Choose the correct choice from the following
A) 15
B) 20
C) 22
D) 12
E) 8 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 8</gadget>
<output>16</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<result>A</result> | A | 15 | on a certain day , joey , the ice - cream seller sold his ice creams to 4 different kids in a manner that each of the kids purchased half of the remaining ice creams and half ice - cream more . if we tell you that the fourth kid bought just a single ice cream , can you find out how many ice creams were sold by joey that day ? | {
"A": "15",
"B": "20",
"C": "22",
"D": "12",
"E": "8"
} | subtract(add(multiply(4, const_2), multiply(4, const_2)), const_1) | multiply(n0,const_2)|add(#0,#0)|subtract(#1,const_1) | a joey sold 15 ice creams that day . the fourth kid bought a single ice cream . therefore , we have the following equation : total - ( total / 2 + 1 / 2 ) = 1 solving it , we get the total as 3 . let ' s work this method till we reach the first kid . the first kid bought 15 / 2 + 1 / 2 = 8 ( leaving 7 ) the second kid bought 7 / 2 + 1 / 2 = 4 ( leaving 3 ) the third kid bought 3 / 2 + 1 / 2 = 2 ( leaving 1 ) the fourth kid bought 1 / 2 + 1 / 2 = 1 adding all of them together , we get 8 + 4 + 2 + 1 = 15 . | general |
math_qa__YL866u60rbdQwMda | If a truck is traveling at a constant rate of 72 kilometers per hour, how many seconds will it take the truck to travel a distance of 600 meters? (1 kilometer = 1000 meters) Choose the correct option
A) 18 B) 24 C) 30 D) 36 E) 48 | <gadget id="calculator">600 / 1_000</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) / 72</gadget>
<output>1/120 = around 0.008333</output>
<gadget id="calculator">(1/120) * 3_600</gadget>
<output>30</output>
<result>C</result> | C | 30 | If a truck is traveling at a constant rate of 72 kilometers per hour, how many seconds will it take the truck to travel a distance of 600 meters? (1 kilometer = 1000 meters) | {
"A": "18",
"B": "24",
"C": "30",
"D": "36",
"E": "48"
} | multiply(divide(divide(600, 1000), 72), const_3600) | divide(n1,n3)|divide(#0,n0)|multiply(#1,const_3600)| | "speed = 72 km / hr = > 72,000 m / hr in one minute = > 72000 / 60 = 1200 meters in one sec = > 1200 / 60 = 20 meters time = total distance need to be covered / avg . speed = > 600 / 20 = 30 and hence the answer : c" | physics |
math_qa__srP5aw7P0EToGLZS | The total cost of a vacation was divided among 3 people. If the total cost of the vacation had been divided equally among 4 people, the cost per person would have been $40 less. What was the total cost cost of the vacation? Choose the correct choice.
A) $ 200
B) $ 300
C) $ 480
D) $ 500
E) $ 600 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">40 / 1</gadget>
<output>40</output>
<gadget id="calculator">12 * 40</gadget>
<output>480</output>
<result>C</result> | C | 480 | The total cost of a vacation was divided among 3 people. If the total cost of the vacation had been divided equally among 4 people, the cost per person would have been $40 less. What was the total cost cost of the vacation? | {
"A": "$ 200",
"B": "$ 300",
"C": "$ 480",
"D": "$ 500",
"E": "$ 600"
} | multiply(multiply(4, 3), divide(40, subtract(4, 3))) | multiply(n0,n1)|subtract(n1,n0)|divide(n2,#1)|multiply(#2,#0)| | "c for cost . p price per person . c = 3 * p c = 4 * p - 160 substituting the value of p from the first equation onto the second we get p = 160 . plugging in the value of p in the first equation , we get c = 480 . which leads us to answer choice c" | general |
math_qa__7YM4BVIP8eDiWiqM | A certain mixture of nuts consists of 5 parts almonds to 2 parts walnuts, by weight. What is the number of pounds of almonds in 150 pounds of the mixture ?
Select the correct option:
A) 107 B) 84 C) 40 D) 28 E) 20 | <gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">750 / 7</gadget>
<output>750/7 = around 107.142857</output>
<result>A</result> | A | 107 | A certain mixture of nuts consists of 5 parts almonds to 2 parts walnuts, by weight. What is the number of pounds of almonds in 150 pounds of the mixture ? | {
"A": "107",
"B": "84",
"C": "40",
"D": "28",
"E": "20"
} | divide(multiply(5, 150), add(5, 2)) | add(n0,n1)|multiply(n0,n2)|divide(#1,#0)| | "almonds : walnuts = 5 : 2 total mixture has 7 parts in a 150 pound mixture , almonds are 5 / 7 ( total mixture ) = 5 / 7 * 150 = 107 pounds answer ( a )" | general |
math_qa__tCYW8dSx0gncJq8s | In the coordinate plane, points (x, 1) and (5, y) are on line k. If line k passes through the origin and has slope 1/5, then what are the values of x and y respectively? Choose the correct choice from the following answers.
A) 4 and 1
B) 1 and 5
C) 5 and 1
D) 3 and 5
E) 5 and 3 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">25 * (1/5)</gadget>
<output>5</output>
<result>C</result> | C | 5 | In the coordinate plane, points (x, 1) and (5, y) are on line k. If line k passes through the origin and has slope 1/5, then what are the values of x and y respectively? | {
"A": "4 and 1",
"B": "1 and 5",
"C": "5 and 1",
"D": "3 and 5",
"E": "5 and 3"
} | multiply(multiply(5, 5), divide(1, 5)) | divide(n0,n3)|multiply(n1,n3)|multiply(#0,#1)| | "line k passes through the origin and has slope 1 / 5 means that its equation is y = 1 / 5 * x . thus : ( x , 1 ) = ( 5 , 1 ) and ( 5 , y ) = ( 5,1 ) - - > x = 5 and y = 1 answer : c" | general |
math_qa__6C1ZRo4GJkhnQ3ou | One fourth of a solution that was 13% salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent salt by weight? Choose the correct choice from the following choices:
A) 25 % B) 34 % C) 22 % D) 18 % E) 8.5 % | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * 4</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">13 / 100</gadget>
<output>13/100 = around 0.13</output>
<gadget id="calculator">(13/100) * 4</gadget>
<output>13/25 = around 0.52</output>
<gadget id="calculator">(13/25) - (13/100)</gadget>
<output>39/100 = around 0.39</output>
<gadget id="calculator">(16/25) - (39/100)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>A</result> | A | 25 | One fourth of a solution that was 13% salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent salt by weight? | {
"A": "25 %",
"B": "34 %",
"C": "22 %",
"D": "18 %",
"E": "8.5 %"
} | multiply(subtract(multiply(divide(16, const_100), const_4), subtract(multiply(divide(13, const_100), const_4), divide(13, const_100))), const_100) | divide(n1,const_100)|divide(n0,const_100)|multiply(#0,const_4)|multiply(#1,const_4)|subtract(#3,#1)|subtract(#2,#4)|multiply(#5,const_100)| | "consider total solution to be 100 liters and in this case you ' ll have : 75 * 0.13 + 25 * x = 100 * 0.16 - - > x = 0.25 . answer : a ." | gain |
math_qa__BLDNdgKMqTlVLaR5 | If daily wages of a man is double to that of a woman, how many men should work for 25 days to earn Rs.14400? Given that wages for 40 women for 30 days are Rs.21600. Select the correct option
A) 12 B) 14 C) 16 D) 18 E) 20 | <gadget id="calculator">40 * 30</gadget>
<output>1_200</output>
<gadget id="calculator">21_600 / 1_200</gadget>
<output>18</output>
<gadget id="calculator">2 * 18</gadget>
<output>36</output>
<gadget id="calculator">25 * 36</gadget>
<output>900</output>
<gadget id="calculator">14_400 / 900</gadget>
<output>16</output>
<result>C</result> | C | 16 | If daily wages of a man is double to that of a woman, how many men should work for 25 days to earn Rs.14400? Given that wages for 40 women for 30 days are Rs.21600. | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "20"
} | divide(14400, multiply(25, multiply(const_2, divide(21600, multiply(40, 30))))) | multiply(n2,n3)|divide(n4,#0)|multiply(#1,const_2)|multiply(n0,#2)|divide(n1,#3) | explanation : wages of 1 woman for 1 day = 21600 / 40 × 30 wages of 1 man for 1 day = 21600 × 2 / 40 × 30 wages of 1 man for 25 days = 21600 × 2 × 25 / 40 × 30 number of men = 14400 / ( 21600 × 2 × 25 / 40 × 30 ) = 144 / ( 216 × 50 / 40 × 30 ) = 144 / 9 = 16 answer : option c | physics |
math_qa__K6PhxLQ2gQISqPZL | what is the compound interest on rs:30,000 for 4 months at the rate of 5% per annum Choose the correct choice from the following options.
