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stringlengths 7
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math_qa__RC8TpLRejEhIN7RR | A car ferry can hold up to 70 tons of cargo. What is the greatest number of vehicles that the ferry can carry if half the vehicles are cars with an average (arithmetic mean) weight of 0.75 tons and half of the vehicles are trucks with an average (arithmetic mean) weight of 5 tons?
Select the correct option: A) 12 B) 24 C) 36 D) 48 E) 60 | <gadget id="calculator">0.75 + 5</gadget>
<output>5.75</output>
<gadget id="calculator">70 / 5.75</gadget>
<output>12.173913</output>
<gadget id="calculator">12.173913 + 12.173913</gadget>
<output>24.347826</output>
<result>B</result> | B | 24 | A car ferry can hold up to 70 tons of cargo. What is the greatest number of vehicles that the ferry can carry if half the vehicles are cars with an average (arithmetic mean) weight of 0.75 tons and half of the vehicles are trucks with an average (arithmetic mean) weight of 5 tons? | {
"A": "12",
"B": "24",
"C": "36",
"D": "48",
"E": "60"
} | add(divide(70, add(0.75, 5)), divide(70, add(0.75, 5))) | add(n1,n2)|divide(n0,#0)|add(#1,#1) | the weight of one car and one truck is 5.75 tons . 70 / 5.75 = 12 plus a remainder the ferry could carry 12 cars and 12 trucks for a total of 24 vehicles . the answer is b . | general |
math_qa__yPx2RMRrHC8K65wu | If a student loses 5 kilograms, he will weigh twice as much as his sister. Together they now weigh 110 kilograms. What is the student's present weight in kilograms?
Choose the correct option: A) 71 B) 72 C) 73 D) 74 E) 75 | <gadget id="calculator">110 - 5</gadget>
<output>105</output>
<gadget id="calculator">105 / 3</gadget>
<output>35</output>
<gadget id="calculator">110 - 35</gadget>
<output>75</output>
<result>E</result> | E | 75 | If a student loses 5 kilograms, he will weigh twice as much as his sister. Together they now weigh 110 kilograms. What is the student's present weight in kilograms? | {
"A": "71",
"B": "72",
"C": "73",
"D": "74",
"E": "75"
} | subtract(110, divide(subtract(110, 5), const_3)) | subtract(n1,n0)|divide(#0,const_3)|subtract(n1,#1) | let x be the weight of the sister . then the student ' s weight is 2 x + 5 . x + ( 2 x + 5 ) = 110 3 x = 105 x = 35 kg then the student ' s weight is 75 kg . the answer is e . | other |
math_qa__cj0448NFPcQ0g2R3 | In a group of ducks and Cows, the total number of legs are 16 more than twice the no. of heads. Find the total no.of buffaloes. Choose the most appropriate option.
A) 10 B) 12 C) 8 D) 12 E) 14 | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>C</result> | C | 8 | In a group of ducks and Cows, the total number of legs are 16 more than twice the no. of heads. Find the total no.of buffaloes. | {
"A": "10",
"B": "12",
"C": "8",
"D": "12",
"E": "14"
} | divide(16, const_2) | divide(n0,const_2) | let the number of buffaloes be x and the number of ducks be y = > 4 x + 2 y = 2 ( x + y ) + 16 = > 2 x = 16 = > x = 8 c | general |
math_qa__xiKcPMFI9fZ0h2mL | The amounts of time that three secretaries worked on a special project are in the ratio of 2 to 3 to 5. If they worked a combined total of 110 hours, how many hours did the secretary who worked the longest spend on the project? Choose the most appropriate option: A) 80 B) 55 C) 56 D) 16 E) 14 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">110 / 10</gadget>
<output>11</output>
<gadget id="calculator">11 * 5</gadget>
<output>55</output>
<result>B</result> | B | 55 | The amounts of time that three secretaries worked on a special project are in the ratio of 2 to 3 to 5. If they worked a combined total of 110 hours, how many hours did the secretary who worked the longest spend on the project? | {
"A": "80",
"B": "55",
"C": "56",
"D": "16",
"E": "14"
} | multiply(divide(110, add(add(2, 3), 5)), 5) | add(n0,n1)|add(n2,#0)|divide(n3,#1)|multiply(n2,#2) | 10 x = 110 = > x = 11 therefore the secretary who worked the longest spent 11 x 5 = 55 hours on the project option ( b ) | physics |
math_qa__aHymwGaImL6j9kg5 | 3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 155kg then find the average weight of all the 7 rounds? Choose the correct choice:
A) 98.5 kgs B) 88.5 kgs C) 86.5 kgs D) 67.5 kgs E) 88.2 kgs | <gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 155</gadget>
<output>620</output>
<gadget id="calculator">620 / 7</gadget>
<output>620/7 = around 88.571429</output>
<result>B</result> | B | 88.5 | 3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 155kg then find the average weight of all the 7 rounds? | {
"A": "98.5 kgs",
"B": "88.5 kgs",
"C": "86.5 kgs",
"D": "67.5 kgs",
"E": "88.2 kgs"
} | divide(multiply(add(const_1, 3), 155), 7) | add(const_1,n0)|multiply(n2,#0)|divide(#1,n1)| | "average weight = [ ( a + b + c + ( a + b ) + ( b + c ) + ( c + a ) + ( a + b + c ) ] / 7 = 4 ( a + b + c ) / 7 = 4 x 155 / 7 = 88.5 kgs answer : b" | general |
math_qa__e0XuZB9uiKA0NvQK | Set J consists of 18 consecutive even numbers. If the smallest term in the set is -12, what is the range of the positive integers in set J?
Pick one.
A) 16 B) 18 C) 20 D) 22 E) 24 | <gadget id="calculator">-2</gadget>
<output>-2</output>
<gadget id="calculator">18 - 1</gadget>
<output>17</output>
<gadget id="calculator">17 * 2</gadget>
<output>34</output>
<gadget id="calculator">(-2) + 34</gadget>
<output>32</output>
<gadget id="calculator">32 - 12</gadget>
<output>20</output>
<result>C</result> | C | 20 | Set J consists of 18 consecutive even numbers. If the smallest term in the set is -12, what is the range of the positive integers in set J? | {
"A": "16",
"B": "18",
"C": "20",
"D": "22",
"E": "24"
} | subtract(add(negate(const_2.0), multiply(subtract(18, const_1), const_2.0)), 12) | negate(const_2.0)|subtract(n0,const_1)|multiply(const_2.0,#1)|add(#2,#0)|subtract(#3,n1)| | "since there are only 18 integers , another approach is the just list all 18 . we get : - 12 , - 10 , - 8 , - 6 , - 4 , - 2 , 0,2 , 4 , 6 , 8 , 10 , 12 , 14 , 16 , 18 , 20 , 22 range of positive integers = 22 - 2 = 20 answer : c" | general |
math_qa__IoDloGyHdtOFKDoB | Find the area of circle whose diameter is 8 m.
Choices.
A) 50.00 square meter B) 50.04 square meter C) 50.28 square meter D) 50.24 square meter E) 50.43 square meter | <gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">pi * (4 ** 2)</gadget>
<output>16*pi = around 50.265482</output>
<result>C</result> | C | 50.28 | Find the area of circle whose diameter is 8 m. | {
"A": "50.00 square meter",
"B": "50.04 square meter",
"C": "50.28 square meter",
"D": "50.24 square meter",
"E": "50.43 square meter"
} | circle_area(divide(8, const_2)) | divide(n0,const_2)|circle_area(#0) | diameter = 8 meter . radius = diameter / 2 . = 8 / 2 . = 4 meter . area of a circle = ï € r 2 . here , pi ( ï € ) = 3.14 meter , radius ( r ) = 4 . area of a circle = 3.14 ã — 4 ã — 4 . . = 3.14 ã — 16 . = 50.28 square meter answer : c | geometry |
math_qa__frPPV5TQJqdUtzoq | Bruce and Anne can clean their house in 4 hours working together at their respective constant rates. If Anne’s speed were doubled, they could clean their house in 3 hours working at their respective rates. How many S hours does it currently take Anne to clean the house on her own? Options.
A) 6
B) 7
C) 8
D) 12
E) 14 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) - (1/4)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>D</result> | D | 12 | Bruce and Anne can clean their house in 4 hours working together at their respective constant rates. If Anne’s speed were doubled, they could clean their house in 3 hours working at their respective rates. How many S hours does it currently take Anne to clean the house on her own? | {
"A": "6",
"B": "7",
"C": "8",
"D": "12",
"E": "14"
} | inverse(subtract(divide(const_1, 3), divide(const_1, 4))) | divide(const_1,n1)|divide(const_1,n0)|subtract(#0,#1)|inverse(#2)| | "lets suppose anne and bruce take a and b hrs working separately so in 1 hour they can together finish 1 / a + 1 / b portion of the work which equals 1 / 4 ( as the work is completed in 4 hours ) after anne doubles her rate of work the portion completed by the both is 1 / a + 2 / b which is equal to 1 / 3 ( as the work is completed in s = 3 hours ) solving these 2 equations we can find b as 12 so , d" | physics |
math_qa__9JQYOO1j7m9JPc4z | Having received his weekly allowance, a student spent 2/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $1.20 at the candy store. What is this student’s weekly allowance?
Choose the correct choice from the following.
A) $ 2.00
B) $ 2.25
C) $ 2.50
D) $ 2.75
E) $ 3.00 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 * 1.2</gadget>
<output>12</output>
<gadget id="calculator">12 / 4</gadget>
<output>3</output>
<result>E</result> | E | 3 | Having received his weekly allowance, a student spent 2/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $1.20 at the candy store. What is this student’s weekly allowance? | {
"A": "$ 2.00",
"B": "$ 2.25",
"C": "$ 2.50",
"D": "$ 2.75",
"E": "$ 3.00"
} | divide(multiply(multiply(2, 5), 1.20), const_4) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_4)| | "let x be the value of the weekly allowance . ( 2 / 3 ) ( 3 / 5 ) x = 120 cents ( 2 / 5 ) x = 120 x = $ 3.00 the answer is e ." | general |
math_qa__HH6Vx0jDtl0aVu0f | Ashley paid 5 dollars for 1 notebook and 1 pencil. If both prices were integers, how many pencils did Ashley buy if she paid 93 dollars for the pencils and for 15 notebooks? Choose one: A) 6 . B) 16 . C) 18 D) 21 E) 26 | <gadget id="calculator">15 + 5</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<result>D</result> | D | 21 | Ashley paid 5 dollars for 1 notebook and 1 pencil. If both prices were integers, how many pencils did Ashley buy if she paid 93 dollars for the pencils and for 15 notebooks? | {
"A": "6 .",
"B": "16 .",
"C": "18",
"D": "21",
"E": "26"
} | add(add(15, 5), const_1) | add(n0,n4)|add(#0,const_1) | 5 = 1 p + 1 n 93 = xp + 15 n , where x is the number of pencils possible prices for 1 p & 1 n ( integers ) : n = 1 p = 4 then 15 n = 15 , 4 x = 93 - 15 = 78 , x = 19.5 ( not an integer ) n = 2 p = 3 then 15 n = 30 , 3 x = 93 - 30 = 63 , x = 21 ( the answer we were looking for , no need to continue calculations ) n = 3 p = 2 n = 4 p = 1 answer : d | other |
math_qa__cGfaTVvLP9GzIItE | In a certificate by mistake a candidate gave his height as 25% more than actual height. In the interview panel, he clarified that his height was 5feet 10 inches. Find the % correction made by the candidate from his stated height to his actual height? Select:
A) 10 B) 20 C) 17.5 D) 43 E) 50 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + (1/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">25 + (1/2)</gadget>
<output>51/2 = around 25.5</output>
<gadget id="calculator">(51/2) - 5</gadget>
<output>41/2 = around 20.5</output>
<gadget id="calculator">100 + (41/2)</gadget>
<output>241/2 = around 120.5</output>
<gadget id="calculator">(41/2) / (241/2)</gadget>
<output>41/241 = around 0.170124</output>
<gadget id="calculator">(41/241) * 100</gadget>
<output>4_100/241 = around 17.012448</output>
<result>C</result> | C | 17.5 | In a certificate by mistake a candidate gave his height as 25% more than actual height. In the interview panel, he clarified that his height was 5feet 10 inches. Find the % correction made by the candidate from his stated height to his actual height? | {
"A": "10",
"B": "20",
"C": "17.5",
"D": "43",
"E": "50"
} | multiply(divide(subtract(add(25, add(const_0_25, const_0_25)), 5), add(const_100, subtract(add(25, add(const_0_25, const_0_25)), 5))), const_100) | add(const_0_25,const_0_25)|add(n0,#0)|subtract(#1,n1)|add(#2,const_100)|divide(#2,#3)|multiply(#4,const_100)| | "his height was = 5 feet 5 inch = 10 + 60 = 70 inch . required % correction = 70 * ( 1.25 - 1 ) = 17.5 c" | gain |
math_qa__B8azkAomzF2VTMSd | At Deluxe paint store, Fuchsia paint is made by mixing 5 parts of red paint with 3 parts of blue paint. Mauve paint is made by mixing 3 parts of red paint with 6 parts blue paint. How many liters of blue paint must be added to 16 liters of Fuchsia to change it to Mauve paint?
Select the correct option: A) 9 B) 12 C) 14 D) 16 E) 18 | <gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">16 * (5/8)</gadget>
<output>10</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">10 / (3/8)</gadget>
<output>80/3 = around 26.666667</output>
<gadget id="calculator">6 / 8</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(80/3) * (3/4)</gadget>
<output>20</output>
<gadget id="calculator">16 - 10</gadget>
<output>6</output>
<gadget id="calculator">20 - 6</gadget>
<output>14</output>
<result>C</result> | C | 14 | At Deluxe paint store, Fuchsia paint is made by mixing 5 parts of red paint with 3 parts of blue paint. Mauve paint is made by mixing 3 parts of red paint with 6 parts blue paint. How many liters of blue paint must be added to 16 liters of Fuchsia to change it to Mauve paint? | {
"A": "9",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | subtract(multiply(divide(multiply(16, divide(5, add(5, 3))), divide(3, add(5, 3))), divide(6, add(5, 3))), subtract(16, multiply(16, divide(5, add(5, 3))))) | add(n0,n1)|divide(n0,#0)|divide(n2,#0)|divide(n3,#0)|multiply(n4,#1)|divide(#4,#2)|subtract(n4,#4)|multiply(#5,#3)|subtract(#7,#6)| | "in 16 liters , red = 5 / 8 * 16 = 10 and blue = 6 so , 10 / ( 6 + x ) = 3 / 6 or , x = 14 ( answer c )" | general |
math_qa__yItyAkMlPcHOS2un | In 1979 approximately 1/3 of the 37.3 million airline passengers traveling to or from the United States used Kennedy Airport. If the number of such passengers that used Miami Airport was 1/3 the number that used Kennedy Airport and 4 times the number that used Logan Airport, approximately how many millions of these passengers used Logan Airport that year? Select
A) 18.6 B) 9.3 C) 6.2 D) 3.1 E) 1.01 | <gadget id="calculator">37.3 / 3</gadget>
<output>12.433333</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12.433333 / 12</gadget>
<output>1.036111</output>
<result>E</result> | E | 1.01 | In 1979 approximately 1/3 of the 37.3 million airline passengers traveling to or from the United States used Kennedy Airport. If the number of such passengers that used Miami Airport was 1/3 the number that used Kennedy Airport and 4 times the number that used Logan Airport, approximately how many millions of these passengers used Logan Airport that year? | {
"A": "18.6",
"B": "9.3",
"C": "6.2",
"D": "3.1",
"E": "1.01"
} | divide(divide(37.3, 3), multiply(4, 3)) | divide(n3,n2)|multiply(n5,n6)|divide(#0,#1)| | "number of passengers using kennedy airport = 37 / 3 = ~ 12.43 passengers using miami airport = 12.43 / 3 = ~ 4.14 passengers using logan airport = 4.14 / 4 = ~ 1.01 so e" | general |
math_qa__R3zX0SdmYaUjkqJy | A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished? Choices:
A) 1
B) 5
C) 7
D) 8
E) 2 | <gadget id="calculator">100 * 35</gadget>
<output>3_500</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">100 * 2</gadget>
<output>200</output>
<gadget id="calculator">5 * 200</gadget>
<output>1_000</output>
<gadget id="calculator">3_500 + 1_000</gadget>
<output>4_500</output>
<gadget id="calculator">4_500 / 100</gadget>
<output>45</output>
<gadget id="calculator">45 - 40</gadget>
<output>5</output>
<result>B</result> | B | 5 | A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished? | {
"A": "1",
"B": "5",
"C": "7",
"D": "8",
"E": "2"
} | subtract(divide(add(multiply(100, 35), multiply(add(const_2, const_3), multiply(100, const_2))), const_100), 40) | add(const_2,const_3)|multiply(n1,n3)|multiply(n1,const_2)|multiply(#0,#2)|add(#1,#3)|divide(#4,const_100)|subtract(#5,n0) | explanation : \ inline \ fn _ jvn [ ( 100 \ times 35 ) + ( 200 \ times 5 ) ] men can finish the work in 1 day \ inline \ fn _ jvn \ therefore 4500 men can finish the work in 1 day . 100 men can finish it in \ inline \ fn _ jvn \ frac { 4500 } { 100 } = 45 days . this is 5 days behind schedule answer : b | general |
math_qa__bPmlhwqWTGPJrnWX | How many integers from 1 to 100 (both inclusive) have odd number of factors?