A) 501.13 B) 502.13 C) 503.13 D) 504.13 E) 505.13 | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">300 * 100</gadget>
<output>30_000</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">4 / 12</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">5 * (1/3)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">30_000 * (5/3)</gadget>
<output>50_000</output>
<gadget id="calculator">50_000 / 100</gadget>
<output>500</output>
<result>C</result> | C | 503.13 | what is the compound interest on rs:30,000 for 4 months at the rate of 5% per annum | {
"A": "501.13",
"B": "502.13",
"C": "503.13",
"D": "504.13",
"E": "505.13"
} | divide(multiply(multiply(multiply(const_3, const_100), const_100), multiply(5, divide(4, multiply(const_4, const_3)))), const_100) | multiply(const_100,const_3)|multiply(const_3,const_4)|divide(n1,#1)|multiply(#0,const_100)|multiply(n2,#2)|multiply(#3,#4)|divide(#5,const_100) | it is monthly compound rate = 5 / 12 % per month 30000 * ( 1 + 5 / 1200 ) ^ 4 - 30000 = 503.13 answer : c | gain |
math_qa__wBttpZ3zTX1SAL1Q | The speed of a car is 90 km in the first hour and 40 km in the second hour. What is the average speed of the car?
Options: A) 12 B) 75 C) 88 D) 65 E) 15 | <gadget id="calculator">90 + 40</gadget>
<output>130</output>
<gadget id="calculator">130 / 2</gadget>
<output>65</output>
<result>D</result> | D | 65 | The speed of a car is 90 km in the first hour and 40 km in the second hour. What is the average speed of the car? | {
"A": "12",
"B": "75",
"C": "88",
"D": "65",
"E": "15"
} | divide(add(90, 40), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 90 + 40 ) / 2 = 65 kmph answer : d" | physics |
math_qa__XZLMQseAww6bnxtt | How many trailing Zeroes does 53! + 54! have? Choose the correct answer.
A) 12
B) 13
C) 14
D) 15
E) 16 | <gadget id="calculator">54 + 1</gadget>
<output>55</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">55 / 5</gadget>
<output>11</output>
<gadget id="calculator">11 + 2</gadget>
<output>13</output>
<result>B</result> | B | 13 | How many trailing Zeroes does 53! + 54! have? | {
"A": "12",
"B": "13",
"C": "14",
"D": "15",
"E": "16"
} | add(divide(add(54, const_1), add(const_1, const_4)), const_2) | add(n1,const_1)|add(const_1,const_4)|divide(#0,#1)|add(#2,const_2) | 53 ! + 54 ! = 53 ! + 54 * 53 ! = 53 ! ( 1 + 54 ) = 53 ! * 55 number of trailing 0 s in 53 ! = number of 5 s in the expansion of 53 ! = 10 + 2 = 12 there is 1 more 5 in 55 . hence , total number of trailing 0 s = 12 + 1 = 13 answer ( b ) . in most cases , when we are adding multiple terms , all of which have trailing 0 s , the sum will have as many trailing 0 s as that in the lowest term . example : 20 + 2300 + 34210000 = 34212320 - > one 0 because lowest term 20 has one 0 . this case has an exception because of an additional 5 in 55 . answer is b | other |
math_qa__RbstAqibSXjQuW5N | An empty fuel tank with a capacity of 208 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added? Choose the correct choice
A) 160 B) 150 C) 82 D) 80 E) 50 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">208 * (4/25)</gadget>
<output>832/25 = around 33.28</output>
<gadget id="calculator">(832/25) - 30</gadget>
<output>82/25 = around 3.28</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(4/25) - (3/25)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(82/25) / (1/25)</gadget>
<output>82</output>
<result>C</result> | C | 82 | An empty fuel tank with a capacity of 208 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added? | {
"A": "160",
"B": "150",
"C": "82",
"D": "80",
"E": "50"
} | divide(subtract(multiply(208, divide(16, const_100)), 30), subtract(divide(16, const_100), divide(12, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n3)|divide(#4,#3)| | "say there are a gallons of fuel a in the tank , then there would be 208 - a gallons of fuel b . the amount of ethanol in a gallons of fuel a is 0.12 a ; the amount of ethanol in 208 - a gallons of fuel b is 0.16 ( 208 - a ) ; since the total amount of ethanol is 30 gallons then 0.12 a + 0.16 ( 208 - a ) = 30 - - > a = 82 . answer : c ." | gain |
math_qa__sYzD0daN04F6Yba1 | 5020−(502÷100.4)=? Choose the correct choice.
A) 15 B) 20 C) 5015 D) 25 E) 35 | <gadget id="calculator">502 / 100.4</gadget>
<output>5</output>
<gadget id="calculator">5_020 - 5</gadget>
<output>5_015</output>
<result>C</result> | C | 5,015 | 5020−(502÷100.4)=? | {
"A": "15",
"B": "20",
"C": "5015",
"D": "25",
"E": "35"
} | subtract(5020, divide(502, 100.4)) | divide(n1,n2)|subtract(n0,#0)| | "explanation : = 5020 − ( 502 / 1004 × 10 ) = 5020 − 5 = 5015 option c" | general |
math_qa__r7b3S7QA6f890QaW | The average of 10 numbers is calculated as 46. It is discovered later on that while calculating the average, the number 65 was incorrectly read as 25, and this incorrect number was used in the calculation. What is the correct average? Choose the correct choice from the following answers: A) 48 B) 50 C) 54 D) 66 E) 86 | <gadget id="calculator">46 * 10</gadget>
<output>460</output>
<gadget id="calculator">460 - 25</gadget>
<output>435</output>
<gadget id="calculator">435 + 65</gadget>
<output>500</output>
<gadget id="calculator">500 / 10</gadget>
<output>50</output>
<result>B</result> | B | 50 | The average of 10 numbers is calculated as 46. It is discovered later on that while calculating the average, the number 65 was incorrectly read as 25, and this incorrect number was used in the calculation. What is the correct average? | {
"A": "48",
"B": "50",
"C": "54",
"D": "66",
"E": "86"
} | divide(add(subtract(multiply(46, 10), 25), 65), 10) | multiply(n0,n1)|subtract(#0,n3)|add(n2,#1)|divide(#2,n0)| | "the total sum of the numbers should be increased by 40 . then the average will increase by 40 / 10 = 4 . the correct average is 50 . the answer is b ." | general |
math_qa__1VMeY5n72X5lVCVH | A part-time employee whose hourly wage was decreased by 20 percent decided to increase the number of hours worked per week so that the employee's total income did not change. By what percent W should the number of hours worked be increased? Choose the correct choice from the following choices
A) 12.5 % B) 20 % C) 25 % D) 50 % E) 100 % | <gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 10</gadget>
<output>8</output>
<gadget id="calculator">40 / 8</gadget>
<output>5</output>
<gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | A part-time employee whose hourly wage was decreased by 20 percent decided to increase the number of hours worked per week so that the employee's total income did not change. By what percent W should the number of hours worked be increased? | {
"A": "12.5 %",
"B": "20 %",
"C": "25 %",
"D": "50 %",
"E": "100 %"
} | multiply(divide(subtract(divide(multiply(const_10, const_4), multiply(divide(subtract(const_100, 20), const_100), const_10)), const_4), const_4), const_100) | multiply(const_10,const_4)|subtract(const_100,n0)|divide(#1,const_100)|multiply(#2,const_10)|divide(#0,#3)|subtract(#4,const_4)|divide(#5,const_4)|multiply(#6,const_100)| | "correct answer : c solution : c . we can set up equations for income before and after the wage reduction . initially , the employee earns w wage and works h hours per week . after the reduction , the employee earns . 8 w wage and works x hours . by setting these equations equal to each other , we can determine the increase in hours worked : wh = . 8 wx ( divide both sides by . 8 w ) 1.25 h = x we know that the new number of hours worked w will be 25 % greater than the original number . the answer is c ." | general |
math_qa__ILwvDphLcYIYw1gW | John spends $320 buying his favorite dolls. If he buys only small Monkey dolls, which are $4 cheaper than the large Monkey dolls, he could buy 40 more dolls than if he were to buy only large Monkey dolls. How much does a large Monkey doll cost?