Pick one: A) 7 B) 8 C) 9 D) 10 E) greater than 10 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<result>D</result> | D | 10 | How many integers from 1 to 100 (both inclusive) have odd number of factors? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "greater than 10"
} | divide(100, const_10) | divide(n1,const_10) | all perfect squares have odd # of factors . squaring integers 1 - 10 produces 1 , 4 , 9 , 16 , . . . 100 which all have odd # of factors . answer is d | other |
math_qa__iyUAckrrXYylfV13 | If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake’s present weight, in pounds? Pick one: A) 131 B) 135 C) 139 D) 147 E) 188 | <gadget id="calculator">278 - 8</gadget>
<output>270</output>
<gadget id="calculator">270 / 3</gadget>
<output>90</output>
<gadget id="calculator">90 * 2</gadget>
<output>180</output>
<gadget id="calculator">180 + 8</gadget>
<output>188</output>
<result>E</result> | E | 188 | If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake’s present weight, in pounds? | {
"A": "131",
"B": "135",
"C": "139",
"D": "147",
"E": "188"
} | add(multiply(divide(subtract(278, 8), const_3), const_2), 8) | subtract(n1,n0)|divide(#0,const_3)|multiply(#1,const_2)|add(n0,#2)| | "consider sister weight now as x jakes weight ( 2 times + 8 ) = 2 x + 8 ( 2 x + 8 ) + ( x ) = 278 x = 90 jake ' s weight is . . . . 188 correct answer is e" | general |
math_qa__YKbu2AJ0ZmPyFb3V | If the annual increase in the population of a town is 10% and the present number of people is 12000, what will the population be in 2 years? Choose the correct answer
A) 12100 B) 15240 C) 12456 D) 11452 E) 14520 | <gadget id="calculator">10 + 100</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) * 12_000</gadget>
<output>13_200</output>
<gadget id="calculator">13_200 * (11/10)</gadget>
<output>14_520</output>
<result>E</result> | E | 14,520 | If the annual increase in the population of a town is 10% and the present number of people is 12000, what will the population be in 2 years? | {
"A": "12100",
"B": "15240",
"C": "12456",
"D": "11452",
"E": "14520"
} | multiply(multiply(divide(add(10, const_100), const_100), 12000), divide(add(10, const_100), const_100)) | add(n0,const_100)|divide(#0,const_100)|multiply(n1,#1)|multiply(#1,#2)| | "the required population is = 12000 ( 1 + 10 / 100 ) ^ 2 = 12000 * 11 / 10 * 11 / 10 = 14520 answer is e" | gain |
math_qa__n5ReHdZWE665tLPi | A monkey start climbing up a tree 19 ft tall.Each hour it hops 3 ft and slips back 2 ft. How much time would it take the monkey to reach the top. Pick one:
A) 15 hrs B) 18 hrs C) 19 hrs D) 17 hrs E) 16 hrs | <gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">19 / 1</gadget>
<output>19</output>
<gadget id="calculator">19 - 2</gadget>
<output>17</output>
<result>D</result> | D | 17 | A monkey start climbing up a tree 19 ft tall.Each hour it hops 3 ft and slips back 2 ft. How much time would it take the monkey to reach the top. | {
"A": "15 hrs",
"B": "18 hrs",
"C": "19 hrs",
"D": "17 hrs",
"E": "16 hrs"
} | subtract(divide(19, subtract(3, 2)), 2) | subtract(n1,n2)|divide(n0,#0)|subtract(#1,n2)| | "if monkey hops 3 ft and slips back 2 ft in a hour , it means the monkey hops ( 3 ft - 2 ft ) = 1 ft / hr . similarly in 16 hrs it wil be 16 ft . bt since the height of the tree is 19 ft , so if the monkey hops up the tree in the next hr i . e 17 th hr then it reaches at the top of the tree . hence it takes 17 hrs for monkey to reach at the top answer : d" | physics |
math_qa__KWlZyp88KeXioZHq | Find the value of y from (12)^2 x 6^3 ÷ 432 = y? Choose the correct choice: A) 2134 B) 2234 C) 2540 D) 2560 E) 72 | <gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">6 ** 3</gadget>
<output>216</output>
<gadget id="calculator">144 * 216</gadget>
<output>31_104</output>
<gadget id="calculator">31_104 / 432</gadget>
<output>72</output>
<result>E</result> | E | 72 | Find the value of y from (12)^2 x 6^3 ÷ 432 = y? | {
"A": "2134",
"B": "2234",
"C": "2540",
"D": "2560",
"E": "72"
} | divide(multiply(power(12, 2), power(6, 3)), 432) | power(n0,n1)|power(n2,n3)|multiply(#0,#1)|divide(#2,n4)| | "72 e" | general |
math_qa__jzBhJo2P3Dao5KnM | Before leaving home for the town of Madison, Pete checks a map which shows that Madison is 5 inches from his current location, Gardensquare. Pete arrives in Madison 6.5 hours later and drove at an average speed of 60 miles per hour. At what scale, in inches per mile, is the map drawn? Pick.
A) 1 / 3
B) 1 / 30
C) 1 / 10
D) 1 / 78
E) 30 | <gadget id="calculator">6.5 / 5</gadget>
<output>1.3</output>
<gadget id="calculator">1.3 * 60</gadget>
<output>78</output>
<gadget id="calculator">1 / 78</gadget>
<output>1/78 = around 0.012821</output>
<result>D</result> | D | 0.012821 | Before leaving home for the town of Madison, Pete checks a map which shows that Madison is 5 inches from his current location, Gardensquare. Pete arrives in Madison 6.5 hours later and drove at an average speed of 60 miles per hour. At what scale, in inches per mile, is the map drawn? | {
"A": "1 / 3",
"B": "1 / 30",
"C": "1 / 10",
"D": "1 / 78",
"E": "30"
} | divide(const_1, multiply(divide(6.5, 5), 60)) | divide(n1,n0)|multiply(#0,n2)|divide(const_1,#1)| | "pete covered 6.5 * 60 = 390 miles which correspond to 5 inches on the map - - > scale in inches per mile is 5 / 390 = 1 / 78 . answer : d ." | physics |
math_qa__apW9LTePc6FNkbvR | A cistern 12 meters long and 4 meters wide contains water up to a depth of 1 meter 25 cm. What is the total area of the wet surface? Choices.
A) 64 B) 72 C) 80 D) 88 E) 96 | <gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">4 * (5/4)</gadget>
<output>5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">48 + 10</gadget>
<output>58</output>
<gadget id="calculator">12 * (5/4)</gadget>
<output>15</output>
<gadget id="calculator">2 * 15</gadget>
<output>30</output>
<gadget id="calculator">58 + 30</gadget>
<output>88</output>
<result>D</result> | D | 88 | A cistern 12 meters long and 4 meters wide contains water up to a depth of 1 meter 25 cm. What is the total area of the wet surface? | {
"A": "64",
"B": "72",
"C": "80",
"D": "88",
"E": "96"
} | add(add(multiply(12, 4), multiply(const_2, multiply(4, add(1, divide(25, const_100))))), multiply(const_2, multiply(12, add(1, divide(25, const_100))))) | divide(n3,const_100)|multiply(n0,n1)|add(n2,#0)|multiply(n1,#2)|multiply(n0,#2)|multiply(#3,const_2)|multiply(#4,const_2)|add(#1,#5)|add(#7,#6)| | "area of the wet surface = [ 2 ( lb + bh + lh ) - lb ] = 2 ( bh + lh ) + lb = [ 2 ( 4 x 1.25 + 12 x 1.25 ) + 12 x 4 ] = 88 the answer is d ." | physics |
math_qa__5Wva860LR9PCtvW1 | The instructions state that Cheryl needs 2/9 square yards of one type of material and 1/8 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 4/18 square yards left that she did not use. What is the total amount of square yards of material Cheryl used? Choose the correct answer:
A) 1 / 12
B) 1 / 9
C) 1 / 8
D) 1 1 / 9
E) 2 1 / 9 | <gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(2/9) + (1/8)</gadget>
<output>25/72 = around 0.347222</output>
<gadget id="calculator">4 / 18</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(25/72) - (2/9)</gadget>
<output>1/8 = around 0.125</output>
<result>C</result> | C | 0.125 | The instructions state that Cheryl needs 2/9 square yards of one type of material and 1/8 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 4/18 square yards left that she did not use. What is the total amount of square yards of material Cheryl used? | {
"A": "1 / 12",
"B": "1 / 9",
"C": "1 / 8",
"D": "1 1 / 9",
"E": "2 1 / 9"
} | subtract(add(divide(2, 9), divide(1, 8)), divide(4, 18)) | divide(n0,n1)|divide(n2,n3)|divide(n4,n5)|add(#0,#1)|subtract(#3,#2) | total bought = 2 / 9 + 1 / 8 left part 4 / 18 - - - > 2 / 9 so used part 2 / 9 + 1 / 8 - 2 / 9 = 1 / 8 answer : c | general |
math_qa__ZcfHYaFblkjyTsd7 | The average age of 17 students of a class is 17 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years, The age of the 17th student is Choose the correct answer
A) 62 B) 66 C) 18 D) 75 E) 12 | <gadget id="calculator">17 * 17</gadget>
<output>289</output>
<gadget id="calculator">5 * 14</gadget>
<output>70</output>
<gadget id="calculator">9 * 16</gadget>
<output>144</output>
<gadget id="calculator">70 + 144</gadget>
<output>214</output>
<gadget id="calculator">289 - 214</gadget>
<output>75</output>
<result>D</result> | D | 75 | The average age of 17 students of a class is 17 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years, The age of the 17th student is | {
"A": "62",
"B": "66",
"C": "18",
"D": "75",
"E": "12"
} | subtract(multiply(17, 17), add(multiply(5, 14), multiply(9, 16))) | multiply(n0,n0)|multiply(n2,n3)|multiply(n4,n5)|add(#1,#2)|subtract(#0,#3)| | "explanation : age of the 17 th student = [ 17 * 17 - ( 14 * 5 + 16 * 9 ) ] = ( 289 - 214 ) = 75 years . answer : d" | general |
math_qa__0Hs0qlkKOjz6ReID | Right triangle ABC is the base of the prism in the figure above. If AB=AC=√2 and the height of the prism is 3, what is the volume of the prism? Choose the correct option
A) 1 B) 3 / 2 C) 2 D) 3 E) 6 | <gadget id="calculator">2 ** (1/2)</gadget>
<output>sqrt(2) = around 1.414214</output>
<gadget id="calculator">(sqrt(2)) * (sqrt(2)) * 3</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>D</result> | D | 3 | Right triangle ABC is the base of the prism in the figure above. If AB=AC=√2 and the height of the prism is 3, what is the volume of the prism? | {
"A": "1",
"B": "3 / 2",
"C": "2",
"D": "3",
"E": "6"
} | divide(volume_rectangular_prism(sqrt(2), sqrt(2), 3), const_2) | sqrt(n0)|volume_rectangular_prism(n1,#0,#0)|divide(#1,const_2) | volume of prism = area of base * height = 1 / 2 * ( square root of 2 ) * ( square root of 2 ) * 3 = 3 answer : d | geometry |
math_qa__NS16rUxXuXh9c7q0 | In a dairy farm, 20 cows eat 20 bags of husk in 20 days. In how many days one cow will eat one bag of husk? Choose the correct choice from the following
A) 1 B) 40 C) 20 D) 26 E) 30 | <gadget id="calculator">20 / 20</gadget>
<output>1</output>
<gadget id="calculator">1 * 20</gadget>
<output>20</output>
<result>C</result> | C | 20 | In a dairy farm, 20 cows eat 20 bags of husk in 20 days. In how many days one cow will eat one bag of husk? | {
"A": "1",
"B": "40",
"C": "20",
"D": "26",
"E": "30"
} | multiply(divide(20, 20), 20) | divide(n0,n0)|multiply(n0,#0)| | "explanation : one bag of husk = 20 cows per day ⇒ 20 × 1 × 20 = 1 × 20 × x for one cow = 20 days answer : c" | physics |
math_qa__kxgHiDdeXiw9pVxs | The average (arithmetic mean) of 4 different integers is 68. If the largest integer is 90, what is the least possible value of the smallest integer? Choose the correct choice from the following answers:
A) 5 B) 19 C) 29 D) 30 E) 33 | <gadget id="calculator">68 * 4</gadget>
<output>272</output>
<gadget id="calculator">272 - 90</gadget>
<output>182</output>
<gadget id="calculator">90 - 1</gadget>
<output>89</output>
<gadget id="calculator">182 - 89</gadget>
<output>93</output>
<gadget id="calculator">90 - 2</gadget>
<output>88</output>
<gadget id="calculator">93 - 88</gadget>
<output>5</output>
<result>A</result> | A | 5 | The average (arithmetic mean) of 4 different integers is 68. If the largest integer is 90, what is the least possible value of the smallest integer? | {
"A": "5",
"B": "19",
"C": "29",
"D": "30",
"E": "33"
} | subtract(subtract(subtract(multiply(68, 4), 90), subtract(90, const_1)), subtract(90, const_2)) | multiply(n0,n1)|subtract(n2,const_1)|subtract(n2,const_2)|subtract(#0,n2)|subtract(#3,#1)|subtract(#4,#2)| | "total of integers = 68 * 4 = 272 lowest of the least possible integer is when the middle 2 intergers are at the maximum or equal to the highest possible integer . but all integers are distinct . so if the largest integer is 90 , then the middle 2 will be 88 and 89 lowest of least possible integer = 272 - ( 90 + 89 + 88 ) = 272 - 267 = 5 answer : a" | general |
math_qa__9eGmc0fyW4QheiOj | How much more would Rs.60000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?