Choose one: A) $ 7.2 B) $ 7.5 C) $ 8 D) $ 9 E) $ 10 | <gadget id="calculator">4 * 40</gadget>
<output>160</output>
<gadget id="calculator">320 - 160</gadget>
<output>160</output>
<gadget id="calculator">160 / 4</gadget>
<output>40</output>
<gadget id="calculator">40 + 40</gadget>
<output>80</output>
<gadget id="calculator">320 / 80</gadget>
<output>4</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<result>C</result> | C | 8 | John spends $320 buying his favorite dolls. If he buys only small Monkey dolls, which are $4 cheaper than the large Monkey dolls, he could buy 40 more dolls than if he were to buy only large Monkey dolls. How much does a large Monkey doll cost? | {
"A": "$ 7.2",
"B": "$ 7.5",
"C": "$ 8",
"D": "$ 9",
"E": "$ 10"
} | add(divide(320, add(divide(subtract(320, multiply(4, 40)), 4), 40)), 4) | multiply(n1,n2)|subtract(n0,#0)|divide(#1,n1)|add(n2,#2)|divide(n0,#3)|add(n1,#4) | a and b is not an integer . so we start with c if large doll costs $ 8 , then he can buy 320 / 8 = 40 large dolls and 320 / 4 = 80 small dolls . difference is 40 , which is we wanted . answer c . | general |
math_qa__MHvoVhILwfwNI6nB | Two trains, each 100 m long, moving in opposite directions, cross other in 12 sec. If one is moving twice as fast the other, then the speed of the faster train is? Choose the correct option.
A) 26 km / hr B) 40 km / hr C) 60 km / hr D) 77 km / hr E) 46 km / hr | <gadget id="calculator">100 + 100</gadget>
<output>200</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">200 / 36</gadget>
<output>50/9 = around 5.555556</output>
<gadget id="calculator">(50/9) * 2</gadget>
<output>100/9 = around 11.111111</output>
<gadget id="calculator">(100/9) * 3_600</gadget>
<output>40_000</output>
<gadget id="calculator">40_000 / 1_000</gadget>
<output>40</output>
<result>B</result> | B | 40 | Two trains, each 100 m long, moving in opposite directions, cross other in 12 sec. If one is moving twice as fast the other, then the speed of the faster train is? | {
"A": "26 km / hr",
"B": "40 km / hr",
"C": "60 km / hr",
"D": "77 km / hr",
"E": "46 km / hr"
} | divide(multiply(multiply(divide(add(100, 100), multiply(12, add(const_1, const_2))), const_2), const_3600), const_1000) | add(n0,n0)|add(const_1,const_2)|multiply(n1,#1)|divide(#0,#2)|multiply(#3,const_2)|multiply(#4,const_3600)|divide(#5,const_1000)| | "let the speed of the slower train be x m / sec . then , speed of the train = 2 x m / sec . relative speed = ( x + 2 x ) = 3 x m / sec . ( 100 + 100 ) / 12 = 3 x = > x = 50 / 9 . so , speed of the faster train = 100 / 9 = 100 / 9 * 18 / 5 = 40 km / hr . answer : b" | physics |
math_qa__pesE7Q4rtqttLvPP | A profit of Rs. 1000 is divided between X and Y in the ratio of 1/2:1/3 . What is the difference between their profit shares ? Options.
A) s . 200
B) s . 100
C) s . 300
D) s . 50
E) s . 90 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/2) + (1/3)</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">1_000 / (5/6)</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 2</gadget>
<output>600</output>
<gadget id="calculator">1_200 / 3</gadget>
<output>400</output>
<gadget id="calculator">600 - 400</gadget>
<output>200</output>
<result>A</result> | A | 200 | A profit of Rs. 1000 is divided between X and Y in the ratio of 1/2:1/3 . What is the difference between their profit shares ? | {
"A": "s . 200",
"B": "s . 100",
"C": "s . 300",
"D": "s . 50",
"E": "s . 90"
} | subtract(divide(divide(1000, add(divide(1, 2), divide(1, 3))), 2), divide(divide(1000, add(divide(1, 2), divide(1, 3))), 3)) | divide(n1,n2)|divide(n1,n4)|add(#0,#1)|divide(n0,#2)|divide(#3,n2)|divide(#3,n4)|subtract(#4,#5)| | "a profit of rs . 1000 is divided between x and y in the ratio of 1 / 2 : 1 / 3 or 3 : 2 . so profits are 600 and 400 . difference in profit share = 600 - 400 = 200 answer : a" | general |
math_qa__08yh0Ogki6DjmLj4 | There is a total of 120 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/4 and the probability that it will be green is 1/3. What is the probability that the marble will be either red or blue ? Pick one: A) 1 / 6 B) 1 / 4 C) 2 / 7 D) 1 / 3 E) 5 / 12 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/4) + (1/3)</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">1 - (7/12)</gadget>
<output>5/12 = around 0.416667</output>
<result>E</result> | E | 0.416667 | There is a total of 120 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/4 and the probability that it will be green is 1/3. What is the probability that the marble will be either red or blue ? | {
"A": "1 / 6",
"B": "1 / 4",
"C": "2 / 7",
"D": "1 / 3",
"E": "5 / 12"
} | subtract(1, add(divide(1, 4), divide(1, 3))) | divide(n1,n2)|divide(n3,n4)|add(#0,#1)|subtract(n1,#2)| | "total marbles in the box = 120 white marbles = 120 / 4 = 30 green marbles = 120 / 3 = 40 w + g = 70 red + blue = 50 p ( red or blue ) = 50 / 120 = 5 / 12 answer : e" | general |
math_qa__nXENmAuwoI268y61 | Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in?
Choose one
A) 08 hours B) 12 hours C) 03 hours D) 04 hours E) 21 hours | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(2/3) * (1/8)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>B</result> | B | 12 | Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in? | {
"A": "08 hours",
"B": "12 hours",
"C": "03 hours",
"D": "04 hours",
"E": "21 hours"
} | inverse(multiply(divide(const_2, const_3), divide(const_1, 8))) | divide(const_2,const_3)|divide(const_1,n0)|multiply(#0,#1)|inverse(#2)| | "the part of the tank filled by three pipes in one hour = 1 / 8 = > the part of the tank filled by two pipes in 1 hour = 2 / 3 * 1 / 8 = 1 / 12 . the tank can be filled in 12 hours . answer : b" | physics |
math_qa__E286DTdZsxdfVJ1C | If a2 + b2 + c2 = 941 and ab + bc + ca = 10, then a + b + c is
Choose the correct choice from the following options
A) 44 B) 56 C) 16 D) 32 E) 31 | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">941 + 20</gadget>
<output>961</output>
<gadget id="calculator">961 ** (1/2)</gadget>
<output>31</output>
<result>E</result> | E | 31 | If a2 + b2 + c2 = 941 and ab + bc + ca = 10, then a + b + c is | {
"A": "44",
"B": "56",
"C": "16",
"D": "32",
"E": "31"
} | sqrt(add(941, multiply(10, 2))) | multiply(n4,n0)|add(n3,#0)|sqrt(#1)| | "by formula , ( a + b + c ) ^ 2 = a ^ 2 + b ^ 2 + c ^ 2 + 2 ( ab + bc + ca ) , since , a ^ 2 + b ^ 2 + c ^ 2 = 941 and ab + bc + ca = 10 , ( a + b + c ) ^ 2 = 941 + 2 ( 10 ) = 961 = 31 ^ 2 therefore : a + b + c = 31 answer : e" | general |
math_qa__hLJjdoM5lePpP5q5 | What is the tens digit of 6^18?
Choose the correct option
A) 1
B) 3
C) 5
D) 7
E) 9 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">18 % 5</gadget>
<output>3</output>
<gadget id="calculator">6 ** 3</gadget>
<output>216</output>
<gadget id="calculator">216 % 100</gadget>
<output>16</output>
<gadget id="calculator">16 / 10</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">floor(8/5)</gadget>
<output>1</output>
<result>A</result> | A | 1 | What is the tens digit of 6^18? | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | floor(divide(reminder(power(6, reminder(18, add(const_4, const_1))), const_100), const_10)) | add(const_1,const_4)|reminder(n1,#0)|power(n0,#1)|reminder(#2,const_100)|divide(#3,const_10)|floor(#4)| | "the tens digit of 6 in integer power starting from 2 ( 6 ^ 1 has no tens digit ) repeats in a pattern of 5 : { 3 , 1 , 9 , 7 , 5 } : the tens digit of 6 ^ 2 = 36 is 3 . the tens digit of 6 ^ 3 = 216 is 1 . the tens digit of 6 ^ 4 = . . . 96 is 9 . the tens digit of 6 ^ 5 = . . . 76 is 7 . the tens digit of 6 ^ 6 = . . . 56 is 5 . the tens digit of 6 ^ 7 = . . . 36 is 3 again . etc . . . 18 has the form 5 n + 3 , so the tens digit of 6 ^ 18 is 1 . the answer is a ." | general |
math_qa__S952dTrgPC06zbFv | If Dev works alone he will take 20 more hours to complete a task than if he worked with Tina to complete the task. If Tina works alone, she will take 5 more hours to complete the complete the task, then if she worked with Dev to complete the task? What is the ratio of the time taken by Dev to that taken by Tina if each of them worked alone to complete the task?