Choose the correct choice from the following
A) 482
B) 725
C) 992
D) 1446
E) 923 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 4</gadget>
<output>14_641/10_000 = around 1.4641</output>
<gadget id="calculator">(14_641/10_000) * 60_000</gadget>
<output>87_846</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) ** 2</gadget>
<output>36/25 = around 1.44</output>
<gadget id="calculator">(36/25) * 60_000</gadget>
<output>86_400</output>
<gadget id="calculator">87_846 - 86_400</gadget>
<output>1_446</output>
<result>D</result> | D | 1,446 | How much more would Rs.60000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly? | {
"A": "482",
"B": "725",
"C": "992",
"D": "1446",
"E": "923"
} | subtract(multiply(power(add(const_1, divide(divide(20, const_100), const_2)), const_4), 60000), multiply(power(add(divide(20, const_100), const_1), const_2), 60000)) | divide(n1,const_100)|add(#0,const_1)|divide(#0,const_2)|add(#2,const_1)|power(#1,const_2)|multiply(n0,#4)|power(#3,const_4)|multiply(n0,#6)|subtract(#7,#5)| | "60000 ( 11 / 10 ) 4 - 60000 ( 6 / 5 ) 2 = 1446 answer : d" | gain |
math_qa__OLwqhiSvm7MmUHLU | Ramu bought an old car for Rs. 45000. He spent Rs. 12000 on repairs and sold it for Rs. 80000. What is his profit percent? Choices: A) 16 % B) 17 % C) 40 % D) 58 % E) 13 % | <gadget id="calculator">45_000 + 12_000</gadget>
<output>57_000</output>
<gadget id="calculator">80_000 - 57_000</gadget>
<output>23_000</output>
<gadget id="calculator">23_000 / 57_000</gadget>
<output>23/57 = around 0.403509</output>
<gadget id="calculator">(23/57) * 100</gadget>
<output>2_300/57 = around 40.350877</output>
<result>C</result> | C | 40 | Ramu bought an old car for Rs. 45000. He spent Rs. 12000 on repairs and sold it for Rs. 80000. What is his profit percent? | {
"A": "16 %",
"B": "17 %",
"C": "40 %",
"D": "58 %",
"E": "13 %"
} | multiply(divide(subtract(80000, add(45000, 12000)), add(45000, 12000)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "total cp = rs . 45000 + rs . 12000 = rs . 57000 and sp = rs . 80000 profit ( % ) = ( 80000 - 57000 ) / 57000 * 100 = 40 % answer : c" | gain |
math_qa__h1CUV1bLg0Emv7jo | A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $198, how many hours overtime did he work? Choose the correct option:
A) 8 B) 5 C) 9 D) 6 E) 13 | <gadget id="calculator">3 * 40</gadget>
<output>120</output>
<gadget id="calculator">198 - 120</gadget>
<output>78</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">78 / 6</gadget>
<output>13</output>
<result>E</result> | E | 13 | A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $198, how many hours overtime did he work? | {
"A": "8",
"B": "5",
"C": "9",
"D": "6",
"E": "13"
} | divide(subtract(198, multiply(3, 40)), multiply(3, const_2)) | multiply(n0,n1)|multiply(n0,const_2)|subtract(n2,#0)|divide(#2,#1)| | "at $ 3 per hour up to 40 hours , regular pay = $ 3 x 40 = $ 120 if total pay = $ 168 , overtime pay = $ 198 - $ 120 = $ 78 overtime rate ( twice regular ) = 2 x $ 3 = $ 6 per hour = > number of overtime hours = $ 78 / $ 6 = 13 ans is e" | physics |
math_qa__3DAoAdifL8lVSYgh | A grocery store bought some apples at a rate of 5 for a dollar. They were separated into two stacks, one of which was sold at a rate of 3 for a dollar and the other at a rate of 6 for a dollar. What was the ratio of the number of apples in the two stacks if the store broke even after having sold all of its apples? Options:
A) 1 : 7 B) 1 : 5 C) 1 : 4 D) 1 : 2 E) 2 : 5 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<result>C</result> | C | 0.25 | A grocery store bought some apples at a rate of 5 for a dollar. They were separated into two stacks, one of which was sold at a rate of 3 for a dollar and the other at a rate of 6 for a dollar. What was the ratio of the number of apples in the two stacks if the store broke even after having sold all of its apples? | {
"A": "1 : 7",
"B": "1 : 5",
"C": "1 : 4",
"D": "1 : 2",
"E": "2 : 5"
} | divide(const_1, const_4) | divide(const_1,const_4) | to avoid fractions , assume there were 45 apples . so the store bought them for 45 / 5 = 9 dollars . to break even , the selling price should be $ 9 too . 45 mangoes can be split into 1 : 4 , 2 : 3 or 1 : 2 . so let ' s try these . 45 split in the ratio 1 : 4 gives 9 and 36 . 9 apples split into 3 apples each will give $ 3 . 36 apples split into 6 apples each will give $ 6 . they add up to $ 9 so we have hit the right answer . answer ( c ) | other |
math_qa__1GMXgZJv5O0XccYI | If 11 lions can kill 11 deers in 11 minutes how long will it take 100 lions to kill 100 deers?
Pick.
A) 1 minutes B) 11 minute C) 100 minutes D) 10000 minutes E) 1000 minutes | <gadget id="calculator">11 / 11</gadget>
<output>1</output>
<gadget id="calculator">1 * 11</gadget>
<output>11</output>
<result>B</result> | B | 11 | If 11 lions can kill 11 deers in 11 minutes how long will it take 100 lions to kill 100 deers? | {
"A": "1 minutes",
"B": "11 minute",
"C": "100 minutes",
"D": "10000 minutes",
"E": "1000 minutes"
} | multiply(divide(11, 11), 11) | divide(n0,n0)|multiply(n0,#0)| | "we can try the logic of time and work , our work is to kill the deers so 11 ( lions ) * 11 ( min ) / 11 ( deers ) = 100 ( lions ) * x ( min ) / 100 ( deers ) hence answer is x = 11 answer : b" | physics |
math_qa__I9uuBOkSP2VrHkcB | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 6 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? Choose the correct choice from the following choices:
A) 19 : 2 B) 18 : 3 C) 29 : 11 D) 29 : 5 E) 29 : 4 | <gadget id="calculator">62.5 * 6</gadget>
<output>375</output>
<gadget id="calculator">375 / 100</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">87.5 * 4</gadget>
<output>350</output>
<gadget id="calculator">350 / 100</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(15/4) + (7/2)</gadget>
<output>29/4 = around 7.25</output>
<gadget id="calculator">6 - (15/4)</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">4 - (7/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(9/4) + (1/2)</gadget>
<output>11/4 = around 2.75</output>
<gadget id="calculator">(29/4) / (11/4)</gadget>
<output>29/11 = around 2.636364</output>
<result>C</result> | C | 2.636364 | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 6 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? | {
"A": "19 : 2",
"B": "18 : 3",
"C": "29 : 11",
"D": "29 : 5",
"E": "29 : 4"
} | divide(add(divide(multiply(62.5, 6), const_100), divide(multiply(87.5, 4), const_100)), add(subtract(6, divide(multiply(62.5, 6), const_100)), subtract(4, divide(multiply(87.5, 4), const_100)))) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|subtract(n2,#2)|subtract(n3,#3)|add(#5,#6)|divide(#4,#7)| | "quantity of alcohol in vessel p = 62.5 / 100 * 6 = 15 / 4 litres quantity of alcohol in vessel q = 87.5 / 100 * 4 = 7 / 2 litres quantity of alcohol in the mixture formed = 15 / 4 + 7 / 2 = 29 / 4 = 7.25 litres as 10 litres of mixture is formed , ratio of alcohol and water in the mixture formed = 7.25 : 2.75 = 29 : 11 . answer : c" | other |
math_qa__yUUN2uqqSz3Es6B3 | What is 1 percent of 12,356? Pick
A) 123.56 B) 1.2356 C) 12.356 D) 0.012356 E) 0.0012356 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 * 100</gadget>
<output>1_200</output>
<gadget id="calculator">10 * 1_200</gadget>
<output>12_000</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">35 * 10</gadget>
<output>350</output>
<gadget id="calculator">12_000 + 350</gadget>
<output>12_350</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">12_350 + 6</gadget>
<output>12_356</output>
<gadget id="calculator">1 * 12_356</gadget>
<output>12_356</output>
<gadget id="calculator">12_356 / 100</gadget>
<output>3_089/25 = around 123.56</output>
<result>A</result> | A | 123.56 | What is 1 percent of 12,356? | {
"A": "123.56",
"B": "1.2356",
"C": "12.356",
"D": "0.012356",
"E": "0.0012356"
} | divide(multiply(1, add(add(multiply(multiply(add(const_3, const_2), const_2), multiply(multiply(const_3, const_4), const_100)), multiply(multiply(add(const_3, const_4), add(const_3, const_2)), multiply(add(const_3, const_2), const_2))), add(const_3, const_3))), const_100) | add(const_2,const_3)|add(const_3,const_4)|add(const_3,const_3)|multiply(const_3,const_4)|multiply(#0,const_2)|multiply(#3,const_100)|multiply(#1,#0)|multiply(#4,#5)|multiply(#6,#4)|add(#7,#8)|add(#9,#2)|multiply(n0,#10)|divide(#11,const_100)| | since , percent = 1 / 100 , what = something ( s ) , and is : = . we can write the question as s = 1 ( 1 / 100 ) 12,356 . the answer is 123.56 . hence , the correct answer is a . | gain |
math_qa__O19NvygyPR4U8cV3 | If x is to be chosen at random from the set {1, 2, 3, 4} and y is to be chosen at random from the set {5, 6}, what is the probability that xy will be even?
Answers.
A) 1 / 6 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 5 / 6 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">binomial(4, 2)</gadget>
<output>6</output>
<gadget id="calculator">binomial(2, 1)</gadget>
<output>2</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">4 / 12</gadget>
<output>1/3 = around 0.333333</output>
<result>B</result> | B | 0.333333 | If x is to be chosen at random from the set {1, 2, 3, 4} and y is to be chosen at random from the set {5, 6}, what is the probability that xy will be even? | {
"A": "1 / 6",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "5 / 6"
} | divide(power(2, 2), multiply(choose(4, 2), choose(2, 1))) | choose(n3,n1)|choose(n1,n0)|power(n1,n1)|multiply(#0,#1)|divide(#2,#3) | probably the best way to solve would be to use 1 - p ( opposite event ) = 1 - p ( odd ) = 1 - p ( odd ) * p ( odd ) = 1 - 2 / 4 * 2 / 3 = 8 / 12 = 1 / 3 . answer : b . | probability |
math_qa__aAaa4V8lhrPIqNtV | A certain music store stocks 800 cellos and 600 violas. Of these instruments, there are 70 cello-viola pairs, such that a cello and a viola were both made with wood from the same tree (each tree can make at most one viola and one cello, so there are no pairs other than these 90). If one viola and one cello are chosen at random, what is the probability that the two instruments are made with wood from the same tree? Choose the correct choice from the following answers.
A) 3 / 16,000 B) 1 / 8,100 C) 7 / 48,000 D) 1 / 90 E) 2 / 45 | <gadget id="calculator">70 / 800</gadget>
<output>7/80 = around 0.0875</output>
<gadget id="calculator">1 / 600</gadget>
<output>1/600 = around 0.001667</output>
<gadget id="calculator">(7/80) * (1/600)</gadget>
<output>7/48_000 = around 0.000146</output>
<result>C</result> | C | 0.000146 | A certain music store stocks 800 cellos and 600 violas. Of these instruments, there are 70 cello-viola pairs, such that a cello and a viola were both made with wood from the same tree (each tree can make at most one viola and one cello, so there are no pairs other than these 90). If one viola and one cello are chosen at random, what is the probability that the two instruments are made with wood from the same tree? | {
"A": "3 / 16,000",
"B": "1 / 8,100",
"C": "7 / 48,000",
"D": "1 / 90",
"E": "2 / 45"
} | multiply(divide(70, 800), divide(const_1, 600)) | divide(n2,n0)|divide(const_1,n1)|multiply(#0,#1)| | "solution provided by stanford 2012 is correct : 70 / 800 choosing one of the cellos which has a pair viola , 1 / 600 choosing the viola which is the pair of chosen cello - - > p = 70 / 800 * 1 / 600 = 7 / 48,000 . answer : c ." | other |
math_qa__jLt3o11Cet5eyT61 | The speed of a boat in still water is 20 km/hr and the rate of current is 5 km/hr. The distance travelled downstream in 24 minutes is: Choose the correct choice from the following.
A) 9
B) 5
C) 7
D) 6
E) 10 | <gadget id="calculator">24 / 60</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">(2/5) * 25</gadget>
<output>10</output>
<result>E</result> | E | 10 | The speed of a boat in still water is 20 km/hr and the rate of current is 5 km/hr. The distance travelled downstream in 24 minutes is: | {
"A": "9",
"B": "5",
"C": "7",
"D": "6",
"E": "10"
} | multiply(divide(24, const_60), add(20, 5)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "explanation : speed downstream = ( 20 + 5 ) kmph = 25 kmph distance travelled = ( 25 * ( 24 / 60 ) ) km = 10 km . answer : e" | physics |
math_qa__BVwpmpekIyoTULZK | The instructions state that Cheryl needs 4/9 square yards of one type of material and 2/3 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 8/18 square yards left that she did not use. What is the total amount of square yards of material Cheryl used? Options:
A) 1 / 12 B) 1 / 9 C) 2 / 3 D) 1 1 / 9 E) 2 1 / 9 | <gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(4/9) + (2/3)</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">8 / 18</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">(10/9) - (4/9)</gadget>
<output>2/3 = around 0.666667</output>
<result>C</result> | C | 0.666667 | The instructions state that Cheryl needs 4/9 square yards of one type of material and 2/3 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 8/18 square yards left that she did not use. What is the total amount of square yards of material Cheryl used? | {
"A": "1 / 12",
"B": "1 / 9",
"C": "2 / 3",
"D": "1 1 / 9",
"E": "2 1 / 9"
} | subtract(add(divide(4, 9), divide(2, 3)), divide(8, 18)) | divide(n0,n1)|divide(n2,n3)|divide(n4,n5)|add(#0,#1)|subtract(#3,#2)| | "total bought = 4 / 9 + 2 / 3 left part 8 / 18 - - - > 4 / 9 so used part 4 / 9 + 2 / 3 - 4 / 9 = 2 / 3 answer : c" | general |
math_qa__AgiXd6PWmstCFtzy | A sells a bicycle to B at a profit of 30% and B sells it to C at a loss of 20%. Find the resultant profit or loss. Choose the correct choice from the following:
A) 5 % B) 4 % C) - 4 % D) - 12 % E) 2 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(13/10) * (4/5)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) - 1</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) * 100</gadget>
<output>4</output>
<result>B</result> | B | 4 | A sells a bicycle to B at a profit of 30% and B sells it to C at a loss of 20%. Find the resultant profit or loss. | {
"A": "5 %",
"B": "4 %",
"C": "- 4 %",
"D": "- 12 %",
"E": "2 %"
} | multiply(subtract(multiply(add(const_1, divide(30, const_100)), subtract(const_1, divide(20, const_100))), const_1), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100) | the resultant profit or loss = 30 - 20 - ( 30 * 20 ) / 100 = 4 % profit = 4 % answer is b | gain |
math_qa__7yX1uKTvIIRZeut4 | In a survey of 335 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured? Choices: A) 38 / 67 B) 8 / 41 C) 9 / 348 D) 1 / 8 E) 41 / 91 | <gadget id="calculator">12.5 * 104</gadget>
<output>1_300</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<gadget id="calculator">1_300 / 100</gadget>
<output>13</output>
<gadget id="calculator">54 - 13</gadget>
<output>41</output>
<gadget id="calculator">41 + 104</gadget>
<output>145</output>
<gadget id="calculator">335 - 145</gadget>
<output>190</output>
<gadget id="calculator">190 / 335</gadget>
<output>38/67 = around 0.567164</output>
<result>A</result> | A | 0.567164 | In a survey of 335 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured? | {
"A": "38 / 67",
"B": "8 / 41",
"C": "9 / 348",
"D": "1 / 8",
"E": "41 / 91"
} | divide(subtract(335, add(subtract(54, divide(multiply(12.5, 104), multiply(const_1, const_100))), 104)), 335) | multiply(n1,n3)|multiply(const_1,const_100)|divide(#0,#1)|subtract(n2,#2)|add(n1,#3)|subtract(n0,#4)|divide(#5,n0)| | "- - - - - - - - - ui - - - - - - - - - - - - - - - - nui - - - - - - - total pt - - - - ( 12.5 / 100 ) * 104 = 13 - - - - - - - - - - - - - 54 npt - - - 104 - 13 - - - - - - - - - - - - - - x - - - - - - - - 281 total - - 104 - - - - - - - - - - - - - - - - - - - - - - - - - - - - 335 we have to find not part time and not uninsured . in other words not part time and insured = x / 335 = ( 281 - 104 + 13 ) / 335 = 38 / 67 answer is a ." | physics |
math_qa__Ys0ZnP02klL8o3Cf | A $500 investment and a $1,500 investment have a combined yearly return of 8.5 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? Choose the most appropriate option:
A) 9 % B) 10 % C) 10 5 / 8 % D) 11 % E) 12 % | <gadget id="calculator">3 * 500</gadget>
<output>1_500</output>
<gadget id="calculator">500 + 1_500</gadget>
<output>2_000</output>
<gadget id="calculator">8.5 / 100</gadget>
<output>0.085</output>
<gadget id="calculator">2_000 * 0.085</gadget>
<output>170</output>
<gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">500 * (7/100)</gadget>
<output>35</output>
<gadget id="calculator">170 - 35</gadget>
<output>135</output>
<gadget id="calculator">135 / 1_500</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">(9/100) * 100</gadget>
<output>9</output>
<result>A</result> | A | 9 | A $500 investment and a $1,500 investment have a combined yearly return of 8.5 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? | {
"A": "9 %",
"B": "10 %",
"C": "10 5 / 8 %",
"D": "11 %",
"E": "12 %"
} | multiply(divide(subtract(multiply(add(500, multiply(const_3, 500)), divide(8.5, const_100)), multiply(500, divide(7, const_100))), multiply(const_3, 500)), const_100) | divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_3)|add(n0,#2)|multiply(n0,#1)|multiply(#3,#0)|subtract(#5,#4)|divide(#6,#2)|multiply(#7,const_100)| | "the ratio of investments is 500 : 1,500 = 1 : 3 . the deviation from the average return from $ 500 investment and $ 1,500 investment must be in the ration 3 : 1 . $ 500 investment return has the deviation from the mean of 8.5 - 7 = 1.5 % , thus $ 1,500 investment return must have the deviation from the mean equal to 0.5 % , which means that $ 1 , 500 investment has 8.5 + 0.5 = 9 % yearly return . answer : a ." | gain |
math_qa__uNsOha2V32Vgjs9U | 8 : 4 seconds :: ? : 4 minutes Choose the most appropriate option.
A) 10 B) 8 C) 20 D) 25 E) 30 | <gadget id="calculator">8 / 4</gadget>
<output>2</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<result>B</result> | B | 8 | 8 : 4 seconds :: ? : 4 minutes | {
"A": "10",
"B": "8",
"C": "20",
"D": "25",
"E": "30"
} | multiply(4, divide(8, 4)) | divide(n0,n1)|multiply(n2,#0)| | "8 * 4 = 4 * x x = 8 answer : b" | physics |
math_qa__AF1GqP6TiYTaVjc5 | A river 2m deep and 45 m wide is flowing at the rate of 7 kmph the amount of water that runs into the sea per minute is? Choose the correct choice from the following options:
A) 4500 m 3 B) 4580 m 3 C) 10500 m 3 D) 4900 m 3 E) 4700 m 3 | <gadget id="calculator">2 * 45</gadget>
<output>90</output>
<gadget id="calculator">7 * 1_000</gadget>
<output>7_000</output>
<gadget id="calculator">90 * 7_000</gadget>
<output>630_000</output>
<gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">630_000 / 60</gadget>
<output>10_500</output>
<result>C</result> | C | 10,500 | A river 2m deep and 45 m wide is flowing at the rate of 7 kmph the amount of water that runs into the sea per minute is? | {
"A": "4500 m 3",
"B": "4580 m 3",
"C": "10500 m 3",
"D": "4900 m 3",
"E": "4700 m 3"
} | divide(multiply(multiply(2, 45), multiply(7, const_1000)), multiply(const_1, const_60)) | multiply(n0,n1)|multiply(n2,const_1000)|multiply(const_1,const_60)|multiply(#0,#1)|divide(#3,#2)| | "explanation : ( 7000 * 2 * 45 ) / 60 = 10500 m 3 answer : option c" | physics |
math_qa__mlAh0j1K7NO5dCDP | What is the area of square field whose side of length 10 m?
Choose the correct choice from the following answers.
A) 100 B) 662 C) 772 D) 882 E) 21 | <gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<result>A</result> | A | 100 | What is the area of square field whose side of length 10 m? | {
"A": "100",
"B": "662",
"C": "772",
"D": "882",
"E": "21"
} | square_area(10) | square_area(n0)| | "10 * 10 = 100 sq m answer : a" | geometry |
math_qa__spCG0L1K1trV3jLk | The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 6 per square feet if there is one door of dimensions 6 feet * 3 feet and three WINDOWS of dimensions 4 feet * 3 feet each? Choices: A) s . 4529 B) s . 4586 C) s . 4597 D) s . 4530 E) s . 5436 | <gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">15 + 25</gadget>
<output>40</output>
<gadget id="calculator">24 * 40</gadget>
<output>960</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">960 - 18</gadget>
<output>942</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">942 - 36</gadget>
<output>906</output>
<gadget id="calculator">906 * 6</gadget>
<output>5_436</output>
<result>E</result> | E | 5,436 | The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 6 per square feet if there is one door of dimensions 6 feet * 3 feet and three WINDOWS of dimensions 4 feet * 3 feet each? | {
"A": "s . 4529",
"B": "s . 4586",
"C": "s . 4597",
"D": "s . 4530",
"E": "s . 5436"
} | multiply(subtract(subtract(multiply(multiply(const_2, 12), add(15, 25)), multiply(6, 3)), multiply(3, multiply(4, 3))), 6) | add(n0,n1)|multiply(n2,const_2)|multiply(n4,n5)|multiply(n5,n6)|multiply(#0,#1)|multiply(n5,#3)|subtract(#4,#2)|subtract(#6,#5)|multiply(n3,#7)| | "area of the four walls = 2 h ( l + b ) since there are doors and windows , area of the walls = 2 * 12 ( 15 + 25 ) - ( 6 * 3 ) - 3 ( 4 * 3 ) = 906 sq . ft . total cost = 906 * 6 = rs . 5436 answer : e" | geometry |
math_qa__byS0Y17ZOPCabXWy | A car dealership has 40 cars on the lot, 10% of which are silver. If the dealership receives a new shipment of 80 cars, 25% of which are not silver, what percentage of total number of cars are silver? Choose one.
A) 15 % B) 18 % C) 20 % D) 21 % E) 22 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">40 * (1/10)</gadget>
<output>4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">80 * (1/4)</gadget>
<output>20</output>
<gadget id="calculator">4 + 20</gadget>
<output>24</output>
<gadget id="calculator">40 + 80</gadget>
<output>120</output>
<gadget id="calculator">24 / 120</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>C</result> | C | 20 | A car dealership has 40 cars on the lot, 10% of which are silver. If the dealership receives a new shipment of 80 cars, 25% of which are not silver, what percentage of total number of cars are silver? | {
"A": "15 %",
"B": "18 %",
"C": "20 %",
"D": "21 %",
"E": "22 %"
} | multiply(divide(add(multiply(40, divide(10, const_100)), multiply(80, divide(25, const_100))), add(40, 80)), const_100) | add(n0,n2)|divide(n1,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n2,#2)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100) | the number of silver cars is 0.1 * 40 + 0.25 * 80 = 24 the percentage of cars which are silver is 24 / 120 = 20 % the answer is c . | gain |
math_qa__M1iEyBYG71fOj9my | Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 333 and for 36kgs of Apples is 366 then the cost of first 15 kgs of Apples is Choose the correct choice from the following answers:
A) 3.69
B) 3.66
C) 3.6
D) 150
E) 3.61 | <gadget id="calculator">33 - 30</gadget>
<output>3</output>
<gadget id="calculator">366 - 333</gadget>
<output>33</output>
<gadget id="calculator">36 - 33</gadget>
<output>3</output>
<gadget id="calculator">33 / 3</gadget>
<output>11</output>
<gadget id="calculator">3 * 11</gadget>
<output>33</output>
<gadget id="calculator">333 - 33</gadget>
<output>300</output>
<gadget id="calculator">300 / 30</gadget>
<output>10</output>
<gadget id="calculator">10 * 15</gadget>
<output>150</output>
<result>D</result> | D | 150 | Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 333 and for 36kgs of Apples is 366 then the cost of first 15 kgs of Apples is | {
"A": "3.69",
"B": "3.66",
"C": "3.6",
"D": "150",
"E": "3.61"
} | multiply(divide(subtract(333, multiply(subtract(33, 30), divide(subtract(366, 333), subtract(36, 33)))), 30), 15) | subtract(n4,n2)|subtract(n3,n1)|subtract(n1,n0)|divide(#0,#1)|multiply(#3,#2)|subtract(n2,#4)|divide(#5,n0)|multiply(n5,#6)| | "ans : by framing equations we get 30 l + 3 q = 333 30 l + 6 q = 366 eliminate q by multiplying the first equation by 2 and subtracting second equation from the first 60 l + 6 q = 666 30 l + 6 q = 366 30 l = 300 = > l = 10 then we get l = 10 cost of 15 kgs of apples = 15 x 10 = 150 answer : d" | other |
math_qa__STxNdkmzTV9qbPcw | The sub-duplicate ratio of 16:36 is
Select
A) 4 : 6
B) 1 : 2
C) 1 : 3
D) 1 : 4
E) 2 : 3 | <gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<result>A</result> | A | 0.666667 | The sub-duplicate ratio of 16:36 is | {
"A": "4 : 6",
"B": "1 : 2",
"C": "1 : 3",
"D": "1 : 4",
"E": "2 : 3"
} | divide(sqrt(16), sqrt(36)) | sqrt(n0)|sqrt(n1)|divide(#0,#1)| | "root ( 16 ) : root ( 36 ) = 4 : 6 answer : a" | other |
math_qa__OW9Ho9cNAoZjWLeh | A can give B 70 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
Choose the correct option:
A) 139.78 B) 139.13 C) 139.22 D) 111.0 E) 111.12 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 200</gadget>
<output>800</output>
<gadget id="calculator">1_000 * 800</gadget>
<output>800_000</output>
<gadget id="calculator">1_000 - 70</gadget>
<output>930</output>
<gadget id="calculator">800_000 / 930</gadget>
<output>80_000/93 = around 860.215054</output>
<gadget id="calculator">1_000 - (80_000/93)</gadget>
<output>13_000/93 = around 139.784946</output>
<result>A</result> | A | 139.78 | A can give B 70 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race? | {
"A": "139.78",
"B": "139.13",
"C": "139.22",
"D": "111.0",
"E": "111.12"
} | subtract(multiply(const_100, const_10), divide(multiply(multiply(const_100, const_10), subtract(multiply(const_100, const_10), 200)), subtract(multiply(const_100, const_10), 70))) | multiply(const_10,const_100)|subtract(#0,n1)|subtract(#0,n0)|multiply(#0,#1)|divide(#3,#2)|subtract(#0,#4)| | "a runs 1000 m while b runs 930 m and c runs 800 m . the number of meters that c runs when b runs 1000 m , = ( 1000 * 800 ) / 930 = 860.21 m . b can give c = 1000 - 860.21 = 139.78 m . answer : a" | physics |
math_qa__bhAnep5KK4ixxuyS | find the area of trapezium whose parallel sides are 10 cm and 18 cm long , and the distance between them is 10.00001 cm . Pick one: A) 140 cm 2 B) 185 cm 2 C) 185 cm 2 D) 185 cm 2 E) 195 cm 2 | <gadget id="calculator">(10.00001 + 18) * 10 / 2</gadget>
<output>140.00005</output>
<result>A</result> | A | 140 | find the area of trapezium whose parallel sides are 10 cm and 18 cm long , and the distance between them is 10.00001 cm . | {
"A": "140 cm 2",
"B": "185 cm 2",
"C": "185 cm 2",
"D": "185 cm 2",
"E": "195 cm 2"
} | quadrilateral_area(10.00001, 18, 10) | quadrilateral_area(n2,n1,n0)| | "explanation : area of a trapezium = 1 / 2 ( sum of parallel sides ) * ( perpendicular distance between them ) = 1 / 2 ( 10 + 18 ) * ( 10 ) = 140 cm 2 answer : option a" | physics |
math_qa__V3JQCTsoKgtzVES0 | A car drives 40 miles on local roads at 20 mph, and 180 miles on the highway at 60 mph, what is the average speed of the entire trip? Choose the correct choice from the following answers: A) 36 mph B) 40 mph C) 44 mph D) 52 mph E) 58 mph | <gadget id="calculator">40 + 180</gadget>
<output>220</output>
<gadget id="calculator">40 / 20</gadget>
<output>2</output>
<gadget id="calculator">180 / 60</gadget>
<output>3</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">220 / 5</gadget>
<output>44</output>
<result>C</result> | C | 44 | A car drives 40 miles on local roads at 20 mph, and 180 miles on the highway at 60 mph, what is the average speed of the entire trip? | {
"A": "36 mph",
"B": "40 mph",
"C": "44 mph",
"D": "52 mph",
"E": "58 mph"
} | divide(add(40, 180), add(divide(40, 20), divide(180, 60))) | add(n0,n2)|divide(n0,n1)|divide(n2,n3)|add(#1,#2)|divide(#0,#3)| | "explanations 1 ) in phase # 1 of the trip , the car traveled 40 mi at 20 mph . that time of this phase was : time = distance / rate = ( 40 mi ) / ( 20 mph ) = 2 hr in phase # 2 of the trip , the car traveled 180 mi at 60 mph . that time of this phase was : time = distance / rate = ( 180 mi ) / ( 60 mph ) = 3 hr the total distance of the trip = 40 mi + 180 mi = 220 mi the total time of the trip = 2 hr + 3 hr = 5 hr the average speed of trip is given by speed = distance / time = ( 220 mi ) / ( 5 hr ) = 44 mph answer : c ." | physics |
math_qa__dEwwxGUzr2RwabWS | A man sold 18 toys for Rs. 16800, gaining thereby the cost price of 3 toy find the cost price of a toy Choose the correct choice from the following answers.