Pick
A) 4 : 1 B) 2 : 1 C) 10 : 1 D) 3 : 1 E) 1 : 2 | <gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">5 + 10</gadget>
<output>15</output>
<gadget id="calculator">30 / 15</gadget>
<output>2</output>
<result>B</result> | B | 2 | If Dev works alone he will take 20 more hours to complete a task than if he worked with Tina to complete the task. If Tina works alone, she will take 5 more hours to complete the complete the task, then if she worked with Dev to complete the task? What is the ratio of the time taken by Dev to that taken by Tina if each of them worked alone to complete the task? | {
"A": "4 : 1",
"B": "2 : 1",
"C": "10 : 1",
"D": "3 : 1",
"E": "1 : 2"
} | divide(add(20, sqrt(multiply(20, 5))), add(5, sqrt(multiply(20, 5)))) | multiply(n0,n1)|sqrt(#0)|add(n0,#1)|add(n1,#1)|divide(#2,#3) | let time taken by dev to complete the work alone be x days and that by tina be y days work done by dev in 1 day = 1 / x work done by tina in 1 day = 1 / y work done by devtina in 1 day = 1 / x + 1 / y = ( x + y ) / xy thus working together they will complete the work in xy / ( x + y ) days acc . to the ques : 1 ) if dev works alone he will take 20 more hours to complete a task than if he worked with tina ' x - xy / ( x + y ) = 20 = > ( x ^ 2 ) / ( x + y ) = 20 . . . . . . . . . . . . . ( i ) 2 ) if tina works alone , she will take 5 more hours to complete the complete the task , then if she worked with dev y - xy / ( x + y ) = 5 = > ( y ^ 2 ) / ( x + y ) = 5 . . . . . . . . . . . . . . ( ii ) dividing ( i ) by ( ii ) x ^ 2 / y ^ 2 = 4 = > x / y = 2 ans : b hope it helps | physics |
math_qa__GhWPGG7UTbZURT2h | A train 140 m long is running with a speed of 50 km/hr. In what time will it pass a man who is running at 4 km/hr in the direction opposite to that in which the train is going? Choices.
A) 8.1 B) 7.0 C) 9.33 D) 8 E) 9 | <gadget id="calculator">50 + 4</gadget>
<output>54</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">140 / 15</gadget>
<output>28/3 = around 9.333333</output>
<result>C</result> | C | 9.33 | A train 140 m long is running with a speed of 50 km/hr. In what time will it pass a man who is running at 4 km/hr in the direction opposite to that in which the train is going? | {
"A": "8.1",
"B": "7.0",
"C": "9.33",
"D": "8",
"E": "9"
} | divide(140, multiply(add(50, 4), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 50 + 4 = 54 km / hr . = 54 * 5 / 18 = 15 m / sec . time taken to pass the men = 140 * 1 / 15 = 9.33 sec . answer : option c" | physics |
math_qa__YAHnA7u4bgqRw0tW | A train 110 m long is running with a speed of 40 km/hr. In what time will it pass a man who is running at 5 km/hr in the direction opposite to that in which the train is going?
Choose the correct answer.
A) 5
B) 6
C) 7.5
D) 8.8
E) 9 | <gadget id="calculator">40 + 5</gadget>
<output>45</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">45 * (5/18)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">110 / (25/2)</gadget>
<output>44/5 = around 8.8</output>
<result>D</result> | D | 8.8 | A train 110 m long is running with a speed of 40 km/hr. In what time will it pass a man who is running at 5 km/hr in the direction opposite to that in which the train is going? | {
"A": "5",
"B": "6",
"C": "7.5",
"D": "8.8",
"E": "9"
} | divide(110, multiply(add(40, 5), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 40 + 5 = 45 km / hr . = 45 * 5 / 18 = 25 / 2 m / sec . time taken to pass the men = 110 * 2 / 25 = 8.8 sec . answer : option d" | physics |
math_qa__z10AUhGlLnnNOfik | John and Steve are speed walkers in a race. John is 15 meters behind Steve when he begins his final push. John blazes to the finish at a pace of 4.2 m/s, while Steve maintains a blistering 3.8 m/s speed. If John finishes the race 2 meters ahead of Steve, how long was John’s final push? Choose the correct choice from the following answers.
A) 13 seconds B) 17 seconds C) 26 seconds D) 34 seconds E) 42.5 seconds | <gadget id="calculator">15 + 2</gadget>
<output>17</output>
<gadget id="calculator">3.8 * 17</gadget>
<output>64.6</output>
<gadget id="calculator">4.2 - 3.8</gadget>
<output>0.4</output>
<gadget id="calculator">64.6 / 0.4</gadget>
<output>161.5</output>
<gadget id="calculator">161.5 + 17</gadget>
<output>178.5</output>
<gadget id="calculator">178.5 / 4.2</gadget>
<output>42.5</output>
<result>E</result> | E | 42.5 | John and Steve are speed walkers in a race. John is 15 meters behind Steve when he begins his final push. John blazes to the finish at a pace of 4.2 m/s, while Steve maintains a blistering 3.8 m/s speed. If John finishes the race 2 meters ahead of Steve, how long was John’s final push? | {
"A": "13 seconds",
"B": "17 seconds",
"C": "26 seconds",
"D": "34 seconds",
"E": "42.5 seconds"
} | divide(add(divide(multiply(3.8, add(15, 2)), subtract(4.2, 3.8)), add(15, 2)), 4.2) | add(n0,n3)|subtract(n1,n2)|multiply(n2,#0)|divide(#2,#1)|add(#0,#3)|divide(#4,n1)| | "let t be the time that john spent for his final push . thus , per the question , 4.2 t = 3.8 t + 15 + 2 - - - > 0.4 t = 17 - - - > t = 42.5 seconds . e is the correct answer ." | physics |
math_qa__DMSXFyeUWCHHAMhH | An error 2.5% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is Choose the correct choice.
A) 6.04 % B) 5.14 % C) 5.23 % D) 5.0625 % E) 5.5 % | <gadget id="calculator">100 + 2.5</gadget>
<output>102.5</output>
<gadget id="calculator">102.5 ** 2</gadget>
<output>10_506.25</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">10_506.25 - 10_000</gadget>
<output>506.25</output>
<gadget id="calculator">506.25 * 100</gadget>
<output>50_625</output>
<gadget id="calculator">50_625 / 10_000</gadget>
<output>81/16 = around 5.0625</output>
<result>D</result> | D | 5.0625 | An error 2.5% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is | {
"A": "6.04 %",
"B": "5.14 %",
"C": "5.23 %",
"D": "5.0625 %",
"E": "5.5 %"
} | divide(multiply(subtract(square_area(add(const_100, 2.5)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)| | "100 cm is read as 102 cm . a 1 = ( 100 x 100 ) cm 2 and a 2 ( 102.5 x 102.5 ) cm 2 . ( a 2 - a 1 ) = [ ( 102.5 ) 2 - ( 100 ) 2 ] = ( 102.5 + 100 ) x ( 102.5 - 100 ) = 506.25 cm 2 . percentage error = 5.0625 d" | gain |
math_qa__c2gcApatgFeKDy7V | The average of 10 consecutive integers is 20. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average? Choices.
A) 14 B) 14.5 C) 15 D) 15.5 E) 16 | <gadget id="calculator">10 * 20</gadget>
<output>200</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 9</gadget>
<output>45</output>
<gadget id="calculator">200 - 45</gadget>
<output>155</output>
<gadget id="calculator">155 / 10</gadget>
<output>31/2 = around 15.5</output>
<result>D</result> | D | 15.5 | The average of 10 consecutive integers is 20. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average? | {
"A": "14",
"B": "14.5",
"C": "15",
"D": "15.5",
"E": "16"
} | divide(subtract(multiply(10, 20), multiply(add(const_4, const_1), 9)), 10) | add(const_1,const_4)|multiply(n0,n1)|multiply(n2,#0)|subtract(#1,#2)|divide(#3,n0)| | "the total subtracted is ( 9 + 8 + . . . + 1 ) = ( 9 * 10 ) / 2 = 45 on average , each number will be reduced by 45 / 10 = 4.5 therefore , the overall average will be reduced by 4.5 the answer is d ." | general |
math_qa__CWxivPd7HRxvwalD | A person decided to build a house in 100days. He employed 100men in the beginning and 100 more after 10 days and completed the construction in stipulated time. If he had not employed the additional men , how many days behind schedule would it have been finished? Choose the most appropriate option.