A) rs . 600 B) rs . 800 C) rs . 500 D) rs . 900 E) rs . 970 | <gadget id="calculator">18 + 3</gadget>
<output>21</output>
<gadget id="calculator">16_800 / 21</gadget>
<output>800</output>
<result>B</result> | B | 800 | A man sold 18 toys for Rs. 16800, gaining thereby the cost price of 3 toy find the cost price of a toy | {
"A": "rs . 600",
"B": "rs . 800",
"C": "rs . 500",
"D": "rs . 900",
"E": "rs . 970"
} | divide(16800, add(18, 3)) | add(n0,n2)|divide(n1,#0)| | "let the cost of one toy = x . then , cost of 18 toys = 18 x . gain = 3 x . sp of 18 toys = rs . 16800 . gain = sp – cp 3 x = 16800 – 18 x 21 x = 16800 x = rs . 800 . answer : b" | gain |
math_qa__qzNGiezLx44pRyOy | 3 people have $ 28 , $ 72 , and $ 98 , respectively . if they pool their money then redistribute it among them , what is the maximum value for the median amount of money ? Answers
A) $ 72 B) $ 85 C) $ 99 D) $ 101 E) $ 202 | <gadget id="calculator">28 + 72</gadget>
<output>100</output>
<gadget id="calculator">100 + 98</gadget>
<output>198</output>
<gadget id="calculator">198 / 2</gadget>
<output>99</output>
<result>C</result> | C | 99 | 3 people have $ 28 , $ 72 , and $ 98 , respectively . if they pool their money then redistribute it among them , what is the maximum value for the median amount of money ? | {
"A": "$ 72",
"B": "$ 85",
"C": "$ 99",
"D": "$ 101",
"E": "$ 202"
} | divide(add(add(28, 72), 98), const_2) | add(n1,n2)|add(n3,#0)|divide(#1,const_2) | solution - total money distributed is $ 198 . in order to maximize median , one person has to accept $ 0 and remaining two people share $ 99 each . hence median is $ 99 . ans c | general |
math_qa__4NVDqgqQEPmUgRkj | If a is an integer greater than 2 but less than 11 and b is an integer greater than 11 but less than 21, what is the range of a/b? Choose one: A) 52 / 45 B) 23 / 47 C) 60 / 41 D) 51 / 42 E) 41 / 60 | <gadget id="calculator">11 - 1</gadget>
<output>10</output>
<gadget id="calculator">11 + 1</gadget>
<output>12</output>
<gadget id="calculator">10 / 12</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">21 - 1</gadget>
<output>20</output>
<gadget id="calculator">3 / 20</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(5/6) - (3/20)</gadget>
<output>41/60 = around 0.683333</output>
<result>E</result> | E | 0.683333 | If a is an integer greater than 2 but less than 11 and b is an integer greater than 11 but less than 21, what is the range of a/b? | {
"A": "52 / 45",
"B": "23 / 47",
"C": "60 / 41",
"D": "51 / 42",
"E": "41 / 60"
} | subtract(divide(subtract(11, const_1), add(11, const_1)), divide(add(2, const_1), subtract(21, const_1))) | add(n2,const_1)|add(n0,const_1)|subtract(n1,const_1)|subtract(n3,const_1)|divide(#2,#0)|divide(#1,#3)|subtract(#4,#5)| | "the way to approach this problem is 2 < a < 11 and 11 < b < 21 minimum possible value of a is 3 and maximum is 10 minimum possible value of b is 12 and maximum is 20 range = max a / min b - min a / max b ( highest - lowest ) 10 / 12 - 3 / 20 = 41 / 60 hence e" | general |
math_qa__oq3gnFQQDHezXfvd | At what price must an article costing Rs.100 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price? Choose the correct choice: A) 131.58 B) 62.0 C) 62.6 D) 62.1 E) 62.2 | <gadget id="calculator">100 * 25</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 100</gadget>
<output>25</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 * 100</gadget>
<output>12_500</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">12_500 / 95</gadget>
<output>2_500/19 = around 131.578947</output>
<result>A</result> | A | 131.58 | At what price must an article costing Rs.100 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price? | {
"A": "131.58",
"B": "62.0",
"C": "62.6",
"D": "62.1",
"E": "62.2"
} | divide(multiply(add(100, divide(multiply(100, 25), const_100)), const_100), subtract(const_100, 5)) | multiply(n0,n2)|subtract(const_100,n1)|divide(#0,const_100)|add(n0,#2)|multiply(#3,const_100)|divide(#4,#1)| | "cp = 100 sp = 100 * ( 125 / 100 ) = 125 mp * ( 95 / 100 ) = 125 mp = 131.58 answer : a" | gain |
math_qa__1Hl796bIDIOgmsFx | How long does a train 110 m long running at a speed of 72 kmph take to cross a bridge 132 m in length? Choices:
A) 9.8 sec
B) 12.1 sec
C) 12.42 sec
D) 14.3 sec
E) 24.3 sec | <gadget id="calculator">110 + 132</gadget>
<output>242</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">242 / 20</gadget>
<output>121/10 = around 12.1</output>
<result>B</result> | B | 12.1 | How long does a train 110 m long running at a speed of 72 kmph take to cross a bridge 132 m in length? | {
"A": "9.8 sec",
"B": "12.1 sec",
"C": "12.42 sec",
"D": "14.3 sec",
"E": "24.3 sec"
} | divide(add(110, 132), multiply(72, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "72 km / hr = 72 * 5 / 18 m / sec = 20 m / sec time = d / s = 110 + 132 / 20 = 242 / 20 = 12.1 sec answer : b" | physics |
math_qa__Y8oziBnPQWsXR4Ov | A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going? Choices:
A) 7 sec
B) 6 sec
C) 8 sec
D) 4 sec
E) 2 sec | <gadget id="calculator">110 / 1_000</gadget>
<output>11/100 = around 0.11</output>
<gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">(11/100) / 66</gadget>
<output>1/600 = around 0.001667</output>
<gadget id="calculator">3_600 * (1/600)</gadget>
<output>6</output>
<result>B</result> | B | 6 | A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going? | {
"A": "7 sec",
"B": "6 sec",
"C": "8 sec",
"D": "4 sec",
"E": "2 sec"
} | multiply(const_3600, divide(divide(110, const_1000), add(60, 6))) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_3600)| | "speed of train relative to man = ( 60 + 6 ) km / hr = 66 km / hr [ 66 * 5 / 18 ] m / sec = [ 55 / 3 ] m / sec . time taken to pass the man = [ 110 * 3 / 55 ] sec = 6 sec answer : b" | physics |
math_qa__KomtyWxmO1qs7EZs | A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 6km? Choose the most appropriate option:
A) 3 B) 5 C) 6 D) 67 E) 7 | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>A</result> | A | 3 | A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 6km? | {
"A": "3",
"B": "5",
"C": "6",
"D": "67",
"E": "7"
} | divide(6, subtract(4, 2)) | subtract(n0,n1)|divide(n2,#0)| | "m = 4 s = 2 us = 4 - 2 = 2 d = 6 t = 6 / 2 = 3 answer : a" | physics |
math_qa__YnjHugg4QHbds8BF | In an election, candidate X got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate? Pick
A) 280000 B) 300000 C) 355000 D) 356000 E) 357000 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 * 75</gadget>
<output>6_375</output>
<gadget id="calculator">560_000 / 100</gadget>
<output>5_600</output>
<gadget id="calculator">5_600 / 100</gadget>
<output>56</output>
<gadget id="calculator">6_375 * 56</gadget>
<output>357_000</output>
<result>E</result> | E | 357,000 | In an election, candidate X got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate? | {
"A": "280000",
"B": "300000",
"C": "355000",
"D": "356000",
"E": "357000"
} | multiply(multiply(subtract(const_100, 15), 75), divide(divide(560000, const_100), const_100)) | divide(n2,const_100)|subtract(const_100,n1)|divide(#0,const_100)|multiply(n0,#1)|multiply(#2,#3) | total number of invalid votes = 15 % of 560000 = 15 / 100 × 560000 = 8400000 / 100 = 84000 total number of valid votes 560000 – 84000 = 476000 percentage of votes polled in favour of candidate x = 75 % therefore , the number of valid votes polled in favour of candidate x = 75 % of 476000 = 75 / 100 × 476000 = 35700000 / 100 = 357000 e ) | general |
math_qa__GT22ZpKZfhJ0qyy1 | At 6′o a clock ticks 6 times. The time between first and last ticks is 35 seconds. How long does it tick at 12′o clock
Select the correct option.
A) 77 B) 76 C) 28 D) 66 E) 11 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">35 / 5</gadget>
<output>7</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">7 * 11</gadget>
<output>77</output>
<result>A</result> | A | 77 | At 6′o a clock ticks 6 times. The time between first and last ticks is 35 seconds. How long does it tick at 12′o clock | {
"A": "77",
"B": "76",
"C": "28",
"D": "66",
"E": "11"
} | multiply(divide(35, subtract(6, const_1)), subtract(12, const_1)) | subtract(n0,const_1)|subtract(n3,const_1)|divide(n2,#0)|multiply(#2,#1)| | "explanation : for ticking 6 times , there are 5 intervals . each interval has time duration of 35 / 5 = 7 secs at 12 o ' clock , there are 11 intervals , so total time for 11 intervals = 11 × 7 = 77 secs . answer : a" | physics |
math_qa__BLNztRYygbHjpBny | A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 20 as remainder. Find the no. is? Select:
A) 122456 B) 220020 C) 220022 D) 235467 E) 220026 | <gadget id="calculator">555 + 445</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 2</gadget>
<output>2_000</output>
<gadget id="calculator">555 - 445</gadget>
<output>110</output>
<gadget id="calculator">2_000 * 110</gadget>
<output>220_000</output>
<gadget id="calculator">220_000 + 20</gadget>
<output>220_020</output>
<result>B</result> | B | 220,020 | A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 20 as remainder. Find the no. is? | {
"A": "122456",
"B": "220020",
"C": "220022",
"D": "235467",
"E": "220026"
} | add(multiply(multiply(add(555, 445), 2), subtract(555, 445)), 20) | add(n0,n1)|subtract(n0,n1)|multiply(n2,#0)|multiply(#2,#1)|add(n3,#3)| | "( 555 + 445 ) * 2 * 110 + 20 = 220000 + 20 = 220020 b" | general |
math_qa__PYMjVtIBWhEfSSaJ | A case contains c cartons. Each carton contains b boxes, and each box contains 300 paper clips. How many paper clips are contained in 2 cases? Options.
A) 300 bc B) 300 b / c C) 600 bc D) 600 b / c E) 600 / bc | <gadget id="calculator">2 * 300</gadget>
<output>600</output>
<result>C</result> | C | 600 | A case contains c cartons. Each carton contains b boxes, and each box contains 300 paper clips. How many paper clips are contained in 2 cases? | {
"A": "300 bc",
"B": "300 b / c",
"C": "600 bc",
"D": "600 b / c",
"E": "600 / bc"
} | multiply(2, 300) | multiply(n0,n1)| | "2 cases * c cartons / case * b boxes / carton * 300 clips / box = 600 bc paper clips the answer is c ." | general |
math_qa__1H7JYisPyygEA7b6 | The cost price of an article is 70% of the marked price. Calculate the gain percent after allowing a discount of 10%.
Choose the correct choice from the following choices: A) 13.6 % B) 28.6 % C) 35.6 % D) 42.3 % E) none | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 70</gadget>
<output>9/7 = around 1.285714</output>
<gadget id="calculator">(9/7) - 1</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(2/7) * 100</gadget>
<output>200/7 = around 28.571429</output>
<result>B</result> | B | 28.6 | The cost price of an article is 70% of the marked price. Calculate the gain percent after allowing a discount of 10%. | {
"A": "13.6 %",
"B": "28.6 %",
"C": "35.6 %",
"D": "42.3 %",
"E": "none"
} | multiply(subtract(divide(subtract(const_100, 10), 70), const_1), const_100) | subtract(const_100,n1)|divide(#0,n0)|subtract(#1,const_1)|multiply(#2,const_100)| | "sol . let marked price = rs . 100 . then , c . p . = rs . 70 . s . p = rs . 90 . â ˆ ´ gain % = [ 20 / 70 * 100 ] % = 28.6 % . answer b" | gain |
math_qa__K91vUV6iTH160s6D | Lola rolls a die 3 times. What is the probability that she gets a 4 on the last one of the 3 rolls? Choose the correct answer.
A) 215 / 216 B) 216 C) 1 / 216 D) none E) 2 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * (1/6)</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(1/36) * (5/6)</gadget>
<output>5/216 = around 0.023148</output>
<gadget id="calculator">1 - (5/216)</gadget>
<output>211/216 = around 0.976852</output>
<result>A</result> | A | 0.99537 | Lola rolls a die 3 times. What is the probability that she gets a 4 on the last one of the 3 rolls? | {
"A": "215 / 216",
"B": "216",
"C": "1 / 216",
"D": "none",
"E": "2"
} | subtract(const_1, multiply(multiply(divide(const_1, const_6), divide(const_1, const_6)), divide(add(4, const_1), const_6))) | add(n1,const_1)|divide(const_1,const_6)|divide(#0,const_6)|multiply(#1,#1)|multiply(#2,#3)|subtract(const_1,#4) | the die has 6 sides and it was rolle 3 times , then 6 * 6 * 6 = 216 the number of ways to get 4 is 1 then 1 / 216 the probability would be 1 - 1 / 216 = 215 / 216 answer a | probability |
math_qa__IHuCqz2nENR6uXHV | A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road? Choose the correct choice from the following options:
A) 2
B) 3.5
C) 3
D) 4
E) 5 | <gadget id="calculator">40 + 60</gadget>
<output>100</output>
<gadget id="calculator">-100</gadget>
<output>-100</output>
<gadget id="calculator">-(-100)</gadget>
<output>100</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">60 * 40</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 - 2_109</gadget>
<output>291</output>
<gadget id="calculator">4 * 291</gadget>
<output>1_164</output>
<gadget id="calculator">10_000 - 1_164</gadget>
<output>8_836</output>
<gadget id="calculator">8_836 ** (1/2)</gadget>
<output>94</output>
<gadget id="calculator">100 - 94</gadget>
<output>6</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>C</result> | C | 3 | A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road? | {
"A": "2",
"B": "3.5",
"C": "3",
"D": "4",
"E": "5"
} | divide(subtract(negate(negate(add(40, 60))), sqrt(subtract(power(const_100, const_2), multiply(multiply(const_4, const_1), subtract(multiply(60, 40), 2109))))), multiply(const_2, const_1)) | add(n0,n1)|multiply(const_1,const_4)|multiply(n0,n1)|multiply(const_1,const_2)|power(const_100,const_2)|negate(#0)|subtract(#2,n2)|multiply(#1,#6)|negate(#5)|subtract(#4,#7)|sqrt(#9)|subtract(#8,#10)|divide(#11,#3) | area of the park = ( 60 x 40 ) m 2 = 2400 m 2 . area of the lawn = 2109 m 2 . area of the crossroads = ( 2400 - 2109 ) m 2 = 291 m 2 . let the width of the road be x metres . then , 60 x + 40 x - x 2 = 291 x 2 - 100 x + 291 = 0 ( x - 97 ) ( x - 3 ) = 0 x = 3 . c ) | geometry |
math_qa__KYgfZpjrSifhmQ3O | A group of people participate in some curriculum, 35 of them practice Yoga, 20 study cooking, 15 study weaving, 7 of them study cooking only, 5 of them study both the cooking and yoga, 3 of them participate all curriculums. How many people study both cooking and weaving? Choose the correct choice: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">20 - 5</gadget>
<output>15</output>
<gadget id="calculator">15 - 3</gadget>
<output>12</output>
<gadget id="calculator">12 - 7</gadget>
<output>5</output>
<result>E</result> | E | 5 | A group of people participate in some curriculum, 35 of them practice Yoga, 20 study cooking, 15 study weaving, 7 of them study cooking only, 5 of them study both the cooking and yoga, 3 of them participate all curriculums. How many people study both cooking and weaving? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(subtract(subtract(20, 5), 3), 7) | subtract(n1,n4)|subtract(#0,n5)|subtract(#1,n3)| | "both cooking and weaving = 20 - ( 7 + 5 + 3 ) = 5 so , the correct answer is e ." | other |
math_qa__ursfJR8AdXxtgP4d | The length of the bridge, which a train 140 metres long and travelling at 45 km/hr can cross in 30 seconds, is: Answers
A) 200 m B) 235 m C) 245 m D) 250 m E) 270 m | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 140</gadget>
<output>235</output>
<result>B</result> | B | 235 | The length of the bridge, which a train 140 metres long and travelling at 45 km/hr can cross in 30 seconds, is: | {
"A": "200 m",
"B": "235 m",
"C": "245 m",
"D": "250 m",
"E": "270 m"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 140) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "let the length of the bridge : l the equation now is l + 140 / 12.5 m / s ( 45 km / hr or 12.5 m / s ) = 30 solving , l = 235 m answer : b" | physics |
math_qa__NtGnirQbuPzosoWN | For the positive integers x, x + 2, x + 4, x + 7, and x + 32, the mean is how much greater than the median? Choices.