A) 40 B) 80 C) 70 D) 60 E) 90 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<result>E</result> | E | 90 | A person decided to build a house in 100days. He employed 100men in the beginning and 100 more after 10 days and completed the construction in stipulated time. If he had not employed the additional men , how many days behind schedule would it have been finished? | {
"A": "40",
"B": "80",
"C": "70",
"D": "60",
"E": "90"
} | subtract(100, 10) | subtract(n0,n3)| | "200 men do the rest of the work in 100 - 10 = 90 days 100 men can do the rest of the work in 90 * 200 / 100 = 180 days required number of days = 180 - 90 = 90 days answer is e" | general |
math_qa__sjhLyb0B06gr8nMH | Suresh can complete a job in 15 hours. Ashutosh alone can complete the same job in 30 hours. Suresh works for 9 hours and then the remaining job is completed by Ashutosh. How many hours will it take Ashutosh to complete the remaining job alone? Pick one
A) 4
B) 5
C) 6
D) 12
E) none of these | <gadget id="calculator">9 / 15</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 30</gadget>
<output>12</output>
<result>D</result> | D | 12 | Suresh can complete a job in 15 hours. Ashutosh alone can complete the same job in 30 hours. Suresh works for 9 hours and then the remaining job is completed by Ashutosh. How many hours will it take Ashutosh to complete the remaining job alone? | {
"A": "4",
"B": "5",
"C": "6",
"D": "12",
"E": "none of these"
} | multiply(subtract(const_1, divide(9, 15)), 30) | divide(n2,n0)|subtract(const_1,#0)|multiply(n1,#1)| | "the part of job that suresh completes in 9 hours = 9 â „ 15 = 3 â „ 5 remaining job = 1 - 3 â „ 5 = 2 â „ 5 remaining job can be done by ashutosh in 2 â „ 5 ã — 30 = 12 hours answer d" | physics |
math_qa__rio8rNQsnYLujRtw | Only a single rail track exists between stations A and B on a railway line. One hour after the north bound super fast train N leaves station A for station B, a south-bound passenger train S reaches
station A from station B. The speed of the super fast train is twice that of a normal express train E, while the speed of a passenger train S is half that of E. On a particular day, N leaves for B from A, 20 min behind the normal schedule. In order to maintain the schedule, both N and S increased their speeds. If the super fast train doubles its speed, what should be the ratio (approximately) of the speeds of passenger train to that of the super fast train so that the passenger train S reaches exactly at the scheduled time at A on that day? Answers.
A) 1 : 3
B) 1 : 4
C) 1 : 5
D) 1 : 6
E) 1 : 7 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">20 - 6</gadget>
<output>14</output>
<gadget id="calculator">14 - 2</gadget>
<output>12</output>
<gadget id="calculator">2 / 12</gadget>
<output>1/6 = around 0.166667</output>
<result>D</result> | D | 0.166667 | Only a single rail track exists between stations A and B on a railway line. One hour after the north bound super fast train N leaves station A for station B, a south-bound passenger train S reaches
station A from station B. The speed of the super fast train is twice that of a normal express train E, while the speed of a passenger train S is half that of E. On a particular day, N leaves for B from A, 20 min behind the normal schedule. In order to maintain the schedule, both N and S increased their speeds. If the super fast train doubles its speed, what should be the ratio (approximately) of the speeds of passenger train to that of the super fast train so that the passenger train S reaches exactly at the scheduled time at A on that day? | {
"A": "1 : 3",
"B": "1 : 4",
"C": "1 : 5",
"D": "1 : 6",
"E": "1 : 7"
} | divide(const_2, subtract(subtract(20, divide(const_12, const_2)), const_2)) | divide(const_12,const_2)|subtract(n0,#0)|subtract(#1,const_2)|divide(const_2,#2) | explanation : if speed of n = 4 , speed of s = 1 . = > average speed = ( 2 x 4 x 1 ) / ( 4 + 1 ) = 1.6 . because time available is 2 / 3 , speed = 3 / 2 . now average speed = 2.4 now speed of n = 8 . speed of s = y . = > ( 2 x 8 x y ) / ( 8 + y ) = 2.4 = > y = 1.3 the required ratio is 1.3 : 8 i . e 1 : 6 . answer : d | general |
math_qa__8fgxJwnRwz84MMmM | A can complete a project in 20 days and B can complete the same project in 30 days. If A and B start working on the project together and A quits 15 days before the project is completed, in how many days total will the project be completed? Choose the correct option: A) 18 B) 21 C) 24 D) 27 E) 30 | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) * 15</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + (1/30)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/2) / (1/12)</gadget>
<output>6</output>
<gadget id="calculator">6 + 15</gadget>
<output>21</output>
<result>B</result> | B | 21 | A can complete a project in 20 days and B can complete the same project in 30 days. If A and B start working on the project together and A quits 15 days before the project is completed, in how many days total will the project be completed? | {
"A": "18",
"B": "21",
"C": "24",
"D": "27",
"E": "30"
} | add(divide(subtract(const_1, multiply(divide(const_1, 30), 15)), add(divide(const_1, 20), divide(const_1, 30))), 15) | divide(const_1,n1)|divide(const_1,n0)|add(#1,#0)|multiply(n2,#0)|subtract(const_1,#3)|divide(#4,#2)|add(n2,#5) | a ' s rate is 1 / 20 of the project per day . b ' s rate is 1 / 30 of the project per day . the combined rate is 1 / 12 of the project per day . in the last 15 days , b can do 1 / 2 of the project . thus a and b must complete 1 / 2 of the project , which takes 6 days . the total number of days is 6 + 15 = 21 . the answer is b . | physics |
math_qa__48ulzFnwChjiDDTT | 2.2 cubic dm of lead is to be drawn into a cylindrical wire 0.50 cm diameter. Find the length of the wire in meters. Pick one: A) 110 B) 111 C) 113 D) 112 E) none of them | <gadget id="calculator">2.2 * 1_000</gadget>
<output>2_200</output>
<gadget id="calculator">0.5 / 2</gadget>
<output>0.25</output>
<gadget id="calculator">pi * (0.25 ** 2)</gadget>
<output>0.0625*pi = around 0.19635</output>
<gadget id="calculator">2_200 / (0.0625*pi)</gadget>
<output>35200.0/pi = around 11_204.507994</output>
<gadget id="calculator">(35200.0/pi) / 100</gadget>
<output>352.0/pi = around 112.04508</output>
<result>D</result> | D | 112 | 2.2 cubic dm of lead is to be drawn into a cylindrical wire 0.50 cm diameter. Find the length of the wire in meters. | {
"A": "110",
"B": "111",
"C": "113",
"D": "112",
"E": "none of them"
} | divide(divide(multiply(2.2, const_1000), circle_area(divide(0.5, const_2))), const_100) | divide(n1,const_2)|multiply(n0,const_1000)|circle_area(#0)|divide(#1,#2)|divide(#3,const_100) | let the length of the wire be h meters . then , ∏ ( 0.50 / ( 2 x 100 ) ) ^ 2 x h = 2.2 / 1000 = h = ( ( 2.2 / 1000 ) x ( 100 x 100 ) / ( 0.25 x 0.25 ) x ( 7 / 22 ) ) = 112 m . answer is d . | geometry |
math_qa__bebHp6SOpN1vus91 | There are 2 sections A and B in a class, consisting of 36 and 24 students respectively. If the average weight of section A is 30kg and that of section B is 30kg, Find the average of the whole class? Choose the correct choice from the following choices.