A) 0 B) 1 C) 2 D) 4 E) 5 | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">6 + 7</gadget>
<output>13</output>
<gadget id="calculator">13 + 32</gadget>
<output>45</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">45 / 5</gadget>
<output>9</output>
<gadget id="calculator">9 - 4</gadget>
<output>5</output>
<result>E</result> | E | 5 | For the positive integers x, x + 2, x + 4, x + 7, and x + 32, the mean is how much greater than the median? | {
"A": "0",
"B": "1",
"C": "2",
"D": "4",
"E": "5"
} | subtract(divide(add(add(add(2, 4), 7), 32), add(4, const_1)), 4) | add(n0,n1)|add(const_1,n1)|add(n2,#0)|add(n3,#2)|divide(#3,#1)|subtract(#4,n1)| | "mean = ( x + x + 2 + x + 4 + x + 7 + x + 32 ) / 5 = ( 5 x + 45 ) / 5 = x + 9 median = x + 4 thus mean - median = x + 9 - ( x + 4 ) = 5 answer = e" | general |
math_qa__75iqWo92xm59KEwU | The ratio of the volumes of two cubes is 27 : 64. What is the ratio of their total surface areas? Choices.
A) 18 : 21 B) 81 : 13 C) 8 : 15 D) 16 : 21 E) 1 : 13 | <gadget id="calculator">27 / 64</gadget>
<output>27/64 = around 0.421875</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(27/64) ** (1/3)</gadget>
<output>3/4 = around 0.75</output>
<result>D</result> | D | 0.761905 | The ratio of the volumes of two cubes is 27 : 64. What is the ratio of their total surface areas? | {
"A": "18 : 21",
"B": "81 : 13",
"C": "8 : 15",
"D": "16 : 21",
"E": "1 : 13"
} | power(divide(27, 64), divide(const_1, const_3)) | divide(n0,n1)|divide(const_1,const_3)|power(#0,#1) | ratio of the sides = ³ √ 27 : ³ √ 64 = 3 : 4 ratio of surface areas = 32 : 42 = 16 : 21 answer : d | geometry |
math_qa__pYuWkxxTidjUmHHi | A driver would have reduced the time it took to drive from home to the store by 1/3 if the average speed had been increased by 18 miles per hour. What was the actual average speed, in miles per hour, when the driver drove from home to the store?
Choose the correct choice from the following
A) 36 B) 40 C) 44 D) 48 E) 52 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 18</gadget>
<output>12</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">12 / (1/3)</gadget>
<output>36</output>
<result>A</result> | A | 36 | A driver would have reduced the time it took to drive from home to the store by 1/3 if the average speed had been increased by 18 miles per hour. What was the actual average speed, in miles per hour, when the driver drove from home to the store? | {
"A": "36",
"B": "40",
"C": "44",
"D": "48",
"E": "52"
} | divide(multiply(subtract(1, divide(1, 3)), 18), subtract(1, subtract(1, divide(1, 3)))) | divide(n0,n1)|subtract(n0,#0)|multiply(#1,n2)|subtract(n0,#1)|divide(#2,#3)| | "let r be the original speed and let t be the original time . since the distance remains the same ( we ' re just changing the rate and time ) , any increase in rate or time is met with a decrease in the other term . decreasing the time by 1 / 3 would give us : d = ( r ) ( t ) = ( 2 t / 3 ) ( x * r ) x = 3 / 2 since ( 2 t / 3 ) ( 3 r / 2 ) = ( r ) ( t ) = d 3 r / 2 = r + 18 r / 2 = 18 r = 36 the answer is a ." | general |
math_qa__h1muB0i5LR50Do4C | What is the probability Q of randomly selecting an arrangement of the letters of the wordMEDITERRANEANin which the first letter is E and the last letter is R? Answers:
A) 1 / 13
B) 1 / 20
C) 1 / 26
D) 1 / 50
E) 1 / 100 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">factorial(11)</gadget>
<output>39_916_800</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">39_916_800 / 8</gadget>
<output>4_989_600</output>
<gadget id="calculator">11 + 2</gadget>
<output>13</output>
<gadget id="calculator">factorial(13)</gadget>
<output>6_227_020_800</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">6_227_020_800 / 48</gadget>
<output>129_729_600</output>
<gadget id="calculator">4_989_600 / 129_729_600</gadget>
<output>1/26 = around 0.038462</output>
<result>C</result> | C | 0.038462 | What is the probability Q of randomly selecting an arrangement of the letters of the wordMEDITERRANEANin which the first letter is E and the last letter is R? | {
"A": "1 / 13",
"B": "1 / 20",
"C": "1 / 26",
"D": "1 / 50",
"E": "1 / 100"
} | divide(divide(factorial(subtract(multiply(const_3, const_4), const_1)), power(factorial(const_2), const_3)), divide(factorial(add(subtract(multiply(const_3, const_4), const_1), const_2)), multiply(factorial(const_3), power(factorial(const_2), const_3)))) | factorial(const_2)|factorial(const_3)|multiply(const_3,const_4)|power(#0,const_3)|subtract(#2,const_1)|add(#4,const_2)|factorial(#4)|multiply(#1,#3)|divide(#6,#3)|factorial(#5)|divide(#9,#7)|divide(#8,#10) | why do you calculate the total combinations and everything , it is much easier to calculate as follows : 3 / 13 * 1 * 1 * 1 * 1 . . . . . * 2 / 12 = 6 / 156 = 1 / 26 this is because 3 / 13 = probability that first letter will be e and 2 / 12 = probability that thefirstletter will be r . between everything else cuts down to 1 * 1 * 1 . . . e . g . probability q of the second letter is 11 / 11 = 1 , > we do not care what ' s in between . c | probability |
math_qa__gYdAxQ4upyerDTjR | The speed of a train is 90 kmph. What is the distance covered by it in 20 minutes? Choose the correct choice from the following answers: A) 15 B) 66 C) 77 D) 30 E) 42 | <gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 90</gadget>
<output>30</output>
<result>D</result> | D | 30 | The speed of a train is 90 kmph. What is the distance covered by it in 20 minutes? | {
"A": "15",
"B": "66",
"C": "77",
"D": "30",
"E": "42"
} | multiply(divide(20, const_60), 90) | divide(n1,const_60)|multiply(n0,#0)| | "90 * 20 / 60 = 30 kmph answer : d" | physics |
math_qa__79izU8P3T9xsonQd | A man can row downstream at the rate of 45 Kmph and upstream at 23 Kmph. Find the man’s rate in still water and rate of current? Choose the correct choice:
A) 8.5
B) 10.0
C) 12.5
D) 11.0
E) 8.25 | <gadget id="calculator">45 - 23</gadget>
<output>22</output>
<gadget id="calculator">22 / 2</gadget>
<output>11</output>
<result>D</result> | D | 11 | A man can row downstream at the rate of 45 Kmph and upstream at 23 Kmph. Find the man’s rate in still water and rate of current? | {
"A": "8.5",
"B": "10.0",
"C": "12.5",
"D": "11.0",
"E": "8.25"
} | divide(subtract(45, 23), const_2) | subtract(n0,n1)|divide(#0,const_2) | rate of still water = 1 / 2 ( down stream + upstream ) = 1 / 2 ( 45 + 23 ) = 34 kmph rate of current = 1 / 2 ( down stream - upstream ) = 1 / 2 ( 45 - 23 ) = 1 / 2 ( 22 ) = 11 kmph answer is d . | gain |
math_qa__jwt3gmIVb6NGvM8t | How many numbers from 9 to 79 are exactly divisible by 11? Select:
A) 5 B) 7 C) 9 D) 11 E) 12 | <gadget id="calculator">79 / 11</gadget>
<output>79/11 = around 7.181818</output>
<gadget id="calculator">floor(79/11)</gadget>
<output>7</output>
<gadget id="calculator">7 * 11</gadget>
<output>77</output>
<gadget id="calculator">9 / 11</gadget>
<output>9/11 = around 0.818182</output>
<gadget id="calculator">floor(9/11)</gadget>
<output>0</output>
<gadget id="calculator">0 + 1</gadget>
<output>1</output>
<gadget id="calculator">1 * 11</gadget>
<output>11</output>
<gadget id="calculator">77 - 11</gadget>
<output>66</output>
<gadget id="calculator">66 / 11</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<result>B</result> | B | 7 | How many numbers from 9 to 79 are exactly divisible by 11? | {
"A": "5",
"B": "7",
"C": "9",
"D": "11",
"E": "12"
} | add(divide(subtract(multiply(floor(divide(79, 11)), 11), multiply(add(floor(divide(9, 11)), const_1), 11)), 11), const_1) | divide(n1,n2)|divide(n0,n2)|floor(#0)|floor(#1)|add(#3,const_1)|multiply(n2,#2)|multiply(n2,#4)|subtract(#5,#6)|divide(#7,n2)|add(#8,const_1)| | "9 / 11 = 0 and 79 / 11 = 7 = = > 7 - 0 = 7 numbers answer : b" | general |
math_qa__ATvaylqB1o0aKAb7 | The speed of a car is 20 km in the first hour and 60 km in the second hour. What is the average speed of the car? Choose the correct choice
A) 79 kmph
B) 40 kmph
C) 34 kmph
D) 23 kmph
E) 14 kmph | <gadget id="calculator">20 + 60</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>B</result> | B | 40 | The speed of a car is 20 km in the first hour and 60 km in the second hour. What is the average speed of the car? | {
"A": "79 kmph",
"B": "40 kmph",
"C": "34 kmph",
"D": "23 kmph",
"E": "14 kmph"
} | divide(add(20, 60), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 20 + 60 ) / 2 = 40 kmph answer : b" | physics |
math_qa__G8bnKiFQKM0FTm6C | What least number should be added to 1053, so that the sum is completely divisible by 23 Select the correct option
A) 4 B) 1 C) 2 D) 3 E) 5 | <gadget id="calculator">1_053 % 23</gadget>
<output>18</output>
<gadget id="calculator">23 - 18</gadget>
<output>5</output>
<result>E</result> | E | 5 | What least number should be added to 1053, so that the sum is completely divisible by 23 | {
"A": "4",
"B": "1",
"C": "2",
"D": "3",
"E": "5"
} | subtract(23, reminder(1053, 23)) | reminder(n0,n1)|subtract(n1,#0)| | "explanation : ( 1053 / 23 ) gives remainder 18 18 + 5 = 23 , so we need to add 5 answer : option e" | general |
math_qa__Z7OEIwwcSbdODqRq | An error 5% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is Answers:
A) 10.4 %
B) 10.25 %
C) 10.23 %
D) 10.26 %
E) 10.5 % | <gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">105 ** 2</gadget>
<output>11_025</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">11_025 - 10_000</gadget>
<output>1_025</output>
<gadget id="calculator">1_025 * 100</gadget>
<output>102_500</output>
<gadget id="calculator">102_500 / 10_000</gadget>
<output>41/4 = around 10.25</output>
<result>B</result> | B | 10.25 | An error 5% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is | {
"A": "10.4 %",
"B": "10.25 %",
"C": "10.23 %",
"D": "10.26 %",
"E": "10.5 %"
} | divide(multiply(subtract(square_area(add(const_100, 5)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)| | "100 cm is read as 102 cm . a 1 = ( 100 x 100 ) cm 2 and a 2 ( 105 x 105 ) cm 2 . ( a 2 - a 1 ) = [ ( 105 ) 2 - ( 100 ) 2 ] = ( 105 + 100 ) x ( 105 - 100 ) = 1025 cm 2 . percentage error = 10.25 b" | gain |
math_qa__tUNfqPOUb1t0Sjv5 | The average weight of 6 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? Pick
A) 76 kg B) 80 kg C) 85 kg D) data inadequate E) none of these | <gadget id="calculator">6 * 2.5</gadget>
<output>15</output>
<gadget id="calculator">15 + 65</gadget>
<output>80</output>
<result>B</result> | B | 80 | The average weight of 6 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? | {
"A": "76 kg",
"B": "80 kg",
"C": "85 kg",
"D": "data inadequate",
"E": "none of these"
} | add(multiply(6, 2.5), 65) | multiply(n0,n1)|add(n2,#0)| | "explanation : total weight increased = ( 6 x 2.5 ) kg = 15 kg . weight of new person = ( 65 + 15 ) kg = 80 kg . answer : b" | general |
math_qa__vbyHyzBAqfpXNJiq | A shopkeeper sells 200 metres of cloth for Rs. 12000 at a loss of Rs.6 per metre. Find his cost price for one metre of cloth? Choose the correct choice from the following answers
A) s . 59 B) s . 58 C) s . 09 D) s . 50 E) s . 66 | <gadget id="calculator">12_000 / 200</gadget>
<output>60</output>
<gadget id="calculator">60 + 6</gadget>
<output>66</output>
<result>E</result> | E | 66 | A shopkeeper sells 200 metres of cloth for Rs. 12000 at a loss of Rs.6 per metre. Find his cost price for one metre of cloth? | {
"A": "s . 59",
"B": "s . 58",
"C": "s . 09",
"D": "s . 50",
"E": "s . 66"
} | add(divide(12000, 200), 6) | divide(n1,n0)|add(n2,#0)| | "sp per metre = 12000 / 200 = rs . 60 loss per metre = rs . 6 cp per metre = 60 + 6 = rs . 66 answer : e" | gain |
math_qa__BdyA5m75m44ShqfZ | In what ratio must rice at $9.30/kg be mixed with rice at $10.80/kg so that the mixture is worth $10/kg?