A) 30 kg B) 37 kg C) 42 kg D) 55.12 kg E) 29.78 kg | <gadget id="calculator">36 * 30</gadget>
<output>1_080</output>
<gadget id="calculator">24 * 30</gadget>
<output>720</output>
<gadget id="calculator">1_080 + 720</gadget>
<output>1_800</output>
<gadget id="calculator">36 + 24</gadget>
<output>60</output>
<gadget id="calculator">1_800 / 60</gadget>
<output>30</output>
<result>A</result> | A | 30 | There are 2 sections A and B in a class, consisting of 36 and 24 students respectively. If the average weight of section A is 30kg and that of section B is 30kg, Find the average of the whole class? | {
"A": "30 kg",
"B": "37 kg",
"C": "42 kg",
"D": "55.12 kg",
"E": "29.78 kg"
} | divide(add(multiply(36, 30), multiply(24, 30)), add(36, 24)) | add(n1,n2)|multiply(n1,n3)|multiply(n2,n4)|add(#1,#2)|divide(#3,#0)| | "total weight of 36 + 44 students = 36 * 30 + 24 * 30 = 1800 average weight of the class is = 1800 / 60 = 30 kg answer is a" | general |
math_qa__JFMSoi4Cif8i040S | Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has travelled 100 km more than the second. The distance between P and Q is :
Choose the correct choice from the following answers
A) 500 km B) 630 km C) 900 km D) 660 km E) none | <gadget id="calculator">100 * 40</gadget>
<output>4_000</output>
<gadget id="calculator">50 - 40</gadget>
<output>10</output>
<gadget id="calculator">4_000 / 10</gadget>
<output>400</output>
<gadget id="calculator">400 + 100</gadget>
<output>500</output>
<gadget id="calculator">500 + 400</gadget>
<output>900</output>
<result>C</result> | C | 900 | Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has travelled 100 km more than the second. The distance between P and Q is : | {
"A": "500 km",
"B": "630 km",
"C": "900 km",
"D": "660 km",
"E": "none"
} | add(add(divide(multiply(100, 40), subtract(50, 40)), 100), divide(multiply(100, 40), subtract(50, 40))) | multiply(n1,n2)|subtract(n0,n1)|divide(#0,#1)|add(n2,#2)|add(#3,#2)| | "sol . at the time of meeting , let the distane travelled byb the second train be x km . then , distance covered by the first train is ( x + 100 ) km ∴ x / 40 = ( x + 100 ) / 50 ⇔ 50 x = 40 x 4000 ⇔ x = 400 . so , distance between p and q = ( x + x + 100 ) km = 900 km . answer c" | physics |
math_qa__Yp3fyA2JYP9CC6Jh | A is thrice as good a workman as B and takes 10 days less to do a piece of work than B takes. B alone can do the whole work in Choose the most appropriate option
A) 15 days B) 10 days C) 9 days D) 8 days E) 7 days | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>A</result> | A | 15 | A is thrice as good a workman as B and takes 10 days less to do a piece of work than B takes. B alone can do the whole work in | {
"A": "15 days",
"B": "10 days",
"C": "9 days",
"D": "8 days",
"E": "7 days"
} | divide(multiply(const_3, 10), const_2) | multiply(n0,const_3)|divide(#0,const_2) | explanation : ratio of times taken by a and b = 1 : 3 means b will take 3 times which a will do in 1 time if difference of time is 2 days , b takes 3 days if difference of time is 10 days , b takes ( 3 / 2 ) * 10 = 15 days option a | physics |
math_qa__bJMaj4ohuw4nVrS6 | The difference between simple and compound interest on Rs. 1500 for one year at 10% per annum reckoned half-yearly is?
Choose the correct choice from the following answers: A) 8.0 B) 3.0 C) 9.5 D) 3.75 E) 2.15 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(441/400) - (11/10)</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">(1/400) * 1_500</gadget>
<output>15/4 = around 3.75</output>
<result>D</result> | D | 3.75 | The difference between simple and compound interest on Rs. 1500 for one year at 10% per annum reckoned half-yearly is? | {
"A": "8.0",
"B": "3.0",
"C": "9.5",
"D": "3.75",
"E": "2.15"
} | multiply(subtract(power(add(divide(divide(10, const_2), const_100), const_1), const_2), add(divide(10, const_100), const_1)), 1500) | divide(n1,const_2)|divide(n1,const_100)|add(#1,const_1)|divide(#0,const_100)|add(#3,const_1)|power(#4,const_2)|subtract(#5,#2)|multiply(n0,#6)| | "s . i . = ( 1500 * 10 * 1 ) / 100 = rs . 150 c . i . = [ 1500 * ( 1 + 5 / 100 ) 2 - 1500 ] = rs . 153.75 difference = ( 153.75 - 150 ) = rs . 3.75 answer : d" | gain |
math_qa__obAcm6oAARNvt9ZF | In a class,12 students like to play Basketball and 8 like to play Cricket. 3 students like to play on both Basketball and Cricket. How many students like to play Basketball or Cricket or both?
Choose the correct option
A) 12 B) 15 C) 17 D) 18 E) 22 | <gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">20 - 3</gadget>
<output>17</output>
<result>C</result> | C | 17 | In a class,12 students like to play Basketball and 8 like to play Cricket. 3 students like to play on both Basketball and Cricket. How many students like to play Basketball or Cricket or both? | {
"A": "12",
"B": "15",
"C": "17",
"D": "18",
"E": "22"
} | subtract(add(12, 8), 3) | add(n0,n1)|subtract(#0,n2)| | "draw a venn diagram yourself ! b + c - bc = number of students that play either basketball or cricket 12 + 8 - 3 = 17 c )" | other |
math_qa__YBZUVUkcz2ELMfBB | In a graduate physics course, 70 percent of the students are male and 30 percent of the students are married. If one-sevenths of the male students are married, what fraction of the female students is single? Select the correct option: A) 1 / 3 B) 1 / 7 C) 1 / 2 D) 2 / 3 E) 5 / 7 | <gadget id="calculator">10 / 30</gadget>
<output>1/3 = around 0.333333</output>
<result>A</result> | A | 0.333333 | In a graduate physics course, 70 percent of the students are male and 30 percent of the students are married. If one-sevenths of the male students are married, what fraction of the female students is single? | {
"A": "1 / 3",
"B": "1 / 7",
"C": "1 / 2",
"D": "2 / 3",
"E": "5 / 7"
} | divide(const_10, 30) | divide(const_10,n1) | let assume there are 100 students of which 70 are male and 30 are females if 30 are married then 70 will be single . now its given that two - sevenths of the male students are married that means 1 / 7 of 70 = 10 males are married if 30 is the total number of students who are married and out of that 10 are males then the remaining 20 will be females who are married . total females = 30 married females = 20 then single females = 30 - 20 = 10 we need to find the fraction of female students who are single i . e single female students / total female student = 10 / 30 = 1 / 3 [ a ] | gain |
math_qa__5bGhQPxbgqGop6V5 | A train ride from Two P to Town Q costs $6.35 more than does a bus ride from Town P to Town Q. Together, the cost of one train ride and one bus ride is $9.85. What is the cost of a bus ride from Town P to Town Q? Choose the correct choice from the following answers.
A) $ 1.75 B) $ 2.50 C) $ 4.10 D) $ 4.70 E) $ 8.20 | <gadget id="calculator">9.85 - 6.35</gadget>
<output>3.5</output>
<gadget id="calculator">3.5 / 2</gadget>
<output>1.75</output>
<result>A</result> | A | 1.75 | A train ride from Two P to Town Q costs $6.35 more than does a bus ride from Town P to Town Q. Together, the cost of one train ride and one bus ride is $9.85. What is the cost of a bus ride from Town P to Town Q? | {
"A": "$ 1.75",
"B": "$ 2.50",
"C": "$ 4.10",
"D": "$ 4.70",
"E": "$ 8.20"
} | divide(subtract(9.85, 6.35), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "let x be the cost of a bus ride . x + ( x + 635 ) = 985 2 x = 350 x = $ 1.75 the answer is a ." | general |
math_qa__34PwyV66MJWLKFPF | A drink vendor has 10 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required? Select.
A) 135
B) 261
C) 422
D) 430
E) 438 | <gadget id="calculator">gcd(10, 144)</gadget>
<output>2</output>
<gadget id="calculator">gcd(2, 368)</gadget>
<output>2</output>
<gadget id="calculator">368 / 2</gadget>
<output>184</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">144 / 2</gadget>
<output>72</output>
<gadget id="calculator">5 + 72</gadget>
<output>77</output>
<gadget id="calculator">184 + 77</gadget>
<output>261</output>
<result>B</result> | B | 261 | A drink vendor has 10 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required? | {
"A": "135",
"B": "261",
"C": "422",
"D": "430",
"E": "438"
} | add(divide(368, gcd(gcd(10, 144), 368)), add(divide(10, gcd(gcd(10, 144), 368)), divide(144, gcd(gcd(10, 144), 368)))) | gcd(n0,n1)|gcd(n2,#0)|divide(n0,#1)|divide(n1,#1)|divide(n2,#1)|add(#2,#3)|add(#5,#4)| | "the number of liters in each can = hcf of 10 , 144 and 368 = 2 liters . number of cans of maaza = 10 / 2 = 5 number of cans of pepsi = 144 / 2 = 72 number of cans of sprite = 368 / 2 = 184 the total number of cans required = 5 + 72 + 184 = 261 cans . answer : b" | general |
math_qa__mFBwIHZS4iHAiDaL | If 40% of a certain number is 160, then what is 30% of that number? Select:
A) 270 B) 380 C) 120 D) 360 E) 180 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">160 / (2/5)</gadget>
<output>400</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">400 * (3/10)</gadget>
<output>120</output>
<result>C</result> | C | 120 | If 40% of a certain number is 160, then what is 30% of that number? | {
"A": "270",
"B": "380",
"C": "120",
"D": "360",
"E": "180"
} | multiply(divide(160, divide(40, const_100)), divide(30, const_100)) | divide(n0,const_100)|divide(n2,const_100)|divide(n1,#0)|multiply(#2,#1)| | "explanation : 40 % = 40 * 4 = 160 30 % = 30 * 4 = 120 answer : option c" | gain |
math_qa__GD54y7rwQ0km4NLZ | If the sum of two numbers is 45 and the L.C.M and sum of the reciprocal of the numbers are 120 and 11/120 then HCF of numbers is equal to: Answers.