Choose the correct choice from the following answers:
A) 1 : 3
B) 9 : 4
C) 8 : 7
D) 11 : 9
E) 11 : 7 | <gadget id="calculator">10.8 - 10</gadget>
<output>0.8</output>
<gadget id="calculator">10 - 9.3</gadget>
<output>0.7</output>
<gadget id="calculator">0.8 / 0.7</gadget>
<output>1.142857</output>
<result>C</result> | C | 1.142857 | In what ratio must rice at $9.30/kg be mixed with rice at $10.80/kg so that the mixture is worth $10/kg? | {
"A": "1 : 3",
"B": "9 : 4",
"C": "8 : 7",
"D": "11 : 9",
"E": "11 : 7"
} | divide(subtract(10.8, 10), subtract(10, 9.3)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1) | 9.30 x + 10.80 y = 10 ( x + y ) . 80 y = . 70 x x / y = 8 / 7 c is the answer | general |
math_qa__bYhx6W1nk6tLHaYl | A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter Q of liquid A was contained by the can initially? Choose the correct choice from the following: A) 10 B) 20 C) 21 D) 25 E) 27 | <gadget id="calculator">7 + 9</gadget>
<output>16</output>
<gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) * 9</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">9 - (15/4)</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">16 * (21/4)</gadget>
<output>84</output>
<gadget id="calculator">9 * 7</gadget>
<output>63</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">63 - 35</gadget>
<output>28</output>
<gadget id="calculator">84 / 28</gadget>
<output>3</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<result>C</result> | C | 21 | A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter Q of liquid A was contained by the can initially? | {
"A": "10",
"B": "20",
"C": "21",
"D": "25",
"E": "27"
} | multiply(7, divide(multiply(add(7, 9), subtract(9, multiply(divide(5, add(7, 5)), 9))), subtract(multiply(9, 7), multiply(7, 5)))) | add(n0,n2)|add(n0,n1)|multiply(n0,n2)|multiply(n0,n1)|divide(n1,#1)|subtract(#2,#3)|multiply(n2,#4)|subtract(n2,#6)|multiply(#0,#7)|divide(#8,#5)|multiply(n0,#9)| | "as a : b : : 7 : 5 - - - > only option c is a multiple of 7 and hence it is a good place to start . also a : b : : 7 : 5 means that , a = ( 712 ) * total and b = ( 5 / 12 ) * total if a = 21 , b = 15 - - - > remove 9 litres - - - > you remove ( 7 / 12 ) * 9 of a - - - > a remaining = 21 - ( 7 / 12 ) * 9 = 63 / 4 similarly , for b , you remove ( 5 / 12 ) * 9 - - - > b remaining = 15 - ( 5 / 12 ) * 9 = 45 / 4 and then add 9 more litres of b - - - > 9 + 45 / 4 = 81 / 4 thus a / b ( final ratio ) = ( 45 / 4 ) / ( 81 / 4 ) = 7 : 9 , the same as the final ratio mentioned in the question . hence c is the correct answer . a / b = 7 / 9 = ( 7 x - ( 7 / 12 ) * 9 ) / ( 5 x - ( 5 / 12 ) * 9 + 9 ) , where 7 x and 5 x are initial quantities of a and b respectively . thus , 7 / 9 = ( 7 x - ( 7 / 12 ) * 9 ) / ( 5 x - ( 5 / 12 ) * 9 + 9 ) - - - > giving you x = 3 . thus a ( original ) q = 7 * 3 = 21 . c" | other |
math_qa__gOhXSqWrfT2E49nG | A salesperson received a commission of 3 percent of the sale price for each of the first 100 machines that she sold and 4 percent of the sale price for each machine that she sold after the first 100. If the sale price of each machine was $10,000 and the salesperson received a $42,000 commission, how many machines did she sell? Pick:
A) 90
B) 103
C) 130
D) 115
E) 120 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">42 * 100</gadget>
<output>4_200</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">4_200 * 10</gadget>
<output>42_000</output>
<gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">10_000 * (3/100)</gadget>
<output>300</output>
<gadget id="calculator">300 * 100</gadget>
<output>30_000</output>
<gadget id="calculator">42_000 - 30_000</gadget>
<output>12_000</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">10_000 * (1/25)</gadget>
<output>400</output>
<gadget id="calculator">12_000 / 400</gadget>
<output>30</output>
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<result>C</result> | C | 130 | A salesperson received a commission of 3 percent of the sale price for each of the first 100 machines that she sold and 4 percent of the sale price for each machine that she sold after the first 100. If the sale price of each machine was $10,000 and the salesperson received a $42,000 commission, how many machines did she sell? | {
"A": "90",
"B": "103",
"C": "130",
"D": "115",
"E": "120"
} | add(100, divide(subtract(multiply(multiply(multiply(add(const_4, const_3), multiply(const_3, const_2)), const_100), multiply(add(const_4, const_1), const_2)), multiply(multiply(multiply(const_100, const_100), divide(3, const_100)), 100)), multiply(multiply(const_100, const_100), divide(4, const_100)))) | add(const_3,const_4)|add(const_1,const_4)|divide(n0,const_100)|divide(n2,const_100)|multiply(const_2,const_3)|multiply(const_100,const_100)|multiply(#0,#4)|multiply(#1,const_2)|multiply(#2,#5)|multiply(#3,#5)|multiply(#6,const_100)|multiply(n1,#8)|multiply(#10,#7)|subtract(#12,#11)|divide(#13,#9)|add(n1,#14) | first 100 machines = 3 % commission = 0.03 * 100 * 10000 = 30000 commission from sale of next machines = 42000 - 30000 = 12000 so 30 more machines . . total = 130 machines imo c . . . | gain |
math_qa__38Z57euMKFMjTYse | In a class of students, 1/2 of the number of girls is equal to 1/6 of the total number of students. What is the ratio of boys to girls in the class? Choose the correct choice from the following answers:
A) 1 / 2
B) 2 / 3
C) 2 / 1
D) 3 / 2
E) 4 / 3 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/2) - (1/6)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) / (1/6)</gadget>
<output>2</output>
<result>C</result> | C | 2 | In a class of students, 1/2 of the number of girls is equal to 1/6 of the total number of students. What is the ratio of boys to girls in the class? | {
"A": "1 / 2",
"B": "2 / 3",
"C": "2 / 1",
"D": "3 / 2",
"E": "4 / 3"
} | divide(subtract(divide(1, 2), divide(1, 6)), divide(1, 6)) | divide(n0,n1)|divide(n2,n3)|subtract(#0,#1)|divide(#2,#1)| | "( 1 / 2 ) g = ( 1 / 6 ) ( b + g ) 6 g = 2 b + 2 g 4 g = 2 b b / g = 2 / 1 . the answer is c ." | general |
math_qa__OxJzNlPzTCmEt7LB | If x is less than y by 45% then y exceed x by: Pick: A) 33.33 % B) 25 % C) 81.81 % D) 66.66 % E) none of these | <gadget id="calculator">100 - 45</gadget>
<output>55</output>
<gadget id="calculator">100 / 55</gadget>
<output>20/11 = around 1.818182</output>
<gadget id="calculator">(20/11) - 1</gadget>
<output>9/11 = around 0.818182</output>
<gadget id="calculator">(9/11) * 100</gadget>
<output>900/11 = around 81.818182</output>
<result>C</result> | C | 81.81 | If x is less than y by 45% then y exceed x by: | {
"A": "33.33 %",
"B": "25 %",
"C": "81.81 %",
"D": "66.66 %",
"E": "none of these"
} | multiply(subtract(divide(const_100, subtract(const_100, 45)), const_1), const_100) | subtract(const_100,n0)|divide(const_100,#0)|subtract(#1,const_1)|multiply(#2,const_100)| | "using formula ( x / ( 100 - x ) * 100 ) where x is percentage decrease ( here it is 25 % ) = > 45 / ( 100 - 45 ) * 100 = 81.81 % answer : c" | general |
math_qa__g9WfNJ0cTQNTqydF | Convert 0.35 in to a vulgar fraction ? Pick one:
A) 18 / 50 B) 16 / 50 C) 7 / 20 D) 19 / 50 E) none | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">100 * 0.35</gadget>
<output>35</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<result>C</result> | C | 0.35 | Convert 0.35 in to a vulgar fraction ? | {
"A": "18 / 50",
"B": "16 / 50",
"C": "7 / 20",
"D": "19 / 50",
"E": "none"
} | divide(multiply(multiply(multiply(add(const_3, const_2), const_2), multiply(add(const_3, const_2), const_2)), 0.35), multiply(multiply(add(const_3, const_2), const_2), multiply(add(const_3, const_2), const_2))) | add(const_2,const_3)|multiply(#0,const_2)|multiply(#1,#1)|multiply(n0,#2)|divide(#3,#2)| | "answer 0.35 = 35 / 100 = 7 / 20 correct option : c" | physics |
math_qa__KBSdM6JDB1dNHgc6 | How many multiples of 10 are there between 10 and 1000, exclusive? Choices:
A) 98
B) 99
C) 100
D) 101
E) 97 | <gadget id="calculator">1_000 - 10</gadget>
<output>990</output>
<gadget id="calculator">990 / 10</gadget>
<output>99</output>
<gadget id="calculator">99 + 1</gadget>
<output>100</output>
<result>A</result> | A | 98 | How many multiples of 10 are there between 10 and 1000, exclusive? | {
"A": "98",
"B": "99",
"C": "100",
"D": "101",
"E": "97"
} | add(divide(subtract(1000, 10), 10), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "98 multiples of 5 between 1 and 36 exclusive . from 10 * 2 upto 10 * 99 , ( 2 , 3,4 , . . . , 99 ) . hence , 98 multiples ! correct option is a" | general |
math_qa__Obo3aKFWX1lhJqYT | Find the average of all the numbers between 6 and 29 which are divisible by 5? Select
A) 17 B) 20 C) 25 D) 30 E) 15 | <gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">29 - 4</gadget>
<output>25</output>
<gadget id="calculator">10 + 25</gadget>
<output>35</output>
<gadget id="calculator">35 / 2</gadget>
<output>35/2 = around 17.5</output>
<result>A</result> | A | 17 | Find the average of all the numbers between 6 and 29 which are divisible by 5? | {
"A": "17",
"B": "20",
"C": "25",
"D": "30",
"E": "15"
} | divide(add(add(6, const_4), subtract(29, const_4)), const_2) | add(n0,const_4)|subtract(n1,const_4)|add(#0,#1)|divide(#2,const_2) | average = ( 10 + 15 + 20 + 25 ) 4 = 70 / 4 = 17 answer is a | general |
math_qa__qp72pu4CH1n74Yx0 | Train A leaves the station traveling at 30 miles per hour. Two hours later train В leaves the same station traveling in the same direction at 36 miles per hour. How many miles from the station was train A overtaken by train B? Choose the correct choice from the following answers: A) 320 B) 360 C) 400 D) 440 E) 480 | <gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">36 - 30</gadget>
<output>6</output>
<gadget id="calculator">60 / 6</gadget>
<output>10</output>
<gadget id="calculator">10 * 36</gadget>
<output>360</output>
<result>B</result> | B | 360 | Train A leaves the station traveling at 30 miles per hour. Two hours later train В leaves the same station traveling in the same direction at 36 miles per hour. How many miles from the station was train A overtaken by train B? | {
"A": "320",
"B": "360",
"C": "400",
"D": "440",
"E": "480"
} | multiply(divide(multiply(30, const_2), subtract(36, 30)), 36) | multiply(n0,const_2)|subtract(n1,n0)|divide(#0,#1)|multiply(n1,#2)| | "after two hours , train a is ahead by 60 miles . train b can catch up at a rate of 6 miles per hour . the time to catch up is 60 / 6 = 10 hours . in 10 hours , train a travels another 30 * 10 = 300 miles for a total of 360 miles . the answer is b ." | physics |
math_qa__5yaKFR6xZgNr2g57 | In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is?
Select: A) 1 hr B) 2 hr C) 6 hr D) 8 hr E) 7 hr | <gadget id="calculator">200 * 30</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 10</gadget>
<output>600</output>
<gadget id="calculator">600 / 600</gadget>
<output>1</output>
<result>A</result> | A | 1 | In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is? | {
"A": "1 hr",
"B": "2 hr",
"C": "6 hr",
"D": "8 hr",
"E": "7 hr"
} | divide(600, divide(multiply(200, 30), const_10)) | multiply(n1,n2)|divide(#0,const_10)|divide(n0,#1) | let the duration of the flight be x hours . then , 600 / x - 600 / ( x + 1 / 2 ) = 200 x ( 2 x + 1 ) = 3 2 x 2 + x - 3 = 0 ( 2 x + 3 ) ( x - 1 ) = 0 x = 1 hr . answer : a | general |
math_qa__DeCGh3KPjwcTXNet | S is a set of 64 consecutive multiples of 4. If the smallest number in S is 68, then the greatest number in S is Pick
A) 198
B) 297
C) 320
D) 402
E) 405 | <gadget id="calculator">64 - 1</gadget>
<output>63</output>
<gadget id="calculator">63 * 4</gadget>
<output>252</output>
<gadget id="calculator">68 + 252</gadget>
<output>320</output>
<result>C</result> | C | 320 | S is a set of 64 consecutive multiples of 4. If the smallest number in S is 68, then the greatest number in S is | {
"A": "198",
"B": "297",
"C": "320",
"D": "402",
"E": "405"
} | add(68, multiply(subtract(64, const_1), 4)) | subtract(n0,const_1)|multiply(n1,#0)|add(n2,#1) | last term = first term + ( total no . of terms - 1 ) consecutive difference s is a set of 64 consecutive multiples of 4 . if the smallest number in s is 68 , then the greatest number in s is first term = 68 ; total terms = 64 ; difference = 4 68 + ( 63 ) 4 = 320 ans c | general |
math_qa__oADhCF3ocT47vvx8 | The “s-number” of a number x is defined as the ones digit of 2^x. Antony rolls a die with 6 sides labeled with the integers from 1 to 6, each of which has an equal probability of landing face-up. He then takes 3^s, where s is the s-number of the result of his die roll, and plots 3^s on a number line as the point A. Finally, he repeats this entire process, this time plotting the result as the point B. What is the probability that the distance between A and B is greater than the value of B? Choose the correct choice from the following answers: A) 3 / 8 B) 13 / 36 C) 17 / 36 D) 19 / 36 E) 23 / 36 | <gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">10 + 3</gadget>
<output>13</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">13 / 36</gadget>
<output>13/36 = around 0.361111</output>
<result>B</result> | B | 0.361111 | The “s-number” of a number x is defined as the ones digit of 2^x. Antony rolls a die with 6 sides labeled with the integers from 1 to 6, each of which has an equal probability of landing face-up. He then takes 3^s, where s is the s-number of the result of his die roll, and plots 3^s on a number line as the point A. Finally, he repeats this entire process, this time plotting the result as the point B. What is the probability that the distance between A and B is greater than the value of B? | {
"A": "3 / 8",
"B": "13 / 36",
"C": "17 / 36",
"D": "19 / 36",
"E": "23 / 36"
} | divide(add(add(add(6, 1), 3), 3), multiply(6, 6)) | add(n1,n2)|multiply(n1,n1)|add(n4,#0)|add(n4,#2)|divide(#3,#1) | if you calculate 3 ^ s for 1 st roll , all 6 results will be 9 , 81 , 6561 , 729 , 9 , 81 . this result is the same for 2 nd roll . 9 , 81 , 6561 , 729 , 9 , 81 . about distance : if the first result is 9 and the second is also 9 , the distance is 9 - 9 = 0 which is smaller than 9 . if the first result is 9 and the second is 81 , the distance is 81 - 9 = 72 which is also smaller than b which has the value of 81 . if the first result is 81 and the second is 9 , the distance will be greater than b . distance 81 - 9 = 72 > 9 . on the first roll , the probability of getting result 9 is 2 / 6 . in this case no other alternative values for second roll which would make the distance greater than b . so probability is 0 . so next estimations are : probability of getting 81 on the first roll ( 2 / 6 ) * probability of getting 9 on the second roll ( 2 / 6 ) = 1 / 9 probability of getting 729 on the first roll ( 1 / 6 ) * probability of getting 9 , 81 on the second roll ( 4 / 6 ) = 1 / 9 probability of getting 6561 on the first roll ( 1 / 6 ) * probability of getting 9 , 81 , 729 on the first roll ( 5 / 6 ) = 5 / 36 all together : 1 / 9 + 1 / 9 + 5 / 36 = 13 / 36 = b | general |
math_qa__knPVUo1yRhJmFulX | Angelina walked 1200 meters from her home to the grocery at a constant speed. She then walked 480 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym? Choose the correct answer.