A) 55 B) 5 C) 10 D) 45 E) 4 | <gadget id="calculator">45 / 11</gadget>
<output>45/11 = around 4.090909</output>
<gadget id="calculator">floor(45/11)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<result>B</result> | B | 5 | If the sum of two numbers is 45 and the L.C.M and sum of the reciprocal of the numbers are 120 and 11/120 then HCF of numbers is equal to: | {
"A": "55",
"B": "5",
"C": "10",
"D": "45",
"E": "4"
} | add(floor(divide(45, 11)), const_1) | divide(n0,n2)|floor(#0)|add(#1,const_1) | let the numbers be a and b and hcf is x , then , a + b = 45 and ab = x * 120 = 120 x required sum = 1 / a + 1 / b = ( a + b ) / ab = 45 / 120 x = 11 / 120 . x = 5 . answer : b | general |
math_qa__SlRMsktDqntEGDji | Find the missing figures: 0.1% of ? = 0.24 Select: A) 12 B) 120 C) 24 D) 240 E) 36 | <gadget id="calculator">0.1 / 100</gadget>
<output>0.001</output>
<gadget id="calculator">0.24 / 0.001</gadget>
<output>240</output>
<result>D</result> | D | 240 | Find the missing figures: 0.1% of ? = 0.24 | {
"A": "12",
"B": "120",
"C": "24",
"D": "240",
"E": "36"
} | divide(0.24, divide(0.1, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "let 0.1 % of x = 0.24 . then , 0.1 * x / 100 = 0.24 x = [ ( 0.24 * 100 ) / 0.1 ] = 240 . answer is d ." | gain |
math_qa__Ccjh8DK3ilYnVuq2 | There has been successive increases of 25% and then 10% in the price of gas from the previous month. By what percentage should a driver reduce gas consumption so that the expenditure does not change? Choose the correct choice from the following answers:
A) 23 % B) 27 % C) 31 % D) 35 % E) 39 % | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 * 10</gadget>
<output>1_250</output>
<gadget id="calculator">1_250 / 100</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">125 + (25/2)</gadget>
<output>275/2 = around 137.5</output>
<gadget id="calculator">100 / (275/2)</gadget>
<output>8/11 = around 0.727273</output>
<gadget id="calculator">1 - (8/11)</gadget>
<output>3/11 = around 0.272727</output>
<gadget id="calculator">(3/11) * 100</gadget>
<output>300/11 = around 27.272727</output>
<result>B</result> | B | 27 | There has been successive increases of 25% and then 10% in the price of gas from the previous month. By what percentage should a driver reduce gas consumption so that the expenditure does not change? | {
"A": "23 %",
"B": "27 %",
"C": "31 %",
"D": "35 %",
"E": "39 %"
} | multiply(subtract(const_1, divide(const_100, add(add(const_100, 25), divide(multiply(add(const_100, 25), 10), const_100)))), const_100) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|add(#0,#2)|divide(const_100,#3)|subtract(const_1,#4)|multiply(#5,const_100)| | "let p be the original price per unit of gas . let x be the original gas consumption . let y be the reduced gas consumption . y * 1.1 * 1.25 * p = x * p y = x / ( 1.1 * 1.25 ) which is about 0.73 x which is a decrease of about 27 % . the answer is b ." | general |
math_qa__9Ex583TA7MhkxFLa | Pipe A can fill a tank in 60 min . There is a second pipe in the bottom of the cistern to empty it. If all the two pipes are simultaneously opened, then the cistern is full in 180 min. In how much time, the second pipe alone can empty the cistern?
Options.
A) 60 min B) 45 min C) 90 min D) 70 min E) 30 min | <gadget id="calculator">1 / 180</gadget>
<output>1/180 = around 0.005556</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/180) + (1/60)</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">1 / (1/45)</gadget>
<output>45</output>
<result>B</result> | B | 45 | Pipe A can fill a tank in 60 min . There is a second pipe in the bottom of the cistern to empty it. If all the two pipes are simultaneously opened, then the cistern is full in 180 min. In how much time, the second pipe alone can empty the cistern? | {
"A": "60 min",
"B": "45 min",
"C": "90 min",
"D": "70 min",
"E": "30 min"
} | inverse(add(divide(const_1, 180), divide(const_1, 60))) | divide(const_1,n1)|divide(const_1,n0)|add(#0,#1)|inverse(#2) | work done by the third pipe in 1 min = 1 / 180 - ( 1 / 60 ) = - 1 / 45 . [ - ve sign means emptying ] the third pipe alone can empty the cistern in 45 min . answer : b | physics |
math_qa__GlyWcprzs2wpkvxQ | A dishonest dealer claims to sell a product at its cost price. He uses a counterfeit weight which is 20% less than the real weight. Further greed overtook him and he added 35% impurities to the product. Find the net profit percentage of the dealer? Choose the correct choice from the following answers:
A) 44 % B) 40 % C) 68.75 % D) 56.25 % E) 36 % | <gadget id="calculator">100 + 35</gadget>
<output>135</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">135 / 80</gadget>
<output>27/16 = around 1.6875</output>
<gadget id="calculator">(27/16) - 1</gadget>
<output>11/16 = around 0.6875</output>
<gadget id="calculator">(11/16) * 100</gadget>
<output>275/4 = around 68.75</output>
<result>C</result> | C | 68.75 | A dishonest dealer claims to sell a product at its cost price. He uses a counterfeit weight which is 20% less than the real weight. Further greed overtook him and he added 35% impurities to the product. Find the net profit percentage of the dealer? | {
"A": "44 %",
"B": "40 %",
"C": "68.75 %",
"D": "56.25 %",
"E": "36 %"
} | multiply(subtract(divide(add(const_100, 35), subtract(const_100, 20)), const_1), const_100) | add(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)|subtract(#2,const_1)|multiply(#3,const_100)| | "the dealer uses weight which is 20 % less than the real weight . or ( 1 - 1 / 5 ) or 4 / 5 of real weight . it means that he is selling $ 4 worth of product for $ 5 . the dealer then further added 35 % impurities to the product . it means that he is selling $ 5 worth of product for $ 6.75 . so his profit is $ 6.75 - $ 4 = $ 2 and his profit percent is ( 2.75 / 4 ) * 100 = 68.75 % answer : - c" | general |
math_qa__CpjsPAQU8V0ny7dt | Nina has exactly enough money to purchase 6 widgets. If the cost of each widget were reduced by $2, then Nina would have exactly enough money to purchase 8 widgets. How much money does Nina have? Choose the correct choice from the following options.
A) $ 22 B) $ 24 C) $ 30 D) $ 36 E) $ 48 | <gadget id="calculator">2 * 8</gadget>
<output>16</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 6</gadget>
<output>48</output>
<result>E</result> | E | 48 | Nina has exactly enough money to purchase 6 widgets. If the cost of each widget were reduced by $2, then Nina would have exactly enough money to purchase 8 widgets. How much money does Nina have? | {
"A": "$ 22",
"B": "$ 24",
"C": "$ 30",
"D": "$ 36",
"E": "$ 48"
} | multiply(divide(multiply(2, 8), subtract(8, 6)), 6) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)|multiply(n0,#2) | e its is . let price = x ( x - 2 ) 8 = 6 x x = 8 hence total money = 6 * 8 = 48 | general |
math_qa__qqt8VUIKPicr15MY | According to a recent student poll, 3/4 out of 20 members of the finance club are interested in a career in investment banking. If two students are chosen at random, what is the probability that at least one of them is interested in investment banking?