A) 12 B) 23 C) 34 D) 48 E) 52 | <gadget id="calculator">480 / 2</gadget>
<output>240</output>
<gadget id="calculator">1_200 - 240</gadget>
<output>960</output>
<gadget id="calculator">960 / 40</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<result>D</result> | D | 48 | Angelina walked 1200 meters from her home to the grocery at a constant speed. She then walked 480 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym? | {
"A": "12",
"B": "23",
"C": "34",
"D": "48",
"E": "52"
} | multiply(divide(subtract(1200, divide(480, const_2)), 40), const_2) | divide(n1,const_2)|subtract(n0,#0)|divide(#1,n2)|multiply(#2,const_2)| | "let the speed be x . . . so time taken from home to grocery = 1200 / x . . the speed to gym = 2 x . . so time taken = 480 / 2 x = 240 / x . . its given 1200 / x - 240 / x = 40 . . 960 / x = 40 . . x = 24 m / secs . . so grocery to gym = 2 * 24 = 48 m / s . . . d" | physics |
math_qa__oh0f4xKehDLWRbhv | A waiter's salary consists of his salary and tips. During one week his tips were 5/2 of his salary. What fraction of his income came from tips ? Choose one.
A) 4 / 9 B) 5 / 4 C) 5 / 8 D) 5 / 7 E) 6 / 9 | <gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) + 1</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(5/2) / (7/2)</gadget>
<output>5/7 = around 0.714286</output>
<result>D</result> | D | 0.714286 | A waiter's salary consists of his salary and tips. During one week his tips were 5/2 of his salary. What fraction of his income came from tips ? | {
"A": "4 / 9",
"B": "5 / 4",
"C": "5 / 8",
"D": "5 / 7",
"E": "6 / 9"
} | divide(divide(5, 2), add(divide(5, 2), const_1)) | divide(n0,n1)|add(#0,const_1)|divide(#0,#1) | income = salary ( s ) + tips = s + s * 5 / 2 = s * 7 / 2 tips = s * 7 / 2 fraction of his income came from tips = ( s * 5 / 2 ) / ( s * 7 / 2 ) = 5 / 7 answer : d | general |
math_qa__dr1hpVkOF6U6gfd6 | If a certain number X is divided by 82, the reminder is 5. what is the reminder when X+7 is divided by 41? Choose the correct answer:
A) 12
B) 5
C) 6
D) 16
E) 18 | <gadget id="calculator">5 + 7</gadget>
<output>12</output>
<result>A</result> | A | 12 | If a certain number X is divided by 82, the reminder is 5. what is the reminder when X+7 is divided by 41? | {
"A": "12",
"B": "5",
"C": "6",
"D": "16",
"E": "18"
} | add(5, 7) | add(n1,n2)| | "x can be written as 82 k + 5 or x = 5 , 87,169 , etc . when k = 0 , 1,2 etc x + 7 = 82 k + 5 + 7 = 82 k + 12 or x + 7 = 12,94 , 176 etc . k = 0 , 1,2 when divided by 41 , we will get the remainder 12 . a" | general |
math_qa__quMq5jCLtsSZiVOy | A reduction of 50% in the price of apples would enable a man to obtain 80 more for Rs.55, what is reduced price per dozen? Pick:
A) 1
B) 3
C) 4
D) 7
E) 10 | <gadget id="calculator">50 * 55</gadget>
<output>2_750</output>
<gadget id="calculator">2_750 / 100</gadget>
<output>55/2 = around 27.5</output>
<gadget id="calculator">(55/2) / 80</gadget>
<output>11/32 = around 0.34375</output>
<gadget id="calculator">(11/32) * 12</gadget>
<output>33/8 = around 4.125</output>
<result>C</result> | C | 4 | A reduction of 50% in the price of apples would enable a man to obtain 80 more for Rs.55, what is reduced price per dozen? | {
"A": "1",
"B": "3",
"C": "4",
"D": "7",
"E": "10"
} | multiply(divide(divide(multiply(50, 55), const_100), 80), const_12) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)|multiply(#2,const_12) | c 55 * ( 50 / 100 ) = 28 - - - 64 ? - - - 12 = > rs . 4 | gain |
math_qa__8i2Kgt8tRamcZRK3 | Cindy has her eye on a sundress but thinks it is too expensive. It goes on sale for 15% less than the original price. Before Cindy can buy the dress, however, the store raises the new price by 25%. If the dress cost $85 after it went on sale for 15% off, what is the difference between the original price and the final price?
Choose one:
A) $ 0.00 B) $ 1.00 C) $ 3.40 D) $ 5.00 E) $ 6.25 | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">85 * (5/4)</gadget>
<output>425/4 = around 106.25</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">85 / (17/20)</gadget>
<output>100</output>
<gadget id="calculator">(425/4) - 100</gadget>
<output>25/4 = around 6.25</output>
<result>E</result> | E | 6.25 | Cindy has her eye on a sundress but thinks it is too expensive. It goes on sale for 15% less than the original price. Before Cindy can buy the dress, however, the store raises the new price by 25%. If the dress cost $85 after it went on sale for 15% off, what is the difference between the original price and the final price? | {
"A": "$ 0.00",
"B": "$ 1.00",
"C": "$ 3.40",
"D": "$ 5.00",
"E": "$ 6.25"
} | subtract(multiply(85, divide(add(const_100, 25), const_100)), divide(85, divide(subtract(const_100, 15), const_100))) | add(n1,const_100)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,const_100)|divide(n2,#3)|multiply(n2,#2)|subtract(#5,#4)| | "0.85 * { original price } = $ 85 - - > { original price } = $ 100 . { final price } = $ 85 * 1.25 = $ 106.25 . the difference = $ 106.25 - $ 100 = $ 6.25 . answer : e ." | general |
math_qa__7CdBc2dle11UYh7a | A committee is reviewing a total of 20x black-and-white films and 6y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction Q of the selected films are in color?
Choose the correct choice from the following answers:
A) 1 / 130
B) 1 / 5
C) 3 / 13
D) 10 / 13
E) 30 / 31 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 6</gadget>
<output>31/5 = around 6.2</output>
<gadget id="calculator">6 / (31/5)</gadget>
<output>30/31 = around 0.967742</output>
<result>E</result> | E | 0.967742 | A committee is reviewing a total of 20x black-and-white films and 6y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction Q of the selected films are in color? | {
"A": "1 / 130",
"B": "1 / 5",
"C": "3 / 13",
"D": "10 / 13",
"E": "30 / 31"
} | divide(6, add(divide(20, const_100), 6)) | divide(n0,const_100)|add(n1,#0)|divide(n1,#1) | it ' s y / xpercentnot y / x . if x = 20 and y = 10 . then : 20 x = 400 black - and - white films ; 6 y = 60 color films . y / x % = 10 / 20 % = 0.5 % of the black - and - white films , so 2 black - and - white films and all 60 color films , thus total of 62 films were selected . color films thus compose q = 60 / 62 = 30 / 31 of the selected films . answer : e . | general |
math_qa__jX2Yb5E7xsc97oNm | A train travels 125 km in 2.5 hours and 270 km in 3 hours.find the average speed of train. Choose the correct option: A) 80 kmph B) 60 kmph C) 72 kmph D) 90 kmph E) none of these | <gadget id="calculator">125 + 270</gadget>
<output>395</output>
<gadget id="calculator">2.5 + 3</gadget>
<output>5.5</output>
<gadget id="calculator">395 / 5.5</gadget>
<output>71.818182</output>
<result>C</result> | C | 72 | A train travels 125 km in 2.5 hours and 270 km in 3 hours.find the average speed of train. | {
"A": "80 kmph",
"B": "60 kmph",
"C": "72 kmph",
"D": "90 kmph",
"E": "none of these"
} | divide(add(125, 270), add(2.5, 3)) | add(n0,n2)|add(n1,n3)|divide(#0,#1)| | "as we know that speed = distance / time for average speed = total distance / total time taken thus , total distance = 125 + 270 = 395 km thus , total speed = 5.5 hrs or , average speed = 5 = 395 / 5.5 or , 72 kmph . answer : c" | physics |
math_qa__uHdVAaDoSUI1zPWr | When x is even, [x] = x/2 + 1, when x is odd [x] = 2x + 1 then [7]*[8] = ? Select.
A) [ 22 ] B) [ 44 ] C) [ 75 ] D) [ 88 ] E) [ 90 ] | <gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) + 1</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">2 * 8</gadget>
<output>16</output>
<gadget id="calculator">16 + 1</gadget>
<output>17</output>
<gadget id="calculator">(9/2) * 17</gadget>
<output>153/2 = around 76.5</output>
<result>C</result> | C | 75 | When x is even, [x] = x/2 + 1, when x is odd [x] = 2x + 1 then [7]*[8] = ? | {
"A": "[ 22 ]",
"B": "[ 44 ]",
"C": "[ 75 ]",
"D": "[ 88 ]",
"E": "[ 90 ]"
} | multiply(add(divide(7, 2), 1), add(multiply(2, 8), 1)) | divide(n4,n0)|multiply(n0,n5)|add(#0,n1)|add(#1,n1)|multiply(#2,#3)| | "[ 7 ] * [ 8 ] = ( 7 * 2 + 1 ) ( 8 / 2 + 1 ) = [ 75 ] . ans - c" | general |
math_qa__mY5QAs70SCcWEooL | The price of a car is marked at $12,000. If the car has successive discounts of 20%, 15% and 5%, then at what price does a customer buy the car? Select:
A) $ 7524 B) $ 7752 C) $ 7880 D) $ 8196 E) $ 8324 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">100 * 12</gadget>
<output>1_200</output>
<gadget id="calculator">10 * 1_200</gadget>
<output>12_000</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">12_000 * (1/5)</gadget>
<output>2_400</output>
<gadget id="calculator">12_000 - 2_400</gadget>
<output>9_600</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">9_600 * (3/20)</gadget>
<output>1_440</output>
<gadget id="calculator">9_600 - 1_440</gadget>
<output>8_160</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">8_160 * (1/20)</gadget>
<output>408</output>
<gadget id="calculator">8_160 - 408</gadget>
<output>7_752</output>
<result>B</result> | B | 7,752 | The price of a car is marked at $12,000. If the car has successive discounts of 20%, 15% and 5%, then at what price does a customer buy the car? | {
"A": "$ 7524",
"B": "$ 7752",
"C": "$ 7880",
"D": "$ 8196",
"E": "$ 8324"
} | subtract(subtract(subtract(multiply(multiply(5, const_2), multiply(const_100, multiply(const_3, const_4))), multiply(multiply(multiply(5, const_2), multiply(const_100, multiply(const_3, const_4))), divide(20, const_100))), multiply(subtract(multiply(multiply(5, const_2), multiply(const_100, multiply(const_3, const_4))), multiply(multiply(multiply(5, const_2), multiply(const_100, multiply(const_3, const_4))), divide(20, const_100))), divide(15, const_100))), multiply(subtract(subtract(multiply(multiply(5, const_2), multiply(const_100, multiply(const_3, const_4))), multiply(multiply(multiply(5, const_2), multiply(const_100, multiply(const_3, const_4))), divide(20, const_100))), multiply(subtract(multiply(multiply(5, const_2), multiply(const_100, multiply(const_3, const_4))), multiply(multiply(multiply(5, const_2), multiply(const_100, multiply(const_3, const_4))), divide(20, const_100))), divide(15, const_100))), divide(5, const_100))) | divide(n1,const_100)|divide(n2,const_100)|divide(n3,const_100)|multiply(n3,const_2)|multiply(const_3,const_4)|multiply(#4,const_100)|multiply(#3,#5)|multiply(#0,#6)|subtract(#6,#7)|multiply(#1,#8)|subtract(#8,#9)|multiply(#2,#10)|subtract(#10,#11) | 0.95 * 0.85 * 0.8 * 12000 = $ 7752 the answer is b . | gain |
math_qa__PAWhn89nz4r6qYzr | A dealer offers a cash discount of 10% and still makes a profit of 20% when he further allows 45 articles to be sold at the cost price of 40 articles to a particular sticky bargainer. How much percent above the cost price were his articles listed? Pick one
A) 40 % B) 50 % C) 55 % D) 80 % E) 90 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">45 - 40</gadget>
<output>5</output>
<gadget id="calculator">5 / 45</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">1 - (1/9)</gadget>
<output>8/9 = around 0.888889</output>
<gadget id="calculator">(6/5) / (8/9)</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(27/20) / (9/10)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>B</result> | B | 50 | A dealer offers a cash discount of 10% and still makes a profit of 20% when he further allows 45 articles to be sold at the cost price of 40 articles to a particular sticky bargainer. How much percent above the cost price were his articles listed? | {
"A": "40 %",
"B": "50 %",
"C": "55 %",
"D": "80 %",
"E": "90 %"
} | multiply(subtract(divide(divide(divide(add(const_100, 20), const_100), subtract(const_1, divide(subtract(45, 40), 45))), divide(subtract(const_100, 10), const_100)), const_1), const_100) | add(n1,const_100)|subtract(n2,n3)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,n2)|divide(#2,const_100)|subtract(const_1,#4)|divide(#3,#6)|divide(#7,#5)|subtract(#8,const_1)|multiply(#9,const_100)| | "given cash discount - 10 % profit - 20 % items sold - 45 price sold at = list price of 40 assume list price = $ 10 total invoice = $ 400 - 10 % cash discount = $ 360 let cost price of 45 items be x so total cost = 45 * x given the shopkeeper had a profit of 20 % 45 * x * 120 / 100 = 360 or x = $ 20 / 3 = $ 6 + ( 2 / 3 ) which means his products were listed at $ 10 which is a 50 % markup over $ 6 + ( 2 / 3 ) answer b" | gain |
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