Choose the most appropriate option
A) 1 / 14 B) 4 / 49 C) 18 / 19 D) 45 / 49 E) 13 / 14 | <gadget id="calculator">binomial(20, 2)</gadget>
<output>190</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">20 * (3/4)</gadget>
<output>15</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">190 - 10</gadget>
<output>180</output>
<gadget id="calculator">180 / 190</gadget>
<output>18/19 = around 0.947368</output>
<result>C</result> | C | 0.947368 | According to a recent student poll, 3/4 out of 20 members of the finance club are interested in a career in investment banking. If two students are chosen at random, what is the probability that at least one of them is interested in investment banking? | {
"A": "1 / 14",
"B": "4 / 49",
"C": "18 / 19",
"D": "45 / 49",
"E": "13 / 14"
} | divide(subtract(choose(20, const_2), choose(subtract(20, multiply(20, divide(3, 4))), const_2)), choose(20, const_2)) | choose(n2,const_2)|divide(n0,n1)|multiply(n2,#1)|subtract(n2,#2)|choose(#3,const_2)|subtract(#0,#4)|divide(#5,#0)| | "15 students are interested , 5 are not interested prob = 1 - 5 c 2 / 20 c 2 = 1 - ( 5 * 4 / ( 20 * 19 ) ) = 1 - 1 / 19 = 18 / 19 answer : c" | gain |
math_qa__VhTCYriap9i7VKlY | There are 4 red shoes & 4 green shoes . If two of red shoes are drawn what is the probability of getting red shoes Choose the correct choice from the following choices: A) 1 / 3 B) 1 / 14 C) 3 / 14 D) 1 / 15 E) 1 / 16 | <gadget id="calculator">binomial(4, 2)</gadget>
<output>6</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">binomial(8, 2)</gadget>
<output>28</output>
<gadget id="calculator">6 / 28</gadget>
<output>3/14 = around 0.214286</output>
<result>C</result> | C | 0.214286 | There are 4 red shoes & 4 green shoes . If two of red shoes are drawn what is the probability of getting red shoes | {
"A": "1 / 3",
"B": "1 / 14",
"C": "3 / 14",
"D": "1 / 15",
"E": "1 / 16"
} | divide(choose(4, const_2), choose(add(4, 4), const_2)) | add(n0,n1)|choose(n0,const_2)|choose(#0,const_2)|divide(#1,#2)| | "taking 2 red shoe the probability is 4 c 2 from 8 shoes probability of taking 2 red shoes is 4 c 2 / 8 c 2 = 3 / 14 answer : c" | probability |
math_qa__YXjcd78LYylaWYxI | Ram, who is half as efficient as Krish, will take 30 days to complete a task if he worked alone. If Ram and Krish worked together, how long will they take to complete the task? Options.
A) 16 days B) 10 days C) 8 days D) 6 days E) 18 days | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/30) + (1/15)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / (1/10)</gadget>
<output>10</output>
<result>B</result> | B | 10 | Ram, who is half as efficient as Krish, will take 30 days to complete a task if he worked alone. If Ram and Krish worked together, how long will they take to complete the task? | {
"A": "16 days",
"B": "10 days",
"C": "8 days",
"D": "6 days",
"E": "18 days"
} | inverse(add(divide(const_1, 30), divide(const_1, divide(30, const_2)))) | divide(const_1,n0)|divide(n0,const_2)|divide(const_1,#1)|add(#0,#2)|inverse(#3)| | "number of days taken by ram to complete task = 30 since ram is half as efficient as krish , amount of work done by krish in 1 day = amount of work done by ram in 2 days if total work done by ram in 30 days is 30 w amount of work done by ram in 1 day = w amount of work done by krish in 1 day = 2 w total amount of work done by krish and ram in a day = 3 w total amount of time needed by krish and ram to complete task = 30 w / 3 w = 10 days answer b" | physics |
math_qa__STT0zgpQhpnffIRI | Of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 5 grades are D's. What is the number of students in the course? Pick:
A) 80
B) 110
C) 160
D) 100
E) 400 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/5) + (1/4)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(9/20) + (1/2)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">1 - (19/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">5 / (1/20)</gadget>
<output>100</output>
<result>D</result> | D | 100 | Of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 5 grades are D's. What is the number of students in the course? | {
"A": "80",
"B": "110",
"C": "160",
"D": "100",
"E": "400"
} | divide(5, subtract(1, add(add(divide(1, 5), divide(1, 4)), divide(1, 2)))) | divide(n0,n1)|divide(n0,n3)|divide(n0,n5)|add(#0,#1)|add(#3,#2)|subtract(n0,#4)|divide(n6,#5)| | "we start by creating a variable for the total number of students in the math course . we can say : t = total number of students in the math course next , we can use variable t in an equation that we translate from the given information . we are given that , of the final grades received by the students in a certain math course , 1 / 5 are a ' s , 1 / 4 are b ' s , 1 / 2 are c ' s , and the remaining 5 grades are d ' s . since this represents all the grades in the class , it represents all the students in the class . thus we know : # a ’ s + # b ’ s + # c ’ s + # d ’ s = total number of students in the class 1 / 5 ( t ) + ¼ ( t ) + ½ ( t ) + 5 = t we can multiply the entire equation by 20 to cancel out the denominators of the fractions and we have : 4 t + 5 t + 10 t + 100 = 20 t 19 t + 100 = 20 t 100 = t there are a total of 100 students in the math class . answer is d ." | general |
math_qa__ZJi2kmilGjsGjeIH | The area of one square is x^2 + 12x + 36 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 64, what is the value of x? Choose the correct choice from the following answers: A) 0 B) 4.3 C) 2.5 D) 4.67 E) 10 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">24 - 12</gadget>
<output>12</output>
<gadget id="calculator">64 - 12</gadget>
<output>52</output>
<gadget id="calculator">52 / 12</gadget>
<output>13/3 = around 4.333333</output>
<result>B</result> | B | 4.3 | The area of one square is x^2 + 12x + 36 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 64, what is the value of x? | {
"A": "0",
"B": "4.3",
"C": "2.5",
"D": "4.67",
"E": "10"
} | divide(subtract(64, subtract(multiply(const_4, divide(12, const_2)), 12)), 12) | divide(n1,const_2)|multiply(#0,const_4)|subtract(#1,n1)|subtract(n7,#2)|divide(#3,n1) | spotting the pattern of equations both are in form of ( x + c ) ^ 2 so a 1 = ( x + 6 ) ^ 2 a 2 = ( 2 x - 3 ) ^ 2 l 1 = x + 6 l 2 = 2 x - 3 p 1 = 4 ( x + 6 ) p 2 = 4 ( 2 x - 3 ) p 1 + p 2 = 64 4 ( x + 6 ) + 4 ( 2 x - 3 ) = 64 . . . . . . . . . . . . . . > x = 4.3 answer : b | general |
math_qa__KEnR0q4KbYZLnsza | In one hour, a boat goes 6 km along the stream and 2 km against the stream. the sped of the boat in still water (in km/hr) is : Pick one: A) 4 B) 5 C) 8 D) 9 E) 10 | <gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>A</result> | A | 4 | In one hour, a boat goes 6 km along the stream and 2 km against the stream. the sped of the boat in still water (in km/hr) is : | {
"A": "4",
"B": "5",
"C": "8",
"D": "9",
"E": "10"
} | divide(add(6, 2), const_2) | add(n0,n1)|divide(#0,const_2)| | "solution speed in still water = 1 / 2 ( 6 + 2 ) km / hr = 4 kmph . answer a" | gain |
math_qa__VqEK1Ysa73eZZ6in | On the first day of her vacation, Louisa traveled 200 miles. On the second day, traveling at the same average speed, she traveled 350 miles. If the 200-mile trip took 3 hours less than the 350-mile trip, what was the average speed, in miles per hour?
Select the correct option: A) 45 B) 55 C) 60 D) 65 E) 50 | <gadget id="calculator">350 - 200</gadget>
<output>150</output>
<gadget id="calculator">150 / 3</gadget>
<output>50</output>
<result>E</result> | E | 50 | On the first day of her vacation, Louisa traveled 200 miles. On the second day, traveling at the same average speed, she traveled 350 miles. If the 200-mile trip took 3 hours less than the 350-mile trip, what was the average speed, in miles per hour? | {
"A": "45",
"B": "55",
"C": "60",
"D": "65",
"E": "50"
} | divide(subtract(350, 200), 3) | subtract(n1,n0)|divide(#0,n3)| | "( time ) * ( rate ) = ( distance ) - - > ( rate ) = ( distance ) / ( time ) - - > given : ( rate ) = 200 / t = 350 / ( t + 3 ) - - > 4 / t = 7 / ( t + 3 ) - - > 4 t + 12 = 7 t - - - - > 3 t = 12 . t = 4 - - - - > ( rate ) = 200 / 4 = 50 answer : e" | physics |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.